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2,000	a87afd08-6ddd-11ea-a2b8-ccda262736ce	https://socratic.org/questions/how-do-you-calculate-the-mass-of-one-mole-of-such-hydrogen-giving-your-answer-to	1.01 g	start physical_unit 11 11 mass g qc_end physical_unit 11 11 7 8 mole qc_end physical_unit 11 11 25 28 avogadro_constant qc_end end	[{"type":"physical unit","value":"mass [OF] hydrogen [IN] g"}]	[{"type":"physical unit","value":"1.01 g"}]	[{"type":"physical unit","value":"mole [OF] hydrogen [=] \\pu{1 mole}"},{"type":"physical unit","value":"Avogadro constant L [OF] hydrogen [=] \\pu{6.0225 × 10^23 mol^(-1)}"}]	<h1 class="questionTitle" itemprop="name">How do you calculate the mass of one mole of such hydrogen giving your answer to atoms four decimal places? (The Avogadro constant, L= #6.0225 xx 10^23 mol^-1#)?</h1>	null	1.01 g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Mass of 1 hydrogen atom"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#1.6727xx10^{-27}"kg"#</mathjax> (<a href="https://www.nyu.edu/classes/tuckerman/adv.chem/lectures/lecture_3/node3.html" rel="nofollow">from this site</a>).</p> <p>And thus, <mathjax>#"mass of 1 mole of hydrogen atoms"#</mathjax> <mathjax>#=#</mathjax></p> <p><mathjax>#1.6727xx10^(-27)"kg"xx6.0225xx10^23mol^-1xx10^(3)"g"kg^-1#</mathjax></p> <p><mathjax>#=1.007"g"*"mol"^-1#</mathjax></p> <p>Clearly, you would not be expected to know these masses. You would be expected to be able to do such a calculation if provided with the masses of the nucleon, and with <mathjax>#"Avogadro's number"#</mathjax>.</p> <p>What is the mass of one mole of hydrogen molecules?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Mass of 1 mole of hydrogen atoms"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Mass of 1 hydrogen atom"xx"N"_A#</mathjax>, where <mathjax>#"N"_A=L=6.0225xx10^23mol^-1#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Mass of 1 hydrogen atom"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#1.6727xx10^{-27}"kg"#</mathjax> (<a href="https://www.nyu.edu/classes/tuckerman/adv.chem/lectures/lecture_3/node3.html" rel="nofollow">from this site</a>).</p> <p>And thus, <mathjax>#"mass of 1 mole of hydrogen atoms"#</mathjax> <mathjax>#=#</mathjax></p> <p><mathjax>#1.6727xx10^(-27)"kg"xx6.0225xx10^23mol^-1xx10^(3)"g"kg^-1#</mathjax></p> <p><mathjax>#=1.007"g""mol"^-1#</mathjax></p> <p>Clearly, you would not be expected to know these masses. You would be expected to be able to do such a calculation if provided with the masses of the nucleon, and with <mathjax>#"Avogadro's number"#</mathjax>.</p> <p>What is the mass of one mole of hydrogen molecules?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you calculate the mass of one mole of such hydrogen giving your answer to atoms four decimal places? (The Avogadro constant, L= #6.0225 xx 10^23 mol^-1#)?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="361339" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-01-07T15:28:39" itemprop="dateCreated"> Jan 7, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Mass of 1 mole of hydrogen atoms"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Mass of 1 hydrogen atom"xx"N"_A#</mathjax>, where <mathjax>#"N"_A=L=6.0225xx10^23mol^-1#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Mass of 1 hydrogen atom"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#1.6727xx10^{-27}"kg"#</mathjax> (<a href="https://www.nyu.edu/classes/tuckerman/adv.chem/lectures/lecture_3/node3.html" rel="nofollow">from this site</a>).</p> <p>And thus, <mathjax>#"mass of 1 mole of hydrogen atoms"#</mathjax> <mathjax>#=#</mathjax></p> <p><mathjax>#1.6727xx10^(-27)"kg"xx6.0225xx10^23mol^-1xx10^(3)"g"kg^-1#</mathjax></p> <p><mathjax>#=1.007"g""mol"^-1#</mathjax></p> <p>Clearly, you would not be expected to know these masses. You would be expected to be able to do such a calculation if provided with the masses of the nucleon, and with <mathjax>#"Avogadro's number"#</mathjax>.</p> <p>What is the mass of one mole of hydrogen molecules?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/361339" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 26481 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How do you calculate the mass of one mole of such hydrogen giving your answer to atoms four decimal places? (The Avogadro constant, L= #6.0225 xx 10^23 mol^-1#)?	null
2,001	a90ca446-6ddd-11ea-ab4a-ccda262736ce	https://socratic.org/questions/aluminum-metal-reacts-with-a-solution-of-copper-ii-nitrate-if-you-want-to-produc	5.98 moles	start physical_unit 0 1 mole mol qc_end substance 7 9 qc_end end	[{"type":"physical unit","value":"Mole [OF] aluminum metal [IN] moles"}]	[{"type":"physical unit","value":"5.98 moles"}]	[{"type":"physical unit","value":"Number [OF] copper atoms [=] \\pu{5.4 ×10^24}"},{"type":"substance name","value":"Copper (II) nitrate"}]	<h1 class="questionTitle" itemprop="name">Aluminum metal reacts with a solution of copper (II) nitrate. If you want to produce #5.4 * 10^24# atoms of copper, how many moles of aluminum metal are needed?</h1>	null	5.98 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First we should always have a balanced chemical equation for any reaction we are calculating.</p> <p>The balanced chemical equation for the reaction of aluminum metal with a solution of copper (II) nitrate is as follows:</p> <p><mathjax>#2 Al + 3Cu(No_3)_2 -> 2Al(No_3)_3 + 3Cu#</mathjax></p> <p>Secondly we should allways know the conversion between atoms and mols. 1 mol = <mathjax>#6.02210^23#</mathjax>.</p> <p>The copper has <mathjax>#5.4⋅10^24#</mathjax> atoms. We can convert this to mols by:</p> <p><mathjax>#(5.410^24)/(6.02210^23)#</mathjax></p> <p>= <mathjax>#8.967120558#</mathjax> mols<br/> = <mathjax>#8.97#</mathjax> mols</p> <p>As the coefficients (the numbers at the front of the <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a> in the chemical equation) are different to each other, we must change the mols. </p> <p>As <mathjax>#3Cu#</mathjax> = <mathjax>#8.97#</mathjax> mols<br/> So the aluminium must be <mathjax>#2Al#</mathjax> = <mathjax>#(8.97/3)2#</mathjax><br/> <mathjax>#2Al#</mathjax> = <mathjax>#5.98#</mathjax> mol</p> <p><mathjax>#:.#</mathjax> <mathjax>#5.98#</mathjax> mols of aluminium metal are need to produce <mathjax>#5.4⋅10^24#</mathjax><br/> atoms of copper.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#5.98#</mathjax> mols of aluminium metal are need to produce <mathjax>#5.4⋅10^24#</mathjax><br/> atoms of copper.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First we should always have a balanced chemical equation for any reaction we are calculating.</p> <p>The balanced chemical equation for the reaction of aluminum metal with a solution of copper (II) nitrate is as follows:</p> <p><mathjax>#2 Al + 3Cu(No_3)_2 -> 2Al(No_3)_3 + 3Cu#</mathjax></p> <p>Secondly we should allways know the conversion between atoms and mols. 1 mol = <mathjax>#6.02210^23#</mathjax>.</p> <p>The copper has <mathjax>#5.4⋅10^24#</mathjax> atoms. We can convert this to mols by:</p> <p><mathjax>#(5.410^24)/(6.02210^23)#</mathjax></p> <p>= <mathjax>#8.967120558#</mathjax> mols<br/> = <mathjax>#8.97#</mathjax> mols</p> <p>As the coefficients (the numbers at the front of the <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a> in the chemical equation) are different to each other, we must change the mols. </p> <p>As <mathjax>#3Cu#</mathjax> = <mathjax>#8.97#</mathjax> mols<br/> So the aluminium must be <mathjax>#2Al#</mathjax> = <mathjax>#(8.97/3)2#</mathjax><br/> <mathjax>#2Al#</mathjax> = <mathjax>#5.98#</mathjax> mol</p> <p><mathjax>#:.#</mathjax> <mathjax>#5.98#</mathjax> mols of aluminium metal are need to produce <mathjax>#5.4⋅10^24#</mathjax><br/> atoms of copper.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Aluminum metal reacts with a solution of copper (II) nitrate. If you want to produce #5.4 * 10^24# atoms of copper, how many moles of aluminum metal are needed?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="219571" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/james-10"><img alt="" class="" src="https://profilepictures.socratic.org/eTjSa9W7Q08A7fzEGlAD_giphy.gif" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/james-10"> James C. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-31T08:21:26" itemprop="dateCreated"> Jan 31, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#5.98#</mathjax> mols of aluminium metal are need to produce <mathjax>#5.4⋅10^24#</mathjax><br/> atoms of copper.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First we should always have a balanced chemical equation for any reaction we are calculating.</p> <p>The balanced chemical equation for the reaction of aluminum metal with a solution of copper (II) nitrate is as follows:</p> <p><mathjax>#2 Al + 3Cu(No_3)_2 -> 2Al(No_3)_3 + 3Cu#</mathjax></p> <p>Secondly we should allways know the conversion between atoms and mols. 1 mol = <mathjax>#6.02210^23#</mathjax>.</p> <p>The copper has <mathjax>#5.4⋅10^24#</mathjax> atoms. We can convert this to mols by:</p> <p><mathjax>#(5.410^24)/(6.02210^23)#</mathjax></p> <p>= <mathjax>#8.967120558#</mathjax> mols<br/> = <mathjax>#8.97#</mathjax> mols</p> <p>As the coefficients (the numbers at the front of the <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a> in the chemical equation) are different to each other, we must change the mols. </p> <p>As <mathjax>#3Cu#</mathjax> = <mathjax>#8.97#</mathjax> mols<br/> So the aluminium must be <mathjax>#2Al#</mathjax> = <mathjax>#(8.97/3)2#</mathjax><br/> <mathjax>#2Al#</mathjax> = <mathjax>#5.98#</mathjax> mol</p> <p><mathjax>#:.#</mathjax> <mathjax>#5.98#</mathjax> mols of aluminium metal are need to produce <mathjax>#5.4⋅10^24#</mathjax><br/> atoms of copper.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/219571" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What is stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ab82402bf342f48d93ac6"> Question #93ac6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-we-study-stoichiometry"> Why do we study stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-naoh-is-produced-from-1-20-x-102-grams-of-na2o-na2o-h2o-2-naoh"> How many grams of NaOH is produced from #1.20 x 10^2# grams of #Na_2O#? #Na_2O + H_2O -> 2NaOH# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-na2o-are-required-to-produce-1-60-x-102-grams-of-naoh-na2o-h2o"> How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? Na2O + H2O ---> 2 NaOH </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-mass-of-iron-is-needed-to-react-with-16-0-grams-of-sulfur-8-fe-s8-8-fes"> What mass of iron is needed to react with 16.0 grams of sulfur? 8 Fe + S8 ---> 8 FeS </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/according-to-8-fe-s8-8-fes-how-many-grams-of-fes-are-produced"> According to 8 Fe + S8 ---> 8 FeS How many grams of FeS are produced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/12-00-moles-of-naclo3-will-produce-how-many-grams-of-o2-2-naclo3-2-nacl-3-o2"> 12.00 moles of NaClO3 will produce how many grams of O2? 2 NaClO3 ---> 2 NaCl + 3 O2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-nacl-are-produced-when-80-0-grams-of-o2-are-produced-2-naclo3-"> How many grams of NaCl are produced when 80.0 grams of O2 are produced? 2 NaClO3 ---> 2 NaCl + 3 O2 </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/stoichiometry"> See all questions in Stoichiometry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 30309 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Aluminum metal reacts with a solution of copper (II) nitrate. If you want to produce #5.4 * 10^24# atoms of copper, how many moles of aluminum metal are needed?	null
2,002	a908d4ba-6ddd-11ea-b8a8-ccda262736ce	https://socratic.org/questions/when-the-equation-ni-no-3-3-pbbr-4-nibr-3-pb-no-3-4-is-balanced-what-is-the-coef	4	start physical_unit 3 3 coefficient none qc_end chemical_equation 3 9 qc_end end	[{"type":"physical unit","value":"Coefficient [OF] Ni(NO3)3"}]	[{"type":"physical unit","value":"4"}]	[{"type":"chemical equation","value":"Ni(NO3)3 + PbBr4 -> NiBr3 + Pb(NO3)4"}]	<h1 class="questionTitle" itemprop="name">When the equation #Ni(NO_3)_3 + PbBr_4 -> NiBr_3 + Pb(NO_3)_4# is balanced, what is the coefficient for #Ni(NO_3)_3#?</h1>	null	4	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Typical oxidation states of nickel are 0, +I, +II, "and rarely" +IV.#</mathjax> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Are you sure you can get trivalent nickel? <mathjax>#Ni(NO_3)_2#</mathjax> is more likely. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Typical oxidation states of nickel are 0, +I, +II, "and rarely" +IV.#</mathjax> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">When the equation #Ni(NO_3)_3 + PbBr_4 -> NiBr_3 + Pb(NO_3)_4# is balanced, what is the coefficient for #Ni(NO_3)_3#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="258568" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-04-25T15:20:50" itemprop="dateCreated"> Apr 25, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Are you sure you can get trivalent nickel? <mathjax>#Ni(NO_3)_2#</mathjax> is more likely. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Typical oxidation states of nickel are 0, +I, +II, "and rarely" +IV.#</mathjax> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/258568" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? 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Sodium phosphate and calcium chloride react to form... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-equation-kclo3-kcl-o2"> How can I balance this equation? ____ #KClO_3 -># ____ #KCl +# ____ #O_2# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-balancing-chemical-equations-important"> Why is balancing chemical equations important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/balancing-chemical-equations"> See all questions in Balancing Chemical Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1283 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	When the equation #Ni(NO_3)_3 + PbBr_4 -> NiBr_3 + Pb(NO_3)_4# is balanced, what is the coefficient for #Ni(NO_3)_3#?	null
2,003	acab6ad6-6ddd-11ea-bda1-ccda262736ce	https://socratic.org/questions/in-the-reaction-represented-by-the-equation-2al-2o-3-4al-3o-2-what-is-the-mole-r	4:3	start physical_unit 21 23 mole_fraction none qc_end chemical_equation 7 14 qc_end end	[{"type":"physical unit","value":"Mole ratio [OF] aluminum to oxygen"}]	[{"type":"physical unit","value":"4:3"}]	[{"type":"chemical equation","value":"2 Al2O3 -> 4 Al + 3 O2"}]	<h1 class="questionTitle" itemprop="name">In the reaction represented by the equation #2Al_2O_3 -> 4Al + 3O_2#, what is the mole ratio of aluminum to oxygen? </h1>	null	4:3	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>As per the equation , <mathjax>#2#</mathjax> moles of Aluminum Oxide (<mathjax>#Al_2O_3#</mathjax>) produces <mathjax>#4#</mathjax> moles of Aluminum (<mathjax>#Al#</mathjax>) and <mathjax>#3#</mathjax> moles of Oxygen (<mathjax>#O_2#</mathjax>).</p> <p>The ratio of <mathjax>#Al#</mathjax> to <mathjax>#O#</mathjax> is <mathjax>#(4 " moles")/(3 " moles")#</mathjax> = <mathjax>#4/3#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#4:3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>As per the equation , <mathjax>#2#</mathjax> moles of Aluminum Oxide (<mathjax>#Al_2O_3#</mathjax>) produces <mathjax>#4#</mathjax> moles of Aluminum (<mathjax>#Al#</mathjax>) and <mathjax>#3#</mathjax> moles of Oxygen (<mathjax>#O_2#</mathjax>).</p> <p>The ratio of <mathjax>#Al#</mathjax> to <mathjax>#O#</mathjax> is <mathjax>#(4 " moles")/(3 " moles")#</mathjax> = <mathjax>#4/3#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">In the reaction represented by the equation #2Al_2O_3 -> 4Al + 3O_2#, what is the mole ratio of aluminum to oxygen? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/mole-ratios" itemprop="url"> <span class="breadcrumb" itemprop="title">Mole Ratios</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="266601" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/manish-b"><img alt="" class="" src="https://profilepictures.socratic.org/eW7uaERSSvtv5ff2XPxA_10203153902643748.jpg" title=""/></a> <a class="secondContributorPic" href="/users/grace-9"><img alt="" class="" src="https://profilepictures.socratic.org/gzi0U3RQNuMSxgKVeKgw_10960213_10153434463490909_9111641440892052754_o.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/manish-b"> Manish Bhardwaj </a>·<a class="topContributorLink" href="/users/grace-9"> Grace </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-17T05:41:46" itemprop="dateCreated"> May 17, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#4:3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>As per the equation , <mathjax>#2#</mathjax> moles of Aluminum Oxide (<mathjax>#Al_2O_3#</mathjax>) produces <mathjax>#4#</mathjax> moles of Aluminum (<mathjax>#Al#</mathjax>) and <mathjax>#3#</mathjax> moles of Oxygen (<mathjax>#O_2#</mathjax>).</p> <p>The ratio of <mathjax>#Al#</mathjax> to <mathjax>#O#</mathjax> is <mathjax>#(4 " moles")/(3 " moles")#</mathjax> = <mathjax>#4/3#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/266601" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div 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around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	In the reaction represented by the equation #2Al_2O_3 -> 4Al + 3O_2#, what is the mole ratio of aluminum to oxygen?	null
2,004	a8d00835-6ddd-11ea-a46d-ccda262736ce	https://socratic.org/questions/h-2-g-cl-2-g-2hcl-g-if-2-mol-of-hydrogen-gas-are-mixed-with-4-mol-of-chlorine-ga	4 moles	start physical_unit 24 25 mole mol qc_end chemical_equation 0 5 qc_end physical_unit 10 11 7 8 mole qc_end physical_unit 18 19 15 16 mole qc_end end	[{"type":"physical unit","value":"Mole [OF] hydrogen chloride [IN] moles"}]	[{"type":"physical unit","value":"4 moles"}]	[{"type":"chemical equation","value":"H2(g) + Cl2(g) -> 2 HCl(g)"},{"type":"physical unit","value":"Mole [OF] hydrogen gas [=] \\pu{2 mol}"},{"type":"physical unit","value":"Mole [OF] chlorine gas [=] \\pu{4 mol}"}]	<h1 class="questionTitle" itemprop="name">#H_2(g) + Cl_2(g) -> 2HCl(g)+#. If 2 mol of hydrogen gas are mixed with 4 mol of chlorine gas, how many moles of hydrogen chloride will be produced?</h1>	null	4 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The ratio at which the compounds react with each other are displayed in a chemical reaction as the numbers in front of the compounds. For example in this reaction:</p> <p>1 <mathjax>#H_2#</mathjax> molecule reacts with 1 <mathjax>#Cl_2#</mathjax> molecule<br/> Forming <br/> 2 <mathjax>#HCl#</mathjax> molecules.</p> <p>In chemistry moles are used as a handy number of a certain amount of stuff. You can compare this to a dozen eggs, which is always 12. In the same way 1 mol is the number <mathjax>#6.02210^(23)#</mathjax>. This number tells us how many particles there are. So in 1 mol there are <mathjax>#6.02210^(23)#</mathjax> particles. This number is also referred to as the constant of Avogadro.</p> <p>In the question the amount of moles for <mathjax>#H_2#</mathjax> and for <mathjax>#Cl_2#</mathjax> are given. We have to calculate how much <mathjax>#HCl#</mathjax> is produced with both these values. Therefore 2 calculations needs to be done.</p> <p>Because moles just tells us something about the amount of particles we can use the ratio of the reaction to calculate how many <mathjax>#HCl#</mathjax> will be produced.</p> <p>We start of with the 2 moles of hydrogen gas. We know the following now:<br/> 1 mole of <mathjax>#H_2#</mathjax> gives 2 moles of <mathjax>#HCl#</mathjax><br/> Therefore <br/> 2 moles of <mathjax>#H_2#</mathjax> gives 4 moles of <mathjax>#HCl#</mathjax></p> <p>Now this same calculation can be done for the <mathjax>#Cl_2#</mathjax>:<br/> 1 mole of <mathjax>#Cl_2#</mathjax> reacts to 2 moles of <mathjax>#HCl#</mathjax>, therefore<br/> 4 moles of <mathjax>#Cl_2#</mathjax> reacts to 8 moles of <mathjax>#HCl#</mathjax>.</p> <p>Now we see we have 2 different amount of moles for <mathjax>#HCl#</mathjax> and the question now is which one should we use? <br/> We must now look at which one of above reactions can occur? So for the 2 moles of <mathjax>#H_2#</mathjax>, we can calculate with the ratio that:<br/> 2 moles of <mathjax>#H_2#</mathjax> reacts with 2 moles of <mathjax>#Cl_2#</mathjax>. <br/> We do have 2 moles of <mathjax>#Cl_2#</mathjax> available!</p> <p>Let's see the other one<br/> 4 moles of <mathjax>#Cl_2#</mathjax> reacts with 4 moles of <mathjax>#H_2#</mathjax><br/> But we do not have 4 moles of <mathjax>#H_2#</mathjax>!! </p> <p>Therefore we can only make 4 moles of <mathjax>#HCl#</mathjax> instead of 8 moles.</p> <p>This situation can be stated as following: The <mathjax>#Cl_2#</mathjax> is abundant.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>4 moles of HCl are produced</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The ratio at which the compounds react with each other are displayed in a chemical reaction as the numbers in front of the compounds. For example in this reaction:</p> <p>1 <mathjax>#H_2#</mathjax> molecule reacts with 1 <mathjax>#Cl_2#</mathjax> molecule<br/> Forming <br/> 2 <mathjax>#HCl#</mathjax> molecules.</p> <p>In chemistry moles are used as a handy number of a certain amount of stuff. You can compare this to a dozen eggs, which is always 12. In the same way 1 mol is the number <mathjax>#6.02210^(23)#</mathjax>. This number tells us how many particles there are. So in 1 mol there are <mathjax>#6.02210^(23)#</mathjax> particles. This number is also referred to as the constant of Avogadro.</p> <p>In the question the amount of moles for <mathjax>#H_2#</mathjax> and for <mathjax>#Cl_2#</mathjax> are given. We have to calculate how much <mathjax>#HCl#</mathjax> is produced with both these values. Therefore 2 calculations needs to be done.</p> <p>Because moles just tells us something about the amount of particles we can use the ratio of the reaction to calculate how many <mathjax>#HCl#</mathjax> will be produced.</p> <p>We start of with the 2 moles of hydrogen gas. We know the following now:<br/> 1 mole of <mathjax>#H_2#</mathjax> gives 2 moles of <mathjax>#HCl#</mathjax><br/> Therefore <br/> 2 moles of <mathjax>#H_2#</mathjax> gives 4 moles of <mathjax>#HCl#</mathjax></p> <p>Now this same calculation can be done for the <mathjax>#Cl_2#</mathjax>:<br/> 1 mole of <mathjax>#Cl_2#</mathjax> reacts to 2 moles of <mathjax>#HCl#</mathjax>, therefore<br/> 4 moles of <mathjax>#Cl_2#</mathjax> reacts to 8 moles of <mathjax>#HCl#</mathjax>.</p> <p>Now we see we have 2 different amount of moles for <mathjax>#HCl#</mathjax> and the question now is which one should we use? <br/> We must now look at which one of above reactions can occur? So for the 2 moles of <mathjax>#H_2#</mathjax>, we can calculate with the ratio that:<br/> 2 moles of <mathjax>#H_2#</mathjax> reacts with 2 moles of <mathjax>#Cl_2#</mathjax>. <br/> We do have 2 moles of <mathjax>#Cl_2#</mathjax> available!</p> <p>Let's see the other one<br/> 4 moles of <mathjax>#Cl_2#</mathjax> reacts with 4 moles of <mathjax>#H_2#</mathjax><br/> But we do not have 4 moles of <mathjax>#H_2#</mathjax>!! </p> <p>Therefore we can only make 4 moles of <mathjax>#HCl#</mathjax> instead of 8 moles.</p> <p>This situation can be stated as following: The <mathjax>#Cl_2#</mathjax> is abundant.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">#H_2(g) + Cl_2(g) -> 2HCl(g)+#. If 2 mol of hydrogen gas are mixed with 4 mol of chlorine gas, how many moles of hydrogen chloride will be produced?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="398952" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/martin-m-2"><img alt="" class="" src="https://profilepictures.socratic.org/f0sDBdFaTJCkuFNIfZjD_Profielfoto.PNG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/martin-m-2"> Martin M. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-30T09:25:20" itemprop="dateCreated"> Mar 30, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>4 moles of HCl are produced</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The ratio at which the compounds react with each other are displayed in a chemical reaction as the numbers in front of the compounds. For example in this reaction:</p> <p>1 <mathjax>#H_2#</mathjax> molecule reacts with 1 <mathjax>#Cl_2#</mathjax> molecule<br/> Forming <br/> 2 <mathjax>#HCl#</mathjax> molecules.</p> <p>In chemistry moles are used as a handy number of a certain amount of stuff. You can compare this to a dozen eggs, which is always 12. In the same way 1 mol is the number <mathjax>#6.02210^(23)#</mathjax>. This number tells us how many particles there are. So in 1 mol there are <mathjax>#6.02210^(23)#</mathjax> particles. This number is also referred to as the constant of Avogadro.</p> <p>In the question the amount of moles for <mathjax>#H_2#</mathjax> and for <mathjax>#Cl_2#</mathjax> are given. We have to calculate how much <mathjax>#HCl#</mathjax> is produced with both these values. Therefore 2 calculations needs to be done.</p> <p>Because moles just tells us something about the amount of particles we can use the ratio of the reaction to calculate how many <mathjax>#HCl#</mathjax> will be produced.</p> <p>We start of with the 2 moles of hydrogen gas. We know the following now:<br/> 1 mole of <mathjax>#H_2#</mathjax> gives 2 moles of <mathjax>#HCl#</mathjax><br/> Therefore <br/> 2 moles of <mathjax>#H_2#</mathjax> gives 4 moles of <mathjax>#HCl#</mathjax></p> <p>Now this same calculation can be done for the <mathjax>#Cl_2#</mathjax>:<br/> 1 mole of <mathjax>#Cl_2#</mathjax> reacts to 2 moles of <mathjax>#HCl#</mathjax>, therefore<br/> 4 moles of <mathjax>#Cl_2#</mathjax> reacts to 8 moles of <mathjax>#HCl#</mathjax>.</p> <p>Now we see we have 2 different amount of moles for <mathjax>#HCl#</mathjax> and the question now is which one should we use? <br/> We must now look at which one of above reactions can occur? So for the 2 moles of <mathjax>#H_2#</mathjax>, we can calculate with the ratio that:<br/> 2 moles of <mathjax>#H_2#</mathjax> reacts with 2 moles of <mathjax>#Cl_2#</mathjax>. <br/> We do have 2 moles of <mathjax>#Cl_2#</mathjax> available!</p> <p>Let's see the other one<br/> 4 moles of <mathjax>#Cl_2#</mathjax> reacts with 4 moles of <mathjax>#H_2#</mathjax><br/> But we do not have 4 moles of <mathjax>#H_2#</mathjax>!! </p> <p>Therefore we can only make 4 moles of <mathjax>#HCl#</mathjax> instead of 8 moles.</p> <p>This situation can be stated as following: The <mathjax>#Cl_2#</mathjax> is abundant.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/398952" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 17540 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	#H_2(g) + Cl_2(g) -> 2HCl(g)+#. If 2 mol of hydrogen gas are mixed with 4 mol of chlorine gas, how many moles of hydrogen chloride will be produced?	null
2,005	aa518088-6ddd-11ea-961e-ccda262736ce	https://socratic.org/questions/what-is-the-oxidation-number-of-s-in-h2so3	+4	start physical_unit 6 6 oxidation_number none qc_end chemical_equation 8 8 qc_end end	[{"type":"physical unit","value":"Oxidation number [OF] S"}]	[{"type":"physical unit","value":"+4"}]	[{"type":"chemical equation","value":"H2SO3"}]	<h1 class="questionTitle" itemprop="name">What is the oxidation number of S in H2SO3?</h1>	null	+4	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We start of by giving the oxidation number for hydrogen and oxygen, since we know these already.<br/> So we have 2 hydrogen which each has a charge of <mathjax>#+1#</mathjax>, and we have 3 oxygen which each has a charge of <mathjax>#-2#</mathjax>. If we cancel these out we would have that sulfur should have a charge of <mathjax>#+4#</mathjax> to give a total charge of <mathjax>#0#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#+4#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We start of by giving the oxidation number for hydrogen and oxygen, since we know these already.<br/> So we have 2 hydrogen which each has a charge of <mathjax>#+1#</mathjax>, and we have 3 oxygen which each has a charge of <mathjax>#-2#</mathjax>. If we cancel these out we would have that sulfur should have a charge of <mathjax>#+4#</mathjax> to give a total charge of <mathjax>#0#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the oxidation number of S in H2SO3?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#electrochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Electrochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/electrochemistry/oxidation-numbers" itemprop="url"> <span class="breadcrumb" itemprop="title">Oxidation Numbers</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="596089" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/reza"><img alt="" class="" src="https://profilepictures.socratic.org/NoWrR4NeTkGIR65BT6As_PowerTowerdrawing.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/reza"> Shulgin </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-04-16T17:54:24" itemprop="dateCreated"> Apr 16, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#+4#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We start of by giving the oxidation number for hydrogen and oxygen, since we know these already.<br/> So we have 2 hydrogen which each has a charge of <mathjax>#+1#</mathjax>, and we have 3 oxygen which each has a charge of <mathjax>#-2#</mathjax>. If we cancel these out we would have that sulfur should have a charge of <mathjax>#+4#</mathjax> to give a total charge of <mathjax>#0#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/596089" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-relate-to-electron-configuration"> How do oxidation numbers relate to electron configuration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-relate-to-valence-electrons"> How do oxidation numbers relate to valence electrons? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-vary-with-the-periodic-table"> How do oxidation numbers vary with the periodic table? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-oxidation-number-of-an-element-in-a-compound"> How do you calculate the oxidation number of an element in a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-sulfur"> What is the oxidation number for sulfur? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-carbon"> What is the oxidation number for carbon? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-copper"> What is the oxidation number for copper? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-nitrogen"> What is the oxidation number for nitrogen? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-oxygen"> What is the oxidation number for oxygen? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-oxidation-state-of-noble-gas-zero"> Why is the oxidation state of noble gas zero? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/electrochemistry/oxidation-numbers"> See all questions in Oxidation Numbers </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 37220 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the oxidation number of S in H2SO3?	null
2,006	a8545c64-6ddd-11ea-9f23-ccda262736ce	https://socratic.org/questions/a-compound-that-contains-just-c-h-and-n-is-burned-in-oxygen-when-5-000-g-of-the-	C2H7N3	start chemical_formula qc_end c_other OTHER qc_end c_other OTHER qc_end physical_unit 17 18 14 15 mass qc_end physical_unit 27 27 24 25 mass qc_end physical_unit 31 31 28 29 mass qc_end physical_unit 36 36 33 34 mass qc_end end	[{"type":"other","value":"Chemical Formula [OF] a compound [IN] empirical"}]	[{"type":"chemical equation","value":"C2H7N3"}]	[{"type":"other","value":"A compound that contains just C, H and N."},{"type":"other","value":"When the compound is burned in excess oxygen, CO2, H2O, and NO2 are the only products."},{"type":"physical unit","value":"Mass [OF] the compound [=] \\pu{5.000 g}"},{"type":"physical unit","value":"Mass [OF] CO2 [=] \\pu{6.019 g}"},{"type":"physical unit","value":"Mass [OF] H2O [=] \\pu{4.313 g}"},{"type":"physical unit","value":"Mass [OF] NO2 [=] \\pu{9.438 g}"}]	<h1 class="questionTitle" itemprop="name">)A compound that contains just C, H and N is burned in oxygen. When 5.000 g of the compound is burned in excess oxygen, 6.019 g of #CO_2#, 4.313 g of #H_2O#, and 9.438g of #NO_2# are the only products. What is the empirical formula of the compound?</h1>	null	C2H7N3	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>We must calculate the masses of <mathjax>#"C, H"#</mathjax>, and <mathjax>#"N"#</mathjax> from the masses of carbon dioxide, water, and nitrogen dioxide.</p> <p><mathjax>#"Mass of C" = 6.019 color(red)(cancel(color(black)("g CO"_2))) × "12.01 g C"/(44.01 color(red)(cancel(color(black)("g CO"_2)))) = "1.6425 g C"#</mathjax></p> <p><mathjax>#"Mass of H" = 4.313 color(red)(cancel(color(black)("g H"_2"O"))) × "2.016 g H"/(18.02 color(red)(cancel(color(black)("g H"_2"O")))) = "0.482 52 g H"#</mathjax></p> <p><mathjax>#"Mass of N" = 9.438 color(red)(cancel(color(black)("g NO"_2))) × "14.01 g C"/(46.01 color(red)(cancel(color(black)("g NO"_2)))) = "2.8739 g N"#</mathjax></p> <blockquote></blockquote> <p>Now, we must <strong>convert these masses to moles</strong> and <strong>find their ratios</strong>.</p> <p>From here on, I like to summarize the calculations in a table.</p> <p><mathjax>#ulbb("Element"color(white)(X) "Mass/g"color(white)(X) "Amt/mol"color(white)(m) "Ratio"color(white)(ml)×2color(white)(m)"Integers")#</mathjax><br/> <mathjax>#color(white)(mm)"C"color(white)(mmml)1.6425color(white)(mml)"0.136 76"color(white)(Xm)1color(white)(mmmll)2color(white)(Xmmmm)2#</mathjax><br/> <mathjax>#color(white)(mm)"H" color(white)(XXXl)0.48252 color(white)(mll)"0.478 69" color(white)(mm)3.5001 color(white)(ml)7.0002color(white)(Xml)7#</mathjax><br/> <mathjax>#color(white)(mm)"N" color(white)(XXXl)2.8739 color(white)(mml)"0.205 13" color(white)(mm)1.4999 color(white)(ml)2.9997color(white)(Xml)3#</mathjax></p> <p>The <strong>empirical formula</strong> is <mathjax>#"C"_2"H"_7"N"_3#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><blockquote></blockquote> <p>The empirical formula is <mathjax>#"C"_2"H"_7"N"_3#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>We must calculate the masses of <mathjax>#"C, H"#</mathjax>, and <mathjax>#"N"#</mathjax> from the masses of carbon dioxide, water, and nitrogen dioxide.</p> <p><mathjax>#"Mass of C" = 6.019 color(red)(cancel(color(black)("g CO"_2))) × "12.01 g C"/(44.01 color(red)(cancel(color(black)("g CO"_2)))) = "1.6425 g C"#</mathjax></p> <p><mathjax>#"Mass of H" = 4.313 color(red)(cancel(color(black)("g H"_2"O"))) × "2.016 g H"/(18.02 color(red)(cancel(color(black)("g H"_2"O")))) = "0.482 52 g H"#</mathjax></p> <p><mathjax>#"Mass of N" = 9.438 color(red)(cancel(color(black)("g NO"_2))) × "14.01 g C"/(46.01 color(red)(cancel(color(black)("g NO"_2)))) = "2.8739 g N"#</mathjax></p> <blockquote></blockquote> <p>Now, we must <strong>convert these masses to moles</strong> and <strong>find their ratios</strong>.</p> <p>From here on, I like to summarize the calculations in a table.</p> <p><mathjax>#ulbb("Element"color(white)(X) "Mass/g"color(white)(X) "Amt/mol"color(white)(m) "Ratio"color(white)(ml)×2color(white)(m)"Integers")#</mathjax><br/> <mathjax>#color(white)(mm)"C"color(white)(mmml)1.6425color(white)(mml)"0.136 76"color(white)(Xm)1color(white)(mmmll)2color(white)(Xmmmm)2#</mathjax><br/> <mathjax>#color(white)(mm)"H" color(white)(XXXl)0.48252 color(white)(mll)"0.478 69" color(white)(mm)3.5001 color(white)(ml)7.0002color(white)(Xml)7#</mathjax><br/> <mathjax>#color(white)(mm)"N" color(white)(XXXl)2.8739 color(white)(mml)"0.205 13" color(white)(mm)1.4999 color(white)(ml)2.9997color(white)(Xml)3#</mathjax></p> <p>The <strong>empirical formula</strong> is <mathjax>#"C"_2"H"_7"N"_3#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">)A compound that contains just C, H and N is burned in oxygen. When 5.000 g of the compound is burned in excess oxygen, 6.019 g of #CO_2#, 4.313 g of #H_2O#, and 9.438g of #NO_2# are the only products. What is the empirical formula of the compound?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="475401" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-09-14T15:48:52" itemprop="dateCreated"> Sep 14, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><blockquote></blockquote> <p>The empirical formula is <mathjax>#"C"_2"H"_7"N"_3#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>We must calculate the masses of <mathjax>#"C, H"#</mathjax>, and <mathjax>#"N"#</mathjax> from the masses of carbon dioxide, water, and nitrogen dioxide.</p> <p><mathjax>#"Mass of C" = 6.019 color(red)(cancel(color(black)("g CO"_2))) × "12.01 g C"/(44.01 color(red)(cancel(color(black)("g CO"_2)))) = "1.6425 g C"#</mathjax></p> <p><mathjax>#"Mass of H" = 4.313 color(red)(cancel(color(black)("g H"_2"O"))) × "2.016 g H"/(18.02 color(red)(cancel(color(black)("g H"_2"O")))) = "0.482 52 g H"#</mathjax></p> <p><mathjax>#"Mass of N" = 9.438 color(red)(cancel(color(black)("g NO"_2))) × "14.01 g C"/(46.01 color(red)(cancel(color(black)("g NO"_2)))) = "2.8739 g N"#</mathjax></p> <blockquote></blockquote> <p>Now, we must <strong>convert these masses to moles</strong> and <strong>find their ratios</strong>.</p> <p>From here on, I like to summarize the calculations in a table.</p> <p><mathjax>#ulbb("Element"color(white)(X) "Mass/g"color(white)(X) "Amt/mol"color(white)(m) "Ratio"color(white)(ml)×2color(white)(m)"Integers")#</mathjax><br/> <mathjax>#color(white)(mm)"C"color(white)(mmml)1.6425color(white)(mml)"0.136 76"color(white)(Xm)1color(white)(mmmll)2color(white)(Xmmmm)2#</mathjax><br/> <mathjax>#color(white)(mm)"H" color(white)(XXXl)0.48252 color(white)(mll)"0.478 69" color(white)(mm)3.5001 color(white)(ml)7.0002color(white)(Xml)7#</mathjax><br/> <mathjax>#color(white)(mm)"N" color(white)(XXXl)2.8739 color(white)(mml)"0.205 13" color(white)(mm)1.4999 color(white)(ml)2.9997color(white)(Xml)3#</mathjax></p> <p>The <strong>empirical formula</strong> is <mathjax>#"C"_2"H"_7"N"_3#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/475401" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? 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</a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-empirical-formula-not-double-that-of-the-monosaccharides"> Why is the empirical formula not double that of the monosaccharides? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5331180502bf342f40b5c3b5"> Question #5c3b5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-molecular-formula-represents-a-carbohydrate"> What molecular formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-of-vinegar"> What is the molecular formula of vinegar? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/empirical-and-molecular-formulas"> See all questions in Empirical and Molecular Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3025 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	)A compound that contains just C, H and N is burned in oxygen. When 5.000 g of the compound is burned in excess oxygen, 6.019 g of #CO_2#, 4.313 g of #H_2O#, and 9.438g of #NO_2# are the only products. What is the empirical formula of the compound?	null
2,007	aab40178-6ddd-11ea-8064-ccda262736ce	https://socratic.org/questions/what-is-the-mass-in-grams-of-1-24-mol-of-water-h-2o	22.34 grams	start physical_unit 11 11 mass g qc_end physical_unit 11 11 7 8 mole qc_end end	[{"type":"physical unit","value":"Mass [OF] H2O [IN] grams"}]	[{"type":"physical unit","value":"22.34 grams"}]	[{"type":"physical unit","value":"Mole [OF] H2O [=] \\pu{1.24 moles}"}]	<h1 class="questionTitle" itemprop="name">What is the mass, in grams, of #1.24# moles of water, #"H"_2"O"# ?</h1>	null	22.34 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your tool of choice here is the <strong>molar mass</strong> of water. The molar mass of a compound tells you the mass of exactly <mathjax>#1#</mathjax> <strong>mole</strong> of that compound. </p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)("the molar mass of H"_2"O" = "the mass of 1 mole of H"_2"O")))#</mathjax></p> </blockquote> <p>Now, water has a molar mass of <mathjax>#"18.015 g mol"^(-1)#</mathjax>. This tells you that <mathjax>#1#</mathjax> <strong>mole</strong> of water has a mass of <mathjax>#"18.015 g"#</mathjax>. So every time your sample of water has a mass of <mathjax>#"18.015 g"#</mathjax>, you can say for a fact that it contains <mathjax>#1#</mathjax> <strong>mole</strong> of water. </p> <p>In your case, the sample contains <mathjax>#1.24#</mathjax> <strong>moles</strong> of water. To find the mass of the sample, use the molar mass of water as a <strong>conversion factor</strong>. </p> <p>You need to go from <em>moles</em> to <em>grams</em>, so rearrange the molar mass like this</p> <blockquote> <p><mathjax>#"18.015 g mol"^(-1) => "18.015 g"/("1 mole H"_2"O") " "color(white)((color(blue)(larr \ "what you need"))/(color(blue)(larr \ "what you have"))#</mathjax></p> </blockquote> <p>So now all you have to do is to multiply the number of moles given to you by this conversion factor.</p> <blockquote> <p><mathjax>#1.24 color(red)(cancel(color(black)("moles H"_2"O"))) * "18.015 g"/(1 color(red)(cancel(color(black)("mole H"_2"O")))) = color(darkgreen)(ul(color(black)("22.3 g")))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the number of moles of water. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"22.3 g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your tool of choice here is the <strong>molar mass</strong> of water. The molar mass of a compound tells you the mass of exactly <mathjax>#1#</mathjax> <strong>mole</strong> of that compound. </p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)("the molar mass of H"_2"O" = "the mass of 1 mole of H"_2"O")))#</mathjax></p> </blockquote> <p>Now, water has a molar mass of <mathjax>#"18.015 g mol"^(-1)#</mathjax>. This tells you that <mathjax>#1#</mathjax> <strong>mole</strong> of water has a mass of <mathjax>#"18.015 g"#</mathjax>. So every time your sample of water has a mass of <mathjax>#"18.015 g"#</mathjax>, you can say for a fact that it contains <mathjax>#1#</mathjax> <strong>mole</strong> of water. </p> <p>In your case, the sample contains <mathjax>#1.24#</mathjax> <strong>moles</strong> of water. To find the mass of the sample, use the molar mass of water as a <strong>conversion factor</strong>. </p> <p>You need to go from <em>moles</em> to <em>grams</em>, so rearrange the molar mass like this</p> <blockquote> <p><mathjax>#"18.015 g mol"^(-1) => "18.015 g"/("1 mole H"_2"O") " "color(white)((color(blue)(larr \ "what you need"))/(color(blue)(larr \ "what you have"))#</mathjax></p> </blockquote> <p>So now all you have to do is to multiply the number of moles given to you by this conversion factor.</p> <blockquote> <p><mathjax>#1.24 color(red)(cancel(color(black)("moles H"_2"O"))) * "18.015 g"/(1 color(red)(cancel(color(black)("mole H"_2"O")))) = color(darkgreen)(ul(color(black)("22.3 g")))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the number of moles of water. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the mass, in grams, of #1.24# moles of water, #"H"_2"O"# ?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="584978" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-03-29T22:53:06" itemprop="dateCreated"> Mar 29, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"22.3 g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your tool of choice here is the <strong>molar mass</strong> of water. The molar mass of a compound tells you the mass of exactly <mathjax>#1#</mathjax> <strong>mole</strong> of that compound. </p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)("the molar mass of H"_2"O" = "the mass of 1 mole of H"_2"O")))#</mathjax></p> </blockquote> <p>Now, water has a molar mass of <mathjax>#"18.015 g mol"^(-1)#</mathjax>. This tells you that <mathjax>#1#</mathjax> <strong>mole</strong> of water has a mass of <mathjax>#"18.015 g"#</mathjax>. So every time your sample of water has a mass of <mathjax>#"18.015 g"#</mathjax>, you can say for a fact that it contains <mathjax>#1#</mathjax> <strong>mole</strong> of water. </p> <p>In your case, the sample contains <mathjax>#1.24#</mathjax> <strong>moles</strong> of water. To find the mass of the sample, use the molar mass of water as a <strong>conversion factor</strong>. </p> <p>You need to go from <em>moles</em> to <em>grams</em>, so rearrange the molar mass like this</p> <blockquote> <p><mathjax>#"18.015 g mol"^(-1) => "18.015 g"/("1 mole H"_2"O") " "color(white)((color(blue)(larr \ "what you need"))/(color(blue)(larr \ "what you have"))#</mathjax></p> </blockquote> <p>So now all you have to do is to multiply the number of moles given to you by this conversion factor.</p> <blockquote> <p><mathjax>#1.24 color(red)(cancel(color(black)("moles H"_2"O"))) * "18.015 g"/(1 color(red)(cancel(color(black)("mole H"_2"O")))) = color(darkgreen)(ul(color(black)("22.3 g")))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the number of moles of water. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/584978" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 46966 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the mass, in grams, of #1.24# moles of water, #"H"_2"O"# ?	null
2,008	abf3d6b4-6ddd-11ea-8ee1-ccda262736ce	https://socratic.org/questions/how-many-co-2-molecules-are-there-in-10-0-mol-of-carbon-dioxide	6.02 × 10^24	start physical_unit 2 3 number none qc_end physical_unit 10 11 7 8 mole qc_end end	[{"type":"physical unit","value":"Number [OF] CO2 molecules"}]	[{"type":"physical unit","value":"6.02 × 10^24"}]	[{"type":"physical unit","value":"Mole [OF] carbon dioxide [=] \\pu{10.0 mol}"}]	<h1 class="questionTitle" itemprop="name">How many #CO_2# molecules are there in 10.0 mol of carbon dioxide?</h1>	null	6.02 × 10^24	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Since there are <mathjax>#6.0210^23#</mathjax> molecules in a mole, in <mathjax>#10#</mathjax> moles of carbon dioxide, there will be:</p> <p><mathjax>#106.0210^23=6.0210^24#</mathjax> carbon dioxide molecules</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Exactly <mathjax>#10N_A#</mathjax> molecules.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Since there are <mathjax>#6.0210^23#</mathjax> molecules in a mole, in <mathjax>#10#</mathjax> moles of carbon dioxide, there will be:</p> <p><mathjax>#106.0210^23=6.02*10^24#</mathjax> carbon dioxide molecules</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many #CO_2# molecules are there in 10.0 mol of carbon dioxide?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="626017" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/nam-d"><img alt="" class="" src="https://profilepictures.socratic.org/QG4MnkoER6u99DIDVWKK_787554714770341.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/nam-d"> Nam D. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-06-06T00:21:44" itemprop="dateCreated"> Jun 6, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Exactly <mathjax>#10N_A#</mathjax> molecules.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Since there are <mathjax>#6.0210^23#</mathjax> molecules in a mole, in <mathjax>#10#</mathjax> moles of carbon dioxide, there will be:</p> <p><mathjax>#106.0210^23=6.02*10^24#</mathjax> carbon dioxide molecules</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/626017" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 6008 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many #CO_2# molecules are there in 10.0 mol of carbon dioxide?	null
2,009	a8e41da6-6ddd-11ea-9965-ccda262736ce	https://socratic.org/questions/6-li-ca3-bo3-2-3-ca-2-li3bo3-how-many-grams-of-calcium-metal-would-be-produced-i	5.05 grams	start physical_unit 14 15 mass g qc_end physical_unit 28 29 25 26 mass qc_end chemical_equation 0 9 qc_end end	[{"type":"physical unit","value":"Mass [OF] calcium metal [IN] grams"}]	[{"type":"physical unit","value":"5.05 grams"}]	[{"type":"physical unit","value":"Mass [OF] calcium borate [=] \\pu{10 grams}"},{"type":"chemical equation","value":"6 Li + Ca3(BO3)2 -> 3 Ca + 2 Li3BO3"}]	<h1 class="questionTitle" itemprop="name">6 Li + Ca3(BO3)2 ---> 3 Ca + 2 Li3BO3 How many grams of calcium metal would be produced if you started the reaction with 10 grams of calcium borate?</h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>How much of the excess reactant would be left over at the end of the reaction?</p></div> </h2> </div> </div>	5.05 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#MM Ca_3(BO_3)_2= 40 xx 3 + (10,8 + 16 xx3) xx 2 = 120 + 117,6 =237,6 g/(mol)#</mathjax><br/> You have to do a proportion: from 1 mol of calcium borate (237,6 g) you obtain 3 mol of calcium atoms (120 g), so from 10 g of calcium borate you obtain <mathjax>#10 g xx 120/237.6=5.05 g#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>5,05 g</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#MM Ca_3(BO_3)_2= 40 xx 3 + (10,8 + 16 xx3) xx 2 = 120 + 117,6 =237,6 g/(mol)#</mathjax><br/> You have to do a proportion: from 1 mol of calcium borate (237,6 g) you obtain 3 mol of calcium atoms (120 g), so from 10 g of calcium borate you obtain <mathjax>#10 g xx 120/237.6=5.05 g#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">6 Li + Ca3(BO3)2 ---> 3 Ca + 2 Li3BO3 How many grams of calcium metal would be produced if you started the reaction with 10 grams of calcium borate?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>How much of the excess reactant would be left over at the end of the reaction?</p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="608706" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/andrea-b-3"><img alt="" class="" src="https://graph.facebook.com/100000553538995/picture?height=50&width=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/andrea-b-3"> Andrea B. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-05-07T05:45:10" itemprop="dateCreated"> May 7, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>5,05 g</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#MM Ca_3(BO_3)_2= 40 xx 3 + (10,8 + 16 xx3) xx 2 = 120 + 117,6 =237,6 g/(mol)#</mathjax><br/> You have to do a proportion: from 1 mol of calcium borate (237,6 g) you obtain 3 mol of calcium atoms (120 g), so from 10 g of calcium borate you obtain <mathjax>#10 g xx 120/237.6=5.05 g#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/608706" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> 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How much of the excess reactant would be left over at the end of the reaction?
