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2,400	a8a6fa2e-6ddd-11ea-9857-ccda262736ce	https://socratic.org/questions/given-the-equation-2-ki-pb-no3-2-pbi2-2-kno3-how-would-you-calculate-themass-of-	41.66 g	start physical_unit 8 8 mass g qc_end chemical_equation 3 11 qc_end physical_unit 4 4 24 25 mass qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Mass [OF] PbI2 [IN] g"}]	[{"type":"physical unit","value":"41.66 g"}]	[{"type":"chemical equation","value":"2 KI + Pb(NO3)2 -> PbI2 + 2 KNO3"},{"type":"physical unit","value":"Mass [OF] KI [=] \\pu{30.0 g}"},{"type":"other","value":"Excess Pb(NO3)2."}]	<h1 class="questionTitle" itemprop="name">Given the equation: 2 KI + Pb(NO3)2 --> PbI2 + 2 KNO3, how would you calculate themass of PbI2 produced by reacting of 30.0 g KI with excess Pb(No3)2?</h1>	null	41.66 g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You have done the hard yakka in quoting the balanced chemical equation. Here, the potassium iodide is clearly the <a href="http://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a>. By the <a href="http://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> of the reaction, there will be half an equiv of lead iodide per equiv of potassium iodide.</p> <p>Moles of <mathjax>#KI#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(30.0g)/(166.0gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax></p> <p>So resultant mass of <mathjax>#PbI_2#</mathjax>:</p> <p><mathjax>#{(30.0gxx461.01gmol^-1)xx1/2}/(166.0gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax> <mathjax>#g#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2KI(aq) + Pb(NO_3)_2(aq) rarr PbI_2(s)darr + 2KNO_3(aq)#</mathjax>.</p> <p>Moles of <mathjax># mol#</mathjax> <mathjax>#KI -=#</mathjax><mathjax>#1/2mol#</mathjax> <mathjax>#PbI_2(s)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You have done the hard yakka in quoting the balanced chemical equation. Here, the potassium iodide is clearly the <a href="http://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a>. By the <a href="http://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> of the reaction, there will be half an equiv of lead iodide per equiv of potassium iodide.</p> <p>Moles of <mathjax>#KI#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(30.0g)/(166.0gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax></p> <p>So resultant mass of <mathjax>#PbI_2#</mathjax>:</p> <p><mathjax>#{(30.0gxx461.01gmol^-1)xx1/2}/(166.0g*mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax> <mathjax>#g#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Given the equation: 2 KI + Pb(NO3)2 --> PbI2 + 2 KNO3, how would you calculate themass of PbI2 produced by reacting of 30.0 g KI with excess Pb(No3)2?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="188373" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-14T14:12:48" itemprop="dateCreated"> Nov 14, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2KI(aq) + Pb(NO_3)_2(aq) rarr PbI_2(s)darr + 2KNO_3(aq)#</mathjax>.</p> <p>Moles of <mathjax># mol#</mathjax> <mathjax>#KI -=#</mathjax><mathjax>#1/2mol#</mathjax> <mathjax>#PbI_2(s)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You have done the hard yakka in quoting the balanced chemical equation. Here, the potassium iodide is clearly the <a href="http://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a>. By the <a href="http://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> of the reaction, there will be half an equiv of lead iodide per equiv of potassium iodide.</p> <p>Moles of <mathjax>#KI#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(30.0g)/(166.0gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax></p> <p>So resultant mass of <mathjax>#PbI_2#</mathjax>:</p> <p><mathjax>#{(30.0gxx461.01gmol^-1)xx1/2}/(166.0g*mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax> <mathjax>#g#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/188373" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What is stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ab82402bf342f48d93ac6"> Question #93ac6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-we-study-stoichiometry"> Why do we study stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-naoh-is-produced-from-1-20-x-102-grams-of-na2o-na2o-h2o-2-naoh"> How many grams of NaOH is produced from #1.20 x 10^2# grams of #Na_2O#? #Na_2O + H_2O -> 2NaOH# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-na2o-are-required-to-produce-1-60-x-102-grams-of-naoh-na2o-h2o"> How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? Na2O + H2O ---> 2 NaOH </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-mass-of-iron-is-needed-to-react-with-16-0-grams-of-sulfur-8-fe-s8-8-fes"> What mass of iron is needed to react with 16.0 grams of sulfur? 8 Fe + S8 ---> 8 FeS </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/according-to-8-fe-s8-8-fes-how-many-grams-of-fes-are-produced"> According to 8 Fe + S8 ---> 8 FeS How many grams of FeS are produced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/12-00-moles-of-naclo3-will-produce-how-many-grams-of-o2-2-naclo3-2-nacl-3-o2"> 12.00 moles of NaClO3 will produce how many grams of O2? 2 NaClO3 ---> 2 NaCl + 3 O2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-nacl-are-produced-when-80-0-grams-of-o2-are-produced-2-naclo3-"> How many grams of NaCl are produced when 80.0 grams of O2 are produced? 2 NaClO3 ---> 2 NaCl + 3 O2 </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/stoichiometry"> See all questions in Stoichiometry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 73802 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Given the equation: 2 KI + Pb(NO3)2 --> PbI2 + 2 KNO3, how would you calculate themass of PbI2 produced by reacting of 30.0 g KI with excess Pb(No3)2?	null
2,401	a8acaa5b-6ddd-11ea-86fe-ccda262736ce	https://socratic.org/questions/what-is-the-molarity-of-2-moles-of-glucose-in-4-00-l-of-a-glucose-solution	0.50 mol/L	start physical_unit 8 8 molarity mol/l qc_end physical_unit 8 8 5 6 mole qc_end physical_unit 13 15 10 11 volume qc_end end	[{"type":"physical unit","value":"Molarity [OF] glucose [IN] mol/L"}]	[{"type":"physical unit","value":"0.50 mol/L"}]	[{"type":"physical unit","value":"Mole [OF] glucose [=] \\pu{2 moles}"},{"type":"physical unit","value":"Volume [OF] a glucose solution [=] \\pu{4.00 L}"}]	<h1 class="questionTitle" itemprop="name">What is the molarity of 2 moles of glucose in 4.00 L of a glucose solution?</h1>	null	0.50 mol/L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Concentration"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Amount of substance in moles"/"Amount of solution in litres"#</mathjax>.</p> <p>Given the definition, <mathjax>#"concentration"#</mathjax> necessarily has units of <mathjax>#molL^-1#</mathjax>.</p> <p>So for your problem, we just have to set up the quotient,</p> <p><mathjax>#(2mol)/(4.00L)#</mathjax> <mathjax>#=??molL^-1#</mathjax>. When we set up the problem this way, it automatically gives us the correct units, <mathjax>#mol*L^-1#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Clearly, it is <mathjax>#0.50molL^-1#</mathjax> with respect to glucose.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Concentration"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Amount of substance in moles"/"Amount of solution in litres"#</mathjax>.</p> <p>Given the definition, <mathjax>#"concentration"#</mathjax> necessarily has units of <mathjax>#molL^-1#</mathjax>.</p> <p>So for your problem, we just have to set up the quotient,</p> <p><mathjax>#(2mol)/(4.00L)#</mathjax> <mathjax>#=??molL^-1#</mathjax>. When we set up the problem this way, it automatically gives us the correct units, <mathjax>#mol*L^-1#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the molarity of 2 moles of glucose in 4.00 L of a glucose solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="261288" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-02T12:37:57" itemprop="dateCreated"> May 2, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Clearly, it is <mathjax>#0.50molL^-1#</mathjax> with respect to glucose.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Concentration"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Amount of substance in moles"/"Amount of solution in litres"#</mathjax>.</p> <p>Given the definition, <mathjax>#"concentration"#</mathjax> necessarily has units of <mathjax>#molL^-1#</mathjax>.</p> <p>So for your problem, we just have to set up the quotient,</p> <p><mathjax>#(2mol)/(4.00L)#</mathjax> <mathjax>#=??molL^-1#</mathjax>. When we set up the problem this way, it automatically gives us the correct units, <mathjax>#mol*L^-1#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/261288" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-morality-be-used-as-a-conversion-factor"> How can molarity be used as a conversion factor? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-high-can-molarity-be"> How high can molarity be? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-molarity-change-with-temperature"> How does molarity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molarity-of-a-solution"> How do you find molarity of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-10-naoh"> What is the molarity of 10 NaOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-3-hydrogen-peroxide"> What is the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 13922 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the molarity of 2 moles of glucose in 4.00 L of a glucose solution?	null
2,402	abc98a11-6ddd-11ea-929b-ccda262736ce	https://socratic.org/questions/consider-the-following-reaction-p4-s-10-cl2-g-4-pcl5-g-ho-1776-kj	444.00 kJ/mol	start physical_unit 10 10 standard_enthalpy_formation kj/mol qc_end chemical_equation 4 10 qc_end physical_unit 3 3 13 14 deltah qc_end end	[{"type":"physical unit","value":"Standard enthalpy of formation [OF] PCl5 [IN] kJ/mol"}]	[{"type":"physical unit","value":"444.00 kJ/mol"}]	[{"type":"chemical equation","value":"P4(s) + 10 Cl2(g) -> 4 PCl5(g)"},{"type":"physical unit","value":"DeltaH [OF] the reaction [=] \\pu{-1776 kJ}"}]	<h1 class="questionTitle" itemprop="name">Consider the following reaction: #"P"_(4(s)) + 10"Cl"_(2(g)) -> 4"PCl"_(5(g))#, #DeltaH =-"1776 kJ"#, what is the standard enthalpy of formation for #"PCl"_5#?</h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>Give the standard enthalpy of formation for PCl5(g). </p></div> </h2> </div> </div>	444.00 kJ/mol	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The most important thing to remember about <em>standard enthalpies of formation</em> is that they represent the <a href="https://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> change of reaction when <em><strong>one mole</strong></em> of a compound is formed from its constituent <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> in their standard state. </p> <p>This means that in order to expresses the standard enthalpy of formation, <mathjax>#DeltaH_f^@#</mathjax>, of a given compound, a <strong>thermochemical equation</strong> must always have <em><strong>one mole</strong></em> of that compound on the products' side. </p> <p>In your case, the thermochemical equation that describes the <strong><a href="https://socratic.org/chemistry/chemical-reactions/synthesis-reactions">synthesis</a></strong> of <em>phosphorus pentachloride</em>, <mathjax>#"PCl"_5#</mathjax>, from <em>white phosphorus</em>, <mathjax>#"P"_4#</mathjax> and <em>chlorine gas</em>, <mathjax>#"Cl"_2#</mathjax>, looks like this </p> <blockquote> <p><mathjax>#"P"_ (4(s)) + 10"Cl"_ (2(g)) -> color(red)(4)"PCl"_ (5(g))" " DeltaH_"rxn"^@ = -"1776 kJ"#</mathjax></p> </blockquote> <p>This thermochemical equation tells you that when <mathjax>#1#</mathjax> <strong>mole</strong> of white phosphorus reacts with <mathjax>#10#</mathjax> <strong>moles</strong> of chlorine gas, <mathjax>#color(red)(4)#</mathjax> <strong>moles</strong> of phosphorus pentachloride are formed and <mathjax>#"1776 kJ"#</mathjax> of heat are <strong>being released</strong>. </p> <p>In order to have a thermochemical equation that expresses the enthalpy change that occurs when <mathjax>#1#</mathjax> <strong>mole</strong> of <mathjax>#"PCl"_5#</mathjax> is formed, i.e. <mathjax>#DeltaH_f^@#</mathjax>, divide all the stoichiometric coefficients by <mathjax>#color(red)(4)#</mathjax></p> <blockquote> <p><mathjax>#1/color(red)(4)"P"_ (4(s)) + 5/2"Cl"_ (2(g)) -> "PCl"_ (5(g))" " DeltaH_f^@ = ?#</mathjax></p> </blockquote> <p>So, if you give off <mathjax>#"1776 kJ"#</mathjax> of heat when <mathjax>#color(red)(4)#</mathjax> <strong>moles</strong> of phosphorus pentachloride are formed, it follows that you will give off </p> <blockquote> <p><mathjax>#1 color(red)(cancel(color(black)("mole PCl"_5))) * "1776 kJ"/(color(red)(4)color(red)(cancel(color(black)("moles PCl"_5)))) = "444 kJ"#</mathjax></p> </blockquote> <p>when <strong>one mole</strong> of phosphorus pentachloride is formed. This means that the standard enthalpy change of formation for this compound will be </p> <blockquote> <p><mathjax>#color(green)(\|bar(ul(color(white)(a/a)color(black)(DeltaH_f^@ = -"444 kJ mol"^(-1))color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>Remember, the <em>minus sign</em> is used to symbolize <strong>heat lost</strong>. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#DeltaH_f^@ = -"444 kJ mol"^(-1)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The most important thing to remember about <em>standard enthalpies of formation</em> is that they represent the <a href="https://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> change of reaction when <em><strong>one mole</strong></em> of a compound is formed from its constituent <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> in their standard state. </p> <p>This means that in order to expresses the standard enthalpy of formation, <mathjax>#DeltaH_f^@#</mathjax>, of a given compound, a <strong>thermochemical equation</strong> must always have <em><strong>one mole</strong></em> of that compound on the products' side. </p> <p>In your case, the thermochemical equation that describes the <strong><a href="https://socratic.org/chemistry/chemical-reactions/synthesis-reactions">synthesis</a></strong> of <em>phosphorus pentachloride</em>, <mathjax>#"PCl"_5#</mathjax>, from <em>white phosphorus</em>, <mathjax>#"P"_4#</mathjax> and <em>chlorine gas</em>, <mathjax>#"Cl"_2#</mathjax>, looks like this </p> <blockquote> <p><mathjax>#"P"_ (4(s)) + 10"Cl"_ (2(g)) -> color(red)(4)"PCl"_ (5(g))" " DeltaH_"rxn"^@ = -"1776 kJ"#</mathjax></p> </blockquote> <p>This thermochemical equation tells you that when <mathjax>#1#</mathjax> <strong>mole</strong> of white phosphorus reacts with <mathjax>#10#</mathjax> <strong>moles</strong> of chlorine gas, <mathjax>#color(red)(4)#</mathjax> <strong>moles</strong> of phosphorus pentachloride are formed and <mathjax>#"1776 kJ"#</mathjax> of heat are <strong>being released</strong>. </p> <p>In order to have a thermochemical equation that expresses the enthalpy change that occurs when <mathjax>#1#</mathjax> <strong>mole</strong> of <mathjax>#"PCl"_5#</mathjax> is formed, i.e. <mathjax>#DeltaH_f^@#</mathjax>, divide all the stoichiometric coefficients by <mathjax>#color(red)(4)#</mathjax></p> <blockquote> <p><mathjax>#1/color(red)(4)"P"_ (4(s)) + 5/2"Cl"_ (2(g)) -> "PCl"_ (5(g))" " DeltaH_f^@ = ?#</mathjax></p> </blockquote> <p>So, if you give off <mathjax>#"1776 kJ"#</mathjax> of heat when <mathjax>#color(red)(4)#</mathjax> <strong>moles</strong> of phosphorus pentachloride are formed, it follows that you will give off </p> <blockquote> <p><mathjax>#1 color(red)(cancel(color(black)("mole PCl"_5))) * "1776 kJ"/(color(red)(4)color(red)(cancel(color(black)("moles PCl"_5)))) = "444 kJ"#</mathjax></p> </blockquote> <p>when <strong>one mole</strong> of phosphorus pentachloride is formed. This means that the standard enthalpy change of formation for this compound will be </p> <blockquote> <p><mathjax>#color(green)(\|bar(ul(color(white)(a/a)color(black)(DeltaH_f^@ = -"444 kJ mol"^(-1))color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>Remember, the <em>minus sign</em> is used to symbolize <strong>heat lost</strong>. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Consider the following reaction: #"P"_(4(s)) + 10"Cl"_(2(g)) -> 4"PCl"_(5(g))#, #DeltaH =-"1776 kJ"#, what is the standard enthalpy of formation for #"PCl"_5#?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>Give the standard enthalpy of formation for PCl5(g). </p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/enthalpy" itemprop="url"> <span class="breadcrumb" itemprop="title">Enthalpy</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="260361" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-04-29T21:49:14" itemprop="dateCreated"> Apr 29, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#DeltaH_f^@ = -"444 kJ mol"^(-1)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The most important thing to remember about <em>standard enthalpies of formation</em> is that they represent the <a href="https://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> change of reaction when <em><strong>one mole</strong></em> of a compound is formed from its constituent <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> in their standard state. </p> <p>This means that in order to expresses the standard enthalpy of formation, <mathjax>#DeltaH_f^@#</mathjax>, of a given compound, a <strong>thermochemical equation</strong> must always have <em><strong>one mole</strong></em> of that compound on the products' side. </p> <p>In your case, the thermochemical equation that describes the <strong><a href="https://socratic.org/chemistry/chemical-reactions/synthesis-reactions">synthesis</a></strong> of <em>phosphorus pentachloride</em>, <mathjax>#"PCl"_5#</mathjax>, from <em>white phosphorus</em>, <mathjax>#"P"_4#</mathjax> and <em>chlorine gas</em>, <mathjax>#"Cl"_2#</mathjax>, looks like this </p> <blockquote> <p><mathjax>#"P"_ (4(s)) + 10"Cl"_ (2(g)) -> color(red)(4)"PCl"_ (5(g))" " DeltaH_"rxn"^@ = -"1776 kJ"#</mathjax></p> </blockquote> <p>This thermochemical equation tells you that when <mathjax>#1#</mathjax> <strong>mole</strong> of white phosphorus reacts with <mathjax>#10#</mathjax> <strong>moles</strong> of chlorine gas, <mathjax>#color(red)(4)#</mathjax> <strong>moles</strong> of phosphorus pentachloride are formed and <mathjax>#"1776 kJ"#</mathjax> of heat are <strong>being released</strong>. </p> <p>In order to have a thermochemical equation that expresses the enthalpy change that occurs when <mathjax>#1#</mathjax> <strong>mole</strong> of <mathjax>#"PCl"_5#</mathjax> is formed, i.e. <mathjax>#DeltaH_f^@#</mathjax>, divide all the stoichiometric coefficients by <mathjax>#color(red)(4)#</mathjax></p> <blockquote> <p><mathjax>#1/color(red)(4)"P"_ (4(s)) + 5/2"Cl"_ (2(g)) -> "PCl"_ (5(g))" " DeltaH_f^@ = ?#</mathjax></p> </blockquote> <p>So, if you give off <mathjax>#"1776 kJ"#</mathjax> of heat when <mathjax>#color(red)(4)#</mathjax> <strong>moles</strong> of phosphorus pentachloride are formed, it follows that you will give off </p> <blockquote> <p><mathjax>#1 color(red)(cancel(color(black)("mole PCl"_5))) * "1776 kJ"/(color(red)(4)color(red)(cancel(color(black)("moles PCl"_5)))) = "444 kJ"#</mathjax></p> </blockquote> <p>when <strong>one mole</strong> of phosphorus pentachloride is formed. This means that the standard enthalpy change of formation for this compound will be </p> <blockquote> <p><mathjax>#color(green)(\|bar(ul(color(white)(a/a)color(black)(DeltaH_f^@ = -"444 kJ mol"^(-1))color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>Remember, the <em>minus sign</em> is used to symbolize <strong>heat lost</strong>. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/260361" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-enthalpy-changes-expressed-in-chemical-equations"> How are enthalpy changes expressed in chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-enthalpy-change-be-determined-for-an-aqueous-solution"> How can enthalpy change be determined for an aqueous solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-enthalpy-change-with-pressure"> How does enthalpy change with pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-standard-molar-enthalpy-formation"> How do you calculate standard molar enthalpy of formation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-enthalpy-a-state-function"> Why is enthalpy a state function? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-enthalpy-of-formation-of-oxygen-zero"> Why is the enthalpy of formation of oxygen zero? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-enthalpy-a-state-function-2"> Why is enthalpy a state function? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-enthalpy-cannot-be-measured-directly"> Why can enthalpy not be measured directly? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-pressure-affect-enthalpy"> How does pressure affect enthalpy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-enthalpy-relate-to-internal-energy"> How does enthalpy relate to internal energy? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/enthalpy"> See all questions in Enthalpy </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 11694 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Consider the following reaction: #"P"_(4(s)) + 10"Cl"_(2(g)) -> 4"PCl"_(5(g))#, #DeltaH =-"1776 kJ"#, what is the standard enthalpy of formation for #"PCl"_5#?	Give the standard enthalpy of formation for PCl5(g).
2,403	abe62bc3-6ddd-11ea-a534-ccda262736ce	https://socratic.org/questions/the-metabolism-of-one-mode-of-glycerol-trioleate-c-51h-93o-6-a-common-fat-produc	0.03 grams	start physical_unit 23 24 mass g qc_end physical_unit 8 8 3 4 mole qc_end physical_unit 8 8 13 16 heat_energy qc_end physical_unit 36 36 33 34 mass qc_end physical_unit 36 36 38 39 temperature qc_end physical_unit 36 36 41 42 temperature qc_end end	[{"type":"physical unit","value":"Mass [OF] the fat [IN] grams"}]	[{"type":"physical unit","value":"0.03 grams"}]	[{"type":"physical unit","value":"Mole [OF] C57H104O6 [=] \\pu{1 mole}"},{"type":"physical unit","value":"Produced heat [OF] C57H104O6 [=] \\pu{3.510 × 10^4 kJ}"},{"type":"physical unit","value":"Mass [OF] water [=] \\pu{50 g}"},{"type":"physical unit","value":"Temperature1 [OF] water [=] \\pu{25.0 ℃}"},{"type":"physical unit","value":"Temperature2 [OF] water [=] \\pu{30.0 ℃}"}]	<h1 class="questionTitle" itemprop="name">The metabolism of one mole of glyceryl trioleate, #C_57H_104O_6#, a common fat, produces #3.510 ×10^4# kJ of heat. How many grams of the fat must be burned to raise the temperature of 50 g of water from 25.0C to 30.0C?</h1>	null	0.03 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>There are two heat transfers involved.</p> <p><mathjax>#"heat of combustion of triolein + heat gained by water = 0"#</mathjax></p> <p><mathjax>#q_1 + q_2 = 0#</mathjax></p> <p><mathjax>#nΔ_ cH + mcΔT = 0#</mathjax></p> <blockquote></blockquote> <p>In this problem,</p> <p><mathjax>#Δ_ cH = "-3.510 × 10"^4color(white)(l) "kJ·mol"^"-1"#</mathjax><br/> <mathjax>#M_r = 885.43#</mathjax></p> <p><mathjax>#m = "50 g"#</mathjax><br/> <mathjax>#c = "4.184 J°C"^"-1""g"^"-1"#</mathjax><br/> <mathjax>#ΔT = T_f - T_i = "30.0 °C - 25.0 °C" = "5.0 °C"#</mathjax></p> <blockquote></blockquote> <p><mathjax>#q_1 = nΔ_cH = n color(red)(cancel(color(black)("mol"))) × ("-3.510 × 10"^4color(white)(l) "kJ"·color(red)(cancel(color(black)("mol"^"-1"))))= "-3.510 × 10"^4ncolor(white)(l) "kJ"#</mathjax></p> <p><mathjax>#q_2 = mcΔT = 50 color(red)(cancel(color(black)("g"))) × "4.184 J"·color(red)(cancel(color(black)("°C"^"-1""g"^"-1"))) × 5.0 color(red)(cancel(color(black)("°C"))) = "1046 J" = "1.046 kJ"#</mathjax></p> <blockquote></blockquote> <p><mathjax>#q_1 + q_2 = "-3.510 × 10"^4ncolor(white)(l) "kJ" + "1.046 kJ" = 0#</mathjax></p> <p><mathjax>#n = ("-1.046" color(red)(cancel(color(black)("kJ"))))/("-3.510 × 10"^4 color(red)(cancel(color(black)("kJ")))) = 2.98 × 10^"-5"#</mathjax></p> <blockquote></blockquote> <p><mathjax>#"Mass of triolein" = 2.98 × 10^"-5" color(red)(cancel(color(black)("mol triolein"))) × "885.43 g triolein"/(1 color(red)(cancel(color(black)("mol triolein")))) = "0.026 g triolein"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>You must burn 0.026 g of the fat.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>There are two heat transfers involved.</p> <p><mathjax>#"heat of combustion of triolein + heat gained by water = 0"#</mathjax></p> <p><mathjax>#q_1 + q_2 = 0#</mathjax></p> <p><mathjax>#nΔ_ cH + mcΔT = 0#</mathjax></p> <blockquote></blockquote> <p>In this problem,</p> <p><mathjax>#Δ_ cH = "-3.510 × 10"^4color(white)(l) "kJ·mol"^"-1"#</mathjax><br/> <mathjax>#M_r = 885.43#</mathjax></p> <p><mathjax>#m = "50 g"#</mathjax><br/> <mathjax>#c = "4.184 J°C"^"-1""g"^"-1"#</mathjax><br/> <mathjax>#ΔT = T_f - T_i = "30.0 °C - 25.0 °C" = "5.0 °C"#</mathjax></p> <blockquote></blockquote> <p><mathjax>#q_1 = nΔ_cH = n color(red)(cancel(color(black)("mol"))) × ("-3.510 × 10"^4color(white)(l) "kJ"·color(red)(cancel(color(black)("mol"^"-1"))))= "-3.510 × 10"^4ncolor(white)(l) "kJ"#</mathjax></p> <p><mathjax>#q_2 = mcΔT = 50 color(red)(cancel(color(black)("g"))) × "4.184 J"·color(red)(cancel(color(black)("°C"^"-1""g"^"-1"))) × 5.0 color(red)(cancel(color(black)("°C"))) = "1046 J" = "1.046 kJ"#</mathjax></p> <blockquote></blockquote> <p><mathjax>#q_1 + q_2 = "-3.510 × 10"^4ncolor(white)(l) "kJ" + "1.046 kJ" = 0#</mathjax></p> <p><mathjax>#n = ("-1.046" color(red)(cancel(color(black)("kJ"))))/("-3.510 × 10"^4 color(red)(cancel(color(black)("kJ")))) = 2.98 × 10^"-5"#</mathjax></p> <blockquote></blockquote> <p><mathjax>#"Mass of triolein" = 2.98 × 10^"-5" color(red)(cancel(color(black)("mol triolein"))) × "885.43 g triolein"/(1 color(red)(cancel(color(black)("mol triolein")))) = "0.026 g triolein"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">The metabolism of one mole of glyceryl trioleate, #C_57H_104O_6#, a common fat, produces #3.510 ×10^4# kJ of heat. How many grams of the fat must be burned to raise the temperature of 50 g of water from 25.0C to 30.0C?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/energy-change-in-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Energy Change in Reactions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="338119" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-11-18T01:57:13" itemprop="dateCreated"> Nov 18, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>You must burn 0.026 g of the fat.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>There are two heat transfers involved.</p> <p><mathjax>#"heat of combustion of triolein + heat gained by water = 0"#</mathjax></p> <p><mathjax>#q_1 + q_2 = 0#</mathjax></p> <p><mathjax>#nΔ_ cH + mcΔT = 0#</mathjax></p> <blockquote></blockquote> <p>In this problem,</p> <p><mathjax>#Δ_ cH = "-3.510 × 10"^4color(white)(l) "kJ·mol"^"-1"#</mathjax><br/> <mathjax>#M_r = 885.43#</mathjax></p> <p><mathjax>#m = "50 g"#</mathjax><br/> <mathjax>#c = "4.184 J°C"^"-1""g"^"-1"#</mathjax><br/> <mathjax>#ΔT = T_f - T_i = "30.0 °C - 25.0 °C" = "5.0 °C"#</mathjax></p> <blockquote></blockquote> <p><mathjax>#q_1 = nΔ_cH = n color(red)(cancel(color(black)("mol"))) × ("-3.510 × 10"^4color(white)(l) "kJ"·color(red)(cancel(color(black)("mol"^"-1"))))= "-3.510 × 10"^4ncolor(white)(l) "kJ"#</mathjax></p> <p><mathjax>#q_2 = mcΔT = 50 color(red)(cancel(color(black)("g"))) × "4.184 J"·color(red)(cancel(color(black)("°C"^"-1""g"^"-1"))) × 5.0 color(red)(cancel(color(black)("°C"))) = "1046 J" = "1.046 kJ"#</mathjax></p> <blockquote></blockquote> <p><mathjax>#q_1 + q_2 = "-3.510 × 10"^4ncolor(white)(l) "kJ" + "1.046 kJ" = 0#</mathjax></p> <p><mathjax>#n = ("-1.046" color(red)(cancel(color(black)("kJ"))))/("-3.510 × 10"^4 color(red)(cancel(color(black)("kJ")))) = 2.98 × 10^"-5"#</mathjax></p> <blockquote></blockquote> <p><mathjax>#"Mass of triolein" = 2.98 × 10^"-5" color(red)(cancel(color(black)("mol triolein"))) × "885.43 g triolein"/(1 color(red)(cancel(color(black)("mol triolein")))) = "0.026 g triolein"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/338119" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-endothermic-reactions-happen"> Why do endothermic reactions happen? 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What is the change in... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/energy-change-in-reactions"> See all questions in Energy Change in Reactions </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3489 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	The metabolism of one mole of glyceryl trioleate, #C_57H_104O_6#, a common fat, produces #3.510 ×10^4# kJ of heat. How many grams of the fat must be burned to raise the temperature of 50 g of water from 25.0C to 30.0C?	null
2,404	a9ebb480-6ddd-11ea-a986-ccda262736ce	https://socratic.org/questions/how-would-you-calculate-the-number-of-grams-of-sodium-oxide-na2o-that-will-be-pr	154.95 grams	start physical_unit 11 11 mass g qc_end physical_unit 19 19 17 18 mole qc_end chemical_equation 26 32 qc_end end	[{"type":"physical unit","value":"Mass [OF] Na2O [IN] grams"}]	[{"type":"physical unit","value":"154.95 grams"}]	[{"type":"physical unit","value":"Mole [OF] natrium [=] \\pu{5.00 moles}"},{"type":"chemical equation","value":"4 Na + O2 -> 2 Na2O"}]	<h1 class="questionTitle" itemprop="name">How would you calculate the number of grams of sodium oxide, Na2O, that will be produced when 5.00 moles react with oxygen given the reaction: 4Na + O2--> 2 Na2O? </h1>	null	154.95 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The molecular mass of natrium oxide is <mathjax>#61.98#</mathjax> <mathjax>#gmol^(-1)#</mathjax>. If <mathjax>#5#</mathjax> <mathjax>#mol#</mathjax> natrium react, then <mathjax>#5/2#</mathjax> <mathjax>#molxx61.98#</mathjax> <mathjax>#gmol^(-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#154.95#</mathjax> <mathjax>#g#</mathjax> natrium oxide should result. </p> <p>So what have I done here? First, I had a balanced chemical equation (this is the important step; is it balanced?). Then I used the stoichiometry to get the molar quantity of product, and converted this molar quantity to mass. If this is not clear, I am willing to have another go.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#4Na + O_2 rarr 2Na_2O#</mathjax>. </p> <p>By the <a href="http://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> of this reaction if 5 mol natrium react, then 2.5 mol <mathjax>#Na_2O#</mathjax> should result.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The molecular mass of natrium oxide is <mathjax>#61.98#</mathjax> <mathjax>#gmol^(-1)#</mathjax>. If <mathjax>#5#</mathjax> <mathjax>#mol#</mathjax> natrium react, then <mathjax>#5/2#</mathjax> <mathjax>#molxx61.98#</mathjax> <mathjax>#gmol^(-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#154.95#</mathjax> <mathjax>#g#</mathjax> natrium oxide should result. </p> <p>So what have I done here? First, I had a balanced chemical equation (this is the important step; is it balanced?). Then I used the stoichiometry to get the molar quantity of product, and converted this molar quantity to mass. If this is not clear, I am willing to have another go.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How would you calculate the number of grams of sodium oxide, Na2O, that will be produced when 5.00 moles react with oxygen given the reaction: 4Na + O2--> 2 Na2O? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="181985" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-01T20:46:32" itemprop="dateCreated"> Nov 1, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#4Na + O_2 rarr 2Na_2O#</mathjax>. </p> <p>By the <a href="http://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> of this reaction if 5 mol natrium react, then 2.5 mol <mathjax>#Na_2O#</mathjax> should result.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The molecular mass of natrium oxide is <mathjax>#61.98#</mathjax> <mathjax>#gmol^(-1)#</mathjax>. If <mathjax>#5#</mathjax> <mathjax>#mol#</mathjax> natrium react, then <mathjax>#5/2#</mathjax> <mathjax>#molxx61.98#</mathjax> <mathjax>#gmol^(-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#154.95#</mathjax> <mathjax>#g#</mathjax> natrium oxide should result. </p> <p>So what have I done here? First, I had a balanced chemical equation (this is the important step; is it balanced?). Then I used the stoichiometry to get the molar quantity of product, and converted this molar quantity to mass. If this is not clear, I am willing to have another go.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/181985" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What is stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ab82402bf342f48d93ac6"> Question #93ac6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-we-study-stoichiometry"> Why do we study stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-naoh-is-produced-from-1-20-x-102-grams-of-na2o-na2o-h2o-2-naoh"> How many grams of NaOH is produced from #1.20 x 10^2# grams of #Na_2O#? #Na_2O + H_2O -> 2NaOH# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-na2o-are-required-to-produce-1-60-x-102-grams-of-naoh-na2o-h2o"> How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? Na2O + H2O ---> 2 NaOH </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-mass-of-iron-is-needed-to-react-with-16-0-grams-of-sulfur-8-fe-s8-8-fes"> What mass of iron is needed to react with 16.0 grams of sulfur? 8 Fe + S8 ---> 8 FeS </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/according-to-8-fe-s8-8-fes-how-many-grams-of-fes-are-produced"> According to 8 Fe + S8 ---> 8 FeS How many grams of FeS are produced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/12-00-moles-of-naclo3-will-produce-how-many-grams-of-o2-2-naclo3-2-nacl-3-o2"> 12.00 moles of NaClO3 will produce how many grams of O2? 2 NaClO3 ---> 2 NaCl + 3 O2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-nacl-are-produced-when-80-0-grams-of-o2-are-produced-2-naclo3-"> How many grams of NaCl are produced when 80.0 grams of O2 are produced? 2 NaClO3 ---> 2 NaCl + 3 O2 </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/stoichiometry"> See all questions in Stoichiometry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 60485 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How would you calculate the number of grams of sodium oxide, Na2O, that will be produced when 5.00 moles react with oxygen given the reaction: 4Na + O2--> 2 Na2O?	null
2,405	ab01f026-6ddd-11ea-a4db-ccda262736ce	https://socratic.org/questions/576b4cb17c01496e94b477e6	14 KMnO4(s) + 4 C3H5(OH)3(l) -> 5 CO2(g) + 7 K2CO3(s) + 7 Mn2O3(s) + 16 H2O(l)	start chemical_equation qc_end substance 10 10 qc_end substance 12 13 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the combustion"}]	[{"type":"chemical equation","value":"14 KMnO4(s) + 4 C3H5(OH)3(l) -> 5 CO2(g) + 7 K2CO3(s) + 7 Mn2O3(s) + 16 H2O(l)"}]	[{"type":"substance name","value":"Glycerol"},{"type":"substance name","value":"Potassium permanganate"}]	<h1 class="questionTitle" itemprop="name">What is the balanced equation that represents the combustion of glycerol by potassium permanganate?</h1>	null	14 KMnO4(s) + 4 C3H5(OH)3(l) -> 5 CO2(g) + 7 K2CO3(s) + 7 Mn2O3(s) + 16 H2O(l)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is stoichiometrically balanced, as indeed it must be if it reflects chemical reality. The oxidation products are carbon dioxide, and potassium carbonate; the reduction products are a <mathjax>#Mn(III)#</mathjax> oxide. It is a spectacular reaction to do, but do it safely! I have seen a few fires when the reaction does not immediately commence, and the reaction mixture is placed into a waste container, where of course it does commence. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#14KMnO_4(s) + 4C_3H_5(OH)_3(l) rarr 5CO_2(g) + 7K_2CO_3(s) + 7Mn_2O_3(s)+16H_2O(l)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is stoichiometrically balanced, as indeed it must be if it reflects chemical reality. The oxidation products are carbon dioxide, and potassium carbonate; the reduction products are a <mathjax>#Mn(III)#</mathjax> oxide. It is a spectacular reaction to do, but do it safely! I have seen a few fires when the reaction does not immediately commence, and the reaction mixture is placed into a waste container, where of course it does commence. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the balanced equation that represents the combustion of glycerol by potassium permanganate?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-reactions-and-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions and Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="326694" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-10-26T06:46:50" itemprop="dateCreated"> Oct 26, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#14KMnO_4(s) + 4C_3H_5(OH)_3(l) rarr 5CO_2(g) + 7K_2CO_3(s) + 7Mn_2O_3(s)+16H_2O(l)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is stoichiometrically balanced, as indeed it must be if it reflects chemical reality. The oxidation products are carbon dioxide, and potassium carbonate; the reduction products are a <mathjax>#Mn(III)#</mathjax> oxide. It is a spectacular reaction to do, but do it safely! I have seen a few fires when the reaction does not immediately commence, and the reaction mixture is placed into a waste container, where of course it does commence. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/326694" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb002bf34694a4fee47"> Question #fee47 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb402bf34694c8c5c15"> Question #c5c15 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb802bf346950519eb9"> Question #19eb9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cbf02bf3469570e2ea2"> Question #e2ea2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc002bf34695a6bc751"> Question #bc751 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc202bf3469570e2ea6"> Question #e2ea6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531e867a02bf342492a08b07"> Question #08b07 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-thermochemical-equation-for-the-combustion-of-benzene"> What is the thermochemical equation for the combustion of benzene? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-reversible"> Why are chemical reactions reversible? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-important"> Why are chemical reactions important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/chemical-reactions-and-equations"> See all questions in Chemical Reactions and Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3698 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the balanced equation that represents the combustion of glycerol by potassium permanganate?	null
2,406	ac7b605d-6ddd-11ea-b728-ccda262736ce	https://socratic.org/questions/a-bottle-of-kmno-4-contains-66-38-g-of-the-compound-how-many-moles-of-kmno-4-doe	0.42 moles	start physical_unit 3 3 mole mol qc_end physical_unit 3 3 5 6 mass qc_end end	[{"type":"physical unit","value":"Mole [OF] KMnO4 [IN] moles"}]	[{"type":"physical unit","value":"0.42 moles"}]	[{"type":"physical unit","value":"Mass [OF] KMnO4 [=] \\pu{66.38 g}"}]	<h1 class="questionTitle" itemprop="name">A bottle of #KMnO_4# contains 66.38 g of the compound. How many moles of #KMnO_4# does it contain?</h1>	null	0.42 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The number of moles in a compound is given by the formula:<br/> moles<mathjax>#=(mass)/(mol. mass)#</mathjax><br/> Molar mass of <mathjax>#KMnO_4=158.034#</mathjax><br/> Given mass of <mathjax>#KMnO_4= 66.38g#</mathjax></p> <p>moles of <mathjax>#KMnO_4 = #</mathjax><mathjax>#66.38/158.034=0.42#</mathjax> g/mol</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#0.42#</mathjax> g/mol</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The number of moles in a compound is given by the formula:<br/> moles<mathjax>#=(mass)/(mol. mass)#</mathjax><br/> Molar mass of <mathjax>#KMnO_4=158.034#</mathjax><br/> Given mass of <mathjax>#KMnO_4= 66.38g#</mathjax></p> <p>moles of <mathjax>#KMnO_4 = #</mathjax><mathjax>#66.38/158.034=0.42#</mathjax> g/mol</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A bottle of #KMnO_4# contains 66.38 g of the compound. How many moles of #KMnO_4# does it contain?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="190313" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/callum-s"><img alt="" class="" src="https://lh3.googleusercontent.com/-XdUIqdMkCWA/AAAAAAAAAAI/AAAAAAAAAAA/4252rscbv5M/photo.jpg?sz=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/callum-s"> Callum S. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-18T19:27:33" itemprop="dateCreated"> Nov 18, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#0.42#</mathjax> g/mol</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The number of moles in a compound is given by the formula:<br/> moles<mathjax>#=(mass)/(mol. mass)#</mathjax><br/> Molar mass of <mathjax>#KMnO_4=158.034#</mathjax><br/> Given mass of <mathjax>#KMnO_4= 66.38g#</mathjax></p> <p>moles of <mathjax>#KMnO_4 = #</mathjax><mathjax>#66.38/158.034=0.42#</mathjax> g/mol</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/190313" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3238 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A bottle of #KMnO_4# contains 66.38 g of the compound. How many moles of #KMnO_4# does it contain?	null
2,407	ab72f1df-6ddd-11ea-a2fd-ccda262736ce	https://socratic.org/questions/how-many-sodium-atoms-are-there-in-6-0-g-of-na-3n	1.31 × 10^23	start physical_unit 2 3 number none qc_end physical_unit 10 10 7 8 mass qc_end end	[{"type":"physical unit","value":"Number [OF] sodium atoms"}]	[{"type":"physical unit","value":"1.31 × 10^23"}]	[{"type":"physical unit","value":"Mass [OF] Na3N [=] \\pu{6.0 g}"}]	<h1 class="questionTitle" itemprop="name">How many sodium atoms are there in 6.0 g of #Na_3N#? </h1>	null	1.31 × 10^23	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Moles of sodium nitride"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(6.0g)/(82.99gmol^-1)#</mathjax> </p> <p>Thus number of sodium atoms (or at least number of sodium ions):</p> <p><mathjax>#(6.0g)/(82.99gmol^-1)xxN_Axx3#</mathjax>, where <mathjax>#N_A=6.022xx10^23mol^-1#</mathjax></p> <p>i.e. <mathjax>#3xx(6.0g)/(82.99gmol^-1)xx6.022xx10^23*mol^-1#</mathjax>. We get an actual number, without units, as required. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Moles of sodium"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#3xx"moles of sodium nitride"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Moles of sodium nitride"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(6.0g)/(82.99gmol^-1)#</mathjax> </p> <p>Thus number of sodium atoms (or at least number of sodium ions):</p> <p><mathjax>#(6.0g)/(82.99gmol^-1)xxN_Axx3#</mathjax>, where <mathjax>#N_A=6.022xx10^23mol^-1#</mathjax></p> <p>i.e. <mathjax>#3xx(6.0g)/(82.99gmol^-1)xx6.022xx10^23*mol^-1#</mathjax>. We get an actual number, without units, as required. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many sodium atoms are there in 6.0 g of #Na_3N#? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="282597" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-29T07:47:59" itemprop="dateCreated"> Jun 29, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Moles of sodium"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#3xx"moles of sodium nitride"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Moles of sodium nitride"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(6.0g)/(82.99gmol^-1)#</mathjax> </p> <p>Thus number of sodium atoms (or at least number of sodium ions):</p> <p><mathjax>#(6.0g)/(82.99gmol^-1)xxN_Axx3#</mathjax>, where <mathjax>#N_A=6.022xx10^23mol^-1#</mathjax></p> <p>i.e. <mathjax>#3xx(6.0g)/(82.99gmol^-1)xx6.022xx10^23*mol^-1#</mathjax>. We get an actual number, without units, as required. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/282597" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 20361 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many sodium atoms are there in 6.0 g of #Na_3N#?	null
2,408	ac0bc96d-6ddd-11ea-af78-ccda262736ce	https://socratic.org/questions/what-is-the-temperature-of-0-80-mol-of-a-gas-stored-in-a-275-ml-cylinder-at-175-	7.24 K	start physical_unit 9 9 temperature k qc_end physical_unit 9 9 5 6 mole qc_end physical_unit 15 15 13 14 volume qc_end physical_unit 9 9 17 18 pressure qc_end end	[{"type":"physical unit","value":"Temperature [OF] the gas [IN] K"}]	[{"type":"physical unit","value":"7.24 K"}]	[{"type":"physical unit","value":"Mole [OF] the gas [=] \\pu{0.80 mol}"},{"type":"physical unit","value":"Volume [OF] cylinder [=] \\pu{275 mL}"},{"type":"physical unit","value":"Pressure [OF] the gas [=] \\pu{175 kPa}"}]	<h1 class="questionTitle" itemprop="name">What is the temperature of 0.80 mol of a gas stored in a 275 mL cylinder at 175 kPa?</h1>	null	7.24 K	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First, let's express pressure <mathjax>#P#</mathjax> in <mathjax>#"Pa"#</mathjax> and volume <mathjax>#V#</mathjax> in <mathjax>#"m"^(3)#</mathjax>:</p> <p><mathjax>#Rightarrow P = 175#</mathjax> <mathjax>#"kPa"#</mathjax></p> <p><mathjax>#Rightarrow P = 1.75 times 10^(5)#</mathjax> <mathjax>#"Pa"#</mathjax></p> <p><mathjax>#"and"#</mathjax></p> <p><mathjax>#Rightarrow V = 275#</mathjax> <mathjax>#"ml"#</mathjax></p> <p><mathjax>#Rightarrow V = 2.75 times 10^(- 4)#</mathjax> <mathjax>#"m"^(3)#</mathjax></p> <p>Then, let's solve the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> <mathjax>#P V = n R T#</mathjax> for temperature <mathjax>#T#</mathjax>:</p> <p><mathjax>#Rightarrow P V = n R T#</mathjax></p> <p><mathjax>#Rightarrow T = frac(P V)(n R)#</mathjax></p> <p>Substituting the appropriate values into the equation:</p> <p><mathjax>#Rightarrow T = frac(1.75 times 10^(5) times 2.75 times 10^(- 4))(0.80 times 8.314)#</mathjax> <mathjax>#"K"#</mathjax></p> <p><mathjax>#Rightarrow T = frac(48.125)(6.6512)#</mathjax> <mathjax>#"K"#</mathjax></p> <p><mathjax>#therefore T approx 7.24#</mathjax> <mathjax>#"K"#</mathjax></p> <p>Therefore, the temperature is around <mathjax>#7.24#</mathjax> <mathjax>#"K"#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#7.24#</mathjax> <mathjax>#"K"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First, let's express pressure <mathjax>#P#</mathjax> in <mathjax>#"Pa"#</mathjax> and volume <mathjax>#V#</mathjax> in <mathjax>#"m"^(3)#</mathjax>:</p> <p><mathjax>#Rightarrow P = 175#</mathjax> <mathjax>#"kPa"#</mathjax></p> <p><mathjax>#Rightarrow P = 1.75 times 10^(5)#</mathjax> <mathjax>#"Pa"#</mathjax></p> <p><mathjax>#"and"#</mathjax></p> <p><mathjax>#Rightarrow V = 275#</mathjax> <mathjax>#"ml"#</mathjax></p> <p><mathjax>#Rightarrow V = 2.75 times 10^(- 4)#</mathjax> <mathjax>#"m"^(3)#</mathjax></p> <p>Then, let's solve the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> <mathjax>#P V = n R T#</mathjax> for temperature <mathjax>#T#</mathjax>:</p> <p><mathjax>#Rightarrow P V = n R T#</mathjax></p> <p><mathjax>#Rightarrow T = frac(P V)(n R)#</mathjax></p> <p>Substituting the appropriate values into the equation:</p> <p><mathjax>#Rightarrow T = frac(1.75 times 10^(5) times 2.75 times 10^(- 4))(0.80 times 8.314)#</mathjax> <mathjax>#"K"#</mathjax></p> <p><mathjax>#Rightarrow T = frac(48.125)(6.6512)#</mathjax> <mathjax>#"K"#</mathjax></p> <p><mathjax>#therefore T approx 7.24#</mathjax> <mathjax>#"K"#</mathjax></p> <p>Therefore, the temperature is around <mathjax>#7.24#</mathjax> <mathjax>#"K"#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the temperature of 0.80 mol of a gas stored in a 275 mL cylinder at 175 kPa?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/gas-laws" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Laws</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="433049" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/tazwar89"><img alt="" class="" src="https://lh3.googleusercontent.com/-XdUIqdMkCWA/AAAAAAAAAAI/AAAAAAAAAAA/4252rscbv5M/photo.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/tazwar89"> Tazwar Sikder </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-01T11:57:56" itemprop="dateCreated"> Jun 1, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#7.24#</mathjax> <mathjax>#"K"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First, let's express pressure <mathjax>#P#</mathjax> in <mathjax>#"Pa"#</mathjax> and volume <mathjax>#V#</mathjax> in <mathjax>#"m"^(3)#</mathjax>:</p> <p><mathjax>#Rightarrow P = 175#</mathjax> <mathjax>#"kPa"#</mathjax></p> <p><mathjax>#Rightarrow P = 1.75 times 10^(5)#</mathjax> <mathjax>#"Pa"#</mathjax></p> <p><mathjax>#"and"#</mathjax></p> <p><mathjax>#Rightarrow V = 275#</mathjax> <mathjax>#"ml"#</mathjax></p> <p><mathjax>#Rightarrow V = 2.75 times 10^(- 4)#</mathjax> <mathjax>#"m"^(3)#</mathjax></p> <p>Then, let's solve the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> <mathjax>#P V = n R T#</mathjax> for temperature <mathjax>#T#</mathjax>:</p> <p><mathjax>#Rightarrow P V = n R T#</mathjax></p> <p><mathjax>#Rightarrow T = frac(P V)(n R)#</mathjax></p> <p>Substituting the appropriate values into the equation:</p> <p><mathjax>#Rightarrow T = frac(1.75 times 10^(5) times 2.75 times 10^(- 4))(0.80 times 8.314)#</mathjax> <mathjax>#"K"#</mathjax></p> <p><mathjax>#Rightarrow T = frac(48.125)(6.6512)#</mathjax> <mathjax>#"K"#</mathjax></p> <p><mathjax>#therefore T approx 7.24#</mathjax> <mathjax>#"K"#</mathjax></p> <p>Therefore, the temperature is around <mathjax>#7.24#</mathjax> <mathjax>#"K"#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/433049" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-boyles-law-relate-to-breathing"> How does Boyle's law relate to breathing? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" 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2,409	aa7b2be2-6ddd-11ea-9a50-ccda262736ce	https://socratic.org/questions/583a9295b72cff66d0ba7062	99.58%	start physical_unit 7 10 mass_percent none qc_end physical_unit 14 15 21 22 mass qc_end physical_unit 32 34 27 28 volume qc_end physical_unit 32 34 30 31 molarity qc_end c_other OTHER qc_end c_other OTHER qc_end physical_unit 52 53 47 48 volume qc_end physical_unit 52 53 50 51 molarity qc_end end	[{"type":"physical unit","value":"Percent by mass [OF] aspirin in the tablets"}]	[{"type":"physical unit","value":"99.58%"}]	[{"type":"physical unit","value":"Mass [OF] aspirin tablets [=] \\pu{1.427 g}"},{"type":"physical unit","value":"Number [OF] aspirin tablets [=] \\pu{4}"},{"type":"physical unit","value":"Volume [OF] sodium hydroxide solution [=] \\pu{50.00 mL}"},{"type":"physical unit","value":"Molarity [OF] sodium hydroxide solution [=] \\pu{0.500 mol/L}"},{"type":"other","value":"Excess sodium hydroxide."},{"type":"other","value":"To a phenolphthalein end-point."},{"type":"physical unit","value":"Volume [OF] hydrochloric acid [=] \\pu{31.92 mL}"},{"type":"physical unit","value":"Molarity [OF] hydrochloric acid [=] \\pu{0.289 mol/L}"}]	<h1 class="questionTitle" itemprop="name">What was the percent by mass of aspirin in the tablets?</h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>I dissolved four aspirin tablets with a total mass of 1.427 g in water and added 50.00 mL of 0.500 mol/L sodium hydroxide solution. Then I titrated the excess sodium hydroxide to a phenolphthalein end-point with 31.92 mL of 0.289 mol/L hydrochloric acid.</p></div> </h2> </div> </div>	99.58%	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>Step 1. Start with the balanced equation.</strong></p> <p><mathjax>#underbrace("C"_9"H"_8"O"_4)_color(red)("aspirin") + "2OH"^"-" → underbrace("C"_7"H"_5"O"_3^"-")_color(red)("salicylate") + underbrace("C"_2"H"_3"O"_2^"-")_color(red)("acetate") + "H"_2"O"#</mathjax></p> <p>For simplicity, let's rewrite the equation as</p> <p><mathjax>#"Asp + 2OH"^"-" → "Sal"^"-" + "Ac"^"-" + "H"_2"O"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 2. Calculate the moles of <mathjax>#"NaOH"#</mathjax> used.</strong></p> <p><mathjax>#"Moles NaOH" = "0.050 00" color(red)(cancel(color(black)("L NaOH"))) × "0.500 mol NaOH"/(1 color(red)(cancel(color(black)("L NaOH")))) = "0.025 00 mol NaOH"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 3. Calculate the moles of <mathjax>#"HCl"#</mathjax> used in the back-titration.</strong></p> <p><mathjax>#"Moles of HCl" = "0.031 92" color(red)(cancel(color(black)("L HCl"))) × "0.289 mol HCl"/(1 color(red)(cancel(color(black)("L HCl")))) = "0.009 225 mol HCl"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 4. Calculate the moles of excess <mathjax>#"NaOH"#</mathjax></strong></p> <p>The only base remaining after the reaction is the excess base that has not reacted with the aspirin.</p> <p>You are doing a <strong>strong acid-strong base</strong> titration.</p> <p>Once the NaOH is neutralized, the solution also contains the salts of the weak acids salicylic acid and acetic acid.</p> <p>The salts of weak acids are stronger bases.</p> <p>Thus <strong>phenolphthalein</strong> (which changes colour at <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> 9) is a good choice for the indicator.</p> <blockquote></blockquote> <p>The equation for the titration is</p> <p><mathjax>#"NaOH" + "HCl" → "H"_2"O" + "NaCl"#</mathjax></p> <p><mathjax>#"Moles of excess NaOH" = "0.009 225" color(red)(cancel(color(black)("mol HCl"))) × "1 mol NaOH"/(1 color(red)(cancel(color(black)("mol HCl")))) = "0.009 225 mol NaOH"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 5. Calculate the moles of <mathjax>#"NaOH"#</mathjax> used in the reaction.</strong></p> <p><mathjax>#"Original moles = moles reacted + excess moles"#</mathjax></p> <p><mathjax>#"Moles reacted" = "original moles - excess moles" = "(0.02500 - 0.009 225 mol) NaOH" = "0.015 775 mol NaOH"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 6. Calculate the moles of aspirin.</strong></p> <p><mathjax>#"Moles of Asp" = "0.015 78" color(red)(cancel(color(black)("mol NaOH"))) × "1 mol Asp"/(2 color(red)(cancel(color(black)("mol NaOH")))) = "0.007 888 mol Asp"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 7. Calculate the mass of aspirin.</strong></p> <p><mathjax>#"Mass of Asp" = "0.007 888" color(red)(cancel(color(black)("mol Asp"))) × "180.16 g Asp"/(1 color(red)(cancel(color(black)("mol Asp")))) = "1.421 g Asp"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 8. Finally (whew!), calculate the purity of the aspirin.</strong></p> <p><mathjax>#"Percent by mass" = "mass of pure Asp"/"mass of impure Asp" × 100 % = (1.421 color(red)(cancel(color(black)("g"))))/(1.427 color(red)(cancel(color(black)("g")))) × 100 %#</mathjax><br/> <mathjax>#= 99.6 %#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><strong>WARNING! Very long answer!</strong> The aspirin was 99.6 % pure.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>Step 1. Start with the balanced equation.</strong></p> <p><mathjax>#underbrace("C"_9"H"_8"O"_4)_color(red)("aspirin") + "2OH"^"-" → underbrace("C"_7"H"_5"O"_3^"-")_color(red)("salicylate") + underbrace("C"_2"H"_3"O"_2^"-")_color(red)("acetate") + "H"_2"O"#</mathjax></p> <p>For simplicity, let's rewrite the equation as</p> <p><mathjax>#"Asp + 2OH"^"-" → "Sal"^"-" + "Ac"^"-" + "H"_2"O"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 2. Calculate the moles of <mathjax>#"NaOH"#</mathjax> used.</strong></p> <p><mathjax>#"Moles NaOH" = "0.050 00" color(red)(cancel(color(black)("L NaOH"))) × "0.500 mol NaOH"/(1 color(red)(cancel(color(black)("L NaOH")))) = "0.025 00 mol NaOH"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 3. Calculate the moles of <mathjax>#"HCl"#</mathjax> used in the back-titration.</strong></p> <p><mathjax>#"Moles of HCl" = "0.031 92" color(red)(cancel(color(black)("L HCl"))) × "0.289 mol HCl"/(1 color(red)(cancel(color(black)("L HCl")))) = "0.009 225 mol HCl"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 4. Calculate the moles of excess <mathjax>#"NaOH"#</mathjax></strong></p> <p>The only base remaining after the reaction is the excess base that has not reacted with the aspirin.</p> <p>You are doing a <strong>strong acid-strong base</strong> titration.</p> <p>Once the NaOH is neutralized, the solution also contains the salts of the weak acids salicylic acid and acetic acid.</p> <p>The salts of weak acids are stronger bases.</p> <p>Thus <strong>phenolphthalein</strong> (which changes colour at <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> 9) is a good choice for the indicator.</p> <blockquote></blockquote> <p>The equation for the titration is</p> <p><mathjax>#"NaOH" + "HCl" → "H"_2"O" + "NaCl"#</mathjax></p> <p><mathjax>#"Moles of excess NaOH" = "0.009 225" color(red)(cancel(color(black)("mol HCl"))) × "1 mol NaOH"/(1 color(red)(cancel(color(black)("mol HCl")))) = "0.009 225 mol NaOH"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 5. Calculate the moles of <mathjax>#"NaOH"#</mathjax> used in the reaction.</strong></p> <p><mathjax>#"Original moles = moles reacted + excess moles"#</mathjax></p> <p><mathjax>#"Moles reacted" = "original moles - excess moles" = "(0.02500 - 0.009 225 mol) NaOH" = "0.015 775 mol NaOH"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 6. Calculate the moles of aspirin.</strong></p> <p><mathjax>#"Moles of Asp" = "0.015 78" color(red)(cancel(color(black)("mol NaOH"))) × "1 mol Asp"/(2 color(red)(cancel(color(black)("mol NaOH")))) = "0.007 888 mol Asp"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 7. Calculate the mass of aspirin.</strong></p> <p><mathjax>#"Mass of Asp" = "0.007 888" color(red)(cancel(color(black)("mol Asp"))) × "180.16 g Asp"/(1 color(red)(cancel(color(black)("mol Asp")))) = "1.421 g Asp"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 8. Finally (whew!), calculate the purity of the aspirin.</strong></p> <p><mathjax>#"Percent by mass" = "mass of pure Asp"/"mass of impure Asp" × 100 % = (1.421 color(red)(cancel(color(black)("g"))))/(1.427 color(red)(cancel(color(black)("g")))) × 100 %#</mathjax><br/> <mathjax>#= 99.6 %#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What was the percent by mass of aspirin in the tablets?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>I dissolved four aspirin tablets with a total mass of 1.427 g in water and added 50.00 mL of 0.500 mol/L sodium hydroxide solution. Then I titrated the excess sodium hydroxide to a phenolphthalein end-point with 31.92 mL of 0.289 mol/L hydrochloric acid.</p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#reactions-in-solution" itemprop="url"> <span class="breadcrumb" itemprop="title">Reactions in Solution</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/reactions-in-solution/titration-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">Titration Calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="342613" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-11-27T15:00:59" itemprop="dateCreated"> Nov 27, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><strong>WARNING! Very long answer!</strong> The aspirin was 99.6 % pure.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>Step 1. Start with the balanced equation.</strong></p> <p><mathjax>#underbrace("C"_9"H"_8"O"_4)_color(red)("aspirin") + "2OH"^"-" → underbrace("C"_7"H"_5"O"_3^"-")_color(red)("salicylate") + underbrace("C"_2"H"_3"O"_2^"-")_color(red)("acetate") + "H"_2"O"#</mathjax></p> <p>For simplicity, let's rewrite the equation as</p> <p><mathjax>#"Asp + 2OH"^"-" → "Sal"^"-" + "Ac"^"-" + "H"_2"O"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 2. Calculate the moles of <mathjax>#"NaOH"#</mathjax> used.</strong></p> <p><mathjax>#"Moles NaOH" = "0.050 00" color(red)(cancel(color(black)("L NaOH"))) × "0.500 mol NaOH"/(1 color(red)(cancel(color(black)("L NaOH")))) = "0.025 00 mol NaOH"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 3. Calculate the moles of <mathjax>#"HCl"#</mathjax> used in the back-titration.</strong></p> <p><mathjax>#"Moles of HCl" = "0.031 92" color(red)(cancel(color(black)("L HCl"))) × "0.289 mol HCl"/(1 color(red)(cancel(color(black)("L HCl")))) = "0.009 225 mol HCl"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 4. Calculate the moles of excess <mathjax>#"NaOH"#</mathjax></strong></p> <p>The only base remaining after the reaction is the excess base that has not reacted with the aspirin.</p> <p>You are doing a <strong>strong acid-strong base</strong> titration.</p> <p>Once the NaOH is neutralized, the solution also contains the salts of the weak acids salicylic acid and acetic acid.</p> <p>The salts of weak acids are stronger bases.</p> <p>Thus <strong>phenolphthalein</strong> (which changes colour at <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> 9) is a good choice for the indicator.</p> <blockquote></blockquote> <p>The equation for the titration is</p> <p><mathjax>#"NaOH" + "HCl" → "H"_2"O" + "NaCl"#</mathjax></p> <p><mathjax>#"Moles of excess NaOH" = "0.009 225" color(red)(cancel(color(black)("mol HCl"))) × "1 mol NaOH"/(1 color(red)(cancel(color(black)("mol HCl")))) = "0.009 225 mol NaOH"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 5. Calculate the moles of <mathjax>#"NaOH"#</mathjax> used in the reaction.</strong></p> <p><mathjax>#"Original moles = moles reacted + excess moles"#</mathjax></p> <p><mathjax>#"Moles reacted" = "original moles - excess moles" = "(0.02500 - 0.009 225 mol) NaOH" = "0.015 775 mol NaOH"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 6. Calculate the moles of aspirin.</strong></p> <p><mathjax>#"Moles of Asp" = "0.015 78" color(red)(cancel(color(black)("mol NaOH"))) × "1 mol Asp"/(2 color(red)(cancel(color(black)("mol NaOH")))) = "0.007 888 mol Asp"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 7. Calculate the mass of aspirin.</strong></p> <p><mathjax>#"Mass of Asp" = "0.007 888" color(red)(cancel(color(black)("mol Asp"))) × "180.16 g Asp"/(1 color(red)(cancel(color(black)("mol Asp")))) = "1.421 g Asp"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 8. Finally (whew!), calculate the purity of the aspirin.</strong></p> <p><mathjax>#"Percent by mass" = "mass of pure Asp"/"mass of impure Asp" × 100 % = (1.421 color(red)(cancel(color(black)("g"))))/(1.427 color(red)(cancel(color(black)("g")))) × 100 %#</mathjax><br/> <mathjax>#= 99.6 %#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/342613" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-do-acid-base-titration-calculations"> How do you do acid base titration calculations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-use-titration-calculations-to-find-ph"> How do you use titration calculations to find pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/radox-titration"> What is a redox titration and what is it used for? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-titration-used-when-standardizing-a-solution"> Why is titration used when standardizing a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-titration-suitable-for-sodium-nitrate"> Is titration suitable for sodium nitrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-do-redox-titration-calculations"> How can I do redox titration calculations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-titration-of-weak-acid-and-strong-base"> How can I calculate the titration of a weak acid and a strong base? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-make-back-titration-calculations"> How can I make back titration calculations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-titration-affect-molarity"> How does titration affect molarity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-endpoint-of-a-titration-differ-from-the-equivalence-point"> How does the endpoint of a titration differ from the equivalence point? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/reactions-in-solution/titration-calculations"> See all questions in Titration Calculations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 57187 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What was the percent by mass of aspirin in the tablets?	I dissolved four aspirin tablets with a total mass of 1.427 g in water and added 50.00 mL of 0.500 mol/L sodium hydroxide solution. Then I titrated the excess sodium hydroxide to a phenolphthalein end-point with 31.92 mL of 0.289 mol/L hydrochloric acid.
