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| 
	http://rosettacode.org/wiki/Achilles_numbers | 
	Achilles numbers | 
	
 This page uses content from Wikipedia. The original article was at Achilles number. The list of authors can be seen in the page history. As with Rosetta Code, the text of Wikipedia is available under the GNU FDL. (See links for details on variance)
An Achilles number is a number that is powerful but imperfect. Named after Achilles, a hero of the Trojan war, who was also powerful but imperfect.
A positive integer n is a powerful number if, for every prime factor p of n, p2 is also a divisor.
In other words, every prime factor appears at least squared in the factorization.
All Achilles numbers are powerful. However, not all powerful numbers are Achilles numbers: only those that cannot be represented as mk, where m and k are positive integers greater than 1.
A strong Achilles number is an Achilles number whose Euler totient (𝜑) is also an Achilles number.
E.G.
108 is a powerful number. Its prime factorization is 22 × 33, and thus its prime factors are 2 and 3. Both 22 = 4 and 32 = 9 are divisors of 108. However, 108 cannot be represented as mk, where m and k are positive integers greater than 1, so 108 is an Achilles number.
360 is not an Achilles number because it is not powerful. One of its prime factors is 5 but 360 is not divisible by 52 = 25.
Finally, 784 is not an Achilles number. It is a powerful number, because not only are 2 and 7 its only prime factors, but also 22 = 4 and 72 = 49 are divisors of it. Nonetheless, it is a perfect power; its square root is an even integer, so it is not an Achilles number.
500 = 22 × 53 is a strong Achilles number as its Euler totient, 𝜑(500), is 200 = 23 × 52 which is also an Achilles number.
Task
 Find and show the first 50 Achilles numbers.
 Find and show at least the first 20 strong Achilles numbers.
 For at least 2 through 5, show the count of Achilles numbers with that many digits.
See also
 Wikipedia: Achilles number
 OEIS:A052486 - Achilles numbers - powerful but imperfect numbers
 OEIS:A194085 - Strong Achilles numbers: Achilles numbers m such that phi(m) is also an Achilles number
 Related task: Powerful numbers
 Related task: Totient function
 | 
	#XPL0 | 
	XPL0 | 
	func GCD(N, D);         \Return the greatest common divisor of N and D
int  N, D;              \numerator and denominator
int  R;
[if D > N then
    [R:= D;  D:= N;  N:= R];    \swap D and N
while D > 0 do
    [R:= rem(N/D);
    N:= D;
    D:= R;
    ];
return N;
];      \GCD
 
func Totient(N);        \Return the totient of N
int  N, Phi, M;
[Phi:= 0;
for M:= 1 to N do
    if GCD(M, N) = 1 then Phi:= Phi+1;
return Phi;
];
 
func Powerful(N0);      \Return 'true' if N0 is a powerful number
int  N0, N, F, Q, L;
[if N0 <= 1 then return false;
N:= N0;  F:= 2;
L:= sqrt(N0);
loop    [Q:= N/F;
        if rem(0) = 0 then      \found a factor
                [if rem(N0/(F*F)) then return false;
                N:= Q;
                if F>N then quit;
                ]
        else    [F:= F+1;
                if F > L then
                    [if rem(N0/(N*N)) then return false;
                    quit;
                    ];
                ];
        ];
return true;
];
 
func Achilles(N);       \Return 'true' if N is an Achilles number
int  N, M, A;
[if not Powerful(N) then return false;
M:= 2;
A:= M*M;
repeat  loop    [if A = N then return false;
                if A > N then quit;
                A:= A*M;
                ];
        M:= M+1;
        A:= M*M;
until   A > N;
return true;
];
 
int Cnt, N, Pwr, Start;
[Cnt:= 0;
N:= 1;
loop    [if Achilles(N) then
            [IntOut(0, N);
            Cnt:= Cnt+1;
            if Cnt >= 50 then quit;
            if rem(Cnt/10) then ChOut(0, 9) else CrLf(0);
            ];
        N:= N+1;
        ];
CrLf(0);  CrLf(0);
Cnt:= 0;
N:= 1;
loop    [if Achilles(N) then
            if Achilles(Totient(N)) then
                [IntOut(0, N);
                Cnt:= Cnt+1;
                if Cnt >= 20 then quit;
                if rem(Cnt/10) then ChOut(0, 9) else CrLf(0);
                ];
        N:= N+1;
        ];
CrLf(0);  CrLf(0);
for Pwr:= 1 to 6 do
    [IntOut(0, Pwr);  Text(0, ": ");
    Start:= fix(Pow(10.0, float(Pwr-1)));
    Cnt:= 0;
    for N:= Start to Start*10-1 do
        if Achilles(N) then Cnt:= Cnt+1;
    IntOut(0, Cnt);  CrLf(0);
    ];
] | 
| 
	http://rosettacode.org/wiki/Aliquot_sequence_classifications | 
	Aliquot sequence classifications | 
	An aliquot sequence of a positive integer K is defined recursively as the first member
being K and subsequent members being the sum of the Proper divisors of the previous term.
 If the terms eventually reach 0 then the series for K is said to terminate.
There are several classifications for non termination:
 If the second term is K then all future terms are also K and so the sequence repeats from the first term with period 1 and K is called perfect.
 If the third term would be repeating K then the sequence repeats with period 2 and K is called amicable.
 If the Nth term would be repeating K for the first time, with N > 3 then the sequence repeats with period N - 1 and K is called sociable.
Perfect, amicable and sociable numbers eventually repeat the original number K; there are other repetitions...
 Some K have a sequence that eventually forms a periodic repetition of period 1 but of a number other than K, for example 95 which forms the sequence 95, 25, 6, 6, 6, ... such K are called aspiring.
 K that have a sequence that eventually forms a periodic repetition of period >= 2 but of a number other than K, for example 562 which forms the sequence 562, 284, 220, 284, 220, ... such K are called cyclic.
And finally:
 Some K form aliquot sequences that are not known to be either terminating or periodic; these K are to be called non-terminating. 
For the purposes of this task, K is to be classed as non-terminating if it has not been otherwise classed after generating 16 terms or if any term of the sequence is greater than 2**47 = 140,737,488,355,328. 
Task
 Create routine(s) to generate the aliquot sequence of a positive integer enough to classify it according to the classifications given above.
 Use it to display the classification and sequences of the numbers one to ten inclusive.
 Use it to show the classification and sequences of the following integers, in order:
 11, 12, 28, 496, 220, 1184, 12496, 1264460, 790, 909, 562, 1064, 1488, and optionally 15355717786080.
Show all output on this page.
Related tasks
   Abundant, deficient and perfect number classifications. (Classifications from only the first two members of the whole sequence).
   Proper divisors
   Amicable pairs
 | 
	#jq | 
	jq | 
	# "until" is available in more recent versions of jq
# than jq 1.4
def until(cond; next):
  def _until:
    if cond then . else (next|_until) end;
  _until;
 
# unordered
def proper_divisors:
  . as $n
  | if $n > 1 then 1,
      ( range(2; 1 + (sqrt|floor)) as $i
        | if ($n % $i) == 0 then $i,
            (($n / $i) | if . == $i then empty else . end)
          else empty
          end)
    else empty
    end;
 
# sum of proper divisors, or 0
def pdsum:
  [proper_divisors] | add // 0;
 
# input is n
# maxlen defaults to 16;
# maxterm defaults to 2^47
def aliquot(maxlen; maxterm):
  (maxlen // 15) as $maxlen
  | (maxterm // 40737488355328) as $maxterm
  | if . == 0 then "terminating at 0" 
    else
    # [s, slen, new] = [[n], 1, n]
    [ [.], 1, .]
    | until( type == "string" or .[1] > $maxlen or .[2] > $maxterm;
             .[0] as $s | .[1] as $slen
             | ($s | .[length-1] | pdsum) as $new
             | if ($s|index($new)) then
                 if $s[0] == $new then
                     if $slen == 1 then "perfect \($s)"
                     elif $slen == 2 then "amicable: \($s)"
                     else "sociable of length \($slen): \($s)"
		     end
                 elif ($s | .[length-1]) == $new then "aspiring: \($s)"
                 else "cyclic back to \($new): \($s)"
		 end
               elif $new == 0 then "terminating: \($s + [0])"
               else [ ($s + [$new]), ($slen + 1), $new ]
               end )
    | if type == "string" then . else "non-terminating: \(.[0])" end
    end;
 
def task:
  def pp: "\(.): \(aliquot(null;null))";
     (range(1; 11) | pp),
     "",
     ((11, 12, 28, 496, 220, 1184, 12496, 1264460,
      790, 909, 562, 1064, 1488, 15355717786080) | pp);
 
task | 
| 
	http://rosettacode.org/wiki/Add_a_variable_to_a_class_instance_at_runtime | 
	Add a variable to a class instance at runtime | 
	Demonstrate how to dynamically add variables to an object (a class instance) at runtime.
This is useful when the methods/variables of an instance are based on a data file that isn't available until runtime. Hal Fulton gives an example of creating an OO CSV parser at An Exercise in Metaprogramming with Ruby. This is referred to as "monkeypatching" by Pythonistas and some others.
 | 
	#REBOL | 
	REBOL | 
	 
rebol [
	Title: "Add Variables to Class at Runtime"
	URL: http://rosettacode.org/wiki/Adding_variables_to_a_class_instance_at_runtime
]
 
; As I understand it, a REBOL object can only ever have whatever
; properties it was born with. However, this is somewhat offset by the
; fact that every instance can serve as a prototype for a new object
; that also has the new parameter you want to add.
 
; Here I create an empty instance of the base object (x), then add the
; new instance variable while creating a new object prototyped from
; x. I assign the new object to x, et voila', a dynamically added
; variable.
 
x: make object! [] ; Empty object.
 
x: make x [
	newvar: "forty-two" ; New property.
]
 
print "Empty object modifed with 'newvar' property:"
probe x
 
; A slightly more interesting example:
 
starfighter: make object! [
	model: "unknown"
	pilot: none
]
x-wing: make starfighter [
	model: "Incom T-65 X-wing"
]
 
squadron: reduce [
	make x-wing [pilot: "Luke Skywalker"]
	make x-wing [pilot: "Wedge Antilles"]
	make starfighter [
		model: "Slayn & Korpil B-wing"
		pilot: "General Salm"
	]
]
 
; Adding new property here.
squadron/1: make squadron/1 [deathstar-removal-expert: yes]
 
print [crlf "Fighter squadron:"]
foreach pilot squadron [probe pilot]
  | 
| 
	http://rosettacode.org/wiki/Add_a_variable_to_a_class_instance_at_runtime | 
	Add a variable to a class instance at runtime | 
	Demonstrate how to dynamically add variables to an object (a class instance) at runtime.
This is useful when the methods/variables of an instance are based on a data file that isn't available until runtime. Hal Fulton gives an example of creating an OO CSV parser at An Exercise in Metaprogramming with Ruby. This is referred to as "monkeypatching" by Pythonistas and some others.
 | 
	#Red | 
	Red | 
	person: make object! [
  name: none
  age:  none
]
 
people: reduce [make person [name: "fred" age: 20] make person [name: "paul" age: 21]]
people/1: make people/1 [skill: "fishing"]
 
foreach person people [
  print reduce [person/age "year old" person/name "is good at" any [select person 'skill "nothing"]]
] | 
| 
	http://rosettacode.org/wiki/Add_a_variable_to_a_class_instance_at_runtime | 
	Add a variable to a class instance at runtime | 
	Demonstrate how to dynamically add variables to an object (a class instance) at runtime.
This is useful when the methods/variables of an instance are based on a data file that isn't available until runtime. Hal Fulton gives an example of creating an OO CSV parser at An Exercise in Metaprogramming with Ruby. This is referred to as "monkeypatching" by Pythonistas and some others.
 | 
	#Ring | 
	Ring | 
	o1 = new point
addattribute(o1,"x")
addattribute(o1,"y")
addattribute(o1,"z")
see o1 {x=10 y=20 z=30}
class point | 
| 
	http://rosettacode.org/wiki/Address_of_a_variable | 
	Address of a variable | 
	
Basic Data Operation
This is a basic data operation. It represents a fundamental action on a basic data type.
You may see other such operations in the Basic Data Operations category, or:
Integer Operations
Arithmetic |
Comparison
Boolean Operations
Bitwise |
Logical
String Operations
Concatenation |
Interpolation |
Comparison |
Matching
Memory Operations
Pointers & references |
Addresses
Task
Demonstrate how to get the address of a variable and how to set the address of a variable.
 | 
	#R | 
	R | 
	 
x <- 5
y <- x
pryr::address(x)
pryr::address(y)
 
y <- y + 1
 
pryr::address(x)
pryr::address(y)
  | 
| 
	http://rosettacode.org/wiki/Address_of_a_variable | 
	Address of a variable | 
	
Basic Data Operation
This is a basic data operation. It represents a fundamental action on a basic data type.
You may see other such operations in the Basic Data Operations category, or:
Integer Operations
Arithmetic |
Comparison
Boolean Operations
Bitwise |
Logical
String Operations
Concatenation |
Interpolation |
Comparison |
Matching
Memory Operations
Pointers & references |
Addresses
Task
Demonstrate how to get the address of a variable and how to set the address of a variable.
 | 
	#Racket | 
	Racket | 
	#lang racket
 
(require ffi/unsafe)
 
(define (madness v) ; i'm so sorry
   (cast v _racket _gcpointer)) | 
| 
	http://rosettacode.org/wiki/Address_of_a_variable | 
	Address of a variable | 
	
Basic Data Operation
This is a basic data operation. It represents a fundamental action on a basic data type.
You may see other such operations in the Basic Data Operations category, or:
Integer Operations
Arithmetic |
Comparison
Boolean Operations
Bitwise |
Logical
String Operations
Concatenation |
Interpolation |
Comparison |
Matching
Memory Operations
Pointers & references |
Addresses
Task
Demonstrate how to get the address of a variable and how to set the address of a variable.
 | 
	#Raku | 
	Raku | 
	my $x;
say $x.WHERE;
 
my $y := $x;   # alias
say $y.WHERE;  # same address as $x
 
say "Same variable" if $y =:= $x;
$x = 42;
say $y;  # 42
  | 
| 
	http://rosettacode.org/wiki/AKS_test_for_primes | 
	AKS test for primes | 
	The AKS algorithm for testing whether a number is prime is a polynomial-time algorithm based on an elementary theorem about Pascal triangles.
The theorem on which the test is based can be stated as follows:
   a number   
p
{\displaystyle p}
   is prime   if and only if   all the coefficients of the polynomial expansion of
 
(
x
−
1
)
p
−
(
x
p
−
1
)
{\displaystyle (x-1)^{p}-(x^{p}-1)}
are divisible by   
p
{\displaystyle p}
.
Example
Using   
p
=
3
{\displaystyle p=3}
:
         (x-1)^3 - (x^3 - 1)
            = (x^3 - 3x^2 + 3x - 1) - (x^3 - 1)
            = -3x^2 + 3x
And all the coefficients are divisible by 3,   so 3 is prime.
 Note:
This task is not the AKS primality test.   It is an inefficient exponential time algorithm discovered in the late 1600s and used as an introductory lemma in the AKS derivation.
Task
 Create a function/subroutine/method that given   
p
{\displaystyle p}
   generates the coefficients of the expanded polynomial representation of   
(
x
−
1
)
p
{\displaystyle (x-1)^{p}}
.
 Use the function to show here the polynomial expansions of   
(
x
−
1
)
p
{\displaystyle (x-1)^{p}}
   for   
p
{\displaystyle p}
   in the range   0   to at least   7,   inclusive.
 Use the previous function in creating another function that when given   
p
{\displaystyle p}
   returns whether   
p
{\displaystyle p}
   is prime using the theorem.
 Use your test to generate a list of all primes under   35.
 As a stretch goal,   generate all primes under   50   (needs integers larger than 31-bit).
References
 Agrawal-Kayal-Saxena (AKS) primality test (Wikipedia) 
 Fool-Proof Test for Primes - Numberphile (Video). The accuracy of this video is disputed -- at best it is an oversimplification.
 | 
	#Erlang | 
	Erlang | 
	#! /usr/bin/escript
 
-import(lists, [all/2, seq/2, zip/2]).
 
iterate(F, X) -> fun() -> [X | iterate(F, F(X))] end.
 
take(0, _lazy) -> [];
take(N, Lazy) ->
    [Value | Next] = Lazy(),
    [Value | take(N-1, Next)].
 
 
pascal() -> iterate(fun (Row) -> [1 | sum_adj(Row)] end, [1]).
 
sum_adj([_] = L) -> L;
sum_adj([A, B | _] = Row) -> [A+B | sum_adj(tl(Row))].
 
 
show_binomial(Row) ->
    Degree = length(Row) - 1,
    ["(x - 1)^",  integer_to_list(Degree), " =", binomial_rhs(Row, 1, Degree)].
 
show_x(0) -> "";
show_x(1) -> "x";
show_x(N) -> [$x, $^ | integer_to_list(N)].
 
binomial_rhs([], _, _) -> [];
binomial_rhs([Coef | Coefs], Sgn, Exp) ->
    SignChar = if Sgn > 0 -> $+; true -> $- end,
    [$ , SignChar, $ , integer_to_list(Coef), show_x(Exp) | binomial_rhs(Coefs, -Sgn, Exp-1)].
 
 
primerow(Row, N) -> all(fun (Coef) -> (Coef =:= 1) or (Coef rem N =:= 0) end, Row).
 
main(_) ->
    [io:format("~s~n", [show_binomial(Row)]) || Row <- take(8, pascal())],
    io:format("~nThe primes upto 50: ~p~n",
               [[N || {Row, N} <- zip(tl(tl(take(51, pascal()))), seq(2, 50)),
                      primerow(Row, N)]]).
  | 
| 
	http://rosettacode.org/wiki/Additive_primes | 
	Additive primes | 
	Definitions
In mathematics, additive primes are prime numbers for which the sum of their decimal digits are also primes.
Task
Write a program to determine (and show here) all additive primes less than 500.
Optionally, show the number of additive primes.
Also see
   the OEIS entry:   A046704 additive primes.
   the prime-numbers entry:   additive primes.
   the geeks for geeks entry: additive prime number.
   the prime-numbers fandom: additive primes.
 | 
	#Julia | 
	Julia | 
	using Primes
 
let
    p = primesmask(500)
    println("Additive primes under 500:")
    pcount = 0
    for i in 2:499
        if p[i] && p[sum(digits(i))]
            pcount += 1
            print(lpad(i, 4), pcount % 20 == 0 ? "\n" : "")
        end
    end
    println("\n\n$pcount additive primes found.")
end
  | 
| 
	http://rosettacode.org/wiki/Additive_primes | 
	Additive primes | 
	Definitions
In mathematics, additive primes are prime numbers for which the sum of their decimal digits are also primes.
Task
Write a program to determine (and show here) all additive primes less than 500.
Optionally, show the number of additive primes.
Also see
   the OEIS entry:   A046704 additive primes.
   the prime-numbers entry:   additive primes.
   the geeks for geeks entry: additive prime number.
   the prime-numbers fandom: additive primes.
 | 
	#Kotlin | 
	Kotlin | 
	fun isPrime(n: Int): Boolean {
    if (n <= 3) return n > 1
    if (n % 2 == 0 || n % 3 == 0) return false
    var i = 5
    while (i * i <= n) {
        if (n % i == 0 || n % (i + 2) == 0) return false
        i += 6
    }
    return true
}
 
fun digitSum(n: Int): Int {
    var sum = 0
    var num = n
    while (num > 0) {
        sum += num % 10
        num /= 10
    }
    return sum
}
 
fun main() {
    var additivePrimes = 0
    for (i in 2 until 500) {
        if (isPrime(i) and isPrime(digitSum(i))) {
            additivePrimes++
            print("$i ")
        }
    }
    println("\nFound $additivePrimes additive primes less than 500")
} | 
| 
	http://rosettacode.org/wiki/Additive_primes | 
	Additive primes | 
	Definitions
In mathematics, additive primes are prime numbers for which the sum of their decimal digits are also primes.
Task
Write a program to determine (and show here) all additive primes less than 500.
Optionally, show the number of additive primes.
Also see
   the OEIS entry:   A046704 additive primes.
   the prime-numbers entry:   additive primes.
   the geeks for geeks entry: additive prime number.
   the prime-numbers fandom: additive primes.
 | 
	#Ksh | 
	Ksh | 
	#!/bin/ksh
 
# Prime numbers for which the sum of their decimal digits are also primes
 
#	# Variables:
#
integer MAX_n=500
 
#	# Functions:
#
#	# Function _isprime(n) return 1 for prime, 0 for not prime
#
function _isprime {
	typeset _n ; integer _n=$1
	typeset _i ; integer _i
 
	(( _n < 2 )) && return 0
	for (( _i=2 ; _i*_i<=_n ; _i++ )); do
		(( ! ( _n % _i ) )) && return 0
	done
	return 1
}
 
#	# Function _sumdigits(n) return sum of n's digits
#
function _sumdigits {
	typeset _n ; _n=$1
	typeset _i _sum ; integer _i _sum=0
 
	for ((_i=0; _i<${#_n}; _i++)); do
		(( _sum+=${_n:${_i}:1} ))
	done
	echo ${_sum}
}
 
 ######
# main #
 ######
 
integer i digsum
for ((i=2; i<MAX_n; i++)); do
	_isprime ${i} && (( ! $? )) && continue
 
	digsum=$(_sumdigits ${i})
	_isprime ${digsum} ; (( $? )) && printf "%4d " ${i}
done
print | 
| 
	http://rosettacode.org/wiki/Almost_prime | 
	Almost prime | 
	A   k-Almost-prime   is a natural number   
n
{\displaystyle n}
   that is the product of   
k
{\displaystyle k}
   (possibly identical) primes.
Example
1-almost-primes,   where   
k
=
1
{\displaystyle k=1}
,   are the prime numbers themselves.
2-almost-primes,   where   
k
=
2
{\displaystyle k=2}
,   are the   semiprimes.
Task
Write a function/method/subroutine/... that generates k-almost primes and use it to create a table here of the first ten members of k-Almost primes for   
1
<=
K
<=
5
{\displaystyle 1<=K<=5}
.
Related tasks
   Semiprime
   Category:Prime Numbers
 | 
	#jq | 
	jq | 
	# Recent versions of jq (version > 1.4) have the following definition of "until":
def until(cond; next):
  def _until:
    if cond then . else (next|_until) end;
  _until;
 
# relatively_prime(previous) tests whether the input integer is prime
# relative to the primes in the array "previous":
def relatively_prime(previous):
  . as $in
  | (previous|length) as $plen
  # state: [found, ix]
  |  [false, 0]
  | until( .[0] or .[1] >= $plen;
           [ ($in % previous[.[1]]) == 0, .[1] + 1] )
  | .[0] | not ;
 
# Emit a stream in increasing order of all primes (from 2 onwards)
# that are less than or equal to mx:
def primes(mx):
 
  # The helper function, next, has arity 0 for tail recursion optimization;
  # it expects its input to be the array of previously found primes:
  def next:
     . as $previous
     | ($previous | .[length-1]) as $last
     | if ($last >= mx) then empty
       else ((2 + $last)
       | until( relatively_prime($previous) ; . + 2)) as $nextp
       | if $nextp <= mx
         then $nextp, (( $previous + [$nextp] ) | next)
	 else empty
         end
       end;
  if mx <= 1 then empty
  elif mx == 2 then 2
  else (2, 3, ( [2,3] | next))
  end
;
 
# Return an array of the distinct prime factors of . in increasing order
def prime_factors:
 
  # Return an array of prime factors of . given that "primes"
  # is an array of relevant primes:
  def pf(primes):
    if . <= 1 then []
    else . as $in
    | if ($in | relatively_prime(primes)) then [$in]
      else reduce primes[] as $p
             ([];
              if ($in % $p) != 0 then .
 	      else . + [$p] +  (($in / $p) | pf(primes))
	      end)
      end
      | unique
    end;
 
  if . <= 1 then []
  else . as $in
  | pf( [ primes( (1+$in) | sqrt | floor)  ] )
  end;
 
# Return an array of prime factors of . repeated according to their multiplicities:
def prime_factors_with_multiplicities:
  # Emit p according to the multiplicity of p
  # in the input integer assuming p > 1
  def multiplicity(p):
    if   .  < p     then empty
    elif . == p     then p
    elif (. % p) == 0 then
       ((./p) | recurse( if (. % p) == 0 then (. / p) else empty end) | p)
    else empty
    end;
 
  if . <= 1 then []
  else . as $in
  | prime_factors as $primes
  | if ($in|relatively_prime($primes)) then [$in]
    else reduce $primes[]  as $p
           ([];
            if ($in % $p) == 0 then . + [$in|multiplicity($p)] else . end )
    end
  end; | 
| 
	http://rosettacode.org/wiki/Almost_prime | 
	Almost prime | 
	A   k-Almost-prime   is a natural number   
n
{\displaystyle n}
   that is the product of   
k
{\displaystyle k}
   (possibly identical) primes.
Example
1-almost-primes,   where   
k
=
1
{\displaystyle k=1}
,   are the prime numbers themselves.
2-almost-primes,   where   
k
=
2
{\displaystyle k=2}
,   are the   semiprimes.
Task
Write a function/method/subroutine/... that generates k-almost primes and use it to create a table here of the first ten members of k-Almost primes for   
1
<=
K
<=
5
{\displaystyle 1<=K<=5}
.
Related tasks
   Semiprime
   Category:Prime Numbers
 | 
	#Julia | 
	Julia | 
	using Primes
 
isalmostprime(n::Integer, k::Integer) = sum(values(factor(n))) == k
 
function almostprimes(N::Integer, k::Integer) # return first N almost-k primes
    P = Vector{typeof(k)}(undef,N)
    i = 0; n = 2
    while i < N
        if isalmostprime(n, k) P[i += 1] = n end
        n += 1
    end
    return P
end
 
for k in 1:5
    println("$k-Almost-primes: ", join(almostprimes(10, k), ", "), "...")
end | 
| 
	http://rosettacode.org/wiki/Anagrams | 
	Anagrams | 
	When two or more words are composed of the same characters, but in a different order, they are called anagrams.
Task[edit]
Using the word list at   http://wiki.puzzlers.org/pub/wordlists/unixdict.txt,
find the sets of words that share the same characters that contain the most words in them.
Related tasks
Word plays
Ordered words
Palindrome detection
Semordnilap
Anagrams
Anagrams/Deranged anagrams
Other tasks related to string operations:
Metrics
 Array length
 String length
 Copy a string
 Empty string  (assignment)
Counting
 Word frequency
 Letter frequency
 Jewels and stones
 I before E except after C
 Bioinformatics/base count
 Count occurrences of a substring
 Count how many vowels and consonants occur in a string
Remove/replace
 XXXX redacted
 Conjugate a Latin verb
 Remove vowels from a string
 String interpolation (included)
 Strip block comments
 Strip comments from a string
 Strip a set of characters from a string
 Strip whitespace from a string -- top and tail
 Strip control codes and extended characters from a string
Anagrams/Derangements/shuffling
 Word wheel
 ABC problem
 Sattolo cycle
 Knuth shuffle
 Ordered words
 Superpermutation minimisation
 Textonyms (using a phone text pad)
 Anagrams
 Anagrams/Deranged anagrams
 Permutations/Derangements
Find/Search/Determine
 ABC words
 Odd words
 Word ladder
 Semordnilap
 Word search
 Wordiff  (game)
 String matching
 Tea cup rim text
 Alternade words
 Changeable words
 State name puzzle
 String comparison
 Unique characters
 Unique characters in each string
 Extract file extension
 Levenshtein distance
 Palindrome detection
 Common list elements
 Longest common suffix
 Longest common prefix
 Compare a list of strings 
 Longest common substring
 Find common directory path
 Words from neighbour ones
 Change e letters to i in words
 Non-continuous subsequences
 Longest common subsequence
 Longest palindromic substrings
 Longest increasing subsequence
 Words containing "the" substring
 Sum of the digits of n is substring of n
 Determine if a string is numeric
 Determine if a string is collapsible
 Determine if a string is squeezable
 Determine if a string has all unique characters
 Determine if a string has all the same characters
 Longest substrings without repeating characters
 Find words which contains all the vowels
 Find words which contains most consonants
 Find words which contains more than 3 vowels
 Find words which first and last three letters are equals
 Find words which odd letters are consonants and even letters are vowels or vice_versa
Formatting
 Substring
 Rep-string
 Word wrap
 String case
 Align columns
 Literals/String
 Repeat a string
 Brace expansion
 Brace expansion using ranges
 Reverse a string
 Phrase reversals
 Comma quibbling
 Special characters
 String concatenation
 Substring/Top and tail
 Commatizing numbers
 Reverse words in a string
 Suffixation of decimal numbers
 Long literals, with continuations 
 Numerical and alphabetical suffixes
 Abbreviations, easy
 Abbreviations, simple
 Abbreviations, automatic
Song lyrics/poems/Mad Libs/phrases
 Mad Libs
 Magic 8-ball
 99 Bottles of Beer
 The Name Game (a song)
 The Old lady swallowed a fly
 The Twelve Days of Christmas
Tokenize
 Text between
 Tokenize a string
 Word break problem
 Tokenize a string with escaping
 Split a character string based on change of character
Sequences
 Show ASCII table
 De Bruijn sequences
 Self-referential sequences
 Generate lower case ASCII alphabet
 | 
	#EchoLisp | 
	EchoLisp | 
	 