2,010	aba4aa12-6ddd-11ea-bc04-ccda262736ce	https://socratic.org/questions/an-air-sample-contains-0-038-co-2-if-the-total-pressure-is-758-mm-hg-what-is-the	0.29 mmHg	start physical_unit 5 5 partial_pressure mmhg qc_end physical_unit 1 2 11 12 total_pressure qc_end end	[{"type":"physical unit","value":"Partial pressure [OF] CO2 [IN] mmHg"}]	[{"type":"physical unit","value":"0.29 mmHg"}]	[{"type":"physical unit","value":"Percent [OF] CO2 in air sample [=] \\pu{0.038%}"},{"type":"physical unit","value":"Total pressure [OF] air sample [=] \\pu{758 mmHg}"}]	<h1 class="questionTitle" itemprop="name">An air sample contains 0.038% #CO_2#. If the total pressure is 758 mm Hg, what is the partial pressure of #CO_2#?</h1>	null	0.29 mmHg	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Given <mathjax>#0.038%#</mathjax> (mole/mole) => <mathjax>#X_(CO_2)#</mathjax> = <mathjax>#(0.0038"mole" CO_2)/(100"moles"AIR")#</mathjax> = <mathjax>#0.00038#</mathjax></p> <p><mathjax>#X_(CO_2)#</mathjax> = <mathjax>#P_(CO_2)/P_"Total"#</mathjax> => <mathjax>#P_(CO_2)#</mathjax>= <mathjax>#X_(CO_2)#</mathjax><mathjax>#dot#</mathjax><mathjax>#P_(CO_2)#</mathjax> </p> <p>= <mathjax>#0.00038(758"mmHg"#</mathjax>)=<mathjax>#0.288"mmHg"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#P_(CO_2)#</mathjax> = <mathjax>#0.288"mmHg"#</mathjax> if <mathjax>#%CO_2#</mathjax> is mole percent. If <mathjax>#%CO_2#</mathjax> is weight percent then one will need the mass values of the other components of the air mixture. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Given <mathjax>#0.038%#</mathjax> (mole/mole) => <mathjax>#X_(CO_2)#</mathjax> = <mathjax>#(0.0038"mole" CO_2)/(100"moles"AIR")#</mathjax> = <mathjax>#0.00038#</mathjax></p> <p><mathjax>#X_(CO_2)#</mathjax> = <mathjax>#P_(CO_2)/P_"Total"#</mathjax> => <mathjax>#P_(CO_2)#</mathjax>= <mathjax>#X_(CO_2)#</mathjax><mathjax>#dot#</mathjax><mathjax>#P_(CO_2)#</mathjax> </p> <p>= <mathjax>#0.00038(758"mmHg"#</mathjax>)=<mathjax>#0.288"mmHg"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">An air sample contains 0.038% #CO_2#. If the total pressure is 758 mm Hg, what is the partial pressure of #CO_2#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/partial-pressure" itemprop="url"> <span class="breadcrumb" itemprop="title">Partial Pressure</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="528138" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/doc048"><img alt="" class="" src="https://profilepictures.socratic.org/e4gaeUMMQESTpfte6aRu_Friendly%20Chem%20Professor.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/doc048"> Doc048 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-12-30T02:29:07" itemprop="dateCreated"> Dec 30, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#P_(CO_2)#</mathjax> = <mathjax>#0.288"mmHg"#</mathjax> if <mathjax>#%CO_2#</mathjax> is mole percent. If <mathjax>#%CO_2#</mathjax> is weight percent then one will need the mass values of the other components of the air mixture. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Given <mathjax>#0.038%#</mathjax> (mole/mole) => <mathjax>#X_(CO_2)#</mathjax> = <mathjax>#(0.0038"mole" CO_2)/(100"moles"AIR")#</mathjax> = <mathjax>#0.00038#</mathjax></p> <p><mathjax>#X_(CO_2)#</mathjax> = <mathjax>#P_(CO_2)/P_"Total"#</mathjax> => <mathjax>#P_(CO_2)#</mathjax>= <mathjax>#X_(CO_2)#</mathjax><mathjax>#dot#</mathjax><mathjax>#P_(CO_2)#</mathjax> </p> <p>= <mathjax>#0.00038(758"mmHg"#</mathjax>)=<mathjax>#0.288"mmHg"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/528138" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/534e256802bf342adfa30010"> How do you do a steam distillation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/53613f9f02bf3416cd9f8a34"> Question #f8a34 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-i-calculate-the-total-pressure-of-a-mixture-of-gases-by-adding-together-the-"> Can I calculate the total pressure of a mixture of gases by adding together the partial... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-formula-of-partial-pressure"> What is the formula of partial pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-dalton-s-law-of-partial-pressures"> What is the Dalton's law of partial pressures? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/nitrogen-gas-n2-reacts-with-hydrogen-gas-h2-to-form-ammonia-nh3-at-200-c-in-a-cl"> Nitrogen gas (N2) reacts with hydrogen gas (H2) to form ammonia (NH3). 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If the total pressure is 758 mm Hg, what is the partial pressure of #CO_2#?	null
2,011	a886c9c2-6ddd-11ea-af06-ccda262736ce	https://socratic.org/questions/900-kg-water-have-t1-40-c-t2-0c-and-t3-5-c-how-much-energy-is-needed-to-melt-thi	395 MJ	start physical_unit 2 2 energy mj qc_end physical_unit 2 2 0 1 mass qc_end physical_unit 2 2 6 7 temperature qc_end physical_unit 2 2 10 11 temperature qc_end physical_unit 2 2 15 16 temperature qc_end physical_unit 2 2 29 30 melted_time qc_end end	[{"type":"physical unit","value":"Needed energy [OF] water [IN] MJ"}]	[{"type":"physical unit","value":"395 MJ"}]	[{"type":"physical unit","value":"Mass [OF] water [=] \\pu{900 Kg}"},{"type":"physical unit","value":"Temperature1 [OF] water [=] \\pu{-40 ℃}"},{"type":"physical unit","value":"Temperature2 [OF] water [=] \\pu{0 ℃}"},{"type":"physical unit","value":"Temperature3 [OF] water [=] \\pu{5 ℃}"},{"type":"physical unit","value":"melted time [OF] water [=] \\pu{2 hours}"}]	<h1 class="questionTitle" itemprop="name">900 kg water have T1 = -40 C, T2 = 0C and T3 = 5 C, How much energy is needed to melt this mass of water in 2 hours? Thank you so much. </h1>	null	395 MJ	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>There are three heat transfers involved.</p> <p><mathjax>#q = "heat to warm ice" + "heat to melt ice" + "heat to warm water"#</mathjax></p> <p><mathjax>#q = q_1 + q_2 +q_3#</mathjax></p> <blockquote></blockquote> <p>The <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> capacity of ice is <mathjax>#"2090 J·kg"^"-1""°C"^"-1"#</mathjax></p> <p><mathjax>#q_1 = mcΔT = 900 color(red)(cancel(color(black)("kg"))) ×" 2090 J"·color(red)(cancel(color(black)("kg"^"-1""°C"^"-1"))) × 40 color(red)(cancel(color(black)("°C"))) = "75 200 000 J" = "75.2 MJ"#</mathjax></p> <blockquote></blockquote> <p>The heat of fusion of ice is 334 kJ/kg.</p> <p><mathjax>#q_2 =mΔ_"fus"H^° = 900 color(red)(cancel(color(black)("kg"))) × "334 kJ"·color(red)(cancel(color(black)("kg"^"-1"))) = "300 600 kJ" = "300.6 MJ"#</mathjax></p> <blockquote></blockquote> <p>The specific heat capacity of water is <mathjax>#"4181 J·kg"^"-1""°C"^"-1"#</mathjax>.</p> <p><mathjax>#q_3 = mcΔT = 900 color(red)(cancel(color(black)("kg"))) × "4181 J"·color(red)(cancel(color(black)("kg"^"-1""°C"^"-1"))) × 5 color(red)(cancel(color(black)("°C"))) = "19 000 000 J" = "19 MJ"#</mathjax>.</p> <blockquote></blockquote> <p><mathjax>#q = q_1 + q_2 + q_3 = "(75.2 + 300.6 + 19) MJ" = "395 MJ"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>You will need to use 395 MJ of energy. The amount of time is immaterial.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>There are three heat transfers involved.</p> <p><mathjax>#q = "heat to warm ice" + "heat to melt ice" + "heat to warm water"#</mathjax></p> <p><mathjax>#q = q_1 + q_2 +q_3#</mathjax></p> <blockquote></blockquote> <p>The <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> capacity of ice is <mathjax>#"2090 J·kg"^"-1""°C"^"-1"#</mathjax></p> <p><mathjax>#q_1 = mcΔT = 900 color(red)(cancel(color(black)("kg"))) ×" 2090 J"·color(red)(cancel(color(black)("kg"^"-1""°C"^"-1"))) × 40 color(red)(cancel(color(black)("°C"))) = "75 200 000 J" = "75.2 MJ"#</mathjax></p> <blockquote></blockquote> <p>The heat of fusion of ice is 334 kJ/kg.</p> <p><mathjax>#q_2 =mΔ_"fus"H^° = 900 color(red)(cancel(color(black)("kg"))) × "334 kJ"·color(red)(cancel(color(black)("kg"^"-1"))) = "300 600 kJ" = "300.6 MJ"#</mathjax></p> <blockquote></blockquote> <p>The specific heat capacity of water is <mathjax>#"4181 J·kg"^"-1""°C"^"-1"#</mathjax>.</p> <p><mathjax>#q_3 = mcΔT = 900 color(red)(cancel(color(black)("kg"))) × "4181 J"·color(red)(cancel(color(black)("kg"^"-1""°C"^"-1"))) × 5 color(red)(cancel(color(black)("°C"))) = "19 000 000 J" = "19 MJ"#</mathjax>.</p> <blockquote></blockquote> <p><mathjax>#q = q_1 + q_2 + q_3 = "(75.2 + 300.6 + 19) MJ" = "395 MJ"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">900 kg water have T1 = -40 C, T2 = 0C and T3 = 5 C, How much energy is needed to melt this mass of water in 2 hours? Thank you so much. </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/calorimetry" itemprop="url"> <span class="breadcrumb" itemprop="title">Calorimetry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="288534" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-16T00:59:30" itemprop="dateCreated"> Jul 16, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>You will need to use 395 MJ of energy. The amount of time is immaterial.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>There are three heat transfers involved.</p> <p><mathjax>#q = "heat to warm ice" + "heat to melt ice" + "heat to warm water"#</mathjax></p> <p><mathjax>#q = q_1 + q_2 +q_3#</mathjax></p> <blockquote></blockquote> <p>The <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> capacity of ice is <mathjax>#"2090 J·kg"^"-1""°C"^"-1"#</mathjax></p> <p><mathjax>#q_1 = mcΔT = 900 color(red)(cancel(color(black)("kg"))) ×" 2090 J"·color(red)(cancel(color(black)("kg"^"-1""°C"^"-1"))) × 40 color(red)(cancel(color(black)("°C"))) = "75 200 000 J" = "75.2 MJ"#</mathjax></p> <blockquote></blockquote> <p>The heat of fusion of ice is 334 kJ/kg.</p> <p><mathjax>#q_2 =mΔ_"fus"H^° = 900 color(red)(cancel(color(black)("kg"))) × "334 kJ"·color(red)(cancel(color(black)("kg"^"-1"))) = "300 600 kJ" = "300.6 MJ"#</mathjax></p> <blockquote></blockquote> <p>The specific heat capacity of water is <mathjax>#"4181 J·kg"^"-1""°C"^"-1"#</mathjax>.</p> <p><mathjax>#q_3 = mcΔT = 900 color(red)(cancel(color(black)("kg"))) × "4181 J"·color(red)(cancel(color(black)("kg"^"-1""°C"^"-1"))) × 5 color(red)(cancel(color(black)("°C"))) = "19 000 000 J" = "19 MJ"#</mathjax>.</p> <blockquote></blockquote> <p><mathjax>#q = q_1 + q_2 + q_3 = "(75.2 + 300.6 + 19) MJ" = "395 MJ"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/288534" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-differential-scanning-in-calorimetry-work"> How does differential scanning in calorimetry work? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-read-differential-scanning-in-calorimetry"> What information do you get from a differential scanning calorimetry plot? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-measure-calorimetry"> How do you measure calorimetry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531d304102bf341e75b962a7"> Question #962a7 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5335021802bf344ae911dfc5"> Question #1dfc5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/533668f502bf34572c341af6"> Question #41af6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-definition-of-calorimetry"> What is calorimetry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-differential-scanning-calorimeter"> What is a differential scanning calorimeter? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-a-calorimeter-measure-energy"> How can a calorimeter measure energy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-calorimeters-made-of"> What are calorimeters made of? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/calorimetry"> See all questions in Calorimetry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1541 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	900 kg water have T1 = -40 C, T2 = 0C and T3 = 5 C, How much energy is needed to melt this mass of water in 2 hours? Thank you so much.	null
2,012	ac5e645c-6ddd-11ea-8c8f-ccda262736ce	https://socratic.org/questions/if-the-atmospheric-pressure-on-mt-everest-is-one-third-the-atmospheric-pressure-	7.07 kPa	start physical_unit 21 23 partial_pressure kpa qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Partial pressure [OF] oxygen on Everest [IN] kPa"}]	[{"type":"physical unit","value":"7.07 kPa"}]	[{"type":"other","value":"Everest is one-third the atmospheric pressure at sea level."}]	<h1 class="questionTitle" itemprop="name">If the atmospheric pressure on Mt. Everest is one-third the atmospheric pressure at sea level, what is the partial pressure of oxygen on Everest?</h1>	null	7.07 kPa	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The law of partial pressures ensures us that since oxygen accounts for 20.8% of the molecules in the air, it also accounts for 20.8% of the pressure of the air, regardless of what that total pressure might be.</p> <p>So, if <a href="https://socratic.org/chemistry/the-behavior-of-gases/atmospheric-pressure">atmospheric pressure</a> is 102 kPa at sea level (just to choose a convenient value), the partial pressure of the oxygen is <mathjax>#102 xx 0.208= 21.22#</mathjax> kPa.</p> <p>On Everest, the total pressure would be 34 kPa (one-third of 102 kPa), and the partial pressure of the oxygen is <mathjax>#34 xx 0.208= 7.07#</mathjax> kPa.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>It would still be 20.8% of whatever the total pressure was. See my example below, which results in a <a href="https://socratic.org/chemistry/the-behavior-of-gases/partial-pressure">partial pressure</a> of slightly more than 7 kPa.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The law of partial pressures ensures us that since oxygen accounts for 20.8% of the molecules in the air, it also accounts for 20.8% of the pressure of the air, regardless of what that total pressure might be.</p> <p>So, if <a href="https://socratic.org/chemistry/the-behavior-of-gases/atmospheric-pressure">atmospheric pressure</a> is 102 kPa at sea level (just to choose a convenient value), the partial pressure of the oxygen is <mathjax>#102 xx 0.208= 21.22#</mathjax> kPa.</p> <p>On Everest, the total pressure would be 34 kPa (one-third of 102 kPa), and the partial pressure of the oxygen is <mathjax>#34 xx 0.208= 7.07#</mathjax> kPa.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">If the atmospheric pressure on Mt. Everest is one-third the atmospheric pressure at sea level, what is the partial pressure of oxygen on Everest?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/partial-pressure" itemprop="url"> <span class="breadcrumb" itemprop="title">Partial Pressure</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="541930" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/dwight"><img alt="" class="" src="https://profilepictures.socratic.org/ZDiTFWmAQmWOT3sd0Xpr_Dwight.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/dwight"> Dwight </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-01-27T03:35:41" itemprop="dateCreated"> Jan 27, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>It would still be 20.8% of whatever the total pressure was. See my example below, which results in a <a href="https://socratic.org/chemistry/the-behavior-of-gases/partial-pressure">partial pressure</a> of slightly more than 7 kPa.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The law of partial pressures ensures us that since oxygen accounts for 20.8% of the molecules in the air, it also accounts for 20.8% of the pressure of the air, regardless of what that total pressure might be.</p> <p>So, if <a href="https://socratic.org/chemistry/the-behavior-of-gases/atmospheric-pressure">atmospheric pressure</a> is 102 kPa at sea level (just to choose a convenient value), the partial pressure of the oxygen is <mathjax>#102 xx 0.208= 21.22#</mathjax> kPa.</p> <p>On Everest, the total pressure would be 34 kPa (one-third of 102 kPa), and the partial pressure of the oxygen is <mathjax>#34 xx 0.208= 7.07#</mathjax> kPa.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/541930" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/534e256802bf342adfa30010"> How do you do a steam distillation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/53613f9f02bf3416cd9f8a34"> Question #f8a34 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-i-calculate-the-total-pressure-of-a-mixture-of-gases-by-adding-together-the-"> Can I calculate the total pressure of a mixture of gases by adding together the partial... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-formula-of-partial-pressure"> What is the formula of partial pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-dalton-s-law-of-partial-pressures"> What is the Dalton's law of partial pressures? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/nitrogen-gas-n2-reacts-with-hydrogen-gas-h2-to-form-ammonia-nh3-at-200-c-in-a-cl"> Nitrogen gas (N2) reacts with hydrogen gas (H2) to form ammonia (NH3). 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Everest is one-third the atmospheric pressure at sea level, what is the partial pressure of oxygen on Everest?	null
2,013	a853240c-6ddd-11ea-9792-ccda262736ce	https://socratic.org/questions/what-is-the-volume-in-milliliters-of-a-5-01-m-silver-nitrate-solution-that-conta	54.9 milliliters	start physical_unit 10 12 volume ml qc_end physical_unit 10 12 8 9 molarity qc_end physical_unit 10 11 15 16 mole qc_end end	[{"type":"physical unit","value":"Volume [OF] silver nitrate solution [IN] milliliters"}]	[{"type":"physical unit","value":"54.9 milliliters"}]	[{"type":"physical unit","value":"Molarity [OF] silver nitrate solution [=] \\pu{5.01 M}"},{"type":"physical unit","value":"Mole [OF] silver nitrate [=] \\pu{275 mmol}"}]	<h1 class="questionTitle" itemprop="name">What is the volume in milliliters of a 5.01 M silver nitrate solution that contains 275. mmol of silver nitrate?</h1>	null	54.9 milliliters	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>275 mmol is 275 mmole, or expressed as moles 0.275 moles (there are 1000 mmol on a mole).</p> <p>A 5.01 M solution contains 5.01 moles per liter.</p> <p>We have 0.275 moles, which is:</p> <p><mathjax>#0.275 / 5.01#</mathjax> of a liter</p> <p><mathjax>#0.275 / 5.01 = 0.0549 " liters" #</mathjax></p> <p>Hence we have: 0.0549 x 1000 = 54.9 ml.</p> <p>This is a fraction question, and what is most probably causing confusion is the chemistry. </p> <p>If I said you had a cake that had been cut in to 6 slices, and I gave you 1 slice, and asked how much of the cake you had, you would say 1 /6.</p> <p>In the question above we have a cake cut in to 5.01 slices (yes, I know we can't really do that), and I have given you 0.275 of a slice.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>54.9 ml</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>275 mmol is 275 mmole, or expressed as moles 0.275 moles (there are 1000 mmol on a mole).</p> <p>A 5.01 M solution contains 5.01 moles per liter.</p> <p>We have 0.275 moles, which is:</p> <p><mathjax>#0.275 / 5.01#</mathjax> of a liter</p> <p><mathjax>#0.275 / 5.01 = 0.0549 " liters" #</mathjax></p> <p>Hence we have: 0.0549 x 1000 = 54.9 ml.</p> <p>This is a fraction question, and what is most probably causing confusion is the chemistry. </p> <p>If I said you had a cake that had been cut in to 6 slices, and I gave you 1 slice, and asked how much of the cake you had, you would say 1 /6.</p> <p>In the question above we have a cake cut in to 5.01 slices (yes, I know we can't really do that), and I have given you 0.275 of a slice.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the volume in milliliters of a 5.01 M silver nitrate solution that contains 275. mmol of silver nitrate?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/solutions" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="300502" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/nick-41"><img alt="" class="" src="https://profilepictures.socratic.org/Sq1QmKQKSPCfDM110rRn_16.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/nick-41"> Nick </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-08-19T06:40:24" itemprop="dateCreated"> Aug 19, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>54.9 ml</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>275 mmol is 275 mmole, or expressed as moles 0.275 moles (there are 1000 mmol on a mole).</p> <p>A 5.01 M solution contains 5.01 moles per liter.</p> <p>We have 0.275 moles, which is:</p> <p><mathjax>#0.275 / 5.01#</mathjax> of a liter</p> <p><mathjax>#0.275 / 5.01 = 0.0549 " liters" #</mathjax></p> <p>Hence we have: 0.0549 x 1000 = 54.9 ml.</p> <p>This is a fraction question, and what is most probably causing confusion is the chemistry. </p> <p>If I said you had a cake that had been cut in to 6 slices, and I gave you 1 slice, and asked how much of the cake you had, you would say 1 /6.</p> <p>In the question above we have a cake cut in to 5.01 slices (yes, I know we can't really do that), and I have given you 0.275 of a slice.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/300502" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" 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The gram formula weight... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-solutions-differ-from-suspensions"> How do solutions differ from suspensions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-a-solution-differ-from-a-compound"> How does a solution differ from a compound? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/solutions"> See all questions in Solutions </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 4374 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the volume in milliliters of a 5.01 M silver nitrate solution that contains 275. mmol of silver nitrate?	null
2,014	a8a72068-6ddd-11ea-9c4a-ccda262736ce	https://socratic.org/questions/what-is-the-oxidation-number-of-nitrogen-in-n-2o-5	+5	start physical_unit 6 8 oxidation_number none qc_end chemical_equation 8 8 qc_end end	[{"type":"physical unit","value":"Oxidation number [OF] nitrogen in N2O5"}]	[{"type":"physical unit","value":"+5"}]	[{"type":"chemical equation","value":"N2O5"}]	<h1 class="questionTitle" itemprop="name">What is the oxidation number of nitrogen in #N_2O_5#?</h1>	null	+5	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Two things come in handy here</p> <blockquote> <ul> <li><em>for a neutral compound, the sum of the <a href="https://socratic.org/chemistry/electrochemistry/oxidation-numbers">oxidation numbers</a> of all constituent atoms <strong>must be</strong> equal to <strong>zero</strong></em></li> <li><em>the oxidation number of oxygen is usually equal to</em> <mathjax>#-2#</mathjax></li> </ul> </blockquote> <p>This means that if you take <mathjax>#?#</mathjax> to be the oxidation number of nitrogen in dinitrogen pentoxide, <mathjax>#"N"_color(blue)(2)"O"_color(red)(5)#</mathjax>, you can say that</p> <blockquote> <p><mathjax>#color(blue)(2) xx ? + color(red)(5) xx (-2) = 0#</mathjax></p> </blockquote> <p>All you have to do now is solve for <mathjax>#?#</mathjax> to find</p> <blockquote> <p><mathjax>#color(blue)(2) xx ? = +10 implies ? = (+10)/2 = +5#</mathjax></p> </blockquote> <p>And there you have it, nitrogen has a <mathjax>#+5#</mathjax> oxidation number in dinitrogen pentoxide. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#+5#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Two things come in handy here</p> <blockquote> <ul> <li><em>for a neutral compound, the sum of the <a href="https://socratic.org/chemistry/electrochemistry/oxidation-numbers">oxidation numbers</a> of all constituent atoms <strong>must be</strong> equal to <strong>zero</strong></em></li> <li><em>the oxidation number of oxygen is usually equal to</em> <mathjax>#-2#</mathjax></li> </ul> </blockquote> <p>This means that if you take <mathjax>#?#</mathjax> to be the oxidation number of nitrogen in dinitrogen pentoxide, <mathjax>#"N"_color(blue)(2)"O"_color(red)(5)#</mathjax>, you can say that</p> <blockquote> <p><mathjax>#color(blue)(2) xx ? + color(red)(5) xx (-2) = 0#</mathjax></p> </blockquote> <p>All you have to do now is solve for <mathjax>#?#</mathjax> to find</p> <blockquote> <p><mathjax>#color(blue)(2) xx ? = +10 implies ? = (+10)/2 = +5#</mathjax></p> </blockquote> <p>And there you have it, nitrogen has a <mathjax>#+5#</mathjax> oxidation number in dinitrogen pentoxide. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the oxidation number of nitrogen in #N_2O_5#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#electrochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Electrochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/electrochemistry/oxidation-numbers" itemprop="url"> <span class="breadcrumb" itemprop="title">Oxidation Numbers</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="324841" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-10-22T01:53:10" itemprop="dateCreated"> Oct 22, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#+5#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Two things come in handy here</p> <blockquote> <ul> <li><em>for a neutral compound, the sum of the <a href="https://socratic.org/chemistry/electrochemistry/oxidation-numbers">oxidation numbers</a> of all constituent atoms <strong>must be</strong> equal to <strong>zero</strong></em></li> <li><em>the oxidation number of oxygen is usually equal to</em> <mathjax>#-2#</mathjax></li> </ul> </blockquote> <p>This means that if you take <mathjax>#?#</mathjax> to be the oxidation number of nitrogen in dinitrogen pentoxide, <mathjax>#"N"_color(blue)(2)"O"_color(red)(5)#</mathjax>, you can say that</p> <blockquote> <p><mathjax>#color(blue)(2) xx ? + color(red)(5) xx (-2) = 0#</mathjax></p> </blockquote> <p>All you have to do now is solve for <mathjax>#?#</mathjax> to find</p> <blockquote> <p><mathjax>#color(blue)(2) xx ? = +10 implies ? = (+10)/2 = +5#</mathjax></p> </blockquote> <p>And there you have it, nitrogen has a <mathjax>#+5#</mathjax> oxidation number in dinitrogen pentoxide. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/324841" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-relate-to-electron-configuration"> How do oxidation numbers relate to electron configuration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-relate-to-valence-electrons"> How do oxidation numbers relate to valence electrons? 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2,015	acf4bfe3-6ddd-11ea-9883-ccda262736ce	https://socratic.org/questions/how-many-grams-are-contained-in-5-24-moles-of-nitrogen-dioxide-no-2	241.04 grams	start physical_unit 11 11 mass g qc_end physical_unit 11 11 6 7 mole qc_end end	[{"type":"physical unit","value":"Mass [OF] NO2 [IN] grams"}]	[{"type":"physical unit","value":"241.04 grams"}]	[{"type":"physical unit","value":"Mole [OF] NO2 [=] \\pu{5.24 moles}"}]	<h1 class="questionTitle" itemprop="name">How many grams are contained in 5.24 moles of nitrogen dioxide #NO_2#? </h1>	null	241.04 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>I make it <mathjax>#46gmol^-1#</mathjax>. And multiply this mass by the given molar quantity to get an answer in grams, approx. <mathjax>#250*g#</mathjax>...</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well what is the molar mass of <mathjax>#NO_2#</mathjax>?</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>I make it <mathjax>#46gmol^-1#</mathjax>. And multiply this mass by the given molar quantity to get an answer in grams, approx. <mathjax>#250*g#</mathjax>...</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many grams are contained in 5.24 moles of nitrogen dioxide #NO_2#? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="627772" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-06-09T10:50:07" itemprop="dateCreated"> Jun 9, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well what is the molar mass of <mathjax>#NO_2#</mathjax>?</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>I make it <mathjax>#46gmol^-1#</mathjax>. And multiply this mass by the given molar quantity to get an answer in grams, approx. <mathjax>#250*g#</mathjax>...</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/627772" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1770 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many grams are contained in 5.24 moles of nitrogen dioxide #NO_2#?	null
2,016	a88ce89e-6ddd-11ea-b404-ccda262736ce	https://socratic.org/questions/gas-that-was-produced-after-burning-14-2g-of-methanol-and-ethanol-mixture-were-l	67%	start physical_unit 29 32 mass_percent none qc_end physical_unit 9 12 6 7 mass qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Mass percent [OF] methanol in the mixture"}]	[{"type":"physical unit","value":"67%"}]	[{"type":"physical unit","value":"Mass [OF] methanol and ethanol mixture [=] \\pu{14.2 g}"},{"type":"physical unit","value":"Mass [OF] precipitate [=] \\pu{50 g}"},{"type":"other","value":"Gas, that was produced after burning methanol and ethanol mixture were let through lime water."}]	<h1 class="questionTitle" itemprop="name">Gas, that was produced after burning 14.2g of methanol and ethanol mixture were let through lime water. 50g of precipitated out. What is the mass percent of methanol in the mixture?</h1>	null	67%	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The pertinent equations are</p> <p><mathjax>#M_r:color(white)(ll)32.04color(white)(mmmmmll)44.01#</mathjax><br/> <mathjax>#color(white)(mm)"CH"_3"OH" + "2O"_2 → "CO"_2 + "2H"_2"O"#</mathjax></p> <p><mathjax>#M_r:color(white)(m)46.07color(white)(mmmmmmll)44.01#</mathjax><br/> <mathjax>#color(white)(mm)"2C"_2"H"_5"OH" + "7O"_2 → "4CO"_2 + "2H"_2"O"#</mathjax></p> <p><mathjax>#M_r:color(white)(mmmmmll)44.01color(white)(mll)100.09#</mathjax><br/> <mathjax>#color(white)(mm)"Ca(OH)"_2 + "CO"_2 → "CaCO"_3 + "H"_2"O"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 1. Calculate the moles of <mathjax>#"CO"_2#</mathjax></strong></p> <p><mathjax>#"Moles of CO"_2 = 50 color(red)(cancel(color(black)("g CaCO"_3))) × (1 color(red)(cancel(color(black)("mol CaCO"_3))))/(100.09 color(red)(cancel(color(black)("g CaCO"_3)))) × ("1 mol CO"_2)/(1 color(red)(cancel(color(black)("mol CaCO"_3)))) = "0.500 mol CO"_2#</mathjax></p> <blockquote></blockquote> <p><strong>Step 2. Calculate the moles of <mathjax>#"CO"_2#</mathjax> from methanol and from ethanol</strong></p> <p>Let mass of methanol be <mathjax>#xcolor(white)(l) g#</mathjax>.</p> <p>Then the mass of ethanol is <mathjax>#(14.2 - x) color(white)(l)"g"#</mathjax></p> <p><strong>From methanol:</strong></p> <p><mathjax>#"Moles of CO"_2 = x color(red)(cancel(color(black)("g methanol"))) × (1color(red)(cancel(color(black)("mol methanol"))))/(32.04 color(red)(cancel(color(black)("g methanol"))))× ("1 mol CO"_2)/(1 color(red)(cancel(color(black)("mol methanol")))) = "0.031 21"xcolor(white)(l) "mol CO"_2#</mathjax></p> <p><strong>From ethanol:</strong></p> <p><mathjax>#"Moles of CO"_2 = (14.2- x) color(red)(cancel(color(black)("g ethanol"))) × (1 color(red)(cancel(color(black)("mol ethanol"))))/(46.07 color(red)(cancel(color(black)("g ethanol")))) × ("4 mol CO"_2)/(2 color(red)(cancel(color(black)("mol ethanol")))) = "0.043 41"(14.2-x)color(white)(l) "mol CO"_2 = ("0.6165 - 0.043 41"x) color(white)(l)"mol CO"_2#</mathjax> </p> <blockquote></blockquote> <p><strong>Step 3. Equate moles of <mathjax>#"CO"_2#</mathjax></strong></p> <p><mathjax>#"0.031 21"xcolor(white)(l) color(red)(cancel(color(black)("mol CO"_2))) + ("0.6165 - 0.043 41"x) color(red)(cancel(color(black)("mol CO"_2))) = 0.500 color(red)(cancel(color(black)("mol CO"_2)))#</mathjax></p> <p><mathjax>#"0.031 21"x + "0.6165 - 0.04341"x = 0.500#</mathjax></p> <p><mathjax>#"0.0122"x = 0.1165#</mathjax></p> <p><mathjax>#x = 0.1165/0.0122 = 9.55#</mathjax></p> <p>∴ <mathjax>#"Mass of methanol = 9.55 g"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 4. Calculate mass percent of methanol</strong></p> <p><mathjax>#"% by mass" = "mass of component"/"total mass" × 100 % = (9.55 color(red)(cancel(color(black)("g"))))/(14.2 color(red)(cancel(color(black)("g")))) × 100 % = 67 %#</mathjax></p> <p><strong>Note:</strong> The answer can have only 2 <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a>, because that is all you gave for the mass of <mathjax>#"CO"_2#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><strong>WARNING! Long answer!</strong> The mass percent of methanol is 67 %.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The pertinent equations are</p> <p><mathjax>#M_r:color(white)(ll)32.04color(white)(mmmmmll)44.01#</mathjax><br/> <mathjax>#color(white)(mm)"CH"_3"OH" + "2O"_2 → "CO"_2 + "2H"_2"O"#</mathjax></p> <p><mathjax>#M_r:color(white)(m)46.07color(white)(mmmmmmll)44.01#</mathjax><br/> <mathjax>#color(white)(mm)"2C"_2"H"_5"OH" + "7O"_2 → "4CO"_2 + "2H"_2"O"#</mathjax></p> <p><mathjax>#M_r:color(white)(mmmmmll)44.01color(white)(mll)100.09#</mathjax><br/> <mathjax>#color(white)(mm)"Ca(OH)"_2 + "CO"_2 → "CaCO"_3 + "H"_2"O"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 1. Calculate the moles of <mathjax>#"CO"_2#</mathjax></strong></p> <p><mathjax>#"Moles of CO"_2 = 50 color(red)(cancel(color(black)("g CaCO"_3))) × (1 color(red)(cancel(color(black)("mol CaCO"_3))))/(100.09 color(red)(cancel(color(black)("g CaCO"_3)))) × ("1 mol CO"_2)/(1 color(red)(cancel(color(black)("mol CaCO"_3)))) = "0.500 mol CO"_2#</mathjax></p> <blockquote></blockquote> <p><strong>Step 2. Calculate the moles of <mathjax>#"CO"_2#</mathjax> from methanol and from ethanol</strong></p> <p>Let mass of methanol be <mathjax>#xcolor(white)(l) g#</mathjax>.</p> <p>Then the mass of ethanol is <mathjax>#(14.2 - x) color(white)(l)"g"#</mathjax></p> <p><strong>From methanol:</strong></p> <p><mathjax>#"Moles of CO"_2 = x color(red)(cancel(color(black)("g methanol"))) × (1color(red)(cancel(color(black)("mol methanol"))))/(32.04 color(red)(cancel(color(black)("g methanol"))))× ("1 mol CO"_2)/(1 color(red)(cancel(color(black)("mol methanol")))) = "0.031 21"xcolor(white)(l) "mol CO"_2#</mathjax></p> <p><strong>From ethanol:</strong></p> <p><mathjax>#"Moles of CO"_2 = (14.2- x) color(red)(cancel(color(black)("g ethanol"))) × (1 color(red)(cancel(color(black)("mol ethanol"))))/(46.07 color(red)(cancel(color(black)("g ethanol")))) × ("4 mol CO"_2)/(2 color(red)(cancel(color(black)("mol ethanol")))) = "0.043 41"(14.2-x)color(white)(l) "mol CO"_2 = ("0.6165 - 0.043 41"x) color(white)(l)"mol CO"_2#</mathjax> </p> <blockquote></blockquote> <p><strong>Step 3. Equate moles of <mathjax>#"CO"_2#</mathjax></strong></p> <p><mathjax>#"0.031 21"xcolor(white)(l) color(red)(cancel(color(black)("mol CO"_2))) + ("0.6165 - 0.043 41"x) color(red)(cancel(color(black)("mol CO"_2))) = 0.500 color(red)(cancel(color(black)("mol CO"_2)))#</mathjax></p> <p><mathjax>#"0.031 21"x + "0.6165 - 0.04341"x = 0.500#</mathjax></p> <p><mathjax>#"0.0122"x = 0.1165#</mathjax></p> <p><mathjax>#x = 0.1165/0.0122 = 9.55#</mathjax></p> <p>∴ <mathjax>#"Mass of methanol = 9.55 g"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 4. Calculate mass percent of methanol</strong></p> <p><mathjax>#"% by mass" = "mass of component"/"total mass" × 100 % = (9.55 color(red)(cancel(color(black)("g"))))/(14.2 color(red)(cancel(color(black)("g")))) × 100 % = 67 %#</mathjax></p> <p><strong>Note:</strong> The answer can have only 2 <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a>, because that is all you gave for the mass of <mathjax>#"CO"_2#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Gas, that was produced after burning 14.2g of methanol and ethanol mixture were let through lime water. 50g of precipitated out. What is the mass percent of methanol in the mixture?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/mole-ratios" itemprop="url"> <span class="breadcrumb" itemprop="title">Mole Ratios</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="363731" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-01-12T19:01:49" itemprop="dateCreated"> Jan 12, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><strong>WARNING! Long answer!</strong> The mass percent of methanol is 67 %.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The pertinent equations are</p> <p><mathjax>#M_r:color(white)(ll)32.04color(white)(mmmmmll)44.01#</mathjax><br/> <mathjax>#color(white)(mm)"CH"_3"OH" + "2O"_2 → "CO"_2 + "2H"_2"O"#</mathjax></p> <p><mathjax>#M_r:color(white)(m)46.07color(white)(mmmmmmll)44.01#</mathjax><br/> <mathjax>#color(white)(mm)"2C"_2"H"_5"OH" + "7O"_2 → "4CO"_2 + "2H"_2"O"#</mathjax></p> <p><mathjax>#M_r:color(white)(mmmmmll)44.01color(white)(mll)100.09#</mathjax><br/> <mathjax>#color(white)(mm)"Ca(OH)"_2 + "CO"_2 → "CaCO"_3 + "H"_2"O"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 1. Calculate the moles of <mathjax>#"CO"_2#</mathjax></strong></p> <p><mathjax>#"Moles of CO"_2 = 50 color(red)(cancel(color(black)("g CaCO"_3))) × (1 color(red)(cancel(color(black)("mol CaCO"_3))))/(100.09 color(red)(cancel(color(black)("g CaCO"_3)))) × ("1 mol CO"_2)/(1 color(red)(cancel(color(black)("mol CaCO"_3)))) = "0.500 mol CO"_2#</mathjax></p> <blockquote></blockquote> <p><strong>Step 2. Calculate the moles of <mathjax>#"CO"_2#</mathjax> from methanol and from ethanol</strong></p> <p>Let mass of methanol be <mathjax>#xcolor(white)(l) g#</mathjax>.</p> <p>Then the mass of ethanol is <mathjax>#(14.2 - x) color(white)(l)"g"#</mathjax></p> <p><strong>From methanol:</strong></p> <p><mathjax>#"Moles of CO"_2 = x color(red)(cancel(color(black)("g methanol"))) × (1color(red)(cancel(color(black)("mol methanol"))))/(32.04 color(red)(cancel(color(black)("g methanol"))))× ("1 mol CO"_2)/(1 color(red)(cancel(color(black)("mol methanol")))) = "0.031 21"xcolor(white)(l) "mol CO"_2#</mathjax></p> <p><strong>From ethanol:</strong></p> <p><mathjax>#"Moles of CO"_2 = (14.2- x) color(red)(cancel(color(black)("g ethanol"))) × (1 color(red)(cancel(color(black)("mol ethanol"))))/(46.07 color(red)(cancel(color(black)("g ethanol")))) × ("4 mol CO"_2)/(2 color(red)(cancel(color(black)("mol ethanol")))) = "0.043 41"(14.2-x)color(white)(l) "mol CO"_2 = ("0.6165 - 0.043 41"x) color(white)(l)"mol CO"_2#</mathjax> </p> <blockquote></blockquote> <p><strong>Step 3. Equate moles of <mathjax>#"CO"_2#</mathjax></strong></p> <p><mathjax>#"0.031 21"xcolor(white)(l) color(red)(cancel(color(black)("mol CO"_2))) + ("0.6165 - 0.043 41"x) color(red)(cancel(color(black)("mol CO"_2))) = 0.500 color(red)(cancel(color(black)("mol CO"_2)))#</mathjax></p> <p><mathjax>#"0.031 21"x + "0.6165 - 0.04341"x = 0.500#</mathjax></p> <p><mathjax>#"0.0122"x = 0.1165#</mathjax></p> <p><mathjax>#x = 0.1165/0.0122 = 9.55#</mathjax></p> <p>∴ <mathjax>#"Mass of methanol = 9.55 g"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 4. Calculate mass percent of methanol</strong></p> <p><mathjax>#"% by mass" = "mass of component"/"total mass" × 100 % = (9.55 color(red)(cancel(color(black)("g"))))/(14.2 color(red)(cancel(color(black)("g")))) × 100 % = 67 %#</mathjax></p> <p><strong>Note:</strong> The answer can have only 2 <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a>, because that is all you gave for the mass of <mathjax>#"CO"_2#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/363731" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4178e02bf3469517a106e"> Question #a106e </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4178e02bf3469570e2e86"> Question #e2e86 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179102bf3469517a1072"> Question #a1072 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179402bf34694c8c5bf1"> Question #c5bf1 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179702bf3469588dc373"> Question #dc373 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179c02bf34694c8c5bf9"> Question #c5bf9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417a302bf3469517a1076"> Question #a1076 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417c702bf3469588dc377"> Question #dc377 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417d002bf346963eb984f"> Question #b984f </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417d402bf346950519ea3"> Question #19ea3 </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/mole-ratios"> See all questions in Mole Ratios </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1555 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Gas, that was produced after burning 14.2g of methanol and ethanol mixture were let through lime water. 50g of precipitated out. What is the mass percent of methanol in the mixture?	null
2,017	ac492775-6ddd-11ea-9564-ccda262736ce	https://socratic.org/questions/5628a0b1581e2a106b7ffc9e	9.00 moles	start physical_unit 4 5 mole mol qc_end physical_unit 15 15 12 13 mole qc_end end	[{"type":"physical unit","value":"Mole [OF] oxygen gas [IN] moles"}]	[{"type":"physical unit","value":"9.00 moles"}]	[{"type":"physical unit","value":"Mole [OF] 3-methylpent-2-ene [=] \\pu{1 mole}"}]	<h1 class="questionTitle" itemprop="name">How many moles of oxygen gas are required for the combustion of one mole of 3-methylpent-2-ene?</h1>	null	9.00 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The first thing to do here is determine the chemical formula of <em>3-methylpent-2-ene</em>. </p> <p>You know that you're dealing with an <em>alkene</em>, hence the suffix <strong>-ene</strong>. </p> <p>Moreover, you know that the parent chain is <em>pentane</em>, and that the double bond is placed on the <strong>second carbon</strong>. This means that you will have a <em>methyl group</em>, <mathjax>#-"CH"_3#</mathjax>, placed on the <strong>third carbon</strong>, hence the prefix <em>3-methyl</em>. </p> <p>The compound will look like this - I'll show you (E)-3-methylpent-2-ene, which is the (E) geometric isomer of 3-methylpent-2-ene</p> <p><img alt="https://www.molport.com/shop/molecular-formula/C6H12" src="https://useruploads.socratic.org/Z1MzLSrVTPCmAn4EYfLW_directory.molecule.image.jpg"/> </p> <p>Notice that the compound's condensed formula can be written as <mathjax>#"CH"_3"CHC"("CH"_3)"CH"_2"CH"_3#</mathjax>. </p> <p>This means that you can represent the compound as <mathjax>#"C"_6"H"_12#</mathjax>, since for its combustion reaction you only need to know how many carbon and how many hydrogen atoms it contains. </p> <p>You're dealing with a <em>hydrocarbon</em>, which means that the combustion reaction will only produce carbon dioxide, <mathjax>#"CO"_2#</mathjax>, and water, <mathjax>#"H"_2"O"#</mathjax>. </p> <p>So, the balanced chemical equation for the combustion of 3-methylpent-2-ene looks like this </p> <blockquote> <p><mathjax>#"C"_6"H"_12 + color(red)(9)"O"_2 -> 6"CO"_2 + 6"H"_2"O"#</mathjax></p> </blockquote> <p>Notice that you have a <mathjax>#1:color(red)(9)#</mathjax> <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> between 3-methylpent-2-ene and oxygen. This means that, in order for the reaction to take place, <em>every mole</em> of the former will require <mathjax>#color(red)(9)#</mathjax> moles of the latter.</p> <p>Therefore, one mole of 3-methylpent-2-ene will require nine moles of oxygen in order to react completely. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"9 moles"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The first thing to do here is determine the chemical formula of <em>3-methylpent-2-ene</em>. </p> <p>You know that you're dealing with an <em>alkene</em>, hence the suffix <strong>-ene</strong>. </p> <p>Moreover, you know that the parent chain is <em>pentane</em>, and that the double bond is placed on the <strong>second carbon</strong>. This means that you will have a <em>methyl group</em>, <mathjax>#-"CH"_3#</mathjax>, placed on the <strong>third carbon</strong>, hence the prefix <em>3-methyl</em>. </p> <p>The compound will look like this - I'll show you (E)-3-methylpent-2-ene, which is the (E) geometric isomer of 3-methylpent-2-ene</p> <p><img alt="https://www.molport.com/shop/molecular-formula/C6H12" src="https://useruploads.socratic.org/Z1MzLSrVTPCmAn4EYfLW_directory.molecule.image.jpg"/> </p> <p>Notice that the compound's condensed formula can be written as <mathjax>#"CH"_3"CHC"("CH"_3)"CH"_2"CH"_3#</mathjax>. </p> <p>This means that you can represent the compound as <mathjax>#"C"_6"H"_12#</mathjax>, since for its combustion reaction you only need to know how many carbon and how many hydrogen atoms it contains. </p> <p>You're dealing with a <em>hydrocarbon</em>, which means that the combustion reaction will only produce carbon dioxide, <mathjax>#"CO"_2#</mathjax>, and water, <mathjax>#"H"_2"O"#</mathjax>. </p> <p>So, the balanced chemical equation for the combustion of 3-methylpent-2-ene looks like this </p> <blockquote> <p><mathjax>#"C"_6"H"_12 + color(red)(9)"O"_2 -> 6"CO"_2 + 6"H"_2"O"#</mathjax></p> </blockquote> <p>Notice that you have a <mathjax>#1:color(red)(9)#</mathjax> <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> between 3-methylpent-2-ene and oxygen. This means that, in order for the reaction to take place, <em>every mole</em> of the former will require <mathjax>#color(red)(9)#</mathjax> moles of the latter.</p> <p>Therefore, one mole of 3-methylpent-2-ene will require nine moles of oxygen in order to react completely. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles of oxygen gas are required for the combustion of one mole of 3-methylpent-2-ene?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="179004" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-10-22T10:20:03" itemprop="dateCreated"> Oct 22, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"9 moles"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The first thing to do here is determine the chemical formula of <em>3-methylpent-2-ene</em>. </p> <p>You know that you're dealing with an <em>alkene</em>, hence the suffix <strong>-ene</strong>. </p> <p>Moreover, you know that the parent chain is <em>pentane</em>, and that the double bond is placed on the <strong>second carbon</strong>. This means that you will have a <em>methyl group</em>, <mathjax>#-"CH"_3#</mathjax>, placed on the <strong>third carbon</strong>, hence the prefix <em>3-methyl</em>. </p> <p>The compound will look like this - I'll show you (E)-3-methylpent-2-ene, which is the (E) geometric isomer of 3-methylpent-2-ene</p> <p><img alt="https://www.molport.com/shop/molecular-formula/C6H12" src="https://useruploads.socratic.org/Z1MzLSrVTPCmAn4EYfLW_directory.molecule.image.jpg"/> </p> <p>Notice that the compound's condensed formula can be written as <mathjax>#"CH"_3"CHC"("CH"_3)"CH"_2"CH"_3#</mathjax>. </p> <p>This means that you can represent the compound as <mathjax>#"C"_6"H"_12#</mathjax>, since for its combustion reaction you only need to know how many carbon and how many hydrogen atoms it contains. </p> <p>You're dealing with a <em>hydrocarbon</em>, which means that the combustion reaction will only produce carbon dioxide, <mathjax>#"CO"_2#</mathjax>, and water, <mathjax>#"H"_2"O"#</mathjax>. </p> <p>So, the balanced chemical equation for the combustion of 3-methylpent-2-ene looks like this </p> <blockquote> <p><mathjax>#"C"_6"H"_12 + color(red)(9)"O"_2 -> 6"CO"_2 + 6"H"_2"O"#</mathjax></p> </blockquote> <p>Notice that you have a <mathjax>#1:color(red)(9)#</mathjax> <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> between 3-methylpent-2-ene and oxygen. This means that, in order for the reaction to take place, <em>every mole</em> of the former will require <mathjax>#color(red)(9)#</mathjax> moles of the latter.</p> <p>Therefore, one mole of 3-methylpent-2-ene will require nine moles of oxygen in order to react completely. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/179004" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 13161 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many moles of oxygen gas are required for the combustion of one mole of 3-methylpent-2-ene?	null
2,018	a8c1b0d9-6ddd-11ea-9709-ccda262736ce	https://socratic.org/questions/56d4a62b7c014905f75b1084	10 FeSO4 + 2 KMnO + 8 H2SO4 -> 5 Fe2(SO4)3 + K2SO4 + 2 MnSO4 + 8 H2O	start chemical_equation qc_end chemical_equation 6 25 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the equation"}]	[{"type":"chemical equation","value":"10 FeSO4 + 2 KMnO + 8 H2SO4 -> 5 Fe2(SO4)3 + K2SO4 + 2 MnSO4 + 8 H2O"}]	[{"type":"chemical equation","value":"(A) FeSO4 + (B) KMnO + (C) H2SO4 -> (D) Fe2(SO4)3 + (E) K2SO4 + (F) MnSO4 + (G) H2O"}]	<h1 class="questionTitle" itemprop="name">How do you balance the equation: #(A)FeSO_4+(B)KMnO+(C)H_2SO_4 -> (D)Fe_2(SO_4)_3+(E)K_2SO_4+(F)MnSO_4+(G)H_2O# ?</h1>	null	10 FeSO4 + 2 KMnO + 8 H2SO4 -> 5 Fe2(SO4)3 + K2SO4 + 2 MnSO4 + 8 H2O	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Let's eliminate unknowns backwards, starting with <mathjax>#G#</mathjax>.</p> <p>From the equations for <mathjax>#H#</mathjax>, <mathjax>#Mn#</mathjax>, <mathjax>#K#</mathjax> and <mathjax>#Fe#</mathjax> we find:</p> <blockquote> <p><mathjax>#G=C#</mathjax></p> <p><mathjax>#F=B#</mathjax></p> <p><mathjax>#E=1/2 B#</mathjax></p> <p><mathjax>#D=1/2 A#</mathjax></p> </blockquote> <p>Substituting these in the remaining equations we get:</p> <blockquote> <p><mathjax>#S: A+C=3(1/2 A)+(1/2 B)+B = 3/2A + 3/2B#</mathjax></p> <p><mathjax>#O: 4A+4B+4C = 12 (1/2 A)+4 (1/2 B)+4B+C = 6A + 6B+C#</mathjax></p> </blockquote> <p>Subtracting <mathjax>#A#</mathjax> from both sides of the equation for <mathjax>#S#</mathjax> we get:</p> <blockquote> <p><mathjax>#C=1/2A+3/2B#</mathjax></p> </blockquote> <p>Substitute this in our equation for <mathjax>#O#</mathjax> to get:</p> <blockquote> <p><mathjax>#4A+4B+4(1/2A+3/2B) = 6A+6B+(1/2A+3/2B)#</mathjax></p> </blockquote> <p>That is:</p> <blockquote> <p><mathjax>#6A+10B = 13/2A+15/2B#</mathjax></p> </blockquote> <p>Multiplying both sides by <mathjax>#2#</mathjax> that becomes:</p> <blockquote> <p><mathjax>#12A+20B = 13A+15B#</mathjax></p> </blockquote> <p>Subtract <mathjax>#12A+15B#</mathjax> from both sides to get:</p> <blockquote> <p><mathjax>#5B=A#</mathjax></p> </blockquote> <p>So if we put <mathjax>#B=2#</mathjax> then we get:</p> <blockquote> <p><mathjax>#A=5B=10#</mathjax></p> <p><mathjax>#B=2#</mathjax></p> <p><mathjax>#C=1/2A+3/2B=5+3=8#</mathjax></p> <p><mathjax>#D=1/2A = 5#</mathjax></p> <p><mathjax>#E=1/2B = 1#</mathjax></p> <p><mathjax>#F=B=2#</mathjax></p> <p><mathjax>#G=C=8#</mathjax></p> </blockquote> <p>So:</p> <blockquote> <p><mathjax>#10FeSO_4+2KMnO+8H_2SO_4 -> 5Fe_2(SO_4)_3+K_2SO_4+2MnSO_4+8H_2O#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><blockquote> <p><mathjax>#10FeSO_4+2KMnO+8H_2SO_4 -> 5Fe_2(SO_4)_3+K_2SO_4+2MnSO_4+8H_2O#</mathjax></p> </blockquote></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Let's eliminate unknowns backwards, starting with <mathjax>#G#</mathjax>.</p> <p>From the equations for <mathjax>#H#</mathjax>, <mathjax>#Mn#</mathjax>, <mathjax>#K#</mathjax> and <mathjax>#Fe#</mathjax> we find:</p> <blockquote> <p><mathjax>#G=C#</mathjax></p> <p><mathjax>#F=B#</mathjax></p> <p><mathjax>#E=1/2 B#</mathjax></p> <p><mathjax>#D=1/2 A#</mathjax></p> </blockquote> <p>Substituting these in the remaining equations we get:</p> <blockquote> <p><mathjax>#S: A+C=3(1/2 A)+(1/2 B)+B = 3/2A + 3/2B#</mathjax></p> <p><mathjax>#O: 4A+4B+4C = 12 (1/2 A)+4 (1/2 B)+4B+C = 6A + 6B+C#</mathjax></p> </blockquote> <p>Subtracting <mathjax>#A#</mathjax> from both sides of the equation for <mathjax>#S#</mathjax> we get:</p> <blockquote> <p><mathjax>#C=1/2A+3/2B#</mathjax></p> </blockquote> <p>Substitute this in our equation for <mathjax>#O#</mathjax> to get:</p> <blockquote> <p><mathjax>#4A+4B+4(1/2A+3/2B) = 6A+6B+(1/2A+3/2B)#</mathjax></p> </blockquote> <p>That is:</p> <blockquote> <p><mathjax>#6A+10B = 13/2A+15/2B#</mathjax></p> </blockquote> <p>Multiplying both sides by <mathjax>#2#</mathjax> that becomes:</p> <blockquote> <p><mathjax>#12A+20B = 13A+15B#</mathjax></p> </blockquote> <p>Subtract <mathjax>#12A+15B#</mathjax> from both sides to get:</p> <blockquote> <p><mathjax>#5B=A#</mathjax></p> </blockquote> <p>So if we put <mathjax>#B=2#</mathjax> then we get:</p> <blockquote> <p><mathjax>#A=5B=10#</mathjax></p> <p><mathjax>#B=2#</mathjax></p> <p><mathjax>#C=1/2A+3/2B=5+3=8#</mathjax></p> <p><mathjax>#D=1/2A = 5#</mathjax></p> <p><mathjax>#E=1/2B = 1#</mathjax></p> <p><mathjax>#F=B=2#</mathjax></p> <p><mathjax>#G=C=8#</mathjax></p> </blockquote> <p>So:</p> <blockquote> <p><mathjax>#10FeSO_4+2KMnO+8H_2SO_4 -> 5Fe_2(SO_4)_3+K_2SO_4+2MnSO_4+8H_2O#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you balance the equation: #(A)FeSO_4+(B)KMnO+(C)H_2SO_4 -> (D)Fe_2(SO_4)_3+(E)K_2SO_4+(F)MnSO_4+(G)H_2O# ?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="233148" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/george-c"><img alt="" class="" src="https://profilepictures.socratic.org/bBXPOzf0TltJlJ8iwRB4_mugshot.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/george-c"> George C. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-02-29T21:02:28" itemprop="dateCreated"> Feb 29, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><blockquote> <p><mathjax>#10FeSO_4+2KMnO+8H_2SO_4 -> 5Fe_2(SO_4)_3+K_2SO_4+2MnSO_4+8H_2O#</mathjax></p> </blockquote></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Let's eliminate unknowns backwards, starting with <mathjax>#G#</mathjax>.</p> <p>From the equations for <mathjax>#H#</mathjax>, <mathjax>#Mn#</mathjax>, <mathjax>#K#</mathjax> and <mathjax>#Fe#</mathjax> we find:</p> <blockquote> <p><mathjax>#G=C#</mathjax></p> <p><mathjax>#F=B#</mathjax></p> <p><mathjax>#E=1/2 B#</mathjax></p> <p><mathjax>#D=1/2 A#</mathjax></p> </blockquote> <p>Substituting these in the remaining equations we get:</p> <blockquote> <p><mathjax>#S: A+C=3(1/2 A)+(1/2 B)+B = 3/2A + 3/2B#</mathjax></p> <p><mathjax>#O: 4A+4B+4C = 12 (1/2 A)+4 (1/2 B)+4B+C = 6A + 6B+C#</mathjax></p> </blockquote> <p>Subtracting <mathjax>#A#</mathjax> from both sides of the equation for <mathjax>#S#</mathjax> we get:</p> <blockquote> <p><mathjax>#C=1/2A+3/2B#</mathjax></p> </blockquote> <p>Substitute this in our equation for <mathjax>#O#</mathjax> to get:</p> <blockquote> <p><mathjax>#4A+4B+4(1/2A+3/2B) = 6A+6B+(1/2A+3/2B)#</mathjax></p> </blockquote> <p>That is:</p> <blockquote> <p><mathjax>#6A+10B = 13/2A+15/2B#</mathjax></p> </blockquote> <p>Multiplying both sides by <mathjax>#2#</mathjax> that becomes:</p> <blockquote> <p><mathjax>#12A+20B = 13A+15B#</mathjax></p> </blockquote> <p>Subtract <mathjax>#12A+15B#</mathjax> from both sides to get:</p> <blockquote> <p><mathjax>#5B=A#</mathjax></p> </blockquote> <p>So if we put <mathjax>#B=2#</mathjax> then we get:</p> <blockquote> <p><mathjax>#A=5B=10#</mathjax></p> <p><mathjax>#B=2#</mathjax></p> <p><mathjax>#C=1/2A+3/2B=5+3=8#</mathjax></p> <p><mathjax>#D=1/2A = 5#</mathjax></p> <p><mathjax>#E=1/2B = 1#</mathjax></p> <p><mathjax>#F=B=2#</mathjax></p> <p><mathjax>#G=C=8#</mathjax></p> </blockquote> <p>So:</p> <blockquote> <p><mathjax>#10FeSO_4+2KMnO+8H_2SO_4 -> 5Fe_2(SO_4)_3+K_2SO_4+2MnSO_4+8H_2O#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/233148" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a 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2,019	ac22687e-6ddd-11ea-bf8d-ccda262736ce	https://socratic.org/questions/what-mass-of-nacl-is-needed-to-make-2-50-l-of-a-2-20-m-of-a-nacl-solution	321 g	start physical_unit 3 3 mass g qc_end physical_unit 16 17 8 9 volume qc_end physical_unit 16 17 12 13 molarity qc_end end	[{"type":"physical unit","value":"Mass [OF] NaCl [IN] g"}]	[{"type":"physical unit","value":"321 g"}]	[{"type":"physical unit","value":"Volume [OF] NaCl Solution [=] \\pu{2.50 L}"},{"type":"physical unit","value":"Molarity [OF] NaCl Solution [=] \\pu{2.20 M}"}]	<h1 class="questionTitle" itemprop="name">What mass of NaCl is needed to make 2.50 L of a 2.20 M of a NaCl Solution?</h1>	null	321 g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>All you need to know here is that the <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></strong> of a solution tells you the number of moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> present in exactly <mathjax>#"1 L"#</mathjax> of the solution. </p> <p>In your case, a <mathjax>#"2.20-M"#</mathjax> sodium chloride solution will contain <mathjax>#2.20#</mathjax> <strong>moles</strong> of sodium chloride, the solute, <strong>for every</strong> <mathjax>#"1 L"#</mathjax> of the solution. </p> <p>So if every <mathjax>#"1 L"#</mathjax> of this solution must contain <mathjax>#2.20#</mathjax> <strong>moles</strong> of sodium chloride in order for the solution to have a molarity of <mathjax>#"2.20 M"#</mathjax>, it means that <mathjax>#"2.50 L"#</mathjax> of this solution must contain</p> <blockquote> <p><mathjax>#2.50 color(red)(cancel(color(black)("L solution"))) * "2.20 moles NaCl"/(1color(red)(cancel(color(black)("L solution")))) = "5.50 moles NaCl"#</mathjax></p> </blockquote> <p>To convert the number of moles of sodium chloride to <em>grams</em>, use the <strong>molar mass</strong> of the compound.</p> <blockquote> <p><mathjax>#5.50 color(red)(cancel(color(black)("moles NaCl"))) * "58.4 g"/(1color(red)(cancel(color(black)("mole NaCl")))) = color(darkgreen)(ul(color(black)("321 g")))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"321 g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>All you need to know here is that the <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></strong> of a solution tells you the number of moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> present in exactly <mathjax>#"1 L"#</mathjax> of the solution. </p> <p>In your case, a <mathjax>#"2.20-M"#</mathjax> sodium chloride solution will contain <mathjax>#2.20#</mathjax> <strong>moles</strong> of sodium chloride, the solute, <strong>for every</strong> <mathjax>#"1 L"#</mathjax> of the solution. </p> <p>So if every <mathjax>#"1 L"#</mathjax> of this solution must contain <mathjax>#2.20#</mathjax> <strong>moles</strong> of sodium chloride in order for the solution to have a molarity of <mathjax>#"2.20 M"#</mathjax>, it means that <mathjax>#"2.50 L"#</mathjax> of this solution must contain</p> <blockquote> <p><mathjax>#2.50 color(red)(cancel(color(black)("L solution"))) * "2.20 moles NaCl"/(1color(red)(cancel(color(black)("L solution")))) = "5.50 moles NaCl"#</mathjax></p> </blockquote> <p>To convert the number of moles of sodium chloride to <em>grams</em>, use the <strong>molar mass</strong> of the compound.</p> <blockquote> <p><mathjax>#5.50 color(red)(cancel(color(black)("moles NaCl"))) * "58.4 g"/(1color(red)(cancel(color(black)("mole NaCl")))) = color(darkgreen)(ul(color(black)("321 g")))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What mass of NaCl is needed to make 2.50 L of a 2.20 M of a NaCl Solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="563276" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-03-04T00:02:08" itemprop="dateCreated"> Mar 4, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"321 g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>All you need to know here is that the <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></strong> of a solution tells you the number of moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> present in exactly <mathjax>#"1 L"#</mathjax> of the solution. </p> <p>In your case, a <mathjax>#"2.20-M"#</mathjax> sodium chloride solution will contain <mathjax>#2.20#</mathjax> <strong>moles</strong> of sodium chloride, the solute, <strong>for every</strong> <mathjax>#"1 L"#</mathjax> of the solution. </p> <p>So if every <mathjax>#"1 L"#</mathjax> of this solution must contain <mathjax>#2.20#</mathjax> <strong>moles</strong> of sodium chloride in order for the solution to have a molarity of <mathjax>#"2.20 M"#</mathjax>, it means that <mathjax>#"2.50 L"#</mathjax> of this solution must contain</p> <blockquote> <p><mathjax>#2.50 color(red)(cancel(color(black)("L solution"))) * "2.20 moles NaCl"/(1color(red)(cancel(color(black)("L solution")))) = "5.50 moles NaCl"#</mathjax></p> </blockquote> <p>To convert the number of moles of sodium chloride to <em>grams</em>, use the <strong>molar mass</strong> of the compound.</p> <blockquote> <p><mathjax>#5.50 color(red)(cancel(color(black)("moles NaCl"))) * "58.4 g"/(1color(red)(cancel(color(black)("mole NaCl")))) = color(darkgreen)(ul(color(black)("321 g")))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/563276" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a 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src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What mass of NaCl is needed to make 2.50 L of a 2.20 M of a NaCl Solution?	null
2,020	a85ba6e8-6ddd-11ea-881d-ccda262736ce	https://socratic.org/questions/an-average-baked-potato-contains-164-calories-what-is-the-energy-value-of-the-po	686.18 joules	start physical_unit 13 14 energy j qc_end physical_unit 2 3 5 6 energy qc_end end	[{"type":"physical unit","value":"Energy value [OF] the potato [IN] joules"}]	[{"type":"physical unit","value":"686.18 joules"}]	[{"type":"physical unit","value":"Energy [OF] baked potato [=] \\pu{164 calories}"}]	<h1 class="questionTitle" itemprop="name">An average baked potato contains 164 calories. What is the energy value of the potato in joules?</h1>	null	686.18 joules	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And so....we take the product...</p> <p><mathjax>#164"Calorie"xx4.184J"calorie"^-1=??J#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"1 Calorie "-=" 4.184 J"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And so....we take the product...</p> <p><mathjax>#164"Calorie"xx4.184J"calorie"^-1=??J#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">An average baked potato contains 164 calories. What is the energy value of the potato in joules?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/calorimetry" itemprop="url"> <span class="breadcrumb" itemprop="title">Calorimetry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="624807" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-06-03T20:10:51" itemprop="dateCreated"> Jun 3, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"1 Calorie "-=" 4.184 J"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And so....we take the product...</p> <p><mathjax>#164"Calorie"xx4.184J"calorie"^-1=??J#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/624807" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-differential-scanning-in-calorimetry-work"> How does differential scanning in calorimetry work? 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What is the energy value of the potato in joules?	null
2,021	abf75902-6ddd-11ea-98eb-ccda262736ce	https://socratic.org/questions/what-is-the-correct-formula-for-a-compound-that-has-three-oxygen-atoms-and-one-s	SO3	start chemical_formula qc_end end	[{"type":"other","value":"Chemical Formula [OF] the compound [IN] default"}]	[{"type":"chemical equation","value":"SO3"}]	[{"type":"physical unit","value":"Number [OF] oxygen atoms [=] \\pu{3}"},{"type":"physical unit","value":"Number [OF] sulfur atom [=] \\pu{1}"}]	<h1 class="questionTitle" itemprop="name">What is the correct formula for a compound that has three oxygen atoms and one sulfur atom? </h1>	null	SO3	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is a significant industrial pollutant, as well as the precursor to sulfuric acid. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>You mean sulfur trioxide, <mathjax>#SO_3#</mathjax>?</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is a significant industrial pollutant, as well as the precursor to sulfuric acid. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the correct formula for a compound that has three oxygen atoms and one sulfur atom? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#ionic-bonds-and-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Ionic Bonds</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/ionic-bonds-and-formulas/writing-ionic-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Writing Ionic Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="281764" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-27T06:29:58" itemprop="dateCreated"> Jun 27, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>You mean sulfur trioxide, <mathjax>#SO_3#</mathjax>?</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is a significant industrial pollutant, as well as the precursor to sulfuric acid. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/281764" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-write-ionic-formulas-for-binary-compounds"> How do you write ionic formulas for binary compounds? 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2,022	ac4c9cf4-6ddd-11ea-a15f-ccda262736ce	https://socratic.org/questions/the-complete-combustion-of-1-mole-of-pentane-c-5h-12-will-require-how-many-moles	8 moles	start physical_unit 16 16 mole mol qc_end c_other OTHER qc_end physical_unit 8 8 4 5 mole qc_end end	[{"type":"physical unit","value":"Mole [OF] O2 [IN] moles"}]	[{"type":"physical unit","value":"8 moles"}]	[{"type":"other","value":"Complete combustion."},{"type":"physical unit","value":"Mole [OF] C5H12 [=] \\pu{1 mole}"}]	<h1 class="questionTitle" itemprop="name">The complete combustion of 1 mole of pentane, #C_5H_12#, will require how many moles of oxygen, #O_2#?</h1>	null	8 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We're asked to find the number of <strong>moles of <mathjax>#"O"_2#</mathjax></strong> needed to completely combust <mathjax>#1#</mathjax> <mathjax>#"mol C"_5"H"_12#</mathjax>.</p> <blockquote></blockquote> <p>To do this, we first need to write the <strong>chemical equation</strong> for this reaction, following the general formula for a hydrocarbon combustion reaction:</p> <blockquote> <p><mathjax>#"hydrocarbon"color(white)(l) + "oxygen" rarr "carbon dioxide" + "water (vapor)"#</mathjax></p> <blockquote></blockquote> </blockquote> <p>So</p> <blockquote> <p><mathjax>#"C"_5"H"_12(l) + "O"_2(g) rarr "CO"_2(g) + "H"_2"O"(g)" "#</mathjax> (unbalanced)</p> <blockquote></blockquote> </blockquote> <p>Let's now balance this equation. We'll first put a "<mathjax>#5#</mathjax>" in front of the <mathjax>#"CO"_2#</mathjax> to balance the <strong>carbons</strong>:</p> <blockquote> <p><mathjax>#"C"_5"H"_12(l) + "O"_2(g) rarr 5"CO"_2(g) + "H"_2"O"(g)" "#</mathjax> (unbalanced)</p> <blockquote></blockquote> </blockquote> <p>Now we'll put a "<mathjax>#6#</mathjax>" in front of <mathjax>#"H"_2"O"#</mathjax> to balance the <strong>hydrogens</strong>:</p> <blockquote> <p><mathjax>#"C"_5"H"_12(l) + "O"_2(g) rarr 5"CO"_2(g) + 6"H"_2"O"(g)" "#</mathjax> (unbalanced)</p> <blockquote></blockquote> </blockquote> <p>We now have <mathjax>#2#</mathjax> oxygens on the left side and <mathjax>#16#</mathjax> on the right side. Putting an "<mathjax>#8#</mathjax>" in front of <mathjax>#"O"_2#</mathjax> balances the equation:</p> <blockquote> <p><mathjax>#ul("C"_5"H"_12(l) + 8"O"_2(g) rarr 5"CO"_2(g) + 6"H"_2"O"(g)#</mathjax> </p> <blockquote></blockquote> </blockquote> <p>Now, we can realize that the stoichiometric ratio of pentane to oxygen is <mathjax>#1:8#</mathjax> (from <strong>coefficients</strong>).</p> <blockquote></blockquote> <p>Therefore, in order to completely combust <mathjax>#1#</mathjax> <mathjax>#"mol pentane"#</mathjax>, we must use <mathjax>#color(red)(ul(8color(white)(l)"mol O"_2#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#8#</mathjax> <mathjax>#"mol O"_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We're asked to find the number of <strong>moles of <mathjax>#"O"_2#</mathjax></strong> needed to completely combust <mathjax>#1#</mathjax> <mathjax>#"mol C"_5"H"_12#</mathjax>.</p> <blockquote></blockquote> <p>To do this, we first need to write the <strong>chemical equation</strong> for this reaction, following the general formula for a hydrocarbon combustion reaction:</p> <blockquote> <p><mathjax>#"hydrocarbon"color(white)(l) + "oxygen" rarr "carbon dioxide" + "water (vapor)"#</mathjax></p> <blockquote></blockquote> </blockquote> <p>So</p> <blockquote> <p><mathjax>#"C"_5"H"_12(l) + "O"_2(g) rarr "CO"_2(g) + "H"_2"O"(g)" "#</mathjax> (unbalanced)</p> <blockquote></blockquote> </blockquote> <p>Let's now balance this equation. We'll first put a "<mathjax>#5#</mathjax>" in front of the <mathjax>#"CO"_2#</mathjax> to balance the <strong>carbons</strong>:</p> <blockquote> <p><mathjax>#"C"_5"H"_12(l) + "O"_2(g) rarr 5"CO"_2(g) + "H"_2"O"(g)" "#</mathjax> (unbalanced)</p> <blockquote></blockquote> </blockquote> <p>Now we'll put a "<mathjax>#6#</mathjax>" in front of <mathjax>#"H"_2"O"#</mathjax> to balance the <strong>hydrogens</strong>:</p> <blockquote> <p><mathjax>#"C"_5"H"_12(l) + "O"_2(g) rarr 5"CO"_2(g) + 6"H"_2"O"(g)" "#</mathjax> (unbalanced)</p> <blockquote></blockquote> </blockquote> <p>We now have <mathjax>#2#</mathjax> oxygens on the left side and <mathjax>#16#</mathjax> on the right side. Putting an "<mathjax>#8#</mathjax>" in front of <mathjax>#"O"_2#</mathjax> balances the equation:</p> <blockquote> <p><mathjax>#ul("C"_5"H"_12(l) + 8"O"_2(g) rarr 5"CO"_2(g) + 6"H"_2"O"(g)#</mathjax> </p> <blockquote></blockquote> </blockquote> <p>Now, we can realize that the stoichiometric ratio of pentane to oxygen is <mathjax>#1:8#</mathjax> (from <strong>coefficients</strong>).</p> <blockquote></blockquote> <p>Therefore, in order to completely combust <mathjax>#1#</mathjax> <mathjax>#"mol pentane"#</mathjax>, we must use <mathjax>#color(red)(ul(8color(white)(l)"mol O"_2#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">The complete combustion of 1 mole of pentane, #C_5H_12#, will require how many moles of oxygen, #O_2#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/single-replacement-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Single Replacement Reactions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="466203" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/mrtas"><img alt="" class="" src="https://profilepictures.socratic.org/HY14X7r4S6AyDQgK2gwQ_IMG_0062.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/mrtas"> Nathan L. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-20T19:20:05" itemprop="dateCreated"> Aug 20, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#8#</mathjax> <mathjax>#"mol O"_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We're asked to find the number of <strong>moles of <mathjax>#"O"_2#</mathjax></strong> needed to completely combust <mathjax>#1#</mathjax> <mathjax>#"mol C"_5"H"_12#</mathjax>.</p> <blockquote></blockquote> <p>To do this, we first need to write the <strong>chemical equation</strong> for this reaction, following the general formula for a hydrocarbon combustion reaction:</p> <blockquote> <p><mathjax>#"hydrocarbon"color(white)(l) + "oxygen" rarr "carbon dioxide" + "water (vapor)"#</mathjax></p> <blockquote></blockquote> </blockquote> <p>So</p> <blockquote> <p><mathjax>#"C"_5"H"_12(l) + "O"_2(g) rarr "CO"_2(g) + "H"_2"O"(g)" "#</mathjax> (unbalanced)</p> <blockquote></blockquote> </blockquote> <p>Let's now balance this equation. We'll first put a "<mathjax>#5#</mathjax>" in front of the <mathjax>#"CO"_2#</mathjax> to balance the <strong>carbons</strong>:</p> <blockquote> <p><mathjax>#"C"_5"H"_12(l) + "O"_2(g) rarr 5"CO"_2(g) + "H"_2"O"(g)" "#</mathjax> (unbalanced)</p> <blockquote></blockquote> </blockquote> <p>Now we'll put a "<mathjax>#6#</mathjax>" in front of <mathjax>#"H"_2"O"#</mathjax> to balance the <strong>hydrogens</strong>:</p> <blockquote> <p><mathjax>#"C"_5"H"_12(l) + "O"_2(g) rarr 5"CO"_2(g) + 6"H"_2"O"(g)" "#</mathjax> (unbalanced)</p> <blockquote></blockquote> </blockquote> <p>We now have <mathjax>#2#</mathjax> oxygens on the left side and <mathjax>#16#</mathjax> on the right side. Putting an "<mathjax>#8#</mathjax>" in front of <mathjax>#"O"_2#</mathjax> balances the equation:</p> <blockquote> <p><mathjax>#ul("C"_5"H"_12(l) + 8"O"_2(g) rarr 5"CO"_2(g) + 6"H"_2"O"(g)#</mathjax> </p> <blockquote></blockquote> </blockquote> <p>Now, we can realize that the stoichiometric ratio of pentane to oxygen is <mathjax>#1:8#</mathjax> (from <strong>coefficients</strong>).</p> <blockquote></blockquote> <p>Therefore, in order to completely combust <mathjax>#1#</mathjax> <mathjax>#"mol pentane"#</mathjax>, we must use <mathjax>#color(red)(ul(8color(white)(l)"mol O"_2#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/466203" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41c1602bf3469588dc38d"> Question #dc38d </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41c3802bf34695a6bc748"> When does a single replacement reaction occur? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-examples-of-single-replacement-reactions"> What are some examples of single replacement reactions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-single-replacement-reactions-be-recognized"> How can single replacement reactions be recognized? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-balance-a-single-replacement-reaction"> How do you balance a single replacement reaction? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/are-single-displacement-reactions-exothermic"> Are single displacement reactions exothermic? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-happens-in-a-single-displacement-reaction"> What happens in a single displacement reaction? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-the-applications-of-the-displacement-reactions"> What are the applications of displacement reactions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-difference-between-a-decomposition-reaction-and-a-replacement-reacti"> What is the difference between a decomposition reaction and a replacement reaction? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-a-neutralization-reaction-different-from-a-single-displacement-reaction"> How is a neutralization reaction different from a single displacement reaction? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/single-replacement-reactions"> See all questions in Single Replacement Reactions </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 34069 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	The complete combustion of 1 mole of pentane, #C_5H_12#, will require how many moles of oxygen, #O_2#?	null
