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2,100	a858b968-6ddd-11ea-ba4f-ccda262736ce	https://socratic.org/questions/100-grams-of-magnesium-and-2-50-grams-of-oxygen-react-together-in-synthesis-reac	Mg(s) + 1/2 O2 -> MgO(s)	start chemical_equation qc_end physical_unit 3 3 0 1 mass qc_end physical_unit 8 8 5 6 mass qc_end substance 16 17 qc_end end	[{"type":"other","value":"Chemical Equation [OF] this balanced reaction"}]	[{"type":"chemical equation","value":"Mg(s) + 1/2 O2 -> MgO(s)"}]	[{"type":"physical unit","value":"Mass [OF] magnesium [=] \\pu{100 grams}"},{"type":"physical unit","value":"Mass [OF] oxygen [=] \\pu{2.50 grams}"},{"type":"substance name","value":"Magnesium oxide"}]	<h1 class="questionTitle" itemprop="name">100 grams of magnesium and 2.50 grams of oxygen react together in synthesis reaction to form magnesium oxide. How do you write this balanced reaction?</h1>	null	Mg(s) + 1/2 O2 -> MgO(s)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>It is abundantly clear that magnesium is in vast molar excess:</p> <p>i.e. <mathjax>#"Moles of metal"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(100g)/(24.31gmol^-1)#</mathjax> <mathjax>#~=#</mathjax> <mathjax>#5mol#</mathjax></p> <p><mathjax>#"Moles of dioxygen"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(2.5g)/(32.00gmol^-1)#</mathjax> <mathjax>#~=#</mathjax> <mathjax>#0.08mol#</mathjax></p> <p>Clearly, <mathjax>#O_2#</mathjax> is the <a href="https://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a>, and our calculation proceeds on the basis of the molar quantity of the gas. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The balanced equation is clearly:</p> <p><mathjax>#Mg(s) + 1/2O_2(g) rarr MgO(s)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>It is abundantly clear that magnesium is in vast molar excess:</p> <p>i.e. <mathjax>#"Moles of metal"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(100g)/(24.31gmol^-1)#</mathjax> <mathjax>#~=#</mathjax> <mathjax>#5mol#</mathjax></p> <p><mathjax>#"Moles of dioxygen"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(2.5g)/(32.00gmol^-1)#</mathjax> <mathjax>#~=#</mathjax> <mathjax>#0.08mol#</mathjax></p> <p>Clearly, <mathjax>#O_2#</mathjax> is the <a href="https://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a>, and our calculation proceeds on the basis of the molar quantity of the gas. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">100 grams of magnesium and 2.50 grams of oxygen react together in synthesis reaction to form magnesium oxide. How do you write this balanced reaction?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-reactions-and-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions and Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="260641" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-04-30T15:27:46" itemprop="dateCreated"> Apr 30, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The balanced equation is clearly:</p> <p><mathjax>#Mg(s) + 1/2O_2(g) rarr MgO(s)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>It is abundantly clear that magnesium is in vast molar excess:</p> <p>i.e. <mathjax>#"Moles of metal"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(100g)/(24.31gmol^-1)#</mathjax> <mathjax>#~=#</mathjax> <mathjax>#5mol#</mathjax></p> <p><mathjax>#"Moles of dioxygen"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(2.5g)/(32.00gmol^-1)#</mathjax> <mathjax>#~=#</mathjax> <mathjax>#0.08mol#</mathjax></p> <p>Clearly, <mathjax>#O_2#</mathjax> is the <a href="https://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a>, and our calculation proceeds on the basis of the molar quantity of the gas. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/260641" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb002bf34694a4fee47"> Question #fee47 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb402bf34694c8c5c15"> Question #c5c15 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb802bf346950519eb9"> Question #19eb9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cbf02bf3469570e2ea2"> Question #e2ea2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc002bf34695a6bc751"> Question #bc751 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc202bf3469570e2ea6"> Question #e2ea6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531e867a02bf342492a08b07"> Question #08b07 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-thermochemical-equation-for-the-combustion-of-benzene"> What is the thermochemical equation for the combustion of benzene? 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How do you write this balanced reaction?	null
2,101	ab1923e8-6ddd-11ea-940e-ccda262736ce	https://socratic.org/questions/58f1d5287c0149461a5fd295	13.62 L	start physical_unit 3 4 volume l qc_end physical_unit 13 14 9 10 mass qc_end physical_unit 25 26 19 20 volume qc_end physical_unit 25 26 23 24 molarity qc_end end	[{"type":"physical unit","value":"Volume [OF] carbon dioxide [IN] L"}]	[{"type":"physical unit","value":"13.62 L"}]	[{"type":"physical unit","value":"Mass [OF] zinc carbonate [=] \\pu{25 g}"},{"type":"physical unit","value":"Volume [OF] nitric acid [=] \\pu{0.300 dm^3}"},{"type":"physical unit","value":"Molarity [OF] nitric acid [=] \\pu{2 mol/dm^3}"}]	<h1 class="questionTitle" itemprop="name">What volume of carbon dioxide would evolve if....?</h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>What volume of carbon dioxide would evolve if a <mathjax>#25g#</mathjax> mass of zinc carbonate is treated with a <mathjax>#0.300dm^3#</mathjax> volume of <mathjax>#2moldm^-3#</mathjax> nitric acid?</p></div> </h2> </div> </div>	13.62 L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Moles of zinc carbonate"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(25.0g)/(125.42gmol^-1)=0.199mol.#</mathjax></p> <p><mathjax>#"Moles of nitric acid"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.300dm^3xx2moldm^-3=0.60mol.#</mathjax></p> <p>clearly there is excess acid, and the reaction is stoichiometric in zinc carbonate. We should get <mathjax>#0.199mol#</mathjax> of <mathjax>#CO_2(g)#</mathjax> evolved. Under standard conditions (and you should check which standard conditions pertain - they vary across each syllabus), the molar volume is <mathjax>#22.7Lmol^-1#</mathjax>. And thus.........</p> <p><mathjax>#22.7Lmol^-1xx0.60mol=13-14*L#</mathjax>. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We interrogate the following reaction:</p> <p><mathjax>#ZnCO_3(s) + 2HNO_3(aq) rarr Zn(NO_3)_2(aq) + H_2O(l) + CO_2(g)uarr#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Moles of zinc carbonate"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(25.0g)/(125.42gmol^-1)=0.199mol.#</mathjax></p> <p><mathjax>#"Moles of nitric acid"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.300dm^3xx2moldm^-3=0.60mol.#</mathjax></p> <p>clearly there is excess acid, and the reaction is stoichiometric in zinc carbonate. We should get <mathjax>#0.199mol#</mathjax> of <mathjax>#CO_2(g)#</mathjax> evolved. Under standard conditions (and you should check which standard conditions pertain - they vary across each syllabus), the molar volume is <mathjax>#22.7Lmol^-1#</mathjax>. And thus.........</p> <p><mathjax>#22.7Lmol^-1xx0.60mol=13-14*L#</mathjax>. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What volume of carbon dioxide would evolve if....?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>What volume of carbon dioxide would evolve if a <mathjax>#25g#</mathjax> mass of zinc carbonate is treated with a <mathjax>#0.300dm^3#</mathjax> volume of <mathjax>#2moldm^-3#</mathjax> nitric acid?</p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="407079" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-15T09:00:37" itemprop="dateCreated"> Apr 15, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We interrogate the following reaction:</p> <p><mathjax>#ZnCO_3(s) + 2HNO_3(aq) rarr Zn(NO_3)_2(aq) + H_2O(l) + CO_2(g)uarr#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Moles of zinc carbonate"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(25.0g)/(125.42gmol^-1)=0.199mol.#</mathjax></p> <p><mathjax>#"Moles of nitric acid"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.300dm^3xx2moldm^-3=0.60mol.#</mathjax></p> <p>clearly there is excess acid, and the reaction is stoichiometric in zinc carbonate. We should get <mathjax>#0.199mol#</mathjax> of <mathjax>#CO_2(g)#</mathjax> evolved. Under standard conditions (and you should check which standard conditions pertain - they vary across each syllabus), the molar volume is <mathjax>#22.7Lmol^-1#</mathjax>. And thus.........</p> <p><mathjax>#22.7Lmol^-1xx0.60mol=13-14*L#</mathjax>. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/407079" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What is stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ab82402bf342f48d93ac6"> Question #93ac6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-we-study-stoichiometry"> Why do we study stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-naoh-is-produced-from-1-20-x-102-grams-of-na2o-na2o-h2o-2-naoh"> How many grams of NaOH is produced from #1.20 x 10^2# grams of #Na_2O#? #Na_2O + H_2O -> 2NaOH# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-na2o-are-required-to-produce-1-60-x-102-grams-of-naoh-na2o-h2o"> How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? 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What volume of carbon dioxide would evolve if a #25g# mass of zinc carbonate is treated with a #0.300dm^3# volume of #2moldm^-3# nitric acid?
2,102	acd88a6c-6ddd-11ea-965a-ccda262736ce	https://socratic.org/questions/what-is-the-molarity-of-a-solution-made-by-dissolving-8-56-g-of-sodium-acetate-i	0.14 M	start physical_unit 13 14 molarity mol/l qc_end physical_unit 13 14 10 11 mass qc_end physical_unit 6 6 20 21 volume qc_end substance 16 16 qc_end end	[{"type":"physical unit","value":"Molarity [OF] sodium acetate solution [IN] M"}]	[{"type":"physical unit","value":"0.14 M"}]	[{"type":"physical unit","value":"Mass [OF] sodium acetate [=] \\pu{8.56 g}"},{"type":"physical unit","value":"Volume [OF] sodium acetate solution [=] \\pu{750.0 mL}"},{"type":"substance name","value":"Water"}]	<h1 class="questionTitle" itemprop="name">What is the molarity of a solution made by dissolving 8.56 g of sodium acetate in water and diluting to 750.0 mL? </h1>	null	0.14 M	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a> is gm mole <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> dissolve per liter of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a>.<br/> The Mol. mass of sodium acetate is 82.0343 <br/> Since 82.0343 gm sodium acetate in 1000 ml of water is equal to 1 M molarity.</p> <p>So, </p> <p>8.56 gm dissolved in 750 ml of water </p> <p>hence <br/> <mathjax># 8.56/750*1000/82.0343=0.139#</mathjax></p> <p>Hence Molarity of solution is 0.139 M</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.139 M</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a> is gm mole <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> dissolve per liter of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a>.<br/> The Mol. mass of sodium acetate is 82.0343 <br/> Since 82.0343 gm sodium acetate in 1000 ml of water is equal to 1 M molarity.</p> <p>So, </p> <p>8.56 gm dissolved in 750 ml of water </p> <p>hence <br/> <mathjax># 8.56/750*1000/82.0343=0.139#</mathjax></p> <p>Hence Molarity of solution is 0.139 M</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the molarity of a solution made by dissolving 8.56 g of sodium acetate in water and diluting to 750.0 mL? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="348601" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/suresh-rawal"><img alt="" class="" src="https://profilepictures.socratic.org/xtD9rRMRMOIMqQl8Irg3_scan0002.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/suresh-rawal"> Suresh Rawal </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-12-08T04:33:54" itemprop="dateCreated"> Dec 8, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.139 M</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a> is gm mole <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> dissolve per liter of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a>.<br/> The Mol. mass of sodium acetate is 82.0343 <br/> Since 82.0343 gm sodium acetate in 1000 ml of water is equal to 1 M molarity.</p> <p>So, </p> <p>8.56 gm dissolved in 750 ml of water </p> <p>hence <br/> <mathjax># 8.56/750*1000/82.0343=0.139#</mathjax></p> <p>Hence Molarity of solution is 0.139 M</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/348601" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? 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2,103	a8ef52b6-6ddd-11ea-a4e4-ccda262736ce	https://socratic.org/questions/59722f087c01496a1d9b2efb	4.54 × 10^(-2) m^3	start physical_unit 9 10 volume m^3 qc_end physical_unit 9 10 5 6 mole qc_end physical_unit 9 10 12 13 temperature qc_end physical_unit 9 10 15 16 pressure qc_end end	[{"type":"physical unit","value":"Volume [OF] the Ideal Gas [IN] m^3"}]	[{"type":"physical unit","value":"4.54 × 10^(-2) m^3"}]	[{"type":"physical unit","value":"Mole [OF] the Ideal Gas [=] \\pu{2 mol}"},{"type":"physical unit","value":"Temperature [OF] the Ideal Gas [=] \\pu{0 ℃}"},{"type":"physical unit","value":"Pressure [OF] the Ideal Gas [=] \\pu{1 atm}"}]	<h1 class="questionTitle" itemprop="name">What is the volume of #2mol# of an Ideal Gas at #0# #""^@C#, and #1atm#?</h1>	null	4.54 × 10^(-2) m^3	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> says that, <mathjax>#pV=nRT#</mathjax>, where:<br/> <mathjax>#p#</mathjax> = pressure (<mathjax>#Pa#</mathjax>)<br/> <mathjax>#V#</mathjax> = volume (<mathjax>#m^3#</mathjax>)<br/> <mathjax>#n#</mathjax> = number of moles (<mathjax>#mol#</mathjax>)<br/> <mathjax>#R#</mathjax> = gas constant, (<mathjax>#8.31J#</mathjax> <mathjax>#K^(-1)#</mathjax> <mathjax>#mol^(-1)#</mathjax>)<br/> <mathjax>#T#</mathjax> = temperature (<mathjax>#K#</mathjax>)</p> <p><mathjax>#1#</mathjax> <mathjax>#atm ~~ 100000Pa#</mathjax><br/> <mathjax>#0^circC ~~ 273^circK#</mathjax></p> <p><mathjax>#V=(nRT)/P=(28.31273)/100000=0.0453726m^3~~0.0454m^3=4.54*10^(-2)m^3#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#4.5410^(-2)m^3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> says that, <mathjax>#pV=nRT#</mathjax>, where:<br/> <mathjax>#p#</mathjax> = pressure (<mathjax>#Pa#</mathjax>)<br/> <mathjax>#V#</mathjax> = volume (<mathjax>#m^3#</mathjax>)<br/> <mathjax>#n#</mathjax> = number of moles (<mathjax>#mol#</mathjax>)<br/> <mathjax>#R#</mathjax> = gas constant, (<mathjax>#8.31J#</mathjax> <mathjax>#K^(-1)#</mathjax> <mathjax>#mol^(-1)#</mathjax>)<br/> <mathjax>#T#</mathjax> = temperature (<mathjax>#K#</mathjax>)</p> <p><mathjax>#1#</mathjax> <mathjax>#atm ~~ 100000Pa#</mathjax><br/> <mathjax>#0^circC ~~ 273^circK#</mathjax></p> <p><mathjax>#V=(nRT)/P=(28.31273)/100000=0.0453726m^3~~0.0454m^3=4.5410^(-2)m^3#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the volume of #2mol# of an Ideal Gas at #0# #""^@C#, and #1atm#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/ideal-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Ideal Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="454652" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/idkwhatname"><img alt="" class="" src="https://profilepictures.socratic.org/FoNvPMlqRulVUxwohUEn_download%20%281%29.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/idkwhatname"> IDKwhatName </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-07-21T16:56:31" itemprop="dateCreated"> Jul 21, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#4.5410^(-2)m^3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> says that, <mathjax>#pV=nRT#</mathjax>, where:<br/> <mathjax>#p#</mathjax> = pressure (<mathjax>#Pa#</mathjax>)<br/> <mathjax>#V#</mathjax> = volume (<mathjax>#m^3#</mathjax>)<br/> <mathjax>#n#</mathjax> = number of moles (<mathjax>#mol#</mathjax>)<br/> <mathjax>#R#</mathjax> = gas constant, (<mathjax>#8.31J#</mathjax> <mathjax>#K^(-1)#</mathjax> <mathjax>#mol^(-1)#</mathjax>)<br/> <mathjax>#T#</mathjax> = temperature (<mathjax>#K#</mathjax>)</p> <p><mathjax>#1#</mathjax> <mathjax>#atm ~~ 100000Pa#</mathjax><br/> <mathjax>#0^circC ~~ 273^circK#</mathjax></p> <p><mathjax>#V=(nRT)/P=(28.31273)/100000=0.0453726m^3~~0.0454m^3=4.5410^(-2)m^3#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/454652" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul 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R = 8.314 kPa L / (K mol) =... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-molar-mass-of-a-gas"> How do you calculate the molar mass of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-should-i-use-the-ideal-gas-law-and-not-the-combined-gas-law"> When should I use the ideal gas law and not the combined gas law? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/ideal-gas-law"> See all questions in Ideal Gas Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1522 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the volume of #2mol# of an Ideal Gas at #0# #""^@C#, and #1atm#?	null
2,104	ac574df0-6ddd-11ea-b1c7-ccda262736ce	https://socratic.org/questions/58c7613411ef6b407b51a712	0.51 g/L	start physical_unit 5 6 density g/l qc_end physical_unit 5 6 11 12 pressure qc_end physical_unit 5 6 17 18 temperature qc_end end	[{"type":"physical unit","value":"Density [OF] neon gas [IN] g/L"}]	[{"type":"physical unit","value":"0.51 g/L"}]	[{"type":"physical unit","value":"Pressure [OF] neon gas [=] \\pu{505 mmHg}"},{"type":"physical unit","value":"Temperature [OF] neon gas [=] \\pu{318 K}"}]	<h1 class="questionTitle" itemprop="name">What is the density of neon gas given a pressure of #505mmHg#, and a temperature of #318*K#?</h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>What is the density of neon gas given a pressure of <mathjax>#505mmHg#</mathjax>, and a temperature of <mathjax>#318*K#</mathjax>?</p></div> </h2> </div> </div>	0.51 g/L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Now, we know <mathjax>#PV=nRT#</mathjax>, for an Ideal Gas, and we ASSUME that neon will approximate Ideal Gas behaviour.</p> <p>From the equation: <mathjax>#P/(RT)=n/V=("mass"/"molar mass")/V#</mathjax></p> <p><mathjax>#P/(RT)=("mass"/"molar mass")/V=rhoxx1/"molar mass"#</mathjax></p> <p>And thus, (FINALLY!): <mathjax>#rho=P/(RT)xx"molar mass"#</mathjax></p> <p>And we plug in the given numbers:</p> <p><mathjax>#rho=((505mmHg)/(760mmHgatm^-1)xx20.18gmol^-1)/(0.0821(Latm)/(K^-1mol^-1)xx318K)~=0.51g*L^-1#</mathjax></p> <p>The units are appropriate for <a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a>, as we require. Please check my figures and assumptions; there is a lot of 'rithmetic here.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We assume a litre volume of gas under these conditions.</p> <p>And get <mathjax>#rho=0.5gL^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Now, we know <mathjax>#PV=nRT#</mathjax>, for an Ideal Gas, and we ASSUME that neon will approximate Ideal Gas behaviour.</p> <p>From the equation: <mathjax>#P/(RT)=n/V=("mass"/"molar mass")/V#</mathjax></p> <p><mathjax>#P/(RT)=("mass"/"molar mass")/V=rhoxx1/"molar mass"#</mathjax></p> <p>And thus, (FINALLY!): <mathjax>#rho=P/(RT)xx"molar mass"#</mathjax></p> <p>And we plug in the given numbers:</p> <p><mathjax>#rho=((505mmHg)/(760mmHgatm^-1)xx20.18gmol^-1)/(0.0821(Latm)/(K^-1mol^-1)xx318K)~=0.51g*L^-1#</mathjax></p> <p>The units are appropriate for <a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a>, as we require. Please check my figures and assumptions; there is a lot of 'rithmetic here.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the density of neon gas given a pressure of #505mmHg#, and a temperature of #318K#?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>What is the density of neon gas given a pressure of <mathjax>#505mmHg#</mathjax>, and a temperature of <mathjax>#318K#</mathjax>?</p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/ideal-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Ideal Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="390973" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-14T04:00:18" itemprop="dateCreated"> Mar 14, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We assume a litre volume of gas under these conditions.</p> <p>And get <mathjax>#rho=0.5gL^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Now, we know <mathjax>#PV=nRT#</mathjax>, for an Ideal Gas, and we ASSUME that neon will approximate Ideal Gas behaviour.</p> <p>From the equation: <mathjax>#P/(RT)=n/V=("mass"/"molar mass")/V#</mathjax></p> <p><mathjax>#P/(RT)=("mass"/"molar mass")/V=rhoxx1/"molar mass"#</mathjax></p> <p>And thus, (FINALLY!): <mathjax>#rho=P/(RT)xx"molar mass"#</mathjax></p> <p>And we plug in the given numbers:</p> <p><mathjax>#rho=((505mmHg)/(760mmHgatm^-1)xx20.18gmol^-1)/(0.0821(Latm)/(K^-1mol^-1)xx318K)~=0.51g*L^-1#</mathjax></p> <p>The units are appropriate for <a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a>, as we require. Please check my figures and assumptions; there is a lot of 'rithmetic here.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/390973" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-ideal-gas-constant"> How do you find the ideal gas constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-solve-ideal-gas-law-problems"> How do you solve ideal gas law problems? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-know-which-ideal-gas-constant-to-use"> How do you know which ideal gas constant to use? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ideal-gas-constant-for-butane"> What is the ideal gas constant for butane? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-ideal-gas-law-in-kelvin"> Why is ideal gas law in kelvin? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ideal-gas-constant-important"> Why is the ideal gas constant important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-di-electric-constant"> What is the di-electric constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-volume-l-will-0-20-mol-hi-occupy-at-300-k-and-100-0-kpa-r-8-314-kpa-l-k-mol"> What volume (L) will 0.20 mol HI occupy at 300 K and 100.0 kPa? R = 8.314 kPa L / (K mol) =... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-molar-mass-of-a-gas"> How do you calculate the molar mass of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-should-i-use-the-ideal-gas-law-and-not-the-combined-gas-law"> When should I use the ideal gas law and not the combined gas law? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/ideal-gas-law"> See all questions in Ideal Gas Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2135 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the density of neon gas given a pressure of #505mmHg#, and a temperature of #318*K#?	What is the density of neon gas given a pressure of #505mmHg#, and a temperature of #318*K#?
2,105	a9af9efe-6ddd-11ea-9519-ccda262736ce	https://socratic.org/questions/how-many-grams-of-co-2-are-produced-when-88-g-of-o-2-are-reacted-with-an-excess-	69 grams	start physical_unit 4 4 mass g qc_end physical_unit 11 11 8 9 mass qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Mass [OF] CO2 [IN] grams"}]	[{"type":"physical unit","value":"69 grams"}]	[{"type":"physical unit","value":"Mass [OF] O2 [=] \\pu{88 g}"},{"type":"other","value":"Excess of ethane."}]	<h1 class="questionTitle" itemprop="name">How many grams of #CO_2# are produced when 88 g of #O_2# are reacted with an excess of ethane?</h1>	null	69 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Ethane's formula is <mathjax>#C_2H_6#</mathjax>. These products and reactants are common in combustion reactions, below is the balanced reaction. This is the key to solving this problem.</p> <p><mathjax>#2C_2H_6+7O_2 to 6H_2O+ 4CO_2#</mathjax></p> <p>The question tells us <mathjax>#C_2H_6#</mathjax> is the excess reactant, thus <mathjax>#O_2#</mathjax> is the limiting reactant. </p> <p><mathjax>#88g((O_2)/(32g))((4CO_2)/(7O_2))((44.01g)/(CO_2)) = 69g#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>69g of <mathjax>#CO_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Ethane's formula is <mathjax>#C_2H_6#</mathjax>. These products and reactants are common in combustion reactions, below is the balanced reaction. This is the key to solving this problem.</p> <p><mathjax>#2C_2H_6+7O_2 to 6H_2O+ 4CO_2#</mathjax></p> <p>The question tells us <mathjax>#C_2H_6#</mathjax> is the excess reactant, thus <mathjax>#O_2#</mathjax> is the limiting reactant. </p> <p><mathjax>#88g((O_2)/(32g))((4CO_2)/(7O_2))((44.01g)/(CO_2)) = 69g#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many grams of #CO_2# are produced when 88 g of #O_2# are reacted with an excess of ethane?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/equation-stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Equation Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="443964" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/al-e"><img alt="" class="" src="https://lh4.googleusercontent.com/-oz5UmZwruBQ/AAAAAAAAAAI/AAAAAAAAAFs/Oc0IDeN2ejw/photo.jpg?sz=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/al-e"> Al E. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-24T19:42:50" itemprop="dateCreated"> Jun 24, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>69g of <mathjax>#CO_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Ethane's formula is <mathjax>#C_2H_6#</mathjax>. These products and reactants are common in combustion reactions, below is the balanced reaction. This is the key to solving this problem.</p> <p><mathjax>#2C_2H_6+7O_2 to 6H_2O+ 4CO_2#</mathjax></p> <p>The question tells us <mathjax>#C_2H_6#</mathjax> is the excess reactant, thus <mathjax>#O_2#</mathjax> is the limiting reactant. </p> <p><mathjax>#88g((O_2)/(32g))((4CO_2)/(7O_2))((44.01g)/(CO_2)) = 69g#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/443964" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4171602bf3469588dc36e"> What are the types of stoichiometry examples, with examples? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4171802bf3469570e2e82"> Question #e2e82 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/533668a402bf34573b4e66fb"> What mass of carbon dioxide can 1.00 kg of lithium oxide absorb? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-an-example-of-a-stoichiometry-practice-problem"> What is an example of a stoichiometry practice problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-an-example-of-a-balanced-equation-practice-problem"> What is an example of a balanced equation practice problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-a-chemical-equation"> How can I balance a chemical equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-stoichiometry-be-used"> How can stoichiometry be used? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-stoichiometric-ratios-relate-reactants-to-products"> How do stoichiometric ratios relate reactants to products? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-gas-stoichiometry-differ-from-stoichiometry-of-solids-and-liquids"> How does gas stoichiometry differ from stoichiometry of solids and liquids? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-stoichiometry-relate-to-the-law-of-conservation"> How does stoichiometry relate to the law of conservation? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/equation-stoichiometry"> See all questions in Equation Stoichiometry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 6388 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many grams of #CO_2# are produced when 88 g of #O_2# are reacted with an excess of ethane?	null
2,106	ac6fefb0-6ddd-11ea-91cf-ccda262736ce	https://socratic.org/questions/what-is-the-volume-of-80-g-o-2-at-stp	56.00 L	start physical_unit 7 7 volume l qc_end physical_unit 7 7 5 6 mass qc_end c_other STP qc_end end	[{"type":"physical unit","value":"Volume [OF] O2 [IN] L"}]	[{"type":"physical unit","value":"56.00 L"}]	[{"type":"physical unit","value":"Mass [OF] O2 [=] \\pu{80 g}"},{"type":"other","value":"STP"}]	<h1 class="questionTitle" itemprop="name">What is the volume of 80 g #O_2# at STP?</h1>	null	56.00 L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So, all you have to do is calculate how many moles of oxygen you have (and oxygen like most gases save the Noble gases is diatomic), and multiply this by the molar volume at <mathjax>#273K#</mathjax>, <mathjax>#22.4#</mathjax> <mathjax>#L#</mathjax> <mathjax>#mol^-1#</mathjax>.</p> <p>If you look in the literature, you will find that the molar volume of oxygen is slightly different than that predicted by the ideal gas equation. It will be close, and that is why the ideal gas equation is widely used.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>At standard temperature and pressures, a molar quantity of an ideal gas has a volume of <mathjax>#22.4#</mathjax> <mathjax>#L#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So, all you have to do is calculate how many moles of oxygen you have (and oxygen like most gases save the Noble gases is diatomic), and multiply this by the molar volume at <mathjax>#273K#</mathjax>, <mathjax>#22.4#</mathjax> <mathjax>#L#</mathjax> <mathjax>#mol^-1#</mathjax>.</p> <p>If you look in the literature, you will find that the molar volume of oxygen is slightly different than that predicted by the ideal gas equation. It will be close, and that is why the ideal gas equation is widely used.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the volume of 80 g #O_2# at STP?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp" itemprop="url"> <span class="breadcrumb" itemprop="title">Molar Volume of a Gas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="185041" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-07T08:09:41" itemprop="dateCreated"> Nov 7, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>At standard temperature and pressures, a molar quantity of an ideal gas has a volume of <mathjax>#22.4#</mathjax> <mathjax>#L#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So, all you have to do is calculate how many moles of oxygen you have (and oxygen like most gases save the Noble gases is diatomic), and multiply this by the molar volume at <mathjax>#273K#</mathjax>, <mathjax>#22.4#</mathjax> <mathjax>#L#</mathjax> <mathjax>#mol^-1#</mathjax>.</p> <p>If you look in the literature, you will find that the molar volume of oxygen is slightly different than that predicted by the ideal gas equation. It will be close, and that is why the ideal gas equation is widely used.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/185041" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-stoichiometric-ratios-relate-to-molar-volume-of-a-gas"> How do stoichiometric ratios relate to molar volume of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-a-gas-at-stp"> How do you calculate molar volume of a gas at STP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-molar-volume-of-hydrogen-gas"> How do you find the molar volume of hydrogen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-oxygen-gas"> How do you calculate molar volume of oxygen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molar-gas-volume"> What is molar gas volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/534c7bf202bf3420a007f014"> What is the volume at 0 °C and 1 atm of a mixture that contains 4.0 g of methane and 2.0 g of helium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5361f75702bf3429040e0599"> What is the difference between STP and NTP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-volume-of-25-moles-of-oxygen-o2-gas"> What is the volume of .25 moles of oxygen (O2) Gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-would-knowing-the-molar-volume-of-a-gas-be-important"> Why would knowing the molar volume of a gas be important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-22-4-liters-called-the-molar-volume-of-a-gas"> Why is 22.4 liters called the molar volume of a gas? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp"> See all questions in Molar Volume of a Gas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 6584 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the volume of 80 g #O_2# at STP?	null
2,107	ad1b8dcd-6ddd-11ea-8067-ccda262736ce	https://socratic.org/questions/how-many-grams-of-hydrogen-are-necessary-to-react-completely-with-2-3-moles-of-n	13.80 grams	start physical_unit 4 4 mass g qc_end physical_unit 14 14 11 12 mole qc_end chemical_equation 18 24 qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Mass [OF] hydrogen [IN] grams"}]	[{"type":"physical unit","value":"13.80 grams"}]	[{"type":"physical unit","value":"Mole [OF] nitrogen [=] \\pu{2.3 moles}"},{"type":"chemical equation","value":"N2 + 3 H2 -> 2 NH3"},{"type":"other","value":"React completely."}]	<h1 class="questionTitle" itemprop="name">How many grams of hydrogen are necessary to react completely with 2.3 moles of nitrogen, in the reaction N2+3H2 = 2NH3?</h1>	null	13.80 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><ol> <li>Starting from moles of nitrogen, we'll find the moles of hydrogen using the stoichiometric coefficient (the number in front of <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a> in the balanced equation). </li> <li>then, from the moles of hydrogen, we'll use molar mass of hydrogen to find the mass of hydrogen. </li> </ol> <p>Here's how we can set it up,</p> <p><mathjax>#"mass of hydrogen"="2.3 mols " N_2("3 mols "H_2)/("1 mol "N_2)((2*1)"g/mol")/("3 mols "H_2)=4.6 g#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>4.6 g</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><ol> <li>Starting from moles of nitrogen, we'll find the moles of hydrogen using the stoichiometric coefficient (the number in front of <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a> in the balanced equation). </li> <li>then, from the moles of hydrogen, we'll use molar mass of hydrogen to find the mass of hydrogen. </li> </ol> <p>Here's how we can set it up,</p> <p><mathjax>#"mass of hydrogen"="2.3 mols " N_2("3 mols "H_2)/("1 mol "N_2)((2*1)"g/mol")/("3 mols "H_2)=4.6 g#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many grams of hydrogen are necessary to react completely with 2.3 moles of nitrogen, in the reaction N2+3H2 = 2NH3?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="637054" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/dr-k"><img alt="" class="" src="https://yt3.ggpht.com/-9hqy4z72uJU/AAAAAAAAAAI/AAAAAAAAAAA/U4oALcr4dCU/s88-c-k-no-mo-rj-c0xffffff/photo.jpg?sz=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/dr-k"> Dr. K. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-06-29T13:13:46" itemprop="dateCreated"> Jun 29, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>4.6 g</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><ol> <li>Starting from moles of nitrogen, we'll find the moles of hydrogen using the stoichiometric coefficient (the number in front of <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a> in the balanced equation). </li> <li>then, from the moles of hydrogen, we'll use molar mass of hydrogen to find the mass of hydrogen. </li> </ol> <p>Here's how we can set it up,</p> <p><mathjax>#"mass of hydrogen"="2.3 mols " N_2("3 mols "H_2)/("1 mol "N_2)((2*1)"g/mol")/("3 mols "H_2)=4.6 g#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/637054" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What is stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ab82402bf342f48d93ac6"> Question #93ac6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" 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2,108	abb2c628-6ddd-11ea-a54d-ccda262736ce	https://socratic.org/questions/how-would-you-balance-c3h8-o2-co2-h2o-1	C3H8 + 5 O2 -> 3 CO2 + 4 H2O	start chemical_equation qc_end chemical_equation 4 10 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the equation"}]	[{"type":"chemical equation","value":"C3H8 + 5 O2 -> 3 CO2 + 4 H2O"}]	[{"type":"chemical equation","value":"C3H8 + O2 -> CO2 + H2O"}]	<h1 class="questionTitle" itemprop="name">How would you balance: C3H8 + O2 --> CO2 + H2O? </h1>	null	C3H8 + 5 O2 -> 3 CO2 + 4 H2O	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This equation represents the combustion of proprane (a 3 carbon alkane) and it it highly exothermic, gives off heat, delta H < 0. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_3 H_8 + 5O_2 ->3CO_2 +4H_2 O#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This equation represents the combustion of proprane (a 3 carbon alkane) and it it highly exothermic, gives off heat, delta H < 0. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How would you balance: C3H8 + O2 --> CO2 + H2O? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="190462" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/trevor-r-1"><img alt="" class="" src="https://profilepictures.socratic.org/2Wf9lLD9RaSzPbXY0EW8_S5002678.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/trevor-r-1"> Trevor Ryan. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-19T05:06:34" itemprop="dateCreated"> Nov 19, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_3 H_8 + 5O_2 ->3CO_2 +4H_2 O#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This equation represents the combustion of proprane (a 3 carbon alkane) and it it highly exothermic, gives off heat, delta H < 0. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/190462" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? 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Sodium phosphate and calcium chloride react to form... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-equation-kclo3-kcl-o2"> How can I balance this equation? ____ #KClO_3 -># ____ #KCl +# ____ #O_2# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-balancing-chemical-equations-important"> Why is balancing chemical equations important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/balancing-chemical-equations"> See all questions in Balancing Chemical Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 14537 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How would you balance: C3H8 + O2 --> CO2 + H2O?	null
2,109	aae910da-6ddd-11ea-8ae4-ccda262736ce	https://socratic.org/questions/excess-pbbr2-s-is-placed-in-water-at-25-c-at-equilibrium-the-solution-contains-0	6.91 × 10^(-3)	start physical_unit 25 25 equilibrium_constant_k none qc_end c_other OTHER qc_end physical_unit 25 25 7 8 temperature qc_end physical_unit 16 16 14 15 molarity qc_end chemical_equation 26 31 qc_end end	[{"type":"physical unit","value":"Equilibrium constant [OF] the reaction"}]	[{"type":"physical unit","value":"6.91 × 10^(-3)"}]	[{"type":"other","value":"Excess PbBr2(s)"},{"type":"physical unit","value":"Temperature [OF] the reaction [=] \\pu{25 ℃}"},{"type":"physical unit","value":"Molarity [OF] Pb^2+(aq) [=] \\pu{0.012 M}"},{"type":"chemical equation","value":"PbBr2(s) -> Pb^2+(aq) + 2 Br-(aq)"}]	<h1 class="questionTitle" itemprop="name"> Excess PbBr2(s) is placed in water at 25 C. At equilibrium, the solution contains 0.012 M Pb 2+(aq). What is the equilibrium constant for the following reaction? PbBr2(s) --> Pb2+(aq) + 2Br-(aq)</h1>	null	6.91 × 10^(-3)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is just another equilibrium reaction in which the amount of <em>undissolved</em> lead bromide is irrelevant, and, therefore, does not appear in the equilibrium expression.</p> <p>We are given that at equilibrium, <mathjax>#[Pb^(2+)] = 0.012#</mathjax> <mathjax>#molL^(-1)#</mathjax>. By the <a href="http://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> of the reaction, <mathjax>#[Br^(-)] = 0.024#</mathjax> <mathjax>#molL^(-1)#</mathjax>, because for each lead iron in solution, two bromide ions go up.</p> <p>So, <mathjax>#K_(sp) = [Pb^(2+)][Br^-]^2#</mathjax> <mathjax>#=#</mathjax> <mathjax>#[0.012][0.024]^2 = ??#</mathjax></p> <p>Would you expect <mathjax>#K_(sp)#</mathjax> to increase or decrease at higher temperature? Why? Also, if the solution already had bromide ion present, would you expect solubility to go up or down?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#PbBr_2(s)rightleftharpoons Pb^(2+) + 2Br^-#</mathjax></p> <p><mathjax>#K_(sp) = [Pb^(2+)][Br^-]^2#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is just another equilibrium reaction in which the amount of <em>undissolved</em> lead bromide is irrelevant, and, therefore, does not appear in the equilibrium expression.</p> <p>We are given that at equilibrium, <mathjax>#[Pb^(2+)] = 0.012#</mathjax> <mathjax>#molL^(-1)#</mathjax>. By the <a href="http://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> of the reaction, <mathjax>#[Br^(-)] = 0.024#</mathjax> <mathjax>#molL^(-1)#</mathjax>, because for each lead iron in solution, two bromide ions go up.</p> <p>So, <mathjax>#K_(sp) = [Pb^(2+)][Br^-]^2#</mathjax> <mathjax>#=#</mathjax> <mathjax>#[0.012][0.024]^2 = ??#</mathjax></p> <p>Would you expect <mathjax>#K_(sp)#</mathjax> to increase or decrease at higher temperature? Why? Also, if the solution already had bromide ion present, would you expect solubility to go up or down?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name"> Excess PbBr2(s) is placed in water at 25 C. At equilibrium, the solution contains 0.012 M Pb 2+(aq). What is the equilibrium constant for the following reaction? PbBr2(s) --> Pb2+(aq) + 2Br-(aq)</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-equilibrium" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Equilibrium</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-equilibrium/dynamic-equilibrium" itemprop="url"> <span class="breadcrumb" itemprop="title">Dynamic Equilibrium</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="192514" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-24T07:08:16" itemprop="dateCreated"> Nov 24, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#PbBr_2(s)rightleftharpoons Pb^(2+) + 2Br^-#</mathjax></p> <p><mathjax>#K_(sp) = [Pb^(2+)][Br^-]^2#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is just another equilibrium reaction in which the amount of <em>undissolved</em> lead bromide is irrelevant, and, therefore, does not appear in the equilibrium expression.</p> <p>We are given that at equilibrium, <mathjax>#[Pb^(2+)] = 0.012#</mathjax> <mathjax>#molL^(-1)#</mathjax>. By the <a href="http://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> of the reaction, <mathjax>#[Br^(-)] = 0.024#</mathjax> <mathjax>#molL^(-1)#</mathjax>, because for each lead iron in solution, two bromide ions go up.</p> <p>So, <mathjax>#K_(sp) = [Pb^(2+)][Br^-]^2#</mathjax> <mathjax>#=#</mathjax> <mathjax>#[0.012][0.024]^2 = ??#</mathjax></p> <p>Would you expect <mathjax>#K_(sp)#</mathjax> to increase or decrease at higher temperature? Why? Also, if the solution already had bromide ion present, would you expect solubility to go up or down?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/192514" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-temperature-affect-dynamic-equilibrium"> How does temperature affect dynamic equilibrium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-dynamic-equilibrium-important-for-living-organisms"> Why is dynamic equilibrium important for living organisms? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-dynamic-equilibrium-1"> What is dynamic equilibrium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-common-mistakes-students-make-with-dynamic-equilibrium-1"> What are some common mistakes students make with dynamic equilibrium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-dynamic-equilibrium-be-disrupted"> Can dynamic equilibrium be disrupted? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-concentration-effect-dynamic-equilibrium"> How does concentration effect dynamic equilibrium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-dynamic-equilibrium-related-to-vapor-pressure-1"> How is dynamic equilibrium related to vapor pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-homeostasis-a-type-of-dynamic-equilibrium"> Is homeostasis a type of dynamic equilibrium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-the-concentration-of-reactants-equal-to-the-concentration-of-products-in-a-dy"> Is the concentration of reactants equal to the concentration of products in a dynamic equilibrium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/once-dynamic-equilibrium-is-established-will-it-shift-if-additional-reactants-ar"> Once dynamic equilibrium is established, will it shift if additional reactants are added? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-equilibrium/dynamic-equilibrium"> See all questions in Dynamic Equilibrium </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 6878 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Excess PbBr2(s) is placed in water at 25 C. At equilibrium, the solution contains 0.012 M Pb 2+(aq). What is the equilibrium constant for the following reaction? PbBr2(s) --> Pb2+(aq) + 2Br-(aq)	null
2,110	a9f689b5-6ddd-11ea-9d30-ccda262736ce	https://socratic.org/questions/which-is-the-balanced-equation-for-s-8-o-2-so-2	S8 + 8 O2 -> 8 SO2	start chemical_equation qc_end chemical_equation 6 10 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the equation"}]	[{"type":"chemical equation","value":"S8 + 8 O2 -> 8 SO2"}]	[{"type":"chemical equation","value":"S8 + O2 -> SO2"}]	<h1 class="questionTitle" itemprop="name">What is the balanced equation for #S_8+O_2->SO_2#?</h1>	null	S8 + 8 O2 -> 8 SO2	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Alternatively I could use a non-integral stoichiometric coefficient for sulfur:</p> <p><mathjax>#1/8S_8(s) + O_2(g) rarr SO_2(g)#</mathjax>, or more simply,</p> <p><mathjax>#S(s) + O_2(g) rarr SO_2(g)#</mathjax></p> <p>This form might make the arithmetic a bit easier. What is the oxidation state of <mathjax>#S#</mathjax> in <mathjax>#SO_2#</mathjax>?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#S_8(s) + 8O_2(g) rarr 8SO_2(g)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Alternatively I could use a non-integral stoichiometric coefficient for sulfur:</p> <p><mathjax>#1/8S_8(s) + O_2(g) rarr SO_2(g)#</mathjax>, or more simply,</p> <p><mathjax>#S(s) + O_2(g) rarr SO_2(g)#</mathjax></p> <p>This form might make the arithmetic a bit easier. What is the oxidation state of <mathjax>#S#</mathjax> in <mathjax>#SO_2#</mathjax>?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the balanced equation for #S_8+O_2->SO_2#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="254247" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-04-14T22:14:02" itemprop="dateCreated"> Apr 14, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#S_8(s) + 8O_2(g) rarr 8SO_2(g)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Alternatively I could use a non-integral stoichiometric coefficient for sulfur:</p> <p><mathjax>#1/8S_8(s) + O_2(g) rarr SO_2(g)#</mathjax>, or more simply,</p> <p><mathjax>#S(s) + O_2(g) rarr SO_2(g)#</mathjax></p> <p>This form might make the arithmetic a bit easier. What is the oxidation state of <mathjax>#S#</mathjax> in <mathjax>#SO_2#</mathjax>?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/254247" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------> H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -> Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? 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Sodium phosphate and calcium chloride react to form... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-equation-kclo3-kcl-o2"> How can I balance this equation? ____ #KClO_3 -># ____ #KCl +# ____ #O_2# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-balancing-chemical-equations-important"> Why is balancing chemical equations important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/balancing-chemical-equations"> See all questions in Balancing Chemical Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1381 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the balanced equation for #S_8+O_2->SO_2#?	null
2,111	a9a5b436-6ddd-11ea-92ea-ccda262736ce	https://socratic.org/questions/what-is-the-mole-ratio-of-h-2o-to-h-3po-4-in-the-following-chemical-equation-p-4	3:2	start physical_unit 6 8 mole_fraction none qc_end chemical_equation 14 20 qc_end end	[{"type":"physical unit","value":"Mole ratio [OF] H2O to H3PO4"}]	[{"type":"physical unit","value":"3:2"}]	[{"type":"chemical equation","value":"P4O10 + 6 H2O -> 4 H3PO4"}]	<h1 class="questionTitle" itemprop="name">What is the mole ratio of #H_2O# to #H_3PO_4# in the following chemical equation? #P_4O_10 + 6H_2O -> 4H_3PO_4#?</h1>	null	3:2	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And so the molar ration is <mathjax>#6:1#</mathjax>, <mathjax>#"water:phosphoric acid"#</mathjax>.......</p> <p>And you have written the stoichiometrically balanced chemical reaction to inform you. </p> <p>Note that <mathjax>#P_4O_10#</mathjax> is a common laboratory reagent for drying halogenated reagents such as methylene chloride. Because <mathjax>#P_4O_10#</mathjax> reacts with atmospheric water, often when you open a used bottle of phosphorus pentoxide, you see a sticky white syrup on the surface of the reagent, where atmospheric water has reacted with the oxide. When you dig down, sometimes you find the actual reagent, which should be a free-flowing powder. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well the <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> demands 6 equiv of water per 1 equiv water. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And so the molar ration is <mathjax>#6:1#</mathjax>, <mathjax>#"water:phosphoric acid"#</mathjax>.......</p> <p>And you have written the stoichiometrically balanced chemical reaction to inform you. </p> <p>Note that <mathjax>#P_4O_10#</mathjax> is a common laboratory reagent for drying halogenated reagents such as methylene chloride. Because <mathjax>#P_4O_10#</mathjax> reacts with atmospheric water, often when you open a used bottle of phosphorus pentoxide, you see a sticky white syrup on the surface of the reagent, where atmospheric water has reacted with the oxide. When you dig down, sometimes you find the actual reagent, which should be a free-flowing powder. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the mole ratio of #H_2O# to #H_3PO_4# in the following chemical equation? #P_4O_10 + 6H_2O -> 4H_3PO_4#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/mole-ratios" itemprop="url"> <span class="breadcrumb" itemprop="title">Mole Ratios</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="389612" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-11T07:28:37" itemprop="dateCreated"> Mar 11, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well the <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> demands 6 equiv of water per 1 equiv water. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And so the molar ration is <mathjax>#6:1#</mathjax>, <mathjax>#"water:phosphoric acid"#</mathjax>.......</p> <p>And you have written the stoichiometrically balanced chemical reaction to inform you. </p> <p>Note that <mathjax>#P_4O_10#</mathjax> is a common laboratory reagent for drying halogenated reagents such as methylene chloride. Because <mathjax>#P_4O_10#</mathjax> reacts with atmospheric water, often when you open a used bottle of phosphorus pentoxide, you see a sticky white syrup on the surface of the reagent, where atmospheric water has reacted with the oxide. When you dig down, sometimes you find the actual reagent, which should be a free-flowing powder. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/389612" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4178e02bf3469517a106e"> Question #a106e </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4178e02bf3469570e2e86"> Question #e2e86 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179102bf3469517a1072"> Question #a1072 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179402bf34694c8c5bf1"> Question #c5bf1 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179702bf3469588dc373"> Question #dc373 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179c02bf34694c8c5bf9"> Question #c5bf9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417a302bf3469517a1076"> Question #a1076 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417c702bf3469588dc377"> Question #dc377 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417d002bf346963eb984f"> Question #b984f </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417d402bf346950519ea3"> Question #19ea3 </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/mole-ratios"> See all questions in Mole Ratios </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 11289 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the mole ratio of #H_2O# to #H_3PO_4# in the following chemical equation? #P_4O_10 + 6H_2O -> 4H_3PO_4#?	null
2,112	ac455640-6ddd-11ea-9d7d-ccda262736ce	https://socratic.org/questions/if-1-0-g-of-hydrogen-reacts-completely-with-19-0-g-of-fluorine-what-is-the-perce	5%	start physical_unit 19 22 mass_percent none qc_end physical_unit 4 4 1 2 mass qc_end c_other OTHER qc_end physical_unit 11 11 8 9 mass qc_end end	[{"type":"physical unit","value":"Percent by mass [OF] hydrogen in the compound"}]	[{"type":"physical unit","value":"5%"}]	[{"type":"physical unit","value":"Mass [OF] hydrogen [=] \\pu{1.0 g}"},{"type":"other","value":"React completely."},{"type":"physical unit","value":"Mass [OF] fluorine [=] \\pu{19.0 g}"}]	<h1 class="questionTitle" itemprop="name">If 1.0 g of hydrogen reacts completely with 19.0 g of fluorine, what is the percent by mass of hydrogen in the compound that is formed?</h1>	null	5%	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>With all the problems, a stoichiometric equation is the prerequisite:</p> <p><mathjax>#1/2H_2(g) + 1/2F_2(g) rarr HF(g)#</mathjax></p> <p>As specified, you have stoichiometric equivalents of dihydrogen and difluorine. Why?</p> <p>And so <mathjax>#"percentage by mass hydrogen"#</mathjax></p> <p><mathjax>#="Mass of hydrogen"/"Mass of hydrogen fluoride"xx100%#</mathjax></p> <p><mathjax>#(1g)/(20g)xx100%=??%#</mathjax></p> <p>And thus <mathjax>#20*g#</mathjax> of hydrogen fluoride, which was the combined mass of the reactants, will result from stoichiometric reaction. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Well, 5%.......by mass......"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>With all the problems, a stoichiometric equation is the prerequisite:</p> <p><mathjax>#1/2H_2(g) + 1/2F_2(g) rarr HF(g)#</mathjax></p> <p>As specified, you have stoichiometric equivalents of dihydrogen and difluorine. Why?</p> <p>And so <mathjax>#"percentage by mass hydrogen"#</mathjax></p> <p><mathjax>#="Mass of hydrogen"/"Mass of hydrogen fluoride"xx100%#</mathjax></p> <p><mathjax>#(1g)/(20g)xx100%=??%#</mathjax></p> <p>And thus <mathjax>#20*g#</mathjax> of hydrogen fluoride, which was the combined mass of the reactants, will result from stoichiometric reaction. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">If 1.0 g of hydrogen reacts completely with 19.0 g of fluorine, what is the percent by mass of hydrogen in the compound that is formed?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/percent-composition" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Composition</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="380520" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-02-20T14:01:46" itemprop="dateCreated"> Feb 20, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Well, 5%.......by mass......"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>With all the problems, a stoichiometric equation is the prerequisite:</p> <p><mathjax>#1/2H_2(g) + 1/2F_2(g) rarr HF(g)#</mathjax></p> <p>As specified, you have stoichiometric equivalents of dihydrogen and difluorine. Why?</p> <p>And so <mathjax>#"percentage by mass hydrogen"#</mathjax></p> <p><mathjax>#="Mass of hydrogen"/"Mass of hydrogen fluoride"xx100%#</mathjax></p> <p><mathjax>#(1g)/(20g)xx100%=??%#</mathjax></p> <p>And thus <mathjax>#20*g#</mathjax> of hydrogen fluoride, which was the combined mass of the reactants, will result from stoichiometric reaction. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/380520" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-mole-percent"> What is mole percent? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4188602bf3469570e2e8b"> Question #e2e8b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4188702bf34695a6bc737"> Question #bc737 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418be02bf34695a6bc73b"> Question #bc73b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418c202bf3469570e2e8f"> Question #e2e8f </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418c802bf346963eb9857"> Question #b9857 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418ca02bf346963eb985b"> Question #b985b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418cc02bf34694a4fee41"> Question #fee41 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418d502bf34694c8c5c01"> Question #c5c01 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4196e02bf34695a6bc73f"> Question #bc73f </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/percent-composition"> See all questions in Percent Composition </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 26158 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	If 1.0 g of hydrogen reacts completely with 19.0 g of fluorine, what is the percent by mass of hydrogen in the compound that is formed?	null
2,113	a8eec7c7-6ddd-11ea-92ee-ccda262736ce	https://socratic.org/questions/how-much-would-a-dosage-of-1g-strontium-chloride-raise-the-ppm-in-a-total-water-	3.3 ppm	start physical_unit 8 8 concentration ppm qc_end physical_unit 8 10 6 7 mass qc_end physical_unit 19 19 22 23 volume qc_end end	[{"type":"physical unit","value":"Raised PPM [OF] strontium [IN] ppm"}]	[{"type":"physical unit","value":"3.3 ppm"}]	[{"type":"physical unit","value":"Mass [OF] strontium chloride hexahydrate [=] \\pu{1 g}"},{"type":"physical unit","value":"Total volume [OF] water [=] \\pu{100 L}"}]	<h1 class="questionTitle" itemprop="name">How much would a dosage of 1g strontium chloride hexahydrate raise the PPM of strontium in a total water volume of 100L? </h1>	null	3.3 ppm	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>PPM concentration is defined as <strong>one part <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a></strong> per <strong>one million parts solvent</strong>.</p> <p>To determine the concentration in PPM, you need to divide the mass of the solute <strong>in grams</strong> by the mass of the solvent <strong>in grams</strong>, and multiply the ratio by <mathjax>#10^6#</mathjax>. </p> <p>This is exactly what you would do to get the <em><a href="http://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration</a></em>, the only difference being that you multiply said ratio by <mathjax>#10^2#</mathjax>, not <mathjax>#10^6#</mathjax>. </p> <p>The important thing to remember about <em>hydrates</em> is that when you're adding them to water, you're essentially adding a combination of <strong>solute and solvent</strong> to your existing volume of water. </p> <p>To find the increase in strontium levels, you need to first determine two things</p> <ul> <li><em>the percent composition of strontium chloride in strontium chloride hexahydrate</em></li> <li><em>the percent composition of strontium in strontium chloride</em></li> </ul> <p>Let's start with the first one. Use the molar masses of the hydrate and of the anhydrous salt to get the percent composition of strontium chloride in the hydrate</p> <blockquote> <p><mathjax>#(158.526color(red)(cancel(color(black)("g/mol"))))/(266.618color(red)(cancel(color(black)("g/mol")))) * 100 = "59.46% SrCl"""_2#</mathjax></p> </blockquote> <p>This means that <strong>1 g</strong> of strontium chloride hexahydrate would contain </p> <blockquote> <p><mathjax>#1color(red)(cancel(color(black)("g hydrate"))) * ("59.46 g SrCl"""_2)/(100color(red)(cancel(color(black)("g hydrate")))) = "0.5946 g SrCl"""_2#</mathjax></p> </blockquote> <p>Now use strontium's's molar mass to find out the percent composition of strontium in strontium chloride</p> <blockquote> <p><mathjax>#(87.62color(red)(cancel(color(black)("g/mol"))))/(158.526color(red)(cancel(color(black)("g/mol")))) * 100 = "55.27% Sr"#</mathjax></p> </blockquote> <p>This means that <strong>0.5946 g</strong> of strontium chloride would contain </p> <blockquote> <p><mathjax>#0.5946color(red)(cancel(color(black)("g SrCl"""_2))) * "55.27 g Sr"/(100color(red)(cancel(color(black)("g SrCl"""_2)))) = "0.3286 g Sr"#</mathjax></p> </blockquote> <p>Now, to get the concetration of calcium in ppm, you need to divide this mass by the <strong>total mass of the solute</strong>. Since you're adding less than one gram of water to a volume of 100 L of water, you can safely assume that the volume will not change. </p> <p>The total mass of water will be - assuming a density of <mathjax>#"1000 g/L"#</mathjax>, will be</p> <blockquote> <p><mathjax>#100color(red)(cancel(color(black)("L"))) * "1000 g"/color(red)(cancel(color(black)("L"))) = 10^5"g water"#</mathjax></p> </blockquote> <p>The concentration in ppm for the strontium ions will be </p> <blockquote> <p><mathjax>#(0.3286color(red)(cancel(color(black)("g"))))/(10^5color(red)(cancel(color(black)("g")))) * 10^6 = color(green)("3.3 ppm")#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>That much <em>strontium chloride hexahydrate</em> in that much water would increase the concentration of strontium ions by <mathjax>#"3.3 ppm"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>PPM concentration is defined as <strong>one part <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a></strong> per <strong>one million parts solvent</strong>.</p> <p>To determine the concentration in PPM, you need to divide the mass of the solute <strong>in grams</strong> by the mass of the solvent <strong>in grams</strong>, and multiply the ratio by <mathjax>#10^6#</mathjax>. </p> <p>This is exactly what you would do to get the <em><a href="http://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration</a></em>, the only difference being that you multiply said ratio by <mathjax>#10^2#</mathjax>, not <mathjax>#10^6#</mathjax>. </p> <p>The important thing to remember about <em>hydrates</em> is that when you're adding them to water, you're essentially adding a combination of <strong>solute and solvent</strong> to your existing volume of water. </p> <p>To find the increase in strontium levels, you need to first determine two things</p> <ul> <li><em>the percent composition of strontium chloride in strontium chloride hexahydrate</em></li> <li><em>the percent composition of strontium in strontium chloride</em></li> </ul> <p>Let's start with the first one. Use the molar masses of the hydrate and of the anhydrous salt to get the percent composition of strontium chloride in the hydrate</p> <blockquote> <p><mathjax>#(158.526color(red)(cancel(color(black)("g/mol"))))/(266.618color(red)(cancel(color(black)("g/mol")))) * 100 = "59.46% SrCl"""_2#</mathjax></p> </blockquote> <p>This means that <strong>1 g</strong> of strontium chloride hexahydrate would contain </p> <blockquote> <p><mathjax>#1color(red)(cancel(color(black)("g hydrate"))) * ("59.46 g SrCl"""_2)/(100color(red)(cancel(color(black)("g hydrate")))) = "0.5946 g SrCl"""_2#</mathjax></p> </blockquote> <p>Now use strontium's's molar mass to find out the percent composition of strontium in strontium chloride</p> <blockquote> <p><mathjax>#(87.62color(red)(cancel(color(black)("g/mol"))))/(158.526color(red)(cancel(color(black)("g/mol")))) * 100 = "55.27% Sr"#</mathjax></p> </blockquote> <p>This means that <strong>0.5946 g</strong> of strontium chloride would contain </p> <blockquote> <p><mathjax>#0.5946color(red)(cancel(color(black)("g SrCl"""_2))) * "55.27 g Sr"/(100color(red)(cancel(color(black)("g SrCl"""_2)))) = "0.3286 g Sr"#</mathjax></p> </blockquote> <p>Now, to get the concetration of calcium in ppm, you need to divide this mass by the <strong>total mass of the solute</strong>. Since you're adding less than one gram of water to a volume of 100 L of water, you can safely assume that the volume will not change. </p> <p>The total mass of water will be - assuming a density of <mathjax>#"1000 g/L"#</mathjax>, will be</p> <blockquote> <p><mathjax>#100color(red)(cancel(color(black)("L"))) * "1000 g"/color(red)(cancel(color(black)("L"))) = 10^5"g water"#</mathjax></p> </blockquote> <p>The concentration in ppm for the strontium ions will be </p> <blockquote> <p><mathjax>#(0.3286color(red)(cancel(color(black)("g"))))/(10^5color(red)(cancel(color(black)("g")))) * 10^6 = color(green)("3.3 ppm")#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How much would a dosage of 1g strontium chloride hexahydrate raise the PPM of strontium in a total water volume of 100L? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/solving-using-ppm-parts-per-million" itemprop="url"> <span class="breadcrumb" itemprop="title">Solving Using PPM (Parts Per Million)</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="166747" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-09-08T16:46:09" itemprop="dateCreated"> Sep 8, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>That much <em>strontium chloride hexahydrate</em> in that much water would increase the concentration of strontium ions by <mathjax>#"3.3 ppm"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>PPM concentration is defined as <strong>one part <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a></strong> per <strong>one million parts solvent</strong>.</p> <p>To determine the concentration in PPM, you need to divide the mass of the solute <strong>in grams</strong> by the mass of the solvent <strong>in grams</strong>, and multiply the ratio by <mathjax>#10^6#</mathjax>. </p> <p>This is exactly what you would do to get the <em><a href="http://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration</a></em>, the only difference being that you multiply said ratio by <mathjax>#10^2#</mathjax>, not <mathjax>#10^6#</mathjax>. </p> <p>The important thing to remember about <em>hydrates</em> is that when you're adding them to water, you're essentially adding a combination of <strong>solute and solvent</strong> to your existing volume of water. </p> <p>To find the increase in strontium levels, you need to first determine two things</p> <ul> <li><em>the percent composition of strontium chloride in strontium chloride hexahydrate</em></li> <li><em>the percent composition of strontium in strontium chloride</em></li> </ul> <p>Let's start with the first one. Use the molar masses of the hydrate and of the anhydrous salt to get the percent composition of strontium chloride in the hydrate</p> <blockquote> <p><mathjax>#(158.526color(red)(cancel(color(black)("g/mol"))))/(266.618color(red)(cancel(color(black)("g/mol")))) * 100 = "59.46% SrCl"""_2#</mathjax></p> </blockquote> <p>This means that <strong>1 g</strong> of strontium chloride hexahydrate would contain </p> <blockquote> <p><mathjax>#1color(red)(cancel(color(black)("g hydrate"))) * ("59.46 g SrCl"""_2)/(100color(red)(cancel(color(black)("g hydrate")))) = "0.5946 g SrCl"""_2#</mathjax></p> </blockquote> <p>Now use strontium's's molar mass to find out the percent composition of strontium in strontium chloride</p> <blockquote> <p><mathjax>#(87.62color(red)(cancel(color(black)("g/mol"))))/(158.526color(red)(cancel(color(black)("g/mol")))) * 100 = "55.27% Sr"#</mathjax></p> </blockquote> <p>This means that <strong>0.5946 g</strong> of strontium chloride would contain </p> <blockquote> <p><mathjax>#0.5946color(red)(cancel(color(black)("g SrCl"""_2))) * "55.27 g Sr"/(100color(red)(cancel(color(black)("g SrCl"""_2)))) = "0.3286 g Sr"#</mathjax></p> </blockquote> <p>Now, to get the concetration of calcium in ppm, you need to divide this mass by the <strong>total mass of the solute</strong>. Since you're adding less than one gram of water to a volume of 100 L of water, you can safely assume that the volume will not change. </p> <p>The total mass of water will be - assuming a density of <mathjax>#"1000 g/L"#</mathjax>, will be</p> <blockquote> <p><mathjax>#100color(red)(cancel(color(black)("L"))) * "1000 g"/color(red)(cancel(color(black)("L"))) = 10^5"g water"#</mathjax></p> </blockquote> <p>The concentration in ppm for the strontium ions will be </p> <blockquote> <p><mathjax>#(0.3286color(red)(cancel(color(black)("g"))))/(10^5color(red)(cancel(color(black)("g")))) * 10^6 = color(green)("3.3 ppm")#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/166747" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-ppm"> What is PPM? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-ppm-be-calculated-in-chemistry"> How can PPM be calculated in chemistry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-ppm-a-useful-measurement"> Why is PPM a useful measurement? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/54c39459581e2a50bb6742ad"> Question #742ad </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/54c4d4dc581e2a50d46797aa"> Question #797aa </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/h2s-g-concentrations-of-660ppm-is-dangerous-6-h2s-generators-continually-release"> H2S (g) concentrations of 660ppm is dangerous. 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2,114	ac974ef1-6ddd-11ea-bece-ccda262736ce	https://socratic.org/questions/56a8e93d11ef6b294638b7ab	5 S2O3^2- + 8 MnO4- + 14 H+ -> 8Mn^2+ + 10 SO4^2- + 7H2O(l)	start chemical_equation qc_end chemical_equation 4 4 qc_end chemical_equation 9 9 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the equation"}]	[{"type":"chemical equation","value":"5 S2O3^2- + 8 MnO4- + 14 H+ -> 8Mn^2+ + 10 SO4^2- + 7H2O(l)"}]	[{"type":"chemical equation","value":"S2O3^2-"},{"type":"chemical equation","value":"MnO4-"}]	<h1 class="questionTitle" itemprop="name">How is #"thiosulfate anion"#, #S_2O_3^(2-)#, oxidized by #"permanganate anion"#, #MnO_4^(-)#?</h1>	null	5 S2O3^2- + 8 MnO4- + 14 H+ -> 8Mn^2+ + 10 SO4^2- + 7H2O(l)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Thiosulfate is oxidized to sulfate <mathjax>#S(II)rarrS(VI)#</mathjax>:</p> <p><mathjax>#S_2O_3^(2-) + 5H_2O rarr 2SO_4^(2-) + 10H^(+) + 8e^-#</mathjax> <mathjax>#(i)#</mathjax></p> <p>Permanganate (<mathjax>#Mn(VII)#</mathjax>) is reduced to <mathjax>#Mn^(2+)#</mathjax>:</p> <p><mathjax>#MnO_4^(-) + 8H^(+) + 5e^(-) rarr Mn^(2+) +4H_2O(l)#</mathjax> <mathjax>#(ii)#</mathjax></p> <p>If we take <mathjax>#5xx(i)+8xx(ii)#</mathjax> (we do this cross-multiplication so that electrons, <mathjax>#e^ -#</mathjax>, do not appear in the reaction), we get (finally!):</p> <p><mathjax>#8MnO_4^(-) + 5S_2O_3^(2-) +14H^(+)rarr 8Mn^(2+) +10SO_4^(2-)+7H_2O(l)#</mathjax></p> <p>This equation (I think) is balanced with respect to mass and charge (I did a double take when I realized there were 47 oxygens on each side!). The reaction is also self-indicating: deep purple permanganate ion is reduced to (almost) colourless <mathjax>#Mn^(2+)#</mathjax>. I leave it to you to give the complete reaction (i.e. where <mathjax>#MnO_4^-#</mathjax> appears as <mathjax>#KMnO_4#</mathjax> and thiosulfate appears as <mathjax>#Na_2S_2O_3#</mathjax>).</p> <p>Note that I designated the AVERAGE oxidation state of sulfur in thiosulfate as <mathjax>#+II#</mathjax>. I could have treated the terminal sulfur as the analogue of oxygen in sulfate, i.e. a <mathjax>#-II#</mathjax> oxidation state, and the central sulfur as the analogue of the central sulfur in sulfate, i.e. <mathjax>#+VI#</mathjax>. The average oxidation state of <mathjax>#S#</mathjax> of course is the same, <mathjax>#+II#</mathjax> in each case.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#5S_2O_3^(2-) + 8MnO_4^(-) + 14H^(+) rarr 8Mn^(2+) + 10SO_4^(2-) + 7H_2O(l)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Thiosulfate is oxidized to sulfate <mathjax>#S(II)rarrS(VI)#</mathjax>:</p> <p><mathjax>#S_2O_3^(2-) + 5H_2O rarr 2SO_4^(2-) + 10H^(+) + 8e^-#</mathjax> <mathjax>#(i)#</mathjax></p> <p>Permanganate (<mathjax>#Mn(VII)#</mathjax>) is reduced to <mathjax>#Mn^(2+)#</mathjax>:</p> <p><mathjax>#MnO_4^(-) + 8H^(+) + 5e^(-) rarr Mn^(2+) +4H_2O(l)#</mathjax> <mathjax>#(ii)#</mathjax></p> <p>If we take <mathjax>#5xx(i)+8xx(ii)#</mathjax> (we do this cross-multiplication so that electrons, <mathjax>#e^ -#</mathjax>, do not appear in the reaction), we get (finally!):</p> <p><mathjax>#8MnO_4^(-) + 5S_2O_3^(2-) +14H^(+)rarr 8Mn^(2+) +10SO_4^(2-)+7H_2O(l)#</mathjax></p> <p>This equation (I think) is balanced with respect to mass and charge (I did a double take when I realized there were 47 oxygens on each side!). The reaction is also self-indicating: deep purple permanganate ion is reduced to (almost) colourless <mathjax>#Mn^(2+)#</mathjax>. I leave it to you to give the complete reaction (i.e. where <mathjax>#MnO_4^-#</mathjax> appears as <mathjax>#KMnO_4#</mathjax> and thiosulfate appears as <mathjax>#Na_2S_2O_3#</mathjax>).</p> <p>Note that I designated the AVERAGE oxidation state of sulfur in thiosulfate as <mathjax>#+II#</mathjax>. I could have treated the terminal sulfur as the analogue of oxygen in sulfate, i.e. a <mathjax>#-II#</mathjax> oxidation state, and the central sulfur as the analogue of the central sulfur in sulfate, i.e. <mathjax>#+VI#</mathjax>. The average oxidation state of <mathjax>#S#</mathjax> of course is the same, <mathjax>#+II#</mathjax> in each case.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How is #"thiosulfate anion"#, #S_2O_3^(2-)#, oxidized by #"permanganate anion"#, #MnO_4^(-)#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#electrochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Electrochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/electrochemistry/balancing-redox-equations-using-the-oxidation-number-method" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Redox Equations Using the Oxidation Number Method</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="217932" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-27T18:09:37" itemprop="dateCreated"> Jan 27, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#5S_2O_3^(2-) + 8MnO_4^(-) + 14H^(+) rarr 8Mn^(2+) + 10SO_4^(2-) + 7H_2O(l)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Thiosulfate is oxidized to sulfate <mathjax>#S(II)rarrS(VI)#</mathjax>:</p> <p><mathjax>#S_2O_3^(2-) + 5H_2O rarr 2SO_4^(2-) + 10H^(+) + 8e^-#</mathjax> <mathjax>#(i)#</mathjax></p> <p>Permanganate (<mathjax>#Mn(VII)#</mathjax>) is reduced to <mathjax>#Mn^(2+)#</mathjax>:</p> <p><mathjax>#MnO_4^(-) + 8H^(+) + 5e^(-) rarr Mn^(2+) +4H_2O(l)#</mathjax> <mathjax>#(ii)#</mathjax></p> <p>If we take <mathjax>#5xx(i)+8xx(ii)#</mathjax> (we do this cross-multiplication so that electrons, <mathjax>#e^ -#</mathjax>, do not appear in the reaction), we get (finally!):</p> <p><mathjax>#8MnO_4^(-) + 5S_2O_3^(2-) +14H^(+)rarr 8Mn^(2+) +10SO_4^(2-)+7H_2O(l)#</mathjax></p> <p>This equation (I think) is balanced with respect to mass and charge (I did a double take when I realized there were 47 oxygens on each side!). The reaction is also self-indicating: deep purple permanganate ion is reduced to (almost) colourless <mathjax>#Mn^(2+)#</mathjax>. I leave it to you to give the complete reaction (i.e. where <mathjax>#MnO_4^-#</mathjax> appears as <mathjax>#KMnO_4#</mathjax> and thiosulfate appears as <mathjax>#Na_2S_2O_3#</mathjax>).</p> <p>Note that I designated the AVERAGE oxidation state of sulfur in thiosulfate as <mathjax>#+II#</mathjax>. I could have treated the terminal sulfur as the analogue of oxygen in sulfate, i.e. a <mathjax>#-II#</mathjax> oxidation state, and the central sulfur as the analogue of the central sulfur in sulfate, i.e. <mathjax>#+VI#</mathjax>. The average oxidation state of <mathjax>#S#</mathjax> of course is the same, <mathjax>#+II#</mathjax> in each case.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/217932" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-balance-redox-reactions-in-basic-solution"> How do you balance redox reactions in basic solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-balance-redox-equations-by-oxidation-number-method"> How do you balance redox equations by oxidation number method? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-balance-redox-equations-in-acidic-solutions"> How do you balance redox equations in acidic solutions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-method"> What is the oxidation number method? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-examples-of-balancing-redox-equations-using-the-oxidation-number-m"> What are some examples of balancing redox equations using the oxidation number method? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-oxidation-number-method-useful"> Why is the oxidation number method useful? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-it-necessary-to-break-the-equation-into-half-reactions-in-the-oxidation-numbe"> Is it necessary to break the equation into half reactions in the oxidation number method? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-difference-between-the-oxidation-number-method-and-the-ion-electron-"> What is the difference between the oxidation number method and the ion-electron method? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-balance-the-equation-using-the-oxidation-states-method-mno2-al-mn-al2o3"> Can you balance the equation using the oxidation states method MnO2+Al--->Mn+Al2O3? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-balance-this-redox-reaction-using-the-oxidation-number-method-fe2-aq-"> How do you balance this redox reaction using the oxidation number method? Fe2+(aq) + MnO4–(aq)... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/electrochemistry/balancing-redox-equations-using-the-oxidation-number-method"> See all questions in Balancing Redox Equations Using the Oxidation Number Method </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 9617 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How is #"thiosulfate anion"#, #S_2O_3^(2-)#, oxidized by #"permanganate anion"#, #MnO_4^(-)#?	null
2,115	ac65b71e-6ddd-11ea-a086-ccda262736ce	https://socratic.org/questions/2-moles-pcl5-are-heated-in-a-2l-flask-at-equilibrium-40-pcl5-dissociates-what-is	0.27	start physical_unit 21 22 equilibrium_constant_k none qc_end physical_unit 2 2 0 1 mole qc_end physical_unit 9 9 7 8 volume qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Equilibrium constant [OF] this reaction"}]	[{"type":"physical unit","value":"0.27"}]	[{"type":"physical unit","value":"Mole [OF] PCl5 [=] \\pu{2 moles}"},{"type":"physical unit","value":"Volume [OF] flask [=] \\pu{2 L}"},{"type":"other","value":"At equilibrium."},{"type":"physical unit","value":"Percent [OF] PCl5 dissociated [=] \\pu{40%}"}]	<h1 class="questionTitle" itemprop="name">2 moles PCl5 are heated in a 2L flask.At equilibrium 40% PCl5 dissociates . what is the equilibrium constant for this reaction?</h1>	null	0.27	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>THE GIVEN REVERSIBLE GASEOUS REACTION & ICE TABLE</p> <p><mathjax>#" "PCl_5(g)" "rightleftharpoons" "PCl_3(g)" "+" "Cl_2(g)#</mathjax></p> <p><strong>I</strong> <mathjax>#" "2" mol"" "" "" "" "0 " mol"" "" "" "" "0" mol"#</mathjax></p> <p><strong>C</strong> <mathjax>#-2alpha" mol"" "" "" "" "2alpha " mol" " "" "" "2alpha" mol"#</mathjax></p> <p><strong>E</strong> <mathjax>#" "2(1-alpha)" mol"" "2alpha" mol"" "" "" "2alpha" " "mol"#</mathjax></p> <p><mathjax>#"Where degree of dissociation, "alpha=40%=0.4#</mathjax> </p> <p><mathjax>#"Volume of the equilibrium mixture, V = 2 L"#</mathjax></p> <p>At equilibrium the molar concentrations of the components of the mixture are</p> <p><mathjax>#[PCl_5(g) ] =(2(1-alpha))/V=(2(1-0.4))/2= "0.6 mol·L"^-1#</mathjax></p> <p><mathjax>#[PCl_3(g) ]=(2(alpha))/V=(2xx0.4)/2= "0.4 mol·L"^-1#</mathjax></p> <p><mathjax>#[Cl_2(g) ]=(2(alpha))/V=(2xx0.4)/2="0.4 mol·L"^-1#</mathjax></p> <p><strong>Equilibrium constant</strong></p> <p><mathjax>#" "K_c=([PCl_3(g) ]xx[Cl_2(g) ]) /[(PCl_5(g) ) ]#</mathjax></p> <p><mathjax>#" "=(0.4xx0.4)/0.6 " mol·L"^-1#</mathjax></p> <p><mathjax>#" "=0.27 " mol·L"^-1#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#K_c = 0.27#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>THE GIVEN REVERSIBLE GASEOUS REACTION & ICE TABLE</p> <p><mathjax>#" "PCl_5(g)" "rightleftharpoons" "PCl_3(g)" "+" "Cl_2(g)#</mathjax></p> <p><strong>I</strong> <mathjax>#" "2" mol"" "" "" "" "0 " mol"" "" "" "" "0" mol"#</mathjax></p> <p><strong>C</strong> <mathjax>#-2alpha" mol"" "" "" "" "2alpha " mol" " "" "" "2alpha" mol"#</mathjax></p> <p><strong>E</strong> <mathjax>#" "2(1-alpha)" mol"" "2alpha" mol"" "" "" "2alpha" " "mol"#</mathjax></p> <p><mathjax>#"Where degree of dissociation, "alpha=40%=0.4#</mathjax> </p> <p><mathjax>#"Volume of the equilibrium mixture, V = 2 L"#</mathjax></p> <p>At equilibrium the molar concentrations of the components of the mixture are</p> <p><mathjax>#[PCl_5(g) ] =(2(1-alpha))/V=(2(1-0.4))/2= "0.6 mol·L"^-1#</mathjax></p> <p><mathjax>#[PCl_3(g) ]=(2(alpha))/V=(2xx0.4)/2= "0.4 mol·L"^-1#</mathjax></p> <p><mathjax>#[Cl_2(g) ]=(2(alpha))/V=(2xx0.4)/2="0.4 mol·L"^-1#</mathjax></p> <p><strong>Equilibrium constant</strong></p> <p><mathjax>#" "K_c=([PCl_3(g) ]xx[Cl_2(g) ]) /[(PCl_5(g) ) ]#</mathjax></p> <p><mathjax>#" "=(0.4xx0.4)/0.6 " mol·L"^-1#</mathjax></p> <p><mathjax>#" "=0.27 " mol·L"^-1#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">2 moles PCl5 are heated in a 2L flask.At equilibrium 40% PCl5 dissociates . what is the equilibrium constant for this reaction?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-equilibrium" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Equilibrium</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-equilibrium/equilibrium-stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Equilibrium Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="303240" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/dk-ch"><img alt="" class="" src="https://profilepictures.socratic.org/0aBlt69MSiWhfD1SEqb8_lotus.jpg" title=""/></a> <a class="secondContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/dk-ch"> P dilip_k </a>·<a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a>·<a class="topContributorLink" href="/users/truong-son-n"> Truong-Son N. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-08-27T16:45:16" itemprop="dateCreated"> Aug 27, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#K_c = 0.27#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>THE GIVEN REVERSIBLE GASEOUS REACTION & ICE TABLE</p> <p><mathjax>#" "PCl_5(g)" "rightleftharpoons" "PCl_3(g)" "+" "Cl_2(g)#</mathjax></p> <p><strong>I</strong> <mathjax>#" "2" mol"" "" "" "" "0 " mol"" "" "" "" "0" mol"#</mathjax></p> <p><strong>C</strong> <mathjax>#-2alpha" mol"" "" "" "" "2alpha " mol" " "" "" "2alpha" mol"#</mathjax></p> <p><strong>E</strong> <mathjax>#" "2(1-alpha)" mol"" "2alpha" mol"" "" "" "2alpha" " "mol"#</mathjax></p> <p><mathjax>#"Where degree of dissociation, "alpha=40%=0.4#</mathjax> </p> <p><mathjax>#"Volume of the equilibrium mixture, V = 2 L"#</mathjax></p> <p>At equilibrium the molar concentrations of the components of the mixture are</p> <p><mathjax>#[PCl_5(g) ] =(2(1-alpha))/V=(2(1-0.4))/2= "0.6 mol·L"^-1#</mathjax></p> <p><mathjax>#[PCl_3(g) ]=(2(alpha))/V=(2xx0.4)/2= "0.4 mol·L"^-1#</mathjax></p> <p><mathjax>#[Cl_2(g) ]=(2(alpha))/V=(2xx0.4)/2="0.4 mol·L"^-1#</mathjax></p> <p><strong>Equilibrium constant</strong></p> <p><mathjax>#" "K_c=([PCl_3(g) ]xx[Cl_2(g) ]) /[(PCl_5(g) ) ]#</mathjax></p> <p><mathjax>#" "=(0.4xx0.4)/0.6 " mol·L"^-1#</mathjax></p> <p><mathjax>#" "=0.27 " mol·L"^-1#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/303240" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-a-sample-of-no-g-11-75-mol-is-placed-in-440-0-l-reaction-vessel-at-882-0-k-"> When a sample of NO(g) (11.75 mol) is placed in 440.0 L reaction vessel at 882.0 K and allowed... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" 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2,116	acd88a6d-6ddd-11ea-a7be-ccda262736ce	https://socratic.org/questions/what-is-the-initial-partial-pressure-in-mmhg-of-n2o5-g	21 mmHg	start physical_unit 9 9 pressure mmhg qc_end physical_unit 9 9 11 12 temperature qc_end c_other OTHER qc_end physical_unit 9 9 22 23 half-life qc_end chemical_equation 24 30 qc_end physical_unit 9 9 31 32 mass qc_end physical_unit 42 42 40 41 volume qc_end end	[{"type":"physical unit","value":"Pressure1 [OF] N2O5(g) [IN] mmHg"}]	[{"type":"physical unit","value":"21 mmHg"}]	[{"type":"physical unit","value":"Temperature [OF] N2O5(g) [=] \\pu{65 ℃}"},{"type":"other","value":"First-order decomposition."},{"type":"physical unit","value":"Half-life [OF] N2O5 [=] \\pu{2.38 min}"},{"type":"chemical equation","value":"N2O5(g) -> 2 NO2(g) + 1/2 O2(g)"},{"type":"physical unit","value":"Mass [OF] N2O5 [=] \\pu{1.50 g}"},{"type":"physical unit","value":"Volume [OF] flask [=] \\pu{14 L}"}]	<h1 class="questionTitle" itemprop="name">What is the initial partial pressure, in mmHg, of N2O5(g)?</h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>At 65∘C, the half-life for the first-order decomposition of N2O5 is 2.38 min.<br/> <mathjax>#N_2O_5(g)#</mathjax>→<mathjax>#2NO_2(g)+1/2O_2(g)#</mathjax><br/> 1.50 g of N2O5 is introduced into an evacuated 14 −L flask at 65∘C.</p></div> </h2> </div> </div>	21 mmHg	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>I suspect that there is more to this question than what you've added here since all you have to do to find out the initial <a href="https://socratic.org/chemistry/the-behavior-of-gases/partial-pressure">partial pressure</a> of dinitrogen pentoxide is use the <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> equation</strong>. </p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)(PV = nRT)))#</mathjax></p> </blockquote> <p>Here</p> <blockquote> <ul> <li><mathjax>#P#</mathjax> is the pressure of the gas</li> <li><mathjax>#V#</mathjax> is the volume it occupies</li> <li><mathjax>#n#</mathjax> is the number of moles of gas present in the sample</li> <li><mathjax>#R#</mathjax> is the <em>universal gas constant</em>, equal to <mathjax>#0.0821("atm L")/("mol K")#</mathjax></li> <li><mathjax>#T#</mathjax> is the <strong>absolute temperature</strong> of the gas</li> </ul> </blockquote> <p>Convert the mass of dinitrogen pentoxide to <em>moles</em> by using the compound's <strong>molar mass</strong></p> <blockquote> <p><mathjax>#1.50 color(red)(cancel(color(black)("g"))) * ("1 mole N"_2"O"_5)/(108.01color(red)(cancel(color(black)("g")))) = "0.01389 moles N"_2"O"_5#</mathjax></p> </blockquote> <p>Rearrange the ideal gas law equation to solve for <mathjax>#P#</mathjax></p> <blockquote> <p><mathjax>#PV = nRT implies P = (nRT)/V#</mathjax></p> </blockquote> <p>make sure to convert the temperature to <em>Kelvin</em> and plug in your values to find</p> <blockquote> <p><mathjax>#P = (0.01389 color(red)(cancel(color(black)("moles"))) * 0.0821("atm" * color(red)(cancel(color(black)("L"))))/(color(red)(cancel(color(black)("mol"))) * color(red)(cancel(color(black)("K")))) * (273.15 + 65) color(red)(cancel(color(black)("K"))))/(14color(red)(cancel(color(black)("L"))))#</mathjax></p> <p><mathjax>#P = "0.02754 atm"#</mathjax></p> </blockquote> <p>To convert this to <em>mmHg</em>, use the fact that</p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)("1 atm = 760 mmHg")))#</mathjax></p> </blockquote> <p>You should end up with </p> <blockquote> <p><mathjax>#0.02754 color(red)(cancel(color(black)("atm"))) * "760 mmHg"/(1color(red)(cancel(color(black)("atm")))) = color(darkgreen)(ul(color(black)("21 mmHg")))#</mathjax></p> </blockquote> <p>The answer is rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"21 mmHg"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>I suspect that there is more to this question than what you've added here since all you have to do to find out the initial <a href="https://socratic.org/chemistry/the-behavior-of-gases/partial-pressure">partial pressure</a> of dinitrogen pentoxide is use the <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> equation</strong>. </p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)(PV = nRT)))#</mathjax></p> </blockquote> <p>Here</p> <blockquote> <ul> <li><mathjax>#P#</mathjax> is the pressure of the gas</li> <li><mathjax>#V#</mathjax> is the volume it occupies</li> <li><mathjax>#n#</mathjax> is the number of moles of gas present in the sample</li> <li><mathjax>#R#</mathjax> is the <em>universal gas constant</em>, equal to <mathjax>#0.0821("atm L")/("mol K")#</mathjax></li> <li><mathjax>#T#</mathjax> is the <strong>absolute temperature</strong> of the gas</li> </ul> </blockquote> <p>Convert the mass of dinitrogen pentoxide to <em>moles</em> by using the compound's <strong>molar mass</strong></p> <blockquote> <p><mathjax>#1.50 color(red)(cancel(color(black)("g"))) * ("1 mole N"_2"O"_5)/(108.01color(red)(cancel(color(black)("g")))) = "0.01389 moles N"_2"O"_5#</mathjax></p> </blockquote> <p>Rearrange the ideal gas law equation to solve for <mathjax>#P#</mathjax></p> <blockquote> <p><mathjax>#PV = nRT implies P = (nRT)/V#</mathjax></p> </blockquote> <p>make sure to convert the temperature to <em>Kelvin</em> and plug in your values to find</p> <blockquote> <p><mathjax>#P = (0.01389 color(red)(cancel(color(black)("moles"))) * 0.0821("atm" * color(red)(cancel(color(black)("L"))))/(color(red)(cancel(color(black)("mol"))) * color(red)(cancel(color(black)("K")))) * (273.15 + 65) color(red)(cancel(color(black)("K"))))/(14color(red)(cancel(color(black)("L"))))#</mathjax></p> <p><mathjax>#P = "0.02754 atm"#</mathjax></p> </blockquote> <p>To convert this to <em>mmHg</em>, use the fact that</p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)("1 atm = 760 mmHg")))#</mathjax></p> </blockquote> <p>You should end up with </p> <blockquote> <p><mathjax>#0.02754 color(red)(cancel(color(black)("atm"))) * "760 mmHg"/(1color(red)(cancel(color(black)("atm")))) = color(darkgreen)(ul(color(black)("21 mmHg")))#</mathjax></p> </blockquote> <p>The answer is rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the initial partial pressure, in mmHg, of N2O5(g)?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>At 65∘C, the half-life for the first-order decomposition of N2O5 is 2.38 min.<br/> <mathjax>#N_2O_5(g)#</mathjax>→<mathjax>#2NO_2(g)+1/2O_2(g)#</mathjax><br/> 1.50 g of N2O5 is introduced into an evacuated 14 −L flask at 65∘C.</p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/partial-pressure" itemprop="url"> <span class="breadcrumb" itemprop="title">Partial Pressure</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="382121" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-02-24T01:46:01" itemprop="dateCreated"> Feb 24, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"21 mmHg"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>I suspect that there is more to this question than what you've added here since all you have to do to find out the initial <a href="https://socratic.org/chemistry/the-behavior-of-gases/partial-pressure">partial pressure</a> of dinitrogen pentoxide is use the <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> equation</strong>. </p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)(PV = nRT)))#</mathjax></p> </blockquote> <p>Here</p> <blockquote> <ul> <li><mathjax>#P#</mathjax> is the pressure of the gas</li> <li><mathjax>#V#</mathjax> is the volume it occupies</li> <li><mathjax>#n#</mathjax> is the number of moles of gas present in the sample</li> <li><mathjax>#R#</mathjax> is the <em>universal gas constant</em>, equal to <mathjax>#0.0821("atm L")/("mol K")#</mathjax></li> <li><mathjax>#T#</mathjax> is the <strong>absolute temperature</strong> of the gas</li> </ul> </blockquote> <p>Convert the mass of dinitrogen pentoxide to <em>moles</em> by using the compound's <strong>molar mass</strong></p> <blockquote> <p><mathjax>#1.50 color(red)(cancel(color(black)("g"))) * ("1 mole N"_2"O"_5)/(108.01color(red)(cancel(color(black)("g")))) = "0.01389 moles N"_2"O"_5#</mathjax></p> </blockquote> <p>Rearrange the ideal gas law equation to solve for <mathjax>#P#</mathjax></p> <blockquote> <p><mathjax>#PV = nRT implies P = (nRT)/V#</mathjax></p> </blockquote> <p>make sure to convert the temperature to <em>Kelvin</em> and plug in your values to find</p> <blockquote> <p><mathjax>#P = (0.01389 color(red)(cancel(color(black)("moles"))) * 0.0821("atm" * color(red)(cancel(color(black)("L"))))/(color(red)(cancel(color(black)("mol"))) * color(red)(cancel(color(black)("K")))) * (273.15 + 65) color(red)(cancel(color(black)("K"))))/(14color(red)(cancel(color(black)("L"))))#</mathjax></p> <p><mathjax>#P = "0.02754 atm"#</mathjax></p> </blockquote> <p>To convert this to <em>mmHg</em>, use the fact that</p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)("1 atm = 760 mmHg")))#</mathjax></p> </blockquote> <p>You should end up with </p> <blockquote> <p><mathjax>#0.02754 color(red)(cancel(color(black)("atm"))) * "760 mmHg"/(1color(red)(cancel(color(black)("atm")))) = color(darkgreen)(ul(color(black)("21 mmHg")))#</mathjax></p> </blockquote> <p>The answer is rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/382121" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/534e256802bf342adfa30010"> How do you do a steam distillation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/53613f9f02bf3416cd9f8a34"> Question #f8a34 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-i-calculate-the-total-pressure-of-a-mixture-of-gases-by-adding-together-the-"> Can I calculate the total pressure of a mixture of gases by adding together the partial... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" 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At 65∘C, the half-life for the first-order decomposition of N2O5 is 2.38 min. #N_2O_5(g)#→#2NO_2(g)+1/2O_2(g)# 1.50 g of N2O5 is introduced into an evacuated 14 −L flask at 65∘C.
