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1,700	abd0755e-6ddd-11ea-b19e-ccda262736ce	https://socratic.org/questions/what-mass-of-carbon-dioxide-is-made-when-22-g-of-propane-is-burned-in-oxygen	66 g	start physical_unit 3 4 mass g qc_end physical_unit 11 11 8 9 mass qc_end substance 15 15 qc_end end	[{"type":"physical unit","value":"Mass [OF] carbon dioxide [IN] g"}]	[{"type":"physical unit","value":"66 g"}]	[{"type":"physical unit","value":"Mass [OF] propane [=] \\pu{22 g}"},{"type":"substance name","value":"Oxygen"}]	<h1 class="questionTitle" itemprop="name">What mass of carbon dioxide is made when 22 g of propane is burned in oxygen? </h1>	null	66 g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The common currency of chemistry is moles. So it is necessary to change the mass of propane to moles. Then write a balance equation so the moles of propane to moles of Carbon Dioxide. Finally moles of Carbon Dioxide must be changed to grams. </p> <p><mathjax># C_3H_8 +5 O_2== 3 CO_2 + 4 H_2O #</mathjax> </p> <p>This is the balance equation for the burning of propane in Oxygen.</p> <p>From the equation it can be seen that 1 mole of propane makes 3 moles of Carbon Dioxide a ratio of 1:3 </p> <p>Convert 22 grams of propane to moles by dividing by the molar mass of propane. </p> <p>3 x 12 = 36 grams <br/> 1 x 8 = + 8 grams <br/> total = 44 grams/ mole. </p> <p><mathjax># 22/44#</mathjax> = .5 moles of propane. </p> <p>Using the ratio of 1:3 .5 = 3( .5) = 1.5 moles of Carbon Dioxide. </p> <p>Now multiply 1.5 moles of Carbon Dioxide by the molar mass of Carbon Dioxide </p> <p>1 x 12 = 12 grams <br/> 2 x 16 = +32 grams <br/> total = 44 grams /mole.</p> <p>1.5 moles x 44 grams/mole = 66 grams. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>66 grams of Carbon Dioxide. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The common currency of chemistry is moles. So it is necessary to change the mass of propane to moles. Then write a balance equation so the moles of propane to moles of Carbon Dioxide. Finally moles of Carbon Dioxide must be changed to grams. </p> <p><mathjax># C_3H_8 +5 O_2== 3 CO_2 + 4 H_2O #</mathjax> </p> <p>This is the balance equation for the burning of propane in Oxygen.</p> <p>From the equation it can be seen that 1 mole of propane makes 3 moles of Carbon Dioxide a ratio of 1:3 </p> <p>Convert 22 grams of propane to moles by dividing by the molar mass of propane. </p> <p>3 x 12 = 36 grams <br/> 1 x 8 = + 8 grams <br/> total = 44 grams/ mole. </p> <p><mathjax># 22/44#</mathjax> = .5 moles of propane. </p> <p>Using the ratio of 1:3 .5 = 3( .5) = 1.5 moles of Carbon Dioxide. </p> <p>Now multiply 1.5 moles of Carbon Dioxide by the molar mass of Carbon Dioxide </p> <p>1 x 12 = 12 grams <br/> 2 x 16 = +32 grams <br/> total = 44 grams /mole.</p> <p>1.5 moles x 44 grams/mole = 66 grams. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What mass of carbon dioxide is made when 22 g of propane is burned in oxygen? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-reactions-and-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions and Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="321155" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/david-drayer"><img alt="" class="" src="https://graph.facebook.com/10206723679871989/picture?height=50&width=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/david-drayer"> David Drayer </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-10-13T04:06:01" itemprop="dateCreated"> Oct 13, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>66 grams of Carbon Dioxide. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The common currency of chemistry is moles. So it is necessary to change the mass of propane to moles. Then write a balance equation so the moles of propane to moles of Carbon Dioxide. Finally moles of Carbon Dioxide must be changed to grams. </p> <p><mathjax># C_3H_8 +5 O_2== 3 CO_2 + 4 H_2O #</mathjax> </p> <p>This is the balance equation for the burning of propane in Oxygen.</p> <p>From the equation it can be seen that 1 mole of propane makes 3 moles of Carbon Dioxide a ratio of 1:3 </p> <p>Convert 22 grams of propane to moles by dividing by the molar mass of propane. </p> <p>3 x 12 = 36 grams <br/> 1 x 8 = + 8 grams <br/> total = 44 grams/ mole. </p> <p><mathjax># 22/44#</mathjax> = .5 moles of propane. </p> <p>Using the ratio of 1:3 .5 = 3( .5) = 1.5 moles of Carbon Dioxide. </p> <p>Now multiply 1.5 moles of Carbon Dioxide by the molar mass of Carbon Dioxide </p> <p>1 x 12 = 12 grams <br/> 2 x 16 = +32 grams <br/> total = 44 grams /mole.</p> <p>1.5 moles x 44 grams/mole = 66 grams. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/321155" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb002bf34694a4fee47"> Question #fee47 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb402bf34694c8c5c15"> Question #c5c15 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb802bf346950519eb9"> Question #19eb9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cbf02bf3469570e2ea2"> Question #e2ea2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc002bf34695a6bc751"> Question #bc751 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc202bf3469570e2ea6"> Question #e2ea6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531e867a02bf342492a08b07"> Question #08b07 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-thermochemical-equation-for-the-combustion-of-benzene"> What is the thermochemical equation for the combustion of benzene? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-reversible"> Why are chemical reactions reversible? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-important"> Why are chemical reactions important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/chemical-reactions-and-equations"> See all questions in Chemical Reactions and Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 45908 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What mass of carbon dioxide is made when 22 g of propane is burned in oxygen?	null
1,701	abd2a51c-6ddd-11ea-b292-ccda262736ce	https://socratic.org/questions/a-vinegar-solution-has-a-oh-4-2-10-10-m-at-25-c-what-is-the-h-3o-of-the-vinegar-	2.38 × 10^(-5) M	start physical_unit 1 2 [h3o+] mol/l qc_end physical_unit 1 2 7 10 [oh-] qc_end physical_unit 1 2 12 13 temperature qc_end end	[{"type":"physical unit","value":"[H3O+] [OF] vinegar solution [IN] M"}]	[{"type":"physical unit","value":"2.38 × 10^(-5) M"}]	[{"type":"physical unit","value":"[OH-] [OF] vinegar solution [=] \\pu{4.2 × 10^(-10) M}"},{"type":"physical unit","value":"Temperature [OF] vinegar solution [=] \\pu{25 ℃}"}]	<h1 class="questionTitle" itemprop="name"> A vinegar solution has a #[OH^-] = 4.2*10^-10# #M# at 25°C. What is the #[H_3O^+]# of the vinegar solution?</h1>	null	2.38 × 10^(-5) M	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#[HO^-]=4.2xx10^-10#</mathjax>; <mathjax>#pOH=-log_10(4.2xx10^-10)=9.38#</mathjax>;</p> <p><mathjax>#pH=14-9.38=4.62#</mathjax></p> <p>And thus <mathjax>#[H_3O^+]=10^(-4.62)=2.38xx10^-5molL^-1.#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#[H_3O^+]=2.38xx10^-5molL^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#[HO^-]=4.2xx10^-10#</mathjax>; <mathjax>#pOH=-log_10(4.2xx10^-10)=9.38#</mathjax>;</p> <p><mathjax>#pH=14-9.38=4.62#</mathjax></p> <p>And thus <mathjax>#[H_3O^+]=10^(-4.62)=2.38xx10^-5molL^-1.#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name"> A vinegar solution has a #[OH^-] = 4.210^-10# #M# at 25°C. What is the #[H_3O^+]# of the vinegar solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/solutions" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="352992" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-12-16T22:50:12" itemprop="dateCreated"> Dec 16, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#[H_3O^+]=2.38xx10^-5molL^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#[HO^-]=4.2xx10^-10#</mathjax>; <mathjax>#pOH=-log_10(4.2xx10^-10)=9.38#</mathjax>;</p> <p><mathjax>#pH=14-9.38=4.62#</mathjax></p> <p>And thus <mathjax>#[H_3O^+]=10^(-4.62)=2.38xx10^-5mol*L^-1.#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/352992" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-solution-solute-and-solvent-related"> How are solution, solute, and solvent related? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-solutions-become-saturated"> Why do solutions become saturated? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-temperature-affect-solutions"> How does temperature affect solutions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-a-solution-differ-from-a-colloid"> How does a solution differ from a colloid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/calculate-the-amount-of-1-m-naoh-aqueous-solution-needed-to-make-100-ml-of-0-5-m"> Calculate the amount of 1 M NaOH aqueous solution needed to make 100 mL of 0.5 M NaOH aqueous solution. </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-buffering-a-solution-change-the-solutions-behavior"> How does buffering a solution change the solutions behavior? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-benedict-s-solution-change-colour"> How does Benedict's solution change colour? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/describe-how-would-you-prepare-1-l-of-a-1-m-solution-of-sodium-chloride-the-gram"> Describe how would you prepare 1 L of a 1 M solution of sodium chloride. The gram formula weight... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-solutions-differ-from-suspensions"> How do solutions differ from suspensions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-a-solution-differ-from-a-compound"> How does a solution differ from a compound? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/solutions"> See all questions in Solutions </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2892 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A vinegar solution has a #[OH^-] = 4.2*10^-10# #M# at 25°C. What is the #[H_3O^+]# of the vinegar solution?	null
1,702	a8f7ef95-6ddd-11ea-addb-ccda262736ce	https://socratic.org/questions/58a7834511ef6b02e732e08d	3	start physical_unit 2 2 number none qc_end chemical_equation 7 7 qc_end end	[{"type":"physical unit","value":"Number [OF] isomers"}]	[{"type":"physical unit","value":"3"}]	[{"type":"chemical equation","value":"C5H12"}]	<h1 class="questionTitle" itemprop="name">How many isomers can a formula of #C_5H_12# support?</h1>	null	3	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>There are <mathjax>#"n-pentane"#</mathjax>, <mathjax>#"isopentane"#</mathjax>, and <mathjax>#"neopentane"#</mathjax>, i.e. <mathjax>#"pentane"#</mathjax>, <mathjax>#"2-methylbutane"#</mathjax>, and <mathjax>#"2,2-dimethylpropane."#</mathjax></p> <p><img alt="omerchemblog.blogspot.com" src="https://useruploads.socratic.org/5MvNSamwTtGvUZjZGgVO_pentane_2.png"/> </p> <p>How would you predict the order of volatility with respect to the 3 isomers?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>For <mathjax>#"pentane"#</mathjax>, <mathjax>#C_5H_12#</mathjax>, I count 3 isomers.......</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>There are <mathjax>#"n-pentane"#</mathjax>, <mathjax>#"isopentane"#</mathjax>, and <mathjax>#"neopentane"#</mathjax>, i.e. <mathjax>#"pentane"#</mathjax>, <mathjax>#"2-methylbutane"#</mathjax>, and <mathjax>#"2,2-dimethylpropane."#</mathjax></p> <p><img alt="omerchemblog.blogspot.com" src="https://useruploads.socratic.org/5MvNSamwTtGvUZjZGgVO_pentane_2.png"/> </p> <p>How would you predict the order of volatility with respect to the 3 isomers?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many isomers can a formula of #C_5H_12# support?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#organic-chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Organic Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/organic-chemistry/isomerisms" itemprop="url"> <span class="breadcrumb" itemprop="title">Isomerisms</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="382486" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-02-24T21:31:42" itemprop="dateCreated"> Feb 24, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>For <mathjax>#"pentane"#</mathjax>, <mathjax>#C_5H_12#</mathjax>, I count 3 isomers.......</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>There are <mathjax>#"n-pentane"#</mathjax>, <mathjax>#"isopentane"#</mathjax>, and <mathjax>#"neopentane"#</mathjax>, i.e. <mathjax>#"pentane"#</mathjax>, <mathjax>#"2-methylbutane"#</mathjax>, and <mathjax>#"2,2-dimethylpropane."#</mathjax></p> <p><img alt="omerchemblog.blogspot.com" src="https://useruploads.socratic.org/5MvNSamwTtGvUZjZGgVO_pentane_2.png"/> </p> <p>How would you predict the order of volatility with respect to the 3 isomers?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/382486" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/53e3a5bd02bf340360ad6c0e"> Question #d6c0e </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a 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<a class="showMoreRelatedQuestions" href="/chemistry/organic-chemistry/isomerisms"> See all questions in Isomerisms </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2721 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many isomers can a formula of #C_5H_12# support?	null
1,703	aa8b3bb6-6ddd-11ea-928a-ccda262736ce	https://socratic.org/questions/dissolving-120g-of-urea-mol-wt-60-in-1000g-of-water-gave-a-solution-of-density-1	2.05 mol/L	start physical_unit 25 26 molarity mol/l qc_end physical_unit 4 4 1 2 mass qc_end physical_unit 4 4 6 7 molecular_weight qc_end physical_unit 12 12 9 10 mass qc_end physical_unit 25 26 18 19 density qc_end end	[{"type":"physical unit","value":"Molarity [OF] the solution [IN] mol/L"}]	[{"type":"physical unit","value":"2.05 mol/L"}]	[{"type":"physical unit","value":"Mass [OF] urea [=] \\pu{120 g}"},{"type":"physical unit","value":"mol.wt [OF] urea [=] \\pu{60 g/mol}"},{"type":"physical unit","value":"Mass [OF] water [=] \\pu{1000 g}"},{"type":"physical unit","value":"Density [OF] the solution [=] \\pu{1.15 g/mL}"}]	<h1 class="questionTitle" itemprop="name">Dissolving 120g of urea (mol.wt 60) in 1000g of water gave a solution of density 1.15 g/mL. What is the molarity of the solution?</h1>	null	2.05 mol/L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that a solution's <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></strong> tells you the number of moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> present in <mathjax>#"1 L"#</mathjax> of solution. </p> <p>So in order to calculate a solution's <strong>molarity</strong>, you essentially need to know the number of moles of solute present in exactly <mathjax>#"1 L" = 10^3#</mathjax> <mathjax>#"mL"#</mathjax> of solution.</p> <p>Start by using the <strong>molar mass</strong> of urea to calculate the number of moles present in your sample</p> <blockquote> <p><mathjax>#120 color(red)(cancel(color(black)("g"))) * "1 mole urea"/(60color(red)(cancel(color(black)("g")))) = "2 moles urea"#</mathjax></p> </blockquote> <p>Now, you know that your solution contains <mathjax>#"120 g"#</mathjax> of urea, the solute, and <mathjax>#"1000 g"#</mathjax> of water, the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a>. This implies that the <strong>total mass</strong> of the solution</p> <blockquote> <p><mathjax>#"mass solution = mass solute + mass solvent"#</mathjax></p> </blockquote> <p>will be equal to</p> <blockquote> <p><mathjax>#"mass solution" = "120 g + 1000 g" = "1120 g"#</mathjax></p> </blockquote> <p>You also know that this solution has a <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a></strong> of <mathjax>#"1.15 g mL"^(-1)#</mathjax>, which means that <strong>every</strong> <mathjax>#"1 mL"#</mathjax> <strong>of solution</strong> has a mass of <mathjax>#"1.15 g"#</mathjax>.</p> <p>Use the density of the solution to calculate its volume</p> <blockquote> <p><mathjax>#1120 color(red)(cancel(color(black)("g"))) * "1 mL"/(1.15color(red)(cancel(color(black)("g"))) ) = "973.9 mL"#</mathjax></p> </blockquote> <p>Now, your goal is to figure out the number of moles of solute present in <mathjax>#10^3#</mathjax> <mathjax>#"mL"#</mathjax> of solution, so use the known composition of the solution as a <em>conversion factor</em> to get</p> <blockquote> <p><mathjax>#10^3 color(red)(cancel(color(black)("mL solution"))) * "2 moles urea"/(973.9color(red)(cancel(color(black)("mL solution")))) = "2.0536 moles urea"#</mathjax></p> </blockquote> <p>You can thus say that the molarity of the solution is equal to</p> <blockquote> <p><mathjax>#color(darkgreen)(ul(color(black)("molarity = 2.1 mol L"^(-1))))#</mathjax></p> </blockquote> <p>I'll leave the answer rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"2.1 mol L"^(-1)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that a solution's <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></strong> tells you the number of moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> present in <mathjax>#"1 L"#</mathjax> of solution. </p> <p>So in order to calculate a solution's <strong>molarity</strong>, you essentially need to know the number of moles of solute present in exactly <mathjax>#"1 L" = 10^3#</mathjax> <mathjax>#"mL"#</mathjax> of solution.</p> <p>Start by using the <strong>molar mass</strong> of urea to calculate the number of moles present in your sample</p> <blockquote> <p><mathjax>#120 color(red)(cancel(color(black)("g"))) * "1 mole urea"/(60color(red)(cancel(color(black)("g")))) = "2 moles urea"#</mathjax></p> </blockquote> <p>Now, you know that your solution contains <mathjax>#"120 g"#</mathjax> of urea, the solute, and <mathjax>#"1000 g"#</mathjax> of water, the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a>. This implies that the <strong>total mass</strong> of the solution</p> <blockquote> <p><mathjax>#"mass solution = mass solute + mass solvent"#</mathjax></p> </blockquote> <p>will be equal to</p> <blockquote> <p><mathjax>#"mass solution" = "120 g + 1000 g" = "1120 g"#</mathjax></p> </blockquote> <p>You also know that this solution has a <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a></strong> of <mathjax>#"1.15 g mL"^(-1)#</mathjax>, which means that <strong>every</strong> <mathjax>#"1 mL"#</mathjax> <strong>of solution</strong> has a mass of <mathjax>#"1.15 g"#</mathjax>.</p> <p>Use the density of the solution to calculate its volume</p> <blockquote> <p><mathjax>#1120 color(red)(cancel(color(black)("g"))) * "1 mL"/(1.15color(red)(cancel(color(black)("g"))) ) = "973.9 mL"#</mathjax></p> </blockquote> <p>Now, your goal is to figure out the number of moles of solute present in <mathjax>#10^3#</mathjax> <mathjax>#"mL"#</mathjax> of solution, so use the known composition of the solution as a <em>conversion factor</em> to get</p> <blockquote> <p><mathjax>#10^3 color(red)(cancel(color(black)("mL solution"))) * "2 moles urea"/(973.9color(red)(cancel(color(black)("mL solution")))) = "2.0536 moles urea"#</mathjax></p> </blockquote> <p>You can thus say that the molarity of the solution is equal to</p> <blockquote> <p><mathjax>#color(darkgreen)(ul(color(black)("molarity = 2.1 mol L"^(-1))))#</mathjax></p> </blockquote> <p>I'll leave the answer rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Dissolving 120g of urea (mol.wt 60) in 1000g of water gave a solution of density 1.15 g/mL. What is the molarity of the solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="439390" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-14T00:02:10" itemprop="dateCreated"> Jun 14, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"2.1 mol L"^(-1)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that a solution's <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></strong> tells you the number of moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> present in <mathjax>#"1 L"#</mathjax> of solution. </p> <p>So in order to calculate a solution's <strong>molarity</strong>, you essentially need to know the number of moles of solute present in exactly <mathjax>#"1 L" = 10^3#</mathjax> <mathjax>#"mL"#</mathjax> of solution.</p> <p>Start by using the <strong>molar mass</strong> of urea to calculate the number of moles present in your sample</p> <blockquote> <p><mathjax>#120 color(red)(cancel(color(black)("g"))) * "1 mole urea"/(60color(red)(cancel(color(black)("g")))) = "2 moles urea"#</mathjax></p> </blockquote> <p>Now, you know that your solution contains <mathjax>#"120 g"#</mathjax> of urea, the solute, and <mathjax>#"1000 g"#</mathjax> of water, the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a>. This implies that the <strong>total mass</strong> of the solution</p> <blockquote> <p><mathjax>#"mass solution = mass solute + mass solvent"#</mathjax></p> </blockquote> <p>will be equal to</p> <blockquote> <p><mathjax>#"mass solution" = "120 g + 1000 g" = "1120 g"#</mathjax></p> </blockquote> <p>You also know that this solution has a <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a></strong> of <mathjax>#"1.15 g mL"^(-1)#</mathjax>, which means that <strong>every</strong> <mathjax>#"1 mL"#</mathjax> <strong>of solution</strong> has a mass of <mathjax>#"1.15 g"#</mathjax>.</p> <p>Use the density of the solution to calculate its volume</p> <blockquote> <p><mathjax>#1120 color(red)(cancel(color(black)("g"))) * "1 mL"/(1.15color(red)(cancel(color(black)("g"))) ) = "973.9 mL"#</mathjax></p> </blockquote> <p>Now, your goal is to figure out the number of moles of solute present in <mathjax>#10^3#</mathjax> <mathjax>#"mL"#</mathjax> of solution, so use the known composition of the solution as a <em>conversion factor</em> to get</p> <blockquote> <p><mathjax>#10^3 color(red)(cancel(color(black)("mL solution"))) * "2 moles urea"/(973.9color(red)(cancel(color(black)("mL solution")))) = "2.0536 moles urea"#</mathjax></p> </blockquote> <p>You can thus say that the molarity of the solution is equal to</p> <blockquote> <p><mathjax>#color(darkgreen)(ul(color(black)("molarity = 2.1 mol L"^(-1))))#</mathjax></p> </blockquote> <p>I'll leave the answer rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/439390" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-morality-be-used-as-a-conversion-factor"> How can molarity be used as a conversion factor? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-high-can-molarity-be"> How high can molarity be? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-molarity-change-with-temperature"> How does molarity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molarity-of-a-solution"> How do you find molarity of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-10-naoh"> What is the molarity of 10 NaOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-3-hydrogen-peroxide"> What is the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 41933 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Dissolving 120g of urea (mol.wt 60) in 1000g of water gave a solution of density 1.15 g/mL. What is the molarity of the solution?	null
1,704	ac0428ec-6ddd-11ea-a86f-ccda262736ce	https://socratic.org/questions/56d68a0f7c01490e790b97a0	CuSO4(aq) + BaCl2(aq) -> BaSO4(s) + CuCl2(aq)	start chemical_equation qc_end substance 7 8 qc_end substance 10 11 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the reaction"}]	[{"type":"chemical equation","value":"CuSO4(aq) + BaCl2(aq) -> BaSO4(s) + CuCl2(aq)"}]	[{"type":"substance name","value":"Copper sulfate"},{"type":"substance name","value":"Barium chloride"}]	<h1 class="questionTitle" itemprop="name">How do you represent the reaction of copper sulfate with barium chloride in aqueous solution?</h1>	null	CuSO4(aq) + BaCl2(aq) -> BaSO4(s) + CuCl2(aq)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Barium sulfate is reasonably insoluble in water, whereas both cupric sulfate and cupric chloride have some aqueous solubility. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#CuSO_4(aq) + BaCl_2(aq) rarr BaSO_4(s)darr + CuCl_2(aq)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Barium sulfate is reasonably insoluble in water, whereas both cupric sulfate and cupric chloride have some aqueous solubility. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you represent the reaction of copper sulfate with barium chloride in aqueous solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-reactions-and-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions and Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="233881" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-02T08:11:02" itemprop="dateCreated"> Mar 2, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#CuSO_4(aq) + BaCl_2(aq) rarr BaSO_4(s)darr + CuCl_2(aq)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Barium sulfate is reasonably insoluble in water, whereas both cupric sulfate and cupric chloride have some aqueous solubility. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/233881" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related 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1,705	a8ca630a-6ddd-11ea-9368-ccda262736ce	https://socratic.org/questions/how-do-you-find-the-h-of-the-following-reaction-sncl-2-s-cl-2-g-sncl-4-l	-194.8 kJ	start physical_unit 9 9 deltah none qc_end chemical_equation 10 14 qc_end chemical_equation 19 28 qc_end chemical_equation 29 38 qc_end chemical_equation 39 46 qc_end end	[{"type":"physical unit","value":"DeltaH [OF] the reaction"}]	[{"type":"physical unit","value":"-194.8 kJ"}]	[{"type":"chemical equation","value":"SnCl2(s) + Cl2(g) -> SnCl4(l)"},{"type":"chemical equation","value":"SnCl2(s) + TiBr2(s) -> SnBr2(s) + TiC2(s) deltaH = +4.2kJ"},{"type":"chemical equation","value":" TiBr2(s) + SnCl4(l) -> SnBr2(s) + TiCl4(l) deltaH = −74kJ"},{"type":"chemical equation","value":"TiCl4(l) -> TiCl2(s) + Cl2(g) deltaH = +273kJ"}]	<h1 class="questionTitle" itemprop="name">How do you find the #ΔH# of the following reaction: #SnCl_2(s) + Cl_2(g) → SnCl_4(l)#? </h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>Given the following data:<br/> <mathjax>#SnCl_2(s) + TiBr_2(s) → SnBr_2(s) + TiCl_2(s)#</mathjax> <br/> <mathjax>#ΔH = +4.2 kJ#</mathjax><br/> <mathjax>#TiBr_2(s) + SnCl_4(l) → SnBr_2(s) + TiCl_4(l)#</mathjax> <br/> <mathjax>#ΔH = -74 kJ#</mathjax><br/> <mathjax>#TiCl_4(l) → TiCl_2(s) + Cl_2(g)#</mathjax> <br/> <mathjax>#ΔH = +273 kJ#</mathjax></p></div> </h2> </div> </div>	-194.8 kJ	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Knowing that elemental molecules (made of only one element, like <mathjax>#O_2, Cl_2, Br_2#</mathjax>) etc have <mathjax>#0#</mathjax> <a href="https://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a>, and the equation for enthalpy </p> <p><mathjax>#DeltaH_("rxn")=Sigman"products"-Sigman"reactants"#</mathjax>,</p> <p>or overall enthalpy (<mathjax>#DeltaH_("rxn")#</mathjax>) is the enthalpy of products minus enthalpy of reactants, we can rearrange equation <mathjax>#3.#</mathjax>.</p> <p><mathjax>#TiCl_4->TiCl_2+Cl_2, DeltaH=+273kJ#</mathjax></p> <p><mathjax>#273=(TiCl_2+Cl_2)-TiCl_4#</mathjax> (products minus reactants)</p> <p><mathjax>#273=TiCl_2-TiCl_4#</mathjax> (enthalpy of <mathjax>#Cl_2#</mathjax> is <mathjax>#0#</mathjax>)</p> <p><mathjax>#TiCl_4=TiCl_2-273#</mathjax> (rearranged algebraically)</p> <p>Now you can substitute this into equation <mathjax>#2.#</mathjax>, again using the products minus reactants equation</p> <p><mathjax>#TiBr_2+SnCl_4->SnBr_2+TiCl_4, DeltaH=-74kJ#</mathjax></p> <p><mathjax>#-74=(SnBr_2+TiCl_4)-(TiBr_2+SnCl_4)#</mathjax></p> <p><mathjax>#-74=SnBr_2+TiCl_2-273-TiBr_2-SnCl_4#</mathjax> (substituting in equation <mathjax>#3.#</mathjax> and expanding out everything)</p> <p><mathjax>#199=SnBr_2+TiCl_2-TiBr_2-SnCl_4#</mathjax> (rearranging, adding <mathjax>#273#</mathjax> to both sides)</p> <p>You also have equation <mathjax>#1.#</mathjax>, which you can use products minus reactants to find</p> <p><mathjax>#SnCl_2+TiBr_2->SnBr_2+TiCl_2, DeltaH=+4.2kJ#</mathjax></p> <p><mathjax>#4.2=(SnBr_2+TiCl_2)-(SnCl_2+TiBr_2)#</mathjax> (products minus reactants)</p> <p><mathjax>#4.2=SnBr_2+TiCl_2-SnCl_2-TiBr_2#</mathjax> (expanding out brackets)</p> <p>Now you can equate equations <mathjax>#1.#</mathjax> and <mathjax>#2.#</mathjax> in their new form, as so</p> <p><mathjax>#SnBr_2+TiCl_2-SnCl_2-TiBr_2+194.8=SnBr_2+TiCl_2-TiBr_2-SnCl_4#</mathjax></p> <p>because if you add <mathjax>#194.8#</mathjax> to equation <mathjax>#1#</mathjax> it equals <mathjax>#199#</mathjax> in total, the same as equation <mathjax>#2.#</mathjax> With these two equal to each other, you can cancel out the similarities on both sides and find what's left. </p> <p>Both sides have a <mathjax>#SnBr_2#</mathjax>, so you can cancel that. They also have a <mathjax>#TiCl_2#</mathjax> and a <mathjax>#-TiBr_2#</mathjax>, so get rid of those from each side, leaving</p> <p><mathjax>#-SnCl_2+194.8=-SnCl_4#</mathjax></p> <p><mathjax>#SnCl_4-SnCl_2=-194.8kJ#</mathjax></p> <p>This is the answer to the question in the form of products minus reactants, because you can see the product is <mathjax>#SnCl_4#</mathjax> and the reactants are <mathjax>#SnCl_2#</mathjax> and <mathjax>#Cl_2#</mathjax>, though <mathjax>#Cl_2#</mathjax> has an enthalpy of <mathjax>#0#</mathjax> so it can be ignored. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#DeltaH=-194.8kJ#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Knowing that elemental molecules (made of only one element, like <mathjax>#O_2, Cl_2, Br_2#</mathjax>) etc have <mathjax>#0#</mathjax> <a href="https://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a>, and the equation for enthalpy </p> <p><mathjax>#DeltaH_("rxn")=Sigman"products"-Sigman"reactants"#</mathjax>,</p> <p>or overall enthalpy (<mathjax>#DeltaH_("rxn")#</mathjax>) is the enthalpy of products minus enthalpy of reactants, we can rearrange equation <mathjax>#3.#</mathjax>.</p> <p><mathjax>#TiCl_4->TiCl_2+Cl_2, DeltaH=+273kJ#</mathjax></p> <p><mathjax>#273=(TiCl_2+Cl_2)-TiCl_4#</mathjax> (products minus reactants)</p> <p><mathjax>#273=TiCl_2-TiCl_4#</mathjax> (enthalpy of <mathjax>#Cl_2#</mathjax> is <mathjax>#0#</mathjax>)</p> <p><mathjax>#TiCl_4=TiCl_2-273#</mathjax> (rearranged algebraically)</p> <p>Now you can substitute this into equation <mathjax>#2.#</mathjax>, again using the products minus reactants equation</p> <p><mathjax>#TiBr_2+SnCl_4->SnBr_2+TiCl_4, DeltaH=-74kJ#</mathjax></p> <p><mathjax>#-74=(SnBr_2+TiCl_4)-(TiBr_2+SnCl_4)#</mathjax></p> <p><mathjax>#-74=SnBr_2+TiCl_2-273-TiBr_2-SnCl_4#</mathjax> (substituting in equation <mathjax>#3.#</mathjax> and expanding out everything)</p> <p><mathjax>#199=SnBr_2+TiCl_2-TiBr_2-SnCl_4#</mathjax> (rearranging, adding <mathjax>#273#</mathjax> to both sides)</p> <p>You also have equation <mathjax>#1.#</mathjax>, which you can use products minus reactants to find</p> <p><mathjax>#SnCl_2+TiBr_2->SnBr_2+TiCl_2, DeltaH=+4.2kJ#</mathjax></p> <p><mathjax>#4.2=(SnBr_2+TiCl_2)-(SnCl_2+TiBr_2)#</mathjax> (products minus reactants)</p> <p><mathjax>#4.2=SnBr_2+TiCl_2-SnCl_2-TiBr_2#</mathjax> (expanding out brackets)</p> <p>Now you can equate equations <mathjax>#1.#</mathjax> and <mathjax>#2.#</mathjax> in their new form, as so</p> <p><mathjax>#SnBr_2+TiCl_2-SnCl_2-TiBr_2+194.8=SnBr_2+TiCl_2-TiBr_2-SnCl_4#</mathjax></p> <p>because if you add <mathjax>#194.8#</mathjax> to equation <mathjax>#1#</mathjax> it equals <mathjax>#199#</mathjax> in total, the same as equation <mathjax>#2.#</mathjax> With these two equal to each other, you can cancel out the similarities on both sides and find what's left. </p> <p>Both sides have a <mathjax>#SnBr_2#</mathjax>, so you can cancel that. They also have a <mathjax>#TiCl_2#</mathjax> and a <mathjax>#-TiBr_2#</mathjax>, so get rid of those from each side, leaving</p> <p><mathjax>#-SnCl_2+194.8=-SnCl_4#</mathjax></p> <p><mathjax>#SnCl_4-SnCl_2=-194.8kJ#</mathjax></p> <p>This is the answer to the question in the form of products minus reactants, because you can see the product is <mathjax>#SnCl_4#</mathjax> and the reactants are <mathjax>#SnCl_2#</mathjax> and <mathjax>#Cl_2#</mathjax>, though <mathjax>#Cl_2#</mathjax> has an enthalpy of <mathjax>#0#</mathjax> so it can be ignored. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you find the #ΔH# of the following reaction: #SnCl_2(s) + Cl_2(g) → SnCl_4(l)#? </h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>Given the following data:<br/> <mathjax>#SnCl_2(s) + TiBr_2(s) → SnBr_2(s) + TiCl_2(s)#</mathjax> <br/> <mathjax>#ΔH = +4.2 kJ#</mathjax><br/> <mathjax>#TiBr_2(s) + SnCl_4(l) → SnBr_2(s) + TiCl_4(l)#</mathjax> <br/> <mathjax>#ΔH = -74 kJ#</mathjax><br/> <mathjax>#TiCl_4(l) → TiCl_2(s) + Cl_2(g)#</mathjax> <br/> <mathjax>#ΔH = +273 kJ#</mathjax></p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/hess-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Hess' Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="257753" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/reudhreghs"><img alt="" class="" src="https://profilepictures.socratic.org/cbvHaqiiRa2eTNL3y20D_Just%20monkeying%20around%20%F0%9F%90%92%F0%9F%98%8D%F0%9F%8C%9E.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/reudhreghs"> reudhreghs </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-04-23T10:56:57" itemprop="dateCreated"> Apr 23, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#DeltaH=-194.8kJ#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Knowing that elemental molecules (made of only one element, like <mathjax>#O_2, Cl_2, Br_2#</mathjax>) etc have <mathjax>#0#</mathjax> <a href="https://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a>, and the equation for enthalpy </p> <p><mathjax>#DeltaH_("rxn")=Sigman"products"-Sigman"reactants"#</mathjax>,</p> <p>or overall enthalpy (<mathjax>#DeltaH_("rxn")#</mathjax>) is the enthalpy of products minus enthalpy of reactants, we can rearrange equation <mathjax>#3.#</mathjax>.</p> <p><mathjax>#TiCl_4->TiCl_2+Cl_2, DeltaH=+273kJ#</mathjax></p> <p><mathjax>#273=(TiCl_2+Cl_2)-TiCl_4#</mathjax> (products minus reactants)</p> <p><mathjax>#273=TiCl_2-TiCl_4#</mathjax> (enthalpy of <mathjax>#Cl_2#</mathjax> is <mathjax>#0#</mathjax>)</p> <p><mathjax>#TiCl_4=TiCl_2-273#</mathjax> (rearranged algebraically)</p> <p>Now you can substitute this into equation <mathjax>#2.#</mathjax>, again using the products minus reactants equation</p> <p><mathjax>#TiBr_2+SnCl_4->SnBr_2+TiCl_4, DeltaH=-74kJ#</mathjax></p> <p><mathjax>#-74=(SnBr_2+TiCl_4)-(TiBr_2+SnCl_4)#</mathjax></p> <p><mathjax>#-74=SnBr_2+TiCl_2-273-TiBr_2-SnCl_4#</mathjax> (substituting in equation <mathjax>#3.#</mathjax> and expanding out everything)</p> <p><mathjax>#199=SnBr_2+TiCl_2-TiBr_2-SnCl_4#</mathjax> (rearranging, adding <mathjax>#273#</mathjax> to both sides)</p> <p>You also have equation <mathjax>#1.#</mathjax>, which you can use products minus reactants to find</p> <p><mathjax>#SnCl_2+TiBr_2->SnBr_2+TiCl_2, DeltaH=+4.2kJ#</mathjax></p> <p><mathjax>#4.2=(SnBr_2+TiCl_2)-(SnCl_2+TiBr_2)#</mathjax> (products minus reactants)</p> <p><mathjax>#4.2=SnBr_2+TiCl_2-SnCl_2-TiBr_2#</mathjax> (expanding out brackets)</p> <p>Now you can equate equations <mathjax>#1.#</mathjax> and <mathjax>#2.#</mathjax> in their new form, as so</p> <p><mathjax>#SnBr_2+TiCl_2-SnCl_2-TiBr_2+194.8=SnBr_2+TiCl_2-TiBr_2-SnCl_4#</mathjax></p> <p>because if you add <mathjax>#194.8#</mathjax> to equation <mathjax>#1#</mathjax> it equals <mathjax>#199#</mathjax> in total, the same as equation <mathjax>#2.#</mathjax> With these two equal to each other, you can cancel out the similarities on both sides and find what's left. </p> <p>Both sides have a <mathjax>#SnBr_2#</mathjax>, so you can cancel that. They also have a <mathjax>#TiCl_2#</mathjax> and a <mathjax>#-TiBr_2#</mathjax>, so get rid of those from each side, leaving</p> <p><mathjax>#-SnCl_2+194.8=-SnCl_4#</mathjax></p> <p><mathjax>#SnCl_4-SnCl_2=-194.8kJ#</mathjax></p> <p>This is the answer to the question in the form of products minus reactants, because you can see the product is <mathjax>#SnCl_4#</mathjax> and the reactants are <mathjax>#SnCl_2#</mathjax> and <mathjax>#Cl_2#</mathjax>, though <mathjax>#Cl_2#</mathjax> has an enthalpy of <mathjax>#0#</mathjax> so it can be ignored. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/257753" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-hesss-law-applied-in-calculating-enthalpy"> How is Hess's law applied in calculating enthalpy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-compute-hesss-law-calculations"> How do you compute Hess's law calculations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-draw-a-hesss-law-diagram"> How do you draw a Hess's law diagram? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-hesss-law-say-about-the-enthalpy-of-a-reaction"> What does Hess's law say about the enthalpy of a reaction? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-isn-t-hess-s-law-helpful-to-calculate-the-heat-of-reaction-involved-in-conve"> Why isn't Hess's law helpful to calculate the heat of reaction involved in converting a diamond... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-hess-law-useful-to-calculate-enthalpies"> Why is Hess' law useful to calculate enthalpies? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-importance-of-hess-s-law-to-do-thermodynamic-calculations"> What is the importance of Hess's law to do thermodynamic calculations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-equation-for-hess-s-law"> What is the equation for Hess's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-hess-s-law-of-heat-summation"> What is Hess's law of heat summation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-enthalpy-of-mixing-zero"> Why is enthalpy of mixing zero? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/hess-law"> See all questions in Hess' Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1565 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How do you find the #ΔH# of the following reaction: #SnCl_2(s) + Cl_2(g) → SnCl_4(l)#?	Given the following data: #SnCl_2(s) + TiBr_2(s) → SnBr_2(s) + TiCl_2(s)# #ΔH = +4.2 kJ# #TiBr_2(s) + SnCl_4(l) → SnBr_2(s) + TiCl_4(l)# #ΔH = -74 kJ# #TiCl_4(l) → TiCl_2(s) + Cl_2(g)# #ΔH = +273 kJ#
1,706	acaddbf6-6ddd-11ea-a4a9-ccda262736ce	https://socratic.org/questions/a-scuba-diver-is-at-a-depth-of-355-m-where-the-pressure-is-36-5-atm-what-should-	5.73 × 10^(-3)	start physical_unit 23 27 mole_fraction none qc_end physical_unit 1 2 8 9 depth qc_end physical_unit 1 2 14 15 pressure qc_end c_other OTHER qc_end physical_unit 56 59 61 61 mole_fraction qc_end end	[{"type":"physical unit","value":"Mole fraction [OF] O2 in the gas mixture"}]	[{"type":"physical unit","value":"5.73 × 10^(-3)"}]	[{"type":"physical unit","value":"Depth [OF] the scuba diver [=] \\pu{355 m}"},{"type":"physical unit","value":"Pressure [OF] the scuba diver [=] \\pu{36.5 atm}"},{"type":"other","value":"In order to have the same partial pressure of oxygen in his lungs as he would at sea level."},{"type":"physical unit","value":"Mole fraction [OF] oxygen at sea level [=] \\pu{0.209}"}]	<h1 class="questionTitle" itemprop="name">A scuba diver is at a depth of 355 m, where the pressure is 36.5 atm. What should be the mole fraction of #O_2# in the gas mixture the diver breathes in order to have the same partial pressure of oxygen in his lungs as he would at sea level? </h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>Note that the mole fraction of oxygen at sea level is 0.209.</p></div> </h2> </div> </div>	5.73 × 10^(-3)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that the <a href="https://socratic.org/chemistry/the-behavior-of-gases/partial-pressure">partial pressure</a> of a gas that's part of a gaseous mixture depends on the <strong>mole fraction</strong> of said gas and on the <strong>total pressure</strong> of the mixture, as given by <strong>Dalton's Law of Partial Pressures</strong>.</p> <p>In your case, you know that at a depth of <mathjax>#"355 m"#</mathjax>, the total pressure is equal to <mathjax>#"36.5 atm"#</mathjax>. </p> <p>This means that you can write</p> <blockquote> <p><mathjax>#P_ ("O"_ 2\|"355 m") = chi_ ("O"_ 2\|"355 m") * P_ ("total"\|"355 m"#</mathjax></p> </blockquote> <p>You also know that at <em>sea level</em>, the <strong>total pressure</strong> of the atmosphere is equal to <mathjax>#"1 atm"#</mathjax> and <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> fraction of oxygen gas is <mathjax>#0.209#</mathjax>.</p> <p>This means that at sea level, you have</p> <blockquote> <p><mathjax>#P_ ("O"_ 2\|"sea level") = 0.209 * "1 atm"#</mathjax></p> </blockquote> <p>Since the partial pressure of oxygen gas at <mathjax>#"355 m"#</mathjax> must be <strong>equal</strong> to the partial pressure of oxygen gas at sea level, you can say that you have</p> <blockquote> <p><mathjax>#0.209 * 1 color(red)(cancel(color(black)("atm"))) = chi_ ("O"_ 2\|"355 m") * 36.5 color(red)(cancel(color(black)("atm")))#</mathjax></p> </blockquote> <p>which gets you</p> <blockquote> <p><mathjax>#chi_ ("O"_ 2\|"355 m") = 0.209/36.5 = color(darkgreen)(ul(color(black)(0.00573)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#0.00573#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that the <a href="https://socratic.org/chemistry/the-behavior-of-gases/partial-pressure">partial pressure</a> of a gas that's part of a gaseous mixture depends on the <strong>mole fraction</strong> of said gas and on the <strong>total pressure</strong> of the mixture, as given by <strong>Dalton's Law of Partial Pressures</strong>.</p> <p>In your case, you know that at a depth of <mathjax>#"355 m"#</mathjax>, the total pressure is equal to <mathjax>#"36.5 atm"#</mathjax>. </p> <p>This means that you can write</p> <blockquote> <p><mathjax>#P_ ("O"_ 2\|"355 m") = chi_ ("O"_ 2\|"355 m") * P_ ("total"\|"355 m"#</mathjax></p> </blockquote> <p>You also know that at <em>sea level</em>, the <strong>total pressure</strong> of the atmosphere is equal to <mathjax>#"1 atm"#</mathjax> and <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> fraction of oxygen gas is <mathjax>#0.209#</mathjax>.</p> <p>This means that at sea level, you have</p> <blockquote> <p><mathjax>#P_ ("O"_ 2\|"sea level") = 0.209 * "1 atm"#</mathjax></p> </blockquote> <p>Since the partial pressure of oxygen gas at <mathjax>#"355 m"#</mathjax> must be <strong>equal</strong> to the partial pressure of oxygen gas at sea level, you can say that you have</p> <blockquote> <p><mathjax>#0.209 * 1 color(red)(cancel(color(black)("atm"))) = chi_ ("O"_ 2\|"355 m") * 36.5 color(red)(cancel(color(black)("atm")))#</mathjax></p> </blockquote> <p>which gets you</p> <blockquote> <p><mathjax>#chi_ ("O"_ 2\|"355 m") = 0.209/36.5 = color(darkgreen)(ul(color(black)(0.00573)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A scuba diver is at a depth of 355 m, where the pressure is 36.5 atm. What should be the mole fraction of #O_2# in the gas mixture the diver breathes in order to have the same partial pressure of oxygen in his lungs as he would at sea level? </h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>Note that the mole fraction of oxygen at sea level is 0.209.</p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/partial-pressure" itemprop="url"> <span class="breadcrumb" itemprop="title">Partial Pressure</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="459129" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-02T00:50:07" itemprop="dateCreated"> Aug 2, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#0.00573#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that the <a href="https://socratic.org/chemistry/the-behavior-of-gases/partial-pressure">partial pressure</a> of a gas that's part of a gaseous mixture depends on the <strong>mole fraction</strong> of said gas and on the <strong>total pressure</strong> of the mixture, as given by <strong>Dalton's Law of Partial Pressures</strong>.</p> <p>In your case, you know that at a depth of <mathjax>#"355 m"#</mathjax>, the total pressure is equal to <mathjax>#"36.5 atm"#</mathjax>. </p> <p>This means that you can write</p> <blockquote> <p><mathjax>#P_ ("O"_ 2\|"355 m") = chi_ ("O"_ 2\|"355 m") * P_ ("total"\|"355 m"#</mathjax></p> </blockquote> <p>You also know that at <em>sea level</em>, the <strong>total pressure</strong> of the atmosphere is equal to <mathjax>#"1 atm"#</mathjax> and <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> fraction of oxygen gas is <mathjax>#0.209#</mathjax>.</p> <p>This means that at sea level, you have</p> <blockquote> <p><mathjax>#P_ ("O"_ 2\|"sea level") = 0.209 * "1 atm"#</mathjax></p> </blockquote> <p>Since the partial pressure of oxygen gas at <mathjax>#"355 m"#</mathjax> must be <strong>equal</strong> to the partial pressure of oxygen gas at sea level, you can say that you have</p> <blockquote> <p><mathjax>#0.209 * 1 color(red)(cancel(color(black)("atm"))) = chi_ ("O"_ 2\|"355 m") * 36.5 color(red)(cancel(color(black)("atm")))#</mathjax></p> </blockquote> <p>which gets you</p> <blockquote> <p><mathjax>#chi_ ("O"_ 2\|"355 m") = 0.209/36.5 = color(darkgreen)(ul(color(black)(0.00573)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/459129" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/534e256802bf342adfa30010"> How do you do a steam distillation? 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What should be the mole fraction of #O_2# in the gas mixture the diver breathes in order to have the same partial pressure of oxygen in his lungs as he would at sea level?	Note that the mole fraction of oxygen at sea level is 0.209.
1,707	a8b6e115-6ddd-11ea-a565-ccda262736ce	https://socratic.org/questions/in-the-polyatomic-ion-cro4-2-what-is-the-charge-on-the-chromium-atom	+6	start physical_unit 11 12 charge none qc_end chemical_equation 4 4 qc_end end	[{"type":"physical unit","value":"Charge [OF] chromium atom"}]	[{"type":"physical unit","value":"+6"}]	[{"type":"chemical equation","value":"CrO4^2-"}]	<h1 class="questionTitle" itemprop="name">In the polyatomic ion, CrO4 -2, what is the charge on the chromium atom? </h1>	null	+6	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>As far as anyone knows, the charge in chromate is localized on the oxygen (i.e <mathjax>#(O=)_2Cr(-O^-)_2#</mathjax>). Chromic acid, <mathjax>#H_2CrO_4#</mathjax> (or <mathjax>#(O=)_2Cr(-OH)_2#</mathjax>), is the precursor; this is a potent oxidant. In each case, the metal oxidation state (<mathjax>#VI^+#</mathjax>) is clear. Note that in this formal representation, the charge on chromium is neutral. The negative charge is borne by the 2 singly bound oxygen atoms.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The oxidation state of <mathjax>#Cr#</mathjax> in chromate ion, <mathjax>#CrO_4^(2-)#</mathjax>, is <mathjax>#VI^+#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>As far as anyone knows, the charge in chromate is localized on the oxygen (i.e <mathjax>#(O=)_2Cr(-O^-)_2#</mathjax>). Chromic acid, <mathjax>#H_2CrO_4#</mathjax> (or <mathjax>#(O=)_2Cr(-OH)_2#</mathjax>), is the precursor; this is a potent oxidant. In each case, the metal oxidation state (<mathjax>#VI^+#</mathjax>) is clear. Note that in this formal representation, the charge on chromium is neutral. The negative charge is borne by the 2 singly bound oxygen atoms.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">In the polyatomic ion, CrO4 -2, what is the charge on the chromium atom? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#ionic-bonds-and-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Ionic Bonds</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/ionic-bonds-and-formulas/polyatomic-ions" itemprop="url"> <span class="breadcrumb" itemprop="title">Polyatomic Ions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="187519" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-12T16:57:19" itemprop="dateCreated"> Nov 12, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The oxidation state of <mathjax>#Cr#</mathjax> in chromate ion, <mathjax>#CrO_4^(2-)#</mathjax>, is <mathjax>#VI^+#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>As far as anyone knows, the charge in chromate is localized on the oxygen (i.e <mathjax>#(O=)_2Cr(-O^-)_2#</mathjax>). Chromic acid, <mathjax>#H_2CrO_4#</mathjax> (or <mathjax>#(O=)_2Cr(-OH)_2#</mathjax>), is the precursor; this is a potent oxidant. In each case, the metal oxidation state (<mathjax>#VI^+#</mathjax>) is clear. Note that in this formal representation, the charge on chromium is neutral. The negative charge is borne by the 2 singly bound oxygen atoms.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/187519" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-draw-the-lewis-structure-for-polyatomic-ions"> How do you draw the lewis structure for polyatomic ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/the-number-of-protons-are-not-suppose-to-be-equal-to-the-number-of-electrons-how"> The number of protons are not suppose to be equal to the number of electrons? 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1,708	abc9bf4a-6ddd-11ea-a5bd-ccda262736ce	https://socratic.org/questions/56f966d311ef6b2bb7d2837c	1.43 × 10^(-11) grams per liter	start physical_unit 5 6 solubility g/l qc_end physical_unit 12 12 14 15 temperature qc_end end	[{"type":"physical unit","value":"Solubility [OF] lanthanum trichloride [IN] grams per liter"}]	[{"type":"physical unit","value":"1.43 × 10^(-11) grams per liter"}]	[{"type":"physical unit","value":"Temperature [OF] the solution [=] \\pu{25 ℃}"}]	<h1 class="questionTitle" itemprop="name">What is the solubility of lanthanum trichloride in grams per liter of solution at #25^@"C"# ?</h1>	null	1.43 × 10^(-11) grams per liter	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to be able to solve this problem, you need to know the value of lanthanum trifluoride's <em>solubility product constant</em>, <mathjax>#K_(sp)#</mathjax>. You'll find this listed as </p> <blockquote> <p><mathjax>#K_(sp) = 2.0 * 10^(-19)#</mathjax></p> </blockquote> <p>So, lanthanum trifluoride is <em>insoluble8</em> in aqueous solution, which means that when you place it water, an equilibrium is established between the dissolved ions and the undissolved solid </p> <blockquote> <p><mathjax>#"LaF"_text(3(s]) rightleftharpoons "La"_text((aq])^(3+) + color(red)(3)"F"_text((aq])^(-)#</mathjax></p> </blockquote> <p>Now, the thing to keep in mind here is that you're interested in finding the solubility of lanthanum trifluoride in a solution that contains <em>aqueous potassium fluoride</em>, <mathjax>#"KF"#</mathjax>. </p> <p>Potassium fluoride is a <strong>soluble</strong> ionic compound that dissociates completely in aqueous solution to form potassium cations and fluoride anions</p> <blockquote> <p><mathjax>#"KF"_text((aq]) -> "K"_text((aq])^(+) + "F"_text((aq])^(-)#</mathjax></p> </blockquote> <p>The presence of these fluoride anions will <strong>affect</strong> the dissociation equilibrium of lanthanum trifluoride, i.e. <strong>less solid</strong> will dissolve because of the additional fluoride anions present in solution - this is known as the <strong>common ion effect</strong>. </p> <p>Potassium fluoride dissociates in a <mathjax>#1:1#</mathjax> mole ratio with the fluoride anions,which means that you can take the initial concentration of fluoride anions to be </p> <blockquote> <p><mathjax>#["F"^(-)]_0 = 1.4 10^(-2)"M"#</mathjax></p> </blockquote> <p>Set up an <strong>ICE table</strong> to help you find the <em>molar solubility</em> of the compound</p> <blockquote> <p><mathjax>#" ""LaF"_text(3(s]) " "rightleftharpoons" " "La"_text((aq])^(3+) " "+" " color(red)(3)"F"_text((aq])^(-)#</mathjax></p> </blockquote> <p><mathjax>#color(purple)("I")" " " "-" " " " " " " " " " " " "0" " " " " " "1.4 * 10^(-2)#</mathjax><br/> <mathjax>#color(purple)("C")" " " "-" " " " " " " " " "(+x)" " " " "(+color(red)(3)x)#</mathjax><br/> <mathjax>#color(purple)("E")" " " "-" " " " " " " " " " " "x" " " " "1.4 * 10^(-2) + color(red)(3)x#</mathjax></p> <p>By definition, the solubility product constant will be equal to </p> <blockquote> <p><mathjax>#K_(sp) = ["La"^(3+)] * ["F"^(-)]^color(red)(3)#</mathjax></p> </blockquote> <p>In your case, you will have </p> <blockquote> <p><mathjax>#K_(sp) = x * (1.4 * 10^(-2) + color(red)(3)x)^color(red)(3)#</mathjax></p> </blockquote> <p>Now, because <mathjax>#K_(sp)#</mathjax> is so small, you can use the approximation </p> <blockquote> <p><mathjax>#1.4 * 10^(-2) + color(red)(3)x ~~ 1.4 * 10^(-2)#</mathjax></p> </blockquote> <p>This will get you </p> <blockquote> <p><mathjax>#2 * 10^(-19) = x * (1.4 * 10^(-2))^color(red)(3)#</mathjax></p> <p><mathjax>#x = (2 * 10^(-19))/(2.744 * 10^(-6)) = 7.29 * 10^(-14)#</mathjax></p> </blockquote> <p>The <strong>molar solubility</strong> of lanthanum fluoride in a solution that contains <mathjax>#1.4 * 10^(-2)"M"#</mathjax> potassium fluoride will be equal to <mathjax>#7.3 * 10^(-14)"M"#</mathjax>. </p> <p>To get the solubility in <em>grams per liter</em>, use lanthanum trifluoride's <strong>molar mass</strong></p> <blockquote> <p><mathjax>#7.3 * 10^(-13)color(red)(cancel(color(black)("mol")))"L"^(-1) * "195.9 g"/(1color(red)(cancel(color(black)("mole")))) = color(green)(\|bar(ul(color(white)(a/a)1.4 * 10^(-11)"g L"^(-1)color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer is rounded to two <strong><a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1.4 * 10^(-11)"g L"^(-1)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to be able to solve this problem, you need to know the value of lanthanum trifluoride's <em>solubility product constant</em>, <mathjax>#K_(sp)#</mathjax>. You'll find this listed as </p> <blockquote> <p><mathjax>#K_(sp) = 2.0 * 10^(-19)#</mathjax></p> </blockquote> <p>So, lanthanum trifluoride is <em>insoluble8</em> in aqueous solution, which means that when you place it water, an equilibrium is established between the dissolved ions and the undissolved solid </p> <blockquote> <p><mathjax>#"LaF"_text(3(s]) rightleftharpoons "La"_text((aq])^(3+) + color(red)(3)"F"_text((aq])^(-)#</mathjax></p> </blockquote> <p>Now, the thing to keep in mind here is that you're interested in finding the solubility of lanthanum trifluoride in a solution that contains <em>aqueous potassium fluoride</em>, <mathjax>#"KF"#</mathjax>. </p> <p>Potassium fluoride is a <strong>soluble</strong> ionic compound that dissociates completely in aqueous solution to form potassium cations and fluoride anions</p> <blockquote> <p><mathjax>#"KF"_text((aq]) -> "K"_text((aq])^(+) + "F"_text((aq])^(-)#</mathjax></p> </blockquote> <p>The presence of these fluoride anions will <strong>affect</strong> the dissociation equilibrium of lanthanum trifluoride, i.e. <strong>less solid</strong> will dissolve because of the additional fluoride anions present in solution - this is known as the <strong>common ion effect</strong>. </p> <p>Potassium fluoride dissociates in a <mathjax>#1:1#</mathjax> mole ratio with the fluoride anions,which means that you can take the initial concentration of fluoride anions to be </p> <blockquote> <p><mathjax>#["F"^(-)]_0 = 1.4 10^(-2)"M"#</mathjax></p> </blockquote> <p>Set up an <strong>ICE table</strong> to help you find the <em>molar solubility</em> of the compound</p> <blockquote> <p><mathjax>#" ""LaF"_text(3(s]) " "rightleftharpoons" " "La"_text((aq])^(3+) " "+" " color(red)(3)"F"_text((aq])^(-)#</mathjax></p> </blockquote> <p><mathjax>#color(purple)("I")" " " "-" " " " " " " " " " " " "0" " " " " " "1.4 * 10^(-2)#</mathjax><br/> <mathjax>#color(purple)("C")" " " "-" " " " " " " " " "(+x)" " " " "(+color(red)(3)x)#</mathjax><br/> <mathjax>#color(purple)("E")" " " "-" " " " " " " " " " " "x" " " " "1.4 * 10^(-2) + color(red)(3)x#</mathjax></p> <p>By definition, the solubility product constant will be equal to </p> <blockquote> <p><mathjax>#K_(sp) = ["La"^(3+)] * ["F"^(-)]^color(red)(3)#</mathjax></p> </blockquote> <p>In your case, you will have </p> <blockquote> <p><mathjax>#K_(sp) = x * (1.4 * 10^(-2) + color(red)(3)x)^color(red)(3)#</mathjax></p> </blockquote> <p>Now, because <mathjax>#K_(sp)#</mathjax> is so small, you can use the approximation </p> <blockquote> <p><mathjax>#1.4 * 10^(-2) + color(red)(3)x ~~ 1.4 * 10^(-2)#</mathjax></p> </blockquote> <p>This will get you </p> <blockquote> <p><mathjax>#2 * 10^(-19) = x * (1.4 * 10^(-2))^color(red)(3)#</mathjax></p> <p><mathjax>#x = (2 * 10^(-19))/(2.744 * 10^(-6)) = 7.29 * 10^(-14)#</mathjax></p> </blockquote> <p>The <strong>molar solubility</strong> of lanthanum fluoride in a solution that contains <mathjax>#1.4 * 10^(-2)"M"#</mathjax> potassium fluoride will be equal to <mathjax>#7.3 * 10^(-14)"M"#</mathjax>. </p> <p>To get the solubility in <em>grams per liter</em>, use lanthanum trifluoride's <strong>molar mass</strong></p> <blockquote> <p><mathjax>#7.3 * 10^(-13)color(red)(cancel(color(black)("mol")))"L"^(-1) * "195.9 g"/(1color(red)(cancel(color(black)("mole")))) = color(green)(\|bar(ul(color(white)(a/a)1.4 * 10^(-11)"g L"^(-1)color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer is rounded to two <strong><a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the solubility of lanthanum trichloride in grams per liter of solution at #25^@"C"# ?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-equilibrium" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Equilibrium</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-equilibrium/solubility-equilbria" itemprop="url"> <span class="breadcrumb" itemprop="title">Solubility Equilbria</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="246516" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-28T23:46:32" itemprop="dateCreated"> Mar 28, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1.4 * 10^(-11)"g L"^(-1)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to be able to solve this problem, you need to know the value of lanthanum trifluoride's <em>solubility product constant</em>, <mathjax>#K_(sp)#</mathjax>. You'll find this listed as </p> <blockquote> <p><mathjax>#K_(sp) = 2.0 * 10^(-19)#</mathjax></p> </blockquote> <p>So, lanthanum trifluoride is <em>insoluble8</em> in aqueous solution, which means that when you place it water, an equilibrium is established between the dissolved ions and the undissolved solid </p> <blockquote> <p><mathjax>#"LaF"_text(3(s]) rightleftharpoons "La"_text((aq])^(3+) + color(red)(3)"F"_text((aq])^(-)#</mathjax></p> </blockquote> <p>Now, the thing to keep in mind here is that you're interested in finding the solubility of lanthanum trifluoride in a solution that contains <em>aqueous potassium fluoride</em>, <mathjax>#"KF"#</mathjax>. </p> <p>Potassium fluoride is a <strong>soluble</strong> ionic compound that dissociates completely in aqueous solution to form potassium cations and fluoride anions</p> <blockquote> <p><mathjax>#"KF"_text((aq]) -> "K"_text((aq])^(+) + "F"_text((aq])^(-)#</mathjax></p> </blockquote> <p>The presence of these fluoride anions will <strong>affect</strong> the dissociation equilibrium of lanthanum trifluoride, i.e. <strong>less solid</strong> will dissolve because of the additional fluoride anions present in solution - this is known as the <strong>common ion effect</strong>. </p> <p>Potassium fluoride dissociates in a <mathjax>#1:1#</mathjax> mole ratio with the fluoride anions,which means that you can take the initial concentration of fluoride anions to be </p> <blockquote> <p><mathjax>#["F"^(-)]_0 = 1.4 10^(-2)"M"#</mathjax></p> </blockquote> <p>Set up an <strong>ICE table</strong> to help you find the <em>molar solubility</em> of the compound</p> <blockquote> <p><mathjax>#" ""LaF"_text(3(s]) " "rightleftharpoons" " "La"_text((aq])^(3+) " "+" " color(red)(3)"F"_text((aq])^(-)#</mathjax></p> </blockquote> <p><mathjax>#color(purple)("I")" " " "-" " " " " " " " " " " " "0" " " " " " "1.4 * 10^(-2)#</mathjax><br/> <mathjax>#color(purple)("C")" " " "-" " " " " " " " " "(+x)" " " " "(+color(red)(3)x)#</mathjax><br/> <mathjax>#color(purple)("E")" " " "-" " " " " " " " " " " "x" " " " "1.4 * 10^(-2) + color(red)(3)x#</mathjax></p> <p>By definition, the solubility product constant will be equal to </p> <blockquote> <p><mathjax>#K_(sp) = ["La"^(3+)] * ["F"^(-)]^color(red)(3)#</mathjax></p> </blockquote> <p>In your case, you will have </p> <blockquote> <p><mathjax>#K_(sp) = x * (1.4 * 10^(-2) + color(red)(3)x)^color(red)(3)#</mathjax></p> </blockquote> <p>Now, because <mathjax>#K_(sp)#</mathjax> is so small, you can use the approximation </p> <blockquote> <p><mathjax>#1.4 * 10^(-2) + color(red)(3)x ~~ 1.4 * 10^(-2)#</mathjax></p> </blockquote> <p>This will get you </p> <blockquote> <p><mathjax>#2 * 10^(-19) = x * (1.4 * 10^(-2))^color(red)(3)#</mathjax></p> <p><mathjax>#x = (2 * 10^(-19))/(2.744 * 10^(-6)) = 7.29 * 10^(-14)#</mathjax></p> </blockquote> <p>The <strong>molar solubility</strong> of lanthanum fluoride in a solution that contains <mathjax>#1.4 * 10^(-2)"M"#</mathjax> potassium fluoride will be equal to <mathjax>#7.3 * 10^(-14)"M"#</mathjax>. </p> <p>To get the solubility in <em>grams per liter</em>, use lanthanum trifluoride's <strong>molar mass</strong></p> <blockquote> <p><mathjax>#7.3 * 10^(-13)color(red)(cancel(color(black)("mol")))"L"^(-1) * "195.9 g"/(1color(red)(cancel(color(black)("mole")))) = color(green)(\|bar(ul(color(white)(a/a)1.4 * 10^(-11)"g L"^(-1)color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer is rounded to two <strong><a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/246516" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-solubility-affect-equilibrium"> How does solubility affect equilibrium? 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1,709	a9f5aa76-6ddd-11ea-b3b0-ccda262736ce	https://socratic.org/questions/a-breathing-mixture-used-by-deep-sea-divers-has-a-total-pressure-of-101-4-kpa-an	18.5 kPa	start physical_unit 18 18 partial_pressure kpa qc_end physical_unit 1 2 13 14 total_pressure qc_end end	[{"type":"physical unit","value":"Partial pressure [OF] oxygen [IN] kPa"}]	[{"type":"physical unit","value":"18.5 kPa"}]	[{"type":"physical unit","value":"Total pressure [OF] the breathing mixture [=] \\pu{101.4 kPa}"},{"type":"physical unit","value":"Partial pressure [OF] He [=] \\pu{82.5 kPa}"},{"type":"physical unit","value":"Partial pressure [OF] CO2 [=] \\pu{0.4 kPa}"}]	<h1 class="questionTitle" itemprop="name">A breathing mixture used by deep sea divers has a total pressure of 101.4 kPa and contains hellum, oxygen and carbon doxide. What is the partial pressure of oxygen if #P_(He) = 82.5 kPa# and #P_(CO_2) = 0.4 kPa#?</h1>	null	18.5 kPa	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And so <mathjax>#P_(O_2)=P_"Total"-P_(He)-P_(CO_2)#</mathjax></p> <p><mathjax>#={101.4-82.5-0.4}kPa#</mathjax></p> <p><mathjax>#=18.5kPa#</mathjax></p> <p>In commercial diving mixes I am not sure that carbon dioxide would be added in those quantities. I used to do a lot of recreational scuba diving, and of course we filled our tanks with compressed air. Commercial divers, nowadays, use so-called <mathjax>#"trimix"#</mathjax>, which is usually <mathjax>#"trimix 10/70"#</mathjax>, <mathjax>#10%#</mathjax> <mathjax>#O_2#</mathjax>, <mathjax>#70%#</mathjax> <mathjax>#He#</mathjax>, and <mathjax>#20%#</mathjax> <mathjax>#N_2#</mathjax>.....which is apparently suitable for <mathjax>#100m#</mathjax>, i.e. <mathjax>#330ft#</mathjax> depths, which to me are frightening. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#P_"Total"=P_(O_2)+P_(He)+P_(CO_2)........#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And so <mathjax>#P_(O_2)=P_"Total"-P_(He)-P_(CO_2)#</mathjax></p> <p><mathjax>#={101.4-82.5-0.4}kPa#</mathjax></p> <p><mathjax>#=18.5kPa#</mathjax></p> <p>In commercial diving mixes I am not sure that carbon dioxide would be added in those quantities. I used to do a lot of recreational scuba diving, and of course we filled our tanks with compressed air. Commercial divers, nowadays, use so-called <mathjax>#"trimix"#</mathjax>, which is usually <mathjax>#"trimix 10/70"#</mathjax>, <mathjax>#10%#</mathjax> <mathjax>#O_2#</mathjax>, <mathjax>#70%#</mathjax> <mathjax>#He#</mathjax>, and <mathjax>#20%#</mathjax> <mathjax>#N_2#</mathjax>.....which is apparently suitable for <mathjax>#100m#</mathjax>, i.e. <mathjax>#330ft#</mathjax> depths, which to me are frightening. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A breathing mixture used by deep sea divers has a total pressure of 101.4 kPa and contains hellum, oxygen and carbon doxide. What is the partial pressure of oxygen if #P_(He) = 82.5 kPa# and #P_(CO_2) = 0.4 kPa#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/measuring-gas-pressure" itemprop="url"> <span class="breadcrumb" itemprop="title">Measuring Gas Pressure</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="446714" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-07-01T18:09:35" itemprop="dateCreated"> Jul 1, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#P_"Total"=P_(O_2)+P_(He)+P_(CO_2)........#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And so <mathjax>#P_(O_2)=P_"Total"-P_(He)-P_(CO_2)#</mathjax></p> <p><mathjax>#={101.4-82.5-0.4}kPa#</mathjax></p> <p><mathjax>#=18.5kPa#</mathjax></p> <p>In commercial diving mixes I am not sure that carbon dioxide would be added in those quantities. I used to do a lot of recreational scuba diving, and of course we filled our tanks with compressed air. Commercial divers, nowadays, use so-called <mathjax>#"trimix"#</mathjax>, which is usually <mathjax>#"trimix 10/70"#</mathjax>, <mathjax>#10%#</mathjax> <mathjax>#O_2#</mathjax>, <mathjax>#70%#</mathjax> <mathjax>#He#</mathjax>, and <mathjax>#20%#</mathjax> <mathjax>#N_2#</mathjax>.....which is apparently suitable for <mathjax>#100m#</mathjax>, i.e. <mathjax>#330ft#</mathjax> depths, which to me are frightening. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/446714" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-used-to-measure-gas-pressure-in-a-closed-container"> What is used to measure gas pressure in a closed container? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-tool-is-used-to-measure-gas-pressure"> What tool is used to measure gas pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-units-are-used-to-measure-gas-pressure"> What units are used to measure gas pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-boyle-s-law"> What is Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-an-example-of-a-gas-pressure-practice-problem"> What is an example of a gas pressure practice problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-common-mistakes-students-make-when-measuring-gas-pressure"> What are some common mistakes students make when measuring gas pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-an-example-of-a-boyle-s-law-practice-problem"> What is an example of a Boyle's law practice problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-boyle-s-law-and-charles-law-differ-1"> How do Boyle's law and Charles' law differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-measure-gas-pressure"> How can I measure gas pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-boyle-s-law-affect-the-human-body"> How does Boyle's law affect the human body? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/measuring-gas-pressure"> See all questions in Measuring Gas Pressure </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2753 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A breathing mixture used by deep sea divers has a total pressure of 101.4 kPa and contains hellum, oxygen and carbon doxide. What is the partial pressure of oxygen if #P_(He) = 82.5 kPa# and #P_(CO_2) = 0.4 kPa#?	null
1,710	abd89398-6ddd-11ea-b5b9-ccda262736ce	https://socratic.org/questions/the-percentage-composition-of-acetic-acid-is-found-to-be-39-9-carbon-6-7-hydroge	CH2O	start chemical_formula qc_end end	[{"type":"other","value":"Chemical Formula [OF] acetic acid [IN] empirical"}]	[{"type":"chemical equation","value":"CH2O"}]	[{"type":"physical unit","value":"Percentage composition [OF] carbon in acetic acid [=] \\pu{39.9%}"},{"type":"physical unit","value":"Percentage composition [OF] hydrogen in acetic acid [=] \\pu{6.7%}"},{"type":"physical unit","value":"Percentage composition [OF] oxygen in acetic acid [=] \\pu{53.4%}"}]	<h1 class="questionTitle" itemprop="name">The percentage composition of acetic acid is found to be 39.9% carbon, 6.7% hydrogen, and 53.4% oxygen, how would you determine the empirical formula of acetic acid?</h1>	null	CH2O	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We divide the percentage composition by the <em>atomic</em> mass of each constituent element:</p> <p><mathjax>#(39.9g)/(12.011gmol^-1)= 3.32mol#</mathjax></p> <p><mathjax>#(6.7g)/(1.0794gmol^-1)= 6.65mol#</mathjax></p> <p><mathjax>#(53.4g)/(16.00 gmol^-1)= 3.34mol#</mathjax></p> <p>We divide thru by the lowest quotient <mathjax>#(3.32)#</mathjax> to get <mathjax>#C:H:O-=1:2:1#</mathjax>.</p> <p>So the empirical formula is <mathjax>#CH_2O#</mathjax>. And the empirical formula is the simplest whole number ratio that defines constituent atoms in a species. </p> <p>Now it is a fact that the molecular formula of acetic acid is <mathjax>#H_3C-C(=O)OH = C_2H_4O_2#</mathjax>. Is this a mulitple of the empirical formula; i.e. what is <mathjax>#n#</mathjax> for <mathjax>#(CH_2O)_n = C_2H_4O_2#</mathjax>?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We assume <mathjax>#100* g#</mathjax> of compound. Therefore the acid contains <mathjax>#39.9* g* C#</mathjax>; <mathjax>#6.7* g* H#</mathjax>; and <mathjax>#53.4gO#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We divide the percentage composition by the <em>atomic</em> mass of each constituent element:</p> <p><mathjax>#(39.9g)/(12.011gmol^-1)= 3.32mol#</mathjax></p> <p><mathjax>#(6.7g)/(1.0794gmol^-1)= 6.65mol#</mathjax></p> <p><mathjax>#(53.4g)/(16.00 gmol^-1)= 3.34mol#</mathjax></p> <p>We divide thru by the lowest quotient <mathjax>#(3.32)#</mathjax> to get <mathjax>#C:H:O-=1:2:1#</mathjax>.</p> <p>So the empirical formula is <mathjax>#CH_2O#</mathjax>. And the empirical formula is the simplest whole number ratio that defines constituent atoms in a species. </p> <p>Now it is a fact that the molecular formula of acetic acid is <mathjax>#H_3C-C(=O)OH = C_2H_4O_2#</mathjax>. Is this a mulitple of the empirical formula; i.e. what is <mathjax>#n#</mathjax> for <mathjax>#(CH_2O)_n = C_2H_4O_2#</mathjax>?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">The percentage composition of acetic acid is found to be 39.9% carbon, 6.7% hydrogen, and 53.4% oxygen, how would you determine the empirical formula of acetic acid?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="180184" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-10-26T19:59:56" itemprop="dateCreated"> Oct 26, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We assume <mathjax>#100* g#</mathjax> of compound. Therefore the acid contains <mathjax>#39.9* g* C#</mathjax>; <mathjax>#6.7* g* H#</mathjax>; and <mathjax>#53.4gO#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We divide the percentage composition by the <em>atomic</em> mass of each constituent element:</p> <p><mathjax>#(39.9g)/(12.011gmol^-1)= 3.32mol#</mathjax></p> <p><mathjax>#(6.7g)/(1.0794gmol^-1)= 6.65mol#</mathjax></p> <p><mathjax>#(53.4g)/(16.00 gmol^-1)= 3.34mol#</mathjax></p> <p>We divide thru by the lowest quotient <mathjax>#(3.32)#</mathjax> to get <mathjax>#C:H:O-=1:2:1#</mathjax>.</p> <p>So the empirical formula is <mathjax>#CH_2O#</mathjax>. And the empirical formula is the simplest whole number ratio that defines constituent atoms in a species. </p> <p>Now it is a fact that the molecular formula of acetic acid is <mathjax>#H_3C-C(=O)OH = C_2H_4O_2#</mathjax>. Is this a mulitple of the empirical formula; i.e. what is <mathjax>#n#</mathjax> for <mathjax>#(CH_2O)_n = C_2H_4O_2#</mathjax>?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/180184" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molecular-formula-of-a-compound"> How do you find molecular formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-diamond"> What is the chemical formula of a diamond? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-carbohydrate"> What is the chemical formula of a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-valproic-acid"> What is the empirical formula for valproic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-of-magnesium-oxide"> What is the empirical formula of magnesium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-empirical-formula-not-double-that-of-the-monosaccharides"> Why is the empirical formula not double that of the monosaccharides? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5331180502bf342f40b5c3b5"> Question #5c3b5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-molecular-formula-represents-a-carbohydrate"> What molecular formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-of-vinegar"> What is the molecular formula of vinegar? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/empirical-and-molecular-formulas"> See all questions in Empirical and Molecular Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 38892 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	The percentage composition of acetic acid is found to be 39.9% carbon, 6.7% hydrogen, and 53.4% oxygen, how would you determine the empirical formula of acetic acid?	null
1,711	aa874312-6ddd-11ea-9f98-ccda262736ce	https://socratic.org/questions/how-many-moles-of-mgi-2-will-you-have-if-you-have-345-0-g-of-it	1.24 moles	start physical_unit 4 4 mole mol qc_end physical_unit 4 4 11 12 mass qc_end end	[{"type":"physical unit","value":"Mole [OF] MgI2 [IN] moles"}]	[{"type":"physical unit","value":"1.24 moles"}]	[{"type":"physical unit","value":"Mass [OF] MgI2 [=] \\pu{345.0 g}"}]	<h1 class="questionTitle" itemprop="name">How many moles of #MgI_2# will you have if you have 345.0 g of it?</h1>	null	1.24 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Number of moles"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Mass"/"Molar Mass"#</mathjax></p> <p><mathjax>#=#</mathjax> <mathjax>#(345.0g)/(278.11g*mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??mol#</mathjax>.</p> <p>How may moles of iodine does this represent? Why?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>A bit over <mathjax>#1#</mathjax> <mathjax>#mol#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Number of moles"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Mass"/"Molar Mass"#</mathjax></p> <p><mathjax>#=#</mathjax> <mathjax>#(345.0g)/(278.11g*mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??mol#</mathjax>.</p> <p>How may moles of iodine does this represent? Why?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles of #MgI_2# will you have if you have 345.0 g of it?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="284484" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-04T04:47:48" itemprop="dateCreated"> Jul 4, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>A bit over <mathjax>#1#</mathjax> <mathjax>#mol#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Number of moles"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Mass"/"Molar Mass"#</mathjax></p> <p><mathjax>#=#</mathjax> <mathjax>#(345.0g)/(278.11g*mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??mol#</mathjax>.</p> <p>How may moles of iodine does this represent? Why?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/284484" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1011 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many moles of #MgI_2# will you have if you have 345.0 g of it?	null