2,023	ad0bbf92-6ddd-11ea-a7f4-ccda262736ce	https://socratic.org/questions/5885631fb72cff1ab68610f0	78.18 g/mol	start physical_unit 7 7 atomic_mass g/mol qc_end physical_unit 7 7 12 13 density qc_end physical_unit 7 7 18 19 pressure qc_end physical_unit 7 7 24 25 temperature qc_end end	[{"type":"physical unit","value":"Atomic mass [OF] the gas [IN] g/mol"}]	[{"type":"physical unit","value":"78.18 g/mol"}]	[{"type":"physical unit","value":"ρ [OF] the gas [=] \\pu{2.50 g/L}"},{"type":"physical unit","value":"Pressure [OF] the gas [=] \\pu{0.974 atm}"},{"type":"physical unit","value":"Temperature [OF] the gas [=] \\pu{371 K}"}]	<h1 class="questionTitle" itemprop="name">What is the atomic mass of a gas that has #rho=2.50gL^-1# at a pressure of #0.974atm#, and a temperature of #371K#?</h1>	null	78.18 g/mol	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#P/(RT)=n/V=("mass"/"molar mass")/V#</mathjax></p> <p>And thus <mathjax>#"molar mass"="mass of gas"/(PV)xxRT#</mathjax></p> <p>All I have done is manipulate the equation,</p> <p>So <mathjax>#"molar mass"="mass"/(V)xx(RT)/P#</mathjax></p> <p>But <mathjax>#"mass"/V="density", rho#</mathjax></p> <p>Finally, <mathjax>#"molar mass"=rhoxx(RT)/P#</mathjax></p> <p><mathjax>#(2.50gcancel(L^-1)xx0.0821cancel(L)cancel(atm)cancel(K^-1)mol^-1xx371cancel(K))/(0.974cancel(atm))#</mathjax></p> <p><mathjax>#=??gmol^-1#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Given <mathjax>#PV=nRT#</mathjax>..........<mathjax>#"molar mass"#</mathjax> <mathjax>#~=#</mathjax> <mathjax>#80gmol^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#P/(RT)=n/V=("mass"/"molar mass")/V#</mathjax></p> <p>And thus <mathjax>#"molar mass"="mass of gas"/(PV)xxRT#</mathjax></p> <p>All I have done is manipulate the equation,</p> <p>So <mathjax>#"molar mass"="mass"/(V)xx(RT)/P#</mathjax></p> <p>But <mathjax>#"mass"/V="density", rho#</mathjax></p> <p>Finally, <mathjax>#"molar mass"=rhoxx(RT)/P#</mathjax></p> <p><mathjax>#(2.50gcancel(L^-1)xx0.0821cancel(L)cancel(atm)cancel(K^-1)mol^-1xx371cancel(K))/(0.974cancel(atm))#</mathjax></p> <p><mathjax>#=??gmol^-1#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the atomic mass of a gas that has #rho=2.50gL^-1# at a pressure of #0.974atm#, and a temperature of #371K#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/ideal-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Ideal Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="368538" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-01-24T07:29:17" itemprop="dateCreated"> Jan 24, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Given <mathjax>#PV=nRT#</mathjax>..........<mathjax>#"molar mass"#</mathjax> <mathjax>#~=#</mathjax> <mathjax>#80gmol^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#P/(RT)=n/V=("mass"/"molar mass")/V#</mathjax></p> <p>And thus <mathjax>#"molar mass"="mass of gas"/(PV)xxRT#</mathjax></p> <p>All I have done is manipulate the equation,</p> <p>So <mathjax>#"molar mass"="mass"/(V)xx(RT)/P#</mathjax></p> <p>But <mathjax>#"mass"/V="density", rho#</mathjax></p> <p>Finally, <mathjax>#"molar mass"=rhoxx(RT)/P#</mathjax></p> <p><mathjax>#(2.50gcancel(L^-1)xx0.0821cancel(L)cancel(atm)cancel(K^-1)mol^-1xx371cancel(K))/(0.974cancel(atm))#</mathjax></p> <p><mathjax>#=??gmol^-1#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/368538" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-ideal-gas-constant"> How do you find the ideal gas constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-solve-ideal-gas-law-problems"> How do you solve ideal gas law problems? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a 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R = 8.314 kPa L / (K mol) =... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-molar-mass-of-a-gas"> How do you calculate the molar mass of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-should-i-use-the-ideal-gas-law-and-not-the-combined-gas-law"> When should I use the ideal gas law and not the combined gas law? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/ideal-gas-law"> See all questions in Ideal Gas Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1284 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the atomic mass of a gas that has #rho=2.50gL^-1# at a pressure of #0.974atm#, and a temperature of #371K#?	null
2,024	ab29b10a-6ddd-11ea-8772-ccda262736ce	https://socratic.org/questions/what-volume-of-2-5-m-v-koh-can-be-prepared-from-125-ml-of-a-5-0-koh-solution	250.00 mL	start physical_unit 15 16 volume ml qc_end physical_unit 15 16 10 11 volume qc_end end	[{"type":"physical unit","value":"Volume2 [OF] KOH solution [IN] mL"}]	[{"type":"physical unit","value":"250.00 mL"}]	[{"type":"physical unit","value":"m/v2 [OF] KOH in solution [=] \\pu{2.5%}"},{"type":"physical unit","value":"Volume1 [OF] KOH solution [=] \\pu{125 mL}"},{"type":"physical unit","value":"m/v1 [OF] KOH in solution [=] \\pu{5.0%}"}]	<h1 class="questionTitle" itemprop="name">What volume of 2.5% (m/v) KOH can be prepared from 125 mL of a 5.0% KOH solution?</h1>	null	250.00 mL	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <em>short answer</em> is that the volume of the target solution will be equal to <mathjax>#"250 mL"#</mathjax>. </p> <p>Think about it like this - you want the concentration of the target solution to be <strong>half</strong> of the concentration of the stock solution.</p> <p>Since you're keeping the amount of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> <strong>unchanged</strong>, you can say that <strong>doubling the volume</strong> of the solution will result in <strong>half</strong> the initial concentration <mathjax>#->#</mathjax> you're essentially <a href="https://socratic.org/chemistry/solutions-and-their-behavior/dilution-calculations">diluting</a> the initial solution by a <a href="https://socratic.org/questions/how-do-you-calculate-dilution-factor">factor</a> of <mathjax>#2#</mathjax>. </p> <p>Now for the <em>long answer</em>. </p> <p>So, you're dealing with <mathjax>#"125 mL"#</mathjax> of a <mathjax>#"5.0% m/v"#</mathjax> potassium hydroxide stock solution, and are interested in finding out what volume of <mathjax>#"2.5% m/v"#</mathjax> potassium hydroxide solution can be prepared using this starting solution. </p> <p>A <em>mass by volume</em> <a href="https://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration</a> is defined as <strong>mass of solute</strong>, usually expressed in <em>grams</em>, divided by <strong>volume of solution</strong>, usually expressed in <em>milliliters</em>, and multiplied by <mathjax>#100#</mathjax></p> <blockquote> <p><mathjax>#color(blue)("%m/v" = "mass of solute"/"volume of solution" xx 100)#</mathjax></p> </blockquote> <p>In your case, the stock solution will contain </p> <blockquote> <p><mathjax>#"5.0% g/mL" = m_(KOH)/"125 mL" xx 100#</mathjax></p> <p><mathjax>#m_(KOH) = (5.0"g"/color(red)(cancel(color(black)("mL"))) * 125 color(red)(cancel(color(black)("mL"))))/100 = "6.25 g"#</mathjax></p> </blockquote> <p>So, your stock solution contains <mathjax>#"6.25 g"#</mathjax> of potassium hydroxide. This is exactly how much potassium hydroxide the <mathjax>#"2.5%"#</mathjax> target solution must contain. </p> <p>This means that you have </p> <blockquote> <p><mathjax>#"2.5% g/mL" = "6.25 g"/V_"sol" * 100#</mathjax></p> <p><mathjax>#V_"sol" = (6.25 color(red)(cancel(color(black)("g"))))/(2.5color(red)(cancel(color(black)("g")))/"mL") * 100 = color(green)("250 mL")#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"250 mL"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <em>short answer</em> is that the volume of the target solution will be equal to <mathjax>#"250 mL"#</mathjax>. </p> <p>Think about it like this - you want the concentration of the target solution to be <strong>half</strong> of the concentration of the stock solution.</p> <p>Since you're keeping the amount of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> <strong>unchanged</strong>, you can say that <strong>doubling the volume</strong> of the solution will result in <strong>half</strong> the initial concentration <mathjax>#->#</mathjax> you're essentially <a href="https://socratic.org/chemistry/solutions-and-their-behavior/dilution-calculations">diluting</a> the initial solution by a <a href="https://socratic.org/questions/how-do-you-calculate-dilution-factor">factor</a> of <mathjax>#2#</mathjax>. </p> <p>Now for the <em>long answer</em>. </p> <p>So, you're dealing with <mathjax>#"125 mL"#</mathjax> of a <mathjax>#"5.0% m/v"#</mathjax> potassium hydroxide stock solution, and are interested in finding out what volume of <mathjax>#"2.5% m/v"#</mathjax> potassium hydroxide solution can be prepared using this starting solution. </p> <p>A <em>mass by volume</em> <a href="https://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration</a> is defined as <strong>mass of solute</strong>, usually expressed in <em>grams</em>, divided by <strong>volume of solution</strong>, usually expressed in <em>milliliters</em>, and multiplied by <mathjax>#100#</mathjax></p> <blockquote> <p><mathjax>#color(blue)("%m/v" = "mass of solute"/"volume of solution" xx 100)#</mathjax></p> </blockquote> <p>In your case, the stock solution will contain </p> <blockquote> <p><mathjax>#"5.0% g/mL" = m_(KOH)/"125 mL" xx 100#</mathjax></p> <p><mathjax>#m_(KOH) = (5.0"g"/color(red)(cancel(color(black)("mL"))) * 125 color(red)(cancel(color(black)("mL"))))/100 = "6.25 g"#</mathjax></p> </blockquote> <p>So, your stock solution contains <mathjax>#"6.25 g"#</mathjax> of potassium hydroxide. This is exactly how much potassium hydroxide the <mathjax>#"2.5%"#</mathjax> target solution must contain. </p> <p>This means that you have </p> <blockquote> <p><mathjax>#"2.5% g/mL" = "6.25 g"/V_"sol" * 100#</mathjax></p> <p><mathjax>#V_"sol" = (6.25 color(red)(cancel(color(black)("g"))))/(2.5color(red)(cancel(color(black)("g")))/"mL") * 100 = color(green)("250 mL")#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What volume of 2.5% (m/v) KOH can be prepared from 125 mL of a 5.0% KOH solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/percent-concentration" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Concentration</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="203316" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-25T01:29:02" itemprop="dateCreated"> Dec 25, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"250 mL"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <em>short answer</em> is that the volume of the target solution will be equal to <mathjax>#"250 mL"#</mathjax>. </p> <p>Think about it like this - you want the concentration of the target solution to be <strong>half</strong> of the concentration of the stock solution.</p> <p>Since you're keeping the amount of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> <strong>unchanged</strong>, you can say that <strong>doubling the volume</strong> of the solution will result in <strong>half</strong> the initial concentration <mathjax>#->#</mathjax> you're essentially <a href="https://socratic.org/chemistry/solutions-and-their-behavior/dilution-calculations">diluting</a> the initial solution by a <a href="https://socratic.org/questions/how-do-you-calculate-dilution-factor">factor</a> of <mathjax>#2#</mathjax>. </p> <p>Now for the <em>long answer</em>. </p> <p>So, you're dealing with <mathjax>#"125 mL"#</mathjax> of a <mathjax>#"5.0% m/v"#</mathjax> potassium hydroxide stock solution, and are interested in finding out what volume of <mathjax>#"2.5% m/v"#</mathjax> potassium hydroxide solution can be prepared using this starting solution. </p> <p>A <em>mass by volume</em> <a href="https://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration</a> is defined as <strong>mass of solute</strong>, usually expressed in <em>grams</em>, divided by <strong>volume of solution</strong>, usually expressed in <em>milliliters</em>, and multiplied by <mathjax>#100#</mathjax></p> <blockquote> <p><mathjax>#color(blue)("%m/v" = "mass of solute"/"volume of solution" xx 100)#</mathjax></p> </blockquote> <p>In your case, the stock solution will contain </p> <blockquote> <p><mathjax>#"5.0% g/mL" = m_(KOH)/"125 mL" xx 100#</mathjax></p> <p><mathjax>#m_(KOH) = (5.0"g"/color(red)(cancel(color(black)("mL"))) * 125 color(red)(cancel(color(black)("mL"))))/100 = "6.25 g"#</mathjax></p> </blockquote> <p>So, your stock solution contains <mathjax>#"6.25 g"#</mathjax> of potassium hydroxide. This is exactly how much potassium hydroxide the <mathjax>#"2.5%"#</mathjax> target solution must contain. </p> <p>This means that you have </p> <blockquote> <p><mathjax>#"2.5% g/mL" = "6.25 g"/V_"sol" * 100#</mathjax></p> <p><mathjax>#V_"sol" = (6.25 color(red)(cancel(color(black)("g"))))/(2.5color(red)(cancel(color(black)("g")))/"mL") * 100 = color(green)("250 mL")#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/203316" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-concentration-of-water-in-solution-be-decreased"> How can the concentration of water in solution be decreased? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-concentration-of-a-solution-be-increased"> How can the concentration of a solution be increased? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-concentration-of-a-solution-in-ppm"> How do you find the concentration of a solution in ppm? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-make-a-10-percent-solution"> How do you make a 10 percent solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-make-a-2-percent-solution"> How do you make a 2 percent solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-weight-per-volume-method-to-calculate-concentration"> What is the weight per volume method to calculate concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-percent-concentration-of-kcl-would-be-isotonic"> What percent concentration of KCl would be isotonic? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-of-sodium-chloride-in-normal-saline"> What is the percent concentration of sodium chloride in normal saline? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-of-a-6m-solution-of-nacl"> What is the percent concentration of a 6m solution of NaCl? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-formula"> What is the percent concentration formula? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/percent-concentration"> See all questions in Percent Concentration </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 28960 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What volume of 2.5% (m/v) KOH can be prepared from 125 mL of a 5.0% KOH solution?	null
2,025	ab0e26c1-6ddd-11ea-9bea-ccda262736ce	https://socratic.org/questions/what-is-the-molar-mass-of-nh4-2cr207-ammonium-dichromate	252.06 g/mol	start physical_unit 6 6 molar_mass g/mol qc_end chemical_equation 6 6 qc_end end	[{"type":"physical unit","value":"Molar mass [OF] (NH4)2Cr2O7 [IN] g/mol"}]	[{"type":"physical unit","value":"252.06 g/mol"}]	[{"type":"chemical equation","value":"(NH4)2Cr2O7"}]	<h1 class="questionTitle" itemprop="name">What is the molar mass of (NH4)2Cr207 (Ammonium dichromate)?</h1>	null	252.06 g/mol	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To calculate the molar mass of a compound, you multiply the subscripts of each element times its molar mass (atomic weight in g/mol).</p> <p><mathjax>#"(NH"_4)_2"Cr"_2"O"_7"#</mathjax></p> <p>When there is no written subscript, it is understood to be <mathjax>#1#</mathjax>. Also, when <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> are enclosed in parentheses, the subscripts on the inside are multiplied by the number outside the parentheses.</p> <p><strong>Molar Masses of the Elements</strong><br/> Nitogen: <mathjax>#"14.007 g/mol"#</mathjax><br/> Hydrogen: <mathjax>#"1.00794 g/mol"#</mathjax><br/> Chromium: <mathjax>#"51.9961 g/mol"#</mathjax><br/> Oxygen: <mathjax>#"15.999 g/mol"#</mathjax></p> <p><strong>Molar Mass of Ammonium Dichromate</strong><br/> <mathjax>#(2xx14.007)+(8xx1.00794)+(2xx51.9961)+(7xx15.999)="252.06 g/mol"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The molar mass of ammonium dichromate is <mathjax>#"252.06 g/mol"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To calculate the molar mass of a compound, you multiply the subscripts of each element times its molar mass (atomic weight in g/mol).</p> <p><mathjax>#"(NH"_4)_2"Cr"_2"O"_7"#</mathjax></p> <p>When there is no written subscript, it is understood to be <mathjax>#1#</mathjax>. Also, when <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> are enclosed in parentheses, the subscripts on the inside are multiplied by the number outside the parentheses.</p> <p><strong>Molar Masses of the Elements</strong><br/> Nitogen: <mathjax>#"14.007 g/mol"#</mathjax><br/> Hydrogen: <mathjax>#"1.00794 g/mol"#</mathjax><br/> Chromium: <mathjax>#"51.9961 g/mol"#</mathjax><br/> Oxygen: <mathjax>#"15.999 g/mol"#</mathjax></p> <p><strong>Molar Mass of Ammonium Dichromate</strong><br/> <mathjax>#(2xx14.007)+(8xx1.00794)+(2xx51.9961)+(7xx15.999)="252.06 g/mol"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the molar mass of (NH4)2Cr207 (Ammonium dichromate)?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="195338" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-02T09:24:15" itemprop="dateCreated"> Dec 2, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The molar mass of ammonium dichromate is <mathjax>#"252.06 g/mol"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To calculate the molar mass of a compound, you multiply the subscripts of each element times its molar mass (atomic weight in g/mol).</p> <p><mathjax>#"(NH"_4)_2"Cr"_2"O"_7"#</mathjax></p> <p>When there is no written subscript, it is understood to be <mathjax>#1#</mathjax>. Also, when <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> are enclosed in parentheses, the subscripts on the inside are multiplied by the number outside the parentheses.</p> <p><strong>Molar Masses of the Elements</strong><br/> Nitogen: <mathjax>#"14.007 g/mol"#</mathjax><br/> Hydrogen: <mathjax>#"1.00794 g/mol"#</mathjax><br/> Chromium: <mathjax>#"51.9961 g/mol"#</mathjax><br/> Oxygen: <mathjax>#"15.999 g/mol"#</mathjax></p> <p><strong>Molar Mass of Ammonium Dichromate</strong><br/> <mathjax>#(2xx14.007)+(8xx1.00794)+(2xx51.9961)+(7xx15.999)="252.06 g/mol"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/195338" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 27369 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the molar mass of (NH4)2Cr207 (Ammonium dichromate)?	null
2,026	a8decf38-6ddd-11ea-8527-ccda262736ce	https://socratic.org/questions/if-35-9-grams-of-ca-oh-2-are-dissolved-in-535-ml-of-solution-what-is-the-molarit	0.91 mol/L	start physical_unit 17 18 molarity mol/l qc_end physical_unit 4 4 1 2 mass qc_end physical_unit 11 11 8 9 volume qc_end end	[{"type":"physical unit","value":"Molarity [OF] the solution [IN] mol/L"}]	[{"type":"physical unit","value":"0.91 mol/L"}]	[{"type":"physical unit","value":"Mass [OF] Ca(OH)2 [=] \\pu{35.9 grams}"},{"type":"physical unit","value":"Volume [OF] solution [=] \\pu{535 mL}"}]	<h1 class="questionTitle" itemprop="name">If 35.9 grams of #Ca(OH)_2# are dissolved in 535 mL of solution, what is the molarity of the solution?</h1>	null	0.91 mol/L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This value, <mathjax>#0.906molL^-1#</mathjax> with respect to <mathjax>#"calcium hydroxide"#</mathjax> makes no sense at all, as calcium hydroxide has fairly limited water solubility. </p> <p>This <a href="https://en.wikipedia.org/wiki/Calcium_hydroxide" rel="nofollow">site</a> list a solubility product for calcium hydroxide, <mathjax>#K_(sp)=5.5xx10^-6#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#(35.9g)/(74.10gmol^-1)xx1/(0.535L)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.906molL^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This value, <mathjax>#0.906molL^-1#</mathjax> with respect to <mathjax>#"calcium hydroxide"#</mathjax> makes no sense at all, as calcium hydroxide has fairly limited water solubility. </p> <p>This <a href="https://en.wikipedia.org/wiki/Calcium_hydroxide" rel="nofollow">site</a> list a solubility product for calcium hydroxide, <mathjax>#K_(sp)=5.5xx10^-6#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">If 35.9 grams of #Ca(OH)_2# are dissolved in 535 mL of solution, what is the molarity of the solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="266003" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-15T10:42:17" itemprop="dateCreated"> May 15, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#(35.9g)/(74.10gmol^-1)xx1/(0.535L)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.906molL^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This value, <mathjax>#0.906molL^-1#</mathjax> with respect to <mathjax>#"calcium hydroxide"#</mathjax> makes no sense at all, as calcium hydroxide has fairly limited water solubility. </p> <p>This <a href="https://en.wikipedia.org/wiki/Calcium_hydroxide" rel="nofollow">site</a> list a solubility product for calcium hydroxide, <mathjax>#K_(sp)=5.5xx10^-6#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/266003" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" 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2,027	a8e88b43-6ddd-11ea-8823-ccda262736ce	https://socratic.org/questions/58349d187c014934a6a08588	CaO(s) + 2HNO3(aq) -> Ca(NO3)2(aq) + H2O(l)	start chemical_equation qc_end substance 5 6 qc_end substance 8 9 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the reaction"}]	[{"type":"chemical equation","value":"CaO(s) + 2HNO3(aq) -> Ca(NO3)2(aq) + H2O(l)"}]	[{"type":"substance name","value":"Calcium oxide"},{"type":"substance name","value":"Nitric acid"}]	<h1 class="questionTitle" itemprop="name">How does the reaction between calcium oxide, and nitric acid demonstrate the principle of stoichiometry?</h1>	null	CaO(s) + 2HNO3(aq) -> Ca(NO3)2(aq) + H2O(l)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>For every reactant particle, is there a corresponding product particle? Has charge been conserved in the reaction as written?</p> <p>Chemical reactions conserve (i) mass, and (ii) charge absolutely, and invariably. And so if your reaction does not stoichiometrically balance, then it is not a valid representation of chemical reality. </p> <p>The given reaction is an example of an <mathjax>#"acid-base reaction"#</mathjax>. Which reagent is the acid, and which is the base?</p> <p>Note that <mathjax>#Ca#</mathjax> metal is an <mathjax>#"alkaline-earth"#</mathjax>, from <mathjax>#"Group 2"#</mathjax> of <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the Periodic Table</a>, and normally forms <mathjax>#Ca^(2+)#</mathjax> upon oxidation. Its hydroxide salt is thus <mathjax>#Ca(OH)_2#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#CaO(s) + 2HNO_3(aq) rarr Ca(NO_3)_2(aq) + H_2O(l)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>For every reactant particle, is there a corresponding product particle? Has charge been conserved in the reaction as written?</p> <p>Chemical reactions conserve (i) mass, and (ii) charge absolutely, and invariably. And so if your reaction does not stoichiometrically balance, then it is not a valid representation of chemical reality. </p> <p>The given reaction is an example of an <mathjax>#"acid-base reaction"#</mathjax>. Which reagent is the acid, and which is the base?</p> <p>Note that <mathjax>#Ca#</mathjax> metal is an <mathjax>#"alkaline-earth"#</mathjax>, from <mathjax>#"Group 2"#</mathjax> of <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the Periodic Table</a>, and normally forms <mathjax>#Ca^(2+)#</mathjax> upon oxidation. Its hydroxide salt is thus <mathjax>#Ca(OH)_2#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How does the reaction between calcium oxide, and nitric acid demonstrate the principle of stoichiometry?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="340404" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-11-22T19:38:24" itemprop="dateCreated"> Nov 22, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#CaO(s) + 2HNO_3(aq) rarr Ca(NO_3)_2(aq) + H_2O(l)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>For every reactant particle, is there a corresponding product particle? Has charge been conserved in the reaction as written?</p> <p>Chemical reactions conserve (i) mass, and (ii) charge absolutely, and invariably. And so if your reaction does not stoichiometrically balance, then it is not a valid representation of chemical reality. </p> <p>The given reaction is an example of an <mathjax>#"acid-base reaction"#</mathjax>. Which reagent is the acid, and which is the base?</p> <p>Note that <mathjax>#Ca#</mathjax> metal is an <mathjax>#"alkaline-earth"#</mathjax>, from <mathjax>#"Group 2"#</mathjax> of <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the Periodic Table</a>, and normally forms <mathjax>#Ca^(2+)#</mathjax> upon oxidation. Its hydroxide salt is thus <mathjax>#Ca(OH)_2#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/340404" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------> H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -> Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? 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Sodium phosphate and calcium chloride react to form... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-equation-kclo3-kcl-o2"> How can I balance this equation? ____ #KClO_3 -># ____ #KCl +# ____ #O_2# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-balancing-chemical-equations-important"> Why is balancing chemical equations important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/balancing-chemical-equations"> See all questions in Balancing Chemical Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1646 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How does the reaction between calcium oxide, and nitric acid demonstrate the principle of stoichiometry?	null
2,028	a8e30ccc-6ddd-11ea-ab22-ccda262736ce	https://socratic.org/questions/how-many-grams-of-aluminum-are-contained-in-100-0-g-of-aluminum-chloride-alcl-3	0.75 grams	start physical_unit 4 4 mass g qc_end physical_unit 13 13 8 9 mass qc_end end	[{"type":"physical unit","value":"Mass [OF] aluminum [IN] grams"}]	[{"type":"physical unit","value":"0.75 grams"}]	[{"type":"physical unit","value":"Mass [OF] AlCl3 [=] \\pu{100.0 g}"}]	<h1 class="questionTitle" itemprop="name">How many grams of aluminum are contained in 100.0 g of aluminum chloride, #AlCl_3#? </h1>	null	0.75 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>100.0 g <mathjax>#AlCl_3 (1mol AlCl_3)/(133.34 g)= .74996 mol AlCl_3#</mathjax><br/> There is 1 mol of Aluminum per one mole of <mathjax>#AlCl_3#</mathjax><br/> Therefore there is .74996 mols of Al<br/> Rounded to correct sig figs (4) that would be: .7500 mols of Al</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.7500 mols of Al</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>100.0 g <mathjax>#AlCl_3 (1mol AlCl_3)/(133.34 g)= .74996 mol AlCl_3#</mathjax><br/> There is 1 mol of Aluminum per one mole of <mathjax>#AlCl_3#</mathjax><br/> Therefore there is .74996 mols of Al<br/> Rounded to correct sig figs (4) that would be: .7500 mols of Al</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many grams of aluminum are contained in 100.0 g of aluminum chloride, #AlCl_3#? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="404397" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/a-raz"><img alt="" class="" src="https://profilepictures.socratic.org/RTbzR8EpS3OStVOgUbpC_Screen%20Shot%202017-04-08%20at%208.32.56%20PM.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/a-raz"> A.Raz </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-10T04:54:53" itemprop="dateCreated"> Apr 10, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.7500 mols of Al</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>100.0 g <mathjax>#AlCl_3 (1mol AlCl_3)/(133.34 g)= .74996 mol AlCl_3#</mathjax><br/> There is 1 mol of Aluminum per one mole of <mathjax>#AlCl_3#</mathjax><br/> Therefore there is .74996 mols of Al<br/> Rounded to correct sig figs (4) that would be: .7500 mols of Al</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/404397" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? 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2,029	a8fadd34-6ddd-11ea-acaa-ccda262736ce	https://socratic.org/questions/59303dd611ef6b1ef4a115e1	5.31 × 10^(-23) g	start physical_unit 7 8 mass g qc_end end	[{"type":"physical unit","value":"Mass [OF] ^32S atom [IN] g"}]	[{"type":"physical unit","value":"5.31 × 10^(-23) g"}]	[{"type":"physical unit","value":"Number [OF] ^32S atom [=] \\pu{1}"}]	<h1 class="questionTitle" itemprop="name">What is the mass of a SINGLE #""^32S# atom?</h1>	null	5.31 × 10^(-23) g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Well we know that <mathjax>#1mol#</mathjax> of <mathjax>#""^32S#</mathjax> has a mass of <mathjax>#32g#</mathjax>.</p> <p><mathjax>#32g#</mathjax>.</p> <p>And so we take the quotient..............</p> <p><mathjax>#=(32gcancel(mol^-1))/(6.022xx10^23cancel(mol^-1))=5.31xx10^-23*g#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Mass of ONE atom of sulfur"-=5.31xx10^-23g#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Well we know that <mathjax>#1mol#</mathjax> of <mathjax>#""^32S#</mathjax> has a mass of <mathjax>#32g#</mathjax>.</p> <p><mathjax>#32g#</mathjax>.</p> <p>And so we take the quotient..............</p> <p><mathjax>#=(32gcancel(mol^-1))/(6.022xx10^23cancel(mol^-1))=5.31xx10^-23g#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the mass of a SINGLE #""^32S# atom?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="433142" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-01T16:40:40" itemprop="dateCreated"> Jun 1, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Mass of ONE atom of sulfur"-=5.31xx10^-23g#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Well we know that <mathjax>#1mol#</mathjax> of <mathjax>#""^32S#</mathjax> has a mass of <mathjax>#32g#</mathjax>.</p> <p><mathjax>#32g#</mathjax>.</p> <p>And so we take the quotient..............</p> <p><mathjax>#=(32gcancel(mol^-1))/(6.022xx10^23cancel(mol^-1))=5.31xx10^-23g#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/433142" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? 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2,030	aac6a81c-6ddd-11ea-a9e9-ccda262736ce	https://socratic.org/questions/the-h-in-a-solution-is-0-01-m-what-is-the-ph-of-the-solution	2	start physical_unit 13 14 ph none qc_end physical_unit 13 14 6 7 [h+] qc_end end	[{"type":"physical unit","value":"pH [OF] the solution"}]	[{"type":"physical unit","value":"2"}]	[{"type":"physical unit","value":"[H+] [OF] the solution [=] \\pu{0.01 M}"}]	<h1 class="questionTitle" itemprop="name">The [#H^+#] in a solution is 0.01 M. What is the pH of the solution? </h1>	null	2	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> of a given solution is nothing more than the <strong>negative log base</strong> <mathjax>#10#</mathjax> of the concentration of hydrogen ions, <mathjax>#"H"^(+)#</mathjax>, which you'll sometimes see written as <mathjax>#"H"_ 3"O"^(+)#</mathjax>, the <em>hydronium ion</em>.</p> <p>You thus have</p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)("pH" = - log(["H"^(+)]))))#</mathjax></p> </blockquote> <p>In your case, the problem provides you with the concentration of hydrogen ions</p> <blockquote> <p><mathjax>#["H"^(+)] = "0.01 M"#</mathjax></p> </blockquote> <p>This means that the pH of the solution will be</p> <blockquote> <p><mathjax>#"pH" = - log(0.01)#</mathjax></p> <p><mathjax>#"pH" = - log(10^(-2)) = - (-2) * log(10)#</mathjax></p> </blockquote> <p>Since you know that</p> <blockquote> <p><mathjax>#log_(10)(10) = log(10) = 1#</mathjax></p> </blockquote> <p>you can say that</p> <blockquote> <p><mathjax>#color(darkgreen)(ul(color(black)("pH" = - (-2) * 1 = 2)))#</mathjax></p> </blockquote> <p>Because the pH is <mathjax>#<7#</mathjax>, this solution will be <strong>acidic</strong>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"pH" = 2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> of a given solution is nothing more than the <strong>negative log base</strong> <mathjax>#10#</mathjax> of the concentration of hydrogen ions, <mathjax>#"H"^(+)#</mathjax>, which you'll sometimes see written as <mathjax>#"H"_ 3"O"^(+)#</mathjax>, the <em>hydronium ion</em>.</p> <p>You thus have</p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)("pH" = - log(["H"^(+)]))))#</mathjax></p> </blockquote> <p>In your case, the problem provides you with the concentration of hydrogen ions</p> <blockquote> <p><mathjax>#["H"^(+)] = "0.01 M"#</mathjax></p> </blockquote> <p>This means that the pH of the solution will be</p> <blockquote> <p><mathjax>#"pH" = - log(0.01)#</mathjax></p> <p><mathjax>#"pH" = - log(10^(-2)) = - (-2) * log(10)#</mathjax></p> </blockquote> <p>Since you know that</p> <blockquote> <p><mathjax>#log_(10)(10) = log(10) = 1#</mathjax></p> </blockquote> <p>you can say that</p> <blockquote> <p><mathjax>#color(darkgreen)(ul(color(black)("pH" = - (-2) * 1 = 2)))#</mathjax></p> </blockquote> <p>Because the pH is <mathjax>#<7#</mathjax>, this solution will be <strong>acidic</strong>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">The [#H^+#] in a solution is 0.01 M. What is the pH of the solution? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/the-ph-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">pH</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="348519" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-12-08T00:04:57" itemprop="dateCreated"> Dec 8, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"pH" = 2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> of a given solution is nothing more than the <strong>negative log base</strong> <mathjax>#10#</mathjax> of the concentration of hydrogen ions, <mathjax>#"H"^(+)#</mathjax>, which you'll sometimes see written as <mathjax>#"H"_ 3"O"^(+)#</mathjax>, the <em>hydronium ion</em>.</p> <p>You thus have</p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)("pH" = - log(["H"^(+)]))))#</mathjax></p> </blockquote> <p>In your case, the problem provides you with the concentration of hydrogen ions</p> <blockquote> <p><mathjax>#["H"^(+)] = "0.01 M"#</mathjax></p> </blockquote> <p>This means that the pH of the solution will be</p> <blockquote> <p><mathjax>#"pH" = - log(0.01)#</mathjax></p> <p><mathjax>#"pH" = - log(10^(-2)) = - (-2) * log(10)#</mathjax></p> </blockquote> <p>Since you know that</p> <blockquote> <p><mathjax>#log_(10)(10) = log(10) = 1#</mathjax></p> </blockquote> <p>you can say that</p> <blockquote> <p><mathjax>#color(darkgreen)(ul(color(black)("pH" = - (-2) * 1 = 2)))#</mathjax></p> </blockquote> <p>Because the pH is <mathjax>#<7#</mathjax>, this solution will be <strong>acidic</strong>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/348519" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-pka"> How do you determine pH from pKa? 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What is the pH of the solution?	null
2,031	a9db3312-6ddd-11ea-84c0-ccda262736ce	https://socratic.org/questions/the-osmotic-pressure-of-blood-is-7-7-atm-at-25-c-what-concentration-of-glucose-c	0.31 M	start physical_unit 15 15 concentration mol/l qc_end c_other OTHER qc_end physical_unit 4 4 6 7 osmotic_pressure qc_end physical_unit 4 4 9 10 temperature qc_end end	[{"type":"physical unit","value":"Concentration [OF] C6H12O6 [IN] M"}]	[{"type":"physical unit","value":"0.31 M"}]	[{"type":"other","value":"Same osmotic pressure."},{"type":"physical unit","value":"Osmotic pressure [OF] blood [=] \\pu{7.7 atm}"},{"type":"physical unit","value":"Temperature [OF] blood [=] \\pu{25 ℃}"}]	<h1 class="questionTitle" itemprop="name">The osmotic pressure of blood is 7.7 atm at 25°C. What concentration of glucose, #C_6H_12O_6#, is isotonic (same osmotic pressure) with blood?</h1>	null	0.31 M	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The problem wants you to determine what concentration of glucose would produce a solution that has the same <strong>osmotic pressure</strong> as blood at <mathjax>#25^@"C"#</mathjax>.</p> <p>As you know, <strong>osmotic pressure</strong> is defined as the pressure <em>required</em> to prevent the flow of water across a semi-permeable membrane from a region of <strong>lower <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> concentration</strong> into a region of <strong>higher solute concentration</strong> <mathjax>#->#</mathjax> think <strong><a href="http://socratic.org/biology/movement-in-and-out-of-cells/osmosis">osmosis</a></strong>. </p> <p><img alt="chemwiki.ucdavis.edu/Wikitexts/University_of_California_Davis/UCD_Chem_002B" src="https://useruploads.socratic.org/u3E14u86QnGlFSMwDbWU_%3Dc0d01b7aef63f35303c43d781b0b3d15.jpg"/> </p> <p>Osmotic pressure can be calculated using the formula</p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a)Pi = i * c_"solute" * RTcolor(white)(a/a)\|)))" "#</mathjax>, where</p> </blockquote> <p><mathjax>#Pi#</mathjax> - the osmotic pressure of the solution<br/> <mathjax>#i#</mathjax> - the <em>van't Hoff factor</em>, equal to <mathjax>#1#</mathjax> for <strong>non-electrolytes</strong><br/> <mathjax>#c_"solute"#</mathjax> - the <strong><a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></strong> of the solution<br/> <mathjax>#R#</mathjax> - the <em>universal gas constant</em>, usually given as <mathjax>#0.0821("atm" * "L")/("mol" * "K")#</mathjax><br/> <mathjax>#T#</mathjax> - the <strong>absolute temperature</strong></p> <p>All you have to do here is rearrange this equation to solve for <mathjax>#c_"solute"#</mathjax>, the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of a glucose solution that would have an osmotic pressure equal to <mathjax>#"7.7 atm"#</mathjax> at <mathjax>#25^@"C"#</mathjax>. </p> <p>Make sure to convert the temperature from <em>degrees Celsius</em> to <em>Kelvin</em> by using the conversion factor</p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a)T["K"] = t[""^@"C"] + 273.15color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>You will have</p> <blockquote> <p><mathjax>#c_"glucose" = Pi/(i * RT)#</mathjax></p> <p><mathjax>#c_"glucose" = (7.7 color(red)(cancel(color(black)("atm"))))/(1 * 0.0821( color(red)(cancel(color(black)("atm"))) * "L")/("mol" * color(red)(cancel(color(black)("K")))) * (273.15 + 25) color(red)(cancel(color(black)("K"))))#</mathjax></p> <p><mathjax>#c_"glucose" = "0.3146 mol L"^(-1)#</mathjax></p> </blockquote> <p>Rounded to two <strong><a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the answer will be </p> <blockquote> <p><mathjax>#c_"glucose" = color(green)(\|bar(ul(color(white)(a/a)"0.31 mol L"^(-1)color(white)(a/a)\|)))#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"0.31 mol L"^(-1)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The problem wants you to determine what concentration of glucose would produce a solution that has the same <strong>osmotic pressure</strong> as blood at <mathjax>#25^@"C"#</mathjax>.</p> <p>As you know, <strong>osmotic pressure</strong> is defined as the pressure <em>required</em> to prevent the flow of water across a semi-permeable membrane from a region of <strong>lower <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> concentration</strong> into a region of <strong>higher solute concentration</strong> <mathjax>#->#</mathjax> think <strong><a href="http://socratic.org/biology/movement-in-and-out-of-cells/osmosis">osmosis</a></strong>. </p> <p><img alt="chemwiki.ucdavis.edu/Wikitexts/University_of_California_Davis/UCD_Chem_002B" src="https://useruploads.socratic.org/u3E14u86QnGlFSMwDbWU_%3Dc0d01b7aef63f35303c43d781b0b3d15.jpg"/> </p> <p>Osmotic pressure can be calculated using the formula</p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a)Pi = i * c_"solute" * RTcolor(white)(a/a)\|)))" "#</mathjax>, where</p> </blockquote> <p><mathjax>#Pi#</mathjax> - the osmotic pressure of the solution<br/> <mathjax>#i#</mathjax> - the <em>van't Hoff factor</em>, equal to <mathjax>#1#</mathjax> for <strong>non-electrolytes</strong><br/> <mathjax>#c_"solute"#</mathjax> - the <strong><a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></strong> of the solution<br/> <mathjax>#R#</mathjax> - the <em>universal gas constant</em>, usually given as <mathjax>#0.0821("atm" * "L")/("mol" * "K")#</mathjax><br/> <mathjax>#T#</mathjax> - the <strong>absolute temperature</strong></p> <p>All you have to do here is rearrange this equation to solve for <mathjax>#c_"solute"#</mathjax>, the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of a glucose solution that would have an osmotic pressure equal to <mathjax>#"7.7 atm"#</mathjax> at <mathjax>#25^@"C"#</mathjax>. </p> <p>Make sure to convert the temperature from <em>degrees Celsius</em> to <em>Kelvin</em> by using the conversion factor</p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a)T["K"] = t[""^@"C"] + 273.15color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>You will have</p> <blockquote> <p><mathjax>#c_"glucose" = Pi/(i * RT)#</mathjax></p> <p><mathjax>#c_"glucose" = (7.7 color(red)(cancel(color(black)("atm"))))/(1 * 0.0821( color(red)(cancel(color(black)("atm"))) * "L")/("mol" * color(red)(cancel(color(black)("K")))) * (273.15 + 25) color(red)(cancel(color(black)("K"))))#</mathjax></p> <p><mathjax>#c_"glucose" = "0.3146 mol L"^(-1)#</mathjax></p> </blockquote> <p>Rounded to two <strong><a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the answer will be </p> <blockquote> <p><mathjax>#c_"glucose" = color(green)(\|bar(ul(color(white)(a/a)"0.31 mol L"^(-1)color(white)(a/a)\|)))#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">The osmotic pressure of blood is 7.7 atm at 25°C. What concentration of glucose, #C_6H_12O_6#, is isotonic (same osmotic pressure) with blood?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/partial-pressure" itemprop="url"> <span class="breadcrumb" itemprop="title">Partial Pressure</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="238707" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-12T12:57:00" itemprop="dateCreated"> Mar 12, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"0.31 mol L"^(-1)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The problem wants you to determine what concentration of glucose would produce a solution that has the same <strong>osmotic pressure</strong> as blood at <mathjax>#25^@"C"#</mathjax>.</p> <p>As you know, <strong>osmotic pressure</strong> is defined as the pressure <em>required</em> to prevent the flow of water across a semi-permeable membrane from a region of <strong>lower <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> concentration</strong> into a region of <strong>higher solute concentration</strong> <mathjax>#->#</mathjax> think <strong><a href="http://socratic.org/biology/movement-in-and-out-of-cells/osmosis">osmosis</a></strong>. </p> <p><img alt="chemwiki.ucdavis.edu/Wikitexts/University_of_California_Davis/UCD_Chem_002B" src="https://useruploads.socratic.org/u3E14u86QnGlFSMwDbWU_%3Dc0d01b7aef63f35303c43d781b0b3d15.jpg"/> </p> <p>Osmotic pressure can be calculated using the formula</p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a)Pi = i * c_"solute" * RTcolor(white)(a/a)\|)))" "#</mathjax>, where</p> </blockquote> <p><mathjax>#Pi#</mathjax> - the osmotic pressure of the solution<br/> <mathjax>#i#</mathjax> - the <em>van't Hoff factor</em>, equal to <mathjax>#1#</mathjax> for <strong>non-electrolytes</strong><br/> <mathjax>#c_"solute"#</mathjax> - the <strong><a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></strong> of the solution<br/> <mathjax>#R#</mathjax> - the <em>universal gas constant</em>, usually given as <mathjax>#0.0821("atm" * "L")/("mol" * "K")#</mathjax><br/> <mathjax>#T#</mathjax> - the <strong>absolute temperature</strong></p> <p>All you have to do here is rearrange this equation to solve for <mathjax>#c_"solute"#</mathjax>, the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of a glucose solution that would have an osmotic pressure equal to <mathjax>#"7.7 atm"#</mathjax> at <mathjax>#25^@"C"#</mathjax>. </p> <p>Make sure to convert the temperature from <em>degrees Celsius</em> to <em>Kelvin</em> by using the conversion factor</p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a)T["K"] = t[""^@"C"] + 273.15color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>You will have</p> <blockquote> <p><mathjax>#c_"glucose" = Pi/(i * RT)#</mathjax></p> <p><mathjax>#c_"glucose" = (7.7 color(red)(cancel(color(black)("atm"))))/(1 * 0.0821( color(red)(cancel(color(black)("atm"))) * "L")/("mol" * color(red)(cancel(color(black)("K")))) * (273.15 + 25) color(red)(cancel(color(black)("K"))))#</mathjax></p> <p><mathjax>#c_"glucose" = "0.3146 mol L"^(-1)#</mathjax></p> </blockquote> <p>Rounded to two <strong><a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the answer will be </p> <blockquote> <p><mathjax>#c_"glucose" = color(green)(\|bar(ul(color(white)(a/a)"0.31 mol L"^(-1)color(white)(a/a)\|)))#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/238707" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/534e256802bf342adfa30010"> How do you do a steam distillation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/53613f9f02bf3416cd9f8a34"> Question #f8a34 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-i-calculate-the-total-pressure-of-a-mixture-of-gases-by-adding-together-the-"> Can I calculate the total pressure of a mixture of gases by adding together the partial... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-formula-of-partial-pressure"> What is the formula of partial pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-dalton-s-law-of-partial-pressures"> What is the Dalton's law of partial pressures? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/nitrogen-gas-n2-reacts-with-hydrogen-gas-h2-to-form-ammonia-nh3-at-200-c-in-a-cl"> Nitrogen gas (N2) reacts with hydrogen gas (H2) to form ammonia (NH3). 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What concentration of glucose, #C_6H_12O_6#, is isotonic (same osmotic pressure) with blood?	null
2,032	a9c3f04a-6ddd-11ea-80e1-ccda262736ce	https://socratic.org/questions/57a9791911ef6b0596c422b3	6.11 × 10^20	start physical_unit 2 3 number none qc_end end	[{"type":"physical unit","value":"Number [OF] gold atoms"}]	[{"type":"physical unit","value":"6.11 × 10^20"}]	[{"type":"physical unit","value":"Mass [OF] gold [=] \\pu{1 carat}"}]	<h1 class="questionTitle" itemprop="name">How many gold atoms in a #"carat"#?</h1>	null	6.11 × 10^20	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"No. of moles"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"mass"/"molar mass"#</mathjax> <mathjax>#=#</mathjax> </p> <p><mathjax>#("22 carat"xx200mg"carat"^-1)/(196.97gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??mol#</mathjax></p> <p>And <mathjax>#"number of gold atoms"#</mathjax> <mathjax>#=#</mathjax> </p> <p><mathjax>#("22 carat"xx200xx10^-3g"carat"^-1)/(196.97gmol^-1)xx6.022xx10^23mol^-1#</mathjax>, which gives a result as a NOOMBER!</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"1 carat"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"0.007055 oz"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#200mg#</mathjax>, so...........</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"No. of moles"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"mass"/"molar mass"#</mathjax> <mathjax>#=#</mathjax> </p> <p><mathjax>#("22 carat"xx200mg"carat"^-1)/(196.97gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??mol#</mathjax></p> <p>And <mathjax>#"number of gold atoms"#</mathjax> <mathjax>#=#</mathjax> </p> <p><mathjax>#("22 carat"xx200xx10^-3g"carat"^-1)/(196.97gmol^-1)xx6.022xx10^23*mol^-1#</mathjax>, which gives a result as a NOOMBER!</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many gold atoms in a #"carat"#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/percent-composition" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Composition</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="297030" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-08-09T06:44:45" itemprop="dateCreated"> Aug 9, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"1 carat"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"0.007055 oz"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#200mg#</mathjax>, so...........</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"No. of moles"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"mass"/"molar mass"#</mathjax> <mathjax>#=#</mathjax> </p> <p><mathjax>#("22 carat"xx200mg"carat"^-1)/(196.97gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??mol#</mathjax></p> <p>And <mathjax>#"number of gold atoms"#</mathjax> <mathjax>#=#</mathjax> </p> <p><mathjax>#("22 carat"xx200xx10^-3g"carat"^-1)/(196.97gmol^-1)xx6.022xx10^23*mol^-1#</mathjax>, which gives a result as a NOOMBER!</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/297030" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-mole-percent"> What is mole percent? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4188602bf3469570e2e8b"> Question #e2e8b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4188702bf34695a6bc737"> Question #bc737 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418be02bf34695a6bc73b"> Question #bc73b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418c202bf3469570e2e8f"> Question #e2e8f </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418c802bf346963eb9857"> Question #b9857 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a 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class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many gold atoms in a #"carat"#?	null
2,033	a9dce3e2-6ddd-11ea-a2d9-ccda262736ce	https://socratic.org/questions/56122aac11ef6b16f74201bb	71.00%	start physical_unit 13 14 mass_percent none qc_end physical_unit 13 14 9 10 molarity qc_end end	[{"type":"physical unit","value":"Percentage concentration by mass [OF] nitric acid in solution"}]	[{"type":"physical unit","value":"71.00%"}]	[{"type":"physical unit","value":"Molarity [OF] nitric acid solution [=] \\pu{16 mol/L}"},{"type":"physical unit","value":"Density [OF] nitric acid solution [=] \\pu{1.42 g/mL}"}]	<h1 class="questionTitle" itemprop="name">What is the percentage concentration by mass of a #16molL^-1# solution of nitric acid, for which density is #1.42gmL^-1#?</h1>	null	71.00%	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>A <mathjax>#16#</mathjax> <mathjax>#M#</mathjax> concentration refers to the concentration of the solution. That is the nitric acid solution has a concentration of <mathjax>#16#</mathjax> <mathjax>#mol#</mathjax> <mathjax>#L^-1#</mathjax> of <em>solution</em> . We can work out percentages (<mathjax>#w/w#</mathjax> <mathjax>#xx100%#</mathjax>) provided that we know the <a href="http://socratic.org/chemistry/measurement-in-chemistry/density">density</a> of the solution, which we do because you have kindly included it in your question. So <mathjax>#1#</mathjax> <mathjax>#L#</mathjax> of solution has a mass of <mathjax>#1420#</mathjax> <mathjax>#g#</mathjax>. In the solution there are <mathjax>#16#</mathjax> <mathjax>#mol#</mathjax> <mathjax>#HNO_3#</mathjax>, i.e. <mathjax>#16#</mathjax> <mathjax>#mol#</mathjax> <mathjax>#xx#</mathjax> <mathjax>#63.0#</mathjax> <mathjax>#g#</mathjax> <mathjax>#mol^-1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#1008.2#</mathjax> <mathjax>#g#</mathjax>.</p> <p>So now we calculate the quotient, 1008.2 g <mathjax>#xx#</mathjax> 1/(1420 g) <mathjax>#xx#</mathjax> <mathjax>#100%#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax> <mathjax>#%#</mathjax>. And this gives us our percentage concentration: (mass of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a>/mass of solution) <mathjax>#xx#</mathjax> <mathjax>#100%#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Around 70% concentration, mass of acid/mass of solution.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>A <mathjax>#16#</mathjax> <mathjax>#M#</mathjax> concentration refers to the concentration of the solution. That is the nitric acid solution has a concentration of <mathjax>#16#</mathjax> <mathjax>#mol#</mathjax> <mathjax>#L^-1#</mathjax> of <em>solution</em> . We can work out percentages (<mathjax>#w/w#</mathjax> <mathjax>#xx100%#</mathjax>) provided that we know the <a href="http://socratic.org/chemistry/measurement-in-chemistry/density">density</a> of the solution, which we do because you have kindly included it in your question. So <mathjax>#1#</mathjax> <mathjax>#L#</mathjax> of solution has a mass of <mathjax>#1420#</mathjax> <mathjax>#g#</mathjax>. In the solution there are <mathjax>#16#</mathjax> <mathjax>#mol#</mathjax> <mathjax>#HNO_3#</mathjax>, i.e. <mathjax>#16#</mathjax> <mathjax>#mol#</mathjax> <mathjax>#xx#</mathjax> <mathjax>#63.0#</mathjax> <mathjax>#g#</mathjax> <mathjax>#mol^-1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#1008.2#</mathjax> <mathjax>#g#</mathjax>.</p> <p>So now we calculate the quotient, 1008.2 g <mathjax>#xx#</mathjax> 1/(1420 g) <mathjax>#xx#</mathjax> <mathjax>#100%#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax> <mathjax>#%#</mathjax>. And this gives us our percentage concentration: (mass of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a>/mass of solution) <mathjax>#xx#</mathjax> <mathjax>#100%#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the percentage concentration by mass of a #16molL^-1# solution of nitric acid, for which density is #1.42gmL^-1#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/dilution-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">Dilution Calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="174326" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-10-05T08:27:49" itemprop="dateCreated"> Oct 5, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Around 70% concentration, mass of acid/mass of solution.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>A <mathjax>#16#</mathjax> <mathjax>#M#</mathjax> concentration refers to the concentration of the solution. That is the nitric acid solution has a concentration of <mathjax>#16#</mathjax> <mathjax>#mol#</mathjax> <mathjax>#L^-1#</mathjax> of <em>solution</em> . We can work out percentages (<mathjax>#w/w#</mathjax> <mathjax>#xx100%#</mathjax>) provided that we know the <a href="http://socratic.org/chemistry/measurement-in-chemistry/density">density</a> of the solution, which we do because you have kindly included it in your question. So <mathjax>#1#</mathjax> <mathjax>#L#</mathjax> of solution has a mass of <mathjax>#1420#</mathjax> <mathjax>#g#</mathjax>. In the solution there are <mathjax>#16#</mathjax> <mathjax>#mol#</mathjax> <mathjax>#HNO_3#</mathjax>, i.e. <mathjax>#16#</mathjax> <mathjax>#mol#</mathjax> <mathjax>#xx#</mathjax> <mathjax>#63.0#</mathjax> <mathjax>#g#</mathjax> <mathjax>#mol^-1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#1008.2#</mathjax> <mathjax>#g#</mathjax>.</p> <p>So now we calculate the quotient, 1008.2 g <mathjax>#xx#</mathjax> 1/(1420 g) <mathjax>#xx#</mathjax> <mathjax>#100%#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax> <mathjax>#%#</mathjax>. And this gives us our percentage concentration: (mass of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a>/mass of solution) <mathjax>#xx#</mathjax> <mathjax>#100%#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/174326" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="174327" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-10-05T08:35:21" itemprop="dateCreated"> Oct 5, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Your stock solution is <mathjax>#71%"w/w"#</mathjax> nitric acid. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>What you need to do here is pick a sample of this stock nitric acid solution and use its <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> to find out how much nitric acid it would contain. </p> <p>Then use its <a href="http://socratic.org/chemistry/measurement-in-chemistry/density">density</a> to determine athe sample's mass.</p> <p>So, to make calculations easier, pick a <mathjax>#"1.00-L"#</mathjax> sample of the stock solution. Since <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> is defined as moles of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a>, in your case nitric cid, divided by liters of solution, you get that</p> <blockquote> <p><mathjax>#C = n/V implies n = C * V#</mathjax></p> <p><mathjax>#n_(HNO_3) = "16 M" * "1.00 L" = "16 moles"#</mathjax></p> </blockquote> <p>Use nitric acid's molar mass to help you find how many grams of acid would contain this many moles</p> <blockquote> <p><mathjax>#16color(red)(cancel(color(black)("moles HNO"""_3))) * "63.013 g"/(1color(red)(cancel(color(black)("mole HNO"""_3)))) = "1008.2 g HNO"""_3#</mathjax></p> </blockquote> <p>What would be the mass of the sample? Use its known density!</p> <blockquote> <p><mathjax>#1.00color(red)(cancel(color(black)("L"))) * (1000color(red)(cancel(color(black)("mL"))))/(1color(red)(cancel(color(black)("L")))) * "1.42 g"/(1color(red)(cancel(color(black)("mL")))) = "1420 g"#</mathjax></p> </blockquote> <p>The solution's <a href="http://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration by mass</a>, or <mathjax>#"%w/w"#</mathjax>, is defined as </p> <blockquote> <p><mathjax>#"%w/w" = "mass of solute"/"mass of solution" xx 100#</mathjax></p> </blockquote> <p>In your case, you would have</p> <blockquote> <p><mathjax>#"%w/w" = (1008.2color(red)(cancel(color(black)("g"))))/(1420color(red)(cancel(color(black)("g")))) xx 100 = color(green)(71%)#</mathjax></p> </blockquote> <p><strong>SIDE NOTE</strong> <em>You can redo the calculations using any sample of the stock solution, the result will always come out the same.</em></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/174327" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-concentration-from-absorbance"> How do you calculate concentration from absorbance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-concentration-from-titration"> How do you calculate concentration from titration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-dilution-factor"> How do you calculate dilution factor? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-do-serial-dilution-calculations"> How do you calculate serial dilutions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-calculate-concentration-of-solution-when-its-diluted"> How to calculate concentration of solution when it's diluted? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-examples-of-dilution-calculations"> What are some examples of dilution calculations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-would-be-the-concentration-of-a-solution-made-by-adding-250-ml-of-water-to-"> What would be the concentration of a solution made by adding 250 mL of water to 45.0 mL of 4.2 M KOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-would-be-the-concentration-of-a-solution-made-by-diluting-45-0-ml-of-4-2-m-"> What would be the concentration of a solution made by diluting 45.0 mL of 4.2 M KOH to 250 mL? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-a-solution-that-is-made-by-diluting-50-00-ml-of-a-4-74-m"> What is the molarity of a solution that is made by diluting 50.00 mL of a 4.74 M solution of HCl... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-volume-of-water-would-you-add-to-15-00-ml-of-a-6-77-m-solution-of-nitric-ac"> What volume of water would you add to 15.00 mL of a 6.77 M solution of nitric acid in order to... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/dilution-calculations"> See all questions in Dilution Calculations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 10444 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the percentage concentration by mass of a #16molL^-1# solution of nitric acid, for which density is #1.42gmL^-1#?	null
2,034	a960ad4a-6ddd-11ea-8c2b-ccda262736ce	https://socratic.org/questions/ch-2h-3o-2-aq-h-2o-l-rightleftharpoons-h-3o-c-2h-3o-2-aq-k-c-1-8-x-10-5-at-25-oc	1.94 × 10^(-3) mol/L	start physical_unit 4 4 equilibrium_concentration mol/l qc_end chemical_equation 0 6 qc_end physical_unit 22 22 20 21 molarity qc_end end	[{"type":"physical unit","value":"Equilibrium concentration [OF] H3O+ [IN] mol/L"}]	[{"type":"physical unit","value":"1.94 × 10^(-3) mol/L"}]	[{"type":"chemical equation","value":"CH2H3O2(aq) + H2O(l) -> H3O+ + C2H3O2−(aq)"},{"type":"physical unit","value":"Kc [OF] the reaction [=] \\pu{1.8 × 10^(−5)}"},{"type":"physical unit","value":"Temperature [OF] the reaction [=] \\pu{25 ℃}"},{"type":"physical unit","value":"Molarity [OF] HC2H3O2 solution [=] \\pu{0.210 M}"}]	<h1 class="questionTitle" itemprop="name">#CH_2H_3O_2(aq) + H_2O(l) rightleftharpoons H_3O^+ + C_2H_3O_2^-(aq)#. #K_c = 1.8 X 10^-5# at 25 #"^oC#. If a solution initially contains 0.210 M #HC_2H_3O_2#, what is the equilibrium concentration of #H_3O^+# at 25 #"^oC#?</h1>	null	1.94 × 10^(-3) mol/L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Set up an <strong>ICE</strong> table based on concentrations in mol/l:</p> <p><mathjax>#sf(" "CH_2H_3O_(2)+H_2OrightleftharpoonsC_2H_3O_2^(-)+H_3O^(+))#</mathjax></p> <p><mathjax>#sf(color(red)(I)" "0.210" "0" "0)#</mathjax></p> <p><mathjax>#sf(color(red)(C)" "-x" "+x" "+x)#</mathjax></p> <p><mathjax>#sf(color(red)(E)" "(0.210-x)" "x" "x)#</mathjax></p> <p>Applying the equilibrium law:</p> <p><mathjax>#sf(K_c=(x^2)/((0.210-x))=1.8xx10^(-5))#</mathjax></p> <p>Because the dissociation is so small we can make the approximation:</p> <p><mathjax>#sf((0.210-x)rArr0.210)#</mathjax></p> <p><mathjax>#:.#</mathjax><mathjax>#sf(x^(2)=0.210xx1.8xx10^(-5)=0.378xx10^(-5))#</mathjax></p> <p><mathjax>#:.#</mathjax><mathjax>#sf(x=sqrt(0.378xx10^(-5))=1.9xx10^(-3)color(white)(x)"mol/l")#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#sf([H_3O^(+)]=1.9xx10^(-3)color(white)(x)"mol/l")#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Set up an <strong>ICE</strong> table based on concentrations in mol/l:</p> <p><mathjax>#sf(" "CH_2H_3O_(2)+H_2OrightleftharpoonsC_2H_3O_2^(-)+H_3O^(+))#</mathjax></p> <p><mathjax>#sf(color(red)(I)" "0.210" "0" "0)#</mathjax></p> <p><mathjax>#sf(color(red)(C)" "-x" "+x" "+x)#</mathjax></p> <p><mathjax>#sf(color(red)(E)" "(0.210-x)" "x" "x)#</mathjax></p> <p>Applying the equilibrium law:</p> <p><mathjax>#sf(K_c=(x^2)/((0.210-x))=1.8xx10^(-5))#</mathjax></p> <p>Because the dissociation is so small we can make the approximation:</p> <p><mathjax>#sf((0.210-x)rArr0.210)#</mathjax></p> <p><mathjax>#:.#</mathjax><mathjax>#sf(x^(2)=0.210xx1.8xx10^(-5)=0.378xx10^(-5))#</mathjax></p> <p><mathjax>#:.#</mathjax><mathjax>#sf(x=sqrt(0.378xx10^(-5))=1.9xx10^(-3)color(white)(x)"mol/l")#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">#CH_2H_3O_2(aq) + H_2O(l) rightleftharpoons H_3O^+ + C_2H_3O_2^-(aq)#. #K_c = 1.8 X 10^-5# at 25 #"^oC#. If a solution initially contains 0.210 M #HC_2H_3O_2#, what is the equilibrium concentration of #H_3O^+# at 25 #"^oC#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-equilibrium" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Equilibrium</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-equilibrium/equilibrium-constants" itemprop="url"> <span class="breadcrumb" itemprop="title">Equilibrium Constants</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="322104" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/michael-2"><img alt="" class="" src="https://lh3.googleusercontent.com/-gCv6FQRhls0/AAAAAAAAAAI/AAAAAAAAAAA/AAnnY7oOJS05Ylqn3KuDSW0LfnbOk7FezQ/mo/photo.jpg?sz=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/michael-2"> Michael </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-10-15T17:21:29" itemprop="dateCreated"> Oct 15, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#sf([H_3O^(+)]=1.9xx10^(-3)color(white)(x)"mol/l")#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Set up an <strong>ICE</strong> table based on concentrations in mol/l:</p> <p><mathjax>#sf(" "CH_2H_3O_(2)+H_2OrightleftharpoonsC_2H_3O_2^(-)+H_3O^(+))#</mathjax></p> <p><mathjax>#sf(color(red)(I)" "0.210" "0" "0)#</mathjax></p> <p><mathjax>#sf(color(red)(C)" "-x" "+x" "+x)#</mathjax></p> <p><mathjax>#sf(color(red)(E)" "(0.210-x)" "x" "x)#</mathjax></p> <p>Applying the equilibrium law:</p> <p><mathjax>#sf(K_c=(x^2)/((0.210-x))=1.8xx10^(-5))#</mathjax></p> <p>Because the dissociation is so small we can make the approximation:</p> <p><mathjax>#sf((0.210-x)rArr0.210)#</mathjax></p> <p><mathjax>#:.#</mathjax><mathjax>#sf(x^(2)=0.210xx1.8xx10^(-5)=0.378xx10^(-5))#</mathjax></p> <p><mathjax>#:.#</mathjax><mathjax>#sf(x=sqrt(0.378xx10^(-5))=1.9xx10^(-3)color(white)(x)"mol/l")#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/322104" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-equilibrium-constant-change-with-temperature"> How does the equilibrium constant change with temperature? 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If a solution initially contains 0.210 M #HC_2H_3O_2#, what is the equilibrium concentration of #H_3O^+# at 25 #"^oC#?	null
2,035	ab9298dc-6ddd-11ea-a176-ccda262736ce	https://socratic.org/questions/can-someone-please-solve-this-three-questions-for-me-thank-you-for-your-help-1-i	30.00%	start physical_unit 16 17 percent_yield none qc_end physical_unit 6 6 3 4 mass qc_end physical_unit 16 17 13 14 mass qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Percentage yield [OF] copper(1) sulphide"}]	[{"type":"physical unit","value":"30.00%"}]	[{"type":"physical unit","value":"Mass [OF] copper [=] \\pu{5 g}"},{"type":"physical unit","value":"Mass [OF] copper(1) sulphide [=] \\pu{3 g}"},{"type":"other","value":"Copper was heated with excess sulphur."}]	<h1 class="questionTitle" itemprop="name">Can someone please solve this three questions for me. Thank you for your help. (1)- in an experiment, 5g of copper was heated with excess sulphur yield 3g of copper (1)sulphide. what is the percentage yield? </h1>	null	30.00%	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Mass: S= 32g , Cu= 63.5g ... <mathjax>#Cu_2S#</mathjax>=127g</p> <p>practical product = 3g of <mathjax>#Cu_2S#</mathjax></p> <p><mathjax>#2Cu + S -> Cu_2S#</mathjax> </p> <p>63.5g --- 127g<br/> <mathjax>#color(white)d#</mathjax> 5g<mathjax>#color(white)d#</mathjax> --- x </p> <p><mathjax>#"127 * 5"/63.5 = 10g#</mathjax> --> theoretical product</p> <p>Percentage yield:</p> <p><mathjax>#"practical product"/"theoretical product"100#</mathjax></p> <p><mathjax>#"3g"/"10g"100=30%#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>30%</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Mass: S= 32g , Cu= 63.5g ... <mathjax>#Cu_2S#</mathjax>=127g</p> <p>practical product = 3g of <mathjax>#Cu_2S#</mathjax></p> <p><mathjax>#2Cu + S -> Cu_2S#</mathjax> </p> <p>63.5g --- 127g<br/> <mathjax>#color(white)d#</mathjax> 5g<mathjax>#color(white)d#</mathjax> --- x </p> <p><mathjax>#"127 * 5"/63.5 = 10g#</mathjax> --> theoretical product</p> <p>Percentage yield:</p> <p><mathjax>#"practical product"/"theoretical product"100#</mathjax></p> <p><mathjax>#"3g"/"10g"100=30%#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Can someone please solve this three questions for me. Thank you for your help. (1)- in an experiment, 5g of copper was heated with excess sulphur yield 3g of copper (1)sulphide. what is the percentage yield? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/percent-yield" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Yield</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="447563" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/diego-m-4"><img alt="" class="" src="https://profilepictures.socratic.org/4XV18ZMUTvCWHbbks5Y6_archer.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/diego-m-4"> Diego Martínez Paz </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-07-03T22:11:52" itemprop="dateCreated"> Jul 3, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>30%</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Mass: S= 32g , Cu= 63.5g ... <mathjax>#Cu_2S#</mathjax>=127g</p> <p>practical product = 3g of <mathjax>#Cu_2S#</mathjax></p> <p><mathjax>#2Cu + S -> Cu_2S#</mathjax> </p> <p>63.5g --- 127g<br/> <mathjax>#color(white)d#</mathjax> 5g<mathjax>#color(white)d#</mathjax> --- x </p> <p><mathjax>#"127 * 5"/63.5 = 10g#</mathjax> --> theoretical product</p> <p>Percentage yield:</p> <p><mathjax>#"practical product"/"theoretical product"100#</mathjax></p> <p><mathjax>#"3g"/"10g"100=30%#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/447563" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ebd02bf3469570e2e62"> Question #e2e62 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ec502bf34694a4fee2e"> Question #fee2e </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ec902bf34694a4fee32"> Question #fee32 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ece02bf346950519e89"> Question #19e89 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ed302bf34694c8c5bdc"> Question #c5bdc </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ee302bf3469517a1065"> Question #a1065 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-would-be-the-limiting-reagent-if-26-0-grams-of-c3h9n-were-reacted-with-46-3"> What would be the limiting reagent if 26.0 grams of C3H9N were reacted with 46.3 grams of... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-percent-yield-always-less-than-100"> Is percent yield always less than 100? 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Thank you for your help. (1)- in an experiment, 5g of copper was heated with excess sulphur yield 3g of copper (1)sulphide. what is the percentage yield?	null