(require 'struct)
(require 'hash)
(require 'sql)
(require 'words)
(require 'dico.fr.no-accent)
 
 
(define mots-français (words-select #:any null 999999))
(string-delimiter "")
 
(define (string-sort str)
	(list->string (list-sort string<?  (string->list str))))
 
(define (ana-sort H words) ;; bump counter for each word
	(for ((w words))
		#:continue (< (string-length w) 4)
		(let [(key (string-sort w))]  (hash-set H key (1+ (hash-ref! H key 0))))))
 
;; input w word
;; output : list of matching words
(define (anagrams w words)
	(set! w (string-sort w))
	(make-set
	(for/list (( ana words))
		#:when (string=? w (string-sort ana))
		ana)))
 
(define (task words)
(define H (make-hash))
	(ana-sort H words) ;; build counters key= sorted-string, value = count
	(hash-get-keys H   ;; extract max count values
	    (for/fold (hmax 0) ((h H) ) 
	    #:when (>= (cdr h) hmax)
	    (cdr h))
	))
  | 
| 
	http://rosettacode.org/wiki/Angle_difference_between_two_bearings | 
	Angle difference between two bearings | 
	Finding the angle between two bearings is often confusing.[1]
Task
Find the angle which is the result of the subtraction b2 - b1, where b1 and b2 are the bearings.
Input bearings are expressed in the range   -180   to   +180   degrees.
The  result  is also expressed in the range   -180   to   +180   degrees.
Compute the angle for the following pairs:
 20 degrees (b1) and 45 degrees (b2)
 -45 and 45
 -85 and 90
 -95 and 90
 -45 and 125
 -45 and 145
 29.4803 and -88.6381
 -78.3251 and -159.036
Optional extra
 
Allow the input bearings to be any (finite) value.
Test cases
 -70099.74233810938 and 29840.67437876723
 -165313.6666297357 and 33693.9894517456
 1174.8380510598456 and -154146.66490124757
 60175.77306795546 and 42213.07192354373
 | 
	#Raku | 
	Raku | 
	sub infix:<∠> (Real $b1, Real $b2) {
   (my $b = ($b2 - $b1 + 720) % 360) > 180 ?? $b - 360 !! $b;
}
 
for 20, 45,
   -45, 45,
   -85, 90,
   -95, 90,
   -45, 125,
   -45, 145,
   29.4803, -88.6381,
   -78.3251, -159.036,
   -70099.74233810938, 29840.67437876723,
   -165313.6666297357, 33693.9894517456,
   1174.8380510598456, -154146.66490124757,
   60175.77306795546, 42213.07192354373
 
  -> $b1, $b2 { printf "%10.2f %10.2f = %8.2f\n", $b1, $b2, $b1 ∠ $b2 } | 
| 
	http://rosettacode.org/wiki/Anagrams/Deranged_anagrams | 
	Anagrams/Deranged anagrams | 
	Two or more words are said to be anagrams if they have the same characters, but in a different order.
By analogy with derangements we define a deranged anagram as two words with the same characters, but in which the same character does not appear in the same position in both words.
Task[edit]
Use the word list at unixdict to find and display the longest deranged anagram.
Related tasks
 Permutations/Derangements
 Best shuffle
Word plays
Ordered words
Palindrome detection
Semordnilap
Anagrams
Anagrams/Deranged anagrams
Other tasks related to string operations:
Metrics
 Array length
 String length
 Copy a string
 Empty string  (assignment)
Counting
 Word frequency
 Letter frequency
 Jewels and stones
 I before E except after C
 Bioinformatics/base count
 Count occurrences of a substring
 Count how many vowels and consonants occur in a string
Remove/replace
 XXXX redacted
 Conjugate a Latin verb
 Remove vowels from a string
 String interpolation (included)
 Strip block comments
 Strip comments from a string
 Strip a set of characters from a string
 Strip whitespace from a string -- top and tail
 Strip control codes and extended characters from a string
Anagrams/Derangements/shuffling
 Word wheel
 ABC problem
 Sattolo cycle
 Knuth shuffle
 Ordered words
 Superpermutation minimisation
 Textonyms (using a phone text pad)
 Anagrams
 Anagrams/Deranged anagrams
 Permutations/Derangements
Find/Search/Determine
 ABC words
 Odd words
 Word ladder
 Semordnilap
 Word search
 Wordiff  (game)
 String matching
 Tea cup rim text
 Alternade words
 Changeable words
 State name puzzle
 String comparison
 Unique characters
 Unique characters in each string
 Extract file extension
 Levenshtein distance
 Palindrome detection
 Common list elements
 Longest common suffix
 Longest common prefix
 Compare a list of strings 
 Longest common substring
 Find common directory path
 Words from neighbour ones
 Change e letters to i in words
 Non-continuous subsequences
 Longest common subsequence
 Longest palindromic substrings
 Longest increasing subsequence
 Words containing "the" substring
 Sum of the digits of n is substring of n
 Determine if a string is numeric
 Determine if a string is collapsible
 Determine if a string is squeezable
 Determine if a string has all unique characters
 Determine if a string has all the same characters
 Longest substrings without repeating characters
 Find words which contains all the vowels
 Find words which contains most consonants
 Find words which contains more than 3 vowels
 Find words which first and last three letters are equals
 Find words which odd letters are consonants and even letters are vowels or vice_versa
Formatting
 Substring
 Rep-string
 Word wrap
 String case
 Align columns
 Literals/String
 Repeat a string
 Brace expansion
 Brace expansion using ranges
 Reverse a string
 Phrase reversals
 Comma quibbling
 Special characters
 String concatenation
 Substring/Top and tail
 Commatizing numbers
 Reverse words in a string
 Suffixation of decimal numbers
 Long literals, with continuations 
 Numerical and alphabetical suffixes
 Abbreviations, easy
 Abbreviations, simple
 Abbreviations, automatic
Song lyrics/poems/Mad Libs/phrases
 Mad Libs
 Magic 8-ball
 99 Bottles of Beer
 The Name Game (a song)
 The Old lady swallowed a fly
 The Twelve Days of Christmas
Tokenize
 Text between
 Tokenize a string
 Word break problem
 Tokenize a string with escaping
 Split a character string based on change of character
Sequences
 Show ASCII table
 De Bruijn sequences
 Self-referential sequences
 Generate lower case ASCII alphabet
 | 
	#Ruby | 
	Ruby | 
	def deranged?(a, b)
  a.chars.zip(b.chars).all? {|char_a, char_b| char_a != char_b}
end
 
def find_derangements(list)
  list.combination(2) {|a,b| return a,b  if deranged?(a,b)}
  nil
end
 
require 'open-uri'
anagram = open('http://www.puzzlers.org/pub/wordlists/unixdict.txt') do |f|
  f.read.split.group_by {|s| s.each_char.sort}
end
 
anagram = anagram.select{|k,list| list.size>1}.sort_by{|k,list| -k.size}
 
anagram.each do |k,list|
  if derangements = find_derangements(list)
    puts "Longest derangement anagram: #{derangements}"
    break
  end
end | 
| 
	http://rosettacode.org/wiki/Anonymous_recursion | 
	Anonymous recursion | 
	While implementing a recursive function, it often happens that we must resort to a separate   helper function   to handle the actual recursion.
This is usually the case when directly calling the current function would waste too many resources (stack space, execution time), causing unwanted side-effects,   and/or the function doesn't have the right arguments and/or return values.
So we end up inventing some silly name like   foo2   or   foo_helper.   I have always found it painful to come up with a proper name, and see some disadvantages:
   You have to think up a name, which then pollutes the namespace
   Function is created which is called from nowhere else
   The program flow in the source code is interrupted
Some languages allow you to embed recursion directly in-place.   This might work via a label, a local gosub instruction, or some special keyword.
Anonymous recursion can also be accomplished using the   Y combinator.
Task
If possible, demonstrate this by writing the recursive version of the fibonacci function   (see Fibonacci sequence)   which checks for a negative argument before doing the actual recursion.
 | 
	#Perl | 
	Perl | 
	sub recur (&@) {
    my $f = shift;
    local *recurse = $f;
    $f->(@_);
}
 
sub fibo {
    my $n = shift;
    $n < 0 and die 'Negative argument';
    recur {
        my $m = shift;
        $m < 3 ? 1 : recurse($m - 1) + recurse($m - 2);
    } $n;
} | 
| 
	http://rosettacode.org/wiki/Amicable_pairs | 
	Amicable pairs | 
	Two integers 
N
{\displaystyle N}
 and 
M
{\displaystyle M}
 are said to be amicable pairs if 
N
≠
M
{\displaystyle N\neq M}
 and the sum of the proper divisors of 
N
{\displaystyle N}
 (
s
u
m
(
p
r
o
p
D
i
v
s
(
N
)
)
{\displaystyle \mathrm {sum} (\mathrm {propDivs} (N))}
) 
=
M
{\displaystyle =M}
 as well as 
s
u
m
(
p
r
o
p
D
i
v
s
(
M
)
)
=
N
{\displaystyle \mathrm {sum} (\mathrm {propDivs} (M))=N}
.
Example
1184 and 1210 are an amicable pair, with proper divisors:
   1, 2, 4, 8, 16, 32, 37, 74, 148, 296, 592   and 
   1, 2, 5, 10, 11, 22, 55, 110, 121, 242, 605   respectively.
Task
Calculate and show here the Amicable pairs below 20,000; (there are eight).
Related tasks
 Proper divisors
 Abundant, deficient and perfect number classifications
 Aliquot sequence classifications and its amicable classification. 
 | 
	#PARI.2FGP | 
	PARI/GP | 
	for(x=1,20000,my(y=sigma(x)-x); if(y>x && x == sigma(y)-y,print(x" "y))) | 
| 
	http://rosettacode.org/wiki/Animate_a_pendulum | 
	Animate a pendulum | 
	
One good way of making an animation is by simulating a physical system and illustrating the variables in that system using a dynamically changing graphical display.
The classic such physical system is a simple gravity pendulum.
Task
Create a simple physical model of a pendulum and animate it.
 | 
	#Racket | 
	Racket | 
	 
#lang racket
 
(require 2htdp/image 2htdp/universe)
 
(define (pendulum)
  (define (accel θ) (- (sin θ)))
  (define θ (/ pi 2.5))
  (define θ′ 0)
  (define θ′′ (accel (/ pi 2.5)))
  (define (x θ) (+ 200 (* 150 (sin θ))))
  (define (y θ) (* 150 (cos θ)))
  (λ (n)
    (define p-image (underlay/xy (add-line (empty-scene 400 200) 200 0 (x θ) (y θ) "black") 
                                 (- (x θ) 5) (- (y θ) 5) (circle 5 "solid" "blue")))
    (set! θ (+ θ (* θ′ 0.04)))
    (set! θ′ (+ θ′ (* (accel θ) 0.04)))
    p-image))
 
(animate (pendulum))
  | 
| 
	http://rosettacode.org/wiki/Amb | 
	Amb | 
	Define and give an example of the Amb operator.
The Amb operator (short for "ambiguous") expresses nondeterminism. This doesn't refer to randomness (as in "nondeterministic universe") but is closely related to the term as it is used in automata theory ("non-deterministic finite automaton").
The Amb operator takes a variable number of expressions (or values if that's simpler in the language) and yields a correct one which will satisfy a constraint in some future computation, thereby avoiding failure.
Problems whose solution the Amb operator naturally expresses can be approached with other tools, such as explicit nested iterations over data sets, or with pattern matching. By contrast, the Amb operator appears integrated into the language. Invocations of Amb are not wrapped in any visible loops or other search patterns; they appear to be independent.
Essentially Amb(x, y, z) splits the computation into three possible futures: a future in which the value x is yielded, a future in which the value y is yielded and a future in which the value z is yielded. The future which leads to a successful subsequent computation is chosen. The other "parallel universes" somehow go away. Amb called with no arguments fails.
For simplicity, one of the domain values usable with Amb may denote failure, if that is convenient. For instance, it is convenient if a Boolean false denotes failure, so that Amb(false) fails, and thus constraints can be expressed using Boolean expressions like Amb(x * y == 8) which unless x and y add to four.
A pseudo-code program which satisfies this constraint might look like:
let x = Amb(1, 2, 3)
let y = Amb(7, 6, 4, 5)
Amb(x * y = 8)
print x, y
The output is 2 4 because Amb(1, 2, 3) correctly chooses the future in which x has value 2, Amb(7, 6, 4, 5) chooses 4 and consequently Amb(x * y = 8) produces a success.
Alternatively, failure could be represented using strictly Amb():
unless x * y = 8 do Amb()
Or else Amb could take the form of two operators or functions: one for producing values and one for enforcing constraints:
let x = Ambsel(1, 2, 3)
let y = Ambsel(4, 5, 6)
Ambassert(x * y = 8)
print x, y
where Ambassert behaves like Amb() if the Boolean expression is false, otherwise it allows the future computation to take place, without yielding any value.
The task is to somehow implement Amb, and demonstrate it with a program which chooses one word from each of the following four sets of character strings to generate a four-word sentence:
"the" "that" "a"
"frog" "elephant" "thing"
"walked" "treaded" "grows"
"slowly" "quickly"
The constraint to be satisfied is that the last character of each word (other than the last) is the same as the first character of its successor.
The only successful sentence is "that thing grows slowly"; other combinations do not satisfy the constraint and thus fail.
The goal of this task isn't to simply process the four lists of words with explicit, deterministic program flow such as nested iteration, to trivially demonstrate the correct output. The goal is to implement the Amb operator, or a facsimile thereof that is possible within the language limitations.
 | 
	#jq | 
	jq | 
	def amb: .[];
 
def joins:
  (.[0][-1:]) as $left
  | (.[1][0:1]) as $right
  | if $left == $right then true else empty end;
  | 
| 
	http://rosettacode.org/wiki/Accumulator_factory | 
	Accumulator factory | 
	A problem posed by Paul Graham is that of creating a function that takes a single (numeric) argument and which returns another function that is an accumulator. The returned accumulator function in turn also takes a single numeric argument, and returns the sum of all the numeric values passed in so far to that accumulator (including the initial value passed when the accumulator was created).
Rules
The detailed rules are at http://paulgraham.com/accgensub.html and are reproduced here for simplicity (with additions in small italic text).
Before you submit an example, make sure the function
 Takes a number n and returns a function (lets call it g), that takes a number i, and returns n incremented by the accumulation of i from every call of function g(i).
Although these exact function and parameter names need not be used
 Works for any numeric type-- i.e. can take both ints and floats and returns functions that can take both ints and floats. (It is not enough simply to convert all input to floats. An accumulator that has only seen integers must return integers.) (i.e., if the language doesn't allow for numeric polymorphism, you have to use overloading or something like that)
 Generates functions that return the sum of every number ever passed to them, not just the most recent. (This requires a piece of state to hold the accumulated value, which in turn means that pure functional languages can't be used for this task.)
 Returns a real function, meaning something that you can use wherever you could use a function you had defined in the ordinary way in the text of your program. (Follow your language's conventions here.)
 Doesn't store the accumulated value or the returned functions in a way that could cause them to be inadvertently modified by other code. (No global variables or other such things.)
 E.g. if after the example, you added the following code (in a made-up language) where the factory function is called foo:
 x = foo(1); 
x(5); 
foo(3);
print x(2.3);
 It should print 8.3. (There is no need to print the form of the accumulator function returned by foo(3); it's not part of the task at all.)
Task
Create a function that implements the described rules.
It need not handle any special error cases not described above. The simplest way to implement the task as described is typically to use a closure, providing the language supports them.
Where it is not possible to hold exactly to the constraints above, describe the deviations.
 | 
	#Ceylon | 
	Ceylon | 
	shared void run() {
    Integer|Float accumulator
            (variable Integer|Float n)
            (Integer|Float i)
        =>  switch (i)
            case (is Integer)
                (n = n.plusInteger(i))
            case (is Float)
                (n = i + (switch(prev = n)
                          case (is Float) prev
                          case (is Integer) prev.float));
 
    value x = accumulator(1);
    print(x(5));
    print(accumulator(3));
    print(x(2.3));
} | 
| 
	http://rosettacode.org/wiki/Accumulator_factory | 
	Accumulator factory | 
	A problem posed by Paul Graham is that of creating a function that takes a single (numeric) argument and which returns another function that is an accumulator. The returned accumulator function in turn also takes a single numeric argument, and returns the sum of all the numeric values passed in so far to that accumulator (including the initial value passed when the accumulator was created).
Rules
The detailed rules are at http://paulgraham.com/accgensub.html and are reproduced here for simplicity (with additions in small italic text).
Before you submit an example, make sure the function
 Takes a number n and returns a function (lets call it g), that takes a number i, and returns n incremented by the accumulation of i from every call of function g(i).
Although these exact function and parameter names need not be used
 Works for any numeric type-- i.e. can take both ints and floats and returns functions that can take both ints and floats. (It is not enough simply to convert all input to floats. An accumulator that has only seen integers must return integers.) (i.e., if the language doesn't allow for numeric polymorphism, you have to use overloading or something like that)
 Generates functions that return the sum of every number ever passed to them, not just the most recent. (This requires a piece of state to hold the accumulated value, which in turn means that pure functional languages can't be used for this task.)
 Returns a real function, meaning something that you can use wherever you could use a function you had defined in the ordinary way in the text of your program. (Follow your language's conventions here.)
 Doesn't store the accumulated value or the returned functions in a way that could cause them to be inadvertently modified by other code. (No global variables or other such things.)
 E.g. if after the example, you added the following code (in a made-up language) where the factory function is called foo:
 x = foo(1); 
x(5); 
foo(3);
print x(2.3);
 It should print 8.3. (There is no need to print the form of the accumulator function returned by foo(3); it's not part of the task at all.)
Task
Create a function that implements the described rules.
It need not handle any special error cases not described above. The simplest way to implement the task as described is typically to use a closure, providing the language supports them.
Where it is not possible to hold exactly to the constraints above, describe the deviations.
 | 
	#Clay | 
	Clay | 
	acc(n) {
    return (m) => {
        n = n + m;
        return n;
    };
}
 
main() {
    var x = acc(1.0);
    x(5);
    acc(3);
    println(x(2.3)); // Prints “8.300000000000001”.
} | 
| 
	http://rosettacode.org/wiki/Ackermann_function | 
	Ackermann function | 
	The Ackermann function is a classic example of a recursive function, notable especially because it is not a primitive recursive function. It grows very quickly in value, as does the size of its call tree.
The Ackermann function is usually defined as follows:
A
(
m
,
n
)
=
{
n
+
1
if 
m
=
0
A
(
m
−
1
,
1
)
if 
m
>
0
 and 
n
=
0
A
(
m
−
1
,
A
(
m
,
n
−
1
)
)
if 
m
>
0
 and 
n
>
0.
{\displaystyle A(m,n)={\begin{cases}n+1&{\mbox{if }}m=0\\A(m-1,1)&{\mbox{if }}m>0{\mbox{ and }}n=0\\A(m-1,A(m,n-1))&{\mbox{if }}m>0{\mbox{ and }}n>0.\end{cases}}}
Its arguments are never negative and it always terminates.
Task
Write a function which returns the value of 
A
(
m
,
n
)
{\displaystyle A(m,n)}
. Arbitrary precision is preferred (since the function grows so quickly), but not required.
See also
 Conway chained arrow notation for the Ackermann function.
 | 
	#8080_Assembly | 
	8080 Assembly | 
		org	100h
	jmp	demo
	;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;
	;;;	ACK(M,N); DE=M, HL=N, return value in HL.
ack:	mov	a,d	; M=0?
	ora	e
	jnz	ackm
	inx	h	; If so, N+1.
	ret
ackm:	mov	a,h	; N=0?
	ora	l
	jnz	ackmn
	lxi	h,1	; If so, N=1,
	dcx	d	; N-=1,
	jmp	ack	; A(M,N) - tail recursion
ackmn:	push	d	; M>0 and N>0: store M on the stack
	dcx	h	; N-=1
	call	ack	; N = ACK(M,N-1)
	pop	d	; Restore previous M
	dcx	d	; M-=1
	jmp	ack	; A(M,N) - tail recursion
	;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;
	;;;	Print table of ack(m,n)
MMAX:	equ	4	; Size of table to print. Note that math is done in
NMAX:	equ	9	; 16 bits. 
demo:	lhld	6	; Put stack pointer at top of available memory
	sphl
	lxi	b,0	; let B,C hold 8-bit M and N.
acknum:	xra	a	; Set high bit of M and N to zero
	mov	d,a	; DE = B (M)
	mov	e,b
	mov	h,a	; HL = C (N)
	mov	l,c
	call	ack	; HL = ack(DE,HL)
	call	prhl	; Print the number
	inr	c	; N += 1
	mvi	a,NMAX	; Time for next line?
	cmp	c
	jnz	acknum	; If not, print next number
	push	b	; Otherwise, save BC
	mvi	c,9	; Print newline
	lxi	d,nl
	call	5
	pop	b	; Restore BC
	mvi	c,0	; Set N to 0
	inr	b	; M += 1
	mvi	a,MMAX	; Time to stop?
	cmp	b
	jnz	acknum	; If not, print next number
	rst	0
	;;;	Print HL as ASCII number.
prhl:	push	h	; Save all registers
	push	d
	push	b
	lxi	b,pnum	; Store pointer to num string on stack
	push	b
	lxi	b,-10	; Divisor
prdgt:	lxi	d,-1
prdgtl:	inx	d	; Divide by 10 through trial subtraction
	dad	b
	jc	prdgtl
	mvi	a,'0'+10
	add	l	; L = remainder - 10
	pop	h	; Get pointer from stack
	dcx	h	; Store digit
	mov	m,a
	push	h	; Put pointer back on stack
	xchg		; Put quotient in HL
	mov	a,h	; Check if zero 
	ora	l
	jnz	prdgt	; If not, next digit
	pop	d	; Get pointer and put in DE
	mvi	c,9	; CP/M print string
	call	5
	pop	b	; Restore registers 
	pop	d
	pop	h
	ret
	db	'*****'	; Placeholder for number
pnum:	db	9,'$'
nl:	db	13,10,'$' | 
| 
	http://rosettacode.org/wiki/Abundant,_deficient_and_perfect_number_classifications | 
	Abundant, deficient and perfect number classifications | 
	These define three classifications of positive integers based on their   proper divisors.
Let   P(n)   be the sum of the proper divisors of   n   where the proper divisors are all positive divisors of   n   other than   n   itself.
   if    P(n) <  n    then  n  is classed as  deficient  (OEIS A005100).
   if    P(n) == n    then  n  is classed as  perfect    (OEIS A000396).
   if    P(n) >  n    then  n  is classed as  abundant   (OEIS A005101).
Example
6   has proper divisors of   1,   2,   and   3.
1 + 2 + 3 = 6,   so   6   is classed as a perfect number.
Task
Calculate how many of the integers   1   to   20,000   (inclusive) are in each of the three classes.
Show the results here.
Related tasks
   Aliquot sequence classifications.   (The whole series from which this task is a subset.)
   Proper divisors
   Amicable pairs
 | 
	#ALGOL_68 | 
	ALGOL 68 | 
	BEGIN # classify the numbers 1 : 20 000 as abudant, deficient or perfect #
    INT abundant count    := 0;
    INT deficient count   := 0;
    INT perfect count     := 0;
    INT abundant example  := 0;
    INT deficient example := 0;
    INT perfect example   := 0;
    INT max number         = 20 000;
    # construct a table of the proper divisor sums                 #
    [ 1 : max number ]INT pds;
    pds[ 1 ] := 0;
    FOR i FROM 2 TO UPB pds DO pds[ i ] := 1 OD;
    FOR i FROM 2 TO UPB pds DO
        FOR j FROM i + i BY i TO UPB pds DO pds[ j ] +:= i OD
    OD;
    # classify the numbers                                         #
    FOR n TO max number DO
        IF     INT pd sum = pds[ n ];
               pd sum < n
        THEN
            # have a deficient number                              #
            deficient count    +:= 1;
            deficient example   := n
        ELIF   pd sum = n
        THEN
            # have a perfect number                                #
            perfect count      +:= 1;
            perfect example     := n
        ELSE # pd sum > n #
            # have an abundant number                              #
            abundant count     +:= 1;
            abundant example    := n
        FI
    OD;
    # displays the classification, count and example                   #
    PROC show result = ( STRING classification, INT count, example )VOID:
         print( ( "There are "
                , whole( count, -8 )
                , " "
                , classification
                , " numbers up to "
                , whole( max number, 0 )
                , " e.g.: "
                , whole( example, 0 )
                , newline
                )
              );
 
    # show how many of each type of number there are and an example    #
    show result( "abundant ",  abundant count,  abundant example  );
    show result( "deficient", deficient count, deficient example );
    show result( "perfect  ",   perfect count,   perfect example   )
END | 
| 
	http://rosettacode.org/wiki/Align_columns | 
	Align columns | 
	Given a text file of many lines, where fields within a line
are delineated by a single 'dollar' character, write a program
that aligns each column of fields by ensuring that words in each
column are separated by at least one space.
Further, allow for each word in a column to be either left
justified, right justified, or center justified within its column.
Use the following text to test your programs:
Given$a$text$file$of$many$lines,$where$fields$within$a$line$
are$delineated$by$a$single$'dollar'$character,$write$a$program
that$aligns$each$column$of$fields$by$ensuring$that$words$in$each$
column$are$separated$by$at$least$one$space.
Further,$allow$for$each$word$in$a$column$to$be$either$left$
justified,$right$justified,$or$center$justified$within$its$column.
Note that:
   The example input texts lines may, or may not, have trailing dollar characters.
   All columns should share the same alignment.
   Consecutive space characters produced adjacent to the end of lines are insignificant for the purposes of the task.
   Output text will be viewed in a mono-spaced font on a plain text editor or basic terminal.
   The minimum space between columns should be computed from the text and not hard-coded.
   It is not a requirement to add separating characters between or around columns.
Other tasks related to string operations:
Metrics
 Array length
 String length
 Copy a string
 Empty string  (assignment)
Counting
 Word frequency
 Letter frequency
 Jewels and stones
 I before E except after C
 Bioinformatics/base count
 Count occurrences of a substring
 Count how many vowels and consonants occur in a string
Remove/replace
 XXXX redacted
 Conjugate a Latin verb
 Remove vowels from a string
 String interpolation (included)
 Strip block comments
 Strip comments from a string
 Strip a set of characters from a string
 Strip whitespace from a string -- top and tail
 Strip control codes and extended characters from a string
Anagrams/Derangements/shuffling
 Word wheel
 ABC problem
 Sattolo cycle
 Knuth shuffle
 Ordered words
 Superpermutation minimisation
 Textonyms (using a phone text pad)
 Anagrams
 Anagrams/Deranged anagrams
 Permutations/Derangements
Find/Search/Determine
 ABC words
 Odd words
 Word ladder
 Semordnilap
 Word search
 Wordiff  (game)
 String matching
 Tea cup rim text
 Alternade words
 Changeable words
 State name puzzle
 String comparison
 Unique characters
 Unique characters in each string
 Extract file extension
 Levenshtein distance
 Palindrome detection
 Common list elements
 Longest common suffix
 Longest common prefix
 Compare a list of strings 
 Longest common substring
 Find common directory path
 Words from neighbour ones
 Change e letters to i in words
 Non-continuous subsequences
 Longest common subsequence
 Longest palindromic substrings
 Longest increasing subsequence
 Words containing "the" substring
 Sum of the digits of n is substring of n
 Determine if a string is numeric
 Determine if a string is collapsible
 Determine if a string is squeezable
 Determine if a string has all unique characters
 Determine if a string has all the same characters
 Longest substrings without repeating characters
 Find words which contains all the vowels
 Find words which contains most consonants
 Find words which contains more than 3 vowels
 Find words which first and last three letters are equals
 Find words which odd letters are consonants and even letters are vowels or vice_versa
Formatting
 Substring
 Rep-string
 Word wrap
 String case
 Align columns
 Literals/String
 Repeat a string
 Brace expansion
 Brace expansion using ranges
 Reverse a string
 Phrase reversals
 Comma quibbling
 Special characters
 String concatenation
 Substring/Top and tail
 Commatizing numbers
 Reverse words in a string
 Suffixation of decimal numbers
 Long literals, with continuations 
 Numerical and alphabetical suffixes
 Abbreviations, easy
 Abbreviations, simple
 Abbreviations, automatic
Song lyrics/poems/Mad Libs/phrases
 Mad Libs
 Magic 8-ball
 99 Bottles of Beer
 The Name Game (a song)
 The Old lady swallowed a fly
 The Twelve Days of Christmas
Tokenize
 Text between
 Tokenize a string
 Word break problem
 Tokenize a string with escaping
 Split a character string based on change of character
Sequences
 Show ASCII table
 De Bruijn sequences
 Self-referential sequences
 Generate lower case ASCII alphabet
 | 
	#Arturo | 
	Arturo | 
	text: {
    Given$a$text$file$of$many$lines,$where$fields$within$a$line$
    are$delineated$by$a$single$'dollar'$character,$write$a$program
    that$aligns$each$column$of$fields$by$ensuring$that$words$in$each$
    column$are$separated$by$at$least$one$space.
    Further,$allow$for$each$word$in$a$column$to$be$either$left$
    justified,$right$justified,$or$center$justified$within$its$column.
}
 
output: map split.lines text => [split.by:"$"]
 
loop output 'line [
    loop line 'word -> prints pad word 12
    print ""
] | 
| 
	http://rosettacode.org/wiki/Active_object | 
	Active object | 
	In object-oriented programming an object is active when its state depends on clock. Usually an active object encapsulates a task that updates the object's state. To the outer world the object looks like a normal object with methods that can be called from outside. Implementation of such methods must have a certain synchronization mechanism with the encapsulated task in order to prevent object's state corruption.
A typical instance of an active object is an animation widget. The widget state changes with the time, while as an object it has all properties of a normal widget.
The task
Implement an active integrator object. The object has an input and output. The input can be set using the method Input. The input is a function of time. The output can be queried using the method Output. The object integrates its input over the time and the result becomes the object's output. So if the input is K(t) and the output is S, the object state S is changed to S + (K(t1) + K(t0)) * (t1 - t0) / 2, i.e. it integrates K using the trapeze method. Initially K is constant 0 and S is 0.
In order to test the object:
 set its input to sin (2π f t), where the frequency f=0.5Hz. The phase is irrelevant.
 wait 2s
 set the input to constant 0
 wait 0.5s
Verify that now the object's output is approximately 0 (the sine has the period of 2s). The accuracy of the result will depend on the OS scheduler time slicing and the accuracy of the clock.
 | 
	#F.23 | 
	F# | 
	open System
open System.Threading
 
