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http://rosettacode.org/wiki/Closures/Value_capture | Closures/Value capture | Task
Create a list of ten functions, in the simplest manner possible (anonymous functions are encouraged), such that the function at index i (you may choose to start i from either 0 or 1), when run, should return the square of the index, that is, i 2.
Display the result of running any but the last function, to demonstrate that the function indeed remembers its value.
Goal
Demonstrate how to create a series of independent closures based on the same template but maintain separate copies of the variable closed over.
In imperative languages, one would generally use a loop with a mutable counter variable.
For each function to maintain the correct number, it has to capture the value of the variable at the time it was created, rather than just a reference to the variable, which would have a different value by the time the function was run.
See also: Multiple distinct objects
| #C.2B.2B | C++ | #include <iostream>
#include <functional>
#include <vector>
int main() {
std::vector<std::function<int()> > funcs;
for (int i = 0; i < 10; i++)
funcs.push_back([=]() { return i * i; });
for ( std::function<int( )> f : funcs )
std::cout << f( ) << std::endl ;
return 0;
} |
http://rosettacode.org/wiki/Circular_primes | Circular primes | Definitions
A circular prime is a prime number with the property that the number generated at each intermediate step when cyclically permuting its (base 10) digits will also be prime.
For example:
1193 is a circular prime, since 1931, 9311 and 3119 are all also prime.
Note that a number which is a cyclic permutation of a smaller circular prime is not considered to be itself a circular prime. So 13 is a circular prime, but 31 is not.
A repunit (denoted by R) is a number whose base 10 representation contains only the digit 1.
For example:
R(2) = 11 and R(5) = 11111 are repunits.
Task
Find the first 19 circular primes.
If your language has access to arbitrary precision integer arithmetic, given that they are all repunits, find the next 4 circular primes.
(Stretch) Determine which of the following repunits are probably circular primes: R(5003), R(9887), R(15073), R(25031), R(35317) and R(49081). The larger ones may take a long time to process so just do as many as you reasonably can.
See also
Wikipedia article - Circular primes.
Wikipedia article - Repunit.
OEIS sequence A016114 - Circular primes.
| #C | C | #include <stdbool.h>
#include <stdint.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <gmp.h>
bool is_prime(uint32_t n) {
if (n == 2)
return true;
if (n < 2 || n % 2 == 0)
return false;
for (uint32_t p = 3; p * p <= n; p += 2) {
if (n % p == 0)
return false;
}
return true;
}
// e.g. returns 2341 if n = 1234
uint32_t cycle(uint32_t n) {
uint32_t m = n, p = 1;
while (m >= 10) {
p *= 10;
m /= 10;
}
return m + 10 * (n % p);
}
bool is_circular_prime(uint32_t p) {
if (!is_prime(p))
return false;
uint32_t p2 = cycle(p);
while (p2 != p) {
if (p2 < p || !is_prime(p2))
return false;
p2 = cycle(p2);
}
return true;
}
void test_repunit(uint32_t digits) {
char* str = malloc(digits + 1);
if (str == 0) {
fprintf(stderr, "Out of memory\n");
exit(1);
}
memset(str, '1', digits);
str[digits] = 0;
mpz_t bignum;
mpz_init_set_str(bignum, str, 10);
free(str);
if (mpz_probab_prime_p(bignum, 10))
printf("R(%u) is probably prime.\n", digits);
else
printf("R(%u) is not prime.\n", digits);
mpz_clear(bignum);
}
int main() {
uint32_t p = 2;
printf("First 19 circular primes:\n");
for (int count = 0; count < 19; ++p) {
if (is_circular_prime(p)) {
if (count > 0)
printf(", ");
printf("%u", p);
++count;
}
}
printf("\n");
printf("Next 4 circular primes:\n");
uint32_t repunit = 1, digits = 1;
for (; repunit < p; ++digits)
repunit = 10 * repunit + 1;
mpz_t bignum;
mpz_init_set_ui(bignum, repunit);
for (int count = 0; count < 4; ) {
if (mpz_probab_prime_p(bignum, 15)) {
if (count > 0)
printf(", ");
printf("R(%u)", digits);
++count;
}
++digits;
mpz_mul_ui(bignum, bignum, 10);
mpz_add_ui(bignum, bignum, 1);
}
mpz_clear(bignum);
printf("\n");
test_repunit(5003);
test_repunit(9887);
test_repunit(15073);
test_repunit(25031);
test_repunit(35317);
test_repunit(49081);
return 0;
} |
http://rosettacode.org/wiki/Collections | Collections | This task has been clarified. Its programming examples are in need of review to ensure that they still fit the requirements of the task.
Collections are abstractions to represent sets of values.
In statically-typed languages, the values are typically of a common data type.
Task
Create a collection, and add a few values to it.
See also
Array
Associative array: Creation, Iteration
Collections
Compound data type
Doubly-linked list: Definition, Element definition, Element insertion, List Traversal, Element Removal
Linked list
Queue: Definition, Usage
Set
Singly-linked list: Element definition, Element insertion, List Traversal, Element Removal
Stack
| #ABAP | ABAP |
REPORT z_test_rosetta_collection.
CLASS lcl_collection DEFINITION CREATE PUBLIC.
PUBLIC SECTION.
METHODS: start.
ENDCLASS.
CLASS lcl_collection IMPLEMENTATION.
METHOD start.
DATA(itab) = VALUE int4_table( ( 1 ) ( 2 ) ( 3 ) ).
cl_demo_output=>display( itab ).
ENDMETHOD.
ENDCLASS.
START-OF-SELECTION.
NEW lcl_collection( )->start( ).
|
http://rosettacode.org/wiki/Combinations | Combinations | Task
Given non-negative integers m and n, generate all size m combinations of the integers from 0 (zero) to n-1 in sorted order (each combination is sorted and the entire table is sorted).
Example
3 comb 5 is:
0 1 2
0 1 3
0 1 4
0 2 3
0 2 4
0 3 4
1 2 3
1 2 4
1 3 4
2 3 4
If it is more "natural" in your language to start counting from 1 (unity) instead of 0 (zero),
the combinations can be of the integers from 1 to n.
See also
The number of samples of size k from n objects.
With combinations and permutations generation tasks.
Order Unimportant
Order Important
Without replacement
(
n
k
)
=
n
C
k
=
n
(
n
−
1
)
…
(
n
−
k
+
1
)
k
(
k
−
1
)
…
1
{\displaystyle {\binom {n}{k}}=^{n}\operatorname {C} _{k}={\frac {n(n-1)\ldots (n-k+1)}{k(k-1)\dots 1}}}
n
P
k
=
n
⋅
(
n
−
1
)
⋅
(
n
−
2
)
⋯
(
n
−
k
+
1
)
{\displaystyle ^{n}\operatorname {P} _{k}=n\cdot (n-1)\cdot (n-2)\cdots (n-k+1)}
Task: Combinations
Task: Permutations
With replacement
(
n
+
k
−
1
k
)
=
n
+
k
−
1
C
k
=
(
n
+
k
−
1
)
!
(
n
−
1
)
!
k
!
{\displaystyle {\binom {n+k-1}{k}}=^{n+k-1}\operatorname {C} _{k}={(n+k-1)! \over (n-1)!k!}}
n
k
{\displaystyle n^{k}}
Task: Combinations with repetitions
Task: Permutations with repetitions
| #Emacs_Lisp | Emacs Lisp | (defun comb-recurse (m n n-max)
(cond ((zerop m) '(()))
((= n-max n) '())
(t (append (mapcar #'(lambda (rest) (cons n rest))
(comb-recurse (1- m) (1+ n) n-max))
(comb-recurse m (1+ n) n-max)))))
(defun comb (m n)
(comb-recurse m 0 n))
(comb 3 5) |
http://rosettacode.org/wiki/Conditional_structures | Conditional structures | Control Structures
These are examples of control structures. You may also be interested in:
Conditional structures
Exceptions
Flow-control structures
Loops
Task
List the conditional structures offered by a programming language. See Wikipedia: conditionals for descriptions.
Common conditional structures include if-then-else and switch.
Less common are arithmetic if, ternary operator and Hash-based conditionals.
Arithmetic if allows tight control over computed gotos, which optimizers have a hard time to figure out.
| #Objective-C | Objective-C | let condition = true
if condition then
1 (* evaluate something *)
else
2 (* evaluate something *) |
http://rosettacode.org/wiki/Comments | Comments | Task
Show all ways to include text in a language source file
that's completely ignored by the compiler or interpreter.
Related tasks
Documentation
Here_document
See also
Wikipedia
xkcd (Humor: hand gesture denoting // for "commenting out" people.)
| #Set_lang | Set lang | > Comments start where a > (greater than symbol) starts
set a 0 > Comments may start after a Set command |
http://rosettacode.org/wiki/Comments | Comments | Task
Show all ways to include text in a language source file
that's completely ignored by the compiler or interpreter.
Related tasks
Documentation
Here_document
See also
Wikipedia
xkcd (Humor: hand gesture denoting // for "commenting out" people.)
| #SETL | SETL | print("This is not a comment"); -- This is a comment
$ For nostalgic reasons, this is also a comment. |
http://rosettacode.org/wiki/Comments | Comments | Task
Show all ways to include text in a language source file
that's completely ignored by the compiler or interpreter.
Related tasks
Documentation
Here_document
See also
Wikipedia
xkcd (Humor: hand gesture denoting // for "commenting out" people.)
| #Sidef | Sidef | # this is commented |
http://rosettacode.org/wiki/Colour_bars/Display | Colour bars/Display | Task
Display a series of vertical color bars across the width of the display.
The color bars should either use:
the system palette, or
the sequence of colors:
black
red
green
blue
magenta
cyan
yellow
white
| #M2000_Interpreter | M2000 Interpreter |
Module Checkit {
Module Bars {
barwidth=x.twips div 8
barheight=y.twips
barcolors=(0,#ff0000,#00ff00, #0000ff, #FF00FF, #00ffff, #ffff00, #ffffff)
For i=0 to 7
Move i*barwidth, 0
\\ gradient fill. Here second color are the same as first color
Fill barwidth, barheight, array(barcolors, i), array(barcolors, i)
Next i
}
\\ first draw on console
Call Bars
Declare Form1 Form
Layer Form1 {
window 12, 10000,8000;
\\ now draw on Form1 layer, above console, in a window
Call Bars
}
Method Form1, "Show", 1 ' open modal
Declare Form1 Nothing
}
Checkit
|
http://rosettacode.org/wiki/Colour_bars/Display | Colour bars/Display | Task
Display a series of vertical color bars across the width of the display.
The color bars should either use:
the system palette, or
the sequence of colors:
black
red
green
blue
magenta
cyan
yellow
white
| #Maple | Maple |
with(plottools):
plots:-display([rectangle([0, 0], [.3, 2.1], color = black), rectangle([.3, 0], [.6, 2.1], color = red), rectangle([.6, 0], [.9, 2.1], color = green), rectangle([.9, 0], [1.2, 2.1], color = magenta), rectangle([1.2, 0], [1.5, 2.1], color = cyan), rectangle([1.5, 0], [1.8, 2.1], color = white), rectangle([1.8, 0], [2.1, 2.1], color = yellow)])
|
http://rosettacode.org/wiki/Colour_bars/Display | Colour bars/Display | Task
Display a series of vertical color bars across the width of the display.
The color bars should either use:
the system palette, or
the sequence of colors:
black
red
green
blue
magenta
cyan
yellow
white
| #Mathematica_.2F_Wolfram_Language | Mathematica / Wolfram Language | ArrayPlot[
ConstantArray[{Black, Red, Green, Blue, Magenta, Cyan, Yellow,
White}, 5]] |
http://rosettacode.org/wiki/Closures/Value_capture | Closures/Value capture | Task
Create a list of ten functions, in the simplest manner possible (anonymous functions are encouraged), such that the function at index i (you may choose to start i from either 0 or 1), when run, should return the square of the index, that is, i 2.
Display the result of running any but the last function, to demonstrate that the function indeed remembers its value.
Goal
Demonstrate how to create a series of independent closures based on the same template but maintain separate copies of the variable closed over.
In imperative languages, one would generally use a loop with a mutable counter variable.
For each function to maintain the correct number, it has to capture the value of the variable at the time it was created, rather than just a reference to the variable, which would have a different value by the time the function was run.
See also: Multiple distinct objects
| #Ceylon | Ceylon | shared void run() {
//create a list of closures with a list comprehension
value closures = [for(i in 0:10) () => i ^ 2];
for(i->closure in closures.indexed) {
print("closure number ``i`` returns: ``closure()``");
}
} |
http://rosettacode.org/wiki/Closures/Value_capture | Closures/Value capture | Task
Create a list of ten functions, in the simplest manner possible (anonymous functions are encouraged), such that the function at index i (you may choose to start i from either 0 or 1), when run, should return the square of the index, that is, i 2.
Display the result of running any but the last function, to demonstrate that the function indeed remembers its value.
Goal
Demonstrate how to create a series of independent closures based on the same template but maintain separate copies of the variable closed over.
In imperative languages, one would generally use a loop with a mutable counter variable.
For each function to maintain the correct number, it has to capture the value of the variable at the time it was created, rather than just a reference to the variable, which would have a different value by the time the function was run.
See also: Multiple distinct objects
| #Clojure | Clojure | (def funcs (map #(fn [] (* % %)) (range 11)))
(printf "%d\n%d\n" ((nth funcs 3)) ((nth funcs 4))) |
http://rosettacode.org/wiki/Circular_primes | Circular primes | Definitions
A circular prime is a prime number with the property that the number generated at each intermediate step when cyclically permuting its (base 10) digits will also be prime.
For example:
1193 is a circular prime, since 1931, 9311 and 3119 are all also prime.
Note that a number which is a cyclic permutation of a smaller circular prime is not considered to be itself a circular prime. So 13 is a circular prime, but 31 is not.
A repunit (denoted by R) is a number whose base 10 representation contains only the digit 1.
For example:
R(2) = 11 and R(5) = 11111 are repunits.
Task
Find the first 19 circular primes.
If your language has access to arbitrary precision integer arithmetic, given that they are all repunits, find the next 4 circular primes.
(Stretch) Determine which of the following repunits are probably circular primes: R(5003), R(9887), R(15073), R(25031), R(35317) and R(49081). The larger ones may take a long time to process so just do as many as you reasonably can.
See also
Wikipedia article - Circular primes.
Wikipedia article - Repunit.
OEIS sequence A016114 - Circular primes.
| #C.2B.2B | C++ | #include <cstdint>
#include <algorithm>
#include <iostream>
#include <sstream>
#include <gmpxx.h>
typedef mpz_class integer;
bool is_prime(const integer& n, int reps = 50) {
return mpz_probab_prime_p(n.get_mpz_t(), reps);
}
std::string to_string(const integer& n) {
std::ostringstream out;
out << n;
return out.str();
}
bool is_circular_prime(const integer& p) {
if (!is_prime(p))
return false;
std::string str(to_string(p));
for (size_t i = 0, n = str.size(); i + 1 < n; ++i) {
std::rotate(str.begin(), str.begin() + 1, str.end());
integer p2(str, 10);
if (p2 < p || !is_prime(p2))
return false;
}
return true;
}
integer next_repunit(const integer& n) {
integer p = 1;
while (p < n)
p = 10 * p + 1;
return p;
}
integer repunit(int digits) {
std::string str(digits, '1');
integer p(str);
return p;
}
void test_repunit(int digits) {
if (is_prime(repunit(digits), 10))
std::cout << "R(" << digits << ") is probably prime\n";
else
std::cout << "R(" << digits << ") is not prime\n";
}
int main() {
integer p = 2;
std::cout << "First 19 circular primes:\n";
for (int count = 0; count < 19; ++p) {
if (is_circular_prime(p)) {
if (count > 0)
std::cout << ", ";
std::cout << p;
++count;
}
}
std::cout << '\n';
std::cout << "Next 4 circular primes:\n";
p = next_repunit(p);
std::string str(to_string(p));
int digits = str.size();
for (int count = 0; count < 4; ) {
if (is_prime(p, 15)) {
if (count > 0)
std::cout << ", ";
std::cout << "R(" << digits << ")";
++count;
}
p = repunit(++digits);
}
std::cout << '\n';
test_repunit(5003);
test_repunit(9887);
test_repunit(15073);
test_repunit(25031);
test_repunit(35317);
test_repunit(49081);
return 0;
} |
http://rosettacode.org/wiki/Collections | Collections | This task has been clarified. Its programming examples are in need of review to ensure that they still fit the requirements of the task.
Collections are abstractions to represent sets of values.
In statically-typed languages, the values are typically of a common data type.
Task
Create a collection, and add a few values to it.
See also
Array
Associative array: Creation, Iteration
Collections
Compound data type
Doubly-linked list: Definition, Element definition, Element insertion, List Traversal, Element Removal
Linked list
Queue: Definition, Usage
Set
Singly-linked list: Element definition, Element insertion, List Traversal, Element Removal
Stack
| #Ada | Ada | procedure Array_Collection is
A : array (-3 .. -1) of Integer := (1, 2, 3);
begin
A (-3) := 3;
A (-2) := 2;
A (-1) := 1;
end Array_Collection; |
http://rosettacode.org/wiki/Combinations | Combinations | Task
Given non-negative integers m and n, generate all size m combinations of the integers from 0 (zero) to n-1 in sorted order (each combination is sorted and the entire table is sorted).
Example
3 comb 5 is:
0 1 2
0 1 3
0 1 4
0 2 3
0 2 4
0 3 4
1 2 3
1 2 4
1 3 4
2 3 4
If it is more "natural" in your language to start counting from 1 (unity) instead of 0 (zero),
the combinations can be of the integers from 1 to n.
See also
The number of samples of size k from n objects.
With combinations and permutations generation tasks.
Order Unimportant
Order Important
Without replacement
(
n
k
)
=
n
C
k
=
n
(
n
−
1
)
…
(
n
−
k
+
1
)
k
(
k
−
1
)
…
1
{\displaystyle {\binom {n}{k}}=^{n}\operatorname {C} _{k}={\frac {n(n-1)\ldots (n-k+1)}{k(k-1)\dots 1}}}
n
P
k
=
n
⋅
(
n
−
1
)
⋅
(
n
−
2
)
⋯
(
n
−
k
+
1
)
{\displaystyle ^{n}\operatorname {P} _{k}=n\cdot (n-1)\cdot (n-2)\cdots (n-k+1)}
Task: Combinations
Task: Permutations
With replacement
(
n
+
k
−
1
k
)
=
n
+
k
−
1
C
k
=
(
n
+
k
−
1
)
!
(
n
−
1
)
!
k
!
{\displaystyle {\binom {n+k-1}{k}}=^{n+k-1}\operatorname {C} _{k}={(n+k-1)! \over (n-1)!k!}}
n
k
{\displaystyle n^{k}}
Task: Combinations with repetitions
Task: Permutations with repetitions
| #Erlang | Erlang |
-module(comb).
-compile(export_all).
comb(0,_) ->
[[]];
comb(_,[]) ->
[];
comb(N,[H|T]) ->
[[H|L] || L <- comb(N-1,T)]++comb(N,T).
|
http://rosettacode.org/wiki/Conditional_structures | Conditional structures | Control Structures
These are examples of control structures. You may also be interested in:
Conditional structures
Exceptions
Flow-control structures
Loops
Task
List the conditional structures offered by a programming language. See Wikipedia: conditionals for descriptions.
