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1,500	aa912ae4-6ddd-11ea-afa3-ccda262736ce	https://socratic.org/questions/56aaba807c01497d213df01f	S + 6 HNO3 -> SO3 + 6 NO2 + 3 H2O	start chemical_equation qc_end substance 2 2 qc_end chemical_equation 6 6 qc_end chemical_equation 11 11 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the equation"}]	[{"type":"chemical equation","value":"S + 6 HNO3 -> SO3 + 6 NO2 + 3 H2O"}]	[{"type":"substance name","value":"Sulfur"},{"type":"chemical equation","value":"SO3"},{"type":"chemical equation","value":"NO3-"}]	<h1 class="questionTitle" itemprop="name">How could sulfur be oxidized to #SO_3# by the action of #NO_3^(-)#?</h1>	null	S + 6 HNO3 -> SO3 + 6 NO2 + 3 H2O	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Oxidation:</p> <p><mathjax>#S +3H_2O rarr SO_3 + 6H^+ + 6e^-#</mathjax> <mathjax>#(i)#</mathjax></p> <p>Zerovalent sulfur is oxidized to <mathjax>#S(VI^+)#</mathjax>.</p> <p>Reduction:</p> <p><mathjax>#NO_3^(-) + 2H^(+) + e^(-) rarr NO_2 + H_2O#</mathjax> <mathjax>#(ii)#</mathjax></p> <p>So, <mathjax>#6xx(ii) + (i)=#</mathjax> </p> <p><mathjax>#S + 6NO_3^(-) + 6H^(+)rarr SO_3 + 6NO_2 + 3H_2O#</mathjax>; alternatively:</p> <p><mathjax>#S + 6HNO_3 rarr SO_3 + 6NO_2 + 3H_2O#</mathjax></p> <p>This is balanced with respect to mass and charge. It would not be a feasible reaction in practical terms. Industrially, sulfur trioxide is produced from sulfur dioxide and oxygen directly with some form of supported catalysis. It must be an incredible dirty and smelly process.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Sulfur is oxidized to sulfur trioxide. Nitric acid is reduced to nitric oxide, <mathjax>#NO_2#</mathjax>. Here, we do NOT use oxygen gas as a reactant, and use standard redox processes. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Oxidation:</p> <p><mathjax>#S +3H_2O rarr SO_3 + 6H^+ + 6e^-#</mathjax> <mathjax>#(i)#</mathjax></p> <p>Zerovalent sulfur is oxidized to <mathjax>#S(VI^+)#</mathjax>.</p> <p>Reduction:</p> <p><mathjax>#NO_3^(-) + 2H^(+) + e^(-) rarr NO_2 + H_2O#</mathjax> <mathjax>#(ii)#</mathjax></p> <p>So, <mathjax>#6xx(ii) + (i)=#</mathjax> </p> <p><mathjax>#S + 6NO_3^(-) + 6H^(+)rarr SO_3 + 6NO_2 + 3H_2O#</mathjax>; alternatively:</p> <p><mathjax>#S + 6HNO_3 rarr SO_3 + 6NO_2 + 3H_2O#</mathjax></p> <p>This is balanced with respect to mass and charge. It would not be a feasible reaction in practical terms. Industrially, sulfur trioxide is produced from sulfur dioxide and oxygen directly with some form of supported catalysis. It must be an incredible dirty and smelly process.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How could sulfur be oxidized to #SO_3# by the action of #NO_3^(-)#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#electrochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Electrochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/electrochemistry/balancing-redox-equations-using-the-oxidation-number-method" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Redox Equations Using the Oxidation Number Method</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="219146" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-30T09:10:13" itemprop="dateCreated"> Jan 30, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Sulfur is oxidized to sulfur trioxide. Nitric acid is reduced to nitric oxide, <mathjax>#NO_2#</mathjax>. Here, we do NOT use oxygen gas as a reactant, and use standard redox processes. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Oxidation:</p> <p><mathjax>#S +3H_2O rarr SO_3 + 6H^+ + 6e^-#</mathjax> <mathjax>#(i)#</mathjax></p> <p>Zerovalent sulfur is oxidized to <mathjax>#S(VI^+)#</mathjax>.</p> <p>Reduction:</p> <p><mathjax>#NO_3^(-) + 2H^(+) + e^(-) rarr NO_2 + H_2O#</mathjax> <mathjax>#(ii)#</mathjax></p> <p>So, <mathjax>#6xx(ii) + (i)=#</mathjax> </p> <p><mathjax>#S + 6NO_3^(-) + 6H^(+)rarr SO_3 + 6NO_2 + 3H_2O#</mathjax>; alternatively:</p> <p><mathjax>#S + 6HNO_3 rarr SO_3 + 6NO_2 + 3H_2O#</mathjax></p> <p>This is balanced with respect to mass and charge. It would not be a feasible reaction in practical terms. Industrially, sulfur trioxide is produced from sulfur dioxide and oxygen directly with some form of supported catalysis. It must be an incredible dirty and smelly process.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/219146" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-balance-redox-reactions-in-basic-solution"> How do you balance redox reactions in basic solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-balance-redox-equations-by-oxidation-number-method"> How do you balance redox equations by oxidation number method? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-balance-redox-equations-in-acidic-solutions"> How do you balance redox equations in acidic solutions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-method"> What is the oxidation number method? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-examples-of-balancing-redox-equations-using-the-oxidation-number-m"> What are some examples of balancing redox equations using the oxidation number method? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-oxidation-number-method-useful"> Why is the oxidation number method useful? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-it-necessary-to-break-the-equation-into-half-reactions-in-the-oxidation-numbe"> Is it necessary to break the equation into half reactions in the oxidation number method? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-difference-between-the-oxidation-number-method-and-the-ion-electron-"> What is the difference between the oxidation number method and the ion-electron method? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-balance-the-equation-using-the-oxidation-states-method-mno2-al-mn-al2o3"> Can you balance the equation using the oxidation states method MnO2+Al--->Mn+Al2O3? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-balance-this-redox-reaction-using-the-oxidation-number-method-fe2-aq-"> How do you balance this redox reaction using the oxidation number method? Fe2+(aq) + MnO4–(aq)... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/electrochemistry/balancing-redox-equations-using-the-oxidation-number-method"> See all questions in Balancing Redox Equations Using the Oxidation Number Method </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1409 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How could sulfur be oxidized to #SO_3# by the action of #NO_3^(-)#?	null
1,501	aa7167ec-6ddd-11ea-a238-ccda262736ce	https://socratic.org/questions/what-is-the-poh-of-a-solution-if-the-oh-33-5-x-10-2-m	0.48	start physical_unit 6 6 poh none qc_end physical_unit 6 6 11 14 [oh-] qc_end end	[{"type":"physical unit","value":"pOH [OF] the solution"}]	[{"type":"physical unit","value":"0.48"}]	[{"type":"physical unit","value":"[OH-] [OF] the solution [=] \\pu{33.5 × 10^(-2) M}"}]	<h1 class="questionTitle" itemprop="name">What is the #"pOH"# of a solution if the #["OH"^-] = 33.5 xx 10^-2# #"M"#? </h1>	null	0.48	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The chemical definition of <mathjax>#"pOH"#</mathjax> or in fact, the <mathjax>#"p"#</mathjax> of any value/constant is given as the cologarithm of that thing. That is the negative (or reciprocal) logarithm of that thing.</p> <p><mathjax>#therefore#</mathjax> <mathjax>#"pOH"=-log["OH"^-]=log(1/(["OH"^-]))#</mathjax></p> <p><mathjax>#"pOH"=-log(3.35xx10^-1)=0.475#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"pOH"=0.475#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The chemical definition of <mathjax>#"pOH"#</mathjax> or in fact, the <mathjax>#"p"#</mathjax> of any value/constant is given as the cologarithm of that thing. That is the negative (or reciprocal) logarithm of that thing.</p> <p><mathjax>#therefore#</mathjax> <mathjax>#"pOH"=-log["OH"^-]=log(1/(["OH"^-]))#</mathjax></p> <p><mathjax>#"pOH"=-log(3.35xx10^-1)=0.475#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the #"pOH"# of a solution if the #["OH"^-] = 33.5 xx 10^-2# #"M"#? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/stoichiometry-with-acid-and-base-dissociation" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry with Acid and Base Dissociation</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="407322" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/abdur-r"><img alt="" class="" src="https://profilepictures.socratic.org/YXIUDMM0SoZAxTdY3kn6_niagara_falls_fog_water_height_6376_3840x2160.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/abdur-r"> Monzur R. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-15T23:52:21" itemprop="dateCreated"> Apr 15, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"pOH"=0.475#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The chemical definition of <mathjax>#"pOH"#</mathjax> or in fact, the <mathjax>#"p"#</mathjax> of any value/constant is given as the cologarithm of that thing. That is the negative (or reciprocal) logarithm of that thing.</p> <p><mathjax>#therefore#</mathjax> <mathjax>#"pOH"=-log["OH"^-]=log(1/(["OH"^-]))#</mathjax></p> <p><mathjax>#"pOH"=-log(3.35xx10^-1)=0.475#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/407322" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/533129fb02bf342f40b5c3cd"> Question #5c3cd </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-common-mistakes-students-make-with-stoichiometry-1"> What are some common mistakes students make with stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-an-example-of-a-stoichiometry-practice-problem-1"> What is an example of a stoichiometry practice problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-examples-of-acid-and-base-dissociation"> What are some examples of acid and base dissociation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-an-example-of-an-acid-and-base-dissociation-practice-problem"> What is an example of an acid and base dissociation practice problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-common-mistakes-students-make-with-acid-and-base-dissociation"> What are some common mistakes students make with acid and base dissociation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stoichiometry-with-acid-and-base-dissociation"> What is stoichiometry with acid and base dissociation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-examples-of-stoichiometry-with-acid-and-base-dissociation"> What are some examples of stoichiometry with acid and base dissociation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-an-example-of-a-stoichiometry-with-acid-and-base-dissociation-practice-p"> What is an example of a stoichiometry with acid and base dissociation practice problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-we-relate-stoichiometry-to-everyday-processes"> How do we relate stoichiometry to everyday processes? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/stoichiometry-with-acid-and-base-dissociation"> See all questions in Stoichiometry with Acid and Base Dissociation </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1410 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the #"pOH"# of a solution if the #["OH"^-] = 33.5 xx 10^-2# #"M"#?	null
1,502	a9908e80-6ddd-11ea-b162-ccda262736ce	https://socratic.org/questions/how-many-oxygen-atoms-are-there-in-one-formula-unit-of-copper-ll-phosphate	8	start physical_unit 2 3 number none qc_end end	[{"type":"physical unit","value":"Number [OF] oxygen atoms"}]	[{"type":"physical unit","value":"8"}]	[{"type":"physical unit","value":"Number [OF] copper(ll) phosphate formula unit [=] \\pu{1}"}]	<h1 class="questionTitle" itemprop="name">How many oxygen atoms are there in one formula unit of copper(ll) phosphate? </h1>	null	8	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Copper(II) phosphate has the formula</p> <p><mathjax>#Cu_3(PO_4)_2#</mathjax></p> <p>The total number of <mathjax>#O#</mathjax> atoms in one formula unit of <mathjax>#Cu_3(PO_4)_2#</mathjax> is <mathjax>#4 xx 2 = 8 #</mathjax> <mathjax>#O#</mathjax> atoms.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#8#</mathjax> <mathjax>#O#</mathjax> atoms</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Copper(II) phosphate has the formula</p> <p><mathjax>#Cu_3(PO_4)_2#</mathjax></p> <p>The total number of <mathjax>#O#</mathjax> atoms in one formula unit of <mathjax>#Cu_3(PO_4)_2#</mathjax> is <mathjax>#4 xx 2 = 8 #</mathjax> <mathjax>#O#</mathjax> atoms.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many oxygen atoms are there in one formula unit of copper(ll) phosphate? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="424725" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/mrtas"><img alt="" class="" src="https://profilepictures.socratic.org/HY14X7r4S6AyDQgK2gwQ_IMG_0062.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/mrtas"> Nathan L. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-17T02:49:21" itemprop="dateCreated"> May 17, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#8#</mathjax> <mathjax>#O#</mathjax> atoms</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Copper(II) phosphate has the formula</p> <p><mathjax>#Cu_3(PO_4)_2#</mathjax></p> <p>The total number of <mathjax>#O#</mathjax> atoms in one formula unit of <mathjax>#Cu_3(PO_4)_2#</mathjax> is <mathjax>#4 xx 2 = 8 #</mathjax> <mathjax>#O#</mathjax> atoms.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/424725" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? 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</a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 8606 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many oxygen atoms are there in one formula unit of copper(ll) phosphate?	null
1,503	ab43a61e-6ddd-11ea-8e4c-ccda262736ce	https://socratic.org/questions/what-is-the-ph-of-a-solution-prepared-by-mixing-50-0-ml-of-0-010-mol-l-hcl-aq-an	11.40	start physical_unit 6 6 ph none qc_end physical_unit 6 6 10 11 volume qc_end physical_unit 15 15 13 14 molarity qc_end physical_unit 6 6 10 11 volume qc_end physical_unit 22 22 13 14 molarity qc_end physical_unit 6 6 27 29 temperature qc_end end	[{"type":"physical unit","value":"pH [OF] the solution"}]	[{"type":"physical unit","value":"11.40"}]	[{"type":"physical unit","value":"Volume [OF] HCl(aq) solution [=] \\pu{50.0 mL}"},{"type":"physical unit","value":"Molarity [OF] HCl(aq) solution [=] \\pu{0.010 mol/L}"},{"type":"physical unit","value":"Volume [OF] Ca(OH)2(aq) solution [=] \\pu{50.0 mL}"},{"type":"physical unit","value":"Molarity [OF] Ca(OH)2(aq) solution [=] \\pu{0.010 mol/L}"},{"type":"physical unit","value":"Temperature [OF] the solution [=] \\pu{25 degrees celcius}"}]	<h1 class="questionTitle" itemprop="name">What is the pH of a solution prepared by mixing 50.0 mL of 0.010 mol/L HCl(aq) and 50.0 mL of 0.010 mol/L Ca(OH)2(aq)? Assume the temperature is 25 degrees celcius. </h1>	null	11.40	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#Ca(OH)_2(aq) + 2HCl(aq) rarr CaCl_2(aq) + 2H_2O(l)#</mathjax>.</p> <p><mathjax>#"Moles of HCl"=50.0xx10^-3Lxx0.010molL^-1=5.00xx10^-4mol#</mathjax>.</p> <p><mathjax>#"Moles of "Ca(OH)_2=50.0xx10^-3Lxx0.010molL^-1=5.00xx10^-4mol#</mathjax>.</p> <p>Now there are EQUIMOLAR quantities of <mathjax>#Ca(OH)_2#</mathjax> and <mathjax>#HCl#</mathjax>.</p> <p>Clearly, at the end of the addition, we have a<mathjax>#100mL#</mathjax> solution that contains, nominally, <mathjax>#Ca(OH)Cl#</mathjax>, i.e. we have added HALF an EQUIV of acid to the base. </p> <p>And thus we have <mathjax>#2.500xx10^-4mol#</mathjax> <mathjax>#HO^-#</mathjax> in <mathjax>#100mL#</mathjax> of solution.</p> <p><mathjax>#[HO^-]=2.50xx10^-4mol*L^-1#</mathjax>.</p> <p><mathjax>#pOH=-log_10([HO^-])=-log_10(2.50xx10^-4)=-(-2.60)=2.60#</mathjax>.</p> <p>But <mathjax>#pH=14-pOH=14-2.60=11.4#</mathjax>.</p> <p>Can you follow this? If no, state your objections, and someone will help you. For another example problem, see <a href="https://socratic.org/questions/what-is-the-ph-of-an-aqueous-solution-if-the-h-0-000001?source=search">here.</a> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#pH=11.4........#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#Ca(OH)_2(aq) + 2HCl(aq) rarr CaCl_2(aq) + 2H_2O(l)#</mathjax>.</p> <p><mathjax>#"Moles of HCl"=50.0xx10^-3Lxx0.010molL^-1=5.00xx10^-4mol#</mathjax>.</p> <p><mathjax>#"Moles of "Ca(OH)_2=50.0xx10^-3Lxx0.010molL^-1=5.00xx10^-4mol#</mathjax>.</p> <p>Now there are EQUIMOLAR quantities of <mathjax>#Ca(OH)_2#</mathjax> and <mathjax>#HCl#</mathjax>.</p> <p>Clearly, at the end of the addition, we have a<mathjax>#100mL#</mathjax> solution that contains, nominally, <mathjax>#Ca(OH)Cl#</mathjax>, i.e. we have added HALF an EQUIV of acid to the base. </p> <p>And thus we have <mathjax>#2.500xx10^-4mol#</mathjax> <mathjax>#HO^-#</mathjax> in <mathjax>#100mL#</mathjax> of solution.</p> <p><mathjax>#[HO^-]=2.50xx10^-4mol*L^-1#</mathjax>.</p> <p><mathjax>#pOH=-log_10([HO^-])=-log_10(2.50xx10^-4)=-(-2.60)=2.60#</mathjax>.</p> <p>But <mathjax>#pH=14-pOH=14-2.60=11.4#</mathjax>.</p> <p>Can you follow this? If no, state your objections, and someone will help you. For another example problem, see <a href="https://socratic.org/questions/what-is-the-ph-of-an-aqueous-solution-if-the-h-0-000001?source=search">here.</a> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the pH of a solution prepared by mixing 50.0 mL of 0.010 mol/L HCl(aq) and 50.0 mL of 0.010 mol/L Ca(OH)2(aq)? Assume the temperature is 25 degrees celcius. </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/ph-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">pH calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="413055" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-26T07:42:40" itemprop="dateCreated"> Apr 26, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#pH=11.4........#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#Ca(OH)_2(aq) + 2HCl(aq) rarr CaCl_2(aq) + 2H_2O(l)#</mathjax>.</p> <p><mathjax>#"Moles of HCl"=50.0xx10^-3Lxx0.010molL^-1=5.00xx10^-4mol#</mathjax>.</p> <p><mathjax>#"Moles of "Ca(OH)_2=50.0xx10^-3Lxx0.010molL^-1=5.00xx10^-4mol#</mathjax>.</p> <p>Now there are EQUIMOLAR quantities of <mathjax>#Ca(OH)_2#</mathjax> and <mathjax>#HCl#</mathjax>.</p> <p>Clearly, at the end of the addition, we have a<mathjax>#100mL#</mathjax> solution that contains, nominally, <mathjax>#Ca(OH)Cl#</mathjax>, i.e. we have added HALF an EQUIV of acid to the base. </p> <p>And thus we have <mathjax>#2.500xx10^-4mol#</mathjax> <mathjax>#HO^-#</mathjax> in <mathjax>#100mL#</mathjax> of solution.</p> <p><mathjax>#[HO^-]=2.50xx10^-4mol*L^-1#</mathjax>.</p> <p><mathjax>#pOH=-log_10([HO^-])=-log_10(2.50xx10^-4)=-(-2.60)=2.60#</mathjax>.</p> <p>But <mathjax>#pH=14-pOH=14-2.60=11.4#</mathjax>.</p> <p>Can you follow this? If no, state your objections, and someone will help you. For another example problem, see <a href="https://socratic.org/questions/what-is-the-ph-of-an-aqueous-solution-if-the-h-0-000001?source=search">here.</a> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/413055" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-of-a-solution"> How do you determine ph of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-at-an-equivalence-point"> How do you determine pH at an equivalence point? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-molarity"> How do you determine pH from molarity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-alkalinity-mean"> What does alkalinity mean? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-base"> What is a base? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-acid-base-indicators-change-color"> How do acid base indicators change color? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-neutral-ph"> What is a neutral pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-alkalinity-affect-pool-water"> How does alkalinity affect pool water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ph-important-in-drinking-water"> Why is pH important in drinking water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-ph-of-solution"> How can I calculate the pH of a solution? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/ph-calculations"> See all questions in pH calculations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 6066 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the pH of a solution prepared by mixing 50.0 mL of 0.010 mol/L HCl(aq) and 50.0 mL of 0.010 mol/L Ca(OH)2(aq)? Assume the temperature is 25 degrees celcius.	null
1,504	a9b2494c-6ddd-11ea-b609-ccda262736ce	https://socratic.org/questions/if-64-grams-of-o-2-gas-occupy-a-volume-of-56-liters-at-a-temperature-or-25-c-wha	0.87 atmosphere	start physical_unit 23 24 pressure atm qc_end physical_unit 4 5 1 2 mass qc_end physical_unit 4 5 10 11 volume qc_end physical_unit 4 5 16 17 temperature qc_end end	[{"type":"physical unit","value":"Pressure [OF] the gas [IN] atmosphere"}]	[{"type":"physical unit","value":"0.87 atmosphere"}]	[{"type":"physical unit","value":"Mass [OF] O2 gas [=] \\pu{64 grams}"},{"type":"physical unit","value":"Volume [OF] O2 gas [=] \\pu{56 liters}"},{"type":"physical unit","value":"Temperature [OF] O2 gas [=] \\pu{25 ℃}"}]	<h1 class="questionTitle" itemprop="name">If 64 grams of #O_2# gas occupy a volume of 56 liters at a temperature or 25°C, what is the pressure of the gas, in atmosphere?</h1>	null	0.87 atmosphere	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use the equation for the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a>.<br/> <img alt="http://imgarcade.com/1/ideal-gas-law-equation/" src="https://useruploads.socratic.org/vDFpoGlzR5yDfn2NW1gh_gaseq0.jpg"/> <br/> Since <a href="https://socratic.org/chemistry/the-behavior-of-gases/gas-laws">gas laws</a> require temperature to be in Kelvins, the Celsius temperature will have to be converted by adding <mathjax>#273.15#</mathjax> to the Celsius temperature.</p> <p>You don't have <mathjax>#n#</mathjax>, but it can be calculated by dividing the given mass of <mathjax>#"O"_2"#</mathjax> by its molar mass: <mathjax>#2xx15.999"g/mol"="31.998 g/mol"#</mathjax></p> <p><mathjax>#n_"oxygen"=(64cancel"g")/(31.998cancel"g"/"1 mol")="2.0 mol O"_2"#</mathjax></p> <p><strong>Known</strong><br/> <mathjax>#n="2.0 mol O"_2"#</mathjax><br/> <mathjax>#V="56 L"#</mathjax><br/> <mathjax>#T="25"^@"C"+273.15="298 K"#</mathjax><br/> <mathjax>#R=0.08206 ("L·atm")/("K·mol")#</mathjax></p> <p><strong>Unknown</strong><br/> <mathjax>#P#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#P#</mathjax>. Substitute the known values into the equation and solve.</p> <p><mathjax>#P=(nRT)/V#</mathjax></p> <p><mathjax>#P=2.0cancel"mol"xx0.08206 (cancel"L"·"atm")/(cancel"K"·cancel"mol")xx(298cancel"K")/(56cancel"L")="0.87 atm"#</mathjax> rounded to two figures</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The pressure of oxygen gas is 0.87 atm.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use the equation for the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a>.<br/> <img alt="http://imgarcade.com/1/ideal-gas-law-equation/" src="https://useruploads.socratic.org/vDFpoGlzR5yDfn2NW1gh_gaseq0.jpg"/> <br/> Since <a href="https://socratic.org/chemistry/the-behavior-of-gases/gas-laws">gas laws</a> require temperature to be in Kelvins, the Celsius temperature will have to be converted by adding <mathjax>#273.15#</mathjax> to the Celsius temperature.</p> <p>You don't have <mathjax>#n#</mathjax>, but it can be calculated by dividing the given mass of <mathjax>#"O"_2"#</mathjax> by its molar mass: <mathjax>#2xx15.999"g/mol"="31.998 g/mol"#</mathjax></p> <p><mathjax>#n_"oxygen"=(64cancel"g")/(31.998cancel"g"/"1 mol")="2.0 mol O"_2"#</mathjax></p> <p><strong>Known</strong><br/> <mathjax>#n="2.0 mol O"_2"#</mathjax><br/> <mathjax>#V="56 L"#</mathjax><br/> <mathjax>#T="25"^@"C"+273.15="298 K"#</mathjax><br/> <mathjax>#R=0.08206 ("L·atm")/("K·mol")#</mathjax></p> <p><strong>Unknown</strong><br/> <mathjax>#P#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#P#</mathjax>. Substitute the known values into the equation and solve.</p> <p><mathjax>#P=(nRT)/V#</mathjax></p> <p><mathjax>#P=2.0cancel"mol"xx0.08206 (cancel"L"·"atm")/(cancel"K"·cancel"mol")xx(298cancel"K")/(56cancel"L")="0.87 atm"#</mathjax> rounded to two figures</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">If 64 grams of #O_2# gas occupy a volume of 56 liters at a temperature or 25°C, what is the pressure of the gas, in atmosphere?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/ideal-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Ideal Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="342435" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-11-27T07:20:05" itemprop="dateCreated"> Nov 27, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The pressure of oxygen gas is 0.87 atm.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use the equation for the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a>.<br/> <img alt="http://imgarcade.com/1/ideal-gas-law-equation/" src="https://useruploads.socratic.org/vDFpoGlzR5yDfn2NW1gh_gaseq0.jpg"/> <br/> Since <a href="https://socratic.org/chemistry/the-behavior-of-gases/gas-laws">gas laws</a> require temperature to be in Kelvins, the Celsius temperature will have to be converted by adding <mathjax>#273.15#</mathjax> to the Celsius temperature.</p> <p>You don't have <mathjax>#n#</mathjax>, but it can be calculated by dividing the given mass of <mathjax>#"O"_2"#</mathjax> by its molar mass: <mathjax>#2xx15.999"g/mol"="31.998 g/mol"#</mathjax></p> <p><mathjax>#n_"oxygen"=(64cancel"g")/(31.998cancel"g"/"1 mol")="2.0 mol O"_2"#</mathjax></p> <p><strong>Known</strong><br/> <mathjax>#n="2.0 mol O"_2"#</mathjax><br/> <mathjax>#V="56 L"#</mathjax><br/> <mathjax>#T="25"^@"C"+273.15="298 K"#</mathjax><br/> <mathjax>#R=0.08206 ("L·atm")/("K·mol")#</mathjax></p> <p><strong>Unknown</strong><br/> <mathjax>#P#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#P#</mathjax>. Substitute the known values into the equation and solve.</p> <p><mathjax>#P=(nRT)/V#</mathjax></p> <p><mathjax>#P=2.0cancel"mol"xx0.08206 (cancel"L"·"atm")/(cancel"K"·cancel"mol")xx(298cancel"K")/(56cancel"L")="0.87 atm"#</mathjax> rounded to two figures</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/342435" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-ideal-gas-constant"> How do you find the ideal gas constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-solve-ideal-gas-law-problems"> How do you solve ideal gas law problems? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-know-which-ideal-gas-constant-to-use"> How do you know which ideal gas constant to use? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ideal-gas-constant-for-butane"> What is the ideal gas constant for butane? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-ideal-gas-law-in-kelvin"> Why is ideal gas law in kelvin? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ideal-gas-constant-important"> Why is the ideal gas constant important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-di-electric-constant"> What is the di-electric constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-volume-l-will-0-20-mol-hi-occupy-at-300-k-and-100-0-kpa-r-8-314-kpa-l-k-mol"> What volume (L) will 0.20 mol HI occupy at 300 K and 100.0 kPa? R = 8.314 kPa L / (K mol) =... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-molar-mass-of-a-gas"> How do you calculate the molar mass of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-should-i-use-the-ideal-gas-law-and-not-the-combined-gas-law"> When should I use the ideal gas law and not the combined gas law? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/ideal-gas-law"> See all questions in Ideal Gas Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3696 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	If 64 grams of #O_2# gas occupy a volume of 56 liters at a temperature or 25°C, what is the pressure of the gas, in atmosphere?	null
1,505	ab44691a-6ddd-11ea-b9e6-ccda262736ce	https://socratic.org/questions/if-the-ph-of-a-solution-is-10-7-what-would-the-poh-be	3.30	start physical_unit 5 5 poh none qc_end physical_unit 5 5 7 7 ph qc_end end	[{"type":"physical unit","value":"pOH [OF] the solution"}]	[{"type":"physical unit","value":"3.30"}]	[{"type":"physical unit","value":"pH [OF] the solution [=] \\pu{10.7}"}]	<h1 class="questionTitle" itemprop="name">If the pH of a solution is 10.7, what would the pOH be? </h1>	null	3.30	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Remember a simple thing that <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a>+pOH=14<br/> so pOH= 14-10.7 = 3.3</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>3.3</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Remember a simple thing that <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a>+pOH=14<br/> so pOH= 14-10.7 = 3.3</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">If the pH of a solution is 10.7, what would the pOH be? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/solutions" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="318569" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/kazi-i"><img alt="" class="" src="https://graph.facebook.com/910141219080809/picture?height=50&width=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/kazi-i"> Kazi Ashiq Iqbal </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-10-06T16:04:26" itemprop="dateCreated"> Oct 6, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>3.3</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Remember a simple thing that <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a>+pOH=14<br/> so pOH= 14-10.7 = 3.3</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/318569" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="318571" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-10-06T16:12:37" itemprop="dateCreated"> Oct 6, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#pOH=3.3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#2H_2O rightleftharpoons H_3O^+ +HO^-#</mathjax></p> <p>At <mathjax>#298*K#</mathjax>, we can write and quantify this equilibrium reaction:</p> <p><mathjax>#K_w=[H_3O^+][HO^-]=10^-14#</mathjax></p> <p>And taking <mathjax>#log_10#</mathjax> of both sides:</p> <p><mathjax>#logK_w=log_(10)[H_3O^+] +log_10[HO^-]=log_(10)10^-14#</mathjax></p> <p>OR <mathjax>#14=-logK_w=-log_(10)[H_3O^+] -log_10[HO^-]#</mathjax></p> <p>But, by definitions, <mathjax>#pH=-log_(10)[H_3O^+]#</mathjax>, and <mathjax>#pOH=-log_(10)[HO^-]#</mathjax>, and <mathjax>#-logK_w=pK_w#</mathjax>.</p> <p>And thus, <mathjax>#pK_w=14=pH+pOH#</mathjax>.</p> <p>Given your question (finally we've got to it!), <mathjax>#pOH=14-pH#</mathjax> <mathjax>#=#</mathjax> <mathjax>#14-10.7=?#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/318571" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-solution-solute-and-solvent-related"> How are solution, solute, and solvent related? 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1,506	abff4622-6ddd-11ea-b3d1-ccda262736ce	https://socratic.org/questions/how-many-grams-are-in-4-5-x-1028-moles-of-sodium-fluoride-naf	3.14 × 10^6 grams	start physical_unit 12 12 mass g qc_end end	[{"type":"physical unit","value":"Mass [OF] NaF [IN] grams"}]	[{"type":"physical unit","value":"3.14 × 10^6 grams"}]	[{"type":"physical unit","value":"Number [OF] NaF molecules [=] \\pu{4.5 × 10^28}"}]	<h1 class="questionTitle" itemprop="name">How many grams are in 4.5 x 1028 moles of sodium fluoride, NaF?</h1>	null	3.14 × 10^6 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>I think your question is, </p> <p><strong>How many grams are in <mathjax>#4.5 xx 10^28#</mathjax> molecules of sodium fluoride, <mathjax>#NaF#</mathjax>?</strong> </p> <p>That's because if you talk about <mathjax>#4.5 x 1028#</mathjax> moles of sodium fluoride, you would get a really absurd number of grams.</p> <p>So, I'd solve your problem assuming your question is <strong>How many grams are in <mathjax>#4.5 xx 10^28#</mathjax> molecules of sodium fluoride, <mathjax>#NaF#</mathjax>?</strong>.</p> <p>In that, we first have to convert the amount of molecules into moles. </p> <p>We know that <mathjax>#1 \ "mol" = 6.0210^23#</mathjax> molecules, so in here, we get</p> <p><mathjax>#(4.510^28cancel"molecules")/(6.0210^23cancel"molecules""/mol")=74750.8306~~74751 \ "mol"#</mathjax> </p> <p>Sodium fluoride has a molar mass of <mathjax>#42 \ "g/mol"#</mathjax>. So, the mass of <mathjax>#74751#</mathjax> moles of sodium fluoride will be</p> <p><mathjax>#42"g/"cancel"mol"74751cancel"mol"=3139542 \ "g"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>I get around <mathjax>#3139542 \ "g"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>I think your question is, </p> <p><strong>How many grams are in <mathjax>#4.5 xx 10^28#</mathjax> molecules of sodium fluoride, <mathjax>#NaF#</mathjax>?</strong> </p> <p>That's because if you talk about <mathjax>#4.5 x 1028#</mathjax> moles of sodium fluoride, you would get a really absurd number of grams.</p> <p>So, I'd solve your problem assuming your question is <strong>How many grams are in <mathjax>#4.5 xx 10^28#</mathjax> molecules of sodium fluoride, <mathjax>#NaF#</mathjax>?</strong>.</p> <p>In that, we first have to convert the amount of molecules into moles. </p> <p>We know that <mathjax>#1 \ "mol" = 6.0210^23#</mathjax> molecules, so in here, we get</p> <p><mathjax>#(4.510^28cancel"molecules")/(6.0210^23cancel"molecules""/mol")=74750.8306~~74751 \ "mol"#</mathjax> </p> <p>Sodium fluoride has a molar mass of <mathjax>#42 \ "g/mol"#</mathjax>. So, the mass of <mathjax>#74751#</mathjax> moles of sodium fluoride will be</p> <p><mathjax>#42"g/"cancel"mol"74751cancel"mol"=3139542 \ "g"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many grams are in 4.5 x 1028 moles of sodium fluoride, NaF?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="554648" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/nam-d"><img alt="" class="" src="https://profilepictures.socratic.org/QG4MnkoER6u99DIDVWKK_787554714770341.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/nam-d"> Nam D. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-02-20T04:04:37" itemprop="dateCreated"> Feb 20, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>I get around <mathjax>#3139542 \ "g"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>I think your question is, </p> <p><strong>How many grams are in <mathjax>#4.5 xx 10^28#</mathjax> molecules of sodium fluoride, <mathjax>#NaF#</mathjax>?</strong> </p> <p>That's because if you talk about <mathjax>#4.5 x 1028#</mathjax> moles of sodium fluoride, you would get a really absurd number of grams.</p> <p>So, I'd solve your problem assuming your question is <strong>How many grams are in <mathjax>#4.5 xx 10^28#</mathjax> molecules of sodium fluoride, <mathjax>#NaF#</mathjax>?</strong>.</p> <p>In that, we first have to convert the amount of molecules into moles. </p> <p>We know that <mathjax>#1 \ "mol" = 6.0210^23#</mathjax> molecules, so in here, we get</p> <p><mathjax>#(4.510^28cancel"molecules")/(6.0210^23cancel"molecules""/mol")=74750.8306~~74751 \ "mol"#</mathjax> </p> <p>Sodium fluoride has a molar mass of <mathjax>#42 \ "g/mol"#</mathjax>. So, the mass of <mathjax>#74751#</mathjax> moles of sodium fluoride will be</p> <p><mathjax>#42"g/"cancel"mol"74751cancel"mol"=3139542 \ "g"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/554648" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 7082 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many grams are in 4.5 x 1028 moles of sodium fluoride, NaF?	null
1,507	ace3a966-6ddd-11ea-b83a-ccda262736ce	https://socratic.org/questions/how-many-liters-are-in-16-grams-of-h-2-at-stp	176.96 liters	start physical_unit 8 8 volume l qc_end physical_unit 8 8 5 6 mass qc_end c_other STP qc_end end	[{"type":"physical unit","value":"Volume [OF] H2 [IN] liters"}]	[{"type":"physical unit","value":"176.96 liters"}]	[{"type":"physical unit","value":"Mass [OF] H2 [=] \\pu{16 grams}"},{"type":"other","value":"STP"}]	<h1 class="questionTitle" itemprop="name">How many liters are in 16 grams of #H_2# at STP?</h1>	null	176.96 liters	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use the ideal gas equation </p> <p><mathjax>#PV = n RT#</mathjax></p> <p>Where:</p> <p><mathjax>#P -> " is the pressure expressed in " atm#</mathjax></p> <p><mathjax>#V -> " is the volume occupied by the gas expressed in "L #</mathjax></p> <p><mathjax>#n-> " is the number of moles of the gas"#</mathjax></p> <p><mathjax># R ->" is the universal gas constant" =0.0821 \ L atmmol^-1 K^-1#</mathjax></p> <p><mathjax># T -> " is the kelvin temperature "#</mathjax></p> <p><mathjax>#-----------------#</mathjax></p> <p><mathjax># S.T.P "conditions" => T = 273 K and P= 1.00 \ atm#</mathjax></p> <p>Rearrange the formula and solve for V.</p> <p><mathjax># V = (n * RT)/P#</mathjax></p> <p>Find the number of moles of the hydrogen gas present in the 16 grams.</p> <p><mathjax>#n_(H_2)= 16 \ g \ H_2xx(1 \ mol. H_2)/(2.016\ g \ H_2)#</mathjax></p> <p><mathjax>#n_(H_2)~=7.9 \ mol.#</mathjax></p> <p><mathjax>#V=(7.9 \ mol. xx 0.0821 \ L atmmol^-1 K^-1xx 273 \ K)/ (1.00 \ atm)#</mathjax></p> <p><mathjax>#V=(7.9 \ cancel(mol.) xx 0.0821 \ L* cancel(atm)cancel(mol^-1)cancel(K^-1)xx 273 \ cancel(K))/ (1.00 \ cancel(atm))#</mathjax></p> <p><mathjax>#V~=1.8xx10^2\ L#</mathjax></p> <p><mathjax>#--------------------#</mathjax></p> <p>A quick approach</p> <p>At S.T.P you can use the following formula:</p> <p><mathjax># n_(H_2)= V/V_M#</mathjax></p> <p><mathjax># n_(H_2) " is the number of moles of the gas." #</mathjax></p> <p><mathjax>#V " is Volume of the gas under S.T.P conditions"#</mathjax></p> <p><mathjax># V_M" is the molar volume i.e the volume occupied by 1 mole of "#</mathjax><br/> <mathjax># "any gas under S.T.P conditions, equal to 22.4 L/mol."#</mathjax></p> <p><mathjax>#n_(H_2)= 16 \ g \ H_2xx(1 \ mol. H_2)/(2.016\ g \ H_2)#</mathjax></p> <p><mathjax>#n_(H_2)~=7.9 \ mol.#</mathjax></p> <p><mathjax># V = n_(H_2)xxV_M#</mathjax></p> <p><mathjax># V = 7.9 \ mol xx 22.4 L* mol^-1#</mathjax></p> <p><mathjax>#V~=1.8xx10^2\ L#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#V~=1.8xx10^2\ L#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use the ideal gas equation </p> <p><mathjax>#PV = n RT#</mathjax></p> <p>Where:</p> <p><mathjax>#P -> " is the pressure expressed in " atm#</mathjax></p> <p><mathjax>#V -> " is the volume occupied by the gas expressed in "L #</mathjax></p> <p><mathjax>#n-> " is the number of moles of the gas"#</mathjax></p> <p><mathjax># R ->" is the universal gas constant" =0.0821 \ L atmmol^-1 K^-1#</mathjax></p> <p><mathjax># T -> " is the kelvin temperature "#</mathjax></p> <p><mathjax>#-----------------#</mathjax></p> <p><mathjax># S.T.P "conditions" => T = 273 K and P= 1.00 \ atm#</mathjax></p> <p>Rearrange the formula and solve for V.</p> <p><mathjax># V = (n * RT)/P#</mathjax></p> <p>Find the number of moles of the hydrogen gas present in the 16 grams.</p> <p><mathjax>#n_(H_2)= 16 \ g \ H_2xx(1 \ mol. H_2)/(2.016\ g \ H_2)#</mathjax></p> <p><mathjax>#n_(H_2)~=7.9 \ mol.#</mathjax></p> <p><mathjax>#V=(7.9 \ mol. xx 0.0821 \ L atmmol^-1 K^-1xx 273 \ K)/ (1.00 \ atm)#</mathjax></p> <p><mathjax>#V=(7.9 \ cancel(mol.) xx 0.0821 \ L* cancel(atm)cancel(mol^-1)cancel(K^-1)xx 273 \ cancel(K))/ (1.00 \ cancel(atm))#</mathjax></p> <p><mathjax>#V~=1.8xx10^2\ L#</mathjax></p> <p><mathjax>#--------------------#</mathjax></p> <p>A quick approach</p> <p>At S.T.P you can use the following formula:</p> <p><mathjax># n_(H_2)= V/V_M#</mathjax></p> <p><mathjax># n_(H_2) " is the number of moles of the gas." #</mathjax></p> <p><mathjax>#V " is Volume of the gas under S.T.P conditions"#</mathjax></p> <p><mathjax># V_M" is the molar volume i.e the volume occupied by 1 mole of "#</mathjax><br/> <mathjax># "any gas under S.T.P conditions, equal to 22.4 L/mol."#</mathjax></p> <p><mathjax>#n_(H_2)= 16 \ g \ H_2xx(1 \ mol. H_2)/(2.016\ g \ H_2)#</mathjax></p> <p><mathjax>#n_(H_2)~=7.9 \ mol.#</mathjax></p> <p><mathjax># V = n_(H_2)xxV_M#</mathjax></p> <p><mathjax># V = 7.9 \ mol xx 22.4 L* mol^-1#</mathjax></p> <p><mathjax>#V~=1.8xx10^2\ L#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many liters are in 16 grams of #H_2# at STP?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp" itemprop="url"> <span class="breadcrumb" itemprop="title">Molar Volume of a Gas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="278186" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/sam-54"><img alt="" class="" src="https://profilepictures.socratic.org/3bkyAGe2RVWw1lx2h1A5_Avatar%201.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/sam-54"> Sam </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-16T21:09:26" itemprop="dateCreated"> Jun 16, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#V~=1.8xx10^2\ L#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use the ideal gas equation </p> <p><mathjax>#PV = n RT#</mathjax></p> <p>Where:</p> <p><mathjax>#P -> " is the pressure expressed in " atm#</mathjax></p> <p><mathjax>#V -> " is the volume occupied by the gas expressed in "L #</mathjax></p> <p><mathjax>#n-> " is the number of moles of the gas"#</mathjax></p> <p><mathjax># R ->" is the universal gas constant" =0.0821 \ L atmmol^-1 K^-1#</mathjax></p> <p><mathjax># T -> " is the kelvin temperature "#</mathjax></p> <p><mathjax>#-----------------#</mathjax></p> <p><mathjax># S.T.P "conditions" => T = 273 K and P= 1.00 \ atm#</mathjax></p> <p>Rearrange the formula and solve for V.</p> <p><mathjax># V = (n * RT)/P#</mathjax></p> <p>Find the number of moles of the hydrogen gas present in the 16 grams.</p> <p><mathjax>#n_(H_2)= 16 \ g \ H_2xx(1 \ mol. H_2)/(2.016\ g \ H_2)#</mathjax></p> <p><mathjax>#n_(H_2)~=7.9 \ mol.#</mathjax></p> <p><mathjax>#V=(7.9 \ mol. xx 0.0821 \ L atmmol^-1 K^-1xx 273 \ K)/ (1.00 \ atm)#</mathjax></p> <p><mathjax>#V=(7.9 \ cancel(mol.) xx 0.0821 \ L* cancel(atm)cancel(mol^-1)cancel(K^-1)xx 273 \ cancel(K))/ (1.00 \ cancel(atm))#</mathjax></p> <p><mathjax>#V~=1.8xx10^2\ L#</mathjax></p> <p><mathjax>#--------------------#</mathjax></p> <p>A quick approach</p> <p>At S.T.P you can use the following formula:</p> <p><mathjax># n_(H_2)= V/V_M#</mathjax></p> <p><mathjax># n_(H_2) " is the number of moles of the gas." #</mathjax></p> <p><mathjax>#V " is Volume of the gas under S.T.P conditions"#</mathjax></p> <p><mathjax># V_M" is the molar volume i.e the volume occupied by 1 mole of "#</mathjax><br/> <mathjax># "any gas under S.T.P conditions, equal to 22.4 L/mol."#</mathjax></p> <p><mathjax>#n_(H_2)= 16 \ g \ H_2xx(1 \ mol. H_2)/(2.016\ g \ H_2)#</mathjax></p> <p><mathjax>#n_(H_2)~=7.9 \ mol.#</mathjax></p> <p><mathjax># V = n_(H_2)xxV_M#</mathjax></p> <p><mathjax># V = 7.9 \ mol xx 22.4 L* mol^-1#</mathjax></p> <p><mathjax>#V~=1.8xx10^2\ L#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/278186" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-stoichiometric-ratios-relate-to-molar-volume-of-a-gas"> How do stoichiometric ratios relate to molar volume of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-a-gas-at-stp"> How do you calculate molar volume of a gas at STP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-molar-volume-of-hydrogen-gas"> How do you find the molar volume of hydrogen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-oxygen-gas"> How do you calculate molar volume of oxygen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molar-gas-volume"> What is molar gas volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/534c7bf202bf3420a007f014"> What is the volume at 0 °C and 1 atm of a mixture that contains 4.0 g of methane and 2.0 g of helium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5361f75702bf3429040e0599"> What is the difference between STP and NTP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-volume-of-25-moles-of-oxygen-o2-gas"> What is the volume of .25 moles of oxygen (O2) Gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-would-knowing-the-molar-volume-of-a-gas-be-important"> Why would knowing the molar volume of a gas be important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-22-4-liters-called-the-molar-volume-of-a-gas"> Why is 22.4 liters called the molar volume of a gas? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp"> See all questions in Molar Volume of a Gas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3956 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many liters are in 16 grams of #H_2# at STP?	null
1,508	a83b777a-6ddd-11ea-a126-ccda262736ce	https://socratic.org/questions/you-have-a-freshly-prepared-01-m-ascorbic-acid-vitamin-c-solution-each-liter-of-	6 × 10^21	start physical_unit 20 22 number none qc_end physical_unit 9 10 5 6 molarity qc_end end	[{"type":"physical unit","value":"Number [OF] ascorbic acid molecules"}]	[{"type":"physical unit","value":"6 × 10^21"}]	[{"type":"physical unit","value":"Molarity [OF] vitamin C solution [=] \\pu{0.01 M}"},{"type":"physical unit","value":"Volume [OF] vitamin C solution [=] \\pu{1 liter}"}]	<h1 class="questionTitle" itemprop="name">You have a freshly prepared .01 M ascorbic acid (vitamin C) solution. Each liter of this solution contains how many ascorbic acid molecules? </h1>	null	6 × 10^21	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to be able to find the number of <em>molecules</em> of ascorbic acid you get <em>per liter</em> of that solution, you need to know how many moles of ascorbic acid you have <em>per liter</em> of solution. </p> <p>Notice that the problem gives you the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of the solution, which is defined as the moles of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a>, in your case ascorbic acid, divided by liters of solution. </p> <blockquote> <p><mathjax>#color(blue)("molarity" = "moles of solute"/"liters of solution")#</mathjax></p> </blockquote> <p>Since your solution has a <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of <mathjax>#"0.01 moles/L"#</mathjax>, it follows that <em>every liter</em> will contain <strong>exactly</strong> <mathjax>#"0.01 moles"#</mathjax> of ascorbic acid. </p> <p>Now, you know that one mole of any substance contains exactly <mathjax>#6.022 * 10^(23)#</mathjax> molecules of that substance - this is known as <strong>Avogadro's number</strong>. </p> <p>In your case, <mathjax>#0.01#</mathjax> moles would contain </p> <blockquote> <p><mathjax>#0.01color(red)(cancel(color(black)("moles"))) * (6.022 * 10^(23)"molecules")/(1color(red)(cancel(color(black)("mole")))) = 6.022 * 10^(21)"molecules"#</mathjax></p> </blockquote> <p>Rounded to one <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig fig</a>, the answer will be </p> <blockquote> <p><mathjax>#"no. of molecules" = color(green)(6 * 10^(21)"molecules")#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#6 * 10^(21) "molecules"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to be able to find the number of <em>molecules</em> of ascorbic acid you get <em>per liter</em> of that solution, you need to know how many moles of ascorbic acid you have <em>per liter</em> of solution. </p> <p>Notice that the problem gives you the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of the solution, which is defined as the moles of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a>, in your case ascorbic acid, divided by liters of solution. </p> <blockquote> <p><mathjax>#color(blue)("molarity" = "moles of solute"/"liters of solution")#</mathjax></p> </blockquote> <p>Since your solution has a <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of <mathjax>#"0.01 moles/L"#</mathjax>, it follows that <em>every liter</em> will contain <strong>exactly</strong> <mathjax>#"0.01 moles"#</mathjax> of ascorbic acid. </p> <p>Now, you know that one mole of any substance contains exactly <mathjax>#6.022 * 10^(23)#</mathjax> molecules of that substance - this is known as <strong>Avogadro's number</strong>. </p> <p>In your case, <mathjax>#0.01#</mathjax> moles would contain </p> <blockquote> <p><mathjax>#0.01color(red)(cancel(color(black)("moles"))) * (6.022 * 10^(23)"molecules")/(1color(red)(cancel(color(black)("mole")))) = 6.022 * 10^(21)"molecules"#</mathjax></p> </blockquote> <p>Rounded to one <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig fig</a>, the answer will be </p> <blockquote> <p><mathjax>#"no. of molecules" = color(green)(6 * 10^(21)"molecules")#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">You have a freshly prepared .01 M ascorbic acid (vitamin C) solution. Each liter of this solution contains how many ascorbic acid molecules? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="181743" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-01T03:52:10" itemprop="dateCreated"> Nov 1, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#6 * 10^(21) "molecules"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to be able to find the number of <em>molecules</em> of ascorbic acid you get <em>per liter</em> of that solution, you need to know how many moles of ascorbic acid you have <em>per liter</em> of solution. </p> <p>Notice that the problem gives you the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of the solution, which is defined as the moles of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a>, in your case ascorbic acid, divided by liters of solution. </p> <blockquote> <p><mathjax>#color(blue)("molarity" = "moles of solute"/"liters of solution")#</mathjax></p> </blockquote> <p>Since your solution has a <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of <mathjax>#"0.01 moles/L"#</mathjax>, it follows that <em>every liter</em> will contain <strong>exactly</strong> <mathjax>#"0.01 moles"#</mathjax> of ascorbic acid. </p> <p>Now, you know that one mole of any substance contains exactly <mathjax>#6.022 * 10^(23)#</mathjax> molecules of that substance - this is known as <strong>Avogadro's number</strong>. </p> <p>In your case, <mathjax>#0.01#</mathjax> moles would contain </p> <blockquote> <p><mathjax>#0.01color(red)(cancel(color(black)("moles"))) * (6.022 * 10^(23)"molecules")/(1color(red)(cancel(color(black)("mole")))) = 6.022 * 10^(21)"molecules"#</mathjax></p> </blockquote> <p>Rounded to one <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig fig</a>, the answer will be </p> <blockquote> <p><mathjax>#"no. of molecules" = color(green)(6 * 10^(21)"molecules")#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/181743" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? 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</a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3610 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	You have a freshly prepared .01 M ascorbic acid (vitamin C) solution. Each liter of this solution contains how many ascorbic acid molecules?	null
1,509	ab802627-6ddd-11ea-91a1-ccda262736ce	https://socratic.org/questions/when-heated-solid-copper-ii-carbonate-decomposes-to-solid-copper-ii-oxide-and-ca	CuCO3(s) ->[\Delta] CuO(s) + CO2(g)	start chemical_equation qc_end substance 2 4 qc_end substance 7 9 qc_end substance 11 13 qc_end end	[{"type":"other","value":"Chemical Equation [OF] this reaction"}]	[{"type":"chemical equation","value":"CuCO3(s) ->[\\Delta] CuO(s) + CO2(g)"}]	[{"type":"substance name","value":"Solid copper(II) carbonate"},{"type":"substance name","value":"Solid copper(II) oxide"},{"type":"substance name","value":"Carbon dioxide gas"}]	<h1 class="questionTitle" itemprop="name">When heated, solid copper(II) carbonate decomposes to solid copper(II) oxide and carbon dioxide gas. What is the chemical equation (including phases) that describes this reaction?</h1>	null	CuCO3(s) ->[\Delta] CuO(s) + CO2(g)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This reaction is balanced with respect to mass and charge; as indeed it must be if it reflects chemical reality. Most carbonates undergo this decomposition, provided you supply enuff heat to the reaction. </p> <p>Typically, we would fiercely heat the copper carbonate in a vessel whose outflow was bled into a solution of limewater, <mathjax>#Ca(OH)_2(aq)#</mathjax>. The liberated carbon dioxide would react with the calcium hydroxide to form a carbonate:</p> <p><mathjax>#Ca(OH)_2(aq) + CO_2(g) rarr CaCO_3(s)darr + H_2O(l)#</mathjax></p> <p>If you were careful, you would see a fine white precipitate of calcium carbonate form in the second flask. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#CuCO_3(s) + Delta rarr CuO(s) + CO_2(g)uarr#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This reaction is balanced with respect to mass and charge; as indeed it must be if it reflects chemical reality. Most carbonates undergo this decomposition, provided you supply enuff heat to the reaction. </p> <p>Typically, we would fiercely heat the copper carbonate in a vessel whose outflow was bled into a solution of limewater, <mathjax>#Ca(OH)_2(aq)#</mathjax>. The liberated carbon dioxide would react with the calcium hydroxide to form a carbonate:</p> <p><mathjax>#Ca(OH)_2(aq) + CO_2(g) rarr CaCO_3(s)darr + H_2O(l)#</mathjax></p> <p>If you were careful, you would see a fine white precipitate of calcium carbonate form in the second flask. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">When heated, solid copper(II) carbonate decomposes to solid copper(II) oxide and carbon dioxide gas. What is the chemical equation (including phases) that describes this reaction?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="463851" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-14T08:36:37" itemprop="dateCreated"> Aug 14, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#CuCO_3(s) + Delta rarr CuO(s) + CO_2(g)uarr#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This reaction is balanced with respect to mass and charge; as indeed it must be if it reflects chemical reality. Most carbonates undergo this decomposition, provided you supply enuff heat to the reaction. </p> <p>Typically, we would fiercely heat the copper carbonate in a vessel whose outflow was bled into a solution of limewater, <mathjax>#Ca(OH)_2(aq)#</mathjax>. The liberated carbon dioxide would react with the calcium hydroxide to form a carbonate:</p> <p><mathjax>#Ca(OH)_2(aq) + CO_2(g) rarr CaCO_3(s)darr + H_2O(l)#</mathjax></p> <p>If you were careful, you would see a fine white precipitate of calcium carbonate form in the second flask. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/463851" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-equation-for-photosynthesis"> What is the chemical equation for photosynthesis? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-know-the-relative-number-of-grams-of-each-substance-used-or-produced-w"> How can I know the relative number of grams of each substance used or produced with chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-know-the-relative-number-of-moles-of-each-substance-with-chemical-equa"> How can I know the relative number of moles of each substance with chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-chemical-equations-illustrate-that-atoms-are-conserved-1"> How do chemical equations illustrate that atoms are conserved? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-know-the-formula-of-the-reactants-and-products-with-chemical-equations"> How can I know the formula of the reactants and products with chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-potassium-metal-and-chlorine-gas-combi"> How can I balance this chemical equations? 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What is the chemical equation (including phases) that describes this reaction?	null
1,510	a993d114-6ddd-11ea-87b2-ccda262736ce	https://socratic.org/questions/a-chemist-has-400-grams-of-salt-solution-that-is-10-salt-how-many-grams-of-20-sa	100 grams	start physical_unit 6 7 mass g qc_end physical_unit 6 7 3 4 mass qc_end physical_unit 6 6 10 10 percent qc_end physical_unit 6 6 16 16 percent qc_end physical_unit 6 6 25 25 percent qc_end end	[{"type":"physical unit","value":"Mass2 [OF] salt solution [IN] grams"}]	[{"type":"physical unit","value":"100 grams"}]	[{"type":"physical unit","value":"Mass1 [OF] salt solution [=] \\pu{400 grams}"},{"type":"physical unit","value":"Percent1 [OF] salt in solution [=] \\pu{10%}"},{"type":"physical unit","value":"Percent2 [OF] salt in solution [=] \\pu{20%}"},{"type":"physical unit","value":"Percent3 [OF] salt in solution [=] \\pu{12%}"}]	<h1 class="questionTitle" itemprop="name">A chemist has 400 grams of salt solution that is 10% salt. How many grams of 20% salt solution must be added to obtain a 12% solution of salt?</h1>	null	100 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So, you're dealing with two salt <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> of different <a href="http://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentrations by mass</a>. </p> <p>Start by calculating how much salt you get in the 400-g sample of the 10% solution. </p> <p><mathjax>#m_"salt"/m_"solution" * 100 = 10%#</mathjax></p> <p><mathjax>#m_"salt" = (10 * m_"solution")/100#</mathjax></p> <p><mathjax>#m_"salt" = (10 * 400)/100 = "40 g salt"#</mathjax></p> <p>Now, let's say that the mass of the 20% solution needed is equal to <mathjax>#x#</mathjax> grams. SInce this solution has <strong>20 g</strong> of salt for every <strong>100 g</strong> of solution, you can say that </p> <p><mathjax>#xcolor(red)(cancel(color(black)("g solution"))) * "20 g salt"/(100color(red)(cancel(color(black)("g solution")))) = 20/100x = x/5" g salt"#</mathjax></p> <p>The <em>taol mass of the salt</em> in the target 12% solution will be </p> <p><mathjax>#m_"salt" = 40 + x/5#</mathjax></p> <p>The <em>total mass of the target solution</em> will be </p> <p><mathjax>#m_"sol" = 400 + x#</mathjax></p> <p>This means that you can write </p> <p><mathjax>#((40 + x/5)"g salt")/((400 + x)" g solution") * 100 = 12%#</mathjax></p> <p>Rearrange and solve this equation for <mathjax>#x#</mathjax> to get</p> <p><mathjax>#(40 + x/5) * 100 = 12 * (400 + x)#</mathjax></p> <p><mathjax>#4000 + 20x = 4800 + 12x#</mathjax></p> <p><mathjax>#8x = 800 => x = 800/8 = color(green)("100 g")#</mathjax></p> <p>This means that if you add <strong>100 g</strong> of the 20% solution to <strong>400g</strong> of the 10% solution, you will get <strong>500 g</strong> of a 12% salt solution.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>You need to add <strong>100 g</strong> of the 20% salt solution. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So, you're dealing with two salt <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> of different <a href="http://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentrations by mass</a>. </p> <p>Start by calculating how much salt you get in the 400-g sample of the 10% solution. </p> <p><mathjax>#m_"salt"/m_"solution" * 100 = 10%#</mathjax></p> <p><mathjax>#m_"salt" = (10 * m_"solution")/100#</mathjax></p> <p><mathjax>#m_"salt" = (10 * 400)/100 = "40 g salt"#</mathjax></p> <p>Now, let's say that the mass of the 20% solution needed is equal to <mathjax>#x#</mathjax> grams. SInce this solution has <strong>20 g</strong> of salt for every <strong>100 g</strong> of solution, you can say that </p> <p><mathjax>#xcolor(red)(cancel(color(black)("g solution"))) * "20 g salt"/(100color(red)(cancel(color(black)("g solution")))) = 20/100x = x/5" g salt"#</mathjax></p> <p>The <em>taol mass of the salt</em> in the target 12% solution will be </p> <p><mathjax>#m_"salt" = 40 + x/5#</mathjax></p> <p>The <em>total mass of the target solution</em> will be </p> <p><mathjax>#m_"sol" = 400 + x#</mathjax></p> <p>This means that you can write </p> <p><mathjax>#((40 + x/5)"g salt")/((400 + x)" g solution") * 100 = 12%#</mathjax></p> <p>Rearrange and solve this equation for <mathjax>#x#</mathjax> to get</p> <p><mathjax>#(40 + x/5) * 100 = 12 * (400 + x)#</mathjax></p> <p><mathjax>#4000 + 20x = 4800 + 12x#</mathjax></p> <p><mathjax>#8x = 800 => x = 800/8 = color(green)("100 g")#</mathjax></p> <p>This means that if you add <strong>100 g</strong> of the 20% solution to <strong>400g</strong> of the 10% solution, you will get <strong>500 g</strong> of a 12% salt solution.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A chemist has 400 grams of salt solution that is 10% salt. How many grams of 20% salt solution must be added to obtain a 12% solution of salt?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/percent-concentration" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Concentration</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="162302" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-08-05T13:47:01" itemprop="dateCreated"> Aug 5, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>You need to add <strong>100 g</strong> of the 20% salt solution. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So, you're dealing with two salt <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> of different <a href="http://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentrations by mass</a>. </p> <p>Start by calculating how much salt you get in the 400-g sample of the 10% solution. </p> <p><mathjax>#m_"salt"/m_"solution" * 100 = 10%#</mathjax></p> <p><mathjax>#m_"salt" = (10 * m_"solution")/100#</mathjax></p> <p><mathjax>#m_"salt" = (10 * 400)/100 = "40 g salt"#</mathjax></p> <p>Now, let's say that the mass of the 20% solution needed is equal to <mathjax>#x#</mathjax> grams. SInce this solution has <strong>20 g</strong> of salt for every <strong>100 g</strong> of solution, you can say that </p> <p><mathjax>#xcolor(red)(cancel(color(black)("g solution"))) * "20 g salt"/(100color(red)(cancel(color(black)("g solution")))) = 20/100x = x/5" g salt"#</mathjax></p> <p>The <em>taol mass of the salt</em> in the target 12% solution will be </p> <p><mathjax>#m_"salt" = 40 + x/5#</mathjax></p> <p>The <em>total mass of the target solution</em> will be </p> <p><mathjax>#m_"sol" = 400 + x#</mathjax></p> <p>This means that you can write </p> <p><mathjax>#((40 + x/5)"g salt")/((400 + x)" g solution") * 100 = 12%#</mathjax></p> <p>Rearrange and solve this equation for <mathjax>#x#</mathjax> to get</p> <p><mathjax>#(40 + x/5) * 100 = 12 * (400 + x)#</mathjax></p> <p><mathjax>#4000 + 20x = 4800 + 12x#</mathjax></p> <p><mathjax>#8x = 800 => x = 800/8 = color(green)("100 g")#</mathjax></p> <p>This means that if you add <strong>100 g</strong> of the 20% solution to <strong>400g</strong> of the 10% solution, you will get <strong>500 g</strong> of a 12% salt solution.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/162302" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-concentration-of-water-in-solution-be-decreased"> How can the concentration of water in solution be decreased? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-concentration-of-a-solution-be-increased"> How can the concentration of a solution be increased? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-concentration-of-a-solution-in-ppm"> How do you find the concentration of a solution in ppm? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-make-a-10-percent-solution"> How do you make a 10 percent solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-make-a-2-percent-solution"> How do you make a 2 percent solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-weight-per-volume-method-to-calculate-concentration"> What is the weight per volume method to calculate concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-percent-concentration-of-kcl-would-be-isotonic"> What percent concentration of KCl would be isotonic? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-of-sodium-chloride-in-normal-saline"> What is the percent concentration of sodium chloride in normal saline? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-of-a-6m-solution-of-nacl"> What is the percent concentration of a 6m solution of NaCl? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-formula"> What is the percent concentration formula? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/percent-concentration"> See all questions in Percent Concentration </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 8816 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A chemist has 400 grams of salt solution that is 10% salt. How many grams of 20% salt solution must be added to obtain a 12% solution of salt?	null
1,511	abe62bc5-6ddd-11ea-8ae2-ccda262736ce	https://socratic.org/questions/what-is-the-ph-of-0-09-m-solution-of-hbr-hydrobromic-acid	1.05	start physical_unit 7 7 ph none qc_end physical_unit 9 9 5 6 molarity qc_end end	[{"type":"physical unit","value":"pH [OF] HBr solution"}]	[{"type":"physical unit","value":"1.05"}]	[{"type":"physical unit","value":"Molarity [OF] HBr solution [=] \\pu{0.09 M}"}]	<h1 class="questionTitle" itemprop="name">What is the pH of 0.09 M solution of HBr (hydrobromic acid)? </h1>	null	1.05	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#pH = -log[H_3O^+] = - log [H^+]#</mathjax></p> <p>HBr is a strong acid in aqueous media therefore it ionizes 100%.<br/> This means that 0.09M HBr => 0.09M H + 0.09M Br</p> <p>pH = -log[H] = -log(0.09) = 1.05</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> of 0.09M HNr => 1.05</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#pH = -log[H_3O^+] = - log [H^+]#</mathjax></p> <p>HBr is a strong acid in aqueous media therefore it ionizes 100%.<br/> This means that 0.09M HBr => 0.09M H + 0.09M Br</p> <p>pH = -log[H] = -log(0.09) = 1.05</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the pH of 0.09 M solution of HBr (hydrobromic acid)? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/the-ph-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">pH</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="432947" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/doc048"><img alt="" class="" src="https://profilepictures.socratic.org/e4gaeUMMQESTpfte6aRu_Friendly%20Chem%20Professor.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/doc048"> Doc048 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-01T07:11:14" itemprop="dateCreated"> Jun 1, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> of 0.09M HNr => 1.05</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#pH = -log[H_3O^+] = - log [H^+]#</mathjax></p> <p>HBr is a strong acid in aqueous media therefore it ionizes 100%.<br/> This means that 0.09M HBr => 0.09M H + 0.09M Br</p> <p>pH = -log[H] = -log(0.09) = 1.05</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/432947" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-pka"> How do you determine pH from pKa? 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</a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ph-scale-0-14"> Why is the pH scale 0-14? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-ph-the-measure-of-the-hydrogen-ion-concentration"> Is pH a measure of the hydrogen ion concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-solubility-affect-ph"> How does solubility affect pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-ph-relate-to-pka-in-a-titration"> How does pH relate to pKa in a titration? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/the-ph-concept"> See all questions in pH </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 40566 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the pH of 0.09 M solution of HBr (hydrobromic acid)?	null
1,512	acaca6c8-6ddd-11ea-afe0-ccda262736ce	https://socratic.org/questions/55d00af6581e2a25d0370bc6	100.84 grams	start physical_unit 18 18 theoretical_yield g qc_end physical_unit 4 4 1 2 mass qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Theoretical yield [OF] H2(g) [IN] grams"}]	[{"type":"physical unit","value":"100.84 grams"}]	[{"type":"physical unit","value":"Mass [OF] Na(s) [=] \\pu{2300.0 g}"},{"type":"other","value":"Sufficient amount of water."}]	<h1 class="questionTitle" itemprop="name">If #"2300.0 g"# of #"Na"(s)# reacts in a sufficient amount of water, what is the theoretical yield of #"H"_2(g)# in grams?</h1>	null	100.84 grams	<div class="answerDescription"> <div> <div class="markdown"><p>Sodium metal <mathjax>#(Na(s))#</mathjax> reacts in a <strong>single-replacement reaction</strong>, like so (I'll break it down into steps, where the middle dots mean there's a lone electron, and <mathjax>#=>#</mathjax> means the reaction step is taken as-written):</p> <blockquote> <p><mathjax>#1. H-OH(l) => Hcdot(g) + cancel(cdotOH(aq))#</mathjax><br/> <mathjax>#2. Nacdot(s) + cancel(cdotOH(aq)) => NaOH(aq)#</mathjax></p> <p><mathjax>#1.#</mathjax> The <mathjax>#H-OH#</mathjax> bond is split in two. This is a violent step, and in real life there's bubbling in the water!<br/> <mathjax>#2.#</mathjax> <mathjax>#Nacdot#</mathjax> then bonds with <mathjax>#cdotOH#</mathjax>.</p> </blockquote> <p>Overall, we get the product of a (radical) <strong>single-replacement reaction</strong>:</p> <blockquote> <p><mathjax>#color(green)(Nacdot(s) + H_2O(l) -> NaOH(aq) + Hcdot(g))#</mathjax></p> <p>or</p> <p><mathjax>#color(green)(2Na(s) + 2H_2O(l) -> 2NaOH(aq) + H_2(g))#</mathjax></p> </blockquote> <p>The first obvious piece of information is that your <a href="http://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a> is sodium metal (since the water is in <strong>excess</strong>), so you can use that as the starting compound for your "mole-bridge" <mathjax>#("g"_1->"mol"_1/"g"_1->"mol"_2/"mol"_1->"g"_2/"mol"_2)#</mathjax> conversion.</p> <p>Now, since we have <mathjax>#2300.0"g"#</mathjax> of Na (that's going to be rather expensive... and explosive! Don't try this at home!):</p> <blockquote> <p><mathjax>#2300.0cancel(g Na) * (cancel(1 mol Na))/(22.989 cancel(g Na)) * (cancel(1 mol H))/(cancel(1 mol Na)) * (1.0079 g H)/(cancel(1 mol H))#</mathjax></p> <p><mathjax>#= color(blue)(100.84 "g" H(g))#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerDescription"> <div> <div class="markdown"><p>Sodium metal <mathjax>#(Na(s))#</mathjax> reacts in a <strong>single-replacement reaction</strong>, like so (I'll break it down into steps, where the middle dots mean there's a lone electron, and <mathjax>#=>#</mathjax> means the reaction step is taken as-written):</p> <blockquote> <p><mathjax>#1. H-OH(l) => Hcdot(g) + cancel(cdotOH(aq))#</mathjax><br/> <mathjax>#2. Nacdot(s) + cancel(cdotOH(aq)) => NaOH(aq)#</mathjax></p> <p><mathjax>#1.#</mathjax> The <mathjax>#H-OH#</mathjax> bond is split in two. This is a violent step, and in real life there's bubbling in the water!<br/> <mathjax>#2.#</mathjax> <mathjax>#Nacdot#</mathjax> then bonds with <mathjax>#cdotOH#</mathjax>.</p> </blockquote> <p>Overall, we get the product of a (radical) <strong>single-replacement reaction</strong>:</p> <blockquote> <p><mathjax>#color(green)(Nacdot(s) + H_2O(l) -> NaOH(aq) + Hcdot(g))#</mathjax></p> <p>or</p> <p><mathjax>#color(green)(2Na(s) + 2H_2O(l) -> 2NaOH(aq) + H_2(g))#</mathjax></p> </blockquote> <p>The first obvious piece of information is that your <a href="http://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a> is sodium metal (since the water is in <strong>excess</strong>), so you can use that as the starting compound for your "mole-bridge" <mathjax>#("g"_1->"mol"_1/"g"_1->"mol"_2/"mol"_1->"g"_2/"mol"_2)#</mathjax> conversion.</p> <p>Now, since we have <mathjax>#2300.0"g"#</mathjax> of Na (that's going to be rather expensive... and explosive! Don't try this at home!):</p> <blockquote> <p><mathjax>#2300.0cancel(g Na) * (cancel(1 mol Na))/(22.989 cancel(g Na)) * (cancel(1 mol H))/(cancel(1 mol Na)) * (1.0079 g H)/(cancel(1 mol H))#</mathjax></p> <p><mathjax>#= color(blue)(100.84 "g" H(g))#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">If #"2300.0 g"# of #"Na"(s)# reacts in a sufficient amount of water, what is the theoretical yield of #"H"_2(g)# in grams?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/percent-yield" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Yield</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="163829" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/truong-son-n"><img alt="" class="" src="https://profilepictures.socratic.org/07k4plnQfmnmzMuesQzw_14844-1449381920.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/truong-son-n"> Truong-Son N. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-08-16T05:19:46" itemprop="dateCreated"> Aug 16, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerDescription"> <div> <div class="markdown"><p>Sodium metal <mathjax>#(Na(s))#</mathjax> reacts in a <strong>single-replacement reaction</strong>, like so (I'll break it down into steps, where the middle dots mean there's a lone electron, and <mathjax>#=>#</mathjax> means the reaction step is taken as-written):</p> <blockquote> <p><mathjax>#1. H-OH(l) => Hcdot(g) + cancel(cdotOH(aq))#</mathjax><br/> <mathjax>#2. Nacdot(s) + cancel(cdotOH(aq)) => NaOH(aq)#</mathjax></p> <p><mathjax>#1.#</mathjax> The <mathjax>#H-OH#</mathjax> bond is split in two. This is a violent step, and in real life there's bubbling in the water!<br/> <mathjax>#2.#</mathjax> <mathjax>#Nacdot#</mathjax> then bonds with <mathjax>#cdotOH#</mathjax>.</p> </blockquote> <p>Overall, we get the product of a (radical) <strong>single-replacement reaction</strong>:</p> <blockquote> <p><mathjax>#color(green)(Nacdot(s) + H_2O(l) -> NaOH(aq) + Hcdot(g))#</mathjax></p> <p>or</p> <p><mathjax>#color(green)(2Na(s) + 2H_2O(l) -> 2NaOH(aq) + H_2(g))#</mathjax></p> </blockquote> <p>The first obvious piece of information is that your <a href="http://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a> is sodium metal (since the water is in <strong>excess</strong>), so you can use that as the starting compound for your "mole-bridge" <mathjax>#("g"_1->"mol"_1/"g"_1->"mol"_2/"mol"_1->"g"_2/"mol"_2)#</mathjax> conversion.</p> <p>Now, since we have <mathjax>#2300.0"g"#</mathjax> of Na (that's going to be rather expensive... and explosive! Don't try this at home!):</p> <blockquote> <p><mathjax>#2300.0cancel(g Na) * (cancel(1 mol Na))/(22.989 cancel(g Na)) * (cancel(1 mol H))/(cancel(1 mol Na)) * (1.0079 g H)/(cancel(1 mol H))#</mathjax></p> <p><mathjax>#= color(blue)(100.84 "g" H(g))#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/163829" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="163831" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> <a class="secondContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a>·<a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-08-16T06:00:24" itemprop="dateCreated"> Aug 16, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The theoretical yield of hydrogen gas is <mathjax>#"100.84 g"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We need to start with a balanced equation. This will give us <a href="http://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio between sodium metal and hydrogen gas. We will also need the molar masses of sodium and hydrogen gas in order to convert between moles and mass.</p> <p><strong>Balanced Equation</strong><br/> <mathjax>#"2Na(s)"+"2H"_2"O(l")#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"2NaOH(aq)"+"H"_2("g)"#</mathjax></p> <p><strong>Mole ratio between <mathjax>#"Na"#</mathjax> and <mathjax>#"H"_2"#</mathjax></strong></p> <p><mathjax>#(2 "mol Na")/(1"mol H"""_2")#</mathjax> and <mathjax>#(1"mol H"""_2)/(2"mol Na")#</mathjax></p> <p><strong>Molar masses of sodium and hydrogen gas</strong></p> <p><mathjax>#"Na":#</mathjax><mathjax>#"22.990 g/mol"#</mathjax></p> <p><mathjax>#"H"_2:#</mathjax><mathjax>#"2.0159 g/mol"#</mathjax></p> <p><strong>Convert <mathjax>#"2300.0 g Na"#</mathjax> to moles <mathjax>#"Na"#</mathjax> using its molar mass.</strong></p> <p><mathjax>#2300.0 cancel"g Na"xx(1"mol Na")/(22.990cancel"g Na")="100.04 mol Na"#</mathjax></p> <p><strong>Convert moles of <mathjax>#"Na"#</mathjax> to moles of <mathjax>#"H"_2#</mathjax> using the mole ratio from the balanced equation</strong> .</p> <p><mathjax>#100.04cancel"mol Na"xx(1"mol H"_2)/(2cancel"mol Na")="50.020 mol H"""_2"#</mathjax></p> <p><strong>Theoretical Yield of Hydrogen Gas</strong></p> <p><strong>Convert moles of <mathjax>#"H"_2"#</mathjax> to mass of <mathjax>#"H"_2"#</mathjax> using the molar mass of <mathjax>#"H"_2"#</mathjax>.</strong></p> <p><mathjax>#50.020 cancel"mol H"_2xx(2.0159"g H"""_2)/(1cancel"mol H"_2)="100.84 g H"""_2"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/163831" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ebd02bf3469570e2e62"> Question #e2e62 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ec502bf34694a4fee2e"> Question #fee2e </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ec902bf34694a4fee32"> Question #fee32 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ece02bf346950519e89"> Question #19e89 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ed302bf34694c8c5bdc"> Question #c5bdc </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ee302bf3469517a1065"> Question #a1065 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-would-be-the-limiting-reagent-if-26-0-grams-of-c3h9n-were-reacted-with-46-3"> What would be the limiting reagent if 26.0 grams of C3H9N were reacted with 46.3 grams of... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-percent-yield-always-less-than-100"> Is percent yield always less than 100? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-would-be-the-limiting-reagent-if-41-9-grams-of-c2h3of-were-reacted-with-61-"> What would be the limiting reagent if 41.9 grams of C2H3OF were reacted with 61.0 grams of... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-yield-of-the-following-reaction-if-60-grams-of-caco3-is-heat"> What is the percent yield of the following reaction if 60 grams of CaCO3 is heated to give 15... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/percent-yield"> See all questions in Percent Yield </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2713 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	If #"2300.0 g"# of #"Na"(s)# reacts in a sufficient amount of water, what is the theoretical yield of #"H"_2(g)# in grams?	null
1,513	a8908e18-6ddd-11ea-8906-ccda262736ce	https://socratic.org/questions/elemental-analysis-of-a-compound-showed-that-it-consisted-of-81-82-carbon-and-18-1	8	start physical_unit 19 20 number none qc_end end	[{"type":"physical unit","value":"Number [OF] hydrogen atoms"}]	[{"type":"physical unit","value":"8"}]	[{"type":"physical unit","value":"Percent by mass [OF] carbon in the compound [=] \\pu{81.82%}"},{"type":"physical unit","value":"Percent by mass [OF] hydrogen in the compound [=] \\pu{18.18%}"}]	<h1 class="questionTitle" itemprop="name">Elemental analysis of a compound showed that it consisted of 81.82% carbon and 18.18% hydrogen by mass. How many hydrogen atoms appear in the empirical formula of the compound?</h1>	null	8	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Since the percentages add up to 100, we can assume that we have a 100.0 g sample of the compound, and the percentages become grams.</p> <p><strong>Determine the Moles of Each Element</strong><br/> Divide the mass of each element by its molar mass. The molar mass of an element is its atomic weight on <a href="http://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a> in grams/ mole (g/mol). </p> <p><mathjax>#81.82cancel"g C"xx(1"mol C")/(12.011cancel"g C")="6.812 mol C"#</mathjax></p> <p><mathjax>#18.18cancel"g H"xx(1"mol H")/(1.00794cancel"g H")="18.04 mol H"#</mathjax></p> <p><strong>Determine the <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">Mole Ratios</a></strong><br/> Divide the number of moles of each element by the least number of moles.</p> <p><mathjax>#"C":#</mathjax><mathjax>#(6.812)/(6.812)="1.000"#</mathjax></p> <p><mathjax>#"H":#</mathjax><mathjax>#(18.04)/(6.812)="2.648"#</mathjax></p> <p>Since <a href="http://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio for H cannot be rounded to a whole number, we must multiply it times a factor that will result in a whole number.</p> <p><mathjax>#"H":#</mathjax><mathjax>#2.648xx3=7.944~~8#</mathjax></p> <p>We must multiply both mole ratios times <mathjax>#3#</mathjax>.</p> <p><mathjax>#"C":#</mathjax><mathjax>#1.000xx3=3.000"#</mathjax></p> <p>The empirical formula is <mathjax>#"C"_3"H"_8"#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The empirical formula is <mathjax>#"C"_3"H"_8"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Since the percentages add up to 100, we can assume that we have a 100.0 g sample of the compound, and the percentages become grams.</p> <p><strong>Determine the Moles of Each Element</strong><br/> Divide the mass of each element by its molar mass. The molar mass of an element is its atomic weight on <a href="http://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a> in grams/ mole (g/mol). </p> <p><mathjax>#81.82cancel"g C"xx(1"mol C")/(12.011cancel"g C")="6.812 mol C"#</mathjax></p> <p><mathjax>#18.18cancel"g H"xx(1"mol H")/(1.00794cancel"g H")="18.04 mol H"#</mathjax></p> <p><strong>Determine the <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">Mole Ratios</a></strong><br/> Divide the number of moles of each element by the least number of moles.</p> <p><mathjax>#"C":#</mathjax><mathjax>#(6.812)/(6.812)="1.000"#</mathjax></p> <p><mathjax>#"H":#</mathjax><mathjax>#(18.04)/(6.812)="2.648"#</mathjax></p> <p>Since <a href="http://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio for H cannot be rounded to a whole number, we must multiply it times a factor that will result in a whole number.</p> <p><mathjax>#"H":#</mathjax><mathjax>#2.648xx3=7.944~~8#</mathjax></p> <p>We must multiply both mole ratios times <mathjax>#3#</mathjax>.</p> <p><mathjax>#"C":#</mathjax><mathjax>#1.000xx3=3.000"#</mathjax></p> <p>The empirical formula is <mathjax>#"C"_3"H"_8"#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Elemental analysis of a compound showed that it consisted of 81.82% carbon and 18.18% hydrogen by mass. How many hydrogen atoms appear in the empirical formula of the compound?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="184920" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-06T22:24:34" itemprop="dateCreated"> Nov 6, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The empirical formula is <mathjax>#"C"_3"H"_8"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Since the percentages add up to 100, we can assume that we have a 100.0 g sample of the compound, and the percentages become grams.</p> <p><strong>Determine the Moles of Each Element</strong><br/> Divide the mass of each element by its molar mass. The molar mass of an element is its atomic weight on <a href="http://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a> in grams/ mole (g/mol). </p> <p><mathjax>#81.82cancel"g C"xx(1"mol C")/(12.011cancel"g C")="6.812 mol C"#</mathjax></p> <p><mathjax>#18.18cancel"g H"xx(1"mol H")/(1.00794cancel"g H")="18.04 mol H"#</mathjax></p> <p><strong>Determine the <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">Mole Ratios</a></strong><br/> Divide the number of moles of each element by the least number of moles.</p> <p><mathjax>#"C":#</mathjax><mathjax>#(6.812)/(6.812)="1.000"#</mathjax></p> <p><mathjax>#"H":#</mathjax><mathjax>#(18.04)/(6.812)="2.648"#</mathjax></p> <p>Since <a href="http://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio for H cannot be rounded to a whole number, we must multiply it times a factor that will result in a whole number.</p> <p><mathjax>#"H":#</mathjax><mathjax>#2.648xx3=7.944~~8#</mathjax></p> <p>We must multiply both mole ratios times <mathjax>#3#</mathjax>.</p> <p><mathjax>#"C":#</mathjax><mathjax>#1.000xx3=3.000"#</mathjax></p> <p>The empirical formula is <mathjax>#"C"_3"H"_8"#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/184920" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molecular-formula-of-a-compound"> How do you find molecular formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-diamond"> What is the chemical formula of a diamond? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-carbohydrate"> What is the chemical formula of a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-valproic-acid"> What is the empirical formula for valproic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-of-magnesium-oxide"> What is the empirical formula of magnesium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-empirical-formula-not-double-that-of-the-monosaccharides"> Why is the empirical formula not double that of the monosaccharides? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5331180502bf342f40b5c3b5"> Question #5c3b5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-molecular-formula-represents-a-carbohydrate"> What molecular formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-of-vinegar"> What is the molecular formula of vinegar? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/empirical-and-molecular-formulas"> See all questions in Empirical and Molecular Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 14151 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Elemental analysis of a compound showed that it consisted of 81.82% carbon and 18.18% hydrogen by mass. How many hydrogen atoms appear in the empirical formula of the compound?	null
1,514	ac0c45d7-6ddd-11ea-827a-ccda262736ce	https://socratic.org/questions/599875967c014904aab4ea11	62.25%	start physical_unit 5 8 percent none qc_end substance 5 5 qc_end substance 7 8 qc_end end	[{"type":"physical unit","value":"Percentage [OF] oxygen in sulfuric acid"}]	[{"type":"physical unit","value":"62.25%"}]	[{"type":"substance name","value":"Oxygen"},{"type":"substance name","value":"Sulfuric acid"}]	<h1 class="questionTitle" itemprop="name">What is the percentage of oxygen in sulfuric acid?</h1>	null	62.25%	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The chemical formula for sulfuric acid, <mathjax>#"H"_2"SO"_4#</mathjax>, indicates that in one mole of sulfuric acid, there are four moles of oxygen atoms. In order to calculate the percentage of oxygen in sulfuric acid, you need to divide the mass of oxygen in one mole of sulfuric acid by the molar mass of sulfuric acid and multiply by 100.</p> <p>Molar mass <mathjax>#"H"_2"SO"_4="98.072 g/mol"#</mathjax></p> <p>Mass of O: <mathjax>#4xx"15.999 g/mol"="63.996 g/mol"#</mathjax></p> <p>Percentage O</p> <p><mathjax>#(63.996color(red)cancel(color(black)("g/mol")))/(98.072color(red)cancel(color(black)("g/mol")))xx100="65.254% O"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The percentage of oxygen in sulfuric acid is 65.254%.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The chemical formula for sulfuric acid, <mathjax>#"H"_2"SO"_4#</mathjax>, indicates that in one mole of sulfuric acid, there are four moles of oxygen atoms. In order to calculate the percentage of oxygen in sulfuric acid, you need to divide the mass of oxygen in one mole of sulfuric acid by the molar mass of sulfuric acid and multiply by 100.</p> <p>Molar mass <mathjax>#"H"_2"SO"_4="98.072 g/mol"#</mathjax></p> <p>Mass of O: <mathjax>#4xx"15.999 g/mol"="63.996 g/mol"#</mathjax></p> <p>Percentage O</p> <p><mathjax>#(63.996color(red)cancel(color(black)("g/mol")))/(98.072color(red)cancel(color(black)("g/mol")))xx100="65.254% O"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the percentage of oxygen in sulfuric acid?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/percent-composition" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Composition</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="466004" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-20T04:18:05" itemprop="dateCreated"> Aug 20, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The percentage of oxygen in sulfuric acid is 65.254%.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The chemical formula for sulfuric acid, <mathjax>#"H"_2"SO"_4#</mathjax>, indicates that in one mole of sulfuric acid, there are four moles of oxygen atoms. In order to calculate the percentage of oxygen in sulfuric acid, you need to divide the mass of oxygen in one mole of sulfuric acid by the molar mass of sulfuric acid and multiply by 100.</p> <p>Molar mass <mathjax>#"H"_2"SO"_4="98.072 g/mol"#</mathjax></p> <p>Mass of O: <mathjax>#4xx"15.999 g/mol"="63.996 g/mol"#</mathjax></p> <p>Percentage O</p> <p><mathjax>#(63.996color(red)cancel(color(black)("g/mol")))/(98.072color(red)cancel(color(black)("g/mol")))xx100="65.254% O"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/466004" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-mole-percent"> What is mole percent? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4188602bf3469570e2e8b"> Question #e2e8b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4188702bf34695a6bc737"> Question #bc737 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418be02bf34695a6bc73b"> Question #bc73b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418c202bf3469570e2e8f"> Question #e2e8f </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418c802bf346963eb9857"> Question #b9857 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418ca02bf346963eb985b"> Question #b985b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418cc02bf34694a4fee41"> Question #fee41 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418d502bf34694c8c5c01"> Question #c5c01 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4196e02bf34695a6bc73f"> Question #bc73f </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/percent-composition"> See all questions in Percent Composition </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 20823 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the percentage of oxygen in sulfuric acid?	null
