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900	ab026565-6ddd-11ea-9c59-ccda262736ce	https://socratic.org/questions/how-would-you-balance-h3po4-mg-oh-2-mg3-po4-2-h20	2 H3PO4 + 3 Mg(OH)2 -> Mg3(PO4)2 + 6 H2O	start chemical_equation qc_end chemical_equation 4 10 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the equation"}]	[{"type":"chemical equation","value":"2 H3PO4 + 3 Mg(OH)2 -> Mg3(PO4)2 + 6 H2O"}]	[{"type":"chemical equation","value":"H3PO4 + Mg(OH)2 -> Mg3(PO4)2 + H2O"}]	<h1 class="questionTitle" itemprop="name">How would you balance H3PO4 +Mg(OH)2-->Mg3(PO4)2 +H20?</h1>	null	2 H3PO4 + 3 Mg(OH)2 -> Mg3(PO4)2 + 6 H2O	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>I can either tally all the atoms one by one or use my knowledge of ionic bonds to make the tally system much simpler. </p> <p>I'll do the simpler version.</p> <p>First re-write the chemical equation to avoid confusing myself:</p> <p><mathjax>#H_3PO_4#</mathjax> + <mathjax>#Mg(OH)_2#</mathjax> = <mathjax>#Mg_3(PO_4)_2#</mathjax> + <mathjax>#H#</mathjax>-<mathjax>#OH#</mathjax></p> <p>Notice that I had shown the line structure between the <mathjax>#H^+#</mathjax> and <mathjax>#OH^-#</mathjax> ions. Now, let's tally based on the subscripts.</p> <p><em>left side:</em></p> <p><mathjax>#H^+#</mathjax> = 3</p> <p><mathjax>#PO_4^"3-"#</mathjax> = 1</p> <p><mathjax>#Mg^"2+"#</mathjax> = 1</p> <p><mathjax>#OH^-#</mathjax> = 2</p> <p><em>right side:</em></p> <p><mathjax>#H^+#</mathjax> = 1</p> <p><mathjax>#PO_4^"3-"#</mathjax> = 2</p> <p><mathjax>#Mg^"2+"#</mathjax> = 3</p> <p><mathjax>#OH^-#</mathjax> = 1</p> <p>Let's start balancing the largest ion, <mathjax>#PO_4^"3-"#</mathjax>.</p> <p><mathjax>#color (red) 2 H_3PO_4#</mathjax> + <mathjax>#Mg(OH)_2#</mathjax> = <mathjax>#Mg_3(PO_4)_2#</mathjax> + <mathjax>#H#</mathjax>-<mathjax>#OH#</mathjax></p> <p><em>left side:</em></p> <p><mathjax>#H^+#</mathjax> = 3 x <mathjax>#color (red) 2#</mathjax> = 6</p> <p><mathjax>#PO_4^"3-"#</mathjax> = 1 x <mathjax>#color (red) 2#</mathjax> = <strong>2</strong></p> <p><mathjax>#Mg^"2+"#</mathjax> = 1</p> <p><mathjax>#OH^-#</mathjax> = 2</p> <p><em>right side:</em></p> <p><mathjax>#H^+#</mathjax> = 1</p> <p><mathjax>#PO_4^"3-"#</mathjax> = <strong>2</strong></p> <p><mathjax>#Mg^"2+"#</mathjax> = 3</p> <p><mathjax>#OH^-#</mathjax> = 1</p> <p>Do not forget that since <mathjax>#H_3PO_4#</mathjax> is a substance, you need to also multiply the coefficient with the number of <mathjax>#H#</mathjax> atoms.</p> <p>Next,</p> <p><mathjax>#2 H_3PO_4#</mathjax> + <mathjax>#color (green) 3Mg(OH)_2#</mathjax> = <mathjax>#Mg_3(PO_4)_2#</mathjax> + <mathjax>#H#</mathjax>-<mathjax>#OH#</mathjax></p> <p><em>left side:</em></p> <p><mathjax>#H^+#</mathjax> = 3 x 2 = 6</p> <p><mathjax>#PO_4^"3-"#</mathjax> = 1 x 2 = <strong>2</strong></p> <p><mathjax>#Mg^"2+"#</mathjax> = 1 x <mathjax>#color (green) 3#</mathjax> = <strong>3</strong></p> <p><mathjax>#OH^-#</mathjax> = 2 x <mathjax>#color (green) 3#</mathjax> = 6</p> <p><em>right side:</em></p> <p><mathjax>#H^+#</mathjax> = 1</p> <p><mathjax>#PO_4^"3-"#</mathjax> = <strong>2</strong></p> <p><mathjax>#Mg^"2+"#</mathjax> = <strong>3</strong></p> <p><mathjax>#OH^-#</mathjax> = 1</p> <p>Again, since <mathjax>#Mg(OH)_2#</mathjax> is a substance, whatever coefficient you apply to <mathjax>#Mg^"2+"#</mathjax> ion will also be applied to <mathjax>#OH^-#</mathjax> ion. </p> <p><mathjax>#2 H_3PO_4#</mathjax> + <mathjax>#3Mg(OH)_2#</mathjax> = <mathjax>#Mg_3(PO_4)_2#</mathjax> + <mathjax>#color (blue) 6#</mathjax><mathjax>#H#</mathjax>-<mathjax>#OH#</mathjax></p> <p><em>left side:</em></p> <p><mathjax>#H^+#</mathjax> = 3 x 2 = <strong>6</strong></p> <p><mathjax>#PO_4^"3-"#</mathjax> = 1 x 2 = <strong>2</strong></p> <p><mathjax>#Mg^"2+"#</mathjax> = 1 x 3 = <strong>3</strong></p> <p><mathjax>#OH^-#</mathjax> = 2 x 3 = <strong>6</strong></p> <p><em>right side:</em></p> <p><mathjax>#H^+#</mathjax> = 1 x <mathjax>#color (blue) 6#</mathjax> = <strong>6</strong></p> <p><mathjax>#PO_4^"3-"#</mathjax> = <strong>2</strong></p> <p><mathjax>#Mg^"2+"#</mathjax> = <strong>3</strong></p> <p><mathjax>#OH^-#</mathjax> = 1 x <mathjax>#color (blue) 6#</mathjax> = <strong>6</strong></p> <p>Reverting back to the original equation,</p> <p><mathjax>#2 H_3PO_4#</mathjax> + <mathjax>#3Mg(OH)_2#</mathjax> = <mathjax>#Mg_3(PO_4)_2#</mathjax> + <mathjax>#6H_2O#</mathjax></p> <p>The equation is now balanced.</p> <p>Please take note this method is only applicable for <strong><a href="http://socratic.org/chemistry/bonding-basics/ionic-bonding">IONIC bonding</a> of <a href="http://socratic.org/chemistry/ionic-bonds-and-formulas/polyatomic-ions">polyatomic ions</a></strong>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2H_3PO_4#</mathjax> + <mathjax>#3Mg(OH)_2#</mathjax> = <mathjax>#Mg_3(PO_4)_2#</mathjax> + <mathjax>#6H_2O#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>I can either tally all the atoms one by one or use my knowledge of ionic bonds to make the tally system much simpler. </p> <p>I'll do the simpler version.</p> <p>First re-write the chemical equation to avoid confusing myself:</p> <p><mathjax>#H_3PO_4#</mathjax> + <mathjax>#Mg(OH)_2#</mathjax> = <mathjax>#Mg_3(PO_4)_2#</mathjax> + <mathjax>#H#</mathjax>-<mathjax>#OH#</mathjax></p> <p>Notice that I had shown the line structure between the <mathjax>#H^+#</mathjax> and <mathjax>#OH^-#</mathjax> ions. Now, let's tally based on the subscripts.</p> <p><em>left side:</em></p> <p><mathjax>#H^+#</mathjax> = 3</p> <p><mathjax>#PO_4^"3-"#</mathjax> = 1</p> <p><mathjax>#Mg^"2+"#</mathjax> = 1</p> <p><mathjax>#OH^-#</mathjax> = 2</p> <p><em>right side:</em></p> <p><mathjax>#H^+#</mathjax> = 1</p> <p><mathjax>#PO_4^"3-"#</mathjax> = 2</p> <p><mathjax>#Mg^"2+"#</mathjax> = 3</p> <p><mathjax>#OH^-#</mathjax> = 1</p> <p>Let's start balancing the largest ion, <mathjax>#PO_4^"3-"#</mathjax>.</p> <p><mathjax>#color (red) 2 H_3PO_4#</mathjax> + <mathjax>#Mg(OH)_2#</mathjax> = <mathjax>#Mg_3(PO_4)_2#</mathjax> + <mathjax>#H#</mathjax>-<mathjax>#OH#</mathjax></p> <p><em>left side:</em></p> <p><mathjax>#H^+#</mathjax> = 3 x <mathjax>#color (red) 2#</mathjax> = 6</p> <p><mathjax>#PO_4^"3-"#</mathjax> = 1 x <mathjax>#color (red) 2#</mathjax> = <strong>2</strong></p> <p><mathjax>#Mg^"2+"#</mathjax> = 1</p> <p><mathjax>#OH^-#</mathjax> = 2</p> <p><em>right side:</em></p> <p><mathjax>#H^+#</mathjax> = 1</p> <p><mathjax>#PO_4^"3-"#</mathjax> = <strong>2</strong></p> <p><mathjax>#Mg^"2+"#</mathjax> = 3</p> <p><mathjax>#OH^-#</mathjax> = 1</p> <p>Do not forget that since <mathjax>#H_3PO_4#</mathjax> is a substance, you need to also multiply the coefficient with the number of <mathjax>#H#</mathjax> atoms.</p> <p>Next,</p> <p><mathjax>#2 H_3PO_4#</mathjax> + <mathjax>#color (green) 3Mg(OH)_2#</mathjax> = <mathjax>#Mg_3(PO_4)_2#</mathjax> + <mathjax>#H#</mathjax>-<mathjax>#OH#</mathjax></p> <p><em>left side:</em></p> <p><mathjax>#H^+#</mathjax> = 3 x 2 = 6</p> <p><mathjax>#PO_4^"3-"#</mathjax> = 1 x 2 = <strong>2</strong></p> <p><mathjax>#Mg^"2+"#</mathjax> = 1 x <mathjax>#color (green) 3#</mathjax> = <strong>3</strong></p> <p><mathjax>#OH^-#</mathjax> = 2 x <mathjax>#color (green) 3#</mathjax> = 6</p> <p><em>right side:</em></p> <p><mathjax>#H^+#</mathjax> = 1</p> <p><mathjax>#PO_4^"3-"#</mathjax> = <strong>2</strong></p> <p><mathjax>#Mg^"2+"#</mathjax> = <strong>3</strong></p> <p><mathjax>#OH^-#</mathjax> = 1</p> <p>Again, since <mathjax>#Mg(OH)_2#</mathjax> is a substance, whatever coefficient you apply to <mathjax>#Mg^"2+"#</mathjax> ion will also be applied to <mathjax>#OH^-#</mathjax> ion. </p> <p><mathjax>#2 H_3PO_4#</mathjax> + <mathjax>#3Mg(OH)_2#</mathjax> = <mathjax>#Mg_3(PO_4)_2#</mathjax> + <mathjax>#color (blue) 6#</mathjax><mathjax>#H#</mathjax>-<mathjax>#OH#</mathjax></p> <p><em>left side:</em></p> <p><mathjax>#H^+#</mathjax> = 3 x 2 = <strong>6</strong></p> <p><mathjax>#PO_4^"3-"#</mathjax> = 1 x 2 = <strong>2</strong></p> <p><mathjax>#Mg^"2+"#</mathjax> = 1 x 3 = <strong>3</strong></p> <p><mathjax>#OH^-#</mathjax> = 2 x 3 = <strong>6</strong></p> <p><em>right side:</em></p> <p><mathjax>#H^+#</mathjax> = 1 x <mathjax>#color (blue) 6#</mathjax> = <strong>6</strong></p> <p><mathjax>#PO_4^"3-"#</mathjax> = <strong>2</strong></p> <p><mathjax>#Mg^"2+"#</mathjax> = <strong>3</strong></p> <p><mathjax>#OH^-#</mathjax> = 1 x <mathjax>#color (blue) 6#</mathjax> = <strong>6</strong></p> <p>Reverting back to the original equation,</p> <p><mathjax>#2 H_3PO_4#</mathjax> + <mathjax>#3Mg(OH)_2#</mathjax> = <mathjax>#Mg_3(PO_4)_2#</mathjax> + <mathjax>#6H_2O#</mathjax></p> <p>The equation is now balanced.</p> <p>Please take note this method is only applicable for <strong><a href="http://socratic.org/chemistry/bonding-basics/ionic-bonding">IONIC bonding</a> of <a href="http://socratic.org/chemistry/ionic-bonds-and-formulas/polyatomic-ions">polyatomic ions</a></strong>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How would you balance H3PO4 +Mg(OH)2-->Mg3(PO4)2 +H20?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="181739" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/nikka-c"><img alt="" class="" src="https://profilepictures.socratic.org/AQ8VOCyTM1J7U0TvIWhw_nkahara.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/nikka-c"> Nikka C. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-01T03:44:51" itemprop="dateCreated"> Nov 1, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2H_3PO_4#</mathjax> + <mathjax>#3Mg(OH)_2#</mathjax> = <mathjax>#Mg_3(PO_4)_2#</mathjax> + <mathjax>#6H_2O#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>I can either tally all the atoms one by one or use my knowledge of ionic bonds to make the tally system much simpler. </p> <p>I'll do the simpler version.</p> <p>First re-write the chemical equation to avoid confusing myself:</p> <p><mathjax>#H_3PO_4#</mathjax> + <mathjax>#Mg(OH)_2#</mathjax> = <mathjax>#Mg_3(PO_4)_2#</mathjax> + <mathjax>#H#</mathjax>-<mathjax>#OH#</mathjax></p> <p>Notice that I had shown the line structure between the <mathjax>#H^+#</mathjax> and <mathjax>#OH^-#</mathjax> ions. Now, let's tally based on the subscripts.</p> <p><em>left side:</em></p> <p><mathjax>#H^+#</mathjax> = 3</p> <p><mathjax>#PO_4^"3-"#</mathjax> = 1</p> <p><mathjax>#Mg^"2+"#</mathjax> = 1</p> <p><mathjax>#OH^-#</mathjax> = 2</p> <p><em>right side:</em></p> <p><mathjax>#H^+#</mathjax> = 1</p> <p><mathjax>#PO_4^"3-"#</mathjax> = 2</p> <p><mathjax>#Mg^"2+"#</mathjax> = 3</p> <p><mathjax>#OH^-#</mathjax> = 1</p> <p>Let's start balancing the largest ion, <mathjax>#PO_4^"3-"#</mathjax>.</p> <p><mathjax>#color (red) 2 H_3PO_4#</mathjax> + <mathjax>#Mg(OH)_2#</mathjax> = <mathjax>#Mg_3(PO_4)_2#</mathjax> + <mathjax>#H#</mathjax>-<mathjax>#OH#</mathjax></p> <p><em>left side:</em></p> <p><mathjax>#H^+#</mathjax> = 3 x <mathjax>#color (red) 2#</mathjax> = 6</p> <p><mathjax>#PO_4^"3-"#</mathjax> = 1 x <mathjax>#color (red) 2#</mathjax> = <strong>2</strong></p> <p><mathjax>#Mg^"2+"#</mathjax> = 1</p> <p><mathjax>#OH^-#</mathjax> = 2</p> <p><em>right side:</em></p> <p><mathjax>#H^+#</mathjax> = 1</p> <p><mathjax>#PO_4^"3-"#</mathjax> = <strong>2</strong></p> <p><mathjax>#Mg^"2+"#</mathjax> = 3</p> <p><mathjax>#OH^-#</mathjax> = 1</p> <p>Do not forget that since <mathjax>#H_3PO_4#</mathjax> is a substance, you need to also multiply the coefficient with the number of <mathjax>#H#</mathjax> atoms.</p> <p>Next,</p> <p><mathjax>#2 H_3PO_4#</mathjax> + <mathjax>#color (green) 3Mg(OH)_2#</mathjax> = <mathjax>#Mg_3(PO_4)_2#</mathjax> + <mathjax>#H#</mathjax>-<mathjax>#OH#</mathjax></p> <p><em>left side:</em></p> <p><mathjax>#H^+#</mathjax> = 3 x 2 = 6</p> <p><mathjax>#PO_4^"3-"#</mathjax> = 1 x 2 = <strong>2</strong></p> <p><mathjax>#Mg^"2+"#</mathjax> = 1 x <mathjax>#color (green) 3#</mathjax> = <strong>3</strong></p> <p><mathjax>#OH^-#</mathjax> = 2 x <mathjax>#color (green) 3#</mathjax> = 6</p> <p><em>right side:</em></p> <p><mathjax>#H^+#</mathjax> = 1</p> <p><mathjax>#PO_4^"3-"#</mathjax> = <strong>2</strong></p> <p><mathjax>#Mg^"2+"#</mathjax> = <strong>3</strong></p> <p><mathjax>#OH^-#</mathjax> = 1</p> <p>Again, since <mathjax>#Mg(OH)_2#</mathjax> is a substance, whatever coefficient you apply to <mathjax>#Mg^"2+"#</mathjax> ion will also be applied to <mathjax>#OH^-#</mathjax> ion. </p> <p><mathjax>#2 H_3PO_4#</mathjax> + <mathjax>#3Mg(OH)_2#</mathjax> = <mathjax>#Mg_3(PO_4)_2#</mathjax> + <mathjax>#color (blue) 6#</mathjax><mathjax>#H#</mathjax>-<mathjax>#OH#</mathjax></p> <p><em>left side:</em></p> <p><mathjax>#H^+#</mathjax> = 3 x 2 = <strong>6</strong></p> <p><mathjax>#PO_4^"3-"#</mathjax> = 1 x 2 = <strong>2</strong></p> <p><mathjax>#Mg^"2+"#</mathjax> = 1 x 3 = <strong>3</strong></p> <p><mathjax>#OH^-#</mathjax> = 2 x 3 = <strong>6</strong></p> <p><em>right side:</em></p> <p><mathjax>#H^+#</mathjax> = 1 x <mathjax>#color (blue) 6#</mathjax> = <strong>6</strong></p> <p><mathjax>#PO_4^"3-"#</mathjax> = <strong>2</strong></p> <p><mathjax>#Mg^"2+"#</mathjax> = <strong>3</strong></p> <p><mathjax>#OH^-#</mathjax> = 1 x <mathjax>#color (blue) 6#</mathjax> = <strong>6</strong></p> <p>Reverting back to the original equation,</p> <p><mathjax>#2 H_3PO_4#</mathjax> + <mathjax>#3Mg(OH)_2#</mathjax> = <mathjax>#Mg_3(PO_4)_2#</mathjax> + <mathjax>#6H_2O#</mathjax></p> <p>The equation is now balanced.</p> <p>Please take note this method is only applicable for <strong><a href="http://socratic.org/chemistry/bonding-basics/ionic-bonding">IONIC bonding</a> of <a href="http://socratic.org/chemistry/ionic-bonds-and-formulas/polyatomic-ions">polyatomic ions</a></strong>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/181739" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? 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901	a8c09ef6-6ddd-11ea-beb1-ccda262736ce	https://socratic.org/questions/what-is-the-combination-reaction-for-k-s-cl2-g	2 K(s) + Cl2(g) -> 2 KCl(s)	start chemical_equation qc_end chemical_equation 6 6 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the combination reaction"}]	[{"type":"chemical equation","value":"2 K(s) + Cl2(g) -> 2 KCl(s)"}]	[{"type":"chemical equation","value":"K(s)"},{"type":"chemical equation","value":"Cl2(g)"}]	<h1 class="questionTitle" itemprop="name">What is the combination reaction for #K(s) +Cl_2(g)#?</h1>	null	2 K(s) + Cl2(g) -> 2 KCl(s)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Potassium metal, <mathjax>#"K"#</mathjax>, can be ignited in the presence of chlorine gas, <mathjax>#"Cl"_2#</mathjax>, to produce <em>potassium chloride</em>, <mathjax>#"KCl"#</mathjax>, an <strong>ionic compound</strong>. </p> <p>Potassium chloride's lattice structure looks like this</p> <blockquote> <blockquote> <blockquote> <p><img alt="http://www.chm.bris.ac.uk/webprojects2006/Macgee/Web%20Project/lethal_injection.htm" src="https://useruploads.socratic.org/fzj6QATZ6jq0Forck5Lg_kcl.jpg"/> </p> </blockquote> </blockquote> </blockquote> <p>Here each potassium cation, shown here in dark gray, is surrounded by six chloride anions, shown here in green. </p> <p>The balanced chemical equation that describes this <strong><a href="https://socratic.org/chemistry/chemical-reactions/synthesis-reactions">synthesis reaction</a></strong>, also known as a <em>combination reaction</em>, looks like this </p> <blockquote> <p><mathjax>#2"K"_ ((s)) + "Cl"_ (2(g)) -> 2"KCl"_ ((s))#</mathjax></p> </blockquote> <p>You can also think about this reaction in terms of <strong>oxidation</strong> and <strong>reduction</strong>. Here potassium metal is being <strong>oxidized</strong> to potassium cations, <mathjax>#"K"^(+)#</mathjax>, and chlorine is being <strong>reduced</strong> to chlorine anions, <mathjax>#"Cl"^(-)#</mathjax>. </p> <blockquote> <p><mathjax>#2stackrel(color(blue)(0))"K"_ ((s)) + stackrel(color(blue)(0))"Cl"_ (2(g)) -> 2stackrel(color(blue)(+1))("K")stackrel(color(blue)(-1))("Cl")_ ((s))#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2"K"_ ((s)) + "Cl"_ (2(g)) -> 2"KCl"_ ((s))#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Potassium metal, <mathjax>#"K"#</mathjax>, can be ignited in the presence of chlorine gas, <mathjax>#"Cl"_2#</mathjax>, to produce <em>potassium chloride</em>, <mathjax>#"KCl"#</mathjax>, an <strong>ionic compound</strong>. </p> <p>Potassium chloride's lattice structure looks like this</p> <blockquote> <blockquote> <blockquote> <p><img alt="http://www.chm.bris.ac.uk/webprojects2006/Macgee/Web%20Project/lethal_injection.htm" src="https://useruploads.socratic.org/fzj6QATZ6jq0Forck5Lg_kcl.jpg"/> </p> </blockquote> </blockquote> </blockquote> <p>Here each potassium cation, shown here in dark gray, is surrounded by six chloride anions, shown here in green. </p> <p>The balanced chemical equation that describes this <strong><a href="https://socratic.org/chemistry/chemical-reactions/synthesis-reactions">synthesis reaction</a></strong>, also known as a <em>combination reaction</em>, looks like this </p> <blockquote> <p><mathjax>#2"K"_ ((s)) + "Cl"_ (2(g)) -> 2"KCl"_ ((s))#</mathjax></p> </blockquote> <p>You can also think about this reaction in terms of <strong>oxidation</strong> and <strong>reduction</strong>. Here potassium metal is being <strong>oxidized</strong> to potassium cations, <mathjax>#"K"^(+)#</mathjax>, and chlorine is being <strong>reduced</strong> to chlorine anions, <mathjax>#"Cl"^(-)#</mathjax>. </p> <blockquote> <p><mathjax>#2stackrel(color(blue)(0))"K"_ ((s)) + stackrel(color(blue)(0))"Cl"_ (2(g)) -> 2stackrel(color(blue)(+1))("K")stackrel(color(blue)(-1))("Cl")_ ((s))#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the combination reaction for #K(s) +Cl_2(g)#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-reactions-and-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions and Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="292760" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-28T02:02:13" itemprop="dateCreated"> Jul 28, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2"K"_ ((s)) + "Cl"_ (2(g)) -> 2"KCl"_ ((s))#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Potassium metal, <mathjax>#"K"#</mathjax>, can be ignited in the presence of chlorine gas, <mathjax>#"Cl"_2#</mathjax>, to produce <em>potassium chloride</em>, <mathjax>#"KCl"#</mathjax>, an <strong>ionic compound</strong>. </p> <p>Potassium chloride's lattice structure looks like this</p> <blockquote> <blockquote> <blockquote> <p><img alt="http://www.chm.bris.ac.uk/webprojects2006/Macgee/Web%20Project/lethal_injection.htm" src="https://useruploads.socratic.org/fzj6QATZ6jq0Forck5Lg_kcl.jpg"/> </p> </blockquote> </blockquote> </blockquote> <p>Here each potassium cation, shown here in dark gray, is surrounded by six chloride anions, shown here in green. </p> <p>The balanced chemical equation that describes this <strong><a href="https://socratic.org/chemistry/chemical-reactions/synthesis-reactions">synthesis reaction</a></strong>, also known as a <em>combination reaction</em>, looks like this </p> <blockquote> <p><mathjax>#2"K"_ ((s)) + "Cl"_ (2(g)) -> 2"KCl"_ ((s))#</mathjax></p> </blockquote> <p>You can also think about this reaction in terms of <strong>oxidation</strong> and <strong>reduction</strong>. Here potassium metal is being <strong>oxidized</strong> to potassium cations, <mathjax>#"K"^(+)#</mathjax>, and chlorine is being <strong>reduced</strong> to chlorine anions, <mathjax>#"Cl"^(-)#</mathjax>. </p> <blockquote> <p><mathjax>#2stackrel(color(blue)(0))"K"_ ((s)) + stackrel(color(blue)(0))"Cl"_ (2(g)) -> 2stackrel(color(blue)(+1))("K")stackrel(color(blue)(-1))("Cl")_ ((s))#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/292760" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb002bf34694a4fee47"> Question #fee47 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb402bf34694c8c5c15"> Question #c5c15 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb802bf346950519eb9"> Question #19eb9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cbf02bf3469570e2ea2"> Question #e2ea2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc002bf34695a6bc751"> Question #bc751 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc202bf3469570e2ea6"> Question #e2ea6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531e867a02bf342492a08b07"> Question #08b07 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-thermochemical-equation-for-the-combustion-of-benzene"> What is the thermochemical equation for the combustion of benzene? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-reversible"> Why are chemical reactions reversible? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-important"> Why are chemical reactions important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/chemical-reactions-and-equations"> See all questions in Chemical Reactions and Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 12829 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the combination reaction for #K(s) +Cl_2(g)#?	null
902	a9aae410-6ddd-11ea-a7f8-ccda262736ce	https://socratic.org/questions/if-given-4-5-ml-of-0-05-m-magnesium-sulfate-how-many-moles-of-magnesium-sulfate-	2.3 × 10^(-4) moles	start physical_unit 7 8 mole mol qc_end physical_unit 7 8 5 6 molarity qc_end end	[{"type":"physical unit","value":"Mole [OF] magnesium sulfate [IN] moles"}]	[{"type":"physical unit","value":"2.3 × 10^(-4) moles"}]	[{"type":"physical unit","value":"Volume [OF] magnesium sulfate solution [=] \\pu{4.5 mL}"},{"type":"physical unit","value":"Molarity [OF] magnesium sulfate solution [=] \\pu{0.05 M}"}]	<h1 class="questionTitle" itemprop="name">If given 4.5 mL of 0.05 M magnesium sulfate, how many moles of magnesium sulfate do we have?</h1>	null	2.3 × 10^(-4) moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a> is represented by the following equation:<br/> <img alt="http://woodridge.k12.oh.us/ourpages/users/dweaver/Chemistry/ChemistryHelpTopics/Molarity/Molarity.html" src="https://useruploads.socratic.org/AAJYsmmETBe3s4ab30Yj_molarity1.gif"/> </p> <p>We know the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> and the volume of solution. However, the volume does not have the proper units since it is given in terms of milliliters instead of liters. We can convert 4.5 mL into liters by using the conversion factor 1000mL = 1L. </p> <p>When 4.5 mL is divided by 1000 mL/L, we obtain a volume of 0.0045 L.</p> <p>Now we can rearrange the equation to solve for the number of moles. This can be accomplished by multiplying by liters of solution on both sides of the equation. The liters of solution will cancel out on the right side, leaving the number of moles being equal to the molarity times volume like so:</p> <p>Moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> = <mathjax>#"liters of solution" xx Molarity #</mathjax></p> <p>Moles of solute = <mathjax>#0.0045Lxx0.05M#</mathjax></p> <p><mathjax>#2.3xx10^(-4) mol#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We have <mathjax>#2.3xx10^(-4)#</mathjax> moles of <mathjax>#MgSO_4#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a> is represented by the following equation:<br/> <img alt="http://woodridge.k12.oh.us/ourpages/users/dweaver/Chemistry/ChemistryHelpTopics/Molarity/Molarity.html" src="https://useruploads.socratic.org/AAJYsmmETBe3s4ab30Yj_molarity1.gif"/> </p> <p>We know the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> and the volume of solution. However, the volume does not have the proper units since it is given in terms of milliliters instead of liters. We can convert 4.5 mL into liters by using the conversion factor 1000mL = 1L. </p> <p>When 4.5 mL is divided by 1000 mL/L, we obtain a volume of 0.0045 L.</p> <p>Now we can rearrange the equation to solve for the number of moles. This can be accomplished by multiplying by liters of solution on both sides of the equation. The liters of solution will cancel out on the right side, leaving the number of moles being equal to the molarity times volume like so:</p> <p>Moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> = <mathjax>#"liters of solution" xx Molarity #</mathjax></p> <p>Moles of solute = <mathjax>#0.0045Lxx0.05M#</mathjax></p> <p><mathjax>#2.3xx10^(-4) mol#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">If given 4.5 mL of 0.05 M magnesium sulfate, how many moles of magnesium sulfate do we have?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp" itemprop="url"> <span class="breadcrumb" itemprop="title">Molar Volume of a Gas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="285127" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/kayla-14"><img alt="" class="" src="https://profilepictures.socratic.org/OvMTWaamQPWcqLIkUNnG_793604964071127.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/kayla-14"> Kayla </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-06T00:46:10" itemprop="dateCreated"> Jul 6, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We have <mathjax>#2.3xx10^(-4)#</mathjax> moles of <mathjax>#MgSO_4#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a> is represented by the following equation:<br/> <img alt="http://woodridge.k12.oh.us/ourpages/users/dweaver/Chemistry/ChemistryHelpTopics/Molarity/Molarity.html" src="https://useruploads.socratic.org/AAJYsmmETBe3s4ab30Yj_molarity1.gif"/> </p> <p>We know the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> and the volume of solution. However, the volume does not have the proper units since it is given in terms of milliliters instead of liters. We can convert 4.5 mL into liters by using the conversion factor 1000mL = 1L. </p> <p>When 4.5 mL is divided by 1000 mL/L, we obtain a volume of 0.0045 L.</p> <p>Now we can rearrange the equation to solve for the number of moles. This can be accomplished by multiplying by liters of solution on both sides of the equation. The liters of solution will cancel out on the right side, leaving the number of moles being equal to the molarity times volume like so:</p> <p>Moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> = <mathjax>#"liters of solution" xx Molarity #</mathjax></p> <p>Moles of solute = <mathjax>#0.0045Lxx0.05M#</mathjax></p> <p><mathjax>#2.3xx10^(-4) mol#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/285127" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-stoichiometric-ratios-relate-to-molar-volume-of-a-gas"> How do stoichiometric ratios relate to molar volume of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-a-gas-at-stp"> How do you calculate molar volume of a gas at STP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-molar-volume-of-hydrogen-gas"> How do you find the molar volume of hydrogen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-oxygen-gas"> How do you calculate molar volume of oxygen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molar-gas-volume"> What is molar gas volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/534c7bf202bf3420a007f014"> What is the volume at 0 °C and 1 atm of a mixture that contains 4.0 g of methane and 2.0 g of helium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5361f75702bf3429040e0599"> What is the difference between STP and NTP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-volume-of-25-moles-of-oxygen-o2-gas"> What is the volume of .25 moles of oxygen (O2) Gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-would-knowing-the-molar-volume-of-a-gas-be-important"> Why would knowing the molar volume of a gas be important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-22-4-liters-called-the-molar-volume-of-a-gas"> Why is 22.4 liters called the molar volume of a gas? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp"> See all questions in Molar Volume of a Gas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 4007 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	If given 4.5 mL of 0.05 M magnesium sulfate, how many moles of magnesium sulfate do we have?	null
903	aa7e3fd9-6ddd-11ea-99de-ccda262736ce	https://socratic.org/questions/the-volume-of-a-gas-is-0-250-l-at-340-0-kpa-pressure-what-will-the-volume-be-whe	1.70 L	start physical_unit 4 4 volume l qc_end physical_unit 4 4 6 7 volume qc_end physical_unit 4 4 9 10 pressure qc_end physical_unit 4 4 23 24 pressure qc_end c_other constant_temperature qc_end end	[{"type":"physical unit","value":"Volume2 [OF] the gas [IN] L"}]	[{"type":"physical unit","value":"1.70 L"}]	[{"type":"physical unit","value":"Volume1 [OF] the gas [=] \\pu{0.250 L}"},{"type":"physical unit","value":"Pressure1 [OF] the gas [=] \\pu{340.0 kPa}"},{"type":"physical unit","value":"Pressure2 [OF] the gas [=] \\pu{50.0 kPa}"},{"type":"other","value":"ConstantTemperature"}]	<h1 class="questionTitle" itemprop="name">The volume of a gas is 0.250 L at 340.0 kPa pressure. What will the volume be when the pressure is reduced to 50.0 kPa, assuming the temperature remains constant? </h1>	null	1.70 L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Thus <mathjax>#V_2#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(P_1V_1)/P_2#</mathjax>. </p> <p>The good thing about <a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's law</a> is that here, given the proportionality, we don't have to bother about converting units; we could use pints, and bushels, and pounds and shillings and pence if we liked. </p> <p>Thus <mathjax>#V_2#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(340cancel(kPa)xx0.250L)/(50*cancel(kPa))#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??L#</mathjax>.</p> <p>Clearly volume will INCREASE almost sevenfold, as we would expect if we reduce the pressure. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#P_1V_1=P_2V_2#</mathjax> at <a href="https://en.wikipedia.org/wiki/Boyle%27s_law" rel="nofollow">constant temperature</a>. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Thus <mathjax>#V_2#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(P_1V_1)/P_2#</mathjax>. </p> <p>The good thing about <a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's law</a> is that here, given the proportionality, we don't have to bother about converting units; we could use pints, and bushels, and pounds and shillings and pence if we liked. </p> <p>Thus <mathjax>#V_2#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(340cancel(kPa)xx0.250L)/(50*cancel(kPa))#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??L#</mathjax>.</p> <p>Clearly volume will INCREASE almost sevenfold, as we would expect if we reduce the pressure. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">The volume of a gas is 0.250 L at 340.0 kPa pressure. What will the volume be when the pressure is reduced to 50.0 kPa, assuming the temperature remains constant? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/boyle-s-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Boyle's Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="260635" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-04-30T15:18:15" itemprop="dateCreated"> Apr 30, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#P_1V_1=P_2V_2#</mathjax> at <a href="https://en.wikipedia.org/wiki/Boyle%27s_law" rel="nofollow">constant temperature</a>. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Thus <mathjax>#V_2#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(P_1V_1)/P_2#</mathjax>. </p> <p>The good thing about <a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's law</a> is that here, given the proportionality, we don't have to bother about converting units; we could use pints, and bushels, and pounds and shillings and pence if we liked. </p> <p>Thus <mathjax>#V_2#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(340cancel(kPa)xx0.250L)/(50cancel(kPa))#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??L#</mathjax>.</p> <p>Clearly volume will INCREASE almost sevenfold, as we would expect if we reduce the pressure. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/260635" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="260651" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/marilia-e"><img alt="" class="" src="https://profilepictures.socratic.org/he1v8fg3TWOXSgMYYiGS_CdgDRhtWwAA2YvD.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/marilia-e"> Marilia E.K. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-04-30T15:47:08" itemprop="dateCreated"> Apr 30, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The final volume of this gas will be <strong>1.7L</strong>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Assuming this is an <strong>ideal gas</strong>, and that the <strong>number of molecules n<strong><em> of this gas remains </em>constant</strong>, and given that the </strong>temperature is also constant<strong>, we have then a situation where the </strong>Boyle-Mariotte Law* applies.</p> <p>This law basically states that <strong>pressure P and volume V of a gas are inversely proportional</strong> when the number of molecules and temperature are constant:<br/> <mathjax>#P prop 1/V#</mathjax><br/> That is, in these conditions, <strong>pressure times volume is constant</strong> :<br/> <mathjax>#PV = k#</mathjax><br/> So if we compare two separate situations, we conclude that<br/> <mathjax>#P_1V_1 = P_2V_2#</mathjax></p> <p>Now we can solve this problem. We know that the initial pressure is <mathjax>#340.0kPa#</mathjax>, the initial volume is <mathjax>#0.250L#</mathjax>, and the final pressure is <mathjax>#50.0kPa#</mathjax>:</p> <p><mathjax>#340.0kPa0.250L = 50.0kPaV_2#</mathjax></p> <p>If we cancel out the pressure units, we end up with a volume unit, which is precisely what we want:<br/> <mathjax>#340.0color(red)cancel(kPa)0.250L = 50.0color(red)cancel(kPa)V_2#</mathjax></p> <p>So the final volume of this gas, at 50kPa, will be:<br/> <mathjax>#85L = 50.0V_2#</mathjax><br/> <mathjax>#V_2 = (85/50)L#</mathjax></p> <p><mathjax>#V_2 = 1.7L#</mathjax></p> <p>This is in accordance with Boyle-Mariotte, which implies that an <strong>increase in pressure</strong> results in a <strong>decrease in volume</strong>, and <strong>vice-versa</strong>.<br/> Hope this helped!</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/260651" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-graph-boyles-law"> How do you graph Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-functional-groups-are-found-in-lipids"> What functional groups are found in lipids? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-k-constant-in-boyle-s-law"> Why is k constant in Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-boyle-s-law-graph-curved-1"> Why is Boyle's law graph curved? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-boyle-s-law-an-inverse-relationship-2"> Why is Boyle's law an inverse relationship? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-40-0-l-tank-of-ammonia-has-a-pressure-of-8-00-atm-calculate-the-volume-of-the-"> A 40.0 L tank of ammonia has a pressure of 8.00 atm. Calculate the volume of the ammonia if its... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-charles-law-different-from-boyle-s-law"> How is Charles' law different from Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-boyle-s-law-written-mathematically"> How is Boyle's law written mathematically? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-temperature-affect-boyle-s-law"> How does temperature affect Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-boyle-s-law-relate-to-ventilation"> How does Boyle's law relate to ventilation? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/boyle-s-law"> See all questions in Boyle's Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 10057 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	The volume of a gas is 0.250 L at 340.0 kPa pressure. What will the volume be when the pressure is reduced to 50.0 kPa, assuming the temperature remains constant?	null