2,410	aa6f1e0c-6ddd-11ea-b380-ccda262736ce	https://socratic.org/questions/if-30-0-ml-of-12-0-m-hcl-stock-solution-are-diluted-to-a-volume-of-500-ml-what-i	0.72 M	start physical_unit 22 24 molarity mol/l qc_end physical_unit 6 8 1 2 volume qc_end physical_unit 6 8 4 5 molarity qc_end physical_unit 6 8 15 16 volume qc_end end	[{"type":"physical unit","value":"Molarity2 [OF] the dilute solution [IN] M"}]	[{"type":"physical unit","value":"0.72 M"}]	[{"type":"physical unit","value":"Volume1 [OF] HCl stock solution [=] \\pu{30.0 mL}"},{"type":"physical unit","value":"Molarity1 [OF] HCl stock solution [=] \\pu{12.0 M}"},{"type":"physical unit","value":"Volume2 [OF] HCl stock solution [=] \\pu{500 mL}"}]	<h1 class="questionTitle" itemprop="name">If 30.0 mL of 12.0 M #HCl# stock solution are diluted to a volume of 500 mL, what is the molarity of the dilute solution?</h1>	null	0.72 M	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><pre><code>Required conc. = ml * stock conc. / make up vol. </code></pre> <p>So, we can apply the calculation</p> <pre><code> = 30 * 12 / 500 = 0.72 M </code></pre></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.72 M</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><pre><code>Required conc. = ml * stock conc. / make up vol. </code></pre> <p>So, we can apply the calculation</p> <pre><code> = 30 * 12 / 500 = 0.72 M </code></pre></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">If 30.0 mL of 12.0 M #HCl# stock solution are diluted to a volume of 500 mL, what is the molarity of the dilute solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/dilution-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">Dilution Calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="250784" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/k-venkatesan"><img alt="" class="" src="https://profilepictures.socratic.org/NZRlDScSBegEKXTQLGwg_946715_1383978781827900_558114094_n.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/k-venkatesan"> k.venkatesan </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-04-07T04:43:15" itemprop="dateCreated"> Apr 7, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.72 M</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><pre><code>Required conc. = ml * stock conc. / make up vol. </code></pre> <p>So, we can apply the calculation</p> <pre><code> = 30 * 12 / 500 = 0.72 M </code></pre></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/250784" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-concentration-from-absorbance"> How do you calculate concentration from absorbance? 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</a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-would-be-the-concentration-of-a-solution-made-by-adding-250-ml-of-water-to-"> What would be the concentration of a solution made by adding 250 mL of water to 45.0 mL of 4.2 M KOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-would-be-the-concentration-of-a-solution-made-by-diluting-45-0-ml-of-4-2-m-"> What would be the concentration of a solution made by diluting 45.0 mL of 4.2 M KOH to 250 mL? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-a-solution-that-is-made-by-diluting-50-00-ml-of-a-4-74-m"> What is the molarity of a solution that is made by diluting 50.00 mL of a 4.74 M solution of HCl... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-volume-of-water-would-you-add-to-15-00-ml-of-a-6-77-m-solution-of-nitric-ac"> What volume of water would you add to 15.00 mL of a 6.77 M solution of nitric acid in order to... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/dilution-calculations"> See all questions in Dilution Calculations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 53288 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	If 30.0 mL of 12.0 M #HCl# stock solution are diluted to a volume of 500 mL, what is the molarity of the dilute solution?	null
2,411	a8db04dc-6ddd-11ea-bcc2-ccda262736ce	https://socratic.org/questions/5895df9511ef6b3c42733f45	5	start physical_unit 2 3 number none qc_end chemical_equation 11 11 qc_end end	[{"type":"physical unit","value":"Number [OF] structural isomers"}]	[{"type":"physical unit","value":"5"}]	[{"type":"chemical equation","value":"C4H8"}]	<h1 class="questionTitle" itemprop="name">How many structural isomers can be proposed for a formula of #C_4H_8#?</h1>	null	5	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#C_4H_8#</mathjax> has one degree of unsaturation, and thus whatever the compound we have the one degree of unsaturation, i.e. one olefinic bond, or 1 ring junction. </p> <p>So I count 2 ring structures: <mathjax>#"cyclobutane"#</mathjax>; and <mathjax>#"methylcyclopropane."#</mathjax></p> <p>And I count 3 olefinic structural isomers: <mathjax>#"1-butylene"#</mathjax>; <mathjax>#"2-butylene"#</mathjax>; <mathjax>#"2-methylpropene"#</mathjax>. <mathjax>#"2-butylene"#</mathjax> can exist as 2 geometric isomers, which are? </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, I count 5 structural isomers........</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#C_4H_8#</mathjax> has one degree of unsaturation, and thus whatever the compound we have the one degree of unsaturation, i.e. one olefinic bond, or 1 ring junction. </p> <p>So I count 2 ring structures: <mathjax>#"cyclobutane"#</mathjax>; and <mathjax>#"methylcyclopropane."#</mathjax></p> <p>And I count 3 olefinic structural isomers: <mathjax>#"1-butylene"#</mathjax>; <mathjax>#"2-butylene"#</mathjax>; <mathjax>#"2-methylpropene"#</mathjax>. <mathjax>#"2-butylene"#</mathjax> can exist as 2 geometric isomers, which are? </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many structural isomers can be proposed for a formula of #C_4H_8#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#organic-chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Organic Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/organic-chemistry/isomerisms" itemprop="url"> <span class="breadcrumb" itemprop="title">Isomerisms</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="373360" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-02-04T14:17:54" itemprop="dateCreated"> Feb 4, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, I count 5 structural isomers........</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#C_4H_8#</mathjax> has one degree of unsaturation, and thus whatever the compound we have the one degree of unsaturation, i.e. one olefinic bond, or 1 ring junction. </p> <p>So I count 2 ring structures: <mathjax>#"cyclobutane"#</mathjax>; and <mathjax>#"methylcyclopropane."#</mathjax></p> <p>And I count 3 olefinic structural isomers: <mathjax>#"1-butylene"#</mathjax>; <mathjax>#"2-butylene"#</mathjax>; <mathjax>#"2-methylpropene"#</mathjax>. <mathjax>#"2-butylene"#</mathjax> can exist as 2 geometric isomers, which are? </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/373360" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/53e3a5bd02bf340360ad6c0e"> Question #d6c0e </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/53e90b6702bf340d71c9959f"> Question #9959f </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-an-isomer"> What is an isomer? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/54939b6a581e2a1c2d5eb772"> Question #eb772 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-the-isomers-of-butane"> What are the isomers of butane? 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2,412	ac21cc43-6ddd-11ea-85a8-ccda262736ce	https://socratic.org/questions/what-is-the-correct-formula-for-dicarbon-tetrahydride	C2H4	start chemical_formula qc_end substance 6 7 qc_end end	[{"type":"other","value":"Chemical Formula [OF] dicarbon tetrahydride [IN] default"}]	[{"type":"chemical equation","value":"C2H4"}]	[{"type":"substance name","value":"Dicarbon tetrahydride"}]	<h1 class="questionTitle" itemprop="name">What is the correct formula for dicarbon tetrahydride? </h1>	null	C2H4	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Know your prefixes. "Di-" <mathjax>#rarr2#</mathjax> and "tetra-"<mathjax>#rarr4#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_2H_4#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Know your prefixes. "Di-" <mathjax>#rarr2#</mathjax> and "tetra-"<mathjax>#rarr4#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the correct formula for dicarbon tetrahydride? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#covalent-bonds-and-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Covalent Bonds</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/covalent-bonds-and-formulas/covalent-formulas-and-nomenclature" itemprop="url"> <span class="breadcrumb" itemprop="title">Covalent Formulas and Nomenclature</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="188914" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/mason-m"><img alt="" class="" src="https://profilepictures.socratic.org/U70pu8hUTGGkEuy92fsO_IMG_2585.jpeg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/mason-m"> mason m </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-15T15:56:38" itemprop="dateCreated"> Nov 15, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_2H_4#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Know your prefixes. "Di-" <mathjax>#rarr2#</mathjax> and "tetra-"<mathjax>#rarr4#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/188914" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-for-sugar"> What is the chemical formula for sugar? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-chemical-formula-represents-a-carbohydrate"> What chemical formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-for-gold"> What is the chemical formula for gold? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-for-a-diamond"> What is the chemical formula for a diamond? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-formulas-for-covalent-compounds"> How do you find formulas for covalent compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-common-mistakes-students-make-with-empirical-forumlas"> What are common mistakes students make with empirical forumlas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-empirical-formulas"> What are empirical formulas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-examples-of-empirical-formulas"> What are some examples of empirical formulas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-naming-a-covalent-bond-between-atoms-how-would-you-write-the-prefix-for-if-"> When naming a covalently-bonded molecule, how would you write the prefix if you had four atoms... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-nomenclature-for-ch3cl"> What is the chemical nomenclature for CH3Cl? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/covalent-bonds-and-formulas/covalent-formulas-and-nomenclature"> See all questions in Covalent Formulas and Nomenclature </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 25642 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the correct formula for dicarbon tetrahydride?	null
2,413	a978244b-6ddd-11ea-b588-ccda262736ce	https://socratic.org/questions/what-is-the-volume-of-4-50-mol-of-so-2-at-stp	100.80 L	start physical_unit 8 8 volume l qc_end physical_unit 8 8 5 6 mole qc_end c_other STP qc_end end	[{"type":"physical unit","value":"Volume [OF] SO2 [IN] L"}]	[{"type":"physical unit","value":"100.80 L"}]	[{"type":"physical unit","value":"Mole [OF] SO2 [=] \\pu{4.50 mol}"},{"type":"other","value":"STP"}]	<h1 class="questionTitle" itemprop="name">What is the volume of 4.50 mol of #SO_2# at #STP#?</h1>	null	100.80 L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>If we assume the behaviour of <mathjax>#SO_2#</mathjax> to be ideal, the volume of the given quantity of gas is <mathjax>#4.5xx22.4#</mathjax> <mathjax>#dm^3#</mathjax>. It is likely that <mathjax>#SO_2#</mathjax> would show some deviation from ideality at this temperature, but the value would be good for a first approximation. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The molar volume of an ideal gas at <mathjax>#STP#</mathjax> is <mathjax>#22.4#</mathjax> <mathjax>#dm^3#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>If we assume the behaviour of <mathjax>#SO_2#</mathjax> to be ideal, the volume of the given quantity of gas is <mathjax>#4.5xx22.4#</mathjax> <mathjax>#dm^3#</mathjax>. It is likely that <mathjax>#SO_2#</mathjax> would show some deviation from ideality at this temperature, but the value would be good for a first approximation. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the volume of 4.50 mol of #SO_2# at #STP#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="220636" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-02-02T19:37:43" itemprop="dateCreated"> Feb 2, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The molar volume of an ideal gas at <mathjax>#STP#</mathjax> is <mathjax>#22.4#</mathjax> <mathjax>#dm^3#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>If we assume the behaviour of <mathjax>#SO_2#</mathjax> to be ideal, the volume of the given quantity of gas is <mathjax>#4.5xx22.4#</mathjax> <mathjax>#dm^3#</mathjax>. It is likely that <mathjax>#SO_2#</mathjax> would show some deviation from ideality at this temperature, but the value would be good for a first approximation. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/220636" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-morality-be-used-as-a-conversion-factor"> How can molarity be used as a conversion factor? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-high-can-molarity-be"> How high can molarity be? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-molarity-change-with-temperature"> How does molarity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molarity-of-a-solution"> How do you find molarity of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-10-naoh"> What is the molarity of 10 NaOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-3-hydrogen-peroxide"> What is the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1310 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the volume of 4.50 mol of #SO_2# at #STP#?	null
2,414	a9476506-6ddd-11ea-b2ee-ccda262736ce	https://socratic.org/questions/how-many-moles-of-o-2-are-produced-from-4-01-10-23-molecules-fe-2o-3	1.00 moles	start physical_unit 4 4 mole mol qc_end end	[{"type":"physical unit","value":"Mole [OF] O2 [IN] moles"}]	[{"type":"physical unit","value":"1.00 moles"}]	[{"type":"physical unit","value":"Number [OF] Fe2O3 molecules [=] \\pu{4.01 × 10^23}"}]	<h1 class="questionTitle" itemprop="name">How many moles of #O_2# are produced from #4.01 * 10^23# molecules #Fe_2O_3#?</h1>	null	1.00 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>Given:</strong> Formula units of <mathjax>#"Fe"_2"O"_3#</mathjax>; chemical equation (understood)</p> <p><strong>Find:</strong> Moles of <mathjax>#"O"_2#</mathjax></p> <p><strong>Strategy:</strong></p> <p>The central part of any <a href="http://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> problem is to <strong>convert moles of something to moles of something else</strong>.</p> <p><strong>(a)</strong> We start with the balanced chemical equation for the reaction.</p> <p><strong>(b)</strong> We can use the <strong>molar ratio</strong> to convert moles of <mathjax>#"Fe"_2"O"_3#</mathjax> to moles of <mathjax>#"O"_2#</mathjax>.</p> <p><mathjax>#"moles of Fe"_2"O"_3stackrelcolor (blue)("molar ratio"color(white)(Xl))( →) "moles of O"_2#</mathjax></p> <p><strong>(c)</strong> Then we can use <strong>Avogadro's number</strong> to convert formula units of <mathjax>#"Fe"_2"O"_3#</mathjax> to moles of <mathjax>#"Fe"_2"O"_3#</mathjax>.</p> <p>Our complete strategy is:</p> <p><mathjax>#"Formula units of Fe"_2"O"_3stackrelcolor (blue)("Avogadro's number"color(white)(Xl))(→) "moles of Fe"_2"O"_3stackrelcolor (blue)("molar ratio"color(white)(Xl))( →) "moles of O"_2#</mathjax></p> <blockquote></blockquote> <p><strong>Solution</strong></p> <p><strong>(a)</strong> The balanced equation is</p> <p><mathjax>#"2Fe"_2"O"_3 → "4Fe" + "3O"_2#</mathjax></p> <blockquote></blockquote> <p><strong>(b)</strong> <mathjax>#"Moles of Fe"_2"O"_3 = 4.01×10^23color(red)(cancel(color(black)("FU Fe"_2"O"_3))) × ("1 mol Fe"_2"O"_3)/(6.022×10^23color(red)(cancel(color(black)("FU Fe"_2"O"_3)))) = "0.6659 mol Fe"_2"O"_3#</mathjax></p> <blockquote></blockquote> <p><strong>(c)</strong><mathjax>#"Moles of O"_2 = 0.6659 color(red)(cancel(color(black)("mol Fe"_2"O"_3))) × ("3 mol O"_2)/(2 color(red)(cancel(color(black)("mol Fe"_2"O"_3)))) = "0.999 mol O"_2#</mathjax><br/> (3 significant figures)</p> <p><strong>Answer:</strong> <mathjax>#4.01×10^23color(white)(l)"FU Fe"_2"O"_3#</mathjax> will produce <mathjax>#color(red)("0.999 mol O"_2)#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The reaction produces 0.999 mol of <mathjax>#"O"_2#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>Given:</strong> Formula units of <mathjax>#"Fe"_2"O"_3#</mathjax>; chemical equation (understood)</p> <p><strong>Find:</strong> Moles of <mathjax>#"O"_2#</mathjax></p> <p><strong>Strategy:</strong></p> <p>The central part of any <a href="http://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> problem is to <strong>convert moles of something to moles of something else</strong>.</p> <p><strong>(a)</strong> We start with the balanced chemical equation for the reaction.</p> <p><strong>(b)</strong> We can use the <strong>molar ratio</strong> to convert moles of <mathjax>#"Fe"_2"O"_3#</mathjax> to moles of <mathjax>#"O"_2#</mathjax>.</p> <p><mathjax>#"moles of Fe"_2"O"_3stackrelcolor (blue)("molar ratio"color(white)(Xl))( →) "moles of O"_2#</mathjax></p> <p><strong>(c)</strong> Then we can use <strong>Avogadro's number</strong> to convert formula units of <mathjax>#"Fe"_2"O"_3#</mathjax> to moles of <mathjax>#"Fe"_2"O"_3#</mathjax>.</p> <p>Our complete strategy is:</p> <p><mathjax>#"Formula units of Fe"_2"O"_3stackrelcolor (blue)("Avogadro's number"color(white)(Xl))(→) "moles of Fe"_2"O"_3stackrelcolor (blue)("molar ratio"color(white)(Xl))( →) "moles of O"_2#</mathjax></p> <blockquote></blockquote> <p><strong>Solution</strong></p> <p><strong>(a)</strong> The balanced equation is</p> <p><mathjax>#"2Fe"_2"O"_3 → "4Fe" + "3O"_2#</mathjax></p> <blockquote></blockquote> <p><strong>(b)</strong> <mathjax>#"Moles of Fe"_2"O"_3 = 4.01×10^23color(red)(cancel(color(black)("FU Fe"_2"O"_3))) × ("1 mol Fe"_2"O"_3)/(6.022×10^23color(red)(cancel(color(black)("FU Fe"_2"O"_3)))) = "0.6659 mol Fe"_2"O"_3#</mathjax></p> <blockquote></blockquote> <p><strong>(c)</strong><mathjax>#"Moles of O"_2 = 0.6659 color(red)(cancel(color(black)("mol Fe"_2"O"_3))) × ("3 mol O"_2)/(2 color(red)(cancel(color(black)("mol Fe"_2"O"_3)))) = "0.999 mol O"_2#</mathjax><br/> (3 significant figures)</p> <p><strong>Answer:</strong> <mathjax>#4.01×10^23color(white)(l)"FU Fe"_2"O"_3#</mathjax> will produce <mathjax>#color(red)("0.999 mol O"_2)#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles of #O_2# are produced from #4.01 * 10^23# molecules #Fe_2O_3#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/equation-stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Equation Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="209985" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-08T20:31:34" itemprop="dateCreated"> Jan 8, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The reaction produces 0.999 mol of <mathjax>#"O"_2#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>Given:</strong> Formula units of <mathjax>#"Fe"_2"O"_3#</mathjax>; chemical equation (understood)</p> <p><strong>Find:</strong> Moles of <mathjax>#"O"_2#</mathjax></p> <p><strong>Strategy:</strong></p> <p>The central part of any <a href="http://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> problem is to <strong>convert moles of something to moles of something else</strong>.</p> <p><strong>(a)</strong> We start with the balanced chemical equation for the reaction.</p> <p><strong>(b)</strong> We can use the <strong>molar ratio</strong> to convert moles of <mathjax>#"Fe"_2"O"_3#</mathjax> to moles of <mathjax>#"O"_2#</mathjax>.</p> <p><mathjax>#"moles of Fe"_2"O"_3stackrelcolor (blue)("molar ratio"color(white)(Xl))( →) "moles of O"_2#</mathjax></p> <p><strong>(c)</strong> Then we can use <strong>Avogadro's number</strong> to convert formula units of <mathjax>#"Fe"_2"O"_3#</mathjax> to moles of <mathjax>#"Fe"_2"O"_3#</mathjax>.</p> <p>Our complete strategy is:</p> <p><mathjax>#"Formula units of Fe"_2"O"_3stackrelcolor (blue)("Avogadro's number"color(white)(Xl))(→) "moles of Fe"_2"O"_3stackrelcolor (blue)("molar ratio"color(white)(Xl))( →) "moles of O"_2#</mathjax></p> <blockquote></blockquote> <p><strong>Solution</strong></p> <p><strong>(a)</strong> The balanced equation is</p> <p><mathjax>#"2Fe"_2"O"_3 → "4Fe" + "3O"_2#</mathjax></p> <blockquote></blockquote> <p><strong>(b)</strong> <mathjax>#"Moles of Fe"_2"O"_3 = 4.01×10^23color(red)(cancel(color(black)("FU Fe"_2"O"_3))) × ("1 mol Fe"_2"O"_3)/(6.022×10^23color(red)(cancel(color(black)("FU Fe"_2"O"_3)))) = "0.6659 mol Fe"_2"O"_3#</mathjax></p> <blockquote></blockquote> <p><strong>(c)</strong><mathjax>#"Moles of O"_2 = 0.6659 color(red)(cancel(color(black)("mol Fe"_2"O"_3))) × ("3 mol O"_2)/(2 color(red)(cancel(color(black)("mol Fe"_2"O"_3)))) = "0.999 mol O"_2#</mathjax><br/> (3 significant figures)</p> <p><strong>Answer:</strong> <mathjax>#4.01×10^23color(white)(l)"FU Fe"_2"O"_3#</mathjax> will produce <mathjax>#color(red)("0.999 mol O"_2)#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/209985" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4171602bf3469588dc36e"> What are the types of stoichiometry examples, with examples? </a> 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2,415	ab0153ef-6ddd-11ea-97b2-ccda262736ce	https://socratic.org/questions/in-the-complete-reaction-of-22-99-g-of-sodium-with-35-45-g-of-chloride-what-mass	58.44 g	start physical_unit 17 18 mass g qc_end physical_unit 8 8 5 6 mass qc_end physical_unit 13 13 10 11 mass qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Mass [OF] sodium chloride [IN] g"}]	[{"type":"physical unit","value":"58.44 g"}]	[{"type":"physical unit","value":"Mass [OF] sodium [=] \\pu{22.99 g}"},{"type":"physical unit","value":"Mass [OF] chloride [=] \\pu{35.45 g}"},{"type":"other","value":"Complete reaction."}]	<h1 class="questionTitle" itemprop="name">In the complete reaction of 22.99 g of sodium with 35,45 g of chloride, what mass of sodium chloride is formed?</h1>	null	58.44 g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The reaction that takes place is:</p> <p>Na + Cl -> NaCl<br/> the ratio of this reaction is 1 : 1 : 1</p> <p>Na = 22.9898 g/mole<br/> Cl = 35.453 g/mole<br/> NaCl = 58.44 g/mole</p> <p>First you calculate <a href="http://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> using the known data:<br/> mole = mass / molar mass<br/> mole sodium = 22.99 / 22.9898 = 1.00</p> <p>since the ratio is 1 : 1 : 1, all you have to do is:<br/> mass = mole * molar mass<br/> mass NaCl = 1.00 * 58.44 = 58.44 g</p> <p>you can check if all the mass of Cl is used by calculating the mass using the mole and the molar mass:<br/> Mass Cl = 1.00 * 35.45 = 35.45 g<br/> Which was the amount of mass used in the reaction so everything correct, meaning the amount of mass formed in the reaction is 58.44 grams.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>58.44 g</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The reaction that takes place is:</p> <p>Na + Cl -> NaCl<br/> the ratio of this reaction is 1 : 1 : 1</p> <p>Na = 22.9898 g/mole<br/> Cl = 35.453 g/mole<br/> NaCl = 58.44 g/mole</p> <p>First you calculate <a href="http://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> using the known data:<br/> mole = mass / molar mass<br/> mole sodium = 22.99 / 22.9898 = 1.00</p> <p>since the ratio is 1 : 1 : 1, all you have to do is:<br/> mass = mole * molar mass<br/> mass NaCl = 1.00 * 58.44 = 58.44 g</p> <p>you can check if all the mass of Cl is used by calculating the mass using the mole and the molar mass:<br/> Mass Cl = 1.00 * 35.45 = 35.45 g<br/> Which was the amount of mass used in the reaction so everything correct, meaning the amount of mass formed in the reaction is 58.44 grams.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">In the complete reaction of 22.99 g of sodium with 35,45 g of chloride, what mass of sodium chloride is formed?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="190813" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/chiara-g-1"><img alt="" class="" src="https://profilepictures.socratic.org/Y0YMEEsQZuqC7ijLEFP2_DSC_0026_2.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/chiara-g-1"> Chiara G. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-19T22:46:08" itemprop="dateCreated"> Nov 19, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>58.44 g</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The reaction that takes place is:</p> <p>Na + Cl -> NaCl<br/> the ratio of this reaction is 1 : 1 : 1</p> <p>Na = 22.9898 g/mole<br/> Cl = 35.453 g/mole<br/> NaCl = 58.44 g/mole</p> <p>First you calculate <a href="http://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> using the known data:<br/> mole = mass / molar mass<br/> mole sodium = 22.99 / 22.9898 = 1.00</p> <p>since the ratio is 1 : 1 : 1, all you have to do is:<br/> mass = mole * molar mass<br/> mass NaCl = 1.00 * 58.44 = 58.44 g</p> <p>you can check if all the mass of Cl is used by calculating the mass using the mole and the molar mass:<br/> Mass Cl = 1.00 * 35.45 = 35.45 g<br/> Which was the amount of mass used in the reaction so everything correct, meaning the amount of mass formed in the reaction is 58.44 grams.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/190813" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul 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2,416	ab54c714-6ddd-11ea-8f21-ccda262736ce	https://socratic.org/questions/59071e0811ef6b5672fdc9bb	Mn3O4	start chemical_formula qc_end end	[{"type":"other","value":"Chemical Formula [OF] manganese oxide [IN] empirical"}]	[{"type":"chemical equation","value":"Mn3O4"}]	[{"type":"physical unit","value":"Percent [OF] manganese in manganese oxide [=] \\pu{72%}"}]	<h1 class="questionTitle" itemprop="name">A certain manganese oxide contains 72% manganese. What is the empirical formula?</h1>	null	Mn3O4	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We convert the mass ratio into mol ratio:</p> <p>Then 72g of this is Manganese. <br/> The molar mass of <mathjax>#Mn=55#</mathjax>, so <mathjax>#72gharr72/55=1.31mol#</mathjax> of <mathjax>#Mn#</mathjax></p> <p>The 28g of Oxygen (molar mass <mathjax>#O= 16#</mathjax>) breaks down to:<br/> <mathjax>#28gharr28/16=1.75mol#</mathjax> of <mathjax>#O#</mathjax></p> <p>The mol ratio <mathjax>#MndivO=1.31div1.75=0.75div1=3div4#</mathjax></p> <p>Empirical formula: <mathjax>#Mn_3O_4#</mathjax></p> <p><strong>Note:</strong><br/> This works if you take any other sample size, but then there are more calculations to do.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Since <mathjax>#%#</mathjax> litterally means "per hundred" let's take a 100g sample.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We convert the mass ratio into mol ratio:</p> <p>Then 72g of this is Manganese. <br/> The molar mass of <mathjax>#Mn=55#</mathjax>, so <mathjax>#72gharr72/55=1.31mol#</mathjax> of <mathjax>#Mn#</mathjax></p> <p>The 28g of Oxygen (molar mass <mathjax>#O= 16#</mathjax>) breaks down to:<br/> <mathjax>#28gharr28/16=1.75mol#</mathjax> of <mathjax>#O#</mathjax></p> <p>The mol ratio <mathjax>#MndivO=1.31div1.75=0.75div1=3div4#</mathjax></p> <p>Empirical formula: <mathjax>#Mn_3O_4#</mathjax></p> <p><strong>Note:</strong><br/> This works if you take any other sample size, but then there are more calculations to do.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A certain manganese oxide contains 72% manganese. What is the empirical formula?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="415749" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meneernask"><img alt="" class="" src="https://profilepictures.socratic.org/gpA0lokRGK9vLVUnAMAy_meneernask.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meneernask"> MeneerNask </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-01T12:39:02" itemprop="dateCreated"> May 1, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Since <mathjax>#%#</mathjax> litterally means "per hundred" let's take a 100g sample.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We convert the mass ratio into mol ratio:</p> <p>Then 72g of this is Manganese. <br/> The molar mass of <mathjax>#Mn=55#</mathjax>, so <mathjax>#72gharr72/55=1.31mol#</mathjax> of <mathjax>#Mn#</mathjax></p> <p>The 28g of Oxygen (molar mass <mathjax>#O= 16#</mathjax>) breaks down to:<br/> <mathjax>#28gharr28/16=1.75mol#</mathjax> of <mathjax>#O#</mathjax></p> <p>The mol ratio <mathjax>#MndivO=1.31div1.75=0.75div1=3div4#</mathjax></p> <p>Empirical formula: <mathjax>#Mn_3O_4#</mathjax></p> <p><strong>Note:</strong><br/> This works if you take any other sample size, but then there are more calculations to do.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/415749" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? 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</a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-empirical-formula-not-double-that-of-the-monosaccharides"> Why is the empirical formula not double that of the monosaccharides? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5331180502bf342f40b5c3b5"> Question #5c3b5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-molecular-formula-represents-a-carbohydrate"> What molecular formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-of-vinegar"> What is the molecular formula of vinegar? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/empirical-and-molecular-formulas"> See all questions in Empirical and Molecular Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 6474 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A certain manganese oxide contains 72% manganese. What is the empirical formula?	null
2,417	aa71b8bc-6ddd-11ea-8a71-ccda262736ce	https://socratic.org/questions/what-is-the-oxidation-number-of-sulfur-in-na2so4	+6	start physical_unit 6 6 oxidation_number none qc_end chemical_equation 8 8 qc_end end	[{"type":"physical unit","value":"Oxidation number [OF] sulfur"}]	[{"type":"physical unit","value":"+6"}]	[{"type":"chemical equation","value":"Na2SO4"}]	<h1 class="questionTitle" itemprop="name">What is the oxidation number of sulfur in Na2SO4?</h1>	null	+6	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You're dealing with <em>sodium sulfate</em>, an <a href="http://socratic.org/chemistry/ionic-bonds-and-formulas/ionic-compounds">ionic compound</a> composed of sodium cations, <mathjax>#"Na"^(+)#</mathjax>, and sulfate anions, <mathjax>#"SO"_4^(2-)#</mathjax>, in <mathjax>#2:1#</mathjax> ratio. </p> <p>Start with what you know. Sodium has an oxidation state that matches its overall ionic charge, so right from the start you know that sodium will have an oxidation state of <mathjax>#color(blue)(+1)#</mathjax>. </p> <p>Now focus on the sulfate anion. </p> <p>In most compoiunds, oxygen has an oxidation state of <mathjax>#color(blue)(-2)#</mathjax>. </p> <p>When dealing with ions, the oxidation states of <em>all the atoms</em> that make up the ion <strong>must add up to give</strong> the overall charge of said ion. </p> <p>In this case, the overall charge of the sulfate anion is <mathjax>#(2-)#</mathjax>. As you know, <a href="http://socratic.org/chemistry/electrochemistry/oxidation-numbers">oxidation states</a> are assigned <em>per atom</em>, so you can say that</p> <blockquote> <p><mathjax>#1 xx ON_"sulfur" + 4 xx ON_"oxygen" = -2#</mathjax></p> </blockquote> <p>This means that the oxidation state of sulfur is </p> <blockquote> <p><mathjax>#ON_"sulfur" + 4 * (-2) = -2#</mathjax></p> <p><mathjax>#ON_"sulfur" = -2 + 8 = color(green)(+6)#</mathjax></p> </blockquote> <p>The oxidation states for this compound are</p> <blockquote> <p><mathjax>#stackrel(color(blue)(+1))("Na")_2stackrel(color(blue)(+6))"S" stackrel(color(blue)(-2))("O"_4)#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#+6#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You're dealing with <em>sodium sulfate</em>, an <a href="http://socratic.org/chemistry/ionic-bonds-and-formulas/ionic-compounds">ionic compound</a> composed of sodium cations, <mathjax>#"Na"^(+)#</mathjax>, and sulfate anions, <mathjax>#"SO"_4^(2-)#</mathjax>, in <mathjax>#2:1#</mathjax> ratio. </p> <p>Start with what you know. Sodium has an oxidation state that matches its overall ionic charge, so right from the start you know that sodium will have an oxidation state of <mathjax>#color(blue)(+1)#</mathjax>. </p> <p>Now focus on the sulfate anion. </p> <p>In most compoiunds, oxygen has an oxidation state of <mathjax>#color(blue)(-2)#</mathjax>. </p> <p>When dealing with ions, the oxidation states of <em>all the atoms</em> that make up the ion <strong>must add up to give</strong> the overall charge of said ion. </p> <p>In this case, the overall charge of the sulfate anion is <mathjax>#(2-)#</mathjax>. As you know, <a href="http://socratic.org/chemistry/electrochemistry/oxidation-numbers">oxidation states</a> are assigned <em>per atom</em>, so you can say that</p> <blockquote> <p><mathjax>#1 xx ON_"sulfur" + 4 xx ON_"oxygen" = -2#</mathjax></p> </blockquote> <p>This means that the oxidation state of sulfur is </p> <blockquote> <p><mathjax>#ON_"sulfur" + 4 * (-2) = -2#</mathjax></p> <p><mathjax>#ON_"sulfur" = -2 + 8 = color(green)(+6)#</mathjax></p> </blockquote> <p>The oxidation states for this compound are</p> <blockquote> <p><mathjax>#stackrel(color(blue)(+1))("Na")_2stackrel(color(blue)(+6))"S" stackrel(color(blue)(-2))("O"_4)#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the oxidation number of sulfur in Na2SO4?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#electrochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Electrochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/electrochemistry/oxidation-numbers" itemprop="url"> <span class="breadcrumb" itemprop="title">Oxidation Numbers</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="180016" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-10-26T01:06:28" itemprop="dateCreated"> Oct 26, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#+6#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You're dealing with <em>sodium sulfate</em>, an <a href="http://socratic.org/chemistry/ionic-bonds-and-formulas/ionic-compounds">ionic compound</a> composed of sodium cations, <mathjax>#"Na"^(+)#</mathjax>, and sulfate anions, <mathjax>#"SO"_4^(2-)#</mathjax>, in <mathjax>#2:1#</mathjax> ratio. </p> <p>Start with what you know. Sodium has an oxidation state that matches its overall ionic charge, so right from the start you know that sodium will have an oxidation state of <mathjax>#color(blue)(+1)#</mathjax>. </p> <p>Now focus on the sulfate anion. </p> <p>In most compoiunds, oxygen has an oxidation state of <mathjax>#color(blue)(-2)#</mathjax>. </p> <p>When dealing with ions, the oxidation states of <em>all the atoms</em> that make up the ion <strong>must add up to give</strong> the overall charge of said ion. </p> <p>In this case, the overall charge of the sulfate anion is <mathjax>#(2-)#</mathjax>. As you know, <a href="http://socratic.org/chemistry/electrochemistry/oxidation-numbers">oxidation states</a> are assigned <em>per atom</em>, so you can say that</p> <blockquote> <p><mathjax>#1 xx ON_"sulfur" + 4 xx ON_"oxygen" = -2#</mathjax></p> </blockquote> <p>This means that the oxidation state of sulfur is </p> <blockquote> <p><mathjax>#ON_"sulfur" + 4 * (-2) = -2#</mathjax></p> <p><mathjax>#ON_"sulfur" = -2 + 8 = color(green)(+6)#</mathjax></p> </blockquote> <p>The oxidation states for this compound are</p> <blockquote> <p><mathjax>#stackrel(color(blue)(+1))("Na")_2stackrel(color(blue)(+6))"S" stackrel(color(blue)(-2))("O"_4)#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/180016" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-relate-to-electron-configuration"> How do oxidation numbers relate to electron configuration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-relate-to-valence-electrons"> How do oxidation numbers relate to valence electrons? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-vary-with-the-periodic-table"> How do oxidation numbers vary with the periodic table? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-oxidation-number-of-an-element-in-a-compound"> How do you calculate the oxidation number of an element in a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-sulfur"> What is the oxidation number for sulfur? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-carbon"> What is the oxidation number for carbon? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-copper"> What is the oxidation number for copper? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-nitrogen"> What is the oxidation number for nitrogen? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-oxygen"> What is the oxidation number for oxygen? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-oxidation-state-of-noble-gas-zero"> Why is the oxidation state of noble gas zero? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/electrochemistry/oxidation-numbers"> See all questions in Oxidation Numbers </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 42958 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the oxidation number of sulfur in Na2SO4?	null
2,418	a91ad546-6ddd-11ea-afb6-ccda262736ce	https://socratic.org/questions/the-activation-energy-of-a-certain-reaction-is-49-4-kj-mol-at-20-degrees-c-the-r	1.00 s^(-1)	start physical_unit 6 6 constant_r s^(-1) qc_end physical_unit 6 6 8 9 activation_barrier qc_end physical_unit 6 6 11 13 temperature qc_end physical_unit 6 6 18 19 constant_r qc_end physical_unit 6 6 26 28 temperature qc_end end	[{"type":"physical unit","value":"Rate constant2 [OF] the reaction [IN] s^(-1)"}]	[{"type":"physical unit","value":"1.00 s^(-1)"}]	[{"type":"physical unit","value":"Activation energy [OF] the reaction [=] \\pu{49.4 kJ/mol}"},{"type":"physical unit","value":"Temperature1 [OF] the reaction [=] \\pu{20 degrees C}"},{"type":"physical unit","value":"Rate constant1 [OF] the reaction [=] \\pu{0.0130 s^(-1)}"},{"type":"physical unit","value":"Temperature2 [OF] the reaction [=] \\pu{100 degree C}"}]	<h1 class="questionTitle" itemprop="name">The activation energy of a certain reaction is 49.4 kJ/mol. At 20 degrees C, the rate constant is .0130 s^-1. What is the rate constant at 100 degree C?</h1>	null	1.00 s^(-1)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The <strong>Arrhenius equation</strong> gives the relation between temperature and reaction rates:</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a) k = Ae^(-E_"a"/(RT))color(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>where</p> <p><mathjax>#k#</mathjax> = the rate constant<br/> <mathjax>#A#</mathjax> = the pre-exponential factor<br/> <mathjax>#E_"a"#</mathjax> = the activation energy<br/> <mathjax>#R#</mathjax> = the Universal Gas Constant<br/> <mathjax>#T#</mathjax> = the temperature</p> <blockquote></blockquote> <p>If we take the logarithms of both sides, we get</p> <blockquote> <blockquote> <p><mathjax>#lnk = lnA - E_"a"/(RT)#</mathjax></p> </blockquote> </blockquote> <p>Finally, if we have the rates at two different temperatures, we can derive the expression</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a) ln(k_2/k_1) = E_"a"/R(1/T_1 -1/T_2)color(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>In your problem, </p> <p><mathjax>#k_1 = "0.0130 s"^"-1"#</mathjax><br/> <mathjax>#E_"a" = "49.4 kJ/mol" = "49 400 J/mol"#</mathjax><br/> <mathjax>#R = "8.314 J·K"^"-1""mol"^"-1"#</mathjax><br/> <mathjax>#T_2 = "100 °C" = "373.15 K"#</mathjax><br/> <mathjax>#T_1 = "20 °" = "293.15 K"#</mathjax></p> <blockquote></blockquote> <p>Now, let's insert the numbers.</p> <p><mathjax>#ln(k_2/k_1) = E_"a"/R(1/T_1 -1/T_2)#</mathjax></p> <p><mathjax>#ln(k_2/k_1) = ("49 400" color(red)(cancel(color(black)("J·mol"^"-1"))))/(8.314 color(red)(cancel(color(black)("J·K"^"-1""mol"^"-1")))) (1/(293.15 color(red)(cancel(color(black)("K")))) - 1/(373.15 color(red)(cancel(color(black)("K")))))#</mathjax></p> <p><mathjax>#ln(k_2/k_1) = 5942× 7.313 × 10^"-4" = 4.346#</mathjax></p> <p><mathjax>#(k_2/k_1) = e^4.346 = 77.14#</mathjax></p> <p><mathjax>#k_2 = 77.14k_1 = 77.14 × "0.0130 s"^"-1" = "1.00 s"^"-1"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The rate constant is <mathjax>#"1.00 s"^"-1"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The <strong>Arrhenius equation</strong> gives the relation between temperature and reaction rates:</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a) k = Ae^(-E_"a"/(RT))color(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>where</p> <p><mathjax>#k#</mathjax> = the rate constant<br/> <mathjax>#A#</mathjax> = the pre-exponential factor<br/> <mathjax>#E_"a"#</mathjax> = the activation energy<br/> <mathjax>#R#</mathjax> = the Universal Gas Constant<br/> <mathjax>#T#</mathjax> = the temperature</p> <blockquote></blockquote> <p>If we take the logarithms of both sides, we get</p> <blockquote> <blockquote> <p><mathjax>#lnk = lnA - E_"a"/(RT)#</mathjax></p> </blockquote> </blockquote> <p>Finally, if we have the rates at two different temperatures, we can derive the expression</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a) ln(k_2/k_1) = E_"a"/R(1/T_1 -1/T_2)color(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>In your problem, </p> <p><mathjax>#k_1 = "0.0130 s"^"-1"#</mathjax><br/> <mathjax>#E_"a" = "49.4 kJ/mol" = "49 400 J/mol"#</mathjax><br/> <mathjax>#R = "8.314 J·K"^"-1""mol"^"-1"#</mathjax><br/> <mathjax>#T_2 = "100 °C" = "373.15 K"#</mathjax><br/> <mathjax>#T_1 = "20 °" = "293.15 K"#</mathjax></p> <blockquote></blockquote> <p>Now, let's insert the numbers.</p> <p><mathjax>#ln(k_2/k_1) = E_"a"/R(1/T_1 -1/T_2)#</mathjax></p> <p><mathjax>#ln(k_2/k_1) = ("49 400" color(red)(cancel(color(black)("J·mol"^"-1"))))/(8.314 color(red)(cancel(color(black)("J·K"^"-1""mol"^"-1")))) (1/(293.15 color(red)(cancel(color(black)("K")))) - 1/(373.15 color(red)(cancel(color(black)("K")))))#</mathjax></p> <p><mathjax>#ln(k_2/k_1) = 5942× 7.313 × 10^"-4" = 4.346#</mathjax></p> <p><mathjax>#(k_2/k_1) = e^4.346 = 77.14#</mathjax></p> <p><mathjax>#k_2 = 77.14k_1 = 77.14 × "0.0130 s"^"-1" = "1.00 s"^"-1"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">The activation energy of a certain reaction is 49.4 kJ/mol. At 20 degrees C, the rate constant is .0130 s^-1. What is the rate constant at 100 degree C?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-kinetics" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Kinetics</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-kinetics/rate-of-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Rate of Reactions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="296654" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-08-08T00:40:00" itemprop="dateCreated"> Aug 8, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The rate constant is <mathjax>#"1.00 s"^"-1"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The <strong>Arrhenius equation</strong> gives the relation between temperature and reaction rates:</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a) k = Ae^(-E_"a"/(RT))color(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>where</p> <p><mathjax>#k#</mathjax> = the rate constant<br/> <mathjax>#A#</mathjax> = the pre-exponential factor<br/> <mathjax>#E_"a"#</mathjax> = the activation energy<br/> <mathjax>#R#</mathjax> = the Universal Gas Constant<br/> <mathjax>#T#</mathjax> = the temperature</p> <blockquote></blockquote> <p>If we take the logarithms of both sides, we get</p> <blockquote> <blockquote> <p><mathjax>#lnk = lnA - E_"a"/(RT)#</mathjax></p> </blockquote> </blockquote> <p>Finally, if we have the rates at two different temperatures, we can derive the expression</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a) ln(k_2/k_1) = E_"a"/R(1/T_1 -1/T_2)color(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>In your problem, </p> <p><mathjax>#k_1 = "0.0130 s"^"-1"#</mathjax><br/> <mathjax>#E_"a" = "49.4 kJ/mol" = "49 400 J/mol"#</mathjax><br/> <mathjax>#R = "8.314 J·K"^"-1""mol"^"-1"#</mathjax><br/> <mathjax>#T_2 = "100 °C" = "373.15 K"#</mathjax><br/> <mathjax>#T_1 = "20 °" = "293.15 K"#</mathjax></p> <blockquote></blockquote> <p>Now, let's insert the numbers.</p> <p><mathjax>#ln(k_2/k_1) = E_"a"/R(1/T_1 -1/T_2)#</mathjax></p> <p><mathjax>#ln(k_2/k_1) = ("49 400" color(red)(cancel(color(black)("J·mol"^"-1"))))/(8.314 color(red)(cancel(color(black)("J·K"^"-1""mol"^"-1")))) (1/(293.15 color(red)(cancel(color(black)("K")))) - 1/(373.15 color(red)(cancel(color(black)("K")))))#</mathjax></p> <p><mathjax>#ln(k_2/k_1) = 5942× 7.313 × 10^"-4" = 4.346#</mathjax></p> <p><mathjax>#(k_2/k_1) = e^4.346 = 77.14#</mathjax></p> <p><mathjax>#k_2 = 77.14k_1 = 77.14 × "0.0130 s"^"-1" = "1.00 s"^"-1"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/296654" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-rate-of-reaction"> How do you calculate rate of reaction? 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At 20 degrees C, the rate constant is .0130 s^-1. What is the rate constant at 100 degree C?	null
2,419	aa86019c-6ddd-11ea-b085-ccda262736ce	https://socratic.org/questions/what-is-the-percent-by-mass-of-a-solution-that-is-prepared-by-mixing-3-785-grams	7.97%	start physical_unit 17 18 mass_percent none qc_end physical_unit 17 18 14 15 mass qc_end physical_unit 23 23 20 21 volume qc_end physical_unit 23 23 30 31 density qc_end end	[{"type":"physical unit","value":"Percent by mass [OF] sodium chloride in solution"}]	[{"type":"physical unit","value":"7.97%"}]	[{"type":"physical unit","value":"Mass [OF] sodium chloride [=] \\pu{3.785 grams}"},{"type":"physical unit","value":"Volume [OF] water [=] \\pu{43.7 milliliters}"},{"type":"physical unit","value":"Density [OF] water [=] \\pu{1.00 g/mL}"}]	<h1 class="questionTitle" itemprop="name">What is the percent by mass of a solution that is prepared by mixing 3.785 grams of sodium chloride with 43.7 milliliters of water (assume the density of water is 1.00 g/mL)? Thanks!?</h1>	null	7.97%	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to determine a solution's <a href="http://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration by mass</a>, you need to know the mass of the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a>, in your case sodium chloride, and the mass of the <strong>entire solution</strong>, which contains sodium chloride and water. </p> <p>Since you know what the <a href="http://socratic.org/chemistry/measurement-in-chemistry/density">density</a> of water is, you can use its volume to determine its mass. </p> <p><mathjax>#rho = m/V => m = rho * V#</mathjax></p> <p><mathjax>#43.7cancel("mL") * "1.00 g"/(1cancel("mL")) = "43.7 g"#</mathjax></p> <p>This means that the mass of the solution will be </p> <p><mathjax>#m_"solution" = m_"sodium chloride" + m_"water"#</mathjax></p> <p><mathjax>#m_"solution" = 3.785 + 43.7 = "47.485 g"#</mathjax></p> <p>Therefore, your solution's <a href="http://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration by mass</a> will be </p> <p><mathjax>#"%m/m" = m_"sodium chloride"/m_"solution" * 100#</mathjax></p> <p><mathjax>#"%m/m" = (3.785cancel("g"))/(47.485cancel("g")) * 100 = color(green)("7.97%")#</mathjax></p> <p>Your sodium chloride solution is <strong>7.97% m/m</strong>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The solution is <strong>7.97% m/m</strong>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to determine a solution's <a href="http://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration by mass</a>, you need to know the mass of the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a>, in your case sodium chloride, and the mass of the <strong>entire solution</strong>, which contains sodium chloride and water. </p> <p>Since you know what the <a href="http://socratic.org/chemistry/measurement-in-chemistry/density">density</a> of water is, you can use its volume to determine its mass. </p> <p><mathjax>#rho = m/V => m = rho * V#</mathjax></p> <p><mathjax>#43.7cancel("mL") * "1.00 g"/(1cancel("mL")) = "43.7 g"#</mathjax></p> <p>This means that the mass of the solution will be </p> <p><mathjax>#m_"solution" = m_"sodium chloride" + m_"water"#</mathjax></p> <p><mathjax>#m_"solution" = 3.785 + 43.7 = "47.485 g"#</mathjax></p> <p>Therefore, your solution's <a href="http://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration by mass</a> will be </p> <p><mathjax>#"%m/m" = m_"sodium chloride"/m_"solution" * 100#</mathjax></p> <p><mathjax>#"%m/m" = (3.785cancel("g"))/(47.485cancel("g")) * 100 = color(green)("7.97%")#</mathjax></p> <p>Your sodium chloride solution is <strong>7.97% m/m</strong>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the percent by mass of a solution that is prepared by mixing 3.785 grams of sodium chloride with 43.7 milliliters of water (assume the density of water is 1.00 g/mL)? Thanks!?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/percent-concentration" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Concentration</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="156933" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-07-07T06:35:32" itemprop="dateCreated"> Jul 7, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The solution is <strong>7.97% m/m</strong>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to determine a solution's <a href="http://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration by mass</a>, you need to know the mass of the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a>, in your case sodium chloride, and the mass of the <strong>entire solution</strong>, which contains sodium chloride and water. </p> <p>Since you know what the <a href="http://socratic.org/chemistry/measurement-in-chemistry/density">density</a> of water is, you can use its volume to determine its mass. </p> <p><mathjax>#rho = m/V => m = rho * V#</mathjax></p> <p><mathjax>#43.7cancel("mL") * "1.00 g"/(1cancel("mL")) = "43.7 g"#</mathjax></p> <p>This means that the mass of the solution will be </p> <p><mathjax>#m_"solution" = m_"sodium chloride" + m_"water"#</mathjax></p> <p><mathjax>#m_"solution" = 3.785 + 43.7 = "47.485 g"#</mathjax></p> <p>Therefore, your solution's <a href="http://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration by mass</a> will be </p> <p><mathjax>#"%m/m" = m_"sodium chloride"/m_"solution" * 100#</mathjax></p> <p><mathjax>#"%m/m" = (3.785cancel("g"))/(47.485cancel("g")) * 100 = color(green)("7.97%")#</mathjax></p> <p>Your sodium chloride solution is <strong>7.97% m/m</strong>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/156933" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-concentration-of-water-in-solution-be-decreased"> How can the concentration of water in solution be decreased? 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</a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-percent-concentration-of-kcl-would-be-isotonic"> What percent concentration of KCl would be isotonic? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-of-sodium-chloride-in-normal-saline"> What is the percent concentration of sodium chloride in normal saline? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-of-a-6m-solution-of-nacl"> What is the percent concentration of a 6m solution of NaCl? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-formula"> What is the percent concentration formula? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/percent-concentration"> See all questions in Percent Concentration </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2117 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the percent by mass of a solution that is prepared by mixing 3.785 grams of sodium chloride with 43.7 milliliters of water (assume the density of water is 1.00 g/mL)? Thanks!?	null
2,420	acfb668a-6ddd-11ea-bd5c-ccda262736ce	https://socratic.org/questions/ammonia-is-produced-in-the-reaction-3h-2-n-2-2nh-3-what-mass-of-nh-3-could-be-pr	70.31 g	start physical_unit 12 12 mass g qc_end chemical_equation 6 12 qc_end physical_unit 7 7 21 22 mass qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Mass [OF] NH3 [IN] g"}]	[{"type":"physical unit","value":"70.31 g"}]	[{"type":"chemical equation","value":"3 H2 + N2 -> 2 NH3"},{"type":"physical unit","value":"Mass [OF] H2 [=] \\pu{12.5 g}"},{"type":"other","value":"Excess nitrogen."}]	<h1 class="questionTitle" itemprop="name">Ammonia is produced in the reaction #3H_2 + N_2 -> 2NH_3#. What mass of #NH_3# could be produced if 12.5 #H_2# reacts with excess nitrogen?</h1>	null	70.31 g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We ASSUME <mathjax>#(i)#</mathjax> <mathjax>#12.5g#</mathjax> dihydrogen gas, and <mathjax>#(ii)#</mathjax> QUANTITATIVE reaction with stoichiometric dinitrogen. (And the second assumption is a bit unwarranted).</p> <p><mathjax>#"Moles of dihydrogen"=(12.5g)/(2.016gmol^-1)=6.20mol#</mathjax>...and thus <mathjax>#2.07mol#</mathjax> of dinitrogen are required. We get <mathjax>#4.14mol#</mathjax> ammonia gas, a mass of <mathjax>#4.14molxx17.01gmol^-1=70.31*g#</mathjax>...</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We assess the reaction...<mathjax>#1/2N_2(g)+3/2H_2(g) rarr NH_3(g)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We ASSUME <mathjax>#(i)#</mathjax> <mathjax>#12.5g#</mathjax> dihydrogen gas, and <mathjax>#(ii)#</mathjax> QUANTITATIVE reaction with stoichiometric dinitrogen. (And the second assumption is a bit unwarranted).</p> <p><mathjax>#"Moles of dihydrogen"=(12.5g)/(2.016gmol^-1)=6.20mol#</mathjax>...and thus <mathjax>#2.07mol#</mathjax> of dinitrogen are required. We get <mathjax>#4.14mol#</mathjax> ammonia gas, a mass of <mathjax>#4.14molxx17.01gmol^-1=70.31*g#</mathjax>...</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Ammonia is produced in the reaction #3H_2 + N_2 -> 2NH_3#. What mass of #NH_3# could be produced if 12.5 #H_2# reacts with excess nitrogen?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/stoichiometry-involving-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="645934" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-08-06T14:45:21" itemprop="dateCreated"> Aug 6, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We assess the reaction...<mathjax>#1/2N_2(g)+3/2H_2(g) rarr NH_3(g)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We ASSUME <mathjax>#(i)#</mathjax> <mathjax>#12.5g#</mathjax> dihydrogen gas, and <mathjax>#(ii)#</mathjax> QUANTITATIVE reaction with stoichiometric dinitrogen. (And the second assumption is a bit unwarranted).</p> <p><mathjax>#"Moles of dihydrogen"=(12.5g)/(2.016gmol^-1)=6.20mol#</mathjax>...and thus <mathjax>#2.07mol#</mathjax> of dinitrogen are required. We get <mathjax>#4.14mol#</mathjax> ammonia gas, a mass of <mathjax>#4.14molxx17.01gmol^-1=70.31*g#</mathjax>...</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/645934" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-apply-gas-stoichiometry"> How do you apply gas stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-solve-a-gas-law-stoichiometry-problem"> How do you solve a gas law stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-do-gas-stoichiometry-problems-at-stp"> How do you do gas stoichiometry problems at STP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-an-agno3-solution-is-treated-with-50-0-ml-of-hi-gas-to-give-0-235-g-of-agi-"> When an AgNO3 solution is treated with 50.0 mL of HI gas to give 0.235 g of AgI, what is the... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-10-0-ml-of-agno3-solution-is-treated-with-excess-amount-of-hi-gas-to-give-0"> When 10.0 mL of AgNO3 solution is treated with excess amount of HI gas to give 0.235 g of AgI,... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/hydrogen-sulfide-reacts-with-sulfur-dioxide-to-give-h2o-and-s-h2s-so2-h2o-s-soli"> Hydrogen sulfide reacts with sulfur dioxide to give H2O and S, H2S + SO2 = H2O + S(solid),... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-100-ml-of-hcl-gas-at-300-k-and-200-kpa-dissolved-in-pure-water-requires-12-50"> If 100 mL of HCl gas at 300 K and 200 kPa dissolved in pure water requires 12.50 mL of the NaOH... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-100-ml-of-hcl-gas-at-300-k-and-100-kpa-dissolved-in-pure-water-requires-12-50"> If 100 mL of HCl gas at 300 K and 100 kPa dissolved in pure water requires 12.50 mL of the NaOH... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-100-ml-of-hcl-gas-at-300-k-and-100-kpa-dissolve-in-20-ml-of-pure-water-what-i"> If 100 mL of HCl gas at 300 K and 100 kPa dissolve in 20 mL of pure water, what is the concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-2-00-g-mixture-of-na-and-ca-reat-with-water-1-164-l-hydrogen-was-produced-a"> When 2.00 g mixture of Na and Ca reat with water, 1.164 L hydrogen was produced at 300.0 K and... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/stoichiometry-involving-gases"> See all questions in Gas Stoichiometry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1700 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Ammonia is produced in the reaction #3H_2 + N_2 -> 2NH_3#. What mass of #NH_3# could be produced if 12.5 #H_2# reacts with excess nitrogen?	null
2,421	aa39455f-6ddd-11ea-92ff-ccda262736ce	https://socratic.org/questions/how-many-moles-of-sodium-hydroxide-are-in-20-0-ml-of-a-0-50-m-naoh-solution	0.01 moles	start physical_unit 4 5 mole mol qc_end physical_unit 14 15 8 9 volume qc_end physical_unit 14 15 12 13 molarity qc_end end	[{"type":"physical unit","value":"Mole [OF] sodium hydroxide [IN] moles"}]	[{"type":"physical unit","value":"0.01 moles"}]	[{"type":"physical unit","value":"Volume [OF] NaOH solution [=] \\pu{20.0 mL}"},{"type":"physical unit","value":"Molarity [OF] NaOH solution [=] \\pu{0.50 M}"}]	<h1 class="questionTitle" itemprop="name">How many moles of sodium hydroxide are in 20.0 mL of a 0.50 M #NaOH# solution?</h1>	null	0.01 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Molarity is a measure of moles per Liter</p> <p><mathjax>#M = (mol)/L#</mathjax> or <mathjax>#ML =#</mathjax> moles</p> <p>M = 0.50 M<br/> L = 20.0 ml or 0.020L<br/> moles = ?</p> <p><mathjax>#0.50 M (0.020 L) =#</mathjax> moles</p> <p><mathjax>#0.01 =#</mathjax> moles of NaOH</p> <p> <iframe src="https://www.youtube.com/embed/loL46MQt1vQ?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#0.01 =#</mathjax> moles of NaOH</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Molarity is a measure of moles per Liter</p> <p><mathjax>#M = (mol)/L#</mathjax> or <mathjax>#ML =#</mathjax> moles</p> <p>M = 0.50 M<br/> L = 20.0 ml or 0.020L<br/> moles = ?</p> <p><mathjax>#0.50 M (0.020 L) =#</mathjax> moles</p> <p><mathjax>#0.01 =#</mathjax> moles of NaOH</p> <p> <iframe src="https://www.youtube.com/embed/loL46MQt1vQ?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles of sodium hydroxide are in 20.0 mL of a 0.50 M #NaOH# solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="265174" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/brian-m"><img alt="" class="" src="https://profilepictures.socratic.org/ZCpnJDgSFKORtvaSPDeG_Lego%20Me.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/brian-m"> BRIAN M. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-13T02:25:42" itemprop="dateCreated"> May 13, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#0.01 =#</mathjax> moles of NaOH</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Molarity is a measure of moles per Liter</p> <p><mathjax>#M = (mol)/L#</mathjax> or <mathjax>#ML =#</mathjax> moles</p> <p>M = 0.50 M<br/> L = 20.0 ml or 0.020L<br/> moles = ?</p> <p><mathjax>#0.50 M (0.020 L) =#</mathjax> moles</p> <p><mathjax>#0.01 =#</mathjax> moles of NaOH</p> <p> <iframe src="https://www.youtube.com/embed/loL46MQt1vQ?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/265174" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" 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2,422	acf2282f-6ddd-11ea-b24c-ccda262736ce	https://socratic.org/questions/565c6c6811ef6b44ca33ba4e	MnO4- + 5 Cu+ + 8 H+ -> Mn^2+ + 5 Cu^2+ + 4 H2O(l)	start chemical_equation qc_end chemical_equation 7 7 qc_end chemical_equation 9 9 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the oxidation"}]	[{"type":"chemical equation","value":"MnO4- + 5 Cu+ + 8 H+ -> Mn^2+ + 5 Cu^2+ + 4 H2O(l)"}]	[{"type":"chemical equation","value":"Cu+"},{"type":"chemical equation","value":"MnO4-"}]	<h1 class="questionTitle" itemprop="name">How do you represent the oxidation of #Cu^+# by #MnO_4^(-)#?</h1>	null	MnO4- + 5 Cu+ + 8 H+ -> Mn^2+ + 5 Cu^2+ + 4 H2O(l)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We can write the overall redox equation by adding <mathjax>#5#</mathjax> <mathjax>#xx#</mathjax> the oxidation equation to <mathjax>#1#</mathjax> of the reduction reaction to give:</p> <p><mathjax>#5Cu^+ + MnO_4^(-) + 8H^(+) rarr Mn^(2+) + 5Cu^(2+) + 4H_2O(l)#</mathjax></p> <p>This reaction is stoichiometrically balanced with respect to mass and charge, and it is self indicating. Why? Because permanganate ion, <mathjax>#MnO_4^-#</mathjax>, has a strong purple colour, whereas <mathjax>#Mn^(2+)#</mathjax> is almost colourless. The colour of the permanganate ion will persist at the endpoint. </p> <p>Concentration of cuprous ion: <mathjax>#(n_(Cu^+))/(2.49xx10^-2L)#</mathjax></p> <p>Moles of permanganate ion <mathjax>#=#</mathjax> <mathjax>#0.128molcancel(L)^(-1)xx3.19xx10^(-2)cancel(L)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#4.08xx10^(-3) mol#</mathjax>. Given the <a href="http://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> there were <mathjax>#5xx4.08xx10^(-3)mol#</mathjax> <mathjax>#=#</mathjax> <mathjax>#2.042xx10^(-2)#</mathjax> <mathjax>#mol#</mathjax> of cuprous ion.</p> <p>SO the concentration of the original solution was <mathjax>#(2.042xx10^(-2)mol)/(2.49xx10^-2L)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.820#</mathjax> <mathjax>#molL^(-1)#</mathjax> in <mathjax>#Cu^+#</mathjax> ion.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Cu^(+) rarr Cu^(2+) + e^-#</mathjax> OXIDATION<br/> <mathjax>#MnO_4^(-) + 8H^(+) + 5e^(-)rarr Mn^(2+) + 4H_2O#</mathjax> REDUCTION</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We can write the overall redox equation by adding <mathjax>#5#</mathjax> <mathjax>#xx#</mathjax> the oxidation equation to <mathjax>#1#</mathjax> of the reduction reaction to give:</p> <p><mathjax>#5Cu^+ + MnO_4^(-) + 8H^(+) rarr Mn^(2+) + 5Cu^(2+) + 4H_2O(l)#</mathjax></p> <p>This reaction is stoichiometrically balanced with respect to mass and charge, and it is self indicating. Why? Because permanganate ion, <mathjax>#MnO_4^-#</mathjax>, has a strong purple colour, whereas <mathjax>#Mn^(2+)#</mathjax> is almost colourless. The colour of the permanganate ion will persist at the endpoint. </p> <p>Concentration of cuprous ion: <mathjax>#(n_(Cu^+))/(2.49xx10^-2L)#</mathjax></p> <p>Moles of permanganate ion <mathjax>#=#</mathjax> <mathjax>#0.128molcancel(L)^(-1)xx3.19xx10^(-2)cancel(L)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#4.08xx10^(-3) mol#</mathjax>. Given the <a href="http://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> there were <mathjax>#5xx4.08xx10^(-3)mol#</mathjax> <mathjax>#=#</mathjax> <mathjax>#2.042xx10^(-2)#</mathjax> <mathjax>#mol#</mathjax> of cuprous ion.</p> <p>SO the concentration of the original solution was <mathjax>#(2.042xx10^(-2)mol)/(2.49xx10^-2L)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.820#</mathjax> <mathjax>#molL^(-1)#</mathjax> in <mathjax>#Cu^+#</mathjax> ion.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you represent the oxidation of #Cu^+# by #MnO_4^(-)#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="194735" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-30T16:22:13" itemprop="dateCreated"> Nov 30, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Cu^(+) rarr Cu^(2+) + e^-#</mathjax> OXIDATION<br/> <mathjax>#MnO_4^(-) + 8H^(+) + 5e^(-)rarr Mn^(2+) + 4H_2O#</mathjax> REDUCTION</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We can write the overall redox equation by adding <mathjax>#5#</mathjax> <mathjax>#xx#</mathjax> the oxidation equation to <mathjax>#1#</mathjax> of the reduction reaction to give:</p> <p><mathjax>#5Cu^+ + MnO_4^(-) + 8H^(+) rarr Mn^(2+) + 5Cu^(2+) + 4H_2O(l)#</mathjax></p> <p>This reaction is stoichiometrically balanced with respect to mass and charge, and it is self indicating. Why? Because permanganate ion, <mathjax>#MnO_4^-#</mathjax>, has a strong purple colour, whereas <mathjax>#Mn^(2+)#</mathjax> is almost colourless. The colour of the permanganate ion will persist at the endpoint. </p> <p>Concentration of cuprous ion: <mathjax>#(n_(Cu^+))/(2.49xx10^-2L)#</mathjax></p> <p>Moles of permanganate ion <mathjax>#=#</mathjax> <mathjax>#0.128molcancel(L)^(-1)xx3.19xx10^(-2)cancel(L)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#4.08xx10^(-3) mol#</mathjax>. Given the <a href="http://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> there were <mathjax>#5xx4.08xx10^(-3)mol#</mathjax> <mathjax>#=#</mathjax> <mathjax>#2.042xx10^(-2)#</mathjax> <mathjax>#mol#</mathjax> of cuprous ion.</p> <p>SO the concentration of the original solution was <mathjax>#(2.042xx10^(-2)mol)/(2.49xx10^-2L)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.820#</mathjax> <mathjax>#molL^(-1)#</mathjax> in <mathjax>#Cu^+#</mathjax> ion.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/194735" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-morality-be-used-as-a-conversion-factor"> How can molarity be used as a conversion factor? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-high-can-molarity-be"> How high can molarity be? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-molarity-change-with-temperature"> How does molarity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molarity-of-a-solution"> How do you find molarity of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-10-naoh"> What is the molarity of 10 NaOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-3-hydrogen-peroxide"> What is the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1305 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How do you represent the oxidation of #Cu^+# by #MnO_4^(-)#?	null
2,423	ad06239f-6ddd-11ea-819c-ccda262736ce	https://socratic.org/questions/what-is-the-ph-of-a-013-m-hcl-solution	1.89	start physical_unit 8 9 ph none qc_end physical_unit 8 9 6 7 molarity qc_end end	[{"type":"physical unit","value":"pH [OF] HCl solution"}]	[{"type":"physical unit","value":"1.89"}]	[{"type":"physical unit","value":"Molarity [OF] HCl solution [=] \\pu{0.013 M}"}]	<h1 class="questionTitle" itemprop="name">What is the pH of a .013 M #HCl# solution?</h1>	null	1.89	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Since HCl is a strong acid, it completely dissociates into its respective ions when placed in water. In this case HCl ionizes to produce <mathjax>#H^(+) (aq)#</mathjax> and <mathjax>#Cl^(-)(aq)#</mathjax>. </p> <p>As soon as we know that we're dealing with a strong acid, the <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> can be obtained directly from the concentration of <mathjax>#H^(+)#</mathjax> using the following formula:</p> <p><a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> = -log[<mathjax>#H^(+#</mathjax>]</p> <p>All we have to do is take the -log of the given concentration like so:</p> <p><mathjax>#pH = -log [0.013] #</mathjax></p> <p><mathjax>#pH = 1.89#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> of this solution is 1.89.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Since HCl is a strong acid, it completely dissociates into its respective ions when placed in water. In this case HCl ionizes to produce <mathjax>#H^(+) (aq)#</mathjax> and <mathjax>#Cl^(-)(aq)#</mathjax>. </p> <p>As soon as we know that we're dealing with a strong acid, the <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> can be obtained directly from the concentration of <mathjax>#H^(+)#</mathjax> using the following formula:</p> <p><a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> = -log[<mathjax>#H^(+#</mathjax>]</p> <p>All we have to do is take the -log of the given concentration like so:</p> <p><mathjax>#pH = -log [0.013] #</mathjax></p> <p><mathjax>#pH = 1.89#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the pH of a .013 M #HCl# solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="284102" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/kayla-14"><img alt="" class="" src="https://profilepictures.socratic.org/OvMTWaamQPWcqLIkUNnG_793604964071127.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/kayla-14"> Kayla </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-03T02:59:40" itemprop="dateCreated"> Jul 3, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> of this solution is 1.89.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Since HCl is a strong acid, it completely dissociates into its respective ions when placed in water. In this case HCl ionizes to produce <mathjax>#H^(+) (aq)#</mathjax> and <mathjax>#Cl^(-)(aq)#</mathjax>. </p> <p>As soon as we know that we're dealing with a strong acid, the <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> can be obtained directly from the concentration of <mathjax>#H^(+)#</mathjax> using the following formula:</p> <p><a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> = -log[<mathjax>#H^(+#</mathjax>]</p> <p>All we have to do is take the -log of the given concentration like so:</p> <p><mathjax>#pH = -log [0.013] #</mathjax></p> <p><mathjax>#pH = 1.89#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/284102" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-resonance-structures-affect-acidity"> How do resonance structures affect acidity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-carbon-dioxide-change-the-acid-base-condition-of-a-solution"> How does carbon dioxide change the acid-base condition of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-strong-acids-have-a-low-ph"> Why do strong acids have a low pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-neutralization-a-double-replacement-reaction"> Is neutralization a double replacement reaction? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-nah-a-strong-base"> Why is NaH a strong base? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-hbr-a-strong-acid"> Is HBr a strong acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-hf-a-strong-acid"> Is HF a strong acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-does-neutralization-occur"> Why does neutralization occur? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/do-strong-acids-completely-dissociate-in-water"> Do strong acids completely dissociate in water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-ph-of-weak-acid"> How can I calculate pH of weak acid? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/acids-and-bases"> See all questions in Acids and Bases </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 6675 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the pH of a .013 M #HCl# solution?	null
2,424	a8e0c250-6ddd-11ea-acb4-ccda262736ce	https://socratic.org/questions/a-tank-contains-115-moles-of-neon-gas-it-has-a-pressure-of-57-atm-at-a-temperatu	53 L	start physical_unit 28 29 volume l qc_end physical_unit 6 7 3 4 mole qc_end physical_unit 28 29 13 14 pressure qc_end physical_unit 28 29 19 20 temperature qc_end end	[{"type":"physical unit","value":"Volume [OF] the tank [IN] L"}]	[{"type":"physical unit","value":"53 L"}]	[{"type":"physical unit","value":"Mole [OF] neon gas [=] \\pu{115 moles}"},{"type":"physical unit","value":"Pressure [OF] the tank [=] \\pu{57 atm}"},{"type":"physical unit","value":"Temperature [OF] the tank [=] \\pu{45 ℃}"}]	<h1 class="questionTitle" itemprop="name">A tank contains 115 moles of neon gas. It has a pressure of 57 atm at a temperature of 45 C. How do you calculate the volume of the tank?</h1>	null	53 L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>We can use the <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a></strong> to calculate the volume.</p> <blockquote></blockquote> <p>The <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a> is:</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(\|color(white)(a/a)PV = nRTcolor(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>where </p> <ul> <li><mathjax>#P#</mathjax> is the pressure</li> <li><mathjax>#V#</mathjax> is the volume</li> <li><mathjax>#n#</mathjax> is the number of moles</li> <li><mathjax>#R#</mathjax> is the gas constant</li> <li><mathjax>#T#</mathjax> is the temperature</li> </ul> <blockquote></blockquote> <p>We can rearrange the Ideal Gas Law to get</p> <blockquote> <blockquote> <p><mathjax>#V = (nRT)/P#</mathjax></p> </blockquote> </blockquote> <p><mathjax>#n = "115 mol"#</mathjax><br/> <mathjax>#R = "0.082 06 L·atm·K"^"-1""mol"^"-1"#</mathjax><br/> <mathjax>#T = "(45 + 273.15) K" = "318.15 K"#</mathjax><br/> <mathjax>#P = "57 atm"#</mathjax></p> <blockquote></blockquote> <p><mathjax>#V = (nRT)/P = (115 color(red)(cancel(color(black)("mol"))) × "0.082 06 L"· color(red)(cancel(color(black)("atm·K"^"-1""mol"^"-1"))) × 318.15 color(red)(cancel(color(black)("K"))))/(57 color(red)(cancel(color(black)("atm")))) = "53 L"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The volume of the tank is 53 L.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>We can use the <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a></strong> to calculate the volume.</p> <blockquote></blockquote> <p>The <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a> is:</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(\|color(white)(a/a)PV = nRTcolor(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>where </p> <ul> <li><mathjax>#P#</mathjax> is the pressure</li> <li><mathjax>#V#</mathjax> is the volume</li> <li><mathjax>#n#</mathjax> is the number of moles</li> <li><mathjax>#R#</mathjax> is the gas constant</li> <li><mathjax>#T#</mathjax> is the temperature</li> </ul> <blockquote></blockquote> <p>We can rearrange the Ideal Gas Law to get</p> <blockquote> <blockquote> <p><mathjax>#V = (nRT)/P#</mathjax></p> </blockquote> </blockquote> <p><mathjax>#n = "115 mol"#</mathjax><br/> <mathjax>#R = "0.082 06 L·atm·K"^"-1""mol"^"-1"#</mathjax><br/> <mathjax>#T = "(45 + 273.15) K" = "318.15 K"#</mathjax><br/> <mathjax>#P = "57 atm"#</mathjax></p> <blockquote></blockquote> <p><mathjax>#V = (nRT)/P = (115 color(red)(cancel(color(black)("mol"))) × "0.082 06 L"· color(red)(cancel(color(black)("atm·K"^"-1""mol"^"-1"))) × 318.15 color(red)(cancel(color(black)("K"))))/(57 color(red)(cancel(color(black)("atm")))) = "53 L"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A tank contains 115 moles of neon gas. It has a pressure of 57 atm at a temperature of 45 C. How do you calculate the volume of the tank?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp" itemprop="url"> <span class="breadcrumb" itemprop="title">Molar Volume of a Gas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="338133" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-11-18T02:29:28" itemprop="dateCreated"> Nov 18, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The volume of the tank is 53 L.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>We can use the <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a></strong> to calculate the volume.</p> <blockquote></blockquote> <p>The <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a> is:</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(\|color(white)(a/a)PV = nRTcolor(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>where </p> <ul> <li><mathjax>#P#</mathjax> is the pressure</li> <li><mathjax>#V#</mathjax> is the volume</li> <li><mathjax>#n#</mathjax> is the number of moles</li> <li><mathjax>#R#</mathjax> is the gas constant</li> <li><mathjax>#T#</mathjax> is the temperature</li> </ul> <blockquote></blockquote> <p>We can rearrange the Ideal Gas Law to get</p> <blockquote> <blockquote> <p><mathjax>#V = (nRT)/P#</mathjax></p> </blockquote> </blockquote> <p><mathjax>#n = "115 mol"#</mathjax><br/> <mathjax>#R = "0.082 06 L·atm·K"^"-1""mol"^"-1"#</mathjax><br/> <mathjax>#T = "(45 + 273.15) K" = "318.15 K"#</mathjax><br/> <mathjax>#P = "57 atm"#</mathjax></p> <blockquote></blockquote> <p><mathjax>#V = (nRT)/P = (115 color(red)(cancel(color(black)("mol"))) × "0.082 06 L"· color(red)(cancel(color(black)("atm·K"^"-1""mol"^"-1"))) × 318.15 color(red)(cancel(color(black)("K"))))/(57 color(red)(cancel(color(black)("atm")))) = "53 L"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/338133" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-stoichiometric-ratios-relate-to-molar-volume-of-a-gas"> How do stoichiometric ratios relate to molar volume of a gas? 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It has a pressure of 57 atm at a temperature of 45 C. How do you calculate the volume of the tank?	null
