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1,800	ad21516c-6ddd-11ea-bc2d-ccda262736ce	https://socratic.org/questions/what-is-the-rms-speed-of-o-2-molecules-at-at-295-k	479.40 m/s	start physical_unit 6 7 rms_speed m/s qc_end physical_unit 6 7 9 10 temperature qc_end end	[{"type":"physical unit","value":"Rms speed [OF] O2 molecules [IN] m/s"}]	[{"type":"physical unit","value":"479.40 m/s"}]	[{"type":"physical unit","value":"Temperature [OF] O2 molecules [=] \\pu{295 K}"}]	<h1 class="questionTitle" itemprop="name">What is the rms speed of #O_2# molecules at at 295 K? </h1>	null	479.40 m/s	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You can calculate the rms speed using:</p> <p><mathjax>#sf(v_(rms)=sqrt((3RT)/(M_r)))#</mathjax></p> <p>Putting in the numbers:</p> <p><mathjax>#sf(v_(rms)=sqrt((3xx8.31xx295)/(0.0320))=497.4color(white)(x)"m/s")#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#sf(479.4color(white)(x)"m/s")#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You can calculate the rms speed using:</p> <p><mathjax>#sf(v_(rms)=sqrt((3RT)/(M_r)))#</mathjax></p> <p>Putting in the numbers:</p> <p><mathjax>#sf(v_(rms)=sqrt((3xx8.31xx295)/(0.0320))=497.4color(white)(x)"m/s")#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the rms speed of #O_2# molecules at at 295 K? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/kinetic-theory-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Kinetic Theory of Gases</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="321405" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/michael-2"><img alt="" class="" src="https://lh3.googleusercontent.com/-gCv6FQRhls0/AAAAAAAAAAI/AAAAAAAAAAA/AAnnY7oOJS05Ylqn3KuDSW0LfnbOk7FezQ/mo/photo.jpg?sz=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/michael-2"> Michael </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-10-13T19:38:34" itemprop="dateCreated"> Oct 13, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#sf(479.4color(white)(x)"m/s")#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You can calculate the rms speed using:</p> <p><mathjax>#sf(v_(rms)=sqrt((3RT)/(M_r)))#</mathjax></p> <p>Putting in the numbers:</p> <p><mathjax>#sf(v_(rms)=sqrt((3xx8.31xx295)/(0.0320))=497.4color(white)(x)"m/s")#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/321405" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-kinetic-molecular-theory-explain-gas-laws"> How does kinetic molecular theory explain gas laws? 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1,801	ac6d565d-6ddd-11ea-b3b0-ccda262736ce	https://socratic.org/questions/what-is-the-ph-or-a-solution-with-h-7-0-times-10-7	6.15	start physical_unit 6 6 ph none qc_end physical_unit 6 6 10 13 [h+] qc_end end	[{"type":"physical unit","value":"pH [OF] the solution"}]	[{"type":"physical unit","value":"6.15"}]	[{"type":"physical unit","value":"[H+] [OF] the solution [=] \\pu{7.0 × 10^(-7) mol/L}"}]	<h1 class="questionTitle" itemprop="name">What is the pH or a solution with #[H^+] = 7.0 times 10^-7#?</h1>	null	6.15	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The pH of a solution has a range of 0-7. Each step having a logarithmic relation. </p> <p>Thus we use the following equation: <mathjax>#pH = -log[H^+]#</mathjax></p> <blockquote> <p><mathjax>#pH = -log[H^+]#</mathjax></p> <p><mathjax>#= -log[(7xx10^-7)]#</mathjax></p> <p><mathjax>#=6.15490196#</mathjax></p> <p><mathjax>#=6.2#</mathjax></p> </blockquote> <p>Therefore, the acid has a pH of <mathjax>#6.2#</mathjax>. This number is very close to <mathjax>#7#</mathjax>, so we can conclude it is a weak acid. </p> <p>Hope this helps :)</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> of <mathjax>#6.2#</mathjax>. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The pH of a solution has a range of 0-7. Each step having a logarithmic relation. </p> <p>Thus we use the following equation: <mathjax>#pH = -log[H^+]#</mathjax></p> <blockquote> <p><mathjax>#pH = -log[H^+]#</mathjax></p> <p><mathjax>#= -log[(7xx10^-7)]#</mathjax></p> <p><mathjax>#=6.15490196#</mathjax></p> <p><mathjax>#=6.2#</mathjax></p> </blockquote> <p>Therefore, the acid has a pH of <mathjax>#6.2#</mathjax>. This number is very close to <mathjax>#7#</mathjax>, so we can conclude it is a weak acid. </p> <p>Hope this helps :)</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the pH or a solution with #[H^+] = 7.0 times 10^-7#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/the-ph-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">pH</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="372272" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ryuu"><img alt="" class="" src="https://profilepictures.socratic.org/ybMAUPwJSLW0wuAqV5i2_meh.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ryuu"> Ryuu </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-02-01T21:34:36" itemprop="dateCreated"> Feb 1, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> of <mathjax>#6.2#</mathjax>. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The pH of a solution has a range of 0-7. Each step having a logarithmic relation. </p> <p>Thus we use the following equation: <mathjax>#pH = -log[H^+]#</mathjax></p> <blockquote> <p><mathjax>#pH = -log[H^+]#</mathjax></p> <p><mathjax>#= -log[(7xx10^-7)]#</mathjax></p> <p><mathjax>#=6.15490196#</mathjax></p> <p><mathjax>#=6.2#</mathjax></p> </blockquote> <p>Therefore, the acid has a pH of <mathjax>#6.2#</mathjax>. This number is very close to <mathjax>#7#</mathjax>, so we can conclude it is a weak acid. </p> <p>Hope this helps :)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/372272" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-pka"> How do you determine pH from pKa? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-ph-values-of-acids-and-bases-differ"> How do pH values of acids and bases differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-something-on-a-ph-scale"> How do you calculate something on a pH scale? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-diprotic-acid"> How do you calculate pH diprotic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-from-acid-dissociation-constant"> How do you calculate pH from acid dissociation constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-of-acid-and-base-solution"> How do you calculate pH of acid and base solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ph-scale-0-14"> Why is the pH scale 0-14? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-ph-the-measure-of-the-hydrogen-ion-concentration"> Is pH a measure of the hydrogen ion concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-solubility-affect-ph"> How does solubility affect pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-ph-relate-to-pka-in-a-titration"> How does pH relate to pKa in a titration? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/the-ph-concept"> See all questions in pH </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 9848 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the pH or a solution with #[H^+] = 7.0 times 10^-7#?	null
1,802	ac1ee614-6ddd-11ea-a18d-ccda262736ce	https://socratic.org/questions/5640428e11ef6b4bcf7943ce	0.1 mol	start physical_unit 15 15 mole mol qc_end physical_unit 3 3 1 2 mole qc_end physical_unit 8 8 6 7 mole qc_end end	[{"type":"physical unit","value":"Mole [OF] Ba3(PO4)2 [IN] mol"}]	[{"type":"physical unit","value":"0.1 mol"}]	[{"type":"physical unit","value":"Mole [OF] BaCl2 [=] \\pu{0.5 mol}"},{"type":"physical unit","value":"Mole [OF] Na3PO4 [=] \\pu{0.2 mol}"}]	<h1 class="questionTitle" itemprop="name">If #"0.5 mol BaCl"_2"# reacts with #"0.2 mol Na"_3"PO"_4"#, what is the maximum amount of #"Ba"_3"(PO"_4)_2"# that can be produced?</h1>	null	0.1 mol	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is a limiting reactant (reagent) question. The reactant that produces the least amount of barium phosphate is the limiting reactant. The limiting reactant determines the maximum amount of a product can be produced.</p> <p><strong>Start with a balanced equation.</strong></p> <p><mathjax>#"3BaCl"_2("aq")"+ 2Na"_3"PO"_4("aq")#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"Ba"_3"(PO"_4)_2("s") + "6NaCl(aq)"#</mathjax></p> <p>Multiply the moles of each reactant times <a href="http://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio from the balanced equation with barium phosphate in the numerator to get moles of barium phosphate.</p> <p><mathjax>#0.5color(red)cancel(color(black)("mol BaCl"_2))xx(1"mol Ba"_3"(PO"_4")"_2)/(3color(red)cancel(color(black)("mol BaCl"_2)))="0.2 mol Ba"_3"(PO"_4")"_2"#</mathjax> (rounded to one significant figure)</p> <p><mathjax>#0.2color(red)cancel(color(black)("mol Na"_3"PO"_4))xx(1"mol Ba"_3"(PO"_4")"_2)/(2color(red)cancel(color(black)("mol Na"_3"PO"_4)))="0.1 mol Ba"_3"(PO"_4")"_2"#</mathjax></p> <p><mathjax>#"Na"_3"PO"_4"#</mathjax> is the limiting reactant, so the maximum amount of <mathjax>#"Ba"_3"(PO"_4")"_2"#</mathjax> that can be produced by this reaction is <mathjax>#"0.1 mol"#</mathjax>. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The maximum amount of <mathjax>#"Ba"_3"(PO"_4")"_2"#</mathjax> that can be produced is <mathjax>#"0.1 mol"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is a limiting reactant (reagent) question. The reactant that produces the least amount of barium phosphate is the limiting reactant. The limiting reactant determines the maximum amount of a product can be produced.</p> <p><strong>Start with a balanced equation.</strong></p> <p><mathjax>#"3BaCl"_2("aq")"+ 2Na"_3"PO"_4("aq")#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"Ba"_3"(PO"_4)_2("s") + "6NaCl(aq)"#</mathjax></p> <p>Multiply the moles of each reactant times <a href="http://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio from the balanced equation with barium phosphate in the numerator to get moles of barium phosphate.</p> <p><mathjax>#0.5color(red)cancel(color(black)("mol BaCl"_2))xx(1"mol Ba"_3"(PO"_4")"_2)/(3color(red)cancel(color(black)("mol BaCl"_2)))="0.2 mol Ba"_3"(PO"_4")"_2"#</mathjax> (rounded to one significant figure)</p> <p><mathjax>#0.2color(red)cancel(color(black)("mol Na"_3"PO"_4))xx(1"mol Ba"_3"(PO"_4")"_2)/(2color(red)cancel(color(black)("mol Na"_3"PO"_4)))="0.1 mol Ba"_3"(PO"_4")"_2"#</mathjax></p> <p><mathjax>#"Na"_3"PO"_4"#</mathjax> is the limiting reactant, so the maximum amount of <mathjax>#"Ba"_3"(PO"_4")"_2"#</mathjax> that can be produced by this reaction is <mathjax>#"0.1 mol"#</mathjax>. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">If #"0.5 mol BaCl"_2"# reacts with #"0.2 mol Na"_3"PO"_4"#, what is the maximum amount of #"Ba"_3"(PO"_4)_2"# that can be produced?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="194206" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-29T04:40:46" itemprop="dateCreated"> Nov 29, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The maximum amount of <mathjax>#"Ba"_3"(PO"_4")"_2"#</mathjax> that can be produced is <mathjax>#"0.1 mol"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is a limiting reactant (reagent) question. The reactant that produces the least amount of barium phosphate is the limiting reactant. The limiting reactant determines the maximum amount of a product can be produced.</p> <p><strong>Start with a balanced equation.</strong></p> <p><mathjax>#"3BaCl"_2("aq")"+ 2Na"_3"PO"_4("aq")#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"Ba"_3"(PO"_4)_2("s") + "6NaCl(aq)"#</mathjax></p> <p>Multiply the moles of each reactant times <a href="http://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio from the balanced equation with barium phosphate in the numerator to get moles of barium phosphate.</p> <p><mathjax>#0.5color(red)cancel(color(black)("mol BaCl"_2))xx(1"mol Ba"_3"(PO"_4")"_2)/(3color(red)cancel(color(black)("mol BaCl"_2)))="0.2 mol Ba"_3"(PO"_4")"_2"#</mathjax> (rounded to one significant figure)</p> <p><mathjax>#0.2color(red)cancel(color(black)("mol Na"_3"PO"_4))xx(1"mol Ba"_3"(PO"_4")"_2)/(2color(red)cancel(color(black)("mol Na"_3"PO"_4)))="0.1 mol Ba"_3"(PO"_4")"_2"#</mathjax></p> <p><mathjax>#"Na"_3"PO"_4"#</mathjax> is the limiting reactant, so the maximum amount of <mathjax>#"Ba"_3"(PO"_4")"_2"#</mathjax> that can be produced by this reaction is <mathjax>#"0.1 mol"#</mathjax>. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/194206" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What is stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ab82402bf342f48d93ac6"> Question #93ac6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-we-study-stoichiometry"> Why do we study stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-naoh-is-produced-from-1-20-x-102-grams-of-na2o-na2o-h2o-2-naoh"> How many grams of NaOH is produced from #1.20 x 10^2# grams of #Na_2O#? #Na_2O + H_2O -> 2NaOH# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-na2o-are-required-to-produce-1-60-x-102-grams-of-naoh-na2o-h2o"> How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? Na2O + H2O ---> 2 NaOH </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-mass-of-iron-is-needed-to-react-with-16-0-grams-of-sulfur-8-fe-s8-8-fes"> What mass of iron is needed to react with 16.0 grams of sulfur? 8 Fe + S8 ---> 8 FeS </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/according-to-8-fe-s8-8-fes-how-many-grams-of-fes-are-produced"> According to 8 Fe + S8 ---> 8 FeS How many grams of FeS are produced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/12-00-moles-of-naclo3-will-produce-how-many-grams-of-o2-2-naclo3-2-nacl-3-o2"> 12.00 moles of NaClO3 will produce how many grams of O2? 2 NaClO3 ---> 2 NaCl + 3 O2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-nacl-are-produced-when-80-0-grams-of-o2-are-produced-2-naclo3-"> How many grams of NaCl are produced when 80.0 grams of O2 are produced? 2 NaClO3 ---> 2 NaCl + 3 O2 </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/stoichiometry"> See all questions in Stoichiometry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2222 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	If #"0.5 mol BaCl"_2"# reacts with #"0.2 mol Na"_3"PO"_4"#, what is the maximum amount of #"Ba"_3"(PO"_4)_2"# that can be produced?	null
1,803	aa489ad2-6ddd-11ea-aa17-ccda262736ce	https://socratic.org/questions/what-is-the-correct-formula-for-the-compound-made-by-magnesium-and-nitrogen	Mg3N2	start chemical_formula qc_end substance 10 10 qc_end substance 12 12 qc_end end	[{"type":"other","value":"Chemical Formula [OF] the compound [IN] default"}]	[{"type":"chemical equation","value":"Mg3N2"}]	[{"type":"substance name","value":"Magnesium"},{"type":"substance name","value":"Nitrogen"}]	<h1 class="questionTitle" itemprop="name">What is the correct formula for the compound made by magnesium and nitrogen? </h1>	null	Mg3N2	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Magnesium has two <a href="http://socratic.org/chemistry/the-periodic-table/valence-electrons-and-the-periodic-table">valence electrons</a>, and Nitrogen has five <a href="http://socratic.org/chemistry/the-electron-configuration-of-atoms/valence-electrons">valence electrons</a>. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The correct formula for the Magnesium Nitrogen compound is <mathjax>#Mg_3N_2#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Magnesium has two <a href="http://socratic.org/chemistry/the-periodic-table/valence-electrons-and-the-periodic-table">valence electrons</a>, and Nitrogen has five <a href="http://socratic.org/chemistry/the-electron-configuration-of-atoms/valence-electrons">valence electrons</a>. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the correct formula for the compound made by magnesium and nitrogen? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#ionic-bonds-and-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Ionic Bonds</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/ionic-bonds-and-formulas/writing-ionic-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Writing Ionic Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">3</span> Answers </h5> <div class="answers"> <div class="answer" id="181389" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/elle-4"><img alt="" class="" src="https://profilepictures.socratic.org/ME1NijwDR0ulYHvijDl5_Roses.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/elle-4"> Elle </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-10-30T22:45:09" itemprop="dateCreated"> Oct 30, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The correct formula for the Magnesium Nitrogen compound is <mathjax>#Mg_3N_2#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Magnesium has two <a href="http://socratic.org/chemistry/the-periodic-table/valence-electrons-and-the-periodic-table">valence electrons</a>, and Nitrogen has five <a href="http://socratic.org/chemistry/the-electron-configuration-of-atoms/valence-electrons">valence electrons</a>. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/181389" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="181390" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-10-30T22:51:25" itemprop="dateCreated"> Oct 30, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Mg_3N_2#</mathjax>, magnesium nitride.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Magnesium is in Group 2, nitrogen is in Group 15; the formula is as you would predict from magnesium ion, <mathjax>#Mg^(2+)#</mathjax>, and nitride anion, <mathjax>#N^(3-)#</mathjax>. This is an ionic solid that hydrolyzes to give ammonia, and magnesium hydroxide, I.e.:</p> <p><mathjax>#Mg_3N_2#</mathjax> <mathjax>#+#</mathjax> <mathjax>#6H_2O rarr #</mathjax><mathjax>#2NH_3#</mathjax> <mathjax>#+#</mathjax> <mathjax>#3Mg(OH)_2#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/181390" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="181392" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-10-30T22:56:52" itemprop="dateCreated"> Oct 30, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Magnesium and nitrogen combine to form magnesium nitride, <mathjax>#"Mg"_3"N"_2"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Magnesium nitride is an ionic compound. Magnesium forms ions with a <mathjax>#"2+"#</mathjax> charge, and nitrogen forms nitride ions with a <mathjax>#"3-"#</mathjax> charge. The overall charge of the compound must be zero. Therefore, the numerical value of the positive and negative charge must be <mathjax>#"6"#</mathjax>.</p> <p><mathjax>#3["Mg"]^(2+) + 2 ["N"]^(3-)#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"Mg"_3"N"_2"#</mathjax></p> <p><mathjax>#3xx(2+)=6+#</mathjax> and <mathjax>#2xx(3-)=6-#</mathjax></p> <p><mathjax>#(6+)+(6-)=0#</mathjax></p> <p>An easy way to determine the formula unit of an ionic compound is called the crisscross method, as demonstrated in the video below.</p> <p> <iframe src="https://www.youtube.com/embed/d9Xpt5Xh_D4?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/181392" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-write-ionic-formulas-for-binary-compounds"> How do you write ionic formulas for binary compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-formula-for-calcium-chloride"> What is the ionic formula for calcium chloride? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-formula-for-calcium-oxide"> What is the ionic formula for calcium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-formula-for-lithium-oxide"> What is the ionic formula for lithium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-formula-for-ionic-compounds"> How do you write the formula for ionic compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-correctly-write-the-ions-present-in-sn-no3-2"> How do I write #Sn(NO_3)_2# in Ionic formula? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-an-ionic-compound"> What is the empirical formula for an ionic compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-for-chorate"> What is the molecular formula for chorate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5363023c02bf343b2ee7086b"> Question #7086b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-polyatomic-ions-covalent-1"> Why are polyatomic ions covalent? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/ionic-bonds-and-formulas/writing-ionic-formulas"> See all questions in Writing Ionic Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 93774 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the correct formula for the compound made by magnesium and nitrogen?	null
1,804	a8c1d764-6ddd-11ea-a3a4-ccda262736ce	https://socratic.org/questions/the-gas-in-a-closed-container-has-a-pressure-of-3-00-10-2-kpa-at-30-c-303-k-what	145 kPa	start physical_unit 0 1 pressure kpa qc_end physical_unit 0 1 10 13 pressure qc_end physical_unit 0 1 15 18 temperature qc_end physical_unit 0 1 30 33 temperature qc_end end	[{"type":"physical unit","value":"Pressure2 [OF] the gas [IN] kPa"}]	[{"type":"physical unit","value":"145 kPa"}]	[{"type":"physical unit","value":"Pressure1 [OF] the gas [=] \\pu{3.00 × 10^2 kPa}"},{"type":"physical unit","value":"Temperature1 [OF] the gas [=] \\pu{30 ℃ (303 K)}"},{"type":"physical unit","value":"Temperature2 [OF] the gas [=] \\pu{-172 ℃ (146 K)}"}]	<h1 class="questionTitle" itemprop="name">The gas in a closed container has a pressure of #3.00 * 10^2# #kPa# at #30°C# #(303 K)#. What will the pressure be if the temperature is lowered to #-172°C# #(146 K)#?</h1>	null	145 kPa	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is an example of Gay-Lussac's law, which states that the pressure of a given gas is directly proportional to its Kelvin temperature, when held at a constant volume. The equation that represents this law is <mathjax>#P_1/T_1=P_2/T_2#</mathjax>.</p> <p><strong>Given/Known</strong><br/> <mathjax>#P_1=3.00xx10^2"kPa"#</mathjax><br/> <mathjax>#T_1="303 K"#</mathjax><br/> <mathjax>#T_2=-127^@"C+273.15=146 K"#</mathjax> </p> <p><strong>Unknown</strong><br/> <mathjax>#P_2#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#P_2#</mathjax>. Substitute the given/known values into the equation and solve.</p> <p><mathjax>#P_1/T_1=P_2/T_2#</mathjax></p> <p><mathjax>#P_2=(P_1T_2)/T_1#</mathjax></p> <p><mathjax>#P_2=(3.00xx10^2"kPa" xx 146cancel"K")/(303cancel"K")="145 kPa"#</mathjax></p> <p>Kelvin temperature changed to 146 K, which is <mathjax>#(-127^@ "C"+273.15)#</mathjax></p> <p>Excellent Resource for the <a href="http://socratic.org/chemistry/the-behavior-of-gases/gas-laws">gas laws</a>: <a href="http://chemistry.bd.psu.edu/jircitano/gases.html" rel="nofollow" target="_blank">http://chemistry.bd.psu.edu/jircitano/gases.html</a></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The final pressure will be 145 kPa.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is an example of Gay-Lussac's law, which states that the pressure of a given gas is directly proportional to its Kelvin temperature, when held at a constant volume. The equation that represents this law is <mathjax>#P_1/T_1=P_2/T_2#</mathjax>.</p> <p><strong>Given/Known</strong><br/> <mathjax>#P_1=3.00xx10^2"kPa"#</mathjax><br/> <mathjax>#T_1="303 K"#</mathjax><br/> <mathjax>#T_2=-127^@"C+273.15=146 K"#</mathjax> </p> <p><strong>Unknown</strong><br/> <mathjax>#P_2#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#P_2#</mathjax>. Substitute the given/known values into the equation and solve.</p> <p><mathjax>#P_1/T_1=P_2/T_2#</mathjax></p> <p><mathjax>#P_2=(P_1T_2)/T_1#</mathjax></p> <p><mathjax>#P_2=(3.00xx10^2"kPa" xx 146cancel"K")/(303cancel"K")="145 kPa"#</mathjax></p> <p>Kelvin temperature changed to 146 K, which is <mathjax>#(-127^@ "C"+273.15)#</mathjax></p> <p>Excellent Resource for the <a href="http://socratic.org/chemistry/the-behavior-of-gases/gas-laws">gas laws</a>: <a href="http://chemistry.bd.psu.edu/jircitano/gases.html" rel="nofollow" target="_blank">http://chemistry.bd.psu.edu/jircitano/gases.html</a></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">The gas in a closed container has a pressure of #3.00 * 10^2# #kPa# at #30°C# #(303 K)#. What will the pressure be if the temperature is lowered to #-172°C# #(146 K)#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/gay-lussac-s-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Gay Lussac's Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="229655" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-02-22T11:50:39" itemprop="dateCreated"> Feb 22, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The final pressure will be 145 kPa.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is an example of Gay-Lussac's law, which states that the pressure of a given gas is directly proportional to its Kelvin temperature, when held at a constant volume. The equation that represents this law is <mathjax>#P_1/T_1=P_2/T_2#</mathjax>.</p> <p><strong>Given/Known</strong><br/> <mathjax>#P_1=3.00xx10^2"kPa"#</mathjax><br/> <mathjax>#T_1="303 K"#</mathjax><br/> <mathjax>#T_2=-127^@"C+273.15=146 K"#</mathjax> </p> <p><strong>Unknown</strong><br/> <mathjax>#P_2#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#P_2#</mathjax>. Substitute the given/known values into the equation and solve.</p> <p><mathjax>#P_1/T_1=P_2/T_2#</mathjax></p> <p><mathjax>#P_2=(P_1T_2)/T_1#</mathjax></p> <p><mathjax>#P_2=(3.00xx10^2"kPa" xx 146cancel"K")/(303cancel"K")="145 kPa"#</mathjax></p> <p>Kelvin temperature changed to 146 K, which is <mathjax>#(-127^@ "C"+273.15)#</mathjax></p> <p>Excellent Resource for the <a href="http://socratic.org/chemistry/the-behavior-of-gases/gas-laws">gas laws</a>: <a href="http://chemistry.bd.psu.edu/jircitano/gases.html" rel="nofollow" target="_blank">http://chemistry.bd.psu.edu/jircitano/gases.html</a></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/229655" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535d701102bf342f53d9bcb0"> Question #9bcb0 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-gay-lussac-s-law-formula"> What is the Gay Lussac's law formula? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-the-temperature-of-a-gas-in-a-container-is-doubled-on-the-kelvin-scale-the-pr"> If the temperature of a gas in a container is doubled on the Kelvin scale, what will happen to... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-the-original-pressure-of-a-gas-sample-at-20-c-was-5-00-atm-and-it-is-heated-u"> If the original pressure of a gas sample at 20 ˚C was 5.00 atm, and it is heated up to 40. ˚C ,... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-gay-lussac-s-law-state"> What does Gay Lussac's law state? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-gay-lussac-s-law-relate"> What does Gay Lussac's law relate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-sample-of-o2-under-2-00-atm-occupies-500-ml-at-25-0-c-what-pressure-will-the-s"> A sample of O2 under 2.00 atm occupies 500 ml at 25.0˚C. What pressure will the sample have at 0.0˚C ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-sample-of-o2-under-2-00-atm-occupies-500-ml-at-25-0-c-what-temperature-will-be"> A sample of O2 under 2.00 atm occupies 500 ml at 25.0˚C. What temperature will be needed to... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-gay-lussac-s-law-direct-or-inverse"> Is Gay Lussac's law direct or inverse? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/determine-the-pressure-change-when-a-constant-volume-of-gas-at-1-00-atm-is-heate"> Determine the pressure change when a constant volume of gas at 1.00 atm is heated from 20.0 ˚C... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/gay-lussac-s-law"> See all questions in Gay Lussac's Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 14033 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	The gas in a closed container has a pressure of #3.00 * 10^2# #kPa# at #30°C# #(303 K)#. What will the pressure be if the temperature is lowered to #-172°C# #(146 K)#?	null
1,805	ad1b4007-6ddd-11ea-91a5-ccda262736ce	https://socratic.org/questions/what-volume-of-o-2-at-912-mmhg-and-21-c-is-required-to-synthesize-18-0-mol-of-no	181.03 L	start physical_unit 3 3 volume l qc_end physical_unit 3 3 8 9 temperature qc_end physical_unit 3 3 5 6 pressure qc_end physical_unit 17 17 14 15 mole qc_end end	[{"type":"physical unit","value":"Volume [OF] O2 [IN] L"}]	[{"type":"physical unit","value":"181.03 L"}]	[{"type":"physical unit","value":"Temperature [OF] O2 [=] \\pu{21 ℃}"},{"type":"physical unit","value":"Pressure [OF] O2 [=] \\pu{912 mmHg}"},{"type":"physical unit","value":"Mole [OF] NO [=] \\pu{18.0 mol}"}]	<h1 class="questionTitle" itemprop="name">What volume of #O_2# at 912 mmHg and 21° C is required to synthesize 18.0 mol of #NO#?</h1>	null	181.03 L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Assuming the nitrogen monoxide is made from oxygen and nitrogen according to the following reaction:</p> <p><mathjax>#N_2(g)+O_2(g)->2NO(g)#</mathjax></p> <p>Therefore, 2 moles of <mathjax>#NO#</mathjax> are prepared using only 1 mole of <mathjax>#O_2#</mathjax>, thus, we will need 9.00 moles of <mathjax>#O_2#</mathjax> to prepare 18.0 moles of <mathjax>#NO#</mathjax>.</p> <p>The pressure of <mathjax>#O_2#</mathjax> is <mathjax>#P=912cancel(mmHg)xx(1atm)/(760cancel(mmHg)=1.20atm#</mathjax></p> <p>The Kelvin temperature is <mathjax>#T=21+273=294K#</mathjax></p> <p>Therefore, using the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a>, <mathjax>#PV=nRT#</mathjax>, the volume of oxygen can be found by:</p> <p><mathjax>#V=(nRT)/P=(9.00cancel(mol)xx0.0821(cancel(atm)L)/(cancel(mol)cancel(K))xx294cancel(K))/(1.2cancel(atm))=181L#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#V_(O_2)=181L#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Assuming the nitrogen monoxide is made from oxygen and nitrogen according to the following reaction:</p> <p><mathjax>#N_2(g)+O_2(g)->2NO(g)#</mathjax></p> <p>Therefore, 2 moles of <mathjax>#NO#</mathjax> are prepared using only 1 mole of <mathjax>#O_2#</mathjax>, thus, we will need 9.00 moles of <mathjax>#O_2#</mathjax> to prepare 18.0 moles of <mathjax>#NO#</mathjax>.</p> <p>The pressure of <mathjax>#O_2#</mathjax> is <mathjax>#P=912cancel(mmHg)xx(1atm)/(760cancel(mmHg)=1.20atm#</mathjax></p> <p>The Kelvin temperature is <mathjax>#T=21+273=294K#</mathjax></p> <p>Therefore, using the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a>, <mathjax>#PV=nRT#</mathjax>, the volume of oxygen can be found by:</p> <p><mathjax>#V=(nRT)/P=(9.00cancel(mol)xx0.0821(cancel(atm)L)/(cancel(mol)cancel(K))xx294cancel(K))/(1.2cancel(atm))=181L#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What volume of #O_2# at 912 mmHg and 21° C is required to synthesize 18.0 mol of #NO#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/stoichiometry-involving-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="266503" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ali-h-1"><img alt="" class="" src="https://profilepictures.socratic.org/IITeL1YTQdODdLp0aJTL_StereoPicture%20copy.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ali-h-1"> Dr. Hayek </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-16T20:52:09" itemprop="dateCreated"> May 16, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#V_(O_2)=181L#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Assuming the nitrogen monoxide is made from oxygen and nitrogen according to the following reaction:</p> <p><mathjax>#N_2(g)+O_2(g)->2NO(g)#</mathjax></p> <p>Therefore, 2 moles of <mathjax>#NO#</mathjax> are prepared using only 1 mole of <mathjax>#O_2#</mathjax>, thus, we will need 9.00 moles of <mathjax>#O_2#</mathjax> to prepare 18.0 moles of <mathjax>#NO#</mathjax>.</p> <p>The pressure of <mathjax>#O_2#</mathjax> is <mathjax>#P=912cancel(mmHg)xx(1atm)/(760cancel(mmHg)=1.20atm#</mathjax></p> <p>The Kelvin temperature is <mathjax>#T=21+273=294K#</mathjax></p> <p>Therefore, using the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a>, <mathjax>#PV=nRT#</mathjax>, the volume of oxygen can be found by:</p> <p><mathjax>#V=(nRT)/P=(9.00cancel(mol)xx0.0821(cancel(atm)L)/(cancel(mol)cancel(K))xx294cancel(K))/(1.2cancel(atm))=181L#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/266503" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-apply-gas-stoichiometry"> How do you apply gas stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-solve-a-gas-law-stoichiometry-problem"> How do you solve a gas law stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a 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dioxide to give H2O and S, H2S + SO2 = H2O + S(solid),... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-100-ml-of-hcl-gas-at-300-k-and-200-kpa-dissolved-in-pure-water-requires-12-50"> If 100 mL of HCl gas at 300 K and 200 kPa dissolved in pure water requires 12.50 mL of the NaOH... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-100-ml-of-hcl-gas-at-300-k-and-100-kpa-dissolved-in-pure-water-requires-12-50"> If 100 mL of HCl gas at 300 K and 100 kPa dissolved in pure water requires 12.50 mL of the NaOH... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-100-ml-of-hcl-gas-at-300-k-and-100-kpa-dissolve-in-20-ml-of-pure-water-what-i"> If 100 mL of HCl gas at 300 K and 100 kPa dissolve in 20 mL of pure water, what is the concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-2-00-g-mixture-of-na-and-ca-reat-with-water-1-164-l-hydrogen-was-produced-a"> When 2.00 g mixture of Na and Ca reat with water, 1.164 L hydrogen was produced at 300.0 K and... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/stoichiometry-involving-gases"> See all questions in Gas Stoichiometry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 19154 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What volume of #O_2# at 912 mmHg and 21° C is required to synthesize 18.0 mol of #NO#?	null
1,806	ab12cd80-6ddd-11ea-a637-ccda262736ce	https://socratic.org/questions/if-the-mass-of-a-test-tube-with-copper-oxide-before-heating-is-30g-and-the-mass-	10.00 grams	start physical_unit 36 36 mass g qc_end physical_unit 5 9 13 14 mass qc_end physical_unit 5 8 28 29 mass qc_end end	[{"type":"physical unit","value":"Mass [OF] oxygen [IN] grams"}]	[{"type":"physical unit","value":"10.00 grams"}]	[{"type":"physical unit","value":"Mass [OF] test tube with copper oxide [=] \\pu{30 g}"},{"type":"physical unit","value":"Mass [OF] test tube with copper [=] \\pu{20 g}"}]	<h1 class="questionTitle" itemprop="name">If the mass of a test tube with copper oxide before heating is 30g and the mass of the test tube with copper after heating is is 20g, what was the mass of the oxygen heated off? </h1>	null	10.00 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#30 - 20 = 10#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#10#</mathjax> grams</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#30 - 20 = 10#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">If the mass of a test tube with copper oxide before heating is 30g and the mass of the test tube with copper after heating is is 20g, what was the mass of the oxygen heated off? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/thermochemistry-of-phase-changes" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry of Phase Changes</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="313868" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/eshaan-g"><img alt="" class="" src="https://profilepictures.socratic.org/ikwETQdxQwqxJT9cTsPi_CoS%20crow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/eshaan-g"> S.S </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-09-24T11:46:53" itemprop="dateCreated"> Sep 24, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#10#</mathjax> grams</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#30 - 20 = 10#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/313868" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-much-energy-is-required-to-heat-100-g-of-ice-at-0-00-degrees-celsius-to-wate"> How much energy is required to convert 100.g of ice at 0.00 °C to water vapor at 100.00 °C? 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</a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/thermochemistry-of-phase-changes"> See all questions in Thermochemistry of Phase Changes </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1840 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	If the mass of a test tube with copper oxide before heating is 30g and the mass of the test tube with copper after heating is is 20g, what was the mass of the oxygen heated off?	null
1,807	a8c33a36-6ddd-11ea-b400-ccda262736ce	https://socratic.org/questions/how-do-you-calculate-the-ph-of-an-aqueous-solution-of-0-0726-m-potassium-sulfite	9.92	start physical_unit 9 9 ph none qc_end end	[{"type":"physical unit","value":"pH [OF] potassium sulfite aqueous solution"}]	[{"type":"physical unit","value":"9.92"}]	[{"type":"physical unit","value":"Molarity [OF] potassium sulfite aqueous solution [=] \\pu{0.0726 M}"}]	<h1 class="questionTitle" itemprop="name">How do you calculate the pH of an aqueous solution of 0.0726 M potassium sulfite?</h1>	null	9.92	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This <a href="https://en.wikipedia.org/wiki/Bisulfite" rel="nofollow">site</a> reports that the <mathjax>#pK_a#</mathjax> of <mathjax>#HSO_3^(-)#</mathjax> is <mathjax>#6.97#</mathjax>....and therefore, the <mathjax>#pK_b#</mathjax> of <mathjax>#SO_3^(2-)#</mathjax>, its conjugate base is <mathjax>#14-6.97=7.03#</mathjax>..(because <mathjax>#pK_a+pK_b=14#</mathjax> in aqueous solution)….</p> <p>And so we address the following equilibrium....</p> <p><mathjax>#SO_3^(2-)+H_2O(l) rightleftharpoonsHSO_3^(-) +HO^-#</mathjax> </p> <p>And thus <mathjax>#K_b=10^(-7.03)=([HSO_3^(-)][HO^-])/([SO_3^(2-)])#</mathjax></p> <p>Now INITIALLY, <mathjax>#[SO_3^(2-)]=0.0726molL^-1#</mathjax>...and if <mathjax>#xmolL^-1#</mathjax> sulfite ion associates then....</p> <p><mathjax>#K_b=10^(-7.03)=(x^2)/(0.0726-x)#</mathjax>...we propose that <mathjax>#0.0726">>"x#</mathjax>...and so....</p> <p><mathjax>#x_1=sqrt(10^(-7.03)xx0.0726)=8.23xx10^-5molL^-1#</mathjax>...and we use this value for a successive approximation...</p> <p><mathjax>#x_2=sqrt(10^(-7.03)xx(0.0726-8.23xx10^-5))=8.23xx10^-5molL^-1#</mathjax></p> <p>And since the approximations have converged, I am prepared to accept this as the true value.... </p> <p>But <mathjax>#x=[HO^-]#</mathjax>...<mathjax>#pOH=-log_10(8.23xx10^-5)=4.08#</mathjax>....<mathjax>#pH=14-pOH=14-4.08=9.92#</mathjax></p> <p>(Why? Because <mathjax>#pH+pOH=14#</mathjax> in aqueous solution under standard conditions...)</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>You ain't given us any data with respect to <mathjax>#pK_a#</mathjax> of <mathjax>#"bisulfite"#</mathjax>, or <mathjax>#pK_b#</mathjax> of <mathjax>#SO_3^(2-)#</mathjax>....I gets <mathjax>#pH~=10#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This <a href="https://en.wikipedia.org/wiki/Bisulfite" rel="nofollow">site</a> reports that the <mathjax>#pK_a#</mathjax> of <mathjax>#HSO_3^(-)#</mathjax> is <mathjax>#6.97#</mathjax>....and therefore, the <mathjax>#pK_b#</mathjax> of <mathjax>#SO_3^(2-)#</mathjax>, its conjugate base is <mathjax>#14-6.97=7.03#</mathjax>..(because <mathjax>#pK_a+pK_b=14#</mathjax> in aqueous solution)….</p> <p>And so we address the following equilibrium....</p> <p><mathjax>#SO_3^(2-)+H_2O(l) rightleftharpoonsHSO_3^(-) +HO^-#</mathjax> </p> <p>And thus <mathjax>#K_b=10^(-7.03)=([HSO_3^(-)][HO^-])/([SO_3^(2-)])#</mathjax></p> <p>Now INITIALLY, <mathjax>#[SO_3^(2-)]=0.0726molL^-1#</mathjax>...and if <mathjax>#xmolL^-1#</mathjax> sulfite ion associates then....</p> <p><mathjax>#K_b=10^(-7.03)=(x^2)/(0.0726-x)#</mathjax>...we propose that <mathjax>#0.0726">>"x#</mathjax>...and so....</p> <p><mathjax>#x_1=sqrt(10^(-7.03)xx0.0726)=8.23xx10^-5molL^-1#</mathjax>...and we use this value for a successive approximation...</p> <p><mathjax>#x_2=sqrt(10^(-7.03)xx(0.0726-8.23xx10^-5))=8.23xx10^-5molL^-1#</mathjax></p> <p>And since the approximations have converged, I am prepared to accept this as the true value.... </p> <p>But <mathjax>#x=[HO^-]#</mathjax>...<mathjax>#pOH=-log_10(8.23xx10^-5)=4.08#</mathjax>....<mathjax>#pH=14-pOH=14-4.08=9.92#</mathjax></p> <p>(Why? Because <mathjax>#pH+pOH=14#</mathjax> in aqueous solution under standard conditions...)</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you calculate the pH of an aqueous solution of 0.0726 M potassium sulfite?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/ph-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">pH calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="640151" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-07-11T15:28:22" itemprop="dateCreated"> Jul 11, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>You ain't given us any data with respect to <mathjax>#pK_a#</mathjax> of <mathjax>#"bisulfite"#</mathjax>, or <mathjax>#pK_b#</mathjax> of <mathjax>#SO_3^(2-)#</mathjax>....I gets <mathjax>#pH~=10#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This <a href="https://en.wikipedia.org/wiki/Bisulfite" rel="nofollow">site</a> reports that the <mathjax>#pK_a#</mathjax> of <mathjax>#HSO_3^(-)#</mathjax> is <mathjax>#6.97#</mathjax>....and therefore, the <mathjax>#pK_b#</mathjax> of <mathjax>#SO_3^(2-)#</mathjax>, its conjugate base is <mathjax>#14-6.97=7.03#</mathjax>..(because <mathjax>#pK_a+pK_b=14#</mathjax> in aqueous solution)….</p> <p>And so we address the following equilibrium....</p> <p><mathjax>#SO_3^(2-)+H_2O(l) rightleftharpoonsHSO_3^(-) +HO^-#</mathjax> </p> <p>And thus <mathjax>#K_b=10^(-7.03)=([HSO_3^(-)][HO^-])/([SO_3^(2-)])#</mathjax></p> <p>Now INITIALLY, <mathjax>#[SO_3^(2-)]=0.0726molL^-1#</mathjax>...and if <mathjax>#xmolL^-1#</mathjax> sulfite ion associates then....</p> <p><mathjax>#K_b=10^(-7.03)=(x^2)/(0.0726-x)#</mathjax>...we propose that <mathjax>#0.0726">>"x#</mathjax>...and so....</p> <p><mathjax>#x_1=sqrt(10^(-7.03)xx0.0726)=8.23xx10^-5molL^-1#</mathjax>...and we use this value for a successive approximation...</p> <p><mathjax>#x_2=sqrt(10^(-7.03)xx(0.0726-8.23xx10^-5))=8.23xx10^-5molL^-1#</mathjax></p> <p>And since the approximations have converged, I am prepared to accept this as the true value.... </p> <p>But <mathjax>#x=[HO^-]#</mathjax>...<mathjax>#pOH=-log_10(8.23xx10^-5)=4.08#</mathjax>....<mathjax>#pH=14-pOH=14-4.08=9.92#</mathjax></p> <p>(Why? Because <mathjax>#pH+pOH=14#</mathjax> in aqueous solution under standard conditions...)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/640151" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-of-a-solution"> How do you determine ph of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-at-an-equivalence-point"> How do you determine pH at an equivalence point? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-molarity"> How do you determine pH from molarity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-alkalinity-mean"> What does alkalinity mean? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-base"> What is a base? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-acid-base-indicators-change-color"> How do acid base indicators change color? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-neutral-ph"> What is a neutral pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-alkalinity-affect-pool-water"> How does alkalinity affect pool water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ph-important-in-drinking-water"> Why is pH important in drinking water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-ph-of-solution"> How can I calculate the pH of a solution? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/ph-calculations"> See all questions in pH calculations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3683 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How do you calculate the pH of an aqueous solution of 0.0726 M potassium sulfite?	null
1,808	aadf7664-6ddd-11ea-af65-ccda262736ce	https://socratic.org/questions/a-molecule-of-silver-nitrate-contains-a-polyatomic-ion-what-chemical-equation-re	2 AgNO3(aq) + CaCl2(aq) -> 2 AgCl(s) + 2 Ca(NO3)2(aq)	start chemical_equation qc_end substance 3 4 qc_end substance 19 20 qc_end c_other OTHER qc_end end	[{"type":"other","value":"Chemical Equation [OF] the equation"}]	[{"type":"chemical equation","value":"2 AgNO3(aq) + CaCl2(aq) -> 2 AgCl(s) + 2 Ca(NO3)2(aq)"}]	[{"type":"substance name","value":"Silver nitrate"},{"type":"substance name","value":"Calcium chloride"},{"type":"other","value":"A molecule of silver nitrate contains a polyatomic ion."}]	<h1 class="questionTitle" itemprop="name">A molecule of silver nitrate contains a polyatomic ion. What chemical equation represents the reaction between silver nitrate and calcium chloride?</h1>	null	2 AgNO3(aq) + CaCl2(aq) -> 2 AgCl(s) + 2 Ca(NO3)2(aq)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is a simple metathesis or partner exchange reaction. Silver chloride is about as soluble as a brick, and precipitates from solution as a curdy white solid. Calcium chloride and calcium nitrate are soluble in aqueous solution.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2AgNO_3(aq) + CaCl_2(aq) rarr 2AgCl(s)darr + 2Ca(NO_3)_2(aq)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is a simple metathesis or partner exchange reaction. Silver chloride is about as soluble as a brick, and precipitates from solution as a curdy white solid. Calcium chloride and calcium nitrate are soluble in aqueous solution.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A molecule of silver nitrate contains a polyatomic ion. What chemical equation represents the reaction between silver nitrate and calcium chloride?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#ionic-bonds-and-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Ionic Bonds</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/ionic-bonds-and-formulas/polyatomic-ions" itemprop="url"> <span class="breadcrumb" itemprop="title">Polyatomic Ions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="288453" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-15T17:09:24" itemprop="dateCreated"> Jul 15, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2AgNO_3(aq) + CaCl_2(aq) rarr 2AgCl(s)darr + 2Ca(NO_3)_2(aq)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is a simple metathesis or partner exchange reaction. Silver chloride is about as soluble as a brick, and precipitates from solution as a curdy white solid. Calcium chloride and calcium nitrate are soluble in aqueous solution.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/288453" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-draw-the-lewis-structure-for-polyatomic-ions"> How do you draw the lewis structure for polyatomic ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/the-number-of-protons-are-not-suppose-to-be-equal-to-the-number-of-electrons-how"> The number of protons are not suppose to be equal to the number of electrons? 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What chemical equation represents the reaction between silver nitrate and calcium chloride?	null
1,809	ac2045ef-6ddd-11ea-94dd-ccda262736ce	https://socratic.org/questions/what-volume-does-0-0250-mole-h-2-occupy-at-0-821-atm-pressure-and-300-k	0.7 L	start physical_unit 5 5 volume l qc_end physical_unit 5 5 3 4 mole qc_end physical_unit 5 5 8 9 pressure qc_end physical_unit 5 5 12 13 temperature qc_end end	[{"type":"physical unit","value":"Volume [OF] H2 [IN] L"}]	[{"type":"physical unit","value":"0.7 L"}]	[{"type":"physical unit","value":"Mole [OF] H2 [=] \\pu{0.0250 mole}"},{"type":"physical unit","value":"Pressure [OF] H2 [=] \\pu{0.821 atm}"},{"type":"physical unit","value":"Temperature [OF] H2 [=] \\pu{300 K}"}]	<h1 class="questionTitle" itemprop="name">What volume does 0.0250 mole #H_2# occupy at 0.821 atm pressure and 300 K?</h1>	null	0.7 L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>Hydrogen behaves like an ideal gas.</p> <p><mathjax>#PV=nRT#</mathjax>, where</p> <p><mathjax>#P = "the pressure" = 0.821 color(red)(cancel(color(black)("atm")))(1.0132510^5 "Pa")/(1 color(red)(cancel(color(black)("atm"))))#</mathjax></p> <p><mathjax>#P = "83 190" color(red)(cancel(color(black)("Pa"))) "1N/m"^2/(1 color(red)(cancel(color(black)("Pa")))) = "83 190 N/m"^2#</mathjax></p> <p><mathjax>#T= "the temperature"#</mathjax></p> <p><mathjax>#n = "number of moles"#</mathjax></p> <p><mathjax>#R= "ideal gas constant" = 8.314 color(red)(cancel(color(black)("J")))//("K·mol") * "1 N·m"/(1 color(red)(cancel(color(black)("J")))) = "8.314 N·m/(K·mol)"#</mathjax></p> <p><mathjax>#V = "the volume"#</mathjax></p> <blockquote></blockquote> <p><mathjax>#V=(nRT)/P#</mathjax></p> <p><mathjax>#V=((0.250 color(red)(cancel(color(black)("mol"))) * 8.314 color(red)(cancel(color(black)("N")))"m")//(color(red)(cancel(color(black)("K·mol")))) · 300 color(red)(cancel(color(black)("K"))))/("83 190" color(red)(cancel(color(black)("N")))//"m"^2)#</mathjax></p> <p><mathjax>#V = 7.5010^-4 " m"^3 = "0.750 dm"^3#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The volume is <mathjax>#"0.750 dm"^3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>Hydrogen behaves like an ideal gas.</p> <p><mathjax>#PV=nRT#</mathjax>, where</p> <p><mathjax>#P = "the pressure" = 0.821 color(red)(cancel(color(black)("atm")))(1.0132510^5 "Pa")/(1 color(red)(cancel(color(black)("atm"))))#</mathjax></p> <p><mathjax>#P = "83 190" color(red)(cancel(color(black)("Pa"))) "1N/m"^2/(1 color(red)(cancel(color(black)("Pa")))) = "83 190 N/m"^2#</mathjax></p> <p><mathjax>#T= "the temperature"#</mathjax></p> <p><mathjax>#n = "number of moles"#</mathjax></p> <p><mathjax>#R= "ideal gas constant" = 8.314 color(red)(cancel(color(black)("J")))//("K·mol") * "1 N·m"/(1 color(red)(cancel(color(black)("J")))) = "8.314 N·m/(K·mol)"#</mathjax></p> <p><mathjax>#V = "the volume"#</mathjax></p> <blockquote></blockquote> <p><mathjax>#V=(nRT)/P#</mathjax></p> <p><mathjax>#V=((0.250 color(red)(cancel(color(black)("mol"))) * 8.314 color(red)(cancel(color(black)("N")))"m")//(color(red)(cancel(color(black)("K·mol")))) · 300 color(red)(cancel(color(black)("K"))))/("83 190" color(red)(cancel(color(black)("N")))//"m"^2)#</mathjax></p> <p><mathjax>#V = 7.5010^-4 " m"^3 = "0.750 dm"^3#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What volume does 0.0250 mole #H_2# occupy at 0.821 atm pressure and 300 K?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/ideal-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Ideal Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="190990" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> <a class="secondContributorPic" href="/users/hpn"><img alt="" class="" src="https://profilepictures.socratic.org/wY7uD5FuQoCETOjcbnCa_SealVictoriaBC.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a>·<a class="topContributorLink" href="/users/hpn"> HPN </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-20T10:25:30" itemprop="dateCreated"> Nov 20, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The volume is <mathjax>#"0.750 dm"^3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>Hydrogen behaves like an ideal gas.</p> <p><mathjax>#PV=nRT#</mathjax>, where</p> <p><mathjax>#P = "the pressure" = 0.821 color(red)(cancel(color(black)("atm")))(1.0132510^5 "Pa")/(1 color(red)(cancel(color(black)("atm"))))#</mathjax></p> <p><mathjax>#P = "83 190" color(red)(cancel(color(black)("Pa"))) "1N/m"^2/(1 color(red)(cancel(color(black)("Pa")))) = "83 190 N/m"^2#</mathjax></p> <p><mathjax>#T= "the temperature"#</mathjax></p> <p><mathjax>#n = "number of moles"#</mathjax></p> <p><mathjax>#R= "ideal gas constant" = 8.314 color(red)(cancel(color(black)("J")))//("K·mol") * "1 N·m"/(1 color(red)(cancel(color(black)("J")))) = "8.314 N·m/(K·mol)"#</mathjax></p> <p><mathjax>#V = "the volume"#</mathjax></p> <blockquote></blockquote> <p><mathjax>#V=(nRT)/P#</mathjax></p> <p><mathjax>#V=((0.250 color(red)(cancel(color(black)("mol"))) * 8.314 color(red)(cancel(color(black)("N")))"m")//(color(red)(cancel(color(black)("K·mol")))) · 300 color(red)(cancel(color(black)("K"))))/("83 190" color(red)(cancel(color(black)("N")))//"m"^2)#</mathjax></p> <p><mathjax>#V = 7.5010^-4 " m"^3 = "0.750 dm"^3#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/190990" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="191018" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-20T11:41:59" itemprop="dateCreated"> Nov 20, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The volume will be <mathjax>#"0.7 L"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a>.</p> <p><mathjax>#PV=nRT#</mathjax>, where <mathjax>#n#</mathjax> is moles, and <mathjax>#R#</mathjax> is the gas constant.</p> <p><strong>Given/Known</strong><br/> <mathjax>#P="0.821 atm"#</mathjax><br/> <mathjax>#n="0.0250 mol"#</mathjax><br/> <mathjax>#R="0.082057338 L atm K"^(-1) "mol"^(-1)#</mathjax><br/> <mathjax>#T="300 K"#</mathjax></p> <p><strong>Unknown</strong></p> <p><mathjax>#V#</mathjax></p> <p><strong>Equation</strong></p> <p><mathjax>#PV=nRT#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#V#</mathjax> and solve.</p> <p><mathjax>#V=(nRT)/P#</mathjax></p> <p><mathjax>#V=((0.0250cancel"mol"xx0.08205733" L" cancel"atm" cancel("K"^(-1)) cancel("mol"^(-1)) xx 300cancel"K"))/(0.821cancel"atm")="0.7 L"#</mathjax> (rounded to one significant figure due to 300 K)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/191018" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-ideal-gas-constant"> How do you find the ideal gas constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-solve-ideal-gas-law-problems"> How do you solve ideal gas law problems? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" 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1,810	a9db3311-6ddd-11ea-b9e5-ccda262736ce	https://socratic.org/questions/what-is-the-volume-of-75-0-g-of-o-2-at-stp	105.07 L	start physical_unit 8 8 volume l qc_end physical_unit 8 8 5 6 mass qc_end c_other STP qc_end end	[{"type":"physical unit","value":"Volume [OF] O2 [IN] L"}]	[{"type":"physical unit","value":"105.07 L"}]	[{"type":"physical unit","value":"Mass [OF] O2 [=] \\pu{75.0 g}"},{"type":"other","value":"STP"}]	<h1 class="questionTitle" itemprop="name">What is the volume of 75.0 g of #O_2# at STP?</h1>	null	105.07 L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#p=1 atm#</mathjax><br/> <mathjax>#t=273.15 K#</mathjax><br/> <mathjax>#R=0.08206 (Latm)/(molK)#</mathjax><br/> <mathjax>#n=(75.0gO_2)/(16.00(g/(mol)O_2)=4.6875mol#</mathjax></p> <p><a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal gas law</a>: <mathjax>#PV=nRT#</mathjax>, solve for volume:<br/> <mathjax>#V=(nRT)/P#</mathjax></p> <p><mathjax>#V=(4.6875mol0.08206 (Latm)/(molK)273.15K)/(1atm)#</mathjax></p> <p><mathjax>#V=105 L#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#V=105L#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#p=1 atm#</mathjax><br/> <mathjax>#t=273.15 K#</mathjax><br/> <mathjax>#R=0.08206 (Latm)/(molK)#</mathjax><br/> <mathjax>#n=(75.0gO_2)/(16.00(g/(mol)O_2)=4.6875mol#</mathjax></p> <p><a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal gas law</a>: <mathjax>#PV=nRT#</mathjax>, solve for volume:<br/> <mathjax>#V=(nRT)/P#</mathjax></p> <p><mathjax>#V=(4.6875mol0.08206 (Latm)/(molK)273.15K)/(1atm)#</mathjax></p> <p><mathjax>#V=105 L#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the volume of 75.0 g of #O_2# at STP?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/gas-laws" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Laws</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="461863" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/tcw1"><img alt="" class="" src="https://profilepictures.socratic.org/Ox6b9VazRq1N5FiU8YFj_fractal-026.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/tcw1"> tcw1 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-09T01:32:58" itemprop="dateCreated"> Aug 9, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#V=105L#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#p=1 atm#</mathjax><br/> <mathjax>#t=273.15 K#</mathjax><br/> <mathjax>#R=0.08206 (Latm)/(molK)#</mathjax><br/> <mathjax>#n=(75.0gO_2)/(16.00(g/(mol)O_2)=4.6875mol#</mathjax></p> <p><a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal gas law</a>: <mathjax>#PV=nRT#</mathjax>, solve for volume:<br/> <mathjax>#V=(nRT)/P#</mathjax></p> <p><mathjax>#V=(4.6875mol0.08206 (Latm)/(molK)273.15K)/(1atm)#</mathjax></p> <p><mathjax>#V=105 L#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/461863" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-boyles-law-relate-to-breathing"> How does Boyle's law relate to breathing? 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1,811	a9b25e25-6ddd-11ea-9e8f-ccda262736ce	https://socratic.org/questions/what-is-the-oxidation-number-of-cl-in-ba-clo2-2	+3	start physical_unit 6 6 oxidation_number none qc_end chemical_equation 8 8 qc_end end	[{"type":"physical unit","value":"Oxidation number [OF] Cl"}]	[{"type":"physical unit","value":"+3"}]	[{"type":"chemical equation","value":"Ba(ClO2)2"}]	<h1 class="questionTitle" itemprop="name">What is the oxidation number of Cl in Ba(ClO2)2?</h1>	null	+3	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Oxidation number is the charge left on the atom of interest, when all the <a href="http://socratic.org/chemistry/bonding-basics/bonding">bonding</a> pairs of electrons are broken with the charge devolving to the most electronegative atom.</p> <p>We have <mathjax>#ClO_2^-#</mathjax>; the individual <a href="http://socratic.org/chemistry/electrochemistry/oxidation-numbers">oxidation numbers</a> of the <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> <mathjax>#(2xxO + Cl)#</mathjax> must sum (by definition) to the charge on the chlorite ion, which is <mathjax>#-1#</mathjax>. Oxygen gets the charge when we break the <mathjax>#Cl-O#</mathjax> bonds, so it is <mathjax>#-II#</mathjax> (oxygen is more electronegative than <mathjax>#Cl#</mathjax>). So <mathjax>#-2-2+Cl_(ON) = -1#</mathjax>. This gives <mathjax>#Cl#</mathjax> in chlorite a formal oxidation number of <mathjax>#+III#</mathjax>. What is the oxidation number of <mathjax>#Cl#</mathjax> in perchlorate anion, <mathjax>#ClO_4^-#</mathjax>? Please post your answer here.</p> <p>Note that the oxidation number of <mathjax>#O#</mathjax> in is <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a> is normally <mathjax>#-II#</mathjax>, as here. Elemental oxygen is <mathjax>#0#</mathjax>, BUT peroxide, <mathjax>#O_2^(2-)#</mathjax>, is <mathjax>#-I#</mathjax>. See <a href="http://socratic.org/questions/oxygen-has-1-oxidation-state-in-peroxide-but-each-oxygen-forms-two-bonds-why">here.</a> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Oxidation numnber of <mathjax>#Cl#</mathjax> in chlorite? Well the parent ion is <mathjax>#ClO_2^-#</mathjax>. (How did I know this?) So oxidation number of <mathjax>#Cl#</mathjax> is <mathjax>#+III#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Oxidation number is the charge left on the atom of interest, when all the <a href="http://socratic.org/chemistry/bonding-basics/bonding">bonding</a> pairs of electrons are broken with the charge devolving to the most electronegative atom.</p> <p>We have <mathjax>#ClO_2^-#</mathjax>; the individual <a href="http://socratic.org/chemistry/electrochemistry/oxidation-numbers">oxidation numbers</a> of the <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> <mathjax>#(2xxO + Cl)#</mathjax> must sum (by definition) to the charge on the chlorite ion, which is <mathjax>#-1#</mathjax>. Oxygen gets the charge when we break the <mathjax>#Cl-O#</mathjax> bonds, so it is <mathjax>#-II#</mathjax> (oxygen is more electronegative than <mathjax>#Cl#</mathjax>). So <mathjax>#-2-2+Cl_(ON) = -1#</mathjax>. This gives <mathjax>#Cl#</mathjax> in chlorite a formal oxidation number of <mathjax>#+III#</mathjax>. What is the oxidation number of <mathjax>#Cl#</mathjax> in perchlorate anion, <mathjax>#ClO_4^-#</mathjax>? Please post your answer here.</p> <p>Note that the oxidation number of <mathjax>#O#</mathjax> in is <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a> is normally <mathjax>#-II#</mathjax>, as here. Elemental oxygen is <mathjax>#0#</mathjax>, BUT peroxide, <mathjax>#O_2^(2-)#</mathjax>, is <mathjax>#-I#</mathjax>. See <a href="http://socratic.org/questions/oxygen-has-1-oxidation-state-in-peroxide-but-each-oxygen-forms-two-bonds-why">here.</a> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the oxidation number of Cl in Ba(ClO2)2?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#electrochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Electrochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/electrochemistry/oxidation-numbers" itemprop="url"> <span class="breadcrumb" itemprop="title">Oxidation Numbers</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="187959" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-13T18:00:00" itemprop="dateCreated"> Nov 13, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Oxidation numnber of <mathjax>#Cl#</mathjax> in chlorite? Well the parent ion is <mathjax>#ClO_2^-#</mathjax>. (How did I know this?) So oxidation number of <mathjax>#Cl#</mathjax> is <mathjax>#+III#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Oxidation number is the charge left on the atom of interest, when all the <a href="http://socratic.org/chemistry/bonding-basics/bonding">bonding</a> pairs of electrons are broken with the charge devolving to the most electronegative atom.</p> <p>We have <mathjax>#ClO_2^-#</mathjax>; the individual <a href="http://socratic.org/chemistry/electrochemistry/oxidation-numbers">oxidation numbers</a> of the <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> <mathjax>#(2xxO + Cl)#</mathjax> must sum (by definition) to the charge on the chlorite ion, which is <mathjax>#-1#</mathjax>. Oxygen gets the charge when we break the <mathjax>#Cl-O#</mathjax> bonds, so it is <mathjax>#-II#</mathjax> (oxygen is more electronegative than <mathjax>#Cl#</mathjax>). So <mathjax>#-2-2+Cl_(ON) = -1#</mathjax>. This gives <mathjax>#Cl#</mathjax> in chlorite a formal oxidation number of <mathjax>#+III#</mathjax>. What is the oxidation number of <mathjax>#Cl#</mathjax> in perchlorate anion, <mathjax>#ClO_4^-#</mathjax>? Please post your answer here.</p> <p>Note that the oxidation number of <mathjax>#O#</mathjax> in is <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a> is normally <mathjax>#-II#</mathjax>, as here. Elemental oxygen is <mathjax>#0#</mathjax>, BUT peroxide, <mathjax>#O_2^(2-)#</mathjax>, is <mathjax>#-I#</mathjax>. See <a href="http://socratic.org/questions/oxygen-has-1-oxidation-state-in-peroxide-but-each-oxygen-forms-two-bonds-why">here.</a> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/187959" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-relate-to-electron-configuration"> How do oxidation numbers relate to electron configuration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-relate-to-valence-electrons"> How do oxidation numbers relate to valence electrons? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-vary-with-the-periodic-table"> How do oxidation numbers vary with the periodic table? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-oxidation-number-of-an-element-in-a-compound"> How do you calculate the oxidation number of an element in a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-sulfur"> What is the oxidation number for sulfur? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-carbon"> What is the oxidation number for carbon? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-copper"> What is the oxidation number for copper? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-nitrogen"> What is the oxidation number for nitrogen? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-oxygen"> What is the oxidation number for oxygen? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-oxidation-state-of-noble-gas-zero"> Why is the oxidation state of noble gas zero? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/electrochemistry/oxidation-numbers"> See all questions in Oxidation Numbers </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 20016 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the oxidation number of Cl in Ba(ClO2)2?	null
1,812	aca6fe66-6ddd-11ea-ab22-ccda262736ce	https://socratic.org/questions/58-0-ml-of-a-1-30-m-solution-is-diluted-to-a-total-volume-248-ml-a-124-ml-portio	0.13 M	start physical_unit 6 6 concentration mol/l qc_end physical_unit 6 6 0 1 volume qc_end physical_unit 6 6 4 5 concentration qc_end physical_unit 6 6 13 14 volume qc_end physical_unit 6 6 16 17 volume qc_end physical_unit 29 29 26 27 volume qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Concentration4 [OF] the solution [IN] M"}]	[{"type":"physical unit","value":"0.13 M"}]	[{"type":"physical unit","value":"Volume1 [OF] the solution [=] \\pu{58.0 mL}"},{"type":"physical unit","value":"Concentration1 [OF] the solution [=] \\pu{1.30 M}"},{"type":"physical unit","value":"Volume2 [OF] the solution [=] \\pu{248 mL}"},{"type":"physical unit","value":"Volume3 [OF] the solution [=] \\pu{124 mL}"},{"type":"physical unit","value":"Volume [OF] water [=] \\pu{165 mL}"},{"type":"other","value":"Assume the volumes are additive."}]	<h1 class="questionTitle" itemprop="name">58.0 mL of a 1.30 M solution is diluted to a total volume 248 mL. A 124-mL portion of that solution is diluted by adding 165 mL of water. What is the final concentration? Assume the volumes are additive</h1>	null	0.13 M	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You can solve this problem by using the <strong><a href="https://socratic.org/questions/how-do-you-calculate-dilution-factor">dilution factor</a></strong>, <mathjax>#"DF"#</mathjax>, which essentially tells you the factor by which the concentration of an initial solution <strong>decreased</strong> upon dilution. </p> <p>The dilution factor is calculated by using either <em>volumes</em> or <em>molarities</em></p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a)"DF" = V_"diluted"/V_"concentrated" = c_"concentrated"/c_"diluted"color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>So, the dilution factor for the <strong>first dilution</strong></p> <blockquote> <p><mathjax>#"58.0 mL " -> " 248 mL"#</mathjax></p> </blockquote> <p>will be </p> <blockquote> <p><mathjax>#"DF"_1 = (248 color(red)(cancel(color(black)("mL"))))/(58.0color(red)(cancel(color(black)("mL")))) = 4.276#</mathjax></p> </blockquote> <p>The first solution was diluted by a factor of <mathjax>#4.276#</mathjax>, which means that its concentration <strong>decreased</strong> by a factor of <mathjax>#4.276#</mathjax>. Therefore, the concentration of the diluted solution will be </p> <blockquote> <p><mathjax>#c_"diluted" = c_"concentrated"/"DF"_ 1#</mathjax></p> <p><mathjax>#c_"diluted" = "1.30 M"/4.276 = "0.304 M"#</mathjax></p> </blockquote> <p>Now, you take a sample of <mathjax>#"124 mL"#</mathjax> of this diluted solution and <strong>add</strong> another <mathjax>#"165 mL"#</mathjax> of water. The <strong>final volume</strong> of the solution will be </p> <blockquote> <p><mathjax>#V_"final" = "124 mL" + "165 mL" = "289 mL"#</mathjax></p> </blockquote> <p>The concentration of the <mathjax>#"124 mL"#</mathjax> sample is <strong>equal</strong> to the concentration of the first diluted solution, i.e. <mathjax>#"0.304 M"#</mathjax>.</p> <p>The dilution factor for the <strong>second dilution</strong> will be </p> <blockquote> <p><mathjax>#"DF"_ 2 = V_"final"/V_"sample"#</mathjax></p> <p><mathjax>#"DF"_ 2 = (289 color(red)(cancel(color(black)("mL"))))/(124color(red)(cancel(color(black)("mL")))) = 2.331#</mathjax></p> </blockquote> <p>Therefore, the concentration of the <strong>final solution</strong> will be </p> <blockquote> <p><mathjax>#c_"final" = c_"sample"/"DF"_ 2#</mathjax></p> <p><mathjax>#c_"final" = "0.304 M"/2.331 = color(green)(\|bar(ul(color(white)(a/a)color(black)("0.130 M")color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"0.130 M"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You can solve this problem by using the <strong><a href="https://socratic.org/questions/how-do-you-calculate-dilution-factor">dilution factor</a></strong>, <mathjax>#"DF"#</mathjax>, which essentially tells you the factor by which the concentration of an initial solution <strong>decreased</strong> upon dilution. </p> <p>The dilution factor is calculated by using either <em>volumes</em> or <em>molarities</em></p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a)"DF" = V_"diluted"/V_"concentrated" = c_"concentrated"/c_"diluted"color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>So, the dilution factor for the <strong>first dilution</strong></p> <blockquote> <p><mathjax>#"58.0 mL " -> " 248 mL"#</mathjax></p> </blockquote> <p>will be </p> <blockquote> <p><mathjax>#"DF"_1 = (248 color(red)(cancel(color(black)("mL"))))/(58.0color(red)(cancel(color(black)("mL")))) = 4.276#</mathjax></p> </blockquote> <p>The first solution was diluted by a factor of <mathjax>#4.276#</mathjax>, which means that its concentration <strong>decreased</strong> by a factor of <mathjax>#4.276#</mathjax>. Therefore, the concentration of the diluted solution will be </p> <blockquote> <p><mathjax>#c_"diluted" = c_"concentrated"/"DF"_ 1#</mathjax></p> <p><mathjax>#c_"diluted" = "1.30 M"/4.276 = "0.304 M"#</mathjax></p> </blockquote> <p>Now, you take a sample of <mathjax>#"124 mL"#</mathjax> of this diluted solution and <strong>add</strong> another <mathjax>#"165 mL"#</mathjax> of water. The <strong>final volume</strong> of the solution will be </p> <blockquote> <p><mathjax>#V_"final" = "124 mL" + "165 mL" = "289 mL"#</mathjax></p> </blockquote> <p>The concentration of the <mathjax>#"124 mL"#</mathjax> sample is <strong>equal</strong> to the concentration of the first diluted solution, i.e. <mathjax>#"0.304 M"#</mathjax>.</p> <p>The dilution factor for the <strong>second dilution</strong> will be </p> <blockquote> <p><mathjax>#"DF"_ 2 = V_"final"/V_"sample"#</mathjax></p> <p><mathjax>#"DF"_ 2 = (289 color(red)(cancel(color(black)("mL"))))/(124color(red)(cancel(color(black)("mL")))) = 2.331#</mathjax></p> </blockquote> <p>Therefore, the concentration of the <strong>final solution</strong> will be </p> <blockquote> <p><mathjax>#c_"final" = c_"sample"/"DF"_ 2#</mathjax></p> <p><mathjax>#c_"final" = "0.304 M"/2.331 = color(green)(\|bar(ul(color(white)(a/a)color(black)("0.130 M")color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">58.0 mL of a 1.30 M solution is diluted to a total volume 248 mL. A 124-mL portion of that solution is diluted by adding 165 mL of water. What is the final concentration? Assume the volumes are additive</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/dilution-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">Dilution Calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="285913" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-08T01:43:40" itemprop="dateCreated"> Jul 8, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"0.130 M"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You can solve this problem by using the <strong><a href="https://socratic.org/questions/how-do-you-calculate-dilution-factor">dilution factor</a></strong>, <mathjax>#"DF"#</mathjax>, which essentially tells you the factor by which the concentration of an initial solution <strong>decreased</strong> upon dilution. </p> <p>The dilution factor is calculated by using either <em>volumes</em> or <em>molarities</em></p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a)"DF" = V_"diluted"/V_"concentrated" = c_"concentrated"/c_"diluted"color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>So, the dilution factor for the <strong>first dilution</strong></p> <blockquote> <p><mathjax>#"58.0 mL " -> " 248 mL"#</mathjax></p> </blockquote> <p>will be </p> <blockquote> <p><mathjax>#"DF"_1 = (248 color(red)(cancel(color(black)("mL"))))/(58.0color(red)(cancel(color(black)("mL")))) = 4.276#</mathjax></p> </blockquote> <p>The first solution was diluted by a factor of <mathjax>#4.276#</mathjax>, which means that its concentration <strong>decreased</strong> by a factor of <mathjax>#4.276#</mathjax>. Therefore, the concentration of the diluted solution will be </p> <blockquote> <p><mathjax>#c_"diluted" = c_"concentrated"/"DF"_ 1#</mathjax></p> <p><mathjax>#c_"diluted" = "1.30 M"/4.276 = "0.304 M"#</mathjax></p> </blockquote> <p>Now, you take a sample of <mathjax>#"124 mL"#</mathjax> of this diluted solution and <strong>add</strong> another <mathjax>#"165 mL"#</mathjax> of water. The <strong>final volume</strong> of the solution will be </p> <blockquote> <p><mathjax>#V_"final" = "124 mL" + "165 mL" = "289 mL"#</mathjax></p> </blockquote> <p>The concentration of the <mathjax>#"124 mL"#</mathjax> sample is <strong>equal</strong> to the concentration of the first diluted solution, i.e. <mathjax>#"0.304 M"#</mathjax>.</p> <p>The dilution factor for the <strong>second dilution</strong> will be </p> <blockquote> <p><mathjax>#"DF"_ 2 = V_"final"/V_"sample"#</mathjax></p> <p><mathjax>#"DF"_ 2 = (289 color(red)(cancel(color(black)("mL"))))/(124color(red)(cancel(color(black)("mL")))) = 2.331#</mathjax></p> </blockquote> <p>Therefore, the concentration of the <strong>final solution</strong> will be </p> <blockquote> <p><mathjax>#c_"final" = c_"sample"/"DF"_ 2#</mathjax></p> <p><mathjax>#c_"final" = "0.304 M"/2.331 = color(green)(\|bar(ul(color(white)(a/a)color(black)("0.130 M")color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/285913" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-concentration-from-absorbance"> How do you calculate concentration from absorbance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-concentration-from-titration"> How do you calculate concentration from titration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-dilution-factor"> How do you calculate dilution factor? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-do-serial-dilution-calculations"> How do you calculate serial dilutions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-calculate-concentration-of-solution-when-its-diluted"> How to calculate concentration of solution when it's diluted? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-examples-of-dilution-calculations"> What are some examples of dilution calculations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-would-be-the-concentration-of-a-solution-made-by-adding-250-ml-of-water-to-"> What would be the concentration of a solution made by adding 250 mL of water to 45.0 mL of 4.2 M KOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-would-be-the-concentration-of-a-solution-made-by-diluting-45-0-ml-of-4-2-m-"> What would be the concentration of a solution made by diluting 45.0 mL of 4.2 M KOH to 250 mL? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-a-solution-that-is-made-by-diluting-50-00-ml-of-a-4-74-m"> What is the molarity of a solution that is made by diluting 50.00 mL of a 4.74 M solution of HCl... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-volume-of-water-would-you-add-to-15-00-ml-of-a-6-77-m-solution-of-nitric-ac"> What volume of water would you add to 15.00 mL of a 6.77 M solution of nitric acid in order to... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/dilution-calculations"> See all questions in Dilution Calculations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 68114 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	58.0 mL of a 1.30 M solution is diluted to a total volume 248 mL. A 124-mL portion of that solution is diluted by adding 165 mL of water. What is the final concentration? Assume the volumes are additive	null
1,813	ac14f63c-6ddd-11ea-a6fc-ccda262736ce	https://socratic.org/questions/what-is-the-poh-of-a-0-001-m-hcl-solution	11.00	start physical_unit 8 9 poh none qc_end physical_unit 8 9 6 7 molarity qc_end end	[{"type":"physical unit","value":"pOH [OF] HCl solution"}]	[{"type":"physical unit","value":"11.00"}]	[{"type":"physical unit","value":"Molarity [OF] HCl solution [=] \\pu{0.001 M}"}]	<h1 class="questionTitle" itemprop="name">What is the pOH of a 0.001 M HCl solution? </h1>	null	11.00	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>For the autoprotolysis reaction:</p> <p><mathjax>#2H_2O(l) rightleftharpoons H_3O^+ +HO^(-)#</mathjax>,</p> <p>we know that <mathjax>#K_w=[H_3O^+][HO^-]=10^-14#</mathjax> under standard conditions............</p> <p>And taking <mathjax>#log_10#</mathjax> of both sides we gets............</p> <p><mathjax>#log_10K_w=log_(10)10^-14=log_10[H_3O^+]+log_10[HO^-]#</mathjax></p> <p>And thus <mathjax>#-log_10[H_3O^+]-log_10[HO^-]=-log_(10)10^(-14)=14#</mathjax></p> <p>But by definition, <mathjax>#-log_10[H_3O^+]=pH#</mathjax>, and <mathjax>#-log_10[HO^-]=pOH#</mathjax></p> <p>So................</p> <p><mathjax>#pH+pOH=14#</mathjax></p> <p>You will not be asked to reproduce this as a first year student or as an A-level student. You will be asked (as you have been here!) to use the relationship. </p> <p>And <mathjax>#[HO^-]=10^(-11)molL^-1#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, we know that <mathjax>#pH+pOH=14#</mathjax>, so..............</p> <p><mathjax>#pOH=11#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>For the autoprotolysis reaction:</p> <p><mathjax>#2H_2O(l) rightleftharpoons H_3O^+ +HO^(-)#</mathjax>,</p> <p>we know that <mathjax>#K_w=[H_3O^+][HO^-]=10^-14#</mathjax> under standard conditions............</p> <p>And taking <mathjax>#log_10#</mathjax> of both sides we gets............</p> <p><mathjax>#log_10K_w=log_(10)10^-14=log_10[H_3O^+]+log_10[HO^-]#</mathjax></p> <p>And thus <mathjax>#-log_10[H_3O^+]-log_10[HO^-]=-log_(10)10^(-14)=14#</mathjax></p> <p>But by definition, <mathjax>#-log_10[H_3O^+]=pH#</mathjax>, and <mathjax>#-log_10[HO^-]=pOH#</mathjax></p> <p>So................</p> <p><mathjax>#pH+pOH=14#</mathjax></p> <p>You will not be asked to reproduce this as a first year student or as an A-level student. You will be asked (as you have been here!) to use the relationship. </p> <p>And <mathjax>#[HO^-]=10^(-11)molL^-1#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the pOH of a 0.001 M HCl solution? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/the-ph-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">pH</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="423645" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-15T07:02:35" itemprop="dateCreated"> May 15, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, we know that <mathjax>#pH+pOH=14#</mathjax>, so..............</p> <p><mathjax>#pOH=11#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>For the autoprotolysis reaction:</p> <p><mathjax>#2H_2O(l) rightleftharpoons H_3O^+ +HO^(-)#</mathjax>,</p> <p>we know that <mathjax>#K_w=[H_3O^+][HO^-]=10^-14#</mathjax> under standard conditions............</p> <p>And taking <mathjax>#log_10#</mathjax> of both sides we gets............</p> <p><mathjax>#log_10K_w=log_(10)10^-14=log_10[H_3O^+]+log_10[HO^-]#</mathjax></p> <p>And thus <mathjax>#-log_10[H_3O^+]-log_10[HO^-]=-log_(10)10^(-14)=14#</mathjax></p> <p>But by definition, <mathjax>#-log_10[H_3O^+]=pH#</mathjax>, and <mathjax>#-log_10[HO^-]=pOH#</mathjax></p> <p>So................</p> <p><mathjax>#pH+pOH=14#</mathjax></p> <p>You will not be asked to reproduce this as a first year student or as an A-level student. You will be asked (as you have been here!) to use the relationship. </p> <p>And <mathjax>#[HO^-]=10^(-11)molL^-1#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/423645" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-pka"> How do you determine pH from pKa? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-ph-values-of-acids-and-bases-differ"> How do pH values of acids and bases differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-something-on-a-ph-scale"> How do you calculate something on a pH scale? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-diprotic-acid"> How do you calculate pH diprotic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-from-acid-dissociation-constant"> How do you calculate pH from acid dissociation constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-of-acid-and-base-solution"> How do you calculate pH of acid and base solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ph-scale-0-14"> Why is the pH scale 0-14? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-ph-the-measure-of-the-hydrogen-ion-concentration"> Is pH a measure of the hydrogen ion concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-solubility-affect-ph"> How does solubility affect pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-ph-relate-to-pka-in-a-titration"> How does pH relate to pKa in a titration? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/the-ph-concept"> See all questions in pH </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 7091 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the pOH of a 0.001 M HCl solution?	null