2,036	a8b2e5bb-6ddd-11ea-92b7-ccda262736ce	https://socratic.org/questions/how-many-moles-are-in-68-grams-of-copper-ii-hydroxide-cu-oh-2	0.70 moles	start physical_unit 11 11 mole mol qc_end physical_unit 11 11 5 6 mass qc_end end	[{"type":"physical unit","value":"Mole [OF] Cu(OH)2 [IN] moles"}]	[{"type":"physical unit","value":"0.70 moles"}]	[{"type":"physical unit","value":"Mass [OF] Cu(OH)2 [=] \\pu{68 grams}"}]	<h1 class="questionTitle" itemprop="name">How many moles are in 68 grams of copper (II) hydroxide, #Cu(OH)2#?</h1>	null	0.70 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We can use the following formula to determine the number of moles:</p> <blockquote> <p><mathjax>#m=nM#</mathjax></p> </blockquote> <p>where:<br/> m = mass (grams)<br/> n = number of moles<br/> M = molar mass</p> <p>To find the number of moles, we first have to find the molar mass of <mathjax>#Cu(OH)_"2"#</mathjax>. We can do this by adding the molar masses of copper, oxygen, and hydrogen together, accounting for the number of atoms for each element.</p> <blockquote> <p><mathjax>#M_color(brown)"copper"=color(brown)((63.55g)/(mol))#</mathjax></p> <p><mathjax>#M_color(blue)"hydrogen"=(1.01g)/(mol)2=color(blue)((2.02g)/(mol))#</mathjax></p> <p><mathjax>#M_color(green)"oxygen"=(16.00g)/(mol)2=color(green)((32.00g)/(mol))#</mathjax></p> <p><mathjax>#M_color(purple)"copper (II) hydroxide"=color(brown)((63.55g)/(mol))+color(blue)((2.02g)/(mol))+color(green)((32.00g)/(mol))=color(purple)((97.57g)/(mol))#</mathjax></p> </blockquote> <p>Now we can substitute our known values into the formula to solve for number of moles:</p> <blockquote> <p><mathjax>#m=nM#</mathjax></p> <p><mathjax>#n=m/M#</mathjax></p> <p><mathjax>#n=68g-:color(purple)((97.57g)/(mol))#</mathjax></p> <p><mathjax>#n=68g(mol)/(97.57g)#</mathjax></p> <p><mathjax>#n=68color(red)cancelcolor(black)(g)(mol)/(97.57color(red)cancelcolor(black)(g))#</mathjax></p> <p><mathjax>#n=(68mol)/97.57#</mathjax></p> <p><mathjax>#n=0.6969355335 mol#</mathjax></p> <p><mathjax>#n=0.70mol#</mathjax></p> </blockquote> <p>Note:<br/> The final answer should always have the correct number of <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a>.</p> <p><mathjax>#:.#</mathjax>, there are <mathjax>#0.70#</mathjax> moles of <mathjax>#Cu(OH)_"2"#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>There are <mathjax>#0.70#</mathjax> moles of <mathjax>#Cu(OH)_"2"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We can use the following formula to determine the number of moles:</p> <blockquote> <p><mathjax>#m=nM#</mathjax></p> </blockquote> <p>where:<br/> m = mass (grams)<br/> n = number of moles<br/> M = molar mass</p> <p>To find the number of moles, we first have to find the molar mass of <mathjax>#Cu(OH)_"2"#</mathjax>. We can do this by adding the molar masses of copper, oxygen, and hydrogen together, accounting for the number of atoms for each element.</p> <blockquote> <p><mathjax>#M_color(brown)"copper"=color(brown)((63.55g)/(mol))#</mathjax></p> <p><mathjax>#M_color(blue)"hydrogen"=(1.01g)/(mol)2=color(blue)((2.02g)/(mol))#</mathjax></p> <p><mathjax>#M_color(green)"oxygen"=(16.00g)/(mol)2=color(green)((32.00g)/(mol))#</mathjax></p> <p><mathjax>#M_color(purple)"copper (II) hydroxide"=color(brown)((63.55g)/(mol))+color(blue)((2.02g)/(mol))+color(green)((32.00g)/(mol))=color(purple)((97.57g)/(mol))#</mathjax></p> </blockquote> <p>Now we can substitute our known values into the formula to solve for number of moles:</p> <blockquote> <p><mathjax>#m=nM#</mathjax></p> <p><mathjax>#n=m/M#</mathjax></p> <p><mathjax>#n=68g-:color(purple)((97.57g)/(mol))#</mathjax></p> <p><mathjax>#n=68g(mol)/(97.57g)#</mathjax></p> <p><mathjax>#n=68color(red)cancelcolor(black)(g)(mol)/(97.57color(red)cancelcolor(black)(g))#</mathjax></p> <p><mathjax>#n=(68mol)/97.57#</mathjax></p> <p><mathjax>#n=0.6969355335 mol#</mathjax></p> <p><mathjax>#n=0.70mol#</mathjax></p> </blockquote> <p>Note:<br/> The final answer should always have the correct number of <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a>.</p> <p><mathjax>#:.#</mathjax>, there are <mathjax>#0.70#</mathjax> moles of <mathjax>#Cu(OH)_"2"#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles are in 68 grams of copper (II) hydroxide, #Cu(OH)2#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="193856" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/johnson"><img alt="" class="" src="https://profilepictures.socratic.org/CODc7QKDQ4O1bKIs5CiO_SnakeSkin.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/johnson"> Johnson Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-28T03:09:06" itemprop="dateCreated"> Nov 28, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>There are <mathjax>#0.70#</mathjax> moles of <mathjax>#Cu(OH)_"2"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We can use the following formula to determine the number of moles:</p> <blockquote> <p><mathjax>#m=nM#</mathjax></p> </blockquote> <p>where:<br/> m = mass (grams)<br/> n = number of moles<br/> M = molar mass</p> <p>To find the number of moles, we first have to find the molar mass of <mathjax>#Cu(OH)_"2"#</mathjax>. We can do this by adding the molar masses of copper, oxygen, and hydrogen together, accounting for the number of atoms for each element.</p> <blockquote> <p><mathjax>#M_color(brown)"copper"=color(brown)((63.55g)/(mol))#</mathjax></p> <p><mathjax>#M_color(blue)"hydrogen"=(1.01g)/(mol)2=color(blue)((2.02g)/(mol))#</mathjax></p> <p><mathjax>#M_color(green)"oxygen"=(16.00g)/(mol)2=color(green)((32.00g)/(mol))#</mathjax></p> <p><mathjax>#M_color(purple)"copper (II) hydroxide"=color(brown)((63.55g)/(mol))+color(blue)((2.02g)/(mol))+color(green)((32.00g)/(mol))=color(purple)((97.57g)/(mol))#</mathjax></p> </blockquote> <p>Now we can substitute our known values into the formula to solve for number of moles:</p> <blockquote> <p><mathjax>#m=nM#</mathjax></p> <p><mathjax>#n=m/M#</mathjax></p> <p><mathjax>#n=68g-:color(purple)((97.57g)/(mol))#</mathjax></p> <p><mathjax>#n=68g(mol)/(97.57g)#</mathjax></p> <p><mathjax>#n=68color(red)cancelcolor(black)(g)(mol)/(97.57color(red)cancelcolor(black)(g))#</mathjax></p> <p><mathjax>#n=(68mol)/97.57#</mathjax></p> <p><mathjax>#n=0.6969355335 mol#</mathjax></p> <p><mathjax>#n=0.70mol#</mathjax></p> </blockquote> <p>Note:<br/> The final answer should always have the correct number of <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a>.</p> <p><mathjax>#:.#</mathjax>, there are <mathjax>#0.70#</mathjax> moles of <mathjax>#Cu(OH)_"2"#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/193856" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 38578 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many moles are in 68 grams of copper (II) hydroxide, #Cu(OH)2#?	null
2,037	a87ab31c-6ddd-11ea-9a8a-ccda262736ce	https://socratic.org/questions/how-do-you-balance-ca-2-po-4-2-h-3po-4-ca-h-2po-4	Ca3(PO4)2 + 4 H3PO4 -> 3 Ca(H2PO4)2	start chemical_equation qc_end chemical_equation 4 8 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the equation"}]	[{"type":"chemical equation","value":"Ca3(PO4)2 + 4 H3PO4 -> 3 Ca(H2PO4)2"}]	[{"type":"chemical equation","value":"Ca3(PO4)2 + H3PO4 -> Ca(H2PO4)2"}]	<h1 class="questionTitle" itemprop="name">How do you balance #Ca_3(PO_4)_2 + H_3PO_4 -> Ca(H_2PO_4)_2#?</h1>	null	Ca3(PO4)2 + 4 H3PO4 -> 3 Ca(H2PO4)2	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Given equation:</p> <p><mathjax>#"Ca"_3("PO"_4)_2+"H"_3"PO"_4"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"Ca(H"_2"PO"_4)_2"#</mathjax></p> <p>There are three Ca atoms on the left-hand side (LHS), and one on the right-hand side (RHS). Place a coefficient of <mathjax>#3#</mathjax> in front of <mathjax>#"Ca(H"_2"PO"_4)_2#</mathjax>.</p> <p><mathjax>#"Ca"_3("PO"_4)_2+"H"_3"PO"_4"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(teal)3"Ca(H"_2"PO"_4)_2"#</mathjax></p> <p>Now there are twelve H atoms on the RHS <mathjax>#(3xx2xx2)#</mathjax>, and three on the LHS. Place a coefficient of <mathjax>#4#</mathjax> in front of <mathjax>#"H"_3"PO"_4"#</mathjax>.</p> <p><mathjax>#"Ca"_3("PO"_4)_2+color(magenta)4"H"_3"PO"_4"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(teal)3"Ca(H"_2"PO"_4)_2"#</mathjax></p> <p>Now lets count the number of atoms of each element on each side of the equation.</p> <p><mathjax>#"LHS:"#</mathjax> <mathjax>#"3 Ca atoms"#</mathjax>, <mathjax>#"6 P atoms"#</mathjax>, <mathjax>#"12 H atoms"#</mathjax>, <mathjax>#"24 O atoms"#</mathjax></p> <p><mathjax>#"RHS:"#</mathjax> <mathjax>#"3 Ca atoms"#</mathjax>, <mathjax>#"6 P atoms"#</mathjax>, <mathjax>#"12 H atoms"#</mathjax>, <mathjax>#"24 O atoms"#</mathjax></p> <p>Since there are the same number of atoms of each element on both sides of the equation, it is balanced.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Ca"_3("PO"_4)_2+4"H"_3"PO"_4"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#3"Ca(H"_2"PO"_4)_2"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Given equation:</p> <p><mathjax>#"Ca"_3("PO"_4)_2+"H"_3"PO"_4"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"Ca(H"_2"PO"_4)_2"#</mathjax></p> <p>There are three Ca atoms on the left-hand side (LHS), and one on the right-hand side (RHS). Place a coefficient of <mathjax>#3#</mathjax> in front of <mathjax>#"Ca(H"_2"PO"_4)_2#</mathjax>.</p> <p><mathjax>#"Ca"_3("PO"_4)_2+"H"_3"PO"_4"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(teal)3"Ca(H"_2"PO"_4)_2"#</mathjax></p> <p>Now there are twelve H atoms on the RHS <mathjax>#(3xx2xx2)#</mathjax>, and three on the LHS. Place a coefficient of <mathjax>#4#</mathjax> in front of <mathjax>#"H"_3"PO"_4"#</mathjax>.</p> <p><mathjax>#"Ca"_3("PO"_4)_2+color(magenta)4"H"_3"PO"_4"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(teal)3"Ca(H"_2"PO"_4)_2"#</mathjax></p> <p>Now lets count the number of atoms of each element on each side of the equation.</p> <p><mathjax>#"LHS:"#</mathjax> <mathjax>#"3 Ca atoms"#</mathjax>, <mathjax>#"6 P atoms"#</mathjax>, <mathjax>#"12 H atoms"#</mathjax>, <mathjax>#"24 O atoms"#</mathjax></p> <p><mathjax>#"RHS:"#</mathjax> <mathjax>#"3 Ca atoms"#</mathjax>, <mathjax>#"6 P atoms"#</mathjax>, <mathjax>#"12 H atoms"#</mathjax>, <mathjax>#"24 O atoms"#</mathjax></p> <p>Since there are the same number of atoms of each element on both sides of the equation, it is balanced.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you balance #Ca_3(PO_4)_2 + H_3PO_4 -> Ca(H_2PO_4)_2#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="601069" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-04-24T12:50:15" itemprop="dateCreated"> Apr 24, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Ca"_3("PO"_4)_2+4"H"_3"PO"_4"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#3"Ca(H"_2"PO"_4)_2"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Given equation:</p> <p><mathjax>#"Ca"_3("PO"_4)_2+"H"_3"PO"_4"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"Ca(H"_2"PO"_4)_2"#</mathjax></p> <p>There are three Ca atoms on the left-hand side (LHS), and one on the right-hand side (RHS). Place a coefficient of <mathjax>#3#</mathjax> in front of <mathjax>#"Ca(H"_2"PO"_4)_2#</mathjax>.</p> <p><mathjax>#"Ca"_3("PO"_4)_2+"H"_3"PO"_4"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(teal)3"Ca(H"_2"PO"_4)_2"#</mathjax></p> <p>Now there are twelve H atoms on the RHS <mathjax>#(3xx2xx2)#</mathjax>, and three on the LHS. Place a coefficient of <mathjax>#4#</mathjax> in front of <mathjax>#"H"_3"PO"_4"#</mathjax>.</p> <p><mathjax>#"Ca"_3("PO"_4)_2+color(magenta)4"H"_3"PO"_4"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(teal)3"Ca(H"_2"PO"_4)_2"#</mathjax></p> <p>Now lets count the number of atoms of each element on each side of the equation.</p> <p><mathjax>#"LHS:"#</mathjax> <mathjax>#"3 Ca atoms"#</mathjax>, <mathjax>#"6 P atoms"#</mathjax>, <mathjax>#"12 H atoms"#</mathjax>, <mathjax>#"24 O atoms"#</mathjax></p> <p><mathjax>#"RHS:"#</mathjax> <mathjax>#"3 Ca atoms"#</mathjax>, <mathjax>#"6 P atoms"#</mathjax>, <mathjax>#"12 H atoms"#</mathjax>, <mathjax>#"24 O atoms"#</mathjax></p> <p>Since there are the same number of atoms of each element on both sides of the equation, it is balanced.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/601069" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------> H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -> Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? 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2,038	ac614a36-6ddd-11ea-9efc-ccda262736ce	https://socratic.org/questions/58b3dc6eb72cff572e4677ed	4.00 g	start physical_unit 3 4 mass g qc_end physical_unit 10 10 12 13 volume qc_end physical_unit 22 22 17 18 molarity qc_end end	[{"type":"physical unit","value":"Mass [OF] caustic soda [IN] g"}]	[{"type":"physical unit","value":"4.00 g"}]	[{"type":"physical unit","value":"Volume [OF] NaOH solution [=] \\pu{100 mL}"},{"type":"physical unit","value":"Molarity [OF] NaOH solution [=] \\pu{1.0 mol/L}"}]	<h1 class="questionTitle" itemprop="name">What mass of caustic soda are required to prepare a solution of #100mL# volume that is #1.0mol*L^-1# with respect to #NaOH#? </h1>	null	4.00 g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Concentration"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Moles of solute"/"Volume of solution"#</mathjax></p> <p>Here, <mathjax>#"concentration"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#1.0molL^-1#</mathjax>, <mathjax>#"volume"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#100mL#</mathjax>.</p> <p>And thus <mathjax>#"moles of solute"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Concentration "xx" Volume"#</mathjax></p> <p><mathjax>#=1molL^-1xx100xx10^-3L=0.100mol#</mathjax>.</p> <p>And thus <mathjax>#"mass of solute"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"number of moles "xx" molar mass"#</mathjax></p> <p><mathjax>#=0.100molxx40.0gmol^-1=??g#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>A mass of <mathjax>#4.0g#</mathjax> <mathjax>#"sodium hydroxide"#</mathjax> is required............</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Concentration"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Moles of solute"/"Volume of solution"#</mathjax></p> <p>Here, <mathjax>#"concentration"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#1.0molL^-1#</mathjax>, <mathjax>#"volume"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#100mL#</mathjax>.</p> <p>And thus <mathjax>#"moles of solute"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Concentration "xx" Volume"#</mathjax></p> <p><mathjax>#=1molL^-1xx100xx10^-3L=0.100mol#</mathjax>.</p> <p>And thus <mathjax>#"mass of solute"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"number of moles "xx" molar mass"#</mathjax></p> <p><mathjax>#=0.100molxx40.0gmol^-1=??*g#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What mass of caustic soda are required to prepare a solution of #100mL# volume that is #1.0molL^-1# with respect to #NaOH#? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="383663" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-02-27T08:42:10" itemprop="dateCreated"> Feb 27, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>A mass of <mathjax>#4.0g#</mathjax> <mathjax>#"sodium hydroxide"#</mathjax> is required............</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Concentration"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Moles of solute"/"Volume of solution"#</mathjax></p> <p>Here, <mathjax>#"concentration"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#1.0molL^-1#</mathjax>, <mathjax>#"volume"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#100mL#</mathjax>.</p> <p>And thus <mathjax>#"moles of solute"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Concentration "xx" Volume"#</mathjax></p> <p><mathjax>#=1molL^-1xx100xx10^-3L=0.100mol#</mathjax>.</p> <p>And thus <mathjax>#"mass of solute"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"number of moles "xx" molar mass"#</mathjax></p> <p><mathjax>#=0.100molxx40.0gmol^-1=??g#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/383663" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? 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2,039	a8430f26-6ddd-11ea-8adf-ccda262736ce	https://socratic.org/questions/what-is-the-ph-of-ch3-3-solution-in-a-titration-of-25ml-of-0-12m-ch3-3-with-0-1m	5.03	start physical_unit 5 6 ph none qc_end physical_unit 5 6 11 12 volume qc_end physical_unit 5 6 14 15 molarity qc_end physical_unit 5 6 24 26 kb qc_end physical_unit 20 20 18 19 molarity qc_end end	[{"type":"physical unit","value":"pH [OF] (CH3)3N solution"}]	[{"type":"physical unit","value":"5.03"}]	[{"type":"physical unit","value":"Volume [OF] (CH3)3N solution [=] \\pu{25 mL}"},{"type":"physical unit","value":"Molarity [OF] (CH3)3N solution [=] \\pu{0.12 M}"},{"type":"physical unit","value":"Kb [OF] (CH3)3N solution [=] \\pu{6.3 x 10^(-5)}"},{"type":"physical unit","value":"Molarity [OF] HCl [=] \\pu{0.1 M}"}]	<h1 class="questionTitle" itemprop="name">What is the pH of (CH3)3N solution, in a titration of 25mL of 0.12M (CH3)3N with 0.1M HCl, and Kb = 6.3 x 10^-5? </h1>	null	5.03	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First thing first, I assume that you're interested in finding the <a href="http://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> of the solution <strong>at equivalence point</strong>, that is, when all the weak base has been <a href="https://socratic.org/chemistry/reactions-in-solution/neutralization">neutralized</a> by the strong acid. </p> <p>The reaction between <em>trimethylamine</em>, <mathjax>#("CH"_3)_3"N"#</mathjax>, a weak base, and <em>hydrochloric acid</em>, <mathjax>#"HCl"#</mathjax>, a strong acid, will produce <em>trimethylammonium ions</em>, <mathjax>#("CH"_3)_3"NH"^(+)#</mathjax>, and <em>chloride ions</em>, <mathjax>#"Cl"^(-)#</mathjax>. </p> <p>For simplicity, I'll use <mathjax>#"Me"#</mathjax> to symbolize a methyl group, <mathjax>#"-CH"_3#</mathjax>. So, the reaction will look like this </p> <blockquote> <p><mathjax>#"Me"_3"N"_text((aq]) + "HCl"_text((aq]) -> "Me"_3"NH"_text((aq])^(+) + "Cl"_text((aq])^(-)#</mathjax></p> </blockquote> <p>Notice that the weak base and the strong acid react in a <mathjax>#1:1#</mathjax> <a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a>. Moreover, the trimethylammonium ion, which is the conjugate acid of trimethylamine, is produced in a <mathjax>#1:1#</mathjax> mole ratio with both reactants. </p> <p>This means that <strong>for every</strong> mole of weak base and strong acid consumed by the reaction, <strong>one mole</strong> of conjugate acid will be produced. </p> <p>Use the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> and volume of the trimethylamine solution to determine how many moles of weak base you start with </p> <blockquote> <p><mathjax>#color(blue)(c = n/V implies n = c * V)#</mathjax></p> <p><mathjax>#n = "0.12 M" * 25 * 10^(-3)"L" = "0.0030 moles Me"_3"N"#</mathjax></p> </blockquote> <p>According to the balanced chemical equation, at <strong>equivalence point</strong> you need <strong>equal numbers of moles</strong> of strong acid and weak base. This means that you need to add </p> <blockquote> <p><mathjax>#color(blue)(c = n/V implies V = n/c)#</mathjax></p> <p><mathjax>#V = (0.0030 color(red)(cancel(color(black)("moles"))))/(0.1color(red)(cancel(color(black)("moles")))/"L") = "0.030 L" = "30 mL"#</mathjax></p> </blockquote> <p>of hydrochloric acid solution. The <strong>total volume</strong> of the resulting solution will be </p> <blockquote> <p><mathjax>#V_"total" = "25 mL" + "30 mL" = "55 mL"#</mathjax></p> </blockquote> <p>Now, the weak base and the strong acid will neutralize each other. This means that the reaction will produce </p> <blockquote> <p><mathjax>#n = "0.0030 moles Me"_3"NH"^(+)#</mathjax></p> </blockquote> <p>The cocnentration of the trimethylammonium ions will be </p> <blockquote> <p><mathjax>#["Me"_3"NH"^(+)] = "0.0030 moles"/(55 * 10^(-3)"L") = "0.545 M"#</mathjax></p> </blockquote> <p>Now, the conjugate acid will react with water to reform the weak base and produce <em>hydronium ions</em>, <mathjax>#"H"_3"O"^(+)#</mathjax>. Use an <strong>ICE table</strong> to determine the equilibrium concentration of the hydronium ions </p> <blockquote> <p><mathjax>#" " "Me"_3"NH"_text((aq])^(+) + "H"_2"O"_text((l]) " "rightleftharpoons" " "Me"_3"N"_text((aq]) + "H"_3"O"_text((aq])^(+)#</mathjax></p> </blockquote> <p><mathjax>#color(purple)("I")" " " " " " "0.545" " " " " " " " " " " " " " " " " " "0" " " " " " " " "0#</mathjax><br/> <mathjax>#color(purple)("C")" " " " " "(-x)" " " " " " " " " " " " " " " "(+x)" " " " "(+x)#</mathjax><br/> <mathjax>#color(purple)("E")" " " "0.545-x" " " " " " " " " " " " " " " "x" " " " " " " " "x#</mathjax></p> <p>Now, to get the <em>acid dissociation constant</em> for the trimethylammonium ion, use the equation</p> <blockquote> <p><mathjax>#color(blue)(K_a * K_b = K_W)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#K_w#</mathjax> - the self-ionization constant for water, equal to <mathjax>#10^(-14)#</mathjax> at room temperature. </p> <p>In your case, you will have </p> <blockquote> <p><mathjax>#K_a = K_W/K_b = 10^(-14)/(6.3 * 10^(-5)) = 1.6 * 10^(-10)#</mathjax></p> </blockquote> <p>By definition, the acid dissociation constant will be </p> <blockquote> <p><mathjax>#K_a = (["Me"_3"N"] * ["H"_3"O"^(+)])/(["Me"_3"NH"^(+)])#</mathjax></p> <p><mathjax>#K_a = (x * x)/(0.545 - x)#</mathjax></p> </blockquote> <p>Because <mathjax>#K_a#</mathjax> is so small, you can say that </p> <blockquote> <p><mathjax>#0.545 - x ~~ 0.545#</mathjax></p> </blockquote> <p>This means that you have </p> <blockquote> <p><mathjax>#K_a = x^2/0.545 = 1.6 * 10^(-10)#</mathjax></p> </blockquote> <p>The value of <mathjax>#x#</mathjax> will be </p> <blockquote> <p><mathjax>#x = sqrt(0.545 * 1.6 * 10^(-10)) = 9.3 * 10^(-6)#</mathjax></p> </blockquote> <p>This means that the concentration of hydronium ions will be </p> <blockquote> <p><mathjax>#["H"_3"O"^(+)] = x = 9.3 * 10^(-6)"M"#</mathjax></p> </blockquote> <p>The pH of the solution will thus be </p> <blockquote> <p><mathjax>#"pH" = -log( ["H"_3"O"^(+)])#</mathjax></p> <p><mathjax>#"pH" = - log(9.3 * 10^(-6)) = color(green)(5.03)#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"pH" = 5.03#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First thing first, I assume that you're interested in finding the <a href="http://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> of the solution <strong>at equivalence point</strong>, that is, when all the weak base has been <a href="https://socratic.org/chemistry/reactions-in-solution/neutralization">neutralized</a> by the strong acid. </p> <p>The reaction between <em>trimethylamine</em>, <mathjax>#("CH"_3)_3"N"#</mathjax>, a weak base, and <em>hydrochloric acid</em>, <mathjax>#"HCl"#</mathjax>, a strong acid, will produce <em>trimethylammonium ions</em>, <mathjax>#("CH"_3)_3"NH"^(+)#</mathjax>, and <em>chloride ions</em>, <mathjax>#"Cl"^(-)#</mathjax>. </p> <p>For simplicity, I'll use <mathjax>#"Me"#</mathjax> to symbolize a methyl group, <mathjax>#"-CH"_3#</mathjax>. So, the reaction will look like this </p> <blockquote> <p><mathjax>#"Me"_3"N"_text((aq]) + "HCl"_text((aq]) -> "Me"_3"NH"_text((aq])^(+) + "Cl"_text((aq])^(-)#</mathjax></p> </blockquote> <p>Notice that the weak base and the strong acid react in a <mathjax>#1:1#</mathjax> <a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a>. Moreover, the trimethylammonium ion, which is the conjugate acid of trimethylamine, is produced in a <mathjax>#1:1#</mathjax> mole ratio with both reactants. </p> <p>This means that <strong>for every</strong> mole of weak base and strong acid consumed by the reaction, <strong>one mole</strong> of conjugate acid will be produced. </p> <p>Use the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> and volume of the trimethylamine solution to determine how many moles of weak base you start with </p> <blockquote> <p><mathjax>#color(blue)(c = n/V implies n = c * V)#</mathjax></p> <p><mathjax>#n = "0.12 M" * 25 * 10^(-3)"L" = "0.0030 moles Me"_3"N"#</mathjax></p> </blockquote> <p>According to the balanced chemical equation, at <strong>equivalence point</strong> you need <strong>equal numbers of moles</strong> of strong acid and weak base. This means that you need to add </p> <blockquote> <p><mathjax>#color(blue)(c = n/V implies V = n/c)#</mathjax></p> <p><mathjax>#V = (0.0030 color(red)(cancel(color(black)("moles"))))/(0.1color(red)(cancel(color(black)("moles")))/"L") = "0.030 L" = "30 mL"#</mathjax></p> </blockquote> <p>of hydrochloric acid solution. The <strong>total volume</strong> of the resulting solution will be </p> <blockquote> <p><mathjax>#V_"total" = "25 mL" + "30 mL" = "55 mL"#</mathjax></p> </blockquote> <p>Now, the weak base and the strong acid will neutralize each other. This means that the reaction will produce </p> <blockquote> <p><mathjax>#n = "0.0030 moles Me"_3"NH"^(+)#</mathjax></p> </blockquote> <p>The cocnentration of the trimethylammonium ions will be </p> <blockquote> <p><mathjax>#["Me"_3"NH"^(+)] = "0.0030 moles"/(55 * 10^(-3)"L") = "0.545 M"#</mathjax></p> </blockquote> <p>Now, the conjugate acid will react with water to reform the weak base and produce <em>hydronium ions</em>, <mathjax>#"H"_3"O"^(+)#</mathjax>. Use an <strong>ICE table</strong> to determine the equilibrium concentration of the hydronium ions </p> <blockquote> <p><mathjax>#" " "Me"_3"NH"_text((aq])^(+) + "H"_2"O"_text((l]) " "rightleftharpoons" " "Me"_3"N"_text((aq]) + "H"_3"O"_text((aq])^(+)#</mathjax></p> </blockquote> <p><mathjax>#color(purple)("I")" " " " " " "0.545" " " " " " " " " " " " " " " " " " "0" " " " " " " " "0#</mathjax><br/> <mathjax>#color(purple)("C")" " " " " "(-x)" " " " " " " " " " " " " " " "(+x)" " " " "(+x)#</mathjax><br/> <mathjax>#color(purple)("E")" " " "0.545-x" " " " " " " " " " " " " " " "x" " " " " " " " "x#</mathjax></p> <p>Now, to get the <em>acid dissociation constant</em> for the trimethylammonium ion, use the equation</p> <blockquote> <p><mathjax>#color(blue)(K_a * K_b = K_W)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#K_w#</mathjax> - the self-ionization constant for water, equal to <mathjax>#10^(-14)#</mathjax> at room temperature. </p> <p>In your case, you will have </p> <blockquote> <p><mathjax>#K_a = K_W/K_b = 10^(-14)/(6.3 * 10^(-5)) = 1.6 * 10^(-10)#</mathjax></p> </blockquote> <p>By definition, the acid dissociation constant will be </p> <blockquote> <p><mathjax>#K_a = (["Me"_3"N"] * ["H"_3"O"^(+)])/(["Me"_3"NH"^(+)])#</mathjax></p> <p><mathjax>#K_a = (x * x)/(0.545 - x)#</mathjax></p> </blockquote> <p>Because <mathjax>#K_a#</mathjax> is so small, you can say that </p> <blockquote> <p><mathjax>#0.545 - x ~~ 0.545#</mathjax></p> </blockquote> <p>This means that you have </p> <blockquote> <p><mathjax>#K_a = x^2/0.545 = 1.6 * 10^(-10)#</mathjax></p> </blockquote> <p>The value of <mathjax>#x#</mathjax> will be </p> <blockquote> <p><mathjax>#x = sqrt(0.545 * 1.6 * 10^(-10)) = 9.3 * 10^(-6)#</mathjax></p> </blockquote> <p>This means that the concentration of hydronium ions will be </p> <blockquote> <p><mathjax>#["H"_3"O"^(+)] = x = 9.3 * 10^(-6)"M"#</mathjax></p> </blockquote> <p>The pH of the solution will thus be </p> <blockquote> <p><mathjax>#"pH" = -log( ["H"_3"O"^(+)])#</mathjax></p> <p><mathjax>#"pH" = - log(9.3 * 10^(-6)) = color(green)(5.03)#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the pH of (CH3)3N solution, in a titration of 25mL of 0.12M (CH3)3N with 0.1M HCl, and Kb = 6.3 x 10^-5? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#reactions-in-solution" itemprop="url"> <span class="breadcrumb" itemprop="title">Reactions in Solution</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/reactions-in-solution/titration-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">Titration Calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="194087" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-28T20:25:28" itemprop="dateCreated"> Nov 28, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"pH" = 5.03#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First thing first, I assume that you're interested in finding the <a href="http://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> of the solution <strong>at equivalence point</strong>, that is, when all the weak base has been <a href="https://socratic.org/chemistry/reactions-in-solution/neutralization">neutralized</a> by the strong acid. </p> <p>The reaction between <em>trimethylamine</em>, <mathjax>#("CH"_3)_3"N"#</mathjax>, a weak base, and <em>hydrochloric acid</em>, <mathjax>#"HCl"#</mathjax>, a strong acid, will produce <em>trimethylammonium ions</em>, <mathjax>#("CH"_3)_3"NH"^(+)#</mathjax>, and <em>chloride ions</em>, <mathjax>#"Cl"^(-)#</mathjax>. </p> <p>For simplicity, I'll use <mathjax>#"Me"#</mathjax> to symbolize a methyl group, <mathjax>#"-CH"_3#</mathjax>. So, the reaction will look like this </p> <blockquote> <p><mathjax>#"Me"_3"N"_text((aq]) + "HCl"_text((aq]) -> "Me"_3"NH"_text((aq])^(+) + "Cl"_text((aq])^(-)#</mathjax></p> </blockquote> <p>Notice that the weak base and the strong acid react in a <mathjax>#1:1#</mathjax> <a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a>. Moreover, the trimethylammonium ion, which is the conjugate acid of trimethylamine, is produced in a <mathjax>#1:1#</mathjax> mole ratio with both reactants. </p> <p>This means that <strong>for every</strong> mole of weak base and strong acid consumed by the reaction, <strong>one mole</strong> of conjugate acid will be produced. </p> <p>Use the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> and volume of the trimethylamine solution to determine how many moles of weak base you start with </p> <blockquote> <p><mathjax>#color(blue)(c = n/V implies n = c * V)#</mathjax></p> <p><mathjax>#n = "0.12 M" * 25 * 10^(-3)"L" = "0.0030 moles Me"_3"N"#</mathjax></p> </blockquote> <p>According to the balanced chemical equation, at <strong>equivalence point</strong> you need <strong>equal numbers of moles</strong> of strong acid and weak base. This means that you need to add </p> <blockquote> <p><mathjax>#color(blue)(c = n/V implies V = n/c)#</mathjax></p> <p><mathjax>#V = (0.0030 color(red)(cancel(color(black)("moles"))))/(0.1color(red)(cancel(color(black)("moles")))/"L") = "0.030 L" = "30 mL"#</mathjax></p> </blockquote> <p>of hydrochloric acid solution. The <strong>total volume</strong> of the resulting solution will be </p> <blockquote> <p><mathjax>#V_"total" = "25 mL" + "30 mL" = "55 mL"#</mathjax></p> </blockquote> <p>Now, the weak base and the strong acid will neutralize each other. This means that the reaction will produce </p> <blockquote> <p><mathjax>#n = "0.0030 moles Me"_3"NH"^(+)#</mathjax></p> </blockquote> <p>The cocnentration of the trimethylammonium ions will be </p> <blockquote> <p><mathjax>#["Me"_3"NH"^(+)] = "0.0030 moles"/(55 * 10^(-3)"L") = "0.545 M"#</mathjax></p> </blockquote> <p>Now, the conjugate acid will react with water to reform the weak base and produce <em>hydronium ions</em>, <mathjax>#"H"_3"O"^(+)#</mathjax>. Use an <strong>ICE table</strong> to determine the equilibrium concentration of the hydronium ions </p> <blockquote> <p><mathjax>#" " "Me"_3"NH"_text((aq])^(+) + "H"_2"O"_text((l]) " "rightleftharpoons" " "Me"_3"N"_text((aq]) + "H"_3"O"_text((aq])^(+)#</mathjax></p> </blockquote> <p><mathjax>#color(purple)("I")" " " " " " "0.545" " " " " " " " " " " " " " " " " " "0" " " " " " " " "0#</mathjax><br/> <mathjax>#color(purple)("C")" " " " " "(-x)" " " " " " " " " " " " " " " "(+x)" " " " "(+x)#</mathjax><br/> <mathjax>#color(purple)("E")" " " "0.545-x" " " " " " " " " " " " " " " "x" " " " " " " " "x#</mathjax></p> <p>Now, to get the <em>acid dissociation constant</em> for the trimethylammonium ion, use the equation</p> <blockquote> <p><mathjax>#color(blue)(K_a * K_b = K_W)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#K_w#</mathjax> - the self-ionization constant for water, equal to <mathjax>#10^(-14)#</mathjax> at room temperature. </p> <p>In your case, you will have </p> <blockquote> <p><mathjax>#K_a = K_W/K_b = 10^(-14)/(6.3 * 10^(-5)) = 1.6 * 10^(-10)#</mathjax></p> </blockquote> <p>By definition, the acid dissociation constant will be </p> <blockquote> <p><mathjax>#K_a = (["Me"_3"N"] * ["H"_3"O"^(+)])/(["Me"_3"NH"^(+)])#</mathjax></p> <p><mathjax>#K_a = (x * x)/(0.545 - x)#</mathjax></p> </blockquote> <p>Because <mathjax>#K_a#</mathjax> is so small, you can say that </p> <blockquote> <p><mathjax>#0.545 - x ~~ 0.545#</mathjax></p> </blockquote> <p>This means that you have </p> <blockquote> <p><mathjax>#K_a = x^2/0.545 = 1.6 * 10^(-10)#</mathjax></p> </blockquote> <p>The value of <mathjax>#x#</mathjax> will be </p> <blockquote> <p><mathjax>#x = sqrt(0.545 * 1.6 * 10^(-10)) = 9.3 * 10^(-6)#</mathjax></p> </blockquote> <p>This means that the concentration of hydronium ions will be </p> <blockquote> <p><mathjax>#["H"_3"O"^(+)] = x = 9.3 * 10^(-6)"M"#</mathjax></p> </blockquote> <p>The pH of the solution will thus be </p> <blockquote> <p><mathjax>#"pH" = -log( ["H"_3"O"^(+)])#</mathjax></p> <p><mathjax>#"pH" = - log(9.3 * 10^(-6)) = color(green)(5.03)#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/194087" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-do-acid-base-titration-calculations"> How do you do acid base titration calculations? 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2,040	ac9a1ee8-6ddd-11ea-b72a-ccda262736ce	https://socratic.org/questions/how-much-ki-is-present-in-836-l-of-a-1-82-m-solution-assuming-the-solvent-is-h-2	252 g	start physical_unit 2 2 mass g qc_end c_other OTHER qc_end physical_unit 12 12 6 7 volume qc_end physical_unit 2 2 10 11 molarity qc_end end	[{"type":"physical unit","value":"Mass [OF] KI [IN] g"}]	[{"type":"physical unit","value":"252 g"}]	[{"type":"other","value":"Assuming the solvent is H2O."},{"type":"physical unit","value":"Volume [OF] KI solution [=] \\pu{0.836 L}"},{"type":"physical unit","value":"Molarity [OF] KI solution [=] \\pu{1.82 M}"}]	<h1 class="questionTitle" itemprop="name">How much #KI# is present in .836 L of a 1.82 M solution, assuming the solvent is #H_2O#? </h1>	null	252 g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>Step 1. Calculate the moles of <mathjax>#"KI"#</mathjax>.</strong></p> <p>Your solution contains 1.82 mol of <mathjax>#"KI"#</mathjax> in 1 L of solution.</p> <p>So, in 0.836 L of solution you have</p> <p><mathjax>#0.836 color(red)(cancel(color(black)("L solution"))) × "1.82 mol KI"/(1 color(red)(cancel(color(black)("L solution")))) = "1.522 mol KI"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 2. Convert moles of <mathjax>#"KI"#</mathjax> to grams of <mathjax>#"KI"#</mathjax></strong></p> <p><mathjax>#"1 mol KI"#</mathjax> has a mass of <mathjax>#"(39.10 + 126.90) g = 166.00 g"#</mathjax>.</p> <p>Hence,</p> <p><mathjax>#"Mass of KI" = 1.522 color(red)(cancel(color(black)("mol KI"))) × "166.00 g KI"/(1 color(red)(cancel(color(black)("mol KI")))) = "252 g KI"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The solution contains 252 g of <mathjax>#"KI"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>Step 1. Calculate the moles of <mathjax>#"KI"#</mathjax>.</strong></p> <p>Your solution contains 1.82 mol of <mathjax>#"KI"#</mathjax> in 1 L of solution.</p> <p>So, in 0.836 L of solution you have</p> <p><mathjax>#0.836 color(red)(cancel(color(black)("L solution"))) × "1.82 mol KI"/(1 color(red)(cancel(color(black)("L solution")))) = "1.522 mol KI"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 2. Convert moles of <mathjax>#"KI"#</mathjax> to grams of <mathjax>#"KI"#</mathjax></strong></p> <p><mathjax>#"1 mol KI"#</mathjax> has a mass of <mathjax>#"(39.10 + 126.90) g = 166.00 g"#</mathjax>.</p> <p>Hence,</p> <p><mathjax>#"Mass of KI" = 1.522 color(red)(cancel(color(black)("mol KI"))) × "166.00 g KI"/(1 color(red)(cancel(color(black)("mol KI")))) = "252 g KI"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How much #KI# is present in .836 L of a 1.82 M solution, assuming the solvent is #H_2O#? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="238426" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-11T22:15:28" itemprop="dateCreated"> Mar 11, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The solution contains 252 g of <mathjax>#"KI"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>Step 1. Calculate the moles of <mathjax>#"KI"#</mathjax>.</strong></p> <p>Your solution contains 1.82 mol of <mathjax>#"KI"#</mathjax> in 1 L of solution.</p> <p>So, in 0.836 L of solution you have</p> <p><mathjax>#0.836 color(red)(cancel(color(black)("L solution"))) × "1.82 mol KI"/(1 color(red)(cancel(color(black)("L solution")))) = "1.522 mol KI"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 2. Convert moles of <mathjax>#"KI"#</mathjax> to grams of <mathjax>#"KI"#</mathjax></strong></p> <p><mathjax>#"1 mol KI"#</mathjax> has a mass of <mathjax>#"(39.10 + 126.90) g = 166.00 g"#</mathjax>.</p> <p>Hence,</p> <p><mathjax>#"Mass of KI" = 1.522 color(red)(cancel(color(black)("mol KI"))) × "166.00 g KI"/(1 color(red)(cancel(color(black)("mol KI")))) = "252 g KI"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/238426" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-morality-be-used-as-a-conversion-factor"> How can molarity be used as a conversion factor? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-high-can-molarity-be"> How high can molarity be? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-molarity-change-with-temperature"> How does molarity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molarity-of-a-solution"> How do you find molarity of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-10-naoh"> What is the molarity of 10 NaOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-3-hydrogen-peroxide"> What is the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1250 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How much #KI# is present in .836 L of a 1.82 M solution, assuming the solvent is #H_2O#?	null
2,041	abd1295c-6ddd-11ea-b398-ccda262736ce	https://socratic.org/questions/581f67c87c0149442b09e1ce	10 g/L	start physical_unit 22 23 density g/l qc_end physical_unit 22 23 8 9 mass qc_end physical_unit 16 16 14 15 volume qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Density [OF] the gas [IN] g/L"}]	[{"type":"physical unit","value":"10 g/L"}]	[{"type":"physical unit","value":"Mass [OF] the gas [=] \\pu{222 g}"},{"type":"physical unit","value":"Volume [OF] container [=] \\pu{22.4 L}"},{"type":"other","value":"A molar volume of gas."}]	<h1 class="questionTitle" itemprop="name">A molar volume of gas whose mass is #222gmol^-1# is confined in a #22.4L# container. What is the density of the gas in #gL^-1#?</h1>	null	10 g/L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#rho, "density"="Mass"/"Volume"#</mathjax>.</p> <p>If we assume that the gas behaves ideally (a safe assumption!) then,</p> <p><mathjax>#rho=(222gmol^-1)/(22.4Lmol^-1)~=10gL^-1#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>At <mathjax>#"STP"#</mathjax>, one mole of ideal gas occupies occupies a volume of <mathjax>#22.4L#</mathjax>. So.......</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#rho, "density"="Mass"/"Volume"#</mathjax>.</p> <p>If we assume that the gas behaves ideally (a safe assumption!) then,</p> <p><mathjax>#rho=(222gmol^-1)/(22.4Lmol^-1)~=10g*L^-1#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A molar volume of gas whose mass is #222gmol^-1# is confined in a #22.4L# container. What is the density of the gas in #gL^-1#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="332412" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-11-06T17:42:36" itemprop="dateCreated"> Nov 6, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>At <mathjax>#"STP"#</mathjax>, one mole of ideal gas occupies occupies a volume of <mathjax>#22.4L#</mathjax>. So.......</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#rho, "density"="Mass"/"Volume"#</mathjax>.</p> <p>If we assume that the gas behaves ideally (a safe assumption!) then,</p> <p><mathjax>#rho=(222gmol^-1)/(22.4Lmol^-1)~=10g*L^-1#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/332412" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-morality-be-used-as-a-conversion-factor"> How can molarity be used as a conversion factor? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-high-can-molarity-be"> How high can molarity be? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-molarity-change-with-temperature"> How does molarity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molarity-of-a-solution"> How do you find molarity of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-10-naoh"> What is the molarity of 10 NaOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-3-hydrogen-peroxide"> What is the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1545 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A molar volume of gas whose mass is #222gmol^-1# is confined in a #22.4L# container. What is the density of the gas in #gL^-1#?	null
2,042	aad7fa66-6ddd-11ea-8b2b-ccda262736ce	https://socratic.org/questions/how-do-you-balance-fe-s-s-s-fe-2s-3-s	2 Fe(s) + 3 S(s) -> Fe2S3(s)	start chemical_equation qc_end chemical_equation 4 8 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the equation"}]	[{"type":"chemical equation","value":"2 Fe(s) + 3 S(s) -> Fe2S3(s)"}]	[{"type":"chemical equation","value":"Fe(s) + S(s) -> Fe2S3(s)"}]	<h1 class="questionTitle" itemprop="name">How do you balance #Fe(s) + S(s) -> Fe_2S_3(s)#?</h1>	null	2 Fe(s) + 3 S(s) -> Fe2S3(s)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Step 1 : First of all write the equation<br/> <mathjax>#Fe_(s)#</mathjax> + <mathjax>#S_(s)#</mathjax> ------------> <mathjax>#Fe_2S_3#</mathjax></p> <p>Step 2 : Now balance the number of <mathjax>#Fe#</mathjax> atoms on both reactant and product side</p> <p>Here reactant side has one <mathjax>#Fe_(S)#</mathjax> atom and product side has <mathjax>#2#</mathjax> atoms of <mathjax>#Fe_(S)#</mathjax>, therefore multiply <mathjax>#Fe_(S)#</mathjax> at reactant side by <mathjax>#2#</mathjax></p> <p>Step 3: Balance <mathjax>#S_(s)#</mathjax></p> <p>Here reactant side has one <mathjax>#S_(s)#</mathjax> atom and product side has <mathjax>#3#</mathjax> atoms of <mathjax>#S_(s)#</mathjax>, therefore multiply <mathjax>#S_(s)#</mathjax> at reactant side by <mathjax>#3#</mathjax></p> <p>Step 4.<br/> Write the final eqaution</p> <p><mathjax>#2Fe_(s)#</mathjax> + <mathjax>#3S_(s)#</mathjax> ------------> <mathjax>#Fe_2S_3#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2Fe_(s)#</mathjax> + <mathjax>#3S_(s)#</mathjax> ------------> <mathjax>#Fe_2S_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Step 1 : First of all write the equation<br/> <mathjax>#Fe_(s)#</mathjax> + <mathjax>#S_(s)#</mathjax> ------------> <mathjax>#Fe_2S_3#</mathjax></p> <p>Step 2 : Now balance the number of <mathjax>#Fe#</mathjax> atoms on both reactant and product side</p> <p>Here reactant side has one <mathjax>#Fe_(S)#</mathjax> atom and product side has <mathjax>#2#</mathjax> atoms of <mathjax>#Fe_(S)#</mathjax>, therefore multiply <mathjax>#Fe_(S)#</mathjax> at reactant side by <mathjax>#2#</mathjax></p> <p>Step 3: Balance <mathjax>#S_(s)#</mathjax></p> <p>Here reactant side has one <mathjax>#S_(s)#</mathjax> atom and product side has <mathjax>#3#</mathjax> atoms of <mathjax>#S_(s)#</mathjax>, therefore multiply <mathjax>#S_(s)#</mathjax> at reactant side by <mathjax>#3#</mathjax></p> <p>Step 4.<br/> Write the final eqaution</p> <p><mathjax>#2Fe_(s)#</mathjax> + <mathjax>#3S_(s)#</mathjax> ------------> <mathjax>#Fe_2S_3#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you balance #Fe(s) + S(s) -> Fe_2S_3(s)#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="381485" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/sarita-rana"><img alt="" class="" src="https://profilepictures.socratic.org/tvT08VaORGyEZTsSaNA4_images.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/sarita-rana"> Sarita Rana </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-02-22T17:45:03" itemprop="dateCreated"> Feb 22, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2Fe_(s)#</mathjax> + <mathjax>#3S_(s)#</mathjax> ------------> <mathjax>#Fe_2S_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Step 1 : First of all write the equation<br/> <mathjax>#Fe_(s)#</mathjax> + <mathjax>#S_(s)#</mathjax> ------------> <mathjax>#Fe_2S_3#</mathjax></p> <p>Step 2 : Now balance the number of <mathjax>#Fe#</mathjax> atoms on both reactant and product side</p> <p>Here reactant side has one <mathjax>#Fe_(S)#</mathjax> atom and product side has <mathjax>#2#</mathjax> atoms of <mathjax>#Fe_(S)#</mathjax>, therefore multiply <mathjax>#Fe_(S)#</mathjax> at reactant side by <mathjax>#2#</mathjax></p> <p>Step 3: Balance <mathjax>#S_(s)#</mathjax></p> <p>Here reactant side has one <mathjax>#S_(s)#</mathjax> atom and product side has <mathjax>#3#</mathjax> atoms of <mathjax>#S_(s)#</mathjax>, therefore multiply <mathjax>#S_(s)#</mathjax> at reactant side by <mathjax>#3#</mathjax></p> <p>Step 4.<br/> Write the final eqaution</p> <p><mathjax>#2Fe_(s)#</mathjax> + <mathjax>#3S_(s)#</mathjax> ------------> <mathjax>#Fe_2S_3#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/381485" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a 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2,043	aa1fead3-6ddd-11ea-aeab-ccda262736ce	https://socratic.org/questions/58b80b0b11ef6b15bcfa5218	SiO2(s) + 6 HF(aq) -> SiF6^2- + 2 H3O+	start chemical_equation qc_end substance 2 3 qc_end substance 6 7 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the reaction"}]	[{"type":"chemical equation","value":"SiO2(s) + 6 HF(aq) -> SiF6^2- + 2 H3O+"}]	[{"type":"substance name","value":"Silicon dioxide"},{"type":"substance name","value":"Hydrofluoric acid"}]	<h1 class="questionTitle" itemprop="name">How does silicon dioxide react with hydrofluoric acid?</h1>	null	SiO2(s) + 6 HF(aq) -> SiF6^2- + 2 H3O+	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#SiO_2(s) + 6HF(aq) rarr SiF_6^(2-) + 2H_3O^(+)#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Silicon dioxide can give the <mathjax>#SiF_6^(2-)#</mathjax> ion upon treatment with hydrofluoric acid. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#SiO_2(s) + 6HF(aq) rarr SiF_6^(2-) + 2H_3O^(+)#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How does silicon dioxide react with hydrofluoric acid?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-reactions-and-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions and Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="386760" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-05T09:33:54" itemprop="dateCreated"> Mar 5, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Silicon dioxide can give the <mathjax>#SiF_6^(2-)#</mathjax> ion upon treatment with hydrofluoric acid. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#SiO_2(s) + 6HF(aq) rarr SiF_6^(2-) + 2H_3O^(+)#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/386760" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" 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</div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1349 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How does silicon dioxide react with hydrofluoric acid?	null
2,044	ad294069-6ddd-11ea-9cf4-ccda262736ce	https://socratic.org/questions/58ee3554b72cff633c63f496	2164.80 g	start physical_unit 2 3 mass g qc_end physical_unit 12 12 8 9 volume qc_end end	[{"type":"physical unit","value":"Mass [OF] carbon dioxide [IN] g"}]	[{"type":"physical unit","value":"2164.80 g"}]	[{"type":"physical unit","value":"Volume [OF] octane [=] \\pu{1 L}"}]	<h1 class="questionTitle" itemprop="name">How much carbon dioxide is released when a #1*L# volume of octane is combusted?</h1>	null	2164.80 g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We reproduce your given equation:</p> <p><mathjax>#C_8H_18(l) +25/2O_2(g) rarr 8CO_2(g) + 9H_2O(l)#</mathjax></p> <p>I halved the stoichiometric equation to make the arithmetic a bit easier.</p> <p><mathjax>#"Moles of octane"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(1cancelLxx10^3cancel(mLL^-1)xx0.703cancel(gmL^-1))/(114.24cancelgmol^-1)=6.15mol#</mathjax></p> <p>And given the <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>, <mathjax>#"FOR EACH MOLE OCTANE"#</mathjax> <mathjax>#"COMBUSTED THERE ARE 8 MOLE CARBON"#</mathjax> <mathjax>#"DIOXIDE EVOLVED"#</mathjax>, i.e. so approx. <mathjax>#49mol#</mathjax> carbon dioxide gas.........which represents a mass of over <mathjax>#2kg#</mathjax>. </p> <p>Questions like this often ask you to estimate the volume occupied by the gas under standard conditions. Can you do this?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Let us suppose that we use a <mathjax>#1L#</mathjax> of octane to when we drive our motor...............</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We reproduce your given equation:</p> <p><mathjax>#C_8H_18(l) +25/2O_2(g) rarr 8CO_2(g) + 9H_2O(l)#</mathjax></p> <p>I halved the stoichiometric equation to make the arithmetic a bit easier.</p> <p><mathjax>#"Moles of octane"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(1cancelLxx10^3cancel(mLL^-1)xx0.703cancel(gmL^-1))/(114.24cancelgmol^-1)=6.15mol#</mathjax></p> <p>And given the <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>, <mathjax>#"FOR EACH MOLE OCTANE"#</mathjax> <mathjax>#"COMBUSTED THERE ARE 8 MOLE CARBON"#</mathjax> <mathjax>#"DIOXIDE EVOLVED"#</mathjax>, i.e. so approx. <mathjax>#49mol#</mathjax> carbon dioxide gas.........which represents a mass of over <mathjax>#2*kg#</mathjax>. </p> <p>Questions like this often ask you to estimate the volume occupied by the gas under standard conditions. Can you do this?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How much carbon dioxide is released when a #1L# volume of octane is combusted?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="405767" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-12T15:34:21" itemprop="dateCreated"> Apr 12, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Let us suppose that we use a <mathjax>#1L#</mathjax> of octane to when we drive our motor...............</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We reproduce your given equation:</p> <p><mathjax>#C_8H_18(l) +25/2O_2(g) rarr 8CO_2(g) + 9H_2O(l)#</mathjax></p> <p>I halved the stoichiometric equation to make the arithmetic a bit easier.</p> <p><mathjax>#"Moles of octane"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(1cancelLxx10^3cancel(mLL^-1)xx0.703cancel(gmL^-1))/(114.24cancelgmol^-1)=6.15mol#</mathjax></p> <p>And given the <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>, <mathjax>#"FOR EACH MOLE OCTANE"#</mathjax> <mathjax>#"COMBUSTED THERE ARE 8 MOLE CARBON"#</mathjax> <mathjax>#"DIOXIDE EVOLVED"#</mathjax>, i.e. so approx. <mathjax>#49mol#</mathjax> carbon dioxide gas.........which represents a mass of over <mathjax>#2kg#</mathjax>. </p> <p>Questions like this often ask you to estimate the volume occupied by the gas under standard conditions. Can you do this?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/405767" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What is stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ab82402bf342f48d93ac6"> Question #93ac6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-we-study-stoichiometry"> Why do we study stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-naoh-is-produced-from-1-20-x-102-grams-of-na2o-na2o-h2o-2-naoh"> How many grams of NaOH is produced from #1.20 x 10^2# grams of #Na_2O#? #Na_2O + H_2O -> 2NaOH# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-na2o-are-required-to-produce-1-60-x-102-grams-of-naoh-na2o-h2o"> How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? 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2,045	aa8c6ac0-6ddd-11ea-9d10-ccda262736ce	https://socratic.org/questions/what-is-a-balanced-equation-for-the-combustion-of-gaseous-ethane-c-2h-6-a-minori	C2H6(g) + 7/2 O2(g) -> 2 CO2(g) + 3 H2O(g)	start chemical_equation qc_end chemical_equation 11 11 qc_end substance 23 24 qc_end substance 27 29 qc_end substance 31 32 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the combustion"}]	[{"type":"chemical equation","value":"C2H6(g) + 7/2 O2(g) -> 2 CO2(g) + 3 H2O(g)"}]	[{"type":"chemical equation","value":"C2H6"},{"type":"substance name","value":"Gaseous oxygen"},{"type":"substance name","value":"Gaseous carbon dioxide"},{"type":"substance name","value":"Gaseous water"}]	<h1 class="questionTitle" itemprop="name">What is a balanced equation for the combustion of gaseous ethane (#C_2H_6#), a minority component of natural gas, in which it combines with gaseous oxygen to form gaseous carbon dioxide and gaseous water?</h1>	null	C2H6(g) + 7/2 O2(g) -> 2 CO2(g) + 3 H2O(g)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You can double the equation if you like; either equation shows that 1 equiv of ethane reacts with 7/2 equiv dioxygen gas to give 2 equiv carbon dioxide and 3 equiv of water.</p> <p>How does energy transfer in the reaction. Is it exothermic or endothermic?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_2H_6(g) + 7/2O_2(g) rarr 2CO_2(g) +3H_2O(g)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You can double the equation if you like; either equation shows that 1 equiv of ethane reacts with 7/2 equiv dioxygen gas to give 2 equiv carbon dioxide and 3 equiv of water.</p> <p>How does energy transfer in the reaction. Is it exothermic or endothermic?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is a balanced equation for the combustion of gaseous ethane (#C_2H_6#), a minority component of natural gas, in which it combines with gaseous oxygen to form gaseous carbon dioxide and gaseous water?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="330660" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-11-03T09:30:40" itemprop="dateCreated"> Nov 3, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_2H_6(g) + 7/2O_2(g) rarr 2CO_2(g) +3H_2O(g)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You can double the equation if you like; either equation shows that 1 equiv of ethane reacts with 7/2 equiv dioxygen gas to give 2 equiv carbon dioxide and 3 equiv of water.</p> <p>How does energy transfer in the reaction. Is it exothermic or endothermic?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/330660" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------> H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -> Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? 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Sodium phosphate and calcium chloride react to form... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-equation-kclo3-kcl-o2"> How can I balance this equation? ____ #KClO_3 -># ____ #KCl +# ____ #O_2# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-balancing-chemical-equations-important"> Why is balancing chemical equations important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/balancing-chemical-equations"> See all questions in Balancing Chemical Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 27949 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is a balanced equation for the combustion of gaseous ethane (#C_2H_6#), a minority component of natural gas, in which it combines with gaseous oxygen to form gaseous carbon dioxide and gaseous water?	null
2,046	aa136793-6ddd-11ea-bc26-ccda262736ce	https://socratic.org/questions/750-ml-of-a-5-molar-solution-needs-to-be-diluted-to-1m-how-much-water-should-be-	3.75 L	start physical_unit 16 16 volume l qc_end physical_unit 6 6 4 5 molarity qc_end physical_unit 6 6 0 1 volume qc_end physical_unit 6 6 12 13 molarity qc_end end	[{"type":"physical unit","value":"Volume [OF] water [IN] L"}]	[{"type":"physical unit","value":"3.75 L"}]	[{"type":"physical unit","value":"Molarity1 [OF] solution [=] \\pu{5.0 M}"},{"type":"physical unit","value":"Volume1 [OF] solution [=] \\pu{750 mL}"},{"type":"physical unit","value":"Molarity2 [OF] solution [=] \\pu{1.0 M}"}]	<h1 class="questionTitle" itemprop="name">#"750. mL"# of a #"5.0 M"# solution needs to be diluted to #"1.0 M"#. How much water should be added to reach this concentration? </h1>	null	3.75 L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The trick here is to realize that because the amount of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> <strong>must remain constant</strong> in a dilution, the <strong>decrease</strong> in concentration must be <strong>equal</strong> to the <strong>increase</strong> in volume. </p> <p>In other words, diluting a solution will <strong>decrease</strong> its concentration by a factor <mathjax>#"DF"#</mathjax> and <strong>increase</strong> its volume by the same factor <mathjax>#"DF"#</mathjax>. </p> <p>This factor is called the <strong>dilution factor</strong> and can be written as</p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)("DF" = overbrace(c_"concentrated"/c_"diluted")^(color(red)("decrease in concentration")) = overbrace(V_"diluted"/V_"concentrated")^(color(purple)("increase in volume")) )))#</mathjax></p> </blockquote> <p>In your case, the concentration decreases by a factor of </p> <blockquote> <p><mathjax>#"DF" = (5.0 color(red)(cancel(color(black)("M"))))/(1.0color(red)(cancel(color(black)("M")))) = color(blue)(5)#</mathjax></p> </blockquote> <p>which means that the volume must increase by factor of <mathjax>#color(blue)(5)#</mathjax></p> <blockquote> <p><mathjax>#V_"diluted" = color(blue)(5) * "750. mL" = "3750 mL"#</mathjax></p> </blockquote> <p>This means that you must add</p> <blockquote> <p><mathjax>#"volume of water" = "3750 mL" - "750. mL" = color(darkgreen)(ul(color(black)(3.0 * 10^(3)color(white)(.)"mL")))#</mathjax></p> </blockquote> <p>of water to your concentrated solution in order to dilute it from <mathjax>#"5 M"#</mathjax> to <mathjax>#"1 M"#</mathjax>. </p> <p>The answer is rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#3.0 * 10^3"mL"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The trick here is to realize that because the amount of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> <strong>must remain constant</strong> in a dilution, the <strong>decrease</strong> in concentration must be <strong>equal</strong> to the <strong>increase</strong> in volume. </p> <p>In other words, diluting a solution will <strong>decrease</strong> its concentration by a factor <mathjax>#"DF"#</mathjax> and <strong>increase</strong> its volume by the same factor <mathjax>#"DF"#</mathjax>. </p> <p>This factor is called the <strong>dilution factor</strong> and can be written as</p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)("DF" = overbrace(c_"concentrated"/c_"diluted")^(color(red)("decrease in concentration")) = overbrace(V_"diluted"/V_"concentrated")^(color(purple)("increase in volume")) )))#</mathjax></p> </blockquote> <p>In your case, the concentration decreases by a factor of </p> <blockquote> <p><mathjax>#"DF" = (5.0 color(red)(cancel(color(black)("M"))))/(1.0color(red)(cancel(color(black)("M")))) = color(blue)(5)#</mathjax></p> </blockquote> <p>which means that the volume must increase by factor of <mathjax>#color(blue)(5)#</mathjax></p> <blockquote> <p><mathjax>#V_"diluted" = color(blue)(5) * "750. mL" = "3750 mL"#</mathjax></p> </blockquote> <p>This means that you must add</p> <blockquote> <p><mathjax>#"volume of water" = "3750 mL" - "750. mL" = color(darkgreen)(ul(color(black)(3.0 * 10^(3)color(white)(.)"mL")))#</mathjax></p> </blockquote> <p>of water to your concentrated solution in order to dilute it from <mathjax>#"5 M"#</mathjax> to <mathjax>#"1 M"#</mathjax>. </p> <p>The answer is rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">#"750. mL"# of a #"5.0 M"# solution needs to be diluted to #"1.0 M"#. How much water should be added to reach this concentration? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/dilution-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">Dilution Calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="385690" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-03T02:50:56" itemprop="dateCreated"> Mar 3, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#3.0 * 10^3"mL"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The trick here is to realize that because the amount of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> <strong>must remain constant</strong> in a dilution, the <strong>decrease</strong> in concentration must be <strong>equal</strong> to the <strong>increase</strong> in volume. </p> <p>In other words, diluting a solution will <strong>decrease</strong> its concentration by a factor <mathjax>#"DF"#</mathjax> and <strong>increase</strong> its volume by the same factor <mathjax>#"DF"#</mathjax>. </p> <p>This factor is called the <strong>dilution factor</strong> and can be written as</p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)("DF" = overbrace(c_"concentrated"/c_"diluted")^(color(red)("decrease in concentration")) = overbrace(V_"diluted"/V_"concentrated")^(color(purple)("increase in volume")) )))#</mathjax></p> </blockquote> <p>In your case, the concentration decreases by a factor of </p> <blockquote> <p><mathjax>#"DF" = (5.0 color(red)(cancel(color(black)("M"))))/(1.0color(red)(cancel(color(black)("M")))) = color(blue)(5)#</mathjax></p> </blockquote> <p>which means that the volume must increase by factor of <mathjax>#color(blue)(5)#</mathjax></p> <blockquote> <p><mathjax>#V_"diluted" = color(blue)(5) * "750. mL" = "3750 mL"#</mathjax></p> </blockquote> <p>This means that you must add</p> <blockquote> <p><mathjax>#"volume of water" = "3750 mL" - "750. mL" = color(darkgreen)(ul(color(black)(3.0 * 10^(3)color(white)(.)"mL")))#</mathjax></p> </blockquote> <p>of water to your concentrated solution in order to dilute it from <mathjax>#"5 M"#</mathjax> to <mathjax>#"1 M"#</mathjax>. </p> <p>The answer is rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/385690" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-concentration-from-absorbance"> How do you calculate concentration from absorbance? 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How much water should be added to reach this concentration?	null
2,047	abf891a6-6ddd-11ea-8a70-ccda262736ce	https://socratic.org/questions/if-0-225-mol-of-tin-combines-with-0-450-mol-of-sulfur-what-is-the-empirical-form	SnS2	start chemical_formula qc_end physical_unit 4 4 1 2 mole qc_end physical_unit 10 10 7 8 mole qc_end end	[{"type":"other","value":"Chemical Formula [OF] the tin sulfide [IN] empirical"}]	[{"type":"chemical equation","value":"SnS2"}]	[{"type":"physical unit","value":"Mole [OF] tin [=] \\pu{0.225 mol}"},{"type":"physical unit","value":"Mole [OF] sulfur [=] \\pu{0.450 mol}"}]	<h1 class="questionTitle" itemprop="name">If 0.225 mol of tin combines with 0.450 mol of sulfur, what is the empirical formula of the tin sulfide product? </h1>	null	SnS2	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>By definition, the empirical formula is the simplest whole numer ratio that defines constituent atoms in a species. Normally we are given percentages, and use this mass percent to determine the elemental composition. Here, we are explicitly given the molar ratios, i.e. <mathjax>#Sn:S, 1:2#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, clearly it is <mathjax>#SnS_2#</mathjax>. Why?</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>By definition, the empirical formula is the simplest whole numer ratio that defines constituent atoms in a species. Normally we are given percentages, and use this mass percent to determine the elemental composition. Here, we are explicitly given the molar ratios, i.e. <mathjax>#Sn:S, 1:2#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">If 0.225 mol of tin combines with 0.450 mol of sulfur, what is the empirical formula of the tin sulfide product? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="268703" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-23T06:30:07" itemprop="dateCreated"> May 23, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, clearly it is <mathjax>#SnS_2#</mathjax>. Why?</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>By definition, the empirical formula is the simplest whole numer ratio that defines constituent atoms in a species. Normally we are given percentages, and use this mass percent to determine the elemental composition. Here, we are explicitly given the molar ratios, i.e. <mathjax>#Sn:S, 1:2#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/268703" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molecular-formula-of-a-compound"> How do you find molecular formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-diamond"> What is the chemical formula of a diamond? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-carbohydrate"> What is the chemical formula of a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-valproic-acid"> What is the empirical formula for valproic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-of-magnesium-oxide"> What is the empirical formula of magnesium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-empirical-formula-not-double-that-of-the-monosaccharides"> Why is the empirical formula not double that of the monosaccharides? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5331180502bf342f40b5c3b5"> Question #5c3b5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-molecular-formula-represents-a-carbohydrate"> What molecular formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-of-vinegar"> What is the molecular formula of vinegar? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/empirical-and-molecular-formulas"> See all questions in Empirical and Molecular Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 4345 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	If 0.225 mol of tin combines with 0.450 mol of sulfur, what is the empirical formula of the tin sulfide product?	null
2,048	aa744e5c-6ddd-11ea-8322-ccda262736ce	https://socratic.org/questions/how-many-moles-are-in-1-56-x-10-23-atoms-of-silver-ag	0.26 moles	start physical_unit 11 11 mole mol qc_end end	[{"type":"physical unit","value":"Mole [OF] Ag [IN] moles"}]	[{"type":"physical unit","value":"0.26 moles"}]	[{"type":"physical unit","value":"Number [OF] Ag atoms [=] \\pu{1.56 × 10^23}"}]	<h1 class="questionTitle" itemprop="name">How many moles are in #1.56 x 10^23# atoms of silver (Ag)?</h1>	null	0.26 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>All <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a>, regardless of what element they are, always have <br/> 6.02 x <mathjax>#10^23#</mathjax> number of atoms in one mole.</p> <p>Hence,</p> <p>6.02 x <mathjax>#10^23#</mathjax> ---> 1 mol</p> <p>1.56 x <mathjax>#10^23#</mathjax> ---> <mathjax>#(1.56 * 10^23)/(6.0210^23) 1#</mathjax> = 0.259 mol (3 significant figures)</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.259 mol</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>All <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a>, regardless of what element they are, always have <br/> 6.02 x <mathjax>#10^23#</mathjax> number of atoms in one mole.</p> <p>Hence,</p> <p>6.02 x <mathjax>#10^23#</mathjax> ---> 1 mol</p> <p>1.56 x <mathjax>#10^23#</mathjax> ---> <mathjax>#(1.56 * 10^23)/(6.0210^23) 1#</mathjax> = 0.259 mol (3 significant figures)</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles are in #1.56 x 10^23# atoms of silver (Ag)?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="403840" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/alyssa-24"><img alt="" class="" src="https://profilepictures.socratic.org/5HCkrFRYSimKMjU12O0V_File_000.jpeg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/alyssa-24"> Alyssa </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-08T22:53:30" itemprop="dateCreated"> Apr 8, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.259 mol</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>All <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a>, regardless of what element they are, always have <br/> 6.02 x <mathjax>#10^23#</mathjax> number of atoms in one mole.</p> <p>Hence,</p> <p>6.02 x <mathjax>#10^23#</mathjax> ---> 1 mol</p> <p>1.56 x <mathjax>#10^23#</mathjax> ---> <mathjax>#(1.56 * 10^23)/(6.0210^23) 1#</mathjax> = 0.259 mol (3 significant figures)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/403840" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? 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2,049	ab4d219d-6ddd-11ea-8a21-ccda262736ce	https://socratic.org/questions/how-many-grams-of-cr-no-3-2-are-in-8-4-mole	176.01 grams	start physical_unit 4 4 mass g qc_end physical_unit 4 4 7 8 mole qc_end end	[{"type":"physical unit","value":"Mass [OF] Cr(NO3)2 [IN] grams"}]	[{"type":"physical unit","value":"176.01 grams"}]	[{"type":"physical unit","value":"Mole [OF] Cr(NO3)2 [=] \\pu{8.4 moles}"}]	<h1 class="questionTitle" itemprop="name">How many grams of #Cr(NO_3)_2# are in 8.4 mole?</h1>	null	176.01 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You have an <mathjax>#8.4#</mathjax> <mathjax>#mol#</mathjax> quantity, which has a mass of <mathjax>#8.4cancel(mol)xx176.01g*cancel(mol^-1)#</mathjax> <mathjax>#~=#</mathjax> <mathjax>#1.5#</mathjax> <mathjax>#kg#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Chromous nitrate, <mathjax>#Cr(NO_3)_2#</mathjax>, has a formula weight of <mathjax>#176.01#</mathjax> <mathjax>#gmol#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You have an <mathjax>#8.4#</mathjax> <mathjax>#mol#</mathjax> quantity, which has a mass of <mathjax>#8.4cancel(mol)xx176.01gcancel(mol^-1)#</mathjax> <mathjax>#~=#</mathjax> <mathjax>#1.5#</mathjax> <mathjax>#kg#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many grams of #Cr(NO_3)_2# are in 8.4 mole?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="244498" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-24T16:43:37" itemprop="dateCreated"> Mar 24, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Chromous nitrate, <mathjax>#Cr(NO_3)_2#</mathjax>, has a formula weight of <mathjax>#176.01#</mathjax> <mathjax>#gmol#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You have an <mathjax>#8.4#</mathjax> <mathjax>#mol#</mathjax> quantity, which has a mass of <mathjax>#8.4cancel(mol)xx176.01gcancel(mol^-1)#</mathjax> <mathjax>#~=#</mathjax> <mathjax>#1.5#</mathjax> <mathjax>#kg#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/244498" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="244499" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/larry-l"><img alt="" class="" src="https://profilepictures.socratic.org/yqebo7rVRTqcSuSK9nT8_photo.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/larry-l"> Larry Leitch-Casey </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-24T16:57:36" itemprop="dateCreated"> Mar 24, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Hi there!</p> <p>With <mathjax>#Cr(NO_3)_2#</mathjax>, there is approximately 1460.97 g in 8.3 moles. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To figure this out, note the relationship between mass, molar mass and moles whereby:</p> <p>n (moles) = mass/molar mass... </p> <p>or if you're more of a visual oriented learner, I will show the unit conversion/dimensional analysis method! Either will work!</p> <p>Let's start off with what you're given:</p> <p>n = 8.3<br/> m (mass in grams) = ?<br/> M (molar mass) = <mathjax>#Cr(NO_3)_2 = (52.00 g/(mol)+)2((14.01 g/(mol))+3(16.00g/(mol)))#</mathjax></p> <p><mathjax># M = 176.02 g/(mol) #</mathjax></p> <p>Now you know n and M, you can find m using the aforementioned expression! Substituting in you get:</p> <p><mathjax># 8.3 = m/(176.02) #</mathjax></p> <p><mathjax># m = (8.3)(176.02) #</mathjax></p> <p><mathjax># m = 1460.97 g #</mathjax></p> <p>You can also use unit conversion/dimensional analysis whereby:</p> <p><mathjax># 8.3 mol * 176.02 g/(mol) -> #</mathjax> Moles cancel and you're left with:</p> <p><mathjax># 1460.97 g #</mathjax></p> <p>Therefore, in 8.3 moles of <mathjax>#Cr(NO_3)_2#</mathjax>, there is approximately 1460.97 g! Hopefully this was helpful! If you have any questions, let me know! :)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/244499" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1631 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many grams of #Cr(NO_3)_2# are in 8.4 mole?	null
2,050	ab0132e4-6ddd-11ea-b129-ccda262736ce	https://socratic.org/questions/how-much-heat-energy-must-be-absorbed-to-completely-melt-35-0-grams-of-h-2o-s-at	11690 J	start physical_unit 13 13 heat_energy j qc_end c_other OTHER qc_end physical_unit 13 13 10 11 mass qc_end physical_unit 13 13 15 16 temperature qc_end end	[{"type":"physical unit","value":"Absorbed heat energy [OF] H2O(s) [IN] J"}]	[{"type":"physical unit","value":"11690 J"}]	[{"type":"other","value":"Completely melt."},{"type":"physical unit","value":"Mass [OF] H2O(s) [=] \\pu{35.0 grams}"},{"type":"physical unit","value":"Temperature [OF] H2O(s) [=] \\pu{0 ℃}"}]	<h1 class="questionTitle" itemprop="name">How much heat energy must be absorbed to completely melt 35.0 grams of #H_2O#(s) at 0°C? </h1>	null	11690 J	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Here, we melt the piece of ice, so we use the latent heat of fusion. The equation is thus:</p> <p><mathjax>#q=mL_f#</mathjax></p> <p>where:</p> <blockquote> <ul> <li> <p><mathjax>#q#</mathjax> is the heat energy supplied in joules</p> </li> <li> <p><mathjax>#m#</mathjax> is the mass of the substance</p> </li> <li> <p><mathjax>#L_f#</mathjax> is the latent heat of fusion of the substance</p> </li> </ul> </blockquote> <p>So here, we get:</p> <p><mathjax>#q=35color(red)cancelcolor(black)"g"*(334 \ "J")/(color(red)cancelcolor(black)"g")=11690 \ "J"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#11690#</mathjax> joules</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Here, we melt the piece of ice, so we use the latent heat of fusion. The equation is thus:</p> <p><mathjax>#q=mL_f#</mathjax></p> <p>where:</p> <blockquote> <ul> <li> <p><mathjax>#q#</mathjax> is the heat energy supplied in joules</p> </li> <li> <p><mathjax>#m#</mathjax> is the mass of the substance</p> </li> <li> <p><mathjax>#L_f#</mathjax> is the latent heat of fusion of the substance</p> </li> </ul> </blockquote> <p>So here, we get:</p> <p><mathjax>#q=35color(red)cancelcolor(black)"g"*(334 \ "J")/(color(red)cancelcolor(black)"g")=11690 \ "J"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How much heat energy must be absorbed to completely melt 35.0 grams of #H_2O#(s) at 0°C? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/enthalpy" itemprop="url"> <span class="breadcrumb" itemprop="title">Enthalpy</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="625137" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/nam-d"><img alt="" class="" src="https://profilepictures.socratic.org/QG4MnkoER6u99DIDVWKK_787554714770341.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/nam-d"> Nam D. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-06-04T12:46:31" itemprop="dateCreated"> Jun 4, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#11690#</mathjax> joules</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Here, we melt the piece of ice, so we use the latent heat of fusion. The equation is thus:</p> <p><mathjax>#q=mL_f#</mathjax></p> <p>where:</p> <blockquote> <ul> <li> <p><mathjax>#q#</mathjax> is the heat energy supplied in joules</p> </li> <li> <p><mathjax>#m#</mathjax> is the mass of the substance</p> </li> <li> <p><mathjax>#L_f#</mathjax> is the latent heat of fusion of the substance</p> </li> </ul> </blockquote> <p>So here, we get:</p> <p><mathjax>#q=35color(red)cancelcolor(black)"g"*(334 \ "J")/(color(red)cancelcolor(black)"g")=11690 \ "J"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/625137" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-enthalpy-changes-expressed-in-chemical-equations"> How are enthalpy changes expressed in chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-enthalpy-change-be-determined-for-an-aqueous-solution"> How can enthalpy change be determined for an aqueous solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-enthalpy-change-with-pressure"> How does enthalpy change with pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-standard-molar-enthalpy-formation"> How do you calculate standard molar enthalpy of formation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-enthalpy-a-state-function"> Why is enthalpy a state function? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-enthalpy-of-formation-of-oxygen-zero"> Why is the enthalpy of formation of oxygen zero? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-enthalpy-a-state-function-2"> Why is enthalpy a state function? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-enthalpy-cannot-be-measured-directly"> Why can enthalpy not be measured directly? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-pressure-affect-enthalpy"> How does pressure affect enthalpy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-enthalpy-relate-to-internal-energy"> How does enthalpy relate to internal energy? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/enthalpy"> See all questions in Enthalpy </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 13777 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How much heat energy must be absorbed to completely melt 35.0 grams of #H_2O#(s) at 0°C?	null