2,425	aab476fe-6ddd-11ea-a9f6-ccda262736ce	https://socratic.org/questions/to-form-100-g-of-h-2o-2-5-927-g-of-h-must-react-with-94-073-g-of-o-how-many-gram	97.84 grams	start physical_unit 16 16 mass g qc_end physical_unit 5 5 2 3 mass qc_end physical_unit 9 9 6 7 mass qc_end physical_unit 16 16 13 14 mass qc_end physical_unit 5 5 27 28 mass qc_end end	[{"type":"physical unit","value":"Mass2 [OF] O [IN] grams"}]	[{"type":"physical unit","value":"97.84 grams"}]	[{"type":"physical unit","value":"Mass1 [OF] H2O2 [=] \\pu{100 g}"},{"type":"physical unit","value":"Mass1 [OF] H [=] \\pu{5.927 g}"},{"type":"physical unit","value":"Mass1 [OF] O [=] \\pu{94.073 g}"},{"type":"physical unit","value":"Mass2 [OF] H2O2 [=] \\pu{104 g}"}]	<h1 class="questionTitle" itemprop="name">To form 100 g of #H_2O_2#, 5.927 g of H must react with 94.073 g of O. How many grams of O would be needed to form 104 g of #H_2O_2#?</h1>	null	97.84 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And I make this....</p> <p><mathjax>#5.927%xx104g=6.164g#</mathjax></p> <p>And let us just check this...and examine the empirical formula of the <mathjax>#104g#</mathjax> mass...and for this we divide thru by the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">ATOMIC mass</a> of each constituent element...</p> <p><mathjax>#"Moles of hydrogen"=(6.164g)/(1.00794gmol^-1)=6.116mol#</mathjax></p> <p><mathjax>#"Moles of oxygen"=(104g-6.164g)/(16.00gmol^-1)=6.116mol#</mathjax></p> <p>And thus the empirical formula is simply <mathjax>#HO#</mathjax>...why is this different from the chemical formula of hydrogen peroxide?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, what is <mathjax>#5.927%#</mathjax> of <mathjax>#104g#</mathjax>?</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And I make this....</p> <p><mathjax>#5.927%xx104g=6.164g#</mathjax></p> <p>And let us just check this...and examine the empirical formula of the <mathjax>#104g#</mathjax> mass...and for this we divide thru by the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">ATOMIC mass</a> of each constituent element...</p> <p><mathjax>#"Moles of hydrogen"=(6.164g)/(1.00794gmol^-1)=6.116mol#</mathjax></p> <p><mathjax>#"Moles of oxygen"=(104g-6.164g)/(16.00gmol^-1)=6.116*mol#</mathjax></p> <p>And thus the empirical formula is simply <mathjax>#HO#</mathjax>...why is this different from the chemical formula of hydrogen peroxide?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">To form 100 g of #H_2O_2#, 5.927 g of H must react with 94.073 g of O. How many grams of O would be needed to form 104 g of #H_2O_2#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-reactions-and-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions and Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="630043" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-06-14T07:29:42" itemprop="dateCreated"> Jun 14, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, what is <mathjax>#5.927%#</mathjax> of <mathjax>#104g#</mathjax>?</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And I make this....</p> <p><mathjax>#5.927%xx104g=6.164g#</mathjax></p> <p>And let us just check this...and examine the empirical formula of the <mathjax>#104g#</mathjax> mass...and for this we divide thru by the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">ATOMIC mass</a> of each constituent element...</p> <p><mathjax>#"Moles of hydrogen"=(6.164g)/(1.00794gmol^-1)=6.116mol#</mathjax></p> <p><mathjax>#"Moles of oxygen"=(104g-6.164g)/(16.00gmol^-1)=6.116*mol#</mathjax></p> <p>And thus the empirical formula is simply <mathjax>#HO#</mathjax>...why is this different from the chemical formula of hydrogen peroxide?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/630043" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb002bf34694a4fee47"> Question #fee47 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb402bf34694c8c5c15"> Question #c5c15 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb802bf346950519eb9"> Question #19eb9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cbf02bf3469570e2ea2"> Question #e2ea2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc002bf34695a6bc751"> Question #bc751 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc202bf3469570e2ea6"> Question #e2ea6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531e867a02bf342492a08b07"> Question #08b07 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-thermochemical-equation-for-the-combustion-of-benzene"> What is the thermochemical equation for the combustion of benzene? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-reversible"> Why are chemical reactions reversible? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-important"> Why are chemical reactions important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/chemical-reactions-and-equations"> See all questions in Chemical Reactions and Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1007 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	To form 100 g of #H_2O_2#, 5.927 g of H must react with 94.073 g of O. How many grams of O would be needed to form 104 g of #H_2O_2#?	null
2,426	acc9ae9e-6ddd-11ea-9b3a-ccda262736ce	https://socratic.org/questions/58ed6fbf7c01492de7aca88f	2 C2H6 + 7 O2 -> 4 CO2 + 6 H2O	start chemical_equation qc_end chemical_equation 10 10 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the complete combustion"}]	[{"type":"chemical equation","value":"2 C2H6 + 7 O2 -> 4 CO2 + 6 H2O"}]	[{"type":"chemical equation","value":"C2H6"}]	<h1 class="questionTitle" itemprop="name">What is the balanced equation for the complete combustion of #"C"_2"H"_6"#?</h1>	null	2 C2H6 + 7 O2 -> 4 CO2 + 6 H2O	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>General rules for balancing combustion equations: </p> <ol> <li>Balance the carbons: If the alkane has an even number of carbon atoms, place a coefficient of 2 in front of its formula, then balance the carbons.</li> <li>Balance the hydrogens.</li> <li>Balance the oxygens.</li> </ol> <p><strong>Balance the carbons.</strong> Since the formula for the alkane <mathjax>#"C"_2"H"_6"#</mathjax> has an even number of carbon atoms, place a coefficient of <mathjax>#2#</mathjax> in front of its formula first. Next place a <mathjax>#4#</mathjax> in front of the <mathjax>#"CO"_2"#</mathjax>.</p> <p><mathjax>#color(red)("2")"C"_2"H"_6 + "O"_2#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(red)("4")"CO"_2 + "H"_2"O"#</mathjax></p> <p><strong>Balance the hydrogens.</strong> <br/> Place a <mathjax>#6#</mathjax> in front of the <mathjax>#"H"_2"O"#</mathjax>.</p> <p><mathjax>#"2C"_2"H"_6 + "O"_2#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"4CO"_2 + color(red)("6")"H"_2"O"#</mathjax></p> <p><strong>Balance the oxygens.</strong><br/> Place a <mathjax>#7#</mathjax> in front of the <mathjax>#"O"_2"#</mathjax>.</p> <p><mathjax>#"2C"_2"H"_6 + color(red)("7")"O"_2#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"4CO"_2 + "6H"_2"O"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Balanced Equation:</p> <p><mathjax>#"2C"_2"H"_6 + "7O"_2#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"4CO"_2 + "6H"_2"O"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>General rules for balancing combustion equations: </p> <ol> <li>Balance the carbons: If the alkane has an even number of carbon atoms, place a coefficient of 2 in front of its formula, then balance the carbons.</li> <li>Balance the hydrogens.</li> <li>Balance the oxygens.</li> </ol> <p><strong>Balance the carbons.</strong> Since the formula for the alkane <mathjax>#"C"_2"H"_6"#</mathjax> has an even number of carbon atoms, place a coefficient of <mathjax>#2#</mathjax> in front of its formula first. Next place a <mathjax>#4#</mathjax> in front of the <mathjax>#"CO"_2"#</mathjax>.</p> <p><mathjax>#color(red)("2")"C"_2"H"_6 + "O"_2#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(red)("4")"CO"_2 + "H"_2"O"#</mathjax></p> <p><strong>Balance the hydrogens.</strong> <br/> Place a <mathjax>#6#</mathjax> in front of the <mathjax>#"H"_2"O"#</mathjax>.</p> <p><mathjax>#"2C"_2"H"_6 + "O"_2#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"4CO"_2 + color(red)("6")"H"_2"O"#</mathjax></p> <p><strong>Balance the oxygens.</strong><br/> Place a <mathjax>#7#</mathjax> in front of the <mathjax>#"O"_2"#</mathjax>.</p> <p><mathjax>#"2C"_2"H"_6 + color(red)("7")"O"_2#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"4CO"_2 + "6H"_2"O"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the balanced equation for the complete combustion of #"C"_2"H"_6"#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="405427" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-12T00:53:29" itemprop="dateCreated"> Apr 12, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Balanced Equation:</p> <p><mathjax>#"2C"_2"H"_6 + "7O"_2#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"4CO"_2 + "6H"_2"O"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>General rules for balancing combustion equations: </p> <ol> <li>Balance the carbons: If the alkane has an even number of carbon atoms, place a coefficient of 2 in front of its formula, then balance the carbons.</li> <li>Balance the hydrogens.</li> <li>Balance the oxygens.</li> </ol> <p><strong>Balance the carbons.</strong> Since the formula for the alkane <mathjax>#"C"_2"H"_6"#</mathjax> has an even number of carbon atoms, place a coefficient of <mathjax>#2#</mathjax> in front of its formula first. Next place a <mathjax>#4#</mathjax> in front of the <mathjax>#"CO"_2"#</mathjax>.</p> <p><mathjax>#color(red)("2")"C"_2"H"_6 + "O"_2#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(red)("4")"CO"_2 + "H"_2"O"#</mathjax></p> <p><strong>Balance the hydrogens.</strong> <br/> Place a <mathjax>#6#</mathjax> in front of the <mathjax>#"H"_2"O"#</mathjax>.</p> <p><mathjax>#"2C"_2"H"_6 + "O"_2#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"4CO"_2 + color(red)("6")"H"_2"O"#</mathjax></p> <p><strong>Balance the oxygens.</strong><br/> Place a <mathjax>#7#</mathjax> in front of the <mathjax>#"O"_2"#</mathjax>.</p> <p><mathjax>#"2C"_2"H"_6 + color(red)("7")"O"_2#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"4CO"_2 + "6H"_2"O"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/405427" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------> H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -> Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? 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2,427	abf33a4a-6ddd-11ea-ab2d-ccda262736ce	https://socratic.org/questions/what-is-the-number-of-electrons-in-an-al-3-ion	10	start physical_unit 5 5 number none qc_end chemical_equation 8 8 qc_end end	[{"type":"physical unit","value":"Number [OF] electrons"}]	[{"type":"physical unit","value":"10"}]	[{"type":"chemical equation","value":"Al^3+"}]	<h1 class="questionTitle" itemprop="name">What is the number of electrons in an #Al^(3+)# ion?</h1>	null	10	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Clearly, there are 10 electrons associated with a single <mathjax>#Al^(3+)#</mathjax> ion. We don't need any chemistry to make this determination.</p> <p>The atomic number specifies the number of positively charged particles in the atomic nucleus. The aluminum nucleus contains 13 protons, 13 fundamental, positively charged particles; this is what identifies the nucleus as aluminum. To balance this charge (all matter is neutral after all), there must be also be 13 fundamental negatively charged particles associated with the aluminum nucleus, and what do we call these?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/atomic-number">atomic number</a>, <mathjax>#Z#</mathjax>, of aluminum metal is <mathjax>#13#</mathjax>. What is <mathjax>#13-3#</mathjax>?</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Clearly, there are 10 electrons associated with a single <mathjax>#Al^(3+)#</mathjax> ion. We don't need any chemistry to make this determination.</p> <p>The atomic number specifies the number of positively charged particles in the atomic nucleus. The aluminum nucleus contains 13 protons, 13 fundamental, positively charged particles; this is what identifies the nucleus as aluminum. To balance this charge (all matter is neutral after all), there must be also be 13 fundamental negatively charged particles associated with the aluminum nucleus, and what do we call these?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the number of electrons in an #Al^(3+)# ion?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#ionic-bonds-and-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Ionic Bonds</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/ionic-bonds-and-formulas/ionic-compounds" itemprop="url"> <span class="breadcrumb" itemprop="title">Ionic Compounds</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="216719" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-25T07:04:10" itemprop="dateCreated"> Jan 25, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/atomic-number">atomic number</a>, <mathjax>#Z#</mathjax>, of aluminum metal is <mathjax>#13#</mathjax>. What is <mathjax>#13-3#</mathjax>?</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Clearly, there are 10 electrons associated with a single <mathjax>#Al^(3+)#</mathjax> ion. We don't need any chemistry to make this determination.</p> <p>The atomic number specifies the number of positively charged particles in the atomic nucleus. The aluminum nucleus contains 13 protons, 13 fundamental, positively charged particles; this is what identifies the nucleus as aluminum. To balance this charge (all matter is neutral after all), there must be also be 13 fundamental negatively charged particles associated with the aluminum nucleus, and what do we call these?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/216719" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52f1151302bf34732c779c2f"> Question #79c2f </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52f1151302bf3473360cd842"> Question #cd842 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52f1151702bf34733dc14e7e"> Why do ionic compounds dissolve in water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52f1151b02bf3473394975aa"> Question #975aa </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52f1151b02bf3473394975ae"> Question #975ae </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52f1151e02bf34733e367e72"> Question #67e72 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/532eff8902bf341e776bd809"> What do the terms anhydrous, hydrous, and undissociated mean? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-ionic-compounds"> What are ionic compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-identify-ionic-compounds"> How can I identify ionic compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-ionic-compounds-solid-at-a-room-temperature"> Why are ionic compounds solid at room temperature? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/ionic-bonds-and-formulas/ionic-compounds"> See all questions in Ionic Compounds </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 41076 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the number of electrons in an #Al^(3+)# ion?	null
2,428	acfbac9c-6ddd-11ea-a649-ccda262736ce	https://socratic.org/questions/how-much-heat-must-be-removed-to-freeze-a-tray-of-ice-cubes-at-0-c-if-the-water--1	75.20 kJ	start physical_unit 11 12 heat_energy kj qc_end physical_unit 11 12 14 15 temperature qc_end physical_unit 18 18 23 24 mass qc_end end	[{"type":"physical unit","value":"Removed heat [OF] ice cubes [IN] kJ"}]	[{"type":"physical unit","value":"75.20 kJ"}]	[{"type":"physical unit","value":"Temperature [OF] ice cubes [=] \\pu{0 ℃}"},{"type":"physical unit","value":"Mass [OF] water [=] \\pu{225 g}"}]	<h1 class="questionTitle" itemprop="name">How much heat must be removed to freeze a tray of ice cubes at 0°C if the water has a mass of 225 g?</h1>	null	75.20 kJ	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>Use the heat of fusion equation:</strong></p> <p><mathjax>#q=m*H_"f"#</mathjax>,</p> <p>where:</p> <p><mathjax>#q#</mathjax> is the amount of energy, <mathjax>#m#</mathjax> is mass in grams, and <mathjax>#H_"f"#</mathjax> is the heat of fusion.</p> <p><strong>Known</strong></p> <p><mathjax>#"mass", m="225 g"#</mathjax></p> <p><mathjax>#"heat of fusion of water", H_"f"="334 J/g"#</mathjax></p> <p><strong>Unknown</strong></p> <p><mathjax>#"energy removed", q"#</mathjax></p> <p><strong>Solution</strong></p> <p>Plug in the known values and solve.</p> <p><mathjax>#q=225color(red)cancel(color(black)("g"))xx(334"J")/(1color(red)cancel(color(black)("g")))="75200 J"#</mathjax> rounded to three <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>It will require the removal of <mathjax>#"75200 J"#</mathjax> of energy.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>Use the heat of fusion equation:</strong></p> <p><mathjax>#q=m*H_"f"#</mathjax>,</p> <p>where:</p> <p><mathjax>#q#</mathjax> is the amount of energy, <mathjax>#m#</mathjax> is mass in grams, and <mathjax>#H_"f"#</mathjax> is the heat of fusion.</p> <p><strong>Known</strong></p> <p><mathjax>#"mass", m="225 g"#</mathjax></p> <p><mathjax>#"heat of fusion of water", H_"f"="334 J/g"#</mathjax></p> <p><strong>Unknown</strong></p> <p><mathjax>#"energy removed", q"#</mathjax></p> <p><strong>Solution</strong></p> <p>Plug in the known values and solve.</p> <p><mathjax>#q=225color(red)cancel(color(black)("g"))xx(334"J")/(1color(red)cancel(color(black)("g")))="75200 J"#</mathjax> rounded to three <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How much heat must be removed to freeze a tray of ice cubes at 0°C if the water has a mass of 225 g?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/energy-change-in-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Energy Change in Reactions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="641061" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-07-16T03:07:08" itemprop="dateCreated"> Jul 16, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>It will require the removal of <mathjax>#"75200 J"#</mathjax> of energy.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>Use the heat of fusion equation:</strong></p> <p><mathjax>#q=m*H_"f"#</mathjax>,</p> <p>where:</p> <p><mathjax>#q#</mathjax> is the amount of energy, <mathjax>#m#</mathjax> is mass in grams, and <mathjax>#H_"f"#</mathjax> is the heat of fusion.</p> <p><strong>Known</strong></p> <p><mathjax>#"mass", m="225 g"#</mathjax></p> <p><mathjax>#"heat of fusion of water", H_"f"="334 J/g"#</mathjax></p> <p><strong>Unknown</strong></p> <p><mathjax>#"energy removed", q"#</mathjax></p> <p><strong>Solution</strong></p> <p>Plug in the known values and solve.</p> <p><mathjax>#q=225color(red)cancel(color(black)("g"))xx(334"J")/(1color(red)cancel(color(black)("g")))="75200 J"#</mathjax> rounded to three <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/641061" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-endothermic-reactions-happen"> Why do endothermic reactions happen? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-causes-energy-changes-in-chemical-reactions"> What causes energy changes in chemical reactions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-endothermic-reactions-absorb-heat"> How do endothermic reactions absorb heat? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" 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What is the change in... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/energy-change-in-reactions"> See all questions in Energy Change in Reactions </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3106 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How much heat must be removed to freeze a tray of ice cubes at 0°C if the water has a mass of 225 g?	null
2,429	abcb10e9-6ddd-11ea-b86e-ccda262736ce	https://socratic.org/questions/five-gases-combined-in-a-gas-cylinder-have-the-following-partial-pressures-3-00-	5.37 atm	start physical_unit 37 38 total_pressure atm qc_end physical_unit 14 14 12 13 partial_pressure qc_end physical_unit 17 17 15 16 partial_pressure qc_end physical_unit 20 20 18 19 partial_pressure qc_end physical_unit 23 23 21 22 partial_pressure qc_end physical_unit 27 27 25 26 partial_pressure qc_end end	[{"type":"physical unit","value":"Total pressure [OF] the gases [IN] atm"}]	[{"type":"physical unit","value":"5.37 atm"}]	[{"type":"physical unit","value":"Partial pressure [OF] N2 [=] \\pu{3.00 atm}"},{"type":"physical unit","value":"Partial pressure [OF] O2 [=] \\pu{1.80 atm}"},{"type":"physical unit","value":"Partial pressure [OF] Ar [=] \\pu{0.29 atm}"},{"type":"physical unit","value":"Partial pressure [OF] He [=] \\pu{0.18 atm}"},{"type":"physical unit","value":"Partial pressure [OF] H2 [=] \\pu{0.10 atm}"}]	<h1 class="questionTitle" itemprop="name">Five gases combined in a gas cylinder have the following partial pressures 3.00 atm (#N_2#), 1.80 atm (#O_2), 0.29 atm (Ar), 0.18 atm (He), and 0.10 atm (H). What is the total pressure that is exerted by the gases? </h1>	null	5.37 atm	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Old <mathjax>#"Dalton's Law of Partial Pressures"#</mathjax> states that in a gaseous mixture, the <a href="https://socratic.org/chemistry/the-behavior-of-gases/partial-pressure">partial pressure</a> exerted by a component gas is the same as it would have exerted if it alone occupied the container. The total pressure is the sum of the individual partial pressures.</p> <p>For your problem, we have 5 component gases that are not expected to react with each other........</p> <p><mathjax>#P_"Total"=P_(N_2)+P_(O_2)+P_(Ar)+P_(He)+P_(H_2)#</mathjax> (NB as written the problem says atomic hydrogen, which I don't think you got!).</p> <p>And so............</p> <p><mathjax>#P_"Total"={3.00+1.80+0.29+0.18+0.10}atm#</mathjax></p> <p>Note also that given the <a href="https://socratic.org/chemistry/the-behavior-of-gases/gas-laws">gas laws</a>, the partial pressures may be used to find <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> fraction of each component:</p> <p><mathjax>#"Mole fraction,"#</mathjax> <mathjax>#"N_2=(3.00atm)/({3.00+1.80+0.29+0.18+0.10}*atm)#</mathjax></p> <p><mathjax>#=0.55#</mathjax> etc. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#P_"Total"~=5.4atm#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Old <mathjax>#"Dalton's Law of Partial Pressures"#</mathjax> states that in a gaseous mixture, the <a href="https://socratic.org/chemistry/the-behavior-of-gases/partial-pressure">partial pressure</a> exerted by a component gas is the same as it would have exerted if it alone occupied the container. The total pressure is the sum of the individual partial pressures.</p> <p>For your problem, we have 5 component gases that are not expected to react with each other........</p> <p><mathjax>#P_"Total"=P_(N_2)+P_(O_2)+P_(Ar)+P_(He)+P_(H_2)#</mathjax> (NB as written the problem says atomic hydrogen, which I don't think you got!).</p> <p>And so............</p> <p><mathjax>#P_"Total"={3.00+1.80+0.29+0.18+0.10}atm#</mathjax></p> <p>Note also that given the <a href="https://socratic.org/chemistry/the-behavior-of-gases/gas-laws">gas laws</a>, the partial pressures may be used to find <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> fraction of each component:</p> <p><mathjax>#"Mole fraction,"#</mathjax> <mathjax>#"N_2=(3.00atm)/({3.00+1.80+0.29+0.18+0.10}atm)#</mathjax></p> <p><mathjax>#=0.55#</mathjax> etc. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Five gases combined in a gas cylinder have the following partial pressures 3.00 atm (#N_2#), 1.80 atm (#O_2), 0.29 atm (Ar), 0.18 atm (He), and 0.10 atm (H). What is the total pressure that is exerted by the gases? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/gas-pressure" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Pressure</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="437368" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-10T05:50:53" itemprop="dateCreated"> Jun 10, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#P_"Total"~=5.4atm#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Old <mathjax>#"Dalton's Law of Partial Pressures"#</mathjax> states that in a gaseous mixture, the <a href="https://socratic.org/chemistry/the-behavior-of-gases/partial-pressure">partial pressure</a> exerted by a component gas is the same as it would have exerted if it alone occupied the container. The total pressure is the sum of the individual partial pressures.</p> <p>For your problem, we have 5 component gases that are not expected to react with each other........</p> <p><mathjax>#P_"Total"=P_(N_2)+P_(O_2)+P_(Ar)+P_(He)+P_(H_2)#</mathjax> (NB as written the problem says atomic hydrogen, which I don't think you got!).</p> <p>And so............</p> <p><mathjax>#P_"Total"={3.00+1.80+0.29+0.18+0.10}atm#</mathjax></p> <p>Note also that given the <a href="https://socratic.org/chemistry/the-behavior-of-gases/gas-laws">gas laws</a>, the partial pressures may be used to find <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> fraction of each component:</p> <p><mathjax>#"Mole fraction,"#</mathjax> <mathjax>#"N_2=(3.00atm)/({3.00+1.80+0.29+0.18+0.10}atm)#</mathjax></p> <p><mathjax>#=0.55#</mathjax> etc. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/437368" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-gas-pressure-be-changed"> How can gas pressure be changed? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-you-increase-gas-pressure-in-a-container"> How can you increase gas pressure in a container? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-gas-pressure-created"> How is gas pressure created? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-does-gas-pressure-increase-when-temperature-increases"> Why does gas pressure increase when temperature increases? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-gas-pressure-zero-at-absolute-zero"> Why is gas pressure zero at absolute zero? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-does-gas-pressure-increase-with-temperature"> Why does gas pressure increase with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-there-no-gas-pressure-in-a-vacuum"> Why is there no gas pressure in a vacuum? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-total-gas-pressure-in-a-sealed-flask-that-contains-oxygen-at-a-parti-1"> What is the total gas pressure in a sealed flask that contains oxygen at a partial pressure of... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-the-absolute-pressure-of-a-gas-is-550-280-kpa-what-is-its-gage-pressure"> If the absolute pressure of a gas is 550.280 kPa, what is its gage pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-a-gas-sample-occupies-4-2-l-at-a-pressure-of-101-kpa-what-volume-will-it-occu"> If a gas sample occupies 4.2 L at a pressure of 101 kPa. What volume will it occupy if the... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/gas-pressure"> See all questions in Gas Pressure </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 6404 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Five gases combined in a gas cylinder have the following partial pressures 3.00 atm (#N_2#), 1.80 atm (#O_2), 0.29 atm (Ar), 0.18 atm (He), and 0.10 atm (H). What is the total pressure that is exerted by the gases?	null
2,430	ac2464b6-6ddd-11ea-b138-ccda262736ce	https://socratic.org/questions/a-0-10-m-nh3-solution-has-a-degree-of-dissociation-1-3-at-temperature-t-calculat	1.7 × 10^(-5)	start physical_unit 3 3 kb none qc_end physical_unit 3 4 1 2 molarity qc_end physical_unit 3 4 10 10 degree_of_dissociation qc_end end	[{"type":"physical unit","value":"Kb [OF] NH3"}]	[{"type":"physical unit","value":"1.7 × 10^(-5)"}]	[{"type":"physical unit","value":"Molarity [OF] NH3 solution [=] \\pu{0.10 M}"},{"type":"physical unit","value":"Degree of dissociation [OF] NH3 solution [=] \\pu{1.3%}"}]	<h1 class="questionTitle" itemprop="name">A 0.10 M NH3 solution has a degree of dissociation 1.3% at temperature T. Calculate Kb for NH3 at this temperature?</h1>	null	1.7 × 10^(-5)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to solve this problem, you need to know two things</p> <ul> <li><em>the balanced chemical equation for the dissociation of ammonia in aqueous solution</em></li> <li><em>the equilibrium concentrations of the three chemical species that are of interest for this reaction</em></li> </ul> <p>As you know, ammonia, <mathjax>#"NH"_3#</mathjax>, is a <strong>weak base</strong>, which means that it <strong>does not</strong> dissociate completely in aqueous solution to form <em>ammonium ions</em>, <mathjax>#"NH"_4^(+)#</mathjax>, its <a href="http://socratic.org/chemistry/acids-and-bases/conjugate-acids-and-conjugate-bases">conjugate acid</a>, and <em>hydroxide anions</em>, <mathjax>#"OH"^(-)#</mathjax>. </p> <p>Instead, only a fraction of the number of molecules of ammonia will actually dissociate. That fraction depends on ammonia's <em>base dissociation constant</em> , <mathjax>#K_b#</mathjax>. </p> <p>You are told that your ammonia solution has a <strong>degree of dissociation</strong> of <mathjax>#1.3%#</mathjax> at a given temperature <mathjax>#T#</mathjax>. What that means is that <strong>for every</strong> <mathjax>#100#</mathjax> molecules of ammonia present in solution, only <mathjax>#1.3#</mathjax> will dissociate. </p> <p>Alternatively, you can think about it like this - for every <mathjax>#1000#</mathjax> molecules of ammonia, only <mathjax>#13#</mathjax> will ionize to form the aforementioned ions. The rest will remain as molecules of ammonia. </p> <p>The balanced chemical equation for this reaction looks like this</p> <blockquote> <p><mathjax>#"NH"_text(3(aq]) + "H"_2"O"_text((l]) rightleftharpoons "NH"_text(4(aq])^(+) + "OH"_text((aq])^(-)#</mathjax></p> </blockquote> <p>BY definition, the base dissociation constant will be equal to </p> <blockquote> <p><mathjax>#K_b = (["NH"_4^(+)] * ["OH"^(-)])/(["NH"_3])#</mathjax></p> </blockquote> <p>You know that</p> <blockquote> <p><mathjax>#["NH"_3] = "0.10 M"#</mathjax></p> </blockquote> <p>Now, use the degree of dissociation to find the concentrations of the two ions. You have <mathjax>#1:1#</mathjax> <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratios</a> between all chemical species, so you can say that</p> <blockquote> <p><mathjax>#["NH"_4^(+)] = ["OH"^(-)] = 1.3/100 * ["NH"_3]#</mathjax></p> <p><mathjax>#["NH"_4^(+)] = ["OH"^(-)] = 1.3 * 10^(-2) * "0.10 M" = 1.3 * 10^(-3)"M"#</mathjax></p> </blockquote> <p>This means that you get</p> <blockquote> <p><mathjax>#K_b = (1.3 * 10^(-3) * 1.3 * 10^(-3))/0.10 = color(green)(1.7 * 10^(-5))#</mathjax></p> </blockquote> <p>The answer is rounded to two <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the number of sig figs you have for the initial concentration of ammonia. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#K_b = 1.7 * 10^(-5)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to solve this problem, you need to know two things</p> <ul> <li><em>the balanced chemical equation for the dissociation of ammonia in aqueous solution</em></li> <li><em>the equilibrium concentrations of the three chemical species that are of interest for this reaction</em></li> </ul> <p>As you know, ammonia, <mathjax>#"NH"_3#</mathjax>, is a <strong>weak base</strong>, which means that it <strong>does not</strong> dissociate completely in aqueous solution to form <em>ammonium ions</em>, <mathjax>#"NH"_4^(+)#</mathjax>, its <a href="http://socratic.org/chemistry/acids-and-bases/conjugate-acids-and-conjugate-bases">conjugate acid</a>, and <em>hydroxide anions</em>, <mathjax>#"OH"^(-)#</mathjax>. </p> <p>Instead, only a fraction of the number of molecules of ammonia will actually dissociate. That fraction depends on ammonia's <em>base dissociation constant</em> , <mathjax>#K_b#</mathjax>. </p> <p>You are told that your ammonia solution has a <strong>degree of dissociation</strong> of <mathjax>#1.3%#</mathjax> at a given temperature <mathjax>#T#</mathjax>. What that means is that <strong>for every</strong> <mathjax>#100#</mathjax> molecules of ammonia present in solution, only <mathjax>#1.3#</mathjax> will dissociate. </p> <p>Alternatively, you can think about it like this - for every <mathjax>#1000#</mathjax> molecules of ammonia, only <mathjax>#13#</mathjax> will ionize to form the aforementioned ions. The rest will remain as molecules of ammonia. </p> <p>The balanced chemical equation for this reaction looks like this</p> <blockquote> <p><mathjax>#"NH"_text(3(aq]) + "H"_2"O"_text((l]) rightleftharpoons "NH"_text(4(aq])^(+) + "OH"_text((aq])^(-)#</mathjax></p> </blockquote> <p>BY definition, the base dissociation constant will be equal to </p> <blockquote> <p><mathjax>#K_b = (["NH"_4^(+)] * ["OH"^(-)])/(["NH"_3])#</mathjax></p> </blockquote> <p>You know that</p> <blockquote> <p><mathjax>#["NH"_3] = "0.10 M"#</mathjax></p> </blockquote> <p>Now, use the degree of dissociation to find the concentrations of the two ions. You have <mathjax>#1:1#</mathjax> <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratios</a> between all chemical species, so you can say that</p> <blockquote> <p><mathjax>#["NH"_4^(+)] = ["OH"^(-)] = 1.3/100 * ["NH"_3]#</mathjax></p> <p><mathjax>#["NH"_4^(+)] = ["OH"^(-)] = 1.3 * 10^(-2) * "0.10 M" = 1.3 * 10^(-3)"M"#</mathjax></p> </blockquote> <p>This means that you get</p> <blockquote> <p><mathjax>#K_b = (1.3 * 10^(-3) * 1.3 * 10^(-3))/0.10 = color(green)(1.7 * 10^(-5))#</mathjax></p> </blockquote> <p>The answer is rounded to two <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the number of sig figs you have for the initial concentration of ammonia. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A 0.10 M NH3 solution has a degree of dissociation 1.3% at temperature T. Calculate Kb for NH3 at this temperature?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-equilibrium" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Equilibrium</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-equilibrium/equilibrium-constants" itemprop="url"> <span class="breadcrumb" itemprop="title">Equilibrium Constants</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="202132" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-22T11:24:23" itemprop="dateCreated"> Dec 22, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#K_b = 1.7 * 10^(-5)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to solve this problem, you need to know two things</p> <ul> <li><em>the balanced chemical equation for the dissociation of ammonia in aqueous solution</em></li> <li><em>the equilibrium concentrations of the three chemical species that are of interest for this reaction</em></li> </ul> <p>As you know, ammonia, <mathjax>#"NH"_3#</mathjax>, is a <strong>weak base</strong>, which means that it <strong>does not</strong> dissociate completely in aqueous solution to form <em>ammonium ions</em>, <mathjax>#"NH"_4^(+)#</mathjax>, its <a href="http://socratic.org/chemistry/acids-and-bases/conjugate-acids-and-conjugate-bases">conjugate acid</a>, and <em>hydroxide anions</em>, <mathjax>#"OH"^(-)#</mathjax>. </p> <p>Instead, only a fraction of the number of molecules of ammonia will actually dissociate. That fraction depends on ammonia's <em>base dissociation constant</em> , <mathjax>#K_b#</mathjax>. </p> <p>You are told that your ammonia solution has a <strong>degree of dissociation</strong> of <mathjax>#1.3%#</mathjax> at a given temperature <mathjax>#T#</mathjax>. What that means is that <strong>for every</strong> <mathjax>#100#</mathjax> molecules of ammonia present in solution, only <mathjax>#1.3#</mathjax> will dissociate. </p> <p>Alternatively, you can think about it like this - for every <mathjax>#1000#</mathjax> molecules of ammonia, only <mathjax>#13#</mathjax> will ionize to form the aforementioned ions. The rest will remain as molecules of ammonia. </p> <p>The balanced chemical equation for this reaction looks like this</p> <blockquote> <p><mathjax>#"NH"_text(3(aq]) + "H"_2"O"_text((l]) rightleftharpoons "NH"_text(4(aq])^(+) + "OH"_text((aq])^(-)#</mathjax></p> </blockquote> <p>BY definition, the base dissociation constant will be equal to </p> <blockquote> <p><mathjax>#K_b = (["NH"_4^(+)] * ["OH"^(-)])/(["NH"_3])#</mathjax></p> </blockquote> <p>You know that</p> <blockquote> <p><mathjax>#["NH"_3] = "0.10 M"#</mathjax></p> </blockquote> <p>Now, use the degree of dissociation to find the concentrations of the two ions. You have <mathjax>#1:1#</mathjax> <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratios</a> between all chemical species, so you can say that</p> <blockquote> <p><mathjax>#["NH"_4^(+)] = ["OH"^(-)] = 1.3/100 * ["NH"_3]#</mathjax></p> <p><mathjax>#["NH"_4^(+)] = ["OH"^(-)] = 1.3 * 10^(-2) * "0.10 M" = 1.3 * 10^(-3)"M"#</mathjax></p> </blockquote> <p>This means that you get</p> <blockquote> <p><mathjax>#K_b = (1.3 * 10^(-3) * 1.3 * 10^(-3))/0.10 = color(green)(1.7 * 10^(-5))#</mathjax></p> </blockquote> <p>The answer is rounded to two <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the number of sig figs you have for the initial concentration of ammonia. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/202132" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-equilibrium-constant-change-with-temperature"> How does the equilibrium constant change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-equilibrium-constant-for-a-reverse-reaction"> How do you find equilibrium constant for a reversable reaction? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/532a4f1602bf347ef7da90d2"> Question #a90d2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-equilibrium-constant-for-the-reaction-of-nh3-with-water"> What is the equilibrium constant for the reaction of NH3 with water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-equation-for-finding-the-equilibrium-constant-for-a-chemical-reactio"> What is the equation for finding the equilibrium constant for a chemical reaction? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-equilibrium-constant-for-the-weak-acid-khp"> What is the equilibrium constant for the weak acid KHP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/consider-this-equilibrium-i2-s-h2o-l-h-aq-i-aq-hoi-aq-what-is-the-keq-expression"> Consider this equilibrium: I2(s) + H2O(l) ⇌ H+(aq) + I-(aq) + HOI(aq). 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Calculate Kb for NH3 at this temperature?	null
2,431	a87b761e-6ddd-11ea-a9f8-ccda262736ce	https://socratic.org/questions/a-sample-in-a-1cm-cuvette-gives-an-absorbance-reading-of-0-558-if-the-absorptivi	3.72 × 10^(-5) mol/L	start physical_unit 17 18 molarity mol/l qc_end physical_unit 6 6 4 5 path_length qc_end physical_unit 0 1 12 12 absorbance_reading qc_end physical_unit 17 18 20 23 absorptivity qc_end end	[{"type":"physical unit","value":"Molar concentration [OF] this sample [IN] mol/L"}]	[{"type":"physical unit","value":"3.72 × 10^(-5) mol/L"}]	[{"type":"physical unit","value":"path length [OF] cuvette [=] \\pu{1 cm}"},{"type":"physical unit","value":"absorbance reading [OF] a sample [=] \\pu{0.558}"},{"type":"physical unit","value":"absorptivity [OF] this sample [=] \\pu{15000 L/(mol * cm)}"}]	<h1 class="questionTitle" itemprop="name">A sample in a #1cm# cuvette gives an absorbance reading of #0.558#. If the absorptivity for this sample is #15000 L/(mol.cm)#, what is the molar concentration? </h1>	null	3.72 × 10^(-5) mol/L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>A. Molar concentration from absorbance</strong></p> <p>To solve this problem, we use <strong>Beer's Law</strong>:</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(\|color(white)(a/a) A = epsilonlc color(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>where</p> <p><mathjax>#A =#</mathjax> the absorbance<br/> <mathjax>#epsilon =#</mathjax> the molar absorptivity constant<br/> <mathjax>#l =#</mathjax> the path length of the cuvette<br/> <mathjax>#c = #</mathjax> the molar concentration of the solution.</p> <blockquote></blockquote> <p>We can rearrange this equation to get</p> <blockquote> <blockquote> <p><mathjax>#c = A/(epsilonl)#</mathjax></p> </blockquote> </blockquote> <p>In this problem,</p> <p><mathjax>#A = 0.558#</mathjax><br/> <mathjax>#epsilon =color(white)(l) "15 000 L·mol"^"-1""cm"^"-1"#</mathjax><br/> <mathjax>#lcolor(white)(ll) = "1 cm"#</mathjax></p> <p>Then,</p> <p><mathjax>#c = 0.558/("15 000 L·mol"^"-1"color(red)(cancel(color(black)("cm"^"-1"))) × 1 color(red)(cancel(color(black)("cm")))) = 3.72 × 10^"-5" color(white)(l)"mol·L"^"-1"#</mathjax></p> <blockquote></blockquote> <p><strong>Molar concentration from transmittance</strong></p> <p>Recall that <strong>absorbance</strong> is defined as</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(\|color(white)(a/a)A = log(I_0/I)color(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>where</p> <p><mathjax>#I_0#</mathjax> and <mathjax>#I#</mathjax> are the intensities of the incident and transmitted light.</p> <p><strong>Transmittance</strong> <mathjax>#T#</mathjax> is defined as </p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(\|color(white)(a/a)T = I/I_0color(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>∴ <mathjax>#A = log(1/T)#</mathjax></p> <p>Also, <strong>percent transmittance</strong> <mathjax>#%T = 100T#</mathjax> </p> <p>so</p> <p><mathjax>#T = (%T)/100#</mathjax></p> <p>∴ <mathjax>#A = log(100/(%T))#</mathjax> or </p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(\|color(white)(a/a)A = 2-log(%T)color(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>This last equation is <strong>worth remembering</strong> because it gives you an easy way to calculate absorbance from percent transmittance.</p> <p><mathjax>#A = 2 - log72.6 = "2 - 1.860" = 0.140#</mathjax></p> <p>Now, we can use Beer's Law:</p> <p><mathjax>#c = A/(epsilonl) = 0.140/("15 000 L·mol"^"-1"color(red)(cancel(color(black)("cm"^"-1"))) × 1 color(red)(cancel(color(black)("cm")))) = 9.33 × 10^"-6" color(white)(l)"mol·L"^"-1"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The concentrations are (a) <mathjax>#3.72 × 10^"-5" color(white)(l)"mol·L"^"-1"#</mathjax> and (b) <mathjax>#9.33 × 10^"-6" color(white)(l)"mol·L"^"-1"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>A. Molar concentration from absorbance</strong></p> <p>To solve this problem, we use <strong>Beer's Law</strong>:</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(\|color(white)(a/a) A = epsilonlc color(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>where</p> <p><mathjax>#A =#</mathjax> the absorbance<br/> <mathjax>#epsilon =#</mathjax> the molar absorptivity constant<br/> <mathjax>#l =#</mathjax> the path length of the cuvette<br/> <mathjax>#c = #</mathjax> the molar concentration of the solution.</p> <blockquote></blockquote> <p>We can rearrange this equation to get</p> <blockquote> <blockquote> <p><mathjax>#c = A/(epsilonl)#</mathjax></p> </blockquote> </blockquote> <p>In this problem,</p> <p><mathjax>#A = 0.558#</mathjax><br/> <mathjax>#epsilon =color(white)(l) "15 000 L·mol"^"-1""cm"^"-1"#</mathjax><br/> <mathjax>#lcolor(white)(ll) = "1 cm"#</mathjax></p> <p>Then,</p> <p><mathjax>#c = 0.558/("15 000 L·mol"^"-1"color(red)(cancel(color(black)("cm"^"-1"))) × 1 color(red)(cancel(color(black)("cm")))) = 3.72 × 10^"-5" color(white)(l)"mol·L"^"-1"#</mathjax></p> <blockquote></blockquote> <p><strong>Molar concentration from transmittance</strong></p> <p>Recall that <strong>absorbance</strong> is defined as</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(\|color(white)(a/a)A = log(I_0/I)color(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>where</p> <p><mathjax>#I_0#</mathjax> and <mathjax>#I#</mathjax> are the intensities of the incident and transmitted light.</p> <p><strong>Transmittance</strong> <mathjax>#T#</mathjax> is defined as </p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(\|color(white)(a/a)T = I/I_0color(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>∴ <mathjax>#A = log(1/T)#</mathjax></p> <p>Also, <strong>percent transmittance</strong> <mathjax>#%T = 100T#</mathjax> </p> <p>so</p> <p><mathjax>#T = (%T)/100#</mathjax></p> <p>∴ <mathjax>#A = log(100/(%T))#</mathjax> or </p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(\|color(white)(a/a)A = 2-log(%T)color(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>This last equation is <strong>worth remembering</strong> because it gives you an easy way to calculate absorbance from percent transmittance.</p> <p><mathjax>#A = 2 - log72.6 = "2 - 1.860" = 0.140#</mathjax></p> <p>Now, we can use Beer's Law:</p> <p><mathjax>#c = A/(epsilonl) = 0.140/("15 000 L·mol"^"-1"color(red)(cancel(color(black)("cm"^"-1"))) × 1 color(red)(cancel(color(black)("cm")))) = 9.33 × 10^"-6" color(white)(l)"mol·L"^"-1"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A sample in a #1cm# cuvette gives an absorbance reading of #0.558#. If the absorptivity for this sample is #15000 L/(mol.cm)#, what is the molar concentration? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="394542" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-21T20:58:57" itemprop="dateCreated"> Mar 21, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The concentrations are (a) <mathjax>#3.72 × 10^"-5" color(white)(l)"mol·L"^"-1"#</mathjax> and (b) <mathjax>#9.33 × 10^"-6" color(white)(l)"mol·L"^"-1"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>A. Molar concentration from absorbance</strong></p> <p>To solve this problem, we use <strong>Beer's Law</strong>:</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(\|color(white)(a/a) A = epsilonlc color(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>where</p> <p><mathjax>#A =#</mathjax> the absorbance<br/> <mathjax>#epsilon =#</mathjax> the molar absorptivity constant<br/> <mathjax>#l =#</mathjax> the path length of the cuvette<br/> <mathjax>#c = #</mathjax> the molar concentration of the solution.</p> <blockquote></blockquote> <p>We can rearrange this equation to get</p> <blockquote> <blockquote> <p><mathjax>#c = A/(epsilonl)#</mathjax></p> </blockquote> </blockquote> <p>In this problem,</p> <p><mathjax>#A = 0.558#</mathjax><br/> <mathjax>#epsilon =color(white)(l) "15 000 L·mol"^"-1""cm"^"-1"#</mathjax><br/> <mathjax>#lcolor(white)(ll) = "1 cm"#</mathjax></p> <p>Then,</p> <p><mathjax>#c = 0.558/("15 000 L·mol"^"-1"color(red)(cancel(color(black)("cm"^"-1"))) × 1 color(red)(cancel(color(black)("cm")))) = 3.72 × 10^"-5" color(white)(l)"mol·L"^"-1"#</mathjax></p> <blockquote></blockquote> <p><strong>Molar concentration from transmittance</strong></p> <p>Recall that <strong>absorbance</strong> is defined as</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(\|color(white)(a/a)A = log(I_0/I)color(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>where</p> <p><mathjax>#I_0#</mathjax> and <mathjax>#I#</mathjax> are the intensities of the incident and transmitted light.</p> <p><strong>Transmittance</strong> <mathjax>#T#</mathjax> is defined as </p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(\|color(white)(a/a)T = I/I_0color(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>∴ <mathjax>#A = log(1/T)#</mathjax></p> <p>Also, <strong>percent transmittance</strong> <mathjax>#%T = 100T#</mathjax> </p> <p>so</p> <p><mathjax>#T = (%T)/100#</mathjax></p> <p>∴ <mathjax>#A = log(100/(%T))#</mathjax> or </p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(\|color(white)(a/a)A = 2-log(%T)color(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>This last equation is <strong>worth remembering</strong> because it gives you an easy way to calculate absorbance from percent transmittance.</p> <p><mathjax>#A = 2 - log72.6 = "2 - 1.860" = 0.140#</mathjax></p> <p>Now, we can use Beer's Law:</p> <p><mathjax>#c = A/(epsilonl) = 0.140/("15 000 L·mol"^"-1"color(red)(cancel(color(black)("cm"^"-1"))) × 1 color(red)(cancel(color(black)("cm")))) = 9.33 × 10^"-6" color(white)(l)"mol·L"^"-1"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/394542" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? 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If the absorptivity for this sample is #15000 L/(mol.cm)#, what is the molar concentration?	null
2,432	ac0a1bae-6ddd-11ea-9bf5-ccda262736ce	https://socratic.org/questions/can-you-help-me-out-please-thanks	4.00 ℃	start physical_unit 14 14 boiling_point_temperature °c qc_end physical_unit 6 6 2 3 mole qc_end physical_unit 14 14 21 23 boiling_point_temperature qc_end physical_unit 28 29 2 3 mole qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Changed boiling point2 [OF] water [IN] ℃"}]	[{"type":"physical unit","value":"4.00 ℃"}]	[{"type":"physical unit","value":"Mole [OF] C12H22O11 [=] \\pu{2.5 mol}"},{"type":"physical unit","value":"Raised boiling point1 [OF] water [=] \\pu{1 Celsius degree}"},{"type":"physical unit","value":"Mole [OF] aluminum nitrate [=] \\pu{2.5 mol}"},{"type":"other","value":"Same amount of water."}]	<h1 class="questionTitle" itemprop="name">Can you help me out please? Thanks! </h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>When a 2.5 mol of sugar (C12H22O11) are added to a certain amount of water the boiling point is raised by 1 Celsius degree. If 2.5 mol of aluminum nitrate is added to the same amount of water, by how much will the boiling point be changed? Show all calculations leading to your answer OR use 3 – 4 sentences to explain your answer.</p></div> </h2> </div> </div>	4.00 ℃	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The formula for boiling point elevation <mathjax>#ΔT_text(b)#</mathjax> is</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(\|color(white)(a/a)ΔT_text(b) = iK_text(b)bcolor(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>where</p> <p><mathjax>#i#</mathjax> is the <strong>van't Hoff <mathjax>#i#</mathjax>-factor</strong> for the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a><br/> <mathjax>#K_text(b)#</mathjax> is the <strong>molal boiling point elevation constant</strong> of the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a><br/> <mathjax>#b#</mathjax> is the <strong>molal concentration</strong> (molality) of the solute</p> <p>If we have two different <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> of the same <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molality">molality</a> in the same solvent, we can write</p> <p><mathjax>#(ΔT_text(b,2))/(ΔT_text(b,1)) = (i_2color(red)(cancel(color(black)(K_text(b)b))))/(i_1color(red)(cancel(color(black)(K_text(b)b)))) = i_2/i_1#</mathjax></p> <p>or </p> <p><mathjax>#ΔT_text(b,2) = ΔT_text(b,1) × i_2/i_1#</mathjax></p> <blockquote></blockquote> <p>Let <mathjax>#"component 1 = sucrose"#</mathjax> and <mathjax>#"component 2 = aluminium nitrate"#</mathjax>.</p> <p>Sucrose is a covalent compound. It does not dissociate in solution, so <mathjax>#i = 1#</mathjax>.</p> <blockquote></blockquote> <p>Aluminium nitrate is a soluble ionic compound. It dissociates in solution according to the equation</p> <p><mathjax>#"Al"("NO"_3)_3"(s)" → "Al"^"3+""(aq)" + 3"NO"_3^"-""(aq)"#</mathjax></p> <p>Thus, 1 mol of solute forms 4 mol of particles, and <mathjax>#i = 4#</mathjax>.</p> <p>∴ <mathjax>#ΔT_text(b,2) = "1 °C" × 4/1 = "4 °C"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><blockquote></blockquote> <p>The boiling point will be raised by 4 °C.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The formula for boiling point elevation <mathjax>#ΔT_text(b)#</mathjax> is</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(\|color(white)(a/a)ΔT_text(b) = iK_text(b)bcolor(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>where</p> <p><mathjax>#i#</mathjax> is the <strong>van't Hoff <mathjax>#i#</mathjax>-factor</strong> for the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a><br/> <mathjax>#K_text(b)#</mathjax> is the <strong>molal boiling point elevation constant</strong> of the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a><br/> <mathjax>#b#</mathjax> is the <strong>molal concentration</strong> (molality) of the solute</p> <p>If we have two different <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> of the same <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molality">molality</a> in the same solvent, we can write</p> <p><mathjax>#(ΔT_text(b,2))/(ΔT_text(b,1)) = (i_2color(red)(cancel(color(black)(K_text(b)b))))/(i_1color(red)(cancel(color(black)(K_text(b)b)))) = i_2/i_1#</mathjax></p> <p>or </p> <p><mathjax>#ΔT_text(b,2) = ΔT_text(b,1) × i_2/i_1#</mathjax></p> <blockquote></blockquote> <p>Let <mathjax>#"component 1 = sucrose"#</mathjax> and <mathjax>#"component 2 = aluminium nitrate"#</mathjax>.</p> <p>Sucrose is a covalent compound. It does not dissociate in solution, so <mathjax>#i = 1#</mathjax>.</p> <blockquote></blockquote> <p>Aluminium nitrate is a soluble ionic compound. It dissociates in solution according to the equation</p> <p><mathjax>#"Al"("NO"_3)_3"(s)" → "Al"^"3+""(aq)" + 3"NO"_3^"-""(aq)"#</mathjax></p> <p>Thus, 1 mol of solute forms 4 mol of particles, and <mathjax>#i = 4#</mathjax>.</p> <p>∴ <mathjax>#ΔT_text(b,2) = "1 °C" × 4/1 = "4 °C"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Can you help me out please? Thanks! </h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>When a 2.5 mol of sugar (C12H22O11) are added to a certain amount of water the boiling point is raised by 1 Celsius degree. If 2.5 mol of aluminum nitrate is added to the same amount of water, by how much will the boiling point be changed? Show all calculations leading to your answer OR use 3 – 4 sentences to explain your answer.</p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/colligative-properties" itemprop="url"> <span class="breadcrumb" itemprop="title">Colligative Properties</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="467343" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-23T18:33:38" itemprop="dateCreated"> Aug 23, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><blockquote></blockquote> <p>The boiling point will be raised by 4 °C.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The formula for boiling point elevation <mathjax>#ΔT_text(b)#</mathjax> is</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(\|color(white)(a/a)ΔT_text(b) = iK_text(b)bcolor(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>where</p> <p><mathjax>#i#</mathjax> is the <strong>van't Hoff <mathjax>#i#</mathjax>-factor</strong> for the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a><br/> <mathjax>#K_text(b)#</mathjax> is the <strong>molal boiling point elevation constant</strong> of the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a><br/> <mathjax>#b#</mathjax> is the <strong>molal concentration</strong> (molality) of the solute</p> <p>If we have two different <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> of the same <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molality">molality</a> in the same solvent, we can write</p> <p><mathjax>#(ΔT_text(b,2))/(ΔT_text(b,1)) = (i_2color(red)(cancel(color(black)(K_text(b)b))))/(i_1color(red)(cancel(color(black)(K_text(b)b)))) = i_2/i_1#</mathjax></p> <p>or </p> <p><mathjax>#ΔT_text(b,2) = ΔT_text(b,1) × i_2/i_1#</mathjax></p> <blockquote></blockquote> <p>Let <mathjax>#"component 1 = sucrose"#</mathjax> and <mathjax>#"component 2 = aluminium nitrate"#</mathjax>.</p> <p>Sucrose is a covalent compound. It does not dissociate in solution, so <mathjax>#i = 1#</mathjax>.</p> <blockquote></blockquote> <p>Aluminium nitrate is a soluble ionic compound. It dissociates in solution according to the equation</p> <p><mathjax>#"Al"("NO"_3)_3"(s)" → "Al"^"3+""(aq)" + 3"NO"_3^"-""(aq)"#</mathjax></p> <p>Thus, 1 mol of solute forms 4 mol of particles, and <mathjax>#i = 4#</mathjax>.</p> <p>∴ <mathjax>#ΔT_text(b,2) = "1 °C" × 4/1 = "4 °C"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/467343" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-colligative-properties-determined"> How are colligative properties determined? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-freezing-point-depression"> How do you calculate freezing point depression? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-freezing-point-depression-determine-purity"> How can freezing point depression determine purity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-colligative-properties-affect-boiling-point"> How does the nature of the solute affect boiling point? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-colligative-properties-affect-freezing-point"> How do colligative properties affect freezing point? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-colligative-property-causes-ice-to-melt"> What colligative property causes ice to melt? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-colligative-properties-depend-on-the-number-of-particles"> Why do colligative properties depend on the number of particles? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-ionic-bonding-affect-the-boiling-point"> How do ionic solutes affect the boiling point? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-solutes-lower-vapor-pressure"> Why do solutes lower vapor pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-solubility-affect-boiling-point"> How does solubility affect boiling point? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/colligative-properties"> See all questions in Colligative Properties </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3080 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Can you help me out please? Thanks!	When a 2.5 mol of sugar (C12H22O11) are added to a certain amount of water the boiling point is raised by 1 Celsius degree. If 2.5 mol of aluminum nitrate is added to the same amount of water, by how much will the boiling point be changed? Show all calculations leading to your answer OR use 3 – 4 sentences to explain your answer.
2,433	abc7b92e-6ddd-11ea-bfe1-ccda262736ce	https://socratic.org/questions/59a41fd7b72cff2bca916d55	201.5 K	start physical_unit 14 14 temperature k qc_end c_other OTHER qc_end physical_unit 14 14 16 17 temperature qc_end physical_unit 14 14 10 11 volume qc_end physical_unit 14 14 26 27 volume qc_end end	[{"type":"physical unit","value":"Temperature2 [OF] the gas [IN] K"}]	[{"type":"physical unit","value":"201.5 K"}]	[{"type":"other","value":"Constant pressure."},{"type":"physical unit","value":"Temperature1 [OF] the gas [=] \\pu{373 K}"},{"type":"physical unit","value":"Volume1 [OF] the gas [=] \\pu{500 cm^3}"},{"type":"physical unit","value":"Volume2 [OF] the gas [=] \\pu{270 cm^3}"}]	<h1 class="questionTitle" itemprop="name">Given constant pressure, how does the temperature change when a #500cm^3# volume of gas at #373K# is cooled so that then volume reduces to #270*cm^3#?</h1>	null	201.5 K	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We solve for <mathjax>#T_2=V_2/V_1xxT_1=(270cm^3)/(500cm^3)xx373K#</mathjax></p> <p><mathjax>#=201.5K#</mathjax></p> <p>Clearly the temperature has to drop to reduce the volume so substantially. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Old <a href="https://socratic.org/chemistry/the-behavior-of-gases/charles-law">Charles' Law</a> holds that <mathjax>#V_1/T_1=V_2/T_2#</mathjax> under conditions of constant pressure......</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We solve for <mathjax>#T_2=V_2/V_1xxT_1=(270cm^3)/(500cm^3)xx373K#</mathjax></p> <p><mathjax>#=201.5K#</mathjax></p> <p>Clearly the temperature has to drop to reduce the volume so substantially. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Given constant pressure, how does the temperature change when a #500cm^3# volume of gas at #373K# is cooled so that then volume reduces to #270cm^3#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/charles-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Charles' Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="468975" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-28T13:59:48" itemprop="dateCreated"> Aug 28, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Old <a href="https://socratic.org/chemistry/the-behavior-of-gases/charles-law">Charles' Law</a> holds that <mathjax>#V_1/T_1=V_2/T_2#</mathjax> under conditions of constant pressure......</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We solve for <mathjax>#T_2=V_2/V_1xxT_1=(270cm^3)/(500cm^3)xx373K#</mathjax></p> <p><mathjax>#=201.5*K#</mathjax></p> <p>Clearly the temperature has to drop to reduce the volume so substantially. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/468975" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-must-charles-law-be-in-kelvins"> Why must Charles' law be in kelvin? 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When the temperature is lowered to... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-sample-of-oxygen-occupies-a-volume-of-160-dm3-at-91-c-what-will-be-volume-of-o"> A sample of oxygen occupies a volume of 160 dm3 at 91° C. What will be volume of oxygen when the... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/charles-law"> See all questions in Charles' Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1478 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Given constant pressure, how does the temperature change when a #500cm^3# volume of gas at #373K# is cooled so that then volume reduces to #270*cm^3#?	null
2,434	acde7c5a-6ddd-11ea-8651-ccda262736ce	https://socratic.org/questions/what-is-the-final-temperature-when-50-ml-of-water-at-80-c-are-added-to-25-ml-of-	61.7 ℃	start physical_unit 9 9 temperature °c qc_end physical_unit 9 9 11 12 temperature qc_end physical_unit 9 9 6 7 volume qc_end physical_unit 9 9 21 22 temperature qc_end physical_unit 9 9 16 17 volume qc_end end	[{"type":"physical unit","value":"Temperature3 [OF] water [IN] ℃"}]	[{"type":"physical unit","value":"61.7 ℃"}]	[{"type":"physical unit","value":"Temperature1 [OF] water [=] \\pu{80 ℃}"},{"type":"physical unit","value":"Volume1 [OF] water [=] \\pu{50 mL}"},{"type":"physical unit","value":"Temperature2 [OF] water [=] \\pu{25 ℃}"},{"type":"physical unit","value":"Volume2 [OF] water [=] \\pu{25 mL}"}]	<h1 class="questionTitle" itemprop="name">What is the final temperature when 50 mL of water at 80°C are added to 25 mL of water at 25°C?</h1>	null	61.7 ℃	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#sum#</mathjax> energy changes = 0</p> <p><mathjax>#sumQ = Q_(80^oC) + Q_(25^oC)#</mathjax> = <mathjax>#[mcDeltaT_(80^oC) + mcDeltaT_(25^oC)#</mathjax>] = 0</p> <p><a href="https://socratic.org/chemistry/measurement-in-chemistry/density">Density</a> HOH = 1.00 g/ml; <br/> Speific Heat(c) HOH = <mathjax>#1.00 "cal"/g^oC#</mathjax></p> <p><mathjax>#[(50g)(1("cal"/g^oC))(T_("final") - 80^oC)]#</mathjax> + </p> <blockquote> <blockquote> <blockquote> <blockquote> <blockquote> <p><mathjax>#[(25g)(1("cal"/g^oC))(T_("final") - 25^oC)]#</mathjax> = <mathjax>#0#</mathjax></p> </blockquote> </blockquote> </blockquote> </blockquote> </blockquote> <p>=> <mathjax>#[(50)(1)(T_("final") - 80)] + [(25)(1)(T_("final") - 25)] = 0#</mathjax></p> <p>=> <mathjax>#(50T_("final") - 4000) + (25T_("final") - 625) = 0#</mathjax></p> <p>=> <mathjax>#75T_("final") = (4000 + 625) = 4625#</mathjax></p> <p>=> <mathjax>#T = (4625/75)^oC = 61.7^oC#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#61.7^oC#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#sum#</mathjax> energy changes = 0</p> <p><mathjax>#sumQ = Q_(80^oC) + Q_(25^oC)#</mathjax> = <mathjax>#[mcDeltaT_(80^oC) + mcDeltaT_(25^oC)#</mathjax>] = 0</p> <p><a href="https://socratic.org/chemistry/measurement-in-chemistry/density">Density</a> HOH = 1.00 g/ml; <br/> Speific Heat(c) HOH = <mathjax>#1.00 "cal"/g^oC#</mathjax></p> <p><mathjax>#[(50g)(1("cal"/g^oC))(T_("final") - 80^oC)]#</mathjax> + </p> <blockquote> <blockquote> <blockquote> <blockquote> <blockquote> <p><mathjax>#[(25g)(1("cal"/g^oC))(T_("final") - 25^oC)]#</mathjax> = <mathjax>#0#</mathjax></p> </blockquote> </blockquote> </blockquote> </blockquote> </blockquote> <p>=> <mathjax>#[(50)(1)(T_("final") - 80)] + [(25)(1)(T_("final") - 25)] = 0#</mathjax></p> <p>=> <mathjax>#(50T_("final") - 4000) + (25T_("final") - 625) = 0#</mathjax></p> <p>=> <mathjax>#75T_("final") = (4000 + 625) = 4625#</mathjax></p> <p>=> <mathjax>#T = (4625/75)^oC = 61.7^oC#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the final temperature when 50 mL of water at 80°C are added to 25 mL of water at 25°C?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/calorimetry" itemprop="url"> <span class="breadcrumb" itemprop="title">Calorimetry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="433267" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/doc048"><img alt="" class="" src="https://profilepictures.socratic.org/e4gaeUMMQESTpfte6aRu_Friendly%20Chem%20Professor.jpg" title=""/></a> <a class="secondContributorPic" href="/users/truong-son-n"><img alt="" class="" src="https://profilepictures.socratic.org/07k4plnQfmnmzMuesQzw_14844-1449381920.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/doc048"> Doc048 </a>·<a class="topContributorLink" href="/users/truong-son-n"> Truong-Son N. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-01T22:40:59" itemprop="dateCreated"> Jun 1, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#61.7^oC#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#sum#</mathjax> energy changes = 0</p> <p><mathjax>#sumQ = Q_(80^oC) + Q_(25^oC)#</mathjax> = <mathjax>#[mcDeltaT_(80^oC) + mcDeltaT_(25^oC)#</mathjax>] = 0</p> <p><a href="https://socratic.org/chemistry/measurement-in-chemistry/density">Density</a> HOH = 1.00 g/ml; <br/> Speific Heat(c) HOH = <mathjax>#1.00 "cal"/g^oC#</mathjax></p> <p><mathjax>#[(50g)(1("cal"/g^oC))(T_("final") - 80^oC)]#</mathjax> + </p> <blockquote> <blockquote> <blockquote> <blockquote> <blockquote> <p><mathjax>#[(25g)(1("cal"/g^oC))(T_("final") - 25^oC)]#</mathjax> = <mathjax>#0#</mathjax></p> </blockquote> </blockquote> </blockquote> </blockquote> </blockquote> <p>=> <mathjax>#[(50)(1)(T_("final") - 80)] + [(25)(1)(T_("final") - 25)] = 0#</mathjax></p> <p>=> <mathjax>#(50T_("final") - 4000) + (25T_("final") - 625) = 0#</mathjax></p> <p>=> <mathjax>#75T_("final") = (4000 + 625) = 4625#</mathjax></p> <p>=> <mathjax>#T = (4625/75)^oC = 61.7^oC#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/433267" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-differential-scanning-in-calorimetry-work"> How does differential scanning in calorimetry work? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-read-differential-scanning-in-calorimetry"> What information do you get from a differential scanning calorimetry plot? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-measure-calorimetry"> How do you measure calorimetry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531d304102bf341e75b962a7"> Question #962a7 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5335021802bf344ae911dfc5"> Question #1dfc5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/533668f502bf34572c341af6"> Question #41af6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-definition-of-calorimetry"> What is calorimetry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-differential-scanning-calorimeter"> What is a differential scanning calorimeter? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-a-calorimeter-measure-energy"> How can a calorimeter measure energy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-calorimeters-made-of"> What are calorimeters made of? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/calorimetry"> See all questions in Calorimetry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 28356 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the final temperature when 50 mL of water at 80°C are added to 25 mL of water at 25°C?	null
2,435	aa8ceedc-6ddd-11ea-88c6-ccda262736ce	https://socratic.org/questions/59a3f89fb72cff2e472ccdab	7256.81 kJ	start physical_unit 10 10 energy kj qc_end physical_unit 10 10 12 13 temperature qc_end physical_unit 10 10 7 8 mass qc_end physical_unit 10 10 16 17 delta_{vap}h qc_end end	[{"type":"physical unit","value":"Required energy [OF] water [IN] kJ"}]	[{"type":"physical unit","value":"7256.81 kJ"}]	[{"type":"physical unit","value":"Temperature [OF] water [=] \\pu{100 ℃}"},{"type":"physical unit","value":"Mass [OF] water [=] \\pu{3210 g}"},{"type":"physical unit","value":"Delta_{vap}H [OF] water [=] \\pu{40.7 J/mol}"}]	<h1 class="questionTitle" itemprop="name">How much energy is required to vaporize 3210 g of water at 100 °C ?</h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p><mathjax>#Δ_text(vap)H = "40.7 J/mol"#</mathjax></p></div> </h2> </div> </div>	7256.81 kJ	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#DeltaH_(vap) = 40.7kJ*mol^(-1)#</mathjax><br/> This means that the total heat required to vaporise 1 mol of liquid water at <mathjax>#100^oC#</mathjax> is <mathjax>#40.7kJ#</mathjax></p> <p><mathjax>#1 mol#</mathjax> of <mathjax># H_2O = 18 g#</mathjax> </p> <p><mathjax>#:. 3210 g #</mathjax> of <mathjax>#H_2O = 3210/18 = 178.3 mol#</mathjax></p> <p><mathjax>#1mol#</mathjax> of <mathjax>#H_2O#</mathjax> requires <mathjax>#40.7kJ#</mathjax> of heat.<br/> <mathjax>#:. 178.3 mol#</mathjax> requires <mathjax>#178.3 xx 40.7 = 7256.81 kJ~~73000kJ#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#7256.81 kJ#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#DeltaH_(vap) = 40.7kJ*mol^(-1)#</mathjax><br/> This means that the total heat required to vaporise 1 mol of liquid water at <mathjax>#100^oC#</mathjax> is <mathjax>#40.7kJ#</mathjax></p> <p><mathjax>#1 mol#</mathjax> of <mathjax># H_2O = 18 g#</mathjax> </p> <p><mathjax>#:. 3210 g #</mathjax> of <mathjax>#H_2O = 3210/18 = 178.3 mol#</mathjax></p> <p><mathjax>#1mol#</mathjax> of <mathjax>#H_2O#</mathjax> requires <mathjax>#40.7kJ#</mathjax> of heat.<br/> <mathjax>#:. 178.3 mol#</mathjax> requires <mathjax>#178.3 xx 40.7 = 7256.81 kJ~~73000kJ#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How much energy is required to vaporize 3210 g of water at 100 °C ?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p><mathjax>#Δ_text(vap)H = "40.7 J/mol"#</mathjax></p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/enthalpy" itemprop="url"> <span class="breadcrumb" itemprop="title">Enthalpy</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="468927" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/sarthak-3"><img alt="" class="" src="https://profilepictures.socratic.org/r1uCBFoR32iP5CryFHLD_1174593909317479.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/sarthak-3"> Sarthak </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-28T11:35:02" itemprop="dateCreated"> Aug 28, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#7256.81 kJ#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#DeltaH_(vap) = 40.7kJ*mol^(-1)#</mathjax><br/> This means that the total heat required to vaporise 1 mol of liquid water at <mathjax>#100^oC#</mathjax> is <mathjax>#40.7kJ#</mathjax></p> <p><mathjax>#1 mol#</mathjax> of <mathjax># H_2O = 18 g#</mathjax> </p> <p><mathjax>#:. 3210 g #</mathjax> of <mathjax>#H_2O = 3210/18 = 178.3 mol#</mathjax></p> <p><mathjax>#1mol#</mathjax> of <mathjax>#H_2O#</mathjax> requires <mathjax>#40.7kJ#</mathjax> of heat.<br/> <mathjax>#:. 178.3 mol#</mathjax> requires <mathjax>#178.3 xx 40.7 = 7256.81 kJ~~73000kJ#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/468927" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-enthalpy-changes-expressed-in-chemical-equations"> How are enthalpy changes 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2,436	a8f564fa-6ddd-11ea-b3fd-ccda262736ce	https://socratic.org/questions/a-solution-is-prepared-by-dissolving-3-5-g-of-kcl-in-water-making-the-volume-of-	47 millimoles	start physical_unit 9 9 mole mmol qc_end physical_unit 1 1 19 20 volume qc_end physical_unit 9 9 6 7 mass qc_end substance 11 11 qc_end end	[{"type":"physical unit","value":"Mole [OF] KCl [IN] millimoles"}]	[{"type":"physical unit","value":"47 millimoles"}]	[{"type":"physical unit","value":"Volume [OF] solution [=] \\pu{250 mL}"},{"type":"physical unit","value":"Mass [OF] KCl [=] \\pu{3.5 g}"},{"type":"substance name","value":"Water"}]	<h1 class="questionTitle" itemprop="name">A solution is prepared by dissolving 3.5 #g# of #KCl# in water & making the volume of solution to 250 #mL#. What is the millimoles of #KCl# dissolved?</h1>	null	47 millimoles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To calculate how many <em>milimoles</em> of potassium chloride you dissolved in solution, all you really need to do is figure out how many <em>moles</em> of the salt you used. </p> <p>A simple conversion factor will then take you from moles to milimoles. </p> <p>So, use potassium chloride's molar mass to determine how many moles you added. </p> <p><mathjax>#3.5cancel("g") * "1 mole KCl"/(74.55cancel("g")) = "0.0469 moles KCl"#</mathjax></p> <p>To convert to milimoles, simply use the fact that one mole contains <strong>1000 milimoles</strong>.</p> <p><mathjax>#0.0469cancel("moles") * "1000 mmoles"/(1cancel("mole")) = "46.9 mmoles"#</mathjax></p> <p>You need to round this off to two <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the number of sig figs you gave for the mass of the salt. </p> <p><mathjax>#n_"KCl" = color(green)("47 mmoles")#</mathjax></p> <p>You can go on to calculate the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of the solution in <em>milimolar</em>, <strong>mM</strong>.</p> <p><mathjax>#C = n/V = "47 mmoles"/(250 * 10^(-3)"L") = 188"mmoles"/"L"#</mathjax></p> <p>Once again, round this off to two <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a> to get </p> <p><mathjax>#C = color(green)("190 mM")#</mathjax> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Your solution contains <strong>47 mmoles</strong> of potassium chloride.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To calculate how many <em>milimoles</em> of potassium chloride you dissolved in solution, all you really need to do is figure out how many <em>moles</em> of the salt you used. </p> <p>A simple conversion factor will then take you from moles to milimoles. </p> <p>So, use potassium chloride's molar mass to determine how many moles you added. </p> <p><mathjax>#3.5cancel("g") * "1 mole KCl"/(74.55cancel("g")) = "0.0469 moles KCl"#</mathjax></p> <p>To convert to milimoles, simply use the fact that one mole contains <strong>1000 milimoles</strong>.</p> <p><mathjax>#0.0469cancel("moles") * "1000 mmoles"/(1cancel("mole")) = "46.9 mmoles"#</mathjax></p> <p>You need to round this off to two <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the number of sig figs you gave for the mass of the salt. </p> <p><mathjax>#n_"KCl" = color(green)("47 mmoles")#</mathjax></p> <p>You can go on to calculate the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of the solution in <em>milimolar</em>, <strong>mM</strong>.</p> <p><mathjax>#C = n/V = "47 mmoles"/(250 * 10^(-3)"L") = 188"mmoles"/"L"#</mathjax></p> <p>Once again, round this off to two <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a> to get </p> <p><mathjax>#C = color(green)("190 mM")#</mathjax> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A solution is prepared by dissolving 3.5 #g# of #KCl# in water & making the volume of solution to 250 #mL#. What is the millimoles of #KCl# dissolved?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="158244" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-07-13T17:13:53" itemprop="dateCreated"> Jul 13, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Your solution contains <strong>47 mmoles</strong> of potassium chloride.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To calculate how many <em>milimoles</em> of potassium chloride you dissolved in solution, all you really need to do is figure out how many <em>moles</em> of the salt you used. </p> <p>A simple conversion factor will then take you from moles to milimoles. </p> <p>So, use potassium chloride's molar mass to determine how many moles you added. </p> <p><mathjax>#3.5cancel("g") * "1 mole KCl"/(74.55cancel("g")) = "0.0469 moles KCl"#</mathjax></p> <p>To convert to milimoles, simply use the fact that one mole contains <strong>1000 milimoles</strong>.</p> <p><mathjax>#0.0469cancel("moles") * "1000 mmoles"/(1cancel("mole")) = "46.9 mmoles"#</mathjax></p> <p>You need to round this off to two <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the number of sig figs you gave for the mass of the salt. </p> <p><mathjax>#n_"KCl" = color(green)("47 mmoles")#</mathjax></p> <p>You can go on to calculate the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of the solution in <em>milimolar</em>, <strong>mM</strong>.</p> <p><mathjax>#C = n/V = "47 mmoles"/(250 * 10^(-3)"L") = 188"mmoles"/"L"#</mathjax></p> <p>Once again, round this off to two <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a> to get </p> <p><mathjax>#C = color(green)("190 mM")#</mathjax> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/158244" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? 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What is the millimoles of #KCl# dissolved?	null