2,117	a8c5cefb-6ddd-11ea-a60e-ccda262736ce	https://socratic.org/questions/how-would-you-balance-h3bo3-h4b6o11-h2o	6 H3BO3 -> H4B6O11 + 7 H2O	start chemical_equation qc_end chemical_equation 4 8 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the equation"}]	[{"type":"chemical equation","value":"6 H3BO3 -> H4B6O11 + 7 H2O"}]	[{"type":"chemical equation","value":"H3BO3 -> H4B6O11 + H2O"}]	<h1 class="questionTitle" itemprop="name">How would you balance #"H"_3"BO"_3"##rarr##"H"_4"B"_6"O"_11" +H"_2"O"#?</h1>	null	6 H3BO3 -> H4B6O11 + 7 H2O	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This answer balances the equation by equating (the conservation of) the number of boron atoms on both sides of the equation.</p> <p><mathjax>#"H"_3"BO"_3#</mathjax> and <mathjax>#"H"_4"B"_6"O"_11#</mathjax> are the only two boron-containing species in this reaction. Each molecule of <mathjax>#"H"_3 color(navy)("B")"O"_3#</mathjax> contains one boron <mathjax>#"B"#</mathjax> atom whereas each molecule of <mathjax>#"H"_4color(navy)("B"_6)"O"_11#</mathjax> contains six. Add the coefficient <mathjax>#"color(navy)(6)#</mathjax> to the front of <mathjax>#"H"_3 "BO"_3#</mathjax> and <mathjax>#color(navy)(1)#</mathjax> to <mathjax>#"H"_4"B"_6"O"_11#</mathjax> balance the number of boron atoms on the two sides.</p> <p><mathjax>#color(purple)(6) color(white)(l)"H"_3color(navy)("B")"O"_3#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#color(purple)(1) color(white)(l) "H"_4color(navy)("B"_6) "O"_11 + "H"_2"O"#</mathjax> <mathjax>#color(grey)("NOT BALANCED")#</mathjax></p> <p>The left-hand side of the equation contains <mathjax>#6 xx 3 =18#</mathjax> oxygen <mathjax>#"O"#</mathjax> atoms. The number of oxygen atoms shall also conserve in this equation. Therefore <mathjax>#"H"_4"B"_6"O"_11#</mathjax> and <mathjax>#"H"_2"O"#</mathjax> on the product side shall contain a total of <mathjax>#18#</mathjax> oxygen atoms. <mathjax>#11#</mathjax> of them go to the <mathjax>#"H"_4color(navy)("B"_6)"O"_11#</mathjax> molecule. Water molecules would account for rest <mathjax>#7#</mathjax> oxygen atoms. </p> <p>Each water molecule contains one single oxygen atom. <mathjax>#7#</mathjax> of the oxygen atoms would thus correspond to <mathjax>#7#</mathjax> water molecules on the product side. Hence the equation:</p> <p><mathjax>#color(black)(6) color(white)(l)"H"_3color(black)("B")"O"_3#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#color(black)(1) color(white)(l) "H"_4color(black)("B"_6) "O"_11 + color(purple)(7) color(white)(l) "H"_2"O"#</mathjax> </p> <p>Optionally, check if the number of hydrogen <mathjax>#"H"#</mathjax> atoms on the two sides conserves to see if the equation is properly balanced:</p> <ul> <li>Number of <mathjax>#"H"#</mathjax> atoms on the right-hand side: <mathjax>#6 xx 3 = 18#</mathjax></li> <li>Number of <mathjax>#"H"#</mathjax> atoms on the left-hand side: <mathjax>#1 xx 4 + 7 xx 2 = 18#</mathjax></li> </ul> <p>The two numbers are equal, and thus this chemical equation is stoichiometrically balanced.</p> <p><mathjax>#color(darkgreen)(6) color(white)(l)"H"_3color(black)("B")"O"_3#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#color(darkgreen)(1) color(white)(l) "H"_4color(black)("B"_6) "O"_11 + color(darkgreen)(7) color(white)(l) "H"_2"O"#</mathjax> <mathjax>#color(grey)("Balanced")#</mathjax></p> <p><strong>Reference</strong><br/> "Balance Chemical Equation - Online Balancer," <a href="http://webqc.org" rel="nofollow" target="_blank">webqc.org</a>,<br/> <a href="https://www.webqc.org/balance.php" rel="nofollow" target="_blank">https://www.webqc.org/balance.php</a>, "Enter H3BO3 = H4B6O11 + H2O for this equation."</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#color(darkgreen)(6) color(white)(l)"H"_3color(black)("B")"O"_3#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#color(darkgreen)(1) color(white)(l) "H"_4color(black)("B"_6) "O"_11 + color(darkgreen)(7) color(white)(l) "H"_2"O"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This answer balances the equation by equating (the conservation of) the number of boron atoms on both sides of the equation.</p> <p><mathjax>#"H"_3"BO"_3#</mathjax> and <mathjax>#"H"_4"B"_6"O"_11#</mathjax> are the only two boron-containing species in this reaction. Each molecule of <mathjax>#"H"_3 color(navy)("B")"O"_3#</mathjax> contains one boron <mathjax>#"B"#</mathjax> atom whereas each molecule of <mathjax>#"H"_4color(navy)("B"_6)"O"_11#</mathjax> contains six. Add the coefficient <mathjax>#"color(navy)(6)#</mathjax> to the front of <mathjax>#"H"_3 "BO"_3#</mathjax> and <mathjax>#color(navy)(1)#</mathjax> to <mathjax>#"H"_4"B"_6"O"_11#</mathjax> balance the number of boron atoms on the two sides.</p> <p><mathjax>#color(purple)(6) color(white)(l)"H"_3color(navy)("B")"O"_3#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#color(purple)(1) color(white)(l) "H"_4color(navy)("B"_6) "O"_11 + "H"_2"O"#</mathjax> <mathjax>#color(grey)("NOT BALANCED")#</mathjax></p> <p>The left-hand side of the equation contains <mathjax>#6 xx 3 =18#</mathjax> oxygen <mathjax>#"O"#</mathjax> atoms. The number of oxygen atoms shall also conserve in this equation. Therefore <mathjax>#"H"_4"B"_6"O"_11#</mathjax> and <mathjax>#"H"_2"O"#</mathjax> on the product side shall contain a total of <mathjax>#18#</mathjax> oxygen atoms. <mathjax>#11#</mathjax> of them go to the <mathjax>#"H"_4color(navy)("B"_6)"O"_11#</mathjax> molecule. Water molecules would account for rest <mathjax>#7#</mathjax> oxygen atoms. </p> <p>Each water molecule contains one single oxygen atom. <mathjax>#7#</mathjax> of the oxygen atoms would thus correspond to <mathjax>#7#</mathjax> water molecules on the product side. Hence the equation:</p> <p><mathjax>#color(black)(6) color(white)(l)"H"_3color(black)("B")"O"_3#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#color(black)(1) color(white)(l) "H"_4color(black)("B"_6) "O"_11 + color(purple)(7) color(white)(l) "H"_2"O"#</mathjax> </p> <p>Optionally, check if the number of hydrogen <mathjax>#"H"#</mathjax> atoms on the two sides conserves to see if the equation is properly balanced:</p> <ul> <li>Number of <mathjax>#"H"#</mathjax> atoms on the right-hand side: <mathjax>#6 xx 3 = 18#</mathjax></li> <li>Number of <mathjax>#"H"#</mathjax> atoms on the left-hand side: <mathjax>#1 xx 4 + 7 xx 2 = 18#</mathjax></li> </ul> <p>The two numbers are equal, and thus this chemical equation is stoichiometrically balanced.</p> <p><mathjax>#color(darkgreen)(6) color(white)(l)"H"_3color(black)("B")"O"_3#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#color(darkgreen)(1) color(white)(l) "H"_4color(black)("B"_6) "O"_11 + color(darkgreen)(7) color(white)(l) "H"_2"O"#</mathjax> <mathjax>#color(grey)("Balanced")#</mathjax></p> <p><strong>Reference</strong><br/> "Balance Chemical Equation - Online Balancer," <a href="http://webqc.org" rel="nofollow" target="_blank">webqc.org</a>,<br/> <a href="https://www.webqc.org/balance.php" rel="nofollow" target="_blank">https://www.webqc.org/balance.php</a>, "Enter H3BO3 = H4B6O11 + H2O for this equation."</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How would you balance #"H"_3"BO"_3"##rarr##"H"_4"B"_6"O"_11" +H"_2"O"#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="644838" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/jacob-t-3"><img alt="" class="" src="https://profilepictures.socratic.org/cDl6OiFtT16bIyMtJPfM_Protractor.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/jacob-t-3"> Jacob T. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-07-31T19:19:11" itemprop="dateCreated"> Jul 31, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#color(darkgreen)(6) color(white)(l)"H"_3color(black)("B")"O"_3#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#color(darkgreen)(1) color(white)(l) "H"_4color(black)("B"_6) "O"_11 + color(darkgreen)(7) color(white)(l) "H"_2"O"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This answer balances the equation by equating (the conservation of) the number of boron atoms on both sides of the equation.</p> <p><mathjax>#"H"_3"BO"_3#</mathjax> and <mathjax>#"H"_4"B"_6"O"_11#</mathjax> are the only two boron-containing species in this reaction. Each molecule of <mathjax>#"H"_3 color(navy)("B")"O"_3#</mathjax> contains one boron <mathjax>#"B"#</mathjax> atom whereas each molecule of <mathjax>#"H"_4color(navy)("B"_6)"O"_11#</mathjax> contains six. Add the coefficient <mathjax>#"color(navy)(6)#</mathjax> to the front of <mathjax>#"H"_3 "BO"_3#</mathjax> and <mathjax>#color(navy)(1)#</mathjax> to <mathjax>#"H"_4"B"_6"O"_11#</mathjax> balance the number of boron atoms on the two sides.</p> <p><mathjax>#color(purple)(6) color(white)(l)"H"_3color(navy)("B")"O"_3#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#color(purple)(1) color(white)(l) "H"_4color(navy)("B"_6) "O"_11 + "H"_2"O"#</mathjax> <mathjax>#color(grey)("NOT BALANCED")#</mathjax></p> <p>The left-hand side of the equation contains <mathjax>#6 xx 3 =18#</mathjax> oxygen <mathjax>#"O"#</mathjax> atoms. The number of oxygen atoms shall also conserve in this equation. Therefore <mathjax>#"H"_4"B"_6"O"_11#</mathjax> and <mathjax>#"H"_2"O"#</mathjax> on the product side shall contain a total of <mathjax>#18#</mathjax> oxygen atoms. <mathjax>#11#</mathjax> of them go to the <mathjax>#"H"_4color(navy)("B"_6)"O"_11#</mathjax> molecule. Water molecules would account for rest <mathjax>#7#</mathjax> oxygen atoms. </p> <p>Each water molecule contains one single oxygen atom. <mathjax>#7#</mathjax> of the oxygen atoms would thus correspond to <mathjax>#7#</mathjax> water molecules on the product side. Hence the equation:</p> <p><mathjax>#color(black)(6) color(white)(l)"H"_3color(black)("B")"O"_3#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#color(black)(1) color(white)(l) "H"_4color(black)("B"_6) "O"_11 + color(purple)(7) color(white)(l) "H"_2"O"#</mathjax> </p> <p>Optionally, check if the number of hydrogen <mathjax>#"H"#</mathjax> atoms on the two sides conserves to see if the equation is properly balanced:</p> <ul> <li>Number of <mathjax>#"H"#</mathjax> atoms on the right-hand side: <mathjax>#6 xx 3 = 18#</mathjax></li> <li>Number of <mathjax>#"H"#</mathjax> atoms on the left-hand side: <mathjax>#1 xx 4 + 7 xx 2 = 18#</mathjax></li> </ul> <p>The two numbers are equal, and thus this chemical equation is stoichiometrically balanced.</p> <p><mathjax>#color(darkgreen)(6) color(white)(l)"H"_3color(black)("B")"O"_3#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#color(darkgreen)(1) color(white)(l) "H"_4color(black)("B"_6) "O"_11 + color(darkgreen)(7) color(white)(l) "H"_2"O"#</mathjax> <mathjax>#color(grey)("Balanced")#</mathjax></p> <p><strong>Reference</strong><br/> "Balance Chemical Equation - Online Balancer," <a href="http://webqc.org" rel="nofollow" target="_blank">webqc.org</a>,<br/> <a href="https://www.webqc.org/balance.php" rel="nofollow" target="_blank">https://www.webqc.org/balance.php</a>, "Enter H3BO3 = H4B6O11 + H2O for this equation."</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/644838" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------> H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -> Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? 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Sodium phosphate and calcium chloride react to form... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-equation-kclo3-kcl-o2"> How can I balance this equation? ____ #KClO_3 -># ____ #KCl +# ____ #O_2# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-balancing-chemical-equations-important"> Why is balancing chemical equations important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/balancing-chemical-equations"> See all questions in Balancing Chemical Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3943 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How would you balance #"H"_3"BO"_3"##rarr##"H"_4"B"_6"O"_11" +H"_2"O"#?	null
2,118	ab804a66-6ddd-11ea-8450-ccda262736ce	https://socratic.org/questions/what-mass-of-sulfur-gas-would-be-found-in-a-2-45-liter-container-at-satp	3.21 grams	start physical_unit 3 4 mass g qc_end physical_unit 3 4 10 11 volume qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Mass [OF] sulfur gas [IN] grams"}]	[{"type":"physical unit","value":"3.21 grams"}]	[{"type":"physical unit","value":"Volume [OF] sulfur gas [=] \\pu{2.45 liters}"},{"type":"other","value":"At SATP."}]	<h1 class="questionTitle" itemprop="name">What mass of sulfur gas would be found in a 2.45 liter container at SATP?</h1>	null	3.21 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We're asked to to find the mass of gaseous sulfur that occupies a volume of <mathjax>#2.45#</mathjax> <mathjax>#"L"#</mathjax> at <em>standard ambient temperature and pressure</em>.</p> <p>I'll assume for these purposes that the sulfur is present as individual, gaseous atoms, rather than <mathjax>#"S"_8#</mathjax> (which is reasonable considering <mathjax>#"S"_8#</mathjax> is a <em>solid</em> at these conditions). </p> <p>Standard ambient temperature and pressure (SATP) is defined as</p> <ul> <li> <p><mathjax>#298.15#</mathjax> <mathjax>#"K"#</mathjax> (temperature; equal to <mathjax>#25.0^"o""C"#</mathjax>)</p> </li> <li> <p><mathjax>#1#</mathjax> <mathjax>#"atm"#</mathjax> (pressure)</p> </li> </ul> <p>We can use the <strong>ideal-gas equation</strong> to solve for the number of moles of sulfur, <mathjax>#n#</mathjax>, knowing that the gas constant, <mathjax>#R#</mathjax> is equal to <mathjax>#0.082057("L"•"atm")/("mol"•"K")#</mathjax>:</p> <p><mathjax>#PV = nRT#</mathjax></p> <p><mathjax>#n = (PV)/(RT) = ((1cancel("atm"))(2.45cancel("L")))/((0.082057(cancel("L")•cancel("atm"))/("mol"•cancel("K")))(298.15cancel("K")))#</mathjax></p> <p><mathjax>#= color(red)(0.100#</mathjax> <mathjax>#color(red)("mol S"#</mathjax></p> <p>Now, let's use the <em>molar mass</em> of sulfur, <mathjax>#32.07#</mathjax> <mathjax>#"g/mol"#</mathjax>, to calculate the number of grams:</p> <p><mathjax>#0.100cancel("mol S")((32.07color(white)(l)"g S")/(1cancel("mol S"))) = color(blue)(3.21#</mathjax> <mathjax>#color(blue)("g S"#</mathjax></p> <p>Thus, if a <mathjax>#2.45#</mathjax>-<mathjax>#"L"#</mathjax> tank is filled with pure gaseous sulfur at SATP, we can expect the sulfur sample to have a mass of <mathjax>#color(blue)(3.21#</mathjax> <mathjax>#sfcolor(blue)("grams"#</mathjax>. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#3.21#</mathjax> <mathjax>#"g S"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We're asked to to find the mass of gaseous sulfur that occupies a volume of <mathjax>#2.45#</mathjax> <mathjax>#"L"#</mathjax> at <em>standard ambient temperature and pressure</em>.</p> <p>I'll assume for these purposes that the sulfur is present as individual, gaseous atoms, rather than <mathjax>#"S"_8#</mathjax> (which is reasonable considering <mathjax>#"S"_8#</mathjax> is a <em>solid</em> at these conditions). </p> <p>Standard ambient temperature and pressure (SATP) is defined as</p> <ul> <li> <p><mathjax>#298.15#</mathjax> <mathjax>#"K"#</mathjax> (temperature; equal to <mathjax>#25.0^"o""C"#</mathjax>)</p> </li> <li> <p><mathjax>#1#</mathjax> <mathjax>#"atm"#</mathjax> (pressure)</p> </li> </ul> <p>We can use the <strong>ideal-gas equation</strong> to solve for the number of moles of sulfur, <mathjax>#n#</mathjax>, knowing that the gas constant, <mathjax>#R#</mathjax> is equal to <mathjax>#0.082057("L"•"atm")/("mol"•"K")#</mathjax>:</p> <p><mathjax>#PV = nRT#</mathjax></p> <p><mathjax>#n = (PV)/(RT) = ((1cancel("atm"))(2.45cancel("L")))/((0.082057(cancel("L")•cancel("atm"))/("mol"•cancel("K")))(298.15cancel("K")))#</mathjax></p> <p><mathjax>#= color(red)(0.100#</mathjax> <mathjax>#color(red)("mol S"#</mathjax></p> <p>Now, let's use the <em>molar mass</em> of sulfur, <mathjax>#32.07#</mathjax> <mathjax>#"g/mol"#</mathjax>, to calculate the number of grams:</p> <p><mathjax>#0.100cancel("mol S")((32.07color(white)(l)"g S")/(1cancel("mol S"))) = color(blue)(3.21#</mathjax> <mathjax>#color(blue)("g S"#</mathjax></p> <p>Thus, if a <mathjax>#2.45#</mathjax>-<mathjax>#"L"#</mathjax> tank is filled with pure gaseous sulfur at SATP, we can expect the sulfur sample to have a mass of <mathjax>#color(blue)(3.21#</mathjax> <mathjax>#sfcolor(blue)("grams"#</mathjax>. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What mass of sulfur gas would be found in a 2.45 liter container at SATP?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/gas-pressure" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Pressure</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="445620" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/mrtas"><img alt="" class="" src="https://profilepictures.socratic.org/HY14X7r4S6AyDQgK2gwQ_IMG_0062.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/mrtas"> Nathan L. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-29T01:53:52" itemprop="dateCreated"> Jun 29, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#3.21#</mathjax> <mathjax>#"g S"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We're asked to to find the mass of gaseous sulfur that occupies a volume of <mathjax>#2.45#</mathjax> <mathjax>#"L"#</mathjax> at <em>standard ambient temperature and pressure</em>.</p> <p>I'll assume for these purposes that the sulfur is present as individual, gaseous atoms, rather than <mathjax>#"S"_8#</mathjax> (which is reasonable considering <mathjax>#"S"_8#</mathjax> is a <em>solid</em> at these conditions). </p> <p>Standard ambient temperature and pressure (SATP) is defined as</p> <ul> <li> <p><mathjax>#298.15#</mathjax> <mathjax>#"K"#</mathjax> (temperature; equal to <mathjax>#25.0^"o""C"#</mathjax>)</p> </li> <li> <p><mathjax>#1#</mathjax> <mathjax>#"atm"#</mathjax> (pressure)</p> </li> </ul> <p>We can use the <strong>ideal-gas equation</strong> to solve for the number of moles of sulfur, <mathjax>#n#</mathjax>, knowing that the gas constant, <mathjax>#R#</mathjax> is equal to <mathjax>#0.082057("L"•"atm")/("mol"•"K")#</mathjax>:</p> <p><mathjax>#PV = nRT#</mathjax></p> <p><mathjax>#n = (PV)/(RT) = ((1cancel("atm"))(2.45cancel("L")))/((0.082057(cancel("L")•cancel("atm"))/("mol"•cancel("K")))(298.15cancel("K")))#</mathjax></p> <p><mathjax>#= color(red)(0.100#</mathjax> <mathjax>#color(red)("mol S"#</mathjax></p> <p>Now, let's use the <em>molar mass</em> of sulfur, <mathjax>#32.07#</mathjax> <mathjax>#"g/mol"#</mathjax>, to calculate the number of grams:</p> <p><mathjax>#0.100cancel("mol S")((32.07color(white)(l)"g S")/(1cancel("mol S"))) = color(blue)(3.21#</mathjax> <mathjax>#color(blue)("g S"#</mathjax></p> <p>Thus, if a <mathjax>#2.45#</mathjax>-<mathjax>#"L"#</mathjax> tank is filled with pure gaseous sulfur at SATP, we can expect the sulfur sample to have a mass of <mathjax>#color(blue)(3.21#</mathjax> <mathjax>#sfcolor(blue)("grams"#</mathjax>. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/445620" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-gas-pressure-be-changed"> How can gas pressure be changed? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-you-increase-gas-pressure-in-a-container"> How can you increase gas pressure in a container? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-gas-pressure-created"> How is gas pressure created? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-does-gas-pressure-increase-when-temperature-increases"> Why does gas pressure increase when temperature increases? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-gas-pressure-zero-at-absolute-zero"> Why is gas pressure zero at absolute zero? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-does-gas-pressure-increase-with-temperature"> Why does gas pressure increase with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-there-no-gas-pressure-in-a-vacuum"> Why is there no gas pressure in a vacuum? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-total-gas-pressure-in-a-sealed-flask-that-contains-oxygen-at-a-parti-1"> What is the total gas pressure in a sealed flask that contains oxygen at a partial pressure of... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-the-absolute-pressure-of-a-gas-is-550-280-kpa-what-is-its-gage-pressure"> If the absolute pressure of a gas is 550.280 kPa, what is its gage pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-a-gas-sample-occupies-4-2-l-at-a-pressure-of-101-kpa-what-volume-will-it-occu"> If a gas sample occupies 4.2 L at a pressure of 101 kPa. What volume will it occupy if the... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/gas-pressure"> See all questions in Gas Pressure </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1915 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What mass of sulfur gas would be found in a 2.45 liter container at SATP?	null
2,119	ac2045ee-6ddd-11ea-a9c9-ccda262736ce	https://socratic.org/questions/what-is-the-ionic-compound-formed-between-oxygen-and-aluminum	Al2O3	start chemical_formula qc_end substance 7 7 qc_end substance 9 9 qc_end end	[{"type":"other","value":"Chemical Formula [OF] the ionic compound [IN] default"}]	[{"type":"chemical equation","value":"Al2O3"}]	[{"type":"substance name","value":"Oxygen"},{"type":"substance name","value":"Aluminum"}]	<h1 class="questionTitle" itemprop="name">What is the ionic compound formed between oxygen and aluminum?</h1>	null	Al2O3	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Aluminum generally forms <mathjax>#Al^(3+)#</mathjax> ions.</p> <p>Oxygen generally forms <mathjax>#O^(2-)#</mathjax> ions.</p> <p>So when the metal and the non-metal make music together they form a neutral compound, i.e. <mathjax>#Al_2O_3#</mathjax> (i.e. <mathjax>#2xx3-3xx2=0)#</mathjax>.</p> <p>The <a href="https://socratic.org/chemistry/bonding-basics/ionic-bonding">ionic bonding</a> is so strong (due to charge magnitude) in this material that it is reasonably insoluble. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>You speak of <mathjax>#"alumina, "Al_2O_3#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Aluminum generally forms <mathjax>#Al^(3+)#</mathjax> ions.</p> <p>Oxygen generally forms <mathjax>#O^(2-)#</mathjax> ions.</p> <p>So when the metal and the non-metal make music together they form a neutral compound, i.e. <mathjax>#Al_2O_3#</mathjax> (i.e. <mathjax>#2xx3-3xx2=0)#</mathjax>.</p> <p>The <a href="https://socratic.org/chemistry/bonding-basics/ionic-bonding">ionic bonding</a> is so strong (due to charge magnitude) in this material that it is reasonably insoluble. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the ionic compound formed between oxygen and aluminum?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#ionic-bonds-and-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Ionic Bonds</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/ionic-bonds-and-formulas/ionic-compounds" itemprop="url"> <span class="breadcrumb" itemprop="title">Ionic Compounds</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="315671" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-09-29T04:44:25" itemprop="dateCreated"> Sep 29, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>You speak of <mathjax>#"alumina, "Al_2O_3#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Aluminum generally forms <mathjax>#Al^(3+)#</mathjax> ions.</p> <p>Oxygen generally forms <mathjax>#O^(2-)#</mathjax> ions.</p> <p>So when the metal and the non-metal make music together they form a neutral compound, i.e. <mathjax>#Al_2O_3#</mathjax> (i.e. <mathjax>#2xx3-3xx2=0)#</mathjax>.</p> <p>The <a href="https://socratic.org/chemistry/bonding-basics/ionic-bonding">ionic bonding</a> is so strong (due to charge magnitude) in this material that it is reasonably insoluble. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/315671" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a 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Compounds </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 30798 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the ionic compound formed between oxygen and aluminum?	null
2,120	ac3262e5-6ddd-11ea-902b-ccda262736ce	https://socratic.org/questions/how-many-moles-of-aluminum-ions-are-present-in-0-44-moles-of-al-2-so-4-3	0.88 moles	start physical_unit 4 5 mole mol qc_end physical_unit 12 12 9 10 mole qc_end end	[{"type":"physical unit","value":"Mole [OF] aluminum ions [IN] moles"}]	[{"type":"physical unit","value":"0.88 moles"}]	[{"type":"physical unit","value":"Mole [OF] Al2(SO4)3 [=] \\pu{0.44 moles}"}]	<h1 class="questionTitle" itemprop="name">How many moles of aluminum ions are present in 0.44 moles of #Al_2(SO_4)_3#?</h1>	null	0.88 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In ONE mole of aluminum sulfate there are TWO mole of aluminum metal precisely...i.e. there are <mathjax>#54g#</mathjax> of aluminum metal per <mathjax>#342.15g#</mathjax> of salt...</p> <p>Here we specify a molar quantity of <mathjax>#0.44mol#</mathjax> with respect to aluminum sulfate….i.e. a mass of <mathjax>#150.5g#</mathjax>...and in this quantity there are TWO EQUIV aluminum….i.e. a mass of <mathjax>#2xx0.44molxx27.0g=23.8*g#</mathjax>...</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Surely there are <mathjax>#0.88mol#</mathjax> of aluminum metal in this molar quantity of salt....</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In ONE mole of aluminum sulfate there are TWO mole of aluminum metal precisely...i.e. there are <mathjax>#54g#</mathjax> of aluminum metal per <mathjax>#342.15g#</mathjax> of salt...</p> <p>Here we specify a molar quantity of <mathjax>#0.44mol#</mathjax> with respect to aluminum sulfate….i.e. a mass of <mathjax>#150.5g#</mathjax>...and in this quantity there are TWO EQUIV aluminum….i.e. a mass of <mathjax>#2xx0.44molxx27.0g=23.8g#</mathjax>...</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles of aluminum ions are present in 0.44 moles of #Al_2(SO_4)_3#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="640800" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-07-14T15:16:23" itemprop="dateCreated"> Jul 14, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Surely there are <mathjax>#0.88mol#</mathjax> of aluminum metal in this molar quantity of salt....</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In ONE mole of aluminum sulfate there are TWO mole of aluminum metal precisely...i.e. there are <mathjax>#54g#</mathjax> of aluminum metal per <mathjax>#342.15g#</mathjax> of salt...</p> <p>Here we specify a molar quantity of <mathjax>#0.44mol#</mathjax> with respect to aluminum sulfate….i.e. a mass of <mathjax>#150.5g#</mathjax>...and in this quantity there are TWO EQUIV aluminum….i.e. a mass of <mathjax>#2xx0.44molxx27.0g=23.8g#</mathjax>...</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/640800" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a 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class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 11498 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many moles of aluminum ions are present in 0.44 moles of #Al_2(SO_4)_3#?	null
2,121	acf90594-6ddd-11ea-bf92-ccda262736ce	https://socratic.org/questions/a-certain-compound-is-made-up-of-one-phosphorus-p-atom-three-chlorine-cl-atoms-a	PCl3O	start chemical_formula qc_end end	[{"type":"other","value":"Chemical Formula [OF] this compound [IN] default"}]	[{"type":"chemical equation","value":"PCl3O"}]	[{"type":"physical unit","value":"Number [OF] P atom [=] \\pu{1}"},{"type":"physical unit","value":"Number [OF] Cl atom [=] \\pu{3}"},{"type":"physical unit","value":"Number [OF] O atom [=] \\pu{1}"}]	<h1 class="questionTitle" itemprop="name">A certain compound is made up of one phosphorus (P) atom, three chlorine (Cl) atoms, and one oxygen (O) atom. What is the chemical formula of this compound?</h1>	null	PCl3O	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>See <a href="https://en.wikipedia.org/wiki/Phosphoryl_chloride" rel="nofollow">here</a> for details of its chemistry. It would be found in every inorganic and organic laboratory. It is used in the <a href="https://en.wikipedia.org/wiki/Vilsmeier%E2%80%93Haack_reaction" rel="nofollow">Vilsmeier-Haack-Arnold reaction.</a>.</p> <p>The alternative representation is <mathjax>#""^(-)O-P^(+)Cl_3#</mathjax>; you will see both representations in the texts. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Phosphoryl chloride, <mathjax>#O=PCl_3#</mathjax>, which in the lab you would call "POCKLE3"</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>See <a href="https://en.wikipedia.org/wiki/Phosphoryl_chloride" rel="nofollow">here</a> for details of its chemistry. It would be found in every inorganic and organic laboratory. It is used in the <a href="https://en.wikipedia.org/wiki/Vilsmeier%E2%80%93Haack_reaction" rel="nofollow">Vilsmeier-Haack-Arnold reaction.</a>.</p> <p>The alternative representation is <mathjax>#""^(-)O-P^(+)Cl_3#</mathjax>; you will see both representations in the texts. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A certain compound is made up of one phosphorus (P) atom, three chlorine (Cl) atoms, and one oxygen (O) atom. What is the chemical formula of this compound?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/determining-formula-and-molar-masses" itemprop="url"> <span class="breadcrumb" itemprop="title">Determining Formula</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="212888" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-15T19:57:18" itemprop="dateCreated"> Jan 15, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Phosphoryl chloride, <mathjax>#O=PCl_3#</mathjax>, which in the lab you would call "POCKLE3"</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>See <a href="https://en.wikipedia.org/wiki/Phosphoryl_chloride" rel="nofollow">here</a> for details of its chemistry. It would be found in every inorganic and organic laboratory. It is used in the <a href="https://en.wikipedia.org/wiki/Vilsmeier%E2%80%93Haack_reaction" rel="nofollow">Vilsmeier-Haack-Arnold reaction.</a>.</p> <p>The alternative representation is <mathjax>#""^(-)O-P^(+)Cl_3#</mathjax>; you will see both representations in the texts. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/212888" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-it-possible-to-find-a-molecular-formula-from-molar-mass"> Is it possible to find a molecular formula from molar mass? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5368e0cc02bf34779e175781"> Question #75781 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-common-mistakes-students-make-when-determining-formulas"> What are some common mistakes students make when determining formulas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-formula-of-an-acid"> How can I determine the formula of an acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-chemical-formula-of-a-product"> How can I determine the chemical formula of a product? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-empirical-formula-of-a-compound"> How can I determine the empirical formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-formula-of-a-hydrate"> How can I determine the formula of a hydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-the-empirical-formula-indicate"> What does the empirical formula indicate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-molecule-with-molecular-weight-of-180-18-g-mol-is-analyzed-and-found-to-contai"> A molecule with molecular weight of 180.18 g/mol is analyzed and found to contain 40.00% carbon,... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/do-i-need-to-know-the-number-of-moles-of-each-element-to-determine-the-formula-o"> Do I need to know the number of moles of each element to determine the formula of the compound? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/determining-formula-and-molar-masses"> See all questions in Determining Formula </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 27227 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A certain compound is made up of one phosphorus (P) atom, three chlorine (Cl) atoms, and one oxygen (O) atom. What is the chemical formula of this compound?	null
2,122	a908d4b8-6ddd-11ea-9c14-ccda262736ce	https://socratic.org/questions/how-many-moles-of-potassium-are-there-in-2-4-times-10-21-atoms-k	3.99 × 10^(-3) moles	start physical_unit 4 4 mole mol qc_end end	[{"type":"physical unit","value":"Mole [OF] potassium [IN] moles"}]	[{"type":"physical unit","value":"3.99 × 10^(-3) moles"}]	[{"type":"physical unit","value":"Number [OF] K atoms [=] \\pu{2.4 × 10^21}"}]	<h1 class="questionTitle" itemprop="name">How many moles of potassium are there in #2.4 \times 10^21# atoms K?</h1>	null	3.99 × 10^(-3) moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to do the conversion:</p> <p><mathjax>#2.410^21 "atoms of K"("1 mol of K"/(6.02210^23 "atoms")) = 0.0040 "mols of K"#</mathjax></p> <p>Since there are <mathjax>#6.02210^23#</mathjax> atoms in 1 mol of a substance (Avogadro's number), we use that conversion factor in the dimensional analysis. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.0040 mols of potassium.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to do the conversion:</p> <p><mathjax>#2.410^21 "atoms of K"("1 mol of K"/(6.02210^23 "atoms")) = 0.0040 "mols of K"#</mathjax></p> <p>Since there are <mathjax>#6.02210^23#</mathjax> atoms in 1 mol of a substance (Avogadro's number), we use that conversion factor in the dimensional analysis. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles of potassium are there in #2.4 \times 10^21# atoms K?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="509434" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/evan-12"><img alt="" class="" src="https://profilepictures.socratic.org/VVKGFJEmQ66DHVnuBvTK_fireball-422746_960_720.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/evan-12"> Evan Holbrook </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-11-21T21:15:03" itemprop="dateCreated"> Nov 21, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.0040 mols of potassium.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to do the conversion:</p> <p><mathjax>#2.410^21 "atoms of K"("1 mol of K"/(6.02210^23 "atoms")) = 0.0040 "mols of K"#</mathjax></p> <p>Since there are <mathjax>#6.02210^23#</mathjax> atoms in 1 mol of a substance (Avogadro's number), we use that conversion factor in the dimensional analysis. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/509434" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 11719 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many moles of potassium are there in #2.4 \times 10^21# atoms K?	null
2,123	abe5dd62-6ddd-11ea-95e7-ccda262736ce	https://socratic.org/questions/how-would-you-calculate-the-partial-pressure-of-co2-given-an-atmospheric-pressur	0.30 mmHg	start physical_unit 8 8 partial_pressure mmhg qc_end end	[{"type":"physical unit","value":"Partial pressure [OF] CO2 [IN] mmHg"}]	[{"type":"physical unit","value":"0.30 mmHg"}]	[{"type":"physical unit","value":"Concentration [OF] CO2 in atmosphere [=] \\pu{0.04%}"},{"type":"physical unit","value":"Pressure [OF] atmosphere [=] \\pu{760 mmHg}"}]	<h1 class="questionTitle" itemprop="name">How would you calculate the partial pressure of CO2, given an atmospheric pressure of 760 mm Hg and a 0.04% concentration?</h1>	null	0.30 mmHg	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The key to this problem is the fact that each component of a gaseous mixture will contribute to the total pressure exerted by the mixture <strong>proportionally</strong> to the number of <em>molecules</em> in has in the mixture. </p> <p>More often than not, you will see the <a href="https://socratic.org/chemistry/the-behavior-of-gases/partial-pressure">partial pressure</a> of a gas being expresses in terms of its <strong>mole fraction</strong>. </p> <blockquote> <p><mathjax>#color(blue)(P_"gas" = chi_"gas" xx P_"mixture")#</mathjax></p> </blockquote> <p>This is exactly what <em>proportionally to the number of molecules</em> means. </p> <p>As you know, one <strong>mole</strong> of any substance is equal to exactly <mathjax>#6.022 * 10^(23)#</mathjax> molecules of that substance - this is known as <strong>Avogadro's number</strong>, <mathjax>#N_A#</mathjax>.</p> <p>This means that you an express the <em>number of moles</em> of a gas by using the number of molecules, let's say <mathjax>#x#</mathjax>, and Avogadro's number</p> <blockquote> <p><mathjax>#color(blue)("no. of moles" = "no. of molecules" xx N_A)#</mathjax></p> </blockquote> <p>Now, the <a href="https://socratic.org/chemistry/the-mole-concept/percent-composition">percent composition</a> of a gaseous mixture tells you how many molecules each gas contributes in <mathjax>#100#</mathjax> molecules of mixture. </p> <p>In this case, air is said to be <mathjax>#0.04%#</mathjax> carbon dioxide. This means that <strong>in every</strong> <mathjax>#100#</mathjax> molecules of air, <mathjax>#0.04#</mathjax> will be <mathjax>#"CO"_2#</mathjax> molecules. </p> <p>For example, the <em>number of moles</em> of carbon dioxide in <mathjax>#100#</mathjax> molecules of air will be </p> <blockquote> <p><mathjax>#n_(CO_2) = "0.04 molecules" xx N_A = 0.04 * N_A#</mathjax></p> </blockquote> <p>The <strong>total number of moles</strong> in this sample of air will be </p> <blockquote> <p><mathjax>#n_"total" = "100 molecules" xx N_A = 100 * N_A#</mathjax></p> </blockquote> <p>This means that the <strong>mole fraction</strong> of carbon dioxide in the mixture will be </p> <blockquote> <p><mathjax>#chi_(CO_2) = (0.4 color(red)(cancel(color(black)(N_A))))/(100color(red)(cancel(color(black)(N_A)))) = 0.00004#</mathjax></p> </blockquote> <p>Carbon dioxide's <a href="http://socratic.org/chemistry/the-behavior-of-gases/partial-pressure">partial pressure</a> in air will thus be </p> <blockquote> <p><mathjax>#P_(CO_2) = 0.00004 * "760 mmHg" = "0.304 mmHg"#</mathjax></p> </blockquote> <p>Rounded to one <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig fig</a>, the number of sig figs you have for the <a href="http://socratic.org/chemistry/the-mole-concept/percent-composition">percent composition</a> of <mathjax>#"CO"_2#</mathjax>, the answer will be </p> <blockquote> <p><mathjax>#P_(CO_2) = color(green)("0.3 mmHg")#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"0.3 mmHg"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The key to this problem is the fact that each component of a gaseous mixture will contribute to the total pressure exerted by the mixture <strong>proportionally</strong> to the number of <em>molecules</em> in has in the mixture. </p> <p>More often than not, you will see the <a href="https://socratic.org/chemistry/the-behavior-of-gases/partial-pressure">partial pressure</a> of a gas being expresses in terms of its <strong>mole fraction</strong>. </p> <blockquote> <p><mathjax>#color(blue)(P_"gas" = chi_"gas" xx P_"mixture")#</mathjax></p> </blockquote> <p>This is exactly what <em>proportionally to the number of molecules</em> means. </p> <p>As you know, one <strong>mole</strong> of any substance is equal to exactly <mathjax>#6.022 * 10^(23)#</mathjax> molecules of that substance - this is known as <strong>Avogadro's number</strong>, <mathjax>#N_A#</mathjax>.</p> <p>This means that you an express the <em>number of moles</em> of a gas by using the number of molecules, let's say <mathjax>#x#</mathjax>, and Avogadro's number</p> <blockquote> <p><mathjax>#color(blue)("no. of moles" = "no. of molecules" xx N_A)#</mathjax></p> </blockquote> <p>Now, the <a href="https://socratic.org/chemistry/the-mole-concept/percent-composition">percent composition</a> of a gaseous mixture tells you how many molecules each gas contributes in <mathjax>#100#</mathjax> molecules of mixture. </p> <p>In this case, air is said to be <mathjax>#0.04%#</mathjax> carbon dioxide. This means that <strong>in every</strong> <mathjax>#100#</mathjax> molecules of air, <mathjax>#0.04#</mathjax> will be <mathjax>#"CO"_2#</mathjax> molecules. </p> <p>For example, the <em>number of moles</em> of carbon dioxide in <mathjax>#100#</mathjax> molecules of air will be </p> <blockquote> <p><mathjax>#n_(CO_2) = "0.04 molecules" xx N_A = 0.04 * N_A#</mathjax></p> </blockquote> <p>The <strong>total number of moles</strong> in this sample of air will be </p> <blockquote> <p><mathjax>#n_"total" = "100 molecules" xx N_A = 100 * N_A#</mathjax></p> </blockquote> <p>This means that the <strong>mole fraction</strong> of carbon dioxide in the mixture will be </p> <blockquote> <p><mathjax>#chi_(CO_2) = (0.4 color(red)(cancel(color(black)(N_A))))/(100color(red)(cancel(color(black)(N_A)))) = 0.00004#</mathjax></p> </blockquote> <p>Carbon dioxide's <a href="http://socratic.org/chemistry/the-behavior-of-gases/partial-pressure">partial pressure</a> in air will thus be </p> <blockquote> <p><mathjax>#P_(CO_2) = 0.00004 * "760 mmHg" = "0.304 mmHg"#</mathjax></p> </blockquote> <p>Rounded to one <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig fig</a>, the number of sig figs you have for the <a href="http://socratic.org/chemistry/the-mole-concept/percent-composition">percent composition</a> of <mathjax>#"CO"_2#</mathjax>, the answer will be </p> <blockquote> <p><mathjax>#P_(CO_2) = color(green)("0.3 mmHg")#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How would you calculate the partial pressure of CO2, given an atmospheric pressure of 760 mm Hg and a 0.04% concentration?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/partial-pressure" itemprop="url"> <span class="breadcrumb" itemprop="title">Partial Pressure</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="197834" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-08T19:58:36" itemprop="dateCreated"> Dec 8, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"0.3 mmHg"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The key to this problem is the fact that each component of a gaseous mixture will contribute to the total pressure exerted by the mixture <strong>proportionally</strong> to the number of <em>molecules</em> in has in the mixture. </p> <p>More often than not, you will see the <a href="https://socratic.org/chemistry/the-behavior-of-gases/partial-pressure">partial pressure</a> of a gas being expresses in terms of its <strong>mole fraction</strong>. </p> <blockquote> <p><mathjax>#color(blue)(P_"gas" = chi_"gas" xx P_"mixture")#</mathjax></p> </blockquote> <p>This is exactly what <em>proportionally to the number of molecules</em> means. </p> <p>As you know, one <strong>mole</strong> of any substance is equal to exactly <mathjax>#6.022 * 10^(23)#</mathjax> molecules of that substance - this is known as <strong>Avogadro's number</strong>, <mathjax>#N_A#</mathjax>.</p> <p>This means that you an express the <em>number of moles</em> of a gas by using the number of molecules, let's say <mathjax>#x#</mathjax>, and Avogadro's number</p> <blockquote> <p><mathjax>#color(blue)("no. of moles" = "no. of molecules" xx N_A)#</mathjax></p> </blockquote> <p>Now, the <a href="https://socratic.org/chemistry/the-mole-concept/percent-composition">percent composition</a> of a gaseous mixture tells you how many molecules each gas contributes in <mathjax>#100#</mathjax> molecules of mixture. </p> <p>In this case, air is said to be <mathjax>#0.04%#</mathjax> carbon dioxide. This means that <strong>in every</strong> <mathjax>#100#</mathjax> molecules of air, <mathjax>#0.04#</mathjax> will be <mathjax>#"CO"_2#</mathjax> molecules. </p> <p>For example, the <em>number of moles</em> of carbon dioxide in <mathjax>#100#</mathjax> molecules of air will be </p> <blockquote> <p><mathjax>#n_(CO_2) = "0.04 molecules" xx N_A = 0.04 * N_A#</mathjax></p> </blockquote> <p>The <strong>total number of moles</strong> in this sample of air will be </p> <blockquote> <p><mathjax>#n_"total" = "100 molecules" xx N_A = 100 * N_A#</mathjax></p> </blockquote> <p>This means that the <strong>mole fraction</strong> of carbon dioxide in the mixture will be </p> <blockquote> <p><mathjax>#chi_(CO_2) = (0.4 color(red)(cancel(color(black)(N_A))))/(100color(red)(cancel(color(black)(N_A)))) = 0.00004#</mathjax></p> </blockquote> <p>Carbon dioxide's <a href="http://socratic.org/chemistry/the-behavior-of-gases/partial-pressure">partial pressure</a> in air will thus be </p> <blockquote> <p><mathjax>#P_(CO_2) = 0.00004 * "760 mmHg" = "0.304 mmHg"#</mathjax></p> </blockquote> <p>Rounded to one <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig fig</a>, the number of sig figs you have for the <a href="http://socratic.org/chemistry/the-mole-concept/percent-composition">percent composition</a> of <mathjax>#"CO"_2#</mathjax>, the answer will be </p> <blockquote> <p><mathjax>#P_(CO_2) = color(green)("0.3 mmHg")#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/197834" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/534e256802bf342adfa30010"> How do you do a steam distillation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/53613f9f02bf3416cd9f8a34"> Question #f8a34 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-i-calculate-the-total-pressure-of-a-mixture-of-gases-by-adding-together-the-"> Can I calculate the total pressure of a mixture of gases by adding together the partial... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-formula-of-partial-pressure"> What is the formula of partial pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-dalton-s-law-of-partial-pressures"> What is the Dalton's law of partial pressures? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/nitrogen-gas-n2-reacts-with-hydrogen-gas-h2-to-form-ammonia-nh3-at-200-c-in-a-cl"> Nitrogen gas (N2) reacts with hydrogen gas (H2) to form ammonia (NH3). 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2,124	abf0a325-6ddd-11ea-b4a6-ccda262736ce	https://socratic.org/questions/598280feb72cff77828a6219	1.0 × 10^25	start physical_unit 2 3 number none qc_end physical_unit 9 9 6 7 mole qc_end end	[{"type":"physical unit","value":"Number [OF] hydrogen atoms"}]	[{"type":"physical unit","value":"1.0 × 10^25"}]	[{"type":"physical unit","value":"Mole [OF] methane [=] \\pu{4.2 moles}"}]	<h1 class="questionTitle" itemprop="name">How many hydrogen atoms are in 4.2 moles of methane?</h1>	null	1.0 × 10^25	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>One mole of atoms equals <mathjax>#6.022xx10^23#</mathjax> atoms.</p> <p>The formula for methane, <mathjax>#"CH"_4"#</mathjax> indicates that one mole of the compound contains four moles of hydrogen atoms.</p> <p>In order to determine how many hydrogen atoms there are in the given moles of methane, multiply the given moles by <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio between <mathjax>#"CH"_4"#</mathjax> and <mathjax>#"H"#</mathjax> to get moles of <mathjax>#"H"#</mathjax>. Then multiply the moles <mathjax>#"H"#</mathjax> by <mathjax>#"6.022xx10^23#</mathjax> atoms/mol.</p> <p><mathjax>#4.2color(red)cancel(color(black)("mol CH"_4))xx(4"mol H")/(1color(red)cancel(color(black)("mol CH"_4)))="16.8 mol H"#</mathjax></p> <p><mathjax>#16.8color(red)cancel(color(black)("mol H"))xx(6.022xx10^23"atoms H")/(1color(red)cancel(color(black)("mol H")))=1.0xx10^25" atoms H"#</mathjax> </p> <p>(rounded to two sig figs due to <mathjax>#4.2#</mathjax> mol <mathjax>#"CH"_4"#</mathjax>)</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>There are <mathjax>#1.0xx10^25#</mathjax> atoms of hydrogen in <mathjax>#4.2#</mathjax> moles methane.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>One mole of atoms equals <mathjax>#6.022xx10^23#</mathjax> atoms.</p> <p>The formula for methane, <mathjax>#"CH"_4"#</mathjax> indicates that one mole of the compound contains four moles of hydrogen atoms.</p> <p>In order to determine how many hydrogen atoms there are in the given moles of methane, multiply the given moles by <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio between <mathjax>#"CH"_4"#</mathjax> and <mathjax>#"H"#</mathjax> to get moles of <mathjax>#"H"#</mathjax>. Then multiply the moles <mathjax>#"H"#</mathjax> by <mathjax>#"6.022xx10^23#</mathjax> atoms/mol.</p> <p><mathjax>#4.2color(red)cancel(color(black)("mol CH"_4))xx(4"mol H")/(1color(red)cancel(color(black)("mol CH"_4)))="16.8 mol H"#</mathjax></p> <p><mathjax>#16.8color(red)cancel(color(black)("mol H"))xx(6.022xx10^23"atoms H")/(1color(red)cancel(color(black)("mol H")))=1.0xx10^25" atoms H"#</mathjax> </p> <p>(rounded to two sig figs due to <mathjax>#4.2#</mathjax> mol <mathjax>#"CH"_4"#</mathjax>)</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many hydrogen atoms are in 4.2 moles of methane?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="459514" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-03T03:17:19" itemprop="dateCreated"> Aug 3, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>There are <mathjax>#1.0xx10^25#</mathjax> atoms of hydrogen in <mathjax>#4.2#</mathjax> moles methane.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>One mole of atoms equals <mathjax>#6.022xx10^23#</mathjax> atoms.</p> <p>The formula for methane, <mathjax>#"CH"_4"#</mathjax> indicates that one mole of the compound contains four moles of hydrogen atoms.</p> <p>In order to determine how many hydrogen atoms there are in the given moles of methane, multiply the given moles by <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio between <mathjax>#"CH"_4"#</mathjax> and <mathjax>#"H"#</mathjax> to get moles of <mathjax>#"H"#</mathjax>. Then multiply the moles <mathjax>#"H"#</mathjax> by <mathjax>#"6.022xx10^23#</mathjax> atoms/mol.</p> <p><mathjax>#4.2color(red)cancel(color(black)("mol CH"_4))xx(4"mol H")/(1color(red)cancel(color(black)("mol CH"_4)))="16.8 mol H"#</mathjax></p> <p><mathjax>#16.8color(red)cancel(color(black)("mol H"))xx(6.022xx10^23"atoms H")/(1color(red)cancel(color(black)("mol H")))=1.0xx10^25" atoms H"#</mathjax> </p> <p>(rounded to two sig figs due to <mathjax>#4.2#</mathjax> mol <mathjax>#"CH"_4"#</mathjax>)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/459514" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 7447 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many hydrogen atoms are in 4.2 moles of methane?	null
2,125	abca26b0-6ddd-11ea-957d-ccda262736ce	https://socratic.org/questions/when-18-grams-of-copper-absorbs-1-kj-1000-j-of-energy-the-temperature-increases-	0.39 J/(g * ℃)	start physical_unit 4 4 specific_heat j/(°c_·_g) qc_end physical_unit 4 4 1 2 mass qc_end physical_unit 4 4 6 7 heat_energy qc_end physical_unit 4 4 16 17 temperature qc_end physical_unit 4 4 19 20 temperature qc_end end	[{"type":"physical unit","value":"Specific heat [OF] copper [IN] J/(g * ℃)"}]	[{"type":"physical unit","value":"0.39 J/(g * ℃)"}]	[{"type":"physical unit","value":"Mass [OF] copper [=] \\pu{18 grams}"},{"type":"physical unit","value":"Absorbed energy [OF] copper [=] \\pu{1 kJ}"},{"type":"physical unit","value":"Temperature1 [OF] copper [=] \\pu{35.0 ℃}"},{"type":"physical unit","value":"Temperature2 [OF] copper [=] \\pu{179.3 ℃}"}]	<h1 class="questionTitle" itemprop="name">When 18 grams of copper absorbs 1 kJ (1000 J) of energy, the temperature increases from 35.0°C to 179.3 °C. What is the specific heat of copper? </h1>	null	0.39 J/(g * ℃)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <strong><a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a></strong> of a substance tells you the amount of heat needed to increase the temperature of <mathjax>#"1 g"#</mathjax> of said substance by <mathjax>#1^@"C"#</mathjax>. </p> <p>This implies that your ultimate goal here is to figure how much heat is needed to increase the temperature of <mathjax>#"1 g"#</mathjax> of copper by <mathjax>#1^@"C"#</mathjax>. </p> <p>Now, you know that <mathjax>#"1000 J"#</mathjax> of heat increased the temperature of <mathjax>#"18 g"#</mathjax> of copper by</p> <blockquote> <p><mathjax>#179.3^@"C" - 35.0^@"C" = 144.3^@"C"#</mathjax></p> </blockquote> <p>so a good place to start would be to figure out the amount of heat needed to increase the temperature of <mathjax>#"1 g"#</mathjax> of copper by <mathjax>#144.3^@"C"#</mathjax>.</p> <blockquote> <p><mathjax>#1 color(red)(cancel(color(black)("g"))) * overbrace("1000 J"/(18color(red)(cancel(color(black)("g")))))^(color(blue)("to increase the temperature by 144.3"^@"C")) = "55.556 J"#</mathjax></p> </blockquote> <p>So, you know that if you add <mathjax>#"55.556 J"#</mathjax> of heat to <mathjax>#"1 g"#</mathjax> of copper, you will increase its temperature by <mathjax>#144.3^@"C"#</mathjax>. </p> <p>This implies that in order to increase the temperature of <mathjax>#"1 g"#</mathjax> of copper by <mathjax>#1^@"C"#</mathjax>, you will need</p> <blockquote> <p><mathjax>#1 color(red)(cancel(color(black)(""^@"C"))) * overbrace("55.556 J"/(144.3color(red)(cancel(color(black)(""^@"C")))))^(color(blue)("for 1 g of copper")) = "0.385 J"#</mathjax></p> </blockquote> <p>Therefore, you can say that copper has a specific heat of</p> <blockquote> <p><mathjax>#c_ "copper" = "0.39 J g"^(-1)""^@"C"^(-1)#</mathjax></p> <blockquote> <p><em>This tells you that you need</em> <mathjax>#"0.39 J"#</mathjax> <em>of heat to increase the temperature of</em> <mathjax>#"1 g"#</mathjax> <em>of copper by</em> <mathjax>#1^@"C"#</mathjax></p> </blockquote> </blockquote> <p>I'll leave the answer rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the mass of copper, but keep in mind that you only have one significant figure for the energy absorbed by the sample. </p> <p>This is an excellent result because the specific heat of copper is listed as being equal to <mathjax>#"0.39 J g"^(-1)""^@"C"^(-1)#</mathjax>.</p> <p><a href="http://www.engineeringtoolbox.com/specific-heat-metals-d_152.html" rel="nofollow" target="_blank">http://www.engineeringtoolbox.com/specific-heat-metals-d_152.html</a></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"0.39 J g"^(-1)""^@"C"^(-1)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <strong><a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a></strong> of a substance tells you the amount of heat needed to increase the temperature of <mathjax>#"1 g"#</mathjax> of said substance by <mathjax>#1^@"C"#</mathjax>. </p> <p>This implies that your ultimate goal here is to figure how much heat is needed to increase the temperature of <mathjax>#"1 g"#</mathjax> of copper by <mathjax>#1^@"C"#</mathjax>. </p> <p>Now, you know that <mathjax>#"1000 J"#</mathjax> of heat increased the temperature of <mathjax>#"18 g"#</mathjax> of copper by</p> <blockquote> <p><mathjax>#179.3^@"C" - 35.0^@"C" = 144.3^@"C"#</mathjax></p> </blockquote> <p>so a good place to start would be to figure out the amount of heat needed to increase the temperature of <mathjax>#"1 g"#</mathjax> of copper by <mathjax>#144.3^@"C"#</mathjax>.</p> <blockquote> <p><mathjax>#1 color(red)(cancel(color(black)("g"))) * overbrace("1000 J"/(18color(red)(cancel(color(black)("g")))))^(color(blue)("to increase the temperature by 144.3"^@"C")) = "55.556 J"#</mathjax></p> </blockquote> <p>So, you know that if you add <mathjax>#"55.556 J"#</mathjax> of heat to <mathjax>#"1 g"#</mathjax> of copper, you will increase its temperature by <mathjax>#144.3^@"C"#</mathjax>. </p> <p>This implies that in order to increase the temperature of <mathjax>#"1 g"#</mathjax> of copper by <mathjax>#1^@"C"#</mathjax>, you will need</p> <blockquote> <p><mathjax>#1 color(red)(cancel(color(black)(""^@"C"))) * overbrace("55.556 J"/(144.3color(red)(cancel(color(black)(""^@"C")))))^(color(blue)("for 1 g of copper")) = "0.385 J"#</mathjax></p> </blockquote> <p>Therefore, you can say that copper has a specific heat of</p> <blockquote> <p><mathjax>#c_ "copper" = "0.39 J g"^(-1)""^@"C"^(-1)#</mathjax></p> <blockquote> <p><em>This tells you that you need</em> <mathjax>#"0.39 J"#</mathjax> <em>of heat to increase the temperature of</em> <mathjax>#"1 g"#</mathjax> <em>of copper by</em> <mathjax>#1^@"C"#</mathjax></p> </blockquote> </blockquote> <p>I'll leave the answer rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the mass of copper, but keep in mind that you only have one significant figure for the energy absorbed by the sample. </p> <p>This is an excellent result because the specific heat of copper is listed as being equal to <mathjax>#"0.39 J g"^(-1)""^@"C"^(-1)#</mathjax>.</p> <p><a href="http://www.engineeringtoolbox.com/specific-heat-metals-d_152.html" rel="nofollow" target="_blank">http://www.engineeringtoolbox.com/specific-heat-metals-d_152.html</a></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">When 18 grams of copper absorbs 1 kJ (1000 J) of energy, the temperature increases from 35.0°C to 179.3 °C. What is the specific heat of copper? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/specific-heat" itemprop="url"> <span class="breadcrumb" itemprop="title">Specific Heat</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="439999" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-15T01:40:54" itemprop="dateCreated"> Jun 15, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"0.39 J g"^(-1)""^@"C"^(-1)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <strong><a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a></strong> of a substance tells you the amount of heat needed to increase the temperature of <mathjax>#"1 g"#</mathjax> of said substance by <mathjax>#1^@"C"#</mathjax>. </p> <p>This implies that your ultimate goal here is to figure how much heat is needed to increase the temperature of <mathjax>#"1 g"#</mathjax> of copper by <mathjax>#1^@"C"#</mathjax>. </p> <p>Now, you know that <mathjax>#"1000 J"#</mathjax> of heat increased the temperature of <mathjax>#"18 g"#</mathjax> of copper by</p> <blockquote> <p><mathjax>#179.3^@"C" - 35.0^@"C" = 144.3^@"C"#</mathjax></p> </blockquote> <p>so a good place to start would be to figure out the amount of heat needed to increase the temperature of <mathjax>#"1 g"#</mathjax> of copper by <mathjax>#144.3^@"C"#</mathjax>.</p> <blockquote> <p><mathjax>#1 color(red)(cancel(color(black)("g"))) * overbrace("1000 J"/(18color(red)(cancel(color(black)("g")))))^(color(blue)("to increase the temperature by 144.3"^@"C")) = "55.556 J"#</mathjax></p> </blockquote> <p>So, you know that if you add <mathjax>#"55.556 J"#</mathjax> of heat to <mathjax>#"1 g"#</mathjax> of copper, you will increase its temperature by <mathjax>#144.3^@"C"#</mathjax>. </p> <p>This implies that in order to increase the temperature of <mathjax>#"1 g"#</mathjax> of copper by <mathjax>#1^@"C"#</mathjax>, you will need</p> <blockquote> <p><mathjax>#1 color(red)(cancel(color(black)(""^@"C"))) * overbrace("55.556 J"/(144.3color(red)(cancel(color(black)(""^@"C")))))^(color(blue)("for 1 g of copper")) = "0.385 J"#</mathjax></p> </blockquote> <p>Therefore, you can say that copper has a specific heat of</p> <blockquote> <p><mathjax>#c_ "copper" = "0.39 J g"^(-1)""^@"C"^(-1)#</mathjax></p> <blockquote> <p><em>This tells you that you need</em> <mathjax>#"0.39 J"#</mathjax> <em>of heat to increase the temperature of</em> <mathjax>#"1 g"#</mathjax> <em>of copper by</em> <mathjax>#1^@"C"#</mathjax></p> </blockquote> </blockquote> <p>I'll leave the answer rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the mass of copper, but keep in mind that you only have one significant figure for the energy absorbed by the sample. </p> <p>This is an excellent result because the specific heat of copper is listed as being equal to <mathjax>#"0.39 J g"^(-1)""^@"C"^(-1)#</mathjax>.</p> <p><a href="http://www.engineeringtoolbox.com/specific-heat-metals-d_152.html" rel="nofollow" target="_blank">http://www.engineeringtoolbox.com/specific-heat-metals-d_152.html</a></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/439999" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> 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</div> </div> </div> </div> </div> </article>	When 18 grams of copper absorbs 1 kJ (1000 J) of energy, the temperature increases from 35.0°C to 179.3 °C. What is the specific heat of copper?	null
2,126	a8c09ef5-6ddd-11ea-98f6-ccda262736ce	https://socratic.org/questions/how-many-cheese-doodles-are-in-2-0-moles-of-cheese-doodles	1.20 × 10^24	start physical_unit 2 3 number none qc_end physical_unit 2 3 6 7 mole qc_end end	[{"type":"physical unit","value":"Number [OF] cheese doodles"}]	[{"type":"physical unit","value":"1.20 × 10^24 "}]	[{"type":"physical unit","value":"Mole [OF] cheese doodles [=] \\pu{2.0 moles}"}]	<h1 class="questionTitle" itemprop="name">How many cheese doodles are in 2.0 moles of cheese doodles?</h1>	null	1.20 × 10^24	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So 2 moles would be twice as many. In the case of the cheese doodles, this number would probably cover a whole country in a thick layer, but you can work this out for yourself.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>1 mole means <mathjax>#~~6.02xx10^23#</mathjax> particles of anything.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So 2 moles would be twice as many. In the case of the cheese doodles, this number would probably cover a whole country in a thick layer, but you can work this out for yourself.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many cheese doodles are in 2.0 moles of cheese doodles?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="320328" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meneernask"><img alt="" class="" src="https://profilepictures.socratic.org/gpA0lokRGK9vLVUnAMAy_meneernask.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meneernask"> MeneerNask </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-10-11T02:44:39" itemprop="dateCreated"> Oct 11, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>1 mole means <mathjax>#~~6.02xx10^23#</mathjax> particles of anything.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So 2 moles would be twice as many. In the case of the cheese doodles, this number would probably cover a whole country in a thick layer, but you can work this out for yourself.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/320328" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1300 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many cheese doodles are in 2.0 moles of cheese doodles?	null
2,127	a83c3f62-6ddd-11ea-a090-ccda262736ce	https://socratic.org/questions/at-conditions-of-785-0-torr-of-pressure-and-15-0-c-temperature-a-gas-occupies-a-	50.0 mL	start physical_unit 25 27 volume ml qc_end physical_unit 11 12 3 4 pressure qc_end physical_unit 11 12 8 9 temperature qc_end physical_unit 11 12 29 30 pressure qc_end physical_unit 11 12 32 33 temperature qc_end physical_unit 11 12 17 18 volume qc_end end	[{"type":"physical unit","value":"Volume2 [OF] the same gas [IN] mL"}]	[{"type":"physical unit","value":"50.0 mL"}]	[{"type":"physical unit","value":"Pressure1 [OF] a gas [=] \\pu{785.0 torr}"},{"type":"physical unit","value":"Temperature1 [OF] a gas [=] \\pu{15.0 ℃}"},{"type":"physical unit","value":"Pressure2 [OF] a gas [=] \\pu{745.0 torr}"},{"type":"physical unit","value":"Temperature2 [OF] a gas [=] \\pu{30.0 ℃}"},{"type":"physical unit","value":"Volume1 [OF] a gas [=] \\pu{45.5 mL}"}]	<h1 class="questionTitle" itemprop="name">At conditions of 785.0 torr of pressure and 15.0 °C temperature, a gas occupies a volume of 45.5 mL. What will be the volume of the same gas at 745.0 torr and 30.0 °C?</h1>	null	50.0 mL	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#P_1 = 785.0"Torr"#</mathjax> => <mathjax>#P_2=745.0"Torr"#</mathjax> <br/> Decreasing Pressure => Increasing Volume (Boyles Law) => Use ratio of pressure values that decrease <mathjax>#V_1#</mathjax>. => (785.0/745.0)</p> <p><mathjax>#T_1=(15 + 273)K = 288K#</mathjax> => <mathjax>#T_2=(30 + 273)K= 303K#</mathjax><br/> Increasing Temperature (Charles Law) => Increasing Volume => Use ratio of temperature values that increase <mathjax>#V_1#</mathjax>. => (303/288)</p> <p><mathjax>#V_1=45.0ml#</mathjax> => <mathjax>#V_2=?#</mathjax></p> <p><mathjax>#V_2 = 45.0mlxx(785.0"Torr")/(745.0"Torr")xx(303K)/(288K)#</mathjax> = <mathjax>#49.9ml => 50.0ml#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>50.0ml</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#P_1 = 785.0"Torr"#</mathjax> => <mathjax>#P_2=745.0"Torr"#</mathjax> <br/> Decreasing Pressure => Increasing Volume (Boyles Law) => Use ratio of pressure values that decrease <mathjax>#V_1#</mathjax>. => (785.0/745.0)</p> <p><mathjax>#T_1=(15 + 273)K = 288K#</mathjax> => <mathjax>#T_2=(30 + 273)K= 303K#</mathjax><br/> Increasing Temperature (Charles Law) => Increasing Volume => Use ratio of temperature values that increase <mathjax>#V_1#</mathjax>. => (303/288)</p> <p><mathjax>#V_1=45.0ml#</mathjax> => <mathjax>#V_2=?#</mathjax></p> <p><mathjax>#V_2 = 45.0mlxx(785.0"Torr")/(745.0"Torr")xx(303K)/(288K)#</mathjax> = <mathjax>#49.9ml => 50.0ml#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">At conditions of 785.0 torr of pressure and 15.0 °C temperature, a gas occupies a volume of 45.5 mL. What will be the volume of the same gas at 745.0 torr and 30.0 °C?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/gas-laws" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Laws</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="441615" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/doc048"><img alt="" class="" src="https://profilepictures.socratic.org/e4gaeUMMQESTpfte6aRu_Friendly%20Chem%20Professor.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/doc048"> Doc048 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-18T22:42:39" itemprop="dateCreated"> Jun 18, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>50.0ml</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#P_1 = 785.0"Torr"#</mathjax> => <mathjax>#P_2=745.0"Torr"#</mathjax> <br/> Decreasing Pressure => Increasing Volume (Boyles Law) => Use ratio of pressure values that decrease <mathjax>#V_1#</mathjax>. => (785.0/745.0)</p> <p><mathjax>#T_1=(15 + 273)K = 288K#</mathjax> => <mathjax>#T_2=(30 + 273)K= 303K#</mathjax><br/> Increasing Temperature (Charles Law) => Increasing Volume => Use ratio of temperature values that increase <mathjax>#V_1#</mathjax>. => (303/288)</p> <p><mathjax>#V_1=45.0ml#</mathjax> => <mathjax>#V_2=?#</mathjax></p> <p><mathjax>#V_2 = 45.0mlxx(785.0"Torr")/(745.0"Torr")xx(303K)/(288K)#</mathjax> = <mathjax>#49.9ml => 50.0ml#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/441615" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-boyles-law-relate-to-breathing"> How does Boyle's law relate to breathing? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/in-avogadro-s-law-what-would-happen-to-v-if-n-is-increased-decreased-and-what-wo"> In Avogadro's Law what would happen to V if N is increased/decreased? 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What will be the volume of the same gas at 745.0 torr and 30.0 °C?	null
2,128	ab804a67-6ddd-11ea-80d0-ccda262736ce	https://socratic.org/questions/a-sample-of-nh-3-gas-occupies-75-0-l-at-stp-how-many-molecules-is-this	1.99 × 10^24	start physical_unit 12 12 number none qc_end physical_unit 1 4 6 7 volume qc_end c_other STP qc_end end	[{"type":"physical unit","value":"Number [OF] molecules"}]	[{"type":"physical unit","value":"1.99 × 10^24"}]	[{"type":"physical unit","value":"Volume [OF] NH3 gas sample [=] \\pu{75.0 L}"},{"type":"other","value":"STP"}]	<h1 class="questionTitle" itemprop="name"> A sample of #NH_3# gas occupies 75.0 L at STP. How many molecules is this?</h1>	null	1.99 × 10^24	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your strategy for this problem will be to determine how many <em>moles</em> of gas you have in that volume at <strong>STP</strong>, then use <strong>Avogadro's number</strong> to find the number of <em>molecules</em> of ammonia would be found in that many moles. </p> <p><strong>STP</strong>, <em>Standard Temperature and Pressure</em>, conditions are defined as a temperature of <mathjax>#0^@"C"#</mathjax> and a pressure of <mathjax>#"100 kPa"#</mathjax>.</p> <p>Under these conditions for pressure and temperature, <strong>One mole</strong> of any ideal gas occupies exactly <mathjax>#"22.7 L"#</mathjax> - this is known as the <a href="http://socratic.org/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp">molar volume of a gas at STP</a>. </p> <p>This means that you can use the <a href="http://socratic.org/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp">molar volume of a gas</a> to determine how many moles you have in <mathjax>#"75.0 L"#</mathjax> of ammonia.</p> <blockquote> <p><mathjax>#75.0color(red)(cancel(color(black)("L"))) * "1 mole"/(22.7color(red)(cancel(color(black)("L")))) = "3.304 moles"#</mathjax></p> </blockquote> <p>Now, you know that <strong>one mole</strong> of any substance contains exactly <mathjax>#6.022 * 10^(23)#</mathjax> molecules of that substance. IN you case, <mathjax>#3.304#</mathjax> moles of ammonia will contain</p> <blockquote> <p><mathjax>#3.304color(red)(cancel(color(black)("moles"))) * (6.022 * 10^(23)"molecules NH"_3)/(1color(red)(cancel(color(black)("mole")))) = color(green)(1.99 * 10^(24)"molecules NH"_3#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1.99 * 10^(24)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your strategy for this problem will be to determine how many <em>moles</em> of gas you have in that volume at <strong>STP</strong>, then use <strong>Avogadro's number</strong> to find the number of <em>molecules</em> of ammonia would be found in that many moles. </p> <p><strong>STP</strong>, <em>Standard Temperature and Pressure</em>, conditions are defined as a temperature of <mathjax>#0^@"C"#</mathjax> and a pressure of <mathjax>#"100 kPa"#</mathjax>.</p> <p>Under these conditions for pressure and temperature, <strong>One mole</strong> of any ideal gas occupies exactly <mathjax>#"22.7 L"#</mathjax> - this is known as the <a href="http://socratic.org/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp">molar volume of a gas at STP</a>. </p> <p>This means that you can use the <a href="http://socratic.org/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp">molar volume of a gas</a> to determine how many moles you have in <mathjax>#"75.0 L"#</mathjax> of ammonia.</p> <blockquote> <p><mathjax>#75.0color(red)(cancel(color(black)("L"))) * "1 mole"/(22.7color(red)(cancel(color(black)("L")))) = "3.304 moles"#</mathjax></p> </blockquote> <p>Now, you know that <strong>one mole</strong> of any substance contains exactly <mathjax>#6.022 * 10^(23)#</mathjax> molecules of that substance. IN you case, <mathjax>#3.304#</mathjax> moles of ammonia will contain</p> <blockquote> <p><mathjax>#3.304color(red)(cancel(color(black)("moles"))) * (6.022 * 10^(23)"molecules NH"_3)/(1color(red)(cancel(color(black)("mole")))) = color(green)(1.99 * 10^(24)"molecules NH"_3#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name"> A sample of #NH_3# gas occupies 75.0 L at STP. How many molecules is this?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp" itemprop="url"> <span class="breadcrumb" itemprop="title">Molar Volume of a Gas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="192903" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-25T10:41:11" itemprop="dateCreated"> Nov 25, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1.99 * 10^(24)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your strategy for this problem will be to determine how many <em>moles</em> of gas you have in that volume at <strong>STP</strong>, then use <strong>Avogadro's number</strong> to find the number of <em>molecules</em> of ammonia would be found in that many moles. </p> <p><strong>STP</strong>, <em>Standard Temperature and Pressure</em>, conditions are defined as a temperature of <mathjax>#0^@"C"#</mathjax> and a pressure of <mathjax>#"100 kPa"#</mathjax>.</p> <p>Under these conditions for pressure and temperature, <strong>One mole</strong> of any ideal gas occupies exactly <mathjax>#"22.7 L"#</mathjax> - this is known as the <a href="http://socratic.org/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp">molar volume of a gas at STP</a>. </p> <p>This means that you can use the <a href="http://socratic.org/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp">molar volume of a gas</a> to determine how many moles you have in <mathjax>#"75.0 L"#</mathjax> of ammonia.</p> <blockquote> <p><mathjax>#75.0color(red)(cancel(color(black)("L"))) * "1 mole"/(22.7color(red)(cancel(color(black)("L")))) = "3.304 moles"#</mathjax></p> </blockquote> <p>Now, you know that <strong>one mole</strong> of any substance contains exactly <mathjax>#6.022 * 10^(23)#</mathjax> molecules of that substance. IN you case, <mathjax>#3.304#</mathjax> moles of ammonia will contain</p> <blockquote> <p><mathjax>#3.304color(red)(cancel(color(black)("moles"))) * (6.022 * 10^(23)"molecules NH"_3)/(1color(red)(cancel(color(black)("mole")))) = color(green)(1.99 * 10^(24)"molecules NH"_3#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/192903" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-stoichiometric-ratios-relate-to-molar-volume-of-a-gas"> How do stoichiometric ratios relate to molar volume of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-a-gas-at-stp"> How do you calculate molar volume of a gas at STP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-molar-volume-of-hydrogen-gas"> How do you find the molar volume of hydrogen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-oxygen-gas"> How do you calculate molar volume of oxygen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molar-gas-volume"> What is molar gas volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/534c7bf202bf3420a007f014"> What is the volume at 0 °C and 1 atm of a mixture that contains 4.0 g of methane and 2.0 g of helium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5361f75702bf3429040e0599"> What is the difference between STP and NTP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-volume-of-25-moles-of-oxygen-o2-gas"> What is the volume of .25 moles of oxygen (O2) Gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-would-knowing-the-molar-volume-of-a-gas-be-important"> Why would knowing the molar volume of a gas be important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-22-4-liters-called-the-molar-volume-of-a-gas"> Why is 22.4 liters called the molar volume of a gas? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp"> See all questions in Molar Volume of a Gas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 19533 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A sample of #NH_3# gas occupies 75.0 L at STP. How many molecules is this?	null