1,814	a92ed434-6ddd-11ea-b518-ccda262736ce	https://socratic.org/questions/how-do-you-balance-clo-2-h-2o-hclo-3-hcl	6 ClO2 + 3 H2O -> 5 HClO3 + HCl	start chemical_equation qc_end chemical_equation 4 10 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the equation"}]	[{"type":"chemical equation","value":"6 ClO2 + 3 H2O -> 5 HClO3 + HCl"}]	[{"type":"chemical equation","value":"ClO2 + H2O -> HClO3 + HCl"}]	<h1 class="questionTitle" itemprop="name">How do you balance #ClO_2 + H_2O = HClO_3 + HCl#?</h1>	null	6 ClO2 + 3 H2O -> 5 HClO3 + HCl	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is quite difficult for a beginner especially if you're doing the trial and error method. But this kind of equation can also be solved using the algebraic method to find the coefficients of each compound in the equation. </p> <p>By Trial and Error:</p> <p><mathjax>#ClO_2#</mathjax> + <mathjax>#H_2O#</mathjax> <mathjax>#->#</mathjax> <mathjax>#HClO_3#</mathjax> + <mathjax>#HCl#</mathjax></p> <p><mathjax>#6ClO_2#</mathjax> + <mathjax>#3H_2O#</mathjax> <mathjax>#->#</mathjax> <mathjax>#5HClO_3#</mathjax> + <mathjax>#HCl#</mathjax></p> <p>Make initial inventory of the <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> composing the <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a> in both reactants and products of the equation.</p> <p>Reactants<br/> Cl=<mathjax>#cancel1#</mathjax>6<br/> O=<mathjax>#cancel3#</mathjax><mathjax>#cancel13#</mathjax>15<br/> H=<mathjax>#cancel2#</mathjax>6</p> <p>Products<br/> Cl=<mathjax>#cancel2#</mathjax>6<br/> O=<mathjax>#cancel3#</mathjax>15<br/> H=<mathjax>#cancel2#</mathjax>6</p> <ol> <li>Put 6 in front of the 1st reactant and recount the number of moles of each element since coefficient has been changed;</li> <li>To balance the chlorine on the product side, put 5 as coefficient for the 1st compound of the products;</li> <li>Then, recount the number of moles for each element of the products,in which case chlorine is already 6; balance with the reactants side;</li> <li>Back to the reactants side,balance the hydrogen by putting 3 as coefficient for the 2nd reactant; then recount the number of moles and observed whether the inventory of both the reactants and products are balanced.</li> </ol></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#6ClO_2#</mathjax> + <mathjax>#3H_2O#</mathjax> <mathjax>#->#</mathjax> <mathjax>#5HClO_3#</mathjax> + <mathjax>#HCl#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is quite difficult for a beginner especially if you're doing the trial and error method. But this kind of equation can also be solved using the algebraic method to find the coefficients of each compound in the equation. </p> <p>By Trial and Error:</p> <p><mathjax>#ClO_2#</mathjax> + <mathjax>#H_2O#</mathjax> <mathjax>#->#</mathjax> <mathjax>#HClO_3#</mathjax> + <mathjax>#HCl#</mathjax></p> <p><mathjax>#6ClO_2#</mathjax> + <mathjax>#3H_2O#</mathjax> <mathjax>#->#</mathjax> <mathjax>#5HClO_3#</mathjax> + <mathjax>#HCl#</mathjax></p> <p>Make initial inventory of the <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> composing the <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a> in both reactants and products of the equation.</p> <p>Reactants<br/> Cl=<mathjax>#cancel1#</mathjax>6<br/> O=<mathjax>#cancel3#</mathjax><mathjax>#cancel13#</mathjax>15<br/> H=<mathjax>#cancel2#</mathjax>6</p> <p>Products<br/> Cl=<mathjax>#cancel2#</mathjax>6<br/> O=<mathjax>#cancel3#</mathjax>15<br/> H=<mathjax>#cancel2#</mathjax>6</p> <ol> <li>Put 6 in front of the 1st reactant and recount the number of moles of each element since coefficient has been changed;</li> <li>To balance the chlorine on the product side, put 5 as coefficient for the 1st compound of the products;</li> <li>Then, recount the number of moles for each element of the products,in which case chlorine is already 6; balance with the reactants side;</li> <li>Back to the reactants side,balance the hydrogen by putting 3 as coefficient for the 2nd reactant; then recount the number of moles and observed whether the inventory of both the reactants and products are balanced.</li> </ol></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you balance #ClO_2 + H_2O = HClO_3 + HCl#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="204335" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/jarni-renz"><img alt="" class="" src="https://profilepictures.socratic.org/i6OiZQmVRHWljDVlwm8v_WIN_20160301_180231.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/jarni-renz"> Jarni Renz </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-27T12:17:14" itemprop="dateCreated"> Dec 27, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#6ClO_2#</mathjax> + <mathjax>#3H_2O#</mathjax> <mathjax>#->#</mathjax> <mathjax>#5HClO_3#</mathjax> + <mathjax>#HCl#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is quite difficult for a beginner especially if you're doing the trial and error method. But this kind of equation can also be solved using the algebraic method to find the coefficients of each compound in the equation. </p> <p>By Trial and Error:</p> <p><mathjax>#ClO_2#</mathjax> + <mathjax>#H_2O#</mathjax> <mathjax>#->#</mathjax> <mathjax>#HClO_3#</mathjax> + <mathjax>#HCl#</mathjax></p> <p><mathjax>#6ClO_2#</mathjax> + <mathjax>#3H_2O#</mathjax> <mathjax>#->#</mathjax> <mathjax>#5HClO_3#</mathjax> + <mathjax>#HCl#</mathjax></p> <p>Make initial inventory of the <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> composing the <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a> in both reactants and products of the equation.</p> <p>Reactants<br/> Cl=<mathjax>#cancel1#</mathjax>6<br/> O=<mathjax>#cancel3#</mathjax><mathjax>#cancel13#</mathjax>15<br/> H=<mathjax>#cancel2#</mathjax>6</p> <p>Products<br/> Cl=<mathjax>#cancel2#</mathjax>6<br/> O=<mathjax>#cancel3#</mathjax>15<br/> H=<mathjax>#cancel2#</mathjax>6</p> <ol> <li>Put 6 in front of the 1st reactant and recount the number of moles of each element since coefficient has been changed;</li> <li>To balance the chlorine on the product side, put 5 as coefficient for the 1st compound of the products;</li> <li>Then, recount the number of moles for each element of the products,in which case chlorine is already 6; balance with the reactants side;</li> <li>Back to the reactants side,balance the hydrogen by putting 3 as coefficient for the 2nd reactant; then recount the number of moles and observed whether the inventory of both the reactants and products are balanced.</li> </ol></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/204335" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------> H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -> Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? 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Sodium phosphate and calcium chloride react to form... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-equation-kclo3-kcl-o2"> How can I balance this equation? ____ #KClO_3 -># ____ #KCl +# ____ #O_2# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-balancing-chemical-equations-important"> Why is balancing chemical equations important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/balancing-chemical-equations"> See all questions in Balancing Chemical Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1654 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How do you balance #ClO_2 + H_2O = HClO_3 + HCl#?	null
1,815	aad83c74-6ddd-11ea-a12c-ccda262736ce	https://socratic.org/questions/in-the-reaction-b-2h-6-g-3o-2-g-b-2o-3-s-3h-2o-g-h-2035-kj-how-much-heat-is-rele	124.68 kJ	start physical_unit 1 2 heat_energy kj qc_end chemical_equation 3 11 qc_end physical_unit 1 2 14 15 deltah qc_end physical_unit 3 3 25 26 mass qc_end physical_unit 6 6 29 30 mass qc_end end	[{"type":"physical unit","value":"Released heat [OF] the reaction [IN] kJ"}]	[{"type":"physical unit","value":"124.68 kJ"}]	[{"type":"chemical equation","value":"B2H6(g) + 3 O2(g) -> B2O3(s) + 3 H2O(g)"},{"type":"physical unit","value":"DeltaH [OF] the reaction [=] \\pu{-2035 kJ}"},{"type":"physical unit","value":"Mass [OF] B2H6 [=] \\pu{4.65 g}"},{"type":"physical unit","value":"Mass [OF] O2 [=] \\pu{2.94 g}"}]	<h1 class="questionTitle" itemprop="name">In the reaction #B_2H_6(g) + 3O_2(g) -> B_2O_3(s) + 3H_2O(g), ΔH = -2035 kJ#, how much heat is released when a mixture of #4.65# #g# #B_2H_6# and #2.94# #g# #O_2# is burned?</h1>	null	124.68 kJ	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The most important thing to realize here is that you must first determine whether or not you're dealing with a <strong><a href="http://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a></strong>. </p> <p>This is important because it tells you the <em>number of moles</em> of diborane, <mathjax>#"B"_2"H"_6#</mathjax>, that <strong>actually take part in the reaction</strong>. </p> <p>So, start by taking a look at the balanced chemical equation for this reaction </p> <blockquote> <p><mathjax>#"B"_2"H"_text(6(g]) + color(purple)(3)"O"_text(2(g]) -> "B"_2"O"_text(3(s]) + 3"H"_2"O"_text((g])#</mathjax></p> </blockquote> <p>The <mathjax>#1:color(purple)(3)#</mathjax> <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> that exists between diborane and oxygen gas tells you tha the reaction consumes <mathjax>#color(purple)(3)#</mathjax> <strong>moles</strong> of oxygen gas <strong>for every</strong> <mathjax>#1#</mathjax> <strong>mole</strong> of diborane that takes part in the reaction. </p> <p>So, use the <strong>molar masses</strong> of diborane and oxygen gas to calculate how many moles of each you have in your samples</p> <blockquote> <p><mathjax>#4.56 color(red)(cancel(color(black)("g"))) * ("1 mole B"_2"H"_6)/(27.67color(red)(cancel(color(black)("g")))) = "0.1648 moles B"_2"H"_6#</mathjax></p> </blockquote> <p>and</p> <blockquote> <p><mathjax>#2.94 color(red)(cancel(color(black)("g"))) * "1 mole O"_2/(15.9994color(red)(cancel(color(black)("g")))) = "0.1838 moles O"_2#</mathjax></p> </blockquote> <p>Notice that you don't have enough oxygen gas to allow for <strong>all the moles</strong> of diborane to take part in the reaction <mathjax>#->#</mathjax> oxygen acts as a <a href="http://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a>. </p> <p>This means that the oxygen will be <strong>consumed</strong> before all the moles of dibirane are consumed. More specifically, only</p> <blockquote> <p><mathjax>#0.1838 color(red)(cancel(color(black)("moles O"_2))) * ("1 mole B"_2"H"_6)/(color(purple)(3)color(red)(cancel(color(black)("moles O"_2)))) = "0.06127 moles B"_2"H"_6#</mathjax> </p> </blockquote> <p>will take part in the reaction, the rest will be <em>in excess</em>. </p> <p>Now, according to the <strong>thermochemical equation</strong>, when <strong>one mole</strong> of diborane reacts with <strong>three moles</strong> of oxygen gas, <strong>one mole</strong> of boron trioxide, <mathjax>#"B"_2"O"_3#</mathjax> and <strong>three moles</strong> of water are produced, and <mathjax>#"2035 kJ"#</mathjax> of heat are <strong>released</strong>. </p> <p>In your case, <mathjax>#0.06127#</mathjax> moles of diborane will react with your sample of oxygen gas to give off </p> <blockquote> <p><mathjax>#0.06127 color(red)(cancel(color(black)("moles B"_2"H"_6))) * "2035 kJ"/(1color(red)(cancel(color(black)("mole B"_2"H"_6)))) = "124.68 kJ"#</mathjax></p> </blockquote> <p>Rounded to three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the answer will be </p> <blockquote> <p><mathjax>#q = color(green)("125 kJ") ->#</mathjax> <em>heat <strong>given off</strong></em></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"125 kJ"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The most important thing to realize here is that you must first determine whether or not you're dealing with a <strong><a href="http://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a></strong>. </p> <p>This is important because it tells you the <em>number of moles</em> of diborane, <mathjax>#"B"_2"H"_6#</mathjax>, that <strong>actually take part in the reaction</strong>. </p> <p>So, start by taking a look at the balanced chemical equation for this reaction </p> <blockquote> <p><mathjax>#"B"_2"H"_text(6(g]) + color(purple)(3)"O"_text(2(g]) -> "B"_2"O"_text(3(s]) + 3"H"_2"O"_text((g])#</mathjax></p> </blockquote> <p>The <mathjax>#1:color(purple)(3)#</mathjax> <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> that exists between diborane and oxygen gas tells you tha the reaction consumes <mathjax>#color(purple)(3)#</mathjax> <strong>moles</strong> of oxygen gas <strong>for every</strong> <mathjax>#1#</mathjax> <strong>mole</strong> of diborane that takes part in the reaction. </p> <p>So, use the <strong>molar masses</strong> of diborane and oxygen gas to calculate how many moles of each you have in your samples</p> <blockquote> <p><mathjax>#4.56 color(red)(cancel(color(black)("g"))) * ("1 mole B"_2"H"_6)/(27.67color(red)(cancel(color(black)("g")))) = "0.1648 moles B"_2"H"_6#</mathjax></p> </blockquote> <p>and</p> <blockquote> <p><mathjax>#2.94 color(red)(cancel(color(black)("g"))) * "1 mole O"_2/(15.9994color(red)(cancel(color(black)("g")))) = "0.1838 moles O"_2#</mathjax></p> </blockquote> <p>Notice that you don't have enough oxygen gas to allow for <strong>all the moles</strong> of diborane to take part in the reaction <mathjax>#->#</mathjax> oxygen acts as a <a href="http://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a>. </p> <p>This means that the oxygen will be <strong>consumed</strong> before all the moles of dibirane are consumed. More specifically, only</p> <blockquote> <p><mathjax>#0.1838 color(red)(cancel(color(black)("moles O"_2))) * ("1 mole B"_2"H"_6)/(color(purple)(3)color(red)(cancel(color(black)("moles O"_2)))) = "0.06127 moles B"_2"H"_6#</mathjax> </p> </blockquote> <p>will take part in the reaction, the rest will be <em>in excess</em>. </p> <p>Now, according to the <strong>thermochemical equation</strong>, when <strong>one mole</strong> of diborane reacts with <strong>three moles</strong> of oxygen gas, <strong>one mole</strong> of boron trioxide, <mathjax>#"B"_2"O"_3#</mathjax> and <strong>three moles</strong> of water are produced, and <mathjax>#"2035 kJ"#</mathjax> of heat are <strong>released</strong>. </p> <p>In your case, <mathjax>#0.06127#</mathjax> moles of diborane will react with your sample of oxygen gas to give off </p> <blockquote> <p><mathjax>#0.06127 color(red)(cancel(color(black)("moles B"_2"H"_6))) * "2035 kJ"/(1color(red)(cancel(color(black)("mole B"_2"H"_6)))) = "124.68 kJ"#</mathjax></p> </blockquote> <p>Rounded to three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the answer will be </p> <blockquote> <p><mathjax>#q = color(green)("125 kJ") ->#</mathjax> <em>heat <strong>given off</strong></em></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">In the reaction #B_2H_6(g) + 3O_2(g) -> B_2O_3(s) + 3H_2O(g), ΔH = -2035 kJ#, how much heat is released when a mixture of #4.65# #g# #B_2H_6# and #2.94# #g# #O_2# is burned?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/enthalpy" itemprop="url"> <span class="breadcrumb" itemprop="title">Enthalpy</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="221185" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-02-03T23:37:41" itemprop="dateCreated"> Feb 3, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"125 kJ"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The most important thing to realize here is that you must first determine whether or not you're dealing with a <strong><a href="http://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a></strong>. </p> <p>This is important because it tells you the <em>number of moles</em> of diborane, <mathjax>#"B"_2"H"_6#</mathjax>, that <strong>actually take part in the reaction</strong>. </p> <p>So, start by taking a look at the balanced chemical equation for this reaction </p> <blockquote> <p><mathjax>#"B"_2"H"_text(6(g]) + color(purple)(3)"O"_text(2(g]) -> "B"_2"O"_text(3(s]) + 3"H"_2"O"_text((g])#</mathjax></p> </blockquote> <p>The <mathjax>#1:color(purple)(3)#</mathjax> <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> that exists between diborane and oxygen gas tells you tha the reaction consumes <mathjax>#color(purple)(3)#</mathjax> <strong>moles</strong> of oxygen gas <strong>for every</strong> <mathjax>#1#</mathjax> <strong>mole</strong> of diborane that takes part in the reaction. </p> <p>So, use the <strong>molar masses</strong> of diborane and oxygen gas to calculate how many moles of each you have in your samples</p> <blockquote> <p><mathjax>#4.56 color(red)(cancel(color(black)("g"))) * ("1 mole B"_2"H"_6)/(27.67color(red)(cancel(color(black)("g")))) = "0.1648 moles B"_2"H"_6#</mathjax></p> </blockquote> <p>and</p> <blockquote> <p><mathjax>#2.94 color(red)(cancel(color(black)("g"))) * "1 mole O"_2/(15.9994color(red)(cancel(color(black)("g")))) = "0.1838 moles O"_2#</mathjax></p> </blockquote> <p>Notice that you don't have enough oxygen gas to allow for <strong>all the moles</strong> of diborane to take part in the reaction <mathjax>#->#</mathjax> oxygen acts as a <a href="http://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a>. </p> <p>This means that the oxygen will be <strong>consumed</strong> before all the moles of dibirane are consumed. More specifically, only</p> <blockquote> <p><mathjax>#0.1838 color(red)(cancel(color(black)("moles O"_2))) * ("1 mole B"_2"H"_6)/(color(purple)(3)color(red)(cancel(color(black)("moles O"_2)))) = "0.06127 moles B"_2"H"_6#</mathjax> </p> </blockquote> <p>will take part in the reaction, the rest will be <em>in excess</em>. </p> <p>Now, according to the <strong>thermochemical equation</strong>, when <strong>one mole</strong> of diborane reacts with <strong>three moles</strong> of oxygen gas, <strong>one mole</strong> of boron trioxide, <mathjax>#"B"_2"O"_3#</mathjax> and <strong>three moles</strong> of water are produced, and <mathjax>#"2035 kJ"#</mathjax> of heat are <strong>released</strong>. </p> <p>In your case, <mathjax>#0.06127#</mathjax> moles of diborane will react with your sample of oxygen gas to give off </p> <blockquote> <p><mathjax>#0.06127 color(red)(cancel(color(black)("moles B"_2"H"_6))) * "2035 kJ"/(1color(red)(cancel(color(black)("mole B"_2"H"_6)))) = "124.68 kJ"#</mathjax></p> </blockquote> <p>Rounded to three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the answer will be </p> <blockquote> <p><mathjax>#q = color(green)("125 kJ") ->#</mathjax> <em>heat <strong>given off</strong></em></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/221185" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-enthalpy-changes-expressed-in-chemical-equations"> How are enthalpy changes expressed in chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-enthalpy-change-be-determined-for-an-aqueous-solution"> How can enthalpy change be determined for an aqueous solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-enthalpy-change-with-pressure"> How does enthalpy change with pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-standard-molar-enthalpy-formation"> How do you calculate standard molar enthalpy of formation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-enthalpy-a-state-function"> Why is enthalpy a state function? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-enthalpy-of-formation-of-oxygen-zero"> Why is the enthalpy of formation of oxygen zero? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-enthalpy-a-state-function-2"> Why is enthalpy a state function? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-enthalpy-cannot-be-measured-directly"> Why can enthalpy not be measured directly? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-pressure-affect-enthalpy"> How does pressure affect enthalpy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-enthalpy-relate-to-internal-energy"> How does enthalpy relate to internal energy? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/enthalpy"> See all questions in Enthalpy </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 14082 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	In the reaction #B_2H_6(g) + 3O_2(g) -> B_2O_3(s) + 3H_2O(g), ΔH = -2035 kJ#, how much heat is released when a mixture of #4.65# #g# #B_2H_6# and #2.94# #g# #O_2# is burned?	null
1,816	aad81538-6ddd-11ea-8c11-ccda262736ce	https://socratic.org/questions/how-many-grams-of-ag-can-be-formed-from-5-50-grams-of-ag-2o-in-the-equation-2ag-	5.12 grams	start physical_unit 4 4 mass g qc_end physical_unit 12 12 9 10 mass qc_end chemical_equation 16 22 qc_end end	[{"type":"physical unit","value":"Mass [OF] Ag [IN] grams"}]	[{"type":"physical unit","value":"5.12 grams"}]	[{"type":"physical unit","value":"Mass [OF] Ag2O [=] \\pu{5.50 grams}"},{"type":"chemical equation","value":"2 Ag2O(s) -> 4 Ag(s) + O2(g)"}]	<h1 class="questionTitle" itemprop="name">How many grams of #Ag# can be formed from 5.50 grams of #Ag_2O# in the equation: #2Ag_2O (s) -> 4Ag (s) + O_2 (g)#?</h1>	null	5.12 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Moles of silver oxide"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(5.50g)/(231.74gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??mol#</mathjax></p> <p><mathjax>#"Grams of silver metal"#</mathjax> <mathjax>#=#</mathjax> </p> <p><mathjax>#2xx(5.50g)/(231.74gmol^-1)xx107.87gmol^-1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??*g#</mathjax>.</p> <p>Why did I put the <mathjax>#2#</mathjax> in the front of the expression?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Clearly <mathjax>#"moles of silver oxide:moles of dioxygen"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#2:1#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Moles of silver oxide"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(5.50g)/(231.74gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??mol#</mathjax></p> <p><mathjax>#"Grams of silver metal"#</mathjax> <mathjax>#=#</mathjax> </p> <p><mathjax>#2xx(5.50g)/(231.74gmol^-1)xx107.87gmol^-1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??*g#</mathjax>.</p> <p>Why did I put the <mathjax>#2#</mathjax> in the front of the expression?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many grams of #Ag# can be formed from 5.50 grams of #Ag_2O# in the equation: #2Ag_2O (s) -> 4Ag (s) + O_2 (g)#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="273314" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-03T07:07:28" itemprop="dateCreated"> Jun 3, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Clearly <mathjax>#"moles of silver oxide:moles of dioxygen"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#2:1#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Moles of silver oxide"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(5.50g)/(231.74gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??mol#</mathjax></p> <p><mathjax>#"Grams of silver metal"#</mathjax> <mathjax>#=#</mathjax> </p> <p><mathjax>#2xx(5.50g)/(231.74gmol^-1)xx107.87gmol^-1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??*g#</mathjax>.</p> <p>Why did I put the <mathjax>#2#</mathjax> in the front of the expression?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/273314" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What is stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ab82402bf342f48d93ac6"> Question #93ac6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-we-study-stoichiometry"> Why do we study stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" 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Na2O + H2O ---> 2 NaOH </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-mass-of-iron-is-needed-to-react-with-16-0-grams-of-sulfur-8-fe-s8-8-fes"> What mass of iron is needed to react with 16.0 grams of sulfur? 8 Fe + S8 ---> 8 FeS </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/according-to-8-fe-s8-8-fes-how-many-grams-of-fes-are-produced"> According to 8 Fe + S8 ---> 8 FeS How many grams of FeS are produced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/12-00-moles-of-naclo3-will-produce-how-many-grams-of-o2-2-naclo3-2-nacl-3-o2"> 12.00 moles of NaClO3 will produce how many grams of O2? 2 NaClO3 ---> 2 NaCl + 3 O2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-nacl-are-produced-when-80-0-grams-of-o2-are-produced-2-naclo3-"> How many grams of NaCl are produced when 80.0 grams of O2 are produced? 2 NaClO3 ---> 2 NaCl + 3 O2 </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/stoichiometry"> See all questions in Stoichiometry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1681 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many grams of #Ag# can be formed from 5.50 grams of #Ag_2O# in the equation: #2Ag_2O (s) -> 4Ag (s) + O_2 (g)#?	null
1,817	ac11e7e8-6ddd-11ea-b0a1-ccda262736ce	https://socratic.org/questions/how-do-you-write-an-equation-for-the-reaction-between-zinc-metal-and-hydrochlori	Zn(s) + 2 HCl(aq) -> ZnCl2(aq) + H2(g)	start chemical_equation qc_end substance 10 11 qc_end substance 13 15 qc_end substance 17 19 qc_end substance 21 22 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the reaction"}]	[{"type":"chemical equation","value":"Zn(s) + 2 HCl(aq) -> ZnCl2(aq) + H2(g)"}]	[{"type":"substance name","value":"Zinc metal"},{"type":"substance name","value":"Hydrochloric acid (aqueous)"},{"type":"substance name","value":"Zinc chloride (aqueous)"},{"type":"substance name","value":"Hydrogen gas"}]	<h1 class="questionTitle" itemprop="name">How do you write an equation for the reaction between zinc metal and hydrochloric acid (aqueous) producing zinc chloride (aqueous) and hydrogen gas?</h1>	null	Zn(s) + 2 HCl(aq) -> ZnCl2(aq) + H2(g)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The net reaction is <mathjax>#Zn(s)+2H^+(aq) ->Zn^(2+)(aq)+H_2(g)#</mathjax><br/> The <mathjax>#Cl^-#</mathjax> ions are spectators - they don't change.</p> <p>This experiment includes the reaction of zinc with hydrochloric acid. The experiment compares reactivity of three metals; magnesium, zinc and copper. The video includes a discussion of writing balanced equations for all the observed reactions.</p> <p> <iframe src="https://www.youtube.com/embed/qhzF3qsQfDk?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Zn(s)+2HCl(aq)->ZnCl_2(aq)+H_2(g)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The net reaction is <mathjax>#Zn(s)+2H^+(aq) ->Zn^(2+)(aq)+H_2(g)#</mathjax><br/> The <mathjax>#Cl^-#</mathjax> ions are spectators - they don't change.</p> <p>This experiment includes the reaction of zinc with hydrochloric acid. The experiment compares reactivity of three metals; magnesium, zinc and copper. The video includes a discussion of writing balanced equations for all the observed reactions.</p> <p> <iframe src="https://www.youtube.com/embed/qhzF3qsQfDk?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you write an equation for the reaction between zinc metal and hydrochloric acid (aqueous) producing zinc chloride (aqueous) and hydrogen gas?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-reactions-and-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions and Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="334716" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/noel-p"><img alt="" class="" src="https://profilepictures.socratic.org/02ThC0uRMah0LVgFe9Tg_CrabbyMrP.jpg" title=""/></a> <a class="secondContributorPic" href="/users/meneernask"><img alt="" class="" src="https://profilepictures.socratic.org/gpA0lokRGK9vLVUnAMAy_meneernask.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/noel-p"> mrpauller.weebly.com </a>·<a class="topContributorLink" href="/users/meneernask"> MeneerNask </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-11-11T12:18:43" itemprop="dateCreated"> Nov 11, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Zn(s)+2HCl(aq)->ZnCl_2(aq)+H_2(g)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The net reaction is <mathjax>#Zn(s)+2H^+(aq) ->Zn^(2+)(aq)+H_2(g)#</mathjax><br/> The <mathjax>#Cl^-#</mathjax> ions are spectators - they don't change.</p> <p>This experiment includes the reaction of zinc with hydrochloric acid. The experiment compares reactivity of three metals; magnesium, zinc and copper. The video includes a discussion of writing balanced equations for all the observed reactions.</p> <p> <iframe src="https://www.youtube.com/embed/qhzF3qsQfDk?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/334716" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb002bf34694a4fee47"> Question #fee47 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb402bf34694c8c5c15"> Question #c5c15 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb802bf346950519eb9"> Question #19eb9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cbf02bf3469570e2ea2"> Question #e2ea2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc002bf34695a6bc751"> Question #bc751 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc202bf3469570e2ea6"> Question #e2ea6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531e867a02bf342492a08b07"> Question #08b07 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-thermochemical-equation-for-the-combustion-of-benzene"> What is the thermochemical equation for the combustion of benzene? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-reversible"> Why are chemical reactions reversible? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-important"> Why are chemical reactions important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/chemical-reactions-and-equations"> See all questions in Chemical Reactions and Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 82182 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How do you write an equation for the reaction between zinc metal and hydrochloric acid (aqueous) producing zinc chloride (aqueous) and hydrogen gas?	null
1,818	abcb44ca-6ddd-11ea-86eb-ccda262736ce	https://socratic.org/questions/what-is-the-reaction-of-an-ion-with-h-2o-to-produce-h-aq-and-oh-aq	H2O <=> H+(aq) + OH-(aq)	start chemical_equation qc_end chemical_equation 8 8 qc_end chemical_equation 11 11 qc_end chemical_equation 13 13 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the reaction"}]	[{"type":"chemical equation","value":"H2O <=> H+(aq) + OH-(aq)"}]	[{"type":"chemical equation","value":"H2O"},{"type":"chemical equation","value":"H+(aq)"},{"type":"chemical equation","value":"OH-(aq)"}]	<h1 class="questionTitle" itemprop="name">What is the reaction of an ion with #H_2O# to produce #H^+(aq)# and #OH^(-)(aq)#?</h1>	null	H2O <=> H+(aq) + OH-(aq)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>OR, MORE COMMONLY..........</p> <p><mathjax>#2H_2O rightleftharpoonsH_3O^+ +HO^-#</mathjax></p> <p>This is the so-called <mathjax>#"autoprotolysis reaction of water"#</mathjax>, which has been meticulously studied, and underlies our conception of acid/base chemistry.</p> <p>The <mathjax>#"hydronium ion"#</mathjax>, <mathjax>#H_3O^+#</mathjax>, and <mathjax>#"hydroxide ion"#</mathjax>, <mathjax>#HO^-#</mathjax>, are conceived to be the characteristic cation and characteristic anion of the <mathjax>#"WATER SOLVENT"#</mathjax>, i.e. <mathjax>#"the acidium ion"#</mathjax>, and <mathjax>#"the hydroxide ion"#</mathjax>. I write <mathjax>#"conceived"#</mathjax> because the acidium ion in water solution is probably <mathjax>#H_5O_2^+#</mathjax> or <mathjax>#H_7O_3^+#</mathjax>, a cluster of several water molecules WITH AN EXTRA <mathjax>#H^+#</mathjax> associated with the cluster. We write <mathjax>#H^+#</mathjax>, or <mathjax>#H_3O^+#</mathjax> to represent this species, i.e. as a shorthand. </p> <p>In water at <mathjax>#298*K#</mathjax>, </p> <p><mathjax>#2H_2O rightleftharpoonsH_3O^+ +HO^-#</mathjax> <mathjax>#K_w=[H_3O^+][HO^-]=10^-14#</mathjax>.</p> <p>Given that this is a bond-breaking reaction, how do you think this equilibrium would evolve AT HIGHER TEMPERATURES? (If you are not an undergrad, don't bother with this question). </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We write.........<mathjax>#H_2O(l) rightleftharpoonsH^(+) + HO^-#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>OR, MORE COMMONLY..........</p> <p><mathjax>#2H_2O rightleftharpoonsH_3O^+ +HO^-#</mathjax></p> <p>This is the so-called <mathjax>#"autoprotolysis reaction of water"#</mathjax>, which has been meticulously studied, and underlies our conception of acid/base chemistry.</p> <p>The <mathjax>#"hydronium ion"#</mathjax>, <mathjax>#H_3O^+#</mathjax>, and <mathjax>#"hydroxide ion"#</mathjax>, <mathjax>#HO^-#</mathjax>, are conceived to be the characteristic cation and characteristic anion of the <mathjax>#"WATER SOLVENT"#</mathjax>, i.e. <mathjax>#"the acidium ion"#</mathjax>, and <mathjax>#"the hydroxide ion"#</mathjax>. I write <mathjax>#"conceived"#</mathjax> because the acidium ion in water solution is probably <mathjax>#H_5O_2^+#</mathjax> or <mathjax>#H_7O_3^+#</mathjax>, a cluster of several water molecules WITH AN EXTRA <mathjax>#H^+#</mathjax> associated with the cluster. We write <mathjax>#H^+#</mathjax>, or <mathjax>#H_3O^+#</mathjax> to represent this species, i.e. as a shorthand. </p> <p>In water at <mathjax>#298*K#</mathjax>, </p> <p><mathjax>#2H_2O rightleftharpoonsH_3O^+ +HO^-#</mathjax> <mathjax>#K_w=[H_3O^+][HO^-]=10^-14#</mathjax>.</p> <p>Given that this is a bond-breaking reaction, how do you think this equilibrium would evolve AT HIGHER TEMPERATURES? (If you are not an undergrad, don't bother with this question). </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the reaction of an ion with #H_2O# to produce #H^+(aq)# and #OH^(-)(aq)#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/stoichiometry-with-acid-and-base-dissociation" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry with Acid and Base Dissociation</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="405513" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-12T05:32:21" itemprop="dateCreated"> Apr 12, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We write.........<mathjax>#H_2O(l) rightleftharpoonsH^(+) + HO^-#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>OR, MORE COMMONLY..........</p> <p><mathjax>#2H_2O rightleftharpoonsH_3O^+ +HO^-#</mathjax></p> <p>This is the so-called <mathjax>#"autoprotolysis reaction of water"#</mathjax>, which has been meticulously studied, and underlies our conception of acid/base chemistry.</p> <p>The <mathjax>#"hydronium ion"#</mathjax>, <mathjax>#H_3O^+#</mathjax>, and <mathjax>#"hydroxide ion"#</mathjax>, <mathjax>#HO^-#</mathjax>, are conceived to be the characteristic cation and characteristic anion of the <mathjax>#"WATER SOLVENT"#</mathjax>, i.e. <mathjax>#"the acidium ion"#</mathjax>, and <mathjax>#"the hydroxide ion"#</mathjax>. I write <mathjax>#"conceived"#</mathjax> because the acidium ion in water solution is probably <mathjax>#H_5O_2^+#</mathjax> or <mathjax>#H_7O_3^+#</mathjax>, a cluster of several water molecules WITH AN EXTRA <mathjax>#H^+#</mathjax> associated with the cluster. We write <mathjax>#H^+#</mathjax>, or <mathjax>#H_3O^+#</mathjax> to represent this species, i.e. as a shorthand. </p> <p>In water at <mathjax>#298*K#</mathjax>, </p> <p><mathjax>#2H_2O rightleftharpoonsH_3O^+ +HO^-#</mathjax> <mathjax>#K_w=[H_3O^+][HO^-]=10^-14#</mathjax>.</p> <p>Given that this is a bond-breaking reaction, how do you think this equilibrium would evolve AT HIGHER TEMPERATURES? (If you are not an undergrad, don't bother with this question). </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/405513" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/533129fb02bf342f40b5c3cd"> Question #5c3cd </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-common-mistakes-students-make-with-stoichiometry-1"> What are some common mistakes students make with stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-an-example-of-a-stoichiometry-practice-problem-1"> What is an example of a stoichiometry practice problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-examples-of-acid-and-base-dissociation"> What are some examples of acid and base dissociation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-an-example-of-an-acid-and-base-dissociation-practice-problem"> What is an example of an acid and base dissociation practice problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-common-mistakes-students-make-with-acid-and-base-dissociation"> What are some common mistakes students make with acid and base dissociation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stoichiometry-with-acid-and-base-dissociation"> What is stoichiometry with acid and base dissociation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-examples-of-stoichiometry-with-acid-and-base-dissociation"> What are some examples of stoichiometry with acid and base dissociation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-an-example-of-a-stoichiometry-with-acid-and-base-dissociation-practice-p"> What is an example of a stoichiometry with acid and base dissociation practice problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-we-relate-stoichiometry-to-everyday-processes"> How do we relate stoichiometry to everyday processes? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/stoichiometry-with-acid-and-base-dissociation"> See all questions in Stoichiometry with Acid and Base Dissociation </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3001 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the reaction of an ion with #H_2O# to produce #H^+(aq)# and #OH^(-)(aq)#?	null
1,819	aaabd98a-6ddd-11ea-b90b-ccda262736ce	https://socratic.org/questions/56573a52581e2a53a3d36cc5	6	start physical_unit 6 6 coordination_number none qc_end chemical_equation 9 9 qc_end end	[{"type":"physical unit","value":"Coordination number [OF] cobalt"}]	[{"type":"physical unit","value":"6"}]	[{"type":"chemical equation","value":"[Co(en)2Br2]+"}]	<h1 class="questionTitle" itemprop="name">What is the coordination number of cobalt in the #[Co(en)_2Br_2]^+# complex?</h1>	null	6	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First thing first, if you're dealing with the <em>dibromobis(ethylenediamine) cobalt(III)</em> complex ion, <mathjax>#"Co"("en")_2"Br"_2^(+)#</mathjax>, then I'm not sure about the formula you have for the complex ion. </p> <p>The charge of the chloride anion is <mathjax>#(1-)#</mathjax>, which means that you would either need <strong>two</strong> of these complex ions to balance it, or you have cobalt in the <mathjax>#+4#</mathjax> <a href="https://socratic.org/chemistry/electrochemistry/oxidation-numbers">oxidation state</a>, which is not very common at all. </p> <p>I think you could get cobalt in its <mathjax>#+4#</mathjax> oxidation state by using fluoride anions, since they have a much better chance at being able to stabilize the charge on the cobalt cation.</p> <p>So my guess is that you're either dealing with <mathjax>#["Co"("en")_2"Br"_2]"Cl"#</mathjax>, or with <mathjax>#["Co"("en")_2"Br"_2]_2"Cl"_2#</mathjax>, maybe? </p> <p>Anyway, this doesn't actually matter for finding the <em>coordination number</em> of cobalt. </p> <p>As you know, the coordination number of an atom is determined by counting the number of <strong>other atoms</strong> to which it is bonded. Remember, <em>single</em>, <em>double</em>, or <em>triple bonds</em> have the same significance here. </p> <p>So, take a look at the <em>dibromobis(ethylenediamine) cobalt(III) ion</em>. The central cobalt atom is bonded to </p> <blockquote> <ul> <li><em>two ethylenediamine molecules</em> ,<mathjax>#"en"#</mathjax></li> <li><em>two bromide anions</em>, <mathjax>#"Br"^(-)#</mathjax></li> </ul> </blockquote> <p>Now, it's important to realize that ethylenediamine is a <strong>bidentate ligand</strong>, which means that it uses <strong>two</strong> donor atoms to bind to the central cobalt atom. </p> <p>More specifically, these donor atoms are the two nitrogen atoms</p> <p><img alt="http://glossary.periodni.com/glossary.php?en=bidentate+ligand" src="https://useruploads.socratic.org/Qtlkb6UT8OVnMQ0s3OcP_bidentate_ligand.jpg"/> </p> <p>This means that the central cobalt atom will actually be bonded to a total of <strong>six atoms</strong> </p> <blockquote> <ul> <li><em>two nitrogen atoms from the first ethylenediamine molecule</em></li> <li><em>two nitrogen atoms from the second ethylenediamine molecule</em></li> <li><em>two bromine atoms</em></li> </ul> </blockquote> <p>Therefore, the coordination number of cobalt in the <mathjax>#"Co"("en")_2"Br"_2^(+)#</mathjax> complex ion is equal to <mathjax>#6#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#6#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First thing first, if you're dealing with the <em>dibromobis(ethylenediamine) cobalt(III)</em> complex ion, <mathjax>#"Co"("en")_2"Br"_2^(+)#</mathjax>, then I'm not sure about the formula you have for the complex ion. </p> <p>The charge of the chloride anion is <mathjax>#(1-)#</mathjax>, which means that you would either need <strong>two</strong> of these complex ions to balance it, or you have cobalt in the <mathjax>#+4#</mathjax> <a href="https://socratic.org/chemistry/electrochemistry/oxidation-numbers">oxidation state</a>, which is not very common at all. </p> <p>I think you could get cobalt in its <mathjax>#+4#</mathjax> oxidation state by using fluoride anions, since they have a much better chance at being able to stabilize the charge on the cobalt cation.</p> <p>So my guess is that you're either dealing with <mathjax>#["Co"("en")_2"Br"_2]"Cl"#</mathjax>, or with <mathjax>#["Co"("en")_2"Br"_2]_2"Cl"_2#</mathjax>, maybe? </p> <p>Anyway, this doesn't actually matter for finding the <em>coordination number</em> of cobalt. </p> <p>As you know, the coordination number of an atom is determined by counting the number of <strong>other atoms</strong> to which it is bonded. Remember, <em>single</em>, <em>double</em>, or <em>triple bonds</em> have the same significance here. </p> <p>So, take a look at the <em>dibromobis(ethylenediamine) cobalt(III) ion</em>. The central cobalt atom is bonded to </p> <blockquote> <ul> <li><em>two ethylenediamine molecules</em> ,<mathjax>#"en"#</mathjax></li> <li><em>two bromide anions</em>, <mathjax>#"Br"^(-)#</mathjax></li> </ul> </blockquote> <p>Now, it's important to realize that ethylenediamine is a <strong>bidentate ligand</strong>, which means that it uses <strong>two</strong> donor atoms to bind to the central cobalt atom. </p> <p>More specifically, these donor atoms are the two nitrogen atoms</p> <p><img alt="http://glossary.periodni.com/glossary.php?en=bidentate+ligand" src="https://useruploads.socratic.org/Qtlkb6UT8OVnMQ0s3OcP_bidentate_ligand.jpg"/> </p> <p>This means that the central cobalt atom will actually be bonded to a total of <strong>six atoms</strong> </p> <blockquote> <ul> <li><em>two nitrogen atoms from the first ethylenediamine molecule</em></li> <li><em>two nitrogen atoms from the second ethylenediamine molecule</em></li> <li><em>two bromine atoms</em></li> </ul> </blockquote> <p>Therefore, the coordination number of cobalt in the <mathjax>#"Co"("en")_2"Br"_2^(+)#</mathjax> complex ion is equal to <mathjax>#6#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the coordination number of cobalt in the #[Co(en)_2Br_2]^+# complex?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#ionic-bonds-and-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Ionic Bonds</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/ionic-bonds-and-formulas/polyatomic-ions" itemprop="url"> <span class="breadcrumb" itemprop="title">Polyatomic Ions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="193386" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-26T18:31:58" itemprop="dateCreated"> Nov 26, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#6#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First thing first, if you're dealing with the <em>dibromobis(ethylenediamine) cobalt(III)</em> complex ion, <mathjax>#"Co"("en")_2"Br"_2^(+)#</mathjax>, then I'm not sure about the formula you have for the complex ion. </p> <p>The charge of the chloride anion is <mathjax>#(1-)#</mathjax>, which means that you would either need <strong>two</strong> of these complex ions to balance it, or you have cobalt in the <mathjax>#+4#</mathjax> <a href="https://socratic.org/chemistry/electrochemistry/oxidation-numbers">oxidation state</a>, which is not very common at all. </p> <p>I think you could get cobalt in its <mathjax>#+4#</mathjax> oxidation state by using fluoride anions, since they have a much better chance at being able to stabilize the charge on the cobalt cation.</p> <p>So my guess is that you're either dealing with <mathjax>#["Co"("en")_2"Br"_2]"Cl"#</mathjax>, or with <mathjax>#["Co"("en")_2"Br"_2]_2"Cl"_2#</mathjax>, maybe? </p> <p>Anyway, this doesn't actually matter for finding the <em>coordination number</em> of cobalt. </p> <p>As you know, the coordination number of an atom is determined by counting the number of <strong>other atoms</strong> to which it is bonded. Remember, <em>single</em>, <em>double</em>, or <em>triple bonds</em> have the same significance here. </p> <p>So, take a look at the <em>dibromobis(ethylenediamine) cobalt(III) ion</em>. The central cobalt atom is bonded to </p> <blockquote> <ul> <li><em>two ethylenediamine molecules</em> ,<mathjax>#"en"#</mathjax></li> <li><em>two bromide anions</em>, <mathjax>#"Br"^(-)#</mathjax></li> </ul> </blockquote> <p>Now, it's important to realize that ethylenediamine is a <strong>bidentate ligand</strong>, which means that it uses <strong>two</strong> donor atoms to bind to the central cobalt atom. </p> <p>More specifically, these donor atoms are the two nitrogen atoms</p> <p><img alt="http://glossary.periodni.com/glossary.php?en=bidentate+ligand" src="https://useruploads.socratic.org/Qtlkb6UT8OVnMQ0s3OcP_bidentate_ligand.jpg"/> </p> <p>This means that the central cobalt atom will actually be bonded to a total of <strong>six atoms</strong> </p> <blockquote> <ul> <li><em>two nitrogen atoms from the first ethylenediamine molecule</em></li> <li><em>two nitrogen atoms from the second ethylenediamine molecule</em></li> <li><em>two bromine atoms</em></li> </ul> </blockquote> <p>Therefore, the coordination number of cobalt in the <mathjax>#"Co"("en")_2"Br"_2^(+)#</mathjax> complex ion is equal to <mathjax>#6#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/193386" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="193389" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-26T18:36:29" itemprop="dateCreated"> Nov 26, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The coordination number of <mathjax>#Co#</mathjax> in <mathjax>#[Co(en)_2Br_2]^(+)#</mathjax> is 6. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Ethylenediamine is a bidentate ligand; it has 2 donor atoms to coordinate to the metal centre in a 5-membered chelate ring. Note that this (I presume) is a <mathjax>#Co^(3+)#</mathjax> complex, i.e. <mathjax>#d^6#</mathjax> configuration, whose formula is <mathjax>#[Co(en)_2Br_2]^(+)#</mathjax>, not as quoted in your question. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/193389" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-draw-the-lewis-structure-for-polyatomic-ions"> How do you draw the lewis structure for polyatomic ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/the-number-of-protons-are-not-suppose-to-be-equal-to-the-number-of-electrons-how"> The number of protons are not suppose to be equal to the number of electrons? 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1,820	aca3f937-6ddd-11ea-bc4b-ccda262736ce	https://socratic.org/questions/what-is-the-molar-mass-of-titanium-dioxide-tio-2-the-white-pigment-of-white-pain	79.87 grams	start physical_unit 8 8 molar_mass g/mol qc_end chemical_equation 8 8 qc_end end	[{"type":"physical unit","value":"Molar mass [OF] TiO2 [IN] g/mol"}]	[{"type":"physical unit","value":"79.87 grams"}]	[{"type":"chemical equation","value":"TiO2"}]	<h1 class="questionTitle" itemprop="name">What is the molar mass of titanium dioxide, #TiO_2#, the white pigment of white paint, in grams?</h1>	null	79.87 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To determine the molar mass of a compound, multiply the molar mass of each element by its subscript in the formula. The molar mass of an element is its atomic weight on <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a> in g/mol.</p> <p>Molar mass of <mathjax>#"TiO"_2"#</mathjax></p> <p><mathjax>#(1xx47.867color(white)(.)"g/mol")+(2xx15.999color(white)(.)"g/mol")="79.865 g/mol"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The molar mass of <mathjax>#"TiO"_2"#</mathjax> is <mathjax>#"79.865 g/mol"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To determine the molar mass of a compound, multiply the molar mass of each element by its subscript in the formula. The molar mass of an element is its atomic weight on <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a> in g/mol.</p> <p>Molar mass of <mathjax>#"TiO"_2"#</mathjax></p> <p><mathjax>#(1xx47.867color(white)(.)"g/mol")+(2xx15.999color(white)(.)"g/mol")="79.865 g/mol"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the molar mass of titanium dioxide, #TiO_2#, the white pigment of white paint, in grams?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="332625" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-11-07T03:34:50" itemprop="dateCreated"> Nov 7, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The molar mass of <mathjax>#"TiO"_2"#</mathjax> is <mathjax>#"79.865 g/mol"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To determine the molar mass of a compound, multiply the molar mass of each element by its subscript in the formula. The molar mass of an element is its atomic weight on <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a> in g/mol.</p> <p>Molar mass of <mathjax>#"TiO"_2"#</mathjax></p> <p><mathjax>#(1xx47.867color(white)(.)"g/mol")+(2xx15.999color(white)(.)"g/mol")="79.865 g/mol"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/332625" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 14091 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the molar mass of titanium dioxide, #TiO_2#, the white pigment of white paint, in grams?	null
1,821	a8ff1119-6ddd-11ea-972c-ccda262736ce	https://socratic.org/questions/cobalt-ii-sulfide-cos-has-a-ksp-value-of-3-0-x-10-26-what-is-the-solubility-of-c	1.73 × 10^(-13) mol/L	start physical_unit 2 2 solubility mol/l qc_end physical_unit 2 2 8 10 equilibrium_constant_k qc_end end	[{"type":"physical unit","value":"Solubility [OF] CoS [IN] mol/L"}]	[{"type":"physical unit","value":"1.73 × 10^(-13) mol/L"}]	[{"type":"physical unit","value":"Ksp value [OF] CoS [=] \\pu{3.0 × 10^(-26)}"}]	<h1 class="questionTitle" itemprop="name">Cobalt(II) sulfide, #"CoS"#, has a #K_(sp)# value of #3.0 xx 10^(-26)#. What is the solubility of #"CoS"# in mol/L? </h1>	null	1.73 × 10^(-13) mol/L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that cobalt(II) sulfide, <mathjax>#"CoS"#</mathjax>, is considered <strong>Insoluble</strong> in aqueous solution, as shown by the very, very small value of its <em>equilibrium solubility constant</em>, <mathjax>#K_(sp)#</mathjax>. </p> <p>This means that when cobalt(II) sulfide is dissolved in water, only a <strong>tiny fraction</strong> of the ions will dissociate. </p> <p>Your goal here is to calculate the <em>molar concentration</em> of these dissociated ions. To do that, use an <strong>ICE table</strong> and the dissociation equation for cobalt(II) sulfide.</p> <p>If you take <mathjax>#s#</mathjax> to be the <strong>molar solubility</strong> of the salt, i.e. the number of moles of ions dissociated in one liter of solution <strong>per mole</strong> of salt added, you can say that you have</p> <blockquote> <p><mathjax>#" " "CoS"_ ((s)) rightleftharpoons " ""Co"_ ((aq))^(2+) " "+" " "S"_ ((aq))^(2-)#</mathjax></p> </blockquote> <p><mathjax>#color(purple)("I")color(white)(aaaaacolor(black)(-)aaaaaaaaacolor(black)(0)aaaaaaaaaaacolor(black)(0)#</mathjax><br/> <mathjax>#color(purple)("C")color(white)(aaaaacolor(black)(-)aaaaaaacolor(black)((+s))aaaaaaacolor(black)((+s))#</mathjax><br/> <mathjax>#color(purple)("E")color(white)(aaaaacolor(black)(-)aaaaaaaaacolor(black)(s)aaaaaaaaaaacolor(black)(s)#</mathjax> </p> <p>By definition, the product solubility constant will be </p> <blockquote> <p><mathjax>#K_(sp) = ["Co"^(2+)] * ["S"^(2-)]#</mathjax></p> </blockquote> <p>In your case, you have</p> <blockquote> <p><mathjax>#K_(sp) = s * s = s^2#</mathjax></p> </blockquote> <p>This means that <mathjax>#s#</mathjax> is equal to </p> <blockquote> <p><mathjax>#s = sqrt(K_(sp)) = sqrt(3.0 * 10^(-26)) = 1.7 * 10^(-13)#</mathjax></p> </blockquote> <p>You can thus say that the <em>molar solubility</em> of cobalt(II) sulfide is equal to </p> <blockquote> <p><mathjax>#s = color(green)(\|bar(ul(color(white)(a/a)color(black)(1.7 * 10^(-13)"mol L"^(-1))color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>This means that <strong>for every mole</strong> of cobalt(II) sulfide added to <strong>one liter</strong> of water, you will only get a concentration of <mathjax>#1.7 * 10^(-13)"mol L"^(-1)#</mathjax> for the dissociated ions. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1.7 * 10^(-13)"mol L"^(-1)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that cobalt(II) sulfide, <mathjax>#"CoS"#</mathjax>, is considered <strong>Insoluble</strong> in aqueous solution, as shown by the very, very small value of its <em>equilibrium solubility constant</em>, <mathjax>#K_(sp)#</mathjax>. </p> <p>This means that when cobalt(II) sulfide is dissolved in water, only a <strong>tiny fraction</strong> of the ions will dissociate. </p> <p>Your goal here is to calculate the <em>molar concentration</em> of these dissociated ions. To do that, use an <strong>ICE table</strong> and the dissociation equation for cobalt(II) sulfide.</p> <p>If you take <mathjax>#s#</mathjax> to be the <strong>molar solubility</strong> of the salt, i.e. the number of moles of ions dissociated in one liter of solution <strong>per mole</strong> of salt added, you can say that you have</p> <blockquote> <p><mathjax>#" " "CoS"_ ((s)) rightleftharpoons " ""Co"_ ((aq))^(2+) " "+" " "S"_ ((aq))^(2-)#</mathjax></p> </blockquote> <p><mathjax>#color(purple)("I")color(white)(aaaaacolor(black)(-)aaaaaaaaacolor(black)(0)aaaaaaaaaaacolor(black)(0)#</mathjax><br/> <mathjax>#color(purple)("C")color(white)(aaaaacolor(black)(-)aaaaaaacolor(black)((+s))aaaaaaacolor(black)((+s))#</mathjax><br/> <mathjax>#color(purple)("E")color(white)(aaaaacolor(black)(-)aaaaaaaaacolor(black)(s)aaaaaaaaaaacolor(black)(s)#</mathjax> </p> <p>By definition, the product solubility constant will be </p> <blockquote> <p><mathjax>#K_(sp) = ["Co"^(2+)] * ["S"^(2-)]#</mathjax></p> </blockquote> <p>In your case, you have</p> <blockquote> <p><mathjax>#K_(sp) = s * s = s^2#</mathjax></p> </blockquote> <p>This means that <mathjax>#s#</mathjax> is equal to </p> <blockquote> <p><mathjax>#s = sqrt(K_(sp)) = sqrt(3.0 * 10^(-26)) = 1.7 * 10^(-13)#</mathjax></p> </blockquote> <p>You can thus say that the <em>molar solubility</em> of cobalt(II) sulfide is equal to </p> <blockquote> <p><mathjax>#s = color(green)(\|bar(ul(color(white)(a/a)color(black)(1.7 * 10^(-13)"mol L"^(-1))color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>This means that <strong>for every mole</strong> of cobalt(II) sulfide added to <strong>one liter</strong> of water, you will only get a concentration of <mathjax>#1.7 * 10^(-13)"mol L"^(-1)#</mathjax> for the dissociated ions. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Cobalt(II) sulfide, #"CoS"#, has a #K_(sp)# value of #3.0 xx 10^(-26)#. What is the solubility of #"CoS"# in mol/L? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-equilibrium" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Equilibrium</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-equilibrium/ksp" itemprop="url"> <span class="breadcrumb" itemprop="title">Ksp</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="294730" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-08-02T11:39:18" itemprop="dateCreated"> Aug 2, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1.7 * 10^(-13)"mol L"^(-1)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that cobalt(II) sulfide, <mathjax>#"CoS"#</mathjax>, is considered <strong>Insoluble</strong> in aqueous solution, as shown by the very, very small value of its <em>equilibrium solubility constant</em>, <mathjax>#K_(sp)#</mathjax>. </p> <p>This means that when cobalt(II) sulfide is dissolved in water, only a <strong>tiny fraction</strong> of the ions will dissociate. </p> <p>Your goal here is to calculate the <em>molar concentration</em> of these dissociated ions. To do that, use an <strong>ICE table</strong> and the dissociation equation for cobalt(II) sulfide.</p> <p>If you take <mathjax>#s#</mathjax> to be the <strong>molar solubility</strong> of the salt, i.e. the number of moles of ions dissociated in one liter of solution <strong>per mole</strong> of salt added, you can say that you have</p> <blockquote> <p><mathjax>#" " "CoS"_ ((s)) rightleftharpoons " ""Co"_ ((aq))^(2+) " "+" " "S"_ ((aq))^(2-)#</mathjax></p> </blockquote> <p><mathjax>#color(purple)("I")color(white)(aaaaacolor(black)(-)aaaaaaaaacolor(black)(0)aaaaaaaaaaacolor(black)(0)#</mathjax><br/> <mathjax>#color(purple)("C")color(white)(aaaaacolor(black)(-)aaaaaaacolor(black)((+s))aaaaaaacolor(black)((+s))#</mathjax><br/> <mathjax>#color(purple)("E")color(white)(aaaaacolor(black)(-)aaaaaaaaacolor(black)(s)aaaaaaaaaaacolor(black)(s)#</mathjax> </p> <p>By definition, the product solubility constant will be </p> <blockquote> <p><mathjax>#K_(sp) = ["Co"^(2+)] * ["S"^(2-)]#</mathjax></p> </blockquote> <p>In your case, you have</p> <blockquote> <p><mathjax>#K_(sp) = s * s = s^2#</mathjax></p> </blockquote> <p>This means that <mathjax>#s#</mathjax> is equal to </p> <blockquote> <p><mathjax>#s = sqrt(K_(sp)) = sqrt(3.0 * 10^(-26)) = 1.7 * 10^(-13)#</mathjax></p> </blockquote> <p>You can thus say that the <em>molar solubility</em> of cobalt(II) sulfide is equal to </p> <blockquote> <p><mathjax>#s = color(green)(\|bar(ul(color(white)(a/a)color(black)(1.7 * 10^(-13)"mol L"^(-1))color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>This means that <strong>for every mole</strong> of cobalt(II) sulfide added to <strong>one liter</strong> of water, you will only get a concentration of <mathjax>#1.7 * 10^(-13)"mol L"^(-1)#</mathjax> for the dissociated ions. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/294730" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-you-use-the-solubility-product-constant-to-calculate-the-solubility-of-a"> How can you use the solubility product constant to calculate the solubility of a sparingly... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5397ae9102bf3458eddf5130"> Question #f5130 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-ksp"> What is Ksp? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-ksp-be-calculated"> How can Ksp be calculated? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-ksp-related-to-molarity"> How is Ksp related to molarity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/54acbccb581e2a063bcda59d"> Question #da59d </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/551bf79e581e2a41eb271344"> Question #71344 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/552b6da7581e2a666ea17cc3"> Question #17cc3 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/552bd9cd581e2a666ea18e4c"> What is the molar solubility of magnesium fluoride in a solution that is #"0.1 M"# sodium fluoride? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5536aaad581e2a253fd94985"> (a) How much aluminium hydroxide will dissolve in 500ml of water at #25^@C# given that... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-equilibrium/ksp"> See all questions in Ksp </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 11943 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Cobalt(II) sulfide, #"CoS"#, has a #K_(sp)# value of #3.0 xx 10^(-26)#. What is the solubility of #"CoS"# in mol/L?	null
1,822	ac93d1e8-6ddd-11ea-9f91-ccda262736ce	https://socratic.org/questions/a-compound-is-found-to-be-12-7-carbon-3-2-hydrogen-and-84-1-bromine-what-is-its-	CH3Br	start chemical_formula qc_end end	[{"type":"other","value":"Chemical Formula [OF] the compound [IN] empirical"}]	[{"type":"chemical equation","value":"CH3Br"}]	[{"type":"physical unit","value":"Percent [OF] carbon in the compound [=] \\pu{12.7%}"},{"type":"physical unit","value":"Percent [OF] hydrogen in the compound [=] \\pu{3.2%}"},{"type":"physical unit","value":"Percent [OF] bromine in the compound [=] \\pu{84.1%}"}]	<h1 class="questionTitle" itemprop="name">A compound is found to be 12.7% carbon, 3.2% hydrogen, and 84.1% bromine. What is its empirical formula?</h1>	null	CH3Br	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>If there is a <mathjax>#100g#</mathjax> mass of compound, then we interrogate its ATOMIC composition......</p> <p><mathjax>#"Moles of carbon"=(12.7g)/(12.011gmol^-1)=1.06mol#</mathjax>.</p> <p><mathjax>#"Moles of hydrogen"=(3.2g)/(1.00794gmol^-1)=3.175mol#</mathjax>.</p> <p><mathjax>#"Moles of bromine"=(84.1g)/(79.90gmol^-1)=1.05*mol#</mathjax>.</p> <p>And we divide these molar quantities by THE SMALLEST such quantity to get an empirical formula of <mathjax>#CH_3Br#</mathjax>. This is quite probably <mathjax>#"methyl bromide"#</mathjax> but we require an estimate of molecular mass before we address the molecular formula. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>As with these problems, we assume a mass of <mathjax>#100g#</mathjax> of unknown compound..........and get an empirical formula of <mathjax>#CH_3Br#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>If there is a <mathjax>#100g#</mathjax> mass of compound, then we interrogate its ATOMIC composition......</p> <p><mathjax>#"Moles of carbon"=(12.7g)/(12.011gmol^-1)=1.06mol#</mathjax>.</p> <p><mathjax>#"Moles of hydrogen"=(3.2g)/(1.00794gmol^-1)=3.175mol#</mathjax>.</p> <p><mathjax>#"Moles of bromine"=(84.1g)/(79.90gmol^-1)=1.05mol#</mathjax>.</p> <p>And we divide these molar quantities by THE SMALLEST such quantity to get an empirical formula of <mathjax>#CH_3Br#</mathjax>. This is quite probably <mathjax>#"methyl bromide"#</mathjax> but we require an estimate of molecular mass before we address the molecular formula. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A compound is found to be 12.7% carbon, 3.2% hydrogen, and 84.1% bromine. What is its empirical formula?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="414940" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-29T18:17:51" itemprop="dateCreated"> Apr 29, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>As with these problems, we assume a mass of <mathjax>#100g#</mathjax> of unknown compound..........and get an empirical formula of <mathjax>#CH_3Br#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>If there is a <mathjax>#100g#</mathjax> mass of compound, then we interrogate its ATOMIC composition......</p> <p><mathjax>#"Moles of carbon"=(12.7g)/(12.011gmol^-1)=1.06mol#</mathjax>.</p> <p><mathjax>#"Moles of hydrogen"=(3.2g)/(1.00794gmol^-1)=3.175mol#</mathjax>.</p> <p><mathjax>#"Moles of bromine"=(84.1g)/(79.90gmol^-1)=1.05mol#</mathjax>.</p> <p>And we divide these molar quantities by THE SMALLEST such quantity to get an empirical formula of <mathjax>#CH_3Br#</mathjax>. This is quite probably <mathjax>#"methyl bromide"#</mathjax> but we require an estimate of molecular mass before we address the molecular formula. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/414940" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molecular-formula-of-a-compound"> How do you find molecular formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-diamond"> What is the chemical formula of a diamond? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-carbohydrate"> What is the chemical formula of a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-valproic-acid"> What is the empirical formula for valproic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-of-magnesium-oxide"> What is the empirical formula of magnesium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-empirical-formula-not-double-that-of-the-monosaccharides"> Why is the empirical formula not double that of the monosaccharides? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5331180502bf342f40b5c3b5"> Question #5c3b5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-molecular-formula-represents-a-carbohydrate"> What molecular formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-of-vinegar"> What is the molecular formula of vinegar? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/empirical-and-molecular-formulas"> See all questions in Empirical and Molecular Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 4157 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A compound is found to be 12.7% carbon, 3.2% hydrogen, and 84.1% bromine. What is its empirical formula?	null
1,823	a8acc58b-6ddd-11ea-a4fa-ccda262736ce	https://socratic.org/questions/what-is-the-number-of-moles-in-36-g-of-h2o	2.00 moles	start physical_unit 10 10 number mol qc_end physical_unit 10 10 7 8 mass qc_end end	[{"type":"physical unit","value":"Number [OF] H2O [IN] moles"}]	[{"type":"physical unit","value":"2.00 moles"}]	[{"type":"physical unit","value":"Mass [OF] H2O [=] \\pu{36 g}"}]	<h1 class="questionTitle" itemprop="name">What is the number of moles in #"36 g"# of #"H"_2"O"# ?</h1>	null	2.00 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The relationship between the <strong>number of moles</strong> of a given substance present in a sample and the <strong>mass</strong> of the sample is given by the <strong>molar mass</strong> of the substance.</p> <p>For any chemical species, you have</p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)("molar mass" \ = \ "the mass of exactly 1 mole")))#</mathjax></p> </blockquote> <p>Now, water has a <strong>molar mass</strong> of <mathjax>#"18.015 g mol"^(-1)#</mathjax>, which means that <mathjax>#1#</mathjax> <strong>mole</strong> of water has a mass of <mathjax>#"18.015 g"#</mathjax>. </p> <blockquote> <p><mathjax>#"18.015 g mol"^(-1) = "18.015 g"/("1 mole H"_2"O")#</mathjax></p> </blockquote> <p>So for every <mathjax>#"18.015 g"#</mathjax> of water present in your sample, you have <mathjax>#1#</mathjax> <strong>mole</strong> of water. </p> <p>This means that your <mathjax>#"36-g"#</mathjax> sample will contain</p> <blockquote> <p><mathjax>#36 color(red)(cancel(color(black)("g"))) * overbrace(("1 mole H"_2"O")/(18.015color(red)(cancel(color(black)("g")))))^(color(blue)("given by the molar mass of H"_2"O")) = color(darkgreen)(ul(color(black)("2.0 moles H"_2"O")))#</mathjax></p> </blockquote> <p>The answer must be rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the mass of water. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"2.0 moles"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The relationship between the <strong>number of moles</strong> of a given substance present in a sample and the <strong>mass</strong> of the sample is given by the <strong>molar mass</strong> of the substance.</p> <p>For any chemical species, you have</p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)("molar mass" \ = \ "the mass of exactly 1 mole")))#</mathjax></p> </blockquote> <p>Now, water has a <strong>molar mass</strong> of <mathjax>#"18.015 g mol"^(-1)#</mathjax>, which means that <mathjax>#1#</mathjax> <strong>mole</strong> of water has a mass of <mathjax>#"18.015 g"#</mathjax>. </p> <blockquote> <p><mathjax>#"18.015 g mol"^(-1) = "18.015 g"/("1 mole H"_2"O")#</mathjax></p> </blockquote> <p>So for every <mathjax>#"18.015 g"#</mathjax> of water present in your sample, you have <mathjax>#1#</mathjax> <strong>mole</strong> of water. </p> <p>This means that your <mathjax>#"36-g"#</mathjax> sample will contain</p> <blockquote> <p><mathjax>#36 color(red)(cancel(color(black)("g"))) * overbrace(("1 mole H"_2"O")/(18.015color(red)(cancel(color(black)("g")))))^(color(blue)("given by the molar mass of H"_2"O")) = color(darkgreen)(ul(color(black)("2.0 moles H"_2"O")))#</mathjax></p> </blockquote> <p>The answer must be rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the mass of water. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the number of moles in #"36 g"# of #"H"_2"O"# ?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="644781" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-07-31T11:19:35" itemprop="dateCreated"> Jul 31, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"2.0 moles"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The relationship between the <strong>number of moles</strong> of a given substance present in a sample and the <strong>mass</strong> of the sample is given by the <strong>molar mass</strong> of the substance.</p> <p>For any chemical species, you have</p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)("molar mass" \ = \ "the mass of exactly 1 mole")))#</mathjax></p> </blockquote> <p>Now, water has a <strong>molar mass</strong> of <mathjax>#"18.015 g mol"^(-1)#</mathjax>, which means that <mathjax>#1#</mathjax> <strong>mole</strong> of water has a mass of <mathjax>#"18.015 g"#</mathjax>. </p> <blockquote> <p><mathjax>#"18.015 g mol"^(-1) = "18.015 g"/("1 mole H"_2"O")#</mathjax></p> </blockquote> <p>So for every <mathjax>#"18.015 g"#</mathjax> of water present in your sample, you have <mathjax>#1#</mathjax> <strong>mole</strong> of water. </p> <p>This means that your <mathjax>#"36-g"#</mathjax> sample will contain</p> <blockquote> <p><mathjax>#36 color(red)(cancel(color(black)("g"))) * overbrace(("1 mole H"_2"O")/(18.015color(red)(cancel(color(black)("g")))))^(color(blue)("given by the molar mass of H"_2"O")) = color(darkgreen)(ul(color(black)("2.0 moles H"_2"O")))#</mathjax></p> </blockquote> <p>The answer must be rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the mass of water. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/644781" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" 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class="impactStatements"> 35014 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the number of moles in #"36 g"# of #"H"_2"O"# ?	null
1,824	abc9ff64-6ddd-11ea-8f82-ccda262736ce	https://socratic.org/questions/the-thallium-present-as-tl-2so-4-in-a-9-486-g-pesticide-sample-was-precipitated-	1.47%	start physical_unit 21 24 mass_percent none qc_end physical_unit 9 10 7 8 mass qc_end physical_unit 29 29 26 27 mass qc_end end	[{"type":"physical unit","value":"Mass percent [OF] Tl2SO4 in the sample"}]	[{"type":"physical unit","value":"1.47%"}]	[{"type":"physical unit","value":"Mass [OF] pesticide sample [=] \\pu{9.486 g}"},{"type":"physical unit","value":"Mass [OF] TlI [=] \\pu{0.1824 g}"}]	<h1 class="questionTitle" itemprop="name">The thallium (present as #Tl_2SO_4#) in a #9.486# g pesticide sample was precipitated as Thallium(I) iodide. Calculate the mass percent of #Tl_2SO_4# in the sample if #0.1824# g of #TlI# was recovered?</h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>Help is much appreciated.</p></div> </h2> </div> </div>	1.47%	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>Step 1. Write an equation for the reaction</strong></p> <p>A partial equation for the reaction is</p> <p><mathjax>#M_text(r):color(white)(m)504.83color(white)(mmmmll)331.29#</mathjax><br/> <mathjax>#color(white)(mmm)"Tl"_2"SO"_4 + … → "2TlI" + …#</mathjax></p> <p>We don’t know what the other reactants and products are.</p> <p>However, that doesn't matter as long as atoms of <mathjax>#"Tl"#</mathjax> are balanced.</p> <blockquote></blockquote> <p><strong>Step 2. Calculate the moles of <mathjax>#"TlI"#</mathjax></strong></p> <p><mathjax>#"Moles of TlI" = 0.1824 color(red)(cancel(color(black)("g TlI"))) × "1 mol TlI"/(331.29 color(red)(cancel(color(black)("g TlI")))) = 5.5058 × 10^"-4"color(white)(l) "mol TlI"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 3. Calculate the moles of <mathjax>#"Tl"_2"SO"_4#</mathjax></strong></p> <p><mathjax>#"Moles of Tl"_2"SO"_4 = 5.5058 × 10^"-4"color(red)(cancel(color(black)("mol TlI"))) × (1 "mol Tl"_2"SO"_4)/(2 color(red)(cancel(color(black)("mol TlI"))))#</mathjax></p> <p><mathjax># = 2.7529 × 10^"-4"color(white)(l) "mol Tl"_2"SO"_4#</mathjax></p> <blockquote></blockquote> <p><strong>Step 4. Calculate the mass of <mathjax>#"Tl"_2"SO"_4#</mathjax></strong></p> <p><mathjax>#"Mass of Tl"_2"SO"_4 = 2.7529 × 10^"-4"color(red)(cancel(color(black)("mol Tl"_2"SO"_4))) × (504.83 "g Tl"_2"SO"_4)/(1 color(red)(cancel(color(black)("mol Tl"_2"SO"_4)))) = "0.138 97 g Tl"_2"SO"_4#</mathjax></p> <blockquote></blockquote> <p><strong>Step 5. Calculate the mass percent of <mathjax>#"Tl"_2"SO"_4#</mathjax></strong></p> <p><mathjax>#"Mass %" = ("mass of Tl"_2"SO"_4)/"mass of pesticide" × 100 % = ("0.138 97" color(red)(cancel(color(black)("g"))))/(9.486 color(red)(cancel(color(black)("g")))) × 100 % = 1.465 %#</mathjax></p> <p>I hope that helps!</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><blockquote></blockquote> <p>The mass percent of <mathjax>#"Tl"_2"SO"_4#</mathjax> in the sample is <mathjax>#1.465%#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>Step 1. Write an equation for the reaction</strong></p> <p>A partial equation for the reaction is</p> <p><mathjax>#M_text(r):color(white)(m)504.83color(white)(mmmmll)331.29#</mathjax><br/> <mathjax>#color(white)(mmm)"Tl"_2"SO"_4 + … → "2TlI" + …#</mathjax></p> <p>We don’t know what the other reactants and products are.</p> <p>However, that doesn't matter as long as atoms of <mathjax>#"Tl"#</mathjax> are balanced.</p> <blockquote></blockquote> <p><strong>Step 2. Calculate the moles of <mathjax>#"TlI"#</mathjax></strong></p> <p><mathjax>#"Moles of TlI" = 0.1824 color(red)(cancel(color(black)("g TlI"))) × "1 mol TlI"/(331.29 color(red)(cancel(color(black)("g TlI")))) = 5.5058 × 10^"-4"color(white)(l) "mol TlI"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 3. Calculate the moles of <mathjax>#"Tl"_2"SO"_4#</mathjax></strong></p> <p><mathjax>#"Moles of Tl"_2"SO"_4 = 5.5058 × 10^"-4"color(red)(cancel(color(black)("mol TlI"))) × (1 "mol Tl"_2"SO"_4)/(2 color(red)(cancel(color(black)("mol TlI"))))#</mathjax></p> <p><mathjax># = 2.7529 × 10^"-4"color(white)(l) "mol Tl"_2"SO"_4#</mathjax></p> <blockquote></blockquote> <p><strong>Step 4. Calculate the mass of <mathjax>#"Tl"_2"SO"_4#</mathjax></strong></p> <p><mathjax>#"Mass of Tl"_2"SO"_4 = 2.7529 × 10^"-4"color(red)(cancel(color(black)("mol Tl"_2"SO"_4))) × (504.83 "g Tl"_2"SO"_4)/(1 color(red)(cancel(color(black)("mol Tl"_2"SO"_4)))) = "0.138 97 g Tl"_2"SO"_4#</mathjax></p> <blockquote></blockquote> <p><strong>Step 5. Calculate the mass percent of <mathjax>#"Tl"_2"SO"_4#</mathjax></strong></p> <p><mathjax>#"Mass %" = ("mass of Tl"_2"SO"_4)/"mass of pesticide" × 100 % = ("0.138 97" color(red)(cancel(color(black)("g"))))/(9.486 color(red)(cancel(color(black)("g")))) × 100 % = 1.465 %#</mathjax></p> <p>I hope that helps!</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">The thallium (present as #Tl_2SO_4#) in a #9.486# g pesticide sample was precipitated as Thallium(I) iodide. Calculate the mass percent of #Tl_2SO_4# in the sample if #0.1824# g of #TlI# was recovered?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>Help is much appreciated.</p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="473127" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> <a class="secondContributorPic" href="/users/ani-6"><img alt="" class="" src="https://profilepictures.socratic.org/KgBnvWxsSOCGP63lfiF1_triangle2.gif" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a>·<a class="topContributorLink" href="/users/ani-6"> Anirudh E. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-09-08T14:28:06" itemprop="dateCreated"> Sep 8, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><blockquote></blockquote> <p>The mass percent of <mathjax>#"Tl"_2"SO"_4#</mathjax> in the sample is <mathjax>#1.465%#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>Step 1. Write an equation for the reaction</strong></p> <p>A partial equation for the reaction is</p> <p><mathjax>#M_text(r):color(white)(m)504.83color(white)(mmmmll)331.29#</mathjax><br/> <mathjax>#color(white)(mmm)"Tl"_2"SO"_4 + … → "2TlI" + …#</mathjax></p> <p>We don’t know what the other reactants and products are.</p> <p>However, that doesn't matter as long as atoms of <mathjax>#"Tl"#</mathjax> are balanced.</p> <blockquote></blockquote> <p><strong>Step 2. Calculate the moles of <mathjax>#"TlI"#</mathjax></strong></p> <p><mathjax>#"Moles of TlI" = 0.1824 color(red)(cancel(color(black)("g TlI"))) × "1 mol TlI"/(331.29 color(red)(cancel(color(black)("g TlI")))) = 5.5058 × 10^"-4"color(white)(l) "mol TlI"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 3. Calculate the moles of <mathjax>#"Tl"_2"SO"_4#</mathjax></strong></p> <p><mathjax>#"Moles of Tl"_2"SO"_4 = 5.5058 × 10^"-4"color(red)(cancel(color(black)("mol TlI"))) × (1 "mol Tl"_2"SO"_4)/(2 color(red)(cancel(color(black)("mol TlI"))))#</mathjax></p> <p><mathjax># = 2.7529 × 10^"-4"color(white)(l) "mol Tl"_2"SO"_4#</mathjax></p> <blockquote></blockquote> <p><strong>Step 4. Calculate the mass of <mathjax>#"Tl"_2"SO"_4#</mathjax></strong></p> <p><mathjax>#"Mass of Tl"_2"SO"_4 = 2.7529 × 10^"-4"color(red)(cancel(color(black)("mol Tl"_2"SO"_4))) × (504.83 "g Tl"_2"SO"_4)/(1 color(red)(cancel(color(black)("mol Tl"_2"SO"_4)))) = "0.138 97 g Tl"_2"SO"_4#</mathjax></p> <blockquote></blockquote> <p><strong>Step 5. Calculate the mass percent of <mathjax>#"Tl"_2"SO"_4#</mathjax></strong></p> <p><mathjax>#"Mass %" = ("mass of Tl"_2"SO"_4)/"mass of pesticide" × 100 % = ("0.138 97" color(red)(cancel(color(black)("g"))))/(9.486 color(red)(cancel(color(black)("g")))) × 100 % = 1.465 %#</mathjax></p> <p>I hope that helps!</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/473127" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-equation-for-photosynthesis"> What is the chemical equation for photosynthesis? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-know-the-relative-number-of-grams-of-each-substance-used-or-produced-w"> How can I know the relative number of grams of each substance used or produced with chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-know-the-relative-number-of-moles-of-each-substance-with-chemical-equa"> How can I know the relative number of moles of each substance with chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-chemical-equations-illustrate-that-atoms-are-conserved-1"> How do chemical equations illustrate that atoms are conserved? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-know-the-formula-of-the-reactants-and-products-with-chemical-equations"> How can I know the formula of the reactants and products with chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-potassium-metal-and-chlorine-gas-combi"> How can I balance this chemical equations? 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Calculate the mass percent of #Tl_2SO_4# in the sample if #0.1824# g of #TlI# was recovered?	Help is much appreciated.
