Datasets:

avaliev
/

ChemistryQA

Dataset card Data Studio Files Files and versions Community

Split (3)

train · 3.43k rows

Unnamed: 0 int64 0 3.43k	guid stringlengths 36 36	url stringlengths 44 113	correct_answer stringlengths 1 105	annotation stringlengths 33 449	target_var_json stringlengths 48 152	answer_json stringlengths 38 146	condition_json stringlengths 32 823	question_title stringlengths 68 312	question_details stringclasses 188 values	answer stringlengths 1 105	answer_description stringlengths 153 8.47k	answer_text stringlengths 146 8.65k	full_articfle stringlengths 5.44k 19.2k	question stringlengths 21 265	question_description stringclasses 187 values
2,200	ac4169e4-6ddd-11ea-8e69-ccda262736ce	https://socratic.org/questions/how-many-moles-of-atoms-does-224-liters-of-helium-contain-at-stp	10 moles	start physical_unit 4 4 mole mol qc_end physical_unit 9 9 6 7 volume qc_end c_other STP qc_end end	[{"type":"physical unit","value":"Mole [OF] atoms [IN] moles"}]	[{"type":"physical unit","value":"10 moles"}]	[{"type":"physical unit","value":"Volume [OF] helium [=] \\pu{224 liters}"},{"type":"other","value":"STP"}]	<h1 class="questionTitle" itemprop="name">How many moles of atoms does 224 liters of helium contain at STP?</h1>	null	10 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <strong>molar volume</strong> of an ideal gas at STP (273 K) is 22.4 L.<br/> Most gases (and especially not helium) differ enough from the ideal gas to make a measurable difference.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>10 moles</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <strong>molar volume</strong> of an ideal gas at STP (273 K) is 22.4 L.<br/> Most gases (and especially not helium) differ enough from the ideal gas to make a measurable difference.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles of atoms does 224 liters of helium contain at STP?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp" itemprop="url"> <span class="breadcrumb" itemprop="title">Molar Volume of a Gas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="356383" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meneernask"><img alt="" class="" src="https://profilepictures.socratic.org/gpA0lokRGK9vLVUnAMAy_meneernask.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meneernask"> MeneerNask </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-12-25T00:39:01" itemprop="dateCreated"> Dec 25, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>10 moles</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <strong>molar volume</strong> of an ideal gas at STP (273 K) is 22.4 L.<br/> Most gases (and especially not helium) differ enough from the ideal gas to make a measurable difference.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/356383" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-stoichiometric-ratios-relate-to-molar-volume-of-a-gas"> How do stoichiometric ratios relate to molar volume of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-a-gas-at-stp"> How do you calculate molar volume of a gas at STP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-molar-volume-of-hydrogen-gas"> How do you find the molar volume of hydrogen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-oxygen-gas"> How do you calculate molar volume of oxygen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molar-gas-volume"> What is molar gas volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/534c7bf202bf3420a007f014"> What is the volume at 0 °C and 1 atm of a mixture that contains 4.0 g of methane and 2.0 g of helium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5361f75702bf3429040e0599"> What is the difference between STP and NTP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-volume-of-25-moles-of-oxygen-o2-gas"> What is the volume of .25 moles of oxygen (O2) Gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-would-knowing-the-molar-volume-of-a-gas-be-important"> Why would knowing the molar volume of a gas be important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-22-4-liters-called-the-molar-volume-of-a-gas"> Why is 22.4 liters called the molar volume of a gas? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp"> See all questions in Molar Volume of a Gas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2483 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many moles of atoms does 224 liters of helium contain at STP?	null
2,201	ab553c47-6ddd-11ea-a438-ccda262736ce	https://socratic.org/questions/how-many-moles-of-n-2-are-formed-by-the-decomposition-of-2-5-moles-of-nan-3	3.75 moles	start physical_unit 4 4 mole mol qc_end physical_unit 14 14 11 12 mole qc_end end	[{"type":"physical unit","value":"Mole [OF] N2 [IN] moles"}]	[{"type":"physical unit","value":"3.75 moles"}]	[{"type":"physical unit","value":"Mole [OF] NaN3 [=] \\pu{2.5 moles}"}]	<h1 class="questionTitle" itemprop="name">How many moles of #N_2# are formed by the decomposition of 2.5 moles of #NaN_3#?</h1>	null	3.75 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The decomposition reaction of sodium azide <mathjax>#NaN_3#</mathjax> is:</p> <p><mathjax>#2NaN_3(s)->2Na(s)+3N_2(g)#</mathjax></p> <p>Using dimensional analysis, we can find the number of mole of <mathjax>#N_2#</mathjax> gas formed:</p> <p><mathjax>#?molN_2(g)=2.5cancel(mol NaN_3)xx(3molN_2)/(2cancel(molNaN_3))=3.75molN_2#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#3.75molN_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The decomposition reaction of sodium azide <mathjax>#NaN_3#</mathjax> is:</p> <p><mathjax>#2NaN_3(s)->2Na(s)+3N_2(g)#</mathjax></p> <p>Using dimensional analysis, we can find the number of mole of <mathjax>#N_2#</mathjax> gas formed:</p> <p><mathjax>#?molN_2(g)=2.5cancel(mol NaN_3)xx(3molN_2)/(2cancel(molNaN_3))=3.75molN_2#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles of #N_2# are formed by the decomposition of 2.5 moles of #NaN_3#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/decomposition-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Decomposition Reactions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="227229" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ali-h-1"><img alt="" class="" src="https://profilepictures.socratic.org/IITeL1YTQdODdLp0aJTL_StereoPicture%20copy.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ali-h-1"> Dr. Hayek </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-02-16T19:40:56" itemprop="dateCreated"> Feb 16, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#3.75molN_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The decomposition reaction of sodium azide <mathjax>#NaN_3#</mathjax> is:</p> <p><mathjax>#2NaN_3(s)->2Na(s)+3N_2(g)#</mathjax></p> <p>Using dimensional analysis, we can find the number of mole of <mathjax>#N_2#</mathjax> gas formed:</p> <p><mathjax>#?molN_2(g)=2.5cancel(mol NaN_3)xx(3molN_2)/(2cancel(molNaN_3))=3.75molN_2#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/227229" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="227232" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/abdul-s-1"><img alt="" class="" src="https://lh6.googleusercontent.com/-W8XMY2yP-hM/AAAAAAAAAAI/AAAAAAAAABg/XwBa66Uif8k/photo.jpg?sz=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/abdul-s-1"> Abdul Sammad </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-02-16T19:44:03" itemprop="dateCreated"> Feb 16, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#5.8 mols#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>first multiply the mols with the mr <mathjax>#65*2.5=162.5#</mathjax> <br/> then use this to get the mols of <mathjax>#N_2#</mathjax> <br/> <mathjax>#mols=162.5/28#</mathjax><br/> <mathjax>#mols=5.8#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/227232" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-decomposition-reactions"> What are decomposition reactions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-examples-of-decomposition-reactions"> What are some examples of decomposition reactions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-a-decomposition-reaction-be-recognized"> How can a decomposition reaction be recognized? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-a-decomposition-reaction-differ-from-other-types-of-reactions"> How does a decomposition reaction differ from other types of reactions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-double-decomposition-reactions"> What are double decomposition reactions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-decomposition-reactions"> How can I balance decomposition reactions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-thermal-decomposition-reactions"> What are thermal decomposition reactions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/do-decomposition-reactions-require-energy"> Do decomposition reactions require energy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-mass-spectrometry-relate-to-decomposition"> How does mass spectrometry relate to decomposition? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/do-chlorates-decompose-when-heated"> Do chlorates decompose when heated? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/decomposition-reactions"> See all questions in Decomposition Reactions </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 6380 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many moles of #N_2# are formed by the decomposition of 2.5 moles of #NaN_3#?	null
2,202	a9a628f8-6ddd-11ea-a667-ccda262736ce	https://socratic.org/questions/what-is-the-mass-volume-percent-of-34-5g-nacl-in-165ml-solution	21%	start physical_unit 12 12 mass/volume_percent none qc_end physical_unit 8 8 6 7 mass qc_end physical_unit 12 12 10 11 volume qc_end end	[{"type":"physical unit","value":"mass/volume percent [OF] NaCl in solution"}]	[{"type":"physical unit","value":"21%"}]	[{"type":"physical unit","value":"Mass [OF] NaCl [=] \\pu{34.5 g}"},{"type":"physical unit","value":"Volume [OF] solution [=] \\pu{165 mL}"}]	<h1 class="questionTitle" itemprop="name">What is the mass/volume percent of 34.5g NaCl in 165mL solution?</h1>	null	21%	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#(34.5g)/(165mL)xx100%=21%"m"/"v"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We take the quotient...<mathjax>#"m"/"v"="Mass of solute"/"Volume of solution"xx100%#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#(34.5g)/(165mL)xx100%=21%"m"/"v"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the mass/volume percent of 34.5g NaCl in 165mL solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/percent-concentration" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Concentration</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="541444" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-01-26T08:39:39" itemprop="dateCreated"> Jan 26, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We take the quotient...<mathjax>#"m"/"v"="Mass of solute"/"Volume of solution"xx100%#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#(34.5g)/(165mL)xx100%=21%"m"/"v"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/541444" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-concentration-of-water-in-solution-be-decreased"> How can the concentration of water in solution be decreased? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-concentration-of-a-solution-be-increased"> How can the concentration of a solution be increased? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-concentration-of-a-solution-in-ppm"> How do you find the concentration of a solution in ppm? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-make-a-10-percent-solution"> How do you make a 10 percent solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-make-a-2-percent-solution"> How do you make a 2 percent solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-weight-per-volume-method-to-calculate-concentration"> What is the weight per volume method to calculate concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-percent-concentration-of-kcl-would-be-isotonic"> What percent concentration of KCl would be isotonic? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-of-sodium-chloride-in-normal-saline"> What is the percent concentration of sodium chloride in normal saline? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-of-a-6m-solution-of-nacl"> What is the percent concentration of a 6m solution of NaCl? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-formula"> What is the percent concentration formula? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/percent-concentration"> See all questions in Percent Concentration </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 6693 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the mass/volume percent of 34.5g NaCl in 165mL solution?	null
2,203	aaefeeb2-6ddd-11ea-a701-ccda262736ce	https://socratic.org/questions/593d4c457c014979352a398f	1.81 × 10^20	start physical_unit 20 20 number none qc_end physical_unit 6 6 2 3 volume qc_end physical_unit 14 14 9 10 molarity qc_end end	[{"type":"physical unit","value":"Number [OF] ions"}]	[{"type":"physical unit","value":"1.81 × 10^20"}]	[{"type":"physical unit","value":"Volume [OF] CaCl2(aq) solution [=] \\pu{1 mL}"},{"type":"physical unit","value":"Molarity [OF] CaCl2(aq) solution [=] \\pu{0.10 mol/L}"}]	<h1 class="questionTitle" itemprop="name">In a #1mL# volume of solution that is #0.10mol*L^-1# with respect to #CaCl_2(aq)#, what is the NUMBER of #"ions in solution?"#</h1>	null	1.81 × 10^20	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Now <mathjax>#"concentration"#</mathjax> is given by the quotient:</p> <p><mathjax>#"concentration"="Moles of solute"/"Volume of solution"#</mathjax></p> <p>And thus to get the <mathjax>#"moles of solute"#</mathjax> we takes the product </p> <p><mathjax>#"Volume of solution "xx" concentration"#</mathjax>.......</p> <p>And so here, </p> <p><mathjax>#"moles of calcium chloride"#</mathjax> <mathjax>#=#</mathjax> </p> <p><mathjax>#1mLxx10^-3LmL^-1xx0.10molL^-1=10^-4mol#</mathjax> </p> <p>WITH RESPECT TO THE SALT <mathjax>#CaCl_2#</mathjax>.</p> <p>Why did we emphasize <mathjax>#"the salt"#</mathjax>? Because EACH formula unit of <mathjax>#CaCl_2#</mathjax> contributes 3 ions to the solution, i.e.....</p> <p><mathjax>#CaCl_2(s)stackrel(H_2O)rarrCa^(2+) + 2Cl^-#</mathjax></p> <p>And so we have <mathjax>#3xx10^-4molxx6.022xx10^23*mol^-1=??#</mathjax> ions??</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>There are <mathjax>#3xx10^-4molxxN_A#</mathjax> ions in solution.......</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Now <mathjax>#"concentration"#</mathjax> is given by the quotient:</p> <p><mathjax>#"concentration"="Moles of solute"/"Volume of solution"#</mathjax></p> <p>And thus to get the <mathjax>#"moles of solute"#</mathjax> we takes the product </p> <p><mathjax>#"Volume of solution "xx" concentration"#</mathjax>.......</p> <p>And so here, </p> <p><mathjax>#"moles of calcium chloride"#</mathjax> <mathjax>#=#</mathjax> </p> <p><mathjax>#1mLxx10^-3LmL^-1xx0.10molL^-1=10^-4mol#</mathjax> </p> <p>WITH RESPECT TO THE SALT <mathjax>#CaCl_2#</mathjax>.</p> <p>Why did we emphasize <mathjax>#"the salt"#</mathjax>? Because EACH formula unit of <mathjax>#CaCl_2#</mathjax> contributes 3 ions to the solution, i.e.....</p> <p><mathjax>#CaCl_2(s)stackrel(H_2O)rarrCa^(2+) + 2Cl^-#</mathjax></p> <p>And so we have <mathjax>#3xx10^-4molxx6.022xx10^23mol^-1=??#</mathjax> ions??</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">In a #1mL# volume of solution that is #0.10molL^-1# with respect to #CaCl_2(aq)#, what is the NUMBER of #"ions in solution?"#</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="438053" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-11T14:08:23" itemprop="dateCreated"> Jun 11, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>There are <mathjax>#3xx10^-4molxxN_A#</mathjax> ions in solution.......</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Now <mathjax>#"concentration"#</mathjax> is given by the quotient:</p> <p><mathjax>#"concentration"="Moles of solute"/"Volume of solution"#</mathjax></p> <p>And thus to get the <mathjax>#"moles of solute"#</mathjax> we takes the product </p> <p><mathjax>#"Volume of solution "xx" concentration"#</mathjax>.......</p> <p>And so here, </p> <p><mathjax>#"moles of calcium chloride"#</mathjax> <mathjax>#=#</mathjax> </p> <p><mathjax>#1mLxx10^-3LmL^-1xx0.10molL^-1=10^-4mol#</mathjax> </p> <p>WITH RESPECT TO THE SALT <mathjax>#CaCl_2#</mathjax>.</p> <p>Why did we emphasize <mathjax>#"the salt"#</mathjax>? Because EACH formula unit of <mathjax>#CaCl_2#</mathjax> contributes 3 ions to the solution, i.e.....</p> <p><mathjax>#CaCl_2(s)stackrel(H_2O)rarrCa^(2+) + 2Cl^-#</mathjax></p> <p>And so we have <mathjax>#3xx10^-4molxx6.022xx10^23*mol^-1=??#</mathjax> ions??</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/438053" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1166 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	In a #1mL# volume of solution that is #0.10mol*L^-1# with respect to #CaCl_2(aq)#, what is the NUMBER of #"ions in solution?"#	null
2,204	a8d82118-6ddd-11ea-95ce-ccda262736ce	https://socratic.org/questions/you-have-2-5l-of-14m-salt-solution-how-many-grams-of-salt-would-be-needed-to-mak	20 grams	start physical_unit 7 7 mass g qc_end physical_unit 7 8 2 3 volume qc_end physical_unit 7 8 5 6 molarity qc_end end	[{"type":"physical unit","value":"Mass [OF] salt [IN] grams"}]	[{"type":"physical unit","value":"20 grams"}]	[{"type":"physical unit","value":"Volume [OF] salt solution [=] \\pu{2.5 L}"},{"type":"physical unit","value":"Molarity [OF] salt solution [=] \\pu{0.14 M}"}]	<h1 class="questionTitle" itemprop="name">You have 2.5L of .14M salt solution, how many grams of salt would be needed to make this solution?</h1>	null	20 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The thing to recognize here is that the <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></strong> of the solution tells you the number of moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> present in exactly <mathjax>#"1 L"#</mathjax> of this solution. </p> <p>In your case, the solution is said to have a molarity of <mathjax>#"0.14 M"#</mathjax>, which implies that every <mathjax>#"1 L"#</mathjax> of this solution contains <mathjax>#0.14#</mathjax> <strong>moles</strong> of salt, the solute. </p> <p>Now, in order to have <mathjax>#"2.5 L"#</mathjax> of <mathjax>#"0.14 M"#</mathjax> salt solution, you need the solution to contain</p> <blockquote> <p><mathjax>#2.5 color(red)(cancel(color(black)("L solution"))) * "0.14 moles salt"/(1color(red)(cancel(color(black)("L solution")))) = "0.35 moles salt"#</mathjax></p> </blockquote> <p>In order to find the number of grams needed to have <mathjax>#0.35#</mathjax> <strong>moles</strong> of salt, you need to use the compound's <strong>molar mass</strong>. Assuming that the salt is <em>table salt</em>, or sodium chloride, <mathjax>#"NaCl"#</mathjax>, you will have</p> <blockquote> <p><mathjax>#0.35 color(red)(cancel(color(black)("moles NaCl"))) * "58.4 g"/(1color(red)(cancel(color(black)("mole NaCl")))) = color(darkgreen)(ul(color(black)("20. g")))#</mathjax></p> </blockquote> <p>The answer must be rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for your values. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"20. g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The thing to recognize here is that the <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></strong> of the solution tells you the number of moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> present in exactly <mathjax>#"1 L"#</mathjax> of this solution. </p> <p>In your case, the solution is said to have a molarity of <mathjax>#"0.14 M"#</mathjax>, which implies that every <mathjax>#"1 L"#</mathjax> of this solution contains <mathjax>#0.14#</mathjax> <strong>moles</strong> of salt, the solute. </p> <p>Now, in order to have <mathjax>#"2.5 L"#</mathjax> of <mathjax>#"0.14 M"#</mathjax> salt solution, you need the solution to contain</p> <blockquote> <p><mathjax>#2.5 color(red)(cancel(color(black)("L solution"))) * "0.14 moles salt"/(1color(red)(cancel(color(black)("L solution")))) = "0.35 moles salt"#</mathjax></p> </blockquote> <p>In order to find the number of grams needed to have <mathjax>#0.35#</mathjax> <strong>moles</strong> of salt, you need to use the compound's <strong>molar mass</strong>. Assuming that the salt is <em>table salt</em>, or sodium chloride, <mathjax>#"NaCl"#</mathjax>, you will have</p> <blockquote> <p><mathjax>#0.35 color(red)(cancel(color(black)("moles NaCl"))) * "58.4 g"/(1color(red)(cancel(color(black)("mole NaCl")))) = color(darkgreen)(ul(color(black)("20. g")))#</mathjax></p> </blockquote> <p>The answer must be rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for your values. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">You have 2.5L of .14M salt solution, how many grams of salt would be needed to make this solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="568590" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-03-09T00:17:33" itemprop="dateCreated"> Mar 9, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"20. g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The thing to recognize here is that the <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></strong> of the solution tells you the number of moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> present in exactly <mathjax>#"1 L"#</mathjax> of this solution. </p> <p>In your case, the solution is said to have a molarity of <mathjax>#"0.14 M"#</mathjax>, which implies that every <mathjax>#"1 L"#</mathjax> of this solution contains <mathjax>#0.14#</mathjax> <strong>moles</strong> of salt, the solute. </p> <p>Now, in order to have <mathjax>#"2.5 L"#</mathjax> of <mathjax>#"0.14 M"#</mathjax> salt solution, you need the solution to contain</p> <blockquote> <p><mathjax>#2.5 color(red)(cancel(color(black)("L solution"))) * "0.14 moles salt"/(1color(red)(cancel(color(black)("L solution")))) = "0.35 moles salt"#</mathjax></p> </blockquote> <p>In order to find the number of grams needed to have <mathjax>#0.35#</mathjax> <strong>moles</strong> of salt, you need to use the compound's <strong>molar mass</strong>. Assuming that the salt is <em>table salt</em>, or sodium chloride, <mathjax>#"NaCl"#</mathjax>, you will have</p> <blockquote> <p><mathjax>#0.35 color(red)(cancel(color(black)("moles NaCl"))) * "58.4 g"/(1color(red)(cancel(color(black)("mole NaCl")))) = color(darkgreen)(ul(color(black)("20. g")))#</mathjax></p> </blockquote> <p>The answer must be rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for your values. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/568590" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-morality-be-used-as-a-conversion-factor"> How can molarity be used as a conversion factor? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-high-can-molarity-be"> How high can molarity be? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-molarity-change-with-temperature"> How does molarity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molarity-of-a-solution"> How do you find molarity of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-10-naoh"> What is the molarity of 10 NaOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-3-hydrogen-peroxide"> What is the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 5061 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	You have 2.5L of .14M salt solution, how many grams of salt would be needed to make this solution?	null
2,205	acf4e79e-6ddd-11ea-8c65-ccda262736ce	https://socratic.org/questions/how-many-grams-of-water-can-be-prepared-from-10-10-grams-of-hydrogen-gas-and-exc	90.9 grams	start physical_unit 4 4 mass g qc_end physical_unit 12 13 9 10 mass qc_end c_other OTHER qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Mass [OF] water [IN] grams"}]	[{"type":"physical unit","value":"90.9 grams"}]	[{"type":"physical unit","value":"Mass [OF] hydrogen gas [=] \\pu{10.10 grams}"},{"type":"other","value":"Excess oxygen gas."},{"type":"other","value":"At standard conditions."}]	<h1 class="questionTitle" itemprop="name">How many grams of water can be prepared from 10.10 grams of hydrogen gas and excess oxygen gas at standard conditions?</h1>	null	90.9 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First write a balanced chemical equation for the reaction :</p> <p><mathjax>#2H_2+O_2->2H_2O#</mathjax></p> <p>Since oxygen is in excess, it implies that hydrogen is the <a href="http://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a> and will decide how much product is formed, according to <a href="http://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio of the balanced equation.</p> <p><mathjax>#n_(H_2)=m/(M_r)=(10.10g)/(2g//mol)=5.05mol#</mathjax>.</p> <p><mathjax>#therefore moles of water formed will also be #</mathjax>5.05mol#.</p> <p><mathjax>#therefore m_(H_2O)=nxxM_r#</mathjax></p> <p><mathjax>#=5.05xx(2+16)#</mathjax></p> <p><mathjax>#=90.9g#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#90.9g#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First write a balanced chemical equation for the reaction :</p> <p><mathjax>#2H_2+O_2->2H_2O#</mathjax></p> <p>Since oxygen is in excess, it implies that hydrogen is the <a href="http://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a> and will decide how much product is formed, according to <a href="http://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio of the balanced equation.</p> <p><mathjax>#n_(H_2)=m/(M_r)=(10.10g)/(2g//mol)=5.05mol#</mathjax>.</p> <p><mathjax>#therefore moles of water formed will also be #</mathjax>5.05mol#.</p> <p><mathjax>#therefore m_(H_2O)=nxxM_r#</mathjax></p> <p><mathjax>#=5.05xx(2+16)#</mathjax></p> <p><mathjax>#=90.9g#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many grams of water can be prepared from 10.10 grams of hydrogen gas and excess oxygen gas at standard conditions?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="213542" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/trevor-r-1"><img alt="" class="" src="https://profilepictures.socratic.org/2Wf9lLD9RaSzPbXY0EW8_S5002678.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/trevor-r-1"> Trevor Ryan. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-17T20:28:30" itemprop="dateCreated"> Jan 17, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#90.9g#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First write a balanced chemical equation for the reaction :</p> <p><mathjax>#2H_2+O_2->2H_2O#</mathjax></p> <p>Since oxygen is in excess, it implies that hydrogen is the <a href="http://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a> and will decide how much product is formed, according to <a href="http://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio of the balanced equation.</p> <p><mathjax>#n_(H_2)=m/(M_r)=(10.10g)/(2g//mol)=5.05mol#</mathjax>.</p> <p><mathjax>#therefore moles of water formed will also be #</mathjax>5.05mol#.</p> <p><mathjax>#therefore m_(H_2O)=nxxM_r#</mathjax></p> <p><mathjax>#=5.05xx(2+16)#</mathjax></p> <p><mathjax>#=90.9g#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/213542" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What is stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ab82402bf342f48d93ac6"> Question #93ac6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-we-study-stoichiometry"> Why do we study stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-naoh-is-produced-from-1-20-x-102-grams-of-na2o-na2o-h2o-2-naoh"> How many grams of NaOH is produced from #1.20 x 10^2# grams of #Na_2O#? #Na_2O + H_2O -> 2NaOH# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-na2o-are-required-to-produce-1-60-x-102-grams-of-naoh-na2o-h2o"> How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? Na2O + H2O ---> 2 NaOH </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-mass-of-iron-is-needed-to-react-with-16-0-grams-of-sulfur-8-fe-s8-8-fes"> What mass of iron is needed to react with 16.0 grams of sulfur? 8 Fe + S8 ---> 8 FeS </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/according-to-8-fe-s8-8-fes-how-many-grams-of-fes-are-produced"> According to 8 Fe + S8 ---> 8 FeS How many grams of FeS are produced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/12-00-moles-of-naclo3-will-produce-how-many-grams-of-o2-2-naclo3-2-nacl-3-o2"> 12.00 moles of NaClO3 will produce how many grams of O2? 2 NaClO3 ---> 2 NaCl + 3 O2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-nacl-are-produced-when-80-0-grams-of-o2-are-produced-2-naclo3-"> How many grams of NaCl are produced when 80.0 grams of O2 are produced? 2 NaClO3 ---> 2 NaCl + 3 O2 </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/stoichiometry"> See all questions in Stoichiometry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 6472 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many grams of water can be prepared from 10.10 grams of hydrogen gas and excess oxygen gas at standard conditions?	null
2,206	a8c8b530-6ddd-11ea-a282-ccda262736ce	https://socratic.org/questions/the-pressure-of-250-kpa-acting-on-15-cubic-meters-of-gas-at-a-temperature-of-100	400 K	start physical_unit 37 38 temperature k qc_end physical_unit 37 38 7 9 volume qc_end physical_unit 37 38 16 17 temperature qc_end physical_unit 37 38 29 31 volume qc_end physical_unit 37 38 21 22 pressure qc_end end	[{"type":"physical unit","value":"Temperature2 [OF] the gas [IN] K"}]	[{"type":"physical unit","value":"400 K"}]	[{"type":"physical unit","value":"Pressure1 [OF] the gas [=] \\pu{V}"},{"type":"physical unit","value":"Volume1 [OF] the gas [=] \\pu{15 cubic meters}"},{"type":"physical unit","value":"Temperature1 [OF] the gas [=] \\pu{100 K}"},{"type":"physical unit","value":"Volume2 [OF] the gas [=] \\pu{30 cubic meters}"},{"type":"physical unit","value":"Pressure2 [OF] the gas [=] \\pu{500 kPa}"}]	<h1 class="questionTitle" itemprop="name">The pressure of 250 kPa acting on 15 cubic meters of gas at a temperature of 100 K is increased to 500 kPa and the volume is increased to 30 cubic meters. What is the temperature of the gas at this new pressure and volume?</h1>	null	400 K	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is an example of the <a href="http://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">combined gas law</a>. The equation to use is <mathjax>#(P_1V_1)/(T_1)=(P_2V_2)/(T_2)#</mathjax>.</p> <p><strong>Given</strong><br/> Initial pressure, <mathjax>#P_1="250 kPa"#</mathjax><br/> Initial volume, <mathjax>#V_1="15 m"^3"#</mathjax><br/> Initial temperature, <mathjax>#T_1="100 K"#</mathjax><br/> Final pressure, <mathjax>#P_2="500 kPa"#</mathjax><br/> Final volume, <mathjax>#V_2="30 m"^3"#</mathjax></p> <p><strong>Unknown</strong><br/> Final temperature, <mathjax>#T_2#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#T_2#</mathjax>. Substitute the given values into the equation and solve.</p> <p><mathjax>#(P_1V_1)/(T_1)=(P_2V_2)/(T_2)#</mathjax></p> <p><mathjax>#T_2=(T_1P_2V_2)/(P_1V_1)#</mathjax></p> <p><mathjax>#T_2=(100"K"·500cancel"kPa"·30cancel"m"^3)/(250cancel"kPa"·15cancel"m"^3)="400K"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The final temperature will be 400 K.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is an example of the <a href="http://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">combined gas law</a>. The equation to use is <mathjax>#(P_1V_1)/(T_1)=(P_2V_2)/(T_2)#</mathjax>.</p> <p><strong>Given</strong><br/> Initial pressure, <mathjax>#P_1="250 kPa"#</mathjax><br/> Initial volume, <mathjax>#V_1="15 m"^3"#</mathjax><br/> Initial temperature, <mathjax>#T_1="100 K"#</mathjax><br/> Final pressure, <mathjax>#P_2="500 kPa"#</mathjax><br/> Final volume, <mathjax>#V_2="30 m"^3"#</mathjax></p> <p><strong>Unknown</strong><br/> Final temperature, <mathjax>#T_2#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#T_2#</mathjax>. Substitute the given values into the equation and solve.</p> <p><mathjax>#(P_1V_1)/(T_1)=(P_2V_2)/(T_2)#</mathjax></p> <p><mathjax>#T_2=(T_1P_2V_2)/(P_1V_1)#</mathjax></p> <p><mathjax>#T_2=(100"K"·500cancel"kPa"·30cancel"m"^3)/(250cancel"kPa"·15cancel"m"^3)="400K"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">The pressure of 250 kPa acting on 15 cubic meters of gas at a temperature of 100 K is increased to 500 kPa and the volume is increased to 30 cubic meters. What is the temperature of the gas at this new pressure and volume?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/combined-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Combined Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="238123" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-11T08:56:55" itemprop="dateCreated"> Mar 11, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The final temperature will be 400 K.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is an example of the <a href="http://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">combined gas law</a>. The equation to use is <mathjax>#(P_1V_1)/(T_1)=(P_2V_2)/(T_2)#</mathjax>.</p> <p><strong>Given</strong><br/> Initial pressure, <mathjax>#P_1="250 kPa"#</mathjax><br/> Initial volume, <mathjax>#V_1="15 m"^3"#</mathjax><br/> Initial temperature, <mathjax>#T_1="100 K"#</mathjax><br/> Final pressure, <mathjax>#P_2="500 kPa"#</mathjax><br/> Final volume, <mathjax>#V_2="30 m"^3"#</mathjax></p> <p><strong>Unknown</strong><br/> Final temperature, <mathjax>#T_2#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#T_2#</mathjax>. Substitute the given values into the equation and solve.</p> <p><mathjax>#(P_1V_1)/(T_1)=(P_2V_2)/(T_2)#</mathjax></p> <p><mathjax>#T_2=(T_1P_2V_2)/(P_1V_1)#</mathjax></p> <p><mathjax>#T_2=(100"K"·500cancel"kPa"·30cancel"m"^3)/(250cancel"kPa"·15cancel"m"^3)="400K"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/238123" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5345df5f02bf345f71b1c8e8"> Question #1c8e8 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ac3df02bf342f4c3bfabb"> Question #bfabb </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-you-want-to-solve-for-the-volume-of-a-gas-v2-and-p1-is-greater-than-p2-would-"> If you want to solve for the volume of a gas (V2) and P1 is greater than P2, would you expect V2... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-modern-refrigerator-take-advantage-of-the-gas-laws-to-remove-heat-f"> How does the modern refrigerator take advantage of the gas laws to remove heat from a system? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-certain-sample-of-gas-has-a-volume-of-0-452-l-measured-at-87-c-and-0-620-atm-w"> A certain sample of gas has a volume of 0.452 L measured at 87°C and 0.620 atm. What is its... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/which-situations-does-the-combined-gas-law-enable-you-to-do-calculations-when-th"> Which situations does the combined gas law enable you to do calculations when the other gas laws... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-small-research-submarine-with-a-volume-of-1-2x10-5-l-has-an-internal-pressure-"> A small research submarine with a volume of 1.2x10 ^5 L has an internal pressure of 1.0 atm and... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-the-combined-gas-law-different-from-boyle-s-law"> How is the combined gas law different from boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-pressure-of-an-combined-gas-change-as-temperature-increases"> How does the pressure of an combined gas change as temperature increases? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-ideal-gas-law-differ-from-the-combined-gas-law-1"> How does the ideal gas law differ from the combined gas law? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/combined-gas-law"> See all questions in Combined Gas Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 8146 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	The pressure of 250 kPa acting on 15 cubic meters of gas at a temperature of 100 K is increased to 500 kPa and the volume is increased to 30 cubic meters. What is the temperature of the gas at this new pressure and volume?	null
2,207	a8f5cd0c-6ddd-11ea-88f4-ccda262736ce	https://socratic.org/questions/what-is-the-ph-of-pure-water-at-25-0-c-if-the-kw-at-this-temperature-is-1-0-x-10	7.00	start physical_unit 5 6 ph none qc_end physical_unit 5 6 8 9 temperature qc_end physical_unit 5 6 17 19 kw qc_end end	[{"type":"physical unit","value":"pH [OF] pure water"}]	[{"type":"physical unit","value":"7.00"}]	[{"type":"physical unit","value":"Temperature [OF] pure water [=] \\pu{25.0 ℃}"},{"type":"physical unit","value":"Kw [OF] pure water [=] \\pu{1.0 × 10^(-14)}"}]	<h1 class="questionTitle" itemprop="name">What is the pH of pure water at 25.0 °C if the Kw at this temperature is #1.0 x 10-^14#?</h1>	null	7.00	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Note: It's generally pretty well known that the <mathjax>#pH#</mathjax> of pure water at <mathjax>#"25 ºC"#</mathjax> is <mathjax>#7#</mathjax>, but here's what we'd do to get to find that <mathjax>#pH#</mathjax> if we didn't know this:</p> <p>To find <mathjax>#pH#</mathjax>, we'll need to use two formulas:</p> <ol> <li><mathjax>#K_w = [H^+]xx[OH^-]#</mathjax></li> <li><mathjax>#pH = -log[H^+]#</mathjax></li> </ol> <p>First, we need to find the concentration of <mathjax>#H^+#</mathjax> ions in water at this temperature. </p> <p>We know that pure water is neutral, and that in neutral <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a>, the concentration of <mathjax>#H^+#</mathjax> equals the concentration of <mathjax>#OH^-#</mathjax>. </p> <p>So, effectively:</p> <p><mathjax>#K_w = [H^+]xx[OH^-]#</mathjax><br/> <mathjax>#K_w = [H^+]xx[H^+]#</mathjax> because <mathjax>#[H^+] = [OH^-]#</mathjax> in neutral solution</p> <p>To find the concentration of <mathjax>#H^+#</mathjax> ions now, we'll just need to square root <mathjax>#K_w#</mathjax>. The question tells us that <mathjax>#K_w = 1.0 xx 10^(-14)#</mathjax>, so:</p> <p><mathjax>#1.0 xx 10^(-14) = [H^+]xx[H^+]#</mathjax></p> <p><mathjax>#[H^+] = sqrt(1.0 xx 10^(-14)) = 1.0 xx 10^(-7) M#</mathjax></p> <p>Now, we can just use our second equation to calculate the <mathjax>#pH#</mathjax>: </p> <p><mathjax>#pH = -log[H^+]#</mathjax><br/> <mathjax>#pH = -log(1.0 xx 10^(-7) M) = 7.00#</mathjax></p> <p>(The number of decimal places in our <mathjax>#pH#</mathjax> value needs to be the same as the number of <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a> in our <mathjax>#[H^+]#</mathjax> value.)</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#pH = 7.00#</mathjax>. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Note: It's generally pretty well known that the <mathjax>#pH#</mathjax> of pure water at <mathjax>#"25 ºC"#</mathjax> is <mathjax>#7#</mathjax>, but here's what we'd do to get to find that <mathjax>#pH#</mathjax> if we didn't know this:</p> <p>To find <mathjax>#pH#</mathjax>, we'll need to use two formulas:</p> <ol> <li><mathjax>#K_w = [H^+]xx[OH^-]#</mathjax></li> <li><mathjax>#pH = -log[H^+]#</mathjax></li> </ol> <p>First, we need to find the concentration of <mathjax>#H^+#</mathjax> ions in water at this temperature. </p> <p>We know that pure water is neutral, and that in neutral <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a>, the concentration of <mathjax>#H^+#</mathjax> equals the concentration of <mathjax>#OH^-#</mathjax>. </p> <p>So, effectively:</p> <p><mathjax>#K_w = [H^+]xx[OH^-]#</mathjax><br/> <mathjax>#K_w = [H^+]xx[H^+]#</mathjax> because <mathjax>#[H^+] = [OH^-]#</mathjax> in neutral solution</p> <p>To find the concentration of <mathjax>#H^+#</mathjax> ions now, we'll just need to square root <mathjax>#K_w#</mathjax>. The question tells us that <mathjax>#K_w = 1.0 xx 10^(-14)#</mathjax>, so:</p> <p><mathjax>#1.0 xx 10^(-14) = [H^+]xx[H^+]#</mathjax></p> <p><mathjax>#[H^+] = sqrt(1.0 xx 10^(-14)) = 1.0 xx 10^(-7) M#</mathjax></p> <p>Now, we can just use our second equation to calculate the <mathjax>#pH#</mathjax>: </p> <p><mathjax>#pH = -log[H^+]#</mathjax><br/> <mathjax>#pH = -log(1.0 xx 10^(-7) M) = 7.00#</mathjax></p> <p>(The number of decimal places in our <mathjax>#pH#</mathjax> value needs to be the same as the number of <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a> in our <mathjax>#[H^+]#</mathjax> value.)</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the pH of pure water at 25.0 °C if the Kw at this temperature is #1.0 x 10-^14#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/ph-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">pH calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="627658" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/z-15"><img alt="" class="" src="https://profilepictures.socratic.org/2RYTfnQ27oIM5G69ZmQg_chrome.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/z-15"> zhirou </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-06-09T06:23:02" itemprop="dateCreated"> Jun 9, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#pH = 7.00#</mathjax>. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Note: It's generally pretty well known that the <mathjax>#pH#</mathjax> of pure water at <mathjax>#"25 ºC"#</mathjax> is <mathjax>#7#</mathjax>, but here's what we'd do to get to find that <mathjax>#pH#</mathjax> if we didn't know this:</p> <p>To find <mathjax>#pH#</mathjax>, we'll need to use two formulas:</p> <ol> <li><mathjax>#K_w = [H^+]xx[OH^-]#</mathjax></li> <li><mathjax>#pH = -log[H^+]#</mathjax></li> </ol> <p>First, we need to find the concentration of <mathjax>#H^+#</mathjax> ions in water at this temperature. </p> <p>We know that pure water is neutral, and that in neutral <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a>, the concentration of <mathjax>#H^+#</mathjax> equals the concentration of <mathjax>#OH^-#</mathjax>. </p> <p>So, effectively:</p> <p><mathjax>#K_w = [H^+]xx[OH^-]#</mathjax><br/> <mathjax>#K_w = [H^+]xx[H^+]#</mathjax> because <mathjax>#[H^+] = [OH^-]#</mathjax> in neutral solution</p> <p>To find the concentration of <mathjax>#H^+#</mathjax> ions now, we'll just need to square root <mathjax>#K_w#</mathjax>. The question tells us that <mathjax>#K_w = 1.0 xx 10^(-14)#</mathjax>, so:</p> <p><mathjax>#1.0 xx 10^(-14) = [H^+]xx[H^+]#</mathjax></p> <p><mathjax>#[H^+] = sqrt(1.0 xx 10^(-14)) = 1.0 xx 10^(-7) M#</mathjax></p> <p>Now, we can just use our second equation to calculate the <mathjax>#pH#</mathjax>: </p> <p><mathjax>#pH = -log[H^+]#</mathjax><br/> <mathjax>#pH = -log(1.0 xx 10^(-7) M) = 7.00#</mathjax></p> <p>(The number of decimal places in our <mathjax>#pH#</mathjax> value needs to be the same as the number of <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a> in our <mathjax>#[H^+]#</mathjax> value.)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/627658" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-of-a-solution"> How do you determine ph of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-at-an-equivalence-point"> How do you determine pH at an equivalence point? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-molarity"> How do you determine pH from molarity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-alkalinity-mean"> What does alkalinity mean? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-base"> What is a base? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-acid-base-indicators-change-color"> How do acid base indicators change color? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-neutral-ph"> What is a neutral pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-alkalinity-affect-pool-water"> How does alkalinity affect pool water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ph-important-in-drinking-water"> Why is pH important in drinking water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-ph-of-solution"> How can I calculate the pH of a solution? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/ph-calculations"> See all questions in pH calculations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 94138 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the pH of pure water at 25.0 °C if the Kw at this temperature is #1.0 x 10-^14#?	null
2,208	a874718c-6ddd-11ea-b7c0-ccda262736ce	https://socratic.org/questions/58188a9e7c0149405b653047	8.39 g	start physical_unit 5 5 mass g qc_end c_other NTP qc_end physical_unit 13 13 10 11 volume qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Mass [OF] water [IN] g"}]	[{"type":"physical unit","value":"8.39 g"}]	[{"type":"other","value":"NTP"},{"type":"physical unit","value":"Volume [OF] gas [=] \\pu{16.8 L}"},{"type":"other","value":"On electrolysis."}]	<h1 class="questionTitle" itemprop="name">What is the mass of water that on electrolysis gives 16.8 L of gas at NTP?</h1>	null	8.39 g	<div class="answerDescription"> <div> <div class="markdown"><p>On <a href="https://socratic.org/chemistry/electrochemistry/electrolysis">electrolysis</a> of water the net reaction occurred is represented by the following balanced equation</p> <p><mathjax>#2H_2O(l)->2H_2(g)+O_2(g)#</mathjax></p> <p><mathjax>#H_2 and O_2#</mathjax> are are produced in 2:1 mol ratio.So the volumetric ratio under same conditions of temperature and prssure will also be 2:1.</p> <p>Here total volume of electrolytic gas is 16.8L at NTP. So the volume of <mathjax>#H_2#</mathjax> gas produced is <mathjax>#2/3xx16.8L=11.2L#</mathjax> at NTP.</p> <p>The above equation suggests that 2mol or <mathjax>#2xx22.4L" "H_2#</mathjax> gas is produced from 2moles or 36g water.</p> <p>So 11.2L <mathjax>#H_2#</mathjax> at NTP will be produced from <mathjax>#(36g)/(2xx22.4L)xx11.2L#</mathjax></p> <p><mathjax>#=9g" "H_2O#</mathjax> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerDescription"> <div> <div class="markdown"><p>On <a href="https://socratic.org/chemistry/electrochemistry/electrolysis">electrolysis</a> of water the net reaction occurred is represented by the following balanced equation</p> <p><mathjax>#2H_2O(l)->2H_2(g)+O_2(g)#</mathjax></p> <p><mathjax>#H_2 and O_2#</mathjax> are are produced in 2:1 mol ratio.So the volumetric ratio under same conditions of temperature and prssure will also be 2:1.</p> <p>Here total volume of electrolytic gas is 16.8L at NTP. So the volume of <mathjax>#H_2#</mathjax> gas produced is <mathjax>#2/3xx16.8L=11.2L#</mathjax> at NTP.</p> <p>The above equation suggests that 2mol or <mathjax>#2xx22.4L" "H_2#</mathjax> gas is produced from 2moles or 36g water.</p> <p>So 11.2L <mathjax>#H_2#</mathjax> at NTP will be produced from <mathjax>#(36g)/(2xx22.4L)xx11.2L#</mathjax></p> <p><mathjax>#=9g" "H_2O#</mathjax> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the mass of water that on electrolysis gives 16.8 L of gas at NTP?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#electrochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Electrochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/electrochemistry/electrolysis" itemprop="url"> <span class="breadcrumb" itemprop="title">Electrolysis</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="329728" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/dk-ch"><img alt="" class="" src="https://profilepictures.socratic.org/0aBlt69MSiWhfD1SEqb8_lotus.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/dk-ch"> P dilip_k </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-11-01T16:15:14" itemprop="dateCreated"> Nov 1, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerDescription"> <div> <div class="markdown"><p>On <a href="https://socratic.org/chemistry/electrochemistry/electrolysis">electrolysis</a> of water the net reaction occurred is represented by the following balanced equation</p> <p><mathjax>#2H_2O(l)->2H_2(g)+O_2(g)#</mathjax></p> <p><mathjax>#H_2 and O_2#</mathjax> are are produced in 2:1 mol ratio.So the volumetric ratio under same conditions of temperature and prssure will also be 2:1.</p> <p>Here total volume of electrolytic gas is 16.8L at NTP. So the volume of <mathjax>#H_2#</mathjax> gas produced is <mathjax>#2/3xx16.8L=11.2L#</mathjax> at NTP.</p> <p>The above equation suggests that 2mol or <mathjax>#2xx22.4L" "H_2#</mathjax> gas is produced from 2moles or 36g water.</p> <p>So 11.2L <mathjax>#H_2#</mathjax> at NTP will be produced from <mathjax>#(36g)/(2xx22.4L)xx11.2L#</mathjax></p> <p><mathjax>#=9g" "H_2O#</mathjax> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/329728" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="329786" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-11-01T17:32:43" itemprop="dateCreated"> Nov 1, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The mass of the electrolyzed water is 8.39 g.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The balanced equation is</p> <p><mathjax>#"2H"_2"O(l)" → "2H"_2"(g)" + "O"_2"(g)"#</mathjax></p> <blockquote></blockquote> <p>We can use the <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a></strong> to calculate the number of moles of gas at NTP (20 °C and 1 atm).</p> <blockquote> <blockquote> <p><mathjax>#PV = nRT#</mathjax></p> </blockquote> </blockquote> <p><mathjax>#T = "(20 + 273.15) K" = "293.15 K"#</mathjax></p> <p><mathjax>#n = (PV)/(RT) = (1 color(red)(cancel(color(black)("atm"))) × 16.8 color(red)(cancel(color(black)("L"))))/("0.082 06" color(red)(cancel(color(black)("L·atm·K"^"-1")))"mol"^"-1" × 293.15 color(red)(cancel(color(black)("K")))) = "0.6984 mol"#</mathjax></p> <blockquote></blockquote> <p>According to the balanced equation, ⅓ of the moles are oxygen and ⅔ of the moles are hydrogen.</p> <p>∴ <mathjax>#"Moles of O"_2 = 1/3 × "0.6984 mol" = "0.2328 mol"#</mathjax></p> <p><mathjax>#"Mass of water" = 0.2328 color(red)(cancel(color(black)("mol O"_2))) × (2 color(red)(cancel(color(black)("mol H"_2"O"))))/(1 color(red)(cancel(color(black)("mol O"_2)))) × ("18.02 g H"_2"O")/(1 color(red)(cancel(color(black)("mol O"_2)))) = "8.39 g H"_2"O"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/329786" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-electrolysis-be-used-to-produce-chlorine"> How can electrolysis be used to produce chlorine? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-electrolysis-be-used-to-purify-copper"> How can electrolysis be used to purify copper? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-dpes-electrolysis-separate-hydrogen-and-oxygen"> How does electrolysis separate hydrogen and oxygen? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-electrolysis-used-to-extract-aluminium"> How is electrolysis used to extract aluminium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/two-cells-one-containing-agno3-and-the-other-sncl2-are-connected-in-series-and-a"> Two cells, one containing AgNO3 and the other SnCl2, are connected in series and a given... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-electrochemical-cells-relate-to-electrolysis"> How do electrochemical cells relate to electrolysis? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-happens-on-the-cathode-during-the-electrolysis-of-a-copper-ii-sulfate-solut"> What happens on the cathode during the electrolysis of a copper(II) sulfate solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-extract-sodium-and-chloride-from-salt"> How can I extract sodium and chloride from salt? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-delta-g-negative-for-electrolysis-reactions"> Why is #Delta G# negative for electrolysis reactions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-covalent-compounds-be-split-by-electrolysis"> Can covalent compounds be split by electrolysis? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/electrochemistry/electrolysis"> See all questions in Electrolysis </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 7160 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the mass of water that on electrolysis gives 16.8 L of gas at NTP?	null
2,209	aabb35ec-6ddd-11ea-99cc-ccda262736ce	https://socratic.org/questions/56538a9211ef6b6813def648	23.60 moles	start physical_unit 4 5 mole mol qc_end physical_unit 12 13 9 10 mole qc_end substance 16 17 qc_end end	[{"type":"physical unit","value":"Mole [OF] hydrogen fluoride [IN] moles"}]	[{"type":"physical unit","value":"23.60 moles"}]	[{"type":"physical unit","value":"Mole [OF] silicon dioxide [=] \\pu{5.90 moles}"},{"type":"substance name","value":"Silicon tetrafluoride"}]	<h1 class="questionTitle" itemprop="name">How many moles of hydrogen fluoride will react with #5.90# moles of silicon dioxide to produce silicon tetrafluoride? </h1>	null	23.60 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The key to this problem is the <strong>balanced</strong> chemical equation for this reaction. </p> <p><em>Hydrogen fluoride</em>, <mathjax>#"HF"#</mathjax>, will react with <em>silicon dioxide</em>, <mathjax>#"SiO"_2#</mathjax>, to produce <em>silicon tetrachloride</em>, <mathjax>#"SiF"_4#</mathjax>, and liquid water according to the following chemical equation</p> <blockquote> <p><mathjax>#color(red)(4)"HF"_text((g]) + "SiO"_text(2(s]) -> "SiF"_text(4(g]) + 2"H"_2"O"_text((l])#</mathjax></p> </blockquote> <p>Notice that you have a <mathjax>#color(red)(4):1#</mathjax> <a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> between hydrogen fluoride and silicon dioxide. </p> <p>This tells you that <strong>regardless</strong> of how many moles of silicon dioxide take part in the reaction, the reaction will <strong>always</strong> consume <mathjax>#color(red)(4)#</mathjax> <strong>times more moles</strong> of hydrogen fluoride. </p> <p>In your case, you need to know how many moles of hydrogen fluoride will be needed to react <strong>completely</strong> with <mathjax>#5.90#</mathjax> moles of silicon dioxide. </p> <p>To <em>react completely</em> simply means that all the moles of silicon dioxide must be consumed in the reaction. </p> <p>So, use the aforementioned mole ratio to get</p> <blockquote> <p><mathjax>#5.90color(red)(cancel(color(black)("moles SiO"_2))) * (color(red)(4)" moles HF")/(1color(red)(cancel(color(black)("mole SiO"_2)))) = color(green)("23.6 moles HF")#</mathjax></p> </blockquote> <p> <iframe src="https://www.youtube.com/embed/S6UQX7ZdkTg?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"23.6 moles HF"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The key to this problem is the <strong>balanced</strong> chemical equation for this reaction. </p> <p><em>Hydrogen fluoride</em>, <mathjax>#"HF"#</mathjax>, will react with <em>silicon dioxide</em>, <mathjax>#"SiO"_2#</mathjax>, to produce <em>silicon tetrachloride</em>, <mathjax>#"SiF"_4#</mathjax>, and liquid water according to the following chemical equation</p> <blockquote> <p><mathjax>#color(red)(4)"HF"_text((g]) + "SiO"_text(2(s]) -> "SiF"_text(4(g]) + 2"H"_2"O"_text((l])#</mathjax></p> </blockquote> <p>Notice that you have a <mathjax>#color(red)(4):1#</mathjax> <a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> between hydrogen fluoride and silicon dioxide. </p> <p>This tells you that <strong>regardless</strong> of how many moles of silicon dioxide take part in the reaction, the reaction will <strong>always</strong> consume <mathjax>#color(red)(4)#</mathjax> <strong>times more moles</strong> of hydrogen fluoride. </p> <p>In your case, you need to know how many moles of hydrogen fluoride will be needed to react <strong>completely</strong> with <mathjax>#5.90#</mathjax> moles of silicon dioxide. </p> <p>To <em>react completely</em> simply means that all the moles of silicon dioxide must be consumed in the reaction. </p> <p>So, use the aforementioned mole ratio to get</p> <blockquote> <p><mathjax>#5.90color(red)(cancel(color(black)("moles SiO"_2))) * (color(red)(4)" moles HF")/(1color(red)(cancel(color(black)("mole SiO"_2)))) = color(green)("23.6 moles HF")#</mathjax></p> </blockquote> <p> <iframe src="https://www.youtube.com/embed/S6UQX7ZdkTg?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles of hydrogen fluoride will react with #5.90# moles of silicon dioxide to produce silicon tetrafluoride? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/mole-ratios" itemprop="url"> <span class="breadcrumb" itemprop="title">Mole Ratios</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="192579" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-24T12:47:28" itemprop="dateCreated"> Nov 24, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"23.6 moles HF"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The key to this problem is the <strong>balanced</strong> chemical equation for this reaction. </p> <p><em>Hydrogen fluoride</em>, <mathjax>#"HF"#</mathjax>, will react with <em>silicon dioxide</em>, <mathjax>#"SiO"_2#</mathjax>, to produce <em>silicon tetrachloride</em>, <mathjax>#"SiF"_4#</mathjax>, and liquid water according to the following chemical equation</p> <blockquote> <p><mathjax>#color(red)(4)"HF"_text((g]) + "SiO"_text(2(s]) -> "SiF"_text(4(g]) + 2"H"_2"O"_text((l])#</mathjax></p> </blockquote> <p>Notice that you have a <mathjax>#color(red)(4):1#</mathjax> <a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> between hydrogen fluoride and silicon dioxide. </p> <p>This tells you that <strong>regardless</strong> of how many moles of silicon dioxide take part in the reaction, the reaction will <strong>always</strong> consume <mathjax>#color(red)(4)#</mathjax> <strong>times more moles</strong> of hydrogen fluoride. </p> <p>In your case, you need to know how many moles of hydrogen fluoride will be needed to react <strong>completely</strong> with <mathjax>#5.90#</mathjax> moles of silicon dioxide. </p> <p>To <em>react completely</em> simply means that all the moles of silicon dioxide must be consumed in the reaction. </p> <p>So, use the aforementioned mole ratio to get</p> <blockquote> <p><mathjax>#5.90color(red)(cancel(color(black)("moles SiO"_2))) * (color(red)(4)" moles HF")/(1color(red)(cancel(color(black)("mole SiO"_2)))) = color(green)("23.6 moles HF")#</mathjax></p> </blockquote> <p> <iframe src="https://www.youtube.com/embed/S6UQX7ZdkTg?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/192579" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4178e02bf3469517a106e"> Question #a106e </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4178e02bf3469570e2e86"> Question #e2e86 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179102bf3469517a1072"> Question #a1072 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179402bf34694c8c5bf1"> Question #c5bf1 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179702bf3469588dc373"> Question #dc373 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179c02bf34694c8c5bf9"> Question #c5bf9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417a302bf3469517a1076"> Question #a1076 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417c702bf3469588dc377"> Question #dc377 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417d002bf346963eb984f"> Question #b984f </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417d402bf346950519ea3"> Question #19ea3 </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/mole-ratios"> See all questions in Mole Ratios </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 5767 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many moles of hydrogen fluoride will react with #5.90# moles of silicon dioxide to produce silicon tetrafluoride?	null
2,210	aa20fc8a-6ddd-11ea-bcee-ccda262736ce	https://socratic.org/questions/593016a711ef6b1eee79e983	16.67 mL	start physical_unit 4 4 volume ml qc_end physical_unit 4 4 14 15 volume qc_end physical_unit 9 9 18 19 molarity qc_end physical_unit 9 9 7 8 molarity qc_end end	[{"type":"physical unit","value":"Volume1 [OF] HCl solution [IN] mL"}]	[{"type":"physical unit","value":"16.67 mL"}]	[{"type":"physical unit","value":"Volume2 [OF] HCl solution [=] \\pu{1.00 L}"},{"type":"physical unit","value":"Molarity2 [OF] HCl solution [=] \\pu{0.10 mol/L}"},{"type":"physical unit","value":"Molarity1 [OF] HCl solution [=] \\pu{6.0 mol/L}"}]	<h1 class="questionTitle" itemprop="name">What volume of a solution that is #6.0molL^-1# #HCl# is required to make #1.00L# of a #0.10mol*L^-1# solution?</h1>	null	16.67 mL	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We use the old relationship, <mathjax>#C_1V_1=C_2V_2#</mathjax>. The product in each side gives units of <mathjax>#"moles"#</mathjax>.</p> <p>And so <mathjax>#6.0molL^-1xxV_1=1.000Lxx0.1molL^-1#</mathjax></p> <p>and thus..............................</p> <p><mathjax>#V_1=(1.000Lxx0.1molL^-1)/(6.0molL^-1)=0.0167L=16.7mL.#</mathjax></p> <p>Do you add the water to the acid, or the acid to water? (I am not taking the p, the order of addition is important!)</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We need under <mathjax>#20mL#</mathjax> of stock solution. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We use the old relationship, <mathjax>#C_1V_1=C_2V_2#</mathjax>. The product in each side gives units of <mathjax>#"moles"#</mathjax>.</p> <p>And so <mathjax>#6.0molL^-1xxV_1=1.000Lxx0.1molL^-1#</mathjax></p> <p>and thus..............................</p> <p><mathjax>#V_1=(1.000Lxx0.1molL^-1)/(6.0molL^-1)=0.0167L=16.7*mL.#</mathjax></p> <p>Do you add the water to the acid, or the acid to water? (I am not taking the p, the order of addition is important!)</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What volume of a solution that is #6.0molL^-1# #HCl# is required to make #1.00L# of a #0.10molL^-1# solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/dilution-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">Dilution Calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="433095" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-01T14:20:33" itemprop="dateCreated"> Jun 1, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We need under <mathjax>#20mL#</mathjax> of stock solution. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We use the old relationship, <mathjax>#C_1V_1=C_2V_2#</mathjax>. The product in each side gives units of <mathjax>#"moles"#</mathjax>.</p> <p>And so <mathjax>#6.0molL^-1xxV_1=1.000Lxx0.1molL^-1#</mathjax></p> <p>and thus..............................</p> <p><mathjax>#V_1=(1.000Lxx0.1molL^-1)/(6.0molL^-1)=0.0167L=16.7mL.#</mathjax></p> <p>Do you add the water to the acid, or the acid to water? (I am not taking the p, the order of addition is important!)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/433095" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-concentration-from-absorbance"> How do you calculate concentration from absorbance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-concentration-from-titration"> How do you calculate concentration from titration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-dilution-factor"> How do you calculate dilution factor? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-do-serial-dilution-calculations"> How do you calculate serial dilutions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-calculate-concentration-of-solution-when-its-diluted"> How to calculate concentration of solution when it's diluted? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-examples-of-dilution-calculations"> What are some examples of dilution calculations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-would-be-the-concentration-of-a-solution-made-by-adding-250-ml-of-water-to-"> What would be the concentration of a solution made by adding 250 mL of water to 45.0 mL of 4.2 M KOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-would-be-the-concentration-of-a-solution-made-by-diluting-45-0-ml-of-4-2-m-"> What would be the concentration of a solution made by diluting 45.0 mL of 4.2 M KOH to 250 mL? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-a-solution-that-is-made-by-diluting-50-00-ml-of-a-4-74-m"> What is the molarity of a solution that is made by diluting 50.00 mL of a 4.74 M solution of HCl... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-volume-of-water-would-you-add-to-15-00-ml-of-a-6-77-m-solution-of-nitric-ac"> What volume of water would you add to 15.00 mL of a 6.77 M solution of nitric acid in order to... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/dilution-calculations"> See all questions in Dilution Calculations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1234 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What volume of a solution that is #6.0molL^-1# #HCl# is required to make #1.00L# of a #0.10mol*L^-1# solution?	null
2,211	a95a151c-6ddd-11ea-bf11-ccda262736ce	https://socratic.org/questions/how-would-you-calculate-the-specific-beat-of-silver-given-that-280-g-of-the-meta	0.06 cal/(g * ℃)	start physical_unit 8 8 specific_heat cal/(g_·_°c) qc_end end	[{"type":"physical unit","value":"Specific heat [OF] silver [IN] cal/(g * ℃)"}]	[{"type":"physical unit","value":"0.06 cal/(g * ℃)"}]	[{"type":"physical unit","value":"Mass [OF] the silver metal [=] \\pu{280 g}"},{"type":"physical unit","value":"Absorbed heat [OF] the silver metal [=] \\pu{136 calories}"},{"type":"physical unit","value":"Temperature1 [OF] the silver metal [=] \\pu{22.13 ℃}"},{"type":"physical unit","value":"Temperature2 [OF] the silver metal [=] \\pu{30.79 ℃}"}]	<h1 class="questionTitle" itemprop="name">How would you calculate the specific beat of silver, given that 280 g of the metal absorbed 136 calories when changed from 22.13°C to 30.79°C?</h1>	null	0.06 cal/(g * ℃)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The equation you'll need is the following: <br/> <img alt="http://hyperphysics.phy-astr.gsu.edu/hbase/thermo/spht.html" src="https://useruploads.socratic.org/kcFXadkRCurUlboMnedw_shta.gif"/><br/> where <mathjax>#Q#</mathjax> is in calories, <mathjax>#c#</mathjax> is in <mathjax>#"cal"/("g"^@"C")#</mathjax>, <mathjax>#m#</mathjax> is mass in grams, and <mathjax>#DeltaT#</mathjax> is the change in Celcius temperature. <mathjax>#DeltaT=T_"final"-T_"initial"#</mathjax></p> <p><mathjax>#Q="136 cal"#</mathjax><br/> <mathjax>#m="280 g"#</mathjax><br/> <mathjax>#T_"initial"="22.13"^@"C"#</mathjax><br/> <mathjax>#T_"final"="30.79"^@"C"#</mathjax><br/> <mathjax>#DeltaT="30.79"^@"C"-"22.13"^@"C"#</mathjax>"="8.66"^@"C"#</p> <p>Rearrange the equation to isolate <mathjax>#c#</mathjax>.</p> <p><mathjax>#c_"Ag"=Q/(mDeltaT)#</mathjax></p> <p><mathjax>#c_"Ag"=(136"cal")/(280"g"8.66^@"C")#</mathjax></p> <p><mathjax>#c_"Ag"=0.056"cal"/("g"*^@"C")#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#c_"Ag"=0.056"cal"/("g"^@"C")#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The equation you'll need is the following: <br/> <img alt="http://hyperphysics.phy-astr.gsu.edu/hbase/thermo/spht.html" src="https://useruploads.socratic.org/kcFXadkRCurUlboMnedw_shta.gif"/><br/> where <mathjax>#Q#</mathjax> is in calories, <mathjax>#c#</mathjax> is in <mathjax>#"cal"/("g"^@"C")#</mathjax>, <mathjax>#m#</mathjax> is mass in grams, and <mathjax>#DeltaT#</mathjax> is the change in Celcius temperature. <mathjax>#DeltaT=T_"final"-T_"initial"#</mathjax></p> <p><mathjax>#Q="136 cal"#</mathjax><br/> <mathjax>#m="280 g"#</mathjax><br/> <mathjax>#T_"initial"="22.13"^@"C"#</mathjax><br/> <mathjax>#T_"final"="30.79"^@"C"#</mathjax><br/> <mathjax>#DeltaT="30.79"^@"C"-"22.13"^@"C"#</mathjax>"="8.66"^@"C"#</p> <p>Rearrange the equation to isolate <mathjax>#c#</mathjax>.</p> <p><mathjax>#c_"Ag"=Q/(mDeltaT)#</mathjax></p> <p><mathjax>#c_"Ag"=(136"cal")/(280"g"8.66^@"C")#</mathjax></p> <p><mathjax>#c_"Ag"=0.056"cal"/("g"^@"C")#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How would you calculate the specific beat of silver, given that 280 g of the metal absorbed 136 calories when changed from 22.13°C to 30.79°C?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/specific-heat" itemprop="url"> <span class="breadcrumb" itemprop="title">Specific Heat</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="344757" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-12-01T03:39:33" itemprop="dateCreated"> Dec 1, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#c_"Ag"=0.056"cal"/("g"^@"C")#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The equation you'll need is the following: <br/> <img alt="http://hyperphysics.phy-astr.gsu.edu/hbase/thermo/spht.html" src="https://useruploads.socratic.org/kcFXadkRCurUlboMnedw_shta.gif"/><br/> where <mathjax>#Q#</mathjax> is in calories, <mathjax>#c#</mathjax> is in <mathjax>#"cal"/("g"^@"C")#</mathjax>, <mathjax>#m#</mathjax> is mass in grams, and <mathjax>#DeltaT#</mathjax> is the change in Celcius temperature. <mathjax>#DeltaT=T_"final"-T_"initial"#</mathjax></p> <p><mathjax>#Q="136 cal"#</mathjax><br/> <mathjax>#m="280 g"#</mathjax><br/> <mathjax>#T_"initial"="22.13"^@"C"#</mathjax><br/> <mathjax>#T_"final"="30.79"^@"C"#</mathjax><br/> <mathjax>#DeltaT="30.79"^@"C"-"22.13"^@"C"#</mathjax>"="8.66"^@"C"#</p> <p>Rearrange the equation to isolate <mathjax>#c#</mathjax>.</p> <p><mathjax>#c_"Ag"=Q/(mDeltaT)#</mathjax></p> <p><mathjax>#c_"Ag"=(136"cal")/(280"g"8.66^@"C")#</mathjax></p> <p><mathjax>#c_"Ag"=0.056"cal"/("g"^@"C")#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/344757" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-specific-heat-be-used-to-identify-substances"> How can specific heat be used to identify substances? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-heat-capacity-of-a-lead-sinker-be-determined"> How can the heat capacity of a lead sinker be determined? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-the-specific-heats-of-metals-compare-with-water"> How do the specific heats of metals compare with water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-specific-heat-change-with-temperature"> How does specific heat change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/dissolving-some-potassium-bromide-in-200cm3-of-water-leads-to-a-decrease-in-temp"> Dissolving some potassium bromide in 200cm3 of water leads to a decrease in temperature of 3oC.... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-heat-capacity-larger-for-polymers"> Is heat capacity larger for polymers? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-heat-capacity-an-extensive-property"> Why is heat capacity an extensive property? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-does-heat-capacity-change-with-temperature"> Why does heat capacity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-specific-heat-measured-in"> What is specific heat measured in? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-heat-capacity-measured-in"> What is heat capacity measured in? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/specific-heat"> See all questions in Specific Heat </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2898 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How would you calculate the specific beat of silver, given that 280 g of the metal absorbed 136 calories when changed from 22.13°C to 30.79°C?	null