904	a8e41da4-6ddd-11ea-8600-ccda262736ce	https://socratic.org/questions/what-is-the-molarity-of-a-sucrose-solution-that-contains-10-0-g-of-c-12h-22o-11-	0.29 mol/L	start physical_unit 6 7 molarity mol/l qc_end physical_unit 13 13 10 11 mass qc_end physical_unit 13 13 13 14 molecular_weight qc_end physical_unit 7 7 17 18 volume qc_end end	[{"type":"physical unit","value":"Molarity [OF] sucrose solution [IN] mol/L"}]	[{"type":"physical unit","value":"0.29 mol/L"}]	[{"type":"physical unit","value":"Mass [OF] C12H22O11 [=] \\pu{10.0 g}"},{"type":"physical unit","value":"Molecular mass [OF] C12H22O11 [=] \\pu{342.34 g/mol}"},{"type":"physical unit","value":"Volume [OF] solution [=] \\pu{100.0 mL}"}]	<h1 class="questionTitle" itemprop="name">What is the molarity of a sucrose solution that contains 10.0 g of #C_12H_22O_11# (342.34 g/mol) dissolved in 100.0 mL of solution?</h1>	null	0.29 mol/L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your goal when trying to find a solution's <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></strong> is to determine how many <em>moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a></em> you have in <strong>one liter of solution</strong>. </p> <p>Notice that your solution has a volume of <mathjax>#"100.0 mL"#</mathjax>. Since</p> <blockquote> <p><mathjax>#color(purple)(\|bar(ul(color(white)(a/a)color(black)("1 L" = 10^3"mL")color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>you can say that your solution has a volume that is equivalent to <mathjax>#1/10"th"#</mathjax> of <mathjax>#"1 L"#</mathjax>. Therefore, the number of moles that will be present in your sample will represent <mathjax>#1/10"th"#</mathjax> of the number of moles present in <mathjax>#"1 L"#</mathjax> of this solution. </p> <p>So, use sucrose's <strong>molar mass</strong> to find the number of moles present in your sample</p> <blockquote> <p><mathjax>#10.0 color(red)(cancel(color(black)("g"))) * "1 mole sucrose"/(342.34color(red)(cancel(color(black)("g")))) = "0.02921 moles sucrose"#</mathjax></p> </blockquote> <p>So, if this is how many moles you have in <mathjax>#"100.0 mL"#</mathjax> of this solution, it follows that <mathjax>#"1 L"#</mathjax> will contain </p> <blockquote> <p><mathjax>#1 color(red)(cancel(color(black)("L solution"))) * (10^3color(red)(cancel(color(black)("mL solution"))))/(1color(red)(cancel(color(black)("L solution")))) * "0.02921 moles"/(100color(red)(cancel(color(black)("mL solution")))) = "0.2921 moles"#</mathjax></p> </blockquote> <p>You get <mathjax>#0.2921#</mathjax> <strong>moles</strong> of sucrose, you solute, <em>per liter of solution</em>, which means that the solution's <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> will be </p> <blockquote> <p><mathjax>#"molarity" = c = color(green)(\|bar(ul(color(white)(a/a)"0.292 mol L"^(-1)color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"0.292 mol L"^(-1)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your goal when trying to find a solution's <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></strong> is to determine how many <em>moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a></em> you have in <strong>one liter of solution</strong>. </p> <p>Notice that your solution has a volume of <mathjax>#"100.0 mL"#</mathjax>. Since</p> <blockquote> <p><mathjax>#color(purple)(\|bar(ul(color(white)(a/a)color(black)("1 L" = 10^3"mL")color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>you can say that your solution has a volume that is equivalent to <mathjax>#1/10"th"#</mathjax> of <mathjax>#"1 L"#</mathjax>. Therefore, the number of moles that will be present in your sample will represent <mathjax>#1/10"th"#</mathjax> of the number of moles present in <mathjax>#"1 L"#</mathjax> of this solution. </p> <p>So, use sucrose's <strong>molar mass</strong> to find the number of moles present in your sample</p> <blockquote> <p><mathjax>#10.0 color(red)(cancel(color(black)("g"))) * "1 mole sucrose"/(342.34color(red)(cancel(color(black)("g")))) = "0.02921 moles sucrose"#</mathjax></p> </blockquote> <p>So, if this is how many moles you have in <mathjax>#"100.0 mL"#</mathjax> of this solution, it follows that <mathjax>#"1 L"#</mathjax> will contain </p> <blockquote> <p><mathjax>#1 color(red)(cancel(color(black)("L solution"))) * (10^3color(red)(cancel(color(black)("mL solution"))))/(1color(red)(cancel(color(black)("L solution")))) * "0.02921 moles"/(100color(red)(cancel(color(black)("mL solution")))) = "0.2921 moles"#</mathjax></p> </blockquote> <p>You get <mathjax>#0.2921#</mathjax> <strong>moles</strong> of sucrose, you solute, <em>per liter of solution</em>, which means that the solution's <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> will be </p> <blockquote> <p><mathjax>#"molarity" = c = color(green)(\|bar(ul(color(white)(a/a)"0.292 mol L"^(-1)color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the molarity of a sucrose solution that contains 10.0 g of #C_12H_22O_11# (342.34 g/mol) dissolved in 100.0 mL of solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="263428" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-08T02:36:55" itemprop="dateCreated"> May 8, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"0.292 mol L"^(-1)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your goal when trying to find a solution's <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></strong> is to determine how many <em>moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a></em> you have in <strong>one liter of solution</strong>. </p> <p>Notice that your solution has a volume of <mathjax>#"100.0 mL"#</mathjax>. Since</p> <blockquote> <p><mathjax>#color(purple)(\|bar(ul(color(white)(a/a)color(black)("1 L" = 10^3"mL")color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>you can say that your solution has a volume that is equivalent to <mathjax>#1/10"th"#</mathjax> of <mathjax>#"1 L"#</mathjax>. Therefore, the number of moles that will be present in your sample will represent <mathjax>#1/10"th"#</mathjax> of the number of moles present in <mathjax>#"1 L"#</mathjax> of this solution. </p> <p>So, use sucrose's <strong>molar mass</strong> to find the number of moles present in your sample</p> <blockquote> <p><mathjax>#10.0 color(red)(cancel(color(black)("g"))) * "1 mole sucrose"/(342.34color(red)(cancel(color(black)("g")))) = "0.02921 moles sucrose"#</mathjax></p> </blockquote> <p>So, if this is how many moles you have in <mathjax>#"100.0 mL"#</mathjax> of this solution, it follows that <mathjax>#"1 L"#</mathjax> will contain </p> <blockquote> <p><mathjax>#1 color(red)(cancel(color(black)("L solution"))) * (10^3color(red)(cancel(color(black)("mL solution"))))/(1color(red)(cancel(color(black)("L solution")))) * "0.02921 moles"/(100color(red)(cancel(color(black)("mL solution")))) = "0.2921 moles"#</mathjax></p> </blockquote> <p>You get <mathjax>#0.2921#</mathjax> <strong>moles</strong> of sucrose, you solute, <em>per liter of solution</em>, which means that the solution's <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> will be </p> <blockquote> <p><mathjax>#"molarity" = c = color(green)(\|bar(ul(color(white)(a/a)"0.292 mol L"^(-1)color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/263428" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-morality-be-used-as-a-conversion-factor"> How can molarity be used as a conversion factor? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-high-can-molarity-be"> How high can molarity be? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-molarity-change-with-temperature"> How does molarity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molarity-of-a-solution"> How do you find molarity of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-10-naoh"> What is the molarity of 10 NaOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-3-hydrogen-peroxide"> What is the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 32996 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the molarity of a sucrose solution that contains 10.0 g of #C_12H_22O_11# (342.34 g/mol) dissolved in 100.0 mL of solution?	null
905	a9243c69-6ddd-11ea-a705-ccda262736ce	https://socratic.org/questions/59aeeffa11ef6b4c5d4a27d0	H2C=CHCH2CH3(g) + 6 O2(g) -> 4 CO2(g) + 4 H2O(l)	start chemical_equation qc_end substance 6 6 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the oxidation"}]	[{"type":"chemical equation","value":"H2C=CHCH2CH3(g) + 6 O2(g) -> 4 CO2(g) + 4 H2O(l)"}]	[{"type":"substance name","value":"1-butylene"}]	<h1 class="questionTitle" itemprop="name">Can you represent the oxidation of #"1-butylene"#?</h1>	null	H2C=CHCH2CH3(g) + 6 O2(g) -> 4 CO2(g) + 4 H2O(l)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The usual rigmarole is to balance the carbons as carbon dioxide, then balance the hydrogens as water, and then balance the oxygens.........you can get very good at this <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>, and remember that you do this already every time you get change from a large bill....</p> <p>For an alkanes, say butane, we follow the same rigmarole....</p> <p><mathjax>#C_4H_10(g) + 13/2O_2(g)rarr4CO_2(g) + 5H_2O(l)#</mathjax></p> <p>And thus here I took 4 equiv carbon dioxide, and then five equiv of water, and then balanced up the required dioxygens. You could double the entire equation to give....</p> <p><mathjax>#2C_4H_10(g) + 13O_2(g)rarr8CO_2(g) + 10H_2O(l)#</mathjax></p> <p>I think the arithmetic is easier in the former case.... Anyway try it out for <mathjax>#C_2H_6#</mathjax>, <mathjax>#H_2C=CHCH_3#</mathjax>, and <mathjax>#H_3C-CH_2OH#</mathjax>; these are probably all reasonable questions at your current level.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#H_2C=CHCH_2CH_3(g) + 6O_2(g)rarr4CO_2(g) + 4H_2O(l)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The usual rigmarole is to balance the carbons as carbon dioxide, then balance the hydrogens as water, and then balance the oxygens.........you can get very good at this <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>, and remember that you do this already every time you get change from a large bill....</p> <p>For an alkanes, say butane, we follow the same rigmarole....</p> <p><mathjax>#C_4H_10(g) + 13/2O_2(g)rarr4CO_2(g) + 5H_2O(l)#</mathjax></p> <p>And thus here I took 4 equiv carbon dioxide, and then five equiv of water, and then balanced up the required dioxygens. You could double the entire equation to give....</p> <p><mathjax>#2C_4H_10(g) + 13O_2(g)rarr8CO_2(g) + 10H_2O(l)#</mathjax></p> <p>I think the arithmetic is easier in the former case.... Anyway try it out for <mathjax>#C_2H_6#</mathjax>, <mathjax>#H_2C=CHCH_3#</mathjax>, and <mathjax>#H_3C-CH_2OH#</mathjax>; these are probably all reasonable questions at your current level.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Can you represent the oxidation of #"1-butylene"#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">3</span> Answers </h5> <div class="answers"> <div class="answer" id="472097" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-09-05T19:07:45" itemprop="dateCreated"> Sep 5, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#H_2C=CHCH_2CH_3(g) + 6O_2(g)rarr4CO_2(g) + 4H_2O(l)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The usual rigmarole is to balance the carbons as carbon dioxide, then balance the hydrogens as water, and then balance the oxygens.........you can get very good at this <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>, and remember that you do this already every time you get change from a large bill....</p> <p>For an alkanes, say butane, we follow the same rigmarole....</p> <p><mathjax>#C_4H_10(g) + 13/2O_2(g)rarr4CO_2(g) + 5H_2O(l)#</mathjax></p> <p>And thus here I took 4 equiv carbon dioxide, and then five equiv of water, and then balanced up the required dioxygens. You could double the entire equation to give....</p> <p><mathjax>#2C_4H_10(g) + 13O_2(g)rarr8CO_2(g) + 10H_2O(l)#</mathjax></p> <p>I think the arithmetic is easier in the former case.... Anyway try it out for <mathjax>#C_2H_6#</mathjax>, <mathjax>#H_2C=CHCH_3#</mathjax>, and <mathjax>#H_3C-CH_2OH#</mathjax>; these are probably all reasonable questions at your current level.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/472097" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="472098" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/douglas-k"><img alt="" class="" src="https://graph.facebook.com/10206526058779249/picture?height=50&width=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/douglas-k"> Douglas K. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-09-05T19:08:19" itemprop="dateCreated"> Sep 5, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The balanced equation is:</p> <p><mathjax>#C_4H_8 + 6O_2 to 4CO_2+ 4H_2O#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The formula for <a href="https://en.wikipedia.org/wiki/Butene" rel="nofollow">butene</a> is</p> <p><mathjax>#C_4H_8#</mathjax></p> <p>You are going to bun it with plenty of oxygen:</p> <p><mathjax>#C_4H_8 + (n_1)O_2#</mathjax></p> <p>The products are carbon dioxide and water:</p> <p><mathjax>#C_4H_8 + (n_1)O_2 to (n_2)CO_2+ (n_3)H_2O#</mathjax></p> <p>Solved for the 3 variables:</p> <p><mathjax>#C_4 = (n_2)C#</mathjax></p> <p><mathjax>#n_2 = 4#</mathjax></p> <p><mathjax>#H_8 = (n_3)H_2#</mathjax></p> <p><mathjax>#n_3=4#</mathjax></p> <p><mathjax>#(n_1)O_2 = (4)O_2+(4)O#</mathjax></p> <p><mathjax>#(n_1)O_2 = (4)O_2+(2)O_2#</mathjax></p> <p><mathjax>#n_1 = 6#</mathjax></p> <p>The balanced equation is:</p> <p><mathjax>#C_4H_8 + 6O_2 to 4CO_2+ 4H_2O#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/472098" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="472103" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/daniel-l-3"><img alt="" class="" src="https://graph.facebook.com/100001647465264/picture?height=50&width=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/daniel-l-3"> Daniel L. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-09-05T19:26:00" itemprop="dateCreated"> Sep 5, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The balanced equation is:</p> <p><mathjax>#2C_4H_6 +11O_2 -> 8CO_2+6H_2O#</mathjax> </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Unbalanced equation is:</p> <p><mathjax>#C_4H_6+O_2 -> CO_2+ H_2O#</mathjax></p> <p>First we can put <mathjax>#4#</mathjax> in front of <mathjax>#CO_2#</mathjax> to balance the number of carbon atoms:</p> <p><mathjax>#C_4H_6+O_2 -> 4CO_2+ H_2O#</mathjax></p> <p>Now we can put <mathjax>#3#</mathjax> next to water to balance hydrogene:</p> <p><mathjax>#C_4H_6+O_2 -> 4CO_2+ 3H_2O#</mathjax></p> <p>Hydrogen and carbon are now balanced, but not oxygen. On the right side there are <mathjax>#11#</mathjax> atoms, on the left side <mathjax>#2#</mathjax>. To balance it we have to put <mathjax>#5.5#</mathjax> on the left side:</p> <p><mathjax>#C_4H_6+5.5O_2 -> 4CO_2+ 3H_2O#</mathjax> </p> <p>The equation is now balanced, but it is not correct to put fractions as the coefficients in a chemical reactions. To keep the equation ballanced and make all coefficients integer we have to multiply all coefficients by <mathjax>#2#</mathjax></p> <p><mathjax>#2C_4H_6+11O_2 -> 8CO_2+ 6H_2O#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/472103" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What is stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ab82402bf342f48d93ac6"> Question #93ac6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-we-study-stoichiometry"> Why do we study stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-naoh-is-produced-from-1-20-x-102-grams-of-na2o-na2o-h2o-2-naoh"> How many grams of NaOH is produced from #1.20 x 10^2# grams of #Na_2O#? #Na_2O + H_2O -> 2NaOH# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-na2o-are-required-to-produce-1-60-x-102-grams-of-naoh-na2o-h2o"> How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? 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906	ad21794d-6ddd-11ea-a9df-ccda262736ce	https://socratic.org/questions/58ba3a98b72cff425bcba4eb	2.1 × 10^(-6) mo/L	start physical_unit 9 9 [h3o+] mol/l qc_end physical_unit 9 9 3 5 ka qc_end physical_unit 9 9 18 19 concentration qc_end end	[{"type":"physical unit","value":"[H3O+] [OF] HOI(aq) [IN] mo/L"}]	[{"type":"physical unit","value":"2.1 × 10^(-6) mo/L"}]	[{"type":"physical unit","value":"Ka [OF] HOI(aq) [=] \\pu{2.0 × 10^(-11)}"},{"type":"physical unit","value":"Concentration [OF] HOI(aq) [=] \\pu{0.23 mo/L}"}]	<h1 class="questionTitle" itemprop="name">If #K_a=2.0xx10^-11# for #"hypoiodous acid"#, #HOI(aq)# what is #[H_3O^+]# for #[HOI(aq)]#, whose concentration is #0.23molL^-1#?</h1>	null	2.1 × 10^(-6) mo/L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We need (i) a stoichometrically balanced equation:</p> <p><mathjax>#HOI(aq) + H_2O(l) rightleftharpoons IO^(-) + H_3O^+#</mathjax></p> <p>And (ii), the equilibrium equation that represents the dissociation of the acid:</p> <p><mathjax>#([IO^-][H_3O^+])/([HOI])=K_a=2.0xx10^-11#</mathjax></p> <p>Now, using the typical approach we assume that the concentration of acid that dissociates is <mathjax>#x#</mathjax>, and thus we can rewrite the equilibrium equation,</p> <p><mathjax>#((x)(x))/(0.23-x)=2.0xx10^-11#</mathjax></p> <p>This is a quadratic in <mathjax>#x#</mathjax>, which is solvable exactly. Because I am a lazy soul, however, I make the approximation that <mathjax>#(0.23-x)~=0.23#</mathjax>. Note that I must justify this approx. later.</p> <p>So <mathjax>#x^2=0.23xx2.0xx10^-11#</mathjax>,</p> <p><mathjax>#x_1=sqrt(0.23xx2.0xx10^-11)=2.14xx10^-6#</mathjax></p> <p>This value is indeed small compared to <mathjax>#0.23#</mathjax>, but sometimes it is necessary to take a second approximation, or even a third approximation.