1,825	aa95b8ec-6ddd-11ea-bc81-ccda262736ce	https://socratic.org/questions/what-is-the-ionization-energy-of-rubidium-atoms-in-kilojoules-per-mole-if-light-	403.04 kilojoules per mole	start physical_unit 6 7 ionization_energy kj/mol qc_end physical_unit 13 13 17 18 λ qc_end physical_unit 20 20 25 28 velocity qc_end end	[{"type":"physical unit","value":"Ionization energy [OF] rubidium atoms [IN] kilojoules per mole"}]	[{"type":"physical unit","value":"403.04 kilojoules per mole"}]	[{"type":"physical unit","value":"λ [OF] light [=] \\pu{58.4 nm}"},{"type":"physical unit","value":"Velocity [OF] electrons [=] \\pu{2.450 × 10^6 m/s}"}]	<h1 class="questionTitle" itemprop="name">What is the ionization energy of rubidium atoms (in kilojoules per mole) if light with λ = 58.4 nm produces electrons with a velocity of 2.450×10 6 m/s 2.450*10^6 m/s? </h1>	null	403.04 kilojoules per mole	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The first ionisation energy is the energy required to remove 1 mole of electrons from 1 mole of atoms in the gaseous state.</p> <p>It is the <a href="https://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> change for:</p> <p><mathjax>#X_((g))rarrX_((g))^(+)+e#</mathjax></p> <p>In this example I will assume that we have gaseous rubidium atoms.</p> <p>When a photon strikes a rubidium atom it may have sufficient energy to excite electrons to higher energy levels:</p> <p><img alt="www.freethought-forum.com" src="http://www.freethought-forum.com/images/anatomy2/excited.gif"/></p> <p>If the photon has a lot of energy it may cause the electron to be ejected from the atom forming an ion.</p> <p>The excess energy of the photon, after ionisation, will appear as the kinetic energy of the ejected electron.</p> <p>We can use the conservation of energy to set this up as an equation:</p> <p>Photon energy = ionisation energy + kinetic energy of electron</p> <p>The energy of the photon is given by the Planck expression:</p> <p><mathjax>#E=hf#</mathjax></p> <p><mathjax>#f#</mathjax> is the frequency of the photon.</p> <p><mathjax>#h#</mathjax> is the Planck Constant with the value of <mathjax>#6.626xx10^(-34)" " "Js"#</mathjax></p> <p>The kinetic energy of the electron is given by:</p> <p><mathjax>#"KE"=1/2mv^2#</mathjax></p> <p><mathjax>#m#</mathjax> is the mass <mathjax>#=9.11xx10^(-31)" ""kg"#</mathjax></p> <p><mathjax>#v#</mathjax> is the velocity <mathjax>#=2.45xx10^(6)" ""m/s"#</mathjax> </p> <p>So we can say:</p> <p><mathjax>#hf="IE"+1/2mv^(2)#</mathjax></p> <p><mathjax>#:."IE"=hf-1/2mv^2#</mathjax></p> <p>Since <mathjax>#c=fxxlambda#</mathjax> we can write this as:</p> <p><mathjax>#"IE"=(hc)/lambda-1/2mv^2#</mathjax></p> <p>Putting in the numbers:</p> <p><mathjax>#"IE"=(6.626xx10^(-34)xx3xx10^(8))/(58.4xx10^(-9))-[1/2xx9.11xx10^(-31)xx(2.45xx10^6)^2]#</mathjax></p> <p><mathjax>#"IE"=[3.403xx10^(-18)]-[2.734xx10^(-18)]" ""J"#</mathjax></p> <p><mathjax>#"IE"=6.690xx10^(-19)" ""J"#</mathjax></p> <p>This is the energy required to ionise 1 atom of <mathjax>#"Rb"#</mathjax></p> <p>To get the energy required to ionise a mole of atoms we need to multiply this by the Avogadro Constant:</p> <p><mathjax>#"IE"=6.690xx10^(-19)xx6.022xx10^(23)=4.0287xx10^(5)" ""J/mol"#</mathjax></p> <p>Since there are 1000J in 1kJ this becomes:</p> <p><mathjax>#"IE"=402.9" ""kJ/mol"#</mathjax></p> <p>The literature value gives <mathjax>#403.032" ""kJ/mol"#</mathjax> so this seems a reasonable answer.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#402.9" ""kJ/mol"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The first ionisation energy is the energy required to remove 1 mole of electrons from 1 mole of atoms in the gaseous state.</p> <p>It is the <a href="https://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> change for:</p> <p><mathjax>#X_((g))rarrX_((g))^(+)+e#</mathjax></p> <p>In this example I will assume that we have gaseous rubidium atoms.</p> <p>When a photon strikes a rubidium atom it may have sufficient energy to excite electrons to higher energy levels:</p> <p><img alt="www.freethought-forum.com" src="http://www.freethought-forum.com/images/anatomy2/excited.gif"/></p> <p>If the photon has a lot of energy it may cause the electron to be ejected from the atom forming an ion.</p> <p>The excess energy of the photon, after ionisation, will appear as the kinetic energy of the ejected electron.</p> <p>We can use the conservation of energy to set this up as an equation:</p> <p>Photon energy = ionisation energy + kinetic energy of electron</p> <p>The energy of the photon is given by the Planck expression:</p> <p><mathjax>#E=hf#</mathjax></p> <p><mathjax>#f#</mathjax> is the frequency of the photon.</p> <p><mathjax>#h#</mathjax> is the Planck Constant with the value of <mathjax>#6.626xx10^(-34)" " "Js"#</mathjax></p> <p>The kinetic energy of the electron is given by:</p> <p><mathjax>#"KE"=1/2mv^2#</mathjax></p> <p><mathjax>#m#</mathjax> is the mass <mathjax>#=9.11xx10^(-31)" ""kg"#</mathjax></p> <p><mathjax>#v#</mathjax> is the velocity <mathjax>#=2.45xx10^(6)" ""m/s"#</mathjax> </p> <p>So we can say:</p> <p><mathjax>#hf="IE"+1/2mv^(2)#</mathjax></p> <p><mathjax>#:."IE"=hf-1/2mv^2#</mathjax></p> <p>Since <mathjax>#c=fxxlambda#</mathjax> we can write this as:</p> <p><mathjax>#"IE"=(hc)/lambda-1/2mv^2#</mathjax></p> <p>Putting in the numbers:</p> <p><mathjax>#"IE"=(6.626xx10^(-34)xx3xx10^(8))/(58.4xx10^(-9))-[1/2xx9.11xx10^(-31)xx(2.45xx10^6)^2]#</mathjax></p> <p><mathjax>#"IE"=[3.403xx10^(-18)]-[2.734xx10^(-18)]" ""J"#</mathjax></p> <p><mathjax>#"IE"=6.690xx10^(-19)" ""J"#</mathjax></p> <p>This is the energy required to ionise 1 atom of <mathjax>#"Rb"#</mathjax></p> <p>To get the energy required to ionise a mole of atoms we need to multiply this by the Avogadro Constant:</p> <p><mathjax>#"IE"=6.690xx10^(-19)xx6.022xx10^(23)=4.0287xx10^(5)" ""J/mol"#</mathjax></p> <p>Since there are 1000J in 1kJ this becomes:</p> <p><mathjax>#"IE"=402.9" ""kJ/mol"#</mathjax></p> <p>The literature value gives <mathjax>#403.032" ""kJ/mol"#</mathjax> so this seems a reasonable answer.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the ionization energy of rubidium atoms (in kilojoules per mole) if light with λ = 58.4 nm produces electrons with a velocity of 2.450×10 6 m/s 2.450*10^6 m/s? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-periodic-table" itemprop="url"> <span class="breadcrumb" itemprop="title">The Periodic Table</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-periodic-table/periodic-trends-in-ionization-energy" itemprop="url"> <span class="breadcrumb" itemprop="title">Periodic Trends in Ionization Energy</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="281254" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/michael-2"><img alt="" class="" src="https://lh3.googleusercontent.com/-gCv6FQRhls0/AAAAAAAAAAI/AAAAAAAAAAA/AAnnY7oOJS05Ylqn3KuDSW0LfnbOk7FezQ/mo/photo.jpg?sz=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/michael-2"> Michael </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-25T16:08:12" itemprop="dateCreated"> Jun 25, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#402.9" ""kJ/mol"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The first ionisation energy is the energy required to remove 1 mole of electrons from 1 mole of atoms in the gaseous state.</p> <p>It is the <a href="https://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> change for:</p> <p><mathjax>#X_((g))rarrX_((g))^(+)+e#</mathjax></p> <p>In this example I will assume that we have gaseous rubidium atoms.</p> <p>When a photon strikes a rubidium atom it may have sufficient energy to excite electrons to higher energy levels:</p> <p><img alt="www.freethought-forum.com" src="http://www.freethought-forum.com/images/anatomy2/excited.gif"/></p> <p>If the photon has a lot of energy it may cause the electron to be ejected from the atom forming an ion.</p> <p>The excess energy of the photon, after ionisation, will appear as the kinetic energy of the ejected electron.</p> <p>We can use the conservation of energy to set this up as an equation:</p> <p>Photon energy = ionisation energy + kinetic energy of electron</p> <p>The energy of the photon is given by the Planck expression:</p> <p><mathjax>#E=hf#</mathjax></p> <p><mathjax>#f#</mathjax> is the frequency of the photon.</p> <p><mathjax>#h#</mathjax> is the Planck Constant with the value of <mathjax>#6.626xx10^(-34)" " "Js"#</mathjax></p> <p>The kinetic energy of the electron is given by:</p> <p><mathjax>#"KE"=1/2mv^2#</mathjax></p> <p><mathjax>#m#</mathjax> is the mass <mathjax>#=9.11xx10^(-31)" ""kg"#</mathjax></p> <p><mathjax>#v#</mathjax> is the velocity <mathjax>#=2.45xx10^(6)" ""m/s"#</mathjax> </p> <p>So we can say:</p> <p><mathjax>#hf="IE"+1/2mv^(2)#</mathjax></p> <p><mathjax>#:."IE"=hf-1/2mv^2#</mathjax></p> <p>Since <mathjax>#c=fxxlambda#</mathjax> we can write this as:</p> <p><mathjax>#"IE"=(hc)/lambda-1/2mv^2#</mathjax></p> <p>Putting in the numbers:</p> <p><mathjax>#"IE"=(6.626xx10^(-34)xx3xx10^(8))/(58.4xx10^(-9))-[1/2xx9.11xx10^(-31)xx(2.45xx10^6)^2]#</mathjax></p> <p><mathjax>#"IE"=[3.403xx10^(-18)]-[2.734xx10^(-18)]" ""J"#</mathjax></p> <p><mathjax>#"IE"=6.690xx10^(-19)" ""J"#</mathjax></p> <p>This is the energy required to ionise 1 atom of <mathjax>#"Rb"#</mathjax></p> <p>To get the energy required to ionise a mole of atoms we need to multiply this by the Avogadro Constant:</p> <p><mathjax>#"IE"=6.690xx10^(-19)xx6.022xx10^(23)=4.0287xx10^(5)" ""J/mol"#</mathjax></p> <p>Since there are 1000J in 1kJ this becomes:</p> <p><mathjax>#"IE"=402.9" ""kJ/mol"#</mathjax></p> <p>The literature value gives <mathjax>#403.032" ""kJ/mol"#</mathjax> so this seems a reasonable answer.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/281254" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-ionization-energy-relate-to-reactivity"> How does ionization energy relate to reactivity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" 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<h5>Impact of this question</h5> <div class="impactStatements"> 16618 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the ionization energy of rubidium atoms (in kilojoules per mole) if light with λ = 58.4 nm produces electrons with a velocity of 2.450×10 6 m/s 2.450*10^6 m/s?	null
1,826	a96e9428-6ddd-11ea-92b9-ccda262736ce	https://socratic.org/questions/how-many-grams-of-carbon-are-needed-to-react-completely-with-75-2-g-sio-2-accord	30.08 grams	start physical_unit 4 4 mass g qc_end physical_unit 13 13 11 12 mass qc_end chemical_equation 18 26 qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Mass [OF] carbon [IN] grams"}]	[{"type":"physical unit","value":"30.08 grams"}]	[{"type":"physical unit","value":"Mass [OF] SiO2 [=] \\pu{75.2 g}"},{"type":"chemical equation","value":"SiO2(s) + 2 C(s) -> Si(s) + 2 CO(g)"},{"type":"other","value":"React completely."}]	<h1 class="questionTitle" itemprop="name">How many grams of carbon are needed to react completely with 75.2 g #SiO_2# according to the equation: #SiO_2(s) + 2C(s) -> Si(s) + 2CO(g)#?</h1>	null	30.08 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The balanced chemical equation given to you tells you the <strong>mole ratio</strong> that must exist between the two reactants, silicon dioxide, <mathjax>#"SiO"_2#</mathjax>, and carbon, <mathjax>#"C"#</mathjax></p> <blockquote> <p><mathjax>#"SiO"_ (2(s)) + color(red)(2)"C"_ ((s)) -> "Si" _ ((s)) + 2"CO"_ ((g))#</mathjax></p> </blockquote> <p>You know by examining this chemical equation that <mathjax>#1#</mathjax> <strong>mole</strong> of silicon dioxide requires <mathjax>#color(red)(2)#</mathjax> <strong>moles</strong> of carbon in order to react completely. </p> <p>The problem provides you with <em>grams</em> of silicon dioxide and asks you to find the number of grams of carbon required to ensure that <strong>all the mass</strong> of silicon dioxide reacts. </p> <p>The first thing to do here is use the <strong>molar mass</strong> of silicon dioxide to convert the mass to <em>moles</em></p> <blockquote> <p><mathjax>#75.2 color(red)(cancel(color(black)("g"))) * "1 mole SiO"_2/(60.08color(red)(cancel(color(black)("g")))) = "1.252 moles SiO"_2#</mathjax></p> </blockquote> <p>You can now use the aforementioned mole ratio to find the number of <em>moles</em> of carbon needed</p> <blockquote> <p><mathjax>#1.252 color(red)(cancel(color(black)("moles SiO"_2))) * (color(red)(2)color(white)(a) "C")/(1 color(red)(cancel(color(black)("mole SiO"_2)))) = "2.504 moles C"#</mathjax></p> </blockquote> <p>Finally, use the <strong>molar mass</strong> of elemental carbon to see how many grams would contain this many moles </p> <blockquote> <p><mathjax>#2.504 color(red)(cancel(color(black)("moles C"))) * "12.011 g"/(1color(red)(cancel(color(black)("mole C")))) = color(green)(\|bar(ul(color(white)(a/a)color(black)("30.1 g")color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"30.1 g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The balanced chemical equation given to you tells you the <strong>mole ratio</strong> that must exist between the two reactants, silicon dioxide, <mathjax>#"SiO"_2#</mathjax>, and carbon, <mathjax>#"C"#</mathjax></p> <blockquote> <p><mathjax>#"SiO"_ (2(s)) + color(red)(2)"C"_ ((s)) -> "Si" _ ((s)) + 2"CO"_ ((g))#</mathjax></p> </blockquote> <p>You know by examining this chemical equation that <mathjax>#1#</mathjax> <strong>mole</strong> of silicon dioxide requires <mathjax>#color(red)(2)#</mathjax> <strong>moles</strong> of carbon in order to react completely. </p> <p>The problem provides you with <em>grams</em> of silicon dioxide and asks you to find the number of grams of carbon required to ensure that <strong>all the mass</strong> of silicon dioxide reacts. </p> <p>The first thing to do here is use the <strong>molar mass</strong> of silicon dioxide to convert the mass to <em>moles</em></p> <blockquote> <p><mathjax>#75.2 color(red)(cancel(color(black)("g"))) * "1 mole SiO"_2/(60.08color(red)(cancel(color(black)("g")))) = "1.252 moles SiO"_2#</mathjax></p> </blockquote> <p>You can now use the aforementioned mole ratio to find the number of <em>moles</em> of carbon needed</p> <blockquote> <p><mathjax>#1.252 color(red)(cancel(color(black)("moles SiO"_2))) * (color(red)(2)color(white)(a) "C")/(1 color(red)(cancel(color(black)("mole SiO"_2)))) = "2.504 moles C"#</mathjax></p> </blockquote> <p>Finally, use the <strong>molar mass</strong> of elemental carbon to see how many grams would contain this many moles </p> <blockquote> <p><mathjax>#2.504 color(red)(cancel(color(black)("moles C"))) * "12.011 g"/(1color(red)(cancel(color(black)("mole C")))) = color(green)(\|bar(ul(color(white)(a/a)color(black)("30.1 g")color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many grams of carbon are needed to react completely with 75.2 g #SiO_2# according to the equation: #SiO_2(s) + 2C(s) -> Si(s) + 2CO(g)#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="296425" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-08-07T11:23:26" itemprop="dateCreated"> Aug 7, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"30.1 g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The balanced chemical equation given to you tells you the <strong>mole ratio</strong> that must exist between the two reactants, silicon dioxide, <mathjax>#"SiO"_2#</mathjax>, and carbon, <mathjax>#"C"#</mathjax></p> <blockquote> <p><mathjax>#"SiO"_ (2(s)) + color(red)(2)"C"_ ((s)) -> "Si" _ ((s)) + 2"CO"_ ((g))#</mathjax></p> </blockquote> <p>You know by examining this chemical equation that <mathjax>#1#</mathjax> <strong>mole</strong> of silicon dioxide requires <mathjax>#color(red)(2)#</mathjax> <strong>moles</strong> of carbon in order to react completely. </p> <p>The problem provides you with <em>grams</em> of silicon dioxide and asks you to find the number of grams of carbon required to ensure that <strong>all the mass</strong> of silicon dioxide reacts. </p> <p>The first thing to do here is use the <strong>molar mass</strong> of silicon dioxide to convert the mass to <em>moles</em></p> <blockquote> <p><mathjax>#75.2 color(red)(cancel(color(black)("g"))) * "1 mole SiO"_2/(60.08color(red)(cancel(color(black)("g")))) = "1.252 moles SiO"_2#</mathjax></p> </blockquote> <p>You can now use the aforementioned mole ratio to find the number of <em>moles</em> of carbon needed</p> <blockquote> <p><mathjax>#1.252 color(red)(cancel(color(black)("moles SiO"_2))) * (color(red)(2)color(white)(a) "C")/(1 color(red)(cancel(color(black)("mole SiO"_2)))) = "2.504 moles C"#</mathjax></p> </blockquote> <p>Finally, use the <strong>molar mass</strong> of elemental carbon to see how many grams would contain this many moles </p> <blockquote> <p><mathjax>#2.504 color(red)(cancel(color(black)("moles C"))) * "12.011 g"/(1color(red)(cancel(color(black)("mole C")))) = color(green)(\|bar(ul(color(white)(a/a)color(black)("30.1 g")color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/296425" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What 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1,827	acfb01ca-6ddd-11ea-aca2-ccda262736ce	https://socratic.org/questions/what-concentration-of-no-3-results-when-697-ml-of-0-515-m-nano-3-is-mixed-with-6	1.02 M	start physical_unit 3 3 concentration mol/l qc_end physical_unit 11 11 9 10 concentration qc_end physical_unit 20 20 18 19 concentration qc_end end	[{"type":"physical unit","value":"Concentration [OF] NO3- [IN] M"}]	[{"type":"physical unit","value":"1.02 M"}]	[{"type":"physical unit","value":"Volume [OF] NaNO3 [=] \\pu{697 mL}"},{"type":"physical unit","value":"Concentration [OF] NaNO3 [=] \\pu{0.515 M}"},{"type":"physical unit","value":"Volume [OF] Ca(NO3)2 [=] \\pu{635 mL}"},{"type":"physical unit","value":"Concentration [OF] Ca(NO3)2 [=] \\pu{0.785 M}"}]	<h1 class="questionTitle" itemprop="name">What concentration of #NO_3^(-)# results when 697 mL of 0.515 M #NaNO_3# is mixed with 635 mL of 0.785 M #Ca(NO_3)_2#?</h1>	null	1.02 M	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>As you know, <em>sodium nitrate</em>, <mathjax>#"NaNO"_3#</mathjax>, and <em>calcium nitrate</em>, <mathjax>#"Ca"("NO"_3)_2#</mathjax>, are both <strong>soluble</strong> in aqueous solution.</p> <p>This means that when dissolved in water, these <a href="https://socratic.org/chemistry/ionic-bonds-and-formulas/ionic-compounds">ionic compounds</a> will dissociate completely and exist as cations and anions. </p> <p>More specifically, they will dissociate to form </p> <blockquote> <p><mathjax>#"NaNO"_text(3(aq]) -> "Na"_text((aq])^(+) + "NO"_text(3(aq])^(-)#</mathjax></p> </blockquote> <p>and</p> <blockquote> <p><mathjax>#"Ca"("NO"_3)_text(2(aq]) -> "Ca"_text((aq])^(2+) + color(red)(2)"NO"_text(3(aq])^(-)#</mathjax></p> </blockquote> <p>Notice that sodium nitrate dissociates in a <mathjax>#1:1#</mathjax> <a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> with the nitrate anions, which means that <strong>every mole</strong> of the former will produce <mathjax>#1#</mathjax> <strong>mole</strong> of nitrate anions in solution.</p> <p>On the other hand, calcium nitrate dissociates in a <mathjax>#1:color(red)(2)#</mathjax> mole ratio with the nitrate anions, which means that <strong>every mole</strong> of the former will produce <mathjax>#color(red)(2)#</mathjax> <strong>moles</strong> of nitrate anions in solution. </p> <p>Use the molarities and volumes of the two solution to figure out how many moles of each salt you start with</p> <blockquote> <p><mathjax>#color(blue)(c = n/V implies n = c * V)#</mathjax></p> <p><mathjax>#n_(NaNO_3) = "0.515 M" * 697 * 10^(-3)"L" = "0.3590 moles NanO"_3#</mathjax></p> <p><mathjax>#n_(Ca(NO_3)_2) = "0.785 M" * 635 * 10^(-3)"L" = "0.4985 moles Ca"("NO"_3)_2#</mathjax></p> </blockquote> <p>This corresponds to </p> <blockquote> <p><mathjax>#0.3590 color(red)(cancel(color(black)("moles NaNO"_3))) * ("1 mole NO"_3^(-))/(1color(red)(cancel(color(black)("mole NaNO"_3)))) = "0.3590 moles NO"_3^(-)#</mathjax></p> </blockquote> <p>and</p> <blockquote> <p><mathjax>#0.4985 color(red)(cancel(color(black)("moles Ca"("NO"_3)_2))) * (color(red)(2)" moles NO"_3^(-))/(1color(red)(cancel(color(black)("mole Ca"("NO"_3)_2)))) = "0.9970 moles NO"_3^(-)#</mathjax></p> </blockquote> <p>The <strong>total number of moles</strong> of nitrate anions will thus be</p> <blockquote> <p><mathjax>#n_"total" = 0.3590 + 0.9970 = "1.356 moles NO"_3^(-)#</mathjax></p> </blockquote> <p>Now, in order to get the concentration of the anions, you need to get the <em>total volume</em> of the solution <strong>in liters</strong></p> <blockquote> <p><mathjax>#V_"total" = 697 * 10^(-3)"L" + 635 * 10^(-3)"L" = "1.332 L"#</mathjax></p> </blockquote> <p>Therefore, the concentration of the nitrate anions will be</p> <blockquote> <p><mathjax>#["NO"_3^(-)] = "1.356 moles"/"1.332 L" = color(green)("1.02 M")#</mathjax></p> </blockquote> <p>The answer is rounded to three <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#["NO"_3^(-)] = "1.02 M"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>As you know, <em>sodium nitrate</em>, <mathjax>#"NaNO"_3#</mathjax>, and <em>calcium nitrate</em>, <mathjax>#"Ca"("NO"_3)_2#</mathjax>, are both <strong>soluble</strong> in aqueous solution.</p> <p>This means that when dissolved in water, these <a href="https://socratic.org/chemistry/ionic-bonds-and-formulas/ionic-compounds">ionic compounds</a> will dissociate completely and exist as cations and anions. </p> <p>More specifically, they will dissociate to form </p> <blockquote> <p><mathjax>#"NaNO"_text(3(aq]) -> "Na"_text((aq])^(+) + "NO"_text(3(aq])^(-)#</mathjax></p> </blockquote> <p>and</p> <blockquote> <p><mathjax>#"Ca"("NO"_3)_text(2(aq]) -> "Ca"_text((aq])^(2+) + color(red)(2)"NO"_text(3(aq])^(-)#</mathjax></p> </blockquote> <p>Notice that sodium nitrate dissociates in a <mathjax>#1:1#</mathjax> <a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> with the nitrate anions, which means that <strong>every mole</strong> of the former will produce <mathjax>#1#</mathjax> <strong>mole</strong> of nitrate anions in solution.</p> <p>On the other hand, calcium nitrate dissociates in a <mathjax>#1:color(red)(2)#</mathjax> mole ratio with the nitrate anions, which means that <strong>every mole</strong> of the former will produce <mathjax>#color(red)(2)#</mathjax> <strong>moles</strong> of nitrate anions in solution. </p> <p>Use the molarities and volumes of the two solution to figure out how many moles of each salt you start with</p> <blockquote> <p><mathjax>#color(blue)(c = n/V implies n = c * V)#</mathjax></p> <p><mathjax>#n_(NaNO_3) = "0.515 M" * 697 * 10^(-3)"L" = "0.3590 moles NanO"_3#</mathjax></p> <p><mathjax>#n_(Ca(NO_3)_2) = "0.785 M" * 635 * 10^(-3)"L" = "0.4985 moles Ca"("NO"_3)_2#</mathjax></p> </blockquote> <p>This corresponds to </p> <blockquote> <p><mathjax>#0.3590 color(red)(cancel(color(black)("moles NaNO"_3))) * ("1 mole NO"_3^(-))/(1color(red)(cancel(color(black)("mole NaNO"_3)))) = "0.3590 moles NO"_3^(-)#</mathjax></p> </blockquote> <p>and</p> <blockquote> <p><mathjax>#0.4985 color(red)(cancel(color(black)("moles Ca"("NO"_3)_2))) * (color(red)(2)" moles NO"_3^(-))/(1color(red)(cancel(color(black)("mole Ca"("NO"_3)_2)))) = "0.9970 moles NO"_3^(-)#</mathjax></p> </blockquote> <p>The <strong>total number of moles</strong> of nitrate anions will thus be</p> <blockquote> <p><mathjax>#n_"total" = 0.3590 + 0.9970 = "1.356 moles NO"_3^(-)#</mathjax></p> </blockquote> <p>Now, in order to get the concentration of the anions, you need to get the <em>total volume</em> of the solution <strong>in liters</strong></p> <blockquote> <p><mathjax>#V_"total" = 697 * 10^(-3)"L" + 635 * 10^(-3)"L" = "1.332 L"#</mathjax></p> </blockquote> <p>Therefore, the concentration of the nitrate anions will be</p> <blockquote> <p><mathjax>#["NO"_3^(-)] = "1.356 moles"/"1.332 L" = color(green)("1.02 M")#</mathjax></p> </blockquote> <p>The answer is rounded to three <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What concentration of #NO_3^(-)# results when 697 mL of 0.515 M #NaNO_3# is mixed with 635 mL of 0.785 M #Ca(NO_3)_2#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="202198" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-22T15:02:52" itemprop="dateCreated"> Dec 22, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#["NO"_3^(-)] = "1.02 M"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>As you know, <em>sodium nitrate</em>, <mathjax>#"NaNO"_3#</mathjax>, and <em>calcium nitrate</em>, <mathjax>#"Ca"("NO"_3)_2#</mathjax>, are both <strong>soluble</strong> in aqueous solution.</p> <p>This means that when dissolved in water, these <a href="https://socratic.org/chemistry/ionic-bonds-and-formulas/ionic-compounds">ionic compounds</a> will dissociate completely and exist as cations and anions. </p> <p>More specifically, they will dissociate to form </p> <blockquote> <p><mathjax>#"NaNO"_text(3(aq]) -> "Na"_text((aq])^(+) + "NO"_text(3(aq])^(-)#</mathjax></p> </blockquote> <p>and</p> <blockquote> <p><mathjax>#"Ca"("NO"_3)_text(2(aq]) -> "Ca"_text((aq])^(2+) + color(red)(2)"NO"_text(3(aq])^(-)#</mathjax></p> </blockquote> <p>Notice that sodium nitrate dissociates in a <mathjax>#1:1#</mathjax> <a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> with the nitrate anions, which means that <strong>every mole</strong> of the former will produce <mathjax>#1#</mathjax> <strong>mole</strong> of nitrate anions in solution.</p> <p>On the other hand, calcium nitrate dissociates in a <mathjax>#1:color(red)(2)#</mathjax> mole ratio with the nitrate anions, which means that <strong>every mole</strong> of the former will produce <mathjax>#color(red)(2)#</mathjax> <strong>moles</strong> of nitrate anions in solution. </p> <p>Use the molarities and volumes of the two solution to figure out how many moles of each salt you start with</p> <blockquote> <p><mathjax>#color(blue)(c = n/V implies n = c * V)#</mathjax></p> <p><mathjax>#n_(NaNO_3) = "0.515 M" * 697 * 10^(-3)"L" = "0.3590 moles NanO"_3#</mathjax></p> <p><mathjax>#n_(Ca(NO_3)_2) = "0.785 M" * 635 * 10^(-3)"L" = "0.4985 moles Ca"("NO"_3)_2#</mathjax></p> </blockquote> <p>This corresponds to </p> <blockquote> <p><mathjax>#0.3590 color(red)(cancel(color(black)("moles NaNO"_3))) * ("1 mole NO"_3^(-))/(1color(red)(cancel(color(black)("mole NaNO"_3)))) = "0.3590 moles NO"_3^(-)#</mathjax></p> </blockquote> <p>and</p> <blockquote> <p><mathjax>#0.4985 color(red)(cancel(color(black)("moles Ca"("NO"_3)_2))) * (color(red)(2)" moles NO"_3^(-))/(1color(red)(cancel(color(black)("mole Ca"("NO"_3)_2)))) = "0.9970 moles NO"_3^(-)#</mathjax></p> </blockquote> <p>The <strong>total number of moles</strong> of nitrate anions will thus be</p> <blockquote> <p><mathjax>#n_"total" = 0.3590 + 0.9970 = "1.356 moles NO"_3^(-)#</mathjax></p> </blockquote> <p>Now, in order to get the concentration of the anions, you need to get the <em>total volume</em> of the solution <strong>in liters</strong></p> <blockquote> <p><mathjax>#V_"total" = 697 * 10^(-3)"L" + 635 * 10^(-3)"L" = "1.332 L"#</mathjax></p> </blockquote> <p>Therefore, the concentration of the nitrate anions will be</p> <blockquote> <p><mathjax>#["NO"_3^(-)] = "1.356 moles"/"1.332 L" = color(green)("1.02 M")#</mathjax></p> </blockquote> <p>The answer is rounded to three <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/202198" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul 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1,828	aa7315c4-6ddd-11ea-a8b0-ccda262736ce	https://socratic.org/questions/58abceb211ef6b7f44c76832	C5H12(l) + 8 O2(g) -> 5 CO2(g) + 6 H2O(l)	start chemical_equation qc_end substance 6 6 qc_end c_other OTHER qc_end end	[{"type":"other","value":"Chemical Equation [OF] the combustion"}]	[{"type":"chemical equation","value":"C5H12(l) + 8 O2(g) -> 5 CO2(g) + 6 H2O(l)"}]	[{"type":"substance name","value":"Pentane"},{"type":"other","value":"By means of a stoichiometric equation."}]	<h1 class="questionTitle" itemprop="name">Can you represent the combustion of pentane by means of a stoichiometric equation?</h1>	null	C5H12(l) + 8 O2(g) -> 5 CO2(g) + 6 H2O(l)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The given equation is stoichiometrically balanced: garbage in equals garbage out. If the pentane is in stoichiometric proportion with the dioxygen and <mathjax>#"10 mol dioxygen"#</mathjax> were used, then there were <mathjax>#5/4mol#</mathjax> of <mathjax>#"pentane"#</mathjax> precisely, and <mathjax>#25/4mol#</mathjax> of carbon dioxide gas would result.</p> <p>Why? Because I merely follow the <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> of the rxn.<br/> <mathjax>#"1 mole"#</mathjax> or <mathjax>#"1 equiv"#</mathjax> <mathjax>#"pentane"#</mathjax> react with <mathjax>#"8 equiv"#</mathjax> dioxygen to give <mathjax>#"5 equiv"#</mathjax> carbon dioxide, and <mathjax>#"6 equiv"#</mathjax> water. In an internal combustion engine, however, combustion is rarely so complete. The products of incomplete combustion, <mathjax>#CO#</mathjax>, and <mathjax>#C#</mathjax>, are known to occur. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_5H_12(l) +8O_2(g) rarr 5CO_2(g) + 6H_2O(l)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The given equation is stoichiometrically balanced: garbage in equals garbage out. If the pentane is in stoichiometric proportion with the dioxygen and <mathjax>#"10 mol dioxygen"#</mathjax> were used, then there were <mathjax>#5/4mol#</mathjax> of <mathjax>#"pentane"#</mathjax> precisely, and <mathjax>#25/4mol#</mathjax> of carbon dioxide gas would result.</p> <p>Why? Because I merely follow the <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> of the rxn.<br/> <mathjax>#"1 mole"#</mathjax> or <mathjax>#"1 equiv"#</mathjax> <mathjax>#"pentane"#</mathjax> react with <mathjax>#"8 equiv"#</mathjax> dioxygen to give <mathjax>#"5 equiv"#</mathjax> carbon dioxide, and <mathjax>#"6 equiv"#</mathjax> water. In an internal combustion engine, however, combustion is rarely so complete. The products of incomplete combustion, <mathjax>#CO#</mathjax>, and <mathjax>#C#</mathjax>, are known to occur. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Can you represent the combustion of pentane by means of a stoichiometric equation?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/mole-ratios" itemprop="url"> <span class="breadcrumb" itemprop="title">Mole Ratios</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="380890" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-02-21T07:01:11" itemprop="dateCreated"> Feb 21, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_5H_12(l) +8O_2(g) rarr 5CO_2(g) + 6H_2O(l)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The given equation is stoichiometrically balanced: garbage in equals garbage out. If the pentane is in stoichiometric proportion with the dioxygen and <mathjax>#"10 mol dioxygen"#</mathjax> were used, then there were <mathjax>#5/4mol#</mathjax> of <mathjax>#"pentane"#</mathjax> precisely, and <mathjax>#25/4mol#</mathjax> of carbon dioxide gas would result.</p> <p>Why? Because I merely follow the <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> of the rxn.<br/> <mathjax>#"1 mole"#</mathjax> or <mathjax>#"1 equiv"#</mathjax> <mathjax>#"pentane"#</mathjax> react with <mathjax>#"8 equiv"#</mathjax> dioxygen to give <mathjax>#"5 equiv"#</mathjax> carbon dioxide, and <mathjax>#"6 equiv"#</mathjax> water. In an internal combustion engine, however, combustion is rarely so complete. The products of incomplete combustion, <mathjax>#CO#</mathjax>, and <mathjax>#C#</mathjax>, are known to occur. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/380890" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4178e02bf3469517a106e"> Question #a106e </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4178e02bf3469570e2e86"> Question #e2e86 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179102bf3469517a1072"> Question #a1072 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179402bf34694c8c5bf1"> Question #c5bf1 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179702bf3469588dc373"> Question #dc373 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179c02bf34694c8c5bf9"> Question #c5bf9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417a302bf3469517a1076"> Question #a1076 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417c702bf3469588dc377"> Question #dc377 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417d002bf346963eb984f"> Question #b984f </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417d402bf346950519ea3"> Question #19ea3 </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/mole-ratios"> See all questions in Mole Ratios </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2030 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Can you represent the combustion of pentane by means of a stoichiometric equation?	null
1,829	a99f3288-6ddd-11ea-aa79-ccda262736ce	https://socratic.org/questions/5925a8517c0149508b4e30d8	5.50 moles	start physical_unit 4 4 mole mol qc_end physical_unit 12 12 9 10 mole qc_end end	[{"type":"physical unit","value":"Mole [OF] Al2O3 [IN] moles"}]	[{"type":"physical unit","value":"5.50 moles"}]	[{"type":"physical unit","value":"Mole [OF] aluminum [=] \\pu{11 mol}"}]	<h1 class="questionTitle" itemprop="name">How many moles of #Al_2O_3# can be prepared from #11*mol# of aluminum?</h1>	null	5.50 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>If I have 18 eggs, then how many dozen eggs do I have? I think you would quickly be able to respond that you have <mathjax>#3/2#</mathjax> <mathjax>#"dozen"#</mathjax>, because <mathjax>#"1 dozen"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#12#</mathjax>.</p> <p>If I have a mole of stuff, aluminum atoms, oxygen atoms, I have <mathjax>#"Avogadro's number"#</mathjax> of individual atoms, where <mathjax>#"Avogadro's number"-=6.022xx10^23mol^-1#</mathjax>.</p> <p>Here we have <mathjax>#11mol#</mathjax> of aluminum metal; given the <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> we can make <mathjax>#5.5mol#</mathjax> <mathjax>#Al_2O_3#</mathjax>, which has a molar mass of <mathjax>#101.96g*mol^-1#</mathjax>. </p> <p>And thus we take the product, <mathjax>#"molar quantity"xx"molar mass"#</mathjax> to get an actual mass.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#5.5molxx101.96gmol^-1=560.78g#</mathjax>...........</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>If I have 18 eggs, then how many dozen eggs do I have? I think you would quickly be able to respond that you have <mathjax>#3/2#</mathjax> <mathjax>#"dozen"#</mathjax>, because <mathjax>#"1 dozen"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#12#</mathjax>.</p> <p>If I have a mole of stuff, aluminum atoms, oxygen atoms, I have <mathjax>#"Avogadro's number"#</mathjax> of individual atoms, where <mathjax>#"Avogadro's number"-=6.022xx10^23mol^-1#</mathjax>.</p> <p>Here we have <mathjax>#11mol#</mathjax> of aluminum metal; given the <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> we can make <mathjax>#5.5mol#</mathjax> <mathjax>#Al_2O_3#</mathjax>, which has a molar mass of <mathjax>#101.96g*mol^-1#</mathjax>. </p> <p>And thus we take the product, <mathjax>#"molar quantity"xx"molar mass"#</mathjax> to get an actual mass.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles of #Al_2O_3# can be prepared from #11mol# of aluminum?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="428965" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-24T15:53:21" itemprop="dateCreated"> May 24, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#5.5molxx101.96gmol^-1=560.78g#</mathjax>...........</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>If I have 18 eggs, then how many dozen eggs do I have? I think you would quickly be able to respond that you have <mathjax>#3/2#</mathjax> <mathjax>#"dozen"#</mathjax>, because <mathjax>#"1 dozen"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#12#</mathjax>.</p> <p>If I have a mole of stuff, aluminum atoms, oxygen atoms, I have <mathjax>#"Avogadro's number"#</mathjax> of individual atoms, where <mathjax>#"Avogadro's number"-=6.022xx10^23mol^-1#</mathjax>.</p> <p>Here we have <mathjax>#11mol#</mathjax> of aluminum metal; given the <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> we can make <mathjax>#5.5mol#</mathjax> <mathjax>#Al_2O_3#</mathjax>, which has a molar mass of <mathjax>#101.96gmol^-1#</mathjax>. </p> <p>And thus we take the product, <mathjax>#"molar quantity"xx"molar mass"#</mathjax> to get an actual mass.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/428965" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 917 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many moles of #Al_2O_3# can be prepared from #11*mol# of aluminum?	null
1,830	abdc1546-6ddd-11ea-8507-ccda262736ce	https://socratic.org/questions/2nan-3-s-2na-s-3n-2-g-given-the-equation-how-many-moles-of-n-2-are-produced-by-t	2.25 moles	start physical_unit 7 7 mole mol qc_end chemical_equation 0 7 qc_end physical_unit 1 1 22 23 mole qc_end end	[{"type":"physical unit","value":"Mole [OF] N2 [IN] moles"}]	[{"type":"physical unit","value":"2.25 moles"}]	[{"type":"chemical equation","value":"2 NaN3(s) -> 2 Na(s) + 3 N2(g)"},{"type":"physical unit","value":"Mole [OF] NaN3 [=] \\pu{1.50 mol}"}]	<h1 class="questionTitle" itemprop="name">#2NaN_3(s) -> 2Na(s) + 3N_2(g)# Given the equation, how many moles of #N_2# are produced by the decomposition of 1.50 mol of #NaN_3#?</h1>	null	2.25 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The equation tells you that for every 2 moles of <mathjax>#NaN_3#</mathjax> decomposed, you get 3 moles of <mathjax>#N_2#</mathjax> out. </p> <p>So simply take the 1.5 mol and divide by two, then multiply by 3.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>2.25mol.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The equation tells you that for every 2 moles of <mathjax>#NaN_3#</mathjax> decomposed, you get 3 moles of <mathjax>#N_2#</mathjax> out. </p> <p>So simply take the 1.5 mol and divide by two, then multiply by 3.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">#2NaN_3(s) -> 2Na(s) + 3N_2(g)# Given the equation, how many moles of #N_2# are produced by the decomposition of 1.50 mol of #NaN_3#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/decomposition-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Decomposition Reactions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="309276" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/xik"><img alt="" class="" src="https://profilepictures.socratic.org/qjW7byZlQZy1HNp9uBe0_bdonat.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/xik"> Xik </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-09-12T17:48:44" itemprop="dateCreated"> Sep 12, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>2.25mol.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The equation tells you that for every 2 moles of <mathjax>#NaN_3#</mathjax> decomposed, you get 3 moles of <mathjax>#N_2#</mathjax> out. </p> <p>So simply take the 1.5 mol and divide by two, then multiply by 3.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/309276" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-decomposition-reactions"> What are decomposition reactions? 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</a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-thermal-decomposition-reactions"> What are thermal decomposition reactions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/do-decomposition-reactions-require-energy"> Do decomposition reactions require energy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-mass-spectrometry-relate-to-decomposition"> How does mass spectrometry relate to decomposition? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/do-chlorates-decompose-when-heated"> Do chlorates decompose when heated? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/decomposition-reactions"> See all questions in Decomposition Reactions </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1865 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	#2NaN_3(s) -> 2Na(s) + 3N_2(g)# Given the equation, how many moles of #N_2# are produced by the decomposition of 1.50 mol of #NaN_3#?	null
1,831	ad1b8dcc-6ddd-11ea-9735-ccda262736ce	https://socratic.org/questions/what-is-the-formula-for-sodium-peroxide	Na2O2	start chemical_formula qc_end substance 5 6 qc_end end	[{"type":"other","value":"Chemical Formula [OF] sodium peroxide [IN] default"}]	[{"type":"chemical equation","value":"Na2O2"}]	[{"type":"substance name","value":"Sodium peroxide"}]	<h1 class="questionTitle" itemprop="name">What is the formula for sodium peroxide?</h1>	null	Na2O2	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Oxygen in peroxide dianion has a formal <mathjax>#-I#</mathjax> oxidation state. Is this consistent with the given charge of the ion?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Na_2O_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Oxygen in peroxide dianion has a formal <mathjax>#-I#</mathjax> oxidation state. Is this consistent with the given charge of the ion?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the formula for sodium peroxide?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#ionic-bonds-and-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Ionic Bonds</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/ionic-bonds-and-formulas/writing-ionic-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Writing Ionic Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="288446" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-15T16:31:06" itemprop="dateCreated"> Jul 15, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Na_2O_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Oxygen in peroxide dianion has a formal <mathjax>#-I#</mathjax> oxidation state. Is this consistent with the given charge of the ion?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/288446" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-write-ionic-formulas-for-binary-compounds"> How do you write ionic formulas for binary compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-formula-for-calcium-chloride"> What is the ionic formula for calcium chloride? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-formula-for-calcium-oxide"> What is the ionic formula for calcium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-formula-for-lithium-oxide"> What is the ionic formula for lithium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-formula-for-ionic-compounds"> How do you write the formula for ionic compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-correctly-write-the-ions-present-in-sn-no3-2"> How do I write #Sn(NO_3)_2# in Ionic formula? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-an-ionic-compound"> What is the empirical formula for an ionic compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-for-chorate"> What is the molecular formula for chorate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5363023c02bf343b2ee7086b"> Question #7086b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-polyatomic-ions-covalent-1"> Why are polyatomic ions covalent? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/ionic-bonds-and-formulas/writing-ionic-formulas"> See all questions in Writing Ionic Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3720 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the formula for sodium peroxide?	null
1,832	a8e9c2f9-6ddd-11ea-8286-ccda262736ce	https://socratic.org/questions/58fa4c9cb72cff38e15a32f7	1.7 mol/L	start physical_unit 11 11 molarity mol/l qc_end physical_unit 2 2 0 1 mole qc_end physical_unit 11 11 7 8 volume qc_end end	[{"type":"physical unit","value":"Molar concentration [OF] the solution [IN] mol/L"}]	[{"type":"physical unit","value":"1.7 mol/L"}]	[{"type":"physical unit","value":"Mole [OF] solute [=] \\pu{0.50 mol}"},{"type":"physical unit","value":"Volume [OF] solution [=] \\pu{0.30 L}"}]	<h1 class="questionTitle" itemprop="name">#0.50mol# solute is dissolved in a #0.30L# volume of solution. What is the molar concentration?</h1>	null	1.7 mol/L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And thus <mathjax>#"molar concentration"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(0.50mol)/(0.30L)#</mathjax></p> <p><mathjax>#=??molL^-1#</mathjax>............</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Concentration"="Moles of solute"/"Volume of solution"#</mathjax></p> <p><mathjax>#~=1.7molL^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And thus <mathjax>#"molar concentration"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(0.50mol)/(0.30L)#</mathjax></p> <p><mathjax>#=??molL^-1#</mathjax>............</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">#0.50mol# solute is dissolved in a #0.30L# volume of solution. What is the molar concentration?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="410557" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-21T18:32:08" itemprop="dateCreated"> Apr 21, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Concentration"="Moles of solute"/"Volume of solution"#</mathjax></p> <p><mathjax>#~=1.7molL^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And thus <mathjax>#"molar concentration"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(0.50mol)/(0.30L)#</mathjax></p> <p><mathjax>#=??molL^-1#</mathjax>............</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/410557" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? 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What is the molar concentration?	null
1,833	abce0a70-6ddd-11ea-bd7f-ccda262736ce	https://socratic.org/questions/what-is-the-mass-in-grams-of-9-76-10-12-atoms-of-naturally-occurring-sodium	3.73 × 10^(-8) grams	start physical_unit 14 14 mass g qc_end end	[{"type":"physical unit","value":"Mass [OF] sodium [IN] grams"}]	[{"type":"physical unit","value":"3.73 × 10^(-8) grams"}]	[{"type":"physical unit","value":"Number [OF] sodium atoms [=] \\pu{9.76 × 10^12}"}]	<h1 class="questionTitle" itemprop="name">What is the mass in grams of #9.76 * 10^12# atoms of naturally occurring sodium? </h1>	null	3.73 × 10^(-8) grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The important thing here is to ignore the <em>naturally ocurring</em> part and realize that you're dealing with sodium metal, <mathjax>#"Na"#</mathjax>. </p> <p>Now, you need to use two concepts to help you solve this problem</p> <blockquote> <ul> <li><em>the molar mass of sulfur</em></li> <li><em>the number of atoms you get per mole, also known as <strong>Avogadro's number</strong></em></li> </ul> </blockquote> <p>An element's <strong>molar mass</strong> tells you what the exact mass of <strong>one mole</strong> of said element is. Sodium has a molar mass of approximately <mathjax>#"23.0 g/mol"#</mathjax>, which means that <strong>one mole</strong> of sodium has a mass of <mathjax>#"23.0 g"#</mathjax>.</p> <p>You also know that <strong>one mole</strong> of any element contains exactly <mathjax>#6.022 * 10^(23)#</mathjax> atoms of that element. This means that one mole of sodium has a mass of <mathjax>#"23.0 g"#</mathjax> and contains <mathjax>#6.022 * 10^(23)#</mathjax> atoms of sodium. </p> <blockquote> <p><mathjax>#"1 mole Na" = "23.0 g" = 6.022 * 10^(23)"atoms of Na"#</mathjax></p> </blockquote> <p>Therefore, that many atoms of sodium will have a mass of </p> <blockquote> <p><mathjax>#9.76 * 10^(14)color(red)(cancel(color(black)("atoms of Na"))) * "23.0 g"/(6.022 * 10^(23)color(red)(cancel(color(black)("atoms of Na")))) = color(green)(3.73 * 10^(-8)"g")#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#3.73 * 10^(-8)"g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The important thing here is to ignore the <em>naturally ocurring</em> part and realize that you're dealing with sodium metal, <mathjax>#"Na"#</mathjax>. </p> <p>Now, you need to use two concepts to help you solve this problem</p> <blockquote> <ul> <li><em>the molar mass of sulfur</em></li> <li><em>the number of atoms you get per mole, also known as <strong>Avogadro's number</strong></em></li> </ul> </blockquote> <p>An element's <strong>molar mass</strong> tells you what the exact mass of <strong>one mole</strong> of said element is. Sodium has a molar mass of approximately <mathjax>#"23.0 g/mol"#</mathjax>, which means that <strong>one mole</strong> of sodium has a mass of <mathjax>#"23.0 g"#</mathjax>.</p> <p>You also know that <strong>one mole</strong> of any element contains exactly <mathjax>#6.022 * 10^(23)#</mathjax> atoms of that element. This means that one mole of sodium has a mass of <mathjax>#"23.0 g"#</mathjax> and contains <mathjax>#6.022 * 10^(23)#</mathjax> atoms of sodium. </p> <blockquote> <p><mathjax>#"1 mole Na" = "23.0 g" = 6.022 * 10^(23)"atoms of Na"#</mathjax></p> </blockquote> <p>Therefore, that many atoms of sodium will have a mass of </p> <blockquote> <p><mathjax>#9.76 * 10^(14)color(red)(cancel(color(black)("atoms of Na"))) * "23.0 g"/(6.022 * 10^(23)color(red)(cancel(color(black)("atoms of Na")))) = color(green)(3.73 * 10^(-8)"g")#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the mass in grams of #9.76 * 10^12# atoms of naturally occurring sodium? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="186804" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-11T01:37:47" itemprop="dateCreated"> Nov 11, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#3.73 * 10^(-8)"g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The important thing here is to ignore the <em>naturally ocurring</em> part and realize that you're dealing with sodium metal, <mathjax>#"Na"#</mathjax>. </p> <p>Now, you need to use two concepts to help you solve this problem</p> <blockquote> <ul> <li><em>the molar mass of sulfur</em></li> <li><em>the number of atoms you get per mole, also known as <strong>Avogadro's number</strong></em></li> </ul> </blockquote> <p>An element's <strong>molar mass</strong> tells you what the exact mass of <strong>one mole</strong> of said element is. Sodium has a molar mass of approximately <mathjax>#"23.0 g/mol"#</mathjax>, which means that <strong>one mole</strong> of sodium has a mass of <mathjax>#"23.0 g"#</mathjax>.</p> <p>You also know that <strong>one mole</strong> of any element contains exactly <mathjax>#6.022 * 10^(23)#</mathjax> atoms of that element. This means that one mole of sodium has a mass of <mathjax>#"23.0 g"#</mathjax> and contains <mathjax>#6.022 * 10^(23)#</mathjax> atoms of sodium. </p> <blockquote> <p><mathjax>#"1 mole Na" = "23.0 g" = 6.022 * 10^(23)"atoms of Na"#</mathjax></p> </blockquote> <p>Therefore, that many atoms of sodium will have a mass of </p> <blockquote> <p><mathjax>#9.76 * 10^(14)color(red)(cancel(color(black)("atoms of Na"))) * "23.0 g"/(6.022 * 10^(23)color(red)(cancel(color(black)("atoms of Na")))) = color(green)(3.73 * 10^(-8)"g")#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/186804" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 21389 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the mass in grams of #9.76 * 10^12# atoms of naturally occurring sodium?	null
1,834	ab2828ad-6ddd-11ea-a3b2-ccda262736ce	https://socratic.org/questions/nitric-acid-in-acid-rain-forms-when-gaseous-nitrogen-dioxide-pollutant-reacts-wi	4 NO2(g) + O2(g) + 2 H2O(l) -> 4 HNO3(aq)	start chemical_equation qc_end substance 0 1 qc_end substance 7 9 qc_end substance 13 14 qc_end substance 16 17 qc_end end	[{"type":"other","value":"Chemical Equation [OF] this reaction"}]	[{"type":"chemical equation","value":"4 NO2(g) + O2(g) + 2 H2O(l) -> 4 HNO3(aq)"}]	[{"type":"substance name","value":"Nitric acid"},{"type":"substance name","value":"Gaseous nitrogen dioxide"},{"type":"substance name","value":"Gaseous oxygen"},{"type":"substance name","value":"Liquid water"}]	<h1 class="questionTitle" itemprop="name">Nitric acid in acid rain forms when gaseous nitrogen dioxide pollutant reacts with gaseous oxygen and liquid water to form aqueous nitric acid. How do you write a balanced chemical equation for this reaction?</h1>	null	4 NO2(g) + O2(g) + 2 H2O(l) -> 4 HNO3(aq)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The first thing to do here is identify your <strong>reactants</strong> and your <strong>product</strong>. </p> <p>The problem tells you that <em>gaseous</em> nitrogen dioxide, <mathjax>#"NO"_2#</mathjax> reacts with <em>gaseous</em> oxygen, <mathjax>#"O"_2#</mathjax>, and <em>liquid</em> water, <mathjax>#"H"_2"O"#</mathjax>, to form <em>aqueous</em> nitric acid, <mathjax>#"HNO"_3#</mathjax>. </p> <p>Your reactants are</p> <blockquote> <ul> <li><mathjax>#"NO"_ (2(g)) -> #</mathjax> <em>the</em> <mathjax>#(g)#</mathjax> <em>is used to denote a compound in the <strong>gaseous</strong> form</em></li> <li><mathjax>#"O"_ (2(g)) ->#</mathjax> <em>molecular oxygen in <strong>gaseous form</strong></em></li> <li><mathjax>#"H"_ 2"O"_ ((l)) ->#</mathjax> <em>the</em> <mathjax>#(l)#</mathjax> <em>is used to denote a compound in the <strong>liquid</strong> form</em></li> </ul> </blockquote> <p>Your product will be </p> <blockquote> <ul> <li><mathjax>#"HNO"_ (3(aq)) ->#</mathjax> <em>the</em> <mathjax>#(aq)#</mathjax> <em>is used to denote a compound in the <strong>aqueous</strong> form</em></li> </ul> </blockquote> <p>Your next goal is to write the <strong>unbalanced</strong> chemical equation by placing the reactants on the <strong>left side</strong> of the reaction arrow, <mathjax>#->#</mathjax>, and the products on the <strong>right side</strong> of the arrow</p> <blockquote> <p><mathjax>#"NO"_ (2(g)) + "O"_ (2(g)) + "H"_ 2"O"_ ((l)) -> "HNO"_ (3(aq))#</mathjax></p> </blockquote> <p>Now all you have to do is <strong>balance</strong> this equation by making sure that all the atoms present on the reactants' side are also present on the products' side. </p> <p>Now, this equation can be a little tricky to balance <em>by inspection</em>, but a cool trick to try out here is to get the oxygen atoms present on the reactants' side to an <strong>even number</strong> by multiplying the water molecule by <mathjax>#color(red)(2)#</mathjax></p> <blockquote> <p><mathjax>#"NO"_ (2(g)) + "O"_ (2(g)) + color(red)(2)"H"_ 2"O"_ ((l)) -> "HNO"_ (3(aq))#</mathjax></p> </blockquote> <p>You now have <mathjax>#6#</mathjax> <strong>atoms</strong> of oxygen on the reactants' side and <mathjax>#3#</mathjax> on the products' side. Ignore this for now. </p> <p>Focus on the hydrogen atoms next. Notice that you have </p> <blockquote> <p><mathjax>#color(red)(2) xx 2 = "4 atoms of H"#</mathjax></p> </blockquote> <p>on the reactants' side, and only <mathjax>#1#</mathjax> <strong>atom</strong> on the products' side, so multiply the nitric acid by <mathjax>#color(blue)(4)#</mathjax> to balance out the hydrogen atoms</p> <blockquote> <p><mathjax>#"NO"_ (2(g)) + "O"_ (2(g)) + color(red)(2)"H"_ 2"O"_ ((l)) -> color(blue)(4)"HNO"_ (3(aq))#</mathjax></p> </blockquote> <p>Now focus on the nitrogen atoms. You have </p> <blockquote> <p><mathjax>#color(blue)(4) xx 1 = "4 atoms of N"#</mathjax></p> </blockquote> <p>on the products' side, and only <mathjax>#1#</mathjax> <strong>atom</strong> on the reactants' side, so multiply the nitrogen dioxide molecule by <mathjax>#color(darkgreen)(4)#</mathjax> to get</p> <blockquote> <p><mathjax>#color(darkgreen)(4)"NO"_ (2(g)) + "O"_ (2(g)) + color(red)(2)"H"_ 2"O"_ ((l)) -> color(blue)(4)"HNO"_ (3(aq))#</mathjax></p> </blockquote> <p>As it turns out, the trick we used paid off because the oxygen are balanced! You have </p> <blockquote> <p><mathjax>#color(darkgreen)(4) xx 2 + 2 + color(red)(2) xx 1 = "12 atoms of O"#</mathjax></p> </blockquote> <p>on the reactants' side and </p> <blockquote> <p><mathjax>#color(blue)(4) xx 3 = "12 atoms of O"#</mathjax></p> </blockquote> <p>on the products' side, which means that the chemical equation is now <strong>balanced</strong>. </p> <blockquote> <p><mathjax>#color(green)(\|bar(ul(color(white)(a/a)color(black)(4"NO"_ (2(g)) + "O"_ (2(g)) + 2"H"_ 2"O"_ ((l)) -> 4"HNO"_ (3(aq)))color(white)(a/a)\|)))#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#4"NO"_ (2(g)) + "O"_ (2(g)) + 2"H"_ 2"O"_ ((l)) -> 4"HNO"_ (3(aq))#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The first thing to do here is identify your <strong>reactants</strong> and your <strong>product</strong>. </p> <p>The problem tells you that <em>gaseous</em> nitrogen dioxide, <mathjax>#"NO"_2#</mathjax> reacts with <em>gaseous</em> oxygen, <mathjax>#"O"_2#</mathjax>, and <em>liquid</em> water, <mathjax>#"H"_2"O"#</mathjax>, to form <em>aqueous</em> nitric acid, <mathjax>#"HNO"_3#</mathjax>. </p> <p>Your reactants are</p> <blockquote> <ul> <li><mathjax>#"NO"_ (2(g)) -> #</mathjax> <em>the</em> <mathjax>#(g)#</mathjax> <em>is used to denote a compound in the <strong>gaseous</strong> form</em></li> <li><mathjax>#"O"_ (2(g)) ->#</mathjax> <em>molecular oxygen in <strong>gaseous form</strong></em></li> <li><mathjax>#"H"_ 2"O"_ ((l)) ->#</mathjax> <em>the</em> <mathjax>#(l)#</mathjax> <em>is used to denote a compound in the <strong>liquid</strong> form</em></li> </ul> </blockquote> <p>Your product will be </p> <blockquote> <ul> <li><mathjax>#"HNO"_ (3(aq)) ->#</mathjax> <em>the</em> <mathjax>#(aq)#</mathjax> <em>is used to denote a compound in the <strong>aqueous</strong> form</em></li> </ul> </blockquote> <p>Your next goal is to write the <strong>unbalanced</strong> chemical equation by placing the reactants on the <strong>left side</strong> of the reaction arrow, <mathjax>#->#</mathjax>, and the products on the <strong>right side</strong> of the arrow</p> <blockquote> <p><mathjax>#"NO"_ (2(g)) + "O"_ (2(g)) + "H"_ 2"O"_ ((l)) -> "HNO"_ (3(aq))#</mathjax></p> </blockquote> <p>Now all you have to do is <strong>balance</strong> this equation by making sure that all the atoms present on the reactants' side are also present on the products' side. </p> <p>Now, this equation can be a little tricky to balance <em>by inspection</em>, but a cool trick to try out here is to get the oxygen atoms present on the reactants' side to an <strong>even number</strong> by multiplying the water molecule by <mathjax>#color(red)(2)#</mathjax></p> <blockquote> <p><mathjax>#"NO"_ (2(g)) + "O"_ (2(g)) + color(red)(2)"H"_ 2"O"_ ((l)) -> "HNO"_ (3(aq))#</mathjax></p> </blockquote> <p>You now have <mathjax>#6#</mathjax> <strong>atoms</strong> of oxygen on the reactants' side and <mathjax>#3#</mathjax> on the products' side. Ignore this for now. </p> <p>Focus on the hydrogen atoms next. Notice that you have </p> <blockquote> <p><mathjax>#color(red)(2) xx 2 = "4 atoms of H"#</mathjax></p> </blockquote> <p>on the reactants' side, and only <mathjax>#1#</mathjax> <strong>atom</strong> on the products' side, so multiply the nitric acid by <mathjax>#color(blue)(4)#</mathjax> to balance out the hydrogen atoms</p> <blockquote> <p><mathjax>#"NO"_ (2(g)) + "O"_ (2(g)) + color(red)(2)"H"_ 2"O"_ ((l)) -> color(blue)(4)"HNO"_ (3(aq))#</mathjax></p> </blockquote> <p>Now focus on the nitrogen atoms. You have </p> <blockquote> <p><mathjax>#color(blue)(4) xx 1 = "4 atoms of N"#</mathjax></p> </blockquote> <p>on the products' side, and only <mathjax>#1#</mathjax> <strong>atom</strong> on the reactants' side, so multiply the nitrogen dioxide molecule by <mathjax>#color(darkgreen)(4)#</mathjax> to get</p> <blockquote> <p><mathjax>#color(darkgreen)(4)"NO"_ (2(g)) + "O"_ (2(g)) + color(red)(2)"H"_ 2"O"_ ((l)) -> color(blue)(4)"HNO"_ (3(aq))#</mathjax></p> </blockquote> <p>As it turns out, the trick we used paid off because the oxygen are balanced! You have </p> <blockquote> <p><mathjax>#color(darkgreen)(4) xx 2 + 2 + color(red)(2) xx 1 = "12 atoms of O"#</mathjax></p> </blockquote> <p>on the reactants' side and </p> <blockquote> <p><mathjax>#color(blue)(4) xx 3 = "12 atoms of O"#</mathjax></p> </blockquote> <p>on the products' side, which means that the chemical equation is now <strong>balanced</strong>. </p> <blockquote> <p><mathjax>#color(green)(\|bar(ul(color(white)(a/a)color(black)(4"NO"_ (2(g)) + "O"_ (2(g)) + 2"H"_ 2"O"_ ((l)) -> 4"HNO"_ (3(aq)))color(white)(a/a)\|)))#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Nitric acid in acid rain forms when gaseous nitrogen dioxide pollutant reacts with gaseous oxygen and liquid water to form aqueous nitric acid. How do you write a balanced chemical equation for this reaction?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="278577" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-17T22:58:04" itemprop="dateCreated"> Jun 17, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#4"NO"_ (2(g)) + "O"_ (2(g)) + 2"H"_ 2"O"_ ((l)) -> 4"HNO"_ (3(aq))#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The first thing to do here is identify your <strong>reactants</strong> and your <strong>product</strong>. </p> <p>The problem tells you that <em>gaseous</em> nitrogen dioxide, <mathjax>#"NO"_2#</mathjax> reacts with <em>gaseous</em> oxygen, <mathjax>#"O"_2#</mathjax>, and <em>liquid</em> water, <mathjax>#"H"_2"O"#</mathjax>, to form <em>aqueous</em> nitric acid, <mathjax>#"HNO"_3#</mathjax>. </p> <p>Your reactants are</p> <blockquote> <ul> <li><mathjax>#"NO"_ (2(g)) -> #</mathjax> <em>the</em> <mathjax>#(g)#</mathjax> <em>is used to denote a compound in the <strong>gaseous</strong> form</em></li> <li><mathjax>#"O"_ (2(g)) ->#</mathjax> <em>molecular oxygen in <strong>gaseous form</strong></em></li> <li><mathjax>#"H"_ 2"O"_ ((l)) ->#</mathjax> <em>the</em> <mathjax>#(l)#</mathjax> <em>is used to denote a compound in the <strong>liquid</strong> form</em></li> </ul> </blockquote> <p>Your product will be </p> <blockquote> <ul> <li><mathjax>#"HNO"_ (3(aq)) ->#</mathjax> <em>the</em> <mathjax>#(aq)#</mathjax> <em>is used to denote a compound in the <strong>aqueous</strong> form</em></li> </ul> </blockquote> <p>Your next goal is to write the <strong>unbalanced</strong> chemical equation by placing the reactants on the <strong>left side</strong> of the reaction arrow, <mathjax>#->#</mathjax>, and the products on the <strong>right side</strong> of the arrow</p> <blockquote> <p><mathjax>#"NO"_ (2(g)) + "O"_ (2(g)) + "H"_ 2"O"_ ((l)) -> "HNO"_ (3(aq))#</mathjax></p> </blockquote> <p>Now all you have to do is <strong>balance</strong> this equation by making sure that all the atoms present on the reactants' side are also present on the products' side. </p> <p>Now, this equation can be a little tricky to balance <em>by inspection</em>, but a cool trick to try out here is to get the oxygen atoms present on the reactants' side to an <strong>even number</strong> by multiplying the water molecule by <mathjax>#color(red)(2)#</mathjax></p> <blockquote> <p><mathjax>#"NO"_ (2(g)) + "O"_ (2(g)) + color(red)(2)"H"_ 2"O"_ ((l)) -> "HNO"_ (3(aq))#</mathjax></p> </blockquote> <p>You now have <mathjax>#6#</mathjax> <strong>atoms</strong> of oxygen on the reactants' side and <mathjax>#3#</mathjax> on the products' side. Ignore this for now. </p> <p>Focus on the hydrogen atoms next. Notice that you have </p> <blockquote> <p><mathjax>#color(red)(2) xx 2 = "4 atoms of H"#</mathjax></p> </blockquote> <p>on the reactants' side, and only <mathjax>#1#</mathjax> <strong>atom</strong> on the products' side, so multiply the nitric acid by <mathjax>#color(blue)(4)#</mathjax> to balance out the hydrogen atoms</p> <blockquote> <p><mathjax>#"NO"_ (2(g)) + "O"_ (2(g)) + color(red)(2)"H"_ 2"O"_ ((l)) -> color(blue)(4)"HNO"_ (3(aq))#</mathjax></p> </blockquote> <p>Now focus on the nitrogen atoms. You have </p> <blockquote> <p><mathjax>#color(blue)(4) xx 1 = "4 atoms of N"#</mathjax></p> </blockquote> <p>on the products' side, and only <mathjax>#1#</mathjax> <strong>atom</strong> on the reactants' side, so multiply the nitrogen dioxide molecule by <mathjax>#color(darkgreen)(4)#</mathjax> to get</p> <blockquote> <p><mathjax>#color(darkgreen)(4)"NO"_ (2(g)) + "O"_ (2(g)) + color(red)(2)"H"_ 2"O"_ ((l)) -> color(blue)(4)"HNO"_ (3(aq))#</mathjax></p> </blockquote> <p>As it turns out, the trick we used paid off because the oxygen are balanced! You have </p> <blockquote> <p><mathjax>#color(darkgreen)(4) xx 2 + 2 + color(red)(2) xx 1 = "12 atoms of O"#</mathjax></p> </blockquote> <p>on the reactants' side and </p> <blockquote> <p><mathjax>#color(blue)(4) xx 3 = "12 atoms of O"#</mathjax></p> </blockquote> <p>on the products' side, which means that the chemical equation is now <strong>balanced</strong>. </p> <blockquote> <p><mathjax>#color(green)(\|bar(ul(color(white)(a/a)color(black)(4"NO"_ (2(g)) + "O"_ (2(g)) + 2"H"_ 2"O"_ ((l)) -> 4"HNO"_ (3(aq)))color(white)(a/a)\|)))#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/278577" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-equation-for-photosynthesis"> What is the chemical equation for photosynthesis? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-know-the-relative-number-of-grams-of-each-substance-used-or-produced-w"> How can I know the relative number of grams of each substance used or produced with chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-know-the-relative-number-of-moles-of-each-substance-with-chemical-equa"> How can I know the relative number of moles of each substance with chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-chemical-equations-illustrate-that-atoms-are-conserved-1"> How do chemical equations illustrate that atoms are conserved? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-know-the-formula-of-the-reactants-and-products-with-chemical-equations"> How can I know the formula of the reactants and products with chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-potassium-metal-and-chlorine-gas-combi"> How can I balance this chemical equations? 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How do you write a balanced chemical equation for this reaction?	null