2,212	aabb0ec2-6ddd-11ea-8a73-ccda262736ce	https://socratic.org/questions/how-many-moles-of-nh-4-2so-4-are-present-in-25-0-grams-of-nh-4-2so-4	0.19 moles	start physical_unit 4 4 mole mol qc_end physical_unit 4 4 8 9 mass qc_end end	[{"type":"physical unit","value":"Mole [OF] (NH4)2SO4 [IN] moles"}]	[{"type":"physical unit","value":"0.19 moles"}]	[{"type":"physical unit","value":"Mass [OF] (NH4)2SO4 [=] \\pu{25.0 grams}"}]	<h1 class="questionTitle" itemprop="name"> How many moles of #(NH_4)_2SO_4# are present in 25.0 grams of #(NH_4)_2SO_4#?</h1>	null	0.19 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Mass of one mole of Ammonium Sulfate is 132 g</p> <p>We can set up conversion factors/ ratios</p> <p>1 mol Ammonium Sulfate = 132g of <mathjax># (N#</mathjax>H4<mathjax>#)_2#</mathjax>S<mathjax>#O_4#</mathjax></p> <p>1 mol Ammonium Sulfate / 132g of <mathjax># (N#</mathjax>H4<mathjax>#)_2#</mathjax>S<mathjax>#O_4#</mathjax> (a) </p> <p>and </p> <p>132g of <mathjax># (N#</mathjax>H4<mathjax>#)_2#</mathjax>S<mathjax>#O_4#</mathjax> / 1 mol of Ammonium Sulfate (b)</p> <p>Using the conversion factor (a) we can find number of moles.</p> <p>25 g <mathjax># (N#</mathjax>H4<mathjax>#)_2#</mathjax>S<mathjax>#O_4#</mathjax> x 1 mol of Ammonium sulfate / 132g of <mathjax># (N#</mathjax>H4<mathjax>#)_2#</mathjax>S<mathjax>#O_4#</mathjax> </p> <p>0.2 moles Ammonium sulfate</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.2 moles </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Mass of one mole of Ammonium Sulfate is 132 g</p> <p>We can set up conversion factors/ ratios</p> <p>1 mol Ammonium Sulfate = 132g of <mathjax># (N#</mathjax>H4<mathjax>#)_2#</mathjax>S<mathjax>#O_4#</mathjax></p> <p>1 mol Ammonium Sulfate / 132g of <mathjax># (N#</mathjax>H4<mathjax>#)_2#</mathjax>S<mathjax>#O_4#</mathjax> (a) </p> <p>and </p> <p>132g of <mathjax># (N#</mathjax>H4<mathjax>#)_2#</mathjax>S<mathjax>#O_4#</mathjax> / 1 mol of Ammonium Sulfate (b)</p> <p>Using the conversion factor (a) we can find number of moles.</p> <p>25 g <mathjax># (N#</mathjax>H4<mathjax>#)_2#</mathjax>S<mathjax>#O_4#</mathjax> x 1 mol of Ammonium sulfate / 132g of <mathjax># (N#</mathjax>H4<mathjax>#)_2#</mathjax>S<mathjax>#O_4#</mathjax> </p> <p>0.2 moles Ammonium sulfate</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name"> How many moles of #(NH_4)_2SO_4# are present in 25.0 grams of #(NH_4)_2SO_4#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="253609" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/manish-b"><img alt="" class="" src="https://profilepictures.socratic.org/eW7uaERSSvtv5ff2XPxA_10203153902643748.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/manish-b"> Manish Bhardwaj </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-04-13T05:50:40" itemprop="dateCreated"> Apr 13, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.2 moles </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Mass of one mole of Ammonium Sulfate is 132 g</p> <p>We can set up conversion factors/ ratios</p> <p>1 mol Ammonium Sulfate = 132g of <mathjax># (N#</mathjax>H4<mathjax>#)_2#</mathjax>S<mathjax>#O_4#</mathjax></p> <p>1 mol Ammonium Sulfate / 132g of <mathjax># (N#</mathjax>H4<mathjax>#)_2#</mathjax>S<mathjax>#O_4#</mathjax> (a) </p> <p>and </p> <p>132g of <mathjax># (N#</mathjax>H4<mathjax>#)_2#</mathjax>S<mathjax>#O_4#</mathjax> / 1 mol of Ammonium Sulfate (b)</p> <p>Using the conversion factor (a) we can find number of moles.</p> <p>25 g <mathjax># (N#</mathjax>H4<mathjax>#)_2#</mathjax>S<mathjax>#O_4#</mathjax> x 1 mol of Ammonium sulfate / 132g of <mathjax># (N#</mathjax>H4<mathjax>#)_2#</mathjax>S<mathjax>#O_4#</mathjax> </p> <p>0.2 moles Ammonium sulfate</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/253609" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1672 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many moles of #(NH_4)_2SO_4# are present in 25.0 grams of #(NH_4)_2SO_4#?	null
2,213	aa7c9754-6ddd-11ea-9d7a-ccda262736ce	https://socratic.org/questions/the-pressure-in-a-bicycle-tire-is-1-34-atm-at-33-0-c-at-what-temperature-will-th	365.61 K	start physical_unit 4 5 temperature k qc_end physical_unit 4 5 7 8 pressure qc_end physical_unit 4 5 10 11 temperature qc_end physical_unit 4 5 22 23 pressure qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Temperature2 [OF] the bicycle tire [IN] K"}]	[{"type":"physical unit","value":"365.61 K"}]	[{"type":"physical unit","value":"Pressure1 [OF] the bicycle tire [=] \\pu{1.34 atm}"},{"type":"physical unit","value":"Temperature1 [OF] the bicycle tire [=] \\pu{33.0 ℃}"},{"type":"physical unit","value":"Pressure2 [OF] the bicycle tire [=] \\pu{1.60 atm}"},{"type":"other","value":"Constant volume."}]	<h1 class="questionTitle" itemprop="name">The pressure in a bicycle tire is 1.34 atm at 33.0°C. At what temperature will the pressure inside the tire be 1.60 atm if volume is constant?</h1>	null	365.61 K	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is an example of Gay-Lussac's law in which the pressure and Kelvin temperature are directly proportional at constant volume. The equation to use is <mathjax>#P_1/T_1=P_2/T_2#</mathjax>.</p> <p><mathjax>#P_1="1.34 atm"#</mathjax><br/> <mathjax>#T_1="33.0"^"o""C"+273.15="306.2 K"#</mathjax><br/> <mathjax>#P_2="1.60 atm"#</mathjax><br/> <mathjax>#T_2="???"#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#T_2#</mathjax> and solve.<br/> <mathjax>#P_1/T_1=P_2/T_2#</mathjax></p> <p><mathjax>#T_2=(P_2T_1)/P_1#</mathjax></p> <p><mathjax>#T_2=(1.60cancel"atm"xx306.2"K")/(1.34cancel"atm")#</mathjax></p> <p><mathjax>#T_2="366 K"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The temperature will be 366 K.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is an example of Gay-Lussac's law in which the pressure and Kelvin temperature are directly proportional at constant volume. The equation to use is <mathjax>#P_1/T_1=P_2/T_2#</mathjax>.</p> <p><mathjax>#P_1="1.34 atm"#</mathjax><br/> <mathjax>#T_1="33.0"^"o""C"+273.15="306.2 K"#</mathjax><br/> <mathjax>#P_2="1.60 atm"#</mathjax><br/> <mathjax>#T_2="???"#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#T_2#</mathjax> and solve.<br/> <mathjax>#P_1/T_1=P_2/T_2#</mathjax></p> <p><mathjax>#T_2=(P_2T_1)/P_1#</mathjax></p> <p><mathjax>#T_2=(1.60cancel"atm"xx306.2"K")/(1.34cancel"atm")#</mathjax></p> <p><mathjax>#T_2="366 K"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">The pressure in a bicycle tire is 1.34 atm at 33.0°C. At what temperature will the pressure inside the tire be 1.60 atm if volume is constant?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/gas-pressure" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Pressure</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="202004" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-22T00:56:14" itemprop="dateCreated"> Dec 22, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The temperature will be 366 K.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is an example of Gay-Lussac's law in which the pressure and Kelvin temperature are directly proportional at constant volume. The equation to use is <mathjax>#P_1/T_1=P_2/T_2#</mathjax>.</p> <p><mathjax>#P_1="1.34 atm"#</mathjax><br/> <mathjax>#T_1="33.0"^"o""C"+273.15="306.2 K"#</mathjax><br/> <mathjax>#P_2="1.60 atm"#</mathjax><br/> <mathjax>#T_2="???"#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#T_2#</mathjax> and solve.<br/> <mathjax>#P_1/T_1=P_2/T_2#</mathjax></p> <p><mathjax>#T_2=(P_2T_1)/P_1#</mathjax></p> <p><mathjax>#T_2=(1.60cancel"atm"xx306.2"K")/(1.34cancel"atm")#</mathjax></p> <p><mathjax>#T_2="366 K"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/202004" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-gas-pressure-be-changed"> How can gas pressure be changed? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-you-increase-gas-pressure-in-a-container"> How can you increase gas pressure in a container? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-gas-pressure-created"> How is gas pressure created? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-does-gas-pressure-increase-when-temperature-increases"> Why does gas pressure increase when temperature increases? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-gas-pressure-zero-at-absolute-zero"> Why is gas pressure zero at absolute zero? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-does-gas-pressure-increase-with-temperature"> Why does gas pressure increase with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-there-no-gas-pressure-in-a-vacuum"> Why is there no gas pressure in a vacuum? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-total-gas-pressure-in-a-sealed-flask-that-contains-oxygen-at-a-parti-1"> What is the total gas pressure in a sealed flask that contains oxygen at a partial pressure of... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-the-absolute-pressure-of-a-gas-is-550-280-kpa-what-is-its-gage-pressure"> If the absolute pressure of a gas is 550.280 kPa, what is its gage pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-a-gas-sample-occupies-4-2-l-at-a-pressure-of-101-kpa-what-volume-will-it-occu"> If a gas sample occupies 4.2 L at a pressure of 101 kPa. What volume will it occupy if the... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/gas-pressure"> See all questions in Gas Pressure </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 12452 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	The pressure in a bicycle tire is 1.34 atm at 33.0°C. At what temperature will the pressure inside the tire be 1.60 atm if volume is constant?	null
2,214	aca30f2c-6ddd-11ea-8216-ccda262736ce	https://socratic.org/questions/59b0f1cb11ef6b14cfb03062	C5H4O2	start chemical_formula qc_end substance 9 9 qc_end end	[{"type":"other","value":"Chemical Formula [OF] the organic compound [IN] empirical"}]	[{"type":"chemical equation","value":"C5H4O2"}]	[{"type":"physical unit","value":"Percentage [OF] C in the organic compound [=] \\pu{62.6%}"},{"type":"physical unit","value":"Percentage [OF] H in the organic compound [=] \\pu{4.21%}"},{"type":"substance name","value":"Oxygen"}]	<h1 class="questionTitle" itemprop="name">Microanalysis of an organic compound containing carbon, hydrogen, and oxygen, gives #62.6%C#, and #4.21%H#. What is the empirical formula of the compound?</h1>	null	C5H4O2	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We assume a <mathjax>#100g#</mathjax> mass of compound, and thus....</p> <p><mathjax>#"Moles of carbon"=(62.6g)/(12.011gmol^-1)=5.21molC#</mathjax></p> <p><mathjax>#"Moles of hydrogen"=(4.21g)/(1.00794gmol^-1)=4.16molH#</mathjax></p> <p><mathjax>#"Moles of oxygen"=(33.3g)/(15.999gmol^-1)=2.08molH#</mathjax></p> <p>In each case, we have divided the mass of element by the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">ATOMIC mass</a> of each element to give an elemental ratio.... How did I know that the compound was <mathjax>#33.3%#</mathjax> by mass with respect to oxygen?</p> <p>And now we divide thru by the LOWEST molar quantity, that of oxygen to get a trial empirical formula of <mathjax>#C_(2.50)H_2O#</mathjax>. But by definition, the empirical formula is the lowest WHOLE number ratio defining constituent atoms in a species...so we gots <mathjax>#C_5H_4O_2#</mathjax>.</p> <p>We cannot access the molecular formula inasmuch as we need a measurement of molecular mass. See <a href="https://socratic.org/questions/what-is-empirical-formula?source=search">here.</a> </p> <p><mathjax>#"Molecular formula"="empirical formula"xxn#</mathjax>....</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_5H_4O_2#</mathjax> is the <mathjax>#"empirical formula....."#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We assume a <mathjax>#100g#</mathjax> mass of compound, and thus....</p> <p><mathjax>#"Moles of carbon"=(62.6g)/(12.011gmol^-1)=5.21molC#</mathjax></p> <p><mathjax>#"Moles of hydrogen"=(4.21g)/(1.00794gmol^-1)=4.16molH#</mathjax></p> <p><mathjax>#"Moles of oxygen"=(33.3g)/(15.999gmol^-1)=2.08molH#</mathjax></p> <p>In each case, we have divided the mass of element by the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">ATOMIC mass</a> of each element to give an elemental ratio.... How did I know that the compound was <mathjax>#33.3%#</mathjax> by mass with respect to oxygen?</p> <p>And now we divide thru by the LOWEST molar quantity, that of oxygen to get a trial empirical formula of <mathjax>#C_(2.50)H_2O#</mathjax>. But by definition, the empirical formula is the lowest WHOLE number ratio defining constituent atoms in a species...so we gots <mathjax>#C_5H_4O_2#</mathjax>.</p> <p>We cannot access the molecular formula inasmuch as we need a measurement of molecular mass. See <a href="https://socratic.org/questions/what-is-empirical-formula?source=search">here.</a> </p> <p><mathjax>#"Molecular formula"="empirical formula"xxn#</mathjax>....</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Microanalysis of an organic compound containing carbon, hydrogen, and oxygen, gives #62.6%C#, and #4.21%H#. What is the empirical formula of the compound?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="472641" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-09-07T07:55:50" itemprop="dateCreated"> Sep 7, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_5H_4O_2#</mathjax> is the <mathjax>#"empirical formula....."#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We assume a <mathjax>#100g#</mathjax> mass of compound, and thus....</p> <p><mathjax>#"Moles of carbon"=(62.6g)/(12.011gmol^-1)=5.21molC#</mathjax></p> <p><mathjax>#"Moles of hydrogen"=(4.21g)/(1.00794gmol^-1)=4.16molH#</mathjax></p> <p><mathjax>#"Moles of oxygen"=(33.3g)/(15.999gmol^-1)=2.08molH#</mathjax></p> <p>In each case, we have divided the mass of element by the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">ATOMIC mass</a> of each element to give an elemental ratio.... How did I know that the compound was <mathjax>#33.3%#</mathjax> by mass with respect to oxygen?</p> <p>And now we divide thru by the LOWEST molar quantity, that of oxygen to get a trial empirical formula of <mathjax>#C_(2.50)H_2O#</mathjax>. But by definition, the empirical formula is the lowest WHOLE number ratio defining constituent atoms in a species...so we gots <mathjax>#C_5H_4O_2#</mathjax>.</p> <p>We cannot access the molecular formula inasmuch as we need a measurement of molecular mass. See <a href="https://socratic.org/questions/what-is-empirical-formula?source=search">here.</a> </p> <p><mathjax>#"Molecular formula"="empirical formula"xxn#</mathjax>....</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/472641" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molecular-formula-of-a-compound"> How do you find molecular formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-diamond"> What is the chemical formula of a diamond? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-carbohydrate"> What is the chemical formula of a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-valproic-acid"> What is the empirical formula for valproic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-of-magnesium-oxide"> What is the empirical formula of magnesium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-empirical-formula-not-double-that-of-the-monosaccharides"> Why is the empirical formula not double that of the monosaccharides? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5331180502bf342f40b5c3b5"> Question #5c3b5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-molecular-formula-represents-a-carbohydrate"> What molecular formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-of-vinegar"> What is the molecular formula of vinegar? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/empirical-and-molecular-formulas"> See all questions in Empirical and Molecular Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1465 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Microanalysis of an organic compound containing carbon, hydrogen, and oxygen, gives #62.6%C#, and #4.21%H#. What is the empirical formula of the compound?	null
2,215	a9e76ea6-6ddd-11ea-9302-ccda262736ce	https://socratic.org/questions/how-would-you-balance-ag2o-ag-o2-1	2 Ag2O -> 4 Ag + O2	start chemical_equation qc_end chemical_equation 4 8 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the equation"}]	[{"type":"chemical equation","value":"2 Ag2O -> 4 Ag + O2"}]	[{"type":"chemical equation","value":"Ag2O -> Ag + O2"}]	<h1 class="questionTitle" itemprop="name">How would you balance Ag2O --> Ag + O2?</h1>	null	2 Ag2O -> 4 Ag + O2	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>How to balance?<br/> We have an equation;<br/> <mathjax>#Ag_2O -> Ag + O_2#</mathjax><br/> First of all balance the O on both sides, now look at the product side. We have 2 oxygen on right side and on left side we have only 1 oxygen. To balance it, put a coefficient 2 on left side before <mathjax>#Ag_2O#</mathjax> . The equation becomes as<br/> <mathjax>#2Ag_2O -> Ag + O_2#</mathjax> <br/> Now again check the product side, There is 1 Ag but in reactant side there is 4 Ag. Now put coefficient 4 before Ag on right side. The equation becomes as;<br/> <mathjax>#2Ag_2O-> 4Ag + O_2#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2Ag_2O-> 4Ag + O_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>How to balance?<br/> We have an equation;<br/> <mathjax>#Ag_2O -> Ag + O_2#</mathjax><br/> First of all balance the O on both sides, now look at the product side. We have 2 oxygen on right side and on left side we have only 1 oxygen. To balance it, put a coefficient 2 on left side before <mathjax>#Ag_2O#</mathjax> . The equation becomes as<br/> <mathjax>#2Ag_2O -> Ag + O_2#</mathjax> <br/> Now again check the product side, There is 1 Ag but in reactant side there is 4 Ag. Now put coefficient 4 before Ag on right side. The equation becomes as;<br/> <mathjax>#2Ag_2O-> 4Ag + O_2#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How would you balance Ag2O --> Ag + O2?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="190193" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ali-t-2"><img alt="" class="" src="https://profilepictures.socratic.org/qEOEm9jRlSQ0484FUicg_SAM_2492.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ali-t-2"> MAT </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-18T13:40:43" itemprop="dateCreated"> Nov 18, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2Ag_2O-> 4Ag + O_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>How to balance?<br/> We have an equation;<br/> <mathjax>#Ag_2O -> Ag + O_2#</mathjax><br/> First of all balance the O on both sides, now look at the product side. We have 2 oxygen on right side and on left side we have only 1 oxygen. To balance it, put a coefficient 2 on left side before <mathjax>#Ag_2O#</mathjax> . The equation becomes as<br/> <mathjax>#2Ag_2O -> Ag + O_2#</mathjax> <br/> Now again check the product side, There is 1 Ag but in reactant side there is 4 Ag. Now put coefficient 4 before Ag on right side. The equation becomes as;<br/> <mathjax>#2Ag_2O-> 4Ag + O_2#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/190193" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------> H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -> Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? Aluminum and hydrochloric acid react to form aluminum... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equation-sodium-phosphate-and-calcium-chloride-r"> How can I balance this chemical equation? Sodium phosphate and calcium chloride react to form... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-equation-kclo3-kcl-o2"> How can I balance this equation? ____ #KClO_3 -># ____ #KCl +# ____ #O_2# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-balancing-chemical-equations-important"> Why is balancing chemical equations important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/balancing-chemical-equations"> See all questions in Balancing Chemical Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 31381 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How would you balance Ag2O --> Ag + O2?	null
2,216	ac68c294-6ddd-11ea-9abc-ccda262736ce	https://socratic.org/questions/what-is-the-density-of-water-vapor-at-room-temperature	0.02 g/L	start physical_unit 5 6 density g/l qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Density [OF] water vapor [IN] g/L"}]	[{"type":"physical unit","value":"0.02 g/L"}]	[{"type":"other","value":"Room temperature."}]	<h1 class="questionTitle" itemprop="name">What is the density of water vapor at room temperature?</h1>	null	0.02 g/L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The first thing to do here is to pick a temperature that can be considered <em>room temperature</em>. I'll go with <mathjax>#20^@"C"#</mathjax>, which is equivalent to </p> <blockquote> <p><mathjax>#T["K"] = 20^@"C" + 273.15 = "293.15 K"#</mathjax></p> </blockquote> <p>Next, look up the <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/partial-pressure">partial pressure</a></strong> of water vapor at <mathjax>#20^@"C"#</mathjax>. You'll find it listed as </p> <blockquote> <p><mathjax>#P = "0.0230 atm"#</mathjax></p> </blockquote> <p><a href="http://www.endmemo.com/chem/vaporpressurewater.php" rel="nofollow" target="_blank">http://www.endmemo.com/chem/vaporpressurewater.php</a></p> <p>Now, that you have a pressure and a temperature to work with, use the <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a></strong> equation to find the <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a></strong> of water vapor. </p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a)PV = nRTcolor(white)(a/a)\|)))" "#</mathjax></p> </blockquote> <p>Here you have</p> <blockquote> <p><mathjax>#P#</mathjax> - the pressure of the gas<br/> <mathjax>#V#</mathjax> - the volume it occupies<br/> <mathjax>#n#</mathjax> - the number of moles of gas<br/> <mathjax>#R#</mathjax> - the <em>universal gas constant</em><br/> <mathjax>#T#</mathjax> - the <strong>absolute temperature</strong> of the gas</p> </blockquote> <p>Let's assume that your room contains a mass <mathjax>#m#</mathjax> <mathjax>#"g"#</mathjax> of water vapor. Use the <strong>molar mass</strong> of water, <mathjax>#M_("M H"_2"O")#</mathjax>, to express the <em>number of moles</em> in terms of this mass <mathjax>#m#</mathjax></p> <blockquote> <p><mathjax>#n = m/M_("M H"_2"O")#</mathjax></p> </blockquote> <p>Plug this into the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> equation to get </p> <blockquote> <p><mathjax>#PV = m/M_("M H"_2"O") * RT#</mathjax></p> </blockquote> <p>As you know, <strong>density</strong>, <mathjax>#rho#</mathjax>, is defined as mass per unit of volume. Rearrange the above equation to get <mathjax>#m/v = rho#</mathjax> isolated on one side</p> <blockquote> <p><mathjax>#P = m/M_("M H"_2"O") * 1/V * RT#</mathjax></p> <p><mathjax>#P * M_("M H"_2"O") = m/V * RT#</mathjax></p> <p><mathjax>#m/V = (P * M_ ("M H"_ 2"O"))/(RT) implies color(purple)(\|bar(ul(color(white)(a/a)color(black)(rho = M_ ("M H"_2"O") * P/(RT))color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>Water has a <strong>molar mass</strong> of <mathjax>#"18.015 g mol"^(-1)#</mathjax>. Plug in your values to find </p> <blockquote> <p><mathjax>#rho = "18.015 g"color(red)(cancel(color(black)("mol"^(-1)))) * (0.0230 color(red)(cancel(color(black)("atm"))))/(0.0821(color(red)(cancel(color(black)("atm"))) * "L")/(color(red)(cancel(color(black)("mol"))) * color(red)(cancel(color(black)("K")))) * 293.15 color(red)(cancel(color(black)("K"))))#</mathjax></p> <p><mathjax>#color(green)(\|bar(ul(color(white)(a/a)color(black)(rho = "0.0172 g L"^(-1))color(white)(a/a)\|)))#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"0.0172 g L"^(-1)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The first thing to do here is to pick a temperature that can be considered <em>room temperature</em>. I'll go with <mathjax>#20^@"C"#</mathjax>, which is equivalent to </p> <blockquote> <p><mathjax>#T["K"] = 20^@"C" + 273.15 = "293.15 K"#</mathjax></p> </blockquote> <p>Next, look up the <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/partial-pressure">partial pressure</a></strong> of water vapor at <mathjax>#20^@"C"#</mathjax>. You'll find it listed as </p> <blockquote> <p><mathjax>#P = "0.0230 atm"#</mathjax></p> </blockquote> <p><a href="http://www.endmemo.com/chem/vaporpressurewater.php" rel="nofollow" target="_blank">http://www.endmemo.com/chem/vaporpressurewater.php</a></p> <p>Now, that you have a pressure and a temperature to work with, use the <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a></strong> equation to find the <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a></strong> of water vapor. </p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a)PV = nRTcolor(white)(a/a)\|)))" "#</mathjax></p> </blockquote> <p>Here you have</p> <blockquote> <p><mathjax>#P#</mathjax> - the pressure of the gas<br/> <mathjax>#V#</mathjax> - the volume it occupies<br/> <mathjax>#n#</mathjax> - the number of moles of gas<br/> <mathjax>#R#</mathjax> - the <em>universal gas constant</em><br/> <mathjax>#T#</mathjax> - the <strong>absolute temperature</strong> of the gas</p> </blockquote> <p>Let's assume that your room contains a mass <mathjax>#m#</mathjax> <mathjax>#"g"#</mathjax> of water vapor. Use the <strong>molar mass</strong> of water, <mathjax>#M_("M H"_2"O")#</mathjax>, to express the <em>number of moles</em> in terms of this mass <mathjax>#m#</mathjax></p> <blockquote> <p><mathjax>#n = m/M_("M H"_2"O")#</mathjax></p> </blockquote> <p>Plug this into the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> equation to get </p> <blockquote> <p><mathjax>#PV = m/M_("M H"_2"O") * RT#</mathjax></p> </blockquote> <p>As you know, <strong>density</strong>, <mathjax>#rho#</mathjax>, is defined as mass per unit of volume. Rearrange the above equation to get <mathjax>#m/v = rho#</mathjax> isolated on one side</p> <blockquote> <p><mathjax>#P = m/M_("M H"_2"O") * 1/V * RT#</mathjax></p> <p><mathjax>#P * M_("M H"_2"O") = m/V * RT#</mathjax></p> <p><mathjax>#m/V = (P * M_ ("M H"_ 2"O"))/(RT) implies color(purple)(\|bar(ul(color(white)(a/a)color(black)(rho = M_ ("M H"_2"O") * P/(RT))color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>Water has a <strong>molar mass</strong> of <mathjax>#"18.015 g mol"^(-1)#</mathjax>. Plug in your values to find </p> <blockquote> <p><mathjax>#rho = "18.015 g"color(red)(cancel(color(black)("mol"^(-1)))) * (0.0230 color(red)(cancel(color(black)("atm"))))/(0.0821(color(red)(cancel(color(black)("atm"))) * "L")/(color(red)(cancel(color(black)("mol"))) * color(red)(cancel(color(black)("K")))) * 293.15 color(red)(cancel(color(black)("K"))))#</mathjax></p> <p><mathjax>#color(green)(\|bar(ul(color(white)(a/a)color(black)(rho = "0.0172 g L"^(-1))color(white)(a/a)\|)))#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the density of water vapor at room temperature?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/ideal-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Ideal Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="296436" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-08-07T12:01:20" itemprop="dateCreated"> Aug 7, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"0.0172 g L"^(-1)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The first thing to do here is to pick a temperature that can be considered <em>room temperature</em>. I'll go with <mathjax>#20^@"C"#</mathjax>, which is equivalent to </p> <blockquote> <p><mathjax>#T["K"] = 20^@"C" + 273.15 = "293.15 K"#</mathjax></p> </blockquote> <p>Next, look up the <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/partial-pressure">partial pressure</a></strong> of water vapor at <mathjax>#20^@"C"#</mathjax>. You'll find it listed as </p> <blockquote> <p><mathjax>#P = "0.0230 atm"#</mathjax></p> </blockquote> <p><a href="http://www.endmemo.com/chem/vaporpressurewater.php" rel="nofollow" target="_blank">http://www.endmemo.com/chem/vaporpressurewater.php</a></p> <p>Now, that you have a pressure and a temperature to work with, use the <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a></strong> equation to find the <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a></strong> of water vapor. </p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a)PV = nRTcolor(white)(a/a)\|)))" "#</mathjax></p> </blockquote> <p>Here you have</p> <blockquote> <p><mathjax>#P#</mathjax> - the pressure of the gas<br/> <mathjax>#V#</mathjax> - the volume it occupies<br/> <mathjax>#n#</mathjax> - the number of moles of gas<br/> <mathjax>#R#</mathjax> - the <em>universal gas constant</em><br/> <mathjax>#T#</mathjax> - the <strong>absolute temperature</strong> of the gas</p> </blockquote> <p>Let's assume that your room contains a mass <mathjax>#m#</mathjax> <mathjax>#"g"#</mathjax> of water vapor. Use the <strong>molar mass</strong> of water, <mathjax>#M_("M H"_2"O")#</mathjax>, to express the <em>number of moles</em> in terms of this mass <mathjax>#m#</mathjax></p> <blockquote> <p><mathjax>#n = m/M_("M H"_2"O")#</mathjax></p> </blockquote> <p>Plug this into the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> equation to get </p> <blockquote> <p><mathjax>#PV = m/M_("M H"_2"O") * RT#</mathjax></p> </blockquote> <p>As you know, <strong>density</strong>, <mathjax>#rho#</mathjax>, is defined as mass per unit of volume. Rearrange the above equation to get <mathjax>#m/v = rho#</mathjax> isolated on one side</p> <blockquote> <p><mathjax>#P = m/M_("M H"_2"O") * 1/V * RT#</mathjax></p> <p><mathjax>#P * M_("M H"_2"O") = m/V * RT#</mathjax></p> <p><mathjax>#m/V = (P * M_ ("M H"_ 2"O"))/(RT) implies color(purple)(\|bar(ul(color(white)(a/a)color(black)(rho = M_ ("M H"_2"O") * P/(RT))color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>Water has a <strong>molar mass</strong> of <mathjax>#"18.015 g mol"^(-1)#</mathjax>. Plug in your values to find </p> <blockquote> <p><mathjax>#rho = "18.015 g"color(red)(cancel(color(black)("mol"^(-1)))) * (0.0230 color(red)(cancel(color(black)("atm"))))/(0.0821(color(red)(cancel(color(black)("atm"))) * "L")/(color(red)(cancel(color(black)("mol"))) * color(red)(cancel(color(black)("K")))) * 293.15 color(red)(cancel(color(black)("K"))))#</mathjax></p> <p><mathjax>#color(green)(\|bar(ul(color(white)(a/a)color(black)(rho = "0.0172 g L"^(-1))color(white)(a/a)\|)))#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/296436" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-ideal-gas-constant"> How do you find the ideal gas constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-solve-ideal-gas-law-problems"> How do you solve ideal gas law problems? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-know-which-ideal-gas-constant-to-use"> How do you know which ideal gas constant to use? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ideal-gas-constant-for-butane"> What is the ideal gas constant for butane? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-ideal-gas-law-in-kelvin"> Why is ideal gas law in kelvin? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ideal-gas-constant-important"> Why is the ideal gas constant important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-di-electric-constant"> What is the di-electric constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-volume-l-will-0-20-mol-hi-occupy-at-300-k-and-100-0-kpa-r-8-314-kpa-l-k-mol"> What volume (L) will 0.20 mol HI occupy at 300 K and 100.0 kPa? R = 8.314 kPa L / (K mol) =... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-molar-mass-of-a-gas"> How do you calculate the molar mass of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-should-i-use-the-ideal-gas-law-and-not-the-combined-gas-law"> When should I use the ideal gas law and not the combined gas law? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/ideal-gas-law"> See all questions in Ideal Gas Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 9746 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the density of water vapor at room temperature?	null
2,217	ad188048-6ddd-11ea-a250-ccda262736ce	https://socratic.org/questions/the-decomposition-of-kclo3-s-into-kcl-s-and-o2-g-with-an-85-yield-how-many-moles	2.75 moles	start physical_unit 3 3 mole mol qc_end physical_unit 7 7 22 23 mole qc_end chemical_equation 5 5 qc_end end	[{"type":"physical unit","value":"Mole [OF] KClO3 [IN] moles"}]	[{"type":"physical unit","value":"2.75 moles"}]	[{"type":"physical unit","value":"Mole [OF] O2 [=] \\pu{3.50 moles}"},{"type":"chemical equation","value":"KCl(s)"},{"type":"physical unit","value":"Yield [OF] the reaction [=] \\pu{85%}"}]	<h1 class="questionTitle" itemprop="name">The decomposition of KClO3(s) into KCl(s) and O2(g) with an 85% yield. How many moles of KClO3 must be used to generate 3.50 moles of O2?</h1>	null	2.75 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Here, the equation of the reaction is </p> <p><mathjax>#2KClO_3(s) #</mathjax> -> <mathjax>#2KCl (s) + 3O_2(g) #</mathjax> <br/> Now as you see, the yield of the reaction is 85% which means that out of the number of moles of the products to be given out, only 80% is obtained. <br/> In order to obtain 3.50 moles of <mathjax>#O_2#</mathjax>, which is 85% of the no. of moles which ought to be obtained. <br/> So, if the reaction gave 100% of the yield, no. of moles of <mathjax>#O_2#</mathjax> would be 4.12 moles. (<mathjax>#0.85x = 3.50 #</mathjax> )</p> <p>Now, 3 molecules of <mathjax>#O_2#</mathjax> are given by 2 molecules of <mathjax>#KClO_3#</mathjax> <br/> No. of moles of 1 molecule of <mathjax>#O_2#</mathjax> = <mathjax>#4.12/3#</mathjax> <br/> By ratio, <br/> No. of moles of 2 molecules of <mathjax>#KCLO_3 #</mathjax> that reacted = <mathjax>#4.122/3#</mathjax> = 2.75 moles</p> <p>Therefore, 2.75 moles of <mathjax>#KCLO_3 #</mathjax> is required. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>2.75 moles</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Here, the equation of the reaction is </p> <p><mathjax>#2KClO_3(s) #</mathjax> -> <mathjax>#2KCl (s) + 3O_2(g) #</mathjax> <br/> Now as you see, the yield of the reaction is 85% which means that out of the number of moles of the products to be given out, only 80% is obtained. <br/> In order to obtain 3.50 moles of <mathjax>#O_2#</mathjax>, which is 85% of the no. of moles which ought to be obtained. <br/> So, if the reaction gave 100% of the yield, no. of moles of <mathjax>#O_2#</mathjax> would be 4.12 moles. (<mathjax>#0.85x = 3.50 #</mathjax> )</p> <p>Now, 3 molecules of <mathjax>#O_2#</mathjax> are given by 2 molecules of <mathjax>#KClO_3#</mathjax> <br/> No. of moles of 1 molecule of <mathjax>#O_2#</mathjax> = <mathjax>#4.12/3#</mathjax> <br/> By ratio, <br/> No. of moles of 2 molecules of <mathjax>#KCLO_3 #</mathjax> that reacted = <mathjax>#4.122/3#</mathjax> = 2.75 moles</p> <p>Therefore, 2.75 moles of <mathjax>#KCLO_3 #</mathjax> is required. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">The decomposition of KClO3(s) into KCl(s) and O2(g) with an 85% yield. How many moles of KClO3 must be used to generate 3.50 moles of O2?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/equation-stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Equation Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="418976" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/tidy-bat"><img alt="" class="" src="https://profilepictures.socratic.org/bWv2PcqJRgGnhJi1gkn4_DSC_0015.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/tidy-bat"> Anuj Baskota </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-07T05:33:32" itemprop="dateCreated"> May 7, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>2.75 moles</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Here, the equation of the reaction is </p> <p><mathjax>#2KClO_3(s) #</mathjax> -> <mathjax>#2KCl (s) + 3O_2(g) #</mathjax> <br/> Now as you see, the yield of the reaction is 85% which means that out of the number of moles of the products to be given out, only 80% is obtained. <br/> In order to obtain 3.50 moles of <mathjax>#O_2#</mathjax>, which is 85% of the no. of moles which ought to be obtained. <br/> So, if the reaction gave 100% of the yield, no. of moles of <mathjax>#O_2#</mathjax> would be 4.12 moles. (<mathjax>#0.85x = 3.50 #</mathjax> )</p> <p>Now, 3 molecules of <mathjax>#O_2#</mathjax> are given by 2 molecules of <mathjax>#KClO_3#</mathjax> <br/> No. of moles of 1 molecule of <mathjax>#O_2#</mathjax> = <mathjax>#4.12/3#</mathjax> <br/> By ratio, <br/> No. of moles of 2 molecules of <mathjax>#KCLO_3 #</mathjax> that reacted = <mathjax>#4.122/3#</mathjax> = 2.75 moles</p> <p>Therefore, 2.75 moles of <mathjax>#KCLO_3 #</mathjax> is required. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/418976" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4171602bf3469588dc36e"> What are the types of stoichiometry examples, with examples? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4171802bf3469570e2e82"> Question #e2e82 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/533668a402bf34573b4e66fb"> What mass of carbon dioxide can 1.00 kg of lithium oxide absorb? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-an-example-of-a-stoichiometry-practice-problem"> What is an example of a stoichiometry practice problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-an-example-of-a-balanced-equation-practice-problem"> What is an example of a balanced equation practice problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-a-chemical-equation"> How can I balance a chemical equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-stoichiometry-be-used"> How can stoichiometry be used? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-stoichiometric-ratios-relate-reactants-to-products"> How do stoichiometric ratios relate reactants to products? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-gas-stoichiometry-differ-from-stoichiometry-of-solids-and-liquids"> How does gas stoichiometry differ from stoichiometry of solids and liquids? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-stoichiometry-relate-to-the-law-of-conservation"> How does stoichiometry relate to the law of conservation? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/equation-stoichiometry"> See all questions in Equation Stoichiometry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 6670 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	The decomposition of KClO3(s) into KCl(s) and O2(g) with an 85% yield. How many moles of KClO3 must be used to generate 3.50 moles of O2?	null
2,218	ad2492a6-6ddd-11ea-b436-ccda262736ce	https://socratic.org/questions/use-hess-s-law-and-the-following-information-to-calculate-the-change-in-enthalpy	227 kJ/mol	start physical_unit 14 15 enthalpy kj/mol qc_end chemical_equation 16 21 qc_end chemical_equation 22 30 qc_end chemical_equation 35 39 qc_end chemical_equation 44 49 qc_end physical_unit 14 15 33 34 entropy qc_end physical_unit 14 15 42 43 entropy qc_end physical_unit 14 15 52 53 entropy qc_end end	[{"type":"physical unit","value":"Change in enthalpy [OF] the reaction [IN] kJ/mol"}]	[{"type":"physical unit","value":"227 kJ/mol"}]	[{"type":"chemical equation","value":"2 C + H2 -> C2H2"},{"type":"chemical equation","value":"C2H2 + 5/2 O2 -> 2 CO2 + H2O "},{"type":"chemical equation","value":"C + O2 -> CO2"},{"type":"chemical equation","value":"H2 + 1/2 O2 -> H2O"},{"type":"physical unit","value":"Entropy1 [OF] the reaction [=] \\pu{-1299.6 kJ}"},{"type":"physical unit","value":"Entropy2 [OF] the reaction [=] \\pu{-393.5 kJ}"},{"type":"physical unit","value":"Entropy3 [OF] the reaction [=] \\pu{-285.8 kJ}"}]	<h1 class="questionTitle" itemprop="name">Use Hess's Law and the following information to calculate the change in enthalpy for the reaction 2C + H2 -> C2H2?</h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>C2H2 + 5/2 O2 -> 2CO2 + H2O Entropy = -1299.6 kJ<br/> C + O2 -> CO2 Entropy = -393.5 kJ<br/> H2 + 1/2 O2 -> H2O Entropy = -285.8 kJ</p></div> </h2> </div> </div>	227 kJ/mol	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You have listed <a href="https://socratic.org/chemistry/thermochemistry/entropy">entropy</a> changes for the reaction. In fact, these are values for <mathjax>#DeltaH^@""_"reaction"#</mathjax></p> <p><mathjax>#HC-=CH + 5/2O_2 rarr 2CO_2 + H_2O#</mathjax> <mathjax>#;DeltaH^@""_"reaction"=-1299.6kJmol^-1#</mathjax> <mathjax>#(i)#</mathjax></p> <p><mathjax>#C + O_2 rarr CO_2#</mathjax> <mathjax>#;DeltaH^@""_"reaction"=-393.5kJmol^-1#</mathjax> <mathjax>#(ii)#</mathjax></p> <p><mathjax>#H_2 + 1/2O_2 rarr H_2O#</mathjax> <mathjax>#;DeltaH^@""_"reaction"=-285.6kJmol^-1#</mathjax> <mathjax>#(iii)#</mathjax></p> <p>We want <mathjax>#DeltaH^@#</mathjax> for:</p> <p><mathjax>#2C+H_2 rarr HC-=CH#</mathjax> <mathjax>#;DeltaH^@=??#</mathjax></p> <p>If I do the sum of the given reactions in this manner, <mathjax>#2xx(ii)-(i)+(iii)#</mathjax>, I get the following:</p> <p><mathjax>#2C + cancel(2O_2) +cancel(2CO_2) + cancel(H_2O) +H_2 + cancel(1/2O_2)rarr cancel(2CO_2)+HC-=CH +cancel(H_2O)+ cancel(5/2O_2)#</mathjax></p> <p>Which after cancelling gives:</p> <p><mathjax>#2C(s) +H_2(g) rarr HC-=CH(g)#</mathjax> <mathjax>#DeltaH^@""_"reaction"=227kJmol^-1#</mathjax></p> <p>Note here that <mathjax>#DeltaH^@""_"reaction"=DeltaH^@""_f" acetylene"#</mathjax>.<br/> So here we have used the thermochemical equations as linear equations to give us the equation that we sought (and thus necessarily the thermodynamic parameters). </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2C(s) +H_2(g) rarr HC-=CH(g)#</mathjax><br/> <mathjax>#DeltaH^@""_"reaction"=227kJmol^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You have listed <a href="https://socratic.org/chemistry/thermochemistry/entropy">entropy</a> changes for the reaction. In fact, these are values for <mathjax>#DeltaH^@""_"reaction"#</mathjax></p> <p><mathjax>#HC-=CH + 5/2O_2 rarr 2CO_2 + H_2O#</mathjax> <mathjax>#;DeltaH^@""_"reaction"=-1299.6kJmol^-1#</mathjax> <mathjax>#(i)#</mathjax></p> <p><mathjax>#C + O_2 rarr CO_2#</mathjax> <mathjax>#;DeltaH^@""_"reaction"=-393.5kJmol^-1#</mathjax> <mathjax>#(ii)#</mathjax></p> <p><mathjax>#H_2 + 1/2O_2 rarr H_2O#</mathjax> <mathjax>#;DeltaH^@""_"reaction"=-285.6kJmol^-1#</mathjax> <mathjax>#(iii)#</mathjax></p> <p>We want <mathjax>#DeltaH^@#</mathjax> for:</p> <p><mathjax>#2C+H_2 rarr HC-=CH#</mathjax> <mathjax>#;DeltaH^@=??#</mathjax></p> <p>If I do the sum of the given reactions in this manner, <mathjax>#2xx(ii)-(i)+(iii)#</mathjax>, I get the following:</p> <p><mathjax>#2C + cancel(2O_2) +cancel(2CO_2) + cancel(H_2O) +H_2 + cancel(1/2O_2)rarr cancel(2CO_2)+HC-=CH +cancel(H_2O)+ cancel(5/2O_2)#</mathjax></p> <p>Which after cancelling gives:</p> <p><mathjax>#2C(s) +H_2(g) rarr HC-=CH(g)#</mathjax> <mathjax>#DeltaH^@""_"reaction"=227kJmol^-1#</mathjax></p> <p>Note here that <mathjax>#DeltaH^@""_"reaction"=DeltaH^@""_f" acetylene"#</mathjax>.<br/> So here we have used the thermochemical equations as linear equations to give us the equation that we sought (and thus necessarily the thermodynamic parameters). </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Use Hess's Law and the following information to calculate the change in enthalpy for the reaction 2C + H2 -> C2H2?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>C2H2 + 5/2 O2 -> 2CO2 + H2O Entropy = -1299.6 kJ<br/> C + O2 -> CO2 Entropy = -393.5 kJ<br/> H2 + 1/2 O2 -> H2O Entropy = -285.8 kJ</p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/hess-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Hess' Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="321958" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-10-15T09:14:38" itemprop="dateCreated"> Oct 15, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2C(s) +H_2(g) rarr HC-=CH(g)#</mathjax><br/> <mathjax>#DeltaH^@""_"reaction"=227kJmol^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You have listed <a href="https://socratic.org/chemistry/thermochemistry/entropy">entropy</a> changes for the reaction. In fact, these are values for <mathjax>#DeltaH^@""_"reaction"#</mathjax></p> <p><mathjax>#HC-=CH + 5/2O_2 rarr 2CO_2 + H_2O#</mathjax> <mathjax>#;DeltaH^@""_"reaction"=-1299.6kJmol^-1#</mathjax> <mathjax>#(i)#</mathjax></p> <p><mathjax>#C + O_2 rarr CO_2#</mathjax> <mathjax>#;DeltaH^@""_"reaction"=-393.5kJmol^-1#</mathjax> <mathjax>#(ii)#</mathjax></p> <p><mathjax>#H_2 + 1/2O_2 rarr H_2O#</mathjax> <mathjax>#;DeltaH^@""_"reaction"=-285.6kJmol^-1#</mathjax> <mathjax>#(iii)#</mathjax></p> <p>We want <mathjax>#DeltaH^@#</mathjax> for:</p> <p><mathjax>#2C+H_2 rarr HC-=CH#</mathjax> <mathjax>#;DeltaH^@=??#</mathjax></p> <p>If I do the sum of the given reactions in this manner, <mathjax>#2xx(ii)-(i)+(iii)#</mathjax>, I get the following:</p> <p><mathjax>#2C + cancel(2O_2) +cancel(2CO_2) + cancel(H_2O) +H_2 + cancel(1/2O_2)rarr cancel(2CO_2)+HC-=CH +cancel(H_2O)+ cancel(5/2O_2)#</mathjax></p> <p>Which after cancelling gives:</p> <p><mathjax>#2C(s) +H_2(g) rarr HC-=CH(g)#</mathjax> <mathjax>#DeltaH^@""_"reaction"=227kJmol^-1#</mathjax></p> <p>Note here that <mathjax>#DeltaH^@""_"reaction"=DeltaH^@""_f" acetylene"#</mathjax>.<br/> So here we have used the thermochemical equations as linear equations to give us the equation that we sought (and thus necessarily the thermodynamic parameters). </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/321958" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-hesss-law-applied-in-calculating-enthalpy"> How is Hess's law applied in calculating enthalpy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-compute-hesss-law-calculations"> How do you compute Hess's law calculations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-draw-a-hesss-law-diagram"> How do you draw a Hess's law diagram? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-hesss-law-say-about-the-enthalpy-of-a-reaction"> What does Hess's law say about the enthalpy of a reaction? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-isn-t-hess-s-law-helpful-to-calculate-the-heat-of-reaction-involved-in-conve"> Why isn't Hess's law helpful to calculate the heat of reaction involved in converting a diamond... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-hess-law-useful-to-calculate-enthalpies"> Why is Hess' law useful to calculate enthalpies? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-importance-of-hess-s-law-to-do-thermodynamic-calculations"> What is the importance of Hess's law to do thermodynamic calculations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-equation-for-hess-s-law"> What is the equation for Hess's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-hess-s-law-of-heat-summation"> What is Hess's law of heat summation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-enthalpy-of-mixing-zero"> Why is enthalpy of mixing zero? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/hess-law"> See all questions in Hess' Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 37585 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Use Hess's Law and the following information to calculate the change in enthalpy for the reaction 2C + H2 -> C2H2?	C2H2 + 5/2 O2 -> 2CO2 + H2O Entropy = -1299.6 kJ C + O2 -> CO2 Entropy = -393.5 kJ H2 + 1/2 O2 -> H2O Entropy = -285.8 kJ
2,219	ab65d9b6-6ddd-11ea-8da7-ccda262736ce	https://socratic.org/questions/the-combination-of-coke-and-steam-produces-a-mixture-called-coal-gas-which-can-b	2 C(s) + 2 H2O(g) -> CH4(g) + CO2(g)	start chemical_equation qc_end substance 3 3 qc_end substance 5 5 qc_end substance 10 11 qc_end c_other OTHER qc_end end	[{"type":"other","value":"Chemical Equation [OF] the production"}]	[{"type":"chemical equation","value":"2 C(s) + 2 H2O(g) -> CH4(g) + CO2(g)"}]	[{"type":"substance name","value":"Coke"},{"type":"substance name","value":"Steam"},{"type":"substance name","value":"Coal gas"},{"type":"other","value":"Assume coke can be represented by graphite."}]	<h1 class="questionTitle" itemprop="name">The combination of coke and steam produces a mixture called coal gas, which can be used as a fuel or as a starting material for other reactions. If we assume coke can be represented by graphite, the equation for the production of coal gas is? </h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>The combination of coke and steam produces a mixture called coal gas, which can be<br/> used as a fuel or as a starting material for other reactions. If we assume coke can be<br/> represented by graphite, the equation for the production of coal gas is<br/> (3) CH (g) H O (g) 3 H (g) CO (g) H 206.1kJ<br/> (2) CO (g) H O (g) CO (g) H (g) H - 41.2 kJ<br/> (1) C(s) H O (g) CO (g) H (g) H 131.3 kJ<br/> standard enthalpies of reaction :<br/> Determine the standard enthalpy change for this reaction from the following<br/> 2 C (s) 2 H O (g) CH (g) CO (g)</p></div> </h2> </div> </div>	2 C(s) + 2 H2O(g) -> CH4(g) + CO2(g)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The equation for the formation of coal gas is</p> <p><mathjax>#"2C(s)" + "2H"_2"O(g)" → "CH"_4("g") + "CO"_2("g")#</mathjax></p> <p>This is our target equation. We must create it from equations (1) - (3).</p> <blockquote></blockquote> <p>We start with Equation (1), because it contains <mathjax>#"C(s)"#</mathjax>. We also multiply it by 2 to get <mathjax>#"2C(s)"#</mathjax>. Then we add the other equations to eliminate compounds like <mathjax>#"CO and H"_2#</mathjax> that are not in our target equation:</p> <blockquote></blockquote> <p>2 × (3): <mathjax>#"2C(s)" + "2H"_2"O(g)" → color(red)(cancel(color(black)("2CO(g)"))) + color(blue)(cancel(color(black)("2H"_2"(g)"))); color(white)(mll)ΔH = color(white)(l)"262.6 kJ"#</mathjax><br/> (2): <mathjax>#color(red)(cancel(color(black)("CO(g)"))) + color(orange)(cancel(color(black)("H"_2"O(g)"))) → "CO"_2("g") + color(blue)(cancel(color(black)("H"_2("g"))));color(white)(mmm) ΔH =color(white)(ll) "-41.2 kJ "#</mathjax><br/> -(1): <mathjax>#color(red)(cancel(color(black)("CO(g)"))) + color(blue)(cancel(color(black)("3H"_2"(g)"))) → "CH"_4("g") + color(orange)(cancel(color(black)("H"_2"O(g)"))) ; color(white)(mml)ΔH =color(white)(l) "-206.1 J"#</mathjax><br/> (4): <mathjax>#stackrel(——————————————————)("2C(s)" + "2H"_2"O(g)" → "CH"_4("g") + "CO"_2("g"));color(white)(mmmll) stackrel(———————)(ΔH = "+15.3 kJ")#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#""_"rxn"ΔH = "+15.3 kJ"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The equation for the formation of coal gas is</p> <p><mathjax>#"2C(s)" + "2H"_2"O(g)" → "CH"_4("g") + "CO"_2("g")#</mathjax></p> <p>This is our target equation. We must create it from equations (1) - (3).</p> <blockquote></blockquote> <p>We start with Equation (1), because it contains <mathjax>#"C(s)"#</mathjax>. We also multiply it by 2 to get <mathjax>#"2C(s)"#</mathjax>. Then we add the other equations to eliminate compounds like <mathjax>#"CO and H"_2#</mathjax> that are not in our target equation:</p> <blockquote></blockquote> <p>2 × (3): <mathjax>#"2C(s)" + "2H"_2"O(g)" → color(red)(cancel(color(black)("2CO(g)"))) + color(blue)(cancel(color(black)("2H"_2"(g)"))); color(white)(mll)ΔH = color(white)(l)"262.6 kJ"#</mathjax><br/> (2): <mathjax>#color(red)(cancel(color(black)("CO(g)"))) + color(orange)(cancel(color(black)("H"_2"O(g)"))) → "CO"_2("g") + color(blue)(cancel(color(black)("H"_2("g"))));color(white)(mmm) ΔH =color(white)(ll) "-41.2 kJ "#</mathjax><br/> -(1): <mathjax>#color(red)(cancel(color(black)("CO(g)"))) + color(blue)(cancel(color(black)("3H"_2"(g)"))) → "CH"_4("g") + color(orange)(cancel(color(black)("H"_2"O(g)"))) ; color(white)(mml)ΔH =color(white)(l) "-206.1 J"#</mathjax><br/> (4): <mathjax>#stackrel(——————————————————)("2C(s)" + "2H"_2"O(g)" → "CH"_4("g") + "CO"_2("g"));color(white)(mmmll) stackrel(———————)(ΔH = "+15.3 kJ")#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">The combination of coke and steam produces a mixture called coal gas, which can be used as a fuel or as a starting material for other reactions. If we assume coke can be represented by graphite, the equation for the production of coal gas is? </h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>The combination of coke and steam produces a mixture called coal gas, which can be<br/> used as a fuel or as a starting material for other reactions. If we assume coke can be<br/> represented by graphite, the equation for the production of coal gas is<br/> (3) CH (g) H O (g) 3 H (g) CO (g) H 206.1kJ<br/> (2) CO (g) H O (g) CO (g) H (g) H - 41.2 kJ<br/> (1) C(s) H O (g) CO (g) H (g) H 131.3 kJ<br/> standard enthalpies of reaction :<br/> Determine the standard enthalpy change for this reaction from the following<br/> 2 C (s) 2 H O (g) CH (g) CO (g)</p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="268519" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-22T18:44:15" itemprop="dateCreated"> May 22, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#""_"rxn"ΔH = "+15.3 kJ"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The equation for the formation of coal gas is</p> <p><mathjax>#"2C(s)" + "2H"_2"O(g)" → "CH"_4("g") + "CO"_2("g")#</mathjax></p> <p>This is our target equation. We must create it from equations (1) - (3).</p> <blockquote></blockquote> <p>We start with Equation (1), because it contains <mathjax>#"C(s)"#</mathjax>. We also multiply it by 2 to get <mathjax>#"2C(s)"#</mathjax>. Then we add the other equations to eliminate compounds like <mathjax>#"CO and H"_2#</mathjax> that are not in our target equation:</p> <blockquote></blockquote> <p>2 × (3): <mathjax>#"2C(s)" + "2H"_2"O(g)" → color(red)(cancel(color(black)("2CO(g)"))) + color(blue)(cancel(color(black)("2H"_2"(g)"))); color(white)(mll)ΔH = color(white)(l)"262.6 kJ"#</mathjax><br/> (2): <mathjax>#color(red)(cancel(color(black)("CO(g)"))) + color(orange)(cancel(color(black)("H"_2"O(g)"))) → "CO"_2("g") + color(blue)(cancel(color(black)("H"_2("g"))));color(white)(mmm) ΔH =color(white)(ll) "-41.2 kJ "#</mathjax><br/> -(1): <mathjax>#color(red)(cancel(color(black)("CO(g)"))) + color(blue)(cancel(color(black)("3H"_2"(g)"))) → "CH"_4("g") + color(orange)(cancel(color(black)("H"_2"O(g)"))) ; color(white)(mml)ΔH =color(white)(l) "-206.1 J"#</mathjax><br/> (4): <mathjax>#stackrel(——————————————————)("2C(s)" + "2H"_2"O(g)" → "CH"_4("g") + "CO"_2("g"));color(white)(mmmll) stackrel(———————)(ΔH = "+15.3 kJ")#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/268519" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What is stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ab82402bf342f48d93ac6"> Question #93ac6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-we-study-stoichiometry"> Why do we study stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-naoh-is-produced-from-1-20-x-102-grams-of-na2o-na2o-h2o-2-naoh"> How many grams of NaOH is produced from #1.20 x 10^2# grams of #Na_2O#? #Na_2O + H_2O -> 2NaOH# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-na2o-are-required-to-produce-1-60-x-102-grams-of-naoh-na2o-h2o"> How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? Na2O + H2O ---> 2 NaOH </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-mass-of-iron-is-needed-to-react-with-16-0-grams-of-sulfur-8-fe-s8-8-fes"> What mass of iron is needed to react with 16.0 grams of sulfur? 8 Fe + S8 ---> 8 FeS </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/according-to-8-fe-s8-8-fes-how-many-grams-of-fes-are-produced"> According to 8 Fe + S8 ---> 8 FeS How many grams of FeS are produced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/12-00-moles-of-naclo3-will-produce-how-many-grams-of-o2-2-naclo3-2-nacl-3-o2"> 12.00 moles of NaClO3 will produce how many grams of O2? 2 NaClO3 ---> 2 NaCl + 3 O2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-nacl-are-produced-when-80-0-grams-of-o2-are-produced-2-naclo3-"> How many grams of NaCl are produced when 80.0 grams of O2 are produced? 2 NaClO3 ---> 2 NaCl + 3 O2 </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/stoichiometry"> See all questions in Stoichiometry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 9076 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	The combination of coke and steam produces a mixture called coal gas, which can be used as a fuel or as a starting material for other reactions. If we assume coke can be represented by graphite, the equation for the production of coal gas is?	The combination of coke and steam produces a mixture called coal gas, which can be used as a fuel or as a starting material for other reactions. If we assume coke can be represented by graphite, the equation for the production of coal gas is (3) CH (g) H O (g) 3 H (g) CO (g) H 206.1kJ (2) CO (g) H O (g) CO (g) H (g) H - 41.2 kJ (1) C(s) H O (g) CO (g) H (g) H 131.3 kJ standard enthalpies of reaction : Determine the standard enthalpy change for this reaction from the following 2 C (s) 2 H O (g) CH (g) CO (g)
2,220	ac086e26-6ddd-11ea-9228-ccda262736ce	https://socratic.org/questions/the-temperature-of-a-sample-of-water-changes-from-10-c-to-20-c-when-the-water-ab	10.03 g	start physical_unit 27 28 mass g qc_end physical_unit 4 6 9 10 temperature qc_end physical_unit 4 6 12 13 temperature qc_end physical_unit 4 6 18 19 heat_energy qc_end end	[{"type":"physical unit","value":"Mass [OF] the sample [IN] g"}]	[{"type":"physical unit","value":"10.03 g"}]	[{"type":"physical unit","value":"Temperature1 [OF] water sample [=] \\pu{10 ℃}"},{"type":"physical unit","value":"Temperature2 [OF] water sample [=] \\pu{20 ℃}"},{"type":"physical unit","value":"Absorbed heat [OF] water sample [=] \\pu{420 joules}"}]	<h1 class="questionTitle" itemprop="name">The temperature of a sample of water changes from 10°C to 20°C when the water absorbs 420 joules of heat. What is the mass of the sample?</h1>	null	10.03 g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The problem can be solved using the formula:</p> <p><mathjax>#Q=mCpDeltaT#</mathjax></p> <p>where: </p> <p><mathjax>#Q=heat#</mathjax> <br/> <mathjax>#m=mass#</mathjax><br/> <mathjax>#Cp=sp. heat#</mathjax><br/> <mathjax>#DeltaT=temperature#</mathjax> change <mathjax>#(T_2-T_1)#</mathjax></p> <p>Some data are provided in the problem like <br/> <mathjax>#Q=420#</mathjax> Joules<br/> <mathjax>#T_2=20^oC#</mathjax><br/> <mathjax>#T_1=10^oC#</mathjax><br/> and the <mathjax>##[specific heat](http://socratic.org/chemistry/thermochemistry/specific-heat) of water is known to be #</mathjax>4.186 (J)/(g.^oC)#. (<a href="http://www.calculator.org/property.aspx?name=specific%20heat%20capacity" rel="nofollow" target="_blank">http://www.calculator.org/property.aspx?name=specific%20heat%20capacity</a>)</p> <p>All you have to do is to rearrange the original formula to isolate <mathjax>#m#</mathjax> and to derive the new formula which is;</p> <p><mathjax>#m=(Q)/(CpDeltaT)#</mathjax>, plug in values and make sure to cancel out units.<br/> until you have the desired unit.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#10.03#</mathjax> grams</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The problem can be solved using the formula:</p> <p><mathjax>#Q=mCpDeltaT#</mathjax></p> <p>where: </p> <p><mathjax>#Q=heat#</mathjax> <br/> <mathjax>#m=mass#</mathjax><br/> <mathjax>#Cp=sp. heat#</mathjax><br/> <mathjax>#DeltaT=temperature#</mathjax> change <mathjax>#(T_2-T_1)#</mathjax></p> <p>Some data are provided in the problem like <br/> <mathjax>#Q=420#</mathjax> Joules<br/> <mathjax>#T_2=20^oC#</mathjax><br/> <mathjax>#T_1=10^oC#</mathjax><br/> and the <mathjax>##[specific heat](http://socratic.org/chemistry/thermochemistry/specific-heat) of water is known to be #</mathjax>4.186 (J)/(g.^oC)#. (<a href="http://www.calculator.org/property.aspx?name=specific%20heat%20capacity" rel="nofollow" target="_blank">http://www.calculator.org/property.aspx?name=specific%20heat%20capacity</a>)</p> <p>All you have to do is to rearrange the original formula to isolate <mathjax>#m#</mathjax> and to derive the new formula which is;</p> <p><mathjax>#m=(Q)/(CpDeltaT)#</mathjax>, plug in values and make sure to cancel out units.<br/> until you have the desired unit.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">The temperature of a sample of water changes from 10°C to 20°C when the water absorbs 420 joules of heat. What is the mass of the sample?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/specific-heat" itemprop="url"> <span class="breadcrumb" itemprop="title">Specific Heat</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="233949" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/jarni-renz"><img alt="" class="" src="https://profilepictures.socratic.org/i6OiZQmVRHWljDVlwm8v_WIN_20160301_180231.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/jarni-renz"> Jarni Renz </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-02T10:52:03" itemprop="dateCreated"> Mar 2, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#10.03#</mathjax> grams</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The problem can be solved using the formula:</p> <p><mathjax>#Q=mCpDeltaT#</mathjax></p> <p>where: </p> <p><mathjax>#Q=heat#</mathjax> <br/> <mathjax>#m=mass#</mathjax><br/> <mathjax>#Cp=sp. heat#</mathjax><br/> <mathjax>#DeltaT=temperature#</mathjax> change <mathjax>#(T_2-T_1)#</mathjax></p> <p>Some data are provided in the problem like <br/> <mathjax>#Q=420#</mathjax> Joules<br/> <mathjax>#T_2=20^oC#</mathjax><br/> <mathjax>#T_1=10^oC#</mathjax><br/> and the <mathjax>##[specific heat](http://socratic.org/chemistry/thermochemistry/specific-heat) of water is known to be #</mathjax>4.186 (J)/(g.^oC)#. (<a href="http://www.calculator.org/property.aspx?name=specific%20heat%20capacity" rel="nofollow" target="_blank">http://www.calculator.org/property.aspx?name=specific%20heat%20capacity</a>)</p> <p>All you have to do is to rearrange the original formula to isolate <mathjax>#m#</mathjax> and to derive the new formula which is;</p> <p><mathjax>#m=(Q)/(CpDeltaT)#</mathjax>, plug in values and make sure to cancel out units.<br/> until you have the desired unit.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/233949" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-specific-heat-be-used-to-identify-substances"> How can specific heat be used to identify substances? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-heat-capacity-of-a-lead-sinker-be-determined"> How can the heat capacity of a lead sinker be determined? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-the-specific-heats-of-metals-compare-with-water"> How do the specific heats of metals compare with water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-specific-heat-change-with-temperature"> How does specific heat change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/dissolving-some-potassium-bromide-in-200cm3-of-water-leads-to-a-decrease-in-temp"> Dissolving some potassium bromide in 200cm3 of water leads to a decrease in temperature of 3oC.... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-heat-capacity-larger-for-polymers"> Is heat capacity larger for polymers? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-heat-capacity-an-extensive-property"> Why is heat capacity an extensive property? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-does-heat-capacity-change-with-temperature"> Why does heat capacity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-specific-heat-measured-in"> What is specific heat measured in? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-heat-capacity-measured-in"> What is heat capacity measured in? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/specific-heat"> See all questions in Specific Heat </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 8605 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	The temperature of a sample of water changes from 10°C to 20°C when the water absorbs 420 joules of heat. What is the mass of the sample?	null
2,221	a96c988a-6ddd-11ea-95c1-ccda262736ce	https://socratic.org/questions/how-would-you-write-a-balanced-symbol-equation-for-the-combustion-of-hydrogen	2 H2 + O2 -> 2 H2O	start chemical_equation qc_end substance 12 12 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the combustion"}]	[{"type":"chemical equation","value":"2 H2 + O2 -> 2 H2O"}]	[{"type":"substance name","value":"hydrogen"}]	<h1 class="questionTitle" itemprop="name">How would you write a balanced symbol equation for the combustion of hydrogen?</h1>	null	2 H2 + O2 -> 2 H2O	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>If the half-integral coefficient bothers you, you can always double the entire equation to give...........</p> <p>What does <mathjax>#Delta#</mathjax> represent?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#H_2(g)+1/2O_2(g) rarr H_2O(l) + Delta#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>If the half-integral coefficient bothers you, you can always double the entire equation to give...........</p> <p>What does <mathjax>#Delta#</mathjax> represent?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How would you write a balanced symbol equation for the combustion of hydrogen?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="428150" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-23T02:48:14" itemprop="dateCreated"> May 23, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#H_2(g)+1/2O_2(g) rarr H_2O(l) + Delta#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>If the half-integral coefficient bothers you, you can always double the entire equation to give...........</p> <p>What does <mathjax>#Delta#</mathjax> represent?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/428150" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------> H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -> Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? Aluminum and hydrochloric acid react to form aluminum... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equation-sodium-phosphate-and-calcium-chloride-r"> How can I balance this chemical equation? Sodium phosphate and calcium chloride react to form... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-equation-kclo3-kcl-o2"> How can I balance this equation? ____ #KClO_3 -># ____ #KCl +# ____ #O_2# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-balancing-chemical-equations-important"> Why is balancing chemical equations important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/balancing-chemical-equations"> See all questions in Balancing Chemical Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1587 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How would you write a balanced symbol equation for the combustion of hydrogen?	null
2,222	aa53a1ae-6ddd-11ea-a4f9-ccda262736ce	https://socratic.org/questions/what-is-the-formula-for-sodium-sulfide	Na2S	start chemical_formula qc_end substance 5 6 qc_end end	[{"type":"other","value":"Chemical Formula [OF] sodium sulfide [IN] default"}]	[{"type":"chemical equation","value":"Na2S"}]	[{"type":"substance name","value":"Sodium sulfide"}]	<h1 class="questionTitle" itemprop="name">What is the formula for sodium sulfide?</h1>	null	Na2S	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>When dealing with <a href="http://socratic.org/chemistry/ionic-bonds-and-formulas/ionic-compounds">ionic compounds</a>, it's important to know that the <em>cation</em> is <strong>always</strong> written first and the <em>anion</em> is written second. </p> <p>In this case, <em>sodium</em>,<mathjax>#"Na"#</mathjax>, will be your cations and <strong>sulfide</strong> will be your anion. </p> <p>Now, what exactly is a <em>sulfide anion</em>? </p> <p>As you know, anions that <strong>consist of a single atom</strong> are named using the <em>suffix</em> <strong>-ide</strong>. Removing this suffix will give you the identity of the parent atom, which in this case is <em>sulfur</em>, <mathjax>#"S"#</mathjax>. </p> <p>A quick look in the <a href="http://socratic.org/chemistry/the-periodic-table/the-periodic-table">periodic table</a> will show that sulfur is located in group 16, which means that it has a total of <mathjax>#6#</mathjax> <a href="http://socratic.org/chemistry/the-periodic-table/valence-electrons-and-the-periodic-table">valence electrons</a>. </p> <p>To complete its <a href="http://socratic.org/chemistry/bonding-basics/electrons-in-bonding-and-the-octet-rule">octet</a>, sulfur needs <strong>two more electrons</strong>. This means that the sulfur anion will carry a <mathjax>#2-#</mathjax> charge. </p> <p>Since sodium is located in group 1 of <a href="http://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a>, it will lose its valence electron and form <mathjax>#1+#</mathjax> cations. </p> <p>As you know, <a href="http://socratic.org/chemistry/ionic-bonds-and-formulas/ionic-compounds">ionic compounds</a> <strong>must be neutral</strong>. This means that you need <strong>two sodium cations</strong> to balance the negative charge of the sulfur anion. </p> <p>The ionic formula for <em>sodium sulfide</em> will thus be </p> <blockquote> <p><mathjax>#"Na"_2"S"#</mathjax></p> </blockquote> <p>Sodium sulfide is a yellow in color, but aqueous <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> are colorless. </p> <p><img alt="http://muruganantham.tradeindia.com/yellow-sodium-sulphide-flakes--709535.html" src="https://useruploads.socratic.org/6ggc5VY3S7WmzyF1pNgS_Yellow-Sodium-Sulphide-Flakes-.jpg"/> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Na"_2"S"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>When dealing with <a href="http://socratic.org/chemistry/ionic-bonds-and-formulas/ionic-compounds">ionic compounds</a>, it's important to know that the <em>cation</em> is <strong>always</strong> written first and the <em>anion</em> is written second. </p> <p>In this case, <em>sodium</em>,<mathjax>#"Na"#</mathjax>, will be your cations and <strong>sulfide</strong> will be your anion. </p> <p>Now, what exactly is a <em>sulfide anion</em>? </p> <p>As you know, anions that <strong>consist of a single atom</strong> are named using the <em>suffix</em> <strong>-ide</strong>. Removing this suffix will give you the identity of the parent atom, which in this case is <em>sulfur</em>, <mathjax>#"S"#</mathjax>. </p> <p>A quick look in the <a href="http://socratic.org/chemistry/the-periodic-table/the-periodic-table">periodic table</a> will show that sulfur is located in group 16, which means that it has a total of <mathjax>#6#</mathjax> <a href="http://socratic.org/chemistry/the-periodic-table/valence-electrons-and-the-periodic-table">valence electrons</a>. </p> <p>To complete its <a href="http://socratic.org/chemistry/bonding-basics/electrons-in-bonding-and-the-octet-rule">octet</a>, sulfur needs <strong>two more electrons</strong>. This means that the sulfur anion will carry a <mathjax>#2-#</mathjax> charge. </p> <p>Since sodium is located in group 1 of <a href="http://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a>, it will lose its valence electron and form <mathjax>#1+#</mathjax> cations. </p> <p>As you know, <a href="http://socratic.org/chemistry/ionic-bonds-and-formulas/ionic-compounds">ionic compounds</a> <strong>must be neutral</strong>. This means that you need <strong>two sodium cations</strong> to balance the negative charge of the sulfur anion. </p> <p>The ionic formula for <em>sodium sulfide</em> will thus be </p> <blockquote> <p><mathjax>#"Na"_2"S"#</mathjax></p> </blockquote> <p>Sodium sulfide is a yellow in color, but aqueous <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> are colorless. </p> <p><img alt="http://muruganantham.tradeindia.com/yellow-sodium-sulphide-flakes--709535.html" src="https://useruploads.socratic.org/6ggc5VY3S7WmzyF1pNgS_Yellow-Sodium-Sulphide-Flakes-.jpg"/> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the formula for sodium sulfide?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/determining-formula-and-molar-masses" itemprop="url"> <span class="breadcrumb" itemprop="title">Determining Formula</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="205864" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-30T20:29:12" itemprop="dateCreated"> Dec 30, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Na"_2"S"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>When dealing with <a href="http://socratic.org/chemistry/ionic-bonds-and-formulas/ionic-compounds">ionic compounds</a>, it's important to know that the <em>cation</em> is <strong>always</strong> written first and the <em>anion</em> is written second. </p> <p>In this case, <em>sodium</em>,<mathjax>#"Na"#</mathjax>, will be your cations and <strong>sulfide</strong> will be your anion. </p> <p>Now, what exactly is a <em>sulfide anion</em>? </p> <p>As you know, anions that <strong>consist of a single atom</strong> are named using the <em>suffix</em> <strong>-ide</strong>. Removing this suffix will give you the identity of the parent atom, which in this case is <em>sulfur</em>, <mathjax>#"S"#</mathjax>. </p> <p>A quick look in the <a href="http://socratic.org/chemistry/the-periodic-table/the-periodic-table">periodic table</a> will show that sulfur is located in group 16, which means that it has a total of <mathjax>#6#</mathjax> <a href="http://socratic.org/chemistry/the-periodic-table/valence-electrons-and-the-periodic-table">valence electrons</a>. </p> <p>To complete its <a href="http://socratic.org/chemistry/bonding-basics/electrons-in-bonding-and-the-octet-rule">octet</a>, sulfur needs <strong>two more electrons</strong>. This means that the sulfur anion will carry a <mathjax>#2-#</mathjax> charge. </p> <p>Since sodium is located in group 1 of <a href="http://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a>, it will lose its valence electron and form <mathjax>#1+#</mathjax> cations. </p> <p>As you know, <a href="http://socratic.org/chemistry/ionic-bonds-and-formulas/ionic-compounds">ionic compounds</a> <strong>must be neutral</strong>. This means that you need <strong>two sodium cations</strong> to balance the negative charge of the sulfur anion. </p> <p>The ionic formula for <em>sodium sulfide</em> will thus be </p> <blockquote> <p><mathjax>#"Na"_2"S"#</mathjax></p> </blockquote> <p>Sodium sulfide is a yellow in color, but aqueous <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> are colorless. </p> <p><img alt="http://muruganantham.tradeindia.com/yellow-sodium-sulphide-flakes--709535.html" src="https://useruploads.socratic.org/6ggc5VY3S7WmzyF1pNgS_Yellow-Sodium-Sulphide-Flakes-.jpg"/> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/205864" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-it-possible-to-find-a-molecular-formula-from-molar-mass"> Is it possible to find a molecular formula from molar mass? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5368e0cc02bf34779e175781"> Question #75781 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-common-mistakes-students-make-when-determining-formulas"> What are some common mistakes students make when determining formulas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-formula-of-an-acid"> How can I determine the formula of an acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-chemical-formula-of-a-product"> How can I determine the chemical formula of a product? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-empirical-formula-of-a-compound"> How can I determine the empirical formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-formula-of-a-hydrate"> How can I determine the formula of a hydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-the-empirical-formula-indicate"> What does the empirical formula indicate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-molecule-with-molecular-weight-of-180-18-g-mol-is-analyzed-and-found-to-contai"> A molecule with molecular weight of 180.18 g/mol is analyzed and found to contain 40.00% carbon,... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/do-i-need-to-know-the-number-of-moles-of-each-element-to-determine-the-formula-o"> Do I need to know the number of moles of each element to determine the formula of the compound? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/determining-formula-and-molar-masses"> See all questions in Determining Formula </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 21691 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the formula for sodium sulfide?	null