2,129	aadf7665-6ddd-11ea-9d83-ccda262736ce	https://socratic.org/questions/if-you-have-68-5-moles-of-p-4o-10-how-many-moles-of-p-are-there	274.00 moles	start physical_unit 11 11 mole mol qc_end physical_unit 6 6 3 4 mole qc_end end	[{"type":"physical unit","value":"Mole [OF] P [IN] moles"}]	[{"type":"physical unit","value":"274.00 moles"}]	[{"type":"physical unit","value":"Mole [OF] P4O10 [=] \\pu{68.5 moles}"}]	<h1 class="questionTitle" itemprop="name">If you have 68.5 moles of #P_4O_10# how many moles of #P# are there?</h1>	null	274.00 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Well clearly, I have <mathjax>#4xx13#</mathjax> cards in the diamond suit.</p> <p>You propose <mathjax>#68.5mol#</mathjax> of <mathjax>#P_4O_10#</mathjax>, and clearly I have <mathjax>#4xx68.5mol#</mathjax> of <mathjax>#"phosphorus atoms"#</mathjax>.</p> <p>And this has a precise numerical value,</p> <p>I,e, <mathjax>#4xx68.5molxx6.022xx10^23mol^-1=1.65*10^26#</mathjax> <mathjax>#"phosphorus atoms".#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>I have 4 decks of cards, then how many cards do I have in the diamond suit. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Well clearly, I have <mathjax>#4xx13#</mathjax> cards in the diamond suit.</p> <p>You propose <mathjax>#68.5mol#</mathjax> of <mathjax>#P_4O_10#</mathjax>, and clearly I have <mathjax>#4xx68.5mol#</mathjax> of <mathjax>#"phosphorus atoms"#</mathjax>.</p> <p>And this has a precise numerical value,</p> <p>I,e, <mathjax>#4xx68.5molxx6.022xx10^23mol^-1=1.65*10^26#</mathjax> <mathjax>#"phosphorus atoms".#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">If you have 68.5 moles of #P_4O_10# how many moles of #P# are there?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="386835" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-05T12:40:50" itemprop="dateCreated"> Mar 5, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>I have 4 decks of cards, then how many cards do I have in the diamond suit. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Well clearly, I have <mathjax>#4xx13#</mathjax> cards in the diamond suit.</p> <p>You propose <mathjax>#68.5mol#</mathjax> of <mathjax>#P_4O_10#</mathjax>, and clearly I have <mathjax>#4xx68.5mol#</mathjax> of <mathjax>#"phosphorus atoms"#</mathjax>.</p> <p>And this has a precise numerical value,</p> <p>I,e, <mathjax>#4xx68.5molxx6.022xx10^23mol^-1=1.65*10^26#</mathjax> <mathjax>#"phosphorus atoms".#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/386835" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1848 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	If you have 68.5 moles of #P_4O_10# how many moles of #P# are there?	null
2,130	acadbb8a-6ddd-11ea-8285-ccda262736ce	https://socratic.org/questions/what-is-the-molecular-mass-of-sodium-oxide-na-2o	62 amu	start physical_unit 8 8 molecular_weight amu qc_end chemical_equation 8 8 qc_end end	[{"type":"physical unit","value":"Molecular mass [OF] Na2O [IN] amu"}]	[{"type":"physical unit","value":"62 amu"}]	[{"type":"chemical equation","value":"Na2O"}]	<h1 class="questionTitle" itemprop="name">What is the molecular mass of sodium oxide #Na_2O#?</h1>	null	62 amu	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Sodium Na number 11 has 11 protons and 12 neutrons for a mass of 23 amu. Since there are two Sodiums the mass of Sodium in the molecules is 2 x 23 = 46 amu.</p> <p>Oxygen <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/atomic-number">Atomic number</a> 8 has 8 protons and 8 neutrons, for a mass of 16 amu for the mass of Oxygen in the molecule is 16 amu since there is only one Oxygen atom in the molecule</p> <p>Add the mass of the sodium ( 46 amu) with the mass of Oxygen (16 amu) to find the mass of the molecule</p> <p>46 amu + 16 amu = 62 amu</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The molecular mass of sodium oxide is the sum of 2 Sodium atoms and one Oxygen atom or 62 amu </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Sodium Na number 11 has 11 protons and 12 neutrons for a mass of 23 amu. Since there are two Sodiums the mass of Sodium in the molecules is 2 x 23 = 46 amu.</p> <p>Oxygen <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/atomic-number">Atomic number</a> 8 has 8 protons and 8 neutrons, for a mass of 16 amu for the mass of Oxygen in the molecule is 16 amu since there is only one Oxygen atom in the molecule</p> <p>Add the mass of the sodium ( 46 amu) with the mass of Oxygen (16 amu) to find the mass of the molecule</p> <p>46 amu + 16 amu = 62 amu</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the molecular mass of sodium oxide #Na_2O#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="298005" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/david-drayer"><img alt="" class="" src="https://graph.facebook.com/10206723679871989/picture?height=50&width=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/david-drayer"> David Drayer </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-08-12T03:08:05" itemprop="dateCreated"> Aug 12, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The molecular mass of sodium oxide is the sum of 2 Sodium atoms and one Oxygen atom or 62 amu </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Sodium Na number 11 has 11 protons and 12 neutrons for a mass of 23 amu. Since there are two Sodiums the mass of Sodium in the molecules is 2 x 23 = 46 amu.</p> <p>Oxygen <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/atomic-number">Atomic number</a> 8 has 8 protons and 8 neutrons, for a mass of 16 amu for the mass of Oxygen in the molecule is 16 amu since there is only one Oxygen atom in the molecule</p> <p>Add the mass of the sodium ( 46 amu) with the mass of Oxygen (16 amu) to find the mass of the molecule</p> <p>46 amu + 16 amu = 62 amu</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/298005" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 18952 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the molecular mass of sodium oxide #Na_2O#?	null
2,131	ab30425a-6ddd-11ea-a432-ccda262736ce	https://socratic.org/questions/a-solution-of-liquid-toluene-dissolved-in-liquid-benzene-has-a-benzene-mole-frac	164.5 mmHg	start physical_unit 21 22 vapor_pressure mmhg qc_end physical_unit 29 30 34 35 vapor_pressure qc_end physical_unit 32 32 37 38 vapor_pressure qc_end end	[{"type":"physical unit","value":"Vapor pressure [OF] the solution [IN] mmHg"}]	[{"type":"physical unit","value":"164.5 mmHg"}]	[{"type":"physical unit","value":"Vapor pressure [OF] pure benzene [=] \\pu{183 mmHg}"},{"type":"physical unit","value":"Vapor pressure [OF] toulene [=] \\pu{59.2 mmHg}"},{"type":"physical unit","value":"Benzene mole fraction [OF] liquid benzene in liquid toluene solution [=] \\pu{0.850}"}]	<h1 class="questionTitle" itemprop="name">A solution of liquid toluene dissolved in liquid benzene has a benzene mole fraction of .850. Calculate the vapor pressure of the solution given that the vapor pressures of pure benzene and toulene are 183 mmHg and 59.2 mmHg, respectively?</h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>I tried solving it like this:</p> <p>183(.850) + 59.2(.850) = 206 mmHg but this is wrong, please explain what I am doing wrong </p></div> </h2> </div> </div>	164.5 mmHg	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Mole fraction of benzene"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#n_"benzene"/(n_"benzene"+n_"toluene")=0.850#</mathjax></p> <p>And given a binary solution:</p> <p><mathjax>#"Mole fraction of toluene"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#n_"toluene"/(n_"benzene"+n_"toluene")=0.150#</mathjax></p> <p>Why? Because <mathjax>#chi_"benzene"+chi_"toluene"=1#</mathjax></p> <p>And thus <mathjax>#"vapour pressure of the solution"#</mathjax> is equal to the weighted average of the mole fractions:</p> <p><mathjax>#"Vapour pressure"=(chi_"benzene"xx183+chi_"toluene"xx59.2)mmHg#</mathjax></p> <p><mathjax>#=(0.850xx183+0.150xx59.2)mmHg=164.5mmHg#</mathjax></p> <p>I think you will kick yourself when you realize the mistake you made. Remember, we have ALL made this sort of error. It is easy to do. </p> <p>Is this answer consistent with your model answer? As usual, the vapour pressure is enriched with respect to the proportion of the more volatile component of the solution, i.e. enriched with respect to benzene.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Now the sum of <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> fractions must equal <mathjax>#1#</mathjax>. Do you agree?</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Mole fraction of benzene"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#n_"benzene"/(n_"benzene"+n_"toluene")=0.850#</mathjax></p> <p>And given a binary solution:</p> <p><mathjax>#"Mole fraction of toluene"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#n_"toluene"/(n_"benzene"+n_"toluene")=0.150#</mathjax></p> <p>Why? Because <mathjax>#chi_"benzene"+chi_"toluene"=1#</mathjax></p> <p>And thus <mathjax>#"vapour pressure of the solution"#</mathjax> is equal to the weighted average of the mole fractions:</p> <p><mathjax>#"Vapour pressure"=(chi_"benzene"xx183+chi_"toluene"xx59.2)mmHg#</mathjax></p> <p><mathjax>#=(0.850xx183+0.150xx59.2)mmHg=164.5mmHg#</mathjax></p> <p>I think you will kick yourself when you realize the mistake you made. Remember, we have ALL made this sort of error. It is easy to do. </p> <p>Is this answer consistent with your model answer? As usual, the vapour pressure is enriched with respect to the proportion of the more volatile component of the solution, i.e. enriched with respect to benzene.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A solution of liquid toluene dissolved in liquid benzene has a benzene mole fraction of .850. Calculate the vapor pressure of the solution given that the vapor pressures of pure benzene and toulene are 183 mmHg and 59.2 mmHg, respectively?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>I tried solving it like this:</p> <p>183(.850) + 59.2(.850) = 206 mmHg but this is wrong, please explain what I am doing wrong </p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/partial-pressure" itemprop="url"> <span class="breadcrumb" itemprop="title">Partial Pressure</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="396730" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-26T14:37:16" itemprop="dateCreated"> Mar 26, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Now the sum of <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> fractions must equal <mathjax>#1#</mathjax>. Do you agree?</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Mole fraction of benzene"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#n_"benzene"/(n_"benzene"+n_"toluene")=0.850#</mathjax></p> <p>And given a binary solution:</p> <p><mathjax>#"Mole fraction of toluene"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#n_"toluene"/(n_"benzene"+n_"toluene")=0.150#</mathjax></p> <p>Why? Because <mathjax>#chi_"benzene"+chi_"toluene"=1#</mathjax></p> <p>And thus <mathjax>#"vapour pressure of the solution"#</mathjax> is equal to the weighted average of the mole fractions:</p> <p><mathjax>#"Vapour pressure"=(chi_"benzene"xx183+chi_"toluene"xx59.2)mmHg#</mathjax></p> <p><mathjax>#=(0.850xx183+0.150xx59.2)mmHg=164.5mmHg#</mathjax></p> <p>I think you will kick yourself when you realize the mistake you made. Remember, we have ALL made this sort of error. It is easy to do. </p> <p>Is this answer consistent with your model answer? As usual, the vapour pressure is enriched with respect to the proportion of the more volatile component of the solution, i.e. enriched with respect to benzene.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/396730" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/534e256802bf342adfa30010"> How do you do a steam distillation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/53613f9f02bf3416cd9f8a34"> Question #f8a34 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-i-calculate-the-total-pressure-of-a-mixture-of-gases-by-adding-together-the-"> Can I calculate the total pressure of a mixture of gases by adding together the partial... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-formula-of-partial-pressure"> What is the formula of partial pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-dalton-s-law-of-partial-pressures"> What is the Dalton's law of partial pressures? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/nitrogen-gas-n2-reacts-with-hydrogen-gas-h2-to-form-ammonia-nh3-at-200-c-in-a-cl"> Nitrogen gas (N2) reacts with hydrogen gas (H2) to form ammonia (NH3). 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Calculate the vapor pressure of the solution given that the vapor pressures of pure benzene and toulene are 183 mmHg and 59.2 mmHg, respectively?	I tried solving it like this: 183(.850) + 59.2(.850) = 206 mmHg but this is wrong, please explain what I am doing wrong
2,132	ab4d5e28-6ddd-11ea-a633-ccda262736ce	https://socratic.org/questions/how-many-grams-are-in-17-83-moles-of-carbon-dioxide	784.68 grams	start physical_unit 8 9 mass g qc_end physical_unit 8 9 5 6 mole qc_end end	[{"type":"physical unit","value":"Mass [OF] carbon dioxide [IN] grams"}]	[{"type":"physical unit","value":"784.68 grams"}]	[{"type":"physical unit","value":"Mole [OF] carbon dioxide [=] \\pu{17.83 moles}"}]	<h1 class="questionTitle" itemprop="name">How many grams are in 17.83 moles of carbon dioxide? </h1>	null	784.68 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to determine the mass of a given numbers of moles of an element or compound, multiply the given moles by its molar mass.</p> <p>Molar Mass of <mathjax>#"CO"_2"#</mathjax></p> <p><mathjax>#(1xx12.011 "g/mol")+(2xx15.999"g/mol")="44.009 g/mol CO"_2"#</mathjax></p> <p>Multiply the given moles of <mathjax>#"CO"_2"#</mathjax> times its molar mass.</p> <p><mathjax>#17.83cancel"mol CO"_2xx(44.009"g CO"_2)/(1cancel"mol CO"_2)="784.7 g CO"_2"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"17.83 moles CO"_2#</mathjax> have a mass of <mathjax>#"784.7 g"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to determine the mass of a given numbers of moles of an element or compound, multiply the given moles by its molar mass.</p> <p>Molar Mass of <mathjax>#"CO"_2"#</mathjax></p> <p><mathjax>#(1xx12.011 "g/mol")+(2xx15.999"g/mol")="44.009 g/mol CO"_2"#</mathjax></p> <p>Multiply the given moles of <mathjax>#"CO"_2"#</mathjax> times its molar mass.</p> <p><mathjax>#17.83cancel"mol CO"_2xx(44.009"g CO"_2)/(1cancel"mol CO"_2)="784.7 g CO"_2"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many grams are in 17.83 moles of carbon dioxide? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="260755" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-04-30T22:49:59" itemprop="dateCreated"> Apr 30, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"17.83 moles CO"_2#</mathjax> have a mass of <mathjax>#"784.7 g"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to determine the mass of a given numbers of moles of an element or compound, multiply the given moles by its molar mass.</p> <p>Molar Mass of <mathjax>#"CO"_2"#</mathjax></p> <p><mathjax>#(1xx12.011 "g/mol")+(2xx15.999"g/mol")="44.009 g/mol CO"_2"#</mathjax></p> <p>Multiply the given moles of <mathjax>#"CO"_2"#</mathjax> times its molar mass.</p> <p><mathjax>#17.83cancel"mol CO"_2xx(44.009"g CO"_2)/(1cancel"mol CO"_2)="784.7 g CO"_2"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/260755" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="260909" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/edmund-l"><img alt="" class="" src="https://profilepictures.socratic.org/DnAPD8TISDW0aROTp4qA_Day_3_Story_1._Photo_with_Sky_Tower_from_distance_Walked_around_most_of_west_Auckland_suburbs._Some_of_you_mightve_seen_.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/edmund-l"> Edmund Liew </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-01T10:32:17" itemprop="dateCreated"> May 1, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerDescription"> <div> <div class="markdown"><p>Number of moles = mass of substance <mathjax>#-:#</mathjax> molar mass</p> <p>17.83 moles has been provided for you.</p> <p>The formula of carbon dioxide is: <mathjax>#CO_2#</mathjax>.</p> <p>The molar mass of carbon and oxygen is:<br/> C = 12.0 g/mol<br/> O = 16.0 g/mol<br/> Therefore the molar mass of <mathjax>#CO_2#</mathjax> is:<br/> [<mathjax>#1 xx 12.0 + 2 xx 16.0#</mathjax>] = 44.0 g/mol.</p> <p>The mass of <mathjax>#CO_2#</mathjax> is:<br/> <mathjax>#44.0 xx 17.83#</mathjax> = 784.5 grams<br/> Note: This answer is rounded to nearest one decimal place.</p> <p>Overall, there are 784.5 grams in 17.83 moles of <mathjax>#CO_2#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/260909" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? 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2,133	ac59a948-6ddd-11ea-8480-ccda262736ce	https://socratic.org/questions/58b8449cb72cff795ad24dfa	100 mL	start physical_unit 3 3 volume ml qc_end physical_unit 11 11 9 10 volume qc_end physical_unit 11 11 13 14 concentration qc_end physical_unit 11 11 21 22 concentration qc_end end	[{"type":"physical unit","value":"Volume [OF] SOLVENT [IN] mL"}]	[{"type":"physical unit","value":"100 mL"}]	[{"type":"physical unit","value":"Volume1 [OF] solution [=] \\pu{500 mL}"},{"type":"physical unit","value":"Concentration1 [OF] solution [=] \\pu{1.2 mol/L}"},{"type":"physical unit","value":"Concentration2 [OF] solution [=] \\pu{1.0 mol/L}"}]	<h1 class="questionTitle" itemprop="name">What volume OF SOLVENT must we add to a #500mL# solution of #1.2molL^-1# concentration to dilute the concentration to #1.0mol*L^-1#?</h1>	null	100 mL	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#C_1V_1=C_2V_2#</mathjax>, if we multiply the DIMENSIONS of concentration and volume, i.e.:</p> <p><mathjax>#"Concentration"xx"Volume"-=molcancel(L^-1)xxcancelL=mol#</mathjax>, i.e. <mathjax>#CV-="moles, i.e. amount of substance. "#</mathjax></p> <p>And so, we solve for <mathjax>#V_2=(C_1V_1)/C_2#</mathjax> (and CLEARLY this has the units of volume, as we require.)</p> <p>And so..........,</p> <p><mathjax>#V_2=(1.2cancel(mol)cancel(L^-1)xx500cancel(mL)xx10^-3Lcancel(mL^-1))/(1.0cancel(mol)cancel(L^-1))#</mathjax></p> <p><mathjax>#=0.60L#</mathjax></p> <p>And so we ADD <mathjax>#100mL#</mathjax> to the original solution.........</p> <p>If you're still unsure, say the word, and someone will try again. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Look at this dimensionally...........we must add <mathjax>#100mL#</mathjax> to the initial volume, to make up to a volume of <mathjax>#600mL#</mathjax>...........</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#C_1V_1=C_2V_2#</mathjax>, if we multiply the DIMENSIONS of concentration and volume, i.e.:</p> <p><mathjax>#"Concentration"xx"Volume"-=molcancel(L^-1)xxcancelL=mol#</mathjax>, i.e. <mathjax>#CV-="moles, i.e. amount of substance. "#</mathjax></p> <p>And so, we solve for <mathjax>#V_2=(C_1V_1)/C_2#</mathjax> (and CLEARLY this has the units of volume, as we require.)</p> <p>And so..........,</p> <p><mathjax>#V_2=(1.2cancel(mol)cancel(L^-1)xx500cancel(mL)xx10^-3Lcancel(mL^-1))/(1.0cancel(mol)cancel(L^-1))#</mathjax></p> <p><mathjax>#=0.60L#</mathjax></p> <p>And so we ADD <mathjax>#100mL#</mathjax> to the original solution.........</p> <p>If you're still unsure, say the word, and someone will try again. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What volume OF SOLVENT must we add to a #500mL# solution of #1.2molL^-1# concentration to dilute the concentration to #1.0molL^-1#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/dilution-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">Dilution Calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="385454" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-02T16:32:04" itemprop="dateCreated"> Mar 2, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Look at this dimensionally...........we must add <mathjax>#100mL#</mathjax> to the initial volume, to make up to a volume of <mathjax>#600mL#</mathjax>...........</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#C_1V_1=C_2V_2#</mathjax>, if we multiply the DIMENSIONS of concentration and volume, i.e.:</p> <p><mathjax>#"Concentration"xx"Volume"-=molcancel(L^-1)xxcancelL=mol#</mathjax>, i.e. <mathjax>#CV-="moles, i.e. amount of substance. "#</mathjax></p> <p>And so, we solve for <mathjax>#V_2=(C_1V_1)/C_2#</mathjax> (and CLEARLY this has the units of volume, as we require.)</p> <p>And so..........,</p> <p><mathjax>#V_2=(1.2cancel(mol)cancel(L^-1)xx500cancel(mL)xx10^-3Lcancel(mL^-1))/(1.0cancel(mol)cancel(L^-1))#</mathjax></p> <p><mathjax>#=0.60L#</mathjax></p> <p>And so we ADD <mathjax>#100*mL#</mathjax> to the original solution.........</p> <p>If you're still unsure, say the word, and someone will try again. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/385454" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-concentration-from-absorbance"> How do you calculate concentration from absorbance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-concentration-from-titration"> How do you calculate concentration from titration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-dilution-factor"> How do you calculate dilution factor? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-do-serial-dilution-calculations"> How do you calculate serial dilutions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-calculate-concentration-of-solution-when-its-diluted"> How to calculate concentration of solution when it's diluted? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-examples-of-dilution-calculations"> What are some examples of dilution calculations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-would-be-the-concentration-of-a-solution-made-by-adding-250-ml-of-water-to-"> What would be the concentration of a solution made by adding 250 mL of water to 45.0 mL of 4.2 M KOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-would-be-the-concentration-of-a-solution-made-by-diluting-45-0-ml-of-4-2-m-"> What would be the concentration of a solution made by diluting 45.0 mL of 4.2 M KOH to 250 mL? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-a-solution-that-is-made-by-diluting-50-00-ml-of-a-4-74-m"> What is the molarity of a solution that is made by diluting 50.00 mL of a 4.74 M solution of HCl... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-volume-of-water-would-you-add-to-15-00-ml-of-a-6-77-m-solution-of-nitric-ac"> What volume of water would you add to 15.00 mL of a 6.77 M solution of nitric acid in order to... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/dilution-calculations"> See all questions in Dilution Calculations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1537 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What volume OF SOLVENT must we add to a #500mL# solution of #1.2molL^-1# concentration to dilute the concentration to #1.0mol*L^-1#?	null
2,134	ab207bf0-6ddd-11ea-ab92-ccda262736ce	https://socratic.org/questions/in-the-equation-mg-s-2hcl-aq-mgcl-2-aq-h-2-g-what-mass-of-hydrogen-will-be-obtai	0.20 g	start physical_unit 14 14 mass g qc_end physical_unit 6 6 22 23 molarity qc_end physical_unit 31 31 28 29 mass qc_end chemical_equation 3 10 qc_end end	[{"type":"physical unit","value":"Mass [OF] hydrogen [IN] g"}]	[{"type":"physical unit","value":"0.20 g"}]	[{"type":"chemical equation","value":"Mg(s) + 2 HCl(aq) -> MgCl2(aq) + H2(g)"},{"type":"physical unit","value":"Volume [OF] HCl solution [=] \\pu{100 cm^3}"},{"type":"physical unit","value":"Molarity [OF] HCl solution [=] \\pu{2.00 mol/dm^3}"},{"type":"physical unit","value":"Mass [OF] magnesium [=] \\pu{4.86 g}"}]	<h1 class="questionTitle" itemprop="name">In the equation #Mg(s) + 2HCl(aq) -> MgCL_2(aq) + H_2(g)#, what mass of hydrogen will be obtained if #100# #cm^3# of 2.00 mol #dm^-3# #HCl# are added to 4.86 g of magnesium?</h1>	null	0.20 g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Moles of metal, <mathjax>#=#</mathjax> <mathjax>#(4.86g)/(24.305gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.200#</mathjax> <mathjax>#mol#</mathjax>.</p> <p>Moles of <mathjax>#HCl#</mathjax> <mathjax>#=#</mathjax> <mathjax>#100 cm^-3xx2.00moldm^-3#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.200#</mathjax> <mathjax>#mol#</mathjax></p> <p>Clearly, the acid is in <em>deficiency</em> ; i.e. it is the <a href="http://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a>, because the equation above specifies that that 2 equiv of HCl are required for each equiv of metal. </p> <p>So if <mathjax>#0.200#</mathjax> <mathjax>#mol#</mathjax> acid react, then (by the stoichiometry), 1/2 this quantity, i.e. <mathjax>#0.100#</mathjax> <mathjax>#mol#</mathjax> of dihydrogen will evolve.</p> <p>So, <mathjax>#0.100#</mathjax> <mathjax>#mol#</mathjax> dihydrogen are evolved; this has a mass of <mathjax>#0.100molxx2.00g*mol^-1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??g#</mathjax>.</p> <p>If 1 mol dihydrogen gas occupies <mathjax>#24.5#</mathjax> <mathjax>#dm^3#</mathjax> at room temperature and pressure, what will be the VOLUME of gas evolved?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Mg(s) + 2HCl(aq) rarr MgCl_2(aq) + H_2(g)uarr#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Moles of metal, <mathjax>#=#</mathjax> <mathjax>#(4.86g)/(24.305gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.200#</mathjax> <mathjax>#mol#</mathjax>.</p> <p>Moles of <mathjax>#HCl#</mathjax> <mathjax>#=#</mathjax> <mathjax>#100 cm^-3xx2.00moldm^-3#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.200#</mathjax> <mathjax>#mol#</mathjax></p> <p>Clearly, the acid is in <em>deficiency</em> ; i.e. it is the <a href="http://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a>, because the equation above specifies that that 2 equiv of HCl are required for each equiv of metal. </p> <p>So if <mathjax>#0.200#</mathjax> <mathjax>#mol#</mathjax> acid react, then (by the stoichiometry), 1/2 this quantity, i.e. <mathjax>#0.100#</mathjax> <mathjax>#mol#</mathjax> of dihydrogen will evolve.</p> <p>So, <mathjax>#0.100#</mathjax> <mathjax>#mol#</mathjax> dihydrogen are evolved; this has a mass of <mathjax>#0.100molxx2.00g*mol^-1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??g#</mathjax>.</p> <p>If 1 mol dihydrogen gas occupies <mathjax>#24.5#</mathjax> <mathjax>#dm^3#</mathjax> at room temperature and pressure, what will be the VOLUME of gas evolved?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">In the equation #Mg(s) + 2HCl(aq) -> MgCL_2(aq) + H_2(g)#, what mass of hydrogen will be obtained if #100# #cm^3# of 2.00 mol #dm^-3# #HCl# are added to 4.86 g of magnesium?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="194029" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-28T17:56:42" itemprop="dateCreated"> Nov 28, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Mg(s) + 2HCl(aq) rarr MgCl_2(aq) + H_2(g)uarr#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Moles of metal, <mathjax>#=#</mathjax> <mathjax>#(4.86g)/(24.305gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.200#</mathjax> <mathjax>#mol#</mathjax>.</p> <p>Moles of <mathjax>#HCl#</mathjax> <mathjax>#=#</mathjax> <mathjax>#100 cm^-3xx2.00moldm^-3#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.200#</mathjax> <mathjax>#mol#</mathjax></p> <p>Clearly, the acid is in <em>deficiency</em> ; i.e. it is the <a href="http://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a>, because the equation above specifies that that 2 equiv of HCl are required for each equiv of metal. </p> <p>So if <mathjax>#0.200#</mathjax> <mathjax>#mol#</mathjax> acid react, then (by the stoichiometry), 1/2 this quantity, i.e. <mathjax>#0.100#</mathjax> <mathjax>#mol#</mathjax> of dihydrogen will evolve.</p> <p>So, <mathjax>#0.100#</mathjax> <mathjax>#mol#</mathjax> dihydrogen are evolved; this has a mass of <mathjax>#0.100molxx2.00g*mol^-1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??g#</mathjax>.</p> <p>If 1 mol dihydrogen gas occupies <mathjax>#24.5#</mathjax> <mathjax>#dm^3#</mathjax> at room temperature and pressure, what will be the VOLUME of gas evolved?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/194029" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="194121" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-28T22:11:57" itemprop="dateCreated"> Nov 28, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The limiting reactant is <mathjax>#"HCl"#</mathjax>, which will produce <mathjax>#"0.202 g H"_2"#</mathjax> under the stated conditions.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is a limiting reactant problem.</p> <p><mathjax>#"Mg(s)" + "2HCl(aq)"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"MgCl"_2("aq")"+ H"_2("g")"#</mathjax></p> <p><strong>Determine Moles of Magnesium</strong><br/> Divide the given mass of magnesium by its molar mass (atomic weight on periodic table in g/mol).</p> <p><mathjax>#4.86cancel"g Mg"xx(1"mol Mg")/(24.3050cancel"g Mg")="0.200 mol Mg"#</mathjax></p> <p><strong>Determine Moles of 2M Hydrochloric Acid</strong><br/> Convert <mathjax>#"100 cm"^3"#</mathjax> to <mathjax>#"100 mL"#</mathjax> and then to <mathjax>#"0.1 L"#</mathjax>. <br/> <mathjax>#"1 dm"^3#</mathjax><mathjax>#=#</mathjax><mathjax>#"1 L"#</mathjax><br/> Convert <mathjax>#"2.00 mol/dm"^3#</mathjax> to <mathjax>#"2.00 mol/L"#</mathjax><br/> Multiply <mathjax>#0.1"L"#</mathjax> times <mathjax>#"2.00 mol/L"#</mathjax>.</p> <p><mathjax>#100cancel"cm"^3xx(1cancel"mL")/(1cancel"cm"^3)xx(1"L")/(1000cancel"mL")="0.1 L HCl"#</mathjax></p> <p><mathjax>#"2.00 mol/dm"^3"#</mathjax><mathjax>#=#</mathjax><mathjax>#"2.00 mol/L"#</mathjax></p> <p><mathjax>#0.1cancel"L"xx(2.00"mol")/(1cancel"L")="0.200 mol HCl"#</mathjax></p> <p>Multiply the moles of each reactant times the appropriate mole ratio from the balanced equation. Then multiply times the molar mass of hydrogen gas, <mathjax>#"2.01588 g/mol"#</mathjax></p> <p><mathjax>#0.200"mol Mg"xx(1"mol H"_2)/(1"mol Mg")xx(2.01588"g H"_2)/(1"mol H"_2)="0.403 g H"_2"#</mathjax></p> <p><mathjax>#0.200"mol HCl"xx(1"mol H"_2)/(2"mol HCl")xx(2.01588"g H"_2)/(1"mol H"_2)="0.202 g H"_2"#</mathjax></p> <p>The limiting reactant is <mathjax>#"HCl"#</mathjax>, which will produce <mathjax>#"0.202 g H"_2"#</mathjax> under the stated conditions.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/194121" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What is stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ab82402bf342f48d93ac6"> Question #93ac6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-we-study-stoichiometry"> Why do we study stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-naoh-is-produced-from-1-20-x-102-grams-of-na2o-na2o-h2o-2-naoh"> How many grams of NaOH is produced from #1.20 x 10^2# grams of #Na_2O#? #Na_2O + H_2O -> 2NaOH# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-na2o-are-required-to-produce-1-60-x-102-grams-of-naoh-na2o-h2o"> How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? 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2,135	a8539f88-6ddd-11ea-aef6-ccda262736ce	https://socratic.org/questions/5814bbfa7c014941484eec43	MnO2 + 4 H+ + 2 Cl- -> Mn^2+ + Cl(g) + 2 H2O	start chemical_equation qc_end chemical_equation 7 7 qc_end substance 9 10 qc_end chemical_equation 13 13 qc_end substance 15 16 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the reduction"}]	[{"type":"chemical equation","value":"MnO2 + 4 H+ + 2 Cl- -> Mn^2+ + Cl(g) + 2 H2O"}]	[{"type":"chemical equation","value":"MnO2"},{"type":"substance name","value":"chloride anion"},{"type":"chemical equation","value":"Mn^2+"},{"type":"substance name","value":"chlorine gas"}]	<h1 class="questionTitle" itemprop="name">How do we represent the reduction of #MnO_2# by chloride anion to give #Mn^(2+)# and chlorine gas?</h1>	null	MnO2 + 4 H+ + 2 Cl- -> Mn^2+ + Cl(g) + 2 H2O	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>...........and chloride ion is oxidized.</p> <p><mathjax>#Cl^(-) rarr 1/2Cl_2(g) + e^-#</mathjax> <mathjax>#(ii)#</mathjax></p> <p><mathjax>#(i) + (ii)xx2:#</mathjax> (we wish to remove electrons from the final redox equation.</p> <p><mathjax>#MnO_2 +4H^+ + 2Cl^(-) rarr Mn^(2+) + Cl_2(g) + 2H_2O#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>This is a redox reaction: manganese is reduced......</p> <p><mathjax>#MnO_2 +4H^+ + 2e^(-) rarr Mn^(2+) + 2H_2O#</mathjax> <mathjax>#(i)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>...........and chloride ion is oxidized.</p> <p><mathjax>#Cl^(-) rarr 1/2Cl_2(g) + e^-#</mathjax> <mathjax>#(ii)#</mathjax></p> <p><mathjax>#(i) + (ii)xx2:#</mathjax> (we wish to remove electrons from the final redox equation.</p> <p><mathjax>#MnO_2 +4H^+ + 2Cl^(-) rarr Mn^(2+) + Cl_2(g) + 2H_2O#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do we represent the reduction of #MnO_2# by chloride anion to give #Mn^(2+)# and chlorine gas?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-reactions-and-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions and Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="328718" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-10-30T16:15:39" itemprop="dateCreated"> Oct 30, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>This is a redox reaction: manganese is reduced......</p> <p><mathjax>#MnO_2 +4H^+ + 2e^(-) rarr Mn^(2+) + 2H_2O#</mathjax> <mathjax>#(i)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>...........and chloride ion is oxidized.</p> <p><mathjax>#Cl^(-) rarr 1/2Cl_2(g) + e^-#</mathjax> <mathjax>#(ii)#</mathjax></p> <p><mathjax>#(i) + (ii)xx2:#</mathjax> (we wish to remove electrons from the final redox equation.</p> <p><mathjax>#MnO_2 +4H^+ + 2Cl^(-) rarr Mn^(2+) + Cl_2(g) + 2H_2O#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/328718" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" 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</div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1614 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How do we represent the reduction of #MnO_2# by chloride anion to give #Mn^(2+)# and chlorine gas?	null
2,136	ad18ce52-6ddd-11ea-887b-ccda262736ce	https://socratic.org/questions/what-is-the-celsius-temperature-of-100-0-g-of-chlorine-gas-in-a-55-0-l-container	226.87 Celsius	start physical_unit 9 10 temperature °c qc_end physical_unit 9 10 6 7 mass qc_end physical_unit 9 10 13 14 volume qc_end physical_unit 9 10 17 18 pressure qc_end end	[{"type":"physical unit","value":"Temperature [OF] chlorine gas [IN] Celsius"}]	[{"type":"physical unit","value":"226.87 Celsius"}]	[{"type":"physical unit","value":"Mass [OF] chlorine gas [=] \\pu{100.0 g}"},{"type":"physical unit","value":"Volume [OF] chlorine gas [=] \\pu{55.0 L}"},{"type":"physical unit","value":"Pressure [OF] chlorine gas [=] \\pu{800 mmHg}"}]	<h1 class="questionTitle" itemprop="name">What is the Celsius temperature of 100.0 g of chlorine gas in a 55.0-L container at 800 mm Hg?</h1>	null	226.87 Celsius	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your tool of choice here will be the <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> equation</strong>, which looks like this </p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)(PV = nRT)))#</mathjax></p> </blockquote> <p>Here</p> <blockquote> <ul> <li><mathjax>#P#</mathjax> is the pressure of the gas</li> <li><mathjax>#V#</mathjax> is the volume it occupies</li> <li><mathjax>#n#</mathjax> is the number of moles of gas present in the sample</li> <li><mathjax>#R#</mathjax> is the <em>universal gas constant</em>, equal to <mathjax>#0.0821("atm L")/("mol K")#</mathjax></li> <li><mathjax>#T#</mathjax> is the <strong>absolute temperature</strong> of the gas</li> </ul> </blockquote> <p>Now, it's important to realize that the unit you have for pressure <strong>must match</strong> the unit used by the universal gas constant. </p> <p>In your case, you must convert the pressure from <em>mmHg</em> to <em>atm</em> by using the conversion factor </p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)("1 atm = 760 mmHg")))#</mathjax></p> </blockquote> <p>Start by converting the mass of chlorine to <em>moles</em> by using the <strong>molar mass</strong> of chlorine gas, <mathjax>#"Cl"_2#</mathjax></p> <blockquote> <p><mathjax>#100.0 color(red)(cancel(color(black)("g"))) * "1 mol Cl"_2/(70.906color(red)(cancel(color(black)("g")))) = "1.4103 moles Cl"_2#</mathjax></p> </blockquote> <p>Rearrange the ideal gas law equation to solve for <mathjax>#T#</mathjax></p> <blockquote> <p><mathjax>#PV = nRT implies T = (PV)/(nR)#</mathjax></p> </blockquote> <p>and plug in your values to find the <strong>absolute temperature</strong> of the gas</p> <blockquote> <p><mathjax>#T = ( 800/760 color(red)(cancel(color(black)("atm"))) * 55.0color(red)(cancel(color(black)("L"))))/(1.4103color(red)(cancel(color(black)("moles"))) * 0.0821(color(red)(cancel(color(black)("atm"))) * color(red)(cancel(color(black)("L"))))/(color(red)(cancel(color(black)("mol"))) * "K"))#</mathjax></p> <p><mathjax>#T = "500.02 K"#</mathjax></p> </blockquote> <p>To convert this to <em>degrees Celsius</em>, use the fact that</p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)(t[""^@"C"] = T["K"] - 273.15)))#</mathjax></p> </blockquote> <p>You will thus have</p> <blockquote> <p><mathjax>#t = "500.02 K" - 273.15 = color(darkgreen)(ul(color(black)(230^@"C")))#</mathjax></p> </blockquote> <p>I'll leave the answer rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, but keep in mind that you only have one significant figure for the pressure of the gas. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#230^@"C"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your tool of choice here will be the <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> equation</strong>, which looks like this </p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)(PV = nRT)))#</mathjax></p> </blockquote> <p>Here</p> <blockquote> <ul> <li><mathjax>#P#</mathjax> is the pressure of the gas</li> <li><mathjax>#V#</mathjax> is the volume it occupies</li> <li><mathjax>#n#</mathjax> is the number of moles of gas present in the sample</li> <li><mathjax>#R#</mathjax> is the <em>universal gas constant</em>, equal to <mathjax>#0.0821("atm L")/("mol K")#</mathjax></li> <li><mathjax>#T#</mathjax> is the <strong>absolute temperature</strong> of the gas</li> </ul> </blockquote> <p>Now, it's important to realize that the unit you have for pressure <strong>must match</strong> the unit used by the universal gas constant. </p> <p>In your case, you must convert the pressure from <em>mmHg</em> to <em>atm</em> by using the conversion factor </p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)("1 atm = 760 mmHg")))#</mathjax></p> </blockquote> <p>Start by converting the mass of chlorine to <em>moles</em> by using the <strong>molar mass</strong> of chlorine gas, <mathjax>#"Cl"_2#</mathjax></p> <blockquote> <p><mathjax>#100.0 color(red)(cancel(color(black)("g"))) * "1 mol Cl"_2/(70.906color(red)(cancel(color(black)("g")))) = "1.4103 moles Cl"_2#</mathjax></p> </blockquote> <p>Rearrange the ideal gas law equation to solve for <mathjax>#T#</mathjax></p> <blockquote> <p><mathjax>#PV = nRT implies T = (PV)/(nR)#</mathjax></p> </blockquote> <p>and plug in your values to find the <strong>absolute temperature</strong> of the gas</p> <blockquote> <p><mathjax>#T = ( 800/760 color(red)(cancel(color(black)("atm"))) * 55.0color(red)(cancel(color(black)("L"))))/(1.4103color(red)(cancel(color(black)("moles"))) * 0.0821(color(red)(cancel(color(black)("atm"))) * color(red)(cancel(color(black)("L"))))/(color(red)(cancel(color(black)("mol"))) * "K"))#</mathjax></p> <p><mathjax>#T = "500.02 K"#</mathjax></p> </blockquote> <p>To convert this to <em>degrees Celsius</em>, use the fact that</p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)(t[""^@"C"] = T["K"] - 273.15)))#</mathjax></p> </blockquote> <p>You will thus have</p> <blockquote> <p><mathjax>#t = "500.02 K" - 273.15 = color(darkgreen)(ul(color(black)(230^@"C")))#</mathjax></p> </blockquote> <p>I'll leave the answer rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, but keep in mind that you only have one significant figure for the pressure of the gas. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the Celsius temperature of 100.0 g of chlorine gas in a 55.0-L container at 800 mm Hg?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/ideal-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Ideal Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="384040" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-02-28T00:02:31" itemprop="dateCreated"> Feb 28, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#230^@"C"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your tool of choice here will be the <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> equation</strong>, which looks like this </p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)(PV = nRT)))#</mathjax></p> </blockquote> <p>Here</p> <blockquote> <ul> <li><mathjax>#P#</mathjax> is the pressure of the gas</li> <li><mathjax>#V#</mathjax> is the volume it occupies</li> <li><mathjax>#n#</mathjax> is the number of moles of gas present in the sample</li> <li><mathjax>#R#</mathjax> is the <em>universal gas constant</em>, equal to <mathjax>#0.0821("atm L")/("mol K")#</mathjax></li> <li><mathjax>#T#</mathjax> is the <strong>absolute temperature</strong> of the gas</li> </ul> </blockquote> <p>Now, it's important to realize that the unit you have for pressure <strong>must match</strong> the unit used by the universal gas constant. </p> <p>In your case, you must convert the pressure from <em>mmHg</em> to <em>atm</em> by using the conversion factor </p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)("1 atm = 760 mmHg")))#</mathjax></p> </blockquote> <p>Start by converting the mass of chlorine to <em>moles</em> by using the <strong>molar mass</strong> of chlorine gas, <mathjax>#"Cl"_2#</mathjax></p> <blockquote> <p><mathjax>#100.0 color(red)(cancel(color(black)("g"))) * "1 mol Cl"_2/(70.906color(red)(cancel(color(black)("g")))) = "1.4103 moles Cl"_2#</mathjax></p> </blockquote> <p>Rearrange the ideal gas law equation to solve for <mathjax>#T#</mathjax></p> <blockquote> <p><mathjax>#PV = nRT implies T = (PV)/(nR)#</mathjax></p> </blockquote> <p>and plug in your values to find the <strong>absolute temperature</strong> of the gas</p> <blockquote> <p><mathjax>#T = ( 800/760 color(red)(cancel(color(black)("atm"))) * 55.0color(red)(cancel(color(black)("L"))))/(1.4103color(red)(cancel(color(black)("moles"))) * 0.0821(color(red)(cancel(color(black)("atm"))) * color(red)(cancel(color(black)("L"))))/(color(red)(cancel(color(black)("mol"))) * "K"))#</mathjax></p> <p><mathjax>#T = "500.02 K"#</mathjax></p> </blockquote> <p>To convert this to <em>degrees Celsius</em>, use the fact that</p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)(t[""^@"C"] = T["K"] - 273.15)))#</mathjax></p> </blockquote> <p>You will thus have</p> <blockquote> <p><mathjax>#t = "500.02 K" - 273.15 = color(darkgreen)(ul(color(black)(230^@"C")))#</mathjax></p> </blockquote> <p>I'll leave the answer rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, but keep in mind that you only have one significant figure for the pressure of the gas. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/384040" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-ideal-gas-constant"> How do you find the ideal gas constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-solve-ideal-gas-law-problems"> How do you solve ideal gas law problems? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-know-which-ideal-gas-constant-to-use"> How do you know which ideal gas constant to use? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ideal-gas-constant-for-butane"> What is the ideal gas constant for butane? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-ideal-gas-law-in-kelvin"> Why is ideal gas law in kelvin? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ideal-gas-constant-important"> Why is the ideal gas constant important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-di-electric-constant"> What is the di-electric constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-volume-l-will-0-20-mol-hi-occupy-at-300-k-and-100-0-kpa-r-8-314-kpa-l-k-mol"> What volume (L) will 0.20 mol HI occupy at 300 K and 100.0 kPa? R = 8.314 kPa L / (K mol) =... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-molar-mass-of-a-gas"> How do you calculate the molar mass of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-should-i-use-the-ideal-gas-law-and-not-the-combined-gas-law"> When should I use the ideal gas law and not the combined gas law? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/ideal-gas-law"> See all questions in Ideal Gas Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 14663 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the Celsius temperature of 100.0 g of chlorine gas in a 55.0-L container at 800 mm Hg?	null
2,137	ab43f3ca-6ddd-11ea-92fb-ccda262736ce	https://socratic.org/questions/what-is-the-formula-for-barium-bromide	BaBr2	start chemical_formula qc_end substance 5 6 qc_end end	[{"type":"other","value":"Chemical Formula [OF] barium bromide [IN] default"}]	[{"type":"chemical equation","value":"BaBr2"}]	[{"type":"substance name","value":"Barium bromide"}]	<h1 class="questionTitle" itemprop="name">What is the formula for barium bromide? </h1>	null	BaBr2	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Barium is an <mathjax>#"alkaline-earth metal"#</mathjax>............i.e. <mathjax>#"Group 2"#</mathjax>.</p> <p>And thus barium commonly forms a <mathjax>#Ba^(2+)#</mathjax> ion, just as the halogen bromine, commonly forms a <mathjax>#Br^-#</mathjax>. And hence the salt formed is <mathjax>#BaBr_2#</mathjax>. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#BaBr_2#</mathjax>...............</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Barium is an <mathjax>#"alkaline-earth metal"#</mathjax>............i.e. <mathjax>#"Group 2"#</mathjax>.</p> <p>And thus barium commonly forms a <mathjax>#Ba^(2+)#</mathjax> ion, just as the halogen bromine, commonly forms a <mathjax>#Br^-#</mathjax>. And hence the salt formed is <mathjax>#BaBr_2#</mathjax>. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the formula for barium bromide? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#ionic-bonds-and-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Ionic Bonds</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/ionic-bonds-and-formulas/naming-ionic-compounds" itemprop="url"> <span class="breadcrumb" itemprop="title">Naming Ionic Compounds</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="406421" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-13T19:08:19" itemprop="dateCreated"> Apr 13, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#BaBr_2#</mathjax>...............</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Barium is an <mathjax>#"alkaline-earth metal"#</mathjax>............i.e. <mathjax>#"Group 2"#</mathjax>.</p> <p>And thus barium commonly forms a <mathjax>#Ba^(2+)#</mathjax> ion, just as the halogen bromine, commonly forms a <mathjax>#Br^-#</mathjax>. And hence the salt formed is <mathjax>#BaBr_2#</mathjax>. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/406421" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-name-ionic-compounds-with-transition-metals"> How do you name ionic compounds with transition metals? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-name-of-the-ionic-compound-ni3-po4-2"> What is the name of the ionic compound Ni3(PO4)2? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-rules-are-used-to-name-ionic-compounds"> What rules are used to name ionic compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-name-ionic-compounds-with-three-elements"> How can I name ionic compounds with three elements? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-name-ionic-compounds-with-transition-metals"> How can I name ionic compounds with transition metals? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-name-ionic-compounds-with-roman-numerals"> How do you name ionic compounds with roman numerals? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-name-polyatomic-ionic-compounds"> How can I name polyatomic ionic compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-name-ionic-compounds"> How can I name ionic compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-name-binary-ionic-compounds"> How can I name binary ionic compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-examples-of-ionic-compounds-names"> What are some examples of ionic compounds names? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/ionic-bonds-and-formulas/naming-ionic-compounds"> See all questions in Naming Ionic Compounds </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 9146 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the formula for barium bromide?	null
2,138	ac994b1c-6ddd-11ea-ba1e-ccda262736ce	https://socratic.org/questions/what-is-the-oh-in-a-solution-of-ph-3-00	1.00 × 10^(-11) M	start physical_unit 6 6 [oh-] mol/l qc_end physical_unit 6 6 9 9 ph qc_end end	[{"type":"physical unit","value":"[OH-] [OF] the solution [IN] M"}]	[{"type":"physical unit","value":"1.00 × 10^(-11) M"}]	[{"type":"physical unit","value":"pH [OF] the solution [=] \\pu{3.00}"}]	<h1 class="questionTitle" itemprop="name">What is the [#OH^-#] in a solution of pH 3.00?</h1>	null	1.00 × 10^(-11) M	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>For this answer, we use the formula:<br/> <mathjax>#pH+pOH =14#</mathjax> <br/> We can write that like this:<br/> <mathjax>#pOH =14-pH#</mathjax></p> <p>Since <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a>=3 is given, we calculate pOH<br/> <mathjax>#pOH=14-3=11#</mathjax></p> <p>Now the <mathjax>#[OH^"-"]#</mathjax> can be calculated from the pOH by using this formula: <mathjax>#[OH^"-"]=10^(-pOH)#</mathjax><br/> We obtain: <mathjax>#[OH^"-"]=10^(-11)#</mathjax><br/> For more information about pH, check <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">here</a>!</p> <p><strong>----------------------------------------------------------</strong></p> <p><strong>How is <mathjax>#pH+pOH =14#</mathjax> established? </strong><br/> In water, the following (ionization) reaction occurs:<br/> <mathjax>#2 H_"2"O -> H_"3"O^"+" + OH^"-"#</mathjax></p> <p>Therefore the equilibrium can be written like <br/> <mathjax>#K_"c"=([H_"3"O^"+"][OH^"-"])/[H_"2"O]#</mathjax><br/> Since water is the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a> here, we do not take the concentration of water into consideration (is very big). We obtain the following expression:<br/> <mathjax>#K_"c"=[H_"3"O^"+"][OH^"-"]#</mathjax></p> <p>The <mathjax>#K_"c"#</mathjax> in this equation represents a special number because we talk about the ionisation of water. Therefore we denote <mathjax>#K_"c"#</mathjax> as <mathjax>#K_"w"#</mathjax>. The value of the <mathjax>#K_"w"#</mathjax> is measured at 25°C.<br/> <mathjax>#K_"w" (25°C) = 110^(-14)#</mathjax> <br/> This means we can say:<br/> <mathjax>#K_"c"=K_"w"=[H_"3"O^"+"][OH^"-"]=110^(-14)#</mathjax></p> <p>To get from the <mathjax>#[H_"3"O^"+"]#</mathjax> (concentration <mathjax>#H_"3"O^"+"#</mathjax>) to the pH, we use the following formula:<br/> <mathjax>#pH=- log[H_"3"O^"+"]#</mathjax><br/> The same is true for the <mathjax>#[OH^"-"]#</mathjax>, since we define pOH as<br/> <mathjax>#pOH=-log[OH^"-"]#</mathjax></p> <p>Now if we take the Log from both sides of the <mathjax>#K_"w"#</mathjax> equation, we get:<br/> <mathjax>#log(110^(-14))=log([H_"3"O"]*[OH^-])#</mathjax><br/> A mathematics rule tells us that multiplying inside the logarithm function is the same as adding these logarithms. Therefore we get<br/> <mathjax>#log(10^(-14))=log[H_"3"O"]+log[OH^-]#</mathjax></p> <p>And now we can use the definitions of pOH and OH! We get:<br/> <mathjax>#log(10^(-14))=-pH -pOH#</mathjax><br/> with <mathjax>#log(10^(-14))=-14#</mathjax> we get our function<br/> <mathjax>#-pH-pOH =-14#</mathjax><br/> Which is the same as<br/> <mathjax>#pH+pOH=14#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#[OH^"-"]=10^(-11)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>For this answer, we use the formula:<br/> <mathjax>#pH+pOH =14#</mathjax> <br/> We can write that like this:<br/> <mathjax>#pOH =14-pH#</mathjax></p> <p>Since <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a>=3 is given, we calculate pOH<br/> <mathjax>#pOH=14-3=11#</mathjax></p> <p>Now the <mathjax>#[OH^"-"]#</mathjax> can be calculated from the pOH by using this formula: <mathjax>#[OH^"-"]=10^(-pOH)#</mathjax><br/> We obtain: <mathjax>#[OH^"-"]=10^(-11)#</mathjax><br/> For more information about pH, check <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">here</a>!</p> <p><strong>----------------------------------------------------------</strong></p> <p><strong>How is <mathjax>#pH+pOH =14#</mathjax> established? </strong><br/> In water, the following (ionization) reaction occurs:<br/> <mathjax>#2 H_"2"O -> H_"3"O^"+" + OH^"-"#</mathjax></p> <p>Therefore the equilibrium can be written like <br/> <mathjax>#K_"c"=([H_"3"O^"+"][OH^"-"])/[H_"2"O]#</mathjax><br/> Since water is the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a> here, we do not take the concentration of water into consideration (is very big). We obtain the following expression:<br/> <mathjax>#K_"c"=[H_"3"O^"+"][OH^"-"]#</mathjax></p> <p>The <mathjax>#K_"c"#</mathjax> in this equation represents a special number because we talk about the ionisation of water. Therefore we denote <mathjax>#K_"c"#</mathjax> as <mathjax>#K_"w"#</mathjax>. The value of the <mathjax>#K_"w"#</mathjax> is measured at 25°C.<br/> <mathjax>#K_"w" (25°C) = 110^(-14)#</mathjax> <br/> This means we can say:<br/> <mathjax>#K_"c"=K_"w"=[H_"3"O^"+"][OH^"-"]=110^(-14)#</mathjax></p> <p>To get from the <mathjax>#[H_"3"O^"+"]#</mathjax> (concentration <mathjax>#H_"3"O^"+"#</mathjax>) to the pH, we use the following formula:<br/> <mathjax>#pH=- log[H_"3"O^"+"]#</mathjax><br/> The same is true for the <mathjax>#[OH^"-"]#</mathjax>, since we define pOH as<br/> <mathjax>#pOH=-log[OH^"-"]#</mathjax></p> <p>Now if we take the Log from both sides of the <mathjax>#K_"w"#</mathjax> equation, we get:<br/> <mathjax>#log(110^(-14))=log([H_"3"O"]*[OH^-])#</mathjax><br/> A mathematics rule tells us that multiplying inside the logarithm function is the same as adding these logarithms. Therefore we get<br/> <mathjax>#log(10^(-14))=log[H_"3"O"]+log[OH^-]#</mathjax></p> <p>And now we can use the definitions of pOH and OH! We get:<br/> <mathjax>#log(10^(-14))=-pH -pOH#</mathjax><br/> with <mathjax>#log(10^(-14))=-14#</mathjax> we get our function<br/> <mathjax>#-pH-pOH =-14#</mathjax><br/> Which is the same as<br/> <mathjax>#pH+pOH=14#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the [#OH^-#] in a solution of pH 3.00?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/ph-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">pH calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="400435" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/martin-m-2"><img alt="" class="" src="https://profilepictures.socratic.org/f0sDBdFaTJCkuFNIfZjD_Profielfoto.PNG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/martin-m-2"> Martin M. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-02T13:57:37" itemprop="dateCreated"> Apr 2, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#[OH^"-"]=10^(-11)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>For this answer, we use the formula:<br/> <mathjax>#pH+pOH =14#</mathjax> <br/> We can write that like this:<br/> <mathjax>#pOH =14-pH#</mathjax></p> <p>Since <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a>=3 is given, we calculate pOH<br/> <mathjax>#pOH=14-3=11#</mathjax></p> <p>Now the <mathjax>#[OH^"-"]#</mathjax> can be calculated from the pOH by using this formula: <mathjax>#[OH^"-"]=10^(-pOH)#</mathjax><br/> We obtain: <mathjax>#[OH^"-"]=10^(-11)#</mathjax><br/> For more information about pH, check <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">here</a>!</p> <p><strong>----------------------------------------------------------</strong></p> <p><strong>How is <mathjax>#pH+pOH =14#</mathjax> established? </strong><br/> In water, the following (ionization) reaction occurs:<br/> <mathjax>#2 H_"2"O -> H_"3"O^"+" + OH^"-"#</mathjax></p> <p>Therefore the equilibrium can be written like <br/> <mathjax>#K_"c"=([H_"3"O^"+"][OH^"-"])/[H_"2"O]#</mathjax><br/> Since water is the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a> here, we do not take the concentration of water into consideration (is very big). We obtain the following expression:<br/> <mathjax>#K_"c"=[H_"3"O^"+"][OH^"-"]#</mathjax></p> <p>The <mathjax>#K_"c"#</mathjax> in this equation represents a special number because we talk about the ionisation of water. Therefore we denote <mathjax>#K_"c"#</mathjax> as <mathjax>#K_"w"#</mathjax>. The value of the <mathjax>#K_"w"#</mathjax> is measured at 25°C.<br/> <mathjax>#K_"w" (25°C) = 110^(-14)#</mathjax> <br/> This means we can say:<br/> <mathjax>#K_"c"=K_"w"=[H_"3"O^"+"][OH^"-"]=110^(-14)#</mathjax></p> <p>To get from the <mathjax>#[H_"3"O^"+"]#</mathjax> (concentration <mathjax>#H_"3"O^"+"#</mathjax>) to the pH, we use the following formula:<br/> <mathjax>#pH=- log[H_"3"O^"+"]#</mathjax><br/> The same is true for the <mathjax>#[OH^"-"]#</mathjax>, since we define pOH as<br/> <mathjax>#pOH=-log[OH^"-"]#</mathjax></p> <p>Now if we take the Log from both sides of the <mathjax>#K_"w"#</mathjax> equation, we get:<br/> <mathjax>#log(110^(-14))=log([H_"3"O"]*[OH^-])#</mathjax><br/> A mathematics rule tells us that multiplying inside the logarithm function is the same as adding these logarithms. Therefore we get<br/> <mathjax>#log(10^(-14))=log[H_"3"O"]+log[OH^-]#</mathjax></p> <p>And now we can use the definitions of pOH and OH! We get:<br/> <mathjax>#log(10^(-14))=-pH -pOH#</mathjax><br/> with <mathjax>#log(10^(-14))=-14#</mathjax> we get our function<br/> <mathjax>#-pH-pOH =-14#</mathjax><br/> Which is the same as<br/> <mathjax>#pH+pOH=14#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/400435" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-of-a-solution"> How do you determine ph of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-at-an-equivalence-point"> How do you determine pH at an equivalence point? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-molarity"> How do you determine pH from molarity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-alkalinity-mean"> What does alkalinity mean? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-base"> What is a base? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-acid-base-indicators-change-color"> How do acid base indicators change color? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-neutral-ph"> What is a neutral pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-alkalinity-affect-pool-water"> How does alkalinity affect pool water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ph-important-in-drinking-water"> Why is pH important in drinking water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-ph-of-solution"> How can I calculate the pH of a solution? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/ph-calculations"> See all questions in pH calculations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 38469 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the [#OH^-#] in a solution of pH 3.00?	null
2,139	a9288a02-6ddd-11ea-b29c-ccda262736ce	https://socratic.org/questions/a-student-collects-425-ml-of-oxygen-at-a-temperature-of-24-c-and-a-pressure-of-0	0.02 moles	start physical_unit 6 6 mole mol qc_end physical_unit 6 6 3 4 volume qc_end physical_unit 6 6 11 12 temperature qc_end physical_unit 6 6 17 18 pressure qc_end end	[{"type":"physical unit","value":"Mole [OF] oxygen [IN] moles"}]	[{"type":"physical unit","value":"0.02 moles"}]	[{"type":"physical unit","value":"Volume [OF] oxygen [=] \\pu{425 mL}"},{"type":"physical unit","value":"Temperature [OF] oxygen [=] \\pu{24 ℃}"},{"type":"physical unit","value":"Pressure [OF] oxygen [=] \\pu{0.899 atm}"}]	<h1 class="questionTitle" itemprop="name">A student collects 425 mL of oxygen at a temperature of 24°C and a pressure of 0.899 atm. How many moles of oxygen did the student collect?</h1>	null	0.02 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We solve for <mathjax>#n#</mathjax> in the old Ideal Gas equation...and perforce we use units of <mathjax>#"absolute temperature...."#</mathjax></p> <p><mathjax>#n=(PV)/(RT)=(0.899atmxx425mLxx10^-3LmL^-1)/(0.0821(Latm)/(Kmol)xx297.15K)#</mathjax></p> <p><mathjax>#-=0.0157*mol#</mathjax>...and what mass of dioxygen does this represent?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#n_(O_2)=0.0157mol#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We solve for <mathjax>#n#</mathjax> in the old Ideal Gas equation...and perforce we use units of <mathjax>#"absolute temperature...."#</mathjax></p> <p><mathjax>#n=(PV)/(RT)=(0.899atmxx425mLxx10^-3LmL^-1)/(0.0821(Latm)/(Kmol)xx297.15K)#</mathjax></p> <p><mathjax>#-=0.0157mol#</mathjax>...and what mass of dioxygen does this represent?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A student collects 425 mL of oxygen at a temperature of 24°C and a pressure of 0.899 atm. How many moles of oxygen did the student collect?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="613286" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-05-14T14:41:55" itemprop="dateCreated"> May 14, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#n_(O_2)=0.0157mol#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We solve for <mathjax>#n#</mathjax> in the old Ideal Gas equation...and perforce we use units of <mathjax>#"absolute temperature...."#</mathjax></p> <p><mathjax>#n=(PV)/(RT)=(0.899atmxx425mLxx10^-3LmL^-1)/(0.0821(Latm)/(Kmol)xx297.15K)#</mathjax></p> <p><mathjax>#-=0.0157mol#</mathjax>...and what mass of dioxygen does this represent?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/613286" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? 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How many moles of oxygen did the student collect?	null
2,140	a9b2fac2-6ddd-11ea-afec-ccda262736ce	https://socratic.org/questions/what-is-the-molarity-of-a-2-4-liter-solution-containing-124-grams-of-hf	2.58 M	start physical_unit 13 13 molarity mol/l qc_end physical_unit 8 8 6 7 volume qc_end physical_unit 13 13 10 11 mass qc_end end	[{"type":"physical unit","value":"Molarity [OF] HF solution [IN] M"}]	[{"type":"physical unit","value":"2.58 M"}]	[{"type":"physical unit","value":"Volume [OF] HF solution [=] \\pu{2.4 liter}"},{"type":"physical unit","value":"Mass [OF] HF [=] \\pu{124 grams}"}]	<h1 class="questionTitle" itemprop="name">What is the molarity of a 2.4-liter solution containing 124 grams of HF?</h1>	null	2.58 M	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>By definition, <mathjax>#"molarity"="moles of solute"/"volume of solution"#</mathjax>.</p> <p>And so we take the quotient...<mathjax>#((124g)/(20.01gmol^-1))/(2.40L)=2.58molL^-1#</mathjax>...are the units of concentration correct?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, what is <mathjax>#"molarity"#</mathjax>?</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>By definition, <mathjax>#"molarity"="moles of solute"/"volume of solution"#</mathjax>.</p> <p>And so we take the quotient...<mathjax>#((124g)/(20.01gmol^-1))/(2.40L)=2.58molL^-1#</mathjax>...are the units of concentration correct?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the molarity of a 2.4-liter solution containing 124 grams of HF?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="617930" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-05-22T05:22:46" itemprop="dateCreated"> May 22, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, what is <mathjax>#"molarity"#</mathjax>?</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>By definition, <mathjax>#"molarity"="moles of solute"/"volume of solution"#</mathjax>.</p> <p>And so we take the quotient...<mathjax>#((124g)/(20.01gmol^-1))/(2.40L)=2.58molL^-1#</mathjax>...are the units of concentration correct?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/617930" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="617931" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/junaid-mirza"><img alt="" class="" src="https://profilepictures.socratic.org/BBeNx7NTQ7WmDQKll8wN_BDC9EDF4-5DCB-440D-8ADC-ADACE2966216.jpeg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/junaid-mirza"> Junaid Mirza </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-05-22T05:24:42" itemprop="dateCreated"> May 22, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"2.6 M"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Molar mass of <mathjax>#"HF"#</mathjax> is <mathjax>#"20 g/mol"#</mathjax></p> <p>Moles of <mathjax>#"HF"#</mathjax> in solution is</p> <blockquote> <p><mathjax>#"n" = "124 g"/"20 g/mol" = "6.2 mol"#</mathjax></p> </blockquote> <p><mathjax>#"Molarity" = "Moles of solute"/"Volume of solution (in litres)"#</mathjax></p> <p><mathjax>#"Molarity" = "6.2 mol"/"2.4 L" = "2.6 M"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/617931" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" 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2,141	ac40c268-6ddd-11ea-b9eb-ccda262736ce	https://socratic.org/questions/how-do-you-balance-k2cr2o7-agno3	K2Cr2O7 + AgNO3	start chemical_equation qc_end end	[{"type":"other","value":"Chemical Equation [OF] the equation"}]	[{"type":"chemical equation","value":"K2Cr2O7 + AgNO3"}]	[{"type":"chemical equation","value":"K2Cr2O7 + 2 AgNO3 -> Ag2Cr2O7 + 2 KNO3"}]	<h1 class="questionTitle" itemprop="name">How do you balance K2Cr2O7 + AgNO3? </h1>	null	K2Cr2O7 + AgNO3	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Since you did not put the end product in your question, I'm going to assume that the above equation is true.</p> <p>How do you balance this? There are two ways: (1) you can separately tally each atom or (2) you can use your knowledge of ions.</p> <p>Since it would be much more complicated to do step (1) in this kind of equation, I'm going to go with step 2.</p> <p>First, to avoid confusing yourself, rewrite the equation into this:</p> <p><mathjax>#(2K^"+" + Cr_2O_7^"2-") + (Ag^"+" + NO_3^"-") = Ag_2Cr_2O_7 (s) + (K^"+" + NO_3^"-")#</mathjax></p> <p>Left side: <br/> <mathjax>#K^+#</mathjax> = 2 (based on initial subscript)<br/> <mathjax>#Cr_2O_7^"2-"#</mathjax> = 1 <br/> <mathjax>#Ag^+#</mathjax> = 1<br/> <mathjax>#NO_3^-#</mathjax> = 1</p> <p>Right side:<br/> <mathjax>#K^+#</mathjax> = 1<br/> <mathjax>#Cr_2O_7^"2-"#</mathjax> = 1 <br/> <mathjax>#Ag^+#</mathjax> = 2<br/> <mathjax>#NO_3^-#</mathjax> = 1</p> <p>Notice that the <mathjax>#K^+#</mathjax> and <mathjax>#Ag^+#</mathjax> ions are not balanced. To balance, you need to multiply both ions by 2.</p> <p>Thus,</p> <p>Left side: <br/> <mathjax>#K^+#</mathjax> = <strong>2</strong> <br/> <mathjax>#Cr_2O_7^"2-"#</mathjax> = <strong>1</strong> <br/> <mathjax>#Ag^+#</mathjax> = 1 x 2 = <strong>2</strong><br/> <mathjax>#NO_3^-#</mathjax> = 1 x 2 = <strong>2</strong> </p> <p>Right side:<br/> <mathjax>#K^+#</mathjax> = 1 x 2 = <strong>2</strong><br/> <mathjax>#Cr_2O_7^"2-"#</mathjax> = <strong>1</strong> <br/> <mathjax>#Ag^+#</mathjax> = <strong>2</strong><br/> <mathjax>#NO_3^-#</mathjax> = 1 x 2 = <strong>2</strong></p> <p><mathjax>#(2K^"+" + Cr_2O_7^"2-") + 2(Ag^"+" + 2NO_3^"-") = Ag_2Cr_2O_7 (s) + 2(K^"+" + NO_3^"-")#</mathjax></p> <p>Reverting back to the original form, now you can write the balanced equation as</p> <p><mathjax>#K_2Cr_2O_7 + 2AgNO_3 = Ag_2Cr_2O_7 + 2KNO_3#</mathjax> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#K_2Cr_2O_7 + 2AgNO_3 = Ag_2Cr_2O_7 + 2KNO_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Since you did not put the end product in your question, I'm going to assume that the above equation is true.</p> <p>How do you balance this? There are two ways: (1) you can separately tally each atom or (2) you can use your knowledge of ions.</p> <p>Since it would be much more complicated to do step (1) in this kind of equation, I'm going to go with step 2.</p> <p>First, to avoid confusing yourself, rewrite the equation into this:</p> <p><mathjax>#(2K^"+" + Cr_2O_7^"2-") + (Ag^"+" + NO_3^"-") = Ag_2Cr_2O_7 (s) + (K^"+" + NO_3^"-")#</mathjax></p> <p>Left side: <br/> <mathjax>#K^+#</mathjax> = 2 (based on initial subscript)<br/> <mathjax>#Cr_2O_7^"2-"#</mathjax> = 1 <br/> <mathjax>#Ag^+#</mathjax> = 1<br/> <mathjax>#NO_3^-#</mathjax> = 1</p> <p>Right side:<br/> <mathjax>#K^+#</mathjax> = 1<br/> <mathjax>#Cr_2O_7^"2-"#</mathjax> = 1 <br/> <mathjax>#Ag^+#</mathjax> = 2<br/> <mathjax>#NO_3^-#</mathjax> = 1</p> <p>Notice that the <mathjax>#K^+#</mathjax> and <mathjax>#Ag^+#</mathjax> ions are not balanced. To balance, you need to multiply both ions by 2.</p> <p>Thus,</p> <p>Left side: <br/> <mathjax>#K^+#</mathjax> = <strong>2</strong> <br/> <mathjax>#Cr_2O_7^"2-"#</mathjax> = <strong>1</strong> <br/> <mathjax>#Ag^+#</mathjax> = 1 x 2 = <strong>2</strong><br/> <mathjax>#NO_3^-#</mathjax> = 1 x 2 = <strong>2</strong> </p> <p>Right side:<br/> <mathjax>#K^+#</mathjax> = 1 x 2 = <strong>2</strong><br/> <mathjax>#Cr_2O_7^"2-"#</mathjax> = <strong>1</strong> <br/> <mathjax>#Ag^+#</mathjax> = <strong>2</strong><br/> <mathjax>#NO_3^-#</mathjax> = 1 x 2 = <strong>2</strong></p> <p><mathjax>#(2K^"+" + Cr_2O_7^"2-") + 2(Ag^"+" + 2NO_3^"-") = Ag_2Cr_2O_7 (s) + 2(K^"+" + NO_3^"-")#</mathjax></p> <p>Reverting back to the original form, now you can write the balanced equation as</p> <p><mathjax>#K_2Cr_2O_7 + 2AgNO_3 = Ag_2Cr_2O_7 + 2KNO_3#</mathjax> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you balance K2Cr2O7 + AgNO3? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="179547" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/nikka-c"><img alt="" class="" src="https://profilepictures.socratic.org/AQ8VOCyTM1J7U0TvIWhw_nkahara.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/nikka-c"> Nikka C. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-10-24T09:07:23" itemprop="dateCreated"> Oct 24, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#K_2Cr_2O_7 + 2AgNO_3 = Ag_2Cr_2O_7 + 2KNO_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Since you did not put the end product in your question, I'm going to assume that the above equation is true.</p> <p>How do you balance this? There are two ways: (1) you can separately tally each atom or (2) you can use your knowledge of ions.</p> <p>Since it would be much more complicated to do step (1) in this kind of equation, I'm going to go with step 2.</p> <p>First, to avoid confusing yourself, rewrite the equation into this:</p> <p><mathjax>#(2K^"+" + Cr_2O_7^"2-") + (Ag^"+" + NO_3^"-") = Ag_2Cr_2O_7 (s) + (K^"+" + NO_3^"-")#</mathjax></p> <p>Left side: <br/> <mathjax>#K^+#</mathjax> = 2 (based on initial subscript)<br/> <mathjax>#Cr_2O_7^"2-"#</mathjax> = 1 <br/> <mathjax>#Ag^+#</mathjax> = 1<br/> <mathjax>#NO_3^-#</mathjax> = 1</p> <p>Right side:<br/> <mathjax>#K^+#</mathjax> = 1<br/> <mathjax>#Cr_2O_7^"2-"#</mathjax> = 1 <br/> <mathjax>#Ag^+#</mathjax> = 2<br/> <mathjax>#NO_3^-#</mathjax> = 1</p> <p>Notice that the <mathjax>#K^+#</mathjax> and <mathjax>#Ag^+#</mathjax> ions are not balanced. To balance, you need to multiply both ions by 2.</p> <p>Thus,</p> <p>Left side: <br/> <mathjax>#K^+#</mathjax> = <strong>2</strong> <br/> <mathjax>#Cr_2O_7^"2-"#</mathjax> = <strong>1</strong> <br/> <mathjax>#Ag^+#</mathjax> = 1 x 2 = <strong>2</strong><br/> <mathjax>#NO_3^-#</mathjax> = 1 x 2 = <strong>2</strong> </p> <p>Right side:<br/> <mathjax>#K^+#</mathjax> = 1 x 2 = <strong>2</strong><br/> <mathjax>#Cr_2O_7^"2-"#</mathjax> = <strong>1</strong> <br/> <mathjax>#Ag^+#</mathjax> = <strong>2</strong><br/> <mathjax>#NO_3^-#</mathjax> = 1 x 2 = <strong>2</strong></p> <p><mathjax>#(2K^"+" + Cr_2O_7^"2-") + 2(Ag^"+" + 2NO_3^"-") = Ag_2Cr_2O_7 (s) + 2(K^"+" + NO_3^"-")#</mathjax></p> <p>Reverting back to the original form, now you can write the balanced equation as</p> <p><mathjax>#K_2Cr_2O_7 + 2AgNO_3 = Ag_2Cr_2O_7 + 2KNO_3#</mathjax> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/179547" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------> H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -> Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? 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2,142	ab3eb9f4-6ddd-11ea-9ca5-ccda262736ce	https://socratic.org/questions/a-solution-of-rubbing-alcohol-is-74-3-v-v-isopropanol-in-water-how-many-mililite	46.4 mililiters	start physical_unit 8 8 volume ml qc_end physical_unit 8 10 6 6 volume_percent qc_end physical_unit 23 24 18 19 volume qc_end end	[{"type":"physical unit","value":"Volume [OF] isopropanol [IN] mililiters"}]	[{"type":"physical unit","value":"46.4 mililiters"}]	[{"type":"physical unit","value":"v/v [OF] isopropanol in water [=] \\pu{74.3%}"},{"type":"physical unit","value":"volume [OF] alcohol solution sample [=] \\pu{62.4 mL}"}]	<h1 class="questionTitle" itemprop="name">A solution of rubbing alcohol is 74.3% (v/v) isopropanol in water. How many mililiters of Isopropanol are in 62.4 mL sample of the alcohol solution?</h1>	null	46.4 mililiters	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The trick here is to use the known volume by volume <a href="https://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration</a>, <mathjax>#"v/v%"#</mathjax>, to figure out how many milliliters of isopropanol, the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a>, are present in your sample. </p> <p>Now, the thing to remember about volume by volume percent concentrations is that they are meant to represent the number of milliliters of solute present <strong>for every</strong> <mathjax>#"100 mL"#</mathjax> <strong>of solution</strong>. </p> <p>In your case, the solution contains</p> <blockquote> <p><mathjax>#color(blue)(74.3)color(red)(%)"v/v isopropanol" = color(blue)("74.3 mL")color(white)(.)"isopropanol in" color(white)(.)color(red)("100 mL")color(white)(.)"solution"#</mathjax></p> </blockquote> <p>As you know, <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> are <strong>homogeneous mixture</strong>, which implies that they have the same composition throughout. </p> <p>This means that you can use solution's volume by volume percent concentration to calculate the number of milliliters of isopropanol present in <mathjax>#"62.4 mL"#</mathjax> of solution.</p> <p>Set up the equation as</p> <blockquote> <p><mathjax>#(?color(white)(.)"mL solute")/"62.4 mL solution" = (color(blue)("74.3 mL")color(white)(.)"solute")/(color(red)("100 mL")color(white)(.)"solution")#</mathjax></p> </blockquote> <p>Rearrange and solve to find</p> <blockquote> <p><mathjax>#? = (62.4 color(red)(cancel(color(black)("mL solution"))))/(100color(red)(cancel(color(black)("mL solution")))) * "74.3 mL solute"#</mathjax></p> <p><mathjax>#? = "46.36 mL solute"#</mathjax></p> </blockquote> <p>Rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the answer will be</p> <blockquote> <p><mathjax>#color(darkgreen)(ul(color(black)("volume isopropanol = 46.4 mL")))#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"46.4 mL"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The trick here is to use the known volume by volume <a href="https://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration</a>, <mathjax>#"v/v%"#</mathjax>, to figure out how many milliliters of isopropanol, the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a>, are present in your sample. </p> <p>Now, the thing to remember about volume by volume percent concentrations is that they are meant to represent the number of milliliters of solute present <strong>for every</strong> <mathjax>#"100 mL"#</mathjax> <strong>of solution</strong>. </p> <p>In your case, the solution contains</p> <blockquote> <p><mathjax>#color(blue)(74.3)color(red)(%)"v/v isopropanol" = color(blue)("74.3 mL")color(white)(.)"isopropanol in" color(white)(.)color(red)("100 mL")color(white)(.)"solution"#</mathjax></p> </blockquote> <p>As you know, <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> are <strong>homogeneous mixture</strong>, which implies that they have the same composition throughout. </p> <p>This means that you can use solution's volume by volume percent concentration to calculate the number of milliliters of isopropanol present in <mathjax>#"62.4 mL"#</mathjax> of solution.</p> <p>Set up the equation as</p> <blockquote> <p><mathjax>#(?color(white)(.)"mL solute")/"62.4 mL solution" = (color(blue)("74.3 mL")color(white)(.)"solute")/(color(red)("100 mL")color(white)(.)"solution")#</mathjax></p> </blockquote> <p>Rearrange and solve to find</p> <blockquote> <p><mathjax>#? = (62.4 color(red)(cancel(color(black)("mL solution"))))/(100color(red)(cancel(color(black)("mL solution")))) * "74.3 mL solute"#</mathjax></p> <p><mathjax>#? = "46.36 mL solute"#</mathjax></p> </blockquote> <p>Rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the answer will be</p> <blockquote> <p><mathjax>#color(darkgreen)(ul(color(black)("volume isopropanol = 46.4 mL")))#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A solution of rubbing alcohol is 74.3% (v/v) isopropanol in water. How many mililiters of Isopropanol are in 62.4 mL sample of the alcohol solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/percent-concentration" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Concentration</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="437545" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-10T14:57:51" itemprop="dateCreated"> Jun 10, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"46.4 mL"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The trick here is to use the known volume by volume <a href="https://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration</a>, <mathjax>#"v/v%"#</mathjax>, to figure out how many milliliters of isopropanol, the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a>, are present in your sample. </p> <p>Now, the thing to remember about volume by volume percent concentrations is that they are meant to represent the number of milliliters of solute present <strong>for every</strong> <mathjax>#"100 mL"#</mathjax> <strong>of solution</strong>. </p> <p>In your case, the solution contains</p> <blockquote> <p><mathjax>#color(blue)(74.3)color(red)(%)"v/v isopropanol" = color(blue)("74.3 mL")color(white)(.)"isopropanol in" color(white)(.)color(red)("100 mL")color(white)(.)"solution"#</mathjax></p> </blockquote> <p>As you know, <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> are <strong>homogeneous mixture</strong>, which implies that they have the same composition throughout. </p> <p>This means that you can use solution's volume by volume percent concentration to calculate the number of milliliters of isopropanol present in <mathjax>#"62.4 mL"#</mathjax> of solution.</p> <p>Set up the equation as</p> <blockquote> <p><mathjax>#(?color(white)(.)"mL solute")/"62.4 mL solution" = (color(blue)("74.3 mL")color(white)(.)"solute")/(color(red)("100 mL")color(white)(.)"solution")#</mathjax></p> </blockquote> <p>Rearrange and solve to find</p> <blockquote> <p><mathjax>#? = (62.4 color(red)(cancel(color(black)("mL solution"))))/(100color(red)(cancel(color(black)("mL solution")))) * "74.3 mL solute"#</mathjax></p> <p><mathjax>#? = "46.36 mL solute"#</mathjax></p> </blockquote> <p>Rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the answer will be</p> <blockquote> <p><mathjax>#color(darkgreen)(ul(color(black)("volume isopropanol = 46.4 mL")))#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/437545" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-concentration-of-water-in-solution-be-decreased"> How can the concentration of water in solution be decreased? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-concentration-of-a-solution-be-increased"> How can the concentration of a solution be increased? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-concentration-of-a-solution-in-ppm"> How do you find the concentration of a solution in ppm? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-make-a-10-percent-solution"> How do you make a 10 percent solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-make-a-2-percent-solution"> How do you make a 2 percent solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-weight-per-volume-method-to-calculate-concentration"> What is the weight per volume method to calculate concentration? 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How many mililiters of Isopropanol are in 62.4 mL sample of the alcohol solution?	null