2,437	a94c234c-6ddd-11ea-b80b-ccda262736ce	https://socratic.org/questions/what-is-the-ph-of-a-0-00162-m-naoh-solution	11.21	start physical_unit 8 9 ph none qc_end physical_unit 8 9 6 7 molarity qc_end end	[{"type":"physical unit","value":"pH [OF] NaOH solution"}]	[{"type":"physical unit","value":"11.21"}]	[{"type":"physical unit","value":"Molarity [OF] NaOH solution [=] \\pu{0.00162 M}"}]	<h1 class="questionTitle" itemprop="name">What is the pH of a 0.00162 M NaOH solution?</h1>	null	11.21	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So we calculate <mathjax>#pOH#</mathjax>, i.e. <mathjax>#pOH=-log_10(1.62xx10^-3)=2.79#</mathjax>. This is by definition of <mathjax>#p#</mathjax> function. </p> <p>But <mathjax>#pH=14-2.79#</mathjax> from the above, so <mathjax>#pH=??#</mathjax></p> <p>Is this an acidic or basic solution? Why?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We know [from here](<a href="/questions/what-is-the-ph-of-a-5-00-x-10-2-m-aqueous-solution-of-ba-oh-2klzzwxh:0000pH+pOH=14">https://socratic.org/questions/what-is-the-ph-of-a-5-00-x-10-2-m-aqueous-solution-of-ba-oh-2<mathjax>#414169) that #</mathjax>pH+pOH=14#</a>. And this has to be committed to memory.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So we calculate <mathjax>#pOH#</mathjax>, i.e. <mathjax>#pOH=-log_10(1.62xx10^-3)=2.79#</mathjax>. This is by definition of <mathjax>#p#</mathjax> function. </p> <p>But <mathjax>#pH=14-2.79#</mathjax> from the above, so <mathjax>#pH=??#</mathjax></p> <p>Is this an acidic or basic solution? Why?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the pH of a 0.00162 M NaOH solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/ph-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">pH calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="414180" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-28T03:07:09" itemprop="dateCreated"> Apr 28, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We know [from here](<a href="/questions/what-is-the-ph-of-a-5-00-x-10-2-m-aqueous-solution-of-ba-oh-2klzzwxh:0000pH+pOH=14">https://socratic.org/questions/what-is-the-ph-of-a-5-00-x-10-2-m-aqueous-solution-of-ba-oh-2<mathjax>#414169) that #</mathjax>pH+pOH=14#</a>. And this has to be committed to memory.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So we calculate <mathjax>#pOH#</mathjax>, i.e. <mathjax>#pOH=-log_10(1.62xx10^-3)=2.79#</mathjax>. This is by definition of <mathjax>#p#</mathjax> function. </p> <p>But <mathjax>#pH=14-2.79#</mathjax> from the above, so <mathjax>#pH=??#</mathjax></p> <p>Is this an acidic or basic solution? Why?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/414180" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-of-a-solution"> How do you determine ph of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-at-an-equivalence-point"> How do you determine pH at an equivalence point? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-molarity"> How do you determine pH from molarity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-alkalinity-mean"> What does alkalinity mean? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-base"> What is a base? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-acid-base-indicators-change-color"> How do acid base indicators change color? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-neutral-ph"> What is a neutral pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-alkalinity-affect-pool-water"> How does alkalinity affect pool water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ph-important-in-drinking-water"> Why is pH important in drinking water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-ph-of-solution"> How can I calculate the pH of a solution? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/ph-calculations"> See all questions in pH calculations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 14478 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the pH of a 0.00162 M NaOH solution?	null
2,438	ac1ff800-6ddd-11ea-9f8c-ccda262736ce	https://socratic.org/questions/mg-was-reacted-with-an-excess-of-hcl-dilute-and-the-h-2-gas-produced-collected-i	0.1 g	start physical_unit 0 0 mass g qc_end c_other OTHER qc_end c_other STP qc_end physical_unit 11 11 32 33 volume qc_end end	[{"type":"physical unit","value":"Mass [OF] Mg [IN] g"}]	[{"type":"physical unit","value":"0.1 g"}]	[{"type":"other","value":"Excess of HCl."},{"type":"other","value":"STP"},{"type":"physical unit","value":"Volume [OF] H2 [=] \\pu{94.1 milliliters}"}]	<h1 class="questionTitle" itemprop="name">Mg was reacted with an excess of HCl dilute and the #H_2# gas produced collected in an eudiometer. The volume of hydrogen in the eudiometer was corrected to conditions of STP. If 94.1 milliliters of H2 was produced, how much Mg reacted in this experiment?</h1>	null	0.1 g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><img alt="en.wikipedia.org" src="https://useruploads.socratic.org/lv4CV65UR0ydj0F0RcQC_eudiometer_1.png"/> </p> <p>A <mathjax>#"eudiometer"#</mathjax> is a fancy name for a simple setup..as shown in the diagram. Note that as depicted the pressure of gas in the tube is LESS than atmospheric pressure. It is only when level of water inside the column is equal to the level OUTSIDE that the pressures are equal.....i.e. <mathjax>#P_"atmospheric"=P_"gas"+P_"saturated vapour pressure"#</mathjax>. <mathjax>#P_"SVP"="vapour pressure of water"#</mathjax>, a constant at constant temperature. </p> <p>The stoichiometric equation EXPLICITLY shows stoichiometric equivalence between the metal and dihydrogen. </p> <p><mathjax>#"Moles of dihydrogen"=(PV)/(RT)#</mathjax></p> <p><mathjax>#=(0.987atmxx94.1xx10^-3L)/(0.0821LatmK^-1mol^-1xx273.15K)#</mathjax></p> <p>(And if you think all this bumf in converting to LESS than 1 standard atmosphere is a bit tedious, I agree with you!).</p> <p><mathjax>#n_(H_2)~=4mmol#</mathjax></p> <p>Given the <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>, we use approx. <mathjax>#4mmolxx24.3gmol^-1=0.1g#</mathjax> of metal, a good mass for such an experiment. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Given <mathjax>#Mg(s) + 2HCl rarr MgCl_2(aq) + H_2(g)uarr#</mathjax>....we gets.....</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><img alt="en.wikipedia.org" src="https://useruploads.socratic.org/lv4CV65UR0ydj0F0RcQC_eudiometer_1.png"/> </p> <p>A <mathjax>#"eudiometer"#</mathjax> is a fancy name for a simple setup..as shown in the diagram. Note that as depicted the pressure of gas in the tube is LESS than atmospheric pressure. It is only when level of water inside the column is equal to the level OUTSIDE that the pressures are equal.....i.e. <mathjax>#P_"atmospheric"=P_"gas"+P_"saturated vapour pressure"#</mathjax>. <mathjax>#P_"SVP"="vapour pressure of water"#</mathjax>, a constant at constant temperature. </p> <p>The stoichiometric equation EXPLICITLY shows stoichiometric equivalence between the metal and dihydrogen. </p> <p><mathjax>#"Moles of dihydrogen"=(PV)/(RT)#</mathjax></p> <p><mathjax>#=(0.987atmxx94.1xx10^-3L)/(0.0821LatmK^-1mol^-1xx273.15K)#</mathjax></p> <p>(And if you think all this bumf in converting to LESS than 1 standard atmosphere is a bit tedious, I agree with you!).</p> <p><mathjax>#n_(H_2)~=4mmol#</mathjax></p> <p>Given the <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>, we use approx. <mathjax>#4mmolxx24.3gmol^-1=0.1g#</mathjax> of metal, a good mass for such an experiment. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Mg was reacted with an excess of HCl dilute and the #H_2# gas produced collected in an eudiometer. The volume of hydrogen in the eudiometer was corrected to conditions of STP. If 94.1 milliliters of H2 was produced, how much Mg reacted in this experiment?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/stoichiometry-with-acid-and-base-dissociation" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry with Acid and Base Dissociation</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="468228" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-26T05:08:40" itemprop="dateCreated"> Aug 26, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Given <mathjax>#Mg(s) + 2HCl rarr MgCl_2(aq) + H_2(g)uarr#</mathjax>....we gets.....</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><img alt="en.wikipedia.org" src="https://useruploads.socratic.org/lv4CV65UR0ydj0F0RcQC_eudiometer_1.png"/> </p> <p>A <mathjax>#"eudiometer"#</mathjax> is a fancy name for a simple setup..as shown in the diagram. Note that as depicted the pressure of gas in the tube is LESS than atmospheric pressure. It is only when level of water inside the column is equal to the level OUTSIDE that the pressures are equal.....i.e. <mathjax>#P_"atmospheric"=P_"gas"+P_"saturated vapour pressure"#</mathjax>. <mathjax>#P_"SVP"="vapour pressure of water"#</mathjax>, a constant at constant temperature. </p> <p>The stoichiometric equation EXPLICITLY shows stoichiometric equivalence between the metal and dihydrogen. </p> <p><mathjax>#"Moles of dihydrogen"=(PV)/(RT)#</mathjax></p> <p><mathjax>#=(0.987atmxx94.1xx10^-3L)/(0.0821LatmK^-1mol^-1xx273.15K)#</mathjax></p> <p>(And if you think all this bumf in converting to LESS than 1 standard atmosphere is a bit tedious, I agree with you!).</p> <p><mathjax>#n_(H_2)~=4mmol#</mathjax></p> <p>Given the <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>, we use approx. <mathjax>#4mmolxx24.3gmol^-1=0.1g#</mathjax> of metal, a good mass for such an experiment. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/468228" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/533129fb02bf342f40b5c3cd"> Question #5c3cd </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-common-mistakes-students-make-with-stoichiometry-1"> What are some common mistakes students make with stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-an-example-of-a-stoichiometry-practice-problem-1"> What is an example of a stoichiometry practice problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-examples-of-acid-and-base-dissociation"> What are some examples of acid and base dissociation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-an-example-of-an-acid-and-base-dissociation-practice-problem"> What is an example of an acid and base dissociation practice problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-common-mistakes-students-make-with-acid-and-base-dissociation"> What are some common mistakes students make with acid and base dissociation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stoichiometry-with-acid-and-base-dissociation"> What is stoichiometry with acid and base dissociation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-examples-of-stoichiometry-with-acid-and-base-dissociation"> What are some examples of stoichiometry with acid and base dissociation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-an-example-of-a-stoichiometry-with-acid-and-base-dissociation-practice-p"> What is an example of a stoichiometry with acid and base dissociation practice problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-we-relate-stoichiometry-to-everyday-processes"> How do we relate stoichiometry to everyday processes? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/stoichiometry-with-acid-and-base-dissociation"> See all questions in Stoichiometry with Acid and Base Dissociation </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 10542 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Mg was reacted with an excess of HCl dilute and the #H_2# gas produced collected in an eudiometer. The volume of hydrogen in the eudiometer was corrected to conditions of STP. If 94.1 milliliters of H2 was produced, how much Mg reacted in this experiment?	null
2,439	a8c003d5-6ddd-11ea-8580-ccda262736ce	https://socratic.org/questions/581ff2a7b72cff4088aaee77	3.66 moles	start physical_unit 2 2 mole mol qc_end physical_unit 14 15 10 11 mole qc_end end	[{"type":"physical unit","value":"Mole [OF] dihydrogen [IN] moles"}]	[{"type":"physical unit","value":"3.66 moles"}]	[{"type":"physical unit","value":"Mole [OF] dinitrogen gas [=] \\pu{1.22 mol}"}]	<h1 class="questionTitle" itemprop="name">How much dihydrogen will be required to reduce completely a #1.22*mol# quantity of dinitrogen gas?</h1>	null	3.66 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Given the <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>, precisely <mathjax>#3.66*mol#</mathjax> dihydrogen gas are required to give ammonia. Each equiv dinitrogen requires three equiv dihydrogen. How much ammonia gas would be produced given complete reaction (an unlikely scenario)?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1/2N_2(g) + 3/2H_2(g) rarr NH_3(g)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Given the <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>, precisely <mathjax>#3.66*mol#</mathjax> dihydrogen gas are required to give ammonia. Each equiv dinitrogen requires three equiv dihydrogen. How much ammonia gas would be produced given complete reaction (an unlikely scenario)?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How much dihydrogen will be required to reduce completely a #1.22mol# quantity of dinitrogen gas?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/mole-ratios" itemprop="url"> <span class="breadcrumb" itemprop="title">Mole Ratios</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="333424" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-11-08T17:59:09" itemprop="dateCreated"> Nov 8, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1/2N_2(g) + 3/2H_2(g) rarr NH_3(g)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Given the <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>, precisely <mathjax>#3.66mol#</mathjax> dihydrogen gas are required to give ammonia. Each equiv dinitrogen requires three equiv dihydrogen. How much ammonia gas would be produced given complete reaction (an unlikely scenario)?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/333424" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4178e02bf3469517a106e"> Question #a106e </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4178e02bf3469570e2e86"> Question #e2e86 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179102bf3469517a1072"> Question #a1072 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179402bf34694c8c5bf1"> Question #c5bf1 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179702bf3469588dc373"> Question #dc373 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179c02bf34694c8c5bf9"> Question #c5bf9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417a302bf3469517a1076"> Question #a1076 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417c702bf3469588dc377"> Question #dc377 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417d002bf346963eb984f"> Question #b984f </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417d402bf346950519ea3"> Question #19ea3 </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/mole-ratios"> See all questions in Mole Ratios </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1607 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How much dihydrogen will be required to reduce completely a #1.22*mol# quantity of dinitrogen gas?	null
2,440	a9a1fffa-6ddd-11ea-a809-ccda262736ce	https://socratic.org/questions/ionic-product-of-water-at-310-k-is-2-7-x-10-14-what-is-the-ph-of-neutral-water-a	7	start physical_unit 16 17 ph none qc_end physical_unit 3 3 8 10 ionic_product qc_end physical_unit 3 3 5 6 temperature qc_end end	[{"type":"physical unit","value":"pH [OF] neutral water"}]	[{"type":"physical unit","value":"7"}]	[{"type":"physical unit","value":"Lonic product [OF] water [=] \\pu{2.7 × 10^(-14)}"},{"type":"physical unit","value":"Temperature [OF] water [=] \\pu{310 K}"}]	<h1 class="questionTitle" itemprop="name">Ionic product of water at #310# #K# is #2.7# x #10^-14#. What is the #pH# of neutral water at this temperature?</h1>	null	7	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#H_2OrarrH^(+) + OH^-#</mathjax>; <mathjax>#K_w#</mathjax> <mathjax>#=#</mathjax> <mathjax>#[H^+][OH^-]#</mathjax> <mathjax>#=#</mathjax> <mathjax>#2.7xx10^(-14)#</mathjax> at <mathjax>#310#</mathjax> <mathjax>#K#</mathjax> (this is almost 3 times the value at <mathjax>#298#</mathjax> <mathjax>#K#</mathjax>).</p> <p>By definition <mathjax>#pH=-log_10[H^+] #</mathjax> <mathjax>#=#</mathjax> <mathjax>#-log_(10){sqrt{2.7xx10^(-14)}}#</mathjax>. <mathjax>#pH#</mathjax> should be less than <mathjax>#7#</mathjax>, because the higher temperature facilitates the breaking of the <mathjax>#H-OH#</mathjax> bond. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Because acid base dissociation is a bond breaking reaction, and you have increased the temperature (thus favoring bond-breaking), <mathjax>#pH#</mathjax> should be less than <mathjax>#7#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#H_2OrarrH^(+) + OH^-#</mathjax>; <mathjax>#K_w#</mathjax> <mathjax>#=#</mathjax> <mathjax>#[H^+][OH^-]#</mathjax> <mathjax>#=#</mathjax> <mathjax>#2.7xx10^(-14)#</mathjax> at <mathjax>#310#</mathjax> <mathjax>#K#</mathjax> (this is almost 3 times the value at <mathjax>#298#</mathjax> <mathjax>#K#</mathjax>).</p> <p>By definition <mathjax>#pH=-log_10[H^+] #</mathjax> <mathjax>#=#</mathjax> <mathjax>#-log_(10){sqrt{2.7xx10^(-14)}}#</mathjax>. <mathjax>#pH#</mathjax> should be less than <mathjax>#7#</mathjax>, because the higher temperature facilitates the breaking of the <mathjax>#H-OH#</mathjax> bond. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Ionic product of water at #310# #K# is #2.7# x #10^-14#. What is the #pH# of neutral water at this temperature?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/ph-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">pH calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="213332" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-17T05:56:04" itemprop="dateCreated"> Jan 17, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Because acid base dissociation is a bond breaking reaction, and you have increased the temperature (thus favoring bond-breaking), <mathjax>#pH#</mathjax> should be less than <mathjax>#7#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#H_2OrarrH^(+) + OH^-#</mathjax>; <mathjax>#K_w#</mathjax> <mathjax>#=#</mathjax> <mathjax>#[H^+][OH^-]#</mathjax> <mathjax>#=#</mathjax> <mathjax>#2.7xx10^(-14)#</mathjax> at <mathjax>#310#</mathjax> <mathjax>#K#</mathjax> (this is almost 3 times the value at <mathjax>#298#</mathjax> <mathjax>#K#</mathjax>).</p> <p>By definition <mathjax>#pH=-log_10[H^+] #</mathjax> <mathjax>#=#</mathjax> <mathjax>#-log_(10){sqrt{2.7xx10^(-14)}}#</mathjax>. <mathjax>#pH#</mathjax> should be less than <mathjax>#7#</mathjax>, because the higher temperature facilitates the breaking of the <mathjax>#H-OH#</mathjax> bond. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/213332" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-of-a-solution"> How do you determine ph of a solution? 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What is the #pH# of neutral water at this temperature?	null
2,441	a8ca14d2-6ddd-11ea-bad5-ccda262736ce	https://socratic.org/questions/what-is-the-mass-of-cu-2s-formed-if-64-g-of-s-are-used-in-the-reaction-2cu-s-cu-	318 grams	start physical_unit 5 5 mass g qc_end physical_unit 11 11 8 9 mass qc_end chemical_equation 17 22 qc_end end	[{"type":"physical unit","value":"Mass [OF] Cu2S [IN] grams"}]	[{"type":"physical unit","value":"318 grams"}]	[{"type":"physical unit","value":"Mass [OF] S [=] \\pu{64 g}"},{"type":"chemical equation","value":"2 Cu + S -> Cu2S"}]	<h1 class="questionTitle" itemprop="name">What is the mass of #Cu_2S# formed if 64 g of #S# are used in the reaction #2Cu + S -> Cu_2S#?</h1>	null	318 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><ol> <li>First know what element/compound involved in the problem. In this case, it's <mathjax>#S#</mathjax> and <mathjax>#Cu_2S#</mathjax>;</li> <li>Once known, find the <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">atomic mass</a> and the molar mass, respectively for stoichiometric calculation later;<br/> <mathjax>#S#</mathjax>= 32 gram/mol<br/> <mathjax>#Cu_2S#</mathjax>=159 gram/mol </li> <li>Start the calculation with the mass of <mathjax>#S#</mathjax> as provided in the problem and all the way to the desired answer using all data you have gathered. Make sure to cancel units out, leaving your desired unit which is mass in <mathjax>#grams#</mathjax> of <mathjax>#Cu_2S#</mathjax>;<br/> <mathjax>#64 cancel(g S) #</mathjax>x<mathjax># (1 cancel(mol S))/(32 cancel(g S)) #</mathjax>x<mathjax># (1 cancel(mol Cu_2S))/(1 cancel(mol S)) #</mathjax>x<mathjax># (159 g Cu_2S)/(1 cancel(mol Cu_2S))#</mathjax></li> <li>The answer is <mathjax>#318#</mathjax> <mathjax>#grams#</mathjax> <mathjax>#Cu_2S#</mathjax></li> </ol></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#318#</mathjax> grams <mathjax>#Cu_2S#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><ol> <li>First know what element/compound involved in the problem. In this case, it's <mathjax>#S#</mathjax> and <mathjax>#Cu_2S#</mathjax>;</li> <li>Once known, find the <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">atomic mass</a> and the molar mass, respectively for stoichiometric calculation later;<br/> <mathjax>#S#</mathjax>= 32 gram/mol<br/> <mathjax>#Cu_2S#</mathjax>=159 gram/mol </li> <li>Start the calculation with the mass of <mathjax>#S#</mathjax> as provided in the problem and all the way to the desired answer using all data you have gathered. Make sure to cancel units out, leaving your desired unit which is mass in <mathjax>#grams#</mathjax> of <mathjax>#Cu_2S#</mathjax>;<br/> <mathjax>#64 cancel(g S) #</mathjax>x<mathjax># (1 cancel(mol S))/(32 cancel(g S)) #</mathjax>x<mathjax># (1 cancel(mol Cu_2S))/(1 cancel(mol S)) #</mathjax>x<mathjax># (159 g Cu_2S)/(1 cancel(mol Cu_2S))#</mathjax></li> <li>The answer is <mathjax>#318#</mathjax> <mathjax>#grams#</mathjax> <mathjax>#Cu_2S#</mathjax></li> </ol></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the mass of #Cu_2S# formed if 64 g of #S# are used in the reaction #2Cu + S -> Cu_2S#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="243090" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/jarni-renz"><img alt="" class="" src="https://profilepictures.socratic.org/i6OiZQmVRHWljDVlwm8v_WIN_20160301_180231.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/jarni-renz"> Jarni Renz </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-21T19:37:05" itemprop="dateCreated"> Mar 21, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#318#</mathjax> grams <mathjax>#Cu_2S#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><ol> <li>First know what element/compound involved in the problem. In this case, it's <mathjax>#S#</mathjax> and <mathjax>#Cu_2S#</mathjax>;</li> <li>Once known, find the <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">atomic mass</a> and the molar mass, respectively for stoichiometric calculation later;<br/> <mathjax>#S#</mathjax>= 32 gram/mol<br/> <mathjax>#Cu_2S#</mathjax>=159 gram/mol </li> <li>Start the calculation with the mass of <mathjax>#S#</mathjax> as provided in the problem and all the way to the desired answer using all data you have gathered. Make sure to cancel units out, leaving your desired unit which is mass in <mathjax>#grams#</mathjax> of <mathjax>#Cu_2S#</mathjax>;<br/> <mathjax>#64 cancel(g S) #</mathjax>x<mathjax># (1 cancel(mol S))/(32 cancel(g S)) #</mathjax>x<mathjax># (1 cancel(mol Cu_2S))/(1 cancel(mol S)) #</mathjax>x<mathjax># (159 g Cu_2S)/(1 cancel(mol Cu_2S))#</mathjax></li> <li>The answer is <mathjax>#318#</mathjax> <mathjax>#grams#</mathjax> <mathjax>#Cu_2S#</mathjax></li> </ol></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/243090" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What is stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ab82402bf342f48d93ac6"> Question #93ac6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-we-study-stoichiometry"> Why do we study stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-naoh-is-produced-from-1-20-x-102-grams-of-na2o-na2o-h2o-2-naoh"> How many grams of NaOH is produced from #1.20 x 10^2# grams of #Na_2O#? #Na_2O + H_2O -> 2NaOH# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-na2o-are-required-to-produce-1-60-x-102-grams-of-naoh-na2o-h2o"> How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? Na2O + H2O ---> 2 NaOH </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-mass-of-iron-is-needed-to-react-with-16-0-grams-of-sulfur-8-fe-s8-8-fes"> What mass of iron is needed to react with 16.0 grams of sulfur? 8 Fe + S8 ---> 8 FeS </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/according-to-8-fe-s8-8-fes-how-many-grams-of-fes-are-produced"> According to 8 Fe + S8 ---> 8 FeS How many grams of FeS are produced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/12-00-moles-of-naclo3-will-produce-how-many-grams-of-o2-2-naclo3-2-nacl-3-o2"> 12.00 moles of NaClO3 will produce how many grams of O2? 2 NaClO3 ---> 2 NaCl + 3 O2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-nacl-are-produced-when-80-0-grams-of-o2-are-produced-2-naclo3-"> How many grams of NaCl are produced when 80.0 grams of O2 are produced? 2 NaClO3 ---> 2 NaCl + 3 O2 </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/stoichiometry"> See all questions in Stoichiometry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1107 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the mass of #Cu_2S# formed if 64 g of #S# are used in the reaction #2Cu + S -> Cu_2S#?	null
2,442	acad3fb4-6ddd-11ea-950b-ccda262736ce	https://socratic.org/questions/a-canister-containing-air-has-a-volume-of-85-cm-3-and-a-pressure-of-1-45-atm-whe	0.52 atm	start physical_unit 3 3 pressure atm qc_end physical_unit 3 3 8 9 volume qc_end physical_unit 3 3 14 15 pressure qc_end physical_unit 3 3 20 21 temperature qc_end physical_unit 3 3 32 33 volume qc_end physical_unit 3 3 40 41 temperature qc_end end	[{"type":"physical unit","value":"Pressure2 [OF] air [IN] atm"}]	[{"type":"physical unit","value":"0.52 atm"}]	[{"type":"physical unit","value":"Volume1 [OF] air [=] \\pu{85 cm^3}"},{"type":"physical unit","value":"Pressure1 [OF] air [=] \\pu{1.45 atm}"},{"type":"physical unit","value":"Temperature1 [OF] air [=] \\pu{310 K}"},{"type":"physical unit","value":"Volume2 [OF] air [=] \\pu{180 cm^3}"},{"type":"physical unit","value":"Temperature2 [OF] air [=] \\pu{280 K}"}]	<h1 class="questionTitle" itemprop="name">A canister containing air has a volume of #85# #cm^3# and a pressure of #1.45# #atm# when the temperature is #310# #K#. What is the pressure when the volume is increased to #180# #cm^3# and the temperature is reduced to #280# #K#? </h1>	null	0.52 atm	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>According to the ideal gas equation we know that:</p> <h2><mathjax>#(pV)/T=const#</mathjax></h2> <p>so if we write that:</p> <p><mathjax>#p_1=1atm#</mathjax></p> <p><mathjax>#v_1=85cm^3#</mathjax></p> <p><mathjax>#T_1=310K#</mathjax></p> <p>After the change we have:</p> <p><mathjax>#v_2=180cm^3#</mathjax></p> <p><mathjax>#T_2=280K#</mathjax></p> <p>We have to calculate the new pressure <mathjax>#p_2#</mathjax></p> <p>Using the equation stated at the beginning we have:</p> <p><mathjax>#(p_1v_1)/T_1=(p_2v_2)/T_2#</mathjax></p> <p>If we transform the formula we get:</p> <p><mathjax>#p_2=(p_1v_1T_2)/(T_1v_2)#</mathjax></p> <p>If we substitute the given data we get:</p> <p><mathjax>#p_2=(185310)/(180280)=2635/5040~~0.523#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The pressure will fall to <mathjax>#p_2~~0.523#</mathjax> <mathjax>#atm#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>According to the ideal gas equation we know that:</p> <h2><mathjax>#(pV)/T=const#</mathjax></h2> <p>so if we write that:</p> <p><mathjax>#p_1=1atm#</mathjax></p> <p><mathjax>#v_1=85cm^3#</mathjax></p> <p><mathjax>#T_1=310K#</mathjax></p> <p>After the change we have:</p> <p><mathjax>#v_2=180cm^3#</mathjax></p> <p><mathjax>#T_2=280K#</mathjax></p> <p>We have to calculate the new pressure <mathjax>#p_2#</mathjax></p> <p>Using the equation stated at the beginning we have:</p> <p><mathjax>#(p_1v_1)/T_1=(p_2v_2)/T_2#</mathjax></p> <p>If we transform the formula we get:</p> <p><mathjax>#p_2=(p_1v_1T_2)/(T_1v_2)#</mathjax></p> <p>If we substitute the given data we get:</p> <p><mathjax>#p_2=(185310)/(180280)=2635/5040~~0.523#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A canister containing air has a volume of #85# #cm^3# and a pressure of #1.45# #atm# when the temperature is #310# #K#. What is the pressure when the volume is increased to #180# #cm^3# and the temperature is reduced to #280# #K#? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/gas-laws" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Laws</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="385352" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/daniel-l-3"><img alt="" class="" src="https://graph.facebook.com/100001647465264/picture?height=50&width=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/daniel-l-3"> Daniel L. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-02T11:57:03" itemprop="dateCreated"> Mar 2, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The pressure will fall to <mathjax>#p_2~~0.523#</mathjax> <mathjax>#atm#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>According to the ideal gas equation we know that:</p> <h2><mathjax>#(pV)/T=const#</mathjax></h2> <p>so if we write that:</p> <p><mathjax>#p_1=1atm#</mathjax></p> <p><mathjax>#v_1=85cm^3#</mathjax></p> <p><mathjax>#T_1=310K#</mathjax></p> <p>After the change we have:</p> <p><mathjax>#v_2=180cm^3#</mathjax></p> <p><mathjax>#T_2=280K#</mathjax></p> <p>We have to calculate the new pressure <mathjax>#p_2#</mathjax></p> <p>Using the equation stated at the beginning we have:</p> <p><mathjax>#(p_1v_1)/T_1=(p_2v_2)/T_2#</mathjax></p> <p>If we transform the formula we get:</p> <p><mathjax>#p_2=(p_1v_1T_2)/(T_1v_2)#</mathjax></p> <p>If we substitute the given data we get:</p> <p><mathjax>#p_2=(185310)/(180280)=2635/5040~~0.523#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/385352" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-boyles-law-relate-to-breathing"> How does Boyle's law relate to breathing? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/in-avogadro-s-law-what-would-happen-to-v-if-n-is-increased-decreased-and-what-wo"> In Avogadro's Law what would happen to V if N is increased/decreased? 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What is the pressure when the volume is increased to #180# #cm^3# and the temperature is reduced to #280# #K#?	null
2,443	a83efa64-6ddd-11ea-ba8a-ccda262736ce	https://socratic.org/questions/590b35837c01491a80ac70ed	0.6 mol/L	start physical_unit 3 3 concentration mol/l qc_end physical_unit 3 3 9 10 mass qc_end physical_unit 22 22 18 19 volume qc_end end	[{"type":"physical unit","value":"Concentration [OF] NaOH solution [IN] mol/L"}]	[{"type":"physical unit","value":"0.6 mol/L"}]	[{"type":"physical unit","value":"Mass [OF] NaOH(s) [=] \\pu{15.5 g}"},{"type":"physical unit","value":"Volume [OF] water [=] \\pu{650 mL}"}]	<h1 class="questionTitle" itemprop="name">With respect to #NaOH(s)#, what is the concentration of #15.5g# mass of sodium hydroxide dissolved in a #650mL# volume of water?</h1>	null	0.6 mol/L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Given the formula:</p> <p><mathjax>#"Molarity"=((15.50cancelg)/(40.00cancelgmol^-1))/(650.0cancel(mL)xx10^-3Lcancel(mL^-1))=??molL^-1#</mathjax>.</p> <p>Note that this is dimensionally consistent, i.e. <mathjax>#1/(mol^-1)=1/(1/(mol))#</mathjax> <mathjax>#=mol#</mathjax> as required...........</p> <p>Since we wanted an answer in <mathjax>#mol*L^-1#</mathjax> expressing <mathjax>#"concentration"#</mathjax>, and we got one, this is a good check that we performed the analysis properly. It is all too easy to divide instead of multiply or vice versa, and botch the problem entirely. We have all done it. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Molarity"="Moles of solute"/"Volume of solution"~=0.6molL^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Given the formula:</p> <p><mathjax>#"Molarity"=((15.50cancelg)/(40.00cancelgmol^-1))/(650.0cancel(mL)xx10^-3Lcancel(mL^-1))=??molL^-1#</mathjax>.</p> <p>Note that this is dimensionally consistent, i.e. <mathjax>#1/(mol^-1)=1/(1/(mol))#</mathjax> <mathjax>#=mol#</mathjax> as required...........</p> <p>Since we wanted an answer in <mathjax>#mol*L^-1#</mathjax> expressing <mathjax>#"concentration"#</mathjax>, and we got one, this is a good check that we performed the analysis properly. It is all too easy to divide instead of multiply or vice versa, and botch the problem entirely. We have all done it. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">With respect to #NaOH(s)#, what is the concentration of #15.5g# mass of sodium hydroxide dissolved in a #650mL# volume of water?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="417607" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-04T14:18:20" itemprop="dateCreated"> May 4, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Molarity"="Moles of solute"/"Volume of solution"~=0.6molL^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Given the formula:</p> <p><mathjax>#"Molarity"=((15.50cancelg)/(40.00cancelgmol^-1))/(650.0cancel(mL)xx10^-3Lcancel(mL^-1))=??molL^-1#</mathjax>.</p> <p>Note that this is dimensionally consistent, i.e. <mathjax>#1/(mol^-1)=1/(1/(mol))#</mathjax> <mathjax>#=mol#</mathjax> as required...........</p> <p>Since we wanted an answer in <mathjax>#mol*L^-1#</mathjax> expressing <mathjax>#"concentration"#</mathjax>, and we got one, this is a good check that we performed the analysis properly. It is all too easy to divide instead of multiply or vice versa, and botch the problem entirely. We have all done it. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/417607" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-morality-be-used-as-a-conversion-factor"> How can molarity be used as a conversion factor? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-high-can-molarity-be"> How high can molarity be? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-molarity-change-with-temperature"> How does molarity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molarity-of-a-solution"> How do you find molarity of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-10-naoh"> What is the molarity of 10 NaOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-3-hydrogen-peroxide"> What is the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1352 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	With respect to #NaOH(s)#, what is the concentration of #15.5g# mass of sodium hydroxide dissolved in a #650mL# volume of water?	null
2,444	a8e7c765-6ddd-11ea-a0b7-ccda262736ce	https://socratic.org/questions/how-do-you-balance-this-redox-reaction-using-the-oxidation-number-method-kclo3-s	2 KClO3(s) -> 2 KCl(s) + 3 O2(g)	start chemical_equation qc_end chemical_equation 12 16 qc_end end	[{"type":"other","value":"Chemical Equation [OF] this redox reaction"}]	[{"type":"chemical equation","value":"2 KClO3(s) -> 2 KCl(s) + 3 O2(g)"}]	[{"type":"chemical equation","value":"KClO3(s) -> KCl(s) + O2(g)"}]	<h1 class="questionTitle" itemprop="name">How do you balance this redox reaction using the oxidation number method? KClO3(s) → KCl(s)+O2(g)</h1>	null	2 KClO3(s) -> 2 KCl(s) + 3 O2(g)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>For one method, see <a href="http://socratic.org/questions/how-do-you-balance-redox-equations-by-oxidation-number-method">How do you balance redox equations by oxidation number method?</a></p> <p>Your unbalanced equation is</p> <p>KClO₃ → KCl + O₂</p> <p><strong>Step 1.</strong> The <a href="http://socratic.org/chemistry/electrochemistry/oxidation-numbers">oxidation numbers</a> are:</p> <p>Left hand side: K = +1; O = -2; Cl = +5<br/> Right hand side: K = +1; Cl = -1; O = 0</p> <p><strong>Step 2.</strong> The changes in oxidation number are:</p> <p>O: -2 → 0; Change = +2<br/> Cl: +5 → -1; Change = -6</p> <p><strong>Step 3.</strong> Equalize the changes in oxidation number.</p> <p>You need 3 atoms of O for every 1 atom of Cl or 6 atoms of O for every 2 atoms of Cl. This gives us total changes of +12 and -12.</p> <p><strong>Step 4.</strong> Insert coefficients to get these numbers.</p> <p><strong>2</strong> KClO₃ → <strong>2</strong> KCl + <strong>3</strong> O₂</p> <p>Every substance now has a coefficient.</p> <p><strong>Step 5.</strong> Check that all atoms balance.</p> <p>Left hand side: 2 K; 2 Cl; 6 O<br/> Right hand side: 2 K; 2 Cl; 6 O</p> <p>The balanced equation is</p> <p>2KClO₃ → 2KCl + 3O₂</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>2KClO₃ → 2KCl + 3O₂</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>For one method, see <a href="http://socratic.org/questions/how-do-you-balance-redox-equations-by-oxidation-number-method">How do you balance redox equations by oxidation number method?</a></p> <p>Your unbalanced equation is</p> <p>KClO₃ → KCl + O₂</p> <p><strong>Step 1.</strong> The <a href="http://socratic.org/chemistry/electrochemistry/oxidation-numbers">oxidation numbers</a> are:</p> <p>Left hand side: K = +1; O = -2; Cl = +5<br/> Right hand side: K = +1; Cl = -1; O = 0</p> <p><strong>Step 2.</strong> The changes in oxidation number are:</p> <p>O: -2 → 0; Change = +2<br/> Cl: +5 → -1; Change = -6</p> <p><strong>Step 3.</strong> Equalize the changes in oxidation number.</p> <p>You need 3 atoms of O for every 1 atom of Cl or 6 atoms of O for every 2 atoms of Cl. This gives us total changes of +12 and -12.</p> <p><strong>Step 4.</strong> Insert coefficients to get these numbers.</p> <p><strong>2</strong> KClO₃ → <strong>2</strong> KCl + <strong>3</strong> O₂</p> <p>Every substance now has a coefficient.</p> <p><strong>Step 5.</strong> Check that all atoms balance.</p> <p>Left hand side: 2 K; 2 Cl; 6 O<br/> Right hand side: 2 K; 2 Cl; 6 O</p> <p>The balanced equation is</p> <p>2KClO₃ → 2KCl + 3O₂</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you balance this redox reaction using the oxidation number method? KClO3(s) → KCl(s)+O2(g)</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#electrochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Electrochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/electrochemistry/balancing-redox-equations-using-the-oxidation-number-method" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Redox Equations Using the Oxidation Number Method</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="109595" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> <a class="secondContributorPic" href="/users/dwayne-m"><img alt="" class="" src="https://graph.facebook.com/589089719/picture?height=50&width=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a>·<a class="topContributorLink" href="/users/dwayne-m"> Dwayne M. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2014-09-24T15:47:46" itemprop="dateCreated"> Sep 24, 2014 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>2KClO₃ → 2KCl + 3O₂</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>For one method, see <a href="http://socratic.org/questions/how-do-you-balance-redox-equations-by-oxidation-number-method">How do you balance redox equations by oxidation number method?</a></p> <p>Your unbalanced equation is</p> <p>KClO₃ → KCl + O₂</p> <p><strong>Step 1.</strong> The <a href="http://socratic.org/chemistry/electrochemistry/oxidation-numbers">oxidation numbers</a> are:</p> <p>Left hand side: K = +1; O = -2; Cl = +5<br/> Right hand side: K = +1; Cl = -1; O = 0</p> <p><strong>Step 2.</strong> The changes in oxidation number are:</p> <p>O: -2 → 0; Change = +2<br/> Cl: +5 → -1; Change = -6</p> <p><strong>Step 3.</strong> Equalize the changes in oxidation number.</p> <p>You need 3 atoms of O for every 1 atom of Cl or 6 atoms of O for every 2 atoms of Cl. This gives us total changes of +12 and -12.</p> <p><strong>Step 4.</strong> Insert coefficients to get these numbers.</p> <p><strong>2</strong> KClO₃ → <strong>2</strong> KCl + <strong>3</strong> O₂</p> <p>Every substance now has a coefficient.</p> <p><strong>Step 5.</strong> Check that all atoms balance.</p> <p>Left hand side: 2 K; 2 Cl; 6 O<br/> Right hand side: 2 K; 2 Cl; 6 O</p> <p>The balanced equation is</p> <p>2KClO₃ → 2KCl + 3O₂</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/109595" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-balance-redox-reactions-in-basic-solution"> How do you balance redox reactions in basic solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-balance-redox-equations-by-oxidation-number-method"> How do you balance redox equations by oxidation number method? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-balance-redox-equations-in-acidic-solutions"> How do you balance redox equations in acidic solutions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-method"> What is the oxidation number method? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-examples-of-balancing-redox-equations-using-the-oxidation-number-m"> What are some examples of balancing redox equations using the oxidation number method? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-oxidation-number-method-useful"> Why is the oxidation number method useful? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-it-necessary-to-break-the-equation-into-half-reactions-in-the-oxidation-numbe"> Is it necessary to break the equation into half reactions in the oxidation number method? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-difference-between-the-oxidation-number-method-and-the-ion-electron-"> What is the difference between the oxidation number method and the ion-electron method? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-balance-the-equation-using-the-oxidation-states-method-mno2-al-mn-al2o3"> Can you balance the equation using the oxidation states method MnO2+Al--->Mn+Al2O3? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-balance-this-redox-reaction-using-the-oxidation-number-method-fe2-aq-"> How do you balance this redox reaction using the oxidation number method? Fe2+(aq) + MnO4–(aq)... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/electrochemistry/balancing-redox-equations-using-the-oxidation-number-method"> See all questions in Balancing Redox Equations Using the Oxidation Number Method </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 43780 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How do you balance this redox reaction using the oxidation number method? KClO3(s) → KCl(s)+O2(g)	null
2,445	ab00909f-6ddd-11ea-b999-ccda262736ce	https://socratic.org/questions/how-many-grams-of-potassium-nitrate-kno-3-are-formed-when-102-grams-of-nitric-ac	164 grams	start physical_unit 6 6 mass g qc_end physical_unit 15 15 10 11 mass qc_end chemical_equation 20 20 qc_end end	[{"type":"physical unit","value":"Mass [OF] KNO3 [IN] grams"}]	[{"type":"physical unit","value":"164 grams"}]	[{"type":"physical unit","value":"Mass [OF] HNO3 [=] \\pu{102 grams}"},{"type":"chemical equation","value":"KOH"}]	<h1 class="questionTitle" itemprop="name">How many grams of potassium nitrate, #KNO_3#. are formed when 102 grams of nitric acid, #HNO_3#, react with potassium hydroxide #KOH#? </h1>	null	164 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Let's start by creating the chemical equation for this reaction:</p> <p><mathjax>#HNO_3(aq) + KOH(aq) rightleftharpoons KNO_3(aq) + H_2O(l)#</mathjax></p> <p>This is a <em><a href="https://socratic.org/chemistry/reactions-in-solution/neutralization">neutralization</a></em> reaction, in which an acid (<mathjax>#HNO_3#</mathjax>) and a base (<mathjax>#KOH#</mathjax>) react to form a salt and (most often liquid) water. </p> <p>We'll go about this problem by first using the molar mass of <mathjax>#HNO_3#</mathjax> to calculate the number of moles present, then use the stoichiometric relationships (the coefficients, which are all <mathjax>#1#</mathjax> in this case), to calculate the moles of <mathjax>#KNO_3#</mathjax> that form, and lastly use its molar mass to find how many grams were formed.</p> <p>Using dimensional analysis, the whole procedure is</p> <p><mathjax>#102cancel(gHNO_3)((1cancel(molHNO_3))/(63.02cancel(gHNO_3)))((1cancel(molKNO_3))/(1cancel(molHNO_3)))((101.11gKNO_3)/(1cancel(molKNO_3))) = color(red)(164gKNO_3#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#164gKNO_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Let's start by creating the chemical equation for this reaction:</p> <p><mathjax>#HNO_3(aq) + KOH(aq) rightleftharpoons KNO_3(aq) + H_2O(l)#</mathjax></p> <p>This is a <em><a href="https://socratic.org/chemistry/reactions-in-solution/neutralization">neutralization</a></em> reaction, in which an acid (<mathjax>#HNO_3#</mathjax>) and a base (<mathjax>#KOH#</mathjax>) react to form a salt and (most often liquid) water. </p> <p>We'll go about this problem by first using the molar mass of <mathjax>#HNO_3#</mathjax> to calculate the number of moles present, then use the stoichiometric relationships (the coefficients, which are all <mathjax>#1#</mathjax> in this case), to calculate the moles of <mathjax>#KNO_3#</mathjax> that form, and lastly use its molar mass to find how many grams were formed.</p> <p>Using dimensional analysis, the whole procedure is</p> <p><mathjax>#102cancel(gHNO_3)((1cancel(molHNO_3))/(63.02cancel(gHNO_3)))((1cancel(molKNO_3))/(1cancel(molHNO_3)))((101.11gKNO_3)/(1cancel(molKNO_3))) = color(red)(164gKNO_3#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many grams of potassium nitrate, #KNO_3#. are formed when 102 grams of nitric acid, #HNO_3#, react with potassium hydroxide #KOH#? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="427487" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/mrtas"><img alt="" class="" src="https://profilepictures.socratic.org/HY14X7r4S6AyDQgK2gwQ_IMG_0062.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/mrtas"> Nathan L. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-22T00:19:20" itemprop="dateCreated"> May 22, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#164gKNO_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Let's start by creating the chemical equation for this reaction:</p> <p><mathjax>#HNO_3(aq) + KOH(aq) rightleftharpoons KNO_3(aq) + H_2O(l)#</mathjax></p> <p>This is a <em><a href="https://socratic.org/chemistry/reactions-in-solution/neutralization">neutralization</a></em> reaction, in which an acid (<mathjax>#HNO_3#</mathjax>) and a base (<mathjax>#KOH#</mathjax>) react to form a salt and (most often liquid) water. </p> <p>We'll go about this problem by first using the molar mass of <mathjax>#HNO_3#</mathjax> to calculate the number of moles present, then use the stoichiometric relationships (the coefficients, which are all <mathjax>#1#</mathjax> in this case), to calculate the moles of <mathjax>#KNO_3#</mathjax> that form, and lastly use its molar mass to find how many grams were formed.</p> <p>Using dimensional analysis, the whole procedure is</p> <p><mathjax>#102cancel(gHNO_3)((1cancel(molHNO_3))/(63.02cancel(gHNO_3)))((1cancel(molKNO_3))/(1cancel(molHNO_3)))((101.11gKNO_3)/(1cancel(molKNO_3))) = color(red)(164gKNO_3#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/427487" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="427504" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-22T01:03:45" itemprop="dateCreated"> May 22, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>There would be <mathjax>#"164 g KNO"_3"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>Balanced Equation</strong></p> <p><mathjax>#"HNO"_3("aq") + "KOH(aq)"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"KNO"_3("aq") + "H"_2"O(l)"#</mathjax></p> <p>This is a <a href="https://socratic.org/chemistry/reactions-in-solution/neutralization">neutralization</a> reaction, which is a type of double replacement reaction. <mathjax>#"KNO"_3"#</mathjax> is in aqueous solution, which means the <mathjax>#"K"^+"#</mathjax> and <mathjax>#"NO"_3"^(-)#</mathjax> ions are dissociated and there is no discrete compound of <mathjax>#"KNO"_3"#</mathjax> as a product. However, if the reaction went to completion, and the only products were potassium nitrate and water, you could evaporate the water to isolate the potassium nitrate, and you should get the calculated mass <mathjax>#+-#</mathjax>. Regardless, the purpose of this question is to help you learn how to do <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> problems, so I will go ahead and answer as if <mathjax>#"KNO"_3"#</mathjax> were a discrete product, which it would be if the water were evaporated.</p> <p><strong>The process goes like this:</strong></p> <p><mathjax>#color(red)("given mass HNO"_3"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(red)("moles HNO"_3"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(red)("moles KNO"_3"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(red)("mass KNO"_3"#</mathjax> </p> <p><strong>We will need the MOLAR MASSES of <mathjax>#"HNO"_3"#</mathjax> and <mathjax>#"KNO"_3"#</mathjax>.</strong> <br/> Multiply the molar mass of each element by its subscript and add. The molar mass is the element's atomic weight on <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a> in g/mol.</p> <p><mathjax>#"HNO"_3:#</mathjax><mathjax>#(1xx1.008"g/mol H")+(1xx14.007"g/mol N")+(3xx15.999"g/mol O")="63.012 g/mol HNO"_3"#</mathjax></p> <p><mathjax>#"KNO"_3:#</mathjax><mathjax>#(1xx39.0983"g/mol K")+(1xx14.007"g/mol N")+(3xx15.999"g/mol O")="101.102 g/mol KNO"_3"#</mathjax></p> <p><mathjax>#color(blue)("Given Mass of Nitric Acid to Moles"#</mathjax><br/> <strong>Multiply the given mass of <mathjax>#"HNO"_3"#</mathjax> by the inverse of its molar mass.</strong></p> <p><mathjax>#102color(red)cancel(color(black)("g HNO"_3))xx(1"mol HNO"_3)/(63.012color(red)cancel(color(black)("g HNO"_3)))="1.6187 mol HNO"_3"#</mathjax> </p> <p><mathjax>#color(blue)("Moles Nitric Acid to Moles Potassium Nitrate"#</mathjax><br/> <strong>Multiply the moles <mathjax>#"HNO"_3#</mathjax> by <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio between <mathjax>#"HNO"_3#</mathjax> and <mathjax>#"KNO"_3#</mathjax> so that mol <mathjax>#"HNO"_3#</mathjax> cancels.</strong></p> <p><mathjax>#1.6187color(red)cancel(color(black)("mol HNO"_3))xx(1"mol KNO"_3)/(1color(red)cancel(color(black)("mol HNO"_3)))="1.6187 mol KNO"_3"#</mathjax></p> <p><mathjax>#color(blue)("Moles Potassium Nitrate to Mass Potassium Nitrate"#</mathjax><br/> <strong>Multiply mol <mathjax>#"KNO"_3"#</mathjax> by its molar mass.</strong></p> <p><mathjax>#1.6187color(red)cancel(color(black)("mol KNO"_3))xx(101.102"g KNO"_3)/(1color(red)cancel(color(black)("mol KNO"_3)))="164 g KNO"_3#</mathjax> (rounded to three <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a> due to 102 g)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/427504" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What is stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ab82402bf342f48d93ac6"> Question #93ac6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-we-study-stoichiometry"> Why do we study stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-naoh-is-produced-from-1-20-x-102-grams-of-na2o-na2o-h2o-2-naoh"> How many grams of NaOH is produced from #1.20 x 10^2# grams of #Na_2O#? #Na_2O + H_2O -> 2NaOH# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-na2o-are-required-to-produce-1-60-x-102-grams-of-naoh-na2o-h2o"> How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? 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2,446	a9c9b39a-6ddd-11ea-9ecd-ccda262736ce	https://socratic.org/questions/what-is-the-oxidation-number-for-beryllium	+2	start physical_unit 6 6 oxidation_number none qc_end substance 6 6 qc_end end	[{"type":"physical unit","value":"Oxidation number [OF] beryllium"}]	[{"type":"physical unit","value":"+2"}]	[{"type":"substance name","value":"Beryllium"}]	<h1 class="questionTitle" itemprop="name">What is the oxidation number for beryllium?</h1>	null	+2	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><ol> <li> <p>This element is in group 2 which is the alkali-earth metals. These <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> want to lose 2 electrons. </p> </li> <li> <p>Don't let the word "lose" fool you! Electrons are negative. If I lose electrons, I'm losing my negativity and becoming more positive. </p> </li> <li> <p>By losing 2 negative ions, 2 positive ions move into place and become Be +2 </p> </li> </ol> <p>Clarification: This is just a technique I've learned in Chemistry class. However, don't mix up positive with protons.. Note that Be+2 does not mean Be has 2 extra protons. It has 2 extra positive ions and 2 less electrons. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The oxidation number would be +2</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><ol> <li> <p>This element is in group 2 which is the alkali-earth metals. These <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> want to lose 2 electrons. </p> </li> <li> <p>Don't let the word "lose" fool you! Electrons are negative. If I lose electrons, I'm losing my negativity and becoming more positive. </p> </li> <li> <p>By losing 2 negative ions, 2 positive ions move into place and become Be +2 </p> </li> </ol> <p>Clarification: This is just a technique I've learned in Chemistry class. However, don't mix up positive with protons.. Note that Be+2 does not mean Be has 2 extra protons. It has 2 extra positive ions and 2 less electrons. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the oxidation number for beryllium?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#electrochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Electrochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/electrochemistry/oxidation-numbers" itemprop="url"> <span class="breadcrumb" itemprop="title">Oxidation Numbers</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="220771" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/nuha-a"><img alt="" class="" src="https://profilepictures.socratic.org/lnnn3ieQW2pjClcNvXvE_1240258_1416677685224297_735347422_n.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/nuha-a"> Zoe </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-02-03T02:25:10" itemprop="dateCreated"> Feb 3, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The oxidation number would be +2</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><ol> <li> <p>This element is in group 2 which is the alkali-earth metals. These <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> want to lose 2 electrons. </p> </li> <li> <p>Don't let the word "lose" fool you! Electrons are negative. If I lose electrons, I'm losing my negativity and becoming more positive. </p> </li> <li> <p>By losing 2 negative ions, 2 positive ions move into place and become Be +2 </p> </li> </ol> <p>Clarification: This is just a technique I've learned in Chemistry class. However, don't mix up positive with protons.. Note that Be+2 does not mean Be has 2 extra protons. It has 2 extra positive ions and 2 less electrons. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/220771" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-relate-to-electron-configuration"> How do oxidation numbers relate to electron configuration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-relate-to-valence-electrons"> How do oxidation numbers relate to valence electrons? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-vary-with-the-periodic-table"> How do oxidation numbers vary with the periodic table? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-oxidation-number-of-an-element-in-a-compound"> How do you calculate the oxidation number of an element in a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-sulfur"> What is the oxidation number for sulfur? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-carbon"> What is the oxidation number for carbon? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-copper"> What is the oxidation number for copper? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-nitrogen"> What is the oxidation number for nitrogen? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-oxygen"> What is the oxidation number for oxygen? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-oxidation-state-of-noble-gas-zero"> Why is the oxidation state of noble gas zero? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/electrochemistry/oxidation-numbers"> See all questions in Oxidation Numbers </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 5643 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the oxidation number for beryllium?	null
2,447	ac9615e7-6ddd-11ea-95c0-ccda262736ce	https://socratic.org/questions/how-many-so-2-molecules-are-there-in-7-08-moles-of-so-2	4.26 × 10^24	start physical_unit 2 3 number none qc_end physical_unit 2 2 7 8 mole qc_end end	[{"type":"physical unit","value":"Number [OF] SO2 molecules"}]	[{"type":"physical unit","value":"4.26 × 10^24"}]	[{"type":"physical unit","value":"Mole [OF] SO2 [=] \\pu{7.08 moles}"}]	<h1 class="questionTitle" itemprop="name">How many #SO_2# molecules are there in 7.08 moles of #SO_2#?</h1>	null	4.26 × 10^24	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You have 7.08 mol; therefore you have approx. 42 <mathjax>#xx#</mathjax> <mathjax>#10^23#</mathjax> <mathjax>#SO_2#</mathjax> molecules. Of course you can be more exact in your actual answer.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>1 mole is equivalent to Avogadro's number, <mathjax>#N_A#</mathjax>: <mathjax>#6.022xx10^23#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You have 7.08 mol; therefore you have approx. 42 <mathjax>#xx#</mathjax> <mathjax>#10^23#</mathjax> <mathjax>#SO_2#</mathjax> molecules. Of course you can be more exact in your actual answer.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many #SO_2# molecules are there in 7.08 moles of #SO_2#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="191948" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-22T18:23:00" itemprop="dateCreated"> Nov 22, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>1 mole is equivalent to Avogadro's number, <mathjax>#N_A#</mathjax>: <mathjax>#6.022xx10^23#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You have 7.08 mol; therefore you have approx. 42 <mathjax>#xx#</mathjax> <mathjax>#10^23#</mathjax> <mathjax>#SO_2#</mathjax> molecules. Of course you can be more exact in your actual answer.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/191948" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 987 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many #SO_2# molecules are there in 7.08 moles of #SO_2#?	null
2,448	a9c7246c-6ddd-11ea-acab-ccda262736ce	https://socratic.org/questions/an-unknown-volume-of-water-at-18-2-c-is-added-to-33-5-ml-of-water-at-35-0-c-if-t	72.35 mL	start physical_unit 4 4 volume ml qc_end physical_unit 4 4 6 7 temperature qc_end physical_unit 4 4 11 12 volume qc_end physical_unit 4 4 16 17 temperature qc_end physical_unit 4 4 23 24 temperature qc_end end	[{"type":"physical unit","value":"Volume1 [OF] water [IN] mL"}]	[{"type":"physical unit","value":"72.35 mL"}]	[{"type":"physical unit","value":"Temperature1 [OF] water [=] \\pu{18.2 ℃}"},{"type":"physical unit","value":"Volume2 [OF] water [=] \\pu{33.5 mL}"},{"type":"physical unit","value":"Temperature2 [OF] water [=] \\pu{35.0 ℃}"},{"type":"physical unit","value":"Temperature3 [OF] water [=] \\pu{23.5 ℃}"}]	<h1 class="questionTitle" itemprop="name">An unknown volume of water at 18.2°C is added to 33.5 mL of water at 35.0°C. If the final temperature is 23.5°C, what was the unknown volume?</h1>	null	72.35 mL	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Before doing any calculations, try to predict what you would <em>expect</em> the answer to be. </p> <p>Notice that the final temperature is <strong>closer</strong> to the temperature of the <em>colder</em> water sample than it is to the temperature of the <em>warmer</em> sample. </p> <p>This means that you can expect the volume of the colder sample to be <strong>bigger</strong> than that of the warmer sample. </p> <p>Now, you will need to use the <a href="http://socratic.org/chemistry/measurement-in-chemistry/density">density</a> of water to determine the mass of the warmer water sample. You can find the density of water at different temperature here</p> <p><a href="http://antoine.frostburg.edu/chem/senese/javascript/water-density.html" rel="nofollow" target="_blank">http://antoine.frostburg.edu/chem/senese/javascript/water-density.html</a></p> <p>So, at <mathjax>#35.0^@"C"#</mathjax>, water has a density of approximately <mathjax>#"0.994 g/mL"#</mathjax>. This means that the warmer sample has a mass of </p> <blockquote> <p><mathjax>#33.5color(red)(cancel(color(black)("mL"))) * "0.994 g"/(1color(red)(cancel(color(black)("mL")))) = "33.3 g"#</mathjax></p> </blockquote> <p>Now, your tool of choice will be the equation that establishes a relationship between heat gained or lost and change in temperature</p> <blockquote> <p><mathjax>#color(blue)(q = m * c * DeltaT)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#q#</mathjax> - the amount of heat <br/> <mathjax>#m#</mathjax> - the mass of the sample<br/> <mathjax>#c#</mathjax> - its <a href="http://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a>, in your case equal to <mathjax>#4.18"J"/("g" ""^@"C")#</mathjax><br/> <mathjax>#DeltaT#</mathjax> - the change in temperature, defined s <em>final temperature</em> minus <em>initial temperature</em></p> <p>The key to this problem is the fact that the heat <strong>lost</strong> by the warmer sample will be <strong>equal to</strong> the heat <strong>gained</strong> by the colder sample. </p> <blockquote> <p><mathjax>#-q_"lost" = q_"gained"#</mathjax> </p> <p><mathjax>#-m_"cold" * color(red)(cancel(color(black)(c))) * DeltaT_"cold" = m_"warm" * color(red)(cancel(color(black)(c))) * DeltaT_"warm"#</mathjax></p> <p><mathjax>#m_"cold" = -(DeltaT_"warm")/(DeltaT_"cold") * m_"warm"#</mathjax></p> </blockquote> <p>The minus sign is needed because <em>heat lost</em> carries a negative sign as well. </p> <p>Plug in your values into the above equation and solve for <mathjax>#m_"cold"#</mathjax></p> <blockquote> <p><mathjax>#m_"cold" = -( (23.5 - 35.0)color(red)(cancel(color(black)(""^@"C"))))/((23.5 - 18.2)color(red)(cancel(color(black)(""^@"C")))) * "33.3 g"#</mathjax></p> <p><mathjax>#m_"cold" = 2.1698 * "33.3 g" = "72.25 g"#</mathjax></p> </blockquote> <p>To get he <em>volume</em> of the colder sample, use water's density at <mathjax>#18.2^@"C"#</mathjax>, which is approximately <mathjax>#"0.99856 g/mL"#</mathjax></p> <blockquote> <p><mathjax>#72.25color(red)(cancel(color(black)("g"))) * "1 mL"/(0.99856color(red)(cancel(color(black)("g")))) = "72.353 mL"#</mathjax></p> </blockquote> <p>Rounded to three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the answer will be </p> <blockquote> <p><mathjax>#V_"cold" = color(green)("72.4 mL")#</mathjax></p> </blockquote> <p>Indeed, the initial prediction turned out to be correct, the volume of the colder sample was indeed <em>bigger</em> than that of the warmer sample. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"72.4 mL"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Before doing any calculations, try to predict what you would <em>expect</em> the answer to be. </p> <p>Notice that the final temperature is <strong>closer</strong> to the temperature of the <em>colder</em> water sample than it is to the temperature of the <em>warmer</em> sample. </p> <p>This means that you can expect the volume of the colder sample to be <strong>bigger</strong> than that of the warmer sample. </p> <p>Now, you will need to use the <a href="http://socratic.org/chemistry/measurement-in-chemistry/density">density</a> of water to determine the mass of the warmer water sample. You can find the density of water at different temperature here</p> <p><a href="http://antoine.frostburg.edu/chem/senese/javascript/water-density.html" rel="nofollow" target="_blank">http://antoine.frostburg.edu/chem/senese/javascript/water-density.html</a></p> <p>So, at <mathjax>#35.0^@"C"#</mathjax>, water has a density of approximately <mathjax>#"0.994 g/mL"#</mathjax>. This means that the warmer sample has a mass of </p> <blockquote> <p><mathjax>#33.5color(red)(cancel(color(black)("mL"))) * "0.994 g"/(1color(red)(cancel(color(black)("mL")))) = "33.3 g"#</mathjax></p> </blockquote> <p>Now, your tool of choice will be the equation that establishes a relationship between heat gained or lost and change in temperature</p> <blockquote> <p><mathjax>#color(blue)(q = m * c * DeltaT)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#q#</mathjax> - the amount of heat <br/> <mathjax>#m#</mathjax> - the mass of the sample<br/> <mathjax>#c#</mathjax> - its <a href="http://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a>, in your case equal to <mathjax>#4.18"J"/("g" ""^@"C")#</mathjax><br/> <mathjax>#DeltaT#</mathjax> - the change in temperature, defined s <em>final temperature</em> minus <em>initial temperature</em></p> <p>The key to this problem is the fact that the heat <strong>lost</strong> by the warmer sample will be <strong>equal to</strong> the heat <strong>gained</strong> by the colder sample. </p> <blockquote> <p><mathjax>#-q_"lost" = q_"gained"#</mathjax> </p> <p><mathjax>#-m_"cold" * color(red)(cancel(color(black)(c))) * DeltaT_"cold" = m_"warm" * color(red)(cancel(color(black)(c))) * DeltaT_"warm"#</mathjax></p> <p><mathjax>#m_"cold" = -(DeltaT_"warm")/(DeltaT_"cold") * m_"warm"#</mathjax></p> </blockquote> <p>The minus sign is needed because <em>heat lost</em> carries a negative sign as well. </p> <p>Plug in your values into the above equation and solve for <mathjax>#m_"cold"#</mathjax></p> <blockquote> <p><mathjax>#m_"cold" = -( (23.5 - 35.0)color(red)(cancel(color(black)(""^@"C"))))/((23.5 - 18.2)color(red)(cancel(color(black)(""^@"C")))) * "33.3 g"#</mathjax></p> <p><mathjax>#m_"cold" = 2.1698 * "33.3 g" = "72.25 g"#</mathjax></p> </blockquote> <p>To get he <em>volume</em> of the colder sample, use water's density at <mathjax>#18.2^@"C"#</mathjax>, which is approximately <mathjax>#"0.99856 g/mL"#</mathjax></p> <blockquote> <p><mathjax>#72.25color(red)(cancel(color(black)("g"))) * "1 mL"/(0.99856color(red)(cancel(color(black)("g")))) = "72.353 mL"#</mathjax></p> </blockquote> <p>Rounded to three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the answer will be </p> <blockquote> <p><mathjax>#V_"cold" = color(green)("72.4 mL")#</mathjax></p> </blockquote> <p>Indeed, the initial prediction turned out to be correct, the volume of the colder sample was indeed <em>bigger</em> than that of the warmer sample. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">An unknown volume of water at 18.2°C is added to 33.5 mL of water at 35.0°C. If the final temperature is 23.5°C, what was the unknown volume?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/calorimetry" itemprop="url"> <span class="breadcrumb" itemprop="title">Calorimetry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="189760" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-17T13:04:28" itemprop="dateCreated"> Nov 17, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"72.4 mL"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Before doing any calculations, try to predict what you would <em>expect</em> the answer to be. </p> <p>Notice that the final temperature is <strong>closer</strong> to the temperature of the <em>colder</em> water sample than it is to the temperature of the <em>warmer</em> sample. </p> <p>This means that you can expect the volume of the colder sample to be <strong>bigger</strong> than that of the warmer sample. </p> <p>Now, you will need to use the <a href="http://socratic.org/chemistry/measurement-in-chemistry/density">density</a> of water to determine the mass of the warmer water sample. You can find the density of water at different temperature here</p> <p><a href="http://antoine.frostburg.edu/chem/senese/javascript/water-density.html" rel="nofollow" target="_blank">http://antoine.frostburg.edu/chem/senese/javascript/water-density.html</a></p> <p>So, at <mathjax>#35.0^@"C"#</mathjax>, water has a density of approximately <mathjax>#"0.994 g/mL"#</mathjax>. This means that the warmer sample has a mass of </p> <blockquote> <p><mathjax>#33.5color(red)(cancel(color(black)("mL"))) * "0.994 g"/(1color(red)(cancel(color(black)("mL")))) = "33.3 g"#</mathjax></p> </blockquote> <p>Now, your tool of choice will be the equation that establishes a relationship between heat gained or lost and change in temperature</p> <blockquote> <p><mathjax>#color(blue)(q = m * c * DeltaT)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#q#</mathjax> - the amount of heat <br/> <mathjax>#m#</mathjax> - the mass of the sample<br/> <mathjax>#c#</mathjax> - its <a href="http://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a>, in your case equal to <mathjax>#4.18"J"/("g" ""^@"C")#</mathjax><br/> <mathjax>#DeltaT#</mathjax> - the change in temperature, defined s <em>final temperature</em> minus <em>initial temperature</em></p> <p>The key to this problem is the fact that the heat <strong>lost</strong> by the warmer sample will be <strong>equal to</strong> the heat <strong>gained</strong> by the colder sample. </p> <blockquote> <p><mathjax>#-q_"lost" = q_"gained"#</mathjax> </p> <p><mathjax>#-m_"cold" * color(red)(cancel(color(black)(c))) * DeltaT_"cold" = m_"warm" * color(red)(cancel(color(black)(c))) * DeltaT_"warm"#</mathjax></p> <p><mathjax>#m_"cold" = -(DeltaT_"warm")/(DeltaT_"cold") * m_"warm"#</mathjax></p> </blockquote> <p>The minus sign is needed because <em>heat lost</em> carries a negative sign as well. </p> <p>Plug in your values into the above equation and solve for <mathjax>#m_"cold"#</mathjax></p> <blockquote> <p><mathjax>#m_"cold" = -( (23.5 - 35.0)color(red)(cancel(color(black)(""^@"C"))))/((23.5 - 18.2)color(red)(cancel(color(black)(""^@"C")))) * "33.3 g"#</mathjax></p> <p><mathjax>#m_"cold" = 2.1698 * "33.3 g" = "72.25 g"#</mathjax></p> </blockquote> <p>To get he <em>volume</em> of the colder sample, use water's density at <mathjax>#18.2^@"C"#</mathjax>, which is approximately <mathjax>#"0.99856 g/mL"#</mathjax></p> <blockquote> <p><mathjax>#72.25color(red)(cancel(color(black)("g"))) * "1 mL"/(0.99856color(red)(cancel(color(black)("g")))) = "72.353 mL"#</mathjax></p> </blockquote> <p>Rounded to three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the answer will be </p> <blockquote> <p><mathjax>#V_"cold" = color(green)("72.4 mL")#</mathjax></p> </blockquote> <p>Indeed, the initial prediction turned out to be correct, the volume of the colder sample was indeed <em>bigger</em> than that of the warmer sample. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/189760" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-differential-scanning-in-calorimetry-work"> How does differential scanning in calorimetry work? 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If the final temperature is 23.5°C, what was the unknown volume?	null
2,449	aadf48e2-6ddd-11ea-8c8d-ccda262736ce	https://socratic.org/questions/how-many-grams-of-cacl-2-can-dissolve-in-200-g-of-water-at-10-c	128 grams	start physical_unit 4 4 mass g qc_end physical_unit 11 11 8 9 mass qc_end physical_unit 11 11 13 14 temperature qc_end end	[{"type":"physical unit","value":"Mass [OF] CaCl2 [IN] grams"}]	[{"type":"physical unit","value":"128 grams"}]	[{"type":"physical unit","value":"Mass [OF] water [=] \\pu{200 g}"},{"type":"physical unit","value":"Temperature [OF] water [=] \\pu{10 ℃}"}]	<h1 class="questionTitle" itemprop="name">How many grams of #CaCl_2# can dissolve in 200 g of water at 10°C?</h1>	null	128 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You will need to refer to a <em>solubility curve graph</em>, which indicates how much of each <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> will dissolve in <mathjax>#100"g"#</mathjax> water at indicated temperatures. A typical one looks like this:</p> <blockquote></blockquote> <p><img alt="enter image source here" src="https://useruploads.socratic.org/WPDSk2KeT6Oh3ExhJN1G_solubility.gif"/> </p> <p>We need to look at how much <mathjax>#"CaCl"_2#</mathjax> will dissolve in <mathjax>#100"g" "H"_2"O"#</mathjax> at <mathjax>#10^oC#</mathjax>. </p> <p>From the graph, the point of intersection between the <mathjax>#"CaCl"_2#</mathjax> curve (the orange line) and the <mathjax>#10^oC#</mathjax> line appears to occur at the point of roughly <mathjax>#64"g"#</mathjax> per <mathjax>#100"g"H_2O#</mathjax></p> <p>This means that at <mathjax>#10^oC#</mathjax>, <mathjax>#64"gCaCl"_2#</mathjax> will dissolve in <mathjax>#color(black)(100"gH"_2"O"#</mathjax>, but the question asks how much will dissolve in <mathjax>#color(black)(200"gH"_2"O"#</mathjax>. This can be found simply enough by doubling the solubility at <mathjax>#10^oC#</mathjax>:</p> <p><mathjax>#64"gCaCl"_2 xx 2 = 128"gCaCl"_2#</mathjax>.</p> <p>So, <mathjax>#128"gCaCl"_2#</mathjax> will dissolve in <mathjax>#200"gH"_2"O"#</mathjax> at <mathjax>#10^oC#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#128"gCaCl"_2#</mathjax> per <mathjax>#200"gH"_2"O"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You will need to refer to a <em>solubility curve graph</em>, which indicates how much of each <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> will dissolve in <mathjax>#100"g"#</mathjax> water at indicated temperatures. A typical one looks like this:</p> <blockquote></blockquote> <p><img alt="enter image source here" src="https://useruploads.socratic.org/WPDSk2KeT6Oh3ExhJN1G_solubility.gif"/> </p> <p>We need to look at how much <mathjax>#"CaCl"_2#</mathjax> will dissolve in <mathjax>#100"g" "H"_2"O"#</mathjax> at <mathjax>#10^oC#</mathjax>. </p> <p>From the graph, the point of intersection between the <mathjax>#"CaCl"_2#</mathjax> curve (the orange line) and the <mathjax>#10^oC#</mathjax> line appears to occur at the point of roughly <mathjax>#64"g"#</mathjax> per <mathjax>#100"g"H_2O#</mathjax></p> <p>This means that at <mathjax>#10^oC#</mathjax>, <mathjax>#64"gCaCl"_2#</mathjax> will dissolve in <mathjax>#color(black)(100"gH"_2"O"#</mathjax>, but the question asks how much will dissolve in <mathjax>#color(black)(200"gH"_2"O"#</mathjax>. This can be found simply enough by doubling the solubility at <mathjax>#10^oC#</mathjax>:</p> <p><mathjax>#64"gCaCl"_2 xx 2 = 128"gCaCl"_2#</mathjax>.</p> <p>So, <mathjax>#128"gCaCl"_2#</mathjax> will dissolve in <mathjax>#200"gH"_2"O"#</mathjax> at <mathjax>#10^oC#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many grams of #CaCl_2# can dissolve in 200 g of water at 10°C?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/solution-formation---what-happens-when-stuff-dissolves" itemprop="url"> <span class="breadcrumb" itemprop="title">Solution Formation</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="428475" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/mrtas"><img alt="" class="" src="https://profilepictures.socratic.org/HY14X7r4S6AyDQgK2gwQ_IMG_0062.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/mrtas"> Nathan L. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-23T16:57:55" itemprop="dateCreated"> May 23, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#128"gCaCl"_2#</mathjax> per <mathjax>#200"gH"_2"O"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You will need to refer to a <em>solubility curve graph</em>, which indicates how much of each <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> will dissolve in <mathjax>#100"g"#</mathjax> water at indicated temperatures. A typical one looks like this:</p> <blockquote></blockquote> <p><img alt="enter image source here" src="https://useruploads.socratic.org/WPDSk2KeT6Oh3ExhJN1G_solubility.gif"/> </p> <p>We need to look at how much <mathjax>#"CaCl"_2#</mathjax> will dissolve in <mathjax>#100"g" "H"_2"O"#</mathjax> at <mathjax>#10^oC#</mathjax>. </p> <p>From the graph, the point of intersection between the <mathjax>#"CaCl"_2#</mathjax> curve (the orange line) and the <mathjax>#10^oC#</mathjax> line appears to occur at the point of roughly <mathjax>#64"g"#</mathjax> per <mathjax>#100"g"H_2O#</mathjax></p> <p>This means that at <mathjax>#10^oC#</mathjax>, <mathjax>#64"gCaCl"_2#</mathjax> will dissolve in <mathjax>#color(black)(100"gH"_2"O"#</mathjax>, but the question asks how much will dissolve in <mathjax>#color(black)(200"gH"_2"O"#</mathjax>. This can be found simply enough by doubling the solubility at <mathjax>#10^oC#</mathjax>:</p> <p><mathjax>#64"gCaCl"_2 xx 2 = 128"gCaCl"_2#</mathjax>.</p> <p>So, <mathjax>#128"gCaCl"_2#</mathjax> will dissolve in <mathjax>#200"gH"_2"O"#</mathjax> at <mathjax>#10^oC#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/428475" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-temperature-affect-the-formation-of-a-solution"> How can temperature affect the formation of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-formation-of-a-solution-be-exothermic-or-endothermic"> How can the formation of a solution be exothermic or endothermic? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-formation-of-a-solution-involve-energy"> How does the formation of a solution involve energy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-heat-formation-of-solution"> How do you find heat of formation of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-factor-promotes-the-formation-of-solutions"> Which factors promote the formation of solutions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/which-two-processes-are-at-equilibrium-in-a-saturated-sugar-solution"> Which two processes are at equilibrium in a saturated sugar solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-solutes-lower-the-freezing-point"> Why do solutes lower the freezing point? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-does-solution-formation-require-energy"> Why does solution formation require energy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-solutes-dissolve-in-solvents"> Why do solutes dissolve in solvents? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-solvent-dissolves-silicone"> What solvent dissolves silicone? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/solution-formation---what-happens-when-stuff-dissolves"> See all questions in Solution Formation </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 14729 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many grams of #CaCl_2# can dissolve in 200 g of water at 10°C?	null