2,223	aaa2d5ca-6ddd-11ea-9a7c-ccda262736ce	https://socratic.org/questions/how-many-grams-of-silver-chromate-will-precipitate-when-150-ml-of-0-500-m-silver-1	12.44 grams	start physical_unit 4 5 mass g qc_end physical_unit 14 15 9 10 volume qc_end physical_unit 14 15 12 13 molarity qc_end physical_unit 24 25 19 20 volume qc_end physical_unit 24 25 22 23 molarity qc_end end	[{"type":"physical unit","value":"Mass [OF] silver chromate [IN] grams"}]	[{"type":"physical unit","value":"12.44 grams"}]	[{"type":"physical unit","value":"Volume [OF] silver nitrate [=] \\pu{150 mL}"},{"type":"physical unit","value":"Molarity [OF] silver nitrate [=] \\pu{0.500 M}"},{"type":"physical unit","value":"Volume [OF] potassium chromate [=] \\pu{100 mL}"},{"type":"physical unit","value":"Molarity [OF] potassium chromate [=] \\pu{0.400 M}"}]	<h1 class="questionTitle" itemprop="name">How many grams of silver chromate will precipitate when 150 mL of 0.500 M silver nitrate are added to 100 mL of 0.400 M potassium chromate?</h1>	null	12.44 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#2Ag^(+) + CrO_4^(2-) rarr Ag_2CrO_4(s)darr#</mathjax></p> <p>Silver chromate is EXCEPTIONALLY insoluble, and will deposit with alacrity as a brick-red precipitate.</p> <p>And we need equivalent quantities of silver ion and chromate ion.</p> <p><mathjax>#"Moles of silver ion"=150xx10^-3Lxx0.500molL^-1=0.075mol#</mathjax></p> <p><mathjax>#"Moles of chromate ion"=100xx10^-3Lxx0.400molL^-1=0.040mol#</mathjax></p> <p>Clearly, there is EXCESS chromate ion, MORE than 1/2 equiv. And thus all the silver ion will precipitate as silver chromate. </p> <p>Given the <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>, <mathjax>#0.075/2mol#</mathjax> <mathjax>#Ag_2CrO_4#</mathjax> (approx. <mathjax>#12g)#</mathjax> should precipitate......</p> <p>i.e. <mathjax>#0.0375molxx331.73gmol^-1=??g#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>WE need (i) a stoichiometric equation........and should get over <mathjax>#12g#</mathjax> of a brick-red precipitate. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#2Ag^(+) + CrO_4^(2-) rarr Ag_2CrO_4(s)darr#</mathjax></p> <p>Silver chromate is EXCEPTIONALLY insoluble, and will deposit with alacrity as a brick-red precipitate.</p> <p>And we need equivalent quantities of silver ion and chromate ion.</p> <p><mathjax>#"Moles of silver ion"=150xx10^-3Lxx0.500molL^-1=0.075mol#</mathjax></p> <p><mathjax>#"Moles of chromate ion"=100xx10^-3Lxx0.400molL^-1=0.040mol#</mathjax></p> <p>Clearly, there is EXCESS chromate ion, MORE than 1/2 equiv. And thus all the silver ion will precipitate as silver chromate. </p> <p>Given the <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>, <mathjax>#0.075/2mol#</mathjax> <mathjax>#Ag_2CrO_4#</mathjax> (approx. <mathjax>#12g)#</mathjax> should precipitate......</p> <p>i.e. <mathjax>#0.0375molxx331.73gmol^-1=??*g#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many grams of silver chromate will precipitate when 150 mL of 0.500 M silver nitrate are added to 100 mL of 0.400 M potassium chromate?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-reactions-and-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions and Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="411172" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-23T05:43:15" itemprop="dateCreated"> Apr 23, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>WE need (i) a stoichiometric equation........and should get over <mathjax>#12g#</mathjax> of a brick-red precipitate. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#2Ag^(+) + CrO_4^(2-) rarr Ag_2CrO_4(s)darr#</mathjax></p> <p>Silver chromate is EXCEPTIONALLY insoluble, and will deposit with alacrity as a brick-red precipitate.</p> <p>And we need equivalent quantities of silver ion and chromate ion.</p> <p><mathjax>#"Moles of silver ion"=150xx10^-3Lxx0.500molL^-1=0.075mol#</mathjax></p> <p><mathjax>#"Moles of chromate ion"=100xx10^-3Lxx0.400molL^-1=0.040mol#</mathjax></p> <p>Clearly, there is EXCESS chromate ion, MORE than 1/2 equiv. And thus all the silver ion will precipitate as silver chromate. </p> <p>Given the <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>, <mathjax>#0.075/2mol#</mathjax> <mathjax>#Ag_2CrO_4#</mathjax> (approx. <mathjax>#12g)#</mathjax> should precipitate......</p> <p>i.e. <mathjax>#0.0375molxx331.73gmol^-1=??*g#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/411172" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb002bf34694a4fee47"> Question #fee47 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb402bf34694c8c5c15"> Question #c5c15 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb802bf346950519eb9"> Question #19eb9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cbf02bf3469570e2ea2"> Question #e2ea2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc002bf34695a6bc751"> Question #bc751 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc202bf3469570e2ea6"> Question #e2ea6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531e867a02bf342492a08b07"> Question #08b07 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-thermochemical-equation-for-the-combustion-of-benzene"> What is the thermochemical equation for the combustion of benzene? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-reversible"> Why are chemical reactions reversible? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-important"> Why are chemical reactions important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/chemical-reactions-and-equations"> See all questions in Chemical Reactions and Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 6455 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many grams of silver chromate will precipitate when 150 mL of 0.500 M silver nitrate are added to 100 mL of 0.400 M potassium chromate?	null
2,224	a9863d03-6ddd-11ea-9faa-ccda262736ce	https://socratic.org/questions/given-the-reaction-na2s2o3-aq-4cl2-g-5h2o-aq-2nahso4-aq-8hcl-aq-how-many-moles-o	0.03 moles	start physical_unit 3 3 mole mol qc_end chemical_equation 3 15 qc_end physical_unit 6 6 26 27 mole qc_end end	[{"type":"physical unit","value":"Mole [OF] Na2S2O3 [IN] moles"}]	[{"type":"physical unit","value":"0.03 moles"}]	[{"type":"chemical equation","value":"Na2S2O3(aq) + 4 Cl2(g) + 5 H2O(aq) -> 2 NaHSO4(aq) + 8 HCl(aq)"},{"type":"physical unit","value":"Mole [OF] Cl2 [=] \\pu{0.12 mol}"}]	<h1 class="questionTitle" itemprop="name">Given the reaction:Na2S2O3(aq) + 4Cl2(g) + 5H2O(aq) --> 2NaHSO4(aq) + 8HCl(aq), how many moles of Na2S2O3 are needed to react with 0.12mol of Cl2? </h1>	null	0.03 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We can use <a href="http://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio to solve this problem. We will assume that we have excess <mathjax>#H_2O#</mathjax> and it won't effect our ratio. We are told that we will react 0.12 mol of <mathjax>#Cl_2#</mathjax> so we will start there.</p> <p><mathjax>#0.012 mol Cl_2#</mathjax> X <mathjax>#(1 mol Na_2S_2O_3)/(4 mol Cl_2)#</mathjax>= <mathjax>#0.03 molNa_2S_2O_3#</mathjax></p> <p>When setting up the dimensional analysis it is important that you pay attention to how many moles are in the balanced equation, that is the mole ratio.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.03 mol <mathjax>#Na_2S_2O_3#</mathjax> </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We can use <a href="http://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio to solve this problem. We will assume that we have excess <mathjax>#H_2O#</mathjax> and it won't effect our ratio. We are told that we will react 0.12 mol of <mathjax>#Cl_2#</mathjax> so we will start there.</p> <p><mathjax>#0.012 mol Cl_2#</mathjax> X <mathjax>#(1 mol Na_2S_2O_3)/(4 mol Cl_2)#</mathjax>= <mathjax>#0.03 molNa_2S_2O_3#</mathjax></p> <p>When setting up the dimensional analysis it is important that you pay attention to how many moles are in the balanced equation, that is the mole ratio.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Given the reaction:Na2S2O3(aq) + 4Cl2(g) + 5H2O(aq) --> 2NaHSO4(aq) + 8HCl(aq), how many moles of Na2S2O3 are needed to react with 0.12mol of Cl2? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="192043" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/slangus"><img alt="" class="" src="https://profilepictures.socratic.org/drkbgwWiTc2nF7Sd9TrX_1103421756345992.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/slangus"> Slangus </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-22T22:43:47" itemprop="dateCreated"> Nov 22, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.03 mol <mathjax>#Na_2S_2O_3#</mathjax> </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We can use <a href="http://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio to solve this problem. We will assume that we have excess <mathjax>#H_2O#</mathjax> and it won't effect our ratio. We are told that we will react 0.12 mol of <mathjax>#Cl_2#</mathjax> so we will start there.</p> <p><mathjax>#0.012 mol Cl_2#</mathjax> X <mathjax>#(1 mol Na_2S_2O_3)/(4 mol Cl_2)#</mathjax>= <mathjax>#0.03 molNa_2S_2O_3#</mathjax></p> <p>When setting up the dimensional analysis it is important that you pay attention to how many moles are in the balanced equation, that is the mole ratio.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/192043" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What is stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ab82402bf342f48d93ac6"> Question #93ac6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-we-study-stoichiometry"> Why do we study stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-naoh-is-produced-from-1-20-x-102-grams-of-na2o-na2o-h2o-2-naoh"> How many grams of NaOH is produced from #1.20 x 10^2# grams of #Na_2O#? #Na_2O + H_2O -> 2NaOH# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-na2o-are-required-to-produce-1-60-x-102-grams-of-naoh-na2o-h2o"> How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? Na2O + H2O ---> 2 NaOH </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-mass-of-iron-is-needed-to-react-with-16-0-grams-of-sulfur-8-fe-s8-8-fes"> What mass of iron is needed to react with 16.0 grams of sulfur? 8 Fe + S8 ---> 8 FeS </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/according-to-8-fe-s8-8-fes-how-many-grams-of-fes-are-produced"> According to 8 Fe + S8 ---> 8 FeS How many grams of FeS are produced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/12-00-moles-of-naclo3-will-produce-how-many-grams-of-o2-2-naclo3-2-nacl-3-o2"> 12.00 moles of NaClO3 will produce how many grams of O2? 2 NaClO3 ---> 2 NaCl + 3 O2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-nacl-are-produced-when-80-0-grams-of-o2-are-produced-2-naclo3-"> How many grams of NaCl are produced when 80.0 grams of O2 are produced? 2 NaClO3 ---> 2 NaCl + 3 O2 </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/stoichiometry"> See all questions in Stoichiometry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 13289 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Given the reaction:Na2S2O3(aq) + 4Cl2(g) + 5H2O(aq) --> 2NaHSO4(aq) + 8HCl(aq), how many moles of Na2S2O3 are needed to react with 0.12mol of Cl2?	null
2,225	ace45876-6ddd-11ea-b66d-ccda262736ce	https://socratic.org/questions/a-solution-has-h-2-0-10-5-m-how-do-you-find-the-poh-of-this-solution	9.30	start physical_unit 16 17 poh none qc_end physical_unit 16 17 5 8 [h+] qc_end end	[{"type":"physical unit","value":"pOH [OF] this solution"}]	[{"type":"physical unit","value":"9.30"}]	[{"type":"physical unit","value":"[H+] [OF] this solution [=] \\pu{2.0 × 10^(-5) M}"}]	<h1 class="questionTitle" itemprop="name">A solution has #[H^+] = 2.0 * 10^-5# #M#. How do you find the pOH of this solution?</h1>	null	9.30	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You could find the answer one of two ways. The first is using the ion-product constant for water: </p> <blockquote> <p><mathjax>#K_w = ["H"_3"O"^(+)]["OH"^(-)] = 1.0xx10^(-14)#</mathjax></p> </blockquote> <p>Since Kw and the concentration of hydrogen ions in solution are known we can rearrange the equation to solve for the concentration of hydroxide ions. We can do this by dividing Kw by [H+] to solve for [OH-] like so:</p> <p>Kw / [H+] = [OH-]</p> <p><mathjax>#(1.0xx10^(-14))/(2.0xx10^(-5) "M") = 5xx10^(-10) "M"#</mathjax></p> <p>Now we have the concentration of hydroxide ions in solution. To find the pOH, you have to take the -log of that concentration like this:<br/> -log(<mathjax>#5xx10^(-10)#</mathjax> M) = 9.30. Thus, the pOH = 9.30.</p> <p>The second method is much easier. Just take the -log of the concentration of hydrogen ions: -log(<mathjax>#2.0xx10^(-5#</mathjax> M) = 4.70</p> <p>That value represents the <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> of the solution. To obtain the pOH from the pH just do 14 - pH = pOH</p> <p>Then you should arrive at the same answer: 14 - 4.70 = 9.30</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>pOH = 9.30</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You could find the answer one of two ways. The first is using the ion-product constant for water: </p> <blockquote> <p><mathjax>#K_w = ["H"_3"O"^(+)]["OH"^(-)] = 1.0xx10^(-14)#</mathjax></p> </blockquote> <p>Since Kw and the concentration of hydrogen ions in solution are known we can rearrange the equation to solve for the concentration of hydroxide ions. We can do this by dividing Kw by [H+] to solve for [OH-] like so:</p> <p>Kw / [H+] = [OH-]</p> <p><mathjax>#(1.0xx10^(-14))/(2.0xx10^(-5) "M") = 5xx10^(-10) "M"#</mathjax></p> <p>Now we have the concentration of hydroxide ions in solution. To find the pOH, you have to take the -log of that concentration like this:<br/> -log(<mathjax>#5xx10^(-10)#</mathjax> M) = 9.30. Thus, the pOH = 9.30.</p> <p>The second method is much easier. Just take the -log of the concentration of hydrogen ions: -log(<mathjax>#2.0xx10^(-5#</mathjax> M) = 4.70</p> <p>That value represents the <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> of the solution. To obtain the pOH from the pH just do 14 - pH = pOH</p> <p>Then you should arrive at the same answer: 14 - 4.70 = 9.30</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A solution has #[H^+] = 2.0 * 10^-5# #M#. How do you find the pOH of this solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/the-ph-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">pH</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="274097" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/kayla-14"><img alt="" class="" src="https://profilepictures.socratic.org/OvMTWaamQPWcqLIkUNnG_793604964071127.jpg" title=""/></a> <a class="secondContributorPic" href="/users/truong-son-n"><img alt="" class="" src="https://profilepictures.socratic.org/07k4plnQfmnmzMuesQzw_14844-1449381920.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/kayla-14"> Kayla </a>·<a class="topContributorLink" href="/users/truong-son-n"> Truong-Son N. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-05T04:37:15" itemprop="dateCreated"> Jun 5, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>pOH = 9.30</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You could find the answer one of two ways. The first is using the ion-product constant for water: </p> <blockquote> <p><mathjax>#K_w = ["H"_3"O"^(+)]["OH"^(-)] = 1.0xx10^(-14)#</mathjax></p> </blockquote> <p>Since Kw and the concentration of hydrogen ions in solution are known we can rearrange the equation to solve for the concentration of hydroxide ions. We can do this by dividing Kw by [H+] to solve for [OH-] like so:</p> <p>Kw / [H+] = [OH-]</p> <p><mathjax>#(1.0xx10^(-14))/(2.0xx10^(-5) "M") = 5xx10^(-10) "M"#</mathjax></p> <p>Now we have the concentration of hydroxide ions in solution. To find the pOH, you have to take the -log of that concentration like this:<br/> -log(<mathjax>#5xx10^(-10)#</mathjax> M) = 9.30. Thus, the pOH = 9.30.</p> <p>The second method is much easier. Just take the -log of the concentration of hydrogen ions: -log(<mathjax>#2.0xx10^(-5#</mathjax> M) = 4.70</p> <p>That value represents the <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> of the solution. To obtain the pOH from the pH just do 14 - pH = pOH</p> <p>Then you should arrive at the same answer: 14 - 4.70 = 9.30</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/274097" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-pka"> How do you determine pH from pKa? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-ph-values-of-acids-and-bases-differ"> How do pH values of acids and bases differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-something-on-a-ph-scale"> How do you calculate something on a pH scale? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-diprotic-acid"> How do you calculate pH diprotic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-from-acid-dissociation-constant"> How do you calculate pH from acid dissociation constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-of-acid-and-base-solution"> How do you calculate pH of acid and base solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ph-scale-0-14"> Why is the pH scale 0-14? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-ph-the-measure-of-the-hydrogen-ion-concentration"> Is pH a measure of the hydrogen ion concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-solubility-affect-ph"> How does solubility affect pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-ph-relate-to-pka-in-a-titration"> How does pH relate to pKa in a titration? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/the-ph-concept"> See all questions in pH </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 35929 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A solution has #[H^+] = 2.0 * 10^-5# #M#. How do you find the pOH of this solution?	null
2,226	a860357a-6ddd-11ea-b12f-ccda262736ce	https://socratic.org/questions/what-is-the-total-number-of-moles-present-in-a-52-0-gram-sample-of-nan-3	0.80 moles	start physical_unit 12 14 mole mol qc_end physical_unit 12 14 10 11 mass qc_end physical_unit 12 14 18 19 molar_mass qc_end end	[{"type":"physical unit","value":"Mole [OF] NaN3 sample [IN] moles"}]	[{"type":"physical unit","value":"0.80 moles"}]	[{"type":"physical unit","value":"Mass [OF] NaN3 sample [=] \\pu{52.0 gram}"},{"type":"physical unit","value":"Gram-formula mass [OF] NaN3 sample [=] \\pu{65.0 grams/mole}"}]	<h1 class="questionTitle" itemprop="name">What is the total number of moles present in a 52.0 gram sample of #NaN_3#? </h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>Gram-formula mass = 65.0 grams/mole</p></div> </h2> </div> </div>	0.80 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The formula for calculating moles given the mass and a compound is: </p> <blockquote> <p><mathjax>#n = m/M#</mathjax> </p> </blockquote> <p><mathjax>#n#</mathjax> = moles <br/> <mathjax>#m#</mathjax> = mass in grams <mathjax>#("g")#</mathjax> <br/> <mathjax>#M#</mathjax> = molar mass <mathjax>#("g/mol")#</mathjax></p> <p>The molar mass is the sum of all the atomic masses in the compound.</p> <blockquote> <p><mathjax>#"Na" = "22.99 g/mol"#</mathjax><br/> <mathjax>#"N" = "14.01 g/mol" xx 3 ->#</mathjax> (there are <mathjax>#3#</mathjax> <mathjax>#"N"#</mathjax> atoms) </p> </blockquote> <p>Add them up and you get <mathjax>#"65.02 g/mol"#</mathjax></p> <blockquote> <p><mathjax>#n = m/M#</mathjax></p> <blockquote> <p><mathjax># = (52.0 cancel("g"))/(65.02 cancel("g")/"mol")#</mathjax></p> <p><mathjax>#= "0.799753921 moles"#</mathjax></p> <p><mathjax>#= "0.800 moles " ->#</mathjax> (rounded to three sig figs) </p> </blockquote> </blockquote> <p>Therefore, there are <mathjax>#0.800#</mathjax> moles in 52.0g of <mathjax>#"NaN"_3#</mathjax>. </p> <p>I hope this made sense :)</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"0.800 moles"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The formula for calculating moles given the mass and a compound is: </p> <blockquote> <p><mathjax>#n = m/M#</mathjax> </p> </blockquote> <p><mathjax>#n#</mathjax> = moles <br/> <mathjax>#m#</mathjax> = mass in grams <mathjax>#("g")#</mathjax> <br/> <mathjax>#M#</mathjax> = molar mass <mathjax>#("g/mol")#</mathjax></p> <p>The molar mass is the sum of all the atomic masses in the compound.</p> <blockquote> <p><mathjax>#"Na" = "22.99 g/mol"#</mathjax><br/> <mathjax>#"N" = "14.01 g/mol" xx 3 ->#</mathjax> (there are <mathjax>#3#</mathjax> <mathjax>#"N"#</mathjax> atoms) </p> </blockquote> <p>Add them up and you get <mathjax>#"65.02 g/mol"#</mathjax></p> <blockquote> <p><mathjax>#n = m/M#</mathjax></p> <blockquote> <p><mathjax># = (52.0 cancel("g"))/(65.02 cancel("g")/"mol")#</mathjax></p> <p><mathjax>#= "0.799753921 moles"#</mathjax></p> <p><mathjax>#= "0.800 moles " ->#</mathjax> (rounded to three sig figs) </p> </blockquote> </blockquote> <p>Therefore, there are <mathjax>#0.800#</mathjax> moles in 52.0g of <mathjax>#"NaN"_3#</mathjax>. </p> <p>I hope this made sense :)</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the total number of moles present in a 52.0 gram sample of #NaN_3#? </h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>Gram-formula mass = 65.0 grams/mole</p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="336358" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ryuu"><img alt="" class="" src="https://profilepictures.socratic.org/ybMAUPwJSLW0wuAqV5i2_meh.jpg" title=""/></a> <a class="secondContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ryuu"> Ryuu </a>·<a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-11-15T00:43:54" itemprop="dateCreated"> Nov 15, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"0.800 moles"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The formula for calculating moles given the mass and a compound is: </p> <blockquote> <p><mathjax>#n = m/M#</mathjax> </p> </blockquote> <p><mathjax>#n#</mathjax> = moles <br/> <mathjax>#m#</mathjax> = mass in grams <mathjax>#("g")#</mathjax> <br/> <mathjax>#M#</mathjax> = molar mass <mathjax>#("g/mol")#</mathjax></p> <p>The molar mass is the sum of all the atomic masses in the compound.</p> <blockquote> <p><mathjax>#"Na" = "22.99 g/mol"#</mathjax><br/> <mathjax>#"N" = "14.01 g/mol" xx 3 ->#</mathjax> (there are <mathjax>#3#</mathjax> <mathjax>#"N"#</mathjax> atoms) </p> </blockquote> <p>Add them up and you get <mathjax>#"65.02 g/mol"#</mathjax></p> <blockquote> <p><mathjax>#n = m/M#</mathjax></p> <blockquote> <p><mathjax># = (52.0 cancel("g"))/(65.02 cancel("g")/"mol")#</mathjax></p> <p><mathjax>#= "0.799753921 moles"#</mathjax></p> <p><mathjax>#= "0.800 moles " ->#</mathjax> (rounded to three sig figs) </p> </blockquote> </blockquote> <p>Therefore, there are <mathjax>#0.800#</mathjax> moles in 52.0g of <mathjax>#"NaN"_3#</mathjax>. </p> <p>I hope this made sense :)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/336358" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 10689 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the total number of moles present in a 52.0 gram sample of #NaN_3#?	Gram-formula mass = 65.0 grams/mole
2,227	a9130cc1-6ddd-11ea-899a-ccda262736ce	https://socratic.org/questions/5821020e7c014934b54e33d2	0.04 L	start physical_unit 5 5 volume l qc_end physical_unit 5 5 1 2 volume qc_end physical_unit 5 5 10 11 pressure qc_end physical_unit 5 5 23 24 pressure qc_end end	[{"type":"physical unit","value":"Volume2 [OF] gas [IN] L"}]	[{"type":"physical unit","value":"0.04 L"}]	[{"type":"physical unit","value":"Volume1 [OF] gas [=] \\pu{1.32 L}"},{"type":"physical unit","value":"Pressure1 [OF] gas [=] \\pu{1.00 atm}"},{"type":"physical unit","value":"Pressure2 [OF] gas [=] \\pu{30.0 atm}"}]	<h1 class="questionTitle" itemprop="name">A #"1.32 L"# volume of gas has a pressure of #"1.00 atm"#. What will the volume be if the pressure is increased to #"30.0 atm"#?</h1>	null	0.04 L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This question involves <a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's law</a>, which states that the volume of a given amount of gas varies inversely to its pressure as long as the temperature and mass remain constant.</p> <p><img alt="slideplayer.com/2/698879" src="https://useruploads.socratic.org/03W6DyvbR9aaPXG5nTmF_slide_6.jpg"/> </p> <p><mathjax>#P_1="1.00 atm"#</mathjax><br/> <mathjax>#V_1="1.32 L"#</mathjax><br/> <mathjax>#P_2="30.0 atm"#</mathjax><br/> <mathjax>#V_2="???"#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#V_2#</mathjax>. Substitute the known values into the equation and solve.</p> <p><mathjax>#V_2=(P_1V_1)/P_2#</mathjax></p> <p><mathjax>#V_2=(1.00cancel"atm"xx1.32"L")/(30.0cancel"atm")="0.0440 L"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The final volume will be <mathjax>#"0.0440 L"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This question involves <a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's law</a>, which states that the volume of a given amount of gas varies inversely to its pressure as long as the temperature and mass remain constant.</p> <p><img alt="slideplayer.com/2/698879" src="https://useruploads.socratic.org/03W6DyvbR9aaPXG5nTmF_slide_6.jpg"/> </p> <p><mathjax>#P_1="1.00 atm"#</mathjax><br/> <mathjax>#V_1="1.32 L"#</mathjax><br/> <mathjax>#P_2="30.0 atm"#</mathjax><br/> <mathjax>#V_2="???"#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#V_2#</mathjax>. Substitute the known values into the equation and solve.</p> <p><mathjax>#V_2=(P_1V_1)/P_2#</mathjax></p> <p><mathjax>#V_2=(1.00cancel"atm"xx1.32"L")/(30.0cancel"atm")="0.0440 L"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A #"1.32 L"# volume of gas has a pressure of #"1.00 atm"#. What will the volume be if the pressure is increased to #"30.0 atm"#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/boyle-s-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Boyle's Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="333136" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-11-08T02:33:05" itemprop="dateCreated"> Nov 8, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The final volume will be <mathjax>#"0.0440 L"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This question involves <a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's law</a>, which states that the volume of a given amount of gas varies inversely to its pressure as long as the temperature and mass remain constant.</p> <p><img alt="slideplayer.com/2/698879" src="https://useruploads.socratic.org/03W6DyvbR9aaPXG5nTmF_slide_6.jpg"/> </p> <p><mathjax>#P_1="1.00 atm"#</mathjax><br/> <mathjax>#V_1="1.32 L"#</mathjax><br/> <mathjax>#P_2="30.0 atm"#</mathjax><br/> <mathjax>#V_2="???"#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#V_2#</mathjax>. Substitute the known values into the equation and solve.</p> <p><mathjax>#V_2=(P_1V_1)/P_2#</mathjax></p> <p><mathjax>#V_2=(1.00cancel"atm"xx1.32"L")/(30.0cancel"atm")="0.0440 L"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/333136" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-graph-boyles-law"> How do you graph Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-functional-groups-are-found-in-lipids"> What functional groups are found in lipids? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-k-constant-in-boyle-s-law"> Why is k constant in Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-boyle-s-law-graph-curved-1"> Why is Boyle's law graph curved? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-boyle-s-law-an-inverse-relationship-2"> Why is Boyle's law an inverse relationship? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-40-0-l-tank-of-ammonia-has-a-pressure-of-8-00-atm-calculate-the-volume-of-the-"> A 40.0 L tank of ammonia has a pressure of 8.00 atm. Calculate the volume of the ammonia if its... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-charles-law-different-from-boyle-s-law"> How is Charles' law different from Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-boyle-s-law-written-mathematically"> How is Boyle's law written mathematically? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-temperature-affect-boyle-s-law"> How does temperature affect Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-boyle-s-law-relate-to-ventilation"> How does Boyle's law relate to ventilation? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/boyle-s-law"> See all questions in Boyle's Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 7079 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A #"1.32 L"# volume of gas has a pressure of #"1.00 atm"#. What will the volume be if the pressure is increased to #"30.0 atm"#?	null
2,228	abe679a9-6ddd-11ea-8ad5-ccda262736ce	https://socratic.org/questions/referring-to-the-following-information-if-a-0-1593-gram-sample-of-sodium-carbona	0.10 M	start physical_unit 29 30 concentration mol/l qc_end physical_unit 13 13 7 8 mass qc_end physical_unit 18 19 15 16 volume qc_end c_other OTHER qc_end chemical_equation 31 41 qc_end end	[{"type":"physical unit","value":"Precise concentration [OF] the acid [IN] M"}]	[{"type":"physical unit","value":"0.10 M"}]	[{"type":"physical unit","value":"Mass [OF] Na2CO3 sample [=] \\pu{0.1593 grams}"},{"type":"physical unit","value":"Volume [OF] HCl solution [=] \\pu{31.45 mL}"},{"type":"other","value":"Complete neutralization."},{"type":"chemical equation","value":"Na2CO3 + 2 HCl2 -> 2 NaCl + CO2 + H2O"}]	<h1 class="questionTitle" itemprop="name">Referring to the following information, if a 0.1593 gram sample of sodium carbonate, #Na_2CO_3# requires 31.45 mL of #HCl# solution for complete neutralization, what is the precise concentration of the acid? </h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>A student must prepare a solution of HCl whose concentration will be precisely known. He prepares a liter of solution which is approximately 0.1 M, and uses it to titrate precisely weighed samples of sodium carbonate, <mathjax>#Na_2CO_3#</mathjax>. <mathjax>#Na_2CO_3 + 2HCl_2 -> 2NaCl + CO_2 + H_2O#</mathjax></p></div> </h2> </div> </div>	0.10 M	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>First,</strong><br/> convert the grams of <mathjax>#Na_2CO_3#</mathjax> to moles </p> <p>to do so, divide the given grams by the molar mass of <mathjax>#Na_2CO_3#</mathjax></p> <p>0.1593 g / 106 g/mol = 0.001503 mol <mathjax>#Na_2CO_3#</mathjax></p> <p><strong>Second,</strong><br/> use molar ratio to find the moles of <mathjax>#HCl#</mathjax></p> <p>0.001503 mol <mathjax>#Na_2CO_3#</mathjax> x <mathjax>#(2 mol HCl)/(1molNa_2CO_3)#</mathjax> = 0.003006 mol <mathjax>#HCl#</mathjax></p> <p><strong>Third,</strong><br/> use the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a> formula to calculate the concentration of HCl</p> <p><mathjax>#c = (mol)/L = (0.003006mol)/(0.03145 L)#</mathjax> = 0.09558 M</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.09558 M</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>First,</strong><br/> convert the grams of <mathjax>#Na_2CO_3#</mathjax> to moles </p> <p>to do so, divide the given grams by the molar mass of <mathjax>#Na_2CO_3#</mathjax></p> <p>0.1593 g / 106 g/mol = 0.001503 mol <mathjax>#Na_2CO_3#</mathjax></p> <p><strong>Second,</strong><br/> use molar ratio to find the moles of <mathjax>#HCl#</mathjax></p> <p>0.001503 mol <mathjax>#Na_2CO_3#</mathjax> x <mathjax>#(2 mol HCl)/(1molNa_2CO_3)#</mathjax> = 0.003006 mol <mathjax>#HCl#</mathjax></p> <p><strong>Third,</strong><br/> use the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a> formula to calculate the concentration of HCl</p> <p><mathjax>#c = (mol)/L = (0.003006mol)/(0.03145 L)#</mathjax> = 0.09558 M</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Referring to the following information, if a 0.1593 gram sample of sodium carbonate, #Na_2CO_3# requires 31.45 mL of #HCl# solution for complete neutralization, what is the precise concentration of the acid? </h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>A student must prepare a solution of HCl whose concentration will be precisely known. He prepares a liter of solution which is approximately 0.1 M, and uses it to titrate precisely weighed samples of sodium carbonate, <mathjax>#Na_2CO_3#</mathjax>. <mathjax>#Na_2CO_3 + 2HCl_2 -> 2NaCl + CO_2 + H_2O#</mathjax></p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#reactions-in-solution" itemprop="url"> <span class="breadcrumb" itemprop="title">Reactions in Solution</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/reactions-in-solution/titration-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">Titration Calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="529497" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/kai-12"><img alt="" class="" src="https://profilepictures.socratic.org/sPfa5LVCTsaJw9GVGTcy_tumblr_n6phblVObs1smkr46o1_1280.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/kai-12"> kai </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-01-02T20:15:59" itemprop="dateCreated"> Jan 2, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.09558 M</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>First,</strong><br/> convert the grams of <mathjax>#Na_2CO_3#</mathjax> to moles </p> <p>to do so, divide the given grams by the molar mass of <mathjax>#Na_2CO_3#</mathjax></p> <p>0.1593 g / 106 g/mol = 0.001503 mol <mathjax>#Na_2CO_3#</mathjax></p> <p><strong>Second,</strong><br/> use molar ratio to find the moles of <mathjax>#HCl#</mathjax></p> <p>0.001503 mol <mathjax>#Na_2CO_3#</mathjax> x <mathjax>#(2 mol HCl)/(1molNa_2CO_3)#</mathjax> = 0.003006 mol <mathjax>#HCl#</mathjax></p> <p><strong>Third,</strong><br/> use the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a> formula to calculate the concentration of HCl</p> <p><mathjax>#c = (mol)/L = (0.003006mol)/(0.03145 L)#</mathjax> = 0.09558 M</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/529497" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-do-acid-base-titration-calculations"> How do you do acid base titration calculations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-use-titration-calculations-to-find-ph"> How do you use titration calculations to find pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/radox-titration"> What is a redox titration and what is it used for? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-titration-used-when-standardizing-a-solution"> Why is titration used when standardizing a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-titration-suitable-for-sodium-nitrate"> Is titration suitable for sodium nitrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-do-redox-titration-calculations"> How can I do redox titration calculations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-titration-of-weak-acid-and-strong-base"> How can I calculate the titration of a weak acid and a strong base? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-make-back-titration-calculations"> How can I make back titration calculations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-titration-affect-molarity"> How does titration affect molarity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-endpoint-of-a-titration-differ-from-the-equivalence-point"> How does the endpoint of a titration differ from the equivalence point? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/reactions-in-solution/titration-calculations"> See all questions in Titration Calculations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 9867 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Referring to the following information, if a 0.1593 gram sample of sodium carbonate, #Na_2CO_3# requires 31.45 mL of #HCl# solution for complete neutralization, what is the precise concentration of the acid?	A student must prepare a solution of HCl whose concentration will be precisely known. He prepares a liter of solution which is approximately 0.1 M, and uses it to titrate precisely weighed samples of sodium carbonate, #Na_2CO_3#. #Na_2CO_3 + 2HCl_2 -> 2NaCl + CO_2 + H_2O#
2,229	a8a6ac00-6ddd-11ea-9f5c-ccda262736ce	https://socratic.org/questions/how-do-you-calculate-the-molar-solubility-of-alop-4	7.94 × 10^(-10) M	start physical_unit 8 8 molar_solubility mol/l qc_end chemical_equation 8 8 qc_end end	[{"type":"physical unit","value":"Molar solubility [OF] AlPO4 [IN] M"}]	[{"type":"physical unit","value":"7.94 × 10^(-10) M"}]	[{"type":"chemical equation","value":"AlPO4"}]	<h1 class="questionTitle" itemprop="name">How do you calculate the molar solubility of #AlPO_4#?</h1>	null	7.94 × 10^(-10) M	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#AlPO_4 rightleftharpoons Al^(3+) + PO_4^(3-)#</mathjax><br/> <mathjax>#K_(sp) = [Al^(3+)][PO_4^(3-)] = (x)(x) = x^2#</mathjax> <br/> => <mathjax>#x#</mathjax> = Solubility = <mathjax>#sqrt(K_(sp))#</mathjax><br/> <mathjax>#K_(sp)(AlPO_4) = 6.3x10^(-19)#</mathjax><br/> => Solubility = <mathjax>#sqrt(6.3x10^(-19))M = 7.94x10^(-10)M#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Molar Solubility of 1:1 ionization ratio = <mathjax>#sqrt(K_(sp)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#AlPO_4 rightleftharpoons Al^(3+) + PO_4^(3-)#</mathjax><br/> <mathjax>#K_(sp) = [Al^(3+)][PO_4^(3-)] = (x)(x) = x^2#</mathjax> <br/> => <mathjax>#x#</mathjax> = Solubility = <mathjax>#sqrt(K_(sp))#</mathjax><br/> <mathjax>#K_(sp)(AlPO_4) = 6.3x10^(-19)#</mathjax><br/> => Solubility = <mathjax>#sqrt(6.3x10^(-19))M = 7.94x10^(-10)M#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you calculate the molar solubility of #AlPO_4#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/factors-affecting-solubility" itemprop="url"> <span class="breadcrumb" itemprop="title">Factors Affecting Solubility</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="425347" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/doc048"><img alt="" class="" src="https://profilepictures.socratic.org/e4gaeUMMQESTpfte6aRu_Friendly%20Chem%20Professor.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/doc048"> Doc048 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-18T03:30:04" itemprop="dateCreated"> May 18, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Molar Solubility of 1:1 ionization ratio = <mathjax>#sqrt(K_(sp)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#AlPO_4 rightleftharpoons Al^(3+) + PO_4^(3-)#</mathjax><br/> <mathjax>#K_(sp) = [Al^(3+)][PO_4^(3-)] = (x)(x) = x^2#</mathjax> <br/> => <mathjax>#x#</mathjax> = Solubility = <mathjax>#sqrt(K_(sp))#</mathjax><br/> <mathjax>#K_(sp)(AlPO_4) = 6.3x10^(-19)#</mathjax><br/> => Solubility = <mathjax>#sqrt(6.3x10^(-19))M = 7.94x10^(-10)M#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/425347" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-factors-affect-solubility-in-a-solid-liquid-combination"> What factors affect solubility in a solid-liquid combination? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-factors-affect-solubility-in-water"> What factors affect solubility in water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-factors-affect-solubility-of-ionic-compounds"> What factors affect solubility of ionic compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-factors-affect-the-solubility-of-gases-in-liquids"> What factors affect the solubility of gases in liquids? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-factors-affect-the-solubility-of-a-solid"> What factors affect the solubility of a solid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-solubility-of-potassium-nitrate"> How can I calculate solubility of potassium nitrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-the-solubility-of-kno3-depend-on"> What does the solubility of KNO3 depend on? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-solubility-of-a-solution"> How can I calculate the solubility of solute in a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-solubility-is-affected-by-polymer-chain-structure"> How is solubility affected by polymer chain structure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/does-solubility-differ-from-molar-solubility"> Does solubility differ from molar solubility? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/factors-affecting-solubility"> See all questions in Factors Affecting Solubility </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1202 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How do you calculate the molar solubility of #AlPO_4#?	null
2,230	ab4664e5-6ddd-11ea-ba0b-ccda262736ce	https://socratic.org/questions/what-is-the-ph-of-a-solution-with-a-hydronium-concentration-of-8-6-times-10-8-m	5.1	start physical_unit 6 6 ph none qc_end physical_unit 9 9 12 15 concentration qc_end end	[{"type":"physical unit","value":"pH [OF] the solution"}]	[{"type":"physical unit","value":"5.1"}]	[{"type":"physical unit","value":"Concentration [OF] hydronium [=] \\pu{8.6 × 10^(-8) M}"}]	<h1 class="questionTitle" itemprop="name">What is the pH of a solution with a hydronium concentration of #8.6 times 10^-8# #M#?</h1>	null	5.1	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>By definition ...</p> <p>pH = - log[Hydronium ion] = - log(8.6E-6) = -(-5.1) = 5.1</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> = 5.1</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>By definition ...</p> <p>pH = - log[Hydronium ion] = - log(8.6E-6) = -(-5.1) = 5.1</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the pH of a solution with a hydronium concentration of #8.6 times 10^-8# #M#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/ph-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">pH calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="427312" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/doc048"><img alt="" class="" src="https://profilepictures.socratic.org/e4gaeUMMQESTpfte6aRu_Friendly%20Chem%20Professor.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/doc048"> Doc048 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-21T18:04:59" itemprop="dateCreated"> May 21, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> = 5.1</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>By definition ...</p> <p>pH = - log[Hydronium ion] = - log(8.6E-6) = -(-5.1) = 5.1</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/427312" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-of-a-solution"> How do you determine ph of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-at-an-equivalence-point"> How do you determine pH at an equivalence point? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-molarity"> How do you determine pH from molarity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-alkalinity-mean"> What does alkalinity mean? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-base"> What is a base? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-acid-base-indicators-change-color"> How do acid base indicators change color? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-neutral-ph"> What is a neutral pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-alkalinity-affect-pool-water"> How does alkalinity affect pool water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ph-important-in-drinking-water"> Why is pH important in drinking water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-ph-of-solution"> How can I calculate the pH of a solution? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/ph-calculations"> See all questions in pH calculations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2867 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the pH of a solution with a hydronium concentration of #8.6 times 10^-8# #M#?	null
2,231	a8e83c9a-6ddd-11ea-971a-ccda262736ce	https://socratic.org/questions/a-reaction-of-53-1-g-of-na-and-35-7-g-of-br-2-yields-40-g-of-nabr-what-is-the-pe	16.81%	start physical_unit 1 1 percent_yield none qc_end physical_unit 5 5 3 4 mass qc_end physical_unit 10 10 7 8 mass qc_end physical_unit 15 15 12 13 mass qc_end end	[{"type":"physical unit","value":"Percentage yield [OF] the reaction"}]	[{"type":"physical unit","value":"16.81%"}]	[{"type":"physical unit","value":"Mass [OF] Na [=] \\pu{53.1 g}"},{"type":"physical unit","value":"Mass [OF] Br2 [=] \\pu{35.7 g}"},{"type":"physical unit","value":"Mass [OF] NaBr [=] \\pu{40 g}"}]	<h1 class="questionTitle" itemprop="name">A reaction of #53.1 "g"# of #"Na"# and #35.7 "g"# of #"Br"_2# yields #40 "g"# of #"NaBr"#. What is the percentage yield?</h1>	null	16.81%	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to work out the percentage yield of a reaction, we must use the following formula:</p> <p><mathjax>#% "yield": "yield from reaction"/("theoretical yield")xx100#</mathjax></p> <p>Now we must work out the theoretical yield of <mathjax>#"NaBr"#</mathjax></p> <p>We start by writing a balanced equation for the reaction</p> <p><mathjax>#2"Na" color(white)(a)+ color(white)(a) "Br"_2 color(white)(a)rarr color(white)(a)2"NaBr"#</mathjax> </p> <p>As we can see, the <a href="http://www.chemteam.info/Stoichiometry/Molar-Ratio.html" rel="nofollow">molar ratio</a> of <mathjax>#"Na " : " NaBr"#</mathjax> is <mathjax>#1:1#</mathjax>, so we shall use these two molecules to work out the theoretical yield. </p> <p>Now that we have the balanced equation, we must work out how many <a href="https://en.wikipedia.org/wiki/Mole_%28unit%29" rel="nofollow">moles</a> we have of any reagent (in this case, sodium). </p> <p>Moles can be worked out using this formula:</p> <p><mathjax>#"n" ("moles")=("m " ("mass"))/("M (atomic mass)")#</mathjax></p> <p>For sodium:</p> <p><mathjax>#"n"=53.1/23=2.31#</mathjax></p> <p>Now that we have the moles of sodium, we can work out the moles of sodium bromide. Since the molar ratio is <mathjax>#1:1#</mathjax>, the rules of <a href="http://chem.libretexts.org/Core/Inorganic_Chemistry/Chemical_Reactions/Stoichiometry_and_Balancing_Reactions" rel="nofollow">stoichiometry</a> tell us that we also have <mathjax>#2.31#</mathjax> moles of <mathjax>#"NaBr"#</mathjax>.</p> <p>We have the moles and the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">atomic mass</a> of <mathjax>#"NaBr"#</mathjax>, but we don't have the mass. However, we can easily rearrange the formula for moles.</p> <p><mathjax>#"n"="m"/"M"#</mathjax></p> <p><mathjax>#"m"="n"xx"M"=2.31xx103=237.93 " g"#</mathjax></p> <p>Finally, we can work out the percentage yield</p> <p><mathjax>#% " yield"=40/237.93xx100=16.8%#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#16.8%#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to work out the percentage yield of a reaction, we must use the following formula:</p> <p><mathjax>#% "yield": "yield from reaction"/("theoretical yield")xx100#</mathjax></p> <p>Now we must work out the theoretical yield of <mathjax>#"NaBr"#</mathjax></p> <p>We start by writing a balanced equation for the reaction</p> <p><mathjax>#2"Na" color(white)(a)+ color(white)(a) "Br"_2 color(white)(a)rarr color(white)(a)2"NaBr"#</mathjax> </p> <p>As we can see, the <a href="http://www.chemteam.info/Stoichiometry/Molar-Ratio.html" rel="nofollow">molar ratio</a> of <mathjax>#"Na " : " NaBr"#</mathjax> is <mathjax>#1:1#</mathjax>, so we shall use these two molecules to work out the theoretical yield. </p> <p>Now that we have the balanced equation, we must work out how many <a href="https://en.wikipedia.org/wiki/Mole_%28unit%29" rel="nofollow">moles</a> we have of any reagent (in this case, sodium). </p> <p>Moles can be worked out using this formula:</p> <p><mathjax>#"n" ("moles")=("m " ("mass"))/("M (atomic mass)")#</mathjax></p> <p>For sodium:</p> <p><mathjax>#"n"=53.1/23=2.31#</mathjax></p> <p>Now that we have the moles of sodium, we can work out the moles of sodium bromide. Since the molar ratio is <mathjax>#1:1#</mathjax>, the rules of <a href="http://chem.libretexts.org/Core/Inorganic_Chemistry/Chemical_Reactions/Stoichiometry_and_Balancing_Reactions" rel="nofollow">stoichiometry</a> tell us that we also have <mathjax>#2.31#</mathjax> moles of <mathjax>#"NaBr"#</mathjax>.</p> <p>We have the moles and the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">atomic mass</a> of <mathjax>#"NaBr"#</mathjax>, but we don't have the mass. However, we can easily rearrange the formula for moles.</p> <p><mathjax>#"n"="m"/"M"#</mathjax></p> <p><mathjax>#"m"="n"xx"M"=2.31xx103=237.93 " g"#</mathjax></p> <p>Finally, we can work out the percentage yield</p> <p><mathjax>#% " yield"=40/237.93xx100=16.8%#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A reaction of #53.1 "g"# of #"Na"# and #35.7 "g"# of #"Br"_2# yields #40 "g"# of #"NaBr"#. What is the percentage yield?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/percent-yield" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Yield</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="338020" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/abdur-r"><img alt="" class="" src="https://profilepictures.socratic.org/YXIUDMM0SoZAxTdY3kn6_niagara_falls_fog_water_height_6376_3840x2160.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/abdur-r"> Monzur R. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-11-17T21:25:45" itemprop="dateCreated"> Nov 17, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#16.8%#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to work out the percentage yield of a reaction, we must use the following formula:</p> <p><mathjax>#% "yield": "yield from reaction"/("theoretical yield")xx100#</mathjax></p> <p>Now we must work out the theoretical yield of <mathjax>#"NaBr"#</mathjax></p> <p>We start by writing a balanced equation for the reaction</p> <p><mathjax>#2"Na" color(white)(a)+ color(white)(a) "Br"_2 color(white)(a)rarr color(white)(a)2"NaBr"#</mathjax> </p> <p>As we can see, the <a href="http://www.chemteam.info/Stoichiometry/Molar-Ratio.html" rel="nofollow">molar ratio</a> of <mathjax>#"Na " : " NaBr"#</mathjax> is <mathjax>#1:1#</mathjax>, so we shall use these two molecules to work out the theoretical yield. </p> <p>Now that we have the balanced equation, we must work out how many <a href="https://en.wikipedia.org/wiki/Mole_%28unit%29" rel="nofollow">moles</a> we have of any reagent (in this case, sodium). </p> <p>Moles can be worked out using this formula:</p> <p><mathjax>#"n" ("moles")=("m " ("mass"))/("M (atomic mass)")#</mathjax></p> <p>For sodium:</p> <p><mathjax>#"n"=53.1/23=2.31#</mathjax></p> <p>Now that we have the moles of sodium, we can work out the moles of sodium bromide. Since the molar ratio is <mathjax>#1:1#</mathjax>, the rules of <a href="http://chem.libretexts.org/Core/Inorganic_Chemistry/Chemical_Reactions/Stoichiometry_and_Balancing_Reactions" rel="nofollow">stoichiometry</a> tell us that we also have <mathjax>#2.31#</mathjax> moles of <mathjax>#"NaBr"#</mathjax>.</p> <p>We have the moles and the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">atomic mass</a> of <mathjax>#"NaBr"#</mathjax>, but we don't have the mass. However, we can easily rearrange the formula for moles.</p> <p><mathjax>#"n"="m"/"M"#</mathjax></p> <p><mathjax>#"m"="n"xx"M"=2.31xx103=237.93 " g"#</mathjax></p> <p>Finally, we can work out the percentage yield</p> <p><mathjax>#% " yield"=40/237.93xx100=16.8%#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/338020" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ebd02bf3469570e2e62"> Question #e2e62 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ec502bf34694a4fee2e"> Question #fee2e </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ec902bf34694a4fee32"> Question #fee32 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ece02bf346950519e89"> Question #19e89 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ed302bf34694c8c5bdc"> Question #c5bdc </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ee302bf3469517a1065"> Question #a1065 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-would-be-the-limiting-reagent-if-26-0-grams-of-c3h9n-were-reacted-with-46-3"> What would be the limiting reagent if 26.0 grams of C3H9N were reacted with 46.3 grams of... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-percent-yield-always-less-than-100"> Is percent yield always less than 100? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-would-be-the-limiting-reagent-if-41-9-grams-of-c2h3of-were-reacted-with-61-"> What would be the limiting reagent if 41.9 grams of C2H3OF were reacted with 61.0 grams of... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-yield-of-the-following-reaction-if-60-grams-of-caco3-is-heat"> What is the percent yield of the following reaction if 60 grams of CaCO3 is heated to give 15... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/percent-yield"> See all questions in Percent Yield </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 4630 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A reaction of #53.1 "g"# of #"Na"# and #35.7 "g"# of #"Br"_2# yields #40 "g"# of #"NaBr"#. What is the percentage yield?	null
2,232	aade8437-6ddd-11ea-a0be-ccda262736ce	https://socratic.org/questions/how-do-you-write-an-equation-to-represent-ammonia-reacts-with-hydrochloric-acid-	NH3 + HCl -> NH4Cl	start chemical_equation qc_end substance 8 8 qc_end substance 11 12 qc_end substance 15 16 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the equation"}]	[{"type":"chemical equation","value":"NH3 + HCl -> NH4Cl"}]	[{"type":"substance name","value":"Ammonia"},{"type":"substance name","value":"Hydrochloric acid"},{"type":"substance name","value":"Ammonium chloride"}]	<h1 class="questionTitle" itemprop="name">How do you write an equation to represent "Ammonia reacts with hydrochloric acid to form ammonium chloride"?</h1>	null	NH3 + HCl -> NH4Cl	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to write the chemical equation, you need to know the correct chemical formulas for each compound.</p> <p><mathjax>#"Ammonia":#</mathjax><mathjax>#"NH"_3"#</mathjax><br/> <mathjax>#"Hydrochloric acid":#</mathjax><mathjax>#"HCl"#</mathjax><br/> <mathjax>#"Ammonium chloride":#</mathjax><mathjax>#"NH"_4"Cl"#</mathjax></p> <p>Now write the formulas in the order stated in the word equation.</p> <p><mathjax>#"NH"_3" + HCl"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"NH"_4"Cl"#</mathjax></p> <p>The equation is already balanced as written.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"NH"_3" + HCl"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"NH"_4"Cl"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to write the chemical equation, you need to know the correct chemical formulas for each compound.</p> <p><mathjax>#"Ammonia":#</mathjax><mathjax>#"NH"_3"#</mathjax><br/> <mathjax>#"Hydrochloric acid":#</mathjax><mathjax>#"HCl"#</mathjax><br/> <mathjax>#"Ammonium chloride":#</mathjax><mathjax>#"NH"_4"Cl"#</mathjax></p> <p>Now write the formulas in the order stated in the word equation.</p> <p><mathjax>#"NH"_3" + HCl"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"NH"_4"Cl"#</mathjax></p> <p>The equation is already balanced as written.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you write an equation to represent "Ammonia reacts with hydrochloric acid to form ammonium chloride"?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-reactions-and-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions and Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="205999" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-31T03:11:00" itemprop="dateCreated"> Dec 31, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"NH"_3" + HCl"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"NH"_4"Cl"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to write the chemical equation, you need to know the correct chemical formulas for each compound.</p> <p><mathjax>#"Ammonia":#</mathjax><mathjax>#"NH"_3"#</mathjax><br/> <mathjax>#"Hydrochloric acid":#</mathjax><mathjax>#"HCl"#</mathjax><br/> <mathjax>#"Ammonium chloride":#</mathjax><mathjax>#"NH"_4"Cl"#</mathjax></p> <p>Now write the formulas in the order stated in the word equation.</p> <p><mathjax>#"NH"_3" + HCl"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"NH"_4"Cl"#</mathjax></p> <p>The equation is already balanced as written.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/205999" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="206023" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/veddesh-1"><img alt="" class="" src="https://profilepictures.socratic.org/MjafVNH7QOaeb7whyr6R_sef.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/veddesh-1"> Veddesh #phi# </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-31T04:50:39" itemprop="dateCreated"> Dec 31, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#NH_3#</mathjax>+<mathjax>#HCl#</mathjax>=<mathjax>#NH_4Cl#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/206023" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb002bf34694a4fee47"> Question #fee47 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb402bf34694c8c5c15"> Question #c5c15 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb802bf346950519eb9"> Question #19eb9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cbf02bf3469570e2ea2"> Question #e2ea2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc002bf34695a6bc751"> Question #bc751 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc202bf3469570e2ea6"> Question #e2ea6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531e867a02bf342492a08b07"> Question #08b07 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-thermochemical-equation-for-the-combustion-of-benzene"> What is the thermochemical equation for the combustion of benzene? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-reversible"> Why are chemical reactions reversible? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-important"> Why are chemical reactions important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/chemical-reactions-and-equations"> See all questions in Chemical Reactions and Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 16092 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How do you write an equation to represent "Ammonia reacts with hydrochloric acid to form ammonium chloride"?	null
2,233	a8bd14b6-6ddd-11ea-98bb-ccda262736ce	https://socratic.org/questions/what-is-the-concentration-of-nitrate-ions-in-a-3-79m-mg-no-3-2-solution	7.58 M	start physical_unit 5 6 concentration mol/l qc_end physical_unit 11 12 9 10 concentration qc_end end	[{"type":"physical unit","value":"Concentration [OF] nitrate ions [IN] M"}]	[{"type":"physical unit","value":"7.58 M"}]	[{"type":"physical unit","value":"Concentration [OF] Mg(NO3)2 solution [=] \\pu{3.79 M}"}]	<h1 class="questionTitle" itemprop="name">What is the concentration of nitrate ions in a 3.79M #Mg(NO_3)_2# solution?</h1>	null	7.58 M	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#Mg(NO_3)_2(s) rarr Mg^(2+) + 2NO_3^-#</mathjax></p> <p><mathjax>#[Mg^(2+)] = 3.79 mol*L^-1; [NO_3^-] = ??#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>If the solution has a concentration of <mathjax>#3.79#</mathjax> <mathjax>#mol#</mathjax> <mathjax>#L^-1#</mathjax> in <mathjax>#Mg(NO_3)_2#</mathjax>, then the concentration of the nitrate is twice this value. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#Mg(NO_3)_2(s) rarr Mg^(2+) + 2NO_3^-#</mathjax></p> <p><mathjax>#[Mg^(2+)] = 3.79 mol*L^-1; [NO_3^-] = ??#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the concentration of nitrate ions in a 3.79M #Mg(NO_3)_2# solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="194595" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-30T07:18:02" itemprop="dateCreated"> Nov 30, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>If the solution has a concentration of <mathjax>#3.79#</mathjax> <mathjax>#mol#</mathjax> <mathjax>#L^-1#</mathjax> in <mathjax>#Mg(NO_3)_2#</mathjax>, then the concentration of the nitrate is twice this value. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#Mg(NO_3)_2(s) rarr Mg^(2+) + 2NO_3^-#</mathjax></p> <p><mathjax>#[Mg^(2+)] = 3.79 mol*L^-1; [NO_3^-] = ??#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/194595" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-morality-be-used-as-a-conversion-factor"> How can molarity be used as a conversion factor? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-high-can-molarity-be"> How high can molarity be? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-molarity-change-with-temperature"> How does molarity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molarity-of-a-solution"> How do you find molarity of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-10-naoh"> What is the molarity of 10 NaOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-3-hydrogen-peroxide"> What is the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 4506 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the concentration of nitrate ions in a 3.79M #Mg(NO_3)_2# solution?	null
2,234	ab807054-6ddd-11ea-806b-ccda262736ce	https://socratic.org/questions/what-is-the-mass-of-3-moles-of-calcium-chloride-cacl-2	332.94 grams	start physical_unit 10 10 mass g qc_end physical_unit 10 10 5 6 mole qc_end end	[{"type":"physical unit","value":"Mass [OF] CaCl2 [IN] grams"}]	[{"type":"physical unit","value":"332.94 grams"}]	[{"type":"physical unit","value":"Mole [OF] CaCl2 [=] \\pu{3 moles}"}]	<h1 class="questionTitle" itemprop="name">What is the mass of 3 moles of calcium chloride, #CaCl_2#?</h1>	null	332.94 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And thus <mathjax>#3#</mathjax> <mathjax>#mol#</mathjax> of <mathjax>#CaCl_2#</mathjax> have a mass of <mathjax>#3cancel(mol)xx110.98gcancel(mol^-1)#</mathjax> <mathjax>#~=#</mathjax> <mathjax>#333g#</mathjax>.</p> <p>What is the mass of metal in this quantity?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The molar mass of anhydrous calcium chloride, <mathjax>#CaCl_2#</mathjax>, is <mathjax>#110.98 gmol^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And thus <mathjax>#3#</mathjax> <mathjax>#mol#</mathjax> of <mathjax>#CaCl_2#</mathjax> have a mass of <mathjax>#3cancel(mol)xx110.98gcancel(mol^-1)#</mathjax> <mathjax>#~=#</mathjax> <mathjax>#333g#</mathjax>.</p> <p>What is the mass of metal in this quantity?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the mass of 3 moles of calcium chloride, #CaCl_2#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="279507" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-20T21:06:59" itemprop="dateCreated"> Jun 20, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The molar mass of anhydrous calcium chloride, <mathjax>#CaCl_2#</mathjax>, is <mathjax>#110.98 gmol^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And thus <mathjax>#3#</mathjax> <mathjax>#mol#</mathjax> of <mathjax>#CaCl_2#</mathjax> have a mass of <mathjax>#3cancel(mol)xx110.98gcancel(mol^-1)#</mathjax> <mathjax>#~=#</mathjax> <mathjax>#333g#</mathjax>.</p> <p>What is the mass of metal in this quantity?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/279507" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 9650 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the mass of 3 moles of calcium chloride, #CaCl_2#?	null
2,235	ac4704ca-6ddd-11ea-930e-ccda262736ce	https://socratic.org/questions/if-the-absolute-pressure-of-a-gas-is-550-280-kpa-what-is-its-gage-pressure	4.43 atm	start physical_unit 6 6 pressure atm qc_end physical_unit 6 6 8 9 pressure qc_end end	[{"type":"physical unit","value":"Gage pressure [OF] the gas [IN] atm"}]	[{"type":"physical unit","value":"4.43 atm"}]	[{"type":"physical unit","value":"Absolute pressure [OF] the gas [=] \\pu{550.280 kPa}"}]	<h1 class="questionTitle" itemprop="name">If the absolute pressure of a gas is 550.280 kPa, what is its gage pressure?</h1>	null	4.43 atm	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The answer is <strong>448.955 kPa</strong>, or <strong>4.43084 atm</strong>.</p> <p>The difference between <strong>absolute</strong> and <strong>gauge</strong> pressure is determined by their respective zero references. </p> <p>The zero reference for absolute pressure is set against a perfect vacuum, while the zero reference for gauge pressure is set against ambient pressure.</p> <p>As a result, absolute pressure is defined as the sum of the gauge pressure and the <a href="http://socratic.org/chemistry/the-behavior-of-gases/atmospheric-pressure">atmospheric pressure</a></p> <p><mathjax>#P_("absolute") = P_("gauge") + P_("atmospheric")#</mathjax></p> <p>which makes gauge pressure equal to</p> <p><mathjax>#P_("gauge") = P_("absolute") - P_("atmospheric")#</mathjax></p> <p>Since a value for the atmospheric pressure was not provided, let's assume its <strong>1 atm</strong>, or <strong>101.325 kPa</strong>. This makes the gauge pressure equal to</p> <p><mathjax>#P_("gauge") = 550.280#</mathjax> <mathjax>#"kPa" - 101.325#</mathjax> <mathjax>#"kPa" = 448.955#</mathjax> <mathjax>#"kPa"#</mathjax>, or</p> <p><mathjax>#448.955#</mathjax> <mathjax>#"kPa" * ("1 atm")/("101.325 kPa") = 4.43084#</mathjax> <mathjax>#"atm"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>4.43084 atm</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The answer is <strong>448.955 kPa</strong>, or <strong>4.43084 atm</strong>.</p> <p>The difference between <strong>absolute</strong> and <strong>gauge</strong> pressure is determined by their respective zero references. </p> <p>The zero reference for absolute pressure is set against a perfect vacuum, while the zero reference for gauge pressure is set against ambient pressure.</p> <p>As a result, absolute pressure is defined as the sum of the gauge pressure and the <a href="http://socratic.org/chemistry/the-behavior-of-gases/atmospheric-pressure">atmospheric pressure</a></p> <p><mathjax>#P_("absolute") = P_("gauge") + P_("atmospheric")#</mathjax></p> <p>which makes gauge pressure equal to</p> <p><mathjax>#P_("gauge") = P_("absolute") - P_("atmospheric")#</mathjax></p> <p>Since a value for the atmospheric pressure was not provided, let's assume its <strong>1 atm</strong>, or <strong>101.325 kPa</strong>. This makes the gauge pressure equal to</p> <p><mathjax>#P_("gauge") = 550.280#</mathjax> <mathjax>#"kPa" - 101.325#</mathjax> <mathjax>#"kPa" = 448.955#</mathjax> <mathjax>#"kPa"#</mathjax>, or</p> <p><mathjax>#448.955#</mathjax> <mathjax>#"kPa" * ("1 atm")/("101.325 kPa") = 4.43084#</mathjax> <mathjax>#"atm"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">If the absolute pressure of a gas is 550.280 kPa, what is its gage pressure?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/gas-pressure" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Pressure</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="116220" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> <a class="secondContributorPic" href="/users/dwayne-1"><img alt="" class="" src="https://profilepictures.socratic.org/DibNg4wlRrG9KFZ5SeFe_IMG_2126.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a>·<a class="topContributorLink" href="/users/dwayne-1"> dwayne </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-01-03T20:27:41" itemprop="dateCreated"> Jan 3, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>4.43084 atm</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The answer is <strong>448.955 kPa</strong>, or <strong>4.43084 atm</strong>.</p> <p>The difference between <strong>absolute</strong> and <strong>gauge</strong> pressure is determined by their respective zero references. </p> <p>The zero reference for absolute pressure is set against a perfect vacuum, while the zero reference for gauge pressure is set against ambient pressure.</p> <p>As a result, absolute pressure is defined as the sum of the gauge pressure and the <a href="http://socratic.org/chemistry/the-behavior-of-gases/atmospheric-pressure">atmospheric pressure</a></p> <p><mathjax>#P_("absolute") = P_("gauge") + P_("atmospheric")#</mathjax></p> <p>which makes gauge pressure equal to</p> <p><mathjax>#P_("gauge") = P_("absolute") - P_("atmospheric")#</mathjax></p> <p>Since a value for the atmospheric pressure was not provided, let's assume its <strong>1 atm</strong>, or <strong>101.325 kPa</strong>. This makes the gauge pressure equal to</p> <p><mathjax>#P_("gauge") = 550.280#</mathjax> <mathjax>#"kPa" - 101.325#</mathjax> <mathjax>#"kPa" = 448.955#</mathjax> <mathjax>#"kPa"#</mathjax>, or</p> <p><mathjax>#448.955#</mathjax> <mathjax>#"kPa" * ("1 atm")/("101.325 kPa") = 4.43084#</mathjax> <mathjax>#"atm"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/116220" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-gas-pressure-be-changed"> How can gas pressure be changed? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-you-increase-gas-pressure-in-a-container"> How can you increase gas pressure in a container? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-gas-pressure-created"> How is gas pressure created? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-does-gas-pressure-increase-when-temperature-increases"> Why does gas pressure increase when temperature increases? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-gas-pressure-zero-at-absolute-zero"> Why is gas pressure zero at absolute zero? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-does-gas-pressure-increase-with-temperature"> Why does gas pressure increase with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-there-no-gas-pressure-in-a-vacuum"> Why is there no gas pressure in a vacuum? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-total-gas-pressure-in-a-sealed-flask-that-contains-oxygen-at-a-parti-1"> What is the total gas pressure in a sealed flask that contains oxygen at a partial pressure of... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-a-gas-sample-occupies-4-2-l-at-a-pressure-of-101-kpa-what-volume-will-it-occu"> If a gas sample occupies 4.2 L at a pressure of 101 kPa. What volume will it occupy if the... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-causes-gas-pressure"> What causes gas pressure? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/gas-pressure"> See all questions in Gas Pressure </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 8438 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	If the absolute pressure of a gas is 550.280 kPa, what is its gage pressure?	null