1,835	abf314d2-6ddd-11ea-b23a-ccda262736ce	https://socratic.org/questions/56e2679b11ef6b57649affee	10 moles	start physical_unit 4 5 mole mol qc_end c_other OTHER qc_end physical_unit 15 15 11 12 mole qc_end end	[{"type":"physical unit","value":"Mole [OF] oxygen gas [IN] moles"}]	[{"type":"physical unit","value":"10 moles"}]	[{"type":"physical unit","value":"Mole [OF] acetylene [=] \\pu{4 mol}"},{"type":"other","value":"Combust completely."}]	<h1 class="questionTitle" itemprop="name">How many moles of oxygen gas are required to combust a #4*mol# quantity of acetylene completely?</h1>	null	10 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The balanced chemical equation is given. Each mole of acetylene requires two and a half moles of oxygen gas. So if 4 mol acetylene are combusted, some 10 moles of dioxygen are necessary.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#H-C-=C-H(g) + 5/2O_2(g) rarr 2CO_2(g) + H_2O(g)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The balanced chemical equation is given. Each mole of acetylene requires two and a half moles of oxygen gas. So if 4 mol acetylene are combusted, some 10 moles of dioxygen are necessary.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles of oxygen gas are required to combust a #4*mol# quantity of acetylene completely?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/stoichiometry-involving-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="238102" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-11T07:32:59" itemprop="dateCreated"> Mar 11, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#H-C-=C-H(g) + 5/2O_2(g) rarr 2CO_2(g) + H_2O(g)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The balanced chemical equation is given. Each mole of acetylene requires two and a half moles of oxygen gas. So if 4 mol acetylene are combusted, some 10 moles of dioxygen are necessary.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/238102" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="238104" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/jarni-renz"><img alt="" class="" src="https://profilepictures.socratic.org/i6OiZQmVRHWljDVlwm8v_WIN_20160301_180231.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/jarni-renz"> Jarni Renz </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-11T08:00:08" itemprop="dateCreated"> Mar 11, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#10#</mathjax> <mathjax># mol#</mathjax> <mathjax># O_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><ol> <li> <p>First thing to do is to balance the chemical equation; The balanced equation is:<br/> <mathjax>#2C_2H_2 + 5O_2 rarr 4CO_2 + 2H_2O#</mathjax></p> </li> <li> <p>Then use the coefficients, which represents the number of mol of its compound/molecules in said reaction, to get the number of mol of <mathjax>#O_2#</mathjax> molecules;</p> </li> <li>Multiply the mol of acetylene as provided in the problem (<mathjax>#4 mol C_2H_2#</mathjax>) with the convertion ratio of the moles of acetylene and oxygen molecules (<mathjax>#(5 mol O_2)/(2mol C_2H_2#</mathjax>)) based on the balanced equation;</li> <li>Make sure to cancel <a href="http://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> of <mathjax>#C_2H_2#</mathjax> and get your desired mole of <mathjax>#O_2#</mathjax> molecules. </li> <li>The answer per computation is 10 mol of <mathjax>#O_2#</mathjax>moleules</li> </ol></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/238104" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-apply-gas-stoichiometry"> How do you apply gas stoichiometry? 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</a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-2-00-g-mixture-of-na-and-ca-reat-with-water-1-164-l-hydrogen-was-produced-a"> When 2.00 g mixture of Na and Ca reat with water, 1.164 L hydrogen was produced at 300.0 K and... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/stoichiometry-involving-gases"> See all questions in Gas Stoichiometry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 7023 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many moles of oxygen gas are required to combust a #4*mol# quantity of acetylene completely?	null
1,836	ac2f5625-6ddd-11ea-8daa-ccda262736ce	https://socratic.org/questions/what-mass-of-gold-au-contains-the-same-number-of-atoms-9-0-g-of-aluminum-al	65 g	start physical_unit 4 4 mass g qc_end physical_unit 15 15 11 12 mass qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Mass [OF] Au [IN] g"}]	[{"type":"physical unit","value":"65 g"}]	[{"type":"physical unit","value":"Mass [OF] Al [=] \\pu{9.0 g}"},{"type":"other","value":"Au contains the same number of atoms of Al."}]	<h1 class="questionTitle" itemprop="name">What mass of gold, Au, contains the same number of atoms 9.0 g of aluminum, Al? </h1>	null	65 g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First determine the number of atoms in <mathjax>#"9.0 g Al"#</mathjax>.</p> <p>Divide the given mass of <mathjax>#"Al"#</mathjax> by its molar mass (atomic weight on <a href="http://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a> in g/mol), then multiply times <mathjax>#6.022xx10^23"atoms/mol"#</mathjax>, which is the same for all <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a>.</p> <p><mathjax>#9.0cancel"g Al"xx(1cancel"mol Al")/(26.982cancel"g Al")xx(6.022xx10^23"atoms Al")/(1cancel"mol Al")=2.0xx10^23 "atoms Al"#</mathjax></p> <p>Now reverse the process to determine the mass of gold that contains <mathjax>#2.0xx10^23"atoms Au"#</mathjax>.</p> <p>Divide the calculated atoms by the number of atoms in one mole, then multiply times the molar mass of <mathjax>#"Au"#</mathjax>.</p> <p><mathjax>#2.0xx10^23cancel"atoms Au"xx(1cancel"mol Au")/(6.022xx10^23cancel"atoms Au")xx(196.967"g Au")/(1cancel"mol Au")="65 g Au"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"9.0 g Al"#</mathjax> contains <mathjax>#2.0xx10^23"atoms Al"#</mathjax>.<br/> <mathjax>#2.0xx10^23"atoms Au"#</mathjax> has a mass of <mathjax>#"65 g"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First determine the number of atoms in <mathjax>#"9.0 g Al"#</mathjax>.</p> <p>Divide the given mass of <mathjax>#"Al"#</mathjax> by its molar mass (atomic weight on <a href="http://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a> in g/mol), then multiply times <mathjax>#6.022xx10^23"atoms/mol"#</mathjax>, which is the same for all <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a>.</p> <p><mathjax>#9.0cancel"g Al"xx(1cancel"mol Al")/(26.982cancel"g Al")xx(6.022xx10^23"atoms Al")/(1cancel"mol Al")=2.0xx10^23 "atoms Al"#</mathjax></p> <p>Now reverse the process to determine the mass of gold that contains <mathjax>#2.0xx10^23"atoms Au"#</mathjax>.</p> <p>Divide the calculated atoms by the number of atoms in one mole, then multiply times the molar mass of <mathjax>#"Au"#</mathjax>.</p> <p><mathjax>#2.0xx10^23cancel"atoms Au"xx(1cancel"mol Au")/(6.022xx10^23cancel"atoms Au")xx(196.967"g Au")/(1cancel"mol Au")="65 g Au"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What mass of gold, Au, contains the same number of atoms 9.0 g of aluminum, Al? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="193122" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-26T00:33:05" itemprop="dateCreated"> Nov 26, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"9.0 g Al"#</mathjax> contains <mathjax>#2.0xx10^23"atoms Al"#</mathjax>.<br/> <mathjax>#2.0xx10^23"atoms Au"#</mathjax> has a mass of <mathjax>#"65 g"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First determine the number of atoms in <mathjax>#"9.0 g Al"#</mathjax>.</p> <p>Divide the given mass of <mathjax>#"Al"#</mathjax> by its molar mass (atomic weight on <a href="http://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a> in g/mol), then multiply times <mathjax>#6.022xx10^23"atoms/mol"#</mathjax>, which is the same for all <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a>.</p> <p><mathjax>#9.0cancel"g Al"xx(1cancel"mol Al")/(26.982cancel"g Al")xx(6.022xx10^23"atoms Al")/(1cancel"mol Al")=2.0xx10^23 "atoms Al"#</mathjax></p> <p>Now reverse the process to determine the mass of gold that contains <mathjax>#2.0xx10^23"atoms Au"#</mathjax>.</p> <p>Divide the calculated atoms by the number of atoms in one mole, then multiply times the molar mass of <mathjax>#"Au"#</mathjax>.</p> <p><mathjax>#2.0xx10^23cancel"atoms Au"xx(1cancel"mol Au")/(6.022xx10^23cancel"atoms Au")xx(196.967"g Au")/(1cancel"mol Au")="65 g Au"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/193122" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? 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1,837	a9c15d86-6ddd-11ea-a591-ccda262736ce	https://socratic.org/questions/what-is-empirical-formula-of-a-compound-which-consists-of-89-14-au-and-10-80-of-	Au2O3	start chemical_formula qc_end end	[{"type":"other","value":"Chemical Formula [OF] the compound [IN] empirical"}]	[{"type":"chemical equation","value":"Au2O3"}]	[{"type":"physical unit","value":"Percentage [OF] Au in the compound [=] \\pu{89.14%}"},{"type":"physical unit","value":"Percentage [OF] O in the compound [=] \\pu{10.80%}"}]	<h1 class="questionTitle" itemprop="name">What is empirical formula of a compound which consists of 89.14% Au and 10.80% of O? </h1>	null	Au2O3	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to find a compound's <em>empirical formula</em> you must determine the <strong>smallest whole number ratio</strong> that exists between its constituent <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a>. </p> <p>In this case, your unknown compound is said to contain only gold, <mathjax>#"Au"#</mathjax>, and oxygen, <mathjax>#"O"#</mathjax>. The compound's <strong><a href="http://socratic.org/chemistry/the-mole-concept/percent-composition">percent composition</a></strong> essentially tells you how many grams of each constituent element you get <strong>per</strong> <mathjax>#"100 g"#</mathjax> of compound. </p> <p>In this case, a <mathjax>#"100-g"#</mathjax> sample of this unknown compound will contain <mathjax>#"89.14 g"#</mathjax> of gold and <mathjax>#"10.86 g"#</mathjax> of oxygen. </p> <p>This means that you can use the <strong>molar mass</strong> of each element to find how many <em>moles</em> you get in that <mathjax>#"100-g"#</mathjax> sample. You will thus have</p> <blockquote> <p><mathjax>#"For Au: " 89.14 color(red)(cancel(color(black)("g"))) * "1 mole Au"/(196.97color(red)(cancel(color(black)("g")))) = "0.45256 moles Au"#</mathjax></p> <p><mathjax>#"For O: " 10.86color(red)(cancel(color(black)("g"))) * "1 mole O"/(15.9994color(red)(cancel(color(black)("g")))) = "0.67876 moles O"#</mathjax></p> </blockquote> <p>To find the <em>mole ratio</em> that exists between the two elements, divide both values by the smallest one. This will get you</p> <blockquote> <p><mathjax>#"For Au:" (0.45256color(red)(cancel(color(black)("moles"))))/(0.45256color(red)(cancel(color(black)("moles")))) = 1#</mathjax></p> <p><mathjax>#"For O: " (0.67876color(red)(cancel(color(black)("moles"))))/(0.45256color(red)(cancel(color(black)("moles")))) = 1.4998 ~~ 1.5#</mathjax></p> </blockquote> <p>Now, it's important to remember that you're looking for the smallest <strong>whole number ratio</strong> here, which means that you're going to have to multiply both values by <mathjax>#2#</mathjax> to get</p> <blockquote> <p><mathjax>#("Au"_1"O"_1.5)_2 implies color(green)(\|bar(ul(color(white)(a/a)"Au"_2"O"_3color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The <em>empirical formula</em> of the compound will be <mathjax>#"Au"_2"O"_3#</mathjax>. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Au"_2"O"_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to find a compound's <em>empirical formula</em> you must determine the <strong>smallest whole number ratio</strong> that exists between its constituent <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a>. </p> <p>In this case, your unknown compound is said to contain only gold, <mathjax>#"Au"#</mathjax>, and oxygen, <mathjax>#"O"#</mathjax>. The compound's <strong><a href="http://socratic.org/chemistry/the-mole-concept/percent-composition">percent composition</a></strong> essentially tells you how many grams of each constituent element you get <strong>per</strong> <mathjax>#"100 g"#</mathjax> of compound. </p> <p>In this case, a <mathjax>#"100-g"#</mathjax> sample of this unknown compound will contain <mathjax>#"89.14 g"#</mathjax> of gold and <mathjax>#"10.86 g"#</mathjax> of oxygen. </p> <p>This means that you can use the <strong>molar mass</strong> of each element to find how many <em>moles</em> you get in that <mathjax>#"100-g"#</mathjax> sample. You will thus have</p> <blockquote> <p><mathjax>#"For Au: " 89.14 color(red)(cancel(color(black)("g"))) * "1 mole Au"/(196.97color(red)(cancel(color(black)("g")))) = "0.45256 moles Au"#</mathjax></p> <p><mathjax>#"For O: " 10.86color(red)(cancel(color(black)("g"))) * "1 mole O"/(15.9994color(red)(cancel(color(black)("g")))) = "0.67876 moles O"#</mathjax></p> </blockquote> <p>To find the <em>mole ratio</em> that exists between the two elements, divide both values by the smallest one. This will get you</p> <blockquote> <p><mathjax>#"For Au:" (0.45256color(red)(cancel(color(black)("moles"))))/(0.45256color(red)(cancel(color(black)("moles")))) = 1#</mathjax></p> <p><mathjax>#"For O: " (0.67876color(red)(cancel(color(black)("moles"))))/(0.45256color(red)(cancel(color(black)("moles")))) = 1.4998 ~~ 1.5#</mathjax></p> </blockquote> <p>Now, it's important to remember that you're looking for the smallest <strong>whole number ratio</strong> here, which means that you're going to have to multiply both values by <mathjax>#2#</mathjax> to get</p> <blockquote> <p><mathjax>#("Au"_1"O"_1.5)_2 implies color(green)(\|bar(ul(color(white)(a/a)"Au"_2"O"_3color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The <em>empirical formula</em> of the compound will be <mathjax>#"Au"_2"O"_3#</mathjax>. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is empirical formula of a compound which consists of 89.14% Au and 10.80% of O? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="238917" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-13T00:06:29" itemprop="dateCreated"> Mar 13, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Au"_2"O"_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to find a compound's <em>empirical formula</em> you must determine the <strong>smallest whole number ratio</strong> that exists between its constituent <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a>. </p> <p>In this case, your unknown compound is said to contain only gold, <mathjax>#"Au"#</mathjax>, and oxygen, <mathjax>#"O"#</mathjax>. The compound's <strong><a href="http://socratic.org/chemistry/the-mole-concept/percent-composition">percent composition</a></strong> essentially tells you how many grams of each constituent element you get <strong>per</strong> <mathjax>#"100 g"#</mathjax> of compound. </p> <p>In this case, a <mathjax>#"100-g"#</mathjax> sample of this unknown compound will contain <mathjax>#"89.14 g"#</mathjax> of gold and <mathjax>#"10.86 g"#</mathjax> of oxygen. </p> <p>This means that you can use the <strong>molar mass</strong> of each element to find how many <em>moles</em> you get in that <mathjax>#"100-g"#</mathjax> sample. You will thus have</p> <blockquote> <p><mathjax>#"For Au: " 89.14 color(red)(cancel(color(black)("g"))) * "1 mole Au"/(196.97color(red)(cancel(color(black)("g")))) = "0.45256 moles Au"#</mathjax></p> <p><mathjax>#"For O: " 10.86color(red)(cancel(color(black)("g"))) * "1 mole O"/(15.9994color(red)(cancel(color(black)("g")))) = "0.67876 moles O"#</mathjax></p> </blockquote> <p>To find the <em>mole ratio</em> that exists between the two elements, divide both values by the smallest one. This will get you</p> <blockquote> <p><mathjax>#"For Au:" (0.45256color(red)(cancel(color(black)("moles"))))/(0.45256color(red)(cancel(color(black)("moles")))) = 1#</mathjax></p> <p><mathjax>#"For O: " (0.67876color(red)(cancel(color(black)("moles"))))/(0.45256color(red)(cancel(color(black)("moles")))) = 1.4998 ~~ 1.5#</mathjax></p> </blockquote> <p>Now, it's important to remember that you're looking for the smallest <strong>whole number ratio</strong> here, which means that you're going to have to multiply both values by <mathjax>#2#</mathjax> to get</p> <blockquote> <p><mathjax>#("Au"_1"O"_1.5)_2 implies color(green)(\|bar(ul(color(white)(a/a)"Au"_2"O"_3color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The <em>empirical formula</em> of the compound will be <mathjax>#"Au"_2"O"_3#</mathjax>. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/238917" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molecular-formula-of-a-compound"> How do you find molecular formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-diamond"> What is the chemical formula of a diamond? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-carbohydrate"> What is the chemical formula of a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-valproic-acid"> What is the empirical formula for valproic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-of-magnesium-oxide"> What is the empirical formula of magnesium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-empirical-formula-not-double-that-of-the-monosaccharides"> Why is the empirical formula not double that of the monosaccharides? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5331180502bf342f40b5c3b5"> Question #5c3b5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-molecular-formula-represents-a-carbohydrate"> What molecular formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-of-vinegar"> What is the molecular formula of vinegar? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/empirical-and-molecular-formulas"> See all questions in Empirical and Molecular Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 18749 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is empirical formula of a compound which consists of 89.14% Au and 10.80% of O?	null
1,838	ab689922-6ddd-11ea-9976-ccda262736ce	https://socratic.org/questions/how-many-grams-of-ne-are-in-a-neon-sign-that-contains-0-0450-mol-of-neon-gas	0.91 grams	start physical_unit 4 4 mass g qc_end physical_unit 15 16 12 13 mole qc_end end	[{"type":"physical unit","value":"Mass [OF] Ne [IN] grams"}]	[{"type":"physical unit","value":"0.91 grams"}]	[{"type":"physical unit","value":"Mole [OF] neon gas [=] \\pu{0.0450 mol}"}]	<h1 class="questionTitle" itemprop="name">How many grams of Ne are in a neon sign that contains 0.0450 mol of neon gas? </h1>	null	0.91 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Elemental neon has a molar mass of <mathjax>#20.18#</mathjax> <mathjax>#g#</mathjax> <mathjax>#mol^-1#</mathjax>. To get the mass, simply multiply the molar mass by the molar quantity:</p> <p><mathjax>#0.0450#</mathjax> <mathjax>#mol#</mathjax> <mathjax>#xx#</mathjax> <mathjax>#20.18#</mathjax> <mathjax>#g*mol^-1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??g#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Almost <mathjax>#1#</mathjax> <mathjax>#g#</mathjax>. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Elemental neon has a molar mass of <mathjax>#20.18#</mathjax> <mathjax>#g#</mathjax> <mathjax>#mol^-1#</mathjax>. To get the mass, simply multiply the molar mass by the molar quantity:</p> <p><mathjax>#0.0450#</mathjax> <mathjax>#mol#</mathjax> <mathjax>#xx#</mathjax> <mathjax>#20.18#</mathjax> <mathjax>#g*mol^-1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??g#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many grams of Ne are in a neon sign that contains 0.0450 mol of neon gas? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="234326" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-03T06:14:19" itemprop="dateCreated"> Mar 3, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Almost <mathjax>#1#</mathjax> <mathjax>#g#</mathjax>. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Elemental neon has a molar mass of <mathjax>#20.18#</mathjax> <mathjax>#g#</mathjax> <mathjax>#mol^-1#</mathjax>. To get the mass, simply multiply the molar mass by the molar quantity:</p> <p><mathjax>#0.0450#</mathjax> <mathjax>#mol#</mathjax> <mathjax>#xx#</mathjax> <mathjax>#20.18#</mathjax> <mathjax>#g*mol^-1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??g#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/234326" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3275 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many grams of Ne are in a neon sign that contains 0.0450 mol of neon gas?	null
1,839	a8c077f2-6ddd-11ea-b02a-ccda262736ce	https://socratic.org/questions/what-is-the-oxidation-half-reaction-for-mg-s-zncl-2-ag-mgcl-2-ag-zn-s	Mg(s) -> Mg^2+ + 2e-	start chemical_equation qc_end chemical_equation 7 13 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the oxidation half reaction"}]	[{"type":"chemical equation","value":"Mg(s) -> Mg^2+ + 2e-"}]	[{"type":"chemical equation","value":"Mg(s) + ZnCl2(ag) -> MgCl2(ag) + Zn(s)"}]	<h1 class="questionTitle" itemprop="name">What is the oxidation half reaction for #Mg(s) + ZnCl_2(ag) -> MgCl_2(ag) + Zn(s)#?</h1>	null	Mg(s) -> Mg^2+ + 2e-	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>If you write what is known as the net ionic equation, it is a simpler matter to identify the oxidation (and the reduction form that matter).</p> <p>First, write the two salts in aqueous ion form:</p> <p><mathjax>#Mg(s)+Zn^(2+)(aq) +2Cl^-1 (aq) rarr Zn(s)+Mg^(2+)(aq) +2Cl^-1 (aq) #</mathjax></p> <p>Since no change occurs in the chloride ion, these are "spectators" and can be omitted:</p> <p><mathjax>#Mg(s)+Zn^(2+)(aq) rarr Zn(s)+Mg^(2+)(aq) #</mathjax></p> <p>Now, we have a more clear description of what has taken place.</p> <p><mathjax>#Zn^(2+)#</mathjax> has been reduced to <mathjax>#Zn(s)#</mathjax></p> <p><mathjax>#Mg(s)#</mathjax> has been oxidized to <mathjax>#Mg^(2+)#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The oxidation half-reaction is</p> <p><mathjax>#Mg(s) rarr Mg^(2+) + 2 e^-#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>If you write what is known as the net ionic equation, it is a simpler matter to identify the oxidation (and the reduction form that matter).</p> <p>First, write the two salts in aqueous ion form:</p> <p><mathjax>#Mg(s)+Zn^(2+)(aq) +2Cl^-1 (aq) rarr Zn(s)+Mg^(2+)(aq) +2Cl^-1 (aq) #</mathjax></p> <p>Since no change occurs in the chloride ion, these are "spectators" and can be omitted:</p> <p><mathjax>#Mg(s)+Zn^(2+)(aq) rarr Zn(s)+Mg^(2+)(aq) #</mathjax></p> <p>Now, we have a more clear description of what has taken place.</p> <p><mathjax>#Zn^(2+)#</mathjax> has been reduced to <mathjax>#Zn(s)#</mathjax></p> <p><mathjax>#Mg(s)#</mathjax> has been oxidized to <mathjax>#Mg^(2+)#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the oxidation half reaction for #Mg(s) + ZnCl_2(ag) -> MgCl_2(ag) + Zn(s)#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#electrochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Electrochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/electrochemistry/oxidation-and-reduction-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Oxidation and Reduction Reactions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="363317" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/dwight"><img alt="" class="" src="https://profilepictures.socratic.org/ZDiTFWmAQmWOT3sd0Xpr_Dwight.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/dwight"> Dwight </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-01-11T23:32:58" itemprop="dateCreated"> Jan 11, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The oxidation half-reaction is</p> <p><mathjax>#Mg(s) rarr Mg^(2+) + 2 e^-#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>If you write what is known as the net ionic equation, it is a simpler matter to identify the oxidation (and the reduction form that matter).</p> <p>First, write the two salts in aqueous ion form:</p> <p><mathjax>#Mg(s)+Zn^(2+)(aq) +2Cl^-1 (aq) rarr Zn(s)+Mg^(2+)(aq) +2Cl^-1 (aq) #</mathjax></p> <p>Since no change occurs in the chloride ion, these are "spectators" and can be omitted:</p> <p><mathjax>#Mg(s)+Zn^(2+)(aq) rarr Zn(s)+Mg^(2+)(aq) #</mathjax></p> <p>Now, we have a more clear description of what has taken place.</p> <p><mathjax>#Zn^(2+)#</mathjax> has been reduced to <mathjax>#Zn(s)#</mathjax></p> <p><mathjax>#Mg(s)#</mathjax> has been oxidized to <mathjax>#Mg^(2+)#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/363317" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="363345" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/scooke"><img alt="" class="" src="https://profilepictures.socratic.org/ezAzqDkjRS6NXBmMH3lg_BioPic2010a.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/scooke"> SCooke </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-01-12T00:30:54" itemprop="dateCreated"> Jan 12, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Anode: Mg → <mathjax>#Mg^(2+)#</mathjax> + 2e- 2.38V</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>From the equation we see that Mg metal (oxidation state 0) changes to the ion <mathjax>#Mg^(2+)#</mathjax>. It is thus “oxidized” and is the reducing agent. It is thus the anode of the cell. </p> <p>Zn is changed from it’s ionic state, <mathjax>#Zn^(2+)#</mathjax> to its metallic state of 0. It is thus “reduced” and is the oxidizing agent. It is thus the cathode of the cell. </p> <p>By convention, all half-cell emf's are compared to the emf of the standard hydrogen electrode. The emf of a half-cell, with respect to the standard hydrogen electrode, is called the reduction potential.<br/> In an electrochemical cell, the general equation is:</p> <p><mathjax>#E = E^o(red)#</mathjax> (cathode) - <mathjax>#E^o(red)#</mathjax> (anode) </p> <p>The emf for the Mg-Zn cell described would be:</p> <p><mathjax>#E = E^o(red)#</mathjax>(Zn) - <mathjax>#E^o(red)#</mathjax>(Mg) = -0.76 - (-2.38) = 1.62V if the solutions are 1.0 M.</p> <p>The two “standard cell” cathode (reduction) half reactions are:<br/> <mathjax>#Mg^(2+)#</mathjax> + 2e- → Mg - 2.38V<br/> <mathjax>#Zn^(2+)#</mathjax> + 2e- → Zn - 0.76V<br/> <a href="http://hyperphysics.phy-astr.gsu.edu/hbase/Tables/electpot.html" rel="nofollow" target="_blank">http://hyperphysics.phy-astr.gsu.edu/hbase/Tables/electpot.html</a></p> <p>Put in the general equation for the actual cell, the full reaction is:<br/> Mg + <mathjax>#Zn^(2+)#</mathjax>→<mathjax>#Mg^(2+)#</mathjax> + Zn <br/> -0.76 - (-2.38) = 1.62V</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/363345" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-balance-equations-with-charges"> How to balance equations for reduction/oxidation reaction? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-an-electode-reaction-has-dssolved-oxygen-as-a-reactant-is-the-electrode-an-an"> If an electode reaction has dssolved oxygen as a reactant, is the electrode an anode or a cathode? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-an-electrode-reaction-has-dissolved-oxygen-as-a-reactant-is-the-electrode-and"> If an electrode reaction has dissolved oxygen as a reactant, is the electrode and anode or a cathode? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-balanced-equation-represents-a-redox-reaction-2"> What balanced equation represents a redox reaction? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-redox-reactions-involved-in-electrolysis"> How are redox reactions involved in electrolysis? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-oxidation-reduction-reactions-coupled"> Why are oxidation reduction reactions coupled? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-do-oxidation-reduction-reactions-involve"> What do oxidation reduction reactions involve? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-reduction-reactions-used-for"> What are reduction reactions used for? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-calx-mean-in-oxidation-reduction-reactions"> What does "calx" mean in oxidation reduction reactions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-the-reduced-components-in-this-reaction-zn-2h-zn-2-h2"> What are the reduced components in this reaction? Zn + 2H(+) → Zn(2+) + H2 </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/electrochemistry/oxidation-and-reduction-reactions"> See all questions in Oxidation and Reduction Reactions </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 35662 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the oxidation half reaction for #Mg(s) + ZnCl_2(ag) -> MgCl_2(ag) + Zn(s)#?	null
1,840	ac81c96d-6ddd-11ea-b707-ccda262736ce	https://socratic.org/questions/571f275e7c01493702a14963	(NH4)2SO4(aq) + 2 KOH(aq) -> K2SO4(aq) + 2 NH3(aq) + 2 H2O(l)	start chemical_equation qc_end substance 10 11 qc_end substance 13 14 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the stoichiometric equation"}]	[{"type":"chemical equation","value":"(NH4)2SO4(aq) + 2 KOH(aq) -> K2SO4(aq) + 2 NH3(aq) + 2 H2O(l)"}]	[{"type":"substance name","value":"Ammonium sulfate"},{"type":"substance name","value":"Potassium hydroxide"}]	<h1 class="questionTitle" itemprop="name">Can you represent the stoichiometric equation for the reaction between ammonium sulfate, and potassium hydroxide?</h1>	null	(NH4)2SO4(aq) + 2 KOH(aq) -> K2SO4(aq) + 2 NH3(aq) + 2 H2O(l)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>What do you think you would notice in this reaction? You would notice the chemical change not with your eyes but with your hooter. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#(NH_4)_2SO_4(aq) + 2KOH(aq)rarrK_2SO_4(aq) +2NH_3(aq) + 2H_2O(l)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>What do you think you would notice in this reaction? You would notice the chemical change not with your eyes but with your hooter. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Can you represent the stoichiometric equation for the reaction between ammonium sulfate, and potassium hydroxide?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-reactions-and-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions and Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="297344" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-08-10T07:50:11" itemprop="dateCreated"> Aug 10, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#(NH_4)_2SO_4(aq) + 2KOH(aq)rarrK_2SO_4(aq) +2NH_3(aq) + 2H_2O(l)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>What do you think you would notice in this reaction? You would notice the chemical change not with your eyes but with your hooter. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/297344" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb002bf34694a4fee47"> Question #fee47 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb402bf34694c8c5c15"> Question #c5c15 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb802bf346950519eb9"> Question #19eb9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cbf02bf3469570e2ea2"> Question #e2ea2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc002bf34695a6bc751"> Question #bc751 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc202bf3469570e2ea6"> Question #e2ea6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531e867a02bf342492a08b07"> Question #08b07 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-thermochemical-equation-for-the-combustion-of-benzene"> What is the thermochemical equation for the combustion of benzene? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-reversible"> Why are chemical reactions reversible? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-important"> Why are chemical reactions important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/chemical-reactions-and-equations"> See all questions in Chemical Reactions and Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 6486 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Can you represent the stoichiometric equation for the reaction between ammonium sulfate, and potassium hydroxide?	null
1,841	a8a6d288-6ddd-11ea-991b-ccda262736ce	https://socratic.org/questions/what-compound-forms-when-an-atom-of-calcium-gains-two-electrons-from-an-atom-of-	CaS	start chemical_formula qc_end c_other OTHER qc_end end	[{"type":"other","value":"Chemical Formula [OF] compound [IN] default"}]	[{"type":"chemical equation","value":"CaS"}]	[{"type":"other","value":"An atom of calcium gains two electrons from an atom of sulfur."}]	<h1 class="questionTitle" itemprop="name">What compound forms when an atom of calcium gains two electrons from an atom of sulfur? </h1>	null	CaS	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Metals lose electrons to nonmetals. So if sulfur gains 2 electrons from calcium, the calcium atom will become a calcium ion with a 2+ charge, and the sulfur atom will become a sulfide ion with a 2- charge. </p> <p>The opposite charges will cause an electrostatic force of attraction between the oppositely charged ions, which will form the ionic compound calcium sulfide, <mathjax>#"CaS"#</mathjax>. <mathjax>#["Ca"]"^(2+)#</mathjax><mathjax>#["S"]"^(2-)#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>It is the other way around. The sulfur atom will gain 2 electrons from the calcium atom.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Metals lose electrons to nonmetals. So if sulfur gains 2 electrons from calcium, the calcium atom will become a calcium ion with a 2+ charge, and the sulfur atom will become a sulfide ion with a 2- charge. </p> <p>The opposite charges will cause an electrostatic force of attraction between the oppositely charged ions, which will form the ionic compound calcium sulfide, <mathjax>#"CaS"#</mathjax>. <mathjax>#["Ca"]"^(2+)#</mathjax><mathjax>#["S"]"^(2-)#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What compound forms when an atom of calcium gains two electrons from an atom of sulfur? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#ionic-bonds-and-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Ionic Bonds</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/ionic-bonds-and-formulas/ionic-compounds" itemprop="url"> <span class="breadcrumb" itemprop="title">Ionic Compounds</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="200005" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-15T08:06:31" itemprop="dateCreated"> Dec 15, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>It is the other way around. The sulfur atom will gain 2 electrons from the calcium atom.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Metals lose electrons to nonmetals. So if sulfur gains 2 electrons from calcium, the calcium atom will become a calcium ion with a 2+ charge, and the sulfur atom will become a sulfide ion with a 2- charge. </p> <p>The opposite charges will cause an electrostatic force of attraction between the oppositely charged ions, which will form the ionic compound calcium sulfide, <mathjax>#"CaS"#</mathjax>. <mathjax>#["Ca"]"^(2+)#</mathjax><mathjax>#["S"]"^(2-)#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/200005" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52f1151302bf34732c779c2f"> Question #79c2f </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52f1151302bf3473360cd842"> Question #cd842 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52f1151702bf34733dc14e7e"> Why do ionic compounds dissolve in water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52f1151b02bf3473394975aa"> Question #975aa </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52f1151b02bf3473394975ae"> Question #975ae </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52f1151e02bf34733e367e72"> Question #67e72 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/532eff8902bf341e776bd809"> What do the terms anhydrous, hydrous, and undissociated mean? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-ionic-compounds"> What are ionic compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-identify-ionic-compounds"> How can I identify ionic compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-ionic-compounds-solid-at-a-room-temperature"> Why are ionic compounds solid at room temperature? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/ionic-bonds-and-formulas/ionic-compounds"> See all questions in Ionic Compounds </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 4676 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What compound forms when an atom of calcium gains two electrons from an atom of sulfur?	null
1,842	ac0c45d5-6ddd-11ea-9202-ccda262736ce	https://socratic.org/questions/how-do-you-find-the-molar-mass-of-dihydrogen-dioxide	34.02 g/mol	start physical_unit 8 9 molar_mass g/mol qc_end substance 8 9 qc_end end	[{"type":"physical unit","value":"Molar mass [OF] dihydrogen dioxide [IN] g/mol"}]	[{"type":"physical unit","value":"34.02 g/mol"}]	[{"type":"substance name","value":"Dihydrogen dioxide"}]	<h1 class="questionTitle" itemprop="name">How do you find the molar mass of dihydrogen dioxide?</h1>	null	34.02 g/mol	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>A mole is a unit-molecular weight (grams/mole in this case) of an Avogadro's number of molecules or atoms. It is calculated for a molecule by adding up the individual atomic weights of its constituent atoms. </p> <p>“Dihydrogen dioxide” means two (2) hydrogens and two (2) oxygen atoms. Looking up the atomic weights on <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the Periodic Table</a> of the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">Elements</a> we obtain 1.0 for hydrogen and 16 for oxygen. Thus the total molecular mass will be</p> <p><mathjax>#2x1 + 2x16 = 34 ((grams)/("mole"))#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Add up the atomic weights of each constituent atom.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>A mole is a unit-molecular weight (grams/mole in this case) of an Avogadro's number of molecules or atoms. It is calculated for a molecule by adding up the individual atomic weights of its constituent atoms. </p> <p>“Dihydrogen dioxide” means two (2) hydrogens and two (2) oxygen atoms. Looking up the atomic weights on <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the Periodic Table</a> of the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">Elements</a> we obtain 1.0 for hydrogen and 16 for oxygen. Thus the total molecular mass will be</p> <p><mathjax>#2x1 + 2x16 = 34 ((grams)/("mole"))#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you find the molar mass of dihydrogen dioxide?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="403447" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/scooke"><img alt="" class="" src="https://profilepictures.socratic.org/ezAzqDkjRS6NXBmMH3lg_BioPic2010a.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/scooke"> SCooke </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-08T01:45:18" itemprop="dateCreated"> Apr 8, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Add up the atomic weights of each constituent atom.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>A mole is a unit-molecular weight (grams/mole in this case) of an Avogadro's number of molecules or atoms. It is calculated for a molecule by adding up the individual atomic weights of its constituent atoms. </p> <p>“Dihydrogen dioxide” means two (2) hydrogens and two (2) oxygen atoms. Looking up the atomic weights on <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the Periodic Table</a> of the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">Elements</a> we obtain 1.0 for hydrogen and 16 for oxygen. Thus the total molecular mass will be</p> <p><mathjax>#2x1 + 2x16 = 34 ((grams)/("mole"))#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/403447" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="403453" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/david-l-9"><img alt="" class="" src="https://profilepictures.socratic.org/4hB5YwS4T8mCJo4h2jgW_images.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/david-l-9"> David L. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-08T01:50:10" itemprop="dateCreated"> Apr 8, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#34.02(g/(mol))#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Dihydrogen dioxide is just a really fancy name for the common compond hydrogen peroxide (<mathjax>#H_2O_2#</mathjax>).</p> <p>To determine the molar mass of any compound, go to ther period table and look at the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">atomic mass</a> average (i.e Oxyagen has an atomic mass average of approximately <mathjax>#16.00(g/(mol))#</mathjax>). Adjust this number by how many of each element their are in the compound (<mathjax>#H_2O_2#</mathjax> has 2 hydrogen atoms). Sum as many of these values needed depending on how many elements are in the compund for the molar mass.</p> <p>By using the period table and knowing that hydrogen peroxide of dihydrogen dioxide have 2 hydrogen atoms and 2 oxyagen atoms, we can calculate the molar mass. </p> <p><mathjax>#[2*(1.01(g/(mol)))]+[2(16.00(g/(mol)))]=34.02(g/(mol))#</mathjax></p> <p>Note: Some tables differ slightly by the atomic mass average</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/403453" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 7098 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How do you find the molar mass of dihydrogen dioxide?	null
1,843	aa9347c6-6ddd-11ea-9a66-ccda262736ce	https://socratic.org/questions/59013df511ef6b6032337101	0.20 L	start physical_unit 3 3 volume l qc_end physical_unit 8 8 5 6 volume qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Volume [OF] propane [IN] L"}]	[{"type":"physical unit","value":"0.20 L"}]	[{"type":"physical unit","value":"Volume [OF] oxygen [=] \\pu{1 litre}"},{"type":"other","value":"Complete combustion."}]	<h1 class="questionTitle" itemprop="name">What volume of propane consumes one litre of oxygen during its complete combustion?</h1>	null	0.20 L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The balanced equation is</p> <p><mathjax>#color(white)(mmmmmm)"C"_3"H"_8 + "5O"_2 → "3CO"_2 + "4H"_2"O"#</mathjax><br/> <mathjax>#"Vol. ratio:"color(white)(mll)"1 L"color(white)(mm)"5 L"color(white)(mmll)"3 L"color(white)(mmll)"4 L"#</mathjax></p> <p>According to <strong>Gay-Lussac's Law of Combining volumes</strong>, the ratios of the volumes are the same as the ratios of the molecules (the coefficients in the balanced equation).</p> <p>Hence</p> <p><mathjax>#"Vol. of C"_3"H"_8 = 1 color(red)(cancel(color(black)("L O"_2))) × ("1 L C"_3"H"_8)/(5 color(red)(cancel(color(black)("L O"_2)))) = "0.2 L C"_3"H"_8#</mathjax></p> <p>∴ 0.2 L of propane is required for every litre of oxygen consumed.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.2 L of propane is required for every litre of oxygen consumed.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The balanced equation is</p> <p><mathjax>#color(white)(mmmmmm)"C"_3"H"_8 + "5O"_2 → "3CO"_2 + "4H"_2"O"#</mathjax><br/> <mathjax>#"Vol. ratio:"color(white)(mll)"1 L"color(white)(mm)"5 L"color(white)(mmll)"3 L"color(white)(mmll)"4 L"#</mathjax></p> <p>According to <strong>Gay-Lussac's Law of Combining volumes</strong>, the ratios of the volumes are the same as the ratios of the molecules (the coefficients in the balanced equation).</p> <p>Hence</p> <p><mathjax>#"Vol. of C"_3"H"_8 = 1 color(red)(cancel(color(black)("L O"_2))) × ("1 L C"_3"H"_8)/(5 color(red)(cancel(color(black)("L O"_2)))) = "0.2 L C"_3"H"_8#</mathjax></p> <p>∴ 0.2 L of propane is required for every litre of oxygen consumed.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What volume of propane consumes one litre of oxygen during its complete combustion?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/stoichiometry-involving-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="416669" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-02T21:46:32" itemprop="dateCreated"> May 2, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.2 L of propane is required for every litre of oxygen consumed.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The balanced equation is</p> <p><mathjax>#color(white)(mmmmmm)"C"_3"H"_8 + "5O"_2 → "3CO"_2 + "4H"_2"O"#</mathjax><br/> <mathjax>#"Vol. ratio:"color(white)(mll)"1 L"color(white)(mm)"5 L"color(white)(mmll)"3 L"color(white)(mmll)"4 L"#</mathjax></p> <p>According to <strong>Gay-Lussac's Law of Combining volumes</strong>, the ratios of the volumes are the same as the ratios of the molecules (the coefficients in the balanced equation).</p> <p>Hence</p> <p><mathjax>#"Vol. of C"_3"H"_8 = 1 color(red)(cancel(color(black)("L O"_2))) × ("1 L C"_3"H"_8)/(5 color(red)(cancel(color(black)("L O"_2)))) = "0.2 L C"_3"H"_8#</mathjax></p> <p>∴ 0.2 L of propane is required for every litre of oxygen consumed.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/416669" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-apply-gas-stoichiometry"> How do you apply gas stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a 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src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What volume of propane consumes one litre of oxygen during its complete combustion?	null
1,844	ab123788-6ddd-11ea-b6a4-ccda262736ce	https://socratic.org/questions/what-is-the-mass-of-neon-that-exerts-a-pressure-of-720-mmhg-with-a-temperature-o	1.36 g	start physical_unit 5 5 mass g qc_end physical_unit 5 5 11 12 pressure qc_end physical_unit 5 5 17 18 temperature qc_end physical_unit 5 5 26 27 volume qc_end end	[{"type":"physical unit","value":"Mass [OF] neon [IN] g"}]	[{"type":"physical unit","value":"1.36 g"}]	[{"type":"physical unit","value":"Pressure [OF] neon [=] \\pu{720 mmHg}"},{"type":"physical unit","value":"Temperature [OF] neon [=] \\pu{-15.0 ℃}"},{"type":"physical unit","value":"Volume [OF] neon [=] \\pu{760 mL}"}]	<h1 class="questionTitle" itemprop="name">What is the mass of neon that exerts a pressure of 720 mmHg with a temperature of -15.0°C, when the volume of the container is 760 mL? </h1>	null	1.36 g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We use the old Ideal Gas equation...</p> <p><mathjax>#n=(PV)/(RT)=((720mmHg)/(760mmHgatm^-1)xx760mLxx10^-3LmL^-1)/(0.0821(Latm)/(Kmol)xx258.15K)#</mathjax></p> <p><mathjax>#=0.0340mol#</mathjax>...a mass of ....... </p> <p><mathjax>#0.034molxx40.0gmol^-1=1.36*g#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Mass of neon"-=1.36g#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We use the old Ideal Gas equation...</p> <p><mathjax>#n=(PV)/(RT)=((720mmHg)/(760mmHgatm^-1)xx760mLxx10^-3LmL^-1)/(0.0821(Latm)/(Kmol)xx258.15K)#</mathjax></p> <p><mathjax>#=0.0340mol#</mathjax>...a mass of ....... </p> <p><mathjax>#0.034molxx40.0gmol^-1=1.36g#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the mass of neon that exerts a pressure of 720 mmHg with a temperature of -15.0°C, when the volume of the container is 760 mL? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/ideal-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Ideal Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="612841" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-05-13T18:03:05" itemprop="dateCreated"> May 13, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Mass of neon"-=1.36g#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We use the old Ideal Gas equation...</p> <p><mathjax>#n=(PV)/(RT)=((720mmHg)/(760mmHgatm^-1)xx760mLxx10^-3LmL^-1)/(0.0821(Latm)/(Kmol)xx258.15K)#</mathjax></p> <p><mathjax>#=0.0340mol#</mathjax>...a mass of ....... </p> <p><mathjax>#0.034molxx40.0gmol^-1=1.36g#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/612841" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-ideal-gas-constant"> How do you find the ideal gas constant? 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R = 8.314 kPa L / (K mol) =... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-molar-mass-of-a-gas"> How do you calculate the molar mass of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-should-i-use-the-ideal-gas-law-and-not-the-combined-gas-law"> When should I use the ideal gas law and not the combined gas law? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/ideal-gas-law"> See all questions in Ideal Gas Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 5027 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the mass of neon that exerts a pressure of 720 mmHg with a temperature of -15.0°C, when the volume of the container is 760 mL?	null
1,845	aafff44c-6ddd-11ea-9e6e-ccda262736ce	https://socratic.org/questions/the-following-reaction-is-at-equilibrium-at-a-particular-temperature-h-2-g-i-2-g	50	start physical_unit 36 37 equilibrium_constant_k none qc_end chemical_equation 10 15 qc_end end	[{"type":"physical unit","value":"Kc [OF] the reaction"}]	[{"type":"physical unit","value":"50"}]	[{"type":"chemical equation","value":"H2(g) + I2(g) -> 2 HI(g)"},{"type":"physical unit","value":"[H2]eq [OF] solution [=] \\pu{0.012 M}"},{"type":"physical unit","value":"[I2]eq [OF] solution [=] \\pu{0.15 M}"},{"type":"physical unit","value":"[HI]eq [OF] solution [=] \\pu{0.30 M}"}]	<h1 class="questionTitle" itemprop="name"> The following reaction is at equilibrium at a particular temperature:#H_2(g) + I_2(g) -> 2HI(g)#. The #[H_2]_(eq) = .012 M, [I_2]_(eq) = .15 M#, and #[HI]_(eq) = .30 M#.What is the magnitude of #K_c# for the reaction?</h1>	null	50	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Even without doing any calculation, you should be able to look at the values given for the <em>equilibrium concentrations</em> of the three chemical species that take part in the reaction and predict that <mathjax>#K_c#</mathjax> will be <strong>greater than one</strong>.</p> <p>As you know, the <a href="https://socratic.org/chemistry/chemical-equilibrium/equilibrium-constants">equilibrium constant</a> tells you what the ratio is between the equilibrium concentrations of the <strong>products</strong> and the equilibrium concentrations of the <strong>reactants</strong>, all raised to the power of their respective stoichiometric coefficients.</p> <p>In this case, notice that the concentration of the product, <em>hydrogen iodide</em>, <mathjax>#"HI"#</mathjax>, is bigger than the equilibrium concentrations of the two reactants, hydrogen gas, <mathjax>#"H"_2#</mathjax>, and iodine, <mathjax>#"I"_2#</mathjax>. </p> <p>Moreover, the reaction produces <strong>twice as many</strong> moles of hydrogen iodide than moles of hydrogen and iodine that take part in the reaction, you can expect <mathjax>#K_c > 1#</mathjax>. </p> <p>For your equilibrium reaction</p> <blockquote> <p><mathjax>#"H"_text(2(g]) + "I"_text(2(g]) -> color(red)(2)"HI"_text((g])#</mathjax></p> </blockquote> <p>the equilibrium constant takes the form</p> <blockquote> <p><mathjax>#K_c = ( ["HI"]^color(red)(2))/(["H"_2] * ["I"_2])#</mathjax></p> </blockquote> <p>Plug in your values to get </p> <blockquote> <p><mathjax>#K_c = ( (0.30)^color(red)(2) color(red)(cancel(color(black)("M"^color(red)(2)))))/(0.012 color(red)(cancel(color(black)("M"))) * 0.15color(red)(cancel(color(black)("M")))) = color(green)(50.)#</mathjax></p> </blockquote> <p>Indeed, <mathjax>#K_c>1#</mathjax> as initially predicted. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#K_c = 50.#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Even without doing any calculation, you should be able to look at the values given for the <em>equilibrium concentrations</em> of the three chemical species that take part in the reaction and predict that <mathjax>#K_c#</mathjax> will be <strong>greater than one</strong>.</p> <p>As you know, the <a href="https://socratic.org/chemistry/chemical-equilibrium/equilibrium-constants">equilibrium constant</a> tells you what the ratio is between the equilibrium concentrations of the <strong>products</strong> and the equilibrium concentrations of the <strong>reactants</strong>, all raised to the power of their respective stoichiometric coefficients.</p> <p>In this case, notice that the concentration of the product, <em>hydrogen iodide</em>, <mathjax>#"HI"#</mathjax>, is bigger than the equilibrium concentrations of the two reactants, hydrogen gas, <mathjax>#"H"_2#</mathjax>, and iodine, <mathjax>#"I"_2#</mathjax>. </p> <p>Moreover, the reaction produces <strong>twice as many</strong> moles of hydrogen iodide than moles of hydrogen and iodine that take part in the reaction, you can expect <mathjax>#K_c > 1#</mathjax>. </p> <p>For your equilibrium reaction</p> <blockquote> <p><mathjax>#"H"_text(2(g]) + "I"_text(2(g]) -> color(red)(2)"HI"_text((g])#</mathjax></p> </blockquote> <p>the equilibrium constant takes the form</p> <blockquote> <p><mathjax>#K_c = ( ["HI"]^color(red)(2))/(["H"_2] * ["I"_2])#</mathjax></p> </blockquote> <p>Plug in your values to get </p> <blockquote> <p><mathjax>#K_c = ( (0.30)^color(red)(2) color(red)(cancel(color(black)("M"^color(red)(2)))))/(0.012 color(red)(cancel(color(black)("M"))) * 0.15color(red)(cancel(color(black)("M")))) = color(green)(50.)#</mathjax></p> </blockquote> <p>Indeed, <mathjax>#K_c>1#</mathjax> as initially predicted. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name"> The following reaction is at equilibrium at a particular temperature:#H_2(g) + I_2(g) -> 2HI(g)#. The #[H_2]_(eq) = .012 M, [I_2]_(eq) = .15 M#, and #[HI]_(eq) = .30 M#.What is the magnitude of #K_c# for the reaction?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-equilibrium" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Equilibrium</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-equilibrium/equilibrium-constants" itemprop="url"> <span class="breadcrumb" itemprop="title">Equilibrium Constants</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="198477" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-10T19:22:46" itemprop="dateCreated"> Dec 10, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#K_c = 50.#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Even without doing any calculation, you should be able to look at the values given for the <em>equilibrium concentrations</em> of the three chemical species that take part in the reaction and predict that <mathjax>#K_c#</mathjax> will be <strong>greater than one</strong>.</p> <p>As you know, the <a href="https://socratic.org/chemistry/chemical-equilibrium/equilibrium-constants">equilibrium constant</a> tells you what the ratio is between the equilibrium concentrations of the <strong>products</strong> and the equilibrium concentrations of the <strong>reactants</strong>, all raised to the power of their respective stoichiometric coefficients.</p> <p>In this case, notice that the concentration of the product, <em>hydrogen iodide</em>, <mathjax>#"HI"#</mathjax>, is bigger than the equilibrium concentrations of the two reactants, hydrogen gas, <mathjax>#"H"_2#</mathjax>, and iodine, <mathjax>#"I"_2#</mathjax>. </p> <p>Moreover, the reaction produces <strong>twice as many</strong> moles of hydrogen iodide than moles of hydrogen and iodine that take part in the reaction, you can expect <mathjax>#K_c > 1#</mathjax>. </p> <p>For your equilibrium reaction</p> <blockquote> <p><mathjax>#"H"_text(2(g]) + "I"_text(2(g]) -> color(red)(2)"HI"_text((g])#</mathjax></p> </blockquote> <p>the equilibrium constant takes the form</p> <blockquote> <p><mathjax>#K_c = ( ["HI"]^color(red)(2))/(["H"_2] * ["I"_2])#</mathjax></p> </blockquote> <p>Plug in your values to get </p> <blockquote> <p><mathjax>#K_c = ( (0.30)^color(red)(2) color(red)(cancel(color(black)("M"^color(red)(2)))))/(0.012 color(red)(cancel(color(black)("M"))) * 0.15color(red)(cancel(color(black)("M")))) = color(green)(50.)#</mathjax></p> </blockquote> <p>Indeed, <mathjax>#K_c>1#</mathjax> as initially predicted. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/198477" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-equilibrium-constant-change-with-temperature"> How does the equilibrium constant change with temperature? 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The #[H_2]_(eq) = .012 M, [I_2]_(eq) = .15 M#, and #[HI]_(eq) = .30 M#.What is the magnitude of #K_c# for the reaction?	null
1,846	ac7f7f26-6ddd-11ea-8960-ccda262736ce	https://socratic.org/questions/59225fea7c0149507f4407eb	+2	start physical_unit 6 6 oxidation_number none qc_end substance 8 9 qc_end end	[{"type":"physical unit","value":"Oxidation number [OF] carbon"}]	[{"type":"physical unit","value":"+2"}]	[{"type":"substance name","value":"Cyanide ion"}]	<h1 class="questionTitle" itemprop="name">What is the oxidation number of carbon in cyanide ion?</h1>	null	+2	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The typical Lewis represention of cyanide anion is as <mathjax>#:N-=C:^-#</mathjax>. Of course this means that nitrogen has an oxidation number of <mathjax>#0#</mathjax>, because the sum of the <a href="https://socratic.org/chemistry/electrochemistry/oxidation-numbers">oxidation numbers</a> must be equal to the charge on the ion. We conceive that the 6 electrons that comprise the carbon nitrogen bond are shared by the participating atoms. And there are this 5 electrons around nitrogen, i.e. a neutral nitrogen, <mathjax>#Z=5#</mathjax>, and 5 electrons around carbon, <mathjax>#Z=4#</mathjax>, an ANIONIC carbon.</p> <p>Other formalisms are possible. What is the oxidation number of iron here? This is something you will be asked to assess.</p> <p>If we draw the Lewis structure of cyanide anion as <mathjax>#""^(-):stackrel(ddot)N=C:#</mathjax>, then carbon has an oxidation number of <mathjax>#0#</mathjax>. But I can't think offhand of a complex where cyanide anion binds thru the nitrogen. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>I would say <mathjax>#-I#</mathjax>......</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The typical Lewis represention of cyanide anion is as <mathjax>#:N-=C:^-#</mathjax>. Of course this means that nitrogen has an oxidation number of <mathjax>#0#</mathjax>, because the sum of the <a href="https://socratic.org/chemistry/electrochemistry/oxidation-numbers">oxidation numbers</a> must be equal to the charge on the ion. We conceive that the 6 electrons that comprise the carbon nitrogen bond are shared by the participating atoms. And there are this 5 electrons around nitrogen, i.e. a neutral nitrogen, <mathjax>#Z=5#</mathjax>, and 5 electrons around carbon, <mathjax>#Z=4#</mathjax>, an ANIONIC carbon.</p> <p>Other formalisms are possible. What is the oxidation number of iron here? This is something you will be asked to assess.</p> <p>If we draw the Lewis structure of cyanide anion as <mathjax>#""^(-):stackrel(ddot)N=C:#</mathjax>, then carbon has an oxidation number of <mathjax>#0#</mathjax>. But I can't think offhand of a complex where cyanide anion binds thru the nitrogen. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the oxidation number of carbon in cyanide ion?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#electrochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Electrochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/electrochemistry/oxidation-numbers" itemprop="url"> <span class="breadcrumb" itemprop="title">Oxidation Numbers</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="427606" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-22T06:40:22" itemprop="dateCreated"> May 22, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>I would say <mathjax>#-I#</mathjax>......</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The typical Lewis represention of cyanide anion is as <mathjax>#:N-=C:^-#</mathjax>. Of course this means that nitrogen has an oxidation number of <mathjax>#0#</mathjax>, because the sum of the <a href="https://socratic.org/chemistry/electrochemistry/oxidation-numbers">oxidation numbers</a> must be equal to the charge on the ion. We conceive that the 6 electrons that comprise the carbon nitrogen bond are shared by the participating atoms. And there are this 5 electrons around nitrogen, i.e. a neutral nitrogen, <mathjax>#Z=5#</mathjax>, and 5 electrons around carbon, <mathjax>#Z=4#</mathjax>, an ANIONIC carbon.</p> <p>Other formalisms are possible. What is the oxidation number of iron here? This is something you will be asked to assess.</p> <p>If we draw the Lewis structure of cyanide anion as <mathjax>#""^(-):stackrel(ddot)N=C:#</mathjax>, then carbon has an oxidation number of <mathjax>#0#</mathjax>. But I can't think offhand of a complex where cyanide anion binds thru the nitrogen. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/427606" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-relate-to-electron-configuration"> How do oxidation numbers relate to electron configuration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-relate-to-valence-electrons"> How do oxidation numbers relate to valence electrons? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-vary-with-the-periodic-table"> How do oxidation numbers vary with the periodic table? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-oxidation-number-of-an-element-in-a-compound"> How do you calculate the oxidation number of an element in a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-sulfur"> What is the oxidation number for sulfur? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-carbon"> What is the oxidation number for carbon? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-copper"> What is the oxidation number for copper? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-nitrogen"> What is the oxidation number for nitrogen? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-oxygen"> What is the oxidation number for oxygen? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-oxidation-state-of-noble-gas-zero"> Why is the oxidation state of noble gas zero? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/electrochemistry/oxidation-numbers"> See all questions in Oxidation Numbers </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 5211 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the oxidation number of carbon in cyanide ion?	null
1,847	ac1dfc68-6ddd-11ea-bd2c-ccda262736ce	https://socratic.org/questions/synthetic-diamonds-can-be-manufactured-at-pressures-of-6-00-times-10-4-atm-if-we	0.03 mL	start physical_unit 18 18 volume l qc_end physical_unit 0 1 8 11 pressure qc_end physical_unit 18 18 15 16 volume qc_end physical_unit 18 18 20 21 pressure qc_end physical_unit 18 18 8 11 pressure qc_end end	[{"type":"physical unit","value":"Volume [OF] that gas [IN] mL"}]	[{"type":"physical unit","value":"0.03 mL"}]	[{"type":"physical unit","value":"Pressure [OF] synthetic diamonds [=] \\pu{6.00 × 10^4 atm}"},{"type":"physical unit","value":"Volume [OF] gas [=] \\pu{2.00 liters}"},{"type":"physical unit","value":"Pressure1 [OF] gas [=] \\pu{1.00 atm}"},{"type":"physical unit","value":"Pressure2 [OF] gas [=] \\pu{6.00 × 10^4 atm}"}]	<h1 class="questionTitle" itemprop="name">Synthetic diamonds can be manufactured at pressures of #6.00 times 10^4# atm. If we took 2.00 liters of gas at 1.00 atm and compressed it to a pressure #6.00 times 10^4# atm, what would the volume of that gas be?</h1>	null	0.03 mL	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Apply <a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's Law</a></p> <p><mathjax>#"Pressure "xx" Volume "=" Constant"#</mathjax></p> <p>The temperature being constant</p> <p><mathjax>#P_1V_1=P_2V_2#</mathjax></p> <p>The initial volume is <mathjax>#V_1=2L#</mathjax></p> <p>The initial pressure <mathjax>#P_1=1atm#</mathjax></p> <p>The final pressure is <mathjax>#P_2=610^4atm#</mathjax></p> <p>The final volume is</p> <p><mathjax>#V_2=1/(610^4)2=1/310^-4L=1/30mL#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The volume is <mathjax>#=1/30mL#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Apply <a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's Law</a></p> <p><mathjax>#"Pressure "xx" Volume "=" Constant"#</mathjax></p> <p>The temperature being constant</p> <p><mathjax>#P_1V_1=P_2V_2#</mathjax></p> <p>The initial volume is <mathjax>#V_1=2L#</mathjax></p> <p>The initial pressure <mathjax>#P_1=1atm#</mathjax></p> <p>The final pressure is <mathjax>#P_2=610^4atm#</mathjax></p> <p>The final volume is</p> <p><mathjax>#V_2=1/(610^4)2=1/310^-4L=1/30mL#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Synthetic diamonds can be manufactured at pressures of #6.00 times 10^4# atm. If we took 2.00 liters of gas at 1.00 atm and compressed it to a pressure #6.00 times 10^4# atm, what would the volume of that gas be?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/gas-laws" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Laws</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">3</span> Answers </h5> <div class="answers"> <div class="answer" id="642546" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/narad-t"><img alt="" class="" src="https://profilepictures.socratic.org/zsDo4Wx9QIqYad4PXKE9_150317-1041.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/narad-t"> Narad T. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-07-22T06:39:01" itemprop="dateCreated"> Jul 22, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The volume is <mathjax>#=1/30mL#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Apply <a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's Law</a></p> <p><mathjax>#"Pressure "xx" Volume "=" Constant"#</mathjax></p> <p>The temperature being constant</p> <p><mathjax>#P_1V_1=P_2V_2#</mathjax></p> <p>The initial volume is <mathjax>#V_1=2L#</mathjax></p> <p>The initial pressure <mathjax>#P_1=1atm#</mathjax></p> <p>The final pressure is <mathjax>#P_2=610^4atm#</mathjax></p> <p>The final volume is</p> <p><mathjax>#V_2=1/(610^4)2=1/310^-4L=1/30mL#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/642546" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="642551" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-07-22T07:23:10" itemprop="dateCreated"> Jul 22, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Rather small, a fraction of a millilitre….</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Old <a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's Law</a> insists that <mathjax>#P_1V_1=P_2V_2#</mathjax>...</p> <p>And so …………….</p> <p><mathjax>#V_2=(P_1V_1)/P_2=(2.00Lxx1.00atm)/(6.00xx10^4atm)=3.33xx10^-5L~=0.03*cm^3#</mathjax></p> <p>And note our assumptions...we ASSUME (perhaps wrongly) that the gas would not undergo a phase change. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/642551" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="642568" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/harish-chandra-rajpoot"><img alt="" class="" src="https://profilepictures.socratic.org/jiKCfRCFRCSwvobswJW0_HCR-2013%20GKP-3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/harish-chandra-rajpoot"> Harish Chandra Rajpoot </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-07-22T09:21:11" itemprop="dateCreated"> Jul 22, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#3.33\times 10^{-5}\ \text{ltrs#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Assuming gas is <strong>ideal undergoing a constant temperature process</strong> then </p> <p>According to <a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's Law</a>, at constant temperature <mathjax>#T#</mathjax>, the pressure <mathjax>#P#</mathjax> of a constant mass of an ideal gas is inversely proportional to its volume <mathjax>#V#</mathjax>. Mathematically given as</p> <p><mathjax>#P\prop 1/V#</mathjax></p> <p><mathjax>#PV=\text{constant#</mathjax> </p> <p><mathjax>#P_1V_1=P_2V_2#</mathjax></p> <p>As per given data, initial pressure <mathjax>#P_1=1\ text{atm#</mathjax> , initial volume <mathjax>#V_1=2\ text{ltrs#</mathjax> & final pressure <mathjax>#P_2=6\times 10^4\ text{atm#</mathjax>. Substituting these values in above equation, we get</p> <p><mathjax>#1\times 2=6\times 10^4\times V_2#</mathjax></p> <p><mathjax>#V_2=1/3\times 10^{-4}#</mathjax></p> <p><mathjax>#=3.33\times 10^{-5}\ \text{ltrs}#</mathjax> </p> <p>The final volume of gas becomes <mathjax>#V_2=3.33\times 10^{-5}\ \text{ltrs#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/642568" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-boyles-law-relate-to-breathing"> How does Boyle's law relate to breathing? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/in-avogadro-s-law-what-would-happen-to-v-if-n-is-increased-decreased-and-what-wo"> In Avogadro's Law what would happen to V if N is increased/decreased? 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If we took 2.00 liters of gas at 1.00 atm and compressed it to a pressure #6.00 times 10^4# atm, what would the volume of that gas be?	null