2,143	abeef7ae-6ddd-11ea-bb8c-ccda262736ce	https://socratic.org/questions/how-many-atoms-are-in-1-mole-of-na-3po-4	4.82 × 10^24	start physical_unit 2 2 number none qc_end physical_unit 8 8 5 6 mole qc_end end	[{"type":"physical unit","value":"Number [OF] atoms"}]	[{"type":"physical unit","value":"4.82 × 10^24"}]	[{"type":"physical unit","value":"Mole [OF] Na3PO4 [=] \\pu{1 mole}"}]	<h1 class="questionTitle" itemprop="name">How many atoms are in 1 mole of #Na_3PO_4#?</h1>	null	4.82 × 10^24	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to figure out how many <em>atoms</em> you get <strong>per mole</strong> of sodium triphosphate, <mathjax>#"Na"_3"PO"_4#</mathjax>, you must use the fact that <strong>one mole</strong> of any substance contains <mathjax>#6.022 * 10^(23)#</mathjax> atoms, molecules, or formula units of that substance. </p> <p>This is known as <strong>Avogadro's number</strong>. </p> <p>Since you're dealing with an <strong><a href="http://socratic.org/chemistry/ionic-bonds-and-formulas/ionic-compounds">ionic compound</a></strong>, one mole of sodium triphosphate will contain <mathjax>#6.022 * 10^(23)#</mathjax> formula units of sodium triphosphate. </p> <p><em>Now, how many <strong>atoms</strong> do you get <strong>per formula unit</strong> of sodium triphosphate?</em> </p> <p>As you can see by examining the chemical formula, one formula unit contains</p> <blockquote> <ul> <li><em><strong>three</strong> atoms of sodium</em> <mathjax># -> 3 xx "Na"#</mathjax></li> <li><em><strong>one</strong> atom of phosphorus</em> <mathjax># -> 1 xx "P"#</mathjax></li> <li><em><strong>four</strong> atoms of oxygen</em> <mathjax># -> 4 xx "O"#</mathjax></li> </ul> </blockquote> <p>This means that one formula unit will contain a total of </p> <blockquote> <p><mathjax>#3 xx"Na" + 1 xx "P" + 4 xx "O" = "8 atoms"#</mathjax></p> </blockquote> <p>Therefore, <strong>one mole</strong> of formula units will contain</p> <blockquote> <p><mathjax>#6.022 * 10^(23)color(red)(cancel(color(black)("formula units"))) * "8 atoms"/(1color(red)(cancel(color(black)("formula unit")))) = 4.82 * 10^(24)"atoms"#</mathjax></p> </blockquote> <p>You should round this off to one <strong><a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig fig</a></strong>, the number of sig figs you have in <mathjax>#1#</mathjax> mole, to get</p> <blockquote> <p><mathjax>#"no. of atoms" = color(green)(\| bar(ul(5 * 10^(24)"atoms"))\|)#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#5 * 10^(24)"atoms"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to figure out how many <em>atoms</em> you get <strong>per mole</strong> of sodium triphosphate, <mathjax>#"Na"_3"PO"_4#</mathjax>, you must use the fact that <strong>one mole</strong> of any substance contains <mathjax>#6.022 * 10^(23)#</mathjax> atoms, molecules, or formula units of that substance. </p> <p>This is known as <strong>Avogadro's number</strong>. </p> <p>Since you're dealing with an <strong><a href="http://socratic.org/chemistry/ionic-bonds-and-formulas/ionic-compounds">ionic compound</a></strong>, one mole of sodium triphosphate will contain <mathjax>#6.022 * 10^(23)#</mathjax> formula units of sodium triphosphate. </p> <p><em>Now, how many <strong>atoms</strong> do you get <strong>per formula unit</strong> of sodium triphosphate?</em> </p> <p>As you can see by examining the chemical formula, one formula unit contains</p> <blockquote> <ul> <li><em><strong>three</strong> atoms of sodium</em> <mathjax># -> 3 xx "Na"#</mathjax></li> <li><em><strong>one</strong> atom of phosphorus</em> <mathjax># -> 1 xx "P"#</mathjax></li> <li><em><strong>four</strong> atoms of oxygen</em> <mathjax># -> 4 xx "O"#</mathjax></li> </ul> </blockquote> <p>This means that one formula unit will contain a total of </p> <blockquote> <p><mathjax>#3 xx"Na" + 1 xx "P" + 4 xx "O" = "8 atoms"#</mathjax></p> </blockquote> <p>Therefore, <strong>one mole</strong> of formula units will contain</p> <blockquote> <p><mathjax>#6.022 * 10^(23)color(red)(cancel(color(black)("formula units"))) * "8 atoms"/(1color(red)(cancel(color(black)("formula unit")))) = 4.82 * 10^(24)"atoms"#</mathjax></p> </blockquote> <p>You should round this off to one <strong><a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig fig</a></strong>, the number of sig figs you have in <mathjax>#1#</mathjax> mole, to get</p> <blockquote> <p><mathjax>#"no. of atoms" = color(green)(\| bar(ul(5 * 10^(24)"atoms"))\|)#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many atoms are in 1 mole of #Na_3PO_4#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="235319" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-05T10:52:16" itemprop="dateCreated"> Mar 5, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#5 * 10^(24)"atoms"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to figure out how many <em>atoms</em> you get <strong>per mole</strong> of sodium triphosphate, <mathjax>#"Na"_3"PO"_4#</mathjax>, you must use the fact that <strong>one mole</strong> of any substance contains <mathjax>#6.022 * 10^(23)#</mathjax> atoms, molecules, or formula units of that substance. </p> <p>This is known as <strong>Avogadro's number</strong>. </p> <p>Since you're dealing with an <strong><a href="http://socratic.org/chemistry/ionic-bonds-and-formulas/ionic-compounds">ionic compound</a></strong>, one mole of sodium triphosphate will contain <mathjax>#6.022 * 10^(23)#</mathjax> formula units of sodium triphosphate. </p> <p><em>Now, how many <strong>atoms</strong> do you get <strong>per formula unit</strong> of sodium triphosphate?</em> </p> <p>As you can see by examining the chemical formula, one formula unit contains</p> <blockquote> <ul> <li><em><strong>three</strong> atoms of sodium</em> <mathjax># -> 3 xx "Na"#</mathjax></li> <li><em><strong>one</strong> atom of phosphorus</em> <mathjax># -> 1 xx "P"#</mathjax></li> <li><em><strong>four</strong> atoms of oxygen</em> <mathjax># -> 4 xx "O"#</mathjax></li> </ul> </blockquote> <p>This means that one formula unit will contain a total of </p> <blockquote> <p><mathjax>#3 xx"Na" + 1 xx "P" + 4 xx "O" = "8 atoms"#</mathjax></p> </blockquote> <p>Therefore, <strong>one mole</strong> of formula units will contain</p> <blockquote> <p><mathjax>#6.022 * 10^(23)color(red)(cancel(color(black)("formula units"))) * "8 atoms"/(1color(red)(cancel(color(black)("formula unit")))) = 4.82 * 10^(24)"atoms"#</mathjax></p> </blockquote> <p>You should round this off to one <strong><a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig fig</a></strong>, the number of sig figs you have in <mathjax>#1#</mathjax> mole, to get</p> <blockquote> <p><mathjax>#"no. of atoms" = color(green)(\| bar(ul(5 * 10^(24)"atoms"))\|)#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/235319" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c 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How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 18505 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many atoms are in 1 mole of #Na_3PO_4#?	null
2,144	ab5b36fa-6ddd-11ea-99fd-ccda262736ce	https://socratic.org/questions/a-breathing-mixture-used-by-deep-sea-divers-contains-helium-oxygen-and-carbon-di	18.50 kPa	start physical_unit 9 9 partial_pressure kpa qc_end physical_unit 1 2 21 22 total_pressure qc_end end	[{"type":"physical unit","value":"Partial Pressure [OF] oxygen [IN] kPa"}]	[{"type":"physical unit","value":"18.50 kPa"}]	[{"type":"physical unit","value":"Total pressure [OF] the breathing mixture [=] \\pu{101.4 kPa}"},{"type":"physical unit","value":"Partial Pressure [OF] He [=] \\pu{82.5 kPa}"},{"type":"physical unit","value":"Partial Pressure [OF] CO2 [=] \\pu{0.4 kPa}"}]	<h1 class="questionTitle" itemprop="name">A breathing mixture used by deep-sea divers contains helium, oxygen, and carbon dioxide What is the partial pressure of oxygen at #101.4# #kPa# if #P_(He)# = #82.5# #kPa# and #P_(CO2)# = #.4# #kPa#?</h1>	null	18.50 kPa	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The total pressure is the sum of the partial pressures of the given gases.</p> <p><mathjax>#P_"Total"=P_"He"+P_"CO2"+P_"O2"#</mathjax></p> <p>Rearrange the equation to isolate <mathjax>#P_"O2"#</mathjax>, substitute the given values into the equation and solve.</p> <p><mathjax>#P_"O2"=P_"Total"-(P_"He"+P_"CO2")#</mathjax></p> <p><mathjax>#P_"O2"=101.4"kPa"+(82.5"kPa"+0.4"kPa")#</mathjax></p> <p><mathjax>#P_"O2"=18.5"kPa"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The <a href="http://socratic.org/chemistry/the-behavior-of-gases/partial-pressure">partial pressure</a> of oxygen in the mixture is 18.5 kPa.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The total pressure is the sum of the partial pressures of the given gases.</p> <p><mathjax>#P_"Total"=P_"He"+P_"CO2"+P_"O2"#</mathjax></p> <p>Rearrange the equation to isolate <mathjax>#P_"O2"#</mathjax>, substitute the given values into the equation and solve.</p> <p><mathjax>#P_"O2"=P_"Total"-(P_"He"+P_"CO2")#</mathjax></p> <p><mathjax>#P_"O2"=101.4"kPa"+(82.5"kPa"+0.4"kPa")#</mathjax></p> <p><mathjax>#P_"O2"=18.5"kPa"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A breathing mixture used by deep-sea divers contains helium, oxygen, and carbon dioxide What is the partial pressure of oxygen at #101.4# #kPa# if #P_(He)# = #82.5# #kPa# and #P_(CO2)# = #.4# #kPa#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/partial-pressure" itemprop="url"> <span class="breadcrumb" itemprop="title">Partial Pressure</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="229523" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-02-22T01:43:51" itemprop="dateCreated"> Feb 22, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The <a href="http://socratic.org/chemistry/the-behavior-of-gases/partial-pressure">partial pressure</a> of oxygen in the mixture is 18.5 kPa.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The total pressure is the sum of the partial pressures of the given gases.</p> <p><mathjax>#P_"Total"=P_"He"+P_"CO2"+P_"O2"#</mathjax></p> <p>Rearrange the equation to isolate <mathjax>#P_"O2"#</mathjax>, substitute the given values into the equation and solve.</p> <p><mathjax>#P_"O2"=P_"Total"-(P_"He"+P_"CO2")#</mathjax></p> <p><mathjax>#P_"O2"=101.4"kPa"+(82.5"kPa"+0.4"kPa")#</mathjax></p> <p><mathjax>#P_"O2"=18.5"kPa"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/229523" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="229524" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/david-g-6"><img alt="" class="" src="https://graph.facebook.com/10153408096237887/picture?height=50&width=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/david-g-6"> David G. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-02-22T01:45:29" itemprop="dateCreated"> Feb 22, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The total pressure of <mathjax>#101.4#</mathjax> <mathjax>#kPa#</mathjax> is made up of the sum of the partial pressures of the three gases, so <mathjax>#P_(O2)=101.4-82.5-0.4=18.5#</mathjax> <mathjax>#kPa#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In a little more detail, the total pressure is the sum of the partial pressures of the gases present:</p> <p><mathjax>#P_("tot")=P_(O2)+P_(He)+P_(CO2)#</mathjax></p> <p>We want to know the <a href="http://socratic.org/chemistry/the-behavior-of-gases/partial-pressure">partial pressure</a> of oxygen, <mathjax>#P_(O2)#</mathjax>, so we rearrange:</p> <p><mathjax>#P_(O2)=P_("tot")-P_(He)-P_(CO2)#</mathjax></p> <p>Substituting in the known values gives the answer shown above.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/229524" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/534e256802bf342adfa30010"> How do you do a steam distillation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/53613f9f02bf3416cd9f8a34"> Question #f8a34 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-i-calculate-the-total-pressure-of-a-mixture-of-gases-by-adding-together-the-"> Can I calculate the total pressure of a mixture of gases by adding together the partial... </a> </div> </li> <li 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2,145	abb054fe-6ddd-11ea-84b7-ccda262736ce	https://socratic.org/questions/a-gas-a-volume-of-2-50-l-at-a-pressure-of-of-350-0-kpa-if-the-temperature-remain	0.50 L	start physical_unit 22 23 volume l qc_end physical_unit 22 23 5 6 volume qc_end physical_unit 22 23 12 13 pressure qc_end c_other constant_temperature qc_end physical_unit 22 23 26 27 pressure qc_end end	[{"type":"physical unit","value":"Volume2 [OF] the gas [IN] L"}]	[{"type":"physical unit","value":"0.50 L"}]	[{"type":"physical unit","value":"Volume1 [OF] the gas [=] \\pu{2.50 L}"},{"type":"physical unit","value":"Pressure1 [OF] the gas [=] \\pu{350.0 kPa}"},{"type":"other","value":"ConstantTemperature"},{"type":"physical unit","value":"Pressure2 [OF] the gas [=] \\pu{1750 kPa}"}]	<h1 class="questionTitle" itemprop="name">A gas a volume of 2.50 L at a pressure of of 350.0 kPa. If the temperature remains constant, what volume would the gas occupy at 1750 kPa?</h1>	null	0.50 L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is an example of <a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's law</a>, which states that at constant temperature and mass, the volume of a gas will vary inversely with the pressure. The equation to use for solving your question is <mathjax>#P_1V_1=P_2V_2#</mathjax>, where <mathjax>#P_1#</mathjax> is initial pressure, <mathjax>#V_1#</mathjax> is initial volume, <mathjax>#P_2#</mathjax> is the final pressure, and <mathjax>#V#</mathjax> is the final volume.</p> <p><strong>Known</strong><br/> <mathjax>#P_1="350.0 kPa"#</mathjax><br/> <mathjax>#V_1="2.50 L"#</mathjax><br/> <mathjax>#P_2="1750 kPa"#</mathjax></p> <p><strong>Unknown</strong><br/> <mathjax>#V_2="???"#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#V_2#</mathjax>. Substitute the known values into the equation and solve.</p> <p><mathjax>#P_1V_1=P_2V_2#</mathjax></p> <p><mathjax>#V_2=(P_1V_1)/P_2#</mathjax></p> <p><mathjax>#V_2=(350.0cancel"kPa"xx2.50"L")/(1750 cancel"kPa")="0.500 L"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The new volume of the gas is <mathjax>#"0.500 L"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is an example of <a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's law</a>, which states that at constant temperature and mass, the volume of a gas will vary inversely with the pressure. The equation to use for solving your question is <mathjax>#P_1V_1=P_2V_2#</mathjax>, where <mathjax>#P_1#</mathjax> is initial pressure, <mathjax>#V_1#</mathjax> is initial volume, <mathjax>#P_2#</mathjax> is the final pressure, and <mathjax>#V#</mathjax> is the final volume.</p> <p><strong>Known</strong><br/> <mathjax>#P_1="350.0 kPa"#</mathjax><br/> <mathjax>#V_1="2.50 L"#</mathjax><br/> <mathjax>#P_2="1750 kPa"#</mathjax></p> <p><strong>Unknown</strong><br/> <mathjax>#V_2="???"#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#V_2#</mathjax>. Substitute the known values into the equation and solve.</p> <p><mathjax>#P_1V_1=P_2V_2#</mathjax></p> <p><mathjax>#V_2=(P_1V_1)/P_2#</mathjax></p> <p><mathjax>#V_2=(350.0cancel"kPa"xx2.50"L")/(1750 cancel"kPa")="0.500 L"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A gas a volume of 2.50 L at a pressure of of 350.0 kPa. If the temperature remains constant, what volume would the gas occupy at 1750 kPa?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/boyle-s-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Boyle's Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="261424" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-02T18:56:04" itemprop="dateCreated"> May 2, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The new volume of the gas is <mathjax>#"0.500 L"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is an example of <a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's law</a>, which states that at constant temperature and mass, the volume of a gas will vary inversely with the pressure. The equation to use for solving your question is <mathjax>#P_1V_1=P_2V_2#</mathjax>, where <mathjax>#P_1#</mathjax> is initial pressure, <mathjax>#V_1#</mathjax> is initial volume, <mathjax>#P_2#</mathjax> is the final pressure, and <mathjax>#V#</mathjax> is the final volume.</p> <p><strong>Known</strong><br/> <mathjax>#P_1="350.0 kPa"#</mathjax><br/> <mathjax>#V_1="2.50 L"#</mathjax><br/> <mathjax>#P_2="1750 kPa"#</mathjax></p> <p><strong>Unknown</strong><br/> <mathjax>#V_2="???"#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#V_2#</mathjax>. Substitute the known values into the equation and solve.</p> <p><mathjax>#P_1V_1=P_2V_2#</mathjax></p> <p><mathjax>#V_2=(P_1V_1)/P_2#</mathjax></p> <p><mathjax>#V_2=(350.0cancel"kPa"xx2.50"L")/(1750 cancel"kPa")="0.500 L"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/261424" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-graph-boyles-law"> How do you graph Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-functional-groups-are-found-in-lipids"> What functional groups are found in lipids? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-k-constant-in-boyle-s-law"> Why is k constant in Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-boyle-s-law-graph-curved-1"> Why is Boyle's law graph curved? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-boyle-s-law-an-inverse-relationship-2"> Why is Boyle's law an inverse relationship? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-40-0-l-tank-of-ammonia-has-a-pressure-of-8-00-atm-calculate-the-volume-of-the-"> A 40.0 L tank of ammonia has a pressure of 8.00 atm. Calculate the volume of the ammonia if its... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-charles-law-different-from-boyle-s-law"> How is Charles' law different from Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-boyle-s-law-written-mathematically"> How is Boyle's law written mathematically? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-temperature-affect-boyle-s-law"> How does temperature affect Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-boyle-s-law-relate-to-ventilation"> How does Boyle's law relate to ventilation? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/boyle-s-law"> See all questions in Boyle's Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 4161 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A gas a volume of 2.50 L at a pressure of of 350.0 kPa. If the temperature remains constant, what volume would the gas occupy at 1750 kPa?	null
2,146	ac0bc970-6ddd-11ea-aa17-ccda262736ce	https://socratic.org/questions/how-many-moles-of-oxygen-are-in-a-5-5-l-canister-at-stp	0.25 moles	start physical_unit 4 4 mole mol qc_end physical_unit 4 4 8 9 volume qc_end c_other STP qc_end end	[{"type":"physical unit","value":"Mole [OF] oxygen [IN] moles"}]	[{"type":"physical unit","value":"0.25 moles"}]	[{"type":"physical unit","value":"Volume [OF] oxygen [=] \\pu{5.5 L}"},{"type":"other","value":"STP"}]	<h1 class="questionTitle" itemprop="name">How many moles of oxygen are in a 5.5-L canister at STP? </h1>	null	0.25 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We are at STP, so we have to use the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law equation</a>.<br/> <mathjax>#PxxV = nxxRxxT#</mathjax>. </p> <ul> <li>P represents pressure (could have units of atm, depending on the units of the universal gas constant)</li> <li>V represents volume (must have units of liters)</li> <li>n represents the number of moles</li> <li>R is the universal gas constant (has units of <mathjax>#(Lxxatm)/ (molxxK)#</mathjax>)</li> <li>T represents the temperature, which must be in Kelvins.</li> </ul> <p>Next, list your known and unknown variables. Our only unknown is the number of moles of <mathjax>#O_2(g)#</mathjax>. Our known variables are P,V,R, and T. </p> <p>At STP, the temperature is 273K and the pressure is 1 atm. The proportionality constant, R, is equal to 0.0821 <mathjax>#(Lxxatm)/ (molxxK)#</mathjax></p> <p>Now we have to rearrange the equation to solve for n:</p> <p><mathjax># n = (PV)/(RT)#</mathjax></p> <p><mathjax>#n = (1cancel"atm"xx5.5cancelL)/(0.0821(cancel"Lxxatm")/(molxxcancel"K")xx273cancel"K"#</mathjax><br/> <mathjax>#n = 0.25mol#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>There are <mathjax>#0.25mol#</mathjax> of <mathjax>#O_2#</mathjax> in the 5.5-L canister.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We are at STP, so we have to use the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law equation</a>.<br/> <mathjax>#PxxV = nxxRxxT#</mathjax>. </p> <ul> <li>P represents pressure (could have units of atm, depending on the units of the universal gas constant)</li> <li>V represents volume (must have units of liters)</li> <li>n represents the number of moles</li> <li>R is the universal gas constant (has units of <mathjax>#(Lxxatm)/ (molxxK)#</mathjax>)</li> <li>T represents the temperature, which must be in Kelvins.</li> </ul> <p>Next, list your known and unknown variables. Our only unknown is the number of moles of <mathjax>#O_2(g)#</mathjax>. Our known variables are P,V,R, and T. </p> <p>At STP, the temperature is 273K and the pressure is 1 atm. The proportionality constant, R, is equal to 0.0821 <mathjax>#(Lxxatm)/ (molxxK)#</mathjax></p> <p>Now we have to rearrange the equation to solve for n:</p> <p><mathjax># n = (PV)/(RT)#</mathjax></p> <p><mathjax>#n = (1cancel"atm"xx5.5cancelL)/(0.0821(cancel"Lxxatm")/(molxxcancel"K")xx273cancel"K"#</mathjax><br/> <mathjax>#n = 0.25mol#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles of oxygen are in a 5.5-L canister at STP? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp" itemprop="url"> <span class="breadcrumb" itemprop="title">Molar Volume of a Gas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="280684" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/kayla-14"><img alt="" class="" src="https://profilepictures.socratic.org/OvMTWaamQPWcqLIkUNnG_793604964071127.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/kayla-14"> Kayla </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-24T00:31:25" itemprop="dateCreated"> Jun 24, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>There are <mathjax>#0.25mol#</mathjax> of <mathjax>#O_2#</mathjax> in the 5.5-L canister.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We are at STP, so we have to use the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law equation</a>.<br/> <mathjax>#PxxV = nxxRxxT#</mathjax>. </p> <ul> <li>P represents pressure (could have units of atm, depending on the units of the universal gas constant)</li> <li>V represents volume (must have units of liters)</li> <li>n represents the number of moles</li> <li>R is the universal gas constant (has units of <mathjax>#(Lxxatm)/ (molxxK)#</mathjax>)</li> <li>T represents the temperature, which must be in Kelvins.</li> </ul> <p>Next, list your known and unknown variables. Our only unknown is the number of moles of <mathjax>#O_2(g)#</mathjax>. Our known variables are P,V,R, and T. </p> <p>At STP, the temperature is 273K and the pressure is 1 atm. The proportionality constant, R, is equal to 0.0821 <mathjax>#(Lxxatm)/ (molxxK)#</mathjax></p> <p>Now we have to rearrange the equation to solve for n:</p> <p><mathjax># n = (PV)/(RT)#</mathjax></p> <p><mathjax>#n = (1cancel"atm"xx5.5cancelL)/(0.0821(cancel"Lxxatm")/(molxxcancel"K")xx273cancel"K"#</mathjax><br/> <mathjax>#n = 0.25mol#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/280684" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-stoichiometric-ratios-relate-to-molar-volume-of-a-gas"> How do stoichiometric ratios relate to molar volume of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-a-gas-at-stp"> How do you calculate molar volume of a gas at STP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-molar-volume-of-hydrogen-gas"> How do you find the molar volume of hydrogen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-oxygen-gas"> How do you calculate molar volume of oxygen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molar-gas-volume"> What is molar gas volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/534c7bf202bf3420a007f014"> What is the volume at 0 °C and 1 atm of a mixture that contains 4.0 g of methane and 2.0 g of helium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5361f75702bf3429040e0599"> What is the difference between STP and NTP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-volume-of-25-moles-of-oxygen-o2-gas"> What is the volume of .25 moles of oxygen (O2) Gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-would-knowing-the-molar-volume-of-a-gas-be-important"> Why would knowing the molar volume of a gas be important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-22-4-liters-called-the-molar-volume-of-a-gas"> Why is 22.4 liters called the molar volume of a gas? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp"> See all questions in Molar Volume of a Gas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 7596 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many moles of oxygen are in a 5.5-L canister at STP?	null
2,147	ac1d5f92-6ddd-11ea-a740-ccda262736ce	https://socratic.org/questions/how-many-grams-of-na-l-are-produced-per-litre-of-n2-g-formed-in-the-decompositio	0.62 grams	start physical_unit 4 4 mass g qc_end chemical_equation 18 18 qc_end end	[{"type":"physical unit","value":"Mass [OF] Na(l) [IN] grams"}]	[{"type":"physical unit","value":"0.62 grams"}]	[{"type":"physical unit","value":"Volume [OF] N2(g) [=] \\pu{1 litre}"},{"type":"physical unit","value":"Temperature [OF] the reaction [=] \\pu{25 degrees celsius}"},{"type":"physical unit","value":"Pressure [OF] the reaction [=] \\pu{1.0 bar}"},{"type":"physical unit","value":"Pressure [OF] the reaction [=] \\pu{0.98692 atm}"},{"type":"physical unit","value":"R constant [OF] substance [=] \\pu{0.08206 (L * atm)/(K * mol)}"},{"type":"chemical equation","value":"NaN3"}]	<h1 class="questionTitle" itemprop="name">How many grams of Na(l) are produced per litre of N2(g) formed in the decomposition of sodium azide, NaN3 if the gas is collected at 25 degrees celsius and 1.0 bar (.98692 atm)? The R constant is 0.08206 Latm/Kmol</h1>	null	0.62 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>We aren’t given the amount of <mathjax>#"NaN_3"#</mathjax>, so let's assume that we have 1 mol of <mathjax>#"NaN"_3#</mathjax>.</p> <blockquote></blockquote> <p>There are six steps involved in this problem:</p> <ol> <li>Write the <strong>balanced equation</strong> for the reaction.</li> <li>Use the <strong>molar ratio</strong> of <mathjax>#"Na":"NaN"_3#</mathjax> from the balanced equation to calculate the moles of <mathjax>#"Na"#</mathjax>.</li> <li>Use the molar mass of <mathjax>#"Na"#</mathjax> to calculate the mass of <mathjax>#"Na"#</mathjax>.</li> <li>Use the <strong>molar ratio</strong> of <mathjax>#"N"_2:"NaN"_3#</mathjax> from the balanced equation to calculate the moles of <mathjax>#"N"_2#</mathjax>.</li> <li>Use the <strong><a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a></strong> to calculate the volume of <mathjax>#"N"_2#</mathjax>.</li> <li>Calculate the mass of <mathjax>#"Na"#</mathjax> per litre of <mathjax>#"N"_2#</mathjax>.</li> </ol> <blockquote></blockquote> <p>Let's get started.</p> <blockquote></blockquote> <p><strong>Step 1. Write the balanced chemical equation.</strong></p> <p><mathjax>#"2NaN"_3 → "2Na" + "3N"_2#</mathjax></p> <blockquote></blockquote> <p><strong>2. Calculate the moles of <mathjax>#"Na"#</mathjax></strong></p> <p><mathjax>#"moles of Na" = 1 color(red)(cancel(color(black)("mol NaN"_3))) × "2 mol Na"/(2 color(red)(cancel(color(black)("mol NaN"_3)))) = "1 mol Na"#</mathjax></p> <blockquote></blockquote> <p><strong>3. Calculate the mass of <mathjax>#"Na"#</mathjax>.</strong></p> <p><mathjax>#"mass of Na" = 1 color(red)(cancel(color(black)("mol Na"))) × "22.99 g Na"/(1 color(red)(cancel(color(black)("mol Na")))) = "22.99 g Na"#</mathjax></p> <blockquote></blockquote> <p><strong>4. Calculate the moles of <mathjax>#"N"_2#</mathjax>.</strong> </p> <p><mathjax>#"moles of N"_2 = 1 color(red)(cancel(color(black)("mol NaN"_3))) × ("3 mol N"_2)/(2 color(red)(cancel(color(black)("mol NaN"_3)))) = "1.5 mol N"_2#</mathjax></p> <blockquote></blockquote> <p><strong>5. Calculate the volume of <mathjax>#"N"_2#</mathjax>.</strong></p> <p>The <strong>Ideal Gas Law</strong> is</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(PV = nRT)\|)#</mathjax></p> </blockquote> </blockquote> <p><mathjax>#P = "1 bar" = "0.986 92 atm"#</mathjax><br/> <mathjax>#n= "1.5 mol"#</mathjax><br/> <mathjax>#R = "0.082 06 L·atm·K"^"-1""mol"^"-1"#</mathjax><br/> <mathjax>#T = "25 °C = 298.15 K"#</mathjax></p> <p>We can rearrange the Ideal Gas Law to get:</p> <p><mathjax>#V = (nRT)/P = (1.5 color(red)(cancel(color(black)("mol"))) × "0.082 06 L·"color(red)(cancel(color(black)("atm·K"^"-1""mol"^"-1"))) × 298.15 color(red)(cancel(color(black)("K"))))/("0.986 92" color(red)(cancel(color(black)("atm")))) = "37.19 L"#</mathjax></p> <blockquote></blockquote> <p><strong>5. Calculate the <mathjax>#"Na:N"_2#</mathjax> ratio.</strong></p> <p><mathjax>#"Na"/"N"_2 = "22.99 g Na"/("37.19 L N"_2) = "0.618 g Na"//"L N"_2#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The reaction produces <mathjax>#"0.618 g Na"//"L N"_2#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>We aren’t given the amount of <mathjax>#"NaN_3"#</mathjax>, so let's assume that we have 1 mol of <mathjax>#"NaN"_3#</mathjax>.</p> <blockquote></blockquote> <p>There are six steps involved in this problem:</p> <ol> <li>Write the <strong>balanced equation</strong> for the reaction.</li> <li>Use the <strong>molar ratio</strong> of <mathjax>#"Na":"NaN"_3#</mathjax> from the balanced equation to calculate the moles of <mathjax>#"Na"#</mathjax>.</li> <li>Use the molar mass of <mathjax>#"Na"#</mathjax> to calculate the mass of <mathjax>#"Na"#</mathjax>.</li> <li>Use the <strong>molar ratio</strong> of <mathjax>#"N"_2:"NaN"_3#</mathjax> from the balanced equation to calculate the moles of <mathjax>#"N"_2#</mathjax>.</li> <li>Use the <strong><a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a></strong> to calculate the volume of <mathjax>#"N"_2#</mathjax>.</li> <li>Calculate the mass of <mathjax>#"Na"#</mathjax> per litre of <mathjax>#"N"_2#</mathjax>.</li> </ol> <blockquote></blockquote> <p>Let's get started.</p> <blockquote></blockquote> <p><strong>Step 1. Write the balanced chemical equation.</strong></p> <p><mathjax>#"2NaN"_3 → "2Na" + "3N"_2#</mathjax></p> <blockquote></blockquote> <p><strong>2. Calculate the moles of <mathjax>#"Na"#</mathjax></strong></p> <p><mathjax>#"moles of Na" = 1 color(red)(cancel(color(black)("mol NaN"_3))) × "2 mol Na"/(2 color(red)(cancel(color(black)("mol NaN"_3)))) = "1 mol Na"#</mathjax></p> <blockquote></blockquote> <p><strong>3. Calculate the mass of <mathjax>#"Na"#</mathjax>.</strong></p> <p><mathjax>#"mass of Na" = 1 color(red)(cancel(color(black)("mol Na"))) × "22.99 g Na"/(1 color(red)(cancel(color(black)("mol Na")))) = "22.99 g Na"#</mathjax></p> <blockquote></blockquote> <p><strong>4. Calculate the moles of <mathjax>#"N"_2#</mathjax>.</strong> </p> <p><mathjax>#"moles of N"_2 = 1 color(red)(cancel(color(black)("mol NaN"_3))) × ("3 mol N"_2)/(2 color(red)(cancel(color(black)("mol NaN"_3)))) = "1.5 mol N"_2#</mathjax></p> <blockquote></blockquote> <p><strong>5. Calculate the volume of <mathjax>#"N"_2#</mathjax>.</strong></p> <p>The <strong>Ideal Gas Law</strong> is</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(PV = nRT)\|)#</mathjax></p> </blockquote> </blockquote> <p><mathjax>#P = "1 bar" = "0.986 92 atm"#</mathjax><br/> <mathjax>#n= "1.5 mol"#</mathjax><br/> <mathjax>#R = "0.082 06 L·atm·K"^"-1""mol"^"-1"#</mathjax><br/> <mathjax>#T = "25 °C = 298.15 K"#</mathjax></p> <p>We can rearrange the Ideal Gas Law to get:</p> <p><mathjax>#V = (nRT)/P = (1.5 color(red)(cancel(color(black)("mol"))) × "0.082 06 L·"color(red)(cancel(color(black)("atm·K"^"-1""mol"^"-1"))) × 298.15 color(red)(cancel(color(black)("K"))))/("0.986 92" color(red)(cancel(color(black)("atm")))) = "37.19 L"#</mathjax></p> <blockquote></blockquote> <p><strong>5. Calculate the <mathjax>#"Na:N"_2#</mathjax> ratio.</strong></p> <p><mathjax>#"Na"/"N"_2 = "22.99 g Na"/("37.19 L N"_2) = "0.618 g Na"//"L N"_2#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many grams of Na(l) are produced per litre of N2(g) formed in the decomposition of sodium azide, NaN3 if the gas is collected at 25 degrees celsius and 1.0 bar (.98692 atm)? The R constant is 0.08206 Latm/Kmol</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/stoichiometry-involving-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="245610" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-27T00:44:10" itemprop="dateCreated"> Mar 27, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The reaction produces <mathjax>#"0.618 g Na"//"L N"_2#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>We aren’t given the amount of <mathjax>#"NaN_3"#</mathjax>, so let's assume that we have 1 mol of <mathjax>#"NaN"_3#</mathjax>.</p> <blockquote></blockquote> <p>There are six steps involved in this problem:</p> <ol> <li>Write the <strong>balanced equation</strong> for the reaction.</li> <li>Use the <strong>molar ratio</strong> of <mathjax>#"Na":"NaN"_3#</mathjax> from the balanced equation to calculate the moles of <mathjax>#"Na"#</mathjax>.</li> <li>Use the molar mass of <mathjax>#"Na"#</mathjax> to calculate the mass of <mathjax>#"Na"#</mathjax>.</li> <li>Use the <strong>molar ratio</strong> of <mathjax>#"N"_2:"NaN"_3#</mathjax> from the balanced equation to calculate the moles of <mathjax>#"N"_2#</mathjax>.</li> <li>Use the <strong><a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a></strong> to calculate the volume of <mathjax>#"N"_2#</mathjax>.</li> <li>Calculate the mass of <mathjax>#"Na"#</mathjax> per litre of <mathjax>#"N"_2#</mathjax>.</li> </ol> <blockquote></blockquote> <p>Let's get started.</p> <blockquote></blockquote> <p><strong>Step 1. Write the balanced chemical equation.</strong></p> <p><mathjax>#"2NaN"_3 → "2Na" + "3N"_2#</mathjax></p> <blockquote></blockquote> <p><strong>2. Calculate the moles of <mathjax>#"Na"#</mathjax></strong></p> <p><mathjax>#"moles of Na" = 1 color(red)(cancel(color(black)("mol NaN"_3))) × "2 mol Na"/(2 color(red)(cancel(color(black)("mol NaN"_3)))) = "1 mol Na"#</mathjax></p> <blockquote></blockquote> <p><strong>3. Calculate the mass of <mathjax>#"Na"#</mathjax>.</strong></p> <p><mathjax>#"mass of Na" = 1 color(red)(cancel(color(black)("mol Na"))) × "22.99 g Na"/(1 color(red)(cancel(color(black)("mol Na")))) = "22.99 g Na"#</mathjax></p> <blockquote></blockquote> <p><strong>4. Calculate the moles of <mathjax>#"N"_2#</mathjax>.</strong> </p> <p><mathjax>#"moles of N"_2 = 1 color(red)(cancel(color(black)("mol NaN"_3))) × ("3 mol N"_2)/(2 color(red)(cancel(color(black)("mol NaN"_3)))) = "1.5 mol N"_2#</mathjax></p> <blockquote></blockquote> <p><strong>5. Calculate the volume of <mathjax>#"N"_2#</mathjax>.</strong></p> <p>The <strong>Ideal Gas Law</strong> is</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(PV = nRT)\|)#</mathjax></p> </blockquote> </blockquote> <p><mathjax>#P = "1 bar" = "0.986 92 atm"#</mathjax><br/> <mathjax>#n= "1.5 mol"#</mathjax><br/> <mathjax>#R = "0.082 06 L·atm·K"^"-1""mol"^"-1"#</mathjax><br/> <mathjax>#T = "25 °C = 298.15 K"#</mathjax></p> <p>We can rearrange the Ideal Gas Law to get:</p> <p><mathjax>#V = (nRT)/P = (1.5 color(red)(cancel(color(black)("mol"))) × "0.082 06 L·"color(red)(cancel(color(black)("atm·K"^"-1""mol"^"-1"))) × 298.15 color(red)(cancel(color(black)("K"))))/("0.986 92" color(red)(cancel(color(black)("atm")))) = "37.19 L"#</mathjax></p> <blockquote></blockquote> <p><strong>5. Calculate the <mathjax>#"Na:N"_2#</mathjax> ratio.</strong></p> <p><mathjax>#"Na"/"N"_2 = "22.99 g Na"/("37.19 L N"_2) = "0.618 g Na"//"L N"_2#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/245610" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-apply-gas-stoichiometry"> How do you apply gas stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-solve-a-gas-law-stoichiometry-problem"> How do you solve a gas law stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-do-gas-stoichiometry-problems-at-stp"> How do you do gas stoichiometry problems at STP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-an-agno3-solution-is-treated-with-50-0-ml-of-hi-gas-to-give-0-235-g-of-agi-"> When an AgNO3 solution is treated with 50.0 mL of HI gas to give 0.235 g of AgI, what is the... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-10-0-ml-of-agno3-solution-is-treated-with-excess-amount-of-hi-gas-to-give-0"> When 10.0 mL of AgNO3 solution is treated with excess amount of HI gas to give 0.235 g of AgI,... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/hydrogen-sulfide-reacts-with-sulfur-dioxide-to-give-h2o-and-s-h2s-so2-h2o-s-soli"> Hydrogen sulfide reacts with sulfur dioxide to give H2O and S, H2S + SO2 = H2O + S(solid),... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-100-ml-of-hcl-gas-at-300-k-and-200-kpa-dissolved-in-pure-water-requires-12-50"> If 100 mL of HCl gas at 300 K and 200 kPa dissolved in pure water requires 12.50 mL of the NaOH... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-100-ml-of-hcl-gas-at-300-k-and-100-kpa-dissolved-in-pure-water-requires-12-50"> If 100 mL of HCl gas at 300 K and 100 kPa dissolved in pure water requires 12.50 mL of the NaOH... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-100-ml-of-hcl-gas-at-300-k-and-100-kpa-dissolve-in-20-ml-of-pure-water-what-i"> If 100 mL of HCl gas at 300 K and 100 kPa dissolve in 20 mL of pure water, what is the concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-2-00-g-mixture-of-na-and-ca-reat-with-water-1-164-l-hydrogen-was-produced-a"> When 2.00 g mixture of Na and Ca reat with water, 1.164 L hydrogen was produced at 300.0 K and... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/stoichiometry-involving-gases"> See all questions in Gas Stoichiometry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 11091 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many grams of Na(l) are produced per litre of N2(g) formed in the decomposition of sodium azide, NaN3 if the gas is collected at 25 degrees celsius and 1.0 bar (.98692 atm)? The R constant is 0.08206 Latm/Kmol	null
2,148	ace3d8d0-6ddd-11ea-bd70-ccda262736ce	https://socratic.org/questions/57ffa1fb11ef6b0f6f4d3fa2	-1	start physical_unit 6 6 oxidation_number none qc_end chemical_equation 10 10 qc_end end	[{"type":"physical unit","value":"Oxidation number [OF] oxygen"}]	[{"type":"physical unit","value":"-1"}]	[{"type":"chemical equation","value":"Na2O2"}]	<h1 class="questionTitle" itemprop="name">What is the oxidation number of oxygen in #"sodium peroxide"#, #Na_2O_2#?</h1>	null	-1	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>When we assign <a href="https://socratic.org/chemistry/electrochemistry/oxidation-numbers">oxidation numbers</a>, we assign conceptual charges to the individual atoms such that when these charges are summed up we get the charge on the molecule or the ion. Thus, <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> have an oxidation number of <mathjax>#0#</mathjax>, because they are assumed not to have donated or accepted electrons (the which process defines oxidation and reduction respectively).</p> <p>For your sodium peroxide we have <mathjax>#Na_2O_2#</mathjax>. Now sodium generally has an oxidation state of <mathjax>#+I#</mathjax> in its salts, and it does so here. Thus <mathjax>#1+1+2xx"Oxidation number of oxygen in peroxide"=0#</mathjax>. Clearly, <mathjax>#"Oxidation number of oxygen in peroxide"=-1#</mathjax>.</p> <p>Another way of looking at this is to consider the peroxide ion itself, <mathjax>#""^(-)O-O^-#</mathjax>. When we break a bond conceptually, (i.e. in our imagination), we assume that the charge goes to the most electronegative atom. And so we gets <mathjax>#""^(-)O-O^(-)rarr2xxdotO^(-)#</mathjax>; i.e. a formal <mathjax>#-I#</mathjax> charge. And likewise if we do this for <mathjax>#OF_2#</mathjax> we get <mathjax>#2xxF^-#</mathjax> and <mathjax>#O^(2+)#</mathjax>. And so for element-element bonds, the elements have equal <a href="https://socratic.org/chemistry/bonding-basics/electronegativity-and-bonding">electronegativity</a> and the charge, the electrons, should properly be shared, to give again <mathjax>#O^-#</mathjax>, i.e. oxygen with a <mathjax>#-I#</mathjax> oxidation state. </p> <p>And thus the oxidation state of oxygen in peroxide is conceived to be <mathjax>#-I#</mathjax>. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>In sodium peroxide the oxidation state of oxygen is <mathjax>#-I#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>When we assign <a href="https://socratic.org/chemistry/electrochemistry/oxidation-numbers">oxidation numbers</a>, we assign conceptual charges to the individual atoms such that when these charges are summed up we get the charge on the molecule or the ion. Thus, <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> have an oxidation number of <mathjax>#0#</mathjax>, because they are assumed not to have donated or accepted electrons (the which process defines oxidation and reduction respectively).</p> <p>For your sodium peroxide we have <mathjax>#Na_2O_2#</mathjax>. Now sodium generally has an oxidation state of <mathjax>#+I#</mathjax> in its salts, and it does so here. Thus <mathjax>#1+1+2xx"Oxidation number of oxygen in peroxide"=0#</mathjax>. Clearly, <mathjax>#"Oxidation number of oxygen in peroxide"=-1#</mathjax>.</p> <p>Another way of looking at this is to consider the peroxide ion itself, <mathjax>#""^(-)O-O^-#</mathjax>. When we break a bond conceptually, (i.e. in our imagination), we assume that the charge goes to the most electronegative atom. And so we gets <mathjax>#""^(-)O-O^(-)rarr2xxdotO^(-)#</mathjax>; i.e. a formal <mathjax>#-I#</mathjax> charge. And likewise if we do this for <mathjax>#OF_2#</mathjax> we get <mathjax>#2xxF^-#</mathjax> and <mathjax>#O^(2+)#</mathjax>. And so for element-element bonds, the elements have equal <a href="https://socratic.org/chemistry/bonding-basics/electronegativity-and-bonding">electronegativity</a> and the charge, the electrons, should properly be shared, to give again <mathjax>#O^-#</mathjax>, i.e. oxygen with a <mathjax>#-I#</mathjax> oxidation state. </p> <p>And thus the oxidation state of oxygen in peroxide is conceived to be <mathjax>#-I#</mathjax>. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the oxidation number of oxygen in #"sodium peroxide"#, #Na_2O_2#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#electrochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Electrochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/electrochemistry/oxidation-numbers" itemprop="url"> <span class="breadcrumb" itemprop="title">Oxidation Numbers</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="321311" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-10-13T15:24:47" itemprop="dateCreated"> Oct 13, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>In sodium peroxide the oxidation state of oxygen is <mathjax>#-I#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>When we assign <a href="https://socratic.org/chemistry/electrochemistry/oxidation-numbers">oxidation numbers</a>, we assign conceptual charges to the individual atoms such that when these charges are summed up we get the charge on the molecule or the ion. Thus, <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> have an oxidation number of <mathjax>#0#</mathjax>, because they are assumed not to have donated or accepted electrons (the which process defines oxidation and reduction respectively).</p> <p>For your sodium peroxide we have <mathjax>#Na_2O_2#</mathjax>. Now sodium generally has an oxidation state of <mathjax>#+I#</mathjax> in its salts, and it does so here. Thus <mathjax>#1+1+2xx"Oxidation number of oxygen in peroxide"=0#</mathjax>. Clearly, <mathjax>#"Oxidation number of oxygen in peroxide"=-1#</mathjax>.</p> <p>Another way of looking at this is to consider the peroxide ion itself, <mathjax>#""^(-)O-O^-#</mathjax>. When we break a bond conceptually, (i.e. in our imagination), we assume that the charge goes to the most electronegative atom. And so we gets <mathjax>#""^(-)O-O^(-)rarr2xxdotO^(-)#</mathjax>; i.e. a formal <mathjax>#-I#</mathjax> charge. And likewise if we do this for <mathjax>#OF_2#</mathjax> we get <mathjax>#2xxF^-#</mathjax> and <mathjax>#O^(2+)#</mathjax>. And so for element-element bonds, the elements have equal <a href="https://socratic.org/chemistry/bonding-basics/electronegativity-and-bonding">electronegativity</a> and the charge, the electrons, should properly be shared, to give again <mathjax>#O^-#</mathjax>, i.e. oxygen with a <mathjax>#-I#</mathjax> oxidation state. </p> <p>And thus the oxidation state of oxygen in peroxide is conceived to be <mathjax>#-I#</mathjax>. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/321311" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="321333" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/david-drayer"><img alt="" class="" src="https://graph.facebook.com/10206723679871989/picture?height=50&width=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/david-drayer"> David Drayer </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-10-13T16:11:12" itemprop="dateCreated"> Oct 13, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The Oxidation of state of Oxygen in <mathjax>#Na_2O_2 #</mathjax> is -1</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The structure of the the molecule sodium per oxide is with each sodium joined to one oxygen and the two oxygen joined with one bond to each other and the other bond to the sodium atoms. </p> <p>Oxygen <mathjax># 1s^2 2s^2 2p^4#</mathjax> typically forms two bond to fill the two half filled p orbitals. The one bond that is shared between the two Oxygen atoms does not affect the Oxidation state of Oxygen. The two Oxygen atoms have equal electro negativity so there is no loss or gain of electrons in that bond. </p> <p>The bond that Oxygen shares with Sodium does change the Oxidation state of both Sodium and Oxygen. Sodium with a much lower <a href="https://socratic.org/chemistry/bonding-basics/electronegativity-and-bonding">electronegativity</a> will give up one electron to the Oxygen becoming +-1 ( Sodium is oxidized) The Oxygen having a much high electronegativity will take an electron from the Sodium becoming (-1) The Oxygen is reduced.<br/> ..<br/> Na : O :<br/> ..<br/> O: Na </p> <p>This Lewis dot structure shows the "shared" electrons between the the Sodium and Oxygen atoms which results in the transfer of an electron from the Sodium to the Oxygen resulting in the +1 charge for Sodium and the -1 charge for Oxygen. The shared electrons between the two Oxygens results in no loss or gain of electrons. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/321333" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-relate-to-electron-configuration"> How do oxidation numbers relate to electron configuration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-relate-to-valence-electrons"> How do oxidation numbers relate to valence electrons? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-vary-with-the-periodic-table"> How do oxidation numbers vary with the periodic table? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-oxidation-number-of-an-element-in-a-compound"> How do you calculate the oxidation number of an element in a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-sulfur"> What is the oxidation number for sulfur? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-carbon"> What is the oxidation number for carbon? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-copper"> What is the oxidation number for copper? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-nitrogen"> What is the oxidation number for nitrogen? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-oxygen"> What is the oxidation number for oxygen? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-oxidation-state-of-noble-gas-zero"> Why is the oxidation state of noble gas zero? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/electrochemistry/oxidation-numbers"> See all questions in Oxidation Numbers </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 21828 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the oxidation number of oxygen in #"sodium peroxide"#, #Na_2O_2#?	null
2,149	a9194e74-6ddd-11ea-947a-ccda262736ce	https://socratic.org/questions/a-cu-cu2-concentration-cell-has-a-voltage-of-0-22-v-at-298k-the-concentration-of	5.58 × 10^(-11) M	start physical_unit 30 34 concentration mol/l qc_end physical_unit 1 3 8 9 voltage qc_end physical_unit 1 3 11 12 temperature qc_end physical_unit 16 21 23 24 concentration qc_end end	[{"type":"physical unit","value":"Concentration [OF] Cu^2+ in the other half-cell [IN] M"}]	[{"type":"physical unit","value":"5.58 × 10^(-11) M"}]	[{"type":"physical unit","value":"Voltage [OF] Cu/Cu^2+ concentration cell [=] \\pu{0.22 V}"},{"type":"physical unit","value":"Temperature [OF] Cu/Cu^2+ concentration cell [=] \\pu{298 K}"},{"type":"physical unit","value":"Concentration [OF] Cu^2+ in one of the half-cells [=] \\pu{1.6E(-3) M}"}]	<h1 class="questionTitle" itemprop="name">A Cu/Cu2+ concentration cell has a voltage of 0.22 V at 298K. The concentration of Cu2+ in one of the half-cells is 1.6E−3 M. What is the concentration of Cu2+ in the other half-cell?</h1>	null	5.58 × 10^(-11) M	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Let us first describe the half-equations happening in the cell and write the overall equation:</p> <p><strong>Anode</strong> : <mathjax>#underbrace(Cu(s)->Cu^(2+)(aq)+2e^-)_color(blue)("Oxidation")#</mathjax><mathjax>#" "-E^@=-0.34V#</mathjax></p> <p><strong>Cathode</strong> : <mathjax>#underbrace(Cu^(2+)(aq)+2e^(-)->Cu(s))_color(blue)("Reduction")#</mathjax><mathjax>#" "E^@=0.34V#</mathjax></p> <p><strong>Overall equation</strong> : <mathjax>#Cu(s)+ underbrace(Cu^(2+)(aq))_(Cathode) -> Cu^(2+)(aq) + Cu(s)#</mathjax> </p> <p><mathjax>#E_("cell")^@=E_("Anode")^@+E_("Cathode")^@=0V#</mathjax></p> <p>For concentration cells, we can calculate the cell potential <mathjax>#E_("cell")#</mathjax> using the <strong>Nernst Equation</strong>:</p> <p><mathjax>#E_("cell")=E_("cell")^@#</mathjax><mathjax>#-(0.0591)/(n)#</mathjax><mathjax>#log(([Cu^(2+)]_(Anode))/([Cu^(2+)]_C))#</mathjax></p> <p>Replacing the giving terms in this equation assuming that the given concentration is <mathjax>#[Cu^2+]_("Cathode")=1.6xx10^(-3)M#</mathjax></p> <p>and that <mathjax>#[Cu^2+]_("Anode")=x#</mathjax></p> <p><mathjax>#0.22=0-(0.0591)/(2)log((x)/(1.6xx10^(-3)))#</mathjax></p> <p>Solve for <mathjax>#x=5.7xx10^(-11)M#</mathjax></p> <p>Here is a video that explains in details the concentration cell and the Nernst Equation:</p> <p> <iframe src="https://www.youtube.com/embed/bAubcYnOM-M?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p> <p><em>Do not forget to Like & Subscribe.</em></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#[Cu^2+]_("Anode")=5.7xx10^(-11)M#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Let us first describe the half-equations happening in the cell and write the overall equation:</p> <p><strong>Anode</strong> : <mathjax>#underbrace(Cu(s)->Cu^(2+)(aq)+2e^-)_color(blue)("Oxidation")#</mathjax><mathjax>#" "-E^@=-0.34V#</mathjax></p> <p><strong>Cathode</strong> : <mathjax>#underbrace(Cu^(2+)(aq)+2e^(-)->Cu(s))_color(blue)("Reduction")#</mathjax><mathjax>#" "E^@=0.34V#</mathjax></p> <p><strong>Overall equation</strong> : <mathjax>#Cu(s)+ underbrace(Cu^(2+)(aq))_(Cathode) -> Cu^(2+)(aq) + Cu(s)#</mathjax> </p> <p><mathjax>#E_("cell")^@=E_("Anode")^@+E_("Cathode")^@=0V#</mathjax></p> <p>For concentration cells, we can calculate the cell potential <mathjax>#E_("cell")#</mathjax> using the <strong>Nernst Equation</strong>:</p> <p><mathjax>#E_("cell")=E_("cell")^@#</mathjax><mathjax>#-(0.0591)/(n)#</mathjax><mathjax>#log(([Cu^(2+)]_(Anode))/([Cu^(2+)]_C))#</mathjax></p> <p>Replacing the giving terms in this equation assuming that the given concentration is <mathjax>#[Cu^2+]_("Cathode")=1.6xx10^(-3)M#</mathjax></p> <p>and that <mathjax>#[Cu^2+]_("Anode")=x#</mathjax></p> <p><mathjax>#0.22=0-(0.0591)/(2)log((x)/(1.6xx10^(-3)))#</mathjax></p> <p>Solve for <mathjax>#x=5.7xx10^(-11)M#</mathjax></p> <p>Here is a video that explains in details the concentration cell and the Nernst Equation:</p> <p> <iframe src="https://www.youtube.com/embed/bAubcYnOM-M?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p> <p><em>Do not forget to Like & Subscribe.</em></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A Cu/Cu2+ concentration cell has a voltage of 0.22 V at 298K. The concentration of Cu2+ in one of the half-cells is 1.6E−3 M. What is the concentration of Cu2+ in the other half-cell?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#electrochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Electrochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/electrochemistry/calculating-energy-in-electrochemical-processes" itemprop="url"> <span class="breadcrumb" itemprop="title">Calculating Energy in Electrochemical Processes</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="187952" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ali-h-1"><img alt="" class="" src="https://profilepictures.socratic.org/IITeL1YTQdODdLp0aJTL_StereoPicture%20copy.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ali-h-1"> Dr. Hayek </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-13T17:49:18" itemprop="dateCreated"> Nov 13, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#[Cu^2+]_("Anode")=5.7xx10^(-11)M#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Let us first describe the half-equations happening in the cell and write the overall equation:</p> <p><strong>Anode</strong> : <mathjax>#underbrace(Cu(s)->Cu^(2+)(aq)+2e^-)_color(blue)("Oxidation")#</mathjax><mathjax>#" "-E^@=-0.34V#</mathjax></p> <p><strong>Cathode</strong> : <mathjax>#underbrace(Cu^(2+)(aq)+2e^(-)->Cu(s))_color(blue)("Reduction")#</mathjax><mathjax>#" "E^@=0.34V#</mathjax></p> <p><strong>Overall equation</strong> : <mathjax>#Cu(s)+ underbrace(Cu^(2+)(aq))_(Cathode) -> Cu^(2+)(aq) + Cu(s)#</mathjax> </p> <p><mathjax>#E_("cell")^@=E_("Anode")^@+E_("Cathode")^@=0V#</mathjax></p> <p>For concentration cells, we can calculate the cell potential <mathjax>#E_("cell")#</mathjax> using the <strong>Nernst Equation</strong>:</p> <p><mathjax>#E_("cell")=E_("cell")^@#</mathjax><mathjax>#-(0.0591)/(n)#</mathjax><mathjax>#log(([Cu^(2+)]_(Anode))/([Cu^(2+)]_C))#</mathjax></p> <p>Replacing the giving terms in this equation assuming that the given concentration is <mathjax>#[Cu^2+]_("Cathode")=1.6xx10^(-3)M#</mathjax></p> <p>and that <mathjax>#[Cu^2+]_("Anode")=x#</mathjax></p> <p><mathjax>#0.22=0-(0.0591)/(2)log((x)/(1.6xx10^(-3)))#</mathjax></p> <p>Solve for <mathjax>#x=5.7xx10^(-11)M#</mathjax></p> <p>Here is a video that explains in details the concentration cell and the Nernst Equation:</p> <p> <iframe src="https://www.youtube.com/embed/bAubcYnOM-M?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p> <p><em>Do not forget to Like & Subscribe.</em></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/187952" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-cells-generate-an-electrochemical-gradient"> How do cells generate an electrochemical gradient? 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The concentration of Cu2+ in one of the half-cells is 1.6E−3 M. What is the concentration of Cu2+ in the other half-cell?	null
2,150	ac874726-6ddd-11ea-9724-ccda262736ce	https://socratic.org/questions/595866347c014916d791788e	4.31	start physical_unit 33 34 ph none qc_end physical_unit 2 2 6 7 volume qc_end physical_unit 9 11 13 14 concentration qc_end physical_unit 2 2 18 19 volume qc_end physical_unit 22 22 24 25 concentration qc_end end	[{"type":"physical unit","value":"pH [OF] this buffer"}]	[{"type":"physical unit","value":"4.31"}]	[{"type":"physical unit","value":"Volume [OF] weak acid HA solution [=] \\pu{0.615 L}"},{"type":"physical unit","value":"Concentration [OF] weak acid HA solution [=] \\pu{0.250 mol/L}"},{"type":"physical unit","value":"Volume [OF] NaOH solution [=] \\pu{0.500 L}"},{"type":"physical unit","value":"Concentration [OF] NaOH solution [=] \\pu{0.130 mol/L}"}]	<h1 class="questionTitle" itemprop="name">A buffer solution was prepared from #0.615L# of weak acid #HA# at #0.250molL^-1# concentration, and a #0.500L# volume of #NaOH# at #0.130molL^-1# concentration. What is the resultant #pH# of this buffer?</h1>	null	4.31	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The buffer equation tells us that......</p> <p>Thus <mathjax>#pH=pK_a+log_10{[[A^-]]/[[HA]]}#</mathjax></p> <p>We gots <mathjax>#pK_a=-log_10(3.52xx10^-5)=4.45#</mathjax>, we have to work out the concentrations of free acid, and conjugate base.</p> <p>Now addition of the strong base to the weak acid.....immediately gives us stoichiometric quantities of <mathjax>#Na^+A^-#</mathjax>, where <mathjax>#HA#</mathjax> was the conjugate acid........</p> <p><mathjax>#HA(aq) + NaOH(aq) rarr Na^+A^(-) + H_2O#</mathjax> </p> <p>Starting moles of ..................<mathjax>#HA=0.615Lxx0.250molL^-1=0.154mol#</mathjax> <mathjax>#(i)#</mathjax></p> <p>Moles of <mathjax>#NaOH=0.500Lxx0.130molL^-1=#</mathjax></p> <p><mathjax>#0.0650mol#</mathjax>.</p> <p>And so INITIALLY we gots <mathjax>#(0.154-0.0650)mol#</mathjax> <mathjax>#HA#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.089mol#</mathjax> <mathjax>#(ii)#</mathjax></p> <p>And <mathjax>#0.0650mol#</mathjax> <mathjax>#A^-#</mathjax>. These molar quantities are dissolved in a volume of <mathjax>#(500+615)mL=1115mL=1.115L#</mathjax>, but it doesn't really matter because.....</p> <p><mathjax>#pH=pK_a+log_10{[[A^-]]/[[HA]]}#</mathjax>, and since in the log quotient....the volume of solution <mathjax>#"IS THE SAME"#</mathjax> we can ignore it, and just use the molar quantities of acid and conjugate base.</p> <p>And so FINALLY.......</p> <p><mathjax>#pH=underbrace(-log_10(3.52xx10^-5))_color(red)(pK_a)+log_10{(0.0650)/(0.089)}#</mathjax></p> <p><mathjax>#=#</mathjax> <mathjax>#-(-4.45)+(-0.136)=4.31......#</mathjax></p> <p>Now had <mathjax>#[A^-]=[HA]#</mathjax>, then the <mathjax>#pH#</mathjax> of the resultant buffer would have been equal to <mathjax>#pK_a#</mathjax>. Why because <mathjax>#log_(10)1=0#</mathjax>, and had we put this value back into the expression we get <mathjax>#pH=pK_a#</mathjax>.</p> <p>The final <mathjax>#pH#</mathjax> is a trifle less than the <mathjax>#pK_a#</mathjax>, which makes sense given that there were more moles of acid than there were moles of base.....and the <mathjax>#pH#</mathjax> should be reduced from <mathjax>#pK_a#</mathjax> (because more <mathjax>#[H_3O^+]#</mathjax>.</p> <p>I acknowledge that I have gone on for a long time about nothing to the power of less. But all I have done is to use <mathjax>#log#</mathjax> functions and calculated the molar quantities of acid and base, even tho it takes forever. Good luck. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>See <a href="https://socratic.org/questions/how-do-buffers-maintain-ph">here for background.......</a> We finally get <mathjax>#pH=4.31#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The buffer equation tells us that......</p> <p>Thus <mathjax>#pH=pK_a+log_10{[[A^-]]/[[HA]]}#</mathjax></p> <p>We gots <mathjax>#pK_a=-log_10(3.52xx10^-5)=4.45#</mathjax>, we have to work out the concentrations of free acid, and conjugate base.</p> <p>Now addition of the strong base to the weak acid.....immediately gives us stoichiometric quantities of <mathjax>#Na^+A^-#</mathjax>, where <mathjax>#HA#</mathjax> was the conjugate acid........</p> <p><mathjax>#HA(aq) + NaOH(aq) rarr Na^+A^(-) + H_2O#</mathjax> </p> <p>Starting moles of ..................<mathjax>#HA=0.615Lxx0.250molL^-1=0.154mol#</mathjax> <mathjax>#(i)#</mathjax></p> <p>Moles of <mathjax>#NaOH=0.500Lxx0.130molL^-1=#</mathjax></p> <p><mathjax>#0.0650mol#</mathjax>.</p> <p>And so INITIALLY we gots <mathjax>#(0.154-0.0650)mol#</mathjax> <mathjax>#HA#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.089mol#</mathjax> <mathjax>#(ii)#</mathjax></p> <p>And <mathjax>#0.0650mol#</mathjax> <mathjax>#A^-#</mathjax>. These molar quantities are dissolved in a volume of <mathjax>#(500+615)mL=1115mL=1.115L#</mathjax>, but it doesn't really matter because.....</p> <p><mathjax>#pH=pK_a+log_10{[[A^-]]/[[HA]]}#</mathjax>, and since in the log quotient....the volume of solution <mathjax>#"IS THE SAME"#</mathjax> we can ignore it, and just use the molar quantities of acid and conjugate base.</p> <p>And so FINALLY.......</p> <p><mathjax>#pH=underbrace(-log_10(3.52xx10^-5))_color(red)(pK_a)+log_10{(0.0650)/(0.089)}#</mathjax></p> <p><mathjax>#=#</mathjax> <mathjax>#-(-4.45)+(-0.136)=4.31......#</mathjax></p> <p>Now had <mathjax>#[A^-]=[HA]#</mathjax>, then the <mathjax>#pH#</mathjax> of the resultant buffer would have been equal to <mathjax>#pK_a#</mathjax>. Why because <mathjax>#log_(10)1=0#</mathjax>, and had we put this value back into the expression we get <mathjax>#pH=pK_a#</mathjax>.</p> <p>The final <mathjax>#pH#</mathjax> is a trifle less than the <mathjax>#pK_a#</mathjax>, which makes sense given that there were more moles of acid than there were moles of base.....and the <mathjax>#pH#</mathjax> should be reduced from <mathjax>#pK_a#</mathjax> (because more <mathjax>#[H_3O^+]#</mathjax>.</p> <p>I acknowledge that I have gone on for a long time about nothing to the power of less. But all I have done is to use <mathjax>#log#</mathjax> functions and calculated the molar quantities of acid and base, even tho it takes forever. Good luck. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A buffer solution was prepared from #0.615L# of weak acid #HA# at #0.250molL^-1# concentration, and a #0.500L# volume of #NaOH# at #0.130molL^-1# concentration. What is the resultant #pH# of this buffer?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#reactions-in-solution" itemprop="url"> <span class="breadcrumb" itemprop="title">Reactions in Solution</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/reactions-in-solution/buffer-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">Buffer Calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="446925" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-07-02T08:27:25" itemprop="dateCreated"> Jul 2, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>See <a href="https://socratic.org/questions/how-do-buffers-maintain-ph">here for background.......</a> We finally get <mathjax>#pH=4.31#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The buffer equation tells us that......</p> <p>Thus <mathjax>#pH=pK_a+log_10{[[A^-]]/[[HA]]}#</mathjax></p> <p>We gots <mathjax>#pK_a=-log_10(3.52xx10^-5)=4.45#</mathjax>, we have to work out the concentrations of free acid, and conjugate base.</p> <p>Now addition of the strong base to the weak acid.....immediately gives us stoichiometric quantities of <mathjax>#Na^+A^-#</mathjax>, where <mathjax>#HA#</mathjax> was the conjugate acid........</p> <p><mathjax>#HA(aq) + NaOH(aq) rarr Na^+A^(-) + H_2O#</mathjax> </p> <p>Starting moles of ..................<mathjax>#HA=0.615Lxx0.250molL^-1=0.154mol#</mathjax> <mathjax>#(i)#</mathjax></p> <p>Moles of <mathjax>#NaOH=0.500Lxx0.130molL^-1=#</mathjax></p> <p><mathjax>#0.0650mol#</mathjax>.</p> <p>And so INITIALLY we gots <mathjax>#(0.154-0.0650)mol#</mathjax> <mathjax>#HA#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.089mol#</mathjax> <mathjax>#(ii)#</mathjax></p> <p>And <mathjax>#0.0650mol#</mathjax> <mathjax>#A^-#</mathjax>. These molar quantities are dissolved in a volume of <mathjax>#(500+615)mL=1115mL=1.115L#</mathjax>, but it doesn't really matter because.....</p> <p><mathjax>#pH=pK_a+log_10{[[A^-]]/[[HA]]}#</mathjax>, and since in the log quotient....the volume of solution <mathjax>#"IS THE SAME"#</mathjax> we can ignore it, and just use the molar quantities of acid and conjugate base.</p> <p>And so FINALLY.......</p> <p><mathjax>#pH=underbrace(-log_10(3.52xx10^-5))_color(red)(pK_a)+log_10{(0.0650)/(0.089)}#</mathjax></p> <p><mathjax>#=#</mathjax> <mathjax>#-(-4.45)+(-0.136)=4.31......#</mathjax></p> <p>Now had <mathjax>#[A^-]=[HA]#</mathjax>, then the <mathjax>#pH#</mathjax> of the resultant buffer would have been equal to <mathjax>#pK_a#</mathjax>. Why because <mathjax>#log_(10)1=0#</mathjax>, and had we put this value back into the expression we get <mathjax>#pH=pK_a#</mathjax>.</p> <p>The final <mathjax>#pH#</mathjax> is a trifle less than the <mathjax>#pK_a#</mathjax>, which makes sense given that there were more moles of acid than there were moles of base.....and the <mathjax>#pH#</mathjax> should be reduced from <mathjax>#pK_a#</mathjax> (because more <mathjax>#[H_3O^+]#</mathjax>.</p> <p>I acknowledge that I have gone on for a long time about nothing to the power of less. But all I have done is to use <mathjax>#log#</mathjax> functions and calculated the molar quantities of acid and base, even tho it takes forever. Good luck. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/446925" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-buffer-solutions-used"> How are buffer solutions used? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-buffer-capacity"> How do you calculate buffer capacity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-buffer-solutions-maintain-the-ph-of-blood"> How do buffer solutions maintain the pH of blood? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-buffer-a-solution-with-a-ph-of-12"> How do you buffer a solution with a pH of 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-buffer-solutions-used-to-calibrate-ph"> Why are buffer solutions used to calibrate pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is--solution-used-in-complexometric-titration"> What is the role of buffer solution in complexometric titrations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-you-would-make-100-0-ml-of-a-bu-er-solution-with-a-ph-of-10-80-to-be-made-us"> How you would make 100.0 ml of a 1.00 mol/L buffer solution with a pH of 10.80 to be made using... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-henderson-hasselbalch-equation"> What is the Henderson-Hasselbalch equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-an-example-of-a-ph-buffer-calculation-problem"> What is an example of a pH buffer calculation problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-bicarbonate-buffering-system-important"> Why is the bicarbonate buffering system important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/reactions-in-solution/buffer-calculations"> See all questions in Buffer Calculations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1725 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A buffer solution was prepared from #0.615L# of weak acid #HA# at #0.250molL^-1# concentration, and a #0.500L# volume of #NaOH# at #0.130molL^-1# concentration. What is the resultant #pH# of this buffer?	null