// current time in seconds
let now() = float( DateTime.Now.Ticks / 10000L ) / 1000.0
 
type Integrator( intervalMs ) as x =
  let mutable k = fun _ -> 0.0  // function to integrate
  let mutable s = 0.0           // current value
  let mutable t0 = now()        // last time s was updated
  let mutable running = true    // still running?
 
  do x.ScheduleNextUpdate()
 
  member x.Input(f) = k <- f
 
  member x.Output() = s
 
  member x.Stop() = running <- false
 
  member private x.Update() =
    let t1 = now()
    s <- s + (k t0 + k t1) * (t1 - t0) / 2.0
    t0 <- t1
    x.ScheduleNextUpdate()
 
  member private x.ScheduleNextUpdate() =
    if running then
      async { do! Async.Sleep( intervalMs )
              x.Update()
            }
      |> Async.Start
 
let i = new Integrator(10)
 
i.Input( fun t -> Math.Sin (2.0 * Math.PI * 0.5 * t) )
Thread.Sleep(2000)
 
i.Input( fun _ -> 0.0 )
Thread.Sleep(500)
 
printfn "%f" (i.Output())
i.Stop() | 
| 
	http://rosettacode.org/wiki/Aliquot_sequence_classifications | 
	Aliquot sequence classifications | 
	An aliquot sequence of a positive integer K is defined recursively as the first member
being K and subsequent members being the sum of the Proper divisors of the previous term.
 If the terms eventually reach 0 then the series for K is said to terminate.
There are several classifications for non termination:
 If the second term is K then all future terms are also K and so the sequence repeats from the first term with period 1 and K is called perfect.
 If the third term would be repeating K then the sequence repeats with period 2 and K is called amicable.
 If the Nth term would be repeating K for the first time, with N > 3 then the sequence repeats with period N - 1 and K is called sociable.
Perfect, amicable and sociable numbers eventually repeat the original number K; there are other repetitions...
 Some K have a sequence that eventually forms a periodic repetition of period 1 but of a number other than K, for example 95 which forms the sequence 95, 25, 6, 6, 6, ... such K are called aspiring.
 K that have a sequence that eventually forms a periodic repetition of period >= 2 but of a number other than K, for example 562 which forms the sequence 562, 284, 220, 284, 220, ... such K are called cyclic.
And finally:
 Some K form aliquot sequences that are not known to be either terminating or periodic; these K are to be called non-terminating. 
For the purposes of this task, K is to be classed as non-terminating if it has not been otherwise classed after generating 16 terms or if any term of the sequence is greater than 2**47 = 140,737,488,355,328. 
Task
 Create routine(s) to generate the aliquot sequence of a positive integer enough to classify it according to the classifications given above.
 Use it to display the classification and sequences of the numbers one to ten inclusive.
 Use it to show the classification and sequences of the following integers, in order:
 11, 12, 28, 496, 220, 1184, 12496, 1264460, 790, 909, 562, 1064, 1488, and optionally 15355717786080.
Show all output on this page.
Related tasks
   Abundant, deficient and perfect number classifications. (Classifications from only the first two members of the whole sequence).
   Proper divisors
   Amicable pairs
 | 
	#Julia | 
	Julia | 
	 
function aliquotclassifier{T<:Integer}(n::T)
    a = T[n]
    b = divisorsum(a[end])
    len = 1
    while len < 17 && !(b in a) && 0 < b && b < 2^47+1
        push!(a, b)
        b = divisorsum(a[end])
        len += 1
    end
    if b in a
        1 < len || return ("Perfect", a)
        if b == a[1]
            2 < len || return ("Amicable", a)
            return ("Sociable", a)
        elseif b == a[end]
            return ("Aspiring", a)
        else
            return ("Cyclic", push!(a, b))
        end
    end
    push!(a, b)
    b != 0 || return ("Terminating", a)
    return ("Non-terminating", a)
end
  | 
| 
	http://rosettacode.org/wiki/Add_a_variable_to_a_class_instance_at_runtime | 
	Add a variable to a class instance at runtime | 
	Demonstrate how to dynamically add variables to an object (a class instance) at runtime.
This is useful when the methods/variables of an instance are based on a data file that isn't available until runtime. Hal Fulton gives an example of creating an OO CSV parser at An Exercise in Metaprogramming with Ruby. This is referred to as "monkeypatching" by Pythonistas and some others.
 | 
	#Ruby | 
	Ruby | 
	class Empty
end
 
e = Empty.new
class << e
  attr_accessor :foo
end
e.foo = 1
puts e.foo  # output: "1"
 
f = Empty.new
f.foo = 1   # raises NoMethodError
  | 
| 
	http://rosettacode.org/wiki/Add_a_variable_to_a_class_instance_at_runtime | 
	Add a variable to a class instance at runtime | 
	Demonstrate how to dynamically add variables to an object (a class instance) at runtime.
This is useful when the methods/variables of an instance are based on a data file that isn't available until runtime. Hal Fulton gives an example of creating an OO CSV parser at An Exercise in Metaprogramming with Ruby. This is referred to as "monkeypatching" by Pythonistas and some others.
 | 
	#Scala | 
	Scala | 
	import language.dynamics
import scala.collection.mutable.HashMap
 
class A extends Dynamic {
  private val map = new HashMap[String, Any]
  def selectDynamic(name: String): Any = {
    return map(name)
  }
  def updateDynamic(name:String)(value: Any) = {
    map(name) = value
  }
} | 
| 
	http://rosettacode.org/wiki/Add_a_variable_to_a_class_instance_at_runtime | 
	Add a variable to a class instance at runtime | 
	Demonstrate how to dynamically add variables to an object (a class instance) at runtime.
This is useful when the methods/variables of an instance are based on a data file that isn't available until runtime. Hal Fulton gives an example of creating an OO CSV parser at An Exercise in Metaprogramming with Ruby. This is referred to as "monkeypatching" by Pythonistas and some others.
 | 
	#Sidef | 
	Sidef | 
	class Empty{};
var e = Empty();    # create a new class instance
e{:foo} = 42;       # add variable 'foo'
say e{:foo};        # print the value of 'foo' | 
| 
	http://rosettacode.org/wiki/Address_of_a_variable | 
	Address of a variable | 
	
Basic Data Operation
This is a basic data operation. It represents a fundamental action on a basic data type.
You may see other such operations in the Basic Data Operations category, or:
Integer Operations
Arithmetic |
Comparison
Boolean Operations
Bitwise |
Logical
String Operations
Concatenation |
Interpolation |
Comparison |
Matching
Memory Operations
Pointers & references |
Addresses
Task
Demonstrate how to get the address of a variable and how to set the address of a variable.
 | 
	#RapidQ | 
	RapidQ | 
	 
Dim TheAddress as long
Dim SecVar as byte
Dim MyVar as byte
    MyVar = 10
 
'Get the address of MyVar
TheAddress = varptr(MyVar)
 
'Set a new value on the address
MEMSET(TheAddress, 102, SizeOf(byte))
 
'Myvar is now = 102
showmessage "MyVar = " + str$(MyVar)
 
'...or copy from one address to another using:
MEMCPY(VarPtr(SecVar), TheAddress, SizeOf(byte))
 
'SecVar is now also = 102
showmessage "SecVar = " + str$(SecVar)
  | 
| 
	http://rosettacode.org/wiki/Address_of_a_variable | 
	Address of a variable | 
	
Basic Data Operation
This is a basic data operation. It represents a fundamental action on a basic data type.
You may see other such operations in the Basic Data Operations category, or:
Integer Operations
Arithmetic |
Comparison
Boolean Operations
Bitwise |
Logical
String Operations
Concatenation |
Interpolation |
Comparison |
Matching
Memory Operations
Pointers & references |
Addresses
Task
Demonstrate how to get the address of a variable and how to set the address of a variable.
 | 
	#Retro | 
	Retro | 
	'a var
&a | 
| 
	http://rosettacode.org/wiki/Address_of_a_variable | 
	Address of a variable | 
	
Basic Data Operation
This is a basic data operation. It represents a fundamental action on a basic data type.
You may see other such operations in the Basic Data Operations category, or:
Integer Operations
Arithmetic |
Comparison
Boolean Operations
Bitwise |
Logical
String Operations
Concatenation |
Interpolation |
Comparison |
Matching
Memory Operations
Pointers & references |
Addresses
Task
Demonstrate how to get the address of a variable and how to set the address of a variable.
 | 
	#REXX | 
	REXX | 
	zzz = storage(xxx) | 
| 
	http://rosettacode.org/wiki/Address_of_a_variable | 
	Address of a variable | 
	
Basic Data Operation
This is a basic data operation. It represents a fundamental action on a basic data type.
You may see other such operations in the Basic Data Operations category, or:
Integer Operations
Arithmetic |
Comparison
Boolean Operations
Bitwise |
Logical
String Operations
Concatenation |
Interpolation |
Comparison |
Matching
Memory Operations
Pointers & references |
Addresses
Task
Demonstrate how to get the address of a variable and how to set the address of a variable.
 | 
	#Ruby | 
	Ruby | 
	>foo = Object.new  # => #<Object:0x10ae32000>
>id = foo.object_id  # => 2238812160
>"%x" % (id << 1)  # => "10ae32000"
  | 
| 
	http://rosettacode.org/wiki/AKS_test_for_primes | 
	AKS test for primes | 
	The AKS algorithm for testing whether a number is prime is a polynomial-time algorithm based on an elementary theorem about Pascal triangles.
The theorem on which the test is based can be stated as follows:
   a number   
p
{\displaystyle p}
   is prime   if and only if   all the coefficients of the polynomial expansion of
 
(
x
−
1
)
p
−
(
x
p
−
1
)
{\displaystyle (x-1)^{p}-(x^{p}-1)}
are divisible by   
p
{\displaystyle p}
.
Example
Using   
p
=
3
{\displaystyle p=3}
:
         (x-1)^3 - (x^3 - 1)
            = (x^3 - 3x^2 + 3x - 1) - (x^3 - 1)
            = -3x^2 + 3x
And all the coefficients are divisible by 3,   so 3 is prime.
 Note:
This task is not the AKS primality test.   It is an inefficient exponential time algorithm discovered in the late 1600s and used as an introductory lemma in the AKS derivation.
Task
 Create a function/subroutine/method that given   
p
{\displaystyle p}
   generates the coefficients of the expanded polynomial representation of   
(
x
−
1
)
p
{\displaystyle (x-1)^{p}}
.
 Use the function to show here the polynomial expansions of   
(
x
−
1
)
p
{\displaystyle (x-1)^{p}}
   for   
p
{\displaystyle p}
   in the range   0   to at least   7,   inclusive.
 Use the previous function in creating another function that when given   
p
{\displaystyle p}
   returns whether   
p
{\displaystyle p}
   is prime using the theorem.
 Use your test to generate a list of all primes under   35.
 As a stretch goal,   generate all primes under   50   (needs integers larger than 31-bit).
References
 Agrawal-Kayal-Saxena (AKS) primality test (Wikipedia) 
 Fool-Proof Test for Primes - Numberphile (Video). The accuracy of this video is disputed -- at best it is an oversimplification.
 | 
	#Factor | 
	Factor | 
	USING: combinators formatting io kernel make math math.parser
math.polynomials prettyprint sequences ;
IN: rosetta-code.aks-test
 
! Polynomials are represented by the math.polynomials vocabulary
! as sequences with the highest exponent on the right. Hence
! { -1 1 } represents x - 1.
: (x-1)^ ( n -- seq ) { -1 1 } swap p^ ;
 
: choose-exp ( n -- str )
    { { 0 [ "" ] } { 1 [ "x" ] } [ "x^%d" sprintf ] } case ;
 
: choose-coeff ( n -- str )
    [ dup neg? [ neg "- " ] [ "+ " ] if % # ] "" make ;
 
: terms ( coeffs-seq -- terms-seq )
    [ [ choose-coeff ] [ choose-exp append ] bi* ] map-index ;
 
: (.p) ( n -- str ) (x-1)^ terms <reversed> " " join 3 tail ;
 
: .p ( n -- ) dup zero? [ drop "1" ] [ (.p) ] if print ;
 
: show-poly ( n -- ) [ "(x-1)^%d = " printf ] [ .p ] bi ;
 
: part1 ( -- ) 8 <iota> [ show-poly ] each ;
 
: (prime?) ( n -- ? )
    (x-1)^ rest but-last dup first [ mod 0 = not ] curry find
    nip not ;
 
: prime? ( n -- ? ) dup 2 < [ drop f ] [ (prime?) ] if ;
 
: part2 ( -- )
    "Primes up to 50 via AKS:" print
    50 <iota> [ prime? ] filter . ;
 
: aks-test ( -- ) part1 nl part2 ;
 
MAIN: aks-test | 
| 
	http://rosettacode.org/wiki/Additive_primes | 
	Additive primes | 
	Definitions
In mathematics, additive primes are prime numbers for which the sum of their decimal digits are also primes.
Task
Write a program to determine (and show here) all additive primes less than 500.
Optionally, show the number of additive primes.
Also see
   the OEIS entry:   A046704 additive primes.
   the prime-numbers entry:   additive primes.
   the geeks for geeks entry: additive prime number.
   the prime-numbers fandom: additive primes.
 | 
	#langur | 
	langur | 
	val .isPrime = f .i == 2 or .i > 2 and not any f(.x) .i div .x, pseries 2 to .i ^/ 2
 
val .sumDigits = f fold f{+}, s2n toString .i
 
writeln "Additive primes less than 500:"
 
var .count = 0
 
for .i in [2] ~ series(3..500, 2) {
    if .isPrime(.i) and .isPrime(.sumDigits(.i)) {
        write $"\.i:3;  "
        .count += 1
        if .count div 10: writeln()
    }
}
 
writeln $"\n\n\.count; additive primes found.\n"
  | 
| 
	http://rosettacode.org/wiki/Additive_primes | 
	Additive primes | 
	Definitions
In mathematics, additive primes are prime numbers for which the sum of their decimal digits are also primes.
Task
Write a program to determine (and show here) all additive primes less than 500.
Optionally, show the number of additive primes.
Also see
   the OEIS entry:   A046704 additive primes.
   the prime-numbers entry:   additive primes.
   the geeks for geeks entry: additive prime number.
   the prime-numbers fandom: additive primes.
 | 
	#Lua | 
	Lua | 
	function sumdigits(n)
  local sum = 0
  while n > 0 do
    sum = sum + n % 10
    n = math.floor(n/10)
  end
  return sum
end
 
primegen:generate(nil, 500)
aprimes = primegen:filter(function(n) return primegen.tbd(sumdigits(n)) end)
print(table.concat(aprimes, " "))
print("Count:", #aprimes) | 
| 
	http://rosettacode.org/wiki/Almost_prime | 
	Almost prime | 
	A   k-Almost-prime   is a natural number   
n
{\displaystyle n}
   that is the product of   
k
{\displaystyle k}
   (possibly identical) primes.
Example
1-almost-primes,   where   
k
=
1
{\displaystyle k=1}
,   are the prime numbers themselves.
2-almost-primes,   where   
k
=
2
{\displaystyle k=2}
,   are the   semiprimes.
Task
Write a function/method/subroutine/... that generates k-almost primes and use it to create a table here of the first ten members of k-Almost primes for   
1
<=
K
<=
5
{\displaystyle 1<=K<=5}
.
Related tasks
   Semiprime
   Category:Prime Numbers
 | 
	#Kotlin | 
	Kotlin | 
	fun Int.k_prime(x: Int): Boolean {
    var n = x
    var f = 0
    var p = 2
    while (f < this && p * p <= n) {
        while (0 == n % p) { n /= p; f++ }
        p++
    }
    return f + (if (n > 1) 1 else 0) == this
}
 
fun Int.primes(n : Int) : List<Int> {
    var i = 2
    var list = mutableListOf<Int>()
    while (list.size < n) {
        if (k_prime(i)) list.add(i)
        i++
    }
    return list
}
 
fun main(args: Array<String>) {
    for (k in 1..5)
        println("k = $k: " + k.primes(10))
} | 
| 
	http://rosettacode.org/wiki/Anagrams | 
	Anagrams | 
	When two or more words are composed of the same characters, but in a different order, they are called anagrams.
Task[edit]
Using the word list at   http://wiki.puzzlers.org/pub/wordlists/unixdict.txt,
find the sets of words that share the same characters that contain the most words in them.
Related tasks
Word plays
Ordered words
Palindrome detection
Semordnilap
Anagrams
Anagrams/Deranged anagrams
Other tasks related to string operations:
Metrics
 Array length
 String length
 Copy a string
 Empty string  (assignment)
Counting
 Word frequency
 Letter frequency
 Jewels and stones
 I before E except after C
 Bioinformatics/base count
 Count occurrences of a substring
 Count how many vowels and consonants occur in a string
Remove/replace
 XXXX redacted
 Conjugate a Latin verb
 Remove vowels from a string
 String interpolation (included)
 Strip block comments
 Strip comments from a string
 Strip a set of characters from a string
 Strip whitespace from a string -- top and tail
 Strip control codes and extended characters from a string
Anagrams/Derangements/shuffling
 Word wheel
 ABC problem
 Sattolo cycle
 Knuth shuffle
 Ordered words
 Superpermutation minimisation
 Textonyms (using a phone text pad)
 Anagrams
 Anagrams/Deranged anagrams
 Permutations/Derangements
Find/Search/Determine
 ABC words
 Odd words
 Word ladder
 Semordnilap
 Word search
 Wordiff  (game)
 String matching
 Tea cup rim text
 Alternade words
 Changeable words
 State name puzzle
 String comparison
 Unique characters
 Unique characters in each string
 Extract file extension
 Levenshtein distance
 Palindrome detection
 Common list elements
 Longest common suffix
 Longest common prefix
 Compare a list of strings 
 Longest common substring
 Find common directory path
 Words from neighbour ones
 Change e letters to i in words
 Non-continuous subsequences
 Longest common subsequence
 Longest palindromic substrings
 Longest increasing subsequence
 Words containing "the" substring
 Sum of the digits of n is substring of n
 Determine if a string is numeric
 Determine if a string is collapsible
 Determine if a string is squeezable
 Determine if a string has all unique characters
 Determine if a string has all the same characters
 Longest substrings without repeating characters
 Find words which contains all the vowels
 Find words which contains most consonants
 Find words which contains more than 3 vowels
 Find words which first and last three letters are equals
 Find words which odd letters are consonants and even letters are vowels or vice_versa
Formatting
 Substring
 Rep-string
 Word wrap
 String case
 Align columns
 Literals/String
 Repeat a string
 Brace expansion
 Brace expansion using ranges
 Reverse a string
 Phrase reversals
 Comma quibbling
 Special characters
 String concatenation
 Substring/Top and tail
 Commatizing numbers
 Reverse words in a string
 Suffixation of decimal numbers
 Long literals, with continuations 
 Numerical and alphabetical suffixes
 Abbreviations, easy
 Abbreviations, simple
 Abbreviations, automatic
Song lyrics/poems/Mad Libs/phrases
 Mad Libs
 Magic 8-ball
 99 Bottles of Beer
 The Name Game (a song)
 The Old lady swallowed a fly
 The Twelve Days of Christmas
Tokenize
 Text between
 Tokenize a string
 Word break problem
 Tokenize a string with escaping
 Split a character string based on change of character
Sequences
 Show ASCII table
 De Bruijn sequences
 Self-referential sequences
 Generate lower case ASCII alphabet
 | 
	#Eiffel | 
	Eiffel | 
	 
class
	ANAGRAMS
 
create
	make
 
feature
 
	make
			-- Set of Anagrams, containing most words.
		local
			count: INTEGER
		do
			read_wordlist
			across
				words as wo
			loop
				if wo.item.count > count then
					count := wo.item.count
				end
			end
			across
				words as wo
			loop
				if wo.item.count = count then
					across
						wo.item as list
					loop
						io.put_string (list.item + "%T")
					end
					io.new_line
				end
			end
		end
 
	original_list: STRING = "unixdict.txt"
 
feature {NONE}
 
	read_wordlist
			-- Preprocessed wordlist for finding Anagrams.
		local
			l_file: PLAIN_TEXT_FILE
			sorted: STRING
			empty_list: LINKED_LIST [STRING]
		do
			create l_file.make_open_read_write (original_list)
			l_file.read_stream (l_file.count)
			wordlist := l_file.last_string.split ('%N')
			l_file.close
			create words.make (wordlist.count)
			across
				wordlist as w
			loop
				create empty_list.make
				sorted := sort_letters (w.item)
				words.put (empty_list, sorted)
				if attached words.at (sorted) as ana then
					ana.extend (w.item)
				end
			end
		end
 
	wordlist: LIST [STRING]
 
	sort_letters (word: STRING): STRING
			--Sorted in alphabetical order.
		local
			letters: SORTED_TWO_WAY_LIST [STRING]
		do
			create letters.make
			create Result.make_empty
			across
				1 |..| word.count as i
			loop
				letters.extend (word.at (i.item).out)
			end
			across
				letters as s
			loop
				Result.append (s.item)
			end
		end
 
	words: HASH_TABLE [LINKED_LIST [STRING], STRING]
 
end
  | 
| 
	http://rosettacode.org/wiki/Angle_difference_between_two_bearings | 
	Angle difference between two bearings | 
	Finding the angle between two bearings is often confusing.[1]
Task
Find the angle which is the result of the subtraction b2 - b1, where b1 and b2 are the bearings.
Input bearings are expressed in the range   -180   to   +180   degrees.
The  result  is also expressed in the range   -180   to   +180   degrees.
Compute the angle for the following pairs:
 20 degrees (b1) and 45 degrees (b2)
 -45 and 45
 -85 and 90
 -95 and 90
 -45 and 125
 -45 and 145
 29.4803 and -88.6381
 -78.3251 and -159.036
Optional extra
 