2,450	ab5478a3-6ddd-11ea-9b61-ccda262736ce	https://socratic.org/questions/a-sample-of-hydrogen-exerts-a-pressure-of-1-50-atmospheres-at-a-temperature-of-1	6.00 atm	start physical_unit 19 20 pressure atm qc_end physical_unit 1 3 8 9 pressure qc_end physical_unit 1 3 14 15 temperature qc_end physical_unit 19 20 23 24 temperature qc_end end	[{"type":"physical unit","value":"Pressure2 [OF] the gas [IN] atm"}]	[{"type":"physical unit","value":"6.00 atm"}]	[{"type":"physical unit","value":"Pressure1 [OF] hydrogen sample [=] \\pu{1.50 atmospheres}"},{"type":"physical unit","value":"Temperature1 [OF] hydrogen sample [=] \\pu{160 K}"},{"type":"physical unit","value":"Temperature2 [OF] the gas [=] \\pu{640 K}"}]	<h1 class="questionTitle" itemprop="name">A sample of hydrogen exerts a pressure of 1.50 atmospheres at a temperature of 160 K. What pressure does the gas exert at 640 K? </h1>	null	6.00 atm	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The volume is not given, so I assume it remains unchanged.</p> <p>To calculate the new pressure you use the following equality:</p> <h2><mathjax>#(pxxV)/T=const#</mathjax></h2> <p>So here we have:</p> <p><mathjax>#(p_1xxV)/T_1=(p_2xxV)/T_2#</mathjax> </p> <p>We can divide both sides of the equation by <mathjax>#V#</mathjax></p> <p><mathjax>#p_1/T_1=p_2/T_2#</mathjax></p> <p>From this proportion we calculate that:</p> <h2><mathjax>#p_2=(p_1xxT_2)/T_1#</mathjax></h2> <p>If we substitute the given values we get:</p> <h2><mathjax>#p_2=(1.5xx640)/160#</mathjax></h2> <p><mathjax>#p_2==960/160=96/16=12/2=6#</mathjax></p> <p>Answer: <strong>The new pressure is <mathjax>#6#</mathjax> atmospheres</strong></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The pressure will be <mathjax>#6#</mathjax> atmospheres. see explanation.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The volume is not given, so I assume it remains unchanged.</p> <p>To calculate the new pressure you use the following equality:</p> <h2><mathjax>#(pxxV)/T=const#</mathjax></h2> <p>So here we have:</p> <p><mathjax>#(p_1xxV)/T_1=(p_2xxV)/T_2#</mathjax> </p> <p>We can divide both sides of the equation by <mathjax>#V#</mathjax></p> <p><mathjax>#p_1/T_1=p_2/T_2#</mathjax></p> <p>From this proportion we calculate that:</p> <h2><mathjax>#p_2=(p_1xxT_2)/T_1#</mathjax></h2> <p>If we substitute the given values we get:</p> <h2><mathjax>#p_2=(1.5xx640)/160#</mathjax></h2> <p><mathjax>#p_2==960/160=96/16=12/2=6#</mathjax></p> <p>Answer: <strong>The new pressure is <mathjax>#6#</mathjax> atmospheres</strong></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A sample of hydrogen exerts a pressure of 1.50 atmospheres at a temperature of 160 K. What pressure does the gas exert at 640 K? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/gas-pressure" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Pressure</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="408671" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/daniel-l-3"><img alt="" class="" src="https://graph.facebook.com/100001647465264/picture?height=50&width=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/daniel-l-3"> Daniel L. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-18T12:11:32" itemprop="dateCreated"> Apr 18, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The pressure will be <mathjax>#6#</mathjax> atmospheres. see explanation.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The volume is not given, so I assume it remains unchanged.</p> <p>To calculate the new pressure you use the following equality:</p> <h2><mathjax>#(pxxV)/T=const#</mathjax></h2> <p>So here we have:</p> <p><mathjax>#(p_1xxV)/T_1=(p_2xxV)/T_2#</mathjax> </p> <p>We can divide both sides of the equation by <mathjax>#V#</mathjax></p> <p><mathjax>#p_1/T_1=p_2/T_2#</mathjax></p> <p>From this proportion we calculate that:</p> <h2><mathjax>#p_2=(p_1xxT_2)/T_1#</mathjax></h2> <p>If we substitute the given values we get:</p> <h2><mathjax>#p_2=(1.5xx640)/160#</mathjax></h2> <p><mathjax>#p_2==960/160=96/16=12/2=6#</mathjax></p> <p>Answer: <strong>The new pressure is <mathjax>#6#</mathjax> atmospheres</strong></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/408671" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-gas-pressure-be-changed"> How can gas pressure be changed? 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What volume will it occupy if the... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/gas-pressure"> See all questions in Gas Pressure </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2431 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A sample of hydrogen exerts a pressure of 1.50 atmospheres at a temperature of 160 K. What pressure does the gas exert at 640 K?	null
2,451	ac0f01c9-6ddd-11ea-bb64-ccda262736ce	https://socratic.org/questions/how-many-grams-of-carbon-tetrafluoride-cf-4-are-produced-from-the-complete-react	128 grams	start physical_unit 6 6 mass g qc_end physical_unit 4 4 14 15 mole qc_end c_other OTHER qc_end chemical_equation 21 26 qc_end end	[{"type":"physical unit","value":"Mass [OF] CF4 [IN] grams"}]	[{"type":"physical unit","value":"128 grams"}]	[{"type":"physical unit","value":"Mole [OF] carbon [=] \\pu{1.46 moles}"},{"type":"other","value":"Complete reaction."},{"type":"chemical equation","value":"C + 2 F2 -> CF4"}]	<h1 class="questionTitle" itemprop="name">How many grams of carbon tetrafluoride, #CF_4#, are produced from the complete reaction of 1.46 moles of carbon in the reaction #C+2F_2 -> CF_4#?</h1>	null	128 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#n("CF"_4)=n("C") = 1.46mol#</mathjax><br/> <mathjax>#M("CF"_4)=(1xx12+4xx19)gmol^-1 = 88gmol^-1#</mathjax><br/> <mathjax>#m("CF"_4)=nM = 1.46molxx88gmol^-1 = 128g#</mathjax> (3s.f)</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>128g</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#n("CF"_4)=n("C") = 1.46mol#</mathjax><br/> <mathjax>#M("CF"_4)=(1xx12+4xx19)gmol^-1 = 88gmol^-1#</mathjax><br/> <mathjax>#m("CF"_4)=nM = 1.46molxx88gmol^-1 = 128g#</mathjax> (3s.f)</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many grams of carbon tetrafluoride, #CF_4#, are produced from the complete reaction of 1.46 moles of carbon in the reaction #C+2F_2 -> CF_4#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="284504" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/glowing-grasshopper"><img alt="" class="" src="https://lh6.googleusercontent.com/-yAnywTuHSxk/AAAAAAAAAAI/AAAAAAAAAFI/pNn-rdsyXQk/photo.jpg?sz=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/glowing-grasshopper"> Cameron G. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-04T06:10:42" itemprop="dateCreated"> Jul 4, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>128g</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#n("CF"_4)=n("C") = 1.46mol#</mathjax><br/> <mathjax>#M("CF"_4)=(1xx12+4xx19)gmol^-1 = 88gmol^-1#</mathjax><br/> <mathjax>#m("CF"_4)=nM = 1.46molxx88gmol^-1 = 128g#</mathjax> (3s.f)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/284504" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? 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2,452	acb2e558-6ddd-11ea-b983-ccda262736ce	https://socratic.org/questions/a-4-08-g-sample-of-a-compound-of-nitrogen-and-oxygen-contains-3-02-g-of-oxygen-w	N4O	start chemical_formula qc_end c_other OTHER qc_end physical_unit 6 6 1 2 mass qc_end physical_unit 10 10 12 13 mass qc_end end	[{"type":"other","value":"Chemical Formula [OF] the compound [IN] empirical"}]	[{"type":"chemical equation","value":"N4O"}]	[{"type":"other","value":"A sample of a compound of nitrogen and oxygen."},{"type":"physical unit","value":"Mass [OF] the compound sample [=] \\pu{4.08 g}"},{"type":"physical unit","value":"Mass [OF] oxygen [=] \\pu{3.02 g}"}]	<h1 class="questionTitle" itemprop="name">A 4.08 g sample of a compound of nitrogen and oxygen contains 3.02 g of oxygen. What is the empirical formula? </h1>	null	N4O	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>An empirical formula is the lowest whole number ratio of <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> in a compound. Each ratio will be the subscript of each element.</p> <p><strong>Determine the mass of each element in grams.</strong></p> <p><mathjax>#"N":#</mathjax> <mathjax>#"4.08 g"-"3.02g"="1.06 g"#</mathjax></p> <p><mathjax>#"O":#</mathjax> <mathjax>#"3.02 g"#</mathjax> (given)</p> <p><strong>Determine moles of each element by dividing the mass of each element by its molar mass (atomic weight on <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a> in g/mol.</strong></p> <p><mathjax>#"N":#</mathjax> <mathjax>#"1.06 g N"/"14.007 g/mol"="0.0756764 mol N"#</mathjax></p> <p><mathjax>#"O":#</mathjax> <mathjax>#"3.02 g O"/"15.999 g/mol"="0.188761 mol O"#</mathjax></p> <p><strong>Determine <a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratios</a> by dividing the moles of each element by the least number of moles.</strong></p> <p><mathjax>#"N":#</mathjax> <mathjax>#"0.0756764 mol"/"0.188761 mol"="4.01"~~4#</mathjax></p> <p><mathjax>#"O":#</mathjax> <mathjax>#"0.188761 mol"/"0.188761"=1.00=1#</mathjax></p> <p>The <strong>empirical formula</strong> is <mathjax>#"N"_4"O"#</mathjax>.</p> <p>The compound with this formula is called nitrosylazide with the following structure.</p> <p><img alt="https://en.m.wikipedia.org/wiki/Nitrosylazide" src="https://useruploads.socratic.org/QQ95o0LqQwlKjXGPKdNE_200px-Nitrosylazide.png"/> </p> <p>For more examples of this type of empirical formula problem, check out the following website: <a href="http://www.chemteam.info/Mole/Emp-formula-given-mass-data.html" rel="nofollow" target="_blank">http://www.chemteam.info/Mole/Emp-formula-given-mass-data.html</a></p> <p>For examples of determining an empirical formula from <a href="https://socratic.org/chemistry/the-mole-concept/percent-composition">percent composition</a>, check out this website: <a href="https://www.chem.tamu.edu/class/majors/tutorialnotefiles/empirical.htm" rel="nofollow" target="_blank">https://www.chem.tamu.edu/class/majors/tutorialnotefiles/empirical.htm</a></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The empirical formula is <mathjax>#"N"_4"O"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>An empirical formula is the lowest whole number ratio of <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> in a compound. Each ratio will be the subscript of each element.</p> <p><strong>Determine the mass of each element in grams.</strong></p> <p><mathjax>#"N":#</mathjax> <mathjax>#"4.08 g"-"3.02g"="1.06 g"#</mathjax></p> <p><mathjax>#"O":#</mathjax> <mathjax>#"3.02 g"#</mathjax> (given)</p> <p><strong>Determine moles of each element by dividing the mass of each element by its molar mass (atomic weight on <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a> in g/mol.</strong></p> <p><mathjax>#"N":#</mathjax> <mathjax>#"1.06 g N"/"14.007 g/mol"="0.0756764 mol N"#</mathjax></p> <p><mathjax>#"O":#</mathjax> <mathjax>#"3.02 g O"/"15.999 g/mol"="0.188761 mol O"#</mathjax></p> <p><strong>Determine <a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratios</a> by dividing the moles of each element by the least number of moles.</strong></p> <p><mathjax>#"N":#</mathjax> <mathjax>#"0.0756764 mol"/"0.188761 mol"="4.01"~~4#</mathjax></p> <p><mathjax>#"O":#</mathjax> <mathjax>#"0.188761 mol"/"0.188761"=1.00=1#</mathjax></p> <p>The <strong>empirical formula</strong> is <mathjax>#"N"_4"O"#</mathjax>.</p> <p>The compound with this formula is called nitrosylazide with the following structure.</p> <p><img alt="https://en.m.wikipedia.org/wiki/Nitrosylazide" src="https://useruploads.socratic.org/QQ95o0LqQwlKjXGPKdNE_200px-Nitrosylazide.png"/> </p> <p>For more examples of this type of empirical formula problem, check out the following website: <a href="http://www.chemteam.info/Mole/Emp-formula-given-mass-data.html" rel="nofollow" target="_blank">http://www.chemteam.info/Mole/Emp-formula-given-mass-data.html</a></p> <p>For examples of determining an empirical formula from <a href="https://socratic.org/chemistry/the-mole-concept/percent-composition">percent composition</a>, check out this website: <a href="https://www.chem.tamu.edu/class/majors/tutorialnotefiles/empirical.htm" rel="nofollow" target="_blank">https://www.chem.tamu.edu/class/majors/tutorialnotefiles/empirical.htm</a></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A 4.08 g sample of a compound of nitrogen and oxygen contains 3.02 g of oxygen. What is the empirical formula? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="292761" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-28T02:03:12" itemprop="dateCreated"> Jul 28, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The empirical formula is <mathjax>#"N"_4"O"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>An empirical formula is the lowest whole number ratio of <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> in a compound. Each ratio will be the subscript of each element.</p> <p><strong>Determine the mass of each element in grams.</strong></p> <p><mathjax>#"N":#</mathjax> <mathjax>#"4.08 g"-"3.02g"="1.06 g"#</mathjax></p> <p><mathjax>#"O":#</mathjax> <mathjax>#"3.02 g"#</mathjax> (given)</p> <p><strong>Determine moles of each element by dividing the mass of each element by its molar mass (atomic weight on <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a> in g/mol.</strong></p> <p><mathjax>#"N":#</mathjax> <mathjax>#"1.06 g N"/"14.007 g/mol"="0.0756764 mol N"#</mathjax></p> <p><mathjax>#"O":#</mathjax> <mathjax>#"3.02 g O"/"15.999 g/mol"="0.188761 mol O"#</mathjax></p> <p><strong>Determine <a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratios</a> by dividing the moles of each element by the least number of moles.</strong></p> <p><mathjax>#"N":#</mathjax> <mathjax>#"0.0756764 mol"/"0.188761 mol"="4.01"~~4#</mathjax></p> <p><mathjax>#"O":#</mathjax> <mathjax>#"0.188761 mol"/"0.188761"=1.00=1#</mathjax></p> <p>The <strong>empirical formula</strong> is <mathjax>#"N"_4"O"#</mathjax>.</p> <p>The compound with this formula is called nitrosylazide with the following structure.</p> <p><img alt="https://en.m.wikipedia.org/wiki/Nitrosylazide" src="https://useruploads.socratic.org/QQ95o0LqQwlKjXGPKdNE_200px-Nitrosylazide.png"/> </p> <p>For more examples of this type of empirical formula problem, check out the following website: <a href="http://www.chemteam.info/Mole/Emp-formula-given-mass-data.html" rel="nofollow" target="_blank">http://www.chemteam.info/Mole/Emp-formula-given-mass-data.html</a></p> <p>For examples of determining an empirical formula from <a href="https://socratic.org/chemistry/the-mole-concept/percent-composition">percent composition</a>, check out this website: <a href="https://www.chem.tamu.edu/class/majors/tutorialnotefiles/empirical.htm" rel="nofollow" target="_blank">https://www.chem.tamu.edu/class/majors/tutorialnotefiles/empirical.htm</a></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/292761" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? 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What is the empirical formula?	null
2,453	aa447cac-6ddd-11ea-b54e-ccda262736ce	https://socratic.org/questions/58edf627b72cff4467cf9901	11.17 M	start physical_unit 7 7 molarity mol/l qc_end physical_unit 7 7 5 5 w/w qc_end end	[{"type":"physical unit","value":"Molarity [OF] HNO3 [IN] M"}]	[{"type":"physical unit","value":"11.17 M"}]	[{"type":"physical unit","value":"w/w [OF] HNO3 [=] \\pu{53%}"}]	<h1 class="questionTitle" itemprop="name">What is the molarity of #53%"w/w"# #"HNO"_3#?</h1>	null	11.17 M	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The concentration is the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a>, except that molarity is in decimal form.</p> <p>Molarity, <mathjax>#c#</mathjax>, is defined as <mathjax>#c=n/V#</mathjax>, where <mathjax>#n#</mathjax> is the moles of the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> and <mathjax>#V#</mathjax> the volume of solution.</p> <p>Here, the molarity will be <mathjax>#0.53#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#M=0.53#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The concentration is the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a>, except that molarity is in decimal form.</p> <p>Molarity, <mathjax>#c#</mathjax>, is defined as <mathjax>#c=n/V#</mathjax>, where <mathjax>#n#</mathjax> is the moles of the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> and <mathjax>#V#</mathjax> the volume of solution.</p> <p>Here, the molarity will be <mathjax>#0.53#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the molarity of #53%"w/w"# #"HNO"_3#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="546210" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/surya-k-2"><img alt="" class="" src="https://profilepictures.socratic.org/g84xu6vTUmSnPW2MqvuP_phi-symbol-1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/surya-k-2"> Surya K. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-02-04T05:28:07" itemprop="dateCreated"> Feb 4, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#M=0.53#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The concentration is the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a>, except that molarity is in decimal form.</p> <p>Molarity, <mathjax>#c#</mathjax>, is defined as <mathjax>#c=n/V#</mathjax>, where <mathjax>#n#</mathjax> is the moles of the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> and <mathjax>#V#</mathjax> the volume of solution.</p> <p>Here, the molarity will be <mathjax>#0.53#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/546210" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="561012" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/truong-son-n"><img alt="" class="" src="https://profilepictures.socratic.org/07k4plnQfmnmzMuesQzw_14844-1449381920.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/truong-son-n"> Truong-Son N. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-03-01T21:02:32" itemprop="dateCreated"> Mar 1, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerDescription"> <div> <div class="markdown"><p>I'm getting a bit over <mathjax>#"11 M"#</mathjax>.</p> <hr/> <p>You have</p> <blockquote> <p><mathjax>#"53 g HNO"_3/("100 g solution")#</mathjax></p> </blockquote> <p>And at <mathjax>#20^@ "C"#</mathjax>, <a href="http://www.handymath.com/cgi-bin/nitrictble2.cgi?submit=Entry" rel="nofollow">it has density of <mathjax>#"1.3278 g/mL"#</mathjax>.</a> Therefore, this has a volume of:</p> <blockquote> <p><mathjax>#100 cancel"g solution" xx "1 mL"/(1.3278 cancel"g soln") = "75.31 mL"#</mathjax></p> <p><mathjax>#=#</mathjax> <mathjax>#"0.07531 L"#</mathjax></p> </blockquote> <p>As a result, this has a <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of:</p> <blockquote> <p><mathjax>#color(blue)(["HNO"_3]_(53%)) = (53 cancel"g" xx "1 mol"/(63.0119 cancel("g HNO"_3)))/("0.07531 L")#</mathjax></p> <p><mathjax>#~~#</mathjax> <mathjax>#color(blue)("11.17 M")#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/561012" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that 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class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1865 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the molarity of #53%"w/w"# #"HNO"_3#?	null
2,454	ac0c1777-6ddd-11ea-9db3-ccda262736ce	https://socratic.org/questions/if-the-ph-of-a-solution-is-3-437-what-is-the-hydrogen-ion-concentration-in-mol-l	3.66 × 10^(-4) mol/L	start physical_unit 11 12 concentration mol/l qc_end physical_unit 5 5 7 7 ph qc_end end	[{"type":"physical unit","value":"Concentration [OF] hydrogen ion [IN] mol/L"}]	[{"type":"physical unit","value":"3.66 × 10^(-4) mol/L"}]	[{"type":"physical unit","value":"pH [OF] the solution [=] \\pu{3.437}"}]	<h1 class="questionTitle" itemprop="name">If the pH of a solution is 3.437, what is the hydrogen ion concentration in mol/L?</h1>	null	3.66 × 10^(-4) mol/L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>........so <mathjax>#[H_3O^+]=10^(-3.437)molL^-1#</mathjax></p> <p><mathjax>#=3.656xx10^-4molL^-1#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>By definition, <mathjax>#pH=-log_10[H_3O^+]#</mathjax>............</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>........so <mathjax>#[H_3O^+]=10^(-3.437)molL^-1#</mathjax></p> <p><mathjax>#=3.656xx10^-4molL^-1#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">If the pH of a solution is 3.437, what is the hydrogen ion concentration in mol/L?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/ph-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">pH calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="368746" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-01-24T17:38:50" itemprop="dateCreated"> Jan 24, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>By definition, <mathjax>#pH=-log_10[H_3O^+]#</mathjax>............</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>........so <mathjax>#[H_3O^+]=10^(-3.437)molL^-1#</mathjax></p> <p><mathjax>#=3.656xx10^-4molL^-1#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/368746" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-of-a-solution"> How do you determine ph of a solution? 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2,455	abf695a8-6ddd-11ea-9613-ccda262736ce	https://socratic.org/questions/58d17a31b72cff5cc1cbd41c	16.00 molar	start physical_unit 4 4 mole mol/l qc_end physical_unit 4 4 9 10 mass qc_end end	[{"type":"physical unit","value":"Mole [OF] sulfur [IN] molar"}]	[{"type":"physical unit","value":"16.00 molar"}]	[{"type":"physical unit","value":"Mass [OF] sulfur [=] \\pu{512 g}"}]	<h1 class="questionTitle" itemprop="name">What molar quantity of sulfur is contained in a #512*g# mass of the element?</h1>	null	16.00 molar	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And thus there are approx. 16 moles of sulphur ATOMS. If you are using <mathjax>#S_8#</mathjax>, which is the common elemental form, then there are <mathjax>#2*mol#</mathjax> of sulfur mollykewels..............</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, what's the quotient, <mathjax>#(512g)/(32.06gmol^-1)?#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And thus there are approx. 16 moles of sulphur ATOMS. If you are using <mathjax>#S_8#</mathjax>, which is the common elemental form, then there are <mathjax>#2mol#</mathjax> of sulfur mollykewels..............</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What molar quantity of sulfur is contained in a #512g# mass of the element?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="397784" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-28T07:45:51" itemprop="dateCreated"> Mar 28, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, what's the quotient, <mathjax>#(512g)/(32.06gmol^-1)?#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And thus there are approx. 16 moles of sulphur ATOMS. If you are using <mathjax>#S_8#</mathjax>, which is the common elemental form, then there are <mathjax>#2*mol#</mathjax> of sulfur mollykewels..............</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/397784" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1063 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What molar quantity of sulfur is contained in a #512*g# mass of the element?	null
2,456	a9d16a50-6ddd-11ea-8bbc-ccda262736ce	https://socratic.org/questions/what-is-the-empirical-formula-of-a-phosphoric-acid-that-contains-0-3086-g-of-hyd	H2P4O	start chemical_formula qc_end physical_unit 14 14 11 12 mass qc_end physical_unit 18 18 15 16 mass qc_end physical_unit 23 23 20 21 mass qc_end end	[{"type":"other","value":"Chemical Formula [OF] a phosphoric acid [IN] empirical"}]	[{"type":"chemical equation","value":"H2P4O"}]	[{"type":"physical unit","value":"Mass [OF] hydrogen [=] \\pu{0.3086 g}"},{"type":"physical unit","value":"Mass [OF] phosphorus [=] \\pu{3.161 g}"},{"type":"physical unit","value":"Mass [OF] oxygen [=] \\pu{6.531 g}"}]	<h1 class="questionTitle" itemprop="name">What is the empirical formula of a phosphoric acid that contains 0.3086 g of hydrogen, 3.161 g of phosphorus, and 6.531 g of oxygen? </h1>	null	H2P4O	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to calculate the Empirical formula , we will assume that we have started with 10 g of the compound. On decomposition , we obtained 0.3086 g of Hydrogen , 3.161 g of Phosphorus, and 6.531 g of Oxygen.</p> <p><strong><em>Step 1</em> Calculating the number of moles of different <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a></strong></p> <p><mathjax>#n_#</mathjax><mathjax>#H#</mathjax>= mass of H/ molar mass of H</p> <p><mathjax>#n_#</mathjax><mathjax>#H #</mathjax>= 0.3086 g / 1 g <mathjax>#mol^(-1)#</mathjax></p> <p><mathjax>#n_#</mathjax><mathjax>#H#</mathjax>= 0.3086 mol</p> <p><strong><mathjax>#n_#</mathjax>P## = mass of P/ molar mass of P</strong></p> <p><mathjax>#n_#</mathjax>P<mathjax>#= 3.161 g / 31 g #</mathjax>mol^(-1)#</p> <p><mathjax>#n_#</mathjax><mathjax>#P#</mathjax>= 1.02 mole</p> <p><strong><mathjax>#n_#</mathjax><mathjax>#O#</mathjax> = mass of O / molar mass of O</strong></p> <p><mathjax>#n_#</mathjax><mathjax>#O#</mathjax>= 6.531 g / 32 g <mathjax>#mol^(-1)#</mathjax></p> <p><mathjax>#n_#</mathjax><mathjax>#O#</mathjax>= 0.2 mol</p> <p><strong>Calculating the Simple Ratio of the moles</strong> </p> <p>H= 0.3806/ 0.2 =4 , P = 1.02 / 0.2 =5 , O= 0.2/0.2 =1</p> <p><mathjax>#H_2#</mathjax> <mathjax># P_4#</mathjax> <mathjax>#O_1#</mathjax> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#H_2#</mathjax> <mathjax># P_4#</mathjax> <mathjax>#O_1#</mathjax> </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to calculate the Empirical formula , we will assume that we have started with 10 g of the compound. On decomposition , we obtained 0.3086 g of Hydrogen , 3.161 g of Phosphorus, and 6.531 g of Oxygen.</p> <p><strong><em>Step 1</em> Calculating the number of moles of different <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a></strong></p> <p><mathjax>#n_#</mathjax><mathjax>#H#</mathjax>= mass of H/ molar mass of H</p> <p><mathjax>#n_#</mathjax><mathjax>#H #</mathjax>= 0.3086 g / 1 g <mathjax>#mol^(-1)#</mathjax></p> <p><mathjax>#n_#</mathjax><mathjax>#H#</mathjax>= 0.3086 mol</p> <p><strong><mathjax>#n_#</mathjax>P## = mass of P/ molar mass of P</strong></p> <p><mathjax>#n_#</mathjax>P<mathjax>#= 3.161 g / 31 g #</mathjax>mol^(-1)#</p> <p><mathjax>#n_#</mathjax><mathjax>#P#</mathjax>= 1.02 mole</p> <p><strong><mathjax>#n_#</mathjax><mathjax>#O#</mathjax> = mass of O / molar mass of O</strong></p> <p><mathjax>#n_#</mathjax><mathjax>#O#</mathjax>= 6.531 g / 32 g <mathjax>#mol^(-1)#</mathjax></p> <p><mathjax>#n_#</mathjax><mathjax>#O#</mathjax>= 0.2 mol</p> <p><strong>Calculating the Simple Ratio of the moles</strong> </p> <p>H= 0.3806/ 0.2 =4 , P = 1.02 / 0.2 =5 , O= 0.2/0.2 =1</p> <p><mathjax>#H_2#</mathjax> <mathjax># P_4#</mathjax> <mathjax>#O_1#</mathjax> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the empirical formula of a phosphoric acid that contains 0.3086 g of hydrogen, 3.161 g of phosphorus, and 6.531 g of oxygen? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="260371" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/manish-b"><img alt="" class="" src="https://profilepictures.socratic.org/eW7uaERSSvtv5ff2XPxA_10203153902643748.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/manish-b"> Manish Bhardwaj </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-04-29T22:31:20" itemprop="dateCreated"> Apr 29, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#H_2#</mathjax> <mathjax># P_4#</mathjax> <mathjax>#O_1#</mathjax> </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to calculate the Empirical formula , we will assume that we have started with 10 g of the compound. On decomposition , we obtained 0.3086 g of Hydrogen , 3.161 g of Phosphorus, and 6.531 g of Oxygen.</p> <p><strong><em>Step 1</em> Calculating the number of moles of different <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a></strong></p> <p><mathjax>#n_#</mathjax><mathjax>#H#</mathjax>= mass of H/ molar mass of H</p> <p><mathjax>#n_#</mathjax><mathjax>#H #</mathjax>= 0.3086 g / 1 g <mathjax>#mol^(-1)#</mathjax></p> <p><mathjax>#n_#</mathjax><mathjax>#H#</mathjax>= 0.3086 mol</p> <p><strong><mathjax>#n_#</mathjax>P## = mass of P/ molar mass of P</strong></p> <p><mathjax>#n_#</mathjax>P<mathjax>#= 3.161 g / 31 g #</mathjax>mol^(-1)#</p> <p><mathjax>#n_#</mathjax><mathjax>#P#</mathjax>= 1.02 mole</p> <p><strong><mathjax>#n_#</mathjax><mathjax>#O#</mathjax> = mass of O / molar mass of O</strong></p> <p><mathjax>#n_#</mathjax><mathjax>#O#</mathjax>= 6.531 g / 32 g <mathjax>#mol^(-1)#</mathjax></p> <p><mathjax>#n_#</mathjax><mathjax>#O#</mathjax>= 0.2 mol</p> <p><strong>Calculating the Simple Ratio of the moles</strong> </p> <p>H= 0.3806/ 0.2 =4 , P = 1.02 / 0.2 =5 , O= 0.2/0.2 =1</p> <p><mathjax>#H_2#</mathjax> <mathjax># P_4#</mathjax> <mathjax>#O_1#</mathjax> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/260371" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molecular-formula-of-a-compound"> How do you find molecular formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-diamond"> What is the chemical formula of a diamond? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-carbohydrate"> What is the chemical formula of a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-valproic-acid"> What is the empirical formula for valproic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-of-magnesium-oxide"> What is the empirical formula of magnesium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-empirical-formula-not-double-that-of-the-monosaccharides"> Why is the empirical formula not double that of the monosaccharides? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5331180502bf342f40b5c3b5"> Question #5c3b5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-molecular-formula-represents-a-carbohydrate"> What molecular formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-of-vinegar"> What is the molecular formula of vinegar? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/empirical-and-molecular-formulas"> See all questions in Empirical and Molecular Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 12779 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the empirical formula of a phosphoric acid that contains 0.3086 g of hydrogen, 3.161 g of phosphorus, and 6.531 g of oxygen?	null
2,457	ac978e2e-6ddd-11ea-b19e-ccda262736ce	https://socratic.org/questions/what-is-the-pressure-exerted-by-32-00-g-of-oxygen-gas-in-a-20-l-container-at-30-	1.24 atm	start physical_unit 9 10 pressure atm qc_end physical_unit 9 10 6 7 mass qc_end physical_unit 9 10 13 14 volume qc_end physical_unit 9 10 17 18 temperature qc_end physical_unit 9 10 22 27 constant_r qc_end end	[{"type":"physical unit","value":"Pressure [OF] Oxygen gas [IN] atm"}]	[{"type":"physical unit","value":"1.24 atm"}]	[{"type":"physical unit","value":"Mass [OF] Oxygen gas [=] \\pu{32.00 g}"},{"type":"physical unit","value":"Volume [OF] Oxygen gas [=] \\pu{20 L}"},{"type":"physical unit","value":"Temperature [OF] Oxygen gas [=] \\pu{30.00 ℃}"},{"type":"physical unit","value":"R [OF] Oxygen gas [=] \\pu{0.0821 (L * atm)/(mol * K)}"}]	<h1 class="questionTitle" itemprop="name">What is the pressure exerted by 32.00 g of Oxygen gas in a 20. L container at 30.00 C? Use R = 0.0821 L atm/mol k?</h1>	null	1.24 atm	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First, let's determine the number of mole of oxygen gas.</p> <p>Using <mathjax>#n = frac(m)(M)#</mathjax>:</p> <p><mathjax>#Rightarrow n("O") = (frac(32.00)(2 times 15.99))#</mathjax> <mathjax>#"mol"#</mathjax></p> <p><mathjax>#Rightarrow n("O") = (frac(32.00)(31.98))#</mathjax> <mathjax>#"mol"#</mathjax></p> <p><mathjax>#therefore n("O") = 1.00#</mathjax> <mathjax>#"mol"#</mathjax></p> <p>Then, let's convert the units of the given temperature to <mathjax>#"K"#</mathjax>:</p> <p><mathjax>#Rightarrow T_((""^(@)"" "C")) = T_(("K")) - 273.15#</mathjax></p> <p><mathjax>#Rightarrow 30.00 = T_(("K")) - 273.15#</mathjax></p> <p><mathjax>#Rightarrow T_(("K")) = 303.15#</mathjax></p> <p><mathjax>#therefore 30.00#</mathjax> <mathjax>#""^(@)"" "C"#</mathjax> <mathjax>#= 303.15#</mathjax> <mathjax>#"K"#</mathjax></p> <p>Now, let's substitute all relevant values into the equation <mathjax>#P V = n R T#</mathjax>:</p> <p><mathjax>#Rightarrow P times 20.0#</mathjax> <mathjax>#"L"#</mathjax> <mathjax>#= 1.00#</mathjax> <mathjax>#"mol"#</mathjax> <mathjax>#times 0.0821#</mathjax> <mathjax>#"L atm mol"^(- 1) "K"^(- 1)#</mathjax> <mathjax>#times 303.15#</mathjax> <mathjax>#"K"#</mathjax></p> <p><mathjax>#Rightarrow P times 20.0 = 1.00 times 0.0821#</mathjax> <mathjax>#"atm"#</mathjax> <mathjax>#times 303.15#</mathjax></p> <p><mathjax>#Rightarrow P = (frac(0.0821 times 303.15)(20.0))#</mathjax> <mathjax>#"atm"#</mathjax></p> <p><mathjax>#therefore P = 1.24#</mathjax> <mathjax>#"atm"#</mathjax></p> <p>Therefore, the pressure exerted by the oxygen gas is <mathjax>#1.24#</mathjax> <mathjax>#"atm"#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1.24#</mathjax> <mathjax>#"atm"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First, let's determine the number of mole of oxygen gas.</p> <p>Using <mathjax>#n = frac(m)(M)#</mathjax>:</p> <p><mathjax>#Rightarrow n("O") = (frac(32.00)(2 times 15.99))#</mathjax> <mathjax>#"mol"#</mathjax></p> <p><mathjax>#Rightarrow n("O") = (frac(32.00)(31.98))#</mathjax> <mathjax>#"mol"#</mathjax></p> <p><mathjax>#therefore n("O") = 1.00#</mathjax> <mathjax>#"mol"#</mathjax></p> <p>Then, let's convert the units of the given temperature to <mathjax>#"K"#</mathjax>:</p> <p><mathjax>#Rightarrow T_((""^(@)"" "C")) = T_(("K")) - 273.15#</mathjax></p> <p><mathjax>#Rightarrow 30.00 = T_(("K")) - 273.15#</mathjax></p> <p><mathjax>#Rightarrow T_(("K")) = 303.15#</mathjax></p> <p><mathjax>#therefore 30.00#</mathjax> <mathjax>#""^(@)"" "C"#</mathjax> <mathjax>#= 303.15#</mathjax> <mathjax>#"K"#</mathjax></p> <p>Now, let's substitute all relevant values into the equation <mathjax>#P V = n R T#</mathjax>:</p> <p><mathjax>#Rightarrow P times 20.0#</mathjax> <mathjax>#"L"#</mathjax> <mathjax>#= 1.00#</mathjax> <mathjax>#"mol"#</mathjax> <mathjax>#times 0.0821#</mathjax> <mathjax>#"L atm mol"^(- 1) "K"^(- 1)#</mathjax> <mathjax>#times 303.15#</mathjax> <mathjax>#"K"#</mathjax></p> <p><mathjax>#Rightarrow P times 20.0 = 1.00 times 0.0821#</mathjax> <mathjax>#"atm"#</mathjax> <mathjax>#times 303.15#</mathjax></p> <p><mathjax>#Rightarrow P = (frac(0.0821 times 303.15)(20.0))#</mathjax> <mathjax>#"atm"#</mathjax></p> <p><mathjax>#therefore P = 1.24#</mathjax> <mathjax>#"atm"#</mathjax></p> <p>Therefore, the pressure exerted by the oxygen gas is <mathjax>#1.24#</mathjax> <mathjax>#"atm"#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the pressure exerted by 32.00 g of Oxygen gas in a 20. L container at 30.00 C? Use R = 0.0821 L atm/mol k?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/gas-pressure" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Pressure</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">3</span> Answers </h5> <div class="answers"> <div class="answer" id="426906" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/tazwar89"><img alt="" class="" src="https://lh3.googleusercontent.com/-XdUIqdMkCWA/AAAAAAAAAAI/AAAAAAAAAAA/4252rscbv5M/photo.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/tazwar89"> Tazwar Sikder </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-20T22:00:09" itemprop="dateCreated"> May 20, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1.24#</mathjax> <mathjax>#"atm"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First, let's determine the number of mole of oxygen gas.</p> <p>Using <mathjax>#n = frac(m)(M)#</mathjax>:</p> <p><mathjax>#Rightarrow n("O") = (frac(32.00)(2 times 15.99))#</mathjax> <mathjax>#"mol"#</mathjax></p> <p><mathjax>#Rightarrow n("O") = (frac(32.00)(31.98))#</mathjax> <mathjax>#"mol"#</mathjax></p> <p><mathjax>#therefore n("O") = 1.00#</mathjax> <mathjax>#"mol"#</mathjax></p> <p>Then, let's convert the units of the given temperature to <mathjax>#"K"#</mathjax>:</p> <p><mathjax>#Rightarrow T_((""^(@)"" "C")) = T_(("K")) - 273.15#</mathjax></p> <p><mathjax>#Rightarrow 30.00 = T_(("K")) - 273.15#</mathjax></p> <p><mathjax>#Rightarrow T_(("K")) = 303.15#</mathjax></p> <p><mathjax>#therefore 30.00#</mathjax> <mathjax>#""^(@)"" "C"#</mathjax> <mathjax>#= 303.15#</mathjax> <mathjax>#"K"#</mathjax></p> <p>Now, let's substitute all relevant values into the equation <mathjax>#P V = n R T#</mathjax>:</p> <p><mathjax>#Rightarrow P times 20.0#</mathjax> <mathjax>#"L"#</mathjax> <mathjax>#= 1.00#</mathjax> <mathjax>#"mol"#</mathjax> <mathjax>#times 0.0821#</mathjax> <mathjax>#"L atm mol"^(- 1) "K"^(- 1)#</mathjax> <mathjax>#times 303.15#</mathjax> <mathjax>#"K"#</mathjax></p> <p><mathjax>#Rightarrow P times 20.0 = 1.00 times 0.0821#</mathjax> <mathjax>#"atm"#</mathjax> <mathjax>#times 303.15#</mathjax></p> <p><mathjax>#Rightarrow P = (frac(0.0821 times 303.15)(20.0))#</mathjax> <mathjax>#"atm"#</mathjax></p> <p><mathjax>#therefore P = 1.24#</mathjax> <mathjax>#"atm"#</mathjax></p> <p>Therefore, the pressure exerted by the oxygen gas is <mathjax>#1.24#</mathjax> <mathjax>#"atm"#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/426906" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="426907" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/fir3hawk"><img alt="" class="" src="https://lh3.googleusercontent.com/-XdUIqdMkCWA/AAAAAAAAAAI/AAAAAAAAAAA/4252rscbv5M/photo.jpg?sz=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/fir3hawk"> Fir3hawk </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-20T22:00:53" itemprop="dateCreated"> May 20, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1.24#</mathjax> atm, rounded to two <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Note: mols and moles are the same things; formatting issues prevent me from using the same word throughout the answer<br/> We will use the ideal gas equation, which is as follows:</p> <p><mathjax>#PV = nRT#</mathjax></p> <p><mathjax>#P#</mathjax> is pressure (atm)<br/> <mathjax>#V#</mathjax> is volume( liters)<br/> <mathjax>#n#</mathjax> is moles of substance (<mathjax>#(Litersatm)/(molsK)#</mathjax>)<br/> <mathjax>#R#</mathjax> is the constant <mathjax>#0.0821#</mathjax><br/> <mathjax>#T#</mathjax> is temperature (kelvin).</p> <p>We are solving for <mathjax>#P#</mathjax> in this equation, so the formula is reworked as so: <br/> <mathjax>#P = (nRT)/V#</mathjax> <br/> Now, we find the rest of the numbers to plug in</p> <p><mathjax>#n#</mathjax>: We convert Grams of <mathjax>#O_"2"#</mathjax> to moles using dimensional analysis: <mathjax>#32.00g O_2 * (1 mol O_2)/(32.00g O_2) = 1 mol O_2#</mathjax></p> <p><mathjax>#R#</mathjax>: We use the constant <mathjax>#0.0821#</mathjax> </p> <p><mathjax>#T#</mathjax>: We convert the temperature from Celcius to Fahrenheit, using the formula <mathjax>#K = ^oC + 273#</mathjax><br/> <mathjax>#K = 30 + 273 = 303K#</mathjax></p> <p><mathjax>#V#</mathjax>: We use the given liters, which is <mathjax>#20L#</mathjax></p> <p>Now, we solve. </p> <p>First by plugging in numbers:</p> <p><mathjax>#P = (nRT)/V#</mathjax> <br/> => <mathjax>#P = ((1 mol)(0.0821(Litersatm)/(molsK))(303K))/(20L)#</mathjax> </p> <p>Which is the same as:</p> <p><mathjax>#P = ((1 mol)(0.0821(Litersatm))(303K))/(20Lmols*K)#</mathjax></p> <p>Liters, moles, and Kelvin cancel out, giving us:</p> <p><mathjax>#P = ((1)(0.0821 atm)(303))/(20)#</mathjax></p> <p>Now we simplify to get our answer:</p> <p><mathjax>#P = ((1)(0.0821 atm)(303))/(20)#</mathjax></p> <p>=> <mathjax>#P = (24.88atm)/(20)#</mathjax></p> <p>=> <mathjax>#P = 1.24 atm#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/426907" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="426918" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-20T22:36:30" itemprop="dateCreated"> May 20, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The pressure is 1.2 atm.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is an <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a></strong> problem. The equation is:</p> <p><mathjax>#PV=nRT#</mathjax>,</p> <p>where <mathjax>#P#</mathjax> is pressure, <mathjax>#V#</mathjax> is volume, <mathjax>#n#</mathjax> is moles, <mathjax>#R#</mathjax> is a gas constant, and <mathjax>#T#</mathjax> is temperature in Kelvins.</p> <p>You have been given the mass of <mathjax>#"O"_2#</mathjax>, but the equation requires moles. Determine the mol <mathjax>#"O"_2#</mathjax> by multiplying its given mass by the inverse of its molar mass (31.998 g/mol).</p> <p><mathjax>#32.00color(red)cancel(color(black)("g O"_2))xx(1"mol O"_2)/(31.998color(red)cancel(color(black)("g O"_2)))="1.000 mol O"_2"#</mathjax></p> <p>You have been given temperature in degrees Celsius, but gas problems require the temperature to be in Kelvins. Convert <mathjax>#30.00^@"C"#</mathjax> to Kelvins by adding <mathjax>#273.15#</mathjax>.</p> <p><mathjax>#30.00^@"C" + 273.15="303.15 K"#</mathjax></p> <p><mathjax>#color(blue)("Now organize your data."#</mathjax></p> <p><strong>Given/Known</strong></p> <p><mathjax>#V="20. L"=2.0xx10^2color(white)(.)"L"#</mathjax></p> <p><mathjax>#n="1.000 mol"#</mathjax></p> <p><mathjax>#R="0.0821 L atm K"^(-1) "mol"^(-1)"#</mathjax></p> <p><mathjax>#T="303.15 K"#</mathjax></p> <p><mathjax>#color(blue)("Solution."#</mathjax><br/> Rearrange the equation to isolate <mathjax>#P#</mathjax>. Insert your data and solve.</p> <p><mathjax>#P=(nRT)/V#</mathjax></p> <p><mathjax>#P=(1.000color(red)cancel(color(black)("mol"))xx0.0821color(red)cancel(color(black)("L")) "atm" color(red)cancel(color(black)("K"))^(-1) color(red)cancel(color(black)("mol"))^(-1)xx303.15color(red)cancel(color(black)("K")))/(2.0xx10^2color(red)cancel(color(black)("L")))="1.2 atm"#</mathjax> rounded to two significant figures)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/426918" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-gas-pressure-be-changed"> How can gas pressure be changed? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-you-increase-gas-pressure-in-a-container"> How can you increase gas pressure in a container? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-gas-pressure-created"> How is gas pressure created? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-does-gas-pressure-increase-when-temperature-increases"> Why does gas pressure increase when temperature increases? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-gas-pressure-zero-at-absolute-zero"> Why is gas pressure zero at absolute zero? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-does-gas-pressure-increase-with-temperature"> Why does gas pressure increase with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-there-no-gas-pressure-in-a-vacuum"> Why is there no gas pressure in a vacuum? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-total-gas-pressure-in-a-sealed-flask-that-contains-oxygen-at-a-parti-1"> What is the total gas pressure in a sealed flask that contains oxygen at a partial pressure of... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-the-absolute-pressure-of-a-gas-is-550-280-kpa-what-is-its-gage-pressure"> If the absolute pressure of a gas is 550.280 kPa, what is its gage pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-a-gas-sample-occupies-4-2-l-at-a-pressure-of-101-kpa-what-volume-will-it-occu"> If a gas sample occupies 4.2 L at a pressure of 101 kPa. What volume will it occupy if the... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/gas-pressure"> See all questions in Gas Pressure </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 73366 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the pressure exerted by 32.00 g of Oxygen gas in a 20. L container at 30.00 C? Use R = 0.0821 L atm/mol k?	null
2,458	a9d0cda4-6ddd-11ea-9c6b-ccda262736ce	https://socratic.org/questions/what-is-the-energy-released-by-20-grams-of-100-c-steam-that-condenses-and-then-c	53.6 kJ	start physical_unit 11 11 heat_energy kj qc_end physical_unit 11 11 6 7 mass qc_end physical_unit 11 11 9 10 temperature qc_end physical_unit 11 11 18 19 temperature qc_end end	[{"type":"physical unit","value":"Released energy [OF] steam [IN] kJ"}]	[{"type":"physical unit","value":"53.6 kJ"}]	[{"type":"physical unit","value":"Mass [OF] steam [=] \\pu{20 grams}"},{"type":"physical unit","value":"Temperature1 [OF] steam [=] \\pu{100 ℃}"},{"type":"physical unit","value":"Temperature2 [OF] steam [=] \\pu{0 ℃}"}]	<h1 class="questionTitle" itemprop="name">What is the energy released by 20 grams of 100°C steam that condenses and then cools to 0°C?</h1>	null	53.6 kJ	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The energy released came from two discrete processes: </p> <ol> <li>the steam condenses to release some latent heat of condensation at <mathjax>#100 color(white)(l)^"o""C"#</mathjax></li> <li>the water cools down to <mathjax>#0 color(white)(l)^"o""C"#</mathjax> to <mathjax>#100 color(white)(l)^"o""C"#</mathjax> without solidfying.</li> </ol> <p>The amount of energy released in the first process is dependent on the <mathjax>#"L"_"v"#</mathjax> latent heat of vaporization for water and the mass of the sample:</p> <p><mathjax>#"E"("phase change") = m * "L"_"v" = 20 color(white)(l) "g" xx 2, 260 color(white)(l) "J" * "g"^(-1) #</mathjax><br/> <mathjax>#color(white)("E"("phase change"))= 45, 200 color(white)(l) "J"#</mathjax></p> <p>On the other hand, the amount of energy released in the second process depends on both the <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> of water, the mass of the sample, and the magnitude of the change in temperature.</p> <p><mathjax>#"E"("cooling") = m * c * Delta T #</mathjax><br/> <mathjax>#color(white)("E"("cooling") ) = 20 color(white)(l) "g" * 4.2 color(white)(l) "J" * "g" ^(-1) * "K" ^(-1) * (100 color(white)(l) "K" - 0 color(white)(l) "K")#</mathjax><br/> <mathjax>#color(white)("E"("cooling") ) = 8, 400 color(white)(l) "J"#</mathjax><br/> Taking the sum of the energy change of the two processes gives the total amount of energy released:</p> <p><mathjax>#"E"("released") = "E"("phase change") + "E"("cooling") = 53, 600 color(white)(l) "J" = 53.6 color(white)(l) "kJ"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#53. 6 color(white)(l) "kJ"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The energy released came from two discrete processes: </p> <ol> <li>the steam condenses to release some latent heat of condensation at <mathjax>#100 color(white)(l)^"o""C"#</mathjax></li> <li>the water cools down to <mathjax>#0 color(white)(l)^"o""C"#</mathjax> to <mathjax>#100 color(white)(l)^"o""C"#</mathjax> without solidfying.</li> </ol> <p>The amount of energy released in the first process is dependent on the <mathjax>#"L"_"v"#</mathjax> latent heat of vaporization for water and the mass of the sample:</p> <p><mathjax>#"E"("phase change") = m * "L"_"v" = 20 color(white)(l) "g" xx 2, 260 color(white)(l) "J" * "g"^(-1) #</mathjax><br/> <mathjax>#color(white)("E"("phase change"))= 45, 200 color(white)(l) "J"#</mathjax></p> <p>On the other hand, the amount of energy released in the second process depends on both the <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> of water, the mass of the sample, and the magnitude of the change in temperature.</p> <p><mathjax>#"E"("cooling") = m * c * Delta T #</mathjax><br/> <mathjax>#color(white)("E"("cooling") ) = 20 color(white)(l) "g" * 4.2 color(white)(l) "J" * "g" ^(-1) * "K" ^(-1) * (100 color(white)(l) "K" - 0 color(white)(l) "K")#</mathjax><br/> <mathjax>#color(white)("E"("cooling") ) = 8, 400 color(white)(l) "J"#</mathjax><br/> Taking the sum of the energy change of the two processes gives the total amount of energy released:</p> <p><mathjax>#"E"("released") = "E"("phase change") + "E"("cooling") = 53, 600 color(white)(l) "J" = 53.6 color(white)(l) "kJ"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the energy released by 20 grams of 100°C steam that condenses and then cools to 0°C?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/thermochemistry-of-phase-changes" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry of Phase Changes</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="640148" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/jacob-t-3"><img alt="" class="" src="https://profilepictures.socratic.org/cDl6OiFtT16bIyMtJPfM_Protractor.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/jacob-t-3"> Jacob T. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-07-11T15:07:23" itemprop="dateCreated"> Jul 11, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#53. 6 color(white)(l) "kJ"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The energy released came from two discrete processes: </p> <ol> <li>the steam condenses to release some latent heat of condensation at <mathjax>#100 color(white)(l)^"o""C"#</mathjax></li> <li>the water cools down to <mathjax>#0 color(white)(l)^"o""C"#</mathjax> to <mathjax>#100 color(white)(l)^"o""C"#</mathjax> without solidfying.</li> </ol> <p>The amount of energy released in the first process is dependent on the <mathjax>#"L"_"v"#</mathjax> latent heat of vaporization for water and the mass of the sample:</p> <p><mathjax>#"E"("phase change") = m * "L"_"v" = 20 color(white)(l) "g" xx 2, 260 color(white)(l) "J" * "g"^(-1) #</mathjax><br/> <mathjax>#color(white)("E"("phase change"))= 45, 200 color(white)(l) "J"#</mathjax></p> <p>On the other hand, the amount of energy released in the second process depends on both the <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> of water, the mass of the sample, and the magnitude of the change in temperature.</p> <p><mathjax>#"E"("cooling") = m * c * Delta T #</mathjax><br/> <mathjax>#color(white)("E"("cooling") ) = 20 color(white)(l) "g" * 4.2 color(white)(l) "J" * "g" ^(-1) * "K" ^(-1) * (100 color(white)(l) "K" - 0 color(white)(l) "K")#</mathjax><br/> <mathjax>#color(white)("E"("cooling") ) = 8, 400 color(white)(l) "J"#</mathjax><br/> Taking the sum of the energy change of the two processes gives the total amount of energy released:</p> <p><mathjax>#"E"("released") = "E"("phase change") + "E"("cooling") = 53, 600 color(white)(l) "J" = 53.6 color(white)(l) "kJ"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/640148" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-much-energy-is-required-to-heat-100-g-of-ice-at-0-00-degrees-celsius-to-wate"> How much energy is required to convert 100.g of ice at 0.00 °C to water vapor at 100.00 °C? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/534b309602bf34123dd86d5c"> How do you calculate the heat required to melt 15 kg of silver? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-a-liquid-loses-energy-will-it-change-into-a-gas-or-a-solid"> When a liquid loses energy, will it change into a gas or a solid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-name-of-the-process-when-a-liquid-changes-into-a-gas"> What is the name of the process when a liquid changes into a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-much-energy-is-needed-to-convert-23-0-grams-of-ice-at-10-0-c-into-steam-at-1"> How much energy is needed to convert 23.0 grams of ice at -10.0°C into steam at 109°C? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-amount-of-ice-must-be-added-to-540-0-g-of-water-at-25-0-c-to-cool-the-water"> What amount of ice must be added to 540.0 g of water at 25.0 °C to cool the water to 0.0 °C and... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-find-specific-heat-in-thermochemistry-of-phase-of-changes"> How can I find specific heat in thermochemistry of phase of changes? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-much-energy-is-required-to-convert-100-0-g-of-water-at-20-0-c-completely-to-"> How much energy is required to convert 100.0 g of water at 20.0 °C completely to steam at 100.0 °C? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/calculate-the-number-of-joules-given-off-when-32-0-grams-of-steam-cools-from-110"> Calculate the number of joules given off when 32.0 grams of steam cools from 110.0 °C to ice at -40.0 °C. </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-joules-of-heat-are-needed-to-change-50-0-grams-of-ice-at-15-0-c-to-stea"> How many joules of heat are needed to change 50.0 grams of ice at -15.0 °C to steam at 120.0 °C? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/thermochemistry-of-phase-changes"> See all questions in Thermochemistry of Phase Changes </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 83775 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the energy released by 20 grams of 100°C steam that condenses and then cools to 0°C?	null
2,459	ac612318-6ddd-11ea-a30b-ccda262736ce	https://socratic.org/questions/58f6079f11ef6b3c76d30879	75.19%	start physical_unit 18 18 percent_yield none qc_end physical_unit 2 2 0 1 mass qc_end physical_unit 11 11 24 25 actual_yield qc_end chemical_equation 27 34 qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Percent yield [OF] water"}]	[{"type":"physical unit","value":"75.19%"}]	[{"type":"physical unit","value":"Mass [OF] WO3 [=] \\pu{56.9 g}"},{"type":"physical unit","value":"Actual yield [OF] H2O [=] \\pu{10.0 g}"},{"type":"chemical equation","value":"WO3 + H2 -> W + 3 H2O"},{"type":"other","value":"Excess H2."}]	<h1 class="questionTitle" itemprop="name">#"56.9 g WO"_3"# reacts with excess #"H"_2"# to produce #"W"# and #"H"_2"O"#. What is the percent yield of water if the actual yield is #"10.0 g H"_2"O"#?</h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p><mathjax>#"WO"_3 + "H"_2"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"W+3H"_2"O"#</mathjax></p></div> </h2> </div> </div>	75.19%	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>Start with a balanced equation.</strong></p> <p><mathjax>#"WO"_3 + "3H"_2"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"W + 3H"_2"O"#</mathjax></p> <p>The theoretical yield must be determined. This is done by determining the mass of water expected using <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>. The following represents the steps that must be taken to determine the expected (theoretical) mass of water in this reaction.</p> <p><mathjax>#color(red)("given mass WO"_3"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(blue)("mol WO"_3"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(purple)("mol H"_2"O"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(green)("mass H"_2"O"#</mathjax></p> <p>~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~<br/> The molar masses of tungsten oxide and water will need to be determined. </p> <p><strong>Molar Masses</strong><br/> Multiply the subscript of each element by its molar mass, which is its atomic weight on <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a> in g/mol. Add the results for each substance to get the total.</p> <p><mathjax>#"WO"_3:#</mathjax><mathjax>#(1xx183.84color(white)(.)"g/mol W")+(3xx15.999color(white)(.)"g/mol O")="231.837 g/mol WO"_3"#</mathjax></p> <p><mathjax>#"H"_2"O":#</mathjax><mathjax>#(2xx1.008color(white)(.)"g/mol H")+(1xx15.999"g/mol O")="18.015 g/mol H"_2"O"#</mathjax></p> <p>~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~<br/> <strong><a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">Mole Ratios</a></strong><br/> Determine the mol ratio between <mathjax>#"WO"_3"#</mathjax> and <mathjax>#"H"_2"O"#</mathjax> from the balanced equation.</p> <p><mathjax>#(1"mol WO"_3)/(3"mol H"_2"O")#</mathjax> and <mathjax>#(3"mol H"_2"O")/(1"mol WO"_3)#</mathjax></p> <p>~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~<br/> <strong><mathjax>#color(blue)("Moles Tungsten Oxide"#</mathjax></strong><br/> Multiply the <mathjax>#color(red)("given mass WO"_3"#</mathjax> by the inverse of its molar mass.</p> <p><mathjax>#color(red)(56.9cancel"g WO"_3)xx(1"mol WO"_3)/(231.837color(red)cancel(color(black)("g WO"_3)))=color(blue)("0.2454 mol WO"_3"#</mathjax></p> <p>~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~<br/> <strong><mathjax>#color(purple)("Moles Water"#</mathjax></strong><br/> Multiply mol <mathjax>#"WO"_3#</mathjax> by <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio with water in the numerator. </p> <p><mathjax>#0.2454color(red)(cancel(color(black)("mol WO"_3)))xxcolor(black)(3"mol H"_2"O")/(color(red)(cancel(color(black)(1"mol WO"_3))))=color(purple)("0.7362 mol H"_2"O"#</mathjax></p> <p>~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~<br/> <strong><mathjax>#color(green)("Mass of Water"#</mathjax></strong><br/> Multiply mol water by its molar mass.</p> <p><mathjax>#0.7362color(red)(cancel(color(black)("mol H"_2"O")))xx(18.015"g H"_2"O")/(color(red)(cancel(color(black)(1"mol H"_2"O"))))=color(green)("13.3 g H"_2"O")#</mathjax> rounded to three <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a></p> <p>~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~</p> <p>Theoretical Yield of Water is <mathjax>#"13.3 g"#</mathjax>.</p> <p>Actual yield is <mathjax>#"10.0 g H"_2"O"#</mathjax>.</p> <p><mathjax>#"Percent Yield"=("actual yield")/("theoretical yield")xx100#</mathjax></p> <p><mathjax>#"Percent Yield"=("10.0 g H"_2"O")/("13.3 g H"_2"O")xx100="75.2%"#</mathjax> rounded to three significant figures</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The <a href="https://socratic.org/chemistry/stoichiometry/percent-yield">percent yield</a> of water is <mathjax>#75%#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>Start with a balanced equation.</strong></p> <p><mathjax>#"WO"_3 + "3H"_2"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"W + 3H"_2"O"#</mathjax></p> <p>The theoretical yield must be determined. This is done by determining the mass of water expected using <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>. The following represents the steps that must be taken to determine the expected (theoretical) mass of water in this reaction.</p> <p><mathjax>#color(red)("given mass WO"_3"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(blue)("mol WO"_3"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(purple)("mol H"_2"O"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(green)("mass H"_2"O"#</mathjax></p> <p>~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~<br/> The molar masses of tungsten oxide and water will need to be determined. </p> <p><strong>Molar Masses</strong><br/> Multiply the subscript of each element by its molar mass, which is its atomic weight on <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a> in g/mol. Add the results for each substance to get the total.</p> <p><mathjax>#"WO"_3:#</mathjax><mathjax>#(1xx183.84color(white)(.)"g/mol W")+(3xx15.999color(white)(.)"g/mol O")="231.837 g/mol WO"_3"#</mathjax></p> <p><mathjax>#"H"_2"O":#</mathjax><mathjax>#(2xx1.008color(white)(.)"g/mol H")+(1xx15.999"g/mol O")="18.015 g/mol H"_2"O"#</mathjax></p> <p>~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~<br/> <strong><a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">Mole Ratios</a></strong><br/> Determine the mol ratio between <mathjax>#"WO"_3"#</mathjax> and <mathjax>#"H"_2"O"#</mathjax> from the balanced equation.</p> <p><mathjax>#(1"mol WO"_3)/(3"mol H"_2"O")#</mathjax> and <mathjax>#(3"mol H"_2"O")/(1"mol WO"_3)#</mathjax></p> <p>~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~<br/> <strong><mathjax>#color(blue)("Moles Tungsten Oxide"#</mathjax></strong><br/> Multiply the <mathjax>#color(red)("given mass WO"_3"#</mathjax> by the inverse of its molar mass.</p> <p><mathjax>#color(red)(56.9cancel"g WO"_3)xx(1"mol WO"_3)/(231.837color(red)cancel(color(black)("g WO"_3)))=color(blue)("0.2454 mol WO"_3"#</mathjax></p> <p>~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~<br/> <strong><mathjax>#color(purple)("Moles Water"#</mathjax></strong><br/> Multiply mol <mathjax>#"WO"_3#</mathjax> by <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio with water in the numerator. </p> <p><mathjax>#0.2454color(red)(cancel(color(black)("mol WO"_3)))xxcolor(black)(3"mol H"_2"O")/(color(red)(cancel(color(black)(1"mol WO"_3))))=color(purple)("0.7362 mol H"_2"O"#</mathjax></p> <p>~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~<br/> <strong><mathjax>#color(green)("Mass of Water"#</mathjax></strong><br/> Multiply mol water by its molar mass.</p> <p><mathjax>#0.7362color(red)(cancel(color(black)("mol H"_2"O")))xx(18.015"g H"_2"O")/(color(red)(cancel(color(black)(1"mol H"_2"O"))))=color(green)("13.3 g H"_2"O")#</mathjax> rounded to three <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a></p> <p>~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~</p> <p>Theoretical Yield of Water is <mathjax>#"13.3 g"#</mathjax>.</p> <p>Actual yield is <mathjax>#"10.0 g H"_2"O"#</mathjax>.</p> <p><mathjax>#"Percent Yield"=("actual yield")/("theoretical yield")xx100#</mathjax></p> <p><mathjax>#"Percent Yield"=("10.0 g H"_2"O")/("13.3 g H"_2"O")xx100="75.2%"#</mathjax> rounded to three significant figures</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">#"56.9 g WO"_3"# reacts with excess #"H"_2"# to produce #"W"# and #"H"_2"O"#. What is the percent yield of water if the actual yield is #"10.0 g H"_2"O"#?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p><mathjax>#"WO"_3 + "H"_2"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"W+3H"_2"O"#</mathjax></p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/percent-yield" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Yield</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="410303" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-21T04:43:53" itemprop="dateCreated"> Apr 21, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The <a href="https://socratic.org/chemistry/stoichiometry/percent-yield">percent yield</a> of water is <mathjax>#75%#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>Start with a balanced equation.</strong></p> <p><mathjax>#"WO"_3 + "3H"_2"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"W + 3H"_2"O"#</mathjax></p> <p>The theoretical yield must be determined. This is done by determining the mass of water expected using <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>. The following represents the steps that must be taken to determine the expected (theoretical) mass of water in this reaction.</p> <p><mathjax>#color(red)("given mass WO"_3"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(blue)("mol WO"_3"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(purple)("mol H"_2"O"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(green)("mass H"_2"O"#</mathjax></p> <p>~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~<br/> The molar masses of tungsten oxide and water will need to be determined. </p> <p><strong>Molar Masses</strong><br/> Multiply the subscript of each element by its molar mass, which is its atomic weight on <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a> in g/mol. Add the results for each substance to get the total.</p> <p><mathjax>#"WO"_3:#</mathjax><mathjax>#(1xx183.84color(white)(.)"g/mol W")+(3xx15.999color(white)(.)"g/mol O")="231.837 g/mol WO"_3"#</mathjax></p> <p><mathjax>#"H"_2"O":#</mathjax><mathjax>#(2xx1.008color(white)(.)"g/mol H")+(1xx15.999"g/mol O")="18.015 g/mol H"_2"O"#</mathjax></p> <p>~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~<br/> <strong><a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">Mole Ratios</a></strong><br/> Determine the mol ratio between <mathjax>#"WO"_3"#</mathjax> and <mathjax>#"H"_2"O"#</mathjax> from the balanced equation.</p> <p><mathjax>#(1"mol WO"_3)/(3"mol H"_2"O")#</mathjax> and <mathjax>#(3"mol H"_2"O")/(1"mol WO"_3)#</mathjax></p> <p>~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~<br/> <strong><mathjax>#color(blue)("Moles Tungsten Oxide"#</mathjax></strong><br/> Multiply the <mathjax>#color(red)("given mass WO"_3"#</mathjax> by the inverse of its molar mass.</p> <p><mathjax>#color(red)(56.9cancel"g WO"_3)xx(1"mol WO"_3)/(231.837color(red)cancel(color(black)("g WO"_3)))=color(blue)("0.2454 mol WO"_3"#</mathjax></p> <p>~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~<br/> <strong><mathjax>#color(purple)("Moles Water"#</mathjax></strong><br/> Multiply mol <mathjax>#"WO"_3#</mathjax> by <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio with water in the numerator. </p> <p><mathjax>#0.2454color(red)(cancel(color(black)("mol WO"_3)))xxcolor(black)(3"mol H"_2"O")/(color(red)(cancel(color(black)(1"mol WO"_3))))=color(purple)("0.7362 mol H"_2"O"#</mathjax></p> <p>~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~<br/> <strong><mathjax>#color(green)("Mass of Water"#</mathjax></strong><br/> Multiply mol water by its molar mass.</p> <p><mathjax>#0.7362color(red)(cancel(color(black)("mol H"_2"O")))xx(18.015"g H"_2"O")/(color(red)(cancel(color(black)(1"mol H"_2"O"))))=color(green)("13.3 g H"_2"O")#</mathjax> rounded to three <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a></p> <p>~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~</p> <p>Theoretical Yield of Water is <mathjax>#"13.3 g"#</mathjax>.</p> <p>Actual yield is <mathjax>#"10.0 g H"_2"O"#</mathjax>.</p> <p><mathjax>#"Percent Yield"=("actual yield")/("theoretical yield")xx100#</mathjax></p> <p><mathjax>#"Percent Yield"=("10.0 g H"_2"O")/("13.3 g H"_2"O")xx100="75.2%"#</mathjax> rounded to three significant figures</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/410303" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ebd02bf3469570e2e62"> Question #e2e62 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ec502bf34694a4fee2e"> Question #fee2e </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ec902bf34694a4fee32"> Question #fee32 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ece02bf346950519e89"> Question #19e89 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ed302bf34694c8c5bdc"> Question #c5bdc </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ee302bf3469517a1065"> Question #a1065 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-would-be-the-limiting-reagent-if-26-0-grams-of-c3h9n-were-reacted-with-46-3"> What would be the limiting reagent if 26.0 grams of C3H9N were reacted with 46.3 grams of... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-percent-yield-always-less-than-100"> Is percent yield always less than 100? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-would-be-the-limiting-reagent-if-41-9-grams-of-c2h3of-were-reacted-with-61-"> What would be the limiting reagent if 41.9 grams of C2H3OF were reacted with 61.0 grams of... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-yield-of-the-following-reaction-if-60-grams-of-caco3-is-heat"> What is the percent yield of the following reaction if 60 grams of CaCO3 is heated to give 15... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/percent-yield"> See all questions in Percent Yield </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2183 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	#"56.9 g WO"_3"# reacts with excess #"H"_2"# to produce #"W"# and #"H"_2"O"#. What is the percent yield of water if the actual yield is #"10.0 g H"_2"O"#?	#"WO"_3 + "H"_2"##rarr##"W+3H"_2"O"#
2,460	a9aedb91-6ddd-11ea-b471-ccda262736ce	https://socratic.org/questions/what-is-the-chemical-formula-for-iron-ii-hydroxide	Fe(OH)2	start chemical_formula qc_end substance 6 7 qc_end end	[{"type":"other","value":"Chemical Formula [OF] iron(II) hydroxide [IN] default"}]	[{"type":"chemical equation","value":"Fe(OH)2"}]	[{"type":"substance name","value":"Iron(II) hydroxide"}]	<h1 class="questionTitle" itemprop="name">What is the chemical formula for iron(II) hydroxide?</h1>	null	Fe(OH)2	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Hydroxides are poorly characterized beasts. The solid state structure might be <mathjax>#FeO*H_2O#</mathjax>, which is equivalent to <mathjax>#Fe(OH)_2#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Fe(OH)_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Hydroxides are poorly characterized beasts. The solid state structure might be <mathjax>#FeO*H_2O#</mathjax>, which is equivalent to <mathjax>#Fe(OH)_2#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the chemical formula for iron(II) hydroxide?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#ionic-bonds-and-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Ionic Bonds</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/ionic-bonds-and-formulas/writing-ionic-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Writing Ionic Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="271103" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-29T19:49:25" itemprop="dateCreated"> May 29, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Fe(OH)_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Hydroxides are poorly characterized beasts. The solid state structure might be <mathjax>#FeO*H_2O#</mathjax>, which is equivalent to <mathjax>#Fe(OH)_2#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/271103" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-write-ionic-formulas-for-binary-compounds"> How do you write ionic formulas for binary compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-formula-for-calcium-chloride"> What is the ionic formula for calcium chloride? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-formula-for-calcium-oxide"> What is the ionic formula for calcium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-formula-for-lithium-oxide"> What is the ionic formula for lithium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-formula-for-ionic-compounds"> How do you write the formula for ionic compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-correctly-write-the-ions-present-in-sn-no3-2"> How do I write #Sn(NO_3)_2# in Ionic formula? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-an-ionic-compound"> What is the empirical formula for an ionic compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-for-chorate"> What is the molecular formula for chorate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5363023c02bf343b2ee7086b"> Question #7086b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-polyatomic-ions-covalent-1"> Why are polyatomic ions covalent? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/ionic-bonds-and-formulas/writing-ionic-formulas"> See all questions in Writing Ionic Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 6914 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the chemical formula for iron(II) hydroxide?	null