1,848	ab1f8cef-6ddd-11ea-b47c-ccda262736ce	https://socratic.org/questions/in-the-reaction-2mg-o-2-2mgo-the-law-of-definite-proportions-states-that-for-eve	1.00 moles	start physical_unit 6 6 mole mol qc_end chemical_equation 3 9 qc_end physical_unit 4 4 19 20 mole qc_end end	[{"type":"physical unit","value":"Mole [OF] O2 [IN] moles"}]	[{"type":"physical unit","value":"1.00 moles"}]	[{"type":"chemical equation","value":"2 Mg + O2 -> 2 MgO"},{"type":"physical unit","value":"Mole [OF] Mg [=] \\pu{2 moles}"}]	<h1 class="questionTitle" itemprop="name">In the reaction #2Mg + O_2 -> 2MgO#, the law of definite proportions states that for every 2 moles of #Mg# you will need how many moles of #O_2#?</h1>	null	1.00 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>It's in the balanced equation. Each number before a compound corresponds to how many miles you use, and when there is no number you put in a 1. So 2 <mathjax>#Mg#</mathjax> + (1) <mathjax>#O_{2}#</mathjax> means twice as many moles of <mathjax>#Mg#</mathjax> as <mathjax>#O_{2}#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>1.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>It's in the balanced equation. Each number before a compound corresponds to how many miles you use, and when there is no number you put in a 1. So 2 <mathjax>#Mg#</mathjax> + (1) <mathjax>#O_{2}#</mathjax> means twice as many moles of <mathjax>#Mg#</mathjax> as <mathjax>#O_{2}#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">In the reaction #2Mg + O_2 -> 2MgO#, the law of definite proportions states that for every 2 moles of #Mg# you will need how many moles of #O_2#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/mole-ratios" itemprop="url"> <span class="breadcrumb" itemprop="title">Mole Ratios</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="232450" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/olthe3rd"><img alt="" class="" src="https://profilepictures.socratic.org/ooIp4P3ES4imZU7Cwexy_Squirrel.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/olthe3rd"> Oscar L. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-02-28T11:43:13" itemprop="dateCreated"> Feb 28, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>1.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>It's in the balanced equation. Each number before a compound corresponds to how many miles you use, and when there is no number you put in a 1. So 2 <mathjax>#Mg#</mathjax> + (1) <mathjax>#O_{2}#</mathjax> means twice as many moles of <mathjax>#Mg#</mathjax> as <mathjax>#O_{2}#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/232450" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4178e02bf3469517a106e"> Question #a106e </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4178e02bf3469570e2e86"> Question #e2e86 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179102bf3469517a1072"> Question #a1072 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179402bf34694c8c5bf1"> Question #c5bf1 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179702bf3469588dc373"> Question #dc373 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179c02bf34694c8c5bf9"> Question #c5bf9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417a302bf3469517a1076"> Question #a1076 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417c702bf3469588dc377"> Question #dc377 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417d002bf346963eb984f"> Question #b984f </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417d402bf346950519ea3"> Question #19ea3 </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/mole-ratios"> See all questions in Mole Ratios </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2070 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	In the reaction #2Mg + O_2 -> 2MgO#, the law of definite proportions states that for every 2 moles of #Mg# you will need how many moles of #O_2#?	null
1,849	a9c2476c-6ddd-11ea-9d19-ccda262736ce	https://socratic.org/questions/chcif-2-with-a-mass-of-7-21-x-10-2-kg-escaped-into-a-room-with-a-volume-of-200-m	6.27 × 10^17	start physical_unit 37 38 number none qc_end physical_unit 0 0 5 8 mass qc_end physical_unit 28 29 17 18 volume qc_end physical_unit 0 0 41 42 volume qc_end physical_unit 0 0 48 51 avogadro_constant qc_end end	[{"type":"physical unit","value":"Number [OF] CHClF2 molecules"}]	[{"type":"physical unit","value":"6.27 × 10^17"}]	[{"type":"physical unit","value":"Mass [OF] CHClF2 [=] \\pu{7.21 × 10^(-2) kg}"},{"type":"physical unit","value":"Volume [OF] the room [=] \\pu{200 m^3}"},{"type":"physical unit","value":"Volume [OF] CHClF2 sample [=] \\pu{250 cm^3}"},{"type":"physical unit","value":"Avogadro constant [OF] CHClF2 [=] \\pu{6.02 × 10^23 mol^(-1)}"}]	<h1 class="questionTitle" itemprop="name">#"CHClF"_2# with a mass of #7.21 xx 10^(-2)# kg escaped into a room with a volume of #"200 m"^3#. Assuming #"CHClF"_2# is evenly distributed throughout the air in the room, how do you calculate the number of #"CHClF"_2# molecules in a #"250 cm"^3# sample?</h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>The Avogadro constant is <mathjax>#6.02 xx 20^23 "mol"^-1#</mathjax></p></div> </h2> </div> </div>	6.27 × 10^17	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your strategy here will be to use the <strong>molar mass</strong> of chlorodifluoromethane, <mathjax>#"CHClF"_2#</mathjax>, and <strong>Avogadro's number</strong> to calculate how many <strong>molecules</strong> of you have in that <mathjax>#7.21 * 10^(-2)"kg"#</mathjax> sample. </p> <p>Chlorodifluoromethane has a molar mass of <mathjax>#"86.47 g mol"^(-1)#</mathjax>, so start by converting your sample from <em>kilograms</em> to <em>grams</em></p> <blockquote> <p><mathjax>#7.21 * 10^(-2) color(red)(cancel(color(black)("kg"))) * (10^3 "g")/(1color(red)(cancel(color(black)("kg")))) = "72.1 g"#</mathjax></p> </blockquote> <p>Your sample will thus contain </p> <blockquote> <p><mathjax>#72.1 color(red)(cancel(color(black)("g"))) * "1 mole CHClF"_2/(86.47color(red)(cancel(color(black)("g")))) = "0.8338 moles CHClF"_2#</mathjax></p> </blockquote> <p>Now that you know how many <em>moles</em> of chlorodifluoromethane you have in your sample, use Avogadro's number to convert them to <strong>number of molecules</strong></p> <blockquote> <p><mathjax>#0.8338 color(red)(cancel(color(black)("moles CHClF"_2))) * (6.022 * 10^(23)"molec.")/(1color(red)(cancel(color(black)("mole CHClF"_2)))) = 5.021 * 10^(23)"molec."#</mathjax></p> </blockquote> <p>So, you know that your room contains <mathjax>#5.021 * 10^(23)#</mathjax> <strong>molecules</strong> of chlorodifluoromethane and that volume of the room is said to be equal to <mathjax>#"200 m"^3#</mathjax>. </p> <p>In order to determine how many molecules would be present in <mathjax>#"250 cm"^3#</mathjax> of air, convert the volume of the sample from <em>cubic centimeters</em> to <em>cubic meters</em></p> <blockquote> <p><mathjax>#250 color(red)(cancel(color(black)("cm"^3))) * "1 m"^3/(10^6color(red)(cancel(color(black)("cm"^3)))) = 2.5 * 10^(-4)"m"^3#</mathjax></p> </blockquote> <p>Finally, use the known concentration of molecules in the room to get the number of molecules present in the sample</p> <blockquote> <p><mathjax>#2.5 * 10^(-4) color(red)(cancel(color(black)("m"^3))) * (5.021 * 10^(23)"molec.")/(200color(red)(cancel(color(black)("m"^3)))) = color(green)(\|bar(ul(color(white)(a/a)color(black)(6.3 * 10^(17)"molec.")color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>I'll leave the answer rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, but notice that you only have one sig fig for the volume of the room. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#6.3 * 10^(17)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your strategy here will be to use the <strong>molar mass</strong> of chlorodifluoromethane, <mathjax>#"CHClF"_2#</mathjax>, and <strong>Avogadro's number</strong> to calculate how many <strong>molecules</strong> of you have in that <mathjax>#7.21 * 10^(-2)"kg"#</mathjax> sample. </p> <p>Chlorodifluoromethane has a molar mass of <mathjax>#"86.47 g mol"^(-1)#</mathjax>, so start by converting your sample from <em>kilograms</em> to <em>grams</em></p> <blockquote> <p><mathjax>#7.21 * 10^(-2) color(red)(cancel(color(black)("kg"))) * (10^3 "g")/(1color(red)(cancel(color(black)("kg")))) = "72.1 g"#</mathjax></p> </blockquote> <p>Your sample will thus contain </p> <blockquote> <p><mathjax>#72.1 color(red)(cancel(color(black)("g"))) * "1 mole CHClF"_2/(86.47color(red)(cancel(color(black)("g")))) = "0.8338 moles CHClF"_2#</mathjax></p> </blockquote> <p>Now that you know how many <em>moles</em> of chlorodifluoromethane you have in your sample, use Avogadro's number to convert them to <strong>number of molecules</strong></p> <blockquote> <p><mathjax>#0.8338 color(red)(cancel(color(black)("moles CHClF"_2))) * (6.022 * 10^(23)"molec.")/(1color(red)(cancel(color(black)("mole CHClF"_2)))) = 5.021 * 10^(23)"molec."#</mathjax></p> </blockquote> <p>So, you know that your room contains <mathjax>#5.021 * 10^(23)#</mathjax> <strong>molecules</strong> of chlorodifluoromethane and that volume of the room is said to be equal to <mathjax>#"200 m"^3#</mathjax>. </p> <p>In order to determine how many molecules would be present in <mathjax>#"250 cm"^3#</mathjax> of air, convert the volume of the sample from <em>cubic centimeters</em> to <em>cubic meters</em></p> <blockquote> <p><mathjax>#250 color(red)(cancel(color(black)("cm"^3))) * "1 m"^3/(10^6color(red)(cancel(color(black)("cm"^3)))) = 2.5 * 10^(-4)"m"^3#</mathjax></p> </blockquote> <p>Finally, use the known concentration of molecules in the room to get the number of molecules present in the sample</p> <blockquote> <p><mathjax>#2.5 * 10^(-4) color(red)(cancel(color(black)("m"^3))) * (5.021 * 10^(23)"molec.")/(200color(red)(cancel(color(black)("m"^3)))) = color(green)(\|bar(ul(color(white)(a/a)color(black)(6.3 * 10^(17)"molec.")color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>I'll leave the answer rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, but notice that you only have one sig fig for the volume of the room. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">#"CHClF"_2# with a mass of #7.21 xx 10^(-2)# kg escaped into a room with a volume of #"200 m"^3#. Assuming #"CHClF"_2# is evenly distributed throughout the air in the room, how do you calculate the number of #"CHClF"_2# molecules in a #"250 cm"^3# sample?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>The Avogadro constant is <mathjax>#6.02 xx 20^23 "mol"^-1#</mathjax></p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="295244" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-08-04T00:40:52" itemprop="dateCreated"> Aug 4, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#6.3 * 10^(17)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your strategy here will be to use the <strong>molar mass</strong> of chlorodifluoromethane, <mathjax>#"CHClF"_2#</mathjax>, and <strong>Avogadro's number</strong> to calculate how many <strong>molecules</strong> of you have in that <mathjax>#7.21 * 10^(-2)"kg"#</mathjax> sample. </p> <p>Chlorodifluoromethane has a molar mass of <mathjax>#"86.47 g mol"^(-1)#</mathjax>, so start by converting your sample from <em>kilograms</em> to <em>grams</em></p> <blockquote> <p><mathjax>#7.21 * 10^(-2) color(red)(cancel(color(black)("kg"))) * (10^3 "g")/(1color(red)(cancel(color(black)("kg")))) = "72.1 g"#</mathjax></p> </blockquote> <p>Your sample will thus contain </p> <blockquote> <p><mathjax>#72.1 color(red)(cancel(color(black)("g"))) * "1 mole CHClF"_2/(86.47color(red)(cancel(color(black)("g")))) = "0.8338 moles CHClF"_2#</mathjax></p> </blockquote> <p>Now that you know how many <em>moles</em> of chlorodifluoromethane you have in your sample, use Avogadro's number to convert them to <strong>number of molecules</strong></p> <blockquote> <p><mathjax>#0.8338 color(red)(cancel(color(black)("moles CHClF"_2))) * (6.022 * 10^(23)"molec.")/(1color(red)(cancel(color(black)("mole CHClF"_2)))) = 5.021 * 10^(23)"molec."#</mathjax></p> </blockquote> <p>So, you know that your room contains <mathjax>#5.021 * 10^(23)#</mathjax> <strong>molecules</strong> of chlorodifluoromethane and that volume of the room is said to be equal to <mathjax>#"200 m"^3#</mathjax>. </p> <p>In order to determine how many molecules would be present in <mathjax>#"250 cm"^3#</mathjax> of air, convert the volume of the sample from <em>cubic centimeters</em> to <em>cubic meters</em></p> <blockquote> <p><mathjax>#250 color(red)(cancel(color(black)("cm"^3))) * "1 m"^3/(10^6color(red)(cancel(color(black)("cm"^3)))) = 2.5 * 10^(-4)"m"^3#</mathjax></p> </blockquote> <p>Finally, use the known concentration of molecules in the room to get the number of molecules present in the sample</p> <blockquote> <p><mathjax>#2.5 * 10^(-4) color(red)(cancel(color(black)("m"^3))) * (5.021 * 10^(23)"molec.")/(200color(red)(cancel(color(black)("m"^3)))) = color(green)(\|bar(ul(color(white)(a/a)color(black)(6.3 * 10^(17)"molec.")color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>I'll leave the answer rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, but notice that you only have one sig fig for the volume of the room. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/295244" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div 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Assuming #"CHClF"_2# is evenly distributed throughout the air in the room, how do you calculate the number of #"CHClF"_2# molecules in a #"250 cm"^3# sample?	The Avogadro constant is #6.02 xx 20^23 "mol"^-1#
1,850	aab3e1ee-6ddd-11ea-9942-ccda262736ce	https://socratic.org/questions/solution-a-has-a-ph-of-3-and-solution-z-has-a-ph-of-6-how-many-times-greater-is-	1000	start physical_unit 20 34 times none qc_end physical_unit 0 1 6 6 ph qc_end physical_unit 8 9 14 14 ph qc_end end	[{"type":"physical unit","value":"Times greater [OF] the hydronium ion concentration in solution A than the hydronium ion concentration in solution Z"}]	[{"type":"physical unit","value":"1000"}]	[{"type":"physical unit","value":"pH [OF] solution A [=] \\pu{3}"},{"type":"physical unit","value":"pH [OF] solution Z [=] \\pu{6}"}]	<h1 class="questionTitle" itemprop="name">Solution A has a pH of 3 and solution Z has a pH of 6. How many times greater is the hydronium ion concentration in solution A than the hydronium ion concentration in solution Z?</h1>	null	1000	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>By definition, <mathjax>#pH=-log_10[H_3O^+]#</mathjax>. Why should we use such units? Well, back in the day, BEFORE the advent of cheap electronic calculators, scientists, engineers, and accountants used to use sets of printed logarithmic tables for multiplication and division of very large or very small numbers.......</p> <p>And thus for the product <mathjax>#x xx y#</mathjax>, we could take logs, and get <mathjax>#x xx y=10^(log_10x+log_10y)#</mathjax>, and then take antilogs of this quantity to get the product. Believe it or not, it was easier (and less error prone) to do these sets of operations (which involved standard tables and simple addition and subtraction) than long-handed multiplication. Anyway, I digress again.........</p> <p>And for your problem, since for <mathjax>#A/B#</mathjax>, <mathjax>#[H_3O^+""_A]/[H_3O^+""_B]=10^3#</mathjax>, as <mathjax>#log_10[H_3O^+""_A]-log_10[H_3O^+""_B]=3#</mathjax>. You need to remember the given definition of <mathjax>#pH#</mathjax>, which can be extended to <mathjax>#pOH#</mathjax> (and <mathjax>#pH+pOH=14#</mathjax>, for aqueous solutions), and also to the equilibrium constant <mathjax>#K_a#</mathjax>, with <mathjax>#pK_a=-log_10K_a#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Solution A"#</mathjax> has <mathjax>#"ONE THOUSAND times"#</mathjax> the concentration with respect to <mathjax>#H_3O^+#</mathjax> than <mathjax>#"SOLUTION Z"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>By definition, <mathjax>#pH=-log_10[H_3O^+]#</mathjax>. Why should we use such units? Well, back in the day, BEFORE the advent of cheap electronic calculators, scientists, engineers, and accountants used to use sets of printed logarithmic tables for multiplication and division of very large or very small numbers.......</p> <p>And thus for the product <mathjax>#x xx y#</mathjax>, we could take logs, and get <mathjax>#x xx y=10^(log_10x+log_10y)#</mathjax>, and then take antilogs of this quantity to get the product. Believe it or not, it was easier (and less error prone) to do these sets of operations (which involved standard tables and simple addition and subtraction) than long-handed multiplication. Anyway, I digress again.........</p> <p>And for your problem, since for <mathjax>#A/B#</mathjax>, <mathjax>#[H_3O^+""_A]/[H_3O^+""_B]=10^3#</mathjax>, as <mathjax>#log_10[H_3O^+""_A]-log_10[H_3O^+""_B]=3#</mathjax>. You need to remember the given definition of <mathjax>#pH#</mathjax>, which can be extended to <mathjax>#pOH#</mathjax> (and <mathjax>#pH+pOH=14#</mathjax>, for aqueous solutions), and also to the equilibrium constant <mathjax>#K_a#</mathjax>, with <mathjax>#pK_a=-log_10K_a#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Solution A has a pH of 3 and solution Z has a pH of 6. How many times greater is the hydronium ion concentration in solution A than the hydronium ion concentration in solution Z?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/ph-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">pH calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="421521" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-11T13:49:16" itemprop="dateCreated"> May 11, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Solution A"#</mathjax> has <mathjax>#"ONE THOUSAND times"#</mathjax> the concentration with respect to <mathjax>#H_3O^+#</mathjax> than <mathjax>#"SOLUTION Z"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>By definition, <mathjax>#pH=-log_10[H_3O^+]#</mathjax>. Why should we use such units? Well, back in the day, BEFORE the advent of cheap electronic calculators, scientists, engineers, and accountants used to use sets of printed logarithmic tables for multiplication and division of very large or very small numbers.......</p> <p>And thus for the product <mathjax>#x xx y#</mathjax>, we could take logs, and get <mathjax>#x xx y=10^(log_10x+log_10y)#</mathjax>, and then take antilogs of this quantity to get the product. Believe it or not, it was easier (and less error prone) to do these sets of operations (which involved standard tables and simple addition and subtraction) than long-handed multiplication. Anyway, I digress again.........</p> <p>And for your problem, since for <mathjax>#A/B#</mathjax>, <mathjax>#[H_3O^+""_A]/[H_3O^+""_B]=10^3#</mathjax>, as <mathjax>#log_10[H_3O^+""_A]-log_10[H_3O^+""_B]=3#</mathjax>. You need to remember the given definition of <mathjax>#pH#</mathjax>, which can be extended to <mathjax>#pOH#</mathjax> (and <mathjax>#pH+pOH=14#</mathjax>, for aqueous solutions), and also to the equilibrium constant <mathjax>#K_a#</mathjax>, with <mathjax>#pK_a=-log_10K_a#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/421521" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-of-a-solution"> How do you determine ph of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-at-an-equivalence-point"> How do you determine pH at an equivalence point? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-molarity"> How do you determine pH from molarity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-alkalinity-mean"> What does alkalinity mean? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-base"> What is a base? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-acid-base-indicators-change-color"> How do acid base indicators change color? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-neutral-ph"> What is a neutral pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-alkalinity-affect-pool-water"> How does alkalinity affect pool water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ph-important-in-drinking-water"> Why is pH important in drinking water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-ph-of-solution"> How can I calculate the pH of a solution? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/ph-calculations"> See all questions in pH calculations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 16341 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Solution A has a pH of 3 and solution Z has a pH of 6. How many times greater is the hydronium ion concentration in solution A than the hydronium ion concentration in solution Z?	null
1,851	a943e2f6-6ddd-11ea-b94d-ccda262736ce	https://socratic.org/questions/how-do-you-calculate-the-final-pressure-of-a-gas-that-is-compressed-from-a-volum	1.6 bar	start physical_unit 9 9 pressure bar qc_end physical_unit 9 9 17 18 volume qc_end physical_unit 9 9 20 21 volume qc_end physical_unit 9 9 25 26 temperature qc_end physical_unit 9 9 28 29 temperature qc_end physical_unit 9 9 35 36 pressure qc_end end	[{"type":"physical unit","value":"Pressure2 [OF] the gas [IN] bar"}]	[{"type":"physical unit","value":"1.6 bar"}]	[{"type":"physical unit","value":"Volume1 [OF] the gas [=] \\pu{20.0 dm^3}"},{"type":"physical unit","value":"Volume2 [OF] the gas [=] \\pu{10.0 dm^3}"},{"type":"physical unit","value":"Temperature1 [OF] the gas [=] \\pu{100 ℃}"},{"type":"physical unit","value":"Temperature2 [OF] the gas [=] \\pu{25 ℃}"},{"type":"physical unit","value":"Pressure1 [OF] the gas [=] \\pu{1 bar}"}]	<h1 class="questionTitle" itemprop="name">How do you calculate the final pressure of a gas that is compressed from a volume of #"20.0 dm"^3# to #"10.0 dm"^3# and cooled from #100^@"C"# to #25^@"C"# if the initial pressure is #"1 bar"# ?</h1>	null	1.6 bar	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your tool of choice here will be the <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">combined gas law</a> equation</strong>, which looks like this </p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)((P_1V_1)/T_1 = (P_2V_2)/T_2)))#</mathjax></p> </blockquote> <p>Here </p> <blockquote> <ul> <li><mathjax>#P_1#</mathjax>, <mathjax>#V_1#</mathjax>, and <mathjax>#T_1#</mathjax> represent the pressure, volume, and temperature of the gas at an initial state</li> <li><mathjax>#P_2#</mathjax>, <mathjax>#V_2#</mathjax>, and <mathjax>#T_2#</mathjax> represent the pressure, volume, and temperature of the gas at a final state</li> </ul> </blockquote> <p>Before doing anything else, make sure that you convert the temperatures from <em>degrees Celsius</em> to <em>Kelvin</em> by using the fact that</p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)(T["K"] = t[""^@"C"] + 273.15)))#</mathjax></p> </blockquote> <p>Now, the idea here is that <strong>decreasing</strong> the volume of the gas will cause the pressure to <strong>increase</strong>. On the other hand, <strong>decreasing</strong> the temperature of the gas will cause its pressure to <strong>decrease</strong>. </p> <p>You can thus say that the change in volume and the change in temperature will "compete" each other, i.e. whichever change is <em>more significant</em> will determine if the pressure increases or decreases. </p> <p>So, rearrange the combined gas law to solve for <mathjax>#P_2#</mathjax></p> <blockquote> <p><mathjax>#(P_1V_1)/T_1 = (P_2V_2)/T_2 implies P_2 = V_1/V_2 * T_2/T_1 * P_1#</mathjax></p> </blockquote> <p>Plug in your values to find</p> <blockquote> <p><mathjax>#P_2 = (20.0 color(red)(cancel(color(black)("dm"^3))))/(10.0color(red)(cancel(color(black)("dm"^3)))) * ((25 + 273.15)color(red)(cancel(color(black)(""^@"C"))))/((100 + 273.15)color(red)(cancel(color(black)(""^@"C")))) * "1 bar"#</mathjax></p> <p><mathjax>#P_2 = 2 * 0.799 * "1 bar" = color(darkgreen)(ul(color(black)("1.6 bar")))#</mathjax></p> </blockquote> <p>I'll leave the answer rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, but keep in mind that you only have one significant figure for the initial pressure of the gas. </p> <p>As you can see, the decrease in volume was <em>more significant</em> than the decrease in temperature; as a result, the pressure of the gas <strong>increased</strong>. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"1.6 bar"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your tool of choice here will be the <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">combined gas law</a> equation</strong>, which looks like this </p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)((P_1V_1)/T_1 = (P_2V_2)/T_2)))#</mathjax></p> </blockquote> <p>Here </p> <blockquote> <ul> <li><mathjax>#P_1#</mathjax>, <mathjax>#V_1#</mathjax>, and <mathjax>#T_1#</mathjax> represent the pressure, volume, and temperature of the gas at an initial state</li> <li><mathjax>#P_2#</mathjax>, <mathjax>#V_2#</mathjax>, and <mathjax>#T_2#</mathjax> represent the pressure, volume, and temperature of the gas at a final state</li> </ul> </blockquote> <p>Before doing anything else, make sure that you convert the temperatures from <em>degrees Celsius</em> to <em>Kelvin</em> by using the fact that</p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)(T["K"] = t[""^@"C"] + 273.15)))#</mathjax></p> </blockquote> <p>Now, the idea here is that <strong>decreasing</strong> the volume of the gas will cause the pressure to <strong>increase</strong>. On the other hand, <strong>decreasing</strong> the temperature of the gas will cause its pressure to <strong>decrease</strong>. </p> <p>You can thus say that the change in volume and the change in temperature will "compete" each other, i.e. whichever change is <em>more significant</em> will determine if the pressure increases or decreases. </p> <p>So, rearrange the combined gas law to solve for <mathjax>#P_2#</mathjax></p> <blockquote> <p><mathjax>#(P_1V_1)/T_1 = (P_2V_2)/T_2 implies P_2 = V_1/V_2 * T_2/T_1 * P_1#</mathjax></p> </blockquote> <p>Plug in your values to find</p> <blockquote> <p><mathjax>#P_2 = (20.0 color(red)(cancel(color(black)("dm"^3))))/(10.0color(red)(cancel(color(black)("dm"^3)))) * ((25 + 273.15)color(red)(cancel(color(black)(""^@"C"))))/((100 + 273.15)color(red)(cancel(color(black)(""^@"C")))) * "1 bar"#</mathjax></p> <p><mathjax>#P_2 = 2 * 0.799 * "1 bar" = color(darkgreen)(ul(color(black)("1.6 bar")))#</mathjax></p> </blockquote> <p>I'll leave the answer rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, but keep in mind that you only have one significant figure for the initial pressure of the gas. </p> <p>As you can see, the decrease in volume was <em>more significant</em> than the decrease in temperature; as a result, the pressure of the gas <strong>increased</strong>. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you calculate the final pressure of a gas that is compressed from a volume of #"20.0 dm"^3# to #"10.0 dm"^3# and cooled from #100^@"C"# to #25^@"C"# if the initial pressure is #"1 bar"# ?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/combined-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Combined Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="384638" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-01T02:16:52" itemprop="dateCreated"> Mar 1, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"1.6 bar"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your tool of choice here will be the <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">combined gas law</a> equation</strong>, which looks like this </p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)((P_1V_1)/T_1 = (P_2V_2)/T_2)))#</mathjax></p> </blockquote> <p>Here </p> <blockquote> <ul> <li><mathjax>#P_1#</mathjax>, <mathjax>#V_1#</mathjax>, and <mathjax>#T_1#</mathjax> represent the pressure, volume, and temperature of the gas at an initial state</li> <li><mathjax>#P_2#</mathjax>, <mathjax>#V_2#</mathjax>, and <mathjax>#T_2#</mathjax> represent the pressure, volume, and temperature of the gas at a final state</li> </ul> </blockquote> <p>Before doing anything else, make sure that you convert the temperatures from <em>degrees Celsius</em> to <em>Kelvin</em> by using the fact that</p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)(T["K"] = t[""^@"C"] + 273.15)))#</mathjax></p> </blockquote> <p>Now, the idea here is that <strong>decreasing</strong> the volume of the gas will cause the pressure to <strong>increase</strong>. On the other hand, <strong>decreasing</strong> the temperature of the gas will cause its pressure to <strong>decrease</strong>. </p> <p>You can thus say that the change in volume and the change in temperature will "compete" each other, i.e. whichever change is <em>more significant</em> will determine if the pressure increases or decreases. </p> <p>So, rearrange the combined gas law to solve for <mathjax>#P_2#</mathjax></p> <blockquote> <p><mathjax>#(P_1V_1)/T_1 = (P_2V_2)/T_2 implies P_2 = V_1/V_2 * T_2/T_1 * P_1#</mathjax></p> </blockquote> <p>Plug in your values to find</p> <blockquote> <p><mathjax>#P_2 = (20.0 color(red)(cancel(color(black)("dm"^3))))/(10.0color(red)(cancel(color(black)("dm"^3)))) * ((25 + 273.15)color(red)(cancel(color(black)(""^@"C"))))/((100 + 273.15)color(red)(cancel(color(black)(""^@"C")))) * "1 bar"#</mathjax></p> <p><mathjax>#P_2 = 2 * 0.799 * "1 bar" = color(darkgreen)(ul(color(black)("1.6 bar")))#</mathjax></p> </blockquote> <p>I'll leave the answer rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, but keep in mind that you only have one significant figure for the initial pressure of the gas. </p> <p>As you can see, the decrease in volume was <em>more significant</em> than the decrease in temperature; as a result, the pressure of the gas <strong>increased</strong>. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/384638" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5345df5f02bf345f71b1c8e8"> Question #1c8e8 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ac3df02bf342f4c3bfabb"> Question #bfabb </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-you-want-to-solve-for-the-volume-of-a-gas-v2-and-p1-is-greater-than-p2-would-"> If you want to solve for the volume of a gas (V2) and P1 is greater than P2, would you expect V2... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-modern-refrigerator-take-advantage-of-the-gas-laws-to-remove-heat-f"> How does the modern refrigerator take advantage of the gas laws to remove heat from a system? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-certain-sample-of-gas-has-a-volume-of-0-452-l-measured-at-87-c-and-0-620-atm-w"> A certain sample of gas has a volume of 0.452 L measured at 87°C and 0.620 atm. 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1,852	aa3833e8-6ddd-11ea-9829-ccda262736ce	https://socratic.org/questions/58d5fc9d7c01495b1d32ec9c	1.00 moles	start physical_unit 9 10 mole mol qc_end physical_unit 9 10 5 6 mass qc_end end	[{"type":"physical unit","value":"Mole [OF] carbon dioxide [IN] moles"}]	[{"type":"physical unit","value":"1.00 moles"}]	[{"type":"physical unit","value":"Mass [OF] carbon dioxide [=] \\pu{44 g}"}]	<h1 class="questionTitle" itemprop="name">How many moles does a #44*g# mass of carbon dioxide represent?</h1>	null	1.00 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Why <mathjax>#"clearly"#</mathjax>, because we get the number of moles of stuff by using the quotient <mathjax>#"mass"/"molar mass"#</mathjax>.</p> <p>Now the molar mass of <mathjax>#"carbon dioxide"#</mathjax> is <mathjax>#12.01gmol^-1+2xx15.999gmol^-1=44.0gmol^-1#</mathjax>. From where did I get the individual atomic molar masses?</p> <p>And thus the quotient: <mathjax>#(44.0g)/(44.0gmol^-1)=1mol#</mathjax>.</p> <p>Now look at the formula, each formula unit of <mathjax>#CO_2#</mathjax> is constituted by one carbon, AND TWO OXYGEN ATOMS. And therefore is we expand the quantities to moles, we SPECIFY PRECISELY <mathjax>#"2 moles of oxygen atoms............."#</mathjax></p> <p>This idea of equivalence, of the use of mass to specify the precise numbers of atoms and molecules that are present is central to the idea of <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>. If you can master this idea, you won't have too much trouble with chemical calculations. Work at it, and a <a href="https://socratic.org/questions/what-is-meant-by-the-term-one-mole-of-molecules">little bit of study will pay off. </a>Good luck. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, a mass <mathjax>#44g#</mathjax> mass of carbon dioxide clearly specifies <mathjax>#"ONE MOLE"#</mathjax> of carbon dioxide.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Why <mathjax>#"clearly"#</mathjax>, because we get the number of moles of stuff by using the quotient <mathjax>#"mass"/"molar mass"#</mathjax>.</p> <p>Now the molar mass of <mathjax>#"carbon dioxide"#</mathjax> is <mathjax>#12.01gmol^-1+2xx15.999gmol^-1=44.0gmol^-1#</mathjax>. From where did I get the individual atomic molar masses?</p> <p>And thus the quotient: <mathjax>#(44.0g)/(44.0gmol^-1)=1*mol#</mathjax>.</p> <p>Now look at the formula, each formula unit of <mathjax>#CO_2#</mathjax> is constituted by one carbon, AND TWO OXYGEN ATOMS. And therefore is we expand the quantities to moles, we SPECIFY PRECISELY <mathjax>#"2 moles of oxygen atoms............."#</mathjax></p> <p>This idea of equivalence, of the use of mass to specify the precise numbers of atoms and molecules that are present is central to the idea of <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>. If you can master this idea, you won't have too much trouble with chemical calculations. Work at it, and a <a href="https://socratic.org/questions/what-is-meant-by-the-term-one-mole-of-molecules">little bit of study will pay off. </a>Good luck. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles does a #44g# mass of carbon dioxide represent?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="396145" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-25T06:42:34" itemprop="dateCreated"> Mar 25, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, a mass <mathjax>#44g#</mathjax> mass of carbon dioxide clearly specifies <mathjax>#"ONE MOLE"#</mathjax> of carbon dioxide.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Why <mathjax>#"clearly"#</mathjax>, because we get the number of moles of stuff by using the quotient <mathjax>#"mass"/"molar mass"#</mathjax>.</p> <p>Now the molar mass of <mathjax>#"carbon dioxide"#</mathjax> is <mathjax>#12.01gmol^-1+2xx15.999gmol^-1=44.0gmol^-1#</mathjax>. From where did I get the individual atomic molar masses?</p> <p>And thus the quotient: <mathjax>#(44.0g)/(44.0gmol^-1)=1mol#</mathjax>.</p> <p>Now look at the formula, each formula unit of <mathjax>#CO_2#</mathjax> is constituted by one carbon, AND TWO OXYGEN ATOMS. And therefore is we expand the quantities to moles, we SPECIFY PRECISELY <mathjax>#"2 moles of oxygen atoms............."#</mathjax></p> <p>This idea of equivalence, of the use of mass to specify the precise numbers of atoms and molecules that are present is central to the idea of <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>. If you can master this idea, you won't have too much trouble with chemical calculations. Work at it, and a <a href="https://socratic.org/questions/what-is-meant-by-the-term-one-mole-of-molecules">little bit of study will pay off. </a>Good luck. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/396145" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 9999 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many moles does a #44*g# mass of carbon dioxide represent?	null
1,853	a87bebd4-6ddd-11ea-92af-ccda262736ce	https://socratic.org/questions/what-is-the-total-number-of-nitrogen-atoms-in-0-25-mole-of-no-2-gas	1.5 × 10^23	start physical_unit 6 7 number none qc_end physical_unit 12 13 9 10 mole qc_end end	[{"type":"physical unit","value":"Total number [OF] nitrogen atoms"}]	[{"type":"physical unit","value":"1.5 × 10^23"}]	[{"type":"physical unit","value":"Mole [OF] NO2 gas [=] \\pu{0.25 mole}"}]	<h1 class="questionTitle" itemprop="name">What is the total number of nitrogen atoms in 0.25 mole of #NO_2# gas?</h1>	null	1.5 × 10^23	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So there are <mathjax>#1/4#</mathjax> <mathjax>#xx#</mathjax> <mathjax>#N_A#</mathjax> nitrogen atoms in such a molar quantity of nitric oxide, approx. <mathjax>#1.5xx10^23#</mathjax> individual nitrogen atoms. How many OXYGEN atoms in such a quantity? </p> <p>Here I use <mathjax>#N_A#</mathjax> as I would use any other collective number: a dozen, a score, a gross. I am perfectly free to do so, because any physical scientist knows precisely what I mean by a <mathjax>#"mole"#</mathjax>. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1#</mathjax> <mathjax>#"mol"#</mathjax> of atoms contains Avogadro's number of atoms. Avogadro's number <mathjax>#=#</mathjax> <mathjax>#N_A#</mathjax> <mathjax>#=#</mathjax> <mathjax>#6.022140857(74)xx10^23#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So there are <mathjax>#1/4#</mathjax> <mathjax>#xx#</mathjax> <mathjax>#N_A#</mathjax> nitrogen atoms in such a molar quantity of nitric oxide, approx. <mathjax>#1.5xx10^23#</mathjax> individual nitrogen atoms. How many OXYGEN atoms in such a quantity? </p> <p>Here I use <mathjax>#N_A#</mathjax> as I would use any other collective number: a dozen, a score, a gross. I am perfectly free to do so, because any physical scientist knows precisely what I mean by a <mathjax>#"mole"#</mathjax>. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the total number of nitrogen atoms in 0.25 mole of #NO_2# gas?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="229144" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-02-21T05:29:45" itemprop="dateCreated"> Feb 21, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1#</mathjax> <mathjax>#"mol"#</mathjax> of atoms contains Avogadro's number of atoms. Avogadro's number <mathjax>#=#</mathjax> <mathjax>#N_A#</mathjax> <mathjax>#=#</mathjax> <mathjax>#6.022140857(74)xx10^23#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So there are <mathjax>#1/4#</mathjax> <mathjax>#xx#</mathjax> <mathjax>#N_A#</mathjax> nitrogen atoms in such a molar quantity of nitric oxide, approx. <mathjax>#1.5xx10^23#</mathjax> individual nitrogen atoms. How many OXYGEN atoms in such a quantity? </p> <p>Here I use <mathjax>#N_A#</mathjax> as I would use any other collective number: a dozen, a score, a gross. I am perfectly free to do so, because any physical scientist knows precisely what I mean by a <mathjax>#"mole"#</mathjax>. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/229144" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What is stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ab82402bf342f48d93ac6"> Question #93ac6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-we-study-stoichiometry"> Why do we study stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-naoh-is-produced-from-1-20-x-102-grams-of-na2o-na2o-h2o-2-naoh"> How many grams of NaOH is produced from #1.20 x 10^2# grams of #Na_2O#? #Na_2O + H_2O -> 2NaOH# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-na2o-are-required-to-produce-1-60-x-102-grams-of-naoh-na2o-h2o"> How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? 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1,854	aa610f36-6ddd-11ea-b146-ccda262736ce	https://socratic.org/questions/a-sample-of-chlorine-gas-has-a-mass-of-39-2-grams-how-many-cl-2-molecules-are-th	3.33 × 10^23	start physical_unit 13 14 number none qc_end end	[{"type":"physical unit","value":"Number [OF] Cl2 molecules"}]	[{"type":"physical unit","value":"3.33 × 10^23"}]	[{"type":"physical unit","value":"Mass [OF] Cl2 gas sample [=] \\pu{39.2 grams}"}]	<h1 class="questionTitle" itemprop="name">A sample of chlorine gas has a mass of 39.2 grams. How many #Cl_2# molecules are there in the sample?</h1>	null	3.33 × 10^23	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This problem is a classic <em><a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a></em> problem. To solve this problem, you want to have your periodic table (to find the molar mass (g/mol) of Cl2), calculator, and <em>Avogadro's number</em> handy. The approach is outlined below:</p> <p><mathjax>#39.2 " g Cl2" ((1 " mole of Cl2")/(70.9 " g Cl2"))((6.022 * 10^23 "molecules Cl2")/(1 " mole Cl2")) = 3.33 * 10^23 " molecules Cl2"#</mathjax>.</p> <p>Hence, the answer is <mathjax>#3.33 * 10^23#</mathjax> molecules of Cl2. Note that <mathjax>#6.022 * 10^23#</mathjax> is also known as <em>Avogadro's number</em>, and it can be referred to as <em>the number of molecules in one mole of that substance</em>. Also, I calculated <mathjax>#70.9#</mathjax> because <mathjax>#35.45 " g/mol"#</mathjax> (the mass of one Chlorine atom) times <mathjax>#2#</mathjax> is <mathjax>#70.9 " g/mol"#</mathjax> (Cl2 has two Chlorine atoms).</p> <p>I hope that helps!</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>See below.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This problem is a classic <em><a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a></em> problem. To solve this problem, you want to have your periodic table (to find the molar mass (g/mol) of Cl2), calculator, and <em>Avogadro's number</em> handy. The approach is outlined below:</p> <p><mathjax>#39.2 " g Cl2" ((1 " mole of Cl2")/(70.9 " g Cl2"))((6.022 * 10^23 "molecules Cl2")/(1 " mole Cl2")) = 3.33 * 10^23 " molecules Cl2"#</mathjax>.</p> <p>Hence, the answer is <mathjax>#3.33 * 10^23#</mathjax> molecules of Cl2. Note that <mathjax>#6.022 * 10^23#</mathjax> is also known as <em>Avogadro's number</em>, and it can be referred to as <em>the number of molecules in one mole of that substance</em>. Also, I calculated <mathjax>#70.9#</mathjax> because <mathjax>#35.45 " g/mol"#</mathjax> (the mass of one Chlorine atom) times <mathjax>#2#</mathjax> is <mathjax>#70.9 " g/mol"#</mathjax> (Cl2 has two Chlorine atoms).</p> <p>I hope that helps!</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A sample of chlorine gas has a mass of 39.2 grams. How many #Cl_2# molecules are there in the sample?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="424115" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ani-6"><img alt="" class="" src="https://profilepictures.socratic.org/KgBnvWxsSOCGP63lfiF1_triangle2.gif" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ani-6"> Anirudh E. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-16T02:16:18" itemprop="dateCreated"> May 16, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>See below.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This problem is a classic <em><a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a></em> problem. To solve this problem, you want to have your periodic table (to find the molar mass (g/mol) of Cl2), calculator, and <em>Avogadro's number</em> handy. The approach is outlined below:</p> <p><mathjax>#39.2 " g Cl2" ((1 " mole of Cl2")/(70.9 " g Cl2"))((6.022 * 10^23 "molecules Cl2")/(1 " mole Cl2")) = 3.33 * 10^23 " molecules Cl2"#</mathjax>.</p> <p>Hence, the answer is <mathjax>#3.33 * 10^23#</mathjax> molecules of Cl2. Note that <mathjax>#6.022 * 10^23#</mathjax> is also known as <em>Avogadro's number</em>, and it can be referred to as <em>the number of molecules in one mole of that substance</em>. Also, I calculated <mathjax>#70.9#</mathjax> because <mathjax>#35.45 " g/mol"#</mathjax> (the mass of one Chlorine atom) times <mathjax>#2#</mathjax> is <mathjax>#70.9 " g/mol"#</mathjax> (Cl2 has two Chlorine atoms).</p> <p>I hope that helps!</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/424115" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="424121" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-16T02:31:40" itemprop="dateCreated"> May 16, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>There are <mathjax>#3.33xx10^23#</mathjax> molecules of <mathjax>#"Cl"_2"#</mathjax> in the sample.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>There are <mathjax>#6.022xx10^23#</mathjax> items in one mole of anything, including molecules. You have to convert the mass of <mathjax>#"Cl"_2"#</mathjax> into moles, then convert the moles into molecules. You do that by multiplying the given mass by the inverse of its molar mass, then multiply the moles by <mathjax>#6.022xx10^23color(white)(.)"molecules"#</mathjax>/mol. The molar mass is the subscript in the formula of <mathjax>#"Cl"_2"#</mathjax> multiplied by the atomic weight of chlorine on the periodic table in grams/mole, or g/mol.</p> <p><strong>Given mass:</strong> <mathjax>#"39.2 g"#</mathjax><br/> <strong>Molar mass:</strong> <mathjax>#(2xx35.45"g/mol")="70.9 g/mol"#</mathjax></p> <p><strong>Determine the moles <mathjax>#"Cl"_2"#</mathjax>.</strong></p> <p><mathjax>#39.2color(red)cancel(color(black)("g Cl"_2))xx(1"mol Cl"_2)/(70.9color(red)cancel(color(black)("g Cl"_2)))+"0.553 mol Cl"_2"#</mathjax></p> <p><strong>Determine molecules of <mathjax>#"Cl"_2"#</mathjax>.</strong></p> <p><mathjax>#0.553color(red)cancel(color(black)("mol Cl"_2))xx(6.022xx10^23"molecules")/(1color(red)cancel(color(black)"mol Cl"_2"))#</mathjax><mathjax>#=#</mathjax><mathjax>#3.33xx10^23color(white)(.)"molecules Cl"_2"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/424121" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 35218 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A sample of chlorine gas has a mass of 39.2 grams. How many #Cl_2# molecules are there in the sample?	null
1,855	a8ff3882-6ddd-11ea-bca8-ccda262736ce	https://socratic.org/questions/lead-nitrate-can-be-decomposed-by-heating-what-is-the-percent-yield-of-the-decom-1	82.44%	start physical_unit 13 15 percent_yield none qc_end physical_unit 20 20 17 18 mass qc_end physical_unit 28 28 25 26 mass qc_end end	[{"type":"physical unit","value":"Percent yield [OF] the decomposition reaction"}]	[{"type":"physical unit","value":"82.44%"}]	[{"type":"physical unit","value":"Mass [OF] Pb(NO3)2 [=] \\pu{9.9 g}"},{"type":"physical unit","value":"Mass [OF] PbO [=] \\pu{5.5 g}"}]	<h1 class="questionTitle" itemprop="name">Lead nitrate can be decomposed by heating. What is the percent yield of the decomposition reaction if 9.9 g of #Pb(NO_3)_2#are heated to give 5.5 g of #PbO#??</h1>	null	82.44%	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We need (i) a stoichiometric equation........</p> <p><mathjax>#Pb(NO_3)_2 +Delta rarr PbO(s)+2NO_2(g)+1/2O_2(g)#</mathjax></p> <p>This simply must be known; nitrates undergo thermal decomposition to give oxide and nitric oxide and dioxygen gas.</p> <p>And (ii). given the 1:1 <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> between nitrate and oxide, we needs equivalent quantities of lead oxide and lead nitrate:</p> <p><mathjax>#"Percentage yield"="Moles of lead oxide"/"Moles of lead nitrate"xx100%=#</mathjax></p> <p><mathjax>#((5.5g)/(223.2gmol^-1))/((9.9g)/(331.2gmol^-1))xx100%=??%#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Percentage yield"~=80%#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We need (i) a stoichiometric equation........</p> <p><mathjax>#Pb(NO_3)_2 +Delta rarr PbO(s)+2NO_2(g)+1/2O_2(g)#</mathjax></p> <p>This simply must be known; nitrates undergo thermal decomposition to give oxide and nitric oxide and dioxygen gas.</p> <p>And (ii). given the 1:1 <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> between nitrate and oxide, we needs equivalent quantities of lead oxide and lead nitrate:</p> <p><mathjax>#"Percentage yield"="Moles of lead oxide"/"Moles of lead nitrate"xx100%=#</mathjax></p> <p><mathjax>#((5.5g)/(223.2gmol^-1))/((9.9g)/(331.2gmol^-1))xx100%=??%#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Lead nitrate can be decomposed by heating. What is the percent yield of the decomposition reaction if 9.9 g of #Pb(NO_3)_2#are heated to give 5.5 g of #PbO#??</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/decomposition-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Decomposition Reactions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="432352" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-31T04:28:09" itemprop="dateCreated"> May 31, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Percentage yield"~=80%#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We need (i) a stoichiometric equation........</p> <p><mathjax>#Pb(NO_3)_2 +Delta rarr PbO(s)+2NO_2(g)+1/2O_2(g)#</mathjax></p> <p>This simply must be known; nitrates undergo thermal decomposition to give oxide and nitric oxide and dioxygen gas.</p> <p>And (ii). given the 1:1 <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> between nitrate and oxide, we needs equivalent quantities of lead oxide and lead nitrate:</p> <p><mathjax>#"Percentage yield"="Moles of lead oxide"/"Moles of lead nitrate"xx100%=#</mathjax></p> <p><mathjax>#((5.5g)/(223.2gmol^-1))/((9.9g)/(331.2gmol^-1))xx100%=??%#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/432352" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-decomposition-reactions"> What are decomposition reactions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-examples-of-decomposition-reactions"> What are some examples of decomposition reactions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-a-decomposition-reaction-be-recognized"> How can a decomposition reaction be recognized? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-a-decomposition-reaction-differ-from-other-types-of-reactions"> How does a decomposition reaction differ from other types of reactions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-double-decomposition-reactions"> What are double decomposition reactions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-decomposition-reactions"> How can I balance decomposition reactions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-thermal-decomposition-reactions"> What are thermal decomposition reactions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/do-decomposition-reactions-require-energy"> Do decomposition reactions require energy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-mass-spectrometry-relate-to-decomposition"> How does mass spectrometry relate to decomposition? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/do-chlorates-decompose-when-heated"> Do chlorates decompose when heated? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/decomposition-reactions"> See all questions in Decomposition Reactions </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 16721 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Lead nitrate can be decomposed by heating. What is the percent yield of the decomposition reaction if 9.9 g of #Pb(NO_3)_2#are heated to give 5.5 g of #PbO#??	null
1,856	aa175fda-6ddd-11ea-975c-ccda262736ce	https://socratic.org/questions/calculate-the-mole-fraction-of-methanol-in-the-vapor-phase-at-63-5-c-for-an-idea	0.46	start physical_unit 5 9 mole_fraction none qc_end physical_unit 15 16 11 12 temperature qc_end physical_unit 21 22 18 19 mass qc_end physical_unit 27 28 24 25 mass qc_end physical_unit 5 5 38 39 molar_mass qc_end physical_unit 5 5 43 44 vapor_pressure qc_end physical_unit 28 28 48 49 molar_mass qc_end physical_unit 28 28 53 54 vapor_pressure qc_end end	[{"type":"physical unit","value":"Mole fraction [OF] methanol in the vapor phase"}]	[{"type":"physical unit","value":"0.46"}]	[{"type":"physical unit","value":"Temperature [OF] the ideal solution [=] \\pu{63.5 ℃}"},{"type":"physical unit","value":"Mass [OF] pure methanol [=] \\pu{25.0 g}"},{"type":"physical unit","value":"Mass [OF] pure ethanol [=] \\pu{75.0 g}"},{"type":"physical unit","value":"MM [OF] methanol [=] \\pu{32.0 g/mol}"},{"type":"physical unit","value":"Vapor pressure [OF] methanol [=] \\pu{717.2 torr}"},{"type":"physical unit","value":"MM [OF] ethanol [=] \\pu{46.1 g/mol}"},{"type":"physical unit","value":"Vapor pressure [OF] ethanol [=] \\pu{400.0 torr}"}]	<h1 class="questionTitle" itemprop="name">Calculate the mole fraction of methanol in the vapor phase at #63.5°C# for an ideal solution containing #25.0g# of pure methanol and #75.0g# of pure ethanol?</h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>Some data necessary to solve this:</p> <p>Methanol <mathjax>#MM = (32.0g)/(mol)#</mathjax><br/> Vapor pressure <mathjax>#=717.2t o rr#</mathjax></p> <p>Ethanol: <mathjax>#MM = (46.1g)/(mol)#</mathjax><br/> Vapor pressure <mathjax>#=400.0t o rr#</mathjax></p> <p>Thank you!</p></div> </h2> </div> </div>	0.46	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your tool of choice here will be <strong>Raoult's Law</strong>, which states that at a given temperature, the vapor pressure of a <em>volatile</em> component in an <em>ideal mixture</em> is equal to the <strong>mole fraction</strong> of the component in the mixture multiplied by the vapor pressure of the <strong>pure component</strong>.</p> <p>This basically means that for an ideal mixture, the number of moles of each component of the mixture <strong>present in the solution</strong> will determine the vapor pressure of the component <em>above the solution</em>.</p> <p>In your case, the <strong>solution</strong> contains</p> <blockquote> <p><mathjax>#25.0 color(red)(cancel(color(black)("g"))) * "1 mole MetOH"/(32.0color(red)(cancel(color(black)("g")))) = "0.78125 moles MetOH"#</mathjax></p> <p><mathjax>#75.0color(red)(cancel(color(black)("g"))) * "1 mole EtOH"/(46.1color(red)(cancel(color(black)("g")))) = "1.6269 moles EtOH"#</mathjax></p> </blockquote> <p>The <strong>total number of moles</strong> present in the solution is equal to</p> <blockquote> <p><mathjax>#"0.78125 moles + 1.6269 moles = 2.40815 moles"#</mathjax></p> </blockquote> <p>Now, according to Raoult's Law, the <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/partial-pressure">partial pressure</a></strong> of methanol above this solution, <mathjax>#P_"MetOH"#</mathjax>, is given by </p> <blockquote> <p><mathjax>#P_"MetOH" = chi_ "MetOH" * P_"MetOH"^@#</mathjax></p> </blockquote> <p>Here</p> <blockquote> <ul> <li><mathjax>#chi_"MetOH"#</mathjax> is the <strong>mole fraction</strong> of methanol in the mixture</li> <li><mathjax>#P_"MetOH"^@#</mathjax> is the vapor pressure of <em>pure methanol</em> at <mathjax>#63.5^@"C"#</mathjax></li> </ul> </blockquote> <p>The <strong>mole fraction</strong> of methanol in the solution is equal to </p> <blockquote> <p><mathjax>#chi_"MetOH" = (0.78125 color(red)(cancel(color(black)("moles"))))/(2.40815 color(red)(cancel(color(black)("moles")))) = 0.3244#</mathjax></p> </blockquote> <p>The <strong>partial pressure</strong> of methanol above the solution is equal to</p> <blockquote> <p><mathjax>#P_"MetOH" = 0.3244 * "717.2 torr"#</mathjax></p> <p><mathjax>#P_"MetOH" = "232.66 torr"#</mathjax></p> </blockquote> <p>Next, use the same approach to find the <strong>partial pressure</strong> of ethanol above the solution. </p> <blockquote> <p><mathjax>#chi_"EtOH" = (1.6269 color(red)(cancel(color(black)("moles"))))/(2.40815color(red)(cancel(color(black)("moles")))) = 0.6756#</mathjax></p> </blockquote> <p>You will have</p> <blockquote> <p><mathjax>#P_"EtOH" = 0.6756 * "400.0 torr"#</mathjax></p> <p><mathjax>#P_"EtOH" = "270.24 torr"#</mathjax></p> </blockquote> <p>Now, the <strong>total pressure</strong> above the solution is equal to</p> <blockquote> <p><mathjax>#P_"total" = P_"MetOH" + P_"EtOH"#</mathjax></p> <p><mathjax>#P_"total" = "232.66 torr + 270.24 torr"#</mathjax></p> <p><mathjax>#P_"total" = "502.9 torr"#</mathjax></p> </blockquote> <p>In order to find the <strong>mole fraction</strong> of methanol <strong>in the vapor phase</strong>, i.e. above the solution, use the fact that the partial pressure of methanol <em>above the solution</em> is equal to <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> fraction of methanol <em>above the solution</em> multiplied by the <strong>total pressure</strong> <em>above the solution</em>. </p> <blockquote> <p><mathjax>#P_"MetOH" = chi_"MetOH vapor" * P_"total"#</mathjax></p> </blockquote> <p>This means that you have</p> <blockquote> <p><mathjax>#chi_"MetOH vapor" = (232.66 color(red)(cancel(color(black)("torr"))))/(502.9color(red)(cancel(color(black)("torr")))) = color(darkgreen)(ul(color(black)(0.463)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#0.463#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your tool of choice here will be <strong>Raoult's Law</strong>, which states that at a given temperature, the vapor pressure of a <em>volatile</em> component in an <em>ideal mixture</em> is equal to the <strong>mole fraction</strong> of the component in the mixture multiplied by the vapor pressure of the <strong>pure component</strong>.</p> <p>This basically means that for an ideal mixture, the number of moles of each component of the mixture <strong>present in the solution</strong> will determine the vapor pressure of the component <em>above the solution</em>.</p> <p>In your case, the <strong>solution</strong> contains</p> <blockquote> <p><mathjax>#25.0 color(red)(cancel(color(black)("g"))) * "1 mole MetOH"/(32.0color(red)(cancel(color(black)("g")))) = "0.78125 moles MetOH"#</mathjax></p> <p><mathjax>#75.0color(red)(cancel(color(black)("g"))) * "1 mole EtOH"/(46.1color(red)(cancel(color(black)("g")))) = "1.6269 moles EtOH"#</mathjax></p> </blockquote> <p>The <strong>total number of moles</strong> present in the solution is equal to</p> <blockquote> <p><mathjax>#"0.78125 moles + 1.6269 moles = 2.40815 moles"#</mathjax></p> </blockquote> <p>Now, according to Raoult's Law, the <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/partial-pressure">partial pressure</a></strong> of methanol above this solution, <mathjax>#P_"MetOH"#</mathjax>, is given by </p> <blockquote> <p><mathjax>#P_"MetOH" = chi_ "MetOH" * P_"MetOH"^@#</mathjax></p> </blockquote> <p>Here</p> <blockquote> <ul> <li><mathjax>#chi_"MetOH"#</mathjax> is the <strong>mole fraction</strong> of methanol in the mixture</li> <li><mathjax>#P_"MetOH"^@#</mathjax> is the vapor pressure of <em>pure methanol</em> at <mathjax>#63.5^@"C"#</mathjax></li> </ul> </blockquote> <p>The <strong>mole fraction</strong> of methanol in the solution is equal to </p> <blockquote> <p><mathjax>#chi_"MetOH" = (0.78125 color(red)(cancel(color(black)("moles"))))/(2.40815 color(red)(cancel(color(black)("moles")))) = 0.3244#</mathjax></p> </blockquote> <p>The <strong>partial pressure</strong> of methanol above the solution is equal to</p> <blockquote> <p><mathjax>#P_"MetOH" = 0.3244 * "717.2 torr"#</mathjax></p> <p><mathjax>#P_"MetOH" = "232.66 torr"#</mathjax></p> </blockquote> <p>Next, use the same approach to find the <strong>partial pressure</strong> of ethanol above the solution. </p> <blockquote> <p><mathjax>#chi_"EtOH" = (1.6269 color(red)(cancel(color(black)("moles"))))/(2.40815color(red)(cancel(color(black)("moles")))) = 0.6756#</mathjax></p> </blockquote> <p>You will have</p> <blockquote> <p><mathjax>#P_"EtOH" = 0.6756 * "400.0 torr"#</mathjax></p> <p><mathjax>#P_"EtOH" = "270.24 torr"#</mathjax></p> </blockquote> <p>Now, the <strong>total pressure</strong> above the solution is equal to</p> <blockquote> <p><mathjax>#P_"total" = P_"MetOH" + P_"EtOH"#</mathjax></p> <p><mathjax>#P_"total" = "232.66 torr + 270.24 torr"#</mathjax></p> <p><mathjax>#P_"total" = "502.9 torr"#</mathjax></p> </blockquote> <p>In order to find the <strong>mole fraction</strong> of methanol <strong>in the vapor phase</strong>, i.e. above the solution, use the fact that the partial pressure of methanol <em>above the solution</em> is equal to <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> fraction of methanol <em>above the solution</em> multiplied by the <strong>total pressure</strong> <em>above the solution</em>. </p> <blockquote> <p><mathjax>#P_"MetOH" = chi_"MetOH vapor" * P_"total"#</mathjax></p> </blockquote> <p>This means that you have</p> <blockquote> <p><mathjax>#chi_"MetOH vapor" = (232.66 color(red)(cancel(color(black)("torr"))))/(502.9color(red)(cancel(color(black)("torr")))) = color(darkgreen)(ul(color(black)(0.463)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Calculate the mole fraction of methanol in the vapor phase at #63.5°C# for an ideal solution containing #25.0g# of pure methanol and #75.0g# of pure ethanol?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>Some data necessary to solve this:</p> <p>Methanol <mathjax>#MM = (32.0g)/(mol)#</mathjax><br/> Vapor pressure <mathjax>#=717.2t o rr#</mathjax></p> <p>Ethanol: <mathjax>#MM = (46.1g)/(mol)#</mathjax><br/> Vapor pressure <mathjax>#=400.0t o rr#</mathjax></p> <p>Thank you!</p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/partial-pressure" itemprop="url"> <span class="breadcrumb" itemprop="title">Partial Pressure</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="476153" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-09-16T13:10:46" itemprop="dateCreated"> Sep 16, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#0.463#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your tool of choice here will be <strong>Raoult's Law</strong>, which states that at a given temperature, the vapor pressure of a <em>volatile</em> component in an <em>ideal mixture</em> is equal to the <strong>mole fraction</strong> of the component in the mixture multiplied by the vapor pressure of the <strong>pure component</strong>.</p> <p>This basically means that for an ideal mixture, the number of moles of each component of the mixture <strong>present in the solution</strong> will determine the vapor pressure of the component <em>above the solution</em>.</p> <p>In your case, the <strong>solution</strong> contains</p> <blockquote> <p><mathjax>#25.0 color(red)(cancel(color(black)("g"))) * "1 mole MetOH"/(32.0color(red)(cancel(color(black)("g")))) = "0.78125 moles MetOH"#</mathjax></p> <p><mathjax>#75.0color(red)(cancel(color(black)("g"))) * "1 mole EtOH"/(46.1color(red)(cancel(color(black)("g")))) = "1.6269 moles EtOH"#</mathjax></p> </blockquote> <p>The <strong>total number of moles</strong> present in the solution is equal to</p> <blockquote> <p><mathjax>#"0.78125 moles + 1.6269 moles = 2.40815 moles"#</mathjax></p> </blockquote> <p>Now, according to Raoult's Law, the <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/partial-pressure">partial pressure</a></strong> of methanol above this solution, <mathjax>#P_"MetOH"#</mathjax>, is given by </p> <blockquote> <p><mathjax>#P_"MetOH" = chi_ "MetOH" * P_"MetOH"^@#</mathjax></p> </blockquote> <p>Here</p> <blockquote> <ul> <li><mathjax>#chi_"MetOH"#</mathjax> is the <strong>mole fraction</strong> of methanol in the mixture</li> <li><mathjax>#P_"MetOH"^@#</mathjax> is the vapor pressure of <em>pure methanol</em> at <mathjax>#63.5^@"C"#</mathjax></li> </ul> </blockquote> <p>The <strong>mole fraction</strong> of methanol in the solution is equal to </p> <blockquote> <p><mathjax>#chi_"MetOH" = (0.78125 color(red)(cancel(color(black)("moles"))))/(2.40815 color(red)(cancel(color(black)("moles")))) = 0.3244#</mathjax></p> </blockquote> <p>The <strong>partial pressure</strong> of methanol above the solution is equal to</p> <blockquote> <p><mathjax>#P_"MetOH" = 0.3244 * "717.2 torr"#</mathjax></p> <p><mathjax>#P_"MetOH" = "232.66 torr"#</mathjax></p> </blockquote> <p>Next, use the same approach to find the <strong>partial pressure</strong> of ethanol above the solution. </p> <blockquote> <p><mathjax>#chi_"EtOH" = (1.6269 color(red)(cancel(color(black)("moles"))))/(2.40815color(red)(cancel(color(black)("moles")))) = 0.6756#</mathjax></p> </blockquote> <p>You will have</p> <blockquote> <p><mathjax>#P_"EtOH" = 0.6756 * "400.0 torr"#</mathjax></p> <p><mathjax>#P_"EtOH" = "270.24 torr"#</mathjax></p> </blockquote> <p>Now, the <strong>total pressure</strong> above the solution is equal to</p> <blockquote> <p><mathjax>#P_"total" = P_"MetOH" + P_"EtOH"#</mathjax></p> <p><mathjax>#P_"total" = "232.66 torr + 270.24 torr"#</mathjax></p> <p><mathjax>#P_"total" = "502.9 torr"#</mathjax></p> </blockquote> <p>In order to find the <strong>mole fraction</strong> of methanol <strong>in the vapor phase</strong>, i.e. above the solution, use the fact that the partial pressure of methanol <em>above the solution</em> is equal to <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> fraction of methanol <em>above the solution</em> multiplied by the <strong>total pressure</strong> <em>above the solution</em>. </p> <blockquote> <p><mathjax>#P_"MetOH" = chi_"MetOH vapor" * P_"total"#</mathjax></p> </blockquote> <p>This means that you have</p> <blockquote> <p><mathjax>#chi_"MetOH vapor" = (232.66 color(red)(cancel(color(black)("torr"))))/(502.9color(red)(cancel(color(black)("torr")))) = color(darkgreen)(ul(color(black)(0.463)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/476153" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div 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Some data necessary to solve this: Methanol #MM = (32.0g)/(mol)# Vapor pressure #=717.2t o rr# Ethanol: #MM = (46.1g)/(mol)# Vapor pressure #=400.0t o rr# Thank you!