Allow the input bearings to be any (finite) value.
Test cases
 -70099.74233810938 and 29840.67437876723
 -165313.6666297357 and 33693.9894517456
 1174.8380510598456 and -154146.66490124757
 60175.77306795546 and 42213.07192354373
 | 
	#REXX | 
	REXX | 
	/*REXX pgm calculates difference between two angles (in degrees), normalizes the result.*/
numeric digits 25                                    /*use enough dec. digits for angles*/
call show      20,                    45             /*display angular difference (deg).*/
call show     -45,                    45             /*   "       "        "        "   */
call show     -85,                    90             /*   "       "        "        "   */
call show     -95,                    90             /*   "       "        "        "   */
call show     -45,                   125             /*   "       "        "        "   */
call show      45,                   145             /*   "       "        "        "   */
call show      29.4803,              -88.6361        /*   "       "        "        "   */
call show     -78.3251,             -159.036         /*   "       "        "        "   */
call show  -70099.74233810938,     29840.67437876723 /*   "       "        "        "   */
call show -165313.6666297357,      33693.9894517456  /*   "       "        "        "   */
call show    1174.8380510598456, -154146.66490124757 /*   "       "        "        "   */
call show   60175.773067955546,    42213.07192354373 /*   "       "        "        "   */
exit                                                 /*stick a fork in it,  we're done. */
/*──────────────────────────────────────────────────────────────────────────────────────*/
show: parse arg a,b;    d=digits();     $='º'    /*obtain the 2 angles (are in degrees).*/
      x=format( ( ( ((b-a) // 360) + 540) // 360) - 180, 4, d)   /*compute and format.  */
      if pos(., x)\==0  then x=strip( strip(x, 'T', 0), "T", .)  /*strip trailing chaff.*/
      say center(a || $, d)      '─'      center(b || $, d)       " ────► "      x || $
      return                                     /* [↑]  display the angular difference.*/ | 
| 
	http://rosettacode.org/wiki/Anagrams/Deranged_anagrams | 
	Anagrams/Deranged anagrams | 
	Two or more words are said to be anagrams if they have the same characters, but in a different order.
By analogy with derangements we define a deranged anagram as two words with the same characters, but in which the same character does not appear in the same position in both words.
Task[edit]
Use the word list at unixdict to find and display the longest deranged anagram.
Related tasks
 Permutations/Derangements
 Best shuffle
Word plays
Ordered words
Palindrome detection
Semordnilap
Anagrams
Anagrams/Deranged anagrams
Other tasks related to string operations:
Metrics
 Array length
 String length
 Copy a string
 Empty string  (assignment)
Counting
 Word frequency
 Letter frequency
 Jewels and stones
 I before E except after C
 Bioinformatics/base count
 Count occurrences of a substring
 Count how many vowels and consonants occur in a string
Remove/replace
 XXXX redacted
 Conjugate a Latin verb
 Remove vowels from a string
 String interpolation (included)
 Strip block comments
 Strip comments from a string
 Strip a set of characters from a string
 Strip whitespace from a string -- top and tail
 Strip control codes and extended characters from a string
Anagrams/Derangements/shuffling
 Word wheel
 ABC problem
 Sattolo cycle
 Knuth shuffle
 Ordered words
 Superpermutation minimisation
 Textonyms (using a phone text pad)
 Anagrams
 Anagrams/Deranged anagrams
 Permutations/Derangements
Find/Search/Determine
 ABC words
 Odd words
 Word ladder
 Semordnilap
 Word search
 Wordiff  (game)
 String matching
 Tea cup rim text
 Alternade words
 Changeable words
 State name puzzle
 String comparison
 Unique characters
 Unique characters in each string
 Extract file extension
 Levenshtein distance
 Palindrome detection
 Common list elements
 Longest common suffix
 Longest common prefix
 Compare a list of strings 
 Longest common substring
 Find common directory path
 Words from neighbour ones
 Change e letters to i in words
 Non-continuous subsequences
 Longest common subsequence
 Longest palindromic substrings
 Longest increasing subsequence
 Words containing "the" substring
 Sum of the digits of n is substring of n
 Determine if a string is numeric
 Determine if a string is collapsible
 Determine if a string is squeezable
 Determine if a string has all unique characters
 Determine if a string has all the same characters
 Longest substrings without repeating characters
 Find words which contains all the vowels
 Find words which contains most consonants
 Find words which contains more than 3 vowels
 Find words which first and last three letters are equals
 Find words which odd letters are consonants and even letters are vowels or vice_versa
Formatting
 Substring
 Rep-string
 Word wrap
 String case
 Align columns
 Literals/String
 Repeat a string
 Brace expansion
 Brace expansion using ranges
 Reverse a string
 Phrase reversals
 Comma quibbling
 Special characters
 String concatenation
 Substring/Top and tail
 Commatizing numbers
 Reverse words in a string
 Suffixation of decimal numbers
 Long literals, with continuations 
 Numerical and alphabetical suffixes
 Abbreviations, easy
 Abbreviations, simple
 Abbreviations, automatic
Song lyrics/poems/Mad Libs/phrases
 Mad Libs
 Magic 8-ball
 99 Bottles of Beer
 The Name Game (a song)
 The Old lady swallowed a fly
 The Twelve Days of Christmas
Tokenize
 Text between
 Tokenize a string
 Word break problem
 Tokenize a string with escaping
 Split a character string based on change of character
Sequences
 Show ASCII table
 De Bruijn sequences
 Self-referential sequences
 Generate lower case ASCII alphabet
 | 
	#Run_BASIC | 
	Run BASIC | 
	a$ = httpGet$("http://www.puzzlers.org/pub/wordlists/unixdict.txt")
dim theWord$(30000)
dim ssWord$(30000)
 
c10$ = chr$(10)
i = 1
while instr(a$,c10$,i) <> 0
  j     = instr(a$,c10$,i)
  ln    = j - i
  again = 1
  sWord$ = mid$(a$,i,j-i)
  n = n + 1
 theWord$(n) = sWord$
 
 while again = 1
   again  = 0
   for kk = 1 to len(sWord$) - 1
   if mid$(sWord$,kk,1) > mid$(sWord$,kk +1,1) then
     sWord$ = left$(sWord$,kk-1);mid$(sWord$,kk+1,1);mid$(sWord$,kk,1);mid$(sWord$,kk+2)
     again  = 1
   end if
   next kk
 wend
 ssWord$(n) = sWord$
 i = j + 1
wend
 
for i = 1 to n
  if len(theWord$(i)) > maxLen then
    for j = 1 to n
      if ssWord$(i) = ssWord$(j) and i <> j then
        cnt = 0
	for k = 1 to len(theWord$(i))
	  if mid$(theWord$(i),k,1) = mid$(theWord$(j),k,1) then cnt = cnt + 1
	next k
	if cnt = 0 then 
	  maxLen = len(theWord$(i))
	  maxPtrI = i
	  maxPtrJ = j
	end if
      end if
    next j
  end if
next i
 
print maxLen;" ";theWord$(maxPtrI);" => ";theWord$(maxPtrJ)
end | 
| 
	http://rosettacode.org/wiki/Anonymous_recursion | 
	Anonymous recursion | 
	While implementing a recursive function, it often happens that we must resort to a separate   helper function   to handle the actual recursion.
This is usually the case when directly calling the current function would waste too many resources (stack space, execution time), causing unwanted side-effects,   and/or the function doesn't have the right arguments and/or return values.
So we end up inventing some silly name like   foo2   or   foo_helper.   I have always found it painful to come up with a proper name, and see some disadvantages:
   You have to think up a name, which then pollutes the namespace
   Function is created which is called from nowhere else
   The program flow in the source code is interrupted
Some languages allow you to embed recursion directly in-place.   This might work via a label, a local gosub instruction, or some special keyword.
Anonymous recursion can also be accomplished using the   Y combinator.
Task
If possible, demonstrate this by writing the recursive version of the fibonacci function   (see Fibonacci sequence)   which checks for a negative argument before doing the actual recursion.
 | 
	#Phix | 
	Phix | 
	without js -- (no class yet)
class Fib
    private function fib_i(integer n)
        return iff(n<2?n:this.fib_i(n-1)+this.fib_i(n-2))
    end function
    public function fib(integer n)
        if n<0 then throw("constraint error") end if
        return this.fib_i(n)
    end function
end class
Fib f = new()
function fib_i(integer i)
    return sprintf("this is not the fib_i(%d) you are looking for\n",i)
end function
?f.fib(10)
--?f.fib_i(10)  -- illegal
?fib_i(10)
 | 
| 
	http://rosettacode.org/wiki/Amicable_pairs | 
	Amicable pairs | 
	Two integers 
N
{\displaystyle N}
 and 
M
{\displaystyle M}
 are said to be amicable pairs if 
N
≠
M
{\displaystyle N\neq M}
 and the sum of the proper divisors of 
N
{\displaystyle N}
 (
s
u
m
(
p
r
o
p
D
i
v
s
(
N
)
)
{\displaystyle \mathrm {sum} (\mathrm {propDivs} (N))}
) 
=
M
{\displaystyle =M}
 as well as 
s
u
m
(
p
r
o
p
D
i
v
s
(
M
)
)
=
N
{\displaystyle \mathrm {sum} (\mathrm {propDivs} (M))=N}
.
Example
1184 and 1210 are an amicable pair, with proper divisors:
   1, 2, 4, 8, 16, 32, 37, 74, 148, 296, 592   and 
   1, 2, 5, 10, 11, 22, 55, 110, 121, 242, 605   respectively.
Task
Calculate and show here the Amicable pairs below 20,000; (there are eight).
Related tasks
 Proper divisors
 Abundant, deficient and perfect number classifications
 Aliquot sequence classifications and its amicable classification. 
 | 
	#Pascal | 
	Pascal | 
	Chasing Chains of Sums of Factors of Numbers.
Perfect!! 6,
Perfect!! 28,
Amicable! 220,284,
Perfect!! 496,
Amicable! 1184,1210,
Amicable! 2620,2924,
Amicable! 5020,5564,
Amicable! 6232,6368,
Perfect!! 8128,
Amicable! 10744,10856,
Amicable! 12285,14595,
Sociable: 12496,14288,15472,14536,14264,
Sociable: 14316,19116,31704,47616,83328,177792,295488,629072,589786,294896,358336,418904,366556,274924,275444,243760,376736,381028,285778,152990,122410,97946,48976,45946,22976,22744,19916,17716,
Amicable! 17296,18416,
 | 
| 
	http://rosettacode.org/wiki/Animate_a_pendulum | 
	Animate a pendulum | 
	
One good way of making an animation is by simulating a physical system and illustrating the variables in that system using a dynamically changing graphical display.
The classic such physical system is a simple gravity pendulum.
Task
Create a simple physical model of a pendulum and animate it.
 | 
	#Raku | 
	Raku | 
	use SDL2::Raw;
use Cairo;
 
my $width = 1000;
my $height = 400;
 
SDL_Init(VIDEO);
 
my $window = SDL_CreateWindow(
    'Pendulum - Raku',
    SDL_WINDOWPOS_CENTERED_MASK,
    SDL_WINDOWPOS_CENTERED_MASK,
    $width, $height, RESIZABLE
);
 
my $render = SDL_CreateRenderer($window, -1, ACCELERATED +| PRESENTVSYNC);
 
my $bob = Cairo::Image.create( Cairo::FORMAT_ARGB32, 32, 32 );
given Cairo::Context.new($bob) {
     my Cairo::Pattern::Gradient::Radial $sphere .=
        create(13.3, 12.8, 3.2, 12.8, 12.8, 32);
     $sphere.add_color_stop_rgba(0, 1, 1, .698, 1);
     $sphere.add_color_stop_rgba(1, .623, .669, .144, 1);
     .pattern($sphere);
     .arc(16, 16, 15, 0, 2 * pi);
     .fill;
     $sphere.destroy;
}
 
my $bob_texture = SDL_CreateTexture(
    $render, %PIXELFORMAT<ARGB8888>,
    STATIC, 32, 32
);
 
SDL_UpdateTexture(
    $bob_texture,
    SDL_Rect.new(:x(0), :y(0), :w(32), :h(32)),
    $bob.data, $bob.stride // 32
);
 
SDL_SetTextureBlendMode($bob_texture, 1);
 
SDL_SetRenderDrawBlendMode($render, 1);
 
my $event = SDL_Event.new;
 
my $now = now;   # time
my $Θ   = -π/3;  # start angle
my $ppi = 500;   # scale
my $g   = -9.81; # accelaration of gravity
my $ax  = $width/2; # anchor x
my $ay  = 25;       # anchor y
my $len = $height - 75; # 'rope' length
my $vel; # velocity
my $dt;  # delta time
 
main: loop {
    while SDL_PollEvent($event) {
        my $casted_event = SDL_CastEvent($event);
        given $casted_event {
            when *.type == QUIT    { last main }
            when *.type == WINDOWEVENT {
                if .event == 5 {
                    $width  = .data1;
                    $height = .data2;
                    $ax = $width/2;
                    $len = $height - 75;
                }
            }
        }
    }
 
    $dt = now - $now;
    $now = now;
    $vel += $g / $len * sin($Θ) * $ppi * $dt;
    $Θ   += $vel * $dt;
    my $bx = $ax + sin($Θ) * $len;
    my $by = $ay + cos($Θ) * $len;
 
    SDL_SetRenderDrawColor($render, 255, 255, 255, 255);
    SDL_RenderDrawLine($render, |($ax, $ay, $bx, $by)».round);
    SDL_RenderCopy( $render, $bob_texture, Nil,
      SDL_Rect.new($bx - 16, $by - 16, 32, 32)
    );
    SDL_RenderPresent($render);
    SDL_SetRenderDrawColor($render, 0, 0, 0, 0);
    SDL_RenderClear($render);
}
 
SDL_Quit(); | 
| 
	http://rosettacode.org/wiki/Amb | 
	Amb | 
	Define and give an example of the Amb operator.
The Amb operator (short for "ambiguous") expresses nondeterminism. This doesn't refer to randomness (as in "nondeterministic universe") but is closely related to the term as it is used in automata theory ("non-deterministic finite automaton").
The Amb operator takes a variable number of expressions (or values if that's simpler in the language) and yields a correct one which will satisfy a constraint in some future computation, thereby avoiding failure.
Problems whose solution the Amb operator naturally expresses can be approached with other tools, such as explicit nested iterations over data sets, or with pattern matching. By contrast, the Amb operator appears integrated into the language. Invocations of Amb are not wrapped in any visible loops or other search patterns; they appear to be independent.
Essentially Amb(x, y, z) splits the computation into three possible futures: a future in which the value x is yielded, a future in which the value y is yielded and a future in which the value z is yielded. The future which leads to a successful subsequent computation is chosen. The other "parallel universes" somehow go away. Amb called with no arguments fails.
For simplicity, one of the domain values usable with Amb may denote failure, if that is convenient. For instance, it is convenient if a Boolean false denotes failure, so that Amb(false) fails, and thus constraints can be expressed using Boolean expressions like Amb(x * y == 8) which unless x and y add to four.
A pseudo-code program which satisfies this constraint might look like:
let x = Amb(1, 2, 3)
let y = Amb(7, 6, 4, 5)
Amb(x * y = 8)
print x, y
The output is 2 4 because Amb(1, 2, 3) correctly chooses the future in which x has value 2, Amb(7, 6, 4, 5) chooses 4 and consequently Amb(x * y = 8) produces a success.
Alternatively, failure could be represented using strictly Amb():
unless x * y = 8 do Amb()
Or else Amb could take the form of two operators or functions: one for producing values and one for enforcing constraints:
let x = Ambsel(1, 2, 3)
let y = Ambsel(4, 5, 6)
Ambassert(x * y = 8)
print x, y
where Ambassert behaves like Amb() if the Boolean expression is false, otherwise it allows the future computation to take place, without yielding any value.
The task is to somehow implement Amb, and demonstrate it with a program which chooses one word from each of the following four sets of character strings to generate a four-word sentence:
"the" "that" "a"
"frog" "elephant" "thing"
"walked" "treaded" "grows"
"slowly" "quickly"
The constraint to be satisfied is that the last character of each word (other than the last) is the same as the first character of its successor.
The only successful sentence is "that thing grows slowly"; other combinations do not satisfy the constraint and thus fail.
The goal of this task isn't to simply process the four lists of words with explicit, deterministic program flow such as nested iteration, to trivially demonstrate the correct output. The goal is to implement the Amb operator, or a facsimile thereof that is possible within the language limitations.
 | 
	#Julia | 
	Julia | 
	# This is a general purpose AMB function that takes a two-argument failure function and
# arbitrary number of iterable objects and returns the first solution found as an array
# this function is in essence an iterative backtracking solver
 
function amb(failure, itrs...)
    n = length(itrs)
    if n == 1 return end
    states = Vector(n)
    values = Vector(n)
    # starting point, we put down the first value from the first iterable object
    states[1] = start(itrs[1])
    values[1], states[1] = next(itrs[1], states[1])
    i = 1
    # main solver loop
    while true
        # test for failure
        if i > 1 && failure(values[i-1], values[i])
            # loop for generating a new value upon failure
            # in fact this would be way more readable using goto, but Julia doesn't seem to have that :(
            while true
                # if we failed, we must generate a new value, but first we must check whether there is any
                if done(itrs[i], states[i])
                    # backtracking step with sanity check in case we ran out of values from the current generator
                    if i == 1
                        return
                    else
                        i -= 1
                        continue
                    end
                else
                    # if there is indeed a new value, generate it
                    values[i], states[i] = next(itrs[i], states[i])
                    break
                end
            end
        else
            # no failure branch
            # if solution is ready (i.e. all generators are used) just return it
            if i == n return values end
            # else start up the next generator
            i += 1
            states[i] = start(itrs[i])
            values[i], states[i] = next(itrs[i], states[i])
        end
    end
end
 
# Call our generic AMB function according to the task description and
# form the solution sentence from the returned array of words
amb((s1,s2) -> s1[end] != s2[1], # failure function
    ["the", "that", "a"],
    ["frog", "elephant", "thing"],
    ["walked", "treaded", "grows"],
    ["slowly", "quickly"]) |>
    x -> join(x, " ") |>
    println
  | 
| 
	http://rosettacode.org/wiki/Accumulator_factory | 
	Accumulator factory | 
	A problem posed by Paul Graham is that of creating a function that takes a single (numeric) argument and which returns another function that is an accumulator. The returned accumulator function in turn also takes a single numeric argument, and returns the sum of all the numeric values passed in so far to that accumulator (including the initial value passed when the accumulator was created).
Rules
The detailed rules are at http://paulgraham.com/accgensub.html and are reproduced here for simplicity (with additions in small italic text).
Before you submit an example, make sure the function
 Takes a number n and returns a function (lets call it g), that takes a number i, and returns n incremented by the accumulation of i from every call of function g(i).
Although these exact function and parameter names need not be used
 Works for any numeric type-- i.e. can take both ints and floats and returns functions that can take both ints and floats. (It is not enough simply to convert all input to floats. An accumulator that has only seen integers must return integers.) (i.e., if the language doesn't allow for numeric polymorphism, you have to use overloading or something like that)
 Generates functions that return the sum of every number ever passed to them, not just the most recent. (This requires a piece of state to hold the accumulated value, which in turn means that pure functional languages can't be used for this task.)
 Returns a real function, meaning something that you can use wherever you could use a function you had defined in the ordinary way in the text of your program. (Follow your language's conventions here.)
 Doesn't store the accumulated value or the returned functions in a way that could cause them to be inadvertently modified by other code. (No global variables or other such things.)
 E.g. if after the example, you added the following code (in a made-up language) where the factory function is called foo:
 x = foo(1); 
x(5); 
foo(3);
print x(2.3);
 It should print 8.3. (There is no need to print the form of the accumulator function returned by foo(3); it's not part of the task at all.)
Task
Create a function that implements the described rules.
It need not handle any special error cases not described above. The simplest way to implement the task as described is typically to use a closure, providing the language supports them.
Where it is not possible to hold exactly to the constraints above, describe the deviations.
 | 
	#Clojure | 
	Clojure | 
	(defn accum [n]
  (let [acc (atom n)]
    (fn [m] (swap! acc + m)))) | 
| 
	http://rosettacode.org/wiki/Accumulator_factory | 
	Accumulator factory | 
	A problem posed by Paul Graham is that of creating a function that takes a single (numeric) argument and which returns another function that is an accumulator. The returned accumulator function in turn also takes a single numeric argument, and returns the sum of all the numeric values passed in so far to that accumulator (including the initial value passed when the accumulator was created).
Rules
The detailed rules are at http://paulgraham.com/accgensub.html and are reproduced here for simplicity (with additions in small italic text).
Before you submit an example, make sure the function
 Takes a number n and returns a function (lets call it g), that takes a number i, and returns n incremented by the accumulation of i from every call of function g(i).
Although these exact function and parameter names need not be used
 Works for any numeric type-- i.e. can take both ints and floats and returns functions that can take both ints and floats. (It is not enough simply to convert all input to floats. An accumulator that has only seen integers must return integers.) (i.e., if the language doesn't allow for numeric polymorphism, you have to use overloading or something like that)
 Generates functions that return the sum of every number ever passed to them, not just the most recent. (This requires a piece of state to hold the accumulated value, which in turn means that pure functional languages can't be used for this task.)
 Returns a real function, meaning something that you can use wherever you could use a function you had defined in the ordinary way in the text of your program. (Follow your language's conventions here.)
 Doesn't store the accumulated value or the returned functions in a way that could cause them to be inadvertently modified by other code. (No global variables or other such things.)
 E.g. if after the example, you added the following code (in a made-up language) where the factory function is called foo:
 x = foo(1); 
x(5); 
foo(3);
print x(2.3);
 It should print 8.3. (There is no need to print the form of the accumulator function returned by foo(3); it's not part of the task at all.)
Task
Create a function that implements the described rules.
It need not handle any special error cases not described above. The simplest way to implement the task as described is typically to use a closure, providing the language supports them.
Where it is not possible to hold exactly to the constraints above, describe the deviations.
 | 
	#CoffeeScript | 
	CoffeeScript | 
	accumulator = (sum) ->
  (n) -> sum += n
 
f = accumulator(1)
console.log f(5)
console.log f(2.3) | 
| 
	http://rosettacode.org/wiki/Ackermann_function | 
	Ackermann function | 
	The Ackermann function is a classic example of a recursive function, notable especially because it is not a primitive recursive function. It grows very quickly in value, as does the size of its call tree.
The Ackermann function is usually defined as follows:
A
(
m
,
n
)
=
{
n
+
1
if 
m
=
0
A
(
m
−
1
,
1
)
if 
m
>
0
 and 
n
=
0
A
(
m
−
1
,
A
(
m
,
n
−
1
)
)
if 
m
>
0
 and 
n
>
0.
{\displaystyle A(m,n)={\begin{cases}n+1&{\mbox{if }}m=0\\A(m-1,1)&{\mbox{if }}m>0{\mbox{ and }}n=0\\A(m-1,A(m,n-1))&{\mbox{if }}m>0{\mbox{ and }}n>0.\end{cases}}}
Its arguments are never negative and it always terminates.
Task
Write a function which returns the value of 
A
(
m
,
n
)
{\displaystyle A(m,n)}
. Arbitrary precision is preferred (since the function grows so quickly), but not required.
See also
 Conway chained arrow notation for the Ackermann function.
 | 
	#8086_Assembly | 
	8086 Assembly | 
		cpu	8086
	bits	16
	org	100h
section	.text
	jmp	demo
	;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;
	;;;	ACK(M,N); DX=M, AX=N, return value in AX.
ack:	and	dx,dx	; N=0?
	jnz	.m
	inc	ax	; If so, return N+1
	ret
.m:	and	ax,ax	; M=0?
	jnz	.mn
	mov	ax,1	; If so, N=1,
	dec	dx	; M -= 1
	jmp	ack	; ACK(M-1,1) - tail recursion
.mn:	push	dx	; Keep M on the stack
	dec	ax	; N-=1
	call	ack	; N = ACK(M,N-1)
	pop	dx	; Restore M
	dec	dx	; M -= 1
	jmp	ack	; ACK(M-1,ACK(M,N-1)) - tail recursion
	;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;
	;;;	Print table of ack(m,n)
MMAX:	equ	4	; Size of table to print. Noe that math is done
NMAX:	equ	9	; in 16 bits.
demo:	xor	si,si	; Let SI hold M,
	xor	di,di	; and DI hold N.
acknum:	mov	dx,si	; Calculate ack(M,N)
	mov	ax,di
	call	ack
	call	prax	; Print number
	inc	di	; N += 1
	cmp	di,NMAX	; Row done?
	jb	acknum	; If not, print next number on row
	xor	di,di	; Otherwise, N=0,
	inc	si	; M += 1
	mov	dx,nl	; Print newline
	call	prstr
	cmp	si,MMAX	; Done?
	jb	acknum	; If not, start next row
	ret		; Otherwise, stop.
	;;;	Print AX as ASCII number.
prax:	mov	bx,pnum	; Pointer to number string
	mov	cx,10	; Divisor
.dgt:	xor	dx,dx	; Divide AX by ten
	div	cx
	add	dl,'0'	; DX holds remainder - add ASCII 0
	dec	bx	; Move pointer backwards
	mov	[bx],dl	; Save digit in string
	and	ax,ax	; Are we done yet?
	jnz	.dgt	; If not, next digit
	mov	dx,bx	; Tell DOS to print the string
prstr:	mov	ah,9
	int	21h
	ret
section	.data
	db	'*****'	; Placeholder for ASCII number
pnum:	db	9,'$'
nl:	db	13,10,'$' | 
| 
	http://rosettacode.org/wiki/Abundant,_deficient_and_perfect_number_classifications | 
	Abundant, deficient and perfect number classifications | 
	These define three classifications of positive integers based on their   proper divisors.
Let   P(n)   be the sum of the proper divisors of   n   where the proper divisors are all positive divisors of   n   other than   n   itself.
   if    P(n) <  n    then  n  is classed as  deficient  (OEIS A005100).
   if    P(n) == n    then  n  is classed as  perfect    (OEIS A000396).
   if    P(n) >  n    then  n  is classed as  abundant   (OEIS A005101).
Example
6   has proper divisors of   1,   2,   and   3.
1 + 2 + 3 = 6,   so   6   is classed as a perfect number.
Task
Calculate how many of the integers   1   to   20,000   (inclusive) are in each of the three classes.
Show the results here.
Related tasks
   Aliquot sequence classifications.   (The whole series from which this task is a subset.)
   Proper divisors
   Amicable pairs
 | 
	#ALGOL_W | 
	ALGOL W | 
	begin % count abundant, perfect and deficient numbers up to 20 000        % 
    integer MAX_NUMBER;
    MAX_NUMBER := 20000;
    begin
        integer array pds ( 1 :: MAX_NUMBER );
        integer aCount, dCount, pCount, dSum;
        % construct a table of proper divisor sums                        %
        pds( 1 ) := 0;
        for i := 2 until MAX_NUMBER do pds( i ) := 1;
        for i := 2 until MAX_NUMBER do begin
            for j := i + i step i until MAX_NUMBER do pds( j ) := pds( j ) + i
        end for_i ;
        aCount := dCount := pCOunt := 0;
        for i := 1 until 20000 do begin
            dSum := pds( i );
            if      dSum > i then aCount := aCount + 1
            else if dSum < i then dCount := dCOunt + 1
            else %  dSum = i    % pCount := pCount + 1
        end for_i ;
        write( "Abundant  numbers up to 20 000: ", aCount );
        write( "Perfect   numbers up to 20 000: ", pCount );
        write( "Deficient numbers up to 20 000: ", dCount )
    end
end. | 
| 
	http://rosettacode.org/wiki/Align_columns | 
	Align columns | 
	Given a text file of many lines, where fields within a line
are delineated by a single 'dollar' character, write a program
that aligns each column of fields by ensuring that words in each
column are separated by at least one space.
Further, allow for each word in a column to be either left
justified, right justified, or center justified within its column.
Use the following text to test your programs:
Given$a$text$file$of$many$lines,$where$fields$within$a$line$
are$delineated$by$a$single$'dollar'$character,$write$a$program
that$aligns$each$column$of$fields$by$ensuring$that$words$in$each$
column$are$separated$by$at$least$one$space.
Further,$allow$for$each$word$in$a$column$to$be$either$left$
justified,$right$justified,$or$center$justified$within$its$column.
Note that:
   The example input texts lines may, or may not, have trailing dollar characters.
   All columns should share the same alignment.
   Consecutive space characters produced adjacent to the end of lines are insignificant for the purposes of the task.
   Output text will be viewed in a mono-spaced font on a plain text editor or basic terminal.
   The minimum space between columns should be computed from the text and not hard-coded.
   It is not a requirement to add separating characters between or around columns.
Other tasks related to string operations:
Metrics
 Array length
 String length
 Copy a string
 Empty string  (assignment)
Counting
 Word frequency
 Letter frequency
 Jewels and stones
 I before E except after C
 Bioinformatics/base count
 Count occurrences of a substring
 Count how many vowels and consonants occur in a string
Remove/replace
 XXXX redacted
 Conjugate a Latin verb
 Remove vowels from a string
 String interpolation (included)
 Strip block comments
 Strip comments from a string
 Strip a set of characters from a string
 Strip whitespace from a string -- top and tail
 Strip control codes and extended characters from a string
Anagrams/Derangements/shuffling
 Word wheel
 ABC problem
 Sattolo cycle
 Knuth shuffle
 Ordered words
 Superpermutation minimisation
 Textonyms (using a phone text pad)
 Anagrams
 Anagrams/Deranged anagrams
 Permutations/Derangements
Find/Search/Determine
 ABC words
 Odd words
 Word ladder
 Semordnilap
 Word search
 Wordiff  (game)
 String matching
 Tea cup rim text
 Alternade words
 Changeable words
 State name puzzle
 String comparison
 Unique characters
 Unique characters in each string
 Extract file extension
 Levenshtein distance
 Palindrome detection
 Common list elements
 Longest common suffix
 Longest common prefix
 Compare a list of strings 
 Longest common substring
 Find common directory path
 Words from neighbour ones
 Change e letters to i in words
 Non-continuous subsequences
 Longest common subsequence
 Longest palindromic substrings
 Longest increasing subsequence
 Words containing "the" substring
 Sum of the digits of n is substring of n
 Determine if a string is numeric
 Determine if a string is collapsible
 Determine if a string is squeezable
 Determine if a string has all unique characters
 Determine if a string has all the same characters
 Longest substrings without repeating characters
 Find words which contains all the vowels
 Find words which contains most consonants
 Find words which contains more than 3 vowels
 Find words which first and last three letters are equals
 Find words which odd letters are consonants and even letters are vowels or vice_versa
Formatting
 Substring
 Rep-string
 Word wrap
 String case
 Align columns
 Literals/String
 Repeat a string
 Brace expansion
 Brace expansion using ranges
 Reverse a string
 Phrase reversals
 Comma quibbling
 Special characters
 String concatenation
 Substring/Top and tail
 Commatizing numbers
 Reverse words in a string
 Suffixation of decimal numbers
 Long literals, with continuations 
 Numerical and alphabetical suffixes
 Abbreviations, easy
 Abbreviations, simple
 Abbreviations, automatic
Song lyrics/poems/Mad Libs/phrases
 Mad Libs
 Magic 8-ball
 99 Bottles of Beer
 The Name Game (a song)
 The Old lady swallowed a fly
 The Twelve Days of Christmas
Tokenize
 Text between
 Tokenize a string
 Word break problem
 Tokenize a string with escaping
 Split a character string based on change of character
Sequences
 Show ASCII table
 De Bruijn sequences
 Self-referential sequences
 Generate lower case ASCII alphabet
 | 
	#AutoHotkey | 
	AutoHotkey | 
	Alignment := "L"																				; Options: L, R, C
Text = 
( LTrim
	Given$a$text$file$of$many$lines,$where$fields$within$a$line$
	are$delineated$by$a$single$'dollar'$character,$write$a$program
	that$aligns$each$column$of$fields$by$ensuring$that$words$in$each$
	column$are$separated$by$at$least$one$space.
	Further,$allow$for$each$word$in$a$column$to$be$either$left$
	justified,$right$justified,$or$center$justified$within$its$column.
)
 
Loop, Parse, Text																				; calculate column's width
	If A_LoopField in $,`n
		If (N > W)
			W := N, N := 0
		Else
			N := 0
	Else
		++N
Width := ++W
 
Loop, Parse, Text, `n																			; process each line
{
	Words := StrSplit(A_LoopField, "$")
	For i, Word in Words																		; process each word
		Line .= Align(Word, Alignment, Width)
	Result .= RTrim(Line) . "`n"
	Line := ""
}
 