Common conditional structures include if-then-else and switch.
Less common are arithmetic if, ternary operator and Hash-based conditionals.
Arithmetic if allows tight control over computed gotos, which optimizers have a hard time to figure out.
| #OCaml | OCaml | let condition = true
if condition then
1 (* evaluate something *)
else
2 (* evaluate something *) |
http://rosettacode.org/wiki/Comments | Comments | Task
Show all ways to include text in a language source file
that's completely ignored by the compiler or interpreter.
Related tasks
Documentation
Here_document
See also
Wikipedia
xkcd (Humor: hand gesture denoting // for "commenting out" people.)
| #Simula | Simula | COMMENT This is a comment for Simula 67; |
http://rosettacode.org/wiki/Comments | Comments | Task
Show all ways to include text in a language source file
that's completely ignored by the compiler or interpreter.
Related tasks
Documentation
Here_document
See also
Wikipedia
xkcd (Humor: hand gesture denoting // for "commenting out" people.)
| #Slate | Slate | "basically the same as smalltalk" |
http://rosettacode.org/wiki/Comments | Comments | Task
Show all ways to include text in a language source file
that's completely ignored by the compiler or interpreter.
Related tasks
Documentation
Here_document
See also
Wikipedia
xkcd (Humor: hand gesture denoting // for "commenting out" people.)
| #Smalltalk | Smalltalk | "Comments traditionally are in double quotes."
"Multiline comments are also supported.
Comments are saved as metadata along with the source to a method.
A comment just after a method signature is often given to explain the
usage of the method. The class browser may display such comments
specially." |
http://rosettacode.org/wiki/Colour_bars/Display | Colour bars/Display | Task
Display a series of vertical color bars across the width of the display.
The color bars should either use:
the system palette, or
the sequence of colors:
black
red
green
blue
magenta
cyan
yellow
white
| #Nim | Nim | import gintro/[glib, gobject, gtk, gio, cairo]
const
Width = 400
Height = 300
#---------------------------------------------------------------------------------------------------
proc draw(area: DrawingArea; context: Context) =
## Draw the color bars.
const Colors = [[0.0, 0.0, 0.0], [255.0, 0.0, 0.0],
[0.0, 255.0, 0.0], [0.0, 0.0, 255.0],
[255.0, 0.0, 255.0], [0.0, 255.0, 255.0],
[255.0, 255.0, 0.0], [255.0, 255.0, 255.0]]
const
RectWidth = float(Width div Colors.len)
RectHeight = float(Height)
var x = 0.0
for color in Colors:
context.rectangle(x, 0, RectWidth, RectHeight)
context.setSource(color)
context.fill()
x += RectWidth
#---------------------------------------------------------------------------------------------------
proc onDraw(area: DrawingArea; context: Context; data: pointer): bool =
## Callback to draw/redraw the drawing area contents.
area.draw(context)
result = true
#---------------------------------------------------------------------------------------------------
proc activate(app: Application) =
## Activate the application.
let window = app.newApplicationWindow()
window.setSizeRequest(Width, Height)
window.setTitle("Color bars")
# Create the drawing area.
let area = newDrawingArea()
window.add(area)
# Connect the "draw" event to the callback to draw the spiral.
discard area.connect("draw", ondraw, pointer(nil))
window.showAll()
#———————————————————————————————————————————————————————————————————————————————————————————————————
let app = newApplication(Application, "Rosetta.ColorBars")
discard app.connect("activate", activate)
discard app.run() |
http://rosettacode.org/wiki/Colour_bars/Display | Colour bars/Display | Task
Display a series of vertical color bars across the width of the display.
The color bars should either use:
the system palette, or
the sequence of colors:
black
red
green
blue
magenta
cyan
yellow
white
| #OCaml | OCaml | open Graphics
let round x =
int_of_float (floor (x +. 0.5))
let () =
open_graph "";
let cols = size_x () in
let rows = size_y () in
let colors = [| black; red; green; blue; magenta; cyan; yellow; white |] in
let n = Array.length colors in
let bar_width = (float cols) /. (float n) in
Array.iteri (fun i color ->
let x1 = bar_width *. (float i) in
let x2 = bar_width *. (float (succ i)) in
set_color color;
fill_rect (round x1) 0 (round x2) rows;
) colors;
ignore (read_key ());
;; |
http://rosettacode.org/wiki/Closures/Value_capture | Closures/Value capture | Task
Create a list of ten functions, in the simplest manner possible (anonymous functions are encouraged), such that the function at index i (you may choose to start i from either 0 or 1), when run, should return the square of the index, that is, i 2.
Display the result of running any but the last function, to demonstrate that the function indeed remembers its value.
Goal
Demonstrate how to create a series of independent closures based on the same template but maintain separate copies of the variable closed over.
In imperative languages, one would generally use a loop with a mutable counter variable.
For each function to maintain the correct number, it has to capture the value of the variable at the time it was created, rather than just a reference to the variable, which would have a different value by the time the function was run.
See also: Multiple distinct objects
| #CoffeeScript | CoffeeScript |
# Generate an array of functions.
funcs = ( for i in [ 0...10 ] then do ( i ) -> -> i * i )
# Call each function to demonstrate value capture.
console.log func() for func in funcs
|
http://rosettacode.org/wiki/Closures/Value_capture | Closures/Value capture | Task
Create a list of ten functions, in the simplest manner possible (anonymous functions are encouraged), such that the function at index i (you may choose to start i from either 0 or 1), when run, should return the square of the index, that is, i 2.
Display the result of running any but the last function, to demonstrate that the function indeed remembers its value.
Goal
Demonstrate how to create a series of independent closures based on the same template but maintain separate copies of the variable closed over.
In imperative languages, one would generally use a loop with a mutable counter variable.
For each function to maintain the correct number, it has to capture the value of the variable at the time it was created, rather than just a reference to the variable, which would have a different value by the time the function was run.
See also: Multiple distinct objects
| #Common_Lisp | Common Lisp | CL-USER> (defparameter alist
(loop for i from 1 to 10
collect (cons i (let ((i i))
(lambda () (* i i))))))
ALIST
CL-USER> (funcall (cdr (assoc 2 alist)))
4
CL-USER> (funcall (cdr (assoc 8 alist)))
64 |
http://rosettacode.org/wiki/Circular_primes | Circular primes | Definitions
A circular prime is a prime number with the property that the number generated at each intermediate step when cyclically permuting its (base 10) digits will also be prime.
For example:
1193 is a circular prime, since 1931, 9311 and 3119 are all also prime.
Note that a number which is a cyclic permutation of a smaller circular prime is not considered to be itself a circular prime. So 13 is a circular prime, but 31 is not.
A repunit (denoted by R) is a number whose base 10 representation contains only the digit 1.
For example:
R(2) = 11 and R(5) = 11111 are repunits.
Task
Find the first 19 circular primes.
If your language has access to arbitrary precision integer arithmetic, given that they are all repunits, find the next 4 circular primes.
(Stretch) Determine which of the following repunits are probably circular primes: R(5003), R(9887), R(15073), R(25031), R(35317) and R(49081). The larger ones may take a long time to process so just do as many as you reasonably can.
See also
Wikipedia article - Circular primes.
Wikipedia article - Repunit.
OEIS sequence A016114 - Circular primes.
| #D | D | import std.bigint;
import std.stdio;
immutable PRIMES = [
2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97,
101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157, 163, 167, 173, 179, 181, 191, 193, 197, 199,
211, 223, 227, 229, 233, 239, 241, 251, 257, 263, 269, 271, 277, 281, 283, 293,
307, 311, 313, 317, 331, 337, 347, 349, 353, 359, 367, 373, 379, 383, 389, 397,
401, 409, 419, 421, 431, 433, 439, 443, 449, 457, 461, 463, 467, 479, 487, 491, 499,
503, 509, 521, 523, 541, 547, 557, 563, 569, 571, 577, 587, 593, 599,
601, 607, 613, 617, 619, 631, 641, 643, 647, 653, 659, 661, 673, 677, 683, 691,
701, 709, 719, 727, 733, 739, 743, 751, 757, 761, 769, 773, 787, 797,
809, 811, 821, 823, 827, 829, 839, 853, 857, 859, 863, 877, 881, 883, 887,
907, 911, 919, 929, 937, 941, 947, 953, 967, 971, 977, 983, 991, 997
];
bool isPrime(BigInt n) {
if (n < 2) {
return false;
}
foreach (p; PRIMES) {
if (n == p) {
return true;
}
if (n % p == 0) {
return false;
}
if (p * p > n) {
return true;
}
}
for (auto m = BigInt(PRIMES[$ - 1]); m * m <= n ; m += 2) {
if (n % m == 0) {
return false;
}
}
return true;
}
// e.g. returns 2341 if n = 1234
BigInt cycle(BigInt n) {
BigInt m = n;
BigInt p = 1;
while (m >= 10) {
p *= 10;
m /= 10;
}
return m + 10 * (n % p);
}
bool isCircularPrime(BigInt p) {
if (!isPrime(p)) {
return false;
}
for (auto p2 = cycle(p); p2 != p; p2 = cycle(p2)) {
if (p2 < p || !isPrime(p2)) {
return false;
}
}
return true;
}
BigInt repUnit(int len) {
BigInt n = 0;
while (len > 0) {
n = 10 * n + 1;
len--;
}
return n;
}
void main() {
writeln("First 19 circular primes:");
int count = 0;
foreach (p; PRIMES) {
if (isCircularPrime(BigInt(p))) {
if (count > 0) {
write(", ");
}
write(p);
count++;
}
}
for (auto p = BigInt(PRIMES[$ - 1]) + 2; count < 19; p += 2) {
if (isCircularPrime(BigInt(p))) {
if (count > 0) {
write(", ");
}
write(p);
count++;
}
}
writeln;
} |
http://rosettacode.org/wiki/Collections | Collections | This task has been clarified. Its programming examples are in need of review to ensure that they still fit the requirements of the task.
Collections are abstractions to represent sets of values.
In statically-typed languages, the values are typically of a common data type.
Task
Create a collection, and add a few values to it.
See also
Array
Associative array: Creation, Iteration
Collections
Compound data type
Doubly-linked list: Definition, Element definition, Element insertion, List Traversal, Element Removal
Linked list
Queue: Definition, Usage
Set
Singly-linked list: Element definition, Element insertion, List Traversal, Element Removal
Stack
| #Aime | Aime | list l; |
http://rosettacode.org/wiki/Combinations | Combinations | Task
Given non-negative integers m and n, generate all size m combinations of the integers from 0 (zero) to n-1 in sorted order (each combination is sorted and the entire table is sorted).
Example
3 comb 5 is:
0 1 2
0 1 3
0 1 4
0 2 3
0 2 4
0 3 4
1 2 3
1 2 4
1 3 4
2 3 4
If it is more "natural" in your language to start counting from 1 (unity) instead of 0 (zero),
the combinations can be of the integers from 1 to n.
See also
The number of samples of size k from n objects.
With combinations and permutations generation tasks.
Order Unimportant
Order Important
Without replacement
(
n
k
)
=
n
C
k
=
n
(
n
−
1
)
…
(
n
−
k
+
1
)
k
(
k
−
1
)
…
1
{\displaystyle {\binom {n}{k}}=^{n}\operatorname {C} _{k}={\frac {n(n-1)\ldots (n-k+1)}{k(k-1)\dots 1}}}
n
P
k
=
n
⋅
(
n
−
1
)
⋅
(
n
−
2
)
⋯
(
n
−
k
+
1
)
{\displaystyle ^{n}\operatorname {P} _{k}=n\cdot (n-1)\cdot (n-2)\cdots (n-k+1)}
Task: Combinations
Task: Permutations
With replacement
(
n
+
k
−
1
k
)
=
n
+
k
−
1
C
k
=
(
n
+
k
−
1
)
!
(
n
−
1
)
!
k
!
{\displaystyle {\binom {n+k-1}{k}}=^{n+k-1}\operatorname {C} _{k}={(n+k-1)! \over (n-1)!k!}}
n
k
{\displaystyle n^{k}}
Task: Combinations with repetitions
Task: Permutations with repetitions
| #ERRE | ERRE |
PROGRAM COMBINATIONS
CONST M_MAX=3,N_MAX=5
DIM COMBINATION[M_MAX],STACK[100,1]
PROCEDURE GENERATE(M)
LOCAL I
IF (M>M_MAX) THEN
FOR I=1 TO M_MAX DO
PRINT(COMBINATION[I];" ";)
END FOR
PRINT
ELSE
FOR N=1 TO N_MAX DO
IF ((M=1) OR (N>COMBINATION[M-1])) THEN
COMBINATION[M]=N
! --- PUSH STACK -----------
STACK[SP,0]=M STACK[SP,1]=N
SP=SP+1
! --------------------------
GENERATE(M+1)
! --- POP STACK ------------
SP=SP-1
M=STACK[SP,0] N=STACK[SP,1]
! --------------------------
END IF
END FOR
END IF
END PROCEDURE
BEGIN
GENERATE(1)
END PROGRAM
|
http://rosettacode.org/wiki/Conditional_structures | Conditional structures | Control Structures
These are examples of control structures. You may also be interested in:
Conditional structures
Exceptions
Flow-control structures
Loops
Task
List the conditional structures offered by a programming language. See Wikipedia: conditionals for descriptions.
Common conditional structures include if-then-else and switch.
Less common are arithmetic if, ternary operator and Hash-based conditionals.
Arithmetic if allows tight control over computed gotos, which optimizers have a hard time to figure out.
| #Octave | Octave | if (condition)
% body
endif
if (condition)
% body
else
% otherwise body
endif
if (condition1)
% body
elseif (condition2)
% body 2
else
% otherwise body
endif |
http://rosettacode.org/wiki/Comments | Comments | Task
Show all ways to include text in a language source file
that's completely ignored by the compiler or interpreter.
Related tasks
Documentation
Here_document
See also
Wikipedia
xkcd (Humor: hand gesture denoting // for "commenting out" people.)
| #smart_BASIC | smart BASIC | 'Single line comments are preceded by a single quote or the command REM
PRINT "Hello" 'Single line comments may follow code
PRINT "Hello" REM You can also use the command REM following code
/*
Multi-line comments
are surrounded by
mirrored slash
and asterisk
*/
/*Multi-line comments do not have to actually have multiple lines*/
/* Spaces before or after comment bounds are optional.*/
/* A comment can also follow another comment */ 'Like this
Some programmers like to do this to allow for /* Procedural comments */ followed by 'Programmer's notes. |
http://rosettacode.org/wiki/Comments | Comments | Task
Show all ways to include text in a language source file
that's completely ignored by the compiler or interpreter.
Related tasks
Documentation
Here_document
See also
Wikipedia
xkcd (Humor: hand gesture denoting // for "commenting out" people.)
| #SNOBOL4 | SNOBOL4 |
* An asterisk in column 1 is the standard Snobol comment
* mechanism, marking the entire line as a comment. There
* are no block or multiline comments.
* Comments may begin at
* any position on the line.
- A hyphen in column 1 begins a control statement.
- Unrecognized control statements are ignored and
- may also mark comment lines. Not recommended.
;* The semicolon statement separator
output = 'FOO' ;* begins a new statement. This idiom
output = 'BAR' ;* simulates an asterisk in the first
;* column, allowing end of line comments.
END
Any text after the required END label is ignored. |
http://rosettacode.org/wiki/Comments | Comments | Task
Show all ways to include text in a language source file
that's completely ignored by the compiler or interpreter.
Related tasks
Documentation
Here_document
See also
Wikipedia
xkcd (Humor: hand gesture denoting // for "commenting out" people.)
| #SNUSP | SNUSP | 'This is single-line comment
''This is
multiline comment'' |
http://rosettacode.org/wiki/Colour_bars/Display | Colour bars/Display | Task
Display a series of vertical color bars across the width of the display.
The color bars should either use:
the system palette, or
the sequence of colors:
black
red
green
blue
magenta
cyan
yellow
white
| #Perl | Perl | #!/usr/bin/perl -w
use strict ;
use GD ;
my %colors = ( white => [ 255 , 255 , 255 ] , red => [255 , 0 , 0 ] ,
green => [ 0 , 255 , 0 ] , blue => [ 0 , 0 , 255 ] ,
magenta => [ 255 , 0 , 255 ] , yellow => [ 255 , 255 , 0 ] ,
cyan => [ 0 , 255 , 255 ] , black => [ 0 , 0 , 0 ] ) ;
my $barwidth = 160 / 8 ;
my $image = new GD::Image( 160 , 100 ) ;
my $start = 0 ;
foreach my $rgb ( values %colors ) {
my $paintcolor = $image->colorAllocate( @$rgb ) ;
$image->filledRectangle( $start * $barwidth , 0 , $start * $barwidth +
$barwidth - 1 , 99 , $paintcolor ) ;
$start++ ;
}
open ( DISPLAY , ">" , "testprogram.png" ) || die ;
binmode DISPLAY ;
print DISPLAY $image->png ;
close DISPLAY ;#to be watched with <image viewer> testprogram.png |
http://rosettacode.org/wiki/Closest-pair_problem | Closest-pair problem |
This page uses content from Wikipedia. The original article was at Closest pair of points problem. The list of authors can be seen in the page history. As with Rosetta Code, the text of Wikipedia is available under the GNU FDL. (See links for details on variance)
Task
Provide a function to find the closest two points among a set of given points in two dimensions, i.e. to solve the Closest pair of points problem in the planar case.