1,712	ab81a842-6ddd-11ea-9e36-ccda262736ce	https://socratic.org/questions/what-is-the-formula-for-potassium-sulfite	K2SO3	start chemical_formula qc_end substance 5 6 qc_end end	[{"type":"other","value":"Chemical Formula [OF] potassium sulfite [IN] default"}]	[{"type":"chemical equation","value":"K2SO3"}]	[{"type":"substance name","value":"Potassium sulfite"}]	<h1 class="questionTitle" itemprop="name">What is the formula for potassium sulfite?</h1>	null	K2SO3	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Proper nomenclature says that the ion with one less O atom that the "ate" form (i.e. sulfate) is given the suffix "ite". Hence, sulfite ion is <mathjax>#SO_3^2-#</mathjax>.</p> <p>We require two potassium ions, each with a +1 charge to form the electrically neutral compound.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#K_2SO_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Proper nomenclature says that the ion with one less O atom that the "ate" form (i.e. sulfate) is given the suffix "ite". Hence, sulfite ion is <mathjax>#SO_3^2-#</mathjax>.</p> <p>We require two potassium ions, each with a +1 charge to form the electrically neutral compound.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the formula for potassium sulfite?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/determining-formula-and-molar-masses" itemprop="url"> <span class="breadcrumb" itemprop="title">Determining Formula</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="352365" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/dwight"><img alt="" class="" src="https://profilepictures.socratic.org/ZDiTFWmAQmWOT3sd0Xpr_Dwight.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/dwight"> Dwight </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-12-15T21:03:47" itemprop="dateCreated"> Dec 15, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#K_2SO_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Proper nomenclature says that the ion with one less O atom that the "ate" form (i.e. sulfate) is given the suffix "ite". Hence, sulfite ion is <mathjax>#SO_3^2-#</mathjax>.</p> <p>We require two potassium ions, each with a +1 charge to form the electrically neutral compound.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/352365" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-it-possible-to-find-a-molecular-formula-from-molar-mass"> Is it possible to find a molecular formula from molar mass? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5368e0cc02bf34779e175781"> Question #75781 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-common-mistakes-students-make-when-determining-formulas"> What are some common mistakes students make when determining formulas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-formula-of-an-acid"> How can I determine the formula of an acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-chemical-formula-of-a-product"> How can I determine the chemical formula of a product? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-empirical-formula-of-a-compound"> How can I determine the empirical formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-formula-of-a-hydrate"> How can I determine the formula of a hydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-the-empirical-formula-indicate"> What does the empirical formula indicate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-molecule-with-molecular-weight-of-180-18-g-mol-is-analyzed-and-found-to-contai"> A molecule with molecular weight of 180.18 g/mol is analyzed and found to contain 40.00% carbon,... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/do-i-need-to-know-the-number-of-moles-of-each-element-to-determine-the-formula-o"> Do I need to know the number of moles of each element to determine the formula of the compound? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/determining-formula-and-molar-masses"> See all questions in Determining Formula </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 7821 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the formula for potassium sulfite?	null
1,713	aad1dcf4-6ddd-11ea-b9ed-ccda262736ce	https://socratic.org/questions/595413607c014908ab7b2e21	787.75 mmHg	start physical_unit 12 13 pressure mmhg qc_end physical_unit 12 13 8 9 mass qc_end physical_unit 12 13 15 16 temperature qc_end physical_unit 12 13 25 26 volume qc_end end	[{"type":"physical unit","value":"Pressure [OF] oxygen gas [IN] mmHg"}]	[{"type":"physical unit","value":"787.75 mmHg"}]	[{"type":"physical unit","value":"Mass [OF] oxygen gas [=] \\pu{4.0 g}"},{"type":"physical unit","value":"Temperature [OF] oxygen gas [=] \\pu{303 K}"},{"type":"physical unit","value":"Volume [OF] oxygen gas [=] \\pu{3000 mL}"}]	<h1 class="questionTitle" itemprop="name">What is the pressure in #mmHg# if a #4.0g# mass of oxygen gas at #303K# was confined to a container whose volume of #3000mL#?</h1>	null	787.75 mmHg	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We use the Ideal Gas Equation, to give.....</p> <p><mathjax>#P=(nRT)/V=((4.00g)/(32.00gmol^-1)xx0.0821(Latm)/(Kmol)xx303K)/(3000mLxx10^-3LmL^-1)#</mathjax></p> <p><mathjax>#=1.04atm#</mathjax></p> <p>Now had the pressure been UNDER <mathjax>#1atm#</mathjax> I could use the relationship <mathjax>#1atm-=760mmHg#</mathjax>; i.e. an atmosphere will support a column of mercury that is so high. You do not measure a pressure that is greater than <mathjax>#1atm#</mathjax> in <mathjax>#mm*Hg#</mathjax>. Whoever set this problem was ignorant.........</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#P=1.04atm.......#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We use the Ideal Gas Equation, to give.....</p> <p><mathjax>#P=(nRT)/V=((4.00g)/(32.00gmol^-1)xx0.0821(Latm)/(Kmol)xx303K)/(3000mLxx10^-3LmL^-1)#</mathjax></p> <p><mathjax>#=1.04atm#</mathjax></p> <p>Now had the pressure been UNDER <mathjax>#1atm#</mathjax> I could use the relationship <mathjax>#1atm-=760mmHg#</mathjax>; i.e. an atmosphere will support a column of mercury that is so high. You do not measure a pressure that is greater than <mathjax>#1atm#</mathjax> in <mathjax>#mmHg#</mathjax>. Whoever set this problem was ignorant.........</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the pressure in #mmHg# if a #4.0g# mass of oxygen gas at #303K# was confined to a container whose volume of #3000mL#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/ideal-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Ideal Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="445562" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-28T20:51:40" itemprop="dateCreated"> Jun 28, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#P=1.04atm.......#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We use the Ideal Gas Equation, to give.....</p> <p><mathjax>#P=(nRT)/V=((4.00g)/(32.00gmol^-1)xx0.0821(Latm)/(Kmol)xx303K)/(3000mLxx10^-3LmL^-1)#</mathjax></p> <p><mathjax>#=1.04atm#</mathjax></p> <p>Now had the pressure been UNDER <mathjax>#1atm#</mathjax> I could use the relationship <mathjax>#1atm-=760mmHg#</mathjax>; i.e. an atmosphere will support a column of mercury that is so high. You do not measure a pressure that is greater than <mathjax>#1atm#</mathjax> in <mathjax>#mmHg#</mathjax>. Whoever set this problem was ignorant.........</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/445562" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-ideal-gas-constant"> How do you find the ideal gas constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-solve-ideal-gas-law-problems"> How do you solve ideal gas law problems? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-know-which-ideal-gas-constant-to-use"> How do you know which ideal gas constant to use? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ideal-gas-constant-for-butane"> What is the ideal gas constant for butane? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-ideal-gas-law-in-kelvin"> Why is ideal gas law in kelvin? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ideal-gas-constant-important"> Why is the ideal gas constant important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-di-electric-constant"> What is the di-electric constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-volume-l-will-0-20-mol-hi-occupy-at-300-k-and-100-0-kpa-r-8-314-kpa-l-k-mol"> What volume (L) will 0.20 mol HI occupy at 300 K and 100.0 kPa? R = 8.314 kPa L / (K mol) =... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-molar-mass-of-a-gas"> How do you calculate the molar mass of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-should-i-use-the-ideal-gas-law-and-not-the-combined-gas-law"> When should I use the ideal gas law and not the combined gas law? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/ideal-gas-law"> See all questions in Ideal Gas Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1669 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the pressure in #mmHg# if a #4.0g# mass of oxygen gas at #303K# was confined to a container whose volume of #3000mL#?	null
1,714	a9909d68-6ddd-11ea-b231-ccda262736ce	https://socratic.org/questions/the-volume-of-a-gas-is-0-400-l-when-the-pressure-is-2-00-atm-at-the-same-tempera	0.40 atm	start physical_unit 27 28 pressure atm qc_end physical_unit 27 28 12 13 pressure qc_end physical_unit 27 28 6 7 volume qc_end physical_unit 27 28 30 31 volume qc_end c_other constant_temperature qc_end end	[{"type":"physical unit","value":"Pressure2 [OF] the gas [IN] atm"}]	[{"type":"physical unit","value":"0.40 atm"}]	[{"type":"physical unit","value":"Pressure1 [OF] the gas [=] \\pu{2.00 atm}"},{"type":"physical unit","value":"Volume1 [OF] the gas [=] \\pu{0.400 L}"},{"type":"physical unit","value":"Volume2 [OF] the gas [=] \\pu{2.0 L}"},{"type":"other","value":"ConstantTemperature"}]	<h1 class="questionTitle" itemprop="name">The volume of a gas is 0.400 L when the pressure is 2.00 atm. At the same temperature, what is the pressure at which the volume of the gas is 2.0 L? </h1>	null	0.40 atm	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In this question , the gas is kept under the same temperature. Assuming the amount of gas is constant we can apply Boyles' law.</p> <p>As per the Boyle' law equation;</p> <p><mathjax>#P_1#</mathjax> <mathjax># V_1#</mathjax> = <mathjax>#P_2#</mathjax> <mathjax># V_2#</mathjax> </p> <p>2 atm x 0.400 L = <mathjax>#P_2#</mathjax> x 2.0 L</p> <p>0.800 atm L = 2 <mathjax>#P_2#</mathjax> L</p> <p>dividing both the sides by 2 we get,</p> <p><strong>0.400 atm = <mathjax>#P_2#</mathjax></strong> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.4 atm</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In this question , the gas is kept under the same temperature. Assuming the amount of gas is constant we can apply Boyles' law.</p> <p>As per the Boyle' law equation;</p> <p><mathjax>#P_1#</mathjax> <mathjax># V_1#</mathjax> = <mathjax>#P_2#</mathjax> <mathjax># V_2#</mathjax> </p> <p>2 atm x 0.400 L = <mathjax>#P_2#</mathjax> x 2.0 L</p> <p>0.800 atm L = 2 <mathjax>#P_2#</mathjax> L</p> <p>dividing both the sides by 2 we get,</p> <p><strong>0.400 atm = <mathjax>#P_2#</mathjax></strong> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">The volume of a gas is 0.400 L when the pressure is 2.00 atm. At the same temperature, what is the pressure at which the volume of the gas is 2.0 L? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/gas-laws" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Laws</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="418025" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/manish-b"><img alt="" class="" src="https://profilepictures.socratic.org/eW7uaERSSvtv5ff2XPxA_10203153902643748.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/manish-b"> Manish Bhardwaj </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-05T08:30:12" itemprop="dateCreated"> May 5, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.4 atm</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In this question , the gas is kept under the same temperature. Assuming the amount of gas is constant we can apply Boyles' law.</p> <p>As per the Boyle' law equation;</p> <p><mathjax>#P_1#</mathjax> <mathjax># V_1#</mathjax> = <mathjax>#P_2#</mathjax> <mathjax># V_2#</mathjax> </p> <p>2 atm x 0.400 L = <mathjax>#P_2#</mathjax> x 2.0 L</p> <p>0.800 atm L = 2 <mathjax>#P_2#</mathjax> L</p> <p>dividing both the sides by 2 we get,</p> <p><strong>0.400 atm = <mathjax>#P_2#</mathjax></strong> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/418025" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-boyles-law-relate-to-breathing"> How does Boyle's law relate to breathing? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/in-avogadro-s-law-what-would-happen-to-v-if-n-is-increased-decreased-and-what-wo"> In Avogadro's Law what would happen to V if N is increased/decreased? 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At the same temperature, what is the pressure at which the volume of the gas is 2.0 L?	null
1,715	abf0a324-6ddd-11ea-a957-ccda262736ce	https://socratic.org/questions/598e9a0ab72cff426c677d8b	+2	start physical_unit 7 8 oxidation_number none qc_end chemical_equation 10 10 qc_end end	[{"type":"physical unit","value":"Oxidation number [OF] ipso carbon"}]	[{"type":"physical unit","value":"+2"}]	[{"type":"chemical equation","value":"HC(=O)O-"}]	<h1 class="questionTitle" itemprop="name">What is the oxidation number of the ipso carbon in #HC(=O)O^(-)#?</h1>	null	+2	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We gots <mathjax>#HC(=O)O^(-)Na^(+)#</mathjax>. The sum of the <a href="https://socratic.org/chemistry/electrochemistry/oxidation-numbers">oxidation numbers</a> on the formate anion equals <mathjax>#-1#</mathjax>. The oxidation number of oxygen is usually <mathjax>#-II#</mathjax>, and it is here, and the oxidation number of hydrogen is usually <mathjax>#+I#</mathjax>, and it is here.....</p> <p>And so <mathjax>#-1=C_"oxidation number"+1-2xx2#</mathjax></p> <p><mathjax>#C_"oxidation number"=+II#</mathjax></p> <p>Note that for acetate ion or acetic acid, the corresponding oxidation number is <mathjax>#+III#</mathjax> for the ipso carbon......</p> <p>For general rules on the assignment of oxidation numbers see <a href="https://socratic.org/questions/how-do-you-find-oxidation-number-rules">here.</a> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>I make it <mathjax>#C(+II)#</mathjax>......</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We gots <mathjax>#HC(=O)O^(-)Na^(+)#</mathjax>. The sum of the <a href="https://socratic.org/chemistry/electrochemistry/oxidation-numbers">oxidation numbers</a> on the formate anion equals <mathjax>#-1#</mathjax>. The oxidation number of oxygen is usually <mathjax>#-II#</mathjax>, and it is here, and the oxidation number of hydrogen is usually <mathjax>#+I#</mathjax>, and it is here.....</p> <p>And so <mathjax>#-1=C_"oxidation number"+1-2xx2#</mathjax></p> <p><mathjax>#C_"oxidation number"=+II#</mathjax></p> <p>Note that for acetate ion or acetic acid, the corresponding oxidation number is <mathjax>#+III#</mathjax> for the ipso carbon......</p> <p>For general rules on the assignment of oxidation numbers see <a href="https://socratic.org/questions/how-do-you-find-oxidation-number-rules">here.</a> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the oxidation number of the ipso carbon in #HC(=O)O^(-)#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#electrochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Electrochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/electrochemistry/oxidation-numbers" itemprop="url"> <span class="breadcrumb" itemprop="title">Oxidation Numbers</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="462996" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-12T06:15:03" itemprop="dateCreated"> Aug 12, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>I make it <mathjax>#C(+II)#</mathjax>......</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We gots <mathjax>#HC(=O)O^(-)Na^(+)#</mathjax>. The sum of the <a href="https://socratic.org/chemistry/electrochemistry/oxidation-numbers">oxidation numbers</a> on the formate anion equals <mathjax>#-1#</mathjax>. The oxidation number of oxygen is usually <mathjax>#-II#</mathjax>, and it is here, and the oxidation number of hydrogen is usually <mathjax>#+I#</mathjax>, and it is here.....</p> <p>And so <mathjax>#-1=C_"oxidation number"+1-2xx2#</mathjax></p> <p><mathjax>#C_"oxidation number"=+II#</mathjax></p> <p>Note that for acetate ion or acetic acid, the corresponding oxidation number is <mathjax>#+III#</mathjax> for the ipso carbon......</p> <p>For general rules on the assignment of oxidation numbers see <a href="https://socratic.org/questions/how-do-you-find-oxidation-number-rules">here.</a> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/462996" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="463004" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/scooke"><img alt="" class="" src="https://profilepictures.socratic.org/ezAzqDkjRS6NXBmMH3lg_BioPic2010a.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/scooke"> SCooke </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-12T06:47:05" itemprop="dateCreated"> Aug 12, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>+2</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The Lewis Dot Structure analysis may be the best visual.</p> <p>When a Lewis dot structure of a molecule is available, the oxidation states may be assigned by computing the difference between the number of valence electrons that a neutral atom of that element would have and the number of electrons that "belong" to it in the Lewis structure. </p> <p>For purposes of computing oxidation states, electrons in a bond between atoms of different elements belong to the more electronegative atom; electrons in a bond between atoms of the same element are split equally, and electrons in alone pair belong only to the atom with the lone pair. </p> <p><img alt="enter image source here" src="https://useruploads.socratic.org/WEOJr3mtR06YF5YueDCQ_Acetic_acid_oxidation_state_analysis%20-%20Lewis%20Structure.png"/> <br/> From <a href="https://en.wikipedia.org/wiki/Oxidation_state" rel="nofollow" target="_blank">https://en.wikipedia.org/wiki/Oxidation_state</a></p> <p>The methyl group carbon atom has six valence electrons from its bonds to the hydrogen atoms because carbon is more electronegative than hydrogen. Also, one electron is gained from its bond with the other carbon atom because the electron pair in the C−C bond is split equally. </p> <p>It therefore has a total of seven electrons, whereas a neutral carbon atom would have four valence electrons because carbon is in group 14 of the periodic table. The difference, 4 − 7 = −3, is the oxidation state of that carbon atom. That is, if it is assumed that all the bonds were 100% ionic (which in fact they are not), the carbon would be described as C3−<br/> .</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/463004" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-relate-to-electron-configuration"> How do oxidation numbers relate to electron configuration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-relate-to-valence-electrons"> How do oxidation numbers relate to valence electrons? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-vary-with-the-periodic-table"> How do oxidation numbers vary with the periodic table? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-oxidation-number-of-an-element-in-a-compound"> How do you calculate the oxidation number of an element in a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-sulfur"> What is the oxidation number for sulfur? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-carbon"> What is the oxidation number for carbon? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-copper"> What is the oxidation number for copper? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-nitrogen"> What is the oxidation number for nitrogen? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-oxygen"> What is the oxidation number for oxygen? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-oxidation-state-of-noble-gas-zero"> Why is the oxidation state of noble gas zero? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/electrochemistry/oxidation-numbers"> See all questions in Oxidation Numbers </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3067 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the oxidation number of the ipso carbon in #HC(=O)O^(-)#?	null
1,716	a8c9a089-6ddd-11ea-b11b-ccda262736ce	https://socratic.org/questions/how-do-you-balance-and-translate-this-reaction-kclo-3-s-kcl-s-o-2-g	2 KClO3(s) -> 2 KCl(s) + 3 O2(g)	start chemical_equation qc_end chemical_equation 7 11 qc_end end	[{"type":"other","value":"Chemical Equation [OF] this reaction"}]	[{"type":"chemical equation","value":"2 KClO3(s) -> 2 KCl(s) + 3 O2(g)"}]	[{"type":"chemical equation","value":"KClO3(s) -> KCl(s) + O2(g)"}]	<h1 class="questionTitle" itemprop="name">How do you balance and translate this reaction: #KClO_3(s) -> KCl(s) + O_2(g)#?</h1>	null	2 KClO3(s) -> 2 KCl(s) + 3 O2(g)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Let's identify : K is potassium, Cl is chlorine and O is oxygen. </p> <p>Let's identify the state symbols : (s) is solid, and (g) is gas.</p> <p>Let's identify the unbalanced element(s) : Potassium is balanced, there are 1 on each side. Chlorine is balanced, there are 1 on each side. Oxygen is <strong>not</strong> balanced, there's 3 on the LHS, and 2 on the RHS. </p> <p>How many times does 2 go into 3? The answer is 1.5. Change the coefficient of the oxygen on the RHS from 1 to 1.5</p> <p><mathjax>#KClO_3(s)rarrKCl(s)+1.5O_2(g)#</mathjax></p> <p>But we can't have <em>half atoms</em> in <a href="https://socratic.org/chemistry/chemical-reactions/chemical-equations">chemical equations</a>. Multiply the entire equation by 2 to get rid of the half atom.</p> <p><mathjax>#2KClO_3(s)rarr2KCl(s)+3O_2(g)#</mathjax></p> <p>Now everything is balanced : There are 2 potassium, 2 chlorine and 6 oxygen atoms. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2KClO_3(s)rarrKCl(s)+3O_2(g)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Let's identify : K is potassium, Cl is chlorine and O is oxygen. </p> <p>Let's identify the state symbols : (s) is solid, and (g) is gas.</p> <p>Let's identify the unbalanced element(s) : Potassium is balanced, there are 1 on each side. Chlorine is balanced, there are 1 on each side. Oxygen is <strong>not</strong> balanced, there's 3 on the LHS, and 2 on the RHS. </p> <p>How many times does 2 go into 3? The answer is 1.5. Change the coefficient of the oxygen on the RHS from 1 to 1.5</p> <p><mathjax>#KClO_3(s)rarrKCl(s)+1.5O_2(g)#</mathjax></p> <p>But we can't have <em>half atoms</em> in <a href="https://socratic.org/chemistry/chemical-reactions/chemical-equations">chemical equations</a>. Multiply the entire equation by 2 to get rid of the half atom.</p> <p><mathjax>#2KClO_3(s)rarr2KCl(s)+3O_2(g)#</mathjax></p> <p>Now everything is balanced : There are 2 potassium, 2 chlorine and 6 oxygen atoms. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you balance and translate this reaction: #KClO_3(s) -> KCl(s) + O_2(g)#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="428288" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/soya-s"><img alt="" class="" src="https://lh3.googleusercontent.com/-0gsdbRI26uE/AAAAAAAAAAI/AAAAAAAAACE/ho0eSqho828/photo.jpg?sz=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/soya-s"> SoySoy4444 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-23T11:08:53" itemprop="dateCreated"> May 23, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2KClO_3(s)rarrKCl(s)+3O_2(g)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Let's identify : K is potassium, Cl is chlorine and O is oxygen. </p> <p>Let's identify the state symbols : (s) is solid, and (g) is gas.</p> <p>Let's identify the unbalanced element(s) : Potassium is balanced, there are 1 on each side. Chlorine is balanced, there are 1 on each side. Oxygen is <strong>not</strong> balanced, there's 3 on the LHS, and 2 on the RHS. </p> <p>How many times does 2 go into 3? The answer is 1.5. Change the coefficient of the oxygen on the RHS from 1 to 1.5</p> <p><mathjax>#KClO_3(s)rarrKCl(s)+1.5O_2(g)#</mathjax></p> <p>But we can't have <em>half atoms</em> in <a href="https://socratic.org/chemistry/chemical-reactions/chemical-equations">chemical equations</a>. Multiply the entire equation by 2 to get rid of the half atom.</p> <p><mathjax>#2KClO_3(s)rarr2KCl(s)+3O_2(g)#</mathjax></p> <p>Now everything is balanced : There are 2 potassium, 2 chlorine and 6 oxygen atoms. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/428288" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------> H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -> Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? 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Sodium phosphate and calcium chloride react to form... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-equation-kclo3-kcl-o2"> How can I balance this equation? ____ #KClO_3 -># ____ #KCl +# ____ #O_2# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-balancing-chemical-equations-important"> Why is balancing chemical equations important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/balancing-chemical-equations"> See all questions in Balancing Chemical Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2866 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How do you balance and translate this reaction: #KClO_3(s) -> KCl(s) + O_2(g)#?	null
1,717	acaeabec-6ddd-11ea-9337-ccda262736ce	https://socratic.org/questions/how-many-moles-of-of-koh-are-needed-to-exactly-neutralize-500-ml-of-1-0-m-hcl	0.50 moles	start physical_unit 4 4 mole mol qc_end physical_unit 15 15 13 14 molarity qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Mole [OF] KOH [IN] moles"}]	[{"type":"physical unit","value":"0.50 moles"}]	[{"type":"physical unit","value":"Volume [OF] HCl solution [=] \\pu{500 mL}"},{"type":"physical unit","value":"Molarity [OF] HCl solution [=] \\pu{1.0 M}"},{"type":"other","value":"Exactly neutralize."}]	<h1 class="questionTitle" itemprop="name">How many moles of of KOH are needed to exactly neutralize 500. mL of 1.0 M HCl? </h1>	null	0.50 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Potassium hydroxide, <mathjax>#"KOH"#</mathjax>, will react with hydrochloric acid, <mathjax>#"HCl"#</mathjax>, to produce aqueous potassium chloride and water.</p> <p>The balanced chemical equation that describes this <strong><a href="https://socratic.org/chemistry/reactions-in-solution/neutralization">neutralization</a> reaction</strong> looks like this</p> <blockquote> <p><mathjax>#"KOH"_ ((aq)) + "HCl"_ ((aq)) -> "KOH"_ ((aq)) + "H"_ 2"O"_ ((l))#</mathjax></p> </blockquote> <p>So, the reaction consumes potassium hydroxide and hydrochloric acid in a <mathjax>#1:1#</mathjax> <strong>mole ratio</strong>, which implies that the number of moles of potassium hydroxide needed to completely neutralize the hydrochloric acid solution will be <strong>equal</strong> to the number of moles of hydrochloric acid present in said solution. </p> <p>As you know, <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></strong> tells you the number of moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> present in <mathjax>#"1 L" = 10^3#</mathjax> <mathjax>#"mL"#</mathjax> of solution. </p> <p>This implies that the hydrochloric acid solution contains</p> <blockquote> <p><mathjax>#500. color(red)(cancel(color(black)("mL"))) * "1.0 moles HCl"/(10^3color(red)(cancel(color(black)("mL")))) = "0.50 moles HCl"#</mathjax></p> </blockquote> <p>Therefore, you can say that a complete neutralization requires <mathjax>#0.50#</mathjax> <strong>moles</strong> of potassium hydroxide. The answer is rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the molarity of the solution. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"0.50 moles KOH"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Potassium hydroxide, <mathjax>#"KOH"#</mathjax>, will react with hydrochloric acid, <mathjax>#"HCl"#</mathjax>, to produce aqueous potassium chloride and water.</p> <p>The balanced chemical equation that describes this <strong><a href="https://socratic.org/chemistry/reactions-in-solution/neutralization">neutralization</a> reaction</strong> looks like this</p> <blockquote> <p><mathjax>#"KOH"_ ((aq)) + "HCl"_ ((aq)) -> "KOH"_ ((aq)) + "H"_ 2"O"_ ((l))#</mathjax></p> </blockquote> <p>So, the reaction consumes potassium hydroxide and hydrochloric acid in a <mathjax>#1:1#</mathjax> <strong>mole ratio</strong>, which implies that the number of moles of potassium hydroxide needed to completely neutralize the hydrochloric acid solution will be <strong>equal</strong> to the number of moles of hydrochloric acid present in said solution. </p> <p>As you know, <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></strong> tells you the number of moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> present in <mathjax>#"1 L" = 10^3#</mathjax> <mathjax>#"mL"#</mathjax> of solution. </p> <p>This implies that the hydrochloric acid solution contains</p> <blockquote> <p><mathjax>#500. color(red)(cancel(color(black)("mL"))) * "1.0 moles HCl"/(10^3color(red)(cancel(color(black)("mL")))) = "0.50 moles HCl"#</mathjax></p> </blockquote> <p>Therefore, you can say that a complete neutralization requires <mathjax>#0.50#</mathjax> <strong>moles</strong> of potassium hydroxide. The answer is rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the molarity of the solution. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles of of KOH are needed to exactly neutralize 500. mL of 1.0 M HCl? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#reactions-in-solution" itemprop="url"> <span class="breadcrumb" itemprop="title">Reactions in Solution</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/reactions-in-solution/neutralization" itemprop="url"> <span class="breadcrumb" itemprop="title">Neutralization</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="437722" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-10T23:44:13" itemprop="dateCreated"> Jun 10, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"0.50 moles KOH"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Potassium hydroxide, <mathjax>#"KOH"#</mathjax>, will react with hydrochloric acid, <mathjax>#"HCl"#</mathjax>, to produce aqueous potassium chloride and water.</p> <p>The balanced chemical equation that describes this <strong><a href="https://socratic.org/chemistry/reactions-in-solution/neutralization">neutralization</a> reaction</strong> looks like this</p> <blockquote> <p><mathjax>#"KOH"_ ((aq)) + "HCl"_ ((aq)) -> "KOH"_ ((aq)) + "H"_ 2"O"_ ((l))#</mathjax></p> </blockquote> <p>So, the reaction consumes potassium hydroxide and hydrochloric acid in a <mathjax>#1:1#</mathjax> <strong>mole ratio</strong>, which implies that the number of moles of potassium hydroxide needed to completely neutralize the hydrochloric acid solution will be <strong>equal</strong> to the number of moles of hydrochloric acid present in said solution. </p> <p>As you know, <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></strong> tells you the number of moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> present in <mathjax>#"1 L" = 10^3#</mathjax> <mathjax>#"mL"#</mathjax> of solution. </p> <p>This implies that the hydrochloric acid solution contains</p> <blockquote> <p><mathjax>#500. color(red)(cancel(color(black)("mL"))) * "1.0 moles HCl"/(10^3color(red)(cancel(color(black)("mL")))) = "0.50 moles HCl"#</mathjax></p> </blockquote> <p>Therefore, you can say that a complete neutralization requires <mathjax>#0.50#</mathjax> <strong>moles</strong> of potassium hydroxide. The answer is rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the molarity of the solution. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/437722" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-neutralization-reactions-useful"> How are neutralization reactions useful? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-neutralization-reactions-be-identified-symbolically"> How can neutralization reactions be identified symbolically? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-neutralization-reaction-differ-from-buffer"> How does neutralization reaction differ from using a buffer? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-do-acid-base-neutralization-reactions"> How do you do acid base neutralization reactions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-neutralization-reactions-produce-heat"> Why do neutralization reactions produce heat? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-neutralization-a-double-replacement-reaction"> Why is neutralization a double replacement reaction? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-a-neutralization-reaction-exothermic"> Why is a neutralization reaction exothermic? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-predict-and-balance-acid-base-reactions"> How do you predict the products in acid-base reactions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-you-determine-the-strength-of-sulfuric-acid"> How can you determine the strength of sulfuric acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-a-neutralisation-reaction-exothermic"> Why is a neutralisation reaction exothermic? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/reactions-in-solution/neutralization"> See all questions in Neutralization </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 41100 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many moles of of KOH are needed to exactly neutralize 500. mL of 1.0 M HCl?	null
1,718	ac5c4148-6ddd-11ea-b112-ccda262736ce	https://socratic.org/questions/5919f34c7c014926b923f406	1.20 × 10^24	start physical_unit 2 3 number none qc_end physical_unit 2 2 5 6 mole qc_end end	[{"type":"physical unit","value":"Number [OF] carbon atoms"}]	[{"type":"physical unit","value":"1.20 × 10^24"}]	[{"type":"physical unit","value":"Mole [OF] carbon [=] \\pu{2 mol}"}]	<h1 class="questionTitle" itemprop="name">How many carbon atoms in #2*mol# of carbon?</h1>	null	1.20 × 10^24	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In one mole of carbon, there are <mathjax>#6.02 xx10^23#</mathjax> atoms. So in two moles, there will be twice that: <mathjax>#1.204xx10^24#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1.204 xx 10^24#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In one mole of carbon, there are <mathjax>#6.02 xx10^23#</mathjax> atoms. So in two moles, there will be twice that: <mathjax>#1.204xx10^24#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many carbon atoms in #2*mol# of carbon?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="423932" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/abdur-r"><img alt="" class="" src="https://profilepictures.socratic.org/YXIUDMM0SoZAxTdY3kn6_niagara_falls_fog_water_height_6376_3840x2160.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/abdur-r"> Monzur R. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-15T18:35:04" itemprop="dateCreated"> May 15, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1.204 xx 10^24#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In one mole of carbon, there are <mathjax>#6.02 xx10^23#</mathjax> atoms. So in two moles, there will be twice that: <mathjax>#1.204xx10^24#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/423932" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="423934" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-15T18:36:18" itemprop="dateCreated"> May 15, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"In 2 moles of carbon there are "12.04xx10^23" carbon atoms"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In one mole of stuff there are <mathjax>#6.02214085xx10^23#</mathjax> individual items of that stuff. If we got <mathjax>#"2 moles"#</mathjax> we multiply that number by <mathjax>#2#</mathjax>. What is the mass of this quantity of carbon atoms. You should be able to answer this <mathjax>#"pdq"#</mathjax>!</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/423934" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 23528 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many carbon atoms in #2*mol# of carbon?	null
1,719	a8b9c214-6ddd-11ea-af05-ccda262736ce	https://socratic.org/questions/how-would-you-calculate-the-molar-mass-of-water	18 g/mol	start physical_unit 8 8 molar_mass g/mol qc_end substance 8 8 qc_end end	[{"type":"physical unit","value":"Molar mass [OF] water [IN] g/mol"}]	[{"type":"physical unit","value":"18 g/mol"}]	[{"type":"substance name","value":"Water"}]	<h1 class="questionTitle" itemprop="name">How would you calculate the molar mass of water?</h1>	null	18 g/mol	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>One mole of <mathjax>#H_2#</mathjax>O is made up of 2 moles of Hydrogen atoms and 1 mole of Oxygen atom. </p> <p>Mass of 1 mole of Hydrogen atoms= 1 g /mol<br/> Mass of 1mole of Oxygen atoms = 16 g/mol</p> <p>Mass of two moles of Hydrogen atoms = 2x 1 g/mol = 2 g/mol.<br/> Mass of one mole of Oxygen atoms = 1 x 16 g /mol </p> <p>Mass of one mole of water = 2 g/mol + 16 g/mol = 18 g/mol.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>It is 18 g/mol.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>One mole of <mathjax>#H_2#</mathjax>O is made up of 2 moles of Hydrogen atoms and 1 mole of Oxygen atom. </p> <p>Mass of 1 mole of Hydrogen atoms= 1 g /mol<br/> Mass of 1mole of Oxygen atoms = 16 g/mol</p> <p>Mass of two moles of Hydrogen atoms = 2x 1 g/mol = 2 g/mol.<br/> Mass of one mole of Oxygen atoms = 1 x 16 g /mol </p> <p>Mass of one mole of water = 2 g/mol + 16 g/mol = 18 g/mol.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How would you calculate the molar mass of water?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="180279" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/manish-b"><img alt="" class="" src="https://profilepictures.socratic.org/eW7uaERSSvtv5ff2XPxA_10203153902643748.jpg" title=""/></a> <a class="secondContributorPic" href="/users/amusing-bee-1"><img alt="" class="" src="https://profilepictures.socratic.org/JL9QNwoTPm16PoMVmzGa_artwork_5abea3c926989_.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/manish-b"> Manish Bhardwaj </a>·<a class="topContributorLink" href="/users/amusing-bee-1"> Manvi </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-10-27T05:48:14" itemprop="dateCreated"> Oct 27, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>It is 18 g/mol.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>One mole of <mathjax>#H_2#</mathjax>O is made up of 2 moles of Hydrogen atoms and 1 mole of Oxygen atom. </p> <p>Mass of 1 mole of Hydrogen atoms= 1 g /mol<br/> Mass of 1mole of Oxygen atoms = 16 g/mol</p> <p>Mass of two moles of Hydrogen atoms = 2x 1 g/mol = 2 g/mol.<br/> Mass of one mole of Oxygen atoms = 1 x 16 g /mol </p> <p>Mass of one mole of water = 2 g/mol + 16 g/mol = 18 g/mol.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/180279" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 81049 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How would you calculate the molar mass of water?	null
1,720	ab9421b0-6ddd-11ea-bb6f-ccda262736ce	https://socratic.org/questions/58ff5bb7b72cff35c3b261e8	320 K	start physical_unit 25 26 temperature k qc_end physical_unit 5 6 1 2 mole qc_end physical_unit 5 6 13 14 volume qc_end physical_unit 5 6 17 18 pressure qc_end end	[{"type":"physical unit","value":"Temperature [OF] the gas [IN] K"}]	[{"type":"physical unit","value":"320 K"}]	[{"type":"physical unit","value":"Mole [OF] the ideal gas [=] \\pu{9.95 mol}"},{"type":"physical unit","value":"Volume [OF] the ideal gas [=] \\pu{208 L}"},{"type":"physical unit","value":"Pressure [OF] the ideal gas [=] \\pu{1.26 atm}"}]	<h1 class="questionTitle" itemprop="name">A #9.95mol# quantity of ideal gas is placed in a container of #208L# volume at #1.26*atm# pressure. What is the temperature of the gas?</h1>	null	320 K	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#T=(PV)/(nR)= (1.26cancel(atm)xx208cancelL)/(9.95cancel(mol)xx0.0821cancel(Latm)K^-1*cancel(mol^-1))#</mathjax></p> <p>At least this is dimensionally consistent. We wanted an answer in <mathjax>#K#</mathjax>, we got an answer in <mathjax>#1/(K^-1)=1/(1/K)=K#</mathjax> as required............</p> <p>So two questions:</p> <p>From where did I get the expression <mathjax>#T=(PV)/(nR)#</mathjax>?</p> <p>If we had measured <mathjax>#"ammonia gas"#</mathjax> or <mathjax>#"hydrogen chloride"#</mathjax> would our assumption of ideality be justified?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We can assume ideality, and find <mathjax>#T~=320K#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#T=(PV)/(nR)= (1.26cancel(atm)xx208cancelL)/(9.95cancel(mol)xx0.0821cancel(Latm)K^-1cancel(mol^-1))#</mathjax></p> <p>At least this is dimensionally consistent. We wanted an answer in <mathjax>#K#</mathjax>, we got an answer in <mathjax>#1/(K^-1)=1/(1/K)=K#</mathjax> as required............</p> <p>So two questions:</p> <p>From where did I get the expression <mathjax>#T=(PV)/(nR)#</mathjax>?</p> <p>If we had measured <mathjax>#"ammonia gas"#</mathjax> or <mathjax>#"hydrogen chloride"#</mathjax> would our assumption of ideality be justified?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A #9.95mol# quantity of ideal gas is placed in a container of #208L# volume at #1.26atm# pressure. What is the temperature of the gas?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/ideal-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Ideal Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="413013" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-26T05:41:20" itemprop="dateCreated"> Apr 26, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We can assume ideality, and find <mathjax>#T~=320K#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#T=(PV)/(nR)= (1.26cancel(atm)xx208cancelL)/(9.95cancel(mol)xx0.0821cancel(Latm)K^-1*cancel(mol^-1))#</mathjax></p> <p>At least this is dimensionally consistent. We wanted an answer in <mathjax>#K#</mathjax>, we got an answer in <mathjax>#1/(K^-1)=1/(1/K)=K#</mathjax> as required............</p> <p>So two questions:</p> <p>From where did I get the expression <mathjax>#T=(PV)/(nR)#</mathjax>?</p> <p>If we had measured <mathjax>#"ammonia gas"#</mathjax> or <mathjax>#"hydrogen chloride"#</mathjax> would our assumption of ideality be justified?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/413013" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-ideal-gas-constant"> How do you find the ideal gas constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-solve-ideal-gas-law-problems"> How do you solve ideal gas law problems? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-know-which-ideal-gas-constant-to-use"> How do you know which ideal gas constant to use? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ideal-gas-constant-for-butane"> What is the ideal gas constant for butane? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-ideal-gas-law-in-kelvin"> Why is ideal gas law in kelvin? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ideal-gas-constant-important"> Why is the ideal gas constant important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-di-electric-constant"> What is the di-electric constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-volume-l-will-0-20-mol-hi-occupy-at-300-k-and-100-0-kpa-r-8-314-kpa-l-k-mol"> What volume (L) will 0.20 mol HI occupy at 300 K and 100.0 kPa? R = 8.314 kPa L / (K mol) =... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-molar-mass-of-a-gas"> How do you calculate the molar mass of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-should-i-use-the-ideal-gas-law-and-not-the-combined-gas-law"> When should I use the ideal gas law and not the combined gas law? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/ideal-gas-law"> See all questions in Ideal Gas Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1621 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A #9.95mol# quantity of ideal gas is placed in a container of #208L# volume at #1.26*atm# pressure. What is the temperature of the gas?	null
1,721	ab684f1e-6ddd-11ea-852e-ccda262736ce	https://socratic.org/questions/571e933411ef6b32f588b90c	132 grams	start physical_unit 4 5 mass g qc_end physical_unit 12 13 9 10 mass qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Mass [OF] carbon dioxide [IN] grams"}]	[{"type":"physical unit","value":"132 grams"}]	[{"type":"physical unit","value":"Mass [OF] carbon monoxide [=] \\pu{83.7 g}"},{"type":"other","value":"Excess iron(II) oxide."}]	<h1 class="questionTitle" itemprop="name">How many grams of carbon dioxide are produced when #"83.7 g"# of carbon monoxide react with excess iron(II) oxide?</h1>	null	132 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Start by taking a look at the balanced chemical equation that describes this <strong><a href="https://socratic.org/chemistry/chemical-reactions/redox-reactions">redox reaction</a></strong></p> <blockquote> <p><mathjax>#"Fe"_ 2"O"_ (3(s)) + 3"CO"_ ((g)) -> 2"Fe"_ ((s)) + 3"CO"_(2(g))#</mathjax></p> </blockquote> <p>According to the chemical equation, <mathjax>#3#</mathjax> <strong>moles</strong> of carbon monoxide, <mathjax>#"CO"#</mathjax>, will react with <mathjax>#1#</mathjax> <strong>mole</strong> of ferric oxide, <mathjax>#"Fe"_2"O"_3#</mathjax>, and produce <mathjax>#3#</mathjax> <strong>moles</strong> of carbon dioxide, <mathjax>#"CO"_2#</mathjax>. </p> <p>Now, you are given <em>grams</em> of carbon monoxide and asked for <em>grams</em> of carbon dioxide. This means that you'll have to convert the aforementioned <strong><a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a></strong> that exists between carbon monoxide and carbon dioxide to a <em>gram ratio</em>. </p> <p>Since no mention of the mass of ferric oxide was made, you can assume that this reactant is <strong>in excess</strong>.</p> <p>So, to convert between <em>moles</em> and <em>grams</em>, use the <strong>molar mass</strong> of the two <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a>. </p> <blockquote> <p><mathjax>#"For CO: " M_M = "28.01 g mol"^(-1)#</mathjax></p> <p><mathjax>#"For CO"_2: color(white)(a)M_M = "44.01 g mol"^(-1)#</mathjax></p> </blockquote> <p>If <strong>one mole</strong> of carbon monoxide has a mass of <mathjax>#"28.01 g"#</mathjax> and <strong>one mole</strong> of carbon dioxide has a mass of <mathjax>#"44.01 g"#</mathjax>, it follows that the reaction produces <mathjax>#"44.01 g"#</mathjax> of carbon dioxide <strong>for every</strong> <mathjax>#"28.01 g"#</mathjax> of carbon monoxide. </p> <p>This is the case because of the <mathjax>#3:3#</mathjax> mole ratio that exists between the two compounds. </p> <p>So, your <mathjax>#"83.7 g"#</mathjax> of carbon monoxide will produce </p> <blockquote> <p><mathjax>#83.7 color(red)(cancel(color(black)("g CO"))) * "44.01 g CO"_2/(28.01 color(red)(cancel(color(black)("g CO")))) = color(green)(\|bar(ul(color(white)(a/a)"132 g CO"_2color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"132 g CO"_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Start by taking a look at the balanced chemical equation that describes this <strong><a href="https://socratic.org/chemistry/chemical-reactions/redox-reactions">redox reaction</a></strong></p> <blockquote> <p><mathjax>#"Fe"_ 2"O"_ (3(s)) + 3"CO"_ ((g)) -> 2"Fe"_ ((s)) + 3"CO"_(2(g))#</mathjax></p> </blockquote> <p>According to the chemical equation, <mathjax>#3#</mathjax> <strong>moles</strong> of carbon monoxide, <mathjax>#"CO"#</mathjax>, will react with <mathjax>#1#</mathjax> <strong>mole</strong> of ferric oxide, <mathjax>#"Fe"_2"O"_3#</mathjax>, and produce <mathjax>#3#</mathjax> <strong>moles</strong> of carbon dioxide, <mathjax>#"CO"_2#</mathjax>. </p> <p>Now, you are given <em>grams</em> of carbon monoxide and asked for <em>grams</em> of carbon dioxide. This means that you'll have to convert the aforementioned <strong><a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a></strong> that exists between carbon monoxide and carbon dioxide to a <em>gram ratio</em>. </p> <p>Since no mention of the mass of ferric oxide was made, you can assume that this reactant is <strong>in excess</strong>.</p> <p>So, to convert between <em>moles</em> and <em>grams</em>, use the <strong>molar mass</strong> of the two <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a>. </p> <blockquote> <p><mathjax>#"For CO: " M_M = "28.01 g mol"^(-1)#</mathjax></p> <p><mathjax>#"For CO"_2: color(white)(a)M_M = "44.01 g mol"^(-1)#</mathjax></p> </blockquote> <p>If <strong>one mole</strong> of carbon monoxide has a mass of <mathjax>#"28.01 g"#</mathjax> and <strong>one mole</strong> of carbon dioxide has a mass of <mathjax>#"44.01 g"#</mathjax>, it follows that the reaction produces <mathjax>#"44.01 g"#</mathjax> of carbon dioxide <strong>for every</strong> <mathjax>#"28.01 g"#</mathjax> of carbon monoxide. </p> <p>This is the case because of the <mathjax>#3:3#</mathjax> mole ratio that exists between the two compounds. </p> <p>So, your <mathjax>#"83.7 g"#</mathjax> of carbon monoxide will produce </p> <blockquote> <p><mathjax>#83.7 color(red)(cancel(color(black)("g CO"))) * "44.01 g CO"_2/(28.01 color(red)(cancel(color(black)("g CO")))) = color(green)(\|bar(ul(color(white)(a/a)"132 g CO"_2color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many grams of carbon dioxide are produced when #"83.7 g"# of carbon monoxide react with excess iron(II) oxide?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="258744" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-04-26T01:35:23" itemprop="dateCreated"> Apr 26, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"132 g CO"_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Start by taking a look at the balanced chemical equation that describes this <strong><a href="https://socratic.org/chemistry/chemical-reactions/redox-reactions">redox reaction</a></strong></p> <blockquote> <p><mathjax>#"Fe"_ 2"O"_ (3(s)) + 3"CO"_ ((g)) -> 2"Fe"_ ((s)) + 3"CO"_(2(g))#</mathjax></p> </blockquote> <p>According to the chemical equation, <mathjax>#3#</mathjax> <strong>moles</strong> of carbon monoxide, <mathjax>#"CO"#</mathjax>, will react with <mathjax>#1#</mathjax> <strong>mole</strong> of ferric oxide, <mathjax>#"Fe"_2"O"_3#</mathjax>, and produce <mathjax>#3#</mathjax> <strong>moles</strong> of carbon dioxide, <mathjax>#"CO"_2#</mathjax>. </p> <p>Now, you are given <em>grams</em> of carbon monoxide and asked for <em>grams</em> of carbon dioxide. This means that you'll have to convert the aforementioned <strong><a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a></strong> that exists between carbon monoxide and carbon dioxide to a <em>gram ratio</em>. </p> <p>Since no mention of the mass of ferric oxide was made, you can assume that this reactant is <strong>in excess</strong>.</p> <p>So, to convert between <em>moles</em> and <em>grams</em>, use the <strong>molar mass</strong> of the two <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a>. </p> <blockquote> <p><mathjax>#"For CO: " M_M = "28.01 g mol"^(-1)#</mathjax></p> <p><mathjax>#"For CO"_2: color(white)(a)M_M = "44.01 g mol"^(-1)#</mathjax></p> </blockquote> <p>If <strong>one mole</strong> of carbon monoxide has a mass of <mathjax>#"28.01 g"#</mathjax> and <strong>one mole</strong> of carbon dioxide has a mass of <mathjax>#"44.01 g"#</mathjax>, it follows that the reaction produces <mathjax>#"44.01 g"#</mathjax> of carbon dioxide <strong>for every</strong> <mathjax>#"28.01 g"#</mathjax> of carbon monoxide. </p> <p>This is the case because of the <mathjax>#3:3#</mathjax> mole ratio that exists between the two compounds. </p> <p>So, your <mathjax>#"83.7 g"#</mathjax> of carbon monoxide will produce </p> <blockquote> <p><mathjax>#83.7 color(red)(cancel(color(black)("g CO"))) * "44.01 g CO"_2/(28.01 color(red)(cancel(color(black)("g CO")))) = color(green)(\|bar(ul(color(white)(a/a)"132 g CO"_2color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/258744" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What is stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ab82402bf342f48d93ac6"> Question #93ac6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-we-study-stoichiometry"> Why do we study stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-naoh-is-produced-from-1-20-x-102-grams-of-na2o-na2o-h2o-2-naoh"> How many grams of NaOH is produced from #1.20 x 10^2# grams of #Na_2O#? #Na_2O + H_2O -> 2NaOH# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-na2o-are-required-to-produce-1-60-x-102-grams-of-naoh-na2o-h2o"> How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? 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1,722	acd4983a-6ddd-11ea-b0c2-ccda262736ce	https://socratic.org/questions/assuming-gasoline-is-100-isooctane-with-a-density-of-0-692-g-ml-what-mass-of-car	1.39 × 10^11 kg	start physical_unit 14 15 mass kg qc_end physical_unit 1 1 9 10 density qc_end physical_unit 1 1 22 25 volume qc_end end	[{"type":"physical unit","value":"Mass [OF] carbon dioxide [IN] kg"}]	[{"type":"physical unit","value":"1.39 × 10^11 kg"}]	[{"type":"physical unit","value":"Percent [OF] isooctane in gasoline [=] \\pu{100%}"},{"type":"physical unit","value":"Density [OF] gasoline [=] \\pu{0.692 g/mL}"},{"type":"physical unit","value":"Volume [OF] gasoline [=] \\pu{1.2 × 10^10 gal}"}]	<h1 class="questionTitle" itemprop="name">Assuming gasoline is 100% isooctane, with a density of 0.692 g/mL, what mass of carbon dioxide is produced by the combustion of 1.2 x 1010 gal of gasoline?</h1>	null	1.39 × 10^11 kg	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#C_8H_18(l) + O_2(l) + (25/2)O_2(g) rarr 8CO_2(g) + 9H_2O(g)#</mathjax></p> <p>For each equiv of octane consumed, clearly 8 equiv carbon dioxide are produced. </p> <p>So how many moles of octane?</p> <p><mathjax>#(1.2xx10^(10)cancel(gallons)xx3.758cancel(L)/(cancel(gallon))xx10^3cancel(mL)cancel(L^-1)xx0.692cancel(g)cancel(mL^(-1)))/(114.23cancel(g)mol^-1) = (??mol)#</mathjax>.</p> <p>So this is how many moles of octane? And clearly, from the stoichiometrically balanced equation, 8 mol carbon dioxide result from the combustion of 1 mole of octane. You are still not done in that you to multiply this number in moles by the molecular mass of carbon dioxide, <mathjax>#44.0gmol^-1#</mathjax>.</p> <p>I make no guarantees of my formatting or of my arithmetic. This is the problem with using ridiculous units such as pounds or ounces or furlongs or gallons. I don't even know whether you are using a US gallon or an Imperial gallon, <mathjax>#4.8L#</mathjax>; I have assumed the former.</p> <p>PS I have to go to the bank this afternoon to get some readies (cash) for Xmas. Do you think I will get served if instead of asking for £100-00, I ask for 100 <a href="http://resources.woodlands-junior.kent.sch.uk/customs/questions/moneyold.htm" rel="nofollow">guineas</a>?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>I use a US gallon, <mathjax>#3.758L#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#C_8H_18(l) + O_2(l) + (25/2)O_2(g) rarr 8CO_2(g) + 9H_2O(g)#</mathjax></p> <p>For each equiv of octane consumed, clearly 8 equiv carbon dioxide are produced. </p> <p>So how many moles of octane?</p> <p><mathjax>#(1.2xx10^(10)cancel(gallons)xx3.758cancel(L)/(cancel(gallon))xx10^3cancel(mL)cancel(L^-1)xx0.692cancel(g)cancel(mL^(-1)))/(114.23cancel(g)mol^-1) = (??mol)#</mathjax>.</p> <p>So this is how many moles of octane? And clearly, from the stoichiometrically balanced equation, 8 mol carbon dioxide result from the combustion of 1 mole of octane. You are still not done in that you to multiply this number in moles by the molecular mass of carbon dioxide, <mathjax>#44.0gmol^-1#</mathjax>.</p> <p>I make no guarantees of my formatting or of my arithmetic. This is the problem with using ridiculous units such as pounds or ounces or furlongs or gallons. I don't even know whether you are using a US gallon or an Imperial gallon, <mathjax>#4.8*L#</mathjax>; I have assumed the former.</p> <p>PS I have to go to the bank this afternoon to get some readies (cash) for Xmas. Do you think I will get served if instead of asking for £100-00, I ask for 100 <a href="http://resources.woodlands-junior.kent.sch.uk/customs/questions/moneyold.htm" rel="nofollow">guineas</a>?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Assuming gasoline is 100% isooctane, with a density of 0.692 g/mL, what mass of carbon dioxide is produced by the combustion of 1.2 x 1010 gal of gasoline?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="199702" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-14T13:04:48" itemprop="dateCreated"> Dec 14, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>I use a US gallon, <mathjax>#3.758L#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#C_8H_18(l) + O_2(l) + (25/2)O_2(g) rarr 8CO_2(g) + 9H_2O(g)#</mathjax></p> <p>For each equiv of octane consumed, clearly 8 equiv carbon dioxide are produced. </p> <p>So how many moles of octane?</p> <p><mathjax>#(1.2xx10^(10)cancel(gallons)xx3.758cancel(L)/(cancel(gallon))xx10^3cancel(mL)cancel(L^-1)xx0.692cancel(g)cancel(mL^(-1)))/(114.23cancel(g)mol^-1) = (??mol)#</mathjax>.</p> <p>So this is how many moles of octane? And clearly, from the stoichiometrically balanced equation, 8 mol carbon dioxide result from the combustion of 1 mole of octane. You are still not done in that you to multiply this number in moles by the molecular mass of carbon dioxide, <mathjax>#44.0gmol^-1#</mathjax>.</p> <p>I make no guarantees of my formatting or of my arithmetic. This is the problem with using ridiculous units such as pounds or ounces or furlongs or gallons. I don't even know whether you are using a US gallon or an Imperial gallon, <mathjax>#4.8*L#</mathjax>; I have assumed the former.</p> <p>PS I have to go to the bank this afternoon to get some readies (cash) for Xmas. Do you think I will get served if instead of asking for £100-00, I ask for 100 <a href="http://resources.woodlands-junior.kent.sch.uk/customs/questions/moneyold.htm" rel="nofollow">guineas</a>?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/199702" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What is stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ab82402bf342f48d93ac6"> Question #93ac6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-we-study-stoichiometry"> Why do we study stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-naoh-is-produced-from-1-20-x-102-grams-of-na2o-na2o-h2o-2-naoh"> How many grams of NaOH is produced from #1.20 x 10^2# grams of #Na_2O#? #Na_2O + H_2O -> 2NaOH# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-na2o-are-required-to-produce-1-60-x-102-grams-of-naoh-na2o-h2o"> How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? Na2O + H2O ---> 2 NaOH </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-mass-of-iron-is-needed-to-react-with-16-0-grams-of-sulfur-8-fe-s8-8-fes"> What mass of iron is needed to react with 16.0 grams of sulfur? 8 Fe + S8 ---> 8 FeS </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/according-to-8-fe-s8-8-fes-how-many-grams-of-fes-are-produced"> According to 8 Fe + S8 ---> 8 FeS How many grams of FeS are produced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/12-00-moles-of-naclo3-will-produce-how-many-grams-of-o2-2-naclo3-2-nacl-3-o2"> 12.00 moles of NaClO3 will produce how many grams of O2? 2 NaClO3 ---> 2 NaCl + 3 O2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-nacl-are-produced-when-80-0-grams-of-o2-are-produced-2-naclo3-"> How many grams of NaCl are produced when 80.0 grams of O2 are produced? 2 NaClO3 ---> 2 NaCl + 3 O2 </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/stoichiometry"> See all questions in Stoichiometry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 10985 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Assuming gasoline is 100% isooctane, with a density of 0.692 g/mL, what mass of carbon dioxide is produced by the combustion of 1.2 x 1010 gal of gasoline?	null
1,723	a94b47b0-6ddd-11ea-9588-ccda262736ce	https://socratic.org/questions/what-is-the-empirical-formula-of-a-substance-that-is-53-5-c-15-5-h-and-31-19-n-b	C2H7N	start chemical_formula qc_end end	[{"type":"other","value":"Chemical Formula [OF] the substance [IN] empirical"}]	[{"type":"chemical equation","value":"C2H7N"}]	[{"type":"physical unit","value":"Percentage by weight [OF] C in the substance [=] \\pu{53.5%}"},{"type":"physical unit","value":"Percentage by weight [OF] H in the substance [=] \\pu{15.5%}"},{"type":"physical unit","value":"Percentage by weight [OF] N in the substance [=] \\pu{31.19%}"}]	<h1 class="questionTitle" itemprop="name">What is the empirical formula of a substance that is 53.5% C, 15.5% H, and 31.19% N by weight? </h1>	null	C2H7N	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>As always with these problems, we assume that there are <mathjax>#100#</mathjax> <mathjax>#g#</mathjax> of substance, and calculate the elemental composition (we divide thru by the atomic masses of each component):</p> <p><mathjax>#%C#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(53.5g)/(12.011gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#4.45#</mathjax> <mathjax>#mol#</mathjax> <mathjax>#C#</mathjax>.</p> <p><mathjax>#%H#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(15.5g)/(1.00794gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#15.38#</mathjax> <mathjax>#mol#</mathjax> <mathjax>#H#</mathjax>.</p> <p><mathjax>#%N#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(31.19g)/(14.01g*mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#2.23#</mathjax> <mathjax>#mol#</mathjax> <mathjax>#N#</mathjax>.</p> <p>We divide thru by the smallest quotient, that of <mathjax>#N#</mathjax> to give an EMPIRICAL formula of <mathjax>#C_2H_7N#</mathjax> (i.e. we divide each molar quantity by <mathjax>#2.23#</mathjax>!). Without details of molecular weight, this is as far as we can go. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_2H_7N#</mathjax> is the simplest whole number ratio defining constituent atoms in a species, and is thus the empirical formula. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>As always with these problems, we assume that there are <mathjax>#100#</mathjax> <mathjax>#g#</mathjax> of substance, and calculate the elemental composition (we divide thru by the atomic masses of each component):</p> <p><mathjax>#%C#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(53.5g)/(12.011gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#4.45#</mathjax> <mathjax>#mol#</mathjax> <mathjax>#C#</mathjax>.</p> <p><mathjax>#%H#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(15.5g)/(1.00794gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#15.38#</mathjax> <mathjax>#mol#</mathjax> <mathjax>#H#</mathjax>.</p> <p><mathjax>#%N#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(31.19g)/(14.01g*mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#2.23#</mathjax> <mathjax>#mol#</mathjax> <mathjax>#N#</mathjax>.</p> <p>We divide thru by the smallest quotient, that of <mathjax>#N#</mathjax> to give an EMPIRICAL formula of <mathjax>#C_2H_7N#</mathjax> (i.e. we divide each molar quantity by <mathjax>#2.23#</mathjax>!). Without details of molecular weight, this is as far as we can go. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the empirical formula of a substance that is 53.5% C, 15.5% H, and 31.19% N by weight? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="230937" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-02-25T15:39:51" itemprop="dateCreated"> Feb 25, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_2H_7N#</mathjax> is the simplest whole number ratio defining constituent atoms in a species, and is thus the empirical formula. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>As always with these problems, we assume that there are <mathjax>#100#</mathjax> <mathjax>#g#</mathjax> of substance, and calculate the elemental composition (we divide thru by the atomic masses of each component):</p> <p><mathjax>#%C#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(53.5g)/(12.011gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#4.45#</mathjax> <mathjax>#mol#</mathjax> <mathjax>#C#</mathjax>.</p> <p><mathjax>#%H#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(15.5g)/(1.00794gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#15.38#</mathjax> <mathjax>#mol#</mathjax> <mathjax>#H#</mathjax>.</p> <p><mathjax>#%N#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(31.19g)/(14.01g*mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#2.23#</mathjax> <mathjax>#mol#</mathjax> <mathjax>#N#</mathjax>.</p> <p>We divide thru by the smallest quotient, that of <mathjax>#N#</mathjax> to give an EMPIRICAL formula of <mathjax>#C_2H_7N#</mathjax> (i.e. we divide each molar quantity by <mathjax>#2.23#</mathjax>!). Without details of molecular weight, this is as far as we can go. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/230937" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molecular-formula-of-a-compound"> How do you find molecular formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-diamond"> What is the chemical formula of a diamond? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-carbohydrate"> What is the chemical formula of a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-valproic-acid"> What is the empirical formula for valproic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-of-magnesium-oxide"> What is the empirical formula of magnesium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-empirical-formula-not-double-that-of-the-monosaccharides"> Why is the empirical formula not double that of the monosaccharides? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5331180502bf342f40b5c3b5"> Question #5c3b5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-molecular-formula-represents-a-carbohydrate"> What molecular formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-of-vinegar"> What is the molecular formula of vinegar? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/empirical-and-molecular-formulas"> See all questions in Empirical and Molecular Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 23812 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the empirical formula of a substance that is 53.5% C, 15.5% H, and 31.19% N by weight?	null
1,724	a8ebbed2-6ddd-11ea-b667-ccda262736ce	https://socratic.org/questions/the-average-nicotine-c10h14n2-molar-mass-162-3-g-mol-content-of-a-camel-cigarett	2.38 × 10^(-4) moles	start physical_unit 2 2 mole mol qc_end physical_unit 3 3 6 7 molar_mass qc_end physical_unit 2 2 14 15 mass qc_end physical_unit 24 24 23 23 number qc_end end	[{"type":"physical unit","value":"Mole [OF] nicotine [IN] moles"}]	[{"type":"physical unit","value":"2.38 × 10^(-4) moles"}]	[{"type":"physical unit","value":"Molar mass [OF] C10H14N2 [=] \\pu{162.3 g/mol}"},{"type":"physical unit","value":"Average content [OF] nicotine [=] \\pu{1.93 mg}"},{"type":"physical unit","value":"Number [OF] cigarettes [=] \\pu{20}"}]	<h1 class="questionTitle" itemprop="name">The average nicotine (C10H14N2, molar mass 162.3 g/mol) content of a Camel cigarette is 1.93 mg. Suppose an individual smokes one pack of 20 cigarettes a day. How many moles of nicotine are smoked in a day?</h1>	null	2.38 × 10^(-4) moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First, we need to solve for how many milligrams of nicotine is in one pack of cigarettes. All we need to do is times the average amount of nicotine in one cigarette by how many cigarettes are in a pack.</p> <p><mathjax>#1.93mg * 20 = 38.6 mg#</mathjax> </p> <p>Now we need to convert milligrams into grams. There are 1000 mg per 1 g of any substance. Using this ratio we can solve for grams.</p> <p><mathjax>#38.6mg((1 g)/(1000mg))=0.0386 g#</mathjax></p> <p>Next, we use the molar mass which has been given to us in the original problem. The molar mass tells us how many grams are in one mole of that particular substance. Using this we can convert our grams of nicotine into moles of nicotine.</p> <p><mathjax>#0.0386g((1mol)/(162.3g))=2.38*10^-4mol#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2.3810^-4#</mathjax> moles of nicotine.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First, we need to solve for how many milligrams of nicotine is in one pack of cigarettes. All we need to do is times the average amount of nicotine in one cigarette by how many cigarettes are in a pack.</p> <p><mathjax>#1.93mg 20 = 38.6 mg#</mathjax> </p> <p>Now we need to convert milligrams into grams. There are 1000 mg per 1 g of any substance. Using this ratio we can solve for grams.</p> <p><mathjax>#38.6mg((1 g)/(1000mg))=0.0386 g#</mathjax></p> <p>Next, we use the molar mass which has been given to us in the original problem. The molar mass tells us how many grams are in one mole of that particular substance. Using this we can convert our grams of nicotine into moles of nicotine.</p> <p><mathjax>#0.0386g((1mol)/(162.3g))=2.38*10^-4mol#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">The average nicotine (C10H14N2, molar mass 162.3 g/mol) content of a Camel cigarette is 1.93 mg. Suppose an individual smokes one pack of 20 cigarettes a day. How many moles of nicotine are smoked in a day?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="618173" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/wolfeheart"><img alt="" class="" src="https://profilepictures.socratic.org/48J0XLK1To2NunsG33ct_11.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/wolfeheart"> WolfeHeart </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-05-22T14:28:24" itemprop="dateCreated"> May 22, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2.3810^-4#</mathjax> moles of nicotine.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First, we need to solve for how many milligrams of nicotine is in one pack of cigarettes. All we need to do is times the average amount of nicotine in one cigarette by how many cigarettes are in a pack.</p> <p><mathjax>#1.93mg 20 = 38.6 mg#</mathjax> </p> <p>Now we need to convert milligrams into grams. There are 1000 mg per 1 g of any substance. Using this ratio we can solve for grams.</p> <p><mathjax>#38.6mg((1 g)/(1000mg))=0.0386 g#</mathjax></p> <p>Next, we use the molar mass which has been given to us in the original problem. The molar mass tells us how many grams are in one mole of that particular substance. Using this we can convert our grams of nicotine into moles of nicotine.</p> <p><mathjax>#0.0386g((1mol)/(162.3g))=2.38*10^-4mol#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/618173" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 12869 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	The average nicotine (C10H14N2, molar mass 162.3 g/mol) content of a Camel cigarette is 1.93 mg. Suppose an individual smokes one pack of 20 cigarettes a day. How many moles of nicotine are smoked in a day?	null
1,725	abe679ad-6ddd-11ea-882f-ccda262736ce	https://socratic.org/questions/the-empirical-formula-of-butadiene-is-c-2h-3-an-experimental-determination-of-th	C4H6	start chemical_formula qc_end physical_unit 4 4 20 21 molar_mass qc_end c_other OTHER qc_end end	[{"type":"other","value":"Chemical Formula [OF] butadiene [IN] molecular"}]	[{"type":"chemical equation","value":"C4H6"}]	[{"type":"physical unit","value":"Molar mass [OF] butadiene [=] \\pu{54 g/mol}"},{"type":"other","value":"The empirical formula of butadiene is C2H3."}]	<h1 class="questionTitle" itemprop="name">The empirical formula of butadiene is #C_2H_3#. An experimental determination of the molar mass of butadiene yields the value of 54 g/mol. What is the molecular formula of butadiene? </h1>	null	C4H6	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The molecular formula is always a mulitple of the empirical formula; of course the multiple may be one if the molecular formula is the same as the empirical formula. </p> <p>Given that <mathjax>#"MF"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#("EF")_n#</mathjax>, we simply solve for <mathjax>#n#</mathjax> using the sum of the constituent atomic masses:</p> <p><mathjax>#nxx(2xx12.011 + 3xx1.00794)gmol^-1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#54#</mathjax> <mathjax>#g*mol^-1#</mathjax></p> <p>Clearly <mathjax>#n#</mathjax> <mathjax>#=#</mathjax> <mathjax>#2#</mathjax>.</p> <p>Molecular formula <mathjax>#=#</mathjax> <mathjax>#2xxC_2H_3#</mathjax> <mathjax>#=#</mathjax> <mathjax>#C_29H_37??#</mathjax> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_4H_6#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The molecular formula is always a mulitple of the empirical formula; of course the multiple may be one if the molecular formula is the same as the empirical formula. </p> <p>Given that <mathjax>#"MF"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#("EF")_n#</mathjax>, we simply solve for <mathjax>#n#</mathjax> using the sum of the constituent atomic masses:</p> <p><mathjax>#nxx(2xx12.011 + 3xx1.00794)gmol^-1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#54#</mathjax> <mathjax>#g*mol^-1#</mathjax></p> <p>Clearly <mathjax>#n#</mathjax> <mathjax>#=#</mathjax> <mathjax>#2#</mathjax>.</p> <p>Molecular formula <mathjax>#=#</mathjax> <mathjax>#2xxC_2H_3#</mathjax> <mathjax>#=#</mathjax> <mathjax>#C_29H_37??#</mathjax> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">The empirical formula of butadiene is #C_2H_3#. An experimental determination of the molar mass of butadiene yields the value of 54 g/mol. What is the molecular formula of butadiene? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="212637" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-15T07:37:28" itemprop="dateCreated"> Jan 15, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_4H_6#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The molecular formula is always a mulitple of the empirical formula; of course the multiple may be one if the molecular formula is the same as the empirical formula. </p> <p>Given that <mathjax>#"MF"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#("EF")_n#</mathjax>, we simply solve for <mathjax>#n#</mathjax> using the sum of the constituent atomic masses:</p> <p><mathjax>#nxx(2xx12.011 + 3xx1.00794)gmol^-1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#54#</mathjax> <mathjax>#g*mol^-1#</mathjax></p> <p>Clearly <mathjax>#n#</mathjax> <mathjax>#=#</mathjax> <mathjax>#2#</mathjax>.</p> <p>Molecular formula <mathjax>#=#</mathjax> <mathjax>#2xxC_2H_3#</mathjax> <mathjax>#=#</mathjax> <mathjax>#C_29H_37??#</mathjax> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/212637" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? 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An experimental determination of the molar mass of butadiene yields the value of 54 g/mol. What is the molecular formula of butadiene?	null