Clipboard := Result																				; present results
MsgBox, The results are in the Clipboard
 
Align(Pal, How, Width) {																		; function for alignment
	Length := StrLen(Pal)
	If (How = "L")
		Return Pal . Spc(Width - Length)
	Else If (How = "R")
		Return Spc(Width - Length) . Pal
	Else If (How = "C")
		Return Spc((Width - Length)//2) . Pal . Spc(Width - Length - (Width - Length)//2)
}
 
Spc(Number) {																					; function to concatenate space characters
	Loop, %Number%
		Ret .= A_Space
	Return Ret
}
  | 
| 
	http://rosettacode.org/wiki/Active_object | 
	Active object | 
	In object-oriented programming an object is active when its state depends on clock. Usually an active object encapsulates a task that updates the object's state. To the outer world the object looks like a normal object with methods that can be called from outside. Implementation of such methods must have a certain synchronization mechanism with the encapsulated task in order to prevent object's state corruption.
A typical instance of an active object is an animation widget. The widget state changes with the time, while as an object it has all properties of a normal widget.
The task
Implement an active integrator object. The object has an input and output. The input can be set using the method Input. The input is a function of time. The output can be queried using the method Output. The object integrates its input over the time and the result becomes the object's output. So if the input is K(t) and the output is S, the object state S is changed to S + (K(t1) + K(t0)) * (t1 - t0) / 2, i.e. it integrates K using the trapeze method. Initially K is constant 0 and S is 0.
In order to test the object:
 set its input to sin (2π f t), where the frequency f=0.5Hz. The phase is irrelevant.
 wait 2s
 set the input to constant 0
 wait 0.5s
Verify that now the object's output is approximately 0 (the sine has the period of 2s). The accuracy of the result will depend on the OS scheduler time slicing and the accuracy of the clock.
 | 
	#Factor | 
	Factor | 
	USING: accessors alarms calendar combinators kernel locals math
math.constants math.functions prettyprint system threads ;
IN: rosettacode.active
 
TUPLE: active-object alarm function state previous-time ;
 
: apply-stack-effect ( quot -- quot' ) 
    [ call( x -- x ) ] curry ; inline
 
: nano-to-seconds ( -- seconds ) nano-count 9 10^ / ;
 
: object-times ( active-object -- t1 t2 ) 
    [ previous-time>> ] 
    [ nano-to-seconds [ >>previous-time drop ] keep ] bi ;
:: adding-function ( t1 t2 active-object -- function )
    t2 t1 active-object function>> apply-stack-effect bi@ +
    t2 t1 - * 2 / [ + ] curry ;
: integrate ( active-object -- )
    [ object-times ]
    [ adding-function ]
    [ swap apply-stack-effect change-state drop ] tri ;
 
: <active-object> ( -- object )
    active-object new
    0 >>state
    nano-to-seconds >>previous-time
    [ drop 0 ] >>function
    dup [ integrate ] curry 1 nanoseconds every >>alarm ;
: destroy ( active-object -- ) alarm>> cancel-alarm ;
 
: input ( object quot -- object ) >>function ;
: output ( object -- val ) state>> ;
 
: active-test ( -- )
    <active-object>
    [ 2 pi 0.5 * * * sin ] input
    2 seconds sleep
    [ drop 0 ] input
    0.5 seconds sleep
    [ output . ] [ destroy ] bi ;
MAIN: active-test | 
| 
	http://rosettacode.org/wiki/Active_object | 
	Active object | 
	In object-oriented programming an object is active when its state depends on clock. Usually an active object encapsulates a task that updates the object's state. To the outer world the object looks like a normal object with methods that can be called from outside. Implementation of such methods must have a certain synchronization mechanism with the encapsulated task in order to prevent object's state corruption.
A typical instance of an active object is an animation widget. The widget state changes with the time, while as an object it has all properties of a normal widget.
The task
Implement an active integrator object. The object has an input and output. The input can be set using the method Input. The input is a function of time. The output can be queried using the method Output. The object integrates its input over the time and the result becomes the object's output. So if the input is K(t) and the output is S, the object state S is changed to S + (K(t1) + K(t0)) * (t1 - t0) / 2, i.e. it integrates K using the trapeze method. Initially K is constant 0 and S is 0.
In order to test the object:
 set its input to sin (2π f t), where the frequency f=0.5Hz. The phase is irrelevant.
 wait 2s
 set the input to constant 0
 wait 0.5s
Verify that now the object's output is approximately 0 (the sine has the period of 2s). The accuracy of the result will depend on the OS scheduler time slicing and the accuracy of the clock.
 | 
	#FBSL | 
	FBSL | 
	#APPTYPE CONSOLE
 
#INCLUDE <Include\Windows.inc>
 
DIM Entity AS NEW Integrator(): SLEEP(2000) ' respawn and do the job
 
Entity.Relax(): SLEEP(500) ' get some rest
 
PRINT ">>> ", Entity.Yield(): DELETE Entity ' report and die
 
PAUSE
 
' ------------- End Program Code -------------
 
#DEFINE SpawnMutex CreateMutex(NULL, FALSE, "mutex")
#DEFINE LockMutex WaitForSingleObject(mutex, INFINITE)
#DEFINE UnlockMutex ReleaseMutex(mutex)
#DEFINE KillMutex CloseHandle(mutex)
 
CLASS Integrator
 
	PRIVATE:
 
	TYPE LARGE_INTEGER
		lowPart AS INTEGER
		highPart AS INTEGER
	END TYPE
 
	DIM dfreq AS DOUBLE, dlast AS DOUBLE, dnow AS DOUBLE, llint AS LARGE_INTEGER
	DIM dret0 AS DOUBLE, dret1 AS DOUBLE, mutex AS INTEGER, sum AS DOUBLE, thread AS INTEGER
 
	' --------------------------------------------
	SUB INITIALIZE()
		mutex = SpawnMutex
		QueryPerformanceFrequency(@llint)
		dfreq = LargeInt2Double(llint)
		QueryPerformanceCounter(@llint)
		dlast = LargeInt2Double(llint) / dfreq
		thread = FBSLTHREAD(ADDRESSOF Sampler)
		FBSLTHREADRESUME(thread)
	END SUB
	SUB TERMINATE()
		' nothing special
	END SUB
	' --------------------------------------------
 
	SUB Sampler()
		DO
			LockMutex
			SLEEP(5)
			QueryPerformanceCounter(@llint)
			dnow = LargeInt2Double(llint) / dfreq
			dret0 = Task(dlast): dret1 = Task(dnow)
			sum = sum + (dret1 + dret0) * (dnow - dlast) / 2
			dlast = dnow
			UnlockMutex
		LOOP
	END SUB
 
	FUNCTION LargeInt2Double(obj AS VARIANT) AS DOUBLE
		STATIC ret
		ret = obj.highPart
		IF obj.highPart < 0 THEN ret = ret + (2 ^ 32)
		ret = ret * 2 ^ 32
		ret = ret + obj.lowPart
		IF obj.lowPart < 0 THEN ret = ret + (2 ^ 32)
		RETURN ret
	END FUNCTION
 
	PUBLIC:
 
	METHOD Relax()
		LockMutex
		ADDRESSOF Task = ADDRESSOF Idle
		UnlockMutex
	END METHOD
 
	METHOD Yield() AS DOUBLE
		LockMutex
		Yield = sum
		FBSLTHREADKILL(thread)
		UnlockMutex
		KillMutex
	END METHOD
 
END CLASS
 
FUNCTION Idle(BYVAL t AS DOUBLE) AS DOUBLE
	RETURN 0.0
END FUNCTION
 
FUNCTION Task(BYVAL t AS DOUBLE) AS DOUBLE
	RETURN SIN(2 * PI * 0.5 * t)
END FUNCTION | 
| 
	http://rosettacode.org/wiki/Aliquot_sequence_classifications | 
	Aliquot sequence classifications | 
	An aliquot sequence of a positive integer K is defined recursively as the first member
being K and subsequent members being the sum of the Proper divisors of the previous term.
 If the terms eventually reach 0 then the series for K is said to terminate.
There are several classifications for non termination:
 If the second term is K then all future terms are also K and so the sequence repeats from the first term with period 1 and K is called perfect.
 If the third term would be repeating K then the sequence repeats with period 2 and K is called amicable.
 If the Nth term would be repeating K for the first time, with N > 3 then the sequence repeats with period N - 1 and K is called sociable.
Perfect, amicable and sociable numbers eventually repeat the original number K; there are other repetitions...
 Some K have a sequence that eventually forms a periodic repetition of period 1 but of a number other than K, for example 95 which forms the sequence 95, 25, 6, 6, 6, ... such K are called aspiring.
 K that have a sequence that eventually forms a periodic repetition of period >= 2 but of a number other than K, for example 562 which forms the sequence 562, 284, 220, 284, 220, ... such K are called cyclic.
And finally:
 Some K form aliquot sequences that are not known to be either terminating or periodic; these K are to be called non-terminating. 
For the purposes of this task, K is to be classed as non-terminating if it has not been otherwise classed after generating 16 terms or if any term of the sequence is greater than 2**47 = 140,737,488,355,328. 
Task
 Create routine(s) to generate the aliquot sequence of a positive integer enough to classify it according to the classifications given above.
 Use it to display the classification and sequences of the numbers one to ten inclusive.
 Use it to show the classification and sequences of the following integers, in order:
 11, 12, 28, 496, 220, 1184, 12496, 1264460, 790, 909, 562, 1064, 1488, and optionally 15355717786080.
Show all output on this page.
Related tasks
   Abundant, deficient and perfect number classifications. (Classifications from only the first two members of the whole sequence).
   Proper divisors
   Amicable pairs
 | 
	#Kotlin | 
	Kotlin | 
	// version 1.1.3
 
data class Classification(val sequence: List<Long>, val aliquot: String)
 
const val THRESHOLD = 1L shl 47
 
fun sumProperDivisors(n: Long): Long {
    if (n < 2L) return 0L
    val sqrt = Math.sqrt(n.toDouble()).toLong()
    var sum = 1L + (2L..sqrt)
        .filter { n % it == 0L }
        .map { it + n / it }
        .sum()
    if (sqrt * sqrt == n) sum -= sqrt
    return sum
}
 
fun classifySequence(k: Long): Classification {
    require(k > 0)
    var last = k
    val seq = mutableListOf(k)
    while (true) {
        last = sumProperDivisors(last)
        seq.add(last)
        val n = seq.size
        val aliquot = when {
            last == 0L                  -> "Terminating"
            n == 2 && last == k         -> "Perfect"
            n == 3 && last == k         -> "Amicable"
            n >= 4 && last == k         -> "Sociable[${n - 1}]"
            last == seq[n - 2]          -> "Aspiring"
            last in seq.slice(1..n - 3) -> "Cyclic[${n - 1 - seq.indexOf(last)}]"
            n == 16 || last > THRESHOLD -> "Non-Terminating"
            else                        -> ""
        }
        if (aliquot != "") return Classification(seq, aliquot)
    }
}
 
fun main(args: Array<String>) {
    println("Aliqot classifications - periods for Sociable/Cyclic in square brackets:\n")
    for (k in 1L..10) {
        val (seq, aliquot) = classifySequence(k)
        println("${"%2d".format(k)}: ${aliquot.padEnd(15)} $seq")
    }
 
    val la = longArrayOf(
        11, 12, 28, 496, 220, 1184, 12496, 1264460, 790, 909, 562, 1064, 1488
    )
    println()
 
    for (k in la) {
        val (seq, aliquot) = classifySequence(k)
        println("${"%7d".format(k)}: ${aliquot.padEnd(15)} $seq")
    }
 
    println()
 
    val k = 15355717786080L
    val (seq, aliquot) = classifySequence(k)
    println("$k: ${aliquot.padEnd(15)} $seq")
} | 
| 
	http://rosettacode.org/wiki/Add_a_variable_to_a_class_instance_at_runtime | 
	Add a variable to a class instance at runtime | 
	Demonstrate how to dynamically add variables to an object (a class instance) at runtime.
This is useful when the methods/variables of an instance are based on a data file that isn't available until runtime. Hal Fulton gives an example of creating an OO CSV parser at An Exercise in Metaprogramming with Ruby. This is referred to as "monkeypatching" by Pythonistas and some others.
 | 
	#Slate | 
	Slate | 
	define: #Empty -> Cloneable clone.
define: #e -> Empty clone.
e addSlotNamed: #foo valued: 1. | 
| 
	http://rosettacode.org/wiki/Add_a_variable_to_a_class_instance_at_runtime | 
	Add a variable to a class instance at runtime | 
	Demonstrate how to dynamically add variables to an object (a class instance) at runtime.
This is useful when the methods/variables of an instance are based on a data file that isn't available until runtime. Hal Fulton gives an example of creating an OO CSV parser at An Exercise in Metaprogramming with Ruby. This is referred to as "monkeypatching" by Pythonistas and some others.
 | 
	#Smalltalk | 
	Smalltalk | 
	|addSlot p|
 
addSlot := 
  [:obj :slotName |
    |anonCls newObj|
    anonCls := obj class 
            subclass:(obj class name,'+') asSymbol 
            instanceVariableNames:slotName 
            classVariableNames:'' 
            poolDictionaries:'' category:nil 
            inEnvironment:nil.
    anonCls compile:('%1 ^  %1' bindWith:slotName).
    anonCls compile:('%1:v %1 := v' bindWith:slotName).
    newObj := anonCls cloneFrom:obj.
    obj become:newObj.
  ]. | 
| 
	http://rosettacode.org/wiki/Add_a_variable_to_a_class_instance_at_runtime | 
	Add a variable to a class instance at runtime | 
	Demonstrate how to dynamically add variables to an object (a class instance) at runtime.
This is useful when the methods/variables of an instance are based on a data file that isn't available until runtime. Hal Fulton gives an example of creating an OO CSV parser at An Exercise in Metaprogramming with Ruby. This is referred to as "monkeypatching" by Pythonistas and some others.
 | 
	#Swift | 
	Swift | 
	import Foundation
 
let fooKey = UnsafeMutablePointer<UInt8>.alloc(1)
 
class MyClass { }
let e = MyClass()
 
// set
objc_setAssociatedObject(e, fooKey, 1, .OBJC_ASSOCIATION_RETAIN)
 
// get
if let associatedObject = objc_getAssociatedObject(e, fooKey) {
  print("associated object: \(associatedObject)")
} else {
  print("no associated object")
} | 
| 
	http://rosettacode.org/wiki/Add_a_variable_to_a_class_instance_at_runtime | 
	Add a variable to a class instance at runtime | 
	Demonstrate how to dynamically add variables to an object (a class instance) at runtime.
This is useful when the methods/variables of an instance are based on a data file that isn't available until runtime. Hal Fulton gives an example of creating an OO CSV parser at An Exercise in Metaprogramming with Ruby. This is referred to as "monkeypatching" by Pythonistas and some others.
 | 
	#Tcl | 
	Tcl | 
	% package require TclOO
% oo::class create summation {
   constructor {} {
       variable v 0
   }
   method add x {
       variable v
       incr v $x
   }
   method value {{var v}} {
       variable $var
       return [set $var]
   }
   destructor {
       variable v
       puts "Ended with value $v"
   }
}
::summation
% set s [summation new]
% # Do the monkey patch!
% set [info object namespace $s]::time now
now
% # Prove it's really part of the object...
% $s value time
now
% | 
| 
	http://rosettacode.org/wiki/Address_of_a_variable | 
	Address of a variable | 
	
Basic Data Operation
This is a basic data operation. It represents a fundamental action on a basic data type.
You may see other such operations in the Basic Data Operations category, or:
Integer Operations
Arithmetic |
Comparison
Boolean Operations
Bitwise |
Logical
String Operations
Concatenation |
Interpolation |
Comparison |
Matching
Memory Operations
Pointers & references |
Addresses
Task
Demonstrate how to get the address of a variable and how to set the address of a variable.
 | 
	#Rust | 
	Rust | 
	let v1 = vec![vec![1,2,3]; 10];
println!("Original address: {:p}", &v1);
let mut v2;
// Override rust protections on reading from uninitialized memory
unsafe {v2 = mem::uninitialized();} 
let addr = &mut v2 as *mut _;
 
// ptr::write() though it takes v1 by value, v1s destructor is not run when it goes out of
// scope, which is good since then we'd have a vector of free'd vectors
unsafe {ptr::write(addr, v1)}
println!("New address: {:p}", &v2); | 
| 
	http://rosettacode.org/wiki/Address_of_a_variable | 
	Address of a variable | 
	
Basic Data Operation
This is a basic data operation. It represents a fundamental action on a basic data type.
You may see other such operations in the Basic Data Operations category, or:
Integer Operations
Arithmetic |
Comparison
Boolean Operations
Bitwise |
Logical
String Operations
Concatenation |
Interpolation |
Comparison |
Matching
Memory Operations
Pointers & references |
Addresses
Task
Demonstrate how to get the address of a variable and how to set the address of a variable.
 | 
	#Scala | 
	Scala | 
	var n = 42;
say Sys.refaddr(\n);        # prints the address of the variable
say Sys.refaddr(n);         # prints the address of the object at which the variable points to | 
| 
	http://rosettacode.org/wiki/Address_of_a_variable | 
	Address of a variable | 
	
Basic Data Operation
This is a basic data operation. It represents a fundamental action on a basic data type.
You may see other such operations in the Basic Data Operations category, or:
Integer Operations
Arithmetic |
Comparison
Boolean Operations
Bitwise |
Logical
String Operations
Concatenation |
Interpolation |
Comparison |
Matching
Memory Operations
Pointers & references |
Addresses
Task
Demonstrate how to get the address of a variable and how to set the address of a variable.
 | 
	#Sidef | 
	Sidef | 
	var n = 42;
say Sys.refaddr(\n);        # prints the address of the variable
say Sys.refaddr(n);         # prints the address of the object at which the variable points to | 
| 
	http://rosettacode.org/wiki/Address_of_a_variable | 
	Address of a variable | 
	
Basic Data Operation
This is a basic data operation. It represents a fundamental action on a basic data type.
You may see other such operations in the Basic Data Operations category, or:
Integer Operations
Arithmetic |
Comparison
Boolean Operations
Bitwise |
Logical
String Operations
Concatenation |
Interpolation |
Comparison |
Matching
Memory Operations
Pointers & references |
Addresses
Task
Demonstrate how to get the address of a variable and how to set the address of a variable.
 | 
	#Smalltalk | 
	Smalltalk | 
	|p|
p := Point x:10 y:20.
ObjectMemory addressOf:p.
ObjectMemory collectGarbage.
ObjectMemory addressOf:p "may return another value" | 
| 
	http://rosettacode.org/wiki/AKS_test_for_primes | 
	AKS test for primes | 
	The AKS algorithm for testing whether a number is prime is a polynomial-time algorithm based on an elementary theorem about Pascal triangles.
The theorem on which the test is based can be stated as follows:
   a number   
p
{\displaystyle p}
   is prime   if and only if   all the coefficients of the polynomial expansion of
 
(
x
−
1
)
p
−
(
x
p
−
1
)
{\displaystyle (x-1)^{p}-(x^{p}-1)}
are divisible by   
p
{\displaystyle p}
.
Example
Using   
p
=
3
{\displaystyle p=3}
:
         (x-1)^3 - (x^3 - 1)
            = (x^3 - 3x^2 + 3x - 1) - (x^3 - 1)
            = -3x^2 + 3x
And all the coefficients are divisible by 3,   so 3 is prime.
 Note:
This task is not the AKS primality test.   It is an inefficient exponential time algorithm discovered in the late 1600s and used as an introductory lemma in the AKS derivation.
Task
 Create a function/subroutine/method that given   
p
{\displaystyle p}
   generates the coefficients of the expanded polynomial representation of   
(
x
−
1
)
p
{\displaystyle (x-1)^{p}}
.
 Use the function to show here the polynomial expansions of   
(
x
−
1
)
p
{\displaystyle (x-1)^{p}}
   for   
p
{\displaystyle p}
   in the range   0   to at least   7,   inclusive.
 Use the previous function in creating another function that when given   
p
{\displaystyle p}
   returns whether   
p
{\displaystyle p}
   is prime using the theorem.
 Use your test to generate a list of all primes under   35.
 As a stretch goal,   generate all primes under   50   (needs integers larger than 31-bit).
References
 Agrawal-Kayal-Saxena (AKS) primality test (Wikipedia) 
 Fool-Proof Test for Primes - Numberphile (Video). The accuracy of this video is disputed -- at best it is an oversimplification.
 | 
	#Forth | 
	Forth | 
	: coeffs ( u -- nu ... n0 ) \ coefficients of (x-1)^u
   1 swap 1+ dup 1 ?do over over i - i */ negate swap loop drop ;
 
: prime? ( u -- f )
   dup 2 < if drop false exit then
   dup >r coeffs 1+
   \ if not prime, this loop consumes at most half the coefficients, otherwise all
   begin dup 1 <> while
      r@ mod 0= while
   repeat then rdrop
   dup 1 = >r
   begin 1 = until
   r> ;
 
: .monom ( u1 u2 -- )
   dup 0> if [char] + emit then 0 .r ?dup if ." x^" . else space then ;
: .poly ( u -- )
   dup >r coeffs 0 r> 1+ 0 ?do
      tuck swap .monom 1+
   loop ;
 
: main
   11 0 ?do i . ." : " i .poly cr loop cr
   50 1 ?do i prime? if i . then loop
   cr ; | 
| 
	http://rosettacode.org/wiki/Additive_primes | 
	Additive primes | 
	Definitions
In mathematics, additive primes are prime numbers for which the sum of their decimal digits are also primes.
Task
Write a program to determine (and show here) all additive primes less than 500.
Optionally, show the number of additive primes.
Also see
   the OEIS entry:   A046704 additive primes.
   the prime-numbers entry:   additive primes.
   the geeks for geeks entry: additive prime number.
   the prime-numbers fandom: additive primes.
 | 
	#Mathematica.2FWolfram_Language | 
	Mathematica/Wolfram Language | 
	ClearAll[AdditivePrimeQ]
AdditivePrimeQ[n_Integer] := PrimeQ[n] \[And] PrimeQ[Total[IntegerDigits[n]]]
Select[Range[500], AdditivePrimeQ] | 
| 
	http://rosettacode.org/wiki/Additive_primes | 
	Additive primes | 
	Definitions
In mathematics, additive primes are prime numbers for which the sum of their decimal digits are also primes.
Task
Write a program to determine (and show here) all additive primes less than 500.
Optionally, show the number of additive primes.
Also see
   the OEIS entry:   A046704 additive primes.
   the prime-numbers entry:   additive primes.
   the geeks for geeks entry: additive prime number.
   the prime-numbers fandom: additive primes.
 | 
	#Modula-2 | 
	Modula-2 | 
	MODULE AdditivePrimes;
FROM InOut IMPORT WriteString, WriteCard, WriteLn;
 
CONST
    Max = 500;
 
VAR
    N: CARDINAL;
    Count: CARDINAL;
    Prime: ARRAY [2..Max] OF BOOLEAN;
 
PROCEDURE DigitSum(n: CARDINAL): CARDINAL;
BEGIN
    IF n < 10 THEN 
        RETURN n;
    ELSE 
        RETURN (n MOD 10) + DigitSum(n DIV 10);
    END;
END DigitSum;
 
PROCEDURE Sieve;
VAR i, j, max2: CARDINAL;
BEGIN
    FOR i := 2 TO Max DO
        Prime[i] := TRUE;
    END;
 
    FOR i := 2 TO Max DIV 2 DO
        IF Prime[i] THEN;
            j := i*2;
            WHILE j <= Max DO 
                Prime[j] := FALSE;
                j := j + i;
            END;
        END;
    END;
END Sieve;
 
BEGIN
    Count := 0;
    Sieve();
    FOR N := 2 TO Max DO
        IF Prime[N] AND Prime[DigitSum(N)] THEN
            WriteCard(N, 4);
            Count := Count + 1;
            IF Count MOD 10 = 0 THEN WriteLn(); END;
        END;
    END;
    WriteLn();
    WriteString('There are '); WriteCard(Count,0);
    WriteString(' additive primes less than '); WriteCard(Max,0);
    WriteString('.');
    WriteLn();
END AdditivePrimes. | 
| 
	http://rosettacode.org/wiki/Almost_prime | 
	Almost prime | 
	A   k-Almost-prime   is a natural number   
n
{\displaystyle n}
   that is the product of   
k
{\displaystyle k}
   (possibly identical) primes.
Example
1-almost-primes,   where   
k
=
1
{\displaystyle k=1}
,   are the prime numbers themselves.
2-almost-primes,   where   
k
=
2
{\displaystyle k=2}
,   are the   semiprimes.
Task
Write a function/method/subroutine/... that generates k-almost primes and use it to create a table here of the first ten members of k-Almost primes for   
1
<=
K
<=
5
{\displaystyle 1<=K<=5}
.
Related tasks
   Semiprime
   Category:Prime Numbers
 | 
	#Liberty_BASIC | 
	Liberty BASIC | 
	 
' Almost prime
for k = 1 to 5
    print "k = "; k; ":";
    i = 2
    c = 0
    while c < 10
        if kPrime(i, k) then
            print " "; using("###", i);
            c = c + 1
        end if
        i = i + 1
    wend
    print
next k
end
 
function kPrime(n, k)
    f = 0
    for i = 2 to n
    while n mod i = 0
        if f = k then kPrime = 0: exit function
        f = f + 1
        n = int(n / i)
    wend
    next i
    kPrime = abs(f = k)
end function
  | 
| 
	http://rosettacode.org/wiki/Anagrams | 
	Anagrams | 
	When two or more words are composed of the same characters, but in a different order, they are called anagrams.
Task[edit]
Using the word list at   http://wiki.puzzlers.org/pub/wordlists/unixdict.txt,
find the sets of words that share the same characters that contain the most words in them.
Related tasks
Word plays
Ordered words
Palindrome detection
Semordnilap
Anagrams
Anagrams/Deranged anagrams
Other tasks related to string operations:
Metrics
 Array length
 String length
 Copy a string
 Empty string  (assignment)
Counting
 Word frequency
 Letter frequency
 Jewels and stones
 I before E except after C
 Bioinformatics/base count
 Count occurrences of a substring
 Count how many vowels and consonants occur in a string
Remove/replace
 XXXX redacted
 Conjugate a Latin verb
 Remove vowels from a string
 String interpolation (included)
 Strip block comments
 Strip comments from a string
 Strip a set of characters from a string
 Strip whitespace from a string -- top and tail
 Strip control codes and extended characters from a string
Anagrams/Derangements/shuffling
 Word wheel
 ABC problem
 Sattolo cycle
 Knuth shuffle
 Ordered words
 Superpermutation minimisation
 Textonyms (using a phone text pad)
 Anagrams
 Anagrams/Deranged anagrams
 Permutations/Derangements
Find/Search/Determine
 ABC words
 Odd words
 Word ladder
 Semordnilap
 Word search
 Wordiff  (game)
 String matching
 Tea cup rim text
 Alternade words
 Changeable words
 State name puzzle
 String comparison
 Unique characters
 Unique characters in each string
 Extract file extension
 Levenshtein distance
 Palindrome detection
 Common list elements
 Longest common suffix
 Longest common prefix
 Compare a list of strings 
 Longest common substring
 Find common directory path
 Words from neighbour ones
 Change e letters to i in words
 Non-continuous subsequences
 Longest common subsequence
 Longest palindromic substrings
 Longest increasing subsequence
 Words containing "the" substring
 Sum of the digits of n is substring of n
 Determine if a string is numeric
 Determine if a string is collapsible
 Determine if a string is squeezable
 Determine if a string has all unique characters
 Determine if a string has all the same characters
 Longest substrings without repeating characters
 Find words which contains all the vowels
 Find words which contains most consonants
 Find words which contains more than 3 vowels
 Find words which first and last three letters are equals
 Find words which odd letters are consonants and even letters are vowels or vice_versa
Formatting
 Substring
 Rep-string
 Word wrap
 String case
 Align columns
 Literals/String
 Repeat a string
 Brace expansion
 Brace expansion using ranges
 Reverse a string
 Phrase reversals
 Comma quibbling
 Special characters
 String concatenation
 Substring/Top and tail
 Commatizing numbers
 Reverse words in a string
 Suffixation of decimal numbers
 Long literals, with continuations 
 Numerical and alphabetical suffixes
 Abbreviations, easy
 Abbreviations, simple
 Abbreviations, automatic
Song lyrics/poems/Mad Libs/phrases
 Mad Libs
 Magic 8-ball
 99 Bottles of Beer
 The Name Game (a song)
 The Old lady swallowed a fly
 The Twelve Days of Christmas
Tokenize
 Text between
 Tokenize a string
 Word break problem
 Tokenize a string with escaping
 Split a character string based on change of character
Sequences
 Show ASCII table
 De Bruijn sequences
 Self-referential sequences
 Generate lower case ASCII alphabet
 | 
	#Ela | 
	Ela | 
	open monad io list string
 
groupon f x y = f x == f y
 
lines = split "\n" << replace "\n\n" "\n" << replace "\r" "\n"
 
main = do
  fh <- readFile "c:\\test\\unixdict.txt" OpenMode
  f <- readLines fh
  closeFile fh
  let words = lines f
  let wix = groupBy (groupon fst) << sort $ zip (map sort words) words
  let mxl = maximum $ map length wix
  mapM_ (putLn << map snd) << filter ((==mxl) << length) $ wix | 
| 
	http://rosettacode.org/wiki/Angle_difference_between_two_bearings | 
	Angle difference between two bearings | 
	Finding the angle between two bearings is often confusing.[1]
Task
Find the angle which is the result of the subtraction b2 - b1, where b1 and b2 are the bearings.
Input bearings are expressed in the range   -180   to   +180   degrees.
The  result  is also expressed in the range   -180   to   +180   degrees.
Compute the angle for the following pairs:
 20 degrees (b1) and 45 degrees (b2)
 -45 and 45
 -85 and 90
 -95 and 90
 -45 and 125
 -45 and 145
 29.4803 and -88.6381
 -78.3251 and -159.036
Optional extra
 