2,236	ac40e962-6ddd-11ea-8135-ccda262736ce	https://socratic.org/questions/what-is-the-weak-ionization-constant-k-a-for-hcn-equal-to	10^(-9.21)	start physical_unit 8 8 ka none qc_end chemical_equation 8 8 qc_end end	[{"type":"physical unit","value":"Ka [OF] HCN"}]	[{"type":"physical unit","value":"10^(-9.21)"}]	[{"type":"chemical equation","value":"HCN"}]	<h1 class="questionTitle" itemprop="name">What is the weak ionization constant (#K_a#) for #HCN# equal to?</h1>	null	10^(-9.21)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We assess the reaction:</p> <p><mathjax>#H-C-=N + H_2O rightleftharpoons""^(-)C-=N + H_3O^+#</mathjax></p> <p>And <mathjax>#K_a#</mathjax> <mathjax>#=#</mathjax> <mathjax>#10^(-9.21)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#([H_3O^+][""^(-)C-=N])/([HC-=N])#</mathjax></p> <p>Note that the value of <mathjax>#K_a#</mathjax> derives from careful and meticulous measurment under a standard set of conditions. The equilibrium is the reason why salts of hydrogen cyanide, i.e. <mathjax>#KCN#</mathjax> or <mathjax>#NaCN#</mathjax>, give a slightly basic solution upon dissolution in water.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#K_a"(hydrogen cyanide)"=10^(-9.21)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We assess the reaction:</p> <p><mathjax>#H-C-=N + H_2O rightleftharpoons""^(-)C-=N + H_3O^+#</mathjax></p> <p>And <mathjax>#K_a#</mathjax> <mathjax>#=#</mathjax> <mathjax>#10^(-9.21)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#([H_3O^+][""^(-)C-=N])/([HC-=N])#</mathjax></p> <p>Note that the value of <mathjax>#K_a#</mathjax> derives from careful and meticulous measurment under a standard set of conditions. The equilibrium is the reason why salts of hydrogen cyanide, i.e. <mathjax>#KCN#</mathjax> or <mathjax>#NaCN#</mathjax>, give a slightly basic solution upon dissolution in water.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the weak ionization constant (#K_a#) for #HCN# equal to?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/ph-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">pH calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="306334" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-09-05T11:12:04" itemprop="dateCreated"> Sep 5, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#K_a"(hydrogen cyanide)"=10^(-9.21)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We assess the reaction:</p> <p><mathjax>#H-C-=N + H_2O rightleftharpoons""^(-)C-=N + H_3O^+#</mathjax></p> <p>And <mathjax>#K_a#</mathjax> <mathjax>#=#</mathjax> <mathjax>#10^(-9.21)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#([H_3O^+][""^(-)C-=N])/([HC-=N])#</mathjax></p> <p>Note that the value of <mathjax>#K_a#</mathjax> derives from careful and meticulous measurment under a standard set of conditions. The equilibrium is the reason why salts of hydrogen cyanide, i.e. <mathjax>#KCN#</mathjax> or <mathjax>#NaCN#</mathjax>, give a slightly basic solution upon dissolution in water.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/306334" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-of-a-solution"> How do you determine ph of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-at-an-equivalence-point"> How do you determine pH at an equivalence point? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-molarity"> How do you determine pH from molarity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-alkalinity-mean"> What does alkalinity mean? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-base"> What is a base? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-acid-base-indicators-change-color"> How do acid base indicators change color? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-neutral-ph"> What is a neutral pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-alkalinity-affect-pool-water"> How does alkalinity affect pool water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ph-important-in-drinking-water"> Why is pH important in drinking water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-ph-of-solution"> How can I calculate the pH of a solution? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/ph-calculations"> See all questions in pH calculations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 4310 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the weak ionization constant (#K_a#) for #HCN# equal to?	null
2,237	ace381e5-6ddd-11ea-81c3-ccda262736ce	https://socratic.org/questions/59102bac7c0149156311b7e9	11.34 L	start physical_unit 1 1 volume l qc_end physical_unit 1 1 3 4 temperature qc_end physical_unit 1 1 20 21 temperature qc_end physical_unit 1 1 9 10 volume qc_end end	[{"type":"physical unit","value":"Volume2 [OF] the gas [IN] L"}]	[{"type":"physical unit","value":"11.34 L"}]	[{"type":"physical unit","value":"Temperature1 [OF] the gas [=] \\pu{34 ℃}"},{"type":"physical unit","value":"Temperature2 [OF] the gas [=] \\pu{48 ℃}"},{"type":"physical unit","value":"Volume1 [OF] the gas [=] \\pu{10 L}"}]	<h1 class="questionTitle" itemprop="name">A gas at #34# #""^@C# expressed a volume of #10*L# in a piston; what is the new volume at #48# #""^@C#?</h1>	null	11.34 L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Pressure is a constant here, but we know (or should know) that <mathjax>#1atm#</mathjax> pressure will support a column of mercury that is <mathjax>#760mmHg#</mathjax> tall; this relationship is linear: 1/2 an atmosphere will support a column of mercury that is <mathjax>#380mmHg#</mathjax> tall. A mercury manometer is thus useful to measure laboratory pressures of confined gases. </p> <p>We also must employ the absolute temperature scale..........</p> <p>And so <mathjax>#V_2=V_1/T_1xxT_2=(10L)/(307K)xx348K~=11*L#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Old <a href="https://socratic.org/chemistry/the-behavior-of-gases/charles-law">Charles' Law</a> holds that <mathjax>#V_1/T_1=V_2/T_2#</mathjax>, moles and pressure constant.........</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Pressure is a constant here, but we know (or should know) that <mathjax>#1atm#</mathjax> pressure will support a column of mercury that is <mathjax>#760mmHg#</mathjax> tall; this relationship is linear: 1/2 an atmosphere will support a column of mercury that is <mathjax>#380mmHg#</mathjax> tall. A mercury manometer is thus useful to measure laboratory pressures of confined gases. </p> <p>We also must employ the absolute temperature scale..........</p> <p>And so <mathjax>#V_2=V_1/T_1xxT_2=(10L)/(307K)xx348K~=11*L#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A gas at #34# #""^@C# expressed a volume of #10L# in a piston; what is the new volume at #48# #""^@C#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/charles-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Charles' Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="422432" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-13T03:53:42" itemprop="dateCreated"> May 13, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Old <a href="https://socratic.org/chemistry/the-behavior-of-gases/charles-law">Charles' Law</a> holds that <mathjax>#V_1/T_1=V_2/T_2#</mathjax>, moles and pressure constant.........</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Pressure is a constant here, but we know (or should know) that <mathjax>#1atm#</mathjax> pressure will support a column of mercury that is <mathjax>#760mmHg#</mathjax> tall; this relationship is linear: 1/2 an atmosphere will support a column of mercury that is <mathjax>#380mmHg#</mathjax> tall. A mercury manometer is thus useful to measure laboratory pressures of confined gases. </p> <p>We also must employ the absolute temperature scale..........</p> <p>And so <mathjax>#V_2=V_1/T_1xxT_2=(10L)/(307K)xx348K~=11L#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/422432" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-must-charles-law-be-in-kelvins"> Why must Charles' law be in kelvin? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-charles-law-formula"> What is Charles' law formula? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/oxygen-gas-is-at-a-temperature-of-40-c-when-it-occupies-a-volume-of-2-3-liters-t"> Oxygen gas is at a temperature of 40°C when it occupies a volume of 2.3 liters. To what... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-relation-to-absolute-zero-in-charles-law"> What is the relation to absolute zero in Charles' law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/8-00-l-of-a-gas-is-collected-at-60-0-c-what-will-be-its-volume-upon-cooling-to-3"> 8.00 L of a gas is collected at 60.0°C. What will be its volume upon cooling to 30.0°C? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/during-the-day-at-27-c-a-cylinder-with-a-sliding-top-contains-20-0-liters-of-air"> During the day at 27°C a cylinder with a sliding top contains 20.0 liters of air. At night it... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-sample-of-helium-has-a-volume-of-521-dm3-at-a-pressure-of-75-cm-hg-and-a-tempe"> A sample of helium has a volume of 521 dm3 at a pressure of 75 cm Hg and a temperature of 18° C.... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/568-cm3-of-chlorine-at-25-c-will-occupy-what-volume-at-25-c-while-the-pressure-r"> 568 cm3 of chlorine at 25° C will occupy what volume at -25° C while the pressure remains constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-sample-of-hydrogen-has-an-initial-temperature-of-50-c-when-the-temperature-is-"> A sample of hydrogen has an initial temperature of 50.° C. When the temperature is lowered to... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-sample-of-oxygen-occupies-a-volume-of-160-dm3-at-91-c-what-will-be-volume-of-o"> A sample of oxygen occupies a volume of 160 dm3 at 91° C. What will be volume of oxygen when the... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/charles-law"> See all questions in Charles' Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1651 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A gas at #34# #""^@C# expressed a volume of #10*L# in a piston; what is the new volume at #48# #""^@C#?	null
2,238	aadeab3e-6ddd-11ea-ae40-ccda262736ce	https://socratic.org/questions/5915eeb911ef6b6f32d7ccb7	2.1 mol	start physical_unit 2 2 mole mol qc_end physical_unit 9 9 6 7 mole qc_end end	[{"type":"physical unit","value":"Mole [OF] alumina [IN] mol"}]	[{"type":"physical unit","value":"2.1 mol"}]	[{"type":"physical unit","value":"Mole [OF] aluminum [=] \\pu{4.2 mol}"}]	<h1 class="questionTitle" itemprop="name">How much alumina is formed if #4.2*mol# of aluminum is oxidized?</h1>	null	2.1 mol	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#2Al(s) +3/2O_2(g) rarr Al_2O_3(s)#</mathjax></p> <p>Look at the <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> of the oxide: ONE mole of alumina contains 2 moles of aluminum, and 3 moles of oxygen ATOMS. We have <mathjax>#4.2mol#</mathjax> of aluminum, burnt in excess oxygen, and thus <mathjax>#2.1mol#</mathjax> alumina result. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Why, <mathjax>#2.1mol#</mathjax>....................</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#2Al(s) +3/2O_2(g) rarr Al_2O_3(s)#</mathjax></p> <p>Look at the <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> of the oxide: ONE mole of alumina contains 2 moles of aluminum, and 3 moles of oxygen ATOMS. We have <mathjax>#4.2mol#</mathjax> of aluminum, burnt in excess oxygen, and thus <mathjax>#2.1*mol#</mathjax> alumina result. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How much alumina is formed if #4.2mol# of aluminum is oxidized?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/mole-ratios" itemprop="url"> <span class="breadcrumb" itemprop="title">Mole Ratios</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="422261" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-12T17:53:41" itemprop="dateCreated"> May 12, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Why, <mathjax>#2.1mol#</mathjax>....................</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#2Al(s) +3/2O_2(g) rarr Al_2O_3(s)#</mathjax></p> <p>Look at the <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> of the oxide: ONE mole of alumina contains 2 moles of aluminum, and 3 moles of oxygen ATOMS. We have <mathjax>#4.2mol#</mathjax> of aluminum, burnt in excess oxygen, and thus <mathjax>#2.1mol#</mathjax> alumina result. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/422261" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4178e02bf3469517a106e"> Question #a106e </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4178e02bf3469570e2e86"> Question #e2e86 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179102bf3469517a1072"> Question #a1072 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179402bf34694c8c5bf1"> Question #c5bf1 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179702bf3469588dc373"> Question #dc373 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179c02bf34694c8c5bf9"> Question #c5bf9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417a302bf3469517a1076"> Question #a1076 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417c702bf3469588dc377"> Question #dc377 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417d002bf346963eb984f"> Question #b984f </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417d402bf346950519ea3"> Question #19ea3 </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/mole-ratios"> See all questions in Mole Ratios </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1744 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How much alumina is formed if #4.2*mol# of aluminum is oxidized?	null
2,239	ac2b955a-6ddd-11ea-a905-ccda262736ce	https://socratic.org/questions/suppose-a-bag-full-of-ice-450-g-at-0-0-c-sits-on-the-counter-and-begins-to-melt-	100.20 kJ	start physical_unit 5 5 heat_energy kj qc_end physical_unit 5 5 6 7 mass qc_end physical_unit 5 5 9 10 temperature qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Absorbed energy [OF] ice [IN] kJ"}]	[{"type":"physical unit","value":"100.20 kJ"}]	[{"type":"physical unit","value":"Mass [OF] ice [=] \\pu{450 g}"},{"type":"physical unit","value":"Temperature [OF] ice [=] \\pu{0.0 ℃}"},{"type":"other","value":"2/3 of the ice melted."}]	<h1 class="questionTitle" itemprop="name">Suppose a bag full of ice (450 g) at 0.0 °C sits on the counter and begins to melt to liquid water. How much energy must be absorbed by the ice if 2/3 of it melted?</h1>	null	100.20 kJ	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>All you have to do here is figure out how much heat is required to convert ice at <mathjax>#0^@"C"#</mathjax> to liquid water at <mathjax>#0^@"C"#</mathjax>, i.e. how much heat is required for that much ice to undergo a <em>solid</em> <mathjax>#->#</mathjax> <em>liquid</em> <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/introduction-to-phase-changes">phase change</a>.</p> <p>As you know, <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/introduction-to-phase-changes">phase changes</a> take place at <strong>constant temperature</strong> and depend on the given substance's <em><a href="http://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> of fusion</em>, which in water's case is equal to about</p> <blockquote> <p><mathjax>#DeltaH_f = 334"J"/"g"#</mathjax></p> </blockquote> <p><a href="http://www.engineeringtoolbox.com/latent-heat-melting-solids-d_96.html" rel="nofollow" target="_blank">http://www.engineeringtoolbox.com/latent-heat-melting-solids-d_96.html</a></p> <p>What that means is that in order to melt <mathjax>#"1 g"#</mathjax> of ice at <mathjax>#0^@"C"#</mathjax> to liquid water at <mathjax>#0^@"C"#</mathjax>, you need to provide it with <mathjax>#"334 J"#</mathjax> of heat. </p> <p>In your case, you need to know how much heat is required to melt <mathjax>#2/3#</mathjax> of that <mathjax>#"450-g"#</mathjax> sample of ice. Well, if <mathjax>#"1 g"#</mathjax> requires <mathjax>#"334 J"#</mathjax> of heat, it follows that you have</p> <blockquote> <p><mathjax>#2/3 * 450 color(red)(cancel(color(black)("g"))) * "334 J"/(1color(red)(cancel(color(black)("g")))) = "100,200 J"#</mathjax></p> </blockquote> <p>Rounded to two <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a> and expressed in <em>kilojoules</em>, the answer will be </p> <blockquote> <p><mathjax>#q = color(green)(1.0 * 10^2"kJ")#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#q = 1.0 * 10^2"kJ"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>All you have to do here is figure out how much heat is required to convert ice at <mathjax>#0^@"C"#</mathjax> to liquid water at <mathjax>#0^@"C"#</mathjax>, i.e. how much heat is required for that much ice to undergo a <em>solid</em> <mathjax>#->#</mathjax> <em>liquid</em> <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/introduction-to-phase-changes">phase change</a>.</p> <p>As you know, <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/introduction-to-phase-changes">phase changes</a> take place at <strong>constant temperature</strong> and depend on the given substance's <em><a href="http://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> of fusion</em>, which in water's case is equal to about</p> <blockquote> <p><mathjax>#DeltaH_f = 334"J"/"g"#</mathjax></p> </blockquote> <p><a href="http://www.engineeringtoolbox.com/latent-heat-melting-solids-d_96.html" rel="nofollow" target="_blank">http://www.engineeringtoolbox.com/latent-heat-melting-solids-d_96.html</a></p> <p>What that means is that in order to melt <mathjax>#"1 g"#</mathjax> of ice at <mathjax>#0^@"C"#</mathjax> to liquid water at <mathjax>#0^@"C"#</mathjax>, you need to provide it with <mathjax>#"334 J"#</mathjax> of heat. </p> <p>In your case, you need to know how much heat is required to melt <mathjax>#2/3#</mathjax> of that <mathjax>#"450-g"#</mathjax> sample of ice. Well, if <mathjax>#"1 g"#</mathjax> requires <mathjax>#"334 J"#</mathjax> of heat, it follows that you have</p> <blockquote> <p><mathjax>#2/3 * 450 color(red)(cancel(color(black)("g"))) * "334 J"/(1color(red)(cancel(color(black)("g")))) = "100,200 J"#</mathjax></p> </blockquote> <p>Rounded to two <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a> and expressed in <em>kilojoules</em>, the answer will be </p> <blockquote> <p><mathjax>#q = color(green)(1.0 * 10^2"kJ")#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Suppose a bag full of ice (450 g) at 0.0 °C sits on the counter and begins to melt to liquid water. How much energy must be absorbed by the ice if 2/3 of it melted?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/thermochemistry-of-phase-changes" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry of Phase Changes</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="202610" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-23T15:54:46" itemprop="dateCreated"> Dec 23, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#q = 1.0 * 10^2"kJ"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>All you have to do here is figure out how much heat is required to convert ice at <mathjax>#0^@"C"#</mathjax> to liquid water at <mathjax>#0^@"C"#</mathjax>, i.e. how much heat is required for that much ice to undergo a <em>solid</em> <mathjax>#->#</mathjax> <em>liquid</em> <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/introduction-to-phase-changes">phase change</a>.</p> <p>As you know, <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/introduction-to-phase-changes">phase changes</a> take place at <strong>constant temperature</strong> and depend on the given substance's <em><a href="http://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> of fusion</em>, which in water's case is equal to about</p> <blockquote> <p><mathjax>#DeltaH_f = 334"J"/"g"#</mathjax></p> </blockquote> <p><a href="http://www.engineeringtoolbox.com/latent-heat-melting-solids-d_96.html" rel="nofollow" target="_blank">http://www.engineeringtoolbox.com/latent-heat-melting-solids-d_96.html</a></p> <p>What that means is that in order to melt <mathjax>#"1 g"#</mathjax> of ice at <mathjax>#0^@"C"#</mathjax> to liquid water at <mathjax>#0^@"C"#</mathjax>, you need to provide it with <mathjax>#"334 J"#</mathjax> of heat. </p> <p>In your case, you need to know how much heat is required to melt <mathjax>#2/3#</mathjax> of that <mathjax>#"450-g"#</mathjax> sample of ice. Well, if <mathjax>#"1 g"#</mathjax> requires <mathjax>#"334 J"#</mathjax> of heat, it follows that you have</p> <blockquote> <p><mathjax>#2/3 * 450 color(red)(cancel(color(black)("g"))) * "334 J"/(1color(red)(cancel(color(black)("g")))) = "100,200 J"#</mathjax></p> </blockquote> <p>Rounded to two <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a> and expressed in <em>kilojoules</em>, the answer will be </p> <blockquote> <p><mathjax>#q = color(green)(1.0 * 10^2"kJ")#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/202610" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-much-energy-is-required-to-heat-100-g-of-ice-at-0-00-degrees-celsius-to-wate"> How much energy is required to convert 100.g of ice at 0.00 °C to water vapor at 100.00 °C? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/534b309602bf34123dd86d5c"> How do you calculate the heat required to melt 15 kg of silver? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-a-liquid-loses-energy-will-it-change-into-a-gas-or-a-solid"> When a liquid loses energy, will it change into a gas or a solid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-name-of-the-process-when-a-liquid-changes-into-a-gas"> What is the name of the process when a liquid changes into a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-much-energy-is-needed-to-convert-23-0-grams-of-ice-at-10-0-c-into-steam-at-1"> How much energy is needed to convert 23.0 grams of ice at -10.0°C into steam at 109°C? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-amount-of-ice-must-be-added-to-540-0-g-of-water-at-25-0-c-to-cool-the-water"> What amount of ice must be added to 540.0 g of water at 25.0 °C to cool the water to 0.0 °C and... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-find-specific-heat-in-thermochemistry-of-phase-of-changes"> How can I find specific heat in thermochemistry of phase of changes? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-much-energy-is-required-to-convert-100-0-g-of-water-at-20-0-c-completely-to-"> How much energy is required to convert 100.0 g of water at 20.0 °C completely to steam at 100.0 °C? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/calculate-the-number-of-joules-given-off-when-32-0-grams-of-steam-cools-from-110"> Calculate the number of joules given off when 32.0 grams of steam cools from 110.0 °C to ice at -40.0 °C. </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-joules-of-heat-are-needed-to-change-50-0-grams-of-ice-at-15-0-c-to-stea"> How many joules of heat are needed to change 50.0 grams of ice at -15.0 °C to steam at 120.0 °C? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/thermochemistry-of-phase-changes"> See all questions in Thermochemistry of Phase Changes </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 14437 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Suppose a bag full of ice (450 g) at 0.0 °C sits on the counter and begins to melt to liquid water. How much energy must be absorbed by the ice if 2/3 of it melted?	null
2,240	ac033def-6ddd-11ea-bad2-ccda262736ce	https://socratic.org/questions/what-would-be-considered-the-molecular-formula-for-the-compound-that-has-an-empi	C5H20	start chemical_formula qc_end physical_unit 8 9 22 23 molar_mass qc_end c_other OTHER qc_end end	[{"type":"other","value":"Chemical Formula [OF] the compound [IN] molecular"}]	[{"type":"chemical equation","value":"C5H20"}]	[{"type":"physical unit","value":"Molar mass [OF] the compound [=] \\pu{80 g/mol}"},{"type":"other","value":"The compound has an empirical formula of CH4."}]	<h1 class="questionTitle" itemprop="name">What would be considered the molecular formula for the compound that has an empirical formula of #CH_4# but a molar mass of 80 g/mol?</h1>	null	C5H20	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>If we translate this to <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">atomic mass</a> units, the ratio goes to:<br/> <mathjax>#1xx12div4xx1=12div4#</mathjax></p> <p>The sum of the ratios is <mathjax>#16#</mathjax> and this goes into <mathjax>#80#</mathjax> five times.</p> <p>So the molecular formula would be <mathjax>#C_(1xx5)H_(4xx5)=C_5H_20#</mathjax></p> <p><strong>Check</strong> : <mathjax>#5xx12+20xx1=80#</mathjax></p> <p><strong>Note</strong> : This is a non-existing compound, as <mathjax>#5C#</mathjax> atoms can at most hold <mathjax>#12H#</mathjax> atoms (matter of valencies). </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Empirical formula means the ratio <mathjax>#CdivH=1div4#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>If we translate this to <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">atomic mass</a> units, the ratio goes to:<br/> <mathjax>#1xx12div4xx1=12div4#</mathjax></p> <p>The sum of the ratios is <mathjax>#16#</mathjax> and this goes into <mathjax>#80#</mathjax> five times.</p> <p>So the molecular formula would be <mathjax>#C_(1xx5)H_(4xx5)=C_5H_20#</mathjax></p> <p><strong>Check</strong> : <mathjax>#5xx12+20xx1=80#</mathjax></p> <p><strong>Note</strong> : This is a non-existing compound, as <mathjax>#5C#</mathjax> atoms can at most hold <mathjax>#12H#</mathjax> atoms (matter of valencies). </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What would be considered the molecular formula for the compound that has an empirical formula of #CH_4# but a molar mass of 80 g/mol?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="367813" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meneernask"><img alt="" class="" src="https://profilepictures.socratic.org/gpA0lokRGK9vLVUnAMAy_meneernask.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meneernask"> MeneerNask </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-01-22T12:41:58" itemprop="dateCreated"> Jan 22, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Empirical formula means the ratio <mathjax>#CdivH=1div4#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>If we translate this to <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">atomic mass</a> units, the ratio goes to:<br/> <mathjax>#1xx12div4xx1=12div4#</mathjax></p> <p>The sum of the ratios is <mathjax>#16#</mathjax> and this goes into <mathjax>#80#</mathjax> five times.</p> <p>So the molecular formula would be <mathjax>#C_(1xx5)H_(4xx5)=C_5H_20#</mathjax></p> <p><strong>Check</strong> : <mathjax>#5xx12+20xx1=80#</mathjax></p> <p><strong>Note</strong> : This is a non-existing compound, as <mathjax>#5C#</mathjax> atoms can at most hold <mathjax>#12H#</mathjax> atoms (matter of valencies). </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/367813" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molecular-formula-of-a-compound"> How do you find molecular formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-diamond"> What is the chemical formula of a diamond? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-carbohydrate"> What is the chemical formula of a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-valproic-acid"> What is the empirical formula for valproic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-of-magnesium-oxide"> What is the empirical formula of magnesium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-empirical-formula-not-double-that-of-the-monosaccharides"> Why is the empirical formula not double that of the monosaccharides? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5331180502bf342f40b5c3b5"> Question #5c3b5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-molecular-formula-represents-a-carbohydrate"> What molecular formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-of-vinegar"> What is the molecular formula of vinegar? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/empirical-and-molecular-formulas"> See all questions in Empirical and Molecular Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1442 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What would be considered the molecular formula for the compound that has an empirical formula of #CH_4# but a molar mass of 80 g/mol?	null
2,241	aac98882-6ddd-11ea-98a1-ccda262736ce	https://socratic.org/questions/if-5-04-grams-of-iron-ii-nitrate-reacts-with-an-excess-of-h-2s-what-mass-of-iron	2.46 g	start physical_unit 15 16 mass g qc_end physical_unit 4 5 1 2 mass qc_end chemical_equation 23 29 qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Mass [OF] iron(II) sulfide [IN] g"}]	[{"type":"physical unit","value":"2.46 g"}]	[{"type":"physical unit","value":"Mass [OF] iron(II) nitrate [=] \\pu{5.04 grams}"},{"type":"chemical equation","value":"Fe(NO3)2 + H2S -> FeS + H(NO3)"},{"type":"other","value":"Excess of H2S."}]	<h1 class="questionTitle" itemprop="name">If 5.04 grams of iron (II) nitrate reacts with an excess of #H_2S#, what mass of iron(II) sulfide will be produced in the reaction #Fe(NO_3)_2 + H_2S -> FeS + H(NO_3)#?</h1>	null	2.46 g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#Fe(NO_3)_2(aq) + H_2S(aq) rarr FeS(s)darr + 2HNO_3(aq)#</mathjax></p> <p>The stoichiometrically balanced equation tells you explicitly that 1 mol of sulfide will result from every mole of ferrous nitrate.</p> <p><mathjax>#"Moles of ferrous nitrate"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(5.04g)/(179.86gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax></p> <p><mathjax>#"Mass of ferrous sulfide"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(5.04g)/(179.86gmol^-1)xx87.91gmol^-1#</mathjax> <mathjax>#~=#</mathjax> <mathjax>#2.0*g#</mathjax></p> <p>The sulfide will be obtained as a sticky, black mess that is exceptionally difficult to handle and dry. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Mass of ferrous nitrate <mathjax>#=#</mathjax> <mathjax>#(5.04g)/(179.86gmol^-1)xx87.91gmol^-1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??g#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#Fe(NO_3)_2(aq) + H_2S(aq) rarr FeS(s)darr + 2HNO_3(aq)#</mathjax></p> <p>The stoichiometrically balanced equation tells you explicitly that 1 mol of sulfide will result from every mole of ferrous nitrate.</p> <p><mathjax>#"Moles of ferrous nitrate"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(5.04g)/(179.86gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax></p> <p><mathjax>#"Mass of ferrous sulfide"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(5.04g)/(179.86gmol^-1)xx87.91gmol^-1#</mathjax> <mathjax>#~=#</mathjax> <mathjax>#2.0g#</mathjax></p> <p>The sulfide will be obtained as a sticky, black mess that is exceptionally difficult to handle and dry. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">If 5.04 grams of iron (II) nitrate reacts with an excess of #H_2S#, what mass of iron(II) sulfide will be produced in the reaction #Fe(NO_3)_2 + H_2S -> FeS + H(NO_3)#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="296705" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-08-08T08:00:23" itemprop="dateCreated"> Aug 8, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Mass of ferrous nitrate <mathjax>#=#</mathjax> <mathjax>#(5.04g)/(179.86gmol^-1)xx87.91gmol^-1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??g#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#Fe(NO_3)_2(aq) + H_2S(aq) rarr FeS(s)darr + 2HNO_3(aq)#</mathjax></p> <p>The stoichiometrically balanced equation tells you explicitly that 1 mol of sulfide will result from every mole of ferrous nitrate.</p> <p><mathjax>#"Moles of ferrous nitrate"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(5.04g)/(179.86gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax></p> <p><mathjax>#"Mass of ferrous sulfide"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(5.04g)/(179.86gmol^-1)xx87.91gmol^-1#</mathjax> <mathjax>#~=#</mathjax> <mathjax>#2.0g#</mathjax></p> <p>The sulfide will be obtained as a sticky, black mess that is exceptionally difficult to handle and dry. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/296705" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What is stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ab82402bf342f48d93ac6"> Question #93ac6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-we-study-stoichiometry"> Why do we study stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-naoh-is-produced-from-1-20-x-102-grams-of-na2o-na2o-h2o-2-naoh"> How many grams of NaOH is produced from #1.20 x 10^2# grams of #Na_2O#? #Na_2O + H_2O -> 2NaOH# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-na2o-are-required-to-produce-1-60-x-102-grams-of-naoh-na2o-h2o"> How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? Na2O + H2O ---> 2 NaOH </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-mass-of-iron-is-needed-to-react-with-16-0-grams-of-sulfur-8-fe-s8-8-fes"> What mass of iron is needed to react with 16.0 grams of sulfur? 8 Fe + S8 ---> 8 FeS </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/according-to-8-fe-s8-8-fes-how-many-grams-of-fes-are-produced"> According to 8 Fe + S8 ---> 8 FeS How many grams of FeS are produced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/12-00-moles-of-naclo3-will-produce-how-many-grams-of-o2-2-naclo3-2-nacl-3-o2"> 12.00 moles of NaClO3 will produce how many grams of O2? 2 NaClO3 ---> 2 NaCl + 3 O2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-nacl-are-produced-when-80-0-grams-of-o2-are-produced-2-naclo3-"> How many grams of NaCl are produced when 80.0 grams of O2 are produced? 2 NaClO3 ---> 2 NaCl + 3 O2 </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/stoichiometry"> See all questions in Stoichiometry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1417 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	If 5.04 grams of iron (II) nitrate reacts with an excess of #H_2S#, what mass of iron(II) sulfide will be produced in the reaction #Fe(NO_3)_2 + H_2S -> FeS + H(NO_3)#?	null
2,242	ac963e06-6ddd-11ea-b787-ccda262736ce	https://socratic.org/questions/what-is-the-number-of-representative-particles-in-4-80-10-3-mol-nai	9.60 × 10^(-3)	start physical_unit 5 6 number none qc_end physical_unit 12 12 8 11 mole qc_end end	[{"type":"physical unit","value":"Number [OF] representative particles"}]	[{"type":"physical unit","value":"9.60 × 10^(-3)"}]	[{"type":"physical unit","value":"Mole [OF] NaI [=] \\pu{4.80 × 10^(-3) mol}"}]	<h1 class="questionTitle" itemprop="name">What is the number of representative particles in #4.80 * 10^-3# mol #NaI#?</h1>	null	9.60 × 10^(-3)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>A sodium iodide unit is conceived to derive from one <mathjax>#Na^+#</mathjax> and one <mathjax>#I^-#</mathjax>. Because matter is electrically neutral these combine in a 1:1 fashion.</p> <p>You specified <mathjax>#4.80xx10^-3#</mathjax> <mathjax>#mol#</mathjax> of <mathjax>#NaI#</mathjax>. In this molar quantity there are <mathjax>#4.80xx10^-3#</mathjax> <mathjax>#mol#</mathjax> of <mathjax>#Na^+#</mathjax> ions, and <mathjax>#4.80xx10^-3#</mathjax> <mathjax>#mol#</mathjax> of <mathjax>#I^-#</mathjax>; i.e. <mathjax>#9.6xx10^-3#</mathjax> of individual ions. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#9.6xx10^-3#</mathjax> total moles of ions.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>A sodium iodide unit is conceived to derive from one <mathjax>#Na^+#</mathjax> and one <mathjax>#I^-#</mathjax>. Because matter is electrically neutral these combine in a 1:1 fashion.</p> <p>You specified <mathjax>#4.80xx10^-3#</mathjax> <mathjax>#mol#</mathjax> of <mathjax>#NaI#</mathjax>. In this molar quantity there are <mathjax>#4.80xx10^-3#</mathjax> <mathjax>#mol#</mathjax> of <mathjax>#Na^+#</mathjax> ions, and <mathjax>#4.80xx10^-3#</mathjax> <mathjax>#mol#</mathjax> of <mathjax>#I^-#</mathjax>; i.e. <mathjax>#9.6xx10^-3#</mathjax> of individual ions. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the number of representative particles in #4.80 * 10^-3# mol #NaI#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="250627" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-04-06T20:03:31" itemprop="dateCreated"> Apr 6, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#9.6xx10^-3#</mathjax> total moles of ions.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>A sodium iodide unit is conceived to derive from one <mathjax>#Na^+#</mathjax> and one <mathjax>#I^-#</mathjax>. Because matter is electrically neutral these combine in a 1:1 fashion.</p> <p>You specified <mathjax>#4.80xx10^-3#</mathjax> <mathjax>#mol#</mathjax> of <mathjax>#NaI#</mathjax>. In this molar quantity there are <mathjax>#4.80xx10^-3#</mathjax> <mathjax>#mol#</mathjax> of <mathjax>#Na^+#</mathjax> ions, and <mathjax>#4.80xx10^-3#</mathjax> <mathjax>#mol#</mathjax> of <mathjax>#I^-#</mathjax>; i.e. <mathjax>#9.6xx10^-3#</mathjax> of individual ions. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/250627" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3875 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the number of representative particles in #4.80 * 10^-3# mol #NaI#?	null
2,243	a8d49c82-6ddd-11ea-8aa3-ccda262736ce	https://socratic.org/questions/what-is-the-poh-of-a-solution-that-has-oh-concentration-equal-to-1-36-10-10-m	9.87	start physical_unit 6 6 poh none qc_end physical_unit 9 9 13 16 concentration qc_end end	[{"type":"physical unit","value":"pOH [OF] the solution"}]	[{"type":"physical unit","value":"9.87"}]	[{"type":"physical unit","value":"Concentration [OF] OH- [=] \\pu{1.36 × 10^(-10) mol/dm^(-3)}"}]	<h1 class="questionTitle" itemprop="name">What is the pOH of a solution that has OH concentration equal to #1.36×10^-10" mol"*"dm"^(-3)# ?</h1>	null	9.87	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>By definition<br/> <mathjax>#"pOH"=-log_(10)["OH"^-]#</mathjax><br/> where <mathjax>#["OH"^-]#</mathjax> is the hydroxide ion concentration of the solution in <mathjax>#"M"#</mathjax> or <mathjax>#"mol""dm"^(-3)#</mathjax>, moles per cubic decimeter, or equivalently moles per liter.</p> <p>Substituting <mathjax>#["OH"^-]=1.3610^(-10)" mol"*"dm"^(-3)#</mathjax>,<br/> <mathjax>#"pOH"=9.866#</mathjax>.</p> <p>Note that by convention the number of decimal places the <mathjax>#"pOH"#</mathjax> value has shall equal to the number of <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a> in the value of <mathjax>#["OH"^-]#</mathjax>. <mathjax>#["OH"^-]#</mathjax> has <mathjax>#3#</mathjax> significant figures, which correspond to three decimal places for the <mathjax>#"pOH"#</mathjax> measurement.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"pOH"=9.866#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>By definition<br/> <mathjax>#"pOH"=-log_(10)["OH"^-]#</mathjax><br/> where <mathjax>#["OH"^-]#</mathjax> is the hydroxide ion concentration of the solution in <mathjax>#"M"#</mathjax> or <mathjax>#"mol""dm"^(-3)#</mathjax>, moles per cubic decimeter, or equivalently moles per liter.</p> <p>Substituting <mathjax>#["OH"^-]=1.3610^(-10)" mol"*"dm"^(-3)#</mathjax>,<br/> <mathjax>#"pOH"=9.866#</mathjax>.</p> <p>Note that by convention the number of decimal places the <mathjax>#"pOH"#</mathjax> value has shall equal to the number of <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a> in the value of <mathjax>#["OH"^-]#</mathjax>. <mathjax>#["OH"^-]#</mathjax> has <mathjax>#3#</mathjax> significant figures, which correspond to three decimal places for the <mathjax>#"pOH"#</mathjax> measurement.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the pOH of a solution that has OH concentration equal to #1.36×10^-10" mol""dm"^(-3)# ?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/ph-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">pH calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="585818" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/jacob-t-3"><img alt="" class="" src="https://profilepictures.socratic.org/cDl6OiFtT16bIyMtJPfM_Protractor.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/jacob-t-3"> Jacob T. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-03-31T13:09:01" itemprop="dateCreated"> Mar 31, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"pOH"=9.866#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>By definition<br/> <mathjax>#"pOH"=-log_(10)["OH"^-]#</mathjax><br/> where <mathjax>#["OH"^-]#</mathjax> is the hydroxide ion concentration of the solution in <mathjax>#"M"#</mathjax> or <mathjax>#"mol""dm"^(-3)#</mathjax>, moles per cubic decimeter, or equivalently moles per liter.</p> <p>Substituting <mathjax>#["OH"^-]=1.3610^(-10)" mol""dm"^(-3)#</mathjax>,<br/> <mathjax>#"pOH"=9.866#</mathjax>.</p> <p>Note that by convention the number of decimal places the <mathjax>#"pOH"#</mathjax> value has shall equal to the number of <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a> in the value of <mathjax>#["OH"^-]#</mathjax>. <mathjax>#["OH"^-]#</mathjax> has <mathjax>#3#</mathjax> significant figures, which correspond to three decimal places for the <mathjax>#"pOH"#</mathjax> measurement.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/585818" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-of-a-solution"> How do you determine ph of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-at-an-equivalence-point"> How do you determine pH at an equivalence point? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-molarity"> How do you determine pH from molarity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-alkalinity-mean"> What does alkalinity mean? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-base"> What is a base? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-acid-base-indicators-change-color"> How do acid base indicators change color? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-neutral-ph"> What is a neutral pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-alkalinity-affect-pool-water"> How does alkalinity affect pool water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ph-important-in-drinking-water"> Why is pH important in drinking water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-ph-of-solution"> How can I calculate the pH of a solution? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/ph-calculations"> See all questions in pH calculations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 7584 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the pOH of a solution that has OH concentration equal to #1.36×10^-10" mol"*"dm"^(-3)# ?	null
2,244	ab457a5c-6ddd-11ea-845a-ccda262736ce	https://socratic.org/questions/a-gas-has-a-pressure-of-699-0-mm-hg-at-40-0-c-what-is-the-temperature-at-standar	335.84 K	start physical_unit 1 1 temperature k qc_end physical_unit 1 1 6 7 pressure qc_end physical_unit 1 1 9 10 temperature qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Temperature2 [OF] the gas [IN] K"}]	[{"type":"physical unit","value":"335.84 K"}]	[{"type":"physical unit","value":"Pressure1 [OF] the gas [=] \\pu{699.0 mmHg}"},{"type":"physical unit","value":"Temperature1 [OF] the gas [=] \\pu{40.0 ℃}"},{"type":"other","value":"Standard pressure."}]	<h1 class="questionTitle" itemprop="name"> A gas has a pressure of 699.0 mm Hg at 40.0°C. What is the temperature at standard pressure?</h1>	null	335.84 K	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is a pressure-temperature gas problem. This means that it involves Gay-Lussac's law, which states that the pressure of a given amount of a gas, held at constant volume, varies directly with its temperature. This means that if the pressure increases, so does the temperature, and vice-versa. The equation used to solve this problem is:</p> <p><mathjax>#P_1/T_1=P_2/T_2#</mathjax></p> <p>Before we go further, we need to determine what standard pressure is, and we need to convert the Celsius temperature to Kelvin temperature by adding <mathjax>#273.15#</mathjax> to the Celsius temperature.</p> <p>Standard pressure is <mathjax>#"100 kPa"#</mathjax>. <mathjax>#larr#</mathjax> 100 kiloPascals</p> <p>We need to convert <mathjax>#"mmHg"#</mathjax> to <mathjax>#"kPa"#</mathjax>.</p> <p><mathjax>#1"kPa"="7.5006 mmHg"#</mathjax></p> <p><mathjax>#699.0color(red)cancel(color(black)("mmHg"))xx(1"kPa")/(7.5006color(red)cancel(color(black)("mmHg")))="93.2 kPa"#</mathjax></p> <p><strong>Organize your data:</strong></p> <p><strong>Known</strong></p> <p><mathjax>#P_1="93.2 kPa"#</mathjax></p> <p><mathjax>#T_1="40"^@"C" + 273.15="313 K"#</mathjax></p> <p><mathjax>#P_2="100 kPa"#</mathjax></p> <p><strong>Unknown</strong></p> <p><mathjax>#T_2=?#</mathjax></p> <p><strong>Solution</strong></p> <p>Rearrange the equation above to isolate <mathjax>#T_2#</mathjax>. Insert the given data into the new equation and solve.</p> <p><mathjax>#T_2=(P_2T_1)/P_1#</mathjax></p> <p><mathjax>#T_2=(100color(red)cancel(color(black)("kPa"))xx313"K")/(93.2color(red)cancel(color(black)("kPa")))="336 K"#</mathjax></p> <p>If you need to convert the temperature in Kelvins back to the Celsius temperature, subtract <mathjax>#273.15#</mathjax> from <mathjax>#"336 K"#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The temperature will be <mathjax>#"336 K"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is a pressure-temperature gas problem. This means that it involves Gay-Lussac's law, which states that the pressure of a given amount of a gas, held at constant volume, varies directly with its temperature. This means that if the pressure increases, so does the temperature, and vice-versa. The equation used to solve this problem is:</p> <p><mathjax>#P_1/T_1=P_2/T_2#</mathjax></p> <p>Before we go further, we need to determine what standard pressure is, and we need to convert the Celsius temperature to Kelvin temperature by adding <mathjax>#273.15#</mathjax> to the Celsius temperature.</p> <p>Standard pressure is <mathjax>#"100 kPa"#</mathjax>. <mathjax>#larr#</mathjax> 100 kiloPascals</p> <p>We need to convert <mathjax>#"mmHg"#</mathjax> to <mathjax>#"kPa"#</mathjax>.</p> <p><mathjax>#1"kPa"="7.5006 mmHg"#</mathjax></p> <p><mathjax>#699.0color(red)cancel(color(black)("mmHg"))xx(1"kPa")/(7.5006color(red)cancel(color(black)("mmHg")))="93.2 kPa"#</mathjax></p> <p><strong>Organize your data:</strong></p> <p><strong>Known</strong></p> <p><mathjax>#P_1="93.2 kPa"#</mathjax></p> <p><mathjax>#T_1="40"^@"C" + 273.15="313 K"#</mathjax></p> <p><mathjax>#P_2="100 kPa"#</mathjax></p> <p><strong>Unknown</strong></p> <p><mathjax>#T_2=?#</mathjax></p> <p><strong>Solution</strong></p> <p>Rearrange the equation above to isolate <mathjax>#T_2#</mathjax>. Insert the given data into the new equation and solve.</p> <p><mathjax>#T_2=(P_2T_1)/P_1#</mathjax></p> <p><mathjax>#T_2=(100color(red)cancel(color(black)("kPa"))xx313"K")/(93.2color(red)cancel(color(black)("kPa")))="336 K"#</mathjax></p> <p>If you need to convert the temperature in Kelvins back to the Celsius temperature, subtract <mathjax>#273.15#</mathjax> from <mathjax>#"336 K"#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name"> A gas has a pressure of 699.0 mm Hg at 40.0°C. What is the temperature at standard pressure?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/gay-lussac-s-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Gay Lussac's Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="448510" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-07-06T06:43:20" itemprop="dateCreated"> Jul 6, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The temperature will be <mathjax>#"336 K"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is a pressure-temperature gas problem. This means that it involves Gay-Lussac's law, which states that the pressure of a given amount of a gas, held at constant volume, varies directly with its temperature. This means that if the pressure increases, so does the temperature, and vice-versa. The equation used to solve this problem is:</p> <p><mathjax>#P_1/T_1=P_2/T_2#</mathjax></p> <p>Before we go further, we need to determine what standard pressure is, and we need to convert the Celsius temperature to Kelvin temperature by adding <mathjax>#273.15#</mathjax> to the Celsius temperature.</p> <p>Standard pressure is <mathjax>#"100 kPa"#</mathjax>. <mathjax>#larr#</mathjax> 100 kiloPascals</p> <p>We need to convert <mathjax>#"mmHg"#</mathjax> to <mathjax>#"kPa"#</mathjax>.</p> <p><mathjax>#1"kPa"="7.5006 mmHg"#</mathjax></p> <p><mathjax>#699.0color(red)cancel(color(black)("mmHg"))xx(1"kPa")/(7.5006color(red)cancel(color(black)("mmHg")))="93.2 kPa"#</mathjax></p> <p><strong>Organize your data:</strong></p> <p><strong>Known</strong></p> <p><mathjax>#P_1="93.2 kPa"#</mathjax></p> <p><mathjax>#T_1="40"^@"C" + 273.15="313 K"#</mathjax></p> <p><mathjax>#P_2="100 kPa"#</mathjax></p> <p><strong>Unknown</strong></p> <p><mathjax>#T_2=?#</mathjax></p> <p><strong>Solution</strong></p> <p>Rearrange the equation above to isolate <mathjax>#T_2#</mathjax>. Insert the given data into the new equation and solve.</p> <p><mathjax>#T_2=(P_2T_1)/P_1#</mathjax></p> <p><mathjax>#T_2=(100color(red)cancel(color(black)("kPa"))xx313"K")/(93.2color(red)cancel(color(black)("kPa")))="336 K"#</mathjax></p> <p>If you need to convert the temperature in Kelvins back to the Celsius temperature, subtract <mathjax>#273.15#</mathjax> from <mathjax>#"336 K"#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/448510" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535d701102bf342f53d9bcb0"> Question #9bcb0 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-gay-lussac-s-law-formula"> What is the Gay Lussac's law formula? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-the-temperature-of-a-gas-in-a-container-is-doubled-on-the-kelvin-scale-the-pr"> If the temperature of a gas in a container is doubled on the Kelvin scale, what will happen to... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-the-original-pressure-of-a-gas-sample-at-20-c-was-5-00-atm-and-it-is-heated-u"> If the original pressure of a gas sample at 20 ˚C was 5.00 atm, and it is heated up to 40. ˚C ,... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-gay-lussac-s-law-state"> What does Gay Lussac's law state? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-gay-lussac-s-law-relate"> What does Gay Lussac's law relate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-sample-of-o2-under-2-00-atm-occupies-500-ml-at-25-0-c-what-pressure-will-the-s"> A sample of O2 under 2.00 atm occupies 500 ml at 25.0˚C. What pressure will the sample have at 0.0˚C ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-sample-of-o2-under-2-00-atm-occupies-500-ml-at-25-0-c-what-temperature-will-be"> A sample of O2 under 2.00 atm occupies 500 ml at 25.0˚C. What temperature will be needed to... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-gay-lussac-s-law-direct-or-inverse"> Is Gay Lussac's law direct or inverse? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/determine-the-pressure-change-when-a-constant-volume-of-gas-at-1-00-atm-is-heate"> Determine the pressure change when a constant volume of gas at 1.00 atm is heated from 20.0 ˚C... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/gay-lussac-s-law"> See all questions in Gay Lussac's Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 44298 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A gas has a pressure of 699.0 mm Hg at 40.0°C. What is the temperature at standard pressure?	null
2,245	acd9c12c-6ddd-11ea-8e1a-ccda262736ce	https://socratic.org/questions/581cc40a11ef6b4d00691913	Cl2(g) + H2O(l) -> HClO(g) + HCl(aq)	start chemical_equation qc_end chemical_equation 4 10 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the equation"}]	[{"type":"chemical equation","value":"Cl2(g) + H2O(l) -> HClO(g) + HCl(aq)"}]	[{"type":"chemical equation","value":"Cl2(g) + H2O(l) -> HClO(g) + HCl(aq)"}]	<h1 class="questionTitle" itemprop="name">How do you balance #Cl_2(g) + H_2O(l) rarr HClO(g) + HCl(aq)#?</h1>	null	Cl2(g) + H2O(l) -> HClO(g) + HCl(aq)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is a disproportionation reaction, in which chlorine gas is oxidized and reduced:</p> <p><mathjax>#1/2Cl_2(g) +H_2O(l) rarr ClO^(-) +2H^+ +e^- #</mathjax> <mathjax>#i.#</mathjax></p> <p><mathjax>#1/2Cl_2(g) +e^(-) rarr Cl^(-)#</mathjax> <mathjax>#ii.#</mathjax></p> <p>Overall <mathjax>#i.+ii.=#</mathjax>:</p> <p><mathjax>#Cl_2(g) +H_2O(l) rarr ClO^(-)+Cl^(-) +2H^+#</mathjax></p> <p>OR</p> <p><mathjax>#Cl_2(g) +H_2O(l) rarr ClOH(aq)+HCl(aq)#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Is this not already balanced?: </p> <p><mathjax>#Cl_2(g) + H_2O(l) rarr HClO(aq) + HCl(aq)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is a disproportionation reaction, in which chlorine gas is oxidized and reduced:</p> <p><mathjax>#1/2Cl_2(g) +H_2O(l) rarr ClO^(-) +2H^+ +e^- #</mathjax> <mathjax>#i.#</mathjax></p> <p><mathjax>#1/2Cl_2(g) +e^(-) rarr Cl^(-)#</mathjax> <mathjax>#ii.#</mathjax></p> <p>Overall <mathjax>#i.+ii.=#</mathjax>:</p> <p><mathjax>#Cl_2(g) +H_2O(l) rarr ClO^(-)+Cl^(-) +2H^+#</mathjax></p> <p>OR</p> <p><mathjax>#Cl_2(g) +H_2O(l) rarr ClOH(aq)+HCl(aq)#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you balance #Cl_2(g) + H_2O(l) rarr HClO(g) + HCl(aq)#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="331440" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-11-04T17:33:45" itemprop="dateCreated"> Nov 4, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Is this not already balanced?: </p> <p><mathjax>#Cl_2(g) + H_2O(l) rarr HClO(aq) + HCl(aq)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is a disproportionation reaction, in which chlorine gas is oxidized and reduced:</p> <p><mathjax>#1/2Cl_2(g) +H_2O(l) rarr ClO^(-) +2H^+ +e^- #</mathjax> <mathjax>#i.#</mathjax></p> <p><mathjax>#1/2Cl_2(g) +e^(-) rarr Cl^(-)#</mathjax> <mathjax>#ii.#</mathjax></p> <p>Overall <mathjax>#i.+ii.=#</mathjax>:</p> <p><mathjax>#Cl_2(g) +H_2O(l) rarr ClO^(-)+Cl^(-) +2H^+#</mathjax></p> <p>OR</p> <p><mathjax>#Cl_2(g) +H_2O(l) rarr ClOH(aq)+HCl(aq)#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/331440" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------> H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -> Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? Aluminum and hydrochloric acid react to form aluminum... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equation-sodium-phosphate-and-calcium-chloride-r"> How can I balance this chemical equation? Sodium phosphate and calcium chloride react to form... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-equation-kclo3-kcl-o2"> How can I balance this equation? ____ #KClO_3 -># ____ #KCl +# ____ #O_2# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-balancing-chemical-equations-important"> Why is balancing chemical equations important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/balancing-chemical-equations"> See all questions in Balancing Chemical Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3305 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How do you balance #Cl_2(g) + H_2O(l) rarr HClO(g) + HCl(aq)#?	null
2,246	aae1433f-6ddd-11ea-a140-ccda262736ce	https://socratic.org/questions/during-an-experiment-30-ml-of-a-gas-is-collected-at-401-kpa-what-will-the-volume	119.11 mL	start physical_unit 7 7 volume ml qc_end physical_unit 7 7 3 4 volume qc_end physical_unit 7 7 11 12 pressure qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Volume2 [OF] the gas [IN] mL"}]	[{"type":"physical unit","value":"119.11 mL"}]	[{"type":"physical unit","value":"Volume1 [OF] the gas [=] \\pu{30 mL }"},{"type":"physical unit","value":"Pressure1 [OF] the gas [=] \\pu{401 kPa}"},{"type":"other","value":"Standard pressure."}]	<h1 class="questionTitle" itemprop="name">During an experiment, 30 mL of a gas is collected at 401 kPa. What will the volume be at standard pressure? </h1>	null	119.11 mL	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>If the temperature changes the volume will also change. The question does not give any information regarding the temperature so it is necessary to assume the temperature does not change in this problem.</p> <p>Boyle's Law states that pressure and volume are inversely related so in this problem as the pressure decreases the volume will increase. </p> <p>Boyle's Law <mathjax># V_1/ V_2 = P_2/ P_1 #</mathjax></p> <p><mathjax># V_1 = 30 ml#</mathjax> <br/> <mathjax># V_2 = unknown#</mathjax><br/> <mathjax>#P_1 = 401 kpa #</mathjax><br/> <mathjax>#P_2 = 101 kpa#</mathjax> 101 kpa is the standard pressure. </p> <p><mathjax># 30/V_2 = 101/401#</mathjax> solving for <mathjax># V_2#</mathjax> gives</p> <p><mathjax># V_2 = 30 ml xx 401/101#</mathjax> </p> <p><mathjax>#V_2#</mathjax> = 119 ml </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Volume = 119 ml If the temperature does not change it is possible to calculate the new volume using <a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's Law</a>. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>If the temperature changes the volume will also change. The question does not give any information regarding the temperature so it is necessary to assume the temperature does not change in this problem.</p> <p>Boyle's Law states that pressure and volume are inversely related so in this problem as the pressure decreases the volume will increase. </p> <p>Boyle's Law <mathjax># V_1/ V_2 = P_2/ P_1 #</mathjax></p> <p><mathjax># V_1 = 30 ml#</mathjax> <br/> <mathjax># V_2 = unknown#</mathjax><br/> <mathjax>#P_1 = 401 kpa #</mathjax><br/> <mathjax>#P_2 = 101 kpa#</mathjax> 101 kpa is the standard pressure. </p> <p><mathjax># 30/V_2 = 101/401#</mathjax> solving for <mathjax># V_2#</mathjax> gives</p> <p><mathjax># V_2 = 30 ml xx 401/101#</mathjax> </p> <p><mathjax>#V_2#</mathjax> = 119 ml </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">During an experiment, 30 mL of a gas is collected at 401 kPa. What will the volume be at standard pressure? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/combined-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Combined Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="302466" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/david-drayer"><img alt="" class="" src="https://graph.facebook.com/10206723679871989/picture?height=50&width=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/david-drayer"> David Drayer </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-08-25T03:25:25" itemprop="dateCreated"> Aug 25, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Volume = 119 ml If the temperature does not change it is possible to calculate the new volume using <a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's Law</a>. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>If the temperature changes the volume will also change. The question does not give any information regarding the temperature so it is necessary to assume the temperature does not change in this problem.</p> <p>Boyle's Law states that pressure and volume are inversely related so in this problem as the pressure decreases the volume will increase. </p> <p>Boyle's Law <mathjax># V_1/ V_2 = P_2/ P_1 #</mathjax></p> <p><mathjax># V_1 = 30 ml#</mathjax> <br/> <mathjax># V_2 = unknown#</mathjax><br/> <mathjax>#P_1 = 401 kpa #</mathjax><br/> <mathjax>#P_2 = 101 kpa#</mathjax> 101 kpa is the standard pressure. </p> <p><mathjax># 30/V_2 = 101/401#</mathjax> solving for <mathjax># V_2#</mathjax> gives</p> <p><mathjax># V_2 = 30 ml xx 401/101#</mathjax> </p> <p><mathjax>#V_2#</mathjax> = 119 ml </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/302466" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5345df5f02bf345f71b1c8e8"> Question #1c8e8 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ac3df02bf342f4c3bfabb"> Question #bfabb </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-you-want-to-solve-for-the-volume-of-a-gas-v2-and-p1-is-greater-than-p2-would-"> If you want to solve for the volume of a gas (V2) and P1 is greater than P2, would you expect V2... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-modern-refrigerator-take-advantage-of-the-gas-laws-to-remove-heat-f"> How does the modern refrigerator take advantage of the gas laws to remove heat from a system? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-certain-sample-of-gas-has-a-volume-of-0-452-l-measured-at-87-c-and-0-620-atm-w"> A certain sample of gas has a volume of 0.452 L measured at 87°C and 0.620 atm. What is its... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/which-situations-does-the-combined-gas-law-enable-you-to-do-calculations-when-th"> Which situations does the combined gas law enable you to do calculations when the other gas laws... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-small-research-submarine-with-a-volume-of-1-2x10-5-l-has-an-internal-pressure-"> A small research submarine with a volume of 1.2x10 ^5 L has an internal pressure of 1.0 atm and... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-the-combined-gas-law-different-from-boyle-s-law"> How is the combined gas law different from boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-pressure-of-an-combined-gas-change-as-temperature-increases"> How does the pressure of an combined gas change as temperature increases? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-ideal-gas-law-differ-from-the-combined-gas-law-1"> How does the ideal gas law differ from the combined gas law? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/combined-gas-law"> See all questions in Combined Gas Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1359 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	During an experiment, 30 mL of a gas is collected at 401 kPa. What will the volume be at standard pressure?	null
2,247	abf9f17e-6ddd-11ea-af58-ccda262736ce	https://socratic.org/questions/5947fe0011ef6b2bcad55532	0.01	start physical_unit 5 5 ka none qc_end physical_unit 5 5 11 12 concentration qc_end physical_unit 5 5 15 16 concentration qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Ka [OF] HNO2"}]	[{"type":"physical unit","value":"0.01"}]	[{"type":"physical unit","value":"Concentration1 [OF] HNO2 solution [=] \\pu{0.14 M}"},{"type":"physical unit","value":"Concentration2 [OF] HNO2 solution [=] \\pu{0.11 M}"},{"type":"other","value":"The reaction species reached equilibrium."}]	<h1 class="questionTitle" itemprop="name">What is the #K_a# for #"HNO"_2# if its starting concentration of #"0.14 M"# decreased to #"0.11 M"# by the time the reaction species reached equilibrium?</h1>	null	0.01	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>Let's pretend we are trying to solve this question using an ICE table. We would write</p> <p><mathjax>#color(white)(mmmmmm)"HNO"_2 + "H"_2"O" ⇌ "H"_3"O"^"+" + "NO"_2^"-"#</mathjax><br/> <mathjax>#"I/mol·L"^"-1":color(white)(m)0.14color(white)(mmmmmmml)0color(white)(mmmll)0 #</mathjax><br/> <mathjax>#"C/mol·L"^"-1":color(white)(m)"-"xcolor(white)(mmmmmmml)"+"xcolor(white)(mmm)"+"x #</mathjax><br/> <mathjax>#"E/mol·L"^"-1":color(white)(l) "0.14-"xcolor(white)(mmmmmmll)xcolor(white)(mmmll)x#</mathjax></p> <p>In this case, we are told that the equilibrium concentration of the acid, i.e., <mathjax>#["HNO"_2] = "0.11 mol/L"#</mathjax>.</p> <p>In other words,</p> <p><mathjax>#0.14-x = 0.11#</mathjax></p> <p><mathjax>#x = 0.14 - 0.11 = 0.03#</mathjax></p> <blockquote></blockquote> <p>If we insert this number into the ICE table, we get</p> <p><mathjax>#color(white)(mmmmmm)"HNO"_2 + "H"_2"O" ⇌ "H"_3"O"^"+" + "NO"_2^"-"#</mathjax><br/> <mathjax>#"I/mol·L"^"-1":color(white)(m)0.14color(white)(mmmmmmml)0color(white)(mmmll)0 #</mathjax><br/> <mathjax>#"C/mol·L"^"-1":color(white)(l)"-0.03"color(white)(mmmmmm)"+0.03"color(white)(ml)"+0.03"#</mathjax><br/> <mathjax>#"E/mol·L"^"-1":color(white)(ll) 0.11color(white)(mmmmmmm)0.03color(white)(mml)0.03#</mathjax></p> <blockquote></blockquote> <p>We can now insert these numbers into the <mathjax>#K_text(a)#</mathjax> expression.</p> <p><mathjax>#K_text(a) = (["H"_3"O"^"+"]["NO"_2^"-"])/(["HNO"_2]) = (0.03 × 0.03)/0.11 = 0.008#</mathjax> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#K_text(a) = 0.008#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>Let's pretend we are trying to solve this question using an ICE table. We would write</p> <p><mathjax>#color(white)(mmmmmm)"HNO"_2 + "H"_2"O" ⇌ "H"_3"O"^"+" + "NO"_2^"-"#</mathjax><br/> <mathjax>#"I/mol·L"^"-1":color(white)(m)0.14color(white)(mmmmmmml)0color(white)(mmmll)0 #</mathjax><br/> <mathjax>#"C/mol·L"^"-1":color(white)(m)"-"xcolor(white)(mmmmmmml)"+"xcolor(white)(mmm)"+"x #</mathjax><br/> <mathjax>#"E/mol·L"^"-1":color(white)(l) "0.14-"xcolor(white)(mmmmmmll)xcolor(white)(mmmll)x#</mathjax></p> <p>In this case, we are told that the equilibrium concentration of the acid, i.e., <mathjax>#["HNO"_2] = "0.11 mol/L"#</mathjax>.</p> <p>In other words,</p> <p><mathjax>#0.14-x = 0.11#</mathjax></p> <p><mathjax>#x = 0.14 - 0.11 = 0.03#</mathjax></p> <blockquote></blockquote> <p>If we insert this number into the ICE table, we get</p> <p><mathjax>#color(white)(mmmmmm)"HNO"_2 + "H"_2"O" ⇌ "H"_3"O"^"+" + "NO"_2^"-"#</mathjax><br/> <mathjax>#"I/mol·L"^"-1":color(white)(m)0.14color(white)(mmmmmmml)0color(white)(mmmll)0 #</mathjax><br/> <mathjax>#"C/mol·L"^"-1":color(white)(l)"-0.03"color(white)(mmmmmm)"+0.03"color(white)(ml)"+0.03"#</mathjax><br/> <mathjax>#"E/mol·L"^"-1":color(white)(ll) 0.11color(white)(mmmmmmm)0.03color(white)(mml)0.03#</mathjax></p> <blockquote></blockquote> <p>We can now insert these numbers into the <mathjax>#K_text(a)#</mathjax> expression.</p> <p><mathjax>#K_text(a) = (["H"_3"O"^"+"]["NO"_2^"-"])/(["HNO"_2]) = (0.03 × 0.03)/0.11 = 0.008#</mathjax> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the #K_a# for #"HNO"_2# if its starting concentration of #"0.14 M"# decreased to #"0.11 M"# by the time the reaction species reached equilibrium?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/the-ph-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">pH</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="442037" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> <a class="secondContributorPic" href="/users/truong-son-n"><img alt="" class="" src="https://profilepictures.socratic.org/07k4plnQfmnmzMuesQzw_14844-1449381920.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a>·<a class="topContributorLink" href="/users/truong-son-n"> Truong-Son N. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-19T19:57:00" itemprop="dateCreated"> Jun 19, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#K_text(a) = 0.008#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>Let's pretend we are trying to solve this question using an ICE table. We would write</p> <p><mathjax>#color(white)(mmmmmm)"HNO"_2 + "H"_2"O" ⇌ "H"_3"O"^"+" + "NO"_2^"-"#</mathjax><br/> <mathjax>#"I/mol·L"^"-1":color(white)(m)0.14color(white)(mmmmmmml)0color(white)(mmmll)0 #</mathjax><br/> <mathjax>#"C/mol·L"^"-1":color(white)(m)"-"xcolor(white)(mmmmmmml)"+"xcolor(white)(mmm)"+"x #</mathjax><br/> <mathjax>#"E/mol·L"^"-1":color(white)(l) "0.14-"xcolor(white)(mmmmmmll)xcolor(white)(mmmll)x#</mathjax></p> <p>In this case, we are told that the equilibrium concentration of the acid, i.e., <mathjax>#["HNO"_2] = "0.11 mol/L"#</mathjax>.</p> <p>In other words,</p> <p><mathjax>#0.14-x = 0.11#</mathjax></p> <p><mathjax>#x = 0.14 - 0.11 = 0.03#</mathjax></p> <blockquote></blockquote> <p>If we insert this number into the ICE table, we get</p> <p><mathjax>#color(white)(mmmmmm)"HNO"_2 + "H"_2"O" ⇌ "H"_3"O"^"+" + "NO"_2^"-"#</mathjax><br/> <mathjax>#"I/mol·L"^"-1":color(white)(m)0.14color(white)(mmmmmmml)0color(white)(mmmll)0 #</mathjax><br/> <mathjax>#"C/mol·L"^"-1":color(white)(l)"-0.03"color(white)(mmmmmm)"+0.03"color(white)(ml)"+0.03"#</mathjax><br/> <mathjax>#"E/mol·L"^"-1":color(white)(ll) 0.11color(white)(mmmmmmm)0.03color(white)(mml)0.03#</mathjax></p> <blockquote></blockquote> <p>We can now insert these numbers into the <mathjax>#K_text(a)#</mathjax> expression.</p> <p><mathjax>#K_text(a) = (["H"_3"O"^"+"]["NO"_2^"-"])/(["HNO"_2]) = (0.03 × 0.03)/0.11 = 0.008#</mathjax> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/442037" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-pka"> How do you determine pH from pKa? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-ph-values-of-acids-and-bases-differ"> How do pH values of acids and bases differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-something-on-a-ph-scale"> How do you calculate something on a pH scale? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-diprotic-acid"> How do you calculate pH diprotic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-from-acid-dissociation-constant"> How do you calculate pH from acid dissociation constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-of-acid-and-base-solution"> How do you calculate pH of acid and base solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ph-scale-0-14"> Why is the pH scale 0-14? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-ph-the-measure-of-the-hydrogen-ion-concentration"> Is pH a measure of the hydrogen ion concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-solubility-affect-ph"> How does solubility affect pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-ph-relate-to-pka-in-a-titration"> How does pH relate to pKa in a titration? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/the-ph-concept"> See all questions in pH </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1342 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the #K_a# for #"HNO"_2# if its starting concentration of #"0.14 M"# decreased to #"0.11 M"# by the time the reaction species reached equilibrium?	null
2,248	abff4623-6ddd-11ea-8931-ccda262736ce	https://socratic.org/questions/56fe052211ef6b2495f6e3f5	3.33 molar	start physical_unit 21 22 mole mol/l qc_end physical_unit 8 9 4 5 mole qc_end end	[{"type":"physical unit","value":"Mole [OF] this hydrocarbon [IN] molar"}]	[{"type":"physical unit","value":"3.33 molar"}]	[{"type":"physical unit","value":"Mole [OF] CARBON ATOMS [=] \\pu{10 mol}"}]	<h1 class="questionTitle" itemprop="name">If there are a #10*mol# quantity of CARBON ATOMS in a sample of propane, what is the molar quantity of this hydrocarbon?</h1>	null	3.33 molar	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Each formula unit of propane contains 3 carbon atoms, and 8 hydrogen atoms. Thus if there are <mathjax>#10.0#</mathjax> <mathjax>#mol#</mathjax> carbon atoms in the propane sample, there are:</p> <p><mathjax>#10/3#</mathjax> <mathjax>#mol#</mathjax> <mathjax>#C_3H_8#</mathjax> and <mathjax>#80/3#</mathjax> <mathjax>#mol#</mathjax> <mathjax>#H#</mathjax> atoms. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>There are clearly <mathjax>#10/3#</mathjax> <mathjax>#mol#</mathjax> propane. Why?</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Each formula unit of propane contains 3 carbon atoms, and 8 hydrogen atoms. Thus if there are <mathjax>#10.0#</mathjax> <mathjax>#mol#</mathjax> carbon atoms in the propane sample, there are:</p> <p><mathjax>#10/3#</mathjax> <mathjax>#mol#</mathjax> <mathjax>#C_3H_8#</mathjax> and <mathjax>#80/3#</mathjax> <mathjax>#mol#</mathjax> <mathjax>#H#</mathjax> atoms. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">If there are a #10*mol# quantity of CARBON ATOMS in a sample of propane, what is the molar quantity of this hydrocarbon?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="248427" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-04-02T09:44:47" itemprop="dateCreated"> Apr 2, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>There are clearly <mathjax>#10/3#</mathjax> <mathjax>#mol#</mathjax> propane. Why?</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Each formula unit of propane contains 3 carbon atoms, and 8 hydrogen atoms. Thus if there are <mathjax>#10.0#</mathjax> <mathjax>#mol#</mathjax> carbon atoms in the propane sample, there are:</p> <p><mathjax>#10/3#</mathjax> <mathjax>#mol#</mathjax> <mathjax>#C_3H_8#</mathjax> and <mathjax>#80/3#</mathjax> <mathjax>#mol#</mathjax> <mathjax>#H#</mathjax> atoms. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/248427" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3510 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	If there are a #10*mol# quantity of CARBON ATOMS in a sample of propane, what is the molar quantity of this hydrocarbon?	null