1,726	a8eb97ac-6ddd-11ea-85e3-ccda262736ce	https://socratic.org/questions/how-many-grams-of-a-17-8-sugar-solution-contain-68-0-g-of-sugar	382 grams	start physical_unit 6 7 mass g qc_end physical_unit 6 6 9 10 mass qc_end end	[{"type":"physical unit","value":"Mass [OF] sugar solution [IN] grams"}]	[{"type":"physical unit","value":"382 grams"}]	[{"type":"physical unit","value":"Mass [OF] sugar [=] \\pu{68.0 g}"},{"type":"physical unit","value":"Percent [OF] sugar in the sugar solution [=] \\pu{17.8%}"}]	<h1 class="questionTitle" itemprop="name">How many grams of a 17.8% sugar solution contain 68.0 g of sugar? </h1>	null	382 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>A 17.8 % sugar solution means that there are 17.8 g of sugar in 100 g of solution.</p> <p>∴ <mathjax>#"Mass of solution" = 68.0 color(red)(cancel(color(black)("g sugar"))) × "100 g solution"/(17.8 color(red)(cancel(color(black)("g sugar")))) = "382 g solution"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>You will need 382 g of sugar solution.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>A 17.8 % sugar solution means that there are 17.8 g of sugar in 100 g of solution.</p> <p>∴ <mathjax>#"Mass of solution" = 68.0 color(red)(cancel(color(black)("g sugar"))) × "100 g solution"/(17.8 color(red)(cancel(color(black)("g sugar")))) = "382 g solution"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many grams of a 17.8% sugar solution contain 68.0 g of sugar? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/solutions" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="285548" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-07T02:12:34" itemprop="dateCreated"> Jul 7, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>You will need 382 g of sugar solution.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>A 17.8 % sugar solution means that there are 17.8 g of sugar in 100 g of solution.</p> <p>∴ <mathjax>#"Mass of solution" = 68.0 color(red)(cancel(color(black)("g sugar"))) × "100 g solution"/(17.8 color(red)(cancel(color(black)("g sugar")))) = "382 g solution"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/285548" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-solution-solute-and-solvent-related"> How are solution, solute, and solvent related? 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1,727	a8d4ea99-6ddd-11ea-88e5-ccda262736ce	https://socratic.org/questions/what-is-the-solubility-of-hydrogen-in-units-of-grams-per-liter-in-water-at-25-c-	4.50 × 10^(-4) grams per liter	start physical_unit 5 5 solubility g/l qc_end physical_unit 5 5 15 16 temperature qc_end physical_unit 19 20 29 30 partial_pressure qc_end end	[{"type":"physical unit","value":"Solubility [OF] hydrogen [IN] grams per liter"}]	[{"type":"physical unit","value":"4.50 × 10^(-4) grams per liter"}]	[{"type":"physical unit","value":"Temperature [OF] hydrogen [=] \\pu{25 ℃}"},{"type":"physical unit","value":"Partial pressure [OF] H2 gas [=] \\pu{0.286 atm}"}]	<h1 class="questionTitle" itemprop="name">What is the solubility of hydrogen (in units of grams per liter) in water at 25 °C, when the #H_2# gas over the solution has a partial pressure of .286 atm? </h1>	null	4.50 × 10^(-4) grams per liter	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that you need to use the equation for <strong>Henry's Law</strong> to determine the <em>molar solubility</em> of hydrogen gas at that temperature and <a href="http://socratic.org/chemistry/the-behavior-of-gases/partial-pressure">partial pressure</a>, then use its <em>molar mass</em> to convert this from <em>moles per liter</em> to <em>grams per liter</em>.</p> <p>So, according to <strong>Henry's Law</strong>, the solubility of a gas in a liquid is <em>proportional</em> to its partial pressure above the liquid. Mathematically, this is written as </p> <blockquote> <p><mathjax>#color(blue)(k_H = c_"aq"/P)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#k_H#</mathjax> - <em>Henry's constant</em>, specific to each gas and dependent on the temperature<br/> <mathjax>#c_"aq"#</mathjax> - the molar concentration of the dissolved gas<br/> <mathjax>#P#</mathjax> - the partial pressure of the gas above the liquid</p> <p>Now, the value of Henry's constant for hydrogen gas at <mathjax>#25^@"C"#</mathjax> is equal to </p> <blockquote> <p><mathjax>#k_H = 7.8 * 10^(-4)"mol"/("L" * "atm")#</mathjax> </p> </blockquote> <p><img alt="https://chemengineering.wikispaces.com/Henry's+Law" src="https://useruploads.socratic.org/muerkaKLS6enqIHikLxC_Henry%27s_Law.png%22%3B+size%3D%2219126"/> </p> <p>So, plug in your values and calculate the molar solubility of hydrogen gas at that temperature</p> <blockquote> <p><mathjax>#k_H = c_"aq"/P implies c_"aq" = k_H xx P#</mathjax></p> <p><mathjax>#c_"aq" = 7.8 * 10^(-4)"mol"/("L" * color(red)(cancel(color(black)("atm")))) * 0.286 color(red)(cancel(color(black)("atm")))#</mathjax></p> <p><mathjax>#c_"aq" = 2.231 * 10^(-4)"mol"/"L"#</mathjax></p> </blockquote> <p>Hydrogen gas has a molar mass of <mathjax>#"2.0159 g/mol"#</mathjax>, which means that <strong>one mole</strong> of hydrogen gas will have a mass of <mathjax>#"2.0159 g"#</mathjax>. </p> <p>In your case, the solubility of hydrogen gas in <em>grams per liter</em> will be </p> <blockquote> <p><mathjax>#2.231 * 10^(-4) color(red)(cancel(color(black)("mol")))/"L" * "2.0159 g"/(1color(red)(cancel(color(black)("mole")))) = color(green)(4.50* 10^(-4) "g/L")#</mathjax></p> </blockquote> <p>The answer is rounded to three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the number of sig figs you have for the partial pressure of the gas. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#4.50 * 10^(-4)"g/L"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that you need to use the equation for <strong>Henry's Law</strong> to determine the <em>molar solubility</em> of hydrogen gas at that temperature and <a href="http://socratic.org/chemistry/the-behavior-of-gases/partial-pressure">partial pressure</a>, then use its <em>molar mass</em> to convert this from <em>moles per liter</em> to <em>grams per liter</em>.</p> <p>So, according to <strong>Henry's Law</strong>, the solubility of a gas in a liquid is <em>proportional</em> to its partial pressure above the liquid. Mathematically, this is written as </p> <blockquote> <p><mathjax>#color(blue)(k_H = c_"aq"/P)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#k_H#</mathjax> - <em>Henry's constant</em>, specific to each gas and dependent on the temperature<br/> <mathjax>#c_"aq"#</mathjax> - the molar concentration of the dissolved gas<br/> <mathjax>#P#</mathjax> - the partial pressure of the gas above the liquid</p> <p>Now, the value of Henry's constant for hydrogen gas at <mathjax>#25^@"C"#</mathjax> is equal to </p> <blockquote> <p><mathjax>#k_H = 7.8 * 10^(-4)"mol"/("L" * "atm")#</mathjax> </p> </blockquote> <p><img alt="https://chemengineering.wikispaces.com/Henry's+Law" src="https://useruploads.socratic.org/muerkaKLS6enqIHikLxC_Henry%27s_Law.png%22%3B+size%3D%2219126"/> </p> <p>So, plug in your values and calculate the molar solubility of hydrogen gas at that temperature</p> <blockquote> <p><mathjax>#k_H = c_"aq"/P implies c_"aq" = k_H xx P#</mathjax></p> <p><mathjax>#c_"aq" = 7.8 * 10^(-4)"mol"/("L" * color(red)(cancel(color(black)("atm")))) * 0.286 color(red)(cancel(color(black)("atm")))#</mathjax></p> <p><mathjax>#c_"aq" = 2.231 * 10^(-4)"mol"/"L"#</mathjax></p> </blockquote> <p>Hydrogen gas has a molar mass of <mathjax>#"2.0159 g/mol"#</mathjax>, which means that <strong>one mole</strong> of hydrogen gas will have a mass of <mathjax>#"2.0159 g"#</mathjax>. </p> <p>In your case, the solubility of hydrogen gas in <em>grams per liter</em> will be </p> <blockquote> <p><mathjax>#2.231 * 10^(-4) color(red)(cancel(color(black)("mol")))/"L" * "2.0159 g"/(1color(red)(cancel(color(black)("mole")))) = color(green)(4.50* 10^(-4) "g/L")#</mathjax></p> </blockquote> <p>The answer is rounded to three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the number of sig figs you have for the partial pressure of the gas. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the solubility of hydrogen (in units of grams per liter) in water at 25 °C, when the #H_2# gas over the solution has a partial pressure of .286 atm? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-equilibrium" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Equilibrium</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-equilibrium/solubility-equilbria" itemprop="url"> <span class="breadcrumb" itemprop="title">Solubility Equilbria</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="200821" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-18T00:11:58" itemprop="dateCreated"> Dec 18, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#4.50 * 10^(-4)"g/L"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that you need to use the equation for <strong>Henry's Law</strong> to determine the <em>molar solubility</em> of hydrogen gas at that temperature and <a href="http://socratic.org/chemistry/the-behavior-of-gases/partial-pressure">partial pressure</a>, then use its <em>molar mass</em> to convert this from <em>moles per liter</em> to <em>grams per liter</em>.</p> <p>So, according to <strong>Henry's Law</strong>, the solubility of a gas in a liquid is <em>proportional</em> to its partial pressure above the liquid. Mathematically, this is written as </p> <blockquote> <p><mathjax>#color(blue)(k_H = c_"aq"/P)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#k_H#</mathjax> - <em>Henry's constant</em>, specific to each gas and dependent on the temperature<br/> <mathjax>#c_"aq"#</mathjax> - the molar concentration of the dissolved gas<br/> <mathjax>#P#</mathjax> - the partial pressure of the gas above the liquid</p> <p>Now, the value of Henry's constant for hydrogen gas at <mathjax>#25^@"C"#</mathjax> is equal to </p> <blockquote> <p><mathjax>#k_H = 7.8 * 10^(-4)"mol"/("L" * "atm")#</mathjax> </p> </blockquote> <p><img alt="https://chemengineering.wikispaces.com/Henry's+Law" src="https://useruploads.socratic.org/muerkaKLS6enqIHikLxC_Henry%27s_Law.png%22%3B+size%3D%2219126"/> </p> <p>So, plug in your values and calculate the molar solubility of hydrogen gas at that temperature</p> <blockquote> <p><mathjax>#k_H = c_"aq"/P implies c_"aq" = k_H xx P#</mathjax></p> <p><mathjax>#c_"aq" = 7.8 * 10^(-4)"mol"/("L" * color(red)(cancel(color(black)("atm")))) * 0.286 color(red)(cancel(color(black)("atm")))#</mathjax></p> <p><mathjax>#c_"aq" = 2.231 * 10^(-4)"mol"/"L"#</mathjax></p> </blockquote> <p>Hydrogen gas has a molar mass of <mathjax>#"2.0159 g/mol"#</mathjax>, which means that <strong>one mole</strong> of hydrogen gas will have a mass of <mathjax>#"2.0159 g"#</mathjax>. </p> <p>In your case, the solubility of hydrogen gas in <em>grams per liter</em> will be </p> <blockquote> <p><mathjax>#2.231 * 10^(-4) color(red)(cancel(color(black)("mol")))/"L" * "2.0159 g"/(1color(red)(cancel(color(black)("mole")))) = color(green)(4.50* 10^(-4) "g/L")#</mathjax></p> </blockquote> <p>The answer is rounded to three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the number of sig figs you have for the partial pressure of the gas. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/200821" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-solubility-affect-equilibrium"> How does solubility affect equilibrium? 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1,728	ab6dc952-6ddd-11ea-a952-ccda262736ce	https://socratic.org/questions/a-sample-of-no-2-occupies-a-volume-of-2-3-l-at-740-mm-hg-what-volume-would-resul	2.24 L	start physical_unit 1 3 volume l qc_end physical_unit 1 3 8 9 volume qc_end physical_unit 1 3 11 12 pressure qc_end physical_unit 1 3 23 24 pressure qc_end end	[{"type":"physical unit","value":"Volume2 [OF] NO2 sample [IN] L"}]	[{"type":"physical unit","value":"2.24 L"}]	[{"type":"physical unit","value":"Volume1 [OF] NO2 sample [=] \\pu{2.3 L}"},{"type":"physical unit","value":"Pressure1 [OF] NO2 sample [=] \\pu{740 mmHg}"},{"type":"physical unit","value":"Pressure2 [OF] NO2 sample [=] \\pu{760 mmHg}"}]	<h1 class="questionTitle" itemprop="name">A sample of #NO_2# occupies a volume of 2.3 L at 740 mm Hg. What volume would result if the pressure were increased to 760 mm Hg?</h1>	null	2.24 L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And given this proportionality, we don't have to pfaff about with units.</p> <p><mathjax>#V_2=(P_1V_1)/P_2=(740mmHgxx2.3L)/(760mm*Hg)#</mathjax></p> <p>The volume thus reduces slightly.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>From <a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's Law</a>, <mathjax>#P_1V_1=P_2V_2#</mathjax>, if <mathjax>#"temperature"#</mathjax> and <mathjax>#"amount"#</mathjax> of gas are constant.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And given this proportionality, we don't have to pfaff about with units.</p> <p><mathjax>#V_2=(P_1V_1)/P_2=(740mmHgxx2.3L)/(760mm*Hg)#</mathjax></p> <p>The volume thus reduces slightly.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A sample of #NO_2# occupies a volume of 2.3 L at 740 mm Hg. What volume would result if the pressure were increased to 760 mm Hg?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/gas-laws" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Laws</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="339296" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-11-20T16:56:08" itemprop="dateCreated"> Nov 20, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>From <a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's Law</a>, <mathjax>#P_1V_1=P_2V_2#</mathjax>, if <mathjax>#"temperature"#</mathjax> and <mathjax>#"amount"#</mathjax> of gas are constant.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And given this proportionality, we don't have to pfaff about with units.</p> <p><mathjax>#V_2=(P_1V_1)/P_2=(740mmHgxx2.3L)/(760mm*Hg)#</mathjax></p> <p>The volume thus reduces slightly.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/339296" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-boyles-law-relate-to-breathing"> How does Boyle's law relate to breathing? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/in-avogadro-s-law-what-would-happen-to-v-if-n-is-increased-decreased-and-what-wo"> In Avogadro's Law what would happen to V if N is increased/decreased? 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If the gas is compressed to 23.52 L and the... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-the-r-stand-for-in-the-ideal-gas-law-pv-nrt"> What does the R stand for in the ideal gas law (PV=nRT)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-mass-of-a-gas-that-occupies-48-9-liters-has-a-pressure-of-724-torr-a"> What is the mass of a gas that occupies 48.9 liters, has a pressure of 724 torr, a temperature... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-a-sample-of-neon-gas-occupies-a-volume-of-2-8l-at-1-8-atm-what-will-its-volum"> If a sample of neon gas occupies a volume of 2.8L at 1.8 atm. what will its volume be at 1.2 atm? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/gas-laws"> See all questions in Gas Laws </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1364 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A sample of #NO_2# occupies a volume of 2.3 L at 740 mm Hg. What volume would result if the pressure were increased to 760 mm Hg?	null
1,729	a8c050f6-6ddd-11ea-a049-ccda262736ce	https://socratic.org/questions/how-do-you-write-the-balanced-equation-for-this-cell-reaction-2cd-s-2aq-aq-cd-2-	Cd(s) + 2 Ag+ -> Cd^2+ + 2 Ag(s)	start chemical_equation qc_end chemical_equation 11 20 qc_end end	[{"type":"other","value":"Chemical Equation [OF] this cell reaction"}]	[{"type":"chemical equation","value":"Cd(s) + 2 Ag+ -> Cd^2+ + 2 Ag(s)"}]	[{"type":"chemical equation","value":"2 Cd(s) + 2 Ag+(aq) -> Cd^2+(aq) + 2 Ag(s)"}]	<h1 class="questionTitle" itemprop="name">How do you write the balanced equation for this cell reaction? #2Cd(s) + 2Aq^(+)(aq) -> Cd^(2+)(aq) + 2Ag(s)#</h1>	null	Cd(s) + 2 Ag+ -> Cd^2+ + 2 Ag(s)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Both mass and charge are balanced, and thus this is reasonable. </p> <p>How to predict <mathjax>#E^@#</mathjax> for this reaction?</p> <p><mathjax>#Cd^(2+) +2e^(-)rarrCd#</mathjax>; <mathjax>#E^@=-0.40V#</mathjax></p> <p><mathjax>#Ag^(+) +e^(-)rarrAg#</mathjax>; <mathjax>#E^@=+0.80V#</mathjax></p> <p>The given cell should have <mathjax>#E_"cell"=1.20*V#</mathjax>. Do you agree?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Cd(s) + 2Ag^(+) rarr Cd^(2+) + 2Ag(s)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Both mass and charge are balanced, and thus this is reasonable. </p> <p>How to predict <mathjax>#E^@#</mathjax> for this reaction?</p> <p><mathjax>#Cd^(2+) +2e^(-)rarrCd#</mathjax>; <mathjax>#E^@=-0.40V#</mathjax></p> <p><mathjax>#Ag^(+) +e^(-)rarrAg#</mathjax>; <mathjax>#E^@=+0.80V#</mathjax></p> <p>The given cell should have <mathjax>#E_"cell"=1.20*V#</mathjax>. Do you agree?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you write the balanced equation for this cell reaction? #2Cd(s) + 2Aq^(+)(aq) -> Cd^(2+)(aq) + 2Ag(s)#</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#electrochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Electrochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/electrochemistry/galvanic-cells" itemprop="url"> <span class="breadcrumb" itemprop="title">Galvanic Cells</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="351686" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-12-14T16:48:18" itemprop="dateCreated"> Dec 14, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Cd(s) + 2Ag^(+) rarr Cd^(2+) + 2Ag(s)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Both mass and charge are balanced, and thus this is reasonable. </p> <p>How to predict <mathjax>#E^@#</mathjax> for this reaction?</p> <p><mathjax>#Cd^(2+) +2e^(-)rarrCd#</mathjax>; <mathjax>#E^@=-0.40V#</mathjax></p> <p><mathjax>#Ag^(+) +e^(-)rarrAg#</mathjax>; <mathjax>#E^@=+0.80V#</mathjax></p> <p>The given cell should have <mathjax>#E_"cell"=1.20*V#</mathjax>. Do you agree?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/351686" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-a-galvanic-cell-become-an-electrolytic-cell"> How can a galvanic cell become an electrolytic cell? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-electrons-flow-in-a-galvanic-cell"> How do electrons flow in a galvanic cell? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-galvanic-cell-potential"> How do you calculate galvanic cell potential? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-sketch-galvanic-cells"> How do you sketch galvanic cells? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-might-a-galvanic-cell-go-dead"> Why might a galvanic cell go dead? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5350796902bf343989038b3d"> Question #38b3d </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-galvanic-cell"> What is a galvanic cell? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-common-mistakes-students-make-with-galvanic-cells"> What are some common mistakes students make with galvanic cells? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-an-example-of-a-galvanic-cell-practice-problem"> What is an example of a galvanic cell practice problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-energy-conversion-takes-place-in-a-galvanic-cell"> What energy conversion takes place in a galvanic cell? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/electrochemistry/galvanic-cells"> See all questions in Galvanic Cells </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 6845 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How do you write the balanced equation for this cell reaction? #2Cd(s) + 2Aq^(+)(aq) -> Cd^(2+)(aq) + 2Ag(s)#	null
1,730	ab039dd3-6ddd-11ea-b0de-ccda262736ce	https://socratic.org/questions/what-is-the-formula-for-sulfer-hexafluoride	SF6	start chemical_formula qc_end substance 5 6 qc_end end	[{"type":"other","value":"Chemical Formula [OF] sulfer hexafluoride [IN] default"}]	[{"type":"chemical equation","value":"SF6"}]	[{"type":"substance name","value":"Sulfer hexafluoride"}]	<h1 class="questionTitle" itemprop="name">What is the formula for sulfer hexafluoride?</h1>	null	SF6	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is one of the most potent greenhouse gases known. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#SF_6#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is one of the most potent greenhouse gases known. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the formula for sulfer hexafluoride?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/determining-formula-and-molar-masses" itemprop="url"> <span class="breadcrumb" itemprop="title">Determining Formula</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="351179" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-12-13T16:14:53" itemprop="dateCreated"> Dec 13, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#SF_6#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is one of the most potent greenhouse gases known. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/351179" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-it-possible-to-find-a-molecular-formula-from-molar-mass"> Is it possible to find a molecular formula from molar mass? 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</a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/determining-formula-and-molar-masses"> See all questions in Determining Formula </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 933 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the formula for sulfer hexafluoride?	null
1,731	aa4b331a-6ddd-11ea-a692-ccda262736ce	https://socratic.org/questions/what-volume-of-12-m-hcl-solution-is-needed-to-prepare-5-liters-of-0-0250-m-solut	0.01 L	start physical_unit 5 6 volume l qc_end physical_unit 5 6 11 12 volume qc_end physical_unit 5 6 3 4 molarity qc_end physical_unit 5 6 14 15 molarity qc_end end	[{"type":"physical unit","value":"Volume1 [OF] HCl solution [IN] L"}]	[{"type":"physical unit","value":"0.01 L"}]	[{"type":"physical unit","value":"Volume2 [OF] HCl solution [=] \\pu{5 liters}"},{"type":"physical unit","value":"Molarity1 [OF] HCl solution [=] \\pu{12 M}"},{"type":"physical unit","value":"Molarity2 [OF] HCl solution [=] \\pu{0.0250 M}"}]	<h1 class="questionTitle" itemprop="name">What volume of 12 M #HCl# solution is needed to prepare 5 liters of 0.0250 M solution? </h1>	null	0.01 L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to get the answer, you have to use the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/dilution-calculations">dilution</a> equation:<br/> <img alt="study.com" src="https://useruploads.socratic.org/R5mNLfjoTwiMpNhEDK4G_stock-solution-dilution-equation.jpg"/> </p> <p><mathjax>#M_1#</mathjax> is the initial concentration<br/> <mathjax>#V_1#</mathjax> is the initial volume<br/> <mathjax>#M_2#</mathjax> is the final concentration<br/> <mathjax>#V_2#</mathjax> is the final volume</p> <p><strong><em>* TIP. </em></strong> * Whenever you are going from a highly concentrated substance to a less concentrated substance by increasing the volume of the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a> (dilution) you always use this equation. </p> <p>We know <mathjax>#M_1#</mathjax>,<mathjax>#M_2#</mathjax> , and <mathjax>#V_2#</mathjax> . All we have to do rearrange the equation to solve for the <mathjax>#V_1#</mathjax>:</p> <p><mathjax>#(M_2xxV_2)/M_1#</mathjax>= <mathjax>#V_1#</mathjax></p> <p><mathjax>#(0.0250 cancel"M" xx5L)/(12cancel"M") #</mathjax> = <mathjax>#0.0104L#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#0.0104 L#</mathjax> of 12 M HCl is needed.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to get the answer, you have to use the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/dilution-calculations">dilution</a> equation:<br/> <img alt="study.com" src="https://useruploads.socratic.org/R5mNLfjoTwiMpNhEDK4G_stock-solution-dilution-equation.jpg"/> </p> <p><mathjax>#M_1#</mathjax> is the initial concentration<br/> <mathjax>#V_1#</mathjax> is the initial volume<br/> <mathjax>#M_2#</mathjax> is the final concentration<br/> <mathjax>#V_2#</mathjax> is the final volume</p> <p><strong><em>* TIP. </em></strong> * Whenever you are going from a highly concentrated substance to a less concentrated substance by increasing the volume of the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a> (dilution) you always use this equation. </p> <p>We know <mathjax>#M_1#</mathjax>,<mathjax>#M_2#</mathjax> , and <mathjax>#V_2#</mathjax> . All we have to do rearrange the equation to solve for the <mathjax>#V_1#</mathjax>:</p> <p><mathjax>#(M_2xxV_2)/M_1#</mathjax>= <mathjax>#V_1#</mathjax></p> <p><mathjax>#(0.0250 cancel"M" xx5L)/(12cancel"M") #</mathjax> = <mathjax>#0.0104L#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What volume of 12 M #HCl# solution is needed to prepare 5 liters of 0.0250 M solution? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="286570" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/kayla-14"><img alt="" class="" src="https://profilepictures.socratic.org/OvMTWaamQPWcqLIkUNnG_793604964071127.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/kayla-14"> Kayla </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-10T00:51:18" itemprop="dateCreated"> Jul 10, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#0.0104 L#</mathjax> of 12 M HCl is needed.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to get the answer, you have to use the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/dilution-calculations">dilution</a> equation:<br/> <img alt="study.com" src="https://useruploads.socratic.org/R5mNLfjoTwiMpNhEDK4G_stock-solution-dilution-equation.jpg"/> </p> <p><mathjax>#M_1#</mathjax> is the initial concentration<br/> <mathjax>#V_1#</mathjax> is the initial volume<br/> <mathjax>#M_2#</mathjax> is the final concentration<br/> <mathjax>#V_2#</mathjax> is the final volume</p> <p><strong><em>* TIP. </em></strong> * Whenever you are going from a highly concentrated substance to a less concentrated substance by increasing the volume of the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a> (dilution) you always use this equation. </p> <p>We know <mathjax>#M_1#</mathjax>,<mathjax>#M_2#</mathjax> , and <mathjax>#V_2#</mathjax> . All we have to do rearrange the equation to solve for the <mathjax>#V_1#</mathjax>:</p> <p><mathjax>#(M_2xxV_2)/M_1#</mathjax>= <mathjax>#V_1#</mathjax></p> <p><mathjax>#(0.0250 cancel"M" xx5L)/(12cancel"M") #</mathjax> = <mathjax>#0.0104L#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/286570" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-morality-be-used-as-a-conversion-factor"> How can molarity be used as a conversion factor? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-high-can-molarity-be"> How high can molarity be? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-molarity-change-with-temperature"> How does molarity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molarity-of-a-solution"> How do you find molarity of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-10-naoh"> What is the molarity of 10 NaOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-3-hydrogen-peroxide"> What is the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 13989 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What volume of 12 M #HCl# solution is needed to prepare 5 liters of 0.0250 M solution?	null
1,732	ac3c656d-6ddd-11ea-b234-ccda262736ce	https://socratic.org/questions/58fd078f11ef6b50edaec9a2	490 cm^3	start physical_unit 24 25 volume cm^3 qc_end physical_unit 5 5 3 4 volume qc_end physical_unit 14 14 12 13 volume qc_end end	[{"type":"physical unit","value":"Volume [OF] the gases [IN] cm^3"}]	[{"type":"physical unit","value":"490 cm^3"}]	[{"type":"physical unit","value":"Volume [OF] acetylene [=] \\pu{20 cm^3}"},{"type":"physical unit","value":"Volume [OF] dioxygen [=] \\pu{500 cm^3}"}]	<h1 class="questionTitle" itemprop="name">A volume of #20cm^3# acetylene was combusted with a volume of #500cm^3# dioxygen in a piston. What is the end volume of the gases confined by the piston?</h1>	null	490 cm^3	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We gots the combustion equation.....</p> <p><mathjax>#HC-=CH(g) + 5/2O_2(g) rarr 2CO_2(g) +H_2O(l)+Delta#</mathjax></p> <p>I use the half-integral coefficient because I think the arithmetic is easier in this way. Is it balanced? It is your problem not mine. </p> <p>And so we start with <mathjax>#20cm^3#</mathjax> acetylene, which required <mathjax>#50cm^3#</mathjax> of dioxygen, and gives <mathjax>#40cm^3#</mathjax> carbon dioxide gas upon complete combustion. I assume that the water has condensed. Agreed?</p> <p>And so to begin we had a <mathjax>#(20_"acetylene"+500_"dioxygen")cm^3#</mathjax> volume of gas.....</p> <p>To end we had ............ <mathjax>#(520_"starting volume"-50_"dioxygen"-20_"acetylene"+40_(CO_2))cm^3=490cm^3#</mathjax></p> <p>Do you agree? All care taken but no responsibility admitted. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Good question......I gets an end volume of <mathjax>#490cm^3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We gots the combustion equation.....</p> <p><mathjax>#HC-=CH(g) + 5/2O_2(g) rarr 2CO_2(g) +H_2O(l)+Delta#</mathjax></p> <p>I use the half-integral coefficient because I think the arithmetic is easier in this way. Is it balanced? It is your problem not mine. </p> <p>And so we start with <mathjax>#20cm^3#</mathjax> acetylene, which required <mathjax>#50cm^3#</mathjax> of dioxygen, and gives <mathjax>#40cm^3#</mathjax> carbon dioxide gas upon complete combustion. I assume that the water has condensed. Agreed?</p> <p>And so to begin we had a <mathjax>#(20_"acetylene"+500_"dioxygen")cm^3#</mathjax> volume of gas.....</p> <p>To end we had ............ <mathjax>#(520_"starting volume"-50_"dioxygen"-20_"acetylene"+40_(CO_2))cm^3=490*cm^3#</mathjax></p> <p>Do you agree? All care taken but no responsibility admitted. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A volume of #20cm^3# acetylene was combusted with a volume of #500cm^3# dioxygen in a piston. What is the end volume of the gases confined by the piston?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/stoichiometry-involving-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="469311" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-29T07:46:34" itemprop="dateCreated"> Aug 29, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Good question......I gets an end volume of <mathjax>#490cm^3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We gots the combustion equation.....</p> <p><mathjax>#HC-=CH(g) + 5/2O_2(g) rarr 2CO_2(g) +H_2O(l)+Delta#</mathjax></p> <p>I use the half-integral coefficient because I think the arithmetic is easier in this way. Is it balanced? It is your problem not mine. </p> <p>And so we start with <mathjax>#20cm^3#</mathjax> acetylene, which required <mathjax>#50cm^3#</mathjax> of dioxygen, and gives <mathjax>#40cm^3#</mathjax> carbon dioxide gas upon complete combustion. I assume that the water has condensed. Agreed?</p> <p>And so to begin we had a <mathjax>#(20_"acetylene"+500_"dioxygen")cm^3#</mathjax> volume of gas.....</p> <p>To end we had ............ <mathjax>#(520_"starting volume"-50_"dioxygen"-20_"acetylene"+40_(CO_2))cm^3=490*cm^3#</mathjax></p> <p>Do you agree? All care taken but no responsibility admitted. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/469311" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-apply-gas-stoichiometry"> How do you apply gas stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-solve-a-gas-law-stoichiometry-problem"> How do you solve a gas law stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-do-gas-stoichiometry-problems-at-stp"> How do you do gas stoichiometry problems at STP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-an-agno3-solution-is-treated-with-50-0-ml-of-hi-gas-to-give-0-235-g-of-agi-"> When an AgNO3 solution is treated with 50.0 mL of HI gas to give 0.235 g of AgI, what is the... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-10-0-ml-of-agno3-solution-is-treated-with-excess-amount-of-hi-gas-to-give-0"> When 10.0 mL of AgNO3 solution is treated with excess amount of HI gas to give 0.235 g of AgI,... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/hydrogen-sulfide-reacts-with-sulfur-dioxide-to-give-h2o-and-s-h2s-so2-h2o-s-soli"> Hydrogen sulfide reacts with sulfur dioxide to give H2O and S, H2S + SO2 = H2O + S(solid),... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-100-ml-of-hcl-gas-at-300-k-and-200-kpa-dissolved-in-pure-water-requires-12-50"> If 100 mL of HCl gas at 300 K and 200 kPa dissolved in pure water requires 12.50 mL of the NaOH... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-100-ml-of-hcl-gas-at-300-k-and-100-kpa-dissolved-in-pure-water-requires-12-50"> If 100 mL of HCl gas at 300 K and 100 kPa dissolved in pure water requires 12.50 mL of the NaOH... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-100-ml-of-hcl-gas-at-300-k-and-100-kpa-dissolve-in-20-ml-of-pure-water-what-i"> If 100 mL of HCl gas at 300 K and 100 kPa dissolve in 20 mL of pure water, what is the concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-2-00-g-mixture-of-na-and-ca-reat-with-water-1-164-l-hydrogen-was-produced-a"> When 2.00 g mixture of Na and Ca reat with water, 1.164 L hydrogen was produced at 300.0 K and... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/stoichiometry-involving-gases"> See all questions in Gas Stoichiometry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1356 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A volume of #20cm^3# acetylene was combusted with a volume of #500cm^3# dioxygen in a piston. What is the end volume of the gases confined by the piston?	null
1,733	a8acc58a-6ddd-11ea-8853-ccda262736ce	https://socratic.org/questions/how-do-you-balance-p-o-2-p-4o-10	4 P + 5 O2 -> P4O10	start chemical_equation qc_end chemical_equation 4 8 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the equation"}]	[{"type":"chemical equation","value":"4 P + 5 O2 -> P4O10"}]	[{"type":"chemical equation","value":"P + O2 -> P4O10"}]	<h1 class="questionTitle" itemprop="name">How do you balance #P+O_2 -> P_4O_10#?</h1>	null	4 P + 5 O2 -> P4O10	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Multiply <mathjax>#P#</mathjax> by <mathjax>#4#</mathjax> and <mathjax>#O_2#</mathjax> by <mathjax>#5#</mathjax>:</p> <p><mathjax>#4P+5O_(2)->P_4O_10#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#4P+5O_(2)->P_4O_10#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Multiply <mathjax>#P#</mathjax> by <mathjax>#4#</mathjax> and <mathjax>#O_2#</mathjax> by <mathjax>#5#</mathjax>:</p> <p><mathjax>#4P+5O_(2)->P_4O_10#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you balance #P+O_2 -> P_4O_10#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="216039" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ali-h-1"><img alt="" class="" src="https://profilepictures.socratic.org/IITeL1YTQdODdLp0aJTL_StereoPicture%20copy.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ali-h-1"> Dr. Hayek </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-23T15:39:08" itemprop="dateCreated"> Jan 23, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#4P+5O_(2)->P_4O_10#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Multiply <mathjax>#P#</mathjax> by <mathjax>#4#</mathjax> and <mathjax>#O_2#</mathjax> by <mathjax>#5#</mathjax>:</p> <p><mathjax>#4P+5O_(2)->P_4O_10#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/216039" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? 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Sodium phosphate and calcium chloride react to form... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-equation-kclo3-kcl-o2"> How can I balance this equation? ____ #KClO_3 -># ____ #KCl +# ____ #O_2# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-balancing-chemical-equations-important"> Why is balancing chemical equations important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/balancing-chemical-equations"> See all questions in Balancing Chemical Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1083 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How do you balance #P+O_2 -> P_4O_10#?	null
1,734	a837a700-6ddd-11ea-91e3-ccda262736ce	https://socratic.org/questions/what-is-the-ph-of-a-0-01-m-solution-of-the-strong-acid-hclo-4-perchloric-acid	2	start physical_unit 8 8 ph none qc_end physical_unit 13 13 6 7 molarity qc_end end	[{"type":"physical unit","value":"pH [OF] HClO4 solution"}]	[{"type":"physical unit","value":"2"}]	[{"type":"physical unit","value":"Molarity [OF] HClO4 solution [=] \\pu{0.01 M}"}]	<h1 class="questionTitle" itemprop="name"> What is the pH of a 0.01 M solution of the strong acid #HClO_4#, perchloric acid?</h1>	null	2	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This question may be answered without a calculator. We are asked to take the logarithm to the <mathjax>#"base 10"#</mathjax> of <mathjax>#10^(-2)#</mathjax>, which is clearly <mathjax>#-2#</mathjax>, why? We are then asked to give the negative value of that logarithm. </p> <p>Perchloric acid is exceptionally strong, and undergoes complete ionization in water:</p> <p><mathjax>#HClO_4(aq) + H_2O(aq) rarr H_3O^+ + ClO_4^-#</mathjax></p> <p>Now not only do you have to learn how to take logarithms, you also have to learn how to take antilogarithms, if asked to find concentrations given a <mathjax>#pH#</mathjax>, see <a href="https://socratic.org/questions/how-do-you-calculate-the-ka-for-the-weak-acid-with-pka-of-0-21">here</a> .</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#pH=-log_(10)[H_3O^+]=-log_(10)(10^-2) = 2#</mathjax> </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This question may be answered without a calculator. We are asked to take the logarithm to the <mathjax>#"base 10"#</mathjax> of <mathjax>#10^(-2)#</mathjax>, which is clearly <mathjax>#-2#</mathjax>, why? We are then asked to give the negative value of that logarithm. </p> <p>Perchloric acid is exceptionally strong, and undergoes complete ionization in water:</p> <p><mathjax>#HClO_4(aq) + H_2O(aq) rarr H_3O^+ + ClO_4^-#</mathjax></p> <p>Now not only do you have to learn how to take logarithms, you also have to learn how to take antilogarithms, if asked to find concentrations given a <mathjax>#pH#</mathjax>, see <a href="https://socratic.org/questions/how-do-you-calculate-the-ka-for-the-weak-acid-with-pka-of-0-21">here</a> .</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name"> What is the pH of a 0.01 M solution of the strong acid #HClO_4#, perchloric acid?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/the-ph-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">pH</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="264508" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-11T04:32:39" itemprop="dateCreated"> May 11, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#pH=-log_(10)[H_3O^+]=-log_(10)(10^-2) = 2#</mathjax> </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This question may be answered without a calculator. We are asked to take the logarithm to the <mathjax>#"base 10"#</mathjax> of <mathjax>#10^(-2)#</mathjax>, which is clearly <mathjax>#-2#</mathjax>, why? We are then asked to give the negative value of that logarithm. </p> <p>Perchloric acid is exceptionally strong, and undergoes complete ionization in water:</p> <p><mathjax>#HClO_4(aq) + H_2O(aq) rarr H_3O^+ + ClO_4^-#</mathjax></p> <p>Now not only do you have to learn how to take logarithms, you also have to learn how to take antilogarithms, if asked to find concentrations given a <mathjax>#pH#</mathjax>, see <a href="https://socratic.org/questions/how-do-you-calculate-the-ka-for-the-weak-acid-with-pka-of-0-21">here</a> .</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/264508" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-pka"> How do you determine pH from pKa? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-ph-values-of-acids-and-bases-differ"> How do pH values of acids and bases differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-something-on-a-ph-scale"> How do you calculate something on a pH scale? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-diprotic-acid"> How do you calculate pH diprotic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-from-acid-dissociation-constant"> How do you calculate pH from acid dissociation constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-of-acid-and-base-solution"> How do you calculate pH of acid and base solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ph-scale-0-14"> Why is the pH scale 0-14? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-ph-the-measure-of-the-hydrogen-ion-concentration"> Is pH a measure of the hydrogen ion concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-solubility-affect-ph"> How does solubility affect pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-ph-relate-to-pka-in-a-titration"> How does pH relate to pKa in a titration? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/the-ph-concept"> See all questions in pH </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 20990 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the pH of a 0.01 M solution of the strong acid #HClO_4#, perchloric acid?	null
1,735	abb250cc-6ddd-11ea-81b9-ccda262736ce	https://socratic.org/questions/what-is-the-empirical-formula-for-a-compound-containing-38-8-g-carbon-16-2-g-hyd	NCH5	start chemical_formula qc_end physical_unit 11 11 9 10 mass qc_end physical_unit 14 14 12 13 mass qc_end physical_unit 18 18 16 17 mass qc_end end	[{"type":"other","value":"Chemical Formula [OF] a compound [IN] empirical"}]	[{"type":"chemical equation","value":"NCH5"}]	[{"type":"physical unit","value":"mass [OF] carbon in compound [=] \\pu{38.8 g}"},{"type":"physical unit","value":"mass [OF] hydrogen in compound [=] \\pu{16.2 g}"},{"type":"physical unit","value":"mass [OF] nitrogen in compound [=] \\pu{45.1 g}"}]	<h1 class="questionTitle" itemprop="name">What is the empirical formula for a compound containing 38.8 g carbon, 16.2 g hydrogen and 45.1 g nitrogen? </h1>	null	NCH5	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To find the empirical formula change the mass to moles Then find a ratio between the moles. </p> <p>For Carbon <mathjax>#38.8 /12 = 3.233#</mathjax> moles </p> <p>For Hydrogen <mathjax>#16.2/1 = 16.2#</mathjax> moles </p> <p>For Nitrogen <mathjax>#45.1/14 = 3.22#</mathjax> moles. </p> <p>The ratio for Carbon and Nitrogen is <mathjax>#1:1#</mathjax> </p> <p><mathjax># 3.233/3.22 = 1.00 #</mathjax></p> <p>The ratio of Hydrogen to both Carbon and Nitrogen is 5:1 </p> <p><mathjax># 16.2/ 3.22 = 5.03 #</mathjax> </p> <p>So the ratio is 1 C to 1 N to 5 H. </p> <p><mathjax># H_2N C H_3#</mathjax></p> <p>Nitrogen usually forms three bonds one to Carbon and 2 to Hydrogen atoms. Carbon usually forms four bonds one to Nitrogen and 3 to Hydrogen atoms. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax># H_2NCH_3#</mathjax> or <mathjax># NCH_5#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To find the empirical formula change the mass to moles Then find a ratio between the moles. </p> <p>For Carbon <mathjax>#38.8 /12 = 3.233#</mathjax> moles </p> <p>For Hydrogen <mathjax>#16.2/1 = 16.2#</mathjax> moles </p> <p>For Nitrogen <mathjax>#45.1/14 = 3.22#</mathjax> moles. </p> <p>The ratio for Carbon and Nitrogen is <mathjax>#1:1#</mathjax> </p> <p><mathjax># 3.233/3.22 = 1.00 #</mathjax></p> <p>The ratio of Hydrogen to both Carbon and Nitrogen is 5:1 </p> <p><mathjax># 16.2/ 3.22 = 5.03 #</mathjax> </p> <p>So the ratio is 1 C to 1 N to 5 H. </p> <p><mathjax># H_2N C H_3#</mathjax></p> <p>Nitrogen usually forms three bonds one to Carbon and 2 to Hydrogen atoms. Carbon usually forms four bonds one to Nitrogen and 3 to Hydrogen atoms. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the empirical formula for a compound containing 38.8 g carbon, 16.2 g hydrogen and 45.1 g nitrogen? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="620259" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/david-drayer"><img alt="" class="" src="https://graph.facebook.com/10206723679871989/picture?height=50&width=50" title=""/></a> <a class="secondContributorPic" href="/users/jacobi-j"><img alt="" class="" src="https://lh6.googleusercontent.com/-nGGEsAETYxI/AAAAAAAAAAI/AAAAAAAAABU/1_Wcwzsy9pM/photo.jpg?sz=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/david-drayer"> David Drayer </a>·<a class="topContributorLink" href="/users/jacobi-j"> Jacobi J. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-05-26T02:05:10" itemprop="dateCreated"> May 26, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax># H_2NCH_3#</mathjax> or <mathjax># NCH_5#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To find the empirical formula change the mass to moles Then find a ratio between the moles. </p> <p>For Carbon <mathjax>#38.8 /12 = 3.233#</mathjax> moles </p> <p>For Hydrogen <mathjax>#16.2/1 = 16.2#</mathjax> moles </p> <p>For Nitrogen <mathjax>#45.1/14 = 3.22#</mathjax> moles. </p> <p>The ratio for Carbon and Nitrogen is <mathjax>#1:1#</mathjax> </p> <p><mathjax># 3.233/3.22 = 1.00 #</mathjax></p> <p>The ratio of Hydrogen to both Carbon and Nitrogen is 5:1 </p> <p><mathjax># 16.2/ 3.22 = 5.03 #</mathjax> </p> <p>So the ratio is 1 C to 1 N to 5 H. </p> <p><mathjax># H_2N C H_3#</mathjax></p> <p>Nitrogen usually forms three bonds one to Carbon and 2 to Hydrogen atoms. Carbon usually forms four bonds one to Nitrogen and 3 to Hydrogen atoms. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/620259" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="620265" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-05-26T02:39:31" itemprop="dateCreated"> May 26, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The empirical formula is <mathjax>#"CH"_5"N"#</mathjax>.</p> <p>This may be methylamine, <mathjax>#"CH"_3"NH"_2#</mathjax>, derived from ammonia, <mathjax>#"NH"_3"#</mathjax>, in which one <mathjax>#"H"#</mathjax> atom is replaced by a methyl group <mathjax>#"-CH"_3"#</mathjax>. However, we can't know this for certain unless we are given the molecular mass.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The empirical formula of a compound represents the simplest whole number ratio of <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> in the compound.</p> <p>We must first determine the moles of each element in the compound by dividing the given mass by the molar mass.</p> <p>Since the masses of all of the elements equal <mathjax>#"100.1 g"#</mathjax>, we can use the masses as given.</p> <p><mathjax>#"mol C":#</mathjax> <mathjax>#(38.8"g C")/(12.011"g"/"mol")="3.23 mol"#</mathjax></p> <p><mathjax>#"mol H":#</mathjax> <mathjax>#(16.2"g H")/(1.008"g"/"mol")="16.1 mol"#</mathjax></p> <p><mathjax>#"mol N":#</mathjax> <mathjax>#(45.1"g N")/(14.007"g"/"mol")="3.22 mol"#</mathjax></p> <p>To determine the subscripts of the empirical formula, we find the lowest whole number ratio for each element by dividing the moles of each element by the least number of moles, in this case <mathjax>#"3.22 mol"#</mathjax>. </p> <p><mathjax>#"C":#</mathjax> <mathjax>#(3.23)/(3.22)=1.00#</mathjax></p> <p><mathjax>#"H":#</mathjax> <mathjax>#(16.1)/(3.22)=5.00#</mathjax></p> <p><mathjax>#"N":#</mathjax> <mathjax>#(3.22)/(3.22)=1.00#</mathjax></p> <p>The empirical formula is <mathjax>#"CH"_5"N"#</mathjax>.</p> <p><strong>Note:</strong> If the mol ratios are not all whole numbers, you will need to multiply each mole ratio by the same factor that will make all mol ratios whole numbers.</p> <p>This may be methylamine, <mathjax>#"CH"_3"NH"_2#</mathjax>, derived from ammonia, <mathjax>#"NH"_3"#</mathjax>, in which one <mathjax>#"H"#</mathjax> atom is replaced by a methyl group <mathjax>#"-CH"_3"#</mathjax>. However, we can't know this for certain unless we are given the molecular mass.</p> <p><img alt="https://en.wikipedia.org/wiki/Methylamine" src="https://useruploads.socratic.org/54q1ZVq8TCmAE4RJ2V9p_100px-Methylamine.svg.png"/> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/620265" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molecular-formula-of-a-compound"> How do you find molecular formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-diamond"> What is the chemical formula of a diamond? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-carbohydrate"> What is the chemical formula of a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-valproic-acid"> What is the empirical formula for valproic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-of-magnesium-oxide"> What is the empirical formula of magnesium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-empirical-formula-not-double-that-of-the-monosaccharides"> Why is the empirical formula not double that of the monosaccharides? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5331180502bf342f40b5c3b5"> Question #5c3b5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-molecular-formula-represents-a-carbohydrate"> What molecular formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-of-vinegar"> What is the molecular formula of vinegar? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/empirical-and-molecular-formulas"> See all questions in Empirical and Molecular Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 56619 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the empirical formula for a compound containing 38.8 g carbon, 16.2 g hydrogen and 45.1 g nitrogen?	null
1,736	ac7ac45b-6ddd-11ea-84b0-ccda262736ce	https://socratic.org/questions/how-do-you-balance-agi-fe-2-c-3-3-fei-3-ag-2co-3	6 AgI + Fe2(CO3)3 -> 2 FeI3 + 3 Ag2CO3	start chemical_equation qc_end chemical_equation 4 10 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the equation"}]	[{"type":"chemical equation","value":"6 AgI + Fe2(CO3)3 -> 2 FeI3 + 3 Ag2CO3"}]	[{"type":"chemical equation","value":"AgI + Fe2(CO3)3 -> FeI3 + Ag2CO3"}]	<h1 class="questionTitle" itemprop="name">How do you balance #"AgI + Fe"_2"(CO"_3)_3##rarr##"FeI"_3 + "Ag"_2"CO"_3"#?</h1>	null	6 AgI + Fe2(CO3)3 -> 2 FeI3 + 3 Ag2CO3	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The law of the conservation of matter requires that the number of atoms of each element on each side of a chemical equation. This is done by adding coefficients in front of the formulas in the equation. A chemical formula should never be changed, only the amount.</p> <p><mathjax>#"AgI+Fe"_2"(CO"_3)_3"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"FeI"_3+"Ag"_2"CO"_3#</mathjax></p> <p>First notice that there is a polyatomic ion, the carbonate ion, <mathjax>#"CO"_3^(2-)"#</mathjax> that occurs on both sides. When there is a polyatomic ion, it is treated as a single entity. So there are three carbonate ions on the left side and one on the right. So a coefficient of <mathjax>#3#</mathjax> is needed in front of <mathjax>#"Ag"_2"CO"_3"#</mathjax></p> <p><mathjax>#"AgI+Fe"_2"(CO"_3)_3"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"FeI"_3+color(red)("3")"Ag"_2"CO"_3#</mathjax></p> <p>Now there are six <mathjax>#"Ag"#</mathjax> atoms on the right side, but one on the left. So a coefficient of <mathjax>#6#</mathjax> needs to be added in front of the compound <mathjax>#"AgI"#</mathjax>.</p> <p><mathjax>#color(blue)(6)"AgI+Fe"_2"(CO"_3)_3"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"FeI"_3+color(red)(3)"Ag"_2"CO"_3#</mathjax></p> <p>Now there are six <mathjax>#"AgI"#</mathjax>, which gives us six <mathjax>#"I"#</mathjax> atoms on the left side, but three on the right. So a coefficient of <mathjax>#2#</mathjax> is needed in front of the compound <mathjax>#"FeI"_3"#</mathjax>.</p> <p><mathjax>#color(blue)(6)"AgI+Fe"_2"(CO"_3)_3"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(green)(2)"FeI"_3+color(red)(3)"Ag"_2"CO"_3#</mathjax></p> <p>This also balanced the <mathjax>#"Fe"#</mathjax> atoms. So the balanced equation is</p> <p><mathjax>#color(blue)(6)"AgI+Fe"_2"(CO"_3)_3"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(green)(2)"FeI"_3+color(red)(3)"Ag"_2"CO"_3#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The balanced equation is <mathjax>#color(blue)(6)"AgI+Fe"_2"(CO"_3)_3"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(green)(2)"FeI"_3+color(red)(3)"Ag"_2"CO"_3#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The law of the conservation of matter requires that the number of atoms of each element on each side of a chemical equation. This is done by adding coefficients in front of the formulas in the equation. A chemical formula should never be changed, only the amount.</p> <p><mathjax>#"AgI+Fe"_2"(CO"_3)_3"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"FeI"_3+"Ag"_2"CO"_3#</mathjax></p> <p>First notice that there is a polyatomic ion, the carbonate ion, <mathjax>#"CO"_3^(2-)"#</mathjax> that occurs on both sides. When there is a polyatomic ion, it is treated as a single entity. So there are three carbonate ions on the left side and one on the right. So a coefficient of <mathjax>#3#</mathjax> is needed in front of <mathjax>#"Ag"_2"CO"_3"#</mathjax></p> <p><mathjax>#"AgI+Fe"_2"(CO"_3)_3"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"FeI"_3+color(red)("3")"Ag"_2"CO"_3#</mathjax></p> <p>Now there are six <mathjax>#"Ag"#</mathjax> atoms on the right side, but one on the left. So a coefficient of <mathjax>#6#</mathjax> needs to be added in front of the compound <mathjax>#"AgI"#</mathjax>.</p> <p><mathjax>#color(blue)(6)"AgI+Fe"_2"(CO"_3)_3"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"FeI"_3+color(red)(3)"Ag"_2"CO"_3#</mathjax></p> <p>Now there are six <mathjax>#"AgI"#</mathjax>, which gives us six <mathjax>#"I"#</mathjax> atoms on the left side, but three on the right. So a coefficient of <mathjax>#2#</mathjax> is needed in front of the compound <mathjax>#"FeI"_3"#</mathjax>.</p> <p><mathjax>#color(blue)(6)"AgI+Fe"_2"(CO"_3)_3"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(green)(2)"FeI"_3+color(red)(3)"Ag"_2"CO"_3#</mathjax></p> <p>This also balanced the <mathjax>#"Fe"#</mathjax> atoms. So the balanced equation is</p> <p><mathjax>#color(blue)(6)"AgI+Fe"_2"(CO"_3)_3"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(green)(2)"FeI"_3+color(red)(3)"Ag"_2"CO"_3#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you balance #"AgI + Fe"_2"(CO"_3)_3##rarr##"FeI"_3 + "Ag"_2"CO"_3"#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="316010" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-09-29T21:13:26" itemprop="dateCreated"> Sep 29, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The balanced equation is <mathjax>#color(blue)(6)"AgI+Fe"_2"(CO"_3)_3"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(green)(2)"FeI"_3+color(red)(3)"Ag"_2"CO"_3#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The law of the conservation of matter requires that the number of atoms of each element on each side of a chemical equation. This is done by adding coefficients in front of the formulas in the equation. A chemical formula should never be changed, only the amount.</p> <p><mathjax>#"AgI+Fe"_2"(CO"_3)_3"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"FeI"_3+"Ag"_2"CO"_3#</mathjax></p> <p>First notice that there is a polyatomic ion, the carbonate ion, <mathjax>#"CO"_3^(2-)"#</mathjax> that occurs on both sides. When there is a polyatomic ion, it is treated as a single entity. So there are three carbonate ions on the left side and one on the right. So a coefficient of <mathjax>#3#</mathjax> is needed in front of <mathjax>#"Ag"_2"CO"_3"#</mathjax></p> <p><mathjax>#"AgI+Fe"_2"(CO"_3)_3"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"FeI"_3+color(red)("3")"Ag"_2"CO"_3#</mathjax></p> <p>Now there are six <mathjax>#"Ag"#</mathjax> atoms on the right side, but one on the left. So a coefficient of <mathjax>#6#</mathjax> needs to be added in front of the compound <mathjax>#"AgI"#</mathjax>.</p> <p><mathjax>#color(blue)(6)"AgI+Fe"_2"(CO"_3)_3"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"FeI"_3+color(red)(3)"Ag"_2"CO"_3#</mathjax></p> <p>Now there are six <mathjax>#"AgI"#</mathjax>, which gives us six <mathjax>#"I"#</mathjax> atoms on the left side, but three on the right. So a coefficient of <mathjax>#2#</mathjax> is needed in front of the compound <mathjax>#"FeI"_3"#</mathjax>.</p> <p><mathjax>#color(blue)(6)"AgI+Fe"_2"(CO"_3)_3"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(green)(2)"FeI"_3+color(red)(3)"Ag"_2"CO"_3#</mathjax></p> <p>This also balanced the <mathjax>#"Fe"#</mathjax> atoms. So the balanced equation is</p> <p><mathjax>#color(blue)(6)"AgI+Fe"_2"(CO"_3)_3"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(green)(2)"FeI"_3+color(red)(3)"Ag"_2"CO"_3#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/316010" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------> H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -> Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? 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1,737	acbda51e-6ddd-11ea-aa18-ccda262736ce	https://socratic.org/questions/the-reaction-between-propanone-iodine-and-hydrochloric-acid-is-a-first-order-wit	4.32 M/s	start physical_unit 0 1 percent m/s qc_end physical_unit 0 1 24 25 percent qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Rate2 [OF] the reaction [IN] M/s"}]	[{"type":"physical unit","value":"4.32 M/s"}]	[{"type":"physical unit","value":"[H+]1 [OF] the solution [=] \\pu{0.1 M}"},{"type":"physical unit","value":"Rate1 [OF] the reaction [=] \\pu{0.865 M/s}"},{"type":"physical unit","value":"[H+]2 [OF] the solution [=] \\pu{0.5 M}"},{"type":"other","value":"The reaction between propanone,iodine and hydrochloric acid is a first order with respect to H+ ions."}]	<h1 class="questionTitle" itemprop="name">The reaction between propanone,iodine and hydrochloric acid is a first order with respect to H+ ions. When[H+]=0.1M ,the rate is 0.865M/s. What is the rate when [H+] = 0.5 M?</h1>	null	4.32 M/s	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>All you have to do to answer this question is use the definition of a <strong>first-order reaction</strong>. </p> <p>As you know, a <strong>first-order reaction</strong> is characterized by the fact that its <a href="https://socratic.org/chemistry/chemical-kinetics/rate-of-reactions">rate</a> is <strong>directly proportional</strong> to the concentration of one reactant. </p> <p>Simply put, the rate of a first-order reaction will have a <em>linear</em> dependence of the concentration of one reactant. If the concentration of that reactant <strong>increases</strong>, the rate of the reaction <strong>Increases</strong> <em>by the same amount</em>. </p> <p>Likewise, if the concentration of that reactant <strong>decreases</strong>, the rate of the reaction <strong>decreases</strong> by the same amount. </p> <p>In your case, the reaction is first-order in hydrogen ions, <mathjax>#"H"^(+)#</mathjax>. Notice that the concentration of hydrogen ions increases <strong>five-fold</strong>. </p> <blockquote> <p><mathjax>#(["H"^(+)]_2)/(["H"^(+)]_1) = (0.5 color(red)(cancel(color(black)("M"))))/(0.1color(red)(cancel(color(black)("M")))) = 5#</mathjax></p> </blockquote> <p>This means that the rate of reaction will also increase <strong>five-fold</strong>, so that</p> <blockquote> <p><mathjax>#"rate"_2 = 5 xx "rate"_1#</mathjax></p> <p><mathjax>#"rate"_2 = 5 xx "0.865 M s"^(-1) = "4.325 M s"^(-1)#</mathjax></p> </blockquote> <p>You can also show that this is the case by calculating the <em>rate constant</em> for this reaction</p> <blockquote> <p><mathjax>#color(blue)("rate" = -(d["H"^(+)])/dt = k * ["H"^(+)])#</mathjax></p> <p><mathjax>#k = "rate"_1/(["H"^(+)]_1)#</mathjax></p> <p><mathjax>#k = (0.865 color(red)(cancel(color(black)("M"))) "s"^(-1))/(0.1 color(red)(cancel(color(black)("M")))) = "8.65 s"^(-1)#</mathjax></p> </blockquote> <p>This means that the new concentration of hydrogen ions will correspond to a reaction rate of </p> <blockquote> <p><mathjax>#"rate"_2 = k * ["H"^(+)]_2#</mathjax></p> <p><mathjax>#"rate"_2 = "8.65 s"^(-1) * "0.5 M"#</mathjax></p> <p><mathjax>#"rate"_2 = "4.325 M s"^(-1)#</mathjax></p> </blockquote> <p>Now, you <em>should</em> round this off to one <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig fig</a>, the number of sig figs you have for the two concentration of hydrogen ions, but I'll leave the answer rounded to two sig figs</p> <blockquote> <p><mathjax>#"rate"_2 = color(green)("4.3 M s"^(-1))#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"4.3 M s"^(-1)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>All you have to do to answer this question is use the definition of a <strong>first-order reaction</strong>. </p> <p>As you know, a <strong>first-order reaction</strong> is characterized by the fact that its <a href="https://socratic.org/chemistry/chemical-kinetics/rate-of-reactions">rate</a> is <strong>directly proportional</strong> to the concentration of one reactant. </p> <p>Simply put, the rate of a first-order reaction will have a <em>linear</em> dependence of the concentration of one reactant. If the concentration of that reactant <strong>increases</strong>, the rate of the reaction <strong>Increases</strong> <em>by the same amount</em>. </p> <p>Likewise, if the concentration of that reactant <strong>decreases</strong>, the rate of the reaction <strong>decreases</strong> by the same amount. </p> <p>In your case, the reaction is first-order in hydrogen ions, <mathjax>#"H"^(+)#</mathjax>. Notice that the concentration of hydrogen ions increases <strong>five-fold</strong>. </p> <blockquote> <p><mathjax>#(["H"^(+)]_2)/(["H"^(+)]_1) = (0.5 color(red)(cancel(color(black)("M"))))/(0.1color(red)(cancel(color(black)("M")))) = 5#</mathjax></p> </blockquote> <p>This means that the rate of reaction will also increase <strong>five-fold</strong>, so that</p> <blockquote> <p><mathjax>#"rate"_2 = 5 xx "rate"_1#</mathjax></p> <p><mathjax>#"rate"_2 = 5 xx "0.865 M s"^(-1) = "4.325 M s"^(-1)#</mathjax></p> </blockquote> <p>You can also show that this is the case by calculating the <em>rate constant</em> for this reaction</p> <blockquote> <p><mathjax>#color(blue)("rate" = -(d["H"^(+)])/dt = k * ["H"^(+)])#</mathjax></p> <p><mathjax>#k = "rate"_1/(["H"^(+)]_1)#</mathjax></p> <p><mathjax>#k = (0.865 color(red)(cancel(color(black)("M"))) "s"^(-1))/(0.1 color(red)(cancel(color(black)("M")))) = "8.65 s"^(-1)#</mathjax></p> </blockquote> <p>This means that the new concentration of hydrogen ions will correspond to a reaction rate of </p> <blockquote> <p><mathjax>#"rate"_2 = k * ["H"^(+)]_2#</mathjax></p> <p><mathjax>#"rate"_2 = "8.65 s"^(-1) * "0.5 M"#</mathjax></p> <p><mathjax>#"rate"_2 = "4.325 M s"^(-1)#</mathjax></p> </blockquote> <p>Now, you <em>should</em> round this off to one <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig fig</a>, the number of sig figs you have for the two concentration of hydrogen ions, but I'll leave the answer rounded to two sig figs</p> <blockquote> <p><mathjax>#"rate"_2 = color(green)("4.3 M s"^(-1))#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">The reaction between propanone,iodine and hydrochloric acid is a first order with respect to H+ ions. When[H+]=0.1M ,the rate is 0.865M/s. What is the rate when [H+] = 0.5 M?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-kinetics" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Kinetics</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-kinetics/rate-of-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Rate of Reactions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="201381" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-19T23:05:21" itemprop="dateCreated"> Dec 19, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"4.3 M s"^(-1)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>All you have to do to answer this question is use the definition of a <strong>first-order reaction</strong>. </p> <p>As you know, a <strong>first-order reaction</strong> is characterized by the fact that its <a href="https://socratic.org/chemistry/chemical-kinetics/rate-of-reactions">rate</a> is <strong>directly proportional</strong> to the concentration of one reactant. </p> <p>Simply put, the rate of a first-order reaction will have a <em>linear</em> dependence of the concentration of one reactant. If the concentration of that reactant <strong>increases</strong>, the rate of the reaction <strong>Increases</strong> <em>by the same amount</em>. </p> <p>Likewise, if the concentration of that reactant <strong>decreases</strong>, the rate of the reaction <strong>decreases</strong> by the same amount. </p> <p>In your case, the reaction is first-order in hydrogen ions, <mathjax>#"H"^(+)#</mathjax>. Notice that the concentration of hydrogen ions increases <strong>five-fold</strong>. </p> <blockquote> <p><mathjax>#(["H"^(+)]_2)/(["H"^(+)]_1) = (0.5 color(red)(cancel(color(black)("M"))))/(0.1color(red)(cancel(color(black)("M")))) = 5#</mathjax></p> </blockquote> <p>This means that the rate of reaction will also increase <strong>five-fold</strong>, so that</p> <blockquote> <p><mathjax>#"rate"_2 = 5 xx "rate"_1#</mathjax></p> <p><mathjax>#"rate"_2 = 5 xx "0.865 M s"^(-1) = "4.325 M s"^(-1)#</mathjax></p> </blockquote> <p>You can also show that this is the case by calculating the <em>rate constant</em> for this reaction</p> <blockquote> <p><mathjax>#color(blue)("rate" = -(d["H"^(+)])/dt = k * ["H"^(+)])#</mathjax></p> <p><mathjax>#k = "rate"_1/(["H"^(+)]_1)#</mathjax></p> <p><mathjax>#k = (0.865 color(red)(cancel(color(black)("M"))) "s"^(-1))/(0.1 color(red)(cancel(color(black)("M")))) = "8.65 s"^(-1)#</mathjax></p> </blockquote> <p>This means that the new concentration of hydrogen ions will correspond to a reaction rate of </p> <blockquote> <p><mathjax>#"rate"_2 = k * ["H"^(+)]_2#</mathjax></p> <p><mathjax>#"rate"_2 = "8.65 s"^(-1) * "0.5 M"#</mathjax></p> <p><mathjax>#"rate"_2 = "4.325 M s"^(-1)#</mathjax></p> </blockquote> <p>Now, you <em>should</em> round this off to one <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig fig</a>, the number of sig figs you have for the two concentration of hydrogen ions, but I'll leave the answer rounded to two sig figs</p> <blockquote> <p><mathjax>#"rate"_2 = color(green)("4.3 M s"^(-1))#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/201381" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-rate-of-reaction"> How do you calculate rate of reaction? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-rate-of-reaction-be-affected"> How can rate of reaction be affected? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-rate-of-reaction-be-increased"> How can rate of reaction be increased? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-temperature-affect-reaction-rate"> How can temperature affect reaction rate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-rate-of-reaction-be-calculated-from-a-graph"> How can the rate of reaction be calculated from a graph? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-reaction-rates-give-information-about-mechanisms"> How do reaction rates give information about mechanisms? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-reaction-rate-constant"> What is a reaction rate constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-the-reaction-rates-change-as-the-system-approaches-equilibrium"> How do the reaction rates change as the system approaches equilibrium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-does-the-rate-of-reaction-increase-with-concentration"> Why does the rate of reaction increase with concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-rates-of-reaction-change-with-ph"> Why do rates of reaction change with pH? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-kinetics/rate-of-reactions"> See all questions in Rate of Reactions </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 4266 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	The reaction between propanone,iodine and hydrochloric acid is a first order with respect to H+ ions. When[H+]=0.1M ,the rate is 0.865M/s. What is the rate when [H+] = 0.5 M?	null
1,738	aa212974-6ddd-11ea-bfde-ccda262736ce	https://socratic.org/questions/what-is-the-molar-mass-of-a-non-electrolyte-compound-if-4-28-grams-is-dissolved-	270.20 g/mol	start physical_unit 7 8 molar_mass g/mol qc_end physical_unit 7 8 10 11 mass qc_end physical_unit 18 19 15 16 mass qc_end physical_unit 23 23 31 33 boiling_point_temperature qc_end physical_unit 18 18 40 42 boiling_point_temperature qc_end physical_unit 18 18 56 57 molar_mass qc_end end	[{"type":"physical unit","value":"Molar mass [OF] non-electrolyte compound [IN] g/mol"}]	[{"type":"physical unit","value":"270.20 g/mol"}]	[{"type":"physical unit","value":"Mass [OF] non-electrolyte compound [=] \\pu{4.28 grams}"},{"type":"physical unit","value":"Mass [OF] chloroform solvent [=] \\pu{25.0 grams}"},{"type":"physical unit","value":"Boiling point elevation [OF] the solution [=] \\pu{2.30 degrees celsius}"},{"type":"physical unit","value":"Boiling constant [OF] chloroform [=] \\pu{3.63 degrees Celsius/m}"},{"type":"physical unit","value":"Molar mass [OF] chloroform [=] \\pu{119.38 g/mol}"}]	<h1 class="questionTitle" itemprop="name">What is the molar mass of a non-electrolyte compound if 4.28 grams is dissolved in 25.0 grams of chloroform solvent to form a solution which has a boiling point elevation of 2.30 degrees celsius?</h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>The boiling constant of chloroform is 3.63 degrees Celsius/m<br/> im not sure if this is needed but molar mass of chloroform = 119.38 g/mol</p> <p>I need a step by step explanation please.</p></div> </h2> </div> </div>	270.20 g/mol	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The formula for boiling point elevation <mathjax>#ΔT_"b"#</mathjax> is</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(\|color(white)(a/a)ΔT_"b" = K_"b"bcolor(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>where</p> <p><mathjax>#K_"b"#</mathjax> = the molal boiling point elevation constant of the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a><br/> <mathjax>#bcolor(white)(m)#</mathjax> = the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molality">molality</a> of the solution</p> <p>We can rearrange the formula to get</p> <blockquote> <blockquote> <p><mathjax>#b = (ΔT_"b")/K_"b"#</mathjax></p> </blockquote> </blockquote> <p>In your problem,</p> <p><mathjax>#ΔT_"b" = "2.30 °C"#</mathjax><br/> <mathjax>#K_"b" = "3.63 °C·kg·mol"^"-1"#</mathjax></p> <p>∴ <mathjax>#b = (2.30 color(red)(cancel(color(black)("°C"))))/(3.63 color(red)(cancel(color(black)("°C")))·"kg·mol"^"-1") = "0.6336 mol·kg"^"-1"#</mathjax></p> <blockquote></blockquote> <p>You have 4.28 g of compound in 0.0250 kg solvent.</p> <p>;: <mathjax>#b = "0.6336 mol"/(1 color(red)(cancel(color(black)("kg")))) = "4.28 g"/("0.0250" color(red)(cancel(color(black)("kg"))))#</mathjax></p> <p>Divide both sides of the equation by <mathjax>#0.6336#</mathjax>.</p> <p>∴ <mathjax>#"1 mol" = "4.28 g"/0.0250 × 1/0.6336 = "270 g"#</mathjax></p> <p>The molar mass is 270 g/mol.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The molar mass is 270 g/mol.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The formula for boiling point elevation <mathjax>#ΔT_"b"#</mathjax> is</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(\|color(white)(a/a)ΔT_"b" = K_"b"bcolor(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>where</p> <p><mathjax>#K_"b"#</mathjax> = the molal boiling point elevation constant of the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a><br/> <mathjax>#bcolor(white)(m)#</mathjax> = the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molality">molality</a> of the solution</p> <p>We can rearrange the formula to get</p> <blockquote> <blockquote> <p><mathjax>#b = (ΔT_"b")/K_"b"#</mathjax></p> </blockquote> </blockquote> <p>In your problem,</p> <p><mathjax>#ΔT_"b" = "2.30 °C"#</mathjax><br/> <mathjax>#K_"b" = "3.63 °C·kg·mol"^"-1"#</mathjax></p> <p>∴ <mathjax>#b = (2.30 color(red)(cancel(color(black)("°C"))))/(3.63 color(red)(cancel(color(black)("°C")))·"kg·mol"^"-1") = "0.6336 mol·kg"^"-1"#</mathjax></p> <blockquote></blockquote> <p>You have 4.28 g of compound in 0.0250 kg solvent.</p> <p>;: <mathjax>#b = "0.6336 mol"/(1 color(red)(cancel(color(black)("kg")))) = "4.28 g"/("0.0250" color(red)(cancel(color(black)("kg"))))#</mathjax></p> <p>Divide both sides of the equation by <mathjax>#0.6336#</mathjax>.</p> <p>∴ <mathjax>#"1 mol" = "4.28 g"/0.0250 × 1/0.6336 = "270 g"#</mathjax></p> <p>The molar mass is 270 g/mol.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the molar mass of a non-electrolyte compound if 4.28 grams is dissolved in 25.0 grams of chloroform solvent to form a solution which has a boiling point elevation of 2.30 degrees celsius?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>The boiling constant of chloroform is 3.63 degrees Celsius/m<br/> im not sure if this is needed but molar mass of chloroform = 119.38 g/mol</p> <p>I need a step by step explanation please.</p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/colligative-properties" itemprop="url"> <span class="breadcrumb" itemprop="title">Colligative Properties</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="397005" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-27T00:39:15" itemprop="dateCreated"> Mar 27, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The molar mass is 270 g/mol.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The formula for boiling point elevation <mathjax>#ΔT_"b"#</mathjax> is</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(\|color(white)(a/a)ΔT_"b" = K_"b"bcolor(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>where</p> <p><mathjax>#K_"b"#</mathjax> = the molal boiling point elevation constant of the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a><br/> <mathjax>#bcolor(white)(m)#</mathjax> = the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molality">molality</a> of the solution</p> <p>We can rearrange the formula to get</p> <blockquote> <blockquote> <p><mathjax>#b = (ΔT_"b")/K_"b"#</mathjax></p> </blockquote> </blockquote> <p>In your problem,</p> <p><mathjax>#ΔT_"b" = "2.30 °C"#</mathjax><br/> <mathjax>#K_"b" = "3.63 °C·kg·mol"^"-1"#</mathjax></p> <p>∴ <mathjax>#b = (2.30 color(red)(cancel(color(black)("°C"))))/(3.63 color(red)(cancel(color(black)("°C")))·"kg·mol"^"-1") = "0.6336 mol·kg"^"-1"#</mathjax></p> <blockquote></blockquote> <p>You have 4.28 g of compound in 0.0250 kg solvent.</p> <p>;: <mathjax>#b = "0.6336 mol"/(1 color(red)(cancel(color(black)("kg")))) = "4.28 g"/("0.0250" color(red)(cancel(color(black)("kg"))))#</mathjax></p> <p>Divide both sides of the equation by <mathjax>#0.6336#</mathjax>.</p> <p>∴ <mathjax>#"1 mol" = "4.28 g"/0.0250 × 1/0.6336 = "270 g"#</mathjax></p> <p>The molar mass is 270 g/mol.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/397005" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-colligative-properties-determined"> How are colligative properties determined? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-freezing-point-depression"> How do you calculate freezing point 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href="/chemistry/solutions-and-their-behavior/colligative-properties"> See all questions in Colligative Properties </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 13771 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the molar mass of a non-electrolyte compound if 4.28 grams is dissolved in 25.0 grams of chloroform solvent to form a solution which has a boiling point elevation of 2.30 degrees celsius?	The boiling constant of chloroform is 3.63 degrees Celsius/m im not sure if this is needed but molar mass of chloroform = 119.38 g/mol I need a step by step explanation please.