Allow the input bearings to be any (finite) value.
Test cases
 -70099.74233810938 and 29840.67437876723
 -165313.6666297357 and 33693.9894517456
 1174.8380510598456 and -154146.66490124757
 60175.77306795546 and 42213.07192354373
 | 
	#Ring | 
	Ring | 
	 
# Project : Angle difference between two bearings
 
decimals(4)
see "Input in -180 to +180 range:" + nl
see getDifference(20.0, 45.0) + nl
see getDifference(-45.0, 45.0) + nl
see getDifference(-85.0, 90.0) + nl
see getDifference(-95.0, 90.0) + nl
see getDifference(-45.0, 125.0) + nl
see getDifference(-45.0, 145.0) + nl
see getDifference(-45.0, 125.0) + nl
see getDifference(-45.0, 145.0) + nl
see getDifference(29.4803, -88.6381) + nl
see getDifference(-78.3251, -159.036) + nl
 
func getDifference(b1, b2)
     r = (b2 - b1) % 360.0
     if r >= 180.0
        r = r - 360.0
     end
     return r
  | 
| 
	http://rosettacode.org/wiki/Angle_difference_between_two_bearings | 
	Angle difference between two bearings | 
	Finding the angle between two bearings is often confusing.[1]
Task
Find the angle which is the result of the subtraction b2 - b1, where b1 and b2 are the bearings.
Input bearings are expressed in the range   -180   to   +180   degrees.
The  result  is also expressed in the range   -180   to   +180   degrees.
Compute the angle for the following pairs:
 20 degrees (b1) and 45 degrees (b2)
 -45 and 45
 -85 and 90
 -95 and 90
 -45 and 125
 -45 and 145
 29.4803 and -88.6381
 -78.3251 and -159.036
Optional extra
 
Allow the input bearings to be any (finite) value.
Test cases
 -70099.74233810938 and 29840.67437876723
 -165313.6666297357 and 33693.9894517456
 1174.8380510598456 and -154146.66490124757
 60175.77306795546 and 42213.07192354373
 | 
	#Ruby | 
	Ruby | 
	def getDifference(b1, b2)
	r = (b2 - b1) % 360.0
	# Ruby modulus has same sign as divisor, which is positive here,
	# so no need to consider negative case
	if r >= 180.0
		r -= 360.0
	end
	return r
end
 
if __FILE__ == $PROGRAM_NAME
	puts "Input in -180 to +180 range"
	puts getDifference(20.0, 45.0)
	puts getDifference(-45.0, 45.0)
	puts getDifference(-85.0, 90.0)
	puts getDifference(-95.0, 90.0)
	puts getDifference(-45.0, 125.0)
	puts getDifference(-45.0, 145.0)
	puts getDifference(-45.0, 125.0)
	puts getDifference(-45.0, 145.0)
	puts getDifference(29.4803, -88.6381)
	puts getDifference(-78.3251, -159.036)
 
	puts "Input in wider range"
	puts getDifference(-70099.74233810938, 29840.67437876723)
	puts getDifference(-165313.6666297357, 33693.9894517456)
	puts getDifference(1174.8380510598456, -154146.66490124757)
	puts getDifference(60175.77306795546, 42213.07192354373)
end | 
| 
	http://rosettacode.org/wiki/Anagrams/Deranged_anagrams | 
	Anagrams/Deranged anagrams | 
	Two or more words are said to be anagrams if they have the same characters, but in a different order.
By analogy with derangements we define a deranged anagram as two words with the same characters, but in which the same character does not appear in the same position in both words.
Task[edit]
Use the word list at unixdict to find and display the longest deranged anagram.
Related tasks
 Permutations/Derangements
 Best shuffle
Word plays
Ordered words
Palindrome detection
Semordnilap
Anagrams
Anagrams/Deranged anagrams
Other tasks related to string operations:
Metrics
 Array length
 String length
 Copy a string
 Empty string  (assignment)
Counting
 Word frequency
 Letter frequency
 Jewels and stones
 I before E except after C
 Bioinformatics/base count
 Count occurrences of a substring
 Count how many vowels and consonants occur in a string
Remove/replace
 XXXX redacted
 Conjugate a Latin verb
 Remove vowels from a string
 String interpolation (included)
 Strip block comments
 Strip comments from a string
 Strip a set of characters from a string
 Strip whitespace from a string -- top and tail
 Strip control codes and extended characters from a string
Anagrams/Derangements/shuffling
 Word wheel
 ABC problem
 Sattolo cycle
 Knuth shuffle
 Ordered words
 Superpermutation minimisation
 Textonyms (using a phone text pad)
 Anagrams
 Anagrams/Deranged anagrams
 Permutations/Derangements
Find/Search/Determine
 ABC words
 Odd words
 Word ladder
 Semordnilap
 Word search
 Wordiff  (game)
 String matching
 Tea cup rim text
 Alternade words
 Changeable words
 State name puzzle
 String comparison
 Unique characters
 Unique characters in each string
 Extract file extension
 Levenshtein distance
 Palindrome detection
 Common list elements
 Longest common suffix
 Longest common prefix
 Compare a list of strings 
 Longest common substring
 Find common directory path
 Words from neighbour ones
 Change e letters to i in words
 Non-continuous subsequences
 Longest common subsequence
 Longest palindromic substrings
 Longest increasing subsequence
 Words containing "the" substring
 Sum of the digits of n is substring of n
 Determine if a string is numeric
 Determine if a string is collapsible
 Determine if a string is squeezable
 Determine if a string has all unique characters
 Determine if a string has all the same characters
 Longest substrings without repeating characters
 Find words which contains all the vowels
 Find words which contains most consonants
 Find words which contains more than 3 vowels
 Find words which first and last three letters are equals
 Find words which odd letters are consonants and even letters are vowels or vice_versa
Formatting
 Substring
 Rep-string
 Word wrap
 String case
 Align columns
 Literals/String
 Repeat a string
 Brace expansion
 Brace expansion using ranges
 Reverse a string
 Phrase reversals
 Comma quibbling
 Special characters
 String concatenation
 Substring/Top and tail
 Commatizing numbers
 Reverse words in a string
 Suffixation of decimal numbers
 Long literals, with continuations 
 Numerical and alphabetical suffixes
 Abbreviations, easy
 Abbreviations, simple
 Abbreviations, automatic
Song lyrics/poems/Mad Libs/phrases
 Mad Libs
 Magic 8-ball
 99 Bottles of Beer
 The Name Game (a song)
 The Old lady swallowed a fly
 The Twelve Days of Christmas
Tokenize
 Text between
 Tokenize a string
 Word break problem
 Tokenize a string with escaping
 Split a character string based on change of character
Sequences
 Show ASCII table
 De Bruijn sequences
 Self-referential sequences
 Generate lower case ASCII alphabet
 | 
	#Rust | 
	Rust | 
	//! Deranged anagrams
use std::cmp::Ordering;
use std::collections::HashMap;
use std::fs::File;
use std::io;
use std::io::BufReader;
use std::io::BufRead;
use std::usize::MAX;
 
/// Get words from unix dictionary file
pub fn get_words() -> Result<Vec<String>, io::Error> {
    let mut words = vec!();
    // open file
    let f = File::open("data/unixdict.txt")?;
    // read line by line
    let reader = BufReader::new(&f);
    for line in reader.lines() {
        words.push(line?)
    }
    Ok(words)
}
 
/// Get the longest deranged anagram in the given list of word if any
pub fn longest_deranged(v: &mut Vec<String>) -> Option<(String,String)>{
    // sort by length descending then by alphabetical order
    v.sort_by(|s1, s2| {
        let mut c = s2.len().cmp(&s1.len());
        if c == Ordering::Equal {
            c = s1.cmp(s2);
        }
        c
    });
    // keep all strings keyed by sorted characters (since anagrams have the same list of sorted characters)
    let mut signatures : HashMap<Vec<char>, Vec<&String>> = HashMap::new();
    // save on memory by only keeping in the map strings of the current processed length
    let mut previous_length = MAX;
    for s in v {
        // length change, clear the map
        if s.len()<previous_length {
            signatures.clear();
            previous_length = s.len();
        }
        // generate key as sorted characters
        let mut sorted_chars = s.chars().collect::<Vec<char>>();
        sorted_chars.sort();
        let anagrams = signatures.entry(sorted_chars).or_insert(vec!());
        // find if any anagram (string with the same sorted character vector) is deranged
        if let Some(a) = anagrams.iter().filter(|anagram| is_deranged(anagram, s)).next(){
            return Some(((*a).clone(), s.clone()));
        }
        anagrams.push(s);
    }
    None
}
 
/// check if two strings do NOT have the same character in the same position
pub fn is_deranged(s1: &String, s2: &String) -> bool {
    // we zip the character iterators and check we find no position with the same two characters
    s1.chars().zip(s2.chars()).filter(|(a,b)| a == b).next().is_none()
}
 
/// an example main method printing the results
fn main() {
    let r = get_words();
    match r {
        Ok(mut v) => {
            let od = longest_deranged(&mut v);
            match od {
                None => println!("No deranged anagrams found!"),
                Some((s1,s2)) => println!("{} {}",s1,s2),
            }
        },
        Err(e) => panic!("Could not read words: {}",e)
    } 
} | 
| 
	http://rosettacode.org/wiki/Anonymous_recursion | 
	Anonymous recursion | 
	While implementing a recursive function, it often happens that we must resort to a separate   helper function   to handle the actual recursion.
This is usually the case when directly calling the current function would waste too many resources (stack space, execution time), causing unwanted side-effects,   and/or the function doesn't have the right arguments and/or return values.
So we end up inventing some silly name like   foo2   or   foo_helper.   I have always found it painful to come up with a proper name, and see some disadvantages:
   You have to think up a name, which then pollutes the namespace
   Function is created which is called from nowhere else
   The program flow in the source code is interrupted
Some languages allow you to embed recursion directly in-place.   This might work via a label, a local gosub instruction, or some special keyword.
Anonymous recursion can also be accomplished using the   Y combinator.
Task
If possible, demonstrate this by writing the recursive version of the fibonacci function   (see Fibonacci sequence)   which checks for a negative argument before doing the actual recursion.
 | 
	#PHP | 
	PHP | 
	<?php
function fib($n) {
    if ($n < 0)
        throw new Exception('Negative numbers not allowed');
    $f = function($n) { // This function must be called using call_user_func() only
        if ($n < 2)
            return 1;
        else {
            $g = debug_backtrace()[1]['args'][0];
            return call_user_func($g, $n-1) + call_user_func($g, $n-2);
        }
    };
    return call_user_func($f, $n);
}
echo fib(8), "\n";
?> | 
| 
	http://rosettacode.org/wiki/Amicable_pairs | 
	Amicable pairs | 
	Two integers 
N
{\displaystyle N}
 and 
M
{\displaystyle M}
 are said to be amicable pairs if 
N
≠
M
{\displaystyle N\neq M}
 and the sum of the proper divisors of 
N
{\displaystyle N}
 (
s
u
m
(
p
r
o
p
D
i
v
s
(
N
)
)
{\displaystyle \mathrm {sum} (\mathrm {propDivs} (N))}
) 
=
M
{\displaystyle =M}
 as well as 
s
u
m
(
p
r
o
p
D
i
v
s
(
M
)
)
=
N
{\displaystyle \mathrm {sum} (\mathrm {propDivs} (M))=N}
.
Example
1184 and 1210 are an amicable pair, with proper divisors:
   1, 2, 4, 8, 16, 32, 37, 74, 148, 296, 592   and 
   1, 2, 5, 10, 11, 22, 55, 110, 121, 242, 605   respectively.
Task
Calculate and show here the Amicable pairs below 20,000; (there are eight).
Related tasks
 Proper divisors
 Abundant, deficient and perfect number classifications
 Aliquot sequence classifications and its amicable classification. 
 | 
	#Perl | 
	Perl | 
	use ntheory qw/divisor_sum/;
for my $x (1..20000) {
  my $y = divisor_sum($x)-$x;
  say "$x $y" if $y > $x && $x == divisor_sum($y)-$y;
} | 
| 
	http://rosettacode.org/wiki/Animate_a_pendulum | 
	Animate a pendulum | 
	
One good way of making an animation is by simulating a physical system and illustrating the variables in that system using a dynamically changing graphical display.
The classic such physical system is a simple gravity pendulum.
Task
Create a simple physical model of a pendulum and animate it.
 | 
	#REXX | 
	REXX | 
	/*REXX program displays the   (x, y)  coördinates  (at the end of a swinging pendulum). */
parse arg cycles Plength theta .                 /*obtain optional argument from the CL.*/
if  cycles=='' |  cycles==","  then  cycles=  60 /*Not specified?  Then use the default.*/
if pLength=='' | pLength==","  then pLength=  10 /* "      "         "   "   "     "    */
if   theta=='' |   theta==","  then   theta=  30 /* "      "         "   "   "     "    */
theta= theta / 180 * pi()                        /* 'cause that's the way  Ada  did it. */
was= time('R')                                   /*obtain the current elapsed time (was)*/
g= -9.81                                         /*gravitation constant  (for earth).   */
speed= 0                                         /*velocity of the pendulum, now resting*/
         do cycles;            call delay 1/20   /*swing the pendulum a number of times.*/
         now= time('E')                          /*obtain the current time (in seconds).*/
         duration= now - was                     /*calculate duration since last cycle. */
         acceleration= g / pLength * sin(theta)  /*compute the pendulum acceleration.   */
         x= sin(theta) * pLength                 /*calculate  X  coördinate of pendulum.*/
         y= cos(theta) * pLength                 /*    "      Y       "           "     */
         speed= speed + acceleration * duration  /*calculate "   speed      "     "     */
         theta= theta + speed        * duration  /*    "     "   angle      "     "     */
         was= now                                /*save the elapsed time as it was then.*/
         say right('X: ',20)   fmt(x)      right("Y: ", 10)        fmt(y)
         end   /*cycles*/
exit 0                                           /*stick a fork in it,  we're all done. */
/*──────────────────────────────────────────────────────────────────────────────────────*/
fmt:  procedure; parse arg z;  return left('', z>=0)format(z, , digits() - 1)   /*align#*/
pi:   pi= 3.1415926535897932384626433832795028841971693993751058209749445923078; return pi
r2r:  return arg(1)  //  (pi() * 2)              /*normalize radians ──► a unit circle. */
/*──────────────────────────────────────────────────────────────────────────────────────*/
cos:  procedure; parse arg x; x=r2r(x); numeric fuzz min(6,digits()-3);  z=1;  _=1;  x=x*x
      p=z; do k=2  by 2; _=-_*x/(k*(k-1)); z=z+_;  if z=p  then leave; p=z; end;  return z
/*──────────────────────────────────────────────────────────────────────────────────────*/
sin:  procedure; parse arg x; x=r2r(x); _=x; numeric fuzz min(5, max(1,digits()-3)); q=x*x
      z=x;   do k=2  by 2  until p=z;  p= z;  _= -_*q/(k*k+k);   z= z+_;   end;   return z | 
| 
	http://rosettacode.org/wiki/Amb | 
	Amb | 
	Define and give an example of the Amb operator.
The Amb operator (short for "ambiguous") expresses nondeterminism. This doesn't refer to randomness (as in "nondeterministic universe") but is closely related to the term as it is used in automata theory ("non-deterministic finite automaton").
The Amb operator takes a variable number of expressions (or values if that's simpler in the language) and yields a correct one which will satisfy a constraint in some future computation, thereby avoiding failure.
Problems whose solution the Amb operator naturally expresses can be approached with other tools, such as explicit nested iterations over data sets, or with pattern matching. By contrast, the Amb operator appears integrated into the language. Invocations of Amb are not wrapped in any visible loops or other search patterns; they appear to be independent.
Essentially Amb(x, y, z) splits the computation into three possible futures: a future in which the value x is yielded, a future in which the value y is yielded and a future in which the value z is yielded. The future which leads to a successful subsequent computation is chosen. The other "parallel universes" somehow go away. Amb called with no arguments fails.
For simplicity, one of the domain values usable with Amb may denote failure, if that is convenient. For instance, it is convenient if a Boolean false denotes failure, so that Amb(false) fails, and thus constraints can be expressed using Boolean expressions like Amb(x * y == 8) which unless x and y add to four.
A pseudo-code program which satisfies this constraint might look like:
let x = Amb(1, 2, 3)
let y = Amb(7, 6, 4, 5)
Amb(x * y = 8)
print x, y
The output is 2 4 because Amb(1, 2, 3) correctly chooses the future in which x has value 2, Amb(7, 6, 4, 5) chooses 4 and consequently Amb(x * y = 8) produces a success.
Alternatively, failure could be represented using strictly Amb():
unless x * y = 8 do Amb()
Or else Amb could take the form of two operators or functions: one for producing values and one for enforcing constraints:
let x = Ambsel(1, 2, 3)
let y = Ambsel(4, 5, 6)
Ambassert(x * y = 8)
print x, y
where Ambassert behaves like Amb() if the Boolean expression is false, otherwise it allows the future computation to take place, without yielding any value.
The task is to somehow implement Amb, and demonstrate it with a program which chooses one word from each of the following four sets of character strings to generate a four-word sentence:
"the" "that" "a"
"frog" "elephant" "thing"
"walked" "treaded" "grows"
"slowly" "quickly"
The constraint to be satisfied is that the last character of each word (other than the last) is the same as the first character of its successor.
The only successful sentence is "that thing grows slowly"; other combinations do not satisfy the constraint and thus fail.
The goal of this task isn't to simply process the four lists of words with explicit, deterministic program flow such as nested iteration, to trivially demonstrate the correct output. The goal is to implement the Amb operator, or a facsimile thereof that is possible within the language limitations.
 | 
	#Kotlin | 
	Kotlin | 
	// version 1.2.41
import kotlin.coroutines.experimental.*
import kotlin.coroutines.experimental.intrinsics.*
 
fun main(args: Array<String>) = amb {
    val a = amb("the", "that", "a")
    val b = amb("frog", "elephant", "thing")
    val c = amb("walked", "treaded", "grows")
    val d = amb("slowly", "quickly")
 
    if (a[a.lastIndex] != b[0]) amb()
    if (b[b.lastIndex] != c[0]) amb()
    if (c[c.lastIndex] != d[0]) amb()
 
    println(listOf(a, b, c, d))
 
 
    val x = amb(1, 2, 3)
    val y = amb(7, 6, 4, 5)
    if (x * y != 8) amb()
    println(listOf(x, y))
}
 
 
class AmbException(): Exception("Refusing to execute")
data class AmbPair<T>(val cont: Continuation<T>, val valuesLeft: MutableList<T>)
 
@RestrictsSuspension
class AmbEnvironment {
    val ambList = mutableListOf<AmbPair<*>>()
 
    suspend fun <T> amb(value: T, vararg rest: T): T = suspendCoroutineOrReturn { cont -> 
        if (rest.size > 0) {
            ambList.add(AmbPair(clone(cont), mutableListOf(*rest)))
        }
 
        value
    }
 
    suspend fun amb(): Nothing = suspendCoroutine<Nothing> { }
}
 
@Suppress("UNCHECKED_CAST")
fun <R> amb(block: suspend AmbEnvironment.() -> R): R {
    var result: R? = null
    var toThrow: Throwable? = null
 
    val dist = AmbEnvironment()
    block.startCoroutine(receiver = dist, completion = object : Continuation<R> {
        override val context: CoroutineContext get() = EmptyCoroutineContext
        override fun resume(value: R) { result = value }
        override fun resumeWithException(exception: Throwable) { toThrow = exception }
    })
 
    while (result == null && toThrow == null && !dist.ambList.isEmpty()) {
        val last = dist.ambList.run { this[lastIndex] }
 
        if (last.valuesLeft.size == 1) {
            dist.ambList.removeAt(dist.ambList.lastIndex)
            last.apply {
                (cont as Continuation<Any?>).resume(valuesLeft[0])
            }
        } else {
            val value = last.valuesLeft.removeAt(last.valuesLeft.lastIndex)
            (clone(last.cont) as Continuation<Any?>).resume(value)
        }
    }
 
    if (toThrow != null)
    {
        throw toThrow!!
    }
    else if (result != null)
    {
        return result!!
    }
    else 
    {
        throw AmbException()
    }
}
 
val UNSAFE = Class.forName("sun.misc.Unsafe")
    .getDeclaredField("theUnsafe")
    .apply { isAccessible = true }
    .get(null) as sun.misc.Unsafe
 
@Suppress("UNCHECKED_CAST")
fun <T: Any> clone(obj: T): T {
    val clazz = obj::class.java
    val copy = UNSAFE.allocateInstance(clazz) as T
    copyDeclaredFields(obj, copy, clazz)
    return copy
}
 
tailrec fun <T> copyDeclaredFields(obj: T, copy: T, clazz: Class<out T>) {
    for (field in clazz.declaredFields) {
        field.isAccessible = true
        val v = field.get(obj)
        field.set(copy, if (v === obj) copy else v)
    }
    val superclass = clazz.superclass
    if (superclass != null) copyDeclaredFields(obj, copy, superclass)
} | 
| 
	http://rosettacode.org/wiki/Accumulator_factory | 
	Accumulator factory | 
	A problem posed by Paul Graham is that of creating a function that takes a single (numeric) argument and which returns another function that is an accumulator. The returned accumulator function in turn also takes a single numeric argument, and returns the sum of all the numeric values passed in so far to that accumulator (including the initial value passed when the accumulator was created).
Rules
The detailed rules are at http://paulgraham.com/accgensub.html and are reproduced here for simplicity (with additions in small italic text).
Before you submit an example, make sure the function
 Takes a number n and returns a function (lets call it g), that takes a number i, and returns n incremented by the accumulation of i from every call of function g(i).
Although these exact function and parameter names need not be used
 Works for any numeric type-- i.e. can take both ints and floats and returns functions that can take both ints and floats. (It is not enough simply to convert all input to floats. An accumulator that has only seen integers must return integers.) (i.e., if the language doesn't allow for numeric polymorphism, you have to use overloading or something like that)
 Generates functions that return the sum of every number ever passed to them, not just the most recent. (This requires a piece of state to hold the accumulated value, which in turn means that pure functional languages can't be used for this task.)
 Returns a real function, meaning something that you can use wherever you could use a function you had defined in the ordinary way in the text of your program. (Follow your language's conventions here.)
 Doesn't store the accumulated value or the returned functions in a way that could cause them to be inadvertently modified by other code. (No global variables or other such things.)
 E.g. if after the example, you added the following code (in a made-up language) where the factory function is called foo:
 x = foo(1); 
x(5); 
foo(3);
print x(2.3);
 It should print 8.3. (There is no need to print the form of the accumulator function returned by foo(3); it's not part of the task at all.)
Task
Create a function that implements the described rules.
It need not handle any special error cases not described above. The simplest way to implement the task as described is typically to use a closure, providing the language supports them.
Where it is not possible to hold exactly to the constraints above, describe the deviations.
 | 
	#Common_Lisp | 
	Common Lisp | 
	(defun accumulator (sum)
  (lambda (n)
    (incf sum n))) | 
| 
	http://rosettacode.org/wiki/Accumulator_factory | 
	Accumulator factory | 
	A problem posed by Paul Graham is that of creating a function that takes a single (numeric) argument and which returns another function that is an accumulator. The returned accumulator function in turn also takes a single numeric argument, and returns the sum of all the numeric values passed in so far to that accumulator (including the initial value passed when the accumulator was created).
Rules
The detailed rules are at http://paulgraham.com/accgensub.html and are reproduced here for simplicity (with additions in small italic text).
Before you submit an example, make sure the function
 Takes a number n and returns a function (lets call it g), that takes a number i, and returns n incremented by the accumulation of i from every call of function g(i).
Although these exact function and parameter names need not be used
 Works for any numeric type-- i.e. can take both ints and floats and returns functions that can take both ints and floats. (It is not enough simply to convert all input to floats. An accumulator that has only seen integers must return integers.) (i.e., if the language doesn't allow for numeric polymorphism, you have to use overloading or something like that)
 Generates functions that return the sum of every number ever passed to them, not just the most recent. (This requires a piece of state to hold the accumulated value, which in turn means that pure functional languages can't be used for this task.)
 Returns a real function, meaning something that you can use wherever you could use a function you had defined in the ordinary way in the text of your program. (Follow your language's conventions here.)
 Doesn't store the accumulated value or the returned functions in a way that could cause them to be inadvertently modified by other code. (No global variables or other such things.)
 E.g. if after the example, you added the following code (in a made-up language) where the factory function is called foo:
 x = foo(1); 
x(5); 
foo(3);
print x(2.3);
 It should print 8.3. (There is no need to print the form of the accumulator function returned by foo(3); it's not part of the task at all.)
Task
Create a function that implements the described rules.
It need not handle any special error cases not described above. The simplest way to implement the task as described is typically to use a closure, providing the language supports them.
Where it is not possible to hold exactly to the constraints above, describe the deviations.
 | 
	#Crystal | 
	Crystal | 
	 
# Make types a bit easier with an alias
alias Num = Int32 | Int64 | Float32 | Float64
 
def accumulator(sum : Num)
  # This proc is very similar to a Ruby lambda
  ->(n : Num){ sum += n }
end
 
x = accumulator(5)
puts x.call(5)   #=> 10
puts x.call(10)  #=> 20
puts x.call(2.4) #=> 22.4
  | 
| 
	http://rosettacode.org/wiki/Ackermann_function | 
	Ackermann function | 
	The Ackermann function is a classic example of a recursive function, notable especially because it is not a primitive recursive function. It grows very quickly in value, as does the size of its call tree.
The Ackermann function is usually defined as follows:
A
(
m
,
n
)
=
{
n
+
1
if 
m
=
0
A
(
m
−
1
,
1
)
if 
m
>
0
 and 
n
=
0
A
(
m
−
1
,
A
(
m
,
n
−
1
)
)
if 
m
>
0
 and 
n
>
0.
{\displaystyle A(m,n)={\begin{cases}n+1&{\mbox{if }}m=0\\A(m-1,1)&{\mbox{if }}m>0{\mbox{ and }}n=0\\A(m-1,A(m,n-1))&{\mbox{if }}m>0{\mbox{ and }}n>0.\end{cases}}}
Its arguments are never negative and it always terminates.
Task
Write a function which returns the value of 
A
(
m
,
n
)
{\displaystyle A(m,n)}
. Arbitrary precision is preferred (since the function grows so quickly), but not required.
See also
 Conway chained arrow notation for the Ackermann function.
 | 
	#8th | 
	8th | 
	 
\ Ackermann function, illustrating use of "memoization".
 
\ Memoization is a technique whereby intermediate computed values are stored
\ away against later need.  It is particularly valuable when calculating those
\ values is time or resource intensive, as with the Ackermann function.
 