1,857	ac95029b-6ddd-11ea-b164-ccda262736ce	https://socratic.org/questions/a-weather-balloon-is-filled-with-1000-mol-of-he-gas-at-25-o-c-and-101-kpa-of-pre	24.47 m^3	start physical_unit 24 26 volume m^3 qc_end physical_unit 9 10 6 7 mole qc_end physical_unit 9 10 12 13 temperature qc_end physical_unit 9 10 15 16 pressure qc_end end	[{"type":"physical unit","value":"Volume [OF] the weather balloon [IN] m^3"}]	[{"type":"physical unit","value":"24.47 m^3"}]	[{"type":"physical unit","value":"Mole [OF] He gas [=] \\pu{1000 mol}"},{"type":"physical unit","value":"Temperature [OF] He gas [=] \\pu{25 ℃}"},{"type":"physical unit","value":"Pressure [OF] He gas [=] \\pu{101 kPa}"}]	<h1 class="questionTitle" itemprop="name">A weather balloon is filled with 1000 mol of He gas at #25"^o#C and 101 kPa of pressure. What is the volume of the weather balloon?</h1>	null	24.47 m^3	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#V=(10^3molxx0.0821LatmK^-1mol^-1xx298K)/(1atm)#</mathjax></p> <p>Note that <mathjax>#101kPa~=1atm#</mathjax></p> <p>We get <mathjax>#V=24.4xx10^3L=24.4m^3#</mathjax>. </p> <p>What is the mass of the gas inside the balloon? Will it float in air?</p> <p>This problem reminds me of an old story, that of <a href="https://en.wikipedia.org/wiki/Larry_Walters" rel="nofollow">Lawnchair Larry</a>, who luckily survived the experience. Many Darwin award winners don't! </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#V=(nRT)/P~=25m^3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#V=(10^3molxx0.0821LatmK^-1mol^-1xx298K)/(1atm)#</mathjax></p> <p>Note that <mathjax>#101kPa~=1atm#</mathjax></p> <p>We get <mathjax>#V=24.4xx10^3L=24.4*m^3#</mathjax>. </p> <p>What is the mass of the gas inside the balloon? Will it float in air?</p> <p>This problem reminds me of an old story, that of <a href="https://en.wikipedia.org/wiki/Larry_Walters" rel="nofollow">Lawnchair Larry</a>, who luckily survived the experience. Many Darwin award winners don't! </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A weather balloon is filled with 1000 mol of He gas at #25"^o#C and 101 kPa of pressure. What is the volume of the weather balloon?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp" itemprop="url"> <span class="breadcrumb" itemprop="title">Molar Volume of a Gas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="343367" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-11-28T20:36:54" itemprop="dateCreated"> Nov 28, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#V=(nRT)/P~=25m^3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#V=(10^3molxx0.0821LatmK^-1mol^-1xx298K)/(1atm)#</mathjax></p> <p>Note that <mathjax>#101kPa~=1atm#</mathjax></p> <p>We get <mathjax>#V=24.4xx10^3L=24.4*m^3#</mathjax>. </p> <p>What is the mass of the gas inside the balloon? Will it float in air?</p> <p>This problem reminds me of an old story, that of <a href="https://en.wikipedia.org/wiki/Larry_Walters" rel="nofollow">Lawnchair Larry</a>, who luckily survived the experience. Many Darwin award winners don't! </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/343367" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-stoichiometric-ratios-relate-to-molar-volume-of-a-gas"> How do stoichiometric ratios relate to molar volume of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-a-gas-at-stp"> How do you calculate molar volume of a gas at STP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-molar-volume-of-hydrogen-gas"> How do you find the molar volume of hydrogen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-oxygen-gas"> How do you calculate molar volume of oxygen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molar-gas-volume"> What is molar gas volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/534c7bf202bf3420a007f014"> What is the volume at 0 °C and 1 atm of a mixture that contains 4.0 g of methane and 2.0 g of helium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5361f75702bf3429040e0599"> What is the difference between STP and NTP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-volume-of-25-moles-of-oxygen-o2-gas"> What is the volume of .25 moles of oxygen (O2) Gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-would-knowing-the-molar-volume-of-a-gas-be-important"> Why would knowing the molar volume of a gas be important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-22-4-liters-called-the-molar-volume-of-a-gas"> Why is 22.4 liters called the molar volume of a gas? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp"> See all questions in Molar Volume of a Gas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2422 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A weather balloon is filled with 1000 mol of He gas at #25"^o#C and 101 kPa of pressure. What is the volume of the weather balloon?	null
1,858	a94fa636-6ddd-11ea-8384-ccda262736ce	https://socratic.org/questions/59527950b72cff6f71c8b56e	1.21 × 10^(-9) g	start physical_unit 11 11 mass g qc_end end	[{"type":"physical unit","value":"Mass [OF] PCl3 [IN] g"}]	[{"type":"physical unit","value":"1.21 × 10^(-9) g"}]	[{"type":"physical unit","value":"Number [OF] PCl3 molecules [=] \\pu{5.306 × 10^12}"}]	<h1 class="questionTitle" itemprop="name">What is the mass of #5.306xx10^12# individual molecules of #PCl_3#?</h1>	null	1.21 × 10^(-9) g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Mass"="Molar quantity"xx"molar mass"=#</mathjax></p> <p><mathjax>#(5.306xx10^12"molecules"xx137.33gmol^-1)/(6.022xx10^23"molecules"mol^-1)#</mathjax></p> <p><mathjax>#=1"ng"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well for <mathjax>#5.306xx10^12#</mathjax> <mathjax>#"molecules"#</mathjax> of <mathjax>#PCl_3#</mathjax>, we gots a <mathjax>#"nanogram"#</mathjax> mass. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Mass"="Molar quantity"xx"molar mass"=#</mathjax></p> <p><mathjax>#(5.306xx10^12"molecules"xx137.33gmol^-1)/(6.022xx10^23"molecules"mol^-1)#</mathjax></p> <p><mathjax>#=1"ng"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the mass of #5.306xx10^12# individual molecules of #PCl_3#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="445019" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-27T15:55:53" itemprop="dateCreated"> Jun 27, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well for <mathjax>#5.306xx10^12#</mathjax> <mathjax>#"molecules"#</mathjax> of <mathjax>#PCl_3#</mathjax>, we gots a <mathjax>#"nanogram"#</mathjax> mass. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Mass"="Molar quantity"xx"molar mass"=#</mathjax></p> <p><mathjax>#(5.306xx10^12"molecules"xx137.33gmol^-1)/(6.022xx10^23"molecules"mol^-1)#</mathjax></p> <p><mathjax>#=1"ng"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/445019" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? 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1,859	aaf63047-6ddd-11ea-88a6-ccda262736ce	https://socratic.org/questions/what-is-the-percent-by-mass-of-oxygen-in-h-2so-4	65.3%	start physical_unit 7 9 mass_percent none qc_end chemical_equation 9 9 qc_end end	[{"type":"physical unit","value":"Percent by mass [OF] oxygen in H2SO4"}]	[{"type":"physical unit","value":"65.3%"}]	[{"type":"chemical equation","value":"H2SO4"}]	<h1 class="questionTitle" itemprop="name">What is the percent by mass of oxygen in #H_2SO_4#?</h1>	null	65.3%	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Molar mass of <mathjax>#H_2SO_4=2xx1+32+4xx16=98#</mathjax><br/> so percantage of oxygen <mathjax>#=64/98xx100=65.3#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#=65.3%#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Molar mass of <mathjax>#H_2SO_4=2xx1+32+4xx16=98#</mathjax><br/> so percantage of oxygen <mathjax>#=64/98xx100=65.3#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the percent by mass of oxygen in #H_2SO_4#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/percent-composition" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Composition</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="244464" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/dk-ch"><img alt="" class="" src="https://profilepictures.socratic.org/0aBlt69MSiWhfD1SEqb8_lotus.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/dk-ch"> P dilip_k </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-24T15:20:41" itemprop="dateCreated"> Mar 24, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#=65.3%#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Molar mass of <mathjax>#H_2SO_4=2xx1+32+4xx16=98#</mathjax><br/> so percantage of oxygen <mathjax>#=64/98xx100=65.3#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/244464" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-mole-percent"> What is mole percent? 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1,860	ac2b6e2d-6ddd-11ea-b0b5-ccda262736ce	https://socratic.org/questions/how-do-you-balance-the-following-reaction-in-acidic-solution-mno-4-aq-h-2c-2o-4-	2 MnO4-(aq) + 5 H2C2O4(aq)+ 6 H+(aq) -> 2 Mn^2+(aq) + 10 CO2(g) + 8 H2O(l)	start chemical_equation qc_end chemical_equation 10 16 qc_end c_other OTHER qc_end end	[{"type":"other","value":"Chemical Equation [OF] the reaction"}]	[{"type":"chemical equation","value":"2 MnO4-(aq) + 5 H2C2O4(aq)+ 6 H+(aq) -> 2 Mn^2+(aq) + 10 CO2(g) + 8 H2O(l)"}]	[{"type":"chemical equation","value":"MnO4-(aq) + H2C2O4(aq) -> Mn^2+(aq) + CO2(g)"},{"type":"other","value":"Acidic solution."}]	<h1 class="questionTitle" itemprop="name">How do you balance the following reaction in acidic solution #MnO_4^-(aq) + H_2C_2O_4(aq) -> Mn^(2+)(aq) + CO_2(g)#?</h1>	null	2 MnO4-(aq) + 5 H2C2O4(aq)+ 6 H+(aq) -> 2 Mn^2+(aq) + 10 CO2(g) + 8 H2O(l)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First off, you need to recognize this reaction as a REDOX reaction.</p> <p>Then split the equation into its separate half-reactions.</p> <p><mathjax>#MnO_(4)^(-)(aq)rarrMn^(2+)(aq)#</mathjax><br/> <mathjax>#H_2C_2O_4(aq)rarrCO_2(g)#</mathjax></p> <p>Balance everything except the oxygen and hydrogen.</p> <p><mathjax>#MnO_(4)^(-)(aq)rarrMn^(2+)(aq)#</mathjax><br/> <mathjax>#H_2C_2O_4(aq)rarr2CO_2(g)#</mathjax></p> <p>Now balance the oxygen by adding <mathjax>#H_2O(l)#</mathjax>.</p> <p><mathjax>#MnO_(4)^(-)(aq)rarrMn^(2+)(aq)+4H_2O(l)#</mathjax><br/> <mathjax>#H_2C_2O_4(aq)rarr2CO_2(g)#</mathjax></p> <p>Since this is in an acidic solution, the hydrogen can be balanced by adding <mathjax>#H^(+)(aq)#</mathjax>.</p> <p><mathjax>#MnO_(4)^(-)(aq)+8H^+(aq)rarrMn^(2+)(aq)+4H_2O(l)#</mathjax><br/> <mathjax>#H_2C_2O_4(aq)rarr2CO_2(g)+2H^+(aq)#</mathjax></p> <p>Add electrons (<mathjax>#e^-#</mathjax>) in order to balance the overall charge of the two sides of either half-reaction.</p> <p><mathjax>#MnO_(4)^(-)(aq)+8H^+(aq)+5e^(-)rarrMn^(2+)(aq)+4H_2O(l)#</mathjax><br/> <mathjax>#H_2C_2O_4(aq)rarr2CO_2(g)+2H^+(aq)+2e^-#</mathjax></p> <p>Multiply each half-reaction by an integer that will allow the electrons in each half-reaction to cancel out when the half-reactions are added.</p> <p><mathjax>#2MnO_(4)^(-)(aq)+16H^+(aq)+10e^(-)rarr2Mn^(2+)(aq)+8H_2O(l)#</mathjax><br/> <mathjax>#5H_2C_2O_4(aq)rarr10CO_2(g)+10H^+(aq)+10e^-#</mathjax></p> <p>Finally, add the two half-reactions and simplify.</p> <p><mathjax>#2MnO_(4)^(-)(aq)+16H^+(aq)+10e^(-)+5H_2C_2O_4(aq)rarr2Mn^(2+)(aq)+8H_2O+10CO_2(g)+10H^+(aq)+10e^-#</mathjax></p> <p><mathjax>#2MnO_(4)^(-)(aq) + 6cancel(16)H^+(aq) + cancel(10e^(-)) + 5H_2C_2O_4(aq) rarr 2Mn^(2+)(aq) + 8H_2O(l) + 10CO_2(g) + cancel(10H^+(aq)) + cancel(10e^-)#</mathjax></p> <p><mathjax>#2MnO_(4)^(-)(aq) + 5H_2C_2O_4(aq) + 6H^+(aq) rarr 2Mn^(2+)(aq) + 10CO_2(g) + 8H_2O(l)#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2MnO_(4)^(-)(aq) + 5H_2C_2O_4(aq) + 6H^+(aq) rarr 2Mn^(2+)(aq) + 10CO_2(g) + 8H_2O(l)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First off, you need to recognize this reaction as a REDOX reaction.</p> <p>Then split the equation into its separate half-reactions.</p> <p><mathjax>#MnO_(4)^(-)(aq)rarrMn^(2+)(aq)#</mathjax><br/> <mathjax>#H_2C_2O_4(aq)rarrCO_2(g)#</mathjax></p> <p>Balance everything except the oxygen and hydrogen.</p> <p><mathjax>#MnO_(4)^(-)(aq)rarrMn^(2+)(aq)#</mathjax><br/> <mathjax>#H_2C_2O_4(aq)rarr2CO_2(g)#</mathjax></p> <p>Now balance the oxygen by adding <mathjax>#H_2O(l)#</mathjax>.</p> <p><mathjax>#MnO_(4)^(-)(aq)rarrMn^(2+)(aq)+4H_2O(l)#</mathjax><br/> <mathjax>#H_2C_2O_4(aq)rarr2CO_2(g)#</mathjax></p> <p>Since this is in an acidic solution, the hydrogen can be balanced by adding <mathjax>#H^(+)(aq)#</mathjax>.</p> <p><mathjax>#MnO_(4)^(-)(aq)+8H^+(aq)rarrMn^(2+)(aq)+4H_2O(l)#</mathjax><br/> <mathjax>#H_2C_2O_4(aq)rarr2CO_2(g)+2H^+(aq)#</mathjax></p> <p>Add electrons (<mathjax>#e^-#</mathjax>) in order to balance the overall charge of the two sides of either half-reaction.</p> <p><mathjax>#MnO_(4)^(-)(aq)+8H^+(aq)+5e^(-)rarrMn^(2+)(aq)+4H_2O(l)#</mathjax><br/> <mathjax>#H_2C_2O_4(aq)rarr2CO_2(g)+2H^+(aq)+2e^-#</mathjax></p> <p>Multiply each half-reaction by an integer that will allow the electrons in each half-reaction to cancel out when the half-reactions are added.</p> <p><mathjax>#2MnO_(4)^(-)(aq)+16H^+(aq)+10e^(-)rarr2Mn^(2+)(aq)+8H_2O(l)#</mathjax><br/> <mathjax>#5H_2C_2O_4(aq)rarr10CO_2(g)+10H^+(aq)+10e^-#</mathjax></p> <p>Finally, add the two half-reactions and simplify.</p> <p><mathjax>#2MnO_(4)^(-)(aq)+16H^+(aq)+10e^(-)+5H_2C_2O_4(aq)rarr2Mn^(2+)(aq)+8H_2O+10CO_2(g)+10H^+(aq)+10e^-#</mathjax></p> <p><mathjax>#2MnO_(4)^(-)(aq) + 6cancel(16)H^+(aq) + cancel(10e^(-)) + 5H_2C_2O_4(aq) rarr 2Mn^(2+)(aq) + 8H_2O(l) + 10CO_2(g) + cancel(10H^+(aq)) + cancel(10e^-)#</mathjax></p> <p><mathjax>#2MnO_(4)^(-)(aq) + 5H_2C_2O_4(aq) + 6H^+(aq) rarr 2Mn^(2+)(aq) + 10CO_2(g) + 8H_2O(l)#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you balance the following reaction in acidic solution #MnO_4^-(aq) + H_2C_2O_4(aq) -> Mn^(2+)(aq) + CO_2(g)#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="409617" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/tartar-c"><img alt="" class="" src="https://profilepictures.socratic.org/m0AqR4w7RXSxm9gd4o1l_cool-wallpaper-16.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/tartar-c"> Tartar C. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-19T23:47:44" itemprop="dateCreated"> Apr 19, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2MnO_(4)^(-)(aq) + 5H_2C_2O_4(aq) + 6H^+(aq) rarr 2Mn^(2+)(aq) + 10CO_2(g) + 8H_2O(l)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First off, you need to recognize this reaction as a REDOX reaction.</p> <p>Then split the equation into its separate half-reactions.</p> <p><mathjax>#MnO_(4)^(-)(aq)rarrMn^(2+)(aq)#</mathjax><br/> <mathjax>#H_2C_2O_4(aq)rarrCO_2(g)#</mathjax></p> <p>Balance everything except the oxygen and hydrogen.</p> <p><mathjax>#MnO_(4)^(-)(aq)rarrMn^(2+)(aq)#</mathjax><br/> <mathjax>#H_2C_2O_4(aq)rarr2CO_2(g)#</mathjax></p> <p>Now balance the oxygen by adding <mathjax>#H_2O(l)#</mathjax>.</p> <p><mathjax>#MnO_(4)^(-)(aq)rarrMn^(2+)(aq)+4H_2O(l)#</mathjax><br/> <mathjax>#H_2C_2O_4(aq)rarr2CO_2(g)#</mathjax></p> <p>Since this is in an acidic solution, the hydrogen can be balanced by adding <mathjax>#H^(+)(aq)#</mathjax>.</p> <p><mathjax>#MnO_(4)^(-)(aq)+8H^+(aq)rarrMn^(2+)(aq)+4H_2O(l)#</mathjax><br/> <mathjax>#H_2C_2O_4(aq)rarr2CO_2(g)+2H^+(aq)#</mathjax></p> <p>Add electrons (<mathjax>#e^-#</mathjax>) in order to balance the overall charge of the two sides of either half-reaction.</p> <p><mathjax>#MnO_(4)^(-)(aq)+8H^+(aq)+5e^(-)rarrMn^(2+)(aq)+4H_2O(l)#</mathjax><br/> <mathjax>#H_2C_2O_4(aq)rarr2CO_2(g)+2H^+(aq)+2e^-#</mathjax></p> <p>Multiply each half-reaction by an integer that will allow the electrons in each half-reaction to cancel out when the half-reactions are added.</p> <p><mathjax>#2MnO_(4)^(-)(aq)+16H^+(aq)+10e^(-)rarr2Mn^(2+)(aq)+8H_2O(l)#</mathjax><br/> <mathjax>#5H_2C_2O_4(aq)rarr10CO_2(g)+10H^+(aq)+10e^-#</mathjax></p> <p>Finally, add the two half-reactions and simplify.</p> <p><mathjax>#2MnO_(4)^(-)(aq)+16H^+(aq)+10e^(-)+5H_2C_2O_4(aq)rarr2Mn^(2+)(aq)+8H_2O+10CO_2(g)+10H^+(aq)+10e^-#</mathjax></p> <p><mathjax>#2MnO_(4)^(-)(aq) + 6cancel(16)H^+(aq) + cancel(10e^(-)) + 5H_2C_2O_4(aq) rarr 2Mn^(2+)(aq) + 8H_2O(l) + 10CO_2(g) + cancel(10H^+(aq)) + cancel(10e^-)#</mathjax></p> <p><mathjax>#2MnO_(4)^(-)(aq) + 5H_2C_2O_4(aq) + 6H^+(aq) rarr 2Mn^(2+)(aq) + 10CO_2(g) + 8H_2O(l)#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/409617" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, 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Sodium phosphate and calcium chloride react to form... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-equation-kclo3-kcl-o2"> How can I balance this equation? ____ #KClO_3 -># ____ #KCl +# ____ #O_2# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-balancing-chemical-equations-important"> Why is balancing chemical equations important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/balancing-chemical-equations"> See all questions in Balancing Chemical Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 4082 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How do you balance the following reaction in acidic solution #MnO_4^-(aq) + H_2C_2O_4(aq) -> Mn^(2+)(aq) + CO_2(g)#?	null
1,861	aa3c3536-6ddd-11ea-85b5-ccda262736ce	https://socratic.org/questions/how-many-grams-are-there-in-1-5-x-10-25-molecules-of-co-2	2266.00 grams	start physical_unit 11 11 mass g qc_end end	[{"type":"physical unit","value":"Mass [OF] CO2 [IN] grams"}]	[{"type":"physical unit","value":"2266.00 grams"}]	[{"type":"physical unit","value":"Number [OF] CO2 molecules [=] \\pu{1.5 × 10^25}"}]	<h1 class="questionTitle" itemprop="name">How many grams are there in #1.5 x 10^25# molecules of #CO_2#?</h1>	null	2266.00 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Molar mass of CO2 = 44g/mol</p> <p><mathjax>#1.5 * 10^25 / 6.023 * 10^23"#</mathjax> = 51.5 moles of CO2 </p> <p><mathjax>#51.5 * "44g/mol" = 2266grams #</mathjax></p> <p>Hope this helped</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Mass = no. of molecules / 6.023 * 10^ 23 * Molar mass" #</mathjax> </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Molar mass of CO2 = 44g/mol</p> <p><mathjax>#1.5 * 10^25 / 6.023 * 10^23"#</mathjax> = 51.5 moles of CO2 </p> <p><mathjax>#51.5 * "44g/mol" = 2266grams #</mathjax></p> <p>Hope this helped</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many grams are there in #1.5 x 10^25# molecules of #CO_2#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="370312" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/samriddha"><img alt="" class="" src="https://profilepictures.socratic.org/3bMcXdwZTLqpsJaquExz_Shinjuku.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/samriddha"> Professor Sam </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-01-28T09:42:51" itemprop="dateCreated"> Jan 28, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Mass = no. of molecules / 6.023 * 10^ 23 * Molar mass" #</mathjax> </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Molar mass of CO2 = 44g/mol</p> <p><mathjax>#1.5 * 10^25 / 6.023 * 10^23"#</mathjax> = 51.5 moles of CO2 </p> <p><mathjax>#51.5 * "44g/mol" = 2266grams #</mathjax></p> <p>Hope this helped</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/370312" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? 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1,862	a8f68fea-6ddd-11ea-9311-ccda262736ce	https://socratic.org/questions/how-would-you-balance-this-chemical-equation-as-2o-3-naoh-na-3aso-h-2o	As2O3 + 6 NaOH -> 2 Na3AsO3 + 3 H2O	start chemical_equation qc_end chemical_equation 7 13 qc_end end	[{"type":"other","value":"Chemical Equation [OF] this chemical equation"}]	[{"type":"chemical equation","value":"As2O3 + 6 NaOH -> 2 Na3AsO3 + 3 H2O"}]	[{"type":"chemical equation","value":"As2O3 + NaOH -> Na3AsO3 + H2O"}]	<h1 class="questionTitle" itemprop="name">How would you balance this chemical equation? #As_2O_3 + NaOH -> Na_3AsO + H_2O#?</h1>	null	As2O3 + 6 NaOH -> 2 Na3AsO3 + 3 H2O	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>It misses the subscript 3 for the Oxygen of the salt in the second member of the equation. In the first member Arsenic has Oxidation number = 3 and it can't change with reacting with NaOH. The correct reaction is the formation of a salt by reaction of NaOH with an acid oxide <br/> <mathjax>#As_2O_3 + 6 NaOH = 2 Na_3 AsO_3 + 3 H_2O#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#As_2O_3 + 6 NaOH = 2 Na_3 AsO_3 + 3 H_2O#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>It misses the subscript 3 for the Oxygen of the salt in the second member of the equation. In the first member Arsenic has Oxidation number = 3 and it can't change with reacting with NaOH. The correct reaction is the formation of a salt by reaction of NaOH with an acid oxide <br/> <mathjax>#As_2O_3 + 6 NaOH = 2 Na_3 AsO_3 + 3 H_2O#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How would you balance this chemical equation? #As_2O_3 + NaOH -> Na_3AsO + H_2O#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="416880" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/andrea-b-3"><img alt="" class="" src="https://graph.facebook.com/100000553538995/picture?height=50&width=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/andrea-b-3"> Andrea B. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-03T05:29:54" itemprop="dateCreated"> May 3, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#As_2O_3 + 6 NaOH = 2 Na_3 AsO_3 + 3 H_2O#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>It misses the subscript 3 for the Oxygen of the salt in the second member of the equation. In the first member Arsenic has Oxidation number = 3 and it can't change with reacting with NaOH. The correct reaction is the formation of a salt by reaction of NaOH with an acid oxide <br/> <mathjax>#As_2O_3 + 6 NaOH = 2 Na_3 AsO_3 + 3 H_2O#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/416880" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------> H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -> Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? 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Sodium phosphate and calcium chloride react to form... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-equation-kclo3-kcl-o2"> How can I balance this equation? ____ #KClO_3 -># ____ #KCl +# ____ #O_2# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-balancing-chemical-equations-important"> Why is balancing chemical equations important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/balancing-chemical-equations"> See all questions in Balancing Chemical Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1071 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How would you balance this chemical equation? #As_2O_3 + NaOH -> Na_3AsO + H_2O#?	null
1,863	a8ad13ca-6ddd-11ea-9b51-ccda262736ce	https://socratic.org/questions/5920a345b72cff4a6549c4cb	4.00 g	start physical_unit 0 0 mass g qc_end c_other OTHER qc_end physical_unit 7 8 10 11 mass qc_end end	[{"type":"physical unit","value":"Mass [OF] sodium [IN] g"}]	[{"type":"physical unit","value":"4.00 g"}]	[{"type":"other","value":"Sodium and chlorine gas react to produce sodium chloride. "},{"type":"physical unit","value":"Mass [OF] sodium chloride [=] \\pu{234 g}"}]	<h1 class="questionTitle" itemprop="name">Sodium and chlorine gas react to produce sodium chloride. If #"234 g"# of sodium chloride is produced, how much sodium reacted?</h1>	null	4.00 g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You know that</p> <blockquote> <p><mathjax>#2"Na"_ ((s)) + "Cl"_ (2(g)) -> 2"NaCl"_ ((s))#</mathjax></p> </blockquote> <p>and that the reaction produced <mathjax>#"234 g"#</mathjax> of sodium chloride. Convert this to <em>moles</em> by using the compound's <strong>molar mass</strong></p> <blockquote> <p><mathjax>#234 color(red)(cancel(color(black)("g"))) * "1 mole NaCl"/(58.44 color(red)(cancel(color(black)("g")))) = "4.004 moles NaCl"#</mathjax></p> </blockquote> <p>Now, you know that the sample of sodium metal reacted <strong>completely</strong>, which implies that it was completely consumed by the reaction. </p> <p>In other words, you don't have to worry about the sample of chlorine gas because the fact that sample of sodium metal was completely consumed lets you know that the chlorine gas is <strong>not</strong> a <a href="https://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a>. </p> <p>This means that the reaction consumed</p> <blockquote> <p><mathjax>#4.004 color(red)(cancel(color(black)("moles NaCl"))) * "2 moles Na"/(2color(red)(cancel(color(black)("moles NaCl")))) = "4.004 moles Na"#</mathjax></p> </blockquote> <p>Convert this to <em>grams</em> by using the element's <strong>molar mass</strong></p> <blockquote> <p><mathjax>#4.004 color(red)(cancel(color(black)("moles Na"))) * "22.99 g"/(1color(red)(cancel(color(black)("mole Na")))) = color(darkgreen)(ul(color(black)("92.1 g")))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p> <p><strong>SIDE NOTE</strong> <em>You can show that chlorine gas is <strong>not</strong> the limiting reagent by calculating the number of moles present in the sample</em></p> <blockquote> <p><mathjax>#0.142 color(red)(cancel(color(black)("kg"))) * "1 mole Cl"_2/(35.453color(red)(cancel(color(black)("kg")))) = "4.005 moles Cl"_2#</mathjax></p> </blockquote> <p><em>In order to produce</em> <mathjax>#4.004#</mathjax> <em><strong>moles</strong> of sodium chloride, you only need</em></p> <blockquote> <p><mathjax>#4.004 color(red)(cancel(color(black)("moles NaCl"))) * "1 mole Cl"_2/(2color(red)(cancel(color(black)("moles NaCl")))) = "2.002 moles Cl"_2#</mathjax></p> </blockquote> <p><em>Since you have more chlorine gas than you need, chlorine is <strong>in excess</strong></em>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"92.1 g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You know that</p> <blockquote> <p><mathjax>#2"Na"_ ((s)) + "Cl"_ (2(g)) -> 2"NaCl"_ ((s))#</mathjax></p> </blockquote> <p>and that the reaction produced <mathjax>#"234 g"#</mathjax> of sodium chloride. Convert this to <em>moles</em> by using the compound's <strong>molar mass</strong></p> <blockquote> <p><mathjax>#234 color(red)(cancel(color(black)("g"))) * "1 mole NaCl"/(58.44 color(red)(cancel(color(black)("g")))) = "4.004 moles NaCl"#</mathjax></p> </blockquote> <p>Now, you know that the sample of sodium metal reacted <strong>completely</strong>, which implies that it was completely consumed by the reaction. </p> <p>In other words, you don't have to worry about the sample of chlorine gas because the fact that sample of sodium metal was completely consumed lets you know that the chlorine gas is <strong>not</strong> a <a href="https://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a>. </p> <p>This means that the reaction consumed</p> <blockquote> <p><mathjax>#4.004 color(red)(cancel(color(black)("moles NaCl"))) * "2 moles Na"/(2color(red)(cancel(color(black)("moles NaCl")))) = "4.004 moles Na"#</mathjax></p> </blockquote> <p>Convert this to <em>grams</em> by using the element's <strong>molar mass</strong></p> <blockquote> <p><mathjax>#4.004 color(red)(cancel(color(black)("moles Na"))) * "22.99 g"/(1color(red)(cancel(color(black)("mole Na")))) = color(darkgreen)(ul(color(black)("92.1 g")))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p> <p><strong>SIDE NOTE</strong> <em>You can show that chlorine gas is <strong>not</strong> the limiting reagent by calculating the number of moles present in the sample</em></p> <blockquote> <p><mathjax>#0.142 color(red)(cancel(color(black)("kg"))) * "1 mole Cl"_2/(35.453color(red)(cancel(color(black)("kg")))) = "4.005 moles Cl"_2#</mathjax></p> </blockquote> <p><em>In order to produce</em> <mathjax>#4.004#</mathjax> <em><strong>moles</strong> of sodium chloride, you only need</em></p> <blockquote> <p><mathjax>#4.004 color(red)(cancel(color(black)("moles NaCl"))) * "1 mole Cl"_2/(2color(red)(cancel(color(black)("moles NaCl")))) = "2.002 moles Cl"_2#</mathjax></p> </blockquote> <p><em>Since you have more chlorine gas than you need, chlorine is <strong>in excess</strong></em>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Sodium and chlorine gas react to produce sodium chloride. If #"234 g"# of sodium chloride is produced, how much sodium reacted?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="426874" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-20T20:48:10" itemprop="dateCreated"> May 20, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"92.1 g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You know that</p> <blockquote> <p><mathjax>#2"Na"_ ((s)) + "Cl"_ (2(g)) -> 2"NaCl"_ ((s))#</mathjax></p> </blockquote> <p>and that the reaction produced <mathjax>#"234 g"#</mathjax> of sodium chloride. Convert this to <em>moles</em> by using the compound's <strong>molar mass</strong></p> <blockquote> <p><mathjax>#234 color(red)(cancel(color(black)("g"))) * "1 mole NaCl"/(58.44 color(red)(cancel(color(black)("g")))) = "4.004 moles NaCl"#</mathjax></p> </blockquote> <p>Now, you know that the sample of sodium metal reacted <strong>completely</strong>, which implies that it was completely consumed by the reaction. </p> <p>In other words, you don't have to worry about the sample of chlorine gas because the fact that sample of sodium metal was completely consumed lets you know that the chlorine gas is <strong>not</strong> a <a href="https://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a>. </p> <p>This means that the reaction consumed</p> <blockquote> <p><mathjax>#4.004 color(red)(cancel(color(black)("moles NaCl"))) * "2 moles Na"/(2color(red)(cancel(color(black)("moles NaCl")))) = "4.004 moles Na"#</mathjax></p> </blockquote> <p>Convert this to <em>grams</em> by using the element's <strong>molar mass</strong></p> <blockquote> <p><mathjax>#4.004 color(red)(cancel(color(black)("moles Na"))) * "22.99 g"/(1color(red)(cancel(color(black)("mole Na")))) = color(darkgreen)(ul(color(black)("92.1 g")))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p> <p><strong>SIDE NOTE</strong> <em>You can show that chlorine gas is <strong>not</strong> the limiting reagent by calculating the number of moles present in the sample</em></p> <blockquote> <p><mathjax>#0.142 color(red)(cancel(color(black)("kg"))) * "1 mole Cl"_2/(35.453color(red)(cancel(color(black)("kg")))) = "4.005 moles Cl"_2#</mathjax></p> </blockquote> <p><em>In order to produce</em> <mathjax>#4.004#</mathjax> <em><strong>moles</strong> of sodium chloride, you only need</em></p> <blockquote> <p><mathjax>#4.004 color(red)(cancel(color(black)("moles NaCl"))) * "1 mole Cl"_2/(2color(red)(cancel(color(black)("moles NaCl")))) = "2.002 moles Cl"_2#</mathjax></p> </blockquote> <p><em>Since you have more chlorine gas than you need, chlorine is <strong>in excess</strong></em>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/426874" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="426884" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-20T21:30:08" itemprop="dateCreated"> May 20, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The mass of sodium that reacted is 92.1 g, or 0.0921 kg.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Start with a balanced equation.</p> <p><mathjax>#"2Na(s) + Cl"_2("g")"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"2NaCl(s)"#</mathjax></p> <p>In order to determine the mass of chlorine gas that reacted to produce 234 g NaCl, you work backwords, starting with NaCl and ending with Na.</p> <p>The process will involve the following steps:</p> <p><mathjax>#color(red)("given mass NaCl")#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(red)("mol NaCl"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(red)"mol Na"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(red)("mass Na"#</mathjax></p> <p><mathjax>#color(blue)("Determine the mol NaCl that reacted."#</mathjax></p> <p>Multiply the <mathjax>#color(red)("given mass of NaCl"#</mathjax> by the inverse of its molar mass.</p> <p>The molar mass of <mathjax>#"NaCl"#</mathjax> is <mathjax>#"58.44 g/mol NaCl"#</mathjax>.<br/> <a href="https://www.ncbi.nlm.nih.gov/pccompound?term=NaCl" rel="nofollow" target="_blank">https://www.ncbi.nlm.nih.gov/pccompound?term=NaCl</a></p> <p><mathjax>#234color(red)cancel(color(black)("g NaCl"))xx(1"mol NaCl")/(58.44color(red)cancel(color(black)("g Cl"_2)))="4.004 mol NaCl"#</mathjax></p> <p><mathjax>#color(blue)("Determine the moles of Na that reacted."#</mathjax> </p> <p>Multiply mol <mathjax>#"NaCl"#</mathjax> by multiplying <mathjax>#"mol NaCl"#</mathjax> by the mol ratio between <mathjax>#"NaCl"#</mathjax> and <mathjax>#"Na"#</mathjax> from the balanced equation, so that <mathjax>#"mol NaCl"#</mathjax> is cancelled.</p> <p><mathjax>#4.004color(red)cancel(color(black)("mol NaCl"))xx(2"mol Na")/(2color(red)cancel(color(black)("mol NaCl")))="4.004 mol Na"#</mathjax></p> <p><mathjax>#color(blue)("Determine the mass of Na that reacted."#</mathjax></p> <p>Multiply mol <mathjax>#"Na"#</mathjax> by its molar mass.</p> <p>The molar mass of <mathjax>#"Na"#</mathjax> is <mathjax>#"22.98976928 g/mol Na".#</mathjax> (Periodic table)</p> <p><mathjax>#4.004color(red)cancel(color(black)("mol Na"))xx(22.98976928"g Na")/(1color(red)cancel(color(black)("mol Na")))="92.1 g Na"="0.0921 kg"#</mathjax> (rounded to three significant numbers)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/426884" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li 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If #"234 g"# of sodium chloride is produced, how much sodium reacted?	null
1,864	ab519ab0-6ddd-11ea-9c73-ccda262736ce	https://socratic.org/questions/how-would-you-balance-the-combustion-reaction-between-octane-and-oxygen-2c8h18-o	C8H18 + 25/2 O2 -> 8 CO2 + 9 H2O	start chemical_equation qc_end chemical_equation 11 17 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the combustion reaction"}]	[{"type":"chemical equation","value":"C8H18 + 25/2 O2 -> 8 CO2 + 9 H2O"}]	[{"type":"chemical equation","value":"C8H18 + O2 -> CO2 + H2O"}]	<h1 class="questionTitle" itemprop="name">How would you balance the combustion reaction between octane and oxygen: 2C8H18 + O2 → CO2 + H2O?</h1>	null	C8H18 + 25/2 O2 -> 8 CO2 + 9 H2O	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Is the above equation balanced? Don't trust my arithmetic. What would be the physical states of each participant in the reaction? Internal combustion engines rarely combust gas this cleanly, and a lot of <mathjax>#C#</mathjax> particulate, and <mathjax>#CO#</mathjax> gas are given off. </p> <p>If (say) 1 equiv each of <mathjax>#C#</mathjax> and <mathjax>#CO#</mathjax> were given off by the combustion, how would I balance this reaction?</p> <p><mathjax>#C_8H_18 + xO_2 rarr yCO_2 + C + CO +9H_2O#</mathjax></p> <p>Would the energy output be the same?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_8H_18 +25/2O_2 rarr 8CO_2 + 9H_2O#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Is the above equation balanced? Don't trust my arithmetic. What would be the physical states of each participant in the reaction? Internal combustion engines rarely combust gas this cleanly, and a lot of <mathjax>#C#</mathjax> particulate, and <mathjax>#CO#</mathjax> gas are given off. </p> <p>If (say) 1 equiv each of <mathjax>#C#</mathjax> and <mathjax>#CO#</mathjax> were given off by the combustion, how would I balance this reaction?</p> <p><mathjax>#C_8H_18 + xO_2 rarr yCO_2 + C + CO +9H_2O#</mathjax></p> <p>Would the energy output be the same?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How would you balance the combustion reaction between octane and oxygen: 2C8H18 + O2 → CO2 + H2O?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-reactions-and-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions and Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="182597" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-03T20:14:11" itemprop="dateCreated"> Nov 3, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_8H_18 +25/2O_2 rarr 8CO_2 + 9H_2O#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Is the above equation balanced? Don't trust my arithmetic. What would be the physical states of each participant in the reaction? Internal combustion engines rarely combust gas this cleanly, and a lot of <mathjax>#C#</mathjax> particulate, and <mathjax>#CO#</mathjax> gas are given off. </p> <p>If (say) 1 equiv each of <mathjax>#C#</mathjax> and <mathjax>#CO#</mathjax> were given off by the combustion, how would I balance this reaction?</p> <p><mathjax>#C_8H_18 + xO_2 rarr yCO_2 + C + CO +9H_2O#</mathjax></p> <p>Would the energy output be the same?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/182597" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb002bf34694a4fee47"> Question #fee47 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb402bf34694c8c5c15"> Question #c5c15 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb802bf346950519eb9"> Question #19eb9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cbf02bf3469570e2ea2"> Question #e2ea2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc002bf34695a6bc751"> Question #bc751 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc202bf3469570e2ea6"> Question #e2ea6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531e867a02bf342492a08b07"> Question #08b07 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-thermochemical-equation-for-the-combustion-of-benzene"> What is the thermochemical equation for the combustion of benzene? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-reversible"> Why are chemical reactions reversible? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-important"> Why are chemical reactions important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/chemical-reactions-and-equations"> See all questions in Chemical Reactions and Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2859 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How would you balance the combustion reaction between octane and oxygen: 2C8H18 + O2 → CO2 + H2O?	null
1,865	ad0eccc9-6ddd-11ea-ab73-ccda262736ce	https://socratic.org/questions/how-many-moles-of-ca-no-3-2-are-there-in-75-ml-of-0-25-m-solution	0.02 moles	start physical_unit 4 4 mole mol qc_end physical_unit 13 13 8 9 volume qc_end physical_unit 4 4 11 12 molarity qc_end end	[{"type":"physical unit","value":"Mole [OF] Ca(NO3)2 [IN] moles"}]	[{"type":"physical unit","value":"0.02 moles"}]	[{"type":"physical unit","value":"Volume [OF] Ca(NO3)2 solution [=] \\pu{75 mL}"},{"type":"physical unit","value":"Molarity [OF] Ca(NO3)2 solution [=] \\pu{0.25 M}"}]	<h1 class="questionTitle" itemprop="name">How many moles of #Ca(NO_3)_2# are there in 75 mL of 0.25 M solution?</h1>	null	0.02 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We're asked to find the number of <em>moles</em> of calcium nitrate are in <mathjax>#75#</mathjax> <mathjax>#"mL"#</mathjax> of a <mathjax>#0.25#</mathjax> molar solution of <mathjax>#"Ca(NO"_3")"_2#</mathjax>.</p> <p>To solve this equation, we can use the <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> equation</strong>:</p> <p><mathjax>#"molarity" = "moles solute"/"liters solution"#</mathjax></p> <p>We need the solution's volume to be in <mathjax>#"L"#</mathjax>, so let's convert it:</p> <p><mathjax>#75cancel("mL")((1color(white)(l)"L")/(10^3cancel("mL"))) = 0.075#</mathjax> <mathjax>#"L"#</mathjax></p> <p>We're asked to find the number of moles, so</p> <p><mathjax>#"moles solute" = ("molarity")("liters solution")#</mathjax></p> <p><mathjax>#"mol Ca(NO"_3")"_2 = (0.25"mol"/(cancel("L")))(0.075cancel("L"))#</mathjax></p> <p><mathjax># = color(red)(0.019#</mathjax> <mathjax>#color(red)("mol Ca(NO"_3")"_2#</mathjax></p> <p>rounded to two sig figs.</p> <p>Therefore, there are <mathjax>#color(red)(0.019#</mathjax> <mathjax>#sfcolor(red)("moles of calcium nitrate"#</mathjax> in <mathjax>#75#</mathjax> <mathjax>#"mL"#</mathjax> of a <mathjax>#0.25M#</mathjax> solution.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#0.019#</mathjax> <mathjax>#"mol Ca(NO"_3")"_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We're asked to find the number of <em>moles</em> of calcium nitrate are in <mathjax>#75#</mathjax> <mathjax>#"mL"#</mathjax> of a <mathjax>#0.25#</mathjax> molar solution of <mathjax>#"Ca(NO"_3")"_2#</mathjax>.</p> <p>To solve this equation, we can use the <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> equation</strong>:</p> <p><mathjax>#"molarity" = "moles solute"/"liters solution"#</mathjax></p> <p>We need the solution's volume to be in <mathjax>#"L"#</mathjax>, so let's convert it:</p> <p><mathjax>#75cancel("mL")((1color(white)(l)"L")/(10^3cancel("mL"))) = 0.075#</mathjax> <mathjax>#"L"#</mathjax></p> <p>We're asked to find the number of moles, so</p> <p><mathjax>#"moles solute" = ("molarity")("liters solution")#</mathjax></p> <p><mathjax>#"mol Ca(NO"_3")"_2 = (0.25"mol"/(cancel("L")))(0.075cancel("L"))#</mathjax></p> <p><mathjax># = color(red)(0.019#</mathjax> <mathjax>#color(red)("mol Ca(NO"_3")"_2#</mathjax></p> <p>rounded to two sig figs.</p> <p>Therefore, there are <mathjax>#color(red)(0.019#</mathjax> <mathjax>#sfcolor(red)("moles of calcium nitrate"#</mathjax> in <mathjax>#75#</mathjax> <mathjax>#"mL"#</mathjax> of a <mathjax>#0.25M#</mathjax> solution.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles of #Ca(NO_3)_2# are there in 75 mL of 0.25 M solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="443602" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/mrtas"><img alt="" class="" src="https://profilepictures.socratic.org/HY14X7r4S6AyDQgK2gwQ_IMG_0062.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/mrtas"> Nathan L. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-23T18:00:26" itemprop="dateCreated"> Jun 23, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#0.019#</mathjax> <mathjax>#"mol Ca(NO"_3")"_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We're asked to find the number of <em>moles</em> of calcium nitrate are in <mathjax>#75#</mathjax> <mathjax>#"mL"#</mathjax> of a <mathjax>#0.25#</mathjax> molar solution of <mathjax>#"Ca(NO"_3")"_2#</mathjax>.</p> <p>To solve this equation, we can use the <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> equation</strong>:</p> <p><mathjax>#"molarity" = "moles solute"/"liters solution"#</mathjax></p> <p>We need the solution's volume to be in <mathjax>#"L"#</mathjax>, so let's convert it:</p> <p><mathjax>#75cancel("mL")((1color(white)(l)"L")/(10^3cancel("mL"))) = 0.075#</mathjax> <mathjax>#"L"#</mathjax></p> <p>We're asked to find the number of moles, so</p> <p><mathjax>#"moles solute" = ("molarity")("liters solution")#</mathjax></p> <p><mathjax>#"mol Ca(NO"_3")"_2 = (0.25"mol"/(cancel("L")))(0.075cancel("L"))#</mathjax></p> <p><mathjax># = color(red)(0.019#</mathjax> <mathjax>#color(red)("mol Ca(NO"_3")"_2#</mathjax></p> <p>rounded to two sig figs.</p> <p>Therefore, there are <mathjax>#color(red)(0.019#</mathjax> <mathjax>#sfcolor(red)("moles of calcium nitrate"#</mathjax> in <mathjax>#75#</mathjax> <mathjax>#"mL"#</mathjax> of a <mathjax>#0.25M#</mathjax> solution.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/443602" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> 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Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many moles of #Ca(NO_3)_2# are there in 75 mL of 0.25 M solution?	null
1,866	a9fddcaa-6ddd-11ea-9abb-ccda262736ce	https://socratic.org/questions/what-is-the-mass-of-3-21-10-2-mol-ni	1.89 g	start physical_unit 9 9 mass g qc_end physical_unit 9 9 5 8 mole qc_end end	[{"type":"physical unit","value":"Mass [OF] Ni [IN] g"}]	[{"type":"physical unit","value":"1.89 g"}]	[{"type":"physical unit","value":"Mole [OF] Ni [=] \\pu{3.21 × 10^(-2) mol}"}]	<h1 class="questionTitle" itemprop="name">What is the mass of #3.21 * 10^-2# mol #Ni#?</h1>	null	1.89 g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>put the formula <mathjax>#mols=massdividear#</mathjax> then rearrange the formula and multiply the mols with the ar of nickel which is 59 so<br/> <mathjax>#59*3.21^10-2#</mathjax> and the ans will be <mathjax>#1.8939g#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1.8939 g#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>put the formula <mathjax>#mols=massdividear#</mathjax> then rearrange the formula and multiply the mols with the ar of nickel which is 59 so<br/> <mathjax>#59*3.21^10-2#</mathjax> and the ans will be <mathjax>#1.8939g#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the mass of #3.21 * 10^-2# mol #Ni#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="229743" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/abdul-s-1"><img alt="" class="" src="https://lh6.googleusercontent.com/-W8XMY2yP-hM/AAAAAAAAAAI/AAAAAAAAABg/XwBa66Uif8k/photo.jpg?sz=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/abdul-s-1"> Abdul Sammad </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-02-22T16:19:20" itemprop="dateCreated"> Feb 22, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1.8939 g#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>put the formula <mathjax>#mols=massdividear#</mathjax> then rearrange the formula and multiply the mols with the ar of nickel which is 59 so<br/> <mathjax>#59*3.21^10-2#</mathjax> and the ans will be <mathjax>#1.8939g#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/229743" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? 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1,867	acd557c2-6ddd-11ea-9914-ccda262736ce	https://socratic.org/questions/15g-of-copper-ii-chloride-reacts-with-20g-of-sodium-nitrate-calculate-the-mass-o	12.15 g	start physical_unit 16 17 mass g qc_end physical_unit 3 4 0 1 mass qc_end physical_unit 10 11 7 8 mass qc_end end	[{"type":"physical unit","value":"Mass [OF] sodium chloride [IN] g"}]	[{"type":"physical unit","value":"12.15 g"}]	[{"type":"physical unit","value":"Mass [OF] copper(ii) chloride [=] \\pu{15 g}"},{"type":"physical unit","value":"Mass [OF] sodium nitrate [=] \\pu{20 g}"}]	<h1 class="questionTitle" itemprop="name">15g of copper(ii) chloride reacts with 20g of sodium nitrate. Calculate the mass of sodium chloride formed?</h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>I calculated the answer to be around 11.7g. Can someone help verify this?</p></div> </h2> </div> </div>	12.15 g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>I got elemental weights as (Na=22.99 grams; Cu=63.55 grams; Cl=31.45 grams; N=14.01 grams; O=16 grams). The answer (Mass of sodium chloride after reaction) is 12.15 grams </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>12.15 grams</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>I got elemental weights as (Na=22.99 grams; Cu=63.55 grams; Cl=31.45 grams; N=14.01 grams; O=16 grams). The answer (Mass of sodium chloride after reaction) is 12.15 grams </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">15g of copper(ii) chloride reacts with 20g of sodium nitrate. Calculate the mass of sodium chloride formed?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>I calculated the answer to be around 11.7g. Can someone help verify this?</p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="398389" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/g-ozdilek"><img alt="" class="" src="https://profilepictures.socratic.org/KVknsUYQYSYlmT2ycLuw_kentkonseyi-%287%29HGO.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/g-ozdilek"> G_Ozdilek </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-29T11:22:59" itemprop="dateCreated"> Mar 29, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>12.15 grams</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>I got elemental weights as (Na=22.99 grams; Cu=63.55 grams; Cl=31.45 grams; N=14.01 grams; O=16 grams). The answer (Mass of sodium chloride after reaction) is 12.15 grams </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/398389" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="398587" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/sarita-rana"><img alt="" class="" src="https://profilepictures.socratic.org/tvT08VaORGyEZTsSaNA4_images.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/sarita-rana"> Sarita Rana </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-29T17:35:24" itemprop="dateCreated"> Mar 29, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#NaCl#</mathjax> formed = <mathjax>#13.03 g#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#CuCl_2#</mathjax> + <mathjax>#2NaNO_3#</mathjax> ------------> <mathjax>#2NaCl#</mathjax> + <mathjax>#Cu(NO_3)_2#</mathjax></p> <p>no. of moles of <mathjax>#CuCl_2#</mathjax> = <mathjax>#15g#</mathjax>/<mathjax>#134.45#</mathjax> g.mol -1 = <mathjax>#0.1115#</mathjax> moles ..............(1)</p> <p>no. of moles of <mathjax>#NaNO_3#</mathjax> = <mathjax>#20g#</mathjax>/<mathjax>#84.99#</mathjax> g.mol -1 = <mathjax>#0.2353#</mathjax> moles........(2)</p> <p>According to equation <br/> 1 mole of <mathjax>#CuCl_2#</mathjax> produces <mathjax>#NaCl#</mathjax> = <mathjax>#2#</mathjax> moles<br/> so, <mathjax>#0.1115#</mathjax> moles of <mathjax>#CuCl_2#</mathjax> will produce <mathjax>#NaCl#</mathjax> = <mathjax>#2#</mathjax> x <mathjax>#0.1115#</mathjax> moles = <mathjax>#0.223#</mathjax> moles ........(3)</p> <p>2 mole of <mathjax>#NaNO_3#</mathjax> produces <mathjax>#NaCl#</mathjax> = <mathjax>#2#</mathjax> moles<br/> so, <mathjax>#0.2353#</mathjax> moles of <mathjax>#NaNO_3#</mathjax> will produce <mathjax>#NaCl#</mathjax> = <mathjax>#2#</mathjax> x <mathjax>#0.2353#</mathjax> moles...........(4)</p> <p><mathjax>#0.1115#</mathjax> moles of <mathjax>#CuCl_2#</mathjax> produces lesser number of moles of <mathjax>#NaCl#</mathjax>. hence <mathjax>#CuCl_2#</mathjax> is limiting reagent..................(5)</p> <p>Therefore mass of <mathjax>#NaCl#</mathjax> produced = <mathjax>#0.223#</mathjax> moles.......(6)<br/> Molar mass of <mathjax>#NaCl#</mathjax> = <mathjax>#58.44#</mathjax> g/mol<br/> mass of <mathjax>#NaCl#</mathjax> = <mathjax>#0.223#</mathjax> moles x <mathjax>#58.44#</mathjax> g/mol = <mathjax># 13.03 g #</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/398587" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What is stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ab82402bf342f48d93ac6"> Question #93ac6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-we-study-stoichiometry"> Why do we study stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-naoh-is-produced-from-1-20-x-102-grams-of-na2o-na2o-h2o-2-naoh"> How many grams of NaOH is produced from #1.20 x 10^2# grams of #Na_2O#? #Na_2O + H_2O -> 2NaOH# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-na2o-are-required-to-produce-1-60-x-102-grams-of-naoh-na2o-h2o"> How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? 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Calculate the mass of sodium chloride formed?	I calculated the answer to be around 11.7g. Can someone help verify this?
1,868	ab01c953-6ddd-11ea-94c8-ccda262736ce	https://socratic.org/questions/is-gas-volume-of-444-ml-at-273k-and-79-0-kpa-what-is-the-final-kelvin-temperatur	566 kelvin	start physical_unit 22 23 temperature k qc_end physical_unit 22 23 4 5 volume qc_end physical_unit 22 23 7 8 temperature qc_end physical_unit 22 23 10 11 pressure qc_end physical_unit 22 23 27 28 volume qc_end physical_unit 22 23 34 35 pressure qc_end end	[{"type":"physical unit","value":"Temperature2 [OF] the gas [IN] kelvin"}]	[{"type":"physical unit","value":"566 kelvin"}]	[{"type":"physical unit","value":"Volume1 [OF] the gas [=] \\pu{444 mL}"},{"type":"physical unit","value":"Temperature1 [OF] the gas [=] \\pu{273 K}"},{"type":"physical unit","value":"Pressure1 [OF] the gas [=] \\pu{79.0 kPa}"},{"type":"physical unit","value":"Volume2 [OF] the gas [=] \\pu{1880 mL}"},{"type":"physical unit","value":"Pressure2 [OF] the gas [=] \\pu{38.7 kPa}"}]	<h1 class="questionTitle" itemprop="name">Is gas volume of 444 mL at 273K and 79.0 kPa. What is the final kelvin temperature when the volume of the gas is changed to 1880 mL and the pressure changed to 38.7 kPa? </h1>	null	566 kelvin	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We're asked to calculate the final absolute (Kelvin) temperature of a gas system when it is subdued to known pressure and volume changes.</p> <p>To solve this problem, we can use the <em><a href="https://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">combined gas law</a></em>:</p> <p><mathjax>#(P_1V_1)/(T_1) = (P_2V_2)/(T_2)#</mathjax></p> <p>For this equation to work, the units have to be <em>consistent</em>; for example, we can't plug in two values for pressure if one is measured in <mathjax>#"kPa"#</mathjax> and the other in <mathjax>#"atm"#</mathjax>; the units must be the same. </p> <p>Since all the units are consistent, here, solving the problem is straightforward enough: we simply plug in the known variables and solve the equation for the final temperature, <mathjax>#T_2#</mathjax>:</p> <p><mathjax>#T_2 = (T_1P_2V_2)/(P_1V_1) = ((273"K")(38.7cancel("kPa"))(1880cancel("mL")))/((79.0cancel("kPa"))(444cancel("mL")))#</mathjax></p> <p><mathjax>#= color(red)(566"K"#</mathjax></p> <p>rounded to <mathjax>#3#</mathjax> <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a>, the number given in the problem.</p> <p>Thus, the final Kelvin temperature after the changes in pressure and volume is <mathjax>#566"K"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#566"K"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We're asked to calculate the final absolute (Kelvin) temperature of a gas system when it is subdued to known pressure and volume changes.</p> <p>To solve this problem, we can use the <em><a href="https://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">combined gas law</a></em>:</p> <p><mathjax>#(P_1V_1)/(T_1) = (P_2V_2)/(T_2)#</mathjax></p> <p>For this equation to work, the units have to be <em>consistent</em>; for example, we can't plug in two values for pressure if one is measured in <mathjax>#"kPa"#</mathjax> and the other in <mathjax>#"atm"#</mathjax>; the units must be the same. </p> <p>Since all the units are consistent, here, solving the problem is straightforward enough: we simply plug in the known variables and solve the equation for the final temperature, <mathjax>#T_2#</mathjax>:</p> <p><mathjax>#T_2 = (T_1P_2V_2)/(P_1V_1) = ((273"K")(38.7cancel("kPa"))(1880cancel("mL")))/((79.0cancel("kPa"))(444cancel("mL")))#</mathjax></p> <p><mathjax>#= color(red)(566"K"#</mathjax></p> <p>rounded to <mathjax>#3#</mathjax> <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a>, the number given in the problem.</p> <p>Thus, the final Kelvin temperature after the changes in pressure and volume is <mathjax>#566"K"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Is gas volume of 444 mL at 273K and 79.0 kPa. What is the final kelvin temperature when the volume of the gas is changed to 1880 mL and the pressure changed to 38.7 kPa? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/measuring-gas-pressure" itemprop="url"> <span class="breadcrumb" itemprop="title">Measuring Gas Pressure</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="432327" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/mrtas"><img alt="" class="" src="https://profilepictures.socratic.org/HY14X7r4S6AyDQgK2gwQ_IMG_0062.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/mrtas"> Nathan L. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-31T02:59:16" itemprop="dateCreated"> May 31, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#566"K"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We're asked to calculate the final absolute (Kelvin) temperature of a gas system when it is subdued to known pressure and volume changes.</p> <p>To solve this problem, we can use the <em><a href="https://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">combined gas law</a></em>:</p> <p><mathjax>#(P_1V_1)/(T_1) = (P_2V_2)/(T_2)#</mathjax></p> <p>For this equation to work, the units have to be <em>consistent</em>; for example, we can't plug in two values for pressure if one is measured in <mathjax>#"kPa"#</mathjax> and the other in <mathjax>#"atm"#</mathjax>; the units must be the same. </p> <p>Since all the units are consistent, here, solving the problem is straightforward enough: we simply plug in the known variables and solve the equation for the final temperature, <mathjax>#T_2#</mathjax>:</p> <p><mathjax>#T_2 = (T_1P_2V_2)/(P_1V_1) = ((273"K")(38.7cancel("kPa"))(1880cancel("mL")))/((79.0cancel("kPa"))(444cancel("mL")))#</mathjax></p> <p><mathjax>#= color(red)(566"K"#</mathjax></p> <p>rounded to <mathjax>#3#</mathjax> <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a>, the number given in the problem.</p> <p>Thus, the final Kelvin temperature after the changes in pressure and volume is <mathjax>#566"K"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/432327" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="432333" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-31T03:21:05" itemprop="dateCreated"> May 31, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The final temperature will be <mathjax>#"566 K"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This a question involving the <a href="https://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">Combined Gas Law</a>. You can know that this involves the Combined Gas Law, because the variables are pressure, volume, and temperature, and they are the variables in the Combined Gas Law. The equation used to solve questions involving the Combined Gas Law is:</p> <p><mathjax>#(P_1V_1)/T_1=(P_2V_2)/T_2#</mathjax></p> <p>Organize you data.</p> <p><strong>Known</strong></p> <p><mathjax>#P_1="79.0 kPa"#</mathjax></p> <p><mathjax>#V_1="444 mL"#</mathjax></p> <p><mathjax>#T_1="273 K"#</mathjax></p> <p><mathjax>#P_2="38.7 kPa"#</mathjax></p> <p><mathjax>#V_2="1880 mL"#</mathjax></p> <p><strong>Unknown:</strong> <mathjax>#T_2#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation above to isolate <mathjax>#T_2#</mathjax>. Insert the known data into the resulting equation and solve.</p> <p><mathjax>#T_2=(P_2V_2T_1)/(P_1V_1)#</mathjax></p> <p><mathjax>#T_2=(38.7color(red)cancel(color(black)("kPa"))xx1880color(red)cancel(color(black)("mL"))xx273"K")/(79.0color(red)cancel(color(black)("kPa"))xx444color(red)cancel(color(black)("mL")))="566 K"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/432333" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-used-to-measure-gas-pressure-in-a-closed-container"> What is used to measure gas pressure in a closed container? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-tool-is-used-to-measure-gas-pressure"> What tool is used to measure gas pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-units-are-used-to-measure-gas-pressure"> What units are used to measure gas pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-boyle-s-law"> What is Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-an-example-of-a-gas-pressure-practice-problem"> What is an example of a gas pressure practice problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-common-mistakes-students-make-when-measuring-gas-pressure"> What are some common mistakes students make when measuring gas pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-an-example-of-a-boyle-s-law-practice-problem"> What is an example of a Boyle's law practice problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-boyle-s-law-and-charles-law-differ-1"> How do Boyle's law and Charles' law differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-measure-gas-pressure"> How can I measure gas pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-boyle-s-law-affect-the-human-body"> How does Boyle's law affect the human body? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/measuring-gas-pressure"> See all questions in Measuring Gas Pressure </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 15939 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Is gas volume of 444 mL at 273K and 79.0 kPa. What is the final kelvin temperature when the volume of the gas is changed to 1880 mL and the pressure changed to 38.7 kPa?	null
1,869	acf58b1e-6ddd-11ea-8be6-ccda262736ce	https://socratic.org/questions/how-many-moles-are-in-75-0-g-of-dinitrogen-trioxide-n-2o-3	0.99 moles	start physical_unit 10 10 mole mol qc_end physical_unit 10 10 5 6 mass qc_end end	[{"type":"physical unit","value":"Mole [OF] N2O3 [IN] moles"}]	[{"type":"physical unit","value":"0.99 moles"}]	[{"type":"physical unit","value":"Mass [OF] N2O3 [=] \\pu{75.0 g}"}]	<h1 class="questionTitle" itemprop="name">How many moles are in 75.0 g of dinitrogen trioxide, #N_2O_3#?</h1>	null	0.99 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To find the number of moles when given the mass of the substance, we divide the mass of the sample by its molar mass.</p> <p>So, we get:</p> <p><mathjax>#n_(N_2O_3)=(75color(red)cancelcolor(black)"g")/(76.01color(red)cancelcolor(black)"g""/mol")#</mathjax></p> <p><mathjax>#~~0.987 \ "mol"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#~~0.987#</mathjax> moles</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To find the number of moles when given the mass of the substance, we divide the mass of the sample by its molar mass.</p> <p>So, we get:</p> <p><mathjax>#n_(N_2O_3)=(75color(red)cancelcolor(black)"g")/(76.01color(red)cancelcolor(black)"g""/mol")#</mathjax></p> <p><mathjax>#~~0.987 \ "mol"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles are in 75.0 g of dinitrogen trioxide, #N_2O_3#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="629910" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/nam-d"><img alt="" class="" src="https://profilepictures.socratic.org/QG4MnkoER6u99DIDVWKK_787554714770341.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/nam-d"> Nam D. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-06-14T00:26:32" itemprop="dateCreated"> Jun 14, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#~~0.987#</mathjax> moles</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To find the number of moles when given the mass of the substance, we divide the mass of the sample by its molar mass.</p> <p>So, we get:</p> <p><mathjax>#n_(N_2O_3)=(75color(red)cancelcolor(black)"g")/(76.01color(red)cancelcolor(black)"g""/mol")#</mathjax></p> <p><mathjax>#~~0.987 \ "mol"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/629910" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? 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1,870	ab0c1ed4-6ddd-11ea-a1eb-ccda262736ce	https://socratic.org/questions/a-35-00-ml-solution-of-0-2500-m-hf-is-titrated-with-a-standardized-0-1532-m-solu	1.88	start physical_unit 28 29 ph none qc_end physical_unit 28 29 1 2 volume qc_end physical_unit 28 29 5 6 molarity qc_end physical_unit 17 17 13 14 molarity qc_end physical_unit 7 7 39 41 ka qc_end end	[{"type":"physical unit","value":"pH [OF] HF solution"}]	[{"type":"physical unit","value":"1.88"}]	[{"type":"physical unit","value":"Volume [OF] HF solution [=] \\pu{35.00 mL}"},{"type":"physical unit","value":"Molarity [OF] HF solution [=] \\pu{0.2500 M}"},{"type":"physical unit","value":"Molarity [OF] NaOH solution [=] \\pu{0.1532 M}"},{"type":"physical unit","value":"Temperature [OF] NaOH solution [=] \\pu{25 degrees C}"},{"type":"physical unit","value":"Ka [OF] HF [=] \\pu{6.8 × 10^(-4)}"}]	<h1 class="questionTitle" itemprop="name">A 35.00 mL solution of 0.2500 M #HF# is titrated with a standardized 0.1532 M solution of #NaOH# at 25 degrees C. What is the pH of the #HF# solution before titrant is added? For #HF#, the Ka = 6.8 x 10–4 . W</h1>	null	1.88	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>A quick way to do this is to use the the expression:</p> <p><mathjax>#pH=1/2(pK_a-loga)#</mathjax></p> <p>Where <mathjax>#a#</mathjax> is the concentration of the weak acid.</p> <p><mathjax>#K_a=6.8xx10^-4" " "mol/l"#</mathjax></p> <p><mathjax>#:.pK_a=-log[6.8xx10^-4]=3.167#</mathjax></p> <p><mathjax>#:.pH =1/2[3.167-log(0.25)]#</mathjax></p> <p><mathjax>#pH=1/2[3.167-(-0.6)]=1.88#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1.88#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>A quick way to do this is to use the the expression:</p> <p><mathjax>#pH=1/2(pK_a-loga)#</mathjax></p> <p>Where <mathjax>#a#</mathjax> is the concentration of the weak acid.</p> <p><mathjax>#K_a=6.8xx10^-4" " "mol/l"#</mathjax></p> <p><mathjax>#:.pK_a=-log[6.8xx10^-4]=3.167#</mathjax></p> <p><mathjax>#:.pH =1/2[3.167-log(0.25)]#</mathjax></p> <p><mathjax>#pH=1/2[3.167-(-0.6)]=1.88#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A 35.00 mL solution of 0.2500 M #HF# is titrated with a standardized 0.1532 M solution of #NaOH# at 25 degrees C. What is the pH of the #HF# solution before titrant is added? For #HF#, the Ka = 6.8 x 10–4 . W</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#reactions-in-solution" itemprop="url"> <span class="breadcrumb" itemprop="title">Reactions in Solution</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/reactions-in-solution/titration-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">Titration Calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="279844" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/michael-2"><img alt="" class="" src="https://lh3.googleusercontent.com/-gCv6FQRhls0/AAAAAAAAAAI/AAAAAAAAAAA/AAnnY7oOJS05Ylqn3KuDSW0LfnbOk7FezQ/mo/photo.jpg?sz=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/michael-2"> Michael </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-21T17:48:00" itemprop="dateCreated"> Jun 21, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1.88#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>A quick way to do this is to use the the expression:</p> <p><mathjax>#pH=1/2(pK_a-loga)#</mathjax></p> <p>Where <mathjax>#a#</mathjax> is the concentration of the weak acid.</p> <p><mathjax>#K_a=6.8xx10^-4" " "mol/l"#</mathjax></p> <p><mathjax>#:.pK_a=-log[6.8xx10^-4]=3.167#</mathjax></p> <p><mathjax>#:.pH =1/2[3.167-log(0.25)]#</mathjax></p> <p><mathjax>#pH=1/2[3.167-(-0.6)]=1.88#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/279844" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-do-acid-base-titration-calculations"> How do you do acid base titration calculations? 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</a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-titration-of-weak-acid-and-strong-base"> How can I calculate the titration of a weak acid and a strong base? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-make-back-titration-calculations"> How can I make back titration calculations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-titration-affect-molarity"> How does titration affect molarity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-endpoint-of-a-titration-differ-from-the-equivalence-point"> How does the endpoint of a titration differ from the equivalence point? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/reactions-in-solution/titration-calculations"> See all questions in Titration Calculations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 8810 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A 35.00 mL solution of 0.2500 M #HF# is titrated with a standardized 0.1532 M solution of #NaOH# at 25 degrees C. What is the pH of the #HF# solution before titrant is added? For #HF#, the Ka = 6.8 x 10–4 . W	null
1,871	a9c40d86-6ddd-11ea-96e3-ccda262736ce	https://socratic.org/questions/if-water-is-added-to-100-0-ml-of-a-0-150-m-sodium-hydroxide-solution-unit-the-fi	0.10 M	start physical_unit 27 28 molarity mol/l qc_end physical_unit 11 13 5 6 volume qc_end physical_unit 11 13 9 10 molarity qc_end physical_unit 27 28 19 20 volume qc_end end	[{"type":"physical unit","value":"Molarity2 [OF] diluted solution [IN] M"}]	[{"type":"physical unit","value":"0.10 M"}]	[{"type":"physical unit","value":"Volume1 [OF] sodium hydroxide solution [=] \\pu{100.0 mL}"},{"type":"physical unit","value":"Molarity1 [OF] sodium hydroxide solution [=] \\pu{0.150 M}"},{"type":"physical unit","value":"Volume2 [OF] diluted solution [=] \\pu{150.0 mL}"}]	<h1 class="questionTitle" itemprop="name">If water is added to 100.0 mL of a 0.150 M sodium hydroxide solution unit the final volume is 150.0 mL, what will the molarity of the diluted solution be?</h1>	null	0.10 M	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Concentration"="Moles of solute"/"Volume of solution"#</mathjax>, i.e. <mathjax>#C=n/V#</mathjax>.</p> <p>So <mathjax>#n=CV#</mathjax>.</p> <p>Since here <mathjax>#n#</mathjax> is constant:</p> <p><mathjax>#C_1V_1=C_2V_2#</mathjax></p> <p>And <mathjax>#C_2=(C_1V_1)/V_2#</mathjax> (and the RHS clearly has the units of concentration, why?)</p> <p>So <mathjax>#C_2=(100.0cancel(mL)xx0.150molL^-1)/(150cancel(mL))=0.100molL^-1#</mathjax></p> <p>Here, I did not have to convert the <mathjax>#mL#</mathjax> volume to litres, because these clearly cancel out in the calculation to give an answer in <mathjax>#mol*L^-1#</mathjax> as required.........</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The end concentration will be...........<mathjax>#0.100molL^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Concentration"="Moles of solute"/"Volume of solution"#</mathjax>, i.e. <mathjax>#C=n/V#</mathjax>.</p> <p>So <mathjax>#n=CV#</mathjax>.</p> <p>Since here <mathjax>#n#</mathjax> is constant:</p> <p><mathjax>#C_1V_1=C_2V_2#</mathjax></p> <p>And <mathjax>#C_2=(C_1V_1)/V_2#</mathjax> (and the RHS clearly has the units of concentration, why?)</p> <p>So <mathjax>#C_2=(100.0cancel(mL)xx0.150molL^-1)/(150cancel(mL))=0.100molL^-1#</mathjax></p> <p>Here, I did not have to convert the <mathjax>#mL#</mathjax> volume to litres, because these clearly cancel out in the calculation to give an answer in <mathjax>#mol*L^-1#</mathjax> as required.........</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">If water is added to 100.0 mL of a 0.150 M sodium hydroxide solution unit the final volume is 150.0 mL, what will the molarity of the diluted solution be?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="391569" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-15T07:42:30" itemprop="dateCreated"> Mar 15, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The end concentration will be...........<mathjax>#0.100molL^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Concentration"="Moles of solute"/"Volume of solution"#</mathjax>, i.e. <mathjax>#C=n/V#</mathjax>.</p> <p>So <mathjax>#n=CV#</mathjax>.</p> <p>Since here <mathjax>#n#</mathjax> is constant:</p> <p><mathjax>#C_1V_1=C_2V_2#</mathjax></p> <p>And <mathjax>#C_2=(C_1V_1)/V_2#</mathjax> (and the RHS clearly has the units of concentration, why?)</p> <p>So <mathjax>#C_2=(100.0cancel(mL)xx0.150molL^-1)/(150cancel(mL))=0.100molL^-1#</mathjax></p> <p>Here, I did not have to convert the <mathjax>#mL#</mathjax> volume to litres, because these clearly cancel out in the calculation to give an answer in <mathjax>#mol*L^-1#</mathjax> as required.........</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/391569" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li 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in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3840 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	If water is added to 100.0 mL of a 0.150 M sodium hydroxide solution unit the final volume is 150.0 mL, what will the molarity of the diluted solution be?	null
1,872	ac8d15c2-6ddd-11ea-ba82-ccda262736ce	https://socratic.org/questions/if-you-dilute-175-ml-of-a-1-6-m-solution-of-licl-to-1-0-l-what-is-the-new-concen	0.28 M	start physical_unit 11 11 concentration mol/l qc_end physical_unit 11 11 7 8 concentration qc_end physical_unit 9 9 3 4 volume qc_end physical_unit 9 9 13 14 volume qc_end end	[{"type":"physical unit","value":"Concentration2 [OF] LiCl solution [IN] M"}]	[{"type":"physical unit","value":"0.28 M"}]	[{"type":"physical unit","value":"Concentration1 [OF] LiCl solution [=] \\pu{1.6 M}"},{"type":"physical unit","value":"Volume1 [OF] LiCl solution [=] \\pu{175 mL}"},{"type":"physical unit","value":"Volume2 [OF] LiCl solution [=] \\pu{1.0 L}"}]	<h1 class="questionTitle" itemprop="name">If you dilute 175 mL of a 1.6 M solution of LiCl to 1.0 L, what is the new concentration of the solution?</h1>	null	0.28 M	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Concentration"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Moles"/"Volume"#</mathjax>;</p> <p>i.e. <mathjax>#C=n/V#</mathjax> or <mathjax>#n=CxxV#</mathjax></p> <p>So here, we calculate the initial molar quantity of lithium chloride, and then convert this to a concentration by dividing it by its new volume.</p> <p><mathjax>#(0.175Lxx1.60molL^-1)/(1.0L)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.280molL^-1#</mathjax>.</p> <p>What are the concentrations with respect to <mathjax>#Li^+#</mathjax> and <mathjax>#Cl^-#</mathjax>?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The new concentration is <mathjax>#0.280molL^-1#</mathjax> with respect to <mathjax>#LiCl#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Concentration"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Moles"/"Volume"#</mathjax>;</p> <p>i.e. <mathjax>#C=n/V#</mathjax> or <mathjax>#n=CxxV#</mathjax></p> <p>So here, we calculate the initial molar quantity of lithium chloride, and then convert this to a concentration by dividing it by its new volume.</p> <p><mathjax>#(0.175Lxx1.60molL^-1)/(1.0L)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.280molL^-1#</mathjax>.</p> <p>What are the concentrations with respect to <mathjax>#Li^+#</mathjax> and <mathjax>#Cl^-#</mathjax>?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">If you dilute 175 mL of a 1.6 M solution of LiCl to 1.0 L, what is the new concentration of the solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/measuring-concentration" itemprop="url"> <span class="breadcrumb" itemprop="title">Measuring Concentration</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="320113" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-10-10T17:13:21" itemprop="dateCreated"> Oct 10, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The new concentration is <mathjax>#0.280molL^-1#</mathjax> with respect to <mathjax>#LiCl#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Concentration"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Moles"/"Volume"#</mathjax>;</p> <p>i.e. <mathjax>#C=n/V#</mathjax> or <mathjax>#n=CxxV#</mathjax></p> <p>So here, we calculate the initial molar quantity of lithium chloride, and then convert this to a concentration by dividing it by its new volume.</p> <p><mathjax>#(0.175Lxx1.60molL^-1)/(1.0L)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.280molL^-1#</mathjax>.</p> <p>What are the concentrations with respect to <mathjax>#Li^+#</mathjax> and <mathjax>#Cl^-#</mathjax>?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/320113" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-measure-concentration-from-absorbance"> How do you measure concentration from absorbance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" 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the components of the solution formed when 92 g glycerol is mixed... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/measuring-concentration"> See all questions in Measuring Concentration </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 26858 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	If you dilute 175 mL of a 1.6 M solution of LiCl to 1.0 L, what is the new concentration of the solution?	null
1,873	aa7c1668-6ddd-11ea-8b23-ccda262736ce	https://socratic.org/questions/the-solubility-of-an-ionic-compound-mx-molar-mass-of-346g-is-4-63-10-3-g-l-what-	1.80 × 10^(-10)	start physical_unit 21 22 equilibrium_constant_k none qc_end physical_unit 6 6 10 11 molar_mass qc_end physical_unit 6 6 13 16 solubility qc_end end	[{"type":"physical unit","value":"Ksp [OF] the compound"}]	[{"type":"physical unit","value":"1.80 × 10^(-10)"}]	[{"type":"physical unit","value":"Molar mass [OF] MX [=] \\pu{346 g}"},{"type":"physical unit","value":"Solubility [OF] MX [=] \\pu{4.63 × 10^(-3) g/L}"}]	<h1 class="questionTitle" itemprop="name">The solubility of an ionic compound, MX (molar mass of 346g) is #4.63*10^-3 g/L#. What is Ksp for the compound? </h1>	null	1.80 × 10^(-10)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#MX(s) rightleftharpoonsM^(+) + X^(-)#</mathjax></p> <p>This is an equilibrium reaction, and as usual we write the equilibrium expression:</p> <p><mathjax>#K_(sp) = [M^+][X^-]#</mathjax></p> <p><mathjax>#[MX]#</mathjax> does not appear in the expression inasmuch as we cannot speak of the concentration of a solid. </p> <p>Now <mathjax>#S#</mathjax> <mathjax>#=#</mathjax> <mathjax>#4.63xx10^(-3)gL^-1#</mathjax>.</p> <p><mathjax>#=#</mathjax> <mathjax>#(4.63xx10^(-3)g)/(346gmolL^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#1.34xx10^-5molL^-1#</mathjax> with respect to <mathjax>#MX#</mathjax>.</p> <p>Since <mathjax>#[MX]#</mathjax> <mathjax>#=#</mathjax> <mathjax>#[M^+]#</mathjax> <mathjax>#=#</mathjax> <mathjax>#[X^-]#</mathjax>,</p> <p><mathjax>#K_(sp)=[M^+][X^-]#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(1.34xx10^-5)^2#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#K_(sp)~=1.8xx10^-10#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#MX(s) rightleftharpoonsM^(+) + X^(-)#</mathjax></p> <p>This is an equilibrium reaction, and as usual we write the equilibrium expression:</p> <p><mathjax>#K_(sp) = [M^+][X^-]#</mathjax></p> <p><mathjax>#[MX]#</mathjax> does not appear in the expression inasmuch as we cannot speak of the concentration of a solid. </p> <p>Now <mathjax>#S#</mathjax> <mathjax>#=#</mathjax> <mathjax>#4.63xx10^(-3)gL^-1#</mathjax>.</p> <p><mathjax>#=#</mathjax> <mathjax>#(4.63xx10^(-3)g)/(346gmolL^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#1.34xx10^-5molL^-1#</mathjax> with respect to <mathjax>#MX#</mathjax>.</p> <p>Since <mathjax>#[MX]#</mathjax> <mathjax>#=#</mathjax> <mathjax>#[M^+]#</mathjax> <mathjax>#=#</mathjax> <mathjax>#[X^-]#</mathjax>,</p> <p><mathjax>#K_(sp)=[M^+][X^-]#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(1.34xx10^-5)^2#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">The solubility of an ionic compound, MX (molar mass of 346g) is #4.6310^-3 g/L#. What is Ksp for the compound? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/factors-affecting-solubility" itemprop="url"> <span class="breadcrumb" itemprop="title">Factors Affecting Solubility</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="279258" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-20T08:22:43" itemprop="dateCreated"> Jun 20, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#K_(sp)~=1.8xx10^-10#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#MX(s) rightleftharpoonsM^(+) + X^(-)#</mathjax></p> <p>This is an equilibrium reaction, and as usual we write the equilibrium expression:</p> <p><mathjax>#K_(sp) = [M^+][X^-]#</mathjax></p> <p><mathjax>#[MX]#</mathjax> does not appear in the expression inasmuch as we cannot speak of the concentration of a solid. </p> <p>Now <mathjax>#S#</mathjax> <mathjax>#=#</mathjax> <mathjax>#4.63xx10^(-3)gL^-1#</mathjax>.</p> <p><mathjax>#=#</mathjax> <mathjax>#(4.63xx10^(-3)g)/(346gmolL^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#1.34xx10^-5mol*L^-1#</mathjax> with respect to <mathjax>#MX#</mathjax>.</p> <p>Since <mathjax>#[MX]#</mathjax> <mathjax>#=#</mathjax> <mathjax>#[M^+]#</mathjax> <mathjax>#=#</mathjax> <mathjax>#[X^-]#</mathjax>,</p> <p><mathjax>#K_(sp)=[M^+][X^-]#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(1.34xx10^-5)^2#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/279258" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-factors-affect-solubility-in-a-solid-liquid-combination"> What factors affect solubility in a solid-liquid combination? 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What is Ksp for the compound?	null