2,249	abf0a326-6ddd-11ea-a181-ccda262736ce	https://socratic.org/questions/how-many-hydrogen-atoms-are-in-4-5-moles-of-methane-molecules	1.08 × 10^25	start physical_unit 2 3 number none qc_end physical_unit 9 10 6 7 mole qc_end end	[{"type":"physical unit","value":"Number [OF] hydrogen atoms"}]	[{"type":"physical unit","value":"1.08 × 10^25"}]	[{"type":"physical unit","value":"Mole [OF] methane molecules [=] \\pu{4.5 moles}"}]	<h1 class="questionTitle" itemprop="name">How many hydrogen atoms are in 4.5 moles of methane molecules? </h1>	null	1.08 × 10^25	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Instead of <mathjax>#"moles"#</mathjax>, I could use <mathjax>#"dozens"#</mathjax> as my metric. How many hydrogen atoms are in <mathjax>#4#</mathjax> <mathjax>#1/2#</mathjax> <mathjax>#"dozen"#</mathjax> methane molecules? Well clearly each methane molecule contributes <mathjax>#4#</mathjax> hydrogen atoms; therefore there are <mathjax>#4xx4.5xx12=216#</mathjax> <mathjax>#"hydrogen atoms"#</mathjax>. </p> <p>In a <mathjax>#"mole"#</mathjax>, <mathjax>#"a Chemist's dozen"#</mathjax>, there are <mathjax>#6.022xx10^23#</mathjax> individual particles; <mathjax>#N_A=6.022xx10^23mol^-1#</mathjax>.</p> <p>So in <mathjax>#4.5mol#</mathjax> of <mathjax>#CH_4#</mathjax>, there are <mathjax>#4.5*molxxN_Axx4#</mathjax> <mathjax>#"hydrogen atoms"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#18xxN_A#</mathjax> <mathjax>#"hydrogen atoms"#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Well there are 18 moles of hydrogen atoms.........."#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Instead of <mathjax>#"moles"#</mathjax>, I could use <mathjax>#"dozens"#</mathjax> as my metric. How many hydrogen atoms are in <mathjax>#4#</mathjax> <mathjax>#1/2#</mathjax> <mathjax>#"dozen"#</mathjax> methane molecules? Well clearly each methane molecule contributes <mathjax>#4#</mathjax> hydrogen atoms; therefore there are <mathjax>#4xx4.5xx12=216#</mathjax> <mathjax>#"hydrogen atoms"#</mathjax>. </p> <p>In a <mathjax>#"mole"#</mathjax>, <mathjax>#"a Chemist's dozen"#</mathjax>, there are <mathjax>#6.022xx10^23#</mathjax> individual particles; <mathjax>#N_A=6.022xx10^23mol^-1#</mathjax>.</p> <p>So in <mathjax>#4.5mol#</mathjax> of <mathjax>#CH_4#</mathjax>, there are <mathjax>#4.5*molxxN_Axx4#</mathjax> <mathjax>#"hydrogen atoms"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#18xxN_A#</mathjax> <mathjax>#"hydrogen atoms"#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many hydrogen atoms are in 4.5 moles of methane molecules? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="386439" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-04T16:23:12" itemprop="dateCreated"> Mar 4, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Well there are 18 moles of hydrogen atoms.........."#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Instead of <mathjax>#"moles"#</mathjax>, I could use <mathjax>#"dozens"#</mathjax> as my metric. How many hydrogen atoms are in <mathjax>#4#</mathjax> <mathjax>#1/2#</mathjax> <mathjax>#"dozen"#</mathjax> methane molecules? Well clearly each methane molecule contributes <mathjax>#4#</mathjax> hydrogen atoms; therefore there are <mathjax>#4xx4.5xx12=216#</mathjax> <mathjax>#"hydrogen atoms"#</mathjax>. </p> <p>In a <mathjax>#"mole"#</mathjax>, <mathjax>#"a Chemist's dozen"#</mathjax>, there are <mathjax>#6.022xx10^23#</mathjax> individual particles; <mathjax>#N_A=6.022xx10^23mol^-1#</mathjax>.</p> <p>So in <mathjax>#4.5mol#</mathjax> of <mathjax>#CH_4#</mathjax>, there are <mathjax>#4.5*molxxN_Axx4#</mathjax> <mathjax>#"hydrogen atoms"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#18xxN_A#</mathjax> <mathjax>#"hydrogen atoms"#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/386439" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 6276 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many hydrogen atoms are in 4.5 moles of methane molecules?	null
2,250	aa36ae1c-6ddd-11ea-b434-ccda262736ce	https://socratic.org/questions/how-many-grams-of-cuso-45h-2o-are-needed-to-prepare-100-ml-of-a-0-10-m-solution	2.50 grams	start physical_unit 4 4 mass g qc_end physical_unit 15 15 9 10 volume qc_end physical_unit 4 4 13 14 molarity qc_end end	[{"type":"physical unit","value":"Mass [OF] CuSO4.5H2O [IN] grams"}]	[{"type":"physical unit","value":"2.50 grams"}]	[{"type":"physical unit","value":"Volume [OF] CuSO4.5H2O solution [=] \\pu{100 mL}"},{"type":"physical unit","value":"Molarity [OF] CuSO4.5H2O solution [=] \\pu{0.10 M}"}]	<h1 class="questionTitle" itemprop="name">How many grams of #CuSO_4 * 5H_2O# are needed to prepare 100 mL of a 0.10 M solution?</h1>	null	2.50 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You're dealing with <em>copper(II) sulfate pentahydrate</em>, <mathjax>#"CuSO"_4 * 5"H"_2"O"#</mathjax>, an <strong><a href="http://socratic.org/chemistry/ionic-bonds-and-formulas/ionic-compounds">ionic compound</a></strong> that contains <em>water of crystallization</em> in its structure. </p> <p>More specifically, you have <strong>five moles</strong> of water of crystallization <em>for every</em> <strong>one mole</strong> of anhydrous copper(II) sulfate. This means that you're going to have to account for the mass of this water of crystallization in your calculations. </p> <p>Now, you need your target solution to have a <strong><a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></strong> of <mathjax>#"0.10 M"#</mathjax> and a volume of <mathjax>#"100. mL"#</mathjax>. Since <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> is defined as <em>moles of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a></em> per liter of solution, you can say that the target solution must contain</p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a)c = n/V implies n = c * Vcolor(white)(a/a)\|)))#</mathjax></p> <p><mathjax>#n_(CuSO_4) = "0.10 mol" color(red)(cancel(color(black)("L"^(-1)))) * 100. * 10^(-3)color(red)(cancel(color(black)("L"))) = "0.0100 moles CuSO"_4#</mathjax></p> </blockquote> <p>It's important to realize that your solute is <strong>anhydrous</strong> copper(II) sulfate, <mathjax>#"CuSO"_4#</mathjax>. Use the anhydrous salt's <strong>molar mass</strong> to determine how many grams of copper(II) sulfate would contain that many moles</p> <blockquote> <p><mathjax>#0.0100 color(red)(cancel(color(black)("moles CuSO"_4))) * "159.61 g"/(1color(red)(cancel(color(black)("mole CuSO"_4)))) = "1.596 g CuSO"_4#</mathjax></p> </blockquote> <p>Now you have to determine how many grams of copper(II) sulfate pentahydrate would contain this many grams of copper(II) sulfate. </p> <p>To do that, calculate the hydrate's <strong><a href="http://socratic.org/chemistry/the-mole-concept/percent-composition">percent composition</a></strong> by using its <strong>molar mass</strong> and the molar mass of anhydrous copper(II) sulfate. </p> <p>Remember that there are <mathjax>#color(red)(5)#</mathjax> <strong>moles</strong> of water for every <mathjax>#1#</mathjax> <strong>mole</strong> of hydrate</p> <blockquote> <p><mathjax>#(159.61 color(red)(cancel(color(black)("g mol"^(-1)))))/( (159.61 + color(red)(5) xx 18.015)color(red)(cancel(color(black)("g mol"^(-1))))) xx 100 = "63.92% CuSO"_4#</mathjax></p> </blockquote> <p>This tells you that <strong>for every</strong> <mathjax>#"100 g"#</mathjax> of copper(II) sulfate pentahydrate, you get <mathjax>#"63.92 g"#</mathjax> of anhydrous copper(II) sulfate. Use this as a conversion factor to get</p> <blockquote> <p><mathjax>#1.596color(red)(cancel(color(black)("g CuSO"_4))) * ("100 g CuSO"_4 * 5"H"_2"O")/(63.92color(red)(cancel(color(black)("g CuSO"_4)))) = "2.497 g CuSO"_4 * 5"H"_2"O"#</mathjax></p> </blockquote> <p>Rounded to two <strong><a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the answer will be </p> <blockquote> <p><mathjax>#m_(CuSO_4 * 5H_2O) = color(green)(\|bar(ul(color(white)(a/a)"2.5 g CuSO"_4 * 5"H"_2"O"color(white)(a/a)\|)))#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"2.5 g CuSO"_4 * 5"H"_2"O"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You're dealing with <em>copper(II) sulfate pentahydrate</em>, <mathjax>#"CuSO"_4 * 5"H"_2"O"#</mathjax>, an <strong><a href="http://socratic.org/chemistry/ionic-bonds-and-formulas/ionic-compounds">ionic compound</a></strong> that contains <em>water of crystallization</em> in its structure. </p> <p>More specifically, you have <strong>five moles</strong> of water of crystallization <em>for every</em> <strong>one mole</strong> of anhydrous copper(II) sulfate. This means that you're going to have to account for the mass of this water of crystallization in your calculations. </p> <p>Now, you need your target solution to have a <strong><a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></strong> of <mathjax>#"0.10 M"#</mathjax> and a volume of <mathjax>#"100. mL"#</mathjax>. Since <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> is defined as <em>moles of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a></em> per liter of solution, you can say that the target solution must contain</p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a)c = n/V implies n = c * Vcolor(white)(a/a)\|)))#</mathjax></p> <p><mathjax>#n_(CuSO_4) = "0.10 mol" color(red)(cancel(color(black)("L"^(-1)))) * 100. * 10^(-3)color(red)(cancel(color(black)("L"))) = "0.0100 moles CuSO"_4#</mathjax></p> </blockquote> <p>It's important to realize that your solute is <strong>anhydrous</strong> copper(II) sulfate, <mathjax>#"CuSO"_4#</mathjax>. Use the anhydrous salt's <strong>molar mass</strong> to determine how many grams of copper(II) sulfate would contain that many moles</p> <blockquote> <p><mathjax>#0.0100 color(red)(cancel(color(black)("moles CuSO"_4))) * "159.61 g"/(1color(red)(cancel(color(black)("mole CuSO"_4)))) = "1.596 g CuSO"_4#</mathjax></p> </blockquote> <p>Now you have to determine how many grams of copper(II) sulfate pentahydrate would contain this many grams of copper(II) sulfate. </p> <p>To do that, calculate the hydrate's <strong><a href="http://socratic.org/chemistry/the-mole-concept/percent-composition">percent composition</a></strong> by using its <strong>molar mass</strong> and the molar mass of anhydrous copper(II) sulfate. </p> <p>Remember that there are <mathjax>#color(red)(5)#</mathjax> <strong>moles</strong> of water for every <mathjax>#1#</mathjax> <strong>mole</strong> of hydrate</p> <blockquote> <p><mathjax>#(159.61 color(red)(cancel(color(black)("g mol"^(-1)))))/( (159.61 + color(red)(5) xx 18.015)color(red)(cancel(color(black)("g mol"^(-1))))) xx 100 = "63.92% CuSO"_4#</mathjax></p> </blockquote> <p>This tells you that <strong>for every</strong> <mathjax>#"100 g"#</mathjax> of copper(II) sulfate pentahydrate, you get <mathjax>#"63.92 g"#</mathjax> of anhydrous copper(II) sulfate. Use this as a conversion factor to get</p> <blockquote> <p><mathjax>#1.596color(red)(cancel(color(black)("g CuSO"_4))) * ("100 g CuSO"_4 * 5"H"_2"O")/(63.92color(red)(cancel(color(black)("g CuSO"_4)))) = "2.497 g CuSO"_4 * 5"H"_2"O"#</mathjax></p> </blockquote> <p>Rounded to two <strong><a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the answer will be </p> <blockquote> <p><mathjax>#m_(CuSO_4 * 5H_2O) = color(green)(\|bar(ul(color(white)(a/a)"2.5 g CuSO"_4 * 5"H"_2"O"color(white)(a/a)\|)))#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many grams of #CuSO_4 * 5H_2O# are needed to prepare 100 mL of a 0.10 M solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="237987" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-11T01:45:42" itemprop="dateCreated"> Mar 11, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"2.5 g CuSO"_4 * 5"H"_2"O"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You're dealing with <em>copper(II) sulfate pentahydrate</em>, <mathjax>#"CuSO"_4 * 5"H"_2"O"#</mathjax>, an <strong><a href="http://socratic.org/chemistry/ionic-bonds-and-formulas/ionic-compounds">ionic compound</a></strong> that contains <em>water of crystallization</em> in its structure. </p> <p>More specifically, you have <strong>five moles</strong> of water of crystallization <em>for every</em> <strong>one mole</strong> of anhydrous copper(II) sulfate. This means that you're going to have to account for the mass of this water of crystallization in your calculations. </p> <p>Now, you need your target solution to have a <strong><a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></strong> of <mathjax>#"0.10 M"#</mathjax> and a volume of <mathjax>#"100. mL"#</mathjax>. Since <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> is defined as <em>moles of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a></em> per liter of solution, you can say that the target solution must contain</p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a)c = n/V implies n = c * Vcolor(white)(a/a)\|)))#</mathjax></p> <p><mathjax>#n_(CuSO_4) = "0.10 mol" color(red)(cancel(color(black)("L"^(-1)))) * 100. * 10^(-3)color(red)(cancel(color(black)("L"))) = "0.0100 moles CuSO"_4#</mathjax></p> </blockquote> <p>It's important to realize that your solute is <strong>anhydrous</strong> copper(II) sulfate, <mathjax>#"CuSO"_4#</mathjax>. Use the anhydrous salt's <strong>molar mass</strong> to determine how many grams of copper(II) sulfate would contain that many moles</p> <blockquote> <p><mathjax>#0.0100 color(red)(cancel(color(black)("moles CuSO"_4))) * "159.61 g"/(1color(red)(cancel(color(black)("mole CuSO"_4)))) = "1.596 g CuSO"_4#</mathjax></p> </blockquote> <p>Now you have to determine how many grams of copper(II) sulfate pentahydrate would contain this many grams of copper(II) sulfate. </p> <p>To do that, calculate the hydrate's <strong><a href="http://socratic.org/chemistry/the-mole-concept/percent-composition">percent composition</a></strong> by using its <strong>molar mass</strong> and the molar mass of anhydrous copper(II) sulfate. </p> <p>Remember that there are <mathjax>#color(red)(5)#</mathjax> <strong>moles</strong> of water for every <mathjax>#1#</mathjax> <strong>mole</strong> of hydrate</p> <blockquote> <p><mathjax>#(159.61 color(red)(cancel(color(black)("g mol"^(-1)))))/( (159.61 + color(red)(5) xx 18.015)color(red)(cancel(color(black)("g mol"^(-1))))) xx 100 = "63.92% CuSO"_4#</mathjax></p> </blockquote> <p>This tells you that <strong>for every</strong> <mathjax>#"100 g"#</mathjax> of copper(II) sulfate pentahydrate, you get <mathjax>#"63.92 g"#</mathjax> of anhydrous copper(II) sulfate. Use this as a conversion factor to get</p> <blockquote> <p><mathjax>#1.596color(red)(cancel(color(black)("g CuSO"_4))) * ("100 g CuSO"_4 * 5"H"_2"O")/(63.92color(red)(cancel(color(black)("g CuSO"_4)))) = "2.497 g CuSO"_4 * 5"H"_2"O"#</mathjax></p> </blockquote> <p>Rounded to two <strong><a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the answer will be </p> <blockquote> <p><mathjax>#m_(CuSO_4 * 5H_2O) = color(green)(\|bar(ul(color(white)(a/a)"2.5 g CuSO"_4 * 5"H"_2"O"color(white)(a/a)\|)))#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/237987" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-morality-be-used-as-a-conversion-factor"> How can molarity be used as a conversion factor? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-high-can-molarity-be"> How high can molarity be? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-molarity-change-with-temperature"> How does molarity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molarity-of-a-solution"> How do you find molarity of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-10-naoh"> What is the molarity of 10 NaOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-3-hydrogen-peroxide"> What is the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 188262 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many grams of #CuSO_4 * 5H_2O# are needed to prepare 100 mL of a 0.10 M solution?	null
2,251	aa16ea68-6ddd-11ea-a124-ccda262736ce	https://socratic.org/questions/how-many-moles-of-iron-fe-can-be-made-from-fe-2o-3-by-the-use-of-18-moles-of-car	12 moles	start physical_unit 5 5 mole mol qc_end physical_unit 20 20 15 16 mole qc_end chemical_equation 24 30 qc_end end	[{"type":"physical unit","value":"Mole [OF] Fe [IN] moles"}]	[{"type":"physical unit","value":"12 moles"}]	[{"type":"physical unit","value":"Mole [OF] CO [=] \\pu{18 moles}"},{"type":"chemical equation","value":"Fe2O3 + CO -> Fe + CO2"}]	<h1 class="questionTitle" itemprop="name">How many moles of iron, #Fe#, can be made from #Fe_2O_3# by the use of 18 moles of carbon monoxide, #CO# in the reaction #Fe_2O_3 + CO -> Fe+CO_2#?</h1>	null	12 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The given equation takes the following form when balanced<br/> <mathjax>#Fe_2O_3+3CO=2Fe+3CO_2#</mathjax><br/> This equation reveals that 2moles of Fe is produced when 3moles of CO reacts<br/> Hence 18 moles of CO can produce <mathjax>#2/3*18=12 #</mathjax> moles Fe</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>12 moles</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The given equation takes the following form when balanced<br/> <mathjax>#Fe_2O_3+3CO=2Fe+3CO_2#</mathjax><br/> This equation reveals that 2moles of Fe is produced when 3moles of CO reacts<br/> Hence 18 moles of CO can produce <mathjax>#2/3*18=12 #</mathjax> moles Fe</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles of iron, #Fe#, can be made from #Fe_2O_3# by the use of 18 moles of carbon monoxide, #CO# in the reaction #Fe_2O_3 + CO -> Fe+CO_2#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="235236" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/dk-ch"><img alt="" class="" src="https://profilepictures.socratic.org/0aBlt69MSiWhfD1SEqb8_lotus.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/dk-ch"> P dilip_k </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-05T06:17:41" itemprop="dateCreated"> Mar 5, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>12 moles</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The given equation takes the following form when balanced<br/> <mathjax>#Fe_2O_3+3CO=2Fe+3CO_2#</mathjax><br/> This equation reveals that 2moles of Fe is produced when 3moles of CO reacts<br/> Hence 18 moles of CO can produce <mathjax>#2/3*18=12 #</mathjax> moles Fe</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/235236" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What is stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ab82402bf342f48d93ac6"> Question #93ac6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-we-study-stoichiometry"> Why do we study stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-naoh-is-produced-from-1-20-x-102-grams-of-na2o-na2o-h2o-2-naoh"> How many grams of NaOH is produced from #1.20 x 10^2# grams of #Na_2O#? #Na_2O + H_2O -> 2NaOH# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-na2o-are-required-to-produce-1-60-x-102-grams-of-naoh-na2o-h2o"> How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? Na2O + H2O ---> 2 NaOH </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-mass-of-iron-is-needed-to-react-with-16-0-grams-of-sulfur-8-fe-s8-8-fes"> What mass of iron is needed to react with 16.0 grams of sulfur? 8 Fe + S8 ---> 8 FeS </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/according-to-8-fe-s8-8-fes-how-many-grams-of-fes-are-produced"> According to 8 Fe + S8 ---> 8 FeS How many grams of FeS are produced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/12-00-moles-of-naclo3-will-produce-how-many-grams-of-o2-2-naclo3-2-nacl-3-o2"> 12.00 moles of NaClO3 will produce how many grams of O2? 2 NaClO3 ---> 2 NaCl + 3 O2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-nacl-are-produced-when-80-0-grams-of-o2-are-produced-2-naclo3-"> How many grams of NaCl are produced when 80.0 grams of O2 are produced? 2 NaClO3 ---> 2 NaCl + 3 O2 </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/stoichiometry"> See all questions in Stoichiometry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 9699 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many moles of iron, #Fe#, can be made from #Fe_2O_3# by the use of 18 moles of carbon monoxide, #CO# in the reaction #Fe_2O_3 + CO -> Fe+CO_2#?	null
2,252	ac7a9db6-6ddd-11ea-b5f7-ccda262736ce	https://socratic.org/questions/a-chemist-performs-the-reaction-6clo-2-3h-2o-5hclo-3-hcl-if-a-chemist-wants-to-m	47.92 grams	start physical_unit 6 6 mass g qc_end chemical_equation 5 14 qc_end physical_unit 12 12 21 22 mass qc_end end	[{"type":"physical unit","value":"Mass [OF] ClO2 [IN] grams"}]	[{"type":"physical unit","value":"47.92 grams"}]	[{"type":"chemical equation","value":"6 ClO2 + 3 H2O -> 5 HClO3 + HCl"},{"type":"physical unit","value":"Mass [OF] HClO3 [=] \\pu{50.0 g}"}]	<h1 class="questionTitle" itemprop="name">A chemist performs the reaction #6ClO_2 + 3H_2O -> 5HClO_3 + HCl#. If a chemist wants to make 50.0 g of #HClO_3#, what is the minimum number of grams of #ClO_2# that she can use?</h1>	null	47.92 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#ClO_2#</mathjax> is oxidized to <mathjax>#HClO_3#</mathjax>:</p> <p><mathjax>#stackrel(IV)ClO_2(aq) +H_2O(l)rarr Hstackrel(V)ClO_3(aq)+H^+ +e^(-)#</mathjax> <mathjax>#(i)#</mathjax></p> <p>And <mathjax>#ClO_2#</mathjax> is reduced to <mathjax>#Cl^(-)#</mathjax>:</p> <p><mathjax>#stackrel(IV)ClO_2(aq)+4H^+ +5e^(-)rarr Cl^(-)+2H_2O(l)#</mathjax> <mathjax>#(ii)#</mathjax></p> <p>And for both half-equations, mass and charge are conserved. And so we take <mathjax>#5xx(i)+(ii)#</mathjax> to get....</p> <p><mathjax>#5ClO_2(aq)+ClO_2(aq)+4H^+ +5e^(-) +5H_2O(l)rarr 5HClO_3(aq)+Cl^(-)+2H_2O(l)+5H^+ +5e^(-)#</mathjax></p> <p>And we cancel common reagents....</p> <p><mathjax>#5ClO_2(aq)+ClO_2(aq) +3H_2O(l)rarr 5HClO_3(aq)+Cl^(-)+H^+ #</mathjax></p> <p>...or...</p> <p><mathjax>#6ClO_2(aq) +3H_2O(l)rarr HCl(aq)+5HClO_3(aq)#</mathjax></p> <p>The which I think is balanced with respect to mass and charge. </p> <p>And so (finally!) we want a molar quantity with respect to <mathjax>#"chloric acid"#</mathjax>..of <mathjax>#(50.0g)/(84.46gmol^-1)=0.592mol#</mathjax>..</p> <p>And so with respect to <mathjax>#ClO_2#</mathjax> we needs <mathjax>#6/5"equiv"#</mathjax> ...</p> <p>i.e. <mathjax>#6/5xx0.592molxx67.45gmol^-1=??*g#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, <mathjax>#"chlorine dioxide"#</mathjax> DISPROPORTIONATES....and I make it mass of UNDER <mathjax>#50g#</mathjax> with respect to <mathjax>#ClO_2#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#ClO_2#</mathjax> is oxidized to <mathjax>#HClO_3#</mathjax>:</p> <p><mathjax>#stackrel(IV)ClO_2(aq) +H_2O(l)rarr Hstackrel(V)ClO_3(aq)+H^+ +e^(-)#</mathjax> <mathjax>#(i)#</mathjax></p> <p>And <mathjax>#ClO_2#</mathjax> is reduced to <mathjax>#Cl^(-)#</mathjax>:</p> <p><mathjax>#stackrel(IV)ClO_2(aq)+4H^+ +5e^(-)rarr Cl^(-)+2H_2O(l)#</mathjax> <mathjax>#(ii)#</mathjax></p> <p>And for both half-equations, mass and charge are conserved. And so we take <mathjax>#5xx(i)+(ii)#</mathjax> to get....</p> <p><mathjax>#5ClO_2(aq)+ClO_2(aq)+4H^+ +5e^(-) +5H_2O(l)rarr 5HClO_3(aq)+Cl^(-)+2H_2O(l)+5H^+ +5e^(-)#</mathjax></p> <p>And we cancel common reagents....</p> <p><mathjax>#5ClO_2(aq)+ClO_2(aq) +3H_2O(l)rarr 5HClO_3(aq)+Cl^(-)+H^+ #</mathjax></p> <p>...or...</p> <p><mathjax>#6ClO_2(aq) +3H_2O(l)rarr HCl(aq)+5HClO_3(aq)#</mathjax></p> <p>The which I think is balanced with respect to mass and charge. </p> <p>And so (finally!) we want a molar quantity with respect to <mathjax>#"chloric acid"#</mathjax>..of <mathjax>#(50.0g)/(84.46gmol^-1)=0.592mol#</mathjax>..</p> <p>And so with respect to <mathjax>#ClO_2#</mathjax> we needs <mathjax>#6/5"equiv"#</mathjax> ...</p> <p>i.e. <mathjax>#6/5xx0.592molxx67.45gmol^-1=??g#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A chemist performs the reaction #6ClO_2 + 3H_2O -> 5HClO_3 + HCl#. If a chemist wants to make 50.0 g of #HClO_3#, what is the minimum number of grams of #ClO_2# that she can use?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/mole-ratios" itemprop="url"> <span class="breadcrumb" itemprop="title">Mole Ratios</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="599187" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-04-21T14:15:23" itemprop="dateCreated"> Apr 21, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, <mathjax>#"chlorine dioxide"#</mathjax> DISPROPORTIONATES....and I make it mass of UNDER <mathjax>#50g#</mathjax> with respect to <mathjax>#ClO_2#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#ClO_2#</mathjax> is oxidized to <mathjax>#HClO_3#</mathjax>:</p> <p><mathjax>#stackrel(IV)ClO_2(aq) +H_2O(l)rarr Hstackrel(V)ClO_3(aq)+H^+ +e^(-)#</mathjax> <mathjax>#(i)#</mathjax></p> <p>And <mathjax>#ClO_2#</mathjax> is reduced to <mathjax>#Cl^(-)#</mathjax>:</p> <p><mathjax>#stackrel(IV)ClO_2(aq)+4H^+ +5e^(-)rarr Cl^(-)+2H_2O(l)#</mathjax> <mathjax>#(ii)#</mathjax></p> <p>And for both half-equations, mass and charge are conserved. And so we take <mathjax>#5xx(i)+(ii)#</mathjax> to get....</p> <p><mathjax>#5ClO_2(aq)+ClO_2(aq)+4H^+ +5e^(-) +5H_2O(l)rarr 5HClO_3(aq)+Cl^(-)+2H_2O(l)+5H^+ +5e^(-)#</mathjax></p> <p>And we cancel common reagents....</p> <p><mathjax>#5ClO_2(aq)+ClO_2(aq) +3H_2O(l)rarr 5HClO_3(aq)+Cl^(-)+H^+ #</mathjax></p> <p>...or...</p> <p><mathjax>#6ClO_2(aq) +3H_2O(l)rarr HCl(aq)+5HClO_3(aq)#</mathjax></p> <p>The which I think is balanced with respect to mass and charge. </p> <p>And so (finally!) we want a molar quantity with respect to <mathjax>#"chloric acid"#</mathjax>..of <mathjax>#(50.0g)/(84.46gmol^-1)=0.592mol#</mathjax>..</p> <p>And so with respect to <mathjax>#ClO_2#</mathjax> we needs <mathjax>#6/5"equiv"#</mathjax> ...</p> <p>i.e. <mathjax>#6/5xx0.592molxx67.45gmol^-1=??g#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/599187" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4178e02bf3469517a106e"> Question #a106e </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4178e02bf3469570e2e86"> Question #e2e86 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179102bf3469517a1072"> Question #a1072 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179402bf34694c8c5bf1"> Question #c5bf1 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179702bf3469588dc373"> Question #dc373 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179c02bf34694c8c5bf9"> Question #c5bf9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417a302bf3469517a1076"> Question #a1076 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417c702bf3469588dc377"> Question #dc377 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417d002bf346963eb984f"> Question #b984f </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417d402bf346950519ea3"> Question #19ea3 </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/mole-ratios"> See all questions in Mole Ratios </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1935 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A chemist performs the reaction #6ClO_2 + 3H_2O -> 5HClO_3 + HCl#. If a chemist wants to make 50.0 g of #HClO_3#, what is the minimum number of grams of #ClO_2# that she can use?	null
2,253	aad42713-6ddd-11ea-8692-ccda262736ce	https://socratic.org/questions/5903c68411ef6b56899b90a3	67.4 g	start physical_unit 23 24 mass g qc_end physical_unit 23 24 0 1 energy qc_end physical_unit 23 24 13 14 temperature qc_end physical_unit 23 24 16 17 temperature qc_end end	[{"type":"physical unit","value":"Mass [OF] the water [IN] g"}]	[{"type":"physical unit","value":"67.4 g"}]	[{"type":"physical unit","value":"Required energy [OF] the water [=] \\pu{6345 J}"},{"type":"physical unit","value":"Temperature1 [OF] the water [=] \\pu{22.6 ℃}"},{"type":"physical unit","value":"Temperature2 [OF] the water [=] \\pu{45.1 ℃}"}]	<h1 class="questionTitle" itemprop="name">#"6345 J"# of energy are required to raise the temperature of water from #22.6^@"C"# to #45.1^@"C"#. What is the mass of the water?</h1>	null	67.4 g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>Use the equation:</strong> </p> <p><mathjax>#q=mcDeltat#</mathjax></p> <p>where <mathjax>#q#</mathjax> is energy in Joules (J), <mathjax>#m#</mathjax> is mass, <mathjax>#c#</mathjax> is <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> capacity, and <mathjax>#Deltat#</mathjax>, which is change in temperature. <mathjax>#Deltat=T_"final"-T_"initial"#</mathjax></p> <p>The specific heat capacity of water, <mathjax>#c_"H2O"#</mathjax>, is not given. It is <mathjax>#4.184 "J"/("g"^@"C")#</mathjax>. <br/> <a href="https://water.usgs.gov/edu/heat-capacity.html" rel="nofollow" target="_blank">https://water.usgs.gov/edu/heat-capacity.html</a></p> <p><strong>Organize your information.</strong></p> <p><strong>Given</strong><br/> <mathjax>#q="6345 J"#</mathjax><br/> <mathjax>#c_"H2O"=4.184 "J"/("g"^@"C")#</mathjax><br/> <mathjax>#Deltat=("45.1"^@"C"-"22.6"^@"C")="22.5"^@"C"#</mathjax></p> <p><strong>Unknown: mass in grams</strong></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#m#</mathjax>. Substitute the given values into the equation and solve.</p> <p><mathjax>#m=q/(cDeltat)#</mathjax></p> <p><mathjax>#m=(6345color(red)cancel(color(black)("J")))/(4.184color(red)cancel(color(black)("J"))/("g"*^@color(red)cancel(color(black)("C")))xx22.5^@color(red)cancel(color(black)("C")))="67.4 g H"_2"O"#</mathjax> (rounded to three significant figures)</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The mass of water is <mathjax>#"67.4 g"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>Use the equation:</strong> </p> <p><mathjax>#q=mcDeltat#</mathjax></p> <p>where <mathjax>#q#</mathjax> is energy in Joules (J), <mathjax>#m#</mathjax> is mass, <mathjax>#c#</mathjax> is <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> capacity, and <mathjax>#Deltat#</mathjax>, which is change in temperature. <mathjax>#Deltat=T_"final"-T_"initial"#</mathjax></p> <p>The specific heat capacity of water, <mathjax>#c_"H2O"#</mathjax>, is not given. It is <mathjax>#4.184 "J"/("g"^@"C")#</mathjax>. <br/> <a href="https://water.usgs.gov/edu/heat-capacity.html" rel="nofollow" target="_blank">https://water.usgs.gov/edu/heat-capacity.html</a></p> <p><strong>Organize your information.</strong></p> <p><strong>Given</strong><br/> <mathjax>#q="6345 J"#</mathjax><br/> <mathjax>#c_"H2O"=4.184 "J"/("g"^@"C")#</mathjax><br/> <mathjax>#Deltat=("45.1"^@"C"-"22.6"^@"C")="22.5"^@"C"#</mathjax></p> <p><strong>Unknown: mass in grams</strong></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#m#</mathjax>. Substitute the given values into the equation and solve.</p> <p><mathjax>#m=q/(cDeltat)#</mathjax></p> <p><mathjax>#m=(6345color(red)cancel(color(black)("J")))/(4.184color(red)cancel(color(black)("J"))/("g"*^@color(red)cancel(color(black)("C")))xx22.5^@color(red)cancel(color(black)("C")))="67.4 g H"_2"O"#</mathjax> (rounded to three significant figures)</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">#"6345 J"# of energy are required to raise the temperature of water from #22.6^@"C"# to #45.1^@"C"#. What is the mass of the water?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/calorimetry" itemprop="url"> <span class="breadcrumb" itemprop="title">Calorimetry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="415096" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-30T03:54:06" itemprop="dateCreated"> Apr 30, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The mass of water is <mathjax>#"67.4 g"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>Use the equation:</strong> </p> <p><mathjax>#q=mcDeltat#</mathjax></p> <p>where <mathjax>#q#</mathjax> is energy in Joules (J), <mathjax>#m#</mathjax> is mass, <mathjax>#c#</mathjax> is <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> capacity, and <mathjax>#Deltat#</mathjax>, which is change in temperature. <mathjax>#Deltat=T_"final"-T_"initial"#</mathjax></p> <p>The specific heat capacity of water, <mathjax>#c_"H2O"#</mathjax>, is not given. It is <mathjax>#4.184 "J"/("g"^@"C")#</mathjax>. <br/> <a href="https://water.usgs.gov/edu/heat-capacity.html" rel="nofollow" target="_blank">https://water.usgs.gov/edu/heat-capacity.html</a></p> <p><strong>Organize your information.</strong></p> <p><strong>Given</strong><br/> <mathjax>#q="6345 J"#</mathjax><br/> <mathjax>#c_"H2O"=4.184 "J"/("g"^@"C")#</mathjax><br/> <mathjax>#Deltat=("45.1"^@"C"-"22.6"^@"C")="22.5"^@"C"#</mathjax></p> <p><strong>Unknown: mass in grams</strong></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#m#</mathjax>. Substitute the given values into the equation and solve.</p> <p><mathjax>#m=q/(cDeltat)#</mathjax></p> <p><mathjax>#m=(6345color(red)cancel(color(black)("J")))/(4.184color(red)cancel(color(black)("J"))/("g"*^@color(red)cancel(color(black)("C")))xx22.5^@color(red)cancel(color(black)("C")))="67.4 g H"_2"O"#</mathjax> (rounded to three significant figures)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/415096" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-differential-scanning-in-calorimetry-work"> How does differential scanning in calorimetry work? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-read-differential-scanning-in-calorimetry"> What information do you get from a differential scanning calorimetry plot? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-measure-calorimetry"> How do you measure calorimetry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531d304102bf341e75b962a7"> Question #962a7 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5335021802bf344ae911dfc5"> Question #1dfc5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/533668f502bf34572c341af6"> Question #41af6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-definition-of-calorimetry"> What is calorimetry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-differential-scanning-calorimeter"> What is a differential scanning calorimeter? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-a-calorimeter-measure-energy"> How can a calorimeter measure energy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-calorimeters-made-of"> What are calorimeters made of? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/calorimetry"> See all questions in Calorimetry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1303 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	#"6345 J"# of energy are required to raise the temperature of water from #22.6^@"C"# to #45.1^@"C"#. What is the mass of the water?	null
2,254	aa3833e7-6ddd-11ea-8019-ccda262736ce	https://socratic.org/questions/what-is-the-equation-for-the-reaction-of-barium-nitrate-hydrochloric-acid	Ba(NO3)2(s) + 2 HCl(aq) -> BaCl2(s) + 2 HNO3(aq)	start chemical_equation qc_end substance 8 9 qc_end substance 10 11 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the reaction"}]	[{"type":"chemical equation","value":"Ba(NO3)2(s) + 2 HCl(aq) -> BaCl2(s) + 2 HNO3(aq)"}]	[{"type":"substance name","value":"Barium Nitrate"},{"type":"substance name","value":"Hydrochloric Acid"}]	<h1 class="questionTitle" itemprop="name">What is the equation for the reaction of Barium Nitrate Hydrochloric Acid?</h1>	null	Ba(NO3)2(s) + 2 HCl(aq) -> BaCl2(s) + 2 HNO3(aq)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>I'm assuming you mean <mathjax>#Ba(NO_"3")_"2" (s) + HCl (aq) -> ?#</mathjax> so i'm going off of that. </p> <p><strong>Skeleton</strong></p> <blockquote> <p><mathjax>#Ba(NO_"3")_"2" (s) + HCl (aq) -> BaCl_"2" (s) + HNO_"3" (aq)#</mathjax> </p> </blockquote> <p><strong>Balanced</strong></p> <blockquote> <p><mathjax>#Ba(NO_"3")_"2" (s) + 2 HCl (aq) -> BaCl_"2" (s) + 2 HNO_"3" (aq)#</mathjax> </p> </blockquote> <p>Hope this helps :)</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><blockquote> <p><mathjax>#Ba(NO_"3")_"2" (s) + 2 HCl (aq) -> BaCl_"2" (s) + 2 HNO_"3" (aq)#</mathjax> </p> </blockquote></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>I'm assuming you mean <mathjax>#Ba(NO_"3")_"2" (s) + HCl (aq) -> ?#</mathjax> so i'm going off of that. </p> <p><strong>Skeleton</strong></p> <blockquote> <p><mathjax>#Ba(NO_"3")_"2" (s) + HCl (aq) -> BaCl_"2" (s) + HNO_"3" (aq)#</mathjax> </p> </blockquote> <p><strong>Balanced</strong></p> <blockquote> <p><mathjax>#Ba(NO_"3")_"2" (s) + 2 HCl (aq) -> BaCl_"2" (s) + 2 HNO_"3" (aq)#</mathjax> </p> </blockquote> <p>Hope this helps :)</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the equation for the reaction of Barium Nitrate Hydrochloric Acid?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-reactions-and-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions and Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="340558" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ryuu"><img alt="" class="" src="https://profilepictures.socratic.org/ybMAUPwJSLW0wuAqV5i2_meh.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ryuu"> Ryuu </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-11-23T03:36:55" itemprop="dateCreated"> Nov 23, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><blockquote> <p><mathjax>#Ba(NO_"3")_"2" (s) + 2 HCl (aq) -> BaCl_"2" (s) + 2 HNO_"3" (aq)#</mathjax> </p> </blockquote></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>I'm assuming you mean <mathjax>#Ba(NO_"3")_"2" (s) + HCl (aq) -> ?#</mathjax> so i'm going off of that. </p> <p><strong>Skeleton</strong></p> <blockquote> <p><mathjax>#Ba(NO_"3")_"2" (s) + HCl (aq) -> BaCl_"2" (s) + HNO_"3" (aq)#</mathjax> </p> </blockquote> <p><strong>Balanced</strong></p> <blockquote> <p><mathjax>#Ba(NO_"3")_"2" (s) + 2 HCl (aq) -> BaCl_"2" (s) + 2 HNO_"3" (aq)#</mathjax> </p> </blockquote> <p>Hope this helps :)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/340558" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb002bf34694a4fee47"> Question #fee47 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb402bf34694c8c5c15"> Question #c5c15 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb802bf346950519eb9"> Question #19eb9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cbf02bf3469570e2ea2"> Question #e2ea2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc002bf34695a6bc751"> Question #bc751 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc202bf3469570e2ea6"> Question #e2ea6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531e867a02bf342492a08b07"> Question #08b07 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-thermochemical-equation-for-the-combustion-of-benzene"> What is the thermochemical equation for the combustion of benzene? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-reversible"> Why are chemical reactions reversible? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-important"> Why are chemical reactions important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/chemical-reactions-and-equations"> See all questions in Chemical Reactions and Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 13599 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the equation for the reaction of Barium Nitrate Hydrochloric Acid?	null
2,255	abe6529c-6ddd-11ea-9022-ccda262736ce	https://socratic.org/questions/what-is-the-density-of-freon-11-cfcl3-at-166-degrees-celsius-and-5-92-atm	22.57 g/L	start physical_unit 6 6 density g/l qc_end physical_unit 6 6 8 10 temperature qc_end physical_unit 6 6 12 13 pressure qc_end end	[{"type":"physical unit","value":"Density [OF] CFCl3 [IN] g/L"}]	[{"type":"physical unit","value":"22.57 g/L"}]	[{"type":"physical unit","value":"Temperature [OF] CFCl3 [=] \\pu{166 degrees Celsius}"},{"type":"physical unit","value":"Pressure [OF] CFCl3 [=] \\pu{5.92 atm}"}]	<h1 class="questionTitle" itemprop="name">What is the density of Freon-11 (CFCl3) at 166 degrees Celsius and 5.92 atm?</h1>	null	22.57 g/L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>Freon-11 is a compound with formula <mathjax>#"CFCl"_3#</mathjax>. Its chemical name is trichlorofluoromethane.</p> <p>We can use the <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a></strong> to determine its density.</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(\|color(white)(a/a)pV = nRTcolor(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>Since <mathjax>#n = m/M#</mathjax>, we can substitute this to get</p> <blockquote> <blockquote> <p><mathjax>#pV = (m/M)RT#</mathjax></p> </blockquote> </blockquote> <p>We can rearrange this to</p> <blockquote> <blockquote> <p><mathjax>#pM = m/VRT#</mathjax></p> </blockquote> </blockquote> <p>But <mathjax>#"density"= "mass"/"volume"#</mathjax> or <mathjax>#color(brown)(bar(ul(\|color(white)(a/a)ρ = m/Vcolor(white)(a/a)\|)))" "#</mathjax></p> <p>∴ <mathjax>#pM = ρRT#</mathjax></p> <p>and </p> <blockquote> <blockquote> <p><mathjax>#color(brown)(bar(ul(\|color(white)(a/a)ρ = (pM)/(RT)color(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>In your problem,</p> <p><mathjax>#p = "5.92 atm"#</mathjax><br/> <mathjax>#M = "137.37 g/mol"#</mathjax><br/> <mathjax>#R = "0.082 06 L·atm·K"^"-1""mol"^"-1"#</mathjax><br/> <mathjax>#T = "166 °C" = "439.15 K"#</mathjax></p> <blockquote></blockquote> <p>∴ <mathjax>#ρ = (5.92color(red)(cancel(color(black)("atm"))) × 137.37color(white)(l) "g"·color(red)(cancel(color(black)("mol"^"-1"))))/("0.082 06 L"·color(red)(cancel(color(black)("atm·K"^"-1""mol"^"-1"))) × 439.15color(red)(cancel(color(black)("K")))) = "22.6 g/L"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The <a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a> of Freon-11 is 22.6 g/L.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>Freon-11 is a compound with formula <mathjax>#"CFCl"_3#</mathjax>. Its chemical name is trichlorofluoromethane.</p> <p>We can use the <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a></strong> to determine its density.</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(\|color(white)(a/a)pV = nRTcolor(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>Since <mathjax>#n = m/M#</mathjax>, we can substitute this to get</p> <blockquote> <blockquote> <p><mathjax>#pV = (m/M)RT#</mathjax></p> </blockquote> </blockquote> <p>We can rearrange this to</p> <blockquote> <blockquote> <p><mathjax>#pM = m/VRT#</mathjax></p> </blockquote> </blockquote> <p>But <mathjax>#"density"= "mass"/"volume"#</mathjax> or <mathjax>#color(brown)(bar(ul(\|color(white)(a/a)ρ = m/Vcolor(white)(a/a)\|)))" "#</mathjax></p> <p>∴ <mathjax>#pM = ρRT#</mathjax></p> <p>and </p> <blockquote> <blockquote> <p><mathjax>#color(brown)(bar(ul(\|color(white)(a/a)ρ = (pM)/(RT)color(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>In your problem,</p> <p><mathjax>#p = "5.92 atm"#</mathjax><br/> <mathjax>#M = "137.37 g/mol"#</mathjax><br/> <mathjax>#R = "0.082 06 L·atm·K"^"-1""mol"^"-1"#</mathjax><br/> <mathjax>#T = "166 °C" = "439.15 K"#</mathjax></p> <blockquote></blockquote> <p>∴ <mathjax>#ρ = (5.92color(red)(cancel(color(black)("atm"))) × 137.37color(white)(l) "g"·color(red)(cancel(color(black)("mol"^"-1"))))/("0.082 06 L"·color(red)(cancel(color(black)("atm·K"^"-1""mol"^"-1"))) × 439.15color(red)(cancel(color(black)("K")))) = "22.6 g/L"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the density of Freon-11 (CFCl3) at 166 degrees Celsius and 5.92 atm?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/ideal-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Ideal Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="448654" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-07-06T14:26:13" itemprop="dateCreated"> Jul 6, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The <a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a> of Freon-11 is 22.6 g/L.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>Freon-11 is a compound with formula <mathjax>#"CFCl"_3#</mathjax>. Its chemical name is trichlorofluoromethane.</p> <p>We can use the <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a></strong> to determine its density.</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(\|color(white)(a/a)pV = nRTcolor(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>Since <mathjax>#n = m/M#</mathjax>, we can substitute this to get</p> <blockquote> <blockquote> <p><mathjax>#pV = (m/M)RT#</mathjax></p> </blockquote> </blockquote> <p>We can rearrange this to</p> <blockquote> <blockquote> <p><mathjax>#pM = m/VRT#</mathjax></p> </blockquote> </blockquote> <p>But <mathjax>#"density"= "mass"/"volume"#</mathjax> or <mathjax>#color(brown)(bar(ul(\|color(white)(a/a)ρ = m/Vcolor(white)(a/a)\|)))" "#</mathjax></p> <p>∴ <mathjax>#pM = ρRT#</mathjax></p> <p>and </p> <blockquote> <blockquote> <p><mathjax>#color(brown)(bar(ul(\|color(white)(a/a)ρ = (pM)/(RT)color(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>In your problem,</p> <p><mathjax>#p = "5.92 atm"#</mathjax><br/> <mathjax>#M = "137.37 g/mol"#</mathjax><br/> <mathjax>#R = "0.082 06 L·atm·K"^"-1""mol"^"-1"#</mathjax><br/> <mathjax>#T = "166 °C" = "439.15 K"#</mathjax></p> <blockquote></blockquote> <p>∴ <mathjax>#ρ = (5.92color(red)(cancel(color(black)("atm"))) × 137.37color(white)(l) "g"·color(red)(cancel(color(black)("mol"^"-1"))))/("0.082 06 L"·color(red)(cancel(color(black)("atm·K"^"-1""mol"^"-1"))) × 439.15color(red)(cancel(color(black)("K")))) = "22.6 g/L"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/448654" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-ideal-gas-constant"> How do you find the ideal gas constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-solve-ideal-gas-law-problems"> How do you solve ideal gas law problems? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-know-which-ideal-gas-constant-to-use"> How do you know which ideal gas constant to use? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ideal-gas-constant-for-butane"> What is the ideal gas constant for butane? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-ideal-gas-law-in-kelvin"> Why is ideal gas law in kelvin? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ideal-gas-constant-important"> Why is the ideal gas constant important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-di-electric-constant"> What is the di-electric constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-volume-l-will-0-20-mol-hi-occupy-at-300-k-and-100-0-kpa-r-8-314-kpa-l-k-mol"> What volume (L) will 0.20 mol HI occupy at 300 K and 100.0 kPa? R = 8.314 kPa L / (K mol) =... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-molar-mass-of-a-gas"> How do you calculate the molar mass of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-should-i-use-the-ideal-gas-law-and-not-the-combined-gas-law"> When should I use the ideal gas law and not the combined gas law? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/ideal-gas-law"> See all questions in Ideal Gas Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 24782 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the density of Freon-11 (CFCl3) at 166 degrees Celsius and 5.92 atm?	null
2,256	aad8d892-6ddd-11ea-9cc1-ccda262736ce	https://socratic.org/questions/58aae68f7c014911f29d1fca	128.2 g	start physical_unit 8 8 mass g qc_end physical_unit 8 8 5 6 mole qc_end end	[{"type":"physical unit","value":"Mass [OF] sulfur [IN] g"}]	[{"type":"physical unit","value":"128.2 g"}]	[{"type":"physical unit","value":"Mole [OF] sulfur [=] \\pu{4 moles}"}]	<h1 class="questionTitle" itemprop="name">What is the mass of four moles of sulfur?</h1>	null	128.2 g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>From <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a>, we can see that the molar mass of sulfur is <mathjax>#"32.06 g/mol"#</mathjax>. This means that one mole of sulfur atoms has a mass of <mathjax>#"32.06 g"#</mathjax>. </p> <p>Now we need to multiply the molar mass of sulfur by 4 moles.</p> <p><mathjax>#4color(red)cancel(color(black)("mol S"))xx("32.06 g S")/color(red)cancel(color(black)(1"mol S"))="128.2 g S"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Four moles of sulfur has a mass of <mathjax>#"128.2 g"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>From <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a>, we can see that the molar mass of sulfur is <mathjax>#"32.06 g/mol"#</mathjax>. This means that one mole of sulfur atoms has a mass of <mathjax>#"32.06 g"#</mathjax>. </p> <p>Now we need to multiply the molar mass of sulfur by 4 moles.</p> <p><mathjax>#4color(red)cancel(color(black)("mol S"))xx("32.06 g S")/color(red)cancel(color(black)(1"mol S"))="128.2 g S"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the mass of four moles of sulfur?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="382606" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-02-25T04:54:44" itemprop="dateCreated"> Feb 25, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Four moles of sulfur has a mass of <mathjax>#"128.2 g"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>From <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a>, we can see that the molar mass of sulfur is <mathjax>#"32.06 g/mol"#</mathjax>. This means that one mole of sulfur atoms has a mass of <mathjax>#"32.06 g"#</mathjax>. </p> <p>Now we need to multiply the molar mass of sulfur by 4 moles.</p> <p><mathjax>#4color(red)cancel(color(black)("mol S"))xx("32.06 g S")/color(red)cancel(color(black)(1"mol S"))="128.2 g S"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/382606" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 6712 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the mass of four moles of sulfur?	null
2,257	a83c13a2-6ddd-11ea-af7f-ccda262736ce	https://socratic.org/questions/you-have-1500-0-g-of-a-bleach-solution-the-percent-by-mass-of-the-solute-sodium-	54.3 grams	start physical_unit 17 17 mass g qc_end physical_unit 5 7 2 3 mass qc_end end	[{"type":"physical unit","value":"Mass [OF] NaOCl [IN] grams"}]	[{"type":"physical unit","value":"54.3 grams"}]	[{"type":"physical unit","value":"Mass [OF] a bleach solution [=] \\pu{1500.0 g}"},{"type":"physical unit","value":"Percent by mass [OF] NaOCl in the bleach solution [=] \\pu{3.62%}"}]	<h1 class="questionTitle" itemprop="name">You have 1500.0 g of a bleach solution. The percent by mass of the solute sodium hypochlorite, #NaOCl#, is 3.62%. How many grams of #NaOCl# are in the solution?</h1>	null	54.3 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The key to this problem lies with the definition of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration by mass</a>, <mathjax>#"m/m %"#</mathjax>.</p> <p>As you know, <em><a href="http://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration</a> by mass</em> is defined as the ratio between the <strong>mass of the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a></strong> and the <strong>total mass of the solution</strong>, multiplied by <mathjax>#100#</mathjax>.</p> <blockquote> <p><mathjax>#color(blue)("% m/m" = "mass of solute"/"mass of solution" xx 100)#</mathjax></p> </blockquote> <p>You are told that your bleach solution has a <mathjax>#"3.62%#</mathjax> percent concentration by mass. Looking at the above definition, that should tell you that <strong>every</strong> <mathjax>#"100 g"#</mathjax> of solution will contain <mathjax>#"3.62 g"#</mathjax> of sodium hypochlorite, your solute.</p> <p>In your case, the mass of the solution is said to be equal to <mathjax>#"1500.0 g"#</mathjax>. This means that it will contain</p> <blockquote> <p><mathjax>#1500.0 color(red)(cancel(color(black)("g solution"))) * "3.62 g NaOCl"/(100color(red)(cancel(color(black)("g solution")))) = color(green)("54.3 g NaOCl")#</mathjax></p> </blockquote> <p><strong>Alternatively</strong>, you can use the equation for percent concentration by mass to find the mass of the solute</p> <blockquote> <p><mathjax>#"% m/m" = m_"solute"/m_"solution" xx 100#</mathjax></p> <p><mathjax>#m_"solute" = ("%m/m" * m_"solution")/100#</mathjax></p> </blockquote> <p>Plug in your values to get</p> <blockquote> <p><mathjax>#m_"solute" = (3.62 * "1500.0 g")/100 = color(green)("54.3 g NaOCl")#</mathjax></p> </blockquote> <p>Here's a useful video on percent concentration by mass</p> <p> <iframe src="https://www.youtube.com/embed/nOZH3bm47IM?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"54.3 g NaOCl"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The key to this problem lies with the definition of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration by mass</a>, <mathjax>#"m/m %"#</mathjax>.</p> <p>As you know, <em><a href="http://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration</a> by mass</em> is defined as the ratio between the <strong>mass of the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a></strong> and the <strong>total mass of the solution</strong>, multiplied by <mathjax>#100#</mathjax>.</p> <blockquote> <p><mathjax>#color(blue)("% m/m" = "mass of solute"/"mass of solution" xx 100)#</mathjax></p> </blockquote> <p>You are told that your bleach solution has a <mathjax>#"3.62%#</mathjax> percent concentration by mass. Looking at the above definition, that should tell you that <strong>every</strong> <mathjax>#"100 g"#</mathjax> of solution will contain <mathjax>#"3.62 g"#</mathjax> of sodium hypochlorite, your solute.</p> <p>In your case, the mass of the solution is said to be equal to <mathjax>#"1500.0 g"#</mathjax>. This means that it will contain</p> <blockquote> <p><mathjax>#1500.0 color(red)(cancel(color(black)("g solution"))) * "3.62 g NaOCl"/(100color(red)(cancel(color(black)("g solution")))) = color(green)("54.3 g NaOCl")#</mathjax></p> </blockquote> <p><strong>Alternatively</strong>, you can use the equation for percent concentration by mass to find the mass of the solute</p> <blockquote> <p><mathjax>#"% m/m" = m_"solute"/m_"solution" xx 100#</mathjax></p> <p><mathjax>#m_"solute" = ("%m/m" * m_"solution")/100#</mathjax></p> </blockquote> <p>Plug in your values to get</p> <blockquote> <p><mathjax>#m_"solute" = (3.62 * "1500.0 g")/100 = color(green)("54.3 g NaOCl")#</mathjax></p> </blockquote> <p>Here's a useful video on percent concentration by mass</p> <p> <iframe src="https://www.youtube.com/embed/nOZH3bm47IM?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">You have 1500.0 g of a bleach solution. The percent by mass of the solute sodium hypochlorite, #NaOCl#, is 3.62%. How many grams of #NaOCl# are in the solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/percent-concentration" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Concentration</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="213606" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-17T22:52:49" itemprop="dateCreated"> Jan 17, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"54.3 g NaOCl"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The key to this problem lies with the definition of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration by mass</a>, <mathjax>#"m/m %"#</mathjax>.</p> <p>As you know, <em><a href="http://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration</a> by mass</em> is defined as the ratio between the <strong>mass of the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a></strong> and the <strong>total mass of the solution</strong>, multiplied by <mathjax>#100#</mathjax>.</p> <blockquote> <p><mathjax>#color(blue)("% m/m" = "mass of solute"/"mass of solution" xx 100)#</mathjax></p> </blockquote> <p>You are told that your bleach solution has a <mathjax>#"3.62%#</mathjax> percent concentration by mass. Looking at the above definition, that should tell you that <strong>every</strong> <mathjax>#"100 g"#</mathjax> of solution will contain <mathjax>#"3.62 g"#</mathjax> of sodium hypochlorite, your solute.</p> <p>In your case, the mass of the solution is said to be equal to <mathjax>#"1500.0 g"#</mathjax>. This means that it will contain</p> <blockquote> <p><mathjax>#1500.0 color(red)(cancel(color(black)("g solution"))) * "3.62 g NaOCl"/(100color(red)(cancel(color(black)("g solution")))) = color(green)("54.3 g NaOCl")#</mathjax></p> </blockquote> <p><strong>Alternatively</strong>, you can use the equation for percent concentration by mass to find the mass of the solute</p> <blockquote> <p><mathjax>#"% m/m" = m_"solute"/m_"solution" xx 100#</mathjax></p> <p><mathjax>#m_"solute" = ("%m/m" * m_"solution")/100#</mathjax></p> </blockquote> <p>Plug in your values to get</p> <blockquote> <p><mathjax>#m_"solute" = (3.62 * "1500.0 g")/100 = color(green)("54.3 g NaOCl")#</mathjax></p> </blockquote> <p>Here's a useful video on percent concentration by mass</p> <p> <iframe src="https://www.youtube.com/embed/nOZH3bm47IM?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/213606" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-concentration-of-water-in-solution-be-decreased"> How can the concentration of water in solution be decreased? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-concentration-of-a-solution-be-increased"> How can the concentration of a solution be increased? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-concentration-of-a-solution-in-ppm"> How do you find the concentration of a solution in ppm? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-make-a-10-percent-solution"> How do you make a 10 percent solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-make-a-2-percent-solution"> How do you make a 2 percent solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-weight-per-volume-method-to-calculate-concentration"> What is the weight per volume method to calculate concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-percent-concentration-of-kcl-would-be-isotonic"> What percent concentration of KCl would be isotonic? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-of-sodium-chloride-in-normal-saline"> What is the percent concentration of sodium chloride in normal saline? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-of-a-6m-solution-of-nacl"> What is the percent concentration of a 6m solution of NaCl? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-formula"> What is the percent concentration formula? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/percent-concentration"> See all questions in Percent Concentration </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 45678 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	You have 1500.0 g of a bleach solution. The percent by mass of the solute sodium hypochlorite, #NaOCl#, is 3.62%. How many grams of #NaOCl# are in the solution?	null
2,258	a98d9029-6ddd-11ea-8b8f-ccda262736ce	https://socratic.org/questions/what-is-the-formula-for-iron-iii-oxide	Fe2O3	start chemical_formula qc_end substance 5 7 qc_end end	[{"type":"other","value":"Chemical Formula [OF] iron (III) oxide [IN] default"}]	[{"type":"chemical equation","value":"Fe2O3"}]	[{"type":"substance name","value":"Iron (III) oxide"}]	<h1 class="questionTitle" itemprop="name">What is the formula for iron (III) oxide? </h1>	null	Fe2O3	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <mathjax>#+III#</mathjax> oxidation states denotes the <mathjax>#"ferric ion..."#</mathjax> Rust is thus formally <mathjax>#2xxFe^(3+)+3xxO^(2-)#</mathjax>, the which formulation gives a NEUTRAL salt. Rust prevention is a HUGE industrial and commercial concern....</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Is it not <mathjax>#Fe_2O_3#</mathjax>, i.e. <mathjax>#"ferric oxide....."#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <mathjax>#+III#</mathjax> oxidation states denotes the <mathjax>#"ferric ion..."#</mathjax> Rust is thus formally <mathjax>#2xxFe^(3+)+3xxO^(2-)#</mathjax>, the which formulation gives a NEUTRAL salt. Rust prevention is a HUGE industrial and commercial concern....</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the formula for iron (III) oxide? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#ionic-bonds-and-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Ionic Bonds</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/ionic-bonds-and-formulas/naming-ionic-compounds" itemprop="url"> <span class="breadcrumb" itemprop="title">Naming Ionic Compounds</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="614762" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-05-16T18:39:29" itemprop="dateCreated"> May 16, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Is it not <mathjax>#Fe_2O_3#</mathjax>, i.e. <mathjax>#"ferric oxide....."#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <mathjax>#+III#</mathjax> oxidation states denotes the <mathjax>#"ferric ion..."#</mathjax> Rust is thus formally <mathjax>#2xxFe^(3+)+3xxO^(2-)#</mathjax>, the which formulation gives a NEUTRAL salt. Rust prevention is a HUGE industrial and commercial concern....</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/614762" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="614763" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/eric-s-1"><img alt="" class="" src="https://lh3.googleusercontent.com/-XdUIqdMkCWA/AAAAAAAAAAI/AAAAAAAAAAA/4252rscbv5M/photo.jpg?sz=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/eric-s-1"> Eric S. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-05-16T18:40:20" itemprop="dateCreated"> May 16, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Fe_2O_3#</mathjax> </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To name a compound in which the first element is a transition metal and there are roman numerals, find out the charge of the non-transition metal. In this case, if oxygen were to get 8 <a href="https://socratic.org/chemistry/the-periodic-table/valence-electrons-and-the-periodic-table">valence electrons</a>, from its typical 6, it would gain 2. Electrons have a negative charge so its charge would be -2. There are 3 oxygen, as stated by the roman numerals. The resulting answer would be <mathjax>#Fe_2O_3#</mathjax>. If you find that confusing here's a diagram on naming <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a> like this and others. <img alt="http://flowchart.bro-h.com" src="https://useruploads.socratic.org/fB3YodAtTBmYsevxyUz8_Naming%2BCompounds%2BFlowchart.jpg"/> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/614763" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-name-ionic-compounds-with-transition-metals"> How do you name ionic compounds with transition metals? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-name-of-the-ionic-compound-ni3-po4-2"> What is the name of the ionic compound Ni3(PO4)2? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-rules-are-used-to-name-ionic-compounds"> What rules are used to name ionic compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-name-ionic-compounds-with-three-elements"> How can I name ionic compounds with three elements? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-name-ionic-compounds-with-transition-metals"> How can I name ionic compounds with transition metals? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-name-ionic-compounds-with-roman-numerals"> How do you name ionic compounds with roman numerals? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-name-polyatomic-ionic-compounds"> How can I name polyatomic ionic compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-name-ionic-compounds"> How can I name ionic compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-name-binary-ionic-compounds"> How can I name binary ionic compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-examples-of-ionic-compounds-names"> What are some examples of ionic compounds names? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/ionic-bonds-and-formulas/naming-ionic-compounds"> See all questions in Naming Ionic Compounds </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 36614 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the formula for iron (III) oxide?	null
2,259	aaac6a25-6ddd-11ea-8ae1-ccda262736ce	https://socratic.org/questions/5927361511ef6b404038dfe4	1/4 CF4(g) -> 1/4 C(g) + F(g)	start chemical_equation qc_end substance 15 16 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the reaction"}]	[{"type":"chemical equation","value":"1/4 CF4(g) -> 1/4 C(g) + F(g)"}]	[{"type":"substance name","value":"Carbon tetrafluoride"}]	<h1 class="questionTitle" itemprop="name">What is the equation for the reaction that represents the mean #"C-F"# bond energy in carbon tetrafluoride?</h1>	null	1/4 CF4(g) -> 1/4 C(g) + F(g)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The <strong>bond dissociation <a href="https://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a></strong> is the energy needed to break one mole of the bonds to give separated atoms, with everything being in the gaseous state.</p> <p>Tetrafluoromethane, <mathjax>#"CF"_4#</mathjax>, contains four identical <mathjax>#"C-F"#</mathjax> bonds.</p> <p>However, if you take <mathjax>#"CF"_4#</mathjax> to pieces one fluorine at a time, you will have to supply a different amount of energy to break each bond.</p> <p>Each time you break a <mathjax>#"C-F"#</mathjax> bond, the environment of those left behind changes, and the strength of a bond is affected by what else is around it.</p> <p>Thus, you would need to break the bonds in 0.25 mol of <mathjax>#"CF"_4#</mathjax> (1 mol of <mathjax>#"C-F"#</mathjax> bonds), and the total energy involved would then be the mean bond energy.</p> <p>The thermochemical equation representing this process is</p> <p><mathjax>#1/4"CF"_4"(g)" → 1/4"C(g)" + "F(g)"#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The equation is <mathjax>#1/4"CF"_4"(g)" → 1/4"C(g)" + "F(g)"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The <strong>bond dissociation <a href="https://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a></strong> is the energy needed to break one mole of the bonds to give separated atoms, with everything being in the gaseous state.</p> <p>Tetrafluoromethane, <mathjax>#"CF"_4#</mathjax>, contains four identical <mathjax>#"C-F"#</mathjax> bonds.</p> <p>However, if you take <mathjax>#"CF"_4#</mathjax> to pieces one fluorine at a time, you will have to supply a different amount of energy to break each bond.</p> <p>Each time you break a <mathjax>#"C-F"#</mathjax> bond, the environment of those left behind changes, and the strength of a bond is affected by what else is around it.</p> <p>Thus, you would need to break the bonds in 0.25 mol of <mathjax>#"CF"_4#</mathjax> (1 mol of <mathjax>#"C-F"#</mathjax> bonds), and the total energy involved would then be the mean bond energy.</p> <p>The thermochemical equation representing this process is</p> <p><mathjax>#1/4"CF"_4"(g)" → 1/4"C(g)" + "F(g)"#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the equation for the reaction that represents the mean #"C-F"# bond energy in carbon tetrafluoride?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/enthalpy" itemprop="url"> <span class="breadcrumb" itemprop="title">Enthalpy</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="429730" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-25T23:46:11" itemprop="dateCreated"> May 25, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The equation is <mathjax>#1/4"CF"_4"(g)" → 1/4"C(g)" + "F(g)"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The <strong>bond dissociation <a href="https://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a></strong> is the energy needed to break one mole of the bonds to give separated atoms, with everything being in the gaseous state.</p> <p>Tetrafluoromethane, <mathjax>#"CF"_4#</mathjax>, contains four identical <mathjax>#"C-F"#</mathjax> bonds.</p> <p>However, if you take <mathjax>#"CF"_4#</mathjax> to pieces one fluorine at a time, you will have to supply a different amount of energy to break each bond.</p> <p>Each time you break a <mathjax>#"C-F"#</mathjax> bond, the environment of those left behind changes, and the strength of a bond is affected by what else is around it.</p> <p>Thus, you would need to break the bonds in 0.25 mol of <mathjax>#"CF"_4#</mathjax> (1 mol of <mathjax>#"C-F"#</mathjax> bonds), and the total energy involved would then be the mean bond energy.</p> <p>The thermochemical equation representing this process is</p> <p><mathjax>#1/4"CF"_4"(g)" → 1/4"C(g)" + "F(g)"#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/429730" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-enthalpy-changes-expressed-in-chemical-equations"> How are enthalpy changes expressed in chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-enthalpy-change-be-determined-for-an-aqueous-solution"> How can enthalpy change be determined for an aqueous solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-enthalpy-change-with-pressure"> How does enthalpy change with pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-standard-molar-enthalpy-formation"> How do you calculate standard molar enthalpy of formation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-enthalpy-a-state-function"> Why is enthalpy a state function? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-enthalpy-of-formation-of-oxygen-zero"> Why is the enthalpy of formation of oxygen zero? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-enthalpy-a-state-function-2"> Why is enthalpy a state function? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-enthalpy-cannot-be-measured-directly"> Why can enthalpy not be measured directly? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-pressure-affect-enthalpy"> How does pressure affect enthalpy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-enthalpy-relate-to-internal-energy"> How does enthalpy relate to internal energy? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/enthalpy"> See all questions in Enthalpy </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 5251 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the equation for the reaction that represents the mean #"C-F"# bond energy in carbon tetrafluoride?	null
2,260	ac06c066-6ddd-11ea-9db2-ccda262736ce	https://socratic.org/questions/591358b3b72cff0b40046641	1.5 L	start physical_unit 2 2 volume l qc_end physical_unit 2 2 17 18 volume qc_end physical_unit 2 2 4 5 pressure qc_end physical_unit 2 2 9 10 temperature qc_end physical_unit 2 2 25 26 temperature qc_end physical_unit 2 2 29 30 pressure qc_end end	[{"type":"physical unit","value":"Volume2 [OF] the gas [IN] L"}]	[{"type":"physical unit","value":"1.5 L"}]	[{"type":"physical unit","value":"Volume1 [OF] the gas [=] \\pu{2.02 L}"},{"type":"physical unit","value":"Pressure1 [OF] the gas [=] \\pu{600 mmHg}"},{"type":"physical unit","value":"Temperature1 [OF] the gas [=] \\pu{303.15 K}"},{"type":"physical unit","value":"Temperature2 [OF] the gas [=] \\pu{273.15 K}"},{"type":"physical unit","value":"Pressure2 [OF] the gas [=] \\pu{750 mmHg}"}]	<h1 class="questionTitle" itemprop="name">Given a gas under #600"mm Hg"# pressure, and at #303.15K# temperature, that occupies a volume of #2.02L#, what volume will it occupy at #273.15K# temperature, under #750*"mm Hg"# pressure?</h1>	null	1.5 L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And <mathjax>#1"bar"-=(1"bar")/(1.01325atm"bar"^-1)=0.987atm#</mathjax></p> <p>I do all this rigmarole BECAUSE I know that <mathjax>#1atm#</mathjax> will support a column of mercury that is <mathjax>#760mm#</mathjax> high...........</p> <p>And hence in terms of the length of a mercury column, <mathjax>#1"bar"-=760mmHgatm^-1xx0.987atm=750.0mmHg#</mathjax></p> <p><mathjax>#(P_1V_1)/T_1=(P_2V_2)/T_2#</mathjax></p> <p>We want <mathjax>#V_2=(P_1V_1)/T_1xxT_2/P_2#</mathjax></p> <p><mathjax>#(600.0mmHgxx2.02L)/(303.15K)xx(273.15K)/(750mmHg)#</mathjax></p> <p><mathjax>#~=1.5L#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, the current definition of <mathjax>#"STP"#</mathjax> is.... a temperature of <mathjax>#273.15K#</mathjax> and a pressure of exactly <mathjax>#10^5Pa#</mathjax> <mathjax>#(100kPa, 1"bar")#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And <mathjax>#1"bar"-=(1"bar")/(1.01325atm"bar"^-1)=0.987atm#</mathjax></p> <p>I do all this rigmarole BECAUSE I know that <mathjax>#1atm#</mathjax> will support a column of mercury that is <mathjax>#760mm#</mathjax> high...........</p> <p>And hence in terms of the length of a mercury column, <mathjax>#1"bar"-=760mmHgatm^-1xx0.987atm=750.0mmHg#</mathjax></p> <p><mathjax>#(P_1V_1)/T_1=(P_2V_2)/T_2#</mathjax></p> <p>We want <mathjax>#V_2=(P_1V_1)/T_1xxT_2/P_2#</mathjax></p> <p><mathjax>#(600.0mmHgxx2.02L)/(303.15K)xx(273.15K)/(750mmHg)#</mathjax></p> <p><mathjax>#~=1.5L#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Given a gas under #600"mm Hg"# pressure, and at #303.15K# temperature, that occupies a volume of #2.02L#, what volume will it occupy at #273.15K# temperature, under #750"mm Hg"# pressure?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp" itemprop="url"> <span class="breadcrumb" itemprop="title">Molar Volume of a Gas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="459213" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-02T08:27:41" itemprop="dateCreated"> Aug 2, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, the current definition of <mathjax>#"STP"#</mathjax> is.... a temperature of <mathjax>#273.15K#</mathjax> and a pressure of exactly <mathjax>#10^5Pa#</mathjax> <mathjax>#(100kPa, 1"bar")#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And <mathjax>#1"bar"-=(1"bar")/(1.01325atm"bar"^-1)=0.987atm#</mathjax></p> <p>I do all this rigmarole BECAUSE I know that <mathjax>#1atm#</mathjax> will support a column of mercury that is <mathjax>#760mm#</mathjax> high...........</p> <p>And hence in terms of the length of a mercury column, <mathjax>#1"bar"-=760mmHgatm^-1xx0.987atm=750.0mmHg#</mathjax></p> <p><mathjax>#(P_1V_1)/T_1=(P_2V_2)/T_2#</mathjax></p> <p>We want <mathjax>#V_2=(P_1V_1)/T_1xxT_2/P_2#</mathjax></p> <p><mathjax>#(600.0mmHgxx2.02L)/(303.15K)xx(273.15K)/(750mmHg)#</mathjax></p> <p><mathjax>#~=1.5*L#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/459213" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-stoichiometric-ratios-relate-to-molar-volume-of-a-gas"> How do stoichiometric ratios relate to molar volume of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-a-gas-at-stp"> How do you calculate molar volume of a gas at STP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-molar-volume-of-hydrogen-gas"> How do you find the molar volume of hydrogen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-oxygen-gas"> How do you calculate molar volume of oxygen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molar-gas-volume"> What is molar gas volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/534c7bf202bf3420a007f014"> What is the volume at 0 °C and 1 atm of a mixture that contains 4.0 g of methane and 2.0 g of helium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5361f75702bf3429040e0599"> What is the difference between STP and NTP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-volume-of-25-moles-of-oxygen-o2-gas"> What is the volume of .25 moles of oxygen (O2) Gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-would-knowing-the-molar-volume-of-a-gas-be-important"> Why would knowing the molar volume of a gas be important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-22-4-liters-called-the-molar-volume-of-a-gas"> Why is 22.4 liters called the molar volume of a gas? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp"> See all questions in Molar Volume of a Gas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1426 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Given a gas under #600"mm Hg"# pressure, and at #303.15K# temperature, that occupies a volume of #2.02L#, what volume will it occupy at #273.15K# temperature, under #750*"mm Hg"# pressure?	null