The straightforward solution is a O(n2) algorithm (which we can call brute-force algorithm); the pseudo-code (using indexes) could be simply:
bruteForceClosestPair of P(1), P(2), ... P(N)
if N < 2 then
return ∞
else
minDistance ← |P(1) - P(2)|
minPoints ← { P(1), P(2) }
foreach i ∈ [1, N-1]
foreach j ∈ [i+1, N]
if |P(i) - P(j)| < minDistance then
minDistance ← |P(i) - P(j)|
minPoints ← { P(i), P(j) }
endif
endfor
endfor
return minDistance, minPoints
endif
A better algorithm is based on the recursive divide&conquer approach, as explained also at Wikipedia's Closest pair of points problem, which is O(n log n); a pseudo-code could be:
closestPair of (xP, yP)
where xP is P(1) .. P(N) sorted by x coordinate, and
yP is P(1) .. P(N) sorted by y coordinate (ascending order)
if N ≤ 3 then
return closest points of xP using brute-force algorithm
else
xL ← points of xP from 1 to ⌈N/2⌉
xR ← points of xP from ⌈N/2⌉+1 to N
xm ← xP(⌈N/2⌉)x
yL ← { p ∈ yP : px ≤ xm }
yR ← { p ∈ yP : px > xm }
(dL, pairL) ← closestPair of (xL, yL)
(dR, pairR) ← closestPair of (xR, yR)
(dmin, pairMin) ← (dR, pairR)
if dL < dR then
(dmin, pairMin) ← (dL, pairL)
endif
yS ← { p ∈ yP : |xm - px| < dmin }
nS ← number of points in yS
(closest, closestPair) ← (dmin, pairMin)
for i from 1 to nS - 1
k ← i + 1
while k ≤ nS and yS(k)y - yS(i)y < dmin
if |yS(k) - yS(i)| < closest then
(closest, closestPair) ← (|yS(k) - yS(i)|, {yS(k), yS(i)})
endif
k ← k + 1
endwhile
endfor
return closest, closestPair
endif
References and further readings
Closest pair of points problem
Closest Pair (McGill)
Closest Pair (UCSB)
Closest pair (WUStL)
Closest pair (IUPUI)
| #360_Assembly | 360 Assembly | * Closest Pair Problem 10/03/2017
CLOSEST CSECT
USING CLOSEST,R13 base register
B 72(R15) skip savearea
DC 17F'0' savearea
STM R14,R12,12(R13) save previous context
ST R13,4(R15) link backward
ST R15,8(R13) link forward
LR R13,R15 set addressability
LA R6,1 i=1
LA R7,2 j=2
BAL R14,DDCALC dd=(px(i)-px(j))^2+(py(i)-py(j))^2
BAL R14,DDSTORE ddmin=dd; ii=i; jj=j
LA R6,1 i=1
DO WHILE=(C,R6,LE,N) do i=1 to n
LA R7,1 j=1
DO WHILE=(C,R7,LE,N) do j=1 to n
BAL R14,DDCALC dd=(px(i)-px(j))^2+(py(i)-py(j))^2
IF CP,DD,GT,=P'0' THEN if dd>0 then
IF CP,DD,LT,DDMIN THEN if dd<ddmin then
BAL R14,DDSTORE ddmin=dd; ii=i; jj=j
ENDIF , endif
ENDIF , endif
LA R7,1(R7) j++
ENDDO , enddo j
LA R6,1(R6) i++
ENDDO , enddo i
ZAP WPD,DDMIN ddmin
DP WPD,=PL8'2' ddmin/2
ZAP SQRT2,WPD(8) sqrt2=ddmin/2
ZAP SQRT1,DDMIN sqrt1=ddmin
DO WHILE=(CP,SQRT1,NE,SQRT2) do while sqrt1<>sqrt2
ZAP SQRT1,SQRT2 sqrt1=sqrt2
ZAP WPD,DDMIN ddmin
DP WPD,SQRT1 /sqrt1
ZAP WP1,WPD(8) ddmin/sqrt1
AP WP1,SQRT1 +sqrt1
ZAP WPD,WP1 ~
DP WPD,=PL8'2' /2
ZAP SQRT2,WPD(8) sqrt2=(sqrt1+(ddmin/sqrt1))/2
ENDDO , enddo while
MVC PG,=CL80'the minimum distance '
ZAP WP1,SQRT2 sqrt2
BAL R14,EDITPK edit
MVC PG+21(L'WC),WC output
XPRNT PG,L'PG print buffer
XPRNT =CL22'is between the points:',22
MVC PG,PGP init buffer
L R1,II ii
SLA R1,4 *16
LA R4,PXY-16(R1) @px(ii)
MVC WP1,0(R4) px(ii)
BAL R14,EDITPK edit
MVC PG+3(L'WC),WC output
MVC WP1,8(R4) py(ii)
BAL R14,EDITPK edit
MVC PG+21(L'WC),WC output
XPRNT PG,L'PG print buffer
MVC PG,PGP init buffer
L R1,JJ jj
SLA R1,4 *16
LA R4,PXY-16(R1) @px(jj)
MVC WP1,0(R4) px(jj)
BAL R14,EDITPK edit
MVC PG+3(L'WC),WC output
MVC WP1,8(R4) py(jj)
BAL R14,EDITPK edit
MVC PG+21(L'WC),WC output
XPRNT PG,L'PG print buffer
L R13,4(0,R13) restore previous savearea pointer
LM R14,R12,12(R13) restore previous context
XR R15,R15 rc=0
BR R14 exit
DDCALC EQU * ---- dd=(px(i)-px(j))^2+(py(i)-py(j))^2
LR R1,R6 i
SLA R1,4 *16
LA R4,PXY-16(R1) @px(i)
LR R1,R7 j
SLA R1,4 *16
LA R5,PXY-16(R1) @px(j)
ZAP WP1,0(8,R4) px(i)
ZAP WP2,0(8,R5) px(j)
SP WP1,WP2 px(i)-px(j)
ZAP WPS,WP1 =
MP WP1,WPS (px(i)-px(j))*(px(i)-px(j))
ZAP WP2,8(8,R4) py(i)
ZAP WP3,8(8,R5) py(j)
SP WP2,WP3 py(i)-py(j)
ZAP WPS,WP2 =
MP WP2,WPS (py(i)-py(j))*(py(i)-py(j))
AP WP1,WP2 (px(i)-px(j))^2+(py(i)-py(j))^2
ZAP DD,WP1 dd=(px(i)-px(j))^2+(py(i)-py(j))^2
BR R14 ---- return
DDSTORE EQU * ---- ddmin=dd; ii=i; jj=j
ZAP DDMIN,DD ddmin=dd
ST R6,II ii=i
ST R7,JJ jj=j
BR R14 ---- return
EDITPK EQU * ----
MVC WM,MASK set mask
EDMK WM,WP1 edit and mark
BCTR R1,0 -1
MVC 0(1,R1),WM+17 set sign
MVC WC,WM len17<-len18
BR R14 ---- return
N DC A((PGP-PXY)/16)
PXY DC PL8'0.654682',PL8'0.925557',PL8'0.409382',PL8'0.619391'
DC PL8'0.891663',PL8'0.888594',PL8'0.716629',PL8'0.996200'
DC PL8'0.477721',PL8'0.946355',PL8'0.925092',PL8'0.818220'
DC PL8'0.624291',PL8'0.142924',PL8'0.211332',PL8'0.221507'
DC PL8'0.293786',PL8'0.691701',PL8'0.839186',PL8'0.728260'
PGP DC CL80' [+xxxxxxxxx.xxxxxx,+xxxxxxxxx.xxxxxx]'
MASK DC C' ',7X'20',X'21',X'20',C'.',6X'20',C'-' CL18 15num
II DS F
JJ DS F
DD DS PL8
DDMIN DS PL8
SQRT1 DS PL8
SQRT2 DS PL8
WP1 DS PL8
WP2 DS PL8
WP3 DS PL8
WPS DS PL8
WPD DS PL16
WM DS CL18
WC DS CL17
PG DS CL80
YREGS
END CLOSEST |
http://rosettacode.org/wiki/Closures/Value_capture | Closures/Value capture | Task
Create a list of ten functions, in the simplest manner possible (anonymous functions are encouraged), such that the function at index i (you may choose to start i from either 0 or 1), when run, should return the square of the index, that is, i 2.
Display the result of running any but the last function, to demonstrate that the function indeed remembers its value.
Goal
Demonstrate how to create a series of independent closures based on the same template but maintain separate copies of the variable closed over.
In imperative languages, one would generally use a loop with a mutable counter variable.
For each function to maintain the correct number, it has to capture the value of the variable at the time it was created, rather than just a reference to the variable, which would have a different value by the time the function was run.
See also: Multiple distinct objects
| #D | D | import std.stdio;
void main() {
int delegate()[] funcs;
foreach (i; 0 .. 10)
funcs ~= (i => () => i ^^ 2)(i);
writeln(funcs[3]());
} |
http://rosettacode.org/wiki/Closures/Value_capture | Closures/Value capture | Task
Create a list of ten functions, in the simplest manner possible (anonymous functions are encouraged), such that the function at index i (you may choose to start i from either 0 or 1), when run, should return the square of the index, that is, i 2.
Display the result of running any but the last function, to demonstrate that the function indeed remembers its value.
Goal
Demonstrate how to create a series of independent closures based on the same template but maintain separate copies of the variable closed over.
In imperative languages, one would generally use a loop with a mutable counter variable.
For each function to maintain the correct number, it has to capture the value of the variable at the time it was created, rather than just a reference to the variable, which would have a different value by the time the function was run.
See also: Multiple distinct objects
| #Delphi | Delphi | program Project1;
type
TFuncIntResult = reference to function: Integer;
// use function that returns anonymous method to avoid capturing the loop variable
function CreateFunc(i: Integer): TFuncIntResult;
begin
Result :=
function: Integer
begin
Result := i * i;
end;
end;
var
Funcs: array[0..9] of TFuncIntResult;
i: integer;
begin
// create 10 anonymous functions
for i := Low(Funcs) to High(Funcs) do
Funcs[i] := CreateFunc(i);
// call all 10 functions
for i := Low(Funcs) to High(Funcs) do
Writeln(Funcs[i]());
end. |
http://rosettacode.org/wiki/Circular_primes | Circular primes | Definitions
A circular prime is a prime number with the property that the number generated at each intermediate step when cyclically permuting its (base 10) digits will also be prime.
For example:
1193 is a circular prime, since 1931, 9311 and 3119 are all also prime.
Note that a number which is a cyclic permutation of a smaller circular prime is not considered to be itself a circular prime. So 13 is a circular prime, but 31 is not.
A repunit (denoted by R) is a number whose base 10 representation contains only the digit 1.
For example:
R(2) = 11 and R(5) = 11111 are repunits.
Task
Find the first 19 circular primes.
If your language has access to arbitrary precision integer arithmetic, given that they are all repunits, find the next 4 circular primes.
(Stretch) Determine which of the following repunits are probably circular primes: R(5003), R(9887), R(15073), R(25031), R(35317) and R(49081). The larger ones may take a long time to process so just do as many as you reasonably can.
See also
Wikipedia article - Circular primes.
Wikipedia article - Repunit.
OEIS sequence A016114 - Circular primes.
| #F.23 | F# |
// Circular primes - Nigel Galloway: September 13th., 2021
let fG n g=let rec fG y=if y=g then true else if y>g && isPrime y then fG(10*(y%n)+y/n) else false in fG(10*(g%n)+g/n)
let rec fN g l=seq{let g=[for n in g do for g in [1;3;7;9] do let g=n*10+g in yield g] in yield! g|>List.filter(fun n->isPrime n && fG l n); yield! fN g (l*10)}
let circP()=seq{yield! [2;3;5;7]; yield! fN [1;3;7;9] 10}
circP()|> Seq.take 19 |>Seq.iter(printf "%d "); printfn ""
printf "The first 5 repunit primes are "; rUnitP(10)|>Seq.take 5|>Seq.iter(fun n->printf $"R(%d{n}) "); printfn ""
|
http://rosettacode.org/wiki/Collections | Collections | This task has been clarified. Its programming examples are in need of review to ensure that they still fit the requirements of the task.
Collections are abstractions to represent sets of values.
In statically-typed languages, the values are typically of a common data type.
Task
Create a collection, and add a few values to it.
See also
Array
Associative array: Creation, Iteration
Collections
Compound data type
Doubly-linked list: Definition, Element definition, Element insertion, List Traversal, Element Removal
Linked list
Queue: Definition, Usage
Set
Singly-linked list: Element definition, Element insertion, List Traversal, Element Removal
Stack
| #ALGOL_68 | ALGOL 68 | # create a constant array of integers and set its values #
[]INT constant array = ( 1, 2, 3, 4 );
# create an array of integers that can be changed, note the size mst be specified #
# this array has the default lower bound of 1 #
[ 5 ]INT mutable array := ( 9, 8, 7, 6, 5 );
# modify the second element of the mutable array #
mutable array[ 2 ] := -1;
# array sizes are normally fixed when the array is created, however arrays can be #
# declared to be FLEXible, allowing their sizes to change by assigning a new array to them #
# The standard built-in STRING is notionally defined as FLEX[ 1 : 0 ]CHAR in the standard prelude #
# Create a string variable: #
STRING str := "abc";
# assign a longer value to it #
str := "bbc/itv";
# add a few characters to str, +=: adds the text to the beginning, +:= adds it to the end #
"[" +=: str; str +:= "]"; # str now contains "[bbc/itv]" #
# Arrays of any type can be FLEXible: #
# create an array of two integers #
FLEX[ 1 : 2 ]INT fa := ( 0, 0 );
# replace it with a new array of 5 elements #
fa := LOC[ -2 : 2 ]INT;
|
http://rosettacode.org/wiki/Combinations | Combinations | Task
Given non-negative integers m and n, generate all size m combinations of the integers from 0 (zero) to n-1 in sorted order (each combination is sorted and the entire table is sorted).
Example
3 comb 5 is:
0 1 2
0 1 3
0 1 4
0 2 3
0 2 4
0 3 4
1 2 3
1 2 4
1 3 4
2 3 4
If it is more "natural" in your language to start counting from 1 (unity) instead of 0 (zero),
the combinations can be of the integers from 1 to n.
See also
The number of samples of size k from n objects.
With combinations and permutations generation tasks.
Order Unimportant
Order Important
Without replacement
(
n
k
)
=
n
C
k
=
n
(
n
−
1
)
…
(
n
−
k
+
1
)
k
(
k
−
1
)
…
1
{\displaystyle {\binom {n}{k}}=^{n}\operatorname {C} _{k}={\frac {n(n-1)\ldots (n-k+1)}{k(k-1)\dots 1}}}
n
P
k
=
n
⋅
(
n
−
1
)
⋅
(
n
−
2
)
⋯
(
n
−
k
+
1
)
{\displaystyle ^{n}\operatorname {P} _{k}=n\cdot (n-1)\cdot (n-2)\cdots (n-k+1)}
Task: Combinations
Task: Permutations
With replacement
(
n
+
k
−
1
k
)
=
n
+
k
−
1
C
k
=
(
n
+
k
−
1
)
!
(
n
−
1
)
!
k
!
{\displaystyle {\binom {n+k-1}{k}}=^{n+k-1}\operatorname {C} _{k}={(n+k-1)! \over (n-1)!k!}}
n
k
{\displaystyle n^{k}}
Task: Combinations with repetitions
Task: Permutations with repetitions
| #F.23 | F# | let choose m n =
let rec fC prefix m from = seq {
let rec loopFor f = seq {
match f with
| [] -> ()
| x::xs ->
yield (x, fC [] (m-1) xs)
yield! loopFor xs
}
if m = 0 then yield prefix
else
for (i, s) in loopFor from do
for x in s do
yield prefix@[i]@x
}
fC [] m [0..(n-1)]
[<EntryPoint>]
let main argv =
choose 3 5
|> Seq.iter (printfn "%A")
0 |
http://rosettacode.org/wiki/Conditional_structures | Conditional structures | Control Structures
These are examples of control structures. You may also be interested in:
Conditional structures
Exceptions
Flow-control structures
Loops
Task
List the conditional structures offered by a programming language. See Wikipedia: conditionals for descriptions.
Common conditional structures include if-then-else and switch.
Less common are arithmetic if, ternary operator and Hash-based conditionals.
Arithmetic if allows tight control over computed gotos, which optimizers have a hard time to figure out.
| #Oforth | Oforth | aBoolean ifTrue: [ ...]
aBoolean ifFalse: [ ... ]
aObject ifNull: [ ... ]
aObject ifNotNull: [ ... ]
aObject ifZero: [ ... ] |
http://rosettacode.org/wiki/Comments | Comments | Task
Show all ways to include text in a language source file
that's completely ignored by the compiler or interpreter.
Related tasks
Documentation
Here_document
See also
Wikipedia
xkcd (Humor: hand gesture denoting // for "commenting out" people.)
| #SPL | SPL | 'This is single-line comment
''This is
multiline comment'' |
http://rosettacode.org/wiki/Comments | Comments | Task
Show all ways to include text in a language source file
that's completely ignored by the compiler or interpreter.
Related tasks
Documentation
Here_document
See also
Wikipedia
xkcd (Humor: hand gesture denoting // for "commenting out" people.)
| #SQL | SQL | SELECT * FROM mytable -- Selects all columns and rows |
http://rosettacode.org/wiki/Comments | Comments | Task
Show all ways to include text in a language source file
that's completely ignored by the compiler or interpreter.
Related tasks
Documentation
Here_document
See also
Wikipedia
xkcd (Humor: hand gesture denoting // for "commenting out" people.)
| #SQL_PL | SQL PL |
--This is a single line comment.
|
http://rosettacode.org/wiki/Classes | Classes | In object-oriented programming class is a set (a transitive closure) of types bound by the relation of inheritance. It is said that all types derived from some base type T and the type T itself form a class T.
The first type T from the class T sometimes is called the root type of the class.
A class of types itself, as a type, has the values and operations of its own.
The operations of are usually called methods of the root type.
Both operations and values are called polymorphic.
A polymorphic operation (method) selects an implementation depending on the actual specific type of the polymorphic argument.
The action of choice the type-specific implementation of a polymorphic operation is called dispatch. Correspondingly, polymorphic operations are often called dispatching or virtual.
Operations with multiple arguments and/or the results of the class are called multi-methods.
A further generalization of is the operation with arguments and/or results from different classes.
single-dispatch languages are those that allow only one argument or result to control the dispatch. Usually it is the first parameter, often hidden, so that a prefix notation x.f() is used instead of mathematical f(x).
multiple-dispatch languages allow many arguments and/or results to control the dispatch.
A polymorphic value has a type tag indicating its specific type from the class and the corresponding specific value of that type.
This type is sometimes called the most specific type of a [polymorphic] value.
The type tag of the value is used in order to resolve the dispatch.
The set of polymorphic values of a class is a transitive closure of the sets of values of all types from that class.
In many OO languages
the type of the class of T and T itself are considered equivalent.
In some languages they are distinct (like in Ada).
When class T and T are equivalent, there is no way to distinguish
polymorphic and specific values.
Task
Create a basic class with a method, a constructor, an instance variable and how to instantiate it.
| #11l | 11l | T MyType
Int public_variable // member variable = instance variable
. Int private_variable
F () // constructor
.private_variable = 0
F someMethod() // member function = method
.private_variable = 1
.public_variable = 10 |
http://rosettacode.org/wiki/Cistercian_numerals | Cistercian numerals | Cistercian numerals were used across Europe by Cistercian monks during the Late Medieval Period as an alternative to Roman numerals. They were used to represent base 10 integers from 0 to 9999.
How they work
All Cistercian numerals begin with a vertical line segment, which by itself represents the number 0. Then, glyphs representing the digits 1 through 9 are optionally added to the four quadrants surrounding the vertical line segment. These glyphs are drawn with vertical and horizontal symmetry about the initial line segment. Each quadrant corresponds to a digit place in the number:
The upper-right quadrant represents the ones place.
The upper-left quadrant represents the tens place.
The lower-right quadrant represents the hundreds place.
The lower-left quadrant represents the thousands place.
Please consult the following image for examples of Cistercian numerals showing each glyph: [1]
Task
Write a function/procedure/routine to display any given Cistercian numeral. This could be done by drawing to the display, creating an image, or even as text (as long as it is a reasonable facsimile).
Use the routine to show the following Cistercian numerals:
0
1
20
300
4000
5555
6789
And a number of your choice!
Notes
Due to the inability to upload images to Rosetta Code as of this task's creation, showing output here on this page is not required. However, it is welcomed — especially for text output.