</p> <p><mathjax>#x_2=sqrt((0.23-2.14xx10^-6)xx2.0xx10^-11)=2.14xx10^-6#</mathjax></p> <p>Since <mathjax>#x_1#</mathjax> and <mathjax>#x_2#</mathjax> were identical, our approximation was correct, and our value is the same value that we would have obtained had we used the quadratic equation. </p> <p>For some more examples of weak acid dissociation see <a href="http://preparatorychemistry.com/Bishop_weak_acid_Equilibrium.htm" rel="nofollow">here.</a> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#[H_3O^+]#</mathjax> <mathjax>#=#</mathjax> <mathjax>#2.1xx10^-6molL^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We need (i) a stoichometrically balanced equation:</p> <p><mathjax>#HOI(aq) + H_2O(l) rightleftharpoons IO^(-) + H_3O^+#</mathjax></p> <p>And (ii), the equilibrium equation that represents the dissociation of the acid:</p> <p><mathjax>#([IO^-][H_3O^+])/([HOI])=K_a=2.0xx10^-11#</mathjax></p> <p>Now, using the typical approach we assume that the concentration of acid that dissociates is <mathjax>#x#</mathjax>, and thus we can rewrite the equilibrium equation,</p> <p><mathjax>#((x)(x))/(0.23-x)=2.0xx10^-11#</mathjax></p> <p>This is a quadratic in <mathjax>#x#</mathjax>, which is solvable exactly. Because I am a lazy soul, however, I make the approximation that <mathjax>#(0.23-x)~=0.23#</mathjax>. Note that I must justify this approx. later.</p> <p>So <mathjax>#x^2=0.23xx2.0xx10^-11#</mathjax>,</p> <p><mathjax>#x_1=sqrt(0.23xx2.0xx10^-11)=2.14xx10^-6#</mathjax></p> <p>This value is indeed small compared to <mathjax>#0.23#</mathjax>, but sometimes it is necessary to take a second approximation, or even a third approximation.</p> <p><mathjax>#x_2=sqrt((0.23-2.14xx10^-6)xx2.0xx10^-11)=2.14xx10^-6#</mathjax></p> <p>Since <mathjax>#x_1#</mathjax> and <mathjax>#x_2#</mathjax> were identical, our approximation was correct, and our value is the same value that we would have obtained had we used the quadratic equation. </p> <p>For some more examples of weak acid dissociation see <a href="http://preparatorychemistry.com/Bishop_weak_acid_Equilibrium.htm" rel="nofollow">here.</a> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">If #K_a=2.0xx10^-11# for #"hypoiodous acid"#, #HOI(aq)# what is #[H_3O^+]# for #[HOI(aq)]#, whose concentration is #0.23molL^-1#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/ph-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">pH calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="386221" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-04T06:37:48" itemprop="dateCreated"> Mar 4, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#[H_3O^+]#</mathjax> <mathjax>#=#</mathjax> <mathjax>#2.1xx10^-6molL^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We need (i) a stoichometrically balanced equation:</p> <p><mathjax>#HOI(aq) + H_2O(l) rightleftharpoons IO^(-) + H_3O^+#</mathjax></p> <p>And (ii), the equilibrium equation that represents the dissociation of the acid:</p> <p><mathjax>#([IO^-][H_3O^+])/([HOI])=K_a=2.0xx10^-11#</mathjax></p> <p>Now, using the typical approach we assume that the concentration of acid that dissociates is <mathjax>#x#</mathjax>, and thus we can rewrite the equilibrium equation,</p> <p><mathjax>#((x)(x))/(0.23-x)=2.0xx10^-11#</mathjax></p> <p>This is a quadratic in <mathjax>#x#</mathjax>, which is solvable exactly. Because I am a lazy soul, however, I make the approximation that <mathjax>#(0.23-x)~=0.23#</mathjax>. Note that I must justify this approx. later.</p> <p>So <mathjax>#x^2=0.23xx2.0xx10^-11#</mathjax>,</p> <p><mathjax>#x_1=sqrt(0.23xx2.0xx10^-11)=2.14xx10^-6#</mathjax></p> <p>This value is indeed small compared to <mathjax>#0.23#</mathjax>, but sometimes it is necessary to take a second approximation, or even a third approximation.</p> <p><mathjax>#x_2=sqrt((0.23-2.14xx10^-6)xx2.0xx10^-11)=2.14xx10^-6#</mathjax></p> <p>Since <mathjax>#x_1#</mathjax> and <mathjax>#x_2#</mathjax> were identical, our approximation was correct, and our value is the same value that we would have obtained had we used the quadratic equation. </p> <p>For some more examples of weak acid dissociation see <a href="http://preparatorychemistry.com/Bishop_weak_acid_Equilibrium.htm" rel="nofollow">here.</a> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/386221" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-of-a-solution"> How do you determine ph of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-at-an-equivalence-point"> How do you determine pH at an equivalence point? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-molarity"> How do you determine pH from molarity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-alkalinity-mean"> What does alkalinity mean? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-base"> What is a base? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-acid-base-indicators-change-color"> How do acid base indicators change color? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-neutral-ph"> What is a neutral pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-alkalinity-affect-pool-water"> How does alkalinity affect pool water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ph-important-in-drinking-water"> Why is pH important in drinking water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-ph-of-solution"> How can I calculate the pH of a solution? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/ph-calculations"> See all questions in pH calculations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 5071 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	If #K_a=2.0xx10^-11# for #"hypoiodous acid"#, #HOI(aq)# what is #[H_3O^+]# for #[HOI(aq)]#, whose concentration is #0.23molL^-1#?	null
907	aa3a56cd-6ddd-11ea-90c9-ccda262736ce	https://socratic.org/questions/how-would-you-write-the-ionization-equation-for-benzoic-acid-c6h5cooh	C6H5CO2H(aq) + H2O(l) <=> C6H5CO2- + H3O+	start chemical_equation qc_end chemical_equation 10 10 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the ionization equation"}]	[{"type":"chemical equation","value":"C6H5CO2H(aq) + H2O(l) <=> C6H5CO2- + H3O+"}]	[{"type":"chemical equation","value":"C6H5COOH"}]	<h1 class="questionTitle" itemprop="name">How would you write the ionization equation for benzoic acid (C6H5COOH)?</h1>	null	C6H5CO2H(aq) + H2O(l) <=> C6H5CO2- + H3O+	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#K_a#</mathjax> <mathjax>#=#</mathjax> <mathjax>#[[C_6H_5CO_2^-][H_3O^+]]/[[C_6H_5CO_2H(aq)]]#</mathjax></p> <p>The <mathjax>#pK_a#</mathjax> of benzoic acid is <mathjax>#4.2#</mathjax>, whereas the <mathjax>#pK_a#</mathjax> of acetic acid is <mathjax>#4.7#</mathjax>. Can you account for why acetic acid is a weaker acid than benzoic acid? </p> <p>Note <mathjax>#pK_a = -log_(10)K_a#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_6H_5CO_2H(aq) + H_2O(l) rightleftharpoons C_6H_5CO_2^(-) + H_3O^+#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#K_a#</mathjax> <mathjax>#=#</mathjax> <mathjax>#[[C_6H_5CO_2^-][H_3O^+]]/[[C_6H_5CO_2H(aq)]]#</mathjax></p> <p>The <mathjax>#pK_a#</mathjax> of benzoic acid is <mathjax>#4.2#</mathjax>, whereas the <mathjax>#pK_a#</mathjax> of acetic acid is <mathjax>#4.7#</mathjax>. Can you account for why acetic acid is a weaker acid than benzoic acid? </p> <p>Note <mathjax>#pK_a = -log_(10)K_a#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How would you write the ionization equation for benzoic acid (C6H5COOH)?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-periodic-table" itemprop="url"> <span class="breadcrumb" itemprop="title">The Periodic Table</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-periodic-table/periodic-trends-in-ionization-energy" itemprop="url"> <span class="breadcrumb" itemprop="title">Periodic Trends in Ionization Energy</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="206117" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-31T09:46:42" itemprop="dateCreated"> Dec 31, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_6H_5CO_2H(aq) + H_2O(l) rightleftharpoons C_6H_5CO_2^(-) + H_3O^+#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#K_a#</mathjax> <mathjax>#=#</mathjax> <mathjax>#[[C_6H_5CO_2^-][H_3O^+]]/[[C_6H_5CO_2H(aq)]]#</mathjax></p> <p>The <mathjax>#pK_a#</mathjax> of benzoic acid is <mathjax>#4.2#</mathjax>, whereas the <mathjax>#pK_a#</mathjax> of acetic acid is <mathjax>#4.7#</mathjax>. Can you account for why acetic acid is a weaker acid than benzoic acid? </p> <p>Note <mathjax>#pK_a = -log_(10)K_a#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/206117" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-ionization-energy-relate-to-reactivity"> How does ionization energy relate to reactivity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-ionization-energy-measured-in"> What is ionization energy measured in? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-the-first-and-second-ionization-energies"> What are the first and second ionization energies? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-ionization-energy-increase"> How does ionization energy increase? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-ionization-energy-change-down-a-group"> How does ionization energy change down a group? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-trends-in-atomic-radius-relate-to-ionization-energy"> How do trends in atomic radius relate to ionization energy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/53f00f0102bf346733644238"> Question #44238 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/54a13803581e2a1c2d5fbdfe"> Question #fbdfe </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/54c642dc581e2a50cea1a23b"> Question #1a23b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/54e18faf581e2a2f288d7de9"> Question #d7de9 </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-periodic-table/periodic-trends-in-ionization-energy"> See all questions in Periodic Trends in Ionization Energy </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 11558 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How would you write the ionization equation for benzoic acid (C6H5COOH)?	null
908	ac3a9075-6ddd-11ea-a0f0-ccda262736ce	https://socratic.org/questions/how-much-does-1-00-mole-of-sio-2-substances-weigh-in-grams	60.10 grams	start physical_unit 6 6 mass g qc_end physical_unit 6 6 3 4 mole qc_end end	[{"type":"physical unit","value":"Weight [OF] SiO2 [IN] grams"}]	[{"type":"physical unit","value":"60.10 grams"}]	[{"type":"physical unit","value":"Mole [OF] SiO2 [=] \\pu{1.00 mole}"}]	<h1 class="questionTitle" itemprop="name">How much does 1.00 mole of #SiO_2# substances weigh in grams?</h1>	null	60.10 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And what is the mass of a mole of silicon atoms? It is <mathjax>#28.1g#</mathjax>..</p> <p>And thus <mathjax>#SiO_2#</mathjax> has a molar mass of <mathjax>#(28.1+2xx16.0)g*mol^-1#</mathjax>. From where did I get these molar masses?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well what is the mass of a mole of oxygen atoms? It is <mathjax>#16g#</mathjax>...</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And what is the mass of a mole of silicon atoms? It is <mathjax>#28.1g#</mathjax>..</p> <p>And thus <mathjax>#SiO_2#</mathjax> has a molar mass of <mathjax>#(28.1+2xx16.0)gmol^-1#</mathjax>. From where did I get these molar masses?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How much does 1.00 mole of #SiO_2# substances weigh in grams?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="575700" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-03-17T16:22:38" itemprop="dateCreated"> Mar 17, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well what is the mass of a mole of oxygen atoms? It is <mathjax>#16g#</mathjax>...</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And what is the mass of a mole of silicon atoms? It is <mathjax>#28.1g#</mathjax>..</p> <p>And thus <mathjax>#SiO_2#</mathjax> has a molar mass of <mathjax>#(28.1+2xx16.0)gmol^-1#</mathjax>. From where did I get these molar masses?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/575700" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 6579 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How much does 1.00 mole of #SiO_2# substances weigh in grams?	null
909	ab01f024-6ddd-11ea-a5fb-ccda262736ce	https://socratic.org/questions/if-50-ml-of-oxygen-gas-is-compressed-from-20-atm-of-pressure-to-40-atm-of-pressu	25 mL	start physical_unit 4 5 volume ml qc_end physical_unit 4 5 1 2 volume qc_end physical_unit 4 5 9 10 pressure qc_end physical_unit 4 5 14 15 pressure qc_end c_other constant_temperature qc_end end	[{"type":"physical unit","value":"Volume2 [OF] oxygen gas [IN] mL"}]	[{"type":"physical unit","value":"25 mL"}]	[{"type":"physical unit","value":"Volume1 [OF] oxygen gas [=] \\pu{50 mL}"},{"type":"physical unit","value":"Pressure1 [OF] oxygen gas [=] \\pu{20 atm}"},{"type":"physical unit","value":"Pressure2 [OF] oxygen gas [=] \\pu{40 atm}"},{"type":"other","value":"ConstantTemperature"}]	<h1 class="questionTitle" itemprop="name">If 50 mL of oxygen gas is compressed from 20 atm of pressure to 40 atm of pressure, what is the new volume at constant temperature?</h1>	null	25 mL	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Boyle's Law"#</mathjax> holds that the product <mathjax>#PV=k#</mathjax> at constant <mathjax>#T#</mathjax>.</p> <p>Since the temperature is constant here, we solve for <mathjax>#k#</mathjax>, and gets..........</p> <p><mathjax>#P_1V_1=P_2V_2#</mathjax>; so <mathjax>#V_2=(P_1V_1)/(P_2)=(20atmxx50mL)/(40atm)#</mathjax></p> <p><mathjax>#=25mL#</mathjax> as required.............</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#25mL.........#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Boyle's Law"#</mathjax> holds that the product <mathjax>#PV=k#</mathjax> at constant <mathjax>#T#</mathjax>.</p> <p>Since the temperature is constant here, we solve for <mathjax>#k#</mathjax>, and gets..........</p> <p><mathjax>#P_1V_1=P_2V_2#</mathjax>; so <mathjax>#V_2=(P_1V_1)/(P_2)=(20atmxx50mL)/(40atm)#</mathjax></p> <p><mathjax>#=25*mL#</mathjax> as required.............</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">If 50 mL of oxygen gas is compressed from 20 atm of pressure to 40 atm of pressure, what is the new volume at constant temperature?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp" itemprop="url"> <span class="breadcrumb" itemprop="title">Molar Volume of a Gas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="424168" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-16T04:17:11" itemprop="dateCreated"> May 16, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#25mL.........#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Boyle's Law"#</mathjax> holds that the product <mathjax>#PV=k#</mathjax> at constant <mathjax>#T#</mathjax>.</p> <p>Since the temperature is constant here, we solve for <mathjax>#k#</mathjax>, and gets..........</p> <p><mathjax>#P_1V_1=P_2V_2#</mathjax>; so <mathjax>#V_2=(P_1V_1)/(P_2)=(20atmxx50mL)/(40atm)#</mathjax></p> <p><mathjax>#=25*mL#</mathjax> as required.............</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/424168" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-stoichiometric-ratios-relate-to-molar-volume-of-a-gas"> How do stoichiometric ratios relate to molar volume of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-a-gas-at-stp"> How do you calculate molar volume of a gas at STP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-molar-volume-of-hydrogen-gas"> How do you find the molar volume of hydrogen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-oxygen-gas"> How do you calculate molar volume of oxygen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molar-gas-volume"> What is molar gas volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/534c7bf202bf3420a007f014"> What is the volume at 0 °C and 1 atm of a mixture that contains 4.0 g of methane and 2.0 g of helium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5361f75702bf3429040e0599"> What is the difference between STP and NTP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-volume-of-25-moles-of-oxygen-o2-gas"> What is the volume of .25 moles of oxygen (O2) Gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-would-knowing-the-molar-volume-of-a-gas-be-important"> Why would knowing the molar volume of a gas be important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-22-4-liters-called-the-molar-volume-of-a-gas"> Why is 22.4 liters called the molar volume of a gas? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp"> See all questions in Molar Volume of a Gas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 7081 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	If 50 mL of oxygen gas is compressed from 20 atm of pressure to 40 atm of pressure, what is the new volume at constant temperature?	null