2,261	a9dc442e-6ddd-11ea-bd98-ccda262736ce	https://socratic.org/questions/silicon-dioxide-reacts-with-carbon-to-produce-sic-and-carbon-monoxide-how-do-you	SiO2(s) + 3 C(s) -> SiC(s) + 2 CO(g)	start chemical_equation qc_end substance 0 1 qc_end substance 4 4 qc_end chemical_equation 7 7 qc_end substance 9 10 qc_end end	[{"type":"other","value":"Chemical Equation [OF] this reaction"}]	[{"type":"chemical equation","value":"SiO2(s) + 3 C(s) -> SiC(s) + 2 CO(g)"}]	[{"type":"substance name","value":"Silicon dioxide"},{"type":"substance name","value":"Carbon"},{"type":"chemical equation","value":"SiC"},{"type":"substance name","value":"Carbon monoxide"}]	<h1 class="questionTitle" itemprop="name">Silicon dioxide reacts with carbon to produce #SiC# and carbon monoxide. How do you write the balanced equation for this reaction?</h1>	null	SiO2(s) + 3 C(s) -> SiC(s) + 2 CO(g)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The reaction is an redox reaction. I don't know how it is made industrially (though there is a substantial usage of <mathjax>#SiC#</mathjax>). I imagine this is a solid state reaction where materials are roasted on HIGH (approx. <mathjax>#1500#</mathjax> <mathjax>#""^@C#</mathjax>).</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#SiO_2(s) + 3C(s) rarr SiC(s) + 2CO(g)uarr#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The reaction is an redox reaction. I don't know how it is made industrially (though there is a substantial usage of <mathjax>#SiC#</mathjax>). I imagine this is a solid state reaction where materials are roasted on HIGH (approx. <mathjax>#1500#</mathjax> <mathjax>#""^@C#</mathjax>).</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Silicon dioxide reacts with carbon to produce #SiC# and carbon monoxide. How do you write the balanced equation for this reaction?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="212852" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-15T18:28:49" itemprop="dateCreated"> Jan 15, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#SiO_2(s) + 3C(s) rarr SiC(s) + 2CO(g)uarr#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The reaction is an redox reaction. I don't know how it is made industrially (though there is a substantial usage of <mathjax>#SiC#</mathjax>). I imagine this is a solid state reaction where materials are roasted on HIGH (approx. <mathjax>#1500#</mathjax> <mathjax>#""^@C#</mathjax>).</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/212852" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------> H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -> Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? Aluminum and hydrochloric acid react to form aluminum... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equation-sodium-phosphate-and-calcium-chloride-r"> How can I balance this chemical equation? Sodium phosphate and calcium chloride react to form... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-equation-kclo3-kcl-o2"> How can I balance this equation? ____ #KClO_3 -># ____ #KCl +# ____ #O_2# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-balancing-chemical-equations-important"> Why is balancing chemical equations important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/balancing-chemical-equations"> See all questions in Balancing Chemical Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 23301 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Silicon dioxide reacts with carbon to produce #SiC# and carbon monoxide. How do you write the balanced equation for this reaction?	null
2,262	ac4a2f5c-6ddd-11ea-a9f8-ccda262736ce	https://socratic.org/questions/how-many-moles-of-h-2so-4-are-present-in-half-a-liter-of-a-0-150-m-h-2so-4-solut	0.08 moles	start physical_unit 4 4 mole mol qc_end physical_unit 15 16 13 14 molarity qc_end end	[{"type":"physical unit","value":"Mole [OF] H2SO4 [IN] moles"}]	[{"type":"physical unit","value":"0.08 moles"}]	[{"type":"physical unit","value":"Volume [OF] H2SO4 solution [=] \\pu{0.5 liter}"},{"type":"physical unit","value":"Molarity [OF] H2SO4 solution [=] \\pu{0.150 M}"}]	<h1 class="questionTitle" itemprop="name">How many moles of #H_2SO_4# are present in half a liter of a 0.150 M #H_2SO_4# solution?</h1>	null	0.08 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Molarity"="Moles of solute"/"Volume of solution"#</mathjax></p> <p>And thus, <mathjax>#"Moles of solute"="Volume of solution"xx"molarity"#</mathjax></p> <p><mathjax>#=0.5Lxx0.150molL^-1=0.075mol#</mathjax> with respect to <mathjax>#H_2SO_4#</mathjax>.</p> <p>Of course, we speak of a formal concentration. We know that in aqueous solution sulfuric acid speciates to give <mathjax>#HSO_4^-#</mathjax> and <mathjax>#SO_4^(2-)#</mathjax>, and equivalent quantities of <mathjax>#H_3O^+#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#0.075mol#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Molarity"="Moles of solute"/"Volume of solution"#</mathjax></p> <p>And thus, <mathjax>#"Moles of solute"="Volume of solution"xx"molarity"#</mathjax></p> <p><mathjax>#=0.5Lxx0.150molL^-1=0.075*mol#</mathjax> with respect to <mathjax>#H_2SO_4#</mathjax>.</p> <p>Of course, we speak of a formal concentration. We know that in aqueous solution sulfuric acid speciates to give <mathjax>#HSO_4^-#</mathjax> and <mathjax>#SO_4^(2-)#</mathjax>, and equivalent quantities of <mathjax>#H_3O^+#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles of #H_2SO_4# are present in half a liter of a 0.150 M #H_2SO_4# solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="422297" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-12T19:23:55" itemprop="dateCreated"> May 12, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#0.075mol#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Molarity"="Moles of solute"/"Volume of solution"#</mathjax></p> <p>And thus, <mathjax>#"Moles of solute"="Volume of solution"xx"molarity"#</mathjax></p> <p><mathjax>#=0.5Lxx0.150molL^-1=0.075*mol#</mathjax> with respect to <mathjax>#H_2SO_4#</mathjax>.</p> <p>Of course, we speak of a formal concentration. We know that in aqueous solution sulfuric acid speciates to give <mathjax>#HSO_4^-#</mathjax> and <mathjax>#SO_4^(2-)#</mathjax>, and equivalent quantities of <mathjax>#H_3O^+#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/422297" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 969 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many moles of #H_2SO_4# are present in half a liter of a 0.150 M #H_2SO_4# solution?	null
2,263	ac894f12-6ddd-11ea-a44e-ccda262736ce	https://socratic.org/questions/5852fdfb7c01495888fff8da	160.00 g	start physical_unit 8 9 mass g qc_end end	[{"type":"physical unit","value":"Mass [OF] oxygen gas [IN] g"}]	[{"type":"physical unit","value":"160.00 g"}]	[{"type":"physical unit","value":"Mole [OF] oxygen gas [=] \\pu{5 moles}"}]	<h1 class="questionTitle" itemprop="name">What is the mass of five moles of oxygen gas?</h1>	null	160.00 g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So.........in <mathjax>#5mol#</mathjax>, there are <mathjax>#5.0cancel(mol)xx32.00gcancel(mol^-1)=160*g#</mathjax>. Do you agree?</p> <p>What is the mass of <mathjax>#5.00xx10^-3mol#</mathjax>?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well in one mole of <mathjax>#"dioxygen gas"#</mathjax> there are <mathjax>#32.00g#</mathjax>........</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So.........in <mathjax>#5mol#</mathjax>, there are <mathjax>#5.0cancel(mol)xx32.00gcancel(mol^-1)=160g#</mathjax>. Do you agree?</p> <p>What is the mass of <mathjax>#5.00xx10^-3mol#</mathjax>?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the mass of five moles of oxygen gas?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="352359" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-12-15T20:44:24" itemprop="dateCreated"> Dec 15, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well in one mole of <mathjax>#"dioxygen gas"#</mathjax> there are <mathjax>#32.00g#</mathjax>........</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So.........in <mathjax>#5mol#</mathjax>, there are <mathjax>#5.0cancel(mol)xx32.00gcancel(mol^-1)=160g#</mathjax>. Do you agree?</p> <p>What is the mass of <mathjax>#5.00xx10^-3mol#</mathjax>?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/352359" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 5104 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the mass of five moles of oxygen gas?	null
2,264	aa30e1ae-6ddd-11ea-a4b5-ccda262736ce	https://socratic.org/questions/how-much-would-a-dosage-of-12ml-10-potassium-iodine-ki-w-v-solution-increase-iod	9.04 × 10^(-3) mM	start physical_unit 4 4 molarity mm qc_end physical_unit 13 13 6 7 volume qc_end physical_unit 13 13 22 23 volume qc_end end	[{"type":"physical unit","value":"Molarity2 [OF] the dosage [IN] mM"}]	[{"type":"physical unit","value":"9.04 × 10^(-3) mM"}]	[{"type":"physical unit","value":"Volume1 [OF] KI solution [=] \\pu{12 ml}"},{"type":"physical unit","value":"w/v [OF] KI in solution [=] \\pu{10%}"},{"type":"physical unit","value":"Volume2 [OF] KI solution [=] \\pu{800 liters}"}]	<h1 class="questionTitle" itemprop="name">How much would a dosage of 12ml 10% Potassium Iodide (KI) w/v solution increase Iodide levels in a total voluve of 800 liters? </h1>	null	9.04 × 10^(-3) mM	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">concentration</a> of iodide, or <mathjax>#"I"^(-)#</mathjax>, will increase by <mathjax>#"0.009 mM"#</mathjax>. </p> <p>First, start by figuring out exactly how much iodide you'll be adding to the tank. Use the given <mathjax>#"w/v "#</mathjax> <a href="http://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration</a> to determine how much potassium iodide you'd get in <strong>12 mL</strong>. </p> <p>A <mathjax>#"w/v"#</mathjax> percent contration solution is defined as</p> <p><mathjax>#"%w/v" = m_("solute")/V_("solution") * 100#</mathjax></p> <p>In your case, a <strong>10% w/v solution</strong> would have <strong>10 g</strong> of potassium iodide for every <strong>100 mL</strong> of solution. As a result, the <strong>12-mL</strong> sample will contain </p> <p><mathjax>#"12 mL" * "10 g"/"100 mL" = "1.2 g KI"#</mathjax></p> <p>Use potassium iodide's molar mass to determine how many moles you get from that mass </p> <p><mathjax>#"1.2 g KI" * "1 mole"/"166.0 g" = "0.00723 moles KI"#</mathjax></p> <p>Now, because potassium iodide fully dissociates in aqueous solution into <mathjax>#"K"^(+)#</mathjax> and <mathjax>#"I"^(-)#</mathjax> ions, the number of moles of iodide will be </p> <p><mathjax>#KI_((aq)) rightleftharpoons K_((aq))^(+) + I_((aq))^(-)#</mathjax></p> <p><mathjax>#"0.00723 moles KI" * "1 mole I"^(-)/"1 mole KI" = "0.00723 moles I"^(-)#</mathjax></p> <p>It is safe to assume that the added <mathjax>#"KI"#</mathjax> solution will not have an impact on the volume of the tank</p> <p><mathjax>#V_("tank total") = "800 L" + 12 * 10^(-3)"L" = "800.012 L" ~= "800 L"#</mathjax></p> <p>Therefore, the added concentration of iodide in the tank will be </p> <p><mathjax>#C = n/V = "0.00723 moles I"^(-)/"800 L" = "0.00904 mM"#</mathjax></p> <p>Rounded to one <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig fig</a>, the number of sig figs in 800 L, the answer will be </p> <p><mathjax>#["I"^(-)] = "0.009 mM"#</mathjax></p> <p><strong>SIDE NOTE</strong>. <em>Keep in mind that the concentration is milimolar, not molar</em>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.009 mM.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">concentration</a> of iodide, or <mathjax>#"I"^(-)#</mathjax>, will increase by <mathjax>#"0.009 mM"#</mathjax>. </p> <p>First, start by figuring out exactly how much iodide you'll be adding to the tank. Use the given <mathjax>#"w/v "#</mathjax> <a href="http://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration</a> to determine how much potassium iodide you'd get in <strong>12 mL</strong>. </p> <p>A <mathjax>#"w/v"#</mathjax> percent contration solution is defined as</p> <p><mathjax>#"%w/v" = m_("solute")/V_("solution") * 100#</mathjax></p> <p>In your case, a <strong>10% w/v solution</strong> would have <strong>10 g</strong> of potassium iodide for every <strong>100 mL</strong> of solution. As a result, the <strong>12-mL</strong> sample will contain </p> <p><mathjax>#"12 mL" * "10 g"/"100 mL" = "1.2 g KI"#</mathjax></p> <p>Use potassium iodide's molar mass to determine how many moles you get from that mass </p> <p><mathjax>#"1.2 g KI" * "1 mole"/"166.0 g" = "0.00723 moles KI"#</mathjax></p> <p>Now, because potassium iodide fully dissociates in aqueous solution into <mathjax>#"K"^(+)#</mathjax> and <mathjax>#"I"^(-)#</mathjax> ions, the number of moles of iodide will be </p> <p><mathjax>#KI_((aq)) rightleftharpoons K_((aq))^(+) + I_((aq))^(-)#</mathjax></p> <p><mathjax>#"0.00723 moles KI" * "1 mole I"^(-)/"1 mole KI" = "0.00723 moles I"^(-)#</mathjax></p> <p>It is safe to assume that the added <mathjax>#"KI"#</mathjax> solution will not have an impact on the volume of the tank</p> <p><mathjax>#V_("tank total") = "800 L" + 12 * 10^(-3)"L" = "800.012 L" ~= "800 L"#</mathjax></p> <p>Therefore, the added concentration of iodide in the tank will be </p> <p><mathjax>#C = n/V = "0.00723 moles I"^(-)/"800 L" = "0.00904 mM"#</mathjax></p> <p>Rounded to one <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig fig</a>, the number of sig figs in 800 L, the answer will be </p> <p><mathjax>#["I"^(-)] = "0.009 mM"#</mathjax></p> <p><strong>SIDE NOTE</strong>. <em>Keep in mind that the concentration is milimolar, not molar</em>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How much would a dosage of 12ml 10% Potassium Iodide (KI) w/v solution increase Iodide levels in a total voluve of 800 liters? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/percent-concentration" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Concentration</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="131532" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> <a class="secondContributorPic" href="/users/dwayne-m"><img alt="" class="" src="https://graph.facebook.com/589089719/picture?height=50&width=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a>·<a class="topContributorLink" href="/users/dwayne-m"> Dwayne M. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-03-04T20:50:29" itemprop="dateCreated"> Mar 4, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.009 mM.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">concentration</a> of iodide, or <mathjax>#"I"^(-)#</mathjax>, will increase by <mathjax>#"0.009 mM"#</mathjax>. </p> <p>First, start by figuring out exactly how much iodide you'll be adding to the tank. Use the given <mathjax>#"w/v "#</mathjax> <a href="http://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration</a> to determine how much potassium iodide you'd get in <strong>12 mL</strong>. </p> <p>A <mathjax>#"w/v"#</mathjax> percent contration solution is defined as</p> <p><mathjax>#"%w/v" = m_("solute")/V_("solution") * 100#</mathjax></p> <p>In your case, a <strong>10% w/v solution</strong> would have <strong>10 g</strong> of potassium iodide for every <strong>100 mL</strong> of solution. As a result, the <strong>12-mL</strong> sample will contain </p> <p><mathjax>#"12 mL" * "10 g"/"100 mL" = "1.2 g KI"#</mathjax></p> <p>Use potassium iodide's molar mass to determine how many moles you get from that mass </p> <p><mathjax>#"1.2 g KI" * "1 mole"/"166.0 g" = "0.00723 moles KI"#</mathjax></p> <p>Now, because potassium iodide fully dissociates in aqueous solution into <mathjax>#"K"^(+)#</mathjax> and <mathjax>#"I"^(-)#</mathjax> ions, the number of moles of iodide will be </p> <p><mathjax>#KI_((aq)) rightleftharpoons K_((aq))^(+) + I_((aq))^(-)#</mathjax></p> <p><mathjax>#"0.00723 moles KI" * "1 mole I"^(-)/"1 mole KI" = "0.00723 moles I"^(-)#</mathjax></p> <p>It is safe to assume that the added <mathjax>#"KI"#</mathjax> solution will not have an impact on the volume of the tank</p> <p><mathjax>#V_("tank total") = "800 L" + 12 * 10^(-3)"L" = "800.012 L" ~= "800 L"#</mathjax></p> <p>Therefore, the added concentration of iodide in the tank will be </p> <p><mathjax>#C = n/V = "0.00723 moles I"^(-)/"800 L" = "0.00904 mM"#</mathjax></p> <p>Rounded to one <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig fig</a>, the number of sig figs in 800 L, the answer will be </p> <p><mathjax>#["I"^(-)] = "0.009 mM"#</mathjax></p> <p><strong>SIDE NOTE</strong>. <em>Keep in mind that the concentration is milimolar, not molar</em>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/131532" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-concentration-of-water-in-solution-be-decreased"> How can the concentration of water in solution be decreased? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-concentration-of-a-solution-be-increased"> How can the concentration of a solution be increased? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-concentration-of-a-solution-in-ppm"> How do you find the concentration of a solution in ppm? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-make-a-10-percent-solution"> How do you make a 10 percent solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-make-a-2-percent-solution"> How do you make a 2 percent solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-weight-per-volume-method-to-calculate-concentration"> What is the weight per volume method to calculate concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-percent-concentration-of-kcl-would-be-isotonic"> What percent concentration of KCl would be isotonic? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-of-sodium-chloride-in-normal-saline"> What is the percent concentration of sodium chloride in normal saline? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-of-a-6m-solution-of-nacl"> What is the percent concentration of a 6m solution of NaCl? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-formula"> What is the percent concentration formula? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/percent-concentration"> See all questions in Percent Concentration </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 7484 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How much would a dosage of 12ml 10% Potassium Iodide (KI) w/v solution increase Iodide levels in a total voluve of 800 liters?	null
2,265	a8c077f0-6ddd-11ea-9dc1-ccda262736ce	https://socratic.org/questions/a-gas-occupies-a-volume-of-444-ml-at-273-k-and-79-0-kpa-what-is-the-final-kelvin	265 K	start physical_unit 24 25 temperature k qc_end physical_unit 24 25 9 10 temperature qc_end physical_unit 24 25 6 7 volume qc_end physical_unit 24 25 12 13 pressure qc_end physical_unit 24 25 28 29 volume qc_end physical_unit 24 25 36 37 pressure qc_end end	[{"type":"physical unit","value":"Kelvin temperature2 [OF] the gas [IN] K"}]	[{"type":"physical unit","value":"265 K"}]	[{"type":"physical unit","value":"Temperature1 [OF] the gas [=] \\pu{273 K}"},{"type":"physical unit","value":"Volume1 [OF] the gas [=] \\pu{444 mL}"},{"type":"physical unit","value":"Pressure1 [OF] the gas [=] \\pu{79.0 kPa}"},{"type":"physical unit","value":"Volume2 [OF] the gas [=] \\pu{880 mL}"},{"type":"physical unit","value":"Pressure2 [OF] the gas [=] \\pu{38.7 kPa}"}]	<h1 class="questionTitle" itemprop="name">A gas occupies a volume of 444 mL at 273 K and 79.0 kPa. What is the final kelvin temperature when the volume of the gas is change 880 mL and the pressure is changed to 38.7 kPa? </h1>	null	265 K	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Using the <a href="https://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">combined gas law</a> you can solve for your missing variable.</p> <p><mathjax>#(P1V1)/(T1)=(P2V2)/(T2)#</mathjax> </p> <p>P1 = 79.0 kPa<br/> V1 = 444 mL<br/> T1 = 273 K</p> <p>P2 = 38.7 kPa<br/> V2 = 880 mL<br/> T2 = ?</p> <p>Using the combined gas law we need to rearrange our equation to solve for T2. The first step in this process will be to times both T1 and T2 to both sides of the equation.</p> <p><mathjax>#(T1T2)(P1V1)/(T1)=(T1T2)(P2V2)/(T2)#</mathjax> </p> <p>Because T1 and T2 are on both sides of the denominator they cancel each other out, leaving us with the new equation: </p> <p><mathjax>#T2P1V1=T1P2V2#</mathjax></p> <p>We now need to divide P1 and V1 to both sides of the equation and cancel out once again, giving us the final equation:</p> <p><mathjax>#T2=(T1P2V2)/(P1V1)#</mathjax></p> <p>We can now plug in the numbers and solve for T2:</p> <p><mathjax>#T2= (273K * 38.7 kPa * 880 mL)/(79.0kPa * 444mL)=265 K#</mathjax></p> <p>Because kPa and mL are located on both sides of the denominator the units cancel out leaving use the the units K. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>265 K</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Using the <a href="https://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">combined gas law</a> you can solve for your missing variable.</p> <p><mathjax>#(P1V1)/(T1)=(P2V2)/(T2)#</mathjax> </p> <p>P1 = 79.0 kPa<br/> V1 = 444 mL<br/> T1 = 273 K</p> <p>P2 = 38.7 kPa<br/> V2 = 880 mL<br/> T2 = ?</p> <p>Using the combined gas law we need to rearrange our equation to solve for T2. The first step in this process will be to times both T1 and T2 to both sides of the equation.</p> <p><mathjax>#(T1T2)(P1V1)/(T1)=(T1T2)(P2V2)/(T2)#</mathjax> </p> <p>Because T1 and T2 are on both sides of the denominator they cancel each other out, leaving us with the new equation: </p> <p><mathjax>#T2P1V1=T1P2V2#</mathjax></p> <p>We now need to divide P1 and V1 to both sides of the equation and cancel out once again, giving us the final equation:</p> <p><mathjax>#T2=(T1P2V2)/(P1V1)#</mathjax></p> <p>We can now plug in the numbers and solve for T2:</p> <p><mathjax>#T2= (273K * 38.7 kPa * 880 mL)/(79.0kPa * 444mL)=265 K#</mathjax></p> <p>Because kPa and mL are located on both sides of the denominator the units cancel out leaving use the the units K. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A gas occupies a volume of 444 mL at 273 K and 79.0 kPa. What is the final kelvin temperature when the volume of the gas is change 880 mL and the pressure is changed to 38.7 kPa? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp" itemprop="url"> <span class="breadcrumb" itemprop="title">Molar Volume of a Gas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="617558" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/wolfeheart"><img alt="" class="" src="https://profilepictures.socratic.org/48J0XLK1To2NunsG33ct_11.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/wolfeheart"> WolfeHeart </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-05-21T16:08:52" itemprop="dateCreated"> May 21, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>265 K</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Using the <a href="https://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">combined gas law</a> you can solve for your missing variable.</p> <p><mathjax>#(P1V1)/(T1)=(P2V2)/(T2)#</mathjax> </p> <p>P1 = 79.0 kPa<br/> V1 = 444 mL<br/> T1 = 273 K</p> <p>P2 = 38.7 kPa<br/> V2 = 880 mL<br/> T2 = ?</p> <p>Using the combined gas law we need to rearrange our equation to solve for T2. The first step in this process will be to times both T1 and T2 to both sides of the equation.</p> <p><mathjax>#(T1T2)(P1V1)/(T1)=(T1T2)(P2V2)/(T2)#</mathjax> </p> <p>Because T1 and T2 are on both sides of the denominator they cancel each other out, leaving us with the new equation: </p> <p><mathjax>#T2P1V1=T1P2V2#</mathjax></p> <p>We now need to divide P1 and V1 to both sides of the equation and cancel out once again, giving us the final equation:</p> <p><mathjax>#T2=(T1P2V2)/(P1V1)#</mathjax></p> <p>We can now plug in the numbers and solve for T2:</p> <p><mathjax>#T2= (273K * 38.7 kPa * 880 mL)/(79.0kPa * 444mL)=265 K#</mathjax></p> <p>Because kPa and mL are located on both sides of the denominator the units cancel out leaving use the the units K. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/617558" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-stoichiometric-ratios-relate-to-molar-volume-of-a-gas"> How do stoichiometric ratios relate to molar volume of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-a-gas-at-stp"> How do you calculate molar volume of a gas at STP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-molar-volume-of-hydrogen-gas"> How do you find the molar volume of hydrogen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-oxygen-gas"> How do you calculate molar volume of oxygen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molar-gas-volume"> What is molar gas volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/534c7bf202bf3420a007f014"> What is the volume at 0 °C and 1 atm of a mixture that contains 4.0 g of methane and 2.0 g of helium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5361f75702bf3429040e0599"> What is the difference between STP and NTP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-volume-of-25-moles-of-oxygen-o2-gas"> What is the volume of .25 moles of oxygen (O2) Gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-would-knowing-the-molar-volume-of-a-gas-be-important"> Why would knowing the molar volume of a gas be important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-22-4-liters-called-the-molar-volume-of-a-gas"> Why is 22.4 liters called the molar volume of a gas? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp"> See all questions in Molar Volume of a Gas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 6012 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A gas occupies a volume of 444 mL at 273 K and 79.0 kPa. What is the final kelvin temperature when the volume of the gas is change 880 mL and the pressure is changed to 38.7 kPa?	null
2,266	a8b83b68-6ddd-11ea-bb2d-ccda262736ce	https://socratic.org/questions/a-student-collects-a-sample-of-gas-and-finds-that-1-01-g-of-the-gas-will-fill-a-	101 g/mol	start physical_unit 13 14 molar_mass g/mol qc_end c_other STP qc_end physical_unit 13 14 10 11 mass qc_end physical_unit 18 18 23 24 volume qc_end end	[{"type":"physical unit","value":"Molar mass [OF] the gas [IN] g/mol"}]	[{"type":"physical unit","value":"101 g/mol"}]	[{"type":"other","value":"STP"},{"type":"physical unit","value":"Mass [OF] the gas [=] \\pu{1.01 g}"},{"type":"physical unit","value":"Volume [OF] container [=] \\pu{0.225 L}"}]	<h1 class="questionTitle" itemprop="name">A student collects a sample of gas and finds that 1.01 g of the gas will fill a container with a volume of 0.225 L at STP. What is the molar mass of the gas? </h1>	null	101 g/mol	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>At STP, we know that the <a href="http://socratic.org/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp">molar volume of a gas</a> is <mathjax>#22.42L/(mol)#</mathjax>, therefore, now we can calculate the number of mole of the gas from its volume <mathjax>#V=0.225L#</mathjax> at STP.</p> <p><mathjax>#=>n=0.225cancel(L)xx(1mol)/(22.42cancel(L))=0.01 mol#</mathjax></p> <p>From the number of mole and the mass of the sample (<mathjax>#m=1.01g#</mathjax>) we can find the molar mass of the gas:</p> <p><mathjax>#n=m/(MM)=>MM=m/n=(1.01g)/(0.01mol)=101g/(mol)#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#MM=101g/(mol)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>At STP, we know that the <a href="http://socratic.org/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp">molar volume of a gas</a> is <mathjax>#22.42L/(mol)#</mathjax>, therefore, now we can calculate the number of mole of the gas from its volume <mathjax>#V=0.225L#</mathjax> at STP.</p> <p><mathjax>#=>n=0.225cancel(L)xx(1mol)/(22.42cancel(L))=0.01 mol#</mathjax></p> <p>From the number of mole and the mass of the sample (<mathjax>#m=1.01g#</mathjax>) we can find the molar mass of the gas:</p> <p><mathjax>#n=m/(MM)=>MM=m/n=(1.01g)/(0.01mol)=101g/(mol)#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A student collects a sample of gas and finds that 1.01 g of the gas will fill a container with a volume of 0.225 L at STP. What is the molar mass of the gas? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="216024" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ali-h-1"><img alt="" class="" src="https://profilepictures.socratic.org/IITeL1YTQdODdLp0aJTL_StereoPicture%20copy.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ali-h-1"> Dr. Hayek </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-23T15:09:18" itemprop="dateCreated"> Jan 23, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#MM=101g/(mol)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>At STP, we know that the <a href="http://socratic.org/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp">molar volume of a gas</a> is <mathjax>#22.42L/(mol)#</mathjax>, therefore, now we can calculate the number of mole of the gas from its volume <mathjax>#V=0.225L#</mathjax> at STP.</p> <p><mathjax>#=>n=0.225cancel(L)xx(1mol)/(22.42cancel(L))=0.01 mol#</mathjax></p> <p>From the number of mole and the mass of the sample (<mathjax>#m=1.01g#</mathjax>) we can find the molar mass of the gas:</p> <p><mathjax>#n=m/(MM)=>MM=m/n=(1.01g)/(0.01mol)=101g/(mol)#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/216024" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1411 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A student collects a sample of gas and finds that 1.01 g of the gas will fill a container with a volume of 0.225 L at STP. What is the molar mass of the gas?	null
2,267	ace92858-6ddd-11ea-8a06-ccda262736ce	https://socratic.org/questions/a-gas-takes-up-a-volume-of-19-5-liters-has-a-pressure-of-2-9-atm-and-a-temperatu	45.75 L	start physical_unit 42 43 volume l qc_end physical_unit 42 43 7 8 volume qc_end physical_unit 42 43 19 20 temperature qc_end physical_unit 42 43 13 14 pressure qc_end physical_unit 42 43 34 35 pressure qc_end physical_unit 42 43 27 28 temperature qc_end end	[{"type":"physical unit","value":"Volume2 [OF] the gas [IN] L"}]	[{"type":"physical unit","value":"45.75 L"}]	[{"type":"physical unit","value":"Volume1 [OF] the gas [=] \\pu{19.5 liters}"},{"type":"physical unit","value":"Temperature1 [OF] the gas [=] \\pu{5.5 ℃}"},{"type":"physical unit","value":"Pressure1 [OF] the gas [=] \\pu{2.9 atm}"},{"type":"physical unit","value":"Pressure2 [OF] the gas [=] \\pu{1.5 atm}"},{"type":"physical unit","value":"Temperature2 [OF] the gas [=] \\pu{65 ℃}"}]	<h1 class="questionTitle" itemprop="name"> A gas takes up a volume of 19.5 liters, has a pressure of 2.9 atm, and a temperature of 5.5°C. If I raise the temperature to 65°C and lower the pressure to 1.5 atm, what is the new volume of the gas?</h1>	null	45.75 L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>From the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> <mathjax>#PV=nRT#</mathjax> we can conclude that <mathjax>#n=(PV)/(RT)#</mathjax>.</p> <p>If the pressure <mathjax>#P#</mathjax>, the volume <mathjax>#V#</mathjax> and the temperature <mathjax>#T#</mathjax> of the gas change between two points, this change can be illustrated by:</p> <p><mathjax>#n=(P_1V_1)/(RT_1)=(P_2V_2)/(RT_2)#</mathjax></p> <p>Therefore, this expression can be modified as:</p> <p><mathjax>#(P_1V_1)/(cancel(R)T_1)=(P_2V_2)/(cancel(R)T_2)=>(P_1V_1)/(T_1)=(P_2V_2)/(T_2)#</mathjax></p> <p>Thus, <mathjax>#V_2=(P_1V_1)/(T_1)xx(T_2)/(P_2)#</mathjax></p> <p><mathjax>#V_2=(2.9cancel(atm)xx19.5L)/(278.5cancel(K))xx(338cancel(K))/(1.5cancel(atm))=45.8L#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#V_2=45.8L#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>From the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> <mathjax>#PV=nRT#</mathjax> we can conclude that <mathjax>#n=(PV)/(RT)#</mathjax>.</p> <p>If the pressure <mathjax>#P#</mathjax>, the volume <mathjax>#V#</mathjax> and the temperature <mathjax>#T#</mathjax> of the gas change between two points, this change can be illustrated by:</p> <p><mathjax>#n=(P_1V_1)/(RT_1)=(P_2V_2)/(RT_2)#</mathjax></p> <p>Therefore, this expression can be modified as:</p> <p><mathjax>#(P_1V_1)/(cancel(R)T_1)=(P_2V_2)/(cancel(R)T_2)=>(P_1V_1)/(T_1)=(P_2V_2)/(T_2)#</mathjax></p> <p>Thus, <mathjax>#V_2=(P_1V_1)/(T_1)xx(T_2)/(P_2)#</mathjax></p> <p><mathjax>#V_2=(2.9cancel(atm)xx19.5L)/(278.5cancel(K))xx(338cancel(K))/(1.5cancel(atm))=45.8L#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name"> A gas takes up a volume of 19.5 liters, has a pressure of 2.9 atm, and a temperature of 5.5°C. If I raise the temperature to 65°C and lower the pressure to 1.5 atm, what is the new volume of the gas?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/ideal-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Ideal Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="220197" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ali-h-1"><img alt="" class="" src="https://profilepictures.socratic.org/IITeL1YTQdODdLp0aJTL_StereoPicture%20copy.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ali-h-1"> Dr. Hayek </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-02-01T19:33:37" itemprop="dateCreated"> Feb 1, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#V_2=45.8L#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>From the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> <mathjax>#PV=nRT#</mathjax> we can conclude that <mathjax>#n=(PV)/(RT)#</mathjax>.</p> <p>If the pressure <mathjax>#P#</mathjax>, the volume <mathjax>#V#</mathjax> and the temperature <mathjax>#T#</mathjax> of the gas change between two points, this change can be illustrated by:</p> <p><mathjax>#n=(P_1V_1)/(RT_1)=(P_2V_2)/(RT_2)#</mathjax></p> <p>Therefore, this expression can be modified as:</p> <p><mathjax>#(P_1V_1)/(cancel(R)T_1)=(P_2V_2)/(cancel(R)T_2)=>(P_1V_1)/(T_1)=(P_2V_2)/(T_2)#</mathjax></p> <p>Thus, <mathjax>#V_2=(P_1V_1)/(T_1)xx(T_2)/(P_2)#</mathjax></p> <p><mathjax>#V_2=(2.9cancel(atm)xx19.5L)/(278.5cancel(K))xx(338cancel(K))/(1.5cancel(atm))=45.8L#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/220197" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-ideal-gas-constant"> How do you find the ideal gas constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-solve-ideal-gas-law-problems"> How do you solve ideal gas law problems? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-know-which-ideal-gas-constant-to-use"> How do you know which ideal gas constant to use? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ideal-gas-constant-for-butane"> What is the ideal gas constant for butane? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-ideal-gas-law-in-kelvin"> Why is ideal gas law in kelvin? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ideal-gas-constant-important"> Why is the ideal gas constant important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-di-electric-constant"> What is the di-electric constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-volume-l-will-0-20-mol-hi-occupy-at-300-k-and-100-0-kpa-r-8-314-kpa-l-k-mol"> What volume (L) will 0.20 mol HI occupy at 300 K and 100.0 kPa? R = 8.314 kPa L / (K mol) =... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-molar-mass-of-a-gas"> How do you calculate the molar mass of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-should-i-use-the-ideal-gas-law-and-not-the-combined-gas-law"> When should I use the ideal gas law and not the combined gas law? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/ideal-gas-law"> See all questions in Ideal Gas Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1470 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A gas takes up a volume of 19.5 liters, has a pressure of 2.9 atm, and a temperature of 5.5°C. If I raise the temperature to 65°C and lower the pressure to 1.5 atm, what is the new volume of the gas?	null
2,268	a9972aad-6ddd-11ea-b474-ccda262736ce	https://socratic.org/questions/how-many-moles-of-potassium-are-in-0-256-g	6.55 × 10^(-3)	start physical_unit 4 4 mole mol qc_end physical_unit 4 4 7 8 mass qc_end end	[{"type":"physical unit","value":"Mole [OF] potassium [IN] moles"}]	[{"type":"physical unit","value":"6.55 × 10^(-3)"}]	[{"type":"physical unit","value":"Mass [OF] potassium [=] \\pu{0.256 g}"}]	<h1 class="questionTitle" itemprop="name">How many moles of potassium are in 0.256 g? </h1>	null	6.55 × 10^(-3)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Recall that the formula for moles is:</p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a)n=m/Mcolor(white)(a/a)\|)))#</mathjax></p> <p>where:<br/> <mathjax>#color(magenta)n=#</mathjax>number of moles<br/> <mathjax>#color(orange)m=#</mathjax>mass (grams)<br/> <mathjax>#color(teal)M=#</mathjax>molar mass (grams/mole)</p> </blockquote> <p>Since you already have the mass of potassium, <mathjax>#color(orange)(0.256g)#</mathjax>, and the molar mass, <mathjax>#color(teal)(39.1g/(mol))#</mathjax>, which can be determined by looking at a periodic table, the only variable left to solve for is <mathjax>#color(magenta)n#</mathjax>, the number of moles. Thus:</p> <blockquote> <p><mathjax>#color(magenta)n=color(orange)m/color(teal)M#</mathjax></p> <p><mathjax>#color(magenta)n=color(orange)(0.256g)/color(teal)(39.1g/(mol))#</mathjax></p> <p><mathjax>#n=0.256g(mol)/(39.1g)#</mathjax></p> <p><mathjax>#n=0.256color(red)cancelcolor(black)g(mol)/(39.1color(red)cancelcolor(black)g)#</mathjax></p> <p><mathjax>#n=0.006547314578mol#</mathjax></p> </blockquote> <p><mathjax>#color(green)(\|bar(ul(color(white)(a/a)n~~0.00655molcolor(white)(a/a)\|)))rArr#</mathjax>rounded off to <mathjax>#3#</mathjax> <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#n~~0.00655mol#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Recall that the formula for moles is:</p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a)n=m/Mcolor(white)(a/a)\|)))#</mathjax></p> <p>where:<br/> <mathjax>#color(magenta)n=#</mathjax>number of moles<br/> <mathjax>#color(orange)m=#</mathjax>mass (grams)<br/> <mathjax>#color(teal)M=#</mathjax>molar mass (grams/mole)</p> </blockquote> <p>Since you already have the mass of potassium, <mathjax>#color(orange)(0.256g)#</mathjax>, and the molar mass, <mathjax>#color(teal)(39.1g/(mol))#</mathjax>, which can be determined by looking at a periodic table, the only variable left to solve for is <mathjax>#color(magenta)n#</mathjax>, the number of moles. Thus:</p> <blockquote> <p><mathjax>#color(magenta)n=color(orange)m/color(teal)M#</mathjax></p> <p><mathjax>#color(magenta)n=color(orange)(0.256g)/color(teal)(39.1g/(mol))#</mathjax></p> <p><mathjax>#n=0.256g(mol)/(39.1g)#</mathjax></p> <p><mathjax>#n=0.256color(red)cancelcolor(black)g(mol)/(39.1color(red)cancelcolor(black)g)#</mathjax></p> <p><mathjax>#n=0.006547314578mol#</mathjax></p> </blockquote> <p><mathjax>#color(green)(\|bar(ul(color(white)(a/a)n~~0.00655molcolor(white)(a/a)\|)))rArr#</mathjax>rounded off to <mathjax>#3#</mathjax> <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles of potassium are in 0.256 g? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="240547" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/johnson"><img alt="" class="" src="https://profilepictures.socratic.org/CODc7QKDQ4O1bKIs5CiO_SnakeSkin.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/johnson"> Johnson Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-16T18:09:09" itemprop="dateCreated"> Mar 16, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#n~~0.00655mol#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Recall that the formula for moles is:</p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a)n=m/Mcolor(white)(a/a)\|)))#</mathjax></p> <p>where:<br/> <mathjax>#color(magenta)n=#</mathjax>number of moles<br/> <mathjax>#color(orange)m=#</mathjax>mass (grams)<br/> <mathjax>#color(teal)M=#</mathjax>molar mass (grams/mole)</p> </blockquote> <p>Since you already have the mass of potassium, <mathjax>#color(orange)(0.256g)#</mathjax>, and the molar mass, <mathjax>#color(teal)(39.1g/(mol))#</mathjax>, which can be determined by looking at a periodic table, the only variable left to solve for is <mathjax>#color(magenta)n#</mathjax>, the number of moles. Thus:</p> <blockquote> <p><mathjax>#color(magenta)n=color(orange)m/color(teal)M#</mathjax></p> <p><mathjax>#color(magenta)n=color(orange)(0.256g)/color(teal)(39.1g/(mol))#</mathjax></p> <p><mathjax>#n=0.256g(mol)/(39.1g)#</mathjax></p> <p><mathjax>#n=0.256color(red)cancelcolor(black)g(mol)/(39.1color(red)cancelcolor(black)g)#</mathjax></p> <p><mathjax>#n=0.006547314578mol#</mathjax></p> </blockquote> <p><mathjax>#color(green)(\|bar(ul(color(white)(a/a)n~~0.00655molcolor(white)(a/a)\|)))rArr#</mathjax>rounded off to <mathjax>#3#</mathjax> <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/240547" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3790 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many moles of potassium are in 0.256 g?	null
2,269	abef1bf3-6ddd-11ea-a30e-ccda262736ce	https://socratic.org/questions/balancing-calcium-bicarbonate-reacts-with-hydrochloric-acid	Ca(HCO3)2(aq) + 2 HCl(aq) -> CaCl2(aq) + 2 CO2(g) + 2 H2O(l)	start chemical_equation qc_end substance 4 5 qc_end substance 8 9 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the equation"}]	[{"type":"chemical equation","value":"Ca(HCO3)2(aq) + 2 HCl(aq) -> CaCl2(aq) + 2 CO2(g) + 2 H2O(l)"}]	[{"type":"substance name","value":"Calcium bicarbonate"},{"type":"substance name","value":"Hydrochloric acid"}]	<h1 class="questionTitle" itemprop="name">How Do I Balance calcium bicarbonate reacts with hydrochloric acid ? </h1>	null	Ca(HCO3)2(aq) + 2 HCl(aq) -> CaCl2(aq) + 2 CO2(g) + 2 H2O(l)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Well, I think both charge and mass are balanced here......</p> <p>The net ionic equation is.......</p> <p><mathjax>#HCO_3^(-)+H_3O^(+) rarr CO_2(g)uarr + 2H_2O#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Ca(HCO_3)_2(aq)+2HCl(aq) rarr CaCl_2(aq) +2CO_2(g)uarr+2H_2O(l)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Well, I think both charge and mass are balanced here......</p> <p>The net ionic equation is.......</p> <p><mathjax>#HCO_3^(-)+H_3O^(+) rarr CO_2(g)uarr + 2H_2O#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How Do I Balance calcium bicarbonate reacts with hydrochloric acid ? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="454120" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-07-20T15:42:58" itemprop="dateCreated"> Jul 20, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Ca(HCO_3)_2(aq)+2HCl(aq) rarr CaCl_2(aq) +2CO_2(g)uarr+2H_2O(l)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Well, I think both charge and mass are balanced here......</p> <p>The net ionic equation is.......</p> <p><mathjax>#HCO_3^(-)+H_3O^(+) rarr CO_2(g)uarr + 2H_2O#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/454120" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------> H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -> Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? Aluminum and hydrochloric acid react to form aluminum... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equation-sodium-phosphate-and-calcium-chloride-r"> How can I balance this chemical equation? Sodium phosphate and calcium chloride react to form... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-equation-kclo3-kcl-o2"> How can I balance this equation? ____ #KClO_3 -># ____ #KCl +# ____ #O_2# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-balancing-chemical-equations-important"> Why is balancing chemical equations important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/balancing-chemical-equations"> See all questions in Balancing Chemical Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 16909 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How Do I Balance calcium bicarbonate reacts with hydrochloric acid ?	null
2,270	ac682595-6ddd-11ea-870d-ccda262736ce	https://socratic.org/questions/what-is-the-partial-pressure-of-oxygen-in-air	0.21 atm	start physical_unit 6 8 partial_pressure atm qc_end substance 6 6 qc_end end	[{"type":"physical unit","value":"Partial pressure [OF] oxygen in air [IN] atm"}]	[{"type":"physical unit","value":"0.21 atm"}]	[{"type":"substance name","value":"Oxygen"}]	<h1 class="questionTitle" itemprop="name">What is the partial pressure of oxygen in air?</h1>	null	0.21 atm	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Alternatively, <mathjax>#p_(O_2)=159.6mmHg#</mathjax>........</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The <a href="https://socratic.org/chemistry/the-behavior-of-gases/partial-pressure">partial pressure</a> of dioxygen gas at sea level is about <mathjax>#0.21atm#</mathjax>........</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Alternatively, <mathjax>#p_(O_2)=159.6mm*Hg#</mathjax>........</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the partial pressure of oxygen in air?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/partial-pressure" itemprop="url"> <span class="breadcrumb" itemprop="title">Partial Pressure</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="444008" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-24T22:08:16" itemprop="dateCreated"> Jun 24, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The <a href="https://socratic.org/chemistry/the-behavior-of-gases/partial-pressure">partial pressure</a> of dioxygen gas at sea level is about <mathjax>#0.21atm#</mathjax>........</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Alternatively, <mathjax>#p_(O_2)=159.6mm*Hg#</mathjax>........</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/444008" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/534e256802bf342adfa30010"> How do you do a steam distillation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/53613f9f02bf3416cd9f8a34"> Question #f8a34 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-i-calculate-the-total-pressure-of-a-mixture-of-gases-by-adding-together-the-"> Can I calculate the total pressure of a mixture of gases by adding together the partial... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-formula-of-partial-pressure"> What is the formula of partial pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-dalton-s-law-of-partial-pressures"> What is the Dalton's law of partial pressures? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/nitrogen-gas-n2-reacts-with-hydrogen-gas-h2-to-form-ammonia-nh3-at-200-c-in-a-cl"> Nitrogen gas (N2) reacts with hydrogen gas (H2) to form ammonia (NH3). At 200°C in a closed... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-partial-pressure-of-oxygen-in-arterial-blood"> What is partial pressure of oxygen in arterial blood? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-partial-pressure-gradient"> What is partial pressure gradient? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-find-partial-pressure-given-moles"> How can I find partial pressure given moles? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-the-partial-pressure-of-a-gas-in-a-mixture-calculated"> How is the partial pressure of a gas in a mixture calculated? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/partial-pressure"> See all questions in Partial Pressure </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2851 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the partial pressure of oxygen in air?	null
2,271	ac0865f6-6ddd-11ea-b8fb-ccda262736ce	https://socratic.org/questions/how-many-grams-of-sodium-sulfide-are-formed-if-1-50-g-of-hydrogen-sulfide-is-bub	1.83 grams	start physical_unit 4 5 mass g qc_end physical_unit 12 13 9 9 mass qc_end physical_unit 23 24 20 21 mass qc_end physical_unit 4 5 33 33 percent_yield qc_end end	[{"type":"physical unit","value":"Mass [OF] sodium sulfide [IN] grams"}]	[{"type":"physical unit","value":"1.83 grams"}]	[{"type":"physical unit","value":"Mass [OF] hydrogen sulfide [=] \\pu{1.50 }"},{"type":"physical unit","value":"Mass [OF] sodium hydroxide [=] \\pu{2.00 g}"},{"type":"physical unit","value":"Yield [OF] sodium sulfide [=] \\pu{94.0%}"}]	<h1 class="questionTitle" itemprop="name">How many grams of sodium sulfide are formed if 1.50 g of hydrogen sulfide is bubbled into a solution containing 2.00 g of sodium hydroxide, assuming that the sodium sulfide is made in 94.0 % yield? </h1>	null	1.83 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The first step for any chemical reaction is to write out the chemical equation to determine the molar ratios of the reactants and products. Then we will use the molecular formulas and weights to calculate the desired answer.</p> <p><mathjax>#2NaOH + H_2S → Na_2S + 2H_2O#</mathjax> <br/> So, it takes two moles of sodium hydroxide to react with one mole of hydrogen sulfide to produce one mole of sodium sulfide and two moles of water.</p> <p>The actual amounts that we have are 1.5/34 = 0.044 moles of <mathjax>#H_2S#</mathjax> and 2.0/40 = 0.05 moles of NaOH. </p> <p>That means that NaOH is the “<a href="https://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a>” - no more than 0.05/2 = 0.025 moles of <mathjax>#H_2S#</mathjax> would be able to react theoretically. </p> <p>Given the state 94% yield, this means that only 0.94 * 0.025 = 0.0235 moles of <mathjax>#H_2S#</mathjax> will react to form <mathjax>#Na_2S#</mathjax>. </p> <p>This will produce 0.0235 moles of <mathjax>#Na_2S#</mathjax>.<br/> The mass is found from the molecular weight again: <br/> 0.0235 * 78 = 1.83g <mathjax>#Na_2S#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>1.83g <mathjax>#Na_2S#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The first step for any chemical reaction is to write out the chemical equation to determine the molar ratios of the reactants and products. Then we will use the molecular formulas and weights to calculate the desired answer.</p> <p><mathjax>#2NaOH + H_2S → Na_2S + 2H_2O#</mathjax> <br/> So, it takes two moles of sodium hydroxide to react with one mole of hydrogen sulfide to produce one mole of sodium sulfide and two moles of water.</p> <p>The actual amounts that we have are 1.5/34 = 0.044 moles of <mathjax>#H_2S#</mathjax> and 2.0/40 = 0.05 moles of NaOH. </p> <p>That means that NaOH is the “<a href="https://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a>” - no more than 0.05/2 = 0.025 moles of <mathjax>#H_2S#</mathjax> would be able to react theoretically. </p> <p>Given the state 94% yield, this means that only 0.94 * 0.025 = 0.0235 moles of <mathjax>#H_2S#</mathjax> will react to form <mathjax>#Na_2S#</mathjax>. </p> <p>This will produce 0.0235 moles of <mathjax>#Na_2S#</mathjax>.<br/> The mass is found from the molecular weight again: <br/> 0.0235 * 78 = 1.83g <mathjax>#Na_2S#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many grams of sodium sulfide are formed if 1.50 g of hydrogen sulfide is bubbled into a solution containing 2.00 g of sodium hydroxide, assuming that the sodium sulfide is made in 94.0 % yield? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/percent-yield" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Yield</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="377700" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/scooke"><img alt="" class="" src="https://profilepictures.socratic.org/ezAzqDkjRS6NXBmMH3lg_BioPic2010a.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/scooke"> SCooke </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-02-14T11:48:33" itemprop="dateCreated"> Feb 14, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>1.83g <mathjax>#Na_2S#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The first step for any chemical reaction is to write out the chemical equation to determine the molar ratios of the reactants and products. Then we will use the molecular formulas and weights to calculate the desired answer.</p> <p><mathjax>#2NaOH + H_2S → Na_2S + 2H_2O#</mathjax> <br/> So, it takes two moles of sodium hydroxide to react with one mole of hydrogen sulfide to produce one mole of sodium sulfide and two moles of water.</p> <p>The actual amounts that we have are 1.5/34 = 0.044 moles of <mathjax>#H_2S#</mathjax> and 2.0/40 = 0.05 moles of NaOH. </p> <p>That means that NaOH is the “<a href="https://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a>” - no more than 0.05/2 = 0.025 moles of <mathjax>#H_2S#</mathjax> would be able to react theoretically. </p> <p>Given the state 94% yield, this means that only 0.94 * 0.025 = 0.0235 moles of <mathjax>#H_2S#</mathjax> will react to form <mathjax>#Na_2S#</mathjax>. </p> <p>This will produce 0.0235 moles of <mathjax>#Na_2S#</mathjax>.<br/> The mass is found from the molecular weight again: <br/> 0.0235 * 78 = 1.83g <mathjax>#Na_2S#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/377700" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ebd02bf3469570e2e62"> Question #e2e62 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ec502bf34694a4fee2e"> Question #fee2e </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ec902bf34694a4fee32"> Question #fee32 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ece02bf346950519e89"> Question #19e89 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ed302bf34694c8c5bdc"> Question #c5bdc </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ee302bf3469517a1065"> Question #a1065 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-would-be-the-limiting-reagent-if-26-0-grams-of-c3h9n-were-reacted-with-46-3"> What would be the limiting reagent if 26.0 grams of C3H9N were reacted with 46.3 grams of... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-percent-yield-always-less-than-100"> Is percent yield always less than 100? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-would-be-the-limiting-reagent-if-41-9-grams-of-c2h3of-were-reacted-with-61-"> What would be the limiting reagent if 41.9 grams of C2H3OF were reacted with 61.0 grams of... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-yield-of-the-following-reaction-if-60-grams-of-caco3-is-heat"> What is the percent yield of the following reaction if 60 grams of CaCO3 is heated to give 15... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/percent-yield"> See all questions in Percent Yield </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 23401 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many grams of sodium sulfide are formed if 1.50 g of hydrogen sulfide is bubbled into a solution containing 2.00 g of sodium hydroxide, assuming that the sodium sulfide is made in 94.0 % yield?	null
2,272	acf1d9f6-6ddd-11ea-9a7c-ccda262736ce	https://socratic.org/questions/you-have-18-0-g-of-aluminum-metal-and-a-sample-of-1-3m-nitric-acid-in-water-what	1.54 L	start physical_unit 20 20 volume l qc_end physical_unit 5 6 2 3 mass qc_end physical_unit 13 14 11 12 molarity qc_end c_other OTHER qc_end chemical_equation 39 49 qc_end substance 16 16 qc_end end	[{"type":"physical unit","value":"Volume [OF] nitric acid solution [IN] L"}]	[{"type":"physical unit","value":"1.54 L"}]	[{"type":"physical unit","value":"Mass [OF] aluminum metal [=] \\pu{18.0 g}"},{"type":"physical unit","value":"Molarity [OF] nitric acid solution [=] \\pu{1.3 M}"},{"type":"other","value":"Completely consume the aluminum."},{"type":"chemical equation","value":"6 HNO3(aq) + 2 Al(s) -> 2 Al(NO3)3(aq) + 3 H2(g)"},{"type":"substance name","value":"Water"}]	<h1 class="questionTitle" itemprop="name">You have 18.0 g of aluminum metal, and a sample of 1.3M nitric acid in water. What volume of solution would you need to add to the metal to completely consume the aluminum according to the reaction below? 6 HNO3(aq) + 2Al(s) → 2 Al(NO3)3(aq)+ 3 H2(g) </h1>	null	1.54 L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your strategy here will be to use the <strong><a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a></strong> that exists between the two reactants to determine how many moles of nitric acid are needed in order for <strong>all the moles</strong> of aluminium to take part in the reaction. </p> <p>Once you know this, use the <strong><a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></strong> of the nitric acid solution to determine what volume would contain that many moles of acid. </p> <p>So, the balanced chemical equation for this <strong><a href="http://socratic.org/chemistry/chemical-reactions/single-replacement-reactions">single replacement reaction</a></strong> looks like this</p> <blockquote> <p><mathjax>#color(red)(2)"Al"_text((s]) + color(purple)(6)"HNO"_text(3(aq]) -> 2"Al"("NO"_3)_text(3(aq]) + 3"H"_text(2(g]) uarr#</mathjax></p> </blockquote> <p>Notice the <mathjax>#color(red)(2):color(purple)(6)#</mathjax> mole ratio that exists between the metal and the acid. This tells you that the reaction will always consume <strong>three times as many</strong> moles of nitric acid than of aluminium metal. </p> <p>Use aluminium's <strong>molar mass</strong> to determine how many moles you have in that <mathjax>#"18.0-g"#</mathjax> sample</p> <blockquote> <p><mathjax>#18.0color(red)(cancel(color(black)("g"))) * "1 mole Al"/(26.98color(red)(cancel(color(black)("g")))) = "0.6672 moles Al"#</mathjax></p> </blockquote> <p>This means that the nitric acid solution must contain </p> <blockquote> <p><mathjax>#0.6672color(red)(cancel(color(black)("moles Al"))) * (color(purple)(6)color(white)(a)"moles HNO"_3)/(color(red)(2)color(red)(cancel(color(black)("moles Al")))) = "2.002 moles HNO"_3#</mathjax></p> </blockquote> <p>So, <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> is defined as <em>moles of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a></em>, which in your case is nitric acid, <strong>per liter</strong> of solution. </p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a)c = n_"solute"/V_"solution"color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>You know that your solution has a concentration of <mathjax>#"1.3 mol L"^(-1)#</mathjax>, and that it must contain <mathjax>#0.3336#</mathjax> moles of solute. This means that you will have</p> <blockquote> <p><mathjax>#color(purple)(\|bar(ul(color(white)(a/a)color(black)(c = n_"solute"/V_"solution" implies V_"solution" = n_"solute"/c)color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>Plug in your values to get</p> <blockquote> <p><mathjax>#V_(HNO_3) = (2.002 color(red)(cancel(color(black)("moles"))))/(1.3color(red)(cancel(color(black)("mol")))"L"^(-1)) = "1.54 L"#</mathjax></p> </blockquote> <p>Rounded to two <strong><a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the molarity of the nitric acid solution, the answer will be </p> <blockquote> <p><mathjax>#V_"solution" = color(green)(\|bar(ul(color(white)(a/a)"1.5 L"color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p><strong>SIDE NOTE</strong> <em>It's worth mentioning that this reaction only takes place with <strong>dilute nitric acid</strong></em>.</p> <p><em><strong>Concentrated nitric acid</strong> will react with the metal and form a protective layer of metal oxide that will bring the reaction to a halt - this phenomenon is called <strong>passivation</strong></em>. </p> <p><em>Moreover, the reaction will not produce hydrogen gas. Instead, the acid will be reduced to a nitrogen oxide.</em></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"1.5 L"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your strategy here will be to use the <strong><a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a></strong> that exists between the two reactants to determine how many moles of nitric acid are needed in order for <strong>all the moles</strong> of aluminium to take part in the reaction. </p> <p>Once you know this, use the <strong><a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></strong> of the nitric acid solution to determine what volume would contain that many moles of acid. </p> <p>So, the balanced chemical equation for this <strong><a href="http://socratic.org/chemistry/chemical-reactions/single-replacement-reactions">single replacement reaction</a></strong> looks like this</p> <blockquote> <p><mathjax>#color(red)(2)"Al"_text((s]) + color(purple)(6)"HNO"_text(3(aq]) -> 2"Al"("NO"_3)_text(3(aq]) + 3"H"_text(2(g]) uarr#</mathjax></p> </blockquote> <p>Notice the <mathjax>#color(red)(2):color(purple)(6)#</mathjax> mole ratio that exists between the metal and the acid. This tells you that the reaction will always consume <strong>three times as many</strong> moles of nitric acid than of aluminium metal. </p> <p>Use aluminium's <strong>molar mass</strong> to determine how many moles you have in that <mathjax>#"18.0-g"#</mathjax> sample</p> <blockquote> <p><mathjax>#18.0color(red)(cancel(color(black)("g"))) * "1 mole Al"/(26.98color(red)(cancel(color(black)("g")))) = "0.6672 moles Al"#</mathjax></p> </blockquote> <p>This means that the nitric acid solution must contain </p> <blockquote> <p><mathjax>#0.6672color(red)(cancel(color(black)("moles Al"))) * (color(purple)(6)color(white)(a)"moles HNO"_3)/(color(red)(2)color(red)(cancel(color(black)("moles Al")))) = "2.002 moles HNO"_3#</mathjax></p> </blockquote> <p>So, <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> is defined as <em>moles of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a></em>, which in your case is nitric acid, <strong>per liter</strong> of solution. </p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a)c = n_"solute"/V_"solution"color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>You know that your solution has a concentration of <mathjax>#"1.3 mol L"^(-1)#</mathjax>, and that it must contain <mathjax>#0.3336#</mathjax> moles of solute. This means that you will have</p> <blockquote> <p><mathjax>#color(purple)(\|bar(ul(color(white)(a/a)color(black)(c = n_"solute"/V_"solution" implies V_"solution" = n_"solute"/c)color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>Plug in your values to get</p> <blockquote> <p><mathjax>#V_(HNO_3) = (2.002 color(red)(cancel(color(black)("moles"))))/(1.3color(red)(cancel(color(black)("mol")))"L"^(-1)) = "1.54 L"#</mathjax></p> </blockquote> <p>Rounded to two <strong><a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the molarity of the nitric acid solution, the answer will be </p> <blockquote> <p><mathjax>#V_"solution" = color(green)(\|bar(ul(color(white)(a/a)"1.5 L"color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p><strong>SIDE NOTE</strong> <em>It's worth mentioning that this reaction only takes place with <strong>dilute nitric acid</strong></em>.</p> <p><em><strong>Concentrated nitric acid</strong> will react with the metal and form a protective layer of metal oxide that will bring the reaction to a halt - this phenomenon is called <strong>passivation</strong></em>. </p> <p><em>Moreover, the reaction will not produce hydrogen gas. Instead, the acid will be reduced to a nitrogen oxide.</em></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">You have 18.0 g of aluminum metal, and a sample of 1.3M nitric acid in water. What volume of solution would you need to add to the metal to completely consume the aluminum according to the reaction below? 6 HNO3(aq) + 2Al(s) → 2 Al(NO3)3(aq)+ 3 H2(g) </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="239350" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-14T00:08:49" itemprop="dateCreated"> Mar 14, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"1.5 L"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your strategy here will be to use the <strong><a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a></strong> that exists between the two reactants to determine how many moles of nitric acid are needed in order for <strong>all the moles</strong> of aluminium to take part in the reaction. </p> <p>Once you know this, use the <strong><a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></strong> of the nitric acid solution to determine what volume would contain that many moles of acid. </p> <p>So, the balanced chemical equation for this <strong><a href="http://socratic.org/chemistry/chemical-reactions/single-replacement-reactions">single replacement reaction</a></strong> looks like this</p> <blockquote> <p><mathjax>#color(red)(2)"Al"_text((s]) + color(purple)(6)"HNO"_text(3(aq]) -> 2"Al"("NO"_3)_text(3(aq]) + 3"H"_text(2(g]) uarr#</mathjax></p> </blockquote> <p>Notice the <mathjax>#color(red)(2):color(purple)(6)#</mathjax> mole ratio that exists between the metal and the acid. This tells you that the reaction will always consume <strong>three times as many</strong> moles of nitric acid than of aluminium metal. </p> <p>Use aluminium's <strong>molar mass</strong> to determine how many moles you have in that <mathjax>#"18.0-g"#</mathjax> sample</p> <blockquote> <p><mathjax>#18.0color(red)(cancel(color(black)("g"))) * "1 mole Al"/(26.98color(red)(cancel(color(black)("g")))) = "0.6672 moles Al"#</mathjax></p> </blockquote> <p>This means that the nitric acid solution must contain </p> <blockquote> <p><mathjax>#0.6672color(red)(cancel(color(black)("moles Al"))) * (color(purple)(6)color(white)(a)"moles HNO"_3)/(color(red)(2)color(red)(cancel(color(black)("moles Al")))) = "2.002 moles HNO"_3#</mathjax></p> </blockquote> <p>So, <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> is defined as <em>moles of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a></em>, which in your case is nitric acid, <strong>per liter</strong> of solution. </p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a)c = n_"solute"/V_"solution"color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>You know that your solution has a concentration of <mathjax>#"1.3 mol L"^(-1)#</mathjax>, and that it must contain <mathjax>#0.3336#</mathjax> moles of solute. This means that you will have</p> <blockquote> <p><mathjax>#color(purple)(\|bar(ul(color(white)(a/a)color(black)(c = n_"solute"/V_"solution" implies V_"solution" = n_"solute"/c)color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>Plug in your values to get</p> <blockquote> <p><mathjax>#V_(HNO_3) = (2.002 color(red)(cancel(color(black)("moles"))))/(1.3color(red)(cancel(color(black)("mol")))"L"^(-1)) = "1.54 L"#</mathjax></p> </blockquote> <p>Rounded to two <strong><a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the molarity of the nitric acid solution, the answer will be </p> <blockquote> <p><mathjax>#V_"solution" = color(green)(\|bar(ul(color(white)(a/a)"1.5 L"color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p><strong>SIDE NOTE</strong> <em>It's worth mentioning that this reaction only takes place with <strong>dilute nitric acid</strong></em>.</p> <p><em><strong>Concentrated nitric acid</strong> will react with the metal and form a protective layer of metal oxide that will bring the reaction to a halt - this phenomenon is called <strong>passivation</strong></em>. </p> <p><em>Moreover, the reaction will not produce hydrogen gas. Instead, the acid will be reduced to a nitrogen oxide.</em></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/239350" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-morality-be-used-as-a-conversion-factor"> How can molarity be used as a conversion factor? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-high-can-molarity-be"> How high can molarity be? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-molarity-change-with-temperature"> How does molarity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molarity-of-a-solution"> How do you find molarity of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-10-naoh"> What is the molarity of 10 NaOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-3-hydrogen-peroxide"> What is the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3563 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	You have 18.0 g of aluminum metal, and a sample of 1.3M nitric acid in water. What volume of solution would you need to add to the metal to completely consume the aluminum according to the reaction below? 6 HNO3(aq) + 2Al(s) → 2 Al(NO3)3(aq)+ 3 H2(g)	null
2,273	acae0348-6ddd-11ea-98f0-ccda262736ce	https://socratic.org/questions/58cb323a7c01491e98d3be32	2 S(s) + 3 O2(g) -> 2 SO3(g)	start chemical_equation qc_end chemical_equation 9 9 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the formation"}]	[{"type":"chemical equation","value":"2 S(s) + 3 O2(g) -> 2 SO3(g)"}]	[{"type":"chemical equation","value":"SO3"}]	<h1 class="questionTitle" itemprop="name">What is the stoichiometric equation for the formation of #SO_3#?</h1>	null	2 S(s) + 3 O2(g) -> 2 SO3(g)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And this equation directly represents the <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> of the diagram. To make the arithmetic a little bit easier when we work out equivalent mass and stoichiometry we could write.....</p> <p><mathjax>#S(s) + 3/2O_2(g) rarr SO_3(g)#</mathjax>...............</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well you gots <mathjax>#2S(s)+3O_2(g)rarr2SO_3(g)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And this equation directly represents the <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> of the diagram. To make the arithmetic a little bit easier when we work out equivalent mass and stoichiometry we could write.....</p> <p><mathjax>#S(s) + 3/2O_2(g) rarr SO_3(g)#</mathjax>...............</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the stoichiometric equation for the formation of #SO_3#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="469702" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-30T08:38:55" itemprop="dateCreated"> Aug 30, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well you gots <mathjax>#2S(s)+3O_2(g)rarr2SO_3(g)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And this equation directly represents the <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> of the diagram. To make the arithmetic a little bit easier when we work out equivalent mass and stoichiometry we could write.....</p> <p><mathjax>#S(s) + 3/2O_2(g) rarr SO_3(g)#</mathjax>...............</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/469702" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-equation-for-photosynthesis"> What is the chemical equation for photosynthesis? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-know-the-relative-number-of-grams-of-each-substance-used-or-produced-w"> How can I know the relative number of grams of each substance used or produced with chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-know-the-relative-number-of-moles-of-each-substance-with-chemical-equa"> How can I know the relative number of moles of each substance with chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-chemical-equations-illustrate-that-atoms-are-conserved-1"> How do chemical equations illustrate that atoms are conserved? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-know-the-formula-of-the-reactants-and-products-with-chemical-equations"> How can I know the formula of the reactants and products with chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-potassium-metal-and-chlorine-gas-combi"> How can I balance this chemical equations? Potassium metal and chlorine gas combine to form... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-types-of-chemical-reactions-exist"> How many types of chemical reactions exist? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-a-chemical-equation-be-made-more-informative"> How can a chemical equation be made more informative? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-equation-albr3-k2so4-kbr-al2-so4-3"> How can I balance this equation? ___ AlBr3 + ____ K2SO4 ---> ____ KBr + ____ Al2(SO4)3 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-equation-pb-oh-2-hcl-h2o-pbcl2"> How can I balance this equation? ____ Pb(OH)2 + ____ HCl ---> ____ H2O + ____ PbCl2 </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/chemical-equations"> See all questions in Chemical Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1220 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the stoichiometric equation for the formation of #SO_3#?	null