2,461	aa5c5a38-6ddd-11ea-a6c4-ccda262736ce	https://socratic.org/questions/what-is-the-maximum-number-of-grams-of-ph-3-that-can-be-formed-when-6-2-g-of-pho	6.81 grams	start physical_unit 8 8 mass g qc_end physical_unit 17 17 14 15 mass qc_end physical_unit 23 23 20 21 mass qc_end end	[{"type":"physical unit","value":"Mass [OF] PH3 [IN] grams"}]	[{"type":"physical unit","value":"6.81 grams"}]	[{"type":"physical unit","value":"Mass [OF] phosphorus [=] \\pu{6.2 g}"},{"type":"physical unit","value":"Mass [OF] hydrogen [=] \\pu{4.0 g}"}]	<h1 class="questionTitle" itemprop="name">What is the maximum number of grams of #PH_3# that can be formed when 6.2 g of phosphorus reacts with 4.0 g of hydrogen to form #PH_3#?</h1>	null	6.81 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Start with a balanced equation.</p> <p><mathjax>#"P"_4 + "6H"_2"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"4PH"_3"#</mathjax></p> <p>This is a limiting reactant problem. The reactant that produces the least <mathjax>#"PH"_3"#</mathjax> determines the maximum number of grams of <mathjax>#"PH"_3"#</mathjax></p> <p>The process will go as follows:</p> <p><mathjax>#color(blue)("given mass P"_4"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(blue)("mole P"_4"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(red)("mol PH"_3"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(purple)("mass PH"_3"#</mathjax></p> <p>and</p> <p><mathjax>#color(blue)("given mass H"_2"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(blue)("mole H"_2"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(red)("mol PH"_3"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(purple)("mass PH"_3"#</mathjax></p> <p>The molar masses of each substance is needed. Molar mass is the mass of one mole of an element, molecule or ionic compound in g/mol.</p> <p><mathjax>#color(green)("Molar Masses"#</mathjax><br/> Multiply the subscript for each element by its atomic weight on <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a> in g/mol. If there is more than one element, add the molar masses together.</p> <p><mathjax>#"P"_4:#</mathjax><mathjax>#(4xx30.974"g/mol P")="123.896 g/mol P"_4"#</mathjax></p> <p><mathjax>#"H"_2:#</mathjax><mathjax>#(2xx1.008"g/mol H")="2.016 g/mol H"_2"#</mathjax></p> <p><mathjax>#"PH"_3:#</mathjax><mathjax>#(1xx30.974"g/mol P")+(3xx1.008"g/mol H")="33.998 g/mol PH"_3"#</mathjax></p> <p>~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~</p> <p>Now you need to determine the mass of phosphane, <mathjax>#"PH"_3"#</mathjax>, produced individually by <mathjax>#"6.2 g P"_4#</mathjax> and by <mathjax>#"4.0 g H"_2"#</mathjax>. I'm going to start with <mathjax>#"P"_4"#</mathjax> since it is first in the equation.</p> <p><mathjax>#color(blue)("Moles of Phosphorus"#</mathjax><br/> Multiply the given mass of <mathjax>#"P"_4"#</mathjax> by the inverse of its molar mass.</p> <p><mathjax>#6.2color(red)cancel(color(black)("g P"_4))xx(1"mol P"_4)/(123.896color(red)cancel(color(black)("g P"_4)))="0.05004 mol P"_4#</mathjax></p> <p><mathjax>#color(red)("Moles of Phosphane"#</mathjax><br/> Multiply mol <mathjax>#"P"_4#</mathjax> by <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio,in the balanced equation, between <mathjax>#"P"_4"#</mathjax> and <mathjax>#"PH"_3#</mathjax> that will cancel <mathjax>#"P"_4"#</mathjax>.</p> <p><mathjax>#0.05004color(red)cancel(color(black)("mol P"_4))xx(4"mol PH"_3)/(1color(red)cancel(color(black)("mol P"_4)))="0.20016 mole PH"_3"#</mathjax></p> <p><mathjax>#color(purple)("Mass of Phosphane"#</mathjax><br/> Multiply mol <mathjax>#"PH"_3#</mathjax> by its molar mass.</p> <p><mathjax>#0.20016color(red)cancel(color(black)("mol PH"_3))xx(33.998"g PH"_3)/(1color(red)cancel(color(black)("mol PH"_3)))="6.8 g PH"_3"#</mathjax> (rounded to two sig figs due to 6.2 g and 4.0 g)</p> <p>~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~</p> <p>Now you need to determine the mass of phosphane that <mathjax>#"4.0 g H"_2#</mathjax> can produce. I'm going to put the steps together into one equation, but it will contain all of the steps required.</p> <p><mathjax>#color(black)cancel(color(blue)(4.0"g H"_2))xxcolor(blue)((1color(black)cancel(color(blue)("mol H"_2)))/(2.016color(black)cancel(color(blue)("g H"_2)))xxcolor(red)((4color(black)cancel(color(red)("mol PH"_3)))/(6color(black)cancel(color(red)("mol H"_2)))xxcolor(purple)((33.998"g PH"_3)/(1color(black)cancel(color(purple)("mol PH"_3)))=color(purple)("45 g PH"_3#</mathjax></p> <p>Phosphorus is the limiting reactant, which means the maximum amount of phosphane that can be produced is <mathjax>#"6.8 g"#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The maximum mass of phosphane <mathjax>#("PH"_3)#</mathjax> that can be produced under the conditions stated in the question is <mathjax>#"6.8 g"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Start with a balanced equation.</p> <p><mathjax>#"P"_4 + "6H"_2"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"4PH"_3"#</mathjax></p> <p>This is a limiting reactant problem. The reactant that produces the least <mathjax>#"PH"_3"#</mathjax> determines the maximum number of grams of <mathjax>#"PH"_3"#</mathjax></p> <p>The process will go as follows:</p> <p><mathjax>#color(blue)("given mass P"_4"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(blue)("mole P"_4"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(red)("mol PH"_3"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(purple)("mass PH"_3"#</mathjax></p> <p>and</p> <p><mathjax>#color(blue)("given mass H"_2"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(blue)("mole H"_2"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(red)("mol PH"_3"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(purple)("mass PH"_3"#</mathjax></p> <p>The molar masses of each substance is needed. Molar mass is the mass of one mole of an element, molecule or ionic compound in g/mol.</p> <p><mathjax>#color(green)("Molar Masses"#</mathjax><br/> Multiply the subscript for each element by its atomic weight on <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a> in g/mol. If there is more than one element, add the molar masses together.</p> <p><mathjax>#"P"_4:#</mathjax><mathjax>#(4xx30.974"g/mol P")="123.896 g/mol P"_4"#</mathjax></p> <p><mathjax>#"H"_2:#</mathjax><mathjax>#(2xx1.008"g/mol H")="2.016 g/mol H"_2"#</mathjax></p> <p><mathjax>#"PH"_3:#</mathjax><mathjax>#(1xx30.974"g/mol P")+(3xx1.008"g/mol H")="33.998 g/mol PH"_3"#</mathjax></p> <p>~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~</p> <p>Now you need to determine the mass of phosphane, <mathjax>#"PH"_3"#</mathjax>, produced individually by <mathjax>#"6.2 g P"_4#</mathjax> and by <mathjax>#"4.0 g H"_2"#</mathjax>. I'm going to start with <mathjax>#"P"_4"#</mathjax> since it is first in the equation.</p> <p><mathjax>#color(blue)("Moles of Phosphorus"#</mathjax><br/> Multiply the given mass of <mathjax>#"P"_4"#</mathjax> by the inverse of its molar mass.</p> <p><mathjax>#6.2color(red)cancel(color(black)("g P"_4))xx(1"mol P"_4)/(123.896color(red)cancel(color(black)("g P"_4)))="0.05004 mol P"_4#</mathjax></p> <p><mathjax>#color(red)("Moles of Phosphane"#</mathjax><br/> Multiply mol <mathjax>#"P"_4#</mathjax> by <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio,in the balanced equation, between <mathjax>#"P"_4"#</mathjax> and <mathjax>#"PH"_3#</mathjax> that will cancel <mathjax>#"P"_4"#</mathjax>.</p> <p><mathjax>#0.05004color(red)cancel(color(black)("mol P"_4))xx(4"mol PH"_3)/(1color(red)cancel(color(black)("mol P"_4)))="0.20016 mole PH"_3"#</mathjax></p> <p><mathjax>#color(purple)("Mass of Phosphane"#</mathjax><br/> Multiply mol <mathjax>#"PH"_3#</mathjax> by its molar mass.</p> <p><mathjax>#0.20016color(red)cancel(color(black)("mol PH"_3))xx(33.998"g PH"_3)/(1color(red)cancel(color(black)("mol PH"_3)))="6.8 g PH"_3"#</mathjax> (rounded to two sig figs due to 6.2 g and 4.0 g)</p> <p>~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~</p> <p>Now you need to determine the mass of phosphane that <mathjax>#"4.0 g H"_2#</mathjax> can produce. I'm going to put the steps together into one equation, but it will contain all of the steps required.</p> <p><mathjax>#color(black)cancel(color(blue)(4.0"g H"_2))xxcolor(blue)((1color(black)cancel(color(blue)("mol H"_2)))/(2.016color(black)cancel(color(blue)("g H"_2)))xxcolor(red)((4color(black)cancel(color(red)("mol PH"_3)))/(6color(black)cancel(color(red)("mol H"_2)))xxcolor(purple)((33.998"g PH"_3)/(1color(black)cancel(color(purple)("mol PH"_3)))=color(purple)("45 g PH"_3#</mathjax></p> <p>Phosphorus is the limiting reactant, which means the maximum amount of phosphane that can be produced is <mathjax>#"6.8 g"#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the maximum number of grams of #PH_3# that can be formed when 6.2 g of phosphorus reacts with 4.0 g of hydrogen to form #PH_3#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="428576" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-23T21:24:41" itemprop="dateCreated"> May 23, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The maximum mass of phosphane <mathjax>#("PH"_3)#</mathjax> that can be produced under the conditions stated in the question is <mathjax>#"6.8 g"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Start with a balanced equation.</p> <p><mathjax>#"P"_4 + "6H"_2"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"4PH"_3"#</mathjax></p> <p>This is a limiting reactant problem. The reactant that produces the least <mathjax>#"PH"_3"#</mathjax> determines the maximum number of grams of <mathjax>#"PH"_3"#</mathjax></p> <p>The process will go as follows:</p> <p><mathjax>#color(blue)("given mass P"_4"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(blue)("mole P"_4"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(red)("mol PH"_3"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(purple)("mass PH"_3"#</mathjax></p> <p>and</p> <p><mathjax>#color(blue)("given mass H"_2"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(blue)("mole H"_2"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(red)("mol PH"_3"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(purple)("mass PH"_3"#</mathjax></p> <p>The molar masses of each substance is needed. Molar mass is the mass of one mole of an element, molecule or ionic compound in g/mol.</p> <p><mathjax>#color(green)("Molar Masses"#</mathjax><br/> Multiply the subscript for each element by its atomic weight on <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a> in g/mol. If there is more than one element, add the molar masses together.</p> <p><mathjax>#"P"_4:#</mathjax><mathjax>#(4xx30.974"g/mol P")="123.896 g/mol P"_4"#</mathjax></p> <p><mathjax>#"H"_2:#</mathjax><mathjax>#(2xx1.008"g/mol H")="2.016 g/mol H"_2"#</mathjax></p> <p><mathjax>#"PH"_3:#</mathjax><mathjax>#(1xx30.974"g/mol P")+(3xx1.008"g/mol H")="33.998 g/mol PH"_3"#</mathjax></p> <p>~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~</p> <p>Now you need to determine the mass of phosphane, <mathjax>#"PH"_3"#</mathjax>, produced individually by <mathjax>#"6.2 g P"_4#</mathjax> and by <mathjax>#"4.0 g H"_2"#</mathjax>. I'm going to start with <mathjax>#"P"_4"#</mathjax> since it is first in the equation.</p> <p><mathjax>#color(blue)("Moles of Phosphorus"#</mathjax><br/> Multiply the given mass of <mathjax>#"P"_4"#</mathjax> by the inverse of its molar mass.</p> <p><mathjax>#6.2color(red)cancel(color(black)("g P"_4))xx(1"mol P"_4)/(123.896color(red)cancel(color(black)("g P"_4)))="0.05004 mol P"_4#</mathjax></p> <p><mathjax>#color(red)("Moles of Phosphane"#</mathjax><br/> Multiply mol <mathjax>#"P"_4#</mathjax> by <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio,in the balanced equation, between <mathjax>#"P"_4"#</mathjax> and <mathjax>#"PH"_3#</mathjax> that will cancel <mathjax>#"P"_4"#</mathjax>.</p> <p><mathjax>#0.05004color(red)cancel(color(black)("mol P"_4))xx(4"mol PH"_3)/(1color(red)cancel(color(black)("mol P"_4)))="0.20016 mole PH"_3"#</mathjax></p> <p><mathjax>#color(purple)("Mass of Phosphane"#</mathjax><br/> Multiply mol <mathjax>#"PH"_3#</mathjax> by its molar mass.</p> <p><mathjax>#0.20016color(red)cancel(color(black)("mol PH"_3))xx(33.998"g PH"_3)/(1color(red)cancel(color(black)("mol PH"_3)))="6.8 g PH"_3"#</mathjax> (rounded to two sig figs due to 6.2 g and 4.0 g)</p> <p>~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~</p> <p>Now you need to determine the mass of phosphane that <mathjax>#"4.0 g H"_2#</mathjax> can produce. I'm going to put the steps together into one equation, but it will contain all of the steps required.</p> <p><mathjax>#color(black)cancel(color(blue)(4.0"g H"_2))xxcolor(blue)((1color(black)cancel(color(blue)("mol H"_2)))/(2.016color(black)cancel(color(blue)("g H"_2)))xxcolor(red)((4color(black)cancel(color(red)("mol PH"_3)))/(6color(black)cancel(color(red)("mol H"_2)))xxcolor(purple)((33.998"g PH"_3)/(1color(black)cancel(color(purple)("mol PH"_3)))=color(purple)("45 g PH"_3#</mathjax></p> <p>Phosphorus is the limiting reactant, which means the maximum amount of phosphane that can be produced is <mathjax>#"6.8 g"#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/428576" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 23916 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the maximum number of grams of #PH_3# that can be formed when 6.2 g of phosphorus reacts with 4.0 g of hydrogen to form #PH_3#?	null
2,462	a970b702-6ddd-11ea-8494-ccda262736ce	https://socratic.org/questions/7-0-moles-of-sulfur-atoms-and-10-moles-of-oxygen-molecules-are-combined-to-form-	0.33 moles	start physical_unit 26 28 mole mol qc_end physical_unit 3 4 0 1 mole qc_end physical_unit 9 10 6 7 mole qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Mole [OF] reactant remain unused [IN] moles"}]	[{"type":"physical unit","value":"0.33 moles"}]	[{"type":"physical unit","value":"Mole [OF] sulfur atoms [=] \\pu{7.0 moles }"},{"type":"physical unit","value":"Mole [OF] oxygen molecules [=] \\pu{10 moles}"},{"type":"other","value":"Sulfur atoms and oxygen molecules are combined to form the maximum amount of sulfur trioxide."}]	<h1 class="questionTitle" itemprop="name">7.0 moles of sulfur atoms and 10 moles of oxygen molecules are combined to form the maximum amount of sulfur trioxide, how many moles of which reactant remain unused at the end of the reaction?</h1>	null	0.33 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>.........And oxygen is in deficiency.</p> <p>Given <mathjax>#10#</mathjax> <mathjax>#mol#</mathjax> of dioxygen gas, at most, <mathjax>#6.67#</mathjax> <mathjax>#mol#</mathjax> of sulfur trioxide can be generated. This is clearly indicated by the stoichometric equation. Should the reaction proceed to completion (which is unlikely) there will be approx. <mathjax>#0.33#</mathjax> <mathjax>#mol#</mathjax> sulfur unreacted.</p> <p>Industrial production of sulfur trioxide (the precursor to sulfuric acid) relies on the Contact Process: oxidation to <mathjax>#SO_2#</mathjax>, and then catalyzed oxidation of <mathjax>#SO_2#</mathjax> to <mathjax>#SO_3#</mathjax>. It must be an incredibly dirty and smelly process, yet it is undoubtedly vital to our industrial society. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#S(s) +3/2O_2(g) rarr SO_3(g)#</mathjax></p> <p>Clearly sulfur is in excess.......</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>.........And oxygen is in deficiency.</p> <p>Given <mathjax>#10#</mathjax> <mathjax>#mol#</mathjax> of dioxygen gas, at most, <mathjax>#6.67#</mathjax> <mathjax>#mol#</mathjax> of sulfur trioxide can be generated. This is clearly indicated by the stoichometric equation. Should the reaction proceed to completion (which is unlikely) there will be approx. <mathjax>#0.33#</mathjax> <mathjax>#mol#</mathjax> sulfur unreacted.</p> <p>Industrial production of sulfur trioxide (the precursor to sulfuric acid) relies on the Contact Process: oxidation to <mathjax>#SO_2#</mathjax>, and then catalyzed oxidation of <mathjax>#SO_2#</mathjax> to <mathjax>#SO_3#</mathjax>. It must be an incredibly dirty and smelly process, yet it is undoubtedly vital to our industrial society. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">7.0 moles of sulfur atoms and 10 moles of oxygen molecules are combined to form the maximum amount of sulfur trioxide, how many moles of which reactant remain unused at the end of the reaction?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-reactions-and-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions and Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="310736" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-09-16T06:19:58" itemprop="dateCreated"> Sep 16, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#S(s) +3/2O_2(g) rarr SO_3(g)#</mathjax></p> <p>Clearly sulfur is in excess.......</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>.........And oxygen is in deficiency.</p> <p>Given <mathjax>#10#</mathjax> <mathjax>#mol#</mathjax> of dioxygen gas, at most, <mathjax>#6.67#</mathjax> <mathjax>#mol#</mathjax> of sulfur trioxide can be generated. This is clearly indicated by the stoichometric equation. Should the reaction proceed to completion (which is unlikely) there will be approx. <mathjax>#0.33#</mathjax> <mathjax>#mol#</mathjax> sulfur unreacted.</p> <p>Industrial production of sulfur trioxide (the precursor to sulfuric acid) relies on the Contact Process: oxidation to <mathjax>#SO_2#</mathjax>, and then catalyzed oxidation of <mathjax>#SO_2#</mathjax> to <mathjax>#SO_3#</mathjax>. It must be an incredibly dirty and smelly process, yet it is undoubtedly vital to our industrial society. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/310736" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb002bf34694a4fee47"> Question #fee47 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb402bf34694c8c5c15"> Question #c5c15 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb802bf346950519eb9"> Question #19eb9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cbf02bf3469570e2ea2"> Question #e2ea2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc002bf34695a6bc751"> Question #bc751 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc202bf3469570e2ea6"> Question #e2ea6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531e867a02bf342492a08b07"> Question #08b07 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-thermochemical-equation-for-the-combustion-of-benzene"> What is the thermochemical equation for the combustion of benzene? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-reversible"> Why are chemical reactions reversible? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-important"> Why are chemical reactions important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/chemical-reactions-and-equations"> See all questions in Chemical Reactions and Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3719 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	7.0 moles of sulfur atoms and 10 moles of oxygen molecules are combined to form the maximum amount of sulfur trioxide, how many moles of which reactant remain unused at the end of the reaction?	null
2,463	ad254908-6ddd-11ea-bde2-ccda262736ce	https://socratic.org/questions/a-17-5-g-sample-of-metal-at-125-0-c-is-placed-in-a-calorimeter-with-15-0-g-of-wa	0.19 J/(g * ℃)	start physical_unit 38 39 specific_heat j/(°c_·_g) qc_end physical_unit 3 5 1 2 mass qc_end physical_unit 3 5 7 8 temperature qc_end physical_unit 18 18 15 16 mass qc_end physical_unit 18 18 20 21 temperature qc_end physical_unit 18 18 30 31 temperature qc_end end	[{"type":"physical unit","value":"Specific heat [OF] the metal [IN] J/(g * ℃)"}]	[{"type":"physical unit","value":"0.19 J/(g * ℃)"}]	[{"type":"physical unit","value":"Mass [OF] metal sample [=] \\pu{17.5 g}"},{"type":"physical unit","value":"Temperature [OF] metal sample [=] \\pu{125.0 ℃}"},{"type":"physical unit","value":"Mass [OF] water [=] \\pu{15.0 g}"},{"type":"physical unit","value":"Temperature1 [OF] water [=] \\pu{25.0 ℃}"},{"type":"physical unit","value":"Temperature2 [OF] water [=] \\pu{30.0 ℃}"}]	<h1 class="questionTitle" itemprop="name"> A 17.5 g sample of metal at 125.0°C is placed in a calorimeter with 15.0 g of water at 25.0°C. if the temperature of the water rises to 30.0°C, what is the specific heat of the metal?</h1>	null	0.19 J/(g * ℃)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is a thermo-equillibrium situation. We can use the equation</p> <p>Loss of Heat of the Metal = Gain of Heat by the Water</p> <p><mathjax>#-Q_(m) = +Q_(w)#</mathjax></p> <p><mathjax>#Q = mDeltaTC_p#</mathjax></p> <p><mathjax>#Q =#</mathjax> Heat <br/> <mathjax>#m =#</mathjax> mass<br/> <mathjax>#DeltaT = (T_f-T_i)#</mathjax><br/> <mathjax>#T_f=#</mathjax> Final Temp<br/> <mathjax>#T_i=#</mathjax> Initial Temp<br/> <mathjax>#C_P=#</mathjax> Specific Heat</p> <p>Metal<br/> Water<br/> <mathjax>#m =17.5 g#</mathjax><br/> <mathjax>#T_f=30.0^oC#</mathjax><br/> <mathjax>#T_i=125.0^oC#</mathjax><br/> <mathjax>#C_P= x#</mathjax></p> <p>Water<br/> <mathjax>#m =15.0 g#</mathjax><br/> <mathjax>#T_f=30.0^oC#</mathjax><br/> <mathjax>#T_i=25.0^oC#</mathjax><br/> <mathjax>#C_P= 4.184 J/(g^oC)#</mathjax>#</p> <p><mathjax>#-Q_(m) = +Q_(w)#</mathjax><br/> <mathjax>#-[m(T_f-T-i)C_p] = m(T_f-T-i)C_p#</mathjax></p> <p><mathjax>#-[17.5g(30^oC-125^oC)x] = 15g(30^oC-25^oC)4.184J/(g^oC)#</mathjax></p> <p><mathjax>#-[17.5g(-95^oC)x] = 15cancel(g)(5^ocancelC))4.184J/(cancel(g^oC))#</mathjax></p> <p><mathjax>#(1662.5g^oC)x = 313.8J#</mathjax></p> <p><mathjax>#cancel(1662.5g^oC)x/cancel(1662.5g^oC) = (313.8J)/(1662.5g^oC)#</mathjax> </p> <p><mathjax>#C_p = 0.189 J/(g^oC)#</mathjax></p> <p> <iframe src="https://www.youtube.com/embed/7Sp6lxo13dg?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> of the meta is <mathjax>#C_p = 0.189 J/(g^oC)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is a thermo-equillibrium situation. We can use the equation</p> <p>Loss of Heat of the Metal = Gain of Heat by the Water</p> <p><mathjax>#-Q_(m) = +Q_(w)#</mathjax></p> <p><mathjax>#Q = mDeltaTC_p#</mathjax></p> <p><mathjax>#Q =#</mathjax> Heat <br/> <mathjax>#m =#</mathjax> mass<br/> <mathjax>#DeltaT = (T_f-T_i)#</mathjax><br/> <mathjax>#T_f=#</mathjax> Final Temp<br/> <mathjax>#T_i=#</mathjax> Initial Temp<br/> <mathjax>#C_P=#</mathjax> Specific Heat</p> <p>Metal<br/> Water<br/> <mathjax>#m =17.5 g#</mathjax><br/> <mathjax>#T_f=30.0^oC#</mathjax><br/> <mathjax>#T_i=125.0^oC#</mathjax><br/> <mathjax>#C_P= x#</mathjax></p> <p>Water<br/> <mathjax>#m =15.0 g#</mathjax><br/> <mathjax>#T_f=30.0^oC#</mathjax><br/> <mathjax>#T_i=25.0^oC#</mathjax><br/> <mathjax>#C_P= 4.184 J/(g^oC)#</mathjax>#</p> <p><mathjax>#-Q_(m) = +Q_(w)#</mathjax><br/> <mathjax>#-[m(T_f-T-i)C_p] = m(T_f-T-i)C_p#</mathjax></p> <p><mathjax>#-[17.5g(30^oC-125^oC)x] = 15g(30^oC-25^oC)4.184J/(g^oC)#</mathjax></p> <p><mathjax>#-[17.5g(-95^oC)x] = 15cancel(g)(5^ocancelC))4.184J/(cancel(g^oC))#</mathjax></p> <p><mathjax>#(1662.5g^oC)x = 313.8J#</mathjax></p> <p><mathjax>#cancel(1662.5g^oC)x/cancel(1662.5g^oC) = (313.8J)/(1662.5g^oC)#</mathjax> </p> <p><mathjax>#C_p = 0.189 J/(g^oC)#</mathjax></p> <p> <iframe src="https://www.youtube.com/embed/7Sp6lxo13dg?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name"> A 17.5 g sample of metal at 125.0°C is placed in a calorimeter with 15.0 g of water at 25.0°C. if the temperature of the water rises to 30.0°C, what is the specific heat of the metal?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/specific-heat" itemprop="url"> <span class="breadcrumb" itemprop="title">Specific Heat</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="290844" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/brian-m"><img alt="" class="" src="https://profilepictures.socratic.org/ZCpnJDgSFKORtvaSPDeG_Lego%20Me.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/brian-m"> BRIAN M. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-22T16:00:15" itemprop="dateCreated"> Jul 22, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> of the meta is <mathjax>#C_p = 0.189 J/(g^oC)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is a thermo-equillibrium situation. We can use the equation</p> <p>Loss of Heat of the Metal = Gain of Heat by the Water</p> <p><mathjax>#-Q_(m) = +Q_(w)#</mathjax></p> <p><mathjax>#Q = mDeltaTC_p#</mathjax></p> <p><mathjax>#Q =#</mathjax> Heat <br/> <mathjax>#m =#</mathjax> mass<br/> <mathjax>#DeltaT = (T_f-T_i)#</mathjax><br/> <mathjax>#T_f=#</mathjax> Final Temp<br/> <mathjax>#T_i=#</mathjax> Initial Temp<br/> <mathjax>#C_P=#</mathjax> Specific Heat</p> <p>Metal<br/> Water<br/> <mathjax>#m =17.5 g#</mathjax><br/> <mathjax>#T_f=30.0^oC#</mathjax><br/> <mathjax>#T_i=125.0^oC#</mathjax><br/> <mathjax>#C_P= x#</mathjax></p> <p>Water<br/> <mathjax>#m =15.0 g#</mathjax><br/> <mathjax>#T_f=30.0^oC#</mathjax><br/> <mathjax>#T_i=25.0^oC#</mathjax><br/> <mathjax>#C_P= 4.184 J/(g^oC)#</mathjax>#</p> <p><mathjax>#-Q_(m) = +Q_(w)#</mathjax><br/> <mathjax>#-[m(T_f-T-i)C_p] = m(T_f-T-i)C_p#</mathjax></p> <p><mathjax>#-[17.5g(30^oC-125^oC)x] = 15g(30^oC-25^oC)4.184J/(g^oC)#</mathjax></p> <p><mathjax>#-[17.5g(-95^oC)x] = 15cancel(g)(5^ocancelC))4.184J/(cancel(g^oC))#</mathjax></p> <p><mathjax>#(1662.5g^oC)x = 313.8J#</mathjax></p> <p><mathjax>#cancel(1662.5g^oC)x/cancel(1662.5g^oC) = (313.8J)/(1662.5g^oC)#</mathjax> </p> <p><mathjax>#C_p = 0.189 J/(g^oC)#</mathjax></p> <p> <iframe src="https://www.youtube.com/embed/7Sp6lxo13dg?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/290844" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-specific-heat-be-used-to-identify-substances"> How can specific heat be used to identify substances? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-heat-capacity-of-a-lead-sinker-be-determined"> How can the heat capacity of a lead sinker be determined? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-the-specific-heats-of-metals-compare-with-water"> How do the specific heats of metals compare with water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-specific-heat-change-with-temperature"> How does specific heat change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/dissolving-some-potassium-bromide-in-200cm3-of-water-leads-to-a-decrease-in-temp"> Dissolving some potassium bromide in 200cm3 of water leads to a decrease in temperature of 3oC.... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-heat-capacity-larger-for-polymers"> Is heat capacity larger for polymers? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-heat-capacity-an-extensive-property"> Why is heat capacity an extensive property? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-does-heat-capacity-change-with-temperature"> Why does heat capacity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-specific-heat-measured-in"> What is specific heat measured in? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-heat-capacity-measured-in"> What is heat capacity measured in? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/specific-heat"> See all questions in Specific Heat </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 201995 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A 17.5 g sample of metal at 125.0°C is placed in a calorimeter with 15.0 g of water at 25.0°C. if the temperature of the water rises to 30.0°C, what is the specific heat of the metal?	null
2,464	aaa9f936-6ddd-11ea-83c0-ccda262736ce	https://socratic.org/questions/a-12-0-l-gas-cylinder-has-been-filled-with-5-40-moles-of-gas-you-measure-the-pre	83.91 K	start physical_unit 26 27 temperature k qc_end physical_unit 3 4 1 2 volume qc_end physical_unit 3 3 9 10 mole qc_end physical_unit 26 27 19 20 pressure qc_end end	[{"type":"physical unit","value":"Temperature [OF] the tank [IN] K"}]	[{"type":"physical unit","value":"83.91 K"}]	[{"type":"physical unit","value":"Volume [OF] gas cylinder [=] \\pu{12.0 L}"},{"type":"physical unit","value":"Mole [OF] gas [=] \\pu{5.40 moles}"},{"type":"physical unit","value":"Pressure [OF] the tank [=] \\pu{3.10 atm}"}]	<h1 class="questionTitle" itemprop="name">A 12.0 L gas cylinder has been filled with 5.40 moles of gas. You measure the pressure to be 3.10 atm What is the temperature inside the tank? </h1>	null	83.91 K	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Since we are given the number of moles, pressure, and volume of gas, we have to use the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law equation</a> to determine the temperature.</p> <p><img alt="slideplayer.com" src="https://useruploads.socratic.org/gHs2ECdiSxaNBiNU1nC8_slide_3.jpg"/> </p> <ul> <li>P can have units of atm, depending on the units of the universal gas constant</li> <li>V must have units of liters</li> <li>n should have units of moles</li> <li>R has a value of 0.0821 with units of <mathjax>#(Lxxatm)/ (molxxK)#</mathjax></li> <li>T has units of Kelvins.</li> </ul> <p>Next, list your known and unknown variables:</p> <p><mathjax>#color(indigo)("Knowns:")#</mathjax><br/> <mathjax>#R#</mathjax><br/> <mathjax>#V#</mathjax><br/> <mathjax>#n#</mathjax><br/> <mathjax>#P#</mathjax></p> <p><mathjax>#color(orange)("Unknowns:")#</mathjax><br/> <mathjax>#T#</mathjax></p> <p>Rearrange the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> to solve for T:</p> <p><mathjax>#T=(PV)/(nR)#</mathjax></p> <p><mathjax>#T= (3.10cancel"atm"xx12.0cancel"L")/(0.0821cancel"L"xx(cancel"atm")/(cancel"mol"xxK)xx(5.40 cancel"mol")#</mathjax></p> <p><mathjax>#T = 83.9 K#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The temperature inside the tank is <mathjax>#83.9 K#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Since we are given the number of moles, pressure, and volume of gas, we have to use the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law equation</a> to determine the temperature.</p> <p><img alt="slideplayer.com" src="https://useruploads.socratic.org/gHs2ECdiSxaNBiNU1nC8_slide_3.jpg"/> </p> <ul> <li>P can have units of atm, depending on the units of the universal gas constant</li> <li>V must have units of liters</li> <li>n should have units of moles</li> <li>R has a value of 0.0821 with units of <mathjax>#(Lxxatm)/ (molxxK)#</mathjax></li> <li>T has units of Kelvins.</li> </ul> <p>Next, list your known and unknown variables:</p> <p><mathjax>#color(indigo)("Knowns:")#</mathjax><br/> <mathjax>#R#</mathjax><br/> <mathjax>#V#</mathjax><br/> <mathjax>#n#</mathjax><br/> <mathjax>#P#</mathjax></p> <p><mathjax>#color(orange)("Unknowns:")#</mathjax><br/> <mathjax>#T#</mathjax></p> <p>Rearrange the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> to solve for T:</p> <p><mathjax>#T=(PV)/(nR)#</mathjax></p> <p><mathjax>#T= (3.10cancel"atm"xx12.0cancel"L")/(0.0821cancel"L"xx(cancel"atm")/(cancel"mol"xxK)xx(5.40 cancel"mol")#</mathjax></p> <p><mathjax>#T = 83.9 K#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A 12.0 L gas cylinder has been filled with 5.40 moles of gas. You measure the pressure to be 3.10 atm What is the temperature inside the tank? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/ideal-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Ideal Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="300239" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/kayla-14"><img alt="" class="" src="https://profilepictures.socratic.org/OvMTWaamQPWcqLIkUNnG_793604964071127.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/kayla-14"> Kayla </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-08-18T13:47:45" itemprop="dateCreated"> Aug 18, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The temperature inside the tank is <mathjax>#83.9 K#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Since we are given the number of moles, pressure, and volume of gas, we have to use the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law equation</a> to determine the temperature.</p> <p><img alt="slideplayer.com" src="https://useruploads.socratic.org/gHs2ECdiSxaNBiNU1nC8_slide_3.jpg"/> </p> <ul> <li>P can have units of atm, depending on the units of the universal gas constant</li> <li>V must have units of liters</li> <li>n should have units of moles</li> <li>R has a value of 0.0821 with units of <mathjax>#(Lxxatm)/ (molxxK)#</mathjax></li> <li>T has units of Kelvins.</li> </ul> <p>Next, list your known and unknown variables:</p> <p><mathjax>#color(indigo)("Knowns:")#</mathjax><br/> <mathjax>#R#</mathjax><br/> <mathjax>#V#</mathjax><br/> <mathjax>#n#</mathjax><br/> <mathjax>#P#</mathjax></p> <p><mathjax>#color(orange)("Unknowns:")#</mathjax><br/> <mathjax>#T#</mathjax></p> <p>Rearrange the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> to solve for T:</p> <p><mathjax>#T=(PV)/(nR)#</mathjax></p> <p><mathjax>#T= (3.10cancel"atm"xx12.0cancel"L")/(0.0821cancel"L"xx(cancel"atm")/(cancel"mol"xxK)xx(5.40 cancel"mol")#</mathjax></p> <p><mathjax>#T = 83.9 K#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/300239" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-ideal-gas-constant"> How do you find the ideal gas constant? 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R = 8.314 kPa L / (K mol) =... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-molar-mass-of-a-gas"> How do you calculate the molar mass of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-should-i-use-the-ideal-gas-law-and-not-the-combined-gas-law"> When should I use the ideal gas law and not the combined gas law? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/ideal-gas-law"> See all questions in Ideal Gas Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 13590 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A 12.0 L gas cylinder has been filled with 5.40 moles of gas. You measure the pressure to be 3.10 atm What is the temperature inside the tank?	null
2,465	aa1a6c98-6ddd-11ea-9ef7-ccda262736ce	https://socratic.org/questions/how-many-liters-of-oxygen-would-be-needed-to-produce-45-0-liters-of-carbon-dioxi	45.00 liters	start physical_unit 4 4 volume l qc_end end	[{"type":"physical unit","value":"Volume [OF] oxygen gas [IN] liters"}]	[{"type":"physical unit","value":"45.00 liters"}]	[{"type":"physical unit","value":"Volume [OF] carbon dioxide gas [=] \\pu{45.0 liters}"},{"type":"physical unit","value":"Temperature [OF] both gas [=] \\pu{22.0 ℃}"},{"type":"physical unit","value":"Pressure [OF] both gas [=] \\pu{75.0 psi}"}]	<h1 class="questionTitle" itemprop="name">How many liters of oxygen would be needed to produce 45.0 liters of carbon dioxide if the temperature and pressure for both are 22.0° C and 75.0 psi? </h1>	null	45.00 liters	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>At constant pressure, and constant temperature, equal volumes of gases contain an equal number of molecules; this is <a href="http://www.chemistry.co.nz/avogadro.htm" rel="nofollow">Avogadro's law of combining volumes.</a> </p> <p>Given that reaction has <mathjax>#1:1#</mathjax> <a href="http://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>, i.e.</p> <p><mathjax>#C(s) + O_2(g) rarr CO_2(g)#</mathjax></p> <p>If <mathjax>#45#</mathjax> <mathjax>#L#</mathjax> of oxygen were used, stoichiometry insists that <mathjax>#45#</mathjax> <mathjax>#L#</mathjax> of carbon dioxide were produced. This is a good thing, because using mixed units in questions like this (i.e. <mathjax>#"litres"#</mathjax> and <mathjax>#"pounds per square inch"#</mathjax>) is simply asking for trouble. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>A precise volume of <mathjax>#45#</mathjax> <mathjax>#L#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>At constant pressure, and constant temperature, equal volumes of gases contain an equal number of molecules; this is <a href="http://www.chemistry.co.nz/avogadro.htm" rel="nofollow">Avogadro's law of combining volumes.</a> </p> <p>Given that reaction has <mathjax>#1:1#</mathjax> <a href="http://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>, i.e.</p> <p><mathjax>#C(s) + O_2(g) rarr CO_2(g)#</mathjax></p> <p>If <mathjax>#45#</mathjax> <mathjax>#L#</mathjax> of oxygen were used, stoichiometry insists that <mathjax>#45#</mathjax> <mathjax>#L#</mathjax> of carbon dioxide were produced. This is a good thing, because using mixed units in questions like this (i.e. <mathjax>#"litres"#</mathjax> and <mathjax>#"pounds per square inch"#</mathjax>) is simply asking for trouble. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many liters of oxygen would be needed to produce 45.0 liters of carbon dioxide if the temperature and pressure for both are 22.0° C and 75.0 psi? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/stoichiometry-involving-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="229987" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-02-23T07:06:50" itemprop="dateCreated"> Feb 23, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>A precise volume of <mathjax>#45#</mathjax> <mathjax>#L#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>At constant pressure, and constant temperature, equal volumes of gases contain an equal number of molecules; this is <a href="http://www.chemistry.co.nz/avogadro.htm" rel="nofollow">Avogadro's law of combining volumes.</a> </p> <p>Given that reaction has <mathjax>#1:1#</mathjax> <a href="http://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>, i.e.</p> <p><mathjax>#C(s) + O_2(g) rarr CO_2(g)#</mathjax></p> <p>If <mathjax>#45#</mathjax> <mathjax>#L#</mathjax> of oxygen were used, stoichiometry insists that <mathjax>#45#</mathjax> <mathjax>#L#</mathjax> of carbon dioxide were produced. This is a good thing, because using mixed units in questions like this (i.e. <mathjax>#"litres"#</mathjax> and <mathjax>#"pounds per square inch"#</mathjax>) is simply asking for trouble. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/229987" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-apply-gas-stoichiometry"> How do you apply gas stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-solve-a-gas-law-stoichiometry-problem"> How do you solve a gas law stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-do-gas-stoichiometry-problems-at-stp"> How do you do gas stoichiometry problems at STP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-an-agno3-solution-is-treated-with-50-0-ml-of-hi-gas-to-give-0-235-g-of-agi-"> When an AgNO3 solution is treated with 50.0 mL of HI gas to give 0.235 g of AgI, what is the... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-10-0-ml-of-agno3-solution-is-treated-with-excess-amount-of-hi-gas-to-give-0"> When 10.0 mL of AgNO3 solution is treated with excess amount of HI gas to give 0.235 g of AgI,... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/hydrogen-sulfide-reacts-with-sulfur-dioxide-to-give-h2o-and-s-h2s-so2-h2o-s-soli"> Hydrogen sulfide reacts with sulfur dioxide to give H2O and S, H2S + SO2 = H2O + S(solid),... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-100-ml-of-hcl-gas-at-300-k-and-200-kpa-dissolved-in-pure-water-requires-12-50"> If 100 mL of HCl gas at 300 K and 200 kPa dissolved in pure water requires 12.50 mL of the NaOH... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-100-ml-of-hcl-gas-at-300-k-and-100-kpa-dissolved-in-pure-water-requires-12-50"> If 100 mL of HCl gas at 300 K and 100 kPa dissolved in pure water requires 12.50 mL of the NaOH... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-100-ml-of-hcl-gas-at-300-k-and-100-kpa-dissolve-in-20-ml-of-pure-water-what-i"> If 100 mL of HCl gas at 300 K and 100 kPa dissolve in 20 mL of pure water, what is the concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-2-00-g-mixture-of-na-and-ca-reat-with-water-1-164-l-hydrogen-was-produced-a"> When 2.00 g mixture of Na and Ca reat with water, 1.164 L hydrogen was produced at 300.0 K and... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/stoichiometry-involving-gases"> See all questions in Gas Stoichiometry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 6324 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many liters of oxygen would be needed to produce 45.0 liters of carbon dioxide if the temperature and pressure for both are 22.0° C and 75.0 psi?	null
2,466	a8d38adf-6ddd-11ea-b240-ccda262736ce	https://socratic.org/questions/what-mass-of-sodium-benzoate-should-be-added-to-140-0-ml-of-a-0-15-m-benzoic-aci	3.3 g	start physical_unit 3 4 mass g qc_end physical_unit 15 17 9 10 volume qc_end physical_unit 15 17 13 14 molarity qc_end physical_unit 21 21 26 26 ph qc_end end	[{"type":"physical unit","value":"Mass [OF] sodium benzoate [IN] g"}]	[{"type":"physical unit","value":"3.3 g"}]	[{"type":"physical unit","value":"Volume [OF] benzoic acid solution [=] \\pu{140.0 mL}"},{"type":"physical unit","value":"Molarity [OF] benzoic acid solution [=] \\pu{0.15 M}"},{"type":"physical unit","value":"pH [OF] buffer [=] \\pu{4.25}"}]	<h1 class="questionTitle" itemprop="name">What mass of sodium benzoate should be added to 140.0 mL of a 0.15 M benzoic acid solution to obtain a buffer with a pH of 4.25? </h1>	null	3.3 g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <strong>buffer solution</strong> is prepared by mixing benzoic acid and sodium benzoate.</p> <p>Use the <strong>Handerson-Hasselbalch equation</strong> to determine the number of moles of the salt needed to produce the buffer solution with the desired pH. </p> <p>The <mathjax>#pK_a#</mathjax> values for the common weak acids is provided in tables at the end of most chemistry text books.</p> <p>The <mathjax>#pK_a#</mathjax> value for benzoic acid is 4.20.</p> <p><mathjax>#n_"Salt" = ??#</mathjax></p> <p><mathjax>#n_"Acid"= C_M xx V#</mathjax></p> <p><mathjax>#n_"Acid"= 0.15 \ (mol.)/Lxx 0.1400 L#</mathjax></p> <p><mathjax>#n_"Acid"= 0.0210 \ mol.#</mathjax></p> <p><mathjax>#----------------#</mathjax></p> <p>Solve for the unknown (<mathjax>#n_"Salt"#</mathjax>)</p> <p><mathjax># pH = pK_a + log ((n_"Salt")/(n_"Acid"))#</mathjax></p> <p><mathjax>#4.25 = 4.20 + log ((n_"Salt")/(n_"Acid"))#</mathjax></p> <p><mathjax>#log ((n_"Salt")/(n_"Acid")) = 4.25 -4.20#</mathjax></p> <p><mathjax>#log ((n_"Salt")/(n_"Acid")) = 0.05#</mathjax></p> <p><mathjax>#(n_"Salt")/(n_"Acid") = 10^0.05#</mathjax></p> <p><mathjax>#(n_"Salt")/(n_"Acid") = 1.1#</mathjax></p> <p><mathjax>#n_"Salt" = 0.0210 xx 1.1#</mathjax></p> <p><mathjax>#n_"Salt" = 0.0231 \ mol.#</mathjax></p> <p><mathjax>#m_"Salt" = 0.0231 \ mol. xx 144.11 g/(mol.)#</mathjax></p> <p><mathjax>#m_"Salt" ~= 3.3 \ g#</mathjax></p> <p><mathjax>#3.3 \ g #</mathjax> of sodium benzoate must be dissolved in the benzoic acid solution to obtain the solution with the desired pH (4.25).</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#3.3 \ g #</mathjax> of sodium benzoate must be dissolved in the benzoic acid solution to obtain the solution with the desired <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> (4.25).</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <strong>buffer solution</strong> is prepared by mixing benzoic acid and sodium benzoate.</p> <p>Use the <strong>Handerson-Hasselbalch equation</strong> to determine the number of moles of the salt needed to produce the buffer solution with the desired pH. </p> <p>The <mathjax>#pK_a#</mathjax> values for the common weak acids is provided in tables at the end of most chemistry text books.</p> <p>The <mathjax>#pK_a#</mathjax> value for benzoic acid is 4.20.</p> <p><mathjax>#n_"Salt" = ??#</mathjax></p> <p><mathjax>#n_"Acid"= C_M xx V#</mathjax></p> <p><mathjax>#n_"Acid"= 0.15 \ (mol.)/Lxx 0.1400 L#</mathjax></p> <p><mathjax>#n_"Acid"= 0.0210 \ mol.#</mathjax></p> <p><mathjax>#----------------#</mathjax></p> <p>Solve for the unknown (<mathjax>#n_"Salt"#</mathjax>)</p> <p><mathjax># pH = pK_a + log ((n_"Salt")/(n_"Acid"))#</mathjax></p> <p><mathjax>#4.25 = 4.20 + log ((n_"Salt")/(n_"Acid"))#</mathjax></p> <p><mathjax>#log ((n_"Salt")/(n_"Acid")) = 4.25 -4.20#</mathjax></p> <p><mathjax>#log ((n_"Salt")/(n_"Acid")) = 0.05#</mathjax></p> <p><mathjax>#(n_"Salt")/(n_"Acid") = 10^0.05#</mathjax></p> <p><mathjax>#(n_"Salt")/(n_"Acid") = 1.1#</mathjax></p> <p><mathjax>#n_"Salt" = 0.0210 xx 1.1#</mathjax></p> <p><mathjax>#n_"Salt" = 0.0231 \ mol.#</mathjax></p> <p><mathjax>#m_"Salt" = 0.0231 \ mol. xx 144.11 g/(mol.)#</mathjax></p> <p><mathjax>#m_"Salt" ~= 3.3 \ g#</mathjax></p> <p><mathjax>#3.3 \ g #</mathjax> of sodium benzoate must be dissolved in the benzoic acid solution to obtain the solution with the desired pH (4.25).</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What mass of sodium benzoate should be added to 140.0 mL of a 0.15 M benzoic acid solution to obtain a buffer with a pH of 4.25? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#reactions-in-solution" itemprop="url"> <span class="breadcrumb" itemprop="title">Reactions in Solution</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/reactions-in-solution/buffer-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">Buffer Calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="287263" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/sam-54"><img alt="" class="" src="https://profilepictures.socratic.org/3bkyAGe2RVWw1lx2h1A5_Avatar%201.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/sam-54"> Sam </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-12T00:01:40" itemprop="dateCreated"> Jul 12, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#3.3 \ g #</mathjax> of sodium benzoate must be dissolved in the benzoic acid solution to obtain the solution with the desired <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> (4.25).</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <strong>buffer solution</strong> is prepared by mixing benzoic acid and sodium benzoate.</p> <p>Use the <strong>Handerson-Hasselbalch equation</strong> to determine the number of moles of the salt needed to produce the buffer solution with the desired pH. </p> <p>The <mathjax>#pK_a#</mathjax> values for the common weak acids is provided in tables at the end of most chemistry text books.</p> <p>The <mathjax>#pK_a#</mathjax> value for benzoic acid is 4.20.</p> <p><mathjax>#n_"Salt" = ??#</mathjax></p> <p><mathjax>#n_"Acid"= C_M xx V#</mathjax></p> <p><mathjax>#n_"Acid"= 0.15 \ (mol.)/Lxx 0.1400 L#</mathjax></p> <p><mathjax>#n_"Acid"= 0.0210 \ mol.#</mathjax></p> <p><mathjax>#----------------#</mathjax></p> <p>Solve for the unknown (<mathjax>#n_"Salt"#</mathjax>)</p> <p><mathjax># pH = pK_a + log ((n_"Salt")/(n_"Acid"))#</mathjax></p> <p><mathjax>#4.25 = 4.20 + log ((n_"Salt")/(n_"Acid"))#</mathjax></p> <p><mathjax>#log ((n_"Salt")/(n_"Acid")) = 4.25 -4.20#</mathjax></p> <p><mathjax>#log ((n_"Salt")/(n_"Acid")) = 0.05#</mathjax></p> <p><mathjax>#(n_"Salt")/(n_"Acid") = 10^0.05#</mathjax></p> <p><mathjax>#(n_"Salt")/(n_"Acid") = 1.1#</mathjax></p> <p><mathjax>#n_"Salt" = 0.0210 xx 1.1#</mathjax></p> <p><mathjax>#n_"Salt" = 0.0231 \ mol.#</mathjax></p> <p><mathjax>#m_"Salt" = 0.0231 \ mol. xx 144.11 g/(mol.)#</mathjax></p> <p><mathjax>#m_"Salt" ~= 3.3 \ g#</mathjax></p> <p><mathjax>#3.3 \ g #</mathjax> of sodium benzoate must be dissolved in the benzoic acid solution to obtain the solution with the desired pH (4.25).</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/287263" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-buffer-solutions-used"> How are buffer solutions used? 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2,467	a9015a9c-6ddd-11ea-af5a-ccda262736ce	https://socratic.org/questions/a-0-0245-mg-sample-of-nitrogen-reacts-with-oxygen-to-form-0-0945-mg-of-the-oxide	N2O5	start chemical_formula qc_end physical_unit 3 5 1 2 mass qc_end physical_unit 14 15 11 12 mass qc_end substance 8 8 qc_end end	[{"type":"other","value":"Chemical Formula [OF] this nitrogen oxide compound [IN] empirical"}]	[{"type":"chemical equation","value":"N2O5"}]	[{"type":"physical unit","value":"Mass [OF] nitrogen sample [=] \\pu{0.0245 mg}"},{"type":"physical unit","value":"Mass [OF] the oxide [=] \\pu{0.0945 mg}"},{"type":"substance name","value":"Oxygen"}]	<h1 class="questionTitle" itemprop="name">A 0.0245 mg sample of nitrogen reacts with oxygen to form 0.0945 mg of the oxide. What is the empirical formula of this nitrogen oxide compound?</h1>	null	N2O5	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The equation for the reaction is</p> <p><mathjax>#A_"r":color(white)(mmmll)14.01color(white)(mml)16.00#</mathjax><br/> <mathjax>#color(white)(mmmmmll)x"N"_2color(white)(m) + color(white)(ll) y"O"_2 → 2"N"_x"O"_y"#</mathjax><br/> <mathjax>#"Mass/µg":color(white)(m)24.5color(white)(mmm)70.0"color(white)(mml)94.5#</mathjax></p> <blockquote></blockquote> <p>First, we must <strong>calculate the masses</strong> of <mathjax>#"N"#</mathjax> and <mathjax>#"O"#</mathjax> from the mass of the oxide.</p> <p><mathjax>#"Mass of N in oxide = 24.5 µg"#</mathjax></p> <p><mathjax>#"Mass of O in oxide" = "mass of oxide - mass of N" = "(94.5 - 24.5) µg" = "70.0 µg"#</mathjax></p> <blockquote></blockquote> <p>Now, we must <strong>convert these masses to moles</strong> and <strong>find their ratios</strong>.</p> <p>From here on, I like to summarize the calculations in a table.</p> <p><mathjax>#ul(bb("Element"color(white)(X) "Mass/µg"color(white)(X) "Amt/µmol"color(white)(m) "Ratio"color(white)(ml)×2color(white)(mm)"Integers"))#</mathjax><br/> <mathjax>#color(white)(mm)"N"color(white)(mmmml)24.5color(white)(mmmmll)1.748color(white)(Xmm)1color(white)(mmml)2color(white)(Xmmml)2#</mathjax><br/> <mathjax>#color(white)(mm)"O" color(white)(XXXml)70.0 color(white)(mmmmll)4.375 color(white)(mmm)2.502 color(white)(ml)5.004color(white)(Xml)5#</mathjax></p> <p>The <strong>empirical formula</strong> is <mathjax>#"N"_2"O"_5#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><blockquote></blockquote> <p>The empirical formula is <mathjax>#"N"_2"O"_5#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The equation for the reaction is</p> <p><mathjax>#A_"r":color(white)(mmmll)14.01color(white)(mml)16.00#</mathjax><br/> <mathjax>#color(white)(mmmmmll)x"N"_2color(white)(m) + color(white)(ll) y"O"_2 → 2"N"_x"O"_y"#</mathjax><br/> <mathjax>#"Mass/µg":color(white)(m)24.5color(white)(mmm)70.0"color(white)(mml)94.5#</mathjax></p> <blockquote></blockquote> <p>First, we must <strong>calculate the masses</strong> of <mathjax>#"N"#</mathjax> and <mathjax>#"O"#</mathjax> from the mass of the oxide.</p> <p><mathjax>#"Mass of N in oxide = 24.5 µg"#</mathjax></p> <p><mathjax>#"Mass of O in oxide" = "mass of oxide - mass of N" = "(94.5 - 24.5) µg" = "70.0 µg"#</mathjax></p> <blockquote></blockquote> <p>Now, we must <strong>convert these masses to moles</strong> and <strong>find their ratios</strong>.</p> <p>From here on, I like to summarize the calculations in a table.</p> <p><mathjax>#ul(bb("Element"color(white)(X) "Mass/µg"color(white)(X) "Amt/µmol"color(white)(m) "Ratio"color(white)(ml)×2color(white)(mm)"Integers"))#</mathjax><br/> <mathjax>#color(white)(mm)"N"color(white)(mmmml)24.5color(white)(mmmmll)1.748color(white)(Xmm)1color(white)(mmml)2color(white)(Xmmml)2#</mathjax><br/> <mathjax>#color(white)(mm)"O" color(white)(XXXml)70.0 color(white)(mmmmll)4.375 color(white)(mmm)2.502 color(white)(ml)5.004color(white)(Xml)5#</mathjax></p> <p>The <strong>empirical formula</strong> is <mathjax>#"N"_2"O"_5#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A 0.0245 mg sample of nitrogen reacts with oxygen to form 0.0945 mg of the oxide. What is the empirical formula of this nitrogen oxide compound?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="465868" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-19T19:27:32" itemprop="dateCreated"> Aug 19, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><blockquote></blockquote> <p>The empirical formula is <mathjax>#"N"_2"O"_5#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The equation for the reaction is</p> <p><mathjax>#A_"r":color(white)(mmmll)14.01color(white)(mml)16.00#</mathjax><br/> <mathjax>#color(white)(mmmmmll)x"N"_2color(white)(m) + color(white)(ll) y"O"_2 → 2"N"_x"O"_y"#</mathjax><br/> <mathjax>#"Mass/µg":color(white)(m)24.5color(white)(mmm)70.0"color(white)(mml)94.5#</mathjax></p> <blockquote></blockquote> <p>First, we must <strong>calculate the masses</strong> of <mathjax>#"N"#</mathjax> and <mathjax>#"O"#</mathjax> from the mass of the oxide.</p> <p><mathjax>#"Mass of N in oxide = 24.5 µg"#</mathjax></p> <p><mathjax>#"Mass of O in oxide" = "mass of oxide - mass of N" = "(94.5 - 24.5) µg" = "70.0 µg"#</mathjax></p> <blockquote></blockquote> <p>Now, we must <strong>convert these masses to moles</strong> and <strong>find their ratios</strong>.</p> <p>From here on, I like to summarize the calculations in a table.</p> <p><mathjax>#ul(bb("Element"color(white)(X) "Mass/µg"color(white)(X) "Amt/µmol"color(white)(m) "Ratio"color(white)(ml)×2color(white)(mm)"Integers"))#</mathjax><br/> <mathjax>#color(white)(mm)"N"color(white)(mmmml)24.5color(white)(mmmmll)1.748color(white)(Xmm)1color(white)(mmml)2color(white)(Xmmml)2#</mathjax><br/> <mathjax>#color(white)(mm)"O" color(white)(XXXml)70.0 color(white)(mmmmll)4.375 color(white)(mmm)2.502 color(white)(ml)5.004color(white)(Xml)5#</mathjax></p> <p>The <strong>empirical formula</strong> is <mathjax>#"N"_2"O"_5#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/465868" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? 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What is the empirical formula of this nitrogen oxide compound?	null
2,468	aa602968-6ddd-11ea-a8f9-ccda262736ce	https://socratic.org/questions/determine-how-many-liters-of-nitrogen-will-be-required-to-produce-214-4-liters-o	107.20 liters	start physical_unit 5 5 volume l qc_end physical_unit 14 14 11 12 volume qc_end chemical_equation 22 28 qc_end end	[{"type":"physical unit","value":"Volume [OF] nitrogen [IN] liters"}]	[{"type":"physical unit","value":"107.20 liters"}]	[{"type":"physical unit","value":"Volume [OF] ammonia [=] \\pu{214.4 liters}"},{"type":"chemical equation","value":"3 H2(g) + N2(g) -> 2 NH3(g)"}]	<h1 class="questionTitle" itemprop="name">Determine how many liters of nitrogen will be required to produce 214.4 liters of ammonia? The balanced equation for this reaction is: #3"H"_2(g) + "N"_2(g) -> 2"NH"_3(g)# ?</h1>	null	107.20 liters	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that if all the gases that take part in the reaction are kept <strong>under the same conditions</strong> for pressure and temperature, then you can treat the <strong><a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratios</a></strong> that exist between them as <strong>volume ratios</strong>. </p> <blockquote> <p><mathjax>#3"H"_ (2(g)) + "N"_ (2(g)) -> 2"NH"_ (3(g))#</mathjax></p> </blockquote> <p>The balanced chemical equation tells you that in order to produce <mathjax>#2#</mathjax> <strong>moles</strong> of ammonia, the reaction must consume <mathjax>#3#</mathjax> <strong>moles</strong> of hydrogen gas and <mathjax>#1#</mathjax> <strong>mole</strong> of nitrogen gas. </p> <p>If all three gases are kept under the same conditions for pressure and temperature, you can say that in order for the reaction to produce <mathjax>#"2 L"#</mathjax> of ammonia, ti must consume <mathjax>#"3 L"#</mathjax> of hydrogen gas and <mathjax>#"1 L"#</mathjax> of nitrogen gas. </p> <p>This means that your reaction will require</p> <blockquote> <p><mathjax>#214.4 color(red)(cancel(color(black)("L NH"_3))) * "1 L N"_2/(2color(red)(cancel(color(black)("L NH"_3)))) = color(darkgreen)(ul(color(black)("107.2 L N"_2)))#</mathjax></p> </blockquote> <p>The answer is rounded to four <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"107.2 L"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that if all the gases that take part in the reaction are kept <strong>under the same conditions</strong> for pressure and temperature, then you can treat the <strong><a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratios</a></strong> that exist between them as <strong>volume ratios</strong>. </p> <blockquote> <p><mathjax>#3"H"_ (2(g)) + "N"_ (2(g)) -> 2"NH"_ (3(g))#</mathjax></p> </blockquote> <p>The balanced chemical equation tells you that in order to produce <mathjax>#2#</mathjax> <strong>moles</strong> of ammonia, the reaction must consume <mathjax>#3#</mathjax> <strong>moles</strong> of hydrogen gas and <mathjax>#1#</mathjax> <strong>mole</strong> of nitrogen gas. </p> <p>If all three gases are kept under the same conditions for pressure and temperature, you can say that in order for the reaction to produce <mathjax>#"2 L"#</mathjax> of ammonia, ti must consume <mathjax>#"3 L"#</mathjax> of hydrogen gas and <mathjax>#"1 L"#</mathjax> of nitrogen gas. </p> <p>This means that your reaction will require</p> <blockquote> <p><mathjax>#214.4 color(red)(cancel(color(black)("L NH"_3))) * "1 L N"_2/(2color(red)(cancel(color(black)("L NH"_3)))) = color(darkgreen)(ul(color(black)("107.2 L N"_2)))#</mathjax></p> </blockquote> <p>The answer is rounded to four <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Determine how many liters of nitrogen will be required to produce 214.4 liters of ammonia? The balanced equation for this reaction is: #3"H"_2(g) + "N"_2(g) -> 2"NH"_3(g)# ?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/stoichiometry-involving-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="525288" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-12-21T11:15:22" itemprop="dateCreated"> Dec 21, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"107.2 L"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that if all the gases that take part in the reaction are kept <strong>under the same conditions</strong> for pressure and temperature, then you can treat the <strong><a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratios</a></strong> that exist between them as <strong>volume ratios</strong>. </p> <blockquote> <p><mathjax>#3"H"_ (2(g)) + "N"_ (2(g)) -> 2"NH"_ (3(g))#</mathjax></p> </blockquote> <p>The balanced chemical equation tells you that in order to produce <mathjax>#2#</mathjax> <strong>moles</strong> of ammonia, the reaction must consume <mathjax>#3#</mathjax> <strong>moles</strong> of hydrogen gas and <mathjax>#1#</mathjax> <strong>mole</strong> of nitrogen gas. </p> <p>If all three gases are kept under the same conditions for pressure and temperature, you can say that in order for the reaction to produce <mathjax>#"2 L"#</mathjax> of ammonia, ti must consume <mathjax>#"3 L"#</mathjax> of hydrogen gas and <mathjax>#"1 L"#</mathjax> of nitrogen gas. </p> <p>This means that your reaction will require</p> <blockquote> <p><mathjax>#214.4 color(red)(cancel(color(black)("L NH"_3))) * "1 L N"_2/(2color(red)(cancel(color(black)("L NH"_3)))) = color(darkgreen)(ul(color(black)("107.2 L N"_2)))#</mathjax></p> </blockquote> <p>The answer is rounded to four <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/525288" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-apply-gas-stoichiometry"> How do you apply gas stoichiometry? 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</a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-2-00-g-mixture-of-na-and-ca-reat-with-water-1-164-l-hydrogen-was-produced-a"> When 2.00 g mixture of Na and Ca reat with water, 1.164 L hydrogen was produced at 300.0 K and... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/stoichiometry-involving-gases"> See all questions in Gas Stoichiometry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 18242 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Determine how many liters of nitrogen will be required to produce 214.4 liters of ammonia? The balanced equation for this reaction is: #3"H"_2(g) + "N"_2(g) -> 2"NH"_3(g)# ?	null
2,469	a86d8f9e-6ddd-11ea-aec9-ccda262736ce	https://socratic.org/questions/590b74797c01491a72c89548	5.1 mol/L	start physical_unit 5 6 molarity mol/l qc_end physical_unit 12 12 9 10 mole qc_end physical_unit 5 6 19 20 volume qc_end end	[{"type":"physical unit","value":"Molarity [OF] a solution [IN] mol/L"}]	[{"type":"physical unit","value":"5.1 mol/L"}]	[{"type":"physical unit","value":"Mole [OF] solute [=] \\pu{5 moles}"},{"type":"physical unit","value":"Volume [OF] a solution [=] \\pu{975 mL}"}]	<h1 class="questionTitle" itemprop="name">What is the molarity of a solution that contains #"5 moles"# of solute dissolved in a solution that is #"975 mL"#?</h1>	null	5.1 mol/L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Molarity (M)"=("moles of solute")/("liters of solution")#</mathjax></p> <p>The volume of the solution is given in mL. The volume is required to be in liters, so <mathjax>#"975 mL"#</mathjax> must be converted to liters.</p> <p><mathjax>#"1 L=1000 mL"#</mathjax></p> <p><mathjax>#975color(red)cancel(color(black)("mL"))xx(1"L")/(1000color(red)cancel(color(black)("mL")))="0.975 L"#</mathjax></p> <p><mathjax>#"Molarity (M)"=(5.0"mol")/(0.975"L")="5.1 mol/L"#</mathjax> rounded to two <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of the solution is <mathjax>#"5.1 mol/L"#</mathjax>.</p> <p>The solution is said to be <mathjax>#"5.1 molar"#</mathjax>.</p> <p>The shorthand way to indicate molarity is <mathjax>#"5.1 M"#</mathjax>, which is pronounced <mathjax>#"5.1 molar"#</mathjax>, and is how it is written on the label of its container. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Molarity (M)"=("moles of solute")/("liters of solution")#</mathjax></p> <p>The volume of the solution is given in mL. The volume is required to be in liters, so <mathjax>#"975 mL"#</mathjax> must be converted to liters.</p> <p><mathjax>#"1 L=1000 mL"#</mathjax></p> <p><mathjax>#975color(red)cancel(color(black)("mL"))xx(1"L")/(1000color(red)cancel(color(black)("mL")))="0.975 L"#</mathjax></p> <p><mathjax>#"Molarity (M)"=(5.0"mol")/(0.975"L")="5.1 mol/L"#</mathjax> rounded to two <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the molarity of a solution that contains #"5 moles"# of solute dissolved in a solution that is #"975 mL"#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="417972" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-05T05:28:12" itemprop="dateCreated"> May 5, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of the solution is <mathjax>#"5.1 mol/L"#</mathjax>.</p> <p>The solution is said to be <mathjax>#"5.1 molar"#</mathjax>.</p> <p>The shorthand way to indicate molarity is <mathjax>#"5.1 M"#</mathjax>, which is pronounced <mathjax>#"5.1 molar"#</mathjax>, and is how it is written on the label of its container. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Molarity (M)"=("moles of solute")/("liters of solution")#</mathjax></p> <p>The volume of the solution is given in mL. The volume is required to be in liters, so <mathjax>#"975 mL"#</mathjax> must be converted to liters.</p> <p><mathjax>#"1 L=1000 mL"#</mathjax></p> <p><mathjax>#975color(red)cancel(color(black)("mL"))xx(1"L")/(1000color(red)cancel(color(black)("mL")))="0.975 L"#</mathjax></p> <p><mathjax>#"Molarity (M)"=(5.0"mol")/(0.975"L")="5.1 mol/L"#</mathjax> rounded to two <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/417972" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-morality-be-used-as-a-conversion-factor"> How can molarity be used as a conversion factor? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-high-can-molarity-be"> How high can molarity be? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-molarity-change-with-temperature"> How does molarity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molarity-of-a-solution"> How do you find molarity of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-10-naoh"> What is the molarity of 10 NaOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-3-hydrogen-peroxide"> What is the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 16434 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the molarity of a solution that contains #"5 moles"# of solute dissolved in a solution that is #"975 mL"#?	null
2,470	a863192e-6ddd-11ea-98d0-ccda262736ce	https://socratic.org/questions/what-is-the-molecular-formula-of-a-substance-that-decomposes-into-1-33-g-of-h-in	H2O2	start chemical_formula qc_end physical_unit 14 14 11 12 mass qc_end physical_unit 19 19 16 17 mass qc_end physical_unit 6 7 29 30 molar_mass qc_end end	[{"type":"other","value":"Chemical Formula [OF] a substance [IN] molecular"}]	[{"type":"chemical equation","value":"H2O2"}]	[{"type":"physical unit","value":"Mass [OF] H [=] \\pu{1.33 g}"},{"type":"physical unit","value":"Mass [OF] O [=] \\pu{21.3 g}"},{"type":"physical unit","value":"Molar mass [OF] a substance [=] \\pu{34.1 g/mol}"}]	<h1 class="questionTitle" itemprop="name">What is the molecular formula of a substance that decomposes into #1.33# #g# of #H# and #21.3# #g# of #O#, and was found to have a molar mass of #34.1# #gmol^-1#? </h1>	null	H2O2	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#H#</mathjax> has a molar mass of <mathjax>#1#</mathjax> <mathjax>#gmol^-1#</mathjax>, so <mathjax>#1.33#</mathjax> <mathjax>#g#</mathjax> = <mathjax>#1.33#</mathjax> mol.</p> <p>(I have assumed that we are talking about individual <mathjax>#H#</mathjax> atoms, not <mathjax>#H_2#</mathjax> molecules, and similarly for <mathjax>#O#</mathjax> versus <mathjax>#O_2#</mathjax>.</p> <p>Oxygen has a molar mass of <mathjax>#16#</mathjax> <mathjax>#gmol^-1#</mathjax>, so using <mathjax>#n=m/M#</mathjax>, <mathjax>#n = 21.3/16=1.33#</mathjax> <mathjax>#gmol^-1#</mathjax>.</p> <p>We see that there are the same number of moles of each element in the substance, so we can think of the molecular formula as <mathjax>#H_xO_x#</mathjax>. We need to find the value of <mathjax>#x#</mathjax>.</p> <p>If <mathjax>#x#</mathjax> was equal to <mathjax>#1#</mathjax>, the molar mass would be <mathjax>#1+16 = 17#</mathjax> <mathjax>#gmol^-1#</mathjax>.</p> <p>Since the given molar mass is almost exactly 2x that, at <mathjax>#34.1#</mathjax> <mathjax>#gmol^-1#</mathjax>, the value of <mathjax>#x#</mathjax> must be <mathjax>#2#</mathjax>, and the molecular formula must be <mathjax>#H_2O_2#</mathjax>.</p> <p>(incidentally, this is the formula of the chemical substance hydrogen peroxide)</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The molecular formula of the substance is <mathjax>#H_2O_2#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#H#</mathjax> has a molar mass of <mathjax>#1#</mathjax> <mathjax>#gmol^-1#</mathjax>, so <mathjax>#1.33#</mathjax> <mathjax>#g#</mathjax> = <mathjax>#1.33#</mathjax> mol.</p> <p>(I have assumed that we are talking about individual <mathjax>#H#</mathjax> atoms, not <mathjax>#H_2#</mathjax> molecules, and similarly for <mathjax>#O#</mathjax> versus <mathjax>#O_2#</mathjax>.</p> <p>Oxygen has a molar mass of <mathjax>#16#</mathjax> <mathjax>#gmol^-1#</mathjax>, so using <mathjax>#n=m/M#</mathjax>, <mathjax>#n = 21.3/16=1.33#</mathjax> <mathjax>#gmol^-1#</mathjax>.</p> <p>We see that there are the same number of moles of each element in the substance, so we can think of the molecular formula as <mathjax>#H_xO_x#</mathjax>. We need to find the value of <mathjax>#x#</mathjax>.</p> <p>If <mathjax>#x#</mathjax> was equal to <mathjax>#1#</mathjax>, the molar mass would be <mathjax>#1+16 = 17#</mathjax> <mathjax>#gmol^-1#</mathjax>.</p> <p>Since the given molar mass is almost exactly 2x that, at <mathjax>#34.1#</mathjax> <mathjax>#gmol^-1#</mathjax>, the value of <mathjax>#x#</mathjax> must be <mathjax>#2#</mathjax>, and the molecular formula must be <mathjax>#H_2O_2#</mathjax>.</p> <p>(incidentally, this is the formula of the chemical substance hydrogen peroxide)</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the molecular formula of a substance that decomposes into #1.33# #g# of #H# and #21.3# #g# of #O#, and was found to have a molar mass of #34.1# #gmol^-1#? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="426970" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/david-g-6"><img alt="" class="" src="https://graph.facebook.com/10153408096237887/picture?height=50&width=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/david-g-6"> David G. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-21T00:59:20" itemprop="dateCreated"> May 21, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The molecular formula of the substance is <mathjax>#H_2O_2#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#H#</mathjax> has a molar mass of <mathjax>#1#</mathjax> <mathjax>#gmol^-1#</mathjax>, so <mathjax>#1.33#</mathjax> <mathjax>#g#</mathjax> = <mathjax>#1.33#</mathjax> mol.</p> <p>(I have assumed that we are talking about individual <mathjax>#H#</mathjax> atoms, not <mathjax>#H_2#</mathjax> molecules, and similarly for <mathjax>#O#</mathjax> versus <mathjax>#O_2#</mathjax>.</p> <p>Oxygen has a molar mass of <mathjax>#16#</mathjax> <mathjax>#gmol^-1#</mathjax>, so using <mathjax>#n=m/M#</mathjax>, <mathjax>#n = 21.3/16=1.33#</mathjax> <mathjax>#gmol^-1#</mathjax>.</p> <p>We see that there are the same number of moles of each element in the substance, so we can think of the molecular formula as <mathjax>#H_xO_x#</mathjax>. We need to find the value of <mathjax>#x#</mathjax>.</p> <p>If <mathjax>#x#</mathjax> was equal to <mathjax>#1#</mathjax>, the molar mass would be <mathjax>#1+16 = 17#</mathjax> <mathjax>#gmol^-1#</mathjax>.</p> <p>Since the given molar mass is almost exactly 2x that, at <mathjax>#34.1#</mathjax> <mathjax>#gmol^-1#</mathjax>, the value of <mathjax>#x#</mathjax> must be <mathjax>#2#</mathjax>, and the molecular formula must be <mathjax>#H_2O_2#</mathjax>.</p> <p>(incidentally, this is the formula of the chemical substance hydrogen peroxide)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/426970" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molecular-formula-of-a-compound"> How do you find molecular formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-diamond"> What is the chemical formula of a diamond? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-carbohydrate"> What is the chemical formula of a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-valproic-acid"> What is the empirical formula for valproic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-of-magnesium-oxide"> What is the empirical formula of magnesium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-empirical-formula-not-double-that-of-the-monosaccharides"> Why is the empirical formula not double that of the monosaccharides? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5331180502bf342f40b5c3b5"> Question #5c3b5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-molecular-formula-represents-a-carbohydrate"> What molecular formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-of-vinegar"> What is the molecular formula of vinegar? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/empirical-and-molecular-formulas"> See all questions in Empirical and Molecular Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 4219 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the molecular formula of a substance that decomposes into #1.33# #g# of #H# and #21.3# #g# of #O#, and was found to have a molar mass of #34.1# #gmol^-1#?	null
2,471	ac117a30-6ddd-11ea-8346-ccda262736ce	https://socratic.org/questions/what-is-the-mass-of-precipitate-formed-when-50-ml-of-16-9-w-v-solution-of-agno3-	7.11 g	start physical_unit 5 5 mass g qc_end physical_unit 13 13 8 9 volume qc_end physical_unit 24 25 8 9 volume qc_end end	[{"type":"physical unit","value":"Mass [OF] precipitate [IN] g"}]	[{"type":"physical unit","value":"7.11 g"}]	[{"type":"physical unit","value":"Volume [OF] AgNO3 solution [=] \\pu{50 ml}"},{"type":"physical unit","value":"w/v [OF] AgNO3 in solution [=] \\pu{16.9%}"},{"type":"physical unit","value":"Volume [OF] NaCl solution [=] \\pu{50 ml}"},{"type":"physical unit","value":"w/v [OF] NaCl in solution [=] \\pu{5.8%}"}]	<h1 class="questionTitle" itemprop="name">What is the mass of precipitate formed when 50 ml of 16.9% w/v solution of AgNO3 is mixed with 50 ml of 5.8% w/v NaCl solution?</h1>	null	7.11 g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And thus <mathjax>#"mass of silver nitrate"=16.9%xx50mL=8.45g#</mathjax>.</p> <p>And this represents a molar quantity of <mathjax>#(8.45g)/(169.87gmol^-1)#</mathjax></p> <p><mathjax>#=0.0497mol#</mathjax>, with respect to <mathjax>#AgNO_3#</mathjax>.</p> <p>Likewise <mathjax>#"mass of sodium chloride"=5.8%xx50mL=2.90g#</mathjax>.</p> <p>And this represents a molar quantity of <mathjax>#(2.90g)/(58.44gmol^-1)#</mathjax></p> <p><mathjax>#=0.0497mol#</mathjax> with respect to <mathjax>#NaCl#</mathjax>.</p> <p>Clearly the reagents are present in 1:1 molar ratio. The reaction that occurs in solution is the precipitation of a curdy white mass of <mathjax>#AgCl(s)#</mathjax>, i.e. and we represent this reaction by the net ionic equation.....</p> <p><mathjax>#Ag^(+) + Cl^(-)rarrAgCl(s)darr#</mathjax></p> <p>Of course the complete reaction is....</p> <p><mathjax>#AgNO_3(aq) + NaCl(aq) rarr AgCl(s)darr + NaNO_3(aq)#</mathjax>, i.e. sodium nitrate remains in solution and can be separated (with effort) from the precipitate. </p> <p>And given the <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>, we gets <mathjax>#0.04974molxx143.32gmol^-1=7.11g#</mathjax>.</p> <p>Of course a material such as silver halide would be very hard to isolate. Particle size is very small; it is likely to clog the filter, and filter very slowly; and moreover <mathjax>#AgCl#</mathjax> is photoactive, and would decompose under light. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, <mathjax>#"w/v"-="Mass of solute"/"Volume of solution"#</mathjax>, we should get over <mathjax>#7g#</mathjax> of silver chloride. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And thus <mathjax>#"mass of silver nitrate"=16.9%xx50mL=8.45g#</mathjax>.</p> <p>And this represents a molar quantity of <mathjax>#(8.45g)/(169.87gmol^-1)#</mathjax></p> <p><mathjax>#=0.0497mol#</mathjax>, with respect to <mathjax>#AgNO_3#</mathjax>.</p> <p>Likewise <mathjax>#"mass of sodium chloride"=5.8%xx50mL=2.90g#</mathjax>.</p> <p>And this represents a molar quantity of <mathjax>#(2.90g)/(58.44gmol^-1)#</mathjax></p> <p><mathjax>#=0.0497mol#</mathjax> with respect to <mathjax>#NaCl#</mathjax>.</p> <p>Clearly the reagents are present in 1:1 molar ratio. The reaction that occurs in solution is the precipitation of a curdy white mass of <mathjax>#AgCl(s)#</mathjax>, i.e. and we represent this reaction by the net ionic equation.....</p> <p><mathjax>#Ag^(+) + Cl^(-)rarrAgCl(s)darr#</mathjax></p> <p>Of course the complete reaction is....</p> <p><mathjax>#AgNO_3(aq) + NaCl(aq) rarr AgCl(s)darr + NaNO_3(aq)#</mathjax>, i.e. sodium nitrate remains in solution and can be separated (with effort) from the precipitate. </p> <p>And given the <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>, we gets <mathjax>#0.04974molxx143.32gmol^-1=7.11*g#</mathjax>.</p> <p>Of course a material such as silver halide would be very hard to isolate. Particle size is very small; it is likely to clog the filter, and filter very slowly; and moreover <mathjax>#AgCl#</mathjax> is photoactive, and would decompose under light. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the mass of precipitate formed when 50 ml of 16.9% w/v solution of AgNO3 is mixed with 50 ml of 5.8% w/v NaCl solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#reactions-in-solution" itemprop="url"> <span class="breadcrumb" itemprop="title">Reactions in Solution</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/reactions-in-solution/stoichiometry-of-reactions-between-ions-in-solutions" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry of Reactions Between Ions in Solutions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="465174" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-17T17:31:11" itemprop="dateCreated"> Aug 17, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, <mathjax>#"w/v"-="Mass of solute"/"Volume of solution"#</mathjax>, we should get over <mathjax>#7g#</mathjax> of silver chloride. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And thus <mathjax>#"mass of silver nitrate"=16.9%xx50mL=8.45g#</mathjax>.</p> <p>And this represents a molar quantity of <mathjax>#(8.45g)/(169.87gmol^-1)#</mathjax></p> <p><mathjax>#=0.0497mol#</mathjax>, with respect to <mathjax>#AgNO_3#</mathjax>.</p> <p>Likewise <mathjax>#"mass of sodium chloride"=5.8%xx50mL=2.90g#</mathjax>.</p> <p>And this represents a molar quantity of <mathjax>#(2.90g)/(58.44gmol^-1)#</mathjax></p> <p><mathjax>#=0.0497mol#</mathjax> with respect to <mathjax>#NaCl#</mathjax>.</p> <p>Clearly the reagents are present in 1:1 molar ratio. The reaction that occurs in solution is the precipitation of a curdy white mass of <mathjax>#AgCl(s)#</mathjax>, i.e. and we represent this reaction by the net ionic equation.....</p> <p><mathjax>#Ag^(+) + Cl^(-)rarrAgCl(s)darr#</mathjax></p> <p>Of course the complete reaction is....</p> <p><mathjax>#AgNO_3(aq) + NaCl(aq) rarr AgCl(s)darr + NaNO_3(aq)#</mathjax>, i.e. sodium nitrate remains in solution and can be separated (with effort) from the precipitate. </p> <p>And given the <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>, we gets <mathjax>#0.04974molxx143.32gmol^-1=7.11*g#</mathjax>.</p> <p>Of course a material such as silver halide would be very hard to isolate. Particle size is very small; it is likely to clog the filter, and filter very slowly; and moreover <mathjax>#AgCl#</mathjax> is photoactive, and would decompose under light. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/465174" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-measure-concentration-of-reducing-sugars"> How do you measure concentration of reducing sugars? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-525-ml-of-0-80-m-hcl-solution-is-neutralized-with-315-ml-of-sr-oh-2-solution-"> If 525 mL of 0.80 M HCl solution is neutralized with 315 mL of Sr(OH)2 solution what is the... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-stoichiometry-called-stoichiometry"> Why is stoichiometry called stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-solid-baso4-will-form-when-na2so4-reacts-with-25-ml-of-0-50-m-"> How many grams of solid BaSO4 will form when Na2SO4 reacts with 25 mL of 0.50 M Ba(NO3)2? __... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-liters-of-a-0-75-m-solution-of-ca-no3-2-will-be-required-to-react-with-"> How many liters of a 0.75 M solution of Ca(NO3)2 will be required to react with 148 g of Na2CO3?... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-45-ml-of-a-1-5-m-agno3-is-added-to-kcl-how-many-grams-of-agcl-can-be-formed-a"> If 45 mL of a 1.5 M AgNO3 is added to KCl how many grams of AgCl can be formed? __ AgNO3 + __... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-sodium-can-react-with-750-ml-of-a-6-0-m-solution-of-sulfuric-a"> How many grams of sodium can react with 750 mL of a 6.0 M solution of sulfuric acid, H2SO4? __... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-aluminum-are-required-to-react-with-35-ml-of-2-0-m-hydrochlori"> How many grams of aluminum are required to react with 35 mL of 2.0 M hydrochloric acid, HCl? __... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-gas-stoichiometry-differ-from-stoichiometry-of-solids-and-liquids-3"> How does gas stoichiometry differ from stoichiometry of solids and liquids? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-stoichiometry-relate-to-the-law-of-conservation-2"> How does stoichiometry relate to the law of conservation? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/reactions-in-solution/stoichiometry-of-reactions-between-ions-in-solutions"> See all questions in Stoichiometry of Reactions Between Ions in Solutions </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 71609 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the mass of precipitate formed when 50 ml of 16.9% w/v solution of AgNO3 is mixed with 50 ml of 5.8% w/v NaCl solution?	null