2,151	ab542a2c-6ddd-11ea-aadf-ccda262736ce	https://socratic.org/questions/how-much-water-must-be-added-to-1500-ml-of-a-6-0-mol-l-cacl-2-solution-to-make-t	3.00 L	start physical_unit 2 2 volume l qc_end physical_unit 13 14 11 12 concentration qc_end physical_unit 13 14 7 8 volume qc_end physical_unit 13 14 23 24 concentration qc_end end	[{"type":"physical unit","value":"Volume [OF] water [IN] L"}]	[{"type":"physical unit","value":"3.00 L"}]	[{"type":"physical unit","value":"Concentration1 [OF] CaCl2 solution [=] \\pu{6.0 mol/L}"},{"type":"physical unit","value":"Volume1 [OF] CaCl2 solution [=] \\pu{1500 mL}"},{"type":"physical unit","value":"Concentration2 [OF] CaCl2 solution [=] \\pu{2.0 mol/L}"}]	<h1 class="questionTitle" itemprop="name">How much water must be added to 1500 mL of a 6.0 mol/L #CaCl_2# solution to make the concentration of the resulting solution 2.0 mol/L? </h1>	null	3.00 L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The defining relationship for <mathjax>#"concentration"#</mathjax> is,</p> <p><mathjax>#"Concentration"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Moles of stuff"/"Volume of solution"#</mathjax>, now typically the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a> is water, but it could be other materials, even a gas.</p> <p>Here we have a molar quantity of <mathjax>#6.0molL^-1#</mathjax>, and a <mathjax>#1500mL#</mathjax> volume. We wish to dilute this concentration by a THIRD to <mathjax>#2.0molL^-1#</mathjax>.</p> <p>Now clearly, we cannot get the calcium salt out of solution, but we can add more solvent, more water to dilute it.</p> <p>And here we can use the old relationship,</p> <p><mathjax>#C_1V_1=C_2V_2#</mathjax> where <mathjax>#C="concentration"#</mathjax>, and <mathjax>#V="volume"#</mathjax>.</p> <p>So we solve for <mathjax>#V_2=(C_1V_1)/C_2=(1500mLxx6.0molL^-1)/(2.0molL^-1)=4500mL#</mathjax>. </p> <p>And since we began with <mathjax>#1500mL#</mathjax>, another <mathjax>#3000*mL#</mathjax> are required. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>You need to add another <mathjax>#"3 litres"#</mathjax> of water........</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The defining relationship for <mathjax>#"concentration"#</mathjax> is,</p> <p><mathjax>#"Concentration"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Moles of stuff"/"Volume of solution"#</mathjax>, now typically the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a> is water, but it could be other materials, even a gas.</p> <p>Here we have a molar quantity of <mathjax>#6.0molL^-1#</mathjax>, and a <mathjax>#1500mL#</mathjax> volume. We wish to dilute this concentration by a THIRD to <mathjax>#2.0molL^-1#</mathjax>.</p> <p>Now clearly, we cannot get the calcium salt out of solution, but we can add more solvent, more water to dilute it.</p> <p>And here we can use the old relationship,</p> <p><mathjax>#C_1V_1=C_2V_2#</mathjax> where <mathjax>#C="concentration"#</mathjax>, and <mathjax>#V="volume"#</mathjax>.</p> <p>So we solve for <mathjax>#V_2=(C_1V_1)/C_2=(1500mLxx6.0molL^-1)/(2.0molL^-1)=4500mL#</mathjax>. </p> <p>And since we began with <mathjax>#1500mL#</mathjax>, another <mathjax>#3000*mL#</mathjax> are required. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How much water must be added to 1500 mL of a 6.0 mol/L #CaCl_2# solution to make the concentration of the resulting solution 2.0 mol/L? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/solution-formation---what-happens-when-stuff-dissolves" itemprop="url"> <span class="breadcrumb" itemprop="title">Solution Formation</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="369455" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-01-26T09:04:11" itemprop="dateCreated"> Jan 26, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>You need to add another <mathjax>#"3 litres"#</mathjax> of water........</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The defining relationship for <mathjax>#"concentration"#</mathjax> is,</p> <p><mathjax>#"Concentration"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Moles of stuff"/"Volume of solution"#</mathjax>, now typically the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a> is water, but it could be other materials, even a gas.</p> <p>Here we have a molar quantity of <mathjax>#6.0molL^-1#</mathjax>, and a <mathjax>#1500mL#</mathjax> volume. We wish to dilute this concentration by a THIRD to <mathjax>#2.0molL^-1#</mathjax>.</p> <p>Now clearly, we cannot get the calcium salt out of solution, but we can add more solvent, more water to dilute it.</p> <p>And here we can use the old relationship,</p> <p><mathjax>#C_1V_1=C_2V_2#</mathjax> where <mathjax>#C="concentration"#</mathjax>, and <mathjax>#V="volume"#</mathjax>.</p> <p>So we solve for <mathjax>#V_2=(C_1V_1)/C_2=(1500mLxx6.0molL^-1)/(2.0molL^-1)=4500mL#</mathjax>. </p> <p>And since we began with <mathjax>#1500mL#</mathjax>, another <mathjax>#3000*mL#</mathjax> are required. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/369455" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-temperature-affect-the-formation-of-a-solution"> How can temperature affect the formation of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-formation-of-a-solution-be-exothermic-or-endothermic"> How can the formation of a solution be exothermic or endothermic? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-formation-of-a-solution-involve-energy"> How does the formation of a solution involve energy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-heat-formation-of-solution"> How do you find heat of formation of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-factor-promotes-the-formation-of-solutions"> Which factors promote the formation of solutions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/which-two-processes-are-at-equilibrium-in-a-saturated-sugar-solution"> Which two processes are at equilibrium in a saturated sugar solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-solutes-lower-the-freezing-point"> Why do solutes lower the freezing point? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-does-solution-formation-require-energy"> Why does solution formation require energy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-solutes-dissolve-in-solvents"> Why do solutes dissolve in solvents? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-solvent-dissolves-silicone"> What solvent dissolves silicone? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/solution-formation---what-happens-when-stuff-dissolves"> See all questions in Solution Formation </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 6911 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How much water must be added to 1500 mL of a 6.0 mol/L #CaCl_2# solution to make the concentration of the resulting solution 2.0 mol/L?	null
2,152	ab0dec34-6ddd-11ea-bdbd-ccda262736ce	https://socratic.org/questions/a-sample-of-a-mineral-contains-26-83-kcl-and-34-27-mgcl2-find-the-percentage-of-	38.28%	start physical_unit 15 18 percent none qc_end end	[{"type":"physical unit","value":"Percentage [OF] chlorine in this sample"}]	[{"type":"physical unit","value":"38.28%"}]	[{"type":"physical unit","value":"Percentage [OF] KCl in mineral sample [=] \\pu{26.83%}"},{"type":"physical unit","value":"Percentage [OF] MgCl2 in mineral sample [=] \\pu{34.27%}"}]	<h1 class="questionTitle" itemprop="name">A sample of a mineral contains #26.83%# #"KCl"# and #34.27%# #"MgCl"_2#. Find the percentage of chlorine in this sample?</h1>	null	38.28%	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your strategy here will be to use the given percentages to figure out how much chlorine is present in a given sample of this unknown mineral. </p> <p>To make the calculations easier, let's pick a sample of this mineral that has a mass of <mathjax>#"100.0 g"#</mathjax>. This implies that the sample contains</p> <blockquote> <ul> <li><mathjax>#"26.83% KCl in 100.0 g mineral" \ -> \ "26.83 g KCl"#</mathjax></li> <li><mathjax>#"34.27% MgCl"_2 \ "in 100.0 g mineral" \ -> \ "34.27 g MgCl"_2#</mathjax></li> </ul> </blockquote> <p>Now, use the <strong>molar mass</strong> of potassium chloride and the <strong>molar mass</strong> of <em>atomic chlorine</em> to calculate how many grams of chlorine are present in this sample. </p> <blockquote> <p><mathjax>#26.83 color(red)(cancel(color(black)("g KCl"))) * (1color(red)(cancel(color(black)("mole KCl"))))/(74.5513color(red)(cancel(color(black)("g KCl")))) * (1 color(red)(cancel(color(black)("mole Cl"))))/(1color(red)(cancel(color(black)("mole KCl")))) * "35.453 g"/(1color(red)(cancel(color(black)("mole Cl")))) = "12.759 g Cl"#</mathjax></p> </blockquote> <p>So, you know that this sample contains <mathjax>#"12.759 g"#</mathjax> of chlorine from the mass of potassium chloride. To find the mass of chlorine coming from the mass of magnesium chloride, use the <strong>molar mass</strong> of magnesium chloride and the <strong>molar mass</strong> of <em>atomic chlorine</em>. </p> <blockquote> <p><mathjax>#34.27 color(red)(cancel(color(black)("g MgCl"_2))) * (1color(red)(cancel(color(black)("mole MgCl"_2))))/(95.211color(red)(cancel(color(black)("g MgCl"_2)))) * (2color(red)(cancel(color(black)("moles Cl"))))/(1color(red)(cancel(color(black)("mole MgCl"_2)))) * "35.453 g"/(1color(red)(cancel(color(black)("mole Cl")))) = "25.522 g Cl"#</mathjax></p> </blockquote> <p>At this point, you know that the sample contains <mathjax>#"25.522 g"#</mathjax> of chlorine from the mass of magnesium chloride. </p> <p>You can thus say that the <strong>total mass</strong> of chlorine present in the sample is</p> <blockquote> <p><mathjax>#"12.759 g" \ + \ "25.522 g" = "38.281 g"#</mathjax></p> </blockquote> <p>So, you have a sample of this unknown mineral that has a mass of <mathjax>#"100.0 g"#</mathjax> and which contains <mathjax>#"38.281 g"#</mathjax> of chlorine, so you can say that the <strong><a href="https://socratic.org/chemistry/the-mole-concept/percent-composition">percent composition</a></strong> of chlorine in the sample is </p> <blockquote> <p><mathjax>#color(darkgreen)(ul(color(black)("% composition" \ = \ "38.28% Cl")))#</mathjax></p> <blockquote> <p>This is the case because, by definition, the <strong>mass percent</strong> of an element in a substance is given by the mass of said element present in exactly <mathjax>#"100 g"#</mathjax> of the substance. </p> </blockquote> </blockquote> <p>The answer is rounded to four <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for your data. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#38.28%#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your strategy here will be to use the given percentages to figure out how much chlorine is present in a given sample of this unknown mineral. </p> <p>To make the calculations easier, let's pick a sample of this mineral that has a mass of <mathjax>#"100.0 g"#</mathjax>. This implies that the sample contains</p> <blockquote> <ul> <li><mathjax>#"26.83% KCl in 100.0 g mineral" \ -> \ "26.83 g KCl"#</mathjax></li> <li><mathjax>#"34.27% MgCl"_2 \ "in 100.0 g mineral" \ -> \ "34.27 g MgCl"_2#</mathjax></li> </ul> </blockquote> <p>Now, use the <strong>molar mass</strong> of potassium chloride and the <strong>molar mass</strong> of <em>atomic chlorine</em> to calculate how many grams of chlorine are present in this sample. </p> <blockquote> <p><mathjax>#26.83 color(red)(cancel(color(black)("g KCl"))) * (1color(red)(cancel(color(black)("mole KCl"))))/(74.5513color(red)(cancel(color(black)("g KCl")))) * (1 color(red)(cancel(color(black)("mole Cl"))))/(1color(red)(cancel(color(black)("mole KCl")))) * "35.453 g"/(1color(red)(cancel(color(black)("mole Cl")))) = "12.759 g Cl"#</mathjax></p> </blockquote> <p>So, you know that this sample contains <mathjax>#"12.759 g"#</mathjax> of chlorine from the mass of potassium chloride. To find the mass of chlorine coming from the mass of magnesium chloride, use the <strong>molar mass</strong> of magnesium chloride and the <strong>molar mass</strong> of <em>atomic chlorine</em>. </p> <blockquote> <p><mathjax>#34.27 color(red)(cancel(color(black)("g MgCl"_2))) * (1color(red)(cancel(color(black)("mole MgCl"_2))))/(95.211color(red)(cancel(color(black)("g MgCl"_2)))) * (2color(red)(cancel(color(black)("moles Cl"))))/(1color(red)(cancel(color(black)("mole MgCl"_2)))) * "35.453 g"/(1color(red)(cancel(color(black)("mole Cl")))) = "25.522 g Cl"#</mathjax></p> </blockquote> <p>At this point, you know that the sample contains <mathjax>#"25.522 g"#</mathjax> of chlorine from the mass of magnesium chloride. </p> <p>You can thus say that the <strong>total mass</strong> of chlorine present in the sample is</p> <blockquote> <p><mathjax>#"12.759 g" \ + \ "25.522 g" = "38.281 g"#</mathjax></p> </blockquote> <p>So, you have a sample of this unknown mineral that has a mass of <mathjax>#"100.0 g"#</mathjax> and which contains <mathjax>#"38.281 g"#</mathjax> of chlorine, so you can say that the <strong><a href="https://socratic.org/chemistry/the-mole-concept/percent-composition">percent composition</a></strong> of chlorine in the sample is </p> <blockquote> <p><mathjax>#color(darkgreen)(ul(color(black)("% composition" \ = \ "38.28% Cl")))#</mathjax></p> <blockquote> <p>This is the case because, by definition, the <strong>mass percent</strong> of an element in a substance is given by the mass of said element present in exactly <mathjax>#"100 g"#</mathjax> of the substance. </p> </blockquote> </blockquote> <p>The answer is rounded to four <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for your data. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A sample of a mineral contains #26.83%# #"KCl"# and #34.27%# #"MgCl"_2#. Find the percentage of chlorine in this sample?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/percent-composition" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Composition</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="644783" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-07-31T11:57:27" itemprop="dateCreated"> Jul 31, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#38.28%#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your strategy here will be to use the given percentages to figure out how much chlorine is present in a given sample of this unknown mineral. </p> <p>To make the calculations easier, let's pick a sample of this mineral that has a mass of <mathjax>#"100.0 g"#</mathjax>. This implies that the sample contains</p> <blockquote> <ul> <li><mathjax>#"26.83% KCl in 100.0 g mineral" \ -> \ "26.83 g KCl"#</mathjax></li> <li><mathjax>#"34.27% MgCl"_2 \ "in 100.0 g mineral" \ -> \ "34.27 g MgCl"_2#</mathjax></li> </ul> </blockquote> <p>Now, use the <strong>molar mass</strong> of potassium chloride and the <strong>molar mass</strong> of <em>atomic chlorine</em> to calculate how many grams of chlorine are present in this sample. </p> <blockquote> <p><mathjax>#26.83 color(red)(cancel(color(black)("g KCl"))) * (1color(red)(cancel(color(black)("mole KCl"))))/(74.5513color(red)(cancel(color(black)("g KCl")))) * (1 color(red)(cancel(color(black)("mole Cl"))))/(1color(red)(cancel(color(black)("mole KCl")))) * "35.453 g"/(1color(red)(cancel(color(black)("mole Cl")))) = "12.759 g Cl"#</mathjax></p> </blockquote> <p>So, you know that this sample contains <mathjax>#"12.759 g"#</mathjax> of chlorine from the mass of potassium chloride. To find the mass of chlorine coming from the mass of magnesium chloride, use the <strong>molar mass</strong> of magnesium chloride and the <strong>molar mass</strong> of <em>atomic chlorine</em>. </p> <blockquote> <p><mathjax>#34.27 color(red)(cancel(color(black)("g MgCl"_2))) * (1color(red)(cancel(color(black)("mole MgCl"_2))))/(95.211color(red)(cancel(color(black)("g MgCl"_2)))) * (2color(red)(cancel(color(black)("moles Cl"))))/(1color(red)(cancel(color(black)("mole MgCl"_2)))) * "35.453 g"/(1color(red)(cancel(color(black)("mole Cl")))) = "25.522 g Cl"#</mathjax></p> </blockquote> <p>At this point, you know that the sample contains <mathjax>#"25.522 g"#</mathjax> of chlorine from the mass of magnesium chloride. </p> <p>You can thus say that the <strong>total mass</strong> of chlorine present in the sample is</p> <blockquote> <p><mathjax>#"12.759 g" \ + \ "25.522 g" = "38.281 g"#</mathjax></p> </blockquote> <p>So, you have a sample of this unknown mineral that has a mass of <mathjax>#"100.0 g"#</mathjax> and which contains <mathjax>#"38.281 g"#</mathjax> of chlorine, so you can say that the <strong><a href="https://socratic.org/chemistry/the-mole-concept/percent-composition">percent composition</a></strong> of chlorine in the sample is </p> <blockquote> <p><mathjax>#color(darkgreen)(ul(color(black)("% composition" \ = \ "38.28% Cl")))#</mathjax></p> <blockquote> <p>This is the case because, by definition, the <strong>mass percent</strong> of an element in a substance is given by the mass of said element present in exactly <mathjax>#"100 g"#</mathjax> of the substance. </p> </blockquote> </blockquote> <p>The answer is rounded to four <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for your data. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/644783" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-mole-percent"> What is mole percent? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4188602bf3469570e2e8b"> Question #e2e8b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4188702bf34695a6bc737"> Question #bc737 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418be02bf34695a6bc73b"> Question #bc73b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418c202bf3469570e2e8f"> Question #e2e8f </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418c802bf346963eb9857"> Question #b9857 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418ca02bf346963eb985b"> Question #b985b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418cc02bf34694a4fee41"> Question #fee41 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418d502bf34694c8c5c01"> Question #c5c01 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4196e02bf34695a6bc73f"> Question #bc73f </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/percent-composition"> See all questions in Percent Composition </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2915 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A sample of a mineral contains #26.83%# #"KCl"# and #34.27%# #"MgCl"_2#. Find the percentage of chlorine in this sample?	null
2,153	ac070e81-6ddd-11ea-90af-ccda262736ce	https://socratic.org/questions/58e8f584b72cff7539f020f8	3.01 × 10^25	start physical_unit 2 2 number none qc_end physical_unit 7 8 4 5 mole qc_end end	[{"type":"physical unit","value":"Number [OF] electrons"}]	[{"type":"physical unit","value":"3.01 × 10^25"}]	[{"type":"physical unit","value":"Mole [OF] carbon dioxide [=] \\pu{1 mole}"}]	<h1 class="questionTitle" itemprop="name">How many electrons in ONE MOLE of carbon dioxide?</h1>	null	3.01 × 10^25	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>first calculate the moles of <mathjax># CO2 #</mathjax> = 100/44 <br/> = 2.27 mol<br/> now number of electrons in <mathjax># CO2 #</mathjax> are obtained by adding total electrons in each of the three atoms i.e. two O and one C = 6+8+8<br/> = 22<br/> thus one mole of <mathjax># CO2 #</mathjax> has <mathjax># 22 * 6.022 * 10^23 #</mathjax> electrons and 2.27 mol has <mathjax># 2.27 * 22 * 6.022 * 10^23 #</mathjax> electrons = <mathjax># 301.1 * 10^23 #</mathjax> electrons </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>first calculate moles of <mathjax># CO2 #</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>first calculate the moles of <mathjax># CO2 #</mathjax> = 100/44 <br/> = 2.27 mol<br/> now number of electrons in <mathjax># CO2 #</mathjax> are obtained by adding total electrons in each of the three atoms i.e. two O and one C = 6+8+8<br/> = 22<br/> thus one mole of <mathjax># CO2 #</mathjax> has <mathjax># 22 * 6.022 * 10^23 #</mathjax> electrons and 2.27 mol has <mathjax># 2.27 * 22 * 6.022 * 10^23 #</mathjax> electrons = <mathjax># 301.1 * 10^23 #</mathjax> electrons </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many electrons in ONE MOLE of carbon dioxide?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">3</span> Answers </h5> <div class="answers"> <div class="answer" id="403685" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/deep-4"><img alt="" class="" src="https://profilepictures.socratic.org/c4yiQpOSzOnxFgIvig1Q_Photography.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/deep-4"> Deep </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-08T15:02:38" itemprop="dateCreated"> Apr 8, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>first calculate moles of <mathjax># CO2 #</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>first calculate the moles of <mathjax># CO2 #</mathjax> = 100/44 <br/> = 2.27 mol<br/> now number of electrons in <mathjax># CO2 #</mathjax> are obtained by adding total electrons in each of the three atoms i.e. two O and one C = 6+8+8<br/> = 22<br/> thus one mole of <mathjax># CO2 #</mathjax> has <mathjax># 22 * 6.022 * 10^23 #</mathjax> electrons and 2.27 mol has <mathjax># 2.27 * 22 * 6.022 * 10^23 #</mathjax> electrons = <mathjax># 301.1 * 10^23 #</mathjax> electrons </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/403685" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="403691" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-08T15:11:16" itemprop="dateCreated"> Apr 8, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#3 * 10^(25)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The first thing to do here is to calculate the <em>number of moles</em> of carbon dioxide present in your sample. To do that, use the compound's <strong>molar mass</strong></p> <blockquote> <p><mathjax>#100 color(red)(cancel(color(black)("g"))) * "1 mole CO"_2/(44.0color(red)(cancel(color(black)("g")))) = "2.27 moles CO"_2#</mathjax></p> </blockquote> <p>Next, use <strong>Avogadro's constant</strong> to figure out the number of <strong>molecules</strong> of carbon dioxide present in the sample.</p> <blockquote> <p><mathjax>#2.27 color(red)(cancel(color(black)("moles CO"_2))) * (6.022 * 10^(23)color(white)(.)"molecules CO"_2)/(1color(red)(cancel(color(black)("mole CO"_2))))#</mathjax></p> <blockquote> <blockquote> <blockquote> <p><mathjax># =1.37 * 10^(24)#</mathjax> <mathjax>#"molecules CO"_2#</mathjax></p> </blockquote> </blockquote> </blockquote> </blockquote> <p>Now, every molecule of carbon dioxide contains </p> <blockquote> <ul> <li><em><strong>one atom</strong> of carbon</em>, <mathjax>#1 xx "C"#</mathjax></li> <li><em><strong>two atoms</strong> of oxygen</em>, <mathjax>#2 xx "O"#</mathjax></li> </ul> <p><img alt="http://grrebs.ete.inrs.ca/en/csc/csc_co2/" src="https://useruploads.socratic.org/4PjyrP7Q9KrZhvIEbKgN_molecule_co2_eng.jpg"/> </p> </blockquote> <p>This means that your sample contains</p> <blockquote> <p><mathjax>#1.37 * 10^(24)color(red)(cancel(color(black)("molecules CO"_2))) * "1 atom C"/(1color(red)(cancel(color(black)("molecule CO"_2))))#</mathjax></p> <blockquote> <blockquote> <blockquote> <p><mathjax># = 1.38 * 10^(24)#</mathjax> <mathjax>#"atoms of C"#</mathjax></p> </blockquote> </blockquote> </blockquote> </blockquote> <p>and</p> <blockquote> <p><mathjax>#1.37 * 10^(24) color(red)(cancel(color(black)("molecules CO"_2))) * "2 atoms O"/(1 color(red)(cancel(color(black)("molecule CO"_2))))#</mathjax></p> <blockquote> <blockquote> <blockquote> <p><mathjax># = 2.74 * 10^(24)#</mathjax> <mathjax>#"atoms of O"#</mathjax></p> </blockquote> </blockquote> </blockquote> </blockquote> <p>Next, grab a periodic Table and look for the <strong>atomic numbers</strong> of the two <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a>. You will find</p> <blockquote> <p><mathjax>#"For C: " Z = 6#</mathjax></p> <p><mathjax>#"For O: " Z = 8#</mathjax></p> </blockquote> <p>As you know, a <em>neutral atom</em> has <strong>equal numbers</strong> of protons located inside its nucleus and electrons surrounding the nucleus. </p> <p>Therefore, you can say that every atom of carbon will contain <mathjax>#6#</mathjax> <strong>electrons</strong> and every atom of oxygen will contain <mathjax>#8#</mathjax> <strong>electrons</strong>. </p> <p>This means that you will have</p> <blockquote> <p><mathjax>#"total no. of e"^(-) = overbrace(6 * 1.37 * 10^(24))^(color(blue)("coming from C atoms")) + overbrace(8 * 2.74 * 10^(24))^(color(purple)("coming from O atoms"))#</mathjax></p> <p><mathjax>#"total no. of e"^(-) = (8.22 + 21.92) * 10^(24)#</mathjax></p> </blockquote> <p>which gets you </p> <blockquote> <p><mathjax>#color(darkgreen)(ul(color(black)("total no. of e"^(-) = 3 * 10^(25))))#</mathjax></p> </blockquote> <p>The answer must be rounded to one <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figure</a></strong>, the number of sig figs you have for the mass of carbon dioxide. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/403691" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="403947" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-09T05:08:47" itemprop="dateCreated"> Apr 9, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Approx. <mathjax>#3xx10^25#</mathjax> <mathjax>#"electrons........"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First, we calculate the number of electrons in ONE MOLECULE of <mathjax>#CO_2#</mathjax>. There is ONE CARBON ATOM, that is 6 electrons; and TWO OXYGEN ATOMS, that is 16 electrons, i.e. 22 electrons per molecule.</p> <p>And then we calculate the number of carbon dioxide molecules in a mass of <mathjax>#100g#</mathjax> of gas. How do we do this? We use <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> as a counting unit, i.e. <mathjax>#6.022xx10^23#</mathjax> molecules of <mathjax>#CO_2#</mathjax> have a mass of <mathjax>#(12.01+2xx15.999)gmol^-1=44.0gmol^-1#</mathjax></p> <p><mathjax>#"Moles of carbon dioxide"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(100g)/(44.01gmol^-1)=2.27mol#</mathjax>.</p> <p>And (finally) we solve the product:</p> <p><mathjax>#22xx(100g)/(44.01gmol^-1)xx6.022xx10^23"electrons"mol^-1=#</mathjax></p> <p><mathjax>#"how many electrons...........?"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/403947" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 50342 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many electrons in ONE MOLE of carbon dioxide?	null
2,154	a9b967d5-6ddd-11ea-9814-ccda262736ce	https://socratic.org/questions/5721eadd7c01494c5b5f3203	3 Fe + 4 H2O -> Fe3O4 + 4 H2	start chemical_equation qc_end chemical_equation 7 13 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the equation"}]	[{"type":"chemical equation","value":"3 Fe + 4 H2O -> Fe3O4 + 4 H2"}]	[{"type":"chemical equation","value":"Fe + H2O -> Fe3O4 + H2"}]	<h1 class="questionTitle" itemprop="name">How do you balance the chemical equation: #Fe+H_2O = Fe_3O_4+H_2#? </h1>	null	3 Fe + 4 H2O -> Fe3O4 + 4 H2	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <mathjax>#Fe_3#</mathjax> in <mathjax>#Fe_3O_4#</mathjax> on the right implies that there must be some multiple of <mathjax>#3#</mathjax> <mathjax>#Fe#</mathjax> on the left side.</p> <p>Similarly the <mathjax>#O_4#</mathjax> on the right side implies that there must be some multiple of <mathjax>#4#</mathjax> <mathjax>#H_2O#</mathjax> on the left side.</p> <p><mathjax>#(3m)Fe+(4n)H_2O = (p)Fe_3O_4+(q)H_2#</mathjax></p> <p>Since<br/> <mathjax>#color(white)("XXX")(3m)Fe rarr (m)Fe_3O_4#</mathjax> (there's no place else for the <mathjax>#Fe#</mathjax> to go)<br/> and<br/> <mathjax>#color(white)("XXX")(4n)H_2O rarr (n)Fe_3O_4#</mathjax> (there's no place else for the <mathjax>#O#</mathjax> to go)<br/> <mathjax>#rArr m=n#</mathjax></p> <p>Further<br/> <mathjax>#color(white)("XXX")(4n)H_2O rarr (q)H_2#</mathjax><br/> <mathjax>#rArr q=4n#</mathjax></p> <p>Therefore we have<br/> <mathjax>#color(white)("XXX")(3n)Fe+(4n)H_2O = (n)Fe_3O_4+(4n)H_2#</mathjax></p> <p>Using the simplest version: <mathjax>#n=1#</mathjax> gives<br/> <mathjax>#color(white)("XXX")3Fe+4H_2O = Fe_3O_4+4H_2#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#3Fe+4H_2O = Fe_3O_4+4H_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <mathjax>#Fe_3#</mathjax> in <mathjax>#Fe_3O_4#</mathjax> on the right implies that there must be some multiple of <mathjax>#3#</mathjax> <mathjax>#Fe#</mathjax> on the left side.</p> <p>Similarly the <mathjax>#O_4#</mathjax> on the right side implies that there must be some multiple of <mathjax>#4#</mathjax> <mathjax>#H_2O#</mathjax> on the left side.</p> <p><mathjax>#(3m)Fe+(4n)H_2O = (p)Fe_3O_4+(q)H_2#</mathjax></p> <p>Since<br/> <mathjax>#color(white)("XXX")(3m)Fe rarr (m)Fe_3O_4#</mathjax> (there's no place else for the <mathjax>#Fe#</mathjax> to go)<br/> and<br/> <mathjax>#color(white)("XXX")(4n)H_2O rarr (n)Fe_3O_4#</mathjax> (there's no place else for the <mathjax>#O#</mathjax> to go)<br/> <mathjax>#rArr m=n#</mathjax></p> <p>Further<br/> <mathjax>#color(white)("XXX")(4n)H_2O rarr (q)H_2#</mathjax><br/> <mathjax>#rArr q=4n#</mathjax></p> <p>Therefore we have<br/> <mathjax>#color(white)("XXX")(3n)Fe+(4n)H_2O = (n)Fe_3O_4+(4n)H_2#</mathjax></p> <p>Using the simplest version: <mathjax>#n=1#</mathjax> gives<br/> <mathjax>#color(white)("XXX")3Fe+4H_2O = Fe_3O_4+4H_2#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you balance the chemical equation: #Fe+H_2O = Fe_3O_4+H_2#? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="259815" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/alan-p"><img alt="" class="" src="https://graph.facebook.com/1409517466/picture?height=50&width=50" title=""/></a> <a class="secondContributorPic" href="/users/david-b-3"><img alt="" class="" src="https://lh3.googleusercontent.com/-dFXDJkxWdYQ/AAAAAAAAAAI/AAAAAAAACTU/WCn8OFxdP90/photo.jpg?sz=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/alan-p"> Alan P. </a>·<a class="topContributorLink" href="/users/david-b-3"> David B. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-04-28T11:12:40" itemprop="dateCreated"> Apr 28, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#3Fe+4H_2O = Fe_3O_4+4H_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <mathjax>#Fe_3#</mathjax> in <mathjax>#Fe_3O_4#</mathjax> on the right implies that there must be some multiple of <mathjax>#3#</mathjax> <mathjax>#Fe#</mathjax> on the left side.</p> <p>Similarly the <mathjax>#O_4#</mathjax> on the right side implies that there must be some multiple of <mathjax>#4#</mathjax> <mathjax>#H_2O#</mathjax> on the left side.</p> <p><mathjax>#(3m)Fe+(4n)H_2O = (p)Fe_3O_4+(q)H_2#</mathjax></p> <p>Since<br/> <mathjax>#color(white)("XXX")(3m)Fe rarr (m)Fe_3O_4#</mathjax> (there's no place else for the <mathjax>#Fe#</mathjax> to go)<br/> and<br/> <mathjax>#color(white)("XXX")(4n)H_2O rarr (n)Fe_3O_4#</mathjax> (there's no place else for the <mathjax>#O#</mathjax> to go)<br/> <mathjax>#rArr m=n#</mathjax></p> <p>Further<br/> <mathjax>#color(white)("XXX")(4n)H_2O rarr (q)H_2#</mathjax><br/> <mathjax>#rArr q=4n#</mathjax></p> <p>Therefore we have<br/> <mathjax>#color(white)("XXX")(3n)Fe+(4n)H_2O = (n)Fe_3O_4+(4n)H_2#</mathjax></p> <p>Using the simplest version: <mathjax>#n=1#</mathjax> gives<br/> <mathjax>#color(white)("XXX")3Fe+4H_2O = Fe_3O_4+4H_2#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/259815" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? 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Sodium phosphate and calcium chloride react to form... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-equation-kclo3-kcl-o2"> How can I balance this equation? ____ #KClO_3 -># ____ #KCl +# ____ #O_2# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-balancing-chemical-equations-important"> Why is balancing chemical equations important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/balancing-chemical-equations"> See all questions in Balancing Chemical Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 12193 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How do you balance the chemical equation: #Fe+H_2O = Fe_3O_4+H_2#?	null
2,155	aab6995d-6ddd-11ea-98ce-ccda262736ce	https://socratic.org/questions/calcium-metal-ca-can-be-produced-by-passing-an-electric-current-through-molten-c	CaCl2(l) ->[\Delta] Ca(l) + Cl2(g)	start chemical_equation qc_end c_other OTHER qc_end chemical_equation 18 18 qc_end end	[{"type":"other","value":"Chemical Equation [OF] this reaction"}]	[{"type":"chemical equation","value":"CaCl2(l) ->[\\Delta] Ca(l) + Cl2(g)"}]	[{"type":"other","value":"Calcium metal (Ca) can be produced by passing an electric current through molten calcium chloride (CaCl2). "},{"type":"chemical equation","value":"Cl2"}]	<h1 class="questionTitle" itemprop="name">Calcium metal (Ca) can be produced by passing an electric current through molten calcium chloride (#CaCl_2#). Chlorine gas (#Cl_2#) is also formed. What is the balanced equation for this reaction?</h1>	null	CaCl2(l) ->[\Delta] Ca(l) + Cl2(g)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Is charge balanced? Tick. Is mass balanced? Tick.</p> <p>If either quantity was unbalanced, we could not accept the equation as a legitimate representation of reality. What does the <mathjax>#Delta#</mathjax> symbol represent? Is this a redox reaction?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#CaCl_2(l) +Deltararr Ca(l) + Cl_2(g)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Is charge balanced? Tick. Is mass balanced? Tick.</p> <p>If either quantity was unbalanced, we could not accept the equation as a legitimate representation of reality. What does the <mathjax>#Delta#</mathjax> symbol represent? Is this a redox reaction?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Calcium metal (Ca) can be produced by passing an electric current through molten calcium chloride (#CaCl_2#). Chlorine gas (#Cl_2#) is also formed. What is the balanced equation for this reaction?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="390658" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-13T16:13:19" itemprop="dateCreated"> Mar 13, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#CaCl_2(l) +Deltararr Ca(l) + Cl_2(g)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Is charge balanced? Tick. Is mass balanced? Tick.</p> <p>If either quantity was unbalanced, we could not accept the equation as a legitimate representation of reality. What does the <mathjax>#Delta#</mathjax> symbol represent? Is this a redox reaction?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/390658" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------> H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -> Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? 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Sodium phosphate and calcium chloride react to form... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-equation-kclo3-kcl-o2"> How can I balance this equation? ____ #KClO_3 -># ____ #KCl +# ____ #O_2# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-balancing-chemical-equations-important"> Why is balancing chemical equations important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/balancing-chemical-equations"> See all questions in Balancing Chemical Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 4899 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Calcium metal (Ca) can be produced by passing an electric current through molten calcium chloride (#CaCl_2#). Chlorine gas (#Cl_2#) is also formed. What is the balanced equation for this reaction?	null
2,156	ab80970d-6ddd-11ea-af57-ccda262736ce	https://socratic.org/questions/58e5d3bd7c014912bac74dc2	5	start physical_unit 26 27 number none qc_end physical_unit 8 8 5 6 mass qc_end physical_unit 14 14 11 12 volume qc_end substance 22 23 qc_end end	[{"type":"physical unit","value":"Number [OF] water molecules"}]	[{"type":"physical unit","value":"5"}]	[{"type":"physical unit","value":"Mass [OF] salt [=] \\pu{25 g}"},{"type":"physical unit","value":"Volume [OF] water [=] \\pu{1 L}"},{"type":"substance name","value":"Sodium thiosulfate"}]	<h1 class="questionTitle" itemprop="name">A solution is prepared from #25g# of salt dissolved in #1L# of water. If the salt is an hydrate of sodium thiosulfate, how many water molecules are associated with this salt?</h1>	null	5	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#Na_2S_2O_35H_2O#</mathjax> is the common laboratory reagent, this so-called pentahydrate forms large sugary crystals so it is easy and convenient to handle. The formula mass of this material is <mathjax>#248.18gmol^-1#</mathjax> (i.e. this represents the mass of the sodium, the sulfur, the oxygen, and the hydrogen atoms, i.e. INCLUDING the water molecules). So here a mass of <mathjax>#248.18g#</mathjax> of this stuff represents a given quantity (a mole) of such species.</p> <p>Now concentration is typically defined as the quotient:</p> <p><mathjax>#"Concentration"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Amount of substance (in moles)"/"Volume of Solution (in litres)"#</mathjax>, and thus has units <mathjax>#molL^-1#</mathjax>.</p> <p>So, given that we dissolve <mathjax>#25g#</mathjax> of the salt in <mathjax>#1L#</mathjax> of water (and I am making an educated(?) guess here), we have a concentration of.......</p> <p><mathjax>#"Concentration"=((25g)/(248.18gmol^-1))/(1L)=(0.100mol)/(1L)=0.100molL^-1.#</mathjax></p> <p>OR <mathjax>#0.100"N"#</mathjax> with respect to <mathjax>#Na_2S_2O_35H_2O#</mathjax>, i.e. the <mathjax>#"pentahydrate"#</mathjax>. We write <mathjax>#N#</mathjax> for <mathjax>#"normal"#</mathjax>, because formally we have a solution whose concentration with respect to <mathjax>#Na_2S_2O_35H_2O#</mathjax> is the same. Of course, when we dissolve this species up in aqueous (water) solution, we get <mathjax>#2xxNa^+#</mathjax> ions, and <mathjax>#1xxS_2O_3^(2-)#</mathjax> ions IN SOLUTION, as well the hydrate molecules to float round in the water solution INDEPENDENTLY. </p> <p>If this is not clear, or if I have glossed over a step or made an assumption you do not follow, raise a query, and I or someone else will attempt to re-explain. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, at a guess, you are using <mathjax>#Na_2S_2O_35H_2O#</mathjax>........</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#Na_2S_2O_35H_2O#</mathjax> is the common laboratory reagent, this so-called pentahydrate forms large sugary crystals so it is easy and convenient to handle. The formula mass of this material is <mathjax>#248.18gmol^-1#</mathjax> (i.e. this represents the mass of the sodium, the sulfur, the oxygen, and the hydrogen atoms, i.e. INCLUDING the water molecules). So here a mass of <mathjax>#248.18g#</mathjax> of this stuff represents a given quantity (a mole) of such species.</p> <p>Now concentration is typically defined as the quotient:</p> <p><mathjax>#"Concentration"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Amount of substance (in moles)"/"Volume of Solution (in litres)"#</mathjax>, and thus has units <mathjax>#molL^-1#</mathjax>.</p> <p>So, given that we dissolve <mathjax>#25g#</mathjax> of the salt in <mathjax>#1L#</mathjax> of water (and I am making an educated(?) guess here), we have a concentration of.......</p> <p><mathjax>#"Concentration"=((25g)/(248.18gmol^-1))/(1L)=(0.100mol)/(1L)=0.100molL^-1.#</mathjax></p> <p>OR <mathjax>#0.100"N"#</mathjax> with respect to <mathjax>#Na_2S_2O_35H_2O#</mathjax>, i.e. the <mathjax>#"pentahydrate"#</mathjax>. We write <mathjax>#N#</mathjax> for <mathjax>#"normal"#</mathjax>, because formally we have a solution whose concentration with respect to <mathjax>#Na_2S_2O_3*5H_2O#</mathjax> is the same. Of course, when we dissolve this species up in aqueous (water) solution, we get <mathjax>#2xxNa^+#</mathjax> ions, and <mathjax>#1xxS_2O_3^(2-)#</mathjax> ions IN SOLUTION, as well the hydrate molecules to float round in the water solution INDEPENDENTLY. </p> <p>If this is not clear, or if I have glossed over a step or made an assumption you do not follow, raise a query, and I or someone else will attempt to re-explain. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A solution is prepared from #25g# of salt dissolved in #1L# of water. If the salt is an hydrate of sodium thiosulfate, how many water molecules are associated with this salt?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/solutions" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="405807" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-12T16:57:18" itemprop="dateCreated"> Apr 12, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, at a guess, you are using <mathjax>#Na_2S_2O_35H_2O#</mathjax>........</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#Na_2S_2O_35H_2O#</mathjax> is the common laboratory reagent, this so-called pentahydrate forms large sugary crystals so it is easy and convenient to handle. The formula mass of this material is <mathjax>#248.18gmol^-1#</mathjax> (i.e. this represents the mass of the sodium, the sulfur, the oxygen, and the hydrogen atoms, i.e. INCLUDING the water molecules). So here a mass of <mathjax>#248.18g#</mathjax> of this stuff represents a given quantity (a mole) of such species.</p> <p>Now concentration is typically defined as the quotient:</p> <p><mathjax>#"Concentration"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Amount of substance (in moles)"/"Volume of Solution (in litres)"#</mathjax>, and thus has units <mathjax>#molL^-1#</mathjax>.</p> <p>So, given that we dissolve <mathjax>#25g#</mathjax> of the salt in <mathjax>#1L#</mathjax> of water (and I am making an educated(?) guess here), we have a concentration of.......</p> <p><mathjax>#"Concentration"=((25g)/(248.18gmol^-1))/(1L)=(0.100mol)/(1L)=0.100molL^-1.#</mathjax></p> <p>OR <mathjax>#0.100"N"#</mathjax> with respect to <mathjax>#Na_2S_2O_35H_2O#</mathjax>, i.e. the <mathjax>#"pentahydrate"#</mathjax>. We write <mathjax>#N#</mathjax> for <mathjax>#"normal"#</mathjax>, because formally we have a solution whose concentration with respect to <mathjax>#Na_2S_2O_3*5H_2O#</mathjax> is the same. Of course, when we dissolve this species up in aqueous (water) solution, we get <mathjax>#2xxNa^+#</mathjax> ions, and <mathjax>#1xxS_2O_3^(2-)#</mathjax> ions IN SOLUTION, as well the hydrate molecules to float round in the water solution INDEPENDENTLY. </p> <p>If this is not clear, or if I have glossed over a step or made an assumption you do not follow, raise a query, and I or someone else will attempt to re-explain. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/405807" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-solution-solute-and-solvent-related"> How are solution, solute, and solvent related? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-solutions-become-saturated"> Why do solutions become saturated? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-temperature-affect-solutions"> How does temperature affect solutions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-a-solution-differ-from-a-colloid"> How does a solution differ from a colloid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/calculate-the-amount-of-1-m-naoh-aqueous-solution-needed-to-make-100-ml-of-0-5-m"> Calculate the amount of 1 M NaOH aqueous solution needed to make 100 mL of 0.5 M NaOH aqueous solution. </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-buffering-a-solution-change-the-solutions-behavior"> How does buffering a solution change the solutions behavior? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-benedict-s-solution-change-colour"> How does Benedict's solution change colour? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/describe-how-would-you-prepare-1-l-of-a-1-m-solution-of-sodium-chloride-the-gram"> Describe how would you prepare 1 L of a 1 M solution of sodium chloride. The gram formula weight... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-solutions-differ-from-suspensions"> How do solutions differ from suspensions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-a-solution-differ-from-a-compound"> How does a solution differ from a compound? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/solutions"> See all questions in Solutions </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1285 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A solution is prepared from #25g# of salt dissolved in #1L# of water. If the salt is an hydrate of sodium thiosulfate, how many water molecules are associated with this salt?	null
2,157	a9122227-6ddd-11ea-bacd-ccda262736ce	https://socratic.org/questions/a-bottle-of-calcium-bromide-contains-a-bromide-ion-concentration-of-0-10-mol-l-w	0.05 mol/L	start physical_unit 18 20 concentration mol/l qc_end physical_unit 7 8 11 12 concentration qc_end end	[{"type":"physical unit","value":"Concentration [OF] the calcium bromide [IN] mol/L"}]	[{"type":"physical unit","value":"0.05 mol/L"}]	[{"type":"physical unit","value":"Concentration [OF] bromide ion [=] \\pu{0.10 mol/L}"}]	<h1 class="questionTitle" itemprop="name">A bottle of calcium bromide contains a bromide ion concentration of 0.10 mol/L. What is the concentration of the calcium bromide?</h1>	null	0.05 mol/L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Calcium bromide speciates in aqueous solution according to the following equation.........</p> <p><mathjax>#CaBr_2(s) stackrel(H_2O)rarrCa^(2+) + 2Br^-#</mathjax></p> <p>And thus for every metal ion there are necessarily two bromide ions. </p> <p>Here by specification, </p> <p><mathjax>#[Br^-]=0.10molL^-1#</mathjax>, and thus <mathjax>#[Ca^(2+)]=1/2xx[Br^-]=1/2xx0.10molL^-1=0.050molL^-1#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#[CaBr_2]=0.050molL^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Calcium bromide speciates in aqueous solution according to the following equation.........</p> <p><mathjax>#CaBr_2(s) stackrel(H_2O)rarrCa^(2+) + 2Br^-#</mathjax></p> <p>And thus for every metal ion there are necessarily two bromide ions. </p> <p>Here by specification, </p> <p><mathjax>#[Br^-]=0.10molL^-1#</mathjax>, and thus <mathjax>#[Ca^(2+)]=1/2xx[Br^-]=1/2xx0.10molL^-1=0.050molL^-1#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A bottle of calcium bromide contains a bromide ion concentration of 0.10 mol/L. What is the concentration of the calcium bromide?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="432109" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-30T18:40:11" itemprop="dateCreated"> May 30, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#[CaBr_2]=0.050molL^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Calcium bromide speciates in aqueous solution according to the following equation.........</p> <p><mathjax>#CaBr_2(s) stackrel(H_2O)rarrCa^(2+) + 2Br^-#</mathjax></p> <p>And thus for every metal ion there are necessarily two bromide ions. </p> <p>Here by specification, </p> <p><mathjax>#[Br^-]=0.10molL^-1#</mathjax>, and thus <mathjax>#[Ca^(2+)]=1/2xx[Br^-]=1/2xx0.10molL^-1=0.050molL^-1#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/432109" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? 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</a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-3-hydrogen-peroxide"> What is the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2554 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A bottle of calcium bromide contains a bromide ion concentration of 0.10 mol/L. What is the concentration of the calcium bromide?	null
2,158	aa45197a-6ddd-11ea-ae47-ccda262736ce	https://socratic.org/questions/how-would-you-express-tin-iv-oxide-as-a-chemical-formula	SnO2	start chemical_formula qc_end substance 4 6 qc_end end	[{"type":"other","value":"Chemical Formula [OF] Tin (IV) oxide [IN] default"}]	[{"type":"chemical equation","value":"SnO2"}]	[{"type":"substance name","value":"Tin (IV) oxide"}]	<h1 class="questionTitle" itemprop="name">How would you express Tin (IV) oxide as a chemical formula?</h1>	null	SnO2	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We know oxides are <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a> made of a metal, and oxygen.</p> <p>Oxygen always has a <mathjax>#-2#</mathjax> charge in these compounds, and since this compound has a metal with <mathjax>#+4#</mathjax> charge, it takes two oxygens to balance the charge of one metal atom.</p> <p>The symbol for tin is <mathjax>#Sn#</mathjax> (after its latin name, Stannum), so we just put them together:</p> <p><mathjax>#SnO_2#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#SnO_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We know oxides are <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a> made of a metal, and oxygen.</p> <p>Oxygen always has a <mathjax>#-2#</mathjax> charge in these compounds, and since this compound has a metal with <mathjax>#+4#</mathjax> charge, it takes two oxygens to balance the charge of one metal atom.</p> <p>The symbol for tin is <mathjax>#Sn#</mathjax> (after its latin name, Stannum), so we just put them together:</p> <p><mathjax>#SnO_2#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How would you express Tin (IV) oxide as a chemical formula?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/determining-formula-and-molar-masses" itemprop="url"> <span class="breadcrumb" itemprop="title">Determining Formula</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="386145" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/lovecraft"><img alt="" class="" src="https://profilepictures.socratic.org/yRsInkqBQENj1w6bu77a_tumblrmireiwDbf71rz7ozto1400.gif" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/lovecraft"> Lovecraft </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-04T01:48:31" itemprop="dateCreated"> Mar 4, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#SnO_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We know oxides are <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a> made of a metal, and oxygen.</p> <p>Oxygen always has a <mathjax>#-2#</mathjax> charge in these compounds, and since this compound has a metal with <mathjax>#+4#</mathjax> charge, it takes two oxygens to balance the charge of one metal atom.</p> <p>The symbol for tin is <mathjax>#Sn#</mathjax> (after its latin name, Stannum), so we just put them together:</p> <p><mathjax>#SnO_2#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/386145" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a 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found to contain 40.00% carbon,... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/do-i-need-to-know-the-number-of-moles-of-each-element-to-determine-the-formula-o"> Do I need to know the number of moles of each element to determine the formula of the compound? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/determining-formula-and-molar-masses"> See all questions in Determining Formula </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 6879 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How would you express Tin (IV) oxide as a chemical formula?	null
2,159	a912a090-6ddd-11ea-b814-ccda262736ce	https://socratic.org/questions/58d35836b72cff61dbd6d61f	2.00 L	start physical_unit 6 6 volume l qc_end physical_unit 6 6 4 5 molarity qc_end end	[{"type":"physical unit","value":"Volume [OF] solution [IN] L"}]	[{"type":"physical unit","value":"2.00 L"}]	[{"type":"physical unit","value":"Mole [OF] solute [=] \\pu{3 mol}"},{"type":"physical unit","value":"Molarity [OF] solution [=] \\pu{1.5 mol/L}"}]	<h1 class="questionTitle" itemprop="name">What volume of a #1.5molL^-1# solution is required to deliver a #3.0*mol# quantity of solute?</h1>	null	2.00 L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Look at the problem dimensionally:</p> <p>we know that <mathjax>#"Moles of solute"/"Volume of solution"=1.5molL^-1#</mathjax></p> <p>So <mathjax>#"Moles of solute"-="Volume of solution"xx1.5molL^-1#</mathjax></p> <p>OR <mathjax>#"Volume of solution"="Moles of solute"/(1.5molL^-1)#</mathjax></p> <p><mathjax>#=(3.0cancel(mol))/(1.5cancel(mol)L^-1)=2L#</mathjax></p> <p>We get an answer in <mathjax>#L#</mathjax> because <mathjax>#1/L^-1=1/(1/L)=L#</mathjax> as required. </p> <p>In order to use these quotients, you have to remember the basic definition:</p> <p><mathjax>#"Concentration"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Moles of solute (mol)"/"Volume of solution (L)"#</mathjax>; and thus <mathjax>#"concentration"#</mathjax> is commonly quoted with units of <mathjax>#mol*L^-1#</mathjax>.</p> <p>Capisce?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2.0L#</mathjax> of solution are required. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Look at the problem dimensionally:</p> <p>we know that <mathjax>#"Moles of solute"/"Volume of solution"=1.5molL^-1#</mathjax></p> <p>So <mathjax>#"Moles of solute"-="Volume of solution"xx1.5molL^-1#</mathjax></p> <p>OR <mathjax>#"Volume of solution"="Moles of solute"/(1.5molL^-1)#</mathjax></p> <p><mathjax>#=(3.0cancel(mol))/(1.5cancel(mol)L^-1)=2L#</mathjax></p> <p>We get an answer in <mathjax>#L#</mathjax> because <mathjax>#1/L^-1=1/(1/L)=L#</mathjax> as required. </p> <p>In order to use these quotients, you have to remember the basic definition:</p> <p><mathjax>#"Concentration"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Moles of solute (mol)"/"Volume of solution (L)"#</mathjax>; and thus <mathjax>#"concentration"#</mathjax> is commonly quoted with units of <mathjax>#molL^-1#</mathjax>.</p> <p>Capisce?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What volume of a #1.5molL^-1# solution is required to deliver a #3.0mol# quantity of solute?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="395239" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-23T06:53:08" itemprop="dateCreated"> Mar 23, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2.0L#</mathjax> of solution are required. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Look at the problem dimensionally:</p> <p>we know that <mathjax>#"Moles of solute"/"Volume of solution"=1.5molL^-1#</mathjax></p> <p>So <mathjax>#"Moles of solute"-="Volume of solution"xx1.5molL^-1#</mathjax></p> <p>OR <mathjax>#"Volume of solution"="Moles of solute"/(1.5molL^-1)#</mathjax></p> <p><mathjax>#=(3.0cancel(mol))/(1.5cancel(mol)L^-1)=2L#</mathjax></p> <p>We get an answer in <mathjax>#L#</mathjax> because <mathjax>#1/L^-1=1/(1/L)=L#</mathjax> as required. </p> <p>In order to use these quotients, you have to remember the basic definition:</p> <p><mathjax>#"Concentration"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Moles of solute (mol)"/"Volume of solution (L)"#</mathjax>; and thus <mathjax>#"concentration"#</mathjax> is commonly quoted with units of <mathjax>#mol*L^-1#</mathjax>.</p> <p>Capisce?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/395239" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="395284" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/simon-moore"><img alt="" class="" src="https://profilepictures.socratic.org/0ztdJJ7RCWUlBSPeGa9N_6EB6CADA-35F5-4BAA-9B66-9D6F64A622BA.jpeg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/simon-moore"> Simon Moore </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-23T09:14:31" itemprop="dateCreated"> Mar 23, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>2 litres.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To actually work it out, use the simple relationship <mathjax>#M = n/V#</mathjax></p> <p>Where M is <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> (or concentration) in moles per <mathjax>#dm^3#</mathjax> (or moles per litre, which is numerically identical), n is the number of moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a>, and V is the volume of solution in <mathjax>#dm^3#</mathjax> (or litres, which are numerically identical).</p> <p>Then simply rearrange for V, so <mathjax>#V = n/M#</mathjax> and plug in the numbers:</p> <p><mathjax>#V = n/M = 3/1.5 = 2#</mathjax> litres</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/395284" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" 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2,160	ad0ada5a-6ddd-11ea-9470-ccda262736ce	https://socratic.org/questions/a-mole-of-sulfur-trioxide-molecules-contains-how-many-oxygen-atoms	1.81 × 10^24	start physical_unit 9 10 number none qc_end end	[{"type":"physical unit","value":"Number [OF] oxygen atoms"}]	[{"type":"physical unit","value":"1.81 × 10^24"}]	[{"type":"physical unit","value":"Mole [OF] sulfur trioxide molecules [=] \\pu{1 mole}"}]	<h1 class="questionTitle" itemprop="name">A mole of sulfur trioxide molecules contains how many oxygen atoms? </h1>	null	1.81 × 10^24	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Where <mathjax>#N_A-="Avogadro's number"-=6.022xx10^23mol^-1#</mathjax>.</p> <p>And so if we gots a mole of sulfur trioxide molecules we gots <mathjax>#3molxx6.022xx10^23mol^-1#</mathjax> <mathjax>#"oxygen atoms"#</mathjax>...</p> <p>i.e. <mathjax>#18.066xx10^23"oxygen atoms.."#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, <mathjax>#3xxN_A#</mathjax> <mathjax>#"oxygen atoms..."#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Where <mathjax>#N_A-="Avogadro's number"-=6.022xx10^23mol^-1#</mathjax>.</p> <p>And so if we gots a mole of sulfur trioxide molecules we gots <mathjax>#3molxx6.022xx10^23mol^-1#</mathjax> <mathjax>#"oxygen atoms"#</mathjax>...</p> <p>i.e. <mathjax>#18.066xx10^23"oxygen atoms.."#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A mole of sulfur trioxide molecules contains how many oxygen atoms? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="645368" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-08-03T18:49:08" itemprop="dateCreated"> Aug 3, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, <mathjax>#3xxN_A#</mathjax> <mathjax>#"oxygen atoms..."#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Where <mathjax>#N_A-="Avogadro's number"-=6.022xx10^23mol^-1#</mathjax>.</p> <p>And so if we gots a mole of sulfur trioxide molecules we gots <mathjax>#3molxx6.022xx10^23mol^-1#</mathjax> <mathjax>#"oxygen atoms"#</mathjax>...</p> <p>i.e. <mathjax>#18.066xx10^23"oxygen atoms.."#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/645368" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? 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2,161	a9eca5cb-6ddd-11ea-870c-ccda262736ce	https://socratic.org/questions/a-gas-occupies-11-2-liters-at-860-atm-what-is-the-pressure-if-the-volume-becomes	0.64 atm	start physical_unit 1 1 pressure atm qc_end physical_unit 1 1 6 7 pressure qc_end physical_unit 1 1 3 4 volume qc_end physical_unit 1 1 16 17 volume qc_end end	[{"type":"physical unit","value":"Pressure2 [OF] the gas [IN] atm"}]	[{"type":"physical unit","value":"0.64 atm"}]	[{"type":"physical unit","value":"Pressure1 [OF] the gas [=] \\pu{0.860 atm}"},{"type":"physical unit","value":"Volume1 [OF] the gas [=] \\pu{11.2 liters}"},{"type":"physical unit","value":"Volume2 [OF] the gas [=] \\pu{15.0 L}"}]	<h1 class="questionTitle" itemprop="name">A gas occupies 11.2 liters at .860 atm. What is the pressure if the volume becomes 15.0 L?</h1>	null	0.64 atm	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#P_2#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(P_1V_1)/V_2#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(0.860atmxx11.2cancelL)/(15.0cancelL)#</mathjax> <mathjax>#~=0.6atm#</mathjax>.</p> <p><a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's Law</a> is useful in that given non-standard units, it can still be used provided that the units are consistent,</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#P_1V_1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#P_2V_2" at constant "T#</mathjax>. <a href="https://en.wikipedia.org/wiki/Boyle%27s_law" rel="nofollow">Boyle's Law</a> </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#P_2#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(P_1V_1)/V_2#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(0.860atmxx11.2cancelL)/(15.0cancelL)#</mathjax> <mathjax>#~=0.6atm#</mathjax>.</p> <p><a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's Law</a> is useful in that given non-standard units, it can still be used provided that the units are consistent,</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A gas occupies 11.2 liters at .860 atm. What is the pressure if the volume becomes 15.0 L?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/boyle-s-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Boyle's Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="275357" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-08T16:28:06" itemprop="dateCreated"> Jun 8, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#P_1V_1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#P_2V_2" at constant "T#</mathjax>. <a href="https://en.wikipedia.org/wiki/Boyle%27s_law" rel="nofollow">Boyle's Law</a> </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#P_2#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(P_1V_1)/V_2#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(0.860atmxx11.2cancelL)/(15.0cancelL)#</mathjax> <mathjax>#~=0.6atm#</mathjax>.</p> <p><a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's Law</a> is useful in that given non-standard units, it can still be used provided that the units are consistent,</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/275357" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-graph-boyles-law"> How do you graph Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-functional-groups-are-found-in-lipids"> What functional groups are found in lipids? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-k-constant-in-boyle-s-law"> Why is k constant in Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-boyle-s-law-graph-curved-1"> Why is Boyle's law graph curved? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-boyle-s-law-an-inverse-relationship-2"> Why is Boyle's law an inverse relationship? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-40-0-l-tank-of-ammonia-has-a-pressure-of-8-00-atm-calculate-the-volume-of-the-"> A 40.0 L tank of ammonia has a pressure of 8.00 atm. 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What is the pressure if the volume becomes 15.0 L?	null
2,162	acafd7a3-6ddd-11ea-8554-ccda262736ce	https://socratic.org/questions/what-is-the-formula-for-methanol	CH3OH	start chemical_formula qc_end substance 5 5 qc_end end	[{"type":"other","value":"Chemical Formula [OF] methanol [IN] default"}]	[{"type":"chemical equation","value":"CH3OH"}]	[{"type":"substance name","value":"Methanol"}]	<h1 class="questionTitle" itemprop="name">What is the formula for methanol? </h1>	null	CH3OH	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In methanol, one of the H atoms in a molecule of methane is replaced by a hydroxyl group, <mathjax>#"-OH"#</mathjax>.</p> <p><img alt="https://publications.nigms.nih.gov/chemhealth/health.htm" src="https://useruploads.socratic.org/AB3MG0AQqWyGc1ugdkcV_ch6_h2o.gif"/> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"CH"_3"OH"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In methanol, one of the H atoms in a molecule of methane is replaced by a hydroxyl group, <mathjax>#"-OH"#</mathjax>.</p> <p><img alt="https://publications.nigms.nih.gov/chemhealth/health.htm" src="https://useruploads.socratic.org/AB3MG0AQqWyGc1ugdkcV_ch6_h2o.gif"/> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the formula for methanol? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#covalent-bonds-and-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Covalent Bonds</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/covalent-bonds-and-formulas/covalent-formulas-and-nomenclature" itemprop="url"> <span class="breadcrumb" itemprop="title">Covalent Formulas and Nomenclature</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="327188" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-10-27T06:22:56" itemprop="dateCreated"> Oct 27, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"CH"_3"OH"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In methanol, one of the H atoms in a molecule of methane is replaced by a hydroxyl group, <mathjax>#"-OH"#</mathjax>.</p> <p><img alt="https://publications.nigms.nih.gov/chemhealth/health.htm" src="https://useruploads.socratic.org/AB3MG0AQqWyGc1ugdkcV_ch6_h2o.gif"/> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/327188" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-for-sugar"> What is the chemical formula for sugar? 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2,163	aceafc82-6ddd-11ea-bc4c-ccda262736ce	https://socratic.org/questions/what-is-the-maximum-amount-of-kci-that-can-dissolve-in-300-g-of-water-at-20-c	102.00 g	start physical_unit 6 6 mass g qc_end physical_unit 14 14 11 12 mass qc_end physical_unit 14 14 16 17 temperature qc_end physical_unit 6 6 23 26 solubility qc_end physical_unit 6 6 16 17 temperature qc_end end	[{"type":"physical unit","value":"Mass [OF] KCl [IN] g"}]	[{"type":"physical unit","value":"102.00 g"}]	[{"type":"physical unit","value":"Mass [OF] water [=] \\pu{300 g}"},{"type":"physical unit","value":"Temperature [OF] water [=] \\pu{20 ℃}"},{"type":"physical unit","value":"Solubility [OF] KCl [=] \\pu{34 g/100 g H2O}"},{"type":"physical unit","value":"Temperature [OF] KCl [=] \\pu{20 ℃}"}]	<h1 class="questionTitle" itemprop="name">What is the maximum amount of #"KCl"# that can dissolve in 300 g of water at 20°C?</h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>The solubility of <mathjax>#"KCl"#</mathjax> is 34 g/100 g <mathjax>#"H"_2"O"#</mathjax> at 20°C.</p></div> </h2> </div> </div>	102.00 g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The problem provides you with the <strong>solubility</strong> of potassium chloride, <mathjax>#"KCl"#</mathjax>, in water at <mathjax>#20^@"C"#</mathjax>, which is said to be equal to <mathjax>#"34 g / 100 g H"_2"O"#</mathjax>.</p> <p>This means that at <mathjax>#20^@"C"#</mathjax>, a <strong>saturated solution</strong> of potassium chloride will contain <mathjax>#"34 g"#</mathjax> of <em><strong>dissolved</strong></em> salt <strong>for every</strong> <mathjax>#"100 g"#</mathjax> of water. </p> <p>As you know, a saturated solution is a solution that holds the maximum amount of dissolved salt. Adding more solid to a <em>saturated solution</em> will cause the solid to remain <strong>undissolved</strong>. </p> <p>In your case, you can create a saturated solution of potassium chloride by dissolving <mathjax>#"34 g"#</mathjax> of salt in <mathjax>#"100 g"#</mathjax> of water at <mathjax>#20^@"C"#</mathjax>. </p> <p>Now, your goal here is to figure out how much potassium chloride can be dissolved in <mathjax>#"300 g"#</mathjax> of water at this temperature. To do that, use the given solubility as a conversion factor to take you from <em>grams of salt</em> to <em>grams of water</em></p> <blockquote> <p><mathjax>#300 color(red)(cancel(color(black)("g H"_2"O"))) * "34 g KCl"/(100color(red)(cancel(color(black)("g H"_2"O")))) = "102 g KCl"#</mathjax></p> </blockquote> <p>You should round this off to one <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig fig</a></strong>, since that is how many sig figs you have for the mass of water</p> <blockquote> <p><mathjax>#color(green)(\|bar(ul(color(white)(a/a)color(black)("mass of KCl " = " 100 g")color(white)(a/a)\|)))#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"100 g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The problem provides you with the <strong>solubility</strong> of potassium chloride, <mathjax>#"KCl"#</mathjax>, in water at <mathjax>#20^@"C"#</mathjax>, which is said to be equal to <mathjax>#"34 g / 100 g H"_2"O"#</mathjax>.</p> <p>This means that at <mathjax>#20^@"C"#</mathjax>, a <strong>saturated solution</strong> of potassium chloride will contain <mathjax>#"34 g"#</mathjax> of <em><strong>dissolved</strong></em> salt <strong>for every</strong> <mathjax>#"100 g"#</mathjax> of water. </p> <p>As you know, a saturated solution is a solution that holds the maximum amount of dissolved salt. Adding more solid to a <em>saturated solution</em> will cause the solid to remain <strong>undissolved</strong>. </p> <p>In your case, you can create a saturated solution of potassium chloride by dissolving <mathjax>#"34 g"#</mathjax> of salt in <mathjax>#"100 g"#</mathjax> of water at <mathjax>#20^@"C"#</mathjax>. </p> <p>Now, your goal here is to figure out how much potassium chloride can be dissolved in <mathjax>#"300 g"#</mathjax> of water at this temperature. To do that, use the given solubility as a conversion factor to take you from <em>grams of salt</em> to <em>grams of water</em></p> <blockquote> <p><mathjax>#300 color(red)(cancel(color(black)("g H"_2"O"))) * "34 g KCl"/(100color(red)(cancel(color(black)("g H"_2"O")))) = "102 g KCl"#</mathjax></p> </blockquote> <p>You should round this off to one <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig fig</a></strong>, since that is how many sig figs you have for the mass of water</p> <blockquote> <p><mathjax>#color(green)(\|bar(ul(color(white)(a/a)color(black)("mass of KCl " = " 100 g")color(white)(a/a)\|)))#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the maximum amount of #"KCl"# that can dissolve in 300 g of water at 20°C?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>The solubility of <mathjax>#"KCl"#</mathjax> is 34 g/100 g <mathjax>#"H"_2"O"#</mathjax> at 20°C.</p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/saturated-and-supersaturated-solutions" itemprop="url"> <span class="breadcrumb" itemprop="title">Saturated and Supersaturated Solutions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="299804" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-08-17T11:16:42" itemprop="dateCreated"> Aug 17, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"100 g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The problem provides you with the <strong>solubility</strong> of potassium chloride, <mathjax>#"KCl"#</mathjax>, in water at <mathjax>#20^@"C"#</mathjax>, which is said to be equal to <mathjax>#"34 g / 100 g H"_2"O"#</mathjax>.</p> <p>This means that at <mathjax>#20^@"C"#</mathjax>, a <strong>saturated solution</strong> of potassium chloride will contain <mathjax>#"34 g"#</mathjax> of <em><strong>dissolved</strong></em> salt <strong>for every</strong> <mathjax>#"100 g"#</mathjax> of water. </p> <p>As you know, a saturated solution is a solution that holds the maximum amount of dissolved salt. Adding more solid to a <em>saturated solution</em> will cause the solid to remain <strong>undissolved</strong>. </p> <p>In your case, you can create a saturated solution of potassium chloride by dissolving <mathjax>#"34 g"#</mathjax> of salt in <mathjax>#"100 g"#</mathjax> of water at <mathjax>#20^@"C"#</mathjax>. </p> <p>Now, your goal here is to figure out how much potassium chloride can be dissolved in <mathjax>#"300 g"#</mathjax> of water at this temperature. To do that, use the given solubility as a conversion factor to take you from <em>grams of salt</em> to <em>grams of water</em></p> <blockquote> <p><mathjax>#300 color(red)(cancel(color(black)("g H"_2"O"))) * "34 g KCl"/(100color(red)(cancel(color(black)("g H"_2"O")))) = "102 g KCl"#</mathjax></p> </blockquote> <p>You should round this off to one <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig fig</a></strong>, since that is how many sig figs you have for the mass of water</p> <blockquote> <p><mathjax>#color(green)(\|bar(ul(color(white)(a/a)color(black)("mass of KCl " = " 100 g")color(white)(a/a)\|)))#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/299804" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-saturated-solutions-at-equilibrium"> How are saturated solutions at equilibrium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-supersaturated-solutions-prepared"> How are supersaturated solutions prepared? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-you-identify-a-saturated-solution"> How can you identify a saturated solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-supersaturated-solutions-demonstrate-conservation-of-energy"> How do supersaturated solutions demonstrate conservation of energy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-make-saturated-solution-of-potassium-iodide"> How do you make saturated solution of potassium iodide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-make-saturated-solution-of-sodium-bicarbonate"> How do you make saturated solution of sodium bicarbonate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-an-example-of-a-saturation-practice-problem"> What is an example of a saturation practice problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-saturated-solution"> What is a saturated solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-an-example-of-a-saturated-solution-practice-problem"> What is an example of a saturated solution practice problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-common-mistakes-students-make-with-saturated-solutions"> What are some common mistakes students make with saturated solutions? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/saturated-and-supersaturated-solutions"> See all questions in Saturated and Supersaturated Solutions </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 51704 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the maximum amount of #"KCl"# that can dissolve in 300 g of water at 20°C?	The solubility of #"KCl"# is 34 g/100 g #"H"_2"O"# at 20°C.