2,051	ad040bc2-6ddd-11ea-b016-ccda262736ce	https://socratic.org/questions/what-is-the-volume-of-9-783-10-23-atoms-of-kr-at-9-25-atm-and-512k	7.5 L	start physical_unit 10 10 volume l qc_end physical_unit 10 10 12 13 pressure qc_end physical_unit 10 10 15 16 temperature qc_end end	[{"type":"physical unit","value":"Volume [OF] Kr [IN] L"}]	[{"type":"physical unit","value":"7.5 L"}]	[{"type":"physical unit","value":"Number [OF] Kr atoms [=] \\pu{9.783 × 10^23}"},{"type":"physical unit","value":"Pressure [OF] Kr [=] \\pu{9.25 atm}"},{"type":"physical unit","value":"Temperature [OF] Kr [=] \\pu{512 K}"}]	<h1 class="questionTitle" itemprop="name">What is the volume of #9.783*10^23# atoms of Kr at 9.25 atm and 512K? </h1>	null	7.5 L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#V=(nRT)/P#</mathjax><br/> <mathjax>#=(9.783xx10^23cancel"atoms of Kr")/(6.022xx10^23cancel"atoms of Kr"cancel(mol^-1))xx0.0821Lcancel(atmK^-1mol^-1)xx512cancelKxx(1/(9.25*cancel(atm)))=??L#</mathjax></p> <p>The expression is dimensionally consistent. I wanted an answer in <mathjax>#L#</mathjax>, and the expression gave me such an answer.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#V~=7.5L#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#V=(nRT)/P#</mathjax><br/> <mathjax>#=(9.783xx10^23cancel"atoms of Kr")/(6.022xx10^23cancel"atoms of Kr"cancel(mol^-1))xx0.0821Lcancel(atmK^-1mol^-1)xx512cancelKxx(1/(9.25cancel(atm)))=??L#</mathjax></p> <p>The expression is dimensionally consistent. I wanted an answer in <mathjax>#L#</mathjax>, and the expression gave me such an answer.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the volume of #9.78310^23# atoms of Kr at 9.25 atm and 512K? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/ideal-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Ideal Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="285155" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-06T02:42:13" itemprop="dateCreated"> Jul 6, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#V~=7.5L#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#V=(nRT)/P#</mathjax><br/> <mathjax>#=(9.783xx10^23cancel"atoms of Kr")/(6.022xx10^23cancel"atoms of Kr"cancel(mol^-1))xx0.0821Lcancel(atmK^-1mol^-1)xx512cancelKxx(1/(9.25*cancel(atm)))=??L#</mathjax></p> <p>The expression is dimensionally consistent. I wanted an answer in <mathjax>#L#</mathjax>, and the expression gave me such an answer.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/285155" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-ideal-gas-constant"> How do you find the ideal gas constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-solve-ideal-gas-law-problems"> How do you solve ideal gas law problems? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-know-which-ideal-gas-constant-to-use"> How do you know which ideal gas constant to use? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ideal-gas-constant-for-butane"> What is the ideal gas constant for butane? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-ideal-gas-law-in-kelvin"> Why is ideal gas law in kelvin? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ideal-gas-constant-important"> Why is the ideal gas constant important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-di-electric-constant"> What is the di-electric constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-volume-l-will-0-20-mol-hi-occupy-at-300-k-and-100-0-kpa-r-8-314-kpa-l-k-mol"> What volume (L) will 0.20 mol HI occupy at 300 K and 100.0 kPa? R = 8.314 kPa L / (K mol) =... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-molar-mass-of-a-gas"> How do you calculate the molar mass of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-should-i-use-the-ideal-gas-law-and-not-the-combined-gas-law"> When should I use the ideal gas law and not the combined gas law? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/ideal-gas-law"> See all questions in Ideal Gas Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 10517 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the volume of #9.783*10^23# atoms of Kr at 9.25 atm and 512K?	null
2,052	acdf1908-6ddd-11ea-b9b3-ccda262736ce	https://socratic.org/questions/if-3-00-mol-of-caco-3-undergo-decomposition-from-cao-and-co-2-how-many-grams-of-	132.00 grams	start physical_unit 10 10 mass g qc_end physical_unit 4 4 1 2 mole qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Mass [OF] CO2 [IN] grams"}]	[{"type":"physical unit","value":"132.00 grams"}]	[{"type":"physical unit","value":"Mole [OF] CaCO3 [=] \\pu{3.00 mol}"},{"type":"other","value":"CaCO3 undergo decomposition from CaO and CO2."}]	<h1 class="questionTitle" itemprop="name">If 3.00 mol of #CaCO_3# undergo decomposition from #CaO# and #CO_2# how many grams of #CO_2# are produced?</h1>	null	132.00 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We need the stoichiometric equation;</p> <p><mathjax>#CaCO_3(s) + Delta rarr CaO(s) + CO_2(g)uarr#</mathjax></p> <p>You have to heat this fairly fiercely, but clearly, quantitative reaction indicates that 1 mol of carbon dioxide is evolved per mole of calcium carbonate. </p> <p><mathjax>#CaO#</mathjax> dissolves in water to give limewater, aqueous calcium hydroxide (this is sparingly soluble, so filter it);</p> <p><mathjax>#CaO(s) + H_2O(l) rarr Ca(OH)_2(aq)#</mathjax></p> <p>If filtered limewater is treated with carbon dioxide, calcium carbonate is reformed, and precipitates from solution as a milky white solid:</p> <p><mathjax>#Ca(OH)_2(s) + CO_2(g) rarr CaCO_3(s)darr + H_2O(l)#</mathjax></p> <p>All of these equations should be informed by doing the actual reactions in the laboratory. The best source of <mathjax>#CO_2#</mathjax> is sparkling water, the type you would drink for lunch; this is supersaturated with respect to carbon dioxide. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Clearly, <mathjax>#3.00#</mathjax> <mathjax>#mol#</mathjax> of carbon dioxide gas are evolved. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We need the stoichiometric equation;</p> <p><mathjax>#CaCO_3(s) + Delta rarr CaO(s) + CO_2(g)uarr#</mathjax></p> <p>You have to heat this fairly fiercely, but clearly, quantitative reaction indicates that 1 mol of carbon dioxide is evolved per mole of calcium carbonate. </p> <p><mathjax>#CaO#</mathjax> dissolves in water to give limewater, aqueous calcium hydroxide (this is sparingly soluble, so filter it);</p> <p><mathjax>#CaO(s) + H_2O(l) rarr Ca(OH)_2(aq)#</mathjax></p> <p>If filtered limewater is treated with carbon dioxide, calcium carbonate is reformed, and precipitates from solution as a milky white solid:</p> <p><mathjax>#Ca(OH)_2(s) + CO_2(g) rarr CaCO_3(s)darr + H_2O(l)#</mathjax></p> <p>All of these equations should be informed by doing the actual reactions in the laboratory. The best source of <mathjax>#CO_2#</mathjax> is sparkling water, the type you would drink for lunch; this is supersaturated with respect to carbon dioxide. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">If 3.00 mol of #CaCO_3# undergo decomposition from #CaO# and #CO_2# how many grams of #CO_2# are produced?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="243528" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-22T18:13:47" itemprop="dateCreated"> Mar 22, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Clearly, <mathjax>#3.00#</mathjax> <mathjax>#mol#</mathjax> of carbon dioxide gas are evolved. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We need the stoichiometric equation;</p> <p><mathjax>#CaCO_3(s) + Delta rarr CaO(s) + CO_2(g)uarr#</mathjax></p> <p>You have to heat this fairly fiercely, but clearly, quantitative reaction indicates that 1 mol of carbon dioxide is evolved per mole of calcium carbonate. </p> <p><mathjax>#CaO#</mathjax> dissolves in water to give limewater, aqueous calcium hydroxide (this is sparingly soluble, so filter it);</p> <p><mathjax>#CaO(s) + H_2O(l) rarr Ca(OH)_2(aq)#</mathjax></p> <p>If filtered limewater is treated with carbon dioxide, calcium carbonate is reformed, and precipitates from solution as a milky white solid:</p> <p><mathjax>#Ca(OH)_2(s) + CO_2(g) rarr CaCO_3(s)darr + H_2O(l)#</mathjax></p> <p>All of these equations should be informed by doing the actual reactions in the laboratory. The best source of <mathjax>#CO_2#</mathjax> is sparkling water, the type you would drink for lunch; this is supersaturated with respect to carbon dioxide. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/243528" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What is stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ab82402bf342f48d93ac6"> Question #93ac6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-we-study-stoichiometry"> Why do we study stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-naoh-is-produced-from-1-20-x-102-grams-of-na2o-na2o-h2o-2-naoh"> How many grams of NaOH is produced from #1.20 x 10^2# grams of #Na_2O#? #Na_2O + H_2O -> 2NaOH# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-na2o-are-required-to-produce-1-60-x-102-grams-of-naoh-na2o-h2o"> How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? Na2O + H2O ---> 2 NaOH </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-mass-of-iron-is-needed-to-react-with-16-0-grams-of-sulfur-8-fe-s8-8-fes"> What mass of iron is needed to react with 16.0 grams of sulfur? 8 Fe + S8 ---> 8 FeS </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/according-to-8-fe-s8-8-fes-how-many-grams-of-fes-are-produced"> According to 8 Fe + S8 ---> 8 FeS How many grams of FeS are produced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/12-00-moles-of-naclo3-will-produce-how-many-grams-of-o2-2-naclo3-2-nacl-3-o2"> 12.00 moles of NaClO3 will produce how many grams of O2? 2 NaClO3 ---> 2 NaCl + 3 O2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-nacl-are-produced-when-80-0-grams-of-o2-are-produced-2-naclo3-"> How many grams of NaCl are produced when 80.0 grams of O2 are produced? 2 NaClO3 ---> 2 NaCl + 3 O2 </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/stoichiometry"> See all questions in Stoichiometry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3275 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	If 3.00 mol of #CaCO_3# undergo decomposition from #CaO# and #CO_2# how many grams of #CO_2# are produced?	null
2,053	acb8c38c-6ddd-11ea-9ab3-ccda262736ce	https://socratic.org/questions/the-rate-constant-of-a-reaction-at-32-c-is-measured-to-be-0-055m-s-if-the-freque	83.76 kJ/mol	start physical_unit 5 5 activation_barrier kj/mol qc_end physical_unit 5 5 7 8 temperature qc_end physical_unit 5 5 13 14 reaction_rate_constant qc_end physical_unit 5 5 20 23 pre-exponential_factor qc_end end	[{"type":"physical unit","value":"Activation barrier [OF] the reaction [IN] kJ/mol"}]	[{"type":"physical unit","value":"83.76 kJ/mol"}]	[{"type":"physical unit","value":"Temperature [OF] the reaction [=] \\pu{32 ℃ }"},{"type":"physical unit","value":"Rate constant [OF] the reaction [=] \\pu{0.055 s^(-1)}"},{"type":"physical unit","value":"Frequency factor [OF] the reaction [=] \\pu{1.2 × 10^13 s^(-1)}"}]	<h1 class="questionTitle" itemprop="name">The rate constant of a reaction at 32°C is measured to be #"0.055 s"^(-1)#. If the frequency factor is #1.2xx10^13s^-1#, what is the activation barrier?</h1>	null	83.76 kJ/mol	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The Arrhenius equation states that </p> <blockquote> <p><mathjax>#k=Ae^(-(color(purple)(E_A))/(RT))#</mathjax></p> </blockquote> <p>Taking logarithm of both sides gives </p> <blockquote> <p><mathjax>#lnk=lnA-(color(purple)(E_A))/(RT)#</mathjax></p> </blockquote> <p>Where</p> <ul> <li> <p>the rate constant of this particular reaction <mathjax>#k=0.055color(white)(l)s^(-1)#</mathjax>;</p> </li> <li> <p>The frequency factor (a temperature-dependent <em>constant</em> ) <mathjax>#A=1.2xx10^13color(white)(l)"s"^(-1)#</mathjax> as given in the question;</p> </li> <li> <p>The ideal gas <em>constant</em> <mathjax>#R=8.314 color(white)(l) color(darkgreen)("J") color(darkgreen)( "mol"^(-1)) * "K"^(-1)#</mathjax>;</p> </li> <li> <p>Absolute temperature <mathjax>#T=32+273.15=305.15color(white)(l)"K"#</mathjax> at which the reaction take place;</p> </li> <li> <p><mathjax>#color(purple)(E_A)#</mathjax> the <em>activation barrier</em> (a.k.a. <em>activation energy</em> ) the question is asking for</p> </li> </ul> <p>Solve the second equation for <mathjax>#color(purple)(E_A)#</mathjax>:</p> <p><mathjax>#color(purple)(E_A)/(RT)=lnAcolor(darkblue)(-)lnk#</mathjax></p> <p><mathjax>#color(purple)(E_A)=(RT)(lnAcolor(darkblue)(-)lnk)#</mathjax><br/> <mathjax>#color(white)(E_A)=(RT)lncolor(darkblue)(color(black)(A)/color(black)(k))#</mathjax><br/> <mathjax>#color(white)(E_A)=8.314 color(white)(l) color(darkgreen)("J") color(darkgreen)( "mol"^(-1))* color(red)(cancel(color(black)("K"^(-1)))) * 305.15color(white)(l)color(red)(cancel(color(black)("K")))ln((1.2xx10^13color(red)(cancel(color(black)("s"^(-1)))))/(0.055color(red)(cancel(color(black)("s"^(-1))))))#</mathjax><br/> <mathjax>#color(white)(E_A)=8.410^4color(white)(l)color(darkgreen)("J") * color(darkgreen)( "mol"^(-1))#</mathjax></p> <p>Therefore the activation barrier of this reaction is</p> <p><mathjax>#84color(white)(l)color(black)("kJ") * color(darkgreen)( "mol"^(-1))#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#E_A=84color(white)(l)"kJ""mol"^(-1)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The Arrhenius equation states that </p> <blockquote> <p><mathjax>#k=Ae^(-(color(purple)(E_A))/(RT))#</mathjax></p> </blockquote> <p>Taking logarithm of both sides gives </p> <blockquote> <p><mathjax>#lnk=lnA-(color(purple)(E_A))/(RT)#</mathjax></p> </blockquote> <p>Where</p> <ul> <li> <p>the rate constant of this particular reaction <mathjax>#k=0.055color(white)(l)s^(-1)#</mathjax>;</p> </li> <li> <p>The frequency factor (a temperature-dependent <em>constant</em> ) <mathjax>#A=1.2xx10^13color(white)(l)"s"^(-1)#</mathjax> as given in the question;</p> </li> <li> <p>The ideal gas <em>constant</em> <mathjax>#R=8.314 color(white)(l) color(darkgreen)("J") * color(darkgreen)( "mol"^(-1)) * "K"^(-1)#</mathjax>;</p> </li> <li> <p>Absolute temperature <mathjax>#T=32+273.15=305.15color(white)(l)"K"#</mathjax> at which the reaction take place;</p> </li> <li> <p><mathjax>#color(purple)(E_A)#</mathjax> the <em>activation barrier</em> (a.k.a. <em>activation energy</em> ) the question is asking for</p> </li> </ul> <p>Solve the second equation for <mathjax>#color(purple)(E_A)#</mathjax>:</p> <p><mathjax>#color(purple)(E_A)/(RT)=lnAcolor(darkblue)(-)lnk#</mathjax></p> <p><mathjax>#color(purple)(E_A)=(RT)(lnAcolor(darkblue)(-)lnk)#</mathjax><br/> <mathjax>#color(white)(E_A)=(RT)lncolor(darkblue)(color(black)(A)/color(black)(k))#</mathjax><br/> <mathjax>#color(white)(E_A)=8.314 color(white)(l) color(darkgreen)("J") color(darkgreen)( "mol"^(-1))* color(red)(cancel(color(black)("K"^(-1)))) * 305.15color(white)(l)color(red)(cancel(color(black)("K")))ln((1.2xx10^13color(red)(cancel(color(black)("s"^(-1)))))/(0.055color(red)(cancel(color(black)("s"^(-1))))))#</mathjax><br/> <mathjax>#color(white)(E_A)=8.410^4color(white)(l)color(darkgreen)("J") * color(darkgreen)( "mol"^(-1))#</mathjax></p> <p>Therefore the activation barrier of this reaction is</p> <p><mathjax>#84color(white)(l)color(black)("kJ") * color(darkgreen)( "mol"^(-1))#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">The rate constant of a reaction at 32°C is measured to be #"0.055 s"^(-1)#. If the frequency factor is #1.2xx10^13s^-1#, what is the activation barrier?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-kinetics" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Kinetics</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-kinetics/rate-of-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Rate of Reactions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="620821" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/jacob-t-3"><img alt="" class="" src="https://profilepictures.socratic.org/cDl6OiFtT16bIyMtJPfM_Protractor.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/jacob-t-3"> Jacob T. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-05-27T10:05:30" itemprop="dateCreated"> May 27, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#E_A=84color(white)(l)"kJ""mol"^(-1)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The Arrhenius equation states that </p> <blockquote> <p><mathjax>#k=Ae^(-(color(purple)(E_A))/(RT))#</mathjax></p> </blockquote> <p>Taking logarithm of both sides gives </p> <blockquote> <p><mathjax>#lnk=lnA-(color(purple)(E_A))/(RT)#</mathjax></p> </blockquote> <p>Where</p> <ul> <li> <p>the rate constant of this particular reaction <mathjax>#k=0.055color(white)(l)s^(-1)#</mathjax>;</p> </li> <li> <p>The frequency factor (a temperature-dependent <em>constant</em> ) <mathjax>#A=1.2xx10^13color(white)(l)"s"^(-1)#</mathjax> as given in the question;</p> </li> <li> <p>The ideal gas <em>constant</em> <mathjax>#R=8.314 color(white)(l) color(darkgreen)("J") * color(darkgreen)( "mol"^(-1)) * "K"^(-1)#</mathjax>;</p> </li> <li> <p>Absolute temperature <mathjax>#T=32+273.15=305.15color(white)(l)"K"#</mathjax> at which the reaction take place;</p> </li> <li> <p><mathjax>#color(purple)(E_A)#</mathjax> the <em>activation barrier</em> (a.k.a. <em>activation energy</em> ) the question is asking for</p> </li> </ul> <p>Solve the second equation for <mathjax>#color(purple)(E_A)#</mathjax>:</p> <p><mathjax>#color(purple)(E_A)/(RT)=lnAcolor(darkblue)(-)lnk#</mathjax></p> <p><mathjax>#color(purple)(E_A)=(RT)(lnAcolor(darkblue)(-)lnk)#</mathjax><br/> <mathjax>#color(white)(E_A)=(RT)lncolor(darkblue)(color(black)(A)/color(black)(k))#</mathjax><br/> <mathjax>#color(white)(E_A)=8.314 color(white)(l) color(darkgreen)("J") color(darkgreen)( "mol"^(-1))* color(red)(cancel(color(black)("K"^(-1)))) * 305.15color(white)(l)color(red)(cancel(color(black)("K")))ln((1.2xx10^13color(red)(cancel(color(black)("s"^(-1)))))/(0.055color(red)(cancel(color(black)("s"^(-1))))))#</mathjax><br/> <mathjax>#color(white)(E_A)=8.410^4color(white)(l)color(darkgreen)("J") * color(darkgreen)( "mol"^(-1))#</mathjax></p> <p>Therefore the activation barrier of this reaction is</p> <p><mathjax>#84color(white)(l)color(black)("kJ") * color(darkgreen)( "mol"^(-1))#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/620821" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-rate-of-reaction"> How do you calculate rate of reaction? 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If the frequency factor is #1.2xx10^13s^-1#, what is the activation barrier?	null
2,054	a8c66b36-6ddd-11ea-bb4e-ccda262736ce	https://socratic.org/questions/what-is-the-amount-of-heat-liberated-in-kj-from-327-g-of-mercury-when-it-cools-f	−2.99 kJ	start physical_unit 13 13 heat_energy kj qc_end physical_unit 13 13 18 19 temperature qc_end physical_unit 13 13 21 22 temperature qc_end physical_unit 13 13 10 11 mass qc_end end	[{"type":"physical unit","value":"Liberated heat [OF] mercury [IN] kJ"}]	[{"type":"physical unit","value":"−2.99 kJ "}]	[{"type":"physical unit","value":"Temperature1 [OF] mercury [=] \\pu{77.8 ℃}"},{"type":"physical unit","value":"Temperature2 [OF] mercury [=] \\pu{12.0 ℃}"},{"type":"physical unit","value":"Mass [OF] mercury [=] \\pu{327 g}"}]	<h1 class="questionTitle" itemprop="name">What is the amount of heat liberated (in kJ) from 327 g of mercury when it cools from 77.8°C to 12.0°C?</h1>	null	−2.99 kJ	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>For this problem we have to use the <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> capacity equation:</p> <p><img alt="www.chem.purdue.edu" src="https://useruploads.socratic.org/Ahm1BS3uTicaEZRU9xen_Calorimetry_equation.JPG"/> </p> <p>Based on what you've given me, we have the mass of the sample (m), the <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> (c), and the change in temperature <mathjax>#DeltaT#</mathjax>. We just need to find q.</p> <p><mathjax>#DeltaT#</mathjax> is <mathjax>#-65.8^oC#</mathjax> because we have to subtract the initial temperature from the final temperature.<br/> (<mathjax>#12^oC - 77.8^oC#</mathjax>).</p> <p>Since you want the amount of heat liberated to have units of kJ, you need to convert <mathjax>#0.139 J/(gxx^oC)#</mathjax> into a value that has units of <mathjax>#(kJ)/(gxx^oC)#</mathjax></p> <p>We can do that by using this relationship:</p> <p>1000J = 1kJ<br/> Divide 0.139 by 1000 to obtain <mathjax>#0.000139 (kJ)/(gxx^oC)#</mathjax></p> <p>Now, all of the variables have good units, so we just have to multiply all of the given values together to obtain Q (energy transferred).</p> <p><mathjax>#Q = 327cancelgxx(0.000139kJ)/(cancelgxx^ocancelC)xx-65.8^ocancelC#</mathjax></p> <p><mathjax>#Q = -2.99 kJ#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#-2.99kJ#</mathjax> of heat has been liberated.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>For this problem we have to use the <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> capacity equation:</p> <p><img alt="www.chem.purdue.edu" src="https://useruploads.socratic.org/Ahm1BS3uTicaEZRU9xen_Calorimetry_equation.JPG"/> </p> <p>Based on what you've given me, we have the mass of the sample (m), the <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> (c), and the change in temperature <mathjax>#DeltaT#</mathjax>. We just need to find q.</p> <p><mathjax>#DeltaT#</mathjax> is <mathjax>#-65.8^oC#</mathjax> because we have to subtract the initial temperature from the final temperature.<br/> (<mathjax>#12^oC - 77.8^oC#</mathjax>).</p> <p>Since you want the amount of heat liberated to have units of kJ, you need to convert <mathjax>#0.139 J/(gxx^oC)#</mathjax> into a value that has units of <mathjax>#(kJ)/(gxx^oC)#</mathjax></p> <p>We can do that by using this relationship:</p> <p>1000J = 1kJ<br/> Divide 0.139 by 1000 to obtain <mathjax>#0.000139 (kJ)/(gxx^oC)#</mathjax></p> <p>Now, all of the variables have good units, so we just have to multiply all of the given values together to obtain Q (energy transferred).</p> <p><mathjax>#Q = 327cancelgxx(0.000139kJ)/(cancelgxx^ocancelC)xx-65.8^ocancelC#</mathjax></p> <p><mathjax>#Q = -2.99 kJ#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the amount of heat liberated (in kJ) from 327 g of mercury when it cools from 77.8°C to 12.0°C?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/calorimetry" itemprop="url"> <span class="breadcrumb" itemprop="title">Calorimetry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="283707" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/kayla-14"><img alt="" class="" src="https://profilepictures.socratic.org/OvMTWaamQPWcqLIkUNnG_793604964071127.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/kayla-14"> Kayla </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-02T02:15:58" itemprop="dateCreated"> Jul 2, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#-2.99kJ#</mathjax> of heat has been liberated.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>For this problem we have to use the <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> capacity equation:</p> <p><img alt="www.chem.purdue.edu" src="https://useruploads.socratic.org/Ahm1BS3uTicaEZRU9xen_Calorimetry_equation.JPG"/> </p> <p>Based on what you've given me, we have the mass of the sample (m), the <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> (c), and the change in temperature <mathjax>#DeltaT#</mathjax>. We just need to find q.</p> <p><mathjax>#DeltaT#</mathjax> is <mathjax>#-65.8^oC#</mathjax> because we have to subtract the initial temperature from the final temperature.<br/> (<mathjax>#12^oC - 77.8^oC#</mathjax>).</p> <p>Since you want the amount of heat liberated to have units of kJ, you need to convert <mathjax>#0.139 J/(gxx^oC)#</mathjax> into a value that has units of <mathjax>#(kJ)/(gxx^oC)#</mathjax></p> <p>We can do that by using this relationship:</p> <p>1000J = 1kJ<br/> Divide 0.139 by 1000 to obtain <mathjax>#0.000139 (kJ)/(gxx^oC)#</mathjax></p> <p>Now, all of the variables have good units, so we just have to multiply all of the given values together to obtain Q (energy transferred).</p> <p><mathjax>#Q = 327cancelgxx(0.000139kJ)/(cancelgxx^ocancelC)xx-65.8^ocancelC#</mathjax></p> <p><mathjax>#Q = -2.99 kJ#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/283707" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-differential-scanning-in-calorimetry-work"> How does differential scanning in calorimetry work? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-read-differential-scanning-in-calorimetry"> What information do you get from a differential scanning calorimetry plot? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-measure-calorimetry"> How do you measure calorimetry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531d304102bf341e75b962a7"> Question #962a7 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5335021802bf344ae911dfc5"> Question #1dfc5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/533668f502bf34572c341af6"> Question #41af6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-definition-of-calorimetry"> What is calorimetry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-differential-scanning-calorimeter"> What is a differential scanning calorimeter? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-a-calorimeter-measure-energy"> How can a calorimeter measure energy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-calorimeters-made-of"> What are calorimeters made of? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/calorimetry"> See all questions in Calorimetry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 22750 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the amount of heat liberated (in kJ) from 327 g of mercury when it cools from 77.8°C to 12.0°C?	null
2,055	a9f7c21c-6ddd-11ea-b8ca-ccda262736ce	https://socratic.org/questions/590fec2a7c014915562041fc	55.56 mol/kg	start physical_unit 5 6 molality mol/kg qc_end substance 5 6 qc_end end	[{"type":"physical unit","value":"Molality [OF] pure water [IN] mol/kg"}]	[{"type":"physical unit","value":"55.56 mol/kg"}]	[{"type":"substance name","value":"Pure water"}]	<h1 class="questionTitle" itemprop="name">What is the #"molality"# of pure water?</h1>	null	55.56 mol/kg	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Molality"="Moles of solute"/"Kilograms of solvent"#</mathjax>, </p> <p>and so if we assume a <mathjax>#1kg#</mathjax> mass of water,............(what is the volume?).........then</p> <p><mathjax>#"Molality"=((1000g)/(18.01gmol^-1))/(1kg)=??molkg^-1.#</mathjax></p> <p>And this value is quite comparable to water's <mathjax>#"molarity"#</mathjax>?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Large...........<mathjax>#>50molkg^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Molality"="Moles of solute"/"Kilograms of solvent"#</mathjax>, </p> <p>and so if we assume a <mathjax>#1kg#</mathjax> mass of water,............(what is the volume?).........then</p> <p><mathjax>#"Molality"=((1000g)/(18.01gmol^-1))/(1kg)=??molkg^-1.#</mathjax></p> <p>And this value is quite comparable to water's <mathjax>#"molarity"#</mathjax>?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the #"molality"# of pure water?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molality" itemprop="url"> <span class="breadcrumb" itemprop="title">Molality</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="419456" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-08T04:06:12" itemprop="dateCreated"> May 8, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Large...........<mathjax>#>50molkg^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Molality"="Moles of solute"/"Kilograms of solvent"#</mathjax>, </p> <p>and so if we assume a <mathjax>#1kg#</mathjax> mass of water,............(what is the volume?).........then</p> <p><mathjax>#"Molality"=((1000g)/(18.01gmol^-1))/(1kg)=??molkg^-1.#</mathjax></p> <p>And this value is quite comparable to water's <mathjax>#"molarity"#</mathjax>?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/419456" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-molality-and-molarity-differ"> How do molality and molarity differ? 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What... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molality-when-0-75-mol-is-dissolved-in-2-50-l-of-solvent"> What is the molality when 0.75 mol is dissolved in 2.50 L of solvent? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molality-when-48-0-ml-of-6-00-m-h2so4-are-diluted-into-0-250-l"> What is the molality when 48.0 mL of 6.00 M H2SO4 are diluted into 0.250 L? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molality"> See all questions in Molality </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1913 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the #"molality"# of pure water?	null
2,056	ac3c656c-6ddd-11ea-a676-ccda262736ce	https://socratic.org/questions/if-the-atomic-weight-of-nitrogen-is-14-01-what-is-the-mass-of-the-nitrogen-atoms	28.02 g	start physical_unit 14 15 mass g qc_end physical_unit 5 5 7 7 atomic_mass qc_end physical_unit 22 22 17 18 mole qc_end end	[{"type":"physical unit","value":"Mass [OF] nitrogen atoms [IN] g"}]	[{"type":"physical unit","value":"28.02 g"}]	[{"type":"physical unit","value":"Atomic weight [OF] nitrogen [=] \\pu{14.01}"},{"type":"physical unit","value":"Mole [OF] Cd(NO3)2 [=] \\pu{1 mole}"}]	<h1 class="questionTitle" itemprop="name">If the atomic weight of nitrogen is 14.01, what is the mass of the nitrogen atoms in one mole of cadmium nitrate, #Cd(NO_3)_2#?</h1>	null	28.02 g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So in one mole of cadmium nitrate there are two moles of nitrogen.<br/> The mass the nitrogen is thus <mathjax>#2xx14.01=28.02g#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>In one molecule of cadmium nitrate there are two atoms of nitrogen.<br/> (work out the brackets, as in maths, and it'll be <mathjax>#CdN_2O_6#</mathjax>)</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So in one mole of cadmium nitrate there are two moles of nitrogen.<br/> The mass the nitrogen is thus <mathjax>#2xx14.01=28.02g#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">If the atomic weight of nitrogen is 14.01, what is the mass of the nitrogen atoms in one mole of cadmium nitrate, #Cd(NO_3)_2#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="259388" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meneernask"><img alt="" class="" src="https://profilepictures.socratic.org/gpA0lokRGK9vLVUnAMAy_meneernask.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meneernask"> MeneerNask </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-04-27T13:22:20" itemprop="dateCreated"> Apr 27, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>In one molecule of cadmium nitrate there are two atoms of nitrogen.<br/> (work out the brackets, as in maths, and it'll be <mathjax>#CdN_2O_6#</mathjax>)</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So in one mole of cadmium nitrate there are two moles of nitrogen.<br/> The mass the nitrogen is thus <mathjax>#2xx14.01=28.02g#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/259388" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? 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2,057	acf18c2e-6ddd-11ea-89c6-ccda262736ce	https://socratic.org/questions/if-the-ph-of-a-solution-is-10-7-what-would-the-poh-be	3.30	start physical_unit 5 5 poh none qc_end physical_unit 5 5 7 7 ph qc_end end	[{"type":"physical unit","value":"pOH [OF] the solution"}]	[{"type":"physical unit","value":"3.30"}]	[{"type":"physical unit","value":"pH [OF] the solution [=] \\pu{10.7}"}]	<h1 class="questionTitle" itemprop="name">If the pH of a solution is 10.7, what would the pOH be? </h1>	null	3.30	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Remember a simple thing that <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a>+pOH=14<br/> so pOH= 14-10.7 = 3.3</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>3.3</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Remember a simple thing that <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a>+pOH=14<br/> so pOH= 14-10.7 = 3.3</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">If the pH of a solution is 10.7, what would the pOH be? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/solutions" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="318569" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/kazi-i"><img alt="" class="" src="https://graph.facebook.com/910141219080809/picture?height=50&width=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/kazi-i"> Kazi Ashiq Iqbal </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-10-06T16:04:26" itemprop="dateCreated"> Oct 6, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>3.3</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Remember a simple thing that <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a>+pOH=14<br/> so pOH= 14-10.7 = 3.3</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/318569" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="318571" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-10-06T16:12:37" itemprop="dateCreated"> Oct 6, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#pOH=3.3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#2H_2O rightleftharpoons H_3O^+ +HO^-#</mathjax></p> <p>At <mathjax>#298*K#</mathjax>, we can write and quantify this equilibrium reaction:</p> <p><mathjax>#K_w=[H_3O^+][HO^-]=10^-14#</mathjax></p> <p>And taking <mathjax>#log_10#</mathjax> of both sides:</p> <p><mathjax>#logK_w=log_(10)[H_3O^+] +log_10[HO^-]=log_(10)10^-14#</mathjax></p> <p>OR <mathjax>#14=-logK_w=-log_(10)[H_3O^+] -log_10[HO^-]#</mathjax></p> <p>But, by definitions, <mathjax>#pH=-log_(10)[H_3O^+]#</mathjax>, and <mathjax>#pOH=-log_(10)[HO^-]#</mathjax>, and <mathjax>#-logK_w=pK_w#</mathjax>.</p> <p>And thus, <mathjax>#pK_w=14=pH+pOH#</mathjax>.</p> <p>Given your question (finally we've got to it!), <mathjax>#pOH=14-pH#</mathjax> <mathjax>#=#</mathjax> <mathjax>#14-10.7=?#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/318571" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-solution-solute-and-solvent-related"> How are solution, solute, and solvent related? 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2,058	ac9529e4-6ddd-11ea-8866-ccda262736ce	https://socratic.org/questions/581844b57c0149405b650aa2	16.7 L	start physical_unit 14 15 volume l qc_end physical_unit 14 15 4 5 mole qc_end physical_unit 14 15 11 12 mole qc_end physical_unit 14 15 28 29 volume qc_end c_other ConstantTemperaturePressue qc_end end	[{"type":"physical unit","value":"Volume1 [OF] the gas [IN] L"}]	[{"type":"physical unit","value":"16.7 L"}]	[{"type":"physical unit","value":"Mole [OF] the gas [=] \\pu{6.70 mol}"},{"type":"physical unit","value":"Added mole [OF] the gas [=] \\pu{3.50 mol}"},{"type":"physical unit","value":"Volume2 [OF] the gas [=] \\pu{25.4 L}"},{"type":"other","value":"ConstantTemperaturePressue"}]	<h1 class="questionTitle" itemprop="name">A flexible container holds #"6.70 mol"# of a gas. An additional #"3.50 mol"# of the gas is added to the container until it reaches a final volume of #"25.4 L"# while temperature and pressure are kept constant, what was the initial volume? </h1>	null	16.7 L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This problem requires <a href="https://socratic.org/chemistry/the-behavior-of-gases/avogadro-s-law">Avogadro's law</a>, which states that the amount (moles) of a gas is directly proportional to its volume, such that if the amount increases, the volume increases and vice versa. You correctly determined the formula to use: <mathjax>#V_1/n_1=V_2/n_2#</mathjax></p> <p><strong>Known</strong><br/> <mathjax>#n_1="6.70 mol"#</mathjax><br/> <mathjax>#V_2="25.4 L"#</mathjax><br/> <mathjax>#n_2="6.70 mol+3.50 mol"="10.2 mol"#</mathjax></p> <p><strong>Unknown</strong><br/> <mathjax>#V_1#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#V_1#</mathjax>. Substitute the known values into the equation and solve.</p> <p><mathjax>#V_1=(V_2n_1)/n_2#</mathjax></p> <p><mathjax>#V_1=(25.4"L"xx6.70cancel"mol")/(10.2cancel"mol")="16.7 L"#</mathjax> rounded to three <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The initial volume was 16.7 L.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This problem requires <a href="https://socratic.org/chemistry/the-behavior-of-gases/avogadro-s-law">Avogadro's law</a>, which states that the amount (moles) of a gas is directly proportional to its volume, such that if the amount increases, the volume increases and vice versa. You correctly determined the formula to use: <mathjax>#V_1/n_1=V_2/n_2#</mathjax></p> <p><strong>Known</strong><br/> <mathjax>#n_1="6.70 mol"#</mathjax><br/> <mathjax>#V_2="25.4 L"#</mathjax><br/> <mathjax>#n_2="6.70 mol+3.50 mol"="10.2 mol"#</mathjax></p> <p><strong>Unknown</strong><br/> <mathjax>#V_1#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#V_1#</mathjax>. Substitute the known values into the equation and solve.</p> <p><mathjax>#V_1=(V_2n_1)/n_2#</mathjax></p> <p><mathjax>#V_1=(25.4"L"xx6.70cancel"mol")/(10.2cancel"mol")="16.7 L"#</mathjax> rounded to three <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A flexible container holds #"6.70 mol"# of a gas. An additional #"3.50 mol"# of the gas is added to the container until it reaches a final volume of #"25.4 L"# while temperature and pressure are kept constant, what was the initial volume? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/boyle-s-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Boyle's Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="331694" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-11-05T07:58:59" itemprop="dateCreated"> Nov 5, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The initial volume was 16.7 L.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This problem requires <a href="https://socratic.org/chemistry/the-behavior-of-gases/avogadro-s-law">Avogadro's law</a>, which states that the amount (moles) of a gas is directly proportional to its volume, such that if the amount increases, the volume increases and vice versa. You correctly determined the formula to use: <mathjax>#V_1/n_1=V_2/n_2#</mathjax></p> <p><strong>Known</strong><br/> <mathjax>#n_1="6.70 mol"#</mathjax><br/> <mathjax>#V_2="25.4 L"#</mathjax><br/> <mathjax>#n_2="6.70 mol+3.50 mol"="10.2 mol"#</mathjax></p> <p><strong>Unknown</strong><br/> <mathjax>#V_1#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#V_1#</mathjax>. Substitute the known values into the equation and solve.</p> <p><mathjax>#V_1=(V_2n_1)/n_2#</mathjax></p> <p><mathjax>#V_1=(25.4"L"xx6.70cancel"mol")/(10.2cancel"mol")="16.7 L"#</mathjax> rounded to three <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/331694" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-graph-boyles-law"> How do you graph Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-functional-groups-are-found-in-lipids"> What functional groups are found in lipids? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-k-constant-in-boyle-s-law"> Why is k constant in Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-boyle-s-law-graph-curved-1"> Why is Boyle's law graph curved? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-boyle-s-law-an-inverse-relationship-2"> Why is Boyle's law an inverse relationship? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-40-0-l-tank-of-ammonia-has-a-pressure-of-8-00-atm-calculate-the-volume-of-the-"> A 40.0 L tank of ammonia has a pressure of 8.00 atm. Calculate the volume of the ammonia if its... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-charles-law-different-from-boyle-s-law"> How is Charles' law different from Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-boyle-s-law-written-mathematically"> How is Boyle's law written mathematically? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-temperature-affect-boyle-s-law"> How does temperature affect Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-boyle-s-law-relate-to-ventilation"> How does Boyle's law relate to ventilation? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/boyle-s-law"> See all questions in Boyle's Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2304 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A flexible container holds #"6.70 mol"# of a gas. An additional #"3.50 mol"# of the gas is added to the container until it reaches a final volume of #"25.4 L"# while temperature and pressure are kept constant, what was the initial volume?	null
2,059	a8f582f8-6ddd-11ea-a7e2-ccda262736ce	https://socratic.org/questions/56a2ea9611ef6b7024c78575	NaH(s) + H2O(l) -> NaOH(aq) + 12 H2(g)	start chemical_equation qc_end substance 6 6 qc_end substance 2 3 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the reaction"}]	[{"type":"chemical equation","value":"NaH(s) + H2O(l) -> NaOH(aq) + 12 H2(g)"}]	[{"type":"substance name","value":"Water"},{"type":"substance name","value":"Sodium hydride"}]	<h1 class="questionTitle" itemprop="name">How does sodium hydride react with water?</h1>	null	NaH(s) + H2O(l) -> NaOH(aq) + 12 H2(g)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The hydride anion is is unstable with respect to oxidation in water. Hydride salts are often used as drying agents (of organic solvents) for this reason. Lithium aluminum hydride, <mathjax>#LiAlH_4#</mathjax>, is a very common reducing agent in organic chemistry. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#NaH(s) + H_2O(l) rarr NaOH(aq) + 1/2H_2(g)uarr#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The hydride anion is is unstable with respect to oxidation in water. Hydride salts are often used as drying agents (of organic solvents) for this reason. Lithium aluminum hydride, <mathjax>#LiAlH_4#</mathjax>, is a very common reducing agent in organic chemistry. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How does sodium hydride react with water?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-reactions-and-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions and Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="218187" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-28T06:56:01" itemprop="dateCreated"> Jan 28, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#NaH(s) + H_2O(l) rarr NaOH(aq) + 1/2H_2(g)uarr#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The hydride anion is is unstable with respect to oxidation in water. Hydride salts are often used as drying agents (of organic solvents) for this reason. Lithium aluminum hydride, <mathjax>#LiAlH_4#</mathjax>, is a very common reducing agent in organic chemistry. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/218187" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb002bf34694a4fee47"> Question #fee47 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb402bf34694c8c5c15"> Question #c5c15 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb802bf346950519eb9"> Question #19eb9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cbf02bf3469570e2ea2"> Question #e2ea2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc002bf34695a6bc751"> Question #bc751 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc202bf3469570e2ea6"> Question #e2ea6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531e867a02bf342492a08b07"> Question #08b07 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-thermochemical-equation-for-the-combustion-of-benzene"> What is the thermochemical equation for the combustion of benzene? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-reversible"> Why are chemical reactions reversible? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-important"> Why are chemical reactions important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/chemical-reactions-and-equations"> See all questions in Chemical Reactions and Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2738 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How does sodium hydride react with water?	null
2,060	ab21888e-6ddd-11ea-bbf0-ccda262736ce	https://socratic.org/questions/the-oh-in-a-sample-of-egg-whites-is-6-3-times-10-7-m-what-is-the-h-3o-in-these-e	1.5 × 10^(-8) M	start physical_unit 18 20 [h3o+] mol/l qc_end physical_unit 4 7 9 12 [oh-] qc_end end	[{"type":"physical unit","value":"[H3O+] [OF] these egg whites [IN] M"}]	[{"type":"physical unit","value":"1.5 × 10^(-8) M"}]	[{"type":"physical unit","value":"[OH-] [OF] egg whites sample [=] \\pu{6.3 × 10^(-7) M}"}]	<h1 class="questionTitle" itemprop="name">The #[-OH]#] in a sample of egg whites is #6.3 times 10^-7# #M#. What is the #[H_3O^+]# in these egg whites?</h1>	null	1.5 × 10^(-8) M	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#pOH=-log_10(6.3xx10^-7)=-(-6.2)=6.2#</mathjax></p> <p>And thus <mathjax>#pH=7.80#</mathjax></p> <p>Now <mathjax>#pH=-log_10[H_3O^+]#</mathjax></p> <p>And thus, taking anti-logs............</p> <p><mathjax>#[H_3O^+]=10^(-7.80)molL^-1=1.5xx10^-8molL^-1.#</mathjax></p> <p>The soapiness, and bitterness, and sliminess of egg white, is characteristic of this basic property; our sense of taste can discriminate this. Egg-yolks (and most things that taste good) are slightly acidic. </p> <p>See <a href="https://socratic.org/questions/what-type-of-compound-often-tastes-bitter?source=search">here</a> and <a href="https://socratic.org/questions/how-do-acids-usually-taste?source=search">here.</a> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We know that <mathjax>#pOH+pH=14#</mathjax> in aqueous solution...........</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#pOH=-log_10(6.3xx10^-7)=-(-6.2)=6.2#</mathjax></p> <p>And thus <mathjax>#pH=7.80#</mathjax></p> <p>Now <mathjax>#pH=-log_10[H_3O^+]#</mathjax></p> <p>And thus, taking anti-logs............</p> <p><mathjax>#[H_3O^+]=10^(-7.80)molL^-1=1.5xx10^-8molL^-1.#</mathjax></p> <p>The soapiness, and bitterness, and sliminess of egg white, is characteristic of this basic property; our sense of taste can discriminate this. Egg-yolks (and most things that taste good) are slightly acidic. </p> <p>See <a href="https://socratic.org/questions/what-type-of-compound-often-tastes-bitter?source=search">here</a> and <a href="https://socratic.org/questions/how-do-acids-usually-taste?source=search">here.</a> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">The #[-OH]#] in a sample of egg whites is #6.3 times 10^-7# #M#. What is the #[H_3O^+]# in these egg whites?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/the-ph-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">pH</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="409211" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-19T07:54:51" itemprop="dateCreated"> Apr 19, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We know that <mathjax>#pOH+pH=14#</mathjax> in aqueous solution...........</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#pOH=-log_10(6.3xx10^-7)=-(-6.2)=6.2#</mathjax></p> <p>And thus <mathjax>#pH=7.80#</mathjax></p> <p>Now <mathjax>#pH=-log_10[H_3O^+]#</mathjax></p> <p>And thus, taking anti-logs............</p> <p><mathjax>#[H_3O^+]=10^(-7.80)molL^-1=1.5xx10^-8molL^-1.#</mathjax></p> <p>The soapiness, and bitterness, and sliminess of egg white, is characteristic of this basic property; our sense of taste can discriminate this. Egg-yolks (and most things that taste good) are slightly acidic. </p> <p>See <a href="https://socratic.org/questions/what-type-of-compound-often-tastes-bitter?source=search">here</a> and <a href="https://socratic.org/questions/how-do-acids-usually-taste?source=search">here.</a> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/409211" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-pka"> How do you determine pH from pKa? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-ph-values-of-acids-and-bases-differ"> How do pH values of acids and bases differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-something-on-a-ph-scale"> How do you calculate something on a pH scale? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-diprotic-acid"> How do you calculate pH diprotic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-from-acid-dissociation-constant"> How do you calculate pH from acid dissociation constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-of-acid-and-base-solution"> How do you calculate pH of acid and base solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ph-scale-0-14"> Why is the pH scale 0-14? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-ph-the-measure-of-the-hydrogen-ion-concentration"> Is pH a measure of the hydrogen ion concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-solubility-affect-ph"> How does solubility affect pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-ph-relate-to-pka-in-a-titration"> How does pH relate to pKa in a titration? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/the-ph-concept"> See all questions in pH </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 6712 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	The #[-OH]#] in a sample of egg whites is #6.3 times 10^-7# #M#. What is the #[H_3O^+]# in these egg whites?	null
2,061	a8954714-6ddd-11ea-a9b1-ccda262736ce	https://socratic.org/questions/calculate-the-heat-required-to-raise-the-temperature-of-0-75-kg-of-water-from-5-	266.86 kJ	start physical_unit 12 12 heat_energy kj qc_end physical_unit 12 12 9 10 mass qc_end physical_unit 12 12 14 15 temperature qc_end physical_unit 12 12 17 18 temperature qc_end end	[{"type":"physical unit","value":"Required heat [OF] water [IN] kJ"}]	[{"type":"physical unit","value":"266.86 kJ"}]	[{"type":"physical unit","value":"Mass [OF] water [=] \\pu{0.75 kg}"},{"type":"physical unit","value":"Temperature1 [OF] water [=] \\pu{5 ℃}"},{"type":"physical unit","value":"Temperature2 [OF] water [=] \\pu{90 ℃}"}]	<h1 class="questionTitle" itemprop="name">Calculate the heat required to raise the temperature of 0.75 kg of water from 5˚C to 90.˚C? </h1>	null	266.86 kJ	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To calculate the energy required to raise the temperature of any given substance, here's what you require:</p> <p>The mass of the material, <mathjax>#m#</mathjax></p> <p>The temperature change that occurs, <mathjax>#DeltaT#</mathjax></p> <p>The <em><a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> capacity</em> of the material, <mathjax>#c#</mathjax> (which you can look up). This is the amount of heat required to raise 1 gram of that substance by 1°C.</p> <p>Here is a source of values of <mathjax>#c#</mathjax> for different substances:</p> <p><a href="http://www2.ucdsb.on.ca/tiss/stretton/Database/Specific_Heat_Capacity_Table.html" rel="nofollow" target="_blank">http://www2.ucdsb.on.ca/tiss/stretton/Database/Specific_Heat_Capacity_Table.html</a></p> <p>Once you have all that, this is the equation:</p> <p><mathjax>#Q= mxx c xxDeltaT#</mathjax></p> <p>(<mathjax>#Q#</mathjax> is usually used to symbolize that heat required in a case like this.)</p> <p>For water, the value of <mathjax>#c#</mathjax> is <mathjax>#4.186 J/(g°C)#</mathjax></p> <p>So, <mathjax>#Q=750 xx 4.186xx85=266 858 J=266.858 kJ#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>This will require <mathjax>#266.9 kJ#</mathjax> of heat energy.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To calculate the energy required to raise the temperature of any given substance, here's what you require:</p> <p>The mass of the material, <mathjax>#m#</mathjax></p> <p>The temperature change that occurs, <mathjax>#DeltaT#</mathjax></p> <p>The <em><a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> capacity</em> of the material, <mathjax>#c#</mathjax> (which you can look up). This is the amount of heat required to raise 1 gram of that substance by 1°C.</p> <p>Here is a source of values of <mathjax>#c#</mathjax> for different substances:</p> <p><a href="http://www2.ucdsb.on.ca/tiss/stretton/Database/Specific_Heat_Capacity_Table.html" rel="nofollow" target="_blank">http://www2.ucdsb.on.ca/tiss/stretton/Database/Specific_Heat_Capacity_Table.html</a></p> <p>Once you have all that, this is the equation:</p> <p><mathjax>#Q= mxx c xxDeltaT#</mathjax></p> <p>(<mathjax>#Q#</mathjax> is usually used to symbolize that heat required in a case like this.)</p> <p>For water, the value of <mathjax>#c#</mathjax> is <mathjax>#4.186 J/(g°C)#</mathjax></p> <p>So, <mathjax>#Q=750 xx 4.186xx85=266 858 J=266.858 kJ#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Calculate the heat required to raise the temperature of 0.75 kg of water from 5˚C to 90.˚C? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/calorimetry" itemprop="url"> <span class="breadcrumb" itemprop="title">Calorimetry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="370602" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/dwight"><img alt="" class="" src="https://profilepictures.socratic.org/ZDiTFWmAQmWOT3sd0Xpr_Dwight.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/dwight"> Dwight </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-01-28T23:43:21" itemprop="dateCreated"> Jan 28, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>This will require <mathjax>#266.9 kJ#</mathjax> of heat energy.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To calculate the energy required to raise the temperature of any given substance, here's what you require:</p> <p>The mass of the material, <mathjax>#m#</mathjax></p> <p>The temperature change that occurs, <mathjax>#DeltaT#</mathjax></p> <p>The <em><a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> capacity</em> of the material, <mathjax>#c#</mathjax> (which you can look up). This is the amount of heat required to raise 1 gram of that substance by 1°C.</p> <p>Here is a source of values of <mathjax>#c#</mathjax> for different substances:</p> <p><a href="http://www2.ucdsb.on.ca/tiss/stretton/Database/Specific_Heat_Capacity_Table.html" rel="nofollow" target="_blank">http://www2.ucdsb.on.ca/tiss/stretton/Database/Specific_Heat_Capacity_Table.html</a></p> <p>Once you have all that, this is the equation:</p> <p><mathjax>#Q= mxx c xxDeltaT#</mathjax></p> <p>(<mathjax>#Q#</mathjax> is usually used to symbolize that heat required in a case like this.)</p> <p>For water, the value of <mathjax>#c#</mathjax> is <mathjax>#4.186 J/(g°C)#</mathjax></p> <p>So, <mathjax>#Q=750 xx 4.186xx85=266 858 J=266.858 kJ#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/370602" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-differential-scanning-in-calorimetry-work"> How does differential scanning in calorimetry work? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-read-differential-scanning-in-calorimetry"> What information do you get from a differential scanning calorimetry plot? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-measure-calorimetry"> How do you measure calorimetry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531d304102bf341e75b962a7"> Question #962a7 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5335021802bf344ae911dfc5"> Question #1dfc5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/533668f502bf34572c341af6"> Question #41af6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-definition-of-calorimetry"> What is calorimetry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-differential-scanning-calorimeter"> What is a differential scanning calorimeter? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-a-calorimeter-measure-energy"> How can a calorimeter measure energy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-calorimeters-made-of"> What are calorimeters made of? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/calorimetry"> See all questions in Calorimetry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 408753 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Calculate the heat required to raise the temperature of 0.75 kg of water from 5˚C to 90.˚C?	null
2,062	a9f9bdfe-6ddd-11ea-b122-ccda262736ce	https://socratic.org/questions/598de62e11ef6b21eefcc045	164.00 kPa	start physical_unit 8 8 pressure kpa qc_end c_other constant_temperature qc_end physical_unit 8 8 4 5 volume qc_end physical_unit 8 8 15 16 volume qc_end physical_unit 8 8 22 23 pressure qc_end end	[{"type":"physical unit","value":"Pressure2 [OF] gas [IN] kPa"}]	[{"type":"physical unit","value":"164.00 kPa"}]	[{"type":"other","value":"ConstantTemperature"},{"type":"physical unit","value":"Volume1 [OF] gas [=] \\pu{12 L}"},{"type":"physical unit","value":"Volume2 [OF] gas [=] \\pu{3 L}"},{"type":"physical unit","value":"Pressure1 [OF] gas [=] \\pu{41 kPa}"}]	<h1 class="questionTitle" itemprop="name">A constant temperature, a #12L# volume of gas in a piston, is compressed to #3L#. If the original pressure was #41*kPa#, what is the final pressure? </h1>	null	164.00 kPa	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We apply <a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's Law</a></p> <p><mathjax>#P_1V_1=P_2V_2#</mathjax>, the temperature is constant</p> <p>The initial pressure is <mathjax>#P_1=41kPa#</mathjax></p> <p>The initial volume is <mathjax>#V_1=12L#</mathjax></p> <p>The final volume is <mathjax>#V_2=3L#</mathjax></p> <p>The final pressure is</p> <p><mathjax>#P_2=V_1/V_2P_1=12/341=164kPa#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The pressure is <mathjax>#=164kPa#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We apply <a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's Law</a></p> <p><mathjax>#P_1V_1=P_2V_2#</mathjax>, the temperature is constant</p> <p>The initial pressure is <mathjax>#P_1=41kPa#</mathjax></p> <p>The initial volume is <mathjax>#V_1=12L#</mathjax></p> <p>The final volume is <mathjax>#V_2=3L#</mathjax></p> <p>The final pressure is</p> <p><mathjax>#P_2=V_1/V_2P_1=12/341=164kPa#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A constant temperature, a #12L# volume of gas in a piston, is compressed to #3L#. If the original pressure was #41kPa#, what is the final pressure? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/boyle-s-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Boyle's Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="462878" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/narad-t"><img alt="" class="" src="https://profilepictures.socratic.org/zsDo4Wx9QIqYad4PXKE9_150317-1041.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/narad-t"> Narad T. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-11T18:04:03" itemprop="dateCreated"> Aug 11, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The pressure is <mathjax>#=164kPa#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We apply <a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's Law</a></p> <p><mathjax>#P_1V_1=P_2V_2#</mathjax>, the temperature is constant</p> <p>The initial pressure is <mathjax>#P_1=41kPa#</mathjax></p> <p>The initial volume is <mathjax>#V_1=12L#</mathjax></p> <p>The final volume is <mathjax>#V_2=3L#</mathjax></p> <p>The final pressure is</p> <p><mathjax>#P_2=V_1/V_2P_1=12/341=164kPa#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/462878" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="462880" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-11T18:04:51" itemprop="dateCreated"> Aug 11, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, we use old <a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's law</a>.........and get <mathjax>#P_2=164kPa#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>At constant temperature, and constant amount of gas, the product <mathjax>#PxxV=k#</mathjax>, where <mathjax>#k#</mathjax> is some constant....</p> <p>And thus, if we solve for <mathjax>#k#</mathjax> at different conditions of volume and pressure, then <mathjax>#P_1V_1=P_2V_2#</mathjax>.</p> <p>The utility of this equation is that we can use whatever whack units of volume and pressure we like, <mathjax>#"pints, pounds per square inch, torr, atmospheres, quarts"#</mathjax>, as long as we are consistent.</p> <p>And so...<mathjax>#P_2=(P_1V_1)/V_2=(41kPaxx12L)/(3L)=164kPa#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/462880" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-graph-boyles-law"> How do you graph Boyle's law? 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If the original pressure was #41*kPa#, what is the final pressure?	null
2,063	ab0c169c-6ddd-11ea-aeec-ccda262736ce	https://socratic.org/questions/what-is-the-chemical-form-for-barium-bromate	Ba(BrO3)2	start chemical_formula qc_end substance 6 7 qc_end end	[{"type":"other","value":"Chemical Formula [OF] barium bromate [IN] default"}]	[{"type":"chemical equation","value":"Ba(BrO3)2"}]	[{"type":"substance name","value":"Barium bromate"}]	<h1 class="questionTitle" itemprop="name">What is the chemical form for barium bromate?</h1>	null	Ba(BrO3)2	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And thus the formula for barium bromate is <mathjax>#Ba(BrO_3)_2#</mathjax>. All I have done is cross multiply the charges so I get a neutral salt.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The bromate ion is <mathjax>#BrO_3^-#</mathjax>. The alkaline earth barium commonly forms a <mathjax>#Ba^(2+)#</mathjax> ion. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And thus the formula for barium bromate is <mathjax>#Ba(BrO_3)_2#</mathjax>. All I have done is cross multiply the charges so I get a neutral salt.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the chemical form for barium bromate?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#ionic-bonds-and-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Ionic Bonds</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/ionic-bonds-and-formulas/writing-ionic-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Writing Ionic Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="284500" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-04T05:45:05" itemprop="dateCreated"> Jul 4, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The bromate ion is <mathjax>#BrO_3^-#</mathjax>. The alkaline earth barium commonly forms a <mathjax>#Ba^(2+)#</mathjax> ion. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And thus the formula for barium bromate is <mathjax>#Ba(BrO_3)_2#</mathjax>. All I have done is cross multiply the charges so I get a neutral salt.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/284500" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-write-ionic-formulas-for-binary-compounds"> How do you write ionic formulas for binary compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-formula-for-calcium-chloride"> What is the ionic formula for calcium chloride? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-formula-for-calcium-oxide"> What is the ionic formula for calcium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-formula-for-lithium-oxide"> What is the ionic formula for lithium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-formula-for-ionic-compounds"> How do you write the formula for ionic compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-correctly-write-the-ions-present-in-sn-no3-2"> How do I write #Sn(NO_3)_2# in Ionic formula? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-an-ionic-compound"> What is the empirical formula for an ionic compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-for-chorate"> What is the molecular formula for chorate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5363023c02bf343b2ee7086b"> Question #7086b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-polyatomic-ions-covalent-1"> Why are polyatomic ions covalent? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/ionic-bonds-and-formulas/writing-ionic-formulas"> See all questions in Writing Ionic Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 4235 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the chemical form for barium bromate?	null
2,064	a8d2797e-6ddd-11ea-b893-ccda262736ce	https://socratic.org/questions/magnesium-metal-0-100-mol-and-a-volume-of-aqueous-hydrochloric-acid-that-contain	2.24 liters	start physical_unit 27 28 volume l qc_end chemical_equation 35 42 qc_end physical_unit 0 1 2 3 mole qc_end physical_unit 16 16 13 14 mole qc_end c_other STP qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Volume [OF] hydrogen gas [IN] liters"}]	[{"type":"physical unit","value":"2.24 liters"}]	[{"type":"chemical equation","value":"Mg(s) + 2 HCl(aq) -> MgCl2(aq) + H2(g)"},{"type":"physical unit","value":"Mole [OF] magnesium metal [=] \\pu{0.100 mol}"},{"type":"physical unit","value":"Mole [OF] HCl [=] \\pu{0.500 mol}"},{"type":"other","value":"STP"},{"type":"other","value":"React to completion."}]	<h1 class="questionTitle" itemprop="name">Magnesium metal (0.100 mol) and a volume of aqueous hydrochloric acid that contains 0.500 mol of HCl are combined and react to completion. How many liters of hydrogen gas, measured at STP, can be produced? #"Mg"(s) + 2"HCl"(aq) -> "MgCl"_2(aq) + "H"_2(g)#</h1>	null	2.24 liters	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>Step 1: determine the reaction</strong></p> <p>The chemical equation is already given.</p> <blockquote> <blockquote> <p><mathjax>#"Mg" + 2 "HCl" -> "MgCl"_2 + "H"_2#</mathjax></p> </blockquote> </blockquote> <h2></h2> <p><strong>Step 2: determine which reactant is limiting</strong></p> <p>0.100 mol of Mg reacts with 0.500 mol of HCl, which of them will run out first?</p> <p>From the reaction, the ratio of <mathjax>#"Mg"#</mathjax> to <mathjax>#"HCl"#</mathjax> used is <mathjax>#1:2#</mathjax>. This means that if the reaction goes to completion, the <mathjax>#0.100 "mol"#</mathjax> of <mathjax>#"Mg"#</mathjax> will react with <mathjax>#0.100 "mol" xx 2 = 0.200 "mol"#</mathjax> of <mathjax>#"HCl"#</mathjax>. This leaves <mathjax>#0.500 "mol" - 0.200 "mol" = 0.300 "mol"#</mathjax> of <mathjax>#"HCl"#</mathjax>.</p> <h2></h2> <p><strong>Step 3: determine how much <mathjax>#"H"_2#</mathjax> is produced.</strong></p> <p><mathjax>#0.100 "mol"#</mathjax> of <mathjax>#"Mg"#</mathjax> and <mathjax>#0.200 "mol"#</mathjax> of <mathjax>#"HCl"#</mathjax> will produce <mathjax>#0.100 "mol"#</mathjax> of <mathjax>#"H"_2#</mathjax>.</p> <h2></h2> <p><strong>Step 4: determine the volume at STP</strong></p> <p>Each mole of ideal gas occupies <mathjax>#22.4 "L"#</mathjax> at STP. Therefore, <mathjax>#0.100 "mol"#</mathjax> of <mathjax>#"H"_2#</mathjax> will occupy <mathjax>#2.24 "L"#</mathjax> of space.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2.24 "L"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>Step 1: determine the reaction</strong></p> <p>The chemical equation is already given.</p> <blockquote> <blockquote> <p><mathjax>#"Mg" + 2 "HCl" -> "MgCl"_2 + "H"_2#</mathjax></p> </blockquote> </blockquote> <h2></h2> <p><strong>Step 2: determine which reactant is limiting</strong></p> <p>0.100 mol of Mg reacts with 0.500 mol of HCl, which of them will run out first?</p> <p>From the reaction, the ratio of <mathjax>#"Mg"#</mathjax> to <mathjax>#"HCl"#</mathjax> used is <mathjax>#1:2#</mathjax>. This means that if the reaction goes to completion, the <mathjax>#0.100 "mol"#</mathjax> of <mathjax>#"Mg"#</mathjax> will react with <mathjax>#0.100 "mol" xx 2 = 0.200 "mol"#</mathjax> of <mathjax>#"HCl"#</mathjax>. This leaves <mathjax>#0.500 "mol" - 0.200 "mol" = 0.300 "mol"#</mathjax> of <mathjax>#"HCl"#</mathjax>.</p> <h2></h2> <p><strong>Step 3: determine how much <mathjax>#"H"_2#</mathjax> is produced.</strong></p> <p><mathjax>#0.100 "mol"#</mathjax> of <mathjax>#"Mg"#</mathjax> and <mathjax>#0.200 "mol"#</mathjax> of <mathjax>#"HCl"#</mathjax> will produce <mathjax>#0.100 "mol"#</mathjax> of <mathjax>#"H"_2#</mathjax>.</p> <h2></h2> <p><strong>Step 4: determine the volume at STP</strong></p> <p>Each mole of ideal gas occupies <mathjax>#22.4 "L"#</mathjax> at STP. Therefore, <mathjax>#0.100 "mol"#</mathjax> of <mathjax>#"H"_2#</mathjax> will occupy <mathjax>#2.24 "L"#</mathjax> of space.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Magnesium metal (0.100 mol) and a volume of aqueous hydrochloric acid that contains 0.500 mol of HCl are combined and react to completion. How many liters of hydrogen gas, measured at STP, can be produced? #"Mg"(s) + 2"HCl"(aq) -> "MgCl"_2(aq) + "H"_2(g)#</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/gas-pressure" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Pressure</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="263087" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/bio"><img alt="" class="" src="https://profilepictures.socratic.org/Qm2uaSgSTeLzBx8JHnK7_bq.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/bio"> Bio </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-07T04:30:01" itemprop="dateCreated"> May 7, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2.24 "L"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>Step 1: determine the reaction</strong></p> <p>The chemical equation is already given.</p> <blockquote> <blockquote> <p><mathjax>#"Mg" + 2 "HCl" -> "MgCl"_2 + "H"_2#</mathjax></p> </blockquote> </blockquote> <h2></h2> <p><strong>Step 2: determine which reactant is limiting</strong></p> <p>0.100 mol of Mg reacts with 0.500 mol of HCl, which of them will run out first?</p> <p>From the reaction, the ratio of <mathjax>#"Mg"#</mathjax> to <mathjax>#"HCl"#</mathjax> used is <mathjax>#1:2#</mathjax>. This means that if the reaction goes to completion, the <mathjax>#0.100 "mol"#</mathjax> of <mathjax>#"Mg"#</mathjax> will react with <mathjax>#0.100 "mol" xx 2 = 0.200 "mol"#</mathjax> of <mathjax>#"HCl"#</mathjax>. This leaves <mathjax>#0.500 "mol" - 0.200 "mol" = 0.300 "mol"#</mathjax> of <mathjax>#"HCl"#</mathjax>.</p> <h2></h2> <p><strong>Step 3: determine how much <mathjax>#"H"_2#</mathjax> is produced.</strong></p> <p><mathjax>#0.100 "mol"#</mathjax> of <mathjax>#"Mg"#</mathjax> and <mathjax>#0.200 "mol"#</mathjax> of <mathjax>#"HCl"#</mathjax> will produce <mathjax>#0.100 "mol"#</mathjax> of <mathjax>#"H"_2#</mathjax>.</p> <h2></h2> <p><strong>Step 4: determine the volume at STP</strong></p> <p>Each mole of ideal gas occupies <mathjax>#22.4 "L"#</mathjax> at STP. Therefore, <mathjax>#0.100 "mol"#</mathjax> of <mathjax>#"H"_2#</mathjax> will occupy <mathjax>#2.24 "L"#</mathjax> of space.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/263087" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-gas-pressure-be-changed"> How can gas pressure be changed? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-you-increase-gas-pressure-in-a-container"> How can you increase gas pressure in a container? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-gas-pressure-created"> How is gas pressure created? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-does-gas-pressure-increase-when-temperature-increases"> Why does gas pressure increase when temperature increases? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-gas-pressure-zero-at-absolute-zero"> Why is gas pressure zero at absolute zero? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-does-gas-pressure-increase-with-temperature"> Why does gas pressure increase with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-there-no-gas-pressure-in-a-vacuum"> Why is there no gas pressure in a vacuum? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-total-gas-pressure-in-a-sealed-flask-that-contains-oxygen-at-a-parti-1"> What is the total gas pressure in a sealed flask that contains oxygen at a partial pressure of... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-the-absolute-pressure-of-a-gas-is-550-280-kpa-what-is-its-gage-pressure"> If the absolute pressure of a gas is 550.280 kPa, what is its gage pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-a-gas-sample-occupies-4-2-l-at-a-pressure-of-101-kpa-what-volume-will-it-occu"> If a gas sample occupies 4.2 L at a pressure of 101 kPa. What volume will it occupy if the... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/gas-pressure"> See all questions in Gas Pressure </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 18741 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Magnesium metal (0.100 mol) and a volume of aqueous hydrochloric acid that contains 0.500 mol of HCl are combined and react to completion. How many liters of hydrogen gas, measured at STP, can be produced? #"Mg"(s) + 2"HCl"(aq) -> "MgCl"_2(aq) + "H"_2(g)#	null