910	a8bde3dc-6ddd-11ea-b448-ccda262736ce	https://socratic.org/questions/5657ac3f581e2a3dc8b8960d	6.7%	start physical_unit 10 10 percent_ionization none qc_end physical_unit 6 6 12 12 ph qc_end end	[{"type":"physical unit","value":"Percent ionization [OF] HF"}]	[{"type":"physical unit","value":"6.7%"}]	[{"type":"physical unit","value":"pH [OF] HF aqueous solution [=] \\pu{2}"},{"type":"physical unit","value":"Molarity [OF] HF aqueous solution [=] \\pu{0.15 M}"}]	<h1 class="questionTitle" itemprop="name">If the pH of an aqueous solution of #"0.15 M"# #"HF"# is #2#, what is the percent ionization of #"HF"#?</h1>	null	6.7%	<div class="answerDescription"> <div> <div class="markdown"><p>The percent "ionization" is the same as the percent dissociation. Since you know the <a href="http://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> is <mathjax>#2#</mathjax>, and you can find the pKa in your book or online (<mathjax>#~~3.15#</mathjax>), and since this acid is a weak acid when put into water, it is a buffer problem.</p> <blockquote> <p><mathjax>#"HF" rightleftharpoons "H"^(+) + "F"^(-)#</mathjax></p> </blockquote> <p>We can use the Henderson-Hasselbalch equation.</p> <blockquote> <p><mathjax>#pH = pKa + log \frac{["A"^(-)]}{["HA"]}#</mathjax></p> </blockquote> <p>where <mathjax>#"A"^(-)#</mathjax> is the conjugate base (<mathjax>#"F"^(-)#</mathjax>) and <mathjax>#"HA"#</mathjax> is the weak acid (<mathjax>#"HF"#</mathjax>). </p> <blockquote> <p><mathjax>#2 = 3.15 + log \frac{["A"^(-)]}{["HA"]}#</mathjax></p> <p><mathjax>#-1.15 = log \frac{["A"^(-)]}{["HA"]}#</mathjax></p> <p><mathjax>#10^(-1.15) = \frac{["A"^(-)]}{["HA"]}#</mathjax></p> </blockquote> <p>But we know that as <mathjax>#"HF"#</mathjax> dissociates into <mathjax>#"F"^(-)#</mathjax>, <strong>the same number of</strong> <mathjax>#\mathbf"mol"#</mathjax><strong>s of</strong> <mathjax>#\mathbf("F"^(-))#</mathjax> <strong>is created as the number of</strong> <mathjax>#\mathbf"mol"#</mathjax><strong>s of</strong> <mathjax>#\mathbf"HF"#</mathjax> <strong>dissociated</strong>, because there is no other source that gives <mathjax>#"F"^(-)#</mathjax>. </p> <p>Additionally, both species are within the same solution, so <strong>their concentrations are determined by the same total volume.</strong> When we compare concentrations, we simply get:</p> <p><mathjax>#\frac{["A"^(-)]}{["HA"]} = (("mol A"^(-))/cancel"L soln") / ("mol HA"/cancel"L soln") = ("mol A"^(-)) / ("mol HA")#</mathjax></p> <p>Furthermore, we are looking for a <strong>percent</strong>. If we let <mathjax>#x#</mathjax> be the <mathjax>#"mol"#</mathjax>s of <mathjax>#"F"^(-)#</mathjax> produced, then we can normalize the right half of the equation to say that the <mathjax>#"mol"#</mathjax>s of <mathjax>#"HF"#</mathjax> leftover is <mathjax>#1-x#</mathjax>:</p> <blockquote> <p><mathjax>#10^(-1.15) = x/(1-x)#</mathjax></p> <p><mathjax>#10^(-1.15) - 10^(-1.15)x = x#</mathjax></p> <p><mathjax>#10^(-1.15) = (1 + 10^(-1.15))x#</mathjax></p> <p><mathjax>#x = (10^(-1.15))/(1 + 10^(-1.15))#</mathjax></p> <p><mathjax>#= 0.066 => color(blue)("6.6% dissociated")#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerDescription"> <div> <div class="markdown"><p>The percent "ionization" is the same as the percent dissociation. Since you know the <a href="http://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> is <mathjax>#2#</mathjax>, and you can find the pKa in your book or online (<mathjax>#~~3.15#</mathjax>), and since this acid is a weak acid when put into water, it is a buffer problem.</p> <blockquote> <p><mathjax>#"HF" rightleftharpoons "H"^(+) + "F"^(-)#</mathjax></p> </blockquote> <p>We can use the Henderson-Hasselbalch equation.</p> <blockquote> <p><mathjax>#pH = pKa + log \frac{["A"^(-)]}{["HA"]}#</mathjax></p> </blockquote> <p>where <mathjax>#"A"^(-)#</mathjax> is the conjugate base (<mathjax>#"F"^(-)#</mathjax>) and <mathjax>#"HA"#</mathjax> is the weak acid (<mathjax>#"HF"#</mathjax>). </p> <blockquote> <p><mathjax>#2 = 3.15 + log \frac{["A"^(-)]}{["HA"]}#</mathjax></p> <p><mathjax>#-1.15 = log \frac{["A"^(-)]}{["HA"]}#</mathjax></p> <p><mathjax>#10^(-1.15) = \frac{["A"^(-)]}{["HA"]}#</mathjax></p> </blockquote> <p>But we know that as <mathjax>#"HF"#</mathjax> dissociates into <mathjax>#"F"^(-)#</mathjax>, <strong>the same number of</strong> <mathjax>#\mathbf"mol"#</mathjax><strong>s of</strong> <mathjax>#\mathbf("F"^(-))#</mathjax> <strong>is created as the number of</strong> <mathjax>#\mathbf"mol"#</mathjax><strong>s of</strong> <mathjax>#\mathbf"HF"#</mathjax> <strong>dissociated</strong>, because there is no other source that gives <mathjax>#"F"^(-)#</mathjax>. </p> <p>Additionally, both species are within the same solution, so <strong>their concentrations are determined by the same total volume.</strong> When we compare concentrations, we simply get:</p> <p><mathjax>#\frac{["A"^(-)]}{["HA"]} = (("mol A"^(-))/cancel"L soln") / ("mol HA"/cancel"L soln") = ("mol A"^(-)) / ("mol HA")#</mathjax></p> <p>Furthermore, we are looking for a <strong>percent</strong>. If we let <mathjax>#x#</mathjax> be the <mathjax>#"mol"#</mathjax>s of <mathjax>#"F"^(-)#</mathjax> produced, then we can normalize the right half of the equation to say that the <mathjax>#"mol"#</mathjax>s of <mathjax>#"HF"#</mathjax> leftover is <mathjax>#1-x#</mathjax>:</p> <blockquote> <p><mathjax>#10^(-1.15) = x/(1-x)#</mathjax></p> <p><mathjax>#10^(-1.15) - 10^(-1.15)x = x#</mathjax></p> <p><mathjax>#10^(-1.15) = (1 + 10^(-1.15))x#</mathjax></p> <p><mathjax>#x = (10^(-1.15))/(1 + 10^(-1.15))#</mathjax></p> <p><mathjax>#= 0.066 => color(blue)("6.6% dissociated")#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">If the pH of an aqueous solution of #"0.15 M"# #"HF"# is #2#, what is the percent ionization of #"HF"#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/the-ph-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">pH</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="193530" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/truong-son-n"><img alt="" class="" src="https://profilepictures.socratic.org/07k4plnQfmnmzMuesQzw_14844-1449381920.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/truong-son-n"> Truong-Son N. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-27T03:26:34" itemprop="dateCreated"> Nov 27, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerDescription"> <div> <div class="markdown"><p>The percent "ionization" is the same as the percent dissociation. Since you know the <a href="http://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> is <mathjax>#2#</mathjax>, and you can find the pKa in your book or online (<mathjax>#~~3.15#</mathjax>), and since this acid is a weak acid when put into water, it is a buffer problem.</p> <blockquote> <p><mathjax>#"HF" rightleftharpoons "H"^(+) + "F"^(-)#</mathjax></p> </blockquote> <p>We can use the Henderson-Hasselbalch equation.</p> <blockquote> <p><mathjax>#pH = pKa + log \frac{["A"^(-)]}{["HA"]}#</mathjax></p> </blockquote> <p>where <mathjax>#"A"^(-)#</mathjax> is the conjugate base (<mathjax>#"F"^(-)#</mathjax>) and <mathjax>#"HA"#</mathjax> is the weak acid (<mathjax>#"HF"#</mathjax>). </p> <blockquote> <p><mathjax>#2 = 3.15 + log \frac{["A"^(-)]}{["HA"]}#</mathjax></p> <p><mathjax>#-1.15 = log \frac{["A"^(-)]}{["HA"]}#</mathjax></p> <p><mathjax>#10^(-1.15) = \frac{["A"^(-)]}{["HA"]}#</mathjax></p> </blockquote> <p>But we know that as <mathjax>#"HF"#</mathjax> dissociates into <mathjax>#"F"^(-)#</mathjax>, <strong>the same number of</strong> <mathjax>#\mathbf"mol"#</mathjax><strong>s of</strong> <mathjax>#\mathbf("F"^(-))#</mathjax> <strong>is created as the number of</strong> <mathjax>#\mathbf"mol"#</mathjax><strong>s of</strong> <mathjax>#\mathbf"HF"#</mathjax> <strong>dissociated</strong>, because there is no other source that gives <mathjax>#"F"^(-)#</mathjax>. </p> <p>Additionally, both species are within the same solution, so <strong>their concentrations are determined by the same total volume.</strong> When we compare concentrations, we simply get:</p> <p><mathjax>#\frac{["A"^(-)]}{["HA"]} = (("mol A"^(-))/cancel"L soln") / ("mol HA"/cancel"L soln") = ("mol A"^(-)) / ("mol HA")#</mathjax></p> <p>Furthermore, we are looking for a <strong>percent</strong>. If we let <mathjax>#x#</mathjax> be the <mathjax>#"mol"#</mathjax>s of <mathjax>#"F"^(-)#</mathjax> produced, then we can normalize the right half of the equation to say that the <mathjax>#"mol"#</mathjax>s of <mathjax>#"HF"#</mathjax> leftover is <mathjax>#1-x#</mathjax>:</p> <blockquote> <p><mathjax>#10^(-1.15) = x/(1-x)#</mathjax></p> <p><mathjax>#10^(-1.15) - 10^(-1.15)x = x#</mathjax></p> <p><mathjax>#10^(-1.15) = (1 + 10^(-1.15))x#</mathjax></p> <p><mathjax>#x = (10^(-1.15))/(1 + 10^(-1.15))#</mathjax></p> <p><mathjax>#= 0.066 => color(blue)("6.6% dissociated")#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/193530" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="193625" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-27T11:21:45" itemprop="dateCreated"> Nov 27, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#6.7%#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Here's an alternative approach you can use to find the <em>percent ionization</em> of the weak acid. </p> <p>When placed in aqueous solution, <em>hydrofluoric acid</em>, <mathjax>#"HF"#</mathjax>, will dissociate to give <em>hydrogen cations</em>, <mathjax>#"H"^(+)#</mathjax>, and <em>fluoride anions</em>, <mathjax>#"F"^(-)#</mathjax>. </p> <blockquote> <p><mathjax>#"HF"_text((aq]) rightleftharpoons "H"_text((aq])^(+) + "F"_text((aq])^(-)#</mathjax></p> </blockquote> <p>Notice that you have <mathjax>#1:1#</mathjax> <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratios</a> between all the species that take part in this reaction. This means that <strong>every mole</strong> of hydrofluoric acid <strong>that dissociates</strong> will produce <strong>one mole</strong> of hydrogen cations and <strong>one mole</strong> of fluriode anions. </p> <p>Simply put, one molecule of hydrofluoric acid <strong>that ionizes</strong> will split into one hydrogen cation and one fluoride anion. </p> <p>Use the <a href="http://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> of the solution to determine the <em>concentration</em> of hydrogen cations</p> <blockquote> <p><mathjax>#["H"^(+)] = 10^(-"pH")#</mathjax></p> <p><mathjax>#["H"^(+)] = 10^(-2) = "0.010 M"#</mathjax></p> </blockquote> <p>So, if the ionization of the acid produced <mathjax>#"0.010 M"#</mathjax> of <mathjax>#"H"^(+)#</mathjax>, it follows that it also produced <mathjax>#"0.010 M"#</mathjax> of <mathjax>#"F"^(-)#</mathjax>. </p> <p>This means that <strong>out of the</strong> initial <mathjax>#"0.15 M"#</mathjax> of weak acid, <strong>only</strong> <mathjax>#"0.010 M"#</mathjax> ionized. </p> <p><em>Percent ionization</em> is defined as </p> <blockquote> <p><mathjax>#color(blue)("% ionization" = "amount that ionized"/"initial amount" xx 100)#</mathjax></p> </blockquote> <p>In this case, you would have</p> <blockquote> <p><mathjax>#"% ionization" = (0.010 color(red)(cancel(color(black)("M"))))/(0.15color(red)(cancel(color(black)("M")))) xx 100 = 6.667% ~~ color(green)(6.7%)#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/193625" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-pka"> How do you determine pH from pKa? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-ph-values-of-acids-and-bases-differ"> How do pH values of acids and bases differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-something-on-a-ph-scale"> How do you calculate something on a pH scale? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-diprotic-acid"> How do you calculate pH diprotic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-from-acid-dissociation-constant"> How do you calculate pH from acid dissociation constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-of-acid-and-base-solution"> How do you calculate pH of acid and base solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ph-scale-0-14"> Why is the pH scale 0-14? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-ph-the-measure-of-the-hydrogen-ion-concentration"> Is pH a measure of the hydrogen ion concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-solubility-affect-ph"> How does solubility affect pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-ph-relate-to-pka-in-a-titration"> How does pH relate to pKa in a titration? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/the-ph-concept"> See all questions in pH </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 7584 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	If the pH of an aqueous solution of #"0.15 M"# #"HF"# is #2#, what is the percent ionization of #"HF"#?	null
911	aa47897a-6ddd-11ea-8630-ccda262736ce	https://socratic.org/questions/5999262311ef6b28ca981b0f	0.40 mol/L	start physical_unit 7 7 concentration mol/l qc_end physical_unit 15 16 18 19 concentration qc_end physical_unit 15 16 10 11 volume qc_end physical_unit 7 7 27 28 volume qc_end end	[{"type":"physical unit","value":"Concentration2 [OF] the solution [IN] mol/L"}]	[{"type":"physical unit","value":"0.40 mol/L"}]	[{"type":"physical unit","value":"Concentration1 [OF] mother liquor [=] \\pu{2.0 mol/L}"},{"type":"physical unit","value":"Volume1 [OF] mother liquor [=] \\pu{20 mL}"},{"type":"physical unit","value":"Volume2 [OF] the solution [=] \\pu{100 mL}"}]	<h1 class="questionTitle" itemprop="name">What is the new concentration of a solute when a #20mL# volume of a mother liquor at #2.0molL^-1# concentration is diluted to a volume of #100mL#?</h1>	null	0.40 mol/L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Molarity"="Moles of solute"/"Volume of solution"#</mathjax></p> <p>Initially, we have a molar quantity of <mathjax>#20mLxx10^-3LmL^-1xx2molL^-1=0.040mol#</mathjax>, and this molar quantity is further diluted to <mathjax>#100mL#</mathjax>....</p> <p><mathjax>#"Concentration"=(0.040mol)/(100mLxx10^-3LmL^-1)=0.40mol*L^-1#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The new concentration is <mathjax>#0.40molL^-1#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Molarity"="Moles of solute"/"Volume of solution"#</mathjax></p> <p>Initially, we have a molar quantity of <mathjax>#20mLxx10^-3LmL^-1xx2molL^-1=0.040mol#</mathjax>, and this molar quantity is further diluted to <mathjax>#100mL#</mathjax>....</p> <p><mathjax>#"Concentration"=(0.040mol)/(100mLxx10^-3LmL^-1)=0.40mol*L^-1#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the new concentration of a solute when a #20mL# volume of a mother liquor at #2.0molL^-1# concentration is diluted to a volume of #100mL#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/dilution-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">Dilution Calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="466018" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-20T06:13:35" itemprop="dateCreated"> Aug 20, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The new concentration is <mathjax>#0.40molL^-1#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Molarity"="Moles of solute"/"Volume of solution"#</mathjax></p> <p>Initially, we have a molar quantity of <mathjax>#20mLxx10^-3LmL^-1xx2molL^-1=0.040mol#</mathjax>, and this molar quantity is further diluted to <mathjax>#100mL#</mathjax>....</p> <p><mathjax>#"Concentration"=(0.040mol)/(100mLxx10^-3LmL^-1)=0.40mol*L^-1#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/466018" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul 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<li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-a-solution-that-is-made-by-diluting-50-00-ml-of-a-4-74-m"> What is the molarity of a solution that is made by diluting 50.00 mL of a 4.74 M solution of HCl... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-volume-of-water-would-you-add-to-15-00-ml-of-a-6-77-m-solution-of-nitric-ac"> What volume of water would you add to 15.00 mL of a 6.77 M solution of nitric acid in order to... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/dilution-calculations"> See all questions in Dilution Calculations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1316 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the new concentration of a solute when a #20mL# volume of a mother liquor at #2.0molL^-1# concentration is diluted to a volume of #100mL#?	null