2,164	aa92d4d2-6ddd-11ea-8f52-ccda262736ce	https://socratic.org/questions/how-many-water-molecules-are-in-4-0-moles-of-water	2.41 × 10^24	start physical_unit 2 3 number none qc_end physical_unit 2 2 6 7 mole qc_end end	[{"type":"physical unit","value":"Number [OF] water molecules"}]	[{"type":"physical unit","value":"2.41 × 10^24"}]	[{"type":"physical unit","value":"Mole [OF] water [=] \\pu{4.0 moles}"}]	<h1 class="questionTitle" itemprop="name">How many water molecules are in 4.0 moles of water?</h1>	null	2.41 × 10^24	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>All that you need to know here is that in order for a given sample of water to contain exactly <mathjax>#1#</mathjax> <strong>mole</strong> of water, it must contain <mathjax>#6.022 * 10^(23)#</mathjax> <strong>molecules</strong> of water. </p> <p>This is known as <strong>Avogadro's constant</strong> and essentially acts as the definition of a mole. If you have <mathjax>#6.022 * 10^(23)#</mathjax> molecules of water, then you can say for a fact that you have <mathjax>#1#</mathjax> <strong>mole</strong> of water. </p> <blockquote> <p><mathjax>#color(white)(overbrace(color(blue)(ul(color(black)("1 mole H"_2"O" = 6.022 * 10^(23) quad "molecules H"_2"O"))))^(color(red)(ul("Avogadro's constant")))#</mathjax></p> </blockquote> <p>Now, you know that your sample contains <mathjax>#4.0#</mathjax> <strong>moles</strong> of water. In order to find the number of molecules of water it contains, you can use Avogadro's constant as a <strong>conversion factor</strong>. </p> <p>You start with <em>moles</em> and you want to find the <em>number of molecules</em>, so set up the conversion factor like this.</p> <blockquote> <p><mathjax>#(6.022 * 10^(23) quad "molecules H"_2"O")/("1 mole H"_2"O")" "color(white)( (color(blue)(larr " what you need"))/(color(blue)(larr " what you have"))#</mathjax></p> </blockquote> <p>Finally, multiply the number of moles of water by the conversion factor to get</p> <blockquote> <p><mathjax>#4.0 color(red)(cancel(color(black)("moles H"_2"O"))) * (6.022 * 10^(23) quad "molecules H"_2"O")/(1color(red)(cancel(color(black)("mole H"_2"O")))) = color(darkgreen)(ul(color(black)(2.4 * 10^(24) quad "molecules H"_2"O")))#</mathjax></p> </blockquote> <p>The answer is rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the number of moles present in your sample. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2.4 * 10^(24)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>All that you need to know here is that in order for a given sample of water to contain exactly <mathjax>#1#</mathjax> <strong>mole</strong> of water, it must contain <mathjax>#6.022 * 10^(23)#</mathjax> <strong>molecules</strong> of water. </p> <p>This is known as <strong>Avogadro's constant</strong> and essentially acts as the definition of a mole. If you have <mathjax>#6.022 * 10^(23)#</mathjax> molecules of water, then you can say for a fact that you have <mathjax>#1#</mathjax> <strong>mole</strong> of water. </p> <blockquote> <p><mathjax>#color(white)(overbrace(color(blue)(ul(color(black)("1 mole H"_2"O" = 6.022 * 10^(23) quad "molecules H"_2"O"))))^(color(red)(ul("Avogadro's constant")))#</mathjax></p> </blockquote> <p>Now, you know that your sample contains <mathjax>#4.0#</mathjax> <strong>moles</strong> of water. In order to find the number of molecules of water it contains, you can use Avogadro's constant as a <strong>conversion factor</strong>. </p> <p>You start with <em>moles</em> and you want to find the <em>number of molecules</em>, so set up the conversion factor like this.</p> <blockquote> <p><mathjax>#(6.022 * 10^(23) quad "molecules H"_2"O")/("1 mole H"_2"O")" "color(white)( (color(blue)(larr " what you need"))/(color(blue)(larr " what you have"))#</mathjax></p> </blockquote> <p>Finally, multiply the number of moles of water by the conversion factor to get</p> <blockquote> <p><mathjax>#4.0 color(red)(cancel(color(black)("moles H"_2"O"))) * (6.022 * 10^(23) quad "molecules H"_2"O")/(1color(red)(cancel(color(black)("mole H"_2"O")))) = color(darkgreen)(ul(color(black)(2.4 * 10^(24) quad "molecules H"_2"O")))#</mathjax></p> </blockquote> <p>The answer is rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the number of moles present in your sample. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many water molecules are in 4.0 moles of water?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="584980" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-03-29T23:02:48" itemprop="dateCreated"> Mar 29, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2.4 * 10^(24)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>All that you need to know here is that in order for a given sample of water to contain exactly <mathjax>#1#</mathjax> <strong>mole</strong> of water, it must contain <mathjax>#6.022 * 10^(23)#</mathjax> <strong>molecules</strong> of water. </p> <p>This is known as <strong>Avogadro's constant</strong> and essentially acts as the definition of a mole. If you have <mathjax>#6.022 * 10^(23)#</mathjax> molecules of water, then you can say for a fact that you have <mathjax>#1#</mathjax> <strong>mole</strong> of water. </p> <blockquote> <p><mathjax>#color(white)(overbrace(color(blue)(ul(color(black)("1 mole H"_2"O" = 6.022 * 10^(23) quad "molecules H"_2"O"))))^(color(red)(ul("Avogadro's constant")))#</mathjax></p> </blockquote> <p>Now, you know that your sample contains <mathjax>#4.0#</mathjax> <strong>moles</strong> of water. In order to find the number of molecules of water it contains, you can use Avogadro's constant as a <strong>conversion factor</strong>. </p> <p>You start with <em>moles</em> and you want to find the <em>number of molecules</em>, so set up the conversion factor like this.</p> <blockquote> <p><mathjax>#(6.022 * 10^(23) quad "molecules H"_2"O")/("1 mole H"_2"O")" "color(white)( (color(blue)(larr " what you need"))/(color(blue)(larr " what you have"))#</mathjax></p> </blockquote> <p>Finally, multiply the number of moles of water by the conversion factor to get</p> <blockquote> <p><mathjax>#4.0 color(red)(cancel(color(black)("moles H"_2"O"))) * (6.022 * 10^(23) quad "molecules H"_2"O")/(1color(red)(cancel(color(black)("mole H"_2"O")))) = color(darkgreen)(ul(color(black)(2.4 * 10^(24) quad "molecules H"_2"O")))#</mathjax></p> </blockquote> <p>The answer is rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the number of moles present in your sample. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/584980" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 36123 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many water molecules are in 4.0 moles of water?	null
2,165	a9d11b99-6ddd-11ea-8f3a-ccda262736ce	https://socratic.org/questions/what-is-the-molarity-of-a-solution-formed-from-7-1-moles-bacl-2-dissolved-into-8	8.35 M	start physical_unit 5 6 molarity mol/l qc_end physical_unit 11 11 9 10 mole qc_end physical_unit 17 17 14 15 volume qc_end end	[{"type":"physical unit","value":"Molarity [OF] a solution [IN] M"}]	[{"type":"physical unit","value":"8.35 M"}]	[{"type":"physical unit","value":"Mole [OF] BaCl2 [=] \\pu{7.1 moles}"},{"type":"physical unit","value":"Volume [OF] water [=] \\pu{0.85 L}"}]	<h1 class="questionTitle" itemprop="name">What is the molarity of a solution formed from 7.1 moles #BaCl_2# dissolved into .85 L of water?</h1>	null	8.35 M	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>I am surprised that this question did not give a mass of barium chloride, and ask you to calculate the molar quantity for the concentration expression.</p> <p>Anyway, <mathjax>#"Concentration"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Moles of solute (moles)"/"Volume of solution (Litres)"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(7.1mol)/(0.85L)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??molL^-1#</mathjax></p> <p>The given concentration is with respect to <mathjax>#"moles of barium sulfate per litre"#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Over <mathjax>#8#</mathjax> <mathjax>#molL^-1#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>I am surprised that this question did not give a mass of barium chloride, and ask you to calculate the molar quantity for the concentration expression.</p> <p>Anyway, <mathjax>#"Concentration"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Moles of solute (moles)"/"Volume of solution (Litres)"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(7.1mol)/(0.85L)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??mol*L^-1#</mathjax></p> <p>The given concentration is with respect to <mathjax>#"moles of barium sulfate per litre"#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the molarity of a solution formed from 7.1 moles #BaCl_2# dissolved into .85 L of water?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="298382" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-08-13T07:41:44" itemprop="dateCreated"> Aug 13, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Over <mathjax>#8#</mathjax> <mathjax>#molL^-1#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>I am surprised that this question did not give a mass of barium chloride, and ask you to calculate the molar quantity for the concentration expression.</p> <p>Anyway, <mathjax>#"Concentration"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Moles of solute (moles)"/"Volume of solution (Litres)"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(7.1mol)/(0.85L)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??mol*L^-1#</mathjax></p> <p>The given concentration is with respect to <mathjax>#"moles of barium sulfate per litre"#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/298382" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-morality-be-used-as-a-conversion-factor"> How can molarity be 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the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1177 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the molarity of a solution formed from 7.1 moles #BaCl_2# dissolved into .85 L of water?	null
2,166	aa71b8ba-6ddd-11ea-9830-ccda262736ce	https://socratic.org/questions/an-unknown-compound-has-the-formula-c-xh-yo-z-you-burn-0-1523-g-of-the-compound-	C4H8O	start chemical_formula qc_end physical_unit 12 13 9 10 mass qc_end physical_unit 19 19 16 17 mass qc_end physical_unit 24 24 21 22 mass qc_end c_other OTHER qc_end end	[{"type":"other","value":"Chemical Formula [OF] the compound [IN] empirical"}]	[{"type":"chemical equation","value":"C4H8O"}]	[{"type":"physical unit","value":"Mass [OF] the compound [=] \\pu{0.1523 g}"},{"type":"physical unit","value":"Mass [OF] CO2 [=] \\pu{0.3718 g}"},{"type":"physical unit","value":"Mass [OF] H2O [=] \\pu{0.1522 g}"},{"type":"other","value":"The compound has the formula CxHyOz."}]	<h1 class="questionTitle" itemprop="name">An unknown compound has the formula #C_xH_yO_z#. You burn 0.1523 g of the compound and isolate 0.3718 g of #CO_2# and 0.1522 g of #H_2O#. What is the empirical formula of the compound?</h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>If the molar mass is 72.1 g/mol, what is the molecular formula?</p></div> </h2> </div> </div>	C4H8O	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First, work out the mass of each element that was present in the original compound. Carbon is always present as <mathjax>#CO_2#</mathjax> in the ratio (12.011 g / 44.0098 g), and hydrogen is always present as <mathjax>#H_2O#</mathjax> in the ratio (2.0158 g / 18.0152 g).</p> <p>So you need to work out the mass of carbon in 0.3718 g of <mathjax>#CO_2#</mathjax> and the mass of hydrogen in 0.1522 g of water..</p> <p>Carbon: 0.3718 x (12.011 / 44.0098) = 0.10147 g<br/> Hydrogen: 0.1522 x (2.0158 / 18.0152) = 0.01703 g</p> <p>You can determine the mass of oxygen by difference. 0.1523 - 0.10147 - 0.01703 = 0.0338 g<br/> . <br/> Next, convert each of these to numbers of moles:</p> <p>Carbon: 0.10147 / 12.011 = 0.00845 mol<br/> Hydrogen: 0.01703 / 1.0079 = 0.01689 mol<br/> Oxygen: 0.0338 / 15.994 = 0.002113 mol<br/> Remember that you're working out moles of hydrogen atoms here, not moles of molecular hydrogen gas. So use the atomic weight of hydrogen 1.0079.<br/> . <br/> Next, divide each number of moles by the lowest value, so that you get as close as possible to whole numbers.</p> <p>Carbon: 0.00845 / 0.002113 = 4<br/> Hydrogen: 0.001689 / 0.002113 = 8<br/> Oxygen: 0.002113/ 0.002113 = 1</p> <p>So the emprical formula is <mathjax>#C_4H_8O#</mathjax></p> <p>The molar mass is 72.1 g/mol - work out the mass of <mathjax>#C_4H_8O#</mathjax> - this is (12 x 4) + (8 x 1) + 16 = 72. Therefore the molecular formula is the same as the empirical..</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Empirical and molecular formulae are both <mathjax>#C_4H_8O#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First, work out the mass of each element that was present in the original compound. Carbon is always present as <mathjax>#CO_2#</mathjax> in the ratio (12.011 g / 44.0098 g), and hydrogen is always present as <mathjax>#H_2O#</mathjax> in the ratio (2.0158 g / 18.0152 g).</p> <p>So you need to work out the mass of carbon in 0.3718 g of <mathjax>#CO_2#</mathjax> and the mass of hydrogen in 0.1522 g of water..</p> <p>Carbon: 0.3718 x (12.011 / 44.0098) = 0.10147 g<br/> Hydrogen: 0.1522 x (2.0158 / 18.0152) = 0.01703 g</p> <p>You can determine the mass of oxygen by difference. 0.1523 - 0.10147 - 0.01703 = 0.0338 g<br/> . <br/> Next, convert each of these to numbers of moles:</p> <p>Carbon: 0.10147 / 12.011 = 0.00845 mol<br/> Hydrogen: 0.01703 / 1.0079 = 0.01689 mol<br/> Oxygen: 0.0338 / 15.994 = 0.002113 mol<br/> Remember that you're working out moles of hydrogen atoms here, not moles of molecular hydrogen gas. So use the atomic weight of hydrogen 1.0079.<br/> . <br/> Next, divide each number of moles by the lowest value, so that you get as close as possible to whole numbers.</p> <p>Carbon: 0.00845 / 0.002113 = 4<br/> Hydrogen: 0.001689 / 0.002113 = 8<br/> Oxygen: 0.002113/ 0.002113 = 1</p> <p>So the emprical formula is <mathjax>#C_4H_8O#</mathjax></p> <p>The molar mass is 72.1 g/mol - work out the mass of <mathjax>#C_4H_8O#</mathjax> - this is (12 x 4) + (8 x 1) + 16 = 72. Therefore the molecular formula is the same as the empirical..</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">An unknown compound has the formula #C_xH_yO_z#. You burn 0.1523 g of the compound and isolate 0.3718 g of #CO_2# and 0.1522 g of #H_2O#. What is the empirical formula of the compound?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>If the molar mass is 72.1 g/mol, what is the molecular formula?</p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="290106" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/simon-moore"><img alt="" class="" src="https://profilepictures.socratic.org/0ztdJJ7RCWUlBSPeGa9N_6EB6CADA-35F5-4BAA-9B66-9D6F64A622BA.jpeg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/simon-moore"> Simon Moore </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-20T12:48:28" itemprop="dateCreated"> Jul 20, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Empirical and molecular formulae are both <mathjax>#C_4H_8O#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First, work out the mass of each element that was present in the original compound. Carbon is always present as <mathjax>#CO_2#</mathjax> in the ratio (12.011 g / 44.0098 g), and hydrogen is always present as <mathjax>#H_2O#</mathjax> in the ratio (2.0158 g / 18.0152 g).</p> <p>So you need to work out the mass of carbon in 0.3718 g of <mathjax>#CO_2#</mathjax> and the mass of hydrogen in 0.1522 g of water..</p> <p>Carbon: 0.3718 x (12.011 / 44.0098) = 0.10147 g<br/> Hydrogen: 0.1522 x (2.0158 / 18.0152) = 0.01703 g</p> <p>You can determine the mass of oxygen by difference. 0.1523 - 0.10147 - 0.01703 = 0.0338 g<br/> . <br/> Next, convert each of these to numbers of moles:</p> <p>Carbon: 0.10147 / 12.011 = 0.00845 mol<br/> Hydrogen: 0.01703 / 1.0079 = 0.01689 mol<br/> Oxygen: 0.0338 / 15.994 = 0.002113 mol<br/> Remember that you're working out moles of hydrogen atoms here, not moles of molecular hydrogen gas. So use the atomic weight of hydrogen 1.0079.<br/> . <br/> Next, divide each number of moles by the lowest value, so that you get as close as possible to whole numbers.</p> <p>Carbon: 0.00845 / 0.002113 = 4<br/> Hydrogen: 0.001689 / 0.002113 = 8<br/> Oxygen: 0.002113/ 0.002113 = 1</p> <p>So the emprical formula is <mathjax>#C_4H_8O#</mathjax></p> <p>The molar mass is 72.1 g/mol - work out the mass of <mathjax>#C_4H_8O#</mathjax> - this is (12 x 4) + (8 x 1) + 16 = 72. Therefore the molecular formula is the same as the empirical..</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/290106" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="290120" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/dk-ch"><img alt="" class="" src="https://profilepictures.socratic.org/0aBlt69MSiWhfD1SEqb8_lotus.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/dk-ch"> P dilip_k </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-20T13:42:28" itemprop="dateCreated"> Jul 20, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_4H_8O#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>Balanced equation of cmbustion reaction</strong></p> <p><mathjax>#C_xH_yO_z+(x+y/4-z/2)O_2->xCO_2+y/2H_2O#</mathjax></p> <p><mathjax>#"No.of moles of "C_xH_yO_z " reacted"#</mathjax></p> <p><mathjax>#="its mass"/"Its molar mass"=(0.1523g)/(72.1g/"mol")=0.1523/72.1"mol"#</mathjax></p> <p><mathjax>#"No.of moles of "CO_2" formed"#</mathjax></p> <p><mathjax>#="its mass"/"Its molar mass"=(0.3718g)/(44g/"mol")=0.3718/44mol#</mathjax></p> <p><mathjax>#"No.of moles of "H_2O" formed"#</mathjax></p> <p><mathjax>#="its mass"/"Its molar mass"=(0.1522g)/(18g/"mol")=0.1522/18mol#</mathjax></p> <p>By the balanced equation 1 mole of the compound produces x moles <mathjax>#CO_2#</mathjax> and <mathjax>#y/2" moles "H_2O#</mathjax></p> <p>Hence <mathjax>#0.1523/72.1"mol"#</mathjax> compound will produce <mathjax>#0.1523/72.1x" mol "CO_2#</mathjax></p> <p><mathjax>#:.0.1523/72.1x=0.3718/44#</mathjax></p> <p><mathjax>#=>x=0.3718/4472.1/0.1523~~4#</mathjax></p> <p>Again <mathjax>#0.1523/72.1"mol"#</mathjax> <br/> compound will produce <mathjax>#0.1523/72.1y/2" mol "H_2O#</mathjax></p> <p>So<br/> <mathjax>#0.1523/72.1y/2=0.1522/18#</mathjax></p> <p><mathjax>#=>y=0.1522/18(72.12)/0.1533~~8#</mathjax></p> <p>Finally </p> <p><mathjax>#"Molar mass of "C_xH_yO_z=72.1#</mathjax></p> <p><mathjax>#=>12x+y+16z=72.1#</mathjax></p> <p><mathjax>#=>124+8+16z=72.1#</mathjax></p> <p><mathjax>#z=1#</mathjax></p> <p>Hence both empirical and molecular formula of the compound is<mathjax># C_4H_8O#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/290120" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? 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You burn 0.1523 g of the compound and isolate 0.3718 g of #CO_2# and 0.1522 g of #H_2O#. What is the empirical formula of the compound?	If the molar mass is 72.1 g/mol, what is the molecular formula?
2,167	ac572d7e-6ddd-11ea-a313-ccda262736ce	https://socratic.org/questions/the-equilibrium-constant-for-the-reaction-pcl-5-rightleftharpoons-pcl-3-cl-2-is-	0.03 atmospheric	start physical_unit 8 8 partial_pressure atm qc_end chemical_equation 6 10 qc_end physical_unit 4 5 12 12 equilibrium_constant_k qc_end physical_unit 6 6 24 25 pressure qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Partial pressure [OF] PCl3 [IN] atmospheric"}]	[{"type":"physical unit","value":"0.03 atmospheric"}]	[{"type":"chemical equation","value":"PCl5 <=> PCl3 + Cl2"},{"type":"physical unit","value":"Equilibrium constant [OF] the reaction [=] \\pu{0.0121}"},{"type":"physical unit","value":"Pressure [OF] PCl5 [=] \\pu{0.123 atmospheric}"},{"type":"other","value":"At equilibrium."}]	<h1 class="questionTitle" itemprop="name">The equilibrium constant for the reaction: #PCl_5 rightleftharpoons PCl_3 + Cl_2# is 0.0121. A vessel is charged with #PCl_5#, giving an initial pressure of 0.123 atmospheric. How do you calculate the partial pressure of #PCl_3# at equilibrium?</h1>	null	0.03 atmospheric	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#K_p=(P_(PCl_3)P_(Cl_2))/P_(PCl_5)=0.0121#</mathjax></p> <p>Initially, <mathjax>#P_(PCl_5)=0.123atm#</mathjax>, if a quantity <mathjax>#x#</mathjax> dissociates, then,</p> <p><mathjax>#K_P=0.0121=x^2/(0.123-x)#</mathjax></p> <p>(I have assumed that the quoted equilibrium constant is <mathjax>#K_P#</mathjax> not <mathjax>#K_c#</mathjax>. And if I am wrong, I am wrong).</p> <p>Now the given <mathjax>#K_P#</mathjax> expression is a quadratic in <mathjax>#x#</mathjax>. We will assume that <mathjax>#0.123-x~=0.123#</mathjax>.</p> <p>Thus <mathjax>#x_1=sqrt(0.0121xx0.123)=0.0386atm#</mathjax>. This result is indeed small compared to <mathjax>#0.123#</mathjax>, but we will recycle it to give a second approximation:</p> <p><mathjax>#x_2=0.0319atm#</mathjax></p> <p><mathjax>#x_3=0.0332atm#</mathjax> (the result is converging)</p> <p><mathjax>#x_4=0.0330atm#</mathjax> and finally,</p> <p><mathjax>#x_5=0.0330atm#</mathjax></p> <p>And thus <mathjax>#P_(PCl_3)=P_(Cl_2)=0.0330atm;#</mathjax> <mathjax>#P_(PCl_5)=(0.123-0.0330)atm=0.0900*atm#</mathjax>.</p> <p>Given the circumstances of the reaction, I think I am quite justified in assuming that I was given <mathjax>#K_p#</mathjax>, and not <mathjax>#K_c#</mathjax> in the boundary conditions of the problem. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#PCl_5(g) rightleftharpoons PCl_3(g) + Cl_2(g)#</mathjax></p> <p>At equilibrium, <mathjax>#P_(PCl_3)=P_(Cl_2)=0.0330atm#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#K_p=(P_(PCl_3)P_(Cl_2))/P_(PCl_5)=0.0121#</mathjax></p> <p>Initially, <mathjax>#P_(PCl_5)=0.123atm#</mathjax>, if a quantity <mathjax>#x#</mathjax> dissociates, then,</p> <p><mathjax>#K_P=0.0121=x^2/(0.123-x)#</mathjax></p> <p>(I have assumed that the quoted equilibrium constant is <mathjax>#K_P#</mathjax> not <mathjax>#K_c#</mathjax>. And if I am wrong, I am wrong).</p> <p>Now the given <mathjax>#K_P#</mathjax> expression is a quadratic in <mathjax>#x#</mathjax>. We will assume that <mathjax>#0.123-x~=0.123#</mathjax>.</p> <p>Thus <mathjax>#x_1=sqrt(0.0121xx0.123)=0.0386atm#</mathjax>. This result is indeed small compared to <mathjax>#0.123#</mathjax>, but we will recycle it to give a second approximation:</p> <p><mathjax>#x_2=0.0319atm#</mathjax></p> <p><mathjax>#x_3=0.0332atm#</mathjax> (the result is converging)</p> <p><mathjax>#x_4=0.0330atm#</mathjax> and finally,</p> <p><mathjax>#x_5=0.0330atm#</mathjax></p> <p>And thus <mathjax>#P_(PCl_3)=P_(Cl_2)=0.0330atm;#</mathjax> <mathjax>#P_(PCl_5)=(0.123-0.0330)atm=0.0900atm#</mathjax>.</p> <p>Given the circumstances of the reaction, I think I am quite justified in assuming that I was given <mathjax>#K_p#</mathjax>, and not <mathjax>#K_c#</mathjax> in the boundary conditions of the problem. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">The equilibrium constant for the reaction: #PCl_5 rightleftharpoons PCl_3 + Cl_2# is 0.0121. A vessel is charged with #PCl_5#, giving an initial pressure of 0.123 atmospheric. How do you calculate the partial pressure of #PCl_3# at equilibrium?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/measuring-gas-pressure" itemprop="url"> <span class="breadcrumb" itemprop="title">Measuring Gas Pressure</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="387299" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-06T09:20:57" itemprop="dateCreated"> Mar 6, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#PCl_5(g) rightleftharpoons PCl_3(g) + Cl_2(g)#</mathjax></p> <p>At equilibrium, <mathjax>#P_(PCl_3)=P_(Cl_2)=0.0330atm#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#K_p=(P_(PCl_3)P_(Cl_2))/P_(PCl_5)=0.0121#</mathjax></p> <p>Initially, <mathjax>#P_(PCl_5)=0.123atm#</mathjax>, if a quantity <mathjax>#x#</mathjax> dissociates, then,</p> <p><mathjax>#K_P=0.0121=x^2/(0.123-x)#</mathjax></p> <p>(I have assumed that the quoted equilibrium constant is <mathjax>#K_P#</mathjax> not <mathjax>#K_c#</mathjax>. And if I am wrong, I am wrong).</p> <p>Now the given <mathjax>#K_P#</mathjax> expression is a quadratic in <mathjax>#x#</mathjax>. We will assume that <mathjax>#0.123-x~=0.123#</mathjax>.</p> <p>Thus <mathjax>#x_1=sqrt(0.0121xx0.123)=0.0386atm#</mathjax>. This result is indeed small compared to <mathjax>#0.123#</mathjax>, but we will recycle it to give a second approximation:</p> <p><mathjax>#x_2=0.0319atm#</mathjax></p> <p><mathjax>#x_3=0.0332atm#</mathjax> (the result is converging)</p> <p><mathjax>#x_4=0.0330atm#</mathjax> and finally,</p> <p><mathjax>#x_5=0.0330atm#</mathjax></p> <p>And thus <mathjax>#P_(PCl_3)=P_(Cl_2)=0.0330atm;#</mathjax> <mathjax>#P_(PCl_5)=(0.123-0.0330)atm=0.0900atm#</mathjax>.</p> <p>Given the circumstances of the reaction, I think I am quite justified in assuming that I was given <mathjax>#K_p#</mathjax>, and not <mathjax>#K_c#</mathjax> in the boundary conditions of the problem. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/387299" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-used-to-measure-gas-pressure-in-a-closed-container"> What is used to measure gas pressure in a closed container? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-tool-is-used-to-measure-gas-pressure"> What tool is used to measure gas pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-units-are-used-to-measure-gas-pressure"> What units are used to measure gas pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-boyle-s-law"> What is Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-an-example-of-a-gas-pressure-practice-problem"> What is an example of a gas pressure practice problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-common-mistakes-students-make-when-measuring-gas-pressure"> What are some common mistakes students make when measuring gas pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-an-example-of-a-boyle-s-law-practice-problem"> What is an example of a Boyle's law practice problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-boyle-s-law-and-charles-law-differ-1"> How do Boyle's law and Charles' law differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-measure-gas-pressure"> How can I measure gas pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-boyle-s-law-affect-the-human-body"> How does Boyle's law affect the human body? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/measuring-gas-pressure"> See all questions in Measuring Gas Pressure </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1910 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	The equilibrium constant for the reaction: #PCl_5 rightleftharpoons PCl_3 + Cl_2# is 0.0121. A vessel is charged with #PCl_5#, giving an initial pressure of 0.123 atmospheric. How do you calculate the partial pressure of #PCl_3# at equilibrium?	null
2,168	aa9952d2-6ddd-11ea-93f8-ccda262736ce	https://socratic.org/questions/a-sample-of-gas-weighing-0-0286-g-occupies-a-volume-of-50-cm-3-at-76-cmhg-and-25	13.99 g/mol	start physical_unit 26 27 molar_mass g/mol qc_end physical_unit 1 3 5 6 mass qc_end physical_unit 1 3 11 12 volume qc_end physical_unit 1 3 14 15 pressure qc_end physical_unit 1 3 17 19 temperature qc_end end	[{"type":"physical unit","value":"Molar mass [OF] the gas [IN] g/mol"}]	[{"type":"physical unit","value":"13.99 g/mol"}]	[{"type":"physical unit","value":"Weight [OF] gas sample [=] \\pu{0.0286 g}"},{"type":"physical unit","value":"Volume [OF] gas sample [=] \\pu{50 cm^3}"},{"type":"physical unit","value":"Pressure [OF] gas sample [=] \\pu{76 cmHg}"},{"type":"physical unit","value":"Temperature [OF] gas sample [=] \\pu{25 degree centigrade}"}]	<h1 class="questionTitle" itemprop="name">A sample of gas weighing 0.0286 g occupies a volume of 50 #cm^3# at 76 cmHg. and 25 degree centigrade. What is the molar mass of the gas? </h1>	null	13.99 g/mol	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We can find the <em>molar mass</em> <mathjax>#MM#</mathjax> of this gas using the equation</p> <p><mathjax>#MM = (dRT)/P#</mathjax></p> <p>where</p> <ul> <li> <p><mathjax>#d#</mathjax> is the <em><a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a></em> of the gas, in <mathjax>#"g/L"#</mathjax></p> </li> <li> <p><mathjax>#R#</mathjax> is the <em>universal gas constant</em>, equal to <mathjax>#0.082057("L"•"atm")/("mol"•"K")#</mathjax></p> </li> <li> <p><mathjax>#T#</mathjax> is the <em>absolute temperature</em> of the gas, in <mathjax>#"K"#</mathjax></p> </li> <li> <p><mathjax>#P#</mathjax> is the pressure of the gas, in <mathjax>#"atm"#</mathjax></p> </li> </ul> <p>We need to convert some units to get where we need to be. Let's do the density first.</p> <p><mathjax>#1#</mathjax> <mathjax>#"L"#</mathjax> is equal to <mathjax>#1#</mathjax> <mathjax>#"dm"^3#</mathjax>, which is equal to <mathjax>#10^3#</mathjax> <mathjax>#"cm"^3#</mathjax>, so the density is</p> <p><mathjax>#((0.0286color(white)(l)"g")/(50cancel("cm"^3)))((10^3cancel("cm"^3))/(1cancel("dm"^3)))((1cancel("dm"^3))/(1color(white)(l)"L")) =color(red)(0.572#</mathjax> <mathjax>#color(red)("g/L"#</mathjax></p> <blockquote></blockquote> <p>Degrees centigrade is the same as degrees Celsius, so let's convert this to <mathjax>#"K"#</mathjax> by adding <mathjax>#273#</mathjax>:</p> <p><mathjax>#T = 25^"o""C" + 273 = color(green)(298#</mathjax> <mathjax>#color(green)("K"#</mathjax></p> <blockquote></blockquote> <p>Lastly, let's convert our pressure, which is in <em>centimeters</em> of mercury:</p> <p><mathjax>#76cancel("cm Hg")((10cancel("mm Hg"))/(1cancel("cm Hg")))((1color(white)(l)"atm")/(760cancel("mm Hg"))) = color(purple)(1#</mathjax> <mathjax>#color(purple)("atm"#</mathjax></p> <blockquote></blockquote> <p>Now that we have all our values, let's plug them into the equation:</p> <p><mathjax>#MM = ((color(red)(0.572"g"/"L"))(0.082057("L"•"atm")/("mol"•"K"))(color(green)(298"K")))/(color(purple)(1"atm"))#</mathjax></p> <p><mathjax># = color(blue)(14.0#</mathjax> <mathjax>#color(blue)("g/mol"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#MM = 14.0#</mathjax> <mathjax>#"g/mol"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We can find the <em>molar mass</em> <mathjax>#MM#</mathjax> of this gas using the equation</p> <p><mathjax>#MM = (dRT)/P#</mathjax></p> <p>where</p> <ul> <li> <p><mathjax>#d#</mathjax> is the <em><a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a></em> of the gas, in <mathjax>#"g/L"#</mathjax></p> </li> <li> <p><mathjax>#R#</mathjax> is the <em>universal gas constant</em>, equal to <mathjax>#0.082057("L"•"atm")/("mol"•"K")#</mathjax></p> </li> <li> <p><mathjax>#T#</mathjax> is the <em>absolute temperature</em> of the gas, in <mathjax>#"K"#</mathjax></p> </li> <li> <p><mathjax>#P#</mathjax> is the pressure of the gas, in <mathjax>#"atm"#</mathjax></p> </li> </ul> <p>We need to convert some units to get where we need to be. Let's do the density first.</p> <p><mathjax>#1#</mathjax> <mathjax>#"L"#</mathjax> is equal to <mathjax>#1#</mathjax> <mathjax>#"dm"^3#</mathjax>, which is equal to <mathjax>#10^3#</mathjax> <mathjax>#"cm"^3#</mathjax>, so the density is</p> <p><mathjax>#((0.0286color(white)(l)"g")/(50cancel("cm"^3)))((10^3cancel("cm"^3))/(1cancel("dm"^3)))((1cancel("dm"^3))/(1color(white)(l)"L")) =color(red)(0.572#</mathjax> <mathjax>#color(red)("g/L"#</mathjax></p> <blockquote></blockquote> <p>Degrees centigrade is the same as degrees Celsius, so let's convert this to <mathjax>#"K"#</mathjax> by adding <mathjax>#273#</mathjax>:</p> <p><mathjax>#T = 25^"o""C" + 273 = color(green)(298#</mathjax> <mathjax>#color(green)("K"#</mathjax></p> <blockquote></blockquote> <p>Lastly, let's convert our pressure, which is in <em>centimeters</em> of mercury:</p> <p><mathjax>#76cancel("cm Hg")((10cancel("mm Hg"))/(1cancel("cm Hg")))((1color(white)(l)"atm")/(760cancel("mm Hg"))) = color(purple)(1#</mathjax> <mathjax>#color(purple)("atm"#</mathjax></p> <blockquote></blockquote> <p>Now that we have all our values, let's plug them into the equation:</p> <p><mathjax>#MM = ((color(red)(0.572"g"/"L"))(0.082057("L"•"atm")/("mol"•"K"))(color(green)(298"K")))/(color(purple)(1"atm"))#</mathjax></p> <p><mathjax># = color(blue)(14.0#</mathjax> <mathjax>#color(blue)("g/mol"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A sample of gas weighing 0.0286 g occupies a volume of 50 #cm^3# at 76 cmHg. and 25 degree centigrade. What is the molar mass of the gas? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/ideal-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Ideal Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="444659" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/mrtas"><img alt="" class="" src="https://profilepictures.socratic.org/HY14X7r4S6AyDQgK2gwQ_IMG_0062.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/mrtas"> Nathan L. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-26T16:38:01" itemprop="dateCreated"> Jun 26, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#MM = 14.0#</mathjax> <mathjax>#"g/mol"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We can find the <em>molar mass</em> <mathjax>#MM#</mathjax> of this gas using the equation</p> <p><mathjax>#MM = (dRT)/P#</mathjax></p> <p>where</p> <ul> <li> <p><mathjax>#d#</mathjax> is the <em><a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a></em> of the gas, in <mathjax>#"g/L"#</mathjax></p> </li> <li> <p><mathjax>#R#</mathjax> is the <em>universal gas constant</em>, equal to <mathjax>#0.082057("L"•"atm")/("mol"•"K")#</mathjax></p> </li> <li> <p><mathjax>#T#</mathjax> is the <em>absolute temperature</em> of the gas, in <mathjax>#"K"#</mathjax></p> </li> <li> <p><mathjax>#P#</mathjax> is the pressure of the gas, in <mathjax>#"atm"#</mathjax></p> </li> </ul> <p>We need to convert some units to get where we need to be. Let's do the density first.</p> <p><mathjax>#1#</mathjax> <mathjax>#"L"#</mathjax> is equal to <mathjax>#1#</mathjax> <mathjax>#"dm"^3#</mathjax>, which is equal to <mathjax>#10^3#</mathjax> <mathjax>#"cm"^3#</mathjax>, so the density is</p> <p><mathjax>#((0.0286color(white)(l)"g")/(50cancel("cm"^3)))((10^3cancel("cm"^3))/(1cancel("dm"^3)))((1cancel("dm"^3))/(1color(white)(l)"L")) =color(red)(0.572#</mathjax> <mathjax>#color(red)("g/L"#</mathjax></p> <blockquote></blockquote> <p>Degrees centigrade is the same as degrees Celsius, so let's convert this to <mathjax>#"K"#</mathjax> by adding <mathjax>#273#</mathjax>:</p> <p><mathjax>#T = 25^"o""C" + 273 = color(green)(298#</mathjax> <mathjax>#color(green)("K"#</mathjax></p> <blockquote></blockquote> <p>Lastly, let's convert our pressure, which is in <em>centimeters</em> of mercury:</p> <p><mathjax>#76cancel("cm Hg")((10cancel("mm Hg"))/(1cancel("cm Hg")))((1color(white)(l)"atm")/(760cancel("mm Hg"))) = color(purple)(1#</mathjax> <mathjax>#color(purple)("atm"#</mathjax></p> <blockquote></blockquote> <p>Now that we have all our values, let's plug them into the equation:</p> <p><mathjax>#MM = ((color(red)(0.572"g"/"L"))(0.082057("L"•"atm")/("mol"•"K"))(color(green)(298"K")))/(color(purple)(1"atm"))#</mathjax></p> <p><mathjax># = color(blue)(14.0#</mathjax> <mathjax>#color(blue)("g/mol"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/444659" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-ideal-gas-constant"> How do you find the ideal gas constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-solve-ideal-gas-law-problems"> How do you solve ideal gas law problems? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-know-which-ideal-gas-constant-to-use"> How do you know which ideal gas constant to use? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ideal-gas-constant-for-butane"> What is the ideal gas constant for butane? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-ideal-gas-law-in-kelvin"> Why is ideal gas law in kelvin? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ideal-gas-constant-important"> Why is the ideal gas constant important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-di-electric-constant"> What is the di-electric constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-volume-l-will-0-20-mol-hi-occupy-at-300-k-and-100-0-kpa-r-8-314-kpa-l-k-mol"> What volume (L) will 0.20 mol HI occupy at 300 K and 100.0 kPa? R = 8.314 kPa L / (K mol) =... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-molar-mass-of-a-gas"> How do you calculate the molar mass of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-should-i-use-the-ideal-gas-law-and-not-the-combined-gas-law"> When should I use the ideal gas law and not the combined gas law? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/ideal-gas-law"> See all questions in Ideal Gas Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 10885 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A sample of gas weighing 0.0286 g occupies a volume of 50 #cm^3# at 76 cmHg. and 25 degree centigrade. What is the molar mass of the gas?	null
2,169	a8943564-6ddd-11ea-8315-ccda262736ce	https://socratic.org/questions/when-the-ionic-compound-nh-4cl-dissolves-in-water-it-breaks-into-one-ammonium-nh	0.40 moles	start physical_unit 31 31 mole mol qc_end chemical_equation 4 4 qc_end substance 7 7 qc_end chemical_equation 13 13 qc_end chemical_equation 17 17 qc_end physical_unit 4 4 21 22 mass qc_end end	[{"type":"physical unit","value":"Mole [OF] ions [IN] moles"}]	[{"type":"physical unit","value":"0.40 moles"}]	[{"type":"chemical equation","value":"NH4Cl"},{"type":"substance name","value":"water"},{"type":"chemical equation","value":"NH4+"},{"type":"chemical equation","value":"Cl-"},{"type":"physical unit","value":"Mass [OF] NH4Cl [=] \\pu{10.7 g}"}]	<h1 class="questionTitle" itemprop="name">When the ionic compound #NH_4Cl# dissolves in water, it breaks into one ammonium, #NH_4^+# and one chloride #Cl^-#. If you dissolved 10.7 g of #NH_4Cl# in water, how many moles of ions would be in the solution?</h1>	null	0.40 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Well, you know that <strong>one mole</strong> of <em>ammonium chloride</em>, <mathjax>#"NH"_4"Cl"#</mathjax>, dissociates completely in aqueous solution to form <strong>one mole</strong> of <em>ammonium cations</em>, <mathjax>#"NH"_4^(+)#</mathjax>, and <strong>one mole</strong> of <em>chloride anions</em>, <mathjax>#"Cl"^(-)#</mathjax>.</p> <blockquote> <p><mathjax>#"NH"_4"Cl"_text((aq]) -> "NH"_text(4(aq])^(+) + "Cl"_text((aq])^(-)#</mathjax></p> </blockquote> <p>This tells you that <em>regardless</em> of how many moles of ammonium chloride you dissolve in water, you will <strong>always</strong> get <strong>twice as many</strong> moles of ions. </p> <p>All you have to do now is to figure out how many moles of ammonium chloride you get in that <mathjax>#"10.7-g"#</mathjax> sample. To do that, use the compound's <em>molar mass</em></p> <blockquote> <p><mathjax>#10.7 color(red)(cancel(color(black)("g"))) * ("1 mole NH"_4"Cl")/(53.49 color(red)(cancel(color(black)("g")))) = "0.200 moles NH"_4"Cl"#</mathjax></p> </blockquote> <p>So, if <mathjax>#0.200#</mathjax> moles of ammonium chloride are dissociated in aqueous solution, you will get <mathjax>#0.200#</mathjax> moles of ammonium cations and <mathjax>#0.200#</mathjax> moles of chloride anions. </p> <p>Therefore, the resulting solution will contain a total of </p> <blockquote> <p><mathjax>#n_"total" = 0.200 + 0.200 = color(green)("0.400 moles ions")#</mathjax></p> </blockquote> <p><strong>SIDE NOTE</strong> <em>The ammonium cations act as a weak acid in aqueous solution</em>, <em>meaning that they react with water to form ammonia</em>, <mathjax>#"NH"_3#</mathjax>, <em>and hydronium ions</em>, <mathjax>#"H"_3"O"^(+)#</mathjax></p> <blockquote> <p><mathjax>#"NH"_text(4(aq])^(+) + "H"_2"O"_text((l]) rightleftharpoons "NH"_text(3(aq]) + "H"_3"O"_text((aq])^(+)#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"0.400 moles"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Well, you know that <strong>one mole</strong> of <em>ammonium chloride</em>, <mathjax>#"NH"_4"Cl"#</mathjax>, dissociates completely in aqueous solution to form <strong>one mole</strong> of <em>ammonium cations</em>, <mathjax>#"NH"_4^(+)#</mathjax>, and <strong>one mole</strong> of <em>chloride anions</em>, <mathjax>#"Cl"^(-)#</mathjax>.</p> <blockquote> <p><mathjax>#"NH"_4"Cl"_text((aq]) -> "NH"_text(4(aq])^(+) + "Cl"_text((aq])^(-)#</mathjax></p> </blockquote> <p>This tells you that <em>regardless</em> of how many moles of ammonium chloride you dissolve in water, you will <strong>always</strong> get <strong>twice as many</strong> moles of ions. </p> <p>All you have to do now is to figure out how many moles of ammonium chloride you get in that <mathjax>#"10.7-g"#</mathjax> sample. To do that, use the compound's <em>molar mass</em></p> <blockquote> <p><mathjax>#10.7 color(red)(cancel(color(black)("g"))) * ("1 mole NH"_4"Cl")/(53.49 color(red)(cancel(color(black)("g")))) = "0.200 moles NH"_4"Cl"#</mathjax></p> </blockquote> <p>So, if <mathjax>#0.200#</mathjax> moles of ammonium chloride are dissociated in aqueous solution, you will get <mathjax>#0.200#</mathjax> moles of ammonium cations and <mathjax>#0.200#</mathjax> moles of chloride anions. </p> <p>Therefore, the resulting solution will contain a total of </p> <blockquote> <p><mathjax>#n_"total" = 0.200 + 0.200 = color(green)("0.400 moles ions")#</mathjax></p> </blockquote> <p><strong>SIDE NOTE</strong> <em>The ammonium cations act as a weak acid in aqueous solution</em>, <em>meaning that they react with water to form ammonia</em>, <mathjax>#"NH"_3#</mathjax>, <em>and hydronium ions</em>, <mathjax>#"H"_3"O"^(+)#</mathjax></p> <blockquote> <p><mathjax>#"NH"_text(4(aq])^(+) + "H"_2"O"_text((l]) rightleftharpoons "NH"_text(3(aq]) + "H"_3"O"_text((aq])^(+)#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">When the ionic compound #NH_4Cl# dissolves in water, it breaks into one ammonium, #NH_4^+# and one chloride #Cl^-#. If you dissolved 10.7 g of #NH_4Cl# in water, how many moles of ions would be in the solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="201280" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-19T17:19:40" itemprop="dateCreated"> Dec 19, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"0.400 moles"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Well, you know that <strong>one mole</strong> of <em>ammonium chloride</em>, <mathjax>#"NH"_4"Cl"#</mathjax>, dissociates completely in aqueous solution to form <strong>one mole</strong> of <em>ammonium cations</em>, <mathjax>#"NH"_4^(+)#</mathjax>, and <strong>one mole</strong> of <em>chloride anions</em>, <mathjax>#"Cl"^(-)#</mathjax>.</p> <blockquote> <p><mathjax>#"NH"_4"Cl"_text((aq]) -> "NH"_text(4(aq])^(+) + "Cl"_text((aq])^(-)#</mathjax></p> </blockquote> <p>This tells you that <em>regardless</em> of how many moles of ammonium chloride you dissolve in water, you will <strong>always</strong> get <strong>twice as many</strong> moles of ions. </p> <p>All you have to do now is to figure out how many moles of ammonium chloride you get in that <mathjax>#"10.7-g"#</mathjax> sample. To do that, use the compound's <em>molar mass</em></p> <blockquote> <p><mathjax>#10.7 color(red)(cancel(color(black)("g"))) * ("1 mole NH"_4"Cl")/(53.49 color(red)(cancel(color(black)("g")))) = "0.200 moles NH"_4"Cl"#</mathjax></p> </blockquote> <p>So, if <mathjax>#0.200#</mathjax> moles of ammonium chloride are dissociated in aqueous solution, you will get <mathjax>#0.200#</mathjax> moles of ammonium cations and <mathjax>#0.200#</mathjax> moles of chloride anions. </p> <p>Therefore, the resulting solution will contain a total of </p> <blockquote> <p><mathjax>#n_"total" = 0.200 + 0.200 = color(green)("0.400 moles ions")#</mathjax></p> </blockquote> <p><strong>SIDE NOTE</strong> <em>The ammonium cations act as a weak acid in aqueous solution</em>, <em>meaning that they react with water to form ammonia</em>, <mathjax>#"NH"_3#</mathjax>, <em>and hydronium ions</em>, <mathjax>#"H"_3"O"^(+)#</mathjax></p> <blockquote> <p><mathjax>#"NH"_text(4(aq])^(+) + "H"_2"O"_text((l]) rightleftharpoons "NH"_text(3(aq]) + "H"_3"O"_text((aq])^(+)#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/201280" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 16752 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	When the ionic compound #NH_4Cl# dissolves in water, it breaks into one ammonium, #NH_4^+# and one chloride #Cl^-#. If you dissolved 10.7 g of #NH_4Cl# in water, how many moles of ions would be in the solution?	null
2,170	a9217877-6ddd-11ea-9883-ccda262736ce	https://socratic.org/questions/is-gas-volume-of-444-ml-at-273k-and-79-0-kpa-what-is-the-final-kelvin-temperatur	566 kelvin	start physical_unit 22 23 temperature k qc_end physical_unit 22 23 4 5 volume qc_end physical_unit 22 23 7 8 temperature qc_end physical_unit 22 23 10 11 pressure qc_end physical_unit 22 23 27 28 volume qc_end physical_unit 22 23 34 35 pressure qc_end end	[{"type":"physical unit","value":"Temperature2 [OF] the gas [IN] kelvin"}]	[{"type":"physical unit","value":"566 kelvin"}]	[{"type":"physical unit","value":"Volume1 [OF] the gas [=] \\pu{444 mL}"},{"type":"physical unit","value":"Temperature1 [OF] the gas [=] \\pu{273 K}"},{"type":"physical unit","value":"Pressure1 [OF] the gas [=] \\pu{79.0 kPa}"},{"type":"physical unit","value":"Volume2 [OF] the gas [=] \\pu{1880 mL}"},{"type":"physical unit","value":"Pressure2 [OF] the gas [=] \\pu{38.7 kPa}"}]	<h1 class="questionTitle" itemprop="name">Is gas volume of 444 mL at 273K and 79.0 kPa. What is the final kelvin temperature when the volume of the gas is changed to 1880 mL and the pressure changed to 38.7 kPa? </h1>	null	566 kelvin	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We're asked to calculate the final absolute (Kelvin) temperature of a gas system when it is subdued to known pressure and volume changes.</p> <p>To solve this problem, we can use the <em><a href="https://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">combined gas law</a></em>:</p> <p><mathjax>#(P_1V_1)/(T_1) = (P_2V_2)/(T_2)#</mathjax></p> <p>For this equation to work, the units have to be <em>consistent</em>; for example, we can't plug in two values for pressure if one is measured in <mathjax>#"kPa"#</mathjax> and the other in <mathjax>#"atm"#</mathjax>; the units must be the same. </p> <p>Since all the units are consistent, here, solving the problem is straightforward enough: we simply plug in the known variables and solve the equation for the final temperature, <mathjax>#T_2#</mathjax>:</p> <p><mathjax>#T_2 = (T_1P_2V_2)/(P_1V_1) = ((273"K")(38.7cancel("kPa"))(1880cancel("mL")))/((79.0cancel("kPa"))(444cancel("mL")))#</mathjax></p> <p><mathjax>#= color(red)(566"K"#</mathjax></p> <p>rounded to <mathjax>#3#</mathjax> <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a>, the number given in the problem.</p> <p>Thus, the final Kelvin temperature after the changes in pressure and volume is <mathjax>#566"K"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#566"K"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We're asked to calculate the final absolute (Kelvin) temperature of a gas system when it is subdued to known pressure and volume changes.</p> <p>To solve this problem, we can use the <em><a href="https://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">combined gas law</a></em>:</p> <p><mathjax>#(P_1V_1)/(T_1) = (P_2V_2)/(T_2)#</mathjax></p> <p>For this equation to work, the units have to be <em>consistent</em>; for example, we can't plug in two values for pressure if one is measured in <mathjax>#"kPa"#</mathjax> and the other in <mathjax>#"atm"#</mathjax>; the units must be the same. </p> <p>Since all the units are consistent, here, solving the problem is straightforward enough: we simply plug in the known variables and solve the equation for the final temperature, <mathjax>#T_2#</mathjax>:</p> <p><mathjax>#T_2 = (T_1P_2V_2)/(P_1V_1) = ((273"K")(38.7cancel("kPa"))(1880cancel("mL")))/((79.0cancel("kPa"))(444cancel("mL")))#</mathjax></p> <p><mathjax>#= color(red)(566"K"#</mathjax></p> <p>rounded to <mathjax>#3#</mathjax> <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a>, the number given in the problem.</p> <p>Thus, the final Kelvin temperature after the changes in pressure and volume is <mathjax>#566"K"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Is gas volume of 444 mL at 273K and 79.0 kPa. What is the final kelvin temperature when the volume of the gas is changed to 1880 mL and the pressure changed to 38.7 kPa? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/measuring-gas-pressure" itemprop="url"> <span class="breadcrumb" itemprop="title">Measuring Gas Pressure</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="432327" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/mrtas"><img alt="" class="" src="https://profilepictures.socratic.org/HY14X7r4S6AyDQgK2gwQ_IMG_0062.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/mrtas"> Nathan L. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-31T02:59:16" itemprop="dateCreated"> May 31, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#566"K"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We're asked to calculate the final absolute (Kelvin) temperature of a gas system when it is subdued to known pressure and volume changes.</p> <p>To solve this problem, we can use the <em><a href="https://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">combined gas law</a></em>:</p> <p><mathjax>#(P_1V_1)/(T_1) = (P_2V_2)/(T_2)#</mathjax></p> <p>For this equation to work, the units have to be <em>consistent</em>; for example, we can't plug in two values for pressure if one is measured in <mathjax>#"kPa"#</mathjax> and the other in <mathjax>#"atm"#</mathjax>; the units must be the same. </p> <p>Since all the units are consistent, here, solving the problem is straightforward enough: we simply plug in the known variables and solve the equation for the final temperature, <mathjax>#T_2#</mathjax>:</p> <p><mathjax>#T_2 = (T_1P_2V_2)/(P_1V_1) = ((273"K")(38.7cancel("kPa"))(1880cancel("mL")))/((79.0cancel("kPa"))(444cancel("mL")))#</mathjax></p> <p><mathjax>#= color(red)(566"K"#</mathjax></p> <p>rounded to <mathjax>#3#</mathjax> <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a>, the number given in the problem.</p> <p>Thus, the final Kelvin temperature after the changes in pressure and volume is <mathjax>#566"K"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/432327" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="432333" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-31T03:21:05" itemprop="dateCreated"> May 31, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The final temperature will be <mathjax>#"566 K"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This a question involving the <a href="https://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">Combined Gas Law</a>. You can know that this involves the Combined Gas Law, because the variables are pressure, volume, and temperature, and they are the variables in the Combined Gas Law. The equation used to solve questions involving the Combined Gas Law is:</p> <p><mathjax>#(P_1V_1)/T_1=(P_2V_2)/T_2#</mathjax></p> <p>Organize you data.</p> <p><strong>Known</strong></p> <p><mathjax>#P_1="79.0 kPa"#</mathjax></p> <p><mathjax>#V_1="444 mL"#</mathjax></p> <p><mathjax>#T_1="273 K"#</mathjax></p> <p><mathjax>#P_2="38.7 kPa"#</mathjax></p> <p><mathjax>#V_2="1880 mL"#</mathjax></p> <p><strong>Unknown:</strong> <mathjax>#T_2#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation above to isolate <mathjax>#T_2#</mathjax>. Insert the known data into the resulting equation and solve.</p> <p><mathjax>#T_2=(P_2V_2T_1)/(P_1V_1)#</mathjax></p> <p><mathjax>#T_2=(38.7color(red)cancel(color(black)("kPa"))xx1880color(red)cancel(color(black)("mL"))xx273"K")/(79.0color(red)cancel(color(black)("kPa"))xx444color(red)cancel(color(black)("mL")))="566 K"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/432333" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-used-to-measure-gas-pressure-in-a-closed-container"> What is used to measure gas pressure in a closed container? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-tool-is-used-to-measure-gas-pressure"> What tool is used to measure gas pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-units-are-used-to-measure-gas-pressure"> What units are used to measure gas pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-boyle-s-law"> What is Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-an-example-of-a-gas-pressure-practice-problem"> What is an example of a gas pressure practice problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-common-mistakes-students-make-when-measuring-gas-pressure"> What are some common mistakes students make when measuring gas pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-an-example-of-a-boyle-s-law-practice-problem"> What is an example of a Boyle's law practice problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-boyle-s-law-and-charles-law-differ-1"> How do Boyle's law and Charles' law differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-measure-gas-pressure"> How can I measure gas pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-boyle-s-law-affect-the-human-body"> How does Boyle's law affect the human body? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/measuring-gas-pressure"> See all questions in Measuring Gas Pressure </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 15940 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Is gas volume of 444 mL at 273K and 79.0 kPa. What is the final kelvin temperature when the volume of the gas is changed to 1880 mL and the pressure changed to 38.7 kPa?	null
2,171	a8fec6d8-6ddd-11ea-8866-ccda262736ce	https://socratic.org/questions/5835b1ceb72cff66c4835ca3	1.20 × 10^24	start physical_unit 2 3 number none qc_end physical_unit 12 13 8 9 mass qc_end end	[{"type":"physical unit","value":"Number [OF] oxygen atoms"}]	[{"type":"physical unit","value":"1.20 × 10^24"}]	[{"type":"physical unit","value":"Mass [OF] oxygen gas [=] \\pu{32 g}"}]	<h1 class="questionTitle" itemprop="name">How many oxygen atoms are there in a #32*g# mass of oxygen gas?</h1>	null	1.20 × 10^24	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And <mathjax>#N_A#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Avogadro's number"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#6.022xx10^23mol^-1#</mathjax></p> <p>Note that <mathjax>#N_A#</mathjax> oxygen atoms have a mass of <mathjax>#16.0g#</mathjax>.</p> <p>But <mathjax>#N_A#</mathjax> oxygen MOLECULES, i.e. dioxygen, have a mass of <mathjax>#32.0*g#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>There are <mathjax>#2xxN_A#</mathjax> oxygen atoms in a <mathjax>#32g#</mathjax> mass of dioxygen. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And <mathjax>#N_A#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Avogadro's number"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#6.022xx10^23mol^-1#</mathjax></p> <p>Note that <mathjax>#N_A#</mathjax> oxygen atoms have a mass of <mathjax>#16.0g#</mathjax>.</p> <p>But <mathjax>#N_A#</mathjax> oxygen MOLECULES, i.e. dioxygen, have a mass of <mathjax>#32.0g#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many oxygen atoms are there in a #32g# mass of oxygen gas?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="340935" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-11-23T19:58:43" itemprop="dateCreated"> Nov 23, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>There are <mathjax>#2xxN_A#</mathjax> oxygen atoms in a <mathjax>#32g#</mathjax> mass of dioxygen. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And <mathjax>#N_A#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Avogadro's number"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#6.022xx10^23mol^-1#</mathjax></p> <p>Note that <mathjax>#N_A#</mathjax> oxygen atoms have a mass of <mathjax>#16.0g#</mathjax>.</p> <p>But <mathjax>#N_A#</mathjax> oxygen MOLECULES, i.e. dioxygen, have a mass of <mathjax>#32.0*g#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/340935" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? 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</a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 7007 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many oxygen atoms are there in a #32*g# mass of oxygen gas?	null
2,172	a8405e42-6ddd-11ea-9f9e-ccda262736ce	https://socratic.org/questions/how-much-would-4-2-10-23-molecules-of-kso-4-weigh-in-grams	94.14 grams	start physical_unit 8 8 mass g qc_end end	[{"type":"physical unit","value":"Weight [OF] KSO4 [IN] grams"}]	[{"type":"physical unit","value":"94.14 grams"}]	[{"type":"physical unit","value":"Number [OF] KSO4 molecules [=] \\pu{4.2 × 10^23}"}]	<h1 class="questionTitle" itemprop="name"> How much would #4.2 * 10^23# molecules of #KSO_4# weigh in grams?</h1>	null	94.14 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>According to <a href="https://socratic.org/chemistry/the-behavior-of-gases/avogadro-s-law">Avogadro's law</a>,<br/> <mathjax>#6.023xx10^23#</mathjax> molecules of <mathjax>#KSO_4#</mathjax> weigh 135 grams.</p> <p><mathjax>#:.4.2xx10^23#</mathjax> molecules of <mathjax>#KSO_4#</mathjax> weigh <mathjax>#(135)/(6.023xx10^23)xx(4.2xx10^23)#</mathjax> grams,i.e. <mathjax>#94.139#</mathjax> grams. (Answer).</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Answer is 94.139 grams.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>According to <a href="https://socratic.org/chemistry/the-behavior-of-gases/avogadro-s-law">Avogadro's law</a>,<br/> <mathjax>#6.023xx10^23#</mathjax> molecules of <mathjax>#KSO_4#</mathjax> weigh 135 grams.</p> <p><mathjax>#:.4.2xx10^23#</mathjax> molecules of <mathjax>#KSO_4#</mathjax> weigh <mathjax>#(135)/(6.023xx10^23)xx(4.2xx10^23)#</mathjax> grams,i.e. <mathjax>#94.139#</mathjax> grams. (Answer).</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name"> How much would #4.2 * 10^23# molecules of #KSO_4# weigh in grams?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="336120" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/aditya-9"><img alt="" class="" src="https://profilepictures.socratic.org/JI8xltWvSDeHqZTzxqDb_25.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/aditya-9"> Aditya Banerjee. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-11-14T15:39:54" itemprop="dateCreated"> Nov 14, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Answer is 94.139 grams.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>According to <a href="https://socratic.org/chemistry/the-behavior-of-gases/avogadro-s-law">Avogadro's law</a>,<br/> <mathjax>#6.023xx10^23#</mathjax> molecules of <mathjax>#KSO_4#</mathjax> weigh 135 grams.</p> <p><mathjax>#:.4.2xx10^23#</mathjax> molecules of <mathjax>#KSO_4#</mathjax> weigh <mathjax>#(135)/(6.023xx10^23)xx(4.2xx10^23)#</mathjax> grams,i.e. <mathjax>#94.139#</mathjax> grams. (Answer).</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/336120" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1056 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How much would #4.2 * 10^23# molecules of #KSO_4# weigh in grams?	null
2,173	aa7c7492-6ddd-11ea-9733-ccda262736ce	https://socratic.org/questions/calculate-the-ph-at-which-mg-oh-2-begins-to-precipitate-from-a-solution-containi	9.00	start physical_unit 11 11 ph none qc_end physical_unit 15 15 13 14 molarity qc_end physical_unit 5 5 21 23 equilibrium_constant_k qc_end end	[{"type":"physical unit","value":"pH [OF] Mg(OH) solution"}]	[{"type":"physical unit","value":"9.00"}]	[{"type":"physical unit","value":"Molarity [OF] Mg^2+ [=] \\pu{0.1 M}"},{"type":"physical unit","value":"Ksp [OF] Mg(OH)2 [=] \\pu{1.0 x 10^(-11)}"}]	<h1 class="questionTitle" itemprop="name">Calculate the #pH# at which #Mg(OH)_2# begins to precipitate from a solution containing #0.1# #M# #Mg^(2+)# ions? #K_(sp)# for #Mg(OH)_2# = #1.0# x #10^-11#.</h1>	null	9.00	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that you need to use magnesium hydroxide's <a href="https://socratic.org/chemistry/chemical-equilibrium/ksp">solubility product constant</a> to determine what concentration of hydroxide anions, <mathjax>#"OH"^(-)#</mathjax>, would cause the solid to precipitate out of solution. </p> <p>As you know, the dissociation equilibrium for magnesium hydroxide looks like this </p> <blockquote> <p><mathjax>#"Mg"("OH")_text(2(s]) rightleftharpoons "Mg"_text((aq])^(2+) + color(red)(2)"OH"_text((aq])^(-)#</mathjax></p> </blockquote> <p>The solubility product constant, <mathjax>#K_(sp)#</mathjax>, will be equal to</p> <blockquote> <p><mathjax>#K_(sp) = ["Mg"^(2+)] * ["OH"^(-)]^color(red)(2)#</mathjax></p> </blockquote> <p>Rearrange to find the concentration of the hydroxide anions</p> <blockquote> <p><mathjax>#["OH"^(-)] = sqrt(K_(sp)/(["Mg"^(2+)]))#</mathjax></p> </blockquote> <p>Plug in your values to get</p> <blockquote> <p><mathjax>#["OH"^(-)] = sqrt((1.0 * 10^(-11))/0.1) = sqrt(1.0 * 10^(-10)) = 10^(-5)"M"#</mathjax></p> </blockquote> <p>As you know, you can use the concentration of hydroxide anions to find the solution's pOH</p> <blockquote> <p><mathjax>#color(blue)("pOH" = - log(["OH"]^(-)))#</mathjax></p> <p><mathjax>#"pOH" = - log(10^(-5)) = 5#</mathjax></p> </blockquote> <p>Finally, use the relationship that exists between pOH and <a href="http://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> at room temperature</p> <blockquote> <p><mathjax>#color(blue)("pOH " + " pH" = 14)#</mathjax></p> </blockquote> <p>to find the pH of the solution</p> <blockquote> <p><mathjax>#"pH" = 14 - 5 = color(green)(9)#</mathjax></p> </blockquote> <p>So, for pH values that are <strong>below</strong> <mathjax>#9#</mathjax>, the solution will be <em>unsaturated</em>. Once the pH of the solution becomes equal to <mathjax>#9#</mathjax>, the solution becomes <em>saturated</em> and the magnesium hydroxide starts to precipitate. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"pH" = 9#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that you need to use magnesium hydroxide's <a href="https://socratic.org/chemistry/chemical-equilibrium/ksp">solubility product constant</a> to determine what concentration of hydroxide anions, <mathjax>#"OH"^(-)#</mathjax>, would cause the solid to precipitate out of solution. </p> <p>As you know, the dissociation equilibrium for magnesium hydroxide looks like this </p> <blockquote> <p><mathjax>#"Mg"("OH")_text(2(s]) rightleftharpoons "Mg"_text((aq])^(2+) + color(red)(2)"OH"_text((aq])^(-)#</mathjax></p> </blockquote> <p>The solubility product constant, <mathjax>#K_(sp)#</mathjax>, will be equal to</p> <blockquote> <p><mathjax>#K_(sp) = ["Mg"^(2+)] * ["OH"^(-)]^color(red)(2)#</mathjax></p> </blockquote> <p>Rearrange to find the concentration of the hydroxide anions</p> <blockquote> <p><mathjax>#["OH"^(-)] = sqrt(K_(sp)/(["Mg"^(2+)]))#</mathjax></p> </blockquote> <p>Plug in your values to get</p> <blockquote> <p><mathjax>#["OH"^(-)] = sqrt((1.0 * 10^(-11))/0.1) = sqrt(1.0 * 10^(-10)) = 10^(-5)"M"#</mathjax></p> </blockquote> <p>As you know, you can use the concentration of hydroxide anions to find the solution's pOH</p> <blockquote> <p><mathjax>#color(blue)("pOH" = - log(["OH"]^(-)))#</mathjax></p> <p><mathjax>#"pOH" = - log(10^(-5)) = 5#</mathjax></p> </blockquote> <p>Finally, use the relationship that exists between pOH and <a href="http://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> at room temperature</p> <blockquote> <p><mathjax>#color(blue)("pOH " + " pH" = 14)#</mathjax></p> </blockquote> <p>to find the pH of the solution</p> <blockquote> <p><mathjax>#"pH" = 14 - 5 = color(green)(9)#</mathjax></p> </blockquote> <p>So, for pH values that are <strong>below</strong> <mathjax>#9#</mathjax>, the solution will be <em>unsaturated</em>. Once the pH of the solution becomes equal to <mathjax>#9#</mathjax>, the solution becomes <em>saturated</em> and the magnesium hydroxide starts to precipitate. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Calculate the #pH# at which #Mg(OH)_2# begins to precipitate from a solution containing #0.1# #M# #Mg^(2+)# ions? #K_(sp)# for #Mg(OH)_2# = #1.0# x #10^-11#.</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-equilibrium" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Equilibrium</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-equilibrium/ksp" itemprop="url"> <span class="breadcrumb" itemprop="title">Ksp</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="219453" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-31T01:19:23" itemprop="dateCreated"> Jan 31, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"pH" = 9#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that you need to use magnesium hydroxide's <a href="https://socratic.org/chemistry/chemical-equilibrium/ksp">solubility product constant</a> to determine what concentration of hydroxide anions, <mathjax>#"OH"^(-)#</mathjax>, would cause the solid to precipitate out of solution. </p> <p>As you know, the dissociation equilibrium for magnesium hydroxide looks like this </p> <blockquote> <p><mathjax>#"Mg"("OH")_text(2(s]) rightleftharpoons "Mg"_text((aq])^(2+) + color(red)(2)"OH"_text((aq])^(-)#</mathjax></p> </blockquote> <p>The solubility product constant, <mathjax>#K_(sp)#</mathjax>, will be equal to</p> <blockquote> <p><mathjax>#K_(sp) = ["Mg"^(2+)] * ["OH"^(-)]^color(red)(2)#</mathjax></p> </blockquote> <p>Rearrange to find the concentration of the hydroxide anions</p> <blockquote> <p><mathjax>#["OH"^(-)] = sqrt(K_(sp)/(["Mg"^(2+)]))#</mathjax></p> </blockquote> <p>Plug in your values to get</p> <blockquote> <p><mathjax>#["OH"^(-)] = sqrt((1.0 * 10^(-11))/0.1) = sqrt(1.0 * 10^(-10)) = 10^(-5)"M"#</mathjax></p> </blockquote> <p>As you know, you can use the concentration of hydroxide anions to find the solution's pOH</p> <blockquote> <p><mathjax>#color(blue)("pOH" = - log(["OH"]^(-)))#</mathjax></p> <p><mathjax>#"pOH" = - log(10^(-5)) = 5#</mathjax></p> </blockquote> <p>Finally, use the relationship that exists between pOH and <a href="http://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> at room temperature</p> <blockquote> <p><mathjax>#color(blue)("pOH " + " pH" = 14)#</mathjax></p> </blockquote> <p>to find the pH of the solution</p> <blockquote> <p><mathjax>#"pH" = 14 - 5 = color(green)(9)#</mathjax></p> </blockquote> <p>So, for pH values that are <strong>below</strong> <mathjax>#9#</mathjax>, the solution will be <em>unsaturated</em>. Once the pH of the solution becomes equal to <mathjax>#9#</mathjax>, the solution becomes <em>saturated</em> and the magnesium hydroxide starts to precipitate. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/219453" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-you-use-the-solubility-product-constant-to-calculate-the-solubility-of-a"> How can you use the solubility product constant to calculate the solubility of a sparingly... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5397ae9102bf3458eddf5130"> Question #f5130 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-ksp"> What is Ksp? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-ksp-be-calculated"> How can Ksp be calculated? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-ksp-related-to-molarity"> How is Ksp related to molarity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/54acbccb581e2a063bcda59d"> Question #da59d </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/551bf79e581e2a41eb271344"> Question #71344 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/552b6da7581e2a666ea17cc3"> Question #17cc3 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/552bd9cd581e2a666ea18e4c"> What is the molar solubility of magnesium fluoride in a solution that is #"0.1 M"# sodium fluoride? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5536aaad581e2a253fd94985"> (a) How much aluminium hydroxide will dissolve in 500ml of water at #25^@C# given that... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-equilibrium/ksp"> See all questions in Ksp </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 99981 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Calculate the #pH# at which #Mg(OH)_2# begins to precipitate from a solution containing #0.1# #M# #Mg^(2+)# ions? #K_(sp)# for #Mg(OH)_2# = #1.0# x #10^-11#.	null
2,174	aae827dc-6ddd-11ea-a448-ccda262736ce	https://socratic.org/questions/how-would-you-balance-na2so3-s8-na2s2o3	8 Na2SO3 + S8 -> 8 Na2S2O3	start chemical_equation qc_end chemical_equation 4 8 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the equation"}]	[{"type":"chemical equation","value":"8 Na2SO3 + S8 -> 8 Na2S2O3"}]	[{"type":"chemical equation","value":"Na2SO3 + S8 -> Na2S2O3"}]	<h1 class="questionTitle" itemprop="name">How would you balance: Na2SO3+S8 --> Na2S2O3?</h1>	null	8 Na2SO3 + S8 -> 8 Na2S2O3	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>It's Actually easy.</p> <p>First Let's Check The Equation.</p> <p><mathjax>#Na_2SO_3 + S_8 -> Na_2S_2O_3#</mathjax></p> <p>In L.H.S, We can see two sulphur atoms, but in R.H.S, we can see only one.</p> <p>According to this equation, it's a redox reaction. Because value of S in <mathjax>#Na_2SO_3#</mathjax> is <mathjax>#+4#</mathjax>, one of <mathjax>#S_8#</mathjax> in <mathjax>#0#</mathjax> and one of <mathjax>#Na_2S_2O_3#</mathjax> in <mathjax>#+2#</mathjax>.</p> <p>The sulphur is being oxidized (<mathjax>#S^(0) -> S^(2+)#</mathjax>) and it is being reduced (<mathjax>#S^(+4) -> S^(2+)#</mathjax>). If we balance that charge transfer, we balance the element quantities involved.</p> <p>The key changes are:</p> <p><mathjax>#S_8 → 8S^(+2)+16e^(-)#</mathjax> and<br/> <mathjax>#S^(+4)+2e^(-)→ S^(+2)#</mathjax></p> <p>According to these equations, second one must be multiplied by 8 for balance.</p> <p>Put them all together and check the <mathjax>#S#</mathjax> balance:</p> <p><mathjax>#8Na_2SO_3 + S_8 → 8Na_2S_2O_3#</mathjax></p> <p>Total Balance:</p> <p><mathjax>#" " Left" "Right#</mathjax><br/> <mathjax>#Na" 16" " "16#</mathjax><br/> <mathjax>#S" " 16 " "16#</mathjax><br/> <mathjax>#O" 24" " "24#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#8Na_2SO_3 + S_8 → 8Na_2S_2O_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>It's Actually easy.</p> <p>First Let's Check The Equation.</p> <p><mathjax>#Na_2SO_3 + S_8 -> Na_2S_2O_3#</mathjax></p> <p>In L.H.S, We can see two sulphur atoms, but in R.H.S, we can see only one.</p> <p>According to this equation, it's a redox reaction. Because value of S in <mathjax>#Na_2SO_3#</mathjax> is <mathjax>#+4#</mathjax>, one of <mathjax>#S_8#</mathjax> in <mathjax>#0#</mathjax> and one of <mathjax>#Na_2S_2O_3#</mathjax> in <mathjax>#+2#</mathjax>.</p> <p>The sulphur is being oxidized (<mathjax>#S^(0) -> S^(2+)#</mathjax>) and it is being reduced (<mathjax>#S^(+4) -> S^(2+)#</mathjax>). If we balance that charge transfer, we balance the element quantities involved.</p> <p>The key changes are:</p> <p><mathjax>#S_8 → 8S^(+2)+16e^(-)#</mathjax> and<br/> <mathjax>#S^(+4)+2e^(-)→ S^(+2)#</mathjax></p> <p>According to these equations, second one must be multiplied by 8 for balance.</p> <p>Put them all together and check the <mathjax>#S#</mathjax> balance:</p> <p><mathjax>#8Na_2SO_3 + S_8 → 8Na_2S_2O_3#</mathjax></p> <p>Total Balance:</p> <p><mathjax>#" " Left" "Right#</mathjax><br/> <mathjax>#Na" 16" " "16#</mathjax><br/> <mathjax>#S" " 16 " "16#</mathjax><br/> <mathjax>#O" 24" " "24#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How would you balance: Na2SO3+S8 --> Na2S2O3?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="637602" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/cem-sentin"><img alt="" class="" src="https://lh3.googleusercontent.com/-XdUIqdMkCWA/AAAAAAAAAAI/AAAAAAAAAAA/4252rscbv5M/photo.jpg?sz=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/cem-sentin"> Cem Sentin </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-07-01T16:51:49" itemprop="dateCreated"> Jul 1, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#8Na_2SO_3 + S_8 → 8Na_2S_2O_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>It's Actually easy.</p> <p>First Let's Check The Equation.</p> <p><mathjax>#Na_2SO_3 + S_8 -> Na_2S_2O_3#</mathjax></p> <p>In L.H.S, We can see two sulphur atoms, but in R.H.S, we can see only one.</p> <p>According to this equation, it's a redox reaction. Because value of S in <mathjax>#Na_2SO_3#</mathjax> is <mathjax>#+4#</mathjax>, one of <mathjax>#S_8#</mathjax> in <mathjax>#0#</mathjax> and one of <mathjax>#Na_2S_2O_3#</mathjax> in <mathjax>#+2#</mathjax>.</p> <p>The sulphur is being oxidized (<mathjax>#S^(0) -> S^(2+)#</mathjax>) and it is being reduced (<mathjax>#S^(+4) -> S^(2+)#</mathjax>). If we balance that charge transfer, we balance the element quantities involved.</p> <p>The key changes are:</p> <p><mathjax>#S_8 → 8S^(+2)+16e^(-)#</mathjax> and<br/> <mathjax>#S^(+4)+2e^(-)→ S^(+2)#</mathjax></p> <p>According to these equations, second one must be multiplied by 8 for balance.</p> <p>Put them all together and check the <mathjax>#S#</mathjax> balance:</p> <p><mathjax>#8Na_2SO_3 + S_8 → 8Na_2S_2O_3#</mathjax></p> <p>Total Balance:</p> <p><mathjax>#" " Left" "Right#</mathjax><br/> <mathjax>#Na" 16" " "16#</mathjax><br/> <mathjax>#S" " 16 " "16#</mathjax><br/> <mathjax>#O" 24" " "24#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/637602" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="637611" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-07-01T17:51:37" itemprop="dateCreated"> Jul 1, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>What we gots is a <mathjax>#"comproportionation reaction..."#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Where sulfur, as <mathjax>#S(+IV)#</mathjax> and <mathjax>#S(0)#</mathjax> undergoes a redox reaction to give <mathjax>#S(VI+)#</mathjax> and <mathjax>#S(-II)#</mathjax>...i.e. <mathjax>#S(+II)_"average"#</mathjax></p> <p>And so reduction....</p> <p><mathjax>#2SO_3^(2-)+6H^+ +4e^(-) rarr S_2O_3^(2-)+3H_2O#</mathjax></p> <p>And oxidation...</p> <p><mathjax>#1/4S_8 +3H_2Orarr S_2O_3^(2-)+6H^+ +4e^(-)#</mathjax></p> <p>We add the equations together to eliminate the electrons...</p> <p><mathjax>#2SO_3^(2-)+6H^+ +4e^(-) +1/4S_8 +3H_2Orarr S_2O_3^(2-)+3H_2O+S_2O_3^(2-)+6H^+ +4e^(-)#</mathjax></p> <p>And we cancel common reagents...</p> <p><mathjax>#2SO_3^(2-) +1/4S_8 rarr 2S_2O_3^(2-)#</mathjax></p> <p>The which, I think, is balanced with respect to mass and charge...as indeed it must be if we reflect chemical reality...</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/637611" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------> H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -> Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? 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Sodium phosphate and calcium chloride react to form... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-equation-kclo3-kcl-o2"> How can I balance this equation? ____ #KClO_3 -># ____ #KCl +# ____ #O_2# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-balancing-chemical-equations-important"> Why is balancing chemical equations important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/balancing-chemical-equations"> See all questions in Balancing Chemical Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 5654 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How would you balance: Na2SO3+S8 --> Na2S2O3?	null
2,175	a91b186e-6ddd-11ea-9a95-ccda262736ce	https://socratic.org/questions/what-is-the-ph-of-a-solution-with-a-hydrogen-ion-concentration-of-3-5-10-4	3.46	start physical_unit 5 6 ph none qc_end physical_unit 9 10 13 16 concentration qc_end end	[{"type":"physical unit","value":"pH [OF] a solution"}]	[{"type":"physical unit","value":"3.46"}]	[{"type":"physical unit","value":"Concentration [OF] hydrogen ion [=] \\pu{3.5 × 10^(−4) M}"}]	<h1 class="questionTitle" itemprop="name">What is the pH of a solution with a hydrogen ion concentration of #3.5*10^-4#?</h1>	null	3.46	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#pH#</mathjax> <mathjax>#=#</mathjax> <mathjax>#-log_(10)(3.5xx10^-4)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#-(-3.46)#</mathjax></p> <p><mathjax>#=#</mathjax> <mathjax>#3.46#</mathjax></p> <p>Using antilogarithms. can you tell me the <mathjax>#pH#</mathjax> of a solution that is <mathjax>#10^-7#</mathjax> <mathjax>#mol*L^-1#</mathjax> with respect to <mathjax>#H_3O^+#</mathjax>. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#pH#</mathjax> <mathjax>#=#</mathjax> <mathjax>#-log_(10)[H_3O^+]#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#pH#</mathjax> <mathjax>#=#</mathjax> <mathjax>#-log_(10)(3.5xx10^-4)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#-(-3.46)#</mathjax></p> <p><mathjax>#=#</mathjax> <mathjax>#3.46#</mathjax></p> <p>Using antilogarithms. can you tell me the <mathjax>#pH#</mathjax> of a solution that is <mathjax>#10^-7#</mathjax> <mathjax>#mol*L^-1#</mathjax> with respect to <mathjax>#H_3O^+#</mathjax>. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the pH of a solution with a hydrogen ion concentration of #3.510^-4#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/the-ph-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">pH</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="276724" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-12T20:33:58" itemprop="dateCreated"> Jun 12, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#pH#</mathjax> <mathjax>#=#</mathjax> <mathjax>#-log_(10)[H_3O^+]#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#pH#</mathjax> <mathjax>#=#</mathjax> <mathjax>#-log_(10)(3.5xx10^-4)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#-(-3.46)#</mathjax></p> <p><mathjax>#=#</mathjax> <mathjax>#3.46#</mathjax></p> <p>Using antilogarithms. can you tell me the <mathjax>#pH#</mathjax> of a solution that is <mathjax>#10^-7#</mathjax> <mathjax>#molL^-1#</mathjax> with respect to <mathjax>#H_3O^+#</mathjax>. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/276724" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-pka"> How do you determine pH from pKa? 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</a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ph-scale-0-14"> Why is the pH scale 0-14? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-ph-the-measure-of-the-hydrogen-ion-concentration"> Is pH a measure of the hydrogen ion concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-solubility-affect-ph"> How does solubility affect pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-ph-relate-to-pka-in-a-titration"> How does pH relate to pKa in a titration? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/the-ph-concept"> See all questions in pH </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 4679 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the pH of a solution with a hydrogen ion concentration of #3.5*10^-4#?	null