See also
Numberphile - The Forgotten Number System
dcode.fr - Online Cistercian numeral converter
| #Action.21 | Action! | BYTE FUNC AtasciiToInternal(CHAR c)
BYTE c2
c2=c&$7F
IF c2<32 THEN RETURN (c+64)
ELSEIF c2<96 THEN RETURN (c-32) FI
RETURN (c)
PROC CharOut(CARD x BYTE y CHAR c)
BYTE i,j,v
CARD addr
addr=$E000+AtasciiToInternal(c)*8
FOR j=0 TO 7
DO
v=Peek(addr) i=8
WHILE i>0
DO
IF (v&1)=0 THEN Color=0
ELSE Color=1 FI
Plot(x+i,y+j)
v=v RSH 1 i==-1
OD
addr==+1
OD
RETURN
PROC TextOut(CARD x BYTE y CHAR ARRAY text)
BYTE i
FOR i=1 TO text(0)
DO
CharOut(x,y,text(i))
x==+8
OD
RETURN
PROC DrawDigit(BYTE d INT x BYTE y INT dx,dy)
IF d=1 THEN
Plot(x,y) DrawTo(x+dx,y)
ELSEIF d=2 THEN
Plot(x,y+dy) DrawTo(x+dx,y+dy)
ELSEIF d=3 THEN
Plot(x,y) DrawTo(x+dx,y+dy)
ELSEIF d=4 THEN
Plot(x,y+dy) DrawTo(x+dx,y)
ELSEIF d=5 THEN
Plot(x,y) DrawTo(x+dx,y) DrawTo(x,y+dy)
ELSEIF d=6 THEN
Plot(x+dx,y) DrawTo(x+dx,y+dy)
ELSEIF d=7 THEN
Plot(x,y) DrawTo(x+dx,y) DrawTo(x+dx,y+dy)
ELSEIF d=8 THEN
Plot(x,y+dy) DrawTo(x+dx,y+dy) DrawTo(x+dx,y)
ELSEIF d=9 THEN
Plot(x,y) DrawTo(x+dx,y)
DrawTo(x+dx,y+dy) DrawTo(x,y+dy)
FI
RETURN
PROC Cystersian(CARD n INT x BYTE y,s)
INT ms
ms=-s
Color=1
Plot(x+s,y) DrawTo(x+s,y+3*s)
DrawDigit(n MOD 10,x+s,y,s,s)
n==/10
DrawDigit(n MOD 10,x+s,y,ms,s)
n==/10
DrawDigit(n MOD 10,x+s,y+3*s,s,ms)
n==/10
DrawDigit(n MOD 10,x+s,y+3*s,ms,ms)
RETURN
PROC Test(CARD n INT x BYTE y,s)
CHAR ARRAY text(5)
StrC(n,text)
TextOut(x+(2*s-text(0)*8)/2,y-10,text)
Cystersian(n,x,y,s)
RETURN
PROC Main()
CARD ARRAY numbers=[0 1 20 300 4000 5555 6789 6502 1977 2021]
BYTE CH=$02FC,COLOR1=$02C5,COLOR2=$02C6
BYTE s=[16],i
INT x,y
Graphics(8+16)
COLOR1=$0C
COLOR2=$02
x=s y=2*s
FOR i=0 TO 9
DO
Test(numbers(i),x,y,s)
x==+4*s
IF x>=320-s THEN
x=s y==+5*s
FI
OD
DO UNTIL CH#$FF OD
CH=$FF
RETURN |
http://rosettacode.org/wiki/Colour_bars/Display | Colour bars/Display | Task
Display a series of vertical color bars across the width of the display.
The color bars should either use:
the system palette, or
the sequence of colors:
black
red
green
blue
magenta
cyan
yellow
white
| #Phix | Phix | -- demo\rosetta\Colour_bars.exw
with javascript_semantics
include pGUI.e
constant colours = {CD_BLACK, CD_RED, CD_GREEN, CD_BLUE, CD_MAGENTA, CD_CYAN, CD_YELLOW, CD_WHITE}
Ihandle dlg, canvas
cdCanvas cdcanvas
function redraw_cb(Ihandle /*ih*/, integer /*posx*/, /*posy*/)
integer {width, height} = IupGetIntInt(canvas, "DRAWSIZE"),
x = 0, lc = length(colours)
cdCanvasActivate(cdcanvas)
for i=1 to lc do
integer w = floor((width-x)/(lc-i+1))
cdCanvasSetForeground(cdcanvas, colours[i])
cdCanvasBox(cdcanvas, x, x+w, 0, height)
x += w
end for
cdCanvasFlush(cdcanvas)
return IUP_DEFAULT
end function
IupOpen()
canvas = IupCanvas(Icallback("redraw_cb"),"RASTERSIZE=600x400") -- initial size
dlg = IupDialog(canvas,`TITLE="Colour bars"`)
IupMap(dlg)
cdcanvas = cdCreateCanvas(CD_IUP, canvas)
IupShow(dlg)
IupSetAttribute(canvas, "RASTERSIZE", NULL) -- release the minimum limitation
if platform()!=JS then
IupMainLoop()
IupClose()
end if
|
http://rosettacode.org/wiki/Closest-pair_problem | Closest-pair problem |
This page uses content from Wikipedia. The original article was at Closest pair of points problem. The list of authors can be seen in the page history. As with Rosetta Code, the text of Wikipedia is available under the GNU FDL. (See links for details on variance)
Task
Provide a function to find the closest two points among a set of given points in two dimensions, i.e. to solve the Closest pair of points problem in the planar case.
The straightforward solution is a O(n2) algorithm (which we can call brute-force algorithm); the pseudo-code (using indexes) could be simply:
bruteForceClosestPair of P(1), P(2), ... P(N)
if N < 2 then
return ∞
else
minDistance ← |P(1) - P(2)|
minPoints ← { P(1), P(2) }
foreach i ∈ [1, N-1]
foreach j ∈ [i+1, N]
if |P(i) - P(j)| < minDistance then
minDistance ← |P(i) - P(j)|
minPoints ← { P(i), P(j) }
endif
endfor
endfor
return minDistance, minPoints
endif
A better algorithm is based on the recursive divide&conquer approach, as explained also at Wikipedia's Closest pair of points problem, which is O(n log n); a pseudo-code could be:
closestPair of (xP, yP)
where xP is P(1) .. P(N) sorted by x coordinate, and
yP is P(1) .. P(N) sorted by y coordinate (ascending order)
if N ≤ 3 then
return closest points of xP using brute-force algorithm
else
xL ← points of xP from 1 to ⌈N/2⌉
xR ← points of xP from ⌈N/2⌉+1 to N
xm ← xP(⌈N/2⌉)x
yL ← { p ∈ yP : px ≤ xm }
yR ← { p ∈ yP : px > xm }
(dL, pairL) ← closestPair of (xL, yL)
(dR, pairR) ← closestPair of (xR, yR)
(dmin, pairMin) ← (dR, pairR)
if dL < dR then
(dmin, pairMin) ← (dL, pairL)
endif
yS ← { p ∈ yP : |xm - px| < dmin }
nS ← number of points in yS
(closest, closestPair) ← (dmin, pairMin)
for i from 1 to nS - 1
k ← i + 1
while k ≤ nS and yS(k)y - yS(i)y < dmin
if |yS(k) - yS(i)| < closest then
(closest, closestPair) ← (|yS(k) - yS(i)|, {yS(k), yS(i)})
endif
k ← k + 1
endwhile
endfor
return closest, closestPair
endif
References and further readings
Closest pair of points problem
Closest Pair (McGill)
Closest Pair (UCSB)
Closest pair (WUStL)
Closest pair (IUPUI)
| #Ada | Ada | with Ada.Numerics.Generic_Elementary_Functions;
with Ada.Text_IO;
procedure Closest is
package Math is new Ada.Numerics.Generic_Elementary_Functions (Float);
Dimension : constant := 2;
type Vector is array (1 .. Dimension) of Float;
type Matrix is array (Positive range <>) of Vector;
-- calculate the distance of two points
function Distance (Left, Right : Vector) return Float is
Result : Float := 0.0;
Offset : Natural := 0;
begin
loop
Result := Result + (Left(Left'First + Offset) - Right(Right'First + Offset))**2;
Offset := Offset + 1;
exit when Offset >= Left'Length;
end loop;
return Math.Sqrt (Result);
end Distance;
-- determine the two closest points inside a cloud of vectors
function Get_Closest_Points (Cloud : Matrix) return Matrix is
Result : Matrix (1..2);
Min_Distance : Float;
begin
if Cloud'Length(1) < 2 then
raise Constraint_Error;
end if;
Result := (Cloud (Cloud'First), Cloud (Cloud'First + 1));
Min_Distance := Distance (Cloud (Cloud'First), Cloud (Cloud'First + 1));
for I in Cloud'First (1) .. Cloud'Last(1) - 1 loop
for J in I + 1 .. Cloud'Last(1) loop
if Distance (Cloud (I), Cloud (J)) < Min_Distance then
Min_Distance := Distance (Cloud (I), Cloud (J));
Result := (Cloud (I), Cloud (J));
end if;
end loop;
end loop;
return Result;
end Get_Closest_Points;
Test_Cloud : constant Matrix (1 .. 10) := ( (5.0, 9.0), (9.0, 3.0),
(2.0, 0.0), (8.0, 4.0),
(7.0, 4.0), (9.0, 10.0),
(1.0, 9.0), (8.0, 2.0),
(0.0, 10.0), (9.0, 6.0));
Closest_Points : Matrix := Get_Closest_Points (Test_Cloud);
Second_Test : constant Matrix (1 .. 10) := ( (0.654682, 0.925557), (0.409382, 0.619391),
(0.891663, 0.888594), (0.716629, 0.9962),
(0.477721, 0.946355), (0.925092, 0.81822),
(0.624291, 0.142924), (0.211332, 0.221507),
(0.293786, 0.691701), (0.839186, 0.72826));
Second_Points : Matrix := Get_Closest_Points (Second_Test);
begin
Ada.Text_IO.Put_Line ("Closest Points:");
Ada.Text_IO.Put_Line ("P1: " & Float'Image (Closest_Points (1) (1)) & " " & Float'Image (Closest_Points (1) (2)));
Ada.Text_IO.Put_Line ("P2: " & Float'Image (Closest_Points (2) (1)) & " " & Float'Image (Closest_Points (2) (2)));
Ada.Text_IO.Put_Line ("Distance: " & Float'Image (Distance (Closest_Points (1), Closest_Points (2))));
Ada.Text_IO.Put_Line ("Closest Points 2:");
Ada.Text_IO.Put_Line ("P1: " & Float'Image (Second_Points (1) (1)) & " " & Float'Image (Second_Points (1) (2)));
Ada.Text_IO.Put_Line ("P2: " & Float'Image (Second_Points (2) (1)) & " " & Float'Image (Second_Points (2) (2)));
Ada.Text_IO.Put_Line ("Distance: " & Float'Image (Distance (Second_Points (1), Second_Points (2))));
end Closest; |
http://rosettacode.org/wiki/Closures/Value_capture | Closures/Value capture | Task
Create a list of ten functions, in the simplest manner possible (anonymous functions are encouraged), such that the function at index i (you may choose to start i from either 0 or 1), when run, should return the square of the index, that is, i 2.
Display the result of running any but the last function, to demonstrate that the function indeed remembers its value.
Goal
Demonstrate how to create a series of independent closures based on the same template but maintain separate copies of the variable closed over.
In imperative languages, one would generally use a loop with a mutable counter variable.
For each function to maintain the correct number, it has to capture the value of the variable at the time it was created, rather than just a reference to the variable, which would have a different value by the time the function was run.
See also: Multiple distinct objects
| #Dyalect | Dyalect | var xs = []
let num = 10
for n in 0..<num {
xs.Add((n => () => n * n)(n))
}
for x in xs {
print(x())
} |
http://rosettacode.org/wiki/Closures/Value_capture | Closures/Value capture | Task
Create a list of ten functions, in the simplest manner possible (anonymous functions are encouraged), such that the function at index i (you may choose to start i from either 0 or 1), when run, should return the square of the index, that is, i 2.
Display the result of running any but the last function, to demonstrate that the function indeed remembers its value.
Goal
Demonstrate how to create a series of independent closures based on the same template but maintain separate copies of the variable closed over.
In imperative languages, one would generally use a loop with a mutable counter variable.
For each function to maintain the correct number, it has to capture the value of the variable at the time it was created, rather than just a reference to the variable, which would have a different value by the time the function was run.
See also: Multiple distinct objects
| #EchoLisp | EchoLisp |
(define (fgen i) (lambda () (* i i)))
(define fs (for/vector ((i 10)) (fgen i))) ;; vector of 10 anonymous functions
((vector-ref fs 5)) ;; calls fs[5]
→ 25
|
http://rosettacode.org/wiki/Circular_primes | Circular primes | Definitions
A circular prime is a prime number with the property that the number generated at each intermediate step when cyclically permuting its (base 10) digits will also be prime.
For example:
1193 is a circular prime, since 1931, 9311 and 3119 are all also prime.
Note that a number which is a cyclic permutation of a smaller circular prime is not considered to be itself a circular prime. So 13 is a circular prime, but 31 is not.
A repunit (denoted by R) is a number whose base 10 representation contains only the digit 1.
For example:
R(2) = 11 and R(5) = 11111 are repunits.
Task
Find the first 19 circular primes.
If your language has access to arbitrary precision integer arithmetic, given that they are all repunits, find the next 4 circular primes.
(Stretch) Determine which of the following repunits are probably circular primes: R(5003), R(9887), R(15073), R(25031), R(35317) and R(49081). The larger ones may take a long time to process so just do as many as you reasonably can.
See also
Wikipedia article - Circular primes.
Wikipedia article - Repunit.
OEIS sequence A016114 - Circular primes.
| #Factor | Factor | USING: combinators.short-circuit formatting io kernel lists
lists.lazy math math.combinatorics math.functions math.parser
math.primes sequences sequences.extras ;
! Create an ordered infinite lazy list of circular prime
! "candidates" -- the numbers 2, 3, 5 followed by numbers
! composed of only the digits 1, 3, 7, and 9.
: candidates ( -- list )
L{ "2" "3" "5" "7" } 2 lfrom
[ "1379" swap selections >list ] lmap-lazy lconcat lappend ;
: circular-prime? ( str -- ? )
all-rotations {
[ [ infimum ] [ first = ] bi ]
[ [ string>number prime? ] all? ]
} 1&& ;
: circular-primes ( -- list )
candidates [ circular-prime? ] lfilter ;
: prime-repunits ( -- list )
7 lfrom [ 10^ 1 - 9 / prime? ] lfilter ;
"The first 19 circular primes are:" print
19 circular-primes ltake [ write bl ] leach nl nl
"The next 4 circular primes, in repunit format, are:" print
4 prime-repunits ltake [ "R(%d) " printf ] leach nl |
http://rosettacode.org/wiki/Collections | Collections | This task has been clarified. Its programming examples are in need of review to ensure that they still fit the requirements of the task.
Collections are abstractions to represent sets of values.
In statically-typed languages, the values are typically of a common data type.
Task
Create a collection, and add a few values to it.
See also
Array
Associative array: Creation, Iteration
Collections
Compound data type
Doubly-linked list: Definition, Element definition, Element insertion, List Traversal, Element Removal
Linked list
Queue: Definition, Usage
Set
Singly-linked list: Element definition, Element insertion, List Traversal, Element Removal
Stack
| #Apex | Apex |
// Create an empty list of String
List<String> my_list = new List<String>();
// Create a nested list
List<List<Set<Integer>>> my_list_2 = new List<List<Set<Integer>>>();
|
http://rosettacode.org/wiki/Combinations | Combinations | Task
Given non-negative integers m and n, generate all size m combinations of the integers from 0 (zero) to n-1 in sorted order (each combination is sorted and the entire table is sorted).
Example
3 comb 5 is:
0 1 2
0 1 3
0 1 4
0 2 3
0 2 4
0 3 4
1 2 3
1 2 4
1 3 4
2 3 4
If it is more "natural" in your language to start counting from 1 (unity) instead of 0 (zero),
the combinations can be of the integers from 1 to n.
See also
The number of samples of size k from n objects.
With combinations and permutations generation tasks.
Order Unimportant
Order Important
Without replacement
(
n
k
)
=
n
C
k
=
n
(
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(
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{\displaystyle {\binom {n}{k}}=^{n}\operatorname {C} _{k}={\frac {n(n-1)\ldots (n-k+1)}{k(k-1)\dots 1}}}
n
P
k
=
n
⋅
(
n
−
1
)
⋅
(
n
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2
)
⋯
(
n
−
k
+
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)
{\displaystyle ^{n}\operatorname {P} _{k}=n\cdot (n-1)\cdot (n-2)\cdots (n-k+1)}
Task: Combinations
Task: Permutations
With replacement
(
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+
k
−
1
k
)
=
n
+
k
−
1
C
k
=
(
n
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(
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k
!
{\displaystyle {\binom {n+k-1}{k}}=^{n+k-1}\operatorname {C} _{k}={(n+k-1)! \over (n-1)!k!}}
n
k
{\displaystyle n^{k}}
Task: Combinations with repetitions
Task: Permutations with repetitions
| #Factor | Factor | USING: math.combinatorics prettyprint ;
5 iota 3 all-combinations . |
http://rosettacode.org/wiki/Conditional_structures | Conditional structures | Control Structures
These are examples of control structures. You may also be interested in:
Conditional structures
Exceptions
Flow-control structures
Loops
Task
List the conditional structures offered by a programming language. See Wikipedia: conditionals for descriptions.
Common conditional structures include if-then-else and switch.
Less common are arithmetic if, ternary operator and Hash-based conditionals.
Arithmetic if allows tight control over computed gotos, which optimizers have a hard time to figure out.
| #Ol | Ol |
(if (= (* 2 2) 4) (print "if-then: equal"))
(if (= (* 2 2) 6) (print "if-then: non equal"))
; ==> if-then: equal
|
http://rosettacode.org/wiki/Comments | Comments | Task
Show all ways to include text in a language source file
that's completely ignored by the compiler or interpreter.
Related tasks
Documentation
Here_document
See also
Wikipedia
xkcd (Humor: hand gesture denoting // for "commenting out" people.)
| #Squirrel | Squirrel | //this is a single line comment
#this is also a single line comment
/*
this is a multi-line comment
*/ |
http://rosettacode.org/wiki/Comments | Comments | Task
Show all ways to include text in a language source file
that's completely ignored by the compiler or interpreter.
Related tasks
Documentation
Here_document
See also
Wikipedia
xkcd (Humor: hand gesture denoting // for "commenting out" people.)
| #SSEM | SSEM | 00101010010001000100100100001100 |
http://rosettacode.org/wiki/Comments | Comments | Task
Show all ways to include text in a language source file
that's completely ignored by the compiler or interpreter.
Related tasks
Documentation
Here_document
See also
Wikipedia
xkcd (Humor: hand gesture denoting // for "commenting out" people.)
| #Standard_ML | Standard ML | (* This a comment
(* containing nested comment *)
*) |
http://rosettacode.org/wiki/Classes | Classes | In object-oriented programming class is a set (a transitive closure) of types bound by the relation of inheritance. It is said that all types derived from some base type T and the type T itself form a class T.
The first type T from the class T sometimes is called the root type of the class.
A class of types itself, as a type, has the values and operations of its own.
The operations of are usually called methods of the root type.