912	aa79cd0a-6ddd-11ea-906e-ccda262736ce	https://socratic.org/questions/58920d2a7c01491229065a05	5.52 mol/L	start physical_unit 14 15 molarity mol/l qc_end physical_unit 14 15 12 13 mass qc_end physical_unit 22 22 20 21 volume qc_end end	[{"type":"physical unit","value":"Molarity [OF] sodium chloride solution [IN] mol/L"}]	[{"type":"physical unit","value":"5.52 mol/L"}]	[{"type":"physical unit","value":"Mass [OF] sodium chloride [=] \\pu{250 g}"},{"type":"physical unit","value":"Volume [OF] water [=] \\pu{775 mL}"}]	<h1 class="questionTitle" itemprop="name">What is the molarity of a solution of containing a mass of #250g# sodium chloride in a volume of #775mL# water?</h1>	null	5.52 mol/L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And thus,</p> <p><mathjax>#"Molarity"=(250.0g)/(58.44gmol^-1)xx1/(775mLxx10^-3LmL^-1)#</mathjax></p> <p><mathjax>#=??mol*L^-1#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We use the relationship, </p> <p><mathjax>#"Molarity"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Moles of solute"/"Volume of solution (L)"~=6molL^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And thus,</p> <p><mathjax>#"Molarity"=(250.0g)/(58.44gmol^-1)xx1/(775mLxx10^-3LmL^-1)#</mathjax></p> <p><mathjax>#=??mol*L^-1#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the molarity of a solution of containing a mass of #250g# sodium chloride in a volume of #775mL# water?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="372155" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-02-01T16:44:04" itemprop="dateCreated"> Feb 1, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We use the relationship, </p> <p><mathjax>#"Molarity"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Moles of solute"/"Volume of solution (L)"~=6molL^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And thus,</p> <p><mathjax>#"Molarity"=(250.0g)/(58.44gmol^-1)xx1/(775mLxx10^-3LmL^-1)#</mathjax></p> <p><mathjax>#=??mol*L^-1#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/372155" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? 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913	ab2d805a-6ddd-11ea-8b2f-ccda262736ce	https://socratic.org/questions/a-doctor-s-order-is-0-125g-of-ampicillin-the-liquid-suspension-on-hand-contains-	2.5 milliliters	start physical_unit 21 22 volume ml qc_end physical_unit 7 7 4 5 mass qc_end physical_unit 8 10 14 16 molarity qc_end end	[{"type":"physical unit","value":"Volume [OF] the suspension [IN] milliliters"}]	[{"type":"physical unit","value":"2.5 milliliters"}]	[{"type":"physical unit","value":"Mass [OF] ampicillin [=] \\pu{0.125 g}"},{"type":"physical unit","value":"Molarity [OF] the liquid suspension [=] \\pu{250 mg/5.0 mL}"}]	<h1 class="questionTitle" itemprop="name">A doctor's order is 0.125g of ampicillin. The liquid suspension on hand contains 250 mg/5.0 mL. How many milliliters of the suspension are required?</h1>	null	2.5 milliliters	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First lets get the units the same for the suspension (in <mathjax>#mg#</mathjax>) and the required amount of ampicillin (in <mathjax>#g#</mathjax>):</p> <p><mathjax>#1 g = 1000 mg -> 0.125 g = 125 mg#</mathjax></p> <p>For easy calculation and for better understanding of what you are doing, it is best to then calculate how many <mathjax>#mg#</mathjax> is in <mathjax>#1 mL#</mathjax>:</p> <p><mathjax>#(250 mg) / (5.0 mL)= (50 mg)/(1 mL)#</mathjax></p> <p>So <mathjax>#1 mL#</mathjax> of the solution contains <mathjax>#50 mg#</mathjax> ampicillin. <br/> The doctor asks for <mathjax>#125 mg#</mathjax> of ampicillin which is a volume of:</p> <p><mathjax>#(125color(red)(cancel(color(black)(mg)))) / (50 (color(red)cancelcolor(black)(mg))/(mL)) = 2.5 mL#</mathjax></p> <p>So the required volume of the solution is <mathjax>#2.5 mL#</mathjax>. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2.5 mL#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First lets get the units the same for the suspension (in <mathjax>#mg#</mathjax>) and the required amount of ampicillin (in <mathjax>#g#</mathjax>):</p> <p><mathjax>#1 g = 1000 mg -> 0.125 g = 125 mg#</mathjax></p> <p>For easy calculation and for better understanding of what you are doing, it is best to then calculate how many <mathjax>#mg#</mathjax> is in <mathjax>#1 mL#</mathjax>:</p> <p><mathjax>#(250 mg) / (5.0 mL)= (50 mg)/(1 mL)#</mathjax></p> <p>So <mathjax>#1 mL#</mathjax> of the solution contains <mathjax>#50 mg#</mathjax> ampicillin. <br/> The doctor asks for <mathjax>#125 mg#</mathjax> of ampicillin which is a volume of:</p> <p><mathjax>#(125color(red)(cancel(color(black)(mg)))) / (50 (color(red)cancelcolor(black)(mg))/(mL)) = 2.5 mL#</mathjax></p> <p>So the required volume of the solution is <mathjax>#2.5 mL#</mathjax>. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A doctor's order is 0.125g of ampicillin. The liquid suspension on hand contains 250 mg/5.0 mL. How many milliliters of the suspension are required?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/solutions" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="286743" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/jo-lle"><img alt="" class="" src="https://profilepictures.socratic.org/QLjj3UhKRDegWjG5OG8v_1712995393.jpeg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/jo-lle"> Joëlle </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-10T13:06:31" itemprop="dateCreated"> Jul 10, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2.5 mL#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First lets get the units the same for the suspension (in <mathjax>#mg#</mathjax>) and the required amount of ampicillin (in <mathjax>#g#</mathjax>):</p> <p><mathjax>#1 g = 1000 mg -> 0.125 g = 125 mg#</mathjax></p> <p>For easy calculation and for better understanding of what you are doing, it is best to then calculate how many <mathjax>#mg#</mathjax> is in <mathjax>#1 mL#</mathjax>:</p> <p><mathjax>#(250 mg) / (5.0 mL)= (50 mg)/(1 mL)#</mathjax></p> <p>So <mathjax>#1 mL#</mathjax> of the solution contains <mathjax>#50 mg#</mathjax> ampicillin. <br/> The doctor asks for <mathjax>#125 mg#</mathjax> of ampicillin which is a volume of:</p> <p><mathjax>#(125color(red)(cancel(color(black)(mg)))) / (50 (color(red)cancelcolor(black)(mg))/(mL)) = 2.5 mL#</mathjax></p> <p>So the required volume of the solution is <mathjax>#2.5 mL#</mathjax>. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/286743" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-solution-solute-and-solvent-related"> How are solution, solute, and solvent related? 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The liquid suspension on hand contains 250 mg/5.0 mL. How many milliliters of the suspension are required?	null
914	a8c9a088-6ddd-11ea-a410-ccda262736ce	https://socratic.org/questions/59af57007c01492178564022	0.80 molar	start physical_unit 10 11 mole mol/l qc_end physical_unit 10 11 6 7 mass qc_end end	[{"type":"physical unit","value":"Mole [OF] magnesium metal [IN] molar"}]	[{"type":"physical unit","value":"0.80 molar"}]	[{"type":"physical unit","value":"Mass [OF] magnesium metal [=] \\pu{19.32 g}"}]	<h1 class="questionTitle" itemprop="name">What molar quantity is associated with #19.32*g# mass of magnesium metal?</h1>	null	0.80 molar	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>.......so we take the quotient....</p> <p><mathjax>#"Moles of Mg"=(19.32g)/(24.31gmol^-1)~=0.80mol#</mathjax>....</p> <p>....which of course is dimensionally consistent...........in that we get <mathjax>#cancelg/(cancelgmol^-1)=1/(1/(mol))=mol#</mathjax> as required.........i.e. <mathjax>#1/(1/x)=x#</mathjax></p> <p>What is the physical significance of this quantity? It tells us that there are <mathjax>#0.8molxxN_A=0.80molxx6.022xx10^23mol^-1#</mathjax> individual particles of magnesium in the sample......</p> <p>By this reasoning, there are <mathjax>#N_A#</mathjax> individual particles of magnesium in the sample whose mass is <mathjax>#24.31*g#</mathjax>. How did I know these numbers?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, we know that <mathjax>#1mol#</mathjax> of magnesium has a mass of <mathjax>#24.31g#</mathjax>...so..............</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>.......so we take the quotient....</p> <p><mathjax>#"Moles of Mg"=(19.32g)/(24.31gmol^-1)~=0.80mol#</mathjax>....</p> <p>....which of course is dimensionally consistent...........in that we get <mathjax>#cancelg/(cancelgmol^-1)=1/(1/(mol))=mol#</mathjax> as required.........i.e. <mathjax>#1/(1/x)=x#</mathjax></p> <p>What is the physical significance of this quantity? It tells us that there are <mathjax>#0.8molxxN_A=0.80molxx6.022xx10^23mol^-1#</mathjax> individual particles of magnesium in the sample......</p> <p>By this reasoning, there are <mathjax>#N_A#</mathjax> individual particles of magnesium in the sample whose mass is <mathjax>#24.31*g#</mathjax>. How did I know these numbers?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What molar quantity is associated with #19.32g# mass of magnesium metal?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="472222" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-09-06T03:59:48" itemprop="dateCreated"> Sep 6, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, we know that <mathjax>#1mol#</mathjax> of magnesium has a mass of <mathjax>#24.31g#</mathjax>...so..............</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>.......so we take the quotient....</p> <p><mathjax>#"Moles of Mg"=(19.32g)/(24.31gmol^-1)~=0.80mol#</mathjax>....</p> <p>....which of course is dimensionally consistent...........in that we get <mathjax>#cancelg/(cancelgmol^-1)=1/(1/(mol))=mol#</mathjax> as required.........i.e. <mathjax>#1/(1/x)=x#</mathjax></p> <p>What is the physical significance of this quantity? It tells us that there are <mathjax>#0.8molxxN_A=0.80molxx6.022xx10^23mol^-1#</mathjax> individual particles of magnesium in the sample......</p> <p>By this reasoning, there are <mathjax>#N_A#</mathjax> individual particles of magnesium in the sample whose mass is <mathjax>#24.31g#</mathjax>. How did I know these numbers?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/472222" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1033 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What molar quantity is associated with #19.32*g# mass of magnesium metal?	null
915	ab5451b7-6ddd-11ea-b575-ccda262736ce	https://socratic.org/questions/58dc5ba111ef6b3b0bfeda17	Cu^2+ + Fe -> Cu + Fe^2+	start chemical_equation qc_end substance 10 11 qc_end substance 13 13 qc_end end	[{"type":"other","value":"Chemical Equation [OF] net ionic equation"}]	[{"type":"chemical equation","value":"Cu^2+ + Fe -> Cu + Fe^2+"}]	[{"type":"substance name","value":"Copper(II) ion"},{"type":"substance name","value":"Iron"}]	<h1 class="questionTitle" itemprop="name">What is the net ionic equation for the reaction of copper(II) ion with iron?</h1>	null	Cu^2+ + Fe -> Cu + Fe^2+	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The water <mathjax>#H_2O#</mathjax> does not ionize or change, so it is not part of either the ionic equation or the net ionic equation. </p> <p>The sulfate ion <mathjax>#SO_4^-2#</mathjax> does not change so, while it part of the ionic equation, it is not part of the net ionic equation.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax># 1 Cu^(+2) + 1 SO_4^-2 + 1 Fe^0 -> 1 Fe^(+2) + 1 SO_4^-2 + 1 Cu^0#</mathjax> ionic equation. <br/> <mathjax># 1 Cu^(+2) + 1 Fe^0 -> 1 Cu^0 + 1 Fe^(+2)#</mathjax> net ionic equation.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The water <mathjax>#H_2O#</mathjax> does not ionize or change, so it is not part of either the ionic equation or the net ionic equation. </p> <p>The sulfate ion <mathjax>#SO_4^-2#</mathjax> does not change so, while it part of the ionic equation, it is not part of the net ionic equation.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the net ionic equation for the reaction of copper(II) ion with iron?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="398908" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/david-drayer"><img alt="" class="" src="https://graph.facebook.com/10206723679871989/picture?height=50&width=50" title=""/></a> <a class="secondContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/david-drayer"> David Drayer </a>·<a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-30T05:59:19" itemprop="dateCreated"> Mar 30, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax># 1 Cu^(+2) + 1 SO_4^-2 + 1 Fe^0 -> 1 Fe^(+2) + 1 SO_4^-2 + 1 Cu^0#</mathjax> ionic equation. <br/> <mathjax># 1 Cu^(+2) + 1 Fe^0 -> 1 Cu^0 + 1 Fe^(+2)#</mathjax> net ionic equation.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The water <mathjax>#H_2O#</mathjax> does not ionize or change, so it is not part of either the ionic equation or the net ionic equation. </p> <p>The sulfate ion <mathjax>#SO_4^-2#</mathjax> does not change so, while it part of the ionic equation, it is not part of the net ionic equation.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/398908" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a 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916	ac6d565c-6ddd-11ea-b398-ccda262736ce	https://socratic.org/questions/the-mass-of-the-water-water-at-is-70-0-g-what-is-the-energy-required-to-heat-a-b	23.99 kJ	start physical_unit 3 3 energy kj qc_end physical_unit 3 3 5 6 mass qc_end physical_unit 3 3 19 21 temperature qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Required energy [OF] water [IN] kJ"}]	[{"type":"physical unit","value":"23.99 kJ"}]	[{"type":"physical unit","value":"Mass [OF] water [=] \\pu{70.0 g}"},{"type":"physical unit","value":"Temperature1 [OF] water [=] \\pu{18 degrees C}"},{"type":"other","value":"Heat a beaker of water to boiling."}]	<h1 class="questionTitle" itemprop="name"> The mass of water is 70.0 g. What is the energy required to heat a beaker of water at 18 degrees C to boiling? </h1>	null	23.99 kJ	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The energy required to heat an object is given by the formula</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a) q = mcΔTcolor(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>where</p> <p><mathjax>#q#</mathjax> is the energy required<br/> <mathjax>#m#</mathjax> is the mass<br/> <mathjax>#c#</mathjax> is the <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> capacity<br/> <mathjax>#ΔT#</mathjax> is the change in temperature</p> <blockquote></blockquote> <p>In your problem,</p> <p><mathjax>#m = "70.0 g"#</mathjax><br/> <mathjax>#c = "4.179 J"·"°C"^"-1"·"g"^"-1"#</mathjax><br/> <mathjax>#ΔT = "(100 - 18) °C" = "82 °C"#</mathjax></p> <p>∴ <mathjax>#q = 70.0 color(red)(cancel(color(black)("g"))) × "4.179 J"·color(red)(cancel(color(black)("°C"^"-1"·"g"^"-1"))) × 82 color(red)(cancel(color(black)("°C"))) = "24 000 J" = "24 kJ"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The energy required is 24 kJ.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The energy required to heat an object is given by the formula</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a) q = mcΔTcolor(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>where</p> <p><mathjax>#q#</mathjax> is the energy required<br/> <mathjax>#m#</mathjax> is the mass<br/> <mathjax>#c#</mathjax> is the <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> capacity<br/> <mathjax>#ΔT#</mathjax> is the change in temperature</p> <blockquote></blockquote> <p>In your problem,</p> <p><mathjax>#m = "70.0 g"#</mathjax><br/> <mathjax>#c = "4.179 J"·"°C"^"-1"·"g"^"-1"#</mathjax><br/> <mathjax>#ΔT = "(100 - 18) °C" = "82 °C"#</mathjax></p> <p>∴ <mathjax>#q = 70.0 color(red)(cancel(color(black)("g"))) × "4.179 J"·color(red)(cancel(color(black)("°C"^"-1"·"g"^"-1"))) × 82 color(red)(cancel(color(black)("°C"))) = "24 000 J" = "24 kJ"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name"> The mass of water is 70.0 g. What is the energy required to heat a beaker of water at 18 degrees C to boiling? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/specific-heat" itemprop="url"> <span class="breadcrumb" itemprop="title">Specific Heat</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="292709" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-27T20:54:38" itemprop="dateCreated"> Jul 27, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The energy required is 24 kJ.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The energy required to heat an object is given by the formula</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a) q = mcΔTcolor(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>where</p> <p><mathjax>#q#</mathjax> is the energy required<br/> <mathjax>#m#</mathjax> is the mass<br/> <mathjax>#c#</mathjax> is the <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> capacity<br/> <mathjax>#ΔT#</mathjax> is the change in temperature</p> <blockquote></blockquote> <p>In your problem,</p> <p><mathjax>#m = "70.0 g"#</mathjax><br/> <mathjax>#c = "4.179 J"·"°C"^"-1"·"g"^"-1"#</mathjax><br/> <mathjax>#ΔT = "(100 - 18) °C" = "82 °C"#</mathjax></p> <p>∴ <mathjax>#q = 70.0 color(red)(cancel(color(black)("g"))) × "4.179 J"·color(red)(cancel(color(black)("°C"^"-1"·"g"^"-1"))) × 82 color(red)(cancel(color(black)("°C"))) = "24 000 J" = "24 kJ"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/292709" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-specific-heat-be-used-to-identify-substances"> How can specific heat be used to identify substances? 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What is the energy required to heat a beaker of water at 18 degrees C to boiling?	null