1,515	a93cc2ae-6ddd-11ea-94d4-ccda262736ce	https://socratic.org/questions/what-is-the-density-of-carbon-dioxide-at-stp-c-12-01g-mol-o-16-00g-mol	1.95 × 10^(-3) g/cm^3	start physical_unit 5 6 density g/cm^3 qc_end c_other STP qc_end physical_unit 9 9 11 12 molar_mass qc_end physical_unit 13 13 15 16 molar_mass qc_end end	[{"type":"physical unit","value":"density [OF] carbon dioxide [IN] g/cm^3"}]	[{"type":"physical unit","value":"1.95 × 10^(-3) g/cm^3"}]	[{"type":"other","value":"STP"},{"type":"physical unit","value":"Molecular [OF] C [=] \\pu{12.01 g/mol}"},{"type":"physical unit","value":"Molecular [OF] O [=] \\pu{16.00 g/mol}"}]	<h1 class="questionTitle" itemprop="name">What is the density of carbon dioxide at STP? (C=12.01g/mol; O=16.00g/mol)</h1>	null	1.95 × 10^(-3) g/cm^3	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The molar mass of <mathjax>#CO_2#</mathjax> is <mathjax>#"12.01 g/mol" + 2*"16 g/mol" = "44.01 g/mol"#</mathjax></p> <p>At S.T.P, the molar mass of <mathjax>#CO_2#</mathjax> occupies <mathjax>#"22.4 L" = "22400 cm"^3#</mathjax>, i.e. <mathjax>#"1 mol"#</mathjax> occupies <mathjax>#"22400 cm"^3#</mathjax> </p> <p>So, the density of <mathjax>#CO_2#</mathjax> at S.T.P is </p> <p><mathjax>#= "44.01 g"/("22400 cm"^3) = "0.00195 g/cm"^3#</mathjax> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"0.00195 g/cm"^3#</mathjax> </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The molar mass of <mathjax>#CO_2#</mathjax> is <mathjax>#"12.01 g/mol" + 2*"16 g/mol" = "44.01 g/mol"#</mathjax></p> <p>At S.T.P, the molar mass of <mathjax>#CO_2#</mathjax> occupies <mathjax>#"22.4 L" = "22400 cm"^3#</mathjax>, i.e. <mathjax>#"1 mol"#</mathjax> occupies <mathjax>#"22400 cm"^3#</mathjax> </p> <p>So, the density of <mathjax>#CO_2#</mathjax> at S.T.P is </p> <p><mathjax>#= "44.01 g"/("22400 cm"^3) = "0.00195 g/cm"^3#</mathjax> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the density of carbon dioxide at STP? (C=12.01g/mol; O=16.00g/mol)</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp" itemprop="url"> <span class="breadcrumb" itemprop="title">Molar Volume of a Gas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="563723" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/jane-30"><img alt="" class="" src="https://profilepictures.socratic.org/HLtKBlRF25kuCRQITcw2_Sunshine_Love__240_320_146109.gif" title=""/></a> <a class="secondContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/jane-30"> Jane </a>·<a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-03-04T11:35:46" itemprop="dateCreated"> Mar 4, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"0.00195 g/cm"^3#</mathjax> </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The molar mass of <mathjax>#CO_2#</mathjax> is <mathjax>#"12.01 g/mol" + 2*"16 g/mol" = "44.01 g/mol"#</mathjax></p> <p>At S.T.P, the molar mass of <mathjax>#CO_2#</mathjax> occupies <mathjax>#"22.4 L" = "22400 cm"^3#</mathjax>, i.e. <mathjax>#"1 mol"#</mathjax> occupies <mathjax>#"22400 cm"^3#</mathjax> </p> <p>So, the density of <mathjax>#CO_2#</mathjax> at S.T.P is </p> <p><mathjax>#= "44.01 g"/("22400 cm"^3) = "0.00195 g/cm"^3#</mathjax> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/563723" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-stoichiometric-ratios-relate-to-molar-volume-of-a-gas"> How do stoichiometric ratios relate to molar volume of a gas? 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(C=12.01g/mol; O=16.00g/mol)	null
1,516	ac0316e7-6ddd-11ea-8bfb-ccda262736ce	https://socratic.org/questions/how-do-you-balance-ch-4-o-2-co-2-h-2o-1	CH4 + 2 O2 -> CO2 + 2 H2O	start chemical_equation qc_end chemical_equation 4 10 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the equation"}]	[{"type":"chemical equation","value":"CH4 + 2 O2 -> CO2 + 2 H2O"}]	[{"type":"chemical equation","value":"CH4 + O2 -> CO2 + H2O"}]	<h1 class="questionTitle" itemprop="name">How do you balance #CH_4 + O_2 -> CO_2 + H_2O#?</h1>	null	CH4 + 2 O2 -> CO2 + 2 H2O	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Look for imbalances. Both sides have one <mathjax>#C#</mathjax>. However, the left-hand side has four <mathjax>#H#</mathjax>'s while the right-hand side has only two. The left-hand side has two <mathjax>#O#</mathjax>'s while the right-hand side has three.</p> <p>We try to add some coefficients before each molecule to balance the number of atoms. We add a <mathjax>#2#</mathjax> before <mathjax>#H_2O#</mathjax> in the right-hand side as this would balance the number of <mathjax>#H#</mathjax>'s. But the right-hand side has four <mathjax>#O#</mathjax>'s now. Luckily, if we add a <mathjax>#2#</mathjax> before <mathjax>#O_2#</mathjax> in the left-hand side, the <mathjax>#O#</mathjax>'s would balance out.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#CH_4+2O_2->CO_2+2H_2O#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Look for imbalances. Both sides have one <mathjax>#C#</mathjax>. However, the left-hand side has four <mathjax>#H#</mathjax>'s while the right-hand side has only two. The left-hand side has two <mathjax>#O#</mathjax>'s while the right-hand side has three.</p> <p>We try to add some coefficients before each molecule to balance the number of atoms. We add a <mathjax>#2#</mathjax> before <mathjax>#H_2O#</mathjax> in the right-hand side as this would balance the number of <mathjax>#H#</mathjax>'s. But the right-hand side has four <mathjax>#O#</mathjax>'s now. Luckily, if we add a <mathjax>#2#</mathjax> before <mathjax>#O_2#</mathjax> in the left-hand side, the <mathjax>#O#</mathjax>'s would balance out.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you balance #CH_4 + O_2 -> CO_2 + H_2O#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="399052" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/nicktheturtle"><img alt="" class="" src="https://profilepictures.socratic.org/k5p80uDdSHqDUkskcvMz_NickTheTurtle1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/nicktheturtle"> NickTheTurtle </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-30T15:07:48" itemprop="dateCreated"> Mar 30, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#CH_4+2O_2->CO_2+2H_2O#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Look for imbalances. Both sides have one <mathjax>#C#</mathjax>. However, the left-hand side has four <mathjax>#H#</mathjax>'s while the right-hand side has only two. The left-hand side has two <mathjax>#O#</mathjax>'s while the right-hand side has three.</p> <p>We try to add some coefficients before each molecule to balance the number of atoms. We add a <mathjax>#2#</mathjax> before <mathjax>#H_2O#</mathjax> in the right-hand side as this would balance the number of <mathjax>#H#</mathjax>'s. But the right-hand side has four <mathjax>#O#</mathjax>'s now. Luckily, if we add a <mathjax>#2#</mathjax> before <mathjax>#O_2#</mathjax> in the left-hand side, the <mathjax>#O#</mathjax>'s would balance out.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/399052" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="399058" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-30T15:16:39" itemprop="dateCreated"> Mar 30, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Balance the <mathjax>#"carbons"#</mathjax>, then the <mathjax>#"hydrogens"#</mathjax>, and then LASTLY the <mathjax>#"oxygens......"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And thus we follow the rigmarole for combustion of methane...</p> <p><mathjax>#underbrace(CH_4 + O_2 rarr CO_2 + H_2O)_"carbons are balanced"#</mathjax>; .</p> <p><mathjax>#underbrace(CH_4 + O_2 rarr CO_2 + 2H_2O)_"carbons and hydrogens are balanced"#</mathjax>;.</p> <p>And then, <mathjax>#underbrace(CH_4 + 2O_2 rarr CO_2 + 2H_2O)_"carbons and hydrogens and oxygens are balanced"#</mathjax>. And this equation is then stoichiometrically balanced. </p> <p>With alkanes with an ODD number of carbons, this approach gives integral coefficients. Try it out for propane and pentane. When you balance alkanes with EVEN numbers of carbons, this approach requires the use of half-integral oxygen coefficients. e.g. for ethane:</p> <p><mathjax>#H_3C-CH_3 + 7/2O_2 rarr 2CO_2 +3H_2O#</mathjax></p> <p>Alternatively you could double the entire equation to get rid of the half-integral coefficient:</p> <p><mathjax>#2H_3C-CH_3 + 7O_2 rarr 4CO_2 +6H_2O#</mathjax></p> <p>Try this out for butane and hexane. </p> <p>Because it is easier arithmetically to address the former <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>, I tend to favour the half-integral coefficient. Of course we cannot have half a molecule of dioxygen, but we can certainly have <mathjax>#16*g#</mathjax>, i.e. <mathjax>#"half a mole of dioxygen gas."#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/399058" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------> H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -> Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? 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1,517	ac51f200-6ddd-11ea-98bd-ccda262736ce	https://socratic.org/questions/the-solubility-of-scandium-iii-fluoride-scf-3-in-pure-water-is-2-0-x-10-5-moles-	4.32 × 10^(-18)	start physical_unit 3 5 equilibrium_constant_k none qc_end physical_unit 6 6 11 16 solubility qc_end substance 8 9 qc_end end	[{"type":"physical unit","value":"Ksp [OF] scandium (III) fluoride"}]	[{"type":"physical unit","value":"4.32 × 10^(-18)"}]	[{"type":"physical unit","value":"Solubility [OF] ScF3 [=] \\pu{2.0 × 10^(-5) moles per liter}"},{"type":"substance name","value":"Pure water"}]	<h1 class="questionTitle" itemprop="name">The solubility of scandium (III) fluoride, #ScF_3#, in pure water is #2.0 x 10^-5# moles per liter. How do you calculate the value of #K_(sp)# for scandium (III) fluoride from this data?</h1>	null	4.32 × 10^(-18)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We interrogate the reaction.....</p> <p><mathjax>#ScF_3(s) rightleftharpoons Sc^(3+) + 3F^-#</mathjax></p> <p>And as written, we can directly write the solubility expression, <mathjax>#K_"sp"#</mathjax>, where <mathjax>#K_"sp"=[Sc^(3+)][F^-]^3#</mathjax></p> <p>And we are given the solubility of <mathjax>#ScF_3#</mathjax> in water, <mathjax>#2.0xx10^-5molL^-1#</mathjax>....</p> <p>And thus <mathjax>#[Sc^(3+)]=2.0xx10^-5molL^-1#</mathjax></p> <p>And <mathjax>#[F^-]=3xx2.0xx10^-5molL^-1#</mathjax></p> <p>Capisce?</p> <p>And then we input these numbers into the <mathjax>#K_"sp"#</mathjax> expression.....</p> <p><mathjax>#K_"sp"=(2.0xx10^-5)xx(6.0xx10^-5)^3=4.32xx10^-18#</mathjax></p> <p>PS I have not got a good text at hand, but the values I read for <mathjax>#K_"sp"#</mathjax> for scandium fluoride seem to vary widely. I would check the source of these data. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#K_"sp"(ScF_3)=4.32xx10^-18#</mathjax></p> <p>We interrogate the reaction.....</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We interrogate the reaction.....</p> <p><mathjax>#ScF_3(s) rightleftharpoons Sc^(3+) + 3F^-#</mathjax></p> <p>And as written, we can directly write the solubility expression, <mathjax>#K_"sp"#</mathjax>, where <mathjax>#K_"sp"=[Sc^(3+)][F^-]^3#</mathjax></p> <p>And we are given the solubility of <mathjax>#ScF_3#</mathjax> in water, <mathjax>#2.0xx10^-5molL^-1#</mathjax>....</p> <p>And thus <mathjax>#[Sc^(3+)]=2.0xx10^-5molL^-1#</mathjax></p> <p>And <mathjax>#[F^-]=3xx2.0xx10^-5molL^-1#</mathjax></p> <p>Capisce?</p> <p>And then we input these numbers into the <mathjax>#K_"sp"#</mathjax> expression.....</p> <p><mathjax>#K_"sp"=(2.0xx10^-5)xx(6.0xx10^-5)^3=4.32xx10^-18#</mathjax></p> <p>PS I have not got a good text at hand, but the values I read for <mathjax>#K_"sp"#</mathjax> for scandium fluoride seem to vary widely. I would check the source of these data. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">The solubility of scandium (III) fluoride, #ScF_3#, in pure water is #2.0 x 10^-5# moles per liter. How do you calculate the value of #K_(sp)# for scandium (III) fluoride from this data?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/factors-affecting-solubility" itemprop="url"> <span class="breadcrumb" itemprop="title">Factors Affecting Solubility</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="474526" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-09-12T17:15:54" itemprop="dateCreated"> Sep 12, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#K_"sp"(ScF_3)=4.32xx10^-18#</mathjax></p> <p>We interrogate the reaction.....</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We interrogate the reaction.....</p> <p><mathjax>#ScF_3(s) rightleftharpoons Sc^(3+) + 3F^-#</mathjax></p> <p>And as written, we can directly write the solubility expression, <mathjax>#K_"sp"#</mathjax>, where <mathjax>#K_"sp"=[Sc^(3+)][F^-]^3#</mathjax></p> <p>And we are given the solubility of <mathjax>#ScF_3#</mathjax> in water, <mathjax>#2.0xx10^-5molL^-1#</mathjax>....</p> <p>And thus <mathjax>#[Sc^(3+)]=2.0xx10^-5molL^-1#</mathjax></p> <p>And <mathjax>#[F^-]=3xx2.0xx10^-5molL^-1#</mathjax></p> <p>Capisce?</p> <p>And then we input these numbers into the <mathjax>#K_"sp"#</mathjax> expression.....</p> <p><mathjax>#K_"sp"=(2.0xx10^-5)xx(6.0xx10^-5)^3=4.32xx10^-18#</mathjax></p> <p>PS I have not got a good text at hand, but the values I read for <mathjax>#K_"sp"#</mathjax> for scandium fluoride seem to vary widely. I would check the source of these data. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/474526" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-factors-affect-solubility-in-a-solid-liquid-combination"> What factors affect solubility in a solid-liquid combination? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-factors-affect-solubility-in-water"> What factors affect solubility in water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-factors-affect-solubility-of-ionic-compounds"> What factors affect solubility of ionic compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-factors-affect-the-solubility-of-gases-in-liquids"> What factors affect the solubility of gases in liquids? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-factors-affect-the-solubility-of-a-solid"> What factors affect the solubility of a solid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-solubility-of-potassium-nitrate"> How can I calculate solubility of potassium nitrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-the-solubility-of-kno3-depend-on"> What does the solubility of KNO3 depend on? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-solubility-of-a-solution"> How can I calculate the solubility of solute in a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-solubility-is-affected-by-polymer-chain-structure"> How is solubility affected by polymer chain structure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/does-solubility-differ-from-molar-solubility"> Does solubility differ from molar solubility? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/factors-affecting-solubility"> See all questions in Factors Affecting Solubility </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 6940 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	The solubility of scandium (III) fluoride, #ScF_3#, in pure water is #2.0 x 10^-5# moles per liter. How do you calculate the value of #K_(sp)# for scandium (III) fluoride from this data?	null
1,518	aa50e250-6ddd-11ea-b5dc-ccda262736ce	https://socratic.org/questions/59b3393c11ef6b14d3b4c875	1.24 mol/L	start physical_unit 27 28 concentration mol/l qc_end physical_unit 5 6 1 2 volume qc_end physical_unit 15 16 12 13 volume qc_end physical_unit 15 16 20 21 concentration qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Concentration [OF] the acid [IN] mol/L"}]	[{"type":"physical unit","value":"1.24 mol/L"}]	[{"type":"physical unit","value":"Volume [OF] monoprotic acid [=] \\pu{15.62 mL}"},{"type":"physical unit","value":"Volume [OF] sodium hydroxide [=] \\pu{16.49 mL}"},{"type":"physical unit","value":"Concentration [OF] sodium hydroxide [=] \\pu{1.175 mol/L}"},{"type":"other","value":"Monoprotic acid reached a stoichiometric endpoint with sodium hydroxide."}]	<h1 class="questionTitle" itemprop="name">A #15.62mL# volume of monoprotic acid reached a stoichiometric endpoint with #16.49mL# of sodium hydroxide whose concentration was #1.175molL^-1#. What is the concentration of the acid?</h1>	null	1.24 mol/L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We need (i) a stoichiometric equation,</p> <p><mathjax>#HX(aq) + NaOH(aq) rarr NaX(aq) + H_2O#</mathjax></p> <p>And thus there is 1:1 equivalence between acid and base.</p> <p>By definition, <mathjax>#"concentration"="moles of solute"/"volume of solution"#</mathjax>...</p> <p>And thus the PRODUCT, <mathjax>#"volume"xx"concentration"="moles"#</mathjax></p> <p>And so we need (ii) molar quantities of acid and base.....</p> <p><mathjax>#"Moles of NaOH"-=16.49xx10^-3Lxx1.175molL^-1=0.01938mol#</mathjax></p> <p>But given the 1:1 equivalence between acid and base, CLEARLY this molar quantity was contained in the original <mathjax>#15.62mL#</mathjax> volume....</p> <p>And so (finally)......</p> <p><mathjax>#["Base"]=(0.01938mol)/(15.62xx10^-3L)=??mol*L^-1#</mathjax></p> <p>And note that doing the calculation this way, i.e. dimensionally with units included, gives me the appropriate units if we set up the problem correctly. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#[HX]=1.24molL^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We need (i) a stoichiometric equation,</p> <p><mathjax>#HX(aq) + NaOH(aq) rarr NaX(aq) + H_2O#</mathjax></p> <p>And thus there is 1:1 equivalence between acid and base.</p> <p>By definition, <mathjax>#"concentration"="moles of solute"/"volume of solution"#</mathjax>...</p> <p>And thus the PRODUCT, <mathjax>#"volume"xx"concentration"="moles"#</mathjax></p> <p>And so we need (ii) molar quantities of acid and base.....</p> <p><mathjax>#"Moles of NaOH"-=16.49xx10^-3Lxx1.175molL^-1=0.01938mol#</mathjax></p> <p>But given the 1:1 equivalence between acid and base, CLEARLY this molar quantity was contained in the original <mathjax>#15.62mL#</mathjax> volume....</p> <p>And so (finally)......</p> <p><mathjax>#["Base"]=(0.01938mol)/(15.62xx10^-3L)=??mol*L^-1#</mathjax></p> <p>And note that doing the calculation this way, i.e. dimensionally with units included, gives me the appropriate units if we set up the problem correctly. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A #15.62mL# volume of monoprotic acid reached a stoichiometric endpoint with #16.49mL# of sodium hydroxide whose concentration was #1.175molL^-1#. What is the concentration of the acid?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#reactions-in-solution" itemprop="url"> <span class="breadcrumb" itemprop="title">Reactions in Solution</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/reactions-in-solution/titration-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">Titration Calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="473340" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-09-09T03:34:17" itemprop="dateCreated"> Sep 9, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#[HX]=1.24molL^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We need (i) a stoichiometric equation,</p> <p><mathjax>#HX(aq) + NaOH(aq) rarr NaX(aq) + H_2O#</mathjax></p> <p>And thus there is 1:1 equivalence between acid and base.</p> <p>By definition, <mathjax>#"concentration"="moles of solute"/"volume of solution"#</mathjax>...</p> <p>And thus the PRODUCT, <mathjax>#"volume"xx"concentration"="moles"#</mathjax></p> <p>And so we need (ii) molar quantities of acid and base.....</p> <p><mathjax>#"Moles of NaOH"-=16.49xx10^-3Lxx1.175molL^-1=0.01938mol#</mathjax></p> <p>But given the 1:1 equivalence between acid and base, CLEARLY this molar quantity was contained in the original <mathjax>#15.62mL#</mathjax> volume....</p> <p>And so (finally)......</p> <p><mathjax>#["Base"]=(0.01938mol)/(15.62xx10^-3L)=??mol*L^-1#</mathjax></p> <p>And note that doing the calculation this way, i.e. dimensionally with units included, gives me the appropriate units if we set up the problem correctly. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/473340" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-do-acid-base-titration-calculations"> How do you do acid base titration calculations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-use-titration-calculations-to-find-ph"> How do you use titration calculations to find pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/radox-titration"> What is a redox titration and what is it used for? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-titration-used-when-standardizing-a-solution"> Why is titration used when standardizing a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-titration-suitable-for-sodium-nitrate"> Is titration suitable for sodium nitrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-do-redox-titration-calculations"> How can I do redox titration calculations? 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What is the concentration of the acid?	null
1,519	a9eb6752-6ddd-11ea-950d-ccda262736ce	https://socratic.org/questions/what-is-the-formula-for-dihydrogen-monoxide	H2O	start chemical_formula qc_end substance 5 6 qc_end end	[{"type":"other","value":"Chemical Formula [OF] dihydrogen monoxide [IN] default"}]	[{"type":"chemical equation","value":"H2O"}]	[{"type":"substance name","value":"Dihydrogen monoxide"}]	<h1 class="questionTitle" itemprop="name">What is the formula for dihydrogen monoxide?</h1>	null	H2O	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The first part of the name, "dihydrogen," implies the presence of two hydrogen atoms. The second part, "monoxide," implies the presence of one oxygen atom. Therefore, you have two hydrogen atoms and one oxygen atom to make up each molecule. Sound familiar? </p> <p><img alt="Wiki Commons" src="https://useruploads.socratic.org/quGWFJCTvKjynB0Mauh5_220px-Water-2D-flat.png"/> </p> <p>The common name is <em>water,</em> and it has the chemical formula <mathjax>#H_2O#</mathjax>. </p> <p>Basic guidelines on naming other covalent inorganic molecules:</p> <blockquote> <ul> <li>Greek prefixes are used to indicate how many of each element are in a compound (e.g. mono, di, tri, tetra, etc.).</li> <li>The more electronegative element is written last and its ending is changed to –ide.</li> <li>The prefix mono is never used for naming the first element of a compound.</li> <li>The final "o" or "a" of a prefix is often dropped when the element begins with a vowel.</li> </ul> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#H_2O#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The first part of the name, "dihydrogen," implies the presence of two hydrogen atoms. The second part, "monoxide," implies the presence of one oxygen atom. Therefore, you have two hydrogen atoms and one oxygen atom to make up each molecule. Sound familiar? </p> <p><img alt="Wiki Commons" src="https://useruploads.socratic.org/quGWFJCTvKjynB0Mauh5_220px-Water-2D-flat.png"/> </p> <p>The common name is <em>water,</em> and it has the chemical formula <mathjax>#H_2O#</mathjax>. </p> <p>Basic guidelines on naming other covalent inorganic molecules:</p> <blockquote> <ul> <li>Greek prefixes are used to indicate how many of each element are in a compound (e.g. mono, di, tri, tetra, etc.).</li> <li>The more electronegative element is written last and its ending is changed to –ide.</li> <li>The prefix mono is never used for naming the first element of a compound.</li> <li>The final "o" or "a" of a prefix is often dropped when the element begins with a vowel.</li> </ul> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the formula for dihydrogen monoxide?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="379785" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/morgan-h-1"><img alt="" class="" src="https://profilepictures.socratic.org/P5lBRfASSLq9uiwN2FtP_Screen%20Shot%202016-11-26%20at%2012.29.09%20PM.png" title=""/></a> <a class="secondContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/morgan-h-1"> Morgan </a>·<a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-02-18T22:22:11" itemprop="dateCreated"> Feb 18, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#H_2O#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The first part of the name, "dihydrogen," implies the presence of two hydrogen atoms. The second part, "monoxide," implies the presence of one oxygen atom. Therefore, you have two hydrogen atoms and one oxygen atom to make up each molecule. Sound familiar? </p> <p><img alt="Wiki Commons" src="https://useruploads.socratic.org/quGWFJCTvKjynB0Mauh5_220px-Water-2D-flat.png"/> </p> <p>The common name is <em>water,</em> and it has the chemical formula <mathjax>#H_2O#</mathjax>. </p> <p>Basic guidelines on naming other covalent inorganic molecules:</p> <blockquote> <ul> <li>Greek prefixes are used to indicate how many of each element are in a compound (e.g. mono, di, tri, tetra, etc.).</li> <li>The more electronegative element is written last and its ending is changed to –ide.</li> <li>The prefix mono is never used for naming the first element of a compound.</li> <li>The final "o" or "a" of a prefix is often dropped when the element begins with a vowel.</li> </ul> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/379785" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molecular-formula-of-a-compound"> How do you find molecular formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-diamond"> What is the chemical formula of a diamond? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-carbohydrate"> What is the chemical formula of a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-valproic-acid"> What is the empirical formula for valproic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-of-magnesium-oxide"> What is the empirical formula of magnesium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-empirical-formula-not-double-that-of-the-monosaccharides"> Why is the empirical formula not double that of the monosaccharides? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5331180502bf342f40b5c3b5"> Question #5c3b5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-molecular-formula-represents-a-carbohydrate"> What molecular formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-of-vinegar"> What is the molecular formula of vinegar? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/empirical-and-molecular-formulas"> See all questions in Empirical and Molecular Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 27077 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the formula for dihydrogen monoxide?	null
1,520	ad0387c6-6ddd-11ea-b0b5-ccda262736ce	https://socratic.org/questions/suppose-a-sample-of-air-contains-23-0-oxygen-by-mass-how-many-grams-of-air-are-r	522.17 grams	start physical_unit 4 4 mass g qc_end physical_unit 25 25 22 23 mass qc_end substance 27 28 qc_end end	[{"type":"physical unit","value":"Mass [OF] air [IN] grams"}]	[{"type":"physical unit","value":"522.17 grams"}]	[{"type":"physical unit","value":"Percent by mass [OF] oxygen in the air sample [=] \\pu{23.0%}"},{"type":"physical unit","value":"Mass [OF] P [=] \\pu{93.0 g}"},{"type":"substance name","value":"Diphosphorus pentoxide"}]	<h1 class="questionTitle" itemprop="name"> Suppose a sample of air contains 23.0% oxygen by mass. How many grams of air are required to complete the combustion of 93.0 g of P to diphosphorus pentoxide?</h1>	null	522.17 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your starting point here will be the balanced chemical equation for this combustion reaction</p> <blockquote> <p><mathjax>#4"P"_text((s]) + color(red)(5)"O"_text(2(g]) -> 2"P"_2"O"_text(5(s])#</mathjax></p> </blockquote> <p>Notice that you have a <mathjax>#4:color(red)(5)#</mathjax> <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> between phosphorus and oxygen. This means that, regardless of how many moles of phosphorus you have, the reaction will always need <mathjax>#5/4#</mathjax> <strong>time more</strong> moles of oxygen gas. </p> <p>Use phosphorus' molar mass to determine how many moles you have in that <mathjax>#"93.0-g"#</mathjax> sample</p> <blockquote> <p><mathjax>#93.0color(red)(cancel(color(black)("g"))) * " 1mole P"/(30.974color(red)(cancel(color(black)("g")))) = "3.0025 moles P"#</mathjax></p> </blockquote> <p>Use the aforementioned mole ratio to determine how many moles of oxygen you would need for many moles of phosphorus to completely take part in the reaction</p> <blockquote> <p><mathjax>#3.0025color(red)(cancel(color(black)("moles P"))) * (color(red)(5)" moles O"_2)/(4color(red)(cancel(color(black)("moles P")))) = "3.753 moles O"_2#</mathjax></p> </blockquote> <p>Now use oxygen's molar mass to determine how many grams of oxygen would contain this many moles</p> <blockquote> <p><mathjax>#3.753color(red)(cancel(color(black)("moles O"_2))) * "32.0 g"/(1color(red)(cancel(color(black)("mole O"_2)))) = "120.1 g O"_2#</mathjax></p> </blockquote> <p>Now, you know that your air sample contains <mathjax>#23%#</mathjax> oxygen <a href="http://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">by mass</a>, which means that you get <mathjax>#"23.0 g"#</mathjax> of oxygen <strong>for every</strong> <mathjax>#"100 g"#</mathjax> of air.</p> <p>This means that you will need</p> <blockquote> <p><mathjax>#120.1color(red)(cancel(color(black)("g O"_2))) * "100.0 g air"/(23.0color(red)(cancel(color(black)("g O"_2)))) = "522.17 g air"#</mathjax></p> </blockquote> <p>Rounded to three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the answer will be </p> <blockquote> <p><mathjax>#m_"air" = color(green)("522 g")#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"522 g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your starting point here will be the balanced chemical equation for this combustion reaction</p> <blockquote> <p><mathjax>#4"P"_text((s]) + color(red)(5)"O"_text(2(g]) -> 2"P"_2"O"_text(5(s])#</mathjax></p> </blockquote> <p>Notice that you have a <mathjax>#4:color(red)(5)#</mathjax> <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> between phosphorus and oxygen. This means that, regardless of how many moles of phosphorus you have, the reaction will always need <mathjax>#5/4#</mathjax> <strong>time more</strong> moles of oxygen gas. </p> <p>Use phosphorus' molar mass to determine how many moles you have in that <mathjax>#"93.0-g"#</mathjax> sample</p> <blockquote> <p><mathjax>#93.0color(red)(cancel(color(black)("g"))) * " 1mole P"/(30.974color(red)(cancel(color(black)("g")))) = "3.0025 moles P"#</mathjax></p> </blockquote> <p>Use the aforementioned mole ratio to determine how many moles of oxygen you would need for many moles of phosphorus to completely take part in the reaction</p> <blockquote> <p><mathjax>#3.0025color(red)(cancel(color(black)("moles P"))) * (color(red)(5)" moles O"_2)/(4color(red)(cancel(color(black)("moles P")))) = "3.753 moles O"_2#</mathjax></p> </blockquote> <p>Now use oxygen's molar mass to determine how many grams of oxygen would contain this many moles</p> <blockquote> <p><mathjax>#3.753color(red)(cancel(color(black)("moles O"_2))) * "32.0 g"/(1color(red)(cancel(color(black)("mole O"_2)))) = "120.1 g O"_2#</mathjax></p> </blockquote> <p>Now, you know that your air sample contains <mathjax>#23%#</mathjax> oxygen <a href="http://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">by mass</a>, which means that you get <mathjax>#"23.0 g"#</mathjax> of oxygen <strong>for every</strong> <mathjax>#"100 g"#</mathjax> of air.</p> <p>This means that you will need</p> <blockquote> <p><mathjax>#120.1color(red)(cancel(color(black)("g O"_2))) * "100.0 g air"/(23.0color(red)(cancel(color(black)("g O"_2)))) = "522.17 g air"#</mathjax></p> </blockquote> <p>Rounded to three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the answer will be </p> <blockquote> <p><mathjax>#m_"air" = color(green)("522 g")#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name"> Suppose a sample of air contains 23.0% oxygen by mass. How many grams of air are required to complete the combustion of 93.0 g of P to diphosphorus pentoxide?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="187031" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-11T17:36:50" itemprop="dateCreated"> Nov 11, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"522 g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your starting point here will be the balanced chemical equation for this combustion reaction</p> <blockquote> <p><mathjax>#4"P"_text((s]) + color(red)(5)"O"_text(2(g]) -> 2"P"_2"O"_text(5(s])#</mathjax></p> </blockquote> <p>Notice that you have a <mathjax>#4:color(red)(5)#</mathjax> <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> between phosphorus and oxygen. This means that, regardless of how many moles of phosphorus you have, the reaction will always need <mathjax>#5/4#</mathjax> <strong>time more</strong> moles of oxygen gas. </p> <p>Use phosphorus' molar mass to determine how many moles you have in that <mathjax>#"93.0-g"#</mathjax> sample</p> <blockquote> <p><mathjax>#93.0color(red)(cancel(color(black)("g"))) * " 1mole P"/(30.974color(red)(cancel(color(black)("g")))) = "3.0025 moles P"#</mathjax></p> </blockquote> <p>Use the aforementioned mole ratio to determine how many moles of oxygen you would need for many moles of phosphorus to completely take part in the reaction</p> <blockquote> <p><mathjax>#3.0025color(red)(cancel(color(black)("moles P"))) * (color(red)(5)" moles O"_2)/(4color(red)(cancel(color(black)("moles P")))) = "3.753 moles O"_2#</mathjax></p> </blockquote> <p>Now use oxygen's molar mass to determine how many grams of oxygen would contain this many moles</p> <blockquote> <p><mathjax>#3.753color(red)(cancel(color(black)("moles O"_2))) * "32.0 g"/(1color(red)(cancel(color(black)("mole O"_2)))) = "120.1 g O"_2#</mathjax></p> </blockquote> <p>Now, you know that your air sample contains <mathjax>#23%#</mathjax> oxygen <a href="http://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">by mass</a>, which means that you get <mathjax>#"23.0 g"#</mathjax> of oxygen <strong>for every</strong> <mathjax>#"100 g"#</mathjax> of air.</p> <p>This means that you will need</p> <blockquote> <p><mathjax>#120.1color(red)(cancel(color(black)("g O"_2))) * "100.0 g air"/(23.0color(red)(cancel(color(black)("g O"_2)))) = "522.17 g air"#</mathjax></p> </blockquote> <p>Rounded to three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the answer will be </p> <blockquote> <p><mathjax>#m_"air" = color(green)("522 g")#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/187031" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What is stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ab82402bf342f48d93ac6"> Question #93ac6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-we-study-stoichiometry"> Why do we study stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-naoh-is-produced-from-1-20-x-102-grams-of-na2o-na2o-h2o-2-naoh"> How many grams of NaOH is produced from #1.20 x 10^2# grams of #Na_2O#? #Na_2O + H_2O -> 2NaOH# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-na2o-are-required-to-produce-1-60-x-102-grams-of-naoh-na2o-h2o"> How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? 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How many grams of air are required to complete the combustion of 93.0 g of P to diphosphorus pentoxide?	null
1,521	abd138e7-6ddd-11ea-a7ed-ccda262736ce	https://socratic.org/questions/how-much-heat-kj-is-needed-to-raise-the-temperature-of-100-0-grams-of-water-from	10.45 kJ	start physical_unit 14 14 heat_energy kj qc_end physical_unit 14 14 16 17 temperature qc_end physical_unit 14 14 19 20 temperature qc_end physical_unit 14 14 11 12 mass qc_end end	[{"type":"physical unit","value":"Needed heat [OF] water [IN] kJ"}]	[{"type":"physical unit","value":"10.45 kJ"}]	[{"type":"physical unit","value":"Temperature1 [OF] water [=] \\pu{25.0 ℃}"},{"type":"physical unit","value":"Temperature2 [OF] water [=] \\pu{50.0 ℃}"},{"type":"physical unit","value":"Mass [OF] water [=] \\pu{100.0 grams}"}]	<h1 class="questionTitle" itemprop="name">How much heat (kJ) is needed to raise the temperature of 100.0 grams of water from 25.0°C to 50.0°C? </h1>	null	10.45 kJ	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to be able to solve this problem, you will need to know the value of water's <a href="http://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a>, which is listed as </p> <blockquote> <p><mathjax>#c = 4.18"J"/("g" ""^@"C")#</mathjax></p> </blockquote> <p>Now, let's assume that you <strong>don't know</strong> the equation that allows you to plug in your values and find how much heat would be needed to heat that much water by that many degrees Celsius. </p> <p>Take a look at the <a href="http://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> of water. As you know, a substance's <strong>specific heat</strong> tells you how much heat is needed in order to increase the temperature of <mathjax>#"1 g"#</mathjax> of that substance by <mathjax>#1^@"C"#</mathjax>.</p> <p>In water's case, you need to provide <mathjax>#"4.18 J"#</mathjax> of heat <strong>per gram</strong> of water to increase its temperature by <mathjax>#1^@"C"#</mathjax>. </p> <p>What if you wanted to increase the temperature of <mathjax>#"1 g"#</mathjax> of water by <mathjax>#2^@"C"#</mathjax> ? You'd need to provide it with </p> <blockquote> <p><mathjax>#overbrace("4.18 J")^(color(purple)("increase by 1"""^@"C")) + overbrace("4.18 J")^(color(purple)("increase by 1"""^@"C")) = overbrace(2 xx "4.18 J")^(color(green)("increase by 2"""^@"C")#</mathjax></p> </blockquote> <p>To increase the temperature of <mathjax>#"1 g"#</mathjax> of water by <mathjax>#n^@"C"#</mathjax>, you'd need to supply it with </p> <blockquote> <p><mathjax>#overbrace("4.18 J")^(color(purple)("increase by 1"""^@"C")) + overbrace("4.18 J")^(color(purple)("increase by 1"""^@"C")) + " ... " = overbrace(n xx "4.18 J")^(color(green)("increase by n"""^@"C")#</mathjax></p> </blockquote> <p>Now let's say that you wanted to cause a <mathjax>#1^@"C"#</mathjax> increase in a <mathjax>#"2-g"#</mathjax> sample of water. You'd need to provide it with </p> <blockquote> <p><mathjax>#overbrace("4.18 J")^(color(brown)("for 1 g of water")) + overbrace("4.18 J")^(color(brown)("for 1 g of water")) = overbrace(2 xx "4.18 J")^(color(green)("for 2 g of water"))#</mathjax></p> </blockquote> <p>To cause a <mathjax>#1^@"C"#</mathjax> increase in the temperature of <mathjax>#m#</mathjax> grams of water, you'd need to supply it with </p> <blockquote> <p><mathjax>#overbrace("4.18 J")^(color(brown)("for 1 g of water")) + overbrace("4.18 J")^(color(brown)("for 1 g of water")) + " ,,, " = overbrace(m xx "4.18 J")^(color(green)("for m g of water"))#</mathjax></p> </blockquote> <p>This means that in order to increase the temperature of <mathjax>#m#</mathjax> grams of water by <mathjax>#n^@"C"#</mathjax>, you need to provide it with </p> <blockquote> <p><mathjax>#"heat" = m xx n xx "specific heat"#</mathjax></p> </blockquote> <p>This will account for increasing the temperature of the <em>first gram</em> of the sample by <mathjax>#n^@"C"#</mathjax>, of the the <em>second gram</em> by <mathjax>#n^@"C"#</mathjax>, of the <em>third gram</em> by <mathjax>#n^@"C"#</mathjax>, and so on until you reach <mathjax>#m#</mathjax> grams of water. </p> <p>And there you have it. The equation that describes all this will thus be</p> <blockquote> <p><mathjax>#color(blue)(q = m * c * DeltaT)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#q#</mathjax> - heat absorbed<br/> <mathjax>#m#</mathjax> - the mass of the sample<br/> <mathjax>#c#</mathjax> - the <a href="http://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> of the substance<br/> <mathjax>#DeltaT#</mathjax> - the change in temperature, defined as <em>final temperature</em> minus <em>initial temperature</em></p> <p>In your case, you will have </p> <blockquote> <p><mathjax>#q = 100.0 color(red)(cancel(color(black)("g"))) * 4.18"J"/(color(red)(cancel(color(black)("g"))) color(red)(cancel(color(black)(""^@"C")))) * (50.0 - 25.0)color(red)(cancel(color(black)(""^@"C")))#</mathjax></p> <p><mathjax>#q = "10,450 J"#</mathjax></p> </blockquote> <p>Rounded to three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a> and expressed in <em>kilojoules</em>, the answer will be </p> <blockquote> <p><mathjax>#"10,450" color(red)(cancel(color(black)("J"))) * "1 kJ"/(10^3color(red)(cancel(color(black)("J")))) = color(green)("10.5 kJ")#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"10.5 kJ"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to be able to solve this problem, you will need to know the value of water's <a href="http://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a>, which is listed as </p> <blockquote> <p><mathjax>#c = 4.18"J"/("g" ""^@"C")#</mathjax></p> </blockquote> <p>Now, let's assume that you <strong>don't know</strong> the equation that allows you to plug in your values and find how much heat would be needed to heat that much water by that many degrees Celsius. </p> <p>Take a look at the <a href="http://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> of water. As you know, a substance's <strong>specific heat</strong> tells you how much heat is needed in order to increase the temperature of <mathjax>#"1 g"#</mathjax> of that substance by <mathjax>#1^@"C"#</mathjax>.</p> <p>In water's case, you need to provide <mathjax>#"4.18 J"#</mathjax> of heat <strong>per gram</strong> of water to increase its temperature by <mathjax>#1^@"C"#</mathjax>. </p> <p>What if you wanted to increase the temperature of <mathjax>#"1 g"#</mathjax> of water by <mathjax>#2^@"C"#</mathjax> ? You'd need to provide it with </p> <blockquote> <p><mathjax>#overbrace("4.18 J")^(color(purple)("increase by 1"""^@"C")) + overbrace("4.18 J")^(color(purple)("increase by 1"""^@"C")) = overbrace(2 xx "4.18 J")^(color(green)("increase by 2"""^@"C")#</mathjax></p> </blockquote> <p>To increase the temperature of <mathjax>#"1 g"#</mathjax> of water by <mathjax>#n^@"C"#</mathjax>, you'd need to supply it with </p> <blockquote> <p><mathjax>#overbrace("4.18 J")^(color(purple)("increase by 1"""^@"C")) + overbrace("4.18 J")^(color(purple)("increase by 1"""^@"C")) + " ... " = overbrace(n xx "4.18 J")^(color(green)("increase by n"""^@"C")#</mathjax></p> </blockquote> <p>Now let's say that you wanted to cause a <mathjax>#1^@"C"#</mathjax> increase in a <mathjax>#"2-g"#</mathjax> sample of water. You'd need to provide it with </p> <blockquote> <p><mathjax>#overbrace("4.18 J")^(color(brown)("for 1 g of water")) + overbrace("4.18 J")^(color(brown)("for 1 g of water")) = overbrace(2 xx "4.18 J")^(color(green)("for 2 g of water"))#</mathjax></p> </blockquote> <p>To cause a <mathjax>#1^@"C"#</mathjax> increase in the temperature of <mathjax>#m#</mathjax> grams of water, you'd need to supply it with </p> <blockquote> <p><mathjax>#overbrace("4.18 J")^(color(brown)("for 1 g of water")) + overbrace("4.18 J")^(color(brown)("for 1 g of water")) + " ,,, " = overbrace(m xx "4.18 J")^(color(green)("for m g of water"))#</mathjax></p> </blockquote> <p>This means that in order to increase the temperature of <mathjax>#m#</mathjax> grams of water by <mathjax>#n^@"C"#</mathjax>, you need to provide it with </p> <blockquote> <p><mathjax>#"heat" = m xx n xx "specific heat"#</mathjax></p> </blockquote> <p>This will account for increasing the temperature of the <em>first gram</em> of the sample by <mathjax>#n^@"C"#</mathjax>, of the the <em>second gram</em> by <mathjax>#n^@"C"#</mathjax>, of the <em>third gram</em> by <mathjax>#n^@"C"#</mathjax>, and so on until you reach <mathjax>#m#</mathjax> grams of water. </p> <p>And there you have it. The equation that describes all this will thus be</p> <blockquote> <p><mathjax>#color(blue)(q = m * c * DeltaT)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#q#</mathjax> - heat absorbed<br/> <mathjax>#m#</mathjax> - the mass of the sample<br/> <mathjax>#c#</mathjax> - the <a href="http://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> of the substance<br/> <mathjax>#DeltaT#</mathjax> - the change in temperature, defined as <em>final temperature</em> minus <em>initial temperature</em></p> <p>In your case, you will have </p> <blockquote> <p><mathjax>#q = 100.0 color(red)(cancel(color(black)("g"))) * 4.18"J"/(color(red)(cancel(color(black)("g"))) color(red)(cancel(color(black)(""^@"C")))) * (50.0 - 25.0)color(red)(cancel(color(black)(""^@"C")))#</mathjax></p> <p><mathjax>#q = "10,450 J"#</mathjax></p> </blockquote> <p>Rounded to three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a> and expressed in <em>kilojoules</em>, the answer will be </p> <blockquote> <p><mathjax>#"10,450" color(red)(cancel(color(black)("J"))) * "1 kJ"/(10^3color(red)(cancel(color(black)("J")))) = color(green)("10.5 kJ")#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How much heat (kJ) is needed to raise the temperature of 100.0 grams of water from 25.0°C to 50.0°C? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/calorimetry" itemprop="url"> <span class="breadcrumb" itemprop="title">Calorimetry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="216827" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-25T13:33:24" itemprop="dateCreated"> Jan 25, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"10.5 kJ"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to be able to solve this problem, you will need to know the value of water's <a href="http://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a>, which is listed as </p> <blockquote> <p><mathjax>#c = 4.18"J"/("g" ""^@"C")#</mathjax></p> </blockquote> <p>Now, let's assume that you <strong>don't know</strong> the equation that allows you to plug in your values and find how much heat would be needed to heat that much water by that many degrees Celsius. </p> <p>Take a look at the <a href="http://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> of water. As you know, a substance's <strong>specific heat</strong> tells you how much heat is needed in order to increase the temperature of <mathjax>#"1 g"#</mathjax> of that substance by <mathjax>#1^@"C"#</mathjax>.</p> <p>In water's case, you need to provide <mathjax>#"4.18 J"#</mathjax> of heat <strong>per gram</strong> of water to increase its temperature by <mathjax>#1^@"C"#</mathjax>. </p> <p>What if you wanted to increase the temperature of <mathjax>#"1 g"#</mathjax> of water by <mathjax>#2^@"C"#</mathjax> ? You'd need to provide it with </p> <blockquote> <p><mathjax>#overbrace("4.18 J")^(color(purple)("increase by 1"""^@"C")) + overbrace("4.18 J")^(color(purple)("increase by 1"""^@"C")) = overbrace(2 xx "4.18 J")^(color(green)("increase by 2"""^@"C")#</mathjax></p> </blockquote> <p>To increase the temperature of <mathjax>#"1 g"#</mathjax> of water by <mathjax>#n^@"C"#</mathjax>, you'd need to supply it with </p> <blockquote> <p><mathjax>#overbrace("4.18 J")^(color(purple)("increase by 1"""^@"C")) + overbrace("4.18 J")^(color(purple)("increase by 1"""^@"C")) + " ... " = overbrace(n xx "4.18 J")^(color(green)("increase by n"""^@"C")#</mathjax></p> </blockquote> <p>Now let's say that you wanted to cause a <mathjax>#1^@"C"#</mathjax> increase in a <mathjax>#"2-g"#</mathjax> sample of water. You'd need to provide it with </p> <blockquote> <p><mathjax>#overbrace("4.18 J")^(color(brown)("for 1 g of water")) + overbrace("4.18 J")^(color(brown)("for 1 g of water")) = overbrace(2 xx "4.18 J")^(color(green)("for 2 g of water"))#</mathjax></p> </blockquote> <p>To cause a <mathjax>#1^@"C"#</mathjax> increase in the temperature of <mathjax>#m#</mathjax> grams of water, you'd need to supply it with </p> <blockquote> <p><mathjax>#overbrace("4.18 J")^(color(brown)("for 1 g of water")) + overbrace("4.18 J")^(color(brown)("for 1 g of water")) + " ,,, " = overbrace(m xx "4.18 J")^(color(green)("for m g of water"))#</mathjax></p> </blockquote> <p>This means that in order to increase the temperature of <mathjax>#m#</mathjax> grams of water by <mathjax>#n^@"C"#</mathjax>, you need to provide it with </p> <blockquote> <p><mathjax>#"heat" = m xx n xx "specific heat"#</mathjax></p> </blockquote> <p>This will account for increasing the temperature of the <em>first gram</em> of the sample by <mathjax>#n^@"C"#</mathjax>, of the the <em>second gram</em> by <mathjax>#n^@"C"#</mathjax>, of the <em>third gram</em> by <mathjax>#n^@"C"#</mathjax>, and so on until you reach <mathjax>#m#</mathjax> grams of water. </p> <p>And there you have it. The equation that describes all this will thus be</p> <blockquote> <p><mathjax>#color(blue)(q = m * c * DeltaT)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#q#</mathjax> - heat absorbed<br/> <mathjax>#m#</mathjax> - the mass of the sample<br/> <mathjax>#c#</mathjax> - the <a href="http://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> of the substance<br/> <mathjax>#DeltaT#</mathjax> - the change in temperature, defined as <em>final temperature</em> minus <em>initial temperature</em></p> <p>In your case, you will have </p> <blockquote> <p><mathjax>#q = 100.0 color(red)(cancel(color(black)("g"))) * 4.18"J"/(color(red)(cancel(color(black)("g"))) color(red)(cancel(color(black)(""^@"C")))) * (50.0 - 25.0)color(red)(cancel(color(black)(""^@"C")))#</mathjax></p> <p><mathjax>#q = "10,450 J"#</mathjax></p> </blockquote> <p>Rounded to three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a> and expressed in <em>kilojoules</em>, the answer will be </p> <blockquote> <p><mathjax>#"10,450" color(red)(cancel(color(black)("J"))) * "1 kJ"/(10^3color(red)(cancel(color(black)("J")))) = color(green)("10.5 kJ")#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/216827" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-differential-scanning-in-calorimetry-work"> How does differential scanning in calorimetry work? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-read-differential-scanning-in-calorimetry"> What information do you get from a differential scanning calorimetry plot? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-measure-calorimetry"> How do you measure calorimetry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531d304102bf341e75b962a7"> Question #962a7 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5335021802bf344ae911dfc5"> Question #1dfc5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/533668f502bf34572c341af6"> Question #41af6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-definition-of-calorimetry"> What is calorimetry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-differential-scanning-calorimeter"> What is a differential scanning calorimeter? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-a-calorimeter-measure-energy"> How can a calorimeter measure energy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-calorimeters-made-of"> What are calorimeters made of? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/calorimetry"> See all questions in Calorimetry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 389641 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How much heat (kJ) is needed to raise the temperature of 100.0 grams of water from 25.0°C to 50.0°C?	null
1,522	ac8ffa34-6ddd-11ea-8cb2-ccda262736ce	https://socratic.org/questions/what-is-the-h-concentration-for-an-aqueous-solution-with-poh-of-4-31-at-25-c	2.04 × 10^(-10) M	start physical_unit 3 3 concentration mol/l qc_end physical_unit 7 8 12 12 poh qc_end physical_unit 7 8 14 15 temperature qc_end end	[{"type":"physical unit","value":"Concentration [OF] H+ [IN] M"}]	[{"type":"physical unit","value":"2.04 × 10^(-10) M"}]	[{"type":"physical unit","value":"pOH [OF] aqueous solution [=] \\pu{4.31}"},{"type":"physical unit","value":"Temperature [OF] aqueous solution [=] \\pu{25 ℃}"}]	<h1 class="questionTitle" itemprop="name">What is the #H^+# concentration for an aqueous solution with pOH of 4.31 at 25°C?</h1>	null	2.04 × 10^(-10) M	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Why clearly? Because <mathjax>#pOH+pOH=14#</mathjax> in aqueous solution under standard conditions....</p> <p>And so ....</p> <p><mathjax>#[H_3O^+]=10^(-9.69)molL^-1=2.04xx10^-10molL^-1#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, clearly <mathjax>#pH=9.69#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Why clearly? Because <mathjax>#pOH+pOH=14#</mathjax> in aqueous solution under standard conditions....</p> <p>And so ....</p> <p><mathjax>#[H_3O^+]=10^(-9.69)molL^-1=2.04xx10^-10molL^-1#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the #H^+# concentration for an aqueous solution with pOH of 4.31 at 25°C?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/ph-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">pH calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="511328" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-11-26T04:03:36" itemprop="dateCreated"> Nov 26, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, clearly <mathjax>#pH=9.69#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Why clearly? Because <mathjax>#pOH+pOH=14#</mathjax> in aqueous solution under standard conditions....</p> <p>And so ....</p> <p><mathjax>#[H_3O^+]=10^(-9.69)molL^-1=2.04xx10^-10molL^-1#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/511328" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-of-a-solution"> How do you determine ph of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-at-an-equivalence-point"> How do you determine pH at an equivalence point? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-molarity"> How do you determine pH from molarity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-alkalinity-mean"> What does alkalinity mean? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-base"> What is a base? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-acid-base-indicators-change-color"> How do acid base indicators change color? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-neutral-ph"> What is a neutral pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-alkalinity-affect-pool-water"> How does alkalinity affect pool water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ph-important-in-drinking-water"> Why is pH important in drinking water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-ph-of-solution"> How can I calculate the pH of a solution? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/ph-calculations"> See all questions in pH calculations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2321 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the #H^+# concentration for an aqueous solution with pOH of 4.31 at 25°C?	null
1,523	a8a94c30-6ddd-11ea-8dc8-ccda262736ce	https://socratic.org/questions/about-60-million-tonnes-of-calcium-oxide-is-made-in-britain-each-year-how-would-	1.06 × 10^8 tonnes	start physical_unit 20 21 mass t qc_end physical_unit 5 6 1 3 mass qc_end end	[{"type":"physical unit","value":"Mass [OF] calcium carbonate [IN] tonnes"}]	[{"type":"physical unit","value":"1.06 × 10^8 tonnes"}]	[{"type":"physical unit","value":"Mass [OF] calcium oxide [=] \\pu{60 million tonnes}"}]	<h1 class="questionTitle" itemprop="name">About 60 million tonnes of calcium oxide is made in Britain each year. How would you calculate the mass of calcium carbonate needed to make this amount of calcium oxide?</h1>	null	1.06 × 10^8 tonnes	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And (ii) equivalent quantities of calcium oxide...........</p> <p><mathjax>#=(60xx10^6"tonnes"xx10^6g"tonne"^-1)/(56.8gmol^-1)#</mathjax></p> <p><mathjax>#=1.06xx10^12"moles CaO"#</mathjax></p> <p>Given the 1:1 <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>, we generate <mathjax>#1.06xx10^12mol#</mathjax> carbon dioxide gas, and CLEARLY we require <mathjax>#1.06xx10^12mol* CaCO_3#</mathjax>.</p> <p>And this represents a mass of .....................................</p> <p><mathjax>#1.06xx10^12molxx100.06gmol^-1=1.06xx10^14g=#</mathjax></p> <p><mathjax>#1.06xx10^11*kg#</mathjax></p> <p>Note that while this seems a large quantity, this is almost exclusively used for the production of mortar and concrete, i.e. building materials. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We need (i) a stoichiometric equation:</p> <p><mathjax>#CaCO_3(s) + Delta rarr CaO(s) + CO_2(g)uarr#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And (ii) equivalent quantities of calcium oxide...........</p> <p><mathjax>#=(60xx10^6"tonnes"xx10^6g"tonne"^-1)/(56.8gmol^-1)#</mathjax></p> <p><mathjax>#=1.06xx10^12"moles CaO"#</mathjax></p> <p>Given the 1:1 <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>, we generate <mathjax>#1.06xx10^12mol#</mathjax> carbon dioxide gas, and CLEARLY we require <mathjax>#1.06xx10^12mol* CaCO_3#</mathjax>.</p> <p>And this represents a mass of .....................................</p> <p><mathjax>#1.06xx10^12molxx100.06gmol^-1=1.06xx10^14g=#</mathjax></p> <p><mathjax>#1.06xx10^11*kg#</mathjax></p> <p>Note that while this seems a large quantity, this is almost exclusively used for the production of mortar and concrete, i.e. building materials. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">About 60 million tonnes of calcium oxide is made in Britain each year. How would you calculate the mass of calcium carbonate needed to make this amount of calcium oxide?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="403984" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-09T07:10:31" itemprop="dateCreated"> Apr 9, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We need (i) a stoichiometric equation:</p> <p><mathjax>#CaCO_3(s) + Delta rarr CaO(s) + CO_2(g)uarr#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And (ii) equivalent quantities of calcium oxide...........</p> <p><mathjax>#=(60xx10^6"tonnes"xx10^6g"tonne"^-1)/(56.8gmol^-1)#</mathjax></p> <p><mathjax>#=1.06xx10^12"moles CaO"#</mathjax></p> <p>Given the 1:1 <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>, we generate <mathjax>#1.06xx10^12mol#</mathjax> carbon dioxide gas, and CLEARLY we require <mathjax>#1.06xx10^12mol* CaCO_3#</mathjax>.</p> <p>And this represents a mass of .....................................</p> <p><mathjax>#1.06xx10^12molxx100.06gmol^-1=1.06xx10^14g=#</mathjax></p> <p><mathjax>#1.06xx10^11*kg#</mathjax></p> <p>Note that while this seems a large quantity, this is almost exclusively used for the production of mortar and concrete, i.e. building materials. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/403984" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What is stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ab82402bf342f48d93ac6"> Question #93ac6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-we-study-stoichiometry"> Why do we study stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-naoh-is-produced-from-1-20-x-102-grams-of-na2o-na2o-h2o-2-naoh"> How many grams of NaOH is produced from #1.20 x 10^2# grams of #Na_2O#? #Na_2O + H_2O -> 2NaOH# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-na2o-are-required-to-produce-1-60-x-102-grams-of-naoh-na2o-h2o"> How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? 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How would you calculate the mass of calcium carbonate needed to make this amount of calcium oxide?	null
1,524	aa385fa6-6ddd-11ea-960d-ccda262736ce	https://socratic.org/questions/the-h-3o-concentration-of-a-solution-is-equal-to-0-8-m-what-is-the-ph-of-the-sol	0.10	start physical_unit 16 17 ph none qc_end physical_unit 1 1 9 10 concentration qc_end end	[{"type":"physical unit","value":"pH [OF] the solution"}]	[{"type":"physical unit","value":"0.10"}]	[{"type":"physical unit","value":"Concentration [OF] H3O+ [=] \\pu{0.8 M}"}]	<h1 class="questionTitle" itemprop="name">The # H_3O^+# concentration of a solution is equal to 0.8 M. What is the pH of the solution?</h1>	null	0.10	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#pH=-log_10(0.8)#</mathjax></p> <p><mathjax>#=#</mathjax> <mathjax>#-(-0.097)#</mathjax> <mathjax>#~=#</mathjax> <mathjax>#0.10#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#pH=0.10#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#pH=-log_10(0.8)#</mathjax></p> <p><mathjax>#=#</mathjax> <mathjax>#-(-0.097)#</mathjax> <mathjax>#~=#</mathjax> <mathjax>#0.10#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">The # H_3O^+# concentration of a solution is equal to 0.8 M. What is the pH of the solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/the-ph-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">pH</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="316978" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-10-02T11:26:17" itemprop="dateCreated"> Oct 2, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#pH=0.10#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#pH=-log_10(0.8)#</mathjax></p> <p><mathjax>#=#</mathjax> <mathjax>#-(-0.097)#</mathjax> <mathjax>#~=#</mathjax> <mathjax>#0.10#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/316978" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-pka"> How do you determine pH from pKa? 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What is the pH of the solution?	null
1,525	a8c3879a-6ddd-11ea-9257-ccda262736ce	https://socratic.org/questions/5886471f11ef6b1cc01bea53	5 L	start physical_unit 5 5 volume l qc_end physical_unit 5 5 1 2 volume qc_end physical_unit 5 5 7 8 temperature qc_end physical_unit 5 5 21 22 temperature qc_end physical_unit 5 5 11 12 pressure qc_end physical_unit 5 5 28 29 pressure qc_end end	[{"type":"physical unit","value":"Volume2 [OF] the gas [IN] L"}]	[{"type":"physical unit","value":"5 L"}]	[{"type":"physical unit","value":"Volume1 [OF] the gas [=] \\pu{2.94 L}"},{"type":"physical unit","value":"Temperature1 [OF] the gas [=] \\pu{294 K}"},{"type":"physical unit","value":"Temperature2 [OF] the gas [=] \\pu{257 K}"},{"type":"physical unit","value":"Pressure1 [OF] the gas [=] \\pu{69.6 kPa}"},{"type":"physical unit","value":"Pressure2 [OF] the gas [=] \\pu{35.6 kPa}"}]	<h1 class="questionTitle" itemprop="name">A #2.94L# volume of gas at #294K# and under #69.6kPa# pressure enclosed in a piston, is cooled to #257K# and the pressure reduced to #35.6*kPa#. What is the new volume? </h1>	null	5 L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#(P_1V_1)/T_1=(P_2V_2)/T_2#</mathjax>, from the <mathjax>#"combined gas law"#</mathjax>.</p> <p>And thus <mathjax>#V_2=(P_1V_1)/T_1xxT_2/P_2#</mathjax>, which expression CLEARLY has the units of volume.</p> <p>So <mathjax>#V_2=(69.9cancel(kPa)xx2.94L)/(294cancel(K))xx(257cancel(K))/(35.6*cancel(kPa))=??L#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#V_2~=5L#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#(P_1V_1)/T_1=(P_2V_2)/T_2#</mathjax>, from the <mathjax>#"combined gas law"#</mathjax>.</p> <p>And thus <mathjax>#V_2=(P_1V_1)/T_1xxT_2/P_2#</mathjax>, which expression CLEARLY has the units of volume.</p> <p>So <mathjax>#V_2=(69.9cancel(kPa)xx2.94L)/(294cancel(K))xx(257cancel(K))/(35.6cancel(kPa))=??L#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A #2.94L# volume of gas at #294K# and under #69.6kPa# pressure enclosed in a piston, is cooled to #257K# and the pressure reduced to #35.6kPa#. What is the new volume? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/gas-pressure" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Pressure</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="368289" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-01-23T18:20:38" itemprop="dateCreated"> Jan 23, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#V_2~=5L#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#(P_1V_1)/T_1=(P_2V_2)/T_2#</mathjax>, from the <mathjax>#"combined gas law"#</mathjax>.</p> <p>And thus <mathjax>#V_2=(P_1V_1)/T_1xxT_2/P_2#</mathjax>, which expression CLEARLY has the units of volume.</p> <p>So <mathjax>#V_2=(69.9cancel(kPa)xx2.94L)/(294cancel(K))xx(257cancel(K))/(35.6*cancel(kPa))=??L#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/368289" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-gas-pressure-be-changed"> How can gas pressure be changed? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-you-increase-gas-pressure-in-a-container"> How can you increase gas pressure in a container? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-gas-pressure-created"> How is gas pressure created? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-does-gas-pressure-increase-when-temperature-increases"> Why does gas pressure increase when temperature increases? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-gas-pressure-zero-at-absolute-zero"> Why is gas pressure zero at absolute zero? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-does-gas-pressure-increase-with-temperature"> Why does gas pressure increase with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-there-no-gas-pressure-in-a-vacuum"> Why is there no gas pressure in a vacuum? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-total-gas-pressure-in-a-sealed-flask-that-contains-oxygen-at-a-parti-1"> What is the total gas pressure in a sealed flask that contains oxygen at a partial pressure of... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-the-absolute-pressure-of-a-gas-is-550-280-kpa-what-is-its-gage-pressure"> If the absolute pressure of a gas is 550.280 kPa, what is its gage pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-a-gas-sample-occupies-4-2-l-at-a-pressure-of-101-kpa-what-volume-will-it-occu"> If a gas sample occupies 4.2 L at a pressure of 101 kPa. What volume will it occupy if the... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/gas-pressure"> See all questions in Gas Pressure </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1387 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A #2.94L# volume of gas at #294K# and under #69.6kPa# pressure enclosed in a piston, is cooled to #257K# and the pressure reduced to #35.6*kPa#. What is the new volume?	null
1,526	ac874725-6ddd-11ea-8ee5-ccda262736ce	https://socratic.org/questions/what-is-the-threshold-odor-number-ton-for-the-follow-ing-sample	10 TON	start physical_unit 8 10 threshold_odor_number t qc_end physical_unit 10 10 18 19 volume qc_end physical_unit 10 10 24 25 volume qc_end physical_unit 29 30 26 27 volume qc_end end	[{"type":"physical unit","value":"threshold odor number [OF] the following sample [IN] TON"}]	[{"type":"physical unit","value":"10 TON"}]	[{"type":"physical unit","value":"Volume1 [OF] sample [=] \\pu{20 mL}"},{"type":"physical unit","value":"Volume2 [OF] sample [=] \\pu{200 mL}"},{"type":"physical unit","value":"Volume [OF] odor-free water [=] \\pu{180 mL}"}]	<h1 class="questionTitle" itemprop="name">What is the threshold odor number (TON) for the follow- ing sample? </h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>The first detectable odor occurred when the 20 mL sample was diluted to 200 mL (180 mL of odor-free water was added to the 20 mL sample)</p></div> </h2> </div> </div>	10 TON	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The <strong>threshold odour number</strong> is the <strong>dilution factor</strong> at which the odour is just detectable.</p> <p>The dilution factor is given by</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(\|color(white)(a/a) "DF" = V_text(f)/V_text(i) color(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>where <mathjax>#V_text(f)#</mathjax> and <mathjax>#V_text(i)#</mathjax> are the final and initial volumes, respectively.</p> <blockquote></blockquote> <p>In the example, you have diluted 20 mL to 200 mL.</p> <p>∴ <mathjax>#"DF" = (200 color(red)(cancel(color(black)("mL"))))/(20 color(red)(cancel(color(black)("mL")))) = 10#</mathjax></p> <p>and</p> <blockquote> <blockquote> <p><mathjax>#"TON" =10#</mathjax></p> </blockquote> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The TON is 10.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The <strong>threshold odour number</strong> is the <strong>dilution factor</strong> at which the odour is just detectable.</p> <p>The dilution factor is given by</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(\|color(white)(a/a) "DF" = V_text(f)/V_text(i) color(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>where <mathjax>#V_text(f)#</mathjax> and <mathjax>#V_text(i)#</mathjax> are the final and initial volumes, respectively.</p> <blockquote></blockquote> <p>In the example, you have diluted 20 mL to 200 mL.</p> <p>∴ <mathjax>#"DF" = (200 color(red)(cancel(color(black)("mL"))))/(20 color(red)(cancel(color(black)("mL")))) = 10#</mathjax></p> <p>and</p> <blockquote> <blockquote> <p><mathjax>#"TON" =10#</mathjax></p> </blockquote> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the threshold odor number (TON) for the follow- ing sample? </h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>The first detectable odor occurred when the 20 mL sample was diluted to 200 mL (180 mL of odor-free water was added to the 20 mL sample)</p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/dilution-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">Dilution Calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="442777" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-21T15:49:23" itemprop="dateCreated"> Jun 21, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The TON is 10.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The <strong>threshold odour number</strong> is the <strong>dilution factor</strong> at which the odour is just detectable.</p> <p>The dilution factor is given by</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(\|color(white)(a/a) "DF" = V_text(f)/V_text(i) color(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>where <mathjax>#V_text(f)#</mathjax> and <mathjax>#V_text(i)#</mathjax> are the final and initial volumes, respectively.</p> <blockquote></blockquote> <p>In the example, you have diluted 20 mL to 200 mL.</p> <p>∴ <mathjax>#"DF" = (200 color(red)(cancel(color(black)("mL"))))/(20 color(red)(cancel(color(black)("mL")))) = 10#</mathjax></p> <p>and</p> <blockquote> <blockquote> <p><mathjax>#"TON" =10#</mathjax></p> </blockquote> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/442777" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-concentration-from-absorbance"> How do you calculate concentration from absorbance? 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The first detectable odor occurred when the 20 mL sample was diluted to 200 mL (180 mL of odor-free water was added to the 20 mL sample)
1,527	a925e4d8-6ddd-11ea-8b13-ccda262736ce	https://socratic.org/questions/what-is-the-molarity-of-a-solution-with-20-moles-of-salt-nacl-in-10-liters-of-so	2.00 mol/L	start physical_unit 12 12 molarity mol/l qc_end physical_unit 12 12 8 9 mole qc_end physical_unit 6 6 14 15 volume qc_end end	[{"type":"physical unit","value":"Molarity [OF] NaCl solution [IN] mol/L"}]	[{"type":"physical unit","value":"2.00 mol/L"}]	[{"type":"physical unit","value":"Mole [OF] NaCl [=] \\pu{20 moles}"},{"type":"physical unit","value":"Volume [OF] NaCl solution [=] \\pu{10 liters}"}]	<h1 class="questionTitle" itemprop="name">What is the molarity of a solution with 20 moles of salt (#NaCl#) in 10 liters of solution?</h1>	null	2.00 mol/L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a> is a measure of concentration, <mathjax>#"amount of substance (mol)"/"volume of solution (L)"#</mathjax>. The units of molarity are naturally <mathjax>#"moles per litre of solution"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#molL^-1#</mathjax>.</p> <p>To get the amount of substance dissolved in a given volume, all I have to do is multiply the concentration by volume, i.e. <mathjax>#molL^-1xxL#</mathjax> <mathjax>#=#</mathjax> <mathjax>#mol#</mathjax>.</p> <p>If I take <mathjax>#1L#</mathjax> of your solution, how many moles of <mathjax>#NaCl#</mathjax> does it contain?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Molarity"="Amount of solute (moles)"/"Volume of solution (litres)"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(20mol)/(10L)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#2molL^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a> is a measure of concentration, <mathjax>#"amount of substance (mol)"/"volume of solution (L)"#</mathjax>. The units of molarity are naturally <mathjax>#"moles per litre of solution"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#molL^-1#</mathjax>.</p> <p>To get the amount of substance dissolved in a given volume, all I have to do is multiply the concentration by volume, i.e. <mathjax>#molL^-1xxL#</mathjax> <mathjax>#=#</mathjax> <mathjax>#mol#</mathjax>.</p> <p>If I take <mathjax>#1L#</mathjax> of your solution, how many moles of <mathjax>#NaCl#</mathjax> does it contain?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the molarity of a solution with 20 moles of salt (#NaCl#) in 10 liters of solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="245231" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-26T06:10:01" itemprop="dateCreated"> Mar 26, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Molarity"="Amount of solute (moles)"/"Volume of solution (litres)"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(20mol)/(10L)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#2molL^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a> is a measure of concentration, <mathjax>#"amount of substance (mol)"/"volume of solution (L)"#</mathjax>. The units of molarity are naturally <mathjax>#"moles per litre of solution"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#molL^-1#</mathjax>.</p> <p>To get the amount of substance dissolved in a given volume, all I have to do is multiply the concentration by volume, i.e. <mathjax>#molL^-1xxL#</mathjax> <mathjax>#=#</mathjax> <mathjax>#mol#</mathjax>.</p> <p>If I take <mathjax>#1L#</mathjax> of your solution, how many moles of <mathjax>#NaCl#</mathjax> does it contain?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/245231" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-morality-be-used-as-a-conversion-factor"> How can molarity be used as a conversion factor? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-high-can-molarity-be"> How high can molarity be? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-molarity-change-with-temperature"> How does molarity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molarity-of-a-solution"> How do you find molarity of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-10-naoh"> What is the molarity of 10 NaOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-3-hydrogen-peroxide"> What is the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 6666 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the molarity of a solution with 20 moles of salt (#NaCl#) in 10 liters of solution?	null
1,528	a9d82536-6ddd-11ea-a93d-ccda262736ce	https://socratic.org/questions/what-volume-of-water-should-be-added-to-500-ml-of-a-1-0-mol-l-cuso-4-aq-solution	500 mL	start physical_unit 3 3 volume ml qc_end physical_unit 14 16 12 13 molarity qc_end physical_unit 14 16 8 9 volume qc_end physical_unit 14 16 21 22 molarity qc_end end	[{"type":"physical unit","value":"Volume [OF] water [IN] mL"}]	[{"type":"physical unit","value":"500 mL"}]	[{"type":"physical unit","value":"Molarity1 [OF] CuSO4 (aq) solution [=] \\pu{1.0 mol/L}"},{"type":"physical unit","value":"Volume1 [OF] CuSO4 (aq) solution [=] \\pu{500 mL}"},{"type":"physical unit","value":"Molarity2 [OF] CuSO4 (aq) solution [=] \\pu{0.5 mol/L}"}]	<h1 class="questionTitle" itemprop="name">What volume of water should be added to 500 mL of a 1.0 mol/L #CuSO_4# (aq) solution to dilute it to 0.5 mol/L?</h1>	null	500 mL	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The symbol for <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a>, M, pronounced molar, has the unit mol/L. </p> <p>When diluting <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a>, use the equation <mathjax>#M_1V_1xxM_2V_2#</mathjax>, where <mathjax>#M_1#</mathjax> is the initial molarity in mol/L, <mathjax>#M_2#</mathjax> is the final molarity, <mathjax>#V_1#</mathjax> is the initial volume in Liters, and <mathjax>#V_2#</mathjax> is the final volume in Liters.</p> <p><strong>Known</strong><br/> <mathjax>#M_1="1.0 mol/L CuSO"_4"#</mathjax><br/> <mathjax>#V_1=500 cancel"mL"xx(1"L")/(1000cancel"mL")="0.5 L"#</mathjax><br/> <mathjax>#M_2="0.5 mol/L CuSO"_4"#</mathjax></p> <p><strong>Unknown</strong><br/> <mathjax>#V_2#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#V_2#</mathjax>. Substitute the known values into the equation and solve.</p> <p><mathjax>#V_2=(M_1V_1)/M_2#</mathjax></p> <p><mathjax>#V_2=(1.0cancel"mol/L"xx0.5"L")/(0.5cancel"mol/L")="1 L"#</mathjax></p> <p>In order to obtain a volume of <mathjax>#"1 L"#</mathjax>, <mathjax>#"500 mL"#</mathjax> of water must be added to the original solution of <mathjax>#"500 mL"#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>In order to obtain a volume of <mathjax>#"1 L"#</mathjax>, <mathjax>#"500 mL"#</mathjax> of water must be added to the original solution of <mathjax>#"500 L"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The symbol for <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a>, M, pronounced molar, has the unit mol/L. </p> <p>When diluting <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a>, use the equation <mathjax>#M_1V_1xxM_2V_2#</mathjax>, where <mathjax>#M_1#</mathjax> is the initial molarity in mol/L, <mathjax>#M_2#</mathjax> is the final molarity, <mathjax>#V_1#</mathjax> is the initial volume in Liters, and <mathjax>#V_2#</mathjax> is the final volume in Liters.</p> <p><strong>Known</strong><br/> <mathjax>#M_1="1.0 mol/L CuSO"_4"#</mathjax><br/> <mathjax>#V_1=500 cancel"mL"xx(1"L")/(1000cancel"mL")="0.5 L"#</mathjax><br/> <mathjax>#M_2="0.5 mol/L CuSO"_4"#</mathjax></p> <p><strong>Unknown</strong><br/> <mathjax>#V_2#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#V_2#</mathjax>. Substitute the known values into the equation and solve.</p> <p><mathjax>#V_2=(M_1V_1)/M_2#</mathjax></p> <p><mathjax>#V_2=(1.0cancel"mol/L"xx0.5"L")/(0.5cancel"mol/L")="1 L"#</mathjax></p> <p>In order to obtain a volume of <mathjax>#"1 L"#</mathjax>, <mathjax>#"500 mL"#</mathjax> of water must be added to the original solution of <mathjax>#"500 mL"#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What volume of water should be added to 500 mL of a 1.0 mol/L #CuSO_4# (aq) solution to dilute it to 0.5 mol/L?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/dilution-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">Dilution Calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="344665" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-12-01T00:54:05" itemprop="dateCreated"> Dec 1, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>In order to obtain a volume of <mathjax>#"1 L"#</mathjax>, <mathjax>#"500 mL"#</mathjax> of water must be added to the original solution of <mathjax>#"500 L"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The symbol for <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a>, M, pronounced molar, has the unit mol/L. </p> <p>When diluting <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a>, use the equation <mathjax>#M_1V_1xxM_2V_2#</mathjax>, where <mathjax>#M_1#</mathjax> is the initial molarity in mol/L, <mathjax>#M_2#</mathjax> is the final molarity, <mathjax>#V_1#</mathjax> is the initial volume in Liters, and <mathjax>#V_2#</mathjax> is the final volume in Liters.</p> <p><strong>Known</strong><br/> <mathjax>#M_1="1.0 mol/L CuSO"_4"#</mathjax><br/> <mathjax>#V_1=500 cancel"mL"xx(1"L")/(1000cancel"mL")="0.5 L"#</mathjax><br/> <mathjax>#M_2="0.5 mol/L CuSO"_4"#</mathjax></p> <p><strong>Unknown</strong><br/> <mathjax>#V_2#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#V_2#</mathjax>. Substitute the known values into the equation and solve.</p> <p><mathjax>#V_2=(M_1V_1)/M_2#</mathjax></p> <p><mathjax>#V_2=(1.0cancel"mol/L"xx0.5"L")/(0.5cancel"mol/L")="1 L"#</mathjax></p> <p>In order to obtain a volume of <mathjax>#"1 L"#</mathjax>, <mathjax>#"500 mL"#</mathjax> of water must be added to the original solution of <mathjax>#"500 mL"#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/344665" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-concentration-from-absorbance"> How do you calculate concentration from absorbance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-concentration-from-titration"> How do you calculate concentration from titration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-dilution-factor"> How do you calculate dilution factor? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-do-serial-dilution-calculations"> How do you calculate serial dilutions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-calculate-concentration-of-solution-when-its-diluted"> How to calculate concentration of solution when it's diluted? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-examples-of-dilution-calculations"> What are some examples of dilution calculations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-would-be-the-concentration-of-a-solution-made-by-adding-250-ml-of-water-to-"> What would be the concentration of a solution made by adding 250 mL of water to 45.0 mL of 4.2 M KOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-would-be-the-concentration-of-a-solution-made-by-diluting-45-0-ml-of-4-2-m-"> What would be the concentration of a solution made by diluting 45.0 mL of 4.2 M KOH to 250 mL? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-a-solution-that-is-made-by-diluting-50-00-ml-of-a-4-74-m"> What is the molarity of a solution that is made by diluting 50.00 mL of a 4.74 M solution of HCl... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-volume-of-water-would-you-add-to-15-00-ml-of-a-6-77-m-solution-of-nitric-ac"> What volume of water would you add to 15.00 mL of a 6.77 M solution of nitric acid in order to... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/dilution-calculations"> See all questions in Dilution Calculations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 45487 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What volume of water should be added to 500 mL of a 1.0 mol/L #CuSO_4# (aq) solution to dilute it to 0.5 mol/L?	null
1,529	aa4f835c-6ddd-11ea-a54c-ccda262736ce	https://socratic.org/questions/how-would-you-determine-the-molecular-formula-of-npcl2-347-64-g-mol	P3N3Cl6	start chemical_formula qc_end c_other OTHER qc_end end	[{"type":"other","value":"Chemical Formula [OF] the substance [IN] molecular"}]	[{"type":"chemical equation","value":"P3N3Cl6"}]	[{"type":"other","value":"The empirical formula of the substance is NPCl2."},{"type":"physical unit","value":"Molar mass [OF] the substance [=] \\pu{347.64 g/mol}"}]	<h1 class="questionTitle" itemprop="name">How would you determine the molecular formula of #NPCl_2# (347.64 g/mol)? </h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>How would you determine the molecular formula of <mathjax>#NPCl_2 (347.64 g/(mol))#</mathjax>?</p></div> </h2> </div> </div>	P3N3Cl6	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Given that <mathjax>#(EF)_n = MF#</mathjax>, all we have to do is to use atomic masses and solve for <mathjax>#n#</mathjax>.</p> <p>So <mathjax>#347.64gmol^(-1) = nxx(30.9747+14.01+2xx35.45)gmol^-1#</mathjax>.</p> <p>And <mathjax>#347.64gmol^(-1) = n(115.88)gmol^(-1)#</mathjax></p> <p><mathjax>#n = ??#</mathjax> And molecular formula <mathjax>#= (PNCl_2)xxn = P_31N_5Cl_102?#</mathjax></p> <p>Note that sometimes (but not here). the empirical formula is the same as the molecular formula. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>I presume you have quoted the empirical formula in <mathjax>#PNCl_2#</mathjax>. The molecular formula is ALWAYS a multiple of the empirical formula</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Given that <mathjax>#(EF)_n = MF#</mathjax>, all we have to do is to use atomic masses and solve for <mathjax>#n#</mathjax>.</p> <p>So <mathjax>#347.64gmol^(-1) = nxx(30.9747+14.01+2xx35.45)gmol^-1#</mathjax>.</p> <p>And <mathjax>#347.64gmol^(-1) = n(115.88)gmol^(-1)#</mathjax></p> <p><mathjax>#n = ??#</mathjax> And molecular formula <mathjax>#= (PNCl_2)xxn = P_31N_5Cl_102?#</mathjax></p> <p>Note that sometimes (but not here). the empirical formula is the same as the molecular formula. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How would you determine the molecular formula of #NPCl_2# (347.64 g/mol)? </h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>How would you determine the molecular formula of <mathjax>#NPCl_2 (347.64 g/(mol))#</mathjax>?</p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="185062" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-07T09:40:44" itemprop="dateCreated"> Nov 7, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>I presume you have quoted the empirical formula in <mathjax>#PNCl_2#</mathjax>. The molecular formula is ALWAYS a multiple of the empirical formula</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Given that <mathjax>#(EF)_n = MF#</mathjax>, all we have to do is to use atomic masses and solve for <mathjax>#n#</mathjax>.</p> <p>So <mathjax>#347.64gmol^(-1) = nxx(30.9747+14.01+2xx35.45)gmol^-1#</mathjax>.</p> <p>And <mathjax>#347.64gmol^(-1) = n(115.88)gmol^(-1)#</mathjax></p> <p><mathjax>#n = ??#</mathjax> And molecular formula <mathjax>#= (PNCl_2)xxn = P_31N_5Cl_102?#</mathjax></p> <p>Note that sometimes (but not here). the empirical formula is the same as the molecular formula. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/185062" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molecular-formula-of-a-compound"> How do you find molecular formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-diamond"> What is the chemical formula of a diamond? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-carbohydrate"> What is the chemical formula of a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-valproic-acid"> What is the empirical formula for valproic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-of-magnesium-oxide"> What is the empirical formula of magnesium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-empirical-formula-not-double-that-of-the-monosaccharides"> Why is the empirical formula not double that of the monosaccharides? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5331180502bf342f40b5c3b5"> Question #5c3b5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-molecular-formula-represents-a-carbohydrate"> What molecular formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-of-vinegar"> What is the molecular formula of vinegar? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/empirical-and-molecular-formulas"> See all questions in Empirical and Molecular Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 4240 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How would you determine the molecular formula of #NPCl_2# (347.64 g/mol)?	How would you determine the molecular formula of #NPCl_2 (347.64 g/(mol))#?