1,739	ad0c82e0-6ddd-11ea-86f6-ccda262736ce	https://socratic.org/questions/how-would-you-balance-the-following-equation-s8-o2-so3-2	S8 + 12 O2 -> 8 SO3	start chemical_equation qc_end chemical_equation 7 11 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the following equation"}]	[{"type":"chemical equation","value":"S8 + 12 O2 -> 8 SO3"}]	[{"type":"chemical equation","value":"S8 + O2 -> SO3"}]	<h1 class="questionTitle" itemprop="name">How would you balance the following equation: S8 + O2 --> SO3?</h1>	null	S8 + 12 O2 -> 8 SO3	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To start balancing this reaction, we can first multiply <mathjax>#S#</mathjax> by <mathjax>#8#</mathjax> which will make the number of oxygen atoms in the product <mathjax>#24#</mathjax>, then we multiply <mathjax>#O#</mathjax> by <mathjax>#12#</mathjax>. </p> <p>The balanced reaction is then:</p> <p><mathjax>#S_8+color(red)(12)O_2->color(blue)(8)SO_3#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#S_8+color(red)(12)O_2->color(blue)(8)SO_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To start balancing this reaction, we can first multiply <mathjax>#S#</mathjax> by <mathjax>#8#</mathjax> which will make the number of oxygen atoms in the product <mathjax>#24#</mathjax>, then we multiply <mathjax>#O#</mathjax> by <mathjax>#12#</mathjax>. </p> <p>The balanced reaction is then:</p> <p><mathjax>#S_8+color(red)(12)O_2->color(blue)(8)SO_3#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How would you balance the following equation: S8 + O2 --> SO3?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="216108" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ali-h-1"><img alt="" class="" src="https://profilepictures.socratic.org/IITeL1YTQdODdLp0aJTL_StereoPicture%20copy.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ali-h-1"> Dr. Hayek </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-23T19:10:29" itemprop="dateCreated"> Jan 23, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#S_8+color(red)(12)O_2->color(blue)(8)SO_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To start balancing this reaction, we can first multiply <mathjax>#S#</mathjax> by <mathjax>#8#</mathjax> which will make the number of oxygen atoms in the product <mathjax>#24#</mathjax>, then we multiply <mathjax>#O#</mathjax> by <mathjax>#12#</mathjax>. </p> <p>The balanced reaction is then:</p> <p><mathjax>#S_8+color(red)(12)O_2->color(blue)(8)SO_3#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/216108" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? 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1,740	aaa2af00-6ddd-11ea-af0b-ccda262736ce	https://socratic.org/questions/what-is-the-ph-of-a-1-0-x-10-5-m-solution-of-naoh	9.00	start physical_unit 10 10 ph none qc_end physical_unit 12 12 6 9 molarity qc_end end	[{"type":"physical unit","value":"pH [OF] NaOH solution"}]	[{"type":"physical unit","value":"9.00"}]	[{"type":"physical unit","value":"Molarity [OF] NaOH solution [=] \\pu{1.0 × 10^(-5) M}"}]	<h1 class="questionTitle" itemprop="name">What is the pH of a #1.0 x 10^-5# M solution of NaOH?</h1>	null	9.00	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#pOH=-log_10[HO^-]#</mathjax> by definition.</p> <p>Thus <mathjax>#pOH=-log_10(1xx10^-5)=-(-5)=5#</mathjax></p> <p><mathjax>#pH+pOH=14#</mathjax></p> <p><mathjax>#pH=14-pOH=14-5=9#</mathjax></p> <p>When we write <mathjax>#log_ab=c#</mathjax>, we ask to what power we raise the base, <mathjax>#a#</mathjax>, to get <mathjax>#b#</mathjax>; here <mathjax>#a^c=b#</mathjax>. The normal bases are <mathjax>#10#</mathjax>, <mathjax>#"(common logarithms)"#</mathjax>, and <mathjax>#e#</mathjax>, <mathjax>#"(natural logarithms)"#</mathjax>.</p> <p>Thus when we write <mathjax>#log_10(10^-5)#</mathjax>, we are asking to what power we raise <mathjax>#10#</mathjax> to get <mathjax>#10^-5#</mathjax>. Now clearly the answer is <mathjax>#-5#</mathjax>, i.e. <mathjax>#log_10(10^-5)=-5#</mathjax>, alternatively <mathjax>#log_10(10^5)=+5#</mathjax>.</p> <p>What are <mathjax>#log_10(100), log_10(1000), log_10(1000000)??#</mathjax></p> <p>You shouldn't need a calculator, but use one if you don't see it straight off.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>In water <mathjax>#pH+pOH=14#</mathjax></p> <p><mathjax>#pH=14-pOH=14-5=9#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#pOH=-log_10[HO^-]#</mathjax> by definition.</p> <p>Thus <mathjax>#pOH=-log_10(1xx10^-5)=-(-5)=5#</mathjax></p> <p><mathjax>#pH+pOH=14#</mathjax></p> <p><mathjax>#pH=14-pOH=14-5=9#</mathjax></p> <p>When we write <mathjax>#log_ab=c#</mathjax>, we ask to what power we raise the base, <mathjax>#a#</mathjax>, to get <mathjax>#b#</mathjax>; here <mathjax>#a^c=b#</mathjax>. The normal bases are <mathjax>#10#</mathjax>, <mathjax>#"(common logarithms)"#</mathjax>, and <mathjax>#e#</mathjax>, <mathjax>#"(natural logarithms)"#</mathjax>.</p> <p>Thus when we write <mathjax>#log_10(10^-5)#</mathjax>, we are asking to what power we raise <mathjax>#10#</mathjax> to get <mathjax>#10^-5#</mathjax>. Now clearly the answer is <mathjax>#-5#</mathjax>, i.e. <mathjax>#log_10(10^-5)=-5#</mathjax>, alternatively <mathjax>#log_10(10^5)=+5#</mathjax>.</p> <p>What are <mathjax>#log_10(100), log_10(1000), log_10(1000000)??#</mathjax></p> <p>You shouldn't need a calculator, but use one if you don't see it straight off.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the pH of a #1.0 x 10^-5# M solution of NaOH?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/the-ph-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">pH</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="345371" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-12-02T04:18:35" itemprop="dateCreated"> Dec 2, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>In water <mathjax>#pH+pOH=14#</mathjax></p> <p><mathjax>#pH=14-pOH=14-5=9#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#pOH=-log_10[HO^-]#</mathjax> by definition.</p> <p>Thus <mathjax>#pOH=-log_10(1xx10^-5)=-(-5)=5#</mathjax></p> <p><mathjax>#pH+pOH=14#</mathjax></p> <p><mathjax>#pH=14-pOH=14-5=9#</mathjax></p> <p>When we write <mathjax>#log_ab=c#</mathjax>, we ask to what power we raise the base, <mathjax>#a#</mathjax>, to get <mathjax>#b#</mathjax>; here <mathjax>#a^c=b#</mathjax>. The normal bases are <mathjax>#10#</mathjax>, <mathjax>#"(common logarithms)"#</mathjax>, and <mathjax>#e#</mathjax>, <mathjax>#"(natural logarithms)"#</mathjax>.</p> <p>Thus when we write <mathjax>#log_10(10^-5)#</mathjax>, we are asking to what power we raise <mathjax>#10#</mathjax> to get <mathjax>#10^-5#</mathjax>. Now clearly the answer is <mathjax>#-5#</mathjax>, i.e. <mathjax>#log_10(10^-5)=-5#</mathjax>, alternatively <mathjax>#log_10(10^5)=+5#</mathjax>.</p> <p>What are <mathjax>#log_10(100), log_10(1000), log_10(1000000)??#</mathjax></p> <p>You shouldn't need a calculator, but use one if you don't see it straight off.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/345371" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-pka"> How do you determine pH from pKa? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-ph-values-of-acids-and-bases-differ"> How do pH values of acids and bases differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-something-on-a-ph-scale"> How do you calculate something on a pH scale? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-diprotic-acid"> How do you calculate pH diprotic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-from-acid-dissociation-constant"> How do you calculate pH from acid dissociation constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-of-acid-and-base-solution"> How do you calculate pH of acid and base solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ph-scale-0-14"> Why is the pH scale 0-14? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-ph-the-measure-of-the-hydrogen-ion-concentration"> Is pH a measure of the hydrogen ion concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-solubility-affect-ph"> How does solubility affect pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-ph-relate-to-pka-in-a-titration"> How does pH relate to pKa in a titration? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/the-ph-concept"> See all questions in pH </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 38615 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the pH of a #1.0 x 10^-5# M solution of NaOH?	null
1,741	ac0bc96c-6ddd-11ea-8ea1-ccda262736ce	https://socratic.org/questions/if-a-sample-of-gas-occupies-6-80-l-at-325-c-what-will-be-its-volume-at-25-c-if-t	3.39 L	start physical_unit 2 4 volume l qc_end physical_unit 2 4 6 7 volume qc_end physical_unit 2 4 9 10 temperature qc_end physical_unit 2 4 17 18 temperature qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Volume2 [OF] the gas sample [IN] L"}]	[{"type":"physical unit","value":"3.39 L"}]	[{"type":"physical unit","value":"Volume1 [OF] the gas sample [=] \\pu{6.80 L}"},{"type":"physical unit","value":"Temperature1 [OF] the gas sample [=] \\pu{325 ℃}"},{"type":"physical unit","value":"Temperature2 [OF] the gas sample [=] \\pu{25 ℃}"},{"type":"other","value":"The pressure does not change."}]	<h1 class="questionTitle" itemprop="name">If a sample of gas occupies 6.80 L at 325°C, what will be its volume at 25°C if the pressure does not change?</h1>	null	3.39 L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Even without doing any calculations, you should be able to look at the values given to you and predict that the volume of the gas will <strong>decrease</strong> as temperature <em>decreases</em>. </p> <p>When pressure and number of moles of gas are <strong>held constant</strong>, the volume of a gas and its temperature have a <strong>direct relationship</strong> - this is known as <strong><a href="http://socratic.org/chemistry/the-behavior-of-gases/charles-law">Charles' Law</a></strong>. </p> <p>As you know, <a href="http://socratic.org/chemistry/the-behavior-of-gases/gas-pressure">gas pressure</a> is caused by the collisions that take place between the molecules of gas and the walls of the container. </p> <p>The <strong>more powerful and frequent</strong> these collisions are, the <strong>higher</strong> the pressure of the gas. </p> <p>Now, temperature is a measure of the <em>average kinetic energy</em> of the gas molecules. When you <strong>decrease</strong> temperature, you're essentially decreasing the average speed with which these molecules hit the walls of the container. </p> <p>Because molecules are hitting the walls of the container with <em>less force</em>, you need these collisions to be <strong>more frequent</strong> in order for pressure to be <strong>constant</strong>. </p> <p>This means that the volume of the gas must <strong>decrease</strong> as well, since the same number of molecules in a <em>smaller volume</em> will result in more frequent collisions with the walls of the container. </p> <p>So, when temperature <em>decreases</em>, volume <strong>decreases</strong> as well. </p> <p><img alt="https://saylordotorg.github.io/text_introductory-chemistry/s10-03-gas-laws.html" src="https://useruploads.socratic.org/AkNrO1tpSPaXMhnWRVLw_47356453c6e8c28b4aef25ea63139f7b.jpg"/> </p> <p>Mathematically, this is written as </p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a)V_1/T_1 = V_2/T_2color(white)(a/a)\|)))" "#</mathjax>, where</p> </blockquote> <p><mathjax>#V_1#</mathjax>, <mathjax>#T_1#</mathjax> - the volume and temperature of the gas at an initial state<br/> <mathjax>#V_2#</mathjax>, <mathjax>#T_2#</mathjax> - the volume and temperature of the gas at a final state</p> <p>Now, it's <strong>very important</strong> to remember that you must use <strong>absolute temperature</strong>, i.e. the temperature expressed in <em>Kelvin</em>. </p> <p>To go from <em>degrees Celsius</em> to <em>Kelvin</em>, use the conversion factor</p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a)T["K"] = t[""^@"C"] + 273.15color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>So, rearrange the equation for <a href="http://socratic.org/chemistry/the-behavior-of-gases/charles-law">Charles' Law</a> and solve for <mathjax>#V_2#</mathjax></p> <blockquote> <p><mathjax>#V_1/T_1 = V_2/T_2 implies V_2 = T_2/T_1 * V_1#</mathjax></p> </blockquote> <p>Plug in your values to get</p> <blockquote> <p><mathjax>#V_2 = ((273.15 + 25)color(red)(cancel(color(black)("K"))))/((273.15 + 325)color(red)(cancel(color(black)("K")))) * "6.80 L" = "3.3895 L"#</mathjax></p> </blockquote> <p>You need to round this off to two <strong><a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the final temperature of the gas</p> <blockquote> <p><mathjax>#V_2 = color(green)(\|bar(ul(color(white)(a/a)"3.4 L"color(white)(a/a)\|)))#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"3.4 L"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Even without doing any calculations, you should be able to look at the values given to you and predict that the volume of the gas will <strong>decrease</strong> as temperature <em>decreases</em>. </p> <p>When pressure and number of moles of gas are <strong>held constant</strong>, the volume of a gas and its temperature have a <strong>direct relationship</strong> - this is known as <strong><a href="http://socratic.org/chemistry/the-behavior-of-gases/charles-law">Charles' Law</a></strong>. </p> <p>As you know, <a href="http://socratic.org/chemistry/the-behavior-of-gases/gas-pressure">gas pressure</a> is caused by the collisions that take place between the molecules of gas and the walls of the container. </p> <p>The <strong>more powerful and frequent</strong> these collisions are, the <strong>higher</strong> the pressure of the gas. </p> <p>Now, temperature is a measure of the <em>average kinetic energy</em> of the gas molecules. When you <strong>decrease</strong> temperature, you're essentially decreasing the average speed with which these molecules hit the walls of the container. </p> <p>Because molecules are hitting the walls of the container with <em>less force</em>, you need these collisions to be <strong>more frequent</strong> in order for pressure to be <strong>constant</strong>. </p> <p>This means that the volume of the gas must <strong>decrease</strong> as well, since the same number of molecules in a <em>smaller volume</em> will result in more frequent collisions with the walls of the container. </p> <p>So, when temperature <em>decreases</em>, volume <strong>decreases</strong> as well. </p> <p><img alt="https://saylordotorg.github.io/text_introductory-chemistry/s10-03-gas-laws.html" src="https://useruploads.socratic.org/AkNrO1tpSPaXMhnWRVLw_47356453c6e8c28b4aef25ea63139f7b.jpg"/> </p> <p>Mathematically, this is written as </p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a)V_1/T_1 = V_2/T_2color(white)(a/a)\|)))" "#</mathjax>, where</p> </blockquote> <p><mathjax>#V_1#</mathjax>, <mathjax>#T_1#</mathjax> - the volume and temperature of the gas at an initial state<br/> <mathjax>#V_2#</mathjax>, <mathjax>#T_2#</mathjax> - the volume and temperature of the gas at a final state</p> <p>Now, it's <strong>very important</strong> to remember that you must use <strong>absolute temperature</strong>, i.e. the temperature expressed in <em>Kelvin</em>. </p> <p>To go from <em>degrees Celsius</em> to <em>Kelvin</em>, use the conversion factor</p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a)T["K"] = t[""^@"C"] + 273.15color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>So, rearrange the equation for <a href="http://socratic.org/chemistry/the-behavior-of-gases/charles-law">Charles' Law</a> and solve for <mathjax>#V_2#</mathjax></p> <blockquote> <p><mathjax>#V_1/T_1 = V_2/T_2 implies V_2 = T_2/T_1 * V_1#</mathjax></p> </blockquote> <p>Plug in your values to get</p> <blockquote> <p><mathjax>#V_2 = ((273.15 + 25)color(red)(cancel(color(black)("K"))))/((273.15 + 325)color(red)(cancel(color(black)("K")))) * "6.80 L" = "3.3895 L"#</mathjax></p> </blockquote> <p>You need to round this off to two <strong><a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the final temperature of the gas</p> <blockquote> <p><mathjax>#V_2 = color(green)(\|bar(ul(color(white)(a/a)"3.4 L"color(white)(a/a)\|)))#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">If a sample of gas occupies 6.80 L at 325°C, what will be its volume at 25°C if the pressure does not change?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/charles-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Charles' Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="236509" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-07T20:37:17" itemprop="dateCreated"> Mar 7, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"3.4 L"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Even without doing any calculations, you should be able to look at the values given to you and predict that the volume of the gas will <strong>decrease</strong> as temperature <em>decreases</em>. </p> <p>When pressure and number of moles of gas are <strong>held constant</strong>, the volume of a gas and its temperature have a <strong>direct relationship</strong> - this is known as <strong><a href="http://socratic.org/chemistry/the-behavior-of-gases/charles-law">Charles' Law</a></strong>. </p> <p>As you know, <a href="http://socratic.org/chemistry/the-behavior-of-gases/gas-pressure">gas pressure</a> is caused by the collisions that take place between the molecules of gas and the walls of the container. </p> <p>The <strong>more powerful and frequent</strong> these collisions are, the <strong>higher</strong> the pressure of the gas. </p> <p>Now, temperature is a measure of the <em>average kinetic energy</em> of the gas molecules. When you <strong>decrease</strong> temperature, you're essentially decreasing the average speed with which these molecules hit the walls of the container. </p> <p>Because molecules are hitting the walls of the container with <em>less force</em>, you need these collisions to be <strong>more frequent</strong> in order for pressure to be <strong>constant</strong>. </p> <p>This means that the volume of the gas must <strong>decrease</strong> as well, since the same number of molecules in a <em>smaller volume</em> will result in more frequent collisions with the walls of the container. </p> <p>So, when temperature <em>decreases</em>, volume <strong>decreases</strong> as well. </p> <p><img alt="https://saylordotorg.github.io/text_introductory-chemistry/s10-03-gas-laws.html" src="https://useruploads.socratic.org/AkNrO1tpSPaXMhnWRVLw_47356453c6e8c28b4aef25ea63139f7b.jpg"/> </p> <p>Mathematically, this is written as </p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a)V_1/T_1 = V_2/T_2color(white)(a/a)\|)))" "#</mathjax>, where</p> </blockquote> <p><mathjax>#V_1#</mathjax>, <mathjax>#T_1#</mathjax> - the volume and temperature of the gas at an initial state<br/> <mathjax>#V_2#</mathjax>, <mathjax>#T_2#</mathjax> - the volume and temperature of the gas at a final state</p> <p>Now, it's <strong>very important</strong> to remember that you must use <strong>absolute temperature</strong>, i.e. the temperature expressed in <em>Kelvin</em>. </p> <p>To go from <em>degrees Celsius</em> to <em>Kelvin</em>, use the conversion factor</p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a)T["K"] = t[""^@"C"] + 273.15color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>So, rearrange the equation for <a href="http://socratic.org/chemistry/the-behavior-of-gases/charles-law">Charles' Law</a> and solve for <mathjax>#V_2#</mathjax></p> <blockquote> <p><mathjax>#V_1/T_1 = V_2/T_2 implies V_2 = T_2/T_1 * V_1#</mathjax></p> </blockquote> <p>Plug in your values to get</p> <blockquote> <p><mathjax>#V_2 = ((273.15 + 25)color(red)(cancel(color(black)("K"))))/((273.15 + 325)color(red)(cancel(color(black)("K")))) * "6.80 L" = "3.3895 L"#</mathjax></p> </blockquote> <p>You need to round this off to two <strong><a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the final temperature of the gas</p> <blockquote> <p><mathjax>#V_2 = color(green)(\|bar(ul(color(white)(a/a)"3.4 L"color(white)(a/a)\|)))#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/236509" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-must-charles-law-be-in-kelvins"> Why must Charles' law be in kelvin? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-charles-law-formula"> What is Charles' law formula? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/oxygen-gas-is-at-a-temperature-of-40-c-when-it-occupies-a-volume-of-2-3-liters-t"> Oxygen gas is at a temperature of 40°C when it occupies a volume of 2.3 liters. 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1,742	ab6b7f06-6ddd-11ea-87b5-ccda262736ce	https://socratic.org/questions/what-is-the-molarity-of-a-solution-that-contains-0-00372-moles-hydrochloric-acid	1.56 × 10^(-5) M	start physical_unit 11 12 molarity mol/l qc_end physical_unit 6 6 14 17 volume qc_end physical_unit 11 12 9 10 mole qc_end end	[{"type":"physical unit","value":"Molarity [OF] hydrochloric acid solution [IN] M"}]	[{"type":"physical unit","value":"1.56 × 10^(-5) M"}]	[{"type":"physical unit","value":"Volume [OF] hydrochloric acid solution [=] \\pu{2.39 × 10^2 liters}"},{"type":"physical unit","value":"Mole [OF] hydrochloric acid [=] \\pu{0.00372 moles}"}]	<h1 class="questionTitle" itemprop="name">What is the molarity of a solution that contains 0.00372 moles hydrochloric acid in #2.39 times 10^2# liters of solution?</h1>	null	1.56 × 10^(-5) M	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To find the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of this solution, we have to use the equation below:<br/> <img alt="https://www.bing.com/images/search?view=detailV2&ccid=xdOyDgVa&id=81912BA1AAF426EB0252A2EDCBDD4DDA43CD1CA6&thid=OIP.xdOyDgVaJhHGXUoFSo8lhwEsA6&q=molarity+equation&simid=607989739330404602&selectedIndex=46&ajaxhist=0" src="https://useruploads.socratic.org/FG9FqBdKQetJo3TtjISQ_molality_16.jpg"/> </p> <p>Let's list our known and unknown values:</p> <p><mathjax>#color(magenta)"Knowns:"#</mathjax><br/> - Moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> (0.00372 mol)<br/> - Volume of solution (239 L)</p> <p><mathjax>#color(brown)"Unknowns:"#</mathjax><br/> - Molarity of Solution M or <mathjax>#"mol"/"L"#</mathjax></p> <p>Since we know the moles of solute and volume of solution, all we have to do is divide the moles of solute by the volume of solution to obtain the molarity:</p> <p>Molarity = <mathjax>#"0.00372 mol"/"239L"#</mathjax></p> <p><mathjax>#color(red) "Molarity"#</mathjax> = <mathjax>#1.56xx10^-5 M"#</mathjax> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1.56xx10^-5 M"#</mathjax> </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To find the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of this solution, we have to use the equation below:<br/> <img alt="https://www.bing.com/images/search?view=detailV2&ccid=xdOyDgVa&id=81912BA1AAF426EB0252A2EDCBDD4DDA43CD1CA6&thid=OIP.xdOyDgVaJhHGXUoFSo8lhwEsA6&q=molarity+equation&simid=607989739330404602&selectedIndex=46&ajaxhist=0" src="https://useruploads.socratic.org/FG9FqBdKQetJo3TtjISQ_molality_16.jpg"/> </p> <p>Let's list our known and unknown values:</p> <p><mathjax>#color(magenta)"Knowns:"#</mathjax><br/> - Moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> (0.00372 mol)<br/> - Volume of solution (239 L)</p> <p><mathjax>#color(brown)"Unknowns:"#</mathjax><br/> - Molarity of Solution M or <mathjax>#"mol"/"L"#</mathjax></p> <p>Since we know the moles of solute and volume of solution, all we have to do is divide the moles of solute by the volume of solution to obtain the molarity:</p> <p>Molarity = <mathjax>#"0.00372 mol"/"239L"#</mathjax></p> <p><mathjax>#color(red) "Molarity"#</mathjax> = <mathjax>#1.56xx10^-5 M"#</mathjax> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the molarity of a solution that contains 0.00372 moles hydrochloric acid in #2.39 times 10^2# liters of solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="424691" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/kayla-14"><img alt="" class="" src="https://profilepictures.socratic.org/OvMTWaamQPWcqLIkUNnG_793604964071127.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/kayla-14"> Kayla </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-17T01:19:01" itemprop="dateCreated"> May 17, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1.56xx10^-5 M"#</mathjax> </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To find the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of this solution, we have to use the equation below:<br/> <img alt="https://www.bing.com/images/search?view=detailV2&ccid=xdOyDgVa&id=81912BA1AAF426EB0252A2EDCBDD4DDA43CD1CA6&thid=OIP.xdOyDgVaJhHGXUoFSo8lhwEsA6&q=molarity+equation&simid=607989739330404602&selectedIndex=46&ajaxhist=0" src="https://useruploads.socratic.org/FG9FqBdKQetJo3TtjISQ_molality_16.jpg"/> </p> <p>Let's list our known and unknown values:</p> <p><mathjax>#color(magenta)"Knowns:"#</mathjax><br/> - Moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> (0.00372 mol)<br/> - Volume of solution (239 L)</p> <p><mathjax>#color(brown)"Unknowns:"#</mathjax><br/> - Molarity of Solution M or <mathjax>#"mol"/"L"#</mathjax></p> <p>Since we know the moles of solute and volume of solution, all we have to do is divide the moles of solute by the volume of solution to obtain the molarity:</p> <p>Molarity = <mathjax>#"0.00372 mol"/"239L"#</mathjax></p> <p><mathjax>#color(red) "Molarity"#</mathjax> = <mathjax>#1.56xx10^-5 M"#</mathjax> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/424691" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-morality-be-used-as-a-conversion-factor"> How can molarity be used as a conversion factor? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-high-can-molarity-be"> How high can molarity be? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-molarity-change-with-temperature"> How does molarity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molarity-of-a-solution"> How do you find molarity of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-10-naoh"> What is the molarity of 10 NaOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-3-hydrogen-peroxide"> What is the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 6098 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the molarity of a solution that contains 0.00372 moles hydrochloric acid in #2.39 times 10^2# liters of solution?	null
1,743	ad245e80-6ddd-11ea-a6b0-ccda262736ce	https://socratic.org/questions/58e9970c11ef6b705701121b	860.18 torr	start physical_unit 1 3 pressure torr qc_end physical_unit 1 3 11 12 pressure qc_end physical_unit 1 3 5 6 temperature qc_end physical_unit 1 3 23 24 temperature qc_end end	[{"type":"physical unit","value":"Pressure2 [OF] gas sample [IN] torr"}]	[{"type":"physical unit","value":"860.18 torr"}]	[{"type":"physical unit","value":"Pressure1 [OF] gas sample [=] \\pu{745 torr}"},{"type":"physical unit","value":"Temperature1 [OF] gas sample [=] \\pu{31 ℃}"},{"type":"physical unit","value":"Temperature2 [OF] gas sample [=] \\pu{78 ℃}"}]	<h1 class="questionTitle" itemprop="name">A sample of gas at #"31"^@"C"# has a pressure of #"745 Torr"#. What is the pressure if the temperature is increased to #"78"^@"C"#?</h1>	null	860.18 torr	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is an example of <strong>Gay-Lussac's law</strong> , which states that the pressure of a gas with a constant volume and amount, is directly proportional to the temperature in Kelvins. This means that if the pressure is increased, the temperature will increase, and vice-versa.</p> <p>The equation that is used for this law is:</p> <p><mathjax>#P_1/T_1=P_2/T_2#</mathjax></p> <p>where <mathjax>#P_1#</mathjax> is the initial pressure, <mathjax>#P_2#</mathjax> is the final pressure, <mathjax>#T_1#</mathjax> is the initial temperature, <mathjax>#T_2#</mathjax> is the final temperature.</p> <p><strong>Write what is known.</strong><br/> <mathjax>#P_1="745 torr"#</mathjax><br/> <mathjax>#T_1="31"^@"C" + 273.15=304 "K"#</mathjax><br/> <mathjax>#T_2="78"^@"C" + 273.15=351 "K"#</mathjax></p> <p><strong>Write what is unknown:</strong> <mathjax>#P_2#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#P_2#</mathjax>. Substitute the known values into the equation and solve.</p> <p><mathjax>#P_2=(P_1T_2)/T_1#</mathjax></p> <p><mathjax>#P_2=(745"torr"xx351color(red)cancel(color(black)("K")))/(304color(red)cancel(color(black)("K")))="860. torr"#</mathjax> (rounded to three significant figures)</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The final pressure will be <mathjax>#"860. torr"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is an example of <strong>Gay-Lussac's law</strong> , which states that the pressure of a gas with a constant volume and amount, is directly proportional to the temperature in Kelvins. This means that if the pressure is increased, the temperature will increase, and vice-versa.</p> <p>The equation that is used for this law is:</p> <p><mathjax>#P_1/T_1=P_2/T_2#</mathjax></p> <p>where <mathjax>#P_1#</mathjax> is the initial pressure, <mathjax>#P_2#</mathjax> is the final pressure, <mathjax>#T_1#</mathjax> is the initial temperature, <mathjax>#T_2#</mathjax> is the final temperature.</p> <p><strong>Write what is known.</strong><br/> <mathjax>#P_1="745 torr"#</mathjax><br/> <mathjax>#T_1="31"^@"C" + 273.15=304 "K"#</mathjax><br/> <mathjax>#T_2="78"^@"C" + 273.15=351 "K"#</mathjax></p> <p><strong>Write what is unknown:</strong> <mathjax>#P_2#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#P_2#</mathjax>. Substitute the known values into the equation and solve.</p> <p><mathjax>#P_2=(P_1T_2)/T_1#</mathjax></p> <p><mathjax>#P_2=(745"torr"xx351color(red)cancel(color(black)("K")))/(304color(red)cancel(color(black)("K")))="860. torr"#</mathjax> (rounded to three significant figures)</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A sample of gas at #"31"^@"C"# has a pressure of #"745 Torr"#. What is the pressure if the temperature is increased to #"78"^@"C"#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/gay-lussac-s-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Gay Lussac's Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="403912" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-09T02:48:50" itemprop="dateCreated"> Apr 9, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The final pressure will be <mathjax>#"860. torr"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is an example of <strong>Gay-Lussac's law</strong> , which states that the pressure of a gas with a constant volume and amount, is directly proportional to the temperature in Kelvins. This means that if the pressure is increased, the temperature will increase, and vice-versa.</p> <p>The equation that is used for this law is:</p> <p><mathjax>#P_1/T_1=P_2/T_2#</mathjax></p> <p>where <mathjax>#P_1#</mathjax> is the initial pressure, <mathjax>#P_2#</mathjax> is the final pressure, <mathjax>#T_1#</mathjax> is the initial temperature, <mathjax>#T_2#</mathjax> is the final temperature.</p> <p><strong>Write what is known.</strong><br/> <mathjax>#P_1="745 torr"#</mathjax><br/> <mathjax>#T_1="31"^@"C" + 273.15=304 "K"#</mathjax><br/> <mathjax>#T_2="78"^@"C" + 273.15=351 "K"#</mathjax></p> <p><strong>Write what is unknown:</strong> <mathjax>#P_2#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#P_2#</mathjax>. Substitute the known values into the equation and solve.</p> <p><mathjax>#P_2=(P_1T_2)/T_1#</mathjax></p> <p><mathjax>#P_2=(745"torr"xx351color(red)cancel(color(black)("K")))/(304color(red)cancel(color(black)("K")))="860. torr"#</mathjax> (rounded to three significant figures)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/403912" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="403913" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/scooke"><img alt="" class="" src="https://profilepictures.socratic.org/ezAzqDkjRS6NXBmMH3lg_BioPic2010a.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/scooke"> SCooke </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-09T02:50:15" itemprop="dateCreated"> Apr 9, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#P_2 = 860#</mathjax> torr</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>With a constant container volume, <a href="https://socratic.org/chemistry/the-behavior-of-gases/charles-law">Charles' Law</a> becomes simply:<br/> <mathjax>#P_1/T_1 = P_2/T_2#</mathjax><br/> Rearrange for your known values:</p> <p><mathjax>#P_2 = P_1 * T_2/T_1#</mathjax> ; <mathjax>#P_2 = 745 * 351/304#</mathjax> ; <mathjax>#P_2 = 860#</mathjax> torr</p> <p>The <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> (Charles' Law) states:<br/> <mathjax>#(P_1 * V_1)/T_1 = (P_2 * V_2)/T_2#</mathjax><br/> Where <mathjax>#P_1,_2#</mathjax> are pressures – units don't matter in this case as long as they are consistent, because this is a ratio.<br/> <mathjax>#V_1,_2#</mathjax> are the corresponding volumes in Liters<br/> <mathjax>#T_1,_2#</mathjax> are the temperatures in degrees Kelvin</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/403913" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535d701102bf342f53d9bcb0"> Question #9bcb0 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-gay-lussac-s-law-formula"> What is the Gay Lussac's law formula? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-the-temperature-of-a-gas-in-a-container-is-doubled-on-the-kelvin-scale-the-pr"> If the temperature of a gas in a container is doubled on the Kelvin scale, what will happen to... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-the-original-pressure-of-a-gas-sample-at-20-c-was-5-00-atm-and-it-is-heated-u"> If the original pressure of a gas sample at 20 ˚C was 5.00 atm, and it is heated up to 40. ˚C ,... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-gay-lussac-s-law-state"> What does Gay Lussac's law state? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-gay-lussac-s-law-relate"> What does Gay Lussac's law relate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-sample-of-o2-under-2-00-atm-occupies-500-ml-at-25-0-c-what-pressure-will-the-s"> A sample of O2 under 2.00 atm occupies 500 ml at 25.0˚C. 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What is the pressure if the temperature is increased to #"78"^@"C"#?	null
1,744	a9656383-6ddd-11ea-bb85-ccda262736ce	https://socratic.org/questions/what-mass-will-33-6-l-of-chlorine-gas-have-at-stp	104.87 g	start physical_unit 3 3 mass g qc_end physical_unit 3 3 5 6 volume qc_end c_other STP qc_end end	[{"type":"physical unit","value":"Mass [OF] chlorine [IN] g"}]	[{"type":"physical unit","value":"104.87 g"}]	[{"type":"physical unit","value":"Volume [OF] chlorine [=] \\pu{33.6 L}"},{"type":"other","value":"STP"}]	<h1 class="questionTitle" itemprop="name">What mass of chlorine occupies 33.6 L at STP?</h1>	null	104.87 g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>For starters, you should know that <strong>STP conditions</strong> are defined as a pressure of <mathjax>#"100 kPa"#</mathjax> and a temperature of <mathjax>#0^@"C"#</mathjax>. </p> <p>Under these conditions, <mathjax>#1#</mathjax> <strong>mole</strong> of any ideal gas occupies <mathjax>#"22.72 L"#</mathjax>. In other words, the <em><a href="https://socratic.org/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp">molar volume of a gas</a> at STP</em>, i.e. the volume occupied by <mathjax>#1#</mathjax> <strong>mole</strong> of gas, is equal to <mathjax>#"22.72 L"#</mathjax>. </p> <blockquote> <p><mathjax>#"1 mole ideal gas " stackrel(color(white)(acolor(red)("STP conditions")aaa))(color(blue)(->)) " 22.72 L"#</mathjax></p> </blockquote> <p>So, the first thing to do here is to figure out the number of <em>moles</em> of chlorine gas, <mathjax>#"Cl"_2#</mathjax>, present in your sample. </p> <p>To do that, use the molar volume of a gas at STP</p> <blockquote> <p><mathjax>#33.6 color(red)(cancel(color(black)("L"))) * "1 mole Cl"_2/(22.72color(red)(cancel(color(black)("L")))) = "1.479 moles Cl"_2#</mathjax></p> </blockquote> <p>To convert this to <em>grams</em>, sue the <strong>molar mass</strong> of chlorine gas</p> <blockquote> <p><mathjax>#1.479 color(red)(cancel(color(black)("moles Cl"_2))) * "70.906 g"/(1color(red)(cancel(color(black)("mole Cl"_2)))) = color(darkgreen)(ul(color(black)("105 g")))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the volume of the gas. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"105 g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>For starters, you should know that <strong>STP conditions</strong> are defined as a pressure of <mathjax>#"100 kPa"#</mathjax> and a temperature of <mathjax>#0^@"C"#</mathjax>. </p> <p>Under these conditions, <mathjax>#1#</mathjax> <strong>mole</strong> of any ideal gas occupies <mathjax>#"22.72 L"#</mathjax>. In other words, the <em><a href="https://socratic.org/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp">molar volume of a gas</a> at STP</em>, i.e. the volume occupied by <mathjax>#1#</mathjax> <strong>mole</strong> of gas, is equal to <mathjax>#"22.72 L"#</mathjax>. </p> <blockquote> <p><mathjax>#"1 mole ideal gas " stackrel(color(white)(acolor(red)("STP conditions")aaa))(color(blue)(->)) " 22.72 L"#</mathjax></p> </blockquote> <p>So, the first thing to do here is to figure out the number of <em>moles</em> of chlorine gas, <mathjax>#"Cl"_2#</mathjax>, present in your sample. </p> <p>To do that, use the molar volume of a gas at STP</p> <blockquote> <p><mathjax>#33.6 color(red)(cancel(color(black)("L"))) * "1 mole Cl"_2/(22.72color(red)(cancel(color(black)("L")))) = "1.479 moles Cl"_2#</mathjax></p> </blockquote> <p>To convert this to <em>grams</em>, sue the <strong>molar mass</strong> of chlorine gas</p> <blockquote> <p><mathjax>#1.479 color(red)(cancel(color(black)("moles Cl"_2))) * "70.906 g"/(1color(red)(cancel(color(black)("mole Cl"_2)))) = color(darkgreen)(ul(color(black)("105 g")))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the volume of the gas. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What mass of chlorine occupies 33.6 L at STP?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp" itemprop="url"> <span class="breadcrumb" itemprop="title">Molar Volume of a Gas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="440404" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-15T23:15:13" itemprop="dateCreated"> Jun 15, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"105 g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>For starters, you should know that <strong>STP conditions</strong> are defined as a pressure of <mathjax>#"100 kPa"#</mathjax> and a temperature of <mathjax>#0^@"C"#</mathjax>. </p> <p>Under these conditions, <mathjax>#1#</mathjax> <strong>mole</strong> of any ideal gas occupies <mathjax>#"22.72 L"#</mathjax>. In other words, the <em><a href="https://socratic.org/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp">molar volume of a gas</a> at STP</em>, i.e. the volume occupied by <mathjax>#1#</mathjax> <strong>mole</strong> of gas, is equal to <mathjax>#"22.72 L"#</mathjax>. </p> <blockquote> <p><mathjax>#"1 mole ideal gas " stackrel(color(white)(acolor(red)("STP conditions")aaa))(color(blue)(->)) " 22.72 L"#</mathjax></p> </blockquote> <p>So, the first thing to do here is to figure out the number of <em>moles</em> of chlorine gas, <mathjax>#"Cl"_2#</mathjax>, present in your sample. </p> <p>To do that, use the molar volume of a gas at STP</p> <blockquote> <p><mathjax>#33.6 color(red)(cancel(color(black)("L"))) * "1 mole Cl"_2/(22.72color(red)(cancel(color(black)("L")))) = "1.479 moles Cl"_2#</mathjax></p> </blockquote> <p>To convert this to <em>grams</em>, sue the <strong>molar mass</strong> of chlorine gas</p> <blockquote> <p><mathjax>#1.479 color(red)(cancel(color(black)("moles Cl"_2))) * "70.906 g"/(1color(red)(cancel(color(black)("mole Cl"_2)))) = color(darkgreen)(ul(color(black)("105 g")))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the volume of the gas. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/440404" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-stoichiometric-ratios-relate-to-molar-volume-of-a-gas"> How do stoichiometric ratios relate to molar volume of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-a-gas-at-stp"> How do you calculate molar volume of a gas at STP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-molar-volume-of-hydrogen-gas"> How do you find the molar volume of hydrogen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-oxygen-gas"> How do you calculate molar volume of oxygen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molar-gas-volume"> What is molar gas volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/534c7bf202bf3420a007f014"> What is the volume at 0 °C and 1 atm of a mixture that contains 4.0 g of methane and 2.0 g of helium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5361f75702bf3429040e0599"> What is the difference between STP and NTP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-volume-of-25-moles-of-oxygen-o2-gas"> What is the volume of .25 moles of oxygen (O2) Gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-would-knowing-the-molar-volume-of-a-gas-be-important"> Why would knowing the molar volume of a gas be important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-22-4-liters-called-the-molar-volume-of-a-gas"> Why is 22.4 liters called the molar volume of a gas? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp"> See all questions in Molar Volume of a Gas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 11122 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What mass of chlorine occupies 33.6 L at STP?	null
1,745	a947da40-6ddd-11ea-be37-ccda262736ce	https://socratic.org/questions/a-hydrogen-atom-is-84-carbon-by-mass-its-relative-molecular-mass-is-100-what-is-	C7H16	start chemical_formula qc_end physical_unit 1 1 12 13 relative_molecular_weight qc_end end	[{"type":"other","value":"Chemical Formula [OF] hydrocarbon [IN] empirical"}]	[{"type":"chemical equation","value":"C7H16"}]	[{"type":"physical unit","value":"Percentage by mass [OF] carbon in hydrocarbon [=] \\pu{84%}"},{"type":"physical unit","value":"Relative molecular mass [OF] hydrocarbon [=] \\pu{100 g/mol}"}]	<h1 class="questionTitle" itemprop="name">A hydrogen atom is 84% carbon, by mass. Its relative molecular mass is 100. What is it's empirical formula? </h1>	null	C7H16	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>If that is what the question said, then the empirical formula of the hydrocarbon is <mathjax>#C_7H_16#</mathjax>. How do we know?</p> <p><mathjax>#(i)#</mathjax> We assume a mass of <mathjax>#100g#</mathjax> of hydrocarbon.</p> <p><mathjax>#(ii)#</mathjax> We work out its atomic composition on the basis of the atomic percentages:</p> <p><mathjax>#"Moles of carbon"#</mathjax> <mathjax>#-=#</mathjax> <mathjax>#(84.0g)/(12.01gmol^-1)=7mol#</mathjax></p> <p><mathjax>#"Moles of hydrogen"#</mathjax> <mathjax>#-=#</mathjax> <mathjax>#(16.0g)/(1.00794gmol^-1)=16mol#</mathjax></p> <p>How did I know that there were <mathjax>#16g#</mathjax> of hydrogen based solely on the GIVEN <mathjax>#"% percentage composition of carbon?"#</mathjax></p> <p>On this basis, the empirical formula, the simplest whole number representing constituent atoms in a species is <mathjax>#C_7H_16#</mathjax>. Clearly the molecular formula is identical. </p> <p>It is a fact that the <mathjax>#"molecular formula"#</mathjax> is always a whole number multiple of the <mathjax>#"empirical formula"#</mathjax>. </p> <p>Thus <mathjax>#"molecular formula"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#nxx"empirical formula"#</mathjax>. But we have been given an estimate of molecular mass. So.............</p> <p>So <mathjax>#100"amu"-=(C_7H_16)xxn#</mathjax></p> <p>Thus <mathjax>#100"amu"-=(7xx12.011+16xx1.00794)*"amu"xxn#</mathjax></p> <p>We solve for <mathjax>#n#</mathjax> (how), and find <mathjax>#n-=1#</mathjax>.</p> <p><mathjax>#"And thus the molecular formula"-=C_7H_16#</mathjax>.</p> <p>See <a href="https://socratic.org/questions/saccharin-has-the-composition-45-90-c-2-75-h-26-20-o-17-50-s-and-7-65-n-what-is-">here for another example.</a> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"A hydrocarbon is 84% carbon by mass..........."#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>If that is what the question said, then the empirical formula of the hydrocarbon is <mathjax>#C_7H_16#</mathjax>. How do we know?</p> <p><mathjax>#(i)#</mathjax> We assume a mass of <mathjax>#100g#</mathjax> of hydrocarbon.</p> <p><mathjax>#(ii)#</mathjax> We work out its atomic composition on the basis of the atomic percentages:</p> <p><mathjax>#"Moles of carbon"#</mathjax> <mathjax>#-=#</mathjax> <mathjax>#(84.0g)/(12.01gmol^-1)=7mol#</mathjax></p> <p><mathjax>#"Moles of hydrogen"#</mathjax> <mathjax>#-=#</mathjax> <mathjax>#(16.0g)/(1.00794gmol^-1)=16mol#</mathjax></p> <p>How did I know that there were <mathjax>#16g#</mathjax> of hydrogen based solely on the GIVEN <mathjax>#"% percentage composition of carbon?"#</mathjax></p> <p>On this basis, the empirical formula, the simplest whole number representing constituent atoms in a species is <mathjax>#C_7H_16#</mathjax>. Clearly the molecular formula is identical. </p> <p>It is a fact that the <mathjax>#"molecular formula"#</mathjax> is always a whole number multiple of the <mathjax>#"empirical formula"#</mathjax>. </p> <p>Thus <mathjax>#"molecular formula"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#nxx"empirical formula"#</mathjax>. But we have been given an estimate of molecular mass. So.............</p> <p>So <mathjax>#100"amu"-=(C_7H_16)xxn#</mathjax></p> <p>Thus <mathjax>#100"amu"-=(7xx12.011+16xx1.00794)*"amu"xxn#</mathjax></p> <p>We solve for <mathjax>#n#</mathjax> (how), and find <mathjax>#n-=1#</mathjax>.</p> <p><mathjax>#"And thus the molecular formula"-=C_7H_16#</mathjax>.</p> <p>See <a href="https://socratic.org/questions/saccharin-has-the-composition-45-90-c-2-75-h-26-20-o-17-50-s-and-7-65-n-what-is-">here for another example.</a> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A hydrogen atom is 84% carbon, by mass. Its relative molecular mass is 100. What is it's empirical formula? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="381683" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-02-23T02:57:55" itemprop="dateCreated"> Feb 23, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"A hydrocarbon is 84% carbon by mass..........."#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>If that is what the question said, then the empirical formula of the hydrocarbon is <mathjax>#C_7H_16#</mathjax>. How do we know?</p> <p><mathjax>#(i)#</mathjax> We assume a mass of <mathjax>#100g#</mathjax> of hydrocarbon.</p> <p><mathjax>#(ii)#</mathjax> We work out its atomic composition on the basis of the atomic percentages:</p> <p><mathjax>#"Moles of carbon"#</mathjax> <mathjax>#-=#</mathjax> <mathjax>#(84.0g)/(12.01gmol^-1)=7mol#</mathjax></p> <p><mathjax>#"Moles of hydrogen"#</mathjax> <mathjax>#-=#</mathjax> <mathjax>#(16.0g)/(1.00794gmol^-1)=16mol#</mathjax></p> <p>How did I know that there were <mathjax>#16g#</mathjax> of hydrogen based solely on the GIVEN <mathjax>#"% percentage composition of carbon?"#</mathjax></p> <p>On this basis, the empirical formula, the simplest whole number representing constituent atoms in a species is <mathjax>#C_7H_16#</mathjax>. Clearly the molecular formula is identical. </p> <p>It is a fact that the <mathjax>#"molecular formula"#</mathjax> is always a whole number multiple of the <mathjax>#"empirical formula"#</mathjax>. </p> <p>Thus <mathjax>#"molecular formula"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#nxx"empirical formula"#</mathjax>. But we have been given an estimate of molecular mass. So.............</p> <p>So <mathjax>#100"amu"-=(C_7H_16)xxn#</mathjax></p> <p>Thus <mathjax>#100"amu"-=(7xx12.011+16xx1.00794)*"amu"xxn#</mathjax></p> <p>We solve for <mathjax>#n#</mathjax> (how), and find <mathjax>#n-=1#</mathjax>.</p> <p><mathjax>#"And thus the molecular formula"-=C_7H_16#</mathjax>.</p> <p>See <a href="https://socratic.org/questions/saccharin-has-the-composition-45-90-c-2-75-h-26-20-o-17-50-s-and-7-65-n-what-is-">here for another example.</a> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/381683" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molecular-formula-of-a-compound"> How do you find molecular formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-diamond"> What is the chemical formula of a diamond? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-carbohydrate"> What is the chemical formula of a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-valproic-acid"> What is the empirical formula for valproic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-of-magnesium-oxide"> What is the empirical formula of magnesium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-empirical-formula-not-double-that-of-the-monosaccharides"> Why is the empirical formula not double that of the monosaccharides? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5331180502bf342f40b5c3b5"> Question #5c3b5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-molecular-formula-represents-a-carbohydrate"> What molecular formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-of-vinegar"> What is the molecular formula of vinegar? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/empirical-and-molecular-formulas"> See all questions in Empirical and Molecular Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 10763 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A hydrogen atom is 84% carbon, by mass. Its relative molecular mass is 100. What is it's empirical formula?	null
1,746	aaf03ce4-6ddd-11ea-b1b9-ccda262736ce	https://socratic.org/questions/if-26-35332-grams-of-ca-is-reacted-how-many-moles-of-calcium-oxide-are-produced	0.66 moles	start physical_unit 11 12 mole mol qc_end physical_unit 4 4 1 2 mass qc_end end	[{"type":"physical unit","value":"Mole [OF] Calcium Oxide [IN] moles"}]	[{"type":"physical unit","value":"0.66 moles"}]	[{"type":"physical unit","value":"Mass [OF] Ca [=] \\pu{26.35332 grams}"}]	<h1 class="questionTitle" itemprop="name">If 26.35332 grams of Ca is reacted, how many moles of Calcium Oxide are produced? </h1>	null	0.66 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>I'll assume it reacts with <em>excess</em> oxygen, and forms only calcium oxide. The chemical equation for this reaction is</p> <p><mathjax>#2"Ca" (s) + "O"_2 (g) rarr 2"CaO" (s)#</mathjax></p> <p>First let's calculate the number of moles of <mathjax>#"Ca"#</mathjax> that reacts, using its molar mass:</p> <p><mathjax>#26.35332cancel("g Ca")((1"mol Ca")/(40.08cancel("g Ca"))) = color(red)(0.6575180 "mol Ca"#</mathjax></p> <p>Now, let's use the stoichiometrically equivalent values (the coefficients) in the chemical equation to calculate the number of moles of <mathjax>#"CaO"#</mathjax>:</p> <p><mathjax>#0.6575180 cancel("mol Ca")((2"mol CaO")/(2cancel("mol Ca"))) = color(blue)(0.6575180 "mol CaO"#</mathjax></p> <p>Therefore, <mathjax>#0.6575180 "mol CaO"#</mathjax> will form.</p> <p>By the way, I've never seen <mathjax>#7#</mathjax> <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a> used in a problem before, I like it:)</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#0.6575180#</mathjax> <mathjax>#"mol CaO"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>I'll assume it reacts with <em>excess</em> oxygen, and forms only calcium oxide. The chemical equation for this reaction is</p> <p><mathjax>#2"Ca" (s) + "O"_2 (g) rarr 2"CaO" (s)#</mathjax></p> <p>First let's calculate the number of moles of <mathjax>#"Ca"#</mathjax> that reacts, using its molar mass:</p> <p><mathjax>#26.35332cancel("g Ca")((1"mol Ca")/(40.08cancel("g Ca"))) = color(red)(0.6575180 "mol Ca"#</mathjax></p> <p>Now, let's use the stoichiometrically equivalent values (the coefficients) in the chemical equation to calculate the number of moles of <mathjax>#"CaO"#</mathjax>:</p> <p><mathjax>#0.6575180 cancel("mol Ca")((2"mol CaO")/(2cancel("mol Ca"))) = color(blue)(0.6575180 "mol CaO"#</mathjax></p> <p>Therefore, <mathjax>#0.6575180 "mol CaO"#</mathjax> will form.</p> <p>By the way, I've never seen <mathjax>#7#</mathjax> <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a> used in a problem before, I like it:)</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">If 26.35332 grams of Ca is reacted, how many moles of Calcium Oxide are produced? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="432578" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/mrtas"><img alt="" class="" src="https://profilepictures.socratic.org/HY14X7r4S6AyDQgK2gwQ_IMG_0062.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/mrtas"> Nathan L. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-31T16:28:04" itemprop="dateCreated"> May 31, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#0.6575180#</mathjax> <mathjax>#"mol CaO"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>I'll assume it reacts with <em>excess</em> oxygen, and forms only calcium oxide. The chemical equation for this reaction is</p> <p><mathjax>#2"Ca" (s) + "O"_2 (g) rarr 2"CaO" (s)#</mathjax></p> <p>First let's calculate the number of moles of <mathjax>#"Ca"#</mathjax> that reacts, using its molar mass:</p> <p><mathjax>#26.35332cancel("g Ca")((1"mol Ca")/(40.08cancel("g Ca"))) = color(red)(0.6575180 "mol Ca"#</mathjax></p> <p>Now, let's use the stoichiometrically equivalent values (the coefficients) in the chemical equation to calculate the number of moles of <mathjax>#"CaO"#</mathjax>:</p> <p><mathjax>#0.6575180 cancel("mol Ca")((2"mol CaO")/(2cancel("mol Ca"))) = color(blue)(0.6575180 "mol CaO"#</mathjax></p> <p>Therefore, <mathjax>#0.6575180 "mol CaO"#</mathjax> will form.</p> <p>By the way, I've never seen <mathjax>#7#</mathjax> <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a> used in a problem before, I like it:)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/432578" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 8150 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	If 26.35332 grams of Ca is reacted, how many moles of Calcium Oxide are produced?	null
1,747	ab0503b6-6ddd-11ea-ac1c-ccda262736ce	https://socratic.org/questions/what-is-the-empirical-formula-of-c5h10	CH2	start chemical_formula qc_end chemical_equation 6 6 qc_end end	[{"type":"other","value":"Chemical Formula [OF] C5H10 [IN] empirical"}]	[{"type":"chemical equation","value":"CH2"}]	[{"type":"chemical equation","value":"C5H10"}]	<h1 class="questionTitle" itemprop="name">What is the empirical formula of C5H10? </h1>	null	CH2	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The empirical formula is the simplest whole number ratio that describes constituent atoms in a species. <mathjax>#C_5H_10#</mathjax> of course can be reduced to <mathjax>#CH_2#</mathjax>.</p> <p>The molecular formula is always a multiple of the empirical formula (the multiple might be 1). A very useful parameter with molecular formulae is the <em>"degree of unsaturation"</em> concept. An alkane has the general formula <mathjax>#C_nH_(2n+2)#</mathjax> (this could be the same as the empirical formula!). If presented with a molecular formula <mathjax>#C_nH_(2n)#</mathjax> we would say that this molecule has <mathjax>#1^@#</mathjax> of unsaturation. A degree of unsaturation has a double bond (<mathjax>#C=C#</mathjax>, <mathjax>#C=O#</mathjax>, <mathjax>#C=N#</mathjax>) OR a ring to account for the absence of the 2 hydrogens. Simple acetylenes have 2 degrees of unsaturation. Why?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The empirical formula of <mathjax>#C_5H_10#</mathjax> is <mathjax>#CH_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The empirical formula is the simplest whole number ratio that describes constituent atoms in a species. <mathjax>#C_5H_10#</mathjax> of course can be reduced to <mathjax>#CH_2#</mathjax>.</p> <p>The molecular formula is always a multiple of the empirical formula (the multiple might be 1). A very useful parameter with molecular formulae is the <em>"degree of unsaturation"</em> concept. An alkane has the general formula <mathjax>#C_nH_(2n+2)#</mathjax> (this could be the same as the empirical formula!). If presented with a molecular formula <mathjax>#C_nH_(2n)#</mathjax> we would say that this molecule has <mathjax>#1^@#</mathjax> of unsaturation. A degree of unsaturation has a double bond (<mathjax>#C=C#</mathjax>, <mathjax>#C=O#</mathjax>, <mathjax>#C=N#</mathjax>) OR a ring to account for the absence of the 2 hydrogens. Simple acetylenes have 2 degrees of unsaturation. Why?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the empirical formula of C5H10? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="198486" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-10T19:44:41" itemprop="dateCreated"> Dec 10, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The empirical formula of <mathjax>#C_5H_10#</mathjax> is <mathjax>#CH_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The empirical formula is the simplest whole number ratio that describes constituent atoms in a species. <mathjax>#C_5H_10#</mathjax> of course can be reduced to <mathjax>#CH_2#</mathjax>.</p> <p>The molecular formula is always a multiple of the empirical formula (the multiple might be 1). A very useful parameter with molecular formulae is the <em>"degree of unsaturation"</em> concept. An alkane has the general formula <mathjax>#C_nH_(2n+2)#</mathjax> (this could be the same as the empirical formula!). If presented with a molecular formula <mathjax>#C_nH_(2n)#</mathjax> we would say that this molecule has <mathjax>#1^@#</mathjax> of unsaturation. A degree of unsaturation has a double bond (<mathjax>#C=C#</mathjax>, <mathjax>#C=O#</mathjax>, <mathjax>#C=N#</mathjax>) OR a ring to account for the absence of the 2 hydrogens. Simple acetylenes have 2 degrees of unsaturation. Why?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/198486" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molecular-formula-of-a-compound"> How do you find molecular formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-diamond"> What is the chemical formula of a diamond? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-carbohydrate"> What is the chemical formula of a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-valproic-acid"> What is the empirical formula for valproic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-of-magnesium-oxide"> What is the empirical formula of magnesium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-empirical-formula-not-double-that-of-the-monosaccharides"> Why is the empirical formula not double that of the monosaccharides? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5331180502bf342f40b5c3b5"> Question #5c3b5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-molecular-formula-represents-a-carbohydrate"> What molecular formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-of-vinegar"> What is the molecular formula of vinegar? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/empirical-and-molecular-formulas"> See all questions in Empirical and Molecular Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 23261 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the empirical formula of C5H10?	null
1,748	a8d57450-6ddd-11ea-afe9-ccda262736ce	https://socratic.org/questions/how-do-you-balance-c-2h-6-o-2-ch-3cooh	2 C2H6 + 3 O2 -> 2 CH3COOH + 2 H2O	start chemical_equation qc_end chemical_equation 4 10 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the equation"}]	[{"type":"chemical equation","value":"2 C2H6 + 3 O2 -> 2 CH3COOH + 2 H2O"}]	[{"type":"chemical equation","value":"C2H6 + O2 -> CH3COOH + H2O"}]	<h1 class="questionTitle" itemprop="name">How do you balance #C_2H_6 + O_2 -> CH_3COOH + H_2O#?</h1>	null	2 C2H6 + 3 O2 -> 2 CH3COOH + 2 H2O	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First you want to do an atom inventory. Determine the number of atoms of each element that are on both side of the reaction arrow:</p> <p>Reactants side: <br/> C atoms = 2<br/> H atoms = 6<br/> O atoms = 2</p> <p>Products side:<br/> C atoms = 2<br/> H atoms = 6<br/> O atoms = 3</p> <p>As we can see the only element that isn't balanced is oxygen. A simple approach to this would be to focus on the <mathjax>#O_2#</mathjax> on the reactants side. You want to find a coefficient that would make the number of oxygen atoms on both side to be the same. </p> <p>Place a coefficient of 3/2 in front of <mathjax>#O_2#</mathjax> so the total number of atoms will equal three since you always multiply the coefficient by the subscript that's attached to that atom.</p> <p>Then you'll end up with this <mathjax>#C_2H_6 + 3/2O_2 rarr CH_3COOH + H_2O#</mathjax></p> <p>Since some people don't like the idea of fractional coefficients, you could multiply the entire chemical reaction by 2 to obtain whole number coefficients like so: </p> <p><mathjax>#2C_2H_6 + 3O_2 rarr 2CH_3COOH + 2H_2O#</mathjax></p> <p>I hope this makes sense!</p> <p><a href="https://socratic.org/chemistry/chemical-reactions/balancing-chemical-equations">Balancing Equations Help</a> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_2H_6 + 3/2O_2 rarr CH_3COOH + H_2O#</mathjax> or <mathjax>#2C_2H_6 + 3O_2 rarr 2CH_3COOH + 2H_2O#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First you want to do an atom inventory. Determine the number of atoms of each element that are on both side of the reaction arrow:</p> <p>Reactants side: <br/> C atoms = 2<br/> H atoms = 6<br/> O atoms = 2</p> <p>Products side:<br/> C atoms = 2<br/> H atoms = 6<br/> O atoms = 3</p> <p>As we can see the only element that isn't balanced is oxygen. A simple approach to this would be to focus on the <mathjax>#O_2#</mathjax> on the reactants side. You want to find a coefficient that would make the number of oxygen atoms on both side to be the same. </p> <p>Place a coefficient of 3/2 in front of <mathjax>#O_2#</mathjax> so the total number of atoms will equal three since you always multiply the coefficient by the subscript that's attached to that atom.</p> <p>Then you'll end up with this <mathjax>#C_2H_6 + 3/2O_2 rarr CH_3COOH + H_2O#</mathjax></p> <p>Since some people don't like the idea of fractional coefficients, you could multiply the entire chemical reaction by 2 to obtain whole number coefficients like so: </p> <p><mathjax>#2C_2H_6 + 3O_2 rarr 2CH_3COOH + 2H_2O#</mathjax></p> <p>I hope this makes sense!</p> <p><a href="https://socratic.org/chemistry/chemical-reactions/balancing-chemical-equations">Balancing Equations Help</a> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you balance #C_2H_6 + O_2 -> CH_3COOH + H_2O#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="275461" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/kayla-14"><img alt="" class="" src="https://profilepictures.socratic.org/OvMTWaamQPWcqLIkUNnG_793604964071127.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/kayla-14"> Kayla </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-09T02:03:09" itemprop="dateCreated"> Jun 9, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_2H_6 + 3/2O_2 rarr CH_3COOH + H_2O#</mathjax> or <mathjax>#2C_2H_6 + 3O_2 rarr 2CH_3COOH + 2H_2O#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First you want to do an atom inventory. Determine the number of atoms of each element that are on both side of the reaction arrow:</p> <p>Reactants side: <br/> C atoms = 2<br/> H atoms = 6<br/> O atoms = 2</p> <p>Products side:<br/> C atoms = 2<br/> H atoms = 6<br/> O atoms = 3</p> <p>As we can see the only element that isn't balanced is oxygen. A simple approach to this would be to focus on the <mathjax>#O_2#</mathjax> on the reactants side. You want to find a coefficient that would make the number of oxygen atoms on both side to be the same. </p> <p>Place a coefficient of 3/2 in front of <mathjax>#O_2#</mathjax> so the total number of atoms will equal three since you always multiply the coefficient by the subscript that's attached to that atom.</p> <p>Then you'll end up with this <mathjax>#C_2H_6 + 3/2O_2 rarr CH_3COOH + H_2O#</mathjax></p> <p>Since some people don't like the idea of fractional coefficients, you could multiply the entire chemical reaction by 2 to obtain whole number coefficients like so: </p> <p><mathjax>#2C_2H_6 + 3O_2 rarr 2CH_3COOH + 2H_2O#</mathjax></p> <p>I hope this makes sense!</p> <p><a href="https://socratic.org/chemistry/chemical-reactions/balancing-chemical-equations">Balancing Equations Help</a> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/275461" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------> H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -> Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? 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Sodium phosphate and calcium chloride react to form... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-equation-kclo3-kcl-o2"> How can I balance this equation? ____ #KClO_3 -># ____ #KCl +# ____ #O_2# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-balancing-chemical-equations-important"> Why is balancing chemical equations important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/balancing-chemical-equations"> See all questions in Balancing Chemical Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1218 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How do you balance #C_2H_6 + O_2 -> CH_3COOH + H_2O#?	null
1,749	aa142b0d-6ddd-11ea-8592-ccda262736ce	https://socratic.org/questions/how-do-you-balance-c3h5-no3-3-co2-h20-n2-o2	4 C3H5(NO3)3 -> 12 CO2 + 10 H2O + 6 N2 + O2	start chemical_equation qc_end chemical_equation 4 12 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the reaction"}]	[{"type":"chemical equation","value":"4 C3H5(NO3)3 -> 12 CO2 + 10 H2O + 6 N2 + O2"}]	[{"type":"chemical equation","value":"C3H5(NO3)3 -> CO2 + H2O + N2 + O2"}]	<h1 class="questionTitle" itemprop="name">How do you balance C3H5(NO3)3 -->CO2 + H20 + N2 + O2? </h1>	null	4 C3H5(NO3)3 -> 12 CO2 + 10 H2O + 6 N2 + O2	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is a little tricky to balance since your left hand side is a rather large molecule and placing a coefficient before it would affect all those atoms.</p> <p>First step is to tally all the atoms involved.</p> <p><mathjax>#C_3H_5(NO_3)_3#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#CO_2#</mathjax> + <mathjax>#H_2O#</mathjax> + <mathjax>#N_2#</mathjax> + <mathjax>#O_2#</mathjax> (unbalanced)</p> <p>based on the subscipts, we have</p> <p><em>left side:</em></p> <p><mathjax>#C#</mathjax> = 3<br/> <mathjax>#H#</mathjax> = 5<br/> <mathjax>#N#</mathjax> = 3<br/> <mathjax>#O#</mathjax> = 9</p> <p>Notice that since the <mathjax>#NO_3#</mathjax> was enclosed by a parenthesis followed by the subscript 3, I have to multiply the number of atoms inside the parenthesis by 3. (e.g. <mathjax>#N_"1 x 3"#</mathjax> ; <mathjax>#O_"3 x 3"#</mathjax>)</p> <p><em>right side:</em></p> <p><mathjax>#C#</mathjax> = 1<br/> <mathjax>#H#</mathjax> = 2<br/> <mathjax>#N#</mathjax> = 2<br/> <mathjax>#O#</mathjax> = 2 + 1 + 2 (do not add this up yet)</p> <p>Since the molecules on the right side are far more simpler than the molecule on the left side, I'm going to pick an element from the right side that I think would be the key to balance this whole equation.</p> <p><mathjax>#C_3H_5(NO_3)_3#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#CO_2#</mathjax> + <mathjax>#color (blue) 5H_2O#</mathjax> + <mathjax>#N_2#</mathjax> + <mathjax>#O_2#</mathjax> </p> <p><em>left side:</em></p> <p><mathjax>#C#</mathjax> = 3<br/> <mathjax>#H#</mathjax> = 5<br/> <mathjax>#N#</mathjax> = 3<br/> <mathjax>#O#</mathjax> = 9</p> <p><em>right side:</em></p> <p><mathjax>#C#</mathjax> = 1<br/> <mathjax>#H#</mathjax> = 2 x <mathjax>#color (blue) 5#</mathjax> = 10<br/> <mathjax>#N#</mathjax> = 2<br/> <mathjax>#O#</mathjax> = 2 + (1 x <mathjax>#color (blue) 5#</mathjax>) + 2</p> <p>Notice that since <mathjax>#H_2O#</mathjax> is a substance, I would also need to multiply the <mathjax>#O#</mathjax> by 5. Now that there are 10 atoms of <mathjax>#H#</mathjax> on the right side, I would need to also have 10 atoms of <mathjax>#H#</mathjax> on the left side.</p> <p><mathjax>#color (red) 2C_3H_5(NO_3)_3#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#CO_2#</mathjax> + <mathjax>#5H_2O#</mathjax> + <mathjax>#N_2#</mathjax> + <mathjax>#O_2#</mathjax> </p> <p><em>left side:</em></p> <p><mathjax>#C#</mathjax> = 3 x <mathjax>#color (red) 2#</mathjax> = 6<br/> <mathjax>#H#</mathjax> = 5 x <mathjax>#color (red) 2#</mathjax> = <strong>10</strong><br/> <mathjax>#N#</mathjax> = 3 x <mathjax>#color (red) 2#</mathjax> = 6<br/> <mathjax>#O#</mathjax> = 9 x <mathjax>#color (red) 2#</mathjax> = 18</p> <p><em>right side:</em></p> <p><mathjax>#C#</mathjax> = 1<br/> <mathjax>#H#</mathjax> = 2 x 5 = <strong>10</strong><br/> <mathjax>#N#</mathjax> = 2<br/> <mathjax>#O#</mathjax> = 2 + (1 x 5) + 2</p> <p>Again notice that all atoms on the left side are multiplied by 2 because they are bonded to one another. Now let's balance the rest of the equation.</p> <p><mathjax>#2C_3H_5(NO_3)_3#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#color (green) 6CO_2#</mathjax> + <mathjax>#5H_2O#</mathjax> + <mathjax>#color (orange) 3N_2#</mathjax> + <mathjax>#O_2#</mathjax> </p> <p><em>left side:</em></p> <p><mathjax>#C#</mathjax> = 3 x 2 = <strong>6</strong><br/> <mathjax>#H#</mathjax> = 5 x 2 = <strong>10</strong><br/> <mathjax>#N#</mathjax> = 3 x 2 = <strong>6</strong><br/> <mathjax>#O#</mathjax> = 9 x 2 = 18</p> <p><em>right side:</em></p> <p><mathjax>#C#</mathjax> = 1 x <mathjax>#color (green) 6#</mathjax> = <strong>6</strong><br/> <mathjax>#H#</mathjax> = 2 x 5 = <strong>10</strong><br/> <mathjax>#N#</mathjax> = 2 x <mathjax>#color (orange) 3#</mathjax> = <strong>6</strong><br/> <mathjax>#O#</mathjax> = (2 x <mathjax>#color (green) 6#</mathjax>) + (1 x 5) + 2</p> <p>Now the only atom left to balance is the <mathjax>#O#</mathjax>. Notice that if you add all the O atoms on the right side, you will come up with a sum of 19. So what to do? <strong>Use your knowledge of fractions</strong>.</p> <p><mathjax>#2C_3H_5(NO_3)_3#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#6CO_2#</mathjax> + <mathjax># 5H_2O#</mathjax> + <mathjax>#3N_2#</mathjax> + <mathjax>#color (magenta) (1/2)O_2#</mathjax> </p> <p><em>left side:</em></p> <p><mathjax>#C#</mathjax> = 3 x 2 = <strong>6</strong><br/> <mathjax>#H#</mathjax> = 5 x 2 = <strong>10</strong><br/> <mathjax>#N#</mathjax> = 3 x 2 = <strong>6</strong><br/> <mathjax>#O#</mathjax> = 9 x 2 = <strong>18</strong></p> <p><em>right side:</em></p> <p><mathjax>#C#</mathjax> = 1 x 6 = <strong>6</strong><br/> <mathjax>#H#</mathjax> = 2 x 5= <strong>10</strong><br/> <mathjax>#N#</mathjax> = 2 x 3 = <strong>6</strong><br/> <mathjax>#O#</mathjax> = (2 x 6) + (1 x 5) + (2 x <mathjax>#color (magenta) (1/2)#</mathjax>) = <strong>18</strong></p> <p>The equation is now balanced.</p> <p>But if you want whole number coefficients instead of fractions, you can always multiply the WHOLE equation by 2.</p> <p><mathjax>#cancel 2#</mathjax> [<mathjax>#2C_3H_5(NO_3)_3#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#6CO_2#</mathjax> + <mathjax>#5H_2O#</mathjax> + <mathjax>#3N_2#</mathjax> + <mathjax>#1/ cancel 2O_2#</mathjax>] </p> <p>=</p> <p><mathjax>#4C_3H_5(NO_3)_3#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#12CO_2#</mathjax> + <mathjax>#10H_2O#</mathjax> + <mathjax>#6N_2#</mathjax> + <mathjax>#O_2#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2C_3H_5(NO_3)_3#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#6CO_2#</mathjax> + <mathjax>#5H_2O#</mathjax> + <mathjax>#3N_2#</mathjax> + <mathjax>#1/2 O_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is a little tricky to balance since your left hand side is a rather large molecule and placing a coefficient before it would affect all those atoms.</p> <p>First step is to tally all the atoms involved.</p> <p><mathjax>#C_3H_5(NO_3)_3#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#CO_2#</mathjax> + <mathjax>#H_2O#</mathjax> + <mathjax>#N_2#</mathjax> + <mathjax>#O_2#</mathjax> (unbalanced)</p> <p>based on the subscipts, we have</p> <p><em>left side:</em></p> <p><mathjax>#C#</mathjax> = 3<br/> <mathjax>#H#</mathjax> = 5<br/> <mathjax>#N#</mathjax> = 3<br/> <mathjax>#O#</mathjax> = 9</p> <p>Notice that since the <mathjax>#NO_3#</mathjax> was enclosed by a parenthesis followed by the subscript 3, I have to multiply the number of atoms inside the parenthesis by 3. (e.g. <mathjax>#N_"1 x 3"#</mathjax> ; <mathjax>#O_"3 x 3"#</mathjax>)</p> <p><em>right side:</em></p> <p><mathjax>#C#</mathjax> = 1<br/> <mathjax>#H#</mathjax> = 2<br/> <mathjax>#N#</mathjax> = 2<br/> <mathjax>#O#</mathjax> = 2 + 1 + 2 (do not add this up yet)</p> <p>Since the molecules on the right side are far more simpler than the molecule on the left side, I'm going to pick an element from the right side that I think would be the key to balance this whole equation.</p> <p><mathjax>#C_3H_5(NO_3)_3#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#CO_2#</mathjax> + <mathjax>#color (blue) 5H_2O#</mathjax> + <mathjax>#N_2#</mathjax> + <mathjax>#O_2#</mathjax> </p> <p><em>left side:</em></p> <p><mathjax>#C#</mathjax> = 3<br/> <mathjax>#H#</mathjax> = 5<br/> <mathjax>#N#</mathjax> = 3<br/> <mathjax>#O#</mathjax> = 9</p> <p><em>right side:</em></p> <p><mathjax>#C#</mathjax> = 1<br/> <mathjax>#H#</mathjax> = 2 x <mathjax>#color (blue) 5#</mathjax> = 10<br/> <mathjax>#N#</mathjax> = 2<br/> <mathjax>#O#</mathjax> = 2 + (1 x <mathjax>#color (blue) 5#</mathjax>) + 2</p> <p>Notice that since <mathjax>#H_2O#</mathjax> is a substance, I would also need to multiply the <mathjax>#O#</mathjax> by 5. Now that there are 10 atoms of <mathjax>#H#</mathjax> on the right side, I would need to also have 10 atoms of <mathjax>#H#</mathjax> on the left side.</p> <p><mathjax>#color (red) 2C_3H_5(NO_3)_3#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#CO_2#</mathjax> + <mathjax>#5H_2O#</mathjax> + <mathjax>#N_2#</mathjax> + <mathjax>#O_2#</mathjax> </p> <p><em>left side:</em></p> <p><mathjax>#C#</mathjax> = 3 x <mathjax>#color (red) 2#</mathjax> = 6<br/> <mathjax>#H#</mathjax> = 5 x <mathjax>#color (red) 2#</mathjax> = <strong>10</strong><br/> <mathjax>#N#</mathjax> = 3 x <mathjax>#color (red) 2#</mathjax> = 6<br/> <mathjax>#O#</mathjax> = 9 x <mathjax>#color (red) 2#</mathjax> = 18</p> <p><em>right side:</em></p> <p><mathjax>#C#</mathjax> = 1<br/> <mathjax>#H#</mathjax> = 2 x 5 = <strong>10</strong><br/> <mathjax>#N#</mathjax> = 2<br/> <mathjax>#O#</mathjax> = 2 + (1 x 5) + 2</p> <p>Again notice that all atoms on the left side are multiplied by 2 because they are bonded to one another. Now let's balance the rest of the equation.</p> <p><mathjax>#2C_3H_5(NO_3)_3#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#color (green) 6CO_2#</mathjax> + <mathjax>#5H_2O#</mathjax> + <mathjax>#color (orange) 3N_2#</mathjax> + <mathjax>#O_2#</mathjax> </p> <p><em>left side:</em></p> <p><mathjax>#C#</mathjax> = 3 x 2 = <strong>6</strong><br/> <mathjax>#H#</mathjax> = 5 x 2 = <strong>10</strong><br/> <mathjax>#N#</mathjax> = 3 x 2 = <strong>6</strong><br/> <mathjax>#O#</mathjax> = 9 x 2 = 18</p> <p><em>right side:</em></p> <p><mathjax>#C#</mathjax> = 1 x <mathjax>#color (green) 6#</mathjax> = <strong>6</strong><br/> <mathjax>#H#</mathjax> = 2 x 5 = <strong>10</strong><br/> <mathjax>#N#</mathjax> = 2 x <mathjax>#color (orange) 3#</mathjax> = <strong>6</strong><br/> <mathjax>#O#</mathjax> = (2 x <mathjax>#color (green) 6#</mathjax>) + (1 x 5) + 2</p> <p>Now the only atom left to balance is the <mathjax>#O#</mathjax>. Notice that if you add all the O atoms on the right side, you will come up with a sum of 19. So what to do? <strong>Use your knowledge of fractions</strong>.</p> <p><mathjax>#2C_3H_5(NO_3)_3#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#6CO_2#</mathjax> + <mathjax># 5H_2O#</mathjax> + <mathjax>#3N_2#</mathjax> + <mathjax>#color (magenta) (1/2)O_2#</mathjax> </p> <p><em>left side:</em></p> <p><mathjax>#C#</mathjax> = 3 x 2 = <strong>6</strong><br/> <mathjax>#H#</mathjax> = 5 x 2 = <strong>10</strong><br/> <mathjax>#N#</mathjax> = 3 x 2 = <strong>6</strong><br/> <mathjax>#O#</mathjax> = 9 x 2 = <strong>18</strong></p> <p><em>right side:</em></p> <p><mathjax>#C#</mathjax> = 1 x 6 = <strong>6</strong><br/> <mathjax>#H#</mathjax> = 2 x 5= <strong>10</strong><br/> <mathjax>#N#</mathjax> = 2 x 3 = <strong>6</strong><br/> <mathjax>#O#</mathjax> = (2 x 6) + (1 x 5) + (2 x <mathjax>#color (magenta) (1/2)#</mathjax>) = <strong>18</strong></p> <p>The equation is now balanced.</p> <p>But if you want whole number coefficients instead of fractions, you can always multiply the WHOLE equation by 2.</p> <p><mathjax>#cancel 2#</mathjax> [<mathjax>#2C_3H_5(NO_3)_3#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#6CO_2#</mathjax> + <mathjax>#5H_2O#</mathjax> + <mathjax>#3N_2#</mathjax> + <mathjax>#1/ cancel 2O_2#</mathjax>] </p> <p>=</p> <p><mathjax>#4C_3H_5(NO_3)_3#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#12CO_2#</mathjax> + <mathjax>#10H_2O#</mathjax> + <mathjax>#6N_2#</mathjax> + <mathjax>#O_2#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you balance C3H5(NO3)3 -->CO2 + H20 + N2 + O2? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="180656" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/nikka-c"><img alt="" class="" src="https://profilepictures.socratic.org/AQ8VOCyTM1J7U0TvIWhw_nkahara.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/nikka-c"> Nikka C. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-10-28T10:32:28" itemprop="dateCreated"> Oct 28, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2C_3H_5(NO_3)_3#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#6CO_2#</mathjax> + <mathjax>#5H_2O#</mathjax> + <mathjax>#3N_2#</mathjax> + <mathjax>#1/2 O_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is a little tricky to balance since your left hand side is a rather large molecule and placing a coefficient before it would affect all those atoms.</p> <p>First step is to tally all the atoms involved.</p> <p><mathjax>#C_3H_5(NO_3)_3#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#CO_2#</mathjax> + <mathjax>#H_2O#</mathjax> + <mathjax>#N_2#</mathjax> + <mathjax>#O_2#</mathjax> (unbalanced)</p> <p>based on the subscipts, we have</p> <p><em>left side:</em></p> <p><mathjax>#C#</mathjax> = 3<br/> <mathjax>#H#</mathjax> = 5<br/> <mathjax>#N#</mathjax> = 3<br/> <mathjax>#O#</mathjax> = 9</p> <p>Notice that since the <mathjax>#NO_3#</mathjax> was enclosed by a parenthesis followed by the subscript 3, I have to multiply the number of atoms inside the parenthesis by 3. (e.g. <mathjax>#N_"1 x 3"#</mathjax> ; <mathjax>#O_"3 x 3"#</mathjax>)</p> <p><em>right side:</em></p> <p><mathjax>#C#</mathjax> = 1<br/> <mathjax>#H#</mathjax> = 2<br/> <mathjax>#N#</mathjax> = 2<br/> <mathjax>#O#</mathjax> = 2 + 1 + 2 (do not add this up yet)</p> <p>Since the molecules on the right side are far more simpler than the molecule on the left side, I'm going to pick an element from the right side that I think would be the key to balance this whole equation.