2,065	ac521d7a-6ddd-11ea-a0d8-ccda262736ce	https://socratic.org/questions/what-is-the-empirical-formula-of-p-4o-10	P2O5	start chemical_formula qc_end chemical_equation 6 6 qc_end end	[{"type":"other","value":"Chemical Formula [OF] P4O10 [IN] empirical"}]	[{"type":"chemical equation","value":"P2O5"}]	[{"type":"chemical equation","value":"P4O10"}]	<h1 class="questionTitle" itemprop="name">What is the empirical formula of #P_4O_10#?</h1>	null	P2O5	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>By definition, <mathjax>#"the empirical formula"#</mathjax> is the simplest whole number that defines constituent atoms in a species. The molecular formula is always a whole number multiple of the empirical formula. Of course, the multiple may be <mathjax>#1#</mathjax>.</p> <p>Can you give me empirical formulae for <mathjax>#Na_2O_2#</mathjax>, <mathjax>#C_4H_10#</mathjax>, <mathjax>#C_6H_6#</mathjax>?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#P_2O_5#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>By definition, <mathjax>#"the empirical formula"#</mathjax> is the simplest whole number that defines constituent atoms in a species. The molecular formula is always a whole number multiple of the empirical formula. Of course, the multiple may be <mathjax>#1#</mathjax>.</p> <p>Can you give me empirical formulae for <mathjax>#Na_2O_2#</mathjax>, <mathjax>#C_4H_10#</mathjax>, <mathjax>#C_6H_6#</mathjax>?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the empirical formula of #P_4O_10#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="284750" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-04T20:59:24" itemprop="dateCreated"> Jul 4, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#P_2O_5#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>By definition, <mathjax>#"the empirical formula"#</mathjax> is the simplest whole number that defines constituent atoms in a species. The molecular formula is always a whole number multiple of the empirical formula. Of course, the multiple may be <mathjax>#1#</mathjax>.</p> <p>Can you give me empirical formulae for <mathjax>#Na_2O_2#</mathjax>, <mathjax>#C_4H_10#</mathjax>, <mathjax>#C_6H_6#</mathjax>?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/284750" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molecular-formula-of-a-compound"> How do you find molecular formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-diamond"> What is the chemical formula of a diamond? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-carbohydrate"> What is the chemical formula of a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-valproic-acid"> What is the empirical formula for valproic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-of-magnesium-oxide"> What is the empirical formula of magnesium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-empirical-formula-not-double-that-of-the-monosaccharides"> Why is the empirical formula not double that of the monosaccharides? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5331180502bf342f40b5c3b5"> Question #5c3b5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-molecular-formula-represents-a-carbohydrate"> What molecular formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-of-vinegar"> What is the molecular formula of vinegar? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/empirical-and-molecular-formulas"> See all questions in Empirical and Molecular Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1046 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the empirical formula of #P_4O_10#?	null
2,066	ac09f478-6ddd-11ea-8b0b-ccda262736ce	https://socratic.org/questions/560981c3581e2a2b1f33707f	C4H10	start chemical_formula qc_end c_other OTHER qc_end end	[{"type":"other","value":"Chemical Formula [OF] the compound [IN] molecular"}]	[{"type":"chemical equation","value":"C4H10"}]	[{"type":"physical unit","value":"Molecular mass [OF] the compound [=] \\pu{58 g/mol}"},{"type":"other","value":"The empirical formula of the compound is C2H5."}]	<h1 class="questionTitle" itemprop="name">If the empirical formula is #C_2H_5#, and the molecular mass is #58gmol^-1#, what is the molecular formula?</h1>	null	C4H10	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Butane is a <mathjax>#C_4#</mathjax> alkane. The isomer depicted is the straight chain, <em>n</em> -butane. It has 1 other isomer.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>If I am reading your question correctly, it is <mathjax>#H_3C-CH_2CH_2CH_3#</mathjax> or <mathjax>#C_4H_10#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Butane is a <mathjax>#C_4#</mathjax> alkane. The isomer depicted is the straight chain, <em>n</em> -butane. It has 1 other isomer.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">If the empirical formula is #C_2H_5#, and the molecular mass is #58gmol^-1#, what is the molecular formula?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="172673" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-09-28T18:16:21" itemprop="dateCreated"> Sep 28, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>If I am reading your question correctly, it is <mathjax>#H_3C-CH_2CH_2CH_3#</mathjax> or <mathjax>#C_4H_10#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Butane is a <mathjax>#C_4#</mathjax> alkane. The isomer depicted is the straight chain, <em>n</em> -butane. It has 1 other isomer.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/172673" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="172735" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-09-29T02:00:31" itemprop="dateCreated"> Sep 29, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"C"_4"H"_10#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>I assume that you have to determine the molecular formula of butane starting from its <em>empirical formula</em> and its molar mass, which is <mathjax>#~= "58 g"#</mathjax>.</p> <p>If you started from butane's <a href="http://socratic.org/chemistry/the-mole-concept/percent-composition">percent composition</a> of carbon and hydrogen, and provided that your calculations were correct, then the empirical formula should have come out as <mathjax>#"C"_2"H"_5#</mathjax>. </p> <p>Now, you know that the empirical formula tells you the <em>simplest ratio</em> of atoms between the <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> that make up a compound. </p> <p>In your case, you know that a butane molecule contains <strong>5 atoms</strong> of hydrogen <em>for every</em> <strong>2 atoms</strong> of carbon. </p> <p>Since you know what the compound's molar mass is, you can say that </p> <blockquote> <p><mathjax>#(2 xx M_"M carbon" + 5 xx M_"M hydrogen") * color(blue)(n) = "58 g"#</mathjax></p> </blockquote> <p>You know that the molecule contains <strong>at least</strong> two atoms of carbon and five atoms of hydrogen, but you don't <em>exactly</em> how many of each you have <mathjax>#->#</mathjax> this is what <mathjax>#color(blue)(n)#</mathjax> represents. </p> <p>So, use the molar masses of carbon and hydrogen to get the value of <mathjax>#color(blue)(n)#</mathjax></p> <blockquote> <p><mathjax>#(2 xx "12.01 g/mol" + 5 xx "1.01 g/mol") * color(blue)(n) = "58 g"#</mathjax></p> <p><mathjax>#color(blue)(n) = (58color(red)(cancel(color(black)("g"))))/(29.07color(red)(cancel(color(black)("g")))) = "1.995 ~= 2#</mathjax></p> </blockquote> <p>This means tha tthe molecular formula of butane is </p> <blockquote> <p><mathjax>#("C"_2"H"_5)_2 = color(green)("C"_4"H"_10)#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/172735" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? 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</a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-empirical-formula-not-double-that-of-the-monosaccharides"> Why is the empirical formula not double that of the monosaccharides? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5331180502bf342f40b5c3b5"> Question #5c3b5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-molecular-formula-represents-a-carbohydrate"> What molecular formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-of-vinegar"> What is the molecular formula of vinegar? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/empirical-and-molecular-formulas"> See all questions in Empirical and Molecular Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 14306 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	If the empirical formula is #C_2H_5#, and the molecular mass is #58gmol^-1#, what is the molecular formula?	null
2,067	ac81f0ac-6ddd-11ea-b7e5-ccda262736ce	https://socratic.org/questions/some-molecules-of-c-11h-24-crack-to-produce-ethene-and-propene-how-would-you-wri	C11H24 -> C2H4 + C3H6 + C6H14	start chemical_equation qc_end chemical_equation 3 3 qc_end substance 7 7 qc_end substance 9 9 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the cracking reaction"}]	[{"type":"chemical equation","value":"C11H24 -> C2H4 + C3H6 + C6H14"}]	[{"type":"chemical equation","value":"C11H24"},{"type":"substance name","value":"Ethene"},{"type":"substance name","value":"Propene"}]	<h1 class="questionTitle" itemprop="name">Some molecules of #C_11H_24# crack to produce ethene and propene. How would you write a balanced equation to show a cracking reaction which makes ethene and propene?</h1>	null	C11H24 -> C2H4 + C3H6 + C6H14	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The starting molecule in the question, undecane, will break down into three products. Two are listed in your question: ethene and propene (these are alkenes). The third product is an alkane that consists of the "leftover" carbons and hydrogens. Ethene has the formula <mathjax>#C_2H_4#</mathjax>. Propene has the formula <mathjax>#C_3H_6#</mathjax>.</p> <p>So far, you have:</p> <p><mathjax>#C_11H_24 -> C_2H_4 + C_3H_6 + C_?H_?#</mathjax></p> <p>Remember that we have to balance the equation, so the leftover carbons and hydrogens will go to the third product. We have <mathjax>#11-2-3 = 6#</mathjax> carbons and <mathjax>#24-4-6=14#</mathjax> hydrogens. This forms the alkane known as hexane.</p> <p>Now the balanced equation is:</p> <p><mathjax>#C_11H_24 -> C_2H_4 + C_3H_6 + C_6H_14#</mathjax></p> <p>Cracking involves larger alkanes, so hexane should not break down.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_11H_24 -> C_2H_4 + C_3H_6 + C_6H_14#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The starting molecule in the question, undecane, will break down into three products. Two are listed in your question: ethene and propene (these are alkenes). The third product is an alkane that consists of the "leftover" carbons and hydrogens. Ethene has the formula <mathjax>#C_2H_4#</mathjax>. Propene has the formula <mathjax>#C_3H_6#</mathjax>.</p> <p>So far, you have:</p> <p><mathjax>#C_11H_24 -> C_2H_4 + C_3H_6 + C_?H_?#</mathjax></p> <p>Remember that we have to balance the equation, so the leftover carbons and hydrogens will go to the third product. We have <mathjax>#11-2-3 = 6#</mathjax> carbons and <mathjax>#24-4-6=14#</mathjax> hydrogens. This forms the alkane known as hexane.</p> <p>Now the balanced equation is:</p> <p><mathjax>#C_11H_24 -> C_2H_4 + C_3H_6 + C_6H_14#</mathjax></p> <p>Cracking involves larger alkanes, so hexane should not break down.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Some molecules of #C_11H_24# crack to produce ethene and propene. How would you write a balanced equation to show a cracking reaction which makes ethene and propene?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-reactions-and-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions and Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="465349" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/jj-22"><img alt="" class="" src="https://profilepictures.socratic.org/7rbmw02SjG0Zao1h2E9A_Chromodorisverrieri.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/jj-22"> JJ </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-18T04:13:00" itemprop="dateCreated"> Aug 18, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_11H_24 -> C_2H_4 + C_3H_6 + C_6H_14#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The starting molecule in the question, undecane, will break down into three products. Two are listed in your question: ethene and propene (these are alkenes). The third product is an alkane that consists of the "leftover" carbons and hydrogens. Ethene has the formula <mathjax>#C_2H_4#</mathjax>. Propene has the formula <mathjax>#C_3H_6#</mathjax>.</p> <p>So far, you have:</p> <p><mathjax>#C_11H_24 -> C_2H_4 + C_3H_6 + C_?H_?#</mathjax></p> <p>Remember that we have to balance the equation, so the leftover carbons and hydrogens will go to the third product. We have <mathjax>#11-2-3 = 6#</mathjax> carbons and <mathjax>#24-4-6=14#</mathjax> hydrogens. This forms the alkane known as hexane.</p> <p>Now the balanced equation is:</p> <p><mathjax>#C_11H_24 -> C_2H_4 + C_3H_6 + C_6H_14#</mathjax></p> <p>Cracking involves larger alkanes, so hexane should not break down.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/465349" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb002bf34694a4fee47"> Question #fee47 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb402bf34694c8c5c15"> Question #c5c15 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb802bf346950519eb9"> Question #19eb9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cbf02bf3469570e2ea2"> Question #e2ea2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc002bf34695a6bc751"> Question #bc751 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc202bf3469570e2ea6"> Question #e2ea6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531e867a02bf342492a08b07"> Question #08b07 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-thermochemical-equation-for-the-combustion-of-benzene"> What is the thermochemical equation for the combustion of benzene? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-reversible"> Why are chemical reactions reversible? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-important"> Why are chemical reactions important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/chemical-reactions-and-equations"> See all questions in Chemical Reactions and Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 10930 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Some molecules of #C_11H_24# crack to produce ethene and propene. How would you write a balanced equation to show a cracking reaction which makes ethene and propene?	null
2,068	a91d8023-6ddd-11ea-ae3a-ccda262736ce	https://socratic.org/questions/how-do-you-balance-nh-3-i-2-ni-3-h-2	NH3 + 3 I2 -> NI3 + 3 HI	start chemical_equation qc_end chemical_equation 4 10 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the equation"}]	[{"type":"chemical equation","value":"NH3 + 3 I2 -> NI3 + 3 HI"}]	[{"type":"chemical equation","value":"NH3 + I2 -> NI3 + HI"}]	<h1 class="questionTitle" itemprop="name">How do you balance #NH_3 + I_2 -> NI_3 + H_2#?</h1>	null	NH3 + 3 I2 -> NI3 + 3 HI	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Is this reaction balanced? How do you know?</p> <p>This reaction is not recommended even on the micro scale. Nitrogen triiodide is extremely shock sensitive when dry, and quite a few chemists are missing a few fingers because of this sensitivity. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#NH_3 + 3I_2 rarr NI_3 + 3HI#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Is this reaction balanced? How do you know?</p> <p>This reaction is not recommended even on the micro scale. Nitrogen triiodide is extremely shock sensitive when dry, and quite a few chemists are missing a few fingers because of this sensitivity. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you balance #NH_3 + I_2 -> NI_3 + H_2#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="192196" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-23T10:47:26" itemprop="dateCreated"> Nov 23, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#NH_3 + 3I_2 rarr NI_3 + 3HI#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Is this reaction balanced? How do you know?</p> <p>This reaction is not recommended even on the micro scale. Nitrogen triiodide is extremely shock sensitive when dry, and quite a few chemists are missing a few fingers because of this sensitivity. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/192196" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------> H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -> Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? 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Sodium phosphate and calcium chloride react to form... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-equation-kclo3-kcl-o2"> How can I balance this equation? ____ #KClO_3 -># ____ #KCl +# ____ #O_2# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-balancing-chemical-equations-important"> Why is balancing chemical equations important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/balancing-chemical-equations"> See all questions in Balancing Chemical Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1228 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How do you balance #NH_3 + I_2 -> NI_3 + H_2#?	null
2,069	ac457d78-6ddd-11ea-bae5-ccda262736ce	https://socratic.org/questions/what-is-the-mass-in-grams-of-15-l-of-o-2-at-stp	21 grams	start physical_unit 10 10 mass g qc_end physical_unit 10 10 7 8 volume qc_end c_other STP qc_end end	[{"type":"physical unit","value":"Mass [OF] O2 [IN] grams"}]	[{"type":"physical unit","value":"21 grams"}]	[{"type":"physical unit","value":"Volume [OF] O2 [=] \\pu{15 L}"},{"type":"other","value":"STP"}]	<h1 class="questionTitle" itemprop="name">What is the mass, in grams, of 15 L of #O_2# at STP?</h1>	null	21 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Since we are at STP this means that we have to use the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law equation</a>.<br/> <mathjax>#PxxV = nxxRxxT#</mathjax>. </p> <ul> <li>P represents pressure (could have units of atm, depending on the units of the universal gas constant)</li> <li>V represents volume (must have units of liters)</li> <li>n represents the number of moles</li> <li>R is the universal gas constant (has units of <mathjax>#(Lxxatm)/ (molxxK)#</mathjax>)</li> <li>T represents the temperature, which must be in Kelvins.</li> </ul> <p>Next, list your known and unknown variables. Our only unknown is the number of moles of <mathjax>#O_2(g)#</mathjax>. Our known variables are P,V,R, and T. </p> <p>At STP, the temperature is 273K and the pressure is 1 atm. The proportionality constant, R, is equal to 0.0821 <mathjax>#(Lxxatm)/ (molxxK)#</mathjax></p> <p>Now we have to rearrange the equation to solve for n:</p> <p><mathjax># n = (PV)/(RT)#</mathjax></p> <p><mathjax>#n = (1cancel"atm"xx15cancelL)/(0.0821(cancel"Lxxatm")/(molxxcancel"K")xx273cancel"K"#</mathjax><br/> <mathjax>#n = 0.6692mol#</mathjax></p> <p>To get the mass of <mathjax>#O_2#</mathjax>, we just have to use the molar mass of oxygen as a conversion factor:</p> <p><mathjax>#0.6692cancel"mol" O_2 xx (32.00g)/(1cancel "mol")#</mathjax> = 21g <mathjax>#O_2#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>There are 21 g of <mathjax>#O_2#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Since we are at STP this means that we have to use the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law equation</a>.<br/> <mathjax>#PxxV = nxxRxxT#</mathjax>. </p> <ul> <li>P represents pressure (could have units of atm, depending on the units of the universal gas constant)</li> <li>V represents volume (must have units of liters)</li> <li>n represents the number of moles</li> <li>R is the universal gas constant (has units of <mathjax>#(Lxxatm)/ (molxxK)#</mathjax>)</li> <li>T represents the temperature, which must be in Kelvins.</li> </ul> <p>Next, list your known and unknown variables. Our only unknown is the number of moles of <mathjax>#O_2(g)#</mathjax>. Our known variables are P,V,R, and T. </p> <p>At STP, the temperature is 273K and the pressure is 1 atm. The proportionality constant, R, is equal to 0.0821 <mathjax>#(Lxxatm)/ (molxxK)#</mathjax></p> <p>Now we have to rearrange the equation to solve for n:</p> <p><mathjax># n = (PV)/(RT)#</mathjax></p> <p><mathjax>#n = (1cancel"atm"xx15cancelL)/(0.0821(cancel"Lxxatm")/(molxxcancel"K")xx273cancel"K"#</mathjax><br/> <mathjax>#n = 0.6692mol#</mathjax></p> <p>To get the mass of <mathjax>#O_2#</mathjax>, we just have to use the molar mass of oxygen as a conversion factor:</p> <p><mathjax>#0.6692cancel"mol" O_2 xx (32.00g)/(1cancel "mol")#</mathjax> = 21g <mathjax>#O_2#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the mass, in grams, of 15 L of #O_2# at STP?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp" itemprop="url"> <span class="breadcrumb" itemprop="title">Molar Volume of a Gas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="279199" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/kayla-14"><img alt="" class="" src="https://profilepictures.socratic.org/OvMTWaamQPWcqLIkUNnG_793604964071127.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/kayla-14"> Kayla </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-20T02:41:24" itemprop="dateCreated"> Jun 20, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>There are 21 g of <mathjax>#O_2#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Since we are at STP this means that we have to use the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law equation</a>.<br/> <mathjax>#PxxV = nxxRxxT#</mathjax>. </p> <ul> <li>P represents pressure (could have units of atm, depending on the units of the universal gas constant)</li> <li>V represents volume (must have units of liters)</li> <li>n represents the number of moles</li> <li>R is the universal gas constant (has units of <mathjax>#(Lxxatm)/ (molxxK)#</mathjax>)</li> <li>T represents the temperature, which must be in Kelvins.</li> </ul> <p>Next, list your known and unknown variables. Our only unknown is the number of moles of <mathjax>#O_2(g)#</mathjax>. Our known variables are P,V,R, and T. </p> <p>At STP, the temperature is 273K and the pressure is 1 atm. The proportionality constant, R, is equal to 0.0821 <mathjax>#(Lxxatm)/ (molxxK)#</mathjax></p> <p>Now we have to rearrange the equation to solve for n:</p> <p><mathjax># n = (PV)/(RT)#</mathjax></p> <p><mathjax>#n = (1cancel"atm"xx15cancelL)/(0.0821(cancel"Lxxatm")/(molxxcancel"K")xx273cancel"K"#</mathjax><br/> <mathjax>#n = 0.6692mol#</mathjax></p> <p>To get the mass of <mathjax>#O_2#</mathjax>, we just have to use the molar mass of oxygen as a conversion factor:</p> <p><mathjax>#0.6692cancel"mol" O_2 xx (32.00g)/(1cancel "mol")#</mathjax> = 21g <mathjax>#O_2#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/279199" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-stoichiometric-ratios-relate-to-molar-volume-of-a-gas"> How do stoichiometric ratios relate to molar volume of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-a-gas-at-stp"> How do you calculate molar volume of a gas at STP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-molar-volume-of-hydrogen-gas"> How do you find the molar volume of hydrogen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-oxygen-gas"> How do you calculate molar volume of oxygen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molar-gas-volume"> What is molar gas volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/534c7bf202bf3420a007f014"> What is the volume at 0 °C and 1 atm of a mixture that contains 4.0 g of methane and 2.0 g of helium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5361f75702bf3429040e0599"> What is the difference between STP and NTP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-volume-of-25-moles-of-oxygen-o2-gas"> What is the volume of .25 moles of oxygen (O2) Gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-would-knowing-the-molar-volume-of-a-gas-be-important"> Why would knowing the molar volume of a gas be important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-22-4-liters-called-the-molar-volume-of-a-gas"> Why is 22.4 liters called the molar volume of a gas? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp"> See all questions in Molar Volume of a Gas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 4448 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the mass, in grams, of 15 L of #O_2# at STP?	null
2,070	ab6b318c-6ddd-11ea-a9bf-ccda262736ce	https://socratic.org/questions/the-value-of-k-w-is-5-13-10-13-at-an-elevate-temperature-what-is-the-h-3o-if-the-1	2.1 × 10^(-11) M	start physical_unit 15 15 concentration mol/l qc_end physical_unit 18 18 21 24 concentration qc_end end	[{"type":"physical unit","value":"Concentration [OF] H3O+ [IN] M"}]	[{"type":"physical unit","value":"2.1 × 10^(-11) M"}]	[{"type":"physical unit","value":"value of Kw [OF] the reaction [=] \\pu{5.13 × 10^(-13)}"},{"type":"physical unit","value":"Concentration [OF] OH- [=] \\pu{2.5 × 10^(-2) M}"}]	<h1 class="questionTitle" itemprop="name">The value of #K_w# is #5.13 * 10^-13#, at an elevate temperature. What is the #H_3O^+# if the #OH^-# concentration is #2.5 * 10^-2# M?</h1>	null	2.1 × 10^(-11) M	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>As you know, water undergoes a <strong>self-ionization reaction</strong> that leads to the formation of <em>hydronium cations</em>, <mathjax>#"H"_3"O"^(+)#</mathjax>, and <em>hydroxide anions</em>, <mathjax>#"OH"^(-)#</mathjax>.</p> <p>In this reaction, water exhibits its <em>amphoteric character</em> by acting both as an acid, and as a base. The balanced chemical equation for this <a href="http://socratic.org/chemistry/chemical-equilibrium/dynamic-equilibrium">equilibrium reaction</a> looks like this </p> <blockquote> <p><mathjax>#"H"_2"O"_text((l]) + "H"_2"O"_text((l]) rightleftharpoons "H"_3"O"_text((aq])^(+) + "OH"_text((aq])^(-)#</mathjax></p> </blockquote> <p>Now, the <a href="http://socratic.org/chemistry/chemical-equilibrium/equilibrium-constants">equilibrium constant</a> for this reaction looks like this </p> <blockquote> <p><mathjax>#K_a = ( ["H"_3"O"^(+)] * ["OH"^(-)])/(["H"_2"O"]^2)#</mathjax></p> </blockquote> <p>In aqueous solution, the concentration of water can be assumed to be constant. This means that you can write </p> <blockquote> <p><mathjax>#overbrace(K_a * ["H"_2"O"]^2)^(color(blue)(K_W)) = ["H"_3"O"^(+)] * ["OH"^(-)]#</mathjax></p> </blockquote> <p>Here <mathjax>#K_W#</mathjax> is called the <strong>self-ionization constant</strong>, or <strong>Ion product constant</strong>, of water.</p> <p>Now, you know that a certain temperature, <mathjax>#K_w = 5.13 * 10^(-13)#</mathjax>. Moreover, you know that this solution contains </p> <blockquote> <p><mathjax>#["OH"^(-)] = 2.5 * 10^(-2)"M"#</mathjax></p> </blockquote> <p>Notice how large the concentration of hydroxide ions is compared with <mathjax>#K_W#</mathjax>. This tells you that you're dealing with a <strong>very basic</strong> solution for which you can expect a very high <a href="http://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> value. </p> <p>Rearrange the above equation and solve for <mathjax>#"H"_3"O"^(+)#</mathjax> to get </p> <blockquote> <p><mathjax>#["H"_3"O"^(+)] = K_W/(["OH"^(-)])#</mathjax></p> <p><mathjax>#["H"_3"O"^(+)] = (5.13 * 10^(-13))/(2.5 * 10^(-2)) = color(green)(2.1 * 10^(-11)"M")#</mathjax></p> </blockquote> <p>As a side note, the pH of the solution will be </p> <blockquote> <p><mathjax>#"pH" = - log( ["H"_3"O"^(+)])#</mathjax></p> <p><mathjax>#"pH" = - log(2.052 * 10^(-11)) = 10.69#</mathjax></p> </blockquote> <p>Another interesting thing to do here is figure out what the pH of <strong>pure water</strong> would be at this temperature. </p> <blockquote> <p><mathjax>#"pH" = - log (sqrt(K_W))#</mathjax></p> <p><mathjax>#"pH" = - log( sqrt(5.13 * 10^(-13))) = 6.14#</mathjax></p> </blockquote> <p>At this temperature, pure water is <strong>neutral</strong> at pH equal to <mathjax>#6.14#</mathjax>. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2.1 * 10^(-11)"M"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>As you know, water undergoes a <strong>self-ionization reaction</strong> that leads to the formation of <em>hydronium cations</em>, <mathjax>#"H"_3"O"^(+)#</mathjax>, and <em>hydroxide anions</em>, <mathjax>#"OH"^(-)#</mathjax>.</p> <p>In this reaction, water exhibits its <em>amphoteric character</em> by acting both as an acid, and as a base. The balanced chemical equation for this <a href="http://socratic.org/chemistry/chemical-equilibrium/dynamic-equilibrium">equilibrium reaction</a> looks like this </p> <blockquote> <p><mathjax>#"H"_2"O"_text((l]) + "H"_2"O"_text((l]) rightleftharpoons "H"_3"O"_text((aq])^(+) + "OH"_text((aq])^(-)#</mathjax></p> </blockquote> <p>Now, the <a href="http://socratic.org/chemistry/chemical-equilibrium/equilibrium-constants">equilibrium constant</a> for this reaction looks like this </p> <blockquote> <p><mathjax>#K_a = ( ["H"_3"O"^(+)] * ["OH"^(-)])/(["H"_2"O"]^2)#</mathjax></p> </blockquote> <p>In aqueous solution, the concentration of water can be assumed to be constant. This means that you can write </p> <blockquote> <p><mathjax>#overbrace(K_a * ["H"_2"O"]^2)^(color(blue)(K_W)) = ["H"_3"O"^(+)] * ["OH"^(-)]#</mathjax></p> </blockquote> <p>Here <mathjax>#K_W#</mathjax> is called the <strong>self-ionization constant</strong>, or <strong>Ion product constant</strong>, of water.</p> <p>Now, you know that a certain temperature, <mathjax>#K_w = 5.13 * 10^(-13)#</mathjax>. Moreover, you know that this solution contains </p> <blockquote> <p><mathjax>#["OH"^(-)] = 2.5 * 10^(-2)"M"#</mathjax></p> </blockquote> <p>Notice how large the concentration of hydroxide ions is compared with <mathjax>#K_W#</mathjax>. This tells you that you're dealing with a <strong>very basic</strong> solution for which you can expect a very high <a href="http://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> value. </p> <p>Rearrange the above equation and solve for <mathjax>#"H"_3"O"^(+)#</mathjax> to get </p> <blockquote> <p><mathjax>#["H"_3"O"^(+)] = K_W/(["OH"^(-)])#</mathjax></p> <p><mathjax>#["H"_3"O"^(+)] = (5.13 * 10^(-13))/(2.5 * 10^(-2)) = color(green)(2.1 * 10^(-11)"M")#</mathjax></p> </blockquote> <p>As a side note, the pH of the solution will be </p> <blockquote> <p><mathjax>#"pH" = - log( ["H"_3"O"^(+)])#</mathjax></p> <p><mathjax>#"pH" = - log(2.052 * 10^(-11)) = 10.69#</mathjax></p> </blockquote> <p>Another interesting thing to do here is figure out what the pH of <strong>pure water</strong> would be at this temperature. </p> <blockquote> <p><mathjax>#"pH" = - log (sqrt(K_W))#</mathjax></p> <p><mathjax>#"pH" = - log( sqrt(5.13 * 10^(-13))) = 6.14#</mathjax></p> </blockquote> <p>At this temperature, pure water is <strong>neutral</strong> at pH equal to <mathjax>#6.14#</mathjax>. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">The value of #K_w# is #5.13 * 10^-13#, at an elevate temperature. What is the #H_3O^+# if the #OH^-# concentration is #2.5 * 10^-2# M?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="196062" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-04T01:57:05" itemprop="dateCreated"> Dec 4, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2.1 * 10^(-11)"M"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>As you know, water undergoes a <strong>self-ionization reaction</strong> that leads to the formation of <em>hydronium cations</em>, <mathjax>#"H"_3"O"^(+)#</mathjax>, and <em>hydroxide anions</em>, <mathjax>#"OH"^(-)#</mathjax>.</p> <p>In this reaction, water exhibits its <em>amphoteric character</em> by acting both as an acid, and as a base. The balanced chemical equation for this <a href="http://socratic.org/chemistry/chemical-equilibrium/dynamic-equilibrium">equilibrium reaction</a> looks like this </p> <blockquote> <p><mathjax>#"H"_2"O"_text((l]) + "H"_2"O"_text((l]) rightleftharpoons "H"_3"O"_text((aq])^(+) + "OH"_text((aq])^(-)#</mathjax></p> </blockquote> <p>Now, the <a href="http://socratic.org/chemistry/chemical-equilibrium/equilibrium-constants">equilibrium constant</a> for this reaction looks like this </p> <blockquote> <p><mathjax>#K_a = ( ["H"_3"O"^(+)] * ["OH"^(-)])/(["H"_2"O"]^2)#</mathjax></p> </blockquote> <p>In aqueous solution, the concentration of water can be assumed to be constant. This means that you can write </p> <blockquote> <p><mathjax>#overbrace(K_a * ["H"_2"O"]^2)^(color(blue)(K_W)) = ["H"_3"O"^(+)] * ["OH"^(-)]#</mathjax></p> </blockquote> <p>Here <mathjax>#K_W#</mathjax> is called the <strong>self-ionization constant</strong>, or <strong>Ion product constant</strong>, of water.</p> <p>Now, you know that a certain temperature, <mathjax>#K_w = 5.13 * 10^(-13)#</mathjax>. Moreover, you know that this solution contains </p> <blockquote> <p><mathjax>#["OH"^(-)] = 2.5 * 10^(-2)"M"#</mathjax></p> </blockquote> <p>Notice how large the concentration of hydroxide ions is compared with <mathjax>#K_W#</mathjax>. This tells you that you're dealing with a <strong>very basic</strong> solution for which you can expect a very high <a href="http://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> value. </p> <p>Rearrange the above equation and solve for <mathjax>#"H"_3"O"^(+)#</mathjax> to get </p> <blockquote> <p><mathjax>#["H"_3"O"^(+)] = K_W/(["OH"^(-)])#</mathjax></p> <p><mathjax>#["H"_3"O"^(+)] = (5.13 * 10^(-13))/(2.5 * 10^(-2)) = color(green)(2.1 * 10^(-11)"M")#</mathjax></p> </blockquote> <p>As a side note, the pH of the solution will be </p> <blockquote> <p><mathjax>#"pH" = - log( ["H"_3"O"^(+)])#</mathjax></p> <p><mathjax>#"pH" = - log(2.052 * 10^(-11)) = 10.69#</mathjax></p> </blockquote> <p>Another interesting thing to do here is figure out what the pH of <strong>pure water</strong> would be at this temperature. </p> <blockquote> <p><mathjax>#"pH" = - log (sqrt(K_W))#</mathjax></p> <p><mathjax>#"pH" = - log( sqrt(5.13 * 10^(-13))) = 6.14#</mathjax></p> </blockquote> <p>At this temperature, pure water is <strong>neutral</strong> at pH equal to <mathjax>#6.14#</mathjax>. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/196062" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-morality-be-used-as-a-conversion-factor"> How can molarity be used as a conversion factor? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-high-can-molarity-be"> How high can molarity be? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-molarity-change-with-temperature"> How does molarity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molarity-of-a-solution"> How do you find molarity of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-10-naoh"> What is the molarity of 10 NaOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-3-hydrogen-peroxide"> What is the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2965 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	The value of #K_w# is #5.13 * 10^-13#, at an elevate temperature. What is the #H_3O^+# if the #OH^-# concentration is #2.5 * 10^-2# M?	null
2,071	aa122f5a-6ddd-11ea-b5f7-ccda262736ce	https://socratic.org/questions/58d7f810b72cff290b2a5a4b	2.71 × 10^23	start physical_unit 2 3 number none qc_end physical_unit 10 10 6 7 mole qc_end end	[{"type":"physical unit","value":"Number [OF] phosphorus atoms"}]	[{"type":"physical unit","value":"2.71 × 10^23"}]	[{"type":"physical unit","value":"Mole [OF] hydroxyapatite [=] \\pu{0.0750 mol}"}]	<h1 class="questionTitle" itemprop="name">How many phosphorus atoms in a #0.0750*mol# quantity of #"hydroxyapatite"#?</h1>	null	2.71 × 10^23	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And of course in one formula unit, I read 6 phosphorus atoms, present as the phosphate.</p> <p>SO in <mathjax>#0.0750mol#</mathjax> of the stuff there are <mathjax>#0.0750molxx6#</mathjax> <mathjax>#mol*P#</mathjax> atoms...........</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Is not <mathjax>#"hydroxyapatite"#</mathjax>, <mathjax>#Ca_10(PO_4)_6(OH)_2#</mathjax>?</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And of course in one formula unit, I read 6 phosphorus atoms, present as the phosphate.</p> <p>SO in <mathjax>#0.0750mol#</mathjax> of the stuff there are <mathjax>#0.0750molxx6#</mathjax> <mathjax>#mol*P#</mathjax> atoms...........</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many phosphorus atoms in a #0.0750mol# quantity of #"hydroxyapatite"#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="397074" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-27T04:01:05" itemprop="dateCreated"> Mar 27, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Is not <mathjax>#"hydroxyapatite"#</mathjax>, <mathjax>#Ca_10(PO_4)_6(OH)_2#</mathjax>?</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And of course in one formula unit, I read 6 phosphorus atoms, present as the phosphate.</p> <p>SO in <mathjax>#0.0750mol#</mathjax> of the stuff there are <mathjax>#0.0750molxx6#</mathjax> <mathjax>#molP#</mathjax> atoms...........</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/397074" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? 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2,072	ab6823b4-6ddd-11ea-8a2d-ccda262736ce	https://socratic.org/questions/during-this-reaction-p-4-5o-2-p-4o-10-1-5-moles-of-product-were-made-in-30-secon	0.05 mol/(L * s)	start physical_unit 2 2 percent mol/(l_·_s) qc_end physical_unit 12 12 9 10 mole qc_end chemical_equation 3 8 qc_end physical_unit 2 2 16 17 time qc_end end	[{"type":"physical unit","value":"Rate [OF] reaction [IN] mol/(L * s)"}]	[{"type":"physical unit","value":"0.05 mol/(L * s)"}]	[{"type":"physical unit","value":"Mole [OF] product [=] \\pu{1.5 moles}"},{"type":"chemical equation","value":"P4 + 5 O2 -> P4O10"},{"type":"physical unit","value":"Time [OF] reaction [=] \\pu{30 seconds}"}]	<h1 class="questionTitle" itemprop="name">During this reaction, #P_4 + 5O_2 -> P_4O_10#, 1.5 moles of product were made in 30 seconds. What is the rate of reaction? </h1>	null	0.05 mol/(L * s)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>For the reaction <mathjax>#"P"_4 +"5O"_2→ "P"_4"O"_10#</mathjax>, the rate of reaction is defined as</p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a) "rate" = -1/1(Δ["P"_4])/(Δt) = -1/5(Δ["O"_2])/(Δt) = +1/1(Δ["P"_4"O"_10])/(Δt)color(white)(a/a)\|)))" "#</mathjax></p> </blockquote> <p>If the volume of the container is 1 L,</p> <p><mathjax>#"rate" = +(Δ"P"_4"O"_10)/(Δt) = +("1.5 mol/L")/("30 s") = "0.050 mol·L"^"-1""s"^"-1"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The rate of reaction is the rate of formation of <mathjax>#"P"_4"O"_10#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>For the reaction <mathjax>#"P"_4 +"5O"_2→ "P"_4"O"_10#</mathjax>, the rate of reaction is defined as</p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a) "rate" = -1/1(Δ["P"_4])/(Δt) = -1/5(Δ["O"_2])/(Δt) = +1/1(Δ["P"_4"O"_10])/(Δt)color(white)(a/a)\|)))" "#</mathjax></p> </blockquote> <p>If the volume of the container is 1 L,</p> <p><mathjax>#"rate" = +(Δ"P"_4"O"_10)/(Δt) = +("1.5 mol/L")/("30 s") = "0.050 mol·L"^"-1""s"^"-1"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">During this reaction, #P_4 + 5O_2 -> P_4O_10#, 1.5 moles of product were made in 30 seconds. What is the rate of reaction? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-kinetics" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Kinetics</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-kinetics/rate-of-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Rate of Reactions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="288507" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-15T22:33:42" itemprop="dateCreated"> Jul 15, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The rate of reaction is the rate of formation of <mathjax>#"P"_4"O"_10#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>For the reaction <mathjax>#"P"_4 +"5O"_2→ "P"_4"O"_10#</mathjax>, the rate of reaction is defined as</p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a) "rate" = -1/1(Δ["P"_4])/(Δt) = -1/5(Δ["O"_2])/(Δt) = +1/1(Δ["P"_4"O"_10])/(Δt)color(white)(a/a)\|)))" "#</mathjax></p> </blockquote> <p>If the volume of the container is 1 L,</p> <p><mathjax>#"rate" = +(Δ"P"_4"O"_10)/(Δt) = +("1.5 mol/L")/("30 s") = "0.050 mol·L"^"-1""s"^"-1"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/288507" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-rate-of-reaction"> How do you calculate rate of reaction? 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</a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-reaction-rate-constant"> What is a reaction rate constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-the-reaction-rates-change-as-the-system-approaches-equilibrium"> How do the reaction rates change as the system approaches equilibrium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-does-the-rate-of-reaction-increase-with-concentration"> Why does the rate of reaction increase with concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-rates-of-reaction-change-with-ph"> Why do rates of reaction change with pH? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-kinetics/rate-of-reactions"> See all questions in Rate of Reactions </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 5524 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	During this reaction, #P_4 + 5O_2 -> P_4O_10#, 1.5 moles of product were made in 30 seconds. What is the rate of reaction?	null
2,073	a86f44c2-6ddd-11ea-8098-ccda262736ce	https://socratic.org/questions/using-the-appropriate-values-of-k-sp-and-k-f-what-is-the-equilibrium-constant-fo	6.50 × 10^9	start physical_unit 16 16 equilibrium_constant_k none qc_end chemical_equation 17 25 qc_end end	[{"type":"physical unit","value":"Equilibrium constant [OF] the reaction"}]	[{"type":"physical unit","value":"6.50 × 10^9"}]	[{"type":"chemical equation","value":"PbCl2(s) + 3 OH^−(aq) <=> Pb(OH)3^−(aq) + 2 Cl^−(aq)"}]	<h1 class="questionTitle" itemprop="name">Using the appropriate values of #K_(sp)# and #K _f#, what is the equilibrium constant for the following reaction: #PbCl_2(s) + 3OH^(-)(aq) rightleftharpoons Pb (OH)_3^(-)(aq) + 2Cl^(-)(aq)# ?</h1>	null	6.50 × 10^9	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The first thing to do here is look up the values of the <strong>solubility product constant</strong>, <mathjax>#K_(sp)#</mathjax>, for lead(II) chloride, <mathjax>#"PbCl"_2#</mathjax>, and the <strong>formation constant</strong>, <mathjax>#K_f#</mathjax>, for the trihydroxoplumbate(II) complex ion, <mathjax>#"Pb"("OH")_3^(-)#</mathjax></p> <blockquote> <p><mathjax>#K_(sp) = 1.70 * 10^(-5)#</mathjax></p> <p><mathjax>#K_f = 3.8 * 10^(14)#</mathjax></p> </blockquote> <p><a href="http://www4.ncsu.edu/~franzen/public_html/CH201/data/Solubility_Product_Constants.pdf" rel="nofollow" target="_blank">http://www4.ncsu.edu/~franzen/public_html/CH201/data/Solubility_Product_Constants.pdf</a></p> <p><a href="http://bilbo.chm.uri.edu/CHM112/tables/Kftable.htm" rel="nofollow" target="_blank">http://bilbo.chm.uri.edu/CHM112/tables/Kftable.htm</a></p> <p>Now, the idea here is that lead(II) chloride is considered <strong>Insoluble</strong> in aqueous solution, which means that a dissociation equilibrium is established when you place this salt in water</p> <blockquote> <p><mathjax>#"PbCl"_ (2(s)) rightleftharpoons "Pb"_ ((aq))^(2+) + 2"Cl"_ ((aq))^(-)#</mathjax></p> </blockquote> <p>As shown by the value of <mathjax>#K_(sp)#</mathjax>, this equilibrium lies to the <em>left</em>, meaning that you will get very small concentrations of lead(II) cations and chloride anions in solution. </p> <p>Now, if you add a <strong>strong base</strong>, which can be symbolized by <mathjax>#"OH"^(-)#</mathjax>, to this solution, a <strong>complexation reaction</strong> will take place</p> <blockquote> <p><mathjax>#"Pb"_ ((aq))^(2+) + 3"OH"_ ((aq))^(-) rightleftharpoons "Pb"("OH")_ (3(aq))^(-)#</mathjax></p> </blockquote> <p>Since <mathjax>#K_f#</mathjax> has such a large value, this equilibrium will lie to the <em>right</em>, meaning that the reaction will proceed in the forward direction</p> <blockquote> <p><mathjax>#"Pb"_ ((aq))^(2+) + 3"OH"_ ((aq))^(-) -> "Pb"("OH")_ (3(aq))^(-)#</mathjax></p> </blockquote> <p>The thing to notice here is that adding hydroxide anions, to the aqueous solution of lead(II) chloride will <strong>consume</strong> the lead(II) cations dissolved in solution. </p> <p>As a result, the dissociation equilibrium for lead(II) chloride will <strong>shift to the right</strong> to compensate for the fact that the concentration of lead(II) cations is decreasing <mathjax>#->#</mathjax> think <strong><a href="https://socratic.org/chemistry/chemical-equilibrium/le-chatelier-s-principle">Le Chatelier's Principle</a></strong> here. </p> <p>This means that you'll have</p> <blockquote> <p><mathjax>#"PbCl"_ (2(s)) -> "Pb"_ ((aq))^(2+) + 2"Cl"_ ((aq))^(-)#</mathjax></p> </blockquote> <p>If you were to <strong>add</strong> these two reactions, you would get</p> <blockquote> <p><mathjax>#{(color(white)(aaaaaaa)"PbCl"_ (2(s)) rightleftharpoons "Pb"_ ((aq))^(2+) + 2"Cl"_ ((aq))^(-)), ("Pb"_ ((aq))^(2+) + 3"OH"_ ((aq))^(-) rightleftharpoons "Pb"("OH")_ (3(aq))^(-)) :}#</mathjax><br/> <mathjax>#color(white)(aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa)/color(white)(a)#</mathjax></p> <p><mathjax>#"PbCl"_ (2(s)) + color(red)(cancel(color(black)("Pb"_ ((aq))^(2+)))) + 3"OH"_ ((aq))^(-) rightleftharpoons "Pb"("OH")_ (3(aq))^(-) + color(red)(cancel(color(black)("Pb"_ ((aq))^(2+)))) + 2"Cl"_ ((aq))^(-)#</mathjax></p> </blockquote> <p>This is equivalent to </p> <blockquote> <p><mathjax>#"PbCl"_ (2(s)) + 3"OH"_ ((aq))^(-) rightleftharpoons "Pb"("OH")_ (3(aq))^(-) + 2"Cl"_ ((aq))^(-)#</mathjax></p> </blockquote> <p>Now, because you're <strong>added</strong> two equilibrium reactions to get your overall equilibrium, you must <strong>multiply</strong> the value of their <a href="https://socratic.org/chemistry/chemical-equilibrium/equilibrium-constants">equilibrium constants</a> to get the equilibrium constant, let's say <mathjax>#K_"eq"#</mathjax>, for this overall equilibrium </p> <blockquote> <p><mathjax>#K_"eq" = K_(sp) * K_f#</mathjax></p> </blockquote> <p>Plug in your values to find</p> <blockquote> <p><mathjax>#K_"eq" = 1.70 * 10^(-5) * 3.8 * 10^(14) = color(green)(\|bar(ul(color(white)(a/a)color(black)(6.5 * 10^9)color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>Once again, the fact the <mathjax>#K_"eq " ">> " 1#</mathjax> tells you that this equilibrium will lie mostly to the <strong>right</strong>, which essentially tells you that you can increase the solubility of lead(II) chloride by increasing the <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> of the solution. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#K_"eq" = 6.5 * 10^9#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The first thing to do here is look up the values of the <strong>solubility product constant</strong>, <mathjax>#K_(sp)#</mathjax>, for lead(II) chloride, <mathjax>#"PbCl"_2#</mathjax>, and the <strong>formation constant</strong>, <mathjax>#K_f#</mathjax>, for the trihydroxoplumbate(II) complex ion, <mathjax>#"Pb"("OH")_3^(-)#</mathjax></p> <blockquote> <p><mathjax>#K_(sp) = 1.70 * 10^(-5)#</mathjax></p> <p><mathjax>#K_f = 3.8 * 10^(14)#</mathjax></p> </blockquote> <p><a href="http://www4.ncsu.edu/~franzen/public_html/CH201/data/Solubility_Product_Constants.pdf" rel="nofollow" target="_blank">http://www4.ncsu.edu/~franzen/public_html/CH201/data/Solubility_Product_Constants.pdf</a></p> <p><a href="http://bilbo.chm.uri.edu/CHM112/tables/Kftable.htm" rel="nofollow" target="_blank">http://bilbo.chm.uri.edu/CHM112/tables/Kftable.htm</a></p> <p>Now, the idea here is that lead(II) chloride is considered <strong>Insoluble</strong> in aqueous solution, which means that a dissociation equilibrium is established when you place this salt in water</p> <blockquote> <p><mathjax>#"PbCl"_ (2(s)) rightleftharpoons "Pb"_ ((aq))^(2+) + 2"Cl"_ ((aq))^(-)#</mathjax></p> </blockquote> <p>As shown by the value of <mathjax>#K_(sp)#</mathjax>, this equilibrium lies to the <em>left</em>, meaning that you will get very small concentrations of lead(II) cations and chloride anions in solution. </p> <p>Now, if you add a <strong>strong base</strong>, which can be symbolized by <mathjax>#"OH"^(-)#</mathjax>, to this solution, a <strong>complexation reaction</strong> will take place</p> <blockquote> <p><mathjax>#"Pb"_ ((aq))^(2+) + 3"OH"_ ((aq))^(-) rightleftharpoons "Pb"("OH")_ (3(aq))^(-)#</mathjax></p> </blockquote> <p>Since <mathjax>#K_f#</mathjax> has such a large value, this equilibrium will lie to the <em>right</em>, meaning that the reaction will proceed in the forward direction</p> <blockquote> <p><mathjax>#"Pb"_ ((aq))^(2+) + 3"OH"_ ((aq))^(-) -> "Pb"("OH")_ (3(aq))^(-)#</mathjax></p> </blockquote> <p>The thing to notice here is that adding hydroxide anions, to the aqueous solution of lead(II) chloride will <strong>consume</strong> the lead(II) cations dissolved in solution. </p> <p>As a result, the dissociation equilibrium for lead(II) chloride will <strong>shift to the right</strong> to compensate for the fact that the concentration of lead(II) cations is decreasing <mathjax>#->#</mathjax> think <strong><a href="https://socratic.org/chemistry/chemical-equilibrium/le-chatelier-s-principle">Le Chatelier's Principle</a></strong> here. </p> <p>This means that you'll have</p> <blockquote> <p><mathjax>#"PbCl"_ (2(s)) -> "Pb"_ ((aq))^(2+) + 2"Cl"_ ((aq))^(-)#</mathjax></p> </blockquote> <p>If you were to <strong>add</strong> these two reactions, you would get</p> <blockquote> <p><mathjax>#{(color(white)(aaaaaaa)"PbCl"_ (2(s)) rightleftharpoons "Pb"_ ((aq))^(2+) + 2"Cl"_ ((aq))^(-)), ("Pb"_ ((aq))^(2+) + 3"OH"_ ((aq))^(-) rightleftharpoons "Pb"("OH")_ (3(aq))^(-)) :}#</mathjax><br/> <mathjax>#color(white)(aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa)/color(white)(a)#</mathjax></p> <p><mathjax>#"PbCl"_ (2(s)) + color(red)(cancel(color(black)("Pb"_ ((aq))^(2+)))) + 3"OH"_ ((aq))^(-) rightleftharpoons "Pb"("OH")_ (3(aq))^(-) + color(red)(cancel(color(black)("Pb"_ ((aq))^(2+)))) + 2"Cl"_ ((aq))^(-)#</mathjax></p> </blockquote> <p>This is equivalent to </p> <blockquote> <p><mathjax>#"PbCl"_ (2(s)) + 3"OH"_ ((aq))^(-) rightleftharpoons "Pb"("OH")_ (3(aq))^(-) + 2"Cl"_ ((aq))^(-)#</mathjax></p> </blockquote> <p>Now, because you're <strong>added</strong> two equilibrium reactions to get your overall equilibrium, you must <strong>multiply</strong> the value of their <a href="https://socratic.org/chemistry/chemical-equilibrium/equilibrium-constants">equilibrium constants</a> to get the equilibrium constant, let's say <mathjax>#K_"eq"#</mathjax>, for this overall equilibrium </p> <blockquote> <p><mathjax>#K_"eq" = K_(sp) * K_f#</mathjax></p> </blockquote> <p>Plug in your values to find</p> <blockquote> <p><mathjax>#K_"eq" = 1.70 * 10^(-5) * 3.8 * 10^(14) = color(green)(\|bar(ul(color(white)(a/a)color(black)(6.5 * 10^9)color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>Once again, the fact the <mathjax>#K_"eq " ">> " 1#</mathjax> tells you that this equilibrium will lie mostly to the <strong>right</strong>, which essentially tells you that you can increase the solubility of lead(II) chloride by increasing the <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> of the solution. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Using the appropriate values of #K_(sp)# and #K _f#, what is the equilibrium constant for the following reaction: #PbCl_2(s) + 3OH^(-)(aq) rightleftharpoons Pb (OH)_3^(-)(aq) + 2Cl^(-)(aq)# ?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-equilibrium" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Equilibrium</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-equilibrium/equilibrium-constants" itemprop="url"> <span class="breadcrumb" itemprop="title">Equilibrium Constants</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="297762" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-08-11T12:46:16" itemprop="dateCreated"> Aug 11, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#K_"eq" = 6.5 * 10^9#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The first thing to do here is look up the values of the <strong>solubility product constant</strong>, <mathjax>#K_(sp)#</mathjax>, for lead(II) chloride, <mathjax>#"PbCl"_2#</mathjax>, and the <strong>formation constant</strong>, <mathjax>#K_f#</mathjax>, for the trihydroxoplumbate(II) complex ion, <mathjax>#"Pb"("OH")_3^(-)#</mathjax></p> <blockquote> <p><mathjax>#K_(sp) = 1.70 * 10^(-5)#</mathjax></p> <p><mathjax>#K_f = 3.8 * 10^(14)#</mathjax></p> </blockquote> <p><a href="http://www4.ncsu.edu/~franzen/public_html/CH201/data/Solubility_Product_Constants.pdf" rel="nofollow" target="_blank">http://www4.ncsu.edu/~franzen/public_html/CH201/data/Solubility_Product_Constants.pdf</a></p> <p><a href="http://bilbo.chm.uri.edu/CHM112/tables/Kftable.htm" rel="nofollow" target="_blank">http://bilbo.chm.uri.edu/CHM112/tables/Kftable.htm</a></p> <p>Now, the idea here is that lead(II) chloride is considered <strong>Insoluble</strong> in aqueous solution, which means that a dissociation equilibrium is established when you place this salt in water</p> <blockquote> <p><mathjax>#"PbCl"_ (2(s)) rightleftharpoons "Pb"_ ((aq))^(2+) + 2"Cl"_ ((aq))^(-)#</mathjax></p> </blockquote> <p>As shown by the value of <mathjax>#K_(sp)#</mathjax>, this equilibrium lies to the <em>left</em>, meaning that you will get very small concentrations of lead(II) cations and chloride anions in solution. </p> <p>Now, if you add a <strong>strong base</strong>, which can be symbolized by <mathjax>#"OH"^(-)#</mathjax>, to this solution, a <strong>complexation reaction</strong> will take place</p> <blockquote> <p><mathjax>#"Pb"_ ((aq))^(2+) + 3"OH"_ ((aq))^(-) rightleftharpoons "Pb"("OH")_ (3(aq))^(-)#</mathjax></p> </blockquote> <p>Since <mathjax>#K_f#</mathjax> has such a large value, this equilibrium will lie to the <em>right</em>, meaning that the reaction will proceed in the forward direction</p> <blockquote> <p><mathjax>#"Pb"_ ((aq))^(2+) + 3"OH"_ ((aq))^(-) -> "Pb"("OH")_ (3(aq))^(-)#</mathjax></p> </blockquote> <p>The thing to notice here is that adding hydroxide anions, to the aqueous solution of lead(II) chloride will <strong>consume</strong> the lead(II) cations dissolved in solution. </p> <p>As a result, the dissociation equilibrium for lead(II) chloride will <strong>shift to the right</strong> to compensate for the fact that the concentration of lead(II) cations is decreasing <mathjax>#->#</mathjax> think <strong><a href="https://socratic.org/chemistry/chemical-equilibrium/le-chatelier-s-principle">Le Chatelier's Principle</a></strong> here. </p> <p>This means that you'll have</p> <blockquote> <p><mathjax>#"PbCl"_ (2(s)) -> "Pb"_ ((aq))^(2+) + 2"Cl"_ ((aq))^(-)#</mathjax></p> </blockquote> <p>If you were to <strong>add</strong> these two reactions, you would get</p> <blockquote> <p><mathjax>#{(color(white)(aaaaaaa)"PbCl"_ (2(s)) rightleftharpoons "Pb"_ ((aq))^(2+) + 2"Cl"_ ((aq))^(-)), ("Pb"_ ((aq))^(2+) + 3"OH"_ ((aq))^(-) rightleftharpoons "Pb"("OH")_ (3(aq))^(-)) :}#</mathjax><br/> <mathjax>#color(white)(aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa)/color(white)(a)#</mathjax></p> <p><mathjax>#"PbCl"_ (2(s)) + color(red)(cancel(color(black)("Pb"_ ((aq))^(2+)))) + 3"OH"_ ((aq))^(-) rightleftharpoons "Pb"("OH")_ (3(aq))^(-) + color(red)(cancel(color(black)("Pb"_ ((aq))^(2+)))) + 2"Cl"_ ((aq))^(-)#</mathjax></p> </blockquote> <p>This is equivalent to </p> <blockquote> <p><mathjax>#"PbCl"_ (2(s)) + 3"OH"_ ((aq))^(-) rightleftharpoons "Pb"("OH")_ (3(aq))^(-) + 2"Cl"_ ((aq))^(-)#</mathjax></p> </blockquote> <p>Now, because you're <strong>added</strong> two equilibrium reactions to get your overall equilibrium, you must <strong>multiply</strong> the value of their <a href="https://socratic.org/chemistry/chemical-equilibrium/equilibrium-constants">equilibrium constants</a> to get the equilibrium constant, let's say <mathjax>#K_"eq"#</mathjax>, for this overall equilibrium </p> <blockquote> <p><mathjax>#K_"eq" = K_(sp) * K_f#</mathjax></p> </blockquote> <p>Plug in your values to find</p> <blockquote> <p><mathjax>#K_"eq" = 1.70 * 10^(-5) * 3.8 * 10^(14) = color(green)(\|bar(ul(color(white)(a/a)color(black)(6.5 * 10^9)color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>Once again, the fact the <mathjax>#K_"eq " ">> " 1#</mathjax> tells you that this equilibrium will lie mostly to the <strong>right</strong>, which essentially tells you that you can increase the solubility of lead(II) chloride by increasing the <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> of the solution. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/297762" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-equilibrium-constant-change-with-temperature"> How does the equilibrium constant change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-equilibrium-constant-for-a-reverse-reaction"> How do you find equilibrium 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2,074	ad081662-6ddd-11ea-8727-ccda262736ce	https://socratic.org/questions/what-is-the-molecular-formula-for-the-compound-that-is-made-up-of-30-45-g-n-and-	N2O4	start chemical_formula qc_end physical_unit 15 15 13 14 mass qc_end physical_unit 19 19 17 18 mass qc_end physical_unit 6 7 26 27 molecular_weight qc_end end	[{"type":"other","value":"Chemical Formula [OF] the compound [IN] molecular"}]	[{"type":"chemical equation","value":"N2O4"}]	[{"type":"physical unit","value":"Mass [OF] N [=] \\pu{30.45 g}"},{"type":"physical unit","value":"Mass [OF] O [=] \\pu{69.55 g}"},{"type":"physical unit","value":"Formula mass [OF] the compound [=] \\pu{92.02 amu}"}]	<h1 class="questionTitle" itemprop="name">What is the molecular formula for the compound that is made up of 30.45 g N and 69.55 g O, and has a formula mass of 92.02 amu? </h1>	null	N2O4	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Moles of nitrogen </p> <blockquote> <p><mathjax>#"n"_"N" = "30.45 g"/"14 g/mol" = "2.175 mol"#</mathjax></p> </blockquote> <p>Moles of oxygen </p> <blockquote> <p><mathjax>#"n"_"O" = "69.55 g"/"16 g/mol" = "4.347 mol"#</mathjax></p> </blockquote> <p>Ratio of moles of nitrogen and oxygen</p> <p><mathjax>#"n"_"N"/"n"_"O" = "2.175 mol"/"4.347 mol" ≈ 1/2#</mathjax></p> <p>∴ Emperical formula <mathjax>#"= NO"_2#</mathjax></p> <p><mathjax>#"Molecular formula mass"/"Emperical formula mass" = "92.02 amu"/"46.0 amu" ≈ 2#</mathjax></p> <p>∴ Molecular formula <mathjax>#= 2 × "NO"_2 = color(Green)("N"_2"O"_4)#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"N"_2"O"_4#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Moles of nitrogen </p> <blockquote> <p><mathjax>#"n"_"N" = "30.45 g"/"14 g/mol" = "2.175 mol"#</mathjax></p> </blockquote> <p>Moles of oxygen </p> <blockquote> <p><mathjax>#"n"_"O" = "69.55 g"/"16 g/mol" = "4.347 mol"#</mathjax></p> </blockquote> <p>Ratio of moles of nitrogen and oxygen</p> <p><mathjax>#"n"_"N"/"n"_"O" = "2.175 mol"/"4.347 mol" ≈ 1/2#</mathjax></p> <p>∴ Emperical formula <mathjax>#"= NO"_2#</mathjax></p> <p><mathjax>#"Molecular formula mass"/"Emperical formula mass" = "92.02 amu"/"46.0 amu" ≈ 2#</mathjax></p> <p>∴ Molecular formula <mathjax>#= 2 × "NO"_2 = color(Green)("N"_2"O"_4)#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the molecular formula for the compound that is made up of 30.45 g N and 69.55 g O, and has a formula mass of 92.02 amu? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="594665" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/junaid-mirza"><img alt="" class="" src="https://profilepictures.socratic.org/BBeNx7NTQ7WmDQKll8wN_BDC9EDF4-5DCB-440D-8ADC-ADACE2966216.jpeg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/junaid-mirza"> Junaid Mirza </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-04-14T10:43:58" itemprop="dateCreated"> Apr 14, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"N"_2"O"_4#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Moles of nitrogen </p> <blockquote> <p><mathjax>#"n"_"N" = "30.45 g"/"14 g/mol" = "2.175 mol"#</mathjax></p> </blockquote> <p>Moles of oxygen </p> <blockquote> <p><mathjax>#"n"_"O" = "69.55 g"/"16 g/mol" = "4.347 mol"#</mathjax></p> </blockquote> <p>Ratio of moles of nitrogen and oxygen</p> <p><mathjax>#"n"_"N"/"n"_"O" = "2.175 mol"/"4.347 mol" ≈ 1/2#</mathjax></p> <p>∴ Emperical formula <mathjax>#"= NO"_2#</mathjax></p> <p><mathjax>#"Molecular formula mass"/"Emperical formula mass" = "92.02 amu"/"46.0 amu" ≈ 2#</mathjax></p> <p>∴ Molecular formula <mathjax>#= 2 × "NO"_2 = color(Green)("N"_2"O"_4)#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/594665" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? 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2,075	ace33b4a-6ddd-11ea-837f-ccda262736ce	https://socratic.org/questions/nitrogen-and-oxygen-extensive-series-of-oxides-with-the-general-formula-n-xo-x-o	N2O3	start chemical_formula qc_end c_other OTHER qc_end c_other OTHER qc_end end	[{"type":"other","value":"Chemical Formula [OF] this oxide [IN] empirical"}]	[{"type":"chemical equation","value":"N2O3"}]	[{"type":"other","value":"Nitrogen and oxygen extensive series of oxides with the general formula NxOx."},{"type":"other","value":"One of them is a blue solid that comes apart, reversibly, in the gas phase."},{"type":"physical unit","value":"Percent [OF] N in this oxide [=] \\pu{36.84%}"}]	<h1 class="questionTitle" itemprop="name">Nitrogen and oxygen extensive series of oxides with the general formula #N_xO_x#. One of them is a blue solid that comes apart, reversibly, in the gas phase. It contains 36.84% N. What is the empirical formula of this oxide?</h1>	null	N2O3	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Work out the number of moles in <mathjax>#100.00#</mathjax> grams of the oxide.</p> <p>For nitrogen: The <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">atomic mass</a> of <mathjax>#"N"#</mathjax> is <mathjax>#14.0067#</mathjax>, and we have <mathjax>#36.84" g N"#</mathjax>:</p> <p><mathjax>#(36.84" g N")/(14.0067" g N/mol N") = 2.630" mol N"#</mathjax></p> <p>For oxygen: The atomic mass of <mathjax>#"O"#</mathjax> is <mathjax>#15.9994#</mathjax>, and we have <mathjax>#100.00-36.84=63.16" g O"#</mathjax>:</p> <p><mathjax>#(63.16" g N")/(15.9994" g N/mol N") = 3.948" mol N"#</mathjax></p> <p>Now the ratio <mathjax>#3.958/2.630#</mathjax> is very close to <mathjax>#1.5=3/2#</mathjax>. So we conclude that the gas has three moles <mathjax>#"O"#</mathjax> to two moles <mathjax>#"N"#</mathjax> making the empirical formula <mathjax>#color(blue)("N"_2"O"_3)#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"N"_2"O"_3#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Work out the number of moles in <mathjax>#100.00#</mathjax> grams of the oxide.</p> <p>For nitrogen: The <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">atomic mass</a> of <mathjax>#"N"#</mathjax> is <mathjax>#14.0067#</mathjax>, and we have <mathjax>#36.84" g N"#</mathjax>:</p> <p><mathjax>#(36.84" g N")/(14.0067" g N/mol N") = 2.630" mol N"#</mathjax></p> <p>For oxygen: The atomic mass of <mathjax>#"O"#</mathjax> is <mathjax>#15.9994#</mathjax>, and we have <mathjax>#100.00-36.84=63.16" g O"#</mathjax>:</p> <p><mathjax>#(63.16" g N")/(15.9994" g N/mol N") = 3.948" mol N"#</mathjax></p> <p>Now the ratio <mathjax>#3.958/2.630#</mathjax> is very close to <mathjax>#1.5=3/2#</mathjax>. So we conclude that the gas has three moles <mathjax>#"O"#</mathjax> to two moles <mathjax>#"N"#</mathjax> making the empirical formula <mathjax>#color(blue)("N"_2"O"_3)#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Nitrogen and oxygen extensive series of oxides with the general formula #N_xO_x#. One of them is a blue solid that comes apart, reversibly, in the gas phase. It contains 36.84% N. What is the empirical formula of this oxide?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#electrochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Electrochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/electrochemistry/oxidation-and-reduction-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Oxidation and Reduction Reactions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="346352" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/olthe3rd"><img alt="" class="" src="https://profilepictures.socratic.org/ooIp4P3ES4imZU7Cwexy_Squirrel.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/olthe3rd"> Oscar L. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-12-04T03:05:52" itemprop="dateCreated"> Dec 4, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"N"_2"O"_3#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Work out the number of moles in <mathjax>#100.00#</mathjax> grams of the oxide.</p> <p>For nitrogen: The <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">atomic mass</a> of <mathjax>#"N"#</mathjax> is <mathjax>#14.0067#</mathjax>, and we have <mathjax>#36.84" g N"#</mathjax>:</p> <p><mathjax>#(36.84" g N")/(14.0067" g N/mol N") = 2.630" mol N"#</mathjax></p> <p>For oxygen: The atomic mass of <mathjax>#"O"#</mathjax> is <mathjax>#15.9994#</mathjax>, and we have <mathjax>#100.00-36.84=63.16" g O"#</mathjax>:</p> <p><mathjax>#(63.16" g N")/(15.9994" g N/mol N") = 3.948" mol N"#</mathjax></p> <p>Now the ratio <mathjax>#3.958/2.630#</mathjax> is very close to <mathjax>#1.5=3/2#</mathjax>. So we conclude that the gas has three moles <mathjax>#"O"#</mathjax> to two moles <mathjax>#"N"#</mathjax> making the empirical formula <mathjax>#color(blue)("N"_2"O"_3)#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/346352" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-balance-equations-with-charges"> How to balance equations for reduction/oxidation reaction? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-an-electode-reaction-has-dssolved-oxygen-as-a-reactant-is-the-electrode-an-an"> If an electode reaction has dssolved oxygen as a reactant, is the electrode an anode or a cathode? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-an-electrode-reaction-has-dissolved-oxygen-as-a-reactant-is-the-electrode-and"> If an electrode reaction has dissolved oxygen as a reactant, is the electrode and anode or a cathode? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-balanced-equation-represents-a-redox-reaction-2"> What balanced equation represents a redox reaction? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-redox-reactions-involved-in-electrolysis"> How are redox reactions involved in electrolysis? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-oxidation-reduction-reactions-coupled"> Why are oxidation reduction reactions coupled? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-do-oxidation-reduction-reactions-involve"> What do oxidation reduction reactions involve? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-reduction-reactions-used-for"> What are reduction reactions used for? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-calx-mean-in-oxidation-reduction-reactions"> What does "calx" mean in oxidation reduction reactions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-the-reduced-components-in-this-reaction-zn-2h-zn-2-h2"> What are the reduced components in this reaction? Zn + 2H(+) → Zn(2+) + H2 </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/electrochemistry/oxidation-and-reduction-reactions"> See all questions in Oxidation and Reduction Reactions </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 21490 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Nitrogen and oxygen extensive series of oxides with the general formula #N_xO_x#. One of them is a blue solid that comes apart, reversibly, in the gas phase. It contains 36.84% N. What is the empirical formula of this oxide?	null