1,874	a888cd89-6ddd-11ea-8bde-ccda262736ce	https://socratic.org/questions/how-many-joules-of-heat-would-be-required-to-heat-0-5-kg-of-aluminum-by-2k	902 joules	start physical_unit 13 13 heat_energy j qc_end physical_unit 13 13 10 11 mass qc_end physical_unit 13 13 15 16 temperature qc_end end	[{"type":"physical unit","value":"required heat [OF] aluminum [IN] joules"}]	[{"type":"physical unit","value":"902 joules"}]	[{"type":"physical unit","value":"mass [OF] aluminum [=] \\pu{0.5 kg}"},{"type":"physical unit","value":"Increased temperature [OF] aluminum [=] \\pu{2 K}"}]	<h1 class="questionTitle" itemprop="name">How many joules of heat would be required to heat 0.5 kg of aluminum by 2K? </h1>	null	902 joules	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use the equation <mathjax>#Q=mcdeltaT#</mathjax></p> <p>Where <mathjax>#Q=#</mathjax>heat flow, <mathjax>#m=#</mathjax>mass, <mathjax>#c=#</mathjax>specifc heat capacity of <mathjax>#Al#</mathjax> and <mathjax>#deltaT=#</mathjax>change in temperature</p> <p>Just looking up the <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> capcity of aluminum off google, which is <mathjax>#0.902#</mathjax> <mathjax>#J/(gC)#</mathjax></p> <p>Sub values in with their correct units (the change in the kelvin scale is the same in celsius)</p> <p><mathjax>#Q=(500g)0.902(J/(gC))(2#</mathjax> celsius) </p> <p><mathjax>#Q=902#</mathjax> <mathjax>#J#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#902#</mathjax> <mathjax>#J#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use the equation <mathjax>#Q=mcdeltaT#</mathjax></p> <p>Where <mathjax>#Q=#</mathjax>heat flow, <mathjax>#m=#</mathjax>mass, <mathjax>#c=#</mathjax>specifc heat capacity of <mathjax>#Al#</mathjax> and <mathjax>#deltaT=#</mathjax>change in temperature</p> <p>Just looking up the <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> capcity of aluminum off google, which is <mathjax>#0.902#</mathjax> <mathjax>#J/(gC)#</mathjax></p> <p>Sub values in with their correct units (the change in the kelvin scale is the same in celsius)</p> <p><mathjax>#Q=(500g)0.902(J/(gC))(2#</mathjax> celsius) </p> <p><mathjax>#Q=902#</mathjax> <mathjax>#J#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many joules of heat would be required to heat 0.5 kg of aluminum by 2K? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/specific-heat" itemprop="url"> <span class="breadcrumb" itemprop="title">Specific Heat</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="408881" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/david-l-9"><img alt="" class="" src="https://profilepictures.socratic.org/4hB5YwS4T8mCJo4h2jgW_images.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/david-l-9"> David L. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-18T19:05:25" itemprop="dateCreated"> Apr 18, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#902#</mathjax> <mathjax>#J#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use the equation <mathjax>#Q=mcdeltaT#</mathjax></p> <p>Where <mathjax>#Q=#</mathjax>heat flow, <mathjax>#m=#</mathjax>mass, <mathjax>#c=#</mathjax>specifc heat capacity of <mathjax>#Al#</mathjax> and <mathjax>#deltaT=#</mathjax>change in temperature</p> <p>Just looking up the <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> capcity of aluminum off google, which is <mathjax>#0.902#</mathjax> <mathjax>#J/(gC)#</mathjax></p> <p>Sub values in with their correct units (the change in the kelvin scale is the same in celsius)</p> <p><mathjax>#Q=(500g)0.902(J/(gC))(2#</mathjax> celsius) </p> <p><mathjax>#Q=902#</mathjax> <mathjax>#J#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/408881" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-specific-heat-be-used-to-identify-substances"> How can specific heat be used to identify substances? 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1,875	abfb9ebe-6ddd-11ea-b828-ccda262736ce	https://socratic.org/questions/what-is-the-mass-of-a-sample-of-co2-if-it-is-held-at-24-degrees-c-0-544-atm-in-a	2.94 g	start physical_unit 6 8 mass g qc_end physical_unit 6 8 14 16 temperature qc_end physical_unit 6 8 17 18 pressure qc_end physical_unit 6 8 21 22 volume qc_end end	[{"type":"physical unit","value":"Mass [OF] CO2 sample [IN] g"}]	[{"type":"physical unit","value":"2.94 g"}]	[{"type":"physical unit","value":"Temperature [OF] CO2 sample [=] \\pu{24 degrees C}"},{"type":"physical unit","value":"Pressure [OF] CO2 sample [=] \\pu{0.544 atm}"},{"type":"physical unit","value":"Volume [OF] CO2 sample [=] \\pu{3.00 L}"}]	<h1 class="questionTitle" itemprop="name">What is the mass of a sample of CO2 if it is held at 24 degrees C, 0.544 atm in a 3.00L flask?</h1>	null	2.94 g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> (<mathjax>#PV=nRT#</mathjax>).</p> <p>Since the question asks for mass, if we find the number of moles of <mathjax>#CO_2#</mathjax>, we can multiply that by the molar mass to find the mass of the <mathjax>#CO_2#</mathjax> gas.</p> <p>If we want to solve for moles, <mathjax>#n=(PV)/(RT)#</mathjax>.</p> <p>Plug in values: <mathjax>#n=(0.5443.00)/(0.08206(24+273.15))#</mathjax></p> <p>Remember, the temperature must be in Kelvin, not Celsius.</p> <p><mathjax>#n=0.67#</mathjax></p> <p><mathjax>#0.67mol#</mathjax><mathjax>#CO_2#</mathjax><mathjax>#xx(44g)/(1mol)=color(blue)(2.94g)#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>2.94g</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> (<mathjax>#PV=nRT#</mathjax>).</p> <p>Since the question asks for mass, if we find the number of moles of <mathjax>#CO_2#</mathjax>, we can multiply that by the molar mass to find the mass of the <mathjax>#CO_2#</mathjax> gas.</p> <p>If we want to solve for moles, <mathjax>#n=(PV)/(RT)#</mathjax>.</p> <p>Plug in values: <mathjax>#n=(0.5443.00)/(0.08206(24+273.15))#</mathjax></p> <p>Remember, the temperature must be in Kelvin, not Celsius.</p> <p><mathjax>#n=0.67#</mathjax></p> <p><mathjax>#0.67mol#</mathjax><mathjax>#CO_2#</mathjax><mathjax>#xx(44g)/(1mol)=color(blue)(2.94g)#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the mass of a sample of CO2 if it is held at 24 degrees C, 0.544 atm in a 3.00L flask?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/ideal-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Ideal Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="188160" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/mason-m"><img alt="" class="" src="https://profilepictures.socratic.org/U70pu8hUTGGkEuy92fsO_IMG_2585.jpeg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/mason-m"> mason m </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-14T01:43:26" itemprop="dateCreated"> Nov 14, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>2.94g</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> (<mathjax>#PV=nRT#</mathjax>).</p> <p>Since the question asks for mass, if we find the number of moles of <mathjax>#CO_2#</mathjax>, we can multiply that by the molar mass to find the mass of the <mathjax>#CO_2#</mathjax> gas.</p> <p>If we want to solve for moles, <mathjax>#n=(PV)/(RT)#</mathjax>.</p> <p>Plug in values: <mathjax>#n=(0.5443.00)/(0.08206(24+273.15))#</mathjax></p> <p>Remember, the temperature must be in Kelvin, not Celsius.</p> <p><mathjax>#n=0.67#</mathjax></p> <p><mathjax>#0.67mol#</mathjax><mathjax>#CO_2#</mathjax><mathjax>#xx(44g)/(1mol)=color(blue)(2.94g)#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/188160" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-ideal-gas-constant"> How do you 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1,876	a9ad36b8-6ddd-11ea-90dd-ccda262736ce	https://socratic.org/questions/how-many-grams-of-h-2-are-needed-to-produce-11-27-g-of-nh-3	2.00 grams	start physical_unit 4 4 mass g qc_end physical_unit 12 12 9 10 mass qc_end end	[{"type":"physical unit","value":"Mass [OF] H2 [IN] grams"}]	[{"type":"physical unit","value":"2.00 grams"}]	[{"type":"physical unit","value":"Mass [OF] NH3 [=] \\pu{11.27 g}"}]	<h1 class="questionTitle" itemprop="name">How many grams of #H_2# are needed to produce 11.27 g of #NH_3#?</h1>	null	2.00 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#1/2N_2(g) + 3/2H_2(g) rarr NH_3(g)#</mathjax></p> <p><mathjax>#11.27#</mathjax> <mathjax>#g#</mathjax> of ammonia represents <mathjax>#(11.27g)/(17.03g*mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax> <mathjax>#mol#</mathjax>.</p> <p>Whatever this molar quantity is, it is clear from the <a href="http://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> of the reaction that 3/2 equiv of dihydrogen gas were required. How much dinitrogen gas was required?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We need (i) the stoichiometric equation, and (ii) the equivalent mass of dihydrogen.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#1/2N_2(g) + 3/2H_2(g) rarr NH_3(g)#</mathjax></p> <p><mathjax>#11.27#</mathjax> <mathjax>#g#</mathjax> of ammonia represents <mathjax>#(11.27g)/(17.03g*mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax> <mathjax>#mol#</mathjax>.</p> <p>Whatever this molar quantity is, it is clear from the <a href="http://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> of the reaction that 3/2 equiv of dihydrogen gas were required. How much dinitrogen gas was required?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many grams of #H_2# are needed to produce 11.27 g of #NH_3#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="230010" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-02-23T09:10:38" itemprop="dateCreated"> Feb 23, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We need (i) the stoichiometric equation, and (ii) the equivalent mass of dihydrogen.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#1/2N_2(g) + 3/2H_2(g) rarr NH_3(g)#</mathjax></p> <p><mathjax>#11.27#</mathjax> <mathjax>#g#</mathjax> of ammonia represents <mathjax>#(11.27g)/(17.03g*mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax> <mathjax>#mol#</mathjax>.</p> <p>Whatever this molar quantity is, it is clear from the <a href="http://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> of the reaction that 3/2 equiv of dihydrogen gas were required. How much dinitrogen gas was required?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/230010" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="230016" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-02-23T09:47:26" itemprop="dateCreated"> Feb 23, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>2.001 g hydrogen gas is needed to produce 11.27 g ammonia if nitrogen gas is present in excess.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Start with a balanced equation.</p> <p><mathjax>#"3H"_2+"N"_2#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"2NH"_3"#</mathjax></p> <p>Since the question concerns the mass of hydrogen gas needed, the assumption is that nitrogen gas is in excess.</p> <p>The molar masses of <mathjax>#"H"_2"#</mathjax> and <mathjax>#"NH"_3"#</mathjax> are needed.</p> <p><mathjax>#"H"_2":#</mathjax> <mathjax>#"2.01588 g/mol"#</mathjax><br/> <a href="http://pubchem.ncbi.nlm.nih.gov/compound/783" rel="nofollow" target="_blank">http://pubchem.ncbi.nlm.nih.gov/compound/783</a></p> <p><mathjax>#"NH"_3"#</mathjax> <mathjax>#"17.03052 g/mol"#</mathjax><br/> <a href="http://pubchem.ncbi.nlm.nih.gov/compound/222#section=Top" rel="nofollow" target="_blank">http://pubchem.ncbi.nlm.nih.gov/compound/222#section=Top</a></p> <p>We will be making the following conversions: mass <mathjax>#"NH"_3"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"mol NH"_3"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"mol H"_2"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"mass H"_2"#</mathjax></p> <ol> <li> <p>Determine moles of <mathjax>#"NH"_3"#</mathjax> by dividing the given mass by its molar mass.</p> </li> <li> <p>Determine moles of <mathjax>#"H"_2"#</mathjax> by multiplying <a href="http://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio from the balanced equation between <mathjax>#"H"_2"#</mathjax> and <mathjax>#"NH"_3"#</mathjax> with moles <mathjax>#"H"_2"#</mathjax> in the numerator. <mathjax>#(3"mol H"_2)/(2"mol NH"_3)#</mathjax></p> </li> <li> <p>Determine mass of <mathjax>#"H"_2"#</mathjax> by multiplying moles <mathjax>#"H"_2"#</mathjax> by its molar mass.</p> </li> </ol> <p><mathjax>#11.27"g NH"_3xx(1"mol NH"_3)/(17.03052"g NH"_3)xx(3"mol H"_2)/(2"mol NH"_3)xx(2.01588"g H"_2)/(1"mol H"_2)="2.001 g H"_2"#</mathjax> (rounded to four significant figures)</p> <p>2.001 g hydrogen gas is needed to produce 11.27 g ammonia if nitrogen gas is present in excess.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/230016" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What is stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ab82402bf342f48d93ac6"> Question #93ac6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-we-study-stoichiometry"> Why do we study stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-naoh-is-produced-from-1-20-x-102-grams-of-na2o-na2o-h2o-2-naoh"> How many grams of NaOH is produced from #1.20 x 10^2# grams of #Na_2O#? #Na_2O + H_2O -> 2NaOH# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-na2o-are-required-to-produce-1-60-x-102-grams-of-naoh-na2o-h2o"> How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? Na2O + H2O ---> 2 NaOH </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-mass-of-iron-is-needed-to-react-with-16-0-grams-of-sulfur-8-fe-s8-8-fes"> What mass of iron is needed to react with 16.0 grams of sulfur? 8 Fe + S8 ---> 8 FeS </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/according-to-8-fe-s8-8-fes-how-many-grams-of-fes-are-produced"> According to 8 Fe + S8 ---> 8 FeS How many grams of FeS are produced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/12-00-moles-of-naclo3-will-produce-how-many-grams-of-o2-2-naclo3-2-nacl-3-o2"> 12.00 moles of NaClO3 will produce how many grams of O2? 2 NaClO3 ---> 2 NaCl + 3 O2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-nacl-are-produced-when-80-0-grams-of-o2-are-produced-2-naclo3-"> How many grams of NaCl are produced when 80.0 grams of O2 are produced? 2 NaClO3 ---> 2 NaCl + 3 O2 </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/stoichiometry"> See all questions in Stoichiometry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 32548 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many grams of #H_2# are needed to produce 11.27 g of #NH_3#?	null
1,877	a9fbb9c9-6ddd-11ea-bf38-ccda262736ce	https://socratic.org/questions/what-is-the-chemical-formula-for-nitrogen	N2	start chemical_formula qc_end substance 6 6 qc_end end	[{"type":"other","value":"Chemical Formula [OF] nitrogen [IN] default"}]	[{"type":"chemical equation","value":"N2"}]	[{"type":"substance name","value":"Nitrogen"}]	<h1 class="questionTitle" itemprop="name">What is the chemical formula for nitrogen? </h1>	null	N2	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The chemical symbol for nitrogen is found on <a href="http://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a>.</p> <p>The chemical formula for nitrogen gas is <mathjax>#"N"_2"#</mathjax>. Nitrogen gas is one of the diatomic <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a>, in which one molecule consists of two atoms of the same element bonded by one or more covalent bonds. In the case of <mathjax>#"N"_2"#</mathjax>, the two nitrogen atoms are bonded by a triple covalent bond.</p> <p><img alt="http://centros.edu.xunta.es/iesames/webantiga/webfq/EUSECTSUSO/chem_phys_bac/Chemistry_2/chemical_bonding.htm" src="https://useruploads.socratic.org/8GyJH4qsRHOSUHAermmS_image052.jpg"/> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The chemical symbol for nitrogen is N. The chemical formula for nitrogen gas is <mathjax>#"N"_2"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The chemical symbol for nitrogen is found on <a href="http://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a>.</p> <p>The chemical formula for nitrogen gas is <mathjax>#"N"_2"#</mathjax>. Nitrogen gas is one of the diatomic <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a>, in which one molecule consists of two atoms of the same element bonded by one or more covalent bonds. In the case of <mathjax>#"N"_2"#</mathjax>, the two nitrogen atoms are bonded by a triple covalent bond.</p> <p><img alt="http://centros.edu.xunta.es/iesames/webantiga/webfq/EUSECTSUSO/chem_phys_bac/Chemistry_2/chemical_bonding.htm" src="https://useruploads.socratic.org/8GyJH4qsRHOSUHAermmS_image052.jpg"/> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the chemical formula for nitrogen? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="190825" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-19T23:04:19" itemprop="dateCreated"> Nov 19, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The chemical symbol for nitrogen is N. The chemical formula for nitrogen gas is <mathjax>#"N"_2"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The chemical symbol for nitrogen is found on <a href="http://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a>.</p> <p>The chemical formula for nitrogen gas is <mathjax>#"N"_2"#</mathjax>. Nitrogen gas is one of the diatomic <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a>, in which one molecule consists of two atoms of the same element bonded by one or more covalent bonds. In the case of <mathjax>#"N"_2"#</mathjax>, the two nitrogen atoms are bonded by a triple covalent bond.</p> <p><img alt="http://centros.edu.xunta.es/iesames/webantiga/webfq/EUSECTSUSO/chem_phys_bac/Chemistry_2/chemical_bonding.htm" src="https://useruploads.socratic.org/8GyJH4qsRHOSUHAermmS_image052.jpg"/> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/190825" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molecular-formula-of-a-compound"> How do you find molecular formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-diamond"> What is the chemical formula of a diamond? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-carbohydrate"> What is the chemical formula of a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-valproic-acid"> What is the empirical formula for valproic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-of-magnesium-oxide"> What is the empirical formula of magnesium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-empirical-formula-not-double-that-of-the-monosaccharides"> Why is the empirical formula not double that of the monosaccharides? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5331180502bf342f40b5c3b5"> Question #5c3b5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-molecular-formula-represents-a-carbohydrate"> What molecular formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-of-vinegar"> What is the molecular formula of vinegar? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/empirical-and-molecular-formulas"> See all questions in Empirical and Molecular Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 41859 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the chemical formula for nitrogen?	null
1,878	aca8fd40-6ddd-11ea-a884-ccda262736ce	https://socratic.org/questions/how-many-grams-of-oxygen-can-be-produced-by-completely-decomposing-10-g-of-mercu	0.74 grams	start physical_unit 4 4 mass g qc_end physical_unit 14 15 11 12 mass qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Mass [OF] oxygen [IN] grams"}]	[{"type":"physical unit","value":"0.74 grams"}]	[{"type":"physical unit","value":"Mass [OF] mercury(II) oxide [=] \\pu{10 g}"},{"type":"other","value":"Completely decompose."}]	<h1 class="questionTitle" itemprop="name">How many grams of oxygen can be produced by completely decomposing 10 g of mercury(II) oxide?</h1>	null	0.74 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Given the equation above, half an equiv dioxygen gas is evolved per equiv of mercuric oxide.</p> <p>Moles of <mathjax>#HgO#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(10g)/(216.6gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.0461#</mathjax> <mathjax>#mol#</mathjax>.</p> <p>There are thus <mathjax>#(0.0461cancel(mol))/2xx32.00gcancel(mol^-1)#</mathjax> <mathjax>#"dioxygen gas"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??g#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2HgO(s)+Deltararr Hg(l) + O_2(g)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Given the equation above, half an equiv dioxygen gas is evolved per equiv of mercuric oxide.</p> <p>Moles of <mathjax>#HgO#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(10g)/(216.6gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.0461#</mathjax> <mathjax>#mol#</mathjax>.</p> <p>There are thus <mathjax>#(0.0461cancel(mol))/2xx32.00gcancel(mol^-1)#</mathjax> <mathjax>#"dioxygen gas"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??g#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many grams of oxygen can be produced by completely decomposing 10 g of mercury(II) oxide?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="232129" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-02-27T19:09:56" itemprop="dateCreated"> Feb 27, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2HgO(s)+Deltararr Hg(l) + O_2(g)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Given the equation above, half an equiv dioxygen gas is evolved per equiv of mercuric oxide.</p> <p>Moles of <mathjax>#HgO#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(10g)/(216.6gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.0461#</mathjax> <mathjax>#mol#</mathjax>.</p> <p>There are thus <mathjax>#(0.0461cancel(mol))/2xx32.00gcancel(mol^-1)#</mathjax> <mathjax>#"dioxygen gas"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??g#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/232129" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" 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1,879	aae33f06-6ddd-11ea-859c-ccda262736ce	https://socratic.org/questions/what-volume-of-a-6-84m-sodium-bromide-solution-would-be-needed-to-make-588ml-of-	158.18 mL	start physical_unit 6 8 volume ml qc_end physical_unit 6 8 14 15 volume qc_end physical_unit 6 8 18 19 molarity qc_end physical_unit 6 8 4 5 molarity qc_end end	[{"type":"physical unit","value":"Volume1 [OF] sodium bromide solution [IN] mL"}]	[{"type":"physical unit","value":"158.18 mL"}]	[{"type":"physical unit","value":"Volume2 [OF] sodium bromide solution [=] \\pu{588 mL}"},{"type":"physical unit","value":"Molarity2 [OF] sodium bromide solution [=] \\pu{1.84 M}"},{"type":"physical unit","value":"Molarity1 [OF] sodium bromide solution [=] \\pu{6.84 M}"}]	<h1 class="questionTitle" itemprop="name">What volume of a 6.84M sodium bromide solution would be needed to make 588mL of a 1.84M solution by dilution?</h1>	null	158.18 mL	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Whenever you are dealing with a dilution, (going from a higher concentration to a lower concentration), use the equation below:<br/> <img alt="slideplayer.com" src="https://useruploads.socratic.org/49DzrjFQxWgNFk9uoM5w_slide_28.jpg"/> </p> <p>Let's determine our known and unknown variables:</p> <p><mathjax>#color(coral)("Knowns:"#</mathjax></p> <ul> <li>Initial <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a></li> <li>Final Volume</li> <li>Final Molarity</li> </ul> <p><mathjax>#color(magenta)("Unknowns:"#</mathjax></p> <ul> <li>Initial Volume</li> </ul> <p>Next, we rearrange the equation to solve for <mathjax>#V_1#</mathjax> by dividing by <mathjax>#M_1#</mathjax> on both sides of the equation:</p> <p><mathjax>#V_1=(M_2xxV_2)/M_1#</mathjax></p> <p>Plug in the known values and solve for your unknown:<br/> <mathjax>#V_1=(1.84cancel"M"xx588mL)/(6.84cancel"M")#</mathjax></p> <p>Thus, </p> <p><mathjax>#V_1 = 158 mL#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The initial volume is <mathjax>#158 mL#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Whenever you are dealing with a dilution, (going from a higher concentration to a lower concentration), use the equation below:<br/> <img alt="slideplayer.com" src="https://useruploads.socratic.org/49DzrjFQxWgNFk9uoM5w_slide_28.jpg"/> </p> <p>Let's determine our known and unknown variables:</p> <p><mathjax>#color(coral)("Knowns:"#</mathjax></p> <ul> <li>Initial <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a></li> <li>Final Volume</li> <li>Final Molarity</li> </ul> <p><mathjax>#color(magenta)("Unknowns:"#</mathjax></p> <ul> <li>Initial Volume</li> </ul> <p>Next, we rearrange the equation to solve for <mathjax>#V_1#</mathjax> by dividing by <mathjax>#M_1#</mathjax> on both sides of the equation:</p> <p><mathjax>#V_1=(M_2xxV_2)/M_1#</mathjax></p> <p>Plug in the known values and solve for your unknown:<br/> <mathjax>#V_1=(1.84cancel"M"xx588mL)/(6.84cancel"M")#</mathjax></p> <p>Thus, </p> <p><mathjax>#V_1 = 158 mL#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What volume of a 6.84M sodium bromide solution would be needed to make 588mL of a 1.84M solution by dilution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/dilution-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">Dilution Calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="293116" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/kayla-14"><img alt="" class="" src="https://profilepictures.socratic.org/OvMTWaamQPWcqLIkUNnG_793604964071127.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/kayla-14"> Kayla </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-29T01:39:50" itemprop="dateCreated"> Jul 29, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The initial volume is <mathjax>#158 mL#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Whenever you are dealing with a dilution, (going from a higher concentration to a lower concentration), use the equation below:<br/> <img alt="slideplayer.com" src="https://useruploads.socratic.org/49DzrjFQxWgNFk9uoM5w_slide_28.jpg"/> </p> <p>Let's determine our known and unknown variables:</p> <p><mathjax>#color(coral)("Knowns:"#</mathjax></p> <ul> <li>Initial <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a></li> <li>Final Volume</li> <li>Final Molarity</li> </ul> <p><mathjax>#color(magenta)("Unknowns:"#</mathjax></p> <ul> <li>Initial Volume</li> </ul> <p>Next, we rearrange the equation to solve for <mathjax>#V_1#</mathjax> by dividing by <mathjax>#M_1#</mathjax> on both sides of the equation:</p> <p><mathjax>#V_1=(M_2xxV_2)/M_1#</mathjax></p> <p>Plug in the known values and solve for your unknown:<br/> <mathjax>#V_1=(1.84cancel"M"xx588mL)/(6.84cancel"M")#</mathjax></p> <p>Thus, </p> <p><mathjax>#V_1 = 158 mL#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/293116" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-concentration-from-absorbance"> 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href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What volume of a 6.84M sodium bromide solution would be needed to make 588mL of a 1.84M solution by dilution?	null
1,880	abfef814-6ddd-11ea-971b-ccda262736ce	https://socratic.org/questions/56f99e3211ef6b139b956a45	2.51 × 10^24	start physical_unit 2 2 number none qc_end physical_unit 9 9 5 6 mass qc_end end	[{"type":"physical unit","value":"Number [OF] atoms"}]	[{"type":"physical unit","value":"2.51 × 10^24"}]	[{"type":"physical unit","value":"Mass [OF] water [=] \\pu{25.0 g}"}]	<h1 class="questionTitle" itemprop="name">How many atoms in a #25.0*g# mass of water?</h1>	null	2.51 × 10^24	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Moles of water"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(25.0g)/("18.01 "gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#1.39mol.#</mathjax></p> <p>In each mole of water there are <mathjax>#3#</mathjax> <mathjax>#mol#</mathjax> atoms.</p> <p>So <mathjax>#"Number of atoms"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#1.39molxxN_Axx3" atoms "mol^-1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#4.16xxN_A " atoms"#</mathjax>.</p> <p><mathjax>#N_A = "Avogadro's number"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#6.022xx10^23#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We calculate the number of moles of water, and then multiply this number by <mathjax>#3N_A#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Moles of water"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(25.0g)/("18.01 "gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#1.39mol.#</mathjax></p> <p>In each mole of water there are <mathjax>#3#</mathjax> <mathjax>#mol#</mathjax> atoms.</p> <p>So <mathjax>#"Number of atoms"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#1.39molxxN_Axx3" atoms "mol^-1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#4.16xxN_A " atoms"#</mathjax>.</p> <p><mathjax>#N_A = "Avogadro's number"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#6.022xx10^23#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many atoms in a #25.0g# mass of water?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="246457" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-28T21:22:39" itemprop="dateCreated"> Mar 28, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We calculate the number of moles of water, and then multiply this number by <mathjax>#3N_A#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Moles of water"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(25.0g)/("18.01 "gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#1.39mol.#</mathjax></p> <p>In each mole of water there are <mathjax>#3#</mathjax> <mathjax>#mol#</mathjax> atoms.</p> <p>So <mathjax>#"Number of atoms"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#1.39*molxxN_Axx3" atoms "mol^-1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#4.16xxN_A " atoms"#</mathjax>.</p> <p><mathjax>#N_A = "Avogadro's number"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#6.022xx10^23#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/246457" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div 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1,881	ac5f4e30-6ddd-11ea-8f4c-ccda262736ce	https://socratic.org/questions/59133da47c014954e74c427d	12.61	start physical_unit 6 7 ph none qc_end physical_unit 6 7 12 13 [oh-] qc_end end	[{"type":"physical unit","value":"pH [OF] the aqueous solution"}]	[{"type":"physical unit","value":"12.61"}]	[{"type":"physical unit","value":"[HO-] [OF] the aqueous solution [=] \\pu{0.041 mol/L}"}]	<h1 class="questionTitle" itemprop="name">What is the #pH# of an aqueous solution in which #[HO^-]=0.041molL^-1#?</h1>	null	12.61	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We know that in aqueous solution under standard conditions.....</p> <p><mathjax>#pH+pOH=14#</mathjax>.</p> <p>And <mathjax>#pOH=-log_(10)[HO^-]#</mathjax>; so here <mathjax>#pOH=-log_10(0.041)=#</mathjax></p> <p><mathjax>#-log_(10)0.041=-(-1.39)=1.39#</mathjax>.</p> <p>And thus <mathjax>#pH=14-pOH=12.6#</mathjax></p> <p>So is this solution acid or alkaline?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#pH=12.6#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We know that in aqueous solution under standard conditions.....</p> <p><mathjax>#pH+pOH=14#</mathjax>.</p> <p>And <mathjax>#pOH=-log_(10)[HO^-]#</mathjax>; so here <mathjax>#pOH=-log_10(0.041)=#</mathjax></p> <p><mathjax>#-log_(10)0.041=-(-1.39)=1.39#</mathjax>.</p> <p>And thus <mathjax>#pH=14-pOH=12.6#</mathjax></p> <p>So is this solution acid or alkaline?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the #pH# of an aqueous solution in which #[HO^-]=0.041molL^-1#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/the-ph-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">pH</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="420989" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-10T16:32:05" itemprop="dateCreated"> May 10, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#pH=12.6#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We know that in aqueous solution under standard conditions.....</p> <p><mathjax>#pH+pOH=14#</mathjax>.</p> <p>And <mathjax>#pOH=-log_(10)[HO^-]#</mathjax>; so here <mathjax>#pOH=-log_10(0.041)=#</mathjax></p> <p><mathjax>#-log_(10)0.041=-(-1.39)=1.39#</mathjax>.</p> <p>And thus <mathjax>#pH=14-pOH=12.6#</mathjax></p> <p>So is this solution acid or alkaline?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/420989" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-pka"> How do you determine pH from pKa? 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1,882	a8c9529e-6ddd-11ea-8041-ccda262736ce	https://socratic.org/questions/571817627c01496639f7fde7	3 CuCl2(aq) + 2 Al(s) -> 2 AlCl3(aq) + 3 Cu(s)	start chemical_equation qc_end chemical_equation 5 5 qc_end substance 7 8 qc_end substance 11 12 qc_end chemical_equation 14 14 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the reaction"}]	[{"type":"chemical equation","value":"3 CuCl2(aq) + 2 Al(s) -> 2 AlCl3(aq) + 3 Cu(s)"}]	[{"type":"chemical equation","value":"CuCl2"},{"type":"substance name","value":"Aluminum metal"},{"type":"substance name","value":"Copper metal"},{"type":"chemical equation","value":"AlCl3"}]	<h1 class="questionTitle" itemprop="name">What is the reaction between #CuCl_2#, and aluminum metal to give copper metal and #AlCl_3#?</h1>	null	3 CuCl2(aq) + 2 Al(s) -> 2 AlCl3(aq) + 3 Cu(s)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#Al rarr Al^(3+) + 3e^-#</mathjax>; oxidation.</p> <p><mathjax>#CuCl_2(aq) +2e^(-) rarr Cu(s)darr + 2Cl^-#</mathjax>; reduction.</p> <p>We cross-mulitply to remove the electrons.</p> <p><mathjax>#3CuCl_2(aq) +2Al(s) rarr 2AlCl_3(aq) + 3Cu(s)darr#</mathjax></p> <p>A sheet of aluminum place in copper sulfate solution would rapidly acquire a coppery surface as the copper metal reduced. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#3CuCl_2(aq) +2Al(s) rarr 2AlCl_3(aq) + 3Cu(s)darr#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#Al rarr Al^(3+) + 3e^-#</mathjax>; oxidation.</p> <p><mathjax>#CuCl_2(aq) +2e^(-) rarr Cu(s)darr + 2Cl^-#</mathjax>; reduction.</p> <p>We cross-mulitply to remove the electrons.</p> <p><mathjax>#3CuCl_2(aq) +2Al(s) rarr 2AlCl_3(aq) + 3Cu(s)darr#</mathjax></p> <p>A sheet of aluminum place in copper sulfate solution would rapidly acquire a coppery surface as the copper metal reduced. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the reaction between #CuCl_2#, and aluminum metal to give copper metal and #AlCl_3#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="256842" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-04-21T06:47:19" itemprop="dateCreated"> Apr 21, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#3CuCl_2(aq) +2Al(s) rarr 2AlCl_3(aq) + 3Cu(s)darr#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#Al rarr Al^(3+) + 3e^-#</mathjax>; oxidation.</p> <p><mathjax>#CuCl_2(aq) +2e^(-) rarr Cu(s)darr + 2Cl^-#</mathjax>; reduction.</p> <p>We cross-mulitply to remove the electrons.</p> <p><mathjax>#3CuCl_2(aq) +2Al(s) rarr 2AlCl_3(aq) + 3Cu(s)darr#</mathjax></p> <p>A sheet of aluminum place in copper sulfate solution would rapidly acquire a coppery surface as the copper metal reduced. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/256842" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-equation-for-photosynthesis"> What is the chemical equation for photosynthesis? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-know-the-relative-number-of-grams-of-each-substance-used-or-produced-w"> How can I know the relative number of grams of each substance used or produced with chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-know-the-relative-number-of-moles-of-each-substance-with-chemical-equa"> How can I know the relative number of moles of each substance with chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-chemical-equations-illustrate-that-atoms-are-conserved-1"> How do chemical equations illustrate that atoms are conserved? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-know-the-formula-of-the-reactants-and-products-with-chemical-equations"> How can I know the formula of the reactants and products with chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-potassium-metal-and-chlorine-gas-combi"> How can I balance this chemical equations? 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1,883	aa602969-6ddd-11ea-8df9-ccda262736ce	https://socratic.org/questions/592b4973b72cff02377d39b5	0.28 moles	start physical_unit 4 5 mole mol qc_end physical_unit 12 13 9 10 mass qc_end physical_unit 19 19 16 17 mass qc_end end	[{"type":"physical unit","value":"Mole [OF] hydrogen gas [IN] moles"}]	[{"type":"physical unit","value":"0.28 moles"}]	[{"type":"physical unit","value":"Mass [OF] sodium metal [=] \\pu{20 g}"},{"type":"physical unit","value":"Mass [OF] water [=] \\pu{10 g}"}]	<h1 class="questionTitle" itemprop="name">How many moles of hydrogen gas are produced when #"20 g"# of sodium metal react with #"10 g"# of water?</h1>	null	0.28 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Start by writing the balanced chemical equation that describes this reaction</p> <blockquote> <p><mathjax>#"Na"_ ((s)) + color(blue)(2)"H"_ 2"O"_ ((l)) -> 2"NaOH"_ ((aq)) + "H"_ (2(g)) uarr#</mathjax></p> </blockquote> <p>Sodium and water react in a <mathjax>#1:color(blue)(2)#</mathjax> <strong>mole ratio</strong>, so the next thing to do here is to convert the given masses to <em>moles</em> by using the <strong>molar mass</strong> of sodium and the <strong>molar mass</strong> of water, respectively.</p> <blockquote> <p><mathjax>#20 color(red)(cancel(color(black)("g"))) * ("1 mole Na")/(23.0color(red)(cancel(color(black)("g")))) = "0.870 moles Na"#</mathjax></p> <p><mathjax>#10 color(red)(cancel(color(black)("g"))) * ("1 mole H"_2"O")/(18.015color(red)(cancel(color(black)("g")))) = "0.555 moles H"_2"O"#</mathjax></p> </blockquote> <p>Now, in order for <strong>all the moles</strong> of sodium to take part in the reaction, you need</p> <blockquote> <p><mathjax>#0.870 color(red)(cancel(color(black)("moles Na"))) * (color(blue)(2)color(white)(.)"moles H"_2"O")/(1color(red)(cancel(color(black)("mole Na")))) = "1.74 moles H"_2"O"#</mathjax></p> </blockquote> <p>As you can see, you have</p> <blockquote> <p><mathjax>#overbrace("0.555 moles H"_2"O")^(color(purple)("what is available")) " "< " "overbrace("1.74 moles H"_2"O")^(color(purple)("what is needed"))#</mathjax></p> </blockquote> <p>This means that water will act as a <strong><a href="https://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a></strong>, i.e. it will be completely consumed <em>before</em> all the moles of sodium will get the chance to take part in the reaction. </p> <p>So, you can say that the reaction will consume <mathjax>#0.555#</mathjax> <strong>moles</strong> of water. </p> <p>To find the number of moles of hydrogen gas produced, use the <mathjax>#color(blue)(2):1#</mathjax> <strong>mole ratio</strong> that exists between water and hydrogen gas.</p> <blockquote> <p><mathjax>#0.555 color(red)(cancel(color(black)("moles H"_2"O"))) * "1 mole H"_2/(color(blue)(2)color(red)(cancel(color(black)("moles H"_2"O")))) = "0.2775 moles H"_2#</mathjax></p> </blockquote> <p>Finally, to convert this to <em>grams</em>, use the <strong>molar mass</strong> of hydrogen gas</p> <blockquote> <p><mathjax>#0.2775 color(red)(cancel(color(black)("moles H"_2))) * "2.016 g"/(1color(red)(cancel(color(black)("mole H"_2)))) = color(darkgreen)(ul(color(black)("0.6 g")))#</mathjax></p> </blockquote> <p>The answer must be rounded to one <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figure</a></strong>, the number of sig figs you have for your values. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"0.6 g H"_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Start by writing the balanced chemical equation that describes this reaction</p> <blockquote> <p><mathjax>#"Na"_ ((s)) + color(blue)(2)"H"_ 2"O"_ ((l)) -> 2"NaOH"_ ((aq)) + "H"_ (2(g)) uarr#</mathjax></p> </blockquote> <p>Sodium and water react in a <mathjax>#1:color(blue)(2)#</mathjax> <strong>mole ratio</strong>, so the next thing to do here is to convert the given masses to <em>moles</em> by using the <strong>molar mass</strong> of sodium and the <strong>molar mass</strong> of water, respectively.</p> <blockquote> <p><mathjax>#20 color(red)(cancel(color(black)("g"))) * ("1 mole Na")/(23.0color(red)(cancel(color(black)("g")))) = "0.870 moles Na"#</mathjax></p> <p><mathjax>#10 color(red)(cancel(color(black)("g"))) * ("1 mole H"_2"O")/(18.015color(red)(cancel(color(black)("g")))) = "0.555 moles H"_2"O"#</mathjax></p> </blockquote> <p>Now, in order for <strong>all the moles</strong> of sodium to take part in the reaction, you need</p> <blockquote> <p><mathjax>#0.870 color(red)(cancel(color(black)("moles Na"))) * (color(blue)(2)color(white)(.)"moles H"_2"O")/(1color(red)(cancel(color(black)("mole Na")))) = "1.74 moles H"_2"O"#</mathjax></p> </blockquote> <p>As you can see, you have</p> <blockquote> <p><mathjax>#overbrace("0.555 moles H"_2"O")^(color(purple)("what is available")) " "< " "overbrace("1.74 moles H"_2"O")^(color(purple)("what is needed"))#</mathjax></p> </blockquote> <p>This means that water will act as a <strong><a href="https://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a></strong>, i.e. it will be completely consumed <em>before</em> all the moles of sodium will get the chance to take part in the reaction. </p> <p>So, you can say that the reaction will consume <mathjax>#0.555#</mathjax> <strong>moles</strong> of water. </p> <p>To find the number of moles of hydrogen gas produced, use the <mathjax>#color(blue)(2):1#</mathjax> <strong>mole ratio</strong> that exists between water and hydrogen gas.</p> <blockquote> <p><mathjax>#0.555 color(red)(cancel(color(black)("moles H"_2"O"))) * "1 mole H"_2/(color(blue)(2)color(red)(cancel(color(black)("moles H"_2"O")))) = "0.2775 moles H"_2#</mathjax></p> </blockquote> <p>Finally, to convert this to <em>grams</em>, use the <strong>molar mass</strong> of hydrogen gas</p> <blockquote> <p><mathjax>#0.2775 color(red)(cancel(color(black)("moles H"_2))) * "2.016 g"/(1color(red)(cancel(color(black)("mole H"_2)))) = color(darkgreen)(ul(color(black)("0.6 g")))#</mathjax></p> </blockquote> <p>The answer must be rounded to one <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figure</a></strong>, the number of sig figs you have for your values. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles of hydrogen gas are produced when #"20 g"# of sodium metal react with #"10 g"# of water?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/limiting-reagent" itemprop="url"> <span class="breadcrumb" itemprop="title">Limiting Reagent</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="431628" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-29T23:27:12" itemprop="dateCreated"> May 29, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"0.6 g H"_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Start by writing the balanced chemical equation that describes this reaction</p> <blockquote> <p><mathjax>#"Na"_ ((s)) + color(blue)(2)"H"_ 2"O"_ ((l)) -> 2"NaOH"_ ((aq)) + "H"_ (2(g)) uarr#</mathjax></p> </blockquote> <p>Sodium and water react in a <mathjax>#1:color(blue)(2)#</mathjax> <strong>mole ratio</strong>, so the next thing to do here is to convert the given masses to <em>moles</em> by using the <strong>molar mass</strong> of sodium and the <strong>molar mass</strong> of water, respectively.</p> <blockquote> <p><mathjax>#20 color(red)(cancel(color(black)("g"))) * ("1 mole Na")/(23.0color(red)(cancel(color(black)("g")))) = "0.870 moles Na"#</mathjax></p> <p><mathjax>#10 color(red)(cancel(color(black)("g"))) * ("1 mole H"_2"O")/(18.015color(red)(cancel(color(black)("g")))) = "0.555 moles H"_2"O"#</mathjax></p> </blockquote> <p>Now, in order for <strong>all the moles</strong> of sodium to take part in the reaction, you need</p> <blockquote> <p><mathjax>#0.870 color(red)(cancel(color(black)("moles Na"))) * (color(blue)(2)color(white)(.)"moles H"_2"O")/(1color(red)(cancel(color(black)("mole Na")))) = "1.74 moles H"_2"O"#</mathjax></p> </blockquote> <p>As you can see, you have</p> <blockquote> <p><mathjax>#overbrace("0.555 moles H"_2"O")^(color(purple)("what is available")) " "< " "overbrace("1.74 moles H"_2"O")^(color(purple)("what is needed"))#</mathjax></p> </blockquote> <p>This means that water will act as a <strong><a href="https://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a></strong>, i.e. it will be completely consumed <em>before</em> all the moles of sodium will get the chance to take part in the reaction. </p> <p>So, you can say that the reaction will consume <mathjax>#0.555#</mathjax> <strong>moles</strong> of water. </p> <p>To find the number of moles of hydrogen gas produced, use the <mathjax>#color(blue)(2):1#</mathjax> <strong>mole ratio</strong> that exists between water and hydrogen gas.</p> <blockquote> <p><mathjax>#0.555 color(red)(cancel(color(black)("moles H"_2"O"))) * "1 mole H"_2/(color(blue)(2)color(red)(cancel(color(black)("moles H"_2"O")))) = "0.2775 moles H"_2#</mathjax></p> </blockquote> <p>Finally, to convert this to <em>grams</em>, use the <strong>molar mass</strong> of hydrogen gas</p> <blockquote> <p><mathjax>#0.2775 color(red)(cancel(color(black)("moles H"_2))) * "2.016 g"/(1color(red)(cancel(color(black)("mole H"_2)))) = color(darkgreen)(ul(color(black)("0.6 g")))#</mathjax></p> </blockquote> <p>The answer must be rounded to one <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figure</a></strong>, the number of sig figs you have for your values. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/431628" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-how-much-of-the-excess-reactant-is-left-over-also-how-do-yo"> How do you determine 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1,884	abc607ee-6ddd-11ea-a126-ccda262736ce	https://socratic.org/questions/to-what-volume-should-5-0-g-of-kcl-be-diluted-in-order-to-prepare-0-25-m-solutio	0.27 L	start physical_unit 16 16 volume l qc_end physical_unit 7 7 14 15 molarity qc_end physical_unit 7 7 4 5 mass qc_end end	[{"type":"physical unit","value":"Volume [OF] KCl solution [IN] L"}]	[{"type":"physical unit","value":"0.27 L"}]	[{"type":"physical unit","value":"Molarity [OF] KCl solution [=] \\pu{0.25 M}"},{"type":"physical unit","value":"Mass [OF] KCl [=] \\pu{5.0 g}"}]	<h1 class="questionTitle" itemprop="name">To what volume should 5.0 g of #KCl# be diluted in order to prepare 0.25 M solution? </h1>	null	0.27 L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We are looking for volume and are given a mass and a <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a>.</p> <p>Note:</p> <p><mathjax>#M=(mol_(solute))/(Liters_(solution))#</mathjax></p> <p>Rearranging this equation to solve for <strong>volume</strong>:</p> <p><mathjax>#L_(solution)=(mol_(solute))/M#</mathjax></p> <p>We have <strong>M</strong>, but we need <mathjax>#mol_(solute)#</mathjax>. To get this, we use the molecular weight of KCl, which is:</p> <p><mathjax>#74.55 g_(KCl)/(mol_(KCl))#</mathjax></p> <p>To get the moles of KCl:</p> <p><mathjax>#5.0 g_(KCl)(1 mol_(KCl))/(74.55g_(KCl))=0.067mol_(KCl)#</mathjax></p> <p>Finally, plug back into the equation for <mathjax>#Liters_(solution)#</mathjax>:<br/> <mathjax>#L_(solution)=(mol_(solute))/M#</mathjax><br/> <mathjax>#L_(solution)=(0.067mol_(KCl))/(0.25(mol_(KCl))/(L_(solution))#</mathjax><br/> <mathjax>#L_(solution)=0.27 L#</mathjax></p> <p><strong>Note:</strong> This is the total <em>solution</em> volume, not the volume of <em><a href="http://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a></em>. Total volume of <strong><a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> + solvent</strong> is the <strong>solution</strong> volume.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.27 L</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We are looking for volume and are given a mass and a <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a>.</p> <p>Note:</p> <p><mathjax>#M=(mol_(solute))/(Liters_(solution))#</mathjax></p> <p>Rearranging this equation to solve for <strong>volume</strong>:</p> <p><mathjax>#L_(solution)=(mol_(solute))/M#</mathjax></p> <p>We have <strong>M</strong>, but we need <mathjax>#mol_(solute)#</mathjax>. To get this, we use the molecular weight of KCl, which is:</p> <p><mathjax>#74.55 g_(KCl)/(mol_(KCl))#</mathjax></p> <p>To get the moles of KCl:</p> <p><mathjax>#5.0 g_(KCl)(1 mol_(KCl))/(74.55g_(KCl))=0.067mol_(KCl)#</mathjax></p> <p>Finally, plug back into the equation for <mathjax>#Liters_(solution)#</mathjax>:<br/> <mathjax>#L_(solution)=(mol_(solute))/M#</mathjax><br/> <mathjax>#L_(solution)=(0.067mol_(KCl))/(0.25(mol_(KCl))/(L_(solution))#</mathjax><br/> <mathjax>#L_(solution)=0.27 L#</mathjax></p> <p><strong>Note:</strong> This is the total <em>solution</em> volume, not the volume of <em><a href="http://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a></em>. Total volume of <strong><a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> + solvent</strong> is the <strong>solution</strong> volume.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">To what volume should 5.0 g of #KCl# be diluted in order to prepare 0.25 M solution? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="235504" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/werkereng"><img alt="" class="" src="https://profilepictures.socratic.org/95y9KzkiQiiyHWa9IZ3c_Profile%20Picture%20-%20Socratic.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/werkereng"> Walker P </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-05T19:23:36" itemprop="dateCreated"> Mar 5, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.27 L</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We are looking for volume and are given a mass and a <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a>.</p> <p>Note:</p> <p><mathjax>#M=(mol_(solute))/(Liters_(solution))#</mathjax></p> <p>Rearranging this equation to solve for <strong>volume</strong>:</p> <p><mathjax>#L_(solution)=(mol_(solute))/M#</mathjax></p> <p>We have <strong>M</strong>, but we need <mathjax>#mol_(solute)#</mathjax>. To get this, we use the molecular weight of KCl, which is:</p> <p><mathjax>#74.55 g_(KCl)/(mol_(KCl))#</mathjax></p> <p>To get the moles of KCl:</p> <p><mathjax>#5.0 g_(KCl)(1 mol_(KCl))/(74.55g_(KCl))=0.067mol_(KCl)#</mathjax></p> <p>Finally, plug back into the equation for <mathjax>#Liters_(solution)#</mathjax>:<br/> <mathjax>#L_(solution)=(mol_(solute))/M#</mathjax><br/> <mathjax>#L_(solution)=(0.067mol_(KCl))/(0.25(mol_(KCl))/(L_(solution))#</mathjax><br/> <mathjax>#L_(solution)=0.27 L#</mathjax></p> <p><strong>Note:</strong> This is the total <em>solution</em> volume, not the volume of <em><a href="http://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a></em>. Total volume of <strong><a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> + solvent</strong> is the <strong>solution</strong> volume.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/235504" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-morality-be-used-as-a-conversion-factor"> How can molarity be used as a conversion factor? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-high-can-molarity-be"> How high can molarity be? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-molarity-change-with-temperature"> How does molarity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molarity-of-a-solution"> How do you find molarity of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-10-naoh"> What is the molarity of 10 NaOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-3-hydrogen-peroxide"> What is the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 19603 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	To what volume should 5.0 g of #KCl# be diluted in order to prepare 0.25 M solution?	null
1,885	a9ec50a2-6ddd-11ea-b3f1-ccda262736ce	https://socratic.org/questions/the-specific-heat-of-ice-is-0-5-calories-gram-c-20-grams-of-ice-will-require-how	10 calories	start physical_unit 4 4 energy cal qc_end physical_unit 4 4 6 9 specific_heat qc_end physical_unit 4 4 10 11 mass qc_end physical_unit 4 4 23 24 temperature qc_end end	[{"type":"physical unit","value":"Required energy [OF] ice [IN] calories"}]	[{"type":"physical unit","value":"10 calories"}]	[{"type":"physical unit","value":"Specific heat [OF] ice [=] \\pu{0.5 calories/(gram * ℃)}"},{"type":"physical unit","value":"Mass [OF] ice [=] \\pu{20 grams}"},{"type":"physical unit","value":"Raised temperature [OF] ice [=] \\pu{1 ℃}"}]	<h1 class="questionTitle" itemprop="name">The specific heat of ice is 0.5 calories/gram°C? 20 grams of ice will require how many calories to raise the temperature 1°C?</h1>	null	10 calories	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The problem provides you with the <strong><a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a></strong> of ice, which is said to be equal to</p> <blockquote> <p><mathjax>#c_"ice" = "0.5 cal g"^(-1)""^@"C"^(-1) = 0.5color(white)(a) "cal"/("g" ""^@"C")#</mathjax></p> </blockquote> <p>As you can see, specific heat is expressed in units of energy, in this case <em>calories</em>, per <strong>gram Celsius</strong>, which means that a substance's specific heat tells you how much energy is needed to increase the temperature of <mathjax>#"1 g"#</mathjax> of said substance by <mathjax>#1^@"C"#</mathjax>. </p> <p>For ice, you know that if you provide <mathjax>#0.5#</mathjax> <strong>calories</strong> of heat to <mathjax>#"1 g"#</mathjax> of ice you will increase its temperature by <mathjax>#1^@"C"#</mathjax>. </p> <p>This is how much heat you need to supply to a given sample of ice <strong>for every</strong> gram and <strong>for every</strong> <mathjax>#1^@"C"#</mathjax> increase in temperature. </p> <p>To increase the temperature of <mathjax>#"20 g"#</mathjax> of ice by <mathjax>#1^@"C"#</mathjax>, you need to provide it with <mathjax>#"0.5 cal"#</mathjax> <strong>for every gram</strong>. This will cause its temperature to increase by <mathjax>#1^@"C"#</mathjax>. </p> <blockquote> <p><mathjax>#20 color(red)(cancel(color(black)("g"))) * ("0.5 cal"""^@"C"^(-1))/(1color(red)(cancel(color(black)("g")))) = "10 cal"""^@"C"^(-1)#</mathjax></p> </blockquote> <p>For a <mathjax>#1^@"C"#</mathjax> increase in temperature, you have</p> <blockquote> <p><mathjax>#1 color(red)(cancel(color(black)(""^@"C"))) * "10 cal"/(1color(red)(cancel(color(black)(""^@"C")))) = color(green)(\|bar(ul(color(white)(a/a)color(black)("10 cal")color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>As you can see, to increase the <em>temperature</em> of this sample by more than <mathjax>#1^@"C"#</mathjax> you need to provide it with <mathjax>#"10 cal"#</mathjax> of heat <strong>for every</strong> <mathjax>#1^@"C"#</mathjax> increase in temperature. </p> <p>For example, to increase the temperature of <mathjax>#"20 g"#</mathjax> of ice by <mathjax>#3^@"C"#</mathjax>, you need to provide it with</p> <blockquote> <p><mathjax>#3 color(red)(cancel(color(black)(""^@"C"))) * overbrace("10 cal"/(1color(red)(cancel(color(black)(""^@"C")))))^color(blue)("amount of heat needed for 1"""^@"C increase") = "30 cal"#</mathjax></p> </blockquote> <p>Therefore, you can say that in order to increase the temperature of <mathjax>#"20 g"#</mathjax> of ice by <mathjax>#3^@"C"#</mathjax>, you need to provide it with <mathjax>#"30 cal"#</mathjax> of heat. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"10 cal"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The problem provides you with the <strong><a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a></strong> of ice, which is said to be equal to</p> <blockquote> <p><mathjax>#c_"ice" = "0.5 cal g"^(-1)""^@"C"^(-1) = 0.5color(white)(a) "cal"/("g" ""^@"C")#</mathjax></p> </blockquote> <p>As you can see, specific heat is expressed in units of energy, in this case <em>calories</em>, per <strong>gram Celsius</strong>, which means that a substance's specific heat tells you how much energy is needed to increase the temperature of <mathjax>#"1 g"#</mathjax> of said substance by <mathjax>#1^@"C"#</mathjax>. </p> <p>For ice, you know that if you provide <mathjax>#0.5#</mathjax> <strong>calories</strong> of heat to <mathjax>#"1 g"#</mathjax> of ice you will increase its temperature by <mathjax>#1^@"C"#</mathjax>. </p> <p>This is how much heat you need to supply to a given sample of ice <strong>for every</strong> gram and <strong>for every</strong> <mathjax>#1^@"C"#</mathjax> increase in temperature. </p> <p>To increase the temperature of <mathjax>#"20 g"#</mathjax> of ice by <mathjax>#1^@"C"#</mathjax>, you need to provide it with <mathjax>#"0.5 cal"#</mathjax> <strong>for every gram</strong>. This will cause its temperature to increase by <mathjax>#1^@"C"#</mathjax>. </p> <blockquote> <p><mathjax>#20 color(red)(cancel(color(black)("g"))) * ("0.5 cal"""^@"C"^(-1))/(1color(red)(cancel(color(black)("g")))) = "10 cal"""^@"C"^(-1)#</mathjax></p> </blockquote> <p>For a <mathjax>#1^@"C"#</mathjax> increase in temperature, you have</p> <blockquote> <p><mathjax>#1 color(red)(cancel(color(black)(""^@"C"))) * "10 cal"/(1color(red)(cancel(color(black)(""^@"C")))) = color(green)(\|bar(ul(color(white)(a/a)color(black)("10 cal")color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>As you can see, to increase the <em>temperature</em> of this sample by more than <mathjax>#1^@"C"#</mathjax> you need to provide it with <mathjax>#"10 cal"#</mathjax> of heat <strong>for every</strong> <mathjax>#1^@"C"#</mathjax> increase in temperature. </p> <p>For example, to increase the temperature of <mathjax>#"20 g"#</mathjax> of ice by <mathjax>#3^@"C"#</mathjax>, you need to provide it with</p> <blockquote> <p><mathjax>#3 color(red)(cancel(color(black)(""^@"C"))) * overbrace("10 cal"/(1color(red)(cancel(color(black)(""^@"C")))))^color(blue)("amount of heat needed for 1"""^@"C increase") = "30 cal"#</mathjax></p> </blockquote> <p>Therefore, you can say that in order to increase the temperature of <mathjax>#"20 g"#</mathjax> of ice by <mathjax>#3^@"C"#</mathjax>, you need to provide it with <mathjax>#"30 cal"#</mathjax> of heat. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">The specific heat of ice is 0.5 calories/gram°C? 20 grams of ice will require how many calories to raise the temperature 1°C?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/specific-heat" itemprop="url"> <span class="breadcrumb" itemprop="title">Specific Heat</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="297976" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-08-12T00:45:37" itemprop="dateCreated"> Aug 12, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"10 cal"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The problem provides you with the <strong><a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a></strong> of ice, which is said to be equal to</p> <blockquote> <p><mathjax>#c_"ice" = "0.5 cal g"^(-1)""^@"C"^(-1) = 0.5color(white)(a) "cal"/("g" ""^@"C")#</mathjax></p> </blockquote> <p>As you can see, specific heat is expressed in units of energy, in this case <em>calories</em>, per <strong>gram Celsius</strong>, which means that a substance's specific heat tells you how much energy is needed to increase the temperature of <mathjax>#"1 g"#</mathjax> of said substance by <mathjax>#1^@"C"#</mathjax>. </p> <p>For ice, you know that if you provide <mathjax>#0.5#</mathjax> <strong>calories</strong> of heat to <mathjax>#"1 g"#</mathjax> of ice you will increase its temperature by <mathjax>#1^@"C"#</mathjax>. </p> <p>This is how much heat you need to supply to a given sample of ice <strong>for every</strong> gram and <strong>for every</strong> <mathjax>#1^@"C"#</mathjax> increase in temperature. </p> <p>To increase the temperature of <mathjax>#"20 g"#</mathjax> of ice by <mathjax>#1^@"C"#</mathjax>, you need to provide it with <mathjax>#"0.5 cal"#</mathjax> <strong>for every gram</strong>. This will cause its temperature to increase by <mathjax>#1^@"C"#</mathjax>. </p> <blockquote> <p><mathjax>#20 color(red)(cancel(color(black)("g"))) * ("0.5 cal"""^@"C"^(-1))/(1color(red)(cancel(color(black)("g")))) = "10 cal"""^@"C"^(-1)#</mathjax></p> </blockquote> <p>For a <mathjax>#1^@"C"#</mathjax> increase in temperature, you have</p> <blockquote> <p><mathjax>#1 color(red)(cancel(color(black)(""^@"C"))) * "10 cal"/(1color(red)(cancel(color(black)(""^@"C")))) = color(green)(\|bar(ul(color(white)(a/a)color(black)("10 cal")color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>As you can see, to increase the <em>temperature</em> of this sample by more than <mathjax>#1^@"C"#</mathjax> you need to provide it with <mathjax>#"10 cal"#</mathjax> of heat <strong>for every</strong> <mathjax>#1^@"C"#</mathjax> increase in temperature. </p> <p>For example, to increase the temperature of <mathjax>#"20 g"#</mathjax> of ice by <mathjax>#3^@"C"#</mathjax>, you need to provide it with</p> <blockquote> <p><mathjax>#3 color(red)(cancel(color(black)(""^@"C"))) * overbrace("10 cal"/(1color(red)(cancel(color(black)(""^@"C")))))^color(blue)("amount of heat needed for 1"""^@"C increase") = "30 cal"#</mathjax></p> </blockquote> <p>Therefore, you can say that in order to increase the temperature of <mathjax>#"20 g"#</mathjax> of ice by <mathjax>#3^@"C"#</mathjax>, you need to provide it with <mathjax>#"30 cal"#</mathjax> of heat. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/297976" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-specific-heat-be-used-to-identify-substances"> How can specific heat be used to identify substances? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-heat-capacity-of-a-lead-sinker-be-determined"> How can the heat capacity of a lead sinker be determined? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-the-specific-heats-of-metals-compare-with-water"> How do the specific heats of metals compare with water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-specific-heat-change-with-temperature"> How does specific heat change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/dissolving-some-potassium-bromide-in-200cm3-of-water-leads-to-a-decrease-in-temp"> Dissolving some potassium bromide in 200cm3 of water leads to a decrease in temperature of 3oC.... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-heat-capacity-larger-for-polymers"> Is heat capacity larger for polymers? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-heat-capacity-an-extensive-property"> Why is heat capacity an extensive property? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-does-heat-capacity-change-with-temperature"> Why does heat capacity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-specific-heat-measured-in"> What is specific heat measured in? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-heat-capacity-measured-in"> What is heat capacity measured in? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/specific-heat"> See all questions in Specific Heat </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 9965 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	The specific heat of ice is 0.5 calories/gram°C? 20 grams of ice will require how many calories to raise the temperature 1°C?	null
1,886	ab229a9a-6ddd-11ea-a9a8-ccda262736ce	https://socratic.org/questions/what-is-the-oxidation-number-of-nitrogen-in-the-nitrate-ion	+5	start physical_unit 6 6 oxidation_number none qc_end substance 9 10 qc_end end	[{"type":"physical unit","value":"Oxidation number [OF] nitrogen"}]	[{"type":"physical unit","value":"+5"}]	[{"type":"substance name","value":"Nitrate ion"}]	<h1 class="questionTitle" itemprop="name">What is the oxidation number of nitrogen in the nitrate ion?</h1>	null	+5	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Here are some of the rules for solving oxidation state of any element:</p> <p>(1) The total charge of a stable compound is always equal to zero (meaning no charge). </p> <p>For example, the <mathjax>#H_2O#</mathjax> molecule exists as a neutrally charged substance. </p> <p>(2) If the substance is an ion (either there is a positive or negative charge) the total oxidation state of the ion is the charge (i.e. oxidation state of <mathjax>#NO_3^"-1"#</mathjax> ion is -1).</p> <p>(3) All <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> from Group 1A has an oxidation state of +1 (e.g. <mathjax>#Na^"+1"#</mathjax>, <mathjax>#Li^"+1"#</mathjax>). All Group 2A and 3A <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> have an oxidation state of +2 and +3, respectively. (e.g. <mathjax>#Ca^"2+"#</mathjax>, <mathjax>#Mg^"2+"#</mathjax>, <mathjax>#Al^"3+"#</mathjax>)</p> <p>(4) Oxygen always have a charge -2 except for peroxide ion (<mathjax>#O_2^"2-"#</mathjax>) which has a charge of -1.</p> <p>(5) Hydrogen always have a charge of +1 if it is bonded with a non-metal (as in the case of <mathjax>#HCl#</mathjax>) and always have a -1 charge if it is bonded with a metal (as in <mathjax>#AlH_3#</mathjax>).</p> <p>So for your problem, according to rule 2, the overall oxidation state of <mathjax>#NO_3^-#</mathjax> is -1.</p> <p><mathjax>#NO_3^-#</mathjax> = -1</p> <p>According to rule 4, the <mathjax>#O#</mathjax> atom should have a -2 charge. But since the oxygen has a subscript in the formula, we need to multiply the charge by the subscript.</p> <p><mathjax>#color (red) x#</mathjax> + [(-2) (3)] = -1 where <mathjax>#color (red) x#</mathjax> is the oxidation state on <mathjax>#N#</mathjax> atom</p> <p>solving for <mathjax>#color (red) x#</mathjax>,</p> <p><mathjax>#color (red) x#</mathjax> + (-6) = -1</p> <p><mathjax>#color (red) x#</mathjax> = -1 + (+6)</p> <p><mathjax>#color (red) x#</mathjax> = +5</p> <p>Therefore, answer is <mathjax>#N^"5+"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>+5</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Here are some of the rules for solving oxidation state of any element:</p> <p>(1) The total charge of a stable compound is always equal to zero (meaning no charge). </p> <p>For example, the <mathjax>#H_2O#</mathjax> molecule exists as a neutrally charged substance. </p> <p>(2) If the substance is an ion (either there is a positive or negative charge) the total oxidation state of the ion is the charge (i.e. oxidation state of <mathjax>#NO_3^"-1"#</mathjax> ion is -1).</p> <p>(3) All <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> from Group 1A has an oxidation state of +1 (e.g. <mathjax>#Na^"+1"#</mathjax>, <mathjax>#Li^"+1"#</mathjax>). All Group 2A and 3A <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> have an oxidation state of +2 and +3, respectively. (e.g. <mathjax>#Ca^"2+"#</mathjax>, <mathjax>#Mg^"2+"#</mathjax>, <mathjax>#Al^"3+"#</mathjax>)</p> <p>(4) Oxygen always have a charge -2 except for peroxide ion (<mathjax>#O_2^"2-"#</mathjax>) which has a charge of -1.</p> <p>(5) Hydrogen always have a charge of +1 if it is bonded with a non-metal (as in the case of <mathjax>#HCl#</mathjax>) and always have a -1 charge if it is bonded with a metal (as in <mathjax>#AlH_3#</mathjax>).</p> <p>So for your problem, according to rule 2, the overall oxidation state of <mathjax>#NO_3^-#</mathjax> is -1.</p> <p><mathjax>#NO_3^-#</mathjax> = -1</p> <p>According to rule 4, the <mathjax>#O#</mathjax> atom should have a -2 charge. But since the oxygen has a subscript in the formula, we need to multiply the charge by the subscript.</p> <p><mathjax>#color (red) x#</mathjax> + [(-2) (3)] = -1 where <mathjax>#color (red) x#</mathjax> is the oxidation state on <mathjax>#N#</mathjax> atom</p> <p>solving for <mathjax>#color (red) x#</mathjax>,</p> <p><mathjax>#color (red) x#</mathjax> + (-6) = -1</p> <p><mathjax>#color (red) x#</mathjax> = -1 + (+6)</p> <p><mathjax>#color (red) x#</mathjax> = +5</p> <p>Therefore, answer is <mathjax>#N^"5+"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the oxidation number of nitrogen in the nitrate ion?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#electrochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Electrochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/electrochemistry/oxidation-and-reduction-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Oxidation and Reduction Reactions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="182801" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/nikka-c"><img alt="" class="" src="https://profilepictures.socratic.org/AQ8VOCyTM1J7U0TvIWhw_nkahara.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/nikka-c"> Nikka C. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-04T10:43:58" itemprop="dateCreated"> Nov 4, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>+5</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Here are some of the rules for solving oxidation state of any element:</p> <p>(1) The total charge of a stable compound is always equal to zero (meaning no charge). </p> <p>For example, the <mathjax>#H_2O#</mathjax> molecule exists as a neutrally charged substance. </p> <p>(2) If the substance is an ion (either there is a positive or negative charge) the total oxidation state of the ion is the charge (i.e. oxidation state of <mathjax>#NO_3^"-1"#</mathjax> ion is -1).</p> <p>(3) All <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> from Group 1A has an oxidation state of +1 (e.g. <mathjax>#Na^"+1"#</mathjax>, <mathjax>#Li^"+1"#</mathjax>). All Group 2A and 3A <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> have an oxidation state of +2 and +3, respectively. (e.g. <mathjax>#Ca^"2+"#</mathjax>, <mathjax>#Mg^"2+"#</mathjax>, <mathjax>#Al^"3+"#</mathjax>)</p> <p>(4) Oxygen always have a charge -2 except for peroxide ion (<mathjax>#O_2^"2-"#</mathjax>) which has a charge of -1.</p> <p>(5) Hydrogen always have a charge of +1 if it is bonded with a non-metal (as in the case of <mathjax>#HCl#</mathjax>) and always have a -1 charge if it is bonded with a metal (as in <mathjax>#AlH_3#</mathjax>).</p> <p>So for your problem, according to rule 2, the overall oxidation state of <mathjax>#NO_3^-#</mathjax> is -1.</p> <p><mathjax>#NO_3^-#</mathjax> = -1</p> <p>According to rule 4, the <mathjax>#O#</mathjax> atom should have a -2 charge. But since the oxygen has a subscript in the formula, we need to multiply the charge by the subscript.</p> <p><mathjax>#color (red) x#</mathjax> + [(-2) (3)] = -1 where <mathjax>#color (red) x#</mathjax> is the oxidation state on <mathjax>#N#</mathjax> atom</p> <p>solving for <mathjax>#color (red) x#</mathjax>,</p> <p><mathjax>#color (red) x#</mathjax> + (-6) = -1</p> <p><mathjax>#color (red) x#</mathjax> = -1 + (+6)</p> <p><mathjax>#color (red) x#</mathjax> = +5</p> <p>Therefore, answer is <mathjax>#N^"5+"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/182801" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-balance-equations-with-charges"> How to balance equations for reduction/oxidation reaction? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-an-electode-reaction-has-dssolved-oxygen-as-a-reactant-is-the-electrode-an-an"> If an electode reaction has dssolved oxygen as a reactant, is the electrode an anode or a cathode? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-an-electrode-reaction-has-dissolved-oxygen-as-a-reactant-is-the-electrode-and"> If an electrode reaction has dissolved oxygen as a reactant, is the electrode and anode or a cathode? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-balanced-equation-represents-a-redox-reaction-2"> What balanced equation represents a redox reaction? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-redox-reactions-involved-in-electrolysis"> How are redox reactions involved in electrolysis? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-oxidation-reduction-reactions-coupled"> Why are oxidation reduction reactions coupled? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-do-oxidation-reduction-reactions-involve"> What do oxidation reduction reactions involve? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-reduction-reactions-used-for"> What are reduction reactions used for? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-calx-mean-in-oxidation-reduction-reactions"> What does "calx" mean in oxidation reduction reactions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-the-reduced-components-in-this-reaction-zn-2h-zn-2-h2"> What are the reduced components in this reaction? Zn + 2H(+) → Zn(2+) + H2 </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/electrochemistry/oxidation-and-reduction-reactions"> See all questions in Oxidation and Reduction Reactions </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 14780 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the oxidation number of nitrogen in the nitrate ion?	null
1,887	ad194398-6ddd-11ea-817f-ccda262736ce	https://socratic.org/questions/what-is-the-volume-of-1-mole-of-any-gas-at-stp	22.71 L	start physical_unit 8 9 volume l qc_end physical_unit 8 9 5 6 mole qc_end c_other STP qc_end end	[{"type":"physical unit","value":"Volume [OF] any gas [IN] L"}]	[{"type":"physical unit","value":"22.71 L"}]	[{"type":"physical unit","value":"Mole [OF] any gas [=] \\pu{1 mole}"},{"type":"other","value":"STP"}]	<h1 class="questionTitle" itemprop="name">What is the volume of 1 mole of any gas at STP? </h1>	null	22.71 L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In reality the 22.4 liters per mole is only an approximation for many gases. Ideal gases actually do not exists though inert gases behave very close to ideal <a href="https://socratic.org/chemistry/the-behavior-of-gases/gas-laws">gas laws</a>. The interactions between molecules do affect the behavior of the gases making small changes to the ideal value of 22.4 liters for an ideal gas. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>22.4 liters for an ideal gas at STP</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In reality the 22.4 liters per mole is only an approximation for many gases. Ideal gases actually do not exists though inert gases behave very close to ideal <a href="https://socratic.org/chemistry/the-behavior-of-gases/gas-laws">gas laws</a>. The interactions between molecules do affect the behavior of the gases making small changes to the ideal value of 22.4 liters for an ideal gas. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the volume of 1 mole of any gas at STP? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp" itemprop="url"> <span class="breadcrumb" itemprop="title">Molar Volume of a Gas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="370259" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/david-drayer"><img alt="" class="" src="https://graph.facebook.com/10206723679871989/picture?height=50&width=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/david-drayer"> David Drayer </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-01-28T04:08:11" itemprop="dateCreated"> Jan 28, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>22.4 liters for an ideal gas at STP</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In reality the 22.4 liters per mole is only an approximation for many gases. Ideal gases actually do not exists though inert gases behave very close to ideal <a href="https://socratic.org/chemistry/the-behavior-of-gases/gas-laws">gas laws</a>. The interactions between molecules do affect the behavior of the gases making small changes to the ideal value of 22.4 liters for an ideal gas. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/370259" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="374863" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-02-08T00:46:51" itemprop="dateCreated"> Feb 8, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The volume of 1 mol of an <em>ideal</em> gas at STP is 22.71 L.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The IUPAC defines STP as a temperature of 0 °C and a pressure of 1 bar.</p> <p>We can use the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a> to calculate the molar volume of an ideal gas.</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(\|color(white)(a/a) PV=nRTcolor(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>We can rearrange this to give</p> <blockquote> <blockquote> <p><mathjax>#V = (nRT)/P#</mathjax></p> </blockquote> </blockquote> <p>∴ <mathjax>#V = (1 color(red)(cancel(color(black)("mol"))) × "0.083 14" color(red)(cancel(color(black)("bar")))·"L"·color(red)(cancel(color(black)("K"^"-1""mol"^"-1"))) × 273.15 color(red)(cancel(color(black)("K"))))/(1 color(red)(cancel(color(black)("bar")))) = "22.71 L"#</mathjax></p> <blockquote></blockquote> <p>In practice, <strong>NO</strong> real gas is an ideal gas.</p> <p>Even helium, which should be closest to an ideal gas, has a molar volume at STP of 22.73 L.</p> <p>In most cases, however, the deviations are so small under "ordinary" conditions that we can treat the gases <strong>as if</strong> they were ideal.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/374863" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-stoichiometric-ratios-relate-to-molar-volume-of-a-gas"> How do stoichiometric ratios relate to molar volume of a gas? 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</a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5361f75702bf3429040e0599"> What is the difference between STP and NTP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-volume-of-25-moles-of-oxygen-o2-gas"> What is the volume of .25 moles of oxygen (O2) Gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-would-knowing-the-molar-volume-of-a-gas-be-important"> Why would knowing the molar volume of a gas be important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-22-4-liters-called-the-molar-volume-of-a-gas"> Why is 22.4 liters called the molar volume of a gas? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp"> See all questions in Molar Volume of a Gas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 62928 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the volume of 1 mole of any gas at STP?	null
1,888	a8a59a1e-6ddd-11ea-a8ce-ccda262736ce	https://socratic.org/questions/consider-a-0-00050-molar-solution-of-methanol-ch3oh-in-water-express-the-concent	16.2 parts per million	start physical_unit 6 6 concentration ppm qc_end physical_unit 7 7 2 3 mole qc_end substance 9 9 qc_end end	[{"type":"physical unit","value":"Concentration [OF] methanol [IN] parts per million"}]	[{"type":"physical unit","value":"16.2 parts per million"}]	[{"type":"physical unit","value":"Mole [OF] CH3OH solution [=] \\pu{0.00050 molar}"},{"type":"substance name","value":"Water"}]	<h1 class="questionTitle" itemprop="name"> Consider a 0.00050 molar solution of methanol, #"CH"_3"OH"#, in water. Express the concentration of methanol in parts per million?</h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>Consider a 0.00050 molar solution of methanol (CH3OH) in water.<br/> Express the concentration of methanol in parts per million.</p></div> </h2> </div> </div>	16.2 parts per million	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>For <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> that contain very, very small amounts of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a>, usually called <em>trace amounts</em>, you can use <strong>Parts Per Million</strong>, or <strong>ppm</strong>, to express their concentration. </p> <p>In essence, <strong>ppm</strong> denotes <em>one part solute</em> <strong>for every</strong> <mathjax>#10^6#</mathjax> <em>parts <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a></em>. This means that you can find a solution's concentration in ppm by using </p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a)"ppm" = "grams of solute"/"grams of solvent" xx 10^6color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>Now, your methanol solution is said to have a <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></strong> of <mathjax>#"0.00050 mol L"^(-1)#</mathjax>. This means that you get <mathjax>#0.00050#</mathjax> <strong>moles</strong> of solute <strong>per liter</strong> of solution. </p> <p>To keep the calculations simple, let's assume that you have a <mathjax>#"1-L"#</mathjax> sample of this solution. </p> <p>The first thing to do here is use methanol's <strong>molar mass</strong> to convert the number of moles to <em>grams</em> </p> <blockquote> <p><mathjax>#0.00050 color(red)(cancel(color(black)("moles CH"_3"OH"))) * "32.04 g"/(1color(red)(cancel(color(black)("mole CH"_3"OH")))) = "0.0162 g CH"_3"OH"#</mathjax></p> </blockquote> <p>Because the solution contains <strong>such a small amount</strong> of methanol, you can assume that its <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a></strong> will be equal to that of pure water. Since no information about water's density was given, you can assume it to be equal to <mathjax>#"1 g mL"^(-1)#</mathjax>. </p> <p>This means that the sample will have a mass of </p> <blockquote> <p><mathjax>#1 color(red)(cancel(color(black)("L"))) * (10^3color(red)(cancel(color(black)("mL"))))/(1color(red)(cancel(color(black)("L")))) * "1 g"/(1 color(red)(cancel(color(black)("mL")))) = 10^3"g"#</mathjax></p> </blockquote> <p>As you can see, you can safely assume that the mass of the <em>solvent</em> is approximately equal to that of the <em>solution</em>. </p> <p>This means that the concentration in ppm will be equal to </p> <blockquote> <p><mathjax>#"ppm" = (0.0162color(red)(cancel(color(black)("g"))))/(10^3color(red)(cancel(color(black)("g")))) * 10^6 = color(green)(\|bar(ul(color(white)(a/a)"16.2 ppm"color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>I'll leave the answer rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"16.2 ppm"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>For <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> that contain very, very small amounts of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a>, usually called <em>trace amounts</em>, you can use <strong>Parts Per Million</strong>, or <strong>ppm</strong>, to express their concentration. </p> <p>In essence, <strong>ppm</strong> denotes <em>one part solute</em> <strong>for every</strong> <mathjax>#10^6#</mathjax> <em>parts <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a></em>. This means that you can find a solution's concentration in ppm by using </p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a)"ppm" = "grams of solute"/"grams of solvent" xx 10^6color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>Now, your methanol solution is said to have a <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></strong> of <mathjax>#"0.00050 mol L"^(-1)#</mathjax>. This means that you get <mathjax>#0.00050#</mathjax> <strong>moles</strong> of solute <strong>per liter</strong> of solution. </p> <p>To keep the calculations simple, let's assume that you have a <mathjax>#"1-L"#</mathjax> sample of this solution. </p> <p>The first thing to do here is use methanol's <strong>molar mass</strong> to convert the number of moles to <em>grams</em> </p> <blockquote> <p><mathjax>#0.00050 color(red)(cancel(color(black)("moles CH"_3"OH"))) * "32.04 g"/(1color(red)(cancel(color(black)("mole CH"_3"OH")))) = "0.0162 g CH"_3"OH"#</mathjax></p> </blockquote> <p>Because the solution contains <strong>such a small amount</strong> of methanol, you can assume that its <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a></strong> will be equal to that of pure water. Since no information about water's density was given, you can assume it to be equal to <mathjax>#"1 g mL"^(-1)#</mathjax>. </p> <p>This means that the sample will have a mass of </p> <blockquote> <p><mathjax>#1 color(red)(cancel(color(black)("L"))) * (10^3color(red)(cancel(color(black)("mL"))))/(1color(red)(cancel(color(black)("L")))) * "1 g"/(1 color(red)(cancel(color(black)("mL")))) = 10^3"g"#</mathjax></p> </blockquote> <p>As you can see, you can safely assume that the mass of the <em>solvent</em> is approximately equal to that of the <em>solution</em>. </p> <p>This means that the concentration in ppm will be equal to </p> <blockquote> <p><mathjax>#"ppm" = (0.0162color(red)(cancel(color(black)("g"))))/(10^3color(red)(cancel(color(black)("g")))) * 10^6 = color(green)(\|bar(ul(color(white)(a/a)"16.2 ppm"color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>I'll leave the answer rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name"> Consider a 0.00050 molar solution of methanol, #"CH"_3"OH"#, in water. Express the concentration of methanol in parts per million?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>Consider a 0.00050 molar solution of methanol (CH3OH) in water.<br/> Express the concentration of methanol in parts per million.</p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/solving-using-ppm-parts-per-million" itemprop="url"> <span class="breadcrumb" itemprop="title">Solving Using PPM (Parts Per Million)</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="267072" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-18T12:53:48" itemprop="dateCreated"> May 18, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"16.2 ppm"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>For <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> that contain very, very small amounts of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a>, usually called <em>trace amounts</em>, you can use <strong>Parts Per Million</strong>, or <strong>ppm</strong>, to express their concentration. </p> <p>In essence, <strong>ppm</strong> denotes <em>one part solute</em> <strong>for every</strong> <mathjax>#10^6#</mathjax> <em>parts <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a></em>. This means that you can find a solution's concentration in ppm by using </p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a)"ppm" = "grams of solute"/"grams of solvent" xx 10^6color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>Now, your methanol solution is said to have a <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></strong> of <mathjax>#"0.00050 mol L"^(-1)#</mathjax>. This means that you get <mathjax>#0.00050#</mathjax> <strong>moles</strong> of solute <strong>per liter</strong> of solution. </p> <p>To keep the calculations simple, let's assume that you have a <mathjax>#"1-L"#</mathjax> sample of this solution. </p> <p>The first thing to do here is use methanol's <strong>molar mass</strong> to convert the number of moles to <em>grams</em> </p> <blockquote> <p><mathjax>#0.00050 color(red)(cancel(color(black)("moles CH"_3"OH"))) * "32.04 g"/(1color(red)(cancel(color(black)("mole CH"_3"OH")))) = "0.0162 g CH"_3"OH"#</mathjax></p> </blockquote> <p>Because the solution contains <strong>such a small amount</strong> of methanol, you can assume that its <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a></strong> will be equal to that of pure water. Since no information about water's density was given, you can assume it to be equal to <mathjax>#"1 g mL"^(-1)#</mathjax>. </p> <p>This means that the sample will have a mass of </p> <blockquote> <p><mathjax>#1 color(red)(cancel(color(black)("L"))) * (10^3color(red)(cancel(color(black)("mL"))))/(1color(red)(cancel(color(black)("L")))) * "1 g"/(1 color(red)(cancel(color(black)("mL")))) = 10^3"g"#</mathjax></p> </blockquote> <p>As you can see, you can safely assume that the mass of the <em>solvent</em> is approximately equal to that of the <em>solution</em>. </p> <p>This means that the concentration in ppm will be equal to </p> <blockquote> <p><mathjax>#"ppm" = (0.0162color(red)(cancel(color(black)("g"))))/(10^3color(red)(cancel(color(black)("g")))) * 10^6 = color(green)(\|bar(ul(color(white)(a/a)"16.2 ppm"color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>I'll leave the answer rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/267072" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-ppm"> What is PPM? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-ppm-be-calculated-in-chemistry"> How can PPM be calculated in chemistry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-ppm-a-useful-measurement"> Why is PPM a useful measurement? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/54c39459581e2a50bb6742ad"> Question #742ad </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/54c4d4dc581e2a50d46797aa"> Question #797aa </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/h2s-g-concentrations-of-660ppm-is-dangerous-6-h2s-generators-continually-release"> H2S (g) concentrations of 660ppm is dangerous. 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Express the concentration of methanol in parts per million?	Consider a 0.00050 molar solution of methanol (CH3OH) in water. Express the concentration of methanol in parts per million.