</p> <p><mathjax>#C_3H_5(NO_3)_3#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#CO_2#</mathjax> + <mathjax>#color (blue) 5H_2O#</mathjax> + <mathjax>#N_2#</mathjax> + <mathjax>#O_2#</mathjax> </p> <p><em>left side:</em></p> <p><mathjax>#C#</mathjax> = 3<br/> <mathjax>#H#</mathjax> = 5<br/> <mathjax>#N#</mathjax> = 3<br/> <mathjax>#O#</mathjax> = 9</p> <p><em>right side:</em></p> <p><mathjax>#C#</mathjax> = 1<br/> <mathjax>#H#</mathjax> = 2 x <mathjax>#color (blue) 5#</mathjax> = 10<br/> <mathjax>#N#</mathjax> = 2<br/> <mathjax>#O#</mathjax> = 2 + (1 x <mathjax>#color (blue) 5#</mathjax>) + 2</p> <p>Notice that since <mathjax>#H_2O#</mathjax> is a substance, I would also need to multiply the <mathjax>#O#</mathjax> by 5. Now that there are 10 atoms of <mathjax>#H#</mathjax> on the right side, I would need to also have 10 atoms of <mathjax>#H#</mathjax> on the left side.</p> <p><mathjax>#color (red) 2C_3H_5(NO_3)_3#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#CO_2#</mathjax> + <mathjax>#5H_2O#</mathjax> + <mathjax>#N_2#</mathjax> + <mathjax>#O_2#</mathjax> </p> <p><em>left side:</em></p> <p><mathjax>#C#</mathjax> = 3 x <mathjax>#color (red) 2#</mathjax> = 6<br/> <mathjax>#H#</mathjax> = 5 x <mathjax>#color (red) 2#</mathjax> = <strong>10</strong><br/> <mathjax>#N#</mathjax> = 3 x <mathjax>#color (red) 2#</mathjax> = 6<br/> <mathjax>#O#</mathjax> = 9 x <mathjax>#color (red) 2#</mathjax> = 18</p> <p><em>right side:</em></p> <p><mathjax>#C#</mathjax> = 1<br/> <mathjax>#H#</mathjax> = 2 x 5 = <strong>10</strong><br/> <mathjax>#N#</mathjax> = 2<br/> <mathjax>#O#</mathjax> = 2 + (1 x 5) + 2</p> <p>Again notice that all atoms on the left side are multiplied by 2 because they are bonded to one another. Now let's balance the rest of the equation.</p> <p><mathjax>#2C_3H_5(NO_3)_3#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#color (green) 6CO_2#</mathjax> + <mathjax>#5H_2O#</mathjax> + <mathjax>#color (orange) 3N_2#</mathjax> + <mathjax>#O_2#</mathjax> </p> <p><em>left side:</em></p> <p><mathjax>#C#</mathjax> = 3 x 2 = <strong>6</strong><br/> <mathjax>#H#</mathjax> = 5 x 2 = <strong>10</strong><br/> <mathjax>#N#</mathjax> = 3 x 2 = <strong>6</strong><br/> <mathjax>#O#</mathjax> = 9 x 2 = 18</p> <p><em>right side:</em></p> <p><mathjax>#C#</mathjax> = 1 x <mathjax>#color (green) 6#</mathjax> = <strong>6</strong><br/> <mathjax>#H#</mathjax> = 2 x 5 = <strong>10</strong><br/> <mathjax>#N#</mathjax> = 2 x <mathjax>#color (orange) 3#</mathjax> = <strong>6</strong><br/> <mathjax>#O#</mathjax> = (2 x <mathjax>#color (green) 6#</mathjax>) + (1 x 5) + 2</p> <p>Now the only atom left to balance is the <mathjax>#O#</mathjax>. Notice that if you add all the O atoms on the right side, you will come up with a sum of 19. So what to do? <strong>Use your knowledge of fractions</strong>.</p> <p><mathjax>#2C_3H_5(NO_3)_3#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#6CO_2#</mathjax> + <mathjax># 5H_2O#</mathjax> + <mathjax>#3N_2#</mathjax> + <mathjax>#color (magenta) (1/2)O_2#</mathjax> </p> <p><em>left side:</em></p> <p><mathjax>#C#</mathjax> = 3 x 2 = <strong>6</strong><br/> <mathjax>#H#</mathjax> = 5 x 2 = <strong>10</strong><br/> <mathjax>#N#</mathjax> = 3 x 2 = <strong>6</strong><br/> <mathjax>#O#</mathjax> = 9 x 2 = <strong>18</strong></p> <p><em>right side:</em></p> <p><mathjax>#C#</mathjax> = 1 x 6 = <strong>6</strong><br/> <mathjax>#H#</mathjax> = 2 x 5= <strong>10</strong><br/> <mathjax>#N#</mathjax> = 2 x 3 = <strong>6</strong><br/> <mathjax>#O#</mathjax> = (2 x 6) + (1 x 5) + (2 x <mathjax>#color (magenta) (1/2)#</mathjax>) = <strong>18</strong></p> <p>The equation is now balanced.</p> <p>But if you want whole number coefficients instead of fractions, you can always multiply the WHOLE equation by 2.</p> <p><mathjax>#cancel 2#</mathjax> [<mathjax>#2C_3H_5(NO_3)_3#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#6CO_2#</mathjax> + <mathjax>#5H_2O#</mathjax> + <mathjax>#3N_2#</mathjax> + <mathjax>#1/ cancel 2O_2#</mathjax>] </p> <p>=</p> <p><mathjax>#4C_3H_5(NO_3)_3#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#12CO_2#</mathjax> + <mathjax>#10H_2O#</mathjax> + <mathjax>#6N_2#</mathjax> + <mathjax>#O_2#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/180656" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------> H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -> Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? 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1,750	ac4e9178-6ddd-11ea-b969-ccda262736ce	https://socratic.org/questions/how-many-liters-of-water-can-be-made-from-55-grams-of-oxygen-gas-and-an-excess-o	8.15 liters	start physical_unit 4 4 volume l qc_end physical_unit 12 13 9 10 mass qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Volume [OF] water [IN] liters"}]	[{"type":"physical unit","value":"8.15 liters"}]	[{"type":"physical unit","value":"Mass [OF] oxygen gas [=] \\pu{55 grams}"},{"type":"other","value":"Excess of hydrogen."},{"type":"physical unit","value":"Pressure [OF] the reaction [=] \\pu{12.4 atm}"},{"type":"physical unit","value":"Temperature [OF] the reaction [=] \\pu{85 ℃}"}]	<h1 class="questionTitle" itemprop="name">How many liters of water can be made from 55 grams of oxygen gas and an excess of hydrogen at a pressure of 12.4 atm and a temperature of 85C?</h1>	null	8.15 liters	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your starting point here will be the balanced chemical equation for the reaction between hydrogen gas and oxygen gas, which looks like this </p> <p><img alt="https://elearning.kctcs.edu/bbcswebdav/users/kmuller0001/SoftChalk%20Files/CHE%20120%20Chapter%205/17_Che_120_Packet_5_print.html" src="https://useruploads.socratic.org/qNBfDAGYQKCE6l7G82EY_water.jpg"/> </p> <p>As you can see, you have a <mathjax>#2:1#</mathjax> <a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> between hydrogen gas and oxygen gas. This means that the reaction will <strong>always</strong> consumed <strong>twice as many moles</strong> of hydrogen gas than of oxygen gas. </p> <p>Likewise, you have a <mathjax>#1:2#</mathjax> mole ratio between oxygen gas and water, which means that the reaction will produce <strong>twice as many moles</strong> of water as you have moles of oxygen taking part in the reaction. </p> <p>To find the number of moles of oxygen, use its <strong>molar mass</strong></p> <blockquote> <p><mathjax>#55 color(red)(cancel(color(black)("g"))) * "1 mole O"_2/(32.0 color(red)(cancel(color(black)("g")))) = "1.719 moles O"_2#</mathjax></p> </blockquote> <p>You are told that hydrogen is <em>in excess</em>, which means that you can assume that <strong>all the moles</strong> of oxygen will react. </p> <p>This means that the reaction will produce</p> <blockquote> <p><mathjax>#1.719 color(red)(cancel(color(black)("moles O"_2))) * ("2 moles H"_2"O")/(1 color(red)(cancel(color(black)("mole O"_2)))) = "3.438 moles H"_2"O"#</mathjax></p> </blockquote> <p>To determine what <strong>volume</strong> that many moles of water would occupy at a pressure of <mathjax>#"12.4 atm"#</mathjax> and a temperature of <mathjax>#85^@"C"#</mathjax>, you can use the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> equation</p> <blockquote> <p><mathjax>#color(blue)(PV = nRT)#</mathjax></p> </blockquote> <p>The value of <mathjax>#R#</mathjax>, the universal gas constant, is usually given as <mathjax>#0.0821("atm" * "L")/("mol" * "K")#</mathjax>. <strong>Do not</strong> forget to convert the temperature from <em>degrees Celsius</em> to <em>Kelvin</em>! </p> <p>Rearrange the above equation to solve for <mathjax>#V#</mathjax></p> <blockquote> <p><mathjax>#PV = nRT implies V = (nRT)/P#</mathjax></p> <p><mathjax>#V = (3.438color(red)(cancel(color(black)("moles"))) * 0.0821(color(red)(cancel(color(black)("atm"))) * "L")/(color(red)(cancel(color(black)("mol"))) * color(red)(cancel(color(black)("K")))) * (273.15 + 85)color(red)(cancel(color(black)("K"))))/(12.4color(red)(cancel(color(black)("atm"))))#</mathjax></p> <p><mathjax>#V = "8.153 L"#</mathjax></p> </blockquote> <p>Rounded to two <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the number of sig figs you have for the mass of oxygen, the answer will be </p> <blockquote> <p><mathjax>#V = color(green)("8.2 L")#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"8.2 L"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your starting point here will be the balanced chemical equation for the reaction between hydrogen gas and oxygen gas, which looks like this </p> <p><img alt="https://elearning.kctcs.edu/bbcswebdav/users/kmuller0001/SoftChalk%20Files/CHE%20120%20Chapter%205/17_Che_120_Packet_5_print.html" src="https://useruploads.socratic.org/qNBfDAGYQKCE6l7G82EY_water.jpg"/> </p> <p>As you can see, you have a <mathjax>#2:1#</mathjax> <a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> between hydrogen gas and oxygen gas. This means that the reaction will <strong>always</strong> consumed <strong>twice as many moles</strong> of hydrogen gas than of oxygen gas. </p> <p>Likewise, you have a <mathjax>#1:2#</mathjax> mole ratio between oxygen gas and water, which means that the reaction will produce <strong>twice as many moles</strong> of water as you have moles of oxygen taking part in the reaction. </p> <p>To find the number of moles of oxygen, use its <strong>molar mass</strong></p> <blockquote> <p><mathjax>#55 color(red)(cancel(color(black)("g"))) * "1 mole O"_2/(32.0 color(red)(cancel(color(black)("g")))) = "1.719 moles O"_2#</mathjax></p> </blockquote> <p>You are told that hydrogen is <em>in excess</em>, which means that you can assume that <strong>all the moles</strong> of oxygen will react. </p> <p>This means that the reaction will produce</p> <blockquote> <p><mathjax>#1.719 color(red)(cancel(color(black)("moles O"_2))) * ("2 moles H"_2"O")/(1 color(red)(cancel(color(black)("mole O"_2)))) = "3.438 moles H"_2"O"#</mathjax></p> </blockquote> <p>To determine what <strong>volume</strong> that many moles of water would occupy at a pressure of <mathjax>#"12.4 atm"#</mathjax> and a temperature of <mathjax>#85^@"C"#</mathjax>, you can use the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> equation</p> <blockquote> <p><mathjax>#color(blue)(PV = nRT)#</mathjax></p> </blockquote> <p>The value of <mathjax>#R#</mathjax>, the universal gas constant, is usually given as <mathjax>#0.0821("atm" * "L")/("mol" * "K")#</mathjax>. <strong>Do not</strong> forget to convert the temperature from <em>degrees Celsius</em> to <em>Kelvin</em>! </p> <p>Rearrange the above equation to solve for <mathjax>#V#</mathjax></p> <blockquote> <p><mathjax>#PV = nRT implies V = (nRT)/P#</mathjax></p> <p><mathjax>#V = (3.438color(red)(cancel(color(black)("moles"))) * 0.0821(color(red)(cancel(color(black)("atm"))) * "L")/(color(red)(cancel(color(black)("mol"))) * color(red)(cancel(color(black)("K")))) * (273.15 + 85)color(red)(cancel(color(black)("K"))))/(12.4color(red)(cancel(color(black)("atm"))))#</mathjax></p> <p><mathjax>#V = "8.153 L"#</mathjax></p> </blockquote> <p>Rounded to two <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the number of sig figs you have for the mass of oxygen, the answer will be </p> <blockquote> <p><mathjax>#V = color(green)("8.2 L")#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many liters of water can be made from 55 grams of oxygen gas and an excess of hydrogen at a pressure of 12.4 atm and a temperature of 85C?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="216962" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-25T19:36:03" itemprop="dateCreated"> Jan 25, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"8.2 L"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your starting point here will be the balanced chemical equation for the reaction between hydrogen gas and oxygen gas, which looks like this </p> <p><img alt="https://elearning.kctcs.edu/bbcswebdav/users/kmuller0001/SoftChalk%20Files/CHE%20120%20Chapter%205/17_Che_120_Packet_5_print.html" src="https://useruploads.socratic.org/qNBfDAGYQKCE6l7G82EY_water.jpg"/> </p> <p>As you can see, you have a <mathjax>#2:1#</mathjax> <a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> between hydrogen gas and oxygen gas. This means that the reaction will <strong>always</strong> consumed <strong>twice as many moles</strong> of hydrogen gas than of oxygen gas. </p> <p>Likewise, you have a <mathjax>#1:2#</mathjax> mole ratio between oxygen gas and water, which means that the reaction will produce <strong>twice as many moles</strong> of water as you have moles of oxygen taking part in the reaction. </p> <p>To find the number of moles of oxygen, use its <strong>molar mass</strong></p> <blockquote> <p><mathjax>#55 color(red)(cancel(color(black)("g"))) * "1 mole O"_2/(32.0 color(red)(cancel(color(black)("g")))) = "1.719 moles O"_2#</mathjax></p> </blockquote> <p>You are told that hydrogen is <em>in excess</em>, which means that you can assume that <strong>all the moles</strong> of oxygen will react. </p> <p>This means that the reaction will produce</p> <blockquote> <p><mathjax>#1.719 color(red)(cancel(color(black)("moles O"_2))) * ("2 moles H"_2"O")/(1 color(red)(cancel(color(black)("mole O"_2)))) = "3.438 moles H"_2"O"#</mathjax></p> </blockquote> <p>To determine what <strong>volume</strong> that many moles of water would occupy at a pressure of <mathjax>#"12.4 atm"#</mathjax> and a temperature of <mathjax>#85^@"C"#</mathjax>, you can use the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> equation</p> <blockquote> <p><mathjax>#color(blue)(PV = nRT)#</mathjax></p> </blockquote> <p>The value of <mathjax>#R#</mathjax>, the universal gas constant, is usually given as <mathjax>#0.0821("atm" * "L")/("mol" * "K")#</mathjax>. <strong>Do not</strong> forget to convert the temperature from <em>degrees Celsius</em> to <em>Kelvin</em>! </p> <p>Rearrange the above equation to solve for <mathjax>#V#</mathjax></p> <blockquote> <p><mathjax>#PV = nRT implies V = (nRT)/P#</mathjax></p> <p><mathjax>#V = (3.438color(red)(cancel(color(black)("moles"))) * 0.0821(color(red)(cancel(color(black)("atm"))) * "L")/(color(red)(cancel(color(black)("mol"))) * color(red)(cancel(color(black)("K")))) * (273.15 + 85)color(red)(cancel(color(black)("K"))))/(12.4color(red)(cancel(color(black)("atm"))))#</mathjax></p> <p><mathjax>#V = "8.153 L"#</mathjax></p> </blockquote> <p>Rounded to two <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the number of sig figs you have for the mass of oxygen, the answer will be </p> <blockquote> <p><mathjax>#V = color(green)("8.2 L")#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/216962" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What is stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ab82402bf342f48d93ac6"> Question #93ac6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-we-study-stoichiometry"> Why do we study stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-naoh-is-produced-from-1-20-x-102-grams-of-na2o-na2o-h2o-2-naoh"> How many grams of NaOH is produced from #1.20 x 10^2# grams of #Na_2O#? #Na_2O + H_2O -> 2NaOH# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-na2o-are-required-to-produce-1-60-x-102-grams-of-naoh-na2o-h2o"> How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? 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1,751	a9cc5b78-6ddd-11ea-a5cf-ccda262736ce	https://socratic.org/questions/a-100-0-ml-sample-of-10-m-nh-is-titrated-with-10-m-hno-3-what-is-the-ph-of-the-s	1.70	start physical_unit 19 20 ph none qc_end physical_unit 7 7 1 2 volume qc_end physical_unit 7 7 5 6 molarity qc_end physical_unit 13 13 5 6 molarity qc_end physical_unit 20 20 25 26 volume qc_end end	[{"type":"physical unit","value":"pH [OF] the solution"}]	[{"type":"physical unit","value":"1.70"}]	[{"type":"physical unit","value":"Volume [OF] NH3 sample [=] \\pu{100.0 mL}"},{"type":"physical unit","value":"Molarity [OF] NH3 sample [=] \\pu{0.10 M}"},{"type":"physical unit","value":"Molarity [OF] HNO3 solution [=] \\pu{0.10 M}"},{"type":"physical unit","value":"Volume [OF] HNO3 solution [=] \\pu{150.0 mL}"}]	<h1 class="questionTitle" itemprop="name">A 100.0 mL sample of .10 M #NH_# is titrated with .10 M #HNO_3#. What is the pH of the solution after the addition of 150.0 mL of #HNO_3#?</h1>	null	1.70	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><img alt="" src="https://useruploads.socratic.org/fihY9FPxQG4tq8jX8MM1_image.jpeg"/> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a>=1.70</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><img alt="" src="https://useruploads.socratic.org/fihY9FPxQG4tq8jX8MM1_image.jpeg"/> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A 100.0 mL sample of .10 M #NH_# is titrated with .10 M #HNO_3#. What is the pH of the solution after the addition of 150.0 mL of #HNO_3#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/ph-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">pH calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="271797" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/sam-54"><img alt="" class="" src="https://profilepictures.socratic.org/3bkyAGe2RVWw1lx2h1A5_Avatar%201.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/sam-54"> Sam </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-31T07:07:32" itemprop="dateCreated"> May 31, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a>=1.70</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><img alt="" src="https://useruploads.socratic.org/fihY9FPxQG4tq8jX8MM1_image.jpeg"/> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/271797" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-of-a-solution"> How do you determine ph of a solution? 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</a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-alkalinity-affect-pool-water"> How does alkalinity affect pool water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ph-important-in-drinking-water"> Why is pH important in drinking water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-ph-of-solution"> How can I calculate the pH of a solution? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/ph-calculations"> See all questions in pH calculations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1902 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A 100.0 mL sample of .10 M #NH_# is titrated with .10 M #HNO_3#. What is the pH of the solution after the addition of 150.0 mL of #HNO_3#?	null
1,752	ab4e2ce2-6ddd-11ea-8627-ccda262736ce	https://socratic.org/questions/3-10-22-atoms-of-water-is-equivalent-to-how-many-grams	0.90 grams	start physical_unit 5 5 mass g qc_end end	[{"type":"physical unit","value":"Mass [OF] water [IN] grams"}]	[{"type":"physical unit","value":"0.90 grams"}]	[{"type":"physical unit","value":"Number [OF] water atoms [=] \\pu{3 × 10^22}"}]	<h1 class="questionTitle" itemprop="name">#3*10^22# atoms of water is equivalent to how many grams?</h1>	null	0.90 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Begin by converting the atoms to moles using Avogadro's number of <mathjax>#6.02x10^23#</mathjax></p> <p><mathjax>#3x10^22cancel(atms)x (1mol)/(6.02x10^23cancel(atms)) = 0.0498 mol#</mathjax></p> <p>Nox convert the moles to grams using the molar mass of water <mathjax>#18.01 g/(mol)#</mathjax></p> <p><mathjax>#0.0498 cancel(mol) x ((18.01 g)/(1 cancel(mol))) = 0.897 grams#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#0.897#</mathjax> grams of water</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Begin by converting the atoms to moles using Avogadro's number of <mathjax>#6.02x10^23#</mathjax></p> <p><mathjax>#3x10^22cancel(atms)x (1mol)/(6.02x10^23cancel(atms)) = 0.0498 mol#</mathjax></p> <p>Nox convert the moles to grams using the molar mass of water <mathjax>#18.01 g/(mol)#</mathjax></p> <p><mathjax>#0.0498 cancel(mol) x ((18.01 g)/(1 cancel(mol))) = 0.897 grams#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">#3*10^22# atoms of water is equivalent to how many grams?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="273060" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/brian-m"><img alt="" class="" src="https://profilepictures.socratic.org/ZCpnJDgSFKORtvaSPDeG_Lego%20Me.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/brian-m"> BRIAN M. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-02T15:41:37" itemprop="dateCreated"> Jun 2, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#0.897#</mathjax> grams of water</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Begin by converting the atoms to moles using Avogadro's number of <mathjax>#6.02x10^23#</mathjax></p> <p><mathjax>#3x10^22cancel(atms)x (1mol)/(6.02x10^23cancel(atms)) = 0.0498 mol#</mathjax></p> <p>Nox convert the moles to grams using the molar mass of water <mathjax>#18.01 g/(mol)#</mathjax></p> <p><mathjax>#0.0498 cancel(mol) x ((18.01 g)/(1 cancel(mol))) = 0.897 grams#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/273060" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1467 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	#3*10^22# atoms of water is equivalent to how many grams?	null
1,753	ac1ee910-6ddd-11ea-97e7-ccda262736ce	https://socratic.org/questions/what-is-the-ph-of-a-solution-in-which-25-0-ml-of-a-0-100-m-solution-of-naoh-has-	1.22	start physical_unit 6 6 ph none qc_end physical_unit 6 6 9 10 volume qc_end physical_unit 17 17 13 14 molarity qc_end physical_unit 28 29 22 23 volume qc_end physical_unit 28 29 13 14 molarity qc_end end	[{"type":"physical unit","value":"pH [OF] the solution"}]	[{"type":"physical unit","value":"1.22"}]	[{"type":"physical unit","value":"Volume [OF] NaOH solution [=] \\pu{25.0 mL}"},{"type":"physical unit","value":"Molarity [OF] NaOH solution [=] \\pu{0.100 M}"},{"type":"physical unit","value":"Volume [OF] HCl solution [=] \\pu{100.0 mL}"},{"type":"physical unit","value":"Molarity [OF] HCl solution [=] \\pu{0.100 M}"}]	<h1 class="questionTitle" itemprop="name">What is the pH of a solution in which #"25.0 mL"# of a #"0.100-M"# solution of #"NaOH"# has been added to #"100. mL"# of a #"0.100-M"# #"HCl"# solution? </h1>	null	1.22	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>As you know, sodium hydroxide and hydrochloric acid neutralize each other in a <mathjax>#1:1#</mathjax> <strong>mole ratio</strong> as described by the balanced chemical equation</p> <blockquote> <p><mathjax>#"NaOH"_ ((aq)) + "HCl"_ ((aq)) -> "NaCl"_ ((aq)) + "H"_ 2"O"_ ((l))#</mathjax></p> </blockquote> <p>This means that a <em>complete <a href="https://socratic.org/chemistry/reactions-in-solution/neutralization">neutralization</a></em>, which would result in a <strong>neutral solution</strong>, i.e. a solution that has <mathjax>#"pH" = 7#</mathjax> at room temperature, requires <strong>equal numbers of moles</strong> of sodium hydroxide and hydrochloric acid. </p> <p>Notice that your two <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> have <strong>equal molarities</strong>, but that the volume of the hydrochloric acid solution is </p> <blockquote> <p><mathjax>#(100. color(red)(cancel(color(black)("mL"))))/(25.0color(red)(cancel(color(black)("mL")))) = 4#</mathjax></p> </blockquote> <p><strong>times larger</strong> than the volume of the sodium hydroxide solution. This implies that the number of moles of hydrochloric acid is <mathjax>#4#</mathjax> <strong>times bigger</strong> than the number of moles of sodium hydroxide.</p> <p>This means that after the reaction is complete, you will be left with <em>excess</em> hydrochloric acid <mathjax>#->#</mathjax> the <mathjax>#"pH"#</mathjax> of the resulting solution will be <mathjax>#< 7#</mathjax>.</p> <p>Now, the number of moles of hydrochloric acid that will <strong>not take part in the reaction</strong> is given by</p> <blockquote> <p><mathjax>#overbrace(100. color(red)(cancel(color(black)("mL"))) * "0.100 moles HCl"/(10^3color(red)(cancel(color(black)("mL")))))^(color(blue)("moles of HCl added")) - overbrace(25.0 color(red)(cancel(color(black)("mL"))) * "0.100 moles NaOH"/(10^3color(red)(cancel(color(black)("mL")))))^(color(blue)("moles of NaOH added"))#</mathjax></p> <blockquote> <blockquote> <p><mathjax># = underbrace(((75 * 0.100)/10^3)color(white)(.)"moles HCl")_(color(blue)("what is not consumed by the reaction"))#</mathjax></p> </blockquote> </blockquote> </blockquote> <p>The <strong>total volume</strong> of the resulting solution will be</p> <blockquote> <p><mathjax>#"25.0 mL + 100. mL = 125 mL"#</mathjax></p> </blockquote> <p>As you know, the <mathjax>#"pH"#</mathjax> of the solution is given by</p> <blockquote> <p><mathjax>#"pH" = - log(["H"_3"O"^(+)])#</mathjax></p> </blockquote> <p>Since hydrochloric acid is a <strong>strong acid</strong> that ionizes in a <mathjax>#1:1#</mathjax> <strong>mole ratio</strong> to produce hydronium cations, you can say that the concentration of hydronium cations in the resulting solution will be</p> <blockquote> <p><mathjax>#["H"_3"O"^(+)] = (((75 * 0.100)/color(blue)(cancel(color(black)(10^3))))color(white)(.)"moles H"_3"O"^(+))/(125 * color(blue)(cancel(color(black)(10^3)))color(white)(.)"L") = ((75 * 0.100)/125)"mol L"^(-1)#</mathjax></p> </blockquote> <p>This means that you have</p> <blockquote> <p><mathjax>#"pH" = - log((75 * 0.100)/125) = color(darkgreen)(ul(color(black)(1.222)#</mathjax></p> </blockquote> <p>The answer is rounded to three <em>decimal places</em>, the number of <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong> you have for your values. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"pH" = 1.222#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>As you know, sodium hydroxide and hydrochloric acid neutralize each other in a <mathjax>#1:1#</mathjax> <strong>mole ratio</strong> as described by the balanced chemical equation</p> <blockquote> <p><mathjax>#"NaOH"_ ((aq)) + "HCl"_ ((aq)) -> "NaCl"_ ((aq)) + "H"_ 2"O"_ ((l))#</mathjax></p> </blockquote> <p>This means that a <em>complete <a href="https://socratic.org/chemistry/reactions-in-solution/neutralization">neutralization</a></em>, which would result in a <strong>neutral solution</strong>, i.e. a solution that has <mathjax>#"pH" = 7#</mathjax> at room temperature, requires <strong>equal numbers of moles</strong> of sodium hydroxide and hydrochloric acid. </p> <p>Notice that your two <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> have <strong>equal molarities</strong>, but that the volume of the hydrochloric acid solution is </p> <blockquote> <p><mathjax>#(100. color(red)(cancel(color(black)("mL"))))/(25.0color(red)(cancel(color(black)("mL")))) = 4#</mathjax></p> </blockquote> <p><strong>times larger</strong> than the volume of the sodium hydroxide solution. This implies that the number of moles of hydrochloric acid is <mathjax>#4#</mathjax> <strong>times bigger</strong> than the number of moles of sodium hydroxide.</p> <p>This means that after the reaction is complete, you will be left with <em>excess</em> hydrochloric acid <mathjax>#->#</mathjax> the <mathjax>#"pH"#</mathjax> of the resulting solution will be <mathjax>#< 7#</mathjax>.</p> <p>Now, the number of moles of hydrochloric acid that will <strong>not take part in the reaction</strong> is given by</p> <blockquote> <p><mathjax>#overbrace(100. color(red)(cancel(color(black)("mL"))) * "0.100 moles HCl"/(10^3color(red)(cancel(color(black)("mL")))))^(color(blue)("moles of HCl added")) - overbrace(25.0 color(red)(cancel(color(black)("mL"))) * "0.100 moles NaOH"/(10^3color(red)(cancel(color(black)("mL")))))^(color(blue)("moles of NaOH added"))#</mathjax></p> <blockquote> <blockquote> <p><mathjax># = underbrace(((75 * 0.100)/10^3)color(white)(.)"moles HCl")_(color(blue)("what is not consumed by the reaction"))#</mathjax></p> </blockquote> </blockquote> </blockquote> <p>The <strong>total volume</strong> of the resulting solution will be</p> <blockquote> <p><mathjax>#"25.0 mL + 100. mL = 125 mL"#</mathjax></p> </blockquote> <p>As you know, the <mathjax>#"pH"#</mathjax> of the solution is given by</p> <blockquote> <p><mathjax>#"pH" = - log(["H"_3"O"^(+)])#</mathjax></p> </blockquote> <p>Since hydrochloric acid is a <strong>strong acid</strong> that ionizes in a <mathjax>#1:1#</mathjax> <strong>mole ratio</strong> to produce hydronium cations, you can say that the concentration of hydronium cations in the resulting solution will be</p> <blockquote> <p><mathjax>#["H"_3"O"^(+)] = (((75 * 0.100)/color(blue)(cancel(color(black)(10^3))))color(white)(.)"moles H"_3"O"^(+))/(125 * color(blue)(cancel(color(black)(10^3)))color(white)(.)"L") = ((75 * 0.100)/125)"mol L"^(-1)#</mathjax></p> </blockquote> <p>This means that you have</p> <blockquote> <p><mathjax>#"pH" = - log((75 * 0.100)/125) = color(darkgreen)(ul(color(black)(1.222)#</mathjax></p> </blockquote> <p>The answer is rounded to three <em>decimal places</em>, the number of <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong> you have for your values. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the pH of a solution in which #"25.0 mL"# of a #"0.100-M"# solution of #"NaOH"# has been added to #"100. mL"# of a #"0.100-M"# #"HCl"# solution? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/the-ph-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">pH</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="491742" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-10-18T13:50:06" itemprop="dateCreated"> Oct 18, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"pH" = 1.222#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>As you know, sodium hydroxide and hydrochloric acid neutralize each other in a <mathjax>#1:1#</mathjax> <strong>mole ratio</strong> as described by the balanced chemical equation</p> <blockquote> <p><mathjax>#"NaOH"_ ((aq)) + "HCl"_ ((aq)) -> "NaCl"_ ((aq)) + "H"_ 2"O"_ ((l))#</mathjax></p> </blockquote> <p>This means that a <em>complete <a href="https://socratic.org/chemistry/reactions-in-solution/neutralization">neutralization</a></em>, which would result in a <strong>neutral solution</strong>, i.e. a solution that has <mathjax>#"pH" = 7#</mathjax> at room temperature, requires <strong>equal numbers of moles</strong> of sodium hydroxide and hydrochloric acid. </p> <p>Notice that your two <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> have <strong>equal molarities</strong>, but that the volume of the hydrochloric acid solution is </p> <blockquote> <p><mathjax>#(100. color(red)(cancel(color(black)("mL"))))/(25.0color(red)(cancel(color(black)("mL")))) = 4#</mathjax></p> </blockquote> <p><strong>times larger</strong> than the volume of the sodium hydroxide solution. This implies that the number of moles of hydrochloric acid is <mathjax>#4#</mathjax> <strong>times bigger</strong> than the number of moles of sodium hydroxide.</p> <p>This means that after the reaction is complete, you will be left with <em>excess</em> hydrochloric acid <mathjax>#->#</mathjax> the <mathjax>#"pH"#</mathjax> of the resulting solution will be <mathjax>#< 7#</mathjax>.</p> <p>Now, the number of moles of hydrochloric acid that will <strong>not take part in the reaction</strong> is given by</p> <blockquote> <p><mathjax>#overbrace(100. color(red)(cancel(color(black)("mL"))) * "0.100 moles HCl"/(10^3color(red)(cancel(color(black)("mL")))))^(color(blue)("moles of HCl added")) - overbrace(25.0 color(red)(cancel(color(black)("mL"))) * "0.100 moles NaOH"/(10^3color(red)(cancel(color(black)("mL")))))^(color(blue)("moles of NaOH added"))#</mathjax></p> <blockquote> <blockquote> <p><mathjax># = underbrace(((75 * 0.100)/10^3)color(white)(.)"moles HCl")_(color(blue)("what is not consumed by the reaction"))#</mathjax></p> </blockquote> </blockquote> </blockquote> <p>The <strong>total volume</strong> of the resulting solution will be</p> <blockquote> <p><mathjax>#"25.0 mL + 100. mL = 125 mL"#</mathjax></p> </blockquote> <p>As you know, the <mathjax>#"pH"#</mathjax> of the solution is given by</p> <blockquote> <p><mathjax>#"pH" = - log(["H"_3"O"^(+)])#</mathjax></p> </blockquote> <p>Since hydrochloric acid is a <strong>strong acid</strong> that ionizes in a <mathjax>#1:1#</mathjax> <strong>mole ratio</strong> to produce hydronium cations, you can say that the concentration of hydronium cations in the resulting solution will be</p> <blockquote> <p><mathjax>#["H"_3"O"^(+)] = (((75 * 0.100)/color(blue)(cancel(color(black)(10^3))))color(white)(.)"moles H"_3"O"^(+))/(125 * color(blue)(cancel(color(black)(10^3)))color(white)(.)"L") = ((75 * 0.100)/125)"mol L"^(-1)#</mathjax></p> </blockquote> <p>This means that you have</p> <blockquote> <p><mathjax>#"pH" = - log((75 * 0.100)/125) = color(darkgreen)(ul(color(black)(1.222)#</mathjax></p> </blockquote> <p>The answer is rounded to three <em>decimal places</em>, the number of <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong> you have for your values. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/491742" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-pka"> How do you determine pH from pKa? 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1,754	aa45b55c-6ddd-11ea-8998-ccda262736ce	https://socratic.org/questions/what-is-ph-of-a-1-5-m-solution-of-ammonia-the-dissociation-constant-of-ammonia-a	11.72	start physical_unit 7 7 ph none qc_end physical_unit 9 9 5 6 molarity qc_end physical_unit 9 9 19 21 equilibrium_constant_k qc_end physical_unit 9 9 16 17 temperature qc_end end	[{"type":"physical unit","value":"pH [OF] ammonia solution"}]	[{"type":"physical unit","value":"11.72"}]	[{"type":"physical unit","value":"Molarity [OF] ammonia solution [=] \\pu{1.5 M}"},{"type":"physical unit","value":"Dissociation constant [OF] ammonia [=] \\pu{1.80 × 10^(-5)}"},{"type":"physical unit","value":"Temperature [OF] ammonia [=] \\pu{25.0 ℃}"}]	<h1 class="questionTitle" itemprop="name">What is the #"pH"# of a #"1.5-M"# solution of ammonia? The dissociation constant of ammonia at #25.0^@"C"# is #1.80 * 10^-5#.</h1>	null	11.72	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>As you know, ammonia acts as a <strong>weak base</strong> in aqueous solution, so right from the start, you should expect the <mathjax>#"pH"#</mathjax> of the solution to be <mathjax>#> 7#</mathjax>. </p> <blockquote> <p><mathjax>#"NH"_ (3(aq)) + "H"_ 2"O"_ ((l)) rightleftharpoons "NH"_ (4(aq))^(+) + "OH"_ ((aq))^(-)#</mathjax></p> </blockquote> <p>The ratio that exists between the <strong>equilibrium concentrations</strong> of the ammonium cations and of the hydroxide anions and the <strong>equilibrium concentration</strong> of ammonia is given by the <strong>base dissociation constant</strong>, <mathjax>#K_b#</mathjax>.</p> <blockquote> <p><mathjax>#K_b = (["NH"_4^(+)] * ["OH"^(-)])/(["NH"_3])#</mathjax></p> </blockquote> <p>Now, ammonia will only <em>partially ionize</em> to produce ammonium cations and hydroxide anions. If you take <mathjax>#x#</mathjax> <mathjax>#"M"#</mathjax> to be the concentration of ammonia <strong>that ionizes</strong>, you can say that, at equilibrium, the solution will contain </p> <blockquote> <p><mathjax>#["NH"_4^(+)] = ["OH"^(-)] = x quad "M"#</mathjax></p> <blockquote> <p>This happens because <strong>every mole</strong> of ammonia <strong>that ionizes</strong> produces <mathjax>#1#</mathjax> <strong>mole</strong> of ammonium cations and <mathjax>#1#</mathjax> <strong>mole</strong> of hydroxide anions.</p> <p>So if <mathjax>#x#</mathjax> <mathjax>#"M"#</mathjax> <strong>ionizes</strong>, you can expect the solution to contain <mathjax>#x#</mathjax> <mathjax>#"M"#</mathjax> of the two ions. </p> </blockquote> </blockquote> <p>The solution will also contain</p> <blockquote> <p><mathjax>#["NH"_3] = (1.5 - x) quad "M"#</mathjax></p> <blockquote> <p>When <mathjax>#x#</mathjax> <mathjax>#"M"#</mathjax> <strong>ionizes</strong>, the initial concentration of ammonia will <strong>decrease</strong> by <mathjax>#x#</mathjax> <mathjax>#"M"#</mathjax>. </p> </blockquote> </blockquote> <p>This means that the expression of the base dissociation constant will now take the form</p> <blockquote> <p><mathjax>#K_b = (x * x)/(1.5 - x)#</mathjax></p> </blockquote> <p>which is equal to</p> <blockquote> <p><mathjax>#1.80 * 10^(-5) = x^2/(1.5 - x)#</mathjax></p> </blockquote> <p>Notice that the value of the base dissociation constant is <em>significantly smaller</em> than the initial concentration of the base. This tells you that you can use the approximation</p> <blockquote> <p><mathjax>#1.5 -x ~~ 1.5#</mathjax></p> </blockquote> <p>because the concentration of ammonia <strong>that ionizes</strong> will be significantly lower than the initial concentration of the base, i.e. the ionization equilibrium will <strong>lie to the left</strong>. </p> <p>You now have</p> <blockquote> <p><mathjax>#1.80 * 10^(-5) = x^2/1.5#</mathjax></p> </blockquote> <p>Rearrange and solve for <mathjax>#x#</mathjax> to get</p> <blockquote> <p><mathjax>#x = sqrt(1.5 * 1.80 * 10^(-5)) = 0.005196#</mathjax></p> </blockquote> <p>Since <mathjax>#x#</mathjax> <mathjax>#"M"#</mathjax> represents the equilibrium concentration of the hydroxide anions, you can say that </p> <blockquote> <p><mathjax>#["OH"^(-)] = "0.005196 M"#</mathjax></p> </blockquote> <p>Now, an aqueous solution at <mathjax>#25^@"C"#</mathjax> has</p> <blockquote> <p><mathjax>#"pH + pOH = 14"#</mathjax></p> </blockquote> <p>Since</p> <blockquote> <p><mathjax>#"pOH" = - log(["OH"^(-)])#</mathjax></p> </blockquote> <p>you can say that the <mathjax>#"pH"#</mathjax> of the solution is given by</p> <blockquote> <p><mathjax>#"pH" = 14 + log(["OH"^(-)])#</mathjax></p> </blockquote> <p>Plug in your value to find</p> <blockquote> <p><mathjax>#"pH" = 14 + log(0.005196) = color(darkgreen)(ul(color(black)(11.72)))#</mathjax></p> </blockquote> <p>The answer is rounded to two <strong>decimal places</strong> because you have two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong> for the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of the solution. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"pH" = 11.72#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>As you know, ammonia acts as a <strong>weak base</strong> in aqueous solution, so right from the start, you should expect the <mathjax>#"pH"#</mathjax> of the solution to be <mathjax>#> 7#</mathjax>. </p> <blockquote> <p><mathjax>#"NH"_ (3(aq)) + "H"_ 2"O"_ ((l)) rightleftharpoons "NH"_ (4(aq))^(+) + "OH"_ ((aq))^(-)#</mathjax></p> </blockquote> <p>The ratio that exists between the <strong>equilibrium concentrations</strong> of the ammonium cations and of the hydroxide anions and the <strong>equilibrium concentration</strong> of ammonia is given by the <strong>base dissociation constant</strong>, <mathjax>#K_b#</mathjax>.</p> <blockquote> <p><mathjax>#K_b = (["NH"_4^(+)] * ["OH"^(-)])/(["NH"_3])#</mathjax></p> </blockquote> <p>Now, ammonia will only <em>partially ionize</em> to produce ammonium cations and hydroxide anions. If you take <mathjax>#x#</mathjax> <mathjax>#"M"#</mathjax> to be the concentration of ammonia <strong>that ionizes</strong>, you can say that, at equilibrium, the solution will contain </p> <blockquote> <p><mathjax>#["NH"_4^(+)] = ["OH"^(-)] = x quad "M"#</mathjax></p> <blockquote> <p>This happens because <strong>every mole</strong> of ammonia <strong>that ionizes</strong> produces <mathjax>#1#</mathjax> <strong>mole</strong> of ammonium cations and <mathjax>#1#</mathjax> <strong>mole</strong> of hydroxide anions.</p> <p>So if <mathjax>#x#</mathjax> <mathjax>#"M"#</mathjax> <strong>ionizes</strong>, you can expect the solution to contain <mathjax>#x#</mathjax> <mathjax>#"M"#</mathjax> of the two ions. </p> </blockquote> </blockquote> <p>The solution will also contain</p> <blockquote> <p><mathjax>#["NH"_3] = (1.5 - x) quad "M"#</mathjax></p> <blockquote> <p>When <mathjax>#x#</mathjax> <mathjax>#"M"#</mathjax> <strong>ionizes</strong>, the initial concentration of ammonia will <strong>decrease</strong> by <mathjax>#x#</mathjax> <mathjax>#"M"#</mathjax>. </p> </blockquote> </blockquote> <p>This means that the expression of the base dissociation constant will now take the form</p> <blockquote> <p><mathjax>#K_b = (x * x)/(1.5 - x)#</mathjax></p> </blockquote> <p>which is equal to</p> <blockquote> <p><mathjax>#1.80 * 10^(-5) = x^2/(1.5 - x)#</mathjax></p> </blockquote> <p>Notice that the value of the base dissociation constant is <em>significantly smaller</em> than the initial concentration of the base. This tells you that you can use the approximation</p> <blockquote> <p><mathjax>#1.5 -x ~~ 1.5#</mathjax></p> </blockquote> <p>because the concentration of ammonia <strong>that ionizes</strong> will be significantly lower than the initial concentration of the base, i.e. the ionization equilibrium will <strong>lie to the left</strong>. </p> <p>You now have</p> <blockquote> <p><mathjax>#1.80 * 10^(-5) = x^2/1.5#</mathjax></p> </blockquote> <p>Rearrange and solve for <mathjax>#x#</mathjax> to get</p> <blockquote> <p><mathjax>#x = sqrt(1.5 * 1.80 * 10^(-5)) = 0.005196#</mathjax></p> </blockquote> <p>Since <mathjax>#x#</mathjax> <mathjax>#"M"#</mathjax> represents the equilibrium concentration of the hydroxide anions, you can say that </p> <blockquote> <p><mathjax>#["OH"^(-)] = "0.005196 M"#</mathjax></p> </blockquote> <p>Now, an aqueous solution at <mathjax>#25^@"C"#</mathjax> has</p> <blockquote> <p><mathjax>#"pH + pOH = 14"#</mathjax></p> </blockquote> <p>Since</p> <blockquote> <p><mathjax>#"pOH" = - log(["OH"^(-)])#</mathjax></p> </blockquote> <p>you can say that the <mathjax>#"pH"#</mathjax> of the solution is given by</p> <blockquote> <p><mathjax>#"pH" = 14 + log(["OH"^(-)])#</mathjax></p> </blockquote> <p>Plug in your value to find</p> <blockquote> <p><mathjax>#"pH" = 14 + log(0.005196) = color(darkgreen)(ul(color(black)(11.72)))#</mathjax></p> </blockquote> <p>The answer is rounded to two <strong>decimal places</strong> because you have two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong> for the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of the solution. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the #"pH"# of a #"1.5-M"# solution of ammonia? The dissociation constant of ammonia at #25.0^@"C"# is #1.80 * 10^-5#.</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/the-ph-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">pH</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="595656" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-04-16T00:36:48" itemprop="dateCreated"> Apr 16, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"pH" = 11.72#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>As you know, ammonia acts as a <strong>weak base</strong> in aqueous solution, so right from the start, you should expect the <mathjax>#"pH"#</mathjax> of the solution to be <mathjax>#> 7#</mathjax>. </p> <blockquote> <p><mathjax>#"NH"_ (3(aq)) + "H"_ 2"O"_ ((l)) rightleftharpoons "NH"_ (4(aq))^(+) + "OH"_ ((aq))^(-)#</mathjax></p> </blockquote> <p>The ratio that exists between the <strong>equilibrium concentrations</strong> of the ammonium cations and of the hydroxide anions and the <strong>equilibrium concentration</strong> of ammonia is given by the <strong>base dissociation constant</strong>, <mathjax>#K_b#</mathjax>.</p> <blockquote> <p><mathjax>#K_b = (["NH"_4^(+)] * ["OH"^(-)])/(["NH"_3])#</mathjax></p> </blockquote> <p>Now, ammonia will only <em>partially ionize</em> to produce ammonium cations and hydroxide anions. If you take <mathjax>#x#</mathjax> <mathjax>#"M"#</mathjax> to be the concentration of ammonia <strong>that ionizes</strong>, you can say that, at equilibrium, the solution will contain </p> <blockquote> <p><mathjax>#["NH"_4^(+)] = ["OH"^(-)] = x quad "M"#</mathjax></p> <blockquote> <p>This happens because <strong>every mole</strong> of ammonia <strong>that ionizes</strong> produces <mathjax>#1#</mathjax> <strong>mole</strong> of ammonium cations and <mathjax>#1#</mathjax> <strong>mole</strong> of hydroxide anions.</p> <p>So if <mathjax>#x#</mathjax> <mathjax>#"M"#</mathjax> <strong>ionizes</strong>, you can expect the solution to contain <mathjax>#x#</mathjax> <mathjax>#"M"#</mathjax> of the two ions. </p> </blockquote> </blockquote> <p>The solution will also contain</p> <blockquote> <p><mathjax>#["NH"_3] = (1.5 - x) quad "M"#</mathjax></p> <blockquote> <p>When <mathjax>#x#</mathjax> <mathjax>#"M"#</mathjax> <strong>ionizes</strong>, the initial concentration of ammonia will <strong>decrease</strong> by <mathjax>#x#</mathjax> <mathjax>#"M"#</mathjax>. </p> </blockquote> </blockquote> <p>This means that the expression of the base dissociation constant will now take the form</p> <blockquote> <p><mathjax>#K_b = (x * x)/(1.5 - x)#</mathjax></p> </blockquote> <p>which is equal to</p> <blockquote> <p><mathjax>#1.80 * 10^(-5) = x^2/(1.5 - x)#</mathjax></p> </blockquote> <p>Notice that the value of the base dissociation constant is <em>significantly smaller</em> than the initial concentration of the base. This tells you that you can use the approximation</p> <blockquote> <p><mathjax>#1.5 -x ~~ 1.5#</mathjax></p> </blockquote> <p>because the concentration of ammonia <strong>that ionizes</strong> will be significantly lower than the initial concentration of the base, i.e. the ionization equilibrium will <strong>lie to the left</strong>. </p> <p>You now have</p> <blockquote> <p><mathjax>#1.80 * 10^(-5) = x^2/1.5#</mathjax></p> </blockquote> <p>Rearrange and solve for <mathjax>#x#</mathjax> to get</p> <blockquote> <p><mathjax>#x = sqrt(1.5 * 1.80 * 10^(-5)) = 0.005196#</mathjax></p> </blockquote> <p>Since <mathjax>#x#</mathjax> <mathjax>#"M"#</mathjax> represents the equilibrium concentration of the hydroxide anions, you can say that </p> <blockquote> <p><mathjax>#["OH"^(-)] = "0.005196 M"#</mathjax></p> </blockquote> <p>Now, an aqueous solution at <mathjax>#25^@"C"#</mathjax> has</p> <blockquote> <p><mathjax>#"pH + pOH = 14"#</mathjax></p> </blockquote> <p>Since</p> <blockquote> <p><mathjax>#"pOH" = - log(["OH"^(-)])#</mathjax></p> </blockquote> <p>you can say that the <mathjax>#"pH"#</mathjax> of the solution is given by</p> <blockquote> <p><mathjax>#"pH" = 14 + log(["OH"^(-)])#</mathjax></p> </blockquote> <p>Plug in your value to find</p> <blockquote> <p><mathjax>#"pH" = 14 + log(0.005196) = color(darkgreen)(ul(color(black)(11.72)))#</mathjax></p> </blockquote> <p>The answer is rounded to two <strong>decimal places</strong> because you have two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong> for the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of the solution. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/595656" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-pka"> How do you determine pH from pKa? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-ph-values-of-acids-and-bases-differ"> How do pH values of acids and bases differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-something-on-a-ph-scale"> How do you calculate something on a pH scale? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-diprotic-acid"> How do you calculate pH diprotic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-from-acid-dissociation-constant"> How do you calculate pH from acid dissociation constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-of-acid-and-base-solution"> How do you calculate pH of acid and base solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ph-scale-0-14"> Why is the pH scale 0-14? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-ph-the-measure-of-the-hydrogen-ion-concentration"> Is pH a measure of the hydrogen ion concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-solubility-affect-ph"> How does solubility affect pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-ph-relate-to-pka-in-a-titration"> How does pH relate to pKa in a titration? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/the-ph-concept"> See all questions in pH </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 52297 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the #"pH"# of a #"1.5-M"# solution of ammonia? The dissociation constant of ammonia at #25.0^@"C"# is #1.80 * 10^-5#.	null
1,755	a837d30b-6ddd-11ea-82e0-ccda262736ce	https://socratic.org/questions/what-is-the-oxidation-state-of-each-individual-carbon-atom-in-c2o4-2	+3	start physical_unit 6 8 oxidation_state none qc_end chemical_equation 11 11 qc_end end	[{"type":"physical unit","value":"Oxidation state [OF] each individual carbon "}]	[{"type":"physical unit","value":"+3"}]	[{"type":"chemical equation","value":"C2O4^(-2)"}]	<h1 class="questionTitle" itemprop="name">What is the oxidation state of each individual carbon atom in C2O4^(-2)?</h1>	null	+3	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The oxygen all have a -2 oxidation state. (peroxides are exceptions)</p> <p>The chemical structure is symmetrical. Both carbon are equivalent.</p> <p>2 (oxidation state of carbon) + 4 (oxidation state of oxygen) = charge of ion.</p> <p>2 (oxidation state of carbon) + 4 (-2) = -2</p> <p>oxidation state of carbon = +3</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Both are +3</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The oxygen all have a -2 oxidation state. (peroxides are exceptions)</p> <p>The chemical structure is symmetrical. Both carbon are equivalent.</p> <p>2 (oxidation state of carbon) + 4 (oxidation state of oxygen) = charge of ion.</p> <p>2 (oxidation state of carbon) + 4 (-2) = -2</p> <p>oxidation state of carbon = +3</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the oxidation state of each individual carbon atom in C2O4^(-2)?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#electrochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Electrochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/electrochemistry/oxidation-numbers" itemprop="url"> <span class="breadcrumb" itemprop="title">Oxidation Numbers</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="184632" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/bio"><img alt="" class="" src="https://profilepictures.socratic.org/Qm2uaSgSTeLzBx8JHnK7_bq.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/bio"> Bio </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-06T08:29:43" itemprop="dateCreated"> Nov 6, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Both are +3</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The oxygen all have a -2 oxidation state. (peroxides are exceptions)</p> <p>The chemical structure is symmetrical. Both carbon are equivalent.</p> <p>2 (oxidation state of carbon) + 4 (oxidation state of oxygen) = charge of ion.</p> <p>2 (oxidation state of carbon) + 4 (-2) = -2</p> <p>oxidation state of carbon = +3</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/184632" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="184634" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ali-h-1"><img alt="" class="" src="https://profilepictures.socratic.org/IITeL1YTQdODdLp0aJTL_StereoPicture%20copy.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ali-h-1"> Dr. Hayek </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-06T08:33:42" itemprop="dateCreated"> Nov 6, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#+3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The oxidation number of carbon atoms in <mathjax>#C_2O_4^(2-)#</mathjax> is the same for both atoms, it can be calculated as follows:</p> <p>The oxidation number of oxygen is <mathjax>#-2#</mathjax>, therefore, assuming that the oxidation number of <mathjax>#C#</mathjax> is <mathjax>#x#</mathjax>, then: <mathjax>#2x+4xx(-2)=-2 => 2x=+6 =>x=+3#</mathjax></p> <p>Therefore, the oxidation number of the carbon atom is <mathjax>#+3#</mathjax>.</p> <p>Note that, the oxidation number of Oxygen is always <mathjax>#-2#</mathjax> except in <mathjax>#H_2O_2#</mathjax> is <mathjax>#-1#</mathjax> and in <mathjax>#OF_2#</mathjax> is <mathjax>#+2#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/184634" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-relate-to-electron-configuration"> How do oxidation numbers relate to electron configuration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-relate-to-valence-electrons"> How do oxidation numbers relate to valence electrons? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-vary-with-the-periodic-table"> How do oxidation numbers vary with the periodic table? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-oxidation-number-of-an-element-in-a-compound"> How do you calculate the oxidation number of an element in a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-sulfur"> What is the oxidation number for sulfur? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-carbon"> What is the oxidation number for carbon? 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1,756	a8d38ade-6ddd-11ea-a266-ccda262736ce	https://socratic.org/questions/what-is-the-gram-formula-mass-of-cuso-4	159.60 g/mol	start physical_unit 7 7 molar_mass g/mol qc_end chemical_equation 7 7 qc_end end	[{"type":"physical unit","value":"Gram formula mass [OF] CuSO4 [IN] g/mol"}]	[{"type":"physical unit","value":"159.60 g/mol"}]	[{"type":"chemical equation","value":"CuSO4"}]	<h1 class="questionTitle" itemprop="name">What is the gram formula mass of #CuSO_4#? </h1>	null	159.60 g/mol	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Multiply the subscript for each element by its molar mass (atomic mass on periodic table in g/mol). Then add the results. This will give you the molar mass of the compound (mass of 1 mole).</p> <p><mathjax>#"Cu":#</mathjax><mathjax>#(1xx"63.546 g/mol")="63.546 g/mol"#</mathjax></p> <p><mathjax>#"S":#</mathjax><mathjax>#(1xx"32.065 g/mol")="32.06 g/mol"#</mathjax></p> <p><mathjax>#"O":#</mathjax><mathjax>#(4xx"15.999 g/mol")="63.996 g/mol"#</mathjax></p> <p><mathjax>#"CuSO"_4":#</mathjax><mathjax>#"63.546 g/mol"+"32.06 g/mol"+"63.996 g/mol"="159.60 g/mol"#</mathjax> (rounded to two decimal places)</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The gram formula mass of <mathjax>#"CuSO"_4"#</mathjax> is <mathjax>#"159.60 g/mol"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Multiply the subscript for each element by its molar mass (atomic mass on periodic table in g/mol). Then add the results. This will give you the molar mass of the compound (mass of 1 mole).</p> <p><mathjax>#"Cu":#</mathjax><mathjax>#(1xx"63.546 g/mol")="63.546 g/mol"#</mathjax></p> <p><mathjax>#"S":#</mathjax><mathjax>#(1xx"32.065 g/mol")="32.06 g/mol"#</mathjax></p> <p><mathjax>#"O":#</mathjax><mathjax>#(4xx"15.999 g/mol")="63.996 g/mol"#</mathjax></p> <p><mathjax>#"CuSO"_4":#</mathjax><mathjax>#"63.546 g/mol"+"32.06 g/mol"+"63.996 g/mol"="159.60 g/mol"#</mathjax> (rounded to two decimal places)</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the gram formula mass of #CuSO_4#? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="353501" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-12-18T02:58:14" itemprop="dateCreated"> Dec 18, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The gram formula mass of <mathjax>#"CuSO"_4"#</mathjax> is <mathjax>#"159.60 g/mol"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Multiply the subscript for each element by its molar mass (atomic mass on periodic table in g/mol). Then add the results. This will give you the molar mass of the compound (mass of 1 mole).</p> <p><mathjax>#"Cu":#</mathjax><mathjax>#(1xx"63.546 g/mol")="63.546 g/mol"#</mathjax></p> <p><mathjax>#"S":#</mathjax><mathjax>#(1xx"32.065 g/mol")="32.06 g/mol"#</mathjax></p> <p><mathjax>#"O":#</mathjax><mathjax>#(4xx"15.999 g/mol")="63.996 g/mol"#</mathjax></p> <p><mathjax>#"CuSO"_4":#</mathjax><mathjax>#"63.546 g/mol"+"32.06 g/mol"+"63.996 g/mol"="159.60 g/mol"#</mathjax> (rounded to two decimal places)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/353501" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2417 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the gram formula mass of #CuSO_4#?	null
1,757	a9aa493a-6ddd-11ea-a404-ccda262736ce	https://socratic.org/questions/what-is-the-mass-of-0-5-mole-of-co2	22 grams	start physical_unit 8 8 mass g qc_end physical_unit 8 8 5 6 mole qc_end end	[{"type":"physical unit","value":"Mass [OF] CO2 [IN] grams"}]	[{"type":"physical unit","value":"22 grams"}]	[{"type":"physical unit","value":"Mole [OF] CO2 [=] \\pu{0.5 moles}"}]	<h1 class="questionTitle" itemprop="name">What is the mass of 0.5 moles of #"CO"_2# ?</h1>	null	22 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We use the following formula </p> <p><mathjax>#n("moles") = (m("mass"))/(M("molar mass"))#</mathjax></p> <p>Rearranging this equation, we find that </p> <p><mathjax>#m = n * M#</mathjax></p> <p>We are given the moles <mathjax>#(0.5)#</mathjax>, so we need to find the molar mass. I'm assuming you are given a table of molar values of <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> such as carbon is <mathjax>#"12 g/mol"#</mathjax>..</p> <p>So to find moles, we add all the molar values together</p> <p><mathjax>#M("CO"_2) = M("C") + 2M("O")#</mathjax></p> <p><mathjax>#M("CO"_2) = (12 + 216) \ "g/mol"#</mathjax></p> <p><mathjax>#M("CO"_2) = 44 \ "g/mol"#</mathjax></p> <p>Therefore, we can then use the above-rearranged equation to find <mathjax>#m#</mathjax>:</p> <p><mathjax>#m = "0.5 moles" * "44 g/mol"#</mathjax></p> <p><mathjax>#m = "22 g"#</mathjax> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#22#</mathjax> grams.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We use the following formula </p> <p><mathjax>#n("moles") = (m("mass"))/(M("molar mass"))#</mathjax></p> <p>Rearranging this equation, we find that </p> <p><mathjax>#m = n * M#</mathjax></p> <p>We are given the moles <mathjax>#(0.5)#</mathjax>, so we need to find the molar mass. I'm assuming you are given a table of molar values of <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> such as carbon is <mathjax>#"12 g/mol"#</mathjax>..</p> <p>So to find moles, we add all the molar values together</p> <p><mathjax>#M("CO"_2) = M("C") + 2M("O")#</mathjax></p> <p><mathjax>#M("CO"_2) = (12 + 216) \ "g/mol"#</mathjax></p> <p><mathjax>#M("CO"_2) = 44 \ "g/mol"#</mathjax></p> <p>Therefore, we can then use the above-rearranged equation to find <mathjax>#m#</mathjax>:</p> <p><mathjax>#m = "0.5 moles" * "44 g/mol"#</mathjax></p> <p><mathjax>#m = "22 g"#</mathjax> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the mass of 0.5 moles of #"CO"_2# ?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="635755" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/joshua-b-3"><img alt="" class="" src="https://lh3.googleusercontent.com/-XdUIqdMkCWA/AAAAAAAAAAI/AAAAAAAAAAA/4252rscbv5M/photo.jpg?sz=50" title=""/></a> <a class="secondContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/joshua-b-3"> Joshua B. </a>·<a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-06-26T11:52:50" itemprop="dateCreated"> Jun 26, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#22#</mathjax> grams.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We use the following formula </p> <p><mathjax>#n("moles") = (m("mass"))/(M("molar mass"))#</mathjax></p> <p>Rearranging this equation, we find that </p> <p><mathjax>#m = n * M#</mathjax></p> <p>We are given the moles <mathjax>#(0.5)#</mathjax>, so we need to find the molar mass. I'm assuming you are given a table of molar values of <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> such as carbon is <mathjax>#"12 g/mol"#</mathjax>..</p> <p>So to find moles, we add all the molar values together</p> <p><mathjax>#M("CO"_2) = M("C") + 2M("O")#</mathjax></p> <p><mathjax>#M("CO"_2) = (12 + 216) \ "g/mol"#</mathjax></p> <p><mathjax>#M("CO"_2) = 44 \ "g/mol"#</mathjax></p> <p>Therefore, we can then use the above-rearranged equation to find <mathjax>#m#</mathjax>:</p> <p><mathjax>#m = "0.5 moles" * "44 g/mol"#</mathjax></p> <p><mathjax>#m = "22 g"#</mathjax> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/635755" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="636253" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/nam-d"><img alt="" class="" src="https://profilepictures.socratic.org/QG4MnkoER6u99DIDVWKK_787554714770341.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/nam-d"> Nam D. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-06-27T10:26:02" itemprop="dateCreated"> Jun 27, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#22#</mathjax> grams</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To find the mass of a certain number of moles of a substance, we multiply the number of moles of the substance by its molar mass.</p> <p>Carbon dioxide <mathjax>#(CO_2)#</mathjax> has a molar mass of <mathjax>#44.01 \ "g/mol"#</mathjax>. Here, there are <mathjax>#0.5 \ "mol"#</mathjax> of the molecule. So, the mass of this sample is:</p> <p><mathjax>#m=(44.01 \ "g")/(color(red)cancelcolor(black)"mol")*0.5color(red)cancelcolor(black)"mol"#</mathjax></p> <p><mathjax>#~~22 \ "g"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/636253" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 26858 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the mass of 0.5 moles of #"CO"_2# ?	null
1,758	a8d7345c-6ddd-11ea-bbc8-ccda262736ce	https://socratic.org/questions/what-is-the-empirical-formula-for-a-compound-that-is-found-to-contain-10-15-mg-p	PCl3	start chemical_formula qc_end physical_unit 15 15 13 14 mass qc_end physical_unit 19 19 17 18 mass qc_end end	[{"type":"other","value":"Chemical Formula [OF] the compound [IN] empirical"}]	[{"type":"chemical equation","value":"PCl3"}]	[{"type":"physical unit","value":"Mass [OF] P [=] \\pu{10.15 mg}"},{"type":"physical unit","value":"Mass [OF] Cl [=] \\pu{34.85 mg}"}]	<h1 class="questionTitle" itemprop="name">What is the empirical formula for a compound that is found to contain 10.15 mg #P# and 34.85 mg #Cl#?</h1>	null	PCl3	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#%P#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(10.15mg)/((34.85+10.15)mg)xx100%#</mathjax> <mathjax>#=#</mathjax> <mathjax>#22.6%#</mathjax></p> <p><mathjax>#%Cl#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(34.85mg)/((34.85+10.15)mg)xx100%#</mathjax> <mathjax>#=#</mathjax> <mathjax>#77.4%#</mathjax></p> <p>We use the percentages and assume <mathjax>#100#</mathjax> <mathjax>#g#</mathjax> of compound.</p> <p><mathjax>#P:#</mathjax> <mathjax>#(22.6g)/(30.9737gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.730mol#</mathjax> <mathjax>#P#</mathjax></p> <p><mathjax>#Cl:#</mathjax> <mathjax>#(77.4g)/(35.45gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#2.18mol#</mathjax> <mathjax>#Cl#</mathjax></p> <p>We divide thru by the SMALLER molar quantity to give an empirical formula of:</p> <p><mathjax>#PCl_3#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#PCl_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#%P#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(10.15mg)/((34.85+10.15)mg)xx100%#</mathjax> <mathjax>#=#</mathjax> <mathjax>#22.6%#</mathjax></p> <p><mathjax>#%Cl#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(34.85mg)/((34.85+10.15)mg)xx100%#</mathjax> <mathjax>#=#</mathjax> <mathjax>#77.4%#</mathjax></p> <p>We use the percentages and assume <mathjax>#100#</mathjax> <mathjax>#g#</mathjax> of compound.</p> <p><mathjax>#P:#</mathjax> <mathjax>#(22.6g)/(30.9737gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.730mol#</mathjax> <mathjax>#P#</mathjax></p> <p><mathjax>#Cl:#</mathjax> <mathjax>#(77.4g)/(35.45gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#2.18mol#</mathjax> <mathjax>#Cl#</mathjax></p> <p>We divide thru by the SMALLER molar quantity to give an empirical formula of:</p> <p><mathjax>#PCl_3#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the empirical formula for a compound that is found to contain 10.15 mg #P# and 34.85 mg #Cl#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="271099" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-29T19:39:53" itemprop="dateCreated"> May 29, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#PCl_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#%P#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(10.15mg)/((34.85+10.15)mg)xx100%#</mathjax> <mathjax>#=#</mathjax> <mathjax>#22.6%#</mathjax></p> <p><mathjax>#%Cl#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(34.85mg)/((34.85+10.15)mg)xx100%#</mathjax> <mathjax>#=#</mathjax> <mathjax>#77.4%#</mathjax></p> <p>We use the percentages and assume <mathjax>#100#</mathjax> <mathjax>#g#</mathjax> of compound.</p> <p><mathjax>#P:#</mathjax> <mathjax>#(22.6g)/(30.9737gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.730mol#</mathjax> <mathjax>#P#</mathjax></p> <p><mathjax>#Cl:#</mathjax> <mathjax>#(77.4g)/(35.45gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#2.18mol#</mathjax> <mathjax>#Cl#</mathjax></p> <p>We divide thru by the SMALLER molar quantity to give an empirical formula of:</p> <p><mathjax>#PCl_3#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/271099" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight 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class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the empirical formula for a compound that is found to contain 10.15 mg #P# and 34.85 mg #Cl#?	null
1,759	ac34fafb-6ddd-11ea-8930-ccda262736ce	https://socratic.org/questions/592725be7c014950762b5e26	8.80 × 10^(-12)	start physical_unit 14 15 equilibrium_constant_k none qc_end physical_unit 4 4 6 9 molar_solubility qc_end end	[{"type":"physical unit","value":"Ksp [OF] this salt"}]	[{"type":"physical unit","value":"8.80 × 10^(-12)"}]	[{"type":"physical unit","value":"Molar solubility [OF] Ag2CO3 [=] \\pu{1.3 × 10^(-4) mol/L}"}]	<h1 class="questionTitle" itemprop="name">The molar solubility of #Ag_2CO_3# is #1.3xx10^-4molL^-1#. What is #K_"sp"# for this salt?</h1>	null	8.80 × 10^(-12)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We interrogate the equilibrium:</p> <p><mathjax>#Ag_2CO_3(s) rightleftharpoons2Ag^(+) + CO_3^(2-)#</mathjax></p> <p>And thus <mathjax>#K_"sp"=[Ag^+]^2[CO_3^(2-)]#</mathjax></p> <p>But from the <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>, <mathjax>#[CO_3^(2-)]=S_(Ag_2CO_3)#</mathjax>, and <mathjax>#[Ag^+]=2S_(Ag_2CO_3)#</mathjax>........and so</p> <p><mathjax>#K_"sp"=Sxx(2S)^2=4S^3=4xx(1.3xx10^-4)^3=8.80xx10^-12.....#</mathjax></p> <p>This <a href="https://en.wikipedia.org/wiki/Silver_carbonate" rel="nofollow">site</a> reports that <mathjax>#K_"sp"#</mathjax>, <mathjax>#Ag_2CO_3#</mathjax>, is <mathjax>#8.46xx10^-12#</mathjax>, so our estimate is kosher. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#K_"sp"=8.80xx10^-12#</mathjax>..........</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We interrogate the equilibrium:</p> <p><mathjax>#Ag_2CO_3(s) rightleftharpoons2Ag^(+) + CO_3^(2-)#</mathjax></p> <p>And thus <mathjax>#K_"sp"=[Ag^+]^2[CO_3^(2-)]#</mathjax></p> <p>But from the <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>, <mathjax>#[CO_3^(2-)]=S_(Ag_2CO_3)#</mathjax>, and <mathjax>#[Ag^+]=2S_(Ag_2CO_3)#</mathjax>........and so</p> <p><mathjax>#K_"sp"=Sxx(2S)^2=4S^3=4xx(1.3xx10^-4)^3=8.80xx10^-12.....#</mathjax></p> <p>This <a href="https://en.wikipedia.org/wiki/Silver_carbonate" rel="nofollow">site</a> reports that <mathjax>#K_"sp"#</mathjax>, <mathjax>#Ag_2CO_3#</mathjax>, is <mathjax>#8.46xx10^-12#</mathjax>, so our estimate is kosher. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">The molar solubility of #Ag_2CO_3# is #1.3xx10^-4molL^-1#. What is #K_"sp"# for this salt?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-equilibrium" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Equilibrium</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-equilibrium/ksp" itemprop="url"> <span class="breadcrumb" itemprop="title">Ksp</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="429604" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-25T18:58:01" itemprop="dateCreated"> May 25, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#K_"sp"=8.80xx10^-12#</mathjax>..........</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We interrogate the equilibrium:</p> <p><mathjax>#Ag_2CO_3(s) rightleftharpoons2Ag^(+) + CO_3^(2-)#</mathjax></p> <p>And thus <mathjax>#K_"sp"=[Ag^+]^2[CO_3^(2-)]#</mathjax></p> <p>But from the <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>, <mathjax>#[CO_3^(2-)]=S_(Ag_2CO_3)#</mathjax>, and <mathjax>#[Ag^+]=2S_(Ag_2CO_3)#</mathjax>........and so</p> <p><mathjax>#K_"sp"=Sxx(2S)^2=4S^3=4xx(1.3xx10^-4)^3=8.80xx10^-12.....#</mathjax></p> <p>This <a href="https://en.wikipedia.org/wiki/Silver_carbonate" rel="nofollow">site</a> reports that <mathjax>#K_"sp"#</mathjax>, <mathjax>#Ag_2CO_3#</mathjax>, is <mathjax>#8.46xx10^-12#</mathjax>, so our estimate is kosher. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/429604" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-you-use-the-solubility-product-constant-to-calculate-the-solubility-of-a"> How can you use the solubility product constant to calculate the solubility of a sparingly... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5397ae9102bf3458eddf5130"> Question #f5130 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-ksp"> What is Ksp? 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</a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5536aaad581e2a253fd94985"> (a) How much aluminium hydroxide will dissolve in 500ml of water at #25^@C# given that... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-equilibrium/ksp"> See all questions in Ksp </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1757 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	The molar solubility of #Ag_2CO_3# is #1.3xx10^-4molL^-1#. What is #K_"sp"# for this salt?	null
1,760	ad041e62-6ddd-11ea-b5b3-ccda262736ce	https://socratic.org/questions/5840cc3811ef6b057b1ea5ca	0.36 g	start physical_unit 10 10 mass g qc_end end	[{"type":"physical unit","value":"Mass [OF] HCl [IN] g"}]	[{"type":"physical unit","value":"0.36 g"}]	[{"type":"physical unit","value":"Number [OF] HCl molecules [=] \\pu{6.12 × 10^21}"}]	<h1 class="questionTitle" itemprop="name">What is the mass of #6.12xx10^21# molecules of #"HCl"#?</h1>	null	0.36 g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>One mole of molecules = <mathjax># 6.02 xx 10^23#</mathjax> particles. </p> <p><mathjax># (6.12 xx 10^21)/ (6.02 xx 10^23 )= 1.02 xx 10^-2#</mathjax> moles </p> <p>One mole of HCl Hydrochloric acid = 36.5 grams </p> <p>1 H = 1 xx 1.00 gram/mole = 1.00 grams</p> <p>1 Cl = 1 xx 35.45 grams/mole = 35.5 grams ( to 3 sig numbers)</p> <p>1.00 + 35.5 = 36.5 grams/ moles </p> <p><mathjax># 36.5 "g" xx 1.02xx 10^-2 = 0.372 #</mathjax> grams </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.359 grams to three <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a>. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>One mole of molecules = <mathjax># 6.02 xx 10^23#</mathjax> particles. </p> <p><mathjax># (6.12 xx 10^21)/ (6.02 xx 10^23 )= 1.02 xx 10^-2#</mathjax> moles </p> <p>One mole of HCl Hydrochloric acid = 36.5 grams </p> <p>1 H = 1 xx 1.00 gram/mole = 1.00 grams</p> <p>1 Cl = 1 xx 35.45 grams/mole = 35.5 grams ( to 3 sig numbers)</p> <p>1.00 + 35.5 = 36.5 grams/ moles </p> <p><mathjax># 36.5 "g" xx 1.02xx 10^-2 = 0.372 #</mathjax> grams </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the mass of #6.12xx10^21# molecules of #"HCl"#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="348350" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/david-drayer"><img alt="" class="" src="https://graph.facebook.com/10206723679871989/picture?height=50&width=50" title=""/></a> <a class="secondContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/david-drayer"> David Drayer </a>·<a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-12-07T16:43:08" itemprop="dateCreated"> Dec 7, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.359 grams to three <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a>. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>One mole of molecules = <mathjax># 6.02 xx 10^23#</mathjax> particles. </p> <p><mathjax># (6.12 xx 10^21)/ (6.02 xx 10^23 )= 1.02 xx 10^-2#</mathjax> moles </p> <p>One mole of HCl Hydrochloric acid = 36.5 grams </p> <p>1 H = 1 xx 1.00 gram/mole = 1.00 grams</p> <p>1 Cl = 1 xx 35.45 grams/mole = 35.5 grams ( to 3 sig numbers)</p> <p>1.00 + 35.5 = 36.5 grams/ moles </p> <p><mathjax># 36.5 "g" xx 1.02xx 10^-2 = 0.372 #</mathjax> grams </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/348350" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div 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1,761	a8e4bddd-6ddd-11ea-b766-ccda262736ce	https://socratic.org/questions/the-volume-of-a-gas-is-250-ml-at-340-0-kpa-pressure-with-the-temperature-remaini	170 mL	start physical_unit 4 4 volume ml qc_end physical_unit 3 4 6 7 volume qc_end physical_unit 3 4 9 10 pressure qc_end c_other constant_temperature qc_end physical_unit 4 4 28 29 pressure qc_end end	[{"type":"physical unit","value":"Volume2 [OF] the gas [IN] mL"}]	[{"type":"physical unit","value":"170 mL"}]	[{"type":"physical unit","value":"Volume1 [OF] a gas [=] \\pu{250 mL}"},{"type":"physical unit","value":"Pressure1 [OF] a gas [=] \\pu{340.0 kPa}"},{"type":"other","value":"ConstantTemperature"},{"type":"physical unit","value":"Pressure2 [OF] the gas [=] \\pu{500.0 kPa}"}]	<h1 class="questionTitle" itemprop="name">The volume of a gas is 250 mL at 340.0 kPa pressure. With the temperature remaining constant what will the volume be when the pressure is reduced to 500.0 kPa? </h1>	null	170 mL	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>According to the data in the question, the pressure is <strong>increased</strong> from <mathjax>#"340.0 kPa"#</mathjax> to <mathjax>#"500.0 kPa"#</mathjax>.</p> <p>This is an example of the pressure-volume law, or <a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's law</a>, which states that the volume of a given amount of gas held at constant temperature varies inversely with the applied pressure when the temperature and mass are constant. This means that if the pressure increases, the volume decreases and vice versa. The equation for this law is:</p> <p><mathjax>#P_1V_1=P_2V_2#</mathjax></p> <p><strong>Known</strong></p> <p><mathjax>#P_1="340.0 kPa"#</mathjax></p> <p><mathjax>#V_1="250 mL"#</mathjax></p> <p><mathjax>#P_2="500.0 kPa"#</mathjax></p> <p><strong>Unknown</strong></p> <p><mathjax>#V_2#</mathjax></p> <p><strong>Solution</strong></p> <p>Rearrange the equation to isolate <mathjax>#V_2#</mathjax>. Plug in the known values and solve.</p> <p><mathjax>#V_2=(P_1V_1)/(P_2)#</mathjax></p> <p><mathjax>#V_2=(340.0color(red)cancel(color(black)("kPa"))xx"250 mL")/(500.0color(red)cancel(color(black)("kPa")))="170 mL"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The final volume will be <mathjax>#"170 mL"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>According to the data in the question, the pressure is <strong>increased</strong> from <mathjax>#"340.0 kPa"#</mathjax> to <mathjax>#"500.0 kPa"#</mathjax>.</p> <p>This is an example of the pressure-volume law, or <a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's law</a>, which states that the volume of a given amount of gas held at constant temperature varies inversely with the applied pressure when the temperature and mass are constant. This means that if the pressure increases, the volume decreases and vice versa. The equation for this law is:</p> <p><mathjax>#P_1V_1=P_2V_2#</mathjax></p> <p><strong>Known</strong></p> <p><mathjax>#P_1="340.0 kPa"#</mathjax></p> <p><mathjax>#V_1="250 mL"#</mathjax></p> <p><mathjax>#P_2="500.0 kPa"#</mathjax></p> <p><strong>Unknown</strong></p> <p><mathjax>#V_2#</mathjax></p> <p><strong>Solution</strong></p> <p>Rearrange the equation to isolate <mathjax>#V_2#</mathjax>. Plug in the known values and solve.</p> <p><mathjax>#V_2=(P_1V_1)/(P_2)#</mathjax></p> <p><mathjax>#V_2=(340.0color(red)cancel(color(black)("kPa"))xx"250 mL")/(500.0color(red)cancel(color(black)("kPa")))="170 mL"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">The volume of a gas is 250 mL at 340.0 kPa pressure. With the temperature remaining constant what will the volume be when the pressure is reduced to 500.0 kPa? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/boyle-s-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Boyle's Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="638016" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-07-03T02:49:57" itemprop="dateCreated"> Jul 3, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The final volume will be <mathjax>#"170 mL"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>According to the data in the question, the pressure is <strong>increased</strong> from <mathjax>#"340.0 kPa"#</mathjax> to <mathjax>#"500.0 kPa"#</mathjax>.</p> <p>This is an example of the pressure-volume law, or <a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's law</a>, which states that the volume of a given amount of gas held at constant temperature varies inversely with the applied pressure when the temperature and mass are constant. This means that if the pressure increases, the volume decreases and vice versa. The equation for this law is:</p> <p><mathjax>#P_1V_1=P_2V_2#</mathjax></p> <p><strong>Known</strong></p> <p><mathjax>#P_1="340.0 kPa"#</mathjax></p> <p><mathjax>#V_1="250 mL"#</mathjax></p> <p><mathjax>#P_2="500.0 kPa"#</mathjax></p> <p><strong>Unknown</strong></p> <p><mathjax>#V_2#</mathjax></p> <p><strong>Solution</strong></p> <p>Rearrange the equation to isolate <mathjax>#V_2#</mathjax>. Plug in the known values and solve.</p> <p><mathjax>#V_2=(P_1V_1)/(P_2)#</mathjax></p> <p><mathjax>#V_2=(340.0color(red)cancel(color(black)("kPa"))xx"250 mL")/(500.0color(red)cancel(color(black)("kPa")))="170 mL"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/638016" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-graph-boyles-law"> How do you graph Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-functional-groups-are-found-in-lipids"> What functional groups are found in lipids? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-k-constant-in-boyle-s-law"> Why is k constant in Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-boyle-s-law-graph-curved-1"> Why is Boyle's law graph curved? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-boyle-s-law-an-inverse-relationship-2"> Why is Boyle's law an inverse relationship? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-40-0-l-tank-of-ammonia-has-a-pressure-of-8-00-atm-calculate-the-volume-of-the-"> A 40.0 L tank of ammonia has a pressure of 8.00 atm. 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With the temperature remaining constant what will the volume be when the pressure is reduced to 500.0 kPa?	null