1,530	ad1fb51e-6ddd-11ea-8740-ccda262736ce	https://socratic.org/questions/58696c097c01493d0d626ee3	6.56 × 10^(-3) M	start physical_unit 27 29 molarity mol/l qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Molar concentration [OF] the methanoic acid [IN] M"}]	[{"type":"physical unit","value":"6.56 × 10^(-3) M"}]	[{"type":"physical unit","value":"Volume [OF] HCHO2 solution [=] \\pu{250.0 mL}"},{"type":"physical unit","value":"Volume [OF] NaOH solution [=] \\pu{16.32 mL}"},{"type":"physical unit","value":"Molar concentration [OF] NaOH solution [=] \\pu{0.1004 mol/L}"},{"type":"other","value":"Reach the end-point."}]	<h1 class="questionTitle" itemprop="name">In a titration of 250.0 mL of methanoic acid (#"HCHO"_2#), takes 16.32 mL of 0.1004 mol/L NaOH to reach the end-point. What is the molar concentration of the methanoic acid? </h1>	null	6.56 × 10^(-3) M	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>A titration calculation is really a <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> problem.</p> <p>You always use the same four steps.</p> <blockquote></blockquote> <p><strong>Step 1. Write the balanced equation</strong></p> <p><mathjax>#"HCOOH + NaOH" → "HCOONa" + "H"_2"O"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 2. Calculate the moles of NaOH</strong></p> <p><mathjax>#"Moles of NaOH" = "0.016 32" color(red)(cancel(color(black)("L NaOH"))) × "0.1004 mol NaOH"/(1 color(red)(cancel(color(black)("L NaOH")))) = "0.001 639 mol NaOH"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 3. Calculate the moles of <mathjax>#"HCOOH"#</mathjax></strong></p> <p><mathjax>#"Moles of HCOOH" = "0.001 639" color(red)(cancel(color(black)("mol NaOH"))) × "1 mol HCOOH"/(1 color(red)(cancel(color(black)("mol NaOH")))) = "0.001 639 mol HCOOH"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 4. Calculate the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of the <mathjax>#"HCOOH"#</mathjax></strong></p> <p><mathjax>#"Molarity of HCOOH" = "moles"/"litres" = "0.001 639 mol"/"0.250 00 L" = "0.006 556 mol/L"#</mathjax></p> <p>(<strong>Note:</strong> I think the volume should have been 25.00 mL.)</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The concentration of the methanoic acid is 0.006 556 mol/L.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>A titration calculation is really a <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> problem.</p> <p>You always use the same four steps.</p> <blockquote></blockquote> <p><strong>Step 1. Write the balanced equation</strong></p> <p><mathjax>#"HCOOH + NaOH" → "HCOONa" + "H"_2"O"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 2. Calculate the moles of NaOH</strong></p> <p><mathjax>#"Moles of NaOH" = "0.016 32" color(red)(cancel(color(black)("L NaOH"))) × "0.1004 mol NaOH"/(1 color(red)(cancel(color(black)("L NaOH")))) = "0.001 639 mol NaOH"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 3. Calculate the moles of <mathjax>#"HCOOH"#</mathjax></strong></p> <p><mathjax>#"Moles of HCOOH" = "0.001 639" color(red)(cancel(color(black)("mol NaOH"))) × "1 mol HCOOH"/(1 color(red)(cancel(color(black)("mol NaOH")))) = "0.001 639 mol HCOOH"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 4. Calculate the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of the <mathjax>#"HCOOH"#</mathjax></strong></p> <p><mathjax>#"Molarity of HCOOH" = "moles"/"litres" = "0.001 639 mol"/"0.250 00 L" = "0.006 556 mol/L"#</mathjax></p> <p>(<strong>Note:</strong> I think the volume should have been 25.00 mL.)</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">In a titration of 250.0 mL of methanoic acid (#"HCHO"_2#), takes 16.32 mL of 0.1004 mol/L NaOH to reach the end-point. What is the molar concentration of the methanoic acid? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#reactions-in-solution" itemprop="url"> <span class="breadcrumb" itemprop="title">Reactions in Solution</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/reactions-in-solution/titration-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">Titration Calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="359152" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-01-02T00:13:47" itemprop="dateCreated"> Jan 2, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The concentration of the methanoic acid is 0.006 556 mol/L.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>A titration calculation is really a <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> problem.</p> <p>You always use the same four steps.</p> <blockquote></blockquote> <p><strong>Step 1. Write the balanced equation</strong></p> <p><mathjax>#"HCOOH + NaOH" → "HCOONa" + "H"_2"O"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 2. Calculate the moles of NaOH</strong></p> <p><mathjax>#"Moles of NaOH" = "0.016 32" color(red)(cancel(color(black)("L NaOH"))) × "0.1004 mol NaOH"/(1 color(red)(cancel(color(black)("L NaOH")))) = "0.001 639 mol NaOH"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 3. Calculate the moles of <mathjax>#"HCOOH"#</mathjax></strong></p> <p><mathjax>#"Moles of HCOOH" = "0.001 639" color(red)(cancel(color(black)("mol NaOH"))) × "1 mol HCOOH"/(1 color(red)(cancel(color(black)("mol NaOH")))) = "0.001 639 mol HCOOH"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 4. Calculate the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of the <mathjax>#"HCOOH"#</mathjax></strong></p> <p><mathjax>#"Molarity of HCOOH" = "moles"/"litres" = "0.001 639 mol"/"0.250 00 L" = "0.006 556 mol/L"#</mathjax></p> <p>(<strong>Note:</strong> I think the volume should have been 25.00 mL.)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/359152" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-do-acid-base-titration-calculations"> How do you do acid base titration calculations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-use-titration-calculations-to-find-ph"> How do you use titration calculations to find pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/radox-titration"> What is a redox titration and what is it used for? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-titration-used-when-standardizing-a-solution"> Why is titration used when standardizing a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-titration-suitable-for-sodium-nitrate"> Is titration suitable for sodium nitrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-do-redox-titration-calculations"> How can I do redox titration calculations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-titration-of-weak-acid-and-strong-base"> How can I calculate the titration of a weak acid and a strong base? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-make-back-titration-calculations"> How can I make back titration calculations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-titration-affect-molarity"> How does titration affect molarity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-endpoint-of-a-titration-differ-from-the-equivalence-point"> How does the endpoint of a titration differ from the equivalence point? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/reactions-in-solution/titration-calculations"> See all questions in Titration Calculations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1745 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	In a titration of 250.0 mL of methanoic acid (#"HCHO"_2#), takes 16.32 mL of 0.1004 mol/L NaOH to reach the end-point. What is the molar concentration of the methanoic acid?	null
1,531	ab7312e8-6ddd-11ea-93a9-ccda262736ce	https://socratic.org/questions/if-the-pressure-of-a-2-00-l-sample-of-gas-is-50-0-kpa-what-pressure-does-the-gas	5.00 MPa	start physical_unit 7 9 pressure mpa qc_end physical_unit 7 9 11 12 pressure qc_end physical_unit 7 9 5 6 volume qc_end physical_unit 7 9 25 26 volume qc_end end	[{"type":"physical unit","value":"Pressure2 [OF] the gas sample [IN] MPa"}]	[{"type":"physical unit","value":"5.00 MPa"}]	[{"type":"physical unit","value":"Pressure1 [OF] the gas sample [=] \\pu{50.0 kPa}"},{"type":"physical unit","value":"Volume1 [OF] the gas sample [=] \\pu{2.00 L}"},{"type":"physical unit","value":"Volume2 [OF] the gas sample [=] \\pu{20.0 mL}"}]	<h1 class="questionTitle" itemprop="name">If the pressure of a 2.00 L sample of gas is 50.0 kPa, what pressure does the gas exert if its volume is decreased to 20.0 mL? </h1>	null	5.00 MPa	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>This appears to be a <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's Law</a></strong> problem.</p> <p>Boyle's Law is</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a) P_1V_1 = P_2V_2color(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p><mathjax>#P_1 = "50.0 kPa"; V_1 = "2.00 L"#</mathjax><br/> <mathjax>#P_2 = "?";color(white)(mmmll) V_2 = "20.0 mL" = "0.0200 L"#</mathjax></p> <blockquote></blockquote> <p>We can rearrange Boyle's Law to get</p> <blockquote> <blockquote> <p><mathjax>#P_2 = P_1 × V_1/V_2#</mathjax></p> </blockquote> </blockquote> <p>∴ <mathjax>#P_2 = "50.0 kPa" × (2.00 color(red)(cancel(color(black)("L"))))/(0.0200 color(red)(cancel(color(black)("L")))) = "5000 kPa" = "5.00 MPa"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The gas exerts a pressure of 5.00 MPa.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>This appears to be a <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's Law</a></strong> problem.</p> <p>Boyle's Law is</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a) P_1V_1 = P_2V_2color(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p><mathjax>#P_1 = "50.0 kPa"; V_1 = "2.00 L"#</mathjax><br/> <mathjax>#P_2 = "?";color(white)(mmmll) V_2 = "20.0 mL" = "0.0200 L"#</mathjax></p> <blockquote></blockquote> <p>We can rearrange Boyle's Law to get</p> <blockquote> <blockquote> <p><mathjax>#P_2 = P_1 × V_1/V_2#</mathjax></p> </blockquote> </blockquote> <p>∴ <mathjax>#P_2 = "50.0 kPa" × (2.00 color(red)(cancel(color(black)("L"))))/(0.0200 color(red)(cancel(color(black)("L")))) = "5000 kPa" = "5.00 MPa"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">If the pressure of a 2.00 L sample of gas is 50.0 kPa, what pressure does the gas exert if its volume is decreased to 20.0 mL? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/boyle-s-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Boyle's Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="284050" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-02T21:53:18" itemprop="dateCreated"> Jul 2, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The gas exerts a pressure of 5.00 MPa.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>This appears to be a <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's Law</a></strong> problem.</p> <p>Boyle's Law is</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a) P_1V_1 = P_2V_2color(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p><mathjax>#P_1 = "50.0 kPa"; V_1 = "2.00 L"#</mathjax><br/> <mathjax>#P_2 = "?";color(white)(mmmll) V_2 = "20.0 mL" = "0.0200 L"#</mathjax></p> <blockquote></blockquote> <p>We can rearrange Boyle's Law to get</p> <blockquote> <blockquote> <p><mathjax>#P_2 = P_1 × V_1/V_2#</mathjax></p> </blockquote> </blockquote> <p>∴ <mathjax>#P_2 = "50.0 kPa" × (2.00 color(red)(cancel(color(black)("L"))))/(0.0200 color(red)(cancel(color(black)("L")))) = "5000 kPa" = "5.00 MPa"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/284050" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-graph-boyles-law"> How do you graph Boyle's law? 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1,532	a9443124-6ddd-11ea-aed2-ccda262736ce	https://socratic.org/questions/concerning-the-reaction-c-o-2-co-2-if-the-h-393-kj-mol-how-many-grams-of-c-must-	8.40 grams	start physical_unit 3 3 mass g qc_end chemical_equation 3 7 qc_end physical_unit 1 2 12 13 deltah^0 qc_end physical_unit 1 2 24 25 heat_energy qc_end end	[{"type":"physical unit","value":"Mass [OF] C [IN] grams"}]	[{"type":"physical unit","value":"8.40 grams"}]	[{"type":"chemical equation","value":"C + O2 -> CO2"},{"type":"physical unit","value":"DeltaH^0 [OF] the reaction [=] \\pu{393 kJ/mol}"},{"type":"physical unit","value":"Release heat [OF] the reaction [=] \\pu{275 kJ}"}]	<h1 class="questionTitle" itemprop="name">Concerning the reaction #C + O_2 -> CO_2#, if the #ΔH° = -393# #kJ#/#mol#, how many grams of #C# must be burned to release #275# #kJ# of heat?</h1>	null	8.40 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Notice that the <em>standard <a href="http://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> change of reaction</em>, <mathjax>#DeltaH^@#</mathjax>, is given to you in kilojoules <strong>per mole</strong>, which means that it corresponds to the formation of <strong>one mole</strong> of carbon dioxide. </p> <blockquote> <p><mathjax>#"C"_text((s]) + "O"_text(2(g]) -> "CO"_text(2(g])#</mathjax></p> </blockquote> <p>More specifically, when <strong>one mole</strong> of carbon reacts with <strong>one mole</strong> of oxygen gas, <strong>one mole</strong> of carbon dioxide is produced and <mathjax>#"393 kJ"#</mathjax> of heat are <strong>given off</strong>. </p> <p>Remember, a <em>negative</em> enthalpy change of reaction tells you that heat is being <em>given off</em>, i.e. the reaction is <a href="https://socratic.org/chemistry/thermochemistry/exothermic-processes">exothermic</a>. </p> <p>Now, in order to determine how much carbon is needed in order for the reaction to give off <mathjax>#"275 kJ"#</mathjax> of heat, use the fact that <strong>one mole</strong> of carbon is needed to give off <mathjax>#"393 kJ"#</mathjax> of heat. </p> <blockquote> <p><mathjax>#275 color(red)(cancel(color(black)("kJ"))) * "1 mole C"/(393 color(red)(cancel(color(black)("kJ")))) = "0.6997 moles C"#</mathjax></p> </blockquote> <p>To see how many grams of carbon would contain this many moles, use carbon's <em>molar mass</em></p> <blockquote> <p><mathjax>#0.6997 color(red)(cancel(color(black)("moles C"))) * "12.011 g"/(1color(red)(cancel(color(black)("mole C")))) = color(green)("8.40 g")#</mathjax></p> </blockquote> <p>So, when <mathjax>#8.40#</mathjax> grams of carbon react with <em>enough</em> oxygen gas, the reaction will give off <mathjax>#"275 kJ"#</mathjax> of heat. This is equivalent to having a standard enthalpy change of reaction equal to </p> <blockquote> <p><mathjax>#DeltaH^@ = -"275 kJ"#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"8.40 g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Notice that the <em>standard <a href="http://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> change of reaction</em>, <mathjax>#DeltaH^@#</mathjax>, is given to you in kilojoules <strong>per mole</strong>, which means that it corresponds to the formation of <strong>one mole</strong> of carbon dioxide. </p> <blockquote> <p><mathjax>#"C"_text((s]) + "O"_text(2(g]) -> "CO"_text(2(g])#</mathjax></p> </blockquote> <p>More specifically, when <strong>one mole</strong> of carbon reacts with <strong>one mole</strong> of oxygen gas, <strong>one mole</strong> of carbon dioxide is produced and <mathjax>#"393 kJ"#</mathjax> of heat are <strong>given off</strong>. </p> <p>Remember, a <em>negative</em> enthalpy change of reaction tells you that heat is being <em>given off</em>, i.e. the reaction is <a href="https://socratic.org/chemistry/thermochemistry/exothermic-processes">exothermic</a>. </p> <p>Now, in order to determine how much carbon is needed in order for the reaction to give off <mathjax>#"275 kJ"#</mathjax> of heat, use the fact that <strong>one mole</strong> of carbon is needed to give off <mathjax>#"393 kJ"#</mathjax> of heat. </p> <blockquote> <p><mathjax>#275 color(red)(cancel(color(black)("kJ"))) * "1 mole C"/(393 color(red)(cancel(color(black)("kJ")))) = "0.6997 moles C"#</mathjax></p> </blockquote> <p>To see how many grams of carbon would contain this many moles, use carbon's <em>molar mass</em></p> <blockquote> <p><mathjax>#0.6997 color(red)(cancel(color(black)("moles C"))) * "12.011 g"/(1color(red)(cancel(color(black)("mole C")))) = color(green)("8.40 g")#</mathjax></p> </blockquote> <p>So, when <mathjax>#8.40#</mathjax> grams of carbon react with <em>enough</em> oxygen gas, the reaction will give off <mathjax>#"275 kJ"#</mathjax> of heat. This is equivalent to having a standard enthalpy change of reaction equal to </p> <blockquote> <p><mathjax>#DeltaH^@ = -"275 kJ"#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Concerning the reaction #C + O_2 -> CO_2#, if the #ΔH° = -393# #kJ#/#mol#, how many grams of #C# must be burned to release #275# #kJ# of heat?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/enthalpy" itemprop="url"> <span class="breadcrumb" itemprop="title">Enthalpy</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="197830" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-08T19:27:18" itemprop="dateCreated"> Dec 8, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"8.40 g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Notice that the <em>standard <a href="http://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> change of reaction</em>, <mathjax>#DeltaH^@#</mathjax>, is given to you in kilojoules <strong>per mole</strong>, which means that it corresponds to the formation of <strong>one mole</strong> of carbon dioxide. </p> <blockquote> <p><mathjax>#"C"_text((s]) + "O"_text(2(g]) -> "CO"_text(2(g])#</mathjax></p> </blockquote> <p>More specifically, when <strong>one mole</strong> of carbon reacts with <strong>one mole</strong> of oxygen gas, <strong>one mole</strong> of carbon dioxide is produced and <mathjax>#"393 kJ"#</mathjax> of heat are <strong>given off</strong>. </p> <p>Remember, a <em>negative</em> enthalpy change of reaction tells you that heat is being <em>given off</em>, i.e. the reaction is <a href="https://socratic.org/chemistry/thermochemistry/exothermic-processes">exothermic</a>. </p> <p>Now, in order to determine how much carbon is needed in order for the reaction to give off <mathjax>#"275 kJ"#</mathjax> of heat, use the fact that <strong>one mole</strong> of carbon is needed to give off <mathjax>#"393 kJ"#</mathjax> of heat. </p> <blockquote> <p><mathjax>#275 color(red)(cancel(color(black)("kJ"))) * "1 mole C"/(393 color(red)(cancel(color(black)("kJ")))) = "0.6997 moles C"#</mathjax></p> </blockquote> <p>To see how many grams of carbon would contain this many moles, use carbon's <em>molar mass</em></p> <blockquote> <p><mathjax>#0.6997 color(red)(cancel(color(black)("moles C"))) * "12.011 g"/(1color(red)(cancel(color(black)("mole C")))) = color(green)("8.40 g")#</mathjax></p> </blockquote> <p>So, when <mathjax>#8.40#</mathjax> grams of carbon react with <em>enough</em> oxygen gas, the reaction will give off <mathjax>#"275 kJ"#</mathjax> of heat. This is equivalent to having a standard enthalpy change of reaction equal to </p> <blockquote> <p><mathjax>#DeltaH^@ = -"275 kJ"#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/197830" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-enthalpy-changes-expressed-in-chemical-equations"> How are enthalpy changes expressed in chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-enthalpy-change-be-determined-for-an-aqueous-solution"> How can enthalpy change be determined for an aqueous solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-enthalpy-change-with-pressure"> How does enthalpy change with pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-standard-molar-enthalpy-formation"> How do you calculate standard molar enthalpy of formation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-enthalpy-a-state-function"> Why is enthalpy a state function? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-enthalpy-of-formation-of-oxygen-zero"> Why is the enthalpy of formation of oxygen zero? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-enthalpy-a-state-function-2"> Why is enthalpy a state function? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-enthalpy-cannot-be-measured-directly"> Why can enthalpy not be measured directly? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-pressure-affect-enthalpy"> How does pressure affect enthalpy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-enthalpy-relate-to-internal-energy"> How does enthalpy relate to internal energy? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/enthalpy"> See all questions in Enthalpy </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 54025 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Concerning the reaction #C + O_2 -> CO_2#, if the #ΔH° = -393# #kJ#/#mol#, how many grams of #C# must be burned to release #275# #kJ# of heat?	null
1,533	aa7d53ca-6ddd-11ea-a50d-ccda262736ce	https://socratic.org/questions/59703d0e11ef6b7fd82b0e78	19.55 L	start physical_unit 4 5 volume l qc_end physical_unit 4 5 1 2 mole qc_end physical_unit 4 5 9 10 mole qc_end physical_unit 4 5 17 18 volume qc_end end	[{"type":"physical unit","value":"Volume2 [OF] freon-12 gas [IN] L"}]	[{"type":"physical unit","value":"19.55 L"}]	[{"type":"physical unit","value":"Added mole [OF] freon-12 gas [=] \\pu{3.50 mols}"},{"type":"physical unit","value":"Mole1 [OF] freon-12 gas [=] \\pu{7.48 mols}"},{"type":"physical unit","value":"Volume1 [OF] freon-12 gas [=] \\pu{28.7 L}"}]	<h1 class="questionTitle" itemprop="name">If #"3.50 mols"# of freon-12 gas was added to #"7.48 mols"# of it, and it started at #"28.7 L"#, what is its final volume?</h1>	null	19.55 L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Generally, the answers are checked by experienced posters, and you will see many corrections and additions to answers. But this is not a cheat site; the emphasis is on the explanation not the final result, which the student is obligated to provide themselves. Learning will not occur otherwise. </p> <p>Old <a href="https://socratic.org/chemistry/the-behavior-of-gases/avogadro-s-law">Avogadro's Law</a> states that <mathjax>#"equal volumes of all gases,"#</mathjax> <mathjax>#"at the same temperature and pressure, have the same number"#</mathjax> <mathjax>#"of molecules". #</mathjax></p> <p>And thus <mathjax>#Vpropn#</mathjax>, where <mathjax>#n="numbers of moles of gas"#</mathjax></p> <p>And so <mathjax>#(7.48mol+3.50mol)xxk=28.7L#</mathjax></p> <p><mathjax>#k=2.61Lmol^-1#</mathjax>.</p> <p>And so <mathjax>#P_"initial"=2.61Lmol^-1xx7.48mol~=20*L#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>When you pay peanuts you get monkeys..........</p> <p><mathjax>#P_"initial"~=20L#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Generally, the answers are checked by experienced posters, and you will see many corrections and additions to answers. But this is not a cheat site; the emphasis is on the explanation not the final result, which the student is obligated to provide themselves. Learning will not occur otherwise. </p> <p>Old <a href="https://socratic.org/chemistry/the-behavior-of-gases/avogadro-s-law">Avogadro's Law</a> states that <mathjax>#"equal volumes of all gases,"#</mathjax> <mathjax>#"at the same temperature and pressure, have the same number"#</mathjax> <mathjax>#"of molecules". #</mathjax></p> <p>And thus <mathjax>#Vpropn#</mathjax>, where <mathjax>#n="numbers of moles of gas"#</mathjax></p> <p>And so <mathjax>#(7.48mol+3.50mol)xxk=28.7L#</mathjax></p> <p><mathjax>#k=2.61Lmol^-1#</mathjax>.</p> <p>And so <mathjax>#P_"initial"=2.61Lmol^-1xx7.48mol~=20L#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">If #"3.50 mols"# of freon-12 gas was added to #"7.48 mols"# of it, and it started at #"28.7 L"#, what is its final volume?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/avogadro-s-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Avogadro's Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="453904" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-07-20T05:34:54" itemprop="dateCreated"> Jul 20, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>When you pay peanuts you get monkeys..........</p> <p><mathjax>#P_"initial"~=20L#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Generally, the answers are checked by experienced posters, and you will see many corrections and additions to answers. But this is not a cheat site; the emphasis is on the explanation not the final result, which the student is obligated to provide themselves. Learning will not occur otherwise. </p> <p>Old <a href="https://socratic.org/chemistry/the-behavior-of-gases/avogadro-s-law">Avogadro's Law</a> states that <mathjax>#"equal volumes of all gases,"#</mathjax> <mathjax>#"at the same temperature and pressure, have the same number"#</mathjax> <mathjax>#"of molecules". #</mathjax></p> <p>And thus <mathjax>#Vpropn#</mathjax>, where <mathjax>#n="numbers of moles of gas"#</mathjax></p> <p>And so <mathjax>#(7.48mol+3.50mol)xxk=28.7L#</mathjax></p> <p><mathjax>#k=2.61Lmol^-1#</mathjax>.</p> <p>And so <mathjax>#P_"initial"=2.61Lmol^-1xx7.48mol~=20L#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/453904" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="453906" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/truong-son-n"><img alt="" class="" src="https://profilepictures.socratic.org/07k4plnQfmnmzMuesQzw_14844-1449381920.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/truong-son-n"> Truong-Son N. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-07-20T05:35:23" itemprop="dateCreated"> Jul 20, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerDescription"> <div> <div class="markdown"><blockquote> <p><mathjax>#V_1 = "19.6 L"#</mathjax></p> </blockquote> <p>That is, if freon-12, or <mathjax>#"CF"_2"Cl"_2#</mathjax>, at whatever the balloon temperature and pressure are, is ideal...</p> <hr/> <p>Well, if we assume the <strong>Freon-12</strong> gas is ideal, then we can use the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a>:</p> <blockquote> <p><mathjax>#PV = nRT#</mathjax>,</p> <p>where:</p> <ul> <li><mathjax>#P#</mathjax> is the <strong>pressure</strong> in, say, <mathjax>#"atm"#</mathjax>.</li> <li><mathjax>#V#</mathjax> is the <strong>volume</strong>, usually in <mathjax>#"L"#</mathjax>.</li> <li><mathjax>#n#</mathjax> is the <strong>mols</strong> of ideal gas.</li> <li><mathjax>#R = "0.082057 L"cdot"atm/mol"cdot"K"#</mathjax> is the <strong>universal gas constant</strong>, if pressure is in <mathjax>#"atm"#</mathjax> and volume is in <mathjax>#"L"#</mathjax>.</li> <li><mathjax>#T#</mathjax> is <strong>temperature</strong> in <mathjax>#"K"#</mathjax>.</li> </ul> </blockquote> <p>There were unstated conditions, and they were:</p> <ul> <li>constant temperature</li> <li>constant pressure</li> </ul> <p>Only then can we come up with <strong>Avogadro's principle</strong>... We set initial and final states as:</p> <blockquote> <p><mathjax>#PV_1 = n_1RT#</mathjax></p> <p><mathjax>#PV_2 = n_2RT#</mathjax></p> </blockquote> <p>And if we rearrange, we realize that...</p> <blockquote> <p><mathjax>#V_1/n_1 = V_2/n_2 = (RT)/P#</mathjax></p> </blockquote> <p>i.e. that the <em>molar volume</em> of the freon gas remains constant (as it must, if it is to remain the same gas at the same temperature and pressure).</p> <p>So, if we add <mathjax>#"3.50 mols"#</mathjax> of freon gas to <mathjax>#"7.48 mols"#</mathjax>, we obtain:</p> <blockquote> <p><mathjax>#n_2 = overbrace("7.48 mols")^(n_1) + overbrace("3.50 mols")^(Deltan)#</mathjax></p> </blockquote> <p>or that <mathjax>#n_2 = "10.98 mols"#</mathjax>. Thus, the <strong>initial volume</strong> is:</p> <blockquote> <p><mathjax>#color(blue)(V_1) = n_1/n_2 xx V_2#</mathjax></p> <p><mathjax>#= "7.48 mols"/"10.98 mols" xx "28.7 L"#</mathjax></p> <p><mathjax>#=#</mathjax> <mathjax>#color(blue)("19.6 L")#</mathjax> to three sig figs.</p> </blockquote> <p>And as always, we should check that our answer makes physical sense. </p> <p>We added <strong>more mols of gas</strong> at constant temperature and pressure, so the balloon SHOULD <strong>expand</strong>, <em>directly proportional to</em> the increase in mols of gas... and it does!</p> <blockquote> <p><mathjax>#V_2/V_1 -= "28.7 L"/"19.6 L" stackrel(?" ")(=) ("10.98 mols")/("7.48 mols") -= n_2/n_1#</mathjax></p> <p><mathjax>#1.464 ~~ 1.468#</mathjax> <mathjax>#color(blue)(sqrt"")#</mathjax></p> </blockquote> <p>But of course, this calculation is only valid for ideal gases. We are not given the temperature or pressure, so if we are in an evacuated refrigerator, we could very well be staring at one of the worst examples of an ideal gas...</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/453906" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-avogadro-s-law-important"> Why is Avogadro's law important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-was-the-avogadro-s-law-discovered"> How was the Avogadro's law discovered? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-avogadro-s-law-used-in-stoichiometry"> Is Avogadro's law used in stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-avogadro-s-law-used-in-everyday-life"> How is Avogadro's law used in everyday life? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-common-mistakes-students-make-with-avogadro-s-law"> What are some common mistakes students make with Avogadro's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-an-example-of-an-avogadro-s-law-practice-problem"> What is an example of an Avogadro's law practice problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-examples-of-the-avogadro-s-law"> What are some examples of the Avogadro's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/according-to-avogadro-s-law-as-the-number-of-moles-of-gas-increases-what-happens"> According to Avogadro's law, as the number of moles of gas increases, what happens to its volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-the-avogadro-s-law-written"> How is the Avogadro's law written? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-avogadro-s-principle"> What is the Avogadro's principle? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/avogadro-s-law"> See all questions in Avogadro's Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3108 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	If #"3.50 mols"# of freon-12 gas was added to #"7.48 mols"# of it, and it started at #"28.7 L"#, what is its final volume?	null
1,534	a9af5193-6ddd-11ea-8696-ccda262736ce	https://socratic.org/questions/how-many-moles-of-nacl-are-in-0-350-l-of-a-1-5m-solution	0.53 moles	start physical_unit 4 4 mole mol qc_end physical_unit 13 13 7 8 volume qc_end physical_unit 4 4 11 12 molarity qc_end end	[{"type":"physical unit","value":"Mole [OF] NaCl [IN] moles"}]	[{"type":"physical unit","value":"0.53 moles"}]	[{"type":"physical unit","value":"Volume [OF] NaCl solution [=] \\pu{0.350 L}"},{"type":"physical unit","value":"Molarity [OF] NaCl solution [=] \\pu{1.5 M}"}]	<h1 class="questionTitle" itemprop="name">How many moles of NaCl are in 0.350 L of a 1.5M solution?</h1>	null	0.53 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a> is a measure of moles per Liter</p> <p><mathjax>#M = (mol)/L#</mathjax> or <mathjax>#ML#</mathjax> =<mathjax>#"moles"#</mathjax></p> <p><mathjax>#M#</mathjax> = <mathjax>#1.50#</mathjax> <mathjax>#M#</mathjax><br/> <mathjax>#L#</mathjax> = <mathjax>#0.350#</mathjax> <mathjax>#L#</mathjax><br/> <mathjax>#"moles" = ?#</mathjax></p> <p><mathjax>#1.50#</mathjax> <mathjax>#M#</mathjax> (<mathjax>#0.350#</mathjax> <mathjax>#L#</mathjax>) = <mathjax>#"moles"#</mathjax></p> <p><mathjax>#0.525#</mathjax> = <mathjax>#"moles of"#</mathjax> <mathjax>#NaCl#</mathjax></p> <p> <iframe src="https://www.youtube.com/embed/loL46MQt1vQ?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#0.525 =#</mathjax> moles of <mathjax>#NaCl#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a> is a measure of moles per Liter</p> <p><mathjax>#M = (mol)/L#</mathjax> or <mathjax>#ML#</mathjax> =<mathjax>#"moles"#</mathjax></p> <p><mathjax>#M#</mathjax> = <mathjax>#1.50#</mathjax> <mathjax>#M#</mathjax><br/> <mathjax>#L#</mathjax> = <mathjax>#0.350#</mathjax> <mathjax>#L#</mathjax><br/> <mathjax>#"moles" = ?#</mathjax></p> <p><mathjax>#1.50#</mathjax> <mathjax>#M#</mathjax> (<mathjax>#0.350#</mathjax> <mathjax>#L#</mathjax>) = <mathjax>#"moles"#</mathjax></p> <p><mathjax>#0.525#</mathjax> = <mathjax>#"moles of"#</mathjax> <mathjax>#NaCl#</mathjax></p> <p> <iframe src="https://www.youtube.com/embed/loL46MQt1vQ?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles of NaCl are in 0.350 L of a 1.5M solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="265178" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/brian-m"><img alt="" class="" src="https://profilepictures.socratic.org/ZCpnJDgSFKORtvaSPDeG_Lego%20Me.png" title=""/></a> <a class="secondContributorPic" href="/users/grace-9"><img alt="" class="" src="https://profilepictures.socratic.org/gzi0U3RQNuMSxgKVeKgw_10960213_10153434463490909_9111641440892052754_o.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/brian-m"> BRIAN M. </a>·<a class="topContributorLink" href="/users/grace-9"> Grace </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-13T02:41:27" itemprop="dateCreated"> May 13, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#0.525 =#</mathjax> moles of <mathjax>#NaCl#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a> is a measure of moles per Liter</p> <p><mathjax>#M = (mol)/L#</mathjax> or <mathjax>#ML#</mathjax> =<mathjax>#"moles"#</mathjax></p> <p><mathjax>#M#</mathjax> = <mathjax>#1.50#</mathjax> <mathjax>#M#</mathjax><br/> <mathjax>#L#</mathjax> = <mathjax>#0.350#</mathjax> <mathjax>#L#</mathjax><br/> <mathjax>#"moles" = ?#</mathjax></p> <p><mathjax>#1.50#</mathjax> <mathjax>#M#</mathjax> (<mathjax>#0.350#</mathjax> <mathjax>#L#</mathjax>) = <mathjax>#"moles"#</mathjax></p> <p><mathjax>#0.525#</mathjax> = <mathjax>#"moles of"#</mathjax> <mathjax>#NaCl#</mathjax></p> <p> <iframe src="https://www.youtube.com/embed/loL46MQt1vQ?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/265178" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-morality-be-used-as-a-conversion-factor"> How can molarity be 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href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many moles of NaCl are in 0.350 L of a 1.5M solution?	null
1,535	acf50e0c-6ddd-11ea-9eef-ccda262736ce	https://socratic.org/questions/how-do-you-calculate-the-initial-pressure-this-situation-a-sealed-container-of-g	60.00 kPa	start physical_unit 13 13 pressure kpa qc_end physical_unit 13 13 30 31 pressure qc_end physical_unit 13 13 20 21 volume qc_end physical_unit 13 13 23 24 volume qc_end end	[{"type":"physical unit","value":"Pressure1 [OF] the gas [IN] kPa"}]	[{"type":"physical unit","value":"60.00 kPa"}]	[{"type":"physical unit","value":"Pressure2 [OF] the gas [=] \\pu{120 kPa}"},{"type":"physical unit","value":"Volume1 [OF] the gas [=] \\pu{0.5 m^3}"},{"type":"physical unit","value":"Volume2 [OF] the gas [=] \\pu{0.25 m^3}"}]	<h1 class="questionTitle" itemprop="name">How do you calculate the initial pressure this situation: a sealed container of gas is squashed, reducing the volume from 0.5 #m^3# to 0.25 #m^3#, with a final pressure of 120 kPa?</h1>	null	60.00 kPa	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And since <mathjax>#PV=k#</mathjax>, and thus for a PISTON at constant temperature, we write.....</p> <p><mathjax>#P_1V_1=P_2V_2#</mathjax>.............</p> <p>And we solve for <mathjax>#P_1=(120kPaxx0.25m^3)/(0.5m^3)=??kPa#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, we use old <a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's law</a>.....<mathjax>#PV=k#</mathjax>, given constant temperature, and CONSTANT amount of gas.....and gets <mathjax>#P_1=60kPa#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And since <mathjax>#PV=k#</mathjax>, and thus for a PISTON at constant temperature, we write.....</p> <p><mathjax>#P_1V_1=P_2V_2#</mathjax>.............</p> <p>And we solve for <mathjax>#P_1=(120kPaxx0.25m^3)/(0.5m^3)=??*kPa#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you calculate the initial pressure this situation: a sealed container of gas is squashed, reducing the volume from 0.5 #m^3# to 0.25 #m^3#, with a final pressure of 120 kPa?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/gas-pressure" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Pressure</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="474760" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-09-13T07:49:23" itemprop="dateCreated"> Sep 13, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, we use old <a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's law</a>.....<mathjax>#PV=k#</mathjax>, given constant temperature, and CONSTANT amount of gas.....and gets <mathjax>#P_1=60kPa#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And since <mathjax>#PV=k#</mathjax>, and thus for a PISTON at constant temperature, we write.....</p> <p><mathjax>#P_1V_1=P_2V_2#</mathjax>.............</p> <p>And we solve for <mathjax>#P_1=(120kPaxx0.25m^3)/(0.5m^3)=??*kPa#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/474760" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions 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What volume will it occupy if the... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/gas-pressure"> See all questions in Gas Pressure </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3759 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How do you calculate the initial pressure this situation: a sealed container of gas is squashed, reducing the volume from 0.5 #m^3# to 0.25 #m^3#, with a final pressure of 120 kPa?	null
1,536	a9874dfa-6ddd-11ea-8eb4-ccda262736ce	https://socratic.org/questions/a-30-00-by-mass-solution-of-hno-3-in-water-has-a-density-of-1-18-g-cm-3-at-20-c-	5.62 mol/L	start physical_unit 6 6 molarity mol/l qc_end physical_unit 6 7 1 1 mass_percent qc_end end	[{"type":"physical unit","value":"Molarity [OF] HNO3 solution [IN] mol/L"}]	[{"type":"physical unit","value":"5.62 mol/L"}]	[{"type":"physical unit","value":"Percent by mass [OF] HNO3 in solution [=] \\pu{30.00%}"},{"type":"physical unit","value":"Density [OF] HNO3 solution [=] \\pu{1.18 g/(cm^3)}"},{"type":"physical unit","value":"Temperature [OF] HNO3 solution [=] \\pu{20 ℃}"}]	<h1 class="questionTitle" itemprop="name">A 30.00% (by mass) solution of #HNO_3# in water has a density of 1.18 g/cm^3 at 20°C. What is the molarity of #HNO_3# in the solution?</h1>	null	5.62 mol/L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Now <mathjax>#"Concentration"="Moles of solute"/"Volume of solution"#</mathjax>.</p> <p>How do we turn one t'other? Well, we need the <a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a> of the solution, which you have supplied, <mathjax>#rho=1.18gcm^-3#</mathjax>, and some tedious 'rithmetic................</p> <p>So we work with a <mathjax>#1L#</mathjax> volume of solution, i.e. <mathjax>#10^3cm^3#</mathjax>.</p> <p><mathjax>#"Moles of solute"=(30.00%xx10^3cancel(cm^3)xx1.180cancelgcancel(cm^-3))/(63.01cancelgmol^-1)#</mathjax></p> <p><mathjax>#=5.62mol#</mathjax></p> <p>But this molar quantity was dissolved in a <mathjax>#1L#</mathjax> volume of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a>.....</p> <p><mathjax>#"Concentration"=(5.62mol)/(1L)=5.62molL^-1#</mathjax>. </p> <p>Now I happen to know that conc. nitric acid, which is commercially supplied as a <mathjax>#68%(w/w)#</mathjax> solution, has a molar concentration of approx. <mathjax>#15molL^-1#</mathjax>, so the value we calculated is reasonably consistent. You should keep doing these types of problems; it's all too easy to get bewildered and make an error. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We are given that <mathjax>#"Mass of nitric acid"/"Mass of solution"xx100%#</mathjax> <mathjax>#=#</mathjax> <mathjax>#30.00%#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Now <mathjax>#"Concentration"="Moles of solute"/"Volume of solution"#</mathjax>.</p> <p>How do we turn one t'other? Well, we need the <a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a> of the solution, which you have supplied, <mathjax>#rho=1.18gcm^-3#</mathjax>, and some tedious 'rithmetic................</p> <p>So we work with a <mathjax>#1L#</mathjax> volume of solution, i.e. <mathjax>#10^3cm^3#</mathjax>.</p> <p><mathjax>#"Moles of solute"=(30.00%xx10^3cancel(cm^3)xx1.180cancelgcancel(cm^-3))/(63.01cancelgmol^-1)#</mathjax></p> <p><mathjax>#=5.62mol#</mathjax></p> <p>But this molar quantity was dissolved in a <mathjax>#1L#</mathjax> volume of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a>.....</p> <p><mathjax>#"Concentration"=(5.62mol)/(1L)=5.62molL^-1#</mathjax>. </p> <p>Now I happen to know that conc. nitric acid, which is commercially supplied as a <mathjax>#68%(w/w)#</mathjax> solution, has a molar concentration of approx. <mathjax>#15molL^-1#</mathjax>, so the value we calculated is reasonably consistent. You should keep doing these types of problems; it's all too easy to get bewildered and make an error. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A 30.00% (by mass) solution of #HNO_3# in water has a density of 1.18 g/cm^3 at 20°C. What is the molarity of #HNO_3# in the solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="410774" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-22T05:47:12" itemprop="dateCreated"> Apr 22, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We are given that <mathjax>#"Mass of nitric acid"/"Mass of solution"xx100%#</mathjax> <mathjax>#=#</mathjax> <mathjax>#30.00%#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Now <mathjax>#"Concentration"="Moles of solute"/"Volume of solution"#</mathjax>.</p> <p>How do we turn one t'other? Well, we need the <a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a> of the solution, which you have supplied, <mathjax>#rho=1.18gcm^-3#</mathjax>, and some tedious 'rithmetic................</p> <p>So we work with a <mathjax>#1L#</mathjax> volume of solution, i.e. <mathjax>#10^3cm^3#</mathjax>.</p> <p><mathjax>#"Moles of solute"=(30.00%xx10^3cancel(cm^3)xx1.180cancelgcancel(cm^-3))/(63.01cancelgmol^-1)#</mathjax></p> <p><mathjax>#=5.62mol#</mathjax></p> <p>But this molar quantity was dissolved in a <mathjax>#1L#</mathjax> volume of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a>.....</p> <p><mathjax>#"Concentration"=(5.62mol)/(1L)=5.62molL^-1#</mathjax>. </p> <p>Now I happen to know that conc. nitric acid, which is commercially supplied as a <mathjax>#68%(w/w)#</mathjax> solution, has a molar concentration of approx. <mathjax>#15molL^-1#</mathjax>, so the value we calculated is reasonably consistent. You should keep doing these types of problems; it's all too easy to get bewildered and make an error. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/410774" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-morality-be-used-as-a-conversion-factor"> How can molarity be used as a conversion factor? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-high-can-molarity-be"> How high can molarity be? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-molarity-change-with-temperature"> How does molarity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molarity-of-a-solution"> How do you find molarity of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-10-naoh"> What is the molarity of 10 NaOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-3-hydrogen-peroxide"> What is the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 15444 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A 30.00% (by mass) solution of #HNO_3# in water has a density of 1.18 g/cm^3 at 20°C. What is the molarity of #HNO_3# in the solution?	null
1,537	ab20c590-6ddd-11ea-8963-ccda262736ce	https://socratic.org/questions/how-many-kilograms-of-water-must-be-evaporated-from-40-kg-of-a-10-salt-solution-	24.00 kilograms	start physical_unit 4 4 mass kg qc_end physical_unit 14 15 9 10 mass qc_end physical_unit 14 14 13 13 percent qc_end physical_unit 14 14 19 19 percent qc_end end	[{"type":"physical unit","value":"Evaporated mass [OF] water [IN] kilograms"}]	[{"type":"physical unit","value":"24.00 kilograms"}]	[{"type":"physical unit","value":"Mass [OF] salt solution [=] \\pu{40 kg}"},{"type":"physical unit","value":"Percentage1 [OF] salt in solution [=] \\pu{10%}"},{"type":"physical unit","value":"Percentage2 [OF] salt in solution [=] \\pu{25%}"}]	<h1 class="questionTitle" itemprop="name">How many kilograms of water must be evaporated from 40 kg of a 10% salt solution to produce a 25% solution?</h1>	null	24.00 kilograms	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that you can <strong>increase</strong> the solution's <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration</a></strong> by <strong>decreasing</strong> the mass of <em><a href="https://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a></em> while keeping the <em>mass of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a></em> <strong>constant</strong>. </p> <p>You are told that <em>water</em> is being evaporated from the initial solution, which confirms the fact that the mass of salt <strong>remains unchanged</strong>.</p> <p>Use the concentration of the initial solution to figure out how many kilograms of solute, which in your case is salt, or sodium chloride, <mathjax>#"NaCl"#</mathjax>, <strong>must be present</strong> in the target solution.</p> <p>A <mathjax>#"10% w/w"#</mathjax> salt solution will contain <mathjax>#"10 kg"#</mathjax> of salt <strong>for every</strong> <mathjax>#"100 kg"#</mathjax> of solution, which means that your <mathjax>#"40-kg"#</mathjax> sample will contain</p> <blockquote> <p><mathjax>#40 color(red)(cancel(color(black)("kg solution"))) * "10 kg NaCl"/(100color(red)(cancel(color(black)("kg solution")))) = "4 kg NaCl"#</mathjax></p> </blockquote> <p>This is exactly how much solute must be present in the target solution. This time, however, this amount of solute makes for a <mathjax>#"25% w/w"#</mathjax> solution. </p> <p>This means that the <strong>total mass</strong> of the target solution will be </p> <blockquote> <p><mathjax>#4color(red)(cancel(color(black)("kg NaCl"))) * "100 kg solution"/(25color(red)(cancel(color(black)("kg solution")))) = "16 kg solution"#</mathjax></p> </blockquote> <p>This tells you that the <em>mass of the solution</em> <strong>decreased</strong> from <mathjax>#"40 kg"#</mathjax> to <mathjax>#"16 kg"#</mathjax>. </p> <p>Since the mass of salt remained constant, it follows that this change is accounted for by the <em>evaporation of the water</em>. Therefore, the mass of water evaporated from the initial solution will be </p> <blockquote> <p><mathjax>#"mass of water" = "40 kg" - "16 kg" = color(green)(\|bar(ul(color(white)(a/a)"24 kg"color(white)(a/a)\|)))#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"24 kg"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that you can <strong>increase</strong> the solution's <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration</a></strong> by <strong>decreasing</strong> the mass of <em><a href="https://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a></em> while keeping the <em>mass of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a></em> <strong>constant</strong>. </p> <p>You are told that <em>water</em> is being evaporated from the initial solution, which confirms the fact that the mass of salt <strong>remains unchanged</strong>.</p> <p>Use the concentration of the initial solution to figure out how many kilograms of solute, which in your case is salt, or sodium chloride, <mathjax>#"NaCl"#</mathjax>, <strong>must be present</strong> in the target solution.</p> <p>A <mathjax>#"10% w/w"#</mathjax> salt solution will contain <mathjax>#"10 kg"#</mathjax> of salt <strong>for every</strong> <mathjax>#"100 kg"#</mathjax> of solution, which means that your <mathjax>#"40-kg"#</mathjax> sample will contain</p> <blockquote> <p><mathjax>#40 color(red)(cancel(color(black)("kg solution"))) * "10 kg NaCl"/(100color(red)(cancel(color(black)("kg solution")))) = "4 kg NaCl"#</mathjax></p> </blockquote> <p>This is exactly how much solute must be present in the target solution. This time, however, this amount of solute makes for a <mathjax>#"25% w/w"#</mathjax> solution. </p> <p>This means that the <strong>total mass</strong> of the target solution will be </p> <blockquote> <p><mathjax>#4color(red)(cancel(color(black)("kg NaCl"))) * "100 kg solution"/(25color(red)(cancel(color(black)("kg solution")))) = "16 kg solution"#</mathjax></p> </blockquote> <p>This tells you that the <em>mass of the solution</em> <strong>decreased</strong> from <mathjax>#"40 kg"#</mathjax> to <mathjax>#"16 kg"#</mathjax>. </p> <p>Since the mass of salt remained constant, it follows that this change is accounted for by the <em>evaporation of the water</em>. Therefore, the mass of water evaporated from the initial solution will be </p> <blockquote> <p><mathjax>#"mass of water" = "40 kg" - "16 kg" = color(green)(\|bar(ul(color(white)(a/a)"24 kg"color(white)(a/a)\|)))#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many kilograms of water must be evaporated from 40 kg of a 10% salt solution to produce a 25% solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/percent-concentration" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Concentration</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="252988" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-04-11T18:39:55" itemprop="dateCreated"> Apr 11, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"24 kg"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that you can <strong>increase</strong> the solution's <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration</a></strong> by <strong>decreasing</strong> the mass of <em><a href="https://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a></em> while keeping the <em>mass of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a></em> <strong>constant</strong>. </p> <p>You are told that <em>water</em> is being evaporated from the initial solution, which confirms the fact that the mass of salt <strong>remains unchanged</strong>.</p> <p>Use the concentration of the initial solution to figure out how many kilograms of solute, which in your case is salt, or sodium chloride, <mathjax>#"NaCl"#</mathjax>, <strong>must be present</strong> in the target solution.</p> <p>A <mathjax>#"10% w/w"#</mathjax> salt solution will contain <mathjax>#"10 kg"#</mathjax> of salt <strong>for every</strong> <mathjax>#"100 kg"#</mathjax> of solution, which means that your <mathjax>#"40-kg"#</mathjax> sample will contain</p> <blockquote> <p><mathjax>#40 color(red)(cancel(color(black)("kg solution"))) * "10 kg NaCl"/(100color(red)(cancel(color(black)("kg solution")))) = "4 kg NaCl"#</mathjax></p> </blockquote> <p>This is exactly how much solute must be present in the target solution. This time, however, this amount of solute makes for a <mathjax>#"25% w/w"#</mathjax> solution. </p> <p>This means that the <strong>total mass</strong> of the target solution will be </p> <blockquote> <p><mathjax>#4color(red)(cancel(color(black)("kg NaCl"))) * "100 kg solution"/(25color(red)(cancel(color(black)("kg solution")))) = "16 kg solution"#</mathjax></p> </blockquote> <p>This tells you that the <em>mass of the solution</em> <strong>decreased</strong> from <mathjax>#"40 kg"#</mathjax> to <mathjax>#"16 kg"#</mathjax>. </p> <p>Since the mass of salt remained constant, it follows that this change is accounted for by the <em>evaporation of the water</em>. Therefore, the mass of water evaporated from the initial solution will be </p> <blockquote> <p><mathjax>#"mass of water" = "40 kg" - "16 kg" = color(green)(\|bar(ul(color(white)(a/a)"24 kg"color(white)(a/a)\|)))#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/252988" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-concentration-of-water-in-solution-be-decreased"> How can the concentration of water in solution be decreased? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-concentration-of-a-solution-be-increased"> How can the concentration of a solution be increased? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-concentration-of-a-solution-in-ppm"> How do you find the concentration of a solution in ppm? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-make-a-10-percent-solution"> How do you make a 10 percent solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-make-a-2-percent-solution"> How do you make a 2 percent solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-weight-per-volume-method-to-calculate-concentration"> What is the weight per volume method to calculate concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-percent-concentration-of-kcl-would-be-isotonic"> What percent concentration of KCl would be isotonic? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-of-sodium-chloride-in-normal-saline"> What is the percent concentration of sodium chloride in normal saline? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-of-a-6m-solution-of-nacl"> What is the percent concentration of a 6m solution of NaCl? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-formula"> What is the percent concentration formula? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/percent-concentration"> See all questions in Percent Concentration </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 4746 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many kilograms of water must be evaporated from 40 kg of a 10% salt solution to produce a 25% solution?	null
1,538	ad064159-6ddd-11ea-8b4f-ccda262736ce	https://socratic.org/questions/58f7f6d37c0149695856f2bc	46.46 mL	start physical_unit 11 11 volume ml qc_end physical_unit 11 11 7 8 volume qc_end physical_unit 11 11 13 14 pressure qc_end physical_unit 11 11 17 18 temperature qc_end c_other STP qc_end end	[{"type":"physical unit","value":"Volume2 [OF] the gas [IN] mL"}]	[{"type":"physical unit","value":"46.46 mL"}]	[{"type":"physical unit","value":"Volume1 [OF] the gas [=] \\pu{50.4 mL}"},{"type":"physical unit","value":"Pressure1 [OF] the gas [=] \\pu{742 mmHg}"},{"type":"physical unit","value":"Temperature1 [OF] the gas [=] \\pu{293.15 K}"},{"type":"other","value":"STP"}]	<h1 class="questionTitle" itemprop="name">What is the new volume for a #50.4mL# volume of gas, at #742mmHg# pressure and #293.15K#, for which conditions are changed to #"STP"#?</h1>	null	46.46 mL	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We use the old <a href="https://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">combined gas law</a>, which says for a GIVEN amount of gas.....</p> <p><mathjax>#(P_1V_1)/T_1=(P_2V_2)/T_2#</mathjax></p> <p>And so we solve for <mathjax>#V_2=(P_1V_1T_2)/(P_2T_1)#</mathjax>, which product clearly has units of volume. Why?</p> <p>And we plug in the numbers knowing that <mathjax>#100kPa-=750mmHg#</mathjax>...</p> <p><mathjax>#V_2=(742mmHgxx50.4xx10^-3Lxx273.15K)/(750mmHgxx293.15K)#</mathjax></p> <p><mathjax>#V_2=0.0465L-=46.5*cm^3#</mathjax>; i.e. the volume is SLIGHTLY compressed......</p> <p>Note that while this does seem complicated, all I have done is use the appropriate units. That I got an answer in <mathjax>#cm^3#</mathjax> suggests that my order of operations was right. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, <a href="https://en.wikipedia.org/wiki/Standard_conditions_for_temperature_and_pressure" rel="nofollow">STP</a> specifies a pressure of <mathjax>#10^5Pa#</mathjax>, and a temperature of <mathjax>#273.15K#</mathjax>..... </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We use the old <a href="https://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">combined gas law</a>, which says for a GIVEN amount of gas.....</p> <p><mathjax>#(P_1V_1)/T_1=(P_2V_2)/T_2#</mathjax></p> <p>And so we solve for <mathjax>#V_2=(P_1V_1T_2)/(P_2T_1)#</mathjax>, which product clearly has units of volume. Why?</p> <p>And we plug in the numbers knowing that <mathjax>#100kPa-=750mmHg#</mathjax>...</p> <p><mathjax>#V_2=(742mmHgxx50.4xx10^-3Lxx273.15K)/(750mmHgxx293.15K)#</mathjax></p> <p><mathjax>#V_2=0.0465L-=46.5*cm^3#</mathjax>; i.e. the volume is SLIGHTLY compressed......</p> <p>Note that while this does seem complicated, all I have done is use the appropriate units. That I got an answer in <mathjax>#cm^3#</mathjax> suggests that my order of operations was right. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the new volume for a #50.4mL# volume of gas, at #742mmHg# pressure and #293.15K#, for which conditions are changed to #"STP"#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp" itemprop="url"> <span class="breadcrumb" itemprop="title">Molar Volume of a Gas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="473713" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-09-10T14:23:26" itemprop="dateCreated"> Sep 10, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, <a href="https://en.wikipedia.org/wiki/Standard_conditions_for_temperature_and_pressure" rel="nofollow">STP</a> specifies a pressure of <mathjax>#10^5Pa#</mathjax>, and a temperature of <mathjax>#273.15K#</mathjax>..... </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We use the old <a href="https://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">combined gas law</a>, which says for a GIVEN amount of gas.....</p> <p><mathjax>#(P_1V_1)/T_1=(P_2V_2)/T_2#</mathjax></p> <p>And so we solve for <mathjax>#V_2=(P_1V_1T_2)/(P_2T_1)#</mathjax>, which product clearly has units of volume. Why?</p> <p>And we plug in the numbers knowing that <mathjax>#100kPa-=750mmHg#</mathjax>...</p> <p><mathjax>#V_2=(742mmHgxx50.4xx10^-3Lxx273.15K)/(750mmHgxx293.15K)#</mathjax></p> <p><mathjax>#V_2=0.0465L-=46.5*cm^3#</mathjax>; i.e. the volume is SLIGHTLY compressed......</p> <p>Note that while this does seem complicated, all I have done is use the appropriate units. That I got an answer in <mathjax>#cm^3#</mathjax> suggests that my order of operations was right. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/473713" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-stoichiometric-ratios-relate-to-molar-volume-of-a-gas"> How do stoichiometric ratios relate to molar volume of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-a-gas-at-stp"> How do you calculate molar volume of a gas at STP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-molar-volume-of-hydrogen-gas"> How do you find the molar volume of hydrogen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-oxygen-gas"> How do you calculate molar volume of oxygen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molar-gas-volume"> What is molar gas volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/534c7bf202bf3420a007f014"> What is the volume at 0 °C and 1 atm of a mixture that contains 4.0 g of methane and 2.0 g of helium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5361f75702bf3429040e0599"> What is the difference between STP and NTP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-volume-of-25-moles-of-oxygen-o2-gas"> What is the volume of .25 moles of oxygen (O2) Gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-would-knowing-the-molar-volume-of-a-gas-be-important"> Why would knowing the molar volume of a gas be important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-22-4-liters-called-the-molar-volume-of-a-gas"> Why is 22.4 liters called the molar volume of a gas? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp"> See all questions in Molar Volume of a Gas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1492 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the new volume for a #50.4mL# volume of gas, at #742mmHg# pressure and #293.15K#, for which conditions are changed to #"STP"#?	null
1,539	a86f1670-6ddd-11ea-98d5-ccda262736ce	https://socratic.org/questions/how-much-water-should-be-evaporated-from-20-l-of-a-20-salt-solution-to-increase-	4 L	start physical_unit 2 2 volume l qc_end physical_unit 12 12 11 11 percent qc_end physical_unit 12 13 7 8 volume qc_end physical_unit 12 12 19 19 percent qc_end end	[{"type":"physical unit","value":"Evaporated volume [OF] water [IN] L"}]	[{"type":"physical unit","value":"4 L"}]	[{"type":"physical unit","value":"Percent1 [OF] salt in solution [=] \\pu{20%}"},{"type":"physical unit","value":"Volume1 [OF] salt solution [=] \\pu{20 L}"},{"type":"physical unit","value":"Percent2 [OF] salt in solution [=] \\pu{25%}"}]	<h1 class="questionTitle" itemprop="name">How much water should be evaporated from 20 L of a 20% salt solution to increase it to a 25% salt solution?</h1>	null	4 L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that you're dealing with a <mathjax>#20%#</mathjax> <em>mass by volume</em> solution, presumably, which means that you get <mathjax>#"20 g"#</mathjax> of salt <strong>for every</strong> <mathjax>#"100 mL"#</mathjax> of solution. </p> <p>In this particular case, your solution will contain a total of</p> <blockquote> <p><mathjax>#20 color(red)(cancel(color(black)("L solution"))) * (10^3color(red)(cancel(color(black)("mL"))))/(1color(red)(cancel(color(black)("L solution")))) * "20 g salt"/(100color(red)(cancel(color(black)("mL solution"))))#</mathjax></p> <blockquote> <blockquote> <blockquote> <blockquote> <p><mathjax># = " 4,000 g salt"#</mathjax></p> </blockquote> </blockquote> </blockquote> </blockquote> </blockquote> <p>Now, you can <strong>increase</strong> the concentration of this solution by <em>removing</em> some of the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a>, i.e. by evaporating some of the water. </p> <p>The amount of salt present in the solution <strong>does not change</strong>, which means that you can use the target concentration to figure out what is the <em>final volume</em> of the solution</p> <blockquote> <p><mathjax>#"4,000" color(red)(cancel(color(black)("kg salt"))) * (100 color(red)(cancel(color(black)("mL solution"))))/(25 color(red)(cancel(color(black)("g salt")))) * "1 L"/(10^3color(red)(cancel(color(black)("mL"))))#</mathjax></p> <blockquote> <blockquote> <blockquote> <blockquote> <p><mathjax>#= " 16 L solution"#</mathjax></p> </blockquote> </blockquote> </blockquote> </blockquote> </blockquote> <p>Therefore, you can make this target solution by evaporating a total of</p> <blockquote> <p><mathjax>#color(green)(bar(ul(\|color(white)(a/a)color(black)(V_"evaporated" = "20 L" - "16 L" = "4 L")color(white)(a/a)\|)))#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"4 L"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that you're dealing with a <mathjax>#20%#</mathjax> <em>mass by volume</em> solution, presumably, which means that you get <mathjax>#"20 g"#</mathjax> of salt <strong>for every</strong> <mathjax>#"100 mL"#</mathjax> of solution. </p> <p>In this particular case, your solution will contain a total of</p> <blockquote> <p><mathjax>#20 color(red)(cancel(color(black)("L solution"))) * (10^3color(red)(cancel(color(black)("mL"))))/(1color(red)(cancel(color(black)("L solution")))) * "20 g salt"/(100color(red)(cancel(color(black)("mL solution"))))#</mathjax></p> <blockquote> <blockquote> <blockquote> <blockquote> <p><mathjax># = " 4,000 g salt"#</mathjax></p> </blockquote> </blockquote> </blockquote> </blockquote> </blockquote> <p>Now, you can <strong>increase</strong> the concentration of this solution by <em>removing</em> some of the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a>, i.e. by evaporating some of the water. </p> <p>The amount of salt present in the solution <strong>does not change</strong>, which means that you can use the target concentration to figure out what is the <em>final volume</em> of the solution</p> <blockquote> <p><mathjax>#"4,000" color(red)(cancel(color(black)("kg salt"))) * (100 color(red)(cancel(color(black)("mL solution"))))/(25 color(red)(cancel(color(black)("g salt")))) * "1 L"/(10^3color(red)(cancel(color(black)("mL"))))#</mathjax></p> <blockquote> <blockquote> <blockquote> <blockquote> <p><mathjax>#= " 16 L solution"#</mathjax></p> </blockquote> </blockquote> </blockquote> </blockquote> </blockquote> <p>Therefore, you can make this target solution by evaporating a total of</p> <blockquote> <p><mathjax>#color(green)(bar(ul(\|color(white)(a/a)color(black)(V_"evaporated" = "20 L" - "16 L" = "4 L")color(white)(a/a)\|)))#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How much water should be evaporated from 20 L of a 20% salt solution to increase it to a 25% salt solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/percent-concentration" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Concentration</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="328911" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-10-31T00:04:15" itemprop="dateCreated"> Oct 31, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"4 L"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that you're dealing with a <mathjax>#20%#</mathjax> <em>mass by volume</em> solution, presumably, which means that you get <mathjax>#"20 g"#</mathjax> of salt <strong>for every</strong> <mathjax>#"100 mL"#</mathjax> of solution. </p> <p>In this particular case, your solution will contain a total of</p> <blockquote> <p><mathjax>#20 color(red)(cancel(color(black)("L solution"))) * (10^3color(red)(cancel(color(black)("mL"))))/(1color(red)(cancel(color(black)("L solution")))) * "20 g salt"/(100color(red)(cancel(color(black)("mL solution"))))#</mathjax></p> <blockquote> <blockquote> <blockquote> <blockquote> <p><mathjax># = " 4,000 g salt"#</mathjax></p> </blockquote> </blockquote> </blockquote> </blockquote> </blockquote> <p>Now, you can <strong>increase</strong> the concentration of this solution by <em>removing</em> some of the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a>, i.e. by evaporating some of the water. </p> <p>The amount of salt present in the solution <strong>does not change</strong>, which means that you can use the target concentration to figure out what is the <em>final volume</em> of the solution</p> <blockquote> <p><mathjax>#"4,000" color(red)(cancel(color(black)("kg salt"))) * (100 color(red)(cancel(color(black)("mL solution"))))/(25 color(red)(cancel(color(black)("g salt")))) * "1 L"/(10^3color(red)(cancel(color(black)("mL"))))#</mathjax></p> <blockquote> <blockquote> <blockquote> <blockquote> <p><mathjax>#= " 16 L solution"#</mathjax></p> </blockquote> </blockquote> </blockquote> </blockquote> </blockquote> <p>Therefore, you can make this target solution by evaporating a total of</p> <blockquote> <p><mathjax>#color(green)(bar(ul(\|color(white)(a/a)color(black)(V_"evaporated" = "20 L" - "16 L" = "4 L")color(white)(a/a)\|)))#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/328911" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-concentration-of-water-in-solution-be-decreased"> How can the concentration of water in solution be decreased? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-concentration-of-a-solution-be-increased"> How can the concentration of a solution be increased? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-concentration-of-a-solution-in-ppm"> How do you find the concentration of a solution in ppm? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-make-a-10-percent-solution"> How do you make a 10 percent solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-make-a-2-percent-solution"> How do you make a 2 percent solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-weight-per-volume-method-to-calculate-concentration"> What is the weight per volume method to calculate concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-percent-concentration-of-kcl-would-be-isotonic"> What percent concentration of KCl would be isotonic? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-of-sodium-chloride-in-normal-saline"> What is the percent concentration of sodium chloride in normal saline? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-of-a-6m-solution-of-nacl"> What is the percent concentration of a 6m solution of NaCl? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-formula"> What is the percent concentration formula? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/percent-concentration"> See all questions in Percent Concentration </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3870 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How much water should be evaporated from 20 L of a 20% salt solution to increase it to a 25% salt solution?	null
1,540	aaf01600-6ddd-11ea-9314-ccda262736ce	https://socratic.org/questions/iron-iii-oxide-reacts-with-carbon-monoxide-to-form-molten-iron-and-carbon-dioxid	0.15 grams	start physical_unit 0 0 mass g qc_end physical_unit 0 2 15 16 mass qc_end physical_unit 5 6 23 24 mass qc_end end	[{"type":"physical unit","value":"Mass [OF] iron [IN] grams"}]	[{"type":"physical unit","value":"0.15 grams"}]	[{"type":"physical unit","value":"Mass [OF] iron (III) oxide [=] \\pu{0.18 g}"},{"type":"physical unit","value":"Mass [OF] carbon monoxide [=] \\pu{0.11 g}"}]	<h1 class="questionTitle" itemprop="name">Iron (III) oxide reacts with carbon monoxide to form molten iron and carbon dioxide. If .18 g of iron (III) oxide reacts with 0.11 g of carbon monoxide, how many grams of iron would be produced? </h1>	null	0.15 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Moles of ferric oxide "=(0.18g)/(159.69gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#1.13xx10^-3mol" metal oxide"#</mathjax>.</p> <p><mathjax>#"Moles of carbon monoxide "=(0.11g)/(28.0gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#3.93xx10^-3mol" CO"#</mathjax>.</p> <p><mathjax>#Fe_2O_3#</mathjax> is the reagent in deficiency (why?), and thus <mathjax>#2xx1.13xx10^-3molxx55.85gmol^-1~=0.150g#</mathjax> iron metal are produced. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Fe_2O_3(s) + 3CO(g) rarr 2Fe(l) + 3CO_2(g)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Moles of ferric oxide "=(0.18g)/(159.69gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#1.13xx10^-3mol" metal oxide"#</mathjax>.</p> <p><mathjax>#"Moles of carbon monoxide "=(0.11g)/(28.0gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#3.93xx10^-3mol" CO"#</mathjax>.</p> <p><mathjax>#Fe_2O_3#</mathjax> is the reagent in deficiency (why?), and thus <mathjax>#2xx1.13xx10^-3molxx55.85gmol^-1~=0.150g#</mathjax> iron metal are produced. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Iron (III) oxide reacts with carbon monoxide to form molten iron and carbon dioxide. If .18 g of iron (III) oxide reacts with 0.11 g of carbon monoxide, how many grams of iron would be produced? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="267618" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-20T05:55:30" itemprop="dateCreated"> May 20, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Fe_2O_3(s) + 3CO(g) rarr 2Fe(l) + 3CO_2(g)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Moles of ferric oxide "=(0.18g)/(159.69gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#1.13xx10^-3mol" metal oxide"#</mathjax>.</p> <p><mathjax>#"Moles of carbon monoxide "=(0.11g)/(28.0gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#3.93xx10^-3mol" CO"#</mathjax>.</p> <p><mathjax>#Fe_2O_3#</mathjax> is the reagent in deficiency (why?), and thus <mathjax>#2xx1.13xx10^-3molxx55.85gmol^-1~=0.150g#</mathjax> iron metal are produced. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/267618" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What is stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ab82402bf342f48d93ac6"> Question #93ac6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-we-study-stoichiometry"> Why do we study stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-naoh-is-produced-from-1-20-x-102-grams-of-na2o-na2o-h2o-2-naoh"> How many grams of NaOH is produced from #1.20 x 10^2# grams of #Na_2O#? #Na_2O + H_2O -> 2NaOH# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-na2o-are-required-to-produce-1-60-x-102-grams-of-naoh-na2o-h2o"> How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? 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If .18 g of iron (III) oxide reacts with 0.11 g of carbon monoxide, how many grams of iron would be produced?	null