2,076	a8ce1711-6ddd-11ea-89d2-ccda262736ce	https://socratic.org/questions/what-volume-of-3-05-m-hcl-aq-will-react-with-25-0-g-zn-s-in-the-reaction-zn-s-2h	251 mL	start physical_unit 5 5 volume ml qc_end chemical_equation 15 22 qc_end physical_unit 11 11 9 10 mass qc_end physical_unit 5 5 3 4 molarity qc_end end	[{"type":"physical unit","value":"Volume [OF] HCl(aq) [IN] mL"}]	[{"type":"physical unit","value":"251 mL"}]	[{"type":"chemical equation","value":"Zn(s) + 2 HCl(aq) -> ZnCl2(aq) + H2(g)"},{"type":"physical unit","value":"Mass [OF] Zn(s) [=] \\pu{25.0 g}"},{"type":"physical unit","value":"Molarity [OF] HCl(aq) [=] \\pu{3.05 M}"}]	<h1 class="questionTitle" itemprop="name">What volume of 3.05 M #HCl(aq)# will react with 25.0 g #Zn(s)# in the reaction #Zn(s) + 2HCl(aq) -> ZnCl_2(aq) + H_2(g)#?</h1>	null	251 mL	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Start by writing down the balanced chemical equation that describes this <strong><a href="https://socratic.org/chemistry/chemical-reactions/single-replacement-reactions">single replacement reaction</a></strong></p> <blockquote> <p><mathjax>#"Zn"_ ((s)) + color(red)(2)"HCl"_ ((aq)) -> "ZnCl"_ (2(aq)) + "H"_(2(g)) uarr#</mathjax></p> </blockquote> <p>Now, notice that the two reactants react in a <mathjax>#1:color(red)(2)#</mathjax> <strong><a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a></strong>. This tells you that the reaction will <strong>always</strong> consume <strong>twice as many moles</strong> of hydrochloric acid than moles of zinc metal. </p> <p>As you know, a solution's <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></strong> tells you how many <em>moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a></em>, which in your case will be hydrochloric acid, <mathjax>#"HCl"#</mathjax>, are present <strong>per liter</strong> of solution. </p> <p>The hydrochloric acid solution is said to have a <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of <mathjax>#"3.05 mol L"^(-1)#</mathjax>. This means that you get <mathjax>#3.05#</mathjax> <strong>moles</strong> of hydrochloric acid <strong>for every</strong> <mathjax>#"1 L"#</mathjax> of solution. Keep this in mind for later. </p> <p>You know that the reaction must consume <mathjax>#"25.0 g"#</mathjax> of zinc metal. You can convert this mass to <em>moles</em> by using zinc's <strong>molar mass</strong></p> <blockquote> <p><mathjax>#25.0 color(red)(cancel(color(black)("g"))) * "1 mole Zn"/(65.38color(red)(cancel(color(black)("g")))) = "0.3824 moles Zn"#</mathjax></p> </blockquote> <p>In order for this many moles of zinc to react, you'd need </p> <blockquote> <p><mathjax>#0.3824 color(red)(cancel(color(black)("moles Zn"))) * (color(red)(2)color(white)(a)"moles HCl")/(1color(red)(cancel(color(black)("mole Zn")))) = "0.7648 moles HCl"#</mathjax></p> </blockquote> <p>Since you know that <mathjax>#"1 L"#</mathjax> of your hydrochloric acid solution contains <mathjax>#3.05#</mathjax> <strong>moles</strong> of hydrochloric acid, ti follows that this many moles would be present in </p> <blockquote> <p><mathjax>#0.7648 color(red)(cancel(color(black)("moles HCl"))) * overbrace("1 L solution"/(3.05 color(red)(cancel(color(black)("moles HCl")))))^(color(purple)(" a molarity of 3.05 mol L"^(-1))) = "0.2508 L solution"#</mathjax> </p> </blockquote> <p>Rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong> and expressed in <em>milliliters</em>, the answer will be </p> <blockquote> <p><mathjax>#"volume of HCl solution" = color(green)(\|bar(ul(color(white)(a/a)"251 mL"color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>Note that you have </p> <blockquote> <p><mathjax>#"1 L" = 10^3"mL"#</mathjax></p> </blockquote> <p><strong>SIDE NOTE</strong> <em>The hydrogen gas produced by the reaction will <strong>bubble out of solution</strong></em>.</p> <p><img alt="http://fphoto.photoshelter.com/image/I0000fVD0.349GYs" src="https://useruploads.socratic.org/6tkHa9ZrReKOUL1aPYTG_Fphoto-45499810C-2RM.jpg"/> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"251 mL"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Start by writing down the balanced chemical equation that describes this <strong><a href="https://socratic.org/chemistry/chemical-reactions/single-replacement-reactions">single replacement reaction</a></strong></p> <blockquote> <p><mathjax>#"Zn"_ ((s)) + color(red)(2)"HCl"_ ((aq)) -> "ZnCl"_ (2(aq)) + "H"_(2(g)) uarr#</mathjax></p> </blockquote> <p>Now, notice that the two reactants react in a <mathjax>#1:color(red)(2)#</mathjax> <strong><a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a></strong>. This tells you that the reaction will <strong>always</strong> consume <strong>twice as many moles</strong> of hydrochloric acid than moles of zinc metal. </p> <p>As you know, a solution's <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></strong> tells you how many <em>moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a></em>, which in your case will be hydrochloric acid, <mathjax>#"HCl"#</mathjax>, are present <strong>per liter</strong> of solution. </p> <p>The hydrochloric acid solution is said to have a <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of <mathjax>#"3.05 mol L"^(-1)#</mathjax>. This means that you get <mathjax>#3.05#</mathjax> <strong>moles</strong> of hydrochloric acid <strong>for every</strong> <mathjax>#"1 L"#</mathjax> of solution. Keep this in mind for later. </p> <p>You know that the reaction must consume <mathjax>#"25.0 g"#</mathjax> of zinc metal. You can convert this mass to <em>moles</em> by using zinc's <strong>molar mass</strong></p> <blockquote> <p><mathjax>#25.0 color(red)(cancel(color(black)("g"))) * "1 mole Zn"/(65.38color(red)(cancel(color(black)("g")))) = "0.3824 moles Zn"#</mathjax></p> </blockquote> <p>In order for this many moles of zinc to react, you'd need </p> <blockquote> <p><mathjax>#0.3824 color(red)(cancel(color(black)("moles Zn"))) * (color(red)(2)color(white)(a)"moles HCl")/(1color(red)(cancel(color(black)("mole Zn")))) = "0.7648 moles HCl"#</mathjax></p> </blockquote> <p>Since you know that <mathjax>#"1 L"#</mathjax> of your hydrochloric acid solution contains <mathjax>#3.05#</mathjax> <strong>moles</strong> of hydrochloric acid, ti follows that this many moles would be present in </p> <blockquote> <p><mathjax>#0.7648 color(red)(cancel(color(black)("moles HCl"))) * overbrace("1 L solution"/(3.05 color(red)(cancel(color(black)("moles HCl")))))^(color(purple)(" a molarity of 3.05 mol L"^(-1))) = "0.2508 L solution"#</mathjax> </p> </blockquote> <p>Rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong> and expressed in <em>milliliters</em>, the answer will be </p> <blockquote> <p><mathjax>#"volume of HCl solution" = color(green)(\|bar(ul(color(white)(a/a)"251 mL"color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>Note that you have </p> <blockquote> <p><mathjax>#"1 L" = 10^3"mL"#</mathjax></p> </blockquote> <p><strong>SIDE NOTE</strong> <em>The hydrogen gas produced by the reaction will <strong>bubble out of solution</strong></em>.</p> <p><img alt="http://fphoto.photoshelter.com/image/I0000fVD0.349GYs" src="https://useruploads.socratic.org/6tkHa9ZrReKOUL1aPYTG_Fphoto-45499810C-2RM.jpg"/> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What volume of 3.05 M #HCl(aq)# will react with 25.0 g #Zn(s)# in the reaction #Zn(s) + 2HCl(aq) -> ZnCl_2(aq) + H_2(g)#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="257784" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-04-23T12:34:17" itemprop="dateCreated"> Apr 23, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"251 mL"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Start by writing down the balanced chemical equation that describes this <strong><a href="https://socratic.org/chemistry/chemical-reactions/single-replacement-reactions">single replacement reaction</a></strong></p> <blockquote> <p><mathjax>#"Zn"_ ((s)) + color(red)(2)"HCl"_ ((aq)) -> "ZnCl"_ (2(aq)) + "H"_(2(g)) uarr#</mathjax></p> </blockquote> <p>Now, notice that the two reactants react in a <mathjax>#1:color(red)(2)#</mathjax> <strong><a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a></strong>. This tells you that the reaction will <strong>always</strong> consume <strong>twice as many moles</strong> of hydrochloric acid than moles of zinc metal. </p> <p>As you know, a solution's <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></strong> tells you how many <em>moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a></em>, which in your case will be hydrochloric acid, <mathjax>#"HCl"#</mathjax>, are present <strong>per liter</strong> of solution. </p> <p>The hydrochloric acid solution is said to have a <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of <mathjax>#"3.05 mol L"^(-1)#</mathjax>. This means that you get <mathjax>#3.05#</mathjax> <strong>moles</strong> of hydrochloric acid <strong>for every</strong> <mathjax>#"1 L"#</mathjax> of solution. Keep this in mind for later. </p> <p>You know that the reaction must consume <mathjax>#"25.0 g"#</mathjax> of zinc metal. You can convert this mass to <em>moles</em> by using zinc's <strong>molar mass</strong></p> <blockquote> <p><mathjax>#25.0 color(red)(cancel(color(black)("g"))) * "1 mole Zn"/(65.38color(red)(cancel(color(black)("g")))) = "0.3824 moles Zn"#</mathjax></p> </blockquote> <p>In order for this many moles of zinc to react, you'd need </p> <blockquote> <p><mathjax>#0.3824 color(red)(cancel(color(black)("moles Zn"))) * (color(red)(2)color(white)(a)"moles HCl")/(1color(red)(cancel(color(black)("mole Zn")))) = "0.7648 moles HCl"#</mathjax></p> </blockquote> <p>Since you know that <mathjax>#"1 L"#</mathjax> of your hydrochloric acid solution contains <mathjax>#3.05#</mathjax> <strong>moles</strong> of hydrochloric acid, ti follows that this many moles would be present in </p> <blockquote> <p><mathjax>#0.7648 color(red)(cancel(color(black)("moles HCl"))) * overbrace("1 L solution"/(3.05 color(red)(cancel(color(black)("moles HCl")))))^(color(purple)(" a molarity of 3.05 mol L"^(-1))) = "0.2508 L solution"#</mathjax> </p> </blockquote> <p>Rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong> and expressed in <em>milliliters</em>, the answer will be </p> <blockquote> <p><mathjax>#"volume of HCl solution" = color(green)(\|bar(ul(color(white)(a/a)"251 mL"color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>Note that you have </p> <blockquote> <p><mathjax>#"1 L" = 10^3"mL"#</mathjax></p> </blockquote> <p><strong>SIDE NOTE</strong> <em>The hydrogen gas produced by the reaction will <strong>bubble out of solution</strong></em>.</p> <p><img alt="http://fphoto.photoshelter.com/image/I0000fVD0.349GYs" src="https://useruploads.socratic.org/6tkHa9ZrReKOUL1aPYTG_Fphoto-45499810C-2RM.jpg"/> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/257784" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What is stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ab82402bf342f48d93ac6"> Question #93ac6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-we-study-stoichiometry"> Why do we study stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-naoh-is-produced-from-1-20-x-102-grams-of-na2o-na2o-h2o-2-naoh"> How many grams of NaOH is produced from #1.20 x 10^2# grams of #Na_2O#? #Na_2O + H_2O -> 2NaOH# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-na2o-are-required-to-produce-1-60-x-102-grams-of-naoh-na2o-h2o"> How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? 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2,077	abd30d83-6ddd-11ea-850a-ccda262736ce	https://socratic.org/questions/a-solution-of-formic-acid-has-a-ph-of-2-70-calculate-the-initial-concentration-o	2.41 × 10^(-2) M	start physical_unit 3 4 concentration mol/l qc_end physical_unit 1 1 9 9 ph qc_end physical_unit 3 4 19 21 ka qc_end end	[{"type":"physical unit","value":"Concentration [OF] formic acid solution [IN] M"}]	[{"type":"physical unit","value":"2.41 × 10^(-2) M"}]	[{"type":"physical unit","value":"pH [OF] formic acid solution [=] \\pu{2.70}"},{"type":"physical unit","value":"Ka [OF] formic acid [=] \\pu{1.8 × 10^(-4)}"}]	<h1 class="questionTitle" itemprop="name">A solution of formic acid has a pH of 2.70, calculate the initial concentration of formic acid?</h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p><mathjax>#K_a=1.8xx10^-4#</mathjax> for formic acid</p> <hr/> <h2>My work:</h2> <p><img alt="webcam" src="https://useruploads.socratic.org/1m4HvQEQECoo0WHQnLHk_WIN_20180720_00_56_58_Pro.jpg"/> </p></div> </h2> </div> </div>	2.41 × 10^(-2) M	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We address the equilibrium...</p> <p><mathjax>#HC(=O)OH(aq)+H_2O(l)rightleftharpoonsHCO_2^(-) + H_3O^+#</mathjax></p> <p>And at equilibrium...<mathjax>#K_a=([HCO_2^(-)][H_3O^+])/([HC(=O)OH(aq)])=1.80xx10^-4#</mathjax></p> <p>But <mathjax>#pH=-log_10[H_3O^+]=2.70#</mathjax>...</p> <p>And so <mathjax>#[H_3O^+]=[HCO_2^-]=10^(-2.70)molL^-1=#</mathjax></p> <p>And so AT EQUILIBRIUM...<mathjax>#1.80xx10^-4=({10^(-2.70)}^2)/([HC(=O)OH(aq)])#</mathjax></p> <p><mathjax>#[HC(=O)OH(aq)]_"at equilibrium"=({10^(-2.70)}^2)/(1.80xx10^-4)#</mathjax></p> <p><mathjax>#-=0.0221molL^-1#</mathjax>...but this is the equilibrium value....and <mathjax>#[H_3O^+]=1.995xx10^-3molL^-1#</mathjax> by definition...</p> <p>And since the hydronium ion is PRESUMED to derive from the formic acid...<mathjax>#[HC(=O)OH]_"initially"=(0.0221+1.995 xx 10^(-3))molL^-1=0.0241molL^-1#</mathjax>...the degree of dissociation was miniscule....</p> <p>Pleas check my 'rithmetik...</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#underbrace([HC(=O)OH]=0.0241molL^-1)_"INITIALLY"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We address the equilibrium...</p> <p><mathjax>#HC(=O)OH(aq)+H_2O(l)rightleftharpoonsHCO_2^(-) + H_3O^+#</mathjax></p> <p>And at equilibrium...<mathjax>#K_a=([HCO_2^(-)][H_3O^+])/([HC(=O)OH(aq)])=1.80xx10^-4#</mathjax></p> <p>But <mathjax>#pH=-log_10[H_3O^+]=2.70#</mathjax>...</p> <p>And so <mathjax>#[H_3O^+]=[HCO_2^-]=10^(-2.70)molL^-1=#</mathjax></p> <p>And so AT EQUILIBRIUM...<mathjax>#1.80xx10^-4=({10^(-2.70)}^2)/([HC(=O)OH(aq)])#</mathjax></p> <p><mathjax>#[HC(=O)OH(aq)]_"at equilibrium"=({10^(-2.70)}^2)/(1.80xx10^-4)#</mathjax></p> <p><mathjax>#-=0.0221molL^-1#</mathjax>...but this is the equilibrium value....and <mathjax>#[H_3O^+]=1.995xx10^-3molL^-1#</mathjax> by definition...</p> <p>And since the hydronium ion is PRESUMED to derive from the formic acid...<mathjax>#[HC(=O)OH]_"initially"=(0.0221+1.995 xx 10^(-3))molL^-1=0.0241molL^-1#</mathjax>...the degree of dissociation was miniscule....</p> <p>Pleas check my 'rithmetik...</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A solution of formic acid has a pH of 2.70, calculate the initial concentration of formic acid?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p><mathjax>#K_a=1.8xx10^-4#</mathjax> for formic acid</p> <hr/> <h2>My work:</h2> <p><img alt="webcam" src="https://useruploads.socratic.org/1m4HvQEQECoo0WHQnLHk_WIN_20180720_00_56_58_Pro.jpg"/> </p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/ph-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">pH calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="642227" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> <a class="secondContributorPic" href="/users/truong-son-n"><img alt="" class="" src="https://profilepictures.socratic.org/07k4plnQfmnmzMuesQzw_14844-1449381920.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a>·<a class="topContributorLink" href="/users/truong-son-n"> Truong-Son N. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-07-20T19:14:21" itemprop="dateCreated"> Jul 20, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#underbrace([HC(=O)OH]=0.0241molL^-1)_"INITIALLY"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We address the equilibrium...</p> <p><mathjax>#HC(=O)OH(aq)+H_2O(l)rightleftharpoonsHCO_2^(-) + H_3O^+#</mathjax></p> <p>And at equilibrium...<mathjax>#K_a=([HCO_2^(-)][H_3O^+])/([HC(=O)OH(aq)])=1.80xx10^-4#</mathjax></p> <p>But <mathjax>#pH=-log_10[H_3O^+]=2.70#</mathjax>...</p> <p>And so <mathjax>#[H_3O^+]=[HCO_2^-]=10^(-2.70)molL^-1=#</mathjax></p> <p>And so AT EQUILIBRIUM...<mathjax>#1.80xx10^-4=({10^(-2.70)}^2)/([HC(=O)OH(aq)])#</mathjax></p> <p><mathjax>#[HC(=O)OH(aq)]_"at equilibrium"=({10^(-2.70)}^2)/(1.80xx10^-4)#</mathjax></p> <p><mathjax>#-=0.0221molL^-1#</mathjax>...but this is the equilibrium value....and <mathjax>#[H_3O^+]=1.995xx10^-3molL^-1#</mathjax> by definition...</p> <p>And since the hydronium ion is PRESUMED to derive from the formic acid...<mathjax>#[HC(=O)OH]_"initially"=(0.0221+1.995 xx 10^(-3))molL^-1=0.0241molL^-1#</mathjax>...the degree of dissociation was miniscule....</p> <p>Pleas check my 'rithmetik...</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/642227" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-of-a-solution"> How do you determine ph of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-at-an-equivalence-point"> How do you determine pH at an equivalence point? </a> </div> </li> <li 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src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A solution of formic acid has a pH of 2.70, calculate the initial concentration of formic acid?	#K_a=1.8xx10^-4# for formic acid My work:
2,078	acacfc24-6ddd-11ea-bcba-ccda262736ce	https://socratic.org/questions/it-takes-10-ml-of-0-15-m-koh-solution-to-neutralize-7-5-ml-of-hno-3-solution-wha	0.20 M	start physical_unit 14 15 molarity mol/l qc_end physical_unit 7 8 2 3 volume qc_end physical_unit 7 8 5 6 molarity qc_end physical_unit 14 15 11 12 volume qc_end end	[{"type":"physical unit","value":"Molarity [OF] HNO3 solution [IN] M"}]	[{"type":"physical unit","value":"0.20 M"}]	[{"type":"physical unit","value":"Volume [OF] KOH solution [=] \\pu{10 mL}"},{"type":"physical unit","value":"Molarity [OF] KOH solution [=] \\pu{0.15 M}"},{"type":"physical unit","value":"Volume [OF] HNO3 solution [=] \\pu{7.5 mL}"}]	<h1 class="questionTitle" itemprop="name">It takes 10 mL of 0.15 M #KOH# solution to neutralize 7.5 mL of #HNO_3# solution. What is the molarity of #HNO_3#?</h1>	null	0.20 M	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Start by writing the balanced chemical equation for this <a href="http://socratic.org/chemistry/reactions-in-solution/neutralization">neutralization reaction</a></p> <blockquote> <p><mathjax>#"KOH"_text((aq]) + "HNO"_text(3(aq]) -> "KNO"_text(3(aq]) + "H"_2"O"_text((aq])#</mathjax></p> </blockquote> <p>Notice that you have <mathjax>#1:1#</mathjax> <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratios</a> between <em>potassium hydroxide</em>, <mathjax>#"KOH"#</mathjax>, and <em>nitric acid</em>, <mathjax>#"HNO"_3#</mathjax>. This tells you that the reaction will <strong>always</strong> consume <strong>equal numbers of moles</strong> of the two reactants. </p> <p>Now, <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> is defined as number of moles of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> per <strong>liters</strong> of solution. </p> <blockquote> <p><mathjax>#color(blue)(c = n_"solute"/V_"solution")#</mathjax></p> </blockquote> <p>Basically, all you have to do here is use the molarity and volume of the potassium hydroxide solution to determine how many <strong>moles</strong> of this strong base were used to neutralize the strong acid. </p> <p>According to the aforementioned mole ratio, the number of moles of acid will be <strong>equal</strong> to the number of moles of base. </p> <blockquote> <p><mathjax>#c = n/V implies n = c * V#</mathjax></p> <p><mathjax>#n_(KOH) = "0.15 M" * 10 * 10^(-3)"L" = "0.0015 moles KOH"#</mathjax></p> </blockquote> <p>This of course implies that you have </p> <blockquote> <p><mathjax>#0.0015 color(red)(cancel(color(black)("moles KOH"))) * "1 mole HNO"_3/(1color(red)(cancel(color(black)("mole KOH")))) = "0.0015 moles HNO"_3#</mathjax></p> </blockquote> <p>This means that the nitric acid solution had a molarity of </p> <blockquote> <p><mathjax>#c = n/V#</mathjax></p> <p><mathjax>#c_(HNO_3) = "0.0015 moles"/(7.5 * 10^(-3)"L") = color(green)("0.2 M")#</mathjax></p> </blockquote> <p>The answer is rounded to one <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig fig</a>, the number of sig figs you have for the volume of the potassium hydroxide solution. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"0.2 M"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Start by writing the balanced chemical equation for this <a href="http://socratic.org/chemistry/reactions-in-solution/neutralization">neutralization reaction</a></p> <blockquote> <p><mathjax>#"KOH"_text((aq]) + "HNO"_text(3(aq]) -> "KNO"_text(3(aq]) + "H"_2"O"_text((aq])#</mathjax></p> </blockquote> <p>Notice that you have <mathjax>#1:1#</mathjax> <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratios</a> between <em>potassium hydroxide</em>, <mathjax>#"KOH"#</mathjax>, and <em>nitric acid</em>, <mathjax>#"HNO"_3#</mathjax>. This tells you that the reaction will <strong>always</strong> consume <strong>equal numbers of moles</strong> of the two reactants. </p> <p>Now, <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> is defined as number of moles of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> per <strong>liters</strong> of solution. </p> <blockquote> <p><mathjax>#color(blue)(c = n_"solute"/V_"solution")#</mathjax></p> </blockquote> <p>Basically, all you have to do here is use the molarity and volume of the potassium hydroxide solution to determine how many <strong>moles</strong> of this strong base were used to neutralize the strong acid. </p> <p>According to the aforementioned mole ratio, the number of moles of acid will be <strong>equal</strong> to the number of moles of base. </p> <blockquote> <p><mathjax>#c = n/V implies n = c * V#</mathjax></p> <p><mathjax>#n_(KOH) = "0.15 M" * 10 * 10^(-3)"L" = "0.0015 moles KOH"#</mathjax></p> </blockquote> <p>This of course implies that you have </p> <blockquote> <p><mathjax>#0.0015 color(red)(cancel(color(black)("moles KOH"))) * "1 mole HNO"_3/(1color(red)(cancel(color(black)("mole KOH")))) = "0.0015 moles HNO"_3#</mathjax></p> </blockquote> <p>This means that the nitric acid solution had a molarity of </p> <blockquote> <p><mathjax>#c = n/V#</mathjax></p> <p><mathjax>#c_(HNO_3) = "0.0015 moles"/(7.5 * 10^(-3)"L") = color(green)("0.2 M")#</mathjax></p> </blockquote> <p>The answer is rounded to one <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig fig</a>, the number of sig figs you have for the volume of the potassium hydroxide solution. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">It takes 10 mL of 0.15 M #KOH# solution to neutralize 7.5 mL of #HNO_3# solution. What is the molarity of #HNO_3#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="214835" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-21T00:16:40" itemprop="dateCreated"> Jan 21, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"0.2 M"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Start by writing the balanced chemical equation for this <a href="http://socratic.org/chemistry/reactions-in-solution/neutralization">neutralization reaction</a></p> <blockquote> <p><mathjax>#"KOH"_text((aq]) + "HNO"_text(3(aq]) -> "KNO"_text(3(aq]) + "H"_2"O"_text((aq])#</mathjax></p> </blockquote> <p>Notice that you have <mathjax>#1:1#</mathjax> <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratios</a> between <em>potassium hydroxide</em>, <mathjax>#"KOH"#</mathjax>, and <em>nitric acid</em>, <mathjax>#"HNO"_3#</mathjax>. This tells you that the reaction will <strong>always</strong> consume <strong>equal numbers of moles</strong> of the two reactants. </p> <p>Now, <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> is defined as number of moles of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> per <strong>liters</strong> of solution. </p> <blockquote> <p><mathjax>#color(blue)(c = n_"solute"/V_"solution")#</mathjax></p> </blockquote> <p>Basically, all you have to do here is use the molarity and volume of the potassium hydroxide solution to determine how many <strong>moles</strong> of this strong base were used to neutralize the strong acid. </p> <p>According to the aforementioned mole ratio, the number of moles of acid will be <strong>equal</strong> to the number of moles of base. </p> <blockquote> <p><mathjax>#c = n/V implies n = c * V#</mathjax></p> <p><mathjax>#n_(KOH) = "0.15 M" * 10 * 10^(-3)"L" = "0.0015 moles KOH"#</mathjax></p> </blockquote> <p>This of course implies that you have </p> <blockquote> <p><mathjax>#0.0015 color(red)(cancel(color(black)("moles KOH"))) * "1 mole HNO"_3/(1color(red)(cancel(color(black)("mole KOH")))) = "0.0015 moles HNO"_3#</mathjax></p> </blockquote> <p>This means that the nitric acid solution had a molarity of </p> <blockquote> <p><mathjax>#c = n/V#</mathjax></p> <p><mathjax>#c_(HNO_3) = "0.0015 moles"/(7.5 * 10^(-3)"L") = color(green)("0.2 M")#</mathjax></p> </blockquote> <p>The answer is rounded to one <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig fig</a>, the number of sig figs you have for the volume of the potassium hydroxide solution. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/214835" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? 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</a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-3-hydrogen-peroxide"> What is the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 9278 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	It takes 10 mL of 0.15 M #KOH# solution to neutralize 7.5 mL of #HNO_3# solution. What is the molarity of #HNO_3#?	null
2,079	aab64ba6-6ddd-11ea-b4f3-ccda262736ce	https://socratic.org/questions/the-atomic-number-of-sulfur-is-16-sulfur-combines-with-hydrogen-by-covalent-bond	H2S	start chemical_formula qc_end physical_unit 4 4 6 6 number qc_end c_other OTHER qc_end c_other OTHER qc_end end	[{"type":"other","value":"Chemical Formula [OF] the compound [IN] molecular"}]	[{"type":"chemical equation","value":"H2S"}]	[{"type":"physical unit","value":"Atomic number [OF] sulfur [=] \\pu{16}"},{"type":"other","value":"Sulfur combines with hydrogen by covalent bonding to form a compound, hydrogen sulfide."},{"type":"other","value":"Based on the number of valence electrons in a sulfur atom."}]	<h1 class="questionTitle" itemprop="name">The atomic number of sulfur is 16. Sulfur combines with hydrogen by covalent bonding to form a compound, hydrogen sulfide. Based on the number of valence electrons in a sulfur atom, how do you predict the molecular formula of the compound?</h1>	null	H2S	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We thus predict that hydrogen sulfide would have a formula of <mathjax>#H_2S#</mathjax>, an analogue of the popular <mathjax>#H_2O#</mathjax> molecule. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Sulfur has 6 <a href="https://socratic.org/chemistry/the-periodic-table/valence-electrons-and-the-periodic-table">valence electrons</a>; sharing electrons with 2 additional hydrogen ATOMS, would give sulfur claim to 8 <a href="https://socratic.org/chemistry/the-electron-configuration-of-atoms/valence-electrons">valence electrons</a>....</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We thus predict that hydrogen sulfide would have a formula of <mathjax>#H_2S#</mathjax>, an analogue of the popular <mathjax>#H_2O#</mathjax> molecule. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">The atomic number of sulfur is 16. Sulfur combines with hydrogen by covalent bonding to form a compound, hydrogen sulfide. Based on the number of valence electrons in a sulfur atom, how do you predict the molecular formula of the compound?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="353612" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-12-18T10:01:22" itemprop="dateCreated"> Dec 18, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Sulfur has 6 <a href="https://socratic.org/chemistry/the-periodic-table/valence-electrons-and-the-periodic-table">valence electrons</a>; sharing electrons with 2 additional hydrogen ATOMS, would give sulfur claim to 8 <a href="https://socratic.org/chemistry/the-electron-configuration-of-atoms/valence-electrons">valence electrons</a>....</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We thus predict that hydrogen sulfide would have a formula of <mathjax>#H_2S#</mathjax>, an analogue of the popular <mathjax>#H_2O#</mathjax> molecule. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/353612" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? 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</a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-empirical-formula-not-double-that-of-the-monosaccharides"> Why is the empirical formula not double that of the monosaccharides? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5331180502bf342f40b5c3b5"> Question #5c3b5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-molecular-formula-represents-a-carbohydrate"> What molecular formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-of-vinegar"> What is the molecular formula of vinegar? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/empirical-and-molecular-formulas"> See all questions in Empirical and Molecular Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 24207 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	The atomic number of sulfur is 16. Sulfur combines with hydrogen by covalent bonding to form a compound, hydrogen sulfide. Based on the number of valence electrons in a sulfur atom, how do you predict the molecular formula of the compound?	null
2,080	aaf5940a-6ddd-11ea-aa8b-ccda262736ce	https://socratic.org/questions/how-much-heat-would-be-needed-to-raise-the-temperature-of-25-0-g-of-water-by-18-	1.9 × 10^3 J	start physical_unit 14 14 heat_energy j qc_end physical_unit 14 14 16 17 temperature qc_end physical_unit 14 14 11 12 mass qc_end end	[{"type":"physical unit","value":"Needed heat [OF] water [IN] J"}]	[{"type":"physical unit","value":"1.9 × 10^3 J"}]	[{"type":"physical unit","value":"Raised temperature [OF] water [=] \\pu{18 ℃}"},{"type":"physical unit","value":"Mass [OF] water [=] \\pu{25.0 g}"}]	<h1 class="questionTitle" itemprop="name">How much heat would be needed to raise the temperature of 25.0 g of water by 18#"^@#C?</h1>	null	1.9 × 10^3 J	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The specific heat of water is 4.18 J/(g·°C).</p> <p>This means that it takes 4.18 J to raise one gram of water one degree.</p> <p>Multiply that by 25.0 g and 18°C.</p> <p><mathjax>#(4.18J)/(gK) 25.0g18K#</mathjax></p> <p>The units cancel out and you get joules.</p> <p>18 °C has 2 sig figs, so you give your answer to 2 sig figs.</p> <p><mathjax>#1.910^3#</mathjax> J.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1.910^3#</mathjax> J.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The specific heat of water is 4.18 J/(g·°C).</p> <p>This means that it takes 4.18 J to raise one gram of water one degree.</p> <p>Multiply that by 25.0 g and 18°C.</p> <p><mathjax>#(4.18J)/(gK) 25.0g18K#</mathjax></p> <p>The units cancel out and you get joules.</p> <p>18 °C has 2 sig figs, so you give your answer to 2 sig figs.</p> <p><mathjax>#1.9*10^3#</mathjax> J.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How much heat would be needed to raise the temperature of 25.0 g of water by 18#"^@#C?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/calorimetry" itemprop="url"> <span class="breadcrumb" itemprop="title">Calorimetry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="465540" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/0ongli"><img alt="" class="" src="https://profilepictures.socratic.org/SPZ4hE6KSuqzS7J3OUwJ_InfFace.061.png" title=""/></a> <a class="secondContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/0ongli"> Pop Quiz Whiz </a>·<a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-18T18:17:25" itemprop="dateCreated"> Aug 18, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1.910^3#</mathjax> J.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The specific heat of water is 4.18 J/(g·°C).</p> <p>This means that it takes 4.18 J to raise one gram of water one degree.</p> <p>Multiply that by 25.0 g and 18°C.</p> <p><mathjax>#(4.18J)/(gK) 25.0g18K#</mathjax></p> <p>The units cancel out and you get joules.</p> <p>18 °C has 2 sig figs, so you give your answer to 2 sig figs.</p> <p><mathjax>#1.9*10^3#</mathjax> J.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/465540" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a 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class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/calorimetry"> See all questions in Calorimetry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1982 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How much heat would be needed to raise the temperature of 25.0 g of water by 18#"^@#C?	null
2,081	ad01d4a7-6ddd-11ea-85d8-ccda262736ce	https://socratic.org/questions/what-is-the-empirical-formula-of-ethylene-glycol	CH3O	start chemical_formula qc_end substance 6 7 qc_end end	[{"type":"other","value":"Chemical Formula [OF] ethylene glycol [IN] empirical"}]	[{"type":"chemical equation","value":"CH3O"}]	[{"type":"substance name","value":"Ethylene glycol"}]	<h1 class="questionTitle" itemprop="name">What is the empirical formula of ethylene glycol?</h1>	null	CH3O	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The empirical formula is the simplest whole number ratio defining constituent atoms in a species (this is glib, I think I learned this definition when I was 15, and it has stuck!). Given this, the molecular formula is clearly not the empirical formula (why not?), but is a multiple of the empirical formula.</p> <p>So the empirical formula of ethylene glycol is <mathjax>#CH_3O#</mathjax>; this is the ratio of carbons to hydrogen to oxygen we would find if we tried to determine the composition of the stuff by experiment (i.e. empirically). </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The molecular formula of ethylene glycol is <mathjax>#HOCH_2CH_2OH#</mathjax>, i.e. <mathjax>#C_2H_6O_2#</mathjax>. The empirical formula is <mathjax>#??#</mathjax> </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The empirical formula is the simplest whole number ratio defining constituent atoms in a species (this is glib, I think I learned this definition when I was 15, and it has stuck!). Given this, the molecular formula is clearly not the empirical formula (why not?), but is a multiple of the empirical formula.</p> <p>So the empirical formula of ethylene glycol is <mathjax>#CH_3O#</mathjax>; this is the ratio of carbons to hydrogen to oxygen we would find if we tried to determine the composition of the stuff by experiment (i.e. empirically). </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the empirical formula of ethylene glycol?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="179061" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-10-22T13:58:32" itemprop="dateCreated"> Oct 22, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The molecular formula of ethylene glycol is <mathjax>#HOCH_2CH_2OH#</mathjax>, i.e. <mathjax>#C_2H_6O_2#</mathjax>. The empirical formula is <mathjax>#??#</mathjax> </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The empirical formula is the simplest whole number ratio defining constituent atoms in a species (this is glib, I think I learned this definition when I was 15, and it has stuck!). Given this, the molecular formula is clearly not the empirical formula (why not?), but is a multiple of the empirical formula.</p> <p>So the empirical formula of ethylene glycol is <mathjax>#CH_3O#</mathjax>; this is the ratio of carbons to hydrogen to oxygen we would find if we tried to determine the composition of the stuff by experiment (i.e. empirically). </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/179061" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molecular-formula-of-a-compound"> How do you find molecular formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-diamond"> What is the chemical formula of a diamond? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-carbohydrate"> What is the chemical formula of a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-valproic-acid"> What is the empirical formula for valproic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-of-magnesium-oxide"> What is the empirical formula of magnesium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-empirical-formula-not-double-that-of-the-monosaccharides"> Why is the empirical formula not double that of the monosaccharides? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5331180502bf342f40b5c3b5"> Question #5c3b5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-molecular-formula-represents-a-carbohydrate"> What molecular formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-of-vinegar"> What is the molecular formula of vinegar? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/empirical-and-molecular-formulas"> See all questions in Empirical and Molecular Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 20792 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the empirical formula of ethylene glycol?	null
2,082	a9bb152e-6ddd-11ea-bec4-ccda262736ce	https://socratic.org/questions/57a9eb327c014949785ea1d7	2.04 × 10^22	start physical_unit 2 3 number none qc_end physical_unit 2 2 6 7 mass qc_end end	[{"type":"physical unit","value":"Number [OF] copper atoms"}]	[{"type":"physical unit","value":"2.04 × 10^22"}]	[{"type":"physical unit","value":"Mass [OF] copper [=] \\pu{2.15 g}"}]	<h1 class="questionTitle" itemprop="name">How many copper atoms are in 2.15 g of copper?</h1>	null	2.04 × 10^22	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>You could use the known <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">atomic mass</a> of <mathjax>#"Cu"#</mathjax> (63.456 u) to calculate the percentages of each isotope, but that's the hard way.</p> <p>The easy way is to calculate the number of atoms with an average mass of 63.546 u.</p> <p>A mole of these atoms has a mass of 63.546 g.</p> <p>∴ <mathjax>#"No. of atoms" = 2.15 color(red)(cancel(color(black)("g Cu"))) × (1 color(red)(cancel(color(black)("mol Cu"))))/(63.456 color(red)(cancel(color(black)("g Cu")))) × (6.022 × 10^23 "Cu atoms")/(1 color(red)(cancel(color(black)("mol Cu"))))#</mathjax></p> <p><mathjax>#= 2.04 × 10^22 color(white)(l)"Cu atoms"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>There are <mathjax>#2.04 × 10^22color(white)(l) "Cu atoms"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>You could use the known <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">atomic mass</a> of <mathjax>#"Cu"#</mathjax> (63.456 u) to calculate the percentages of each isotope, but that's the hard way.</p> <p>The easy way is to calculate the number of atoms with an average mass of 63.546 u.</p> <p>A mole of these atoms has a mass of 63.546 g.</p> <p>∴ <mathjax>#"No. of atoms" = 2.15 color(red)(cancel(color(black)("g Cu"))) × (1 color(red)(cancel(color(black)("mol Cu"))))/(63.456 color(red)(cancel(color(black)("g Cu")))) × (6.022 × 10^23 "Cu atoms")/(1 color(red)(cancel(color(black)("mol Cu"))))#</mathjax></p> <p><mathjax>#= 2.04 × 10^22 color(white)(l)"Cu atoms"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many copper atoms are in 2.15 g of copper?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="298149" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-08-12T13:56:53" itemprop="dateCreated"> Aug 12, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>There are <mathjax>#2.04 × 10^22color(white)(l) "Cu atoms"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>You could use the known <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">atomic mass</a> of <mathjax>#"Cu"#</mathjax> (63.456 u) to calculate the percentages of each isotope, but that's the hard way.</p> <p>The easy way is to calculate the number of atoms with an average mass of 63.546 u.</p> <p>A mole of these atoms has a mass of 63.546 g.</p> <p>∴ <mathjax>#"No. of atoms" = 2.15 color(red)(cancel(color(black)("g Cu"))) × (1 color(red)(cancel(color(black)("mol Cu"))))/(63.456 color(red)(cancel(color(black)("g Cu")))) × (6.022 × 10^23 "Cu atoms")/(1 color(red)(cancel(color(black)("mol Cu"))))#</mathjax></p> <p><mathjax>#= 2.04 × 10^22 color(white)(l)"Cu atoms"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/298149" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a 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class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 8582 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many copper atoms are in 2.15 g of copper?	null
2,083	a9bd1142-6ddd-11ea-a369-ccda262736ce	https://socratic.org/questions/helium-occupies-2-40-l-at-123-c-what-would-the-volume-of-the-same-sample-of-gas-	1.79 L	start physical_unit 14 16 volume l qc_end physical_unit 14 16 2 3 volume qc_end physical_unit 14 16 5 6 temperature qc_end physical_unit 14 16 19 20 temperature qc_end end	[{"type":"physical unit","value":"Volume2 [OF] gas sample [IN] L"}]	[{"type":"physical unit","value":"1.79 L"}]	[{"type":"physical unit","value":"Volume1 [OF] gas sample [=] \\pu{2.40 L}"},{"type":"physical unit","value":"Temperature1 [OF] gas sample [=] \\pu{123 ℃}"},{"type":"physical unit","value":"Temperature2 [OF] gas sample [=] \\pu{23 ℃}"}]	<h1 class="questionTitle" itemprop="name">Helium occupies 2.40 L at 123°C. What would the volume of the same sample of gas be at 23°C?</h1>	null	1.79 L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use the <a href="https://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">combined gas law</a></p> <p><mathjax>#(P_1xxV_1)/T_1=(P_2xxV_2)/T_2#</mathjax></p> <p>Note that the pressure was not mentioned and therefore I would assume it remains constant.</p> <p><mathjax>#(cancel (P_1)xxV_1)/T_1=(cancel(P_2)xxV_2)/T_2#</mathjax></p> <p><mathjax>#V_1/T_1=V_2/T_2#</mathjax></p> <p><mathjax>#V_2=T_2/T_1xxV_1#</mathjax></p> <p><mathjax>#V_2= (296 \ K)/(396 \ K) xx 2.40 \ L#</mathjax></p> <p><mathjax>#V_2= (296 \ cancel (K))/(396 \ cancel (K)) xx 2.40 \ L#</mathjax></p> <p><mathjax>#V_2= 1.79 \ L#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#V= 1.79 \ L#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use the <a href="https://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">combined gas law</a></p> <p><mathjax>#(P_1xxV_1)/T_1=(P_2xxV_2)/T_2#</mathjax></p> <p>Note that the pressure was not mentioned and therefore I would assume it remains constant.</p> <p><mathjax>#(cancel (P_1)xxV_1)/T_1=(cancel(P_2)xxV_2)/T_2#</mathjax></p> <p><mathjax>#V_1/T_1=V_2/T_2#</mathjax></p> <p><mathjax>#V_2=T_2/T_1xxV_1#</mathjax></p> <p><mathjax>#V_2= (296 \ K)/(396 \ K) xx 2.40 \ L#</mathjax></p> <p><mathjax>#V_2= (296 \ cancel (K))/(396 \ cancel (K)) xx 2.40 \ L#</mathjax></p> <p><mathjax>#V_2= 1.79 \ L#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Helium occupies 2.40 L at 123°C. What would the volume of the same sample of gas be at 23°C?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/charles-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Charles' Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="276402" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/sam-54"><img alt="" class="" src="https://profilepictures.socratic.org/3bkyAGe2RVWw1lx2h1A5_Avatar%201.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/sam-54"> Sam </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-11T19:25:29" itemprop="dateCreated"> Jun 11, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#V= 1.79 \ L#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use the <a href="https://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">combined gas law</a></p> <p><mathjax>#(P_1xxV_1)/T_1=(P_2xxV_2)/T_2#</mathjax></p> <p>Note that the pressure was not mentioned and therefore I would assume it remains constant.</p> <p><mathjax>#(cancel (P_1)xxV_1)/T_1=(cancel(P_2)xxV_2)/T_2#</mathjax></p> <p><mathjax>#V_1/T_1=V_2/T_2#</mathjax></p> <p><mathjax>#V_2=T_2/T_1xxV_1#</mathjax></p> <p><mathjax>#V_2= (296 \ K)/(396 \ K) xx 2.40 \ L#</mathjax></p> <p><mathjax>#V_2= (296 \ cancel (K))/(396 \ cancel (K)) xx 2.40 \ L#</mathjax></p> <p><mathjax>#V_2= 1.79 \ L#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/276402" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-must-charles-law-be-in-kelvins"> Why must Charles' law be in kelvin? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-charles-law-formula"> What is Charles' law formula? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/oxygen-gas-is-at-a-temperature-of-40-c-when-it-occupies-a-volume-of-2-3-liters-t"> Oxygen gas is at a temperature of 40°C when it occupies a volume of 2.3 liters. 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2,084	aaa23936-6ddd-11ea-bade-ccda262736ce	https://socratic.org/questions/1-50-moles-of-sodium-nitrate-are-equal-to-how-many-grams-of-sodium-nitrate	127.49 grams	start physical_unit 3 4 mass g qc_end physical_unit 3 4 0 1 mole qc_end end	[{"type":"physical unit","value":"Mass [OF] sodium nitrate [IN] grams"}]	[{"type":"physical unit","value":"127.49 grams"}]	[{"type":"physical unit","value":"Mole [OF] sodium nitrate [=] \\pu{1.50 moles}"}]	<h1 class="questionTitle" itemprop="name">1.50 moles of sodium nitrate are equal to how many grams of sodium nitrate?</h1>	null	127.49 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So we set up the product:</p> <p><mathjax>#1.50cancel(mol)xx84.99g*cancel(mol^-1)=??g#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, one mole of sodium nitrate has a molar mass of <mathjax>#84.99gmol^-1#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So we set up the product:</p> <p><mathjax>#1.50cancel(mol)xx84.99g*cancel(mol^-1)=??g#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">1.50 moles of sodium nitrate are equal to how many grams of sodium nitrate?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="366886" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-01-20T06:38:59" itemprop="dateCreated"> Jan 20, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, one mole of sodium nitrate has a molar mass of <mathjax>#84.99gmol^-1#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So we set up the product:</p> <p><mathjax>#1.50cancel(mol)xx84.99g*cancel(mol^-1)=??g#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/366886" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? 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2,085	aa3cc792-6ddd-11ea-a239-ccda262736ce	https://socratic.org/questions/how-many-moles-of-h2o-contain-2-60-10-23-molecules-of-water	0.43 moles	start physical_unit 4 4 mole mol qc_end end	[{"type":"physical unit","value":"Mole [OF] H2O [IN] moles"}]	[{"type":"physical unit","value":"0.43 moles"}]	[{"type":"physical unit","value":"Number [OF] water molecules [=] \\pu{2.60 × 10^23}"}]	<h1 class="questionTitle" itemprop="name">How many moles of #"H"_2"O"# contain #2.60 * 10^23# molecules of water?</h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>The answer is 0.432 mole of H2O but I dont know how to get that answer. I dont know how to set up the problem</p></div> </h2> </div> </div>	0.43 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Divide the given number of molecules by Avogadro's constant. Avogradro's constant is the number of atoms/molecules in a mole of a substance. </p> <p>Therefore, </p> <p><mathjax>#(2.60 * 10^23 \ "molecules")/(6.022 * 10^23 \ "molecules/mol") = "0.432175 moles" ~~ "0.432 moles"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#0.432#</mathjax>mol </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Divide the given number of molecules by Avogadro's constant. Avogradro's constant is the number of atoms/molecules in a mole of a substance. </p> <p>Therefore, </p> <p><mathjax>#(2.60 * 10^23 \ "molecules")/(6.022 * 10^23 \ "molecules/mol") = "0.432175 moles" ~~ "0.432 moles"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles of #"H"_2"O"# contain #2.60 * 10^23# molecules of water?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>The answer is 0.432 mole of H2O but I dont know how to get that answer. I dont know how to set up the problem</p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="639749" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/alexie"><img alt="" class="" src="https://profilepictures.socratic.org/cE8CHgwMTzaym2hM5xvR_SFBayGGBridge.png" title=""/></a> <a class="secondContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/alexie"> Sydney </a>·<a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-07-10T02:05:34" itemprop="dateCreated"> Jul 10, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#0.432#</mathjax>mol </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Divide the given number of molecules by Avogadro's constant. Avogradro's constant is the number of atoms/molecules in a mole of a substance. </p> <p>Therefore, </p> <p><mathjax>#(2.60 * 10^23 \ "molecules")/(6.022 * 10^23 \ "molecules/mol") = "0.432175 moles" ~~ "0.432 moles"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/639749" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="639774" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-07-10T04:57:25" itemprop="dateCreated"> Jul 10, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, how molecules are present in ONE MOLE of water...?</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>By definition, there are <mathjax>#6.022xx10^23#</mathjax> such molecules, or <mathjax>#N_A#</mathjax> such molecules in ONE mole of water. And thus in such a quantity there are <mathjax>#N_A#</mathjax> oxygen atoms, and <mathjax>#2xxN_A#</mathjax> hydrogen atoms...and the mass associated with this numerical quantity of water molecules is approx. <mathjax>#18g#</mathjax>...</p> <p>And so we simply take the quotient....</p> <p><mathjax>#"Moles of water"=(2.60xx10^23"water molecules")/(6.022xx10^23"water molecules"mol^-1)#</mathjax></p> <p><mathjax>#=0.432mol#</mathjax>...and thus a mass of <mathjax>#0.432molxx18.01gmol^-1=7.78g#</mathjax>...</p> <p>Instead of <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a>, we could use the dozen, or the gross, or some other numerical quantity ... it just happens that one mole of hydrogen ATOMS have a mass of <mathjax>#1g#</mathjax> more or less precisely.. which is why we use this absurdly large quantity .. Capisce?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/639774" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 44767 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many moles of #"H"_2"O"# contain #2.60 * 10^23# molecules of water?	The answer is 0.432 mole of H2O but I dont know how to get that answer. I dont know how to set up the problem
2,086	ab0c40a2-6ddd-11ea-9bfd-ccda262736ce	https://socratic.org/questions/how-much-heat-in-kj-is-absorbed-when-24-8-g-h-2o-l-at-100-c-and-101-3-kpa-is-con	55.97 kJ	start physical_unit 10 10 heat_energy kj qc_end physical_unit 10 10 12 13 temperature qc_end physical_unit 10 10 15 16 pressure qc_end physical_unit 20 20 12 13 temperature qc_end physical_unit 10 10 8 9 mass qc_end end	[{"type":"physical unit","value":"Absorbed heat [OF] H2O(l) [IN] kJ"}]	[{"type":"physical unit","value":"55.97 kJ"}]	[{"type":"physical unit","value":"Temperature1 [OF] H2O(l) [=] \\pu{100 ℃ }"},{"type":"physical unit","value":"Pressure [OF] H2O(l) [=] \\pu{101.3 kPa}"},{"type":"physical unit","value":"Temperature2 [OF] steam [=] \\pu{100 ℃ }"},{"type":"physical unit","value":"Mass [OF] H2O(l) [=] \\pu{24.8 g}"}]	<h1 class="questionTitle" itemprop="name">How much heat (in kJ) is absorbed when 24.8 g #H_2O(l)# at 100°C and 101.3 kPa is converted to steam at 100°C?</h1>	null	55.97 kJ	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In this case, the water is already at it's boiling point at the indicated pressure, so the only energy adsorption required is the heat of vaporization. That is 2257 J/g for water (it is different for every compound).</p> <p>24.8g * 2257 J/g = 55973.6 J or 55.974 kJ </p> <p>With the data precision limitation of 24.8g being three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a>, this answer would most practically be stated at <strong>55.97 kJ</strong></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>55.97 kJ</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In this case, the water is already at it's boiling point at the indicated pressure, so the only energy adsorption required is the heat of vaporization. That is 2257 J/g for water (it is different for every compound).</p> <p>24.8g * 2257 J/g = 55973.6 J or 55.974 kJ </p> <p>With the data precision limitation of 24.8g being three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a>, this answer would most practically be stated at <strong>55.97 kJ</strong></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How much heat (in kJ) is absorbed when 24.8 g #H_2O(l)# at 100°C and 101.3 kPa is converted to steam at 100°C?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/thermochemistry-of-phase-changes" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry of Phase Changes</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="246694" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/scooke"><img alt="" class="" src="https://profilepictures.socratic.org/ezAzqDkjRS6NXBmMH3lg_BioPic2010a.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/scooke"> SCooke </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-29T09:04:21" itemprop="dateCreated"> Mar 29, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>55.97 kJ</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In this case, the water is already at it's boiling point at the indicated pressure, so the only energy adsorption required is the heat of vaporization. That is 2257 J/g for water (it is different for every compound).</p> <p>24.8g * 2257 J/g = 55973.6 J or 55.974 kJ </p> <p>With the data precision limitation of 24.8g being three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a>, this answer would most practically be stated at <strong>55.97 kJ</strong></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/246694" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-much-energy-is-required-to-heat-100-g-of-ice-at-0-00-degrees-celsius-to-wate"> How much energy is required to convert 100.g of ice at 0.00 °C to water vapor at 100.00 °C? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/534b309602bf34123dd86d5c"> How do you calculate the heat required to melt 15 kg of silver? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-a-liquid-loses-energy-will-it-change-into-a-gas-or-a-solid"> When a liquid loses energy, will it change into a gas or a solid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-name-of-the-process-when-a-liquid-changes-into-a-gas"> What is the name of the process when a liquid changes into a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-much-energy-is-needed-to-convert-23-0-grams-of-ice-at-10-0-c-into-steam-at-1"> How much energy is needed to convert 23.0 grams of ice at -10.0°C into steam at 109°C? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-amount-of-ice-must-be-added-to-540-0-g-of-water-at-25-0-c-to-cool-the-water"> What amount of ice must be added to 540.0 g of water at 25.0 °C to cool the water to 0.0 °C and... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-find-specific-heat-in-thermochemistry-of-phase-of-changes"> How can I find specific heat in thermochemistry of phase of changes? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-much-energy-is-required-to-convert-100-0-g-of-water-at-20-0-c-completely-to-"> How much energy is required to convert 100.0 g of water at 20.0 °C completely to steam at 100.0 °C? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/calculate-the-number-of-joules-given-off-when-32-0-grams-of-steam-cools-from-110"> Calculate the number of joules given off when 32.0 grams of steam cools from 110.0 °C to ice at -40.0 °C. </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-joules-of-heat-are-needed-to-change-50-0-grams-of-ice-at-15-0-c-to-stea"> How many joules of heat are needed to change 50.0 grams of ice at -15.0 °C to steam at 120.0 °C? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/thermochemistry-of-phase-changes"> See all questions in Thermochemistry of Phase Changes </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 5416 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How much heat (in kJ) is absorbed when 24.8 g #H_2O(l)# at 100°C and 101.3 kPa is converted to steam at 100°C?	null
2,087	a907ebd3-6ddd-11ea-85aa-ccda262736ce	https://socratic.org/questions/how-many-good-s-buffer-agents-exist	20	start physical_unit 2 4 number none qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Number [OF] Good's buffer agents"}]	[{"type":"physical unit","value":"20"}]	[{"type":"other","value":"Good's buffer agents."}]	<h1 class="questionTitle" itemprop="name">How many Good's buffer agents exist?</h1>	null	20	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>Named after Norman Good, they are all physiological buffers with <mathjax>#"p"K_a#</mathjax> values ranging from 6.1 to 8.5.</p> <blockquote></blockquote> <p>The buffers, with their <mathjax>#"p"K_a#</mathjax> values, are:</p> <ol> <li> <p><strong>MES:</strong> <mathjax>#"2-("N"-morpholino)ethanesulfonic acid"#</mathjax>, 6.15</p> </li> <li> <p><strong>ADA:</strong> <mathjax>#N"-(2-acetamido)iminodiacetic acid"#</mathjax>, 6.62</p> </li> <li> <p><strong>PIPES:</strong> <mathjax>#"piperazine-"N,N′"-bis(2-ethanesulfonic acid)"#</mathjax>, 6.82</p> </li> <li> <p><strong>ACES:</strong> <mathjax>#N"-(2-acetamido)-2-aminoethanesulfonic acid"#</mathjax>, 6.88</p> </li> <li> <p><strong>MOPSO:</strong> <mathjax>#"3-("N"-morpholinyl)-2-hydroxypropanesulfonic acid"#</mathjax>, 6.95</p> </li> <li> <p><strong>Cholamine chloride:</strong> <mathjax>#("CH"_3)_3 stackrel(+)("N")"CH"_2"CH"_2"NH"_2, "Cl"^"-"#</mathjax>, 7.10</p> </li> <li> <p><strong>BES:</strong> <mathjax>#N,N"-bis(2-hydroxyethyl)-2-aminoethanesulfonic acid"#</mathjax>, 7.17</p> </li> <li> <p><strong>MOPS:</strong> <mathjax>#"3-("N"-morpholino)propanesulfonic acid"#</mathjax>, 7.20</p> </li> <li> <p><strong>TES:</strong> <mathjax>#N"-[tris(hydroxymethyl)methyl]-2-aminoethanesulfonic acid"#</mathjax>, 7.40</p> </li> <li> <p><strong>HEPES:</strong> <mathjax>#"4-(2-hydroxyethyl)-1-piperazinylethanesulfonic acid"#</mathjax>, 7.48</p> </li> <li> <p><strong>DIPSO:</strong> <mathjax>#N,N"-bis(2-hydroxyethyl)-3-amino-2-hydroxypropanesulfonic acid"#</mathjax>, 7.60</p> </li> <li> <p><strong>TAPSO:</strong><mathjax># "3-["N"-tris(hydroxymethyl)methylamino]-2-hydroxypropanesulfonic acid"#</mathjax>, 7.60</p> </li> <li> <p><strong>Acetamidoglycine:</strong> <mathjax>#"CH"_3"CONHNHCH"_2"COOH"#</mathjax>, 7.7</p> </li> <li> <p><strong>POPSO:</strong> <mathjax>#"piperazine-"N,N′"-bis(2-hydroxypropanesulfonic acid)"#</mathjax>, 7.85</p> </li> <li> <p><strong>HEPPSO:</strong> <mathjax>#"4-(2-hydroxyethyl)piperazine-1-(2-hydroxypropanesulfonic acid)"#</mathjax>, 7.85</p> </li> <li> <p><strong>HEPPS:</strong> <mathjax>#"3-[4-(2-hydroxyethyl)-1-piperazinyl]propanesulfonic acid"#</mathjax>, 8.00</p> </li> <li> <p><strong>Tricine:</strong> <mathjax>#N"-[tris(hydroxymethyl)methyl)]glycine"#</mathjax>, 8.15</p> </li> <li> <p><strong>Glycinamide:</strong> <mathjax>#"NH"_2"CH"_2"CONH"_2#</mathjax>, 8.20</p> </li> <li> <p><strong>Bicine:</strong> <mathjax>#N,N"-bis(2-hydroxyethyl)glycine"#</mathjax>, 8.35</p> </li> <li> <p><strong>TAPS:</strong> <mathjax>#N"-tris(hydroxymethyl)methyl-3-aminopropanesulfonic acid"#</mathjax>, 8.44</p> </li> </ol></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>There are 20 Good buffers.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>Named after Norman Good, they are all physiological buffers with <mathjax>#"p"K_a#</mathjax> values ranging from 6.1 to 8.5.</p> <blockquote></blockquote> <p>The buffers, with their <mathjax>#"p"K_a#</mathjax> values, are:</p> <ol> <li> <p><strong>MES:</strong> <mathjax>#"2-("N"-morpholino)ethanesulfonic acid"#</mathjax>, 6.15</p> </li> <li> <p><strong>ADA:</strong> <mathjax>#N"-(2-acetamido)iminodiacetic acid"#</mathjax>, 6.62</p> </li> <li> <p><strong>PIPES:</strong> <mathjax>#"piperazine-"N,N′"-bis(2-ethanesulfonic acid)"#</mathjax>, 6.82</p> </li> <li> <p><strong>ACES:</strong> <mathjax>#N"-(2-acetamido)-2-aminoethanesulfonic acid"#</mathjax>, 6.88</p> </li> <li> <p><strong>MOPSO:</strong> <mathjax>#"3-("N"-morpholinyl)-2-hydroxypropanesulfonic acid"#</mathjax>, 6.95</p> </li> <li> <p><strong>Cholamine chloride:</strong> <mathjax>#("CH"_3)_3 stackrel(+)("N")"CH"_2"CH"_2"NH"_2, "Cl"^"-"#</mathjax>, 7.10</p> </li> <li> <p><strong>BES:</strong> <mathjax>#N,N"-bis(2-hydroxyethyl)-2-aminoethanesulfonic acid"#</mathjax>, 7.17</p> </li> <li> <p><strong>MOPS:</strong> <mathjax>#"3-("N"-morpholino)propanesulfonic acid"#</mathjax>, 7.20</p> </li> <li> <p><strong>TES:</strong> <mathjax>#N"-[tris(hydroxymethyl)methyl]-2-aminoethanesulfonic acid"#</mathjax>, 7.40</p> </li> <li> <p><strong>HEPES:</strong> <mathjax>#"4-(2-hydroxyethyl)-1-piperazinylethanesulfonic acid"#</mathjax>, 7.48</p> </li> <li> <p><strong>DIPSO:</strong> <mathjax>#N,N"-bis(2-hydroxyethyl)-3-amino-2-hydroxypropanesulfonic acid"#</mathjax>, 7.60</p> </li> <li> <p><strong>TAPSO:</strong><mathjax># "3-["N"-tris(hydroxymethyl)methylamino]-2-hydroxypropanesulfonic acid"#</mathjax>, 7.60</p> </li> <li> <p><strong>Acetamidoglycine:</strong> <mathjax>#"CH"_3"CONHNHCH"_2"COOH"#</mathjax>, 7.7</p> </li> <li> <p><strong>POPSO:</strong> <mathjax>#"piperazine-"N,N′"-bis(2-hydroxypropanesulfonic acid)"#</mathjax>, 7.85</p> </li> <li> <p><strong>HEPPSO:</strong> <mathjax>#"4-(2-hydroxyethyl)piperazine-1-(2-hydroxypropanesulfonic acid)"#</mathjax>, 7.85</p> </li> <li> <p><strong>HEPPS:</strong> <mathjax>#"3-[4-(2-hydroxyethyl)-1-piperazinyl]propanesulfonic acid"#</mathjax>, 8.00</p> </li> <li> <p><strong>Tricine:</strong> <mathjax>#N"-[tris(hydroxymethyl)methyl)]glycine"#</mathjax>, 8.15</p> </li> <li> <p><strong>Glycinamide:</strong> <mathjax>#"NH"_2"CH"_2"CONH"_2#</mathjax>, 8.20</p> </li> <li> <p><strong>Bicine:</strong> <mathjax>#N,N"-bis(2-hydroxyethyl)glycine"#</mathjax>, 8.35</p> </li> <li> <p><strong>TAPS:</strong> <mathjax>#N"-tris(hydroxymethyl)methyl-3-aminopropanesulfonic acid"#</mathjax>, 8.44</p> </li> </ol></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many Good's buffer agents exist?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#reactions-in-solution" itemprop="url"> <span class="breadcrumb" itemprop="title">Reactions in Solution</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/reactions-in-solution/buffer-theory" itemprop="url"> <span class="breadcrumb" itemprop="title">Buffer Theory</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="262740" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-06T02:11:43" itemprop="dateCreated"> May 6, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>There are 20 Good buffers.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>Named after Norman Good, they are all physiological buffers with <mathjax>#"p"K_a#</mathjax> values ranging from 6.1 to 8.5.</p> <blockquote></blockquote> <p>The buffers, with their <mathjax>#"p"K_a#</mathjax> values, are:</p> <ol> <li> <p><strong>MES:</strong> <mathjax>#"2-("N"-morpholino)ethanesulfonic acid"#</mathjax>, 6.15</p> </li> <li> <p><strong>ADA:</strong> <mathjax>#N"-(2-acetamido)iminodiacetic acid"#</mathjax>, 6.62</p> </li> <li> <p><strong>PIPES:</strong> <mathjax>#"piperazine-"N,N′"-bis(2-ethanesulfonic acid)"#</mathjax>, 6.82</p> </li> <li> <p><strong>ACES:</strong> <mathjax>#N"-(2-acetamido)-2-aminoethanesulfonic acid"#</mathjax>, 6.88</p> </li> <li> <p><strong>MOPSO:</strong> <mathjax>#"3-("N"-morpholinyl)-2-hydroxypropanesulfonic acid"#</mathjax>, 6.95</p> </li> <li> <p><strong>Cholamine chloride:</strong> <mathjax>#("CH"_3)_3 stackrel(+)("N")"CH"_2"CH"_2"NH"_2, "Cl"^"-"#</mathjax>, 7.10</p> </li> <li> <p><strong>BES:</strong> <mathjax>#N,N"-bis(2-hydroxyethyl)-2-aminoethanesulfonic acid"#</mathjax>, 7.17</p> </li> <li> <p><strong>MOPS:</strong> <mathjax>#"3-("N"-morpholino)propanesulfonic acid"#</mathjax>, 7.20</p> </li> <li> <p><strong>TES:</strong> <mathjax>#N"-[tris(hydroxymethyl)methyl]-2-aminoethanesulfonic acid"#</mathjax>, 7.40</p> </li> <li> <p><strong>HEPES:</strong> <mathjax>#"4-(2-hydroxyethyl)-1-piperazinylethanesulfonic acid"#</mathjax>, 7.48</p> </li> <li> <p><strong>DIPSO:</strong> <mathjax>#N,N"-bis(2-hydroxyethyl)-3-amino-2-hydroxypropanesulfonic acid"#</mathjax>, 7.60</p> </li> <li> <p><strong>TAPSO:</strong><mathjax># "3-["N"-tris(hydroxymethyl)methylamino]-2-hydroxypropanesulfonic acid"#</mathjax>, 7.60</p> </li> <li> <p><strong>Acetamidoglycine:</strong> <mathjax>#"CH"_3"CONHNHCH"_2"COOH"#</mathjax>, 7.7</p> </li> <li> <p><strong>POPSO:</strong> <mathjax>#"piperazine-"N,N′"-bis(2-hydroxypropanesulfonic acid)"#</mathjax>, 7.85</p> </li> <li> <p><strong>HEPPSO:</strong> <mathjax>#"4-(2-hydroxyethyl)piperazine-1-(2-hydroxypropanesulfonic acid)"#</mathjax>, 7.85</p> </li> <li> <p><strong>HEPPS:</strong> <mathjax>#"3-[4-(2-hydroxyethyl)-1-piperazinyl]propanesulfonic acid"#</mathjax>, 8.00</p> </li> <li> <p><strong>Tricine:</strong> <mathjax>#N"-[tris(hydroxymethyl)methyl)]glycine"#</mathjax>, 8.15</p> </li> <li> <p><strong>Glycinamide:</strong> <mathjax>#"NH"_2"CH"_2"CONH"_2#</mathjax>, 8.20</p> </li> <li> <p><strong>Bicine:</strong> <mathjax>#N,N"-bis(2-hydroxyethyl)glycine"#</mathjax>, 8.35</p> </li> <li> <p><strong>TAPS:</strong> <mathjax>#N"-tris(hydroxymethyl)methyl-3-aminopropanesulfonic acid"#</mathjax>, 8.44</p> </li> </ol></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/262740" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-the-applications-of-a-buffer"> What are the applications of a buffer? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-buffer-ph-for-polyprotic-acids"> How do you calculate buffer pH for polyprotic acids? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-buffer-ph-for-monoprotic-acids"> How do you calculate buffer pH for monoprotic acids? </a> </div> </li> <li 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What are the different types of buffers found in the... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-carbonic-acid-bicarbonate-buffer-system-1"> What is the "Carbonic acid-bicarbonate" buffer system? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/reactions-in-solution/buffer-theory"> See all questions in Buffer Theory </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3543 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many Good's buffer agents exist?	null
2,088	acaca3e4-6ddd-11ea-90fe-ccda262736ce	https://socratic.org/questions/how-many-grams-of-sugar-would-you-need-to-add-to-water-to-make-235-grams-of-a-7-	16 grams	start physical_unit 4 4 mass g qc_end physical_unit 19 19 14 15 mass qc_end physical_unit 4 4 18 18 percent qc_end substance 11 11 qc_end end	[{"type":"physical unit","value":"Mass [OF] sugar [IN] grams"}]	[{"type":"physical unit","value":"16 grams"}]	[{"type":"physical unit","value":"Mass [OF] solution [=] \\pu{235 grams}"},{"type":"physical unit","value":"Percent [OF] sugar in solution [=] \\pu{7%}"},{"type":"substance name","value":"Water"}]	<h1 class="questionTitle" itemprop="name">How many grams of sugar would you need to add to water to make 235 grams of a 7% solution? using this formula: (Please Help!) </h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p><img alt="enter image source here" src="https://useruploads.socratic.org/hwOaUm0oSiCilnbhZGOP_Percentbymass.gif"/> </p></div> </h2> </div> </div>	16 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>A solution's <strong><a href="http://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration by mass</a></strong>, <mathjax>#"% w/w"#</mathjax>, basically tells you what mass of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> you get <strong>per</strong> <mathjax>#"100 g"#</mathjax> <strong>of solution</strong>. </p> <p>In your case, sugar is the <em>solute</em> and water is the <em><a href="http://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a></em>. A <em>solution</em> is formed when you dissolve a solute in a solvent.</p> <p>Here's how to solve this problem <em>without</em> using the formula for <a href="http://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration</a> by mass, which is given to you as </p> <blockquote> <p><mathjax>#color(blue)("% w/w" = "mass of solute"/"mass of solution" xx 100)#</mathjax></p> </blockquote> <p>You know that your target sugar solution must be <mathjax>#"7% w/w"#</mathjax>. This means that <strong>every</strong> <mathjax>#"100 g"#</mathjax> of this solution must contain <mathjax>#"7 g"#</mathjax> of sugar. </p> <p>This ratio between sugar and water is the same <strong>regardless</strong> of the mass of solution. In your case, you want the solution to have a mass of <mathjax>#"235 g"#</mathjax>. Since it must contain <mathjax>#"7 g"#</mathjax> of sugar for every <mathjax>#"100 g"#</mathjax> of solution, you can say that</p> <blockquote> <p><mathjax>#235 color(red)(cancel(color(black)("g solution"))) * overbrace("7 g sugar"/(100color(red)(cancel(color(black)("g solution")))))^(color(purple)("= 7% w/w")) = "16.45 g sugar"#</mathjax></p> </blockquote> <p>You should round this off to one <strong><a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig fig</a></strong>, since that's how many sig figs you have for the percent by mass, but I'll leave it rounded to two sig figs, just for good measure</p> <blockquote> <p><mathjax>#m_"sugar" = color(green)("16 g")#</mathjax></p> </blockquote> <p>This is what the formula for percent concentration by mass actually means. If you start with </p> <blockquote> <p><mathjax>#"% w/w" = m_"solute"/m_"solution" xx 100#</mathjax></p> </blockquote> <p>you can rearrange to solve for <mathjax>#m_"solute"#</mathjax>, which is the mass of sugar</p> <blockquote> <p><mathjax>#"% w/w" * m_"solution" = m_"solute" * 100#</mathjax></p> <p><mathjax>#m_"solute" = ("% w/w" * m_"solution")/100#</mathjax></p> </blockquote> <p>Now plug in your values to get</p> <blockquote> <p><mathjax>#m_"solute" = (7 * "235 g")/100 = color(green)("16 g")#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"16 g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>A solution's <strong><a href="http://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration by mass</a></strong>, <mathjax>#"% w/w"#</mathjax>, basically tells you what mass of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> you get <strong>per</strong> <mathjax>#"100 g"#</mathjax> <strong>of solution</strong>. </p> <p>In your case, sugar is the <em>solute</em> and water is the <em><a href="http://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a></em>. A <em>solution</em> is formed when you dissolve a solute in a solvent.</p> <p>Here's how to solve this problem <em>without</em> using the formula for <a href="http://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration</a> by mass, which is given to you as </p> <blockquote> <p><mathjax>#color(blue)("% w/w" = "mass of solute"/"mass of solution" xx 100)#</mathjax></p> </blockquote> <p>You know that your target sugar solution must be <mathjax>#"7% w/w"#</mathjax>. This means that <strong>every</strong> <mathjax>#"100 g"#</mathjax> of this solution must contain <mathjax>#"7 g"#</mathjax> of sugar. </p> <p>This ratio between sugar and water is the same <strong>regardless</strong> of the mass of solution. In your case, you want the solution to have a mass of <mathjax>#"235 g"#</mathjax>. Since it must contain <mathjax>#"7 g"#</mathjax> of sugar for every <mathjax>#"100 g"#</mathjax> of solution, you can say that</p> <blockquote> <p><mathjax>#235 color(red)(cancel(color(black)("g solution"))) * overbrace("7 g sugar"/(100color(red)(cancel(color(black)("g solution")))))^(color(purple)("= 7% w/w")) = "16.45 g sugar"#</mathjax></p> </blockquote> <p>You should round this off to one <strong><a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig fig</a></strong>, since that's how many sig figs you have for the percent by mass, but I'll leave it rounded to two sig figs, just for good measure</p> <blockquote> <p><mathjax>#m_"sugar" = color(green)("16 g")#</mathjax></p> </blockquote> <p>This is what the formula for percent concentration by mass actually means. If you start with </p> <blockquote> <p><mathjax>#"% w/w" = m_"solute"/m_"solution" xx 100#</mathjax></p> </blockquote> <p>you can rearrange to solve for <mathjax>#m_"solute"#</mathjax>, which is the mass of sugar</p> <blockquote> <p><mathjax>#"% w/w" * m_"solution" = m_"solute" * 100#</mathjax></p> <p><mathjax>#m_"solute" = ("% w/w" * m_"solution")/100#</mathjax></p> </blockquote> <p>Now plug in your values to get</p> <blockquote> <p><mathjax>#m_"solute" = (7 * "235 g")/100 = color(green)("16 g")#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many grams of sugar would you need to add to water to make 235 grams of a 7% solution? using this formula: (Please Help!) </h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p><img alt="enter image source here" src="https://useruploads.socratic.org/hwOaUm0oSiCilnbhZGOP_Percentbymass.gif"/> </p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/percent-concentration" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Concentration</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="224603" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-02-11T00:03:00" itemprop="dateCreated"> Feb 11, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"16 g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>A solution's <strong><a href="http://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration by mass</a></strong>, <mathjax>#"% w/w"#</mathjax>, basically tells you what mass of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> you get <strong>per</strong> <mathjax>#"100 g"#</mathjax> <strong>of solution</strong>. </p> <p>In your case, sugar is the <em>solute</em> and water is the <em><a href="http://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a></em>. A <em>solution</em> is formed when you dissolve a solute in a solvent.</p> <p>Here's how to solve this problem <em>without</em> using the formula for <a href="http://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration</a> by mass, which is given to you as </p> <blockquote> <p><mathjax>#color(blue)("% w/w" = "mass of solute"/"mass of solution" xx 100)#</mathjax></p> </blockquote> <p>You know that your target sugar solution must be <mathjax>#"7% w/w"#</mathjax>. This means that <strong>every</strong> <mathjax>#"100 g"#</mathjax> of this solution must contain <mathjax>#"7 g"#</mathjax> of sugar. </p> <p>This ratio between sugar and water is the same <strong>regardless</strong> of the mass of solution. In your case, you want the solution to have a mass of <mathjax>#"235 g"#</mathjax>. Since it must contain <mathjax>#"7 g"#</mathjax> of sugar for every <mathjax>#"100 g"#</mathjax> of solution, you can say that</p> <blockquote> <p><mathjax>#235 color(red)(cancel(color(black)("g solution"))) * overbrace("7 g sugar"/(100color(red)(cancel(color(black)("g solution")))))^(color(purple)("= 7% w/w")) = "16.45 g sugar"#</mathjax></p> </blockquote> <p>You should round this off to one <strong><a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig fig</a></strong>, since that's how many sig figs you have for the percent by mass, but I'll leave it rounded to two sig figs, just for good measure</p> <blockquote> <p><mathjax>#m_"sugar" = color(green)("16 g")#</mathjax></p> </blockquote> <p>This is what the formula for percent concentration by mass actually means. If you start with </p> <blockquote> <p><mathjax>#"% w/w" = m_"solute"/m_"solution" xx 100#</mathjax></p> </blockquote> <p>you can rearrange to solve for <mathjax>#m_"solute"#</mathjax>, which is the mass of sugar</p> <blockquote> <p><mathjax>#"% w/w" * m_"solution" = m_"solute" * 100#</mathjax></p> <p><mathjax>#m_"solute" = ("% w/w" * m_"solution")/100#</mathjax></p> </blockquote> <p>Now plug in your values to get</p> <blockquote> <p><mathjax>#m_"solute" = (7 * "235 g")/100 = color(green)("16 g")#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/224603" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-concentration-of-water-in-solution-be-decreased"> How can the concentration of water in solution be decreased? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-concentration-of-a-solution-be-increased"> How can the concentration of a solution be increased? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-concentration-of-a-solution-in-ppm"> How do you find the concentration of a solution in ppm? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-make-a-10-percent-solution"> How do you make a 10 percent solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-make-a-2-percent-solution"> How do you make a 2 percent solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-weight-per-volume-method-to-calculate-concentration"> What is the weight per volume method to calculate concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-percent-concentration-of-kcl-would-be-isotonic"> What percent concentration of KCl would be isotonic? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-of-sodium-chloride-in-normal-saline"> What is the percent concentration of sodium chloride in normal saline? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-of-a-6m-solution-of-nacl"> What is the percent concentration of a 6m solution of NaCl? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-formula"> What is the percent concentration formula? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/percent-concentration"> See all questions in Percent Concentration </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 30656 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many grams of sugar would you need to add to water to make 235 grams of a 7% solution? using this formula: (Please Help!)