1,762	acccbc24-6ddd-11ea-9c8e-ccda262736ce	https://socratic.org/questions/what-is-the-formula-mass-of-ethyl-alcohol-c-2h-5oh	46.08 g/mol	start physical_unit 8 8 molecular_weight g/mol qc_end chemical_equation 8 8 qc_end end	[{"type":"physical unit","value":"Formula mass [OF] C2H5OH [IN] g/mol"}]	[{"type":"physical unit","value":"46.08 g/mol"}]	[{"type":"chemical equation","value":"C2H5OH"}]	<h1 class="questionTitle" itemprop="name">What is the formula mass of ethyl alcohol, #C_2H_5OH#?</h1>	null	46.08 g/mol	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to arrive with this answer, we should know the atomic weight of the <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> present in the compound—in this case, the elements are Carbon, Hydrogen, and Oxygen.</p> <p>The atomic weight for these elements are the following (expressed to the nearest hundredth):</p> <p>Carbon = 12.01 g/mol<br/> Oxygen = 16.00 g/mol<br/> Hydrogen = 1.01 g/mol</p> <p>Now, let's count the total number of each element (expressed in moles) bonded in the compound:</p> <p>Carbon = 2<br/> Oxygen = 1<br/> Hydrogen = 6</p> <p>To calculate for the formula, we should multiply the atomic weights of each element to the corresponding number of moles in the the compound. </p> <p>Carbon: 12.01 x 2 = 24.02<br/> Oxygen: 16.00 x 1 = 16.00<br/> Hydrogen: 1.01 x 6 = 6.06</p> <p>The sum is equal to 48.08 grams per mole; wherein grams per mole can also be denoted as <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">atomic mass</a> unit</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>46.08 gram per mole (g/mol)</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to arrive with this answer, we should know the atomic weight of the <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> present in the compound—in this case, the elements are Carbon, Hydrogen, and Oxygen.</p> <p>The atomic weight for these elements are the following (expressed to the nearest hundredth):</p> <p>Carbon = 12.01 g/mol<br/> Oxygen = 16.00 g/mol<br/> Hydrogen = 1.01 g/mol</p> <p>Now, let's count the total number of each element (expressed in moles) bonded in the compound:</p> <p>Carbon = 2<br/> Oxygen = 1<br/> Hydrogen = 6</p> <p>To calculate for the formula, we should multiply the atomic weights of each element to the corresponding number of moles in the the compound. </p> <p>Carbon: 12.01 x 2 = 24.02<br/> Oxygen: 16.00 x 1 = 16.00<br/> Hydrogen: 1.01 x 6 = 6.06</p> <p>The sum is equal to 48.08 grams per mole; wherein grams per mole can also be denoted as <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">atomic mass</a> unit</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the formula mass of ethyl alcohol, #C_2H_5OH#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="217218" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/louella-l"><img alt="" class="" src="https://profilepictures.socratic.org/aF4OLkdwQCKq8KjRhnbD_IMG_2988.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/louella-l"> Ella Labasbas </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-26T10:45:36" itemprop="dateCreated"> Jan 26, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>46.08 gram per mole (g/mol)</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to arrive with this answer, we should know the atomic weight of the <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> present in the compound—in this case, the elements are Carbon, Hydrogen, and Oxygen.</p> <p>The atomic weight for these elements are the following (expressed to the nearest hundredth):</p> <p>Carbon = 12.01 g/mol<br/> Oxygen = 16.00 g/mol<br/> Hydrogen = 1.01 g/mol</p> <p>Now, let's count the total number of each element (expressed in moles) bonded in the compound:</p> <p>Carbon = 2<br/> Oxygen = 1<br/> Hydrogen = 6</p> <p>To calculate for the formula, we should multiply the atomic weights of each element to the corresponding number of moles in the the compound. </p> <p>Carbon: 12.01 x 2 = 24.02<br/> Oxygen: 16.00 x 1 = 16.00<br/> Hydrogen: 1.01 x 6 = 6.06</p> <p>The sum is equal to 48.08 grams per mole; wherein grams per mole can also be denoted as <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">atomic mass</a> unit</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/217218" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 17921 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the formula mass of ethyl alcohol, #C_2H_5OH#?	null
1,763	aa1216fa-6ddd-11ea-9aaf-ccda262736ce	https://socratic.org/questions/589334dab72cff29416b6b10	1.81 × 10^24	start physical_unit 2 3 number none qc_end physical_unit 10 10 6 7 mole qc_end end	[{"type":"physical unit","value":"Number [OF] hydrogen atoms"}]	[{"type":"physical unit","value":"1.81 × 10^24"}]	[{"type":"physical unit","value":"Mole [OF] water [=] \\pu{15 mol}"}]	<h1 class="questionTitle" itemprop="name">How many hydrogen atoms in a #15*mol# quantity of water?</h1>	null	1.81 × 10^24	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We could have equally asked how many hydrogen atoms are there in the <mathjax>#"ONE molecule of water?"#</mathjax> Of course there are 2.</p> <p><a href="https://socratic.org/chemistry/the-mole-concept/the-mole">The mole</a> is simply another number, admittedly a very large number, i.e. <mathjax>#N_A=6.022xx10^23mol^-1#</mathjax>.</p> <p>And thus in a <mathjax>#15mol#</mathjax> quantity there are approx. <mathjax>#9xx10^24#</mathjax> <mathjax>#"hydrogen atoms"#</mathjax>. What is the mass of this number of <mathjax>#"hydrogen atoms"#</mathjax>?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#30xxN_A#</mathjax>, where <mathjax>#N_A="Avogadro's Number........."#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We could have equally asked how many hydrogen atoms are there in the <mathjax>#"ONE molecule of water?"#</mathjax> Of course there are 2.</p> <p><a href="https://socratic.org/chemistry/the-mole-concept/the-mole">The mole</a> is simply another number, admittedly a very large number, i.e. <mathjax>#N_A=6.022xx10^23mol^-1#</mathjax>.</p> <p>And thus in a <mathjax>#15mol#</mathjax> quantity there are approx. <mathjax>#9xx10^24#</mathjax> <mathjax>#"hydrogen atoms"#</mathjax>. What is the mass of this number of <mathjax>#"hydrogen atoms"#</mathjax>?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many hydrogen atoms in a #15mol# quantity of water?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="372596" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-02-02T16:03:11" itemprop="dateCreated"> Feb 2, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#30xxN_A#</mathjax>, where <mathjax>#N_A="Avogadro's Number........."#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We could have equally asked how many hydrogen atoms are there in the <mathjax>#"ONE molecule of water?"#</mathjax> Of course there are 2.</p> <p><a href="https://socratic.org/chemistry/the-mole-concept/the-mole">The mole</a> is simply another number, admittedly a very large number, i.e. <mathjax>#N_A=6.022xx10^23mol^-1#</mathjax>.</p> <p>And thus in a <mathjax>#15*mol#</mathjax> quantity there are approx. <mathjax>#9xx10^24#</mathjax> <mathjax>#"hydrogen atoms"#</mathjax>. What is the mass of this number of <mathjax>#"hydrogen atoms"#</mathjax>?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/372596" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2588 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many hydrogen atoms in a #15*mol# quantity of water?	null
1,764	aa394561-6ddd-11ea-b40f-ccda262736ce	https://socratic.org/questions/what-is-the-empirical-formula-of-a-compound-with-the-molecular-formula-n-2o-4	NO2	start chemical_formula qc_end c_other OTHER qc_end end	[{"type":"other","value":"Chemical Formula [OF] the compound [IN] empirical"}]	[{"type":"chemical equation","value":"NO2"}]	[{"type":"other","value":"The molecular formula of the compound is N2O4."}]	<h1 class="questionTitle" itemprop="name">What is the empirical formula of a compound with the molecular formula #N_2O_4#?</h1>	null	NO2	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Of course, the empirical formula of <mathjax>#N_2O_4#</mathjax> is <mathjax>#NO_2#</mathjax>. Why?</p> <p>The equilibrium <mathjax>#N_2O_4(g) rightleftharpoons 2NO_2(g)#</mathjax> has been well-studied. Dimerization of <mathjax>#NO_2#</mathjax> to give <mathjax>#N_2O_4#</mathjax> can be rationalized on the basis that the Lewis structure of <mathjax>#NO_2#</mathjax> (with 17 <a href="http://socratic.org/chemistry/the-periodic-table/valence-electrons-and-the-periodic-table">valence electrons</a>!) places a single electron on the cationic nitrogen centre: <mathjax>#""^(-)O-^*N^(+)=O#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The empirical formula is the SIMPLEST whole number ratio that defines constituent atoms in a species. Does <mathjax>#N_2O_4#</mathjax> satisfy that definition?</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Of course, the empirical formula of <mathjax>#N_2O_4#</mathjax> is <mathjax>#NO_2#</mathjax>. Why?</p> <p>The equilibrium <mathjax>#N_2O_4(g) rightleftharpoons 2NO_2(g)#</mathjax> has been well-studied. Dimerization of <mathjax>#NO_2#</mathjax> to give <mathjax>#N_2O_4#</mathjax> can be rationalized on the basis that the Lewis structure of <mathjax>#NO_2#</mathjax> (with 17 <a href="http://socratic.org/chemistry/the-periodic-table/valence-electrons-and-the-periodic-table">valence electrons</a>!) places a single electron on the cationic nitrogen centre: <mathjax>#""^(-)O-^*N^(+)=O#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the empirical formula of a compound with the molecular formula #N_2O_4#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="233158" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-02-29T21:34:43" itemprop="dateCreated"> Feb 29, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The empirical formula is the SIMPLEST whole number ratio that defines constituent atoms in a species. Does <mathjax>#N_2O_4#</mathjax> satisfy that definition?</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Of course, the empirical formula of <mathjax>#N_2O_4#</mathjax> is <mathjax>#NO_2#</mathjax>. Why?</p> <p>The equilibrium <mathjax>#N_2O_4(g) rightleftharpoons 2NO_2(g)#</mathjax> has been well-studied. Dimerization of <mathjax>#NO_2#</mathjax> to give <mathjax>#N_2O_4#</mathjax> can be rationalized on the basis that the Lewis structure of <mathjax>#NO_2#</mathjax> (with 17 <a href="http://socratic.org/chemistry/the-periodic-table/valence-electrons-and-the-periodic-table">valence electrons</a>!) places a single electron on the cationic nitrogen centre: <mathjax>#""^(-)O-^*N^(+)=O#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/233158" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molecular-formula-of-a-compound"> How do you find molecular formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-diamond"> What is the chemical formula of a diamond? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-carbohydrate"> What is the chemical formula of a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-valproic-acid"> What is the empirical formula for valproic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-of-magnesium-oxide"> What is the empirical formula of magnesium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-empirical-formula-not-double-that-of-the-monosaccharides"> Why is the empirical formula not double that of the monosaccharides? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5331180502bf342f40b5c3b5"> Question #5c3b5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-molecular-formula-represents-a-carbohydrate"> What molecular formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-of-vinegar"> What is the molecular formula of vinegar? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/empirical-and-molecular-formulas"> See all questions in Empirical and Molecular Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1903 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the empirical formula of a compound with the molecular formula #N_2O_4#?	null
1,765	ac27c063-6ddd-11ea-90b7-ccda262736ce	https://socratic.org/questions/55f63956581e2a725fb1430c	7.50 × 10^(-7) mol/L	start physical_unit 5 6 solubility mol/l qc_end physical_unit 9 9 13 13 ph qc_end end	[{"type":"physical unit","value":"Solubility [OF] zinc hydroxide [IN] mol/L"}]	[{"type":"physical unit","value":"7.50 × 10^(-7) mol/L"}]	[{"type":"physical unit","value":"pH [OF] zinc hydroxide aqueous solution [=] \\pu{9}"}]	<h1 class="questionTitle" itemprop="name">What is the solubility of zinc hydroxide in aqueous solution if #pH=9#?</h1>	null	7.50 × 10^(-7) mol/L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Here we know the <mathjax>#[OH^-]#</mathjax> value (how; what is the <mathjax>#pH#</mathjax>?). Therefore you have the tools to solve for <mathjax>#[Zn^(2+)]#</mathjax>, whose concentration represents the solubility of zinc hydroxide. Remember that hydroxide ion concentration is squared in the <mathjax>#K_(sp)#</mathjax> expression.</p> <p>As an extension, it may be speculated that we could reduce the <mathjax>#[Zn^(2+)]#</mathjax> value to any degree, simply by increasing <mathjax>#[OH^-]#</mathjax>. Note that at very high levels of <mathjax>#[OH^-]#</mathjax>, we are likely to form complex ions such as, <mathjax>#Zn(OH)_4^(2-)#</mathjax> (I assure you this species is real). This is a competing equilibrium that can occur.</p> <p>And so, we address the equilibrium reaction...</p> <p><mathjax>#Zn(OH)_2(s) rightleftharpoons Zn^(2+) +2HO^-#</mathjax>...</p> <p>For which <mathjax>#K_"sp"=[Zn^(2+)][HO^-]^2#</mathjax>...</p> <p>And if we set <mathjax>#S="solubility of zinc hydroxide"#</mathjax>...IN PURE WATER...</p> <p>Then...<mathjax>#K_"sp"=Sxx(2S)^2=4S^3=3xx10^-16#</mathjax></p> <p>And so finally, <mathjax>#S=""^(3)sqrt((3xx10^-16)/4)=4.22xx10^-6molL^-1#</mathjax>...</p> <p>And so under the given conditions, we can find the mass of zinc hydroxide in solution... <mathjax>#99.42gmol^-1xx4.22xx10^-6molL^-1=0.42mgL^-1#</mathjax>, i.e. less than <mathjax>#"1 ppm"#</mathjax>...</p> <p>But in the given problem, <mathjax>#[HO^-]=10^(-5)molL^-1#</mathjax>...(why?..because <mathjax>#pH=9#</mathjax>, and <mathjax>#K_w=10^-14#</mathjax>)...and so...</p> <p><mathjax>#K_"sp"=Sxx(2S+2xx10^-5)^2#</mathjax> And so <mathjax>#S~=K_"sp"/(2xx10^-5)^2=7.5xx10^-7moll^-1#</mathjax>...and so the solubility of the salt is reduced tenfold...</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>You find the <mathjax>#K_"sp"#</mathjax> expression, <mathjax>#K_"sp"=[Zn^(2+)][HO^-]^2#</mathjax>, i.e. <mathjax>#K_"sp"=3xx10^-16#</mathjax>...</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Here we know the <mathjax>#[OH^-]#</mathjax> value (how; what is the <mathjax>#pH#</mathjax>?). Therefore you have the tools to solve for <mathjax>#[Zn^(2+)]#</mathjax>, whose concentration represents the solubility of zinc hydroxide. Remember that hydroxide ion concentration is squared in the <mathjax>#K_(sp)#</mathjax> expression.</p> <p>As an extension, it may be speculated that we could reduce the <mathjax>#[Zn^(2+)]#</mathjax> value to any degree, simply by increasing <mathjax>#[OH^-]#</mathjax>. Note that at very high levels of <mathjax>#[OH^-]#</mathjax>, we are likely to form complex ions such as, <mathjax>#Zn(OH)_4^(2-)#</mathjax> (I assure you this species is real). This is a competing equilibrium that can occur.</p> <p>And so, we address the equilibrium reaction...</p> <p><mathjax>#Zn(OH)_2(s) rightleftharpoons Zn^(2+) +2HO^-#</mathjax>...</p> <p>For which <mathjax>#K_"sp"=[Zn^(2+)][HO^-]^2#</mathjax>...</p> <p>And if we set <mathjax>#S="solubility of zinc hydroxide"#</mathjax>...IN PURE WATER...</p> <p>Then...<mathjax>#K_"sp"=Sxx(2S)^2=4S^3=3xx10^-16#</mathjax></p> <p>And so finally, <mathjax>#S=""^(3)sqrt((3xx10^-16)/4)=4.22xx10^-6molL^-1#</mathjax>...</p> <p>And so under the given conditions, we can find the mass of zinc hydroxide in solution... <mathjax>#99.42gmol^-1xx4.22xx10^-6molL^-1=0.42mgL^-1#</mathjax>, i.e. less than <mathjax>#"1 ppm"#</mathjax>...</p> <p>But in the given problem, <mathjax>#[HO^-]=10^(-5)molL^-1#</mathjax>...(why?..because <mathjax>#pH=9#</mathjax>, and <mathjax>#K_w=10^-14#</mathjax>)...and so...</p> <p><mathjax>#K_"sp"=Sxx(2S+2xx10^-5)^2#</mathjax> And so <mathjax>#S~=K_"sp"/(2xx10^-5)^2=7.5xx10^-7moll^-1#</mathjax>...and so the solubility of the salt is reduced tenfold...</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the solubility of zinc hydroxide in aqueous solution if #pH=9#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-equilibrium" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Equilibrium</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-equilibrium/solubility-equilbria" itemprop="url"> <span class="breadcrumb" itemprop="title">Solubility Equilbria</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="168339" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-09-14T06:10:10" itemprop="dateCreated"> Sep 14, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>You find the <mathjax>#K_"sp"#</mathjax> expression, <mathjax>#K_"sp"=[Zn^(2+)][HO^-]^2#</mathjax>, i.e. <mathjax>#K_"sp"=3xx10^-16#</mathjax>...</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Here we know the <mathjax>#[OH^-]#</mathjax> value (how; what is the <mathjax>#pH#</mathjax>?). Therefore you have the tools to solve for <mathjax>#[Zn^(2+)]#</mathjax>, whose concentration represents the solubility of zinc hydroxide. Remember that hydroxide ion concentration is squared in the <mathjax>#K_(sp)#</mathjax> expression.</p> <p>As an extension, it may be speculated that we could reduce the <mathjax>#[Zn^(2+)]#</mathjax> value to any degree, simply by increasing <mathjax>#[OH^-]#</mathjax>. Note that at very high levels of <mathjax>#[OH^-]#</mathjax>, we are likely to form complex ions such as, <mathjax>#Zn(OH)_4^(2-)#</mathjax> (I assure you this species is real). This is a competing equilibrium that can occur.</p> <p>And so, we address the equilibrium reaction...</p> <p><mathjax>#Zn(OH)_2(s) rightleftharpoons Zn^(2+) +2HO^-#</mathjax>...</p> <p>For which <mathjax>#K_"sp"=[Zn^(2+)][HO^-]^2#</mathjax>...</p> <p>And if we set <mathjax>#S="solubility of zinc hydroxide"#</mathjax>...IN PURE WATER...</p> <p>Then...<mathjax>#K_"sp"=Sxx(2S)^2=4S^3=3xx10^-16#</mathjax></p> <p>And so finally, <mathjax>#S=""^(3)sqrt((3xx10^-16)/4)=4.22xx10^-6molL^-1#</mathjax>...</p> <p>And so under the given conditions, we can find the mass of zinc hydroxide in solution... <mathjax>#99.42gmol^-1xx4.22xx10^-6molL^-1=0.42mgL^-1#</mathjax>, i.e. less than <mathjax>#"1 ppm"#</mathjax>...</p> <p>But in the given problem, <mathjax>#[HO^-]=10^(-5)molL^-1#</mathjax>...(why?..because <mathjax>#pH=9#</mathjax>, and <mathjax>#K_w=10^-14#</mathjax>)...and so...</p> <p><mathjax>#K_"sp"=Sxx(2S+2xx10^-5)^2#</mathjax> And so <mathjax>#S~=K_"sp"/(2xx10^-5)^2=7.5xx10^-7moll^-1#</mathjax>...and so the solubility of the salt is reduced tenfold...</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/168339" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-solubility-affect-equilibrium"> How does solubility affect equilibrium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5351cdc002bf345ec38f076a"> Question #f076a </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-solubility-of-calcium-hydroxide"> How can I calculate solubility of calcium hydroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-an-example-of-a-solubility-equilibria-practice-problem"> What is an example of a solubility equilibria practice problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-common-mistakes-students-make-with-solubility-equilibria"> What are some common mistakes students make with solubility equilibria? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-examples-of-solubility-equilibria"> What are some examples of solubility equilibria? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-write-the-solubility-equilibrium-equation"> How can I write the solubility equilibrium equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-solubility-equilibrium-a-type-of-dynamic-equilibrium"> Is solubility equilibrium a type of dynamic equilibrium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-temperature-affect-solubility-equilibrium"> How does temperature affect solubility equilibrium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-solubility-equilibrium"> How can I calculate solubility equilibrium? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-equilibrium/solubility-equilbria"> See all questions in Solubility Equilbria </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 6848 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the solubility of zinc hydroxide in aqueous solution if #pH=9#?	null
1,766	a94bd56e-6ddd-11ea-bdb8-ccda262736ce	https://socratic.org/questions/a-16-0-l-gas-cylinder-is-filled-with-7-60-moles-of-gas-the-tank-is-stored-at-41-	12.25 atm	start physical_unit 13 13 pressure atm qc_end physical_unit 3 4 1 2 volume qc_end physical_unit 11 11 8 9 mole qc_end physical_unit 13 13 17 19 temperature qc_end end	[{"type":"physical unit","value":"Pressure [OF] tank [IN] atm"}]	[{"type":"physical unit","value":"12.25 atm"}]	[{"type":"physical unit","value":"Volume [OF] gas cylinder [=] \\pu{16.0 L}"},{"type":"physical unit","value":"Mole [OF] gas. [=] \\pu{7.60 moles}"},{"type":"physical unit","value":"Temperature [OF] tank [=] \\pu{41 degrees Celcius}"}]	<h1 class="questionTitle" itemprop="name">A 16.0 L gas cylinder is filled with 7.60 moles of gas. The tank is stored at 41 degrees Celcius. What is the pressure in the tank?</h1>	null	12.25 atm	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Using the Ideal Gas Equation, <mathjax>#P=(nRT)/V#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(7.6molxx0.0821LatmK^-1mol^-1xx314K)/(16.0*L)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??atm#</mathjax></p> <p>With these problems, we are always faced with choosing the appropriated gas constant, <mathjax>#R#</mathjax>. Typically, chemists use <mathjax>#"litres"#</mathjax> and <mathjax>#"atmospheres"#</mathjax>. Absolute temperature in <mathjax>#"degrees Kelvin"#</mathjax> is common to these problems. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#P~=12atm#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Using the Ideal Gas Equation, <mathjax>#P=(nRT)/V#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(7.6molxx0.0821LatmK^-1mol^-1xx314K)/(16.0L)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??atm#</mathjax></p> <p>With these problems, we are always faced with choosing the appropriated gas constant, <mathjax>#R#</mathjax>. Typically, chemists use <mathjax>#"litres"#</mathjax> and <mathjax>#"atmospheres"#</mathjax>. Absolute temperature in <mathjax>#"degrees Kelvin"#</mathjax> is common to these problems. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A 16.0 L gas cylinder is filled with 7.60 moles of gas. The tank is stored at 41 degrees Celcius. What is the pressure in the tank?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/atmospheric-pressure" itemprop="url"> <span class="breadcrumb" itemprop="title">Atmospheric Pressure</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="293931" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-31T08:16:57" itemprop="dateCreated"> Jul 31, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#P~=12atm#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Using the Ideal Gas Equation, <mathjax>#P=(nRT)/V#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(7.6molxx0.0821LatmK^-1mol^-1xx314K)/(16.0L)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??atm#</mathjax></p> <p>With these problems, we are always faced with choosing the appropriated gas constant, <mathjax>#R#</mathjax>. Typically, chemists use <mathjax>#"litres"#</mathjax> and <mathjax>#"atmospheres"#</mathjax>. Absolute temperature in <mathjax>#"degrees Kelvin"#</mathjax> is common to these problems. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/293931" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-atmospheric-pressure-affect-evaporation"> How does atmospheric pressure affect evaporation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-atmospheric-pressure-at-an-altitude"> How do you calculate atmospheric pressure at an altitude? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-air-pressure-greatest-at-the-earth-s-surface"> Why is air pressure greatest at the Earth's surface? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-causes-hydrostatic-pressure-in-blood-vessels"> What causes hydrostatic pressure in blood vessels? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-hydrostatic-pressure-created"> How is hydrostatic pressure created? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-atmospheric-pressure-change-in-the-troposphere"> How does atmospheric pressure change in the troposphere? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/does-air-pressure-change-with-humidity"> Does air pressure change with humidity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-atmospheric-pressure-affect-boiling-points"> How does atmospheric pressure affect boiling points? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-air-pressure-is-measured-for-weather-information"> How is air pressure measured for weather information? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-air-pressure-regulators-work"> How do air pressure regulators work? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/atmospheric-pressure"> See all questions in Atmospheric Pressure </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2198 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A 16.0 L gas cylinder is filled with 7.60 moles of gas. The tank is stored at 41 degrees Celcius. What is the pressure in the tank?	null
1,767	a977ff3f-6ddd-11ea-a832-ccda262736ce	https://socratic.org/questions/how-would-you-balance-the-following-equation-fe-cl2-h2o-fe-h2o-6-3-cl	2 Fe + 3 Cl2 + 12 H2O -> 2 [Fe(H2O)6]^3+ + 6 Cl-	start chemical_equation qc_end chemical_equation 7 15 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the equation"}]	[{"type":"chemical equation","value":"2 Fe + 3 Cl2 + 12 H2O -> 2 [Fe(H2O)6]^3+ + 6 Cl-"}]	[{"type":"chemical equation","value":"Fe + Cl2 + H2O -> [Fe(H2O)6]^3+ + Cl-"}]	<h1 class="questionTitle" itemprop="name">How would you balance the following equation: Fe + Cl2 + H2O → [Fe(H2O)6]3+ + Cl-?</h1>	null	2 Fe + 3 Cl2 + 12 H2O -> 2 [Fe(H2O)6]^3+ + 6 Cl-	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>OXIDATION</p> <p><mathjax>#Fe(s) + 3/2Cl_2(g) rarr FeCl_3(s)#</mathjax></p> <p>COMPLEXATION</p> <p><mathjax>#FeCl_3(s) + 6H_2O(l) rarr [Fe(OH_2)_6]^(3+)(Cl^-)_3#</mathjax></p> <p>I don't know whether this is completely what you want. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>You are oxidizing iron, and then making a coordination complex. I will give you a reaction scheme.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>OXIDATION</p> <p><mathjax>#Fe(s) + 3/2Cl_2(g) rarr FeCl_3(s)#</mathjax></p> <p>COMPLEXATION</p> <p><mathjax>#FeCl_3(s) + 6H_2O(l) rarr [Fe(OH_2)_6]^(3+)(Cl^-)_3#</mathjax></p> <p>I don't know whether this is completely what you want. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How would you balance the following equation: Fe + Cl2 + H2O → [Fe(H2O)6]3+ + Cl-?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="210016" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-08T21:47:05" itemprop="dateCreated"> Jan 8, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>You are oxidizing iron, and then making a coordination complex. I will give you a reaction scheme.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>OXIDATION</p> <p><mathjax>#Fe(s) + 3/2Cl_2(g) rarr FeCl_3(s)#</mathjax></p> <p>COMPLEXATION</p> <p><mathjax>#FeCl_3(s) + 6H_2O(l) rarr [Fe(OH_2)_6]^(3+)(Cl^-)_3#</mathjax></p> <p>I don't know whether this is completely what you want. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/210016" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="214843" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-21T00:42:29" itemprop="dateCreated"> Jan 21, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2"Fe" + "3Cl"_2 + "12H"_2"O" → 2["Fe"("H"_2"O")_6]^(3+) + "6Cl"^(-)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>A Socratic answer <a href="http://socratic.org/questions/how-can-i-balance-redox-chemical-equations-step-by-step">here</a> shows how to balance redox equations.</p> <p>Your equation is:</p> <p><mathjax>#"Fe"color(white)(l) + "Cl"_2 + "H"_2"O" → ["Fe"("H"_2"O")_6]^(3+) + "Cl"^(-)#</mathjax></p> <blockquote></blockquote> <p><strong>SOLUTION</strong>:</p> <p><strong>1: The two half-reactions are</strong></p> <p><mathjax>#"Fe" → ["Fe"("H"_2"O")_6]^(3+)#</mathjax><br/> <mathjax>#"Cl"_2 → "Cl"^(-)#</mathjax></p> <blockquote></blockquote> <p><strong>2: Balance all atoms other than <mathjax>#"H"#</mathjax> and <mathjax>#"O"#</mathjax>.</strong></p> <p><mathjax>#"Fe" → ["Fe"("H"_2"O")_6]^(3+)#</mathjax><br/> <mathjax>#"Cl"_2 → color(red)(2)"Cl"^(-)#</mathjax></p> <blockquote></blockquote> <p><strong>3: Balance <mathjax>#"O"#</mathjax>.</strong></p> <p><mathjax>#"Fe"color(white)(l) + color(red)("6H"_2"O") → ["Fe"("H"_2"O")_6]^(3+)#</mathjax><br/> <mathjax>#"Cl"_2 → 2"Cl"^(-)#</mathjax></p> <blockquote></blockquote> <p><strong>4: Balance H.</strong></p> <p>Done.</p> <blockquote></blockquote> <p><strong>5: Balance charge.</strong></p> <p><mathjax>#"Fe"color(white)(l)+ "6H"_2"O" → ["Fe"("H"_2"O")_6]^(3+) + color(red)("3e"^(-))#</mathjax><br/> <mathjax>#"Cl"_2 + color(red)("2e"^(-)) → 2"Cl"^(-)#</mathjax></p> <blockquote></blockquote> <p><strong>6: Equalize electrons transferred.</strong></p> <p><mathjax>#color(red)(2 ×) {"Fe" + "6H"_2"O" → ["Fe"("H"_2"O")_6]^(3+) + + "3e"^(-)}#</mathjax><br/> <mathjax>#color(red)(3 ×){"Cl"_2 + "2e"^(-) → 2"Cl"^(-)}#</mathjax></p> <blockquote></blockquote> <p><strong>7: Add the two half-reactions.</strong></p> <p><mathjax>#2"Fe" + 3"Cl"_2 + "12H"_2"O" → 2["Fe"("H"_2"O")_6]^(3+) + "6Cl"^(-)#</mathjax></p> <blockquote></blockquote> <p><strong>8: Check mass balance.</strong></p> <p>On the left: <mathjax>#"2 Fe"; "6 Cl"; "24 H"; "12 O"#</mathjax><br/> On the right: <mathjax>#"2 Fe"; "24 H"; "12 O"; "6 Cl"#</mathjax></p> <blockquote></blockquote> <p><strong>9: Check charge balance</strong></p> <p>On the left: <mathjax>#0#</mathjax><br/> On the right: <mathjax>#"6+ + 6-" = 0#</mathjax></p> <blockquote></blockquote> <p>The balanced equation is</p> <p><mathjax>#2"Fe" + 3"Cl"_2 + "12H"_2"O" → 2["Fe"("H"_2"O")_6]^(3+) + "6Cl"^(-)#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/214843" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? 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Sodium phosphate and calcium chloride react to form... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-equation-kclo3-kcl-o2"> How can I balance this equation? ____ #KClO_3 -># ____ #KCl +# ____ #O_2# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-balancing-chemical-equations-important"> Why is balancing chemical equations important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/balancing-chemical-equations"> See all questions in Balancing Chemical Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 5713 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How would you balance the following equation: Fe + Cl2 + H2O → [Fe(H2O)6]3+ + Cl-?	null
1,768	ad1b70a8-6ddd-11ea-ad72-ccda262736ce	https://socratic.org/questions/a-pitcher-contains-2-l-of-a-solution-whose-concentration-is-25-g-l-how-many-gram	25.00 grams	start physical_unit 17 17 mass g qc_end physical_unit 24 25 3 4 volume qc_end physical_unit 24 25 11 12 concentration qc_end physical_unit 24 25 21 22 volume qc_end end	[{"type":"physical unit","value":"Mass [OF] solvent [IN] grams"}]	[{"type":"physical unit","value":"25.00 grams"}]	[{"type":"physical unit","value":"Volume1 [OF] the solution [=] \\pu{2 L}"},{"type":"physical unit","value":"Concentration1 [OF] the solution [=] \\pu{25 g/L}"},{"type":"physical unit","value":"Volume2 [OF] the solution [=] \\pu{1 L}"}]	<h1 class="questionTitle" itemprop="name">A pitcher contains 2 L of a solution whose concentration is 25 g/L. How many grams of solvent would be in 1L of the solution?</h1>	null	25.00 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is a great example of a problem that provides you with information that you <em>do not need</em>. </p> <p>Notice that you are told that the solution has a volume of <mathjax>#"2 L"#</mathjax> and a <strong>concentration</strong> of <mathjax>#"25 g L"^(-1)#</mathjax>. </p> <p>The <strong>only thing</strong> that you need in order to figure out how many <em>grams</em> of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> you get in <strong>any volume</strong> of this solution is its concentration. </p> <p>You don't need to know how much solution you have in the pitcher to answer this problem. </p> <p>This said, a concentration of <mathjax>#"25 g L"^(-1)#</mathjax> tells you that you get <mathjax>#"25 g"#</mathjax> of solute <strong>for every</strong> <mathjax>#"1 L"#</mathjax> of solution. As it turns out, you must calculate how many grams of solute you get in <mathjax>#"1 L"#</mathjax> of solution. </p> <p>Since the concentration of the solution already tells you how many grams of solute you get <em>per liter</em> of solution, you will have</p> <blockquote> <p><mathjax>#1 color(red)(cancel(color(black)("L"))) * overbrace("25 g solute"/(1color(red)(cancel(color(black)("L")))))^color(purple)("given concentration") = "25 g solute"#</mathjax></p> </blockquote> <p>However, you must round this off to one <strong><a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig fig</a></strong>, since that's how many sig figs you have in <mathjax>#"1 L"#</mathjax></p> <blockquote> <p><mathjax>#m_"solute" = color(green)(\|bar(ul(color(white)(a/a)"30 g"color(white)(a/a)\|)))#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"30 g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is a great example of a problem that provides you with information that you <em>do not need</em>. </p> <p>Notice that you are told that the solution has a volume of <mathjax>#"2 L"#</mathjax> and a <strong>concentration</strong> of <mathjax>#"25 g L"^(-1)#</mathjax>. </p> <p>The <strong>only thing</strong> that you need in order to figure out how many <em>grams</em> of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> you get in <strong>any volume</strong> of this solution is its concentration. </p> <p>You don't need to know how much solution you have in the pitcher to answer this problem. </p> <p>This said, a concentration of <mathjax>#"25 g L"^(-1)#</mathjax> tells you that you get <mathjax>#"25 g"#</mathjax> of solute <strong>for every</strong> <mathjax>#"1 L"#</mathjax> of solution. As it turns out, you must calculate how many grams of solute you get in <mathjax>#"1 L"#</mathjax> of solution. </p> <p>Since the concentration of the solution already tells you how many grams of solute you get <em>per liter</em> of solution, you will have</p> <blockquote> <p><mathjax>#1 color(red)(cancel(color(black)("L"))) * overbrace("25 g solute"/(1color(red)(cancel(color(black)("L")))))^color(purple)("given concentration") = "25 g solute"#</mathjax></p> </blockquote> <p>However, you must round this off to one <strong><a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig fig</a></strong>, since that's how many sig figs you have in <mathjax>#"1 L"#</mathjax></p> <blockquote> <p><mathjax>#m_"solute" = color(green)(\|bar(ul(color(white)(a/a)"30 g"color(white)(a/a)\|)))#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A pitcher contains 2 L of a solution whose concentration is 25 g/L. How many grams of solvent would be in 1L of the solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/percent-concentration" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Concentration</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="237066" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-09T01:15:08" itemprop="dateCreated"> Mar 9, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"30 g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is a great example of a problem that provides you with information that you <em>do not need</em>. </p> <p>Notice that you are told that the solution has a volume of <mathjax>#"2 L"#</mathjax> and a <strong>concentration</strong> of <mathjax>#"25 g L"^(-1)#</mathjax>. </p> <p>The <strong>only thing</strong> that you need in order to figure out how many <em>grams</em> of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> you get in <strong>any volume</strong> of this solution is its concentration. </p> <p>You don't need to know how much solution you have in the pitcher to answer this problem. </p> <p>This said, a concentration of <mathjax>#"25 g L"^(-1)#</mathjax> tells you that you get <mathjax>#"25 g"#</mathjax> of solute <strong>for every</strong> <mathjax>#"1 L"#</mathjax> of solution. As it turns out, you must calculate how many grams of solute you get in <mathjax>#"1 L"#</mathjax> of solution. </p> <p>Since the concentration of the solution already tells you how many grams of solute you get <em>per liter</em> of solution, you will have</p> <blockquote> <p><mathjax>#1 color(red)(cancel(color(black)("L"))) * overbrace("25 g solute"/(1color(red)(cancel(color(black)("L")))))^color(purple)("given concentration") = "25 g solute"#</mathjax></p> </blockquote> <p>However, you must round this off to one <strong><a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig fig</a></strong>, since that's how many sig figs you have in <mathjax>#"1 L"#</mathjax></p> <blockquote> <p><mathjax>#m_"solute" = color(green)(\|bar(ul(color(white)(a/a)"30 g"color(white)(a/a)\|)))#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/237066" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-concentration-of-water-in-solution-be-decreased"> How can the concentration of water in solution be decreased? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-concentration-of-a-solution-be-increased"> How can the concentration of a solution be increased? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-concentration-of-a-solution-in-ppm"> How do you find the concentration of a solution in ppm? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-make-a-10-percent-solution"> How do you make a 10 percent solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-make-a-2-percent-solution"> How do you make a 2 percent solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-weight-per-volume-method-to-calculate-concentration"> What is the weight per volume method to calculate concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-percent-concentration-of-kcl-would-be-isotonic"> What percent concentration of KCl would be isotonic? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-of-sodium-chloride-in-normal-saline"> What is the percent concentration of sodium chloride in normal saline? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-of-a-6m-solution-of-nacl"> What is the percent concentration of a 6m solution of NaCl? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-formula"> What is the percent concentration formula? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/percent-concentration"> See all questions in Percent Concentration </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2409 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A pitcher contains 2 L of a solution whose concentration is 25 g/L. How many grams of solvent would be in 1L of the solution?	null
1,769	acf730e4-6ddd-11ea-b886-ccda262736ce	https://socratic.org/questions/8-8400x10-1-mol-of-an-ideal-gas-has-a-pressure-of-1-50x10-2-kpa-and-temperature-	1.26 × 10^1 L	start physical_unit 28 29 volume l qc_end end	[{"type":"physical unit","value":"Volume [OF] the gas [IN] L"}]	[{"type":"physical unit","value":"1.26 × 10^1 L"}]	[{"type":"physical unit","value":"Mole [OF] the ideal gas [=] \\pu{8.8400 × 10^(-1) mol}"},{"type":"physical unit","value":"Pressure [OF] the ideal gas [=] \\pu{1.50 × 10^2 kPa}"},{"type":"physical unit","value":"Temperature [OF] the ideal gas [=] \\pu{2.5700 × 10^2 K}"}]	<h1 class="questionTitle" itemprop="name">(8.8400x10^-1) mol of an ideal gas has a pressure of (1.50x10^2) kPa and temperature of (2.5700x10^2) K. What is the volume of the gas?</h1>	null	1.26 × 10^1 L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>This looks like the time to apply the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a>:</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(\|color(white)(a/a)pV = nRTcolor(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>where </p> <ul> <li><mathjax>#p#</mathjax> is the pressure</li> <li><mathjax>#V#</mathjax> is the volume</li> <li><mathjax>#n#</mathjax> is the number of moles</li> <li><mathjax>#R#</mathjax> is the universal gas constant</li> <li><mathjax>#T#</mathjax> is the temperature</li> </ul> <p>We can rearrange the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a> to get</p> <blockquote> <blockquote> <p><mathjax>#V = (nRT)/p#</mathjax></p> </blockquote> </blockquote> <p>In this problem,</p> <p><mathjax>#n = 8.8400 × 10^"-1"color(white)(l) "mol"#</mathjax><br/> <mathjax>#R = "8.314 kPa·L·K"^"-1""mol"^"-1"#</mathjax><br/> <mathjax>#T = 2.5700 × 10^2 color(white)(l)"K"#</mathjax><br/> <mathjax>#p = 1.50 ×10^2 color(white)(l)"kPa"#</mathjax></p> <blockquote></blockquote> <p><mathjax>#V = (8.8400 ×10^"-1" color(red)(cancel(color(black)("mol"))) × 8.314 color(red)(cancel(color(black)("kPa")))·"L"·color(red)(cancel(color(black)("K"^"-1"·"mol"^"-1"))) × 2.5700× 10^2color(red)(cancel(color(black)("K"))))/(1.50 × 10^2 color(red)(cancel(color(black)("kPa")))) = 1.26 × 10^1 color(white)(l)"L"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The volume of the gas is <mathjax>#1.26 × 10^1 color(white)(l)"L"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>This looks like the time to apply the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a>:</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(\|color(white)(a/a)pV = nRTcolor(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>where </p> <ul> <li><mathjax>#p#</mathjax> is the pressure</li> <li><mathjax>#V#</mathjax> is the volume</li> <li><mathjax>#n#</mathjax> is the number of moles</li> <li><mathjax>#R#</mathjax> is the universal gas constant</li> <li><mathjax>#T#</mathjax> is the temperature</li> </ul> <p>We can rearrange the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a> to get</p> <blockquote> <blockquote> <p><mathjax>#V = (nRT)/p#</mathjax></p> </blockquote> </blockquote> <p>In this problem,</p> <p><mathjax>#n = 8.8400 × 10^"-1"color(white)(l) "mol"#</mathjax><br/> <mathjax>#R = "8.314 kPa·L·K"^"-1""mol"^"-1"#</mathjax><br/> <mathjax>#T = 2.5700 × 10^2 color(white)(l)"K"#</mathjax><br/> <mathjax>#p = 1.50 ×10^2 color(white)(l)"kPa"#</mathjax></p> <blockquote></blockquote> <p><mathjax>#V = (8.8400 ×10^"-1" color(red)(cancel(color(black)("mol"))) × 8.314 color(red)(cancel(color(black)("kPa")))·"L"·color(red)(cancel(color(black)("K"^"-1"·"mol"^"-1"))) × 2.5700× 10^2color(red)(cancel(color(black)("K"))))/(1.50 × 10^2 color(red)(cancel(color(black)("kPa")))) = 1.26 × 10^1 color(white)(l)"L"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">(8.8400x10^-1) mol of an ideal gas has a pressure of (1.50x10^2) kPa and temperature of (2.5700x10^2) K. What is the volume of the gas?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/ideal-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Ideal Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="416447" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-02T15:00:28" itemprop="dateCreated"> May 2, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The volume of the gas is <mathjax>#1.26 × 10^1 color(white)(l)"L"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>This looks like the time to apply the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a>:</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(\|color(white)(a/a)pV = nRTcolor(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>where </p> <ul> <li><mathjax>#p#</mathjax> is the pressure</li> <li><mathjax>#V#</mathjax> is the volume</li> <li><mathjax>#n#</mathjax> is the number of moles</li> <li><mathjax>#R#</mathjax> is the universal gas constant</li> <li><mathjax>#T#</mathjax> is the temperature</li> </ul> <p>We can rearrange the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a> to get</p> <blockquote> <blockquote> <p><mathjax>#V = (nRT)/p#</mathjax></p> </blockquote> </blockquote> <p>In this problem,</p> <p><mathjax>#n = 8.8400 × 10^"-1"color(white)(l) "mol"#</mathjax><br/> <mathjax>#R = "8.314 kPa·L·K"^"-1""mol"^"-1"#</mathjax><br/> <mathjax>#T = 2.5700 × 10^2 color(white)(l)"K"#</mathjax><br/> <mathjax>#p = 1.50 ×10^2 color(white)(l)"kPa"#</mathjax></p> <blockquote></blockquote> <p><mathjax>#V = (8.8400 ×10^"-1" color(red)(cancel(color(black)("mol"))) × 8.314 color(red)(cancel(color(black)("kPa")))·"L"·color(red)(cancel(color(black)("K"^"-1"·"mol"^"-1"))) × 2.5700× 10^2color(red)(cancel(color(black)("K"))))/(1.50 × 10^2 color(red)(cancel(color(black)("kPa")))) = 1.26 × 10^1 color(white)(l)"L"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/416447" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-ideal-gas-constant"> How do you find the ideal gas constant? 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R = 8.314 kPa L / (K mol) =... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-molar-mass-of-a-gas"> How do you calculate the molar mass of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-should-i-use-the-ideal-gas-law-and-not-the-combined-gas-law"> When should I use the ideal gas law and not the combined gas law? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/ideal-gas-law"> See all questions in Ideal Gas Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1380 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	(8.8400x10^-1) mol of an ideal gas has a pressure of (1.50x10^2) kPa and temperature of (2.5700x10^2) K. What is the volume of the gas?	null
1,770	ab68c69d-6ddd-11ea-9c93-ccda262736ce	https://socratic.org/questions/according-to-the-following-reaction-how-many-moles-of-carbon-dioxide-will-be-for	2.35 moles	start physical_unit 9 10 mole mol qc_end chemical_equation 28 37 qc_end physical_unit 9 9 19 20 mass qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Mole [OF] carbon dioxide [IN] moles"}]	[{"type":"physical unit","value":"2.35 moles"}]	[{"type":"chemical equation","value":"carbon (graphite) (s) + oxygen (g) -> carbon dioxide (g)"},{"type":"physical unit","value":"Mass [OF] carbon [=] \\pu{28.2 grams}"},{"type":"other","value":"Excess oxygen gas."}]	<h1 class="questionTitle" itemprop="name">According to the following reaction how many moles of carbon dioxide will be formed upon the complete reaction of 28.2 grams of carbon (graphite) with excess oxygen gas?</h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>carbon (graphite) (s) + oxygen (g) <mathjax>#->#</mathjax> carbon dioxide (g)</p></div> </h2> </div> </div>	2.35 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#C(s) + O_2(g) rarr CO_2(g)#</mathjax>.</p> <p>The <mathjax>#1:1#</mathjax> <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> is clear: moles of carbon, and dioxygen gas are equivalent to the moles of carbon dioxide gas generated. </p> <p>We start with <mathjax>#(28.2g)/(12.01gmol)=2.35mol#</mathjax> <mathjax>#C#</mathjax>, and thus <mathjax>#2.35molxx44.01gmol^-1#</mathjax> <mathjax>#CO_2(g)#</mathjax> are evolved. </p> <p>Suppose that less than <mathjax>#100g#</mathjax> of gas were collected in the experiment. Barring error on the part of the experimenter, what would be a reasonable explanation?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Each mole of carbon gives <mathjax>#44g#</mathjax> of carbon dioxide gas upon oxidation. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#C(s) + O_2(g) rarr CO_2(g)#</mathjax>.</p> <p>The <mathjax>#1:1#</mathjax> <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> is clear: moles of carbon, and dioxygen gas are equivalent to the moles of carbon dioxide gas generated. </p> <p>We start with <mathjax>#(28.2g)/(12.01gmol)=2.35mol#</mathjax> <mathjax>#C#</mathjax>, and thus <mathjax>#2.35molxx44.01gmol^-1#</mathjax> <mathjax>#CO_2(g)#</mathjax> are evolved. </p> <p>Suppose that less than <mathjax>#100*g#</mathjax> of gas were collected in the experiment. Barring error on the part of the experimenter, what would be a reasonable explanation?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">According to the following reaction how many moles of carbon dioxide will be formed upon the complete reaction of 28.2 grams of carbon (graphite) with excess oxygen gas?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>carbon (graphite) (s) + oxygen (g) <mathjax>#->#</mathjax> carbon dioxide (g)</p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/mole-ratios" itemprop="url"> <span class="breadcrumb" itemprop="title">Mole Ratios</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="330870" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-11-03T18:30:31" itemprop="dateCreated"> Nov 3, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Each mole of carbon gives <mathjax>#44g#</mathjax> of carbon dioxide gas upon oxidation. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#C(s) + O_2(g) rarr CO_2(g)#</mathjax>.</p> <p>The <mathjax>#1:1#</mathjax> <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> is clear: moles of carbon, and dioxygen gas are equivalent to the moles of carbon dioxide gas generated. </p> <p>We start with <mathjax>#(28.2g)/(12.01gmol)=2.35mol#</mathjax> <mathjax>#C#</mathjax>, and thus <mathjax>#2.35molxx44.01gmol^-1#</mathjax> <mathjax>#CO_2(g)#</mathjax> are evolved. </p> <p>Suppose that less than <mathjax>#100*g#</mathjax> of gas were collected in the experiment. Barring error on the part of the experimenter, what would be a reasonable explanation?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/330870" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4178e02bf3469517a106e"> Question #a106e </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4178e02bf3469570e2e86"> Question #e2e86 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179102bf3469517a1072"> Question #a1072 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179402bf34694c8c5bf1"> Question #c5bf1 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179702bf3469588dc373"> Question #dc373 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179c02bf34694c8c5bf9"> Question #c5bf9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417a302bf3469517a1076"> Question #a1076 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417c702bf3469588dc377"> Question #dc377 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417d002bf346963eb984f"> Question #b984f </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417d402bf346950519ea3"> Question #19ea3 </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/mole-ratios"> See all questions in Mole Ratios </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 33185 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	According to the following reaction how many moles of carbon dioxide will be formed upon the complete reaction of 28.2 grams of carbon (graphite) with excess oxygen gas?	carbon (graphite) (s) + oxygen (g) #-># carbon dioxide (g)
1,771	a90a8274-6ddd-11ea-bd5a-ccda262736ce	https://socratic.org/questions/if-the-percent-yield-for-the-following-reaction-is-65-0-how-many-grams-of-kclo3-	164.95 grams	start physical_unit 14 14 mass g qc_end physical_unit 7 7 9 9 percent_yield qc_end physical_unit 22 22 19 20 mass qc_end chemical_equation 23 30 qc_end end	[{"type":"physical unit","value":"Mass [OF] KClO3 [IN] grams"}]	[{"type":"physical unit","value":"164.95 grams"}]	[{"type":"physical unit","value":"Percent yield [OF] the reaction [=] \\pu{65.0%}"},{"type":"physical unit","value":"Mass [OF] O2 [=] \\pu{42.0 g}"},{"type":"chemical equation","value":"2 KClO3(s) -> 2 KCl(s) + 3 O2(g)"}]	<h1 class="questionTitle" itemprop="name">If the percent yield for the following reaction is 65.0%, how many grams of KClO3 are needed to produce 42.0 g of O2? 2 KClO3(s) → 2 KCl(s) + 3 O2(g) </h1>	null	164.95 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Once again, start with the balanced chemical equation for this <a href="http://socratic.org/chemistry/chemical-reactions/decomposition-reactions">decomposition reaction</a></p> <blockquote> <p><mathjax>#color(red)(2)"KClO"_text(3(s]) -> 2"KCl"_text((s]) + color(blue)(3)"O"_text((g])#</mathjax></p> </blockquote> <p>Notice that you have a <mathjax>#color(red)(2):color(blue)(3)#</mathjax> <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> between <em>potassium chlorate</em>, <mathjax>#"KClO"""_3#</mathjax>, and <em>oxygen gas</em>, <mathjax>#"O"""_2#</mathjax>. </p> <p>This means that for a reaction that has an <strong>100%</strong> <a href="http://socratic.org/chemistry/stoichiometry/percent-yield">percent yield</a>, every two moles of potassium chlorate will produce three moles of oxygen gas. </p> <p>Keep this in mind. </p> <p>So, you know that your reaction must produce <mathjax>#"42.0 g"#</mathjax> of oxygen gas. Use oxygen gas' molar mass to find how many moles must be produced</p> <blockquote> <p><mathjax>#42.0color(red)(cancel(color(black)("g"))) * ("1 mole O"""_2)/(32.0color(red)(cancel(color(black)("g")))) = "1.3125 moles O"""_2#</mathjax></p> </blockquote> <p>So, how many moles of potassium chlorate would you need <strong>If the reaction had an 100%</strong> <a href="http://socratic.org/chemistry/stoichiometry/percent-yield">percent yield</a>?</p> <p>Use the aforementioned mole ratio to find</p> <blockquote> <p><mathjax>#1.3125color(red)(cancel(color(black)("moles O"_2))) * (color(red)(2)" moles KClO"""_3)/(color(blue)(3)color(red)(cancel(color(black)(" moles O"""_2)))) = "0.875 moles KClO"""_3#</mathjax></p> </blockquote> <p>However, you know for a fact that the percent yield of the reaction <strong>is not</strong> 100%, but <strong>65.0%</strong>. This means that you will need to use <strong>more potassium chlorate</strong> to produce this much oxygen gas. </p> <p>Percent yield is defined as the <em>actual yield</em> of the reaction divided by the <em>theoretical yield</em> of the reaction.</p> <blockquote> <p><mathjax>#"% yield" = "actual yield"/"theoretical yield" xx 100#</mathjax></p> </blockquote> <p>You know that the reaction's <em>actual yield</em> is <strong>42.0 g</strong> of oxygen gas, which means that the <em>theoretical yield</em> must be </p> <blockquote> <p><mathjax>#"65.0%" = "42.0 g"/"theoretical yield" xx 100#</mathjax> </p> </blockquote> <p><mathjax>#"theoretical yield" = ("42.0 g" * 100)/65 = "64.6 g"#</mathjax></p> <p>This means that you need to find how many grams of potassium chlorate would <strong>theoretically</strong> produce <strong>64.6 g</strong> of oxygen gas. </p> <p>Once again, use oxygen's molar mass and <a href="http://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio that exists between the two <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a></p> <blockquote> <p><mathjax>#64.6color(red)(cancel(color(black)("g O"_2))) * ("1 mole O"""_2)/(32.0color(red)(cancel(color(black)("g O"_2)))) = "2.019 moles O"""_2#</mathjax></p> </blockquote> <p>This means that you need to use</p> <blockquote> <p><mathjax>#2.019color(red)(cancel(color(black)("moles O"_2))) * (color(red)(2)" moles KClO"""_3)/(color(blue)(3)color(red)(cancel(color(black)(" moles O"""_2)))) = "1.346 moles KClO"""_3#</mathjax></p> </blockquote> <p>moles of potassium chlorate. Finally, use the compound's molar mass to find how many grams would contain this many moles</p> <blockquote> <p><mathjax>#1.346color(red)(cancel(color(black)("moles KClO"""_3))) * "122.55 g"/(1color(red)(cancel(color(black)("mole KClO"""_3)))) = color(green)("165 g KClO"""_3)#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"165 g KClO"""_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Once again, start with the balanced chemical equation for this <a href="http://socratic.org/chemistry/chemical-reactions/decomposition-reactions">decomposition reaction</a></p> <blockquote> <p><mathjax>#color(red)(2)"KClO"_text(3(s]) -> 2"KCl"_text((s]) + color(blue)(3)"O"_text((g])#</mathjax></p> </blockquote> <p>Notice that you have a <mathjax>#color(red)(2):color(blue)(3)#</mathjax> <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> between <em>potassium chlorate</em>, <mathjax>#"KClO"""_3#</mathjax>, and <em>oxygen gas</em>, <mathjax>#"O"""_2#</mathjax>. </p> <p>This means that for a reaction that has an <strong>100%</strong> <a href="http://socratic.org/chemistry/stoichiometry/percent-yield">percent yield</a>, every two moles of potassium chlorate will produce three moles of oxygen gas. </p> <p>Keep this in mind. </p> <p>So, you know that your reaction must produce <mathjax>#"42.0 g"#</mathjax> of oxygen gas. Use oxygen gas' molar mass to find how many moles must be produced</p> <blockquote> <p><mathjax>#42.0color(red)(cancel(color(black)("g"))) * ("1 mole O"""_2)/(32.0color(red)(cancel(color(black)("g")))) = "1.3125 moles O"""_2#</mathjax></p> </blockquote> <p>So, how many moles of potassium chlorate would you need <strong>If the reaction had an 100%</strong> <a href="http://socratic.org/chemistry/stoichiometry/percent-yield">percent yield</a>?</p> <p>Use the aforementioned mole ratio to find</p> <blockquote> <p><mathjax>#1.3125color(red)(cancel(color(black)("moles O"_2))) * (color(red)(2)" moles KClO"""_3)/(color(blue)(3)color(red)(cancel(color(black)(" moles O"""_2)))) = "0.875 moles KClO"""_3#</mathjax></p> </blockquote> <p>However, you know for a fact that the percent yield of the reaction <strong>is not</strong> 100%, but <strong>65.0%</strong>. This means that you will need to use <strong>more potassium chlorate</strong> to produce this much oxygen gas. </p> <p>Percent yield is defined as the <em>actual yield</em> of the reaction divided by the <em>theoretical yield</em> of the reaction.</p> <blockquote> <p><mathjax>#"% yield" = "actual yield"/"theoretical yield" xx 100#</mathjax></p> </blockquote> <p>You know that the reaction's <em>actual yield</em> is <strong>42.0 g</strong> of oxygen gas, which means that the <em>theoretical yield</em> must be </p> <blockquote> <p><mathjax>#"65.0%" = "42.0 g"/"theoretical yield" xx 100#</mathjax> </p> </blockquote> <p><mathjax>#"theoretical yield" = ("42.0 g" * 100)/65 = "64.6 g"#</mathjax></p> <p>This means that you need to find how many grams of potassium chlorate would <strong>theoretically</strong> produce <strong>64.6 g</strong> of oxygen gas. </p> <p>Once again, use oxygen's molar mass and <a href="http://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio that exists between the two <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a></p> <blockquote> <p><mathjax>#64.6color(red)(cancel(color(black)("g O"_2))) * ("1 mole O"""_2)/(32.0color(red)(cancel(color(black)("g O"_2)))) = "2.019 moles O"""_2#</mathjax></p> </blockquote> <p>This means that you need to use</p> <blockquote> <p><mathjax>#2.019color(red)(cancel(color(black)("moles O"_2))) * (color(red)(2)" moles KClO"""_3)/(color(blue)(3)color(red)(cancel(color(black)(" moles O"""_2)))) = "1.346 moles KClO"""_3#</mathjax></p> </blockquote> <p>moles of potassium chlorate. Finally, use the compound's molar mass to find how many grams would contain this many moles</p> <blockquote> <p><mathjax>#1.346color(red)(cancel(color(black)("moles KClO"""_3))) * "122.55 g"/(1color(red)(cancel(color(black)("mole KClO"""_3)))) = color(green)("165 g KClO"""_3)#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">If the percent yield for the following reaction is 65.0%, how many grams of KClO3 are needed to produce 42.0 g of O2? 2 KClO3(s) → 2 KCl(s) + 3 O2(g) </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/percent-yield" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Yield</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="171506" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-09-24T11:27:15" itemprop="dateCreated"> Sep 24, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"165 g KClO"""_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Once again, start with the balanced chemical equation for this <a href="http://socratic.org/chemistry/chemical-reactions/decomposition-reactions">decomposition reaction</a></p> <blockquote> <p><mathjax>#color(red)(2)"KClO"_text(3(s]) -> 2"KCl"_text((s]) + color(blue)(3)"O"_text((g])#</mathjax></p> </blockquote> <p>Notice that you have a <mathjax>#color(red)(2):color(blue)(3)#</mathjax> <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> between <em>potassium chlorate</em>, <mathjax>#"KClO"""_3#</mathjax>, and <em>oxygen gas</em>, <mathjax>#"O"""_2#</mathjax>. </p> <p>This means that for a reaction that has an <strong>100%</strong> <a href="http://socratic.org/chemistry/stoichiometry/percent-yield">percent yield</a>, every two moles of potassium chlorate will produce three moles of oxygen gas. </p> <p>Keep this in mind. </p> <p>So, you know that your reaction must produce <mathjax>#"42.0 g"#</mathjax> of oxygen gas. Use oxygen gas' molar mass to find how many moles must be produced</p> <blockquote> <p><mathjax>#42.0color(red)(cancel(color(black)("g"))) * ("1 mole O"""_2)/(32.0color(red)(cancel(color(black)("g")))) = "1.3125 moles O"""_2#</mathjax></p> </blockquote> <p>So, how many moles of potassium chlorate would you need <strong>If the reaction had an 100%</strong> <a href="http://socratic.org/chemistry/stoichiometry/percent-yield">percent yield</a>?</p> <p>Use the aforementioned mole ratio to find</p> <blockquote> <p><mathjax>#1.3125color(red)(cancel(color(black)("moles O"_2))) * (color(red)(2)" moles KClO"""_3)/(color(blue)(3)color(red)(cancel(color(black)(" moles O"""_2)))) = "0.875 moles KClO"""_3#</mathjax></p> </blockquote> <p>However, you know for a fact that the percent yield of the reaction <strong>is not</strong> 100%, but <strong>65.0%</strong>. This means that you will need to use <strong>more potassium chlorate</strong> to produce this much oxygen gas. </p> <p>Percent yield is defined as the <em>actual yield</em> of the reaction divided by the <em>theoretical yield</em> of the reaction.</p> <blockquote> <p><mathjax>#"% yield" = "actual yield"/"theoretical yield" xx 100#</mathjax></p> </blockquote> <p>You know that the reaction's <em>actual yield</em> is <strong>42.0 g</strong> of oxygen gas, which means that the <em>theoretical yield</em> must be </p> <blockquote> <p><mathjax>#"65.0%" = "42.0 g"/"theoretical yield" xx 100#</mathjax> </p> </blockquote> <p><mathjax>#"theoretical yield" = ("42.0 g" * 100)/65 = "64.6 g"#</mathjax></p> <p>This means that you need to find how many grams of potassium chlorate would <strong>theoretically</strong> produce <strong>64.6 g</strong> of oxygen gas. </p> <p>Once again, use oxygen's molar mass and <a href="http://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio that exists between the two <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a></p> <blockquote> <p><mathjax>#64.6color(red)(cancel(color(black)("g O"_2))) * ("1 mole O"""_2)/(32.0color(red)(cancel(color(black)("g O"_2)))) = "2.019 moles O"""_2#</mathjax></p> </blockquote> <p>This means that you need to use</p> <blockquote> <p><mathjax>#2.019color(red)(cancel(color(black)("moles O"_2))) * (color(red)(2)" moles KClO"""_3)/(color(blue)(3)color(red)(cancel(color(black)(" moles O"""_2)))) = "1.346 moles KClO"""_3#</mathjax></p> </blockquote> <p>moles of potassium chlorate. Finally, use the compound's molar mass to find how many grams would contain this many moles</p> <blockquote> <p><mathjax>#1.346color(red)(cancel(color(black)("moles KClO"""_3))) * "122.55 g"/(1color(red)(cancel(color(black)("mole KClO"""_3)))) = color(green)("165 g KClO"""_3)#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/171506" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="171507" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/r-v-subba-rao"><img alt="" class="" src="https://lh6.googleusercontent.com/-VIxfCP4FJBY/AAAAAAAAAAI/AAAAAAAAACM/gieCnhslbxg/photo.jpg?sz=50" title=""/></a> <a class="secondContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/r-v-subba-rao"> R V SUBBARAO </a>·<a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-09-24T11:27:26" itemprop="dateCreated"> Sep 24, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>You need 165 g of <mathjax>#"KClO"_3#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><mathjax>#2"KClO"_3 → "2KCl" + "3O"_2#</mathjax></p> <p>From the above reaction it can be seen that</p> <p><mathjax>#"2 mol of KClO"_3 = "3 mol of O"_2#</mathjax></p> <blockquote></blockquote> <p><mathjax>#"1 mol of KClO"_3 = 3/2 " mol O"_2 = "1.5 mol O"_2#</mathjax>.</p> <p>The yield of the reaction is given in %, i.e., 65 %.</p> <p><mathjax>#"1 mol KClO"_3#</mathjax> generates <mathjax>#"1.5 mol O"_2#</mathjax></p> <p>Since the yield is 65 %, the number of moles of <mathjax>#"O"_2#</mathjax> generated per mole of <mathjax>#"KClO"_3#</mathjax> is</p> <p><mathjax>#"1.5 mol" xx 65/100 = "0.975 mol"#</mathjax></p> <p><mathjax>#"Number of moles of O"_2 = "42.0 g"/"32.0 g/mol" = "1.31 mol"#</mathjax></p> <blockquote></blockquote> <p><mathjax>#"Number of moles of KClO"_3 = "1.31 mol O"_2//("0.975 mol O"_2//"mol KClO"_3) = "1.35 mol KClO"_3#</mathjax></p> <p><mathjax>#"Weight of KClO"_3 = "1.35 mol KClO"_3xx"Molecular weight of KClO"_3#</mathjax></p> <p><mathjax>#= "1.34 mol"xx"122.6 g/mol = 165 g"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/171507" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ebd02bf3469570e2e62"> Question #e2e62 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ec502bf34694a4fee2e"> Question #fee2e </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ec902bf34694a4fee32"> Question #fee32 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ece02bf346950519e89"> Question #19e89 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ed302bf34694c8c5bdc"> Question #c5bdc </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ee302bf3469517a1065"> Question #a1065 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-would-be-the-limiting-reagent-if-26-0-grams-of-c3h9n-were-reacted-with-46-3"> What would be the limiting reagent if 26.0 grams of C3H9N were reacted with 46.3 grams of... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-percent-yield-always-less-than-100"> Is percent yield always less than 100? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-would-be-the-limiting-reagent-if-41-9-grams-of-c2h3of-were-reacted-with-61-"> What would be the limiting reagent if 41.9 grams of C2H3OF were reacted with 61.0 grams of... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-yield-of-the-following-reaction-if-60-grams-of-caco3-is-heat"> What is the percent yield of the following reaction if 60 grams of CaCO3 is heated to give 15... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/percent-yield"> See all questions in Percent Yield </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 120250 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	If the percent yield for the following reaction is 65.0%, how many grams of KClO3 are needed to produce 42.0 g of O2? 2 KClO3(s) → 2 KCl(s) + 3 O2(g)	null
1,772	ab7582be-6ddd-11ea-9349-ccda262736ce	https://socratic.org/questions/what-is-the-n-factor-of-pbso-4	2.00 × 10^(-3) mol	start physical_unit 5 5 mole mol qc_end physical_unit 17 17 15 16 molarity qc_end physical_unit 24 24 15 16 molarity qc_end end	[{"type":"physical unit","value":"Mole [OF] PbSO4 [IN] mol"}]	[{"type":"physical unit","value":"2.00 × 10^(-3) mol"}]	[{"type":"physical unit","value":"Volume [OF] Pb(NO3)2 solution [=] \\pu{20.00 ml}"},{"type":"physical unit","value":"Molarity [OF] Pb(NO3)2 solution [=] \\pu{0.1 M}"},{"type":"physical unit","value":"Volume [OF] Na2SO4 solution [=] \\pu{30.00 ml}"},{"type":"physical unit","value":"Molarity [OF] Na2SO4 solution [=] \\pu{0.1 M}"}]	<h1 class="questionTitle" itemprop="name">Maximum number of mol of #PbSO_4# that can be precipitated by mixing 20.00 ml of 0.1 M #Pb(NO_3)_2# and 30.00 ml of 0.1 M #Na_2SO_4# will be?</h1>	null	2.00 × 10^(-3) mol	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Start by writing the balanced chemical equation that describes this <strong>double replacement reaction</strong></p> <blockquote> <p><mathjax>#"Pb"("NO"_ 3)_ (2(aq)) + "Na"_ 2"SO"_ (4(aq)) -> "PbSO"_ (4(s)) darr + 2"NaNO"_ (3(aq))#</mathjax></p> </blockquote> <p>Notice that the two reactants react in a <mathjax>#1:1#</mathjax> <strong>mole ratio</strong> and produce lead(II) sulfate, the precipitate, in <mathjax>#1:1#</mathjax> <strong><a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratios</a></strong>. </p> <p>Even without doing any calculation you should be able to say that lead(II) nitrate will act as a <strong><a href="https://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a></strong> here. That happens because you're dealing with <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> of <strong>equal molarities</strong>, which implies that the solution with the bigger <em>volume</em> will contain <strong>more moles</strong> of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a>. </p> <p>To confirm this, use the molarities and volumes to find the number of moles of each reactant</p> <blockquote> <p><mathjax>#20.00 color(red)(cancel(color(black)("mL solution"))) * ("0.1 moles Pb"("NO"_ 3)_2)/(10^3color(red)(cancel(color(black)("mL solution")))) = "0.0020 moles Pb"("NO"_3)_2#</mathjax></p> <p><mathjax>#30.00color(red)(cancel(color(black)("mL solution"))) * ("0.1 moles Na"_2"SO"_4)/(10^3color(red)(cancel(color(black)("mL solution")))) = "0.0030 moles Na"_2"SO"_4#</mathjax></p> </blockquote> <p>As you can see, you have <strong>fewer moles</strong> of lead(II) nitrate than of sodium sulfate, which implies that the former will act as a limiting reagent, i.e. it will be completely consumed <strong>before</strong> all the moles of sodium sulfate will get the chance to react. </p> <p>You can thus use the aforementioned <mathjax>#1:1#</mathjax> <strong>mole ratios</strong> to say that the reaction consumes <mathjax>#0.0020#</mathjax> <strong>moles</strong> of lead(II) nitrate <strong>and</strong> of sodium sulfate and produces <mathjax>#0.0020#</mathjax> <strong>moles</strong> of lead(II) sulfate.</p> <p>Therefore, the maximum number of moles of lead(II) sulfate that can be precipitated is equal to</p> <blockquote> <p><mathjax>#color(darkgreen)(ul(color(black)("moles PbSO"_4 = "0.002 moles")))#</mathjax></p> </blockquote> <p>The answer must be rounded to one <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figure</a></strong>, the number of sig figs you have for the molarities of the two solutions. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"0.002 moles PbSO"_4#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Start by writing the balanced chemical equation that describes this <strong>double replacement reaction</strong></p> <blockquote> <p><mathjax>#"Pb"("NO"_ 3)_ (2(aq)) + "Na"_ 2"SO"_ (4(aq)) -> "PbSO"_ (4(s)) darr + 2"NaNO"_ (3(aq))#</mathjax></p> </blockquote> <p>Notice that the two reactants react in a <mathjax>#1:1#</mathjax> <strong>mole ratio</strong> and produce lead(II) sulfate, the precipitate, in <mathjax>#1:1#</mathjax> <strong><a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratios</a></strong>. </p> <p>Even without doing any calculation you should be able to say that lead(II) nitrate will act as a <strong><a href="https://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a></strong> here. That happens because you're dealing with <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> of <strong>equal molarities</strong>, which implies that the solution with the bigger <em>volume</em> will contain <strong>more moles</strong> of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a>. </p> <p>To confirm this, use the molarities and volumes to find the number of moles of each reactant</p> <blockquote> <p><mathjax>#20.00 color(red)(cancel(color(black)("mL solution"))) * ("0.1 moles Pb"("NO"_ 3)_2)/(10^3color(red)(cancel(color(black)("mL solution")))) = "0.0020 moles Pb"("NO"_3)_2#</mathjax></p> <p><mathjax>#30.00color(red)(cancel(color(black)("mL solution"))) * ("0.1 moles Na"_2"SO"_4)/(10^3color(red)(cancel(color(black)("mL solution")))) = "0.0030 moles Na"_2"SO"_4#</mathjax></p> </blockquote> <p>As you can see, you have <strong>fewer moles</strong> of lead(II) nitrate than of sodium sulfate, which implies that the former will act as a limiting reagent, i.e. it will be completely consumed <strong>before</strong> all the moles of sodium sulfate will get the chance to react. </p> <p>You can thus use the aforementioned <mathjax>#1:1#</mathjax> <strong>mole ratios</strong> to say that the reaction consumes <mathjax>#0.0020#</mathjax> <strong>moles</strong> of lead(II) nitrate <strong>and</strong> of sodium sulfate and produces <mathjax>#0.0020#</mathjax> <strong>moles</strong> of lead(II) sulfate.</p> <p>Therefore, the maximum number of moles of lead(II) sulfate that can be precipitated is equal to</p> <blockquote> <p><mathjax>#color(darkgreen)(ul(color(black)("moles PbSO"_4 = "0.002 moles")))#</mathjax></p> </blockquote> <p>The answer must be rounded to one <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figure</a></strong>, the number of sig figs you have for the molarities of the two solutions. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Maximum number of mol of #PbSO_4# that can be precipitated by mixing 20.00 ml of 0.1 M #Pb(NO_3)_2# and 30.00 ml of 0.1 M #Na_2SO_4# will be?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/limiting-reagent" itemprop="url"> <span class="breadcrumb" itemprop="title">Limiting Reagent</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="441657" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-19T00:42:27" itemprop="dateCreated"> Jun 19, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"0.002 moles PbSO"_4#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Start by writing the balanced chemical equation that describes this <strong>double replacement reaction</strong></p> <blockquote> <p><mathjax>#"Pb"("NO"_ 3)_ (2(aq)) + "Na"_ 2"SO"_ (4(aq)) -> "PbSO"_ (4(s)) darr + 2"NaNO"_ (3(aq))#</mathjax></p> </blockquote> <p>Notice that the two reactants react in a <mathjax>#1:1#</mathjax> <strong>mole ratio</strong> and produce lead(II) sulfate, the precipitate, in <mathjax>#1:1#</mathjax> <strong><a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratios</a></strong>. </p> <p>Even without doing any calculation you should be able to say that lead(II) nitrate will act as a <strong><a href="https://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a></strong> here. That happens because you're dealing with <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> of <strong>equal molarities</strong>, which implies that the solution with the bigger <em>volume</em> will contain <strong>more moles</strong> of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a>. </p> <p>To confirm this, use the molarities and volumes to find the number of moles of each reactant</p> <blockquote> <p><mathjax>#20.00 color(red)(cancel(color(black)("mL solution"))) * ("0.1 moles Pb"("NO"_ 3)_2)/(10^3color(red)(cancel(color(black)("mL solution")))) = "0.0020 moles Pb"("NO"_3)_2#</mathjax></p> <p><mathjax>#30.00color(red)(cancel(color(black)("mL solution"))) * ("0.1 moles Na"_2"SO"_4)/(10^3color(red)(cancel(color(black)("mL solution")))) = "0.0030 moles Na"_2"SO"_4#</mathjax></p> </blockquote> <p>As you can see, you have <strong>fewer moles</strong> of lead(II) nitrate than of sodium sulfate, which implies that the former will act as a limiting reagent, i.e. it will be completely consumed <strong>before</strong> all the moles of sodium sulfate will get the chance to react. </p> <p>You can thus use the aforementioned <mathjax>#1:1#</mathjax> <strong>mole ratios</strong> to say that the reaction consumes <mathjax>#0.0020#</mathjax> <strong>moles</strong> of lead(II) nitrate <strong>and</strong> of sodium sulfate and produces <mathjax>#0.0020#</mathjax> <strong>moles</strong> of lead(II) sulfate.</p> <p>Therefore, the maximum number of moles of lead(II) sulfate that can be precipitated is equal to</p> <blockquote> <p><mathjax>#color(darkgreen)(ul(color(black)("moles PbSO"_4 = "0.002 moles")))#</mathjax></p> </blockquote> <p>The answer must be rounded to one <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figure</a></strong>, the number of sig figs you have for the molarities of the two solutions. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/441657" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-how-much-of-the-excess-reactant-is-left-over-also-how-do-yo"> How do you determine how much of the excess reactant is left over? Also, how do you determine... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40fb002bf34694c8c5be2"> What is the limiting reactant in a Grignard reaction? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40fb002bf346950519e8d"> Question #19e8d </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40fb102bf34694c8c5be6"> Question #c5be6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40fb302bf346950519e95"> Question #19e95 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40fb302bf3469588dc361"> Question #dc361 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40fb402bf346963eb983d"> Question #b983d </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40fb702bf346950519e99"> Question #19e99 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5320fad502bf3443cd052b92"> Question #52b92 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5338b3be02bf345c6413f1d9"> Question #3f1d9 </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/limiting-reagent"> See all questions in Limiting Reagent </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 9321 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Maximum number of mol of #PbSO_4# that can be precipitated by mixing 20.00 ml of 0.1 M #Pb(NO_3)_2# and 30.00 ml of 0.1 M #Na_2SO_4# will be?	null