1,541	ac614a38-6ddd-11ea-8075-ccda262736ce	https://socratic.org/questions/what-is-the-molar-mass-of-ammonia-nh3	17.03 g/mol	start physical_unit 7 7 molar_mass g/mol qc_end chemical_equation 7 7 qc_end end	[{"type":"physical unit","value":"Molar mass [OF] NH3 [IN] g/mol"}]	[{"type":"physical unit","value":"17.03 g/mol"}]	[{"type":"chemical equation","value":"NH3"}]	<h1 class="questionTitle" itemprop="name">What is the molar mass of ammonia, #"NH"_3#? </h1>	null	17.03 g/mol	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To determine the <em>molar mass</em> of any compound, all you have to do is add up the molar masses of <strong>every</strong> atom that makes up the respective compound. </p> <p>In this case, you know that <em>ammonia</em>, <mathjax>#"NH"_3#</mathjax>, is composed of </p> <blockquote> <ul> <li><em><strong>one</strong> nitrogen atom</em>, <mathjax>#"N"#</mathjax></li> <li><em><strong>three</strong> hydrogen atoms</em>, <mathjax>#"H"#</mathjax></li> </ul> </blockquote> <p><img alt="http://ammoniabmp.colostate.edu/link%20pages/what%20is%20ammonia.html" src="https://useruploads.socratic.org/Mwp17cykTBOjUIM4dWZ2_NH3%2520mole.jpg"/> </p> <p>This means that its molar mass will be the sum of the molar mass of one nitrogen atom and <strong>three times</strong> the molar mass of a hydrogen atom. </p> <p>A quick look in <a href="http://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a> will show that you have</p> <blockquote> <ul> <li><mathjax>#"N: " "14.0067 g/mol"#</mathjax></li> <li><mathjax>#"H: " "1.00794 g/mol"#</mathjax></li> </ul> </blockquote> <p>The molar mass of ammonia will thus be </p> <blockquote> <p><mathjax>#"14.0067 g/mol" + 3 xx "1.00794 g/mol" = color(green)("17.03052 g/mol")#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"17.03052 g/mol"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To determine the <em>molar mass</em> of any compound, all you have to do is add up the molar masses of <strong>every</strong> atom that makes up the respective compound. </p> <p>In this case, you know that <em>ammonia</em>, <mathjax>#"NH"_3#</mathjax>, is composed of </p> <blockquote> <ul> <li><em><strong>one</strong> nitrogen atom</em>, <mathjax>#"N"#</mathjax></li> <li><em><strong>three</strong> hydrogen atoms</em>, <mathjax>#"H"#</mathjax></li> </ul> </blockquote> <p><img alt="http://ammoniabmp.colostate.edu/link%20pages/what%20is%20ammonia.html" src="https://useruploads.socratic.org/Mwp17cykTBOjUIM4dWZ2_NH3%2520mole.jpg"/> </p> <p>This means that its molar mass will be the sum of the molar mass of one nitrogen atom and <strong>three times</strong> the molar mass of a hydrogen atom. </p> <p>A quick look in <a href="http://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a> will show that you have</p> <blockquote> <ul> <li><mathjax>#"N: " "14.0067 g/mol"#</mathjax></li> <li><mathjax>#"H: " "1.00794 g/mol"#</mathjax></li> </ul> </blockquote> <p>The molar mass of ammonia will thus be </p> <blockquote> <p><mathjax>#"14.0067 g/mol" + 3 xx "1.00794 g/mol" = color(green)("17.03052 g/mol")#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the molar mass of ammonia, #"NH"_3#? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="191424" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-21T11:25:15" itemprop="dateCreated"> Nov 21, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"17.03052 g/mol"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To determine the <em>molar mass</em> of any compound, all you have to do is add up the molar masses of <strong>every</strong> atom that makes up the respective compound. </p> <p>In this case, you know that <em>ammonia</em>, <mathjax>#"NH"_3#</mathjax>, is composed of </p> <blockquote> <ul> <li><em><strong>one</strong> nitrogen atom</em>, <mathjax>#"N"#</mathjax></li> <li><em><strong>three</strong> hydrogen atoms</em>, <mathjax>#"H"#</mathjax></li> </ul> </blockquote> <p><img alt="http://ammoniabmp.colostate.edu/link%20pages/what%20is%20ammonia.html" src="https://useruploads.socratic.org/Mwp17cykTBOjUIM4dWZ2_NH3%2520mole.jpg"/> </p> <p>This means that its molar mass will be the sum of the molar mass of one nitrogen atom and <strong>three times</strong> the molar mass of a hydrogen atom. </p> <p>A quick look in <a href="http://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a> will show that you have</p> <blockquote> <ul> <li><mathjax>#"N: " "14.0067 g/mol"#</mathjax></li> <li><mathjax>#"H: " "1.00794 g/mol"#</mathjax></li> </ul> </blockquote> <p>The molar mass of ammonia will thus be </p> <blockquote> <p><mathjax>#"14.0067 g/mol" + 3 xx "1.00794 g/mol" = color(green)("17.03052 g/mol")#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/191424" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? 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1,542	a8d00837-6ddd-11ea-b30e-ccda262736ce	https://socratic.org/questions/you-heat-0-158g-of-a-white-solid-carbonate-of-a-group-2-metal-and-find-that-the--1	148 g/mol	start physical_unit 41 42 molar_mass g/mol qc_end physical_unit 19 19 32 33 temperature qc_end physical_unit 19 19 24 25 pressure qc_end physical_unit 5 8 2 3 mass qc_end physical_unit 30 30 28 29 volume qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Molar mass [OF] metal carbonate [IN] g/mol"}]	[{"type":"physical unit","value":"148 g/mol"}]	[{"type":"physical unit","value":"Temperature [OF] CO2 [=] \\pu{25 ℃}"},{"type":"physical unit","value":"Pressure [OF] CO2 [=] \\pu{69.8 mmHg}"},{"type":"physical unit","value":"Mass [OF] a white, solid carbonate [=] \\pu{0.158 g}"},{"type":"physical unit","value":"Volume [OF] flask [=] \\pu{285 ml}"},{"type":"other","value":"Group 2 metal."}]	<h1 class="questionTitle" itemprop="name">You heat 0.158g of a white, solid carbonate of a Group 2 metal and find that the evolved #CO_2# has a pressure of 69.8mmHg in a 285ml flask at 25°C. What is the molar mass of the metal carbonate?</h1>	null	148 g/mol	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that you need to use the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> equation to determine how many <strong>moles</strong> of carbon dioxide were produced by the reaction.</p> <p>Once you know the number of moles of carbon dioxide, you can backtrack using the <em>balanced chemical equation</em> for this reaction to determine how many <strong>moles</strong> of the metal carbonate underwent <a href="http://socratic.org/chemistry/chemical-reactions/decomposition-reactions">decomposition</a>. </p> <p>So, a metal located in group 2 of the <a href="http://socratic.org/chemistry/the-periodic-table/the-periodic-table">periodic table</a> will form <mathjax>#2+#</mathjax> cations, <mathjax>#"M"^(2+)#</mathjax>. As you know, the carbonate anions carry a <mathjax>#2-#</mathjax> charge, so you can represent the metal carbonate as </p> <blockquote> <p><mathjax>#["M"]^(2+)["CO"_3]^(2-) implies "MCO"_3#</mathjax></p> </blockquote> <p>Metal carbonates undergo thermal decomposition to form a <em>metal oxide</em>, in your case <mathjax>#"MO"#</mathjax>, and <em>carbon dioxide</em>, <mathjax>#"CO"_2#</mathjax></p> <blockquote> <p><mathjax>#"MCO"_text(3(s]) stackrel(color(red)("heat")color(white)(xx))(->) "MO"_text((s]) + "CO"_text(2(g]) uarr#</mathjax></p> </blockquote> <p>As you know, the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> equation looks like this </p> <blockquote> <p><mathjax>#color(blue)(PV = nRT)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#P#</mathjax> - the pressure of the gas<br/> <mathjax>#V#</mathjax> - the volume it occupies<br/> <mathjax>#n#</mathjax> - the <em>number of moles</em> of gas<br/> <mathjax>#R#</mathjax> - the universal gas constant, usually given as <mathjax>#0.0821("atm" * "L")/("mol" * "K")#</mathjax><br/> <mathjax>#T#</mathjax> - the temperature of the gas, <strong>always</strong> expressed in <em>Kelvin</em></p> <p>Before plugging in your values into this equation, make sure that the units given to you <strong>match</strong> those used in the expression of <mathjax>#R#</mathjax>. </p> <p>In your case, you will need to convert pressure from <em>mmHg</em> to <em>atm</em>, volume from <em>milliliters</em> to <em>liters</em>, and of course temperature from <em>degrees Celsius</em> to <em>Kelvin</em>.</p> <p>Rearrange the above equation to solve for <mathjax>#n#</mathjax></p> <blockquote> <p><mathjax>#PV = nRT implies n = (PV)/(RT)#</mathjax></p> <p><mathjax>#n = (69.8/760 color(red)(cancel(color(black)("atm"))) * 285 * 10^(-3)color(red)(cancel(color(black)("L"))))/(0.0821 (color(red)(cancel(color(black)("atm"))) * color(red)(cancel(color(black)("L"))))/("mol" * color(red)(cancel(color(black)("K")))) * (273.15 + 25.0)color(red)(cancel(color(black)("K"))))#</mathjax> </p> <p><mathjax>#n = "0.001069 moles CO"_2#</mathjax></p> </blockquote> <p>So, your reaction produced <mathjax>#0.001069#</mathjax> moles of carbon dioxide. Since the metal carbonate decomposes in a <mathjax>#1:1#</mathjax> <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> with carbon dioxide, you can say that the reaction used up </p> <blockquote> <p><mathjax>#0.001069 color(red)(cancel(color(black)("moles CO"_2))) * "1 mole MCO"_3/(1color(red)(cancel(color(black)("mole CO"_2)))) = "0.001069 moles MCO"_3#</mathjax></p> </blockquote> <p>As you know, <strong>molar mass</strong> is defined as the mass occupied by <strong>one mole</strong> of a given substance. In your case, the sample that contained <mathjax>#0.001069#</mathjax> moles of metal carbonate has a mass of <mathjax>#"0.158 g"#</mathjax>. </p> <p>This means that <strong>one mole</strong> of the metal carbonate will have a mass of </p> <blockquote> <p><mathjax>#1color(red)(cancel(color(black)("mole MCO"_3))) * "0.158 g"/(0.001069color(red)(cancel(color(black)("moles MCO"_3)))) = "147.8 g"#</mathjax></p> </blockquote> <p>Therefore, the <em>molar mass</em> of your metal carbonate is equal to </p> <blockquote> <p><mathjax>#M_M = color(green)("148 g/mol") ->#</mathjax> <em>rounded to three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></em></p> </blockquote> <p>The closest match to this value is <mathjax>#"147.6 g/mol"#</mathjax>, the molar mass of <em>strontium carbonate</em>, <mathjax>#"SrCO"_3#</mathjax>, so you can say that this is a very good result. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"148 g/mol"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that you need to use the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> equation to determine how many <strong>moles</strong> of carbon dioxide were produced by the reaction.</p> <p>Once you know the number of moles of carbon dioxide, you can backtrack using the <em>balanced chemical equation</em> for this reaction to determine how many <strong>moles</strong> of the metal carbonate underwent <a href="http://socratic.org/chemistry/chemical-reactions/decomposition-reactions">decomposition</a>. </p> <p>So, a metal located in group 2 of the <a href="http://socratic.org/chemistry/the-periodic-table/the-periodic-table">periodic table</a> will form <mathjax>#2+#</mathjax> cations, <mathjax>#"M"^(2+)#</mathjax>. As you know, the carbonate anions carry a <mathjax>#2-#</mathjax> charge, so you can represent the metal carbonate as </p> <blockquote> <p><mathjax>#["M"]^(2+)["CO"_3]^(2-) implies "MCO"_3#</mathjax></p> </blockquote> <p>Metal carbonates undergo thermal decomposition to form a <em>metal oxide</em>, in your case <mathjax>#"MO"#</mathjax>, and <em>carbon dioxide</em>, <mathjax>#"CO"_2#</mathjax></p> <blockquote> <p><mathjax>#"MCO"_text(3(s]) stackrel(color(red)("heat")color(white)(xx))(->) "MO"_text((s]) + "CO"_text(2(g]) uarr#</mathjax></p> </blockquote> <p>As you know, the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> equation looks like this </p> <blockquote> <p><mathjax>#color(blue)(PV = nRT)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#P#</mathjax> - the pressure of the gas<br/> <mathjax>#V#</mathjax> - the volume it occupies<br/> <mathjax>#n#</mathjax> - the <em>number of moles</em> of gas<br/> <mathjax>#R#</mathjax> - the universal gas constant, usually given as <mathjax>#0.0821("atm" * "L")/("mol" * "K")#</mathjax><br/> <mathjax>#T#</mathjax> - the temperature of the gas, <strong>always</strong> expressed in <em>Kelvin</em></p> <p>Before plugging in your values into this equation, make sure that the units given to you <strong>match</strong> those used in the expression of <mathjax>#R#</mathjax>. </p> <p>In your case, you will need to convert pressure from <em>mmHg</em> to <em>atm</em>, volume from <em>milliliters</em> to <em>liters</em>, and of course temperature from <em>degrees Celsius</em> to <em>Kelvin</em>.</p> <p>Rearrange the above equation to solve for <mathjax>#n#</mathjax></p> <blockquote> <p><mathjax>#PV = nRT implies n = (PV)/(RT)#</mathjax></p> <p><mathjax>#n = (69.8/760 color(red)(cancel(color(black)("atm"))) * 285 * 10^(-3)color(red)(cancel(color(black)("L"))))/(0.0821 (color(red)(cancel(color(black)("atm"))) * color(red)(cancel(color(black)("L"))))/("mol" * color(red)(cancel(color(black)("K")))) * (273.15 + 25.0)color(red)(cancel(color(black)("K"))))#</mathjax> </p> <p><mathjax>#n = "0.001069 moles CO"_2#</mathjax></p> </blockquote> <p>So, your reaction produced <mathjax>#0.001069#</mathjax> moles of carbon dioxide. Since the metal carbonate decomposes in a <mathjax>#1:1#</mathjax> <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> with carbon dioxide, you can say that the reaction used up </p> <blockquote> <p><mathjax>#0.001069 color(red)(cancel(color(black)("moles CO"_2))) * "1 mole MCO"_3/(1color(red)(cancel(color(black)("mole CO"_2)))) = "0.001069 moles MCO"_3#</mathjax></p> </blockquote> <p>As you know, <strong>molar mass</strong> is defined as the mass occupied by <strong>one mole</strong> of a given substance. In your case, the sample that contained <mathjax>#0.001069#</mathjax> moles of metal carbonate has a mass of <mathjax>#"0.158 g"#</mathjax>. </p> <p>This means that <strong>one mole</strong> of the metal carbonate will have a mass of </p> <blockquote> <p><mathjax>#1color(red)(cancel(color(black)("mole MCO"_3))) * "0.158 g"/(0.001069color(red)(cancel(color(black)("moles MCO"_3)))) = "147.8 g"#</mathjax></p> </blockquote> <p>Therefore, the <em>molar mass</em> of your metal carbonate is equal to </p> <blockquote> <p><mathjax>#M_M = color(green)("148 g/mol") ->#</mathjax> <em>rounded to three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></em></p> </blockquote> <p>The closest match to this value is <mathjax>#"147.6 g/mol"#</mathjax>, the molar mass of <em>strontium carbonate</em>, <mathjax>#"SrCO"_3#</mathjax>, so you can say that this is a very good result. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">You heat 0.158g of a white, solid carbonate of a Group 2 metal and find that the evolved #CO_2# has a pressure of 69.8mmHg in a 285ml flask at 25°C. What is the molar mass of the metal carbonate?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/ideal-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Ideal Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="204726" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-28T12:37:29" itemprop="dateCreated"> Dec 28, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"148 g/mol"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that you need to use the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> equation to determine how many <strong>moles</strong> of carbon dioxide were produced by the reaction.</p> <p>Once you know the number of moles of carbon dioxide, you can backtrack using the <em>balanced chemical equation</em> for this reaction to determine how many <strong>moles</strong> of the metal carbonate underwent <a href="http://socratic.org/chemistry/chemical-reactions/decomposition-reactions">decomposition</a>. </p> <p>So, a metal located in group 2 of the <a href="http://socratic.org/chemistry/the-periodic-table/the-periodic-table">periodic table</a> will form <mathjax>#2+#</mathjax> cations, <mathjax>#"M"^(2+)#</mathjax>. As you know, the carbonate anions carry a <mathjax>#2-#</mathjax> charge, so you can represent the metal carbonate as </p> <blockquote> <p><mathjax>#["M"]^(2+)["CO"_3]^(2-) implies "MCO"_3#</mathjax></p> </blockquote> <p>Metal carbonates undergo thermal decomposition to form a <em>metal oxide</em>, in your case <mathjax>#"MO"#</mathjax>, and <em>carbon dioxide</em>, <mathjax>#"CO"_2#</mathjax></p> <blockquote> <p><mathjax>#"MCO"_text(3(s]) stackrel(color(red)("heat")color(white)(xx))(->) "MO"_text((s]) + "CO"_text(2(g]) uarr#</mathjax></p> </blockquote> <p>As you know, the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> equation looks like this </p> <blockquote> <p><mathjax>#color(blue)(PV = nRT)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#P#</mathjax> - the pressure of the gas<br/> <mathjax>#V#</mathjax> - the volume it occupies<br/> <mathjax>#n#</mathjax> - the <em>number of moles</em> of gas<br/> <mathjax>#R#</mathjax> - the universal gas constant, usually given as <mathjax>#0.0821("atm" * "L")/("mol" * "K")#</mathjax><br/> <mathjax>#T#</mathjax> - the temperature of the gas, <strong>always</strong> expressed in <em>Kelvin</em></p> <p>Before plugging in your values into this equation, make sure that the units given to you <strong>match</strong> those used in the expression of <mathjax>#R#</mathjax>. </p> <p>In your case, you will need to convert pressure from <em>mmHg</em> to <em>atm</em>, volume from <em>milliliters</em> to <em>liters</em>, and of course temperature from <em>degrees Celsius</em> to <em>Kelvin</em>.</p> <p>Rearrange the above equation to solve for <mathjax>#n#</mathjax></p> <blockquote> <p><mathjax>#PV = nRT implies n = (PV)/(RT)#</mathjax></p> <p><mathjax>#n = (69.8/760 color(red)(cancel(color(black)("atm"))) * 285 * 10^(-3)color(red)(cancel(color(black)("L"))))/(0.0821 (color(red)(cancel(color(black)("atm"))) * color(red)(cancel(color(black)("L"))))/("mol" * color(red)(cancel(color(black)("K")))) * (273.15 + 25.0)color(red)(cancel(color(black)("K"))))#</mathjax> </p> <p><mathjax>#n = "0.001069 moles CO"_2#</mathjax></p> </blockquote> <p>So, your reaction produced <mathjax>#0.001069#</mathjax> moles of carbon dioxide. Since the metal carbonate decomposes in a <mathjax>#1:1#</mathjax> <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> with carbon dioxide, you can say that the reaction used up </p> <blockquote> <p><mathjax>#0.001069 color(red)(cancel(color(black)("moles CO"_2))) * "1 mole MCO"_3/(1color(red)(cancel(color(black)("mole CO"_2)))) = "0.001069 moles MCO"_3#</mathjax></p> </blockquote> <p>As you know, <strong>molar mass</strong> is defined as the mass occupied by <strong>one mole</strong> of a given substance. In your case, the sample that contained <mathjax>#0.001069#</mathjax> moles of metal carbonate has a mass of <mathjax>#"0.158 g"#</mathjax>. </p> <p>This means that <strong>one mole</strong> of the metal carbonate will have a mass of </p> <blockquote> <p><mathjax>#1color(red)(cancel(color(black)("mole MCO"_3))) * "0.158 g"/(0.001069color(red)(cancel(color(black)("moles MCO"_3)))) = "147.8 g"#</mathjax></p> </blockquote> <p>Therefore, the <em>molar mass</em> of your metal carbonate is equal to </p> <blockquote> <p><mathjax>#M_M = color(green)("148 g/mol") ->#</mathjax> <em>rounded to three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></em></p> </blockquote> <p>The closest match to this value is <mathjax>#"147.6 g/mol"#</mathjax>, the molar mass of <em>strontium carbonate</em>, <mathjax>#"SrCO"_3#</mathjax>, so you can say that this is a very good result. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/204726" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-ideal-gas-constant"> How do you find the ideal gas constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-solve-ideal-gas-law-problems"> How do you solve ideal gas law problems? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-know-which-ideal-gas-constant-to-use"> How do you know which ideal gas constant to use? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ideal-gas-constant-for-butane"> What is the ideal gas constant for butane? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-ideal-gas-law-in-kelvin"> Why is ideal gas law in kelvin? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ideal-gas-constant-important"> Why is the ideal gas constant important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-di-electric-constant"> What is the di-electric constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-volume-l-will-0-20-mol-hi-occupy-at-300-k-and-100-0-kpa-r-8-314-kpa-l-k-mol"> What volume (L) will 0.20 mol HI occupy at 300 K and 100.0 kPa? R = 8.314 kPa L / (K mol) =... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-molar-mass-of-a-gas"> How do you calculate the molar mass of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-should-i-use-the-ideal-gas-law-and-not-the-combined-gas-law"> When should I use the ideal gas law and not the combined gas law? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/ideal-gas-law"> See all questions in Ideal Gas Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 4424 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	You heat 0.158g of a white, solid carbonate of a Group 2 metal and find that the evolved #CO_2# has a pressure of 69.8mmHg in a 285ml flask at 25°C. What is the molar mass of the metal carbonate?	null
1,543	a9ca2831-6ddd-11ea-b166-ccda262736ce	https://socratic.org/questions/how-many-total-electrons-are-in-a-ba-2-ion	56	start physical_unit 3 3 number none qc_end chemical_equation 7 7 qc_end end	[{"type":"physical unit","value":"Number [OF] electrons"}]	[{"type":"physical unit","value":"56"}]	[{"type":"chemical equation","value":"Ba^2+"}]	<h1 class="questionTitle" itemprop="name">How many total electrons are in a # Ba^(2+)# ion? </h1>	null	56	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>For barium, <mathjax>#Z=56#</mathjax>. The dication, therefore, will necessarily have <mathjax>#56-2#</mathjax> electrons. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"54 electrons"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>For barium, <mathjax>#Z=56#</mathjax>. The dication, therefore, will necessarily have <mathjax>#56-2#</mathjax> electrons. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many total electrons are in a # Ba^(2+)# ion? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-periodic-table" itemprop="url"> <span class="breadcrumb" itemprop="title">The Periodic Table</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-periodic-table/periodic-trends-in-ionization-energy" itemprop="url"> <span class="breadcrumb" itemprop="title">Periodic Trends in Ionization Energy</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="330902" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-11-03T19:19:27" itemprop="dateCreated"> Nov 3, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"54 electrons"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>For barium, <mathjax>#Z=56#</mathjax>. The dication, therefore, will necessarily have <mathjax>#56-2#</mathjax> electrons. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/330902" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-ionization-energy-relate-to-reactivity"> How does ionization energy relate to reactivity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-ionization-energy-measured-in"> What is ionization energy measured in? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-the-first-and-second-ionization-energies"> What are the first and second ionization energies? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-ionization-energy-increase"> How does ionization energy increase? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-ionization-energy-change-down-a-group"> How does ionization energy change down a group? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-trends-in-atomic-radius-relate-to-ionization-energy"> How do trends in atomic radius relate to ionization energy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/53f00f0102bf346733644238"> Question #44238 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/54a13803581e2a1c2d5fbdfe"> Question #fbdfe </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/54c642dc581e2a50cea1a23b"> Question #1a23b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/54e18faf581e2a2f288d7de9"> Question #d7de9 </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-periodic-table/periodic-trends-in-ionization-energy"> See all questions in Periodic Trends in Ionization Energy </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 11201 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many total electrons are in a # Ba^(2+)# ion?	null
1,544	ac036522-6ddd-11ea-ade0-ccda262736ce	https://socratic.org/questions/what-is-the-total-number-of-oxygen-atoms-on-the-left-hand-side-of-2ca-2-po-4-2-s	24	start physical_unit 6 7 number none qc_end c_other OTHER qc_end chemical_equation 13 28 qc_end end	[{"type":"physical unit","value":"Total number [OF] oxygen atoms"}]	[{"type":"physical unit","value":"24"}]	[{"type":"other","value":"On the left-hand side."},{"type":"chemical equation","value":"2 Ca2(PO4)2(s) + 4 SiO2(s) + 12 C(s) -> 4 CaSiO3(s) + P4(s) + 12 CO(g)"}]	<h1 class="questionTitle" itemprop="name">What is the total number of oxygen atoms on the left-hand side of #2Ca_2(PO_4)_2(s) + 4SiO_2(s) + 12C(s) -> 4CaSiO_3(s) + P_4(s) + 12CO(g)#?</h1>	null	24	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>On the LHS of the equation we have 2 formula units of<br/> <mathjax>#Ca_3#</mathjax> <mathjax>#(P #</mathjax>O4<mathjax>#)_2#</mathjax></p> <p>Each Formula unit has two P<mathjax>#O_4#</mathjax> units , so one formula unit has 8 oxygen atoms. We have two such formula units , so the number of Oxygen atoms is 2 x 8 = 16 Oxygen atoms. </p> <p>On the LHS of the equation we have 4 molecules of Si<mathjax>#O_2#</mathjax><br/> and each molecule has two Oxygen atoms, so four will have 4 x2 = 8 Oxygen atoms.</p> <p>In all 16 + 8 = 24 Oxygen atoms are on the LHS of the equation </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>24 atoms of Oxygen.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>On the LHS of the equation we have 2 formula units of<br/> <mathjax>#Ca_3#</mathjax> <mathjax>#(P #</mathjax>O4<mathjax>#)_2#</mathjax></p> <p>Each Formula unit has two P<mathjax>#O_4#</mathjax> units , so one formula unit has 8 oxygen atoms. We have two such formula units , so the number of Oxygen atoms is 2 x 8 = 16 Oxygen atoms. </p> <p>On the LHS of the equation we have 4 molecules of Si<mathjax>#O_2#</mathjax><br/> and each molecule has two Oxygen atoms, so four will have 4 x2 = 8 Oxygen atoms.</p> <p>In all 16 + 8 = 24 Oxygen atoms are on the LHS of the equation </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the total number of oxygen atoms on the left-hand side of #2Ca_2(PO_4)_2(s) + 4SiO_2(s) + 12C(s) -> 4CaSiO_3(s) + P_4(s) + 12CO(g)#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="252762" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/manish-b"><img alt="" class="" src="https://profilepictures.socratic.org/eW7uaERSSvtv5ff2XPxA_10203153902643748.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/manish-b"> Manish Bhardwaj </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-04-11T07:25:28" itemprop="dateCreated"> Apr 11, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>24 atoms of Oxygen.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>On the LHS of the equation we have 2 formula units of<br/> <mathjax>#Ca_3#</mathjax> <mathjax>#(P #</mathjax>O4<mathjax>#)_2#</mathjax></p> <p>Each Formula unit has two P<mathjax>#O_4#</mathjax> units , so one formula unit has 8 oxygen atoms. We have two such formula units , so the number of Oxygen atoms is 2 x 8 = 16 Oxygen atoms. </p> <p>On the LHS of the equation we have 4 molecules of Si<mathjax>#O_2#</mathjax><br/> and each molecule has two Oxygen atoms, so four will have 4 x2 = 8 Oxygen atoms.</p> <p>In all 16 + 8 = 24 Oxygen atoms are on the LHS of the equation </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/252762" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------> H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -> Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? 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Sodium phosphate and calcium chloride react to form... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-equation-kclo3-kcl-o2"> How can I balance this equation? ____ #KClO_3 -># ____ #KCl +# ____ #O_2# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-balancing-chemical-equations-important"> Why is balancing chemical equations important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/balancing-chemical-equations"> See all questions in Balancing Chemical Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 13562 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the total number of oxygen atoms on the left-hand side of #2Ca_2(PO_4)_2(s) + 4SiO_2(s) + 12C(s) -> 4CaSiO_3(s) + P_4(s) + 12CO(g)#?	null
1,545	aab0f3ae-6ddd-11ea-9091-ccda262736ce	https://socratic.org/questions/57df82277c01497601d20b48	233.10 g	start physical_unit 5 5 mass g qc_end physical_unit 13 13 16 17 mass qc_end end	[{"type":"physical unit","value":"Mass [OF] solution [IN] g"}]	[{"type":"physical unit","value":"233.10 g"}]	[{"type":"physical unit","value":"w/w [OF] sugar in solution [=] \\pu{28.1%}"},{"type":"physical unit","value":"Mass [OF] sugar [=] \\pu{65.5 g}"}]	<h1 class="questionTitle" itemprop="name">What is the mass of solution that is #28.1%# #"(w/w)"# with respect to sugar that contains #65.5*g# of solution?</h1>	null	233.10 g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We are given that <mathjax>#"Mass of sugar"/"Mass of solution"xx100%=28.1%#</mathjax>.</p> <p>Thus <mathjax>#"Mass of solution"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Mass of sugar"/(0.281)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(65.5*g)/(0.281)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??g#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Over <mathjax>#200* g#</mathjax> of solution.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We are given that <mathjax>#"Mass of sugar"/"Mass of solution"xx100%=28.1%#</mathjax>.</p> <p>Thus <mathjax>#"Mass of solution"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Mass of sugar"/(0.281)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(65.5*g)/(0.281)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??g#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the mass of solution that is #28.1%# #"(w/w)"# with respect to sugar that contains #65.5g# of solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/percent-concentration" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Concentration</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="311887" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-09-19T07:12:57" itemprop="dateCreated"> Sep 19, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Over <mathjax>#200 g#</mathjax> of solution.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We are given that <mathjax>#"Mass of sugar"/"Mass of solution"xx100%=28.1%#</mathjax>.</p> <p>Thus <mathjax>#"Mass of solution"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Mass of sugar"/(0.281)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(65.5*g)/(0.281)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??g#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/311887" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-concentration-of-water-in-solution-be-decreased"> How can the concentration of water in solution be decreased? 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</a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-percent-concentration-of-kcl-would-be-isotonic"> What percent concentration of KCl would be isotonic? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-of-sodium-chloride-in-normal-saline"> What is the percent concentration of sodium chloride in normal saline? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-of-a-6m-solution-of-nacl"> What is the percent concentration of a 6m solution of NaCl? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-formula"> What is the percent concentration formula? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/percent-concentration"> See all questions in Percent Concentration </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1794 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the mass of solution that is #28.1%# #"(w/w)"# with respect to sugar that contains #65.5*g# of solution?	null
1,546	ac8fac50-6ddd-11ea-b616-ccda262736ce	https://socratic.org/questions/what-is-the-chemical-equation-for-potassium-oxide-water-potassium-hydroxide	K2O + H2O -> 2 KOH	start chemical_equation qc_end chemical_equation 6 12 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the equation"}]	[{"type":"chemical equation","value":"K2O + H2O -> 2 KOH"}]	[{"type":"chemical equation","value":"potassium oxide + water -> potassium hydroxide"}]	<h1 class="questionTitle" itemprop="name">What is the chemical equation for potassium oxide + water ---> potassium hydroxide?</h1>	null	K2O + H2O -> 2 KOH	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Potassium oxide + water produces potassium hydroxide.</p> <p>Potassium oxide is an ionic compound. The potassium has a charge of <mathjax>#"K"^+#</mathjax> and oxygen has a charge of <mathjax>#"O"^(2-)#</mathjax>. We need 2 potassium ions to balance one oxide ion making the formula <mathjax>#"K"_2"O"#</mathjax>.</p> <p>Potassium hydroxide is an ionic compound. The potassium has a charge of <mathjax>#"K"^+#</mathjax> and hydroxide has a charge of <mathjax>#"OH"^-#</mathjax>. We need 1 potassium ion to balance one hydroxide ion making the formula <mathjax>#"KOH"#</mathjax>.</p> <p><mathjax>#"K"_2"O" +" H"_2"O" -> "KOH"#</mathjax></p> <p>To balance the equation we place a coefficient of 2 in front of the potassium hydroxide.</p> <p><mathjax>#"K"_2"O" + "H"_2"O" -> 2"KOH"#</mathjax></p> <p>I hope this was helpful.<br/> SMARTERTEACHER</p> <p> <iframe src="https://www.youtube.com/embed/gNA1Gv67hXQ?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> <br/> <iframe src="https://www.youtube.com/embed/jwNx-7XDpPg?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"K"_2"O" + "H"_2"O" -> 2"KOH"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Potassium oxide + water produces potassium hydroxide.</p> <p>Potassium oxide is an ionic compound. The potassium has a charge of <mathjax>#"K"^+#</mathjax> and oxygen has a charge of <mathjax>#"O"^(2-)#</mathjax>. We need 2 potassium ions to balance one oxide ion making the formula <mathjax>#"K"_2"O"#</mathjax>.</p> <p>Potassium hydroxide is an ionic compound. The potassium has a charge of <mathjax>#"K"^+#</mathjax> and hydroxide has a charge of <mathjax>#"OH"^-#</mathjax>. We need 1 potassium ion to balance one hydroxide ion making the formula <mathjax>#"KOH"#</mathjax>.</p> <p><mathjax>#"K"_2"O" +" H"_2"O" -> "KOH"#</mathjax></p> <p>To balance the equation we place a coefficient of 2 in front of the potassium hydroxide.</p> <p><mathjax>#"K"_2"O" + "H"_2"O" -> 2"KOH"#</mathjax></p> <p>I hope this was helpful.<br/> SMARTERTEACHER</p> <p> <iframe src="https://www.youtube.com/embed/gNA1Gv67hXQ?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> <br/> <iframe src="https://www.youtube.com/embed/jwNx-7XDpPg?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the chemical equation for potassium oxide + water ---> potassium hydroxide?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/synthesis-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Synthesis Reactions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="103524" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/brian-m"><img alt="" class="" src="https://profilepictures.socratic.org/ZCpnJDgSFKORtvaSPDeG_Lego%20Me.png" title=""/></a> <a class="secondContributorPic" href="/users/abdur-r"><img alt="" class="" src="https://profilepictures.socratic.org/YXIUDMM0SoZAxTdY3kn6_niagara_falls_fog_water_height_6376_3840x2160.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/brian-m"> BRIAN M. </a>·<a class="topContributorLink" href="/users/abdur-r"> Monzur R. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2014-05-13T01:21:34" itemprop="dateCreated"> May 13, 2014 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"K"_2"O" + "H"_2"O" -> 2"KOH"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Potassium oxide + water produces potassium hydroxide.</p> <p>Potassium oxide is an ionic compound. The potassium has a charge of <mathjax>#"K"^+#</mathjax> and oxygen has a charge of <mathjax>#"O"^(2-)#</mathjax>. We need 2 potassium ions to balance one oxide ion making the formula <mathjax>#"K"_2"O"#</mathjax>.</p> <p>Potassium hydroxide is an ionic compound. The potassium has a charge of <mathjax>#"K"^+#</mathjax> and hydroxide has a charge of <mathjax>#"OH"^-#</mathjax>. We need 1 potassium ion to balance one hydroxide ion making the formula <mathjax>#"KOH"#</mathjax>.</p> <p><mathjax>#"K"_2"O" +" H"_2"O" -> "KOH"#</mathjax></p> <p>To balance the equation we place a coefficient of 2 in front of the potassium hydroxide.</p> <p><mathjax>#"K"_2"O" + "H"_2"O" -> 2"KOH"#</mathjax></p> <p>I hope this was helpful.<br/> SMARTERTEACHER</p> <p> <iframe src="https://www.youtube.com/embed/gNA1Gv67hXQ?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> <br/> <iframe src="https://www.youtube.com/embed/jwNx-7XDpPg?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/103524" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41c1302bf3469588dc389"> Question #dc389 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41c1502bf3469517a1081"> Question #a1081 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41c1d02bf346950519eb4"> Question #19eb4 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41c2802bf34695a6bc744"> Question #bc744 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41c3e02bf3469570e2e96"> How do you know when a decomposition reaction is complete? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41c4102bf34694c8c5c0c"> Question #c5c0c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41c4402bf346963eb986b"> How do decomposition reactions differ from synthesis reactions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41c5602bf346963eb986f"> Question #b986f </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-synthesis-reactions-particularly-important-in-the-body"> Why are synthesis reactions particularly important in the body? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-dehydration-synthesis-reactions-important"> Why are dehydration synthesis reactions important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/synthesis-reactions"> See all questions in Synthesis Reactions </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 124003 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the chemical equation for potassium oxide + water ---> potassium hydroxide?	null
1,547	ab17311e-6ddd-11ea-be78-ccda262736ce	https://socratic.org/questions/if-the-percent-yield-for-the-following-reaction-is-65-0-how-many-grams-of-kclo3-	164.95 grams	start physical_unit 14 14 mass g qc_end chemical_equation 23 30 qc_end physical_unit 5 7 9 9 percent_yield qc_end physical_unit 22 22 19 20 mass qc_end end	[{"type":"physical unit","value":"Mass [OF] KClO3 [IN] grams"}]	[{"type":"physical unit","value":"164.95 grams"}]	[{"type":"physical unit","value":"Percent yield [OF] the reaction [=] \\pu{65.0%}"},{"type":"physical unit","value":"Mass [OF] O2 [=] \\pu{42.0 g}"},{"type":"chemical equation","value":"2 KClO3(s) -> 2 KCl(s) + 3 O2(g)"}]	<h1 class="questionTitle" itemprop="name">If the percent yield for the following reaction is 65.0%, how many grams of KClO3 are needed to produce 42.0 g of O2? 2 KClO3(s) → 2 KCl(s) + 3 O2(g) </h1>	null	164.95 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Once again, start with the balanced chemical equation for this <a href="http://socratic.org/chemistry/chemical-reactions/decomposition-reactions">decomposition reaction</a></p> <blockquote> <p><mathjax>#color(red)(2)"KClO"_text(3(s]) -> 2"KCl"_text((s]) + color(blue)(3)"O"_text((g])#</mathjax></p> </blockquote> <p>Notice that you have a <mathjax>#color(red)(2):color(blue)(3)#</mathjax> <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> between <em>potassium chlorate</em>, <mathjax>#"KClO"""_3#</mathjax>, and <em>oxygen gas</em>, <mathjax>#"O"""_2#</mathjax>. </p> <p>This means that for a reaction that has an <strong>100%</strong> <a href="http://socratic.org/chemistry/stoichiometry/percent-yield">percent yield</a>, every two moles of potassium chlorate will produce three moles of oxygen gas. </p> <p>Keep this in mind. </p> <p>So, you know that your reaction must produce <mathjax>#"42.0 g"#</mathjax> of oxygen gas. Use oxygen gas' molar mass to find how many moles must be produced</p> <blockquote> <p><mathjax>#42.0color(red)(cancel(color(black)("g"))) * ("1 mole O"""_2)/(32.0color(red)(cancel(color(black)("g")))) = "1.3125 moles O"""_2#</mathjax></p> </blockquote> <p>So, how many moles of potassium chlorate would you need <strong>If the reaction had an 100%</strong> <a href="http://socratic.org/chemistry/stoichiometry/percent-yield">percent yield</a>?</p> <p>Use the aforementioned mole ratio to find</p> <blockquote> <p><mathjax>#1.3125color(red)(cancel(color(black)("moles O"_2))) * (color(red)(2)" moles KClO"""_3)/(color(blue)(3)color(red)(cancel(color(black)(" moles O"""_2)))) = "0.875 moles KClO"""_3#</mathjax></p> </blockquote> <p>However, you know for a fact that the percent yield of the reaction <strong>is not</strong> 100%, but <strong>65.0%</strong>. This means that you will need to use <strong>more potassium chlorate</strong> to produce this much oxygen gas. </p> <p>Percent yield is defined as the <em>actual yield</em> of the reaction divided by the <em>theoretical yield</em> of the reaction.</p> <blockquote> <p><mathjax>#"% yield" = "actual yield"/"theoretical yield" xx 100#</mathjax></p> </blockquote> <p>You know that the reaction's <em>actual yield</em> is <strong>42.0 g</strong> of oxygen gas, which means that the <em>theoretical yield</em> must be </p> <blockquote> <p><mathjax>#"65.0%" = "42.0 g"/"theoretical yield" xx 100#</mathjax> </p> </blockquote> <p><mathjax>#"theoretical yield" = ("42.0 g" * 100)/65 = "64.6 g"#</mathjax></p> <p>This means that you need to find how many grams of potassium chlorate would <strong>theoretically</strong> produce <strong>64.6 g</strong> of oxygen gas. </p> <p>Once again, use oxygen's molar mass and <a href="http://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio that exists between the two <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a></p> <blockquote> <p><mathjax>#64.6color(red)(cancel(color(black)("g O"_2))) * ("1 mole O"""_2)/(32.0color(red)(cancel(color(black)("g O"_2)))) = "2.019 moles O"""_2#</mathjax></p> </blockquote> <p>This means that you need to use</p> <blockquote> <p><mathjax>#2.019color(red)(cancel(color(black)("moles O"_2))) * (color(red)(2)" moles KClO"""_3)/(color(blue)(3)color(red)(cancel(color(black)(" moles O"""_2)))) = "1.346 moles KClO"""_3#</mathjax></p> </blockquote> <p>moles of potassium chlorate. Finally, use the compound's molar mass to find how many grams would contain this many moles</p> <blockquote> <p><mathjax>#1.346color(red)(cancel(color(black)("moles KClO"""_3))) * "122.55 g"/(1color(red)(cancel(color(black)("mole KClO"""_3)))) = color(green)("165 g KClO"""_3)#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"165 g KClO"""_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Once again, start with the balanced chemical equation for this <a href="http://socratic.org/chemistry/chemical-reactions/decomposition-reactions">decomposition reaction</a></p> <blockquote> <p><mathjax>#color(red)(2)"KClO"_text(3(s]) -> 2"KCl"_text((s]) + color(blue)(3)"O"_text((g])#</mathjax></p> </blockquote> <p>Notice that you have a <mathjax>#color(red)(2):color(blue)(3)#</mathjax> <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> between <em>potassium chlorate</em>, <mathjax>#"KClO"""_3#</mathjax>, and <em>oxygen gas</em>, <mathjax>#"O"""_2#</mathjax>. </p> <p>This means that for a reaction that has an <strong>100%</strong> <a href="http://socratic.org/chemistry/stoichiometry/percent-yield">percent yield</a>, every two moles of potassium chlorate will produce three moles of oxygen gas. </p> <p>Keep this in mind. </p> <p>So, you know that your reaction must produce <mathjax>#"42.0 g"#</mathjax> of oxygen gas. Use oxygen gas' molar mass to find how many moles must be produced</p> <blockquote> <p><mathjax>#42.0color(red)(cancel(color(black)("g"))) * ("1 mole O"""_2)/(32.0color(red)(cancel(color(black)("g")))) = "1.3125 moles O"""_2#</mathjax></p> </blockquote> <p>So, how many moles of potassium chlorate would you need <strong>If the reaction had an 100%</strong> <a href="http://socratic.org/chemistry/stoichiometry/percent-yield">percent yield</a>?</p> <p>Use the aforementioned mole ratio to find</p> <blockquote> <p><mathjax>#1.3125color(red)(cancel(color(black)("moles O"_2))) * (color(red)(2)" moles KClO"""_3)/(color(blue)(3)color(red)(cancel(color(black)(" moles O"""_2)))) = "0.875 moles KClO"""_3#</mathjax></p> </blockquote> <p>However, you know for a fact that the percent yield of the reaction <strong>is not</strong> 100%, but <strong>65.0%</strong>. This means that you will need to use <strong>more potassium chlorate</strong> to produce this much oxygen gas. </p> <p>Percent yield is defined as the <em>actual yield</em> of the reaction divided by the <em>theoretical yield</em> of the reaction.</p> <blockquote> <p><mathjax>#"% yield" = "actual yield"/"theoretical yield" xx 100#</mathjax></p> </blockquote> <p>You know that the reaction's <em>actual yield</em> is <strong>42.0 g</strong> of oxygen gas, which means that the <em>theoretical yield</em> must be </p> <blockquote> <p><mathjax>#"65.0%" = "42.0 g"/"theoretical yield" xx 100#</mathjax> </p> </blockquote> <p><mathjax>#"theoretical yield" = ("42.0 g" * 100)/65 = "64.6 g"#</mathjax></p> <p>This means that you need to find how many grams of potassium chlorate would <strong>theoretically</strong> produce <strong>64.6 g</strong> of oxygen gas. </p> <p>Once again, use oxygen's molar mass and <a href="http://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio that exists between the two <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a></p> <blockquote> <p><mathjax>#64.6color(red)(cancel(color(black)("g O"_2))) * ("1 mole O"""_2)/(32.0color(red)(cancel(color(black)("g O"_2)))) = "2.019 moles O"""_2#</mathjax></p> </blockquote> <p>This means that you need to use</p> <blockquote> <p><mathjax>#2.019color(red)(cancel(color(black)("moles O"_2))) * (color(red)(2)" moles KClO"""_3)/(color(blue)(3)color(red)(cancel(color(black)(" moles O"""_2)))) = "1.346 moles KClO"""_3#</mathjax></p> </blockquote> <p>moles of potassium chlorate. Finally, use the compound's molar mass to find how many grams would contain this many moles</p> <blockquote> <p><mathjax>#1.346color(red)(cancel(color(black)("moles KClO"""_3))) * "122.55 g"/(1color(red)(cancel(color(black)("mole KClO"""_3)))) = color(green)("165 g KClO"""_3)#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">If the percent yield for the following reaction is 65.0%, how many grams of KClO3 are needed to produce 42.0 g of O2? 2 KClO3(s) → 2 KCl(s) + 3 O2(g) </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/percent-yield" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Yield</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="171506" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-09-24T11:27:15" itemprop="dateCreated"> Sep 24, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"165 g KClO"""_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Once again, start with the balanced chemical equation for this <a href="http://socratic.org/chemistry/chemical-reactions/decomposition-reactions">decomposition reaction</a></p> <blockquote> <p><mathjax>#color(red)(2)"KClO"_text(3(s]) -> 2"KCl"_text((s]) + color(blue)(3)"O"_text((g])#</mathjax></p> </blockquote> <p>Notice that you have a <mathjax>#color(red)(2):color(blue)(3)#</mathjax> <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> between <em>potassium chlorate</em>, <mathjax>#"KClO"""_3#</mathjax>, and <em>oxygen gas</em>, <mathjax>#"O"""_2#</mathjax>. </p> <p>This means that for a reaction that has an <strong>100%</strong> <a href="http://socratic.org/chemistry/stoichiometry/percent-yield">percent yield</a>, every two moles of potassium chlorate will produce three moles of oxygen gas. </p> <p>Keep this in mind. </p> <p>So, you know that your reaction must produce <mathjax>#"42.0 g"#</mathjax> of oxygen gas. Use oxygen gas' molar mass to find how many moles must be produced</p> <blockquote> <p><mathjax>#42.0color(red)(cancel(color(black)("g"))) * ("1 mole O"""_2)/(32.0color(red)(cancel(color(black)("g")))) = "1.3125 moles O"""_2#</mathjax></p> </blockquote> <p>So, how many moles of potassium chlorate would you need <strong>If the reaction had an 100%</strong> <a href="http://socratic.org/chemistry/stoichiometry/percent-yield">percent yield</a>?</p> <p>Use the aforementioned mole ratio to find</p> <blockquote> <p><mathjax>#1.3125color(red)(cancel(color(black)("moles O"_2))) * (color(red)(2)" moles KClO"""_3)/(color(blue)(3)color(red)(cancel(color(black)(" moles O"""_2)))) = "0.875 moles KClO"""_3#</mathjax></p> </blockquote> <p>However, you know for a fact that the percent yield of the reaction <strong>is not</strong> 100%, but <strong>65.0%</strong>. This means that you will need to use <strong>more potassium chlorate</strong> to produce this much oxygen gas. </p> <p>Percent yield is defined as the <em>actual yield</em> of the reaction divided by the <em>theoretical yield</em> of the reaction.</p> <blockquote> <p><mathjax>#"% yield" = "actual yield"/"theoretical yield" xx 100#</mathjax></p> </blockquote> <p>You know that the reaction's <em>actual yield</em> is <strong>42.0 g</strong> of oxygen gas, which means that the <em>theoretical yield</em> must be </p> <blockquote> <p><mathjax>#"65.0%" = "42.0 g"/"theoretical yield" xx 100#</mathjax> </p> </blockquote> <p><mathjax>#"theoretical yield" = ("42.0 g" * 100)/65 = "64.6 g"#</mathjax></p> <p>This means that you need to find how many grams of potassium chlorate would <strong>theoretically</strong> produce <strong>64.6 g</strong> of oxygen gas. </p> <p>Once again, use oxygen's molar mass and <a href="http://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio that exists between the two <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a></p> <blockquote> <p><mathjax>#64.6color(red)(cancel(color(black)("g O"_2))) * ("1 mole O"""_2)/(32.0color(red)(cancel(color(black)("g O"_2)))) = "2.019 moles O"""_2#</mathjax></p> </blockquote> <p>This means that you need to use</p> <blockquote> <p><mathjax>#2.019color(red)(cancel(color(black)("moles O"_2))) * (color(red)(2)" moles KClO"""_3)/(color(blue)(3)color(red)(cancel(color(black)(" moles O"""_2)))) = "1.346 moles KClO"""_3#</mathjax></p> </blockquote> <p>moles of potassium chlorate. Finally, use the compound's molar mass to find how many grams would contain this many moles</p> <blockquote> <p><mathjax>#1.346color(red)(cancel(color(black)("moles KClO"""_3))) * "122.55 g"/(1color(red)(cancel(color(black)("mole KClO"""_3)))) = color(green)("165 g KClO"""_3)#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/171506" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="171507" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/r-v-subba-rao"><img alt="" class="" src="https://lh6.googleusercontent.com/-VIxfCP4FJBY/AAAAAAAAAAI/AAAAAAAAACM/gieCnhslbxg/photo.jpg?sz=50" title=""/></a> <a class="secondContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/r-v-subba-rao"> R V SUBBARAO </a>·<a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-09-24T11:27:26" itemprop="dateCreated"> Sep 24, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>You need 165 g of <mathjax>#"KClO"_3#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><mathjax>#2"KClO"_3 → "2KCl" + "3O"_2#</mathjax></p> <p>From the above reaction it can be seen that</p> <p><mathjax>#"2 mol of KClO"_3 = "3 mol of O"_2#</mathjax></p> <blockquote></blockquote> <p><mathjax>#"1 mol of KClO"_3 = 3/2 " mol O"_2 = "1.5 mol O"_2#</mathjax>.</p> <p>The yield of the reaction is given in %, i.e., 65 %.</p> <p><mathjax>#"1 mol KClO"_3#</mathjax> generates <mathjax>#"1.5 mol O"_2#</mathjax></p> <p>Since the yield is 65 %, the number of moles of <mathjax>#"O"_2#</mathjax> generated per mole of <mathjax>#"KClO"_3#</mathjax> is</p> <p><mathjax>#"1.5 mol" xx 65/100 = "0.975 mol"#</mathjax></p> <p><mathjax>#"Number of moles of O"_2 = "42.0 g"/"32.0 g/mol" = "1.31 mol"#</mathjax></p> <blockquote></blockquote> <p><mathjax>#"Number of moles of KClO"_3 = "1.31 mol O"_2//("0.975 mol O"_2//"mol KClO"_3) = "1.35 mol KClO"_3#</mathjax></p> <p><mathjax>#"Weight of KClO"_3 = "1.35 mol KClO"_3xx"Molecular weight of KClO"_3#</mathjax></p> <p><mathjax>#= "1.34 mol"xx"122.6 g/mol = 165 g"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/171507" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ebd02bf3469570e2e62"> Question #e2e62 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ec502bf34694a4fee2e"> Question #fee2e </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ec902bf34694a4fee32"> Question #fee32 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ece02bf346950519e89"> Question #19e89 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ed302bf34694c8c5bdc"> Question #c5bdc </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ee302bf3469517a1065"> Question #a1065 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-would-be-the-limiting-reagent-if-26-0-grams-of-c3h9n-were-reacted-with-46-3"> What would be the limiting reagent if 26.0 grams of C3H9N were reacted with 46.3 grams of... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-percent-yield-always-less-than-100"> Is percent yield always less than 100? 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2 KClO3(s) → 2 KCl(s) + 3 O2(g)	null
1,548	ac00ccfa-6ddd-11ea-b470-ccda262736ce	https://socratic.org/questions/what-is-the-enthalpy-change-for-the-reaction-of-1-000-x-10-2g-of-nitrogen-with-s	+644.69 kJ	start physical_unit 6 7 enthalpy kj qc_end physical_unit 14 14 9 12 mass qc_end c_other OTHER qc_end chemical_equation 22 27 qc_end physical_unit 6 7 30 31 deltah qc_end end	[{"type":"physical unit","value":"Enthalpy change [OF] the reaction [IN] kJ"}]	[{"type":"physical unit","value":"+644.69 kJ"}]	[{"type":"physical unit","value":"Mass [OF] nitrogen [=] \\pu{1.000 × 10^2 g}"},{"type":"other","value":"Sufficient oxygen."},{"type":"chemical equation","value":"N2 + O2 -> 2 NO"},{"type":"physical unit","value":"DeltaH [OF] the reaction [=] \\pu{+180.6 kJ}"}]	<h1 class="questionTitle" itemprop="name">What is the enthalpy change for the reaction of 1.000 x 10^2g of nitrogen with sufficient oxygen according to the equation: N2 + O2 -->2NO H=+180.6 kJ?</h1>	null	+644.69 kJ	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Start by taking a look at the <em><a href="http://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> change of reaction</em>, <mathjax>#DeltaH_"rxn"#</mathjax>, fo this particular reaction</p> <blockquote> <p><mathjax>#"N"_text(2(g]) + "O"_text(2(g]) -> 2"NO"_text((g])" "#</mathjax>, <mathjax>#DeltaH_text(rxn) = +"180.6 kJ"#</mathjax></p> </blockquote> <p>The value given to you for the enthalpy change of reaction corresponds to the reaction of <strong>one mole</strong> of nitrogen gas and <strong>one mole</strong> of oxygen gas, to form <strong>2 moles</strong> of nitric oxide, <mathjax>#"NO"#</mathjax>. </p> <p>That means that you can expect the enthalpy change of reaction to <strong>vary</strong> depending on the exact number of moles of the reactants and of moles of product produced by the reaction. </p> <p>To determine how many moles of nitrogen gas you have in <mathjax>#1.00 * 10^2"g"#</mathjax>, use its <em>molar mass</em></p> <blockquote> <p><mathjax>#1.00 * 10^2color(red)(cancel(color(black)("g"))) * ("1 mole N"_2)/(28.0134color(red)(cancel(color(black)("g")))) = "3.5697 moles N"_2#</mathjax></p> </blockquote> <p>Since no mention was made on how much oxygen gas you have, you can safely assume that it will be in <strong>excess</strong>, which implies that all the moles of nitrogen gas will take part in the reaction. </p> <p>Well, if <strong>one mole</strong> of nitrogen gas corresponds to an enthalpy change of reaction of <mathjax>#+"180.6 kJ"#</mathjax>, it follows that <mathjax>#"3.5697 moles"#</mathjax> will correspond to an enthalpy change of reaction of</p> <blockquote> <p><mathjax>#3.5697color(red)(cancel(color(black)("moles N"_2))) * "180.6 KJ"/(1color(red)(cancel(color(black)("mole N"_2)))) = "644.69 kJ"#</mathjax></p> </blockquote> <p>Rounded to three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the answer will be </p> <blockquote> <p><mathjax>#DeltaH_"rxn" = color(green)(+"645 kJ")#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#DeltaH_"rxn" = +"645 kJ"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Start by taking a look at the <em><a href="http://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> change of reaction</em>, <mathjax>#DeltaH_"rxn"#</mathjax>, fo this particular reaction</p> <blockquote> <p><mathjax>#"N"_text(2(g]) + "O"_text(2(g]) -> 2"NO"_text((g])" "#</mathjax>, <mathjax>#DeltaH_text(rxn) = +"180.6 kJ"#</mathjax></p> </blockquote> <p>The value given to you for the enthalpy change of reaction corresponds to the reaction of <strong>one mole</strong> of nitrogen gas and <strong>one mole</strong> of oxygen gas, to form <strong>2 moles</strong> of nitric oxide, <mathjax>#"NO"#</mathjax>. </p> <p>That means that you can expect the enthalpy change of reaction to <strong>vary</strong> depending on the exact number of moles of the reactants and of moles of product produced by the reaction. </p> <p>To determine how many moles of nitrogen gas you have in <mathjax>#1.00 * 10^2"g"#</mathjax>, use its <em>molar mass</em></p> <blockquote> <p><mathjax>#1.00 * 10^2color(red)(cancel(color(black)("g"))) * ("1 mole N"_2)/(28.0134color(red)(cancel(color(black)("g")))) = "3.5697 moles N"_2#</mathjax></p> </blockquote> <p>Since no mention was made on how much oxygen gas you have, you can safely assume that it will be in <strong>excess</strong>, which implies that all the moles of nitrogen gas will take part in the reaction. </p> <p>Well, if <strong>one mole</strong> of nitrogen gas corresponds to an enthalpy change of reaction of <mathjax>#+"180.6 kJ"#</mathjax>, it follows that <mathjax>#"3.5697 moles"#</mathjax> will correspond to an enthalpy change of reaction of</p> <blockquote> <p><mathjax>#3.5697color(red)(cancel(color(black)("moles N"_2))) * "180.6 KJ"/(1color(red)(cancel(color(black)("mole N"_2)))) = "644.69 kJ"#</mathjax></p> </blockquote> <p>Rounded to three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the answer will be </p> <blockquote> <p><mathjax>#DeltaH_"rxn" = color(green)(+"645 kJ")#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the enthalpy change for the reaction of 1.000 x 10^2g of nitrogen with sufficient oxygen according to the equation: N2 + O2 -->2NO H=+180.6 kJ?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/enthalpy" itemprop="url"> <span class="breadcrumb" itemprop="title">Enthalpy</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="179567" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-10-24T11:25:52" itemprop="dateCreated"> Oct 24, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#DeltaH_"rxn" = +"645 kJ"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Start by taking a look at the <em><a href="http://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> change of reaction</em>, <mathjax>#DeltaH_"rxn"#</mathjax>, fo this particular reaction</p> <blockquote> <p><mathjax>#"N"_text(2(g]) + "O"_text(2(g]) -> 2"NO"_text((g])" "#</mathjax>, <mathjax>#DeltaH_text(rxn) = +"180.6 kJ"#</mathjax></p> </blockquote> <p>The value given to you for the enthalpy change of reaction corresponds to the reaction of <strong>one mole</strong> of nitrogen gas and <strong>one mole</strong> of oxygen gas, to form <strong>2 moles</strong> of nitric oxide, <mathjax>#"NO"#</mathjax>. </p> <p>That means that you can expect the enthalpy change of reaction to <strong>vary</strong> depending on the exact number of moles of the reactants and of moles of product produced by the reaction. </p> <p>To determine how many moles of nitrogen gas you have in <mathjax>#1.00 * 10^2"g"#</mathjax>, use its <em>molar mass</em></p> <blockquote> <p><mathjax>#1.00 * 10^2color(red)(cancel(color(black)("g"))) * ("1 mole N"_2)/(28.0134color(red)(cancel(color(black)("g")))) = "3.5697 moles N"_2#</mathjax></p> </blockquote> <p>Since no mention was made on how much oxygen gas you have, you can safely assume that it will be in <strong>excess</strong>, which implies that all the moles of nitrogen gas will take part in the reaction. </p> <p>Well, if <strong>one mole</strong> of nitrogen gas corresponds to an enthalpy change of reaction of <mathjax>#+"180.6 kJ"#</mathjax>, it follows that <mathjax>#"3.5697 moles"#</mathjax> will correspond to an enthalpy change of reaction of</p> <blockquote> <p><mathjax>#3.5697color(red)(cancel(color(black)("moles N"_2))) * "180.6 KJ"/(1color(red)(cancel(color(black)("mole N"_2)))) = "644.69 kJ"#</mathjax></p> </blockquote> <p>Rounded to three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the answer will be </p> <blockquote> <p><mathjax>#DeltaH_"rxn" = color(green)(+"645 kJ")#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/179567" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> 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equation: N2 + O2 -->2NO H=+180.6 kJ?	null
1,549	aad476e8-6ddd-11ea-af51-ccda262736ce	https://socratic.org/questions/a-sample-of-hydrogen-has-a-volume-of-1107-ml-when-the-temperature-is-101-9-degc-	707.73 mL	start physical_unit 28 29 volume ml qc_end physical_unit 1 3 8 9 volume qc_end physical_unit 1 3 14 15 temperature qc_end physical_unit 1 3 20 21 pressure qc_end c_other STP qc_end end	[{"type":"physical unit","value":"Volume2 [OF] the gas [IN] mL"}]	[{"type":"physical unit","value":"707.73 mL"}]	[{"type":"physical unit","value":"Volume1 [OF] hydrogen sample [=] \\pu{1107 mL}"},{"type":"physical unit","value":"Temperature1 [OF] hydrogen sample [=] \\pu{101.9 degC}"},{"type":"physical unit","value":"Pressure1 [OF] hydrogen sample [=] \\pu{0.867 atm}"},{"type":"other","value":"STP"}]	<h1 class="questionTitle" itemprop="name"> A sample of hydrogen has a volume of 1107 mL when the temperature is 101.9 degC and the pressure is 0.867 atm. What will be the volume of the gas at STP?</h1>	null	707.73 mL	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We use an absolute scale of temperature, <mathjax>#0^@#</mathjax> <mathjax>#C#</mathjax> <mathjax>#=#</mathjax> <mathjax>#273#</mathjax> <mathjax>#K#</mathjax>.</p> <p>So <mathjax>#V_2#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(P_1T_2V_1)/(P_2T_1)#</mathjax> <mathjax>#=#</mathjax> </p> <p><mathjax>#((0.867atm)/(0.987atm))xx(1107mL)xx(273K)/(375.1*K)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax> <mathjax>#mL#</mathjax>.</p> <p>The volume should reasonably decrease even though the pressure increases marginally. Note that I am perfectly justified in retaining non-standard units such as atmospheres and millilitres in that these cancel out. I must use the absolute temperature scale. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The <a href="http://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">combined gas law</a> holds that for a given quantity of gas:</p> <p><mathjax>#(P_1V_1)/T_1 = (P_2V_2)/T_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We use an absolute scale of temperature, <mathjax>#0^@#</mathjax> <mathjax>#C#</mathjax> <mathjax>#=#</mathjax> <mathjax>#273#</mathjax> <mathjax>#K#</mathjax>.</p> <p>So <mathjax>#V_2#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(P_1T_2V_1)/(P_2T_1)#</mathjax> <mathjax>#=#</mathjax> </p> <p><mathjax>#((0.867atm)/(0.987atm))xx(1107mL)xx(273K)/(375.1*K)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax> <mathjax>#mL#</mathjax>.</p> <p>The volume should reasonably decrease even though the pressure increases marginally. Note that I am perfectly justified in retaining non-standard units such as atmospheres and millilitres in that these cancel out. I must use the absolute temperature scale. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name"> A sample of hydrogen has a volume of 1107 mL when the temperature is 101.9 degC and the pressure is 0.867 atm. What will be the volume of the gas at STP?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/gas-laws" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Laws</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="206969" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-02T10:01:22" itemprop="dateCreated"> Jan 2, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The <a href="http://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">combined gas law</a> holds that for a given quantity of gas:</p> <p><mathjax>#(P_1V_1)/T_1 = (P_2V_2)/T_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We use an absolute scale of temperature, <mathjax>#0^@#</mathjax> <mathjax>#C#</mathjax> <mathjax>#=#</mathjax> <mathjax>#273#</mathjax> <mathjax>#K#</mathjax>.</p> <p>So <mathjax>#V_2#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(P_1T_2V_1)/(P_2T_1)#</mathjax> <mathjax>#=#</mathjax> </p> <p><mathjax>#((0.867atm)/(0.987atm))xx(1107mL)xx(273K)/(375.1*K)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax> <mathjax>#mL#</mathjax>.</p> <p>The volume should reasonably decrease even though the pressure increases marginally. Note that I am perfectly justified in retaining non-standard units such as atmospheres and millilitres in that these cancel out. I must use the absolute temperature scale. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/206969" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-boyles-law-relate-to-breathing"> How does Boyle's law relate to breathing? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/in-avogadro-s-law-what-would-happen-to-v-if-n-is-increased-decreased-and-what-wo"> In Avogadro's Law what would happen to V if N is increased/decreased? 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What will be the volume of the gas at STP?	null
1,550	abfdbf7b-6ddd-11ea-85a9-ccda262736ce	https://socratic.org/questions/how-many-moles-of-hydrogen-are-produced-from-the-reaction-of-three-moles-of-zinc	3.00 moles	start physical_unit 4 4 mole mol qc_end physical_unit 14 14 11 12 mole qc_end c_other OTHER qc_end chemical_equation 22 29 qc_end end	[{"type":"physical unit","value":"Mole [OF] hydrogen [IN] moles"}]	[{"type":"physical unit","value":"3.00 moles"}]	[{"type":"physical unit","value":"Mole [OF] zinc [=] \\pu{3 moles}"},{"type":"other","value":"Excess hydrochloric acid."},{"type":"chemical equation","value":"Zn + 2 HCl -> ZnCl2 + H2"}]	<h1 class="questionTitle" itemprop="name">How many moles of hydrogen are produced from the reaction of three moles of zinc with an excess of hydrochloric acid in #Zn + 2HCl -> ZnCl_2 + H_2#?</h1>	null	3.00 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>as per given balanced equation one mole Zn produces 1mole Hydrogen<br/> when reacted with excess acid.<br/> So 3 moles Zn will give 3moles Hydrogen</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>3 moles</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>as per given balanced equation one mole Zn produces 1mole Hydrogen<br/> when reacted with excess acid.<br/> So 3 moles Zn will give 3moles Hydrogen</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles of hydrogen are produced from the reaction of three moles of zinc with an excess of hydrochloric acid in #Zn + 2HCl -> ZnCl_2 + H_2#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/mole-ratios" itemprop="url"> <span class="breadcrumb" itemprop="title">Mole Ratios</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="231336" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/dk-ch"><img alt="" class="" src="https://profilepictures.socratic.org/0aBlt69MSiWhfD1SEqb8_lotus.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/dk-ch"> P dilip_k </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-02-26T12:20:53" itemprop="dateCreated"> Feb 26, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>3 moles</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>as per given balanced equation one mole Zn produces 1mole Hydrogen<br/> when reacted with excess acid.<br/> So 3 moles Zn will give 3moles Hydrogen</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/231336" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div 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Mole Ratios </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 35153 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many moles of hydrogen are produced from the reaction of three moles of zinc with an excess of hydrochloric acid in #Zn + 2HCl -> ZnCl_2 + H_2#?	null
1,551	ab1b6dca-6ddd-11ea-9293-ccda262736ce	https://socratic.org/questions/595b89bf7c014916c542c9e2	4.44 g	start physical_unit 9 10 mass g qc_end physical_unit 9 10 6 7 mole qc_end end	[{"type":"physical unit","value":"Mass [OF] calcium chloride [IN] g"}]	[{"type":"physical unit","value":"4.44 g"}]	[{"type":"physical unit","value":"Mole [OF] calcium chloride [=] \\pu{40 mmol}"}]	<h1 class="questionTitle" itemprop="name">What is the mass represented by #40*mmol# of calcium chloride?</h1>	null	4.44 g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Where, <mathjax>#110.98gmol^-1#</mathjax> is the formula weight of calcium chloride. And so......<mathjax>#40xx10^-3molxx110.98gmol^-1~=4.5g#</mathjax>. What equivalent quantity of chlorine does this mass represent?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We solve the product, <mathjax>#40xx10^-3molxx110.98gmol^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Where, <mathjax>#110.98gmol^-1#</mathjax> is the formula weight of calcium chloride. And so......<mathjax>#40xx10^-3molxx110.98gmol^-1~=4.5*g#</mathjax>. What equivalent quantity of chlorine does this mass represent?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the mass represented by #40mmol# of calcium chloride?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="456922" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-07-27T16:25:54" itemprop="dateCreated"> Jul 27, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We solve the product, <mathjax>#40xx10^-3molxx110.98gmol^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Where, <mathjax>#110.98gmol^-1#</mathjax> is the formula weight of calcium chloride. And so......<mathjax>#40xx10^-3molxx110.98gmol^-1~=4.5g#</mathjax>. What equivalent quantity of chlorine does this mass represent?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/456922" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-morality-be-used-as-a-conversion-factor"> How can molarity be used as a conversion factor? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-high-can-molarity-be"> How high can molarity be? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-molarity-change-with-temperature"> How does molarity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molarity-of-a-solution"> How do you find molarity of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-10-naoh"> What is the molarity of 10 NaOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-3-hydrogen-peroxide"> What is the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1064 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the mass represented by #40*mmol# of calcium chloride?	null