917	accc94e6-6ddd-11ea-a72c-ccda262736ce	https://socratic.org/questions/the-concentration-of-carbonic-acid-in-normal-blood-is-0-029-mol-l-and-the-pka-fo	0.58 M	start physical_unit 30 31 concentration mol/l qc_end physical_unit 3 4 9 10 concentration qc_end physical_unit 3 4 18 18 pka qc_end c_other OTHER qc_end physical_unit 33 35 39 39 ph qc_end end	[{"type":"physical unit","value":"Concentration [OF] bicarbonate ion [IN] M"}]	[{"type":"physical unit","value":"0.58 M"}]	[{"type":"physical unit","value":"Concentration [OF] carbonic acid [=] \\pu{0.029 mol/L}"},{"type":"physical unit","value":"pKa [OF] carbonic acid [=] \\pu{6.1}"},{"type":"other","value":"Using the Henderson-Hasselbach equation."},{"type":"physical unit","value":"pH [OF] normal blood sample [=] \\pu{7.40}"}]	<h1 class="questionTitle" itemprop="name">The concentration of carbonic acid in normal blood is 0.029 mol/L and the pKa for carbonic acid is 6.1. Using the Henderson-Hasselbach equation, how do you determine the concentration of bicarbonate ion in normal blood sample which is pH 7.40?</h1>	null	0.58 M	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>All you have to do here is plug in the values given to you in the <strong>Henderson - Hasselbalch equation</strong> and solve for the concentration of the <em>bicarbonate anions</em>, <mathjax>#"HCO"_3^(-)#</mathjax>.</p> <p>Now, let's assume that you're <strong>not</strong> familiar with the H - H equation. You can derive it by using the equilibrium reaction that describes the partial ionization of carbonic acid, <mathjax>#"H"_2"CO"_3#</mathjax>, in aqueous solution</p> <blockquote> <p><mathjax>#"H"_ 2 "CO"_ (3(aq)) + "H"_ 2"O"_ ((l)) rightleftharpoons "H"_ 3"O"_ ((aq))^(+) + "HCO"_ (3(aq))^(-)#</mathjax></p> </blockquote> <p>By definition, the <em>acid dissociation constant</em>, <mathjax>#K_a#</mathjax>, will be equal to </p> <blockquote> <p><mathjax>#K_a = (["H"_3"O"^(+)] * ["HCO"_3^(-)])/(["H"_2"CO"_3])#</mathjax></p> </blockquote> <p>Take the <strong>log base</strong> <mathjax>#10#</mathjax> of both sides to get </p> <blockquote> <p><mathjax>#log(K_a) = log( ["H"_3"O"^(+)] * (["HCO"_3^(-)])/(["H"_2"CO"_3]))#</mathjax></p> </blockquote> <p>This will be equivalent to </p> <blockquote> <p><mathjax>#log(K_a) = log(["H"_3"O"^(+)]) + log((["HCO"_3^(-)])/(["H"_2"CO"_3]))#</mathjax></p> </blockquote> <p>Rearrange to get</p> <blockquote> <p><mathjax>#- log(["H"_3"O"^(+)]) = - log(K_a) + log((["HCO"_3^(-)])/(["H"_2"CO"_3]))#</mathjax></p> </blockquote> <p>But you know that</p> <blockquote> <p><mathjax>#color(purple)(\|bar(ul(color(white)(a/a)color(black)("pH" = - log(["H"_3"O"^(+)]))color(white)(a/a)\|)))" "#</mathjax> and <mathjax>#" "color(purple)(\|bar(ul(color(white)(a/a)color(black)("p"K_a = - log(K_a))color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>and so you have</p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a)"pH" = "p"K_a + log((["HCO"_3^(-)])/(["H"_2"CO"_3]))color(white)(a/a)\|))) ->#</mathjax> <em>the <strong>Henderson - Hasselbalch equation</strong></em></p> </blockquote> <p>This is the Henderson - Hasselbalch equation for buffer <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> that contain a <strong>weak acid</strong> and its <em>conjugate base</em>. </p> <p>To find the concentration of bicarbonate anions, isolate the log term on one side of the equation</p> <blockquote> <p><mathjax>#7.40 = 6.1 + log((["HCO"_3^(-)])/(["H"_2"CO"_3]))#</mathjax></p> <p><mathjax>#log((["HCO"_3^(-)])/(["H"_2"CO"_3])) = 1.3#</mathjax></p> </blockquote> <p>This will be equivalent to </p> <blockquote> <p><mathjax>#10^log((["HCO"_3^(-)])/(["H"_2"CO"_3])) = 10^1.3#</mathjax></p> </blockquote> <p>which in turn will get you </p> <blockquote> <p><mathjax>#(["HCO"_3^(-)])/(["H"_2"CO"_3]) = 19.95#</mathjax></p> </blockquote> <p>Therefore, you will have</p> <blockquote> <p><mathjax>#["HCO"_3^(-)] = 19.95 * ["H"_2"CO"_3]#</mathjax></p> <p><mathjax>#["HCO"_3^(-)] = 19.95 * "0.029 mol L"^(-1) = color(green)(\|bar(ul(color(white)(a/a)color(black)("0.58 mol L"^(-1))color(white)(a/a)\|)))#</mathjax> </p> </blockquote> <p>Notice that you have a <strong>higher concentration</strong> of conjugate base than you do of weak acid, which is why the <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> of the buffer is <strong>higher</strong> than the <mathjax>#"p"K_a#</mathjax> of the weak acid.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#["HCO"_3^(-)]#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>All you have to do here is plug in the values given to you in the <strong>Henderson - Hasselbalch equation</strong> and solve for the concentration of the <em>bicarbonate anions</em>, <mathjax>#"HCO"_3^(-)#</mathjax>.</p> <p>Now, let's assume that you're <strong>not</strong> familiar with the H - H equation. You can derive it by using the equilibrium reaction that describes the partial ionization of carbonic acid, <mathjax>#"H"_2"CO"_3#</mathjax>, in aqueous solution</p> <blockquote> <p><mathjax>#"H"_ 2 "CO"_ (3(aq)) + "H"_ 2"O"_ ((l)) rightleftharpoons "H"_ 3"O"_ ((aq))^(+) + "HCO"_ (3(aq))^(-)#</mathjax></p> </blockquote> <p>By definition, the <em>acid dissociation constant</em>, <mathjax>#K_a#</mathjax>, will be equal to </p> <blockquote> <p><mathjax>#K_a = (["H"_3"O"^(+)] * ["HCO"_3^(-)])/(["H"_2"CO"_3])#</mathjax></p> </blockquote> <p>Take the <strong>log base</strong> <mathjax>#10#</mathjax> of both sides to get </p> <blockquote> <p><mathjax>#log(K_a) = log( ["H"_3"O"^(+)] * (["HCO"_3^(-)])/(["H"_2"CO"_3]))#</mathjax></p> </blockquote> <p>This will be equivalent to </p> <blockquote> <p><mathjax>#log(K_a) = log(["H"_3"O"^(+)]) + log((["HCO"_3^(-)])/(["H"_2"CO"_3]))#</mathjax></p> </blockquote> <p>Rearrange to get</p> <blockquote> <p><mathjax>#- log(["H"_3"O"^(+)]) = - log(K_a) + log((["HCO"_3^(-)])/(["H"_2"CO"_3]))#</mathjax></p> </blockquote> <p>But you know that</p> <blockquote> <p><mathjax>#color(purple)(\|bar(ul(color(white)(a/a)color(black)("pH" = - log(["H"_3"O"^(+)]))color(white)(a/a)\|)))" "#</mathjax> and <mathjax>#" "color(purple)(\|bar(ul(color(white)(a/a)color(black)("p"K_a = - log(K_a))color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>and so you have</p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a)"pH" = "p"K_a + log((["HCO"_3^(-)])/(["H"_2"CO"_3]))color(white)(a/a)\|))) ->#</mathjax> <em>the <strong>Henderson - Hasselbalch equation</strong></em></p> </blockquote> <p>This is the Henderson - Hasselbalch equation for buffer <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> that contain a <strong>weak acid</strong> and its <em>conjugate base</em>. </p> <p>To find the concentration of bicarbonate anions, isolate the log term on one side of the equation</p> <blockquote> <p><mathjax>#7.40 = 6.1 + log((["HCO"_3^(-)])/(["H"_2"CO"_3]))#</mathjax></p> <p><mathjax>#log((["HCO"_3^(-)])/(["H"_2"CO"_3])) = 1.3#</mathjax></p> </blockquote> <p>This will be equivalent to </p> <blockquote> <p><mathjax>#10^log((["HCO"_3^(-)])/(["H"_2"CO"_3])) = 10^1.3#</mathjax></p> </blockquote> <p>which in turn will get you </p> <blockquote> <p><mathjax>#(["HCO"_3^(-)])/(["H"_2"CO"_3]) = 19.95#</mathjax></p> </blockquote> <p>Therefore, you will have</p> <blockquote> <p><mathjax>#["HCO"_3^(-)] = 19.95 * ["H"_2"CO"_3]#</mathjax></p> <p><mathjax>#["HCO"_3^(-)] = 19.95 * "0.029 mol L"^(-1) = color(green)(\|bar(ul(color(white)(a/a)color(black)("0.58 mol L"^(-1))color(white)(a/a)\|)))#</mathjax> </p> </blockquote> <p>Notice that you have a <strong>higher concentration</strong> of conjugate base than you do of weak acid, which is why the <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> of the buffer is <strong>higher</strong> than the <mathjax>#"p"K_a#</mathjax> of the weak acid.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">The concentration of carbonic acid in normal blood is 0.029 mol/L and the pKa for carbonic acid is 6.1. Using the Henderson-Hasselbach equation, how do you determine the concentration of bicarbonate ion in normal blood sample which is pH 7.40?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#reactions-in-solution" itemprop="url"> <span class="breadcrumb" itemprop="title">Reactions in Solution</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/reactions-in-solution/buffer-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">Buffer Calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="276125" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-11T00:55:45" itemprop="dateCreated"> Jun 11, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#["HCO"_3^(-)]#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>All you have to do here is plug in the values given to you in the <strong>Henderson - Hasselbalch equation</strong> and solve for the concentration of the <em>bicarbonate anions</em>, <mathjax>#"HCO"_3^(-)#</mathjax>.</p> <p>Now, let's assume that you're <strong>not</strong> familiar with the H - H equation. You can derive it by using the equilibrium reaction that describes the partial ionization of carbonic acid, <mathjax>#"H"_2"CO"_3#</mathjax>, in aqueous solution</p> <blockquote> <p><mathjax>#"H"_ 2 "CO"_ (3(aq)) + "H"_ 2"O"_ ((l)) rightleftharpoons "H"_ 3"O"_ ((aq))^(+) + "HCO"_ (3(aq))^(-)#</mathjax></p> </blockquote> <p>By definition, the <em>acid dissociation constant</em>, <mathjax>#K_a#</mathjax>, will be equal to </p> <blockquote> <p><mathjax>#K_a = (["H"_3"O"^(+)] * ["HCO"_3^(-)])/(["H"_2"CO"_3])#</mathjax></p> </blockquote> <p>Take the <strong>log base</strong> <mathjax>#10#</mathjax> of both sides to get </p> <blockquote> <p><mathjax>#log(K_a) = log( ["H"_3"O"^(+)] * (["HCO"_3^(-)])/(["H"_2"CO"_3]))#</mathjax></p> </blockquote> <p>This will be equivalent to </p> <blockquote> <p><mathjax>#log(K_a) = log(["H"_3"O"^(+)]) + log((["HCO"_3^(-)])/(["H"_2"CO"_3]))#</mathjax></p> </blockquote> <p>Rearrange to get</p> <blockquote> <p><mathjax>#- log(["H"_3"O"^(+)]) = - log(K_a) + log((["HCO"_3^(-)])/(["H"_2"CO"_3]))#</mathjax></p> </blockquote> <p>But you know that</p> <blockquote> <p><mathjax>#color(purple)(\|bar(ul(color(white)(a/a)color(black)("pH" = - log(["H"_3"O"^(+)]))color(white)(a/a)\|)))" "#</mathjax> and <mathjax>#" "color(purple)(\|bar(ul(color(white)(a/a)color(black)("p"K_a = - log(K_a))color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>and so you have</p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a)"pH" = "p"K_a + log((["HCO"_3^(-)])/(["H"_2"CO"_3]))color(white)(a/a)\|))) ->#</mathjax> <em>the <strong>Henderson - Hasselbalch equation</strong></em></p> </blockquote> <p>This is the Henderson - Hasselbalch equation for buffer <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> that contain a <strong>weak acid</strong> and its <em>conjugate base</em>. </p> <p>To find the concentration of bicarbonate anions, isolate the log term on one side of the equation</p> <blockquote> <p><mathjax>#7.40 = 6.1 + log((["HCO"_3^(-)])/(["H"_2"CO"_3]))#</mathjax></p> <p><mathjax>#log((["HCO"_3^(-)])/(["H"_2"CO"_3])) = 1.3#</mathjax></p> </blockquote> <p>This will be equivalent to </p> <blockquote> <p><mathjax>#10^log((["HCO"_3^(-)])/(["H"_2"CO"_3])) = 10^1.3#</mathjax></p> </blockquote> <p>which in turn will get you </p> <blockquote> <p><mathjax>#(["HCO"_3^(-)])/(["H"_2"CO"_3]) = 19.95#</mathjax></p> </blockquote> <p>Therefore, you will have</p> <blockquote> <p><mathjax>#["HCO"_3^(-)] = 19.95 * ["H"_2"CO"_3]#</mathjax></p> <p><mathjax>#["HCO"_3^(-)] = 19.95 * "0.029 mol L"^(-1) = color(green)(\|bar(ul(color(white)(a/a)color(black)("0.58 mol L"^(-1))color(white)(a/a)\|)))#</mathjax> </p> </blockquote> <p>Notice that you have a <strong>higher concentration</strong> of conjugate base than you do of weak acid, which is why the <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> of the buffer is <strong>higher</strong> than the <mathjax>#"p"K_a#</mathjax> of the weak acid.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/276125" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-buffer-solutions-used"> How are buffer solutions used? 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Using the Henderson-Hasselbach equation, how do you determine the concentration of bicarbonate ion in normal blood sample which is pH 7.40?	null
918	ac7bae48-6ddd-11ea-bb3c-ccda262736ce	https://socratic.org/questions/the-solubility-of-ba-no-3-2-is-130-5-g-l-at-0-o-c-how-many-moles-of-dissolved-sa	2.00 moles	start physical_unit 14 15 mole mol qc_end physical_unit 3 3 5 6 solubility qc_end physical_unit 3 3 8 9 temperature qc_end physical_unit 24 24 19 20 volume qc_end end	[{"type":"physical unit","value":"Mole [OF] dissolved salt [IN] moles"}]	[{"type":"physical unit","value":"2.00 moles"}]	[{"type":"physical unit","value":"Solubility [OF] Ba(NO3)2 [=] \\pu{130.5 g/L}"},{"type":"physical unit","value":"Temperature [OF] Ba(NO3)2 [=] \\pu{0 ℃}"},{"type":"physical unit","value":"Volume [OF] Ba(NO3)2 saturated solution [=] \\pu{4.0 L}"},{"type":"physical unit","value":"Temperature [OF] Ba(NO3)2 saturated solution [=] \\pu{0 ℃}"}]	<h1 class="questionTitle" itemprop="name">The solubility of #Ba(NO_3)_2# is 130.5 g/L at #0^o C#. How many moles of dissolved salt are present in 4.0 L of a saturated solution of #Ba(NO_3)_2# at #0^oC#? </h1>	null	2.00 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The problem provides you with the solubility of barium nitrate, <mathjax>#"Ba"("NO"_3)_2#</mathjax>, in <strong>grams per liter</strong>, <mathjax>#"g L"^(-1)#</mathjax>, in water at <mathjax>#0^@"C"#</mathjax>, and asks you to figure out how many <em><strong>moles</strong></em> of barium nitrate can be dissolved in <mathjax>#"4.0 L"#</mathjax> of aqueous solution at <mathjax>#0^@"C"#</mathjax>. </p> <p>The first thing to do here is recognize the fact that the solubility of barium nitrate tells you how many <em>grams</em> of the salt can be dissolved in <strong>one liter</strong> of water at <mathjax>#0^@"C"#</mathjax> in order to make a <strong>saturated solution</strong>. </p> <p>In this case, barium nitrate is said to have a solubility of <mathjax>#"130.5 g L"^(-1)#</mathjax>, which tells you that at <mathjax>#0^@"C#</mathjax>", you can only hope to dissolve <mathjax>#"130.5 g"#</mathjax> of barium nitrate <strong>per liter of water</strong>. </p> <p>Use the compound's <strong>molar mass</strong> to convert the mass of barium nitrate to <em>moles</em></p> <blockquote> <p><mathjax>#130.5 color(red)(cancel(color(black)("g"))) * ("1 mole Ba"("NO"_3)_2)/(261.34color(red)(cancel(color(black)("g")))) = "0.4993 moles Ba"("NO"_3)_2#</mathjax></p> </blockquote> <p>Now, you know that <mathjax>#"1 L"#</mathjax> of water can dissolve <mathjax>#0.4993#</mathjax> <strong>moles</strong> of barium nitrate at <mathjax>#0^@"C"#</mathjax>, which means that <mathjax>#"4.0 L"#</mathjax> of water can dissolve</p> <blockquote> <p><mathjax>#4.0 color(red)(cancel(color(black)("L water"))) * ("0.4993 moles Ba"("NO"_3)_2)/(1color(red)(cancel(color(black)("L water")))) = color(green)(\|bar(ul(color(white)(a/a)color(black)("2.0 moles Ba"("NO"_3)_2)color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer is rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the volume of water. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"2.0 moles Ba"("NO"_3)_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The problem provides you with the solubility of barium nitrate, <mathjax>#"Ba"("NO"_3)_2#</mathjax>, in <strong>grams per liter</strong>, <mathjax>#"g L"^(-1)#</mathjax>, in water at <mathjax>#0^@"C"#</mathjax>, and asks you to figure out how many <em><strong>moles</strong></em> of barium nitrate can be dissolved in <mathjax>#"4.0 L"#</mathjax> of aqueous solution at <mathjax>#0^@"C"#</mathjax>. </p> <p>The first thing to do here is recognize the fact that the solubility of barium nitrate tells you how many <em>grams</em> of the salt can be dissolved in <strong>one liter</strong> of water at <mathjax>#0^@"C"#</mathjax> in order to make a <strong>saturated solution</strong>. </p> <p>In this case, barium nitrate is said to have a solubility of <mathjax>#"130.5 g L"^(-1)#</mathjax>, which tells you that at <mathjax>#0^@"C#</mathjax>", you can only hope to dissolve <mathjax>#"130.5 g"#</mathjax> of barium nitrate <strong>per liter of water</strong>. </p> <p>Use the compound's <strong>molar mass</strong> to convert the mass of barium nitrate to <em>moles</em></p> <blockquote> <p><mathjax>#130.5 color(red)(cancel(color(black)("g"))) * ("1 mole Ba"("NO"_3)_2)/(261.34color(red)(cancel(color(black)("g")))) = "0.4993 moles Ba"("NO"_3)_2#</mathjax></p> </blockquote> <p>Now, you know that <mathjax>#"1 L"#</mathjax> of water can dissolve <mathjax>#0.4993#</mathjax> <strong>moles</strong> of barium nitrate at <mathjax>#0^@"C"#</mathjax>, which means that <mathjax>#"4.0 L"#</mathjax> of water can dissolve</p> <blockquote> <p><mathjax>#4.0 color(red)(cancel(color(black)("L water"))) * ("0.4993 moles Ba"("NO"_3)_2)/(1color(red)(cancel(color(black)("L water")))) = color(green)(\|bar(ul(color(white)(a/a)color(black)("2.0 moles Ba"("NO"_3)_2)color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer is rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the volume of water. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">The solubility of #Ba(NO_3)_2# is 130.5 g/L at #0^o C#. How many moles of dissolved salt are present in 4.0 L of a saturated solution of #Ba(NO_3)_2# at #0^oC#? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/factors-affecting-solubility" itemprop="url"> <span class="breadcrumb" itemprop="title">Factors Affecting Solubility</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="288528" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-16T00:11:29" itemprop="dateCreated"> Jul 16, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"2.0 moles Ba"("NO"_3)_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The problem provides you with the solubility of barium nitrate, <mathjax>#"Ba"("NO"_3)_2#</mathjax>, in <strong>grams per liter</strong>, <mathjax>#"g L"^(-1)#</mathjax>, in water at <mathjax>#0^@"C"#</mathjax>, and asks you to figure out how many <em><strong>moles</strong></em> of barium nitrate can be dissolved in <mathjax>#"4.0 L"#</mathjax> of aqueous solution at <mathjax>#0^@"C"#</mathjax>. </p> <p>The first thing to do here is recognize the fact that the solubility of barium nitrate tells you how many <em>grams</em> of the salt can be dissolved in <strong>one liter</strong> of water at <mathjax>#0^@"C"#</mathjax> in order to make a <strong>saturated solution</strong>. </p> <p>In this case, barium nitrate is said to have a solubility of <mathjax>#"130.5 g L"^(-1)#</mathjax>, which tells you that at <mathjax>#0^@"C#</mathjax>", you can only hope to dissolve <mathjax>#"130.5 g"#</mathjax> of barium nitrate <strong>per liter of water</strong>. </p> <p>Use the compound's <strong>molar mass</strong> to convert the mass of barium nitrate to <em>moles</em></p> <blockquote> <p><mathjax>#130.5 color(red)(cancel(color(black)("g"))) * ("1 mole Ba"("NO"_3)_2)/(261.34color(red)(cancel(color(black)("g")))) = "0.4993 moles Ba"("NO"_3)_2#</mathjax></p> </blockquote> <p>Now, you know that <mathjax>#"1 L"#</mathjax> of water can dissolve <mathjax>#0.4993#</mathjax> <strong>moles</strong> of barium nitrate at <mathjax>#0^@"C"#</mathjax>, which means that <mathjax>#"4.0 L"#</mathjax> of water can dissolve</p> <blockquote> <p><mathjax>#4.0 color(red)(cancel(color(black)("L water"))) * ("0.4993 moles Ba"("NO"_3)_2)/(1color(red)(cancel(color(black)("L water")))) = color(green)(\|bar(ul(color(white)(a/a)color(black)("2.0 moles Ba"("NO"_3)_2)color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer is rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the volume of water. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/288528" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-factors-affect-solubility-in-a-solid-liquid-combination"> What factors affect solubility in a solid-liquid combination? 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</a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-the-solubility-of-kno3-depend-on"> What does the solubility of KNO3 depend on? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-solubility-of-a-solution"> How can I calculate the solubility of solute in a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-solubility-is-affected-by-polymer-chain-structure"> How is solubility affected by polymer chain structure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/does-solubility-differ-from-molar-solubility"> Does solubility differ from molar solubility? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/factors-affecting-solubility"> See all questions in Factors Affecting Solubility </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 6031 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	The solubility of #Ba(NO_3)_2# is 130.5 g/L at #0^o C#. How many moles of dissolved salt are present in 4.0 L of a saturated solution of #Ba(NO_3)_2# at #0^oC#?	null