1,889	aba53c1e-6ddd-11ea-9053-ccda262736ce	https://socratic.org/questions/an-hcl-solution-has-a-concentration-of-3-26-10-2-m-what-is-the-ph-of-this-soluti	1.49	start physical_unit 1 2 ph none qc_end physical_unit 1 2 7 10 concentration qc_end end	[{"type":"physical unit","value":"pH [OF] HCl solution"}]	[{"type":"physical unit","value":"1.49"}]	[{"type":"physical unit","value":"Concentration [OF] HCl solution [=] \\pu{3.26 × 10^(-2) M}"}]	<h1 class="questionTitle" itemprop="name">An #HCl# solution has a concentration of #3.26 * 10^-2# #M#. What is the pH of this solution? </h1>	null	1.49	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Since HCl is a strong acid, it completely dissociates into its respective ions when placed in water. In this case HCl ionizes to produce <mathjax>#H^(+) (aq)#</mathjax> and <mathjax>#Cl^(-)(aq)#</mathjax>. </p> <p>As soon as we know that we're dealing with a strong acid, the <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> can be obtained directly from the concentration of <mathjax>#H^(+)#</mathjax> using the following formula:<br/> <img alt="lpoli.50webs.com" src="https://useruploads.socratic.org/HHcKFaZ6T7m45XeIKGHe_ph.jpg"/> </p> <p>All we have to do is take the -log of the given concentration like so:</p> <p><mathjax>#pH = -log [3.26xx10^(-2)] #</mathjax></p> <p><mathjax>#pH = 1.487#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> of this solution is 1.487.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Since HCl is a strong acid, it completely dissociates into its respective ions when placed in water. In this case HCl ionizes to produce <mathjax>#H^(+) (aq)#</mathjax> and <mathjax>#Cl^(-)(aq)#</mathjax>. </p> <p>As soon as we know that we're dealing with a strong acid, the <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> can be obtained directly from the concentration of <mathjax>#H^(+)#</mathjax> using the following formula:<br/> <img alt="lpoli.50webs.com" src="https://useruploads.socratic.org/HHcKFaZ6T7m45XeIKGHe_ph.jpg"/> </p> <p>All we have to do is take the -log of the given concentration like so:</p> <p><mathjax>#pH = -log [3.26xx10^(-2)] #</mathjax></p> <p><mathjax>#pH = 1.487#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">An #HCl# solution has a concentration of #3.26 * 10^-2# #M#. What is the pH of this solution? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/the-ph-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">pH</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="277027" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/kayla-14"><img alt="" class="" src="https://profilepictures.socratic.org/OvMTWaamQPWcqLIkUNnG_793604964071127.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/kayla-14"> Kayla </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-14T00:12:43" itemprop="dateCreated"> Jun 14, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> of this solution is 1.487.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Since HCl is a strong acid, it completely dissociates into its respective ions when placed in water. In this case HCl ionizes to produce <mathjax>#H^(+) (aq)#</mathjax> and <mathjax>#Cl^(-)(aq)#</mathjax>. </p> <p>As soon as we know that we're dealing with a strong acid, the <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> can be obtained directly from the concentration of <mathjax>#H^(+)#</mathjax> using the following formula:<br/> <img alt="lpoli.50webs.com" src="https://useruploads.socratic.org/HHcKFaZ6T7m45XeIKGHe_ph.jpg"/> </p> <p>All we have to do is take the -log of the given concentration like so:</p> <p><mathjax>#pH = -log [3.26xx10^(-2)] #</mathjax></p> <p><mathjax>#pH = 1.487#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/277027" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-pka"> How do you determine pH from pKa? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-ph-values-of-acids-and-bases-differ"> How do pH values of acids and bases differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-something-on-a-ph-scale"> How do you calculate something on a pH scale? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-diprotic-acid"> How do you calculate pH diprotic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-from-acid-dissociation-constant"> How do you calculate pH from acid dissociation constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-of-acid-and-base-solution"> How do you calculate pH of acid and base solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ph-scale-0-14"> Why is the pH scale 0-14? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-ph-the-measure-of-the-hydrogen-ion-concentration"> Is pH a measure of the hydrogen ion concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-solubility-affect-ph"> How does solubility affect pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-ph-relate-to-pka-in-a-titration"> How does pH relate to pKa in a titration? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/the-ph-concept"> See all questions in pH </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2950 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	An #HCl# solution has a concentration of #3.26 * 10^-2# #M#. What is the pH of this solution?	null
1,890	a8e81887-6ddd-11ea-ae31-ccda262736ce	https://socratic.org/questions/a-nurse-wants-to-add-water-to-30-ounces-of-a-10-solution-of-benzalkonium-chlorid	7.5 ounces	start physical_unit 5 5 mass oz qc_end physical_unit 12 12 7 8 mass qc_end physical_unit 14 15 21 21 percent qc_end physical_unit 14 15 11 11 percent qc_end end	[{"type":"physical unit","value":"Mass [OF] water [IN] ounces"}]	[{"type":"physical unit","value":"7.5 ounces"}]	[{"type":"physical unit","value":"Mass [OF] benzalkonium chloride solution [=] \\pu{30 ounces}"},{"type":"physical unit","value":"Percent2 [OF] benzalkonium chloride in solution [=] \\pu{8%}"},{"type":"physical unit","value":"Percent1 [OF] benzalkonium chloride in solution [=] \\pu{10%}"}]	<h1 class="questionTitle" itemprop="name">A nurse wants to add water to 30 ounces of a 10% solution of benzalkonium chloride to dilute it to an 8% solution. How much water must she add? </h1>	null	7.5 ounces	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Using the standard dilution equation:</p> <p><mathjax>#c_1 * v_1 = c_2 * v_2#</mathjax></p> <p>Where:<br/> <mathjax>#c_1#</mathjax> = concentration 1 = 10%<br/> <mathjax>#v_1#</mathjax> = volume 1 = 30 oz<br/> <mathjax>#c_2#</mathjax> = concentration 2 = 8%<br/> <mathjax>#v_2#</mathjax> = volume 2 = ???</p> <p>Rearranging for <mathjax>#v_2#</mathjax> we get:</p> <p><mathjax>#v_2 = (c_1 * v_1) / c_2#</mathjax></p> <p><mathjax>#v_2 = (10 * 30) / 8#</mathjax></p> <p><mathjax>#v_2 = (300) / 8#</mathjax></p> <p><mathjax>#v_2 = (300) / 8#</mathjax></p> <p><mathjax>#v_2 = 37.5#</mathjax> oz</p> <p>We already have 30 oz, so just need to add 7.5 oz.</p> <p>I have a free <a href="https://gum.co/maths4biosciences" rel="nofollow">ebook</a> that covers moles and <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a>, percentage <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a>, and dilutions, which you may find useful.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>7.5 oz</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Using the standard dilution equation:</p> <p><mathjax>#c_1 * v_1 = c_2 * v_2#</mathjax></p> <p>Where:<br/> <mathjax>#c_1#</mathjax> = concentration 1 = 10%<br/> <mathjax>#v_1#</mathjax> = volume 1 = 30 oz<br/> <mathjax>#c_2#</mathjax> = concentration 2 = 8%<br/> <mathjax>#v_2#</mathjax> = volume 2 = ???</p> <p>Rearranging for <mathjax>#v_2#</mathjax> we get:</p> <p><mathjax>#v_2 = (c_1 * v_1) / c_2#</mathjax></p> <p><mathjax>#v_2 = (10 * 30) / 8#</mathjax></p> <p><mathjax>#v_2 = (300) / 8#</mathjax></p> <p><mathjax>#v_2 = (300) / 8#</mathjax></p> <p><mathjax>#v_2 = 37.5#</mathjax> oz</p> <p>We already have 30 oz, so just need to add 7.5 oz.</p> <p>I have a free <a href="https://gum.co/maths4biosciences" rel="nofollow">ebook</a> that covers moles and <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a>, percentage <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a>, and dilutions, which you may find useful.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A nurse wants to add water to 30 ounces of a 10% solution of benzalkonium chloride to dilute it to an 8% solution. How much water must she add? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/solutions" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="306526" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/nick-41"><img alt="" class="" src="https://profilepictures.socratic.org/Sq1QmKQKSPCfDM110rRn_16.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/nick-41"> Nick </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-09-05T19:37:07" itemprop="dateCreated"> Sep 5, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>7.5 oz</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Using the standard dilution equation:</p> <p><mathjax>#c_1 * v_1 = c_2 * v_2#</mathjax></p> <p>Where:<br/> <mathjax>#c_1#</mathjax> = concentration 1 = 10%<br/> <mathjax>#v_1#</mathjax> = volume 1 = 30 oz<br/> <mathjax>#c_2#</mathjax> = concentration 2 = 8%<br/> <mathjax>#v_2#</mathjax> = volume 2 = ???</p> <p>Rearranging for <mathjax>#v_2#</mathjax> we get:</p> <p><mathjax>#v_2 = (c_1 * v_1) / c_2#</mathjax></p> <p><mathjax>#v_2 = (10 * 30) / 8#</mathjax></p> <p><mathjax>#v_2 = (300) / 8#</mathjax></p> <p><mathjax>#v_2 = (300) / 8#</mathjax></p> <p><mathjax>#v_2 = 37.5#</mathjax> oz</p> <p>We already have 30 oz, so just need to add 7.5 oz.</p> <p>I have a free <a href="https://gum.co/maths4biosciences" rel="nofollow">ebook</a> that covers moles and <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a>, percentage <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a>, and dilutions, which you may find useful.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/306526" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-solution-solute-and-solvent-related"> How are solution, solute, and solvent related? 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How much water must she add?	null
1,891	ac2639a4-6ddd-11ea-a9d3-ccda262736ce	https://socratic.org/questions/how-do-you-balance-c-3h-6-o-2-co-h-2o	C3H6 + 3 O2 -> 3 CO + 3 H2O	start chemical_equation qc_end chemical_equation 4 10 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the equation"}]	[{"type":"chemical equation","value":"C3H6 + 3 O2 -> 3 CO + 3 H2O"}]	[{"type":"chemical equation","value":"C3H6 + O2 -> CO + H2O"}]	<h1 class="questionTitle" itemprop="name">How do you balance #C_3H_6 + O_2 -> CO + H_2O#?</h1>	null	C3H6 + 3 O2 -> 3 CO + 3 H2O	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To balance, we add molecules such as to ensure that the number of atoms of each element is the same on each side of the equation.</p> <p>This equation represents the incomplete combustion of propane as insufficient oxygen must have been present since carbon monoxide was form instead of carbon dioxide which would form if there was sufficient oxygen to ensure complete combustion.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_3H_6+3O_2->3CO+3H_2O#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To balance, we add molecules such as to ensure that the number of atoms of each element is the same on each side of the equation.</p> <p>This equation represents the incomplete combustion of propane as insufficient oxygen must have been present since carbon monoxide was form instead of carbon dioxide which would form if there was sufficient oxygen to ensure complete combustion.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you balance #C_3H_6 + O_2 -> CO + H_2O#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="218928" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/trevor-r-1"><img alt="" class="" src="https://profilepictures.socratic.org/2Wf9lLD9RaSzPbXY0EW8_S5002678.JPG" title=""/></a> <a class="secondContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/trevor-r-1"> Trevor Ryan. </a>·<a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-29T19:20:20" itemprop="dateCreated"> Jan 29, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_3H_6+3O_2->3CO+3H_2O#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To balance, we add molecules such as to ensure that the number of atoms of each element is the same on each side of the equation.</p> <p>This equation represents the incomplete combustion of propane as insufficient oxygen must have been present since carbon monoxide was form instead of carbon dioxide which would form if there was sufficient oxygen to ensure complete combustion.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/218928" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="218932" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/lovecraft"><img alt="" class="" src="https://profilepictures.socratic.org/yRsInkqBQENj1w6bu77a_tumblrmireiwDbf71rz7ozto1400.gif" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/lovecraft"> Lovecraft </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-29T19:25:21" itemprop="dateCreated"> Jan 29, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_3H_6 + 3O_2 rarr 3CO + 3H_2O#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We have three carbons on the reagents' side and only one on the products' side, so we need to balance that by making that equal.</p> <p><mathjax>#C_3H_6 + O_2 rarr 3CO + H_2O#</mathjax> </p> <p>We have six hydrogens on the reagents' side and only 2 on the products' side so we need to balance that by making them equal.</p> <p><mathjax>#C_3H_6 + O_2 rarr 3CO + 3H_2O#</mathjax></p> <p>We have 2 oxygens on the reagents' side and 6 on the products' side, so we need to balance that by making them equal, now, since the reagent's side has only one substance with oxygen it'll be easier to make that equal, so,</p> <p><mathjax>#C_3H_6 + 3O_2 rarr 3CO + 3H_2O#</mathjax></p> <p>Do note that if you had equalized the first time around by</p> <p><mathjax>#1/3C_3H_6 + O_2 rarr CO + H_2O#</mathjax></p> <p>It'd be already balanced, but it's considered good practice to balance equations by having integer coefficients, which we could have solved by multiplying everything by 3</p> <p><mathjax>#C_3H_6 + 3O_2 rarr 3CO + 3H_2O#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/218932" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul 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Sodium phosphate and calcium chloride react to form... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-equation-kclo3-kcl-o2"> How can I balance this equation? ____ #KClO_3 -># ____ #KCl +# ____ #O_2# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-balancing-chemical-equations-important"> Why is balancing chemical equations important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/balancing-chemical-equations"> See all questions in Balancing Chemical Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1587 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How do you balance #C_3H_6 + O_2 -> CO + H_2O#?	null
1,892	acb585b5-6ddd-11ea-8c08-ccda262736ce	https://socratic.org/questions/what-is-the-mass-in-grams-of-50-mol-of-carbon	6.01 grams	start physical_unit 10 10 mass g qc_end physical_unit 10 10 7 8 mole qc_end end	[{"type":"physical unit","value":"Mass [OF] carbon [IN] grams"}]	[{"type":"physical unit","value":"6.01 grams"}]	[{"type":"physical unit","value":"Mole [OF] carbon [=] \\pu{0.50 mol}"}]	<h1 class="questionTitle" itemprop="name"> What is the mass in grams of .50 mol of carbon?</h1>	null	6.01 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Did you have to remember this? Even though this is a trivial problem, you MIGHT have been asked the mass in grams of half a mole of iron, or antimony, or osmium. You will be issued with a Periodic Table, which will tell you the molar masses of each element. </p> <p>A follow up question is, "How many <mathjax>#C#</mathjax> atoms are there in <mathjax>#6#</mathjax> <mathjax>#g#</mathjax> of carbon?"</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1#</mathjax> <mathjax>#mol#</mathjax> of carbon has a mass of <mathjax>#12.011#</mathjax> <mathjax>#g#</mathjax>. So <mathjax>#1/2#</mathjax> mole <mathjax>#C#</mathjax> has a mass of about <mathjax>#6#</mathjax> <mathjax>#g#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Did you have to remember this? Even though this is a trivial problem, you MIGHT have been asked the mass in grams of half a mole of iron, or antimony, or osmium. You will be issued with a Periodic Table, which will tell you the molar masses of each element. </p> <p>A follow up question is, "How many <mathjax>#C#</mathjax> atoms are there in <mathjax>#6#</mathjax> <mathjax>#g#</mathjax> of carbon?"</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name"> What is the mass in grams of .50 mol of carbon?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="224218" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-02-10T06:18:44" itemprop="dateCreated"> Feb 10, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1#</mathjax> <mathjax>#mol#</mathjax> of carbon has a mass of <mathjax>#12.011#</mathjax> <mathjax>#g#</mathjax>. So <mathjax>#1/2#</mathjax> mole <mathjax>#C#</mathjax> has a mass of about <mathjax>#6#</mathjax> <mathjax>#g#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Did you have to remember this? Even though this is a trivial problem, you MIGHT have been asked the mass in grams of half a mole of iron, or antimony, or osmium. You will be issued with a Periodic Table, which will tell you the molar masses of each element. </p> <p>A follow up question is, "How many <mathjax>#C#</mathjax> atoms are there in <mathjax>#6#</mathjax> <mathjax>#g#</mathjax> of carbon?"</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/224218" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What is stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ab82402bf342f48d93ac6"> Question #93ac6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-we-study-stoichiometry"> Why do we study stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-naoh-is-produced-from-1-20-x-102-grams-of-na2o-na2o-h2o-2-naoh"> How many grams of NaOH is produced from #1.20 x 10^2# grams of #Na_2O#? #Na_2O + H_2O -> 2NaOH# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-na2o-are-required-to-produce-1-60-x-102-grams-of-naoh-na2o-h2o"> How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? 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1,893	aafa4ef0-6ddd-11ea-b5b7-ccda262736ce	https://socratic.org/questions/what-is-the-coefficient-of-oxygen-gas-after-balancing-the-following-equation-p-s	5	start physical_unit 5 6 coefficient none qc_end chemical_equation 12 16 qc_end end	[{"type":"physical unit","value":"Coefficient [OF] oxygen gas"}]	[{"type":"physical unit","value":"5"}]	[{"type":"chemical equation","value":"P(s) + O2 -> P2O5(s)"}]	<h1 class="questionTitle" itemprop="name">What is the coefficient of oxygen gas after balancing the following equation, #P(s) + O_2 -> P_2O_5(s)#?</h1>	null	5	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Of course, if you like, you can make a meal of the the equation:</p> <p><mathjax>#P_4(s) + 5O_2(g) rarr P_4O_10(s)#</mathjax></p> <p>The <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>, the grams of reactant required for the grams of product, is precisely the same in each equation. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#5/2?#</mathjax> Of course the <mathjax>#P#</mathjax> coefficient has to be changed as well. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Of course, if you like, you can make a meal of the the equation:</p> <p><mathjax>#P_4(s) + 5O_2(g) rarr P_4O_10(s)#</mathjax></p> <p>The <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>, the grams of reactant required for the grams of product, is precisely the same in each equation. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the coefficient of oxygen gas after balancing the following equation, #P(s) + O_2 -> P_2O_5(s)#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="296355" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-08-07T06:33:32" itemprop="dateCreated"> Aug 7, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#5/2?#</mathjax> Of course the <mathjax>#P#</mathjax> coefficient has to be changed as well. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Of course, if you like, you can make a meal of the the equation:</p> <p><mathjax>#P_4(s) + 5O_2(g) rarr P_4O_10(s)#</mathjax></p> <p>The <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>, the grams of reactant required for the grams of product, is precisely the same in each equation. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/296355" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? 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Sodium phosphate and calcium chloride react to form... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-equation-kclo3-kcl-o2"> How can I balance this equation? ____ #KClO_3 -># ____ #KCl +# ____ #O_2# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-balancing-chemical-equations-important"> Why is balancing chemical equations important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/balancing-chemical-equations"> See all questions in Balancing Chemical Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 5649 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the coefficient of oxygen gas after balancing the following equation, #P(s) + O_2 -> P_2O_5(s)#?	null
1,894	aae651cb-6ddd-11ea-92ff-ccda262736ce	https://socratic.org/questions/p4-s-6cl2-g-4pcl3-l-a-reaction-mixture-initially-contains-45-13-g-p4-and-132-0-g	6.69 g	start physical_unit 32 34 mass g qc_end chemical_equation 0 6 qc_end physical_unit 0 0 12 13 mass qc_end physical_unit 3 3 16 17 mass qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Mass [OF] the excess reactant [IN] g"}]	[{"type":"physical unit","value":"6.69 g"}]	[{"type":"chemical equation","value":"P4(s) + 6 Cl2(g) -> 4 PCl3(l)"},{"type":"physical unit","value":"Mass [OF] P4 [=] \\pu{45.13 g}"},{"type":"physical unit","value":"Mass [OF] Cl2 [=] \\pu{132.0 g}"},{"type":"other","value":"The reaction has occurred as completely as possible."}]	<h1 class="questionTitle" itemprop="name">P4(s)+6Cl2(g)→4PCl3(l) A reaction mixture initially contains 45.13 g P4 and 132.0 g Cl2.Once the reaction has occurred as completely as possible, what mass (in g) of the excess reactant is left?</h1>	null	6.69 g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In a more clear form, the reaction is</p> <p><mathjax>#"P"_4 (s) + 6"Cl"_2 (g) rarr 4"PCl"_3 (l)#</mathjax></p> <p>We're asked to calculate how much of the excess reactant (which we have to find) remains after this reaction goes essentially to completion.</p> <p>To find the excess reactant, we must first find the number of moles of each reactant present:</p> <p><mathjax>#"mol P"_4 = 45.13cancel("g P"_4)((1"mol P"_4)/(123.88cancel("g P"_4))) = 0.3643#</mathjax> <mathjax>#"mol P"_4#</mathjax></p> <p><mathjax>#"mol Cl"_2 = 132.0cancel("g Cl"_2)((1"mol Cl"_2)/(70.90cancel("g Cl"_2))) = 1.862#</mathjax> <mathjax>#"mol Cl"_2#</mathjax></p> <p>To find the excess reactant, we divide these values by their respective coefficients; whichever number is greater after this is the reactant of excess:</p> <p><mathjax>#"P"_4 = (0.3643"mol P"_4)/(1 "(coefficient)") = 0.3643#</mathjax></p> <p><mathjax>#"Cl"_2 = (1.862"mol Cl"_2)/(6 "(coefficient)") = 0.3103#</mathjax></p> <p>Phosphorus is thus the excess reactant.</p> <blockquote></blockquote> <p>We need to use <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> value of the <em>limiting reactant</em> in order to find the mass of <mathjax>#"P"_4#</mathjax> used. Using dimensional analysis,</p> <p><mathjax>#1.862"mol Cl"_2((1"mol P"_4)/(6"mol Cl"_2))((123.88"g P"_4)/(1"mol P"_4)) = color(red)(38.44#</mathjax> <mathjax>#color(red)("g P"_4#</mathjax></p> <p>Since this is how much <mathjax>#"P"_4#</mathjax> is used up, we subtract this from the initial value to find how much remains:</p> <p><mathjax>#45.13#</mathjax> <mathjax>#"g P"_4 - color(red)(38.44#</mathjax> <mathjax>#color(red)("g P"_4) = color(blue)(6.69#</mathjax> <mathjax>#color(blue)("g P"_4#</mathjax></p> <p>Thus, after the reaction goes to completion, there will be <mathjax>#6.69#</mathjax> grams of phosphorus left over.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#6.69#</mathjax> <mathjax>#"g P"_4#</mathjax></p> <p>(<mathjax>#"P"_4#</mathjax> is present in excess)</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In a more clear form, the reaction is</p> <p><mathjax>#"P"_4 (s) + 6"Cl"_2 (g) rarr 4"PCl"_3 (l)#</mathjax></p> <p>We're asked to calculate how much of the excess reactant (which we have to find) remains after this reaction goes essentially to completion.</p> <p>To find the excess reactant, we must first find the number of moles of each reactant present:</p> <p><mathjax>#"mol P"_4 = 45.13cancel("g P"_4)((1"mol P"_4)/(123.88cancel("g P"_4))) = 0.3643#</mathjax> <mathjax>#"mol P"_4#</mathjax></p> <p><mathjax>#"mol Cl"_2 = 132.0cancel("g Cl"_2)((1"mol Cl"_2)/(70.90cancel("g Cl"_2))) = 1.862#</mathjax> <mathjax>#"mol Cl"_2#</mathjax></p> <p>To find the excess reactant, we divide these values by their respective coefficients; whichever number is greater after this is the reactant of excess:</p> <p><mathjax>#"P"_4 = (0.3643"mol P"_4)/(1 "(coefficient)") = 0.3643#</mathjax></p> <p><mathjax>#"Cl"_2 = (1.862"mol Cl"_2)/(6 "(coefficient)") = 0.3103#</mathjax></p> <p>Phosphorus is thus the excess reactant.</p> <blockquote></blockquote> <p>We need to use <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> value of the <em>limiting reactant</em> in order to find the mass of <mathjax>#"P"_4#</mathjax> used. Using dimensional analysis,</p> <p><mathjax>#1.862"mol Cl"_2((1"mol P"_4)/(6"mol Cl"_2))((123.88"g P"_4)/(1"mol P"_4)) = color(red)(38.44#</mathjax> <mathjax>#color(red)("g P"_4#</mathjax></p> <p>Since this is how much <mathjax>#"P"_4#</mathjax> is used up, we subtract this from the initial value to find how much remains:</p> <p><mathjax>#45.13#</mathjax> <mathjax>#"g P"_4 - color(red)(38.44#</mathjax> <mathjax>#color(red)("g P"_4) = color(blue)(6.69#</mathjax> <mathjax>#color(blue)("g P"_4#</mathjax></p> <p>Thus, after the reaction goes to completion, there will be <mathjax>#6.69#</mathjax> grams of phosphorus left over.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">P4(s)+6Cl2(g)→4PCl3(l) A reaction mixture initially contains 45.13 g P4 and 132.0 g Cl2.Once the reaction has occurred as completely as possible, what mass (in g) of the excess reactant is left?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/limiting-reagent" itemprop="url"> <span class="breadcrumb" itemprop="title">Limiting Reagent</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="437621" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/mrtas"><img alt="" class="" src="https://profilepictures.socratic.org/HY14X7r4S6AyDQgK2gwQ_IMG_0062.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/mrtas"> Nathan L. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-10T19:25:30" itemprop="dateCreated"> Jun 10, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#6.69#</mathjax> <mathjax>#"g P"_4#</mathjax></p> <p>(<mathjax>#"P"_4#</mathjax> is present in excess)</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In a more clear form, the reaction is</p> <p><mathjax>#"P"_4 (s) + 6"Cl"_2 (g) rarr 4"PCl"_3 (l)#</mathjax></p> <p>We're asked to calculate how much of the excess reactant (which we have to find) remains after this reaction goes essentially to completion.</p> <p>To find the excess reactant, we must first find the number of moles of each reactant present:</p> <p><mathjax>#"mol P"_4 = 45.13cancel("g P"_4)((1"mol P"_4)/(123.88cancel("g P"_4))) = 0.3643#</mathjax> <mathjax>#"mol P"_4#</mathjax></p> <p><mathjax>#"mol Cl"_2 = 132.0cancel("g Cl"_2)((1"mol Cl"_2)/(70.90cancel("g Cl"_2))) = 1.862#</mathjax> <mathjax>#"mol Cl"_2#</mathjax></p> <p>To find the excess reactant, we divide these values by their respective coefficients; whichever number is greater after this is the reactant of excess:</p> <p><mathjax>#"P"_4 = (0.3643"mol P"_4)/(1 "(coefficient)") = 0.3643#</mathjax></p> <p><mathjax>#"Cl"_2 = (1.862"mol Cl"_2)/(6 "(coefficient)") = 0.3103#</mathjax></p> <p>Phosphorus is thus the excess reactant.</p> <blockquote></blockquote> <p>We need to use <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> value of the <em>limiting reactant</em> in order to find the mass of <mathjax>#"P"_4#</mathjax> used. Using dimensional analysis,</p> <p><mathjax>#1.862"mol Cl"_2((1"mol P"_4)/(6"mol Cl"_2))((123.88"g P"_4)/(1"mol P"_4)) = color(red)(38.44#</mathjax> <mathjax>#color(red)("g P"_4#</mathjax></p> <p>Since this is how much <mathjax>#"P"_4#</mathjax> is used up, we subtract this from the initial value to find how much remains:</p> <p><mathjax>#45.13#</mathjax> <mathjax>#"g P"_4 - color(red)(38.44#</mathjax> <mathjax>#color(red)("g P"_4) = color(blue)(6.69#</mathjax> <mathjax>#color(blue)("g P"_4#</mathjax></p> <p>Thus, after the reaction goes to completion, there will be <mathjax>#6.69#</mathjax> grams of phosphorus left over.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/437621" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-how-much-of-the-excess-reactant-is-left-over-also-how-do-yo"> How do you determine how much of the excess reactant is left over? Also, how do you determine... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40fb002bf34694c8c5be2"> What is the limiting reactant in a Grignard reaction? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40fb002bf346950519e8d"> Question #19e8d </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40fb102bf34694c8c5be6"> Question #c5be6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40fb302bf346950519e95"> Question #19e95 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40fb302bf3469588dc361"> Question #dc361 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40fb402bf346963eb983d"> Question #b983d </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40fb702bf346950519e99"> Question #19e99 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5320fad502bf3443cd052b92"> Question #52b92 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5338b3be02bf345c6413f1d9"> Question #3f1d9 </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/limiting-reagent"> See all questions in Limiting Reagent </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 59172 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	P4(s)+6Cl2(g)→4PCl3(l) A reaction mixture initially contains 45.13 g P4 and 132.0 g Cl2.Once the reaction has occurred as completely as possible, what mass (in g) of the excess reactant is left?	null
1,895	ab725408-6ddd-11ea-85d6-ccda262736ce	https://socratic.org/questions/calculate-the-ph-of-a-0-2m-solution-of-nac2h3o2-given-that-the-hydrolysis-consta	9.02	start physical_unit 7 7 ph none qc_end physical_unit 9 9 5 6 molarity qc_end physical_unit 9 9 18 20 kh qc_end end	[{"type":"physical unit","value":"pH [OF] NaC2H3O2 solution"}]	[{"type":"physical unit","value":"9.02"}]	[{"type":"physical unit","value":"Molarity [OF] NaC2H3O2 solution [=] \\pu{0.2 M}"},{"type":"physical unit","value":"Kh [OF] NaC2H3O2 [=] \\pu{5.6 × 10^(-10)}"}]	<h1 class="questionTitle" itemprop="name">Calculate the pH of a #"0.2 M"# solution of #"NaC"_2"H"_3"O"_2# given that the hydrolysis constant is #K_h = 5.6xx10^(-10)#?</h1>	null	9.02	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>We can use an ICE table to help with the calculation.</p> <p><mathjax>#color(white)(mmmmmmm)"A"^"-" + "H"_2"O" ⇌ "HA" + "OH"^"-"#</mathjax><br/> <mathjax>#"I/mol·L"^"-1":color(white)(mll)0.2color(white)(mmmmmm)0color(white)(mmll)0#</mathjax><br/> <mathjax>#"C/mol·L"^"-1":color(white)(mll)"-"xcolor(white)(mmmmml)"+"xcolor(white)(mm)"+"x#</mathjax><br/> <mathjax>#"E/mol·L"^"-1":color(white)(m)"0.2-"xcolor(white)(mmmmml)xcolor(white)(mmll)x#</mathjax></p> <p><mathjax>#K_text(h) = (["HA"]["OH"^"-"])/(["A"^"-"]) = 5.6 × 10^"-10"#</mathjax></p> <p><mathjax>#x^2/("0.2-"x) = 5.6 × 10^"-10"#</mathjax></p> <blockquote></blockquote> <p><strong>Apply the 5 % rule</strong></p> <p><mathjax>#0.2/(5.6 × 10^"-10") = 3.6 × 10^8 > 400#</mathjax>.</p> <p>∴ <mathjax>#x ≪0.2#</mathjax></p> <blockquote></blockquote> <p>Then</p> <p><mathjax>#x^2/0.2 = 5.6 × 10^"-10"#</mathjax></p> <p><mathjax>#x^2 = 0.2(5.6 × 10^"-10") = 1.1 × 10^"-10"#</mathjax></p> <p><mathjax>#x = 1.1 × 10^"-5"#</mathjax></p> <p><mathjax>#["OH"^"-"] = x color(white)(l)"mol/L" = 1.1 × 10^"-5"color(white)(l) "mol/L"#</mathjax></p> <p><mathjax>#"pOH" = "-log"["OH"^"-"] = "-log"(1.1 × 10^"-5") = 4.98#</mathjax></p> <p><mathjax>#"pH = 14.00 - pOH = 14.00 - 4.98 = 9.02"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> = 9.02</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>We can use an ICE table to help with the calculation.</p> <p><mathjax>#color(white)(mmmmmmm)"A"^"-" + "H"_2"O" ⇌ "HA" + "OH"^"-"#</mathjax><br/> <mathjax>#"I/mol·L"^"-1":color(white)(mll)0.2color(white)(mmmmmm)0color(white)(mmll)0#</mathjax><br/> <mathjax>#"C/mol·L"^"-1":color(white)(mll)"-"xcolor(white)(mmmmml)"+"xcolor(white)(mm)"+"x#</mathjax><br/> <mathjax>#"E/mol·L"^"-1":color(white)(m)"0.2-"xcolor(white)(mmmmml)xcolor(white)(mmll)x#</mathjax></p> <p><mathjax>#K_text(h) = (["HA"]["OH"^"-"])/(["A"^"-"]) = 5.6 × 10^"-10"#</mathjax></p> <p><mathjax>#x^2/("0.2-"x) = 5.6 × 10^"-10"#</mathjax></p> <blockquote></blockquote> <p><strong>Apply the 5 % rule</strong></p> <p><mathjax>#0.2/(5.6 × 10^"-10") = 3.6 × 10^8 > 400#</mathjax>.</p> <p>∴ <mathjax>#x ≪0.2#</mathjax></p> <blockquote></blockquote> <p>Then</p> <p><mathjax>#x^2/0.2 = 5.6 × 10^"-10"#</mathjax></p> <p><mathjax>#x^2 = 0.2(5.6 × 10^"-10") = 1.1 × 10^"-10"#</mathjax></p> <p><mathjax>#x = 1.1 × 10^"-5"#</mathjax></p> <p><mathjax>#["OH"^"-"] = x color(white)(l)"mol/L" = 1.1 × 10^"-5"color(white)(l) "mol/L"#</mathjax></p> <p><mathjax>#"pOH" = "-log"["OH"^"-"] = "-log"(1.1 × 10^"-5") = 4.98#</mathjax></p> <p><mathjax>#"pH = 14.00 - pOH = 14.00 - 4.98 = 9.02"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Calculate the pH of a #"0.2 M"# solution of #"NaC"_2"H"_3"O"_2# given that the hydrolysis constant is #K_h = 5.6xx10^(-10)#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/ph-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">pH calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="619176" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-05-24T01:12:06" itemprop="dateCreated"> May 24, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> = 9.02</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>We can use an ICE table to help with the calculation.</p> <p><mathjax>#color(white)(mmmmmmm)"A"^"-" + "H"_2"O" ⇌ "HA" + "OH"^"-"#</mathjax><br/> <mathjax>#"I/mol·L"^"-1":color(white)(mll)0.2color(white)(mmmmmm)0color(white)(mmll)0#</mathjax><br/> <mathjax>#"C/mol·L"^"-1":color(white)(mll)"-"xcolor(white)(mmmmml)"+"xcolor(white)(mm)"+"x#</mathjax><br/> <mathjax>#"E/mol·L"^"-1":color(white)(m)"0.2-"xcolor(white)(mmmmml)xcolor(white)(mmll)x#</mathjax></p> <p><mathjax>#K_text(h) = (["HA"]["OH"^"-"])/(["A"^"-"]) = 5.6 × 10^"-10"#</mathjax></p> <p><mathjax>#x^2/("0.2-"x) = 5.6 × 10^"-10"#</mathjax></p> <blockquote></blockquote> <p><strong>Apply the 5 % rule</strong></p> <p><mathjax>#0.2/(5.6 × 10^"-10") = 3.6 × 10^8 > 400#</mathjax>.</p> <p>∴ <mathjax>#x ≪0.2#</mathjax></p> <blockquote></blockquote> <p>Then</p> <p><mathjax>#x^2/0.2 = 5.6 × 10^"-10"#</mathjax></p> <p><mathjax>#x^2 = 0.2(5.6 × 10^"-10") = 1.1 × 10^"-10"#</mathjax></p> <p><mathjax>#x = 1.1 × 10^"-5"#</mathjax></p> <p><mathjax>#["OH"^"-"] = x color(white)(l)"mol/L" = 1.1 × 10^"-5"color(white)(l) "mol/L"#</mathjax></p> <p><mathjax>#"pOH" = "-log"["OH"^"-"] = "-log"(1.1 × 10^"-5") = 4.98#</mathjax></p> <p><mathjax>#"pH = 14.00 - pOH = 14.00 - 4.98 = 9.02"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/619176" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-of-a-solution"> How do you determine ph of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-at-an-equivalence-point"> How do you determine pH at an equivalence point? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-molarity"> How do you determine pH from molarity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-alkalinity-mean"> What does alkalinity mean? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-base"> What is a base? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-acid-base-indicators-change-color"> How do acid base indicators change color? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-neutral-ph"> What is a neutral pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-alkalinity-affect-pool-water"> How does alkalinity affect pool water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ph-important-in-drinking-water"> Why is pH important in drinking water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-ph-of-solution"> How can I calculate the pH of a solution? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/ph-calculations"> See all questions in pH calculations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 4654 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Calculate the pH of a #"0.2 M"# solution of #"NaC"_2"H"_3"O"_2# given that the hydrolysis constant is #K_h = 5.6xx10^(-10)#?	null
1,896	ab44691b-6ddd-11ea-b148-ccda262736ce	https://socratic.org/questions/the-simplest-formula-for-butane-is-c2h5-and-its-molecular-mass-is-about-60-what-	C4H10	start chemical_formula qc_end physical_unit 4 4 13 13 molecular_weight qc_end c_other OTHER qc_end end	[{"type":"other","value":"Chemical Formula [OF] butane [IN] molecular"}]	[{"type":"chemical equation","value":"C4H10"}]	[{"type":"physical unit","value":"Molecular mass [OF] butane [=] \\pu{60}"},{"type":"other","value":"The simplest formula for butane is C2H5."}]	<h1 class="questionTitle" itemprop="name">The simplest formula for butane is C2H5 and its molecular mass is about 60. What is the molecular formula of butane?</h1>	null	C4H10	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To determine the molecular formula from the empirical (simplest) formula, you need to compare the empirical formula mass to the molecular formula mass.</p> <p>Divide the molecular formula mass by the empirical formula mass. The result is the factor by which the subscripts in the empirical formula will be multiplied to determine the subscripts of the molecular formula.</p> <p>To determine the empirical formula mass, multiply the subscript of each element by its atomic weight on <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a>.</p> <p>The empirical formula mass is:</p> <p><mathjax>#(2xx"12.011 u C") + (5xx"1.008 u H")="29.062 u C"_2"H"_5"#</mathjax></p> <p><mathjax>#"60 u"/"29.062 u"=2#</mathjax> rounded to one significant figure.</p> <p>Multiply the subscripts of the empirical formula by <mathjax>#2#</mathjax>.</p> <p><mathjax>#C_((2xx2))H_((2xx5))="C"_4"H"_10"#</mathjax></p> <p>The molecular formula for butane is:</p> <p><mathjax>#"C"_4"H"_10#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The molecular formula for butane is <mathjax>#"C"_4"H"_10"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To determine the molecular formula from the empirical (simplest) formula, you need to compare the empirical formula mass to the molecular formula mass.</p> <p>Divide the molecular formula mass by the empirical formula mass. The result is the factor by which the subscripts in the empirical formula will be multiplied to determine the subscripts of the molecular formula.</p> <p>To determine the empirical formula mass, multiply the subscript of each element by its atomic weight on <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a>.</p> <p>The empirical formula mass is:</p> <p><mathjax>#(2xx"12.011 u C") + (5xx"1.008 u H")="29.062 u C"_2"H"_5"#</mathjax></p> <p><mathjax>#"60 u"/"29.062 u"=2#</mathjax> rounded to one significant figure.</p> <p>Multiply the subscripts of the empirical formula by <mathjax>#2#</mathjax>.</p> <p><mathjax>#C_((2xx2))H_((2xx5))="C"_4"H"_10"#</mathjax></p> <p>The molecular formula for butane is:</p> <p><mathjax>#"C"_4"H"_10#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">The simplest formula for butane is C2H5 and its molecular mass is about 60. What is the molecular formula of butane?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/determining-formula-and-molar-masses" itemprop="url"> <span class="breadcrumb" itemprop="title">Determining Formula</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="614287" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-05-16T01:29:01" itemprop="dateCreated"> May 16, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The molecular formula for butane is <mathjax>#"C"_4"H"_10"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To determine the molecular formula from the empirical (simplest) formula, you need to compare the empirical formula mass to the molecular formula mass.</p> <p>Divide the molecular formula mass by the empirical formula mass. The result is the factor by which the subscripts in the empirical formula will be multiplied to determine the subscripts of the molecular formula.</p> <p>To determine the empirical formula mass, multiply the subscript of each element by its atomic weight on <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a>.</p> <p>The empirical formula mass is:</p> <p><mathjax>#(2xx"12.011 u C") + (5xx"1.008 u H")="29.062 u C"_2"H"_5"#</mathjax></p> <p><mathjax>#"60 u"/"29.062 u"=2#</mathjax> rounded to one significant figure.</p> <p>Multiply the subscripts of the empirical formula by <mathjax>#2#</mathjax>.</p> <p><mathjax>#C_((2xx2))H_((2xx5))="C"_4"H"_10"#</mathjax></p> <p>The molecular formula for butane is:</p> <p><mathjax>#"C"_4"H"_10#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/614287" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-it-possible-to-find-a-molecular-formula-from-molar-mass"> Is it possible to find a molecular formula from molar mass? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5368e0cc02bf34779e175781"> Question #75781 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-common-mistakes-students-make-when-determining-formulas"> What are some common mistakes students make when determining formulas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-formula-of-an-acid"> How can I determine the formula of an acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-chemical-formula-of-a-product"> How can I determine the chemical formula of a product? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-empirical-formula-of-a-compound"> How can I determine the empirical formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-formula-of-a-hydrate"> How can I determine the formula of a hydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-the-empirical-formula-indicate"> What does the empirical formula indicate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-molecule-with-molecular-weight-of-180-18-g-mol-is-analyzed-and-found-to-contai"> A molecule with molecular weight of 180.18 g/mol is analyzed and found to contain 40.00% carbon,... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/do-i-need-to-know-the-number-of-moles-of-each-element-to-determine-the-formula-o"> Do I need to know the number of moles of each element to determine the formula of the compound? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/determining-formula-and-molar-masses"> See all questions in Determining Formula </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 19557 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	The simplest formula for butane is C2H5 and its molecular mass is about 60. What is the molecular formula of butane?	null
1,897	acdef200-6ddd-11ea-8fe9-ccda262736ce	https://socratic.org/questions/a-gas-at-a-constant-volume-has-an-initial-temperature-of-300-0-k-and-an-initial-	16.67 atm	start physical_unit 23 24 pressure atm qc_end physical_unit 23 24 18 19 pressure qc_end physical_unit 23 24 11 12 temperature qc_end physical_unit 23 24 30 31 temperature qc_end end	[{"type":"physical unit","value":"Pressure2 [OF] the gas [IN] atm"}]	[{"type":"physical unit","value":"16.67 atm"}]	[{"type":"physical unit","value":"Pressure1 [OF] the gas [=] \\pu{10.0 atm}"},{"type":"physical unit","value":"Temperature1 [OF] the gas [=] \\pu{300.0 K}"},{"type":"physical unit","value":"Temperature2 [OF] the gas [=] \\pu{500.0 K}"}]	<h1 class="questionTitle" itemprop="name">A gas at a constant volume has an initial temperature of 300.0 K and an initial pressure of 10.0 atm. What pressure does the gas exert at a temperature of 500.0 K?</h1>	null	16.67 atm	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>As you know, <a href="http://socratic.org/chemistry/the-behavior-of-gases/gas-pressure">gas pressure</a> is caused by the collisions between the gas molecules and the walls of the container. </p> <p>The <strong>more powerful and frequent</strong> these collisions are, the <strong>higher</strong> the pressure exerted by the gas. </p> <p>Now, temperature is actually a measure of the <em>average kinetic speed</em> of the gas molecules. This means that <strong>increasing</strong> the temperature of a gas is equivalent to <strong>increasing</strong> the average kinetic energy of its molecules. </p> <p>When volume and number of moles of gas are <strong>kept constant</strong>, <em>increasing</em> the temperature of the gas will result in an <strong>increase</strong> in pressure - this is known as <strong><a href="http://socratic.org/chemistry/the-behavior-of-gases/gay-lussac-s-law">Gay Lussac's Law</a></strong>. </p> <p><img alt="https://www.coursehero.com/file/13139540/3-Gay-Lussacs-Law-and-temperaturepdf/" src="https://useruploads.socratic.org/3jjcfJlKQ1Gfxlp8xJdR_gay-lusac.jpg"/> </p> <p>This happens because if the molecules are moving at a <em>higher</em> average kinetic energy, they will hit the walls of the container with <strong>more force</strong> and <strong>more frequent</strong> <mathjax>#->#</mathjax> gas pressure will <strong>increase</strong>. </p> <p>Mathematically, this is written as </p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul( color(white)(a/a)P_1/T_1 = P_2/T_2color(white)(a/a)\|)))" "#</mathjax>, where</p> </blockquote> <p><mathjax>#P_1#</mathjax>, <mathjax>#T_1#</mathjax> - the pressure and temperature of the gas at an initial state<br/> <mathjax>#P_2#</mathjax>, <mathjax>#T_2#</mathjax> - the pressure and temperature of the gas at a final state</p> <p>It's <strong>very important</strong> to remember that the temperature of the gas <strong>must</strong> be expressed in <em>Kelvin</em>! </p> <p>So, rearrange the equation to solve for <mathjax>#P_2#</mathjax></p> <blockquote> <p><mathjax>#P_2 = T_2/T_1 * P_1#</mathjax></p> </blockquote> <p>Plug in your values to find</p> <blockquote> <p><mathjax>#P_2 = (500.0 color(red)(cancel(color(black)("K"))))/(300.0color(red)(cancel(color(black)("K")))) * "10.0 atm" = "16.667 atm"#</mathjax></p> </blockquote> <p>Rounded to three <strong><a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the initial pressure of the gas, the answer will be</p> <blockquote> <p><mathjax>#P_2 = color(green)(\|bar(ul(color(white)(a/a)"16.7 atm"color(white)(a/a)\|)))#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"16.7 atm"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>As you know, <a href="http://socratic.org/chemistry/the-behavior-of-gases/gas-pressure">gas pressure</a> is caused by the collisions between the gas molecules and the walls of the container. </p> <p>The <strong>more powerful and frequent</strong> these collisions are, the <strong>higher</strong> the pressure exerted by the gas. </p> <p>Now, temperature is actually a measure of the <em>average kinetic speed</em> of the gas molecules. This means that <strong>increasing</strong> the temperature of a gas is equivalent to <strong>increasing</strong> the average kinetic energy of its molecules. </p> <p>When volume and number of moles of gas are <strong>kept constant</strong>, <em>increasing</em> the temperature of the gas will result in an <strong>increase</strong> in pressure - this is known as <strong><a href="http://socratic.org/chemistry/the-behavior-of-gases/gay-lussac-s-law">Gay Lussac's Law</a></strong>. </p> <p><img alt="https://www.coursehero.com/file/13139540/3-Gay-Lussacs-Law-and-temperaturepdf/" src="https://useruploads.socratic.org/3jjcfJlKQ1Gfxlp8xJdR_gay-lusac.jpg"/> </p> <p>This happens because if the molecules are moving at a <em>higher</em> average kinetic energy, they will hit the walls of the container with <strong>more force</strong> and <strong>more frequent</strong> <mathjax>#->#</mathjax> gas pressure will <strong>increase</strong>. </p> <p>Mathematically, this is written as </p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul( color(white)(a/a)P_1/T_1 = P_2/T_2color(white)(a/a)\|)))" "#</mathjax>, where</p> </blockquote> <p><mathjax>#P_1#</mathjax>, <mathjax>#T_1#</mathjax> - the pressure and temperature of the gas at an initial state<br/> <mathjax>#P_2#</mathjax>, <mathjax>#T_2#</mathjax> - the pressure and temperature of the gas at a final state</p> <p>It's <strong>very important</strong> to remember that the temperature of the gas <strong>must</strong> be expressed in <em>Kelvin</em>! </p> <p>So, rearrange the equation to solve for <mathjax>#P_2#</mathjax></p> <blockquote> <p><mathjax>#P_2 = T_2/T_1 * P_1#</mathjax></p> </blockquote> <p>Plug in your values to find</p> <blockquote> <p><mathjax>#P_2 = (500.0 color(red)(cancel(color(black)("K"))))/(300.0color(red)(cancel(color(black)("K")))) * "10.0 atm" = "16.667 atm"#</mathjax></p> </blockquote> <p>Rounded to three <strong><a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the initial pressure of the gas, the answer will be</p> <blockquote> <p><mathjax>#P_2 = color(green)(\|bar(ul(color(white)(a/a)"16.7 atm"color(white)(a/a)\|)))#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A gas at a constant volume has an initial temperature of 300.0 K and an initial pressure of 10.0 atm. What pressure does the gas exert at a temperature of 500.0 K?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/gay-lussac-s-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Gay Lussac's Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="236780" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-08T12:52:24" itemprop="dateCreated"> Mar 8, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"16.7 atm"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>As you know, <a href="http://socratic.org/chemistry/the-behavior-of-gases/gas-pressure">gas pressure</a> is caused by the collisions between the gas molecules and the walls of the container. </p> <p>The <strong>more powerful and frequent</strong> these collisions are, the <strong>higher</strong> the pressure exerted by the gas. </p> <p>Now, temperature is actually a measure of the <em>average kinetic speed</em> of the gas molecules. This means that <strong>increasing</strong> the temperature of a gas is equivalent to <strong>increasing</strong> the average kinetic energy of its molecules. </p> <p>When volume and number of moles of gas are <strong>kept constant</strong>, <em>increasing</em> the temperature of the gas will result in an <strong>increase</strong> in pressure - this is known as <strong><a href="http://socratic.org/chemistry/the-behavior-of-gases/gay-lussac-s-law">Gay Lussac's Law</a></strong>. </p> <p><img alt="https://www.coursehero.com/file/13139540/3-Gay-Lussacs-Law-and-temperaturepdf/" src="https://useruploads.socratic.org/3jjcfJlKQ1Gfxlp8xJdR_gay-lusac.jpg"/> </p> <p>This happens because if the molecules are moving at a <em>higher</em> average kinetic energy, they will hit the walls of the container with <strong>more force</strong> and <strong>more frequent</strong> <mathjax>#->#</mathjax> gas pressure will <strong>increase</strong>. </p> <p>Mathematically, this is written as </p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul( color(white)(a/a)P_1/T_1 = P_2/T_2color(white)(a/a)\|)))" "#</mathjax>, where</p> </blockquote> <p><mathjax>#P_1#</mathjax>, <mathjax>#T_1#</mathjax> - the pressure and temperature of the gas at an initial state<br/> <mathjax>#P_2#</mathjax>, <mathjax>#T_2#</mathjax> - the pressure and temperature of the gas at a final state</p> <p>It's <strong>very important</strong> to remember that the temperature of the gas <strong>must</strong> be expressed in <em>Kelvin</em>! </p> <p>So, rearrange the equation to solve for <mathjax>#P_2#</mathjax></p> <blockquote> <p><mathjax>#P_2 = T_2/T_1 * P_1#</mathjax></p> </blockquote> <p>Plug in your values to find</p> <blockquote> <p><mathjax>#P_2 = (500.0 color(red)(cancel(color(black)("K"))))/(300.0color(red)(cancel(color(black)("K")))) * "10.0 atm" = "16.667 atm"#</mathjax></p> </blockquote> <p>Rounded to three <strong><a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the initial pressure of the gas, the answer will be</p> <blockquote> <p><mathjax>#P_2 = color(green)(\|bar(ul(color(white)(a/a)"16.7 atm"color(white)(a/a)\|)))#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/236780" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535d701102bf342f53d9bcb0"> Question #9bcb0 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-gay-lussac-s-law-formula"> What is the Gay Lussac's law formula? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-the-temperature-of-a-gas-in-a-container-is-doubled-on-the-kelvin-scale-the-pr"> If the temperature of a gas in a container is doubled on the Kelvin scale, what will happen to... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-the-original-pressure-of-a-gas-sample-at-20-c-was-5-00-atm-and-it-is-heated-u"> If the original pressure of a gas sample at 20 ˚C was 5.00 atm, and it is heated up to 40. ˚C ,... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-gay-lussac-s-law-state"> What does Gay Lussac's law state? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-gay-lussac-s-law-relate"> What does Gay Lussac's law relate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-sample-of-o2-under-2-00-atm-occupies-500-ml-at-25-0-c-what-pressure-will-the-s"> A sample of O2 under 2.00 atm occupies 500 ml at 25.0˚C. 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What pressure does the gas exert at a temperature of 500.0 K?	null
1,898	abaf8bd8-6ddd-11ea-b01c-ccda262736ce	https://socratic.org/questions/a-certain-mass-of-cac-2-reacts-completely-with-water-to-give-64-5-l-of-c-2h-2-at	134 L	start physical_unit 14 14 volume l qc_end c_other OTHER qc_end physical_unit 14 14 11 12 volume qc_end c_other OTHER qc_end chemical_equation 62 69 qc_end end	[{"type":"physical unit","value":"Volume2 [OF] C2H2 [IN] L"}]	[{"type":"physical unit","value":"134 L"}]	[{"type":"other","value":"CaC2 reacts completely with water."},{"type":"physical unit","value":"Volume1 [OF] C2H2 [=] \\pu{64.5 L}"},{"type":"physical unit","value":"Temperature1 [OF] the reaction [=] \\pu{50.0 ℃}"},{"type":"physical unit","value":"Pressure1 [OF] the reaction [=] \\pu{1.00 atm}"},{"type":"other","value":"The same mass of CaC2."},{"type":"physical unit","value":"Temperature2 [OF] the reaction [=] \\pu{400.0 ℃}"},{"type":"physical unit","value":"Pressure2 [OF] the reaction [=] \\pu{1.00 atm}"},{"type":"chemical equation","value":"CaC2 + 2 H2O -> Ca(OH)2 + C2H2"}]	<h1 class="questionTitle" itemprop="name">A certain mass of #CaC_2# reacts completely with water to give 64.5 L of #C_2H_2# at 50.0 C and 1.00 atm. If the same mass of #CaC_2# reacts completely at 400.0 C and P = 1.00 atm, what volume of #C_2H_2# will be collected at the higher temperature?</h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>Calcium carbide (<mathjax>#CaC_2#</mathjax>) reacts with water to produce acetylene (<mathjax>#C_2H_2#</mathjax>) according to the equation <br/> <mathjax>#CaC_2 + 2H_2O -> Ca(OH)_2 + C_2H_2#</mathjax></p></div> </h2> </div> </div>	134 L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>This is really a disguised <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/charles-law">Charles' Law</a></strong> problem.</p> <p>In each case, we have the same mass and therefore the same number of moles of calcium carbide.</p> <p>Hence, we will have the same number of moles of acetylene in each case.</p> <p>Thus, <mathjax>#n#</mathjax> and <mathjax>#P#</mathjax> are constant; the only variables are <mathjax>#V#</mathjax> and <mathjax>#T#</mathjax>.</p> <blockquote></blockquote> <p>Charles' Law is</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(\|color(white)(a/a) V_1/T_1 = V_2/T_2color(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>We can rearrange this to get</p> <blockquote> <blockquote> <p><mathjax>#V_2 = V_1 × T_2/T_1#</mathjax></p> </blockquote> </blockquote> <p>In this problem,</p> <p><mathjax>#V_1 = "64.5 L"; T_1 = color(white)(ll)"50.0 °C" = "323.15 K"#</mathjax><br/> <mathjax>#V_2 = ?color(white)(mml); T_2 = "400.0 °C" = "673.15 K"#</mathjax></p> <p>∴ <mathjax>#V_2 = "64.5 L" × (673.15 color(red)(cancel(color(black)("K"))))/(323.15 color(red)(cancel(color(black)("K")))) = "134 L"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The volume of acetylene is 134 L.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>This is really a disguised <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/charles-law">Charles' Law</a></strong> problem.</p> <p>In each case, we have the same mass and therefore the same number of moles of calcium carbide.</p> <p>Hence, we will have the same number of moles of acetylene in each case.</p> <p>Thus, <mathjax>#n#</mathjax> and <mathjax>#P#</mathjax> are constant; the only variables are <mathjax>#V#</mathjax> and <mathjax>#T#</mathjax>.</p> <blockquote></blockquote> <p>Charles' Law is</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(\|color(white)(a/a) V_1/T_1 = V_2/T_2color(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>We can rearrange this to get</p> <blockquote> <blockquote> <p><mathjax>#V_2 = V_1 × T_2/T_1#</mathjax></p> </blockquote> </blockquote> <p>In this problem,</p> <p><mathjax>#V_1 = "64.5 L"; T_1 = color(white)(ll)"50.0 °C" = "323.15 K"#</mathjax><br/> <mathjax>#V_2 = ?color(white)(mml); T_2 = "400.0 °C" = "673.15 K"#</mathjax></p> <p>∴ <mathjax>#V_2 = "64.5 L" × (673.15 color(red)(cancel(color(black)("K"))))/(323.15 color(red)(cancel(color(black)("K")))) = "134 L"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A certain mass of #CaC_2# reacts completely with water to give 64.5 L of #C_2H_2# at 50.0 C and 1.00 atm. If the same mass of #CaC_2# reacts completely at 400.0 C and P = 1.00 atm, what volume of #C_2H_2# will be collected at the higher temperature?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>Calcium carbide (<mathjax>#CaC_2#</mathjax>) reacts with water to produce acetylene (<mathjax>#C_2H_2#</mathjax>) according to the equation <br/> <mathjax>#CaC_2 + 2H_2O -> Ca(OH)_2 + C_2H_2#</mathjax></p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/measuring-gas-pressure" itemprop="url"> <span class="breadcrumb" itemprop="title">Measuring Gas Pressure</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="377940" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-02-14T22:12:29" itemprop="dateCreated"> Feb 14, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The volume of acetylene is 134 L.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>This is really a disguised <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/charles-law">Charles' Law</a></strong> problem.</p> <p>In each case, we have the same mass and therefore the same number of moles of calcium carbide.</p> <p>Hence, we will have the same number of moles of acetylene in each case.</p> <p>Thus, <mathjax>#n#</mathjax> and <mathjax>#P#</mathjax> are constant; the only variables are <mathjax>#V#</mathjax> and <mathjax>#T#</mathjax>.</p> <blockquote></blockquote> <p>Charles' Law is</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(\|color(white)(a/a) V_1/T_1 = V_2/T_2color(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>We can rearrange this to get</p> <blockquote> <blockquote> <p><mathjax>#V_2 = V_1 × T_2/T_1#</mathjax></p> </blockquote> </blockquote> <p>In this problem,</p> <p><mathjax>#V_1 = "64.5 L"; T_1 = color(white)(ll)"50.0 °C" = "323.15 K"#</mathjax><br/> <mathjax>#V_2 = ?color(white)(mml); T_2 = "400.0 °C" = "673.15 K"#</mathjax></p> <p>∴ <mathjax>#V_2 = "64.5 L" × (673.15 color(red)(cancel(color(black)("K"))))/(323.15 color(red)(cancel(color(black)("K")))) = "134 L"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/377940" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-used-to-measure-gas-pressure-in-a-closed-container"> What is used to measure gas pressure in a closed container? 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If the same mass of #CaC_2# reacts completely at 400.0 C and P = 1.00 atm, what volume of #C_2H_2# will be collected at the higher temperature?	Calcium carbide (#CaC_2#) reacts with water to produce acetylene (#C_2H_2#) according to the equation #CaC_2 + 2H_2O -> Ca(OH)_2 + C_2H_2#
1,899	abe4a4e8-6ddd-11ea-9d00-ccda262736ce	https://socratic.org/questions/my-theoretical-yield-of-beryllium-chloride-was-10-7-grams-in-be-2hcl-becl-2-h-2-	42.06%	start physical_unit 4 5 percent_yield none qc_end physical_unit 4 5 7 8 theoretical_yield qc_end physical_unit 4 5 23 24 actual_yield qc_end chemical_equation 10 17 qc_end end	[{"type":"physical unit","value":"Percent yield [OF] beryllium chloride"}]	[{"type":"physical unit","value":"42.06%"}]	[{"type":"physical unit","value":"Theoretical yield [OF] beryllium chloride [=] \\pu{10.7 grams}"},{"type":"physical unit","value":"Actual yield [OF] beryllium chloride [=] \\pu{4.5 grams}"},{"type":"chemical equation","value":"Be + 2 HCl -> BeCl2 + H2"}]	<h1 class="questionTitle" itemprop="name">My theoretical yield of beryllium chloride was 10.7 grams in #Be + 2HCl -> BeCl_2 + H_2#. If my actual yield was 4.5 grams, what was my percent yield?</h1>	null	42.06%	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You're dealing with a <strong><a href="http://socratic.org/chemistry/chemical-reactions/single-replacement-reactions">single replacement reaction</a></strong> in which beryllium metal, <mathjax>#"Be"#</mathjax>, reacts with hydrochloric acid, <mathjax>#"HCl"#</mathjax>, to form <em>aqueous</em> beryllium chloride, <mathjax>#"BeCl"_2#</mathjax>, and hydrogen gas, <mathjax>#"H"_2#</mathjax>, which bubbles out of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a>. </p> <blockquote> <p><mathjax>#"Be"_text((s]) + 2"HCl"_text((aq]) -> "BeCl"_text(2(aq]) + "H"_text(2(g]) uarr#</mathjax></p> </blockquote> <p>The <strong>theoretical yield</strong> of beryllium chloride is calculated by taking into account the <strong>stoichiometric coefficients</strong> of the reactants and of beryllium chloride. </p> <p>More specifically, you know that <strong>one mole</strong> of beryllium metal reacts with <strong>two moles</strong> of hydrochloric acid to form <strong>one mole</strong> of aqueous beryllium chloride. </p> <p>This corresponds to a reaction that has a <mathjax>#100%#</mathjax> yield. In your case, the theoretical yield is said to be equal to <mathjax>#"10.7 g"#</mathjax>. This corresponds to the <mathjax>#1:1#</mathjax> mole ratio that exists between beryllium metal and beryllium chloride. </p> <p>However, you collect <mathjax>#"4.5 g"#</mathjax> of beryllium chloride, your <strong>actual yield</strong>. </p> <p>The <strong><a href="http://socratic.org/chemistry/stoichiometry/percent-yield">percent yield</a></strong> of a chemical reaction is defined as </p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a)"% yield" = "what you actually get"/"what you should theoretically get" xx 100color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>Plug in your values to get</p> <blockquote> <p><mathjax>#"% yield" = (4.5 color(red)(cancel(color(black)("g"))))/(10.7color(red)(cancel(color(black)("g")))) xx 100 = color(green)(\|bar(ul(color(white)(a/a)42%color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer is rounded to two <strong><a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the actual yield of the reaction. </p> <p> <iframe src="https://www.youtube.com/embed/LQN9lH9WAVQ?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"% yield" = 42%#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You're dealing with a <strong><a href="http://socratic.org/chemistry/chemical-reactions/single-replacement-reactions">single replacement reaction</a></strong> in which beryllium metal, <mathjax>#"Be"#</mathjax>, reacts with hydrochloric acid, <mathjax>#"HCl"#</mathjax>, to form <em>aqueous</em> beryllium chloride, <mathjax>#"BeCl"_2#</mathjax>, and hydrogen gas, <mathjax>#"H"_2#</mathjax>, which bubbles out of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a>. </p> <blockquote> <p><mathjax>#"Be"_text((s]) + 2"HCl"_text((aq]) -> "BeCl"_text(2(aq]) + "H"_text(2(g]) uarr#</mathjax></p> </blockquote> <p>The <strong>theoretical yield</strong> of beryllium chloride is calculated by taking into account the <strong>stoichiometric coefficients</strong> of the reactants and of beryllium chloride. </p> <p>More specifically, you know that <strong>one mole</strong> of beryllium metal reacts with <strong>two moles</strong> of hydrochloric acid to form <strong>one mole</strong> of aqueous beryllium chloride. </p> <p>This corresponds to a reaction that has a <mathjax>#100%#</mathjax> yield. In your case, the theoretical yield is said to be equal to <mathjax>#"10.7 g"#</mathjax>. This corresponds to the <mathjax>#1:1#</mathjax> mole ratio that exists between beryllium metal and beryllium chloride. </p> <p>However, you collect <mathjax>#"4.5 g"#</mathjax> of beryllium chloride, your <strong>actual yield</strong>. </p> <p>The <strong><a href="http://socratic.org/chemistry/stoichiometry/percent-yield">percent yield</a></strong> of a chemical reaction is defined as </p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a)"% yield" = "what you actually get"/"what you should theoretically get" xx 100color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>Plug in your values to get</p> <blockquote> <p><mathjax>#"% yield" = (4.5 color(red)(cancel(color(black)("g"))))/(10.7color(red)(cancel(color(black)("g")))) xx 100 = color(green)(\|bar(ul(color(white)(a/a)42%color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer is rounded to two <strong><a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the actual yield of the reaction. </p> <p> <iframe src="https://www.youtube.com/embed/LQN9lH9WAVQ?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">My theoretical yield of beryllium chloride was 10.7 grams in #Be + 2HCl -> BeCl_2 + H_2#. If my actual yield was 4.5 grams, what was my percent yield?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/percent-yield" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Yield</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="241721" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-19T01:31:28" itemprop="dateCreated"> Mar 19, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"% yield" = 42%#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You're dealing with a <strong><a href="http://socratic.org/chemistry/chemical-reactions/single-replacement-reactions">single replacement reaction</a></strong> in which beryllium metal, <mathjax>#"Be"#</mathjax>, reacts with hydrochloric acid, <mathjax>#"HCl"#</mathjax>, to form <em>aqueous</em> beryllium chloride, <mathjax>#"BeCl"_2#</mathjax>, and hydrogen gas, <mathjax>#"H"_2#</mathjax>, which bubbles out of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a>. </p> <blockquote> <p><mathjax>#"Be"_text((s]) + 2"HCl"_text((aq]) -> "BeCl"_text(2(aq]) + "H"_text(2(g]) uarr#</mathjax></p> </blockquote> <p>The <strong>theoretical yield</strong> of beryllium chloride is calculated by taking into account the <strong>stoichiometric coefficients</strong> of the reactants and of beryllium chloride. </p> <p>More specifically, you know that <strong>one mole</strong> of beryllium metal reacts with <strong>two moles</strong> of hydrochloric acid to form <strong>one mole</strong> of aqueous beryllium chloride. </p> <p>This corresponds to a reaction that has a <mathjax>#100%#</mathjax> yield. In your case, the theoretical yield is said to be equal to <mathjax>#"10.7 g"#</mathjax>. This corresponds to the <mathjax>#1:1#</mathjax> mole ratio that exists between beryllium metal and beryllium chloride. </p> <p>However, you collect <mathjax>#"4.5 g"#</mathjax> of beryllium chloride, your <strong>actual yield</strong>. </p> <p>The <strong><a href="http://socratic.org/chemistry/stoichiometry/percent-yield">percent yield</a></strong> of a chemical reaction is defined as </p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a)"% yield" = "what you actually get"/"what you should theoretically get" xx 100color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>Plug in your values to get</p> <blockquote> <p><mathjax>#"% yield" = (4.5 color(red)(cancel(color(black)("g"))))/(10.7color(red)(cancel(color(black)("g")))) xx 100 = color(green)(\|bar(ul(color(white)(a/a)42%color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer is rounded to two <strong><a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the actual yield of the reaction. </p> <p> <iframe src="https://www.youtube.com/embed/LQN9lH9WAVQ?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/241721" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ebd02bf3469570e2e62"> Question #e2e62 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ec502bf34694a4fee2e"> Question #fee2e </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ec902bf34694a4fee32"> Question #fee32 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ece02bf346950519e89"> Question #19e89 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ed302bf34694c8c5bdc"> Question #c5bdc </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ee302bf3469517a1065"> Question #a1065 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-would-be-the-limiting-reagent-if-26-0-grams-of-c3h9n-were-reacted-with-46-3"> What would be the limiting reagent if 26.0 grams of C3H9N were reacted with 46.3 grams of... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-percent-yield-always-less-than-100"> Is percent yield always less than 100? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-would-be-the-limiting-reagent-if-41-9-grams-of-c2h3of-were-reacted-with-61-"> What would be the limiting reagent if 41.9 grams of C2H3OF were reacted with 61.0 grams of... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-yield-of-the-following-reaction-if-60-grams-of-caco3-is-heat"> What is the percent yield of the following reaction if 60 grams of CaCO3 is heated to give 15... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/percent-yield"> See all questions in Percent Yield </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 11354 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	My theoretical yield of beryllium chloride was 10.7 grams in #Be + 2HCl -> BeCl_2 + H_2#. If my actual yield was 4.5 grams, what was my percent yield?	null

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