1,552	aafc98e4-6ddd-11ea-b40d-ccda262736ce	https://socratic.org/questions/the-temperature-of-a-piece-of-copper-with-a-mass-of-95-4-g-increases-from-25-c-t	0.39 J/(g * ℃)	start physical_unit 6 6 specific_heat j/(°c_·_g) qc_end physical_unit 3 6 15 16 temperature qc_end physical_unit 3 6 18 19 temperature qc_end physical_unit 3 6 11 12 mass qc_end physical_unit 3 6 24 25 heat_energy qc_end end	[{"type":"physical unit","value":"Specific heat [OF] copper [IN] J/(g * ℃)"}]	[{"type":"physical unit","value":"0.39 J/(g * ℃)"}]	[{"type":"physical unit","value":"Temperature1 [OF] a piece of copper [=] \\pu{25 ℃}"},{"type":"physical unit","value":"Temperature2 [OF] a piece of copper [=] \\pu{48 ℃}"},{"type":"physical unit","value":"Mass [OF] a piece of copper [=] \\pu{95.4 g}"},{"type":"physical unit","value":"Absorbed heat [OF] a piece of copper [=] \\pu{849 J}"}]	<h1 class="questionTitle" itemprop="name">The temperature of a piece of copper with a mass of 95.4 g increases from 25°C to 48°C when the metal absorbs 849 J of heat. What is the specific heat of copper?</h1>	null	0.39 J/(g * ℃)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>A substance's <a href="http://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> tells you how much heat much be provided to increase the temperature of <mathjax>#"1 g"#</mathjax> of that substance by <mathjax>#1^@"C"#</mathjax>. </p> <p>The equation that establishes a relationship between how much heat a substance must absorb in order to register a change in its temperature looks like this</p> <blockquote> <p><mathjax>#color(blue)(q = m * c * DeltaT)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#q#</mathjax> - the amount of heat absorbed<br/> <mathjax>#m#</mathjax> - the mass of the sample<br/> <mathjax>#c#</mathjax> - the <a href="http://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> of the substance<br/> <mathjax>#DeltaT#</mathjax> - the change in temperature, defined as the difference betwen the <em>final temperature</em> and the <em>nitial temperature</em></p> <p>In your case, you know that the temperature of <mathjax>#"95.4-g"#</mathjax> sample of copper increases from <mathjax>#25#</mathjax> to <mathjax>#48^@"C"#</mathjax> after absorbing <mathjax>#"849 J"#</mathjax> worth of heat. </p> <p>Rearrange the equation to solve for <mathjax>#c#</mathjax> and plug in your values</p> <blockquote> <p><mathjax>#c = q/(m * DeltaT)#</mathjax></p> <p><mathjax>#c = "849 J"/("95.4 g" * (48-25)^@"C") = 0.38693"J"/("g" ""^@"C")#</mathjax></p> </blockquote> <p>Rounded to two <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the number of sig figs you ahve for the two temperatures of the copper sample, the answer will be</p> <blockquote> <p><mathjax>#c = color(green)(0.39"J"/("g" ""^@"C"))#</mathjax></p> </blockquote> <p>It's worth noting that the result matches listed values almost perfectly </p> <p><a href="http://www.engineeringtoolbox.com/specific-heat-metals-d_152.html" rel="nofollow" target="_blank">http://www.engineeringtoolbox.com/specific-heat-metals-d_152.html</a></p> <p> <iframe src="https://www.youtube.com/embed/4RkDJDDnIss?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#0.39"J"/("g" ""^@"C")#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>A substance's <a href="http://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> tells you how much heat much be provided to increase the temperature of <mathjax>#"1 g"#</mathjax> of that substance by <mathjax>#1^@"C"#</mathjax>. </p> <p>The equation that establishes a relationship between how much heat a substance must absorb in order to register a change in its temperature looks like this</p> <blockquote> <p><mathjax>#color(blue)(q = m * c * DeltaT)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#q#</mathjax> - the amount of heat absorbed<br/> <mathjax>#m#</mathjax> - the mass of the sample<br/> <mathjax>#c#</mathjax> - the <a href="http://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> of the substance<br/> <mathjax>#DeltaT#</mathjax> - the change in temperature, defined as the difference betwen the <em>final temperature</em> and the <em>nitial temperature</em></p> <p>In your case, you know that the temperature of <mathjax>#"95.4-g"#</mathjax> sample of copper increases from <mathjax>#25#</mathjax> to <mathjax>#48^@"C"#</mathjax> after absorbing <mathjax>#"849 J"#</mathjax> worth of heat. </p> <p>Rearrange the equation to solve for <mathjax>#c#</mathjax> and plug in your values</p> <blockquote> <p><mathjax>#c = q/(m * DeltaT)#</mathjax></p> <p><mathjax>#c = "849 J"/("95.4 g" * (48-25)^@"C") = 0.38693"J"/("g" ""^@"C")#</mathjax></p> </blockquote> <p>Rounded to two <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the number of sig figs you ahve for the two temperatures of the copper sample, the answer will be</p> <blockquote> <p><mathjax>#c = color(green)(0.39"J"/("g" ""^@"C"))#</mathjax></p> </blockquote> <p>It's worth noting that the result matches listed values almost perfectly </p> <p><a href="http://www.engineeringtoolbox.com/specific-heat-metals-d_152.html" rel="nofollow" target="_blank">http://www.engineeringtoolbox.com/specific-heat-metals-d_152.html</a></p> <p> <iframe src="https://www.youtube.com/embed/4RkDJDDnIss?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">The temperature of a piece of copper with a mass of 95.4 g increases from 25°C to 48°C when the metal absorbs 849 J of heat. What is the specific heat of copper?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/specific-heat" itemprop="url"> <span class="breadcrumb" itemprop="title">Specific Heat</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="181143" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-10-30T00:34:48" itemprop="dateCreated"> Oct 30, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#0.39"J"/("g" ""^@"C")#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>A substance's <a href="http://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> tells you how much heat much be provided to increase the temperature of <mathjax>#"1 g"#</mathjax> of that substance by <mathjax>#1^@"C"#</mathjax>. </p> <p>The equation that establishes a relationship between how much heat a substance must absorb in order to register a change in its temperature looks like this</p> <blockquote> <p><mathjax>#color(blue)(q = m * c * DeltaT)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#q#</mathjax> - the amount of heat absorbed<br/> <mathjax>#m#</mathjax> - the mass of the sample<br/> <mathjax>#c#</mathjax> - the <a href="http://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> of the substance<br/> <mathjax>#DeltaT#</mathjax> - the change in temperature, defined as the difference betwen the <em>final temperature</em> and the <em>nitial temperature</em></p> <p>In your case, you know that the temperature of <mathjax>#"95.4-g"#</mathjax> sample of copper increases from <mathjax>#25#</mathjax> to <mathjax>#48^@"C"#</mathjax> after absorbing <mathjax>#"849 J"#</mathjax> worth of heat. </p> <p>Rearrange the equation to solve for <mathjax>#c#</mathjax> and plug in your values</p> <blockquote> <p><mathjax>#c = q/(m * DeltaT)#</mathjax></p> <p><mathjax>#c = "849 J"/("95.4 g" * (48-25)^@"C") = 0.38693"J"/("g" ""^@"C")#</mathjax></p> </blockquote> <p>Rounded to two <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the number of sig figs you ahve for the two temperatures of the copper sample, the answer will be</p> <blockquote> <p><mathjax>#c = color(green)(0.39"J"/("g" ""^@"C"))#</mathjax></p> </blockquote> <p>It's worth noting that the result matches listed values almost perfectly </p> <p><a href="http://www.engineeringtoolbox.com/specific-heat-metals-d_152.html" rel="nofollow" target="_blank">http://www.engineeringtoolbox.com/specific-heat-metals-d_152.html</a></p> <p> <iframe src="https://www.youtube.com/embed/4RkDJDDnIss?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/181143" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-specific-heat-be-used-to-identify-substances"> How can specific heat be used to identify substances? 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What is the specific heat of copper?	null
1,553	ad18ce54-6ddd-11ea-af95-ccda262736ce	https://socratic.org/questions/5929b89ab72cff02377bf34a	176 g	start physical_unit 3 4 mass g qc_end physical_unit 14 15 10 11 mass qc_end end	[{"type":"physical unit","value":"Mass [OF] carbon dioxide [IN] g"}]	[{"type":"physical unit","value":"176 g"}]	[{"type":"physical unit","value":"Mass [OF] acetylene gas [=] \\pu{52 g}"}]	<h1 class="questionTitle" itemprop="name">What mass of carbon dioxide results from combustion of a #52*g# mass of acetylene gas?</h1>	null	176 g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And the typical rigmarole is to balance the carbons, and then the hydrogens, and then finally the oxygens.............</p> <p><mathjax>#HC-=CH(g) + 5/2O_2(g) rarr 2CO_2(g) +H_2O(l)#</mathjax></p> <p>Is this balanced? Don't trust my 'rithmetic!</p> <p>And thus, moles of acetylene reactant:</p> <p><mathjax>#=(52g)/(26.04gmol^-1)=2mol#</mathjax></p> <p>Given the <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>, we gets <mathjax>#4mol#</mathjax> <mathjax>#CO_2(g)#</mathjax> given complete combustion, a mass of <mathjax>#4molxx44.0gmol^-1=176*g#</mathjax> <mathjax>#"carbon dioxide.........."#</mathjax> Take that atmosphere!</p> <p>Would this reaction be exothermic? Why or why not?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We needs a stoichiometric equation, and we finally get a mass of <mathjax>#CO_2#</mathjax> under <mathjax>#200g#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And the typical rigmarole is to balance the carbons, and then the hydrogens, and then finally the oxygens.............</p> <p><mathjax>#HC-=CH(g) + 5/2O_2(g) rarr 2CO_2(g) +H_2O(l)#</mathjax></p> <p>Is this balanced? Don't trust my 'rithmetic!</p> <p>And thus, moles of acetylene reactant:</p> <p><mathjax>#=(52g)/(26.04gmol^-1)=2mol#</mathjax></p> <p>Given the <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>, we gets <mathjax>#4mol#</mathjax> <mathjax>#CO_2(g)#</mathjax> given complete combustion, a mass of <mathjax>#4molxx44.0gmol^-1=176g#</mathjax> <mathjax>#"carbon dioxide.........."#</mathjax> Take that atmosphere!</p> <p>Would this reaction be exothermic? Why or why not?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What mass of carbon dioxide results from combustion of a #52g# mass of acetylene gas?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="430630" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-27T17:44:45" itemprop="dateCreated"> May 27, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We needs a stoichiometric equation, and we finally get a mass of <mathjax>#CO_2#</mathjax> under <mathjax>#200g#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And the typical rigmarole is to balance the carbons, and then the hydrogens, and then finally the oxygens.............</p> <p><mathjax>#HC-=CH(g) + 5/2O_2(g) rarr 2CO_2(g) +H_2O(l)#</mathjax></p> <p>Is this balanced? Don't trust my 'rithmetic!</p> <p>And thus, moles of acetylene reactant:</p> <p><mathjax>#=(52g)/(26.04gmol^-1)=2mol#</mathjax></p> <p>Given the <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>, we gets <mathjax>#4mol#</mathjax> <mathjax>#CO_2(g)#</mathjax> given complete combustion, a mass of <mathjax>#4molxx44.0gmol^-1=176*g#</mathjax> <mathjax>#"carbon dioxide.........."#</mathjax> Take that atmosphere!</p> <p>Would this reaction be exothermic? Why or why not?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/430630" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What is stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ab82402bf342f48d93ac6"> Question #93ac6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-we-study-stoichiometry"> Why do we study stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-naoh-is-produced-from-1-20-x-102-grams-of-na2o-na2o-h2o-2-naoh"> How many grams of NaOH is produced from #1.20 x 10^2# grams of #Na_2O#? #Na_2O + H_2O -> 2NaOH# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-na2o-are-required-to-produce-1-60-x-102-grams-of-naoh-na2o-h2o"> How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? Na2O + H2O ---> 2 NaOH </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-mass-of-iron-is-needed-to-react-with-16-0-grams-of-sulfur-8-fe-s8-8-fes"> What mass of iron is needed to react with 16.0 grams of sulfur? 8 Fe + S8 ---> 8 FeS </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/according-to-8-fe-s8-8-fes-how-many-grams-of-fes-are-produced"> According to 8 Fe + S8 ---> 8 FeS How many grams of FeS are produced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/12-00-moles-of-naclo3-will-produce-how-many-grams-of-o2-2-naclo3-2-nacl-3-o2"> 12.00 moles of NaClO3 will produce how many grams of O2? 2 NaClO3 ---> 2 NaCl + 3 O2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-nacl-are-produced-when-80-0-grams-of-o2-are-produced-2-naclo3-"> How many grams of NaCl are produced when 80.0 grams of O2 are produced? 2 NaClO3 ---> 2 NaCl + 3 O2 </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/stoichiometry"> See all questions in Stoichiometry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3275 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What mass of carbon dioxide results from combustion of a #52*g# mass of acetylene gas?	null
1,554	a840ff0c-6ddd-11ea-ad78-ccda262736ce	https://socratic.org/questions/591cee69b72cff1b6153cd90	12.01 g	start physical_unit 9 9 mass g qc_end physical_unit 9 10 6 8 number qc_end end	[{"type":"physical unit","value":"Mass [OF] carbon [IN] g"}]	[{"type":"physical unit","value":"12.01 g"}]	[{"type":"physical unit","value":"Number [OF] carbon atoms [=] \\pu{4.5 × 10^26}"}]	<h1 class="questionTitle" itemprop="name">What would be the mass of #4.5xx10^26# carbon atoms?</h1>	null	12.01 g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>How do we know this? Well, <mathjax>#6.022xx10^23#</mathjax> individual <mathjax>#""^12C#</mathjax> atoms has a mass of <mathjax>#12.00g#</mathjax> precisely, and we use this number as a bridge between the sub-micro world of atoms and molecules to the macro world of grams, and litres, that which we can quantitatively measure.</p> <p>And so.........</p> <p><mathjax>#"Mass of carbon"=(4.5xx10^26"carbon atoms"xx12.011g)/(6.022xx10^23"carbon atoms")#</mathjax></p> <p><mathjax>#~=9*kg#</mathjax> carbon...........</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, the mass of <mathjax>#6.022xx10^23#</mathjax> carbon atoms is <mathjax>#12.011g#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>How do we know this? Well, <mathjax>#6.022xx10^23#</mathjax> individual <mathjax>#""^12C#</mathjax> atoms has a mass of <mathjax>#12.00g#</mathjax> precisely, and we use this number as a bridge between the sub-micro world of atoms and molecules to the macro world of grams, and litres, that which we can quantitatively measure.</p> <p>And so.........</p> <p><mathjax>#"Mass of carbon"=(4.5xx10^26"carbon atoms"xx12.011g)/(6.022xx10^23"carbon atoms")#</mathjax></p> <p><mathjax>#~=9kg#</mathjax> carbon...........</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What would be the mass of #4.5xx10^26# carbon atoms?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="425524" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-18T12:38:09" itemprop="dateCreated"> May 18, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, the mass of <mathjax>#6.022xx10^23#</mathjax> carbon atoms is <mathjax>#12.011g#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>How do we know this? Well, <mathjax>#6.022xx10^23#</mathjax> individual <mathjax>#""^12C#</mathjax> atoms has a mass of <mathjax>#12.00g#</mathjax> precisely, and we use this number as a bridge between the sub-micro world of atoms and molecules to the macro world of grams, and litres, that which we can quantitatively measure.</p> <p>And so.........</p> <p><mathjax>#"Mass of carbon"=(4.5xx10^26"carbon atoms"xx12.011g)/(6.022xx10^23"carbon atoms")#</mathjax></p> <p><mathjax>#~=9kg#</mathjax> carbon...........</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/425524" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="425527" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meneernask"><img alt="" class="" src="https://profilepictures.socratic.org/gpA0lokRGK9vLVUnAMAy_meneernask.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meneernask"> MeneerNask </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-18T12:42:05" itemprop="dateCreated"> May 18, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We will convert to mols.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>1 mol of <mathjax>#C#</mathjax> has 6.02xx10^23 atoms (Avogadro's number).</p> <p>So the number you mention contains:</p> <p><mathjax>#(4.5xx10^26)/(6.02xx10^23)=0.748xx10^3mol#</mathjax></p> <p>Since 1 mol of <mathjax>#C#</mathjax> has a mass of <mathjax>#12.01g#</mathjax></p> <p>Total mass <mathjax>#=12.01xx0.748xx10^3=8.98xx10^3g~~9.0kg#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/425527" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? 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1,555	ac45a4b7-6ddd-11ea-bf5e-ccda262736ce	https://socratic.org/questions/5964ecc8b72cff2edfe3717d	3 Fe(s) + 8 H2O(l) -> Fe^2+ + 2 Fe^3+ + 4 H2(g) + 8 OH-	start chemical_equation qc_end chemical_equation 7 7 qc_end substance 12 13 qc_end c_other OTHER qc_end end	[{"type":"other","value":"Chemical Equation [OF] the formation"}]	[{"type":"chemical equation","value":"3 Fe(s) + 8 H2O(l) -> Fe^2+ + 2 Fe^3+ + 4 H2(g) + 8 OH-"}]	[{"type":"chemical equation","value":"Fe3O4"},{"type":"substance name","value":"Iron metal"},{"type":"other","value":"In basic conditions."}]	<h1 class="questionTitle" itemprop="name">How do we represent the formation of #Fe_3O_4# by the oxidation of iron metal in basic conditions?</h1>	null	3 Fe(s) + 8 H2O(l) -> Fe^2+ + 2 Fe^3+ + 4 H2(g) + 8 OH-	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>If you got <mathjax>#Fe_3O_4#</mathjax>, this is mixed valence oxide of iron ......it occurs as the mineral magnetite, which we could formulate as <mathjax>#FeO*Fe_2O_3-=Fe_3O_4#</mathjax>.......</p> <p>And so metallic iron is oxidized to <mathjax>#Fe^(2+) + 2xxFe^(3+)#</mathjax>............</p> <p><mathjax>#3Fe(s) rarr Fe^(2+) + 2Fe^(3+)+8e^(-)#</mathjax> <mathjax>#(i)#</mathjax></p> <p>But something must be correspondingly reduced.....and here it is the protium ion in water........</p> <p><mathjax>#H_2O+e^(-) rarr1/2H_2(g) + HO^-#</mathjax> <mathjax>#(ii)#</mathjax></p> <p>And so I take <mathjax>#(i)+8xx(ii)#</mathjax> to gives...........</p> <p><mathjax>#3Fe(s) +8H_2Orarr Fe^(2+) + 2Fe^(3+)+4H_2(g) +8HO^-#</mathjax></p> <p>Charge and mass are balanced as is required...........</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#3Fe(s) +8H_2Orarr Fe^(2+) + 2Fe^(3+)+4H_2(g) +8HO^-#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>If you got <mathjax>#Fe_3O_4#</mathjax>, this is mixed valence oxide of iron ......it occurs as the mineral magnetite, which we could formulate as <mathjax>#FeO*Fe_2O_3-=Fe_3O_4#</mathjax>.......</p> <p>And so metallic iron is oxidized to <mathjax>#Fe^(2+) + 2xxFe^(3+)#</mathjax>............</p> <p><mathjax>#3Fe(s) rarr Fe^(2+) + 2Fe^(3+)+8e^(-)#</mathjax> <mathjax>#(i)#</mathjax></p> <p>But something must be correspondingly reduced.....and here it is the protium ion in water........</p> <p><mathjax>#H_2O+e^(-) rarr1/2H_2(g) + HO^-#</mathjax> <mathjax>#(ii)#</mathjax></p> <p>And so I take <mathjax>#(i)+8xx(ii)#</mathjax> to gives...........</p> <p><mathjax>#3Fe(s) +8H_2Orarr Fe^(2+) + 2Fe^(3+)+4H_2(g) +8HO^-#</mathjax></p> <p>Charge and mass are balanced as is required...........</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do we represent the formation of #Fe_3O_4# by the oxidation of iron metal in basic conditions?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="450464" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-07-11T15:33:17" itemprop="dateCreated"> Jul 11, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#3Fe(s) +8H_2Orarr Fe^(2+) + 2Fe^(3+)+4H_2(g) +8HO^-#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>If you got <mathjax>#Fe_3O_4#</mathjax>, this is mixed valence oxide of iron ......it occurs as the mineral magnetite, which we could formulate as <mathjax>#FeO*Fe_2O_3-=Fe_3O_4#</mathjax>.......</p> <p>And so metallic iron is oxidized to <mathjax>#Fe^(2+) + 2xxFe^(3+)#</mathjax>............</p> <p><mathjax>#3Fe(s) rarr Fe^(2+) + 2Fe^(3+)+8e^(-)#</mathjax> <mathjax>#(i)#</mathjax></p> <p>But something must be correspondingly reduced.....and here it is the protium ion in water........</p> <p><mathjax>#H_2O+e^(-) rarr1/2H_2(g) + HO^-#</mathjax> <mathjax>#(ii)#</mathjax></p> <p>And so I take <mathjax>#(i)+8xx(ii)#</mathjax> to gives...........</p> <p><mathjax>#3Fe(s) +8H_2Orarr Fe^(2+) + 2Fe^(3+)+4H_2(g) +8HO^-#</mathjax></p> <p>Charge and mass are balanced as is required...........</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/450464" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight 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Sodium phosphate and calcium chloride react to form... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-equation-kclo3-kcl-o2"> How can I balance this equation? ____ #KClO_3 -># ____ #KCl +# ____ #O_2# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-balancing-chemical-equations-important"> Why is balancing chemical equations important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/balancing-chemical-equations"> See all questions in Balancing Chemical Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 983 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How do we represent the formation of #Fe_3O_4# by the oxidation of iron metal in basic conditions?	null
1,556	a890b4be-6ddd-11ea-b235-ccda262736ce	https://socratic.org/questions/the-k-sp-of-al-oh-3-is-2-10-32-at-what-ph-will-a-0-9-m-al-3-solution-begin-to-sh	2.97	start physical_unit 15 16 ph none qc_end physical_unit 3 3 5 7 equilibrium_constant_k qc_end physical_unit 15 16 13 14 molarity qc_end end	[{"type":"physical unit","value":"pH [OF] Al^3+ solution"}]	[{"type":"physical unit","value":"2.97"}]	[{"type":"physical unit","value":"Ksp [OF] Al(OH)3 [=] \\pu{2 × 10^(-32)}"},{"type":"physical unit","value":"Molarity [OF] Al^3+ solution [=] \\pu{0.9 M}"}]	<h1 class="questionTitle" itemprop="name">The #K_sp# of #Al(OH)_3# is #2*10^-32#. At what pH will a 0.9 M #Al^(3+)# solution begin to show precipitation of #Al(OH)_3#?</h1>	null	2.97	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Solution</p> <p>Write the disassociation equation</p> <p><mathjax>#Al(OH)_3 ⇌ Al^(3+) + 3OH^-#</mathjax></p> <p>The <a href="https://socratic.org/chemistry/chemical-equilibrium/ksp">Ksp</a> expression </p> <p><mathjax>#Ksp = [Al3^+] [3OH¯]^3#</mathjax></p> <p>Plug in the Ksp expression</p> <p><mathjax>#2.0 * 10^(-32) = (0.9)(3x)^3#</mathjax></p> <p>Solve for<mathjax># x#</mathjax> which is the concentration of<mathjax># OH^-#</mathjax></p> <p><mathjax>#0.00000000000000000000000000000002 = 0.9 (3x)^3#</mathjax></p> <p>x =<mathjax># 9.37147E - 12#</mathjax></p> <p>Now calculate <mathjax>#"pOH"#</mathjax> from <mathjax>#OH^- #</mathjax></p> <p><mathjax>#pOH = -log(9.37147E -12M)#</mathjax></p> <p><mathjax>#pOH = 11.0281922807#</mathjax></p> <p><mathjax>#pH = 14 - 11.0281922807#</mathjax><br/> <mathjax>#pH = 2.9718077193 or 3#</mathjax>(rounded off)</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#pH = 2.9718077193 or 3#</mathjax>(rounded off)</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Solution</p> <p>Write the disassociation equation</p> <p><mathjax>#Al(OH)_3 ⇌ Al^(3+) + 3OH^-#</mathjax></p> <p>The <a href="https://socratic.org/chemistry/chemical-equilibrium/ksp">Ksp</a> expression </p> <p><mathjax>#Ksp = [Al3^+] [3OH¯]^3#</mathjax></p> <p>Plug in the Ksp expression</p> <p><mathjax>#2.0 * 10^(-32) = (0.9)(3x)^3#</mathjax></p> <p>Solve for<mathjax># x#</mathjax> which is the concentration of<mathjax># OH^-#</mathjax></p> <p><mathjax>#0.00000000000000000000000000000002 = 0.9 (3x)^3#</mathjax></p> <p>x =<mathjax># 9.37147E - 12#</mathjax></p> <p>Now calculate <mathjax>#"pOH"#</mathjax> from <mathjax>#OH^- #</mathjax></p> <p><mathjax>#pOH = -log(9.37147E -12M)#</mathjax></p> <p><mathjax>#pOH = 11.0281922807#</mathjax></p> <p><mathjax>#pH = 14 - 11.0281922807#</mathjax><br/> <mathjax>#pH = 2.9718077193 or 3#</mathjax>(rounded off)</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">The #K_sp# of #Al(OH)_3# is #210^-32#. At what pH will a 0.9 M #Al^(3+)# solution begin to show precipitation of #Al(OH)_3#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/ph-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">pH calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="379528" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/samriddha"><img alt="" class="" src="https://profilepictures.socratic.org/3bMcXdwZTLqpsJaquExz_Shinjuku.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/samriddha"> Professor Sam </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-02-18T06:58:49" itemprop="dateCreated"> Feb 18, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#pH = 2.9718077193 or 3#</mathjax>(rounded off)</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Solution</p> <p>Write the disassociation equation</p> <p><mathjax>#Al(OH)_3 ⇌ Al^(3+) + 3OH^-#</mathjax></p> <p>The <a href="https://socratic.org/chemistry/chemical-equilibrium/ksp">Ksp</a> expression </p> <p><mathjax>#Ksp = [Al3^+] [3OH¯]^3#</mathjax></p> <p>Plug in the Ksp expression</p> <p><mathjax>#2.0 10^(-32) = (0.9)(3x)^3#</mathjax></p> <p>Solve for<mathjax># x#</mathjax> which is the concentration of<mathjax># OH^-#</mathjax></p> <p><mathjax>#0.00000000000000000000000000000002 = 0.9 (3x)^3#</mathjax></p> <p>x =<mathjax># 9.37147E - 12#</mathjax></p> <p>Now calculate <mathjax>#"pOH"#</mathjax> from <mathjax>#OH^- #</mathjax></p> <p><mathjax>#pOH = -log(9.37147E -12M)#</mathjax></p> <p><mathjax>#pOH = 11.0281922807#</mathjax></p> <p><mathjax>#pH = 14 - 11.0281922807#</mathjax><br/> <mathjax>#pH = 2.9718077193 or 3#</mathjax>(rounded off)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/379528" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-of-a-solution"> How do you determine ph of a solution? 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At what pH will a 0.9 M #Al^(3+)# solution begin to show precipitation of #Al(OH)_3#?	null
1,557	ac81a79a-6ddd-11ea-97f7-ccda262736ce	https://socratic.org/questions/if-you-have-a-gas-at-a-pressure-of-16-5-atm-volume-of-123-9-ml-and-a-temperature	0.09 moles	start physical_unit 4 4 mole mol qc_end physical_unit 4 4 9 10 pressure qc_end physical_unit 4 4 13 14 volume qc_end physical_unit 4 4 19 20 temperature qc_end end	[{"type":"physical unit","value":"Mole [OF] the gas [IN] moles"}]	[{"type":"physical unit","value":"0.09 moles"}]	[{"type":"physical unit","value":"Pressure [OF] the gas [=] \\pu{16.5 atm}"},{"type":"physical unit","value":"Volume [OF] the gas [=] \\pu{123.9 mL}"},{"type":"physical unit","value":"Temperature [OF] the gas [=] \\pu{11 ℃}"}]	<h1 class="questionTitle" itemprop="name">If you have a gas at a pressure of 16.5 atm, volume of 123.9 mL, and a temperature of 11°C, how many moles do you have?</h1>	null	0.09 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>If you assume that the gas behaves like an ideal gas, you can use the expression Pv=NRT where P is pressure, v is volume, N is number of moles, R is the gas constant and T is temperature.</p> <p>As we have units of atm for pressure, we can use the gas constant value expressed in litre atm per degree K, which is 0.08206. We also need to convert the volume into litres, and the temperature into Kelvins to ensure we are working with consistent units.</p> <p>Now simply rearrange for N: N = Pv/RT = (16.5 x 0.1239) / (0.08206 x 284) = 2.044 / 23.305 = 0.0877 moles.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.0877 moles</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>If you assume that the gas behaves like an ideal gas, you can use the expression Pv=NRT where P is pressure, v is volume, N is number of moles, R is the gas constant and T is temperature.</p> <p>As we have units of atm for pressure, we can use the gas constant value expressed in litre atm per degree K, which is 0.08206. We also need to convert the volume into litres, and the temperature into Kelvins to ensure we are working with consistent units.</p> <p>Now simply rearrange for N: N = Pv/RT = (16.5 x 0.1239) / (0.08206 x 284) = 2.044 / 23.305 = 0.0877 moles.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">If you have a gas at a pressure of 16.5 atm, volume of 123.9 mL, and a temperature of 11°C, how many moles do you have?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/ideal-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Ideal Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="264972" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/simon-moore"><img alt="" class="" src="https://profilepictures.socratic.org/0ztdJJ7RCWUlBSPeGa9N_6EB6CADA-35F5-4BAA-9B66-9D6F64A622BA.jpeg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/simon-moore"> Simon Moore </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-12T13:18:51" itemprop="dateCreated"> May 12, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.0877 moles</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>If you assume that the gas behaves like an ideal gas, you can use the expression Pv=NRT where P is pressure, v is volume, N is number of moles, R is the gas constant and T is temperature.</p> <p>As we have units of atm for pressure, we can use the gas constant value expressed in litre atm per degree K, which is 0.08206. We also need to convert the volume into litres, and the temperature into Kelvins to ensure we are working with consistent units.</p> <p>Now simply rearrange for N: N = Pv/RT = (16.5 x 0.1239) / (0.08206 x 284) = 2.044 / 23.305 = 0.0877 moles.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/264972" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-ideal-gas-constant"> How do you find the ideal gas constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-solve-ideal-gas-law-problems"> How do you solve ideal gas law problems? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-know-which-ideal-gas-constant-to-use"> How do you know which ideal gas constant to use? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ideal-gas-constant-for-butane"> What is the ideal gas constant for butane? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-ideal-gas-law-in-kelvin"> Why is ideal gas law in kelvin? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ideal-gas-constant-important"> Why is the ideal gas constant important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-di-electric-constant"> What is the di-electric constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-volume-l-will-0-20-mol-hi-occupy-at-300-k-and-100-0-kpa-r-8-314-kpa-l-k-mol"> What volume (L) will 0.20 mol HI occupy at 300 K and 100.0 kPa? R = 8.314 kPa L / (K mol) =... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-molar-mass-of-a-gas"> How do you calculate the molar mass of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-should-i-use-the-ideal-gas-law-and-not-the-combined-gas-law"> When should I use the ideal gas law and not the combined gas law? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/ideal-gas-law"> See all questions in Ideal Gas Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1609 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	If you have a gas at a pressure of 16.5 atm, volume of 123.9 mL, and a temperature of 11°C, how many moles do you have?	null
1,558	ad0e7eb0-6ddd-11ea-adcb-ccda262736ce	https://socratic.org/questions/solid-magnesium-has-a-specific-heat-of-1-01-j-g-c-how-much-heat-is-given-off-by-	404 J	start physical_unit 21 23 heat_energy j qc_end physical_unit 0 1 7 10 specific_heat qc_end physical_unit 21 23 19 20 mass qc_end physical_unit 21 23 28 29 temperature qc_end physical_unit 21 23 31 32 temperature qc_end end	[{"type":"physical unit","value":"Given off heat [OF] magnesium sample [IN] J"}]	[{"type":"physical unit","value":"404 J"}]	[{"type":"physical unit","value":"Specific heat [OF] solid magnesium [=] \\pu{1.01 J/(g * ℃)}"},{"type":"physical unit","value":"Mass [OF] magnesium sample [=] \\pu{20.0 gram}"},{"type":"physical unit","value":"Temperature1 [OF] magnesium sample [=] \\pu{70.0 ℃}"},{"type":"physical unit","value":"Temperature2 [OF] magnesium sample [=] \\pu{50.0 ℃}"}]	<h1 class="questionTitle" itemprop="name">Solid magnesium has a specific heat of 1.01 J/g°C. How much heat is given off by a 20.0 gram sample of magnesium when it cools from 70.0°C to 50.0°C?</h1>	null	404 J	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Let's get started by using the <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> capacity equation:</p> <p><img alt="1048believe.com" src="https://useruploads.socratic.org/r0akIXceT5ucsG0ORGx6_specific-heat-capacity-formula-physics-i0.jpg"/> </p> <p>Based on what you've given me, we have the mass of the sample (m), the specific heat (c), and the change in temperature <mathjax>#DeltaT#</mathjax>. </p> <p>I should also add that "m" isn't limited to just water, it can be the mass of almost any substance. Also, <mathjax>#DeltaT#</mathjax> is <mathjax>#-20^oC#</mathjax> because the change in temperature is always <strong>final temperature- initial temperature</strong><br/> (<mathjax>#50^oC - 70^oC#</mathjax>).</p> <p>All of the variables have good units, so we just have to multiply all of the given values together to obtain Q (energy transferred).</p> <p><mathjax>#Q = 20.0cancelgxx(1.01J)/(cancelgxx^ocancelC)xx-20^ocancelC#</mathjax></p> <p><mathjax>#Q = -404 J#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>I got <mathjax>#-404 J#</mathjax> of heat being given off.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Let's get started by using the <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> capacity equation:</p> <p><img alt="1048believe.com" src="https://useruploads.socratic.org/r0akIXceT5ucsG0ORGx6_specific-heat-capacity-formula-physics-i0.jpg"/> </p> <p>Based on what you've given me, we have the mass of the sample (m), the specific heat (c), and the change in temperature <mathjax>#DeltaT#</mathjax>. </p> <p>I should also add that "m" isn't limited to just water, it can be the mass of almost any substance. Also, <mathjax>#DeltaT#</mathjax> is <mathjax>#-20^oC#</mathjax> because the change in temperature is always <strong>final temperature- initial temperature</strong><br/> (<mathjax>#50^oC - 70^oC#</mathjax>).</p> <p>All of the variables have good units, so we just have to multiply all of the given values together to obtain Q (energy transferred).</p> <p><mathjax>#Q = 20.0cancelgxx(1.01J)/(cancelgxx^ocancelC)xx-20^ocancelC#</mathjax></p> <p><mathjax>#Q = -404 J#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Solid magnesium has a specific heat of 1.01 J/g°C. How much heat is given off by a 20.0 gram sample of magnesium when it cools from 70.0°C to 50.0°C?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/calorimetry" itemprop="url"> <span class="breadcrumb" itemprop="title">Calorimetry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="282046" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/kayla-14"><img alt="" class="" src="https://profilepictures.socratic.org/OvMTWaamQPWcqLIkUNnG_793604964071127.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/kayla-14"> Kayla </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-28T01:47:08" itemprop="dateCreated"> Jun 28, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>I got <mathjax>#-404 J#</mathjax> of heat being given off.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Let's get started by using the <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> capacity equation:</p> <p><img alt="1048believe.com" src="https://useruploads.socratic.org/r0akIXceT5ucsG0ORGx6_specific-heat-capacity-formula-physics-i0.jpg"/> </p> <p>Based on what you've given me, we have the mass of the sample (m), the specific heat (c), and the change in temperature <mathjax>#DeltaT#</mathjax>. </p> <p>I should also add that "m" isn't limited to just water, it can be the mass of almost any substance. Also, <mathjax>#DeltaT#</mathjax> is <mathjax>#-20^oC#</mathjax> because the change in temperature is always <strong>final temperature- initial temperature</strong><br/> (<mathjax>#50^oC - 70^oC#</mathjax>).</p> <p>All of the variables have good units, so we just have to multiply all of the given values together to obtain Q (energy transferred).</p> <p><mathjax>#Q = 20.0cancelgxx(1.01J)/(cancelgxx^ocancelC)xx-20^ocancelC#</mathjax></p> <p><mathjax>#Q = -404 J#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/282046" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-differential-scanning-in-calorimetry-work"> How does differential scanning in calorimetry work? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-read-differential-scanning-in-calorimetry"> What information do you get from a differential scanning calorimetry plot? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-measure-calorimetry"> How do you measure calorimetry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531d304102bf341e75b962a7"> Question #962a7 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5335021802bf344ae911dfc5"> Question #1dfc5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/533668f502bf34572c341af6"> Question #41af6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-definition-of-calorimetry"> What is calorimetry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-differential-scanning-calorimeter"> What is a differential scanning calorimeter? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-a-calorimeter-measure-energy"> How can a calorimeter measure energy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-calorimeters-made-of"> What are calorimeters made of? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/calorimetry"> See all questions in Calorimetry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 13350 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Solid magnesium has a specific heat of 1.01 J/g°C. How much heat is given off by a 20.0 gram sample of magnesium when it cools from 70.0°C to 50.0°C?	null
1,559	ab81949e-6ddd-11ea-b160-ccda262736ce	https://socratic.org/questions/591e1ae111ef6b6cbf7a0289	+14.36 kJ/mol	start physical_unit 8 10 enthalpy kj/mol qc_end chemical_equation 12 20 qc_end chemical_equation 22 31 qc_end chemical_equation 33 42 qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Enthalpy change [OF] the overall reaction [IN] kJ/mol"}]	[{"type":"physical unit","value":"+14.36 kJ/mol"}]	[{"type":"chemical equation","value":"H3BO3(aq) -> HBO2(aq) + H2O(l), deltaH1 = -0.02 kJ/mol"},{"type":"chemical equation","value":"H2B4O7(aq) + H2O(l) -> 4 HBO2(aq), deltaH2 = -11.3 kJ/mol"},{"type":"chemical equation","value":"H2B4O7(aq) -> 2 B2O3(s) + H2O(l), deltaH3 = 17.5 kJ/mol"},{"type":"other","value":"Using Hess's law."}]	<h1 class="questionTitle" itemprop="name">Using Hess's law, determine the enthalpy change for the overall reaction?</h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><blockquote> <p><mathjax>#(i)#</mathjax> <mathjax>#"H"_3"BO"_3(aq) -> "HBO"_2(aq) + "H"_2"O"(l)#</mathjax>, <mathjax>#DeltaH_1 = -"0.02 kJ/mol"#</mathjax></p> <p><mathjax>#(ii)#</mathjax> <mathjax>#"H"_2"B"_4"O"_7(aq) + "H"_2"O"(l) -> 4"HBO"_2(aq)#</mathjax>, <mathjax>#DeltaH_2 = -"11.3 kJ/mol"#</mathjax></p> <p><mathjax>#(iii)#</mathjax> <mathjax>#"H"_2"B"_4"O"_7(aq) -> 2"B"_2"O"_3(s) + "H"_2"O"(l)#</mathjax>, <mathjax>#DeltaH_3 = "17.5 kJ/mol"#</mathjax></p> </blockquote></div> </h2> </div> </div>	+14.36 kJ/mol	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The given equation can be obtained by</p> <blockquote> <p><mathjax>#2xx(i)-((ii))/2+((iii))/2#</mathjax>,</p> </blockquote> <p>since we have:</p> <blockquote> <p><mathjax>#2("H"_3"BO"_3(aq) -> cancel("HBO"_2(aq)) + "H"_2"O"(l))#</mathjax></p> <p><mathjax>#-1/2 (cancel("H"_2"B"_4"O"_7(aq)) + "H"_2"O"(l) -> cancel(4"HBO"_2(aq)))#</mathjax></p> <p><mathjax>#1/2 (cancel("H"_2"B"_4"O"_7(aq)) -> 2"B"_2"O"_3(s) + "H"_2"O"(l))#</mathjax><br/> So,</p> <p><mathjax>#DeltaH=2(-0.02)-((-11.3))/2+((17.5))/2#</mathjax></p> <p><mathjax>#=>DeltaH=+14.36#</mathjax> <mathjax>#kJmol^-1#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#DeltaH=+14.36#</mathjax> <mathjax>#kJmol^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The given equation can be obtained by</p> <blockquote> <p><mathjax>#2xx(i)-((ii))/2+((iii))/2#</mathjax>,</p> </blockquote> <p>since we have:</p> <blockquote> <p><mathjax>#2("H"_3"BO"_3(aq) -> cancel("HBO"_2(aq)) + "H"_2"O"(l))#</mathjax></p> <p><mathjax>#-1/2 (cancel("H"_2"B"_4"O"_7(aq)) + "H"_2"O"(l) -> cancel(4"HBO"_2(aq)))#</mathjax></p> <p><mathjax>#1/2 (cancel("H"_2"B"_4"O"_7(aq)) -> 2"B"_2"O"_3(s) + "H"_2"O"(l))#</mathjax><br/> So,</p> <p><mathjax>#DeltaH=2(-0.02)-((-11.3))/2+((17.5))/2#</mathjax></p> <p><mathjax>#=>DeltaH=+14.36#</mathjax> <mathjax>#kJ*mol^-1#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Using Hess's law, determine the enthalpy change for the overall reaction?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><blockquote> <p><mathjax>#(i)#</mathjax> <mathjax>#"H"_3"BO"_3(aq) -> "HBO"_2(aq) + "H"_2"O"(l)#</mathjax>, <mathjax>#DeltaH_1 = -"0.02 kJ/mol"#</mathjax></p> <p><mathjax>#(ii)#</mathjax> <mathjax>#"H"_2"B"_4"O"_7(aq) + "H"_2"O"(l) -> 4"HBO"_2(aq)#</mathjax>, <mathjax>#DeltaH_2 = -"11.3 kJ/mol"#</mathjax></p> <p><mathjax>#(iii)#</mathjax> <mathjax>#"H"_2"B"_4"O"_7(aq) -> 2"B"_2"O"_3(s) + "H"_2"O"(l)#</mathjax>, <mathjax>#DeltaH_3 = "17.5 kJ/mol"#</mathjax></p> </blockquote></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/enthalpy" itemprop="url"> <span class="breadcrumb" itemprop="title">Enthalpy</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="462638" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/truong-son-n"><img alt="" class="" src="https://profilepictures.socratic.org/07k4plnQfmnmzMuesQzw_14844-1449381920.png" title=""/></a> <a class="secondContributorPic" href="/users/harsh-s-6"><img alt="" class="" src="https://lh3.googleusercontent.com/-wVwa7ayo26s/AAAAAAAAAAI/AAAAAAAAAHY/2LiJ8tWuxN8/photo.jpg?sz=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/truong-son-n"> Truong-Son N. </a>·<a class="topContributorLink" href="/users/harsh-s-6"> harsh s. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-11T02:04:00" itemprop="dateCreated"> Aug 11, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#DeltaH=+14.36#</mathjax> <mathjax>#kJmol^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The given equation can be obtained by</p> <blockquote> <p><mathjax>#2xx(i)-((ii))/2+((iii))/2#</mathjax>,</p> </blockquote> <p>since we have:</p> <blockquote> <p><mathjax>#2("H"_3"BO"_3(aq) -> cancel("HBO"_2(aq)) + "H"_2"O"(l))#</mathjax></p> <p><mathjax>#-1/2 (cancel("H"_2"B"_4"O"_7(aq)) + "H"_2"O"(l) -> cancel(4"HBO"_2(aq)))#</mathjax></p> <p><mathjax>#1/2 (cancel("H"_2"B"_4"O"_7(aq)) -> 2"B"_2"O"_3(s) + "H"_2"O"(l))#</mathjax><br/> So,</p> <p><mathjax>#DeltaH=2(-0.02)-((-11.3))/2+((17.5))/2#</mathjax></p> <p><mathjax>#=>DeltaH=+14.36#</mathjax> <mathjax>#kJ*mol^-1#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/462638" itemprop="url">Answer link</a> </div> </div> </div> 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</div> </div> </div> </div> </div> </div> </article>	Using Hess's law, determine the enthalpy change for the overall reaction?	#(i)# #"H"_3"BO"_3(aq) -> "HBO"_2(aq) + "H"_2"O"(l)#, #DeltaH_1 = -"0.02 kJ/mol"# #(ii)# #"H"_2"B"_4"O"_7(aq) + "H"_2"O"(l) -> 4"HBO"_2(aq)#, #DeltaH_2 = -"11.3 kJ/mol"# #(iii)# #"H"_2"B"_4"O"_7(aq) -> 2"B"_2"O"_3(s) + "H"_2"O"(l)#, #DeltaH_3 = "17.5 kJ/mol"#
1,560	a9024536-6ddd-11ea-935c-ccda262736ce	https://socratic.org/questions/how-many-moles-of-h2o-could-be-obtained-by-reacting-0-75-mole-of-h2o2-in-the-rea	1.50 moles	start physical_unit 4 4 mole mol qc_end chemical_equation 17 24 qc_end physical_unit 13 13 10 11 mole qc_end end	[{"type":"physical unit","value":"Mole [OF] H2O [IN] moles"}]	[{"type":"physical unit","value":"1.50 moles"}]	[{"type":"chemical equation","value":"H2O2 + H2S -> 2 H2O + S"},{"type":"physical unit","value":"Mole [OF] H2O2 [=] \\pu{0.75 mole}"}]	<h1 class="questionTitle" itemprop="name">How many moles of H2O could be obtained by reacting 0.75 mole of H2O2 in the reaction H2O2+H2S→2H2O+S?</h1>	null	1.50 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You have the stoichiometric reaction:</p> <p><mathjax>#H_2O_2(l) + H_2S(g) rarr 2H_2O(l) + S(s)darr#</mathjax></p> <p>Is it balanced? For every reactant particle is there a corresponding product particle? There must be if the reaction represents chemical reality. It is balanced, and you have done the work not me. The reaction tells me UNEQUIVOCALLY that <mathjax>#34g#</mathjax> of hydrogen peroxide reacts with <mathjax>#34g#</mathjax> hydrogen sulfide to give <mathjax>#36g#</mathjax> water and <mathjax>#32g#</mathjax> sulfur. All of these masses correspond to molar equivalents. Charge and mass are balanced as required. From where did I get these masses? Did I just look them up?</p> <p>Your starting conditions propose that <mathjax>#0.75mol#</mathjax> hydrogen peroxide reacts, to give, THEREFORE, <mathjax>#27g#</mathjax> <mathjax>#H_2O#</mathjax>, and <mathjax>#24g#</mathjax> sulfur. Do you agree? This is an important principle to master, and if you don't from where we are coming, ask again. </p> <p>And note that <mathjax>#0.75mol#</mathjax> <mathjax>#H_2O_2#</mathjax> represents a mass of <mathjax>#0.75molxx34gmol^-1-=25.5g#</mathjax>........etc........</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>What does the <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> say..........? It says that <mathjax>#1mol#</mathjax> of hydrogen peroxide and <mathjax>#1mol#</mathjax> hydrogen sulfide gives <mathjax>#2 mol#</mathjax> of water and <mathjax>#1mol#</mathjax> of sulfur.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You have the stoichiometric reaction:</p> <p><mathjax>#H_2O_2(l) + H_2S(g) rarr 2H_2O(l) + S(s)darr#</mathjax></p> <p>Is it balanced? For every reactant particle is there a corresponding product particle? There must be if the reaction represents chemical reality. It is balanced, and you have done the work not me. The reaction tells me UNEQUIVOCALLY that <mathjax>#34g#</mathjax> of hydrogen peroxide reacts with <mathjax>#34g#</mathjax> hydrogen sulfide to give <mathjax>#36g#</mathjax> water and <mathjax>#32g#</mathjax> sulfur. All of these masses correspond to molar equivalents. Charge and mass are balanced as required. From where did I get these masses? Did I just look them up?</p> <p>Your starting conditions propose that <mathjax>#0.75mol#</mathjax> hydrogen peroxide reacts, to give, THEREFORE, <mathjax>#27g#</mathjax> <mathjax>#H_2O#</mathjax>, and <mathjax>#24g#</mathjax> sulfur. Do you agree? This is an important principle to master, and if you don't from where we are coming, ask again. </p> <p>And note that <mathjax>#0.75mol#</mathjax> <mathjax>#H_2O_2#</mathjax> represents a mass of <mathjax>#0.75molxx34gmol^-1-=25.5g#</mathjax>........etc........</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles of H2O could be obtained by reacting 0.75 mole of H2O2 in the reaction H2O2+H2S→2H2O+S?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/mole-ratios" itemprop="url"> <span class="breadcrumb" itemprop="title">Mole Ratios</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">3</span> Answers </h5> <div class="answers"> <div class="answer" id="457450" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-07-29T04:36:58" itemprop="dateCreated"> Jul 29, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>What does the <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> say..........? It says that <mathjax>#1mol#</mathjax> of hydrogen peroxide and <mathjax>#1mol#</mathjax> hydrogen sulfide gives <mathjax>#2 mol#</mathjax> of water and <mathjax>#1mol#</mathjax> of sulfur.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You have the stoichiometric reaction:</p> <p><mathjax>#H_2O_2(l) + H_2S(g) rarr 2H_2O(l) + S(s)darr#</mathjax></p> <p>Is it balanced? For every reactant particle is there a corresponding product particle? There must be if the reaction represents chemical reality. It is balanced, and you have done the work not me. The reaction tells me UNEQUIVOCALLY that <mathjax>#34g#</mathjax> of hydrogen peroxide reacts with <mathjax>#34g#</mathjax> hydrogen sulfide to give <mathjax>#36g#</mathjax> water and <mathjax>#32g#</mathjax> sulfur. All of these masses correspond to molar equivalents. Charge and mass are balanced as required. From where did I get these masses? Did I just look them up?</p> <p>Your starting conditions propose that <mathjax>#0.75mol#</mathjax> hydrogen peroxide reacts, to give, THEREFORE, <mathjax>#27g#</mathjax> <mathjax>#H_2O#</mathjax>, and <mathjax>#24g#</mathjax> sulfur. Do you agree? This is an important principle to master, and if you don't from where we are coming, ask again. </p> <p>And note that <mathjax>#0.75mol#</mathjax> <mathjax>#H_2O_2#</mathjax> represents a mass of <mathjax>#0.75molxx34gmol^-1-=25.5g#</mathjax>........etc........</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/457450" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="457453" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/peter-m-8"><img alt="" class="" src="https://lh6.googleusercontent.com/-8YyKx7wqg0I/AAAAAAAAAAI/AAAAAAAAACo/JWBHiurCais/photo.jpg?sz=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/peter-m-8"> Peter M. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-07-29T04:45:04" itemprop="dateCreated"> Jul 29, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>1.5 moles of water could be obtained.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First, we always want the balanced chemical equation as this tells us the proportions that the reactants will react in, and how much of the products are formed.</p> <p><mathjax>#H_2O_2+H_2Srarr2H_2O+S#</mathjax></p> <p>This equation tells us that for every mole of <mathjax>#H_2O_2#</mathjax>, two moles of water are produced. Therefore:</p> <p><mathjax>#n(H_2O)=2n(H_2O_2)=20.75=1.5" "mol#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/457453" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="457454" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-07-29T04:45:16" itemprop="dateCreated"> Jul 29, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"1.5 mol H"_2"O"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>Balanced Equation</strong></p> <p><mathjax>#"H"_2"O"_2 + "H"_2"S"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"2H"_2"O" + "S"#</mathjax></p> <p>Multiply the given mol <mathjax>#"H"_2"O"#</mathjax> by <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio between <mathjax>#"H"_2"O"#</mathjax> and <mathjax>#"H"_2"O"_2#</mathjax>.</p> <p><mathjax>#0.75color(red)cancel(color(black)("mol H"_2"O"_2))xx(2"mol H"_2"O")/(1color(red)cancel(color(black)("mol H"_2"O"_2)))="1.5 mol H"_2"O"#</mathjax></p> <p>You can reason out the answer without having to do the math. Notice by looking at the balanced equation, that for every one mole of <mathjax>#"H"_2"O"_2"#</mathjax> in the reactants, there are two moles <mathjax>#"H"_2"O"#</mathjax> in the products. So any number of moles of <mathjax>#"H"_2"O"_2"#</mathjax> will produce twice as many moles of <mathjax>#"H"_2"O"#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/457454" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4178e02bf3469517a106e"> Question #a106e </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4178e02bf3469570e2e86"> Question #e2e86 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179102bf3469517a1072"> Question #a1072 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179402bf34694c8c5bf1"> Question #c5bf1 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179702bf3469588dc373"> Question #dc373 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179c02bf34694c8c5bf9"> Question #c5bf9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417a302bf3469517a1076"> Question #a1076 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417c702bf3469588dc377"> Question #dc377 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417d002bf346963eb984f"> Question #b984f </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417d402bf346950519ea3"> Question #19ea3 </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/mole-ratios"> See all questions in Mole Ratios </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 10826 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many moles of H2O could be obtained by reacting 0.75 mole of H2O2 in the reaction H2O2+H2S→2H2O+S?	null
1,561	aa6972f8-6ddd-11ea-a271-ccda262736ce	https://socratic.org/questions/5911c1c07c0149742a282b22	Cs(s) + 1/2 Br2(l) -> CsBr(s)	start chemical_equation qc_end substance 7 8 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the equation"}]	[{"type":"chemical equation","value":"Cs(s) + 1/2 Br2(l) -> CsBr(s)"}]	[{"type":"substance name","value":"Caesium bromide"}]	<h1 class="questionTitle" itemprop="name">How would we represent the formation of caesium bromide?</h1>	null	Cs(s) + 1/2 Br2(l) -> CsBr(s)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Is this a redox reaction? Why?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Cs(s) + 1/2Br_2(l) rarr CsBr(s)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Is this a redox reaction? Why?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How would we represent the formation of caesium bromide?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="420785" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-10T07:54:22" itemprop="dateCreated"> May 10, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Cs(s) + 1/2Br_2(l) rarr CsBr(s)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Is this a redox reaction? Why?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/420785" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-equation-for-photosynthesis"> What is the chemical equation for photosynthesis? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-know-the-relative-number-of-grams-of-each-substance-used-or-produced-w"> How can I know the relative number of grams of each substance used or produced with chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-know-the-relative-number-of-moles-of-each-substance-with-chemical-equa"> How can I know the relative number of moles of each substance with chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-chemical-equations-illustrate-that-atoms-are-conserved-1"> How do chemical equations illustrate that atoms are conserved? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-know-the-formula-of-the-reactants-and-products-with-chemical-equations"> How can I know the formula of the reactants and products with chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-potassium-metal-and-chlorine-gas-combi"> How can I balance this chemical equations? 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1,562	ac47794c-6ddd-11ea-8af1-ccda262736ce	https://socratic.org/questions/given-the-equation-1ch-4-2o-2-2h-2o-1co-2-what-is-the-total-number-of-moles-of-o	10.00 moles	start physical_unit 20 20 mole mol qc_end physical_unit 29 30 26 27 mole qc_end chemical_equation 3 11 qc_end end	[{"type":"physical unit","value":"Mole [OF] oxygen [IN] moles"}]	[{"type":"physical unit","value":"10.00 moles"}]	[{"type":"physical unit","value":"Mole [OF] carbon dioxide [=] \\pu{5 moles}"},{"type":"chemical equation","value":"CH4 + 2 O2 -> 2 H2O + CO2"}]	<h1 class="questionTitle" itemprop="name">Given the equation, #CH_4 + 2O_2->2H_2O + CO_2#, what is the total number of moles of oxygen that must react to produce 5 moles of carbon dioxide?</h1>	null	10.00 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You must observe the <a href="http://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> of the reaction. A mole of methane produces a mole of carbon dioxide. If 5 mole of carbon dioxide are specified, I need how many moles of methane in order to satisfy this stoichiometry? If 5 mole of carbon dioxide were collected, how many moles of oxygen gas (i.e. <mathjax>#O_2#</mathjax>) were necessary?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, 1 mol methane give 1 mol of carbon dioxide upon complete combustion. You want 5 mole carbon dioxide.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You must observe the <a href="http://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> of the reaction. A mole of methane produces a mole of carbon dioxide. If 5 mole of carbon dioxide are specified, I need how many moles of methane in order to satisfy this stoichiometry? If 5 mole of carbon dioxide were collected, how many moles of oxygen gas (i.e. <mathjax>#O_2#</mathjax>) were necessary?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Given the equation, #CH_4 + 2O_2->2H_2O + CO_2#, what is the total number of moles of oxygen that must react to produce 5 moles of carbon dioxide?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/mole-ratios" itemprop="url"> <span class="breadcrumb" itemprop="title">Mole Ratios</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="211070" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-11T08:00:06" itemprop="dateCreated"> Jan 11, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, 1 mol methane give 1 mol of carbon dioxide upon complete combustion. You want 5 mole carbon dioxide.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You must observe the <a href="http://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> of the reaction. A mole of methane produces a mole of carbon dioxide. If 5 mole of carbon dioxide are specified, I need how many moles of methane in order to satisfy this stoichiometry? If 5 mole of carbon dioxide were collected, how many moles of oxygen gas (i.e. <mathjax>#O_2#</mathjax>) were necessary?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/211070" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4178e02bf3469517a106e"> Question #a106e </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4178e02bf3469570e2e86"> Question #e2e86 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179102bf3469517a1072"> Question #a1072 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179402bf34694c8c5bf1"> Question #c5bf1 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179702bf3469588dc373"> Question #dc373 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179c02bf34694c8c5bf9"> Question #c5bf9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417a302bf3469517a1076"> Question #a1076 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417c702bf3469588dc377"> Question #dc377 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417d002bf346963eb984f"> Question #b984f </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417d402bf346950519ea3"> Question #19ea3 </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/mole-ratios"> See all questions in Mole Ratios </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1948 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Given the equation, #CH_4 + 2O_2->2H_2O + CO_2#, what is the total number of moles of oxygen that must react to produce 5 moles of carbon dioxide?	null
1,563	aa847ad4-6ddd-11ea-b421-ccda262736ce	https://socratic.org/questions/how-would-you-balance-the-reaction-of-white-phosphorous-p-4-with-oxygen-o-2-whic	P4(s) + 5 O2(g) -> P4O10(s)	start chemical_equation qc_end chemical_equation 9 9 qc_end chemical_equation 12 12 qc_end chemical_equation 17 17 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the reaction"}]	[{"type":"chemical equation","value":"P4(s) + 5 O2(g) -> P4O10(s)"}]	[{"type":"chemical equation","value":"P4"},{"type":"chemical equation","value":"O2"},{"type":"chemical equation","value":"P4O10"}]	<h1 class="questionTitle" itemprop="name">How would you balance the reaction of white phosphorous (#P_4#) with oxygen (#O_2#) which produces phosphorous oxide (#P_4O_10#)?</h1>	null	P4(s) + 5 O2(g) -> P4O10(s)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The problem provides you with the <strong>reactants</strong>, which are said to be </p> <blockquote> <ul> <li><em><strong>white phosphorus</strong></em>, <mathjax>#"P"_ (4(s))#</mathjax></li> <li><em><strong>oxygen gas</strong></em>, <mathjax>#"O"_ (2(g))#</mathjax></li> </ul> </blockquote> <p>and with the <strong>product</strong>, which is said to be </p> <blockquote> <ul> <li><em><strong>diphosphorus pentoxide</strong>, also called phosphorus(V) oxide</em>, <mathjax>#"P"_ 4"O"_ (10(s))#</mathjax></li> </ul> </blockquote> <p>which means that you have all the information you need to write the <em>unbalanced</em> chemical equation</p> <blockquote> <p><mathjax>#"P"_ (4(s)) + "O"_ (2(g)) -> "P"_ 4"O"_ (10(s))#</mathjax></p> </blockquote> <p>Now, your goal here will be to make sure that <strong>all the atoms</strong> that are present on the <em>reactants' side</em> are <strong>also present</strong> on the <em>products' side</em> of the reaction. </p> <p>The reactants' side contains </p> <blockquote> <ul> <li><em><strong>four atoms</strong> of phosphorus</em>, <mathjax>#4 xx "P"#</mathjax></li> <li><em><strong>two atoms</strong> of oxygen</em>, <mathjax>#2 xx "O"#</mathjax></li> </ul> </blockquote> <p>The products' side contains </p> <blockquote> <ul> <li><em><strong>four atoms</strong> of phosphorus</em>, <mathjax>#4 xx "P"#</mathjax></li> <li><em><strong>ten atoms</strong> of oxygen</em>, <mathjax>#10 xx "O"#</mathjax></li> </ul> </blockquote> <p>Notice that the atoms of phosphorus are already balanced, since you have four on each side of the chemical equation. The atoms of oxygen, on the other hand, are <em>not</em> balanced. </p> <p>To balance the atoms of oxygen, multiply the oxygen molecule by <mathjax>#color(blue)(5)#</mathjax>. This will ensure that you get </p> <blockquote> <p><mathjax>#2 xx color(blue)(5) = "10 atoms of O"#</mathjax></p> </blockquote> <p>on the reactants' side of the equation. You will thus have</p> <blockquote> <p><mathjax>#color(green)(\|bar(ul(color(white)(a/a)color(black)("P"_ (4(s)) + color(blue)(5)"O"_ (2(g)) -> "P"_ 4"O"_ (10(s)))color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The chemical equation is now <em><strong>balanced</strong></em>, since you have equal numbers of atoms of each element on both sides of the equation. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"P"_ (4(s)) + 5"O"_ (2(g)) -> "P"_ 4"O"_ (10(s))#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The problem provides you with the <strong>reactants</strong>, which are said to be </p> <blockquote> <ul> <li><em><strong>white phosphorus</strong></em>, <mathjax>#"P"_ (4(s))#</mathjax></li> <li><em><strong>oxygen gas</strong></em>, <mathjax>#"O"_ (2(g))#</mathjax></li> </ul> </blockquote> <p>and with the <strong>product</strong>, which is said to be </p> <blockquote> <ul> <li><em><strong>diphosphorus pentoxide</strong>, also called phosphorus(V) oxide</em>, <mathjax>#"P"_ 4"O"_ (10(s))#</mathjax></li> </ul> </blockquote> <p>which means that you have all the information you need to write the <em>unbalanced</em> chemical equation</p> <blockquote> <p><mathjax>#"P"_ (4(s)) + "O"_ (2(g)) -> "P"_ 4"O"_ (10(s))#</mathjax></p> </blockquote> <p>Now, your goal here will be to make sure that <strong>all the atoms</strong> that are present on the <em>reactants' side</em> are <strong>also present</strong> on the <em>products' side</em> of the reaction. </p> <p>The reactants' side contains </p> <blockquote> <ul> <li><em><strong>four atoms</strong> of phosphorus</em>, <mathjax>#4 xx "P"#</mathjax></li> <li><em><strong>two atoms</strong> of oxygen</em>, <mathjax>#2 xx "O"#</mathjax></li> </ul> </blockquote> <p>The products' side contains </p> <blockquote> <ul> <li><em><strong>four atoms</strong> of phosphorus</em>, <mathjax>#4 xx "P"#</mathjax></li> <li><em><strong>ten atoms</strong> of oxygen</em>, <mathjax>#10 xx "O"#</mathjax></li> </ul> </blockquote> <p>Notice that the atoms of phosphorus are already balanced, since you have four on each side of the chemical equation. The atoms of oxygen, on the other hand, are <em>not</em> balanced. </p> <p>To balance the atoms of oxygen, multiply the oxygen molecule by <mathjax>#color(blue)(5)#</mathjax>. This will ensure that you get </p> <blockquote> <p><mathjax>#2 xx color(blue)(5) = "10 atoms of O"#</mathjax></p> </blockquote> <p>on the reactants' side of the equation. You will thus have</p> <blockquote> <p><mathjax>#color(green)(\|bar(ul(color(white)(a/a)color(black)("P"_ (4(s)) + color(blue)(5)"O"_ (2(g)) -> "P"_ 4"O"_ (10(s)))color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The chemical equation is now <em><strong>balanced</strong></em>, since you have equal numbers of atoms of each element on both sides of the equation. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How would you balance the reaction of white phosphorous (#P_4#) with oxygen (#O_2#) which produces phosphorous oxide (#P_4O_10#)?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="292013" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-26T00:38:50" itemprop="dateCreated"> Jul 26, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"P"_ (4(s)) + 5"O"_ (2(g)) -> "P"_ 4"O"_ (10(s))#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The problem provides you with the <strong>reactants</strong>, which are said to be </p> <blockquote> <ul> <li><em><strong>white phosphorus</strong></em>, <mathjax>#"P"_ (4(s))#</mathjax></li> <li><em><strong>oxygen gas</strong></em>, <mathjax>#"O"_ (2(g))#</mathjax></li> </ul> </blockquote> <p>and with the <strong>product</strong>, which is said to be </p> <blockquote> <ul> <li><em><strong>diphosphorus pentoxide</strong>, also called phosphorus(V) oxide</em>, <mathjax>#"P"_ 4"O"_ (10(s))#</mathjax></li> </ul> </blockquote> <p>which means that you have all the information you need to write the <em>unbalanced</em> chemical equation</p> <blockquote> <p><mathjax>#"P"_ (4(s)) + "O"_ (2(g)) -> "P"_ 4"O"_ (10(s))#</mathjax></p> </blockquote> <p>Now, your goal here will be to make sure that <strong>all the atoms</strong> that are present on the <em>reactants' side</em> are <strong>also present</strong> on the <em>products' side</em> of the reaction. </p> <p>The reactants' side contains </p> <blockquote> <ul> <li><em><strong>four atoms</strong> of phosphorus</em>, <mathjax>#4 xx "P"#</mathjax></li> <li><em><strong>two atoms</strong> of oxygen</em>, <mathjax>#2 xx "O"#</mathjax></li> </ul> </blockquote> <p>The products' side contains </p> <blockquote> <ul> <li><em><strong>four atoms</strong> of phosphorus</em>, <mathjax>#4 xx "P"#</mathjax></li> <li><em><strong>ten atoms</strong> of oxygen</em>, <mathjax>#10 xx "O"#</mathjax></li> </ul> </blockquote> <p>Notice that the atoms of phosphorus are already balanced, since you have four on each side of the chemical equation. The atoms of oxygen, on the other hand, are <em>not</em> balanced. </p> <p>To balance the atoms of oxygen, multiply the oxygen molecule by <mathjax>#color(blue)(5)#</mathjax>. This will ensure that you get </p> <blockquote> <p><mathjax>#2 xx color(blue)(5) = "10 atoms of O"#</mathjax></p> </blockquote> <p>on the reactants' side of the equation. You will thus have</p> <blockquote> <p><mathjax>#color(green)(\|bar(ul(color(white)(a/a)color(black)("P"_ (4(s)) + color(blue)(5)"O"_ (2(g)) -> "P"_ 4"O"_ (10(s)))color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The chemical equation is now <em><strong>balanced</strong></em>, since you have equal numbers of atoms of each element on both sides of the equation. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/292013" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------> H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -> Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? 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1,564	ab32bd01-6ddd-11ea-9c19-ccda262736ce	https://socratic.org/questions/how-many-moles-of-nh-3-are-there-in-77-5-g-of-nh-3	4.55 moles	start physical_unit 4 4 mole mol qc_end physical_unit 4 4 8 9 mass qc_end end	[{"type":"physical unit","value":"Mole [OF] NH3 [IN] moles"}]	[{"type":"physical unit","value":"4.55 moles"}]	[{"type":"physical unit","value":"Mass [OF] NH3 [=] \\pu{77.5 g}"}]	<h1 class="questionTitle" itemprop="name"> How many moles of #NH_3# are there in 77.5 g of #NH_3#?</h1>	null	4.55 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Divide the given mass of <mathjax>#"NH"_3"#</mathjax> by its molar mass.</p> <p>Molar mass of <mathjax>#"NH"_3":#</mathjax><mathjax>#"17.03052 g/mol"#</mathjax><a href="http://pubchem.ncbi.nlm.nih.gov/compound/222#section=Top" rel="nofollow" target="_blank">http://pubchem.ncbi.nlm.nih.gov/compound/222#section=Top</a></p> <p><mathjax>#(77.5cancel"g NH"_3)xx(1"mol NH"_3)/(17.03052cancel"g NH"_3)="4.55 mol NH"_3""#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>There are <mathjax>#"4.55 moles"#</mathjax> in <mathjax>#"77.5 g NH"_3"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Divide the given mass of <mathjax>#"NH"_3"#</mathjax> by its molar mass.</p> <p>Molar mass of <mathjax>#"NH"_3":#</mathjax><mathjax>#"17.03052 g/mol"#</mathjax><a href="http://pubchem.ncbi.nlm.nih.gov/compound/222#section=Top" rel="nofollow" target="_blank">http://pubchem.ncbi.nlm.nih.gov/compound/222#section=Top</a></p> <p><mathjax>#(77.5cancel"g NH"_3)xx(1"mol NH"_3)/(17.03052cancel"g NH"_3)="4.55 mol NH"_3""#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name"> How many moles of #NH_3# are there in 77.5 g of #NH_3#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="198664" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-11T09:07:58" itemprop="dateCreated"> Dec 11, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>There are <mathjax>#"4.55 moles"#</mathjax> in <mathjax>#"77.5 g NH"_3"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Divide the given mass of <mathjax>#"NH"_3"#</mathjax> by its molar mass.</p> <p>Molar mass of <mathjax>#"NH"_3":#</mathjax><mathjax>#"17.03052 g/mol"#</mathjax><a href="http://pubchem.ncbi.nlm.nih.gov/compound/222#section=Top" rel="nofollow" target="_blank">http://pubchem.ncbi.nlm.nih.gov/compound/222#section=Top</a></p> <p><mathjax>#(77.5cancel"g NH"_3)xx(1"mol NH"_3)/(17.03052cancel"g NH"_3)="4.55 mol NH"_3""#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/198664" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? 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1,565	ac14f63d-6ddd-11ea-b784-ccda262736ce	https://socratic.org/questions/what-is-the-empirical-formula-of-c-4h-8o-2	C2H4O	start chemical_formula qc_end chemical_equation 6 6 qc_end end	[{"type":"other","value":"Chemical Formula [OF] C4H8O2 [IN] empirical"}]	[{"type":"chemical equation","value":"C2H4O"}]	[{"type":"chemical equation","value":"C4H8O2"}]	<h1 class="questionTitle" itemprop="name">What is the empirical formula of #C_4H_8O_2#?</h1>	null	C2H4O	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Now I was able to do that even without a calculator and without a second thought. Why?</p> <p>I will one day get sick of saying this, but the empirical formula is the simplest whole number ratio that defines constituent atoms in a species. The molecular formula is ALWAYS a multiple of the empirical formula. Of course, the multiple MAY be ONE.</p> <p>The empirical formula is what we find by experiment. Normally we have to take the empirical formula and compare it to a measured molecular mass in order to calculate the multiple, and thus the molecular formula. We have the cart before the horse here, but assignment of molecular formula is straightforward. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_2H_4O#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Now I was able to do that even without a calculator and without a second thought. Why?</p> <p>I will one day get sick of saying this, but the empirical formula is the simplest whole number ratio that defines constituent atoms in a species. The molecular formula is ALWAYS a multiple of the empirical formula. Of course, the multiple MAY be ONE.</p> <p>The empirical formula is what we find by experiment. Normally we have to take the empirical formula and compare it to a measured molecular mass in order to calculate the multiple, and thus the molecular formula. We have the cart before the horse here, but assignment of molecular formula is straightforward. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the empirical formula of #C_4H_8O_2#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="284475" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-04T04:10:08" itemprop="dateCreated"> Jul 4, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_2H_4O#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Now I was able to do that even without a calculator and without a second thought. Why?</p> <p>I will one day get sick of saying this, but the empirical formula is the simplest whole number ratio that defines constituent atoms in a species. The molecular formula is ALWAYS a multiple of the empirical formula. Of course, the multiple MAY be ONE.</p> <p>The empirical formula is what we find by experiment. Normally we have to take the empirical formula and compare it to a measured molecular mass in order to calculate the multiple, and thus the molecular formula. We have the cart before the horse here, but assignment of molecular formula is straightforward. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/284475" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molecular-formula-of-a-compound"> How do you find molecular formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-diamond"> What is the chemical formula of a diamond? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-carbohydrate"> What is the chemical formula of a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-valproic-acid"> What is the empirical formula for valproic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-of-magnesium-oxide"> What is the empirical formula of magnesium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-empirical-formula-not-double-that-of-the-monosaccharides"> Why is the empirical formula not double that of the monosaccharides? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5331180502bf342f40b5c3b5"> Question #5c3b5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-molecular-formula-represents-a-carbohydrate"> What molecular formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-of-vinegar"> What is the molecular formula of vinegar? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/empirical-and-molecular-formulas"> See all questions in Empirical and Molecular Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2833 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the empirical formula of #C_4H_8O_2#?	null