2,176	abea12d2-6ddd-11ea-a9c7-ccda262736ce	https://socratic.org/questions/given-the-incomplete-equation-for-the-combustion-of-ethane-2c-2h-6-7o-2-4co-2-6-	H2O	start chemical_formula qc_end chemical_equation 9 19 qc_end end	[{"type":"other","value":"Chemical Formula [OF] the missing product [IN] default"}]	[{"type":"chemical equation","value":"H2O"}]	[{"type":"chemical equation","value":"2 C2H6 + 7 O2 -> 4 CO2 + 6 _"}]	<h1 class="questionTitle" itemprop="name">Given the incomplete equation for the combustion of ethane, #2C_2H_6 + 7O_2 -> 4CO_2 + 6__#, what is the formula of the missing product?</h1>	null	H2O	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In general any organic compound, when burned will generate an "oxide" of its atoms.</p> <p>Carbon goes to <mathjax>#CO#</mathjax> or <mathjax>#CO_2#</mathjax> (the latter, if complete)<br/> Hydrogen goes to <mathjax>#H_2O#</mathjax><br/> Nitrogen and Sulfur depend on the amount of <mathjax>#O_2#</mathjax> available. If the amount is big enough they'll go for higher oxidation states such as <mathjax>#NO_2#</mathjax>, <mathjax>#SO_3#</mathjax> but with less oxygen they'll settle for lower states like <mathjax>#NO#</mathjax> and <mathjax>#SO_2#</mathjax></p> <p>Another way to solve this is to count the atoms that aren't in the right side. If you do the math you'll see we're missing 12 Hydrogen atoms and 6 Oxygen atoms, dividing by the stoichiometric coefficient that was given, we have 2 Hydrogen atoms and 1 Oxygen atom together to make a compound, which is obviously water.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#H_2O#</mathjax>, aka water.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In general any organic compound, when burned will generate an "oxide" of its atoms.</p> <p>Carbon goes to <mathjax>#CO#</mathjax> or <mathjax>#CO_2#</mathjax> (the latter, if complete)<br/> Hydrogen goes to <mathjax>#H_2O#</mathjax><br/> Nitrogen and Sulfur depend on the amount of <mathjax>#O_2#</mathjax> available. If the amount is big enough they'll go for higher oxidation states such as <mathjax>#NO_2#</mathjax>, <mathjax>#SO_3#</mathjax> but with less oxygen they'll settle for lower states like <mathjax>#NO#</mathjax> and <mathjax>#SO_2#</mathjax></p> <p>Another way to solve this is to count the atoms that aren't in the right side. If you do the math you'll see we're missing 12 Hydrogen atoms and 6 Oxygen atoms, dividing by the stoichiometric coefficient that was given, we have 2 Hydrogen atoms and 1 Oxygen atom together to make a compound, which is obviously water.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Given the incomplete equation for the combustion of ethane, #2C_2H_6 + 7O_2 -> 4CO_2 + 6__#, what is the formula of the missing product?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/determining-formula-and-molar-masses" itemprop="url"> <span class="breadcrumb" itemprop="title">Determining Formula</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="208711" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/lovecraft"><img alt="" class="" src="https://profilepictures.socratic.org/yRsInkqBQENj1w6bu77a_tumblrmireiwDbf71rz7ozto1400.gif" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/lovecraft"> Lovecraft </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-06T00:10:39" itemprop="dateCreated"> Jan 6, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#H_2O#</mathjax>, aka water.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In general any organic compound, when burned will generate an "oxide" of its atoms.</p> <p>Carbon goes to <mathjax>#CO#</mathjax> or <mathjax>#CO_2#</mathjax> (the latter, if complete)<br/> Hydrogen goes to <mathjax>#H_2O#</mathjax><br/> Nitrogen and Sulfur depend on the amount of <mathjax>#O_2#</mathjax> available. If the amount is big enough they'll go for higher oxidation states such as <mathjax>#NO_2#</mathjax>, <mathjax>#SO_3#</mathjax> but with less oxygen they'll settle for lower states like <mathjax>#NO#</mathjax> and <mathjax>#SO_2#</mathjax></p> <p>Another way to solve this is to count the atoms that aren't in the right side. If you do the math you'll see we're missing 12 Hydrogen atoms and 6 Oxygen atoms, dividing by the stoichiometric coefficient that was given, we have 2 Hydrogen atoms and 1 Oxygen atom together to make a compound, which is obviously water.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/208711" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-it-possible-to-find-a-molecular-formula-from-molar-mass"> Is it possible to find a molecular formula from molar mass? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5368e0cc02bf34779e175781"> Question #75781 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-common-mistakes-students-make-when-determining-formulas"> What are some common mistakes students make when determining formulas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-formula-of-an-acid"> How can I determine the formula of an acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-chemical-formula-of-a-product"> How can I determine the chemical formula of a product? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-empirical-formula-of-a-compound"> How can I determine the empirical formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-formula-of-a-hydrate"> How can I determine the formula of a hydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-the-empirical-formula-indicate"> What does the empirical formula indicate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-molecule-with-molecular-weight-of-180-18-g-mol-is-analyzed-and-found-to-contai"> A molecule with molecular weight of 180.18 g/mol is analyzed and found to contain 40.00% carbon,... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/do-i-need-to-know-the-number-of-moles-of-each-element-to-determine-the-formula-o"> Do I need to know the number of moles of each element to determine the formula of the compound? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/determining-formula-and-molar-masses"> See all questions in Determining Formula </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 11274 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Given the incomplete equation for the combustion of ethane, #2C_2H_6 + 7O_2 -> 4CO_2 + 6__#, what is the formula of the missing product?	null
2,177	ac272378-6ddd-11ea-919a-ccda262736ce	https://socratic.org/questions/566718417c01493f0829379b	Li(g) -> Li(g)+ + e-	start chemical_equation qc_end substance 7 7 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the ionization"}]	[{"type":"chemical equation","value":"Li(g) -> Li(g)+ + e-"}]	[{"type":"substance name","value":"Lithium"}]	<h1 class="questionTitle" itemprop="name">How do we represent the ionization of lithium?</h1>	null	Li(g) -> Li(g)+ + e-	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The products and reactants are specified to be in the gas phase. (This way we have a measure of nucleus electron interaction only). Would you expect the reaction as written to be exothermic? Why or why not?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Li(g) rarr Li(g)^+ + e^-#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The products and reactants are specified to be in the gas phase. (This way we have a measure of nucleus electron interaction only). Would you expect the reaction as written to be exothermic? Why or why not?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do we represent the ionization of lithium?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-periodic-table" itemprop="url"> <span class="breadcrumb" itemprop="title">The Periodic Table</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-periodic-table/periodic-trends-in-ionization-energy" itemprop="url"> <span class="breadcrumb" itemprop="title">Periodic Trends in Ionization Energy</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="197824" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-08T18:57:31" itemprop="dateCreated"> Dec 8, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Li(g) rarr Li(g)^+ + e^-#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The products and reactants are specified to be in the gas phase. (This way we have a measure of nucleus electron interaction only). Would you expect the reaction as written to be exothermic? Why or why not?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/197824" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-ionization-energy-relate-to-reactivity"> How does ionization energy relate to reactivity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-ionization-energy-measured-in"> What is ionization energy measured in? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-the-first-and-second-ionization-energies"> What are the first and second ionization energies? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-ionization-energy-increase"> How does ionization energy increase? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-ionization-energy-change-down-a-group"> How does ionization energy change down a group? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-trends-in-atomic-radius-relate-to-ionization-energy"> How do trends in atomic radius relate to ionization energy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/53f00f0102bf346733644238"> Question #44238 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/54a13803581e2a1c2d5fbdfe"> Question #fbdfe </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/54c642dc581e2a50cea1a23b"> Question #1a23b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/54e18faf581e2a2f288d7de9"> Question #d7de9 </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-periodic-table/periodic-trends-in-ionization-energy"> See all questions in Periodic Trends in Ionization Energy </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 14598 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How do we represent the ionization of lithium?	null
2,178	ac941c24-6ddd-11ea-a43b-ccda262736ce	https://socratic.org/questions/the-pressure-of-a-sample-of-argon-at-20-c-is-decreased-from-720-mmhg-to-360-mmhg	-126.5 ℃	start physical_unit 25 26 temperature °c qc_end physical_unit 4 6 8 9 temperature qc_end physical_unit 4 6 13 14 pressure qc_end physical_unit 4 6 16 17 pressure qc_end end	[{"type":"physical unit","value":"Temperature2 [OF] argon gas [IN] ℃"}]	[{"type":"physical unit","value":"-126.5 ℃ "}]	[{"type":"physical unit","value":"Temperature1 [OF] argon sample [=] \\pu{20 ℃}"},{"type":"physical unit","value":"Pressure1 [OF] argon sample [=] \\pu{720 mmHg}"},{"type":"physical unit","value":"Pressure2 [OF] argon sample [=] \\pu{360 mmHg}"}]	<h1 class="questionTitle" itemprop="name">The pressure of a sample of argon at 20°C is decreased from 720 mmHg to 360 mmHg. What was the final temperature of the argon gas?</h1>	null	-126.5 ℃	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>For this solution we will use the Gay-Lussac Law relating pressure and temperature in gases. <mathjax>#P_1/T_1 = P_2/T_2#</mathjax></p> <p>For this case the values are</p> <p><mathjax>#P_1 = 720 mmHg#</mathjax><br/> <mathjax>#T_1 = 20^oC or 293K#</mathjax><br/> <mathjax>#P_2 = 360 mmHg#</mathjax><br/> <mathjax>#T_1 = ?K#</mathjax></p> <p><mathjax>#P_1/T_1 = P_2/T_2#</mathjax></p> <p><mathjax>#(720mmHg)/(293K) = (360mmHg)/T_2#</mathjax></p> <p>We can invert both sides to put the missing variable in the numerator.</p> <p><mathjax>#(293K)/(720mmHg) = T_2/(360mmHg)#</mathjax></p> <p><mathjax>#(293K)/(720cancel(mmHg))(360cancel(mmHg)) = T_2/(cancel(360mmHg))(cancel(360mmHg))#</mathjax></p> <p><mathjax>#T_2 = 146.5 K#</mathjax></p> <p>or </p> <p><mathjax>#T_2 = -126.5^oC#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#T_2 = 146.5 K#</mathjax></p> <p>or </p> <p><mathjax>#T_2 = -126.5^oC#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>For this solution we will use the Gay-Lussac Law relating pressure and temperature in gases. <mathjax>#P_1/T_1 = P_2/T_2#</mathjax></p> <p>For this case the values are</p> <p><mathjax>#P_1 = 720 mmHg#</mathjax><br/> <mathjax>#T_1 = 20^oC or 293K#</mathjax><br/> <mathjax>#P_2 = 360 mmHg#</mathjax><br/> <mathjax>#T_1 = ?K#</mathjax></p> <p><mathjax>#P_1/T_1 = P_2/T_2#</mathjax></p> <p><mathjax>#(720mmHg)/(293K) = (360mmHg)/T_2#</mathjax></p> <p>We can invert both sides to put the missing variable in the numerator.</p> <p><mathjax>#(293K)/(720mmHg) = T_2/(360mmHg)#</mathjax></p> <p><mathjax>#(293K)/(720cancel(mmHg))(360cancel(mmHg)) = T_2/(cancel(360mmHg))(cancel(360mmHg))#</mathjax></p> <p><mathjax>#T_2 = 146.5 K#</mathjax></p> <p>or </p> <p><mathjax>#T_2 = -126.5^oC#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">The pressure of a sample of argon at 20°C is decreased from 720 mmHg to 360 mmHg. What was the final temperature of the argon gas?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/gay-lussac-s-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Gay Lussac's Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="281273" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/brian-m"><img alt="" class="" src="https://profilepictures.socratic.org/ZCpnJDgSFKORtvaSPDeG_Lego%20Me.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/brian-m"> BRIAN M. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-25T17:12:31" itemprop="dateCreated"> Jun 25, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#T_2 = 146.5 K#</mathjax></p> <p>or </p> <p><mathjax>#T_2 = -126.5^oC#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>For this solution we will use the Gay-Lussac Law relating pressure and temperature in gases. <mathjax>#P_1/T_1 = P_2/T_2#</mathjax></p> <p>For this case the values are</p> <p><mathjax>#P_1 = 720 mmHg#</mathjax><br/> <mathjax>#T_1 = 20^oC or 293K#</mathjax><br/> <mathjax>#P_2 = 360 mmHg#</mathjax><br/> <mathjax>#T_1 = ?K#</mathjax></p> <p><mathjax>#P_1/T_1 = P_2/T_2#</mathjax></p> <p><mathjax>#(720mmHg)/(293K) = (360mmHg)/T_2#</mathjax></p> <p>We can invert both sides to put the missing variable in the numerator.</p> <p><mathjax>#(293K)/(720mmHg) = T_2/(360mmHg)#</mathjax></p> <p><mathjax>#(293K)/(720cancel(mmHg))(360cancel(mmHg)) = T_2/(cancel(360mmHg))(cancel(360mmHg))#</mathjax></p> <p><mathjax>#T_2 = 146.5 K#</mathjax></p> <p>or </p> <p><mathjax>#T_2 = -126.5^oC#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/281273" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535d701102bf342f53d9bcb0"> Question #9bcb0 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-gay-lussac-s-law-formula"> What is the Gay Lussac's law formula? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-the-temperature-of-a-gas-in-a-container-is-doubled-on-the-kelvin-scale-the-pr"> If the temperature of a gas in a container is doubled on the Kelvin scale, what will happen to... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-the-original-pressure-of-a-gas-sample-at-20-c-was-5-00-atm-and-it-is-heated-u"> If the original pressure of a gas sample at 20 ˚C was 5.00 atm, and it is heated up to 40. ˚C ,... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-gay-lussac-s-law-state"> What does Gay Lussac's law state? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-gay-lussac-s-law-relate"> What does Gay Lussac's law relate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-sample-of-o2-under-2-00-atm-occupies-500-ml-at-25-0-c-what-pressure-will-the-s"> A sample of O2 under 2.00 atm occupies 500 ml at 25.0˚C. 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What was the final temperature of the argon gas?	null
2,179	abe6529f-6ddd-11ea-afd1-ccda262736ce	https://socratic.org/questions/the-molecular-formula-for-vitamin-c-is-c-6h-8o-6-what-is-the-empirical-formula	C3H4O3	start chemical_formula qc_end c_other OTHER qc_end end	[{"type":"other","value":"Chemical Formula [OF] vitamin C [IN] empirical"}]	[{"type":"chemical equation","value":"C3H4O3"}]	[{"type":"other","value":"The molecular formula for vitamin C is C6H8O6."}]	<h1 class="questionTitle" itemprop="name">The molecular formula for vitamin C is #C_6H_8O_6#. What is the empirical formula?</h1>	null	C3H4O3	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The thing to remember about a compound's <a href="http://socratic.org/chemistry/the-mole-concept/empirical-and-molecular-formulas">empirical formula</a> is that it represents the <strong>smallest whole number ratio</strong> that exists between the <em>atoms</em> that form that compound's molecule. </p> <p>This implies that the <strong>molecular formula</strong>, which tells you exactly <em>how many atoms</em> of each element you have in a compound's molecule, will <strong>always</strong> be a multiple of the <strong>empirical formula</strong></p> <blockquote> <p><mathjax>#color(blue)("molecular formula" = n xx "empirical formula")" "#</mathjax>, where</p> </blockquote> <p><mathjax>#n#</mathjax>, an <strong>integer</strong>, <mathjax>#n>=1#</mathjax></p> <p>So, the empirical formula is a sort of <em>building block</em> for the molecular formula. The question now becomes</p> <blockquote> <p><em>How many building blocks, i.e. empirical formulas, do you need in order to get the molecular formula?</em></p> </blockquote> <p>Well, you know that the molecular formula contains </p> <blockquote> <ul> <li><em><strong>six</strong> atoms of carbon</em></li> <li><em><strong>eight</strong> atoms of hydrogen</em></li> <li><em><strong>six</strong> atoms of oxygen</em></li> </ul> </blockquote> <p>What would be the <strong>smallest whole number ratio</strong> between these numbers? </p> <p>If you divide all three numbers by <mathjax>#2#</mathjax> you will get</p> <blockquote> <p><mathjax>#"For C: " 6/2 = 3#</mathjax></p> <p><mathjax>#"For H: " 8/2 = 4#</mathjax></p> <p><mathjax>#"For O: "6/2 = 3#</mathjax></p> </blockquote> <p>Since you cannot longer divide <strong>by an integer</strong> to get a smaller whole number ratio, the empirical formula of vitamin C will be </p> <blockquote> <p><mathjax>#"C"_3"H"_4"O"_3#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"C"_3"H"_4"O"_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The thing to remember about a compound's <a href="http://socratic.org/chemistry/the-mole-concept/empirical-and-molecular-formulas">empirical formula</a> is that it represents the <strong>smallest whole number ratio</strong> that exists between the <em>atoms</em> that form that compound's molecule. </p> <p>This implies that the <strong>molecular formula</strong>, which tells you exactly <em>how many atoms</em> of each element you have in a compound's molecule, will <strong>always</strong> be a multiple of the <strong>empirical formula</strong></p> <blockquote> <p><mathjax>#color(blue)("molecular formula" = n xx "empirical formula")" "#</mathjax>, where</p> </blockquote> <p><mathjax>#n#</mathjax>, an <strong>integer</strong>, <mathjax>#n>=1#</mathjax></p> <p>So, the empirical formula is a sort of <em>building block</em> for the molecular formula. The question now becomes</p> <blockquote> <p><em>How many building blocks, i.e. empirical formulas, do you need in order to get the molecular formula?</em></p> </blockquote> <p>Well, you know that the molecular formula contains </p> <blockquote> <ul> <li><em><strong>six</strong> atoms of carbon</em></li> <li><em><strong>eight</strong> atoms of hydrogen</em></li> <li><em><strong>six</strong> atoms of oxygen</em></li> </ul> </blockquote> <p>What would be the <strong>smallest whole number ratio</strong> between these numbers? </p> <p>If you divide all three numbers by <mathjax>#2#</mathjax> you will get</p> <blockquote> <p><mathjax>#"For C: " 6/2 = 3#</mathjax></p> <p><mathjax>#"For H: " 8/2 = 4#</mathjax></p> <p><mathjax>#"For O: "6/2 = 3#</mathjax></p> </blockquote> <p>Since you cannot longer divide <strong>by an integer</strong> to get a smaller whole number ratio, the empirical formula of vitamin C will be </p> <blockquote> <p><mathjax>#"C"_3"H"_4"O"_3#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">The molecular formula for vitamin C is #C_6H_8O_6#. What is the empirical formula?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="206785" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-02T00:04:41" itemprop="dateCreated"> Jan 2, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"C"_3"H"_4"O"_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The thing to remember about a compound's <a href="http://socratic.org/chemistry/the-mole-concept/empirical-and-molecular-formulas">empirical formula</a> is that it represents the <strong>smallest whole number ratio</strong> that exists between the <em>atoms</em> that form that compound's molecule. </p> <p>This implies that the <strong>molecular formula</strong>, which tells you exactly <em>how many atoms</em> of each element you have in a compound's molecule, will <strong>always</strong> be a multiple of the <strong>empirical formula</strong></p> <blockquote> <p><mathjax>#color(blue)("molecular formula" = n xx "empirical formula")" "#</mathjax>, where</p> </blockquote> <p><mathjax>#n#</mathjax>, an <strong>integer</strong>, <mathjax>#n>=1#</mathjax></p> <p>So, the empirical formula is a sort of <em>building block</em> for the molecular formula. The question now becomes</p> <blockquote> <p><em>How many building blocks, i.e. empirical formulas, do you need in order to get the molecular formula?</em></p> </blockquote> <p>Well, you know that the molecular formula contains </p> <blockquote> <ul> <li><em><strong>six</strong> atoms of carbon</em></li> <li><em><strong>eight</strong> atoms of hydrogen</em></li> <li><em><strong>six</strong> atoms of oxygen</em></li> </ul> </blockquote> <p>What would be the <strong>smallest whole number ratio</strong> between these numbers? </p> <p>If you divide all three numbers by <mathjax>#2#</mathjax> you will get</p> <blockquote> <p><mathjax>#"For C: " 6/2 = 3#</mathjax></p> <p><mathjax>#"For H: " 8/2 = 4#</mathjax></p> <p><mathjax>#"For O: "6/2 = 3#</mathjax></p> </blockquote> <p>Since you cannot longer divide <strong>by an integer</strong> to get a smaller whole number ratio, the empirical formula of vitamin C will be </p> <blockquote> <p><mathjax>#"C"_3"H"_4"O"_3#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/206785" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molecular-formula-of-a-compound"> How do you find molecular formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-diamond"> What is the chemical formula of a diamond? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-carbohydrate"> What is the chemical formula of a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-valproic-acid"> What is the empirical formula for valproic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-of-magnesium-oxide"> What is the empirical formula of magnesium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-empirical-formula-not-double-that-of-the-monosaccharides"> Why is the empirical formula not double that of the monosaccharides? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5331180502bf342f40b5c3b5"> Question #5c3b5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-molecular-formula-represents-a-carbohydrate"> What molecular formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-of-vinegar"> What is the molecular formula of vinegar? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/empirical-and-molecular-formulas"> See all questions in Empirical and Molecular Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 16916 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	The molecular formula for vitamin C is #C_6H_8O_6#. What is the empirical formula?	null
2,180	ab64dc6e-6ddd-11ea-a972-ccda262736ce	https://socratic.org/questions/a-73-8-g-sample-of-o2-gas-at-0-0-oc-and-5-065x10-4-pa-is-compressed-and-heated-u	1.8 × 10^6 Pa	start physical_unit 3 6 pressure pa qc_end physical_unit 3 6 1 2 mass qc_end physical_unit 3 6 8 9 temperature qc_end physical_unit 3 6 11 14 pressure qc_end physical_unit 3 6 23 24 volume qc_end physical_unit 3 6 29 30 temperature qc_end end	[{"type":"physical unit","value":"Pressure2 [OF] O2 gas sample [IN] Pa"}]	[{"type":"physical unit","value":"1.8 × 10^6 Pa"}]	[{"type":"physical unit","value":"Mass1 [OF] O2 gas sample [=] \\pu{73.8 g}"},{"type":"physical unit","value":"Temperature1 [OF] O2 gas sample [=] \\pu{0.0 ℃}"},{"type":"physical unit","value":"Pressure1 [OF] O2 gas sample [=] \\pu{5.065 × 10^4 Pa}"},{"type":"physical unit","value":"Volume2 [OF] O2 gas sample [=] \\pu{3.26 L}"},{"type":"physical unit","value":"Temperature2 [OF] O2 gas sample [=] \\pu{27 ℃}"}]	<h1 class="questionTitle" itemprop="name">A 73.8 g sample of O2 gas at 0.0 oC and 5.065x10^4 Pa is compressed and heated until the volume is 3.26 L and the temperature is 27 oC. What is the final pressure in Pa? T= 273K and 300K i think u have to convert L to m^3?</h1>	null	1.8 × 10^6 Pa	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Yes, you will need to do some <a href="http://socratic.org/chemistry/measurement-in-chemistry/unit-conversions">unit conversions</a>, but I think it'll be easier to just convert the pressure from <em>Pa</em> to <em>atm</em>. </p> <p>The idea here is that the <em>amount of gas</em> remains <strong>unchanged</strong>, but that changing the volume and temperature of the sample will result in a change in <em>pressure</em>. </p> <p>This means that you can use the <a href="https://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">combined gas law</a> equation to help you find the new pressure of the sample.</p> <blockquote> <p><mathjax>#color(blue)((P_1V_1)/T_1 = (P_2V_2)/T_2)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#P_1#</mathjax>, <mathjax>#V_1#</mathjax>, <mathjax>#T_1#</mathjax> - the pressure, volume, and temperature of the gas at an initial state<br/> <mathjax>#P_2#</mathjax>, <mathjax>#V_2#</mathjax>, <mathjax>#T_2#</mathjax> - the pressure, volume, and temperature of the gas at a final state</p> <p>The two temperature of the gas must be expressed in Kelvin. So, rearrange the above equation to solve for <mathjax>#P_2#</mathjax>, the new pressure of the sample</p> <blockquote> <p><mathjax>#P_2 = V_1/V_2 * T_2/T_1 * P_1#</mathjax></p> </blockquote> <p>Before solving for <mathjax>#P_2#</mathjax>, you need to use the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> equation to determine the <strong>initial volume</strong> of the sample, <mathjax>#V_1#</mathjax>. </p> <blockquote> <p><mathjax>#color(blue)(P_1V_1 = nRT_1 implies V_1 = (nRT_1)/P_1#</mathjax></p> </blockquote> <p>Use oxygen gas' molar mass to determine how many moles you have in the sample</p> <blockquote> <p><mathjax>#73.8color(red)(cancel(color(black)("g"))) * "1 mole O"_2/(32.0color(red)(cancel(color(black)("g")))) = "2.301 moles O"_2#</mathjax></p> </blockquote> <p>Now, you need to convert the initial pressure of the gas from <em>Pa</em> to <em>atm</em> by using the conversion factor</p> <blockquote> <p><mathjax>#"1 atm " = " 101325 Pa" = 1.101325 * 10^5"Pa"#</mathjax></p> <p><mathjax>#5.065 * 10^4color(red)(cancel(color(black)("Pa"))) * "1 atm"/(1.01325 * 10^5color(red)(cancel(color(black)("Pa")))) = "0.4999 atm"#</mathjax></p> </blockquote> <p>Now plug in your values and solve for <mathjax>#V_#</mathjax>, the initial volume of the gas</p> <blockquote> <p><mathjax>#V = (2.301color(red)(cancel(color(black)("moles"))) * 0.0821 (color(red)(cancel(color(black)("atm"))) * "L")/(color(red)(cancel(color(black)("mol"))) * color(red)(cancel(color(black)("K")))) * 273.15color(red)(cancel(color(black)("K"))))/(0.4999color(red)(cancel(color(black)("atm")))) = "103.41 L"#</mathjax></p> </blockquote> <p>Now that you have all you need to find <mathjax>#P_2#</mathjax>, plug in your values into the <a href="http://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">combined gas law</a> equation - use the pressure in <em>Pa</em>, since you need the final pressure to be in <em>Pa</em> as well!</p> <blockquote> <p><mathjax>#P_2 = ( 103.41 color(red)(cancel(color(black)("L"))))/(3.26color(red)(cancel(color(black)("L")))) * ( 300.15color(red)(cancel(color(black)("K"))))/(273.15color(red)(cancel(color(black)("K")))) * 5.065 * 10^4"Pa"#</mathjax></p> <p><mathjax>#P_2 = color(green)(1.8 * 10^6"Pa")#</mathjax></p> </blockquote> <p>The answer is rounded to two <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the number of sig figs you have for the two temperatures of the gas.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1.8 * 10^6"Pa"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Yes, you will need to do some <a href="http://socratic.org/chemistry/measurement-in-chemistry/unit-conversions">unit conversions</a>, but I think it'll be easier to just convert the pressure from <em>Pa</em> to <em>atm</em>. </p> <p>The idea here is that the <em>amount of gas</em> remains <strong>unchanged</strong>, but that changing the volume and temperature of the sample will result in a change in <em>pressure</em>. </p> <p>This means that you can use the <a href="https://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">combined gas law</a> equation to help you find the new pressure of the sample.</p> <blockquote> <p><mathjax>#color(blue)((P_1V_1)/T_1 = (P_2V_2)/T_2)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#P_1#</mathjax>, <mathjax>#V_1#</mathjax>, <mathjax>#T_1#</mathjax> - the pressure, volume, and temperature of the gas at an initial state<br/> <mathjax>#P_2#</mathjax>, <mathjax>#V_2#</mathjax>, <mathjax>#T_2#</mathjax> - the pressure, volume, and temperature of the gas at a final state</p> <p>The two temperature of the gas must be expressed in Kelvin. So, rearrange the above equation to solve for <mathjax>#P_2#</mathjax>, the new pressure of the sample</p> <blockquote> <p><mathjax>#P_2 = V_1/V_2 * T_2/T_1 * P_1#</mathjax></p> </blockquote> <p>Before solving for <mathjax>#P_2#</mathjax>, you need to use the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> equation to determine the <strong>initial volume</strong> of the sample, <mathjax>#V_1#</mathjax>. </p> <blockquote> <p><mathjax>#color(blue)(P_1V_1 = nRT_1 implies V_1 = (nRT_1)/P_1#</mathjax></p> </blockquote> <p>Use oxygen gas' molar mass to determine how many moles you have in the sample</p> <blockquote> <p><mathjax>#73.8color(red)(cancel(color(black)("g"))) * "1 mole O"_2/(32.0color(red)(cancel(color(black)("g")))) = "2.301 moles O"_2#</mathjax></p> </blockquote> <p>Now, you need to convert the initial pressure of the gas from <em>Pa</em> to <em>atm</em> by using the conversion factor</p> <blockquote> <p><mathjax>#"1 atm " = " 101325 Pa" = 1.101325 * 10^5"Pa"#</mathjax></p> <p><mathjax>#5.065 * 10^4color(red)(cancel(color(black)("Pa"))) * "1 atm"/(1.01325 * 10^5color(red)(cancel(color(black)("Pa")))) = "0.4999 atm"#</mathjax></p> </blockquote> <p>Now plug in your values and solve for <mathjax>#V_#</mathjax>, the initial volume of the gas</p> <blockquote> <p><mathjax>#V = (2.301color(red)(cancel(color(black)("moles"))) * 0.0821 (color(red)(cancel(color(black)("atm"))) * "L")/(color(red)(cancel(color(black)("mol"))) * color(red)(cancel(color(black)("K")))) * 273.15color(red)(cancel(color(black)("K"))))/(0.4999color(red)(cancel(color(black)("atm")))) = "103.41 L"#</mathjax></p> </blockquote> <p>Now that you have all you need to find <mathjax>#P_2#</mathjax>, plug in your values into the <a href="http://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">combined gas law</a> equation - use the pressure in <em>Pa</em>, since you need the final pressure to be in <em>Pa</em> as well!</p> <blockquote> <p><mathjax>#P_2 = ( 103.41 color(red)(cancel(color(black)("L"))))/(3.26color(red)(cancel(color(black)("L")))) * ( 300.15color(red)(cancel(color(black)("K"))))/(273.15color(red)(cancel(color(black)("K")))) * 5.065 * 10^4"Pa"#</mathjax></p> <p><mathjax>#P_2 = color(green)(1.8 * 10^6"Pa")#</mathjax></p> </blockquote> <p>The answer is rounded to two <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the number of sig figs you have for the two temperatures of the gas.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A 73.8 g sample of O2 gas at 0.0 oC and 5.065x10^4 Pa is compressed and heated until the volume is 3.26 L and the temperature is 27 oC. What is the final pressure in Pa? T= 273K and 300K i think u have to convert L to m^3?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/gas-laws" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Laws</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="192586" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-24T13:32:56" itemprop="dateCreated"> Nov 24, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1.8 * 10^6"Pa"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Yes, you will need to do some <a href="http://socratic.org/chemistry/measurement-in-chemistry/unit-conversions">unit conversions</a>, but I think it'll be easier to just convert the pressure from <em>Pa</em> to <em>atm</em>. </p> <p>The idea here is that the <em>amount of gas</em> remains <strong>unchanged</strong>, but that changing the volume and temperature of the sample will result in a change in <em>pressure</em>. </p> <p>This means that you can use the <a href="https://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">combined gas law</a> equation to help you find the new pressure of the sample.</p> <blockquote> <p><mathjax>#color(blue)((P_1V_1)/T_1 = (P_2V_2)/T_2)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#P_1#</mathjax>, <mathjax>#V_1#</mathjax>, <mathjax>#T_1#</mathjax> - the pressure, volume, and temperature of the gas at an initial state<br/> <mathjax>#P_2#</mathjax>, <mathjax>#V_2#</mathjax>, <mathjax>#T_2#</mathjax> - the pressure, volume, and temperature of the gas at a final state</p> <p>The two temperature of the gas must be expressed in Kelvin. So, rearrange the above equation to solve for <mathjax>#P_2#</mathjax>, the new pressure of the sample</p> <blockquote> <p><mathjax>#P_2 = V_1/V_2 * T_2/T_1 * P_1#</mathjax></p> </blockquote> <p>Before solving for <mathjax>#P_2#</mathjax>, you need to use the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> equation to determine the <strong>initial volume</strong> of the sample, <mathjax>#V_1#</mathjax>. </p> <blockquote> <p><mathjax>#color(blue)(P_1V_1 = nRT_1 implies V_1 = (nRT_1)/P_1#</mathjax></p> </blockquote> <p>Use oxygen gas' molar mass to determine how many moles you have in the sample</p> <blockquote> <p><mathjax>#73.8color(red)(cancel(color(black)("g"))) * "1 mole O"_2/(32.0color(red)(cancel(color(black)("g")))) = "2.301 moles O"_2#</mathjax></p> </blockquote> <p>Now, you need to convert the initial pressure of the gas from <em>Pa</em> to <em>atm</em> by using the conversion factor</p> <blockquote> <p><mathjax>#"1 atm " = " 101325 Pa" = 1.101325 * 10^5"Pa"#</mathjax></p> <p><mathjax>#5.065 * 10^4color(red)(cancel(color(black)("Pa"))) * "1 atm"/(1.01325 * 10^5color(red)(cancel(color(black)("Pa")))) = "0.4999 atm"#</mathjax></p> </blockquote> <p>Now plug in your values and solve for <mathjax>#V_#</mathjax>, the initial volume of the gas</p> <blockquote> <p><mathjax>#V = (2.301color(red)(cancel(color(black)("moles"))) * 0.0821 (color(red)(cancel(color(black)("atm"))) * "L")/(color(red)(cancel(color(black)("mol"))) * color(red)(cancel(color(black)("K")))) * 273.15color(red)(cancel(color(black)("K"))))/(0.4999color(red)(cancel(color(black)("atm")))) = "103.41 L"#</mathjax></p> </blockquote> <p>Now that you have all you need to find <mathjax>#P_2#</mathjax>, plug in your values into the <a href="http://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">combined gas law</a> equation - use the pressure in <em>Pa</em>, since you need the final pressure to be in <em>Pa</em> as well!</p> <blockquote> <p><mathjax>#P_2 = ( 103.41 color(red)(cancel(color(black)("L"))))/(3.26color(red)(cancel(color(black)("L")))) * ( 300.15color(red)(cancel(color(black)("K"))))/(273.15color(red)(cancel(color(black)("K")))) * 5.065 * 10^4"Pa"#</mathjax></p> <p><mathjax>#P_2 = color(green)(1.8 * 10^6"Pa")#</mathjax></p> </blockquote> <p>The answer is rounded to two <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the number of sig figs you have for the two temperatures of the gas.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/192586" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-boyles-law-relate-to-breathing"> How does Boyle's law relate to breathing? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/in-avogadro-s-law-what-would-happen-to-v-if-n-is-increased-decreased-and-what-wo"> In Avogadro's Law what would happen to V if N is increased/decreased? 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What is the final pressure in Pa? T= 273K and 300K i think u have to convert L to m^3?	null
2,181	a8a79ad2-6ddd-11ea-853e-ccda262736ce	https://socratic.org/questions/in-a-calorimeter-10-0-g-of-ice-melts-at-0-c-the-enthalpy-of-fusion-of-the-ice-is	3.34 kJ	start physical_unit 6 6 heat_energy kj qc_end physical_unit 6 6 3 4 mass qc_end physical_unit 6 6 9 10 temperature qc_end physical_unit 16 17 19 20 enthalpy_of_fusion qc_end end	[{"type":"physical unit","value":"Heat absorbed [OF] ice [IN] kJ"}]	[{"type":"physical unit","value":"3.34 kJ"}]	[{"type":"physical unit","value":"Mass [OF] ice [=] \\pu{10.0 g}"},{"type":"physical unit","value":"Temperature [OF] ice [=] \\pu{0 ℃}"},{"type":"physical unit","value":"Enthalpy of fusion [OF] the ice [=] \\pu{334 J/g}"}]	<h1 class="questionTitle" itemprop="name">In a calorimeter, 10.0 g of ice melts at 0°C. The enthalpy of fusion of the ice is 334 J/g. How much heat was absorbed?</h1>	null	3.34 kJ	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <strong><a href="http://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> of fusion</strong>, sometimes referred to as <em>latent heat of fusion</em>, tells you how much heat is required in order to convert <mathjax>#"1 g"#</mathjax> of a given substance from solid at its melting point to liquid at its melting point. </p> <p>In your case, you know that water has an enthalpy of fusion, <mathjax>#DeltaH_"fus"#</mathjax>, equal to <mathjax>#"334 J g"^(-1)#</mathjax>. </p> <p>This tells you that in order to melt <mathjax>#"1 g"#</mathjax> of ice at <mathjax>#0^@"C"#</mathjax> to <mathjax>#"1 g"#</mathjax> of liquid water at <mathjax>#0^@"C"#</mathjax>, you need to supply it with <mathjax>#"334 J"#</mathjax> of heat. </p> <p><img alt="http://alcheme.tamu.edu/?page_id=2245" src="https://useruploads.socratic.org/QZYcxH3TdCu7lCqc1ZIm_LatentHeatofFusion.jpg"/> </p> <p>So, if <strong>every gram</strong> of ice at <mathjax>#0^@"C"#</mathjax> requires <mathjax>#"334 J"#</mathjax> of heat in order to become liquid water at <mathjax>#0^@"C"#</mathjax>, it follows that <mathjax>#"10.0 g"#</mathjax> of ice will require</p> <blockquote> <p><mathjax>#10.0 color(red)(cancel(color(black)("g"))) * overbrace("334 J"/(1color(red)(cancel(color(black)("g")))))^(color(purple)(DeltaH_"fus")) = color(green)(\|bar(ul(color(white)(a/a)"3,340 J"color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>If you want, you can express the answer in <em>kilojoules</em> by using the fact that <mathjax>#"1 kJ" = 10^3"J"#</mathjax></p> <blockquote> <p><mathjax>#"heat needed" = color(green)(\|bar(ul(color(white)(a/a)"3.34 kJ"color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"3.34 kJ"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <strong><a href="http://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> of fusion</strong>, sometimes referred to as <em>latent heat of fusion</em>, tells you how much heat is required in order to convert <mathjax>#"1 g"#</mathjax> of a given substance from solid at its melting point to liquid at its melting point. </p> <p>In your case, you know that water has an enthalpy of fusion, <mathjax>#DeltaH_"fus"#</mathjax>, equal to <mathjax>#"334 J g"^(-1)#</mathjax>. </p> <p>This tells you that in order to melt <mathjax>#"1 g"#</mathjax> of ice at <mathjax>#0^@"C"#</mathjax> to <mathjax>#"1 g"#</mathjax> of liquid water at <mathjax>#0^@"C"#</mathjax>, you need to supply it with <mathjax>#"334 J"#</mathjax> of heat. </p> <p><img alt="http://alcheme.tamu.edu/?page_id=2245" src="https://useruploads.socratic.org/QZYcxH3TdCu7lCqc1ZIm_LatentHeatofFusion.jpg"/> </p> <p>So, if <strong>every gram</strong> of ice at <mathjax>#0^@"C"#</mathjax> requires <mathjax>#"334 J"#</mathjax> of heat in order to become liquid water at <mathjax>#0^@"C"#</mathjax>, it follows that <mathjax>#"10.0 g"#</mathjax> of ice will require</p> <blockquote> <p><mathjax>#10.0 color(red)(cancel(color(black)("g"))) * overbrace("334 J"/(1color(red)(cancel(color(black)("g")))))^(color(purple)(DeltaH_"fus")) = color(green)(\|bar(ul(color(white)(a/a)"3,340 J"color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>If you want, you can express the answer in <em>kilojoules</em> by using the fact that <mathjax>#"1 kJ" = 10^3"J"#</mathjax></p> <blockquote> <p><mathjax>#"heat needed" = color(green)(\|bar(ul(color(white)(a/a)"3.34 kJ"color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">In a calorimeter, 10.0 g of ice melts at 0°C. The enthalpy of fusion of the ice is 334 J/g. How much heat was absorbed?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/thermochemistry-of-phase-changes" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry of Phase Changes</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="245365" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-26T12:44:43" itemprop="dateCreated"> Mar 26, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"3.34 kJ"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <strong><a href="http://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> of fusion</strong>, sometimes referred to as <em>latent heat of fusion</em>, tells you how much heat is required in order to convert <mathjax>#"1 g"#</mathjax> of a given substance from solid at its melting point to liquid at its melting point. </p> <p>In your case, you know that water has an enthalpy of fusion, <mathjax>#DeltaH_"fus"#</mathjax>, equal to <mathjax>#"334 J g"^(-1)#</mathjax>. </p> <p>This tells you that in order to melt <mathjax>#"1 g"#</mathjax> of ice at <mathjax>#0^@"C"#</mathjax> to <mathjax>#"1 g"#</mathjax> of liquid water at <mathjax>#0^@"C"#</mathjax>, you need to supply it with <mathjax>#"334 J"#</mathjax> of heat. </p> <p><img alt="http://alcheme.tamu.edu/?page_id=2245" src="https://useruploads.socratic.org/QZYcxH3TdCu7lCqc1ZIm_LatentHeatofFusion.jpg"/> </p> <p>So, if <strong>every gram</strong> of ice at <mathjax>#0^@"C"#</mathjax> requires <mathjax>#"334 J"#</mathjax> of heat in order to become liquid water at <mathjax>#0^@"C"#</mathjax>, it follows that <mathjax>#"10.0 g"#</mathjax> of ice will require</p> <blockquote> <p><mathjax>#10.0 color(red)(cancel(color(black)("g"))) * overbrace("334 J"/(1color(red)(cancel(color(black)("g")))))^(color(purple)(DeltaH_"fus")) = color(green)(\|bar(ul(color(white)(a/a)"3,340 J"color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>If you want, you can express the answer in <em>kilojoules</em> by using the fact that <mathjax>#"1 kJ" = 10^3"J"#</mathjax></p> <blockquote> <p><mathjax>#"heat needed" = color(green)(\|bar(ul(color(white)(a/a)"3.34 kJ"color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/245365" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-much-energy-is-required-to-heat-100-g-of-ice-at-0-00-degrees-celsius-to-wate"> How much energy is required to convert 100.g of ice at 0.00 °C to water vapor at 100.00 °C? 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</a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/thermochemistry-of-phase-changes"> See all questions in Thermochemistry of Phase Changes </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 11241 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	In a calorimeter, 10.0 g of ice melts at 0°C. The enthalpy of fusion of the ice is 334 J/g. How much heat was absorbed?	null
2,182	ac3e39f8-6ddd-11ea-9549-ccda262736ce	https://socratic.org/questions/a-gas-occupies-12-3-l-at-a-pressure-of-40-0-mm-hg-what-is-the-volume-when-the-pr	8.20 L	start physical_unit 1 1 volume l qc_end physical_unit 1 1 3 4 volume qc_end physical_unit 1 1 9 10 pressure qc_end end	[{"type":"physical unit","value":"Volume2 [OF] the gas [IN] L"}]	[{"type":"physical unit","value":"8.20 L"}]	[{"type":"physical unit","value":"Volume1 [OF] the gas [=] \\pu{12.3 L}"},{"type":"physical unit","value":"Pressure1 [OF] the gas [=] \\pu{40.0 mmHg}"},{"type":"physical unit","value":"Pressure2 [OF] the gas [=] \\pu{60.00 mmHg}"}]	<h1 class="questionTitle" itemprop="name">A gas occupies 12.3 L at a pressure of 40.0 mm Hg. What is the volume when the pressure is increased to 60.0 mm Hg?</h1>	null	8.20 L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So, <mathjax>#V_2=(P_1V_1)/P_2#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(40"mm Hg"xx12.3L)/(60*"mm Hg")#</mathjax> <mathjax># ~=#</mathjax> <mathjax>#8#</mathjax> <mathjax>#L#</mathjax>.</p> <p>That volume is reduced is reasonable, inasmuch as the gas has been compressed. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>At constant temperature <mathjax>#P_1V_1=P_2V_2#</mathjax>. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So, <mathjax>#V_2=(P_1V_1)/P_2#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(40"mm Hg"xx12.3L)/(60*"mm Hg")#</mathjax> <mathjax># ~=#</mathjax> <mathjax>#8#</mathjax> <mathjax>#L#</mathjax>.</p> <p>That volume is reduced is reasonable, inasmuch as the gas has been compressed. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A gas occupies 12.3 L at a pressure of 40.0 mm Hg. What is the volume when the pressure is increased to 60.0 mm Hg?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/stoichiometry-involving-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="227264" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-02-16T21:18:21" itemprop="dateCreated"> Feb 16, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>At constant temperature <mathjax>#P_1V_1=P_2V_2#</mathjax>. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So, <mathjax>#V_2=(P_1V_1)/P_2#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(40"mm Hg"xx12.3L)/(60*"mm Hg")#</mathjax> <mathjax># ~=#</mathjax> <mathjax>#8#</mathjax> <mathjax>#L#</mathjax>.</p> <p>That volume is reduced is reasonable, inasmuch as the gas has been compressed. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/227264" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-apply-gas-stoichiometry"> How do you apply gas stoichiometry? 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</a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-2-00-g-mixture-of-na-and-ca-reat-with-water-1-164-l-hydrogen-was-produced-a"> When 2.00 g mixture of Na and Ca reat with water, 1.164 L hydrogen was produced at 300.0 K and... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/stoichiometry-involving-gases"> See all questions in Gas Stoichiometry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 64281 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A gas occupies 12.3 L at a pressure of 40.0 mm Hg. What is the volume when the pressure is increased to 60.0 mm Hg?	null
2,183	acb61a0a-6ddd-11ea-a88b-ccda262736ce	https://socratic.org/questions/in-a-calorimeter-1-0-kg-of-ice-melts-at-0-c-the-enthalpy-of-fusion-of-the-ice-is	334 kJ	start physical_unit 6 6 heat_energy kj qc_end physical_unit 6 6 3 4 mass qc_end physical_unit 6 6 9 10 temperature qc_end physical_unit 6 6 19 20 enthalpy_of_fusion qc_end end	[{"type":"physical unit","value":"Absorbed heat [OF] ice [IN] kJ"}]	[{"type":"physical unit","value":"334 kJ"}]	[{"type":"physical unit","value":"Mass [OF] ice [=] \\pu{1.0 kg}"},{"type":"physical unit","value":"Temperature [OF] ice [=] \\pu{0 ℃}"},{"type":"physical unit","value":"Enthalpy of fusion [OF] ice [=] \\pu{334 J/g}"}]	<h1 class="questionTitle" itemprop="name">In a calorimeter, 1.0 kg of ice melts at 0°C. The enthalpy of fusion of the ice is 334 J/g. How much heat was absorbed?</h1>	null	334 kJ	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>A given substance's <em><a href="http://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> of fusion</em>, <mathjax>#DeltaH_"fus"#</mathjax>, tells you how much heat is needed in order to convert <strong>one gram</strong> of that substance from <em>solid</em> at its melting point to <em>liquid</em> at its melting point. </p> <p>It's important to remember that <strong><a href="http://socratic.org/chemistry/a-first-introduction-to-matter/introduction-to-phase-changes">phase changes</a></strong> take place at <strong>constant temperature</strong>, which is why you'll sometimes see the enthalpy of fusion being referred to as the <em>latent heat of fusion</em>. </p> <p><img alt="http://alcheme.tamu.edu/?page_id=2245" src="https://useruploads.socratic.org/PbiIQTsCSLKj8Ajs9zjb_LatentHeatofFusion.jpg"/> </p> <p>So, ice has an enthalpy of fusion equal to <mathjax>#"334 J g"^(-1)#</mathjax>. This means that in order to convert <mathjax>#"1 g"#</mathjax> of solid ice at <mathjax>#0^@"C"#</mathjax> to <mathjax>#"1 g"#</mathjax> of liquid water at <mathjax>#0^@"C"#</mathjax>, you need to provide it with <mathjax>#"334 J"#</mathjax> of heat. </p> <p>To determine how much heat is needed to convert <mathjax>#"1.0 kg"#</mathjax> of solid ice to liquid water, both at <mathjax>#0^@"C"#</mathjax>, you can use the enthalpy of fusion as a <em>conversion factor</em>. </p> <p>First, convert the mass of the sample to <em>grams</em> by using the conversion factor</p> <blockquote> <p><mathjax>#"1 kg" = 10^3"g"#</mathjax></p> </blockquote> <p>This will get you </p> <blockquote> <p><mathjax>#1.0 color(red)(cancel(color(black)("kg"))) * (10^3"g")/(1color(red)(cancel(color(black)("kg")))) = 1.0 * 10^3"g"#</mathjax></p> </blockquote> <p>Use the mass of the sample and the enthalpy of fusion of ice to find</p> <blockquote> <p><mathjax>#1.0 * 10^3color(red)(cancel(color(black)("g"))) * overbrace("334 J"/(1color(red)(cancel(color(black)("g")))))^(color(purple)(DeltaH_"fus")) = 334 * 10^3"J"#</mathjax></p> </blockquote> <p>You need to round this off to two <strong><a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the sample of ice. You can also express the result in <em>kilojoules</em> by using the conversion factor</p> <blockquote> <p><mathjax>#"1 kJ" = 10^3"J"#</mathjax></p> </blockquote> <p>The answer will thus be </p> <blockquote> <p><mathjax>#"heat absorbed" = color(green)(\|bar(ul(color(white)(a/a)"330 kJ"color(white)(a/a)))\|)#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"330 kJ"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>A given substance's <em><a href="http://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> of fusion</em>, <mathjax>#DeltaH_"fus"#</mathjax>, tells you how much heat is needed in order to convert <strong>one gram</strong> of that substance from <em>solid</em> at its melting point to <em>liquid</em> at its melting point. </p> <p>It's important to remember that <strong><a href="http://socratic.org/chemistry/a-first-introduction-to-matter/introduction-to-phase-changes">phase changes</a></strong> take place at <strong>constant temperature</strong>, which is why you'll sometimes see the enthalpy of fusion being referred to as the <em>latent heat of fusion</em>. </p> <p><img alt="http://alcheme.tamu.edu/?page_id=2245" src="https://useruploads.socratic.org/PbiIQTsCSLKj8Ajs9zjb_LatentHeatofFusion.jpg"/> </p> <p>So, ice has an enthalpy of fusion equal to <mathjax>#"334 J g"^(-1)#</mathjax>. This means that in order to convert <mathjax>#"1 g"#</mathjax> of solid ice at <mathjax>#0^@"C"#</mathjax> to <mathjax>#"1 g"#</mathjax> of liquid water at <mathjax>#0^@"C"#</mathjax>, you need to provide it with <mathjax>#"334 J"#</mathjax> of heat. </p> <p>To determine how much heat is needed to convert <mathjax>#"1.0 kg"#</mathjax> of solid ice to liquid water, both at <mathjax>#0^@"C"#</mathjax>, you can use the enthalpy of fusion as a <em>conversion factor</em>. </p> <p>First, convert the mass of the sample to <em>grams</em> by using the conversion factor</p> <blockquote> <p><mathjax>#"1 kg" = 10^3"g"#</mathjax></p> </blockquote> <p>This will get you </p> <blockquote> <p><mathjax>#1.0 color(red)(cancel(color(black)("kg"))) * (10^3"g")/(1color(red)(cancel(color(black)("kg")))) = 1.0 * 10^3"g"#</mathjax></p> </blockquote> <p>Use the mass of the sample and the enthalpy of fusion of ice to find</p> <blockquote> <p><mathjax>#1.0 * 10^3color(red)(cancel(color(black)("g"))) * overbrace("334 J"/(1color(red)(cancel(color(black)("g")))))^(color(purple)(DeltaH_"fus")) = 334 * 10^3"J"#</mathjax></p> </blockquote> <p>You need to round this off to two <strong><a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the sample of ice. You can also express the result in <em>kilojoules</em> by using the conversion factor</p> <blockquote> <p><mathjax>#"1 kJ" = 10^3"J"#</mathjax></p> </blockquote> <p>The answer will thus be </p> <blockquote> <p><mathjax>#"heat absorbed" = color(green)(\|bar(ul(color(white)(a/a)"330 kJ"color(white)(a/a)))\|)#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">In a calorimeter, 1.0 kg of ice melts at 0°C. The enthalpy of fusion of the ice is 334 J/g. How much heat was absorbed?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/thermochemistry-of-phase-changes" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry of Phase Changes</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="235995" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-06T20:33:24" itemprop="dateCreated"> Mar 6, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"330 kJ"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>A given substance's <em><a href="http://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> of fusion</em>, <mathjax>#DeltaH_"fus"#</mathjax>, tells you how much heat is needed in order to convert <strong>one gram</strong> of that substance from <em>solid</em> at its melting point to <em>liquid</em> at its melting point. </p> <p>It's important to remember that <strong><a href="http://socratic.org/chemistry/a-first-introduction-to-matter/introduction-to-phase-changes">phase changes</a></strong> take place at <strong>constant temperature</strong>, which is why you'll sometimes see the enthalpy of fusion being referred to as the <em>latent heat of fusion</em>. </p> <p><img alt="http://alcheme.tamu.edu/?page_id=2245" src="https://useruploads.socratic.org/PbiIQTsCSLKj8Ajs9zjb_LatentHeatofFusion.jpg"/> </p> <p>So, ice has an enthalpy of fusion equal to <mathjax>#"334 J g"^(-1)#</mathjax>. This means that in order to convert <mathjax>#"1 g"#</mathjax> of solid ice at <mathjax>#0^@"C"#</mathjax> to <mathjax>#"1 g"#</mathjax> of liquid water at <mathjax>#0^@"C"#</mathjax>, you need to provide it with <mathjax>#"334 J"#</mathjax> of heat. </p> <p>To determine how much heat is needed to convert <mathjax>#"1.0 kg"#</mathjax> of solid ice to liquid water, both at <mathjax>#0^@"C"#</mathjax>, you can use the enthalpy of fusion as a <em>conversion factor</em>. </p> <p>First, convert the mass of the sample to <em>grams</em> by using the conversion factor</p> <blockquote> <p><mathjax>#"1 kg" = 10^3"g"#</mathjax></p> </blockquote> <p>This will get you </p> <blockquote> <p><mathjax>#1.0 color(red)(cancel(color(black)("kg"))) * (10^3"g")/(1color(red)(cancel(color(black)("kg")))) = 1.0 * 10^3"g"#</mathjax></p> </blockquote> <p>Use the mass of the sample and the enthalpy of fusion of ice to find</p> <blockquote> <p><mathjax>#1.0 * 10^3color(red)(cancel(color(black)("g"))) * overbrace("334 J"/(1color(red)(cancel(color(black)("g")))))^(color(purple)(DeltaH_"fus")) = 334 * 10^3"J"#</mathjax></p> </blockquote> <p>You need to round this off to two <strong><a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the sample of ice. You can also express the result in <em>kilojoules</em> by using the conversion factor</p> <blockquote> <p><mathjax>#"1 kJ" = 10^3"J"#</mathjax></p> </blockquote> <p>The answer will thus be </p> <blockquote> <p><mathjax>#"heat absorbed" = color(green)(\|bar(ul(color(white)(a/a)"330 kJ"color(white)(a/a)))\|)#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/235995" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-much-energy-is-required-to-heat-100-g-of-ice-at-0-00-degrees-celsius-to-wate"> How much energy is required to convert 100.g of ice at 0.00 °C to water vapor at 100.00 °C? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/534b309602bf34123dd86d5c"> How do you calculate the heat required to melt 15 kg of silver? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-a-liquid-loses-energy-will-it-change-into-a-gas-or-a-solid"> When a liquid loses energy, will it change into a gas or a solid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-name-of-the-process-when-a-liquid-changes-into-a-gas"> What is the name of the process when a liquid changes into a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-much-energy-is-needed-to-convert-23-0-grams-of-ice-at-10-0-c-into-steam-at-1"> How much energy is needed to convert 23.0 grams of ice at -10.0°C into steam at 109°C? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-amount-of-ice-must-be-added-to-540-0-g-of-water-at-25-0-c-to-cool-the-water"> What amount of ice must be added to 540.0 g of water at 25.0 °C to cool the water to 0.0 °C and... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-find-specific-heat-in-thermochemistry-of-phase-of-changes"> How can I find specific heat in thermochemistry of phase of changes? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-much-energy-is-required-to-convert-100-0-g-of-water-at-20-0-c-completely-to-"> How much energy is required to convert 100.0 g of water at 20.0 °C completely to steam at 100.0 °C? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/calculate-the-number-of-joules-given-off-when-32-0-grams-of-steam-cools-from-110"> Calculate the number of joules given off when 32.0 grams of steam cools from 110.0 °C to ice at -40.0 °C. </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-joules-of-heat-are-needed-to-change-50-0-grams-of-ice-at-15-0-c-to-stea"> How many joules of heat are needed to change 50.0 grams of ice at -15.0 °C to steam at 120.0 °C? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/thermochemistry-of-phase-changes"> See all questions in Thermochemistry of Phase Changes </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 6179 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	In a calorimeter, 1.0 kg of ice melts at 0°C. The enthalpy of fusion of the ice is 334 J/g. How much heat was absorbed?	null
2,184	ac68d7ae-6ddd-11ea-afbd-ccda262736ce	https://socratic.org/questions/when-168-joules-of-heat-is-added-4-grams-of-water-at-283-k-what-is-the-resulting	293.05 K	start physical_unit 10 10 temperature k qc_end physical_unit 10 10 1 2 heat_energy qc_end physical_unit 10 10 7 8 mass qc_end physical_unit 10 10 12 13 temperature qc_end end	[{"type":"physical unit","value":"Temperature2 [OF] water [IN] K"}]	[{"type":"physical unit","value":"293.05 K"}]	[{"type":"physical unit","value":"Added heat [OF] water [=] \\pu{168 joules}"},{"type":"physical unit","value":"Mass [OF] water [=] \\pu{4 grams}"},{"type":"physical unit","value":"Temperature1 [OF] water [=] \\pu{283 K}"}]	<h1 class="questionTitle" itemprop="name">When 168 joules of heat is added 4 grams of water at 283 K, what is the resulting temperature?</h1>	null	293.05 K	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> formula:<br/> <mathjax>#Q=cmDelta T#</mathjax>, where <mathjax>#Q#</mathjax> is the amount of heat transferred, <mathjax>#c#</mathjax> is the specific heat capacity of the substance, <mathjax>#m#</mathjax> is the mass of the object, and <mathjax>#Delta T#</mathjax> is the change in temperature. In order to solve for the change in temperature, use the formula</p> <p><mathjax>#Delta T=Q/(c_(water)m)#</mathjax></p> <p>The standard heat capacity of water, <mathjax>#c_(water)#</mathjax> is <mathjax>#4.18 Jg^(-1)K^(-1)#</mathjax>.</p> <p>And we get <mathjax>#Delta T=(168J)/(4.18 Jg^(-1)K^(-1)4g)=10.0 K#</mathjax></p> <p>Since <mathjax>#Q>0#</mathjax>, the resulting temperature will be <mathjax>#T_(f)=T_(i)+Delta T=283 K+10.0K=293K#</mathjax><br/> <em>(pay special attention to significant figures)</em></p> <p>Additional resources on Heat Capacity and Specific Heat:<br/> <a href="https://www.ck12.org/chemistry/Heat-Capacity-and-Specific-Heat/lesson/Heat-Capacity-and-Specific-Heat-CHEM/?referrer=concept_details" rel="nofollow"></a><a href="https://www.ck12.org/chemistry/Heat-Capacity-and-Specific-Heat/lesson/Heat-Capacity-and-Specific-Heat-CHEM/?referrer=concept_details" rel="nofollow" target="_blank">https://www.ck12.org/chemistry/Heat-Capacity-and-Specific-Heat/lesson/Heat-Capacity-and-Specific-Heat-CHEM/?referrer=concept_details</a> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#293 K#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> formula:<br/> <mathjax>#Q=cmDelta T#</mathjax>, where <mathjax>#Q#</mathjax> is the amount of heat transferred, <mathjax>#c#</mathjax> is the specific heat capacity of the substance, <mathjax>#m#</mathjax> is the mass of the object, and <mathjax>#Delta T#</mathjax> is the change in temperature. In order to solve for the change in temperature, use the formula</p> <p><mathjax>#Delta T=Q/(c_(water)m)#</mathjax></p> <p>The standard heat capacity of water, <mathjax>#c_(water)#</mathjax> is <mathjax>#4.18 Jg^(-1)K^(-1)#</mathjax>.</p> <p>And we get <mathjax>#Delta T=(168J)/(4.18 Jg^(-1)K^(-1)4g)=10.0 K#</mathjax></p> <p>Since <mathjax>#Q>0#</mathjax>, the resulting temperature will be <mathjax>#T_(f)=T_(i)+Delta T=283 K+10.0K=293K#</mathjax><br/> <em>(pay special attention to significant figures)</em></p> <p>Additional resources on Heat Capacity and Specific Heat:<br/> <a href="https://www.ck12.org/chemistry/Heat-Capacity-and-Specific-Heat/lesson/Heat-Capacity-and-Specific-Heat-CHEM/?referrer=concept_details" rel="nofollow"></a><a href="https://www.ck12.org/chemistry/Heat-Capacity-and-Specific-Heat/lesson/Heat-Capacity-and-Specific-Heat-CHEM/?referrer=concept_details" rel="nofollow" target="_blank">https://www.ck12.org/chemistry/Heat-Capacity-and-Specific-Heat/lesson/Heat-Capacity-and-Specific-Heat-CHEM/?referrer=concept_details</a> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">When 168 joules of heat is added 4 grams of water at 283 K, what is the resulting temperature?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/energy-change-in-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Energy Change in Reactions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="421309" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/jacob-t-3"><img alt="" class="" src="https://profilepictures.socratic.org/cDl6OiFtT16bIyMtJPfM_Protractor.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/jacob-t-3"> Jacob T. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-11T04:39:01" itemprop="dateCreated"> May 11, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#293 K#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> formula:<br/> <mathjax>#Q=cmDelta T#</mathjax>, where <mathjax>#Q#</mathjax> is the amount of heat transferred, <mathjax>#c#</mathjax> is the specific heat capacity of the substance, <mathjax>#m#</mathjax> is the mass of the object, and <mathjax>#Delta T#</mathjax> is the change in temperature. In order to solve for the change in temperature, use the formula</p> <p><mathjax>#Delta T=Q/(c_(water)m)#</mathjax></p> <p>The standard heat capacity of water, <mathjax>#c_(water)#</mathjax> is <mathjax>#4.18 Jg^(-1)K^(-1)#</mathjax>.</p> <p>And we get <mathjax>#Delta T=(168J)/(4.18 Jg^(-1)K^(-1)4g)=10.0 K#</mathjax></p> <p>Since <mathjax>#Q>0#</mathjax>, the resulting temperature will be <mathjax>#T_(f)=T_(i)+Delta T=283 K+10.0K=293K#</mathjax><br/> <em>(pay special attention to significant figures)</em></p> <p>Additional resources on Heat Capacity and Specific Heat:<br/> <a href="https://www.ck12.org/chemistry/Heat-Capacity-and-Specific-Heat/lesson/Heat-Capacity-and-Specific-Heat-CHEM/?referrer=concept_details" rel="nofollow"></a><a href="https://www.ck12.org/chemistry/Heat-Capacity-and-Specific-Heat/lesson/Heat-Capacity-and-Specific-Heat-CHEM/?referrer=concept_details" rel="nofollow" target="_blank">https://www.ck12.org/chemistry/Heat-Capacity-and-Specific-Heat/lesson/Heat-Capacity-and-Specific-Heat-CHEM/?referrer=concept_details</a> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/421309" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-endothermic-reactions-happen"> Why do endothermic reactions happen? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-causes-energy-changes-in-chemical-reactions"> What causes energy changes in chemical reactions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-endothermic-reactions-absorb-heat"> How do endothermic reactions absorb heat? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-endothermic-reaction-be-spontaneous"> How can endothermic reaction be spontaneous? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5584c3ec581e2a7bc3ecf000"> How do I relate equilibrium constants to temperature change to find the enthalpy of reaction? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-happens-to-particles-when-a-substance-gains-energy-and-changes-state"> What happens to particles when a substance gains energy and changes state? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/for-an-isothermal-process-s"> For an isothermal process, S = __________? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-you-seal-the-end-of-a-syringe-and-push-on-the-plunger-is-that-process-isother"> If you seal the end of a syringe and push on the plunger, is that process isothermal? 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What is the change in... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/energy-change-in-reactions"> See all questions in Energy Change in Reactions </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1590 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	When 168 joules of heat is added 4 grams of water at 283 K, what is the resulting temperature?	null
2,185	ad0e7eb1-6ddd-11ea-9aae-ccda262736ce	https://socratic.org/questions/how-do-you-find-the-percent-composition-of-oxygen-in-sodium-hydroxide	40.00%	start physical_unit 8 11 percent_composition none qc_end substance 10 11 qc_end substance 8 8 qc_end end	[{"type":"physical unit","value":"Percent composition [OF] oxygen in sodium hydroxide"}]	[{"type":"physical unit","value":"40.00%"}]	[{"type":"substance name","value":"Sodium hydroxide"},{"type":"substance name","value":"Oxygen"}]	<h1 class="questionTitle" itemprop="name">How do you find the percent composition of oxygen in sodium hydroxide?</h1>	null	40.00%	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Determine the molar mass of sodium hydroxide <mathjax>#("NaOH")#</mathjax>. Then divide the molar mass of oxygen by the molar mass of <mathjax>#"NaOH"#</mathjax>, and multiply by 100.</p> <p><strong>Molar Masses</strong></p> <p><mathjax>#"NaOH":#</mathjax><mathjax>#"39.997 g/mol"#</mathjax><br/> <a href="https://www.ncbi.nlm.nih.gov/pccompound?term=NaOH" rel="nofollow" target="_blank">https://www.ncbi.nlm.nih.gov/pccompound?term=NaOH</a></p> <p><mathjax>#"O":#</mathjax><mathjax>#"15.999 g/mol"#</mathjax> (periodic table) </p> <p><strong>Percent Composition of Oxygen</strong></p> <p><mathjax>#"percent composition"=(15.999cancel("g"/"mol"))/(39.997cancel("g"/"mol"))xx100="40.000%"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The <a href="https://socratic.org/chemistry/the-mole-concept/percent-composition">percent composition</a> of oxygen in sodium hydroxide is <mathjax>#40.000%#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Determine the molar mass of sodium hydroxide <mathjax>#("NaOH")#</mathjax>. Then divide the molar mass of oxygen by the molar mass of <mathjax>#"NaOH"#</mathjax>, and multiply by 100.</p> <p><strong>Molar Masses</strong></p> <p><mathjax>#"NaOH":#</mathjax><mathjax>#"39.997 g/mol"#</mathjax><br/> <a href="https://www.ncbi.nlm.nih.gov/pccompound?term=NaOH" rel="nofollow" target="_blank">https://www.ncbi.nlm.nih.gov/pccompound?term=NaOH</a></p> <p><mathjax>#"O":#</mathjax><mathjax>#"15.999 g/mol"#</mathjax> (periodic table) </p> <p><strong>Percent Composition of Oxygen</strong></p> <p><mathjax>#"percent composition"=(15.999cancel("g"/"mol"))/(39.997cancel("g"/"mol"))xx100="40.000%"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you find the percent composition of oxygen in sodium hydroxide?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/percent-composition" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Composition</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="394165" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-21T00:34:14" itemprop="dateCreated"> Mar 21, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The <a href="https://socratic.org/chemistry/the-mole-concept/percent-composition">percent composition</a> of oxygen in sodium hydroxide is <mathjax>#40.000%#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Determine the molar mass of sodium hydroxide <mathjax>#("NaOH")#</mathjax>. Then divide the molar mass of oxygen by the molar mass of <mathjax>#"NaOH"#</mathjax>, and multiply by 100.</p> <p><strong>Molar Masses</strong></p> <p><mathjax>#"NaOH":#</mathjax><mathjax>#"39.997 g/mol"#</mathjax><br/> <a href="https://www.ncbi.nlm.nih.gov/pccompound?term=NaOH" rel="nofollow" target="_blank">https://www.ncbi.nlm.nih.gov/pccompound?term=NaOH</a></p> <p><mathjax>#"O":#</mathjax><mathjax>#"15.999 g/mol"#</mathjax> (periodic table) </p> <p><strong>Percent Composition of Oxygen</strong></p> <p><mathjax>#"percent composition"=(15.999cancel("g"/"mol"))/(39.997cancel("g"/"mol"))xx100="40.000%"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/394165" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-mole-percent"> What is mole percent? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4188602bf3469570e2e8b"> Question #e2e8b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4188702bf34695a6bc737"> Question #bc737 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418be02bf34695a6bc73b"> Question #bc73b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418c202bf3469570e2e8f"> Question #e2e8f </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418c802bf346963eb9857"> Question #b9857 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418ca02bf346963eb985b"> Question #b985b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418cc02bf34694a4fee41"> Question #fee41 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418d502bf34694c8c5c01"> Question #c5c01 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4196e02bf34695a6bc73f"> Question #bc73f </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/percent-composition"> See all questions in Percent Composition </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 23505 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How do you find the percent composition of oxygen in sodium hydroxide?	null
2,186	ab7cfce3-6ddd-11ea-adcf-ccda262736ce	https://socratic.org/questions/572a267a11ef6b14cbd481fe	1000.00 m^3	start physical_unit 5 5 volume m^3 qc_end physical_unit 5 5 1 2 volume qc_end physical_unit 5 5 7 8 pressure qc_end physical_unit 5 5 13 14 pressure qc_end end	[{"type":"physical unit","value":"Volume2 [OF] the gas [IN] m^3"}]	[{"type":"physical unit","value":"1000.00 m^3"}]	[{"type":"physical unit","value":"Volume1 [OF] the gas [=] \\pu{2500 m^3}"},{"type":"physical unit","value":"Pressure1 [OF] the gas [=] \\pu{200 kPa}"},{"type":"physical unit","value":"Pressure2 [OF] the gas [=] \\pu{500 kPa}"}]	<h1 class="questionTitle" itemprop="name">A #2500m^3# volume of gas under #200kPa# pressure is compressed to #500*kPa#. What is the new volume?</h1>	null	1000.00 m^3	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So <mathjax>#P_1V_1=P_2V_2#</mathjax>, and thus,</p> <p><mathjax>#V_2#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(P_1V_1)/P_2#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(200kPaxx2500m^3)/(500kPa)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??m^3#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Given constant temperature, we use <a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's law</a>, <mathjax>#Pprop1/V#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So <mathjax>#P_1V_1=P_2V_2#</mathjax>, and thus,</p> <p><mathjax>#V_2#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(P_1V_1)/P_2#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(200kPaxx2500m^3)/(500kPa)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??m^3#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A #2500m^3# volume of gas under #200kPa# pressure is compressed to #500kPa#. What is the new volume?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/gas-laws" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Laws</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="264529" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-11T06:19:56" itemprop="dateCreated"> May 11, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Given constant temperature, we use <a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's law</a>, <mathjax>#Pprop1/V#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So <mathjax>#P_1V_1=P_2V_2#</mathjax>, and thus,</p> <p><mathjax>#V_2#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(P_1V_1)/P_2#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(200kPaxx2500m^3)/(500kPa)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??*m^3#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/264529" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-boyles-law-relate-to-breathing"> How does Boyle's law relate to breathing? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/in-avogadro-s-law-what-would-happen-to-v-if-n-is-increased-decreased-and-what-wo"> In Avogadro's Law what would happen to V if N is increased/decreased? 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If the gas is compressed to 23.52 L and the... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-the-r-stand-for-in-the-ideal-gas-law-pv-nrt"> What does the R stand for in the ideal gas law (PV=nRT)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-mass-of-a-gas-that-occupies-48-9-liters-has-a-pressure-of-724-torr-a"> What is the mass of a gas that occupies 48.9 liters, has a pressure of 724 torr, a temperature... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-a-sample-of-neon-gas-occupies-a-volume-of-2-8l-at-1-8-atm-what-will-its-volum"> If a sample of neon gas occupies a volume of 2.8L at 1.8 atm. what will its volume be at 1.2 atm? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/gas-laws"> See all questions in Gas Laws </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1431 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A #2500m^3# volume of gas under #200kPa# pressure is compressed to #500*kPa#. What is the new volume?	null