1,773	aa0cd6f5-6ddd-11ea-a3bf-ccda262736ce	https://socratic.org/questions/how-do-you-write-a-complete-balanced-reaction-of-aqueous-lead-ii-nitrate-pb-no-3	Pb(NO3)2(aq) + 2 KCl(aq) -> PbCl2(s) + 2 KNO3(aq)	start chemical_equation qc_end chemical_equation 13 13 qc_end chemical_equation 18 18 qc_end end	[{"type":"other","value":"Chemical Equation [OF] a complete balanced reaction"}]	[{"type":"chemical equation","value":"Pb(NO3)2(aq) + 2 KCl(aq) -> PbCl2(s) + 2 KNO3(aq)"}]	[{"type":"chemical equation","value":"Pb(NO3)2"},{"type":"chemical equation","value":"KCl"}]	<h1 class="questionTitle" itemprop="name">How do you write a complete balanced reaction of aqueous lead (II) nitrate, #Pb(NO_3)_2#, and aqueous potassium chloride, #KCL#?</h1>	null	Pb(NO3)2(aq) + 2 KCl(aq) -> PbCl2(s) + 2 KNO3(aq)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>How did I know that <mathjax>#PbCl_2#</mathjax> was insoluble? Chemistry is an experimental science and this is something that you must learn. All halides are soluble, EXCEPT for lead(II) chloride, mercurous chloride (<mathjax>#Hg_2Cl_2#</mathjax>), and silver chloride, <mathjax>#AgCl#</mathjax>. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Pb(NO_3)_2(aq) + 2KCl(aq) rarr PbCl_2(s)darr + 2KNO_3(aq) #</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>How did I know that <mathjax>#PbCl_2#</mathjax> was insoluble? Chemistry is an experimental science and this is something that you must learn. All halides are soluble, EXCEPT for lead(II) chloride, mercurous chloride (<mathjax>#Hg_2Cl_2#</mathjax>), and silver chloride, <mathjax>#AgCl#</mathjax>. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you write a complete balanced reaction of aqueous lead (II) nitrate, #Pb(NO_3)_2#, and aqueous potassium chloride, #KCL#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="195129" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-01T16:25:05" itemprop="dateCreated"> Dec 1, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Pb(NO_3)_2(aq) + 2KCl(aq) rarr PbCl_2(s)darr + 2KNO_3(aq) #</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>How did I know that <mathjax>#PbCl_2#</mathjax> was insoluble? Chemistry is an experimental science and this is something that you must learn. All halides are soluble, EXCEPT for lead(II) chloride, mercurous chloride (<mathjax>#Hg_2Cl_2#</mathjax>), and silver chloride, <mathjax>#AgCl#</mathjax>. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/195129" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------> H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -> Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? 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Sodium phosphate and calcium chloride react to form... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-equation-kclo3-kcl-o2"> How can I balance this equation? ____ #KClO_3 -># ____ #KCl +# ____ #O_2# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-balancing-chemical-equations-important"> Why is balancing chemical equations important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/balancing-chemical-equations"> See all questions in Balancing Chemical Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 23905 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How do you write a complete balanced reaction of aqueous lead (II) nitrate, #Pb(NO_3)_2#, and aqueous potassium chloride, #KCL#?	null
1,774	ab06bf72-6ddd-11ea-af3f-ccda262736ce	https://socratic.org/questions/what-volume-of-methanol-0-8g-cm-3-needs-to-be-oxidized-to-produce-500ml-40-forma	300 cm^3	start physical_unit 3 3 volume cm^3 qc_end physical_unit 3 3 6 7 density qc_end physical_unit 17 17 14 15 volume qc_end physical_unit 17 17 20 21 density qc_end physical_unit 17 17 16 16 percent qc_end end	[{"type":"physical unit","value":"Volume [OF] methanol [IN] cm^3"}]	[{"type":"physical unit","value":"300 cm^3"}]	[{"type":"physical unit","value":"ρ [OF] methanol [=] \\pu{0.8 g/cm^3}"},{"type":"physical unit","value":"Volume [OF] formaldehyde [=] \\pu{500 mL}"},{"type":"physical unit","value":"ρ [OF] formaldehyde [=] \\pu{1.11 g/cm^3}"},{"type":"physical unit","value":"Percent [OF] formaldehyde in solution [=] \\pu{40%}"}]	<h1 class="questionTitle" itemprop="name">What volume of methanol (ρ=0.8g/cm^3) needs to be oxidized to produce 500mL 40% formaldehyde (ρ=1.11g/cm^3)?</h1>	null	300 cm^3	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>Step 1. Calculate the mass of formaldehyde</strong></p> <p><mathjax>#"Mass of formalin" = 5000 color(red)(cancel(color(black)("mL formalin"))) × ("1.11 g formalin")/(1 color(red)(cancel(color(black)("mL formalin")))) = "555 g formalin"#</mathjax></p> <p><mathjax>#"Mass of formaldehyde" =555 color(red)(cancel(color(black)("g formalin"))) × "40 g formaldehyde"/(100 color(red)(cancel(color(black)("g formalin")))) = "222 g formaldehyde"#</mathjax></p> <p><mathjax>#"Moles of CH"_2"O" = 222 color(red)(cancel(color(black)("g CH"_2"O"))) × ("1 mol CH"_2"O")/( 30.03 color(red)(cancel(color(black)("g CH"_2"O")))) = "7.393 mol CH"_2"O"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 2. Calculate the moles of methanol</strong></p> <p><mathjax>#"2CH"_3"OH" + "2O"_2 → "2CH"_2"O" + "2H"_2"O"#</mathjax></p> <p><mathjax>#"Moles of CH"_4 = 7.393 color(red)(cancel(color(black)("mol CH"_2"O"))) × ("2 mol CH"_3"OH")/(2 color(red)(cancel(color(black)("mol CH"_2"O")))) = "7.393 mol CH"_3"OH"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 3. Calculate the mass of methanol</strong></p> <p><mathjax>#"Mas of methanol" = 7.393 color(red)(cancel(color(black)("mol CH"_3"OH"))) × ("32.04 g CH"_3"OH")/(1 color(red)(cancel(color(black)("mol CH"_3"OH")))) = "236.9 g CH"_3"OH"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 4. Calculate the volume of methanol</strong></p> <p><mathjax>#"Volume of CH"_3"OH" = 236.9 color(red)(cancel(color(black)("g CH"_3"OH"))) × ("1 cm"^3color(white)(l) "CH"_3"OH")/(0.8 color(red)(cancel(color(black)("g CH"_3"OH")))) = "300 cm"^3color(white)(l) "CH"_3"OH"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>You need <mathjax>#"300 cm"^3#</mathjax> of methanol.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>Step 1. Calculate the mass of formaldehyde</strong></p> <p><mathjax>#"Mass of formalin" = 5000 color(red)(cancel(color(black)("mL formalin"))) × ("1.11 g formalin")/(1 color(red)(cancel(color(black)("mL formalin")))) = "555 g formalin"#</mathjax></p> <p><mathjax>#"Mass of formaldehyde" =555 color(red)(cancel(color(black)("g formalin"))) × "40 g formaldehyde"/(100 color(red)(cancel(color(black)("g formalin")))) = "222 g formaldehyde"#</mathjax></p> <p><mathjax>#"Moles of CH"_2"O" = 222 color(red)(cancel(color(black)("g CH"_2"O"))) × ("1 mol CH"_2"O")/( 30.03 color(red)(cancel(color(black)("g CH"_2"O")))) = "7.393 mol CH"_2"O"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 2. Calculate the moles of methanol</strong></p> <p><mathjax>#"2CH"_3"OH" + "2O"_2 → "2CH"_2"O" + "2H"_2"O"#</mathjax></p> <p><mathjax>#"Moles of CH"_4 = 7.393 color(red)(cancel(color(black)("mol CH"_2"O"))) × ("2 mol CH"_3"OH")/(2 color(red)(cancel(color(black)("mol CH"_2"O")))) = "7.393 mol CH"_3"OH"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 3. Calculate the mass of methanol</strong></p> <p><mathjax>#"Mas of methanol" = 7.393 color(red)(cancel(color(black)("mol CH"_3"OH"))) × ("32.04 g CH"_3"OH")/(1 color(red)(cancel(color(black)("mol CH"_3"OH")))) = "236.9 g CH"_3"OH"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 4. Calculate the volume of methanol</strong></p> <p><mathjax>#"Volume of CH"_3"OH" = 236.9 color(red)(cancel(color(black)("g CH"_3"OH"))) × ("1 cm"^3color(white)(l) "CH"_3"OH")/(0.8 color(red)(cancel(color(black)("g CH"_3"OH")))) = "300 cm"^3color(white)(l) "CH"_3"OH"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What volume of methanol (ρ=0.8g/cm^3) needs to be oxidized to produce 500mL 40% formaldehyde (ρ=1.11g/cm^3)?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/redox-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Redox Reactions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="599222" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-04-21T16:01:39" itemprop="dateCreated"> Apr 21, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>You need <mathjax>#"300 cm"^3#</mathjax> of methanol.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>Step 1. Calculate the mass of formaldehyde</strong></p> <p><mathjax>#"Mass of formalin" = 5000 color(red)(cancel(color(black)("mL formalin"))) × ("1.11 g formalin")/(1 color(red)(cancel(color(black)("mL formalin")))) = "555 g formalin"#</mathjax></p> <p><mathjax>#"Mass of formaldehyde" =555 color(red)(cancel(color(black)("g formalin"))) × "40 g formaldehyde"/(100 color(red)(cancel(color(black)("g formalin")))) = "222 g formaldehyde"#</mathjax></p> <p><mathjax>#"Moles of CH"_2"O" = 222 color(red)(cancel(color(black)("g CH"_2"O"))) × ("1 mol CH"_2"O")/( 30.03 color(red)(cancel(color(black)("g CH"_2"O")))) = "7.393 mol CH"_2"O"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 2. Calculate the moles of methanol</strong></p> <p><mathjax>#"2CH"_3"OH" + "2O"_2 → "2CH"_2"O" + "2H"_2"O"#</mathjax></p> <p><mathjax>#"Moles of CH"_4 = 7.393 color(red)(cancel(color(black)("mol CH"_2"O"))) × ("2 mol CH"_3"OH")/(2 color(red)(cancel(color(black)("mol CH"_2"O")))) = "7.393 mol CH"_3"OH"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 3. Calculate the mass of methanol</strong></p> <p><mathjax>#"Mas of methanol" = 7.393 color(red)(cancel(color(black)("mol CH"_3"OH"))) × ("32.04 g CH"_3"OH")/(1 color(red)(cancel(color(black)("mol CH"_3"OH")))) = "236.9 g CH"_3"OH"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 4. Calculate the volume of methanol</strong></p> <p><mathjax>#"Volume of CH"_3"OH" = 236.9 color(red)(cancel(color(black)("g CH"_3"OH"))) × ("1 cm"^3color(white)(l) "CH"_3"OH")/(0.8 color(red)(cancel(color(black)("g CH"_3"OH")))) = "300 cm"^3color(white)(l) "CH"_3"OH"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/599222" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/54423f26581e2a5bfd08340d"> Question #8340d </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-redox-reaction"> What is a redox reaction? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-oxidation"> What is oxidation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-reduction"> What is reduction? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/54d532c6581e2a49268014c4"> Question #014c4 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/556ea205581e2a438ccb58e9"> Question #b58e9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/55973977581e2a5f9d456add"> Question #56add </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/55ad1b09581e2a5dd320853f"> Question #0853f </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/55b8d545581e2a20b9abe12b"> Question #be12b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5618b78a11ef6b27240f7e3f"> Question #f7e3f </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/redox-reactions"> See all questions in Redox Reactions </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1340 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What volume of methanol (ρ=0.8g/cm^3) needs to be oxidized to produce 500mL 40% formaldehyde (ρ=1.11g/cm^3)?	null
1,775	aa98c70a-6ddd-11ea-81a0-ccda262736ce	https://socratic.org/questions/an-aqueous-solution-has-a-hydronium-ion-concentration-of-6-10-9-mole-per-liter-a	8.22	start physical_unit 1 2 ph none qc_end physical_unit 5 6 9 14 concentration qc_end physical_unit 1 2 16 17 temperature qc_end end	[{"type":"physical unit","value":"pH [OF] the aqueous solution"}]	[{"type":"physical unit","value":"8.22"}]	[{"type":"physical unit","value":"Concentration [OF] hydronium ion [=] \\pu{6 × 10^(-9) mole per liter}"},{"type":"physical unit","value":"Temperature [OF] the aqueous solution [=] \\pu{25 ℃}"}]	<h1 class="questionTitle" itemprop="name">An aqueous solution has a hydronium ion concentration of #6 * 10^-9# mole per liter at 25°C. What is its pH?</h1>	null	8.22	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> of a solution could be calculated using the concentration of hydronium <mathjax>#H_3O^+#</mathjax> by: <mathjax>#pH=-log[H_3O^+]#</mathjax></p> <p>Therefore, <mathjax>#pH=-log(6xx10^(-9))=8.22 =8 ("1 significant figures")#</mathjax></p> <p><strong>Acids & Bases \| Nature, Strength & pH Scale.</strong><br/> <iframe src="https://www.youtube.com/embed/3rPRpozi64Q?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#pH=8#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> of a solution could be calculated using the concentration of hydronium <mathjax>#H_3O^+#</mathjax> by: <mathjax>#pH=-log[H_3O^+]#</mathjax></p> <p>Therefore, <mathjax>#pH=-log(6xx10^(-9))=8.22 =8 ("1 significant figures")#</mathjax></p> <p><strong>Acids & Bases \| Nature, Strength & pH Scale.</strong><br/> <iframe src="https://www.youtube.com/embed/3rPRpozi64Q?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">An aqueous solution has a hydronium ion concentration of #6 * 10^-9# mole per liter at 25°C. What is its pH?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/the-ph-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">pH</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="263926" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ali-h-1"><img alt="" class="" src="https://profilepictures.socratic.org/IITeL1YTQdODdLp0aJTL_StereoPicture%20copy.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ali-h-1"> Dr. Hayek </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-09T13:13:47" itemprop="dateCreated"> May 9, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#pH=8#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> of a solution could be calculated using the concentration of hydronium <mathjax>#H_3O^+#</mathjax> by: <mathjax>#pH=-log[H_3O^+]#</mathjax></p> <p>Therefore, <mathjax>#pH=-log(6xx10^(-9))=8.22 =8 ("1 significant figures")#</mathjax></p> <p><strong>Acids & Bases \| Nature, Strength & pH Scale.</strong><br/> <iframe src="https://www.youtube.com/embed/3rPRpozi64Q?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/263926" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="263929" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-09T13:18:07" itemprop="dateCreated"> May 9, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#pH =8.22#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So what is <mathjax>#pH#</mathjax>?</p> <p>Here it is simply the function <mathjax>#pH=-log_10[H_3O^+]#</mathjax>, <mathjax>#pH#</mathjax> derives from the French <mathjax>#"pouvoir hydrogene"#</mathjax>, <mathjax>#"the power of hydrogen"#</mathjax>.</p> <p>We have <mathjax>#[H_3O^+]#</mathjax> and we have a calculator, so we press the buttons. </p> <p>It is worthwhile to review the logarithmic function, and see why the use of logarithms (and slide rules) was absolutely widespread among scientists and engineers in a pre-calculator world.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/263929" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-pka"> How do you determine pH from pKa? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-ph-values-of-acids-and-bases-differ"> How do pH values of acids and bases differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-something-on-a-ph-scale"> How do you calculate something on a pH scale? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-diprotic-acid"> How do you calculate pH diprotic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-from-acid-dissociation-constant"> How do you calculate pH from acid dissociation constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-of-acid-and-base-solution"> How do you calculate pH of acid and base solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ph-scale-0-14"> Why is the pH scale 0-14? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-ph-the-measure-of-the-hydrogen-ion-concentration"> Is pH a measure of the hydrogen ion concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-solubility-affect-ph"> How does solubility affect pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-ph-relate-to-pka-in-a-titration"> How does pH relate to pKa in a titration? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/the-ph-concept"> See all questions in pH </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 4162 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	An aqueous solution has a hydronium ion concentration of #6 * 10^-9# mole per liter at 25°C. What is its pH?	null
1,776	a99bc09d-6ddd-11ea-bb42-ccda262736ce	https://socratic.org/questions/what-is-the-oh-for-a-water-solution-if-the-h-3o-is-6-0-times-10-11-m	1.67 × 10^(-4) M	start physical_unit 6 7 [oh-] mol/l qc_end physical_unit 6 7 12 15 [h3o+] qc_end end	[{"type":"physical unit","value":"[OH-] [OF] the water solution [IN] M"}]	[{"type":"physical unit","value":"1.67 × 10^(-4) M"}]	[{"type":"physical unit","value":"[H3O+] [OF] the water solution [=] \\pu{6.0 × 10^(-11) M}"}]	<h1 class="questionTitle" itemprop="name">What is the #[OH^-]# for a water solution if the #[H_3O^+]# is #6.0 times 10^-11# #M#? </h1>	null	1.67 × 10^(-4) M	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>For <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> at <mathjax>#25^o"C"#</mathjax>, the total concentration of <mathjax>#["OH"^-]#</mathjax> and <mathjax>#["H"_3"O"^+]#</mathjax> is given by the equation</p> <p><mathjax>#K_"w" = ["OH"^-]["H"_3"O"^+] = 1.00 xx 10^-14 M^2#</mathjax></p> <p>This equation is applicable to both pure water and to any aqueous solution. Although this equilibrium is somewhat affected by the presence of other ions in solution, we generally disregard this unless we're dealing with calculations involving great accuracy.</p> <p>Since the product of the concentrations of the hydroxide and hydronium ions equals a <em>constant</em>, the two concentrations are inversely proportional. That is, if one increases, the other must decrease.</p> <p>We can plug the given <mathjax>#["H"_3"O"^+]#</mathjax> into the above equation and solve for <mathjax>#["OH"^-]#</mathjax>:</p> <p><mathjax>#["OH"^-] = (1.00 xx 10^-14 M^cancel(2))/(6.0 xx 10^-11 cancel(M)) = color(red)(1.7 xx 10^-4 M#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1.7 xx 10^-4 M#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>For <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> at <mathjax>#25^o"C"#</mathjax>, the total concentration of <mathjax>#["OH"^-]#</mathjax> and <mathjax>#["H"_3"O"^+]#</mathjax> is given by the equation</p> <p><mathjax>#K_"w" = ["OH"^-]["H"_3"O"^+] = 1.00 xx 10^-14 M^2#</mathjax></p> <p>This equation is applicable to both pure water and to any aqueous solution. Although this equilibrium is somewhat affected by the presence of other ions in solution, we generally disregard this unless we're dealing with calculations involving great accuracy.</p> <p>Since the product of the concentrations of the hydroxide and hydronium ions equals a <em>constant</em>, the two concentrations are inversely proportional. That is, if one increases, the other must decrease.</p> <p>We can plug the given <mathjax>#["H"_3"O"^+]#</mathjax> into the above equation and solve for <mathjax>#["OH"^-]#</mathjax>:</p> <p><mathjax>#["OH"^-] = (1.00 xx 10^-14 M^cancel(2))/(6.0 xx 10^-11 cancel(M)) = color(red)(1.7 xx 10^-4 M#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the #[OH^-]# for a water solution if the #[H_3O^+]# is #6.0 times 10^-11# #M#? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/the-ph-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">pH</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="430796" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/mrtas"><img alt="" class="" src="https://profilepictures.socratic.org/HY14X7r4S6AyDQgK2gwQ_IMG_0062.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/mrtas"> Nathan L. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-28T03:28:51" itemprop="dateCreated"> May 28, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1.7 xx 10^-4 M#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>For <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> at <mathjax>#25^o"C"#</mathjax>, the total concentration of <mathjax>#["OH"^-]#</mathjax> and <mathjax>#["H"_3"O"^+]#</mathjax> is given by the equation</p> <p><mathjax>#K_"w" = ["OH"^-]["H"_3"O"^+] = 1.00 xx 10^-14 M^2#</mathjax></p> <p>This equation is applicable to both pure water and to any aqueous solution. Although this equilibrium is somewhat affected by the presence of other ions in solution, we generally disregard this unless we're dealing with calculations involving great accuracy.</p> <p>Since the product of the concentrations of the hydroxide and hydronium ions equals a <em>constant</em>, the two concentrations are inversely proportional. That is, if one increases, the other must decrease.</p> <p>We can plug the given <mathjax>#["H"_3"O"^+]#</mathjax> into the above equation and solve for <mathjax>#["OH"^-]#</mathjax>:</p> <p><mathjax>#["OH"^-] = (1.00 xx 10^-14 M^cancel(2))/(6.0 xx 10^-11 cancel(M)) = color(red)(1.7 xx 10^-4 M#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/430796" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-pka"> How do you determine pH from pKa? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-ph-values-of-acids-and-bases-differ"> How do pH values of acids and bases differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-something-on-a-ph-scale"> How do you calculate something on a pH scale? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-diprotic-acid"> How do you calculate pH diprotic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-from-acid-dissociation-constant"> How do you calculate pH from acid dissociation constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-of-acid-and-base-solution"> How do you calculate pH of acid and base solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ph-scale-0-14"> Why is the pH scale 0-14? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-ph-the-measure-of-the-hydrogen-ion-concentration"> Is pH a measure of the hydrogen ion concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-solubility-affect-ph"> How does solubility affect pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-ph-relate-to-pka-in-a-titration"> How does pH relate to pKa in a titration? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/the-ph-concept"> See all questions in pH </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1438 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the #[OH^-]# for a water solution if the #[H_3O^+]# is #6.0 times 10^-11# #M#?	null
1,777	a83f584c-6ddd-11ea-a1aa-ccda262736ce	https://socratic.org/questions/5739d69c11ef6b4a4d63c789	6.45 moles	start physical_unit 4 5 mole mol qc_end physical_unit 12 13 9 10 mole qc_end end	[{"type":"physical unit","value":"Mole [OF] silver(I) bromide [IN] moles"}]	[{"type":"physical unit","value":"6.45 moles"}]	[{"type":"physical unit","value":"Mole [OF] sodium bromide [=] \\pu{6.45 moles}"},{"type":"chemical equation","value":"NaBr(aq) + AgNO3(aq) -> AgBr(s) v + NaNO3(aq)"}]	<h1 class="questionTitle" itemprop="name">How many moles of silver(I) bromide are produced when #6.45# moles of sodium bromide take part in the reaction?</h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p><mathjax>#"NaBr"_ ((aq)) + "AgNO"_ (3(aq)) -> "AgBr"_ ((s)) darr + "NaNO"_ (3(aq))#</mathjax></p></div> </h2> </div> </div>	6.45 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The thing to remember about <em>balanced</em> <a href="https://socratic.org/chemistry/chemical-reactions/chemical-equations">chemical equations</a> is that they tell you the <strong><a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratios</a></strong> in which the reactants and the products find themselves for a given chemical equation. </p> <p>More specifically, the balanced chemical equation tells you how many moles of each reactant will react with each other and how many moles of products will be produced as a result. </p> <p>In this case, the balanced chemical equation that describes this <strong><a href="https://socratic.org/chemistry/chemical-reactions/double-replacement-reactions">double replacement reaction</a></strong> looks like this</p> <blockquote> <p><mathjax>#"NaBr"_ ((aq)) + "AgNO"_ (3(aq)) -> "AgBr"_ ((s)) darr + "NaNO"_ (3(aq))#</mathjax></p> </blockquote> <p>Stoichiometric coefficients of <mathjax>#1#</mathjax> are omitted from the balanced chemical equation, but in your case the problem wants to give you a hand and lists them</p> <blockquote> <p><mathjax>#1"NaBr"_ ((aq)) + 1"AgNO"_ (3(aq)) -> 1"AgBr"_ ((s)) darr + 1"NaNO"_ (3(aq))#</mathjax></p> </blockquote> <p>So, this tells you that <strong>for every mole</strong> of sodium bromide, <mathjax>#"NaBr"#</mathjax>, that takes part in the reaction you get <mathjax>#1#</mathjax> <strong>mole</strong> of silver bromide, <mathjax>#"AgBr"#</mathjax> <mathjax>#->#</mathjax> the two <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a> are in a <mathjax>#1:1#</mathjax> <strong>mole ratio</strong>. </p> <p>Since you know that <mathjax>#6.45#</mathjax> <strong>moles</strong> of sodium bromide are available for the reaction, and assuming that <strong>all of them</strong> react, you can say that the reaction will produce</p> <blockquote> <p><mathjax>#6.45 color(red)(cancel(color(black)("moles NaBr"))) * "1 mole AgBr"/(1color(red)(cancel(color(black)("mole NaBr")))) = color(green)(\|bar(ul(color(white)(a/a)color(black)("6.45 moles AgBr")color(white)(a/a)\|)))#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"6.45 moles AgBr"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The thing to remember about <em>balanced</em> <a href="https://socratic.org/chemistry/chemical-reactions/chemical-equations">chemical equations</a> is that they tell you the <strong><a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratios</a></strong> in which the reactants and the products find themselves for a given chemical equation. </p> <p>More specifically, the balanced chemical equation tells you how many moles of each reactant will react with each other and how many moles of products will be produced as a result. </p> <p>In this case, the balanced chemical equation that describes this <strong><a href="https://socratic.org/chemistry/chemical-reactions/double-replacement-reactions">double replacement reaction</a></strong> looks like this</p> <blockquote> <p><mathjax>#"NaBr"_ ((aq)) + "AgNO"_ (3(aq)) -> "AgBr"_ ((s)) darr + "NaNO"_ (3(aq))#</mathjax></p> </blockquote> <p>Stoichiometric coefficients of <mathjax>#1#</mathjax> are omitted from the balanced chemical equation, but in your case the problem wants to give you a hand and lists them</p> <blockquote> <p><mathjax>#1"NaBr"_ ((aq)) + 1"AgNO"_ (3(aq)) -> 1"AgBr"_ ((s)) darr + 1"NaNO"_ (3(aq))#</mathjax></p> </blockquote> <p>So, this tells you that <strong>for every mole</strong> of sodium bromide, <mathjax>#"NaBr"#</mathjax>, that takes part in the reaction you get <mathjax>#1#</mathjax> <strong>mole</strong> of silver bromide, <mathjax>#"AgBr"#</mathjax> <mathjax>#->#</mathjax> the two <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a> are in a <mathjax>#1:1#</mathjax> <strong>mole ratio</strong>. </p> <p>Since you know that <mathjax>#6.45#</mathjax> <strong>moles</strong> of sodium bromide are available for the reaction, and assuming that <strong>all of them</strong> react, you can say that the reaction will produce</p> <blockquote> <p><mathjax>#6.45 color(red)(cancel(color(black)("moles NaBr"))) * "1 mole AgBr"/(1color(red)(cancel(color(black)("mole NaBr")))) = color(green)(\|bar(ul(color(white)(a/a)color(black)("6.45 moles AgBr")color(white)(a/a)\|)))#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles of silver(I) bromide are produced when #6.45# moles of sodium bromide take part in the reaction?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p><mathjax>#"NaBr"_ ((aq)) + "AgNO"_ (3(aq)) -> "AgBr"_ ((s)) darr + "NaNO"_ (3(aq))#</mathjax></p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/mole-ratios" itemprop="url"> <span class="breadcrumb" itemprop="title">Mole Ratios</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="279928" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-21T22:54:49" itemprop="dateCreated"> Jun 21, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"6.45 moles AgBr"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The thing to remember about <em>balanced</em> <a href="https://socratic.org/chemistry/chemical-reactions/chemical-equations">chemical equations</a> is that they tell you the <strong><a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratios</a></strong> in which the reactants and the products find themselves for a given chemical equation. </p> <p>More specifically, the balanced chemical equation tells you how many moles of each reactant will react with each other and how many moles of products will be produced as a result. </p> <p>In this case, the balanced chemical equation that describes this <strong><a href="https://socratic.org/chemistry/chemical-reactions/double-replacement-reactions">double replacement reaction</a></strong> looks like this</p> <blockquote> <p><mathjax>#"NaBr"_ ((aq)) + "AgNO"_ (3(aq)) -> "AgBr"_ ((s)) darr + "NaNO"_ (3(aq))#</mathjax></p> </blockquote> <p>Stoichiometric coefficients of <mathjax>#1#</mathjax> are omitted from the balanced chemical equation, but in your case the problem wants to give you a hand and lists them</p> <blockquote> <p><mathjax>#1"NaBr"_ ((aq)) + 1"AgNO"_ (3(aq)) -> 1"AgBr"_ ((s)) darr + 1"NaNO"_ (3(aq))#</mathjax></p> </blockquote> <p>So, this tells you that <strong>for every mole</strong> of sodium bromide, <mathjax>#"NaBr"#</mathjax>, that takes part in the reaction you get <mathjax>#1#</mathjax> <strong>mole</strong> of silver bromide, <mathjax>#"AgBr"#</mathjax> <mathjax>#->#</mathjax> the two <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a> are in a <mathjax>#1:1#</mathjax> <strong>mole ratio</strong>. </p> <p>Since you know that <mathjax>#6.45#</mathjax> <strong>moles</strong> of sodium bromide are available for the reaction, and assuming that <strong>all of them</strong> react, you can say that the reaction will produce</p> <blockquote> <p><mathjax>#6.45 color(red)(cancel(color(black)("moles NaBr"))) * "1 mole AgBr"/(1color(red)(cancel(color(black)("mole NaBr")))) = color(green)(\|bar(ul(color(white)(a/a)color(black)("6.45 moles AgBr")color(white)(a/a)\|)))#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/279928" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4178e02bf3469517a106e"> Question #a106e </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4178e02bf3469570e2e86"> Question #e2e86 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a 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#6.45# moles of sodium bromide take part in the reaction?	#"NaBr"_ ((aq)) + "AgNO"_ (3(aq)) -> "AgBr"_ ((s)) darr + "NaNO"_ (3(aq))#
1,778	ab0ba180-6ddd-11ea-bad5-ccda262736ce	https://socratic.org/questions/vanillin-a-flavoring-agent-is-made-up-of-carbon-hydrogen-and-oxygen-atoms-when-a	C8H8O3	start chemical_formula qc_end c_other OTHER qc_end physical_unit 15 17 19 20 mass qc_end c_other OTHER qc_end physical_unit 28 28 25 26 mass qc_end physical_unit 33 33 30 31 mass qc_end end	[{"type":"other","value":"Chemical Formula [OF] vanillin [IN] empirical"}]	[{"type":"chemical equation","value":"C8H8O3"}]	[{"type":"other","value":"Vanillin is made up of carbon, hydrogen, and oxygen atoms."},{"type":"physical unit","value":"Weight [OF] vanillin sample [=] \\pu{2.500 g}"},{"type":"other","value":"The sample of vanillin burns in pure oxygen."},{"type":"physical unit","value":"Weight [OF] CO2 [=] \\pu{5.79 g}"},{"type":"physical unit","value":"Weight [OF] water [=] \\pu{1.18 g}"}]	<h1 class="questionTitle" itemprop="name">Vanillin, a flavoring agent, is made up of carbon, hydrogen, and oxygen atoms. When a sample of vanillin weighting 2.500 g burns in pure oxygen, 5.79 g of #CO_2# and 1.18 g of water are obtained. How would you calculate the empirical formula of vanillin?</h1>	null	C8H8O3	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that you can use the <strong><a href="https://socratic.org/chemistry/a-closer-look-at-the-atom/mass-conservation">Law of Mass Conservation</a></strong> to figure out how much <em>carbon</em> and <em>hydrogen</em> you had in your <mathjax>#"2.500 g"#</mathjax> sample of vanillin. </p> <p>When vanillin undergoes combustion, <strong>all the carbon</strong> that was present in the sample will now be a part of the carbon dioxide. Similarly, <strong>all the hydrogen</strong> that was present in the sample will now be a part of the water. </p> <p>Carbon dioxide, <mathjax>#"CO"_2#</mathjax>, has a <strong>molar mass</strong> of <mathjax>#"44.01 g mol"^(-1)#</mathjax>, which implies that <strong>one mole</strong> of carbon dioxide has a mass of <mathjax>#"44.01 g"#</mathjax>. </p> <p>This means that the <mathjax>#"5.79 g"#</mathjax> of carbon dioxide will be equivalent to </p> <blockquote> <p><mathjax>#5.79 color(red)(cancel(color(black)("g"))) * "1 mole CO"_2/(44.01color(red)(cancel(color(black)("g")))) = "0.13156 moles CO"_2#</mathjax></p> </blockquote> <p>As you know, <strong>every mole</strong> of carbon dioxide contains <mathjax>#1#</mathjax> <strong>mole</strong> of carbon. Use carbon's <strong>molar mass</strong> to figure out how much carbon you have in this sample</p> <blockquote> <p><mathjax>#0.13156 color(red)(cancel(color(black)("moles CO"_2))) * (1 color(red)(cancel(color(black)("mole C"))))/(1color(red)(cancel(color(black)("mole CO"_2)))) * "12.011 g"/(1color(red)(cancel(color(black)("mole C")))) = "1.5802 g C"#</mathjax></p> </blockquote> <p>Water, <mathjax>#"H"_2"O"#</mathjax>, has a <strong>molar mass</strong> of <mathjax>#"18.015 g mol"^(-1)#</mathjax>. Use this value to calculate how many <em>moles</em> of water were produced by the reaction</p> <blockquote> <p><mathjax>#1.18 color(red)(cancel(color(black)("g"))) * ("1 mole H"_2"O")/(18.015color(red)(cancel(color(black)("g")))) = "0.065501 moles H"_2"O"#</mathjax></p> </blockquote> <p>Since <strong>every mole</strong> of water contains <mathjax>#2#</mathjax> <strong>moles</strong> of hydrogen, and since hydrogen has a <strong>molar mass</strong> of <mathjax>#"1.00794 g mol"^(-1)#</mathjax>, you can say that the sample contained</p> <blockquote> <p><mathjax>#0.065501 color(red)(cancel(color(black)("moles H"_2"O"))) * (2color(red)(cancel(color(black)("moles H"))))/(1color(red)(cancel(color(black)("mole H"_2"O")))) * "1.00794 g"/(1color(red)(cancel(color(black)("mole H")))) = "0.1320 g H"#</mathjax></p> </blockquote> <p>You know that vanillin contains carbon, hydrogen, and oxygen, so use the masses of carbon and hydrogen to calculate how many grams of oxygen were present in the original sample</p> <blockquote> <p><mathjax>#m_"vanillin" = m_"C" + m_"H" + m_"O"#</mathjax></p> <p><mathjax>#m_"O" = "2.500 g" - "1.5802 g" - "0.1320 g" = "0.7878 g O"#</mathjax></p> </blockquote> <p>Now, in order to find the compound's <strong>empirical formula</strong>, you must find the <em>smallest whole number ratio</em> that exists between carbon, hydrogen, and oxygen in vanillin. </p> <p>To do that, convert the masses to <em>moles</em> by using molar masses</p> <blockquote> <p><mathjax>#"For C: " 1.5802 color(red)(cancel(color(black)("g"))) * "1 mole C"/(12.011color(red)(cancel(color(black)("g")))) = "0.13156 moles C"#</mathjax></p> <p><mathjax>#"For H: " 0.1320 color(red)(cancel(color(black)("g"))) * "1 mole H"/(1.00794 color(red)(cancel(color(black)("g")))) = "0.1310 moles H"#</mathjax></p> <p><mathjax>#"For O: " 0.7878 color(red)(cancel(color(black)("g"))) * "1 mole O"/(15.9994 color(red)(cancel(color(black)("g")))) = "0.04924 moles O"#</mathjax></p> </blockquote> <p>To find the <strong>mole ratio</strong> that exists between the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a>, divide all values by the <em>smallest one</em> to find</p> <blockquote> <p><mathjax>#"For C: " (0.13156 color(red)(cancel(color(black)("moles"))))/(0.04924color(red)(cancel(color(black)("moles")))) = 2.67#</mathjax></p> <p><mathjax>#"For H: " (0.1310color(red)(cancel(color(black)("moles"))))/(0.04924color(red)(cancel(color(black)("moles")))) = 2.66#</mathjax></p> <p><mathjax>#"For O: " (0.04924color(red)(cancel(color(black)("moles"))))/(0.04924color(red)(cancel(color(black)("moles")))) = 1#</mathjax></p> </blockquote> <p>Now, you're looking for the <strong>smallest whole number ratio</strong> that exists between the three elements, so multiply all values by <mathjax>#3#</mathjax> to get</p> <blockquote> <p><mathjax>#"C"_ ((2.67 * 3)) "H"_ ((2.66 * 3)) "O"_ ((1 * 3)) implies color(green)(\|bar(ul(color(white)(a/a)color(black)("C"_ 8"H"_ 8"O"_3)color(white)(a/a)\|)))#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"C"_8"H"_8"O"_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that you can use the <strong><a href="https://socratic.org/chemistry/a-closer-look-at-the-atom/mass-conservation">Law of Mass Conservation</a></strong> to figure out how much <em>carbon</em> and <em>hydrogen</em> you had in your <mathjax>#"2.500 g"#</mathjax> sample of vanillin. </p> <p>When vanillin undergoes combustion, <strong>all the carbon</strong> that was present in the sample will now be a part of the carbon dioxide. Similarly, <strong>all the hydrogen</strong> that was present in the sample will now be a part of the water. </p> <p>Carbon dioxide, <mathjax>#"CO"_2#</mathjax>, has a <strong>molar mass</strong> of <mathjax>#"44.01 g mol"^(-1)#</mathjax>, which implies that <strong>one mole</strong> of carbon dioxide has a mass of <mathjax>#"44.01 g"#</mathjax>. </p> <p>This means that the <mathjax>#"5.79 g"#</mathjax> of carbon dioxide will be equivalent to </p> <blockquote> <p><mathjax>#5.79 color(red)(cancel(color(black)("g"))) * "1 mole CO"_2/(44.01color(red)(cancel(color(black)("g")))) = "0.13156 moles CO"_2#</mathjax></p> </blockquote> <p>As you know, <strong>every mole</strong> of carbon dioxide contains <mathjax>#1#</mathjax> <strong>mole</strong> of carbon. Use carbon's <strong>molar mass</strong> to figure out how much carbon you have in this sample</p> <blockquote> <p><mathjax>#0.13156 color(red)(cancel(color(black)("moles CO"_2))) * (1 color(red)(cancel(color(black)("mole C"))))/(1color(red)(cancel(color(black)("mole CO"_2)))) * "12.011 g"/(1color(red)(cancel(color(black)("mole C")))) = "1.5802 g C"#</mathjax></p> </blockquote> <p>Water, <mathjax>#"H"_2"O"#</mathjax>, has a <strong>molar mass</strong> of <mathjax>#"18.015 g mol"^(-1)#</mathjax>. Use this value to calculate how many <em>moles</em> of water were produced by the reaction</p> <blockquote> <p><mathjax>#1.18 color(red)(cancel(color(black)("g"))) * ("1 mole H"_2"O")/(18.015color(red)(cancel(color(black)("g")))) = "0.065501 moles H"_2"O"#</mathjax></p> </blockquote> <p>Since <strong>every mole</strong> of water contains <mathjax>#2#</mathjax> <strong>moles</strong> of hydrogen, and since hydrogen has a <strong>molar mass</strong> of <mathjax>#"1.00794 g mol"^(-1)#</mathjax>, you can say that the sample contained</p> <blockquote> <p><mathjax>#0.065501 color(red)(cancel(color(black)("moles H"_2"O"))) * (2color(red)(cancel(color(black)("moles H"))))/(1color(red)(cancel(color(black)("mole H"_2"O")))) * "1.00794 g"/(1color(red)(cancel(color(black)("mole H")))) = "0.1320 g H"#</mathjax></p> </blockquote> <p>You know that vanillin contains carbon, hydrogen, and oxygen, so use the masses of carbon and hydrogen to calculate how many grams of oxygen were present in the original sample</p> <blockquote> <p><mathjax>#m_"vanillin" = m_"C" + m_"H" + m_"O"#</mathjax></p> <p><mathjax>#m_"O" = "2.500 g" - "1.5802 g" - "0.1320 g" = "0.7878 g O"#</mathjax></p> </blockquote> <p>Now, in order to find the compound's <strong>empirical formula</strong>, you must find the <em>smallest whole number ratio</em> that exists between carbon, hydrogen, and oxygen in vanillin. </p> <p>To do that, convert the masses to <em>moles</em> by using molar masses</p> <blockquote> <p><mathjax>#"For C: " 1.5802 color(red)(cancel(color(black)("g"))) * "1 mole C"/(12.011color(red)(cancel(color(black)("g")))) = "0.13156 moles C"#</mathjax></p> <p><mathjax>#"For H: " 0.1320 color(red)(cancel(color(black)("g"))) * "1 mole H"/(1.00794 color(red)(cancel(color(black)("g")))) = "0.1310 moles H"#</mathjax></p> <p><mathjax>#"For O: " 0.7878 color(red)(cancel(color(black)("g"))) * "1 mole O"/(15.9994 color(red)(cancel(color(black)("g")))) = "0.04924 moles O"#</mathjax></p> </blockquote> <p>To find the <strong>mole ratio</strong> that exists between the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a>, divide all values by the <em>smallest one</em> to find</p> <blockquote> <p><mathjax>#"For C: " (0.13156 color(red)(cancel(color(black)("moles"))))/(0.04924color(red)(cancel(color(black)("moles")))) = 2.67#</mathjax></p> <p><mathjax>#"For H: " (0.1310color(red)(cancel(color(black)("moles"))))/(0.04924color(red)(cancel(color(black)("moles")))) = 2.66#</mathjax></p> <p><mathjax>#"For O: " (0.04924color(red)(cancel(color(black)("moles"))))/(0.04924color(red)(cancel(color(black)("moles")))) = 1#</mathjax></p> </blockquote> <p>Now, you're looking for the <strong>smallest whole number ratio</strong> that exists between the three elements, so multiply all values by <mathjax>#3#</mathjax> to get</p> <blockquote> <p><mathjax>#"C"_ ((2.67 * 3)) "H"_ ((2.66 * 3)) "O"_ ((1 * 3)) implies color(green)(\|bar(ul(color(white)(a/a)color(black)("C"_ 8"H"_ 8"O"_3)color(white)(a/a)\|)))#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Vanillin, a flavoring agent, is made up of carbon, hydrogen, and oxygen atoms. When a sample of vanillin weighting 2.500 g burns in pure oxygen, 5.79 g of #CO_2# and 1.18 g of water are obtained. How would you calculate the empirical formula of vanillin?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="293492" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-29T23:56:15" itemprop="dateCreated"> Jul 29, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"C"_8"H"_8"O"_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that you can use the <strong><a href="https://socratic.org/chemistry/a-closer-look-at-the-atom/mass-conservation">Law of Mass Conservation</a></strong> to figure out how much <em>carbon</em> and <em>hydrogen</em> you had in your <mathjax>#"2.500 g"#</mathjax> sample of vanillin. </p> <p>When vanillin undergoes combustion, <strong>all the carbon</strong> that was present in the sample will now be a part of the carbon dioxide. Similarly, <strong>all the hydrogen</strong> that was present in the sample will now be a part of the water. </p> <p>Carbon dioxide, <mathjax>#"CO"_2#</mathjax>, has a <strong>molar mass</strong> of <mathjax>#"44.01 g mol"^(-1)#</mathjax>, which implies that <strong>one mole</strong> of carbon dioxide has a mass of <mathjax>#"44.01 g"#</mathjax>. </p> <p>This means that the <mathjax>#"5.79 g"#</mathjax> of carbon dioxide will be equivalent to </p> <blockquote> <p><mathjax>#5.79 color(red)(cancel(color(black)("g"))) * "1 mole CO"_2/(44.01color(red)(cancel(color(black)("g")))) = "0.13156 moles CO"_2#</mathjax></p> </blockquote> <p>As you know, <strong>every mole</strong> of carbon dioxide contains <mathjax>#1#</mathjax> <strong>mole</strong> of carbon. Use carbon's <strong>molar mass</strong> to figure out how much carbon you have in this sample</p> <blockquote> <p><mathjax>#0.13156 color(red)(cancel(color(black)("moles CO"_2))) * (1 color(red)(cancel(color(black)("mole C"))))/(1color(red)(cancel(color(black)("mole CO"_2)))) * "12.011 g"/(1color(red)(cancel(color(black)("mole C")))) = "1.5802 g C"#</mathjax></p> </blockquote> <p>Water, <mathjax>#"H"_2"O"#</mathjax>, has a <strong>molar mass</strong> of <mathjax>#"18.015 g mol"^(-1)#</mathjax>. Use this value to calculate how many <em>moles</em> of water were produced by the reaction</p> <blockquote> <p><mathjax>#1.18 color(red)(cancel(color(black)("g"))) * ("1 mole H"_2"O")/(18.015color(red)(cancel(color(black)("g")))) = "0.065501 moles H"_2"O"#</mathjax></p> </blockquote> <p>Since <strong>every mole</strong> of water contains <mathjax>#2#</mathjax> <strong>moles</strong> of hydrogen, and since hydrogen has a <strong>molar mass</strong> of <mathjax>#"1.00794 g mol"^(-1)#</mathjax>, you can say that the sample contained</p> <blockquote> <p><mathjax>#0.065501 color(red)(cancel(color(black)("moles H"_2"O"))) * (2color(red)(cancel(color(black)("moles H"))))/(1color(red)(cancel(color(black)("mole H"_2"O")))) * "1.00794 g"/(1color(red)(cancel(color(black)("mole H")))) = "0.1320 g H"#</mathjax></p> </blockquote> <p>You know that vanillin contains carbon, hydrogen, and oxygen, so use the masses of carbon and hydrogen to calculate how many grams of oxygen were present in the original sample</p> <blockquote> <p><mathjax>#m_"vanillin" = m_"C" + m_"H" + m_"O"#</mathjax></p> <p><mathjax>#m_"O" = "2.500 g" - "1.5802 g" - "0.1320 g" = "0.7878 g O"#</mathjax></p> </blockquote> <p>Now, in order to find the compound's <strong>empirical formula</strong>, you must find the <em>smallest whole number ratio</em> that exists between carbon, hydrogen, and oxygen in vanillin. </p> <p>To do that, convert the masses to <em>moles</em> by using molar masses</p> <blockquote> <p><mathjax>#"For C: " 1.5802 color(red)(cancel(color(black)("g"))) * "1 mole C"/(12.011color(red)(cancel(color(black)("g")))) = "0.13156 moles C"#</mathjax></p> <p><mathjax>#"For H: " 0.1320 color(red)(cancel(color(black)("g"))) * "1 mole H"/(1.00794 color(red)(cancel(color(black)("g")))) = "0.1310 moles H"#</mathjax></p> <p><mathjax>#"For O: " 0.7878 color(red)(cancel(color(black)("g"))) * "1 mole O"/(15.9994 color(red)(cancel(color(black)("g")))) = "0.04924 moles O"#</mathjax></p> </blockquote> <p>To find the <strong>mole ratio</strong> that exists between the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a>, divide all values by the <em>smallest one</em> to find</p> <blockquote> <p><mathjax>#"For C: " (0.13156 color(red)(cancel(color(black)("moles"))))/(0.04924color(red)(cancel(color(black)("moles")))) = 2.67#</mathjax></p> <p><mathjax>#"For H: " (0.1310color(red)(cancel(color(black)("moles"))))/(0.04924color(red)(cancel(color(black)("moles")))) = 2.66#</mathjax></p> <p><mathjax>#"For O: " (0.04924color(red)(cancel(color(black)("moles"))))/(0.04924color(red)(cancel(color(black)("moles")))) = 1#</mathjax></p> </blockquote> <p>Now, you're looking for the <strong>smallest whole number ratio</strong> that exists between the three elements, so multiply all values by <mathjax>#3#</mathjax> to get</p> <blockquote> <p><mathjax>#"C"_ ((2.67 * 3)) "H"_ ((2.66 * 3)) "O"_ ((1 * 3)) implies color(green)(\|bar(ul(color(white)(a/a)color(black)("C"_ 8"H"_ 8"O"_3)color(white)(a/a)\|)))#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/293492" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? 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When a sample of vanillin weighting 2.500 g burns in pure oxygen, 5.79 g of #CO_2# and 1.18 g of water are obtained. How would you calculate the empirical formula of vanillin?	null
1,779	a96c719e-6ddd-11ea-a510-ccda262736ce	https://socratic.org/questions/how-would-you-balance-the-following-equation-aluminum-oxygen-gas-aluminum-oxide	4 Al + 3 O2 -> 2 Al2O3	start chemical_equation qc_end chemical_equation 7 13 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the equation"}]	[{"type":"chemical equation","value":"4 Al + 3 O2 -> 2 Al2O3"}]	[{"type":"chemical equation","value":"aluminum + oxygen gas -> aluminum oxide"}]	<h1 class="questionTitle" itemprop="name">How would you balance the following equation: aluminum + oxygen gas --> aluminum oxide?</h1>	null	4 Al + 3 O2 -> 2 Al2O3	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Al"#</mathjax> <mathjax>#+#</mathjax> <mathjax>#"O"_2rarr"Al"_2"O"_3#</mathjax></p> <p>This is the unbalanced equation described.</p> <p>Achieve a common <mathjax>#6#</mathjax> oxygen atoms on either side of the equation.</p> <p><mathjax>#"Al"#</mathjax> <mathjax>#+#</mathjax> <mathjax>#3"O"_2rarr2"Al"_2"O"_3#</mathjax></p> <p>Now, since there are <mathjax>#1#</mathjax> and <mathjax>#4#</mathjax> aluminum atoms on each side respectively, change the coefficient on the reactants side to <mathjax>#4#</mathjax>.</p> <p><strong>Balanced form:</strong></p> <p><mathjax>#4"Al"#</mathjax> <mathjax>#+#</mathjax> <mathjax>#3"O"_2rarr2"Al"_2"O"_3#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#4"Al"#</mathjax> <mathjax>#+#</mathjax> <mathjax>#3"O"_2rarr2"Al"_2"O"_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Al"#</mathjax> <mathjax>#+#</mathjax> <mathjax>#"O"_2rarr"Al"_2"O"_3#</mathjax></p> <p>This is the unbalanced equation described.</p> <p>Achieve a common <mathjax>#6#</mathjax> oxygen atoms on either side of the equation.</p> <p><mathjax>#"Al"#</mathjax> <mathjax>#+#</mathjax> <mathjax>#3"O"_2rarr2"Al"_2"O"_3#</mathjax></p> <p>Now, since there are <mathjax>#1#</mathjax> and <mathjax>#4#</mathjax> aluminum atoms on each side respectively, change the coefficient on the reactants side to <mathjax>#4#</mathjax>.</p> <p><strong>Balanced form:</strong></p> <p><mathjax>#4"Al"#</mathjax> <mathjax>#+#</mathjax> <mathjax>#3"O"_2rarr2"Al"_2"O"_3#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How would you balance the following equation: aluminum + oxygen gas --> aluminum oxide?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="200882" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/mason-m"><img alt="" class="" src="https://profilepictures.socratic.org/U70pu8hUTGGkEuy92fsO_IMG_2585.jpeg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/mason-m"> mason m </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-18T04:23:40" itemprop="dateCreated"> Dec 18, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#4"Al"#</mathjax> <mathjax>#+#</mathjax> <mathjax>#3"O"_2rarr2"Al"_2"O"_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Al"#</mathjax> <mathjax>#+#</mathjax> <mathjax>#"O"_2rarr"Al"_2"O"_3#</mathjax></p> <p>This is the unbalanced equation described.</p> <p>Achieve a common <mathjax>#6#</mathjax> oxygen atoms on either side of the equation.</p> <p><mathjax>#"Al"#</mathjax> <mathjax>#+#</mathjax> <mathjax>#3"O"_2rarr2"Al"_2"O"_3#</mathjax></p> <p>Now, since there are <mathjax>#1#</mathjax> and <mathjax>#4#</mathjax> aluminum atoms on each side respectively, change the coefficient on the reactants side to <mathjax>#4#</mathjax>.</p> <p><strong>Balanced form:</strong></p> <p><mathjax>#4"Al"#</mathjax> <mathjax>#+#</mathjax> <mathjax>#3"O"_2rarr2"Al"_2"O"_3#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/200882" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div 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1,780	ab050aa5-6ddd-11ea-a3b5-ccda262736ce	https://socratic.org/questions/what-is-the-the-volume-occupied-by-2-34-g-of-carbon-dioxide-gas-at-stp	1.18 L	start physical_unit 10 12 volume l qc_end physical_unit 10 12 7 8 mass qc_end c_other STP qc_end end	[{"type":"physical unit","value":"Volume [OF] carbon dioxide gas [IN] L"}]	[{"type":"physical unit","value":"1.18 L"}]	[{"type":"physical unit","value":"Mass [OF] carbon dioxide gas [=] \\pu{2.34 g}"},{"type":"other","value":"STP"}]	<h1 class="questionTitle" itemprop="name">What is the the volume occupied by 2.34 g of carbon dioxide gas at STP?</h1>	null	1.18 L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to solve this problem we would use the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a> formula <mathjax>#PV=nRT#</mathjax></p> <p><mathjax>#P =#</mathjax> Pressure in <mathjax>#atm#</mathjax><br/> <mathjax>#V=#</mathjax> Volume in <mathjax>#L#</mathjax><br/> <mathjax>#n=#</mathjax> moles<br/> <mathjax>#R=#</mathjax> Ideal Gas Law Constant <br/> <mathjax>#T=#</mathjax> Temp in <mathjax>#K#</mathjax></p> <p><mathjax>#STP#</mathjax> is Standard Temperature and Pressure which has values of <br/> <mathjax>#1 atm#</mathjax> and <mathjax>#273K#</mathjax></p> <p><mathjax>#2.34g CO_2#</mathjax> must be converted to moles</p> <p><mathjax>#2.34g CO_2 x (1mol)/(44gCO_2) = 0.053 mols#</mathjax></p> <p><mathjax>#P = 1atm#</mathjax><br/> <mathjax>#V= ??? L#</mathjax><br/> <mathjax>#n= 0.053 mols#</mathjax><br/> <mathjax>#R=0.0821 (atmL)/(molK)#</mathjax> <br/> <mathjax>#T=273K#</mathjax></p> <p><mathjax>#PV=nRT#</mathjax> becomes</p> <p><mathjax>#V = (nRT)/P#</mathjax></p> <p><mathjax>#V = (0.053cancel(mols)(0.0821 (cancel(atm)L)/(cancel(mol)cancel(K)))(273cancelK))/(1atm)#</mathjax></p> <p><mathjax>#V = 1.18 L#</mathjax></p> <p> <iframe src="https://www.youtube.com/embed/DlNjUYLZ_Aw?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#V = 1.18 L#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to solve this problem we would use the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a> formula <mathjax>#PV=nRT#</mathjax></p> <p><mathjax>#P =#</mathjax> Pressure in <mathjax>#atm#</mathjax><br/> <mathjax>#V=#</mathjax> Volume in <mathjax>#L#</mathjax><br/> <mathjax>#n=#</mathjax> moles<br/> <mathjax>#R=#</mathjax> Ideal Gas Law Constant <br/> <mathjax>#T=#</mathjax> Temp in <mathjax>#K#</mathjax></p> <p><mathjax>#STP#</mathjax> is Standard Temperature and Pressure which has values of <br/> <mathjax>#1 atm#</mathjax> and <mathjax>#273K#</mathjax></p> <p><mathjax>#2.34g CO_2#</mathjax> must be converted to moles</p> <p><mathjax>#2.34g CO_2 x (1mol)/(44gCO_2) = 0.053 mols#</mathjax></p> <p><mathjax>#P = 1atm#</mathjax><br/> <mathjax>#V= ??? L#</mathjax><br/> <mathjax>#n= 0.053 mols#</mathjax><br/> <mathjax>#R=0.0821 (atmL)/(molK)#</mathjax> <br/> <mathjax>#T=273K#</mathjax></p> <p><mathjax>#PV=nRT#</mathjax> becomes</p> <p><mathjax>#V = (nRT)/P#</mathjax></p> <p><mathjax>#V = (0.053cancel(mols)(0.0821 (cancel(atm)L)/(cancel(mol)cancel(K)))(273cancelK))/(1atm)#</mathjax></p> <p><mathjax>#V = 1.18 L#</mathjax></p> <p> <iframe src="https://www.youtube.com/embed/DlNjUYLZ_Aw?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the the volume occupied by 2.34 g of carbon dioxide gas at STP?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp" itemprop="url"> <span class="breadcrumb" itemprop="title">Molar Volume of a Gas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="262990" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/brian-m"><img alt="" class="" src="https://profilepictures.socratic.org/ZCpnJDgSFKORtvaSPDeG_Lego%20Me.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/brian-m"> BRIAN M. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-06T20:32:55" itemprop="dateCreated"> May 6, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#V = 1.18 L#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to solve this problem we would use the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a> formula <mathjax>#PV=nRT#</mathjax></p> <p><mathjax>#P =#</mathjax> Pressure in <mathjax>#atm#</mathjax><br/> <mathjax>#V=#</mathjax> Volume in <mathjax>#L#</mathjax><br/> <mathjax>#n=#</mathjax> moles<br/> <mathjax>#R=#</mathjax> Ideal Gas Law Constant <br/> <mathjax>#T=#</mathjax> Temp in <mathjax>#K#</mathjax></p> <p><mathjax>#STP#</mathjax> is Standard Temperature and Pressure which has values of <br/> <mathjax>#1 atm#</mathjax> and <mathjax>#273K#</mathjax></p> <p><mathjax>#2.34g CO_2#</mathjax> must be converted to moles</p> <p><mathjax>#2.34g CO_2 x (1mol)/(44gCO_2) = 0.053 mols#</mathjax></p> <p><mathjax>#P = 1atm#</mathjax><br/> <mathjax>#V= ??? L#</mathjax><br/> <mathjax>#n= 0.053 mols#</mathjax><br/> <mathjax>#R=0.0821 (atmL)/(molK)#</mathjax> <br/> <mathjax>#T=273K#</mathjax></p> <p><mathjax>#PV=nRT#</mathjax> becomes</p> <p><mathjax>#V = (nRT)/P#</mathjax></p> <p><mathjax>#V = (0.053cancel(mols)(0.0821 (cancel(atm)L)/(cancel(mol)cancel(K)))(273cancelK))/(1atm)#</mathjax></p> <p><mathjax>#V = 1.18 L#</mathjax></p> <p> <iframe src="https://www.youtube.com/embed/DlNjUYLZ_Aw?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/262990" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="263064" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/prim"><img alt="" class="" src="https://profilepictures.socratic.org/GAepgFbiSHKCiEE3ByEe_tumblr_n5wio1sTz91tummxoo1_250.gif" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/prim"> Madi </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-07T02:17:48" itemprop="dateCreated"> May 7, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1.18 L#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Alternative solution:</p> <p>Calculate how many moles <mathjax>#2.34g#</mathjax> <mathjax>#CO_2#</mathjax> is</p> <p><mathjax>#2.34g * (1mol)/(44g CO_2) = 0.053 mol#</mathjax></p> <p>Simple <a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratios</a> tell us that <mathjax>#1#</mathjax> mol of any gas at STP is <mathjax>#22.4L#</mathjax>, but since we only have <mathjax>#0.053 mol#</mathjax>, we times <mathjax>#22.4L/(mol)#</mathjax> by <mathjax>#0.053mol.#</mathjax></p> <p><mathjax>#(22.4L)/cancel(mol) * 0.053 cancel(mol) = 1.18L#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/263064" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-stoichiometric-ratios-relate-to-molar-volume-of-a-gas"> How do stoichiometric ratios relate to molar volume of a gas? 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1,781	aadcaa55-6ddd-11ea-bb56-ccda262736ce	https://socratic.org/questions/what-is-the-formula-for-calcium-sulfate	CaSO4	start chemical_formula qc_end substance 5 6 qc_end end	[{"type":"other","value":"Chemical Formula [OF] calcium sulfate [IN] default"}]	[{"type":"chemical equation","value":"CaSO4"}]	[{"type":"substance name","value":"Calcium sulfate"}]	<h1 class="questionTitle" itemprop="name">What is the formula for calcium sulfate?</h1>	null	CaSO4	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Calcium is a Group 2 metal; it tends to lose 2 electrons upon oxidation to form the <mathjax>#Ca^(2+)#</mathjax> ion. Sulfate ion has a formula of <mathjax>#SO_4^(2-)#</mathjax>. Formation of the binary salt, <mathjax>#CaSO_4#</mathjax>, is thus electrically and chemically reasonable.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#CaSO_4#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Calcium is a Group 2 metal; it tends to lose 2 electrons upon oxidation to form the <mathjax>#Ca^(2+)#</mathjax> ion. Sulfate ion has a formula of <mathjax>#SO_4^(2-)#</mathjax>. Formation of the binary salt, <mathjax>#CaSO_4#</mathjax>, is thus electrically and chemically reasonable.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the formula for calcium sulfate?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/determining-formula-and-molar-masses" itemprop="url"> <span class="breadcrumb" itemprop="title">Determining Formula</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="212273" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-14T07:10:56" itemprop="dateCreated"> Jan 14, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#CaSO_4#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Calcium is a Group 2 metal; it tends to lose 2 electrons upon oxidation to form the <mathjax>#Ca^(2+)#</mathjax> ion. Sulfate ion has a formula of <mathjax>#SO_4^(2-)#</mathjax>. Formation of the binary salt, <mathjax>#CaSO_4#</mathjax>, is thus electrically and chemically reasonable.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/212273" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-it-possible-to-find-a-molecular-formula-from-molar-mass"> Is it possible to find a molecular formula from molar mass? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5368e0cc02bf34779e175781"> Question #75781 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-common-mistakes-students-make-when-determining-formulas"> What are some common mistakes students make when determining formulas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-formula-of-an-acid"> How can I determine the formula of an acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-chemical-formula-of-a-product"> How can I determine the chemical formula of a product? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-empirical-formula-of-a-compound"> How can I determine the empirical formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-formula-of-a-hydrate"> How can I determine the formula of a hydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-the-empirical-formula-indicate"> What does the empirical formula indicate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-molecule-with-molecular-weight-of-180-18-g-mol-is-analyzed-and-found-to-contai"> A molecule with molecular weight of 180.18 g/mol is analyzed and found to contain 40.00% carbon,... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/do-i-need-to-know-the-number-of-moles-of-each-element-to-determine-the-formula-o"> Do I need to know the number of moles of each element to determine the formula of the compound? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/determining-formula-and-molar-masses"> See all questions in Determining Formula </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 13049 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the formula for calcium sulfate?	null
1,782	a8d5114c-6ddd-11ea-8799-ccda262736ce	https://socratic.org/questions/591974f3b72cff2f96fa595c	55 mol/L	start physical_unit 5 6 concentration mol/l qc_end physical_unit 5 6 8 9 temperature qc_end physical_unit 5 6 14 15 density qc_end end	[{"type":"physical unit","value":"Concentration [OF] pure water [IN] mol/L"}]	[{"type":"physical unit","value":"55 mol/L"}]	[{"type":"physical unit","value":"Temperature [OF] pure water [=] \\pu{298 K}"},{"type":"physical unit","value":"Density [OF] pure water [=] \\pu{1.00 g/mL}"}]	<h1 class="questionTitle" itemprop="name">What is the concentration of pure water at #298K# given a #"density"# of #1.00g*mL^-1#?</h1>	null	55 mol/L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a> is most commonly used as synonymous to "concentration", i.e. the number of moles of substance dissolved per litre of solution. However, it can also be used (albeit less commonly) to refer to the number of moles of pure substance per unit volume (of that substance). </p> <p>In the case of pure water, we can assume <a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a> to be <mathjax>#1.0 g.cm^-3#</mathjax>, so 1000 ml of water will be 1000 g. Molar mass of water is 18.015 g/mol, so 1000 g contains 1000/18.015 = 55.509 mol per litre.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Just over 55 mol per litre.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a> is most commonly used as synonymous to "concentration", i.e. the number of moles of substance dissolved per litre of solution. However, it can also be used (albeit less commonly) to refer to the number of moles of pure substance per unit volume (of that substance). </p> <p>In the case of pure water, we can assume <a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a> to be <mathjax>#1.0 g.cm^-3#</mathjax>, so 1000 ml of water will be 1000 g. Molar mass of water is 18.015 g/mol, so 1000 g contains 1000/18.015 = 55.509 mol per litre.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the concentration of pure water at #298K# given a #"density"# of #1.00g*mL^-1#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="423730" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/simon-moore"><img alt="" class="" src="https://profilepictures.socratic.org/0ztdJJ7RCWUlBSPeGa9N_6EB6CADA-35F5-4BAA-9B66-9D6F64A622BA.jpeg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/simon-moore"> Simon Moore </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-15T10:42:23" itemprop="dateCreated"> May 15, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Just over 55 mol per litre.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a> is most commonly used as synonymous to "concentration", i.e. the number of moles of substance dissolved per litre of solution. However, it can also be used (albeit less commonly) to refer to the number of moles of pure substance per unit volume (of that substance). </p> <p>In the case of pure water, we can assume <a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a> to be <mathjax>#1.0 g.cm^-3#</mathjax>, so 1000 ml of water will be 1000 g. Molar mass of water is 18.015 g/mol, so 1000 g contains 1000/18.015 = 55.509 mol per litre.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/423730" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-morality-be-used-as-a-conversion-factor"> How can molarity be used as a conversion factor? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-high-can-molarity-be"> How high can molarity be? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-molarity-change-with-temperature"> How does molarity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molarity-of-a-solution"> How do you find molarity of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-10-naoh"> What is the molarity of 10 NaOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-3-hydrogen-peroxide"> What is the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 4366 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the concentration of pure water at #298K# given a #"density"# of #1.00g*mL^-1#?	null
1,783	acb29727-6ddd-11ea-8e6b-ccda262736ce	https://socratic.org/questions/5928488cb72cff023b680837	8 NO2(g) + 4 H2O + ClO4- -> 8 NO3- + 8 H+ + Cl-	start chemical_equation qc_end substance 6 6 qc_end substance 8 8 qc_end chemical_equation 12 12 qc_end substance 14 15 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the reduction"}]	[{"type":"chemical equation","value":"8 NO2(g) + 4 H2O + ClO4- -> 8 NO3- + 8 H+ + Cl-"}]	[{"type":"substance name","value":"Perchlorate"},{"type":"substance name","value":"Chloride"},{"type":"chemical equation","value":"NO2"},{"type":"substance name","value":"Nitrate anion"}]	<h1 class="questionTitle" itemprop="name">Can you represent the reduction of perchlorate to chloride by oxidation of #NO_2# to nitrate anion?</h1>	null	8 NO2(g) + 4 H2O + ClO4- -> 8 NO3- + 8 H+ + Cl-	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#ClO_4^(-) + 8H^(+) + 8e^(-) rarr Cl^(-) + 4H_2O(l)#</mathjax> <mathjax>#(i)#</mathjax></p> <p>And <mathjax>#NO_2#</mathjax> is oxidized, <mathjax>#N(IV+)#</mathjax> to <mathjax>#N(V+)#</mathjax>:</p> <p><mathjax>#NO_2(g) +H_2O rarr NO_3^(-) +2H^(+) +e^-#</mathjax> <mathjax>#(ii)#</mathjax></p> <p>And so to eliminate the electrons, we take <mathjax>#(i) + 8xx(ii)#</mathjax>:</p> <p><mathjax>#8NO_2(g) +4H_2O+ClO_4^(-) rarr 8NO_3^(-) +8H^(+) + Cl^(-)#</mathjax></p> <p>Is this balanced with respect to mass and charge?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, <mathjax>#"perchlorate ion"#</mathjax> is reduced from <mathjax>#Cl(VII+)#</mathjax> to <mathjax>#Cl(-I)#</mathjax>....</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#ClO_4^(-) + 8H^(+) + 8e^(-) rarr Cl^(-) + 4H_2O(l)#</mathjax> <mathjax>#(i)#</mathjax></p> <p>And <mathjax>#NO_2#</mathjax> is oxidized, <mathjax>#N(IV+)#</mathjax> to <mathjax>#N(V+)#</mathjax>:</p> <p><mathjax>#NO_2(g) +H_2O rarr NO_3^(-) +2H^(+) +e^-#</mathjax> <mathjax>#(ii)#</mathjax></p> <p>And so to eliminate the electrons, we take <mathjax>#(i) + 8xx(ii)#</mathjax>:</p> <p><mathjax>#8NO_2(g) +4H_2O+ClO_4^(-) rarr 8NO_3^(-) +8H^(+) + Cl^(-)#</mathjax></p> <p>Is this balanced with respect to mass and charge?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Can you represent the reduction of perchlorate to chloride by oxidation of #NO_2# to nitrate anion?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="430081" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-26T15:42:22" itemprop="dateCreated"> May 26, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, <mathjax>#"perchlorate ion"#</mathjax> is reduced from <mathjax>#Cl(VII+)#</mathjax> to <mathjax>#Cl(-I)#</mathjax>....</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#ClO_4^(-) + 8H^(+) + 8e^(-) rarr Cl^(-) + 4H_2O(l)#</mathjax> <mathjax>#(i)#</mathjax></p> <p>And <mathjax>#NO_2#</mathjax> is oxidized, <mathjax>#N(IV+)#</mathjax> to <mathjax>#N(V+)#</mathjax>:</p> <p><mathjax>#NO_2(g) +H_2O rarr NO_3^(-) +2H^(+) +e^-#</mathjax> <mathjax>#(ii)#</mathjax></p> <p>And so to eliminate the electrons, we take <mathjax>#(i) + 8xx(ii)#</mathjax>:</p> <p><mathjax>#8NO_2(g) +4H_2O+ClO_4^(-) rarr 8NO_3^(-) +8H^(+) + Cl^(-)#</mathjax></p> <p>Is this balanced with respect to mass and charge?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/430081" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the 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Sodium phosphate and calcium chloride react to form... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-equation-kclo3-kcl-o2"> How can I balance this equation? ____ #KClO_3 -># ____ #KCl +# ____ #O_2# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-balancing-chemical-equations-important"> Why is balancing chemical equations important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/balancing-chemical-equations"> See all questions in Balancing Chemical Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1115 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Can you represent the reduction of perchlorate to chloride by oxidation of #NO_2# to nitrate anion?	null
1,784	ac385693-6ddd-11ea-9b13-ccda262736ce	https://socratic.org/questions/5644fd1111ef6b554cd38f02	1.0 M	start physical_unit 21 22 concentration mol/l qc_end physical_unit 9 10 6 7 mole qc_end physical_unit 15 16 6 7 mole qc_end end	[{"type":"physical unit","value":"Concentration [OF] the buffer [IN] M"}]	[{"type":"physical unit","value":"1.0 M"}]	[{"type":"physical unit","value":"Mole [OF] acetic acid [=] \\pu{1 mol}"},{"type":"physical unit","value":"Mole [OF] sodium acetate [=] \\pu{1 mol}"}]	<h1 class="questionTitle" itemprop="name">A buffer is prepared by mixing #1mol# of acetic acid with #1mol# of sodium acetate...what is the concentration of the buffer? </h1>	null	1.0 M	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>As you know, this is a buffer solution, whose <mathjax>#pH#</mathjax> would remain very close to the <mathjax>#pK_a#</mathjax> of acetic acid (which is from memory <mathjax>#4.76#</mathjax>). </p> <p><mathjax>#pH = pK_a + log_(10){[[OAc^-]]/[[HOAc]]}#</mathjax>. </p> <p><mathjax>#HOAc#</mathjax> <mathjax>#=#</mathjax> <mathjax>#H_3C-C(=O)OH#</mathjax></p> <p>As I said before, if you have taken equal volumes of <mathjax>#1.0#</mathjax> <mathjax>#mol*L^(-1)#</mathjax> acetic acid and sodium acetate, because you ADDED these volumes, (i.e doubled the volume), the concentration of each reagent is HALVED.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> is <mathjax>#1.0#</mathjax> <mathjax>#molL^(-1)#</mathjax> with respect to both acetic acid, and to sodium acetate. On the other hand, if you have mixed equal volumes of acetic acid and sodium acetate, then the concentration is <mathjax>#0.5#</mathjax> <mathjax>#mol^(-1)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>As you know, this is a buffer solution, whose <mathjax>#pH#</mathjax> would remain very close to the <mathjax>#pK_a#</mathjax> of acetic acid (which is from memory <mathjax>#4.76#</mathjax>). </p> <p><mathjax>#pH = pK_a + log_(10){[[OAc^-]]/[[HOAc]]}#</mathjax>. </p> <p><mathjax>#HOAc#</mathjax> <mathjax>#=#</mathjax> <mathjax>#H_3C-C(=O)OH#</mathjax></p> <p>As I said before, if you have taken equal volumes of <mathjax>#1.0#</mathjax> <mathjax>#molL^(-1)#</mathjax> acetic acid and sodium acetate, because you ADDED these volumes, (i.e doubled the volume), the concentration of each reagent is HALVED.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A buffer is prepared by mixing #1mol# of acetic acid with #1mol# of sodium acetate...what is the concentration of the buffer? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#reactions-in-solution" itemprop="url"> <span class="breadcrumb" itemprop="title">Reactions in Solution</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/reactions-in-solution/buffer-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">Buffer Calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="187609" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-12T22:02:17" itemprop="dateCreated"> Nov 12, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> is <mathjax>#1.0#</mathjax> <mathjax>#molL^(-1)#</mathjax> with respect to both acetic acid, and to sodium acetate. On the other hand, if you have mixed equal volumes of acetic acid and sodium acetate, then the concentration is <mathjax>#0.5#</mathjax> <mathjax>#mol^(-1)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>As you know, this is a buffer solution, whose <mathjax>#pH#</mathjax> would remain very close to the <mathjax>#pK_a#</mathjax> of acetic acid (which is from memory <mathjax>#4.76#</mathjax>). </p> <p><mathjax>#pH = pK_a + log_(10){[[OAc^-]]/[[HOAc]]}#</mathjax>. </p> <p><mathjax>#HOAc#</mathjax> <mathjax>#=#</mathjax> <mathjax>#H_3C-C(=O)OH#</mathjax></p> <p>As I said before, if you have taken equal volumes of <mathjax>#1.0#</mathjax> <mathjax>#molL^(-1)#</mathjax> acetic acid and sodium acetate, because you ADDED these volumes, (i.e doubled the volume), the concentration of each reagent is HALVED.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/187609" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-buffer-solutions-used"> How are buffer solutions used? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-buffer-capacity"> How do you calculate buffer capacity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-buffer-solutions-maintain-the-ph-of-blood"> How do buffer solutions maintain the pH of blood? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-buffer-a-solution-with-a-ph-of-12"> How do you buffer a solution with a pH of 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-buffer-solutions-used-to-calibrate-ph"> Why are buffer solutions used to calibrate pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is--solution-used-in-complexometric-titration"> What is the role of buffer solution in complexometric titrations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-you-would-make-100-0-ml-of-a-bu-er-solution-with-a-ph-of-10-80-to-be-made-us"> How you would make 100.0 ml of a 1.00 mol/L buffer solution with a pH of 10.80 to be made using... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-henderson-hasselbalch-equation"> What is the Henderson-Hasselbalch equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-an-example-of-a-ph-buffer-calculation-problem"> What is an example of a pH buffer calculation problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-bicarbonate-buffering-system-important"> Why is the bicarbonate buffering system important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/reactions-in-solution/buffer-calculations"> See all questions in Buffer Calculations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2453 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A buffer is prepared by mixing #1mol# of acetic acid with #1mol# of sodium acetate...what is the concentration of the buffer?	null
1,785	a9eb3f68-6ddd-11ea-a3cd-ccda262736ce	https://socratic.org/questions/58e4662ab72cff3b28643a84	-134.7 kJ/mol	start physical_unit 4 4 deltah^0 kj/mol qc_end chemical_equation 6 12 qc_end end	[{"type":"physical unit","value":"DeltaH^0 [OF] rxn [IN] kJ/mol"}]	[{"type":"physical unit","value":"-134.7 kJ/mol"}]	[{"type":"chemical equation","value":"NaOH(s) + HCl(g) -> NaCl(s) + H2O(l)"}]	<h1 class="questionTitle" itemprop="name">How can we find #DeltaH_"rxn"^@# for...? #NaOH(s) + HCl(g) rarr NaCl(s) + H_2O(l)#?</h1>	null	-134.7 kJ/mol	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>But, we can find <mathjax>#DeltaH_f^@#</mathjax> for the participating species on the <a href="https://en.wikipedia.org/wiki/Standard_enthalpy_of_formation" rel="nofollow">interwebz.....</a> :</p> <p><mathjax>#NaOH(s) + HCl(g) rarr NaCl(s) + H_2O(g)#</mathjax></p> <p>And the various <mathjax>#DeltaH_f^@#</mathjax> are taken from the given site.</p> <p><mathjax>#NaOH(s),#</mathjax> <mathjax>#DeltaH_f^@=-426.0kJmol^-1#</mathjax> </p> <p><mathjax>#NaCl(s),#</mathjax> <mathjax>#DeltaH_f^@=-411.2kJmol^-1#</mathjax> </p> <p><mathjax>#HCl(g),#</mathjax> <mathjax>#DeltaH_f^@=-92.3kJmol^-1#</mathjax> </p> <p><mathjax>#H_2O(g),#</mathjax> <mathjax>#DeltaH_f^@=-241.8kJmol^-1#</mathjax> </p> <p>Now <mathjax>#DeltaH_"rxn"^@=SigmaDeltaH_f^@"products"-SigmaDeltaH_f^@"reactants"#</mathjax></p> <p><mathjax>#{(-241.8-411.2)-(-426.0-92.3)}kJmol^-1=-134.7kJmol^-1#</mathjax></p> <p>If I were you, I would check on the <mathjax>#DeltaH_f^@#</mathjax> values. All care taken, but no responsibility admitted.......</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>You normally would quote INDIVIDUAL <mathjax>#DeltaH_f^@#</mathjax> for reactants and products. </p> <p>I get <mathjax>#DeltaH_"rxn"^@=-134.7kJmol^-1.#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>But, we can find <mathjax>#DeltaH_f^@#</mathjax> for the participating species on the <a href="https://en.wikipedia.org/wiki/Standard_enthalpy_of_formation" rel="nofollow">interwebz.....</a> :</p> <p><mathjax>#NaOH(s) + HCl(g) rarr NaCl(s) + H_2O(g)#</mathjax></p> <p>And the various <mathjax>#DeltaH_f^@#</mathjax> are taken from the given site.</p> <p><mathjax>#NaOH(s),#</mathjax> <mathjax>#DeltaH_f^@=-426.0kJmol^-1#</mathjax> </p> <p><mathjax>#NaCl(s),#</mathjax> <mathjax>#DeltaH_f^@=-411.2kJmol^-1#</mathjax> </p> <p><mathjax>#HCl(g),#</mathjax> <mathjax>#DeltaH_f^@=-92.3kJmol^-1#</mathjax> </p> <p><mathjax>#H_2O(g),#</mathjax> <mathjax>#DeltaH_f^@=-241.8kJmol^-1#</mathjax> </p> <p>Now <mathjax>#DeltaH_"rxn"^@=SigmaDeltaH_f^@"products"-SigmaDeltaH_f^@"reactants"#</mathjax></p> <p><mathjax>#{(-241.8-411.2)-(-426.0-92.3)}kJmol^-1=-134.7kJmol^-1#</mathjax></p> <p>If I were you, I would check on the <mathjax>#DeltaH_f^@#</mathjax> values. All care taken, but no responsibility admitted.......</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How can we find #DeltaH_"rxn"^@# for...? #NaOH(s) + HCl(g) rarr NaCl(s) + H_2O(l)#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/enthalpy" itemprop="url"> <span class="breadcrumb" itemprop="title">Enthalpy</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="404133" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-09T16:51:57" itemprop="dateCreated"> Apr 9, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>You normally would quote INDIVIDUAL <mathjax>#DeltaH_f^@#</mathjax> for reactants and products. </p> <p>I get <mathjax>#DeltaH_"rxn"^@=-134.7kJmol^-1.#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>But, we can find <mathjax>#DeltaH_f^@#</mathjax> for the participating species on the <a href="https://en.wikipedia.org/wiki/Standard_enthalpy_of_formation" rel="nofollow">interwebz.....</a> :</p> <p><mathjax>#NaOH(s) + HCl(g) rarr NaCl(s) + H_2O(g)#</mathjax></p> <p>And the various <mathjax>#DeltaH_f^@#</mathjax> are taken from the given site.</p> <p><mathjax>#NaOH(s),#</mathjax> <mathjax>#DeltaH_f^@=-426.0kJmol^-1#</mathjax> </p> <p><mathjax>#NaCl(s),#</mathjax> <mathjax>#DeltaH_f^@=-411.2kJmol^-1#</mathjax> </p> <p><mathjax>#HCl(g),#</mathjax> <mathjax>#DeltaH_f^@=-92.3kJmol^-1#</mathjax> </p> <p><mathjax>#H_2O(g),#</mathjax> <mathjax>#DeltaH_f^@=-241.8kJmol^-1#</mathjax> </p> <p>Now <mathjax>#DeltaH_"rxn"^@=SigmaDeltaH_f^@"products"-SigmaDeltaH_f^@"reactants"#</mathjax></p> <p><mathjax>#{(-241.8-411.2)-(-426.0-92.3)}kJmol^-1=-134.7kJmol^-1#</mathjax></p> <p>If I were you, I would check on the <mathjax>#DeltaH_f^@#</mathjax> values. All care taken, but no responsibility admitted.......</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/404133" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-enthalpy-changes-expressed-in-chemical-equations"> How are enthalpy changes expressed in chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-enthalpy-change-be-determined-for-an-aqueous-solution"> How can enthalpy change be determined for an aqueous solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-enthalpy-change-with-pressure"> How does enthalpy change with pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-standard-molar-enthalpy-formation"> How do you calculate standard molar enthalpy of formation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-enthalpy-a-state-function"> Why is enthalpy a state function? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-enthalpy-of-formation-of-oxygen-zero"> Why is the enthalpy of formation of oxygen zero? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-enthalpy-a-state-function-2"> Why is enthalpy a state function? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-enthalpy-cannot-be-measured-directly"> Why can enthalpy not be measured directly? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-pressure-affect-enthalpy"> How does pressure affect enthalpy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-enthalpy-relate-to-internal-energy"> How does enthalpy relate to internal energy? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/enthalpy"> See all questions in Enthalpy </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2629 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How can we find #DeltaH_"rxn"^@# for...? #NaOH(s) + HCl(g) rarr NaCl(s) + H_2O(l)#?	null