1,566	aac0db1e-6ddd-11ea-b585-ccda262736ce	https://socratic.org/questions/a-certain-sugar-has-a-chemical-composition-of-40-carbon-6-6-hydrogen-and-53-3-pe	C6H12O6	start chemical_formula qc_end physical_unit 2 2 19 20 molar_mass qc_end end	[{"type":"other","value":"Chemical Formula [OF] the sugar [IN] molecular"}]	[{"type":"chemical equation","value":"C6H12O6"}]	[{"type":"physical unit","value":"Percentage [OF] carbon in the sugar [=] \\pu{40 % carbon}"},{"type":"physical unit","value":"Percentage [OF] hydrogen in the sugar [=] \\pu{6.6%}"},{"type":"physical unit","value":"Percentage [OF] oxygen in the sugar [=] \\pu{53.3 percent}"},{"type":"physical unit","value":"Molar mass [OF] the sugar [=] \\pu{180 g/mol}"}]	<h1 class="questionTitle" itemprop="name">A certain sugar has a chemical composition of 40 % carbon, 6.6 % hydrogen, and 53.3 percent oxygen. The molar mass is 180 g/mol. What is the molecular formula?</h1>	null	C6H12O6	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We assume 100 g of unknown. In such quantity there are: </p> <p><mathjax>#((40g) /(12.01gmol^-1))C#</mathjax>; <mathjax>#((6.6g) /(1.00794gmol^-1))H#</mathjax>; and <mathjax>#((53.3g) /(15.99gmol^-1))O#</mathjax>.</p> <p>Note that I divide thru by the ATOMIC masses of each component.</p> <p>I gets the ratio: <mathjax>#3.33:6.55:3.33#</mathjax>. Now I divide thru by the lowest quotient to give <mathjax>#C_nH_mO_o#</mathjax> <mathjax>#=#</mathjax> <mathjax>#CH_2O#</mathjax>.</p> <p><mathjax>#CH_2O#</mathjax> is the simplest whole number ratio defining constituent atoms in a species; that is, the empirical formula, the formula found by experiment. </p> <p>Now it is a fact that while the empirical formula may NOT be the same as the molecular formula, the molecular formula is ALWAYS a multiple of the empirical formula.</p> <p>So, <mathjax>#MF#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(EF)_n#</mathjax>. But we have been given a molecular mass!</p> <p>And <mathjax>#180gmol^-1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(CH_2O)_n#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(30g*mol^-1)_n#</mathjax>.</p> <p>Clearly, <mathjax>#n#</mathjax> <mathjax>#=#</mathjax> <mathjax>#6#</mathjax>. And molecular formula <mathjax>#=#</mathjax> <mathjax>#C_6H_12O_6#</mathjax>, which is probably the stuff you sprinkle on your cornflakes.</p> <p>Normally, you would not be given the percentage composition of oxygen (because oxygen content can rarely be measured!). A more advanced question would have given percentage compositions of <mathjax>#H#</mathjax> and <mathjax>#C#</mathjax>, and left you to figure out the percentage balance was oxygen content.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_6H_12O_6#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We assume 100 g of unknown. In such quantity there are: </p> <p><mathjax>#((40g) /(12.01gmol^-1))C#</mathjax>; <mathjax>#((6.6g) /(1.00794gmol^-1))H#</mathjax>; and <mathjax>#((53.3g) /(15.99gmol^-1))O#</mathjax>.</p> <p>Note that I divide thru by the ATOMIC masses of each component.</p> <p>I gets the ratio: <mathjax>#3.33:6.55:3.33#</mathjax>. Now I divide thru by the lowest quotient to give <mathjax>#C_nH_mO_o#</mathjax> <mathjax>#=#</mathjax> <mathjax>#CH_2O#</mathjax>.</p> <p><mathjax>#CH_2O#</mathjax> is the simplest whole number ratio defining constituent atoms in a species; that is, the empirical formula, the formula found by experiment. </p> <p>Now it is a fact that while the empirical formula may NOT be the same as the molecular formula, the molecular formula is ALWAYS a multiple of the empirical formula.</p> <p>So, <mathjax>#MF#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(EF)_n#</mathjax>. But we have been given a molecular mass!</p> <p>And <mathjax>#180gmol^-1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(CH_2O)_n#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(30g*mol^-1)_n#</mathjax>.</p> <p>Clearly, <mathjax>#n#</mathjax> <mathjax>#=#</mathjax> <mathjax>#6#</mathjax>. And molecular formula <mathjax>#=#</mathjax> <mathjax>#C_6H_12O_6#</mathjax>, which is probably the stuff you sprinkle on your cornflakes.</p> <p>Normally, you would not be given the percentage composition of oxygen (because oxygen content can rarely be measured!). A more advanced question would have given percentage compositions of <mathjax>#H#</mathjax> and <mathjax>#C#</mathjax>, and left you to figure out the percentage balance was oxygen content.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A certain sugar has a chemical composition of 40 % carbon, 6.6 % hydrogen, and 53.3 percent oxygen. The molar mass is 180 g/mol. What is the molecular formula?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="196214" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-04T08:44:49" itemprop="dateCreated"> Dec 4, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_6H_12O_6#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We assume 100 g of unknown. In such quantity there are: </p> <p><mathjax>#((40g) /(12.01gmol^-1))C#</mathjax>; <mathjax>#((6.6g) /(1.00794gmol^-1))H#</mathjax>; and <mathjax>#((53.3g) /(15.99gmol^-1))O#</mathjax>.</p> <p>Note that I divide thru by the ATOMIC masses of each component.</p> <p>I gets the ratio: <mathjax>#3.33:6.55:3.33#</mathjax>. Now I divide thru by the lowest quotient to give <mathjax>#C_nH_mO_o#</mathjax> <mathjax>#=#</mathjax> <mathjax>#CH_2O#</mathjax>.</p> <p><mathjax>#CH_2O#</mathjax> is the simplest whole number ratio defining constituent atoms in a species; that is, the empirical formula, the formula found by experiment. </p> <p>Now it is a fact that while the empirical formula may NOT be the same as the molecular formula, the molecular formula is ALWAYS a multiple of the empirical formula.</p> <p>So, <mathjax>#MF#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(EF)_n#</mathjax>. But we have been given a molecular mass!</p> <p>And <mathjax>#180gmol^-1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(CH_2O)_n#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(30g*mol^-1)_n#</mathjax>.</p> <p>Clearly, <mathjax>#n#</mathjax> <mathjax>#=#</mathjax> <mathjax>#6#</mathjax>. And molecular formula <mathjax>#=#</mathjax> <mathjax>#C_6H_12O_6#</mathjax>, which is probably the stuff you sprinkle on your cornflakes.</p> <p>Normally, you would not be given the percentage composition of oxygen (because oxygen content can rarely be measured!). A more advanced question would have given percentage compositions of <mathjax>#H#</mathjax> and <mathjax>#C#</mathjax>, and left you to figure out the percentage balance was oxygen content.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/196214" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molecular-formula-of-a-compound"> How do you find molecular formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-diamond"> What is the chemical formula of a diamond? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-carbohydrate"> What is the chemical formula of a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-valproic-acid"> What is the empirical formula for valproic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-of-magnesium-oxide"> What is the empirical formula of magnesium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-empirical-formula-not-double-that-of-the-monosaccharides"> Why is the empirical formula not double that of the monosaccharides? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5331180502bf342f40b5c3b5"> Question #5c3b5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-molecular-formula-represents-a-carbohydrate"> What molecular formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-of-vinegar"> What is the molecular formula of vinegar? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/empirical-and-molecular-formulas"> See all questions in Empirical and Molecular Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 11493 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A certain sugar has a chemical composition of 40 % carbon, 6.6 % hydrogen, and 53.3 percent oxygen. The molar mass is 180 g/mol. What is the molecular formula?	null
1,567	aae763d3-6ddd-11ea-a8d8-ccda262736ce	https://socratic.org/questions/if-you-need-to-make-a-5-6-solution-of-nacl-using-9-6g-of-nacl-how-many-grams-of-	171.43 grams	start physical_unit 19 19 mass g qc_end physical_unit 9 9 6 6 percent qc_end physical_unit 9 9 11 12 mass qc_end end	[{"type":"physical unit","value":"Mass [OF] water [IN] grams"}]	[{"type":"physical unit","value":"171.43 grams"}]	[{"type":"physical unit","value":"Percentage [OF] NaCl in solution [=] \\pu{5.6%}"},{"type":"physical unit","value":"Mass [OF] NaCl [=] \\pu{9.6 g}"}]	<h1 class="questionTitle" itemprop="name">If you need to make a 5.6% solution of #NaCl# using 9.6g of #NaCl#, how many grams of water is needed?</h1>	null	171.43 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Mass of sodium chloride"/"Mass of solution"xx100% = 5.6%#</mathjax></p> <p>So <mathjax>#(9.6g)/"Mass of solution"= 0.056#</mathjax></p> <p>So <mathjax>#(9.6g)/(0.056) ="Mass of solution"= 171.4g#</mathjax></p> <p>Of course the mass of solution includes the <mathjax>#9.6g#</mathjax> mass of sodium chloride. So we require <mathjax>#171.4g-9,6g" of water"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#161.8*g#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#161.8g#</mathjax> of water is required. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Mass of sodium chloride"/"Mass of solution"xx100% = 5.6%#</mathjax></p> <p>So <mathjax>#(9.6g)/"Mass of solution"= 0.056#</mathjax></p> <p>So <mathjax>#(9.6g)/(0.056) ="Mass of solution"= 171.4g#</mathjax></p> <p>Of course the mass of solution includes the <mathjax>#9.6g#</mathjax> mass of sodium chloride. So we require <mathjax>#171.4g-9,6g" of water"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#161.8g#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">If you need to make a 5.6% solution of #NaCl# using 9.6g of #NaCl#, how many grams of water is needed?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/percent-concentration" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Concentration</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="259262" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-04-27T05:08:04" itemprop="dateCreated"> Apr 27, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#161.8g#</mathjax> of water is required. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Mass of sodium chloride"/"Mass of solution"xx100% = 5.6%#</mathjax></p> <p>So <mathjax>#(9.6g)/"Mass of solution"= 0.056#</mathjax></p> <p>So <mathjax>#(9.6g)/(0.056) ="Mass of solution"= 171.4g#</mathjax></p> <p>Of course the mass of solution includes the <mathjax>#9.6g#</mathjax> mass of sodium chloride. So we require <mathjax>#171.4g-9,6g" of water"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#161.8g#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/259262" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-concentration-of-water-in-solution-be-decreased"> How can the concentration of water in solution be decreased? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-concentration-of-a-solution-be-increased"> How can the concentration of a solution be increased? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-concentration-of-a-solution-in-ppm"> How do you find the concentration of a solution in ppm? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-make-a-10-percent-solution"> How do you make a 10 percent solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-make-a-2-percent-solution"> How do you make a 2 percent solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-weight-per-volume-method-to-calculate-concentration"> What is the weight per volume method to calculate concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-percent-concentration-of-kcl-would-be-isotonic"> What percent concentration of KCl would be isotonic? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-of-sodium-chloride-in-normal-saline"> What is the percent concentration of sodium chloride in normal saline? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-of-a-6m-solution-of-nacl"> What is the percent concentration of a 6m solution of NaCl? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-formula"> What is the percent concentration formula? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/percent-concentration"> See all questions in Percent Concentration </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1672 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	If you need to make a 5.6% solution of #NaCl# using 9.6g of #NaCl#, how many grams of water is needed?	null
1,568	aca3d7ac-6ddd-11ea-8433-ccda262736ce	https://socratic.org/questions/what-is-the-mass-of-4-49-10-25-particles-of-hcl	2721.44 g	start physical_unit 10 10 mass g qc_end end	[{"type":"physical unit","value":"Mass [OF] HCl [IN] g"}]	[{"type":"physical unit","value":"2721.44 g"}]	[{"type":"physical unit","value":"Number [OF] HCl particles [=] \\pu{4.49 × 10^25}"}]	<h1 class="questionTitle" itemprop="name">What is the mass of #4.49*10^25# particles of #HCl#?</h1>	null	2721.44 g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>It is a fact that <mathjax>#6.022xx10^23#</mathjax> individual <mathjax>#HCl#</mathjax> particles have a mass of <mathjax>#36.5#</mathjax> <mathjax>#g#</mathjax>. This is simply another way of saying that the molar mass of <mathjax>#HCl#</mathjax>, the mass of <mathjax>#"Avogadro's Number"#</mathjax> of <mathjax>#HCl#</mathjax> particles, is <mathjax>#36.5gmol^-1#</mathjax>.</p> <p>So, all we have to do is divide the given number by Avogadro's number to get the number of moles, and then multiply this number by the molar mass:</p> <p><mathjax>#"Number of HCl particles"/"Number of HCl particles per mol"#</mathjax> <mathjax>#xx36.5gmol^-1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(4.49xx10^25)/(6.022xx10^23)#</mathjax> <mathjax>#xx#</mathjax> <mathjax>#36.5*g#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax> <mathjax>#g#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Number of HCl particles"/"Number of HCl particles per mol"#</mathjax> <mathjax>#xx36.5gmol^-1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>It is a fact that <mathjax>#6.022xx10^23#</mathjax> individual <mathjax>#HCl#</mathjax> particles have a mass of <mathjax>#36.5#</mathjax> <mathjax>#g#</mathjax>. This is simply another way of saying that the molar mass of <mathjax>#HCl#</mathjax>, the mass of <mathjax>#"Avogadro's Number"#</mathjax> of <mathjax>#HCl#</mathjax> particles, is <mathjax>#36.5gmol^-1#</mathjax>.</p> <p>So, all we have to do is divide the given number by Avogadro's number to get the number of moles, and then multiply this number by the molar mass:</p> <p><mathjax>#"Number of HCl particles"/"Number of HCl particles per mol"#</mathjax> <mathjax>#xx36.5gmol^-1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(4.49xx10^25)/(6.022xx10^23)#</mathjax> <mathjax>#xx#</mathjax> <mathjax>#36.5*g#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax> <mathjax>#g#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the mass of #4.4910^25# particles of #HCl#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="236676" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-08T06:44:14" itemprop="dateCreated"> Mar 8, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Number of HCl particles"/"Number of HCl particles per mol"#</mathjax> <mathjax>#xx36.5gmol^-1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>It is a fact that <mathjax>#6.022xx10^23#</mathjax> individual <mathjax>#HCl#</mathjax> particles have a mass of <mathjax>#36.5#</mathjax> <mathjax>#g#</mathjax>. This is simply another way of saying that the molar mass of <mathjax>#HCl#</mathjax>, the mass of <mathjax>#"Avogadro's Number"#</mathjax> of <mathjax>#HCl#</mathjax> particles, is <mathjax>#36.5gmol^-1#</mathjax>.</p> <p>So, all we have to do is divide the given number by Avogadro's number to get the number of moles, and then multiply this number by the molar mass:</p> <p><mathjax>#"Number of HCl particles"/"Number of HCl particles per mol"#</mathjax> <mathjax>#xx36.5gmol^-1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(4.49xx10^25)/(6.022xx10^23)#</mathjax> <mathjax>#xx#</mathjax> <mathjax>#36.5g#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax> <mathjax>#g#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/236676" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1845 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the mass of #4.49*10^25# particles of #HCl#?	null
1,569	a95ed5f6-6ddd-11ea-b430-ccda262736ce	https://socratic.org/questions/58a3ec3211ef6b2a4c026c38	0.59 grams	start physical_unit 4 4 mass g qc_end end	[{"type":"physical unit","value":"Mass [OF] salt [IN] grams"}]	[{"type":"physical unit","value":"0.59 grams"}]	[{"type":"physical unit","value":"Mass [OF] chlorine gas [=] \\pu{335 mg}"}]	<h1 class="questionTitle" itemprop="name">How many grams of salt are required to produce a #355*mg# mass of chlorine gas?</h1>	null	0.59 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#NaCl(s) rarr Na(s) + 1/2Cl_2(g)#</mathjax>.</p> <p>We require <mathjax>#(0.355g)/(70.90gmol^-1)=0.00500mol#</mathjax>.</p> <p>Given the <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>, we require at least <mathjax>#0.0100mol#</mathjax> salt, i.e. <mathjax>#0.0100molxx58.44gmol^-1=0.585*g#</mathjax>.</p> <p>This would not be a terribly efficient way to produce chlorine gas.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Of chlorine gas, <mathjax>#Cl_2#</mathjax>..........?</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#NaCl(s) rarr Na(s) + 1/2Cl_2(g)#</mathjax>.</p> <p>We require <mathjax>#(0.355g)/(70.90gmol^-1)=0.00500mol#</mathjax>.</p> <p>Given the <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>, we require at least <mathjax>#0.0100mol#</mathjax> salt, i.e. <mathjax>#0.0100molxx58.44gmol^-1=0.585*g#</mathjax>.</p> <p>This would not be a terribly efficient way to produce chlorine gas.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many grams of salt are required to produce a #355mg# mass of chlorine gas?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="378057" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-02-15T06:18:19" itemprop="dateCreated"> Feb 15, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Of chlorine gas, <mathjax>#Cl_2#</mathjax>..........?</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#NaCl(s) rarr Na(s) + 1/2Cl_2(g)#</mathjax>.</p> <p>We require <mathjax>#(0.355g)/(70.90gmol^-1)=0.00500mol#</mathjax>.</p> <p>Given the <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>, we require at least <mathjax>#0.0100mol#</mathjax> salt, i.e. <mathjax>#0.0100molxx58.44gmol^-1=0.585g#</mathjax>.</p> <p>This would not be a terribly efficient way to produce chlorine gas.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/378057" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? 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1,570	a9401a18-6ddd-11ea-a1a6-ccda262736ce	https://socratic.org/questions/what-is-the-volume-of-a-container-that-holds-9-67-moles-of-oxygen-gas-at-100-c-a	227.79 L	start physical_unit 6 6 volume l qc_end physical_unit 12 13 9 10 mole qc_end physical_unit 12 13 15 16 temperature qc_end physical_unit 12 13 18 19 pressure qc_end end	[{"type":"physical unit","value":"Volume [OF] container [IN] L"}]	[{"type":"physical unit","value":"227.79 L"}]	[{"type":"physical unit","value":"Mole [OF] oxygen gas [=] \\pu{9.67 moles}"},{"type":"physical unit","value":"Temperature [OF] oxygen gas [=] \\pu{100 ℃}"},{"type":"physical unit","value":"Pressure [OF] oxygen gas [=] \\pu{1.30 atm}"}]	<h1 class="questionTitle" itemprop="name">What is the volume of a container that holds 9.67 moles of oxygen gas at 100°C and 1.30 atm pressure?</h1>	null	227.79 L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#V=(9.67molxx0.0821(Latm)/(Kmol)xx373K)/(1.30atm)#</mathjax>.</p> <p>What is the mass of the oxygen gas?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#V=(nRT)/P~=228L#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#V=(9.67molxx0.0821(Latm)/(Kmol)xx373K)/(1.30*atm)#</mathjax>.</p> <p>What is the mass of the oxygen gas?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the volume of a container that holds 9.67 moles of oxygen gas at 100°C and 1.30 atm pressure?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/ideal-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Ideal Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="374807" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-02-07T21:49:14" itemprop="dateCreated"> Feb 7, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#V=(nRT)/P~=228L#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#V=(9.67molxx0.0821(Latm)/(Kmol)xx373K)/(1.30*atm)#</mathjax>.</p> <p>What is the mass of the oxygen gas?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/374807" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-ideal-gas-constant"> How do you find the ideal gas constant? 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R = 8.314 kPa L / (K mol) =... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-molar-mass-of-a-gas"> How do you calculate the molar mass of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-should-i-use-the-ideal-gas-law-and-not-the-combined-gas-law"> When should I use the ideal gas law and not the combined gas law? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/ideal-gas-law"> See all questions in Ideal Gas Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1029 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the volume of a container that holds 9.67 moles of oxygen gas at 100°C and 1.30 atm pressure?	null
1,571	a8ac0290-6ddd-11ea-ac43-ccda262736ce	https://socratic.org/questions/how-many-moles-are-in-25-grams-of-water	1.39 moles	start physical_unit 8 8 mole mol qc_end physical_unit 8 8 5 6 mass qc_end end	[{"type":"physical unit","value":"Mole [OF] water [IN] moles"}]	[{"type":"physical unit","value":"1.39 moles"}]	[{"type":"physical unit","value":"Mass [OF] water [=] \\pu{25 grams}"}]	<h1 class="questionTitle" itemprop="name">How many moles are in 25 grams of water?</h1>	null	1.39 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Moles = Mass divided by molar mass, where molar mass of <mathjax>#H_2O#</mathjax> is <mathjax>#1+1+16=18g//mol#</mathjax>.</p> <p><mathjax>#n=m/(M_r)#</mathjax></p> <p><mathjax>#=25/18#</mathjax></p> <p><mathjax>#=1.389mol#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1.389mol#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Moles = Mass divided by molar mass, where molar mass of <mathjax>#H_2O#</mathjax> is <mathjax>#1+1+16=18g//mol#</mathjax>.</p> <p><mathjax>#n=m/(M_r)#</mathjax></p> <p><mathjax>#=25/18#</mathjax></p> <p><mathjax>#=1.389mol#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles are in 25 grams of water?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="205742" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/trevor-r-1"><img alt="" class="" src="https://profilepictures.socratic.org/2Wf9lLD9RaSzPbXY0EW8_S5002678.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/trevor-r-1"> Trevor Ryan. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-30T15:31:47" itemprop="dateCreated"> Dec 30, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1.389mol#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Moles = Mass divided by molar mass, where molar mass of <mathjax>#H_2O#</mathjax> is <mathjax>#1+1+16=18g//mol#</mathjax>.</p> <p><mathjax>#n=m/(M_r)#</mathjax></p> <p><mathjax>#=25/18#</mathjax></p> <p><mathjax>#=1.389mol#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/205742" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? 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1,572	ac4137d2-6ddd-11ea-bf5e-ccda262736ce	https://socratic.org/questions/what-is-the-oxidation-number-of-titanium-in-titanium-oxide	4	start physical_unit 6 6 oxidation_number none qc_end substance 8 9 qc_end end	[{"type":"physical unit","value":"Oxidation number [OF] titanium"}]	[{"type":"physical unit","value":"4"}]	[{"type":"substance name","value":"Titanium oxide"}]	<h1 class="questionTitle" itemprop="name">What is the oxidation number of titanium in titanium oxide? </h1>	null	4	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#TiO_2#</mathjax> is Titanium oxide, and <mathjax>#O#</mathjax> has an oxidation number of <mathjax>#-2#</mathjax> in this case, so <mathjax>#Ti#</mathjax>'s oxidation number would have to be <mathjax>#4#</mathjax> to make the molecule neutral. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#4#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#TiO_2#</mathjax> is Titanium oxide, and <mathjax>#O#</mathjax> has an oxidation number of <mathjax>#-2#</mathjax> in this case, so <mathjax>#Ti#</mathjax>'s oxidation number would have to be <mathjax>#4#</mathjax> to make the molecule neutral. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the oxidation number of titanium in titanium oxide? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#electrochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Electrochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/electrochemistry/oxidation-numbers" itemprop="url"> <span class="breadcrumb" itemprop="title">Oxidation Numbers</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="625494" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/rjsh"><img alt="" class="" src="https://profilepictures.socratic.org/HG7AXBKURJqe2lz1ijoI_0037.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/rjsh"> Daniel M </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-06-05T03:18:10" itemprop="dateCreated"> Jun 5, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#4#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#TiO_2#</mathjax> is Titanium oxide, and <mathjax>#O#</mathjax> has an oxidation number of <mathjax>#-2#</mathjax> in this case, so <mathjax>#Ti#</mathjax>'s oxidation number would have to be <mathjax>#4#</mathjax> to make the molecule neutral. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/625494" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-relate-to-electron-configuration"> How do oxidation numbers relate to electron configuration? 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1,573	ad1d14c6-6ddd-11ea-af99-ccda262736ce	https://socratic.org/questions/593172397c0149397db1a39e	N2O3	start chemical_formula qc_end physical_unit 13 13 10 11 volume qc_end c_other OTHER qc_end physical_unit 7 7 3 4 volume qc_end end	[{"type":"other","value":"Chemical Formula [OF] the nitrogen oxide [IN] default"}]	[{"type":"chemical equation","value":"N2O3"}]	[{"type":"physical unit","value":"Volume [OF] itrogen oxide [=] \\pu{10 mL}"},{"type":"physical unit","value":"Volume [OF] hydrogen [=] \\pu{30 ml}"},{"type":"other","value":"Reacts completely."},{"type":"physical unit","value":"Volume [OF] nitrogen [=] \\pu{10 mL}"}]	<h1 class="questionTitle" itemprop="name">A mixture containing 10 mL of a nitrogen oxide and 30 ml of hydrogen reacts completely to form 10 mL of nitrogen. What is the formula for the nitrogen oxide?</h1>	null	N2O3	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>Step 1. Summarize the information</strong></p> <p><mathjax>#color(white)(l)"N"_x"O"_y +color(white)(ll) "H"_2 → color(white)(m)"N"_2 + "H"_2"O"#</mathjax><br/> <mathjax>#"10 mL"color(white)(ml)"30 mL"color(white)(m)"10 mL"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 2. Assume that the reaction involves 1 mol of the compound</strong></p> <p>Then the partially balanced equation is</p> <p><mathjax>#"1N"_x"O"_y +"3H"_2 → "1N"_2 + "H"_2"O"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 3. Balance <mathjax>#"N"#</mathjax></strong></p> <p>We have 2 atoms of <mathjax>#"N"#</mathjax> on the right, so we need 2 atoms of <mathjax>#"N"#</mathjax> on the left.</p> <p>∴ <mathjax>#x= 2#</mathjax> and</p> <p><mathjax>#"N"_2"O"_y + "3H"_2 → "N"_2 + "H"_2"O"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 4. Balance <mathjax>#"H"#</mathjax></strong></p> <p>We have 6 <mathjax>#"H"#</mathjax> on the left, so we need 6 <mathjax>#"H"#</mathjax> on the right.</p> <p>Put a 3 in front of <mathjax>#"H"_2"O"#</mathjax>.</p> <p><mathjax>#"N"_2"O"_y + "3H"_2 → "N"_2 + "3H"_2"O"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 5. Balance <mathjax>#"O"#</mathjax></strong>.</p> <p>We have 3 <mathjax>#"O"#</mathjax> on the right, so we need 3 <mathjax>#"O"#</mathjax> on the left.</p> <p>∴ <mathjax>#y = 3#</mathjax> and</p> <p><mathjax>#"N"_2"O"_3 + "3H"_2 → "N"_2 + "3H"_2"O"#</mathjax></p> <p>The formula of the compound is <mathjax>#"N"_2"O"_3#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The molecular formula of the compound is <mathjax>#"N"_2"O"_3#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>Step 1. Summarize the information</strong></p> <p><mathjax>#color(white)(l)"N"_x"O"_y +color(white)(ll) "H"_2 → color(white)(m)"N"_2 + "H"_2"O"#</mathjax><br/> <mathjax>#"10 mL"color(white)(ml)"30 mL"color(white)(m)"10 mL"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 2. Assume that the reaction involves 1 mol of the compound</strong></p> <p>Then the partially balanced equation is</p> <p><mathjax>#"1N"_x"O"_y +"3H"_2 → "1N"_2 + "H"_2"O"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 3. Balance <mathjax>#"N"#</mathjax></strong></p> <p>We have 2 atoms of <mathjax>#"N"#</mathjax> on the right, so we need 2 atoms of <mathjax>#"N"#</mathjax> on the left.</p> <p>∴ <mathjax>#x= 2#</mathjax> and</p> <p><mathjax>#"N"_2"O"_y + "3H"_2 → "N"_2 + "H"_2"O"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 4. Balance <mathjax>#"H"#</mathjax></strong></p> <p>We have 6 <mathjax>#"H"#</mathjax> on the left, so we need 6 <mathjax>#"H"#</mathjax> on the right.</p> <p>Put a 3 in front of <mathjax>#"H"_2"O"#</mathjax>.</p> <p><mathjax>#"N"_2"O"_y + "3H"_2 → "N"_2 + "3H"_2"O"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 5. Balance <mathjax>#"O"#</mathjax></strong>.</p> <p>We have 3 <mathjax>#"O"#</mathjax> on the right, so we need 3 <mathjax>#"O"#</mathjax> on the left.</p> <p>∴ <mathjax>#y = 3#</mathjax> and</p> <p><mathjax>#"N"_2"O"_3 + "3H"_2 → "N"_2 + "3H"_2"O"#</mathjax></p> <p>The formula of the compound is <mathjax>#"N"_2"O"_3#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A mixture containing 10 mL of a nitrogen oxide and 30 ml of hydrogen reacts completely to form 10 mL of nitrogen. What is the formula for the nitrogen oxide?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/determining-formula-and-molar-masses" itemprop="url"> <span class="breadcrumb" itemprop="title">Determining Formula</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="433729" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-02T20:31:07" itemprop="dateCreated"> Jun 2, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The molecular formula of the compound is <mathjax>#"N"_2"O"_3#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>Step 1. Summarize the information</strong></p> <p><mathjax>#color(white)(l)"N"_x"O"_y +color(white)(ll) "H"_2 → color(white)(m)"N"_2 + "H"_2"O"#</mathjax><br/> <mathjax>#"10 mL"color(white)(ml)"30 mL"color(white)(m)"10 mL"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 2. Assume that the reaction involves 1 mol of the compound</strong></p> <p>Then the partially balanced equation is</p> <p><mathjax>#"1N"_x"O"_y +"3H"_2 → "1N"_2 + "H"_2"O"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 3. Balance <mathjax>#"N"#</mathjax></strong></p> <p>We have 2 atoms of <mathjax>#"N"#</mathjax> on the right, so we need 2 atoms of <mathjax>#"N"#</mathjax> on the left.</p> <p>∴ <mathjax>#x= 2#</mathjax> and</p> <p><mathjax>#"N"_2"O"_y + "3H"_2 → "N"_2 + "H"_2"O"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 4. Balance <mathjax>#"H"#</mathjax></strong></p> <p>We have 6 <mathjax>#"H"#</mathjax> on the left, so we need 6 <mathjax>#"H"#</mathjax> on the right.</p> <p>Put a 3 in front of <mathjax>#"H"_2"O"#</mathjax>.</p> <p><mathjax>#"N"_2"O"_y + "3H"_2 → "N"_2 + "3H"_2"O"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 5. Balance <mathjax>#"O"#</mathjax></strong>.</p> <p>We have 3 <mathjax>#"O"#</mathjax> on the right, so we need 3 <mathjax>#"O"#</mathjax> on the left.</p> <p>∴ <mathjax>#y = 3#</mathjax> and</p> <p><mathjax>#"N"_2"O"_3 + "3H"_2 → "N"_2 + "3H"_2"O"#</mathjax></p> <p>The formula of the compound is <mathjax>#"N"_2"O"_3#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/433729" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-it-possible-to-find-a-molecular-formula-from-molar-mass"> Is it possible to find a molecular formula from molar mass? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5368e0cc02bf34779e175781"> Question #75781 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-common-mistakes-students-make-when-determining-formulas"> What are some common mistakes students make when determining formulas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-formula-of-an-acid"> How can I determine the formula of an acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-chemical-formula-of-a-product"> How can I determine the chemical formula of a product? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-empirical-formula-of-a-compound"> How can I determine the empirical formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-formula-of-a-hydrate"> How can I determine the formula of a hydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-the-empirical-formula-indicate"> What does the empirical formula indicate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-molecule-with-molecular-weight-of-180-18-g-mol-is-analyzed-and-found-to-contai"> A molecule with molecular weight of 180.18 g/mol is analyzed and found to contain 40.00% carbon,... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/do-i-need-to-know-the-number-of-moles-of-each-element-to-determine-the-formula-o"> Do I need to know the number of moles of each element to determine the formula of the compound? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/determining-formula-and-molar-masses"> See all questions in Determining Formula </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2957 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A mixture containing 10 mL of a nitrogen oxide and 30 ml of hydrogen reacts completely to form 10 mL of nitrogen. What is the formula for the nitrogen oxide?	null
1,574	ac73e5ee-6ddd-11ea-86b3-ccda262736ce	https://socratic.org/questions/a-gas-occupies-volume-of-0-35dm3-at-290k-and-92-558k-nm-2-pressure-calculate-the	0.31 L	start physical_unit 1 1 volume l qc_end physical_unit 1 1 5 6 volume qc_end physical_unit 1 1 8 9 temperature qc_end physical_unit 1 1 11 12 pressure qc_end c_other STP qc_end end	[{"type":"physical unit","value":"Volume2 [OF] the gas [IN] L"}]	[{"type":"physical unit","value":"0.31 L"}]	[{"type":"physical unit","value":"Volume1 [OF] the gas [=] \\pu{0.35 dm3}"},{"type":"physical unit","value":"Temperature1 [OF] the gas [=] \\pu{290 K}"},{"type":"physical unit","value":"Pressure1 [OF] the gas [=] \\pu{92558 N/m^2}"},{"type":"other","value":"STP"}]	<h1 class="questionTitle" itemprop="name">A gas occupies volume of 0.35dm3 at 290K and 92.558K Nm-2 pressure. Calculate the volume of gas at STP?</h1>	null	0.31 L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The first thing to do is write out what the <strong>STP conditions</strong> are</p> <blockquote> <ul> <li><em>Pressure</em> - <mathjax>#"100 kPa"#</mathjax></li> <li><em>Temperature</em> - <mathjax>#0^@"C"#</mathjax></li> </ul> </blockquote> <p>SInce no mention about the number of moles of gas was made, you can assume that it remains <strong>constant</strong>. This means that you can use the <a href="http://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">combined gas law</a> to find the volume occupied by the gas at STP.</p> <p>If you're not familiar with the <a href="http://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">combined gas law</a>, you can derive it using the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a>. </p> <p>Notice that you will need to convert the pressure from <mathjax>#"kPa"#</mathjax> to <mathjax>#"N m"^(-2)#</mathjax> by using the conversion factor</p> <blockquote> <p><mathjax>#"1 Pa" = "1 N m"^(-2)#</mathjax></p> </blockquote> <p>So, let's say that for the initial state of the gas, you can write</p> <blockquote> <p><mathjax>#P_1 * V_1 = n * R * T_1#</mathjax></p> </blockquote> <p>For the second state of the gas, i.e. at STP, you can write</p> <blockquote> <p><mathjax>#P_2 * V_2 = n * R * T_2#</mathjax></p> </blockquote> <p>If you divide these two equations, you will get the combined gas law form </p> <blockquote> <p><mathjax>#(P_1V_1)/(P_2V_2) = (color(red)(cancel(color(black)(n * R))) * T_1)/(color(red)(cancel(color(black)(n * R))) * T_2) <=> (P_1V_1)/T_1 = (P_2V_2)/T_2#</mathjax></p> </blockquote> <p>Rearrange to solve for <mathjax>#V_2#</mathjax></p> <blockquote> <p><mathjax>#V_2 = P_1/P_2 * T_2/T_1 * V_1#</mathjax></p> </blockquote> <p>Plug in your values - don't forget about converting the temperature from degrees Celsius to Kelvin!</p> <blockquote> <p><mathjax>#V_2 = (92.558 * 10^3color(red)(cancel(color(black)("Nm"^(-2)))))/(100 * 10^3color(red)(cancel(color(black)("Nm"^(-2))))) * ((273.15 + 0)color(red)(cancel(color(black)("K"))))/(290color(red)(cancel(color(black)("K")))) * "0.35 dm"^3#</mathjax></p> <p><mathjax>#V_2 = "0.3051 dm"^3#</mathjax></p> </blockquote> <p>Rounded to two <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the number of sig figs you gave for the volume and temperatue of the gas, the answer will be </p> <blockquote> <p><mathjax>#V_2 = color(green)("0.31 dm"^3)#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"0.31 dm"^3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The first thing to do is write out what the <strong>STP conditions</strong> are</p> <blockquote> <ul> <li><em>Pressure</em> - <mathjax>#"100 kPa"#</mathjax></li> <li><em>Temperature</em> - <mathjax>#0^@"C"#</mathjax></li> </ul> </blockquote> <p>SInce no mention about the number of moles of gas was made, you can assume that it remains <strong>constant</strong>. This means that you can use the <a href="http://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">combined gas law</a> to find the volume occupied by the gas at STP.</p> <p>If you're not familiar with the <a href="http://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">combined gas law</a>, you can derive it using the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a>. </p> <p>Notice that you will need to convert the pressure from <mathjax>#"kPa"#</mathjax> to <mathjax>#"N m"^(-2)#</mathjax> by using the conversion factor</p> <blockquote> <p><mathjax>#"1 Pa" = "1 N m"^(-2)#</mathjax></p> </blockquote> <p>So, let's say that for the initial state of the gas, you can write</p> <blockquote> <p><mathjax>#P_1 * V_1 = n * R * T_1#</mathjax></p> </blockquote> <p>For the second state of the gas, i.e. at STP, you can write</p> <blockquote> <p><mathjax>#P_2 * V_2 = n * R * T_2#</mathjax></p> </blockquote> <p>If you divide these two equations, you will get the combined gas law form </p> <blockquote> <p><mathjax>#(P_1V_1)/(P_2V_2) = (color(red)(cancel(color(black)(n * R))) * T_1)/(color(red)(cancel(color(black)(n * R))) * T_2) <=> (P_1V_1)/T_1 = (P_2V_2)/T_2#</mathjax></p> </blockquote> <p>Rearrange to solve for <mathjax>#V_2#</mathjax></p> <blockquote> <p><mathjax>#V_2 = P_1/P_2 * T_2/T_1 * V_1#</mathjax></p> </blockquote> <p>Plug in your values - don't forget about converting the temperature from degrees Celsius to Kelvin!</p> <blockquote> <p><mathjax>#V_2 = (92.558 * 10^3color(red)(cancel(color(black)("Nm"^(-2)))))/(100 * 10^3color(red)(cancel(color(black)("Nm"^(-2))))) * ((273.15 + 0)color(red)(cancel(color(black)("K"))))/(290color(red)(cancel(color(black)("K")))) * "0.35 dm"^3#</mathjax></p> <p><mathjax>#V_2 = "0.3051 dm"^3#</mathjax></p> </blockquote> <p>Rounded to two <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the number of sig figs you gave for the volume and temperatue of the gas, the answer will be </p> <blockquote> <p><mathjax>#V_2 = color(green)("0.31 dm"^3)#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A gas occupies volume of 0.35dm3 at 290K and 92.558K Nm-2 pressure. Calculate the volume of gas at STP?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/combined-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Combined Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="177701" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-10-18T10:52:31" itemprop="dateCreated"> Oct 18, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"0.31 dm"^3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The first thing to do is write out what the <strong>STP conditions</strong> are</p> <blockquote> <ul> <li><em>Pressure</em> - <mathjax>#"100 kPa"#</mathjax></li> <li><em>Temperature</em> - <mathjax>#0^@"C"#</mathjax></li> </ul> </blockquote> <p>SInce no mention about the number of moles of gas was made, you can assume that it remains <strong>constant</strong>. This means that you can use the <a href="http://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">combined gas law</a> to find the volume occupied by the gas at STP.</p> <p>If you're not familiar with the <a href="http://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">combined gas law</a>, you can derive it using the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a>. </p> <p>Notice that you will need to convert the pressure from <mathjax>#"kPa"#</mathjax> to <mathjax>#"N m"^(-2)#</mathjax> by using the conversion factor</p> <blockquote> <p><mathjax>#"1 Pa" = "1 N m"^(-2)#</mathjax></p> </blockquote> <p>So, let's say that for the initial state of the gas, you can write</p> <blockquote> <p><mathjax>#P_1 * V_1 = n * R * T_1#</mathjax></p> </blockquote> <p>For the second state of the gas, i.e. at STP, you can write</p> <blockquote> <p><mathjax>#P_2 * V_2 = n * R * T_2#</mathjax></p> </blockquote> <p>If you divide these two equations, you will get the combined gas law form </p> <blockquote> <p><mathjax>#(P_1V_1)/(P_2V_2) = (color(red)(cancel(color(black)(n * R))) * T_1)/(color(red)(cancel(color(black)(n * R))) * T_2) <=> (P_1V_1)/T_1 = (P_2V_2)/T_2#</mathjax></p> </blockquote> <p>Rearrange to solve for <mathjax>#V_2#</mathjax></p> <blockquote> <p><mathjax>#V_2 = P_1/P_2 * T_2/T_1 * V_1#</mathjax></p> </blockquote> <p>Plug in your values - don't forget about converting the temperature from degrees Celsius to Kelvin!</p> <blockquote> <p><mathjax>#V_2 = (92.558 * 10^3color(red)(cancel(color(black)("Nm"^(-2)))))/(100 * 10^3color(red)(cancel(color(black)("Nm"^(-2))))) * ((273.15 + 0)color(red)(cancel(color(black)("K"))))/(290color(red)(cancel(color(black)("K")))) * "0.35 dm"^3#</mathjax></p> <p><mathjax>#V_2 = "0.3051 dm"^3#</mathjax></p> </blockquote> <p>Rounded to two <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the number of sig figs you gave for the volume and temperatue of the gas, the answer will be </p> <blockquote> <p><mathjax>#V_2 = color(green)("0.31 dm"^3)#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/177701" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5345df5f02bf345f71b1c8e8"> Question #1c8e8 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ac3df02bf342f4c3bfabb"> Question #bfabb </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-you-want-to-solve-for-the-volume-of-a-gas-v2-and-p1-is-greater-than-p2-would-"> If you want to solve for the volume of a gas (V2) and P1 is greater than P2, would you expect V2... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-modern-refrigerator-take-advantage-of-the-gas-laws-to-remove-heat-f"> How does the modern refrigerator take advantage of the gas laws to remove heat from a system? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-certain-sample-of-gas-has-a-volume-of-0-452-l-measured-at-87-c-and-0-620-atm-w"> A certain sample of gas has a volume of 0.452 L measured at 87°C and 0.620 atm. 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Calculate the volume of gas at STP?	null
1,575	a9f24406-6ddd-11ea-9ac8-ccda262736ce	https://socratic.org/questions/how-would-you-calculate-the-ph-of-a-substance-after-a-titration-of-10-19ml-0-10m	10.15	start physical_unit 7 8 ph none qc_end physical_unit 17 17 15 16 molarity qc_end physical_unit 23 23 21 22 molarity qc_end end	[{"type":"physical unit","value":"pH [OF] a substance"}]	[{"type":"physical unit","value":"10.15"}]	[{"type":"physical unit","value":"Volume [OF] HCl solution [=] \\pu{10.19 mL}"},{"type":"physical unit","value":"Molarity [OF] HCl solution [=] \\pu{0.10 M}"},{"type":"physical unit","value":"Volume [OF] NaOH solution [=] \\pu{10.99 mL}"},{"type":"physical unit","value":"Molarity [OF] NaOH solution [=] \\pu{0.093 M}"}]	<h1 class="questionTitle" itemprop="name">How would you calculate the pH of a substance after a titration of 10.19mL 0.10M HCl with 10.99mL 0.093M NaOH? </h1>	null	10.15	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You're mixing <em>hydrochloric acid</em>, <mathjax>#"HCl"#</mathjax>, a <strong>strong acid</strong>, and <em>sodium hydroxide</em>, <mathjax>#"NaOH"#</mathjax>, a <strong>strong base</strong>, which means that the <a href="http://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> of the resulting solution will depend on whether or not you're dealing with a <strong>complete <a href="http://socratic.org/chemistry/reactions-in-solution/neutralization">neutralization</a></strong>. </p> <p>The balanced chemical equation for this <a href="http://socratic.org/chemistry/reactions-in-solution/neutralization">neutralization</a> reaction looks like this </p> <blockquote> <p><mathjax>#"HCl"_text((aq]) + "NaOH"_text((aq]) -> "NaCl"_text((aq]) + "H"_2"O"_text((l])#</mathjax></p> </blockquote> <p>In order to have a <em>complete neutralization</em>, you need to add <strong>equal numbers of moles</strong> of strong acid and weak base. </p> <p>If you have <strong>more acid</strong> than base, the resulting solution will be <em>acidic</em>, since it will contain an excess of hydronium ions, <mathjax>#"H"_3"O"^(+)#</mathjax>. </p> <p>Likewise, if you have <strong>more base</strong> than acid, the resulting solution will be <em>basic</em>, since it will contain an excess of hydroxide anions, <mathjax>#"OH"^(-)#</mathjax>.</p> <p>Use the molarities and volumes of the two <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> to determine how many moles of each you;'re adding together</p> <blockquote> <p><mathjax>#color(blue)(c = n/V implies n = c * V)#</mathjax></p> <p><mathjax>#n_(HCl) = "0.10 M" * 10.19 * 10^(-3)"L" = "0.001019 moles HCl"#</mathjax></p> <p><mathjax>#n_(NaOH) = "0.093 M" * 10.99 * 10^(-3)"L" = "0.001022 moles NaOH"#</mathjax></p> </blockquote> <p>Notice that you have <em>more moles</em> of sodium hydroxide than you do of hydrochloric acid. This tells you that the reaction will <strong>completely consume</strong> the acid and leave you with</p> <blockquote> <p><mathjax>#n_(NaOH) = 0.001022 - 0.001019 = "0.0000030 moles NaOH"#</mathjax></p> </blockquote> <p>Sodium hydroxide dissociates completely in aqueous solution, so you can say that</p> <blockquote> <p><mathjax>#n_(OH^(-)) = n_(NaOH) = "0.0000030 moles OH"^(-)#</mathjax></p> </blockquote> <p>The <strong>total volume</strong> of the resulting solution will be </p> <blockquote> <p><mathjax>#V_"total" = "10.19 mL" + "10.99 mL" = "21.18 mL"#</mathjax></p> </blockquote> <p>The <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of the hydroxide anions will be </p> <blockquote> <p><mathjax>#c = "0.0000030 moles"/(21.18 * 10^(-3)"L") = 1.42 * 10^(-4)"M"#</mathjax></p> </blockquote> <p>As you know, a solution's pOH is equal to </p> <blockquote> <p><mathjax>#"pOH" = - log( ["OH"^(-)])#</mathjax></p> </blockquote> <p>In this case.</p> <blockquote> <p><mathjax>#"pOH" = - log(1.42 * 10^(-4)) = 3.85#</mathjax></p> </blockquote> <p>The pH of the solution will thus be </p> <blockquote> <p><mathjax>#"pH" + "pOH" = 14#</mathjax></p> <p><mathjax>#"pH" = 14 - 3.85 = color(green)(10.15)#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"pH" = 10.15#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You're mixing <em>hydrochloric acid</em>, <mathjax>#"HCl"#</mathjax>, a <strong>strong acid</strong>, and <em>sodium hydroxide</em>, <mathjax>#"NaOH"#</mathjax>, a <strong>strong base</strong>, which means that the <a href="http://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> of the resulting solution will depend on whether or not you're dealing with a <strong>complete <a href="http://socratic.org/chemistry/reactions-in-solution/neutralization">neutralization</a></strong>. </p> <p>The balanced chemical equation for this <a href="http://socratic.org/chemistry/reactions-in-solution/neutralization">neutralization</a> reaction looks like this </p> <blockquote> <p><mathjax>#"HCl"_text((aq]) + "NaOH"_text((aq]) -> "NaCl"_text((aq]) + "H"_2"O"_text((l])#</mathjax></p> </blockquote> <p>In order to have a <em>complete neutralization</em>, you need to add <strong>equal numbers of moles</strong> of strong acid and weak base. </p> <p>If you have <strong>more acid</strong> than base, the resulting solution will be <em>acidic</em>, since it will contain an excess of hydronium ions, <mathjax>#"H"_3"O"^(+)#</mathjax>. </p> <p>Likewise, if you have <strong>more base</strong> than acid, the resulting solution will be <em>basic</em>, since it will contain an excess of hydroxide anions, <mathjax>#"OH"^(-)#</mathjax>.</p> <p>Use the molarities and volumes of the two <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> to determine how many moles of each you;'re adding together</p> <blockquote> <p><mathjax>#color(blue)(c = n/V implies n = c * V)#</mathjax></p> <p><mathjax>#n_(HCl) = "0.10 M" * 10.19 * 10^(-3)"L" = "0.001019 moles HCl"#</mathjax></p> <p><mathjax>#n_(NaOH) = "0.093 M" * 10.99 * 10^(-3)"L" = "0.001022 moles NaOH"#</mathjax></p> </blockquote> <p>Notice that you have <em>more moles</em> of sodium hydroxide than you do of hydrochloric acid. This tells you that the reaction will <strong>completely consume</strong> the acid and leave you with</p> <blockquote> <p><mathjax>#n_(NaOH) = 0.001022 - 0.001019 = "0.0000030 moles NaOH"#</mathjax></p> </blockquote> <p>Sodium hydroxide dissociates completely in aqueous solution, so you can say that</p> <blockquote> <p><mathjax>#n_(OH^(-)) = n_(NaOH) = "0.0000030 moles OH"^(-)#</mathjax></p> </blockquote> <p>The <strong>total volume</strong> of the resulting solution will be </p> <blockquote> <p><mathjax>#V_"total" = "10.19 mL" + "10.99 mL" = "21.18 mL"#</mathjax></p> </blockquote> <p>The <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of the hydroxide anions will be </p> <blockquote> <p><mathjax>#c = "0.0000030 moles"/(21.18 * 10^(-3)"L") = 1.42 * 10^(-4)"M"#</mathjax></p> </blockquote> <p>As you know, a solution's pOH is equal to </p> <blockquote> <p><mathjax>#"pOH" = - log( ["OH"^(-)])#</mathjax></p> </blockquote> <p>In this case.</p> <blockquote> <p><mathjax>#"pOH" = - log(1.42 * 10^(-4)) = 3.85#</mathjax></p> </blockquote> <p>The pH of the solution will thus be </p> <blockquote> <p><mathjax>#"pH" + "pOH" = 14#</mathjax></p> <p><mathjax>#"pH" = 14 - 3.85 = color(green)(10.15)#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How would you calculate the pH of a substance after a titration of 10.19mL 0.10M HCl with 10.99mL 0.093M NaOH? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/the-ph-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">pH</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="201997" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-22T00:27:36" itemprop="dateCreated"> Dec 22, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"pH" = 10.15#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You're mixing <em>hydrochloric acid</em>, <mathjax>#"HCl"#</mathjax>, a <strong>strong acid</strong>, and <em>sodium hydroxide</em>, <mathjax>#"NaOH"#</mathjax>, a <strong>strong base</strong>, which means that the <a href="http://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> of the resulting solution will depend on whether or not you're dealing with a <strong>complete <a href="http://socratic.org/chemistry/reactions-in-solution/neutralization">neutralization</a></strong>. </p> <p>The balanced chemical equation for this <a href="http://socratic.org/chemistry/reactions-in-solution/neutralization">neutralization</a> reaction looks like this </p> <blockquote> <p><mathjax>#"HCl"_text((aq]) + "NaOH"_text((aq]) -> "NaCl"_text((aq]) + "H"_2"O"_text((l])#</mathjax></p> </blockquote> <p>In order to have a <em>complete neutralization</em>, you need to add <strong>equal numbers of moles</strong> of strong acid and weak base. </p> <p>If you have <strong>more acid</strong> than base, the resulting solution will be <em>acidic</em>, since it will contain an excess of hydronium ions, <mathjax>#"H"_3"O"^(+)#</mathjax>. </p> <p>Likewise, if you have <strong>more base</strong> than acid, the resulting solution will be <em>basic</em>, since it will contain an excess of hydroxide anions, <mathjax>#"OH"^(-)#</mathjax>.</p> <p>Use the molarities and volumes of the two <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> to determine how many moles of each you;'re adding together</p> <blockquote> <p><mathjax>#color(blue)(c = n/V implies n = c * V)#</mathjax></p> <p><mathjax>#n_(HCl) = "0.10 M" * 10.19 * 10^(-3)"L" = "0.001019 moles HCl"#</mathjax></p> <p><mathjax>#n_(NaOH) = "0.093 M" * 10.99 * 10^(-3)"L" = "0.001022 moles NaOH"#</mathjax></p> </blockquote> <p>Notice that you have <em>more moles</em> of sodium hydroxide than you do of hydrochloric acid. This tells you that the reaction will <strong>completely consume</strong> the acid and leave you with</p> <blockquote> <p><mathjax>#n_(NaOH) = 0.001022 - 0.001019 = "0.0000030 moles NaOH"#</mathjax></p> </blockquote> <p>Sodium hydroxide dissociates completely in aqueous solution, so you can say that</p> <blockquote> <p><mathjax>#n_(OH^(-)) = n_(NaOH) = "0.0000030 moles OH"^(-)#</mathjax></p> </blockquote> <p>The <strong>total volume</strong> of the resulting solution will be </p> <blockquote> <p><mathjax>#V_"total" = "10.19 mL" + "10.99 mL" = "21.18 mL"#</mathjax></p> </blockquote> <p>The <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of the hydroxide anions will be </p> <blockquote> <p><mathjax>#c = "0.0000030 moles"/(21.18 * 10^(-3)"L") = 1.42 * 10^(-4)"M"#</mathjax></p> </blockquote> <p>As you know, a solution's pOH is equal to </p> <blockquote> <p><mathjax>#"pOH" = - log( ["OH"^(-)])#</mathjax></p> </blockquote> <p>In this case.</p> <blockquote> <p><mathjax>#"pOH" = - log(1.42 * 10^(-4)) = 3.85#</mathjax></p> </blockquote> <p>The pH of the solution will thus be </p> <blockquote> <p><mathjax>#"pH" + "pOH" = 14#</mathjax></p> <p><mathjax>#"pH" = 14 - 3.85 = color(green)(10.15)#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/201997" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-pka"> How do you determine pH from pKa? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-ph-values-of-acids-and-bases-differ"> How do pH values of acids and bases differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-something-on-a-ph-scale"> How do you calculate something on a pH scale? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-diprotic-acid"> How do you calculate pH diprotic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-from-acid-dissociation-constant"> How do you calculate pH from acid dissociation constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-of-acid-and-base-solution"> How do you calculate pH of acid and base solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ph-scale-0-14"> Why is the pH scale 0-14? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-ph-the-measure-of-the-hydrogen-ion-concentration"> Is pH a measure of the hydrogen ion concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-solubility-affect-ph"> How does solubility affect pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-ph-relate-to-pka-in-a-titration"> How does pH relate to pKa in a titration? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/the-ph-concept"> See all questions in pH </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 9375 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How would you calculate the pH of a substance after a titration of 10.19mL 0.10M HCl with 10.99mL 0.093M NaOH?	null
1,576	ac53fbec-6ddd-11ea-8117-ccda262736ce	https://socratic.org/questions/how-many-grams-of-koh-are-needed-to-neutralise-500ml-of-2mol-l-1-h2so4	112.22 grams	start physical_unit 4 4 mass g qc_end physical_unit 14 14 12 13 molarity qc_end end	[{"type":"physical unit","value":"Mass [OF] KOH [IN] grams"}]	[{"type":"physical unit","value":"112.22 grams"}]	[{"type":"physical unit","value":"Volume [OF] H2SO4 solution [=] \\pu{500 mL}"},{"type":"physical unit","value":"Molarity [OF] H2SO4 solution [=] \\pu{2 mol/L}"}]	<h1 class="questionTitle" itemprop="name">How many grams of KOH are needed to neutralise 500mL of 2mol #L^-1# H2SO4?</h1>	null	112.22 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong><mathjax>#color (green) "Step 1:"#</mathjax></strong></p> <p>The first thing you need to do is write the chemical equation.</p> <p><mathjax>#KOH#</mathjax> + <mathjax>#H_2SO_4#</mathjax> = <mathjax>#K_2SO_4#</mathjax> + <mathjax>#H_2O#</mathjax> (unbalanced)</p> <p><strong><mathjax>#color (green) "Step 2:"#</mathjax></strong></p> <p>Balance the chemical equation. You need to do this because it's the only way that you can get the "conversion factor" you needed to solve the problem.</p> <p><mathjax>#color (red) 2 KOH#</mathjax> + <mathjax>#H_2SO_4#</mathjax> = <mathjax>#K_2SO_4#</mathjax> + <mathjax>#color (red) 2H_2O#</mathjax> (balanced)</p> <p>left side:</p> <p>K = 1 x <mathjax>#color (red) 2#</mathjax> = 2<br/> O = (1 x <mathjax>#color (red) 2#</mathjax>) + 4 = 6<br/> H = (1 x <mathjax>#color (red) 2#</mathjax>) + 2 =4<br/> S = 1</p> <p>right side:</p> <p>K = 2<br/> O = 4 + (1 x <mathjax>#color (red) 2#</mathjax>) = 2<br/> H = 2 x <mathjax>#color (red) 2#</mathjax> = 4 <br/> S = 1</p> <p><strong><mathjax>#color (green) "Step 3:"#</mathjax></strong></p> <p>Convert the volume of <mathjax>#H_2SO_4#</mathjax> into number of moles. How? By multiplying the given volume to its given <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a>. Notice that I already converted the unit from milliliter (mL) to liter (L).</p> <p>volume <mathjax>#H_2SO_4#</mathjax> = 500 mL = 0.5 L<br/> concentration of <mathjax>#H_2SO_4#</mathjax> = 2M or <mathjax>#2 mol*L^"-1"#</mathjax></p> <p><mathjax>#0.5 cancel L#</mathjax> <mathjax>#H_2SO_4#</mathjax> x <mathjax>#"2 moles"/(1 cancel "L") #</mathjax><mathjax>#H_2SO_4#</mathjax> = 1 mole <mathjax>#H_2SO_4#</mathjax></p> <p><strong><mathjax>#color (green) "Step 4:"#</mathjax></strong></p> <p>Now, going back to the balanced equation, </p> <p><mathjax>#color (red) 2 KOH#</mathjax> + <mathjax>#color (red) 1 H_2SO_4#</mathjax> = <mathjax>#color (red) 1 K_2SO_4#</mathjax> + <mathjax>#color (red) 2H_2O#</mathjax></p> <p>we know that</p> <p><mathjax>#color (red) 1#</mathjax> mole <mathjax>#H_2SO_4#</mathjax> = <mathjax>#color (red) 2#</mathjax> moles <mathjax>#KOH#</mathjax></p> <p>Therefore, to convert the computed mole of <mathjax>#H_2SO_4#</mathjax> into mole of <mathjax>#KOH#</mathjax>,</p> <p><mathjax>#1#</mathjax> <mathjax>#cancel "mol"#</mathjax><mathjax>#H_2SO_4#</mathjax> x <mathjax>#(2 "mol" KOH)/(1 cancel ("mol") H_2SO_4)#</mathjax> = <mathjax>#2#</mathjax> <mathjax>#"mol"#</mathjax> <mathjax>#KOH#</mathjax></p> <p><strong><mathjax>#color (green) "Step 5:"#</mathjax></strong></p> <p>Getting the atomic weights from <a href="http://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a>, we can compute the molar mass of <mathjax>#KOH#</mathjax>,</p> <p>K = <mathjax>#39.10 "g/mol"#</mathjax><br/> O = <mathjax>#16.00 "g/mol"#</mathjax><br/> H = <mathjax>#1.01 "g/mol"#</mathjax></p> <p>molar mass of <mathjax>#KOH#</mathjax> = <mathjax>#39.10 "g/mol"#</mathjax> + <mathjax>#16.00 "g/mol"#</mathjax> + <mathjax>#1.01 "g/mol"#</mathjax> = <mathjax>#56.11 "g/mol"#</mathjax></p> <p><strong><mathjax>#color (green) "Step 6:"#</mathjax></strong></p> <p>Converting the number of moles we got from <mathjax>#color (green) "Step 4"#</mathjax> using the molar mass of <mathjax>#KOH#</mathjax> obtained in <mathjax>#color (green) "Step 5"#</mathjax>,</p> <p><mathjax>#2#</mathjax> <mathjax>#cancel "mol"#</mathjax><mathjax>#KOH#</mathjax> x <mathjax>#(56.11 grams KOH)/(1 cancel ("mol") KOH)#</mathjax> = <strong><mathjax>#color (red) (112.22 g KOH)#</mathjax></strong></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>112.22 grams KOH</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong><mathjax>#color (green) "Step 1:"#</mathjax></strong></p> <p>The first thing you need to do is write the chemical equation.</p> <p><mathjax>#KOH#</mathjax> + <mathjax>#H_2SO_4#</mathjax> = <mathjax>#K_2SO_4#</mathjax> + <mathjax>#H_2O#</mathjax> (unbalanced)</p> <p><strong><mathjax>#color (green) "Step 2:"#</mathjax></strong></p> <p>Balance the chemical equation. You need to do this because it's the only way that you can get the "conversion factor" you needed to solve the problem.</p> <p><mathjax>#color (red) 2 KOH#</mathjax> + <mathjax>#H_2SO_4#</mathjax> = <mathjax>#K_2SO_4#</mathjax> + <mathjax>#color (red) 2H_2O#</mathjax> (balanced)</p> <p>left side:</p> <p>K = 1 x <mathjax>#color (red) 2#</mathjax> = 2<br/> O = (1 x <mathjax>#color (red) 2#</mathjax>) + 4 = 6<br/> H = (1 x <mathjax>#color (red) 2#</mathjax>) + 2 =4<br/> S = 1</p> <p>right side:</p> <p>K = 2<br/> O = 4 + (1 x <mathjax>#color (red) 2#</mathjax>) = 2<br/> H = 2 x <mathjax>#color (red) 2#</mathjax> = 4 <br/> S = 1</p> <p><strong><mathjax>#color (green) "Step 3:"#</mathjax></strong></p> <p>Convert the volume of <mathjax>#H_2SO_4#</mathjax> into number of moles. How? By multiplying the given volume to its given <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a>. Notice that I already converted the unit from milliliter (mL) to liter (L).</p> <p>volume <mathjax>#H_2SO_4#</mathjax> = 500 mL = 0.5 L<br/> concentration of <mathjax>#H_2SO_4#</mathjax> = 2M or <mathjax>#2 mol*L^"-1"#</mathjax></p> <p><mathjax>#0.5 cancel L#</mathjax> <mathjax>#H_2SO_4#</mathjax> x <mathjax>#"2 moles"/(1 cancel "L") #</mathjax><mathjax>#H_2SO_4#</mathjax> = 1 mole <mathjax>#H_2SO_4#</mathjax></p> <p><strong><mathjax>#color (green) "Step 4:"#</mathjax></strong></p> <p>Now, going back to the balanced equation, </p> <p><mathjax>#color (red) 2 KOH#</mathjax> + <mathjax>#color (red) 1 H_2SO_4#</mathjax> = <mathjax>#color (red) 1 K_2SO_4#</mathjax> + <mathjax>#color (red) 2H_2O#</mathjax></p> <p>we know that</p> <p><mathjax>#color (red) 1#</mathjax> mole <mathjax>#H_2SO_4#</mathjax> = <mathjax>#color (red) 2#</mathjax> moles <mathjax>#KOH#</mathjax></p> <p>Therefore, to convert the computed mole of <mathjax>#H_2SO_4#</mathjax> into mole of <mathjax>#KOH#</mathjax>,</p> <p><mathjax>#1#</mathjax> <mathjax>#cancel "mol"#</mathjax><mathjax>#H_2SO_4#</mathjax> x <mathjax>#(2 "mol" KOH)/(1 cancel ("mol") H_2SO_4)#</mathjax> = <mathjax>#2#</mathjax> <mathjax>#"mol"#</mathjax> <mathjax>#KOH#</mathjax></p> <p><strong><mathjax>#color (green) "Step 5:"#</mathjax></strong></p> <p>Getting the atomic weights from <a href="http://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a>, we can compute the molar mass of <mathjax>#KOH#</mathjax>,</p> <p>K = <mathjax>#39.10 "g/mol"#</mathjax><br/> O = <mathjax>#16.00 "g/mol"#</mathjax><br/> H = <mathjax>#1.01 "g/mol"#</mathjax></p> <p>molar mass of <mathjax>#KOH#</mathjax> = <mathjax>#39.10 "g/mol"#</mathjax> + <mathjax>#16.00 "g/mol"#</mathjax> + <mathjax>#1.01 "g/mol"#</mathjax> = <mathjax>#56.11 "g/mol"#</mathjax></p> <p><strong><mathjax>#color (green) "Step 6:"#</mathjax></strong></p> <p>Converting the number of moles we got from <mathjax>#color (green) "Step 4"#</mathjax> using the molar mass of <mathjax>#KOH#</mathjax> obtained in <mathjax>#color (green) "Step 5"#</mathjax>,</p> <p><mathjax>#2#</mathjax> <mathjax>#cancel "mol"#</mathjax><mathjax>#KOH#</mathjax> x <mathjax>#(56.11 grams KOH)/(1 cancel ("mol") KOH)#</mathjax> = <strong><mathjax>#color (red) (112.22 g KOH)#</mathjax></strong></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many grams of KOH are needed to neutralise 500mL of 2mol #L^-1# H2SO4?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#reactions-in-solution" itemprop="url"> <span class="breadcrumb" itemprop="title">Reactions in Solution</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/reactions-in-solution/neutralization" itemprop="url"> <span class="breadcrumb" itemprop="title">Neutralization</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="180313" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/nikka-c"><img alt="" class="" src="https://profilepictures.socratic.org/AQ8VOCyTM1J7U0TvIWhw_nkahara.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/nikka-c"> Nikka C. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-10-27T11:06:27" itemprop="dateCreated"> Oct 27, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>112.22 grams KOH</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong><mathjax>#color (green) "Step 1:"#</mathjax></strong></p> <p>The first thing you need to do is write the chemical equation.</p> <p><mathjax>#KOH#</mathjax> + <mathjax>#H_2SO_4#</mathjax> = <mathjax>#K_2SO_4#</mathjax> + <mathjax>#H_2O#</mathjax> (unbalanced)</p> <p><strong><mathjax>#color (green) "Step 2:"#</mathjax></strong></p> <p>Balance the chemical equation. You need to do this because it's the only way that you can get the "conversion factor" you needed to solve the problem.</p> <p><mathjax>#color (red) 2 KOH#</mathjax> + <mathjax>#H_2SO_4#</mathjax> = <mathjax>#K_2SO_4#</mathjax> + <mathjax>#color (red) 2H_2O#</mathjax> (balanced)</p> <p>left side:</p> <p>K = 1 x <mathjax>#color (red) 2#</mathjax> = 2<br/> O = (1 x <mathjax>#color (red) 2#</mathjax>) + 4 = 6<br/> H = (1 x <mathjax>#color (red) 2#</mathjax>) + 2 =4<br/> S = 1</p> <p>right side:</p> <p>K = 2<br/> O = 4 + (1 x <mathjax>#color (red) 2#</mathjax>) = 2<br/> H = 2 x <mathjax>#color (red) 2#</mathjax> = 4 <br/> S = 1</p> <p><strong><mathjax>#color (green) "Step 3:"#</mathjax></strong></p> <p>Convert the volume of <mathjax>#H_2SO_4#</mathjax> into number of moles. How? By multiplying the given volume to its given <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a>. Notice that I already converted the unit from milliliter (mL) to liter (L).</p> <p>volume <mathjax>#H_2SO_4#</mathjax> = 500 mL = 0.5 L<br/> concentration of <mathjax>#H_2SO_4#</mathjax> = 2M or <mathjax>#2 mol*L^"-1"#</mathjax></p> <p><mathjax>#0.5 cancel L#</mathjax> <mathjax>#H_2SO_4#</mathjax> x <mathjax>#"2 moles"/(1 cancel "L") #</mathjax><mathjax>#H_2SO_4#</mathjax> = 1 mole <mathjax>#H_2SO_4#</mathjax></p> <p><strong><mathjax>#color (green) "Step 4:"#</mathjax></strong></p> <p>Now, going back to the balanced equation, </p> <p><mathjax>#color (red) 2 KOH#</mathjax> + <mathjax>#color (red) 1 H_2SO_4#</mathjax> = <mathjax>#color (red) 1 K_2SO_4#</mathjax> + <mathjax>#color (red) 2H_2O#</mathjax></p> <p>we know that</p> <p><mathjax>#color (red) 1#</mathjax> mole <mathjax>#H_2SO_4#</mathjax> = <mathjax>#color (red) 2#</mathjax> moles <mathjax>#KOH#</mathjax></p> <p>Therefore, to convert the computed mole of <mathjax>#H_2SO_4#</mathjax> into mole of <mathjax>#KOH#</mathjax>,</p> <p><mathjax>#1#</mathjax> <mathjax>#cancel "mol"#</mathjax><mathjax>#H_2SO_4#</mathjax> x <mathjax>#(2 "mol" KOH)/(1 cancel ("mol") H_2SO_4)#</mathjax> = <mathjax>#2#</mathjax> <mathjax>#"mol"#</mathjax> <mathjax>#KOH#</mathjax></p> <p><strong><mathjax>#color (green) "Step 5:"#</mathjax></strong></p> <p>Getting the atomic weights from <a href="http://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a>, we can compute the molar mass of <mathjax>#KOH#</mathjax>,</p> <p>K = <mathjax>#39.10 "g/mol"#</mathjax><br/> O = <mathjax>#16.00 "g/mol"#</mathjax><br/> H = <mathjax>#1.01 "g/mol"#</mathjax></p> <p>molar mass of <mathjax>#KOH#</mathjax> = <mathjax>#39.10 "g/mol"#</mathjax> + <mathjax>#16.00 "g/mol"#</mathjax> + <mathjax>#1.01 "g/mol"#</mathjax> = <mathjax>#56.11 "g/mol"#</mathjax></p> <p><strong><mathjax>#color (green) "Step 6:"#</mathjax></strong></p> <p>Converting the number of moles we got from <mathjax>#color (green) "Step 4"#</mathjax> using the molar mass of <mathjax>#KOH#</mathjax> obtained in <mathjax>#color (green) "Step 5"#</mathjax>,</p> <p><mathjax>#2#</mathjax> <mathjax>#cancel "mol"#</mathjax><mathjax>#KOH#</mathjax> x <mathjax>#(56.11 grams KOH)/(1 cancel ("mol") KOH)#</mathjax> = <strong><mathjax>#color (red) (112.22 g KOH)#</mathjax></strong></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/180313" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-neutralization-reactions-useful"> How are neutralization reactions useful? 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1,577	ac0c45d4-6ddd-11ea-b6c6-ccda262736ce	https://socratic.org/questions/how-do-you-calculate-the-enthalpy-change-in-the-following-reaction-4nh-3-g-5o-2-	-1028.64 kJ/mol	start physical_unit 10 10 enthalpy kj/mol qc_end chemical_equation 11 21 qc_end end	[{"type":"physical unit","value":"Enthalpy change [OF] the reaction [IN] kJ/mol"}]	[{"type":"physical unit","value":"-1028.64 kJ/mol"}]	[{"type":"chemical equation","value":"4 NH3(g) + 5 O2(g) -> 4 NO(g) + 6 H2O"}]	<h1 class="questionTitle" itemprop="name">How do you calculate the enthalpy change in the following reaction #4NH_3(g) + 5O_2(g) -> 4NO(g) + 6H_2O#?</h1>	null	-1028.64 kJ/mol	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And I quote <mathjax>#DeltaH_f^@#</mathjax> values for the given substances. I use this <a href="https://en.wikipedia.org/wiki/Standard_enthalpy_of_formation" rel="nofollow">site</a>, and perhaps you should check that I have got the values right.......</p> <p><mathjax>#NH_3(g)#</mathjax>, <mathjax>#DeltaH_f^@=-80.8kJmol^-1#</mathjax></p> <p><mathjax>#NO(g)#</mathjax>, <mathjax>#DeltaH_f^@=+90.29kJmol^-1#</mathjax></p> <p><mathjax>#H_2O(l)#</mathjax>, <mathjax>#DeltaH_f^@=-285.8kJmol^-1#</mathjax></p> <p>And of course <mathjax>#DeltaH_f^@#</mathjax> <mathjax>#O_2(g)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0#</mathjax>, by definition for an element in its standard state under standard conditions. </p> <p>And <mathjax>#DeltaH_"reaction"^@=SigmaDelta_f^@("products")-SigmaDelta_f^@("reactants")#</mathjax></p> <p>And we do this summation for the given reaction:</p> <p><mathjax>#4NH_3(g) + 5O_2(g) rarr 4NO(g) + 6H_2O(l)#</mathjax></p> <p><mathjax>#DeltaH_"rxn"^@={(6xx-285.5+4xx90.29)-(4xx-80.8)}kJmol^-1#</mathjax></p> <p><mathjax>#=-1028.6kJmol^-1#</mathjax> (i.e. per mole of reaction as WRITTEN.....).</p> <p>The <a href="https://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> is strongly negative, i.e. exothermic, because the reaction forms water..........a thermodynamic sink.......</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well first you need some data............I eventually get <mathjax>#DeltaH_"rxn"=-1028.6kJmol^-1#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And I quote <mathjax>#DeltaH_f^@#</mathjax> values for the given substances. I use this <a href="https://en.wikipedia.org/wiki/Standard_enthalpy_of_formation" rel="nofollow">site</a>, and perhaps you should check that I have got the values right.......</p> <p><mathjax>#NH_3(g)#</mathjax>, <mathjax>#DeltaH_f^@=-80.8kJmol^-1#</mathjax></p> <p><mathjax>#NO(g)#</mathjax>, <mathjax>#DeltaH_f^@=+90.29kJmol^-1#</mathjax></p> <p><mathjax>#H_2O(l)#</mathjax>, <mathjax>#DeltaH_f^@=-285.8kJmol^-1#</mathjax></p> <p>And of course <mathjax>#DeltaH_f^@#</mathjax> <mathjax>#O_2(g)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0#</mathjax>, by definition for an element in its standard state under standard conditions. </p> <p>And <mathjax>#DeltaH_"reaction"^@=SigmaDelta_f^@("products")-SigmaDelta_f^@("reactants")#</mathjax></p> <p>And we do this summation for the given reaction:</p> <p><mathjax>#4NH_3(g) + 5O_2(g) rarr 4NO(g) + 6H_2O(l)#</mathjax></p> <p><mathjax>#DeltaH_"rxn"^@={(6xx-285.5+4xx90.29)-(4xx-80.8)}kJmol^-1#</mathjax></p> <p><mathjax>#=-1028.6kJmol^-1#</mathjax> (i.e. per mole of reaction as WRITTEN.....).</p> <p>The <a href="https://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> is strongly negative, i.e. exothermic, because the reaction forms water..........a thermodynamic sink.......</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you calculate the enthalpy change in the following reaction #4NH_3(g) + 5O_2(g) -> 4NO(g) + 6H_2O#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/enthalpy" itemprop="url"> <span class="breadcrumb" itemprop="title">Enthalpy</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="433160" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-01T17:35:07" itemprop="dateCreated"> Jun 1, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well first you need some data............I eventually get <mathjax>#DeltaH_"rxn"=-1028.6kJmol^-1#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And I quote <mathjax>#DeltaH_f^@#</mathjax> values for the given substances. I use this <a href="https://en.wikipedia.org/wiki/Standard_enthalpy_of_formation" rel="nofollow">site</a>, and perhaps you should check that I have got the values right.......</p> <p><mathjax>#NH_3(g)#</mathjax>, <mathjax>#DeltaH_f^@=-80.8kJmol^-1#</mathjax></p> <p><mathjax>#NO(g)#</mathjax>, <mathjax>#DeltaH_f^@=+90.29kJmol^-1#</mathjax></p> <p><mathjax>#H_2O(l)#</mathjax>, <mathjax>#DeltaH_f^@=-285.8kJmol^-1#</mathjax></p> <p>And of course <mathjax>#DeltaH_f^@#</mathjax> <mathjax>#O_2(g)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0#</mathjax>, by definition for an element in its standard state under standard conditions. </p> <p>And <mathjax>#DeltaH_"reaction"^@=SigmaDelta_f^@("products")-SigmaDelta_f^@("reactants")#</mathjax></p> <p>And we do this summation for the given reaction:</p> <p><mathjax>#4NH_3(g) + 5O_2(g) rarr 4NO(g) + 6H_2O(l)#</mathjax></p> <p><mathjax>#DeltaH_"rxn"^@={(6xx-285.5+4xx90.29)-(4xx-80.8)}kJmol^-1#</mathjax></p> <p><mathjax>#=-1028.6kJmol^-1#</mathjax> (i.e. per mole of reaction as WRITTEN.....).</p> <p>The <a href="https://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> is strongly negative, i.e. exothermic, because the reaction forms water..........a thermodynamic sink.......</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/433160" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-enthalpy-changes-expressed-in-chemical-equations"> How are enthalpy changes expressed in chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-enthalpy-change-be-determined-for-an-aqueous-solution"> How can enthalpy change be determined for an aqueous solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-enthalpy-change-with-pressure"> How does enthalpy change with pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-standard-molar-enthalpy-formation"> How do you calculate standard molar enthalpy of formation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-enthalpy-a-state-function"> Why is enthalpy a state function? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-enthalpy-of-formation-of-oxygen-zero"> Why is the enthalpy of formation of oxygen zero? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-enthalpy-a-state-function-2"> Why is enthalpy a state function? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-enthalpy-cannot-be-measured-directly"> Why can enthalpy not be measured directly? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-pressure-affect-enthalpy"> How does pressure affect enthalpy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-enthalpy-relate-to-internal-energy"> How does enthalpy relate to internal energy? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/enthalpy"> See all questions in Enthalpy </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 19149 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How do you calculate the enthalpy change in the following reaction #4NH_3(g) + 5O_2(g) -> 4NO(g) + 6H_2O#?	null