2,472	ab7cea7a-6ddd-11ea-981d-ccda262736ce	https://socratic.org/questions/what-is-the-molecular-formula-of-ethanoic-acid	CH3COOH	start chemical_formula qc_end substance 6 7 qc_end end	[{"type":"other","value":"Chemical Formula [OF] ethanoic acid [IN] molecular"}]	[{"type":"chemical equation","value":"CH3COOH"}]	[{"type":"substance name","value":"Ethanoic acid"}]	<h1 class="questionTitle" itemprop="name">What is the molecular formula of ethanoic acid?</h1>	null	CH3COOH	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Ethanoic acid is more commonly known as acetic acid; its salts are called acetates.</p> <p>That was easy! Do I win £5-00?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#H_3C-C(=O)OH#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Ethanoic acid is more commonly known as acetic acid; its salts are called acetates.</p> <p>That was easy! Do I win £5-00?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the molecular formula of ethanoic acid?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="185281" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-07T20:26:51" itemprop="dateCreated"> Nov 7, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#H_3C-C(=O)OH#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Ethanoic acid is more commonly known as acetic acid; its salts are called acetates.</p> <p>That was easy! Do I win £5-00?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/185281" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molecular-formula-of-a-compound"> How do you find molecular formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-diamond"> What is the chemical formula of a diamond? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-carbohydrate"> What is the chemical formula of a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-valproic-acid"> What is the empirical formula for valproic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-of-magnesium-oxide"> What is the empirical formula of magnesium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-empirical-formula-not-double-that-of-the-monosaccharides"> Why is the empirical formula not double that of the monosaccharides? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5331180502bf342f40b5c3b5"> Question #5c3b5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-molecular-formula-represents-a-carbohydrate"> What molecular formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-of-vinegar"> What is the molecular formula of vinegar? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/empirical-and-molecular-formulas"> See all questions in Empirical and Molecular Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 12019 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the molecular formula of ethanoic acid?	null
2,473	ac28aa0a-6ddd-11ea-b51c-ccda262736ce	https://socratic.org/questions/56d52cb611ef6b7735ede137	3	start physical_unit 8 9 number none qc_end end	[{"type":"physical unit","value":"Number [OF] individual ions"}]	[{"type":"physical unit","value":"3"}]	[{"type":"physical unit","value":"Number [OF] CaF2 formula unit [=] \\pu{1}"}]	<h1 class="questionTitle" itemprop="name">In ONE formula unit of #CaF_2#, how many individual ions are there?</h1>	null	3	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#CaF_2#</mathjax> is the result of ionic bonds between <mathjax>#Ca^(2+)#</mathjax> and <mathjax>#2xxF^-#</mathjax>. Electrical neutrality demands this <a href="http://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>. The resultant fluorite structure is exceptionally strong. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>In one formula unit of <mathjax>#CaF_2#</mathjax>, there are 3 ions, one cation, and 2 anions. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#CaF_2#</mathjax> is the result of ionic bonds between <mathjax>#Ca^(2+)#</mathjax> and <mathjax>#2xxF^-#</mathjax>. Electrical neutrality demands this <a href="http://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>. The resultant fluorite structure is exceptionally strong. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">In ONE formula unit of #CaF_2#, how many individual ions are there?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#ionic-bonds-and-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Ionic Bonds</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/ionic-bonds-and-formulas/ionic-compounds" itemprop="url"> <span class="breadcrumb" itemprop="title">Ionic Compounds</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="233362" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-01T07:51:58" itemprop="dateCreated"> Mar 1, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>In one formula unit of <mathjax>#CaF_2#</mathjax>, there are 3 ions, one cation, and 2 anions. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#CaF_2#</mathjax> is the result of ionic bonds between <mathjax>#Ca^(2+)#</mathjax> and <mathjax>#2xxF^-#</mathjax>. Electrical neutrality demands this <a href="http://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>. The resultant fluorite structure is exceptionally strong. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/233362" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52f1151302bf34732c779c2f"> Question #79c2f </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52f1151302bf3473360cd842"> Question #cd842 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52f1151702bf34733dc14e7e"> Why do ionic compounds dissolve in water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52f1151b02bf3473394975aa"> Question #975aa </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52f1151b02bf3473394975ae"> Question #975ae </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52f1151e02bf34733e367e72"> Question #67e72 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/532eff8902bf341e776bd809"> What do the terms anhydrous, hydrous, and undissociated mean? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-ionic-compounds"> What are ionic compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-identify-ionic-compounds"> How can I identify ionic compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-ionic-compounds-solid-at-a-room-temperature"> Why are ionic compounds solid at room temperature? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/ionic-bonds-and-formulas/ionic-compounds"> See all questions in Ionic Compounds </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3225 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	In ONE formula unit of #CaF_2#, how many individual ions are there?	null
2,474	aa391e7c-6ddd-11ea-88c6-ccda262736ce	https://socratic.org/questions/a-10-ml-sample-of-hydrochloric-acid-neutralizes-15-ml-of-a-0-40-m-solution-of-na	0.60 M	start physical_unit 5 6 molarity mol/l qc_end physical_unit 3 6 1 2 volume qc_end physical_unit 14 14 8 9 volume qc_end physical_unit 16 16 12 13 molarity qc_end end	[{"type":"physical unit","value":"Molarity [OF] hydrochloric acid [IN] M"}]	[{"type":"physical unit","value":"0.60 M"}]	[{"type":"physical unit","value":"Volume [OF] hydrochloric acid sample [=] \\pu{10 mL}"},{"type":"physical unit","value":"Volume [OF] NaOH solution [=] \\pu{15 mL}"},{"type":"physical unit","value":"Molarity [OF] NaOH solution [=] \\pu{0.40 M}"}]	<h1 class="questionTitle" itemprop="name">A 10 mL sample of hydrochloric acid neutralizes 15 mL of a 0.40 M solution of #NaOH#. What is the molarity of the hydrochloric acid?</h1>	null	0.60 M	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><em>Hydrochloric acid</em>, <mathjax>#"HCl"#</mathjax>, a <strong>strong acid</strong>, will react with <em>sodium hydroxide</em>, <mathjax>#"NaOH"#</mathjax>, a <strong>strong base</strong>, to produce water and aqueous sodium chloride, <mathjax>#"NaCl"#</mathjax>. </p> <blockquote> <blockquote> <p><img alt="https://mrzsedwiki.wikispaces.com/WARM-UPS!+%26+LEARNING+OBJECTIVES+2014" src="https://useruploads.socratic.org/RrNEaGnESkSPYwulGAct_naoh%20%2B%20hcl.jpeg%22%3B+size%3D%226728"/> </p> </blockquote> </blockquote> <p>As you can see, it takes <strong>one mole</strong> of hydrochloric acid to neutralize <strong>one mole</strong> of strong base. This means that a <em>complete <a href="https://socratic.org/chemistry/reactions-in-solution/neutralization">neutralization</a></em> requires <strong>equal numbers of moles</strong> of the two reactants. </p> <p>Even without doing any calculations, you can look at the values given to you and try to estimate the concentration of the hydrochloric acid solution <strong>relative</strong> to that of the sodium hydroxide. </p> <p>You know that <mathjax>#"10 mL"#</mathjax> of this hydrochloric acid solution must contain <strong>the same number of moles</strong> of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> as <mathjax>#"15 mL"#</mathjax> of sodium hydroxide solution. </p> <p>Since you have the same number of moles in a <strong>smaller volume</strong>, it follows that the hydrochloric acid solution will be <strong>more concentrated</strong> than the sodium hydroxide solution. </p> <blockquote> <p><mathjax>#color(green)(\|bar(ul(color(white)(a/a)color(black)(["HCl"] > "0.40 M")color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>So, use the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> and volume of the sodium hydroxide solution to determine how many moles of solute it contains </p> <blockquote> <p><mathjax>#color(purple)(\|bar(ul(color(white)(a/a)color(black)(c = n_"solute"/V_"solution" implies n_"solute" = c * V_"solution")color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>You will find</p> <blockquote> <p><mathjax>#n_(NaOH) = "0.40 mol" color(red)(cancel(color(black)("L"^(-1)))) * overbrace(15 * 10^(-3)color(red)(cancel(color(black)("L"))))^(color(blue)("volume in liters"))#</mathjax></p> <p><mathjax>#n_(NaOH) = "0.00600 moles NaOH"#</mathjax></p> </blockquote> <p>Now simply use the volume of the hydrochloric acid solution to find its concentration </p> <blockquote> <p><mathjax>#["HCl"] = "0.00600 moles"/(10 * 10^(-3)"L") = color(green)(\|bar(ul(color(white)(a/a)"0.60 M"color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>I'll leave the answer rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>. </p> <p>As predicted, the hydrochloric acid solution was <em>more concentrated</em> than the sodium hydroxide solution. </p> <blockquote> <p><mathjax>#["HCl"] > ["NaOH"] color(white)(a)color(green)(sqrt())#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"0.60 M"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><em>Hydrochloric acid</em>, <mathjax>#"HCl"#</mathjax>, a <strong>strong acid</strong>, will react with <em>sodium hydroxide</em>, <mathjax>#"NaOH"#</mathjax>, a <strong>strong base</strong>, to produce water and aqueous sodium chloride, <mathjax>#"NaCl"#</mathjax>. </p> <blockquote> <blockquote> <p><img alt="https://mrzsedwiki.wikispaces.com/WARM-UPS!+%26+LEARNING+OBJECTIVES+2014" src="https://useruploads.socratic.org/RrNEaGnESkSPYwulGAct_naoh%20%2B%20hcl.jpeg%22%3B+size%3D%226728"/> </p> </blockquote> </blockquote> <p>As you can see, it takes <strong>one mole</strong> of hydrochloric acid to neutralize <strong>one mole</strong> of strong base. This means that a <em>complete <a href="https://socratic.org/chemistry/reactions-in-solution/neutralization">neutralization</a></em> requires <strong>equal numbers of moles</strong> of the two reactants. </p> <p>Even without doing any calculations, you can look at the values given to you and try to estimate the concentration of the hydrochloric acid solution <strong>relative</strong> to that of the sodium hydroxide. </p> <p>You know that <mathjax>#"10 mL"#</mathjax> of this hydrochloric acid solution must contain <strong>the same number of moles</strong> of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> as <mathjax>#"15 mL"#</mathjax> of sodium hydroxide solution. </p> <p>Since you have the same number of moles in a <strong>smaller volume</strong>, it follows that the hydrochloric acid solution will be <strong>more concentrated</strong> than the sodium hydroxide solution. </p> <blockquote> <p><mathjax>#color(green)(\|bar(ul(color(white)(a/a)color(black)(["HCl"] > "0.40 M")color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>So, use the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> and volume of the sodium hydroxide solution to determine how many moles of solute it contains </p> <blockquote> <p><mathjax>#color(purple)(\|bar(ul(color(white)(a/a)color(black)(c = n_"solute"/V_"solution" implies n_"solute" = c * V_"solution")color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>You will find</p> <blockquote> <p><mathjax>#n_(NaOH) = "0.40 mol" color(red)(cancel(color(black)("L"^(-1)))) * overbrace(15 * 10^(-3)color(red)(cancel(color(black)("L"))))^(color(blue)("volume in liters"))#</mathjax></p> <p><mathjax>#n_(NaOH) = "0.00600 moles NaOH"#</mathjax></p> </blockquote> <p>Now simply use the volume of the hydrochloric acid solution to find its concentration </p> <blockquote> <p><mathjax>#["HCl"] = "0.00600 moles"/(10 * 10^(-3)"L") = color(green)(\|bar(ul(color(white)(a/a)"0.60 M"color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>I'll leave the answer rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>. </p> <p>As predicted, the hydrochloric acid solution was <em>more concentrated</em> than the sodium hydroxide solution. </p> <blockquote> <p><mathjax>#["HCl"] > ["NaOH"] color(white)(a)color(green)(sqrt())#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A 10 mL sample of hydrochloric acid neutralizes 15 mL of a 0.40 M solution of #NaOH#. What is the molarity of the hydrochloric acid?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#reactions-in-solution" itemprop="url"> <span class="breadcrumb" itemprop="title">Reactions in Solution</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/reactions-in-solution/neutralization" itemprop="url"> <span class="breadcrumb" itemprop="title">Neutralization</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="258293" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-04-24T20:51:24" itemprop="dateCreated"> Apr 24, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"0.60 M"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><em>Hydrochloric acid</em>, <mathjax>#"HCl"#</mathjax>, a <strong>strong acid</strong>, will react with <em>sodium hydroxide</em>, <mathjax>#"NaOH"#</mathjax>, a <strong>strong base</strong>, to produce water and aqueous sodium chloride, <mathjax>#"NaCl"#</mathjax>. </p> <blockquote> <blockquote> <p><img alt="https://mrzsedwiki.wikispaces.com/WARM-UPS!+%26+LEARNING+OBJECTIVES+2014" src="https://useruploads.socratic.org/RrNEaGnESkSPYwulGAct_naoh%20%2B%20hcl.jpeg%22%3B+size%3D%226728"/> </p> </blockquote> </blockquote> <p>As you can see, it takes <strong>one mole</strong> of hydrochloric acid to neutralize <strong>one mole</strong> of strong base. This means that a <em>complete <a href="https://socratic.org/chemistry/reactions-in-solution/neutralization">neutralization</a></em> requires <strong>equal numbers of moles</strong> of the two reactants. </p> <p>Even without doing any calculations, you can look at the values given to you and try to estimate the concentration of the hydrochloric acid solution <strong>relative</strong> to that of the sodium hydroxide. </p> <p>You know that <mathjax>#"10 mL"#</mathjax> of this hydrochloric acid solution must contain <strong>the same number of moles</strong> of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> as <mathjax>#"15 mL"#</mathjax> of sodium hydroxide solution. </p> <p>Since you have the same number of moles in a <strong>smaller volume</strong>, it follows that the hydrochloric acid solution will be <strong>more concentrated</strong> than the sodium hydroxide solution. </p> <blockquote> <p><mathjax>#color(green)(\|bar(ul(color(white)(a/a)color(black)(["HCl"] > "0.40 M")color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>So, use the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> and volume of the sodium hydroxide solution to determine how many moles of solute it contains </p> <blockquote> <p><mathjax>#color(purple)(\|bar(ul(color(white)(a/a)color(black)(c = n_"solute"/V_"solution" implies n_"solute" = c * V_"solution")color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>You will find</p> <blockquote> <p><mathjax>#n_(NaOH) = "0.40 mol" color(red)(cancel(color(black)("L"^(-1)))) * overbrace(15 * 10^(-3)color(red)(cancel(color(black)("L"))))^(color(blue)("volume in liters"))#</mathjax></p> <p><mathjax>#n_(NaOH) = "0.00600 moles NaOH"#</mathjax></p> </blockquote> <p>Now simply use the volume of the hydrochloric acid solution to find its concentration </p> <blockquote> <p><mathjax>#["HCl"] = "0.00600 moles"/(10 * 10^(-3)"L") = color(green)(\|bar(ul(color(white)(a/a)"0.60 M"color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>I'll leave the answer rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>. </p> <p>As predicted, the hydrochloric acid solution was <em>more concentrated</em> than the sodium hydroxide solution. </p> <blockquote> <p><mathjax>#["HCl"] > ["NaOH"] color(white)(a)color(green)(sqrt())#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/258293" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-neutralization-reactions-useful"> How are neutralization reactions useful? 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What is the molarity of the hydrochloric acid?	null
2,475	ac2f7cec-6ddd-11ea-bd70-ccda262736ce	https://socratic.org/questions/2-30-l-of-air-at-4-53-atm-is-expanded-to-2219-mmhg-what-is-the-final-volume-in-m	3570 mL	start physical_unit 3 3 volume ml qc_end physical_unit 3 3 0 1 volume qc_end physical_unit 3 3 5 6 pressure qc_end physical_unit 3 3 10 11 pressure qc_end end	[{"type":"physical unit","value":"Volume2 [OF] air [IN] mL"}]	[{"type":"physical unit","value":"3570 mL"}]	[{"type":"physical unit","value":"Volume1 [OF] air [=] \\pu{2.30 L}"},{"type":"physical unit","value":"Pressure1 [OF] air [=] \\pu{4.53 atm}"},{"type":"physical unit","value":"Pressure2 [OF] air [=] \\pu{2219 mmHg}"}]	<h1 class="questionTitle" itemprop="name"> 2.30 L of air at 4.53 atm is expanded to 2219 mmHg. What is the final volume in mL?</h1>	null	3570 mL	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#1atm#</mathjax> will support a column of mercury <mathjax>#760mm#</mathjax> high. Often, we quote the pressure as <mathjax>#760mm#</mathjax> <mathjax>#Hg#</mathjax> (or thereabouts) in order to report daily fluctuations in pressure. In fact due to safety concerns, mercury has almost disappeared from modern laboratories. </p> <p>It is tempting to say that <mathjax>#2219#</mathjax> <mathjax>#mmHg#</mathjax> </p> <p><mathjax>#-=#</mathjax> <mathjax>#(2219mmHg)/(760mmHgatm^-1)~=3atm#</mathjax></p> <p>But I would resist this temptation. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2219#</mathjax> <mathjax>#mmHg#</mathjax> is an absurd unit. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#1atm#</mathjax> will support a column of mercury <mathjax>#760mm#</mathjax> high. Often, we quote the pressure as <mathjax>#760mm#</mathjax> <mathjax>#Hg#</mathjax> (or thereabouts) in order to report daily fluctuations in pressure. In fact due to safety concerns, mercury has almost disappeared from modern laboratories. </p> <p>It is tempting to say that <mathjax>#2219#</mathjax> <mathjax>#mmHg#</mathjax> </p> <p><mathjax>#-=#</mathjax> <mathjax>#(2219mmHg)/(760mmHgatm^-1)~=3*atm#</mathjax></p> <p>But I would resist this temptation. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name"> 2.30 L of air at 4.53 atm is expanded to 2219 mmHg. What is the final volume in mL?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/charles-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Charles' Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="377151" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-02-13T03:52:22" itemprop="dateCreated"> Feb 13, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2219#</mathjax> <mathjax>#mmHg#</mathjax> is an absurd unit. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#1atm#</mathjax> will support a column of mercury <mathjax>#760mm#</mathjax> high. Often, we quote the pressure as <mathjax>#760mm#</mathjax> <mathjax>#Hg#</mathjax> (or thereabouts) in order to report daily fluctuations in pressure. In fact due to safety concerns, mercury has almost disappeared from modern laboratories. </p> <p>It is tempting to say that <mathjax>#2219#</mathjax> <mathjax>#mmHg#</mathjax> </p> <p><mathjax>#-=#</mathjax> <mathjax>#(2219mmHg)/(760mmHgatm^-1)~=3*atm#</mathjax></p> <p>But I would resist this temptation. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/377151" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="377158" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-02-13T04:15:21" itemprop="dateCreated"> Feb 13, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The final volume will be <mathjax>#"3570 mL"#</mathjax>, rounded to three <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First the units of pressure and volume need to be the same.</p> <p><strong>Pressure</strong></p> <p><mathjax>#"1 atm=760.0 mmHg"#</mathjax></p> <p><strong>Convert mmHg to atm.</strong></p> <p><mathjax>#2219color(red)(cancelcolor(black)("mmHg"))xx(1"atm")/(760.0color(red)(cancelcolor(black)("mmHg")))="2.920 atm"#</mathjax></p> <p><strong>Volume</strong></p> <p><mathjax>#"1 L=1000 mL"#</mathjax></p> <p><strong>Convert <mathjax>#"L"#</mathjax> to <mathjax>#"mL"#</mathjax>.</strong></p> <p><mathjax>#2.30color(red)(cancel(color(black)("L")))xx(1000"mL")/(1color(red)(cancel(color(black)("L"))))="2300 mL"=2.30xx10^3"mL"#</mathjax> </p> <p>The number of mL above is given to three significant figures using <a href="https://socratic.org/chemistry/measurement-in-chemistry/scientific-notation">scientific notation</a>. I will use <mathjax>#"2300 mL"#</mathjax> for convenience only.</p> <p>This question is concerns <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's Law</a></strong> , which states that the volume <mathjax>#(V)#</mathjax> of a gas held at constant amount and temperature, is inversely proportional to the pressure <mathjax>#(P)#</mathjax>. This means that if the pressure goes up, the volume goes down, and vice-versa. The equation to use is:</p> <p><mathjax>#P_1V_1=P_2V_2#</mathjax></p> <p><strong>Write what you know:</strong></p> <p><mathjax>#P_1="4.53 atm"#</mathjax><br/> <mathjax>#V_1=2.30xx10^3"mL"#</mathjax><br/> <mathjax>#P_2="2.920 atm"#</mathjax></p> <p><strong>Write what you don't know:</strong> <mathjax>#V_2#</mathjax>.</p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#V_2#</mathjax>. Substitute the known quantities into the equation and solve.</p> <p><mathjax>#V_2=(P_1V_1)/(P_2)#</mathjax></p> <p><mathjax>#V_2=(4.53color(red)(cancel(color(black)("atm")))xx2300"mL")/(2.920color(red)(cancel(color(black)("atm"))))="3570 mL"#</mathjax> rounded to three significant figures</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/377158" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-must-charles-law-be-in-kelvins"> Why must Charles' law be in kelvin? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-charles-law-formula"> What is Charles' law formula? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/oxygen-gas-is-at-a-temperature-of-40-c-when-it-occupies-a-volume-of-2-3-liters-t"> Oxygen gas is at a temperature of 40°C when it occupies a volume of 2.3 liters. 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What will be volume of oxygen when the... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/charles-law"> See all questions in Charles' Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2419 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	2.30 L of air at 4.53 atm is expanded to 2219 mmHg. What is the final volume in mL?	null
2,476	a9ecf7dc-6ddd-11ea-b549-ccda262736ce	https://socratic.org/questions/how-would-you-find-the-molecular-formula-for-a-compound-with-the-empirical-formu	C6H12O6	start chemical_formula qc_end physical_unit 9 9 20 21 molar_mass qc_end c_other OTHER qc_end end	[{"type":"other","value":"Chemical Formula [OF] the compound [IN] molecular"}]	[{"type":"chemical equation","value":"C6H12O6"}]	[{"type":"physical unit","value":"Molar mass [OF] the compound [=] \\pu{180.2 g/mol}"},{"type":"other","value":"The compound has the empirical formula CH2O."}]	<h1 class="questionTitle" itemprop="name">How would you find the molecular formula for a compound with the empirical formula CH2O and the molar mass is 180.2 g/mol?</h1>	null	C6H12O6	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>A compound's <em>empirical formula</em> tells you the <strong>smallest whole number ratio</strong> between the <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> that make up said compound is. </p> <p>This means that you can think about the <em>empirical formula</em> as being a sort of building block for the molecule. </p> <p>Looking at the empirical formula for your compound, <mathjax>#"CH"_2"O"#</mathjax>, you know that you need </p> <blockquote> <ul> <li><em>one carbon atom</em></li> <li><em>two hydrogen atoms</em></li> <li><em>one oxygen atom</em> </li> </ul> </blockquote> <p>in order to start building this molecule. Your job now is to determine <strong>how many</strong> of these building blocks are needed to get the <strong>molecular formula</strong> of the compound. </p> <p>Notice that you know the <strong>molar mass</strong> of the compound. The molar mass tells you what the <strong>total mass</strong> of one mole of the compound is.</p> <p>This means that if you figure out the molar mass of a building block, you can use the total molar mass of the molecule to determine how many buildings blocks you need. </p> <p>To get the molar mass of the empirical formula, use the molar masses of each <strong>atom</strong> it contains </p> <blockquote> <p><mathjax>#overbrace(1 xx "12.011 g/mol")^(color(blue)("one mole of C")) + overbrace(2 xx "1.00794 g/mol")^(color(green)("two moles of H")) + overbrace(1 xx "15.9994 g/mol")^(color(red)("one mole of O")) = "30.03 g/mol"#</mathjax></p> </blockquote> <p>So, one building block has a molar mass of <mathjax>#"30.03 g/mol"#</mathjax>, and the molar mass of the molecule is <mathjax>#"180.2 g/mol"#</mathjax>. This means that you have</p> <blockquote> <p><mathjax># 30.03 color(red)(cancel(color(black)("g/mol"))) * color(blue)(n) = 180.2 color(red)(cancel(color(black)("g/mol")))#</mathjax></p> <p><mathjax>#color(blue)(n) = 180.2/30.03 = 6.0007 ~~ 6#</mathjax></p> </blockquote> <p>The <strong>molecular formula</strong> of the compound will thus be </p> <blockquote> <p><mathjax>#("CH"_2"O")_color(blue)(6) implies "C"_6"H"_12"O"_6 ->#</mathjax> <em>glucose</em></p> </blockquote> <p><img alt="http://www.nutritionalhq.com/about-carbohydrates/about-glucose/" src="https://useruploads.socratic.org/XftRQDW3SReJeR0NSFKO_Glucose-molecule-model.jpg"/> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"C"_6"H"_12"O"_6#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>A compound's <em>empirical formula</em> tells you the <strong>smallest whole number ratio</strong> between the <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> that make up said compound is. </p> <p>This means that you can think about the <em>empirical formula</em> as being a sort of building block for the molecule. </p> <p>Looking at the empirical formula for your compound, <mathjax>#"CH"_2"O"#</mathjax>, you know that you need </p> <blockquote> <ul> <li><em>one carbon atom</em></li> <li><em>two hydrogen atoms</em></li> <li><em>one oxygen atom</em> </li> </ul> </blockquote> <p>in order to start building this molecule. Your job now is to determine <strong>how many</strong> of these building blocks are needed to get the <strong>molecular formula</strong> of the compound. </p> <p>Notice that you know the <strong>molar mass</strong> of the compound. The molar mass tells you what the <strong>total mass</strong> of one mole of the compound is.</p> <p>This means that if you figure out the molar mass of a building block, you can use the total molar mass of the molecule to determine how many buildings blocks you need. </p> <p>To get the molar mass of the empirical formula, use the molar masses of each <strong>atom</strong> it contains </p> <blockquote> <p><mathjax>#overbrace(1 xx "12.011 g/mol")^(color(blue)("one mole of C")) + overbrace(2 xx "1.00794 g/mol")^(color(green)("two moles of H")) + overbrace(1 xx "15.9994 g/mol")^(color(red)("one mole of O")) = "30.03 g/mol"#</mathjax></p> </blockquote> <p>So, one building block has a molar mass of <mathjax>#"30.03 g/mol"#</mathjax>, and the molar mass of the molecule is <mathjax>#"180.2 g/mol"#</mathjax>. This means that you have</p> <blockquote> <p><mathjax># 30.03 color(red)(cancel(color(black)("g/mol"))) * color(blue)(n) = 180.2 color(red)(cancel(color(black)("g/mol")))#</mathjax></p> <p><mathjax>#color(blue)(n) = 180.2/30.03 = 6.0007 ~~ 6#</mathjax></p> </blockquote> <p>The <strong>molecular formula</strong> of the compound will thus be </p> <blockquote> <p><mathjax>#("CH"_2"O")_color(blue)(6) implies "C"_6"H"_12"O"_6 ->#</mathjax> <em>glucose</em></p> </blockquote> <p><img alt="http://www.nutritionalhq.com/about-carbohydrates/about-glucose/" src="https://useruploads.socratic.org/XftRQDW3SReJeR0NSFKO_Glucose-molecule-model.jpg"/> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How would you find the molecular formula for a compound with the empirical formula CH2O and the molar mass is 180.2 g/mol?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="194003" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-28T16:28:03" itemprop="dateCreated"> Nov 28, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"C"_6"H"_12"O"_6#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>A compound's <em>empirical formula</em> tells you the <strong>smallest whole number ratio</strong> between the <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> that make up said compound is. </p> <p>This means that you can think about the <em>empirical formula</em> as being a sort of building block for the molecule. </p> <p>Looking at the empirical formula for your compound, <mathjax>#"CH"_2"O"#</mathjax>, you know that you need </p> <blockquote> <ul> <li><em>one carbon atom</em></li> <li><em>two hydrogen atoms</em></li> <li><em>one oxygen atom</em> </li> </ul> </blockquote> <p>in order to start building this molecule. Your job now is to determine <strong>how many</strong> of these building blocks are needed to get the <strong>molecular formula</strong> of the compound. </p> <p>Notice that you know the <strong>molar mass</strong> of the compound. The molar mass tells you what the <strong>total mass</strong> of one mole of the compound is.</p> <p>This means that if you figure out the molar mass of a building block, you can use the total molar mass of the molecule to determine how many buildings blocks you need. </p> <p>To get the molar mass of the empirical formula, use the molar masses of each <strong>atom</strong> it contains </p> <blockquote> <p><mathjax>#overbrace(1 xx "12.011 g/mol")^(color(blue)("one mole of C")) + overbrace(2 xx "1.00794 g/mol")^(color(green)("two moles of H")) + overbrace(1 xx "15.9994 g/mol")^(color(red)("one mole of O")) = "30.03 g/mol"#</mathjax></p> </blockquote> <p>So, one building block has a molar mass of <mathjax>#"30.03 g/mol"#</mathjax>, and the molar mass of the molecule is <mathjax>#"180.2 g/mol"#</mathjax>. This means that you have</p> <blockquote> <p><mathjax># 30.03 color(red)(cancel(color(black)("g/mol"))) * color(blue)(n) = 180.2 color(red)(cancel(color(black)("g/mol")))#</mathjax></p> <p><mathjax>#color(blue)(n) = 180.2/30.03 = 6.0007 ~~ 6#</mathjax></p> </blockquote> <p>The <strong>molecular formula</strong> of the compound will thus be </p> <blockquote> <p><mathjax>#("CH"_2"O")_color(blue)(6) implies "C"_6"H"_12"O"_6 ->#</mathjax> <em>glucose</em></p> </blockquote> <p><img alt="http://www.nutritionalhq.com/about-carbohydrates/about-glucose/" src="https://useruploads.socratic.org/XftRQDW3SReJeR0NSFKO_Glucose-molecule-model.jpg"/> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/194003" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molecular-formula-of-a-compound"> How do you find molecular formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-diamond"> What is the chemical formula of a diamond? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-carbohydrate"> What is the chemical formula of a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-valproic-acid"> What is the empirical formula for valproic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-of-magnesium-oxide"> What is the empirical formula of magnesium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-empirical-formula-not-double-that-of-the-monosaccharides"> Why is the empirical formula not double that of the monosaccharides? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5331180502bf342f40b5c3b5"> Question #5c3b5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-molecular-formula-represents-a-carbohydrate"> What molecular formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-of-vinegar"> What is the molecular formula of vinegar? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/empirical-and-molecular-formulas"> See all questions in Empirical and Molecular Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 53942 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How would you find the molecular formula for a compound with the empirical formula CH2O and the molar mass is 180.2 g/mol?	null
2,477	ac352202-6ddd-11ea-b232-ccda262736ce	https://socratic.org/questions/what-is-the-final-temperature-of-400g-of-water-at-20-c-after-it-absorbs-226-kj-o	155 ℃	start physical_unit 9 9 temperature °c qc_end physical_unit 9 9 6 7 mass qc_end physical_unit 9 9 11 12 temperature qc_end physical_unit 9 9 16 17 heat_energy qc_end end	[{"type":"physical unit","value":"Temperature2 [OF] water [IN] ℃"}]	[{"type":"physical unit","value":"155 ℃"}]	[{"type":"physical unit","value":"Mass [OF] water [=] \\pu{400 g}"},{"type":"physical unit","value":"Temperature1 [OF] water [=] \\pu{20 ℃}"},{"type":"physical unit","value":"Absorbed heat [OF] water [=] \\pu{226 kJ}"}]	<h1 class="questionTitle" itemprop="name">What is the final temperature of 400 g of water at 20°C after it absorbs 226 kJ of heat? </h1>	null	155 ℃	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>I would use the relationship:<br/> <mathjax>#Q=mcDeltaT#</mathjax><br/> where:<br/> <mathjax>#Q#</mathjax> is the heat;<br/> <mathjax>#m#</mathjax> is the mass;<br/> <mathjax>#c#</mathjax> is the <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a>;<br/> <mathjax>#DeltaT=T_f-T_i#</mathjax> is the difference in temperature.<br/> From literature we have:<br/> <mathjax>#c_("water")=4.18J/(g^@C)#</mathjax><br/> So we have:<br/> <mathjax>#226xx10^3=400*4.18(T_f-20)#</mathjax><br/> <mathjax>#T_f=155^@C#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>I found: <mathjax>#T_f=155^@C#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>I would use the relationship:<br/> <mathjax>#Q=mcDeltaT#</mathjax><br/> where:<br/> <mathjax>#Q#</mathjax> is the heat;<br/> <mathjax>#m#</mathjax> is the mass;<br/> <mathjax>#c#</mathjax> is the <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a>;<br/> <mathjax>#DeltaT=T_f-T_i#</mathjax> is the difference in temperature.<br/> From literature we have:<br/> <mathjax>#c_("water")=4.18J/(g^@C)#</mathjax><br/> So we have:<br/> <mathjax>#226xx10^3=400*4.18(T_f-20)#</mathjax><br/> <mathjax>#T_f=155^@C#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the final temperature of 400 g of water at 20°C after it absorbs 226 kJ of heat? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/calorimetry" itemprop="url"> <span class="breadcrumb" itemprop="title">Calorimetry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="269704" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/gio"><img alt="" class="" src="https://profilepictures.socratic.org/PDAQ7XlwRXWLdTy9hfbV_kuruma.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/gio"> Gió </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-26T00:15:00" itemprop="dateCreated"> May 26, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>I found: <mathjax>#T_f=155^@C#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>I would use the relationship:<br/> <mathjax>#Q=mcDeltaT#</mathjax><br/> where:<br/> <mathjax>#Q#</mathjax> is the heat;<br/> <mathjax>#m#</mathjax> is the mass;<br/> <mathjax>#c#</mathjax> is the <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a>;<br/> <mathjax>#DeltaT=T_f-T_i#</mathjax> is the difference in temperature.<br/> From literature we have:<br/> <mathjax>#c_("water")=4.18J/(g^@C)#</mathjax><br/> So we have:<br/> <mathjax>#226xx10^3=400*4.18(T_f-20)#</mathjax><br/> <mathjax>#T_f=155^@C#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/269704" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-differential-scanning-in-calorimetry-work"> How does differential scanning in calorimetry work? 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2,478	a9af0ce4-6ddd-11ea-a0db-ccda262736ce	https://socratic.org/questions/how-much-energy-is-required-to-convert-100-0-g-of-water-at-20-0-c-completely-to-	259.47 kJ	start physical_unit 10 10 energy kj qc_end physical_unit 10 10 7 8 mass qc_end physical_unit 10 10 12 13 temperature qc_end physical_unit 16 16 18 19 temperature qc_end end	[{"type":"physical unit","value":"Required energy [OF] water [IN] kJ"}]	[{"type":"physical unit","value":"259.47 kJ"}]	[{"type":"physical unit","value":"Mass [OF] water [=] \\pu{100.0 g}"},{"type":"physical unit","value":"Temperature1 [OF] water [=] \\pu{20.0 ℃}"},{"type":"physical unit","value":"Temperature2 [OF] steam [=] \\pu{100.0 ℃}"}]	<h1 class="questionTitle" itemprop="name">How much energy is required to convert 100.0 g of water at 20.0 °C completely to steam at 100.0 °C?</h1>	null	259.47 kJ	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>This is like the Socratic problem <a href="http://socratic.org/questions/how-much-energy-is-needed-to-convert-23-0-grams-of-ice-at-10-0-c-into-steam-at-1">here</a>.</p> <p>For this problem, there are only two heats to consider:</p> <p><mathjax>#q_1#</mathjax> = heat required to warm the water from 20.0 °C to 100.0 °C.<br/> <mathjax>#q_2#</mathjax> = heat required to vapourize the water to steam at 100 °C.</p> <p><mathjax>#q_1 = mcΔT = "100.0 g × 4.184 J"^°"C"^(-1)"g"^(-1) × 80.0^°"C" = "33 472 J" #</mathjax></p> <p><mathjax>#q_2 = mΔH_"vap" = "100.0 g × 2260 J·g"^(-1) = "226 000 J"#</mathjax></p> <p><mathjax>#q_1 + q_2 = "( 33 472 + 226 000) J = 259 472 J = 259.5 kJ"#</mathjax> (4 significant figures)</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>To convert 100.0 g of water at 20.0 °C to steam at 100.0 °C requires 259.5 kJ of energy.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>This is like the Socratic problem <a href="http://socratic.org/questions/how-much-energy-is-needed-to-convert-23-0-grams-of-ice-at-10-0-c-into-steam-at-1">here</a>.</p> <p>For this problem, there are only two heats to consider:</p> <p><mathjax>#q_1#</mathjax> = heat required to warm the water from 20.0 °C to 100.0 °C.<br/> <mathjax>#q_2#</mathjax> = heat required to vapourize the water to steam at 100 °C.</p> <p><mathjax>#q_1 = mcΔT = "100.0 g × 4.184 J"^°"C"^(-1)"g"^(-1) × 80.0^°"C" = "33 472 J" #</mathjax></p> <p><mathjax>#q_2 = mΔH_"vap" = "100.0 g × 2260 J·g"^(-1) = "226 000 J"#</mathjax></p> <p><mathjax>#q_1 + q_2 = "( 33 472 + 226 000) J = 259 472 J = 259.5 kJ"#</mathjax> (4 significant figures)</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How much energy is required to convert 100.0 g of water at 20.0 °C completely to steam at 100.0 °C?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/thermochemistry-of-phase-changes" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry of Phase Changes</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="107165" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2014-07-25T20:41:04" itemprop="dateCreated"> Jul 25, 2014 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>To convert 100.0 g of water at 20.0 °C to steam at 100.0 °C requires 259.5 kJ of energy.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>This is like the Socratic problem <a href="http://socratic.org/questions/how-much-energy-is-needed-to-convert-23-0-grams-of-ice-at-10-0-c-into-steam-at-1">here</a>.</p> <p>For this problem, there are only two heats to consider:</p> <p><mathjax>#q_1#</mathjax> = heat required to warm the water from 20.0 °C to 100.0 °C.<br/> <mathjax>#q_2#</mathjax> = heat required to vapourize the water to steam at 100 °C.</p> <p><mathjax>#q_1 = mcΔT = "100.0 g × 4.184 J"^°"C"^(-1)"g"^(-1) × 80.0^°"C" = "33 472 J" #</mathjax></p> <p><mathjax>#q_2 = mΔH_"vap" = "100.0 g × 2260 J·g"^(-1) = "226 000 J"#</mathjax></p> <p><mathjax>#q_1 + q_2 = "( 33 472 + 226 000) J = 259 472 J = 259.5 kJ"#</mathjax> (4 significant figures)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/107165" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div 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2,479	aa864f78-6ddd-11ea-aaed-ccda262736ce	https://socratic.org/questions/chemistry-calorimetry-calculating-heat-capacity-help-please	85.00 ℃	start physical_unit 46 47 temperature °c qc_end physical_unit 10 11 13 14 temperature qc_end physical_unit 10 11 26 27 temperature qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Temperature3 [OF] the calorimeter [IN] ℃"}]	[{"type":"physical unit","value":"85.00 ℃"}]	[{"type":"physical unit","value":"Temperature1 [OF] copper jewelry [=] \\pu{105 ℃}"},{"type":"physical unit","value":"Temperature2 [OF] copper jewelry [=] \\pu{45 ℃}"},{"type":"other","value":"One piece of copper jewelry has exactly twice the mass of another piece."}]	<h1 class="questionTitle" itemprop="name">Chemistry; Calorimetry; Calculating Heat Capacity; Help Please?!</h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>One piece of copper jewelry at 105C has exactly twice the mass of another piece, which is at 45C. Both pieces are placed inside a calorimeter whose heat capacity is negligible. What is the final temperature inside the calorimeter?</p></div> </h2> </div> </div>	85.00 ℃	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that the heat <strong>lost</strong> by the piece of jewelry that starts at a <em>higher temperature</em> will be <strong>equal</strong> to the heat <strong>gained</strong> by the piece of jewelry that starts at a <em>lower temperature</em>. </p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)(q_"gained" = - q_"lost")))" " " "color(darkorange)("( * )")#</mathjax></p> <blockquote> <p>The <em>minus sign</em> is used here because the heat <strong>given off</strong> by the jewelry that <em>cools off</em> carries a negative sign!</p> </blockquote> </blockquote> <p>Now, you can calculate the heat gained or given off by a substance by using the equation</p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)(q = m * c * DeltaT)))#</mathjax></p> </blockquote> <p>Here</p> <blockquote> <ul> <li><mathjax>#m#</mathjax> is the <strong>mass</strong> of the sample</li> <li><mathjax>#c#</mathjax> is the <strong><a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a></strong> of the substance</li> <li><mathjax>#DeltaT#</mathjax> is the <strong>change in temperature</strong>, calculated as the difference between the <em>final temperature</em> and the <em>initial temperature</em> of the substance</li> </ul> </blockquote> <p>If you take <mathjax>#T_"f"#</mathjax> <mathjax>#""^@"C"#</mathjax> to be the <strong>final temperature</strong> inside the calorimeter, you can say that the heat <strong>gained</strong> by the piece that starts at <mathjax>#45^@"C"#</mathjax> is equal to</p> <blockquote> <p><mathjax>#q_"gained" = m * c * (T_"f" - 45)^@"C"#</mathjax></p> </blockquote> <p>Similarly, the heat <strong>lost</strong> by the piece that starts at <mathjax>#105^@"C"#</mathjax> will be equal to--keep in mind that this piece has <strong>twice the mass</strong>, or <mathjax>#2m#</mathjax></p> <blockquote> <p><mathjax>#q_"lost" = 2m * c * (T_"f" - 105)^@"C"#</mathjax></p> </blockquote> <p>Use equation <mathjax>#color(darkorange)("( * )")#</mathjax> to say that--since both pieces of jewelry are made of copper, you know that they will have the same value for <mathjax>#c#</mathjax></p> <blockquote> <p><mathjax>#color(red)(cancel(color(black)(m))) * color(red)(cancel(color(black)(c))) * (T_"f" - 45) color(red)(cancel(color(black)(""^@"C"))) = - 2color(red)(cancel(color(black)(m))) * color(red)(cancel(color(black)(c))) * (T_"f" - 105)color(red)(cancel(color(black)(""^@"C")))#</mathjax></p> </blockquote> <p>This is equivalent to</p> <blockquote> <p><mathjax>#T_"f" - 45 = -2T_"f" + 210#</mathjax></p> </blockquote> <p>Solve for <mathjax>#T_"f"#</mathjax> to find</p> <blockquote> <p><mathjax>#3T_"f" = 210 + 45#</mathjax></p> <p><mathjax>#T_"f" = 255/3 = 85#</mathjax></p> </blockquote> <p>Therefore, you can say that the final temperature of the mixture is equal to </p> <blockquote> <p><mathjax>#color(darkgreen)(ul(color(black)("final temperature" = 85^@"C")))#</mathjax></p> </blockquote> <p>The answer is rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#85^@"C"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that the heat <strong>lost</strong> by the piece of jewelry that starts at a <em>higher temperature</em> will be <strong>equal</strong> to the heat <strong>gained</strong> by the piece of jewelry that starts at a <em>lower temperature</em>. </p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)(q_"gained" = - q_"lost")))" " " "color(darkorange)("( * )")#</mathjax></p> <blockquote> <p>The <em>minus sign</em> is used here because the heat <strong>given off</strong> by the jewelry that <em>cools off</em> carries a negative sign!</p> </blockquote> </blockquote> <p>Now, you can calculate the heat gained or given off by a substance by using the equation</p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)(q = m * c * DeltaT)))#</mathjax></p> </blockquote> <p>Here</p> <blockquote> <ul> <li><mathjax>#m#</mathjax> is the <strong>mass</strong> of the sample</li> <li><mathjax>#c#</mathjax> is the <strong><a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a></strong> of the substance</li> <li><mathjax>#DeltaT#</mathjax> is the <strong>change in temperature</strong>, calculated as the difference between the <em>final temperature</em> and the <em>initial temperature</em> of the substance</li> </ul> </blockquote> <p>If you take <mathjax>#T_"f"#</mathjax> <mathjax>#""^@"C"#</mathjax> to be the <strong>final temperature</strong> inside the calorimeter, you can say that the heat <strong>gained</strong> by the piece that starts at <mathjax>#45^@"C"#</mathjax> is equal to</p> <blockquote> <p><mathjax>#q_"gained" = m * c * (T_"f" - 45)^@"C"#</mathjax></p> </blockquote> <p>Similarly, the heat <strong>lost</strong> by the piece that starts at <mathjax>#105^@"C"#</mathjax> will be equal to--keep in mind that this piece has <strong>twice the mass</strong>, or <mathjax>#2m#</mathjax></p> <blockquote> <p><mathjax>#q_"lost" = 2m * c * (T_"f" - 105)^@"C"#</mathjax></p> </blockquote> <p>Use equation <mathjax>#color(darkorange)("( * )")#</mathjax> to say that--since both pieces of jewelry are made of copper, you know that they will have the same value for <mathjax>#c#</mathjax></p> <blockquote> <p><mathjax>#color(red)(cancel(color(black)(m))) * color(red)(cancel(color(black)(c))) * (T_"f" - 45) color(red)(cancel(color(black)(""^@"C"))) = - 2color(red)(cancel(color(black)(m))) * color(red)(cancel(color(black)(c))) * (T_"f" - 105)color(red)(cancel(color(black)(""^@"C")))#</mathjax></p> </blockquote> <p>This is equivalent to</p> <blockquote> <p><mathjax>#T_"f" - 45 = -2T_"f" + 210#</mathjax></p> </blockquote> <p>Solve for <mathjax>#T_"f"#</mathjax> to find</p> <blockquote> <p><mathjax>#3T_"f" = 210 + 45#</mathjax></p> <p><mathjax>#T_"f" = 255/3 = 85#</mathjax></p> </blockquote> <p>Therefore, you can say that the final temperature of the mixture is equal to </p> <blockquote> <p><mathjax>#color(darkgreen)(ul(color(black)("final temperature" = 85^@"C")))#</mathjax></p> </blockquote> <p>The answer is rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Chemistry; Calorimetry; Calculating Heat Capacity; Help Please?!</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>One piece of copper jewelry at 105C has exactly twice the mass of another piece, which is at 45C. Both pieces are placed inside a calorimeter whose heat capacity is negligible. What is the final temperature inside the calorimeter?</p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/calorimetry" itemprop="url"> <span class="breadcrumb" itemprop="title">Calorimetry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="472872" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-09-08T00:02:19" itemprop="dateCreated"> Sep 8, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#85^@"C"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that the heat <strong>lost</strong> by the piece of jewelry that starts at a <em>higher temperature</em> will be <strong>equal</strong> to the heat <strong>gained</strong> by the piece of jewelry that starts at a <em>lower temperature</em>. </p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)(q_"gained" = - q_"lost")))" " " "color(darkorange)("( * )")#</mathjax></p> <blockquote> <p>The <em>minus sign</em> is used here because the heat <strong>given off</strong> by the jewelry that <em>cools off</em> carries a negative sign!</p> </blockquote> </blockquote> <p>Now, you can calculate the heat gained or given off by a substance by using the equation</p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)(q = m * c * DeltaT)))#</mathjax></p> </blockquote> <p>Here</p> <blockquote> <ul> <li><mathjax>#m#</mathjax> is the <strong>mass</strong> of the sample</li> <li><mathjax>#c#</mathjax> is the <strong><a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a></strong> of the substance</li> <li><mathjax>#DeltaT#</mathjax> is the <strong>change in temperature</strong>, calculated as the difference between the <em>final temperature</em> and the <em>initial temperature</em> of the substance</li> </ul> </blockquote> <p>If you take <mathjax>#T_"f"#</mathjax> <mathjax>#""^@"C"#</mathjax> to be the <strong>final temperature</strong> inside the calorimeter, you can say that the heat <strong>gained</strong> by the piece that starts at <mathjax>#45^@"C"#</mathjax> is equal to</p> <blockquote> <p><mathjax>#q_"gained" = m * c * (T_"f" - 45)^@"C"#</mathjax></p> </blockquote> <p>Similarly, the heat <strong>lost</strong> by the piece that starts at <mathjax>#105^@"C"#</mathjax> will be equal to--keep in mind that this piece has <strong>twice the mass</strong>, or <mathjax>#2m#</mathjax></p> <blockquote> <p><mathjax>#q_"lost" = 2m * c * (T_"f" - 105)^@"C"#</mathjax></p> </blockquote> <p>Use equation <mathjax>#color(darkorange)("( * )")#</mathjax> to say that--since both pieces of jewelry are made of copper, you know that they will have the same value for <mathjax>#c#</mathjax></p> <blockquote> <p><mathjax>#color(red)(cancel(color(black)(m))) * color(red)(cancel(color(black)(c))) * (T_"f" - 45) color(red)(cancel(color(black)(""^@"C"))) = - 2color(red)(cancel(color(black)(m))) * color(red)(cancel(color(black)(c))) * (T_"f" - 105)color(red)(cancel(color(black)(""^@"C")))#</mathjax></p> </blockquote> <p>This is equivalent to</p> <blockquote> <p><mathjax>#T_"f" - 45 = -2T_"f" + 210#</mathjax></p> </blockquote> <p>Solve for <mathjax>#T_"f"#</mathjax> to find</p> <blockquote> <p><mathjax>#3T_"f" = 210 + 45#</mathjax></p> <p><mathjax>#T_"f" = 255/3 = 85#</mathjax></p> </blockquote> <p>Therefore, you can say that the final temperature of the mixture is equal to </p> <blockquote> <p><mathjax>#color(darkgreen)(ul(color(black)("final temperature" = 85^@"C")))#</mathjax></p> </blockquote> <p>The answer is rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/472872" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-differential-scanning-in-calorimetry-work"> How does differential scanning in calorimetry work? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-read-differential-scanning-in-calorimetry"> What information do you get from a differential scanning calorimetry plot? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-measure-calorimetry"> How do you measure calorimetry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531d304102bf341e75b962a7"> Question #962a7 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5335021802bf344ae911dfc5"> Question #1dfc5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/533668f502bf34572c341af6"> Question #41af6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-definition-of-calorimetry"> What is calorimetry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-differential-scanning-calorimeter"> What is a differential scanning calorimeter? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-a-calorimeter-measure-energy"> How can a calorimeter measure energy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-calorimeters-made-of"> What are calorimeters made of? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/calorimetry"> See all questions in Calorimetry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 13347 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Chemistry; Calorimetry; Calculating Heat Capacity; Help Please?!	One piece of copper jewelry at 105C has exactly twice the mass of another piece, which is at 45C. Both pieces are placed inside a calorimeter whose heat capacity is negligible. What is the final temperature inside the calorimeter?
2,480	ad11b362-6ddd-11ea-ae37-ccda262736ce	https://socratic.org/questions/in-the-reaction-4fe-3o-2-2fe-2o-3-how-many-grams-of-fe-2o-3-are-produced-from-73	104.6 grams	start physical_unit 10 10 mass g qc_end chemical_equation 3 10 qc_end physical_unit 4 4 19 20 mass qc_end end	[{"type":"physical unit","value":"Mass [OF] Fe2O3 [IN] grams"}]	[{"type":"physical unit","value":"104.6 grams"}]	[{"type":"chemical equation","value":"4 Fe + 3 O2 -> 2 Fe2O3"},{"type":"physical unit","value":"Mass [OF] Fe [=] \\pu{73.2 g}"}]	<h1 class="questionTitle" itemprop="name">In the reaction #4Fe + 3O_2 -> 2Fe_2O_3#, how many grams of #Fe_2O_3# are produced from #73.2g# #Fe#?</h1>	null	104.6 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>This can be solved through dimensional analysis. </p> <p><strong>Atomic Masses:</strong></p> <p><mathjax>#"Fe = 55.85 g/mol"#</mathjax><br/> <mathjax>#"O = 16.00 g/mol"#</mathjax></p> <p><strong>Formula Mass:</strong></p> <p><mathjax>#"Fe"_2"O"_3 ="159.69 g/mol"#</mathjax></p> <blockquote></blockquote> <p><mathjax>#"Moles of Fe" =73.2cancel("g Fe") xx ("1 mol Fe")/(55.85cancel("g Fe")) = "1.31 mol Fe"#</mathjax></p> <p><mathjax>#"Moles of Fe"_2"O"_3 =1.31 cancel("mol Fe") xx ("2 mol Fe"_2"O"_3)/(4cancel("mol Fe")) = "0.655 mol Fe"_2"O"_3#</mathjax></p> <p><mathjax>#"Mass of Fe"_2"O"_3 = 0.655cancel("mol Fe"_2"O"_3) xx ("159.69 g Fe"_2"O"_3)/(1 cancel("mol Fe"_2"O"_3)) = "104.6 g Fe"_2"O"_3#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>104.6 g of <mathjax>#"Fe"_2"O"_3#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>This can be solved through dimensional analysis. </p> <p><strong>Atomic Masses:</strong></p> <p><mathjax>#"Fe = 55.85 g/mol"#</mathjax><br/> <mathjax>#"O = 16.00 g/mol"#</mathjax></p> <p><strong>Formula Mass:</strong></p> <p><mathjax>#"Fe"_2"O"_3 ="159.69 g/mol"#</mathjax></p> <blockquote></blockquote> <p><mathjax>#"Moles of Fe" =73.2cancel("g Fe") xx ("1 mol Fe")/(55.85cancel("g Fe")) = "1.31 mol Fe"#</mathjax></p> <p><mathjax>#"Moles of Fe"_2"O"_3 =1.31 cancel("mol Fe") xx ("2 mol Fe"_2"O"_3)/(4cancel("mol Fe")) = "0.655 mol Fe"_2"O"_3#</mathjax></p> <p><mathjax>#"Mass of Fe"_2"O"_3 = 0.655cancel("mol Fe"_2"O"_3) xx ("159.69 g Fe"_2"O"_3)/(1 cancel("mol Fe"_2"O"_3)) = "104.6 g Fe"_2"O"_3#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">In the reaction #4Fe + 3O_2 -> 2Fe_2O_3#, how many grams of #Fe_2O_3# are produced from #73.2g# #Fe#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="231878" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/jarni-renz"><img alt="" class="" src="https://profilepictures.socratic.org/i6OiZQmVRHWljDVlwm8v_WIN_20160301_180231.JPG" title=""/></a> <a class="secondContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/jarni-renz"> Jarni Renz </a>·<a class="topContributorLink" href="/users/guy-c"> anor277 </a>·<a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-02-27T09:38:30" itemprop="dateCreated"> Feb 27, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>104.6 g of <mathjax>#"Fe"_2"O"_3#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>This can be solved through dimensional analysis. </p> <p><strong>Atomic Masses:</strong></p> <p><mathjax>#"Fe = 55.85 g/mol"#</mathjax><br/> <mathjax>#"O = 16.00 g/mol"#</mathjax></p> <p><strong>Formula Mass:</strong></p> <p><mathjax>#"Fe"_2"O"_3 ="159.69 g/mol"#</mathjax></p> <blockquote></blockquote> <p><mathjax>#"Moles of Fe" =73.2cancel("g Fe") xx ("1 mol Fe")/(55.85cancel("g Fe")) = "1.31 mol Fe"#</mathjax></p> <p><mathjax>#"Moles of Fe"_2"O"_3 =1.31 cancel("mol Fe") xx ("2 mol Fe"_2"O"_3)/(4cancel("mol Fe")) = "0.655 mol Fe"_2"O"_3#</mathjax></p> <p><mathjax>#"Mass of Fe"_2"O"_3 = 0.655cancel("mol Fe"_2"O"_3) xx ("159.69 g Fe"_2"O"_3)/(1 cancel("mol Fe"_2"O"_3)) = "104.6 g Fe"_2"O"_3#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/231878" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight 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2,481	a8d27980-6ddd-11ea-886f-ccda262736ce	https://socratic.org/questions/if-the-pressure-of-50-0-ml-of-oxygen-gas-at-100-c-increases-from-735-mm-hg-to-92	39.76 mL	start physical_unit 7 8 volume ml qc_end physical_unit 7 8 4 5 volume qc_end physical_unit 7 8 10 11 temperature qc_end physical_unit 7 8 14 15 pressure qc_end physical_unit 7 8 17 18 pressure qc_end c_other constant_temperature qc_end end	[{"type":"physical unit","value":"Volume2 [OF] oxygen gas [IN] mL"}]	[{"type":"physical unit","value":"39.76 mL"}]	[{"type":"physical unit","value":"Volume1 [OF] oxygen gas [=] \\pu{50.0 mL}"},{"type":"physical unit","value":"Temperature [OF] oxygen gas [=] \\pu{100 ℃}"},{"type":"physical unit","value":"Pressure1 [OF] oxygen gas [=] \\pu{ 735 mmHg}"},{"type":"physical unit","value":"Pressure2 [OF] oxygen gas [=] \\pu{925 mmHg}"},{"type":"other","value":"ConstantTemperature"}]	<h1 class="questionTitle" itemprop="name">If the pressure of 50.0 mL of oxygen gas at 100°C increases from 735 mm Hg to 925 mm Hg, what is the final volume? Assume the temperature remains constant.</h1>	null	39.76 mL	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Recall the gas law</p> <p><mathjax>#PV = nRT#</mathjax></p> <p><mathjax>#P = (nRT)/V#</mathjax></p> <p>Our question<br/> If the pressure of 50.0 mL of oxygen gas at 100°C increases from 735 mm Hg to 925 mm Hg, what is the final volume? Assume the temperature remains constant.<br/> This means</p> <p><mathjax>#735mmHg = "{n * 0.0821L * (100C + 273K )}"/ ("50.0mL "/"1000ml" )#</mathjax></p> <p>mmHg must be converted in <mathjax>#atm#</mathjax> , <mathjax>#"celsius to kelvin"#</mathjax> and <mathjax>#"ml to Litres"#</mathjax></p> <p>=1 atm = 760mmHg</p> <p><mathjax>#"735mmHg" /"760mmHg" = 0.96711atm#</mathjax></p> <p>0.9671053242406501atm = n * 0.0821L * 373K/0.05L</p> <p>Solve the equation</p> <p><mathjax>#0.9671053242406501atm = "30.6233n"/"0.05L"#</mathjax></p> <p>Multiply both sides with 0.05L</p> <p><mathjax>#\frac{30.6233n}{0.05L}0.05=0.96711atm 0.05L#</mathjax></p> <p><mathjax>#30.6233n=0.0483555#</mathjax></p> <p><mathjax>#n = 30.6233/0.048355#</mathjax></p> <p>n = 0.00158moles</p> <p>So lets now calculate volume when we know n.<br/> n is constant in both the equation.</p> <p><mathjax>#"925mmHg"/"760mmHg" = 1.2171052631578947368421052631579atm#</mathjax></p> <p><mathjax>#1.21711atm = "(0.00158 * 0.0821L * 373K)"/V#</mathjax></p> <p><mathjax>#1.21711atm = 0.048384814/V#</mathjax></p> <p><mathjax>#V = 0.048384814/"1.21711atm"#</mathjax></p> <p><mathjax>#V = 0.03976L#</mathjax></p> <p><mathjax>#"volume" = 0.03976L#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"volume" = 0.03976L#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Recall the gas law</p> <p><mathjax>#PV = nRT#</mathjax></p> <p><mathjax>#P = (nRT)/V#</mathjax></p> <p>Our question<br/> If the pressure of 50.0 mL of oxygen gas at 100°C increases from 735 mm Hg to 925 mm Hg, what is the final volume? Assume the temperature remains constant.<br/> This means</p> <p><mathjax>#735mmHg = "{n * 0.0821L * (100C + 273K )}"/ ("50.0mL "/"1000ml" )#</mathjax></p> <p>mmHg must be converted in <mathjax>#atm#</mathjax> , <mathjax>#"celsius to kelvin"#</mathjax> and <mathjax>#"ml to Litres"#</mathjax></p> <p>=1 atm = 760mmHg</p> <p><mathjax>#"735mmHg" /"760mmHg" = 0.96711atm#</mathjax></p> <p>0.9671053242406501atm = n * 0.0821L * 373K/0.05L</p> <p>Solve the equation</p> <p><mathjax>#0.9671053242406501atm = "30.6233n"/"0.05L"#</mathjax></p> <p>Multiply both sides with 0.05L</p> <p><mathjax>#\frac{30.6233n}{0.05L}0.05=0.96711atm 0.05L#</mathjax></p> <p><mathjax>#30.6233n=0.0483555#</mathjax></p> <p><mathjax>#n = 30.6233/0.048355#</mathjax></p> <p>n = 0.00158moles</p> <p>So lets now calculate volume when we know n.<br/> n is constant in both the equation.</p> <p><mathjax>#"925mmHg"/"760mmHg" = 1.2171052631578947368421052631579atm#</mathjax></p> <p><mathjax>#1.21711atm = "(0.00158 * 0.0821L * 373K)"/V#</mathjax></p> <p><mathjax>#1.21711atm = 0.048384814/V#</mathjax></p> <p><mathjax>#V = 0.048384814/"1.21711atm"#</mathjax></p> <p><mathjax>#V = 0.03976L#</mathjax></p> <p><mathjax>#"volume" = 0.03976L#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">If the pressure of 50.0 mL of oxygen gas at 100°C increases from 735 mm Hg to 925 mm Hg, what is the final volume? Assume the temperature remains constant.</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp" itemprop="url"> <span class="breadcrumb" itemprop="title">Molar Volume of a Gas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="378624" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/samriddha"><img alt="" class="" src="https://profilepictures.socratic.org/3bMcXdwZTLqpsJaquExz_Shinjuku.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/samriddha"> Professor Sam </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-02-16T12:10:07" itemprop="dateCreated"> Feb 16, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"volume" = 0.03976L#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Recall the gas law</p> <p><mathjax>#PV = nRT#</mathjax></p> <p><mathjax>#P = (nRT)/V#</mathjax></p> <p>Our question<br/> If the pressure of 50.0 mL of oxygen gas at 100°C increases from 735 mm Hg to 925 mm Hg, what is the final volume? Assume the temperature remains constant.<br/> This means</p> <p><mathjax>#735mmHg = "{n * 0.0821L * (100C + 273K )}"/ ("50.0mL "/"1000ml" )#</mathjax></p> <p>mmHg must be converted in <mathjax>#atm#</mathjax> , <mathjax>#"celsius to kelvin"#</mathjax> and <mathjax>#"ml to Litres"#</mathjax></p> <p>=1 atm = 760mmHg</p> <p><mathjax>#"735mmHg" /"760mmHg" = 0.96711atm#</mathjax></p> <p>0.9671053242406501atm = n * 0.0821L * 373K/0.05L</p> <p>Solve the equation</p> <p><mathjax>#0.9671053242406501atm = "30.6233n"/"0.05L"#</mathjax></p> <p>Multiply both sides with 0.05L</p> <p><mathjax>#\frac{30.6233n}{0.05L}0.05=0.96711atm 0.05L#</mathjax></p> <p><mathjax>#30.6233n=0.0483555#</mathjax></p> <p><mathjax>#n = 30.6233/0.048355#</mathjax></p> <p>n = 0.00158moles</p> <p>So lets now calculate volume when we know n.<br/> n is constant in both the equation.</p> <p><mathjax>#"925mmHg"/"760mmHg" = 1.2171052631578947368421052631579atm#</mathjax></p> <p><mathjax>#1.21711atm = "(0.00158 * 0.0821L * 373K)"/V#</mathjax></p> <p><mathjax>#1.21711atm = 0.048384814/V#</mathjax></p> <p><mathjax>#V = 0.048384814/"1.21711atm"#</mathjax></p> <p><mathjax>#V = 0.03976L#</mathjax></p> <p><mathjax>#"volume" = 0.03976L#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/378624" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-stoichiometric-ratios-relate-to-molar-volume-of-a-gas"> How do stoichiometric ratios relate to molar volume of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-a-gas-at-stp"> How do you calculate molar volume of a gas at STP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-molar-volume-of-hydrogen-gas"> How do you find the molar volume of hydrogen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-oxygen-gas"> How do you calculate molar volume of oxygen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molar-gas-volume"> What is molar gas volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/534c7bf202bf3420a007f014"> What is the volume at 0 °C and 1 atm of a mixture that contains 4.0 g of methane and 2.0 g of helium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5361f75702bf3429040e0599"> What is the difference between STP and NTP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-volume-of-25-moles-of-oxygen-o2-gas"> What is the volume of .25 moles of oxygen (O2) Gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-would-knowing-the-molar-volume-of-a-gas-be-important"> Why would knowing the molar volume of a gas be important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-22-4-liters-called-the-molar-volume-of-a-gas"> Why is 22.4 liters called the molar volume of a gas? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp"> See all questions in Molar Volume of a Gas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 6293 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	If the pressure of 50.0 mL of oxygen gas at 100°C increases from 735 mm Hg to 925 mm Hg, what is the final volume? Assume the temperature remains constant.	null
2,482	acb26ff8-6ddd-11ea-9fdd-ccda262736ce	https://socratic.org/questions/how-many-moles-of-naoh-are-in-10-0-ml-of-a-3-00-m-solution	0.03 moles	start physical_unit 4 4 mole mol qc_end physical_unit 13 13 7 8 volume qc_end physical_unit 4 4 11 12 molarity qc_end end	[{"type":"physical unit","value":"Mole [OF] NaOH [IN] moles"}]	[{"type":"physical unit","value":"0.03 moles"}]	[{"type":"physical unit","value":"Volume [OF] NaOH solution [=] \\pu{10.0 mL}"},{"type":"physical unit","value":"Molarity [OF] NaOH solution [=] \\pu{3.00 M}"}]	<h1 class="questionTitle" itemprop="name">How many moles of #NaOH# are in 10.0 mL of a 3.00 M solution?</h1>	null	0.03 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>here in the formula n=# of moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a><br/> and V=liter volume of solution </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Molarity=n/V#</mathjax></p> <p><mathjax>#n=MV#</mathjax></p> <p><mathjax>#n=3.00M10.0*10^-3L#</mathjax></p> <p>n=0.03 mole</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>here in the formula n=# of moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a><br/> and V=liter volume of solution </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles of #NaOH# are in 10.0 mL of a 3.00 M solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="265786" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/homidhuja"><img alt="" class="" src="https://graph.facebook.com/929753953850538/picture?height=50&width=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/homidhuja"> AKTB </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-14T17:46:44" itemprop="dateCreated"> May 14, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Molarity=n/V#</mathjax></p> <p><mathjax>#n=MV#</mathjax></p> <p><mathjax>#n=3.00M10.0*10^-3L#</mathjax></p> <p>n=0.03 mole</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>here in the formula n=# of moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a><br/> and V=liter volume of solution </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/265786" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? 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</a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-3-hydrogen-peroxide"> What is the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 10329 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many moles of #NaOH# are in 10.0 mL of a 3.00 M solution?	null
2,483	ac217e39-6ddd-11ea-9822-ccda262736ce	https://socratic.org/questions/what-is-the-molarity-of-a-salt-solution-made-by-dissolving-280-0-mg-of-nacl-in-2	2.40 M	start physical_unit 6 7 molarity mol/l qc_end c_other OTHER qc_end physical_unit 14 14 11 12 mass qc_end physical_unit 19 19 16 17 volume qc_end end	[{"type":"physical unit","value":"Molarity [OF] salt solution [IN] M"}]	[{"type":"physical unit","value":"2.40 M"}]	[{"type":"other","value":"Assume the final volume is the same as the volume of the water."},{"type":"physical unit","value":"Mass [OF] NaCl [=] \\pu{280.0 mg}"},{"type":"physical unit","value":"Volume [OF] water [=] \\pu{2.00 mL}"}]	<h1 class="questionTitle" itemprop="name">What is the molarity of a salt solution made by dissolving 280.0 mg of #NaCl# in 2.00 mL of water?</h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>Assume the final volume is the same as the volume of the water.</p></div> </h2> </div> </div>	2.40 M	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></strong> of a solution tells you how many <em>moles of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a></em> you get <strong>per liter</strong> of solution. </p> <p>Notice that the problem provides you with the volume of the solution expressed in <em>milliliters</em>, <mathjax>#"mL"#</mathjax>. Right from the start, you should remember that you <strong>must</strong> convert this volume to <em>liters</em> by using the conversion factor</p> <blockquote> <p><mathjax>#"1 L" = 10^3"mL"#</mathjax></p> </blockquote> <p>Now, in order to get the <em>number of moles</em> of solute, you must use its <strong>molar mass</strong>. Now, molar masses are listed in <em>grams per mol</em>, <mathjax>#"g mol"^(-1)#</mathjax>, which means that you're going to have to convert the mass of the sample from <em>milligrams</em> to <em>grams</em></p> <blockquote> <p><mathjax>#"1 g" = 10^3"mg"#</mathjax></p> </blockquote> <p>Sodium chloride, <mathjax>#"NaCl"#</mathjax>, has a molar mass of <mathjax>#"58.44 g mol"^(-1)#</mathjax>, which means that your sample will contain</p> <blockquote> <p><mathjax>#overbrace(280.0 color(red)(cancel(color(black)("mg"))) * (1color(red)(cancel(color(black)("g"))))/(10^3color(red)(cancel(color(black)("mg")))))^(color(purple)("unit conversion")) * overbrace("1 mole NaCl"/(58.44color(red)(cancel(color(black)("g")))))^(color(brown)("molar mass")) = "0.004791 moles NaCl"#</mathjax></p> </blockquote> <p>This means that the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of the solution will be </p> <blockquote> <p><mathjax>#color(blue)(c = n_"solute"/V_"solution")#</mathjax></p> <p><mathjax>#c = "0.004791 moles"/(2.00 * 10^(-3)"L") = color(green)("2.40 M")#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the volume of the solution. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"2.40 M"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></strong> of a solution tells you how many <em>moles of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a></em> you get <strong>per liter</strong> of solution. </p> <p>Notice that the problem provides you with the volume of the solution expressed in <em>milliliters</em>, <mathjax>#"mL"#</mathjax>. Right from the start, you should remember that you <strong>must</strong> convert this volume to <em>liters</em> by using the conversion factor</p> <blockquote> <p><mathjax>#"1 L" = 10^3"mL"#</mathjax></p> </blockquote> <p>Now, in order to get the <em>number of moles</em> of solute, you must use its <strong>molar mass</strong>. Now, molar masses are listed in <em>grams per mol</em>, <mathjax>#"g mol"^(-1)#</mathjax>, which means that you're going to have to convert the mass of the sample from <em>milligrams</em> to <em>grams</em></p> <blockquote> <p><mathjax>#"1 g" = 10^3"mg"#</mathjax></p> </blockquote> <p>Sodium chloride, <mathjax>#"NaCl"#</mathjax>, has a molar mass of <mathjax>#"58.44 g mol"^(-1)#</mathjax>, which means that your sample will contain</p> <blockquote> <p><mathjax>#overbrace(280.0 color(red)(cancel(color(black)("mg"))) * (1color(red)(cancel(color(black)("g"))))/(10^3color(red)(cancel(color(black)("mg")))))^(color(purple)("unit conversion")) * overbrace("1 mole NaCl"/(58.44color(red)(cancel(color(black)("g")))))^(color(brown)("molar mass")) = "0.004791 moles NaCl"#</mathjax></p> </blockquote> <p>This means that the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of the solution will be </p> <blockquote> <p><mathjax>#color(blue)(c = n_"solute"/V_"solution")#</mathjax></p> <p><mathjax>#c = "0.004791 moles"/(2.00 * 10^(-3)"L") = color(green)("2.40 M")#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the volume of the solution. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the molarity of a salt solution made by dissolving 280.0 mg of #NaCl# in 2.00 mL of water?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>Assume the final volume is the same as the volume of the water.</p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="232749" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-02-29T00:10:21" itemprop="dateCreated"> Feb 29, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"2.40 M"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></strong> of a solution tells you how many <em>moles of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a></em> you get <strong>per liter</strong> of solution. </p> <p>Notice that the problem provides you with the volume of the solution expressed in <em>milliliters</em>, <mathjax>#"mL"#</mathjax>. Right from the start, you should remember that you <strong>must</strong> convert this volume to <em>liters</em> by using the conversion factor</p> <blockquote> <p><mathjax>#"1 L" = 10^3"mL"#</mathjax></p> </blockquote> <p>Now, in order to get the <em>number of moles</em> of solute, you must use its <strong>molar mass</strong>. Now, molar masses are listed in <em>grams per mol</em>, <mathjax>#"g mol"^(-1)#</mathjax>, which means that you're going to have to convert the mass of the sample from <em>milligrams</em> to <em>grams</em></p> <blockquote> <p><mathjax>#"1 g" = 10^3"mg"#</mathjax></p> </blockquote> <p>Sodium chloride, <mathjax>#"NaCl"#</mathjax>, has a molar mass of <mathjax>#"58.44 g mol"^(-1)#</mathjax>, which means that your sample will contain</p> <blockquote> <p><mathjax>#overbrace(280.0 color(red)(cancel(color(black)("mg"))) * (1color(red)(cancel(color(black)("g"))))/(10^3color(red)(cancel(color(black)("mg")))))^(color(purple)("unit conversion")) * overbrace("1 mole NaCl"/(58.44color(red)(cancel(color(black)("g")))))^(color(brown)("molar mass")) = "0.004791 moles NaCl"#</mathjax></p> </blockquote> <p>This means that the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of the solution will be </p> <blockquote> <p><mathjax>#color(blue)(c = n_"solute"/V_"solution")#</mathjax></p> <p><mathjax>#c = "0.004791 moles"/(2.00 * 10^(-3)"L") = color(green)("2.40 M")#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the volume of the solution. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/232749" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-morality-be-used-as-a-conversion-factor"> How can molarity be used as a conversion factor? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-high-can-molarity-be"> How high can molarity be? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-molarity-change-with-temperature"> How does molarity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molarity-of-a-solution"> How do you find molarity of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-10-naoh"> What is the molarity of 10 NaOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-3-hydrogen-peroxide"> What is the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 18850 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the molarity of a salt solution made by dissolving 280.0 mg of #NaCl# in 2.00 mL of water?	Assume the final volume is the same as the volume of the water.