1,786	ac9049b0-6ddd-11ea-b2cd-ccda262736ce	https://socratic.org/questions/how-do-you-calculate-the-heat-capacity-of-a-piece-of-wood-if-1500-0-g-of-the-woo	1.8 J/(g * ℃)	start physical_unit 10 12 specific_heat_capacity j/(°c_·_g) qc_end physical_unit 17 18 14 15 mass qc_end physical_unit 17 18 20 23 heat_energy qc_end physical_unit 17 18 31 32 temperature qc_end physical_unit 17 18 34 35 temperature qc_end end	[{"type":"physical unit","value":"Specific heat capacity [OF] the piece of wood [IN] J/(g * ℃)"}]	[{"type":"physical unit","value":"1.8 J/(g * ℃)"}]	[{"type":"physical unit","value":"Mass [OF] the wood [=] \\pu{1500.0 g}"},{"type":"physical unit","value":"Absorbed heat [OF] the wood [=] \\pu{6.75 × 10^4 joules}"},{"type":"physical unit","value":"Temperature1 [OF] the wood [=] \\pu{32 ℃}"},{"type":"physical unit","value":"Temperature2 [OF] the wood [=] \\pu{57 ℃}"}]	<h1 class="questionTitle" itemprop="name">How do you calculate the specific heat capacity of a piece of wood if 1500.0 g of the wood absorbs #6.75 * 10^4# joules of heat, and its temperature changes from 32°C to 57°C?</h1>	null	1.8 J/(g * ℃)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>A substance's <strong><a href="http://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a></strong> tells you how much heat much either be <em>added</em> or <em>removed</em> from <mathjax>#"1 g"#</mathjax> of that substance in order to cause a <mathjax>#1^@"C"#</mathjax> <strong>change in temperature</strong>. </p> <p>The equation that establishes a relationship between <a href="http://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a>, heat added or removed, and change in temperature looks like this </p> <blockquote> <p><mathjax>#color(blue)(q = m * c * DeltaT)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#q#</mathjax> - the amount of heat added / removed<br/> <mathjax>#m#</mathjax> - the mass of the sample<br/> <mathjax>#c#</mathjax> - the specific heat of the substance<br/> <mathjax>#DeltaT#</mathjax> - the <em>change in temperature</em></p> <p>In your case, the <mathjax>#"1500.0-g"#</mathjax> piece of wood is said to <strong>absorb</strong> a total of <mathjax>#6.75 * 10^4"J"#</mathjax> of heat. This caused its temperature to <em>increase</em> from <mathjax>#32^@"C"#</mathjax> to <mathjax>#57^@"C"#</mathjax>.</p> <p>The difference between the final temperature and the initial temperature of the sample will be the value for <mathjax>#DeltaT#</mathjax>. </p> <blockquote> <p><mathjax>#DeltaT = 57^@"C" - 32^@"C" = 25^@"C"#</mathjax></p> </blockquote> <p>This means that the specific heat of the wood is equal to </p> <blockquote> <p><mathjax>#q = m * c * DeltaT implies c = q/(m * DeltaT)#</mathjax></p> </blockquote> <p>Plug in your values to get</p> <blockquote> <p><mathjax>#c = (6.75 * 10^4"J")/("1500.0 g" * 25^@"C") = color(green)(1.8"J"/("g" ""^@"C"))#</mathjax></p> </blockquote> <p>The answer is rounded to two <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the number of sig figs you have for the two temperatures of the sample. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1.8"J"/("g" ""^@"C")#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>A substance's <strong><a href="http://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a></strong> tells you how much heat much either be <em>added</em> or <em>removed</em> from <mathjax>#"1 g"#</mathjax> of that substance in order to cause a <mathjax>#1^@"C"#</mathjax> <strong>change in temperature</strong>. </p> <p>The equation that establishes a relationship between <a href="http://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a>, heat added or removed, and change in temperature looks like this </p> <blockquote> <p><mathjax>#color(blue)(q = m * c * DeltaT)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#q#</mathjax> - the amount of heat added / removed<br/> <mathjax>#m#</mathjax> - the mass of the sample<br/> <mathjax>#c#</mathjax> - the specific heat of the substance<br/> <mathjax>#DeltaT#</mathjax> - the <em>change in temperature</em></p> <p>In your case, the <mathjax>#"1500.0-g"#</mathjax> piece of wood is said to <strong>absorb</strong> a total of <mathjax>#6.75 * 10^4"J"#</mathjax> of heat. This caused its temperature to <em>increase</em> from <mathjax>#32^@"C"#</mathjax> to <mathjax>#57^@"C"#</mathjax>.</p> <p>The difference between the final temperature and the initial temperature of the sample will be the value for <mathjax>#DeltaT#</mathjax>. </p> <blockquote> <p><mathjax>#DeltaT = 57^@"C" - 32^@"C" = 25^@"C"#</mathjax></p> </blockquote> <p>This means that the specific heat of the wood is equal to </p> <blockquote> <p><mathjax>#q = m * c * DeltaT implies c = q/(m * DeltaT)#</mathjax></p> </blockquote> <p>Plug in your values to get</p> <blockquote> <p><mathjax>#c = (6.75 * 10^4"J")/("1500.0 g" * 25^@"C") = color(green)(1.8"J"/("g" ""^@"C"))#</mathjax></p> </blockquote> <p>The answer is rounded to two <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the number of sig figs you have for the two temperatures of the sample. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you calculate the specific heat capacity of a piece of wood if 1500.0 g of the wood absorbs #6.75 * 10^4# joules of heat, and its temperature changes from 32°C to 57°C?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/specific-heat" itemprop="url"> <span class="breadcrumb" itemprop="title">Specific Heat</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="218729" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-29T09:52:07" itemprop="dateCreated"> Jan 29, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1.8"J"/("g" ""^@"C")#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>A substance's <strong><a href="http://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a></strong> tells you how much heat much either be <em>added</em> or <em>removed</em> from <mathjax>#"1 g"#</mathjax> of that substance in order to cause a <mathjax>#1^@"C"#</mathjax> <strong>change in temperature</strong>. </p> <p>The equation that establishes a relationship between <a href="http://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a>, heat added or removed, and change in temperature looks like this </p> <blockquote> <p><mathjax>#color(blue)(q = m * c * DeltaT)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#q#</mathjax> - the amount of heat added / removed<br/> <mathjax>#m#</mathjax> - the mass of the sample<br/> <mathjax>#c#</mathjax> - the specific heat of the substance<br/> <mathjax>#DeltaT#</mathjax> - the <em>change in temperature</em></p> <p>In your case, the <mathjax>#"1500.0-g"#</mathjax> piece of wood is said to <strong>absorb</strong> a total of <mathjax>#6.75 * 10^4"J"#</mathjax> of heat. This caused its temperature to <em>increase</em> from <mathjax>#32^@"C"#</mathjax> to <mathjax>#57^@"C"#</mathjax>.</p> <p>The difference between the final temperature and the initial temperature of the sample will be the value for <mathjax>#DeltaT#</mathjax>. </p> <blockquote> <p><mathjax>#DeltaT = 57^@"C" - 32^@"C" = 25^@"C"#</mathjax></p> </blockquote> <p>This means that the specific heat of the wood is equal to </p> <blockquote> <p><mathjax>#q = m * c * DeltaT implies c = q/(m * DeltaT)#</mathjax></p> </blockquote> <p>Plug in your values to get</p> <blockquote> <p><mathjax>#c = (6.75 * 10^4"J")/("1500.0 g" * 25^@"C") = color(green)(1.8"J"/("g" ""^@"C"))#</mathjax></p> </blockquote> <p>The answer is rounded to two <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the number of sig figs you have for the two temperatures of the sample. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/218729" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-specific-heat-be-used-to-identify-substances"> How can specific heat be used to identify substances? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-heat-capacity-of-a-lead-sinker-be-determined"> How can the heat capacity of a lead sinker be determined? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-the-specific-heats-of-metals-compare-with-water"> How do the specific heats of metals compare with water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-specific-heat-change-with-temperature"> How does specific heat change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/dissolving-some-potassium-bromide-in-200cm3-of-water-leads-to-a-decrease-in-temp"> Dissolving some potassium bromide in 200cm3 of water leads to a decrease in temperature of 3oC.... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-heat-capacity-larger-for-polymers"> Is heat capacity larger for polymers? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-heat-capacity-an-extensive-property"> Why is heat capacity an extensive property? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-does-heat-capacity-change-with-temperature"> Why does heat capacity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-specific-heat-measured-in"> What is specific heat measured in? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-heat-capacity-measured-in"> What is heat capacity measured in? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/specific-heat"> See all questions in Specific Heat </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 20225 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How do you calculate the specific heat capacity of a piece of wood if 1500.0 g of the wood absorbs #6.75 * 10^4# joules of heat, and its temperature changes from 32°C to 57°C?	null
1,787	ac09a6ff-6ddd-11ea-81cf-ccda262736ce	https://socratic.org/questions/how-do-you-find-the-maximum-mass-of-aluminium-that-can-react-with-0-5-moles-of-h	4.5 g	start physical_unit 8 8 mass g qc_end physical_unit 16 16 13 14 mole qc_end chemical_equation 17 27 qc_end end	[{"type":"physical unit","value":"Mass [OF] aluminium [IN] g"}]	[{"type":"physical unit","value":"4.5 g"}]	[{"type":"physical unit","value":"Mole [OF] HCI [=] \\pu{0.5 moles}"},{"type":"chemical equation","value":"2 Al + 6 HCI -> 2 Al2Cl3 + 3 H2"}]	<h1 class="questionTitle" itemprop="name">How do you find the maximum mass of aluminium that can react with 0.5 moles of HCI? 2Al + 6HCI - > 2Al2Cl3 + 3H2</h1>	null	4.5 g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>Step 1. Start with the balanced equation.</strong></p> <p>The balanced equation is</p> <p><mathjax>#M_text(r):color(white)(m) 26.98#</mathjax><br/> <mathjax>#color(white)(mmmll)"2Al" + "6HCl" → "2AlCl"_3 + "3H"_2#</mathjax></p> <blockquote></blockquote> <p><strong>Step 2. Calculate the moles of <mathjax>#"Al"#</mathjax></strong>.</p> <p><mathjax>#"Moles of Al" = 0.5 color(red)(cancel(color(black)("mol HCl"))) × ("2 mol Al")/(6 color(red)(cancel(color(black)("mol Al")))) = "0.17 mol Al"#</mathjax></p> <blockquote></blockquote> <p><strong>3. Calculate the mass of <mathjax>#"Al"#</mathjax></strong>.</p> <p><mathjax>#"Mass of Al" = 0.17 color(red)(cancel(color(black)("molAl"))) × "26.98 g Al"/(1 color(red)(cancel(color(black)("mol Al")))) = "4.5 g Al"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The mass of aluminium will be 4.5 g.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>Step 1. Start with the balanced equation.</strong></p> <p>The balanced equation is</p> <p><mathjax>#M_text(r):color(white)(m) 26.98#</mathjax><br/> <mathjax>#color(white)(mmmll)"2Al" + "6HCl" → "2AlCl"_3 + "3H"_2#</mathjax></p> <blockquote></blockquote> <p><strong>Step 2. Calculate the moles of <mathjax>#"Al"#</mathjax></strong>.</p> <p><mathjax>#"Moles of Al" = 0.5 color(red)(cancel(color(black)("mol HCl"))) × ("2 mol Al")/(6 color(red)(cancel(color(black)("mol Al")))) = "0.17 mol Al"#</mathjax></p> <blockquote></blockquote> <p><strong>3. Calculate the mass of <mathjax>#"Al"#</mathjax></strong>.</p> <p><mathjax>#"Mass of Al" = 0.17 color(red)(cancel(color(black)("molAl"))) × "26.98 g Al"/(1 color(red)(cancel(color(black)("mol Al")))) = "4.5 g Al"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you find the maximum mass of aluminium that can react with 0.5 moles of HCI? 2Al + 6HCI - > 2Al2Cl3 + 3H2</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="422718" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-13T15:34:28" itemprop="dateCreated"> May 13, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The mass of aluminium will be 4.5 g.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>Step 1. Start with the balanced equation.</strong></p> <p>The balanced equation is</p> <p><mathjax>#M_text(r):color(white)(m) 26.98#</mathjax><br/> <mathjax>#color(white)(mmmll)"2Al" + "6HCl" → "2AlCl"_3 + "3H"_2#</mathjax></p> <blockquote></blockquote> <p><strong>Step 2. Calculate the moles of <mathjax>#"Al"#</mathjax></strong>.</p> <p><mathjax>#"Moles of Al" = 0.5 color(red)(cancel(color(black)("mol HCl"))) × ("2 mol Al")/(6 color(red)(cancel(color(black)("mol Al")))) = "0.17 mol Al"#</mathjax></p> <blockquote></blockquote> <p><strong>3. Calculate the mass of <mathjax>#"Al"#</mathjax></strong>.</p> <p><mathjax>#"Mass of Al" = 0.17 color(red)(cancel(color(black)("molAl"))) × "26.98 g Al"/(1 color(red)(cancel(color(black)("mol Al")))) = "4.5 g Al"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/422718" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What is stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ab82402bf342f48d93ac6"> Question #93ac6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-we-study-stoichiometry"> Why do we study stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-naoh-is-produced-from-1-20-x-102-grams-of-na2o-na2o-h2o-2-naoh"> How many grams of NaOH is produced from #1.20 x 10^2# grams of #Na_2O#? #Na_2O + H_2O -> 2NaOH# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-na2o-are-required-to-produce-1-60-x-102-grams-of-naoh-na2o-h2o"> How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? 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1,788	abb1db81-6ddd-11ea-8020-ccda262736ce	https://socratic.org/questions/how-many-moles-are-in-550-0-g-of-lead-v-sulfate	1.81 moles	start physical_unit 8 9 mole mol qc_end physical_unit 8 9 5 6 mass qc_end end	[{"type":"physical unit","value":"Mole [OF] lead(II) sulfate [IN] moles"}]	[{"type":"physical unit","value":"1.81 moles"}]	[{"type":"physical unit","value":"Mass [OF] lead(II) sulfate [=] \\pu{550.0 g}"}]	<h1 class="questionTitle" itemprop="name">How many moles are in 550.0 g of lead(II) sulfate? </h1>	null	1.81 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You can go from <em>moles</em> of a given substance to <em>grams</em> or vice versa by using the <strong>molar mass</strong> of said substance. </p> <p>The <strong>molar mass</strong> tells you the mass of <mathjax>#1#</mathjax> <strong>mole</strong> of a given substance</p> <blockquote> <p><mathjax>#"molar mass" = "mass in grams"/"1 mole of substance"#</mathjax></p> </blockquote> <p>In your case, lead(II) sulfate, <mathjax>#"PbSO"_4#</mathjax>, has a molar mass of <mathjax>#"303.2626 g mol"^(-1)#</mathjax>, which means that <strong>every mole</strong> of lead(II) sulfate has a mass of <mathjax>#"303.2626 g"#</mathjax>. </p> <p>To convert from <em>grams</em> to <em>moles</em>, set up the molar mass as a conversion factor with the mass of <mathjax>#1#</mathjax> <strong>mole</strong> as the <strong>denominator</strong></p> <blockquote> <p><mathjax>#"1 mole PbSO"_4/"303.2626 g"#</mathjax></p> </blockquote> <p>You will have</p> <blockquote> <p><mathjax>#550.0 color(red)(cancel(color(black)("g"))) * "1 mole PbSO"_4/(303.2626color(red)(cancel(color(black)("g")))) = color(darkgreen)(ul(color(black)("1.814 moles PbSO"_4)))#</mathjax></p> </blockquote> <p>The answer is rounded to four <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"1.814 moles PbSO"_4#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You can go from <em>moles</em> of a given substance to <em>grams</em> or vice versa by using the <strong>molar mass</strong> of said substance. </p> <p>The <strong>molar mass</strong> tells you the mass of <mathjax>#1#</mathjax> <strong>mole</strong> of a given substance</p> <blockquote> <p><mathjax>#"molar mass" = "mass in grams"/"1 mole of substance"#</mathjax></p> </blockquote> <p>In your case, lead(II) sulfate, <mathjax>#"PbSO"_4#</mathjax>, has a molar mass of <mathjax>#"303.2626 g mol"^(-1)#</mathjax>, which means that <strong>every mole</strong> of lead(II) sulfate has a mass of <mathjax>#"303.2626 g"#</mathjax>. </p> <p>To convert from <em>grams</em> to <em>moles</em>, set up the molar mass as a conversion factor with the mass of <mathjax>#1#</mathjax> <strong>mole</strong> as the <strong>denominator</strong></p> <blockquote> <p><mathjax>#"1 mole PbSO"_4/"303.2626 g"#</mathjax></p> </blockquote> <p>You will have</p> <blockquote> <p><mathjax>#550.0 color(red)(cancel(color(black)("g"))) * "1 mole PbSO"_4/(303.2626color(red)(cancel(color(black)("g")))) = color(darkgreen)(ul(color(black)("1.814 moles PbSO"_4)))#</mathjax></p> </blockquote> <p>The answer is rounded to four <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles are in 550.0 g of lead(II) sulfate? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="387135" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-06T00:02:16" itemprop="dateCreated"> Mar 6, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"1.814 moles PbSO"_4#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You can go from <em>moles</em> of a given substance to <em>grams</em> or vice versa by using the <strong>molar mass</strong> of said substance. </p> <p>The <strong>molar mass</strong> tells you the mass of <mathjax>#1#</mathjax> <strong>mole</strong> of a given substance</p> <blockquote> <p><mathjax>#"molar mass" = "mass in grams"/"1 mole of substance"#</mathjax></p> </blockquote> <p>In your case, lead(II) sulfate, <mathjax>#"PbSO"_4#</mathjax>, has a molar mass of <mathjax>#"303.2626 g mol"^(-1)#</mathjax>, which means that <strong>every mole</strong> of lead(II) sulfate has a mass of <mathjax>#"303.2626 g"#</mathjax>. </p> <p>To convert from <em>grams</em> to <em>moles</em>, set up the molar mass as a conversion factor with the mass of <mathjax>#1#</mathjax> <strong>mole</strong> as the <strong>denominator</strong></p> <blockquote> <p><mathjax>#"1 mole PbSO"_4/"303.2626 g"#</mathjax></p> </blockquote> <p>You will have</p> <blockquote> <p><mathjax>#550.0 color(red)(cancel(color(black)("g"))) * "1 mole PbSO"_4/(303.2626color(red)(cancel(color(black)("g")))) = color(darkgreen)(ul(color(black)("1.814 moles PbSO"_4)))#</mathjax></p> </blockquote> <p>The answer is rounded to four <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/387135" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? 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1,789	a9e089dd-6ddd-11ea-b3fa-ccda262736ce	https://socratic.org/questions/what-is-the-molarity-of-50-mol-of-mgcl-2-in-1-5-l-of-solution	0.33 M	start physical_unit 8 8 molarity mol/l qc_end physical_unit 13 13 10 11 volume qc_end physical_unit 8 8 5 6 mole qc_end end	[{"type":"physical unit","value":"Molarity [OF] MgCl2 solution [IN] M"}]	[{"type":"physical unit","value":"0.33 M"}]	[{"type":"physical unit","value":"Volume [OF] MgCl2 solution [=] \\pu{1.5 L}"},{"type":"physical unit","value":"Mole [OF] MgCl2 [=] \\pu{0.50 mol}"}]	<h1 class="questionTitle" itemprop="name">What is the molarity of .50 mol of #MgCl_2# in 1.5 L of solution?</h1>	null	0.33 M	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a> is just moles per liter.</p> <p><mathjax>#M = "moles"/"liters"#</mathjax></p> <p>You have 0.50 mol in 1.5 L.</p> <p><mathjax>#M = "0.50 mol"/"1.5 L"#</mathjax></p> <p><mathjax>#M = 0.33color(white)(l) M#</mathjax></p> <p>For more information on moles and molarity check out this <a href="http://maths4biosciences.com/blog/concentrations/molarity-formula/" rel="nofollow">blog post</a>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.33 M</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a> is just moles per liter.</p> <p><mathjax>#M = "moles"/"liters"#</mathjax></p> <p>You have 0.50 mol in 1.5 L.</p> <p><mathjax>#M = "0.50 mol"/"1.5 L"#</mathjax></p> <p><mathjax>#M = 0.33color(white)(l) M#</mathjax></p> <p>For more information on moles and molarity check out this <a href="http://maths4biosciences.com/blog/concentrations/molarity-formula/" rel="nofollow">blog post</a>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the molarity of .50 mol of #MgCl_2# in 1.5 L of solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="299949" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/nick-41"><img alt="" class="" src="https://profilepictures.socratic.org/Sq1QmKQKSPCfDM110rRn_16.jpg" title=""/></a> <a class="secondContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/nick-41"> Nick </a>·<a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-08-17T18:35:14" itemprop="dateCreated"> Aug 17, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.33 M</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a> is just moles per liter.</p> <p><mathjax>#M = "moles"/"liters"#</mathjax></p> <p>You have 0.50 mol in 1.5 L.</p> <p><mathjax>#M = "0.50 mol"/"1.5 L"#</mathjax></p> <p><mathjax>#M = 0.33color(white)(l) M#</mathjax></p> <p>For more information on moles and molarity check out this <a href="http://maths4biosciences.com/blog/concentrations/molarity-formula/" rel="nofollow">blog post</a>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/299949" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div 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</div> </div> </article>	What is the molarity of .50 mol of #MgCl_2# in 1.5 L of solution?	null
1,790	abcc2c4d-6ddd-11ea-8b40-ccda262736ce	https://socratic.org/questions/if-you-wish-to-warm-100-kg-of-water-by-20-degrees-c-for-your-bath-how-much-heat-	8.37 × 10^6 J	start physical_unit 8 8 heat_energy j qc_end physical_unit 8 8 5 6 mass qc_end physical_unit 8 8 10 12 temperature qc_end end	[{"type":"physical unit","value":"Required heat [OF] water [IN] J"}]	[{"type":"physical unit","value":"8.37 × 10^6 J"}]	[{"type":"physical unit","value":"Mass [OF] water [=] \\pu{100 kg}"},{"type":"physical unit","value":"Raised temperature [OF] water [=] \\pu{20 degrees C}"}]	<h1 class="questionTitle" itemprop="name">If you wish to warm 100 kg of water by 20 degrees C for your bath how much heat is required?</h1>	null	8.37 × 10^6 J	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The heat capacity of water is 1 calorie for 1 gram raised 1 degree C<br/> or 4.186 joules of energy for 1 gram raised 1 degree C ( or <mathjax>#K^o#</mathjax>)</p> <p>l Kg = 1000 grams so </p> <p><mathjax># 100 Kg xx 1000 g /1 #</mathjax> = 100000 grams of water. </p> <p>It takes 10 000 calories to raise 10 000 grams of water 1 degree</p> <p>so 20 degrees x 10 000 grams = 2 000 000 calories. </p> <p>The same type calculations can be done for heat in joules </p> <p>10, 000 grams x 4.186 joules x 20 degrees. = 8372000 joules.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>2000000 heat calories. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The heat capacity of water is 1 calorie for 1 gram raised 1 degree C<br/> or 4.186 joules of energy for 1 gram raised 1 degree C ( or <mathjax>#K^o#</mathjax>)</p> <p>l Kg = 1000 grams so </p> <p><mathjax># 100 Kg xx 1000 g /1 #</mathjax> = 100000 grams of water. </p> <p>It takes 10 000 calories to raise 10 000 grams of water 1 degree</p> <p>so 20 degrees x 10 000 grams = 2 000 000 calories. </p> <p>The same type calculations can be done for heat in joules </p> <p>10, 000 grams x 4.186 joules x 20 degrees. = 8372000 joules.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">If you wish to warm 100 kg of water by 20 degrees C for your bath how much heat is required?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/specific-heat" itemprop="url"> <span class="breadcrumb" itemprop="title">Specific Heat</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="303924" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/david-drayer"><img alt="" class="" src="https://graph.facebook.com/10206723679871989/picture?height=50&width=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/david-drayer"> David Drayer </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-08-29T22:57:10" itemprop="dateCreated"> Aug 29, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>2000000 heat calories. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The heat capacity of water is 1 calorie for 1 gram raised 1 degree C<br/> or 4.186 joules of energy for 1 gram raised 1 degree C ( or <mathjax>#K^o#</mathjax>)</p> <p>l Kg = 1000 grams so </p> <p><mathjax># 100 Kg xx 1000 g /1 #</mathjax> = 100000 grams of water. </p> <p>It takes 10 000 calories to raise 10 000 grams of water 1 degree</p> <p>so 20 degrees x 10 000 grams = 2 000 000 calories. </p> <p>The same type calculations can be done for heat in joules </p> <p>10, 000 grams x 4.186 joules x 20 degrees. = 8372000 joules.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/303924" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="306016" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-09-04T14:11:31" itemprop="dateCreated"> Sep 4, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The heat required is 8.4 MJ.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The energy required to heat an object is given by the formula</p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a) q = mcΔTcolor(white)(a/a)\|)))" "#</mathjax></p> </blockquote> <p>where</p> <p><mathjax>#q#</mathjax> is the energy required<br/> <mathjax>#m#</mathjax> is the mass<br/> <mathjax>#c#</mathjax> is the <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> capacity<br/> <mathjax>#ΔT#</mathjax> is the change in temperature</p> <blockquote></blockquote> <p>In your problem,</p> <p><mathjax>#m = "100 kg" = "100 000 g"#</mathjax><br/> <mathjax>#c = "4.179 J·°C"^"-1"·"g"^"-1"#</mathjax><br/> <mathjax>#ΔT = "20 °C"#</mathjax></p> <p>∴ <mathjax>#q = "100 000" color(red)(cancel(color(black)("g"))) × "4.179 J"·color(red)(cancel(color(black)("°C"^"-1"·"g"^"-1"))) × 20 color(red)(cancel(color(black)("°C"))) = 8.4 ×10^6color(white)(l) "J" = "8.4 MJ"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/306016" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-specific-heat-be-used-to-identify-substances"> How can specific heat be used to identify substances? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-heat-capacity-of-a-lead-sinker-be-determined"> How can the heat capacity of a lead sinker be determined? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-the-specific-heats-of-metals-compare-with-water"> How do the specific 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class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	If you wish to warm 100 kg of water by 20 degrees C for your bath how much heat is required?	null
1,791	a9bcd0e8-6ddd-11ea-ad0f-ccda262736ce	https://socratic.org/questions/how-many-grams-of-silver-are-needed-to-absorb-1-00-kj-of-energy-changing-the-tem	484 grams	start physical_unit 4 4 mass g qc_end physical_unit 4 4 9 10 heat_energy qc_end physical_unit 4 4 17 18 temperature qc_end physical_unit 4 4 20 21 temperature qc_end end	[{"type":"physical unit","value":"Mass [OF] silver [IN] grams"}]	[{"type":"physical unit","value":"484 grams"}]	[{"type":"physical unit","value":"Absorbed energy [OF] silver [=] \\pu{1.00 kJ}"},{"type":"physical unit","value":"Temperature1 [OF] silver [=] \\pu{33.0 ℃}"},{"type":"physical unit","value":"Temperature2 [OF] silver [=] \\pu{41.8 ℃}"}]	<h1 class="questionTitle" itemprop="name">How many grams of silver are needed to absorb 1.00 kJ of energy changing the temperature from 33.0°C to 41.8°C?</h1>	null	484 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To solve this, we use the formula for heat absorption, <mathjax>#Q = mTc#</mathjax>, where<br/> <mathjax>#Q#</mathjax> is the heat energy absorbed, in Joules,<br/> <mathjax>#m#</mathjax> is the mass of the object usually in grams,<br/> <mathjax>#T#</mathjax> is the temperature change of the object, in Celcius or Kelvin, and <br/> <mathjax>#c#</mathjax> is the <em><a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> capacity</em> of the material, in joules per gram °C. This is the amount of energy it takes for one gram of this substance to heat up by 1K.</p> <p>We then rearrange this equation making <mathjax>#m#</mathjax> the subject:<br/> <mathjax>#m = Q/(Tc)#</mathjax></p> <p>The question gives us the values <mathjax>#Q = 1kJ = 1000J#</mathjax>, and we can calculate <mathjax>#T#</mathjax> by using</p> <p><mathjax>#T = "Final Temperature" - "Initial Temperature" = 41.8"°C" - 33.0"°C"#</mathjax><br/> <mathjax>#T = 8.80"°C = 8.80K"#</mathjax></p> <p>Now the only remaining value we need is <mathjax>#c#</mathjax>. Since this depends on the material involved, we have to look up the value for silver.<br/> I found 3 sources: <a href="http://hyperphysics.phy-astr.gsu.edu/hbase/Tables/sphtt.html" rel="nofollow">hyperphysics</a>, <a href="http://periodictable.com/Properties/A/SpecificHeat.al.html" rel="nofollow"></a><a href="http://periodictable.com" rel="nofollow" target="_blank">periodictable.com</a>, and <a href="http://www.ptable.com/#Property/Heat/Specific" rel="nofollow"></a><a href="http://ptable.com" rel="nofollow" target="_blank">ptable.com</a>. </p> <p>These put the value at <mathjax>#0.233Jg^-1K^-1#</mathjax>, <mathjax>#0.235Jg^-1K^-1#</mathjax>, and <mathjax>#0.235Jg^-1K^-1#</mathjax> respectively. I will use <mathjax>#0.235Jg^-1K^-1#</mathjax> here.</p> <p>Now we substitute into the equation:</p> <p><mathjax>#m = Q/(Tc) = (1000J)/(8.80K xx 0.235Jg^-1K^-1) = 484g " (3 s.f.)"#</mathjax></p> <p>If you have been given a value for the specific heat capacity of silver which is not <mathjax>#0.235Jg^-1K^-1#</mathjax>, then your final answer may be slightly different.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#484g#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To solve this, we use the formula for heat absorption, <mathjax>#Q = mTc#</mathjax>, where<br/> <mathjax>#Q#</mathjax> is the heat energy absorbed, in Joules,<br/> <mathjax>#m#</mathjax> is the mass of the object usually in grams,<br/> <mathjax>#T#</mathjax> is the temperature change of the object, in Celcius or Kelvin, and <br/> <mathjax>#c#</mathjax> is the <em><a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> capacity</em> of the material, in joules per gram °C. This is the amount of energy it takes for one gram of this substance to heat up by 1K.</p> <p>We then rearrange this equation making <mathjax>#m#</mathjax> the subject:<br/> <mathjax>#m = Q/(Tc)#</mathjax></p> <p>The question gives us the values <mathjax>#Q = 1kJ = 1000J#</mathjax>, and we can calculate <mathjax>#T#</mathjax> by using</p> <p><mathjax>#T = "Final Temperature" - "Initial Temperature" = 41.8"°C" - 33.0"°C"#</mathjax><br/> <mathjax>#T = 8.80"°C = 8.80K"#</mathjax></p> <p>Now the only remaining value we need is <mathjax>#c#</mathjax>. Since this depends on the material involved, we have to look up the value for silver.<br/> I found 3 sources: <a href="http://hyperphysics.phy-astr.gsu.edu/hbase/Tables/sphtt.html" rel="nofollow">hyperphysics</a>, <a href="http://periodictable.com/Properties/A/SpecificHeat.al.html" rel="nofollow"></a><a href="http://periodictable.com" rel="nofollow" target="_blank">periodictable.com</a>, and <a href="http://www.ptable.com/#Property/Heat/Specific" rel="nofollow"></a><a href="http://ptable.com" rel="nofollow" target="_blank">ptable.com</a>. </p> <p>These put the value at <mathjax>#0.233Jg^-1K^-1#</mathjax>, <mathjax>#0.235Jg^-1K^-1#</mathjax>, and <mathjax>#0.235Jg^-1K^-1#</mathjax> respectively. I will use <mathjax>#0.235Jg^-1K^-1#</mathjax> here.</p> <p>Now we substitute into the equation:</p> <p><mathjax>#m = Q/(Tc) = (1000J)/(8.80K xx 0.235Jg^-1K^-1) = 484g " (3 s.f.)"#</mathjax></p> <p>If you have been given a value for the specific heat capacity of silver which is not <mathjax>#0.235Jg^-1K^-1#</mathjax>, then your final answer may be slightly different.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many grams of silver are needed to absorb 1.00 kJ of energy changing the temperature from 33.0°C to 41.8°C?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/calorimetry" itemprop="url"> <span class="breadcrumb" itemprop="title">Calorimetry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="407053" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/glowing-grasshopper"><img alt="" class="" src="https://lh6.googleusercontent.com/-yAnywTuHSxk/AAAAAAAAAAI/AAAAAAAAAFI/pNn-rdsyXQk/photo.jpg?sz=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/glowing-grasshopper"> Cameron G. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-15T07:07:54" itemprop="dateCreated"> Apr 15, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#484g#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To solve this, we use the formula for heat absorption, <mathjax>#Q = mTc#</mathjax>, where<br/> <mathjax>#Q#</mathjax> is the heat energy absorbed, in Joules,<br/> <mathjax>#m#</mathjax> is the mass of the object usually in grams,<br/> <mathjax>#T#</mathjax> is the temperature change of the object, in Celcius or Kelvin, and <br/> <mathjax>#c#</mathjax> is the <em><a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> capacity</em> of the material, in joules per gram °C. This is the amount of energy it takes for one gram of this substance to heat up by 1K.</p> <p>We then rearrange this equation making <mathjax>#m#</mathjax> the subject:<br/> <mathjax>#m = Q/(Tc)#</mathjax></p> <p>The question gives us the values <mathjax>#Q = 1kJ = 1000J#</mathjax>, and we can calculate <mathjax>#T#</mathjax> by using</p> <p><mathjax>#T = "Final Temperature" - "Initial Temperature" = 41.8"°C" - 33.0"°C"#</mathjax><br/> <mathjax>#T = 8.80"°C = 8.80K"#</mathjax></p> <p>Now the only remaining value we need is <mathjax>#c#</mathjax>. Since this depends on the material involved, we have to look up the value for silver.<br/> I found 3 sources: <a href="http://hyperphysics.phy-astr.gsu.edu/hbase/Tables/sphtt.html" rel="nofollow">hyperphysics</a>, <a href="http://periodictable.com/Properties/A/SpecificHeat.al.html" rel="nofollow"></a><a href="http://periodictable.com" rel="nofollow" target="_blank">periodictable.com</a>, and <a href="http://www.ptable.com/#Property/Heat/Specific" rel="nofollow"></a><a href="http://ptable.com" rel="nofollow" target="_blank">ptable.com</a>. </p> <p>These put the value at <mathjax>#0.233Jg^-1K^-1#</mathjax>, <mathjax>#0.235Jg^-1K^-1#</mathjax>, and <mathjax>#0.235Jg^-1K^-1#</mathjax> respectively. I will use <mathjax>#0.235Jg^-1K^-1#</mathjax> here.</p> <p>Now we substitute into the equation:</p> <p><mathjax>#m = Q/(Tc) = (1000J)/(8.80K xx 0.235Jg^-1K^-1) = 484g " (3 s.f.)"#</mathjax></p> <p>If you have been given a value for the specific heat capacity of silver which is not <mathjax>#0.235Jg^-1K^-1#</mathjax>, then your final answer may be slightly different.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/407053" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-differential-scanning-in-calorimetry-work"> How does differential scanning in calorimetry work? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-read-differential-scanning-in-calorimetry"> What information do you get from a differential scanning calorimetry plot? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-measure-calorimetry"> How do you measure calorimetry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531d304102bf341e75b962a7"> Question #962a7 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5335021802bf344ae911dfc5"> Question #1dfc5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/533668f502bf34572c341af6"> Question #41af6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-definition-of-calorimetry"> What is calorimetry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-differential-scanning-calorimeter"> What is a differential scanning calorimeter? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-a-calorimeter-measure-energy"> How can a calorimeter measure energy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-calorimeters-made-of"> What are calorimeters made of? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/calorimetry"> See all questions in Calorimetry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3134 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many grams of silver are needed to absorb 1.00 kJ of energy changing the temperature from 33.0°C to 41.8°C?	null
1,792	aa33a0ca-6ddd-11ea-8c7c-ccda262736ce	https://socratic.org/questions/what-is-the-ph-of-an-aqueous-solution-if-the-h-0-000001	6.00	start physical_unit 6 7 ph none qc_end physical_unit 6 7 12 13 [h+] qc_end end	[{"type":"physical unit","value":"pH [OF] aqueous solution"}]	[{"type":"physical unit","value":"6.00"}]	[{"type":"physical unit","value":"[H+] [OF] aqueous solution [=] \\pu{0.000001 M}"}]	<h1 class="questionTitle" itemprop="name">What is the pH of an aqueous solution if the [#H^+#]=0.000001?</h1>	null	6.00	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#pH=-log_10[H_3O^+]#</mathjax></p> <p>But if <mathjax>#[H^+]#</mathjax> or <mathjax>#[H_3O^+]#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.000001molL^-1#</mathjax>;</p> <p>then <mathjax>#pH#</mathjax> <mathjax>#=#</mathjax> <mathjax>#-log_10(0.000001)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#-log_10(10^-6)#</mathjax>.</p> <p>Now, by definition, <mathjax>#log_10(10^-6)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#-6#</mathjax>.</p> <p>Thus <mathjax>#pH=-(-6)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#6#</mathjax></p> <p>This is slightly acid, and <mathjax>#[H_3O^+]#</mathjax> is <mathjax>#10xx[HO^-]#</mathjax>.</p> <p>If <mathjax>#[H_3O^+]#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.001molL^-1#</mathjax>, what is <mathjax>#pH#</mathjax>?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#pH=6#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#pH=-log_10[H_3O^+]#</mathjax></p> <p>But if <mathjax>#[H^+]#</mathjax> or <mathjax>#[H_3O^+]#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.000001molL^-1#</mathjax>;</p> <p>then <mathjax>#pH#</mathjax> <mathjax>#=#</mathjax> <mathjax>#-log_10(0.000001)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#-log_10(10^-6)#</mathjax>.</p> <p>Now, by definition, <mathjax>#log_10(10^-6)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#-6#</mathjax>.</p> <p>Thus <mathjax>#pH=-(-6)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#6#</mathjax></p> <p>This is slightly acid, and <mathjax>#[H_3O^+]#</mathjax> is <mathjax>#10xx[HO^-]#</mathjax>.</p> <p>If <mathjax>#[H_3O^+]#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.001molL^-1#</mathjax>, what is <mathjax>#pH#</mathjax>?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the pH of an aqueous solution if the [#H^+#]=0.000001?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/solutions" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="317433" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-10-03T17:07:41" itemprop="dateCreated"> Oct 3, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#pH=6#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#pH=-log_10[H_3O^+]#</mathjax></p> <p>But if <mathjax>#[H^+]#</mathjax> or <mathjax>#[H_3O^+]#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.000001molL^-1#</mathjax>;</p> <p>then <mathjax>#pH#</mathjax> <mathjax>#=#</mathjax> <mathjax>#-log_10(0.000001)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#-log_10(10^-6)#</mathjax>.</p> <p>Now, by definition, <mathjax>#log_10(10^-6)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#-6#</mathjax>.</p> <p>Thus <mathjax>#pH=-(-6)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#6#</mathjax></p> <p>This is slightly acid, and <mathjax>#[H_3O^+]#</mathjax> is <mathjax>#10xx[HO^-]#</mathjax>.</p> <p>If <mathjax>#[H_3O^+]#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.001molL^-1#</mathjax>, what is <mathjax>#pH#</mathjax>?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/317433" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-solution-solute-and-solvent-related"> How are solution, solute, and solvent related? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a 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1,793	a8f68fe9-6ddd-11ea-8168-ccda262736ce	https://socratic.org/questions/a-2-0-ml-sample-of-naoh-solution-is-exactly-neutralized-by-4-0-ml-of-3-0-m-hcl-s	6.0 mol/L	start physical_unit 5 6 concentration mol/l qc_end physical_unit 3 6 1 2 volume qc_end physical_unit 16 17 11 12 volume qc_end physical_unit 16 17 14 15 concentration qc_end end	[{"type":"physical unit","value":"Concentration [OF] NaOH solution [IN] mol/L"}]	[{"type":"physical unit","value":"6.0 mol/L"}]	[{"type":"physical unit","value":"Volume [OF] NaOH solution sample [=] \\pu{2.0 mL}"},{"type":"physical unit","value":"Volume [OF] HCl solution [=] \\pu{4.0 mL}"},{"type":"physical unit","value":"Concentration [OF] HCl solution [=] \\pu{3.0 M}"}]	<h1 class="questionTitle" itemprop="name">A 2.0 mL sample of #NaOH# solution is exactly neutralized by 4.0 mL of 3.0 M #HCl# solution. What is the concentration of the #NaOH# solution?</h1>	null	6.0 mol/L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#NaOH(aq) + HCl(aq) rarr NaCl(aq) + H_2O(l)#</mathjax></p> <p>Clearly a 1:1 <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> pertains. We know the concentration of the hydrochloric acid, and we use this to calculate (i) the number of moles of hydrochloric acid, and (ii) the concentration of the caustic soda.</p> <p><mathjax>#"Moles of hydrochloric acid"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#4.0xx10^-3Lxx3.0molL^-1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#12xx10^-3mol#</mathjax></p> <p><mathjax>#"Concentration of sodium hydroxide"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Moles of NaOH"/"Initial volume of solution"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(12xx10^-3mol)/(2.0xx10^-3*L)#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#[NaOH]#</mathjax> <mathjax>#=#</mathjax> <mathjax>#6.0molL^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#NaOH(aq) + HCl(aq) rarr NaCl(aq) + H_2O(l)#</mathjax></p> <p>Clearly a 1:1 <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> pertains. We know the concentration of the hydrochloric acid, and we use this to calculate (i) the number of moles of hydrochloric acid, and (ii) the concentration of the caustic soda.</p> <p><mathjax>#"Moles of hydrochloric acid"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#4.0xx10^-3Lxx3.0molL^-1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#12xx10^-3mol#</mathjax></p> <p><mathjax>#"Concentration of sodium hydroxide"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Moles of NaOH"/"Initial volume of solution"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(12xx10^-3mol)/(2.0xx10^-3*L)#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A 2.0 mL sample of #NaOH# solution is exactly neutralized by 4.0 mL of 3.0 M #HCl# solution. What is the concentration of the #NaOH# solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#reactions-in-solution" itemprop="url"> <span class="breadcrumb" itemprop="title">Reactions in Solution</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/reactions-in-solution/neutralization" itemprop="url"> <span class="breadcrumb" itemprop="title">Neutralization</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="273283" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-03T06:04:14" itemprop="dateCreated"> Jun 3, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#[NaOH]#</mathjax> <mathjax>#=#</mathjax> <mathjax>#6.0molL^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#NaOH(aq) + HCl(aq) rarr NaCl(aq) + H_2O(l)#</mathjax></p> <p>Clearly a 1:1 <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> pertains. We know the concentration of the hydrochloric acid, and we use this to calculate (i) the number of moles of hydrochloric acid, and (ii) the concentration of the caustic soda.</p> <p><mathjax>#"Moles of hydrochloric acid"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#4.0xx10^-3Lxx3.0molL^-1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#12xx10^-3mol#</mathjax></p> <p><mathjax>#"Concentration of sodium hydroxide"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Moles of NaOH"/"Initial volume of solution"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(12xx10^-3mol)/(2.0xx10^-3*L)#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/273283" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-neutralization-reactions-useful"> How are neutralization reactions useful? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-neutralization-reactions-be-identified-symbolically"> How can neutralization reactions be identified symbolically? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-neutralization-reaction-differ-from-buffer"> How does neutralization reaction differ from using a buffer? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-do-acid-base-neutralization-reactions"> How do you do acid base neutralization reactions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-neutralization-reactions-produce-heat"> Why do neutralization reactions produce heat? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-neutralization-a-double-replacement-reaction"> Why is neutralization a double replacement reaction? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-a-neutralization-reaction-exothermic"> Why is a neutralization reaction exothermic? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-predict-and-balance-acid-base-reactions"> How do you predict the products in acid-base reactions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-you-determine-the-strength-of-sulfuric-acid"> How can you determine the strength of sulfuric acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-a-neutralisation-reaction-exothermic"> Why is a neutralisation reaction exothermic? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/reactions-in-solution/neutralization"> See all questions in Neutralization </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 12695 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A 2.0 mL sample of #NaOH# solution is exactly neutralized by 4.0 mL of 3.0 M #HCl# solution. What is the concentration of the #NaOH# solution?	null
1,794	aae763d2-6ddd-11ea-8e4c-ccda262736ce	https://socratic.org/questions/what-is-the-vapor-in-oxygen-gas-collected-by-water-displacement-at-10-c-and-75-m	64.80 mmHg	start physical_unit 6 7 vapor_pressure mmhg qc_end physical_unit 10 10 13 14 temperature qc_end physical_unit 10 10 16 17 pressure qc_end end	[{"type":"physical unit","value":"Vapor pressure [OF] oxygen gas [IN] mmHg"}]	[{"type":"physical unit","value":"64.80 mmHg"}]	[{"type":"physical unit","value":"Temperature [OF] water [=] \\pu{10 ℃}"},{"type":"physical unit","value":"Pressure [OF] water [=] \\pu{75 mmHg}"}]	<h1 class="questionTitle" itemprop="name">What is the vapor in oxygen gas collected by water displacement at 10°C and 75 mm Hg?</h1>	null	64.80 mmHg	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Any gas collected by water displacement will contain water vapour, the so-called <mathjax>#"saturated vapour pressure"#</mathjax>. This is extensively <a href="https://en.wikipedia.org/wiki/Vapour_pressure_of_water" rel="nofollow">tabulated</a>, and fat <mathjax>#10""^@#</mathjax> <mathjax>#C#</mathjax>, <mathjax>#P_"SVP"=10.2mmHg#</mathjax></p> <p><mathjax>#P_"gas"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#P_"measured"-P_"SVP"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#75mmHg-10.2mmHg#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??mmHg#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#P_"measured"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#P_"gas"+P_"SVP"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Any gas collected by water displacement will contain water vapour, the so-called <mathjax>#"saturated vapour pressure"#</mathjax>. This is extensively <a href="https://en.wikipedia.org/wiki/Vapour_pressure_of_water" rel="nofollow">tabulated</a>, and fat <mathjax>#10""^@#</mathjax> <mathjax>#C#</mathjax>, <mathjax>#P_"SVP"=10.2mmHg#</mathjax></p> <p><mathjax>#P_"gas"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#P_"measured"-P_"SVP"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#75mmHg-10.2mmHg#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??mmHg#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the vapor in oxygen gas collected by water displacement at 10°C and 75 mm Hg?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/partial-pressure" itemprop="url"> <span class="breadcrumb" itemprop="title">Partial Pressure</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="283987" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-02T17:42:20" itemprop="dateCreated"> Jul 2, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#P_"measured"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#P_"gas"+P_"SVP"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Any gas collected by water displacement will contain water vapour, the so-called <mathjax>#"saturated vapour pressure"#</mathjax>. This is extensively <a href="https://en.wikipedia.org/wiki/Vapour_pressure_of_water" rel="nofollow">tabulated</a>, and fat <mathjax>#10""^@#</mathjax> <mathjax>#C#</mathjax>, <mathjax>#P_"SVP"=10.2mmHg#</mathjax></p> <p><mathjax>#P_"gas"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#P_"measured"-P_"SVP"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#75mmHg-10.2mmHg#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??mmHg#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/283987" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/534e256802bf342adfa30010"> How do you do a steam distillation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/53613f9f02bf3416cd9f8a34"> Question #f8a34 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-i-calculate-the-total-pressure-of-a-mixture-of-gases-by-adding-together-the-"> Can I calculate the total pressure of a mixture of gases by adding together the partial... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-formula-of-partial-pressure"> What is the formula of partial pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-dalton-s-law-of-partial-pressures"> What is the Dalton's law of partial pressures? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/nitrogen-gas-n2-reacts-with-hydrogen-gas-h2-to-form-ammonia-nh3-at-200-c-in-a-cl"> Nitrogen gas (N2) reacts with hydrogen gas (H2) to form ammonia (NH3). 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1,795	a9856adc-6ddd-11ea-988b-ccda262736ce	https://socratic.org/questions/a-29-80-g-sample-of-liquid-cadmium-at-377-00-c-is-poured-into-a-mold-and-allowed	4.10 kJ	start physical_unit 30 31 heat_energy kj qc_end physical_unit 3 6 1 2 mass qc_end physical_unit 3 6 8 9 temperature qc_end physical_unit 3 6 20 21 temperature qc_end physical_unit 6 6 40 40 pressure qc_end physical_unit 6 6 43 44 boiling_point_temperature qc_end physical_unit 6 6 48 49 molar_enthalpy_of_vaporization qc_end physical_unit 6 6 52 53 melting_point_temperature qc_end physical_unit 6 6 58 59 enthalpy_of_fusion qc_end end	[{"type":"physical unit","value":"Released energy [OF] this process [IN] kJ"}]	[{"type":"physical unit","value":"4.10 kJ"}]	[{"type":"physical unit","value":"Mass [OF] liquid cadmium sample [=] \\pu{29.80 g}"},{"type":"physical unit","value":"Temperature1 [OF] liquid cadmium sample [=] \\pu{377.00 ℃}"},{"type":"physical unit","value":"Temperature2 [OF] liquid cadmium sample [=] \\pu{24.00 ℃}"},{"type":"physical unit","value":"Pressure [OF] cadmium [=] \\pu{1 atm}"},{"type":"physical unit","value":"Tb [OF] cadmium [=] \\pu{765.00 ℃}"},{"type":"physical unit","value":"Hvap [OF] cadmium [=] \\pu{889.6 J/g}"},{"type":"physical unit","value":"Tm [OF] cadmium [=] \\pu{321.00 ℃}"},{"type":"physical unit","value":"Hfus [OF] cadmium [=] \\pu{54.40 J/g}"},{"type":"physical unit","value":"Specific heat [OF] cadmium solid [=] \\pu{0.2300 J/(g * ℃)}"},{"type":"physical unit","value":"Specific heat [OF] cadmium liquid [=] \\pu{0.2640 J/(g * ℃)}"}]	<h1 class="questionTitle" itemprop="name">A 29.80 g sample of liquid cadmium at 377.00°C is poured into a mold and allowed to cool to 24.00°C. How many kJ of energy are released in this process? </h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>The following information is given for cadmium at 1atm:</p> <p>Tb = 765.00°C Hvap (765.00°C) =889.6 J/g<br/> Tm = 321.00°C Hfus (321.00°C) = 54.40 J/g<br/> Specific heat solid = 0.2300 J/g °C<br/> Specific heat liquid = 0.2640 J/g °C</p> <p>(Report the answer as a positive number.)<br/> Energy= kJ</p></div> </h2> </div> </div>	4.10 kJ	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Since you calcium starts this process at 377 °C and is in liquid phase, the heat of vapourization does not enter into this. However, the heat of fusion does, as the calcium will freeze into a solid before it reaches 24 °C</p> <p>So, three things happen, each of which involves a quantity of heat.</p> <p>First, the liquid calcium cools from 377 °C to 321 °C. Since the <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> for the liquid is 0.2640 J/g °C, this heat is</p> <p><mathjax>#E =mxxCxxDeltat#</mathjax> </p> <p>where <mathjax>#m#</mathjax> is the mass, <mathjax>#C#</mathjax> is the specific heat and <mathjax>#Deltat#</mathjax> is the temperature change.</p> <p><mathjax>#E = 29.80g xx 0.2640 J/(g °C) xx 56 °C = 440.56 J#</mathjax></p> <p>Second, the liquid freezes at 321 °C:.</p> <p><mathjax>#E = 29.80g xx 54.40 J/g=1621.12 J#</mathjax></p> <p>Finally, the solid cools. The calculation is similar to the first one above:</p> <p><mathjax>#E = 29.80g xx 0.2300 J/(g °C) xx 297 °C = 2035.64J#</mathjax></p> <p>(notice the change to the specific heat of the solid, and the large drop in temperature, from 321 ° to 24 °)</p> <p>Total energy is the sum: <mathjax>#440.56+1621.12+2035.64=4097.32 J#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The total energy released is 4097 J (to four sig. digits) or 4.097 kJ</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Since you calcium starts this process at 377 °C and is in liquid phase, the heat of vapourization does not enter into this. However, the heat of fusion does, as the calcium will freeze into a solid before it reaches 24 °C</p> <p>So, three things happen, each of which involves a quantity of heat.</p> <p>First, the liquid calcium cools from 377 °C to 321 °C. Since the <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> for the liquid is 0.2640 J/g °C, this heat is</p> <p><mathjax>#E =mxxCxxDeltat#</mathjax> </p> <p>where <mathjax>#m#</mathjax> is the mass, <mathjax>#C#</mathjax> is the specific heat and <mathjax>#Deltat#</mathjax> is the temperature change.</p> <p><mathjax>#E = 29.80g xx 0.2640 J/(g °C) xx 56 °C = 440.56 J#</mathjax></p> <p>Second, the liquid freezes at 321 °C:.</p> <p><mathjax>#E = 29.80g xx 54.40 J/g=1621.12 J#</mathjax></p> <p>Finally, the solid cools. The calculation is similar to the first one above:</p> <p><mathjax>#E = 29.80g xx 0.2300 J/(g °C) xx 297 °C = 2035.64J#</mathjax></p> <p>(notice the change to the specific heat of the solid, and the large drop in temperature, from 321 ° to 24 °)</p> <p>Total energy is the sum: <mathjax>#440.56+1621.12+2035.64=4097.32 J#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A 29.80 g sample of liquid cadmium at 377.00°C is poured into a mold and allowed to cool to 24.00°C. How many kJ of energy are released in this process? </h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>The following information is given for cadmium at 1atm:</p> <p>Tb = 765.00°C Hvap (765.00°C) =889.6 J/g<br/> Tm = 321.00°C Hfus (321.00°C) = 54.40 J/g<br/> Specific heat solid = 0.2300 J/g °C<br/> Specific heat liquid = 0.2640 J/g °C</p> <p>(Report the answer as a positive number.)<br/> Energy= kJ</p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/calorimetry" itemprop="url"> <span class="breadcrumb" itemprop="title">Calorimetry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="502389" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/dwight"><img alt="" class="" src="https://profilepictures.socratic.org/ZDiTFWmAQmWOT3sd0Xpr_Dwight.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/dwight"> Dwight </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-11-08T23:40:52" itemprop="dateCreated"> Nov 8, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The total energy released is 4097 J (to four sig. digits) or 4.097 kJ</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Since you calcium starts this process at 377 °C and is in liquid phase, the heat of vapourization does not enter into this. However, the heat of fusion does, as the calcium will freeze into a solid before it reaches 24 °C</p> <p>So, three things happen, each of which involves a quantity of heat.</p> <p>First, the liquid calcium cools from 377 °C to 321 °C. Since the <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> for the liquid is 0.2640 J/g °C, this heat is</p> <p><mathjax>#E =mxxCxxDeltat#</mathjax> </p> <p>where <mathjax>#m#</mathjax> is the mass, <mathjax>#C#</mathjax> is the specific heat and <mathjax>#Deltat#</mathjax> is the temperature change.</p> <p><mathjax>#E = 29.80g xx 0.2640 J/(g °C) xx 56 °C = 440.56 J#</mathjax></p> <p>Second, the liquid freezes at 321 °C:.</p> <p><mathjax>#E = 29.80g xx 54.40 J/g=1621.12 J#</mathjax></p> <p>Finally, the solid cools. The calculation is similar to the first one above:</p> <p><mathjax>#E = 29.80g xx 0.2300 J/(g °C) xx 297 °C = 2035.64J#</mathjax></p> <p>(notice the change to the specific heat of the solid, and the large drop in temperature, from 321 ° to 24 °)</p> <p>Total energy is the sum: <mathjax>#440.56+1621.12+2035.64=4097.32 J#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/502389" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-differential-scanning-in-calorimetry-work"> How does differential scanning in calorimetry work? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-read-differential-scanning-in-calorimetry"> What information do you get from a differential scanning calorimetry plot? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-measure-calorimetry"> How do you measure calorimetry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531d304102bf341e75b962a7"> Question #962a7 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5335021802bf344ae911dfc5"> Question #1dfc5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/533668f502bf34572c341af6"> Question #41af6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-definition-of-calorimetry"> What is calorimetry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-differential-scanning-calorimeter"> What is a differential scanning calorimeter? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-a-calorimeter-measure-energy"> How can a calorimeter measure energy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-calorimeters-made-of"> What are calorimeters made of? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/calorimetry"> See all questions in Calorimetry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 12561 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A 29.80 g sample of liquid cadmium at 377.00°C is poured into a mold and allowed to cool to 24.00°C. How many kJ of energy are released in this process?	The following information is given for cadmium at 1atm: Tb = 765.00°C Hvap (765.00°C) =889.6 J/g Tm = 321.00°C Hfus (321.00°C) = 54.40 J/g Specific heat solid = 0.2300 J/g °C Specific heat liquid = 0.2640 J/g °C (Report the answer as a positive number.) Energy= kJ
1,796	ab4cf47a-6ddd-11ea-8b54-ccda262736ce	https://socratic.org/questions/what-is-the-chemical-form-for-chromium-iii-acetate	C6H9CrO6	start chemical_formula qc_end substance 6 8 qc_end end	[{"type":"other","value":"Chemical Formula [OF] chromium (III) acetate [IN] default"}]	[{"type":"chemical equation","value":"C6H9CrO6"}]	[{"type":"substance name","value":"Chromium (III) acetate"}]	<h1 class="questionTitle" itemprop="name">What is the chemical form for chromium (III) acetate?</h1>	null	C6H9CrO6	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Do you mean the chemical formula?</p> <p><mathjax>#C_6H_9CrO_6#</mathjax><br/> <img alt="enter image source here" src="https://useruploads.socratic.org/pWv2361fTfqNrbt2zFY3_p0mRYHK.png"/> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_6H_9CrO_6#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Do you mean the chemical formula?</p> <p><mathjax>#C_6H_9CrO_6#</mathjax><br/> <img alt="enter image source here" src="https://useruploads.socratic.org/pWv2361fTfqNrbt2zFY3_p0mRYHK.png"/> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the chemical form for chromium (III) acetate?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#ionic-bonds-and-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Ionic Bonds</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/ionic-bonds-and-formulas/writing-ionic-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Writing Ionic Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="285340" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/jake-a"><img alt="" class="" src="https://lh3.googleusercontent.com/-jw6LuSIY-4A/AAAAAAAAAAI/AAAAAAAABbI/MsRqgbyStmw/photo.jpg?sz=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/jake-a"> Jake A. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-06T13:12:33" itemprop="dateCreated"> Jul 6, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_6H_9CrO_6#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Do you mean the chemical formula?</p> <p><mathjax>#C_6H_9CrO_6#</mathjax><br/> <img alt="enter image source here" src="https://useruploads.socratic.org/pWv2361fTfqNrbt2zFY3_p0mRYHK.png"/> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/285340" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-write-ionic-formulas-for-binary-compounds"> How do you write ionic formulas for binary compounds? 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1,797	a8a61140-6ddd-11ea-8730-ccda262736ce	https://socratic.org/questions/how-do-you-write-the-formula-of-periodic-acid	HIO4	start chemical_formula qc_end substance 7 8 qc_end end	[{"type":"other","value":"Chemical Formula [OF] periodic acid [IN] default"}]	[{"type":"chemical equation","value":"HIO4"}]	[{"type":"substance name","value":"Periodic acid"}]	<h1 class="questionTitle" itemprop="name">How do you write the formula of periodic acid?</h1>	null	HIO4	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Iodine in periodic acid achieves its maximum oxidation state, <mathjax>#I(VII+)#</mathjax>.</p> <p>Periodic acid, like <mathjax>#HClO_4#</mathjax>, is an exceptionally strong mineral acid. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#HIO_4#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Iodine in periodic acid achieves its maximum oxidation state, <mathjax>#I(VII+)#</mathjax>.</p> <p>Periodic acid, like <mathjax>#HClO_4#</mathjax>, is an exceptionally strong mineral acid. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you write the formula of periodic acid?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#ionic-bonds-and-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Ionic Bonds</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/ionic-bonds-and-formulas/writing-ionic-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Writing Ionic Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="329877" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-11-01T20:20:57" itemprop="dateCreated"> Nov 1, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#HIO_4#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Iodine in periodic acid achieves its maximum oxidation state, <mathjax>#I(VII+)#</mathjax>.</p> <p>Periodic acid, like <mathjax>#HClO_4#</mathjax>, is an exceptionally strong mineral acid. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/329877" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-write-ionic-formulas-for-binary-compounds"> How do you write ionic formulas for binary compounds? 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1,798	a95c67cb-6ddd-11ea-8884-ccda262736ce	https://socratic.org/questions/56ac21507c0149172426a2ae	1.14 moles	start physical_unit 7 7 mole mol qc_end physical_unit 7 7 5 6 mass qc_end end	[{"type":"physical unit","value":"Mole [OF] He [IN] moles"}]	[{"type":"physical unit","value":"1.14 moles"}]	[{"type":"physical unit","value":"Mass [OF] He [=] \\pu{4.555 g}"}]	<h1 class="questionTitle" itemprop="name">How many moles are in #"4.555 g He"#?</h1>	null	1.14 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The molar mass of helium (He) is <mathjax>#"4.002602 g/mol"#</mathjax> (relative <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">atomic mass</a> on <a href="http://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a> in grams/mol), which means that one mole He has a mass of <mathjax>#"4.002602 g"#</mathjax>.</p> <p>To determine the moles He in <mathjax>#"4.555 g He"#</mathjax>, divide the given mass by its molar mass.</p> <p><mathjax>#4.555cancel"g He"xx(1"mol He")/(4.002602cancel"g He")="1.1380 mol He"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"4.555 g He"#</mathjax> contain <mathjax>#"1.1380 mol He"#</mathjax>."</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The molar mass of helium (He) is <mathjax>#"4.002602 g/mol"#</mathjax> (relative <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">atomic mass</a> on <a href="http://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a> in grams/mol), which means that one mole He has a mass of <mathjax>#"4.002602 g"#</mathjax>.</p> <p>To determine the moles He in <mathjax>#"4.555 g He"#</mathjax>, divide the given mass by its molar mass.</p> <p><mathjax>#4.555cancel"g He"xx(1"mol He")/(4.002602cancel"g He")="1.1380 mol He"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles are in #"4.555 g He"#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="219050" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-30T02:57:48" itemprop="dateCreated"> Jan 30, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"4.555 g He"#</mathjax> contain <mathjax>#"1.1380 mol He"#</mathjax>."</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The molar mass of helium (He) is <mathjax>#"4.002602 g/mol"#</mathjax> (relative <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">atomic mass</a> on <a href="http://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a> in grams/mol), which means that one mole He has a mass of <mathjax>#"4.002602 g"#</mathjax>.</p> <p>To determine the moles He in <mathjax>#"4.555 g He"#</mathjax>, divide the given mass by its molar mass.</p> <p><mathjax>#4.555cancel"g He"xx(1"mol He")/(4.002602cancel"g He")="1.1380 mol He"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/219050" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li 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moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3576 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many moles are in #"4.555 g He"#?	null
1,799	aac5bd28-6ddd-11ea-8c88-ccda262736ce	https://socratic.org/questions/assuming-all-volume-measurements-are-made-at-the-same-temperature-and-pressure-w	9.10 L	start physical_unit 15 16 volume l qc_end physical_unit 26 27 23 24 volume qc_end c_other ConstantTemperaturePressue qc_end c_other OTHER qc_end substance 30 31 qc_end end	[{"type":"physical unit","value":"Volume [OF] hydrogen gas [IN] L"}]	[{"type":"physical unit","value":"9.10 L"}]	[{"type":"physical unit","value":"Volume [OF] oxygen gas [=] \\pu{4.55 L}"},{"type":"other","value":"ConstantTemperaturePressue"},{"type":"other","value":"React completely."},{"type":"substance name","value":"Water vapor"}]	<h1 class="questionTitle" itemprop="name">Assuming all volume measurements are made at the same temperature and pressure, what volume of hydrogen gas is needed to react completely with 4.55 L of oxygen gas to produce water vapor?</h1>	null	9.10 L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The important thing to keep in mind when dealing with gases that are <strong>under the same conditions for pressure and temperature</strong> is that their <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> is <strong>equivalent</strong> to their <em>volume ratio</em>.</p> <p>You can prove this by using the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> equation </p> <blockquote> <p><mathjax>#P * V_1 = n_1 * RT ->#</mathjax> <em>the first gas at pressure</em> <mathjax>#P#</mathjax> <em>and temperature</em> <mathjax>#T#</mathjax></p> <p><mathjax>#P * V_2 = n_2 * RT ->#</mathjax> <em>the second gas at pressure</em> <mathjax>#P#</mathjax> <em>and temperature</em> <mathjax>#T#</mathjax></p> </blockquote> <p>Divide these two equations to get</p> <blockquote> <p><mathjax>#(color(red)(cancel(color(black)(P))) * V_1)/(color(red)(cancel(color(black)(P))) * V_2) = (n_1 * color(red)(cancel(color(black)(RT))))/(n_2 * color(red)(cancel(color(black)(RT))))#</mathjax></p> </blockquote> <p>Therefore, you can say that</p> <blockquote> <p><mathjax>#n_1/n_2 = V_1/V_2 ->#</mathjax> <em><a href="http://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio is equal to the volume ratio</em></p> </blockquote> <p>The balanced chemical equation for your reaction looks like this </p> <blockquote> <p><mathjax>#color(red)(2)"H"_text(2(g]) + "O"_text(2(g]) -> 2"H"_2"O"_text((g])#</mathjax></p> </blockquote> <p>Notice that you have a <mathjax>#color(red)(2):1#</mathjax> <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> between hydrogen gas and oxygen gas. This mole ratio tells you that you need <mathjax>#color(red)(2)#</mathjax> <strong>moles</strong> of hydrogen gas <strong>for every</strong> mole of oxygen gas that takes part in the reaction. </p> <p>Now, since all three gases are under the same conditions for <em>pressure</em> and <em>temperature</em>, this mole ratio will be equal to a <strong>volume ratio</strong></p> <blockquote> <p><mathjax>#n_(H_2)/n_(O_2) = V_(H_2)/V_(O_2) = color(red)(2)/1#</mathjax></p> </blockquote> <p>This means that your sample of oxygen would need </p> <blockquote> <p><mathjax>#4.55 color(red)(cancel(color(black)("L O"_2))) * (color(red)(2)" L H"_2)/(1color(red)(cancel(color(black)("L O"_2)))) = color(green)("9.10 L H"_2)#</mathjax></p> </blockquote> <p>The answer is rounded to three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"9.10 L"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The important thing to keep in mind when dealing with gases that are <strong>under the same conditions for pressure and temperature</strong> is that their <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> is <strong>equivalent</strong> to their <em>volume ratio</em>.</p> <p>You can prove this by using the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> equation </p> <blockquote> <p><mathjax>#P * V_1 = n_1 * RT ->#</mathjax> <em>the first gas at pressure</em> <mathjax>#P#</mathjax> <em>and temperature</em> <mathjax>#T#</mathjax></p> <p><mathjax>#P * V_2 = n_2 * RT ->#</mathjax> <em>the second gas at pressure</em> <mathjax>#P#</mathjax> <em>and temperature</em> <mathjax>#T#</mathjax></p> </blockquote> <p>Divide these two equations to get</p> <blockquote> <p><mathjax>#(color(red)(cancel(color(black)(P))) * V_1)/(color(red)(cancel(color(black)(P))) * V_2) = (n_1 * color(red)(cancel(color(black)(RT))))/(n_2 * color(red)(cancel(color(black)(RT))))#</mathjax></p> </blockquote> <p>Therefore, you can say that</p> <blockquote> <p><mathjax>#n_1/n_2 = V_1/V_2 ->#</mathjax> <em><a href="http://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio is equal to the volume ratio</em></p> </blockquote> <p>The balanced chemical equation for your reaction looks like this </p> <blockquote> <p><mathjax>#color(red)(2)"H"_text(2(g]) + "O"_text(2(g]) -> 2"H"_2"O"_text((g])#</mathjax></p> </blockquote> <p>Notice that you have a <mathjax>#color(red)(2):1#</mathjax> <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> between hydrogen gas and oxygen gas. This mole ratio tells you that you need <mathjax>#color(red)(2)#</mathjax> <strong>moles</strong> of hydrogen gas <strong>for every</strong> mole of oxygen gas that takes part in the reaction. </p> <p>Now, since all three gases are under the same conditions for <em>pressure</em> and <em>temperature</em>, this mole ratio will be equal to a <strong>volume ratio</strong></p> <blockquote> <p><mathjax>#n_(H_2)/n_(O_2) = V_(H_2)/V_(O_2) = color(red)(2)/1#</mathjax></p> </blockquote> <p>This means that your sample of oxygen would need </p> <blockquote> <p><mathjax>#4.55 color(red)(cancel(color(black)("L O"_2))) * (color(red)(2)" L H"_2)/(1color(red)(cancel(color(black)("L O"_2)))) = color(green)("9.10 L H"_2)#</mathjax></p> </blockquote> <p>The answer is rounded to three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Assuming all volume measurements are made at the same temperature and pressure, what volume of hydrogen gas is needed to react completely with 4.55 L of oxygen gas to produce water vapor?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/stoichiometry-involving-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="203689" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-26T00:14:20" itemprop="dateCreated"> Dec 26, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"9.10 L"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The important thing to keep in mind when dealing with gases that are <strong>under the same conditions for pressure and temperature</strong> is that their <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> is <strong>equivalent</strong> to their <em>volume ratio</em>.</p> <p>You can prove this by using the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> equation </p> <blockquote> <p><mathjax>#P * V_1 = n_1 * RT ->#</mathjax> <em>the first gas at pressure</em> <mathjax>#P#</mathjax> <em>and temperature</em> <mathjax>#T#</mathjax></p> <p><mathjax>#P * V_2 = n_2 * RT ->#</mathjax> <em>the second gas at pressure</em> <mathjax>#P#</mathjax> <em>and temperature</em> <mathjax>#T#</mathjax></p> </blockquote> <p>Divide these two equations to get</p> <blockquote> <p><mathjax>#(color(red)(cancel(color(black)(P))) * V_1)/(color(red)(cancel(color(black)(P))) * V_2) = (n_1 * color(red)(cancel(color(black)(RT))))/(n_2 * color(red)(cancel(color(black)(RT))))#</mathjax></p> </blockquote> <p>Therefore, you can say that</p> <blockquote> <p><mathjax>#n_1/n_2 = V_1/V_2 ->#</mathjax> <em><a href="http://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio is equal to the volume ratio</em></p> </blockquote> <p>The balanced chemical equation for your reaction looks like this </p> <blockquote> <p><mathjax>#color(red)(2)"H"_text(2(g]) + "O"_text(2(g]) -> 2"H"_2"O"_text((g])#</mathjax></p> </blockquote> <p>Notice that you have a <mathjax>#color(red)(2):1#</mathjax> <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> between hydrogen gas and oxygen gas. This mole ratio tells you that you need <mathjax>#color(red)(2)#</mathjax> <strong>moles</strong> of hydrogen gas <strong>for every</strong> mole of oxygen gas that takes part in the reaction. </p> <p>Now, since all three gases are under the same conditions for <em>pressure</em> and <em>temperature</em>, this mole ratio will be equal to a <strong>volume ratio</strong></p> <blockquote> <p><mathjax>#n_(H_2)/n_(O_2) = V_(H_2)/V_(O_2) = color(red)(2)/1#</mathjax></p> </blockquote> <p>This means that your sample of oxygen would need </p> <blockquote> <p><mathjax>#4.55 color(red)(cancel(color(black)("L O"_2))) * (color(red)(2)" L H"_2)/(1color(red)(cancel(color(black)("L O"_2)))) = color(green)("9.10 L H"_2)#</mathjax></p> </blockquote> <p>The answer is rounded to three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/203689" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-apply-gas-stoichiometry"> How do you apply gas stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-solve-a-gas-law-stoichiometry-problem"> How do you solve a gas law stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-do-gas-stoichiometry-problems-at-stp"> How do you do gas stoichiometry problems at STP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-an-agno3-solution-is-treated-with-50-0-ml-of-hi-gas-to-give-0-235-g-of-agi-"> When an AgNO3 solution is treated with 50.0 mL of HI gas to give 0.235 g of AgI, what is the... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-10-0-ml-of-agno3-solution-is-treated-with-excess-amount-of-hi-gas-to-give-0"> When 10.0 mL of AgNO3 solution is treated with excess amount of HI gas to give 0.235 g of AgI,... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/hydrogen-sulfide-reacts-with-sulfur-dioxide-to-give-h2o-and-s-h2s-so2-h2o-s-soli"> Hydrogen sulfide reacts with sulfur dioxide to give H2O and S, H2S + SO2 = H2O + S(solid),... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-100-ml-of-hcl-gas-at-300-k-and-200-kpa-dissolved-in-pure-water-requires-12-50"> If 100 mL of HCl gas at 300 K and 200 kPa dissolved in pure water requires 12.50 mL of the NaOH... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-100-ml-of-hcl-gas-at-300-k-and-100-kpa-dissolved-in-pure-water-requires-12-50"> If 100 mL of HCl gas at 300 K and 100 kPa dissolved in pure water requires 12.50 mL of the NaOH... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-100-ml-of-hcl-gas-at-300-k-and-100-kpa-dissolve-in-20-ml-of-pure-water-what-i"> If 100 mL of HCl gas at 300 K and 100 kPa dissolve in 20 mL of pure water, what is the concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-2-00-g-mixture-of-na-and-ca-reat-with-water-1-164-l-hydrogen-was-produced-a"> When 2.00 g mixture of Na and Ca reat with water, 1.164 L hydrogen was produced at 300.0 K and... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/stoichiometry-involving-gases"> See all questions in Gas Stoichiometry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 19701 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Assuming all volume measurements are made at the same temperature and pressure, what volume of hydrogen gas is needed to react completely with 4.55 L of oxygen gas to produce water vapor?	null

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