1,578	a8cfe126-6ddd-11ea-b57c-ccda262736ce	https://socratic.org/questions/what-is-the-chemical-equation-for-the-combustion-of-butane	2 C4H10 + 13 O2 -> 8 CO2 + 10 H2O	start chemical_equation qc_end substance 9 9 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the combustion"}]	[{"type":"chemical equation","value":"2 C4H10 + 13 O2 -> 8 CO2 + 10 H2O"}]	[{"type":"substance name","value":"Butane"}]	<h1 class="questionTitle" itemprop="name">What is the chemical equation for the combustion of butane? </h1>	null	2 C4H10 + 13 O2 -> 8 CO2 + 10 H2O	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#C_4H_10(g) + 13/2O_2(g) rarr 4CO_2(g) + 5H_2O(g)#</mathjax></p> <p>Is the equation above balanced? How do you know? How would you remove the <mathjax>#13/2#</mathjax> coefficient for dioxygen?</p> <p>The reaction above represents complete combustion. Suppose I wanted to model a reaction where some of the hydrocarbon were combusted to <mathjax>#CO#</mathjax>; how would you represent this?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Butane + oxygen <mathjax>#rarr#</mathjax> carbon dioxide + water</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#C_4H_10(g) + 13/2O_2(g) rarr 4CO_2(g) + 5H_2O(g)#</mathjax></p> <p>Is the equation above balanced? How do you know? How would you remove the <mathjax>#13/2#</mathjax> coefficient for dioxygen?</p> <p>The reaction above represents complete combustion. Suppose I wanted to model a reaction where some of the hydrocarbon were combusted to <mathjax>#CO#</mathjax>; how would you represent this?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the chemical equation for the combustion of butane? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-reactions-and-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions and Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="193409" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-26T19:28:30" itemprop="dateCreated"> Nov 26, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Butane + oxygen <mathjax>#rarr#</mathjax> carbon dioxide + water</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#C_4H_10(g) + 13/2O_2(g) rarr 4CO_2(g) + 5H_2O(g)#</mathjax></p> <p>Is the equation above balanced? How do you know? How would you remove the <mathjax>#13/2#</mathjax> coefficient for dioxygen?</p> <p>The reaction above represents complete combustion. Suppose I wanted to model a reaction where some of the hydrocarbon were combusted to <mathjax>#CO#</mathjax>; how would you represent this?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/193409" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="193411" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-26T19:37:14" itemprop="dateCreated"> Nov 26, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#color(red)(2)"C"_4"H"_10("g") + color(red)(13)"O"_2("g")#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(red)8"CO"_2("g") + color(red)(10)"H"_2"O(g)"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The chemical formula of butane is <mathjax>#"C"_4"H"_10"#</mathjax>. The combustion of butane is a reaction between butane and oxygen gas that produces carbon dioxide gas and water.</p> <p><mathjax>#color(red)(2)"C"_4"H"_10("g") + color(red)(13)"O"_2("g")#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(red)8"CO"_2("g") + color(red)(10)"H"_2"O(g)"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/193411" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb002bf34694a4fee47"> Question #fee47 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb402bf34694c8c5c15"> Question #c5c15 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb802bf346950519eb9"> Question #19eb9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cbf02bf3469570e2ea2"> Question #e2ea2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc002bf34695a6bc751"> Question #bc751 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc202bf3469570e2ea6"> Question #e2ea6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531e867a02bf342492a08b07"> Question #08b07 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-thermochemical-equation-for-the-combustion-of-benzene"> What is the thermochemical equation for the combustion of benzene? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-reversible"> Why are chemical reactions reversible? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-important"> Why are chemical reactions important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/chemical-reactions-and-equations"> See all questions in Chemical Reactions and Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 206264 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the chemical equation for the combustion of butane?	null
1,579	ace05116-6ddd-11ea-ae14-ccda262736ce	https://socratic.org/questions/in-the-reaction-2al-6hbr-2albr-3-3h-2-when-3-22-moles-of-al-reacts-with-4-96-mol	2.48 moles	start physical_unit 13 13 mole mol qc_end physical_unit 4 4 15 16 mole qc_end physical_unit 7 7 21 22 mole qc_end chemical_equation 3 13 qc_end end	[{"type":"physical unit","value":"Mole [OF] H2 [IN] moles"}]	[{"type":"physical unit","value":"2.48 moles"}]	[{"type":"physical unit","value":"Mole [OF] Al [=] \\pu{3.22 moles}"},{"type":"physical unit","value":"Mole [OF] HBr [=] \\pu{4.96 moles}"},{"type":"chemical equation","value":"2 Al + 6 HBr -> 2 AlBr3 + 3 H2"}]	<h1 class="questionTitle" itemprop="name">In the reaction #2Al +6HBr -> 2AlBr_3 + 3H_2#, when 3.22 moles of #Al# reacts with 4.96 moles of #HBr#, how many moles of #H_2# are formed?</h1>	null	2.48 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The balanced chemical equation represents <a href="http://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio in which the chemicals react.</p> <p>Since 2 moles aluminuim are required for every 6 moles of hydrogen bromide, yet we only have 3.22 moles aluminium and 4.96 moles hydrogen bromide, it implies that <mathjax>#HBr#</mathjax> will get used up first and is hence the limiting reactant, while <mathjax>#Al#</mathjax> is in excess.</p> <p>So all <mathjax>#4.96 mol HBr#</mathjax> is used up and reacts with <mathjax>#4.96/3=1.653mol Al#</mathjax> to produce <mathjax>#4.96/2=2.48 mol H_2#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2.48mol#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The balanced chemical equation represents <a href="http://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio in which the chemicals react.</p> <p>Since 2 moles aluminuim are required for every 6 moles of hydrogen bromide, yet we only have 3.22 moles aluminium and 4.96 moles hydrogen bromide, it implies that <mathjax>#HBr#</mathjax> will get used up first and is hence the limiting reactant, while <mathjax>#Al#</mathjax> is in excess.</p> <p>So all <mathjax>#4.96 mol HBr#</mathjax> is used up and reacts with <mathjax>#4.96/3=1.653mol Al#</mathjax> to produce <mathjax>#4.96/2=2.48 mol H_2#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">In the reaction #2Al +6HBr -> 2AlBr_3 + 3H_2#, when 3.22 moles of #Al# reacts with 4.96 moles of #HBr#, how many moles of #H_2# are formed?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="222047" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/trevor-r-1"><img alt="" class="" src="https://profilepictures.socratic.org/2Wf9lLD9RaSzPbXY0EW8_S5002678.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/trevor-r-1"> Trevor Ryan. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-02-05T21:40:18" itemprop="dateCreated"> Feb 5, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2.48mol#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The balanced chemical equation represents <a href="http://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio in which the chemicals react.</p> <p>Since 2 moles aluminuim are required for every 6 moles of hydrogen bromide, yet we only have 3.22 moles aluminium and 4.96 moles hydrogen bromide, it implies that <mathjax>#HBr#</mathjax> will get used up first and is hence the limiting reactant, while <mathjax>#Al#</mathjax> is in excess.</p> <p>So all <mathjax>#4.96 mol HBr#</mathjax> is used up and reacts with <mathjax>#4.96/3=1.653mol Al#</mathjax> to produce <mathjax>#4.96/2=2.48 mol H_2#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/222047" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 37441 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	In the reaction #2Al +6HBr -> 2AlBr_3 + 3H_2#, when 3.22 moles of #Al# reacts with 4.96 moles of #HBr#, how many moles of #H_2# are formed?	null
1,580	a98308af-6ddd-11ea-941b-ccda262736ce	https://socratic.org/questions/how-many-moles-are-in-508-g-of-ethanol-c-2h-6o	11.02 moles	start physical_unit 9 9 mole mol qc_end physical_unit 9 9 5 6 mass qc_end end	[{"type":"physical unit","value":"Mole [OF] C2H6O [IN] moles"}]	[{"type":"physical unit","value":"11.02 moles"}]	[{"type":"physical unit","value":"Mass [OF] C2H6O [=] \\pu{508 g}"}]	<h1 class="questionTitle" itemprop="name">How many moles are in 508 g of ethanol (#C_2H_6O#)?</h1>	null	11.02 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Calculate the molar mass of <mathjax>#"C"_2"H"_6"O"#</mathjax>.</p> <p><mathjax>#2xx"molar mass of C"=2xx12.01 "g/mol"=24.02"g/mol"#</mathjax><br/> <mathjax>#6xx"molar mass of H"=6xx1.01"g/mol"=6.06"g/mol"#</mathjax><br/> <mathjax>#1xx"molar mass of O"=1xx16.00"g/mol"=16.00"g/mol"#</mathjax></p> <p>The sum of the molar masses of each atom is <mathjax>#46.08"g/mol"#</mathjax>.</p> <p><mathjax>#508color(red)(cancel(color(black)("g")))xx(1"mol")/(46.08color(red)(cancel(color(black)("g"))))="11.02 mol C"_2"H"_6"O"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"11.02 mol C"_2"H"_6"O"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Calculate the molar mass of <mathjax>#"C"_2"H"_6"O"#</mathjax>.</p> <p><mathjax>#2xx"molar mass of C"=2xx12.01 "g/mol"=24.02"g/mol"#</mathjax><br/> <mathjax>#6xx"molar mass of H"=6xx1.01"g/mol"=6.06"g/mol"#</mathjax><br/> <mathjax>#1xx"molar mass of O"=1xx16.00"g/mol"=16.00"g/mol"#</mathjax></p> <p>The sum of the molar masses of each atom is <mathjax>#46.08"g/mol"#</mathjax>.</p> <p><mathjax>#508color(red)(cancel(color(black)("g")))xx(1"mol")/(46.08color(red)(cancel(color(black)("g"))))="11.02 mol C"_2"H"_6"O"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles are in 508 g of ethanol (#C_2H_6O#)?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="199923" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/mason-m"><img alt="" class="" src="https://profilepictures.socratic.org/U70pu8hUTGGkEuy92fsO_IMG_2585.jpeg" title=""/></a> <a class="secondContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/mason-m"> mason m </a>·<a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-15T02:55:42" itemprop="dateCreated"> Dec 15, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"11.02 mol C"_2"H"_6"O"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Calculate the molar mass of <mathjax>#"C"_2"H"_6"O"#</mathjax>.</p> <p><mathjax>#2xx"molar mass of C"=2xx12.01 "g/mol"=24.02"g/mol"#</mathjax><br/> <mathjax>#6xx"molar mass of H"=6xx1.01"g/mol"=6.06"g/mol"#</mathjax><br/> <mathjax>#1xx"molar mass of O"=1xx16.00"g/mol"=16.00"g/mol"#</mathjax></p> <p>The sum of the molar masses of each atom is <mathjax>#46.08"g/mol"#</mathjax>.</p> <p><mathjax>#508color(red)(cancel(color(black)("g")))xx(1"mol")/(46.08color(red)(cancel(color(black)("g"))))="11.02 mol C"_2"H"_6"O"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/199923" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li 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moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 23276 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many moles are in 508 g of ethanol (#C_2H_6O#)?	null
1,581	a9d89a6e-6ddd-11ea-b7c1-ccda262736ce	https://socratic.org/questions/using-the-equation-2h-2-o-2-2h-2o-when-47g-of-oxygen-are-produced-how-many-grams	5.9 grams	start physical_unit 21 21 mass g qc_end physical_unit 14 14 11 12 mass qc_end chemical_equation 3 9 qc_end end	[{"type":"physical unit","value":"Mass [OF] hydrogen [IN] grams"}]	[{"type":"physical unit","value":"5.9 grams"}]	[{"type":"physical unit","value":"Mass [OF] oxygen [=] \\pu{47 g}"},{"type":"chemical equation","value":"2 H2 + O2 -> 2 H2O"}]	<h1 class="questionTitle" itemprop="name">Using the equation #2H_2 + O_2 -> 2H_2O#, when 47g of oxygen are produced, how many grams of hydrogen must react?</h1>	null	5.9 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>1. Write the balanced equation</strong>.</p> <p><mathjax>#2"H"_2 + "O"_2 → "2H"_2"O"#</mathjax></p> <blockquote></blockquote> <p><strong>2. Calculate the moles of <mathjax>#"O"_2#</mathjax></strong>.</p> <p><mathjax>#"Moles of O"_2 = 47 color(red)(cancel(color(black)("g O"_2))) × ("1 mol O"_2)/(32.00 color(red)(cancel(color(black)("g O"_2)))) = "1.47 mol O"_2#</mathjax></p> <blockquote></blockquote> <p><strong>3. Calculate the moles of <mathjax>#"H"_2#</mathjax></strong>.</p> <p><mathjax>#"Moles of H"_2 = 1.47 color(red)(cancel(color(black)("mol O"_2))) × ("2 mol H"_2)/(1 color(red)(cancel(color(black)("mol O"_2)))) = "2.94 mol H"_2#</mathjax></p> <blockquote></blockquote> <p><strong>4. Calculate the mass of <mathjax>#"H"_2#</mathjax></strong>.</p> <p><mathjax>#"Mass of H"_2 = 2.94 color(red)(cancel(color(black)("mol H"_2))) × ("2.016 g H"_2)/(1 color(red)(cancel(color(black)("mol H"_2)))) = "5.9 g H"_2#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>5.9 g of hydrogen must react.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>1. Write the balanced equation</strong>.</p> <p><mathjax>#2"H"_2 + "O"_2 → "2H"_2"O"#</mathjax></p> <blockquote></blockquote> <p><strong>2. Calculate the moles of <mathjax>#"O"_2#</mathjax></strong>.</p> <p><mathjax>#"Moles of O"_2 = 47 color(red)(cancel(color(black)("g O"_2))) × ("1 mol O"_2)/(32.00 color(red)(cancel(color(black)("g O"_2)))) = "1.47 mol O"_2#</mathjax></p> <blockquote></blockquote> <p><strong>3. Calculate the moles of <mathjax>#"H"_2#</mathjax></strong>.</p> <p><mathjax>#"Moles of H"_2 = 1.47 color(red)(cancel(color(black)("mol O"_2))) × ("2 mol H"_2)/(1 color(red)(cancel(color(black)("mol O"_2)))) = "2.94 mol H"_2#</mathjax></p> <blockquote></blockquote> <p><strong>4. Calculate the mass of <mathjax>#"H"_2#</mathjax></strong>.</p> <p><mathjax>#"Mass of H"_2 = 2.94 color(red)(cancel(color(black)("mol H"_2))) × ("2.016 g H"_2)/(1 color(red)(cancel(color(black)("mol H"_2)))) = "5.9 g H"_2#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Using the equation #2H_2 + O_2 -> 2H_2O#, when 47g of oxygen are produced, how many grams of hydrogen must react?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="284055" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-02T22:19:37" itemprop="dateCreated"> Jul 2, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>5.9 g of hydrogen must react.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>1. Write the balanced equation</strong>.</p> <p><mathjax>#2"H"_2 + "O"_2 → "2H"_2"O"#</mathjax></p> <blockquote></blockquote> <p><strong>2. Calculate the moles of <mathjax>#"O"_2#</mathjax></strong>.</p> <p><mathjax>#"Moles of O"_2 = 47 color(red)(cancel(color(black)("g O"_2))) × ("1 mol O"_2)/(32.00 color(red)(cancel(color(black)("g O"_2)))) = "1.47 mol O"_2#</mathjax></p> <blockquote></blockquote> <p><strong>3. Calculate the moles of <mathjax>#"H"_2#</mathjax></strong>.</p> <p><mathjax>#"Moles of H"_2 = 1.47 color(red)(cancel(color(black)("mol O"_2))) × ("2 mol H"_2)/(1 color(red)(cancel(color(black)("mol O"_2)))) = "2.94 mol H"_2#</mathjax></p> <blockquote></blockquote> <p><strong>4. Calculate the mass of <mathjax>#"H"_2#</mathjax></strong>.</p> <p><mathjax>#"Mass of H"_2 = 2.94 color(red)(cancel(color(black)("mol H"_2))) × ("2.016 g H"_2)/(1 color(red)(cancel(color(black)("mol H"_2)))) = "5.9 g H"_2#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/284055" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What is stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ab82402bf342f48d93ac6"> Question #93ac6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-we-study-stoichiometry"> Why do we study stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-naoh-is-produced-from-1-20-x-102-grams-of-na2o-na2o-h2o-2-naoh"> How many grams of NaOH is produced from #1.20 x 10^2# grams of #Na_2O#? #Na_2O + H_2O -> 2NaOH# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-na2o-are-required-to-produce-1-60-x-102-grams-of-naoh-na2o-h2o"> How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? 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1,582	abff4624-6ddd-11ea-aa69-ccda262736ce	https://socratic.org/questions/what-is-the-chemical-formula-for-an-ionic-compound-of-potassium-and-oxygen	K2O	start chemical_formula qc_end substance 10 10 qc_end substance 12 12 qc_end end	[{"type":"other","value":"Chemical Formula [OF] ionic compound [IN] default"}]	[{"type":"chemical equation","value":"K2O"}]	[{"type":"substance name","value":"Potassium"},{"type":"substance name","value":"Oxygen"}]	<h1 class="questionTitle" itemprop="name">What is the chemical formula for an ionic compound of potassium and oxygen?</h1>	null	K2O	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The last level of the electronic structure of oxygen is <mathjax>#2s^2 2p^4#</mathjax>. That means that there are two electrons in the <mathjax>#2s#</mathjax> orbital, two other electrons (paired) in one of the <mathjax>#2p#</mathjax> orbitals and the remaining two (unpaired) electrons placed one in each of the remaining <mathjax>#2p#</mathjax> orbitals.</p> <p>This means that oxygen has two semi-occupied orbitals and, following the <a href="https://socratic.org/chemistry/bonding-basics/electrons-in-bonding-and-the-octet-rule">octet rule</a>, will try to capture two more electrons to complete its structure and acquire that of a noble gas. That is, when it acts to form ionic bonds, oxygen acquires structure <mathjax>#2s^2 2p^6#</mathjax> in its last level, forming the ion oxygen (2-): <mathjax>#O^{2-}#</mathjax>.</p> <p>On the other hand, potassium is an alkali metal whose last level occupied is <mathjax>#4s^1#</mathjax>. That means that it will have a lot of tendency to lose that solitary electron and thus to form <a href="https://socratic.org/chemistry/ionic-bonds-and-formulas/ionic-compounds">ionic compounds</a> in which it takes the form of cation <mathjax>#K^+#</mathjax>.</p> <p>Therefore, the binding of oxygen and potassium will give rise to an oxide of ionic character and <mathjax>#K_2O#</mathjax> stoichiometric formula.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Potassium oxyde, <mathjax>#K_2O#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The last level of the electronic structure of oxygen is <mathjax>#2s^2 2p^4#</mathjax>. That means that there are two electrons in the <mathjax>#2s#</mathjax> orbital, two other electrons (paired) in one of the <mathjax>#2p#</mathjax> orbitals and the remaining two (unpaired) electrons placed one in each of the remaining <mathjax>#2p#</mathjax> orbitals.</p> <p>This means that oxygen has two semi-occupied orbitals and, following the <a href="https://socratic.org/chemistry/bonding-basics/electrons-in-bonding-and-the-octet-rule">octet rule</a>, will try to capture two more electrons to complete its structure and acquire that of a noble gas. That is, when it acts to form ionic bonds, oxygen acquires structure <mathjax>#2s^2 2p^6#</mathjax> in its last level, forming the ion oxygen (2-): <mathjax>#O^{2-}#</mathjax>.</p> <p>On the other hand, potassium is an alkali metal whose last level occupied is <mathjax>#4s^1#</mathjax>. That means that it will have a lot of tendency to lose that solitary electron and thus to form <a href="https://socratic.org/chemistry/ionic-bonds-and-formulas/ionic-compounds">ionic compounds</a> in which it takes the form of cation <mathjax>#K^+#</mathjax>.</p> <p>Therefore, the binding of oxygen and potassium will give rise to an oxide of ionic character and <mathjax>#K_2O#</mathjax> stoichiometric formula.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the chemical formula for an ionic compound of potassium and oxygen?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#ionic-bonds-and-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Ionic Bonds</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/ionic-bonds-and-formulas/writing-ionic-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Writing Ionic Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="368850" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/pitufox27"><img alt="" class="" src="https://profilepictures.socratic.org/ECp7QE4rSIv87risZu2l_Anne%20Stokes%20-%20Rock%20God.bmp" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/pitufox27"> Pitufox27 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-01-24T21:50:20" itemprop="dateCreated"> Jan 24, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Potassium oxyde, <mathjax>#K_2O#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The last level of the electronic structure of oxygen is <mathjax>#2s^2 2p^4#</mathjax>. That means that there are two electrons in the <mathjax>#2s#</mathjax> orbital, two other electrons (paired) in one of the <mathjax>#2p#</mathjax> orbitals and the remaining two (unpaired) electrons placed one in each of the remaining <mathjax>#2p#</mathjax> orbitals.</p> <p>This means that oxygen has two semi-occupied orbitals and, following the <a href="https://socratic.org/chemistry/bonding-basics/electrons-in-bonding-and-the-octet-rule">octet rule</a>, will try to capture two more electrons to complete its structure and acquire that of a noble gas. That is, when it acts to form ionic bonds, oxygen acquires structure <mathjax>#2s^2 2p^6#</mathjax> in its last level, forming the ion oxygen (2-): <mathjax>#O^{2-}#</mathjax>.</p> <p>On the other hand, potassium is an alkali metal whose last level occupied is <mathjax>#4s^1#</mathjax>. That means that it will have a lot of tendency to lose that solitary electron and thus to form <a href="https://socratic.org/chemistry/ionic-bonds-and-formulas/ionic-compounds">ionic compounds</a> in which it takes the form of cation <mathjax>#K^+#</mathjax>.</p> <p>Therefore, the binding of oxygen and potassium will give rise to an oxide of ionic character and <mathjax>#K_2O#</mathjax> stoichiometric formula.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/368850" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-write-ionic-formulas-for-binary-compounds"> How do you write ionic formulas for binary compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-formula-for-calcium-chloride"> What is the ionic formula for calcium chloride? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-formula-for-calcium-oxide"> What is the ionic formula for calcium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-formula-for-lithium-oxide"> What is the ionic formula for lithium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-formula-for-ionic-compounds"> How do you write the formula for ionic compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-correctly-write-the-ions-present-in-sn-no3-2"> How do I write #Sn(NO_3)_2# in Ionic formula? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-an-ionic-compound"> What is the empirical formula for an ionic compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-for-chorate"> What is the molecular formula for chorate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5363023c02bf343b2ee7086b"> Question #7086b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-polyatomic-ions-covalent-1"> Why are polyatomic ions covalent? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/ionic-bonds-and-formulas/writing-ionic-formulas"> See all questions in Writing Ionic Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 23817 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the chemical formula for an ionic compound of potassium and oxygen?	null
1,583	ab0c64e5-6ddd-11ea-a4b3-ccda262736ce	https://socratic.org/questions/58d08754b72cff738fb10f59	4.57 × 10^4 J/g	start physical_unit 4 4 enthalpy_of_combustion j/g qc_end physical_unit 4 4 6 7 deltah^0 qc_end end	[{"type":"physical unit","value":"Heat of combustion [OF] butane [IN] J/g"}]	[{"type":"physical unit","value":"4.57 × 10^4 J/g"}]	[{"type":"physical unit","value":"DeltaH^0 combustion [OF] butane [=] \\pu{-2657 kJ/mol}"}]	<h1 class="questionTitle" itemprop="name">Given #DeltaH_"combustion"^@# for butane is #-2657kJmol^-1#, what is #"heat of combustion"# for butane in #J*g^-1#?</h1>	null	4.57 × 10^4 J/g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We have data for the stoichiometric equation:</p> <p><mathjax>#C_4H_10(g)+ 13/2O_2(g)rarr 4CO_2 + 5H_2O#</mathjax> <mathjax>#DeltaH_"rxn"=-2657kJmol^-1#</mathjax></p> <p>Note that I halved the equation because it makes the arithmetic a little bit easier. I also had to halve the <a href="https://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> change accordingly.</p> <p>And thus <mathjax>#"Heat of combustion of butane"#</mathjax> <mathjax>#-=#</mathjax> <mathjax>#(-2657xx10^3kJcancel(mol^-1))/(58.12gcancel(mol^-1))=45.7kJg^-1#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Heat of combustion of butane"#</mathjax> <mathjax>#-=#</mathjax> <mathjax>#45.7xx10^3Jg^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We have data for the stoichiometric equation:</p> <p><mathjax>#C_4H_10(g)+ 13/2O_2(g)rarr 4CO_2 + 5H_2O#</mathjax> <mathjax>#DeltaH_"rxn"=-2657kJmol^-1#</mathjax></p> <p>Note that I halved the equation because it makes the arithmetic a little bit easier. I also had to halve the <a href="https://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> change accordingly.</p> <p>And thus <mathjax>#"Heat of combustion of butane"#</mathjax> <mathjax>#-=#</mathjax> <mathjax>#(-2657xx10^3kJcancel(mol^-1))/(58.12gcancel(mol^-1))=45.7kJg^-1#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Given #DeltaH_"combustion"^@# for butane is #-2657kJmol^-1#, what is #"heat of combustion"# for butane in #Jg^-1#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/enthalpy" itemprop="url"> <span class="breadcrumb" itemprop="title">Enthalpy</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="394865" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-22T16:39:53" itemprop="dateCreated"> Mar 22, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Heat of combustion of butane"#</mathjax> <mathjax>#-=#</mathjax> <mathjax>#45.7xx10^3Jg^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We have data for the stoichiometric equation:</p> <p><mathjax>#C_4H_10(g)+ 13/2O_2(g)rarr 4CO_2 + 5H_2O#</mathjax> <mathjax>#DeltaH_"rxn"=-2657kJmol^-1#</mathjax></p> <p>Note that I halved the equation because it makes the arithmetic a little bit easier. I also had to halve the <a href="https://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> change accordingly.</p> <p>And thus <mathjax>#"Heat of combustion of butane"#</mathjax> <mathjax>#-=#</mathjax> <mathjax>#(-2657xx10^3kJcancel(mol^-1))/(58.12gcancel(mol^-1))=45.7kJ*g^-1#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/394865" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-enthalpy-changes-expressed-in-chemical-equations"> How are enthalpy changes expressed in chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-enthalpy-change-be-determined-for-an-aqueous-solution"> How can enthalpy change be determined for an aqueous solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-enthalpy-change-with-pressure"> How does enthalpy change with pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-standard-molar-enthalpy-formation"> How do you calculate standard molar enthalpy of formation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-enthalpy-a-state-function"> Why is enthalpy a state function? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-enthalpy-of-formation-of-oxygen-zero"> Why is the enthalpy of formation of oxygen zero? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-enthalpy-a-state-function-2"> Why is enthalpy a state function? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-enthalpy-cannot-be-measured-directly"> Why can enthalpy not be measured directly? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-pressure-affect-enthalpy"> How does pressure affect enthalpy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-enthalpy-relate-to-internal-energy"> How does enthalpy relate to internal energy? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/enthalpy"> See all questions in Enthalpy </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 11494 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Given #DeltaH_"combustion"^@# for butane is #-2657kJmol^-1#, what is #"heat of combustion"# for butane in #J*g^-1#?	null
1,584	a8f53b24-6ddd-11ea-8da6-ccda262736ce	https://socratic.org/questions/how-many-grams-are-there-in-1-18-10-26-atoms-of-iridium	37700 grams	start physical_unit 9 9 mass g qc_end end	[{"type":"physical unit","value":"Mass [OF] iridium [IN] grams"}]	[{"type":"physical unit","value":"37700 grams"}]	[{"type":"physical unit","value":"Number [OF] iridium atoms [=] \\pu{1.18×10^26}"}]	<h1 class="questionTitle" itemprop="name">How many grams are there in #1.18 * 10^26# atoms of iridium?</h1>	null	37700 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We must first determine the molar mass of iridium <mathjax>#("Ir")#</mathjax>, which is its relative <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">atomic mass</a> on <a href="http://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a> in g/mol. </p> <p>The molar mass of <mathjax>#"Ir"#</mathjax><mathjax># =#</mathjax><mathjax>#"192.217 g/mol"#</mathjax>.</p> <p><mathjax>#"1 mol Ir"=6.022xx10^23#</mathjax> atoms <mathjax>#"Ir"#</mathjax></p> <p>To determine the mass of <mathjax>#1.18xx10^26#</mathjax> atoms of <mathjax>#"Ir"#</mathjax>, divide the given number of atoms by <mathjax>#6.022xx10^23#</mathjax> atoms/mol to get moles of <mathjax>#"Ir"#</mathjax>, then multiply times the molar mass of <mathjax>#"Ir"#</mathjax> to get mass of <mathjax>#"Ir"#</mathjax> in grams.</p> <p><mathjax>#1.18xx10^26cancel"atoms Ir"xx(1cancel"mol Ir")/(6.022xx10^23cancel"atoms Ir")xx(192.217"g Ir")/(1cancel"mol Ir")=37700 "g Ir"#</mathjax> rounded to three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1.18xx10^26#</mathjax> atoms of iridium have a mass of 37700 g.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We must first determine the molar mass of iridium <mathjax>#("Ir")#</mathjax>, which is its relative <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">atomic mass</a> on <a href="http://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a> in g/mol. </p> <p>The molar mass of <mathjax>#"Ir"#</mathjax><mathjax># =#</mathjax><mathjax>#"192.217 g/mol"#</mathjax>.</p> <p><mathjax>#"1 mol Ir"=6.022xx10^23#</mathjax> atoms <mathjax>#"Ir"#</mathjax></p> <p>To determine the mass of <mathjax>#1.18xx10^26#</mathjax> atoms of <mathjax>#"Ir"#</mathjax>, divide the given number of atoms by <mathjax>#6.022xx10^23#</mathjax> atoms/mol to get moles of <mathjax>#"Ir"#</mathjax>, then multiply times the molar mass of <mathjax>#"Ir"#</mathjax> to get mass of <mathjax>#"Ir"#</mathjax> in grams.</p> <p><mathjax>#1.18xx10^26cancel"atoms Ir"xx(1cancel"mol Ir")/(6.022xx10^23cancel"atoms Ir")xx(192.217"g Ir")/(1cancel"mol Ir")=37700 "g Ir"#</mathjax> rounded to three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many grams are there in #1.18 * 10^26# atoms of iridium?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="220012" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-02-01T11:28:06" itemprop="dateCreated"> Feb 1, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1.18xx10^26#</mathjax> atoms of iridium have a mass of 37700 g.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We must first determine the molar mass of iridium <mathjax>#("Ir")#</mathjax>, which is its relative <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">atomic mass</a> on <a href="http://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a> in g/mol. </p> <p>The molar mass of <mathjax>#"Ir"#</mathjax><mathjax># =#</mathjax><mathjax>#"192.217 g/mol"#</mathjax>.</p> <p><mathjax>#"1 mol Ir"=6.022xx10^23#</mathjax> atoms <mathjax>#"Ir"#</mathjax></p> <p>To determine the mass of <mathjax>#1.18xx10^26#</mathjax> atoms of <mathjax>#"Ir"#</mathjax>, divide the given number of atoms by <mathjax>#6.022xx10^23#</mathjax> atoms/mol to get moles of <mathjax>#"Ir"#</mathjax>, then multiply times the molar mass of <mathjax>#"Ir"#</mathjax> to get mass of <mathjax>#"Ir"#</mathjax> in grams.</p> <p><mathjax>#1.18xx10^26cancel"atoms Ir"xx(1cancel"mol Ir")/(6.022xx10^23cancel"atoms Ir")xx(192.217"g Ir")/(1cancel"mol Ir")=37700 "g Ir"#</mathjax> rounded to three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/220012" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> 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1,585	a92efb3e-6ddd-11ea-987d-ccda262736ce	https://socratic.org/questions/what-is-the-pressure-of-1-00-mole-of-cl-2-gas-that-is-non-ideal-at-a-temperature	0.65 bar	start physical_unit 8 9 pressure bar qc_end physical_unit 8 9 5 6 mole qc_end c_other OTHER qc_end physical_unit 8 9 17 19 temperature qc_end physical_unit 8 9 23 24 volume qc_end end	[{"type":"physical unit","value":"Pressure [OF] Cl2 gas [IN] bar"}]	[{"type":"physical unit","value":"0.65 bar"}]	[{"type":"physical unit","value":"Mole [OF] Cl2 gas [=] \\pu{1.00 mole}"},{"type":"other","value":"Cl2 gas is non-ideal."},{"type":"physical unit","value":"Temperature [OF] Cl2 gas [=] \\pu{0.0 deg C}"},{"type":"physical unit","value":"Volume [OF] Cl2 gas [=] \\pu{34.6 L}"}]	<h1 class="questionTitle" itemprop="name">What is the pressure of 1.00 mole of #Cl_2# gas that is non-ideal, at a temperature of 0.0 deg C occupying a volume 34.6 L?</h1>	null	0.65 bar	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>I assume that you are treating the chlorine as a van der Waals gas.</p> <p>The <strong>van der Waals equation</strong> is</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(\|color(white)(a/a) (P + (n^2a)/V^2)(V - nb) = nRTcolor(white)(a/a)\|)))" "#</mathjax></p> <p><mathjax>#P + (n^2a)/V^2 = (nRT)/(V - nb)#</mathjax></p> <p><mathjax>#P = (nRT)/(V - nb)- (n^2a)/V^2#</mathjax></p> </blockquote> </blockquote> <p>For this problem,</p> <p><mathjax>#n = "1.00 mol"#</mathjax><br/> <mathjax>#R = "0.083 14"color(white)(l)"bar·L·K"^"-1""mol"^"-1"#</mathjax><br/> <mathjax>#T = "273.15 K"#</mathjax><br/> <mathjax>#V = "34.6 L"#</mathjax><br/> <mathjax>#a = "6.579 bar·L"^2"mol"^"-2"#</mathjax><br/> <mathjax>#b = "0.0562 L·mol"^"-1"#</mathjax></p> <p><mathjax>#P = (nRT)/(V-nb) – (n^2a)/V^2#</mathjax></p> <p><mathjax>#= (1.00 color(red)(cancel(color(black)("mol"))) × "0.083 14 bar"color(red)(cancel(color(black)("L·""K"^(-1)"mol"^(-1))))× 273.15 color(red)(cancel(color(black)("K"))))/(34.6 color(red)(cancel(color(black)("L"))) – 1.00 color(red)(cancel(color(black)("mol")))× 0.0562 color(red)(cancel(color(black)("L·mol"^(-1))))) - ((1.00 color(red)(cancel(color(black)("mol"))))^2 × "6.579 bar" color(red)(cancel(color(black)("L"^2"mol"^"-2"))))/(34.6 color(red)(cancel(color(black)("L"))))^2#</mathjax></p> <p><mathjax>#= "22.71 bar"/(34.6 - 0.0562) - "0.005 50 bar "= "0.6574 bar" - "0.005 50 bar"= "0.652 bar"#</mathjax></p> <p>The pressure predicted by the van der Waals equation is <strong>0.652 bar</strong>.</p> <p><strong>Note:</strong> The <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a> predicts a pressure of 0.656 bar. Under these conditions, chlorine is behaving almost like an ideal gas.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The pressure is 0.652 bar.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>I assume that you are treating the chlorine as a van der Waals gas.</p> <p>The <strong>van der Waals equation</strong> is</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(\|color(white)(a/a) (P + (n^2a)/V^2)(V - nb) = nRTcolor(white)(a/a)\|)))" "#</mathjax></p> <p><mathjax>#P + (n^2a)/V^2 = (nRT)/(V - nb)#</mathjax></p> <p><mathjax>#P = (nRT)/(V - nb)- (n^2a)/V^2#</mathjax></p> </blockquote> </blockquote> <p>For this problem,</p> <p><mathjax>#n = "1.00 mol"#</mathjax><br/> <mathjax>#R = "0.083 14"color(white)(l)"bar·L·K"^"-1""mol"^"-1"#</mathjax><br/> <mathjax>#T = "273.15 K"#</mathjax><br/> <mathjax>#V = "34.6 L"#</mathjax><br/> <mathjax>#a = "6.579 bar·L"^2"mol"^"-2"#</mathjax><br/> <mathjax>#b = "0.0562 L·mol"^"-1"#</mathjax></p> <p><mathjax>#P = (nRT)/(V-nb) – (n^2a)/V^2#</mathjax></p> <p><mathjax>#= (1.00 color(red)(cancel(color(black)("mol"))) × "0.083 14 bar"color(red)(cancel(color(black)("L·""K"^(-1)"mol"^(-1))))× 273.15 color(red)(cancel(color(black)("K"))))/(34.6 color(red)(cancel(color(black)("L"))) – 1.00 color(red)(cancel(color(black)("mol")))× 0.0562 color(red)(cancel(color(black)("L·mol"^(-1))))) - ((1.00 color(red)(cancel(color(black)("mol"))))^2 × "6.579 bar" color(red)(cancel(color(black)("L"^2"mol"^"-2"))))/(34.6 color(red)(cancel(color(black)("L"))))^2#</mathjax></p> <p><mathjax>#= "22.71 bar"/(34.6 - 0.0562) - "0.005 50 bar "= "0.6574 bar" - "0.005 50 bar"= "0.652 bar"#</mathjax></p> <p>The pressure predicted by the van der Waals equation is <strong>0.652 bar</strong>.</p> <p><strong>Note:</strong> The <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a> predicts a pressure of 0.656 bar. Under these conditions, chlorine is behaving almost like an ideal gas.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the pressure of 1.00 mole of #Cl_2# gas that is non-ideal, at a temperature of 0.0 deg C occupying a volume 34.6 L?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/gas-pressure" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Pressure</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="364217" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-01-14T01:33:00" itemprop="dateCreated"> Jan 14, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The pressure is 0.652 bar.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>I assume that you are treating the chlorine as a van der Waals gas.</p> <p>The <strong>van der Waals equation</strong> is</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(\|color(white)(a/a) (P + (n^2a)/V^2)(V - nb) = nRTcolor(white)(a/a)\|)))" "#</mathjax></p> <p><mathjax>#P + (n^2a)/V^2 = (nRT)/(V - nb)#</mathjax></p> <p><mathjax>#P = (nRT)/(V - nb)- (n^2a)/V^2#</mathjax></p> </blockquote> </blockquote> <p>For this problem,</p> <p><mathjax>#n = "1.00 mol"#</mathjax><br/> <mathjax>#R = "0.083 14"color(white)(l)"bar·L·K"^"-1""mol"^"-1"#</mathjax><br/> <mathjax>#T = "273.15 K"#</mathjax><br/> <mathjax>#V = "34.6 L"#</mathjax><br/> <mathjax>#a = "6.579 bar·L"^2"mol"^"-2"#</mathjax><br/> <mathjax>#b = "0.0562 L·mol"^"-1"#</mathjax></p> <p><mathjax>#P = (nRT)/(V-nb) – (n^2a)/V^2#</mathjax></p> <p><mathjax>#= (1.00 color(red)(cancel(color(black)("mol"))) × "0.083 14 bar"color(red)(cancel(color(black)("L·""K"^(-1)"mol"^(-1))))× 273.15 color(red)(cancel(color(black)("K"))))/(34.6 color(red)(cancel(color(black)("L"))) – 1.00 color(red)(cancel(color(black)("mol")))× 0.0562 color(red)(cancel(color(black)("L·mol"^(-1))))) - ((1.00 color(red)(cancel(color(black)("mol"))))^2 × "6.579 bar" color(red)(cancel(color(black)("L"^2"mol"^"-2"))))/(34.6 color(red)(cancel(color(black)("L"))))^2#</mathjax></p> <p><mathjax>#= "22.71 bar"/(34.6 - 0.0562) - "0.005 50 bar "= "0.6574 bar" - "0.005 50 bar"= "0.652 bar"#</mathjax></p> <p>The pressure predicted by the van der Waals equation is <strong>0.652 bar</strong>.</p> <p><strong>Note:</strong> The <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a> predicts a pressure of 0.656 bar. Under these conditions, chlorine is behaving almost like an ideal gas.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/364217" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-gas-pressure-be-changed"> How can gas pressure be changed? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-you-increase-gas-pressure-in-a-container"> How can you increase gas pressure in a container? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-gas-pressure-created"> How is gas pressure created? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-does-gas-pressure-increase-when-temperature-increases"> Why does gas pressure increase when temperature increases? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-gas-pressure-zero-at-absolute-zero"> Why is gas pressure zero at absolute zero? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-does-gas-pressure-increase-with-temperature"> Why does gas pressure increase with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-there-no-gas-pressure-in-a-vacuum"> Why is there no gas pressure in a vacuum? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-total-gas-pressure-in-a-sealed-flask-that-contains-oxygen-at-a-parti-1"> What is the total gas pressure in a sealed flask that contains oxygen at a partial pressure of... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-the-absolute-pressure-of-a-gas-is-550-280-kpa-what-is-its-gage-pressure"> If the absolute pressure of a gas is 550.280 kPa, what is its gage pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-a-gas-sample-occupies-4-2-l-at-a-pressure-of-101-kpa-what-volume-will-it-occu"> If a gas sample occupies 4.2 L at a pressure of 101 kPa. What volume will it occupy if the... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/gas-pressure"> See all questions in Gas Pressure </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1326 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the pressure of 1.00 mole of #Cl_2# gas that is non-ideal, at a temperature of 0.0 deg C occupying a volume 34.6 L?	null
1,586	a9737cd8-6ddd-11ea-bbdc-ccda262736ce	https://socratic.org/questions/given-a-2-2-m-mgcl-2-stock-solution-how-much-stock-solution-in-ml-would-be-neces	13.07 mL	start physical_unit 5 6 volume ml qc_end physical_unit 4 6 2 3 molarity qc_end physical_unit 6 6 18 19 volume qc_end end	[{"type":"physical unit","value":"Volume1 [OF] stock solution [IN] mL"}]	[{"type":"physical unit","value":"13.07 mL"}]	[{"type":"physical unit","value":"Molarity1 [OF] MgCl2 stock solution [=] \\pu{2.2 M}"},{"type":"physical unit","value":"Volume2 [OF] MgCl2 aqueous solution [=] \\pu{250 mL}"},{"type":"physical unit","value":"Molarity2 [OF] MgCl2 aqueous solution [=] \\pu{0.115 M}"}]	<h1 class="questionTitle" itemprop="name">Given a 2.2 M #MgCl_2# stock solution, how much stock solution (in mL) would be necessary to prepare 250 mL of aqueous 0.115 M #MgCl_2#?</h1>	null	13.07 mL	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><img alt="enter image source here" src="https://useruploads.socratic.org/rRHVkqTZQIStbIQ2Ip1a_1461665535060.jpg"/> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>13.06818182 ml solution</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><img alt="enter image source here" src="https://useruploads.socratic.org/rRHVkqTZQIStbIQ2Ip1a_1461665535060.jpg"/> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Given a 2.2 M #MgCl_2# stock solution, how much stock solution (in mL) would be necessary to prepare 250 mL of aqueous 0.115 M #MgCl_2#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/dilution-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">Dilution Calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="258873" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/neh-pandya"><img alt="" class="" src="https://profilepictures.socratic.org/h10GuyemTXFrz9fHsMsF_neh-logo.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/neh-pandya"> Neh Pandya </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-04-26T10:15:47" itemprop="dateCreated"> Apr 26, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>13.06818182 ml solution</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><img alt="enter image source here" src="https://useruploads.socratic.org/rRHVkqTZQIStbIQ2Ip1a_1461665535060.jpg"/> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/258873" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-concentration-from-absorbance"> How do you calculate concentration from absorbance? 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1,587	a991e0b4-6ddd-11ea-b057-ccda262736ce	https://socratic.org/questions/how-do-you-balance-co-oh-3-hno-3-co-no-3-3-h-2o	Co(OH)3 + 3 HNO3 -> Co(NO3)3 + 3 H2O	start chemical_equation qc_end chemical_equation 4 10 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the equation"}]	[{"type":"chemical equation","value":"Co(OH)3 + 3 HNO3 -> Co(NO3)3 + 3 H2O"}]	[{"type":"chemical equation","value":"Co(OH)3 + HNO3 -> Co(NO3)3 + H2O"}]	<h1 class="questionTitle" itemprop="name">How do you balance #Co(OH)_3 + HNO_3 -> Co(NO_3)_3 + H_2O#?</h1>	null	Co(OH)3 + 3 HNO3 -> Co(NO3)3 + 3 H2O	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You really have to know your complex ions for this one! </p> <p>On the left side of the equation we see, initially, one nitrate group (<mathjax>#NO_3#</mathjax>) On the right, we have three. So that means on the left we need three nitrate groups which means three <mathjax>#HNO_3#</mathjax> (aka nitric acids). </p> <p><mathjax>#Co(OH)_3#</mathjax> + <mathjax>#3HNO_3#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#Co(NO_3)_3#</mathjax> + <mathjax>#H_2O#</mathjax> (not balanced)</p> <p>Now, on the left side of the left side of the unbalanced equation we have six hydrogens, but on the right we only have two. We can fix that by putting a 3 coefficient in front of the water:</p> <p><mathjax>#Co(OH)_3#</mathjax> + <mathjax>#3HNO_3#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#Co(NO_3)_3#</mathjax> + <mathjax>#3H_2O#</mathjax></p> <p>Now we see that all the hydrogens balance out on both sides (six and six), all the nitrate groups balance out (three and three), the cobalt is balanced (one and one), and the oxygen (not counting the oxygen we have with the nitrate groups we already counted!) is also balanced (three and three). </p> <p>Notice what I did here: I treated the nitrate groups as distinct species and balanced them as a whole even though the nitrate group has both nitrogen and oxygen! If you think about it, you will probably realize that I could have done the same thing with the hydroxide groups--water is just a hydroxide group wiht an extra hydrogen.</p> <p>Now try a few and see if treating the complex ions as individual species works for you.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Co(OH)_3#</mathjax> + <mathjax>#3HNO_3#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#Co(NO_3)_3#</mathjax> + <mathjax>#3H_2O#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You really have to know your complex ions for this one! </p> <p>On the left side of the equation we see, initially, one nitrate group (<mathjax>#NO_3#</mathjax>) On the right, we have three. So that means on the left we need three nitrate groups which means three <mathjax>#HNO_3#</mathjax> (aka nitric acids). </p> <p><mathjax>#Co(OH)_3#</mathjax> + <mathjax>#3HNO_3#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#Co(NO_3)_3#</mathjax> + <mathjax>#H_2O#</mathjax> (not balanced)</p> <p>Now, on the left side of the left side of the unbalanced equation we have six hydrogens, but on the right we only have two. We can fix that by putting a 3 coefficient in front of the water:</p> <p><mathjax>#Co(OH)_3#</mathjax> + <mathjax>#3HNO_3#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#Co(NO_3)_3#</mathjax> + <mathjax>#3H_2O#</mathjax></p> <p>Now we see that all the hydrogens balance out on both sides (six and six), all the nitrate groups balance out (three and three), the cobalt is balanced (one and one), and the oxygen (not counting the oxygen we have with the nitrate groups we already counted!) is also balanced (three and three). </p> <p>Notice what I did here: I treated the nitrate groups as distinct species and balanced them as a whole even though the nitrate group has both nitrogen and oxygen! If you think about it, you will probably realize that I could have done the same thing with the hydroxide groups--water is just a hydroxide group wiht an extra hydrogen.</p> <p>Now try a few and see if treating the complex ions as individual species works for you.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you balance #Co(OH)_3 + HNO_3 -> Co(NO_3)_3 + H_2O#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="402157" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/andy-wolff"><img alt="" class="" src="https://profilepictures.socratic.org/GbR11eWOTFWVJhdGvFAL_1EhpiCmLTQaUVYrKxoji_Andy%2520Wolff%2520005_r1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/andy-wolff"> Andy Wolff </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-05T19:38:22" itemprop="dateCreated"> Apr 5, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Co(OH)_3#</mathjax> + <mathjax>#3HNO_3#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#Co(NO_3)_3#</mathjax> + <mathjax>#3H_2O#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You really have to know your complex ions for this one! </p> <p>On the left side of the equation we see, initially, one nitrate group (<mathjax>#NO_3#</mathjax>) On the right, we have three. So that means on the left we need three nitrate groups which means three <mathjax>#HNO_3#</mathjax> (aka nitric acids). </p> <p><mathjax>#Co(OH)_3#</mathjax> + <mathjax>#3HNO_3#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#Co(NO_3)_3#</mathjax> + <mathjax>#H_2O#</mathjax> (not balanced)</p> <p>Now, on the left side of the left side of the unbalanced equation we have six hydrogens, but on the right we only have two. We can fix that by putting a 3 coefficient in front of the water:</p> <p><mathjax>#Co(OH)_3#</mathjax> + <mathjax>#3HNO_3#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#Co(NO_3)_3#</mathjax> + <mathjax>#3H_2O#</mathjax></p> <p>Now we see that all the hydrogens balance out on both sides (six and six), all the nitrate groups balance out (three and three), the cobalt is balanced (one and one), and the oxygen (not counting the oxygen we have with the nitrate groups we already counted!) is also balanced (three and three). </p> <p>Notice what I did here: I treated the nitrate groups as distinct species and balanced them as a whole even though the nitrate group has both nitrogen and oxygen! If you think about it, you will probably realize that I could have done the same thing with the hydroxide groups--water is just a hydroxide group wiht an extra hydrogen.</p> <p>Now try a few and see if treating the complex ions as individual species works for you.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/402157" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------> H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -> Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? 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Sodium phosphate and calcium chloride react to form... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-equation-kclo3-kcl-o2"> How can I balance this equation? ____ #KClO_3 -># ____ #KCl +# ____ #O_2# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-balancing-chemical-equations-important"> Why is balancing chemical equations important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/balancing-chemical-equations"> See all questions in Balancing Chemical Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1365 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How do you balance #Co(OH)_3 + HNO_3 -> Co(NO_3)_3 + H_2O#?	null
1,588	acac5de3-6ddd-11ea-b3a8-ccda262736ce	https://socratic.org/questions/595e5fd9b72cff186eb5b199	2 Al(s) + 3 S(s) ->[\delta] Al2S3(s)	start chemical_equation qc_end substance 2 2 qc_end substance 4 4 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the equation"}]	[{"type":"chemical equation","value":"2 Al(s) + 3 S(s) ->[\\delta] Al2S3(s)"}]	[{"type":"substance name","value":"Sulfur"},{"type":"substance name","value":"Aluminum"}]	<h1 class="questionTitle" itemprop="name">How does sulfur oxidize aluminum?</h1>	null	2 Al(s) + 3 S(s) ->[\delta] Al2S3(s)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Sometimes you will see elemental sulfur formulated as <mathjax>#S_8#</mathjax>, in which case we would write......</p> <p><mathjax>#2Al(s) + 3/8S_8(s) stackrel(Delta)rarrAl_2S_3(s)#</mathjax>.......</p> <p>So 2 questions..........</p> <p><mathjax>#"(i) Is this an oxidation reduction reaction?"#</mathjax></p> <p><mathjax>#"(ii) This material is highly non-molecular. What does this mean?"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2Al(s) + 3S(s) stackrel(Delta)rarrAl_2S_3(s)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Sometimes you will see elemental sulfur formulated as <mathjax>#S_8#</mathjax>, in which case we would write......</p> <p><mathjax>#2Al(s) + 3/8S_8(s) stackrel(Delta)rarrAl_2S_3(s)#</mathjax>.......</p> <p>So 2 questions..........</p> <p><mathjax>#"(i) Is this an oxidation reduction reaction?"#</mathjax></p> <p><mathjax>#"(ii) This material is highly non-molecular. What does this mean?"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How does sulfur oxidize aluminum?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="448693" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-07-06T16:42:30" itemprop="dateCreated"> Jul 6, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2Al(s) + 3S(s) stackrel(Delta)rarrAl_2S_3(s)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Sometimes you will see elemental sulfur formulated as <mathjax>#S_8#</mathjax>, in which case we would write......</p> <p><mathjax>#2Al(s) + 3/8S_8(s) stackrel(Delta)rarrAl_2S_3(s)#</mathjax>.......</p> <p>So 2 questions..........</p> <p><mathjax>#"(i) Is this an oxidation reduction reaction?"#</mathjax></p> <p><mathjax>#"(ii) This material is highly non-molecular. What does this mean?"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/448693" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------> H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -> Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? 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1,589	a87b54e6-6ddd-11ea-881f-ccda262736ce	https://socratic.org/questions/how-many-milliliters-of-12-0-m-hcl-aq-are-needed-to-prepare-215-0-ml-of-1-00-m-h	17.9 milliliters	start physical_unit 6 7 volume ml qc_end physical_unit 6 7 12 13 volume qc_end physical_unit 6 7 4 5 molarity qc_end physical_unit 6 7 15 16 molarity qc_end end	[{"type":"physical unit","value":"Volume1 [OF] HCl (aq) [IN] milliliters"}]	[{"type":"physical unit","value":"17.9 milliliters"}]	[{"type":"physical unit","value":"Volume2 [OF] HCl (aq) [=] \\pu{215.0 mL}"},{"type":"physical unit","value":"Molarity1 [OF] HCl (aq) [=] \\pu{12.0 M}"},{"type":"physical unit","value":"Molarity2 [OF] HCl (aq) [=] \\pu{1.00 M}"}]	<h1 class="questionTitle" itemprop="name">How many milliliters of 12.0 M #HCl# (aq) are needed to prepare 215.0 mL of 1.00 M #HCl# (aq)?</h1>	null	17.9 milliliters	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use the relationship <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> = no. of moles / no. of litres.<br/> Then rearrange for no. of moles = no. of litres x molarity<br/> and no. of litres no. of moles / molarity.</p> <p>215 ml of 1 M HCl (aq) contains (0.215 x 1) = 0.215 moles of HCl.</p> <p>The no. of ml of 12 M HCl (aq) that contains 0.215 mol of HCl is (0.215 /12) = 0.0179 litre = 17.9 ml.</p> <p>Therefore you would use 17.9 ml of 12 M HCl,and then dilute up to total volume 215 ml with water.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>17.9 ml</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use the relationship <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> = no. of moles / no. of litres.<br/> Then rearrange for no. of moles = no. of litres x molarity<br/> and no. of litres no. of moles / molarity.</p> <p>215 ml of 1 M HCl (aq) contains (0.215 x 1) = 0.215 moles of HCl.</p> <p>The no. of ml of 12 M HCl (aq) that contains 0.215 mol of HCl is (0.215 /12) = 0.0179 litre = 17.9 ml.</p> <p>Therefore you would use 17.9 ml of 12 M HCl,and then dilute up to total volume 215 ml with water.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many milliliters of 12.0 M #HCl# (aq) are needed to prepare 215.0 mL of 1.00 M #HCl# (aq)?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/dilution-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">Dilution Calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="267041" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/simon-moore"><img alt="" class="" src="https://profilepictures.socratic.org/0ztdJJ7RCWUlBSPeGa9N_6EB6CADA-35F5-4BAA-9B66-9D6F64A622BA.jpeg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/simon-moore"> Simon Moore </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-18T10:52:53" itemprop="dateCreated"> May 18, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>17.9 ml</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use the relationship <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> = no. of moles / no. of litres.<br/> Then rearrange for no. of moles = no. of litres x molarity<br/> and no. of litres no. of moles / molarity.</p> <p>215 ml of 1 M HCl (aq) contains (0.215 x 1) = 0.215 moles of HCl.</p> <p>The no. of ml of 12 M HCl (aq) that contains 0.215 mol of HCl is (0.215 /12) = 0.0179 litre = 17.9 ml.</p> <p>Therefore you would use 17.9 ml of 12 M HCl,and then dilute up to total volume 215 ml with water.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/267041" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-concentration-from-absorbance"> How do you calculate concentration from absorbance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-concentration-from-titration"> How do you calculate concentration from titration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" 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order to... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/dilution-calculations"> See all questions in Dilution Calculations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 44570 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many milliliters of 12.0 M #HCl# (aq) are needed to prepare 215.0 mL of 1.00 M #HCl# (aq)?	null
1,590	a8b9b14c-6ddd-11ea-af3b-ccda262736ce	https://socratic.org/questions/what-is-the-empirical-formula-of-a-compound-containing-60-0-g-sulfur-and-40-0-g-	SO3	start chemical_formula qc_end physical_unit 11 11 9 10 mass qc_end physical_unit 15 15 13 14 mass qc_end end	[{"type":"other","value":"Chemical Formula [OF] the compound [IN] empirical"}]	[{"type":"chemical equation","value":"SO3"}]	[{"type":"physical unit","value":"Mass [OF] sulfur [=] \\pu{60.0 g}"},{"type":"physical unit","value":"Mass [OF] oxygen [=] \\pu{90.0 g}"}]	<h1 class="questionTitle" itemprop="name">What is the empirical formula of a compound containing 60.0 g sulfur and 90.0 g oxygen? </h1>	null	SO3	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your strategy here will be to use <strong>molar masses</strong> of the two <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> to determine how many <em>moles</em> of each you have present in this sample. </p> <p>Once you know that, use the number of moles of sulfur and oxygen to determine the <strong>smallest whole number ratio</strong> that exists between the two elements in the compound. </p> <p>So, sulfur has a molar mass of <mathjax>#"32.065 g mol"^(-1)#</mathjax>, which means that <strong>one mole</strong> of sulfur has a mass of <mathjax>#"32.065 g"#</mathjax>. </p> <p>Your sample will thus contain </p> <blockquote> <p><mathjax>#60.0 color(red)(cancel(color(black)("g"))) * "1 mole S"/(32.065color(red)(cancel(color(black)("g")))) = "1.8712 moles S"#</mathjax></p> </blockquote> <p>Oxygen has molar mass of <mathjax>#"15.9994 g mol"^(-1)#</mathjax>, which means that <strong>one mole</strong> of oxygen will have a mass of <mathjax>#"15.9994 g"#</mathjax>. </p> <p>Your sample will contain </p> <blockquote> <p><mathjax>#90.0 color(red)(cancel(color(black)("g"))) * "1 mole O"/(15.9994color(red)(cancel(color(black)("g")))) = "5.6525 moles O"#</mathjax></p> </blockquote> <p>Now, a compound's <em>empirical formula</em> tells you the <strong>smallest whole number ratio</strong> that exists between the compound's constituent elements. </p> <p>To get <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio that exists between sulfur and oxygen in this compound, divide both values by the <em>smallest one</em></p> <blockquote> <p><mathjax>#"For S: " (1.8712 color(red)(cancel(color(black)("moles"))))/(1.8712color(red)(cancel(color(black)("moles")))) = 1#</mathjax></p> <p><mathjax>#"For O: " (5.6525color(red)(cancel(color(black)("moles"))))/(1.8712color(red)(cancel(color(black)("moles")))) = 3.021 ~~ 3#</mathjax></p> </blockquote> <p>Since <mathjax>#1:3#</mathjax> is the smallest whole number ratio that can exist between the two elements, it follows that the compound's empirical formula will be </p> <blockquote> <p><mathjax>#color(green)(\|bar(ul(color(white)(a/a)"S"_1"O"_3 implies "SO"_3color(white)(a/a)\|)))#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"SO"_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your strategy here will be to use <strong>molar masses</strong> of the two <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> to determine how many <em>moles</em> of each you have present in this sample. </p> <p>Once you know that, use the number of moles of sulfur and oxygen to determine the <strong>smallest whole number ratio</strong> that exists between the two elements in the compound. </p> <p>So, sulfur has a molar mass of <mathjax>#"32.065 g mol"^(-1)#</mathjax>, which means that <strong>one mole</strong> of sulfur has a mass of <mathjax>#"32.065 g"#</mathjax>. </p> <p>Your sample will thus contain </p> <blockquote> <p><mathjax>#60.0 color(red)(cancel(color(black)("g"))) * "1 mole S"/(32.065color(red)(cancel(color(black)("g")))) = "1.8712 moles S"#</mathjax></p> </blockquote> <p>Oxygen has molar mass of <mathjax>#"15.9994 g mol"^(-1)#</mathjax>, which means that <strong>one mole</strong> of oxygen will have a mass of <mathjax>#"15.9994 g"#</mathjax>. </p> <p>Your sample will contain </p> <blockquote> <p><mathjax>#90.0 color(red)(cancel(color(black)("g"))) * "1 mole O"/(15.9994color(red)(cancel(color(black)("g")))) = "5.6525 moles O"#</mathjax></p> </blockquote> <p>Now, a compound's <em>empirical formula</em> tells you the <strong>smallest whole number ratio</strong> that exists between the compound's constituent elements. </p> <p>To get <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio that exists between sulfur and oxygen in this compound, divide both values by the <em>smallest one</em></p> <blockquote> <p><mathjax>#"For S: " (1.8712 color(red)(cancel(color(black)("moles"))))/(1.8712color(red)(cancel(color(black)("moles")))) = 1#</mathjax></p> <p><mathjax>#"For O: " (5.6525color(red)(cancel(color(black)("moles"))))/(1.8712color(red)(cancel(color(black)("moles")))) = 3.021 ~~ 3#</mathjax></p> </blockquote> <p>Since <mathjax>#1:3#</mathjax> is the smallest whole number ratio that can exist between the two elements, it follows that the compound's empirical formula will be </p> <blockquote> <p><mathjax>#color(green)(\|bar(ul(color(white)(a/a)"S"_1"O"_3 implies "SO"_3color(white)(a/a)\|)))#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the empirical formula of a compound containing 60.0 g sulfur and 90.0 g oxygen? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="257990" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-04-24T00:26:11" itemprop="dateCreated"> Apr 24, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"SO"_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your strategy here will be to use <strong>molar masses</strong> of the two <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> to determine how many <em>moles</em> of each you have present in this sample. </p> <p>Once you know that, use the number of moles of sulfur and oxygen to determine the <strong>smallest whole number ratio</strong> that exists between the two elements in the compound. </p> <p>So, sulfur has a molar mass of <mathjax>#"32.065 g mol"^(-1)#</mathjax>, which means that <strong>one mole</strong> of sulfur has a mass of <mathjax>#"32.065 g"#</mathjax>. </p> <p>Your sample will thus contain </p> <blockquote> <p><mathjax>#60.0 color(red)(cancel(color(black)("g"))) * "1 mole S"/(32.065color(red)(cancel(color(black)("g")))) = "1.8712 moles S"#</mathjax></p> </blockquote> <p>Oxygen has molar mass of <mathjax>#"15.9994 g mol"^(-1)#</mathjax>, which means that <strong>one mole</strong> of oxygen will have a mass of <mathjax>#"15.9994 g"#</mathjax>. </p> <p>Your sample will contain </p> <blockquote> <p><mathjax>#90.0 color(red)(cancel(color(black)("g"))) * "1 mole O"/(15.9994color(red)(cancel(color(black)("g")))) = "5.6525 moles O"#</mathjax></p> </blockquote> <p>Now, a compound's <em>empirical formula</em> tells you the <strong>smallest whole number ratio</strong> that exists between the compound's constituent elements. </p> <p>To get <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio that exists between sulfur and oxygen in this compound, divide both values by the <em>smallest one</em></p> <blockquote> <p><mathjax>#"For S: " (1.8712 color(red)(cancel(color(black)("moles"))))/(1.8712color(red)(cancel(color(black)("moles")))) = 1#</mathjax></p> <p><mathjax>#"For O: " (5.6525color(red)(cancel(color(black)("moles"))))/(1.8712color(red)(cancel(color(black)("moles")))) = 3.021 ~~ 3#</mathjax></p> </blockquote> <p>Since <mathjax>#1:3#</mathjax> is the smallest whole number ratio that can exist between the two elements, it follows that the compound's empirical formula will be </p> <blockquote> <p><mathjax>#color(green)(\|bar(ul(color(white)(a/a)"S"_1"O"_3 implies "SO"_3color(white)(a/a)\|)))#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/257990" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molecular-formula-of-a-compound"> How do you find molecular formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-diamond"> What is the chemical 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</div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the empirical formula of a compound containing 60.0 g sulfur and 90.0 g oxygen?	null