2,484	a96195be-6ddd-11ea-8151-ccda262736ce	https://socratic.org/questions/how-would-you-give-a-brief-account-with-equations-of-the-method-you-would-use-to	Na2SO4(aq) + Pb(NO3)2(aq) -> PbSO4(s) + 2 NaNO3(aq)	start chemical_equation qc_end substance 20 21 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the equation"}]	[{"type":"chemical equation","value":"Na2SO4(aq) + Pb(NO3)2(aq) -> PbSO4(s) + 2 NaNO3(aq)"}]	[{"type":"substance name","value":"Lead(II) sulfate"}]	<h1 class="questionTitle" itemprop="name">How would you give a brief account with equations of the method you would use to prepare a sample of lead(II) sulfate?</h1>	null	Na2SO4(aq) + Pb(NO3)2(aq) -> PbSO4(s) + 2 NaNO3(aq)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Get stoichiometric quantities of lead nitrate and sodium sulfate, and prepare separate <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> of each, maybe approx <mathjax>#0.1molL^-1#</mathjax> with respect to the salt. Add the sodium sulfate to the lead solution dropwise with stirring. A fine white salt of lead sulfate will precipitate. This is to be collected on a frit, and then well-washed with distilled water (2-3 volumes), and then ethyl alcohol to aid in water removal. The fine solid will occlude a lot of water; dry under suction to a free flowing powder. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Na_2SO_4(aq) + Pb(NO_3)_2(aq) rarr PbSO_4(s)darr + 2NaNO_3(aq)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Get stoichiometric quantities of lead nitrate and sodium sulfate, and prepare separate <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> of each, maybe approx <mathjax>#0.1molL^-1#</mathjax> with respect to the salt. Add the sodium sulfate to the lead solution dropwise with stirring. A fine white salt of lead sulfate will precipitate. This is to be collected on a frit, and then well-washed with distilled water (2-3 volumes), and then ethyl alcohol to aid in water removal. The fine solid will occlude a lot of water; dry under suction to a free flowing powder. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How would you give a brief account with equations of the method you would use to prepare a sample of lead(II) sulfate?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-reactions-and-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions and Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="304788" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-09-01T08:53:27" itemprop="dateCreated"> Sep 1, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Na_2SO_4(aq) + Pb(NO_3)_2(aq) rarr PbSO_4(s)darr + 2NaNO_3(aq)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Get stoichiometric quantities of lead nitrate and sodium sulfate, and prepare separate <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> of each, maybe approx <mathjax>#0.1molL^-1#</mathjax> with respect to the salt. Add the sodium sulfate to the lead solution dropwise with stirring. A fine white salt of lead sulfate will precipitate. This is to be collected on a frit, and then well-washed with distilled water (2-3 volumes), and then ethyl alcohol to aid in water removal. The fine solid will occlude a lot of water; dry under suction to a free flowing powder. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/304788" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb002bf34694a4fee47"> Question #fee47 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb402bf34694c8c5c15"> Question #c5c15 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb802bf346950519eb9"> Question #19eb9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cbf02bf3469570e2ea2"> Question #e2ea2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc002bf34695a6bc751"> Question #bc751 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc202bf3469570e2ea6"> Question #e2ea6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531e867a02bf342492a08b07"> Question #08b07 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-thermochemical-equation-for-the-combustion-of-benzene"> What is the thermochemical equation for the combustion of benzene? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-reversible"> Why are chemical reactions reversible? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-important"> Why are chemical reactions important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/chemical-reactions-and-equations"> See all questions in Chemical Reactions and Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1073 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How would you give a brief account with equations of the method you would use to prepare a sample of lead(II) sulfate?	null
2,485	ab437e9f-6ddd-11ea-abbd-ccda262736ce	https://socratic.org/questions/calculate-the-molarity-in-mol-l-of-k-ions-present-in-an-aqueous-solution-prepare	0.21 mol/L	start physical_unit 6 7 molarity mol/l qc_end physical_unit 23 24 16 17 volume qc_end physical_unit 23 24 19 22 molarity qc_end physical_unit 29 29 26 27 volume qc_end end	[{"type":"physical unit","value":"Molarity [OF] K+ ions [IN] mol/L"}]	[{"type":"physical unit","value":"0.21 mol/L"}]	[{"type":"physical unit","value":"Volume [OF] aqueous K2SO3 [=] \\pu{23.4 mL}"},{"type":"physical unit","value":"Molarity [OF] aqueous K2SO3 [=] \\pu{9.32 × 10^(-1) M}"},{"type":"physical unit","value":"Volume [OF] water [=] \\pu{185 mL}"}]	<h1 class="questionTitle" itemprop="name">Calculate the molarity (in mol/L) of #"K"^(+)# ions present in an aqueous solution prepared by adding #"23.4 mL"# of #9.32*10^(-1)"M"# aqueous #"K"_2"SO"_3# to #"185 mL"# of water? Report your answer to three significant figures.</h1>	null	0.21 mol/L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The first thing that you need to do here is to figure out how many <em>moles</em> of potassium sulfite are present in the initial sample. </p> <p>To do that, use the <em>volume</em> and the <em><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></em> of the solution--keep in mind that <mathjax>#"1 L" = 10^3color(white)(.)"mL"#</mathjax></p> <blockquote> <p><mathjax>#23.4 color(red)(cancel(color(black)("mL solution"))) * overbrace((9.32 * 10^(-1)color(white)(.)"moles K"_2"SO"_3)/(10^3color(red)(cancel(color(black)("mL solution")))))^(color(blue)(=9.32 * 10^(-1)color(white)(.)"M")) = "0.02181 moles K"_2"SO"_3#</mathjax></p> </blockquote> <p>Now, you know that potassium sulfite is <strong>soluble</strong> in aqueous solution, which implies that it <em>dissociates completely</em> when dissolved in water</p> <blockquote> <p><mathjax>#"K"_ 2"SO"_ (3(aq)) -> 2"K"_ ((aq))^(+) + "SO"_ (3(aq))^(2-)#</mathjax></p> </blockquote> <p>Since <strong>every mole</strong> of potassium sulfite dissolved in the solution will produce <mathjax>#2#</mathjax> <strong>moles</strong> of potassium cations, you can say that your initial solution contains</p> <blockquote> <p><mathjax>#0.02181 color(red)(cancel(color(black)("moles K"_2"SO"_3))) * "2 moles K"^(+)/(1color(red)(cancel(color(black)("mole K"_2"SO"_3)))) = "0.04362 moles K"^(+)#</mathjax></p> </blockquote> <p>Next, calculate the <strong>total volume</strong> of the resulting solution, i.e. the volume of the <em>diluted solution</em></p> <blockquote> <p><mathjax>#V_"total" = "23.4 mL + 185 mL = 208.4 mL"#</mathjax></p> </blockquote> <p>This means that the <strong>molarity</strong> of the potassium cations in the diluted solution will be--don't forget to convert the volume of the solution to <em>liters</em>!</p> <blockquote> <p><mathjax>#["K"^(+)] = "0.04362 moles"/(208.4 * 10^(-3)color(white)(.)"L") = color(darkgreen)(ul(color(black)("0.209 mol L"^(-1))))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"0.209 mol L"^(-1)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The first thing that you need to do here is to figure out how many <em>moles</em> of potassium sulfite are present in the initial sample. </p> <p>To do that, use the <em>volume</em> and the <em><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></em> of the solution--keep in mind that <mathjax>#"1 L" = 10^3color(white)(.)"mL"#</mathjax></p> <blockquote> <p><mathjax>#23.4 color(red)(cancel(color(black)("mL solution"))) * overbrace((9.32 * 10^(-1)color(white)(.)"moles K"_2"SO"_3)/(10^3color(red)(cancel(color(black)("mL solution")))))^(color(blue)(=9.32 * 10^(-1)color(white)(.)"M")) = "0.02181 moles K"_2"SO"_3#</mathjax></p> </blockquote> <p>Now, you know that potassium sulfite is <strong>soluble</strong> in aqueous solution, which implies that it <em>dissociates completely</em> when dissolved in water</p> <blockquote> <p><mathjax>#"K"_ 2"SO"_ (3(aq)) -> 2"K"_ ((aq))^(+) + "SO"_ (3(aq))^(2-)#</mathjax></p> </blockquote> <p>Since <strong>every mole</strong> of potassium sulfite dissolved in the solution will produce <mathjax>#2#</mathjax> <strong>moles</strong> of potassium cations, you can say that your initial solution contains</p> <blockquote> <p><mathjax>#0.02181 color(red)(cancel(color(black)("moles K"_2"SO"_3))) * "2 moles K"^(+)/(1color(red)(cancel(color(black)("mole K"_2"SO"_3)))) = "0.04362 moles K"^(+)#</mathjax></p> </blockquote> <p>Next, calculate the <strong>total volume</strong> of the resulting solution, i.e. the volume of the <em>diluted solution</em></p> <blockquote> <p><mathjax>#V_"total" = "23.4 mL + 185 mL = 208.4 mL"#</mathjax></p> </blockquote> <p>This means that the <strong>molarity</strong> of the potassium cations in the diluted solution will be--don't forget to convert the volume of the solution to <em>liters</em>!</p> <blockquote> <p><mathjax>#["K"^(+)] = "0.04362 moles"/(208.4 * 10^(-3)color(white)(.)"L") = color(darkgreen)(ul(color(black)("0.209 mol L"^(-1))))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Calculate the molarity (in mol/L) of #"K"^(+)# ions present in an aqueous solution prepared by adding #"23.4 mL"# of #9.3210^(-1)"M"# aqueous #"K"_2"SO"_3# to #"185 mL"# of water? Report your answer to three significant figures.</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="478632" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-09-21T23:48:41" itemprop="dateCreated"> Sep 21, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"0.209 mol L"^(-1)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The first thing that you need to do here is to figure out how many <em>moles</em> of potassium sulfite are present in the initial sample. </p> <p>To do that, use the <em>volume</em> and the <em><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></em> of the solution--keep in mind that <mathjax>#"1 L" = 10^3color(white)(.)"mL"#</mathjax></p> <blockquote> <p><mathjax>#23.4 color(red)(cancel(color(black)("mL solution"))) overbrace((9.32 * 10^(-1)color(white)(.)"moles K"_2"SO"_3)/(10^3color(red)(cancel(color(black)("mL solution")))))^(color(blue)(=9.32 * 10^(-1)color(white)(.)"M")) = "0.02181 moles K"_2"SO"_3#</mathjax></p> </blockquote> <p>Now, you know that potassium sulfite is <strong>soluble</strong> in aqueous solution, which implies that it <em>dissociates completely</em> when dissolved in water</p> <blockquote> <p><mathjax>#"K"_ 2"SO"_ (3(aq)) -> 2"K"_ ((aq))^(+) + "SO"_ (3(aq))^(2-)#</mathjax></p> </blockquote> <p>Since <strong>every mole</strong> of potassium sulfite dissolved in the solution will produce <mathjax>#2#</mathjax> <strong>moles</strong> of potassium cations, you can say that your initial solution contains</p> <blockquote> <p><mathjax>#0.02181 color(red)(cancel(color(black)("moles K"_2"SO"_3))) * "2 moles K"^(+)/(1color(red)(cancel(color(black)("mole K"_2"SO"_3)))) = "0.04362 moles K"^(+)#</mathjax></p> </blockquote> <p>Next, calculate the <strong>total volume</strong> of the resulting solution, i.e. the volume of the <em>diluted solution</em></p> <blockquote> <p><mathjax>#V_"total" = "23.4 mL + 185 mL = 208.4 mL"#</mathjax></p> </blockquote> <p>This means that the <strong>molarity</strong> of the potassium cations in the diluted solution will be--don't forget to convert the volume of the solution to <em>liters</em>!</p> <blockquote> <p><mathjax>#["K"^(+)] = "0.04362 moles"/(208.4 * 10^(-3)color(white)(.)"L") = color(darkgreen)(ul(color(black)("0.209 mol L"^(-1))))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/478632" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can 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question</h5> <div class="impactStatements"> 12752 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Calculate the molarity (in mol/L) of #"K"^(+)# ions present in an aqueous solution prepared by adding #"23.4 mL"# of #9.32*10^(-1)"M"# aqueous #"K"_2"SO"_3# to #"185 mL"# of water? Report your answer to three significant figures.	null
2,486	aa1f765a-6ddd-11ea-8432-ccda262736ce	https://socratic.org/questions/598de62e11ef6b21eefcc045	164.00 kPa	start physical_unit 8 8 pressure kpa qc_end physical_unit 8 8 4 5 volume qc_end physical_unit 8 8 15 16 volume qc_end physical_unit 8 8 22 23 pressure qc_end c_other constant_temperature qc_end end	[{"type":"physical unit","value":"Pressure2 [OF] gas [IN] kPa"}]	[{"type":"physical unit","value":"164.00 kPa"}]	[{"type":"other","value":"ConstantTemperature"},{"type":"physical unit","value":"Volume1 [OF] gas [=] \\pu{12 L}"},{"type":"physical unit","value":"Volume2 [OF] gas [=] \\pu{3 L}"},{"type":"physical unit","value":"Pressure1 [OF] gas [=] \\pu{41 kPa}"}]	<h1 class="questionTitle" itemprop="name">A constant temperature, a #12L# volume of gas in a piston, is compressed to #3L#. If the original pressure was #41*kPa#, what is the final pressure? </h1>	null	164.00 kPa	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We apply <a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's Law</a></p> <p><mathjax>#P_1V_1=P_2V_2#</mathjax>, the temperature is constant</p> <p>The initial pressure is <mathjax>#P_1=41kPa#</mathjax></p> <p>The initial volume is <mathjax>#V_1=12L#</mathjax></p> <p>The final volume is <mathjax>#V_2=3L#</mathjax></p> <p>The final pressure is</p> <p><mathjax>#P_2=V_1/V_2P_1=12/341=164kPa#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The pressure is <mathjax>#=164kPa#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We apply <a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's Law</a></p> <p><mathjax>#P_1V_1=P_2V_2#</mathjax>, the temperature is constant</p> <p>The initial pressure is <mathjax>#P_1=41kPa#</mathjax></p> <p>The initial volume is <mathjax>#V_1=12L#</mathjax></p> <p>The final volume is <mathjax>#V_2=3L#</mathjax></p> <p>The final pressure is</p> <p><mathjax>#P_2=V_1/V_2P_1=12/341=164kPa#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A constant temperature, a #12L# volume of gas in a piston, is compressed to #3L#. If the original pressure was #41kPa#, what is the final pressure? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/boyle-s-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Boyle's Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="462878" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/narad-t"><img alt="" class="" src="https://profilepictures.socratic.org/zsDo4Wx9QIqYad4PXKE9_150317-1041.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/narad-t"> Narad T. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-11T18:04:03" itemprop="dateCreated"> Aug 11, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The pressure is <mathjax>#=164kPa#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We apply <a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's Law</a></p> <p><mathjax>#P_1V_1=P_2V_2#</mathjax>, the temperature is constant</p> <p>The initial pressure is <mathjax>#P_1=41kPa#</mathjax></p> <p>The initial volume is <mathjax>#V_1=12L#</mathjax></p> <p>The final volume is <mathjax>#V_2=3L#</mathjax></p> <p>The final pressure is</p> <p><mathjax>#P_2=V_1/V_2P_1=12/341=164kPa#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/462878" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="462880" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-11T18:04:51" itemprop="dateCreated"> Aug 11, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, we use old <a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's law</a>.........and get <mathjax>#P_2=164kPa#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>At constant temperature, and constant amount of gas, the product <mathjax>#PxxV=k#</mathjax>, where <mathjax>#k#</mathjax> is some constant....</p> <p>And thus, if we solve for <mathjax>#k#</mathjax> at different conditions of volume and pressure, then <mathjax>#P_1V_1=P_2V_2#</mathjax>.</p> <p>The utility of this equation is that we can use whatever whack units of volume and pressure we like, <mathjax>#"pints, pounds per square inch, torr, atmospheres, quarts"#</mathjax>, as long as we are consistent.</p> <p>And so...<mathjax>#P_2=(P_1V_1)/V_2=(41kPaxx12L)/(3L)=164kPa#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/462880" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-graph-boyles-law"> How do you graph Boyle's law? 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If the original pressure was #41*kPa#, what is the final pressure?	null
2,487	acd666f8-6ddd-11ea-acd8-ccda262736ce	https://socratic.org/questions/a-student-neutralizes-20-0-ml-of-a-sodium-hydroxide-solution-naoh-by-adding-28-0	1.40 M	start physical_unit 10 10 molarity mol/l qc_end physical_unit 9 9 3 4 volume qc_end physical_unit 9 9 13 14 volume qc_end end	[{"type":"physical unit","value":"Molarity [OF] NaOH solution [IN] M"}]	[{"type":"physical unit","value":"1.40 M"}]	[{"type":"physical unit","value":"Volume [OF] NaOH solution [=] \\pu{20.0 mL}"},{"type":"physical unit","value":"Volume [OF] HCl solution [=] \\pu{28.0 mL}"},{"type":"physical unit","value":"Molarity [OF] HCl solution [=] \\pu{1.0 M}"}]	<h1 class="questionTitle" itemprop="name">A student neutralizes 20.0 mL of a sodium hydroxide solution (NaOH) by adding 28.0 mL at 1.0 M hydrochloric acid (HCI). What is the molarity of the solution?</h1>	null	1.40 M	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The net ionic equation is:</p> <p><mathjax>#H^+(aq)+OH^(-)(aq)->H_2O(l)#</mathjax></p> <p>Therefore, <mathjax>#n_(H^+)=n_(OH^(-)#</mathjax></p> <p>The relationship between number of mole (<mathjax>#n#</mathjax>) and <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> <mathjax>#(C_M)#</mathjax> is: <mathjax>#C_M=n/V#</mathjax>, where <mathjax>#V#</mathjax> is the volume of the solution.</p> <p>Thus, <mathjax>#n=C_MxxV#</mathjax>.</p> <p>Therefore, <mathjax>#(C_MxxV)_(H^+)=(C_MxxV)_(OH^(-)#</mathjax></p> <p><mathjax>#=>(C_M)_(OH^-)#</mathjax><mathjax>#=((C_MxxV)_(H^+))/V=(1.0Mxx28.0cancel(mL))/(20.0cancel(mL))=1.4M#</mathjax></p> <p><mathjax>#=>(C_M)_(NaOH)=1.4M #</mathjax></p> <p>Here is a video that might help you with the experimental procedure and calculations for the titration.<br/> <strong>Lab Demonstration \| Acid - Base Titration.</strong><br/> <iframe src="https://www.youtube.com/embed/HVjvFydMOc8?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#=>(C_M)_(NaOH)=1.4M #</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The net ionic equation is:</p> <p><mathjax>#H^+(aq)+OH^(-)(aq)->H_2O(l)#</mathjax></p> <p>Therefore, <mathjax>#n_(H^+)=n_(OH^(-)#</mathjax></p> <p>The relationship between number of mole (<mathjax>#n#</mathjax>) and <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> <mathjax>#(C_M)#</mathjax> is: <mathjax>#C_M=n/V#</mathjax>, where <mathjax>#V#</mathjax> is the volume of the solution.</p> <p>Thus, <mathjax>#n=C_MxxV#</mathjax>.</p> <p>Therefore, <mathjax>#(C_MxxV)_(H^+)=(C_MxxV)_(OH^(-)#</mathjax></p> <p><mathjax>#=>(C_M)_(OH^-)#</mathjax><mathjax>#=((C_MxxV)_(H^+))/V=(1.0Mxx28.0cancel(mL))/(20.0cancel(mL))=1.4M#</mathjax></p> <p><mathjax>#=>(C_M)_(NaOH)=1.4M #</mathjax></p> <p>Here is a video that might help you with the experimental procedure and calculations for the titration.<br/> <strong>Lab Demonstration \| Acid - Base Titration.</strong><br/> <iframe src="https://www.youtube.com/embed/HVjvFydMOc8?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A student neutralizes 20.0 mL of a sodium hydroxide solution (NaOH) by adding 28.0 mL at 1.0 M hydrochloric acid (HCI). What is the molarity of the solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="192257" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ali-h-1"><img alt="" class="" src="https://profilepictures.socratic.org/IITeL1YTQdODdLp0aJTL_StereoPicture%20copy.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ali-h-1"> Dr. Hayek </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-23T16:04:27" itemprop="dateCreated"> Nov 23, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#=>(C_M)_(NaOH)=1.4M #</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The net ionic equation is:</p> <p><mathjax>#H^+(aq)+OH^(-)(aq)->H_2O(l)#</mathjax></p> <p>Therefore, <mathjax>#n_(H^+)=n_(OH^(-)#</mathjax></p> <p>The relationship between number of mole (<mathjax>#n#</mathjax>) and <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> <mathjax>#(C_M)#</mathjax> is: <mathjax>#C_M=n/V#</mathjax>, where <mathjax>#V#</mathjax> is the volume of the solution.</p> <p>Thus, <mathjax>#n=C_MxxV#</mathjax>.</p> <p>Therefore, <mathjax>#(C_MxxV)_(H^+)=(C_MxxV)_(OH^(-)#</mathjax></p> <p><mathjax>#=>(C_M)_(OH^-)#</mathjax><mathjax>#=((C_MxxV)_(H^+))/V=(1.0Mxx28.0cancel(mL))/(20.0cancel(mL))=1.4M#</mathjax></p> <p><mathjax>#=>(C_M)_(NaOH)=1.4M #</mathjax></p> <p>Here is a video that might help you with the experimental procedure and calculations for the titration.<br/> <strong>Lab Demonstration \| Acid - Base Titration.</strong><br/> <iframe src="https://www.youtube.com/embed/HVjvFydMOc8?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/192257" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? 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</a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-3-hydrogen-peroxide"> What is the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 5572 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A student neutralizes 20.0 mL of a sodium hydroxide solution (NaOH) by adding 28.0 mL at 1.0 M hydrochloric acid (HCI). What is the molarity of the solution?	null
2,488	ab4d69bf-6ddd-11ea-a00a-ccda262736ce	https://socratic.org/questions/how-do-you-balance-zn-no-3-2-ali-3-zni-2-al-no-3-3	3 Zn(NO3)2 + 2 AlI3 -> 3 ZnI2 + 2 Al(NO3)3	start chemical_equation qc_end chemical_equation 4 10 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the equation"}]	[{"type":"chemical equation","value":"3 Zn(NO3)2 + 2 AlI3 -> 3 ZnI2 + 2 Al(NO3)3"}]	[{"type":"chemical equation","value":"Zn(NO3)2 + AlI3 -> ZnI2 + Al(NO3)3"}]	<h1 class="questionTitle" itemprop="name">How do you balance #Zn(NO_3)_2 + AlI_3 -> ZnI_2 + Al(NO_3)3#?</h1>	null	3 Zn(NO3)2 + 2 AlI3 -> 3 ZnI2 + 2 Al(NO3)3	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Here's a trick, try substituting in variables for the different ions if you get stuck on balancing an equation. It cuts down on clutter when you are working on balancing and makes it easier to solve. </p> <p>Since this is a <a href="http://chemistry.about.com/od/chemistryglossary/g/Double-Replacement-Reaction-Definition.htm" rel="nofollow">double replacement</a> reaction, you only need to balance the numbers of the four ions - this is easier than thinking you need to balance both the N and O separately.</p> <p>Zn = A<br/> <mathjax>#NO_3#</mathjax> = B<br/> Al = C<br/> I = D</p> <p>Re-write the equation using the variables and the subscripts from the skeleton (unbalanced equation).</p> <p><mathjax>#AB_2 + CD_3 -> AD_2 + CB_3#</mathjax></p> <p>Balance all the variables using common multiples<br/> <mathjax>#3AB_2 + 2CD_3 -> 3AD_2 + 2CB_3#</mathjax></p> <p>Now re-write the original equation using these coefficients.</p> <p><mathjax>#3Zn(NO_3)_2 + 2AlI_3 -> 3ZnI_2 + 2Al(NO_3)_3#</mathjax></p> <p>Check to see that the ions all balance correctly, make sure that you can't reduce the ratios and then you are done!</p> <p>Here is a similar problem:<br/> <iframe src="https://www.youtube.com/embed/XkUJfZJ5r74?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p> <p>Hope this helps!</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The balanced equation is:</p> <p><mathjax>#3Zn(NO_3)_2 + 2AlI_3 -> 3ZnI_2 + 2Al(NO_3)_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Here's a trick, try substituting in variables for the different ions if you get stuck on balancing an equation. It cuts down on clutter when you are working on balancing and makes it easier to solve. </p> <p>Since this is a <a href="http://chemistry.about.com/od/chemistryglossary/g/Double-Replacement-Reaction-Definition.htm" rel="nofollow">double replacement</a> reaction, you only need to balance the numbers of the four ions - this is easier than thinking you need to balance both the N and O separately.</p> <p>Zn = A<br/> <mathjax>#NO_3#</mathjax> = B<br/> Al = C<br/> I = D</p> <p>Re-write the equation using the variables and the subscripts from the skeleton (unbalanced equation).</p> <p><mathjax>#AB_2 + CD_3 -> AD_2 + CB_3#</mathjax></p> <p>Balance all the variables using common multiples<br/> <mathjax>#3AB_2 + 2CD_3 -> 3AD_2 + 2CB_3#</mathjax></p> <p>Now re-write the original equation using these coefficients.</p> <p><mathjax>#3Zn(NO_3)_2 + 2AlI_3 -> 3ZnI_2 + 2Al(NO_3)_3#</mathjax></p> <p>Check to see that the ions all balance correctly, make sure that you can't reduce the ratios and then you are done!</p> <p>Here is a similar problem:<br/> <iframe src="https://www.youtube.com/embed/XkUJfZJ5r74?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p> <p>Hope this helps!</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you balance #Zn(NO_3)_2 + AlI_3 -> ZnI_2 + Al(NO_3)3#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="258761" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/noel-p"><img alt="" class="" src="https://profilepictures.socratic.org/02ThC0uRMah0LVgFe9Tg_CrabbyMrP.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/noel-p"> mrpauller.weebly.com </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-04-26T03:09:44" itemprop="dateCreated"> Apr 26, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The balanced equation is:</p> <p><mathjax>#3Zn(NO_3)_2 + 2AlI_3 -> 3ZnI_2 + 2Al(NO_3)_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Here's a trick, try substituting in variables for the different ions if you get stuck on balancing an equation. It cuts down on clutter when you are working on balancing and makes it easier to solve. </p> <p>Since this is a <a href="http://chemistry.about.com/od/chemistryglossary/g/Double-Replacement-Reaction-Definition.htm" rel="nofollow">double replacement</a> reaction, you only need to balance the numbers of the four ions - this is easier than thinking you need to balance both the N and O separately.</p> <p>Zn = A<br/> <mathjax>#NO_3#</mathjax> = B<br/> Al = C<br/> I = D</p> <p>Re-write the equation using the variables and the subscripts from the skeleton (unbalanced equation).</p> <p><mathjax>#AB_2 + CD_3 -> AD_2 + CB_3#</mathjax></p> <p>Balance all the variables using common multiples<br/> <mathjax>#3AB_2 + 2CD_3 -> 3AD_2 + 2CB_3#</mathjax></p> <p>Now re-write the original equation using these coefficients.</p> <p><mathjax>#3Zn(NO_3)_2 + 2AlI_3 -> 3ZnI_2 + 2Al(NO_3)_3#</mathjax></p> <p>Check to see that the ions all balance correctly, make sure that you can't reduce the ratios and then you are done!</p> <p>Here is a similar problem:<br/> <iframe src="https://www.youtube.com/embed/XkUJfZJ5r74?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p> <p>Hope this helps!</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/258761" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------> H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -> Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? 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Sodium phosphate and calcium chloride react to form... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-equation-kclo3-kcl-o2"> How can I balance this equation? ____ #KClO_3 -># ____ #KCl +# ____ #O_2# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-balancing-chemical-equations-important"> Why is balancing chemical equations important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/balancing-chemical-equations"> See all questions in Balancing Chemical Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1217 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How do you balance #Zn(NO_3)_2 + AlI_3 -> ZnI_2 + Al(NO_3)3#?	null
2,489	a9ccea52-6ddd-11ea-9c63-ccda262736ce	https://socratic.org/questions/590a7ca3b72cff7aabfa1c6a	1.82 × 10^(-6) mol/L	start physical_unit 5 6 [h3o+] mol/l qc_end physical_unit 5 6 10 10 poh qc_end end	[{"type":"physical unit","value":"[H3O+] [OF] aqueous solution [IN] mol/L"}]	[{"type":"physical unit","value":"1.82 × 10^(-6) mol/L"}]	[{"type":"physical unit","value":"pOH [OF] aqueous solution [=] \\pu{8.26}"}]	<h1 class="questionTitle" itemprop="name">What is #[H_3O^+]# in an aqueous solution whose #pOH=8.26#?</h1>	null	1.82 × 10^(-6) mol/L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And also, we KNOW that in aqueous solution,</p> <p><mathjax>#pH+pOH=14#</mathjax></p> <p><mathjax>#a.#</mathjax> And thus, for <mathjax>#pOH=8.26#</mathjax>, <mathjax>#[HO^-]=10^(-8.26)molL^-1#</mathjax></p> <p><mathjax>#=5xx10^-9molL^-1#</mathjax></p> <p>And thus for <mathjax>#pH=5.74#</mathjax>,............................................</p> <p><mathjax>#[H_3O^+]=10^(-5.74)molL^-1=1.82xx10^-6molL^-1#</mathjax>.</p> <p>I will let you do <mathjax>#b.#</mathjax>, and <mathjax>#c.#</mathjax>. Post the values back in thread if you want them checked. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>By definition <mathjax>#pOH=-log_(10)[HO^-]#</mathjax>..........and</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And also, we KNOW that in aqueous solution,</p> <p><mathjax>#pH+pOH=14#</mathjax></p> <p><mathjax>#a.#</mathjax> And thus, for <mathjax>#pOH=8.26#</mathjax>, <mathjax>#[HO^-]=10^(-8.26)molL^-1#</mathjax></p> <p><mathjax>#=5xx10^-9molL^-1#</mathjax></p> <p>And thus for <mathjax>#pH=5.74#</mathjax>,............................................</p> <p><mathjax>#[H_3O^+]=10^(-5.74)molL^-1=1.82xx10^-6molL^-1#</mathjax>.</p> <p>I will let you do <mathjax>#b.#</mathjax>, and <mathjax>#c.#</mathjax>. Post the values back in thread if you want them checked. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is #[H_3O^+]# in an aqueous solution whose #pOH=8.26#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="418753" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-06T18:20:05" itemprop="dateCreated"> May 6, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>By definition <mathjax>#pOH=-log_(10)[HO^-]#</mathjax>..........and</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And also, we KNOW that in aqueous solution,</p> <p><mathjax>#pH+pOH=14#</mathjax></p> <p><mathjax>#a.#</mathjax> And thus, for <mathjax>#pOH=8.26#</mathjax>, <mathjax>#[HO^-]=10^(-8.26)molL^-1#</mathjax></p> <p><mathjax>#=5xx10^-9molL^-1#</mathjax></p> <p>And thus for <mathjax>#pH=5.74#</mathjax>,............................................</p> <p><mathjax>#[H_3O^+]=10^(-5.74)molL^-1=1.82xx10^-6molL^-1#</mathjax>.</p> <p>I will let you do <mathjax>#b.#</mathjax>, and <mathjax>#c.#</mathjax>. Post the values back in thread if you want them checked. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/418753" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-morality-be-used-as-a-conversion-factor"> How can molarity be used as a conversion factor? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-high-can-molarity-be"> How high can molarity be? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-molarity-change-with-temperature"> How does molarity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molarity-of-a-solution"> How do you find molarity of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-10-naoh"> What is the molarity of 10 NaOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-3-hydrogen-peroxide"> What is the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1412 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is #[H_3O^+]# in an aqueous solution whose #pOH=8.26#?	null
2,490	acb2be58-6ddd-11ea-8cc1-ccda262736ce	https://socratic.org/questions/hydrogen-peroxide-has-the-empirical-formula-ho-and-an-empirical-formula-weight-o	H2O2	start chemical_formula qc_end c_other OTHER qc_end physical_unit 0 1 13 14 formula_weight qc_end physical_unit 0 1 20 21 molecular_weight qc_end end	[{"type":"other","value":"Chemical Formula [OF] hydrogen peroxide [IN] molecular"}]	[{"type":"chemical equation","value":"H2O2"}]	[{"type":"other","value":"Hydrogen peroxide has the empirical formula HO."},{"type":"physical unit","value":"Empirical formula weight [OF] hydrogen peroxide [=] \\pu{17.0 amu}"},{"type":"physical unit","value":"Molecular weight [OF] hydrogen peroxide [=] \\pu{34.0 amu}"}]	<h1 class="questionTitle" itemprop="name">Hydrogen peroxide has the empirical formula HO and an empirical formula weight of 17.0 amu. If the molecular weight is 34.0 amu, what is the molecular formula? </h1>	null	H2O2	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First, you want to find the ratio between the empirical formula and molecular formula; that is, <strong>how much has the molecular formula been simplified to reach the empirical formula</strong>. We do this by dividing the molecular weight by the empirical weight.</p> <p><mathjax>#34.0/17.0#</mathjax> = 2</p> <p>Therefore, the molecular formula has been halved in order to obtain the empirical formula. Now multiple the empirical formula by 2 to obtain the molecular formula.</p> <p>HO x 2 = <mathjax>#H_2#</mathjax><mathjax>#O_2#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#H_2#</mathjax><mathjax>#O_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First, you want to find the ratio between the empirical formula and molecular formula; that is, <strong>how much has the molecular formula been simplified to reach the empirical formula</strong>. We do this by dividing the molecular weight by the empirical weight.</p> <p><mathjax>#34.0/17.0#</mathjax> = 2</p> <p>Therefore, the molecular formula has been halved in order to obtain the empirical formula. Now multiple the empirical formula by 2 to obtain the molecular formula.</p> <p>HO x 2 = <mathjax>#H_2#</mathjax><mathjax>#O_2#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Hydrogen peroxide has the empirical formula HO and an empirical formula weight of 17.0 amu. If the molecular weight is 34.0 amu, what is the molecular formula? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="316540" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/henry-w-2"><img alt="" class="" src="https://profilepictures.socratic.org/7IFCgaDHTbGDlVtThZyG_elephant_seal1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/henry-w-2"> Henry W. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-10-01T09:32:58" itemprop="dateCreated"> Oct 1, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#H_2#</mathjax><mathjax>#O_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First, you want to find the ratio between the empirical formula and molecular formula; that is, <strong>how much has the molecular formula been simplified to reach the empirical formula</strong>. We do this by dividing the molecular weight by the empirical weight.</p> <p><mathjax>#34.0/17.0#</mathjax> = 2</p> <p>Therefore, the molecular formula has been halved in order to obtain the empirical formula. Now multiple the empirical formula by 2 to obtain the molecular formula.</p> <p>HO x 2 = <mathjax>#H_2#</mathjax><mathjax>#O_2#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/316540" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molecular-formula-of-a-compound"> How do you find molecular formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-diamond"> What is the chemical formula of a diamond? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-carbohydrate"> What is the chemical formula of a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-valproic-acid"> What is the empirical formula for valproic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-of-magnesium-oxide"> What is the empirical formula of magnesium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-empirical-formula-not-double-that-of-the-monosaccharides"> Why is the empirical formula not double that of the monosaccharides? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5331180502bf342f40b5c3b5"> Question #5c3b5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-molecular-formula-represents-a-carbohydrate"> What molecular formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-of-vinegar"> What is the molecular formula of vinegar? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/empirical-and-molecular-formulas"> See all questions in Empirical and Molecular Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 4932 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Hydrogen peroxide has the empirical formula HO and an empirical formula weight of 17.0 amu. If the molecular weight is 34.0 amu, what is the molecular formula?	null
2,491	aab52a36-6ddd-11ea-bfff-ccda262736ce	https://socratic.org/questions/what-is-the-volume-in-liters-occupied-by-260-moles-of-n-2-gas	5900 liters	start physical_unit 11 12 volume l qc_end physical_unit 11 12 8 9 mole qc_end end	[{"type":"physical unit","value":"Volume [OF] N2 gas [IN] liters"}]	[{"type":"physical unit","value":"5900 liters"}]	[{"type":"physical unit","value":"Mole [OF] N2 gas [=] \\pu{260 moles}"}]	<h1 class="questionTitle" itemprop="name">What is the volume, in liters, occupied by 260 moles of #N_2# gas?</h1>	null	5900 liters	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>You don’t give the temperature or pressure, so I shall assume the gas is at STP.</p> <p>We can use the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a> to calculate the volume at STP.</p> <blockquote></blockquote> <p>The <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a> is:</p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(PV = nRT)\|)#</mathjax>,</p> </blockquote> <p>where </p> <ul> <li><mathjax>#P#</mathjax> is the pressure</li> <li><mathjax>#V#</mathjax> is the volume</li> <li><mathjax>#n#</mathjax> is the number of moles</li> <li><mathjax>#R#</mathjax> is the gas constant</li> <li><mathjax>#T#</mathjax> is the temperature</li> </ul> <blockquote></blockquote> <p>We can rearrange the Ideal Gas Law to get</p> <blockquote> <blockquote> <p><mathjax>#V = (nRT)/P#</mathjax></p> </blockquote> </blockquote> <p>STP is 1 bar and 0 °C.</p> <p><mathjax>#n = "260 mol"#</mathjax><br/> <mathjax>#R = "0.083 14 bar·L·K"^"-1""mol"^"-1"#</mathjax><br/> <mathjax>#T = "273.15 K"#</mathjax><br/> <mathjax>#P = "1 bar"#</mathjax></p> <blockquote></blockquote> <p><mathjax>#V = (nRT)/P = (260 color(red)(cancel(color(black)("mol"))) × "0.083 14" color(red)(cancel(color(black)("bar")))·"L"· color(red)(cancel(color(black)("K"^"-1""mol"^"-1"))) × 273.15 color(red)(cancel(color(black)("K"))))/(1 color(red)(cancel(color(black)("bar")))) = "5900 L"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The volume at STP is 5900 L.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>You don’t give the temperature or pressure, so I shall assume the gas is at STP.</p> <p>We can use the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a> to calculate the volume at STP.</p> <blockquote></blockquote> <p>The <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a> is:</p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(PV = nRT)\|)#</mathjax>,</p> </blockquote> <p>where </p> <ul> <li><mathjax>#P#</mathjax> is the pressure</li> <li><mathjax>#V#</mathjax> is the volume</li> <li><mathjax>#n#</mathjax> is the number of moles</li> <li><mathjax>#R#</mathjax> is the gas constant</li> <li><mathjax>#T#</mathjax> is the temperature</li> </ul> <blockquote></blockquote> <p>We can rearrange the Ideal Gas Law to get</p> <blockquote> <blockquote> <p><mathjax>#V = (nRT)/P#</mathjax></p> </blockquote> </blockquote> <p>STP is 1 bar and 0 °C.</p> <p><mathjax>#n = "260 mol"#</mathjax><br/> <mathjax>#R = "0.083 14 bar·L·K"^"-1""mol"^"-1"#</mathjax><br/> <mathjax>#T = "273.15 K"#</mathjax><br/> <mathjax>#P = "1 bar"#</mathjax></p> <blockquote></blockquote> <p><mathjax>#V = (nRT)/P = (260 color(red)(cancel(color(black)("mol"))) × "0.083 14" color(red)(cancel(color(black)("bar")))·"L"· color(red)(cancel(color(black)("K"^"-1""mol"^"-1"))) × 273.15 color(red)(cancel(color(black)("K"))))/(1 color(red)(cancel(color(black)("bar")))) = "5900 L"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the volume, in liters, occupied by 260 moles of #N_2# gas?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp" itemprop="url"> <span class="breadcrumb" itemprop="title">Molar Volume of a Gas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="288906" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-17T00:03:33" itemprop="dateCreated"> Jul 17, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The volume at STP is 5900 L.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>You don’t give the temperature or pressure, so I shall assume the gas is at STP.</p> <p>We can use the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a> to calculate the volume at STP.</p> <blockquote></blockquote> <p>The <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a> is:</p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(PV = nRT)\|)#</mathjax>,</p> </blockquote> <p>where </p> <ul> <li><mathjax>#P#</mathjax> is the pressure</li> <li><mathjax>#V#</mathjax> is the volume</li> <li><mathjax>#n#</mathjax> is the number of moles</li> <li><mathjax>#R#</mathjax> is the gas constant</li> <li><mathjax>#T#</mathjax> is the temperature</li> </ul> <blockquote></blockquote> <p>We can rearrange the Ideal Gas Law to get</p> <blockquote> <blockquote> <p><mathjax>#V = (nRT)/P#</mathjax></p> </blockquote> </blockquote> <p>STP is 1 bar and 0 °C.</p> <p><mathjax>#n = "260 mol"#</mathjax><br/> <mathjax>#R = "0.083 14 bar·L·K"^"-1""mol"^"-1"#</mathjax><br/> <mathjax>#T = "273.15 K"#</mathjax><br/> <mathjax>#P = "1 bar"#</mathjax></p> <blockquote></blockquote> <p><mathjax>#V = (nRT)/P = (260 color(red)(cancel(color(black)("mol"))) × "0.083 14" color(red)(cancel(color(black)("bar")))·"L"· color(red)(cancel(color(black)("K"^"-1""mol"^"-1"))) × 273.15 color(red)(cancel(color(black)("K"))))/(1 color(red)(cancel(color(black)("bar")))) = "5900 L"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/288906" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> 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2,492	aca0a808-6ddd-11ea-885d-ccda262736ce	https://socratic.org/questions/how-much-pure-acid-must-be-added-to-6-milliliters-of-a-5-acid-solution-to-produc	3.50 mL	start physical_unit 2 3 volume ml qc_end physical_unit 13 14 8 9 volume qc_end physical_unit 3 3 12 12 percent qc_end physical_unit 3 3 18 18 percent qc_end end	[{"type":"physical unit","value":"Volume [OF] pure acid [IN] mL"}]	[{"type":"physical unit","value":"3.50 mL"}]	[{"type":"physical unit","value":"Volume1 [OF] acid solution [=] \\pu{6 milliliters}"},{"type":"physical unit","value":"Percentage1 [OF] acid in solution [=] \\pu{5%}"},{"type":"physical unit","value":"Percentage2 [OF] acid in solution [=] \\pu{40%}"}]	<h1 class="questionTitle" itemprop="name">How much pure acid must be added to 6 milliliters of a 5% acid solution to produce a 40% acid solution?</h1>	null	3.50 mL	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to solve this problem, you need to use the fact that <a href="http://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration by volume</a> is defined as the ratio between the volume of the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a>, in your case the acid, and the volume of the solution, acid + water, multiplied by 100. </p> <p><mathjax>#"%v/v" = m_"acid"/m_"sol" * 100#</mathjax></p> <p>Use this equation to determine how much acid your original 6-mL sample contains </p> <p><mathjax>#m_"acid" = ("v/v%" * m_"sol")/100 = (5 * "6 mL")/100 = "0.3 mL"#</mathjax></p> <p>Since you're adding <strong>pure acid</strong> to this solution, the volume of the solute and the volume of the solution will increase by the <strong>same amount</strong>, <mathjax>#x#</mathjax> mL, so that you can write, for the target solution </p> <p><mathjax>#(m_"acid" + x)/(m_"sol" + x) * 100 = 40%#</mathjax></p> <p>This is equivalent to </p> <p><mathjax>#(0.3 + x)/(6 + x) * 100 = 40#</mathjax></p> <p>Solve this equation for <mathjax>#x#</mathjax> to get </p> <p><mathjax>#(0.3 + x) * 100 = 40 * (6 + x)#</mathjax></p> <p><mathjax>#30 + 100x = 240 + 40x#</mathjax></p> <p><mathjax>#60x = 210 => x = 210/60 = color(green)("3.5 mL")#</mathjax></p> <p>You thus need to add <strong>3.5 mL</strong> of <em>pure acid</em> to your original solution to get its percent concetration by volume to go from 5 to 40%.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>You need to add <strong>3.5 mL</strong> of pure acid. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to solve this problem, you need to use the fact that <a href="http://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration by volume</a> is defined as the ratio between the volume of the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a>, in your case the acid, and the volume of the solution, acid + water, multiplied by 100. </p> <p><mathjax>#"%v/v" = m_"acid"/m_"sol" * 100#</mathjax></p> <p>Use this equation to determine how much acid your original 6-mL sample contains </p> <p><mathjax>#m_"acid" = ("v/v%" * m_"sol")/100 = (5 * "6 mL")/100 = "0.3 mL"#</mathjax></p> <p>Since you're adding <strong>pure acid</strong> to this solution, the volume of the solute and the volume of the solution will increase by the <strong>same amount</strong>, <mathjax>#x#</mathjax> mL, so that you can write, for the target solution </p> <p><mathjax>#(m_"acid" + x)/(m_"sol" + x) * 100 = 40%#</mathjax></p> <p>This is equivalent to </p> <p><mathjax>#(0.3 + x)/(6 + x) * 100 = 40#</mathjax></p> <p>Solve this equation for <mathjax>#x#</mathjax> to get </p> <p><mathjax>#(0.3 + x) * 100 = 40 * (6 + x)#</mathjax></p> <p><mathjax>#30 + 100x = 240 + 40x#</mathjax></p> <p><mathjax>#60x = 210 => x = 210/60 = color(green)("3.5 mL")#</mathjax></p> <p>You thus need to add <strong>3.5 mL</strong> of <em>pure acid</em> to your original solution to get its percent concetration by volume to go from 5 to 40%.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How much pure acid must be added to 6 milliliters of a 5% acid solution to produce a 40% acid solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/percent-concentration" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Concentration</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="162392" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-08-06T00:10:25" itemprop="dateCreated"> Aug 6, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>You need to add <strong>3.5 mL</strong> of pure acid. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to solve this problem, you need to use the fact that <a href="http://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration by volume</a> is defined as the ratio between the volume of the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a>, in your case the acid, and the volume of the solution, acid + water, multiplied by 100. </p> <p><mathjax>#"%v/v" = m_"acid"/m_"sol" * 100#</mathjax></p> <p>Use this equation to determine how much acid your original 6-mL sample contains </p> <p><mathjax>#m_"acid" = ("v/v%" * m_"sol")/100 = (5 * "6 mL")/100 = "0.3 mL"#</mathjax></p> <p>Since you're adding <strong>pure acid</strong> to this solution, the volume of the solute and the volume of the solution will increase by the <strong>same amount</strong>, <mathjax>#x#</mathjax> mL, so that you can write, for the target solution </p> <p><mathjax>#(m_"acid" + x)/(m_"sol" + x) * 100 = 40%#</mathjax></p> <p>This is equivalent to </p> <p><mathjax>#(0.3 + x)/(6 + x) * 100 = 40#</mathjax></p> <p>Solve this equation for <mathjax>#x#</mathjax> to get </p> <p><mathjax>#(0.3 + x) * 100 = 40 * (6 + x)#</mathjax></p> <p><mathjax>#30 + 100x = 240 + 40x#</mathjax></p> <p><mathjax>#60x = 210 => x = 210/60 = color(green)("3.5 mL")#</mathjax></p> <p>You thus need to add <strong>3.5 mL</strong> of <em>pure acid</em> to your original solution to get its percent concetration by volume to go from 5 to 40%.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/162392" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-concentration-of-water-in-solution-be-decreased"> How can the concentration of water in solution be decreased? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-concentration-of-a-solution-be-increased"> How can the concentration of a solution be increased? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-concentration-of-a-solution-in-ppm"> How do you find the concentration of a solution in 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class="impactStatements"> 4680 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How much pure acid must be added to 6 milliliters of a 5% acid solution to produce a 40% acid solution?	null
2,493	aa4825e2-6ddd-11ea-bc77-ccda262736ce	https://socratic.org/questions/585f57f011ef6b79f13fa81d	75%	start physical_unit 7 8 completion_percent none qc_end physical_unit 7 8 11 11 completion_percent qc_end physical_unit 7 8 14 15 time qc_end physical_unit 7 8 27 28 time qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Completion percentage 2 [OF] the reaction"}]	[{"type":"physical unit","value":"75%"}]	[{"type":"physical unit","value":"Completion percentage1 [OF] the reaction [=] \\pu{50%}"},{"type":"physical unit","value":"Time1 [OF] the reaction [=] \\pu{10 minutes}"},{"type":"physical unit","value":"Time2 [OF] the reaction [=] \\pu{5 minutes}"},{"type":"other","value":"A certain reaction follows zero-order kinetics."}]	<h1 class="questionTitle" itemprop="name">A certain reaction follows zero-order kinetics. Suppose the reaction went to #50%# completion after #10# minutes. What percentage of completion does the reaction reach in an additional #5# minutes? </h1>	null	75%	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>"Zero order" kinetics means that the rate = k and is independent of the amount of material present. Thus, if the rate is such that the reaction is 50% complete in 10 minutes, in another 5 minutes another 25% of the overall reaction is complete - 75% of the total reaction. </p> <p>The total reaction will be completed in 20 minutes.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>75%</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>"Zero order" kinetics means that the rate = k and is independent of the amount of material present. Thus, if the rate is such that the reaction is 50% complete in 10 minutes, in another 5 minutes another 25% of the overall reaction is complete - 75% of the total reaction. </p> <p>The total reaction will be completed in 20 minutes.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A certain reaction follows zero-order kinetics. Suppose the reaction went to #50%# completion after #10# minutes. What percentage of completion does the reaction reach in an additional #5# minutes? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-kinetics" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Kinetics</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-kinetics/rate-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Rate Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="460004" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/scooke"><img alt="" class="" src="https://profilepictures.socratic.org/ezAzqDkjRS6NXBmMH3lg_BioPic2010a.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/scooke"> SCooke </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-04T05:01:47" itemprop="dateCreated"> Aug 4, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>75%</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>"Zero order" kinetics means that the rate = k and is independent of the amount of material present. Thus, if the rate is such that the reaction is 50% complete in 10 minutes, in another 5 minutes another 25% of the overall reaction is complete - 75% of the total reaction. </p> <p>The total reaction will be completed in 20 minutes.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/460004" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="460075" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/truong-son-n"><img alt="" class="" src="https://profilepictures.socratic.org/07k4plnQfmnmzMuesQzw_14844-1449381920.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/truong-son-n"> Truong-Son N. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-04T10:01:19" itemprop="dateCreated"> Aug 4, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerDescription"> <div> <div class="markdown"><blockquote> <p><mathjax>#75%#</mathjax> complete.</p> </blockquote> <hr/> <p>A reaction following <strong>zero order kinetics</strong> has the <a href="https://socratic.org/chemistry/chemical-kinetics/rate-law">rate law</a>:</p> <blockquote> <p><mathjax>#r(t) = k[A]^0[B]^0 cdots#</mathjax></p> </blockquote> <p>and the rate is equal to the rate constant. Consequently, the rate of consumption of all the reactant(s) is a constant, and one could plot concentration <mathjax>#[A]#</mathjax> of reactant <mathjax>#A#</mathjax> vs. time <mathjax>#t#</mathjax> to model the reaction progress.</p> <p>This curve would then be a straight line:</p> <p><img alt="https://files.mtstatic.com/" src="https://useruploads.socratic.org/rVh4xu5ASCak4OJhTHLn_Image01.jpg"/></p> <p>And as such, it allows us to use the reaction progress as indicative of the fraction of <mathjax>#[A]#</mathjax> leftover. <mathjax>#50%#</mathjax> completion therefore means <mathjax>#50%#</mathjax> of <mathjax>#[A]#</mathjax> is gone.</p> <p>Since that occurred in <mathjax>#10#</mathjax> minutes, and the rate is constant, in <mathjax>#5#</mathjax> minutes the reaction proceeds by half of <mathjax>#50%#</mathjax>. As a result, the reaction is <mathjax>#color(blue)(ul(75%))#</mathjax> complete after <mathjax>#5#</mathjax> additional minutes, or <mathjax>#[A] = 0.25[A]_0#</mathjax>. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/460075" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-catalysts-affect-rates-of-reaction"> How do catalysts affect rates of reaction? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-enzymes-speed-up-rates-of-reaction"> How do enzymes speed up rates of reaction? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-rates-of-reaction-change-with-concentration"> How do rates of reaction change with concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-reaction-rates-typically-depend-on-temperature"> How does temperature affect the rate of reaction? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-reaction-rate-and-equilibrium-related"> How are reaction rate and equilibrium related? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-influences-reaction-rates"> What influences reaction rates? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-the-reaction-rate-affected-by-surface-area"> Is the reaction rate affected by surface area? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/does-volume-affect-the-reaction-rate"> Does volume affect the reaction rate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-pressure-affect-the-reaction-rate"> How does pressure affect the reaction rate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-rate-law-for-a-reaction"> How do you find rate law for a reaction? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-kinetics/rate-law"> See all questions in Rate Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 5086 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A certain reaction follows zero-order kinetics. Suppose the reaction went to #50%# completion after #10# minutes. What percentage of completion does the reaction reach in an additional #5# minutes?	null
2,494	acb84db6-6ddd-11ea-87c7-ccda262736ce	https://socratic.org/questions/white-phosphorus-p4-in-an-allotrope-of-phosphorus-that-reacts-with-fluorine-gas-	99.48 grams	start physical_unit 11 12 mass g qc_end physical_unit 16 17 28 29 mass qc_end chemical_equation 2 2 qc_end end	[{"type":"physical unit","value":"Mass [OF] fluorine gas [IN] grams"}]	[{"type":"physical unit","value":"99.48 grams"}]	[{"type":"physical unit","value":"Mass [OF] phosphorus trifluoride [=] \\pu{120 g}"},{"type":"physical unit","value":"Yield [OF] the reaction [=] \\pu{78.1%}"},{"type":"chemical equation","value":"P4"}]	<h1 class="questionTitle" itemprop="name">White phosphorus, #"P"_4#, is an allotrope of phosphorus that reacts with fluorine gas to form gaseous phosphorus trifluoride. What is the mass of fluorine gas needed to produce #"120. g"# of phosphorus trifluoride if the reaction has a #78.1%# yield?</h1>	null	99.48 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Start by writing the balanced chemical equation that describes this reaction</p> <blockquote> <p><mathjax>#"P"_ (4(s)) + 6"F"_ (2(g)) -> 4"PF"_ (3(g))#</mathjax></p> </blockquote> <p>Notice that for every <mathjax>#6#</mathjax> <strong>moles</strong> of fluorine gas <em>that take part in the reaction</em>, the reaction produces <mathjax>#4#</mathjax> <strong>moles</strong> of phosphorus trifluoride. </p> <p>This represents the reaction's <strong>theoretical yield</strong>, i.e. what you get for a reaction that has a <mathjax>#100%#</mathjax> <strong>yield</strong>. </p> <p>In your case, the reaction is said to have a <mathjax>#78.1%#</mathjax> <em><a href="https://socratic.org/chemistry/stoichiometry/percent-yield">percent yield</a></em>. This means that <strong>for every</strong> <mathjax>#100#</mathjax> <strong>moles</strong> of phosphorus trifluoride that the reaction <em>could theoretically produce</em>, you only get <mathjax>#78.1#</mathjax> <strong>moles</strong>. </p> <p>This is equivalent to saying that for every <mathjax>#6#</mathjax> <strong>moles</strong> of fluorine gas that the reaction consumes, you only get</p> <blockquote> <p><mathjax>#4 color(red)(cancel(color(black)("moles PF"_3))) * "78.1 moles PF"_3/(100color(red)(cancel(color(black)("moles PF"_3)))) = "3.124 moles PF"_3#</mathjax></p> </blockquote> <p>This represents the reaction's <strong>actual yield</strong>, i.e. what you actually get when you perform the reaction. </p> <p>This means that instead of </p> <blockquote> <p><mathjax>#"6 moles F"_2 " " stackrel(color(white)(acolor(blue)("at 100% yield")aaaa))(->) " " "4 moles PF"_3#</mathjax></p> </blockquote> <p>you get</p> <blockquote> <p><mathjax>#"6 moles F"_2 " " stackrel(color(white)(acolor(blue)("at 78.1% yield")aaaa))(->) " " "3.124 moles PF"_3#</mathjax></p> </blockquote> <p>So, convert the mass of phosphorus trifluoride to <em>moles</em> by using the compound's <strong>molar mass</strong></p> <blockquote> <p><mathjax>#120. color(red)(cancel(color(black)("g"))) * "1 mole PF"_3/(87.97color(red)(cancel(color(black)("g")))) = "1.363 moles PF"_3#</mathjax></p> </blockquote> <p>This means that the reaction must have consumed</p> <blockquote> <p><mathjax>#1.363 color(red)(cancel(color(black)("moles PF"_3))) * "6 moles F"_2/(3.124 color(red)(cancel(color(black)("moles PF"_3)))) = "2.618 moles F"_2#</mathjax></p> </blockquote> <p>To convert this to <em>grams</em>, use the <strong>molar mass</strong> of fluorine gas</p> <blockquote> <p><mathjax>#2.618 color(red)(cancel(color(black)("moles F"_2))) * "37.997 g"/(1color(red)(cancel(color(black)("mole F"_2)))) = color(darkgreen)(ul(color(black)("99.5 g F"_2)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the mass of phosphorus trifluoride produced by the reaction. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"99.5 g F"_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Start by writing the balanced chemical equation that describes this reaction</p> <blockquote> <p><mathjax>#"P"_ (4(s)) + 6"F"_ (2(g)) -> 4"PF"_ (3(g))#</mathjax></p> </blockquote> <p>Notice that for every <mathjax>#6#</mathjax> <strong>moles</strong> of fluorine gas <em>that take part in the reaction</em>, the reaction produces <mathjax>#4#</mathjax> <strong>moles</strong> of phosphorus trifluoride. </p> <p>This represents the reaction's <strong>theoretical yield</strong>, i.e. what you get for a reaction that has a <mathjax>#100%#</mathjax> <strong>yield</strong>. </p> <p>In your case, the reaction is said to have a <mathjax>#78.1%#</mathjax> <em><a href="https://socratic.org/chemistry/stoichiometry/percent-yield">percent yield</a></em>. This means that <strong>for every</strong> <mathjax>#100#</mathjax> <strong>moles</strong> of phosphorus trifluoride that the reaction <em>could theoretically produce</em>, you only get <mathjax>#78.1#</mathjax> <strong>moles</strong>. </p> <p>This is equivalent to saying that for every <mathjax>#6#</mathjax> <strong>moles</strong> of fluorine gas that the reaction consumes, you only get</p> <blockquote> <p><mathjax>#4 color(red)(cancel(color(black)("moles PF"_3))) * "78.1 moles PF"_3/(100color(red)(cancel(color(black)("moles PF"_3)))) = "3.124 moles PF"_3#</mathjax></p> </blockquote> <p>This represents the reaction's <strong>actual yield</strong>, i.e. what you actually get when you perform the reaction. </p> <p>This means that instead of </p> <blockquote> <p><mathjax>#"6 moles F"_2 " " stackrel(color(white)(acolor(blue)("at 100% yield")aaaa))(->) " " "4 moles PF"_3#</mathjax></p> </blockquote> <p>you get</p> <blockquote> <p><mathjax>#"6 moles F"_2 " " stackrel(color(white)(acolor(blue)("at 78.1% yield")aaaa))(->) " " "3.124 moles PF"_3#</mathjax></p> </blockquote> <p>So, convert the mass of phosphorus trifluoride to <em>moles</em> by using the compound's <strong>molar mass</strong></p> <blockquote> <p><mathjax>#120. color(red)(cancel(color(black)("g"))) * "1 mole PF"_3/(87.97color(red)(cancel(color(black)("g")))) = "1.363 moles PF"_3#</mathjax></p> </blockquote> <p>This means that the reaction must have consumed</p> <blockquote> <p><mathjax>#1.363 color(red)(cancel(color(black)("moles PF"_3))) * "6 moles F"_2/(3.124 color(red)(cancel(color(black)("moles PF"_3)))) = "2.618 moles F"_2#</mathjax></p> </blockquote> <p>To convert this to <em>grams</em>, use the <strong>molar mass</strong> of fluorine gas</p> <blockquote> <p><mathjax>#2.618 color(red)(cancel(color(black)("moles F"_2))) * "37.997 g"/(1color(red)(cancel(color(black)("mole F"_2)))) = color(darkgreen)(ul(color(black)("99.5 g F"_2)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the mass of phosphorus trifluoride produced by the reaction. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">White phosphorus, #"P"_4#, is an allotrope of phosphorus that reacts with fluorine gas to form gaseous phosphorus trifluoride. What is the mass of fluorine gas needed to produce #"120. g"# of phosphorus trifluoride if the reaction has a #78.1%# yield?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/percent-yield" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Yield</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="466649" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-22T00:36:50" itemprop="dateCreated"> Aug 22, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"99.5 g F"_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Start by writing the balanced chemical equation that describes this reaction</p> <blockquote> <p><mathjax>#"P"_ (4(s)) + 6"F"_ (2(g)) -> 4"PF"_ (3(g))#</mathjax></p> </blockquote> <p>Notice that for every <mathjax>#6#</mathjax> <strong>moles</strong> of fluorine gas <em>that take part in the reaction</em>, the reaction produces <mathjax>#4#</mathjax> <strong>moles</strong> of phosphorus trifluoride. </p> <p>This represents the reaction's <strong>theoretical yield</strong>, i.e. what you get for a reaction that has a <mathjax>#100%#</mathjax> <strong>yield</strong>. </p> <p>In your case, the reaction is said to have a <mathjax>#78.1%#</mathjax> <em><a href="https://socratic.org/chemistry/stoichiometry/percent-yield">percent yield</a></em>. This means that <strong>for every</strong> <mathjax>#100#</mathjax> <strong>moles</strong> of phosphorus trifluoride that the reaction <em>could theoretically produce</em>, you only get <mathjax>#78.1#</mathjax> <strong>moles</strong>. </p> <p>This is equivalent to saying that for every <mathjax>#6#</mathjax> <strong>moles</strong> of fluorine gas that the reaction consumes, you only get</p> <blockquote> <p><mathjax>#4 color(red)(cancel(color(black)("moles PF"_3))) * "78.1 moles PF"_3/(100color(red)(cancel(color(black)("moles PF"_3)))) = "3.124 moles PF"_3#</mathjax></p> </blockquote> <p>This represents the reaction's <strong>actual yield</strong>, i.e. what you actually get when you perform the reaction. </p> <p>This means that instead of </p> <blockquote> <p><mathjax>#"6 moles F"_2 " " stackrel(color(white)(acolor(blue)("at 100% yield")aaaa))(->) " " "4 moles PF"_3#</mathjax></p> </blockquote> <p>you get</p> <blockquote> <p><mathjax>#"6 moles F"_2 " " stackrel(color(white)(acolor(blue)("at 78.1% yield")aaaa))(->) " " "3.124 moles PF"_3#</mathjax></p> </blockquote> <p>So, convert the mass of phosphorus trifluoride to <em>moles</em> by using the compound's <strong>molar mass</strong></p> <blockquote> <p><mathjax>#120. color(red)(cancel(color(black)("g"))) * "1 mole PF"_3/(87.97color(red)(cancel(color(black)("g")))) = "1.363 moles PF"_3#</mathjax></p> </blockquote> <p>This means that the reaction must have consumed</p> <blockquote> <p><mathjax>#1.363 color(red)(cancel(color(black)("moles PF"_3))) * "6 moles F"_2/(3.124 color(red)(cancel(color(black)("moles PF"_3)))) = "2.618 moles F"_2#</mathjax></p> </blockquote> <p>To convert this to <em>grams</em>, use the <strong>molar mass</strong> of fluorine gas</p> <blockquote> <p><mathjax>#2.618 color(red)(cancel(color(black)("moles F"_2))) * "37.997 g"/(1color(red)(cancel(color(black)("mole F"_2)))) = color(darkgreen)(ul(color(black)("99.5 g F"_2)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the mass of phosphorus trifluoride produced by the reaction. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/466649" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ebd02bf3469570e2e62"> Question #e2e62 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ec502bf34694a4fee2e"> Question #fee2e </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ec902bf34694a4fee32"> Question #fee32 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ece02bf346950519e89"> Question #19e89 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ed302bf34694c8c5bdc"> Question #c5bdc </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ee302bf3469517a1065"> Question #a1065 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-would-be-the-limiting-reagent-if-26-0-grams-of-c3h9n-were-reacted-with-46-3"> What would be the limiting reagent if 26.0 grams of C3H9N were reacted with 46.3 grams of... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-percent-yield-always-less-than-100"> Is percent yield always less than 100? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-would-be-the-limiting-reagent-if-41-9-grams-of-c2h3of-were-reacted-with-61-"> What would be the limiting reagent if 41.9 grams of C2H3OF were reacted with 61.0 grams of... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-yield-of-the-following-reaction-if-60-grams-of-caco3-is-heat"> What is the percent yield of the following reaction if 60 grams of CaCO3 is heated to give 15... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/percent-yield"> See all questions in Percent Yield </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 4964 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	White phosphorus, #"P"_4#, is an allotrope of phosphorus that reacts with fluorine gas to form gaseous phosphorus trifluoride. What is the mass of fluorine gas needed to produce #"120. g"# of phosphorus trifluoride if the reaction has a #78.1%# yield?	null
2,495	abda6a27-6ddd-11ea-8d8d-ccda262736ce	https://socratic.org/questions/what-is-the-combustion-reaction-of-sucrose	C12H22O11(s) + 35/2 O2(g) -> 12 CO2(g) + 11 H2O(l)	start chemical_equation qc_end substance 6 6 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the combustion reaction"}]	[{"type":"chemical equation","value":"C12H22O11(s) + 35/2 O2(g) -> 12 CO2(g) + 11 H2O(l)"}]	[{"type":"substance name","value":"Sucrose"}]	<h1 class="questionTitle" itemprop="name">What is the combustion reaction of sucrose?</h1>	null	C12H22O11(s) + 35/2 O2(g) -> 12 CO2(g) + 11 H2O(l)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Is this equation balanced? I might have made an error! How would you know? Supposing 1 equiv of carbon in the sucrose was oxidized to <mathjax>#C#</mathjax>. How would I represent that?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_12H_22O_11(s) +35/2O_2(g) rarr 12CO_2(g)uarr + 11H_2O(l)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Is this equation balanced? I might have made an error! How would you know? Supposing 1 equiv of carbon in the sucrose was oxidized to <mathjax>#C#</mathjax>. How would I represent that?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the combustion reaction of sucrose?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-reactions-and-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions and Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="187969" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-13T18:10:47" itemprop="dateCreated"> Nov 13, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_12H_22O_11(s) +35/2O_2(g) rarr 12CO_2(g)uarr + 11H_2O(l)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Is this equation balanced? I might have made an error! How would you know? Supposing 1 equiv of carbon in the sucrose was oxidized to <mathjax>#C#</mathjax>. How would I represent that?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/187969" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb002bf34694a4fee47"> Question #fee47 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb402bf34694c8c5c15"> Question #c5c15 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb802bf346950519eb9"> Question #19eb9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cbf02bf3469570e2ea2"> Question #e2ea2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc002bf34695a6bc751"> Question #bc751 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc202bf3469570e2ea6"> Question #e2ea6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531e867a02bf342492a08b07"> Question #08b07 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-thermochemical-equation-for-the-combustion-of-benzene"> What is the thermochemical equation for the combustion of benzene? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-reversible"> Why are chemical reactions reversible? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-important"> Why are chemical reactions important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/chemical-reactions-and-equations"> See all questions in Chemical Reactions and Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 9952 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the combustion reaction of sucrose?	null
2,496	ac876e8d-6ddd-11ea-b6e1-ccda262736ce	https://socratic.org/questions/the-molar-mass-of-no-2-is-46-01-g-mol-how-many-moles-of-no-2-are-present-in-114-	2.50 moles	start physical_unit 4 4 mole mol qc_end physical_unit 4 4 6 7 molar_mass qc_end physical_unit 4 4 16 17 mass qc_end end	[{"type":"physical unit","value":"Mole [OF] NO2 [IN] moles"}]	[{"type":"physical unit","value":"2.50 moles"}]	[{"type":"physical unit","value":"Molar mass [OF] NO2 [=] \\pu{46.01 g/mol}"},{"type":"physical unit","value":"Mass [OF] NO2 [=] \\pu{114.95 g}"}]	<h1 class="questionTitle" itemprop="name">The molar mass of #NO_2# is 46.01 g/mol. How many moles of #NO_2# are present in 114.95 g?</h1>	null	2.50 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>A substance's <strong>molar mass</strong> tells you the mass of <strong>one mole</strong> of that substance. </p> <p>In your case, <em>nitrogen dioxide</em>, <mathjax>#"NO"_2#</mathjax>, is said to have a molar mass of <mathjax>#"46.01 g/mol"#</mathjax>. That means that <strong>every mole</strong> of nitrogen dioxide will have a mass of <mathjax>#"46.01 g"#</mathjax>. </p> <p>So, in essence, <strong>molar mass</strong> is simply a <em>conversion factor</em> between number of molecules and mass. </p> <p>Since you need <mathjax>#"46.01 g"#</mathjax> of nitrogen dioxide in order to have <strong>one mole</strong> of the compound, it follows that <mathjax>#"114.95 g"#</mathjax> will contain </p> <blockquote> <p><mathjax>#114.95 color(red)(cancel(color(black)("g"))) * "1 mole NO"_2/(46.01color(red)(cancel(color(black)("g")))) = "2.49837 moles NO"_2#</mathjax></p> </blockquote> <p>Rounded to four <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the number of sig figs you have for the molar mass of the compound, the answer will be </p> <blockquote> <p><mathjax>#n_(NO_2) = color(green)("2.498 moles")#</mathjax></p> </blockquote> <p> <iframe src="https://www.youtube.com/embed/CMnkSb2YsXI?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"2.498"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>A substance's <strong>molar mass</strong> tells you the mass of <strong>one mole</strong> of that substance. </p> <p>In your case, <em>nitrogen dioxide</em>, <mathjax>#"NO"_2#</mathjax>, is said to have a molar mass of <mathjax>#"46.01 g/mol"#</mathjax>. That means that <strong>every mole</strong> of nitrogen dioxide will have a mass of <mathjax>#"46.01 g"#</mathjax>. </p> <p>So, in essence, <strong>molar mass</strong> is simply a <em>conversion factor</em> between number of molecules and mass. </p> <p>Since you need <mathjax>#"46.01 g"#</mathjax> of nitrogen dioxide in order to have <strong>one mole</strong> of the compound, it follows that <mathjax>#"114.95 g"#</mathjax> will contain </p> <blockquote> <p><mathjax>#114.95 color(red)(cancel(color(black)("g"))) * "1 mole NO"_2/(46.01color(red)(cancel(color(black)("g")))) = "2.49837 moles NO"_2#</mathjax></p> </blockquote> <p>Rounded to four <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the number of sig figs you have for the molar mass of the compound, the answer will be </p> <blockquote> <p><mathjax>#n_(NO_2) = color(green)("2.498 moles")#</mathjax></p> </blockquote> <p> <iframe src="https://www.youtube.com/embed/CMnkSb2YsXI?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">The molar mass of #NO_2# is 46.01 g/mol. How many moles of #NO_2# are present in 114.95 g?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="210462" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-10T00:37:13" itemprop="dateCreated"> Jan 10, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"2.498"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>A substance's <strong>molar mass</strong> tells you the mass of <strong>one mole</strong> of that substance. </p> <p>In your case, <em>nitrogen dioxide</em>, <mathjax>#"NO"_2#</mathjax>, is said to have a molar mass of <mathjax>#"46.01 g/mol"#</mathjax>. That means that <strong>every mole</strong> of nitrogen dioxide will have a mass of <mathjax>#"46.01 g"#</mathjax>. </p> <p>So, in essence, <strong>molar mass</strong> is simply a <em>conversion factor</em> between number of molecules and mass. </p> <p>Since you need <mathjax>#"46.01 g"#</mathjax> of nitrogen dioxide in order to have <strong>one mole</strong> of the compound, it follows that <mathjax>#"114.95 g"#</mathjax> will contain </p> <blockquote> <p><mathjax>#114.95 color(red)(cancel(color(black)("g"))) * "1 mole NO"_2/(46.01color(red)(cancel(color(black)("g")))) = "2.49837 moles NO"_2#</mathjax></p> </blockquote> <p>Rounded to four <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the number of sig figs you have for the molar mass of the compound, the answer will be </p> <blockquote> <p><mathjax>#n_(NO_2) = color(green)("2.498 moles")#</mathjax></p> </blockquote> <p> <iframe src="https://www.youtube.com/embed/CMnkSb2YsXI?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/210462" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 30135 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	The molar mass of #NO_2# is 46.01 g/mol. How many moles of #NO_2# are present in 114.95 g?	null
2,497	aab5d5af-6ddd-11ea-8c9a-ccda262736ce	https://socratic.org/questions/what-is-the-oxidation-numbers-of-a-n-in-nh-4	-3	start physical_unit 7 7 oxidation_number none qc_end chemical_equation 9 9 qc_end end	[{"type":"physical unit","value":"Oxidation number [OF] N"}]	[{"type":"physical unit","value":"-3"}]	[{"type":"chemical equation","value":"NH4+"}]	<h1 class="questionTitle" itemprop="name">What is the oxidation numbers of (a) N in #NH_4^+#?</h1>	null	-3	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And the sum of the individual <a href="https://socratic.org/chemistry/electrochemistry/oxidation-numbers">oxidation numbers</a> is equal to the charge on the ion...</p> <p>And so <mathjax>#N_"oxidation number"+4xxI^+=+1#</mathjax></p> <p><mathjax>#N_"oxidation number"=-III#</mathjax></p> <p>For a few more examples .... see <a href="https://socratic.org/questions/assign-oxidation-numbers#570916">this older answer.</a></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, as usual, the oxidation number of <mathjax>#H#</mathjax> is <mathjax>#+I#</mathjax> as is typical....</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And the sum of the individual <a href="https://socratic.org/chemistry/electrochemistry/oxidation-numbers">oxidation numbers</a> is equal to the charge on the ion...</p> <p>And so <mathjax>#N_"oxidation number"+4xxI^+=+1#</mathjax></p> <p><mathjax>#N_"oxidation number"=-III#</mathjax></p> <p>For a few more examples .... see <a href="https://socratic.org/questions/assign-oxidation-numbers#570916">this older answer.</a></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the oxidation numbers of (a) N in #NH_4^+#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#electrochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Electrochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/electrochemistry/oxidation-numbers" itemprop="url"> <span class="breadcrumb" itemprop="title">Oxidation Numbers</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="571335" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-03-12T06:39:02" itemprop="dateCreated"> Mar 12, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, as usual, the oxidation number of <mathjax>#H#</mathjax> is <mathjax>#+I#</mathjax> as is typical....</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And the sum of the individual <a href="https://socratic.org/chemistry/electrochemistry/oxidation-numbers">oxidation numbers</a> is equal to the charge on the ion...</p> <p>And so <mathjax>#N_"oxidation number"+4xxI^+=+1#</mathjax></p> <p><mathjax>#N_"oxidation number"=-III#</mathjax></p> <p>For a few more examples .... see <a href="https://socratic.org/questions/assign-oxidation-numbers#570916">this older answer.</a></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/571335" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="571441" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/nam-d"><img alt="" class="" src="https://profilepictures.socratic.org/QG4MnkoER6u99DIDVWKK_787554714770341.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/nam-d"> Nam D. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-03-12T11:10:35" itemprop="dateCreated"> Mar 12, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#-3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We have the ammonium ion, <mathjax>#NH_4^+#</mathjax>.</p> <p>As you can see from the formula, it has a <mathjax>#+1#</mathjax> charge. </p> <p>Since nitrogen is more electronegative than hydrogen, hydrogen will occupy a <mathjax>#+1#</mathjax> charge. There are four hydrogen atoms in this ion, so the total charge of the hydrogens is <mathjax>#+1*4=+4#</mathjax>.</p> <p>Let <mathjax>#x#</mathjax> be the oxidation number of <mathjax>#N#</mathjax> in <mathjax>#NH_4^+#</mathjax>.</p> <p>We got:</p> <p><mathjax>#x+(+4)=+1#</mathjax></p> <p>Treating them as normal numbers, we get</p> <p><mathjax>#x+4=1#</mathjax></p> <p><mathjax>#x=1-4#</mathjax></p> <p><mathjax>#=-3#</mathjax></p> <p>So, nitrogen would have a <mathjax>#-3#</mathjax> charge, which is also its usual charge.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/571441" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-relate-to-electron-configuration"> How do oxidation numbers relate to electron configuration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-relate-to-valence-electrons"> How do oxidation numbers relate to valence electrons? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-vary-with-the-periodic-table"> How do oxidation numbers vary with the periodic table? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-oxidation-number-of-an-element-in-a-compound"> How do you calculate the oxidation number of an element in a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-sulfur"> What is the oxidation number for sulfur? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-carbon"> What is the oxidation number for carbon? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-copper"> What is the oxidation number for copper? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-nitrogen"> What is the oxidation number for nitrogen? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-oxygen"> What is the oxidation number for oxygen? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-oxidation-state-of-noble-gas-zero"> Why is the oxidation state of noble gas zero? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/electrochemistry/oxidation-numbers"> See all questions in Oxidation Numbers </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 33050 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the oxidation numbers of (a) N in #NH_4^+#?	null
2,498	aa989fa2-6ddd-11ea-aa1a-ccda262736ce	https://socratic.org/questions/in-the-equation-n-2-h-2-nh-3-what-mass-of-ammonia-gas-can-be-produced-from-12-mo	136.32 grams	start physical_unit 11 12 mass g qc_end physical_unit 20 21 17 18 mole qc_end chemical_equation 3 7 qc_end end	[{"type":"physical unit","value":"Mass [OF] ammonia gas [IN] grams"}]	[{"type":"physical unit","value":"136.32 grams"}]	[{"type":"physical unit","value":"Mole [OF] hydrogen gas [=] \\pu{12 mol}"},{"type":"chemical equation","value":"N2 + H2 -> NH3"}]	<h1 class="questionTitle" itemprop="name">In the equation #N_2 + H_2 -> NH_3#, what mass of ammonia gas can be produced from 12 mol of hydrogen gas? </h1>	null	136.32 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First, you MUST balance the equation: <br/> <mathjax>#N_2 + 3 H_2 → 2 NH_3#</mathjax><br/> This shows you that for every 3 moles of hydrogen, you can produce 2 moles of ammonia. </p> <p>Then, you can calculate how many moles of ammonia are produced when 12 moles of hydrogen reacts. Keep in mind, you also need a certain amount of nitrogen gas, but that's not what the question is asking, so we can ignore it.</p> <p>We write what we know from the balanced equation first, then an equal sign, then what the question is asking:</p> <p><mathjax>#(3 mol H_2)/(2 mol NH_3)=(12 mol H_2)/(x mol NH_3)#</mathjax></p> <p>Solve for "x" by cross multiplying</p> <p><mathjax>#122=3 x#</mathjax><br/> <mathjax>#(12*2)/3=x#</mathjax></p> <p><mathjax>#8=x#</mathjax></p> <p>Therefore, 12 moles of hydrogen makes 8 moles of ammonia.</p> <p>Then you multiply by the molar mass of ammonia to find the mass:<br/> <mathjax>#8 mol NH_3 xx (17.04 g)/(mol) = 136.32 g#</mathjax></p> <p>You only have 2 significant figures in the question, so your last step is to round your answer to 2 significant figures.</p> <p>Final answer: 140 g or <mathjax>#1.4xx10^2 g#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>12 mol of hydrogen produces 8 mol of ammonia, which then translates into 136.32 g. Round to <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a> and you get 140 g</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First, you MUST balance the equation: <br/> <mathjax>#N_2 + 3 H_2 → 2 NH_3#</mathjax><br/> This shows you that for every 3 moles of hydrogen, you can produce 2 moles of ammonia. </p> <p>Then, you can calculate how many moles of ammonia are produced when 12 moles of hydrogen reacts. Keep in mind, you also need a certain amount of nitrogen gas, but that's not what the question is asking, so we can ignore it.</p> <p>We write what we know from the balanced equation first, then an equal sign, then what the question is asking:</p> <p><mathjax>#(3 mol H_2)/(2 mol NH_3)=(12 mol H_2)/(x mol NH_3)#</mathjax></p> <p>Solve for "x" by cross multiplying</p> <p><mathjax>#122=3 x#</mathjax><br/> <mathjax>#(12*2)/3=x#</mathjax></p> <p><mathjax>#8=x#</mathjax></p> <p>Therefore, 12 moles of hydrogen makes 8 moles of ammonia.</p> <p>Then you multiply by the molar mass of ammonia to find the mass:<br/> <mathjax>#8 mol NH_3 xx (17.04 g)/(mol) = 136.32 g#</mathjax></p> <p>You only have 2 significant figures in the question, so your last step is to round your answer to 2 significant figures.</p> <p>Final answer: 140 g or <mathjax>#1.4xx10^2 g#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">In the equation #N_2 + H_2 -> NH_3#, what mass of ammonia gas can be produced from 12 mol of hydrogen gas? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/mole-ratios" itemprop="url"> <span class="breadcrumb" itemprop="title">Mole Ratios</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="208489" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/sandra-g-2"><img alt="" class="" src="https://lh4.googleusercontent.com/-kaCPmWTnvX8/AAAAAAAAAAI/AAAAAAAAAKw/WYwLLk7mC4s/photo.jpg?sz=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/sandra-g-2"> Sandra G. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-05T13:53:00" itemprop="dateCreated"> Jan 5, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>12 mol of hydrogen produces 8 mol of ammonia, which then translates into 136.32 g. Round to <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a> and you get 140 g</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First, you MUST balance the equation: <br/> <mathjax>#N_2 + 3 H_2 → 2 NH_3#</mathjax><br/> This shows you that for every 3 moles of hydrogen, you can produce 2 moles of ammonia. </p> <p>Then, you can calculate how many moles of ammonia are produced when 12 moles of hydrogen reacts. Keep in mind, you also need a certain amount of nitrogen gas, but that's not what the question is asking, so we can ignore it.</p> <p>We write what we know from the balanced equation first, then an equal sign, then what the question is asking:</p> <p><mathjax>#(3 mol H_2)/(2 mol NH_3)=(12 mol H_2)/(x mol NH_3)#</mathjax></p> <p>Solve for "x" by cross multiplying</p> <p><mathjax>#122=3 x#</mathjax><br/> <mathjax>#(12*2)/3=x#</mathjax></p> <p><mathjax>#8=x#</mathjax></p> <p>Therefore, 12 moles of hydrogen makes 8 moles of ammonia.</p> <p>Then you multiply by the molar mass of ammonia to find the mass:<br/> <mathjax>#8 mol NH_3 xx (17.04 g)/(mol) = 136.32 g#</mathjax></p> <p>You only have 2 significant figures in the question, so your last step is to round your answer to 2 significant figures.</p> <p>Final answer: 140 g or <mathjax>#1.4xx10^2 g#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/208489" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4178e02bf3469517a106e"> Question #a106e </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4178e02bf3469570e2e86"> Question #e2e86 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179102bf3469517a1072"> Question #a1072 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179402bf34694c8c5bf1"> Question #c5bf1 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179702bf3469588dc373"> Question #dc373 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179c02bf34694c8c5bf9"> Question #c5bf9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417a302bf3469517a1076"> Question #a1076 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417c702bf3469588dc377"> Question #dc377 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417d002bf346963eb984f"> Question #b984f </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417d402bf346950519ea3"> Question #19ea3 </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/mole-ratios"> See all questions in Mole Ratios </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 18658 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	In the equation #N_2 + H_2 -> NH_3#, what mass of ammonia gas can be produced from 12 mol of hydrogen gas?	null
2,499	aae6ee06-6ddd-11ea-a4a0-ccda262736ce	https://socratic.org/questions/how-do-you-convert-1-51-10-15-atoms-si-to-mol-si	2.52 × 10^(-9) mol	start physical_unit 8 8 mole mol qc_end end	[{"type":"physical unit","value":"Mole [OF] Si [IN] mol"}]	[{"type":"physical unit","value":"2.52 × 10^(-9) mol"}]	[{"type":"physical unit","value":"Number [OF] Si atoms [=] \\pu{1.51 × 10^15}"}]	<h1 class="questionTitle" itemprop="name">How do you convert #1.51 * 10^15# atoms #Si# to mol #Si#?</h1>	null	2.52 × 10^(-9) mol	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So you divide:</p> <p><mathjax>#(1.51xx10^15)/(6.02xx10^23)=0.252xx10^(-8)=2.52xx10^(-9)mol#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1mol=6.02xx10^23#</mathjax> particles</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So you divide:</p> <p><mathjax>#(1.51xx10^15)/(6.02xx10^23)=0.252xx10^(-8)=2.52xx10^(-9)mol#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you convert #1.51 * 10^15# atoms #Si# to mol #Si#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="373361" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meneernask"><img alt="" class="" src="https://profilepictures.socratic.org/gpA0lokRGK9vLVUnAMAy_meneernask.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meneernask"> MeneerNask </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-02-04T14:20:57" itemprop="dateCreated"> Feb 4, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1mol=6.02xx10^23#</mathjax> particles</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So you divide:</p> <p><mathjax>#(1.51xx10^15)/(6.02xx10^23)=0.252xx10^(-8)=2.52xx10^(-9)mol#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/373361" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? 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