2,274	aa1f2838-6ddd-11ea-81ad-ccda262736ce	https://socratic.org/questions/how-many-moles-of-potassium-iodide-kci-are-there-in-50-grams	0.67 moles	start physical_unit 6 6 mole mol qc_end end	[{"type":"physical unit","value":"Mole [OF] KCI [IN] moles"}]	[{"type":"physical unit","value":"0.67 moles"}]	[{"type":"physical unit","value":"Mass [OF] KCl [=] \\pu{50 grams}"}]	<h1 class="questionTitle" itemprop="name">How many moles of potassium iodide, KCI, are there in 50 grams? </h1>	null	0.67 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To get our answer we just need to do some <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>:<br/> The molar mass of KCl is 74.55 <mathjax>#g/(mol)#</mathjax></p> <p>50 grams KCl <mathjax>#(1 mol KCl) /(74.55 g)= .6707 mols KCl#</mathjax></p> <p>As presented this problem is rounded to 1 sig fig since 50 grams is 1 sig fig.</p> <p>Thus the rounded answer would be 0.7 mols</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.7 mols</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To get our answer we just need to do some <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>:<br/> The molar mass of KCl is 74.55 <mathjax>#g/(mol)#</mathjax></p> <p>50 grams KCl <mathjax>#(1 mol KCl) /(74.55 g)= .6707 mols KCl#</mathjax></p> <p>As presented this problem is rounded to 1 sig fig since 50 grams is 1 sig fig.</p> <p>Thus the rounded answer would be 0.7 mols</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles of potassium iodide, KCI, are there in 50 grams? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="404349" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/a-raz"><img alt="" class="" src="https://profilepictures.socratic.org/RTbzR8EpS3OStVOgUbpC_Screen%20Shot%202017-04-08%20at%208.32.56%20PM.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/a-raz"> A.Raz </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-10T02:54:35" itemprop="dateCreated"> Apr 10, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.7 mols</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To get our answer we just need to do some <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>:<br/> The molar mass of KCl is 74.55 <mathjax>#g/(mol)#</mathjax></p> <p>50 grams KCl <mathjax>#(1 mol KCl) /(74.55 g)= .6707 mols KCl#</mathjax></p> <p>As presented this problem is rounded to 1 sig fig since 50 grams is 1 sig fig.</p> <p>Thus the rounded answer would be 0.7 mols</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/404349" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 6014 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many moles of potassium iodide, KCI, are there in 50 grams?	null
2,275	ace6490a-6ddd-11ea-a760-ccda262736ce	https://socratic.org/questions/the-molar-mass-of-a-certain-gas-is-49-g-what-is-the-density-of-the-gas-in-g-l-at	2.2 g/L	start physical_unit 15 16 density g/l qc_end physical_unit 4 6 8 9 molar_mass qc_end c_other STP qc_end end	[{"type":"physical unit","value":"Density [OF] the gas [IN] g/L"}]	[{"type":"physical unit","value":"2.2 g/L"}]	[{"type":"physical unit","value":"Molar mass [OF] a certain gas [=] \\pu{49 g}"},{"type":"other","value":"STP"}]	<h1 class="questionTitle" itemprop="name">The molar mass of a certain gas is 49 g. What is the density of the gas in g/L at STP?</h1>	null	2.2 g/L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>At STP (0 °C and 1 bar) the <a href="https://socratic.org/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp">molar volume of a gas</a> is 22.71 L.</p> <p>Thus,</p> <p><mathjax>#"Density" = "mass"/"volume" = "49 g"/"22.71 L" = "2.2 g/L"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The <a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a> of the gas is 2.2 g/L.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>At STP (0 °C and 1 bar) the <a href="https://socratic.org/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp">molar volume of a gas</a> is 22.71 L.</p> <p>Thus,</p> <p><mathjax>#"Density" = "mass"/"volume" = "49 g"/"22.71 L" = "2.2 g/L"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">The molar mass of a certain gas is 49 g. What is the density of the gas in g/L at STP?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp" itemprop="url"> <span class="breadcrumb" itemprop="title">Molar Volume of a Gas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="362873" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-01-10T23:19:16" itemprop="dateCreated"> Jan 10, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The <a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a> of the gas is 2.2 g/L.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>At STP (0 °C and 1 bar) the <a href="https://socratic.org/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp">molar volume of a gas</a> is 22.71 L.</p> <p>Thus,</p> <p><mathjax>#"Density" = "mass"/"volume" = "49 g"/"22.71 L" = "2.2 g/L"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/362873" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-stoichiometric-ratios-relate-to-molar-volume-of-a-gas"> How do stoichiometric ratios relate to molar volume of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-a-gas-at-stp"> How do you calculate molar volume of a gas at STP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-molar-volume-of-hydrogen-gas"> How do you find the molar volume of hydrogen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-oxygen-gas"> How do you calculate molar volume of oxygen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molar-gas-volume"> What is molar gas volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/534c7bf202bf3420a007f014"> What is the volume at 0 °C and 1 atm of a mixture that contains 4.0 g of methane and 2.0 g of helium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5361f75702bf3429040e0599"> What is the difference between STP and NTP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-volume-of-25-moles-of-oxygen-o2-gas"> What is the volume of .25 moles of oxygen (O2) Gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-would-knowing-the-molar-volume-of-a-gas-be-important"> Why would knowing the molar volume of a gas be important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-22-4-liters-called-the-molar-volume-of-a-gas"> Why is 22.4 liters called the molar volume of a gas? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp"> See all questions in Molar Volume of a Gas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 9030 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	The molar mass of a certain gas is 49 g. What is the density of the gas in g/L at STP?	null
2,276	aa6bc280-6ddd-11ea-8bdb-ccda262736ce	https://socratic.org/questions/a-mole-of-gas-at-o-c-and-760mmhg-occupies-22-41-l-what-is-the-volume-at-20-c-and	24 L	start physical_unit 3 3 volume l qc_end physical_unit 3 3 11 12 volume qc_end physical_unit 3 3 5 6 temperature qc_end physical_unit 3 3 8 9 pressure qc_end physical_unit 3 3 18 19 temperature qc_end physical_unit 3 3 8 9 pressure qc_end end	[{"type":"physical unit","value":"Volume2 [OF] the gas [IN] L"}]	[{"type":"physical unit","value":"24 L"}]	[{"type":"physical unit","value":"Mole [OF] the gas [=] \\pu{1 mole}"},{"type":"physical unit","value":"Volume1 [OF] the gas [=] \\pu{22.41 L}"},{"type":"physical unit","value":"Temperature1 [OF] the gas [=] \\pu{0 ℃}"},{"type":"physical unit","value":"Pressure1 [OF] the gas [=] \\pu{760 mmHg}"},{"type":"physical unit","value":"Temperature2 [OF] the gas [=] \\pu{20 ℃}"},{"type":"physical unit","value":"Pressure2 [OF] the gas [=] \\pu{760 mmHg}"}]	<h1 class="questionTitle" itemprop="name">A mole of gas at O°C and 760mmHg occupies 22.41 L. What is the volume at 20°C and 760mmHg?</h1>	null	24 L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>At constant pressure <mathjax>#VpropT#</mathjax> or <mathjax>#V=kT#</mathjax>.</p> <p>Thus (solving for <mathjax>#k#</mathjax>), <mathjax>#V_1/T_1=V_2/T_2#</mathjax>, and <mathjax>#V_2=V_1/T_1xxT_2#</mathjax>. Of course, <mathjax>#T#</mathjax> must be in terms of absolute temperature. </p> <p><mathjax>#V_2#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(22.41L)/(273.15K)xx293.15*K#</mathjax> <mathjax>#=??L#</mathjax></p> <p>Is the slight increase in volume consistent with a temperature increase?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We use <a href="https://en.wikipedia.org/wiki/Charles%27s_law" rel="nofollow">Charles' Law</a> to give <mathjax>#V~=24L#</mathjax> </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>At constant pressure <mathjax>#VpropT#</mathjax> or <mathjax>#V=kT#</mathjax>.</p> <p>Thus (solving for <mathjax>#k#</mathjax>), <mathjax>#V_1/T_1=V_2/T_2#</mathjax>, and <mathjax>#V_2=V_1/T_1xxT_2#</mathjax>. Of course, <mathjax>#T#</mathjax> must be in terms of absolute temperature. </p> <p><mathjax>#V_2#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(22.41L)/(273.15K)xx293.15K#</mathjax> <mathjax>#=??L#</mathjax></p> <p>Is the slight increase in volume consistent with a temperature increase?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A mole of gas at O°C and 760mmHg occupies 22.41 L. What is the volume at 20°C and 760mmHg?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/combined-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Combined Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="273792" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-04T15:13:12" itemprop="dateCreated"> Jun 4, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We use <a href="https://en.wikipedia.org/wiki/Charles%27s_law" rel="nofollow">Charles' Law</a> to give <mathjax>#V~=24L#</mathjax> </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>At constant pressure <mathjax>#VpropT#</mathjax> or <mathjax>#V=kT#</mathjax>.</p> <p>Thus (solving for <mathjax>#k#</mathjax>), <mathjax>#V_1/T_1=V_2/T_2#</mathjax>, and <mathjax>#V_2=V_1/T_1xxT_2#</mathjax>. Of course, <mathjax>#T#</mathjax> must be in terms of absolute temperature. </p> <p><mathjax>#V_2#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(22.41L)/(273.15K)xx293.15K#</mathjax> <mathjax>#=??L#</mathjax></p> <p>Is the slight increase in volume consistent with a temperature increase?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/273792" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5345df5f02bf345f71b1c8e8"> Question #1c8e8 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ac3df02bf342f4c3bfabb"> Question #bfabb </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-you-want-to-solve-for-the-volume-of-a-gas-v2-and-p1-is-greater-than-p2-would-"> If you want to solve for the volume of a gas (V2) and P1 is greater than P2, would you expect V2... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-modern-refrigerator-take-advantage-of-the-gas-laws-to-remove-heat-f"> How does the modern refrigerator take advantage of the gas laws to remove heat from a system? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-certain-sample-of-gas-has-a-volume-of-0-452-l-measured-at-87-c-and-0-620-atm-w"> A certain sample of gas has a volume of 0.452 L measured at 87°C and 0.620 atm. What is its... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/which-situations-does-the-combined-gas-law-enable-you-to-do-calculations-when-th"> Which situations does the combined gas law enable you to do calculations when the other gas laws... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-small-research-submarine-with-a-volume-of-1-2x10-5-l-has-an-internal-pressure-"> A small research submarine with a volume of 1.2x10 ^5 L has an internal pressure of 1.0 atm and... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-the-combined-gas-law-different-from-boyle-s-law"> How is the combined gas law different from boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-pressure-of-an-combined-gas-change-as-temperature-increases"> How does the pressure of an combined gas change as temperature increases? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-ideal-gas-law-differ-from-the-combined-gas-law-1"> How does the ideal gas law differ from the combined gas law? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/combined-gas-law"> See all questions in Combined Gas Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 4023 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A mole of gas at O°C and 760mmHg occupies 22.41 L. What is the volume at 20°C and 760mmHg?	null
2,277	aaefeeb0-6ddd-11ea-a272-ccda262736ce	https://socratic.org/questions/given-that-it-requires-31-0-ml-of-0-280-m-na-2s-2o-3-aq-to-titrate-a-10-0-ml-sam	0.43 M	start physical_unit 17 17 molarity mol/l qc_end physical_unit 28 28 4 5 volume qc_end physical_unit 9 9 7 8 molarity qc_end end	[{"type":"physical unit","value":"Molarity [OF] I3-(aq) solution [IN] M"}]	[{"type":"physical unit","value":"0.43 M"}]	[{"type":"physical unit","value":"Volume [OF] I3-(aq) solution sample [=] \\pu{10.0 mL}"},{"type":"physical unit","value":"Volume [OF] Na2S2O3(aq) solution [=] \\pu{31.0 mL}"},{"type":"physical unit","value":"Molarity [OF] Na2S2O3(aq) solution [=] \\pu{0.280 M}"}]	<h1 class="questionTitle" itemprop="name">Given that it requires 31.0 mL of 0.280 M #Na_2S_2O_3(aq)# to titrate a 10.0-mL sample of #I_3^- (aq)#, how would you calculate the molarity of #I_3^- (aq)# in the solution?</h1>	null	0.43 M	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>1. Write the balanced equation</strong></p> <p><mathjax>#"2S"_2"O"_3^"2-" + "I"_3^"-" → "S"_4"O"_6^"2-" + "3I"^"-"#</mathjax></p> <blockquote></blockquote> <p><strong>2. Calculate the moles of <mathjax>#"S"_2"O"_3^"2-"#</mathjax></strong></p> <p><mathjax>#"Moles of S"_2"O"_3^"2-" = 0.0310 color(red)(cancel(color(black)("L S"_2"O"_3^"2-"))) × ("0.280 mol S"_2"O"_3^"2-")/(1 color(red)(cancel(color(black)("L S"_2"O"_3^"2-")))) = "0.008 68 mol S"_2"O"_3^"2-"#</mathjax></p> <blockquote></blockquote> <p><strong>3. Calculate the moles of <mathjax>#"I"_3^"-"#</mathjax></strong></p> <p><mathjax>#"Moles of I"_3^"-" = "0.008 68" color(red)(cancel(color(black)("mol S"_2"O"_3^"2-"))) × ("1 mol I"_3^"-")/(2 color(red)(cancel(color(black)("mol S"_2"O"_3^"2-")))) = "0.004 34 mol I"_3^"-"#</mathjax></p> <blockquote></blockquote> <p><strong>4. Calculate the molarity of <mathjax>#"I"_3^"-"#</mathjax></strong></p> <p><mathjax>#"Molarity" = "moles"/"litres" = "0.004 34 mol"/"0.0100 L" = "0.434 mol/L"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of <mathjax>#"I"_3^"-"#</mathjax> is 0.434 mol/L.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>1. Write the balanced equation</strong></p> <p><mathjax>#"2S"_2"O"_3^"2-" + "I"_3^"-" → "S"_4"O"_6^"2-" + "3I"^"-"#</mathjax></p> <blockquote></blockquote> <p><strong>2. Calculate the moles of <mathjax>#"S"_2"O"_3^"2-"#</mathjax></strong></p> <p><mathjax>#"Moles of S"_2"O"_3^"2-" = 0.0310 color(red)(cancel(color(black)("L S"_2"O"_3^"2-"))) × ("0.280 mol S"_2"O"_3^"2-")/(1 color(red)(cancel(color(black)("L S"_2"O"_3^"2-")))) = "0.008 68 mol S"_2"O"_3^"2-"#</mathjax></p> <blockquote></blockquote> <p><strong>3. Calculate the moles of <mathjax>#"I"_3^"-"#</mathjax></strong></p> <p><mathjax>#"Moles of I"_3^"-" = "0.008 68" color(red)(cancel(color(black)("mol S"_2"O"_3^"2-"))) × ("1 mol I"_3^"-")/(2 color(red)(cancel(color(black)("mol S"_2"O"_3^"2-")))) = "0.004 34 mol I"_3^"-"#</mathjax></p> <blockquote></blockquote> <p><strong>4. Calculate the molarity of <mathjax>#"I"_3^"-"#</mathjax></strong></p> <p><mathjax>#"Molarity" = "moles"/"litres" = "0.004 34 mol"/"0.0100 L" = "0.434 mol/L"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Given that it requires 31.0 mL of 0.280 M #Na_2S_2O_3(aq)# to titrate a 10.0-mL sample of #I_3^- (aq)#, how would you calculate the molarity of #I_3^- (aq)# in the solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#reactions-in-solution" itemprop="url"> <span class="breadcrumb" itemprop="title">Reactions in Solution</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/reactions-in-solution/titration-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">Titration Calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="285553" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-07T02:57:22" itemprop="dateCreated"> Jul 7, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of <mathjax>#"I"_3^"-"#</mathjax> is 0.434 mol/L.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>1. Write the balanced equation</strong></p> <p><mathjax>#"2S"_2"O"_3^"2-" + "I"_3^"-" → "S"_4"O"_6^"2-" + "3I"^"-"#</mathjax></p> <blockquote></blockquote> <p><strong>2. Calculate the moles of <mathjax>#"S"_2"O"_3^"2-"#</mathjax></strong></p> <p><mathjax>#"Moles of S"_2"O"_3^"2-" = 0.0310 color(red)(cancel(color(black)("L S"_2"O"_3^"2-"))) × ("0.280 mol S"_2"O"_3^"2-")/(1 color(red)(cancel(color(black)("L S"_2"O"_3^"2-")))) = "0.008 68 mol S"_2"O"_3^"2-"#</mathjax></p> <blockquote></blockquote> <p><strong>3. Calculate the moles of <mathjax>#"I"_3^"-"#</mathjax></strong></p> <p><mathjax>#"Moles of I"_3^"-" = "0.008 68" color(red)(cancel(color(black)("mol S"_2"O"_3^"2-"))) × ("1 mol I"_3^"-")/(2 color(red)(cancel(color(black)("mol S"_2"O"_3^"2-")))) = "0.004 34 mol I"_3^"-"#</mathjax></p> <blockquote></blockquote> <p><strong>4. Calculate the molarity of <mathjax>#"I"_3^"-"#</mathjax></strong></p> <p><mathjax>#"Molarity" = "moles"/"litres" = "0.004 34 mol"/"0.0100 L" = "0.434 mol/L"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/285553" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-do-acid-base-titration-calculations"> How do you do acid base titration calculations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-use-titration-calculations-to-find-ph"> How do you use titration calculations to find pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/radox-titration"> What is a redox titration and what is it used for? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-titration-used-when-standardizing-a-solution"> Why is titration used when standardizing a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-titration-suitable-for-sodium-nitrate"> Is titration suitable for sodium nitrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-do-redox-titration-calculations"> How can I do redox titration calculations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-titration-of-weak-acid-and-strong-base"> How can I calculate the titration of a weak acid and a strong base? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-make-back-titration-calculations"> How can I make back titration calculations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-titration-affect-molarity"> How does titration affect molarity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-endpoint-of-a-titration-differ-from-the-equivalence-point"> How does the endpoint of a titration differ from the equivalence point? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/reactions-in-solution/titration-calculations"> See all questions in Titration Calculations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 12132 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Given that it requires 31.0 mL of 0.280 M #Na_2S_2O_3(aq)# to titrate a 10.0-mL sample of #I_3^- (aq)#, how would you calculate the molarity of #I_3^- (aq)# in the solution?	null
2,278	ad07ef0c-6ddd-11ea-81b2-ccda262736ce	https://socratic.org/questions/in-a-titration-experiment-12-5-ml-of-0-500-m-h-2so-4-neutralizes-50-0-ml-of-naoh	0.25 M	start physical_unit 21 22 concentration mol/l qc_end physical_unit 22 22 4 5 volume qc_end physical_unit 21 22 11 12 volume qc_end physical_unit 9 9 7 8 concentration qc_end end	[{"type":"physical unit","value":"Concentration [OF] NaOH solution [IN] M"}]	[{"type":"physical unit","value":"0.25 M"}]	[{"type":"physical unit","value":"Volume [OF] H2SO4 solution [=] \\pu{12.5 mL}"},{"type":"physical unit","value":"Volume [OF] NaOH solution [=] \\pu{50.0 mL}"},{"type":"physical unit","value":"Concentration [OF] H2SO4 solution [=] \\pu{0.500 M}"}]	<h1 class="questionTitle" itemprop="name">In a titration experiment, 12.5 mL of 0.500 M #H_2SO_4# neutralizes 50.0 mL of #NaOH#. What is the concentration of the #NaOH# solution? </h1>	null	0.25 M	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#0.500 (mol)/L H_2SO_4 * 0.0125 L = 0.00625 mol H_2SO_4#</mathjax></p> <p>Write a balanced equation for the reaction:</p> <p><mathjax>#H_2SO_4 + 2NaOH -> 2H_2O + Na_2SO_4 #</mathjax></p> <p>1 mol <mathjax>#H_2SO4#</mathjax> neutralizes 2 mol <mathjax>#NaOH#</mathjax>, so:</p> <p><mathjax>#0.00625*2 = 0.0125 mol NaOH#</mathjax></p> <p><mathjax>#0.0125 mol NaOH / 0.05 L= 0.25 M NaOH#</mathjax> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.25 M</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#0.500 (mol)/L H_2SO_4 * 0.0125 L = 0.00625 mol H_2SO_4#</mathjax></p> <p>Write a balanced equation for the reaction:</p> <p><mathjax>#H_2SO_4 + 2NaOH -> 2H_2O + Na_2SO_4 #</mathjax></p> <p>1 mol <mathjax>#H_2SO4#</mathjax> neutralizes 2 mol <mathjax>#NaOH#</mathjax>, so:</p> <p><mathjax>#0.00625*2 = 0.0125 mol NaOH#</mathjax></p> <p><mathjax>#0.0125 mol NaOH / 0.05 L= 0.25 M NaOH#</mathjax> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">In a titration experiment, 12.5 mL of 0.500 M #H_2SO_4# neutralizes 50.0 mL of #NaOH#. What is the concentration of the #NaOH# solution? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#reactions-in-solution" itemprop="url"> <span class="breadcrumb" itemprop="title">Reactions in Solution</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/reactions-in-solution/titration-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">Titration Calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="459975" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/tcw1"><img alt="" class="" src="https://profilepictures.socratic.org/Ox6b9VazRq1N5FiU8YFj_fractal-026.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/tcw1"> tcw1 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-04T03:14:34" itemprop="dateCreated"> Aug 4, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.25 M</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#0.500 (mol)/L H_2SO_4 * 0.0125 L = 0.00625 mol H_2SO_4#</mathjax></p> <p>Write a balanced equation for the reaction:</p> <p><mathjax>#H_2SO_4 + 2NaOH -> 2H_2O + Na_2SO_4 #</mathjax></p> <p>1 mol <mathjax>#H_2SO4#</mathjax> neutralizes 2 mol <mathjax>#NaOH#</mathjax>, so:</p> <p><mathjax>#0.00625*2 = 0.0125 mol NaOH#</mathjax></p> <p><mathjax>#0.0125 mol NaOH / 0.05 L= 0.25 M NaOH#</mathjax> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/459975" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-do-acid-base-titration-calculations"> How do you do acid base titration calculations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-use-titration-calculations-to-find-ph"> How do you use titration calculations to find pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/radox-titration"> What is a redox titration and what is it used for? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-titration-used-when-standardizing-a-solution"> Why is titration used when standardizing a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-titration-suitable-for-sodium-nitrate"> Is titration suitable for sodium nitrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-do-redox-titration-calculations"> How can I do redox titration calculations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-titration-of-weak-acid-and-strong-base"> How can I calculate the titration of a weak acid and a strong base? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-make-back-titration-calculations"> How can I make back titration calculations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-titration-affect-molarity"> How does titration affect molarity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-endpoint-of-a-titration-differ-from-the-equivalence-point"> How does the endpoint of a titration differ from the equivalence point? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/reactions-in-solution/titration-calculations"> See all questions in Titration Calculations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 21817 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	In a titration experiment, 12.5 mL of 0.500 M #H_2SO_4# neutralizes 50.0 mL of #NaOH#. What is the concentration of the #NaOH# solution?	null
2,279	ac7db4f6-6ddd-11ea-b41d-ccda262736ce	https://socratic.org/questions/what-would-be-the-final-temperature-if-you-mixed-a-liter-of-20-c-water-with-2-li	33.33 ℃	start physical_unit 14 14 temperature °c qc_end physical_unit 14 14 12 13 temperature qc_end physical_unit 14 14 16 17 volume qc_end physical_unit 14 14 19 20 temperature qc_end end	[{"type":"physical unit","value":"Temperature3 [OF] water [IN] ℃"}]	[{"type":"physical unit","value":"33.33 ℃"}]	[{"type":"physical unit","value":"Volume1 [OF] water [=] \\pu{1 liter}"},{"type":"physical unit","value":"Temperature1 [OF] water [=] \\pu{20 ℃}"},{"type":"physical unit","value":"Volume2 [OF] water [=] \\pu{2 liters}"},{"type":"physical unit","value":"Temperature2 [OF] water [=] \\pu{40 ℃}"}]	<h1 class="questionTitle" itemprop="name"> What would be the final temperature if you mixed a liter of 20°C water with 2 liters of 40°C water?</h1>	null	33.33 ℃	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Have a look:<br/> <img alt="enter image source here" src="https://useruploads.socratic.org/7WPVAlZETheiT4vRLlaA_termo.jpeg"/> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>I found <mathjax>#33^@C#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Have a look:<br/> <img alt="enter image source here" src="https://useruploads.socratic.org/7WPVAlZETheiT4vRLlaA_termo.jpeg"/> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name"> What would be the final temperature if you mixed a liter of 20°C water with 2 liters of 40°C water?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/calorimetry" itemprop="url"> <span class="breadcrumb" itemprop="title">Calorimetry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="382092" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/gio"><img alt="" class="" src="https://profilepictures.socratic.org/PDAQ7XlwRXWLdTy9hfbV_kuruma.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/gio"> Gió </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-02-24T00:28:29" itemprop="dateCreated"> Feb 24, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>I found <mathjax>#33^@C#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Have a look:<br/> <img alt="enter image source here" src="https://useruploads.socratic.org/7WPVAlZETheiT4vRLlaA_termo.jpeg"/> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/382092" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-differential-scanning-in-calorimetry-work"> How does differential scanning in calorimetry work? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-read-differential-scanning-in-calorimetry"> What information do you get from a differential scanning calorimetry plot? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-measure-calorimetry"> How do you measure calorimetry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531d304102bf341e75b962a7"> Question #962a7 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5335021802bf344ae911dfc5"> Question #1dfc5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/533668f502bf34572c341af6"> Question #41af6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-definition-of-calorimetry"> What is calorimetry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-differential-scanning-calorimeter"> What is a differential scanning calorimeter? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-a-calorimeter-measure-energy"> How can a calorimeter measure energy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-calorimeters-made-of"> What are calorimeters made of? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/calorimetry"> See all questions in Calorimetry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 9241 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What would be the final temperature if you mixed a liter of 20°C water with 2 liters of 40°C water?	null
2,280	a919c338-6ddd-11ea-8c60-ccda262736ce	https://socratic.org/questions/what-pressure-in-atmospheres-is-exerted-by-0-325-moles-of-hydrogen-gas-in-a-4-08	2.01 atmospheres	start physical_unit 10 11 pressure atm qc_end physical_unit 10 11 7 8 mole qc_end physical_unit 10 11 14 15 volume qc_end physical_unit 10 11 18 19 temperature qc_end end	[{"type":"physical unit","value":"Pressure [OF] hydrogen gas [IN] atmospheres"}]	[{"type":"physical unit","value":"2.01 atmospheres"}]	[{"type":"physical unit","value":"Mole [OF] hydrogen gas [=] \\pu{0.325 moles}"},{"type":"physical unit","value":"Volume [OF] hydrogen gas [=] \\pu{4.08 L}"},{"type":"physical unit","value":"Temperature [OF] hydrogen gas [=] \\pu{35 ℃}"}]	<h1 class="questionTitle" itemprop="name">What pressure, in atmospheres, is exerted by 0.325 moles of hydrogen gas in a 4.08 L container at 35°C?</h1>	null	2.01 atmospheres	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is a pretty straightforward example of how an <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a></strong> problem looks like. </p> <p>Your strategy here will be to use the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> to find the pressure of the gas, but not before making sure that the units given to you match those used by the universal gas constant. </p> <p>So, the ideal gas law equation looks like this </p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a)PV = nRTcolor(white)(a/a)\|)))" "#</mathjax></p> </blockquote> <p>Here you have</p> <blockquote> <p><mathjax>#P#</mathjax> - the pressure of the gas<br/> <mathjax>#V#</mathjax> - the volume it occupies<br/> <mathjax>#n#</mathjax> - the number of moles of gas<br/> <mathjax>#R#</mathjax> - the <em>universal gas constant</em>, usually given as <mathjax>#0.0821("atm" * "L")/("mol" * "K")#</mathjax><br/> <mathjax>#T#</mathjax> - the <strong>absolute temperature</strong> of the gas</p> </blockquote> <p>Take a look at the units given to you for the volume and temperature of the gas and compare them with the ones used in the expression of <mathjax>#R#</mathjax>. </p> <blockquote> <p><mathjax>#color(white)(aaaaaaaaaaacolor(Red)("Need")aaaaaaaaaaaaaaacolor(blue)("Have")aaaaa)#</mathjax><br/> <mathjax>#color(white)(aaaaa)color(white)(aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa)/color(white)(aaaaaaaaaaaa)#</mathjax><br/> <mathjax>#color(white)(aaaaaaacolor(black)("Liters, L")aaaaaaaaaaaaacolor(black)("Liters, L")aaaaaaaaaaacolor(green)(sqrt())#</mathjax><br/> <mathjax>#color(white)(aaaaaaacolor(black)("Kelvin, K")aaaaaaaaaaaacolor(black)("Celsius,"""^@"C")aaaaaaaaacolor(red)(xx)#</mathjax></p> </blockquote> <p>Notice that the temperature of the gas <strong>must</strong> be expressed in <em>Kelvin</em> in order to work, so make sure that you convert it before plugging it into the ideal gas law equation</p> <blockquote> <p><mathjax>#color(purple)(\|bar(ul(color(white)(a/a)color(black)(T["K"] = t[""^@"C"] + 273.15)color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>Rearrange the ideal gas law equation to solve for <mathjax>#P#</mathjax></p> <blockquote> <p><mathjax>#PV = nRT implies P = (nRT)/V#</mathjax></p> </blockquote> <p>Plug in your values to find</p> <blockquote> <p><mathjax>#P = (0.325 color(red)(cancel(color(black)("moles"))) * 0.0821("atm" * color(red)(cancel(color(black)("L"))))/(color(red)(cancel(color(black)("mol"))) * color(red)(cancel(color(black)("K")))) * (35 + 273.15)color(red)(cancel(color(black)("K"))))/(4.08color(red)(cancel(color(black)("L"))))#</mathjax></p> <p><mathjax>#P = color(green)(\|bar(ul(color(white)(a/a)color(black)("2.0 atm")color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer is rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the temperature of the gas. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"2.0 atm"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is a pretty straightforward example of how an <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a></strong> problem looks like. </p> <p>Your strategy here will be to use the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> to find the pressure of the gas, but not before making sure that the units given to you match those used by the universal gas constant. </p> <p>So, the ideal gas law equation looks like this </p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a)PV = nRTcolor(white)(a/a)\|)))" "#</mathjax></p> </blockquote> <p>Here you have</p> <blockquote> <p><mathjax>#P#</mathjax> - the pressure of the gas<br/> <mathjax>#V#</mathjax> - the volume it occupies<br/> <mathjax>#n#</mathjax> - the number of moles of gas<br/> <mathjax>#R#</mathjax> - the <em>universal gas constant</em>, usually given as <mathjax>#0.0821("atm" * "L")/("mol" * "K")#</mathjax><br/> <mathjax>#T#</mathjax> - the <strong>absolute temperature</strong> of the gas</p> </blockquote> <p>Take a look at the units given to you for the volume and temperature of the gas and compare them with the ones used in the expression of <mathjax>#R#</mathjax>. </p> <blockquote> <p><mathjax>#color(white)(aaaaaaaaaaacolor(Red)("Need")aaaaaaaaaaaaaaacolor(blue)("Have")aaaaa)#</mathjax><br/> <mathjax>#color(white)(aaaaa)color(white)(aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa)/color(white)(aaaaaaaaaaaa)#</mathjax><br/> <mathjax>#color(white)(aaaaaaacolor(black)("Liters, L")aaaaaaaaaaaaacolor(black)("Liters, L")aaaaaaaaaaacolor(green)(sqrt())#</mathjax><br/> <mathjax>#color(white)(aaaaaaacolor(black)("Kelvin, K")aaaaaaaaaaaacolor(black)("Celsius,"""^@"C")aaaaaaaaacolor(red)(xx)#</mathjax></p> </blockquote> <p>Notice that the temperature of the gas <strong>must</strong> be expressed in <em>Kelvin</em> in order to work, so make sure that you convert it before plugging it into the ideal gas law equation</p> <blockquote> <p><mathjax>#color(purple)(\|bar(ul(color(white)(a/a)color(black)(T["K"] = t[""^@"C"] + 273.15)color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>Rearrange the ideal gas law equation to solve for <mathjax>#P#</mathjax></p> <blockquote> <p><mathjax>#PV = nRT implies P = (nRT)/V#</mathjax></p> </blockquote> <p>Plug in your values to find</p> <blockquote> <p><mathjax>#P = (0.325 color(red)(cancel(color(black)("moles"))) * 0.0821("atm" * color(red)(cancel(color(black)("L"))))/(color(red)(cancel(color(black)("mol"))) * color(red)(cancel(color(black)("K")))) * (35 + 273.15)color(red)(cancel(color(black)("K"))))/(4.08color(red)(cancel(color(black)("L"))))#</mathjax></p> <p><mathjax>#P = color(green)(\|bar(ul(color(white)(a/a)color(black)("2.0 atm")color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer is rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the temperature of the gas. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What pressure, in atmospheres, is exerted by 0.325 moles of hydrogen gas in a 4.08 L container at 35°C?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/ideal-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Ideal Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="282006" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-27T23:29:21" itemprop="dateCreated"> Jun 27, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"2.0 atm"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is a pretty straightforward example of how an <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a></strong> problem looks like. </p> <p>Your strategy here will be to use the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> to find the pressure of the gas, but not before making sure that the units given to you match those used by the universal gas constant. </p> <p>So, the ideal gas law equation looks like this </p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a)PV = nRTcolor(white)(a/a)\|)))" "#</mathjax></p> </blockquote> <p>Here you have</p> <blockquote> <p><mathjax>#P#</mathjax> - the pressure of the gas<br/> <mathjax>#V#</mathjax> - the volume it occupies<br/> <mathjax>#n#</mathjax> - the number of moles of gas<br/> <mathjax>#R#</mathjax> - the <em>universal gas constant</em>, usually given as <mathjax>#0.0821("atm" * "L")/("mol" * "K")#</mathjax><br/> <mathjax>#T#</mathjax> - the <strong>absolute temperature</strong> of the gas</p> </blockquote> <p>Take a look at the units given to you for the volume and temperature of the gas and compare them with the ones used in the expression of <mathjax>#R#</mathjax>. </p> <blockquote> <p><mathjax>#color(white)(aaaaaaaaaaacolor(Red)("Need")aaaaaaaaaaaaaaacolor(blue)("Have")aaaaa)#</mathjax><br/> <mathjax>#color(white)(aaaaa)color(white)(aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa)/color(white)(aaaaaaaaaaaa)#</mathjax><br/> <mathjax>#color(white)(aaaaaaacolor(black)("Liters, L")aaaaaaaaaaaaacolor(black)("Liters, L")aaaaaaaaaaacolor(green)(sqrt())#</mathjax><br/> <mathjax>#color(white)(aaaaaaacolor(black)("Kelvin, K")aaaaaaaaaaaacolor(black)("Celsius,"""^@"C")aaaaaaaaacolor(red)(xx)#</mathjax></p> </blockquote> <p>Notice that the temperature of the gas <strong>must</strong> be expressed in <em>Kelvin</em> in order to work, so make sure that you convert it before plugging it into the ideal gas law equation</p> <blockquote> <p><mathjax>#color(purple)(\|bar(ul(color(white)(a/a)color(black)(T["K"] = t[""^@"C"] + 273.15)color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>Rearrange the ideal gas law equation to solve for <mathjax>#P#</mathjax></p> <blockquote> <p><mathjax>#PV = nRT implies P = (nRT)/V#</mathjax></p> </blockquote> <p>Plug in your values to find</p> <blockquote> <p><mathjax>#P = (0.325 color(red)(cancel(color(black)("moles"))) * 0.0821("atm" * color(red)(cancel(color(black)("L"))))/(color(red)(cancel(color(black)("mol"))) * color(red)(cancel(color(black)("K")))) * (35 + 273.15)color(red)(cancel(color(black)("K"))))/(4.08color(red)(cancel(color(black)("L"))))#</mathjax></p> <p><mathjax>#P = color(green)(\|bar(ul(color(white)(a/a)color(black)("2.0 atm")color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer is rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the temperature of the gas. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/282006" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-ideal-gas-constant"> How do you find the ideal gas constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-solve-ideal-gas-law-problems"> How do you solve ideal gas law problems? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-know-which-ideal-gas-constant-to-use"> How do you know which ideal gas constant to use? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ideal-gas-constant-for-butane"> What is the ideal gas constant for butane? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-ideal-gas-law-in-kelvin"> Why is ideal gas law in kelvin? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ideal-gas-constant-important"> Why is the ideal gas constant important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-di-electric-constant"> What is the di-electric constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-volume-l-will-0-20-mol-hi-occupy-at-300-k-and-100-0-kpa-r-8-314-kpa-l-k-mol"> What volume (L) will 0.20 mol HI occupy at 300 K and 100.0 kPa? R = 8.314 kPa L / (K mol) =... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-molar-mass-of-a-gas"> How do you calculate the molar mass of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-should-i-use-the-ideal-gas-law-and-not-the-combined-gas-law"> When should I use the ideal gas law and not the combined gas law? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/ideal-gas-law"> See all questions in Ideal Gas Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 20473 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What pressure, in atmospheres, is exerted by 0.325 moles of hydrogen gas in a 4.08 L container at 35°C?	null
2,281	a9b19c4a-6ddd-11ea-a089-ccda262736ce	https://socratic.org/questions/59777f29b72cff04ca6a2158	100.19 moles	start physical_unit 4 5 mole mol qc_end physical_unit 4 5 12 13 mass qc_end end	[{"type":"physical unit","value":"Mole [OF] iron oxide [IN] moles"}]	[{"type":"physical unit","value":"100.19 moles"}]	[{"type":"physical unit","value":"Mass [OF] iron oxide [=] \\pu{16 kg}"}]	<h1 class="questionTitle" itemprop="name">How many moles of iron oxide are present in a mass of #16*kg#?</h1>	null	100.19 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>But iron has a particularly rich oxidation chemistry. We don't know whether all the <mathjax>#16kg#</mathjax> mass was ferric oxide, or ferrous oxide, or <mathjax>#Fe_3O_4#</mathjax> or hydrous iron oxides.....Clearly you can work out the molar quantity if all the rust is present as <mathjax>#Fe_2O_3#</mathjax>....</p> <p><mathjax>#"Moles of ferric oxide"=(16xx10^3g)/(159.69gmol^-1)=??mol.#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well the molar mass of ferric oxide, <mathjax>#Fe_2O_3#</mathjax>, is <mathjax>#159.69gmol^-1#</mathjax>....</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>But iron has a particularly rich oxidation chemistry. We don't know whether all the <mathjax>#16kg#</mathjax> mass was ferric oxide, or ferrous oxide, or <mathjax>#Fe_3O_4#</mathjax> or hydrous iron oxides.....Clearly you can work out the molar quantity if all the rust is present as <mathjax>#Fe_2O_3#</mathjax>....</p> <p><mathjax>#"Moles of ferric oxide"=(16xx10^3g)/(159.69gmol^-1)=??mol.#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles of iron oxide are present in a mass of #16kg#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/percent-composition" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Composition</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="456206" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-07-25T18:21:32" itemprop="dateCreated"> Jul 25, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well the molar mass of ferric oxide, <mathjax>#Fe_2O_3#</mathjax>, is <mathjax>#159.69gmol^-1#</mathjax>....</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>But iron has a particularly rich oxidation chemistry. We don't know whether all the <mathjax>#16kg#</mathjax> mass was ferric oxide, or ferrous oxide, or <mathjax>#Fe_3O_4#</mathjax> or hydrous iron oxides.....Clearly you can work out the molar quantity if all the rust is present as <mathjax>#Fe_2O_3#</mathjax>....</p> <p><mathjax>#"Moles of ferric oxide"=(16xx10^3g)/(159.69g*mol^-1)=??mol.#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/456206" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-mole-percent"> What is mole percent? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4188602bf3469570e2e8b"> Question #e2e8b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4188702bf34695a6bc737"> Question #bc737 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418be02bf34695a6bc73b"> Question #bc73b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418c202bf3469570e2e8f"> Question #e2e8f </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418c802bf346963eb9857"> Question #b9857 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418ca02bf346963eb985b"> Question #b985b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418cc02bf34694a4fee41"> Question #fee41 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418d502bf34694c8c5c01"> Question #c5c01 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4196e02bf34695a6bc73f"> Question #bc73f </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/percent-composition"> See all questions in Percent Composition </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1512 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many moles of iron oxide are present in a mass of #16*kg#?	null
2,282	ac45f69d-6ddd-11ea-a21b-ccda262736ce	https://socratic.org/questions/the-molar-mass-of-aluminum-is-of-is-19-00g-mol-how-do-you-calculate-the-molar-ma	83.98 g/mol	start physical_unit 23 24 molar_mass g/mol qc_end physical_unit 4 4 6 7 molar_mass qc_end physical_unit 11 11 13 14 molar_mass qc_end end	[{"type":"physical unit","value":"Molar mass [OF] aluminium fluoride [IN] g/mol"}]	[{"type":"physical unit","value":"83.98 g/mol"}]	[{"type":"physical unit","value":"Molar mass [OF] fluorine [=] \\pu{19.00 g/mol}"},{"type":"physical unit","value":"Molar mass [OF] aluminium [=] \\pu{26.98 g/mol}"}]	<h1 class="questionTitle" itemprop="name">The molar mass of fluorine is 19.00 g/mol and that of aluminium is 26.98 g/mol. How do you calculate the molar mass of aluminium fluoride?</h1>	null	83.98 g/mol	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The formula of aluminium fluoride is <mathjax>#"AlF"_3#</mathjax>. </p> <p>This tells us that one formula unit of <mathjax>#"AlF"_3#</mathjax> contains one atom of <mathjax>#"Al"#</mathjax> and three atoms of <mathjax>#"F"#</mathjax>. </p> <p>It also tells us that one mole of contains one mole of <mathjax>#"Al"#</mathjax> atoms and three moles of <mathjax>#"F"#</mathjax> atoms.</p> <blockquote></blockquote> <p>Thus, we can calculate the molar mass of <mathjax>#"AlF"_3#</mathjax> as follows: </p> <p><mathjax>#"Mass of 1 mol" = 1 color(red)(cancel(color(black)("mol Al"))) × "26.98 g"/(1 color(red)(cancel(color(black)("mol Al")))) + 3 color(red)(cancel(color(black)("mol F"))) × "19.00 g"/(1 color(red)(cancel(color(black)("mol F")))) = "26.98 g + 57.00 g" = "83.98 g"#</mathjax> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The molar mass of aluminium fluoride is 83.98 g/mol.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The formula of aluminium fluoride is <mathjax>#"AlF"_3#</mathjax>. </p> <p>This tells us that one formula unit of <mathjax>#"AlF"_3#</mathjax> contains one atom of <mathjax>#"Al"#</mathjax> and three atoms of <mathjax>#"F"#</mathjax>. </p> <p>It also tells us that one mole of contains one mole of <mathjax>#"Al"#</mathjax> atoms and three moles of <mathjax>#"F"#</mathjax> atoms.</p> <blockquote></blockquote> <p>Thus, we can calculate the molar mass of <mathjax>#"AlF"_3#</mathjax> as follows: </p> <p><mathjax>#"Mass of 1 mol" = 1 color(red)(cancel(color(black)("mol Al"))) × "26.98 g"/(1 color(red)(cancel(color(black)("mol Al")))) + 3 color(red)(cancel(color(black)("mol F"))) × "19.00 g"/(1 color(red)(cancel(color(black)("mol F")))) = "26.98 g + 57.00 g" = "83.98 g"#</mathjax> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">The molar mass of fluorine is 19.00 g/mol and that of aluminium is 26.98 g/mol. How do you calculate the molar mass of aluminium fluoride?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="390696" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-13T17:49:12" itemprop="dateCreated"> Mar 13, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The molar mass of aluminium fluoride is 83.98 g/mol.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The formula of aluminium fluoride is <mathjax>#"AlF"_3#</mathjax>. </p> <p>This tells us that one formula unit of <mathjax>#"AlF"_3#</mathjax> contains one atom of <mathjax>#"Al"#</mathjax> and three atoms of <mathjax>#"F"#</mathjax>. </p> <p>It also tells us that one mole of contains one mole of <mathjax>#"Al"#</mathjax> atoms and three moles of <mathjax>#"F"#</mathjax> atoms.</p> <blockquote></blockquote> <p>Thus, we can calculate the molar mass of <mathjax>#"AlF"_3#</mathjax> as follows: </p> <p><mathjax>#"Mass of 1 mol" = 1 color(red)(cancel(color(black)("mol Al"))) × "26.98 g"/(1 color(red)(cancel(color(black)("mol Al")))) + 3 color(red)(cancel(color(black)("mol F"))) × "19.00 g"/(1 color(red)(cancel(color(black)("mol F")))) = "26.98 g + 57.00 g" = "83.98 g"#</mathjax> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/390696" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 11476 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	The molar mass of fluorine is 19.00 g/mol and that of aluminium is 26.98 g/mol. How do you calculate the molar mass of aluminium fluoride?	null
2,283	acf53a06-6ddd-11ea-ac71-ccda262736ce	https://socratic.org/questions/577ea10e11ef6b171c76467d	5.00 × 10^(-3) mol/L	start physical_unit 5 5 concentration mol/l qc_end physical_unit 13 14 8 9 volume qc_end physical_unit 13 14 11 12 concentration qc_end physical_unit 21 22 8 9 volume qc_end physical_unit 21 22 11 12 concentration qc_end physical_unit 5 5 27 29 equilibrium_constant_k qc_end end	[{"type":"physical unit","value":"Concentration [OF] AlF6^3- [IN] mol/L"}]	[{"type":"physical unit","value":"5.00 × 10^(-3) mol/L"}]	[{"type":"physical unit","value":"Volume [OF] aluminium ion [=] \\pu{25 cm^3}"},{"type":"physical unit","value":"Concentration [OF] aluminium ion [=] \\pu{0.1 mol/L}"},{"type":"physical unit","value":"Volume [OF] fluoride ion [=] \\pu{25 cm^3}"},{"type":"physical unit","value":"Concentration [OF] fluoride ion [=] \\pu{1 mol/L}"},{"type":"physical unit","value":"Keq [OF] AlF6^3- [=] \\pu{1.0 × 10^25}"}]	<h1 class="questionTitle" itemprop="name">What is the concentration of #"AlF"_6^"3-"# after mixing #"25 cm"^3# of 0.1 mol/L aluminium ion with #"25 cm"^3# of 1 mol/L fluoride ion?</h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>For <mathjax>#"AlF"_6^"3-", K_text(eq) = 1.0 × 10^25#</mathjax></p></div> </h2> </div> </div>	5.00 × 10^(-3) mol/L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The equilibrium is</p> <p><mathjax>#"Al"^"3+" + "6F"^"-" ⇌ "AlF"_6^(3-)#</mathjax> </p> <p><mathjax>#K_"eq" = 1.0 × 10^25#</mathjax>.</p> <p>That means that the reaction will essentially go to completion.</p> <p>This becomes a <strong>limiting reactant</strong> problem.</p> <blockquote></blockquote> <p><mathjax>#"Moles of Al"^(3+) = 0.025 color(red)(cancel(color(black)("dm"^3 "Al"^(3+)))) × ("0.010 mol Al"^(3+))/(1 color(red)(cancel(color(black)("dm"^3 "Al"^(3+))))) = "0.000 25 mol Al"^"3+"#</mathjax></p> <p><mathjax>#"Moles of AlF"_6^"3-" color(white)(l)"from Al"^(3+) = "0.000 25" color(red)(cancel(color(black)("mol Al"^(3+)))) × ("1 mol AlF"_6^"3-")/(1 color(red)(cancel(color(black)("mol Al"^(3+))))) = "0.000 25 mol AlF"_6^"3-"#</mathjax></p> <blockquote></blockquote> <p><mathjax>#"Moles of F"^"-" = 0.025 color(red)(cancel(color(black)("dm"^3 "F"^"-"))) × ("0.10 mol F"^"-")/(1 color(red)(cancel(color(black)("dm"^3 "F"^"-")))) = "0.0025 mol F"^"-"#</mathjax></p> <p><mathjax>#"Moles of AlF"_6^"3-" color(white)(l)"from F"^"-" = 0.0025 color(red)(cancel(color(black)("mol F"^"-"))) × ("1 mol AlF"_6^"3-")/(6 color(red)(cancel(color(black)("mol F"^"-")))) = "0.000 433 mol AlF"_6^(3-)#</mathjax></p> <blockquote></blockquote> <p><mathjax>#"Al"^(3+)#</mathjax> gives the fewest moles of <mathjax>#"AlF"_6^"3-"#</mathjax>, so <mathjax>#"Al"^(3+)#</mathjax> is the limiting reactant.</p> <blockquote></blockquote> <p>Thus, when the reaction is complete, we have <mathjax>#"0.000 25 mol AlF"_6^"3-"#</mathjax> in <mathjax>#"50 cm"^3#</mathjax> of solution.</p> <blockquote></blockquote> <p>∴ <mathjax>#["AlF"_6^"3-"] ="0.000 25 mol"/("0.050 dm"^3) = "0.0050 mol/dm"^3#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>I get <mathjax>#["AlF"_6^"3-"] ="0.0050 mol/dm"^3#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The equilibrium is</p> <p><mathjax>#"Al"^"3+" + "6F"^"-" ⇌ "AlF"_6^(3-)#</mathjax> </p> <p><mathjax>#K_"eq" = 1.0 × 10^25#</mathjax>.</p> <p>That means that the reaction will essentially go to completion.</p> <p>This becomes a <strong>limiting reactant</strong> problem.</p> <blockquote></blockquote> <p><mathjax>#"Moles of Al"^(3+) = 0.025 color(red)(cancel(color(black)("dm"^3 "Al"^(3+)))) × ("0.010 mol Al"^(3+))/(1 color(red)(cancel(color(black)("dm"^3 "Al"^(3+))))) = "0.000 25 mol Al"^"3+"#</mathjax></p> <p><mathjax>#"Moles of AlF"_6^"3-" color(white)(l)"from Al"^(3+) = "0.000 25" color(red)(cancel(color(black)("mol Al"^(3+)))) × ("1 mol AlF"_6^"3-")/(1 color(red)(cancel(color(black)("mol Al"^(3+))))) = "0.000 25 mol AlF"_6^"3-"#</mathjax></p> <blockquote></blockquote> <p><mathjax>#"Moles of F"^"-" = 0.025 color(red)(cancel(color(black)("dm"^3 "F"^"-"))) × ("0.10 mol F"^"-")/(1 color(red)(cancel(color(black)("dm"^3 "F"^"-")))) = "0.0025 mol F"^"-"#</mathjax></p> <p><mathjax>#"Moles of AlF"_6^"3-" color(white)(l)"from F"^"-" = 0.0025 color(red)(cancel(color(black)("mol F"^"-"))) × ("1 mol AlF"_6^"3-")/(6 color(red)(cancel(color(black)("mol F"^"-")))) = "0.000 433 mol AlF"_6^(3-)#</mathjax></p> <blockquote></blockquote> <p><mathjax>#"Al"^(3+)#</mathjax> gives the fewest moles of <mathjax>#"AlF"_6^"3-"#</mathjax>, so <mathjax>#"Al"^(3+)#</mathjax> is the limiting reactant.</p> <blockquote></blockquote> <p>Thus, when the reaction is complete, we have <mathjax>#"0.000 25 mol AlF"_6^"3-"#</mathjax> in <mathjax>#"50 cm"^3#</mathjax> of solution.</p> <blockquote></blockquote> <p>∴ <mathjax>#["AlF"_6^"3-"] ="0.000 25 mol"/("0.050 dm"^3) = "0.0050 mol/dm"^3#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the concentration of #"AlF"_6^"3-"# after mixing #"25 cm"^3# of 0.1 mol/L aluminium ion with #"25 cm"^3# of 1 mol/L fluoride ion?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>For <mathjax>#"AlF"_6^"3-", K_text(eq) = 1.0 × 10^25#</mathjax></p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-equilibrium" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Equilibrium</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-equilibrium/equilibrium-constants" itemprop="url"> <span class="breadcrumb" itemprop="title">Equilibrium Constants</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="285919" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-08T02:27:07" itemprop="dateCreated"> Jul 8, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>I get <mathjax>#["AlF"_6^"3-"] ="0.0050 mol/dm"^3#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The equilibrium is</p> <p><mathjax>#"Al"^"3+" + "6F"^"-" ⇌ "AlF"_6^(3-)#</mathjax> </p> <p><mathjax>#K_"eq" = 1.0 × 10^25#</mathjax>.</p> <p>That means that the reaction will essentially go to completion.</p> <p>This becomes a <strong>limiting reactant</strong> problem.</p> <blockquote></blockquote> <p><mathjax>#"Moles of Al"^(3+) = 0.025 color(red)(cancel(color(black)("dm"^3 "Al"^(3+)))) × ("0.010 mol Al"^(3+))/(1 color(red)(cancel(color(black)("dm"^3 "Al"^(3+))))) = "0.000 25 mol Al"^"3+"#</mathjax></p> <p><mathjax>#"Moles of AlF"_6^"3-" color(white)(l)"from Al"^(3+) = "0.000 25" color(red)(cancel(color(black)("mol Al"^(3+)))) × ("1 mol AlF"_6^"3-")/(1 color(red)(cancel(color(black)("mol Al"^(3+))))) = "0.000 25 mol AlF"_6^"3-"#</mathjax></p> <blockquote></blockquote> <p><mathjax>#"Moles of F"^"-" = 0.025 color(red)(cancel(color(black)("dm"^3 "F"^"-"))) × ("0.10 mol F"^"-")/(1 color(red)(cancel(color(black)("dm"^3 "F"^"-")))) = "0.0025 mol F"^"-"#</mathjax></p> <p><mathjax>#"Moles of AlF"_6^"3-" color(white)(l)"from F"^"-" = 0.0025 color(red)(cancel(color(black)("mol F"^"-"))) × ("1 mol AlF"_6^"3-")/(6 color(red)(cancel(color(black)("mol F"^"-")))) = "0.000 433 mol AlF"_6^(3-)#</mathjax></p> <blockquote></blockquote> <p><mathjax>#"Al"^(3+)#</mathjax> gives the fewest moles of <mathjax>#"AlF"_6^"3-"#</mathjax>, so <mathjax>#"Al"^(3+)#</mathjax> is the limiting reactant.</p> <blockquote></blockquote> <p>Thus, when the reaction is complete, we have <mathjax>#"0.000 25 mol AlF"_6^"3-"#</mathjax> in <mathjax>#"50 cm"^3#</mathjax> of solution.</p> <blockquote></blockquote> <p>∴ <mathjax>#["AlF"_6^"3-"] ="0.000 25 mol"/("0.050 dm"^3) = "0.0050 mol/dm"^3#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/285919" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-equilibrium-constant-change-with-temperature"> How does the equilibrium constant change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-equilibrium-constant-for-a-reverse-reaction"> How do you find equilibrium constant for a reversable reaction? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/532a4f1602bf347ef7da90d2"> Question #a90d2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-equilibrium-constant-for-the-reaction-of-nh3-with-water"> What is the equilibrium constant for the reaction of NH3 with water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-equation-for-finding-the-equilibrium-constant-for-a-chemical-reactio"> What is the equation for finding the equilibrium constant for a chemical reaction? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-equilibrium-constant-for-the-weak-acid-khp"> What is the equilibrium constant for the weak acid KHP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/consider-this-equilibrium-i2-s-h2o-l-h-aq-i-aq-hoi-aq-what-is-the-keq-expression"> Consider this equilibrium: I2(s) + H2O(l) ⇌ H+(aq) + I-(aq) + HOI(aq). What is the Keq... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-equilibrium-constant-for-water"> What is the equilibrium constant for water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-equilibrium-constant-of-citric-acid"> What is the equilibrium constant of citric acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-rate-of-production-of-reactants-compared-with-the-rate-of-production"> What is the rate of production of reactants compared with the rate of production of products at... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-equilibrium/equilibrium-constants"> See all questions in Equilibrium Constants </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1304 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the concentration of #"AlF"_6^"3-"# after mixing #"25 cm"^3# of 0.1 mol/L aluminium ion with #"25 cm"^3# of 1 mol/L fluoride ion?	For #"AlF"_6^"3-", K_text(eq) = 1.0 × 10^25#
2,284	ab123f10-6ddd-11ea-8f26-ccda262736ce	https://socratic.org/questions/how-do-you-write-a-reaction-to-represent-carbon-monoxide-reacts-with-chlorine-ga	CO(g) + Cl2(g) -> COCl2(g)	start chemical_equation qc_end substance 8 9 qc_end substance 12 13 qc_end chemical_equation 17 17 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the equation"}]	[{"type":"chemical equation","value":"CO(g) + Cl2(g) -> COCl2(g)"}]	[{"type":"substance name","value":"Carbon monoxide"},{"type":"substance name","value":"Chlorine gas"},{"type":"chemical equation","value":"COCl2"}]	<h1 class="questionTitle" itemprop="name">How do you write an equation to represent "Carbon monoxide reacts with chlorine gas to form phosgene #(COCl_2)#"?</h1>	null	CO(g) + Cl2(g) -> COCl2(g)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>For a discussion of its industrial formation see (<a href="https://en.wikipedia.org/wiki/Phosgene" rel="nofollow" target="_blank">https://en.wikipedia.org/wiki/Phosgene</a>). Phosgene was actually used as a war gas in the first world war. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#CO(g) + Cl_2(g) rarr COCl_2(g)#</mathjax></p> <p>Do I win £5-00?</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>For a discussion of its industrial formation see (<a href="https://en.wikipedia.org/wiki/Phosgene" rel="nofollow" target="_blank">https://en.wikipedia.org/wiki/Phosgene</a>). Phosgene was actually used as a war gas in the first world war. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you write an equation to represent "Carbon monoxide reacts with chlorine gas to form phosgene #(COCl_2)#"?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="201245" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-19T14:50:10" itemprop="dateCreated"> Dec 19, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#CO(g) + Cl_2(g) rarr COCl_2(g)#</mathjax></p> <p>Do I win £5-00?</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>For a discussion of its industrial formation see (<a href="https://en.wikipedia.org/wiki/Phosgene" rel="nofollow" target="_blank">https://en.wikipedia.org/wiki/Phosgene</a>). Phosgene was actually used as a war gas in the first world war. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/201245" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-equation-for-photosynthesis"> What is the chemical equation for photosynthesis? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-know-the-relative-number-of-grams-of-each-substance-used-or-produced-w"> How can I know the relative number of grams of each substance used or produced with chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-know-the-relative-number-of-moles-of-each-substance-with-chemical-equa"> How can I know the relative number of moles of each substance with chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-chemical-equations-illustrate-that-atoms-are-conserved-1"> How do chemical equations illustrate that atoms are conserved? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-know-the-formula-of-the-reactants-and-products-with-chemical-equations"> How can I know the formula of the reactants and products with chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-potassium-metal-and-chlorine-gas-combi"> How can I balance this chemical equations? Potassium metal and chlorine gas combine to form... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-types-of-chemical-reactions-exist"> How many types of chemical reactions exist? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-a-chemical-equation-be-made-more-informative"> How can a chemical equation be made more informative? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-equation-albr3-k2so4-kbr-al2-so4-3"> How can I balance this equation? ___ AlBr3 + ____ K2SO4 ---> ____ KBr + ____ Al2(SO4)3 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-equation-pb-oh-2-hcl-h2o-pbcl2"> How can I balance this equation? ____ Pb(OH)2 + ____ HCl ---> ____ H2O + ____ PbCl2 </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/chemical-equations"> See all questions in Chemical Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 5769 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How do you write an equation to represent "Carbon monoxide reacts with chlorine gas to form phosgene #(COCl_2)#"?	null
2,285	aceaadb8-6ddd-11ea-a9c4-ccda262736ce	https://socratic.org/questions/what-mass-in-grams-of-iron-iii-oxide-contains-71-6-g-ofiron-iron-iii-oxide-is-69	102.37 grams	start physical_unit 5 6 mass g qc_end physical_unit 5 5 8 9 mass qc_end end	[{"type":"physical unit","value":"Mass [OF] iron(III) oxide [IN] grams"}]	[{"type":"physical unit","value":"102.37 grams"}]	[{"type":"physical unit","value":"Mass [OF] iron [=] \\pu{71.6 g}"},{"type":"physical unit","value":"Percent by mass [OF] iron in iron(III) oxide [=] \\pu{69.94%}"}]	<h1 class="questionTitle" itemprop="name">What mass in grams of iron(III) oxide contains 71.6 g ofiron? Iron(III) oxide is 69.94% iron by mass.</h1>	null	102.37 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>A substance's <strong><a href="https://socratic.org/chemistry/the-mole-concept/percent-composition">percent composition</a></strong> essentially tells you how many grams of each constituent element you get <strong>per</strong> <mathjax>#"100 g"#</mathjax> <strong>of said substance</strong>. </p> <p>In this case, a percent composition of <mathjax>#69.94%#</mathjax> means that <strong>for every</strong> <mathjax>#"100 g"#</mathjax> of iron(III) oxide, <mathjax>#"Fe"_2"O"_3#</mathjax>, you get <mathjax>#"69.94 g"#</mathjax> of iron.</p> <p>You can thus use this known composition as a <strong>conversion factor</strong> to take you from mass of iron(III) oxide to mass of iron or vice versa. </p> <p>Therefore, in order to have <mathjax>#"71.6 g"#</mathjax> of iron, you need to have</p> <blockquote> <p><mathjax>#71.6 color(red)(cancel(color(black)("g Fe"))) * overbrace(("100 g Fe"_2"O"_3)/(69.94color(red)(cancel(color(black)("g Fe")))))^(color(blue)("known percent composition")) = color(green)(bar(ul(\|color(white)(a/a)color(black)("102 g Fe"_2"O"_3)color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the mass of iron.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"102 g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>A substance's <strong><a href="https://socratic.org/chemistry/the-mole-concept/percent-composition">percent composition</a></strong> essentially tells you how many grams of each constituent element you get <strong>per</strong> <mathjax>#"100 g"#</mathjax> <strong>of said substance</strong>. </p> <p>In this case, a percent composition of <mathjax>#69.94%#</mathjax> means that <strong>for every</strong> <mathjax>#"100 g"#</mathjax> of iron(III) oxide, <mathjax>#"Fe"_2"O"_3#</mathjax>, you get <mathjax>#"69.94 g"#</mathjax> of iron.</p> <p>You can thus use this known composition as a <strong>conversion factor</strong> to take you from mass of iron(III) oxide to mass of iron or vice versa. </p> <p>Therefore, in order to have <mathjax>#"71.6 g"#</mathjax> of iron, you need to have</p> <blockquote> <p><mathjax>#71.6 color(red)(cancel(color(black)("g Fe"))) * overbrace(("100 g Fe"_2"O"_3)/(69.94color(red)(cancel(color(black)("g Fe")))))^(color(blue)("known percent composition")) = color(green)(bar(ul(\|color(white)(a/a)color(black)("102 g Fe"_2"O"_3)color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the mass of iron.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What mass in grams of iron(III) oxide contains 71.6 g ofiron? Iron(III) oxide is 69.94% iron by mass.</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/percent-composition" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Composition</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="322246" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-10-16T03:12:37" itemprop="dateCreated"> Oct 16, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"102 g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>A substance's <strong><a href="https://socratic.org/chemistry/the-mole-concept/percent-composition">percent composition</a></strong> essentially tells you how many grams of each constituent element you get <strong>per</strong> <mathjax>#"100 g"#</mathjax> <strong>of said substance</strong>. </p> <p>In this case, a percent composition of <mathjax>#69.94%#</mathjax> means that <strong>for every</strong> <mathjax>#"100 g"#</mathjax> of iron(III) oxide, <mathjax>#"Fe"_2"O"_3#</mathjax>, you get <mathjax>#"69.94 g"#</mathjax> of iron.</p> <p>You can thus use this known composition as a <strong>conversion factor</strong> to take you from mass of iron(III) oxide to mass of iron or vice versa. </p> <p>Therefore, in order to have <mathjax>#"71.6 g"#</mathjax> of iron, you need to have</p> <blockquote> <p><mathjax>#71.6 color(red)(cancel(color(black)("g Fe"))) * overbrace(("100 g Fe"_2"O"_3)/(69.94color(red)(cancel(color(black)("g Fe")))))^(color(blue)("known percent composition")) = color(green)(bar(ul(\|color(white)(a/a)color(black)("102 g Fe"_2"O"_3)color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the mass of iron.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/322246" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-mole-percent"> What is mole percent? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4188602bf3469570e2e8b"> Question #e2e8b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4188702bf34695a6bc737"> Question #bc737 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418be02bf34695a6bc73b"> Question #bc73b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418c202bf3469570e2e8f"> Question #e2e8f </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418c802bf346963eb9857"> Question #b9857 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418ca02bf346963eb985b"> Question #b985b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418cc02bf34694a4fee41"> Question #fee41 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418d502bf34694c8c5c01"> Question #c5c01 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4196e02bf34695a6bc73f"> Question #bc73f </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/percent-composition"> See all questions in Percent Composition </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 12950 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What mass in grams of iron(III) oxide contains 71.6 g ofiron? Iron(III) oxide is 69.94% iron by mass.	null
2,286	aad44eb6-6ddd-11ea-a7cc-ccda262736ce	https://socratic.org/questions/58a25d937c01497023d7e0df	0.92 moles	start physical_unit 7 9 mole mol qc_end physical_unit 7 9 4 6 number qc_end end	[{"type":"physical unit","value":"Mole [OF] individual magnesium atoms [IN] moles"}]	[{"type":"physical unit","value":"0.92 moles"}]	[{"type":"physical unit","value":"Number [OF] individual magnesium atoms [=] \\pu{5.541 × 10^23}"}]	<h1 class="questionTitle" itemprop="name">How many moles do #5.541*"individual magnesium atoms"# constitute?</h1>	null	0.92 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And thus our molar quantity is given by the quotient.........</p> <p><mathjax>#(5.451xx10^23"Mg atoms")/(6.022xx10^23"Mg atoms"*mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"not quite a mole........."#</mathjax></p> <p>Can you tell us the mass of this quantity of magnesium atoms? How?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, <mathjax>#"one mole of magnesium metals"#</mathjax> contains <mathjax>#6.022xx10^23#</mathjax> individual magnesium atoms.........</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And thus our molar quantity is given by the quotient.........</p> <p><mathjax>#(5.451xx10^23"Mg atoms")/(6.022xx10^23"Mg atoms"*mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"not quite a mole........."#</mathjax></p> <p>Can you tell us the mass of this quantity of magnesium atoms? How?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles do #5.541"individual magnesium atoms"# constitute?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="457012" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-07-27T19:29:46" itemprop="dateCreated"> Jul 27, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, <mathjax>#"one mole of magnesium metals"#</mathjax> contains <mathjax>#6.022xx10^23#</mathjax> individual magnesium atoms.........</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And thus our molar quantity is given by the quotient.........</p> <p><mathjax>#(5.451xx10^23"Mg atoms")/(6.022xx10^23"Mg atoms"mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"not quite a mole........."#</mathjax></p> <p>Can you tell us the mass of this quantity of magnesium atoms? How?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/457012" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 844 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many moles do #5.541*"individual magnesium atoms"# constitute?	null