Both operations and values are called polymorphic.
A polymorphic operation (method) selects an implementation depending on the actual specific type of the polymorphic argument.
The action of choice the type-specific implementation of a polymorphic operation is called dispatch. Correspondingly, polymorphic operations are often called dispatching or virtual.
Operations with multiple arguments and/or the results of the class are called multi-methods.
A further generalization of is the operation with arguments and/or results from different classes.
single-dispatch languages are those that allow only one argument or result to control the dispatch. Usually it is the first parameter, often hidden, so that a prefix notation x.f() is used instead of mathematical f(x).
multiple-dispatch languages allow many arguments and/or results to control the dispatch.
A polymorphic value has a type tag indicating its specific type from the class and the corresponding specific value of that type.
This type is sometimes called the most specific type of a [polymorphic] value.
The type tag of the value is used in order to resolve the dispatch.
The set of polymorphic values of a class is a transitive closure of the sets of values of all types from that class.
In many OO languages
the type of the class of T and T itself are considered equivalent.
In some languages they are distinct (like in Ada).
When class T and T are equivalent, there is no way to distinguish
polymorphic and specific values.
Task
Create a basic class with a method, a constructor, an instance variable and how to instantiate it.
| #ActionScript | ActionScript | package {
public class MyClass {
private var myVariable:int; // Note: instance variables are usually "private"
/**
* The constructor
*/
public function MyClass() {
// creates a new instance
}
/**
* A method
*/
public function someMethod():void {
this.myVariable = 1; // Note: "this." is optional
// myVariable = 1; works also
}
}
} |
http://rosettacode.org/wiki/Classes | Classes | In object-oriented programming class is a set (a transitive closure) of types bound by the relation of inheritance. It is said that all types derived from some base type T and the type T itself form a class T.
The first type T from the class T sometimes is called the root type of the class.
A class of types itself, as a type, has the values and operations of its own.
The operations of are usually called methods of the root type.
Both operations and values are called polymorphic.
A polymorphic operation (method) selects an implementation depending on the actual specific type of the polymorphic argument.
The action of choice the type-specific implementation of a polymorphic operation is called dispatch. Correspondingly, polymorphic operations are often called dispatching or virtual.
Operations with multiple arguments and/or the results of the class are called multi-methods.
A further generalization of is the operation with arguments and/or results from different classes.
single-dispatch languages are those that allow only one argument or result to control the dispatch. Usually it is the first parameter, often hidden, so that a prefix notation x.f() is used instead of mathematical f(x).
multiple-dispatch languages allow many arguments and/or results to control the dispatch.
A polymorphic value has a type tag indicating its specific type from the class and the corresponding specific value of that type.
This type is sometimes called the most specific type of a [polymorphic] value.
The type tag of the value is used in order to resolve the dispatch.
The set of polymorphic values of a class is a transitive closure of the sets of values of all types from that class.
In many OO languages
the type of the class of T and T itself are considered equivalent.
In some languages they are distinct (like in Ada).
When class T and T are equivalent, there is no way to distinguish
polymorphic and specific values.
Task
Create a basic class with a method, a constructor, an instance variable and how to instantiate it.
| #Ada | Ada | package My_Package is
type My_Type is tagged private;
procedure Some_Procedure(Item : out My_Type);
function Set(Value : in Integer) return My_Type;
private
type My_Type is tagged record
Variable : Integer := -12;
end record;
end My_Package; |
http://rosettacode.org/wiki/Cistercian_numerals | Cistercian numerals | Cistercian numerals were used across Europe by Cistercian monks during the Late Medieval Period as an alternative to Roman numerals. They were used to represent base 10 integers from 0 to 9999.
How they work
All Cistercian numerals begin with a vertical line segment, which by itself represents the number 0. Then, glyphs representing the digits 1 through 9 are optionally added to the four quadrants surrounding the vertical line segment. These glyphs are drawn with vertical and horizontal symmetry about the initial line segment. Each quadrant corresponds to a digit place in the number:
The upper-right quadrant represents the ones place.
The upper-left quadrant represents the tens place.
The lower-right quadrant represents the hundreds place.
The lower-left quadrant represents the thousands place.
Please consult the following image for examples of Cistercian numerals showing each glyph: [1]
Task
Write a function/procedure/routine to display any given Cistercian numeral. This could be done by drawing to the display, creating an image, or even as text (as long as it is a reasonable facsimile).
Use the routine to show the following Cistercian numerals:
0
1
20
300
4000
5555
6789
And a number of your choice!
Notes
Due to the inability to upload images to Rosetta Code as of this task's creation, showing output here on this page is not required. However, it is welcomed — especially for text output.
See also
Numberphile - The Forgotten Number System
dcode.fr - Online Cistercian numeral converter
| #AWK | AWK |
# syntax: GAWK -f CISTERCIAN_NUMERALS.AWK [-v debug={0|1}] [-v xc=anychar] numbers 0-9999 ...
#
# example: GAWK -f CISTERCIAN_NUMERALS.AWK 0 1 20 300 4000 5555 6789 1995 10000
#
# sorting:
# PROCINFO["sorted_in"] is used by GAWK
# SORTTYPE is used by Thompson Automation's TAWK
#
BEGIN {
cistercian_init()
for (i=1; i<=ARGC-1; i++) {
cistercian1(ARGV[i])
}
exit(0)
}
function cistercian1(n, i) {
printf("\n%6s\n",n)
if (!(n ~ /^[0-9]+$/ && length(n) <= 4)) {
print("invalid")
return
}
n = sprintf("%04d",n)
cistercian2(2,1,substr(n,3,1),substr(n,4,1))
for (i=1; i<=5; i++) { # separator between upper and lower parts
printf("%5s%1s%5s\n","",xc,"")
}
cistercian2(4,3,substr(n,1,1),substr(n,2,1))
}
function cistercian2(i1,i2,n1,n2, i,L,R) {
for (i=1; i<=5; i++) {
L = substr(cn_arr[i1][i],n1*6+2,5)
R = substr(cn_arr[i2][i],n2*6+2,5)
printf("%5s%1s%5s\n",L,xc,R)
}
}
function cistercian_init( header,i,j,LL,LR,UL,UR) {
# 1-9 upper-right
cn_arr[1][++UR] = ":xxxxx: :x : x:xxxxx: x:xxxxx: x:xxxxx:"
cn_arr[1][++UR] = ": : : x : x : x : x: x: x: x:"
cn_arr[1][++UR] = ": : : x : x : x : x: x: x: x:"
cn_arr[1][++UR] = ": : : x : x : x : x: x: x: x:"
cn_arr[1][++UR] = ": :xxxxx: x:x :x : x: x:xxxxx:xxxxx:"
# 10-90 upper-left
cn_arr[2][++UL] = ":xxxxx: : x:x :xxxxx:x :xxxxx:x :xxxxx:"
cn_arr[2][++UL] = ": : : x : x : x :x :x :x :x :"
cn_arr[2][++UL] = ": : : x : x : x :x :x :x :x :"
cn_arr[2][++UL] = ": : : x : x : x :x :x :x :x :"
cn_arr[2][++UL] = ": :xxxxx:x : x: x:x :x :xxxxx:xxxxx:"
# 100-900 lower-right
cn_arr[3][++LR] = ": :xxxxx: x:x :x : x: x:xxxxx:xxxxx:"
cn_arr[3][++LR] = ": : : x : x : x : x: x: x: x:"
cn_arr[3][++LR] = ": : : x : x : x : x: x: x: x:"
cn_arr[3][++LR] = ": : : x : x : x : x: x: x: x:"
cn_arr[3][++LR] = ":xxxxx: :x : x:xxxxx: x:xxxxx: x:xxxxx:"
# 1000-9000 lower-left
cn_arr[4][++LL] = ": :xxxxx:x : x: x:x :x :xxxxx:xxxxx:"
cn_arr[4][++LL] = ": : : x : x : x :x :x :x :x :"
cn_arr[4][++LL] = ": : : x : x : x :x :x :x :x :"
cn_arr[4][++LL] = ": : : x : x : x :x :x :x :x :"
cn_arr[4][++LL] = ":xxxxx: : x:x :xxxxx:x :xxxxx:x :xxxxx:"
header = ":00000:11111:22222:33333:44444:55555:66666:77777:88888:99999:"
PROCINFO["sorted_in"] = "@ind_str_asc" ; SORTTYPE = 1
sub(/^ +/,"",xc)
xc = (xc == "") ? "x" : substr(xc,1,1) # substitution character
for (i in cn_arr) {
for (j in cn_arr[i]) {
gsub(/x/,xc,cn_arr[i][j]) # change "x" to substitution character
cn_arr[i][j] = sprintf(":%5s%s","",cn_arr[i][j]) # add zero column to table
if (debug == 1) { printf("%s %2s %d.%d\n",cn_arr[i][j],substr("URULLRLL",i*2-1,2),i,j) }
}
}
if (debug == 1) { printf("%s\n",header) }
}
|
http://rosettacode.org/wiki/Colour_bars/Display | Colour bars/Display | Task
Display a series of vertical color bars across the width of the display.
The color bars should either use:
the system palette, or
the sequence of colors:
black
red
green
blue
magenta
cyan
yellow
white
| #PHP | PHP | <?php
$colors = array(array( 0, 0, 0), // black
array(255, 0, 0), // red
array( 0, 255, 0), // green
array( 0, 0, 255), // blue
array(255, 0, 255), // magenta
array( 0, 255, 255), // cyan
array(255, 255, 0), // yellow
array(255, 255, 255)); // white
define('BARWIDTH', 640 / count($colors));
define('HEIGHT', 480);
$image = imagecreate(BARWIDTH * count($colors), HEIGHT);
foreach ($colors as $position => $color) {
$color = imagecolorallocate($image, $color[0], $color[1], $color[2]);
imagefilledrectangle($image, $position * BARWIDTH, 0,
$position * BARWIDTH + BARWIDTH - 1,
HEIGHT - 1, $color);
}
header('Content-type:image/png');
imagepng($image);
imagedestroy($image); |
http://rosettacode.org/wiki/Closest-pair_problem | Closest-pair problem |
This page uses content from Wikipedia. The original article was at Closest pair of points problem. The list of authors can be seen in the page history. As with Rosetta Code, the text of Wikipedia is available under the GNU FDL. (See links for details on variance)
Task
Provide a function to find the closest two points among a set of given points in two dimensions, i.e. to solve the Closest pair of points problem in the planar case.
The straightforward solution is a O(n2) algorithm (which we can call brute-force algorithm); the pseudo-code (using indexes) could be simply:
bruteForceClosestPair of P(1), P(2), ... P(N)
if N < 2 then
return ∞
else
minDistance ← |P(1) - P(2)|
minPoints ← { P(1), P(2) }
foreach i ∈ [1, N-1]
foreach j ∈ [i+1, N]
if |P(i) - P(j)| < minDistance then
minDistance ← |P(i) - P(j)|
minPoints ← { P(i), P(j) }
endif
endfor
endfor
return minDistance, minPoints
endif
A better algorithm is based on the recursive divide&conquer approach, as explained also at Wikipedia's Closest pair of points problem, which is O(n log n); a pseudo-code could be:
closestPair of (xP, yP)
where xP is P(1) .. P(N) sorted by x coordinate, and
yP is P(1) .. P(N) sorted by y coordinate (ascending order)
if N ≤ 3 then
return closest points of xP using brute-force algorithm
else
xL ← points of xP from 1 to ⌈N/2⌉
xR ← points of xP from ⌈N/2⌉+1 to N
xm ← xP(⌈N/2⌉)x
yL ← { p ∈ yP : px ≤ xm }
yR ← { p ∈ yP : px > xm }
(dL, pairL) ← closestPair of (xL, yL)
(dR, pairR) ← closestPair of (xR, yR)
(dmin, pairMin) ← (dR, pairR)
if dL < dR then
(dmin, pairMin) ← (dL, pairL)
endif
yS ← { p ∈ yP : |xm - px| < dmin }
nS ← number of points in yS
(closest, closestPair) ← (dmin, pairMin)
for i from 1 to nS - 1
k ← i + 1
while k ≤ nS and yS(k)y - yS(i)y < dmin
if |yS(k) - yS(i)| < closest then
(closest, closestPair) ← (|yS(k) - yS(i)|, {yS(k), yS(i)})
endif
k ← k + 1
endwhile
endfor
return closest, closestPair
endif
References and further readings
Closest pair of points problem
Closest Pair (McGill)
Closest Pair (UCSB)
Closest pair (WUStL)
Closest pair (IUPUI)
| #AutoHotkey | AutoHotkey | ClosestPair(points){
if (points.count() <= 3)
return bruteForceClosestPair(points)
split := xSplit(Points)
LP := split.1 ; left points
LD := ClosestPair(LP) ; recursion : left closest pair
RP := split.2 ; right points
RD := ClosestPair(RP) ; recursion : right closest pair
minD := min(LD, RD) ; minimum of LD & RD
xmin := Split.3 - minD ; strip left boundary
xmax := Split.3 + minD ; strip right boundary
S := strip(points, xmin, xmax)
if (s.count()>=2)
{
SD := ClosestPair(S) ; recursion : strip closest pair
return min(SD, minD)
}
return minD
}
;---------------------------------------------------------------
strip(points, xmin, xmax){
strip:=[]
for i, coord in points
if (coord.1 >= xmin) && (coord.1 <= xmax)
strip.push([coord.1, coord.2])
return strip
}
;---------------------------------------------------------------
bruteForceClosestPair(points){
minD := []
loop, % points.count()-1{
p1 := points.RemoveAt(1)
loop, % points.count(){
p2 := points[A_Index]
d := dist(p1, p2)
minD.push(d)
}
}
return min(minD*)
}
;---------------------------------------------------------------
dist(p1, p2){
return Sqrt((p2.1-p1.1)**2 + (p2.2-p1.2)**2)
}
;---------------------------------------------------------------
xSplit(Points){
xL := [], xR := []
p := xSort(Points)
Loop % Ceil(p.count()/2)
xL.push(p.RemoveAt(1))
while p.count()
xR.push(p.RemoveAt(1))
mid := (xL[xl.count(),1] + xR[1,1])/2
return [xL, xR, mid]
}
;---------------------------------------------------------------
xSort(Points){
S := [], Res :=[]
for i, coord in points
S[coord.1, coord.2] := true
for x, coord in S
for y, v in coord
res.push([x, y])
return res
}
;--------------------------------------------------------------- |
http://rosettacode.org/wiki/Closures/Value_capture | Closures/Value capture | Task
Create a list of ten functions, in the simplest manner possible (anonymous functions are encouraged), such that the function at index i (you may choose to start i from either 0 or 1), when run, should return the square of the index, that is, i 2.
Display the result of running any but the last function, to demonstrate that the function indeed remembers its value.
Goal
Demonstrate how to create a series of independent closures based on the same template but maintain separate copies of the variable closed over.
In imperative languages, one would generally use a loop with a mutable counter variable.
For each function to maintain the correct number, it has to capture the value of the variable at the time it was created, rather than just a reference to the variable, which would have a different value by the time the function was run.
See also: Multiple distinct objects
| #Elena | Elena | import system'routines;
import extensions;
public program()
{
var functions := Array.allocate(10).populate:(int i => {^ i * i} );
functions.forEach:(func) { console.printLine(func()) }
} |
http://rosettacode.org/wiki/Closures/Value_capture | Closures/Value capture | Task
Create a list of ten functions, in the simplest manner possible (anonymous functions are encouraged), such that the function at index i (you may choose to start i from either 0 or 1), when run, should return the square of the index, that is, i 2.
Display the result of running any but the last function, to demonstrate that the function indeed remembers its value.
Goal
Demonstrate how to create a series of independent closures based on the same template but maintain separate copies of the variable closed over.
In imperative languages, one would generally use a loop with a mutable counter variable.
For each function to maintain the correct number, it has to capture the value of the variable at the time it was created, rather than just a reference to the variable, which would have a different value by the time the function was run.
See also: Multiple distinct objects
| #Elixir | Elixir | funs = for i <- 0..9, do: (fn -> i*i end)
Enum.each(funs, &IO.puts &1.()) |
http://rosettacode.org/wiki/Circular_primes | Circular primes | Definitions
A circular prime is a prime number with the property that the number generated at each intermediate step when cyclically permuting its (base 10) digits will also be prime.
For example:
1193 is a circular prime, since 1931, 9311 and 3119 are all also prime.
Note that a number which is a cyclic permutation of a smaller circular prime is not considered to be itself a circular prime. So 13 is a circular prime, but 31 is not.
A repunit (denoted by R) is a number whose base 10 representation contains only the digit 1.
For example:
R(2) = 11 and R(5) = 11111 are repunits.
Task
Find the first 19 circular primes.
If your language has access to arbitrary precision integer arithmetic, given that they are all repunits, find the next 4 circular primes.
(Stretch) Determine which of the following repunits are probably circular primes: R(5003), R(9887), R(15073), R(25031), R(35317) and R(49081). The larger ones may take a long time to process so just do as many as you reasonably can.
See also
Wikipedia article - Circular primes.
Wikipedia article - Repunit.
OEIS sequence A016114 - Circular primes.
| #Forth | Forth |
create 235-wheel 6 c, 4 c, 2 c, 4 c, 2 c, 4 c, 6 c, 2 c,
does> swap 7 and + c@ ;
0 1 2constant init-235 \ roll 235 wheel at position 1
: next-235 over 235-wheel + swap 1+ swap ;
\ check that n is prime excepting multiples of 2, 3, 5.
: sq dup * ;
: wheel-prime? ( n -- f )
>r init-235 begin
next-235
dup sq r@ > if rdrop 2drop true exit then
r@ over mod 0= if rdrop 2drop false exit then
again ;
: prime? ( n -- f )
dup 2 < if drop false exit then
dup 2 mod 0= if 2 = exit then
dup 3 mod 0= if 3 = exit then
dup 5 mod 0= if 5 = exit then
wheel-prime? ;
: log10^ ( n -- 10^[log n], log n )
dup 0<= abort" log10^: argument error."
1 0 rot
begin dup 9 > while
>r swap 10 * swap 1+ r> 10 /
repeat drop ;
: log10 ( n -- n ) log10^ nip ;
: rotate ( n -- n )
dup log10^ drop /mod swap 10 * + ;
: prime-rotation? ( p0 p -- f )
tuck <= swap prime? and ;
: circular? ( n -- f ) \ assume n is not a multiple of 2, 3, 5
dup wheel-prime? invert
if drop false exit
then dup >r true
over log10 0 ?do
swap rotate j over prime-rotation? rot and
loop nip rdrop ;
: .primes
2 . 3 . 5 .
16 init-235 \ -- count, [n1 n2] as 2,3,5 wheel
begin
next-235 dup circular?
if dup . rot 1- -rot
then
third 0= until 2drop drop ;
." The first 19 circular primes are:" cr .primes cr
bye
|
http://rosettacode.org/wiki/Collections | Collections | This task has been clarified. Its programming examples are in need of review to ensure that they still fit the requirements of the task.
Collections are abstractions to represent sets of values.
In statically-typed languages, the values are typically of a common data type.
Task
Create a collection, and add a few values to it.