1,591	abf3afd2-6ddd-11ea-83ba-ccda262736ce	https://socratic.org/questions/how-many-grams-of-naoh-are-in-500-ml-of-0-175-m-naoh-solution	3.50 grams	start physical_unit 4 4 mass g qc_end physical_unit 12 13 7 8 volume qc_end physical_unit 12 13 10 11 molarity qc_end end	[{"type":"physical unit","value":"Mass [OF] NaOH [IN] grams"}]	[{"type":"physical unit","value":"3.50 grams"}]	[{"type":"physical unit","value":"Volume [OF] NaOH solution [=] \\pu{500 mL}"},{"type":"physical unit","value":"Molarity [OF] NaOH solution [=] \\pu{0.175 M}"}]	<h1 class="questionTitle" itemprop="name">How many grams of #NaOH# are in 500 mL of 0.175 M #NaOH# solution?</h1>	null	3.50 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Concentration"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Moles"/"Volume of solution"#</mathjax>.</p> <p>Thus <mathjax>#n_"NaOH"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#500xx10^-3cancelLxx0.175molcancel(L^-1)=0.0875mol#</mathjax>. (i.e., <mathjax>#"moles"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"volume "xx" concentration"#</mathjax>); this is certainly consistent dimensionally. </p> <p>We thus have a quantity in moles of <mathjax>#NaOH#</mathjax>. All we have to do is multiply this molar quantity by the molar mass:</p> <p><mathjax>#40.00gcancel(mol^-1)xx0.0875cancel(mol)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??g#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Under <mathjax>#4.0g#</mathjax> of sodium hydroxide.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Concentration"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Moles"/"Volume of solution"#</mathjax>.</p> <p>Thus <mathjax>#n_"NaOH"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#500xx10^-3cancelLxx0.175molcancel(L^-1)=0.0875mol#</mathjax>. (i.e., <mathjax>#"moles"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"volume "xx" concentration"#</mathjax>); this is certainly consistent dimensionally. </p> <p>We thus have a quantity in moles of <mathjax>#NaOH#</mathjax>. All we have to do is multiply this molar quantity by the molar mass:</p> <p><mathjax>#40.00gcancel(mol^-1)xx0.0875*cancel(mol)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??g#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many grams of #NaOH# are in 500 mL of 0.175 M #NaOH# solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="283790" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-02T07:59:39" itemprop="dateCreated"> Jul 2, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Under <mathjax>#4.0g#</mathjax> of sodium hydroxide.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Concentration"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Moles"/"Volume of solution"#</mathjax>.</p> <p>Thus <mathjax>#n_"NaOH"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#500xx10^-3cancelLxx0.175molcancel(L^-1)=0.0875mol#</mathjax>. (i.e., <mathjax>#"moles"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"volume "xx" concentration"#</mathjax>); this is certainly consistent dimensionally. </p> <p>We thus have a quantity in moles of <mathjax>#NaOH#</mathjax>. All we have to do is multiply this molar quantity by the molar mass:</p> <p><mathjax>#40.00gcancel(mol^-1)xx0.0875*cancel(mol)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??g#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/283790" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-morality-be-used-as-a-conversion-factor"> How can molarity be used as a conversion factor? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-high-can-molarity-be"> How high can molarity be? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-molarity-change-with-temperature"> How does molarity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molarity-of-a-solution"> How do you find molarity of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-10-naoh"> What is the molarity of 10 NaOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-3-hydrogen-peroxide"> What is the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 33313 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many grams of #NaOH# are in 500 mL of 0.175 M #NaOH# solution?	null
1,592	a90cddbe-6ddd-11ea-b072-ccda262736ce	https://socratic.org/questions/ibuprofen-a-common-pain-remedy-has-an-empirical-formula-of-c-7h-9o-and-a-molar-m	C14H18O2	start chemical_formula qc_end physical_unit 0 0 17 18 molar_mass qc_end c_other OTHER qc_end end	[{"type":"other","value":"Chemical Formula [OF] ibuprofen [IN] molecular"}]	[{"type":"chemical equation","value":"C14H18O2"}]	[{"type":"physical unit","value":"Molar mass [OF] ibuprofen [=] \\pu{218.078 grams}"},{"type":"other","value":"Ibuprofen has an empirical formula of C7H9O."}]	<h1 class="questionTitle" itemprop="name">Ibuprofen, a common pain remedy, has an empirical formula of #C_7H_9O# and a molar mass of approximately 218.078 grams per mole. What is the molecular formula of ibuprofen? </h1>	null	C14H18O2	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The empirical formula is the simplest ratio of Ibuprofen, which in this case is 7:9:1. </p> <p>To find the molecular formula, you need to find an integer, or a number which you multiply the empirical formula ratio with. To do this, just know this simple equation: </p> <p>n<mathjax>#=#</mathjax> Molar mass of MF<mathjax>#-:#</mathjax>Molar mass of EF</p> <p>'n' represents the numerical integer. </p> <p>Since the molar mass of the molecular formula is given to you (218.078 grams), all we need to find is the molar mass of the empirical formula. The empirical formula has 7 carbon atoms, 9 hydrogen atoms and 1 oxygen atom. </p> <p>As a result, our calculation would look like this:</p> <p>(7 x 12.011) + (9 x 1.008) + (1 x 16)</p> <p>We would get something near 109.149. Now back to our equation for the integer, we simply divide the given molar mass by the molar mass of the empirical formula, and we would get something around 1.99. </p> <p>Keep in mind that in molecular/ empirical formula problems, the integer is always rounded to the nearest whole number unless it is too far away (i.e, 1.5) (which in that case, it is multiplied by another whole number). However, in our problem, 1.99 is close enough to 2 that we can call it 2. </p> <p>Now that we have our integer, we simply multiply each ratio whole number from the empirical formula with 2. As a result, we get <mathjax>#C_14H_18O_2#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_14H_18O_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The empirical formula is the simplest ratio of Ibuprofen, which in this case is 7:9:1. </p> <p>To find the molecular formula, you need to find an integer, or a number which you multiply the empirical formula ratio with. To do this, just know this simple equation: </p> <p>n<mathjax>#=#</mathjax> Molar mass of MF<mathjax>#-:#</mathjax>Molar mass of EF</p> <p>'n' represents the numerical integer. </p> <p>Since the molar mass of the molecular formula is given to you (218.078 grams), all we need to find is the molar mass of the empirical formula. The empirical formula has 7 carbon atoms, 9 hydrogen atoms and 1 oxygen atom. </p> <p>As a result, our calculation would look like this:</p> <p>(7 x 12.011) + (9 x 1.008) + (1 x 16)</p> <p>We would get something near 109.149. Now back to our equation for the integer, we simply divide the given molar mass by the molar mass of the empirical formula, and we would get something around 1.99. </p> <p>Keep in mind that in molecular/ empirical formula problems, the integer is always rounded to the nearest whole number unless it is too far away (i.e, 1.5) (which in that case, it is multiplied by another whole number). However, in our problem, 1.99 is close enough to 2 that we can call it 2. </p> <p>Now that we have our integer, we simply multiply each ratio whole number from the empirical formula with 2. As a result, we get <mathjax>#C_14H_18O_2#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Ibuprofen, a common pain remedy, has an empirical formula of #C_7H_9O# and a molar mass of approximately 218.078 grams per mole. What is the molecular formula of ibuprofen? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="353045" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/jae-hwan-c"><img alt="" class="" src="https://profilepictures.socratic.org/3tM5UY1RSXGZx2k9PIRO_education.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/jae-hwan-c"> Jacob C. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-12-17T02:20:13" itemprop="dateCreated"> Dec 17, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_14H_18O_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The empirical formula is the simplest ratio of Ibuprofen, which in this case is 7:9:1. </p> <p>To find the molecular formula, you need to find an integer, or a number which you multiply the empirical formula ratio with. To do this, just know this simple equation: </p> <p>n<mathjax>#=#</mathjax> Molar mass of MF<mathjax>#-:#</mathjax>Molar mass of EF</p> <p>'n' represents the numerical integer. </p> <p>Since the molar mass of the molecular formula is given to you (218.078 grams), all we need to find is the molar mass of the empirical formula. The empirical formula has 7 carbon atoms, 9 hydrogen atoms and 1 oxygen atom. </p> <p>As a result, our calculation would look like this:</p> <p>(7 x 12.011) + (9 x 1.008) + (1 x 16)</p> <p>We would get something near 109.149. Now back to our equation for the integer, we simply divide the given molar mass by the molar mass of the empirical formula, and we would get something around 1.99. </p> <p>Keep in mind that in molecular/ empirical formula problems, the integer is always rounded to the nearest whole number unless it is too far away (i.e, 1.5) (which in that case, it is multiplied by another whole number). However, in our problem, 1.99 is close enough to 2 that we can call it 2. </p> <p>Now that we have our integer, we simply multiply each ratio whole number from the empirical formula with 2. As a result, we get <mathjax>#C_14H_18O_2#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/353045" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molecular-formula-of-a-compound"> How do you find molecular formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-diamond"> What is the chemical formula of a diamond? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-carbohydrate"> What is the chemical formula of a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-valproic-acid"> What is the empirical formula for valproic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-of-magnesium-oxide"> What is the empirical formula of magnesium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-empirical-formula-not-double-that-of-the-monosaccharides"> Why is the empirical formula not double that of the monosaccharides? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5331180502bf342f40b5c3b5"> Question #5c3b5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-molecular-formula-represents-a-carbohydrate"> What molecular formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-of-vinegar"> What is the molecular formula of vinegar? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/empirical-and-molecular-formulas"> See all questions in Empirical and Molecular Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 8095 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Ibuprofen, a common pain remedy, has an empirical formula of #C_7H_9O# and a molar mass of approximately 218.078 grams per mole. What is the molecular formula of ibuprofen?	null
1,593	ab7694b5-6ddd-11ea-9f88-ccda262736ce	https://socratic.org/questions/how-would-you-balance-the-following-equation-h3po4-mg-oh-2-mg3-po4-2-h20-1	2 H3PO4 + 3 Mg(OH)2 -> Mg3(PO4)2 + 6 H2O	start chemical_equation qc_end chemical_equation 7 13 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the equation"}]	[{"type":"chemical equation","value":"2 H3PO4 + 3 Mg(OH)2 -> Mg3(PO4)2 + 6 H2O"}]	[{"type":"chemical equation","value":"H3PO4 + Mg(OH)2 -> Mg3(PO4)2 + H2O"}]	<h1 class="questionTitle" itemprop="name">How would you balance the following equation: H3PO4 +Mg(OH)2 --> Mg3(PO4)2 +H20?</h1>	null	2 H3PO4 + 3 Mg(OH)2 -> Mg3(PO4)2 + 6 H2O	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"H"_3"PO"_4" + Mg(OH)"_2#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"Mg"_3"(PO"_4)_2 + "H"_2"O"#</mathjax></p> <p>Balance the magnesium first. There are three magnesium ions on the right side and only one on the left side. Add a coefficient of <mathjax>#3#</mathjax> in front of <mathjax>#"Mg(OH)"_2"#</mathjax>..</p> <p><mathjax>#"H"_3"PO"_4" + 3Mg(OH)"_2#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"Mg"_3"(PO"_4)_2 + "H"_2"O"#</mathjax></p> <p>Next balance the <mathjax>#"PO"_4"#</mathjax>.</p> <p>There are two <mathjax>#"PO"_4"#</mathjax> ions on the right side and one on the left. Place a coefficient of <mathjax>#2#</mathjax> in front of <mathjax>#"H"_3"PO"_4"#</mathjax>. </p> <p><mathjax>#"2H"_3"PO"_4" + 3Mg(OH)"_2#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"Mg"_3"(PO"_4)_2 + "H"_2"O"#</mathjax></p> <p>Next balance the <mathjax>#"H"#</mathjax>. There are twelve hydrogens on the left side and two on the right. Place a coefficient of <mathjax>#6#</mathjax> in front of <mathjax>#"H"_2"O"#</mathjax> on the right side.</p> <p><mathjax>#"2H"_3"PO"_4" + 3Mg(OH)"_2#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"Mg"_3"(PO"_4)_2 + "6H"_2"O"#</mathjax></p> <p>Balance the <mathjax>#"O"#</mathjax>. There are fourteen oxygen atoms on both sides of the equation, so it is already balanced.</p> <p>Balanced Equation</p> <p><mathjax>#"2H"_3"PO"_4" + 3Mg(OH)"_2#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"Mg"_3"(PO"_4)_2 + "6H"_2"O"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Balanced Equation</p> <p><mathjax>#"2H"_3"PO"_4" + 3Mg(OH)"_2#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"Mg"_3"(PO"_4)_2 + "6H"_2"O"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"H"_3"PO"_4" + Mg(OH)"_2#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"Mg"_3"(PO"_4)_2 + "H"_2"O"#</mathjax></p> <p>Balance the magnesium first. There are three magnesium ions on the right side and only one on the left side. Add a coefficient of <mathjax>#3#</mathjax> in front of <mathjax>#"Mg(OH)"_2"#</mathjax>..</p> <p><mathjax>#"H"_3"PO"_4" + 3Mg(OH)"_2#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"Mg"_3"(PO"_4)_2 + "H"_2"O"#</mathjax></p> <p>Next balance the <mathjax>#"PO"_4"#</mathjax>.</p> <p>There are two <mathjax>#"PO"_4"#</mathjax> ions on the right side and one on the left. Place a coefficient of <mathjax>#2#</mathjax> in front of <mathjax>#"H"_3"PO"_4"#</mathjax>. </p> <p><mathjax>#"2H"_3"PO"_4" + 3Mg(OH)"_2#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"Mg"_3"(PO"_4)_2 + "H"_2"O"#</mathjax></p> <p>Next balance the <mathjax>#"H"#</mathjax>. There are twelve hydrogens on the left side and two on the right. Place a coefficient of <mathjax>#6#</mathjax> in front of <mathjax>#"H"_2"O"#</mathjax> on the right side.</p> <p><mathjax>#"2H"_3"PO"_4" + 3Mg(OH)"_2#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"Mg"_3"(PO"_4)_2 + "6H"_2"O"#</mathjax></p> <p>Balance the <mathjax>#"O"#</mathjax>. There are fourteen oxygen atoms on both sides of the equation, so it is already balanced.</p> <p>Balanced Equation</p> <p><mathjax>#"2H"_3"PO"_4" + 3Mg(OH)"_2#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"Mg"_3"(PO"_4)_2 + "6H"_2"O"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How would you balance the following equation: H3PO4 +Mg(OH)2 --> Mg3(PO4)2 +H20?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="184396" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-05T23:29:34" itemprop="dateCreated"> Nov 5, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Balanced Equation</p> <p><mathjax>#"2H"_3"PO"_4" + 3Mg(OH)"_2#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"Mg"_3"(PO"_4)_2 + "6H"_2"O"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"H"_3"PO"_4" + Mg(OH)"_2#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"Mg"_3"(PO"_4)_2 + "H"_2"O"#</mathjax></p> <p>Balance the magnesium first. There are three magnesium ions on the right side and only one on the left side. Add a coefficient of <mathjax>#3#</mathjax> in front of <mathjax>#"Mg(OH)"_2"#</mathjax>..</p> <p><mathjax>#"H"_3"PO"_4" + 3Mg(OH)"_2#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"Mg"_3"(PO"_4)_2 + "H"_2"O"#</mathjax></p> <p>Next balance the <mathjax>#"PO"_4"#</mathjax>.</p> <p>There are two <mathjax>#"PO"_4"#</mathjax> ions on the right side and one on the left. Place a coefficient of <mathjax>#2#</mathjax> in front of <mathjax>#"H"_3"PO"_4"#</mathjax>. </p> <p><mathjax>#"2H"_3"PO"_4" + 3Mg(OH)"_2#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"Mg"_3"(PO"_4)_2 + "H"_2"O"#</mathjax></p> <p>Next balance the <mathjax>#"H"#</mathjax>. There are twelve hydrogens on the left side and two on the right. Place a coefficient of <mathjax>#6#</mathjax> in front of <mathjax>#"H"_2"O"#</mathjax> on the right side.</p> <p><mathjax>#"2H"_3"PO"_4" + 3Mg(OH)"_2#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"Mg"_3"(PO"_4)_2 + "6H"_2"O"#</mathjax></p> <p>Balance the <mathjax>#"O"#</mathjax>. There are fourteen oxygen atoms on both sides of the equation, so it is already balanced.</p> <p>Balanced Equation</p> <p><mathjax>#"2H"_3"PO"_4" + 3Mg(OH)"_2#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"Mg"_3"(PO"_4)_2 + "6H"_2"O"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/184396" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------> H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -> Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? 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Sodium phosphate and calcium chloride react to form... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-equation-kclo3-kcl-o2"> How can I balance this equation? ____ #KClO_3 -># ____ #KCl +# ____ #O_2# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-balancing-chemical-equations-important"> Why is balancing chemical equations important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/balancing-chemical-equations"> See all questions in Balancing Chemical Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 12476 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How would you balance the following equation: H3PO4 +Mg(OH)2 --> Mg3(PO4)2 +H20?	null
1,594	aaafbbbb-6ddd-11ea-8c16-ccda262736ce	https://socratic.org/questions/2al-zn-no3-2-2al-no3-3-zn-net-ionic-equation	2 Al + 3 Zn^2+ -> 2 Al^3+ + 3 Zn	start chemical_equation qc_end chemical_equation 0 8 qc_end end	[{"type":"other","value":"Chemical Equation [OF] net ionic equation"}]	[{"type":"chemical equation","value":"2 Al + 3 Zn^2+ -> 2 Al^3+ + 3 Zn"}]	[{"type":"chemical equation","value":"2 Al + Zn(NO3)2 -> 2 Al(NO3)3 + Zn"}]	<h1 class="questionTitle" itemprop="name">2Al+Zn(NO3)2=2Al(NO3)3+Zn net ionic equation?</h1>	null	2 Al + 3 Zn^2+ -> 2 Al^3+ + 3 Zn	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The equation given above is wrongly balanced, so I have to correct it first.</p> <p><mathjax>#Al^@#</mathjax> + <mathjax>#Zn(NO_3)_2#</mathjax> = <mathjax>#Al(NO_3)_3#</mathjax> + <mathjax>#Zn^@#</mathjax> (unbalanced)</p> <p>Tallying the atoms based on subscripts,</p> <p>left side: <mathjax>#Al#</mathjax> = 1; <mathjax>#Zn#</mathjax> = 1; <mathjax>#(NO_3)_3#</mathjax> = 2<br/> right side: <mathjax>#Al#</mathjax> = 1; <mathjax>#Zn#</mathjax> = 1; <mathjax>#(NO_3)_3#</mathjax> = 3</p> <p>Notice that I am considering the <mathjax>#NO_3^-#</mathjax> ion as one "atom" in order to avoid confusing myself.</p> <p>Balancing the equations we have:</p> <p><mathjax>#color (blue) 2Al^@ (s) #</mathjax> + <mathjax>#color (red) 3 Zn(NO_3)_2#</mathjax> = <mathjax>#color (green) 2Al(NO_3)_3#</mathjax> + <mathjax>#color (magenta) 3Zn^@ (s)#</mathjax> (balanced)</p> <p>left side: <mathjax>#Al#</mathjax> = (1 x <mathjax>#color (blue) 2#</mathjax>) = <strong>2</strong>; <mathjax>#Zn#</mathjax> = (1 x <mathjax>#color (red) 3#</mathjax>) = <strong>3</strong>; <mathjax>#(NO_3)_3#</mathjax> = (2 x <mathjax>#color (red) 3#</mathjax>) = <strong>6</strong><br/> right side: <mathjax>#Al#</mathjax> = (1x <mathjax>#color (green) 2#</mathjax>) = <strong>2</strong>; <mathjax>#Zn#</mathjax> = (1 x <mathjax>#color (magenta) 3#</mathjax>) = <strong>3</strong>; <mathjax>#(NO_3)_3#</mathjax> = (3 x <mathjax>#color (green) 2#</mathjax>) = <strong>6</strong></p> <p>Now that we have the correct balance equation, we must rewrite the equation showing all the ions involved in the reaction.</p> <p><mathjax>#2Al^@ (s) #</mathjax> + <mathjax>#3Zn^"2+"#</mathjax> + <mathjax>#6NO_3^-#</mathjax> = <mathjax>#2Al^"3+"#</mathjax> + <mathjax>#6NO_3^-#</mathjax> + <mathjax>#3Zn^@ (s)#</mathjax> </p> <p>Notice that for the <mathjax>#NO_3^-#</mathjax>, I multiply the subscript with the substance's coefficient. Now let us get rid of your spectator ions (ions that are present in both sides of the equation).</p> <p><mathjax>#2Al^@ (s) #</mathjax> + <mathjax>#3Zn^"2+"#</mathjax> + <mathjax>#cancel (6NO_3^-)#</mathjax> = <mathjax>#2Al^"3+"#</mathjax> + <mathjax>#cancel (6NO_3^-)#</mathjax> + <mathjax>#3Zn^@ (s)#</mathjax> </p> <p>Now let's show the electrons per half-reaction:</p> <p><mathjax>#2Al^@ (s) #</mathjax> = <mathjax>#2Al^"3+"#</mathjax> + <mathjax>#6e^-#</mathjax> </p> <p><mathjax>#3Zn^"2+"#</mathjax> + <mathjax>#6e^-#</mathjax> = <mathjax>#3Zn^@ (s)#</mathjax> </p> <p>Thus, the net ionic equation is </p> <p><mathjax>#2Al^@ (s)#</mathjax> + <mathjax>#3Zn^"2+"#</mathjax> = <mathjax>#2Al^"3+"#</mathjax> + <mathjax>#3Zn^@ (s)#</mathjax> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2Al^@ (s)#</mathjax> + <mathjax>#3Zn^"2+"#</mathjax> = <mathjax>#2Al^"3+"#</mathjax> + <mathjax>#3Zn^@ (s)#</mathjax> (net ionic equation)</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The equation given above is wrongly balanced, so I have to correct it first.</p> <p><mathjax>#Al^@#</mathjax> + <mathjax>#Zn(NO_3)_2#</mathjax> = <mathjax>#Al(NO_3)_3#</mathjax> + <mathjax>#Zn^@#</mathjax> (unbalanced)</p> <p>Tallying the atoms based on subscripts,</p> <p>left side: <mathjax>#Al#</mathjax> = 1; <mathjax>#Zn#</mathjax> = 1; <mathjax>#(NO_3)_3#</mathjax> = 2<br/> right side: <mathjax>#Al#</mathjax> = 1; <mathjax>#Zn#</mathjax> = 1; <mathjax>#(NO_3)_3#</mathjax> = 3</p> <p>Notice that I am considering the <mathjax>#NO_3^-#</mathjax> ion as one "atom" in order to avoid confusing myself.</p> <p>Balancing the equations we have:</p> <p><mathjax>#color (blue) 2Al^@ (s) #</mathjax> + <mathjax>#color (red) 3 Zn(NO_3)_2#</mathjax> = <mathjax>#color (green) 2Al(NO_3)_3#</mathjax> + <mathjax>#color (magenta) 3Zn^@ (s)#</mathjax> (balanced)</p> <p>left side: <mathjax>#Al#</mathjax> = (1 x <mathjax>#color (blue) 2#</mathjax>) = <strong>2</strong>; <mathjax>#Zn#</mathjax> = (1 x <mathjax>#color (red) 3#</mathjax>) = <strong>3</strong>; <mathjax>#(NO_3)_3#</mathjax> = (2 x <mathjax>#color (red) 3#</mathjax>) = <strong>6</strong><br/> right side: <mathjax>#Al#</mathjax> = (1x <mathjax>#color (green) 2#</mathjax>) = <strong>2</strong>; <mathjax>#Zn#</mathjax> = (1 x <mathjax>#color (magenta) 3#</mathjax>) = <strong>3</strong>; <mathjax>#(NO_3)_3#</mathjax> = (3 x <mathjax>#color (green) 2#</mathjax>) = <strong>6</strong></p> <p>Now that we have the correct balance equation, we must rewrite the equation showing all the ions involved in the reaction.</p> <p><mathjax>#2Al^@ (s) #</mathjax> + <mathjax>#3Zn^"2+"#</mathjax> + <mathjax>#6NO_3^-#</mathjax> = <mathjax>#2Al^"3+"#</mathjax> + <mathjax>#6NO_3^-#</mathjax> + <mathjax>#3Zn^@ (s)#</mathjax> </p> <p>Notice that for the <mathjax>#NO_3^-#</mathjax>, I multiply the subscript with the substance's coefficient. Now let us get rid of your spectator ions (ions that are present in both sides of the equation).</p> <p><mathjax>#2Al^@ (s) #</mathjax> + <mathjax>#3Zn^"2+"#</mathjax> + <mathjax>#cancel (6NO_3^-)#</mathjax> = <mathjax>#2Al^"3+"#</mathjax> + <mathjax>#cancel (6NO_3^-)#</mathjax> + <mathjax>#3Zn^@ (s)#</mathjax> </p> <p>Now let's show the electrons per half-reaction:</p> <p><mathjax>#2Al^@ (s) #</mathjax> = <mathjax>#2Al^"3+"#</mathjax> + <mathjax>#6e^-#</mathjax> </p> <p><mathjax>#3Zn^"2+"#</mathjax> + <mathjax>#6e^-#</mathjax> = <mathjax>#3Zn^@ (s)#</mathjax> </p> <p>Thus, the net ionic equation is </p> <p><mathjax>#2Al^@ (s)#</mathjax> + <mathjax>#3Zn^"2+"#</mathjax> = <mathjax>#2Al^"3+"#</mathjax> + <mathjax>#3Zn^@ (s)#</mathjax> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">2Al+Zn(NO3)2=2Al(NO3)3+Zn net ionic equation?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="185991" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/nikka-c"><img alt="" class="" src="https://profilepictures.socratic.org/AQ8VOCyTM1J7U0TvIWhw_nkahara.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/nikka-c"> Nikka C. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-09T10:15:13" itemprop="dateCreated"> Nov 9, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2Al^@ (s)#</mathjax> + <mathjax>#3Zn^"2+"#</mathjax> = <mathjax>#2Al^"3+"#</mathjax> + <mathjax>#3Zn^@ (s)#</mathjax> (net ionic equation)</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The equation given above is wrongly balanced, so I have to correct it first.</p> <p><mathjax>#Al^@#</mathjax> + <mathjax>#Zn(NO_3)_2#</mathjax> = <mathjax>#Al(NO_3)_3#</mathjax> + <mathjax>#Zn^@#</mathjax> (unbalanced)</p> <p>Tallying the atoms based on subscripts,</p> <p>left side: <mathjax>#Al#</mathjax> = 1; <mathjax>#Zn#</mathjax> = 1; <mathjax>#(NO_3)_3#</mathjax> = 2<br/> right side: <mathjax>#Al#</mathjax> = 1; <mathjax>#Zn#</mathjax> = 1; <mathjax>#(NO_3)_3#</mathjax> = 3</p> <p>Notice that I am considering the <mathjax>#NO_3^-#</mathjax> ion as one "atom" in order to avoid confusing myself.</p> <p>Balancing the equations we have:</p> <p><mathjax>#color (blue) 2Al^@ (s) #</mathjax> + <mathjax>#color (red) 3 Zn(NO_3)_2#</mathjax> = <mathjax>#color (green) 2Al(NO_3)_3#</mathjax> + <mathjax>#color (magenta) 3Zn^@ (s)#</mathjax> (balanced)</p> <p>left side: <mathjax>#Al#</mathjax> = (1 x <mathjax>#color (blue) 2#</mathjax>) = <strong>2</strong>; <mathjax>#Zn#</mathjax> = (1 x <mathjax>#color (red) 3#</mathjax>) = <strong>3</strong>; <mathjax>#(NO_3)_3#</mathjax> = (2 x <mathjax>#color (red) 3#</mathjax>) = <strong>6</strong><br/> right side: <mathjax>#Al#</mathjax> = (1x <mathjax>#color (green) 2#</mathjax>) = <strong>2</strong>; <mathjax>#Zn#</mathjax> = (1 x <mathjax>#color (magenta) 3#</mathjax>) = <strong>3</strong>; <mathjax>#(NO_3)_3#</mathjax> = (3 x <mathjax>#color (green) 2#</mathjax>) = <strong>6</strong></p> <p>Now that we have the correct balance equation, we must rewrite the equation showing all the ions involved in the reaction.</p> <p><mathjax>#2Al^@ (s) #</mathjax> + <mathjax>#3Zn^"2+"#</mathjax> + <mathjax>#6NO_3^-#</mathjax> = <mathjax>#2Al^"3+"#</mathjax> + <mathjax>#6NO_3^-#</mathjax> + <mathjax>#3Zn^@ (s)#</mathjax> </p> <p>Notice that for the <mathjax>#NO_3^-#</mathjax>, I multiply the subscript with the substance's coefficient. Now let us get rid of your spectator ions (ions that are present in both sides of the equation).</p> <p><mathjax>#2Al^@ (s) #</mathjax> + <mathjax>#3Zn^"2+"#</mathjax> + <mathjax>#cancel (6NO_3^-)#</mathjax> = <mathjax>#2Al^"3+"#</mathjax> + <mathjax>#cancel (6NO_3^-)#</mathjax> + <mathjax>#3Zn^@ (s)#</mathjax> </p> <p>Now let's show the electrons per half-reaction:</p> <p><mathjax>#2Al^@ (s) #</mathjax> = <mathjax>#2Al^"3+"#</mathjax> + <mathjax>#6e^-#</mathjax> </p> <p><mathjax>#3Zn^"2+"#</mathjax> + <mathjax>#6e^-#</mathjax> = <mathjax>#3Zn^@ (s)#</mathjax> </p> <p>Thus, the net ionic equation is </p> <p><mathjax>#2Al^@ (s)#</mathjax> + <mathjax>#3Zn^"2+"#</mathjax> = <mathjax>#2Al^"3+"#</mathjax> + <mathjax>#3Zn^@ (s)#</mathjax> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/185991" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-equation-for-photosynthesis"> What is the chemical equation for photosynthesis? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-know-the-relative-number-of-grams-of-each-substance-used-or-produced-w"> How can I know the relative number of grams of each substance used or produced with chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-know-the-relative-number-of-moles-of-each-substance-with-chemical-equa"> How can I know the relative number of moles of each substance with chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-chemical-equations-illustrate-that-atoms-are-conserved-1"> How do chemical equations illustrate that atoms are conserved? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-know-the-formula-of-the-reactants-and-products-with-chemical-equations"> How can I know the formula of the reactants and products with chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-potassium-metal-and-chlorine-gas-combi"> How can I balance this chemical equations? 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1,595	ab4d69be-6ddd-11ea-a24c-ccda262736ce	https://socratic.org/questions/564eb05d581e2a279602931a	0.30 atm	start physical_unit 1 1 pressure atm qc_end physical_unit 1 1 6 7 pressure qc_end physical_unit 1 1 3 4 volume qc_end physical_unit 1 1 18 19 volume qc_end end	[{"type":"physical unit","value":"Pressure2 [OF] the gas [IN] atm"}]	[{"type":"physical unit","value":"0.30 atm"}]	[{"type":"physical unit","value":"Pressure1 [OF] the gas [=] \\pu{1.2 atm}"},{"type":"physical unit","value":"Volume1 [OF] the gas [=] \\pu{1.0 liter}"},{"type":"physical unit","value":"Volume2 [OF] the gas [=] \\pu{4.0 liters}"}]	<h1 class="questionTitle" itemprop="name">A gas occupies #1.0# liter at #1.2# atm. What is the pressure if the volume is increased to #4.0# liters? </h1>	null	0.30 atm	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="http://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's law</a> states that when temperature and mass is kept constant, the volume of a gas varies inversely with pressure. The equation for this law is <mathjax>#P_1V_1=P_2V_2#</mathjax>.</p> <p><strong>Given</strong><br/> <mathjax>#P_1="1.2 atm"#</mathjax><br/> <mathjax>#V_1="1.0 L"#</mathjax><br/> <mathjax>#V_2="4.0 L"#</mathjax></p> <p><strong>Unknown</strong><br/> <mathjax>#P_2#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#P_2#</mathjax> and solve.</p> <p><mathjax>#P_2=(P_1V_1)/(V_2)#</mathjax></p> <p><mathjax>#P_2=((1.2"atm"xx1.0"L"))/(4.0"L")="0.30 atm"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The final pressure will be <mathjax>#"0.30 atm"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="http://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's law</a> states that when temperature and mass is kept constant, the volume of a gas varies inversely with pressure. The equation for this law is <mathjax>#P_1V_1=P_2V_2#</mathjax>.</p> <p><strong>Given</strong><br/> <mathjax>#P_1="1.2 atm"#</mathjax><br/> <mathjax>#V_1="1.0 L"#</mathjax><br/> <mathjax>#V_2="4.0 L"#</mathjax></p> <p><strong>Unknown</strong><br/> <mathjax>#P_2#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#P_2#</mathjax> and solve.</p> <p><mathjax>#P_2=(P_1V_1)/(V_2)#</mathjax></p> <p><mathjax>#P_2=((1.2"atm"xx1.0"L"))/(4.0"L")="0.30 atm"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A gas occupies #1.0# liter at #1.2# atm. What is the pressure if the volume is increased to #4.0# liters? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/boyle-s-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Boyle's Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="192087" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-23T01:38:45" itemprop="dateCreated"> Nov 23, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The final pressure will be <mathjax>#"0.30 atm"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="http://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's law</a> states that when temperature and mass is kept constant, the volume of a gas varies inversely with pressure. The equation for this law is <mathjax>#P_1V_1=P_2V_2#</mathjax>.</p> <p><strong>Given</strong><br/> <mathjax>#P_1="1.2 atm"#</mathjax><br/> <mathjax>#V_1="1.0 L"#</mathjax><br/> <mathjax>#V_2="4.0 L"#</mathjax></p> <p><strong>Unknown</strong><br/> <mathjax>#P_2#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#P_2#</mathjax> and solve.</p> <p><mathjax>#P_2=(P_1V_1)/(V_2)#</mathjax></p> <p><mathjax>#P_2=((1.2"atm"xx1.0"L"))/(4.0"L")="0.30 atm"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/192087" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-graph-boyles-law"> How do you graph Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-functional-groups-are-found-in-lipids"> What functional groups are found in lipids? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-k-constant-in-boyle-s-law"> Why is k constant in Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-boyle-s-law-graph-curved-1"> Why is Boyle's law graph curved? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-boyle-s-law-an-inverse-relationship-2"> Why is Boyle's law an inverse relationship? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-40-0-l-tank-of-ammonia-has-a-pressure-of-8-00-atm-calculate-the-volume-of-the-"> A 40.0 L tank of ammonia has a pressure of 8.00 atm. Calculate the volume of the ammonia if its... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-charles-law-different-from-boyle-s-law"> How is Charles' law different from Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-boyle-s-law-written-mathematically"> How is Boyle's law written mathematically? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-temperature-affect-boyle-s-law"> How does temperature affect Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-boyle-s-law-relate-to-ventilation"> How does Boyle's law relate to ventilation? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/boyle-s-law"> See all questions in Boyle's Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 11656 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A gas occupies #1.0# liter at #1.2# atm. What is the pressure if the volume is increased to #4.0# liters?	null
1,596	abef90e8-6ddd-11ea-97eb-ccda262736ce	https://socratic.org/questions/if-you-start-with-ten-grams-of-sodium-hydroxide-how-many-moles-of-sodium-chlorid	0.25 moles	start physical_unit 13 14 mole mol qc_end chemical_equation 18 24 qc_end end	[{"type":"physical unit","value":"Mole [OF] sodium chloride [IN] moles"}]	[{"type":"physical unit","value":"0.25 moles"}]	[{"type":"physical unit","value":"Mass [OF] sodium hydroxide [=] \\pu{10 grams}"},{"type":"chemical equation","value":"NaOH(aq) + HCl(aq) -> NaCl(aq) + H2O(l)"}]	<h1 class="questionTitle" itemprop="name">If you start with ten grams of sodium hydroxide, how many moles of sodium chloride will be produced? </h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p><mathjax>#"NaOH"(aq) + "HCl"(aq) -> "NaCl"(aq) + "H"_2"O"(l)#</mathjax></p></div> </h2> </div> </div>	0.25 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Start by converting the mass of sodium hydroxide to <em>moles</em>, as this will allow you to use the <mathjax>#1:1#</mathjax> <strong>mole ratio</strong> that exists between the two reactants to determine how many moles of sodium chloride are produced.</p> <blockquote> <p><mathjax>#10 color(red)(cancel(color(black)("g"))) * "1 mole NaOH"/(40.0 color(red)(cancel(color(black)("g")))) = "0.25 moles NaOH"#</mathjax></p> </blockquote> <p>Now, the chemical reaction tells you that <mathjax>#1#</mathjax> <strong>mole</strong> of sodium hydroxide reacts with <mathjax>#1#</mathjax> <strong>mole</strong> of hydrochloric acid to produce <mathjax>#1#</mathjax> <strong>mole</strong> of aqueous sodium chloride. </p> <p>Since the problem doesn't mention the quantity of hydrochloric acid that is available, you can assume that hydrochloric acid is <em>in excess</em>, which implies that <strong>all the moles</strong> of sodium hydroxide will be consumed. </p> <p>This means that the reaction will produce</p> <blockquote> <p><mathjax>#0.25 color(red)(cancel(color(black)("moles NaOH"))) * "1 mole NaCl"/(1color(red)(cancel(color(black)("moles NaOH")))) = "0.25 moles NaCl"#</mathjax></p> </blockquote> <p>Assuming that the mass of sodium hydroxide was given as <mathjax>#"10 g"#</mathjax>, you must round the answer to one <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figure</a></strong>, so</p> <blockquote> <p><mathjax>#"no. of moles NaCl " = " 0.3 moles"#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"0.3 moles NaCl"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Start by converting the mass of sodium hydroxide to <em>moles</em>, as this will allow you to use the <mathjax>#1:1#</mathjax> <strong>mole ratio</strong> that exists between the two reactants to determine how many moles of sodium chloride are produced.</p> <blockquote> <p><mathjax>#10 color(red)(cancel(color(black)("g"))) * "1 mole NaOH"/(40.0 color(red)(cancel(color(black)("g")))) = "0.25 moles NaOH"#</mathjax></p> </blockquote> <p>Now, the chemical reaction tells you that <mathjax>#1#</mathjax> <strong>mole</strong> of sodium hydroxide reacts with <mathjax>#1#</mathjax> <strong>mole</strong> of hydrochloric acid to produce <mathjax>#1#</mathjax> <strong>mole</strong> of aqueous sodium chloride. </p> <p>Since the problem doesn't mention the quantity of hydrochloric acid that is available, you can assume that hydrochloric acid is <em>in excess</em>, which implies that <strong>all the moles</strong> of sodium hydroxide will be consumed. </p> <p>This means that the reaction will produce</p> <blockquote> <p><mathjax>#0.25 color(red)(cancel(color(black)("moles NaOH"))) * "1 mole NaCl"/(1color(red)(cancel(color(black)("moles NaOH")))) = "0.25 moles NaCl"#</mathjax></p> </blockquote> <p>Assuming that the mass of sodium hydroxide was given as <mathjax>#"10 g"#</mathjax>, you must round the answer to one <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figure</a></strong>, so</p> <blockquote> <p><mathjax>#"no. of moles NaCl " = " 0.3 moles"#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">If you start with ten grams of sodium hydroxide, how many moles of sodium chloride will be produced? </h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p><mathjax>#"NaOH"(aq) + "HCl"(aq) -> "NaCl"(aq) + "H"_2"O"(l)#</mathjax></p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="549357" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-02-10T01:09:42" itemprop="dateCreated"> Feb 10, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"0.3 moles NaCl"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Start by converting the mass of sodium hydroxide to <em>moles</em>, as this will allow you to use the <mathjax>#1:1#</mathjax> <strong>mole ratio</strong> that exists between the two reactants to determine how many moles of sodium chloride are produced.</p> <blockquote> <p><mathjax>#10 color(red)(cancel(color(black)("g"))) * "1 mole NaOH"/(40.0 color(red)(cancel(color(black)("g")))) = "0.25 moles NaOH"#</mathjax></p> </blockquote> <p>Now, the chemical reaction tells you that <mathjax>#1#</mathjax> <strong>mole</strong> of sodium hydroxide reacts with <mathjax>#1#</mathjax> <strong>mole</strong> of hydrochloric acid to produce <mathjax>#1#</mathjax> <strong>mole</strong> of aqueous sodium chloride. </p> <p>Since the problem doesn't mention the quantity of hydrochloric acid that is available, you can assume that hydrochloric acid is <em>in excess</em>, which implies that <strong>all the moles</strong> of sodium hydroxide will be consumed. </p> <p>This means that the reaction will produce</p> <blockquote> <p><mathjax>#0.25 color(red)(cancel(color(black)("moles NaOH"))) * "1 mole NaCl"/(1color(red)(cancel(color(black)("moles NaOH")))) = "0.25 moles NaCl"#</mathjax></p> </blockquote> <p>Assuming that the mass of sodium hydroxide was given as <mathjax>#"10 g"#</mathjax>, you must round the answer to one <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figure</a></strong>, so</p> <blockquote> <p><mathjax>#"no. of moles NaCl " = " 0.3 moles"#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/549357" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? 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1,597	ab519ab1-6ddd-11ea-9cdc-ccda262736ce	https://socratic.org/questions/carbon-and-oxygen-react-to-give-carbon-dioxide-the-reaction-of-4-49-g-c-s-with-9	-393.33 kJ/mol	start physical_unit 30 30 enthalpy_of_formation kj/mol qc_end physical_unit 13 13 11 12 mass qc_end physical_unit 17 17 15 16 mass qc_end physical_unit 8 9 19 20 heat_energy qc_end end	[{"type":"physical unit","value":"Enthalpy of formation [OF] CO2(g) [IN] kJ/mol"}]	[{"type":"physical unit","value":"-393.33 kJ/mol"}]	[{"type":"physical unit","value":"Mass [OF] C(s) [=] \\pu{4.49 g}"},{"type":"physical unit","value":"Mass [OF] O2(g) [=] \\pu{9.21 g}"},{"type":"physical unit","value":"Released heat [OF] the reaction [=] \\pu{113.2 kJ}"}]	<h1 class="questionTitle" itemprop="name">Carbon and oxygen react to give carbon dioxide. The reaction of 4.49 g #C(s)# with 9.21 g #O_2(g)#releases 113.2 kJ of heat. What is the enthalpy of formation of #CO_2(g)#?</h1>	null	-393.33 kJ/mol	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>A compound's <strong><a href="https://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> of formation</strong>, <mathjax>#DeltaH_"f"#</mathjax>, tells you the enthalpy change that accompanies the formation of <strong>one mole</strong> of that compound from its constituent <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> in their stable form. </p> <p>In this case, elemental carbon will react with oxygen gas to form carbon dioxide</p> <blockquote> <p><mathjax>#"C"_ ((s)) + "O"_ (2(g)) -> "CO"_(2(g))#</mathjax></p> </blockquote> <p>Your strategy here will be to determine how many <strong>moles</strong> of carbon dioxide are formed when <mathjax>#"4.49 g"#</mathjax> of carbon and <mathjax>#"9.21 g"#</mathjax> of oxygen gas react, then use the known enthalpy change for <em>this reaction</em> to find <mathjax>#DeltaH_"f"#</mathjax>. </p> <p>So, use the <strong>molar masses</strong> of elemental carbon and oxygen gas to determine how many <em>moles</em> of each are being mixed</p> <blockquote> <p><mathjax>#4.49 color(red)(cancel(color(black)("g"))) * "1 mole C"/(12.011color(red)(cancel(color(black)("g")))) = "0.3738 moles C"#</mathjax></p> <p><mathjax>#9.21 color(red)(cancel(color(black)("g"))) * "1 mole O"_2/(32.0color(red)(cancel(color(black)("g")))) = "0.2878 moles O"_2#</mathjax></p> </blockquote> <p>Notice that the two reactants are consumed in a <mathjax>#1:1#</mathjax> <strong><a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a></strong>, but that you have <strong>fewer moles</strong> of oxygen gas than you have of carbon. </p> <p>This means that the oxygen gas will act as a <em><a href="https://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a></em>, i.e. it will be <strong>completely consumed</strong> before <strong>all the moles</strong> of carbon get the chance to react. </p> <p>Since the reaction produces carbon dioxide in a <mathjax>#1:1#</mathjax> mole ratio with both reactants, you can say that you'll get </p> <blockquote> <p><mathjax>#0.2878 color(red)(cancel(color(black)("moles O"_2))) * "1 mole CO"_2/(1color(red)(cancel(color(black)("mole O"_2)))) = "0.2878 moles CO"_2#</mathjax></p> </blockquote> <p>So, you know that <mathjax>#"113.2 kJ"#</mathjax> of heat <strong>are being released</strong> when <mathjax>#0.2878#</mathjax> <strong>moles</strong> of carbon dioxide are formed. This means that the formation of <strong>one mole</strong> of carbon dioxide will give off</p> <blockquote> <p><mathjax>#1 color(red)(cancel(color(black)("mole CO"_2))) * "113.2 kJ"/(0.2878color(red)(cancel(color(black)("moles CO"_2)))) = "393.3 kJ"#</mathjax></p> </blockquote> <p>Now, heat <strong>given off</strong> corresponds to a <em>negative</em> enthalpy change of reaction. As a result,m the enthalpy of formation for carbon dioxide will be </p> <blockquote> <p><mathjax>#DeltaH_"f" = color(green)(\|bar(ul(color(white)(a/a)-"393 kJ mol"^(-1)color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>. </p> <p>It's worth noting that the listed value for carbon dioxide's <em>standard enthalpy of formation</em>, <mathjax>#DeltaH_"f"^@#</mathjax>, which is imply the enthalpy of formation measured at <mathjax>#25^@"C"#</mathjax> and <mathjax>#"1 atm"#</mathjax>, is equal to </p> <blockquote> <p><mathjax>#DeltaH_"f"^@ = - "393.5 kJ mol"^(-1)#</mathjax></p> </blockquote> <p>which confirms that the result is very accurate. </p> <p><a href="http://nshs-science.net/chemistry/common/pdf/R-standard_enthalpy_of_formation.pdf" rel="nofollow" target="_blank">http://nshs-science.net/chemistry/common/pdf/R-standard_enthalpy_of_formation.pdf</a></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#DeltaH_"f" = -"393 kJ mol"^(-1)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>A compound's <strong><a href="https://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> of formation</strong>, <mathjax>#DeltaH_"f"#</mathjax>, tells you the enthalpy change that accompanies the formation of <strong>one mole</strong> of that compound from its constituent <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> in their stable form. </p> <p>In this case, elemental carbon will react with oxygen gas to form carbon dioxide</p> <blockquote> <p><mathjax>#"C"_ ((s)) + "O"_ (2(g)) -> "CO"_(2(g))#</mathjax></p> </blockquote> <p>Your strategy here will be to determine how many <strong>moles</strong> of carbon dioxide are formed when <mathjax>#"4.49 g"#</mathjax> of carbon and <mathjax>#"9.21 g"#</mathjax> of oxygen gas react, then use the known enthalpy change for <em>this reaction</em> to find <mathjax>#DeltaH_"f"#</mathjax>. </p> <p>So, use the <strong>molar masses</strong> of elemental carbon and oxygen gas to determine how many <em>moles</em> of each are being mixed</p> <blockquote> <p><mathjax>#4.49 color(red)(cancel(color(black)("g"))) * "1 mole C"/(12.011color(red)(cancel(color(black)("g")))) = "0.3738 moles C"#</mathjax></p> <p><mathjax>#9.21 color(red)(cancel(color(black)("g"))) * "1 mole O"_2/(32.0color(red)(cancel(color(black)("g")))) = "0.2878 moles O"_2#</mathjax></p> </blockquote> <p>Notice that the two reactants are consumed in a <mathjax>#1:1#</mathjax> <strong><a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a></strong>, but that you have <strong>fewer moles</strong> of oxygen gas than you have of carbon. </p> <p>This means that the oxygen gas will act as a <em><a href="https://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a></em>, i.e. it will be <strong>completely consumed</strong> before <strong>all the moles</strong> of carbon get the chance to react. </p> <p>Since the reaction produces carbon dioxide in a <mathjax>#1:1#</mathjax> mole ratio with both reactants, you can say that you'll get </p> <blockquote> <p><mathjax>#0.2878 color(red)(cancel(color(black)("moles O"_2))) * "1 mole CO"_2/(1color(red)(cancel(color(black)("mole O"_2)))) = "0.2878 moles CO"_2#</mathjax></p> </blockquote> <p>So, you know that <mathjax>#"113.2 kJ"#</mathjax> of heat <strong>are being released</strong> when <mathjax>#0.2878#</mathjax> <strong>moles</strong> of carbon dioxide are formed. This means that the formation of <strong>one mole</strong> of carbon dioxide will give off</p> <blockquote> <p><mathjax>#1 color(red)(cancel(color(black)("mole CO"_2))) * "113.2 kJ"/(0.2878color(red)(cancel(color(black)("moles CO"_2)))) = "393.3 kJ"#</mathjax></p> </blockquote> <p>Now, heat <strong>given off</strong> corresponds to a <em>negative</em> enthalpy change of reaction. As a result,m the enthalpy of formation for carbon dioxide will be </p> <blockquote> <p><mathjax>#DeltaH_"f" = color(green)(\|bar(ul(color(white)(a/a)-"393 kJ mol"^(-1)color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>. </p> <p>It's worth noting that the listed value for carbon dioxide's <em>standard enthalpy of formation</em>, <mathjax>#DeltaH_"f"^@#</mathjax>, which is imply the enthalpy of formation measured at <mathjax>#25^@"C"#</mathjax> and <mathjax>#"1 atm"#</mathjax>, is equal to </p> <blockquote> <p><mathjax>#DeltaH_"f"^@ = - "393.5 kJ mol"^(-1)#</mathjax></p> </blockquote> <p>which confirms that the result is very accurate. </p> <p><a href="http://nshs-science.net/chemistry/common/pdf/R-standard_enthalpy_of_formation.pdf" rel="nofollow" target="_blank">http://nshs-science.net/chemistry/common/pdf/R-standard_enthalpy_of_formation.pdf</a></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Carbon and oxygen react to give carbon dioxide. The reaction of 4.49 g #C(s)# with 9.21 g #O_2(g)#releases 113.2 kJ of heat. What is the enthalpy of formation of #CO_2(g)#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/enthalpy" itemprop="url"> <span class="breadcrumb" itemprop="title">Enthalpy</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="253947" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-04-14T01:01:52" itemprop="dateCreated"> Apr 14, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#DeltaH_"f" = -"393 kJ mol"^(-1)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>A compound's <strong><a href="https://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> of formation</strong>, <mathjax>#DeltaH_"f"#</mathjax>, tells you the enthalpy change that accompanies the formation of <strong>one mole</strong> of that compound from its constituent <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> in their stable form. </p> <p>In this case, elemental carbon will react with oxygen gas to form carbon dioxide</p> <blockquote> <p><mathjax>#"C"_ ((s)) + "O"_ (2(g)) -> "CO"_(2(g))#</mathjax></p> </blockquote> <p>Your strategy here will be to determine how many <strong>moles</strong> of carbon dioxide are formed when <mathjax>#"4.49 g"#</mathjax> of carbon and <mathjax>#"9.21 g"#</mathjax> of oxygen gas react, then use the known enthalpy change for <em>this reaction</em> to find <mathjax>#DeltaH_"f"#</mathjax>. </p> <p>So, use the <strong>molar masses</strong> of elemental carbon and oxygen gas to determine how many <em>moles</em> of each are being mixed</p> <blockquote> <p><mathjax>#4.49 color(red)(cancel(color(black)("g"))) * "1 mole C"/(12.011color(red)(cancel(color(black)("g")))) = "0.3738 moles C"#</mathjax></p> <p><mathjax>#9.21 color(red)(cancel(color(black)("g"))) * "1 mole O"_2/(32.0color(red)(cancel(color(black)("g")))) = "0.2878 moles O"_2#</mathjax></p> </blockquote> <p>Notice that the two reactants are consumed in a <mathjax>#1:1#</mathjax> <strong><a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a></strong>, but that you have <strong>fewer moles</strong> of oxygen gas than you have of carbon. </p> <p>This means that the oxygen gas will act as a <em><a href="https://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a></em>, i.e. it will be <strong>completely consumed</strong> before <strong>all the moles</strong> of carbon get the chance to react. </p> <p>Since the reaction produces carbon dioxide in a <mathjax>#1:1#</mathjax> mole ratio with both reactants, you can say that you'll get </p> <blockquote> <p><mathjax>#0.2878 color(red)(cancel(color(black)("moles O"_2))) * "1 mole CO"_2/(1color(red)(cancel(color(black)("mole O"_2)))) = "0.2878 moles CO"_2#</mathjax></p> </blockquote> <p>So, you know that <mathjax>#"113.2 kJ"#</mathjax> of heat <strong>are being released</strong> when <mathjax>#0.2878#</mathjax> <strong>moles</strong> of carbon dioxide are formed. This means that the formation of <strong>one mole</strong> of carbon dioxide will give off</p> <blockquote> <p><mathjax>#1 color(red)(cancel(color(black)("mole CO"_2))) * "113.2 kJ"/(0.2878color(red)(cancel(color(black)("moles CO"_2)))) = "393.3 kJ"#</mathjax></p> </blockquote> <p>Now, heat <strong>given off</strong> corresponds to a <em>negative</em> enthalpy change of reaction. As a result,m the enthalpy of formation for carbon dioxide will be </p> <blockquote> <p><mathjax>#DeltaH_"f" = color(green)(\|bar(ul(color(white)(a/a)-"393 kJ mol"^(-1)color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>. </p> <p>It's worth noting that the listed value for carbon dioxide's <em>standard enthalpy of formation</em>, <mathjax>#DeltaH_"f"^@#</mathjax>, which is imply the enthalpy of formation measured at <mathjax>#25^@"C"#</mathjax> and <mathjax>#"1 atm"#</mathjax>, is equal to </p> <blockquote> <p><mathjax>#DeltaH_"f"^@ = - "393.5 kJ mol"^(-1)#</mathjax></p> </blockquote> <p>which confirms that the result is very accurate. </p> <p><a href="http://nshs-science.net/chemistry/common/pdf/R-standard_enthalpy_of_formation.pdf" rel="nofollow" target="_blank">http://nshs-science.net/chemistry/common/pdf/R-standard_enthalpy_of_formation.pdf</a></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/253947" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-enthalpy-changes-expressed-in-chemical-equations"> How are enthalpy changes expressed in chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-enthalpy-change-be-determined-for-an-aqueous-solution"> How can enthalpy change be determined for an aqueous solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-enthalpy-change-with-pressure"> How does enthalpy change with pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-standard-molar-enthalpy-formation"> How do you calculate standard molar enthalpy of formation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-enthalpy-a-state-function"> Why is enthalpy a state function? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-enthalpy-of-formation-of-oxygen-zero"> Why is the enthalpy of formation of oxygen zero? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-enthalpy-a-state-function-2"> Why is enthalpy a state function? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-enthalpy-cannot-be-measured-directly"> Why can enthalpy not be measured directly? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-pressure-affect-enthalpy"> How does pressure affect enthalpy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-enthalpy-relate-to-internal-energy"> How does enthalpy relate to internal energy? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/enthalpy"> See all questions in Enthalpy </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 9416 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Carbon and oxygen react to give carbon dioxide. The reaction of 4.49 g #C(s)# with 9.21 g #O_2(g)#releases 113.2 kJ of heat. What is the enthalpy of formation of #CO_2(g)#?	null
1,598	acd7f874-6ddd-11ea-beb8-ccda262736ce	https://socratic.org/questions/equal-masses-of-methane-and-hydrogen-are-mixed-in-an-empty-container-at-25-degre	8/9	start physical_unit 19 23 ratio none qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Fraction [OF] total pressure exerted by hydrogen "}]	[{"type":"physical unit","value":"8/9"}]	[{"type":"physical unit","value":"Temperature [OF] the mixture gas [=] \\pu{25 degree Celsius}"},{"type":"other","value":"Equal masses of methane and hydrogen are mixed in an empty container. "}]	<h1 class="questionTitle" itemprop="name">Equal masses of methane and hydrogen are mixed in an empty container. At 25 degree Celsius. The fraction of total pressure exerted by hydrogen will be?</h1>	null	8/9	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that the <a href="https://socratic.org/chemistry/the-behavior-of-gases/partial-pressure">partial pressure</a> of hydrogen gas will depend on </p> <blockquote> <ul> <li><em>the <strong>mole fraction</strong> of hydrogen gas in the mixture</em></li> <li><em>the <strong>total pressure</strong> of the mixture</em></li> </ul> </blockquote> <p>Now, let's say that we are mixing <mathjax>#m#</mathjax> <mathjax>#"g"#</mathjax> of hydrogen gas and <mathjax>#m#</mathjax> <mathjax>#"g"#</mathjax> of methane. </p> <p>Use the <strong>molar masses</strong> of the two gases to express the number of moles of each component of the mixture in terms of their mass <mathjax>#m#</mathjax></p> <blockquote> <p><mathjax>#m color(red)(cancel(color(black)("g"))) * "1 mole H"_2/(2.0color(red)(cancel(color(black)("g")))) = (m/2)#</mathjax> <mathjax>#"moles H"_2#</mathjax></p> <p><mathjax>#m color(red)(cancel(color(black)("g"))) * "1 mole CH"_4/(16.0color(red)(cancel(color(black)("g")))) = (m/16)#</mathjax> <mathjax>#"moles O"_2#</mathjax></p> </blockquote> <p>The <strong>total number</strong> of moles of gas present in the mixture will be equal to</p> <blockquote> <p><mathjax>#(m/2)color(white)(.)"moles" + (m/16)color(white)(.)"moles" = (9/16 * m)color(white)(.)"moles"#</mathjax></p> </blockquote> <p>Now, the <strong>mole fraction</strong> of hydrogen gas is calculated by dividing the number of moles of hydrogen gas by the total number of moles of gas present in the mixture.</p> <blockquote> <p><mathjax>#chi_ ("H"_ 2) = ((color(red)(cancel(color(black)(m)))/2)color(red)(cancel(color(black)("moles"))))/((9/16 * color(red)(cancel(color(black)(m))))color(red)(cancel(color(black)("moles")))) = 1/2 * 16/9 = 8/9#</mathjax></p> </blockquote> <p>By definition, the partial pressure of hydrogen gas in the mixture is equal to</p> <blockquote> <p><mathjax>#P_ ("H"_ 2) = chi_ ("H"_ 2) * P_"total"#</mathjax></p> </blockquote> <p>In your case, this will be equal to</p> <blockquote> <p><mathjax>#P_ ("H"_ 2) = 8/9 * P_"total"#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#8/9#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that the <a href="https://socratic.org/chemistry/the-behavior-of-gases/partial-pressure">partial pressure</a> of hydrogen gas will depend on </p> <blockquote> <ul> <li><em>the <strong>mole fraction</strong> of hydrogen gas in the mixture</em></li> <li><em>the <strong>total pressure</strong> of the mixture</em></li> </ul> </blockquote> <p>Now, let's say that we are mixing <mathjax>#m#</mathjax> <mathjax>#"g"#</mathjax> of hydrogen gas and <mathjax>#m#</mathjax> <mathjax>#"g"#</mathjax> of methane. </p> <p>Use the <strong>molar masses</strong> of the two gases to express the number of moles of each component of the mixture in terms of their mass <mathjax>#m#</mathjax></p> <blockquote> <p><mathjax>#m color(red)(cancel(color(black)("g"))) * "1 mole H"_2/(2.0color(red)(cancel(color(black)("g")))) = (m/2)#</mathjax> <mathjax>#"moles H"_2#</mathjax></p> <p><mathjax>#m color(red)(cancel(color(black)("g"))) * "1 mole CH"_4/(16.0color(red)(cancel(color(black)("g")))) = (m/16)#</mathjax> <mathjax>#"moles O"_2#</mathjax></p> </blockquote> <p>The <strong>total number</strong> of moles of gas present in the mixture will be equal to</p> <blockquote> <p><mathjax>#(m/2)color(white)(.)"moles" + (m/16)color(white)(.)"moles" = (9/16 * m)color(white)(.)"moles"#</mathjax></p> </blockquote> <p>Now, the <strong>mole fraction</strong> of hydrogen gas is calculated by dividing the number of moles of hydrogen gas by the total number of moles of gas present in the mixture.</p> <blockquote> <p><mathjax>#chi_ ("H"_ 2) = ((color(red)(cancel(color(black)(m)))/2)color(red)(cancel(color(black)("moles"))))/((9/16 * color(red)(cancel(color(black)(m))))color(red)(cancel(color(black)("moles")))) = 1/2 * 16/9 = 8/9#</mathjax></p> </blockquote> <p>By definition, the partial pressure of hydrogen gas in the mixture is equal to</p> <blockquote> <p><mathjax>#P_ ("H"_ 2) = chi_ ("H"_ 2) * P_"total"#</mathjax></p> </blockquote> <p>In your case, this will be equal to</p> <blockquote> <p><mathjax>#P_ ("H"_ 2) = 8/9 * P_"total"#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Equal masses of methane and hydrogen are mixed in an empty container. At 25 degree Celsius. The fraction of total pressure exerted by hydrogen will be?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/partial-pressure" itemprop="url"> <span class="breadcrumb" itemprop="title">Partial Pressure</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="437279" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-09T23:37:23" itemprop="dateCreated"> Jun 9, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#8/9#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that the <a href="https://socratic.org/chemistry/the-behavior-of-gases/partial-pressure">partial pressure</a> of hydrogen gas will depend on </p> <blockquote> <ul> <li><em>the <strong>mole fraction</strong> of hydrogen gas in the mixture</em></li> <li><em>the <strong>total pressure</strong> of the mixture</em></li> </ul> </blockquote> <p>Now, let's say that we are mixing <mathjax>#m#</mathjax> <mathjax>#"g"#</mathjax> of hydrogen gas and <mathjax>#m#</mathjax> <mathjax>#"g"#</mathjax> of methane. </p> <p>Use the <strong>molar masses</strong> of the two gases to express the number of moles of each component of the mixture in terms of their mass <mathjax>#m#</mathjax></p> <blockquote> <p><mathjax>#m color(red)(cancel(color(black)("g"))) * "1 mole H"_2/(2.0color(red)(cancel(color(black)("g")))) = (m/2)#</mathjax> <mathjax>#"moles H"_2#</mathjax></p> <p><mathjax>#m color(red)(cancel(color(black)("g"))) * "1 mole CH"_4/(16.0color(red)(cancel(color(black)("g")))) = (m/16)#</mathjax> <mathjax>#"moles O"_2#</mathjax></p> </blockquote> <p>The <strong>total number</strong> of moles of gas present in the mixture will be equal to</p> <blockquote> <p><mathjax>#(m/2)color(white)(.)"moles" + (m/16)color(white)(.)"moles" = (9/16 * m)color(white)(.)"moles"#</mathjax></p> </blockquote> <p>Now, the <strong>mole fraction</strong> of hydrogen gas is calculated by dividing the number of moles of hydrogen gas by the total number of moles of gas present in the mixture.</p> <blockquote> <p><mathjax>#chi_ ("H"_ 2) = ((color(red)(cancel(color(black)(m)))/2)color(red)(cancel(color(black)("moles"))))/((9/16 * color(red)(cancel(color(black)(m))))color(red)(cancel(color(black)("moles")))) = 1/2 * 16/9 = 8/9#</mathjax></p> </blockquote> <p>By definition, the partial pressure of hydrogen gas in the mixture is equal to</p> <blockquote> <p><mathjax>#P_ ("H"_ 2) = chi_ ("H"_ 2) * P_"total"#</mathjax></p> </blockquote> <p>In your case, this will be equal to</p> <blockquote> <p><mathjax>#P_ ("H"_ 2) = 8/9 * P_"total"#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/437279" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/534e256802bf342adfa30010"> How do you do a steam distillation? 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At 25 degree Celsius. The fraction of total pressure exerted by hydrogen will be?	null
1,599	a928caee-6ddd-11ea-8c1c-ccda262736ce	https://socratic.org/questions/547e2476581e2a1726aeff45	347.89 mL	start physical_unit 1 1 volume ml qc_end physical_unit 1 1 3 4 volume qc_end physical_unit 1 1 9 10 pressure qc_end physical_unit 1 1 21 22 pressure qc_end end	[{"type":"physical unit","value":"Volume2 [OF] the gas [IN] mL"}]	[{"type":"physical unit","value":"347.89 mL"}]	[{"type":"physical unit","value":"Volume1 [OF] the gas [=] \\pu{175 mL}"},{"type":"physical unit","value":"Pressure1 [OF] the gas [=] \\pu{825 torr}"},{"type":"physical unit","value":"Pressure2 [OF] the gas [=] \\pu{415 torr}"}]	<h1 class="questionTitle" itemprop="name">A gas occupies 175 mL at a pressure of 825 torr. What is the volume when the pressure is decreased to 415 torr?</h1>	null	347.89 mL	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You will need to use <a href="http://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's law</a> to answer this question. Boyle's law states that when temperature is constant, the volume of a gas is inversely proportional to the pressure. This means that if the volume increases, the pressure decreases and vice versa. The equation for Boyle's law is: </p> <p><mathjax>#P_1V_1 = P_2V_2#</mathjax>. </p> <p><strong>Given:</strong></p> <p><mathjax>#P_1 = "825 torr"#</mathjax></p> <p><mathjax>#V_1 = "175 mL"#</mathjax></p> <p><mathjax>#P_2 = "415 torr"#</mathjax></p> <p><strong>Unknown:</strong></p> <p><mathjax>#V_2#</mathjax></p> <p><strong>Solution:</strong> </p> <p>Isolate <mathjax>#V_2#</mathjax> by dividing both sides of the equation by <mathjax>#P_2#</mathjax>, then solve for <mathjax>#V_2#</mathjax>.</p> <p><mathjax>#V_2 = (P_1V_1)/P_2 =(825color(red)cancel(color(black)("torr"))xx175"mL")/(415color(red)cancel(color(black)("torr")))="348 mL"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The new volume will be <mathjax>#"348 mL"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You will need to use <a href="http://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's law</a> to answer this question. Boyle's law states that when temperature is constant, the volume of a gas is inversely proportional to the pressure. This means that if the volume increases, the pressure decreases and vice versa. The equation for Boyle's law is: </p> <p><mathjax>#P_1V_1 = P_2V_2#</mathjax>. </p> <p><strong>Given:</strong></p> <p><mathjax>#P_1 = "825 torr"#</mathjax></p> <p><mathjax>#V_1 = "175 mL"#</mathjax></p> <p><mathjax>#P_2 = "415 torr"#</mathjax></p> <p><strong>Unknown:</strong></p> <p><mathjax>#V_2#</mathjax></p> <p><strong>Solution:</strong> </p> <p>Isolate <mathjax>#V_2#</mathjax> by dividing both sides of the equation by <mathjax>#P_2#</mathjax>, then solve for <mathjax>#V_2#</mathjax>.</p> <p><mathjax>#V_2 = (P_1V_1)/P_2 =(825color(red)cancel(color(black)("torr"))xx175"mL")/(415color(red)cancel(color(black)("torr")))="348 mL"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A gas occupies 175 mL at a pressure of 825 torr. What is the volume when the pressure is decreased to 415 torr?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/boyle-s-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Boyle's Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="113400" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2014-12-02T21:33:24" itemprop="dateCreated"> Dec 2, 2014 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The new volume will be <mathjax>#"348 mL"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You will need to use <a href="http://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's law</a> to answer this question. Boyle's law states that when temperature is constant, the volume of a gas is inversely proportional to the pressure. This means that if the volume increases, the pressure decreases and vice versa. The equation for Boyle's law is: </p> <p><mathjax>#P_1V_1 = P_2V_2#</mathjax>. </p> <p><strong>Given:</strong></p> <p><mathjax>#P_1 = "825 torr"#</mathjax></p> <p><mathjax>#V_1 = "175 mL"#</mathjax></p> <p><mathjax>#P_2 = "415 torr"#</mathjax></p> <p><strong>Unknown:</strong></p> <p><mathjax>#V_2#</mathjax></p> <p><strong>Solution:</strong> </p> <p>Isolate <mathjax>#V_2#</mathjax> by dividing both sides of the equation by <mathjax>#P_2#</mathjax>, then solve for <mathjax>#V_2#</mathjax>.</p> <p><mathjax>#V_2 = (P_1V_1)/P_2 =(825color(red)cancel(color(black)("torr"))xx175"mL")/(415color(red)cancel(color(black)("torr")))="348 mL"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/113400" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-graph-boyles-law"> How do you graph Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-functional-groups-are-found-in-lipids"> What functional groups are found in lipids? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-k-constant-in-boyle-s-law"> Why is k constant in Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-boyle-s-law-graph-curved-1"> Why is Boyle's law graph curved? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-boyle-s-law-an-inverse-relationship-2"> Why is Boyle's law an inverse relationship? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-40-0-l-tank-of-ammonia-has-a-pressure-of-8-00-atm-calculate-the-volume-of-the-"> A 40.0 L tank of ammonia has a pressure of 8.00 atm. 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What is the volume when the pressure is decreased to 415 torr?	null

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