2,287	a92d2786-6ddd-11ea-ac7d-ccda262736ce	https://socratic.org/questions/what-volume-of-1-0-m-cuso-4-would-you-need-to-make-750-l-of-a-20-m-solution	0.15 L	start physical_unit 17 17 volume l qc_end physical_unit 5 5 3 4 molarity qc_end physical_unit 5 5 15 16 molarity qc_end physical_unit 17 17 11 12 volume qc_end end	[{"type":"physical unit","value":"Volume2 [OF] CuSO4 solution [IN] L"}]	[{"type":"physical unit","value":"0.15 L"}]	[{"type":"physical unit","value":"Molarity2 [OF] CuSO4 solution [=] \\pu{1.0 M}"},{"type":"physical unit","value":"Molarity1 [OF] CuSO4 solution [=] \\pu{0.20 M}"},{"type":"physical unit","value":"Volume1 [OF] CuSO4 solution [=] \\pu{0.750 L}"}]	<h1 class="questionTitle" itemprop="name">What volume of 1.0 M #CuSO_4# would you need to make .750 L of a .20 M solution?</h1>	null	0.15 L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Concentration"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Moles of solute"/"Volume of solution"#</mathjax>.</p> <p>And thus <mathjax>#"Moles of solute "(n)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Concentration "(molL^-1)xx"volume "(L)#</mathjax></p> <p>In the required volume there are <mathjax>#0.750Lxx0.20molL^-1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.150mol#</mathjax>.</p> <p>Thus, in the starting volume, we need <mathjax>#0.150L#</mathjax>, which contains <mathjax>#0.150mol#</mathjax>. This volume is then diluted to <mathjax>#0.750L#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#0.150L#</mathjax> are required.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Concentration"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Moles of solute"/"Volume of solution"#</mathjax>.</p> <p>And thus <mathjax>#"Moles of solute "(n)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Concentration "(molL^-1)xx"volume "(L)#</mathjax></p> <p>In the required volume there are <mathjax>#0.750Lxx0.20molL^-1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.150mol#</mathjax>.</p> <p>Thus, in the starting volume, we need <mathjax>#0.150L#</mathjax>, which contains <mathjax>#0.150mol#</mathjax>. This volume is then diluted to <mathjax>#0.750*L#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What volume of 1.0 M #CuSO_4# would you need to make .750 L of a .20 M solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="265220" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-13T05:29:23" itemprop="dateCreated"> May 13, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#0.150L#</mathjax> are required.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Concentration"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Moles of solute"/"Volume of solution"#</mathjax>.</p> <p>And thus <mathjax>#"Moles of solute "(n)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Concentration "(molL^-1)xx"volume "(L)#</mathjax></p> <p>In the required volume there are <mathjax>#0.750Lxx0.20molL^-1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.150mol#</mathjax>.</p> <p>Thus, in the starting volume, we need <mathjax>#0.150L#</mathjax>, which contains <mathjax>#0.150mol#</mathjax>. This volume is then diluted to <mathjax>#0.750*L#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/265220" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-morality-be-used-as-a-conversion-factor"> How can molarity be used as a conversion factor? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-high-can-molarity-be"> How high can molarity be? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-molarity-change-with-temperature"> How does molarity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molarity-of-a-solution"> How do you find molarity of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-10-naoh"> What is the molarity of 10 NaOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-3-hydrogen-peroxide"> What is the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1123 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What volume of 1.0 M #CuSO_4# would you need to make .750 L of a .20 M solution?	null
2,288	aa203c18-6ddd-11ea-abf7-ccda262736ce	https://socratic.org/questions/what-is-the-oxidation-number-of-sulfur-in-an-hso4-ion	+6	start physical_unit 6 6 oxidation_number none qc_end chemical_equation 9 9 qc_end end	[{"type":"physical unit","value":"Oxidation number [OF] sulfur"}]	[{"type":"physical unit","value":"+6"}]	[{"type":"chemical equation","value":"HSO4- "}]	<h1 class="questionTitle" itemprop="name">What is the oxidation number of sulfur in an HSO4- ion? </h1>	null	+6	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Some knowledge in <a href="http://socratic.org/chemistry/electrochemistry/oxidation-numbers">oxidation numbers</a> and algebra is in order.</p> <p>For H atom, the most common oxidation state is +1.<br/> For O atom, the most common oxidation state is -2.</p> <p>Substituting <mathjax>#HSO_4^-#</mathjax> with its oxidation state values we have:</p> <p><mathjax>#(+1) + x + [(-2) * (4)] = -1#</mathjax>, where <mathjax>#x#</mathjax> = unknown</p> <p><mathjax>#(+1) + x + (-8) = -1#</mathjax></p> <p><mathjax>#x + (-7) = -1#</mathjax></p> <p><mathjax>#x = -1 + (+7)#</mathjax></p> <p><mathjax>#x = +6#</mathjax></p> <p>Therefore, the correct answer is <mathjax>#S^"+6"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#S^"+6"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Some knowledge in <a href="http://socratic.org/chemistry/electrochemistry/oxidation-numbers">oxidation numbers</a> and algebra is in order.</p> <p>For H atom, the most common oxidation state is +1.<br/> For O atom, the most common oxidation state is -2.</p> <p>Substituting <mathjax>#HSO_4^-#</mathjax> with its oxidation state values we have:</p> <p><mathjax>#(+1) + x + [(-2) * (4)] = -1#</mathjax>, where <mathjax>#x#</mathjax> = unknown</p> <p><mathjax>#(+1) + x + (-8) = -1#</mathjax></p> <p><mathjax>#x + (-7) = -1#</mathjax></p> <p><mathjax>#x = -1 + (+7)#</mathjax></p> <p><mathjax>#x = +6#</mathjax></p> <p>Therefore, the correct answer is <mathjax>#S^"+6"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the oxidation number of sulfur in an HSO4- ion? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#electrochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Electrochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/electrochemistry/oxidation-numbers" itemprop="url"> <span class="breadcrumb" itemprop="title">Oxidation Numbers</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="180073" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/nikka-c"><img alt="" class="" src="https://profilepictures.socratic.org/AQ8VOCyTM1J7U0TvIWhw_nkahara.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/nikka-c"> Nikka C. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-10-26T11:02:11" itemprop="dateCreated"> Oct 26, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#S^"+6"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Some knowledge in <a href="http://socratic.org/chemistry/electrochemistry/oxidation-numbers">oxidation numbers</a> and algebra is in order.</p> <p>For H atom, the most common oxidation state is +1.<br/> For O atom, the most common oxidation state is -2.</p> <p>Substituting <mathjax>#HSO_4^-#</mathjax> with its oxidation state values we have:</p> <p><mathjax>#(+1) + x + [(-2) * (4)] = -1#</mathjax>, where <mathjax>#x#</mathjax> = unknown</p> <p><mathjax>#(+1) + x + (-8) = -1#</mathjax></p> <p><mathjax>#x + (-7) = -1#</mathjax></p> <p><mathjax>#x = -1 + (+7)#</mathjax></p> <p><mathjax>#x = +6#</mathjax></p> <p>Therefore, the correct answer is <mathjax>#S^"+6"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/180073" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-relate-to-electron-configuration"> How do oxidation numbers relate to electron configuration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-relate-to-valence-electrons"> How do oxidation numbers relate to valence electrons? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-vary-with-the-periodic-table"> How do oxidation numbers vary with the periodic table? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-oxidation-number-of-an-element-in-a-compound"> How do you calculate the oxidation number of an element in a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-sulfur"> What is the oxidation number for sulfur? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-carbon"> What is the oxidation number for carbon? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-copper"> What is the oxidation number for copper? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-nitrogen"> What is the oxidation number for nitrogen? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-oxygen"> What is the oxidation number for oxygen? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-oxidation-state-of-noble-gas-zero"> Why is the oxidation state of noble gas zero? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/electrochemistry/oxidation-numbers"> See all questions in Oxidation Numbers </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 49550 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the oxidation number of sulfur in an HSO4- ion?	null
2,289	a8e90041-6ddd-11ea-ba15-ccda262736ce	https://socratic.org/questions/what-is-the-number-of-grams-in-7-19-moles-of-baso-4	1676 grams	start physical_unit 10 10 mass g qc_end physical_unit 10 10 7 8 mole qc_end end	[{"type":"physical unit","value":"Mass [OF] BaSO4 [IN] grams"}]	[{"type":"physical unit","value":"1676 grams"}]	[{"type":"physical unit","value":"Mole [OF] BaSO4 [=] \\pu{7.19 moles}"}]	<h1 class="questionTitle" itemprop="name">What is the number of grams in 7.19 moles of #BaSO_4#?</h1>	null	1676 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Assume:<br/> n = number of moles<br/> m = mass of substance<br/> M = molar mass</p> <p>7.19 moles has been provided for you</p> <p>Your next step is to find the molar mass (M) of <mathjax>#BaSO_4#</mathjax>. <br/> Unsure what is molar mass? Molar mass is equivalent to the atomic weight on <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a>.</p> <p>Your first step in finding molar mass is to find out what <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> are present in <mathjax>#BaSO_4#</mathjax>. As you can see: Barium, Sulfur and Oxygen are present.</p> <p>If you refer to your periodic table, the molar mass of Barium is 137 g/mol, Sulfur 32.1 g/mol, and Oxygen 16.0 g/mol.</p> <p>Since there are 4 oxygens present, you need to times the molar mass of oxygen (O) by 4.</p> <p>Therefore the molar mass of <mathjax>#BaSO_4#</mathjax> is <br/> [<mathjax>#1 xx 137 + 1 xx 32.1 + 4 xx 16.0#</mathjax>] = 233.1 g/mol</p> <p>You've now found the molar mass.</p> <p>Since you found the number of moles and molar mass, your final step is to find the mass of <mathjax>#BaSO_4#</mathjax>. </p> <p>The mass of <mathjax>#BaSO_4#</mathjax> is:<br/> <mathjax>#m = M xx n#</mathjax><br/> [233.1 g/mol <mathjax>#xx#</mathjax> 7.19 moles] = 1676 grams. This final answer is rounded to nearest whole number. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>7.19 moles <mathjax>#xx#</mathjax> molar mass of <mathjax>#BaSO_4#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Assume:<br/> n = number of moles<br/> m = mass of substance<br/> M = molar mass</p> <p>7.19 moles has been provided for you</p> <p>Your next step is to find the molar mass (M) of <mathjax>#BaSO_4#</mathjax>. <br/> Unsure what is molar mass? Molar mass is equivalent to the atomic weight on <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a>.</p> <p>Your first step in finding molar mass is to find out what <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> are present in <mathjax>#BaSO_4#</mathjax>. As you can see: Barium, Sulfur and Oxygen are present.</p> <p>If you refer to your periodic table, the molar mass of Barium is 137 g/mol, Sulfur 32.1 g/mol, and Oxygen 16.0 g/mol.</p> <p>Since there are 4 oxygens present, you need to times the molar mass of oxygen (O) by 4.</p> <p>Therefore the molar mass of <mathjax>#BaSO_4#</mathjax> is <br/> [<mathjax>#1 xx 137 + 1 xx 32.1 + 4 xx 16.0#</mathjax>] = 233.1 g/mol</p> <p>You've now found the molar mass.</p> <p>Since you found the number of moles and molar mass, your final step is to find the mass of <mathjax>#BaSO_4#</mathjax>. </p> <p>The mass of <mathjax>#BaSO_4#</mathjax> is:<br/> <mathjax>#m = M xx n#</mathjax><br/> [233.1 g/mol <mathjax>#xx#</mathjax> 7.19 moles] = 1676 grams. This final answer is rounded to nearest whole number. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the number of grams in 7.19 moles of #BaSO_4#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="258459" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/edmund-l"><img alt="" class="" src="https://profilepictures.socratic.org/DnAPD8TISDW0aROTp4qA_Day_3_Story_1._Photo_with_Sky_Tower_from_distance_Walked_around_most_of_west_Auckland_suburbs._Some_of_you_mightve_seen_.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/edmund-l"> Edmund Liew </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-04-25T09:54:52" itemprop="dateCreated"> Apr 25, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>7.19 moles <mathjax>#xx#</mathjax> molar mass of <mathjax>#BaSO_4#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Assume:<br/> n = number of moles<br/> m = mass of substance<br/> M = molar mass</p> <p>7.19 moles has been provided for you</p> <p>Your next step is to find the molar mass (M) of <mathjax>#BaSO_4#</mathjax>. <br/> Unsure what is molar mass? Molar mass is equivalent to the atomic weight on <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a>.</p> <p>Your first step in finding molar mass is to find out what <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> are present in <mathjax>#BaSO_4#</mathjax>. As you can see: Barium, Sulfur and Oxygen are present.</p> <p>If you refer to your periodic table, the molar mass of Barium is 137 g/mol, Sulfur 32.1 g/mol, and Oxygen 16.0 g/mol.</p> <p>Since there are 4 oxygens present, you need to times the molar mass of oxygen (O) by 4.</p> <p>Therefore the molar mass of <mathjax>#BaSO_4#</mathjax> is <br/> [<mathjax>#1 xx 137 + 1 xx 32.1 + 4 xx 16.0#</mathjax>] = 233.1 g/mol</p> <p>You've now found the molar mass.</p> <p>Since you found the number of moles and molar mass, your final step is to find the mass of <mathjax>#BaSO_4#</mathjax>. </p> <p>The mass of <mathjax>#BaSO_4#</mathjax> is:<br/> <mathjax>#m = M xx n#</mathjax><br/> [233.1 g/mol <mathjax>#xx#</mathjax> 7.19 moles] = 1676 grams. This final answer is rounded to nearest whole number. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/258459" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1454 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the number of grams in 7.19 moles of #BaSO_4#?	null
2,290	a8ed32a4-6ddd-11ea-bb38-ccda262736ce	https://socratic.org/questions/a-student-combusts-95-70g-of-butane-c-4h-10-in-the-presence-of-94-40g-of-oxygen-	2C4H10(g) + 13 O2(g) -> 8 CO2(g) + 10 H2O(g)	start chemical_equation qc_end physical_unit 7 7 3 4 mass qc_end physical_unit 15 15 12 13 mass qc_end end	[{"type":"other","value":"Chemical Equation [OF] the reaction"}]	[{"type":"chemical equation","value":"2C4H10(g) + 13 O2(g) -> 8 CO2(g) + 10 H2O(g)"}]	[{"type":"physical unit","value":"Mass [OF] C4H10 [=] \\pu{95.70 g}"},{"type":"physical unit","value":"Mass [OF] oxygen [=] \\pu{94.40 g}"}]	<h1 class="questionTitle" itemprop="name"> A student combusts 95.70g of butane (#C_4H_10#) in the presence of 94.40g of oxygen. How do you write and balance the equation for the reaction?</h1>	null	2C4H10(g) + 13 O2(g) -> 8 CO2(g) + 10 H2O(g)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Moles of butane"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(95.7g)/(58.12gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax> <mathjax>#"mol"#</mathjax>.</p> <p><mathjax>#"Moles of oxygen"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(94.4g)/(32.00gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax> <mathjax>#"mol"#</mathjax>.</p> <p>It is pretty clear that there is insufficient oxygen for complete combustion to occur. Butane would combust incompletely in these circumstances to give elemental carbon (as soot) and carbon monoxide gas. We have no handle on the amounts of each. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>For complete combustion:</p> <p><mathjax>#C_4H_10(g) + 13/2O_2(g) rarr 4CO_2(g) + 5H_2O(g)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Moles of butane"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(95.7g)/(58.12gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax> <mathjax>#"mol"#</mathjax>.</p> <p><mathjax>#"Moles of oxygen"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(94.4g)/(32.00gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax> <mathjax>#"mol"#</mathjax>.</p> <p>It is pretty clear that there is insufficient oxygen for complete combustion to occur. Butane would combust incompletely in these circumstances to give elemental carbon (as soot) and carbon monoxide gas. We have no handle on the amounts of each. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name"> A student combusts 95.70g of butane (#C_4H_10#) in the presence of 94.40g of oxygen. How do you write and balance the equation for the reaction?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="230388" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-02-24T09:15:11" itemprop="dateCreated"> Feb 24, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>For complete combustion:</p> <p><mathjax>#C_4H_10(g) + 13/2O_2(g) rarr 4CO_2(g) + 5H_2O(g)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Moles of butane"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(95.7g)/(58.12gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax> <mathjax>#"mol"#</mathjax>.</p> <p><mathjax>#"Moles of oxygen"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(94.4g)/(32.00gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax> <mathjax>#"mol"#</mathjax>.</p> <p>It is pretty clear that there is insufficient oxygen for complete combustion to occur. Butane would combust incompletely in these circumstances to give elemental carbon (as soot) and carbon monoxide gas. We have no handle on the amounts of each. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/230388" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------> H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -> Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? Aluminum and hydrochloric acid react to form aluminum... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equation-sodium-phosphate-and-calcium-chloride-r"> How can I balance this chemical equation? Sodium phosphate and calcium chloride react to form... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-equation-kclo3-kcl-o2"> How can I balance this equation? ____ #KClO_3 -># ____ #KCl +# ____ #O_2# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-balancing-chemical-equations-important"> Why is balancing chemical equations important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/balancing-chemical-equations"> See all questions in Balancing Chemical Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1053 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A student combusts 95.70g of butane (#C_4H_10#) in the presence of 94.40g of oxygen. How do you write and balance the equation for the reaction?	null
2,291	a8a6fa2f-6ddd-11ea-b815-ccda262736ce	https://socratic.org/questions/5654b2f1581e2a08f8ea67e2	CuCO3 + 2 HCl -> CuCl2 + CO2 + H2O	start chemical_equation qc_end substance 8 9 qc_end substance 11 13 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the reaction"}]	[{"type":"chemical equation","value":"CuCO3 + 2 HCl -> CuCl2 + CO2 + H2O"}]	[{"type":"substance name","value":"Copper carbonate"},{"type":"substance name","value":"Concentrated hydrochloric acid"}]	<h1 class="questionTitle" itemprop="name">What would we see in the reaction between copper carbonate and concentrated hydrochloric acid?</h1>	null	CuCO3 + 2 HCl -> CuCl2 + CO2 + H2O	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>There should be no copper carbonate in hydrochloric acid; the carbonate ion is chemically decomposed. Of course, there will be residual metal and non-metal ions. <mathjax>#[Cu(OH_2)_6]^(2+)#</mathjax> has a beautiful blue colour; <mathjax>#[CuCl_4]^(2-)#</mathjax> is yellow green, and this will be the likely colour in conc. hydrochloric acid. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#CuCO_3(s) + 2HCl(aq) rarr CuCl_2(aq) + CO_2(g)uarr + H_2O(aq)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>There should be no copper carbonate in hydrochloric acid; the carbonate ion is chemically decomposed. Of course, there will be residual metal and non-metal ions. <mathjax>#[Cu(OH_2)_6]^(2+)#</mathjax> has a beautiful blue colour; <mathjax>#[CuCl_4]^(2-)#</mathjax> is yellow green, and this will be the likely colour in conc. hydrochloric acid. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What would we see in the reaction between copper carbonate and concentrated hydrochloric acid?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-reactions-and-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions and Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="208841" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-06T08:07:35" itemprop="dateCreated"> Jan 6, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#CuCO_3(s) + 2HCl(aq) rarr CuCl_2(aq) + CO_2(g)uarr + H_2O(aq)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>There should be no copper carbonate in hydrochloric acid; the carbonate ion is chemically decomposed. Of course, there will be residual metal and non-metal ions. <mathjax>#[Cu(OH_2)_6]^(2+)#</mathjax> has a beautiful blue colour; <mathjax>#[CuCl_4]^(2-)#</mathjax> is yellow green, and this will be the likely colour in conc. hydrochloric acid. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/208841" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb002bf34694a4fee47"> Question #fee47 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb402bf34694c8c5c15"> Question #c5c15 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb802bf346950519eb9"> Question #19eb9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cbf02bf3469570e2ea2"> Question #e2ea2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc002bf34695a6bc751"> Question #bc751 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc202bf3469570e2ea6"> Question #e2ea6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531e867a02bf342492a08b07"> Question #08b07 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-thermochemical-equation-for-the-combustion-of-benzene"> What is the thermochemical equation for the combustion of benzene? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-reversible"> Why are chemical reactions reversible? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-important"> Why are chemical reactions important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/chemical-reactions-and-equations"> See all questions in Chemical Reactions and Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3904 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What would we see in the reaction between copper carbonate and concentrated hydrochloric acid?	null
2,292	a9c18508-6ddd-11ea-8ac0-ccda262736ce	https://socratic.org/questions/what-is-the-density-of-krypton-gas-at-stp	3.74 × 10^(-3) g/cm^3	start physical_unit 5 6 density g/cm^3 qc_end c_other STP qc_end end	[{"type":"physical unit","value":"Density [OF] krypton gas [IN] g/cm^3"}]	[{"type":"physical unit","value":"3.74 × 10^(-3) g/cm^3"}]	[{"type":"other","value":"STP"}]	<h1 class="questionTitle" itemprop="name">What is the density of krypton gas at STP?</h1>	null	3.74 × 10^(-3) g/cm^3	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>How to Calculate Density of Krypton from Molar Mass and Molar Volume.</strong></p> <p>Molar mass <mathjax>#("MM")#</mathjax> is the atomic weight of an element on the periodic table in g/mol.</p> <p><mathjax>#"MM"_"Kr"="83.798 g/mol"#</mathjax><br/> <a href="http://www.nist.gov/pml/data/periodic.cfm" rel="nofollow" target="_blank">http://www.nist.gov/pml/data/periodic.cfm</a></p> <p>Molar Volume <mathjax>#(V_"m")#</mathjax> at STP is <mathjax>#"22.414 L/mol"#</mathjax><br/> <a href="https://en.wikipedia.org/wiki/Molar_volume" rel="nofollow" target="_blank">https://en.wikipedia.org/wiki/Molar_volume</a></p> <p><mathjax>#"Density"=("MM")/(V_"m")#</mathjax></p> <p><mathjax>#"Density"_"Kr"=(83.798 "g"/cancel"mol")/(22.414"L"/cancel"mol")="3.7386 g/L"#</mathjax></p> <p><mathjax>#(3.7386"g")/(1"L")xx(1"L")/(1000"mL")="0.0037386 g/mL"="0.0037386 g/cm"^3"#</mathjax> <mathjax>#("1mL=1cm"^3")#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The density of krypton at STP is <mathjax>#"3.74 kg/m"^3"#</mathjax>, or <mathjax>#"0.00374 g/cm"^3"#</mathjax> at STP of <mathjax>#0^"o""C"#</mathjax> <mathjax>#("273.15 K")#</mathjax> and <mathjax>#"1 atm"#</mathjax>.<br/> <a href="http://www.engineeringtoolbox.com/gas-density-d_158.html" rel="nofollow" target="_blank">http://www.engineeringtoolbox.com/gas-density-d_158.html</a><br/> The calculated density is <mathjax>#"0.0037386 g/cm"^3"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>How to Calculate Density of Krypton from Molar Mass and Molar Volume.</strong></p> <p>Molar mass <mathjax>#("MM")#</mathjax> is the atomic weight of an element on the periodic table in g/mol.</p> <p><mathjax>#"MM"_"Kr"="83.798 g/mol"#</mathjax><br/> <a href="http://www.nist.gov/pml/data/periodic.cfm" rel="nofollow" target="_blank">http://www.nist.gov/pml/data/periodic.cfm</a></p> <p>Molar Volume <mathjax>#(V_"m")#</mathjax> at STP is <mathjax>#"22.414 L/mol"#</mathjax><br/> <a href="https://en.wikipedia.org/wiki/Molar_volume" rel="nofollow" target="_blank">https://en.wikipedia.org/wiki/Molar_volume</a></p> <p><mathjax>#"Density"=("MM")/(V_"m")#</mathjax></p> <p><mathjax>#"Density"_"Kr"=(83.798 "g"/cancel"mol")/(22.414"L"/cancel"mol")="3.7386 g/L"#</mathjax></p> <p><mathjax>#(3.7386"g")/(1"L")xx(1"L")/(1000"mL")="0.0037386 g/mL"="0.0037386 g/cm"^3"#</mathjax> <mathjax>#("1mL=1cm"^3")#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the density of krypton gas at STP?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/ideal-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Ideal Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="196008" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-03T22:19:25" itemprop="dateCreated"> Dec 3, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The density of krypton at STP is <mathjax>#"3.74 kg/m"^3"#</mathjax>, or <mathjax>#"0.00374 g/cm"^3"#</mathjax> at STP of <mathjax>#0^"o""C"#</mathjax> <mathjax>#("273.15 K")#</mathjax> and <mathjax>#"1 atm"#</mathjax>.<br/> <a href="http://www.engineeringtoolbox.com/gas-density-d_158.html" rel="nofollow" target="_blank">http://www.engineeringtoolbox.com/gas-density-d_158.html</a><br/> The calculated density is <mathjax>#"0.0037386 g/cm"^3"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>How to Calculate Density of Krypton from Molar Mass and Molar Volume.</strong></p> <p>Molar mass <mathjax>#("MM")#</mathjax> is the atomic weight of an element on the periodic table in g/mol.</p> <p><mathjax>#"MM"_"Kr"="83.798 g/mol"#</mathjax><br/> <a href="http://www.nist.gov/pml/data/periodic.cfm" rel="nofollow" target="_blank">http://www.nist.gov/pml/data/periodic.cfm</a></p> <p>Molar Volume <mathjax>#(V_"m")#</mathjax> at STP is <mathjax>#"22.414 L/mol"#</mathjax><br/> <a href="https://en.wikipedia.org/wiki/Molar_volume" rel="nofollow" target="_blank">https://en.wikipedia.org/wiki/Molar_volume</a></p> <p><mathjax>#"Density"=("MM")/(V_"m")#</mathjax></p> <p><mathjax>#"Density"_"Kr"=(83.798 "g"/cancel"mol")/(22.414"L"/cancel"mol")="3.7386 g/L"#</mathjax></p> <p><mathjax>#(3.7386"g")/(1"L")xx(1"L")/(1000"mL")="0.0037386 g/mL"="0.0037386 g/cm"^3"#</mathjax> <mathjax>#("1mL=1cm"^3")#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/196008" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-ideal-gas-constant"> How do you find the ideal gas constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-solve-ideal-gas-law-problems"> How do you solve ideal gas law problems? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-know-which-ideal-gas-constant-to-use"> How do you know which ideal gas constant to use? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ideal-gas-constant-for-butane"> What is the ideal gas constant for butane? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-ideal-gas-law-in-kelvin"> Why is ideal gas law in kelvin? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ideal-gas-constant-important"> Why is the ideal gas constant important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-di-electric-constant"> What is the di-electric constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-volume-l-will-0-20-mol-hi-occupy-at-300-k-and-100-0-kpa-r-8-314-kpa-l-k-mol"> What volume (L) will 0.20 mol HI occupy at 300 K and 100.0 kPa? R = 8.314 kPa L / (K mol) =... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-molar-mass-of-a-gas"> How do you calculate the molar mass of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-should-i-use-the-ideal-gas-law-and-not-the-combined-gas-law"> When should I use the ideal gas law and not the combined gas law? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/ideal-gas-law"> See all questions in Ideal Gas Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 31819 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the density of krypton gas at STP?	null
2,293	ac617164-6ddd-11ea-a573-ccda262736ce	https://socratic.org/questions/how-much-1-7m-solution-of-nh-4-2so-4-do-you-have-to-use-so-that-it-contains-0-23	1.10 mL	start physical_unit 4 4 volume ml qc_end physical_unit 6 6 2 3 molarity qc_end physical_unit 19 20 16 17 mass qc_end end	[{"type":"physical unit","value":"Volume [OF] (NH4)2SO4 solution [IN] mL"}]	[{"type":"physical unit","value":"1.10 mL"}]	[{"type":"physical unit","value":"Molarity [OF] (NH4)2SO4 solution [=] \\pu{1.7 M}"},{"type":"physical unit","value":"Mass [OF] the substance [=] \\pu{0.230 g}"}]	<h1 class="questionTitle" itemprop="name">How much 1.7M solution of #(NH_4)_2SO_4# do you have to use so that it contains 0.230 g of the substance? </h1>	null	1.10 mL	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The mass of <mathjax>#1#</mathjax> mole of <mathjax>#(NH_4)_2SO_4#</mathjax> is: </p> <p><mathjax>#N xx 2 + Hxx4xx2 + S + Oxx4#</mathjax><br/> <mathjax>#= 14.01 xx 2 + 1.008xx4xx2 + 32.07 + 16.00xx4#</mathjax><br/> <mathjax>#= "132.14 g/mol"#</mathjax></p> <p>So, the number of moles of <mathjax>#(NH_4)_2SO_4#</mathjax> in <mathjax>#"0.230 g"#</mathjax> would be: </p> <p><mathjax>#"moles" = "mass"/"molar mass" = "0.230 g"/"132.14 g/mol" = "0.00187 mol"#</mathjax></p> <p>The question also tells us that the <mathjax>#(NH_4)_2SO_4#</mathjax> solution is <mathjax>#"1.7 M"#</mathjax>. This means that there are <mathjax>#1.7"#</mathjax> moles per liter.</p> <p><mathjax>#"1.7 moles"/"1 L"#</mathjax></p> <p>We can use this ratio to find the volume of solution which would have <mathjax>#"0.00187 mol"#</mathjax> of <mathjax>#(NH_4)_2SO_4#</mathjax>:</p> <p><mathjax>#"1.7 moles"/"1 L" = "1.7 × (0.00187/1.7) moles"/"1.0 × (0.00187/1.7) L"#</mathjax></p> <p><mathjax>#= "0.00187 moles"/"0.0011 L"#</mathjax></p> <p>We'd need <mathjax>#"0.0011 L"#</mathjax> of the <mathjax>#(NH_4)_2SO_4#</mathjax> solution to get <mathjax>#"0.230 g"#</mathjax> of <mathjax>#(NH_4)_2SO_4#</mathjax>. :)</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"0.0011 L"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The mass of <mathjax>#1#</mathjax> mole of <mathjax>#(NH_4)_2SO_4#</mathjax> is: </p> <p><mathjax>#N xx 2 + Hxx4xx2 + S + Oxx4#</mathjax><br/> <mathjax>#= 14.01 xx 2 + 1.008xx4xx2 + 32.07 + 16.00xx4#</mathjax><br/> <mathjax>#= "132.14 g/mol"#</mathjax></p> <p>So, the number of moles of <mathjax>#(NH_4)_2SO_4#</mathjax> in <mathjax>#"0.230 g"#</mathjax> would be: </p> <p><mathjax>#"moles" = "mass"/"molar mass" = "0.230 g"/"132.14 g/mol" = "0.00187 mol"#</mathjax></p> <p>The question also tells us that the <mathjax>#(NH_4)_2SO_4#</mathjax> solution is <mathjax>#"1.7 M"#</mathjax>. This means that there are <mathjax>#1.7"#</mathjax> moles per liter.</p> <p><mathjax>#"1.7 moles"/"1 L"#</mathjax></p> <p>We can use this ratio to find the volume of solution which would have <mathjax>#"0.00187 mol"#</mathjax> of <mathjax>#(NH_4)_2SO_4#</mathjax>:</p> <p><mathjax>#"1.7 moles"/"1 L" = "1.7 × (0.00187/1.7) moles"/"1.0 × (0.00187/1.7) L"#</mathjax></p> <p><mathjax>#= "0.00187 moles"/"0.0011 L"#</mathjax></p> <p>We'd need <mathjax>#"0.0011 L"#</mathjax> of the <mathjax>#(NH_4)_2SO_4#</mathjax> solution to get <mathjax>#"0.230 g"#</mathjax> of <mathjax>#(NH_4)_2SO_4#</mathjax>. :)</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How much 1.7M solution of #(NH_4)_2SO_4# do you have to use so that it contains 0.230 g of the substance? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/solution-formation---what-happens-when-stuff-dissolves" itemprop="url"> <span class="breadcrumb" itemprop="title">Solution Formation</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="613823" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/z-15"><img alt="" class="" src="https://profilepictures.socratic.org/2RYTfnQ27oIM5G69ZmQg_chrome.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/z-15"> zhirou </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-05-15T10:24:04" itemprop="dateCreated"> May 15, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"0.0011 L"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The mass of <mathjax>#1#</mathjax> mole of <mathjax>#(NH_4)_2SO_4#</mathjax> is: </p> <p><mathjax>#N xx 2 + Hxx4xx2 + S + Oxx4#</mathjax><br/> <mathjax>#= 14.01 xx 2 + 1.008xx4xx2 + 32.07 + 16.00xx4#</mathjax><br/> <mathjax>#= "132.14 g/mol"#</mathjax></p> <p>So, the number of moles of <mathjax>#(NH_4)_2SO_4#</mathjax> in <mathjax>#"0.230 g"#</mathjax> would be: </p> <p><mathjax>#"moles" = "mass"/"molar mass" = "0.230 g"/"132.14 g/mol" = "0.00187 mol"#</mathjax></p> <p>The question also tells us that the <mathjax>#(NH_4)_2SO_4#</mathjax> solution is <mathjax>#"1.7 M"#</mathjax>. This means that there are <mathjax>#1.7"#</mathjax> moles per liter.</p> <p><mathjax>#"1.7 moles"/"1 L"#</mathjax></p> <p>We can use this ratio to find the volume of solution which would have <mathjax>#"0.00187 mol"#</mathjax> of <mathjax>#(NH_4)_2SO_4#</mathjax>:</p> <p><mathjax>#"1.7 moles"/"1 L" = "1.7 × (0.00187/1.7) moles"/"1.0 × (0.00187/1.7) L"#</mathjax></p> <p><mathjax>#= "0.00187 moles"/"0.0011 L"#</mathjax></p> <p>We'd need <mathjax>#"0.0011 L"#</mathjax> of the <mathjax>#(NH_4)_2SO_4#</mathjax> solution to get <mathjax>#"0.230 g"#</mathjax> of <mathjax>#(NH_4)_2SO_4#</mathjax>. :)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/613823" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-temperature-affect-the-formation-of-a-solution"> How can temperature affect the formation of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-formation-of-a-solution-be-exothermic-or-endothermic"> How can the formation of a solution be exothermic or endothermic? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-formation-of-a-solution-involve-energy"> How does the formation of a solution involve energy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-heat-formation-of-solution"> How do you find heat of formation of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-factor-promotes-the-formation-of-solutions"> Which factors promote the formation of solutions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/which-two-processes-are-at-equilibrium-in-a-saturated-sugar-solution"> Which two processes are at equilibrium in a saturated sugar solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-solutes-lower-the-freezing-point"> Why do solutes lower the freezing point? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-does-solution-formation-require-energy"> Why does solution formation require energy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-solutes-dissolve-in-solvents"> Why do solutes dissolve in solvents? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-solvent-dissolves-silicone"> What solvent dissolves silicone? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/solution-formation---what-happens-when-stuff-dissolves"> See all questions in Solution Formation </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1628 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How much 1.7M solution of #(NH_4)_2SO_4# do you have to use so that it contains 0.230 g of the substance?	null
2,294	abf0064a-6ddd-11ea-99e0-ccda262736ce	https://socratic.org/questions/what-is-the-number-of-moles-of-solute-in-250-ml-of-a-0-4-m-solution	0.10 moles	start physical_unit 7 7 mole mol qc_end physical_unit 15 15 9 10 volume qc_end physical_unit 15 15 13 14 molarity qc_end end	[{"type":"physical unit","value":"Mole [OF] solute [IN] moles"}]	[{"type":"physical unit","value":"0.10 moles"}]	[{"type":"physical unit","value":"Volume [OF] solution [=] \\pu{250 mL}"},{"type":"physical unit","value":"Molarity [OF] solution [=] \\pu{0.4 M}"}]	<h1 class="questionTitle" itemprop="name">What is the number of moles of solute in 250 mL of a 0.4 M solution?</h1>	null	0.10 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First, recognize that the molar concentration tells you how many moles of the solute are present in one liter of solution. In a 0.4 M solution, there are 0.4 moles of solute in every liter of solution. You can determine the number of moles of solute in 250 mL of the solution using dimensional analysis.</p> <p><mathjax>#250 mL * (1 L)/(1000mL) * (0.4 mol)/(1L)#</mathjax></p> <p>Units of liters and milliliters cancel, leaving you with a final answer in units of moles, at 0.1 mol.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>There are 0.1 moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> in 250 mL of 0.4 M solution.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First, recognize that the molar concentration tells you how many moles of the solute are present in one liter of solution. In a 0.4 M solution, there are 0.4 moles of solute in every liter of solution. You can determine the number of moles of solute in 250 mL of the solution using dimensional analysis.</p> <p><mathjax>#250 mL * (1 L)/(1000mL) * (0.4 mol)/(1L)#</mathjax></p> <p>Units of liters and milliliters cancel, leaving you with a final answer in units of moles, at 0.1 mol.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the number of moles of solute in 250 mL of a 0.4 M solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="332154" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/morgan-h-1"><img alt="" class="" src="https://profilepictures.socratic.org/P5lBRfASSLq9uiwN2FtP_Screen%20Shot%202016-11-26%20at%2012.29.09%20PM.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/morgan-h-1"> Morgan </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-11-06T04:11:28" itemprop="dateCreated"> Nov 6, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>There are 0.1 moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> in 250 mL of 0.4 M solution.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First, recognize that the molar concentration tells you how many moles of the solute are present in one liter of solution. In a 0.4 M solution, there are 0.4 moles of solute in every liter of solution. You can determine the number of moles of solute in 250 mL of the solution using dimensional analysis.</p> <p><mathjax>#250 mL * (1 L)/(1000mL) * (0.4 mol)/(1L)#</mathjax></p> <p>Units of liters and milliliters cancel, leaving you with a final answer in units of moles, at 0.1 mol.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/332154" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 64493 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the number of moles of solute in 250 mL of a 0.4 M solution?	null
2,295	ab9ad274-6ddd-11ea-8340-ccda262736ce	https://socratic.org/questions/how-many-moles-of-ag-are-present-in-25-ml-of-a-0-75-molar-agno-3-solution	0.02 moles	start physical_unit 4 4 mole mol qc_end physical_unit 14 15 12 13 molarity qc_end physical_unit 14 15 8 9 volume qc_end end	[{"type":"physical unit","value":"Mole [OF] Ag+ [IN] moles"}]	[{"type":"physical unit","value":"0.02 moles"}]	[{"type":"physical unit","value":"Molarity [OF] AgNO3 solution [=] \\pu{0.75 molar}"},{"type":"physical unit","value":"Volume [OF] AgNO3 solution [=] \\pu{25 mL}"}]	<h1 class="questionTitle" itemprop="name">How many moles of Ag+ are present in 25 mL of a 0.75 molar #AgNO_3# solution?</h1>	null	0.02 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#c=n/v#</mathjax></p> <p><mathjax>#:.n=cxxv#</mathjax></p> <p><mathjax>#:. nAg^(+)=0.75xx (25)/(1000)=0.019#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>There are 0.019 moles.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#c=n/v#</mathjax></p> <p><mathjax>#:.n=cxxv#</mathjax></p> <p><mathjax>#:. nAg^(+)=0.75xx (25)/(1000)=0.019#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles of Ag+ are present in 25 mL of a 0.75 molar #AgNO_3# solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="184973" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/michael-2"><img alt="" class="" src="https://lh3.googleusercontent.com/-gCv6FQRhls0/AAAAAAAAAAI/AAAAAAAAAAA/AAnnY7oOJS05Ylqn3KuDSW0LfnbOk7FezQ/mo/photo.jpg?sz=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/michael-2"> Michael </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-07T01:23:42" itemprop="dateCreated"> Nov 7, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>There are 0.019 moles.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#c=n/v#</mathjax></p> <p><mathjax>#:.n=cxxv#</mathjax></p> <p><mathjax>#:. nAg^(+)=0.75xx (25)/(1000)=0.019#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/184973" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 7677 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many moles of Ag+ are present in 25 mL of a 0.75 molar #AgNO_3# solution?	null
2,296	ab18d638-6ddd-11ea-b6cb-ccda262736ce	https://socratic.org/questions/a-gas-with-a-volume-of-4-0-l-at-90-0-kpa-expands-until-the-pressure-drops-to-20-	18.00 L	start physical_unit 1 1 volume l qc_end physical_unit 1 1 6 7 volume qc_end physical_unit 1 1 9 10 pressure qc_end physical_unit 1 1 17 18 pressure qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Volume2 [OF] the gas [IN] L"}]	[{"type":"physical unit","value":"18.00 L"}]	[{"type":"physical unit","value":"Volume1 [OF] the gas [=] \\pu{4.0 L}"},{"type":"physical unit","value":"Pressure1 [OF] the gas [=] \\pu{90.0 kPa}"},{"type":"physical unit","value":"Pressure2 [OF] the gas [=] \\pu{20.0 kPa}"},{"type":"other","value":"ConstantTemperature"}]	<h1 class="questionTitle" itemprop="name"> A gas with a volume of 4.0 L at 90.0 kPa expands until the pressure drops to 20.0 kPa. What is its new volume if the temperature doesn't change?</h1>	null	18.00 L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Before doing any calculations, try to predict what you <em>expect</em> to see happen to the volume of the sample. </p> <p>The problem tells you that the <em>temperature</em> of the gas <strong>remains unchanged</strong>. No mention is made about the <em>number of moles</em> of gas present in the sample, which means that you can assume it to be <strong>constant</strong> as well. </p> <p>As you know, temperature is actually a measure of the <strong>average kinetic energy</strong> of the gas molecules. <a href="http://socratic.org/chemistry/the-behavior-of-gases/gas-pressure">Gas pressure</a> is a result of the <em>frequency</em> and <em>intensity</em> of the collisions that take place between the gas molecules and the walls of the container. </p> <p>If a pressure of <mathjax>#"90.0 kPa"#</mathjax> corresponds to a given average kinetic energy of the molecules, i.e. a given <em>temperature</em>, then <strong>decreasing</strong> would result in an <strong>increase</strong> in volume. </p> <p>Think about it like this - the average kinetic energy of the gas molecules remains <strong>unchanged</strong>, which means that in order to produce a <strong>lower pressure</strong> they must hit the walls of the container <strong>less often</strong>. </p> <p>The molecules are moving with the same average kinetic energy, which is why they must hit the walls of the container <em>less often</em>. </p> <p>This can only be achieved by an <strong>increase in volume</strong>. </p> <p>So, when temperature and number of moles are kept constant, pressure and volume have an <strong>inverse relationship</strong> - this is known as <strong><a href="http://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's Law</a></strong>.</p> <p><img alt="https://saylordotorg.github.io/text_introductory-chemistry/s10-03-gas-laws.html" src="https://useruploads.socratic.org/GXXZJVdCQFeIotXgQswi_72ab7ad8a1fdc1f4fdadd93d52db9294.jpg"/> </p> <p>When pressure <strong>increases</strong>, volume <strong>decreases</strong>, and when pressure <strong>decreases</strong>, volume <strong>increases</strong>. </p> <p>This means that you can expect the volume of the gas to <strong>increase</strong>. </p> <p>Mathematically, you can write this as</p> <blockquote> <p><mathjax>#color(blue)(P_1V_1 = P_2V_2)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#P_1#</mathjax>, <mathjax>#V_1#</mathjax> - the pressure and volume of the gas at an initial state<br/> <mathjax>#P_2#</mathjax>, <mathjax>#V_2#</mathjax> - the pressure and volume of the gas at a final state</p> <p>Rearrange and solve for <mathjax>#V_2#</mathjax>, the new volume of the gas</p> <blockquote> <p><mathjax>#V_2 = P_1/P_2 * V_1#</mathjax></p> <p><mathjax>#V_2 = (90.0 color(red)(cancel(color(black)("kPa"))))/(20.0color(red)(cancel(color(black)("kPa")))) * "4.0 L" = color(green)("18 L")#</mathjax></p> </blockquote> <p>As predicted, the volume of the gas <strong>increased</strong> as a result of the <em>decrease</em> in pressure. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"18 L"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Before doing any calculations, try to predict what you <em>expect</em> to see happen to the volume of the sample. </p> <p>The problem tells you that the <em>temperature</em> of the gas <strong>remains unchanged</strong>. No mention is made about the <em>number of moles</em> of gas present in the sample, which means that you can assume it to be <strong>constant</strong> as well. </p> <p>As you know, temperature is actually a measure of the <strong>average kinetic energy</strong> of the gas molecules. <a href="http://socratic.org/chemistry/the-behavior-of-gases/gas-pressure">Gas pressure</a> is a result of the <em>frequency</em> and <em>intensity</em> of the collisions that take place between the gas molecules and the walls of the container. </p> <p>If a pressure of <mathjax>#"90.0 kPa"#</mathjax> corresponds to a given average kinetic energy of the molecules, i.e. a given <em>temperature</em>, then <strong>decreasing</strong> would result in an <strong>increase</strong> in volume. </p> <p>Think about it like this - the average kinetic energy of the gas molecules remains <strong>unchanged</strong>, which means that in order to produce a <strong>lower pressure</strong> they must hit the walls of the container <strong>less often</strong>. </p> <p>The molecules are moving with the same average kinetic energy, which is why they must hit the walls of the container <em>less often</em>. </p> <p>This can only be achieved by an <strong>increase in volume</strong>. </p> <p>So, when temperature and number of moles are kept constant, pressure and volume have an <strong>inverse relationship</strong> - this is known as <strong><a href="http://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's Law</a></strong>.</p> <p><img alt="https://saylordotorg.github.io/text_introductory-chemistry/s10-03-gas-laws.html" src="https://useruploads.socratic.org/GXXZJVdCQFeIotXgQswi_72ab7ad8a1fdc1f4fdadd93d52db9294.jpg"/> </p> <p>When pressure <strong>increases</strong>, volume <strong>decreases</strong>, and when pressure <strong>decreases</strong>, volume <strong>increases</strong>. </p> <p>This means that you can expect the volume of the gas to <strong>increase</strong>. </p> <p>Mathematically, you can write this as</p> <blockquote> <p><mathjax>#color(blue)(P_1V_1 = P_2V_2)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#P_1#</mathjax>, <mathjax>#V_1#</mathjax> - the pressure and volume of the gas at an initial state<br/> <mathjax>#P_2#</mathjax>, <mathjax>#V_2#</mathjax> - the pressure and volume of the gas at a final state</p> <p>Rearrange and solve for <mathjax>#V_2#</mathjax>, the new volume of the gas</p> <blockquote> <p><mathjax>#V_2 = P_1/P_2 * V_1#</mathjax></p> <p><mathjax>#V_2 = (90.0 color(red)(cancel(color(black)("kPa"))))/(20.0color(red)(cancel(color(black)("kPa")))) * "4.0 L" = color(green)("18 L")#</mathjax></p> </blockquote> <p>As predicted, the volume of the gas <strong>increased</strong> as a result of the <em>decrease</em> in pressure. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name"> A gas with a volume of 4.0 L at 90.0 kPa expands until the pressure drops to 20.0 kPa. What is its new volume if the temperature doesn't change?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/boyle-s-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Boyle's Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="233745" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-02T00:01:04" itemprop="dateCreated"> Mar 2, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"18 L"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Before doing any calculations, try to predict what you <em>expect</em> to see happen to the volume of the sample. </p> <p>The problem tells you that the <em>temperature</em> of the gas <strong>remains unchanged</strong>. No mention is made about the <em>number of moles</em> of gas present in the sample, which means that you can assume it to be <strong>constant</strong> as well. </p> <p>As you know, temperature is actually a measure of the <strong>average kinetic energy</strong> of the gas molecules. <a href="http://socratic.org/chemistry/the-behavior-of-gases/gas-pressure">Gas pressure</a> is a result of the <em>frequency</em> and <em>intensity</em> of the collisions that take place between the gas molecules and the walls of the container. </p> <p>If a pressure of <mathjax>#"90.0 kPa"#</mathjax> corresponds to a given average kinetic energy of the molecules, i.e. a given <em>temperature</em>, then <strong>decreasing</strong> would result in an <strong>increase</strong> in volume. </p> <p>Think about it like this - the average kinetic energy of the gas molecules remains <strong>unchanged</strong>, which means that in order to produce a <strong>lower pressure</strong> they must hit the walls of the container <strong>less often</strong>. </p> <p>The molecules are moving with the same average kinetic energy, which is why they must hit the walls of the container <em>less often</em>. </p> <p>This can only be achieved by an <strong>increase in volume</strong>. </p> <p>So, when temperature and number of moles are kept constant, pressure and volume have an <strong>inverse relationship</strong> - this is known as <strong><a href="http://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's Law</a></strong>.</p> <p><img alt="https://saylordotorg.github.io/text_introductory-chemistry/s10-03-gas-laws.html" src="https://useruploads.socratic.org/GXXZJVdCQFeIotXgQswi_72ab7ad8a1fdc1f4fdadd93d52db9294.jpg"/> </p> <p>When pressure <strong>increases</strong>, volume <strong>decreases</strong>, and when pressure <strong>decreases</strong>, volume <strong>increases</strong>. </p> <p>This means that you can expect the volume of the gas to <strong>increase</strong>. </p> <p>Mathematically, you can write this as</p> <blockquote> <p><mathjax>#color(blue)(P_1V_1 = P_2V_2)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#P_1#</mathjax>, <mathjax>#V_1#</mathjax> - the pressure and volume of the gas at an initial state<br/> <mathjax>#P_2#</mathjax>, <mathjax>#V_2#</mathjax> - the pressure and volume of the gas at a final state</p> <p>Rearrange and solve for <mathjax>#V_2#</mathjax>, the new volume of the gas</p> <blockquote> <p><mathjax>#V_2 = P_1/P_2 * V_1#</mathjax></p> <p><mathjax>#V_2 = (90.0 color(red)(cancel(color(black)("kPa"))))/(20.0color(red)(cancel(color(black)("kPa")))) * "4.0 L" = color(green)("18 L")#</mathjax></p> </blockquote> <p>As predicted, the volume of the gas <strong>increased</strong> as a result of the <em>decrease</em> in pressure. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/233745" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-graph-boyles-law"> How do you graph Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-functional-groups-are-found-in-lipids"> What functional groups are found in lipids? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-k-constant-in-boyle-s-law"> Why is k constant in Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-boyle-s-law-graph-curved-1"> Why is Boyle's law graph curved? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-boyle-s-law-an-inverse-relationship-2"> Why is Boyle's law an inverse relationship? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-40-0-l-tank-of-ammonia-has-a-pressure-of-8-00-atm-calculate-the-volume-of-the-"> A 40.0 L tank of ammonia has a pressure of 8.00 atm. Calculate the volume of the ammonia if its... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-charles-law-different-from-boyle-s-law"> How is Charles' law different from Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-boyle-s-law-written-mathematically"> How is Boyle's law written mathematically? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-temperature-affect-boyle-s-law"> How does temperature affect Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-boyle-s-law-relate-to-ventilation"> How does Boyle's law relate to ventilation? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/boyle-s-law"> See all questions in Boyle's Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 12193 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A gas with a volume of 4.0 L at 90.0 kPa expands until the pressure drops to 20.0 kPa. What is its new volume if the temperature doesn't change?	null
2,297	ab7f858c-6ddd-11ea-98b6-ccda262736ce	https://socratic.org/questions/how-many-moles-are-there-in-4-75g-of-magnesium-chloride	0.05 moles	start physical_unit 9 10 mole mol qc_end physical_unit 9 10 6 7 mass qc_end end	[{"type":"physical unit","value":"Mole [OF] magnesium chloride [IN] moles"}]	[{"type":"physical unit","value":"0.05 moles"}]	[{"type":"physical unit","value":"Mass [OF] magnesium chloride [=] \\pu{4.75 g}"}]	<h1 class="questionTitle" itemprop="name">How many moles are there in 4.75g of magnesium chloride?</h1>	null	0.05 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The molar mass (mass of one mole) of magnesium chloride, <mathjax>#"MgCl"_2"#</mathjax>, is <mathjax>#"95.211 g/mol"#</mathjax>. To calculate the number of moles of <mathjax>#"MgCl"_2"#</mathjax> in <mathjax>#"4.75 g"#</mathjax>, divide the given mass by the molar mass.</p> <p><mathjax>#4.75cancel"g MgCl"_2xx(1"mol MgCl"_2)/(95.211cancel"g MgCl"_2)="0.0499 mol MgCl"_2"#</mathjax> (rounded to three significant figures)</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>There are <mathjax>#"0.0499 mol MgCl"#</mathjax> in <mathjax>#"4.75 g"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The molar mass (mass of one mole) of magnesium chloride, <mathjax>#"MgCl"_2"#</mathjax>, is <mathjax>#"95.211 g/mol"#</mathjax>. To calculate the number of moles of <mathjax>#"MgCl"_2"#</mathjax> in <mathjax>#"4.75 g"#</mathjax>, divide the given mass by the molar mass.</p> <p><mathjax>#4.75cancel"g MgCl"_2xx(1"mol MgCl"_2)/(95.211cancel"g MgCl"_2)="0.0499 mol MgCl"_2"#</mathjax> (rounded to three significant figures)</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles are there in 4.75g of magnesium chloride?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="200600" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-17T06:39:18" itemprop="dateCreated"> Dec 17, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>There are <mathjax>#"0.0499 mol MgCl"#</mathjax> in <mathjax>#"4.75 g"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The molar mass (mass of one mole) of magnesium chloride, <mathjax>#"MgCl"_2"#</mathjax>, is <mathjax>#"95.211 g/mol"#</mathjax>. To calculate the number of moles of <mathjax>#"MgCl"_2"#</mathjax> in <mathjax>#"4.75 g"#</mathjax>, divide the given mass by the molar mass.</p> <p><mathjax>#4.75cancel"g MgCl"_2xx(1"mol MgCl"_2)/(95.211cancel"g MgCl"_2)="0.0499 mol MgCl"_2"#</mathjax> (rounded to three significant figures)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/200600" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 13588 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many moles are there in 4.75g of magnesium chloride?	null
2,298	ad1b1868-6ddd-11ea-9be3-ccda262736ce	https://socratic.org/questions/how-much-heat-is-liberated-by-the-combustion-of-206-g-of-hydrogen-deltah-comb-28	58900 kJ	start physical_unit 6 7 heat_energy kj qc_end physical_unit 12 12 9 10 mass qc_end end	[{"type":"physical unit","value":"Liberated heat [OF] the combustion [IN] kJ"}]	[{"type":"physical unit","value":"58900 kJ"}]	[{"type":"physical unit","value":"Mass [OF] hydrogen [=] \\pu{206 g}"},{"type":"physical unit","value":"DeltaH [OF] comb [=] \\pu{-286 kJ/mol}"}]	<h1 class="questionTitle" itemprop="name">How much heat is liberated by the combustion of 206 g of hydrogen? #DeltaH_(comb)# = -286 kJ/mol</h1>	null	58900 kJ	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#n("H")=m/M=(206g)/(1.00gmol^-1)=206mol#</mathjax></p> <p><mathjax>#"Energy Released" = DeltaH_(comb) xx n = -286kJmol^-1xx206mol=58916kJ=58900kJ("3s.f.")#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>58900kJ</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#n("H")=m/M=(206g)/(1.00gmol^-1)=206mol#</mathjax></p> <p><mathjax>#"Energy Released" = DeltaH_(comb) xx n = -286kJmol^-1xx206mol=58916kJ=58900kJ("3s.f.")#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How much heat is liberated by the combustion of 206 g of hydrogen? #DeltaH_(comb)# = -286 kJ/mol</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/specific-heat" itemprop="url"> <span class="breadcrumb" itemprop="title">Specific Heat</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="285190" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/glowing-grasshopper"><img alt="" class="" src="https://lh6.googleusercontent.com/-yAnywTuHSxk/AAAAAAAAAAI/AAAAAAAAAFI/pNn-rdsyXQk/photo.jpg?sz=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/glowing-grasshopper"> Cameron G. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-06T05:01:22" itemprop="dateCreated"> Jul 6, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>58900kJ</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#n("H")=m/M=(206g)/(1.00gmol^-1)=206mol#</mathjax></p> <p><mathjax>#"Energy Released" = DeltaH_(comb) xx n = -286kJmol^-1xx206mol=58916kJ=58900kJ("3s.f.")#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/285190" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-specific-heat-be-used-to-identify-substances"> How can specific heat be used to identify substances? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-heat-capacity-of-a-lead-sinker-be-determined"> How can the heat capacity of a lead sinker be determined? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-the-specific-heats-of-metals-compare-with-water"> How do the specific heats of metals compare with water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-specific-heat-change-with-temperature"> How does specific heat change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/dissolving-some-potassium-bromide-in-200cm3-of-water-leads-to-a-decrease-in-temp"> Dissolving some potassium bromide in 200cm3 of water leads to a decrease in temperature of 3oC.... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-heat-capacity-larger-for-polymers"> Is heat capacity larger for polymers? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-heat-capacity-an-extensive-property"> Why is heat capacity an extensive property? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-does-heat-capacity-change-with-temperature"> Why does heat capacity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-specific-heat-measured-in"> What is specific heat measured in? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-heat-capacity-measured-in"> What is heat capacity measured in? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/specific-heat"> See all questions in Specific Heat </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 9839 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How much heat is liberated by the combustion of 206 g of hydrogen? #DeltaH_(comb)# = -286 kJ/mol	null
2,299	aa2dabcc-6ddd-11ea-b429-ccda262736ce	https://socratic.org/questions/at-120-0-c-the-pressure-of-a-sample-of-nitrogen-is-1-07-atm-what-will-the-pressu	1.42 atm	start physical_unit 7 9 pressure atm qc_end physical_unit 7 9 11 12 pressure qc_end physical_unit 7 9 1 2 temperature qc_end physical_unit 7 9 19 20 temperature qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Pressure2 [OF] nitrogen sample [IN] atm"}]	[{"type":"physical unit","value":"1.42 atm"}]	[{"type":"physical unit","value":"Pressure1 [OF] nitrogen sample [=] \\pu{1.07 atm}"},{"type":"physical unit","value":"Temperature1 [OF] nitrogen sample [=] \\pu{120.0 ℃}"},{"type":"physical unit","value":"Temperature2 [OF] nitrogen sample [=] \\pu{205 ℃}"},{"type":"other","value":"Constant volume."}]	<h1 class="questionTitle" itemprop="name">At 120.0°C, the pressure of a sample of nitrogen is 1.07 atm. What will the pressure be at 205°C, assuming constant volume?</h1>	null	1.42 atm	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The important thing to remember about a gas kept at <strong>constant volume</strong> is that its <em>pressure</em> and its <em>temperature</em> are <strong>directly proportional</strong>, assuming of course that the number of moles of gas are constant as well. </p> <p>So, when volume and number of moles are kept constant, pressure and temperature have a <strong>direct relationship</strong> - this is known as <a href="http://socratic.org/chemistry/the-behavior-of-gases/gay-lussac-s-law">Gay Lussac's Law</a>.</p> <p><img alt="http://ouitschem.weebly.com/gas-laws.html" src="https://useruploads.socratic.org/F7XXt4ZxSsaoCQF4nxmK_232155701.jpg"/> </p> <p>Simply put, when temperature <strong>increases</strong>, pressure <strong>increases</strong>. Likewise, when temperature <strong>decreases</strong>, pressure <strong>decreases</strong> as well. </p> <p>In your case, the temperature of the gas <em>increases</em> from <mathjax>#120.0^@"C"#</mathjax> to <mathjax>#205^@"C"#</mathjax>, so right from the start you can say that the pressure of the gas will <em>increase</em> as well. </p> <p>Mathematically, <a href="http://socratic.org/chemistry/the-behavior-of-gases/gay-lussac-s-law">Gay Lussac's Law</a> is expressed like this </p> <blockquote> <p><mathjax>#color(blue)(P_1/T_1 = P_2/T_2)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#P_1#</mathjax>, <mathjax>#T_1#</mathjax> - the pressure and temperature of the gas at an initial state<br/> <mathjax>#P_2#</mathjax>, <mathjax>#T_2#</mathjax> - the pressure and temperature of the gas at a final state </p> <p>Now, it is <strong>of the utmost importance</strong> that you <strong>do not</strong> forget to convert the temperature from <em>degrees Celsius</em> to <em>Kelvin</em>! </p> <p>In fact, the temperature <strong>must</strong> be expressed in Kelvin <strong>regardless</strong> of which <a href="http://socratic.org/chemistry/the-behavior-of-gases/gas-laws">gas law</a> you're using. </p> <p>So, plug in your values and solve for <mathjax>#P_2#</mathjax></p> <blockquote> <p><mathjax>#P_1/T_1 = P_2/T_2 implies P_2 = T_2/T_1 * P_1#</mathjax></p> <p><mathjax>#P_2 = ( (273.15 + 205)color(red)(cancel(color(black)("K"))))/((273.15 + 120.0)color(red)(cancel(color(black)("K")))) * "1.07 atm" = "1.4238 atm"#</mathjax></p> </blockquote> <p>Rounded to three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the number of sig figs you have for the second temperature of the gas, the answer will be </p> <blockquote> <p><mathjax>#P_2 = color(green)("1.42 atm")#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"1.42 atm"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The important thing to remember about a gas kept at <strong>constant volume</strong> is that its <em>pressure</em> and its <em>temperature</em> are <strong>directly proportional</strong>, assuming of course that the number of moles of gas are constant as well. </p> <p>So, when volume and number of moles are kept constant, pressure and temperature have a <strong>direct relationship</strong> - this is known as <a href="http://socratic.org/chemistry/the-behavior-of-gases/gay-lussac-s-law">Gay Lussac's Law</a>.</p> <p><img alt="http://ouitschem.weebly.com/gas-laws.html" src="https://useruploads.socratic.org/F7XXt4ZxSsaoCQF4nxmK_232155701.jpg"/> </p> <p>Simply put, when temperature <strong>increases</strong>, pressure <strong>increases</strong>. Likewise, when temperature <strong>decreases</strong>, pressure <strong>decreases</strong> as well. </p> <p>In your case, the temperature of the gas <em>increases</em> from <mathjax>#120.0^@"C"#</mathjax> to <mathjax>#205^@"C"#</mathjax>, so right from the start you can say that the pressure of the gas will <em>increase</em> as well. </p> <p>Mathematically, <a href="http://socratic.org/chemistry/the-behavior-of-gases/gay-lussac-s-law">Gay Lussac's Law</a> is expressed like this </p> <blockquote> <p><mathjax>#color(blue)(P_1/T_1 = P_2/T_2)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#P_1#</mathjax>, <mathjax>#T_1#</mathjax> - the pressure and temperature of the gas at an initial state<br/> <mathjax>#P_2#</mathjax>, <mathjax>#T_2#</mathjax> - the pressure and temperature of the gas at a final state </p> <p>Now, it is <strong>of the utmost importance</strong> that you <strong>do not</strong> forget to convert the temperature from <em>degrees Celsius</em> to <em>Kelvin</em>! </p> <p>In fact, the temperature <strong>must</strong> be expressed in Kelvin <strong>regardless</strong> of which <a href="http://socratic.org/chemistry/the-behavior-of-gases/gas-laws">gas law</a> you're using. </p> <p>So, plug in your values and solve for <mathjax>#P_2#</mathjax></p> <blockquote> <p><mathjax>#P_1/T_1 = P_2/T_2 implies P_2 = T_2/T_1 * P_1#</mathjax></p> <p><mathjax>#P_2 = ( (273.15 + 205)color(red)(cancel(color(black)("K"))))/((273.15 + 120.0)color(red)(cancel(color(black)("K")))) * "1.07 atm" = "1.4238 atm"#</mathjax></p> </blockquote> <p>Rounded to three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the number of sig figs you have for the second temperature of the gas, the answer will be </p> <blockquote> <p><mathjax>#P_2 = color(green)("1.42 atm")#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">At 120.0°C, the pressure of a sample of nitrogen is 1.07 atm. What will the pressure be at 205°C, assuming constant volume?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/gay-lussac-s-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Gay Lussac's Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="212961" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-16T01:13:12" itemprop="dateCreated"> Jan 16, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"1.42 atm"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The important thing to remember about a gas kept at <strong>constant volume</strong> is that its <em>pressure</em> and its <em>temperature</em> are <strong>directly proportional</strong>, assuming of course that the number of moles of gas are constant as well. </p> <p>So, when volume and number of moles are kept constant, pressure and temperature have a <strong>direct relationship</strong> - this is known as <a href="http://socratic.org/chemistry/the-behavior-of-gases/gay-lussac-s-law">Gay Lussac's Law</a>.</p> <p><img alt="http://ouitschem.weebly.com/gas-laws.html" src="https://useruploads.socratic.org/F7XXt4ZxSsaoCQF4nxmK_232155701.jpg"/> </p> <p>Simply put, when temperature <strong>increases</strong>, pressure <strong>increases</strong>. Likewise, when temperature <strong>decreases</strong>, pressure <strong>decreases</strong> as well. </p> <p>In your case, the temperature of the gas <em>increases</em> from <mathjax>#120.0^@"C"#</mathjax> to <mathjax>#205^@"C"#</mathjax>, so right from the start you can say that the pressure of the gas will <em>increase</em> as well. </p> <p>Mathematically, <a href="http://socratic.org/chemistry/the-behavior-of-gases/gay-lussac-s-law">Gay Lussac's Law</a> is expressed like this </p> <blockquote> <p><mathjax>#color(blue)(P_1/T_1 = P_2/T_2)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#P_1#</mathjax>, <mathjax>#T_1#</mathjax> - the pressure and temperature of the gas at an initial state<br/> <mathjax>#P_2#</mathjax>, <mathjax>#T_2#</mathjax> - the pressure and temperature of the gas at a final state </p> <p>Now, it is <strong>of the utmost importance</strong> that you <strong>do not</strong> forget to convert the temperature from <em>degrees Celsius</em> to <em>Kelvin</em>! </p> <p>In fact, the temperature <strong>must</strong> be expressed in Kelvin <strong>regardless</strong> of which <a href="http://socratic.org/chemistry/the-behavior-of-gases/gas-laws">gas law</a> you're using. </p> <p>So, plug in your values and solve for <mathjax>#P_2#</mathjax></p> <blockquote> <p><mathjax>#P_1/T_1 = P_2/T_2 implies P_2 = T_2/T_1 * P_1#</mathjax></p> <p><mathjax>#P_2 = ( (273.15 + 205)color(red)(cancel(color(black)("K"))))/((273.15 + 120.0)color(red)(cancel(color(black)("K")))) * "1.07 atm" = "1.4238 atm"#</mathjax></p> </blockquote> <p>Rounded to three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the number of sig figs you have for the second temperature of the gas, the answer will be </p> <blockquote> <p><mathjax>#P_2 = color(green)("1.42 atm")#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/212961" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535d701102bf342f53d9bcb0"> Question #9bcb0 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-gay-lussac-s-law-formula"> What is the Gay Lussac's law formula? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-the-temperature-of-a-gas-in-a-container-is-doubled-on-the-kelvin-scale-the-pr"> If the temperature of a gas in a container is doubled on the Kelvin scale, what will happen to... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-the-original-pressure-of-a-gas-sample-at-20-c-was-5-00-atm-and-it-is-heated-u"> If the original pressure of a gas sample at 20 ˚C was 5.00 atm, and it is heated up to 40. ˚C ,... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-gay-lussac-s-law-state"> What does Gay Lussac's law state? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-gay-lussac-s-law-relate"> What does Gay Lussac's law relate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-sample-of-o2-under-2-00-atm-occupies-500-ml-at-25-0-c-what-pressure-will-the-s"> A sample of O2 under 2.00 atm occupies 500 ml at 25.0˚C. What pressure will the sample have at 0.0˚C ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-sample-of-o2-under-2-00-atm-occupies-500-ml-at-25-0-c-what-temperature-will-be"> A sample of O2 under 2.00 atm occupies 500 ml at 25.0˚C. What temperature will be needed to... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-gay-lussac-s-law-direct-or-inverse"> Is Gay Lussac's law direct or inverse? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/determine-the-pressure-change-when-a-constant-volume-of-gas-at-1-00-atm-is-heate"> Determine the pressure change when a constant volume of gas at 1.00 atm is heated from 20.0 ˚C... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/gay-lussac-s-law"> See all questions in Gay Lussac's Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 25522 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	At 120.0°C, the pressure of a sample of nitrogen is 1.07 atm. What will the pressure be at 205°C, assuming constant volume?	null

Subsets and Splits

No community queries yet

The top public SQL queries from the community will appear here once available.