See also
Array
Associative array: Creation, Iteration
Collections
Compound data type
Doubly-linked list: Definition, Element definition, Element insertion, List Traversal, Element Removal
Linked list
Queue: Definition, Usage
Set
Singly-linked list: Element definition, Element insertion, List Traversal, Element Removal
Stack
| #Arturo | Arturo | ; initialize array
arr: ["one" 2 "three" "four"]
; add an element to the array
arr: arr ++ 5
; print it
print arr |
http://rosettacode.org/wiki/Combinations | Combinations | Task
Given non-negative integers m and n, generate all size m combinations of the integers from 0 (zero) to n-1 in sorted order (each combination is sorted and the entire table is sorted).
Example
3 comb 5 is:
0 1 2
0 1 3
0 1 4
0 2 3
0 2 4
0 3 4
1 2 3
1 2 4
1 3 4
2 3 4
If it is more "natural" in your language to start counting from 1 (unity) instead of 0 (zero),
the combinations can be of the integers from 1 to n.
See also
The number of samples of size k from n objects.
With combinations and permutations generation tasks.
Order Unimportant
Order Important
Without replacement
(
n
k
)
=
n
C
k
=
n
(
n
−
1
)
…
(
n
−
k
+
1
)
k
(
k
−
1
)
…
1
{\displaystyle {\binom {n}{k}}=^{n}\operatorname {C} _{k}={\frac {n(n-1)\ldots (n-k+1)}{k(k-1)\dots 1}}}
n
P
k
=
n
⋅
(
n
−
1
)
⋅
(
n
−
2
)
⋯
(
n
−
k
+
1
)
{\displaystyle ^{n}\operatorname {P} _{k}=n\cdot (n-1)\cdot (n-2)\cdots (n-k+1)}
Task: Combinations
Task: Permutations
With replacement
(
n
+
k
−
1
k
)
=
n
+
k
−
1
C
k
=
(
n
+
k
−
1
)
!
(
n
−
1
)
!
k
!
{\displaystyle {\binom {n+k-1}{k}}=^{n+k-1}\operatorname {C} _{k}={(n+k-1)! \over (n-1)!k!}}
n
k
{\displaystyle n^{k}}
Task: Combinations with repetitions
Task: Permutations with repetitions
| #Fortran | Fortran | program Combinations
use iso_fortran_env
implicit none
type comb_result
integer, dimension(:), allocatable :: combs
end type comb_result
type(comb_result), dimension(:), pointer :: r
integer :: i, j
call comb(5, 3, r)
do i = 0, choose(5, 3) - 1
do j = 2, 0, -1
write(*, "(I4, ' ')", advance="no") r(i)%combs(j)
end do
deallocate(r(i)%combs)
write(*,*) ""
end do
deallocate(r)
contains
function choose(n, k, err)
integer :: choose
integer, intent(in) :: n, k
integer, optional, intent(out) :: err
integer :: imax, i, imin, ie
ie = 0
if ( (n < 0 ) .or. (k < 0 ) ) then
write(ERROR_UNIT, *) "negative in choose"
choose = 0
ie = 1
else
if ( n < k ) then
choose = 0
else if ( n == k ) then
choose = 1
else
imax = max(k, n-k)
imin = min(k, n-k)
choose = 1
do i = imax+1, n
choose = choose * i
end do
do i = 2, imin
choose = choose / i
end do
end if
end if
if ( present(err) ) err = ie
end function choose
subroutine comb(n, k, co)
integer, intent(in) :: n, k
type(comb_result), dimension(:), pointer, intent(out) :: co
integer :: i, j, s, ix, kx, hm, t
integer :: err
hm = choose(n, k, err)
if ( err /= 0 ) then
nullify(co)
return
end if
allocate(co(0:hm-1))
do i = 0, hm-1
allocate(co(i)%combs(0:k-1))
end do
do i = 0, hm-1
ix = i; kx = k
do s = 0, n-1
if ( kx == 0 ) exit
t = choose(n-(s+1), kx-1)
if ( ix < t ) then
co(i)%combs(kx-1) = s
kx = kx - 1
else
ix = ix - t
end if
end do
end do
end subroutine comb
end program Combinations |
http://rosettacode.org/wiki/Conditional_structures | Conditional structures | Control Structures
These are examples of control structures. You may also be interested in:
Conditional structures
Exceptions
Flow-control structures
Loops
Task
List the conditional structures offered by a programming language. See Wikipedia: conditionals for descriptions.
Common conditional structures include if-then-else and switch.
Less common are arithmetic if, ternary operator and Hash-based conditionals.
Arithmetic if allows tight control over computed gotos, which optimizers have a hard time to figure out.
| #ooRexx | ooRexx | if arg~isa(.string) & arg~left(1) == "*" then call processArg arg |
http://rosettacode.org/wiki/Comments | Comments | Task
Show all ways to include text in a language source file
that's completely ignored by the compiler or interpreter.
Related tasks
Documentation
Here_document
See also
Wikipedia
xkcd (Humor: hand gesture denoting // for "commenting out" people.)
| #Stata | Stata | * Line comment: must be used at the beginning of a line (does not work in Mata)
// Line comment until the end of the line
/* Multiline comment
*/ |
http://rosettacode.org/wiki/Comments | Comments | Task
Show all ways to include text in a language source file
that's completely ignored by the compiler or interpreter.
Related tasks
Documentation
Here_document
See also
Wikipedia
xkcd (Humor: hand gesture denoting // for "commenting out" people.)
| #Swift | Swift | // this is a single line comment
/* This a block comment
/* containing nested comment */
*/
///This is a documentation comment
/**
This is a documentation block comment
*/ |
http://rosettacode.org/wiki/Comments | Comments | Task
Show all ways to include text in a language source file
that's completely ignored by the compiler or interpreter.
Related tasks
Documentation
Here_document
See also
Wikipedia
xkcd (Humor: hand gesture denoting // for "commenting out" people.)
| #Symsyn | Symsyn |
| This is a comment
|
http://rosettacode.org/wiki/Classes | Classes | In object-oriented programming class is a set (a transitive closure) of types bound by the relation of inheritance. It is said that all types derived from some base type T and the type T itself form a class T.
The first type T from the class T sometimes is called the root type of the class.
A class of types itself, as a type, has the values and operations of its own.
The operations of are usually called methods of the root type.
Both operations and values are called polymorphic.
A polymorphic operation (method) selects an implementation depending on the actual specific type of the polymorphic argument.
The action of choice the type-specific implementation of a polymorphic operation is called dispatch. Correspondingly, polymorphic operations are often called dispatching or virtual.
Operations with multiple arguments and/or the results of the class are called multi-methods.
A further generalization of is the operation with arguments and/or results from different classes.
single-dispatch languages are those that allow only one argument or result to control the dispatch. Usually it is the first parameter, often hidden, so that a prefix notation x.f() is used instead of mathematical f(x).
multiple-dispatch languages allow many arguments and/or results to control the dispatch.
A polymorphic value has a type tag indicating its specific type from the class and the corresponding specific value of that type.
This type is sometimes called the most specific type of a [polymorphic] value.
The type tag of the value is used in order to resolve the dispatch.
The set of polymorphic values of a class is a transitive closure of the sets of values of all types from that class.
In many OO languages
the type of the class of T and T itself are considered equivalent.
In some languages they are distinct (like in Ada).
When class T and T are equivalent, there is no way to distinguish
polymorphic and specific values.
Task
Create a basic class with a method, a constructor, an instance variable and how to instantiate it.
| #Aikido | Aikido | class Circle (radius, x, y) extends Shape (x, y) implements Drawable {
var myvec = new Vector (x, y)
public function draw() {
// draw the circle
}
} |
http://rosettacode.org/wiki/Classes | Classes | In object-oriented programming class is a set (a transitive closure) of types bound by the relation of inheritance. It is said that all types derived from some base type T and the type T itself form a class T.
The first type T from the class T sometimes is called the root type of the class.
A class of types itself, as a type, has the values and operations of its own.
The operations of are usually called methods of the root type.
Both operations and values are called polymorphic.
A polymorphic operation (method) selects an implementation depending on the actual specific type of the polymorphic argument.
The action of choice the type-specific implementation of a polymorphic operation is called dispatch. Correspondingly, polymorphic operations are often called dispatching or virtual.
Operations with multiple arguments and/or the results of the class are called multi-methods.
A further generalization of is the operation with arguments and/or results from different classes.
single-dispatch languages are those that allow only one argument or result to control the dispatch. Usually it is the first parameter, often hidden, so that a prefix notation x.f() is used instead of mathematical f(x).
multiple-dispatch languages allow many arguments and/or results to control the dispatch.
A polymorphic value has a type tag indicating its specific type from the class and the corresponding specific value of that type.
This type is sometimes called the most specific type of a [polymorphic] value.
The type tag of the value is used in order to resolve the dispatch.
The set of polymorphic values of a class is a transitive closure of the sets of values of all types from that class.
In many OO languages
the type of the class of T and T itself are considered equivalent.
In some languages they are distinct (like in Ada).
When class T and T are equivalent, there is no way to distinguish
polymorphic and specific values.
Task
Create a basic class with a method, a constructor, an instance variable and how to instantiate it.
| #ALGOL_68 | ALGOL 68 | MODE MYDATA = STRUCT(
INT name1
);
STRUCT(
INT name2,
PROC (REF MYDATA)REF MYDATA new,
PROC (REF MYDATA)VOID init,
PROC (REF MYDATA)VOID some method
) class my data;
class my data := (
# name2 := # 2, # Class attribute #
# PROC new := # (REF MYDATA new)REF MYDATA:(
(init OF class my data)(new);
new
),
# PROC init := # (REF MYDATA self)VOID:(
""" Constructor (Technically an initializer rather than a true 'constructor') """;
name1 OF self := 0 # Instance attribute #
),
# PROC some method := # (REF MYDATA self)VOID:(
""" Method """;
name1 OF self := 1;
name2 OF class my data := 3
)
);
# class name, invoked as a function is the constructor syntax #
REF MYDATA my data = (new OF class my data)(LOC MYDATA);
MODE GENDEROPT = UNION(STRING, VOID);
MODE AGEOPT = UNION(INT, VOID);
MODE MYOTHERDATA = STRUCT(
STRING name,
GENDEROPT gender,
AGEOPT age
);
STRUCT (
INT count,
PROC (REF MYOTHERDATA, STRING, GENDEROPT, AGEOPT)REF MYOTHERDATA new,
PROC (REF MYOTHERDATA, STRING, GENDEROPT, AGEOPT)VOID init,
PROC (REF MYOTHERDATA)VOID del
) class my other data;
class my other data := (
# count := # 0, # Population of "(init OF class my other data)" objects #
# PROC new := # (REF MYOTHERDATA new, STRING name, GENDEROPT gender, AGEOPT age)REF MYOTHERDATA:(
(init OF class my other data)(new, name, gender, age);
new
),
# PROC init := # (REF MYOTHERDATA self, STRING name, GENDEROPT gender, AGEOPT age)VOID:(
""" One initializer required, others are optional (with different defaults) """;
count OF class my other data +:= 1;
name OF self := name;
gender OF self := gender;
CASE gender OF self IN
(VOID):gender OF self := "Male"
ESAC;
age OF self := age
),
# PROC del := # (REF MYOTHERDATA self)VOID:(
count OF class my other data -:= 1
)
);
PROC attribute error := STRING: error char; # mend the error with the "error char" #
# Allocate the instance from HEAP #
REF MYOTHERDATA person1 = (new OF class my other data)(HEAP MYOTHERDATA, "John", EMPTY, EMPTY);
print (((name OF person1), ": ",
(gender OF person1|(STRING gender):gender|attribute error), " ")); # "John Male" #
print (((age OF person1|(INT age):age|attribute error), new line)); # Raises AttributeError exception! #
# Allocate the instance from LOC (stack) #
REF MYOTHERDATA person2 = (new OF class my other data)(LOC MYOTHERDATA, "Jane", "Female", 23);
print (((name OF person2), ": ",
(gender OF person2|(STRING gender):gender|attribute error), " "));
print (((age OF person2|(INT age):age|attribute error), new line)) # "Jane Female 23" # |
http://rosettacode.org/wiki/Cistercian_numerals | Cistercian numerals | Cistercian numerals were used across Europe by Cistercian monks during the Late Medieval Period as an alternative to Roman numerals. They were used to represent base 10 integers from 0 to 9999.
How they work
All Cistercian numerals begin with a vertical line segment, which by itself represents the number 0. Then, glyphs representing the digits 1 through 9 are optionally added to the four quadrants surrounding the vertical line segment. These glyphs are drawn with vertical and horizontal symmetry about the initial line segment. Each quadrant corresponds to a digit place in the number:
The upper-right quadrant represents the ones place.
The upper-left quadrant represents the tens place.
The lower-right quadrant represents the hundreds place.
The lower-left quadrant represents the thousands place.
Please consult the following image for examples of Cistercian numerals showing each glyph: [1]
Task
Write a function/procedure/routine to display any given Cistercian numeral. This could be done by drawing to the display, creating an image, or even as text (as long as it is a reasonable facsimile).
Use the routine to show the following Cistercian numerals:
0
1
20
300
4000
5555
6789
And a number of your choice!
Notes
Due to the inability to upload images to Rosetta Code as of this task's creation, showing output here on this page is not required. However, it is welcomed — especially for text output.
See also
Numberphile - The Forgotten Number System
dcode.fr - Online Cistercian numeral converter
| #C | C | #include <stdio.h>
#define GRID_SIZE 15
char canvas[GRID_SIZE][GRID_SIZE];
void initN() {
int i, j;
for (i = 0; i < GRID_SIZE; i++) {
for (j = 0; j < GRID_SIZE; j++) {
canvas[i][j] = ' ';
}
canvas[i][5] = 'x';
}
}
void horizontal(size_t c1, size_t c2, size_t r) {
size_t c;
for (c = c1; c <= c2; c++) {
canvas[r][c] = 'x';
}
}
void vertical(size_t r1, size_t r2, size_t c) {
size_t r;
for (r = r1; r <= r2; r++) {
canvas[r][c] = 'x';
}
}
void diagd(size_t c1, size_t c2, size_t r) {
size_t c;
for (c = c1; c <= c2; c++) {
canvas[r + c - c1][c] = 'x';
}
}
void diagu(size_t c1, size_t c2, size_t r) {
size_t c;
for (c = c1; c <= c2; c++) {
canvas[r - c + c1][c] = 'x';
}
}
void drawOnes(int v) {
switch (v) {
case 1:
horizontal(6, 10, 0);
break;
case 2:
horizontal(6, 10, 4);
break;
case 3:
diagd(6, 10, 0);
break;
case 4:
diagu(6, 10, 4);
break;
case 5:
drawOnes(1);
drawOnes(4);
break;
case 6:
vertical(0, 4, 10);
break;
case 7:
drawOnes(1);
drawOnes(6);
break;
case 8:
drawOnes(2);
drawOnes(6);
break;
case 9:
drawOnes(1);
drawOnes(8);
break;
default:
break;
}
}
void drawTens(int v) {
switch (v) {
case 1:
horizontal(0, 4, 0);
break;
case 2:
horizontal(0, 4, 4);
break;
case 3:
diagu(0, 4, 4);
break;
case 4:
diagd(0, 4, 0);
break;
case 5:
drawTens(1);
drawTens(4);
break;
case 6:
vertical(0, 4, 0);
break;
case 7:
drawTens(1);
drawTens(6);
break;
case 8:
drawTens(2);
drawTens(6);
break;
case 9:
drawTens(1);
drawTens(8);
break;
default:
break;
}
}
void drawHundreds(int hundreds) {
switch (hundreds) {
case 1:
horizontal(6, 10, 14);
break;
case 2:
horizontal(6, 10, 10);
break;
case 3:
diagu(6, 10, 14);
break;
case 4:
diagd(6, 10, 10);
break;
case 5:
drawHundreds(1);
drawHundreds(4);
break;
case 6:
vertical(10, 14, 10);
break;
case 7:
drawHundreds(1);
drawHundreds(6);
break;
case 8:
drawHundreds(2);
drawHundreds(6);
break;
case 9:
drawHundreds(1);
drawHundreds(8);
break;
default:
break;
}
}
void drawThousands(int thousands) {
switch (thousands) {
case 1:
horizontal(0, 4, 14);
break;
case 2:
horizontal(0, 4, 10);
break;
case 3:
diagd(0, 4, 10);
break;
case 4:
diagu(0, 4, 14);
break;
case 5:
drawThousands(1);
drawThousands(4);
break;
case 6:
vertical(10, 14, 0);
break;
case 7:
drawThousands(1);
drawThousands(6);
break;
case 8:
drawThousands(2);
drawThousands(6);
break;
case 9:
drawThousands(1);
drawThousands(8);
break;
default:
break;
}
}
void draw(int v) {
int thousands = v / 1000;
v %= 1000;
int hundreds = v / 100;
v %= 100;
int tens = v / 10;
int ones = v % 10;
if (thousands > 0) {
drawThousands(thousands);
}
if (hundreds > 0) {
drawHundreds(hundreds);
}
if (tens > 0) {
drawTens(tens);
}
if (ones > 0) {
drawOnes(ones);
}
}
void write(FILE *out) {
int i;
for (i = 0; i < GRID_SIZE; i++) {
fprintf(out, "%-.*s", GRID_SIZE, canvas[i]);
putc('\n', out);
}
}
void test(int n) {
printf("%d:\n", n);
initN();
draw(n);
write(stdout);
printf("\n\n");
}
int main() {
test(0);
test(1);
test(20);
test(300);
test(4000);
test(5555);
test(6789);
test(9999);
return 0;
} |
http://rosettacode.org/wiki/Colour_bars/Display | Colour bars/Display | Task
Display a series of vertical color bars across the width of the display.
The color bars should either use:
the system palette, or
the sequence of colors:
black
red
green
blue
magenta
cyan
yellow
white
| #PicoLisp | PicoLisp | (call 'clear)
(let Width (in '(tput cols) (read))
(do (in '(tput lines) (read))
(for B (range 0 7)
(call 'tput 'setab B)
(space (/ Width 8)) )
(prinl) ) )
(call 'tput 'sgr0) # reset |
http://rosettacode.org/wiki/Colour_bars/Display | Colour bars/Display | Task
Display a series of vertical color bars across the width of the display.
The color bars should either use:
the system palette, or
the sequence of colors:
black
red
green
blue
magenta
cyan
yellow
white
| #Plain_English | Plain English | To run:
Start up.
Clear the screen.
Divide the screen width by 8 giving a bar width.
Make a bar with 0 and 0 and the bar width and the screen's bottom.
Draw the color bars using the bar.
Refresh the screen.
Wait for the escape key.
Shut down.
To divide the screen width by a number giving a width:
Put the screen's right into the width.
Divide the width by the number.
A bar is a box.
To draw a bar using a color and move it over:
Draw and fill the bar with the color.
Move the bar right the bar's width.
To draw the color bars using a bar:
Draw the bar using the black color and move it over.
Draw the bar using the red color and move it over.
Draw the bar using the green color and move it over.
Draw the bar using the blue color and move it over.
Draw the bar using the magenta color and move it over.
Draw the bar using the cyan color and move it over.
Draw the bar using the yellow color and move it over.