2,187	ab039dd2-6ddd-11ea-84fb-ccda262736ce	https://socratic.org/questions/what-is-the-empirical-formula-of-the-unknown-compound	C3H8O	start chemical_formula qc_end c_other OTHER qc_end physical_unit 23 24 20 21 mass qc_end physical_unit 29 29 26 27 mass qc_end physical_unit 34 34 20 21 mass qc_end end	[{"type":"other","value":"Chemical Formula [OF] the unknown compound [IN] empirical"}]	[{"type":"chemical equation","value":"C3H8O"}]	[{"type":"other","value":"An unknown compound contains only C, H, and O."},{"type":"physical unit","value":"Mass [OF] this compound [=] \\pu{4.90 g}"},{"type":"physical unit","value":"Mass [OF] CO2 [=] \\pu{12.0 g}"},{"type":"physical unit","value":"Mass [OF] H2O [=] \\pu{4.90 g}"}]	<h1 class="questionTitle" itemprop="name">What is the empirical formula of the unknown compound?</h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>An unknown compound contains only C, H, and O. Combustion of 4.90 g of this compound produced 12.0 g of CO2 and 4.90 g of H2O.</p> <p>CHO (insert subscripts as needed)</p></div> </h2> </div> </div>	C3H8O	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Since I want you to get some practice yourself, I will be showing you the method but to a different question. Hopefully, it will help you to solve this one.</p> <p>What is the empirical formula for isopropyl alcohol (which contains only C, H and O) if the combustion of <mathjax>#0.255#</mathjax> <mathjax>#"g"#</mathjax> of isopropyl alcohol sample produces <mathjax>#0.561#</mathjax> <mathjax>#"g"#</mathjax> of <mathjax>#"CO"_2#</mathjax> and <mathjax>#0.306#</mathjax> <mathjax>#"g"#</mathjax> of <mathjax>#"H"_2"O"#</mathjax>?</p> <p>Before we start working out, we have to assume that we have one mole of all reagents and products.</p> <p>If we write the empirical formula of the compound as <mathjax>#"C"_x"H"_y"O"_z#</mathjax>, we can write its combustion reaction as:</p> <p><mathjax>#"C"_x"H"_y"O"_z+"O"_2 rarr "CO"_2+"H"_2"O"#</mathjax></p> <p><mathjax>#"n"("CO"_2)=0.561/44.0=0.0128#</mathjax></p> <p>One compound of <mathjax>#"CO"_2#</mathjax> is made up of one carbon atom and two oxygen atoms. So if we have <mathjax>#0.0128#</mathjax> moles of carbon dioxide then we also have <mathjax>#0.0128#</mathjax> moles of carbon in our sample (since we are assuming that we have one mole of each product). So now we can work out the mass of carbon in our product.</p> <p><mathjax>#"m"=0.0128xx12=0.154#</mathjax> <mathjax>#"g"#</mathjax></p> <p><mathjax>#"n"("H"_2"O")=0.306/18.0=0.017#</mathjax></p> <p>One compound of <mathjax>#"H"_2"O"#</mathjax> is made up of one oxygen atom and two hydrogen atoms. So if we have <mathjax>#0.017#</mathjax> moles of water then we also have <mathjax>#2(0.017)#</mathjax>, or <mathjax>#0.034#</mathjax>, moles of hydrogen in our sample. So now we can work out the mass of hydrogen in our product.</p> <p><mathjax>#"m"=0.034xx1=0.034#</mathjax> <mathjax>#"g"#</mathjax></p> <p>Adding these two values together will give us the mass of our compound that <mathjax>#"C"#</mathjax> and <mathjax>#"H"#</mathjax> make up.</p> <p><mathjax>#1.54+0.034=0.188#</mathjax> <mathjax>#"g"#</mathjax></p> <p>So this means that the remaining mass must be oxygen.</p> <p><mathjax>#0.255 - 0.188 = 0.067#</mathjax> <mathjax>#"g"#</mathjax></p> <p><mathjax>#"n"("O"_2)=0.067/16= 0.0042 #</mathjax></p> <p>Now we have the molar ratio of each element in our compound:</p> <p><mathjax>#"C"#</mathjax>: <mathjax>#"H"#</mathjax>:<mathjax>#"O"#</mathjax></p> <p><mathjax>#0.0128:0.017:0.0042#</mathjax></p> <p>We must divide by the smallest value (<mathjax>#0.0042#</mathjax>) to normalise the ratios.</p> <p><mathjax>#3:8:1#</mathjax></p> <p>So the empirical formula of the unknowns compound is <mathjax>#"C"_3"H"_8"O"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"C"_3"H"_8"O"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Since I want you to get some practice yourself, I will be showing you the method but to a different question. Hopefully, it will help you to solve this one.</p> <p>What is the empirical formula for isopropyl alcohol (which contains only C, H and O) if the combustion of <mathjax>#0.255#</mathjax> <mathjax>#"g"#</mathjax> of isopropyl alcohol sample produces <mathjax>#0.561#</mathjax> <mathjax>#"g"#</mathjax> of <mathjax>#"CO"_2#</mathjax> and <mathjax>#0.306#</mathjax> <mathjax>#"g"#</mathjax> of <mathjax>#"H"_2"O"#</mathjax>?</p> <p>Before we start working out, we have to assume that we have one mole of all reagents and products.</p> <p>If we write the empirical formula of the compound as <mathjax>#"C"_x"H"_y"O"_z#</mathjax>, we can write its combustion reaction as:</p> <p><mathjax>#"C"_x"H"_y"O"_z+"O"_2 rarr "CO"_2+"H"_2"O"#</mathjax></p> <p><mathjax>#"n"("CO"_2)=0.561/44.0=0.0128#</mathjax></p> <p>One compound of <mathjax>#"CO"_2#</mathjax> is made up of one carbon atom and two oxygen atoms. So if we have <mathjax>#0.0128#</mathjax> moles of carbon dioxide then we also have <mathjax>#0.0128#</mathjax> moles of carbon in our sample (since we are assuming that we have one mole of each product). So now we can work out the mass of carbon in our product.</p> <p><mathjax>#"m"=0.0128xx12=0.154#</mathjax> <mathjax>#"g"#</mathjax></p> <p><mathjax>#"n"("H"_2"O")=0.306/18.0=0.017#</mathjax></p> <p>One compound of <mathjax>#"H"_2"O"#</mathjax> is made up of one oxygen atom and two hydrogen atoms. So if we have <mathjax>#0.017#</mathjax> moles of water then we also have <mathjax>#2(0.017)#</mathjax>, or <mathjax>#0.034#</mathjax>, moles of hydrogen in our sample. So now we can work out the mass of hydrogen in our product.</p> <p><mathjax>#"m"=0.034xx1=0.034#</mathjax> <mathjax>#"g"#</mathjax></p> <p>Adding these two values together will give us the mass of our compound that <mathjax>#"C"#</mathjax> and <mathjax>#"H"#</mathjax> make up.</p> <p><mathjax>#1.54+0.034=0.188#</mathjax> <mathjax>#"g"#</mathjax></p> <p>So this means that the remaining mass must be oxygen.</p> <p><mathjax>#0.255 - 0.188 = 0.067#</mathjax> <mathjax>#"g"#</mathjax></p> <p><mathjax>#"n"("O"_2)=0.067/16= 0.0042 #</mathjax></p> <p>Now we have the molar ratio of each element in our compound:</p> <p><mathjax>#"C"#</mathjax>: <mathjax>#"H"#</mathjax>:<mathjax>#"O"#</mathjax></p> <p><mathjax>#0.0128:0.017:0.0042#</mathjax></p> <p>We must divide by the smallest value (<mathjax>#0.0042#</mathjax>) to normalise the ratios.</p> <p><mathjax>#3:8:1#</mathjax></p> <p>So the empirical formula of the unknowns compound is <mathjax>#"C"_3"H"_8"O"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the empirical formula of the unknown compound?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>An unknown compound contains only C, H, and O. Combustion of 4.90 g of this compound produced 12.0 g of CO2 and 4.90 g of H2O.</p> <p>CHO (insert subscripts as needed)</p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="344026" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/abdur-r"><img alt="" class="" src="https://profilepictures.socratic.org/YXIUDMM0SoZAxTdY3kn6_niagara_falls_fog_water_height_6376_3840x2160.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/abdur-r"> Monzur R. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-11-29T21:25:54" itemprop="dateCreated"> Nov 29, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"C"_3"H"_8"O"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Since I want you to get some practice yourself, I will be showing you the method but to a different question. Hopefully, it will help you to solve this one.</p> <p>What is the empirical formula for isopropyl alcohol (which contains only C, H and O) if the combustion of <mathjax>#0.255#</mathjax> <mathjax>#"g"#</mathjax> of isopropyl alcohol sample produces <mathjax>#0.561#</mathjax> <mathjax>#"g"#</mathjax> of <mathjax>#"CO"_2#</mathjax> and <mathjax>#0.306#</mathjax> <mathjax>#"g"#</mathjax> of <mathjax>#"H"_2"O"#</mathjax>?</p> <p>Before we start working out, we have to assume that we have one mole of all reagents and products.</p> <p>If we write the empirical formula of the compound as <mathjax>#"C"_x"H"_y"O"_z#</mathjax>, we can write its combustion reaction as:</p> <p><mathjax>#"C"_x"H"_y"O"_z+"O"_2 rarr "CO"_2+"H"_2"O"#</mathjax></p> <p><mathjax>#"n"("CO"_2)=0.561/44.0=0.0128#</mathjax></p> <p>One compound of <mathjax>#"CO"_2#</mathjax> is made up of one carbon atom and two oxygen atoms. So if we have <mathjax>#0.0128#</mathjax> moles of carbon dioxide then we also have <mathjax>#0.0128#</mathjax> moles of carbon in our sample (since we are assuming that we have one mole of each product). So now we can work out the mass of carbon in our product.</p> <p><mathjax>#"m"=0.0128xx12=0.154#</mathjax> <mathjax>#"g"#</mathjax></p> <p><mathjax>#"n"("H"_2"O")=0.306/18.0=0.017#</mathjax></p> <p>One compound of <mathjax>#"H"_2"O"#</mathjax> is made up of one oxygen atom and two hydrogen atoms. So if we have <mathjax>#0.017#</mathjax> moles of water then we also have <mathjax>#2(0.017)#</mathjax>, or <mathjax>#0.034#</mathjax>, moles of hydrogen in our sample. So now we can work out the mass of hydrogen in our product.</p> <p><mathjax>#"m"=0.034xx1=0.034#</mathjax> <mathjax>#"g"#</mathjax></p> <p>Adding these two values together will give us the mass of our compound that <mathjax>#"C"#</mathjax> and <mathjax>#"H"#</mathjax> make up.</p> <p><mathjax>#1.54+0.034=0.188#</mathjax> <mathjax>#"g"#</mathjax></p> <p>So this means that the remaining mass must be oxygen.</p> <p><mathjax>#0.255 - 0.188 = 0.067#</mathjax> <mathjax>#"g"#</mathjax></p> <p><mathjax>#"n"("O"_2)=0.067/16= 0.0042 #</mathjax></p> <p>Now we have the molar ratio of each element in our compound:</p> <p><mathjax>#"C"#</mathjax>: <mathjax>#"H"#</mathjax>:<mathjax>#"O"#</mathjax></p> <p><mathjax>#0.0128:0.017:0.0042#</mathjax></p> <p>We must divide by the smallest value (<mathjax>#0.0042#</mathjax>) to normalise the ratios.</p> <p><mathjax>#3:8:1#</mathjax></p> <p>So the empirical formula of the unknowns compound is <mathjax>#"C"_3"H"_8"O"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/344026" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molecular-formula-of-a-compound"> How do you find molecular formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-diamond"> What is the chemical formula of a diamond? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-carbohydrate"> What is the chemical formula of a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-valproic-acid"> What is the empirical formula for valproic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-of-magnesium-oxide"> What is the empirical formula of magnesium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-empirical-formula-not-double-that-of-the-monosaccharides"> Why is the empirical formula not double that of the monosaccharides? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5331180502bf342f40b5c3b5"> Question #5c3b5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-molecular-formula-represents-a-carbohydrate"> What molecular formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-of-vinegar"> What is the molecular formula of vinegar? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/empirical-and-molecular-formulas"> See all questions in Empirical and Molecular Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 69661 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the empirical formula of the unknown compound?	An unknown compound contains only C, H, and O. Combustion of 4.90 g of this compound produced 12.0 g of CO2 and 4.90 g of H2O. CHO (insert subscripts as needed)
2,188	aa699a2e-6ddd-11ea-86f8-ccda262736ce	https://socratic.org/questions/the-diameter-of-a-chlorine-atom-is-200-pm-how-many-chlorine-atoms-are-required-t	5.00 × 10^6	start physical_unit 11 12 number none qc_end physical_unit 4 5 7 8 diameter qc_end physical_unit 11 12 26 27 distance qc_end end	[{"type":"physical unit","value":"Number [OF] chlorine atoms"}]	[{"type":"physical unit","value":"5.00 × 10^6"}]	[{"type":"physical unit","value":"Diameter [OF] chlorine atom [=] \\pu{200 pm}"},{"type":"physical unit","value":"Distance [OF] chlorine atoms [=] \\pu{1.0 mm}"}]	<h1 class="questionTitle" itemprop="name">The diameter of a chlorine atom is 200. pm. How many chlorine atoms are required to line up end to end to stretch a distance of 1.0 mm? </h1>	null	5.00 × 10^6	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#(1xx10^-3m)/(200xx10^-12m)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax></p> <p>A more realistic measurement might consider the chlorine molecule. <mathjax>#Cl_2#</mathjax> has a bond length of <mathjax>#2.00xx10^-10#</mathjax> <mathjax>#m#</mathjax>. How many of these ened to end will fit in a <mathjax>#mm#</mathjax>. Pretty vast but not infinite. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Good question. <mathjax>#(1xx10^-3m)/(200xx10^-12m)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#(1xx10^-3m)/(200xx10^-12m)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax></p> <p>A more realistic measurement might consider the chlorine molecule. <mathjax>#Cl_2#</mathjax> has a bond length of <mathjax>#2.00xx10^-10#</mathjax> <mathjax>#m#</mathjax>. How many of these ened to end will fit in a <mathjax>#mm#</mathjax>. Pretty vast but not infinite. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">The diameter of a chlorine atom is 200. pm. How many chlorine atoms are required to line up end to end to stretch a distance of 1.0 mm? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-periodic-table" itemprop="url"> <span class="breadcrumb" itemprop="title">The Periodic Table</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-periodic-table/periodic-trends-in-atomic-size" itemprop="url"> <span class="breadcrumb" itemprop="title">Periodic Trends in Atomic Size</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="303582" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-08-28T20:54:48" itemprop="dateCreated"> Aug 28, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Good question. <mathjax>#(1xx10^-3m)/(200xx10^-12m)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#(1xx10^-3m)/(200xx10^-12m)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax></p> <p>A more realistic measurement might consider the chlorine molecule. <mathjax>#Cl_2#</mathjax> has a bond length of <mathjax>#2.00xx10^-10#</mathjax> <mathjax>#m#</mathjax>. How many of these ened to end will fit in a <mathjax>#mm#</mathjax>. Pretty vast but not infinite. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/303582" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-periodic-trends-exist-for-electronegativity"> Why do periodic trends exist for electronegativity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-does-atomic-size-increase-down-a-group"> Why does atomic size increase down a group? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-do-periodic-trends-of-reactivity-occur-with-the-halogens"> What do periodic trends of reactivity occur with the halogens? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-atomic-size-of-ions"> How can I determine atomic size of ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/the-atomic-radii-of-transition-metals-do-not-decrease-significantly-across-a-row"> The atomic radii of transition metals do not decrease significantly across a row. As you add... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-octet-rule-affect-periodic-trends-1"> How does the octet rule affect periodic trends? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-number-of-protons-relate-to-atomic-size"> How does the number of protons relate to atomic size? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-periodic-trend-of-atomic-radius-relate-to-the-addition-of-electrons"> How does the periodic trend of atomic radius relate to the addition of electrons? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-atomic-size-affect-the-energy-released-during-bonding"> How does atomic size affect the energy released during bonding? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-atomic-size-affect-reactivity"> How does atomic size affect reactivity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-periodic-table/periodic-trends-in-atomic-size"> See all questions in Periodic Trends in Atomic Size </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 5473 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	The diameter of a chlorine atom is 200. pm. How many chlorine atoms are required to line up end to end to stretch a distance of 1.0 mm?	null
2,189	a83d7342-6ddd-11ea-8233-ccda262736ce	https://socratic.org/questions/the-ph-of-a-solution-is-7-0-what-is-the-poh	7.0	start physical_unit 4 4 poh none qc_end physical_unit 3 4 6 6 ph qc_end end	[{"type":"physical unit","value":"pOH [OF] the solution"}]	[{"type":"physical unit","value":"7.0"}]	[{"type":"physical unit","value":"pH [OF] a solution [=] \\pu{7.0}"}]	<h1 class="questionTitle" itemprop="name">The pH of a solution is 7.0. What is the pOH? </h1>	null	7.0	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>A fundamental equation to know regarding <mathjax>#"pH"#</mathjax> is that (near <mathjax>#25^"o""C"#</mathjax>),</p> <p><mathjax>#"pH" + "pOH" = 14.00#</mathjax></p> <p>That is, near <mathjax>#25^"o""C"#</mathjax>, the sum of the <mathjax>#"pH"#</mathjax> and <mathjax>#"pOH"#</mathjax> is always <mathjax>#14.00#</mathjax>.</p> <p>Therefore,</p> <p><mathjax>#"pOH"= 14.00 - "pH" = 14.00 - 7.0 = color(red)(7.0#</mathjax></p> <p>Since the <mathjax>#"pH"#</mathjax> and <mathjax>#"pOH"#</mathjax> are equal, this solution is said to be <em>neutral</em>; i.e. it is neither acidic nor alkaline (basic).</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"pOH" = 7.0#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>A fundamental equation to know regarding <mathjax>#"pH"#</mathjax> is that (near <mathjax>#25^"o""C"#</mathjax>),</p> <p><mathjax>#"pH" + "pOH" = 14.00#</mathjax></p> <p>That is, near <mathjax>#25^"o""C"#</mathjax>, the sum of the <mathjax>#"pH"#</mathjax> and <mathjax>#"pOH"#</mathjax> is always <mathjax>#14.00#</mathjax>.</p> <p>Therefore,</p> <p><mathjax>#"pOH"= 14.00 - "pH" = 14.00 - 7.0 = color(red)(7.0#</mathjax></p> <p>Since the <mathjax>#"pH"#</mathjax> and <mathjax>#"pOH"#</mathjax> are equal, this solution is said to be <em>neutral</em>; i.e. it is neither acidic nor alkaline (basic).</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">The pH of a solution is 7.0. What is the pOH? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/the-ph-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">pH</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="438350" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/mrtas"><img alt="" class="" src="https://profilepictures.socratic.org/HY14X7r4S6AyDQgK2gwQ_IMG_0062.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/mrtas"> Nathan L. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-12T02:15:26" itemprop="dateCreated"> Jun 12, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"pOH" = 7.0#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>A fundamental equation to know regarding <mathjax>#"pH"#</mathjax> is that (near <mathjax>#25^"o""C"#</mathjax>),</p> <p><mathjax>#"pH" + "pOH" = 14.00#</mathjax></p> <p>That is, near <mathjax>#25^"o""C"#</mathjax>, the sum of the <mathjax>#"pH"#</mathjax> and <mathjax>#"pOH"#</mathjax> is always <mathjax>#14.00#</mathjax>.</p> <p>Therefore,</p> <p><mathjax>#"pOH"= 14.00 - "pH" = 14.00 - 7.0 = color(red)(7.0#</mathjax></p> <p>Since the <mathjax>#"pH"#</mathjax> and <mathjax>#"pOH"#</mathjax> are equal, this solution is said to be <em>neutral</em>; i.e. it is neither acidic nor alkaline (basic).</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/438350" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-pka"> How do you determine pH from pKa? 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What is the pOH?	null
2,190	ad1d3b47-6ddd-11ea-81de-ccda262736ce	https://socratic.org/questions/57d07dd1b72cff6cc501246f	1.87 grams	start physical_unit 4 5 mass g qc_end physical_unit 15 15 11 12 mass qc_end end	[{"type":"physical unit","value":"Mass [OF] dihydrogen gas [IN] grams"}]	[{"type":"physical unit","value":"1.87 grams"}]	[{"type":"physical unit","value":"Mass [OF] ammonia [=] \\pu{10.53 g}"}]	<h1 class="questionTitle" itemprop="name">How many grams of dihydrogen gas are required to produce a #10.53*g# mass of ammonia?</h1>	null	1.87 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We follow the given stoichiometric equation, which explicitly states that <mathjax>#14g#</mathjax> dinitrogen gas react with <mathjax>#3.0g#</mathjax> dihydrogen to give <mathjax>#17g#</mathjax> ammonia. </p> <p><mathjax>#"Moles of ammonia"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(10.53g)/(17.03gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.618mol#</mathjax></p> <p>And thus <mathjax>#3/2xx0.618molxx2.0159gmol^-1" dihydrogen"#</mathjax> are required. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Almost <mathjax>#2g#</mathjax> of dihydrogen gas are required. </p> <p><mathjax>#1/2N_2(g) + 3/2H_2(g) rarr NH_3(g)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We follow the given stoichiometric equation, which explicitly states that <mathjax>#14g#</mathjax> dinitrogen gas react with <mathjax>#3.0g#</mathjax> dihydrogen to give <mathjax>#17g#</mathjax> ammonia. </p> <p><mathjax>#"Moles of ammonia"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(10.53g)/(17.03gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.618mol#</mathjax></p> <p>And thus <mathjax>#3/2xx0.618molxx2.0159g*mol^-1" dihydrogen"#</mathjax> are required. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many grams of dihydrogen gas are required to produce a #10.53g# mass of ammonia?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="308572" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-09-11T08:50:01" itemprop="dateCreated"> Sep 11, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Almost <mathjax>#2g#</mathjax> of dihydrogen gas are required. </p> <p><mathjax>#1/2N_2(g) + 3/2H_2(g) rarr NH_3(g)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We follow the given stoichiometric equation, which explicitly states that <mathjax>#14g#</mathjax> dinitrogen gas react with <mathjax>#3.0g#</mathjax> dihydrogen to give <mathjax>#17g#</mathjax> ammonia. </p> <p><mathjax>#"Moles of ammonia"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(10.53g)/(17.03gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.618mol#</mathjax></p> <p>And thus <mathjax>#3/2xx0.618molxx2.0159gmol^-1" dihydrogen"#</mathjax> are required. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/308572" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul 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Na2O + H2O ---> 2 NaOH </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-mass-of-iron-is-needed-to-react-with-16-0-grams-of-sulfur-8-fe-s8-8-fes"> What mass of iron is needed to react with 16.0 grams of sulfur? 8 Fe + S8 ---> 8 FeS </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/according-to-8-fe-s8-8-fes-how-many-grams-of-fes-are-produced"> According to 8 Fe + S8 ---> 8 FeS How many grams of FeS are produced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/12-00-moles-of-naclo3-will-produce-how-many-grams-of-o2-2-naclo3-2-nacl-3-o2"> 12.00 moles of NaClO3 will produce how many grams of O2? 2 NaClO3 ---> 2 NaCl + 3 O2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-nacl-are-produced-when-80-0-grams-of-o2-are-produced-2-naclo3-"> How many grams of NaCl are produced when 80.0 grams of O2 are produced? 2 NaClO3 ---> 2 NaCl + 3 O2 </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/stoichiometry"> See all questions in Stoichiometry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 5407 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many grams of dihydrogen gas are required to produce a #10.53*g# mass of ammonia?	null
2,191	acde1f98-6ddd-11ea-a9b7-ccda262736ce	https://socratic.org/questions/how-many-grams-are-there-in-3-moles-of-nh-4	54 grams	start physical_unit 9 9 mass g qc_end physical_unit 9 9 6 7 mole qc_end end	[{"type":"physical unit","value":"Mass [OF] NH4 [IN] grams"}]	[{"type":"physical unit","value":"54 grams"}]	[{"type":"physical unit","value":"Mole [OF] NH4 [=] \\pu{3 moles}"}]	<h1 class="questionTitle" itemprop="name">How many grams are there in 3 moles of #NH_4#?</h1>	null	54 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Recall that:</p> <p><mathjax>#"m"="n"xx"Mr"=3#</mathjax> <mathjax>#"mol"#</mathjax> <mathjax>#xx18#</mathjax> <mathjax>#"g"#</mathjax> <mathjax>#"mol"^-1 =54#</mathjax> <mathjax>#"g"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"m"=54#</mathjax> <mathjax>#"g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Recall that:</p> <p><mathjax>#"m"="n"xx"Mr"=3#</mathjax> <mathjax>#"mol"#</mathjax> <mathjax>#xx18#</mathjax> <mathjax>#"g"#</mathjax> <mathjax>#"mol"^-1 =54#</mathjax> <mathjax>#"g"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many grams are there in 3 moles of #NH_4#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="415965" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/abdur-r"><img alt="" class="" src="https://profilepictures.socratic.org/YXIUDMM0SoZAxTdY3kn6_niagara_falls_fog_water_height_6376_3840x2160.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/abdur-r"> Monzur R. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-01T19:06:55" itemprop="dateCreated"> May 1, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"m"=54#</mathjax> <mathjax>#"g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Recall that:</p> <p><mathjax>#"m"="n"xx"Mr"=3#</mathjax> <mathjax>#"mol"#</mathjax> <mathjax>#xx18#</mathjax> <mathjax>#"g"#</mathjax> <mathjax>#"mol"^-1 =54#</mathjax> <mathjax>#"g"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/415965" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? 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2,192	ac486594-6ddd-11ea-a65b-ccda262736ce	https://socratic.org/questions/how-many-moles-are-in-45-0-sample-of-mgo	1.12 moles	start physical_unit 7 9 mole mol qc_end physical_unit 7 9 5 6 mass qc_end end	[{"type":"physical unit","value":"Mole [OF] MgO sample [IN] moles"}]	[{"type":"physical unit","value":"1.12 moles"}]	[{"type":"physical unit","value":"Mass [OF] MgO sample [=] \\pu{45.0 g}"}]	<h1 class="questionTitle" itemprop="name">How many moles are in 45.0 sample of #MgO#?</h1>	null	1.12 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Mass of one mole of Magnesium Oxide is 40.3044 g<br/> We can set up conversion factors/ ratios</p> <p>1 mol MgO = 40.304 g of MgO</p> <p>1 mol MgO / 40.304 g MgO (a) or 40.340 g MgO / 1 mol MgO (b)</p> <p>Using the conversion factor (b) we can find number of moles.</p> <p>45.0 g MgO x ( 1 mol MgO / 40.304 g MgO )</p> <p>1.1 2 moles MgO</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>1.12 moles MgO</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Mass of one mole of Magnesium Oxide is 40.3044 g<br/> We can set up conversion factors/ ratios</p> <p>1 mol MgO = 40.304 g of MgO</p> <p>1 mol MgO / 40.304 g MgO (a) or 40.340 g MgO / 1 mol MgO (b)</p> <p>Using the conversion factor (b) we can find number of moles.</p> <p>45.0 g MgO x ( 1 mol MgO / 40.304 g MgO )</p> <p>1.1 2 moles MgO</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles are in 45.0 sample of #MgO#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="253604" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/manish-b"><img alt="" class="" src="https://profilepictures.socratic.org/eW7uaERSSvtv5ff2XPxA_10203153902643748.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/manish-b"> Manish Bhardwaj </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-04-13T05:29:59" itemprop="dateCreated"> Apr 13, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>1.12 moles MgO</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Mass of one mole of Magnesium Oxide is 40.3044 g<br/> We can set up conversion factors/ ratios</p> <p>1 mol MgO = 40.304 g of MgO</p> <p>1 mol MgO / 40.304 g MgO (a) or 40.340 g MgO / 1 mol MgO (b)</p> <p>Using the conversion factor (b) we can find number of moles.</p> <p>45.0 g MgO x ( 1 mol MgO / 40.304 g MgO )</p> <p>1.1 2 moles MgO</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/253604" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? 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2,193	ac070e80-6ddd-11ea-a7ca-ccda262736ce	https://socratic.org/questions/you-need-to-prepare-an-acetate-buffer-of-ph-6-32-from-a-0-800-m-acetic-acid-solu	292.76 milliliters	start physical_unit 21 22 volume ml qc_end physical_unit 5 6 9 9 ph qc_end physical_unit 14 16 12 13 molarity qc_end physical_unit 21 22 19 20 molarity qc_end physical_unit 14 16 26 27 volume qc_end end	[{"type":"physical unit","value":"Volume [OF] KOH solution [IN] milliliters"}]	[{"type":"physical unit","value":"292.76 milliliters"}]	[{"type":"physical unit","value":"pH [OF] acetate buffer [=] \\pu{6.32}"},{"type":"physical unit","value":"Molarity [OF] acetic acid solution [=] \\pu{0.800 M}"},{"type":"physical unit","value":"Molarity [OF] KOH solution [=] \\pu{2.46 M}"},{"type":"physical unit","value":"Volume [OF] acetic acid solution [=] \\pu{925 mL}"}]	<h1 class="questionTitle" itemprop="name">You need to prepare an acetate buffer of pH 6.32 from a 0.800 M acetic acid solution and a 2.46 M #KOH# solution. If you have 925 mL of the acetic acid solution, how many milliliters of the #KOH# do you need to add to make a bufer of pH 6.32? </h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>The pKa of acetic acid is 4.76. </p></div> </h2> </div> </div>	292.76 milliliters	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Ethanoic acid is a weak acid and dissociates:</p> <p><mathjax>#sf(CH_3COOHrightleftharpoonsCH_3COO^(-)+H^+)#</mathjax></p> <p>For which:</p> <p><mathjax>#sf(K_a=([CH_3COO^(-)][H^+])/([CH_3COOH]))#</mathjax></p> <p>These are equilibrium concentrations.</p> <p><mathjax>#sf(pK_a=4.76)#</mathjax> from which <mathjax>#sf(K_a=1.737xx10^(-5))#</mathjax></p> <p>Rearranging we get:</p> <p><mathjax>#sf([H^+]=K_axx([CH_3COOH])/([CH_3COO^-]))#</mathjax></p> <p><mathjax>#sf(pH=6.32)#</mathjax> from which <mathjax>#sf([H^+]=4.786xx10^(-7)color(white)(x)"mol/l")#</mathjax></p> <p><mathjax>#:.#</mathjax><mathjax>#sf(4.786xx10^(-7)=1.737xx10^(-5)xx([CH_3COOH])/([CH_3COO^(-)])#</mathjax></p> <p><mathjax>#:.#</mathjax><mathjax>#sf(([CH_3COOH])/([CH_3COO^(-)])=(4.786xx10^(-7))/(1.737xx10^(-5))=0.027553)#</mathjax></p> <p>To get the required pH we need to set the acid : salt ratio to this value.</p> <p>To produce the required ethanoate ions we add <mathjax>#sf(OH^-)#</mathjax> ions:</p> <p><mathjax>#sf(CH_3COOH+OH^(-)rarrCH_3COO^(-)+H_2O)#</mathjax></p> <p>You can see from the equation that the no. moles <mathjax>#sf(OH^-)#</mathjax> added = the no. of moles of <mathjax>#sf(CH_3COO^(-))#</mathjax> produced.</p> <p>Since we know <mathjax>#sf([OH^-])#</mathjax> we can say that if <mathjax>#sf(V)#</mathjax> is the volume of the <mathjax>#sf(OH^-)#</mathjax> solution then:</p> <p><mathjax>#sf(nOH^(-)=nCH_3COO_("eqm")^(-)=2.26xxV)#</mathjax></p> <p>Where <mathjax>#sf(n)#</mathjax> is the no. moles.</p> <p>We know the initial moles of ethanoic acid:</p> <p><mathjax>#sf(nCH_3COOH_("init")=0.800xx0.925=0.740)#</mathjax></p> <p>So we can get the moles after the alkali has been added. Because the dissociation is small we will assume that these are a good approximation to the equilibrium moles:</p> <p><mathjax>#sf(nCH_3COOH_("eqm")=(0.740-2.46V))#</mathjax></p> <p><mathjax>#:.#</mathjax><mathjax>#sf((nCH_3COOH_("eqm"))/(nCH_3COO_("eqm")^(-))=(0.740-2.46V)/(2.46V)=0.027553)#</mathjax></p> <p>We can use moles and not concentrations since the total volume is common to both so cancels anyway.</p> <p><mathjax>#:.#</mathjax><mathjax>#sf(0.740-2.46V=0.027553xx2.46V)#</mathjax></p> <p><mathjax>#sf(0.06778V+2.46V=0.740)#</mathjax></p> <p><mathjax>#sf(V=0.740/2.5277=0.293color(white)(x)L)#</mathjax></p> <p><mathjax>#sf(V=293color(white)(x)"ml")#</mathjax></p> <p><mathjax>#--------------------#</mathjax></p> <p>Check by iteration:</p> <p>Volume KOH = 297 ml</p> <p><mathjax>#sf(nOH^(-)=0.293xx2.46=0.72078)#</mathjax></p> <p><mathjax>#:.#</mathjax><mathjax>#sf(nCH_3COO_("eqm")^(-)=0.72078)#</mathjax></p> <p><mathjax>#sf(nCH_3COOH_("init")=0.740)#</mathjax></p> <p><mathjax>#:.#</mathjax><mathjax>#sf(nCH_3COOH_("eqm")=0.740-0.72078=0.01922)#</mathjax></p> <p><mathjax>#:.#</mathjax> <mathjax>#sf("ratio"" "( ["acid"] )/ (["salt"]) = 0.01922/0.72078 = 0.0266655)#</mathjax></p> <p><mathjax>#sf([H^+]=1.737xx10^(-5)xx0.0266655=0.046318xx10^(-5)color(white)(x)"mol/l")#</mathjax></p> <p><mathjax>#sf(pH=6.33)#</mathjax></p> <p>So not too bad.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>293 ml</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Ethanoic acid is a weak acid and dissociates:</p> <p><mathjax>#sf(CH_3COOHrightleftharpoonsCH_3COO^(-)+H^+)#</mathjax></p> <p>For which:</p> <p><mathjax>#sf(K_a=([CH_3COO^(-)][H^+])/([CH_3COOH]))#</mathjax></p> <p>These are equilibrium concentrations.</p> <p><mathjax>#sf(pK_a=4.76)#</mathjax> from which <mathjax>#sf(K_a=1.737xx10^(-5))#</mathjax></p> <p>Rearranging we get:</p> <p><mathjax>#sf([H^+]=K_axx([CH_3COOH])/([CH_3COO^-]))#</mathjax></p> <p><mathjax>#sf(pH=6.32)#</mathjax> from which <mathjax>#sf([H^+]=4.786xx10^(-7)color(white)(x)"mol/l")#</mathjax></p> <p><mathjax>#:.#</mathjax><mathjax>#sf(4.786xx10^(-7)=1.737xx10^(-5)xx([CH_3COOH])/([CH_3COO^(-)])#</mathjax></p> <p><mathjax>#:.#</mathjax><mathjax>#sf(([CH_3COOH])/([CH_3COO^(-)])=(4.786xx10^(-7))/(1.737xx10^(-5))=0.027553)#</mathjax></p> <p>To get the required pH we need to set the acid : salt ratio to this value.</p> <p>To produce the required ethanoate ions we add <mathjax>#sf(OH^-)#</mathjax> ions:</p> <p><mathjax>#sf(CH_3COOH+OH^(-)rarrCH_3COO^(-)+H_2O)#</mathjax></p> <p>You can see from the equation that the no. moles <mathjax>#sf(OH^-)#</mathjax> added = the no. of moles of <mathjax>#sf(CH_3COO^(-))#</mathjax> produced.</p> <p>Since we know <mathjax>#sf([OH^-])#</mathjax> we can say that if <mathjax>#sf(V)#</mathjax> is the volume of the <mathjax>#sf(OH^-)#</mathjax> solution then:</p> <p><mathjax>#sf(nOH^(-)=nCH_3COO_("eqm")^(-)=2.26xxV)#</mathjax></p> <p>Where <mathjax>#sf(n)#</mathjax> is the no. moles.</p> <p>We know the initial moles of ethanoic acid:</p> <p><mathjax>#sf(nCH_3COOH_("init")=0.800xx0.925=0.740)#</mathjax></p> <p>So we can get the moles after the alkali has been added. Because the dissociation is small we will assume that these are a good approximation to the equilibrium moles:</p> <p><mathjax>#sf(nCH_3COOH_("eqm")=(0.740-2.46V))#</mathjax></p> <p><mathjax>#:.#</mathjax><mathjax>#sf((nCH_3COOH_("eqm"))/(nCH_3COO_("eqm")^(-))=(0.740-2.46V)/(2.46V)=0.027553)#</mathjax></p> <p>We can use moles and not concentrations since the total volume is common to both so cancels anyway.</p> <p><mathjax>#:.#</mathjax><mathjax>#sf(0.740-2.46V=0.027553xx2.46V)#</mathjax></p> <p><mathjax>#sf(0.06778V+2.46V=0.740)#</mathjax></p> <p><mathjax>#sf(V=0.740/2.5277=0.293color(white)(x)L)#</mathjax></p> <p><mathjax>#sf(V=293color(white)(x)"ml")#</mathjax></p> <p><mathjax>#--------------------#</mathjax></p> <p>Check by iteration:</p> <p>Volume KOH = 297 ml</p> <p><mathjax>#sf(nOH^(-)=0.293xx2.46=0.72078)#</mathjax></p> <p><mathjax>#:.#</mathjax><mathjax>#sf(nCH_3COO_("eqm")^(-)=0.72078)#</mathjax></p> <p><mathjax>#sf(nCH_3COOH_("init")=0.740)#</mathjax></p> <p><mathjax>#:.#</mathjax><mathjax>#sf(nCH_3COOH_("eqm")=0.740-0.72078=0.01922)#</mathjax></p> <p><mathjax>#:.#</mathjax> <mathjax>#sf("ratio"" "( ["acid"] )/ (["salt"]) = 0.01922/0.72078 = 0.0266655)#</mathjax></p> <p><mathjax>#sf([H^+]=1.737xx10^(-5)xx0.0266655=0.046318xx10^(-5)color(white)(x)"mol/l")#</mathjax></p> <p><mathjax>#sf(pH=6.33)#</mathjax></p> <p>So not too bad.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">You need to prepare an acetate buffer of pH 6.32 from a 0.800 M acetic acid solution and a 2.46 M #KOH# solution. If you have 925 mL of the acetic acid solution, how many milliliters of the #KOH# do you need to add to make a bufer of pH 6.32? </h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>The pKa of acetic acid is 4.76. </p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/solution-formation---what-happens-when-stuff-dissolves" itemprop="url"> <span class="breadcrumb" itemprop="title">Solution Formation</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="463608" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/michael-2"><img alt="" class="" src="https://lh3.googleusercontent.com/-gCv6FQRhls0/AAAAAAAAAAI/AAAAAAAAAAA/AAnnY7oOJS05Ylqn3KuDSW0LfnbOk7FezQ/mo/photo.jpg?sz=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/michael-2"> Michael </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-13T17:32:51" itemprop="dateCreated"> Aug 13, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>293 ml</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Ethanoic acid is a weak acid and dissociates:</p> <p><mathjax>#sf(CH_3COOHrightleftharpoonsCH_3COO^(-)+H^+)#</mathjax></p> <p>For which:</p> <p><mathjax>#sf(K_a=([CH_3COO^(-)][H^+])/([CH_3COOH]))#</mathjax></p> <p>These are equilibrium concentrations.</p> <p><mathjax>#sf(pK_a=4.76)#</mathjax> from which <mathjax>#sf(K_a=1.737xx10^(-5))#</mathjax></p> <p>Rearranging we get:</p> <p><mathjax>#sf([H^+]=K_axx([CH_3COOH])/([CH_3COO^-]))#</mathjax></p> <p><mathjax>#sf(pH=6.32)#</mathjax> from which <mathjax>#sf([H^+]=4.786xx10^(-7)color(white)(x)"mol/l")#</mathjax></p> <p><mathjax>#:.#</mathjax><mathjax>#sf(4.786xx10^(-7)=1.737xx10^(-5)xx([CH_3COOH])/([CH_3COO^(-)])#</mathjax></p> <p><mathjax>#:.#</mathjax><mathjax>#sf(([CH_3COOH])/([CH_3COO^(-)])=(4.786xx10^(-7))/(1.737xx10^(-5))=0.027553)#</mathjax></p> <p>To get the required pH we need to set the acid : salt ratio to this value.</p> <p>To produce the required ethanoate ions we add <mathjax>#sf(OH^-)#</mathjax> ions:</p> <p><mathjax>#sf(CH_3COOH+OH^(-)rarrCH_3COO^(-)+H_2O)#</mathjax></p> <p>You can see from the equation that the no. moles <mathjax>#sf(OH^-)#</mathjax> added = the no. of moles of <mathjax>#sf(CH_3COO^(-))#</mathjax> produced.</p> <p>Since we know <mathjax>#sf([OH^-])#</mathjax> we can say that if <mathjax>#sf(V)#</mathjax> is the volume of the <mathjax>#sf(OH^-)#</mathjax> solution then:</p> <p><mathjax>#sf(nOH^(-)=nCH_3COO_("eqm")^(-)=2.26xxV)#</mathjax></p> <p>Where <mathjax>#sf(n)#</mathjax> is the no. moles.</p> <p>We know the initial moles of ethanoic acid:</p> <p><mathjax>#sf(nCH_3COOH_("init")=0.800xx0.925=0.740)#</mathjax></p> <p>So we can get the moles after the alkali has been added. Because the dissociation is small we will assume that these are a good approximation to the equilibrium moles:</p> <p><mathjax>#sf(nCH_3COOH_("eqm")=(0.740-2.46V))#</mathjax></p> <p><mathjax>#:.#</mathjax><mathjax>#sf((nCH_3COOH_("eqm"))/(nCH_3COO_("eqm")^(-))=(0.740-2.46V)/(2.46V)=0.027553)#</mathjax></p> <p>We can use moles and not concentrations since the total volume is common to both so cancels anyway.</p> <p><mathjax>#:.#</mathjax><mathjax>#sf(0.740-2.46V=0.027553xx2.46V)#</mathjax></p> <p><mathjax>#sf(0.06778V+2.46V=0.740)#</mathjax></p> <p><mathjax>#sf(V=0.740/2.5277=0.293color(white)(x)L)#</mathjax></p> <p><mathjax>#sf(V=293color(white)(x)"ml")#</mathjax></p> <p><mathjax>#--------------------#</mathjax></p> <p>Check by iteration:</p> <p>Volume KOH = 297 ml</p> <p><mathjax>#sf(nOH^(-)=0.293xx2.46=0.72078)#</mathjax></p> <p><mathjax>#:.#</mathjax><mathjax>#sf(nCH_3COO_("eqm")^(-)=0.72078)#</mathjax></p> <p><mathjax>#sf(nCH_3COOH_("init")=0.740)#</mathjax></p> <p><mathjax>#:.#</mathjax><mathjax>#sf(nCH_3COOH_("eqm")=0.740-0.72078=0.01922)#</mathjax></p> <p><mathjax>#:.#</mathjax> <mathjax>#sf("ratio"" "( ["acid"] )/ (["salt"]) = 0.01922/0.72078 = 0.0266655)#</mathjax></p> <p><mathjax>#sf([H^+]=1.737xx10^(-5)xx0.0266655=0.046318xx10^(-5)color(white)(x)"mol/l")#</mathjax></p> <p><mathjax>#sf(pH=6.33)#</mathjax></p> <p>So not too bad.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/463608" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-temperature-affect-the-formation-of-a-solution"> How can temperature affect the formation of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-formation-of-a-solution-be-exothermic-or-endothermic"> How can the formation of a solution be exothermic or endothermic? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-formation-of-a-solution-involve-energy"> How does the formation of a solution involve energy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-heat-formation-of-solution"> How do you find heat of formation of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-factor-promotes-the-formation-of-solutions"> Which factors promote the formation of solutions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/which-two-processes-are-at-equilibrium-in-a-saturated-sugar-solution"> Which two processes are at equilibrium in a saturated sugar solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-solutes-lower-the-freezing-point"> Why do solutes lower the freezing point? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-does-solution-formation-require-energy"> Why does solution formation require energy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-solutes-dissolve-in-solvents"> Why do solutes dissolve in solvents? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-solvent-dissolves-silicone"> What solvent dissolves silicone? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/solution-formation---what-happens-when-stuff-dissolves"> See all questions in Solution Formation </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 19812 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	You need to prepare an acetate buffer of pH 6.32 from a 0.800 M acetic acid solution and a 2.46 M #KOH# solution. If you have 925 mL of the acetic acid solution, how many milliliters of the #KOH# do you need to add to make a bufer of pH 6.32?	The pKa of acetic acid is 4.76.
2,194	acafd7a2-6ddd-11ea-8273-ccda262736ce	https://socratic.org/questions/58ebb1b2b72cff114acd1094	7300 calories	start physical_unit 10 10 heat_energy cal qc_end physical_unit 10 10 7 8 mass qc_end physical_unit 10 10 12 13 temperature qc_end physical_unit 15 15 17 18 temperature qc_end end	[{"type":"physical unit","value":"Required heat [OF] ice [IN] calories"}]	[{"type":"physical unit","value":"7300 calories"}]	[{"type":"physical unit","value":"Mass [OF] ice [=] \\pu{10 g}"},{"type":"physical unit","value":"Temperature1 [OF] ice [=] \\pu{-10 ℃}"},{"type":"physical unit","value":"Temperature2 [OF] steam [=] \\pu{100 ℃}"}]	<h1 class="questionTitle" itemprop="name">How much heat is required to convert #10g# of ice at #-10^@C# into steam at #100^@C#?</h1>	null	7300 calories	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>When <mathjax>#10g#</mathjax> of ice at <mathjax>#-20°C#</mathjax> s being converted into steam at <mathjax>#100°C#</mathjax>, there are four stages.</p> <ol> <li>Ice at <mathjax>#-20°C#</mathjax> to ice at <mathjax>#0°C#</mathjax> - here it continues to be in the same state i.e. ice and hence heat required is <mathjax>#"mass"xx"specific heat"xx"change in temperature"#</mathjax> Specific heat for ice is <mathjax>#0.5#</mathjax> cal/g-°C.</li> <li>Then from ice at <mathjax>#0°C#</mathjax> to water at <mathjax>#0°C#</mathjax> and heat required is <mathjax>#"mass"xx"latent heat"#</mathjax>, this latent heat required is for conversion of each unit mass of substance. From ice to water it is <mathjax>#80"cal per gram"#</mathjax></li> <li>Water at <mathjax>#0°C#</mathjax> to water at <mathjax>#100°C#</mathjax> - here it continues to be in the same state i.e. water and hence heat required is <mathjax>#"mass"xx"specific heat"xx"change in temperature"#</mathjax> Specific heat for water is <mathjax>#1#</mathjax> cal/g-°C.</li> <li>Then from water at <mathjax>#100°C#</mathjax> to steam at <mathjax>#100°C#</mathjax> and heat required is <mathjax>#"mass"xx"latent heat"#</mathjax>, this latent heat required is for conversion of each unit mass of substance. From water to steam, it is <mathjax>#540"cal per gram"#</mathjax></li> </ol> <p>Hence, to find heat is required to convert <mathjax>#10g#</mathjax> of ice at <mathjax>#-20°C#</mathjax> into steam at <mathjax>#100°C#</mathjax>,</p> <p>first calculate heat required to convert <mathjax>#10g#</mathjax> of ice at <mathjax>#-20°C#</mathjax> to ice at <mathjax>#0°C#</mathjax>. As <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> of ice is <mathjax>#0.5"cal/g°C"#</mathjax>, this is</p> <p><mathjax>#10xx20xx0.5=100#</mathjax> cal.</p> <p>heat required to convert <mathjax>#10g#</mathjax> of ice to <mathjax>#10g#</mathjax> of water at <mathjax>#0°C#</mathjax> is</p> <p><mathjax>#10xx80=800#</mathjax> cal - as latent heat is <mathjax>#80"cal/g"#</mathjax></p> <p>heat required to convert <mathjax>#10g#</mathjax> of water at <mathjax>#0°C#</mathjax> to <mathjax>#10g#</mathjax> of water at <mathjax>#100°C#</mathjax> is</p> <p><mathjax>#10xx100x1=1000#</mathjax> cal</p> <p>heat required to convert <mathjax>#10g#</mathjax> of water at <mathjax>#1000°C#</mathjax> to <mathjax>#10g#</mathjax> of steam at <mathjax>#100°C#</mathjax> is</p> <p><mathjax>#10xx540=5400#</mathjax> cal - as latent heat is <mathjax>#540"cal/g"#</mathjax></p> <p>Hence, total heat required is <mathjax>#100+800+1000+5400=7300#</mathjax> calories</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#7300#</mathjax> calories</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>When <mathjax>#10g#</mathjax> of ice at <mathjax>#-20°C#</mathjax> s being converted into steam at <mathjax>#100°C#</mathjax>, there are four stages.</p> <ol> <li>Ice at <mathjax>#-20°C#</mathjax> to ice at <mathjax>#0°C#</mathjax> - here it continues to be in the same state i.e. ice and hence heat required is <mathjax>#"mass"xx"specific heat"xx"change in temperature"#</mathjax> Specific heat for ice is <mathjax>#0.5#</mathjax> cal/g-°C.</li> <li>Then from ice at <mathjax>#0°C#</mathjax> to water at <mathjax>#0°C#</mathjax> and heat required is <mathjax>#"mass"xx"latent heat"#</mathjax>, this latent heat required is for conversion of each unit mass of substance. From ice to water it is <mathjax>#80"cal per gram"#</mathjax></li> <li>Water at <mathjax>#0°C#</mathjax> to water at <mathjax>#100°C#</mathjax> - here it continues to be in the same state i.e. water and hence heat required is <mathjax>#"mass"xx"specific heat"xx"change in temperature"#</mathjax> Specific heat for water is <mathjax>#1#</mathjax> cal/g-°C.</li> <li>Then from water at <mathjax>#100°C#</mathjax> to steam at <mathjax>#100°C#</mathjax> and heat required is <mathjax>#"mass"xx"latent heat"#</mathjax>, this latent heat required is for conversion of each unit mass of substance. From water to steam, it is <mathjax>#540"cal per gram"#</mathjax></li> </ol> <p>Hence, to find heat is required to convert <mathjax>#10g#</mathjax> of ice at <mathjax>#-20°C#</mathjax> into steam at <mathjax>#100°C#</mathjax>,</p> <p>first calculate heat required to convert <mathjax>#10g#</mathjax> of ice at <mathjax>#-20°C#</mathjax> to ice at <mathjax>#0°C#</mathjax>. As <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> of ice is <mathjax>#0.5"cal/g°C"#</mathjax>, this is</p> <p><mathjax>#10xx20xx0.5=100#</mathjax> cal.</p> <p>heat required to convert <mathjax>#10g#</mathjax> of ice to <mathjax>#10g#</mathjax> of water at <mathjax>#0°C#</mathjax> is</p> <p><mathjax>#10xx80=800#</mathjax> cal - as latent heat is <mathjax>#80"cal/g"#</mathjax></p> <p>heat required to convert <mathjax>#10g#</mathjax> of water at <mathjax>#0°C#</mathjax> to <mathjax>#10g#</mathjax> of water at <mathjax>#100°C#</mathjax> is</p> <p><mathjax>#10xx100x1=1000#</mathjax> cal</p> <p>heat required to convert <mathjax>#10g#</mathjax> of water at <mathjax>#1000°C#</mathjax> to <mathjax>#10g#</mathjax> of steam at <mathjax>#100°C#</mathjax> is</p> <p><mathjax>#10xx540=5400#</mathjax> cal - as latent heat is <mathjax>#540"cal/g"#</mathjax></p> <p>Hence, total heat required is <mathjax>#100+800+1000+5400=7300#</mathjax> calories</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How much heat is required to convert #10g# of ice at #-10^@C# into steam at #100^@C#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/calorimetry" itemprop="url"> <span class="breadcrumb" itemprop="title">Calorimetry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="404666" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/shwetank-m"><img alt="" class="" src="https://graph.facebook.com/1274310605917442/picture?height=50&width=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/shwetank-m"> Shwetank Mauria </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-10T16:47:25" itemprop="dateCreated"> Apr 10, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#7300#</mathjax> calories</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>When <mathjax>#10g#</mathjax> of ice at <mathjax>#-20°C#</mathjax> s being converted into steam at <mathjax>#100°C#</mathjax>, there are four stages.</p> <ol> <li>Ice at <mathjax>#-20°C#</mathjax> to ice at <mathjax>#0°C#</mathjax> - here it continues to be in the same state i.e. ice and hence heat required is <mathjax>#"mass"xx"specific heat"xx"change in temperature"#</mathjax> Specific heat for ice is <mathjax>#0.5#</mathjax> cal/g-°C.</li> <li>Then from ice at <mathjax>#0°C#</mathjax> to water at <mathjax>#0°C#</mathjax> and heat required is <mathjax>#"mass"xx"latent heat"#</mathjax>, this latent heat required is for conversion of each unit mass of substance. From ice to water it is <mathjax>#80"cal per gram"#</mathjax></li> <li>Water at <mathjax>#0°C#</mathjax> to water at <mathjax>#100°C#</mathjax> - here it continues to be in the same state i.e. water and hence heat required is <mathjax>#"mass"xx"specific heat"xx"change in temperature"#</mathjax> Specific heat for water is <mathjax>#1#</mathjax> cal/g-°C.</li> <li>Then from water at <mathjax>#100°C#</mathjax> to steam at <mathjax>#100°C#</mathjax> and heat required is <mathjax>#"mass"xx"latent heat"#</mathjax>, this latent heat required is for conversion of each unit mass of substance. From water to steam, it is <mathjax>#540"cal per gram"#</mathjax></li> </ol> <p>Hence, to find heat is required to convert <mathjax>#10g#</mathjax> of ice at <mathjax>#-20°C#</mathjax> into steam at <mathjax>#100°C#</mathjax>,</p> <p>first calculate heat required to convert <mathjax>#10g#</mathjax> of ice at <mathjax>#-20°C#</mathjax> to ice at <mathjax>#0°C#</mathjax>. As <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> of ice is <mathjax>#0.5"cal/g°C"#</mathjax>, this is</p> <p><mathjax>#10xx20xx0.5=100#</mathjax> cal.</p> <p>heat required to convert <mathjax>#10g#</mathjax> of ice to <mathjax>#10g#</mathjax> of water at <mathjax>#0°C#</mathjax> is</p> <p><mathjax>#10xx80=800#</mathjax> cal - as latent heat is <mathjax>#80"cal/g"#</mathjax></p> <p>heat required to convert <mathjax>#10g#</mathjax> of water at <mathjax>#0°C#</mathjax> to <mathjax>#10g#</mathjax> of water at <mathjax>#100°C#</mathjax> is</p> <p><mathjax>#10xx100x1=1000#</mathjax> cal</p> <p>heat required to convert <mathjax>#10g#</mathjax> of water at <mathjax>#1000°C#</mathjax> to <mathjax>#10g#</mathjax> of steam at <mathjax>#100°C#</mathjax> is</p> <p><mathjax>#10xx540=5400#</mathjax> cal - as latent heat is <mathjax>#540"cal/g"#</mathjax></p> <p>Hence, total heat required is <mathjax>#100+800+1000+5400=7300#</mathjax> calories</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/404666" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-differential-scanning-in-calorimetry-work"> How does differential scanning in calorimetry work? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-read-differential-scanning-in-calorimetry"> What information do you get from a differential scanning calorimetry plot? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-measure-calorimetry"> How do you measure calorimetry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531d304102bf341e75b962a7"> Question #962a7 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5335021802bf344ae911dfc5"> Question #1dfc5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/533668f502bf34572c341af6"> Question #41af6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-definition-of-calorimetry"> What is calorimetry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-differential-scanning-calorimeter"> What is a differential scanning calorimeter? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-a-calorimeter-measure-energy"> How can a calorimeter measure energy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-calorimeters-made-of"> What are calorimeters made of? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/calorimetry"> See all questions in Calorimetry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 38770 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How much heat is required to convert #10g# of ice at #-10^@C# into steam at #100^@C#?	null
2,195	ac907419-6ddd-11ea-a4ff-ccda262736ce	https://socratic.org/questions/what-is-the-hydronium-ion-concentration-of-a-solution-that-has-a-ph-of-8-57	2.69 × 10^(-9) M	start physical_unit 3 4 concentration mol/l qc_end physical_unit 8 8 14 14 ph qc_end end	[{"type":"physical unit","value":"Concentration [OF] hydronium ion [IN] M"}]	[{"type":"physical unit","value":"2.69 × 10^(-9) M"}]	[{"type":"physical unit","value":"pH [OF] the solution [=] \\pu{8.57}"}]	<h1 class="questionTitle" itemprop="name">What is the hydronium ion concentration of a solution that has a pH of 8.57?</h1>	null	2.69 × 10^(-9) M	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>By definition, <mathjax>#pH#</mathjax> <mathjax>#=#</mathjax> <mathjax>#-log_10[H_3O^+]#</mathjax></p> <p>And thus <mathjax>#[H_3O^+]#</mathjax> <mathjax>#=#</mathjax> <mathjax>#10^(-8.57)molL^-1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??molL^-1#</mathjax>.</p> <p>What is <mathjax>#[HO^-]#</mathjax> for this solution?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#[H_3O^+]<10^-7molL^-1#</mathjax>. The solution is assumed to be aqueous.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>By definition, <mathjax>#pH#</mathjax> <mathjax>#=#</mathjax> <mathjax>#-log_10[H_3O^+]#</mathjax></p> <p>And thus <mathjax>#[H_3O^+]#</mathjax> <mathjax>#=#</mathjax> <mathjax>#10^(-8.57)molL^-1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??molL^-1#</mathjax>.</p> <p>What is <mathjax>#[HO^-]#</mathjax> for this solution?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the hydronium ion concentration of a solution that has a pH of 8.57?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/ph-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">pH calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="281456" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-26T07:32:19" itemprop="dateCreated"> Jun 26, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#[H_3O^+]<10^-7molL^-1#</mathjax>. The solution is assumed to be aqueous.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>By definition, <mathjax>#pH#</mathjax> <mathjax>#=#</mathjax> <mathjax>#-log_10[H_3O^+]#</mathjax></p> <p>And thus <mathjax>#[H_3O^+]#</mathjax> <mathjax>#=#</mathjax> <mathjax>#10^(-8.57)molL^-1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??molL^-1#</mathjax>.</p> <p>What is <mathjax>#[HO^-]#</mathjax> for this solution?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/281456" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-of-a-solution"> How do you determine ph of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-at-an-equivalence-point"> How do you determine pH at an equivalence point? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-molarity"> How do you determine pH from molarity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-alkalinity-mean"> What does alkalinity mean? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-base"> What is a base? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-acid-base-indicators-change-color"> How do acid base indicators change color? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-neutral-ph"> What is a neutral pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-alkalinity-affect-pool-water"> How does alkalinity affect pool water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ph-important-in-drinking-water"> Why is pH important in drinking water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-ph-of-solution"> How can I calculate the pH of a solution? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/ph-calculations"> See all questions in pH calculations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3213 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the hydronium ion concentration of a solution that has a pH of 8.57?	null
2,196	acaa0bd5-6ddd-11ea-906a-ccda262736ce	https://socratic.org/questions/what-is-the-ph-of-a-20-m-nh-4no-3-solution	4.97	start physical_unit 8 9 ph none qc_end physical_unit 8 9 6 7 molarity qc_end end	[{"type":"physical unit","value":"pH [OF] NH4NO3 solution"}]	[{"type":"physical unit","value":"4.97"}]	[{"type":"physical unit","value":"Molarity [OF] NH4NO3 solution [=] \\pu{0.20 M}"}]	<h1 class="questionTitle" itemprop="name">What is the pH of a .20 M #NH_4NO_3# solution?</h1>	null	4.97	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Ammonium nitrate is the salt of a weak base and a strong acid so we would expect it to be slightly acidic due to salt hydrolysis:</p> <p><mathjax>#sf(NH_4^+rightleftharpoonsNH_3+H^+)#</mathjax></p> <p>The position of equilibrium lies well to the left such that <mathjax>#sf(pK_a=9.24)#</mathjax>.</p> <p>From an ICE table we get this expression which can be used to find the pH of a weak acid:</p> <p><mathjax>#sf(pH=1/2(pK_a-log[acid])#</mathjax></p> <p><mathjax>#:.#</mathjax><mathjax>#sf(pH=1/2(9.24-log(0.2))#</mathjax></p> <p><mathjax>#sf(pH=1/2(9.24-(-0.699))#</mathjax></p> <p><mathjax>#sf(pH=4.97)#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> = 4.97</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Ammonium nitrate is the salt of a weak base and a strong acid so we would expect it to be slightly acidic due to salt hydrolysis:</p> <p><mathjax>#sf(NH_4^+rightleftharpoonsNH_3+H^+)#</mathjax></p> <p>The position of equilibrium lies well to the left such that <mathjax>#sf(pK_a=9.24)#</mathjax>.</p> <p>From an ICE table we get this expression which can be used to find the pH of a weak acid:</p> <p><mathjax>#sf(pH=1/2(pK_a-log[acid])#</mathjax></p> <p><mathjax>#:.#</mathjax><mathjax>#sf(pH=1/2(9.24-log(0.2))#</mathjax></p> <p><mathjax>#sf(pH=1/2(9.24-(-0.699))#</mathjax></p> <p><mathjax>#sf(pH=4.97)#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the pH of a .20 M #NH_4NO_3# solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/the-ph-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">pH</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="462885" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/michael-2"><img alt="" class="" src="https://lh3.googleusercontent.com/-gCv6FQRhls0/AAAAAAAAAAI/AAAAAAAAAAA/AAnnY7oOJS05Ylqn3KuDSW0LfnbOk7FezQ/mo/photo.jpg?sz=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/michael-2"> Michael </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-11T18:13:33" itemprop="dateCreated"> Aug 11, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> = 4.97</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Ammonium nitrate is the salt of a weak base and a strong acid so we would expect it to be slightly acidic due to salt hydrolysis:</p> <p><mathjax>#sf(NH_4^+rightleftharpoonsNH_3+H^+)#</mathjax></p> <p>The position of equilibrium lies well to the left such that <mathjax>#sf(pK_a=9.24)#</mathjax>.</p> <p>From an ICE table we get this expression which can be used to find the pH of a weak acid:</p> <p><mathjax>#sf(pH=1/2(pK_a-log[acid])#</mathjax></p> <p><mathjax>#:.#</mathjax><mathjax>#sf(pH=1/2(9.24-log(0.2))#</mathjax></p> <p><mathjax>#sf(pH=1/2(9.24-(-0.699))#</mathjax></p> <p><mathjax>#sf(pH=4.97)#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/462885" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-pka"> How do you determine pH from pKa? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-ph-values-of-acids-and-bases-differ"> How do pH values of acids and bases differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-something-on-a-ph-scale"> How do you calculate something on a pH scale? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-diprotic-acid"> How do you calculate pH diprotic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-from-acid-dissociation-constant"> How do you calculate pH from acid dissociation constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-of-acid-and-base-solution"> How do you calculate pH of acid and base solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ph-scale-0-14"> Why is the pH scale 0-14? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-ph-the-measure-of-the-hydrogen-ion-concentration"> Is pH a measure of the hydrogen ion concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-solubility-affect-ph"> How does solubility affect pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-ph-relate-to-pka-in-a-titration"> How does pH relate to pKa in a titration? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/the-ph-concept"> See all questions in pH </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 7574 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the pH of a .20 M #NH_4NO_3# solution?	null
2,197	a9924aac-6ddd-11ea-80f7-ccda262736ce	https://socratic.org/questions/what-volume-of-o-2-measured-82-1-c-and-713-mm-hg-will-be-produced-by-the-decompo	2.18 L	start physical_unit 3 3 volume l qc_end physical_unit 3 3 5 6 temperature qc_end physical_unit 3 3 8 9 pressure qc_end physical_unit 20 20 17 18 mass qc_end end	[{"type":"physical unit","value":"Volume [OF] O2 [IN] L"}]	[{"type":"physical unit","value":"2.18 L"}]	[{"type":"physical unit","value":"Temperature [OF] O2 [=] \\pu{82.1 ℃}"},{"type":"physical unit","value":"Pressure [OF] O2 [=] \\pu{713 mmHg}"},{"type":"physical unit","value":"Mass [OF] KClO3 [=] \\pu{5.71 g}"}]	<h1 class="questionTitle" itemprop="name">What volume of #O_2#, measured 82.1°C and 713 mm Hg, will be produced by the decomposition of 5.71 g of #KClO_3#?</h1>	null	2.18 L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>Step 1. Write the balanced chemical equation.</strong></p> <p>The balanced equation is</p> <p><mathjax>#"2KClO"_3 → "2KCl" + "3O"_2#</mathjax></p> <blockquote></blockquote> <p><strong>Step 2. The Procedure</strong></p> <p>The problem is to convert grams of <mathjax>#"KClO"_3#</mathjax> to moles of <mathjax>#"O"_2#</mathjax> and volume of <mathjax>#"O"_2#</mathjax>.</p> <p>The procedure is:</p> <p><strong>(a)</strong> Use the <strong>molar mass</strong> to convert the mass of <mathjax>#"KClO"_3#</mathjax> to moles of <mathjax>#"KClO"_3#</mathjax>.</p> <p><strong>(b)</strong> Use the <strong>molar ratio</strong> (from the balanced equation) to convert moles of <mathjax>#"KClO"_3#</mathjax> to moles of <mathjax>#"O"_2#</mathjax>.</p> <p><strong>(e)</strong> Use the <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a></strong> to convert moles of <mathjax>#"O"_2#</mathjax> to volume of <mathjax>#"O"_2#</mathjax>.</p> <blockquote></blockquote> <p>In equation form,</p> <p><mathjax>#"grams of KClO"_3 stackrelcolor(blue)("molar mass"color(white)(ml)) (→) "moles of KClO"_3 stackrelcolor(blue)("molar ratio"color(white)(ml))→ "moles of O"_2 stackrelcolor(blue)("Ideal Gas Law"color(white)(ml))(→) "volume of O"_2#</mathjax></p> <blockquote></blockquote> <p><strong>The Calculations</strong></p> <p><strong>(a) Moles of <mathjax>#"KClO"_3#</mathjax></strong></p> <p><mathjax>#5.71 color(red)(cancel(color(black)("g KClO"_3))) × ("1 mol KClO"_3)/(122.55 color(red)(cancel(color(black)("g KClO"_3)))) = "0.046 59 mol KClO"_3 #</mathjax></p> <blockquote></blockquote> <p><strong>(b) Moles of <mathjax>#"O"_2#</mathjax></strong></p> <p><mathjax>#"0.046 59"color(red)(cancel(color(black)("mol KClO"_3))) × ("3 mol O"_2)/(2 color(red)(cancel(color(black)("mol KClO"_3)))) = "0.069 89 mol O"_2#</mathjax></p> <blockquote></blockquote> <p><strong>(c) Volume of <mathjax>#"O"_2#</mathjax></strong></p> <p>The <strong>Ideal Gas Law</strong> is</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(\|color(white)(a/a)PV = nRTcolor(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>We can rearrange this to give</p> <blockquote> <blockquote> <blockquote> <p><mathjax>#V = (nRT)/P#</mathjax></p> </blockquote> </blockquote> </blockquote> <p><mathjax>#n = "0.069 89 mol O"_2#</mathjax><br/> <mathjax>#R = "0.082 06 L·atm·K"^"-1""mol"^"-1"#</mathjax><br/> <mathjax>#T = "(82.1 + 273.15) K" = "355.25 K"#</mathjax><br/> <mathjax>#P = 711 color(red)(cancel(color(black)("mmHg"))) × "1 atm"/(760 color(red)(cancel(color(black)("mmHg")))) = "0.9355 atm"#</mathjax></p> <p>∴ <mathjax>#V = ("0.069 89" color(red)(cancel(color(black)("mol"))) × "0.082 06 L"·color(red)(cancel(color(black)("atm·K"^"-1""mol"^"-1"))) × 355.25color(red)(cancel(color(black)( "K"))))/(0.9355 color(red)(cancel(color(black)("atm")))) = "2.18 L"#</mathjax></p> <p>The volume of <mathjax>#"O"_2#</mathjax> produced is <mathjax>#"2.18 L"#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The reaction produces <mathjax>#"2.18 L of O"_2#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>Step 1. Write the balanced chemical equation.</strong></p> <p>The balanced equation is</p> <p><mathjax>#"2KClO"_3 → "2KCl" + "3O"_2#</mathjax></p> <blockquote></blockquote> <p><strong>Step 2. The Procedure</strong></p> <p>The problem is to convert grams of <mathjax>#"KClO"_3#</mathjax> to moles of <mathjax>#"O"_2#</mathjax> and volume of <mathjax>#"O"_2#</mathjax>.</p> <p>The procedure is:</p> <p><strong>(a)</strong> Use the <strong>molar mass</strong> to convert the mass of <mathjax>#"KClO"_3#</mathjax> to moles of <mathjax>#"KClO"_3#</mathjax>.</p> <p><strong>(b)</strong> Use the <strong>molar ratio</strong> (from the balanced equation) to convert moles of <mathjax>#"KClO"_3#</mathjax> to moles of <mathjax>#"O"_2#</mathjax>.</p> <p><strong>(e)</strong> Use the <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a></strong> to convert moles of <mathjax>#"O"_2#</mathjax> to volume of <mathjax>#"O"_2#</mathjax>.</p> <blockquote></blockquote> <p>In equation form,</p> <p><mathjax>#"grams of KClO"_3 stackrelcolor(blue)("molar mass"color(white)(ml)) (→) "moles of KClO"_3 stackrelcolor(blue)("molar ratio"color(white)(ml))→ "moles of O"_2 stackrelcolor(blue)("Ideal Gas Law"color(white)(ml))(→) "volume of O"_2#</mathjax></p> <blockquote></blockquote> <p><strong>The Calculations</strong></p> <p><strong>(a) Moles of <mathjax>#"KClO"_3#</mathjax></strong></p> <p><mathjax>#5.71 color(red)(cancel(color(black)("g KClO"_3))) × ("1 mol KClO"_3)/(122.55 color(red)(cancel(color(black)("g KClO"_3)))) = "0.046 59 mol KClO"_3 #</mathjax></p> <blockquote></blockquote> <p><strong>(b) Moles of <mathjax>#"O"_2#</mathjax></strong></p> <p><mathjax>#"0.046 59"color(red)(cancel(color(black)("mol KClO"_3))) × ("3 mol O"_2)/(2 color(red)(cancel(color(black)("mol KClO"_3)))) = "0.069 89 mol O"_2#</mathjax></p> <blockquote></blockquote> <p><strong>(c) Volume of <mathjax>#"O"_2#</mathjax></strong></p> <p>The <strong>Ideal Gas Law</strong> is</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(\|color(white)(a/a)PV = nRTcolor(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>We can rearrange this to give</p> <blockquote> <blockquote> <blockquote> <p><mathjax>#V = (nRT)/P#</mathjax></p> </blockquote> </blockquote> </blockquote> <p><mathjax>#n = "0.069 89 mol O"_2#</mathjax><br/> <mathjax>#R = "0.082 06 L·atm·K"^"-1""mol"^"-1"#</mathjax><br/> <mathjax>#T = "(82.1 + 273.15) K" = "355.25 K"#</mathjax><br/> <mathjax>#P = 711 color(red)(cancel(color(black)("mmHg"))) × "1 atm"/(760 color(red)(cancel(color(black)("mmHg")))) = "0.9355 atm"#</mathjax></p> <p>∴ <mathjax>#V = ("0.069 89" color(red)(cancel(color(black)("mol"))) × "0.082 06 L"·color(red)(cancel(color(black)("atm·K"^"-1""mol"^"-1"))) × 355.25color(red)(cancel(color(black)( "K"))))/(0.9355 color(red)(cancel(color(black)("atm")))) = "2.18 L"#</mathjax></p> <p>The volume of <mathjax>#"O"_2#</mathjax> produced is <mathjax>#"2.18 L"#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What volume of #O_2#, measured 82.1°C and 713 mm Hg, will be produced by the decomposition of 5.71 g of #KClO_3#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/decomposition-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Decomposition Reactions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="336391" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-11-15T01:28:27" itemprop="dateCreated"> Nov 15, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The reaction produces <mathjax>#"2.18 L of O"_2#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>Step 1. Write the balanced chemical equation.</strong></p> <p>The balanced equation is</p> <p><mathjax>#"2KClO"_3 → "2KCl" + "3O"_2#</mathjax></p> <blockquote></blockquote> <p><strong>Step 2. The Procedure</strong></p> <p>The problem is to convert grams of <mathjax>#"KClO"_3#</mathjax> to moles of <mathjax>#"O"_2#</mathjax> and volume of <mathjax>#"O"_2#</mathjax>.</p> <p>The procedure is:</p> <p><strong>(a)</strong> Use the <strong>molar mass</strong> to convert the mass of <mathjax>#"KClO"_3#</mathjax> to moles of <mathjax>#"KClO"_3#</mathjax>.</p> <p><strong>(b)</strong> Use the <strong>molar ratio</strong> (from the balanced equation) to convert moles of <mathjax>#"KClO"_3#</mathjax> to moles of <mathjax>#"O"_2#</mathjax>.</p> <p><strong>(e)</strong> Use the <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a></strong> to convert moles of <mathjax>#"O"_2#</mathjax> to volume of <mathjax>#"O"_2#</mathjax>.</p> <blockquote></blockquote> <p>In equation form,</p> <p><mathjax>#"grams of KClO"_3 stackrelcolor(blue)("molar mass"color(white)(ml)) (→) "moles of KClO"_3 stackrelcolor(blue)("molar ratio"color(white)(ml))→ "moles of O"_2 stackrelcolor(blue)("Ideal Gas Law"color(white)(ml))(→) "volume of O"_2#</mathjax></p> <blockquote></blockquote> <p><strong>The Calculations</strong></p> <p><strong>(a) Moles of <mathjax>#"KClO"_3#</mathjax></strong></p> <p><mathjax>#5.71 color(red)(cancel(color(black)("g KClO"_3))) × ("1 mol KClO"_3)/(122.55 color(red)(cancel(color(black)("g KClO"_3)))) = "0.046 59 mol KClO"_3 #</mathjax></p> <blockquote></blockquote> <p><strong>(b) Moles of <mathjax>#"O"_2#</mathjax></strong></p> <p><mathjax>#"0.046 59"color(red)(cancel(color(black)("mol KClO"_3))) × ("3 mol O"_2)/(2 color(red)(cancel(color(black)("mol KClO"_3)))) = "0.069 89 mol O"_2#</mathjax></p> <blockquote></blockquote> <p><strong>(c) Volume of <mathjax>#"O"_2#</mathjax></strong></p> <p>The <strong>Ideal Gas Law</strong> is</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(\|color(white)(a/a)PV = nRTcolor(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>We can rearrange this to give</p> <blockquote> <blockquote> <blockquote> <p><mathjax>#V = (nRT)/P#</mathjax></p> </blockquote> </blockquote> </blockquote> <p><mathjax>#n = "0.069 89 mol O"_2#</mathjax><br/> <mathjax>#R = "0.082 06 L·atm·K"^"-1""mol"^"-1"#</mathjax><br/> <mathjax>#T = "(82.1 + 273.15) K" = "355.25 K"#</mathjax><br/> <mathjax>#P = 711 color(red)(cancel(color(black)("mmHg"))) × "1 atm"/(760 color(red)(cancel(color(black)("mmHg")))) = "0.9355 atm"#</mathjax></p> <p>∴ <mathjax>#V = ("0.069 89" color(red)(cancel(color(black)("mol"))) × "0.082 06 L"·color(red)(cancel(color(black)("atm·K"^"-1""mol"^"-1"))) × 355.25color(red)(cancel(color(black)( "K"))))/(0.9355 color(red)(cancel(color(black)("atm")))) = "2.18 L"#</mathjax></p> <p>The volume of <mathjax>#"O"_2#</mathjax> produced is <mathjax>#"2.18 L"#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/336391" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-decomposition-reactions"> What are decomposition reactions? 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2,198	a8c003d4-6ddd-11ea-a03b-ccda262736ce	https://socratic.org/questions/how-do-you-determine-the-specific-heat-of-a-material-if-a-35-g-sample-absorbed-9	0.14 J/(g * ℃)	start physical_unit 9 9 specific_heat j/(°c_·_g) qc_end physical_unit 9 9 12 13 mass qc_end physical_unit 9 9 16 17 heat_energy qc_end physical_unit 9 9 23 24 heat_energy qc_end physical_unit 9 9 26 27 heat_energy qc_end end	[{"type":"physical unit","value":"Specific heat [OF] the material sample [IN] J/(g * ℃)"}]	[{"type":"physical unit","value":"0.14 J/(g * ℃)"}]	[{"type":"physical unit","value":"Mass [OF] the material sample [=] \\pu{35 g}"},{"type":"physical unit","value":"Absorbed energy [OF] the material sample [=] \\pu{96 J}"},{"type":"physical unit","value":"Heat1 [OF] the material sample [=] \\pu{293 K}"},{"type":"physical unit","value":"Heat2 [OF] the material sample [=] \\pu{313 K}"}]	<h1 class="questionTitle" itemprop="name">How do you determine the specific heat of a material if a 35 g sample absorbed 96 J as it was heated from 293 to 313 K?</h1>	null	0.14 J/(g * ℃)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/thermochemistry/specific-heat">Specific heat</a> capacity of a substance is the amount of heat required to raise one gram of the substance by one degree Celsius. This means the first thing you need to do is convert your temperatures to Celsius.</p> <p><mathjax>#""^@C = K - 273.15#</mathjax></p> <p><mathjax>#T_1 = 293 - 273.15 = 19.85 ^@ C#</mathjax></p> <p><mathjax>#T_2 = 313 - 273.15 = 39.85 ^@ C#</mathjax></p> <p><mathjax>#Delta T = T_2 - T_1 = 20.00 ^@ C#</mathjax></p> <p><mathjax>#"specific heat" = q/(m xx Delta T)#</mathjax>, </p> <p>where <mathjax>#q = "heat in Joules", " "m = "mass in grams"#</mathjax></p> <p><mathjax>#"specific heat" = 96/(35 xx 20.00) = 0.137 J/(g^oC)#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"specific heat" = 0.137 J/(g^oC)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/thermochemistry/specific-heat">Specific heat</a> capacity of a substance is the amount of heat required to raise one gram of the substance by one degree Celsius. This means the first thing you need to do is convert your temperatures to Celsius.</p> <p><mathjax>#""^@C = K - 273.15#</mathjax></p> <p><mathjax>#T_1 = 293 - 273.15 = 19.85 ^@ C#</mathjax></p> <p><mathjax>#T_2 = 313 - 273.15 = 39.85 ^@ C#</mathjax></p> <p><mathjax>#Delta T = T_2 - T_1 = 20.00 ^@ C#</mathjax></p> <p><mathjax>#"specific heat" = q/(m xx Delta T)#</mathjax>, </p> <p>where <mathjax>#q = "heat in Joules", " "m = "mass in grams"#</mathjax></p> <p><mathjax>#"specific heat" = 96/(35 xx 20.00) = 0.137 J/(g^oC)#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you determine the specific heat of a material if a 35 g sample absorbed 96 J as it was heated from 293 to 313 K?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/specific-heat" itemprop="url"> <span class="breadcrumb" itemprop="title">Specific Heat</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="445157" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/marfre"><img alt="" class="" src="https://profilepictures.socratic.org/48J0XLK1To2NunsG33ct_11.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/marfre"> marfre </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-28T00:06:16" itemprop="dateCreated"> Jun 28, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"specific heat" = 0.137 J/(g^oC)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/thermochemistry/specific-heat">Specific heat</a> capacity of a substance is the amount of heat required to raise one gram of the substance by one degree Celsius. This means the first thing you need to do is convert your temperatures to Celsius.</p> <p><mathjax>#""^@C = K - 273.15#</mathjax></p> <p><mathjax>#T_1 = 293 - 273.15 = 19.85 ^@ C#</mathjax></p> <p><mathjax>#T_2 = 313 - 273.15 = 39.85 ^@ C#</mathjax></p> <p><mathjax>#Delta T = T_2 - T_1 = 20.00 ^@ C#</mathjax></p> <p><mathjax>#"specific heat" = q/(m xx Delta T)#</mathjax>, </p> <p>where <mathjax>#q = "heat in Joules", " "m = "mass in grams"#</mathjax></p> <p><mathjax>#"specific heat" = 96/(35 xx 20.00) = 0.137 J/(g^oC)#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/445157" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-specific-heat-be-used-to-identify-substances"> How can specific heat be used to identify substances? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-heat-capacity-of-a-lead-sinker-be-determined"> How can the heat capacity of a lead sinker be determined? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-the-specific-heats-of-metals-compare-with-water"> How do the specific heats of metals compare with water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-specific-heat-change-with-temperature"> How does specific heat change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/dissolving-some-potassium-bromide-in-200cm3-of-water-leads-to-a-decrease-in-temp"> Dissolving some potassium bromide in 200cm3 of water leads to a decrease in temperature of 3oC.... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-heat-capacity-larger-for-polymers"> Is heat capacity larger for polymers? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-heat-capacity-an-extensive-property"> Why is heat capacity an extensive property? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-does-heat-capacity-change-with-temperature"> Why does heat capacity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-specific-heat-measured-in"> What is specific heat measured in? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-heat-capacity-measured-in"> What is heat capacity measured in? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/specific-heat"> See all questions in Specific Heat </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 20485 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How do you determine the specific heat of a material if a 35 g sample absorbed 96 J as it was heated from 293 to 313 K?	null
2,199	acdaac28-6ddd-11ea-bb41-ccda262736ce	https://socratic.org/questions/what-is-the-mass-of-4-76-10-21-platinum-atoms	1.54 g	start physical_unit 8 9 mass g qc_end physical_unit 8 9 5 7 number qc_end end	[{"type":"physical unit","value":"Mass [OF] platinum atoms [IN] g"}]	[{"type":"physical unit","value":"1.54 g"}]	[{"type":"physical unit","value":"Number [OF] platinum atoms [=] \\pu{4.76 × 10^21}"}]	<h1 class="questionTitle" itemprop="name">What is the mass of #4.76*10^21# platinum atoms?</h1>	null	1.54 g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So we simply take the quotient, and multiply this number by the mass of Avogadro's number of platinum atoms.</p> <p>And thus,<br/> <mathjax>#(4.76xx10^(21))/(6.0221xx10^(23))xx195.08*g=??g#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well <mathjax>#6.0221xx10^(23)#</mathjax> platinum atoms have a mass of <mathjax>#195.08g#</mathjax>, so you tell us.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So we simply take the quotient, and multiply this number by the mass of Avogadro's number of platinum atoms.</p> <p>And thus,<br/> <mathjax>#(4.76xx10^(21))/(6.0221xx10^(23))xx195.08g=??g#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the mass of #4.7610^21# platinum atoms?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="291236" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-23T17:27:21" itemprop="dateCreated"> Jul 23, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well <mathjax>#6.0221xx10^(23)#</mathjax> platinum atoms have a mass of <mathjax>#195.08g#</mathjax>, so you tell us.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So we simply take the quotient, and multiply this number by the mass of Avogadro's number of platinum atoms.</p> <p>And thus,<br/> <mathjax>#(4.76xx10^(21))/(6.0221xx10^(23))xx195.08*g=??g#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/291236" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? 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