\ make the stack much bigger so this can complete!
100000 stack-size
 
\ This is where memoized values are stored:
{} var, dict
 
\ Simple accessor words
: dict! \ "key" val --
  dict @ -rot m:! drop ;
 
: dict@ \ "key" -- val
  dict @ swap m:@ nip ;
 
defer: ack1
 
\ We just jam the string representation of the two numbers together for a key:
: makeKey  \ m n -- m n key
	2dup >s swap >s s:+ ;
 
: ack2 \ m n -- A
	makeKey dup
	dict@ null?
	if \ can't find key in dict
		\ m n key null
		drop \ m n key
		-rot \ key m n
		ack1 \ key A
		tuck \ A key A
		dict! \ A
	else \ found value
		\ m n key value
		>r drop 2drop r>
	then ;
 
: ack \ m n -- A
	over not 
	if
		nip n:1+
	else
		dup not
		if
			drop n:1- 1 ack2
		else
			over swap n:1- ack2
			swap n:1- swap ack2
		then
	then ;
 
' ack is ack1
 
: ackOf \ m n --
        2dup
        "Ack(" . swap . ", " . . ") = " . ack . cr ;
 
 
0 0 ackOf
0 4 ackOf
1 0 ackOf
1 1 ackOf
2 1 ackOf
2 2 ackOf
3 1 ackOf
3 3 ackOf
4 0 ackOf
 
\ this last requires a very large data stack.  So start 8th with a parameter '-k 100000'
4 1 ackOf
 
bye | 
| 
	http://rosettacode.org/wiki/Abundant,_deficient_and_perfect_number_classifications | 
	Abundant, deficient and perfect number classifications | 
	These define three classifications of positive integers based on their   proper divisors.
Let   P(n)   be the sum of the proper divisors of   n   where the proper divisors are all positive divisors of   n   other than   n   itself.
   if    P(n) <  n    then  n  is classed as  deficient  (OEIS A005100).
   if    P(n) == n    then  n  is classed as  perfect    (OEIS A000396).
   if    P(n) >  n    then  n  is classed as  abundant   (OEIS A005101).
Example
6   has proper divisors of   1,   2,   and   3.
1 + 2 + 3 = 6,   so   6   is classed as a perfect number.
Task
Calculate how many of the integers   1   to   20,000   (inclusive) are in each of the three classes.
Show the results here.
Related tasks
   Aliquot sequence classifications.   (The whole series from which this task is a subset.)
   Proper divisors
   Amicable pairs
 | 
	#AppleScript | 
	AppleScript | 
	on aliquotSum(n)
    if (n < 2) then return 0
    set sum to 1
    set sqrt to n ^ 0.5
    set limit to sqrt div 1
    if (limit = sqrt) then
        set sum to sum + limit
        set limit to limit - 1
    end if
    repeat with i from 2 to limit
        if (n mod i is 0) then set sum to sum + i + n div i
    end repeat
 
    return sum
end aliquotSum
 
on task()
    set {deficient, perfect, abundant} to {0, 0, 0}
    repeat with n from 1 to 20000
        set s to aliquotSum(n)
        if (s < n) then
            set deficient to deficient + 1
        else if (s > n) then
            set abundant to abundant + 1
        else
            set perfect to perfect + 1
        end if
    end repeat
 
    return {deficient:deficient, perfect:perfect, abundant:abundant}
end task
 
task() | 
| 
	http://rosettacode.org/wiki/Align_columns | 
	Align columns | 
	Given a text file of many lines, where fields within a line
are delineated by a single 'dollar' character, write a program
that aligns each column of fields by ensuring that words in each
column are separated by at least one space.
Further, allow for each word in a column to be either left
justified, right justified, or center justified within its column.
Use the following text to test your programs:
Given$a$text$file$of$many$lines,$where$fields$within$a$line$
are$delineated$by$a$single$'dollar'$character,$write$a$program
that$aligns$each$column$of$fields$by$ensuring$that$words$in$each$
column$are$separated$by$at$least$one$space.
Further,$allow$for$each$word$in$a$column$to$be$either$left$
justified,$right$justified,$or$center$justified$within$its$column.
Note that:
   The example input texts lines may, or may not, have trailing dollar characters.
   All columns should share the same alignment.
   Consecutive space characters produced adjacent to the end of lines are insignificant for the purposes of the task.
   Output text will be viewed in a mono-spaced font on a plain text editor or basic terminal.
   The minimum space between columns should be computed from the text and not hard-coded.
   It is not a requirement to add separating characters between or around columns.
Other tasks related to string operations:
Metrics
 Array length
 String length
 Copy a string
 Empty string  (assignment)
Counting
 Word frequency
 Letter frequency
 Jewels and stones
 I before E except after C
 Bioinformatics/base count
 Count occurrences of a substring
 Count how many vowels and consonants occur in a string
Remove/replace
 XXXX redacted
 Conjugate a Latin verb
 Remove vowels from a string
 String interpolation (included)
 Strip block comments
 Strip comments from a string
 Strip a set of characters from a string
 Strip whitespace from a string -- top and tail
 Strip control codes and extended characters from a string
Anagrams/Derangements/shuffling
 Word wheel
 ABC problem
 Sattolo cycle
 Knuth shuffle
 Ordered words
 Superpermutation minimisation
 Textonyms (using a phone text pad)
 Anagrams
 Anagrams/Deranged anagrams
 Permutations/Derangements
Find/Search/Determine
 ABC words
 Odd words
 Word ladder
 Semordnilap
 Word search
 Wordiff  (game)
 String matching
 Tea cup rim text
 Alternade words
 Changeable words
 State name puzzle
 String comparison
 Unique characters
 Unique characters in each string
 Extract file extension
 Levenshtein distance
 Palindrome detection
 Common list elements
 Longest common suffix
 Longest common prefix
 Compare a list of strings 
 Longest common substring
 Find common directory path
 Words from neighbour ones
 Change e letters to i in words
 Non-continuous subsequences
 Longest common subsequence
 Longest palindromic substrings
 Longest increasing subsequence
 Words containing "the" substring
 Sum of the digits of n is substring of n
 Determine if a string is numeric
 Determine if a string is collapsible
 Determine if a string is squeezable
 Determine if a string has all unique characters
 Determine if a string has all the same characters
 Longest substrings without repeating characters
 Find words which contains all the vowels
 Find words which contains most consonants
 Find words which contains more than 3 vowels
 Find words which first and last three letters are equals
 Find words which odd letters are consonants and even letters are vowels or vice_versa
Formatting
 Substring
 Rep-string
 Word wrap
 String case
 Align columns
 Literals/String
 Repeat a string
 Brace expansion
 Brace expansion using ranges
 Reverse a string
 Phrase reversals
 Comma quibbling
 Special characters
 String concatenation
 Substring/Top and tail
 Commatizing numbers
 Reverse words in a string
 Suffixation of decimal numbers
 Long literals, with continuations 
 Numerical and alphabetical suffixes
 Abbreviations, easy
 Abbreviations, simple
 Abbreviations, automatic
Song lyrics/poems/Mad Libs/phrases
 Mad Libs
 Magic 8-ball
 99 Bottles of Beer
 The Name Game (a song)
 The Old lady swallowed a fly
 The Twelve Days of Christmas
Tokenize
 Text between
 Tokenize a string
 Word break problem
 Tokenize a string with escaping
 Split a character string based on change of character
Sequences
 Show ASCII table
 De Bruijn sequences
 Self-referential sequences
 Generate lower case ASCII alphabet
 | 
	#AutoIt | 
	AutoIt | 
	 
; == If the given text is in an file, it will read with:
#include <File.au3>
Global $aRead
_FileReadToArray($sPath, $aRead)  ; == $aRead[0] includes count of lines, every line stored in one item (without linebreak)
 
; == For example we get the same result with StringSplit()
Global $sText = _
"Given$a$text$file$of$many$lines,$where$fields$within$a$line$" & @CRLF & _
"are$delineated$by$a$single$'dollar'$character,$write$a$program" & @CRLF & _
"that$aligns$each$column$of$fields$by$ensuring$that$words$in$each$" & @CRLF & _
"column$are$separated$by$at$least$one$space." & @CRLF & _
"Further,$allow$for$each$word$in$a$column$to$be$either$left$" & @CRLF & _
"justified,$right$justified,$or$center$justified$within$its$column." & @CRLF
 
$aRead = StringSplit($sText, @CRLF, 1)
 
; == strip leading and trailing "$" and trailing spaces, count remaining "$" to get max column number
Global $iMaxColumn = 0, $iLines = 0
For $i = 1 To $aRead[0]
	If $aRead[$i] = '' Then ContinueLoop   ; skip empty lines
	$iLines += 1
	$aRead[$i] = StringRegExpReplace(StringRegExpReplace(StringRegExpReplace($aRead[$i], '^\$', ''), '\$$', ''), '\s*$', '')
	StringReplace($aRead[$i], '$', '$')
	If @extended +1 > $iMaxColumn Then $iMaxColumn = @extended +1
Next
 
; == build array to store all fields and length of every item
Global $aFields[$iLines][$iMaxColumn +1][2]
; == and store the max. length of item in columns
Global $aColLen[$iMaxColumn]
 
; == fill the array
Global $aSplitLine
$iLines = 0
For $i = 1 To $aRead[0]
	If $aRead[$i] = '' Then ContinueLoop   ; skip empty lines
	$iMaxColLen = 0
	$aSplitLine = StringSplit($aRead[$i], '$')
	For $j = 1 To $aSplitLine[0]
		$aFields[$iLines][$j-1][0] = $aSplitLine[$j]
		$aFields[$iLines][$j-1][1] = StringLen($aSplitLine[$j])
		If $aFields[$iLines][$j-1][1] > $aColLen[$j-1] Then $aColLen[$j-1] = $aFields[$iLines][$j-1][1]
	Next
	$iLines += 1
Next
 
; == let the user select the alignment for every column
$sAlign = InputBox('Column alignment', 'There are ' & $iMaxColumn & ' columns.' & @LF & '0 = left    1 = center    2 = right' & @LF &  _
                   'Input alignment for all columns without delimiters.' & @LF & 'Let it empty, to align all left.')
If $sAlign = '' Then
	For $i = 1 To $iMaxColumn
		$sAlign &= '0'
	Next
EndIf
Global $aAlignment = StringSplit($sAlign, '', 2)
 
; == output all to console
Global $sLineOut
For $i = 0 To UBound($aFields) -1
	$sLineOut = ''
	For $j = 0 To $iMaxColumn -1
		If $aFields[$i][$j][0] = '' Then ContinueLoop
		$sLineOut &= _GetAligned($aFields[$i][$j][0], $aFields[$i][$j][1], $aAlignment[$j], $aColLen[$j])
	Next
	ConsoleWrite(StringTrimRight($sLineOut, 1) & @LF)
Next
 
Func _GetAligned($_sString, $_iLen, $_iAlign, $_iMaxLen)
	Local $sSpace = ''
	For $i = 1 To $_iMaxLen
		$sSpace &= ' '
	Next
	Switch $_iAlign
		Case 0
			Return $_sString & StringLeft($sSpace, $_iMaxLen - $_iLen +1)
		Case 1
			Local $iLenLeft = Int(($_iMaxLen - $_iLen)/2)
			Local $iLenRight = $_iMaxLen - $iLenLeft - $_iLen
			Return StringLeft($sSpace, $iLenLeft) & $_sString & StringLeft($sSpace, $iLenRight) & ' '
		Case 2
			Return StringLeft($sSpace, $_iMaxLen - $_iLen) & $_sString & ' '
	EndSwitch
EndFunc  ;==>_GetAligned
  | 
| 
	http://rosettacode.org/wiki/Active_object | 
	Active object | 
	In object-oriented programming an object is active when its state depends on clock. Usually an active object encapsulates a task that updates the object's state. To the outer world the object looks like a normal object with methods that can be called from outside. Implementation of such methods must have a certain synchronization mechanism with the encapsulated task in order to prevent object's state corruption.
A typical instance of an active object is an animation widget. The widget state changes with the time, while as an object it has all properties of a normal widget.
The task
Implement an active integrator object. The object has an input and output. The input can be set using the method Input. The input is a function of time. The output can be queried using the method Output. The object integrates its input over the time and the result becomes the object's output. So if the input is K(t) and the output is S, the object state S is changed to S + (K(t1) + K(t0)) * (t1 - t0) / 2, i.e. it integrates K using the trapeze method. Initially K is constant 0 and S is 0.
In order to test the object:
 set its input to sin (2π f t), where the frequency f=0.5Hz. The phase is irrelevant.
 wait 2s
 set the input to constant 0
 wait 0.5s
Verify that now the object's output is approximately 0 (the sine has the period of 2s). The accuracy of the result will depend on the OS scheduler time slicing and the accuracy of the clock.
 | 
	#FreeBASIC | 
	FreeBASIC | 
	#define twopi 6.2831853071795864769252867665590057684
dim shared as double S = 0     'set up the state as a global variable
dim shared as double t0, t1, ta
 
function sine( x as double, f as double ) as double
    return sin(twopi*f*x)
end function
 
function zero( x as double, f as double ) as double
    return 0
end function
 
sub integrate( K as function(as double, as double) as double, f as double )
    'represent input as pointers to functions
    t1 = timer
    s += (K(t1,f) + K(t0,f))*(t1-t0)/2.0
    t0 = t1
end sub
 
t0 = timer
ta = timer
 
while timer-ta <= 2.5
    if timer-ta <= 2 then integrate( @sine, 0.5 ) else integrate( @zero, 0 )
wend
 
print S
  | 
| 
	http://rosettacode.org/wiki/Active_object | 
	Active object | 
	In object-oriented programming an object is active when its state depends on clock. Usually an active object encapsulates a task that updates the object's state. To the outer world the object looks like a normal object with methods that can be called from outside. Implementation of such methods must have a certain synchronization mechanism with the encapsulated task in order to prevent object's state corruption.
A typical instance of an active object is an animation widget. The widget state changes with the time, while as an object it has all properties of a normal widget.
The task
Implement an active integrator object. The object has an input and output. The input can be set using the method Input. The input is a function of time. The output can be queried using the method Output. The object integrates its input over the time and the result becomes the object's output. So if the input is K(t) and the output is S, the object state S is changed to S + (K(t1) + K(t0)) * (t1 - t0) / 2, i.e. it integrates K using the trapeze method. Initially K is constant 0 and S is 0.
In order to test the object:
 set its input to sin (2π f t), where the frequency f=0.5Hz. The phase is irrelevant.
 wait 2s
 set the input to constant 0
 wait 0.5s
Verify that now the object's output is approximately 0 (the sine has the period of 2s). The accuracy of the result will depend on the OS scheduler time slicing and the accuracy of the clock.
 | 
	#Go | 
	Go | 
	package main
 
import (
    "fmt"
    "math"
    "time"
)
 
// type for input function, k.
// input is duration since an arbitrary start time t0.
type tFunc func(time.Duration) float64
 
// active integrator object.  state variables are not here, but in
// function aif, started as a goroutine in the constructor.
type aio struct {
    iCh chan tFunc        // channel for setting input function
    oCh chan chan float64 // channel for requesting output
}
 
// constructor
func newAio() *aio {
    var a aio
    a.iCh = make(chan tFunc)
    a.oCh = make(chan chan float64)
    go aif(&a)
    return &a
}
 
// input method required by task description.  in practice, this method is
// unnecessary; you would just put that single channel send statement in
// your code wherever you wanted to set the input function.
func (a aio) input(f tFunc) {
    a.iCh <- f
}
 
// output method required by task description.  in practice, this method too
// would not likely be best.  instead any client interested in the value would
// likely make a return channel sCh once, and then reuse it as needed.
func (a aio) output() float64 {
    sCh := make(chan float64)
    a.oCh <- sCh
    return <-sCh
}
 
// integration function that returns constant 0
func zeroFunc(time.Duration) float64 { return 0 }
 
// goroutine serializes access to integrated function k and state variable s
func aif(a *aio) {
    var k tFunc = zeroFunc // integration function
    s := 0.                // "object state" initialized to 0
    t0 := time.Now()       // initial time
    k0 := k(0)             // initial sample value
    t1 := t0               // t1, k1 used for trapezoid formula
    k1 := k0
 
    tk := time.Tick(10 * time.Millisecond) // 10 ms -> 100 Hz
    for {
        select {
        case t2 := <-tk: // timer tick event
            k2 := k(t2.Sub(t0))                        // new sample value
            s += (k1 + k2) * .5 * t2.Sub(t1).Seconds() // trapezoid formula
            t1, k1 = t2, k2                            // save time and value
        case k = <-a.iCh: // input method event: function change
        case sCh := <-a.oCh: // output method event: sample object state
            sCh <- s
        }
    }
}
 
func main() {
    a := newAio()                           // create object
    a.input(func(t time.Duration) float64 { // 1. set input to sin function
        return math.Sin(t.Seconds() * math.Pi)
    })
    time.Sleep(2 * time.Second) // 2. sleep 2 sec
    a.input(zeroFunc)           // 3. set input to zero function
    time.Sleep(time.Second / 2) // 4. sleep .5 sec
    fmt.Println(a.output())     // output should be near zero
} | 
| 
	http://rosettacode.org/wiki/Aliquot_sequence_classifications | 
	Aliquot sequence classifications | 
	An aliquot sequence of a positive integer K is defined recursively as the first member
being K and subsequent members being the sum of the Proper divisors of the previous term.
 If the terms eventually reach 0 then the series for K is said to terminate.
There are several classifications for non termination:
 If the second term is K then all future terms are also K and so the sequence repeats from the first term with period 1 and K is called perfect.
 If the third term would be repeating K then the sequence repeats with period 2 and K is called amicable.
 If the Nth term would be repeating K for the first time, with N > 3 then the sequence repeats with period N - 1 and K is called sociable.
Perfect, amicable and sociable numbers eventually repeat the original number K; there are other repetitions...
 Some K have a sequence that eventually forms a periodic repetition of period 1 but of a number other than K, for example 95 which forms the sequence 95, 25, 6, 6, 6, ... such K are called aspiring.
 K that have a sequence that eventually forms a periodic repetition of period >= 2 but of a number other than K, for example 562 which forms the sequence 562, 284, 220, 284, 220, ... such K are called cyclic.
And finally:
 Some K form aliquot sequences that are not known to be either terminating or periodic; these K are to be called non-terminating. 
For the purposes of this task, K is to be classed as non-terminating if it has not been otherwise classed after generating 16 terms or if any term of the sequence is greater than 2**47 = 140,737,488,355,328. 
Task
 Create routine(s) to generate the aliquot sequence of a positive integer enough to classify it according to the classifications given above.
 Use it to display the classification and sequences of the numbers one to ten inclusive.
 Use it to show the classification and sequences of the following integers, in order:
 11, 12, 28, 496, 220, 1184, 12496, 1264460, 790, 909, 562, 1064, 1488, and optionally 15355717786080.
Show all output on this page.
Related tasks
   Abundant, deficient and perfect number classifications. (Classifications from only the first two members of the whole sequence).
   Proper divisors
   Amicable pairs
 | 
	#Liberty_BASIC | 
	Liberty BASIC | 
	 
print "ROSETTA CODE - Aliquot sequence classifications"
[Start]
input "Enter an integer: "; K
K=abs(int(K)): if K=0 then goto [Quit]
call PrintAS K
goto [Start]
 
[Quit]
print "Program complete."
end
 
sub PrintAS K
    Length=52
    dim Aseq(Length)
    n=K: class=0
    for element=2 to Length
        Aseq(element)=PDtotal(n)
        print Aseq(element); " ";
        select case
            case Aseq(element)=0
                print " terminating": class=1: exit for
            case Aseq(element)=K and element=2
                print " perfect": class=2: exit for
            case Aseq(element)=K and element=3
                print " amicable": class=3: exit for
            case Aseq(element)=K and element>3
                print " sociable": class=4: exit for
            case Aseq(element)<>K and Aseq(element-1)=Aseq(element)
                print " aspiring": class=5: exit for
            case Aseq(element)<>K and Aseq(element-2)= Aseq(element)
                print " cyclic": class=6: exit for
        end select
        n=Aseq(element)
        if n>priorn then priorn=n: inc=inc+1 else inc=0: priorn=0
        if inc=11 or n>30000000 then exit for
    next element
    if class=0 then print " non-terminating"
end sub
 
function PDtotal(n)
    for y=2 to n
        if (n mod y)=0 then PDtotal=PDtotal+(n/y)
    next
end function
  | 
| 
	http://rosettacode.org/wiki/Add_a_variable_to_a_class_instance_at_runtime | 
	Add a variable to a class instance at runtime | 
	Demonstrate how to dynamically add variables to an object (a class instance) at runtime.
This is useful when the methods/variables of an instance are based on a data file that isn't available until runtime. Hal Fulton gives an example of creating an OO CSV parser at An Exercise in Metaprogramming with Ruby. This is referred to as "monkeypatching" by Pythonistas and some others.
 | 
	#Wren | 
	Wren | 
	import "io" for Stdin, Stdout
 
class Birds {
    construct new(userFields) {
        _userFields = userFields
    }
    userFields { _userFields }
}
 
var userFields = {}
System.print("Enter three fields to add to the Birds class:")
for (i in 0..2) {
    System.write("\n  name : ")
    Stdout.flush()
    var name = Stdin.readLine()
    System.write("  value: ")
    Stdout.flush()
    var value = Num.fromString(Stdin.readLine())
    userFields[name] = value
}
 
var birds = Birds.new(userFields)
 
System.print("\nYour fields are:\n")
for (kv in birds.userFields) {
    System.print("  %(kv.key) = %(kv.value)")
} | 
| 
	http://rosettacode.org/wiki/Add_a_variable_to_a_class_instance_at_runtime | 
	Add a variable to a class instance at runtime | 
	Demonstrate how to dynamically add variables to an object (a class instance) at runtime.
This is useful when the methods/variables of an instance are based on a data file that isn't available until runtime. Hal Fulton gives an example of creating an OO CSV parser at An Exercise in Metaprogramming with Ruby. This is referred to as "monkeypatching" by Pythonistas and some others.
 | 
	#XBS | 
	XBS | 
	set Object = {}
Object.Hello = "World";
log(Object.Hello); | 
| 
	http://rosettacode.org/wiki/Address_of_a_variable | 
	Address of a variable | 
	
Basic Data Operation
This is a basic data operation. It represents a fundamental action on a basic data type.
You may see other such operations in the Basic Data Operations category, or:
Integer Operations
Arithmetic |
Comparison
Boolean Operations
Bitwise |
Logical
String Operations
Concatenation |
Interpolation |
Comparison |
Matching
Memory Operations
Pointers & references |
Addresses
Task
Demonstrate how to get the address of a variable and how to set the address of a variable.
 | 
	#Stata | 
	Stata | 
	a = 1
&a
 
function f(x) {
	return(x+1)
}
 
&f() | 
| 
	http://rosettacode.org/wiki/Address_of_a_variable | 
	Address of a variable | 
	
Basic Data Operation
This is a basic data operation. It represents a fundamental action on a basic data type.
You may see other such operations in the Basic Data Operations category, or:
Integer Operations
Arithmetic |
Comparison
Boolean Operations
Bitwise |
Logical
String Operations
Concatenation |
Interpolation |
Comparison |
Matching
Memory Operations
Pointers & references |
Addresses
Task
Demonstrate how to get the address of a variable and how to set the address of a variable.
 | 
	#Swift | 
	Swift | 
	 
class MyClass { }
 
func printAddress<T>(of pointer: UnsafePointer<T>) {
    print(pointer)
}
 
func test() {
    var x = 42
    var y = 3.14
    var z = "foo"
    var obj = MyClass()
 
    // Use a pointer to a variable on the stack and print its address.
    withUnsafePointer(to: &x)   { print($0) }
    withUnsafePointer(to: &y)   { print($0) }
    withUnsafePointer(to: &z)   { print($0) }
    withUnsafePointer(to: &obj) { print($0) }
 
    // Alternately:
    printAddress(of: &x)
    printAddress(of: &y)
    printAddress(of: &z)
    printAddress(of: &obj)
 
    // Printing the address of an object that an object reference points to.
    print(Unmanaged.passUnretained(obj).toOpaque())
}
 
test()
  | 
| 
	http://rosettacode.org/wiki/Address_of_a_variable | 
	Address of a variable | 
	
Basic Data Operation
This is a basic data operation. It represents a fundamental action on a basic data type.
You may see other such operations in the Basic Data Operations category, or:
Integer Operations
Arithmetic |
Comparison
Boolean Operations
Bitwise |
Logical
String Operations
Concatenation |
Interpolation |
Comparison |
Matching
Memory Operations
Pointers & references |
Addresses
Task
Demonstrate how to get the address of a variable and how to set the address of a variable.
 | 
	#Tcl | 
	Tcl | 
	package require critcl
# This code assumes an ILP32 architecture, like classic x86 or VAX.
critcl::cproc peek {int addr} int {
    union {
       int i;
       int *a;
    } u;
 
    u.i = addr;
    return *u.a;
}
critcl::cproc poke {int addr int value} void {
    union {
        int i;
        int *a;
    } u;
 
    u.i = addr;
    *u.a = value;
}
package provide poker 1.0 | 
| 
	http://rosettacode.org/wiki/Address_of_a_variable | 
	Address of a variable | 
	
Basic Data Operation
This is a basic data operation. It represents a fundamental action on a basic data type.
You may see other such operations in the Basic Data Operations category, or:
Integer Operations
Arithmetic |
Comparison
Boolean Operations
Bitwise |
Logical
String Operations
Concatenation |
Interpolation |
Comparison |
Matching
Memory Operations
Pointers & references |
Addresses
Task
Demonstrate how to get the address of a variable and how to set the address of a variable.
 | 
	#Toka | 
	Toka | 
	variable foo
foo .
 | 
| 
	http://rosettacode.org/wiki/AKS_test_for_primes | 
	AKS test for primes | 
	The AKS algorithm for testing whether a number is prime is a polynomial-time algorithm based on an elementary theorem about Pascal triangles.
The theorem on which the test is based can be stated as follows:
   a number   
p
{\displaystyle p}
   is prime   if and only if   all the coefficients of the polynomial expansion of
 
(
x
−
1
)
p
−
(
x
p
−
1
)
{\displaystyle (x-1)^{p}-(x^{p}-1)}
are divisible by   
p
{\displaystyle p}
.
Example
Using   
p
=
3
{\displaystyle p=3}
:
         (x-1)^3 - (x^3 - 1)
            = (x^3 - 3x^2 + 3x - 1) - (x^3 - 1)
            = -3x^2 + 3x
And all the coefficients are divisible by 3,   so 3 is prime.
 Note:
This task is not the AKS primality test.   It is an inefficient exponential time algorithm discovered in the late 1600s and used as an introductory lemma in the AKS derivation.
Task
 Create a function/subroutine/method that given   
p
{\displaystyle p}
   generates the coefficients of the expanded polynomial representation of   
(
x
−
1
)
p
{\displaystyle (x-1)^{p}}
.
 Use the function to show here the polynomial expansions of   
(
x
−
1
)
p
{\displaystyle (x-1)^{p}}
   for   
p
{\displaystyle p}
   in the range   0   to at least   7,   inclusive.
 Use the previous function in creating another function that when given   
p
{\displaystyle p}
   returns whether   
p
{\displaystyle p}
   is prime using the theorem.
 Use your test to generate a list of all primes under   35.
 As a stretch goal,   generate all primes under   50   (needs integers larger than 31-bit).
References
 Agrawal-Kayal-Saxena (AKS) primality test (Wikipedia) 
 Fool-Proof Test for Primes - Numberphile (Video). The accuracy of this video is disputed -- at best it is an oversimplification.
 | 
	#Fortran | 
	Fortran | 
	 
program aks
  implicit none
 
  ! Coefficients of polynomial expansion
  integer(kind=16), dimension(:), allocatable :: coeffs
  integer(kind=16) :: n
  ! Character variable for I/O
  character(len=40) :: tmp
 
  ! Point #2
  do n = 0, 7
    write(tmp, *) n
    call polynomial_expansion(n, coeffs)
    write(*, fmt='(A)', advance='no') '(x - 1)^'//trim(adjustl(tmp))//' ='
    call print_polynom(coeffs)
  end do
 
  ! Point #4
  do n = 2, 35
    if (is_prime(n)) write(*, '(I4)', advance='no') n
  end do
  write(*, *)
 
  ! Point #5
  do n = 2, 124
    if (is_prime(n)) write(*, '(I4)', advance='no') n
  end do
  write(*, *)
 
  if (allocated(coeffs)) deallocate(coeffs)
contains
  ! Calculate coefficients of (x - 1)^n using binomial theorem
  subroutine polynomial_expansion(n, coeffs)
    integer(kind=16), intent(in) :: n
    integer(kind=16), dimension(:), allocatable, intent(out) :: coeffs
    integer(kind=16) :: i, j
 
    if (allocated(coeffs)) deallocate(coeffs)
 
    allocate(coeffs(n + 1))
 
    do i = 1, n + 1
      coeffs(i) = binomial(n, i - 1)*(-1)**(n - i - 1)
    end do
  end subroutine
 