Draw and fill the bar using the white color. |
http://rosettacode.org/wiki/Colour_bars/Display | Colour bars/Display | Task
Display a series of vertical color bars across the width of the display.
The color bars should either use:
the system palette, or
the sequence of colors:
black
red
green
blue
magenta
cyan
yellow
white
| #PowerShell | PowerShell |
[string[]]$colors = "Black" , "DarkBlue" , "DarkGreen" , "DarkCyan",
"DarkRed" , "DarkMagenta", "DarkYellow", "Gray",
"DarkGray", "Blue" , "Green" , "Cyan",
"Red" , "Magenta" , "Yellow" , "White"
for ($i = 0; $i -lt 64; $i++)
{
for ($j = 0; $j -lt $colors.Count; $j++)
{
Write-Host (" " * 12) -BackgroundColor $colors[$j] -NoNewline
}
Write-Host
}
|
http://rosettacode.org/wiki/Closest-pair_problem | Closest-pair problem |
This page uses content from Wikipedia. The original article was at Closest pair of points problem. The list of authors can be seen in the page history. As with Rosetta Code, the text of Wikipedia is available under the GNU FDL. (See links for details on variance)
Task
Provide a function to find the closest two points among a set of given points in two dimensions, i.e. to solve the Closest pair of points problem in the planar case.
The straightforward solution is a O(n2) algorithm (which we can call brute-force algorithm); the pseudo-code (using indexes) could be simply:
bruteForceClosestPair of P(1), P(2), ... P(N)
if N < 2 then
return ∞
else
minDistance ← |P(1) - P(2)|
minPoints ← { P(1), P(2) }
foreach i ∈ [1, N-1]
foreach j ∈ [i+1, N]
if |P(i) - P(j)| < minDistance then
minDistance ← |P(i) - P(j)|
minPoints ← { P(i), P(j) }
endif
endfor
endfor
return minDistance, minPoints
endif
A better algorithm is based on the recursive divide&conquer approach, as explained also at Wikipedia's Closest pair of points problem, which is O(n log n); a pseudo-code could be:
closestPair of (xP, yP)
where xP is P(1) .. P(N) sorted by x coordinate, and
yP is P(1) .. P(N) sorted by y coordinate (ascending order)
if N ≤ 3 then
return closest points of xP using brute-force algorithm
else
xL ← points of xP from 1 to ⌈N/2⌉
xR ← points of xP from ⌈N/2⌉+1 to N
xm ← xP(⌈N/2⌉)x
yL ← { p ∈ yP : px ≤ xm }
yR ← { p ∈ yP : px > xm }
(dL, pairL) ← closestPair of (xL, yL)
(dR, pairR) ← closestPair of (xR, yR)
(dmin, pairMin) ← (dR, pairR)
if dL < dR then
(dmin, pairMin) ← (dL, pairL)
endif
yS ← { p ∈ yP : |xm - px| < dmin }
nS ← number of points in yS
(closest, closestPair) ← (dmin, pairMin)
for i from 1 to nS - 1
k ← i + 1
while k ≤ nS and yS(k)y - yS(i)y < dmin
if |yS(k) - yS(i)| < closest then
(closest, closestPair) ← (|yS(k) - yS(i)|, {yS(k), yS(i)})
endif
k ← k + 1
endwhile
endfor
return closest, closestPair
endif
References and further readings
Closest pair of points problem
Closest Pair (McGill)
Closest Pair (UCSB)
Closest pair (WUStL)
Closest pair (IUPUI)
| #AWK | AWK |
# syntax: GAWK -f CLOSEST-PAIR_PROBLEM.AWK
BEGIN {
x[++n] = 0.654682 ; y[n] = 0.925557
x[++n] = 0.409382 ; y[n] = 0.619391
x[++n] = 0.891663 ; y[n] = 0.888594
x[++n] = 0.716629 ; y[n] = 0.996200
x[++n] = 0.477721 ; y[n] = 0.946355
x[++n] = 0.925092 ; y[n] = 0.818220
x[++n] = 0.624291 ; y[n] = 0.142924
x[++n] = 0.211332 ; y[n] = 0.221507
x[++n] = 0.293786 ; y[n] = 0.691701
x[++n] = 0.839186 ; y[n] = 0.728260
min = 1E20
for (i=1; i<=n-1; i++) {
for (j=i+1; j<=n; j++) {
dsq = (x[i]-x[j])^2 + (y[i]-y[j])^2
if (dsq < min) {
min = dsq
mini = i
minj = j
}
}
}
printf("distance between (%.6f,%.6f) and (%.6f,%.6f) is %g\n",x[mini],y[mini],x[minj],y[minj],sqrt(min))
exit(0)
}
|
http://rosettacode.org/wiki/Closures/Value_capture | Closures/Value capture | Task
Create a list of ten functions, in the simplest manner possible (anonymous functions are encouraged), such that the function at index i (you may choose to start i from either 0 or 1), when run, should return the square of the index, that is, i 2.
Display the result of running any but the last function, to demonstrate that the function indeed remembers its value.
Goal
Demonstrate how to create a series of independent closures based on the same template but maintain separate copies of the variable closed over.
In imperative languages, one would generally use a loop with a mutable counter variable.
For each function to maintain the correct number, it has to capture the value of the variable at the time it was created, rather than just a reference to the variable, which would have a different value by the time the function was run.
See also: Multiple distinct objects
| #Emacs_Lisp | Emacs Lisp | ;; -*- lexical-binding: t; -*-
(mapcar #'funcall
(mapcar (lambda (x)
(lambda ()
(* x x)))
'(1 2 3 4 5 6 7 8 9 10)))
;; => (1 4 9 16 25 36 49 64 81 100) |
http://rosettacode.org/wiki/Closures/Value_capture | Closures/Value capture | Task
Create a list of ten functions, in the simplest manner possible (anonymous functions are encouraged), such that the function at index i (you may choose to start i from either 0 or 1), when run, should return the square of the index, that is, i 2.
Display the result of running any but the last function, to demonstrate that the function indeed remembers its value.
Goal
Demonstrate how to create a series of independent closures based on the same template but maintain separate copies of the variable closed over.
In imperative languages, one would generally use a loop with a mutable counter variable.
For each function to maintain the correct number, it has to capture the value of the variable at the time it was created, rather than just a reference to the variable, which would have a different value by the time the function was run.
See also: Multiple distinct objects
| #Erlang | Erlang |
-module(capture_demo).
-export([demo/0]).
demo() ->
Funs = lists:map(fun (X) ->
fun () ->
X * X
end
end,
lists:seq(1,10)),
lists:foreach(fun (F) ->
io:fwrite("~B~n",[F()])
end, Funs).
|
http://rosettacode.org/wiki/Circular_primes | Circular primes | Definitions
A circular prime is a prime number with the property that the number generated at each intermediate step when cyclically permuting its (base 10) digits will also be prime.
For example:
1193 is a circular prime, since 1931, 9311 and 3119 are all also prime.
Note that a number which is a cyclic permutation of a smaller circular prime is not considered to be itself a circular prime. So 13 is a circular prime, but 31 is not.
A repunit (denoted by R) is a number whose base 10 representation contains only the digit 1.
For example:
R(2) = 11 and R(5) = 11111 are repunits.
Task
Find the first 19 circular primes.
If your language has access to arbitrary precision integer arithmetic, given that they are all repunits, find the next 4 circular primes.
(Stretch) Determine which of the following repunits are probably circular primes: R(5003), R(9887), R(15073), R(25031), R(35317) and R(49081). The larger ones may take a long time to process so just do as many as you reasonably can.
See also
Wikipedia article - Circular primes.
Wikipedia article - Repunit.
OEIS sequence A016114 - Circular primes.
| #FreeBASIC | FreeBASIC | #define floor(x) ((x*2.0-0.5)Shr 1)
Function isPrime(Byval p As Integer) As Boolean
If p < 2 Then Return False
If p Mod 2 = 0 Then Return p = 2
If p Mod 3 = 0 Then Return p = 3
Dim As Integer d = 5
While d * d <= p
If p Mod d = 0 Then Return False Else d += 2
If p Mod d = 0 Then Return False Else d += 4
Wend
Return True
End Function
Function isCircularPrime(Byval p As Integer) As Boolean
Dim As Integer n = floor(Log(p)/Log(10))
Dim As Integer m = 10^n, q = p
For i As Integer = 0 To n
If (q < p Or Not isPrime(q)) Then Return false
q = (q Mod m) * 10 + floor(q / m)
Next i
Return true
End Function
Dim As Integer p = 2, dp = 1, cont = 0
Print("Primeros 19 primos circulares:")
While cont < 19
If isCircularPrime(p) Then Print p;" "; : cont += 1
p += dp: dp = 2
Wend
Sleep |
http://rosettacode.org/wiki/Collections | Collections | This task has been clarified. Its programming examples are in need of review to ensure that they still fit the requirements of the task.
Collections are abstractions to represent sets of values.
In statically-typed languages, the values are typically of a common data type.
Task
Create a collection, and add a few values to it.
See also
Array
Associative array: Creation, Iteration
Collections
Compound data type
Doubly-linked list: Definition, Element definition, Element insertion, List Traversal, Element Removal
Linked list
Queue: Definition, Usage
Set
Singly-linked list: Element definition, Element insertion, List Traversal, Element Removal
Stack
| #AutoHotkey | AutoHotkey | myCol := Object()
mycol.mykey := "my value!"
mycol["mykey"] := "new val!"
MsgBox % mycol.mykey ; new val |
http://rosettacode.org/wiki/Combinations | Combinations | Task
Given non-negative integers m and n, generate all size m combinations of the integers from 0 (zero) to n-1 in sorted order (each combination is sorted and the entire table is sorted).
Example
3 comb 5 is:
0 1 2
0 1 3
0 1 4
0 2 3
0 2 4
0 3 4
1 2 3
1 2 4
1 3 4
2 3 4
If it is more "natural" in your language to start counting from 1 (unity) instead of 0 (zero),
the combinations can be of the integers from 1 to n.
See also
The number of samples of size k from n objects.
With combinations and permutations generation tasks.
Order Unimportant
Order Important
Without replacement
(
n
k
)
=
n
C
k
=
n
(
n
−
1
)
…
(
n
−
k
+
1
)
k
(
k
−
1
)
…
1
{\displaystyle {\binom {n}{k}}=^{n}\operatorname {C} _{k}={\frac {n(n-1)\ldots (n-k+1)}{k(k-1)\dots 1}}}
n
P
k
=
n
⋅
(
n
−
1
)
⋅
(
n
−
2
)
⋯
(
n
−
k
+
1
)
{\displaystyle ^{n}\operatorname {P} _{k}=n\cdot (n-1)\cdot (n-2)\cdots (n-k+1)}
Task: Combinations
Task: Permutations
With replacement
(
n
+
k
−
1
k
)
=
n
+
k
−
1
C
k
=
(
n
+
k
−
1
)
!
(
n
−
1
)
!
k
!
{\displaystyle {\binom {n+k-1}{k}}=^{n+k-1}\operatorname {C} _{k}={(n+k-1)! \over (n-1)!k!}}
n
k
{\displaystyle n^{k}}
Task: Combinations with repetitions
Task: Permutations with repetitions
| #FreeBASIC | FreeBASIC | sub iterate( byval curr as string, byval start as uinteger,_
byval stp as uinteger, byval depth as uinteger )
dim as uinteger i
for i = start to stp
if depth = 0 then
print curr + " " + str(i)
end if
iterate( curr+" "+str(i), i+1, stp, depth-1 )
next i
return
end sub
dim as uinteger m, n
input "Enter n comb m. ", n, m
dim as string outstr = ""
iterate outstr, 0, m-1, n-1 |
http://rosettacode.org/wiki/Conditional_structures | Conditional structures | Control Structures
These are examples of control structures. You may also be interested in:
Conditional structures
Exceptions
Flow-control structures
Loops
Task
List the conditional structures offered by a programming language. See Wikipedia: conditionals for descriptions.
Common conditional structures include if-then-else and switch.
Less common are arithmetic if, ternary operator and Hash-based conditionals.
Arithmetic if allows tight control over computed gotos, which optimizers have a hard time to figure out.
| #OxygenBasic | OxygenBasic |
if a then b=c else b=d
if a=0
b=c
elseif a<0
b=d
else
b=e
end if
select case a
case 'A'
v=21
case 'B'
v=22
case 1 to 64
v=a+300
case else
v=0
end select
|
http://rosettacode.org/wiki/Comments | Comments | Task
Show all ways to include text in a language source file
that's completely ignored by the compiler or interpreter.
Related tasks
Documentation
Here_document
See also
Wikipedia
xkcd (Humor: hand gesture denoting // for "commenting out" people.)
| #Tcl | Tcl | # comment on a line by itself. The next is a command by itself:
set var1 $value1
set var2 $value2 ; # comment that follows a line of code |
http://rosettacode.org/wiki/Comments | Comments | Task
Show all ways to include text in a language source file
that's completely ignored by the compiler or interpreter.
Related tasks
Documentation
Here_document
See also
Wikipedia
xkcd (Humor: hand gesture denoting // for "commenting out" people.)
| #Tern | Tern | :"THIS IS A COMMENT |
http://rosettacode.org/wiki/Comments | Comments | Task
Show all ways to include text in a language source file
that's completely ignored by the compiler or interpreter.
Related tasks
Documentation
Here_document
See also
Wikipedia
xkcd (Humor: hand gesture denoting // for "commenting out" people.)
| #TI-83_BASIC | TI-83 BASIC | :"THIS IS A COMMENT |
http://rosettacode.org/wiki/Classes | Classes | In object-oriented programming class is a set (a transitive closure) of types bound by the relation of inheritance. It is said that all types derived from some base type T and the type T itself form a class T.
The first type T from the class T sometimes is called the root type of the class.
A class of types itself, as a type, has the values and operations of its own.
The operations of are usually called methods of the root type.
Both operations and values are called polymorphic.
A polymorphic operation (method) selects an implementation depending on the actual specific type of the polymorphic argument.
The action of choice the type-specific implementation of a polymorphic operation is called dispatch. Correspondingly, polymorphic operations are often called dispatching or virtual.
Operations with multiple arguments and/or the results of the class are called multi-methods.
A further generalization of is the operation with arguments and/or results from different classes.
single-dispatch languages are those that allow only one argument or result to control the dispatch. Usually it is the first parameter, often hidden, so that a prefix notation x.f() is used instead of mathematical f(x).
multiple-dispatch languages allow many arguments and/or results to control the dispatch.
A polymorphic value has a type tag indicating its specific type from the class and the corresponding specific value of that type.
This type is sometimes called the most specific type of a [polymorphic] value.
The type tag of the value is used in order to resolve the dispatch.
The set of polymorphic values of a class is a transitive closure of the sets of values of all types from that class.
In many OO languages
the type of the class of T and T itself are considered equivalent.
In some languages they are distinct (like in Ada).
When class T and T are equivalent, there is no way to distinguish
polymorphic and specific values.
Task
Create a basic class with a method, a constructor, an instance variable and how to instantiate it.
| #AmigaE | AmigaE | OBJECT a_class
varA, varP
ENDOBJECT
-> this could be used like a constructor
PROC init() OF a_class
self.varP := 10
self.varA := 2
ENDPROC
-> the special proc end() is for destructor
PROC end() OF a_class
-> nothing to do here...
ENDPROC
-> a not so useful getter
PROC getP() OF a_class IS self.varP
PROC main()
DEF obj : PTR TO a_class
NEW obj.init()
WriteF('\d\n', obj.varA) -> this can be done, while
-> varP can't be accessed directly
WriteF('\d\n', obj.varP) -> or
WriteF('\d\n', obj.getP())
END obj
ENDPROC |
http://rosettacode.org/wiki/Classes | Classes | In object-oriented programming class is a set (a transitive closure) of types bound by the relation of inheritance. It is said that all types derived from some base type T and the type T itself form a class T.
The first type T from the class T sometimes is called the root type of the class.
A class of types itself, as a type, has the values and operations of its own.
The operations of are usually called methods of the root type.
Both operations and values are called polymorphic.
A polymorphic operation (method) selects an implementation depending on the actual specific type of the polymorphic argument.
The action of choice the type-specific implementation of a polymorphic operation is called dispatch. Correspondingly, polymorphic operations are often called dispatching or virtual.
Operations with multiple arguments and/or the results of the class are called multi-methods.
A further generalization of is the operation with arguments and/or results from different classes.
single-dispatch languages are those that allow only one argument or result to control the dispatch. Usually it is the first parameter, often hidden, so that a prefix notation x.f() is used instead of mathematical f(x).
multiple-dispatch languages allow many arguments and/or results to control the dispatch.
A polymorphic value has a type tag indicating its specific type from the class and the corresponding specific value of that type.
This type is sometimes called the most specific type of a [polymorphic] value.
The type tag of the value is used in order to resolve the dispatch.
The set of polymorphic values of a class is a transitive closure of the sets of values of all types from that class.
In many OO languages
the type of the class of T and T itself are considered equivalent.
In some languages they are distinct (like in Ada).
When class T and T are equivalent, there is no way to distinguish
polymorphic and specific values.
Task
Create a basic class with a method, a constructor, an instance variable and how to instantiate it.
| #AutoHotkey | AutoHotkey | obj := new MyClass
obj.WhenCreated()
class MyClass {
; Instance Variable #1
time := A_Hour ":" A_Min ":" A_Sec
; Constructor
__New() {
MsgBox, % "Constructing new object of type: " this.__Class
FormatTime, date, , MM/dd/yyyy
; Instance Variable #2
this.date := date
}
; Method
WhenCreated() {
MsgBox, % "Object created at " this.time " on " this.date
}
} |
http://rosettacode.org/wiki/Cistercian_numerals | Cistercian numerals | Cistercian numerals were used across Europe by Cistercian monks during the Late Medieval Period as an alternative to Roman numerals. They were used to represent base 10 integers from 0 to 9999.
How they work
All Cistercian numerals begin with a vertical line segment, which by itself represents the number 0. Then, glyphs representing the digits 1 through 9 are optionally added to the four quadrants surrounding the vertical line segment. These glyphs are drawn with vertical and horizontal symmetry about the initial line segment. Each quadrant corresponds to a digit place in the number:
The upper-right quadrant represents the ones place.
The upper-left quadrant represents the tens place.
The lower-right quadrant represents the hundreds place.
The lower-left quadrant represents the thousands place.
Please consult the following image for examples of Cistercian numerals showing each glyph: [1]
Task
Write a function/procedure/routine to display any given Cistercian numeral. This could be done by drawing to the display, creating an image, or even as text (as long as it is a reasonable facsimile).
Use the routine to show the following Cistercian numerals:
0
1
20
300
4000
5555
6789
And a number of your choice!
Notes
Due to the inability to upload images to Rosetta Code as of this task's creation, showing output here on this page is not required. However, it is welcomed — especially for text output.