2,089	abe1499b-6ddd-11ea-81a7-ccda262736ce	https://socratic.org/questions/how-many-grams-of-sodium-do-you-need-to-produce-18g-of-sodium-chloride	7.1 grams	start physical_unit 4 4 mass g qc_end physical_unit 13 14 10 11 mass qc_end end	[{"type":"physical unit","value":"Mass [OF] sodium [IN] grams"}]	[{"type":"physical unit","value":"7.1 grams"}]	[{"type":"physical unit","value":"Mass [OF] sodium chloride [=] \\pu{18 g}"}]	<h1 class="questionTitle" itemprop="name">How many grams of sodium do you need to produce 18g of sodium chloride?</h1>	null	7.1 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Chemical formula of sodium chloride is <mathjax>#NaCl#</mathjax><br/> Molar mass <mathjax>#:58.5g#</mathjax><br/> Molar mass of sodium <mathjax>#:23g#</mathjax><br/> Molar mass of chlorine <mathjax>#:35.5g#</mathjax></p> <p>Mass of <mathjax>#NaCl#</mathjax> we have is <mathjax>#18g#</mathjax><br/> Recall <mathjax>#n=m/M#</mathjax> <strong>(where n is number of moles, m is given mass, M is molar mass)</strong></p> <p><mathjax>#n=18/58.5#</mathjax></p> <p>Now using this for sodium</p> <p><mathjax>#18/58.5=m/23#</mathjax></p> <p><mathjax>#m= "7.1 g"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"7.1 g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Chemical formula of sodium chloride is <mathjax>#NaCl#</mathjax><br/> Molar mass <mathjax>#:58.5g#</mathjax><br/> Molar mass of sodium <mathjax>#:23g#</mathjax><br/> Molar mass of chlorine <mathjax>#:35.5g#</mathjax></p> <p>Mass of <mathjax>#NaCl#</mathjax> we have is <mathjax>#18g#</mathjax><br/> Recall <mathjax>#n=m/M#</mathjax> <strong>(where n is number of moles, m is given mass, M is molar mass)</strong></p> <p><mathjax>#n=18/58.5#</mathjax></p> <p>Now using this for sodium</p> <p><mathjax>#18/58.5=m/23#</mathjax></p> <p><mathjax>#m= "7.1 g"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many grams of sodium do you need to produce 18g of sodium chloride?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="560594" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/chirag-1"><img alt="" class="" src="https://profilepictures.socratic.org/bBbJzRtrQ8KzJdgnn3mc_1556627021124401.jpg" title=""/></a> <a class="secondContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/chirag-1"> Chirag Mehta </a>·<a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-03-01T05:58:18" itemprop="dateCreated"> Mar 1, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"7.1 g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Chemical formula of sodium chloride is <mathjax>#NaCl#</mathjax><br/> Molar mass <mathjax>#:58.5g#</mathjax><br/> Molar mass of sodium <mathjax>#:23g#</mathjax><br/> Molar mass of chlorine <mathjax>#:35.5g#</mathjax></p> <p>Mass of <mathjax>#NaCl#</mathjax> we have is <mathjax>#18g#</mathjax><br/> Recall <mathjax>#n=m/M#</mathjax> <strong>(where n is number of moles, m is given mass, M is molar mass)</strong></p> <p><mathjax>#n=18/58.5#</mathjax></p> <p>Now using this for sodium</p> <p><mathjax>#18/58.5=m/23#</mathjax></p> <p><mathjax>#m= "7.1 g"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/560594" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What is stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ab82402bf342f48d93ac6"> Question #93ac6 </a> </div> </li> <li class="relatedQuestionItem"> <div 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2,090	a9b940f8-6ddd-11ea-b9b8-ccda262736ce	https://socratic.org/questions/one-of-two-identical-balloons-contained-carbon-dioxide-co2-44-g-mol-1-and-the-ot	112.57 hours	start physical_unit 40 45 time hour qc_end physical_unit 8 8 9 10 molar_mass qc_end physical_unit 16 16 17 18 molar_mass qc_end physical_unit 25 30 22 23 time qc_end end	[{"type":"physical unit","value":"Time [OF] all of the CO2 to escape [IN] hours"}]	[{"type":"physical unit","value":"112.57 hours"}]	[{"type":"physical unit","value":"Molecular [OF] CO2 [=] \\pu{44 g/mol}"},{"type":"physical unit","value":"Molecular [OF] H2 [=] \\pu{2.0 g/mol}"},{"type":"physical unit","value":"Time [OF] all of the H2 to escape [=] \\pu{24 hours}"}]	<h1 class="questionTitle" itemprop="name">One of two identical balloons contained carbon dioxide (CO2, 44 g mol−1) and the other contained hydrogen (H2, 2.0 g mol−1). If it took 24 hours for all of the H2 to escape from its balloon, how long did it take for all of the CO2 to escape?</h1>	null	112.57 hours	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use Graham's Law:<br/> <mathjax>#r_1/r_2 = sqrtM_2/sqrtM_1 = t_2/t_1#</mathjax><br/> <em>Note: <mathjax>#r#</mathjax> is the rate of effusion, <mathjax>#M#</mathjax> is the molar mass of the gas, and <mathjax>#t#</mathjax> is the time the gas took to effuse. Also, know that this formula only works if both gasses are at the same temperature.</em></p> <p>Since molar mass and time is given, we will use the second half of the formula.</p> <p><mathjax>#sqrt("molar mass" CO_2)/sqrt("molar mass"H_2) = (time CO_2)/(time H_2)#</mathjax></p> <p><mathjax>#sqrt(44gmol^(-1) CO_2)/sqrt(2.0gmol^(-1)H_2) = (time CO_2)/(24 hours H_2)#</mathjax></p> <p><mathjax>#((24 hours H_2)sqrt(44gmol^(-1) CO_2))/sqrt(2.0g*mol^(-1)H_2) = time CO_2#</mathjax></p> <p><mathjax>#time CO_2 = 112.569978 hours#</mathjax></p> <p>Since there are only 2 significant figures the answer would be <mathjax>#110 hours#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#112.569978 hours#</mathjax> which rounds to <mathjax>#110 hours#</mathjax> due to <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use Graham's Law:<br/> <mathjax>#r_1/r_2 = sqrtM_2/sqrtM_1 = t_2/t_1#</mathjax><br/> <em>Note: <mathjax>#r#</mathjax> is the rate of effusion, <mathjax>#M#</mathjax> is the molar mass of the gas, and <mathjax>#t#</mathjax> is the time the gas took to effuse. Also, know that this formula only works if both gasses are at the same temperature.</em></p> <p>Since molar mass and time is given, we will use the second half of the formula.</p> <p><mathjax>#sqrt("molar mass" CO_2)/sqrt("molar mass"H_2) = (time CO_2)/(time H_2)#</mathjax></p> <p><mathjax>#sqrt(44gmol^(-1) CO_2)/sqrt(2.0gmol^(-1)H_2) = (time CO_2)/(24 hours H_2)#</mathjax></p> <p><mathjax>#((24 hours H_2)sqrt(44gmol^(-1) CO_2))/sqrt(2.0g*mol^(-1)H_2) = time CO_2#</mathjax></p> <p><mathjax>#time CO_2 = 112.569978 hours#</mathjax></p> <p>Since there are only 2 significant figures the answer would be <mathjax>#110 hours#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">One of two identical balloons contained carbon dioxide (CO2, 44 g mol−1) and the other contained hydrogen (H2, 2.0 g mol−1). If it took 24 hours for all of the H2 to escape from its balloon, how long did it take for all of the CO2 to escape?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/kinetic-theory-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Kinetic Theory of Gases</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="410286" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/tartar-c"><img alt="" class="" src="https://profilepictures.socratic.org/m0AqR4w7RXSxm9gd4o1l_cool-wallpaper-16.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/tartar-c"> Tartar C. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-21T03:52:42" itemprop="dateCreated"> Apr 21, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#112.569978 hours#</mathjax> which rounds to <mathjax>#110 hours#</mathjax> due to <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use Graham's Law:<br/> <mathjax>#r_1/r_2 = sqrtM_2/sqrtM_1 = t_2/t_1#</mathjax><br/> <em>Note: <mathjax>#r#</mathjax> is the rate of effusion, <mathjax>#M#</mathjax> is the molar mass of the gas, and <mathjax>#t#</mathjax> is the time the gas took to effuse. Also, know that this formula only works if both gasses are at the same temperature.</em></p> <p>Since molar mass and time is given, we will use the second half of the formula.</p> <p><mathjax>#sqrt("molar mass" CO_2)/sqrt("molar mass"H_2) = (time CO_2)/(time H_2)#</mathjax></p> <p><mathjax>#sqrt(44gmol^(-1) CO_2)/sqrt(2.0gmol^(-1)H_2) = (time CO_2)/(24 hours H_2)#</mathjax></p> <p><mathjax>#((24 hours H_2)sqrt(44gmol^(-1) CO_2))/sqrt(2.0g*mol^(-1)H_2) = time CO_2#</mathjax></p> <p><mathjax>#time CO_2 = 112.569978 hours#</mathjax></p> <p>Since there are only 2 significant figures the answer would be <mathjax>#110 hours#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/410286" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-kinetic-molecular-theory-explain-gas-laws"> How does kinetic molecular theory explain gas laws? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/garaham-s-law-of-diffusion-1"> What is Graham's Law of Effusion? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-examples-of-the-kinetic-theory-of-gases"> What are some examples of the kinetic theory of gases? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-relationship-between-charles-law-and-the-kinetic-theory-of-gases"> What is the relationship between Charles law and the kinetic theory of gases? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-does-the-kinetic-theory-apply-to-gases"> Why does the kinetic theory apply to gases? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-average-kinetic-energy-of-the-molecules-in-a-gas-at-273k"> What is the average kinetic energy of the molecules in a gas at 273K? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-absolute-temperature-of-a-substance-relate-to-the-average-kinetic-e"> How does the absolute temperature of a substance relate to the average kinetic energy of its molecules? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-a-gas-expand-according-to-the-kinetic-molecular-theory"> How does a gas expand according to the kinetic molecular theory? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/according-to-kinetic-molecular-theory-how-are-gases-compared-with-liquids-and-so"> According to kinetic molecular theory, how are gases compared with liquids and solids? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/use-the-terms-volume-and-density-to-compare-gases-liquids-and-solids-in-terms-of"> Use the terms volume and density to compare gases, liquids and solids in terms of the kinetic... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/kinetic-theory-of-gases"> See all questions in Kinetic Theory of Gases </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 5292 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	One of two identical balloons contained carbon dioxide (CO2, 44 g mol−1) and the other contained hydrogen (H2, 2.0 g mol−1). If it took 24 hours for all of the H2 to escape from its balloon, how long did it take for all of the CO2 to escape?	null
2,091	ab5332da-6ddd-11ea-8cff-ccda262736ce	https://socratic.org/questions/what-is-the-concentration-of-sodium-ions-in-a-2-2x10-0-mol-l-solution-of-sodium-	4.4 × 10^0 mol/L	start physical_unit 5 6 concentration mol/l qc_end end	[{"type":"physical unit","value":"Concentration [OF] sodium ions [IN] mol/L"}]	[{"type":"physical unit","value":"4.4 × 10^0 mol/L"}]	[{"type":"physical unit","value":"Concentration [OF] sodium carbonate [=] \\pu{2.2 × 10^0 mol/L}"}]	<h1 class="questionTitle" itemprop="name">What is the concentration of sodium ions in a (2.2x10^0) mol/L solution of sodium carbonate? (answer to 2 s.d. in mol/L}</h1>	null	4.4 × 10^0 mol/L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Sodium carbonate, <mathjax>#"Na"_color(red)(2)"CO"_3#</mathjax>, is an ionic compound that, as its name and chemical formula suggest, contains sodium cations and carbonate anions in a <mathjax>#color(red)(2):1#</mathjax> ratio. </p> <p>This salt is <strong>soluble</strong> in water, which means that every time <mathjax>#1#</mathjax> <strong>mole</strong> of sodium carbonate dissolves in water, it produces <mathjax>#color(red)(2)#</mathjax> <strong>moles</strong> of sodium cations and <mathjax>#1#</mathjax> <strong>mole</strong> of carbonate anions in aqueous solution. </p> <blockquote> <p><mathjax>#"Na"_ color(red)(2)"CO"_ (3(aq)) -> color(red)(2)"Na"_ ((aq))^(+) + "CO"_ (3(aq))^(2-)#</mathjax></p> </blockquote> <p>This tells you that a sodium carbonate solution will always have</p> <blockquote> <p><mathjax>#["Na"^(+)] = color(red)(2) * ["Na"_ 2"CO"_3]#</mathjax></p> </blockquote> <p>In your case, the solution will have</p> <blockquote> <p><mathjax>#["Na"^(+)] = color(red)(2) * 2.2 * 10^(0)#</mathjax> <mathjax>#"mol L"^(-1)#</mathjax></p> <p><mathjax>#color(darkgreen)(ul(color(black)(["Na"^(+)] =4.4 * 10^0color(white)(.)"mol L"^(-1))))#</mathjax></p> </blockquote> <p>The answer is rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#4.4 * 10^0"mol L"^(-1)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Sodium carbonate, <mathjax>#"Na"_color(red)(2)"CO"_3#</mathjax>, is an ionic compound that, as its name and chemical formula suggest, contains sodium cations and carbonate anions in a <mathjax>#color(red)(2):1#</mathjax> ratio. </p> <p>This salt is <strong>soluble</strong> in water, which means that every time <mathjax>#1#</mathjax> <strong>mole</strong> of sodium carbonate dissolves in water, it produces <mathjax>#color(red)(2)#</mathjax> <strong>moles</strong> of sodium cations and <mathjax>#1#</mathjax> <strong>mole</strong> of carbonate anions in aqueous solution. </p> <blockquote> <p><mathjax>#"Na"_ color(red)(2)"CO"_ (3(aq)) -> color(red)(2)"Na"_ ((aq))^(+) + "CO"_ (3(aq))^(2-)#</mathjax></p> </blockquote> <p>This tells you that a sodium carbonate solution will always have</p> <blockquote> <p><mathjax>#["Na"^(+)] = color(red)(2) * ["Na"_ 2"CO"_3]#</mathjax></p> </blockquote> <p>In your case, the solution will have</p> <blockquote> <p><mathjax>#["Na"^(+)] = color(red)(2) * 2.2 * 10^(0)#</mathjax> <mathjax>#"mol L"^(-1)#</mathjax></p> <p><mathjax>#color(darkgreen)(ul(color(black)(["Na"^(+)] =4.4 * 10^0color(white)(.)"mol L"^(-1))))#</mathjax></p> </blockquote> <p>The answer is rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the concentration of sodium ions in a (2.2x10^0) mol/L solution of sodium carbonate? (answer to 2 s.d. in mol/L}</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="431145" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-29T00:54:33" itemprop="dateCreated"> May 29, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#4.4 * 10^0"mol L"^(-1)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Sodium carbonate, <mathjax>#"Na"_color(red)(2)"CO"_3#</mathjax>, is an ionic compound that, as its name and chemical formula suggest, contains sodium cations and carbonate anions in a <mathjax>#color(red)(2):1#</mathjax> ratio. </p> <p>This salt is <strong>soluble</strong> in water, which means that every time <mathjax>#1#</mathjax> <strong>mole</strong> of sodium carbonate dissolves in water, it produces <mathjax>#color(red)(2)#</mathjax> <strong>moles</strong> of sodium cations and <mathjax>#1#</mathjax> <strong>mole</strong> of carbonate anions in aqueous solution. </p> <blockquote> <p><mathjax>#"Na"_ color(red)(2)"CO"_ (3(aq)) -> color(red)(2)"Na"_ ((aq))^(+) + "CO"_ (3(aq))^(2-)#</mathjax></p> </blockquote> <p>This tells you that a sodium carbonate solution will always have</p> <blockquote> <p><mathjax>#["Na"^(+)] = color(red)(2) * ["Na"_ 2"CO"_3]#</mathjax></p> </blockquote> <p>In your case, the solution will have</p> <blockquote> <p><mathjax>#["Na"^(+)] = color(red)(2) * 2.2 * 10^(0)#</mathjax> <mathjax>#"mol L"^(-1)#</mathjax></p> <p><mathjax>#color(darkgreen)(ul(color(black)(["Na"^(+)] =4.4 * 10^0color(white)(.)"mol L"^(-1))))#</mathjax></p> </blockquote> <p>The answer is rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/431145" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? 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(answer to 2 s.d. in mol/L}	null
2,092	a9122226-6ddd-11ea-a351-ccda262736ce	https://socratic.org/questions/what-is-the-density-of-nitrogen-gas-at-90-5-kpa-and-43-0-c	0.97 g/L	start physical_unit 5 6 density g/l qc_end physical_unit 5 6 8 9 pressure qc_end physical_unit 5 6 11 12 temperature qc_end end	[{"type":"physical unit","value":"Density [OF] nitrogen gas [IN] g/L"}]	[{"type":"physical unit","value":"0.97 g/L"}]	[{"type":"physical unit","value":"Pressure [OF] nitrogen gas [=] \\pu{90.5 kPa}"},{"type":"physical unit","value":"Temperature [OF] nitrogen gas [=] \\pu{43.0 ℃}"}]	<h1 class="questionTitle" itemprop="name">What is the density of nitrogen gas at 90.5 kPa and 43.0 °C? </h1>	null	0.97 g/L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Known:<br/> P= 90.5 kPa = 90500 Pa<br/> T= <mathjax>#43^o#</mathjax> C = 316.15 K</p> <p>We can safely assume that when working with gases, we will be using the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a>. In this case, we combine the ideal gas formula with <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> formula and the <a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a> formula:</p> <p><mathjax>#PV=nRT#</mathjax></p> <p><mathjax>#n=m/M#</mathjax></p> <p><mathjax>#d=m/V#</mathjax><br/> <mathjax>#m=dV#</mathjax></p> <p><mathjax>#n=(dV)/M#</mathjax></p> <p><mathjax>#PV=(dV)/MRT#</mathjax></p> <p><mathjax>#PVM=dVRT#</mathjax></p> <p><mathjax>#(PVM)/(VRT)=d#</mathjax></p> <p><mathjax>#(PM)/(RT)=d#</mathjax></p> <p>Calculate molar mass of <mathjax>#N_2#</mathjax>:</p> <p><mathjax>#M=14.012#</mathjax><br/> <mathjax>#=28.02#</mathjax></p> <p>Sub the values we have in to get density:</p> <p><mathjax>#(PM)/(RT) = d#</mathjax></p> <p><mathjax>#(90500 Pa28.02g·mol^"-1")/(8.314 Pa·m^3K^"-1"mol^"-1"*316.15 K) = d#</mathjax></p> <p><mathjax>#964.75g/m^3 = d#</mathjax></p> <p><strong>Note: the value of R, the gas constant, changes depending on the units you use for other measurements. This is why the answer was in <mathjax>#g/m^3#</mathjax> and has to be converted to <mathjax>#g/L#</mathjax>. It is VERY IMPORTANT to choose the right R value or to adjust other units to accommodate the value of R you picked.</strong> </p> <p>(See <a href="http://chem.libretexts.org/Core/Physical_and_Theoretical_Chemistry/Physical_Properties_of_Matter/States_of_Matter/Gases/Gas_Laws/The_Ideal_Gas_Law#The_Gas_Constant_(R" rel="nofollow" target="_blank">http://chem.libretexts.org/Core/Physical_and_Theoretical_Chemistry/Physical_Properties_of_Matter/States_of_Matter/Gases/Gas_Laws/The_Ideal_Gas_Law#The_Gas_Constant_(R</a>))</p> <p><mathjax>#(964.75 g/m^3)/(1000 L/m^3) = d#</mathjax></p> <p><mathjax>#0.965 g/L = d#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.965 g/L</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Known:<br/> P= 90.5 kPa = 90500 Pa<br/> T= <mathjax>#43^o#</mathjax> C = 316.15 K</p> <p>We can safely assume that when working with gases, we will be using the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a>. In this case, we combine the ideal gas formula with <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> formula and the <a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a> formula:</p> <p><mathjax>#PV=nRT#</mathjax></p> <p><mathjax>#n=m/M#</mathjax></p> <p><mathjax>#d=m/V#</mathjax><br/> <mathjax>#m=dV#</mathjax></p> <p><mathjax>#n=(dV)/M#</mathjax></p> <p><mathjax>#PV=(dV)/MRT#</mathjax></p> <p><mathjax>#PVM=dVRT#</mathjax></p> <p><mathjax>#(PVM)/(VRT)=d#</mathjax></p> <p><mathjax>#(PM)/(RT)=d#</mathjax></p> <p>Calculate molar mass of <mathjax>#N_2#</mathjax>:</p> <p><mathjax>#M=14.012#</mathjax><br/> <mathjax>#=28.02#</mathjax></p> <p>Sub the values we have in to get density:</p> <p><mathjax>#(PM)/(RT) = d#</mathjax></p> <p><mathjax>#(90500 Pa28.02g·mol^"-1")/(8.314 Pa·m^3K^"-1"mol^"-1"*316.15 K) = d#</mathjax></p> <p><mathjax>#964.75g/m^3 = d#</mathjax></p> <p><strong>Note: the value of R, the gas constant, changes depending on the units you use for other measurements. This is why the answer was in <mathjax>#g/m^3#</mathjax> and has to be converted to <mathjax>#g/L#</mathjax>. It is VERY IMPORTANT to choose the right R value or to adjust other units to accommodate the value of R you picked.</strong> </p> <p>(See <a href="http://chem.libretexts.org/Core/Physical_and_Theoretical_Chemistry/Physical_Properties_of_Matter/States_of_Matter/Gases/Gas_Laws/The_Ideal_Gas_Law#The_Gas_Constant_(R" rel="nofollow" target="_blank">http://chem.libretexts.org/Core/Physical_and_Theoretical_Chemistry/Physical_Properties_of_Matter/States_of_Matter/Gases/Gas_Laws/The_Ideal_Gas_Law#The_Gas_Constant_(R</a>))</p> <p><mathjax>#(964.75 g/m^3)/(1000 L/m^3) = d#</mathjax></p> <p><mathjax>#0.965 g/L = d#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the density of nitrogen gas at 90.5 kPa and 43.0 °C? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/gas-laws" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Laws</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="322249" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/yourfavoriteweapon"><img alt="" class="" src="https://profilepictures.socratic.org/GhCbxUPEQHmxTaQrnx5O_Japanesewoods.png" title=""/></a> <a class="secondContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/yourfavoriteweapon"> yourfavoriteweapon </a>·<a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-10-16T03:21:50" itemprop="dateCreated"> Oct 16, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.965 g/L</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Known:<br/> P= 90.5 kPa = 90500 Pa<br/> T= <mathjax>#43^o#</mathjax> C = 316.15 K</p> <p>We can safely assume that when working with gases, we will be using the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a>. In this case, we combine the ideal gas formula with <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> formula and the <a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a> formula:</p> <p><mathjax>#PV=nRT#</mathjax></p> <p><mathjax>#n=m/M#</mathjax></p> <p><mathjax>#d=m/V#</mathjax><br/> <mathjax>#m=dV#</mathjax></p> <p><mathjax>#n=(dV)/M#</mathjax></p> <p><mathjax>#PV=(dV)/MRT#</mathjax></p> <p><mathjax>#PVM=dVRT#</mathjax></p> <p><mathjax>#(PVM)/(VRT)=d#</mathjax></p> <p><mathjax>#(PM)/(RT)=d#</mathjax></p> <p>Calculate molar mass of <mathjax>#N_2#</mathjax>:</p> <p><mathjax>#M=14.012#</mathjax><br/> <mathjax>#=28.02#</mathjax></p> <p>Sub the values we have in to get density:</p> <p><mathjax>#(PM)/(RT) = d#</mathjax></p> <p><mathjax>#(90500 Pa28.02g·mol^"-1")/(8.314 Pa·m^3K^"-1"mol^"-1"*316.15 K) = d#</mathjax></p> <p><mathjax>#964.75g/m^3 = d#</mathjax></p> <p><strong>Note: the value of R, the gas constant, changes depending on the units you use for other measurements. This is why the answer was in <mathjax>#g/m^3#</mathjax> and has to be converted to <mathjax>#g/L#</mathjax>. It is VERY IMPORTANT to choose the right R value or to adjust other units to accommodate the value of R you picked.</strong> </p> <p>(See <a href="http://chem.libretexts.org/Core/Physical_and_Theoretical_Chemistry/Physical_Properties_of_Matter/States_of_Matter/Gases/Gas_Laws/The_Ideal_Gas_Law#The_Gas_Constant_(R" rel="nofollow" target="_blank">http://chem.libretexts.org/Core/Physical_and_Theoretical_Chemistry/Physical_Properties_of_Matter/States_of_Matter/Gases/Gas_Laws/The_Ideal_Gas_Law#The_Gas_Constant_(R</a>))</p> <p><mathjax>#(964.75 g/m^3)/(1000 L/m^3) = d#</mathjax></p> <p><mathjax>#0.965 g/L = d#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/322249" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-boyles-law-relate-to-breathing"> How does Boyle's law relate to breathing? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/in-avogadro-s-law-what-would-happen-to-v-if-n-is-increased-decreased-and-what-wo"> In Avogadro's Law what would happen to V if N is increased/decreased? 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If the gas is compressed to 23.52 L and the... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-the-r-stand-for-in-the-ideal-gas-law-pv-nrt"> What does the R stand for in the ideal gas law (PV=nRT)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-mass-of-a-gas-that-occupies-48-9-liters-has-a-pressure-of-724-torr-a"> What is the mass of a gas that occupies 48.9 liters, has a pressure of 724 torr, a temperature... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-a-sample-of-neon-gas-occupies-a-volume-of-2-8l-at-1-8-atm-what-will-its-volum"> If a sample of neon gas occupies a volume of 2.8L at 1.8 atm. what will its volume be at 1.2 atm? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/gas-laws"> See all questions in Gas Laws </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 13316 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the density of nitrogen gas at 90.5 kPa and 43.0 °C?	null
2,093	a9a84be8-6ddd-11ea-a2bc-ccda262736ce	https://socratic.org/questions/what-is-the-mass-of-3-543-10-23-atoms-of-magnesium	14.3 g	start physical_unit 10 10 mass g qc_end end	[{"type":"physical unit","value":"Mass [OF] magnesium [IN] g"}]	[{"type":"physical unit","value":"14.3 g"}]	[{"type":"physical unit","value":"Number [OF] magnesium atoms [=] \\pu{3.543 × 10^23}"}]	<h1 class="questionTitle" itemprop="name">What is the mass of #3.543 * 10^23# atoms of magnesium?</h1>	null	14.3 g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Molar mass of <mathjax>#"Mg"#</mathjax> is <mathjax>#"24.3 g/mol"#</mathjax></p> <p>It means <mathjax>#"1 mol"#</mathjax> of <mathjax>#"Mg"#</mathjax> atoms weigh <mathjax>#"24.3 g"#</mathjax></p> <p>Mass of <mathjax>#3.543 × 10^23\ "Mg"#</mathjax> atoms is</p> <p><mathjax>#3.543 × cancel(10^23\ "atoms") × (1 cancel"mol")/(6.022 × cancel(10^23\ "atoms")) × 24.3\ "g"/cancel"mol" = "14.3 g"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"14.3 g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Molar mass of <mathjax>#"Mg"#</mathjax> is <mathjax>#"24.3 g/mol"#</mathjax></p> <p>It means <mathjax>#"1 mol"#</mathjax> of <mathjax>#"Mg"#</mathjax> atoms weigh <mathjax>#"24.3 g"#</mathjax></p> <p>Mass of <mathjax>#3.543 × 10^23\ "Mg"#</mathjax> atoms is</p> <p><mathjax>#3.543 × cancel(10^23\ "atoms") × (1 cancel"mol")/(6.022 × cancel(10^23\ "atoms")) × 24.3\ "g"/cancel"mol" = "14.3 g"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the mass of #3.543 * 10^23# atoms of magnesium?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="590273" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/junaid-mirza"><img alt="" class="" src="https://profilepictures.socratic.org/BBeNx7NTQ7WmDQKll8wN_BDC9EDF4-5DCB-440D-8ADC-ADACE2966216.jpeg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/junaid-mirza"> Junaid Mirza </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-04-07T19:05:49" itemprop="dateCreated"> Apr 7, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"14.3 g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Molar mass of <mathjax>#"Mg"#</mathjax> is <mathjax>#"24.3 g/mol"#</mathjax></p> <p>It means <mathjax>#"1 mol"#</mathjax> of <mathjax>#"Mg"#</mathjax> atoms weigh <mathjax>#"24.3 g"#</mathjax></p> <p>Mass of <mathjax>#3.543 × 10^23\ "Mg"#</mathjax> atoms is</p> <p><mathjax>#3.543 × cancel(10^23\ "atoms") × (1 cancel"mol")/(6.022 × cancel(10^23\ "atoms")) × 24.3\ "g"/cancel"mol" = "14.3 g"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/590273" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 15471 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the mass of #3.543 * 10^23# atoms of magnesium?	null
2,094	ab7ae762-6ddd-11ea-86cd-ccda262736ce	https://socratic.org/questions/a-hydrocarbon-is-composed-of-85-57-carbon-and-14-43-hydrogen-and-a-molar-mass-of	C2H4	start chemical_formula qc_end physical_unit 1 1 15 16 molar_mass qc_end end	[{"type":"other","value":"Chemical Formula [OF] hydrocarbon [IN] molecular"}]	[{"type":"chemical equation","value":"C2H4"}]	[{"type":"physical unit","value":"Percent [OF] carbon in hydrocarbon [=] \\pu{85.57%}"},{"type":"physical unit","value":"Percen [OF] hydrogen in hydrocarbon [=] \\pu{14.43%}"},{"type":"physical unit","value":"Molar mass [OF] hydrocarbon [=] \\pu{28.06 g/mol}"}]	<h1 class="questionTitle" itemprop="name">A hydrocarbon is composed of 85.57% carbon and 14.43% hydrogen and a molar mass of 28.06 mol. What is the molecular formula?</h1>	null	C2H4	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>As with all these problems, we assume an <mathjax>#100g#</mathjax> mass of compound.</p> <p>And thus...........</p> <p><mathjax>#"Moles of carbon"=(85.57g)/(12.011gmol^-1)=7.12mol#</mathjax></p> <p><mathjax>#"Moles of hydrogen"=(14.43g)/(1.00794gmol^-1)=14.32mol#</mathjax></p> <p>We divide thru by the smallest molar quantity (that of carbon) to get an <mathjax>#"empirical formula"#</mathjax> of <mathjax>#CH_2#</mathjax>.</p> <p>Now it is a fact that the molecular formula is a whole number multiple of the empirical formula:</p> <p>i.e. <mathjax>#28.06gmol^-1=nxx(12.011+2xx1.00794)g*mol^-1#</mathjax>.</p> <p>Clearly, <mathjax>#n=2#</mathjax>, and the <mathjax>#"molecular formula"#</mathjax> is <mathjax>#C_2H_4#</mathjax>. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The stuff is <mathjax>#"ethylene"#</mathjax>, <mathjax>#H_2C=CH_2#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>As with all these problems, we assume an <mathjax>#100g#</mathjax> mass of compound.</p> <p>And thus...........</p> <p><mathjax>#"Moles of carbon"=(85.57g)/(12.011gmol^-1)=7.12mol#</mathjax></p> <p><mathjax>#"Moles of hydrogen"=(14.43g)/(1.00794gmol^-1)=14.32mol#</mathjax></p> <p>We divide thru by the smallest molar quantity (that of carbon) to get an <mathjax>#"empirical formula"#</mathjax> of <mathjax>#CH_2#</mathjax>.</p> <p>Now it is a fact that the molecular formula is a whole number multiple of the empirical formula:</p> <p>i.e. <mathjax>#28.06gmol^-1=nxx(12.011+2xx1.00794)g*mol^-1#</mathjax>.</p> <p>Clearly, <mathjax>#n=2#</mathjax>, and the <mathjax>#"molecular formula"#</mathjax> is <mathjax>#C_2H_4#</mathjax>. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A hydrocarbon is composed of 85.57% carbon and 14.43% hydrogen and a molar mass of 28.06 mol. What is the molecular formula?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="352877" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-12-16T17:48:50" itemprop="dateCreated"> Dec 16, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The stuff is <mathjax>#"ethylene"#</mathjax>, <mathjax>#H_2C=CH_2#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>As with all these problems, we assume an <mathjax>#100g#</mathjax> mass of compound.</p> <p>And thus...........</p> <p><mathjax>#"Moles of carbon"=(85.57g)/(12.011gmol^-1)=7.12mol#</mathjax></p> <p><mathjax>#"Moles of hydrogen"=(14.43g)/(1.00794gmol^-1)=14.32mol#</mathjax></p> <p>We divide thru by the smallest molar quantity (that of carbon) to get an <mathjax>#"empirical formula"#</mathjax> of <mathjax>#CH_2#</mathjax>.</p> <p>Now it is a fact that the molecular formula is a whole number multiple of the empirical formula:</p> <p>i.e. <mathjax>#28.06gmol^-1=nxx(12.011+2xx1.00794)g*mol^-1#</mathjax>.</p> <p>Clearly, <mathjax>#n=2#</mathjax>, and the <mathjax>#"molecular formula"#</mathjax> is <mathjax>#C_2H_4#</mathjax>. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/352877" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? 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</a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-empirical-formula-not-double-that-of-the-monosaccharides"> Why is the empirical formula not double that of the monosaccharides? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5331180502bf342f40b5c3b5"> Question #5c3b5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-molecular-formula-represents-a-carbohydrate"> What molecular formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-of-vinegar"> What is the molecular formula of vinegar? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/empirical-and-molecular-formulas"> See all questions in Empirical and Molecular Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 11207 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A hydrocarbon is composed of 85.57% carbon and 14.43% hydrogen and a molar mass of 28.06 mol. What is the molecular formula?	null
2,095	a9e1c888-6ddd-11ea-9e03-ccda262736ce	https://socratic.org/questions/what-is-the-ph-of-a-solution-that-has-a-hydronium-ion-concentration-of-0-050-m	1.30	start physical_unit 6 6 ph none qc_end physical_unit 10 11 14 15 concentration qc_end end	[{"type":"physical unit","value":"pH [OF] the solution"}]	[{"type":"physical unit","value":"1.30"}]	[{"type":"physical unit","value":"Concentration [OF] hydronium ion [=] \\pu{0.050 M}"}]	<h1 class="questionTitle" itemprop="name">What is the pH of a solution that has a hydronium ion concentration of 0.050 M?</h1>	null	1.30	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The pH can be found using the formula below:</p> <p><img alt="www.wikihow.com" src="https://useruploads.socratic.org/PRdlFSc8TJGGcmPawqmH_aid1506663-728px-Calculate-a-pH-Step-2-Version-2.jpg"/> </p> <p>Take the -logarithm of the concentration of hydronium ions that are in the solution:</p> <p><mathjax>#pH = -log (0.050M) = 1.30#</mathjax> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>That solution has a <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> of 1.30</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The pH can be found using the formula below:</p> <p><img alt="www.wikihow.com" src="https://useruploads.socratic.org/PRdlFSc8TJGGcmPawqmH_aid1506663-728px-Calculate-a-pH-Step-2-Version-2.jpg"/> </p> <p>Take the -logarithm of the concentration of hydronium ions that are in the solution:</p> <p><mathjax>#pH = -log (0.050M) = 1.30#</mathjax> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the pH of a solution that has a hydronium ion concentration of 0.050 M?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/the-ph-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">pH</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="295976" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/kayla-14"><img alt="" class="" src="https://profilepictures.socratic.org/OvMTWaamQPWcqLIkUNnG_793604964071127.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/kayla-14"> Kayla </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-08-06T01:08:05" itemprop="dateCreated"> Aug 6, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>That solution has a <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> of 1.30</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The pH can be found using the formula below:</p> <p><img alt="www.wikihow.com" src="https://useruploads.socratic.org/PRdlFSc8TJGGcmPawqmH_aid1506663-728px-Calculate-a-pH-Step-2-Version-2.jpg"/> </p> <p>Take the -logarithm of the concentration of hydronium ions that are in the solution:</p> <p><mathjax>#pH = -log (0.050M) = 1.30#</mathjax> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/295976" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-pka"> How do you determine pH from pKa? 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</a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ph-scale-0-14"> Why is the pH scale 0-14? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-ph-the-measure-of-the-hydrogen-ion-concentration"> Is pH a measure of the hydrogen ion concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-solubility-affect-ph"> How does solubility affect pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-ph-relate-to-pka-in-a-titration"> How does pH relate to pKa in a titration? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/the-ph-concept"> See all questions in pH </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2861 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the pH of a solution that has a hydronium ion concentration of 0.050 M?	null
2,096	aa890f80-6ddd-11ea-89a9-ccda262736ce	https://socratic.org/questions/56391b0c11ef6b7520036ea8	27.71 grams	start physical_unit 3 3 mass g qc_end physical_unit 13 13 10 11 volume qc_end c_other STP qc_end substance 7 7 qc_end end	[{"type":"physical unit","value":"Mass [OF] calcium [IN] grams"}]	[{"type":"physical unit","value":"27.71 grams"}]	[{"type":"physical unit","value":"Volume [OF] hydrogen [=] \\pu{15.7 L}"},{"type":"other","value":"STP"},{"type":"substance name","value":"Water"}]	<h1 class="questionTitle" itemprop="name">What mass of calcium when reacted with water will produce 15.7 L of hydrogen at STP?</h1>	null	27.71 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Now it is a fact that 1 mol of gas has a volume of <mathjax>#22.4* dm^3#</mathjax> at STP assuming ideal behaviour. According to the reaction above, 1 mol of calcium metal (<mathjax>#40.08g#</mathjax>) should produce <mathjax>#22.4L#</mathjax> gas. </p> <p>By this <a href="http://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>, <mathjax>#(15.7Lxx40.08g mol^(-1))/(22.4Lmol^-1)#</mathjax> <mathjax>#Ca#</mathjax> were used (about 32 g?). (NB <mathjax>#1L=1*dm^3#</mathjax>)</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Ca(s) + 2H_2O(l) rarr Ca(OH)_2(aq) + H_2(g)uarr#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Now it is a fact that 1 mol of gas has a volume of <mathjax>#22.4* dm^3#</mathjax> at STP assuming ideal behaviour. According to the reaction above, 1 mol of calcium metal (<mathjax>#40.08g#</mathjax>) should produce <mathjax>#22.4L#</mathjax> gas. </p> <p>By this <a href="http://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>, <mathjax>#(15.7Lxx40.08g mol^(-1))/(22.4Lmol^-1)#</mathjax> <mathjax>#Ca#</mathjax> were used (about 32 g?). (NB <mathjax>#1L=1*dm^3#</mathjax>)</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What mass of calcium when reacted with water will produce 15.7 L of hydrogen at STP?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/stoichiometry-involving-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="182604" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-03T21:22:17" itemprop="dateCreated"> Nov 3, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Ca(s) + 2H_2O(l) rarr Ca(OH)_2(aq) + H_2(g)uarr#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Now it is a fact that 1 mol of gas has a volume of <mathjax>#22.4* dm^3#</mathjax> at STP assuming ideal behaviour. According to the reaction above, 1 mol of calcium metal (<mathjax>#40.08g#</mathjax>) should produce <mathjax>#22.4L#</mathjax> gas. </p> <p>By this <a href="http://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>, <mathjax>#(15.7Lxx40.08g mol^(-1))/(22.4Lmol^-1)#</mathjax> <mathjax>#Ca#</mathjax> were used (about 32 g?). (NB <mathjax>#1L=1*dm^3#</mathjax>)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/182604" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="182623" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-03T22:48:42" itemprop="dateCreated"> Nov 3, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"27.7 g Ca"#</mathjax> are required to produce <mathjax>#"15.7 L H"_2"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>Balanced Equation</strong></p> <p><mathjax>#"Ca(s)" + 2"H"_2"O"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"Ca(OH)"_2("s") + "H"_2("g")"#</mathjax></p> <p><mathjax>#"STP"#</mathjax> is <mathjax>#"273.15 K"#</mathjax> and <mathjax>#"100 kPa"#</mathjax>.</p> <p>The molar volume of a gas at <mathjax>#"273.15 K"#</mathjax> and <mathjax>#"100 kPa"#</mathjax> is <mathjax>#"22.710 mol/L"#</mathjax></p> <p>Molar mass of <mathjax>#"Ca = 40.078 g/mol"#</mathjax> (atomic weight in g/mol)</p> <p><strong>The process:</strong></p> <p><mathjax>#color(red)("L H"_2")#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(red)("mol H"_2")#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(green)("mol Ca")#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(blue)("mass Ca")#</mathjax></p> <p><strong>~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~</strong> <br/> <strong>~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~</strong><br/> <strong>~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~</strong></p> <p><mathjax>#color(red)("L H"_2")#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(red)("mol H"_2")#</mathjax></p> <p>First determine moles <mathjax>#"H"_2"#</mathjax> by dividing the given volume by the molar volume <mathjax>#("22.710 L/mol")#</mathjax>. I prefer to divide by multiplying by the reciprocal of its molar volume <mathjax>#("1 mol/22.710 L")#</mathjax>. </p> <p><mathjax>#15.7color(red)cancel(color(black)("L H"_2))xx(1"mol H"_2)/(22.710color(red)cancel(color(black)("L")))="0.6913 mol H"_2"#</mathjax></p> <p><mathjax>#color(red)("mol H"_2")#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(green)("mol Ca")#</mathjax></p> <p>To get mol <mathjax>#"Ca"#</mathjax>, multiply mol <mathjax>#"H"_2"#</mathjax> by the mole ratio between <mathjax>#"Ca"#</mathjax> and <mathjax>#"H"_2"#</mathjax> from the balanced equation, with <mathjax>#"Ca"#</mathjax> in the numerator. </p> <p><mathjax>#0.6913color(red)cancel(color(black)("mol H"_2))xx(1"mol Ca")/(1color(red)cancel(color(black)("mol H")))="0.6913 mol Ca"#</mathjax></p> <p><mathjax>#color(green)("mol Ca")#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(blue)("mass Ca")#</mathjax></p> <p>To determine mass of <mathjax>#"Ca"#</mathjax> multiply times its molar mass. </p> <p><mathjax>#0.6913color(red)cancel(color(black)("mol Ca"))xx(40.078"g Ca")/(1color(red)cancel(color(black)("mol Ca")))="27.7 g Ca"#</mathjax> (rounded to three significant figures)</p> <p><strong>You can put all three steps together into one equation.</strong></p> <p><mathjax>#15.7color(red)cancel(color(black)("L H"_2))xx(1color(red)cancel(color(black)("mol H"_2)))/(22.710color(red)cancel(color(black)("L H"_2)))xx(1color(red)cancel(color(black)("mol Ca")))/(1color(red)cancel(color(black)("mol H"_2)))xx(40.078"g Ca")/(1color(red)cancel(color(black)("mol Ca")))="27.7 g Ca"#</mathjax> (rounded to three significant figures)</p> <p><strong>Note:</strong> If your teacher is still using STP as <mathjax>#0^@"C"#</mathjax> and <mathjax>#"1 atm"#</mathjax>, substitute <mathjax>#"22.414 L/mol"#</mathjax> for <mathjax>#"22.710 L/mol"#</mathjax>.</p> <p>The mass of <mathjax>#"Ca"#</mathjax> would be <mathjax>#"28.1 g Ca"#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/182623" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-apply-gas-stoichiometry"> How do you apply gas stoichiometry? 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</a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-2-00-g-mixture-of-na-and-ca-reat-with-water-1-164-l-hydrogen-was-produced-a"> When 2.00 g mixture of Na and Ca reat with water, 1.164 L hydrogen was produced at 300.0 K and... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/stoichiometry-involving-gases"> See all questions in Gas Stoichiometry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2538 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What mass of calcium when reacted with water will produce 15.7 L of hydrogen at STP?	null
2,097	ad24fbf9-6ddd-11ea-9f2e-ccda262736ce	https://socratic.org/questions/58b3448cb72cff77f3400934	8.31 × 10^22	start physical_unit 2 3 number none qc_end physical_unit 13 13 9 10 mass qc_end end	[{"type":"physical unit","value":"Number [OF] oxygen molecules"}]	[{"type":"physical unit","value":"8.31 × 10^22"}]	[{"type":"physical unit","value":"Mass [OF] sulfur [=] \\pu{4.42 g}"}]	<h1 class="questionTitle" itemprop="name">How many oxygen molecules are required to oxidize a #4.42*g# mass of sulfur?</h1>	null	8.31 × 10^22	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Sulfur COULD be oxidized further, but we will stick with this formula for this calculation.</p> <p><mathjax>#"Moles of sulfur"=(4.42g)/(32.06gmol^-1)=0.138mol#</mathjax></p> <p>Given the <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> of the reaction we need <mathjax>#0.138mol#</mathjax> dioxygen molecules for equivalence, i.e. <mathjax>#0.138molxx6.022xx10^23*mol^-1=??#</mathjax> <mathjax>#O_2#</mathjax> <mathjax>#"molecules?"#</mathjax></p> <p>What mass of dioxygen does this represent?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We address the stoichiometric equation...</p> <p><mathjax>#S(s) + O_2(g) rarr SO_2(g)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Sulfur COULD be oxidized further, but we will stick with this formula for this calculation.</p> <p><mathjax>#"Moles of sulfur"=(4.42g)/(32.06gmol^-1)=0.138mol#</mathjax></p> <p>Given the <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> of the reaction we need <mathjax>#0.138mol#</mathjax> dioxygen molecules for equivalence, i.e. <mathjax>#0.138molxx6.022xx10^23*mol^-1=??#</mathjax> <mathjax>#O_2#</mathjax> <mathjax>#"molecules?"#</mathjax></p> <p>What mass of dioxygen does this represent?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many oxygen molecules are required to oxidize a #4.42g# mass of sulfur?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="526195" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-12-23T16:36:41" itemprop="dateCreated"> Dec 23, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We address the stoichiometric equation...</p> <p><mathjax>#S(s) + O_2(g) rarr SO_2(g)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Sulfur COULD be oxidized further, but we will stick with this formula for this calculation.</p> <p><mathjax>#"Moles of sulfur"=(4.42g)/(32.06gmol^-1)=0.138mol#</mathjax></p> <p>Given the <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> of the reaction we need <mathjax>#0.138mol#</mathjax> dioxygen molecules for equivalence, i.e. <mathjax>#0.138molxx6.022xx10^23mol^-1=??#</mathjax> <mathjax>#O_2#</mathjax> <mathjax>#"molecules?"#</mathjax></p> <p>What mass of dioxygen does this represent?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/526195" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> 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2,098	ab6823b6-6ddd-11ea-bed3-ccda262736ce	https://socratic.org/questions/how-many-o-atoms-are-in-the-formula-unit-ba-no-3-2	6	start physical_unit 2 3 number none qc_end chemical_equation 9 9 qc_end end	[{"type":"physical unit","value":"Number [OF] O atoms"}]	[{"type":"physical unit","value":"6"}]	[{"type":"chemical equation","value":"Ba(NO3)2"}]	<h1 class="questionTitle" itemprop="name">How many O atoms are in the formula unit #Ba(NO_3)_2#?</h1>	null	6	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that subscripts that follow <em>a closed parenthesis</em> are distributed to <strong>all the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a></strong> that are written inside the parentheses. </p> <p>By comparison, subscripts that follow the chemical symbol of an element are distributed <strong>only</strong> to that element. </p> <p>Barium nitrate, <mathjax>#"Ba"("NO"_3)_2#</mathjax>, is an <strong>ionic compound</strong> that consists of barium cations, <mathjax>#"Ba"^(2+)#</mathjax>, and nitrate anions, <mathjax>#"NO"_3^(-)#</mathjax>. </p> <p>Take a look at the nitrate anion. Here you have a <mathjax>#3#</mathjax> <strong>subscript</strong> that follows the chemical symbol for oxygen, <mathjax>#"O"#</mathjax>. This means that the anion contains a total of</p> <blockquote> <p><mathjax>#"O"_color(red)(3) = color(red)(3) xx "O" = "3 atoms of oxygen"#</mathjax></p> </blockquote> <p>Now, the barium cations have a <mathjax>#2+#</mathjax> charge and the nitrate anions have a <mathjax>#1-#</mathjax> charge. This means that in order to have a neutral compound, <strong>two nitrate anions</strong> must be used to balance the overall positive charge coming from the barium cation.</p> <p>Since the nitrate anion contains more than one element, you must enclose it in parentheses and add the <mathjax>#2#</mathjax> <strong>subscript</strong> </p> <blockquote> <p><mathjax>#color(blue)(2) xx "NO"_3^(-) = ("NO"_3)_color(blue)(2)#</mathjax></p> </blockquote> <p>Since you have two nitrate anions in one formula unit of barium nitrate, and since each nitrate anion contains <mathjax>#3#</mathjax> <strong>atoms</strong> of oxygen, you can say that one formula unit of barium nitrate will contain </p> <blockquote> <p><mathjax>#color(blue)(2) xx (color(red)(3) xx "O") = color(darkgreen)(ul(color(black)("6 atoms of oxygen")))#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"6 atoms of oxygen"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that subscripts that follow <em>a closed parenthesis</em> are distributed to <strong>all the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a></strong> that are written inside the parentheses. </p> <p>By comparison, subscripts that follow the chemical symbol of an element are distributed <strong>only</strong> to that element. </p> <p>Barium nitrate, <mathjax>#"Ba"("NO"_3)_2#</mathjax>, is an <strong>ionic compound</strong> that consists of barium cations, <mathjax>#"Ba"^(2+)#</mathjax>, and nitrate anions, <mathjax>#"NO"_3^(-)#</mathjax>. </p> <p>Take a look at the nitrate anion. Here you have a <mathjax>#3#</mathjax> <strong>subscript</strong> that follows the chemical symbol for oxygen, <mathjax>#"O"#</mathjax>. This means that the anion contains a total of</p> <blockquote> <p><mathjax>#"O"_color(red)(3) = color(red)(3) xx "O" = "3 atoms of oxygen"#</mathjax></p> </blockquote> <p>Now, the barium cations have a <mathjax>#2+#</mathjax> charge and the nitrate anions have a <mathjax>#1-#</mathjax> charge. This means that in order to have a neutral compound, <strong>two nitrate anions</strong> must be used to balance the overall positive charge coming from the barium cation.</p> <p>Since the nitrate anion contains more than one element, you must enclose it in parentheses and add the <mathjax>#2#</mathjax> <strong>subscript</strong> </p> <blockquote> <p><mathjax>#color(blue)(2) xx "NO"_3^(-) = ("NO"_3)_color(blue)(2)#</mathjax></p> </blockquote> <p>Since you have two nitrate anions in one formula unit of barium nitrate, and since each nitrate anion contains <mathjax>#3#</mathjax> <strong>atoms</strong> of oxygen, you can say that one formula unit of barium nitrate will contain </p> <blockquote> <p><mathjax>#color(blue)(2) xx (color(red)(3) xx "O") = color(darkgreen)(ul(color(black)("6 atoms of oxygen")))#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many O atoms are in the formula unit #Ba(NO_3)_2#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#ionic-bonds-and-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Ionic Bonds</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/ionic-bonds-and-formulas/writing-ionic-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Writing Ionic Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="356374" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-12-24T23:44:06" itemprop="dateCreated"> Dec 24, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"6 atoms of oxygen"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that subscripts that follow <em>a closed parenthesis</em> are distributed to <strong>all the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a></strong> that are written inside the parentheses. </p> <p>By comparison, subscripts that follow the chemical symbol of an element are distributed <strong>only</strong> to that element. </p> <p>Barium nitrate, <mathjax>#"Ba"("NO"_3)_2#</mathjax>, is an <strong>ionic compound</strong> that consists of barium cations, <mathjax>#"Ba"^(2+)#</mathjax>, and nitrate anions, <mathjax>#"NO"_3^(-)#</mathjax>. </p> <p>Take a look at the nitrate anion. Here you have a <mathjax>#3#</mathjax> <strong>subscript</strong> that follows the chemical symbol for oxygen, <mathjax>#"O"#</mathjax>. This means that the anion contains a total of</p> <blockquote> <p><mathjax>#"O"_color(red)(3) = color(red)(3) xx "O" = "3 atoms of oxygen"#</mathjax></p> </blockquote> <p>Now, the barium cations have a <mathjax>#2+#</mathjax> charge and the nitrate anions have a <mathjax>#1-#</mathjax> charge. This means that in order to have a neutral compound, <strong>two nitrate anions</strong> must be used to balance the overall positive charge coming from the barium cation.</p> <p>Since the nitrate anion contains more than one element, you must enclose it in parentheses and add the <mathjax>#2#</mathjax> <strong>subscript</strong> </p> <blockquote> <p><mathjax>#color(blue)(2) xx "NO"_3^(-) = ("NO"_3)_color(blue)(2)#</mathjax></p> </blockquote> <p>Since you have two nitrate anions in one formula unit of barium nitrate, and since each nitrate anion contains <mathjax>#3#</mathjax> <strong>atoms</strong> of oxygen, you can say that one formula unit of barium nitrate will contain </p> <blockquote> <p><mathjax>#color(blue)(2) xx (color(red)(3) xx "O") = color(darkgreen)(ul(color(black)("6 atoms of oxygen")))#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/356374" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-write-ionic-formulas-for-binary-compounds"> How do you write ionic formulas for binary compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-formula-for-calcium-chloride"> What is the ionic formula for calcium chloride? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-formula-for-calcium-oxide"> What is the ionic formula for calcium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-formula-for-lithium-oxide"> What is the ionic formula for lithium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-formula-for-ionic-compounds"> How do you write the formula for ionic compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-correctly-write-the-ions-present-in-sn-no3-2"> How do I write #Sn(NO_3)_2# in Ionic formula? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-an-ionic-compound"> What is the empirical formula for an ionic compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-for-chorate"> What is the molecular formula for chorate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5363023c02bf343b2ee7086b"> Question #7086b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-polyatomic-ions-covalent-1"> Why are polyatomic ions covalent? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/ionic-bonds-and-formulas/writing-ionic-formulas"> See all questions in Writing Ionic Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 17597 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many O atoms are in the formula unit #Ba(NO_3)_2#?	null
2,099	ac8cec76-6ddd-11ea-8c40-ccda262736ce	https://socratic.org/questions/how-would-you-balance-pcl5-h2o-h3po4-hcl	PCl5 + 4 H2O -> H3PO4 + 5 HCl	start chemical_equation qc_end chemical_equation 4 10 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the equation"}]	[{"type":"chemical equation","value":"PCl5 + 4 H2O -> H3PO4 + 5 HCl"}]	[{"type":"chemical equation","value":"PCl5 + H2O -> H3PO4 + HCl"}]	<h1 class="questionTitle" itemprop="name">How would you balance PCl5 + H2O -->H3PO4 + HCl? </h1>	null	PCl5 + 4 H2O -> H3PO4 + 5 HCl	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Just create a tally sheet for all the <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> involve.</p> <p><mathjax>#PCl_5#</mathjax> + <mathjax>#H_2O#</mathjax> = <mathjax>#H_3PO_4#</mathjax> + <mathjax>#HCl#</mathjax></p> <p>Left side: <br/> P = 1<br/> Cl = 5<br/> H = 2<br/> O = 1</p> <p>Right side:<br/> P = 1<br/> Cl = 1<br/> H = 3 + 1 <strong>(DO NOT ADD IT UP YET)</strong><br/> O = 4</p> <p>Start balancing the easiest element, in this case, the Cl.</p> <p>Left side: <br/> P = <strong>1</strong><br/> Cl = <strong>5</strong><br/> H = 2<br/> O = 1</p> <p>since <mathjax>#HCl#</mathjax> is a substance, you need to also multiply its H by 5.</p> <p>Right side:<br/> P = <strong>1</strong><br/> Cl = 1 x 5 = <strong>5</strong><br/> H = 3 + (1 x 5) = <strong>8</strong><br/> O = 4</p> <p><mathjax>#PCl_5#</mathjax> + <mathjax>#H_2O#</mathjax> = <mathjax>#H_3PO_4#</mathjax> + <mathjax>#5HCl#</mathjax></p> <p>Now the H atom on the left side is not balance with the right side, we have to multiply the H on the left side by 4.</p> <p>Left side: <br/> P = <strong>1</strong><br/> Cl = <strong>5</strong><br/> H = 2 x 4 = <strong>8</strong><br/> O = 1 x 4 = <strong>4</strong></p> <p>Again, since <mathjax>#H_2O#</mathjax> is a substance, you also need to multiply its O by 4.</p> <p>Right side:<br/> P = <strong>1</strong><br/> Cl = 1 x 5 = <strong>5</strong><br/> H = 3 + (1 x 5) = <strong>8</strong><br/> O = <strong>4</strong></p> <p><mathjax>#PCl_5#</mathjax> + <mathjax>#4H_2O#</mathjax> = <mathjax>#H_3PO_4#</mathjax> + <mathjax>#5HCl#</mathjax></p> <p>The equation is now balanced.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#PCl_5#</mathjax> + <mathjax>#4H_2O#</mathjax> = <mathjax>#H_3PO_4#</mathjax> + <mathjax>#5HCl#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Just create a tally sheet for all the <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> involve.</p> <p><mathjax>#PCl_5#</mathjax> + <mathjax>#H_2O#</mathjax> = <mathjax>#H_3PO_4#</mathjax> + <mathjax>#HCl#</mathjax></p> <p>Left side: <br/> P = 1<br/> Cl = 5<br/> H = 2<br/> O = 1</p> <p>Right side:<br/> P = 1<br/> Cl = 1<br/> H = 3 + 1 <strong>(DO NOT ADD IT UP YET)</strong><br/> O = 4</p> <p>Start balancing the easiest element, in this case, the Cl.</p> <p>Left side: <br/> P = <strong>1</strong><br/> Cl = <strong>5</strong><br/> H = 2<br/> O = 1</p> <p>since <mathjax>#HCl#</mathjax> is a substance, you need to also multiply its H by 5.</p> <p>Right side:<br/> P = <strong>1</strong><br/> Cl = 1 x 5 = <strong>5</strong><br/> H = 3 + (1 x 5) = <strong>8</strong><br/> O = 4</p> <p><mathjax>#PCl_5#</mathjax> + <mathjax>#H_2O#</mathjax> = <mathjax>#H_3PO_4#</mathjax> + <mathjax>#5HCl#</mathjax></p> <p>Now the H atom on the left side is not balance with the right side, we have to multiply the H on the left side by 4.</p> <p>Left side: <br/> P = <strong>1</strong><br/> Cl = <strong>5</strong><br/> H = 2 x 4 = <strong>8</strong><br/> O = 1 x 4 = <strong>4</strong></p> <p>Again, since <mathjax>#H_2O#</mathjax> is a substance, you also need to multiply its O by 4.</p> <p>Right side:<br/> P = <strong>1</strong><br/> Cl = 1 x 5 = <strong>5</strong><br/> H = 3 + (1 x 5) = <strong>8</strong><br/> O = <strong>4</strong></p> <p><mathjax>#PCl_5#</mathjax> + <mathjax>#4H_2O#</mathjax> = <mathjax>#H_3PO_4#</mathjax> + <mathjax>#5HCl#</mathjax></p> <p>The equation is now balanced.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How would you balance PCl5 + H2O -->H3PO4 + HCl? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="179857" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/nikka-c"><img alt="" class="" src="https://profilepictures.socratic.org/AQ8VOCyTM1J7U0TvIWhw_nkahara.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/nikka-c"> Nikka C. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-10-25T13:30:57" itemprop="dateCreated"> Oct 25, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#PCl_5#</mathjax> + <mathjax>#4H_2O#</mathjax> = <mathjax>#H_3PO_4#</mathjax> + <mathjax>#5HCl#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Just create a tally sheet for all the <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> involve.</p> <p><mathjax>#PCl_5#</mathjax> + <mathjax>#H_2O#</mathjax> = <mathjax>#H_3PO_4#</mathjax> + <mathjax>#HCl#</mathjax></p> <p>Left side: <br/> P = 1<br/> Cl = 5<br/> H = 2<br/> O = 1</p> <p>Right side:<br/> P = 1<br/> Cl = 1<br/> H = 3 + 1 <strong>(DO NOT ADD IT UP YET)</strong><br/> O = 4</p> <p>Start balancing the easiest element, in this case, the Cl.</p> <p>Left side: <br/> P = <strong>1</strong><br/> Cl = <strong>5</strong><br/> H = 2<br/> O = 1</p> <p>since <mathjax>#HCl#</mathjax> is a substance, you need to also multiply its H by 5.</p> <p>Right side:<br/> P = <strong>1</strong><br/> Cl = 1 x 5 = <strong>5</strong><br/> H = 3 + (1 x 5) = <strong>8</strong><br/> O = 4</p> <p><mathjax>#PCl_5#</mathjax> + <mathjax>#H_2O#</mathjax> = <mathjax>#H_3PO_4#</mathjax> + <mathjax>#5HCl#</mathjax></p> <p>Now the H atom on the left side is not balance with the right side, we have to multiply the H on the left side by 4.</p> <p>Left side: <br/> P = <strong>1</strong><br/> Cl = <strong>5</strong><br/> H = 2 x 4 = <strong>8</strong><br/> O = 1 x 4 = <strong>4</strong></p> <p>Again, since <mathjax>#H_2O#</mathjax> is a substance, you also need to multiply its O by 4.</p> <p>Right side:<br/> P = <strong>1</strong><br/> Cl = 1 x 5 = <strong>5</strong><br/> H = 3 + (1 x 5) = <strong>8</strong><br/> O = <strong>4</strong></p> <p><mathjax>#PCl_5#</mathjax> + <mathjax>#4H_2O#</mathjax> = <mathjax>#H_3PO_4#</mathjax> + <mathjax>#5HCl#</mathjax></p> <p>The equation is now balanced.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/179857" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? 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Sodium phosphate and calcium chloride react to form... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-equation-kclo3-kcl-o2"> How can I balance this equation? ____ #KClO_3 -># ____ #KCl +# ____ #O_2# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-balancing-chemical-equations-important"> Why is balancing chemical equations important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/balancing-chemical-equations"> See all questions in Balancing Chemical Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 105185 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How would you balance PCl5 + H2O -->H3PO4 + HCl?	null

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