  ! Calculate binomial coefficient using recurrent relation, as calculation
  ! using factorial overflows too quickly.
  function binomial(n, k) result (res)
    integer(kind=16), intent(in) :: n, k
    integer(kind=16) :: res
    integer(kind=16) :: i
 
    if (k == 0) then
      res = 1
      return
    end if
 
    res = 1
    do i = 0, k - 1
      res = res*(n - i)/(i + 1)
    end do
  end function
 
  ! Outputs polynomial with given coefficients
  subroutine print_polynom(coeffs)
    integer(kind=16), dimension(:), allocatable, intent(in) :: coeffs
    integer(kind=4) :: i, p
    character(len=40) :: cbuf, pbuf
    logical(kind=1) :: non_zero
 
    if (.not. allocated(coeffs)) return
 
    non_zero = .false.
 
    do i = 1, size(coeffs)
      if (coeffs(i) .eq. 0) cycle
 
      p = i - 1
      write(cbuf, '(I40)') abs(coeffs(i))
      write(pbuf, '(I40)') p 
 
      if (non_zero) then
        if (coeffs(i) .gt. 0) then
          write(*, fmt='(A)', advance='no') ' + '
        else
          write(*, fmt='(A)', advance='no') ' - '
        endif
      else
        if (coeffs(i) .gt. 0) then
          write(*, fmt='(A)', advance='no') '   '
        else
          write(*, fmt='(A)', advance='no') ' - '
        endif
      endif
 
      if (p .eq. 0) then
        write(*, fmt='(A)', advance='no') trim(adjustl(cbuf))
      elseif (p .eq. 1) then
        if (coeffs(i) .eq. 1) then
          write(*, fmt='(A)', advance='no') 'x'
        else
          write(*, fmt='(A)', advance='no') trim(adjustl(cbuf))//'x'
        end if
      else
        if (coeffs(i) .eq. 1) then
          write(*, fmt='(A)', advance='no') 'x^'//trim(adjustl(pbuf))
        else
          write(*, fmt='(A)', advance='no') &
            trim(adjustl(cbuf))//'x^'//trim(adjustl(pbuf))
        end if
      end if
      non_zero = .true.
    end do
 
    write(*, *)
  end subroutine
 
  ! Test if n is prime using AKS test. Point #3.
  function is_prime(n) result (res)
    integer(kind=16), intent (in) :: n
    logical(kind=1) :: res
    integer(kind=16), dimension(:), allocatable :: coeffs
    integer(kind=16) :: i
 
    call polynomial_expansion(n, coeffs)
    coeffs(1) = coeffs(1) + 1
    coeffs(n + 1) = coeffs(n + 1) - 1
 
    res = .true.
 
    do i = 1, n + 1
      res = res .and. (mod(coeffs(i), n) == 0)
    end do
 
    if (allocated(coeffs)) deallocate(coeffs)
  end function
end program aks
  | 
| 
	http://rosettacode.org/wiki/Additive_primes | 
	Additive primes | 
	Definitions
In mathematics, additive primes are prime numbers for which the sum of their decimal digits are also primes.
Task
Write a program to determine (and show here) all additive primes less than 500.
Optionally, show the number of additive primes.
Also see
   the OEIS entry:   A046704 additive primes.
   the prime-numbers entry:   additive primes.
   the geeks for geeks entry: additive prime number.
   the prime-numbers fandom: additive primes.
 | 
	#Nim | 
	Nim | 
	import math, strutils
 
const N = 499
 
# Sieve of Erathostenes.
var composite: array[2..N, bool]  # Initialized to false, ie. prime.
 
for n in 2..sqrt(N.toFloat).int:
  if not composite[n]:
    for k in countup(n * n, N, n):
      composite[k] = true
 
 
func digitSum(n: Positive): Natural =
  ## Compute sum of digits.
  var n = n.int
  while n != 0:
    result += n mod 10
    n = n div 10
 
 
echo "Additive primes less than 500:"
var count = 0
for n in 2..N:
  if not composite[n] and not composite[digitSum(n)]:
    inc count
    stdout.write ($n).align(3)
    stdout.write if count mod 10 == 0: '\n' else: ' '
echo()
 
echo "\nNumber of additive primes found: ", count | 
| 
	http://rosettacode.org/wiki/Additive_primes | 
	Additive primes | 
	Definitions
In mathematics, additive primes are prime numbers for which the sum of their decimal digits are also primes.
Task
Write a program to determine (and show here) all additive primes less than 500.
Optionally, show the number of additive primes.
Also see
   the OEIS entry:   A046704 additive primes.
   the prime-numbers entry:   additive primes.
   the geeks for geeks entry: additive prime number.
   the prime-numbers fandom: additive primes.
 | 
	#Pari.2FGP | 
	Pari/GP | 
	hasPrimeDigitsum(n)=isprime(sumdigits(n)); \\ see A028834 in the OEIS
 
v1 = select(isprime, select(hasPrimeDigitsum, [1..499]));
v2 = select(hasPrimeDigitsum, select(isprime, [1..499]));
v3 = select(hasPrimeDigitsum, primes([1, 499]));
 
s=0; forprime(p=2,499, if(hasPrimeDigitsum(p), s++)); s;
[#v1, #v2, #v3, s] | 
| 
	http://rosettacode.org/wiki/Almost_prime | 
	Almost prime | 
	A   k-Almost-prime   is a natural number   
n
{\displaystyle n}
   that is the product of   
k
{\displaystyle k}
   (possibly identical) primes.
Example
1-almost-primes,   where   
k
=
1
{\displaystyle k=1}
,   are the prime numbers themselves.
2-almost-primes,   where   
k
=
2
{\displaystyle k=2}
,   are the   semiprimes.
Task
Write a function/method/subroutine/... that generates k-almost primes and use it to create a table here of the first ten members of k-Almost primes for   
1
<=
K
<=
5
{\displaystyle 1<=K<=5}
.
Related tasks
   Semiprime
   Category:Prime Numbers
 | 
	#Lua | 
	Lua | 
	-- Returns boolean indicating whether n is k-almost prime
function almostPrime (n, k)
    local divisor, count = 2, 0
    while count < k + 1 and n ~= 1 do
        if n % divisor == 0 then
            n = n / divisor
            count = count + 1
        else
            divisor = divisor + 1
        end
    end
    return count == k
end
 
-- Generates table containing first ten k-almost primes for given k
function kList (k)
    local n, kTab = 2^k, {}
    while #kTab < 10 do
        if almostPrime(n, k) then
            table.insert(kTab, n)
        end
        n = n + 1
    end
    return kTab
end
 
-- Main procedure, displays results from five calls to kList()
for k = 1, 5 do
    io.write("k=" .. k .. ": ")
    for _, v in pairs(kList(k)) do
        io.write(v .. ", ")
    end
    print("...")
end | 
| 
	http://rosettacode.org/wiki/Anagrams | 
	Anagrams | 
	When two or more words are composed of the same characters, but in a different order, they are called anagrams.
Task[edit]
Using the word list at   http://wiki.puzzlers.org/pub/wordlists/unixdict.txt,
find the sets of words that share the same characters that contain the most words in them.
Related tasks
Word plays
Ordered words
Palindrome detection
Semordnilap
Anagrams
Anagrams/Deranged anagrams
Other tasks related to string operations:
Metrics
 Array length
 String length
 Copy a string
 Empty string  (assignment)
Counting
 Word frequency
 Letter frequency
 Jewels and stones
 I before E except after C
 Bioinformatics/base count
 Count occurrences of a substring
 Count how many vowels and consonants occur in a string
Remove/replace
 XXXX redacted
 Conjugate a Latin verb
 Remove vowels from a string
 String interpolation (included)
 Strip block comments
 Strip comments from a string
 Strip a set of characters from a string
 Strip whitespace from a string -- top and tail
 Strip control codes and extended characters from a string
Anagrams/Derangements/shuffling
 Word wheel
 ABC problem
 Sattolo cycle
 Knuth shuffle
 Ordered words
 Superpermutation minimisation
 Textonyms (using a phone text pad)
 Anagrams
 Anagrams/Deranged anagrams
 Permutations/Derangements
Find/Search/Determine
 ABC words
 Odd words
 Word ladder
 Semordnilap
 Word search
 Wordiff  (game)
 String matching
 Tea cup rim text
 Alternade words
 Changeable words
 State name puzzle
 String comparison
 Unique characters
 Unique characters in each string
 Extract file extension
 Levenshtein distance
 Palindrome detection
 Common list elements
 Longest common suffix
 Longest common prefix
 Compare a list of strings 
 Longest common substring
 Find common directory path
 Words from neighbour ones
 Change e letters to i in words
 Non-continuous subsequences
 Longest common subsequence
 Longest palindromic substrings
 Longest increasing subsequence
 Words containing "the" substring
 Sum of the digits of n is substring of n
 Determine if a string is numeric
 Determine if a string is collapsible
 Determine if a string is squeezable
 Determine if a string has all unique characters
 Determine if a string has all the same characters
 Longest substrings without repeating characters
 Find words which contains all the vowels
 Find words which contains most consonants
 Find words which contains more than 3 vowels
 Find words which first and last three letters are equals
 Find words which odd letters are consonants and even letters are vowels or vice_versa
Formatting
 Substring
 Rep-string
 Word wrap
 String case
 Align columns
 Literals/String
 Repeat a string
 Brace expansion
 Brace expansion using ranges
 Reverse a string
 Phrase reversals
 Comma quibbling
 Special characters
 String concatenation
 Substring/Top and tail
 Commatizing numbers
 Reverse words in a string
 Suffixation of decimal numbers
 Long literals, with continuations 
 Numerical and alphabetical suffixes
 Abbreviations, easy
 Abbreviations, simple
 Abbreviations, automatic
Song lyrics/poems/Mad Libs/phrases
 Mad Libs
 Magic 8-ball
 99 Bottles of Beer
 The Name Game (a song)
 The Old lady swallowed a fly
 The Twelve Days of Christmas
Tokenize
 Text between
 Tokenize a string
 Word break problem
 Tokenize a string with escaping
 Split a character string based on change of character
Sequences
 Show ASCII table
 De Bruijn sequences
 Self-referential sequences
 Generate lower case ASCII alphabet
 | 
	#Elena | 
	Elena | 
	import system'routines;
import system'calendar;
import system'io;
import system'collections;
import extensions;
import extensions'routines;
import extensions'text;
 
extension op
{
     string normalized()
         = self.toArray().ascendant().summarize(new StringWriter());
}
 
public program()
{
    var start := now;
 
    auto dictionary := new Map<string,object>();
 
    File.assign("unixdict.txt").forEachLine:(word)
    {
        var key := word.normalized();
        var item := dictionary[key];
        if (nil == item)
        {
            item := new ArrayList();
            dictionary[key] := item
        };
 
        item.append:word
    };
 
    dictionary.Values
        .sort:(former,later => former.Item2.Length > later.Item2.Length )
        .top:20
        .forEach:(pair){ console.printLine(pair.Item2) };
 
    var end := now;
 
    var diff := end - start;
 
    console.printLine("Time elapsed in msec:",diff.Milliseconds);
 
    console.readChar()
} | 
| 
	http://rosettacode.org/wiki/Angle_difference_between_two_bearings | 
	Angle difference between two bearings | 
	Finding the angle between two bearings is often confusing.[1]
Task
Find the angle which is the result of the subtraction b2 - b1, where b1 and b2 are the bearings.
Input bearings are expressed in the range   -180   to   +180   degrees.
The  result  is also expressed in the range   -180   to   +180   degrees.
Compute the angle for the following pairs:
 20 degrees (b1) and 45 degrees (b2)
 -45 and 45
 -85 and 90
 -95 and 90
 -45 and 125
 -45 and 145
 29.4803 and -88.6381
 -78.3251 and -159.036
Optional extra
 
Allow the input bearings to be any (finite) value.
Test cases
 -70099.74233810938 and 29840.67437876723
 -165313.6666297357 and 33693.9894517456
 1174.8380510598456 and -154146.66490124757
 60175.77306795546 and 42213.07192354373
 | 
	#Run_BASIC | 
	Run BASIC | 
	sub getDifference b1, b2
    r = (b2 - b1) mod 360
    if r >= 180 then r = r - 360
    print r
end sub
 
print "Input in -180 to +180 range:"
call getDifference  20, 45 
call getDifference -45, 45 
call getDifference -85, 90
call getDifference -95, 90
call getDifference -45, 125
call getDifference -45, 145
call getDifference -45, 125
call getDifference -45, 145
call getDifference  29.4803, -88.6381
call getDifference -78.3251, -159.036
print "Input in wider range:"
call getDifference -70099.74233810938, 29840.67437876723
call getDifference -165313.6666297357, 33693.9894517456
call getDifference 1174.8380510598456, -154146.66490124757 | 
| 
	http://rosettacode.org/wiki/Angle_difference_between_two_bearings | 
	Angle difference between two bearings | 
	Finding the angle between two bearings is often confusing.[1]
Task
Find the angle which is the result of the subtraction b2 - b1, where b1 and b2 are the bearings.
Input bearings are expressed in the range   -180   to   +180   degrees.
The  result  is also expressed in the range   -180   to   +180   degrees.
Compute the angle for the following pairs:
 20 degrees (b1) and 45 degrees (b2)
 -45 and 45
 -85 and 90
 -95 and 90
 -45 and 125
 -45 and 145
 29.4803 and -88.6381
 -78.3251 and -159.036
Optional extra
 
Allow the input bearings to be any (finite) value.
Test cases
 -70099.74233810938 and 29840.67437876723
 -165313.6666297357 and 33693.9894517456
 1174.8380510598456 and -154146.66490124757
 60175.77306795546 and 42213.07192354373
 | 
	#Rust | 
	Rust | 
	 
/// Calculate difference between two bearings, in -180 to 180 degrees range
pub fn angle_difference(bearing1: f64, bearing2: f64) -> f64 {
    let diff = (bearing2 - bearing1) % 360.0;
    if diff < -180.0 {
        360.0 + diff
    } else if diff > 180.0 {
        -360.0 + diff
    } else {
        diff
    }
 
}
 
#[cfg(test)]
mod tests {
    use super::*;
 
    #[test]
    fn test_angle_difference() {
        assert_eq!(25.00, angle_difference(20.00, 45.00));
        assert_eq!(90.00, angle_difference(-45.00, 45.00));
        assert_eq!(175.00, angle_difference(-85.00, 90.00));
        assert_eq!(-175.00, angle_difference(-95.00, 90.00));
        assert_eq!(170.00, angle_difference(-45.00, 125.00));
        assert_eq!(-170.00, angle_difference(-45.00, 145.00));
        approx_eq(-118.1184, angle_difference(29.4803, -88.6381));
        approx_eq(-80.7109, angle_difference(-78.3251 , -159.036));
        approx_eq(-139.5832, angle_difference(-70099.74233810938, 29840.67437876723));
        approx_eq(-72.3439, angle_difference(-165313.6666297357, 33693.9894517456));
        approx_eq(-161.5029, angle_difference(1174.8380510598456, -154146.66490124757));
        approx_eq(37.2988, angle_difference(60175.77306795546, 42213.07192354373));
    }
 
    // approximate equality on floats.
    // see also https://crates.io/crates/float-cmp
    fn approx_eq(f1: f64, f2: f64) {
        assert!((f2-f1).abs() < 0.0001, "{} != {}", f1, f2)
    }
}
  | 
| 
	http://rosettacode.org/wiki/Anagrams/Deranged_anagrams | 
	Anagrams/Deranged anagrams | 
	Two or more words are said to be anagrams if they have the same characters, but in a different order.
By analogy with derangements we define a deranged anagram as two words with the same characters, but in which the same character does not appear in the same position in both words.
Task[edit]
Use the word list at unixdict to find and display the longest deranged anagram.
Related tasks
 Permutations/Derangements
 Best shuffle
Word plays
Ordered words
Palindrome detection
Semordnilap
Anagrams
Anagrams/Deranged anagrams
Other tasks related to string operations:
Metrics
 Array length
 String length
 Copy a string
 Empty string  (assignment)
Counting
 Word frequency
 Letter frequency
 Jewels and stones
 I before E except after C
 Bioinformatics/base count
 Count occurrences of a substring
 Count how many vowels and consonants occur in a string
Remove/replace
 XXXX redacted
 Conjugate a Latin verb
 Remove vowels from a string
 String interpolation (included)
 Strip block comments
 Strip comments from a string
 Strip a set of characters from a string
 Strip whitespace from a string -- top and tail
 Strip control codes and extended characters from a string
Anagrams/Derangements/shuffling
 Word wheel
 ABC problem
 Sattolo cycle
 Knuth shuffle
 Ordered words
 Superpermutation minimisation
 Textonyms (using a phone text pad)
 Anagrams
 Anagrams/Deranged anagrams
 Permutations/Derangements
Find/Search/Determine
 ABC words
 Odd words
 Word ladder
 Semordnilap
 Word search
 Wordiff  (game)
 String matching
 Tea cup rim text
 Alternade words
 Changeable words
 State name puzzle
 String comparison
 Unique characters
 Unique characters in each string
 Extract file extension
 Levenshtein distance
 Palindrome detection
 Common list elements
 Longest common suffix
 Longest common prefix
 Compare a list of strings 
 Longest common substring
 Find common directory path
 Words from neighbour ones
 Change e letters to i in words
 Non-continuous subsequences
 Longest common subsequence
 Longest palindromic substrings
 Longest increasing subsequence
 Words containing "the" substring
 Sum of the digits of n is substring of n
 Determine if a string is numeric
 Determine if a string is collapsible
 Determine if a string is squeezable
 Determine if a string has all unique characters
 Determine if a string has all the same characters
 Longest substrings without repeating characters
 Find words which contains all the vowels
 Find words which contains most consonants
 Find words which contains more than 3 vowels
 Find words which first and last three letters are equals
 Find words which odd letters are consonants and even letters are vowels or vice_versa
Formatting
 Substring
 Rep-string
 Word wrap
 String case
 Align columns
 Literals/String
 Repeat a string
 Brace expansion
 Brace expansion using ranges
 Reverse a string
 Phrase reversals
 Comma quibbling
 Special characters
 String concatenation
 Substring/Top and tail
 Commatizing numbers
 Reverse words in a string
 Suffixation of decimal numbers
 Long literals, with continuations 
 Numerical and alphabetical suffixes
 Abbreviations, easy
 Abbreviations, simple
 Abbreviations, automatic
Song lyrics/poems/Mad Libs/phrases
 Mad Libs
 Magic 8-ball
 99 Bottles of Beer
 The Name Game (a song)
 The Old lady swallowed a fly
 The Twelve Days of Christmas
Tokenize
 Text between
 Tokenize a string
 Word break problem
 Tokenize a string with escaping
 Split a character string based on change of character
Sequences
 Show ASCII table
 De Bruijn sequences
 Self-referential sequences
 Generate lower case ASCII alphabet
 | 
	#Scala | 
	Scala | 
	object DerangedAnagrams {
 
  /** Returns a map of anagrams keyed by the sorted characters */ 
  def groupAnagrams(words: Iterable[String]): Map[String, Set[String]] =
    words.foldLeft (Map[String, Set[String]]()) { (map, word) =>
      val sorted = word.sorted
      val entry = map.getOrElse(sorted, Set.empty)
      map + (sorted -> (entry + word))
    }
 
  /* Returns true if the pair of strings has no positions with the same
   * characters */
  def isDeranged(ss: (String, String)): Boolean = 
    ss._1 zip ss._2 forall { case (c1, c2) => c1 != c2 }
 
  /* Returns pairwise combination of all Strings in the argument Iterable */
  def pairWords(as: Iterable[String]): Iterable[(String, String)] =
    if (as.size < 2) Seq() else (as.tail map (as.head -> _)) ++ pairWords(as.tail)
 
  /* Returns the contents of the argument URL as an Iterable[String], each
   * String is one line in the file */
  def readLines(url: String): Iterable[String] = 
    io.Source.fromURL(url).getLines().toIterable
 
  val wordsURL = "http://www.puzzlers.org/pub/wordlists/unixdict.txt"
 
  def main(args: Array[String]): Unit = {
    val anagramMap = groupAnagrams(readLines(wordsURL))
    val derangedPairs = anagramMap.values flatMap (pairWords) filter (isDeranged)
    val (w1, w2) = derangedPairs maxBy (pair => pair._1.length)
    println("Longest deranged pair: "+w1+" and "+w2)
  }   
 
} | 
| 
	http://rosettacode.org/wiki/Anonymous_recursion | 
	Anonymous recursion | 
	While implementing a recursive function, it often happens that we must resort to a separate   helper function   to handle the actual recursion.
This is usually the case when directly calling the current function would waste too many resources (stack space, execution time), causing unwanted side-effects,   and/or the function doesn't have the right arguments and/or return values.
So we end up inventing some silly name like   foo2   or   foo_helper.   I have always found it painful to come up with a proper name, and see some disadvantages:
   You have to think up a name, which then pollutes the namespace
   Function is created which is called from nowhere else
   The program flow in the source code is interrupted
Some languages allow you to embed recursion directly in-place.   This might work via a label, a local gosub instruction, or some special keyword.
Anonymous recursion can also be accomplished using the   Y combinator.
Task
If possible, demonstrate this by writing the recursive version of the fibonacci function   (see Fibonacci sequence)   which checks for a negative argument before doing the actual recursion.
 | 
	#PicoLisp | 
	PicoLisp | 
	(de fibo (N)
   (if (lt0 N)
      (quit "Illegal argument" N) )
   (recur (N)
      (if (> 2 N)
         1
         (+ (recurse (dec N)) (recurse (- N 2))) ) ) ) | 
| 
	http://rosettacode.org/wiki/Amicable_pairs | 
	Amicable pairs | 
	Two integers 
N
{\displaystyle N}
 and 
M
{\displaystyle M}
 are said to be amicable pairs if 
N
≠
M
{\displaystyle N\neq M}
 and the sum of the proper divisors of 
N
{\displaystyle N}
 (
s
u
m
(
p
r
o
p
D
i
v
s
(
N
)
)
{\displaystyle \mathrm {sum} (\mathrm {propDivs} (N))}
) 
=
M
{\displaystyle =M}
 as well as 
s
u
m
(
p
r
o
p
D
i
v
s
(
M
)
)
=
N
{\displaystyle \mathrm {sum} (\mathrm {propDivs} (M))=N}
.
Example
1184 and 1210 are an amicable pair, with proper divisors:
   1, 2, 4, 8, 16, 32, 37, 74, 148, 296, 592   and 
   1, 2, 5, 10, 11, 22, 55, 110, 121, 242, 605   respectively.
Task
Calculate and show here the Amicable pairs below 20,000; (there are eight).
Related tasks
 Proper divisors
 Abundant, deficient and perfect number classifications
 Aliquot sequence classifications and its amicable classification. 
 | 
	#Phix | 
	Phix | 
	integer n
for m=1 to 20000 do
    n = sum(factors(m,-1))
    if m<n and m=sum(factors(n,-1)) then ?{m,n} end if
end for
 | 
| 
	http://rosettacode.org/wiki/Animate_a_pendulum | 
	Animate a pendulum | 
	
One good way of making an animation is by simulating a physical system and illustrating the variables in that system using a dynamically changing graphical display.
The classic such physical system is a simple gravity pendulum.
Task
Create a simple physical model of a pendulum and animate it.
 | 
	#Ring | 
	Ring | 
	 
# Project : Animate a pendulum
 
load "guilib.ring"
load "stdlib.ring"
 
CounterMan = 1
paint = null
pi = 22/7
theta = pi/180*40 
g = 9.81 
l = 0.50 
speed = 0 
 
new qapp 
        {
        win1 = new qwidget() {
                  setwindowtitle("Animate a pendulum")
                  setgeometry(100,100,800,600)
                  label1 = new qlabel(win1) {
                              setgeometry(10,10,800,600)
                              settext("")
                  }
                  new qpushbutton(win1) {
                          setgeometry(150,500,100,30)
                          settext("draw")
                          setclickevent("draw()")
                  }
                  TimerMan = new qtimer(win1)
                  {
                                    setinterval(1000)
                                    settimeoutevent("draw()")
                                    start()
                  }
                  show()
        }
        exec()
        }
 
func draw
        p1 = new qpicture()
               color = new qcolor() {
               setrgb(0,0,255,255)
        }
        pen = new qpen() {
                 setcolor(color)
                 setwidth(1)
        }
        paint = new qpainter() {
                  begin(p1)
                  setpen(pen)
        ptime()
        endpaint()
        }
        label1 { setpicture(p1) show() }
        return
 
 func ptime()
         TimerMan.start()
         pPlaySleep()
         sleep(0.1)
         CounterMan++
         if CounterMan = 20
            TimerMan.stop()
         ok
 
func pPlaySleep()
       pendulum(theta, l)
       pendulum(theta, l)
       accel = - g * sin(theta) / l / 100
       speed = speed + accel / 100
       theta = theta + speed
 
func pendulum(a, l)
       pivotx = 640
       pivoty = 800
       bobx = pivotx + l * 1000 * sin(a)
       boby = pivoty - l * 1000 * cos(a)
       paint.drawline(pivotx, pivoty, bobx, boby)
       paint.drawellipse(bobx + 24 * sin(a), boby - 24 * cos(a), 24, 24)
  | 
| 
	http://rosettacode.org/wiki/Amb | 
	Amb | 
	Define and give an example of the Amb operator.
The Amb operator (short for "ambiguous") expresses nondeterminism. This doesn't refer to randomness (as in "nondeterministic universe") but is closely related to the term as it is used in automata theory ("non-deterministic finite automaton").
The Amb operator takes a variable number of expressions (or values if that's simpler in the language) and yields a correct one which will satisfy a constraint in some future computation, thereby avoiding failure.
Problems whose solution the Amb operator naturally expresses can be approached with other tools, such as explicit nested iterations over data sets, or with pattern matching. By contrast, the Amb operator appears integrated into the language. Invocations of Amb are not wrapped in any visible loops or other search patterns; they appear to be independent.
Essentially Amb(x, y, z) splits the computation into three possible futures: a future in which the value x is yielded, a future in which the value y is yielded and a future in which the value z is yielded. The future which leads to a successful subsequent computation is chosen. The other "parallel universes" somehow go away. Amb called with no arguments fails.
For simplicity, one of the domain values usable with Amb may denote failure, if that is convenient. For instance, it is convenient if a Boolean false denotes failure, so that Amb(false) fails, and thus constraints can be expressed using Boolean expressions like Amb(x * y == 8) which unless x and y add to four.
A pseudo-code program which satisfies this constraint might look like:
let x = Amb(1, 2, 3)
let y = Amb(7, 6, 4, 5)
Amb(x * y = 8)
print x, y
The output is 2 4 because Amb(1, 2, 3) correctly chooses the future in which x has value 2, Amb(7, 6, 4, 5) chooses 4 and consequently Amb(x * y = 8) produces a success.
Alternatively, failure could be represented using strictly Amb():
unless x * y = 8 do Amb()
Or else Amb could take the form of two operators or functions: one for producing values and one for enforcing constraints:
let x = Ambsel(1, 2, 3)
let y = Ambsel(4, 5, 6)
Ambassert(x * y = 8)
print x, y
where Ambassert behaves like Amb() if the Boolean expression is false, otherwise it allows the future computation to take place, without yielding any value.
The task is to somehow implement Amb, and demonstrate it with a program which chooses one word from each of the following four sets of character strings to generate a four-word sentence:
"the" "that" "a"
"frog" "elephant" "thing"
"walked" "treaded" "grows"
"slowly" "quickly"
The constraint to be satisfied is that the last character of each word (other than the last) is the same as the first character of its successor.
The only successful sentence is "that thing grows slowly"; other combinations do not satisfy the constraint and thus fail.
The goal of this task isn't to simply process the four lists of words with explicit, deterministic program flow such as nested iteration, to trivially demonstrate the correct output. The goal is to implement the Amb operator, or a facsimile thereof that is possible within the language limitations.
 | 
	#langur | 
	langur | 
	val .wordsets = [
    w/the that a/,
    w/frog elephant thing/,
    w/walked treaded grows/,
    w/slowly quickly/,
]
 
val .alljoin = f(.words) for[=true] .i of len(.words)-1 {
    if last(.words[.i]) != first(.words[.i+1]): break = false
}
 
# .amb expects 2 or more arguments
val .amb = f(...[2 to -1] .words) if(.alljoin(.words): join " ", .words)
 
writeln join "\n", where(mapX(.amb, .wordsets...)) | 
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