See also
Numberphile - The Forgotten Number System
dcode.fr - Online Cistercian numeral converter
| #C.2B.2B | C++ | #include <array>
#include <iostream>
template<typename T, size_t S>
using FixedSquareGrid = std::array<std::array<T, S>, S>;
struct Cistercian {
public:
Cistercian() {
initN();
}
Cistercian(int v) {
initN();
draw(v);
}
Cistercian &operator=(int v) {
initN();
draw(v);
}
friend std::ostream &operator<<(std::ostream &, const Cistercian &);
private:
FixedSquareGrid<char, 15> canvas;
void initN() {
for (auto &row : canvas) {
row.fill(' ');
row[5] = 'x';
}
}
void horizontal(size_t c1, size_t c2, size_t r) {
for (size_t c = c1; c <= c2; c++) {
canvas[r][c] = 'x';
}
}
void vertical(size_t r1, size_t r2, size_t c) {
for (size_t r = r1; r <= r2; r++) {
canvas[r][c] = 'x';
}
}
void diagd(size_t c1, size_t c2, size_t r) {
for (size_t c = c1; c <= c2; c++) {
canvas[r + c - c1][c] = 'x';
}
}
void diagu(size_t c1, size_t c2, size_t r) {
for (size_t c = c1; c <= c2; c++) {
canvas[r - c + c1][c] = 'x';
}
}
void drawOnes(int v) {
switch (v) {
case 1:
horizontal(6, 10, 0);
break;
case 2:
horizontal(6, 10, 4);
break;
case 3:
diagd(6, 10, 0);
break;
case 4:
diagu(6, 10, 4);
break;
case 5:
drawOnes(1);
drawOnes(4);
break;
case 6:
vertical(0, 4, 10);
break;
case 7:
drawOnes(1);
drawOnes(6);
break;
case 8:
drawOnes(2);
drawOnes(6);
break;
case 9:
drawOnes(1);
drawOnes(8);
break;
default:
break;
}
}
void drawTens(int v) {
switch (v) {
case 1:
horizontal(0, 4, 0);
break;
case 2:
horizontal(0, 4, 4);
break;
case 3:
diagu(0, 4, 4);
break;
case 4:
diagd(0, 4, 0);
break;
case 5:
drawTens(1);
drawTens(4);
break;
case 6:
vertical(0, 4, 0);
break;
case 7:
drawTens(1);
drawTens(6);
break;
case 8:
drawTens(2);
drawTens(6);
break;
case 9:
drawTens(1);
drawTens(8);
break;
default:
break;
}
}
void drawHundreds(int hundreds) {
switch (hundreds) {
case 1:
horizontal(6, 10, 14);
break;
case 2:
horizontal(6, 10, 10);
break;
case 3:
diagu(6, 10, 14);
break;
case 4:
diagd(6, 10, 10);
break;
case 5:
drawHundreds(1);
drawHundreds(4);
break;
case 6:
vertical(10, 14, 10);
break;
case 7:
drawHundreds(1);
drawHundreds(6);
break;
case 8:
drawHundreds(2);
drawHundreds(6);
break;
case 9:
drawHundreds(1);
drawHundreds(8);
break;
default:
break;
}
}
void drawThousands(int thousands) {
switch (thousands) {
case 1:
horizontal(0, 4, 14);
break;
case 2:
horizontal(0, 4, 10);
break;
case 3:
diagd(0, 4, 10);
break;
case 4:
diagu(0, 4, 14);
break;
case 5:
drawThousands(1);
drawThousands(4);
break;
case 6:
vertical(10, 14, 0);
break;
case 7:
drawThousands(1);
drawThousands(6);
break;
case 8:
drawThousands(2);
drawThousands(6);
break;
case 9:
drawThousands(1);
drawThousands(8);
break;
default:
break;
}
}
void draw(int v) {
int thousands = v / 1000;
v %= 1000;
int hundreds = v / 100;
v %= 100;
int tens = v / 10;
int ones = v % 10;
if (thousands > 0) {
drawThousands(thousands);
}
if (hundreds > 0) {
drawHundreds(hundreds);
}
if (tens > 0) {
drawTens(tens);
}
if (ones > 0) {
drawOnes(ones);
}
}
};
std::ostream &operator<<(std::ostream &os, const Cistercian &c) {
for (auto &row : c.canvas) {
for (auto cell : row) {
os << cell;
}
os << '\n';
}
return os;
}
int main() {
for (auto number : { 0, 1, 20, 300, 4000, 5555, 6789, 9999 }) {
std::cout << number << ":\n";
Cistercian c(number);
std::cout << c << '\n';
}
return 0;
} |
http://rosettacode.org/wiki/Colour_bars/Display | Colour bars/Display | Task
Display a series of vertical color bars across the width of the display.
The color bars should either use:
the system palette, or
the sequence of colors:
black
red
green
blue
magenta
cyan
yellow
white
| #Processing | Processing | fullScreen();
noStroke();
color[] cs = {
color(0), // black
color(255,0,0), // red
color(0,255,0), // green
color(255,0,255), // magenta
color(0,255,255), // cyan
color(255,255,0), // yellow
color(255) // white
};
for(int i=0; i<7; i++) {
fill(cs[i]);
rect(i*width/8,0,width/8,height);
} |
http://rosettacode.org/wiki/Colour_bars/Display | Colour bars/Display | Task
Display a series of vertical color bars across the width of the display.
The color bars should either use:
the system palette, or
the sequence of colors:
black
red
green
blue
magenta
cyan
yellow
white
| #Python | Python |
#!/usr/bin/env python
#vertical coloured stripes in window in Python 2.7.1
from livewires import *
horiz=640; vert=480
begin_graphics(width=horiz,height=vert,title="v_stripes",background=Colour.black)
NameColors=["black","red","green","dark_blue","purple","blue","yellow","white"]
stepik=horiz/len(NameColors)
for index,each in enumerate(NameColors):
ExcStrng="set_colour(Colour."+each+")"
exec ExcStrng
box(index*stepik,0,(index+1)*stepik,vert,filled=1)
while keys_pressed() != ['x']: # press x key to terminate program
pass
end_graphics()
|
http://rosettacode.org/wiki/Closest-pair_problem | Closest-pair problem |
This page uses content from Wikipedia. The original article was at Closest pair of points problem. The list of authors can be seen in the page history. As with Rosetta Code, the text of Wikipedia is available under the GNU FDL. (See links for details on variance)
Task
Provide a function to find the closest two points among a set of given points in two dimensions, i.e. to solve the Closest pair of points problem in the planar case.
The straightforward solution is a O(n2) algorithm (which we can call brute-force algorithm); the pseudo-code (using indexes) could be simply:
bruteForceClosestPair of P(1), P(2), ... P(N)
if N < 2 then
return ∞
else
minDistance ← |P(1) - P(2)|
minPoints ← { P(1), P(2) }
foreach i ∈ [1, N-1]
foreach j ∈ [i+1, N]
if |P(i) - P(j)| < minDistance then
minDistance ← |P(i) - P(j)|
minPoints ← { P(i), P(j) }
endif
endfor
endfor
return minDistance, minPoints
endif
A better algorithm is based on the recursive divide&conquer approach, as explained also at Wikipedia's Closest pair of points problem, which is O(n log n); a pseudo-code could be:
closestPair of (xP, yP)
where xP is P(1) .. P(N) sorted by x coordinate, and
yP is P(1) .. P(N) sorted by y coordinate (ascending order)
if N ≤ 3 then
return closest points of xP using brute-force algorithm
else
xL ← points of xP from 1 to ⌈N/2⌉
xR ← points of xP from ⌈N/2⌉+1 to N
xm ← xP(⌈N/2⌉)x
yL ← { p ∈ yP : px ≤ xm }
yR ← { p ∈ yP : px > xm }
(dL, pairL) ← closestPair of (xL, yL)
(dR, pairR) ← closestPair of (xR, yR)
(dmin, pairMin) ← (dR, pairR)
if dL < dR then
(dmin, pairMin) ← (dL, pairL)
endif
yS ← { p ∈ yP : |xm - px| < dmin }
nS ← number of points in yS
(closest, closestPair) ← (dmin, pairMin)
for i from 1 to nS - 1
k ← i + 1
while k ≤ nS and yS(k)y - yS(i)y < dmin
if |yS(k) - yS(i)| < closest then
(closest, closestPair) ← (|yS(k) - yS(i)|, {yS(k), yS(i)})
endif
k ← k + 1
endwhile
endfor
return closest, closestPair
endif
References and further readings
Closest pair of points problem
Closest Pair (McGill)
Closest Pair (UCSB)
Closest pair (WUStL)
Closest pair (IUPUI)
| #BASIC256 | BASIC256 |
Dim x(9)
x = {0.654682, 0.409382, 0.891663, 0.716629, 0.477721, 0.925092, 0.624291, 0.211332, 0.293786, 0.839186}
Dim y(9)
y = {0.925557, 0.619391, 0.888594, 0.996200, 0.946355, 0.818220, 0.142924, 0.221507, 0.691701, 0.728260}
minDist = 1^30
For i = 0 To 8
For j = i+1 To 9
dist = (x[i] - x[j])^2 + (y[i] - y[j])^2
If dist < minDist Then minDist = dist : minDisti = i : minDistj = j
Next j
Next i
Print "El par más cercano es "; minDisti; " y "; minDistj; " a una distancia de "; Sqr(minDist)
End
|
http://rosettacode.org/wiki/Closures/Value_capture | Closures/Value capture | Task
Create a list of ten functions, in the simplest manner possible (anonymous functions are encouraged), such that the function at index i (you may choose to start i from either 0 or 1), when run, should return the square of the index, that is, i 2.
Display the result of running any but the last function, to demonstrate that the function indeed remembers its value.
Goal
Demonstrate how to create a series of independent closures based on the same template but maintain separate copies of the variable closed over.
In imperative languages, one would generally use a loop with a mutable counter variable.
For each function to maintain the correct number, it has to capture the value of the variable at the time it was created, rather than just a reference to the variable, which would have a different value by the time the function was run.
See also: Multiple distinct objects
| #F.23 | F# | [<EntryPoint>]
let main argv =
let fs = List.init 10 (fun i -> fun () -> i*i)
do List.iter (fun f -> printfn "%d" <| f()) fs
0 |
http://rosettacode.org/wiki/Closures/Value_capture | Closures/Value capture | Task
Create a list of ten functions, in the simplest manner possible (anonymous functions are encouraged), such that the function at index i (you may choose to start i from either 0 or 1), when run, should return the square of the index, that is, i 2.
Display the result of running any but the last function, to demonstrate that the function indeed remembers its value.
Goal
Demonstrate how to create a series of independent closures based on the same template but maintain separate copies of the variable closed over.
In imperative languages, one would generally use a loop with a mutable counter variable.
For each function to maintain the correct number, it has to capture the value of the variable at the time it was created, rather than just a reference to the variable, which would have a different value by the time the function was run.
See also: Multiple distinct objects
| #Factor | Factor | USING: io kernel locals math prettyprint sequences ;
[let
! Create a sequence of 10 quotations
10 iota [
:> i ! Bind lexical variable i
[ i i * ] ! Push a quotation to calculate i squared
] map :> seq
{ 3 8 } [
dup pprint " squared is " write
seq nth call .
] each
] |
http://rosettacode.org/wiki/Circular_primes | Circular primes | Definitions
A circular prime is a prime number with the property that the number generated at each intermediate step when cyclically permuting its (base 10) digits will also be prime.
For example:
1193 is a circular prime, since 1931, 9311 and 3119 are all also prime.
Note that a number which is a cyclic permutation of a smaller circular prime is not considered to be itself a circular prime. So 13 is a circular prime, but 31 is not.
A repunit (denoted by R) is a number whose base 10 representation contains only the digit 1.
For example:
R(2) = 11 and R(5) = 11111 are repunits.
Task
Find the first 19 circular primes.
If your language has access to arbitrary precision integer arithmetic, given that they are all repunits, find the next 4 circular primes.
(Stretch) Determine which of the following repunits are probably circular primes: R(5003), R(9887), R(15073), R(25031), R(35317) and R(49081). The larger ones may take a long time to process so just do as many as you reasonably can.
See also
Wikipedia article - Circular primes.
Wikipedia article - Repunit.
OEIS sequence A016114 - Circular primes.
| #Go | Go | package main
import (
"fmt"
big "github.com/ncw/gmp"
"strings"
)
// OK for 'small' numbers.
func isPrime(n int) bool {
switch {
case n < 2:
return false
case n%2 == 0:
return n == 2
case n%3 == 0:
return n == 3
default:
d := 5
for d*d <= n {
if n%d == 0 {
return false
}
d += 2
if n%d == 0 {
return false
}
d += 4
}
return true
}
}
func repunit(n int) *big.Int {
ones := strings.Repeat("1", n)
b, _ := new(big.Int).SetString(ones, 10)
return b
}
var circs = []int{}
// binary search is overkill for a small number of elements
func alreadyFound(n int) bool {
for _, i := range circs {
if i == n {
return true
}
}
return false
}
func isCircular(n int) bool {
nn := n
pow := 1 // will eventually contain 10 ^ d where d is number of digits in n
for nn > 0 {
pow *= 10
nn /= 10
}
nn = n
for {
nn *= 10
f := nn / pow // first digit
nn += f * (1 - pow)
if alreadyFound(nn) {
return false
}
if nn == n {
break
}
if !isPrime(nn) {
return false
}
}
return true
}
func main() {
fmt.Println("The first 19 circular primes are:")
digits := [4]int{1, 3, 7, 9}
q := []int{1, 2, 3, 5, 7, 9} // queue the numbers to be examined
fq := []int{1, 2, 3, 5, 7, 9} // also queue the corresponding first digits
count := 0
for {
f := q[0] // peek first element
fd := fq[0] // peek first digit
if isPrime(f) && isCircular(f) {
circs = append(circs, f)
count++
if count == 19 {
break
}
}
copy(q, q[1:]) // pop first element
q = q[:len(q)-1] // reduce length by 1
copy(fq, fq[1:]) // ditto for first digit queue
fq = fq[:len(fq)-1]
if f == 2 || f == 5 { // if digits > 1 can't contain a 2 or 5
continue
}
// add numbers with one more digit to queue
// only numbers whose last digit >= first digit need be added
for _, d := range digits {
if d >= fd {
q = append(q, f*10+d)
fq = append(fq, fd)
}
}
}
fmt.Println(circs)
fmt.Println("\nThe next 4 circular primes, in repunit format, are:")
count = 0
var rus []string
for i := 7; count < 4; i++ {
if repunit(i).ProbablyPrime(10) {
count++
rus = append(rus, fmt.Sprintf("R(%d)", i))
}
}
fmt.Println(rus)
fmt.Println("\nThe following repunits are probably circular primes:")
for _, i := range []int{5003, 9887, 15073, 25031, 35317, 49081} {
fmt.Printf("R(%-5d) : %t\n", i, repunit(i).ProbablyPrime(10))
}
} |
http://rosettacode.org/wiki/Collections | Collections | This task has been clarified. Its programming examples are in need of review to ensure that they still fit the requirements of the task.
Collections are abstractions to represent sets of values.
In statically-typed languages, the values are typically of a common data type.
Task
Create a collection, and add a few values to it.
See also
Array
Associative array: Creation, Iteration
Collections
Compound data type
Doubly-linked list: Definition, Element definition, Element insertion, List Traversal, Element Removal
Linked list
Queue: Definition, Usage
Set
Singly-linked list: Element definition, Element insertion, List Traversal, Element Removal
Stack
| #AWK | AWK | a[0]="hello" |
http://rosettacode.org/wiki/Combinations | Combinations | Task
Given non-negative integers m and n, generate all size m combinations of the integers from 0 (zero) to n-1 in sorted order (each combination is sorted and the entire table is sorted).
Example
3 comb 5 is:
0 1 2
0 1 3
0 1 4
0 2 3
0 2 4
0 3 4
1 2 3
1 2 4
1 3 4
2 3 4
If it is more "natural" in your language to start counting from 1 (unity) instead of 0 (zero),
the combinations can be of the integers from 1 to n.
See also
The number of samples of size k from n objects.
With combinations and permutations generation tasks.
Order Unimportant
Order Important
Without replacement
(
n
k
)
=
n
C
k
=
n
(
n
−
1
)
…
(
n
−
k
+
1
)
k
(
k
−
1
)
…
1
{\displaystyle {\binom {n}{k}}=^{n}\operatorname {C} _{k}={\frac {n(n-1)\ldots (n-k+1)}{k(k-1)\dots 1}}}
n
P
k
=
n
⋅
(
n
−
1
)
⋅
(
n
−
2
)
⋯
(
n
−
k
+
1
)
{\displaystyle ^{n}\operatorname {P} _{k}=n\cdot (n-1)\cdot (n-2)\cdots (n-k+1)}
Task: Combinations
Task: Permutations
With replacement
(
n
+
k
−
1
k
)
=
n
+
k
−
1
C
k
=
(
n
+
k
−
1
)
!
(
n
−
1
)
!
k
!
{\displaystyle {\binom {n+k-1}{k}}=^{n+k-1}\operatorname {C} _{k}={(n+k-1)! \over (n-1)!k!}}
n
k
{\displaystyle n^{k}}
Task: Combinations with repetitions
Task: Permutations with repetitions
| #GAP | GAP | # Built-in
Combinations([1 .. n], m);
Combinations([1 .. 5], 3);
# [ [ 1, 2, 3 ], [ 1, 2, 4 ], [ 1, 2, 5 ], [ 1, 3, 4 ], [ 1, 3, 5 ],
# [ 1, 4, 5 ], [ 2, 3, 4 ], [ 2, 3, 5 ], [ 2, 4, 5 ], [ 3, 4, 5 ] ] |
http://rosettacode.org/wiki/Conditional_structures | Conditional structures | Control Structures
These are examples of control structures. You may also be interested in:
Conditional structures
Exceptions
Flow-control structures
Loops
Task
List the conditional structures offered by a programming language. See Wikipedia: conditionals for descriptions.
Common conditional structures include if-then-else and switch.
Less common are arithmetic if, ternary operator and Hash-based conditionals.
Arithmetic if allows tight control over computed gotos, which optimizers have a hard time to figure out.
| #Oz | Oz | proc {PrintParity X}
if {IsEven X} then
{Show even}
elseif {IsOdd X} then
{Show odd}
else
{Show 'should not happen'}
end
end |
http://rosettacode.org/wiki/Comments | Comments | Task
Show all ways to include text in a language source file
that's completely ignored by the compiler or interpreter.
Related tasks
Documentation
Here_document
See also
Wikipedia
xkcd (Humor: hand gesture denoting // for "commenting out" people.)
| #TI-89_BASIC | TI-89 BASIC | © This is a comment. Everything from © to the end of the line is ignored. |
http://rosettacode.org/wiki/Comments | Comments | Task
Show all ways to include text in a language source file
that's completely ignored by the compiler or interpreter.
Related tasks
Documentation
Here_document
See also
Wikipedia
xkcd (Humor: hand gesture denoting // for "commenting out" people.)
| #Tiny_BASIC | Tiny BASIC |
10 REM this is a comment
20
40 REM from above you can see that line numbers with no statement
50 REM and blank lines also are ignored
|
http://rosettacode.org/wiki/Comments | Comments | Task
Show all ways to include text in a language source file
that's completely ignored by the compiler or interpreter.
Related tasks
Documentation
Here_document
See also
Wikipedia
xkcd (Humor: hand gesture denoting // for "commenting out" people.)
| #Toka | Toka | #! Everything on this line (after the shebang to the left) will be ignored. |
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