919	ac33019a-6ddd-11ea-9685-ccda262736ce	https://socratic.org/questions/how-many-grams-are-contained-in-2-22-moles-of-sucrose-c-12h-22o-11	759 grams	start physical_unit 10 10 mass g qc_end physical_unit 10 10 6 7 mole qc_end end	[{"type":"physical unit","value":"Mass [OF] C12H22O11 [IN] grams"}]	[{"type":"physical unit","value":"759 grams"}]	[{"type":"physical unit","value":"Mole [OF] C12H22O11 [=] \\pu{2.22 moles}"}]	<h1 class="questionTitle" itemprop="name">How many grams are contained in 2.22 moles of sucrose #C_12H_22O_11#?</h1>	null	759 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The relationship between the number of mole (<mathjax>#n#</mathjax>) and the mass (<mathjax>#m#</mathjax>) of sucrose is the following:</p> <p><mathjax>#n=m/(MM)#</mathjax>, where <mathjax>#MM=342 g/(mol)#</mathjax> is the molar mass of sucrose.</p> <p><mathjax>#=>m=nxxMM=2.22cancel(mol)xx342 g/(cancel(mol))=759g#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#759g#</mathjax> of <mathjax>#C_12H_22O_11#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The relationship between the number of mole (<mathjax>#n#</mathjax>) and the mass (<mathjax>#m#</mathjax>) of sucrose is the following:</p> <p><mathjax>#n=m/(MM)#</mathjax>, where <mathjax>#MM=342 g/(mol)#</mathjax> is the molar mass of sucrose.</p> <p><mathjax>#=>m=nxxMM=2.22cancel(mol)xx342 g/(cancel(mol))=759g#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many grams are contained in 2.22 moles of sucrose #C_12H_22O_11#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="241415" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ali-h-1"><img alt="" class="" src="https://profilepictures.socratic.org/IITeL1YTQdODdLp0aJTL_StereoPicture%20copy.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ali-h-1"> Dr. Hayek </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-18T11:33:22" itemprop="dateCreated"> Mar 18, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#759g#</mathjax> of <mathjax>#C_12H_22O_11#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The relationship between the number of mole (<mathjax>#n#</mathjax>) and the mass (<mathjax>#m#</mathjax>) of sucrose is the following:</p> <p><mathjax>#n=m/(MM)#</mathjax>, where <mathjax>#MM=342 g/(mol)#</mathjax> is the molar mass of sucrose.</p> <p><mathjax>#=>m=nxxMM=2.22cancel(mol)xx342 g/(cancel(mol))=759g#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/241415" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? 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</a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1888 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many grams are contained in 2.22 moles of sucrose #C_12H_22O_11#?	null
920	ab35c39d-6ddd-11ea-969e-ccda262736ce	https://socratic.org/questions/56d2d65111ef6b77382037e0	10.52	start physical_unit 6 6 ph none qc_end physical_unit 8 9 14 16 equilibrium_constant_k qc_end end	[{"type":"physical unit","value":"pH [OF] magnesium hydroxide solution"}]	[{"type":"physical unit","value":"10.52"}]	[{"type":"physical unit","value":"Ksp [OF] magnesium hydroxide [=] \\pu{1.8 × 10^(-11)}"}]	<h1 class="questionTitle" itemprop="name">What is the #"pH"# of a solution of magnesium hydroxide given that #K_(sp) = 1.8 * 10^(-11)# ?</h1>	null	10.52	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to find the <a href="http://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> of a solution, you must determine the concentration of <em>hydronium ions</em>, <mathjax>#"H"_3"O"^(+)#</mathjax>, either <em>directly</em> or <em>indirectly</em>. </p> <p>When you're dealing with a <strong>Bronsted - Lowry acid</strong>, you will be solving for the concentration of hydronium ions <em>directly</em>. </p> <p>When you're dealing with a <strong>Bronsted - Lowry base</strong>, like you are here, you will be solving for the concentration of hydronium ions <em>indirectly</em>, i.e. by solving for the concentration of <em>hydroxide ions</em>, <mathjax>#"OH"^(-)#</mathjax>.</p> <p><em>Magnesium hydroxide</em>, <mathjax>#"Mg"("OH")_2#</mathjax>, us <strong>insoluble</strong> in aqueous solution. This means that when you place magnesium hydroxide in water, an <strong><a href="http://socratic.org/chemistry/chemical-equilibrium/dynamic-equilibrium">equilibrium</a></strong> will be established between the <em>undissolved solid</em> and the <em>dissolved ions</em>. </p> <blockquote> <p><mathjax>#"Mg"("OH")_text(2(s]) rightleftharpoons "Mg"_text((aq])^(2+) + color(red)(2)"OH"_text((aq])^(-)#</mathjax></p> </blockquote> <p>The <em>solubility product constant</em>, <mathjax>#K_(sp)#</mathjax>, for this equilibrium looks like this</p> <blockquote> <p><mathjax>#K_(sp) = ["Mg"^(2+)] * ["OH"^(-)]^color(red)(2)#</mathjax></p> </blockquote> <p>What you need to do here is use the <mathjax>#K_(sp)#</mathjax> to find the <strong>molar solubility</strong>, <mathjax>#s#</mathjax>, of magnesium hydroxide in aqueous solution at <mathjax>#25^@"C"#</mathjax>. </p> <p>To do that, set up an <strong>ICE table</strong></p> <blockquote> <p><mathjax>#" ""Mg"("OH")_text(2(s]) " "rightleftharpoons" " "Mg"_text((aq])^(2+) " "+" " color(red)(2)"OH"_text((aq])^(-)#</mathjax></p> </blockquote> <p><mathjax>#color(purple)("I")" " " " " "-" " " " " " " " " " " " " "0" " " " " " " " " " 0#</mathjax><br/> <mathjax>#color(purple)("C")" " " " " "-" " " " " " " " " " " "(+s)" " " " " "(+color(red)(2)s)#</mathjax><br/> <mathjax>#color(purple)("E")" " " " " "-" " " " " " " " " " " " " "s" " " " " " " " " "color(red)(2)s#</mathjax></p> <p>Remember, the concentration of the solid is assumed to be <strong>constant</strong>. </p> <p>Here <mathjax>#K_(sp)#</mathjax> will be equal to</p> <blockquote> <p><mathjax>#K_(sp) = s * (color(red)(2)s)^color(red)(2) = 4s^3#</mathjax> </p> </blockquote> <p>Rearrange to solve for <mathjax>#s#</mathjax></p> <blockquote> <p><mathjax>#s = root(3)(K_(sp)/4) = root(3)((1.8 * 10^(-11))/4) = 1.65 * 10^(-4)#</mathjax></p> </blockquote> <p>This means that the concentration of hydroxide ions in a <em>saturated</em> solution of magnesium hydroxide at <mathjax>#25^@"C"#</mathjax> will be </p> <blockquote> <p><mathjax>#["OH"^(-)] = color(red)(2) * 1.65 * 10^(-4)"M" = 3.30 * 10^(-4)"M"#</mathjax></p> </blockquote> <p>Now, at <mathjax>#25^@"C"#</mathjax>, the concentration of hydronium ions and the concentration of hydroxide ions have the following relationship</p> <blockquote> <p><mathjax>#color(blue)(K_W = ["H"_3"O"^(+)] * ["OH"^(-)] = 10^(-4))" "#</mathjax>, where</p> </blockquote> <p><mathjax>#K_W#</mathjax> - the <strong>ion product</strong> for water's auto-ionization</p> <p>Plug in your value to get</p> <blockquote> <p><mathjax>#["H"_3"O"^(+)] = 10^(-14)/(3.30 * 10^(-4)) = 3.03 * 10^(-11)"M"#</mathjax></p> </blockquote> <p>This means that the pH of the solution will be </p> <blockquote> <p><mathjax>#color(blue)("pH" = - log(["H"_3"O"^(+)]))#</mathjax></p> <p><mathjax>#"pH" = - log(3.03 * 10^(-11)) = color(green)(10.52)#</mathjax></p> </blockquote> <p><strong>Alternatively</strong>, you can use the equation</p> <blockquote> <p><mathjax>#color(blue)("pH " + " pOH" = 14)#</mathjax></p> </blockquote> <p>Here </p> <blockquote> <p><mathjax>#color(blue)("pOH" = - log(["OH"^(-)]))#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"pH" = 10.52#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to find the <a href="http://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> of a solution, you must determine the concentration of <em>hydronium ions</em>, <mathjax>#"H"_3"O"^(+)#</mathjax>, either <em>directly</em> or <em>indirectly</em>. </p> <p>When you're dealing with a <strong>Bronsted - Lowry acid</strong>, you will be solving for the concentration of hydronium ions <em>directly</em>. </p> <p>When you're dealing with a <strong>Bronsted - Lowry base</strong>, like you are here, you will be solving for the concentration of hydronium ions <em>indirectly</em>, i.e. by solving for the concentration of <em>hydroxide ions</em>, <mathjax>#"OH"^(-)#</mathjax>.</p> <p><em>Magnesium hydroxide</em>, <mathjax>#"Mg"("OH")_2#</mathjax>, us <strong>insoluble</strong> in aqueous solution. This means that when you place magnesium hydroxide in water, an <strong><a href="http://socratic.org/chemistry/chemical-equilibrium/dynamic-equilibrium">equilibrium</a></strong> will be established between the <em>undissolved solid</em> and the <em>dissolved ions</em>. </p> <blockquote> <p><mathjax>#"Mg"("OH")_text(2(s]) rightleftharpoons "Mg"_text((aq])^(2+) + color(red)(2)"OH"_text((aq])^(-)#</mathjax></p> </blockquote> <p>The <em>solubility product constant</em>, <mathjax>#K_(sp)#</mathjax>, for this equilibrium looks like this</p> <blockquote> <p><mathjax>#K_(sp) = ["Mg"^(2+)] * ["OH"^(-)]^color(red)(2)#</mathjax></p> </blockquote> <p>What you need to do here is use the <mathjax>#K_(sp)#</mathjax> to find the <strong>molar solubility</strong>, <mathjax>#s#</mathjax>, of magnesium hydroxide in aqueous solution at <mathjax>#25^@"C"#</mathjax>. </p> <p>To do that, set up an <strong>ICE table</strong></p> <blockquote> <p><mathjax>#" ""Mg"("OH")_text(2(s]) " "rightleftharpoons" " "Mg"_text((aq])^(2+) " "+" " color(red)(2)"OH"_text((aq])^(-)#</mathjax></p> </blockquote> <p><mathjax>#color(purple)("I")" " " " " "-" " " " " " " " " " " " " "0" " " " " " " " " " 0#</mathjax><br/> <mathjax>#color(purple)("C")" " " " " "-" " " " " " " " " " " "(+s)" " " " " "(+color(red)(2)s)#</mathjax><br/> <mathjax>#color(purple)("E")" " " " " "-" " " " " " " " " " " " " "s" " " " " " " " " "color(red)(2)s#</mathjax></p> <p>Remember, the concentration of the solid is assumed to be <strong>constant</strong>. </p> <p>Here <mathjax>#K_(sp)#</mathjax> will be equal to</p> <blockquote> <p><mathjax>#K_(sp) = s * (color(red)(2)s)^color(red)(2) = 4s^3#</mathjax> </p> </blockquote> <p>Rearrange to solve for <mathjax>#s#</mathjax></p> <blockquote> <p><mathjax>#s = root(3)(K_(sp)/4) = root(3)((1.8 * 10^(-11))/4) = 1.65 * 10^(-4)#</mathjax></p> </blockquote> <p>This means that the concentration of hydroxide ions in a <em>saturated</em> solution of magnesium hydroxide at <mathjax>#25^@"C"#</mathjax> will be </p> <blockquote> <p><mathjax>#["OH"^(-)] = color(red)(2) * 1.65 * 10^(-4)"M" = 3.30 * 10^(-4)"M"#</mathjax></p> </blockquote> <p>Now, at <mathjax>#25^@"C"#</mathjax>, the concentration of hydronium ions and the concentration of hydroxide ions have the following relationship</p> <blockquote> <p><mathjax>#color(blue)(K_W = ["H"_3"O"^(+)] * ["OH"^(-)] = 10^(-4))" "#</mathjax>, where</p> </blockquote> <p><mathjax>#K_W#</mathjax> - the <strong>ion product</strong> for water's auto-ionization</p> <p>Plug in your value to get</p> <blockquote> <p><mathjax>#["H"_3"O"^(+)] = 10^(-14)/(3.30 * 10^(-4)) = 3.03 * 10^(-11)"M"#</mathjax></p> </blockquote> <p>This means that the pH of the solution will be </p> <blockquote> <p><mathjax>#color(blue)("pH" = - log(["H"_3"O"^(+)]))#</mathjax></p> <p><mathjax>#"pH" = - log(3.03 * 10^(-11)) = color(green)(10.52)#</mathjax></p> </blockquote> <p><strong>Alternatively</strong>, you can use the equation</p> <blockquote> <p><mathjax>#color(blue)("pH " + " pOH" = 14)#</mathjax></p> </blockquote> <p>Here </p> <blockquote> <p><mathjax>#color(blue)("pOH" = - log(["OH"^(-)]))#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the #"pH"# of a solution of magnesium hydroxide given that #K_(sp) = 1.8 * 10^(-11)# ?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/the-ph-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">pH</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="232489" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-02-28T13:06:54" itemprop="dateCreated"> Feb 28, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"pH" = 10.52#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to find the <a href="http://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> of a solution, you must determine the concentration of <em>hydronium ions</em>, <mathjax>#"H"_3"O"^(+)#</mathjax>, either <em>directly</em> or <em>indirectly</em>. </p> <p>When you're dealing with a <strong>Bronsted - Lowry acid</strong>, you will be solving for the concentration of hydronium ions <em>directly</em>. </p> <p>When you're dealing with a <strong>Bronsted - Lowry base</strong>, like you are here, you will be solving for the concentration of hydronium ions <em>indirectly</em>, i.e. by solving for the concentration of <em>hydroxide ions</em>, <mathjax>#"OH"^(-)#</mathjax>.</p> <p><em>Magnesium hydroxide</em>, <mathjax>#"Mg"("OH")_2#</mathjax>, us <strong>insoluble</strong> in aqueous solution. This means that when you place magnesium hydroxide in water, an <strong><a href="http://socratic.org/chemistry/chemical-equilibrium/dynamic-equilibrium">equilibrium</a></strong> will be established between the <em>undissolved solid</em> and the <em>dissolved ions</em>. </p> <blockquote> <p><mathjax>#"Mg"("OH")_text(2(s]) rightleftharpoons "Mg"_text((aq])^(2+) + color(red)(2)"OH"_text((aq])^(-)#</mathjax></p> </blockquote> <p>The <em>solubility product constant</em>, <mathjax>#K_(sp)#</mathjax>, for this equilibrium looks like this</p> <blockquote> <p><mathjax>#K_(sp) = ["Mg"^(2+)] * ["OH"^(-)]^color(red)(2)#</mathjax></p> </blockquote> <p>What you need to do here is use the <mathjax>#K_(sp)#</mathjax> to find the <strong>molar solubility</strong>, <mathjax>#s#</mathjax>, of magnesium hydroxide in aqueous solution at <mathjax>#25^@"C"#</mathjax>. </p> <p>To do that, set up an <strong>ICE table</strong></p> <blockquote> <p><mathjax>#" ""Mg"("OH")_text(2(s]) " "rightleftharpoons" " "Mg"_text((aq])^(2+) " "+" " color(red)(2)"OH"_text((aq])^(-)#</mathjax></p> </blockquote> <p><mathjax>#color(purple)("I")" " " " " "-" " " " " " " " " " " " " "0" " " " " " " " " " 0#</mathjax><br/> <mathjax>#color(purple)("C")" " " " " "-" " " " " " " " " " " "(+s)" " " " " "(+color(red)(2)s)#</mathjax><br/> <mathjax>#color(purple)("E")" " " " " "-" " " " " " " " " " " " " "s" " " " " " " " " "color(red)(2)s#</mathjax></p> <p>Remember, the concentration of the solid is assumed to be <strong>constant</strong>. </p> <p>Here <mathjax>#K_(sp)#</mathjax> will be equal to</p> <blockquote> <p><mathjax>#K_(sp) = s * (color(red)(2)s)^color(red)(2) = 4s^3#</mathjax> </p> </blockquote> <p>Rearrange to solve for <mathjax>#s#</mathjax></p> <blockquote> <p><mathjax>#s = root(3)(K_(sp)/4) = root(3)((1.8 * 10^(-11))/4) = 1.65 * 10^(-4)#</mathjax></p> </blockquote> <p>This means that the concentration of hydroxide ions in a <em>saturated</em> solution of magnesium hydroxide at <mathjax>#25^@"C"#</mathjax> will be </p> <blockquote> <p><mathjax>#["OH"^(-)] = color(red)(2) * 1.65 * 10^(-4)"M" = 3.30 * 10^(-4)"M"#</mathjax></p> </blockquote> <p>Now, at <mathjax>#25^@"C"#</mathjax>, the concentration of hydronium ions and the concentration of hydroxide ions have the following relationship</p> <blockquote> <p><mathjax>#color(blue)(K_W = ["H"_3"O"^(+)] * ["OH"^(-)] = 10^(-4))" "#</mathjax>, where</p> </blockquote> <p><mathjax>#K_W#</mathjax> - the <strong>ion product</strong> for water's auto-ionization</p> <p>Plug in your value to get</p> <blockquote> <p><mathjax>#["H"_3"O"^(+)] = 10^(-14)/(3.30 * 10^(-4)) = 3.03 * 10^(-11)"M"#</mathjax></p> </blockquote> <p>This means that the pH of the solution will be </p> <blockquote> <p><mathjax>#color(blue)("pH" = - log(["H"_3"O"^(+)]))#</mathjax></p> <p><mathjax>#"pH" = - log(3.03 * 10^(-11)) = color(green)(10.52)#</mathjax></p> </blockquote> <p><strong>Alternatively</strong>, you can use the equation</p> <blockquote> <p><mathjax>#color(blue)("pH " + " pOH" = 14)#</mathjax></p> </blockquote> <p>Here </p> <blockquote> <p><mathjax>#color(blue)("pOH" = - log(["OH"^(-)]))#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/232489" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-pka"> How do you determine pH from pKa? 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921	a9a8e8b6-6ddd-11ea-9d0e-ccda262736ce	https://socratic.org/questions/if-something-is-made-of-1-05-g-ni3-and-0-58-g-o-what-is-the-empirical-formula	NiO2	start chemical_formula qc_end physical_unit 7 7 5 6 mass qc_end physical_unit 11 11 9 10 mass qc_end end	[{"type":"other","value":"Chemical Formula [OF] the substance [IN] empirical"}]	[{"type":"chemical equation","value":"NiO2"}]	[{"type":"physical unit","value":"Mass [OF] Ni [=] \\pu{1.05 g}"},{"type":"physical unit","value":"Mass [OF] O [=] \\pu{0.58 g}"}]	<h1 class="questionTitle" itemprop="name">If something is made of 1.05 g #"Ni"# and 0.58 g #"O"#, what is the empirical formula? </h1>	null	NiO2	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The empirical formula of a compound is the lowest whole number ratio of the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> in the compound. These whole numbers are the subscripts. </p> <p>To determine an empirical formula, convert the given mass to moles. Then divide the number of moles of each element by the lowest number of moles. If you get whole numbers, those are the lowest whole number ratio. If you don't get whole numbers, you will need to multiply by a number that will give whole numbers.</p> <p>Moles</p> <p>Determine the moles of each element by dividing its given mass by its molar mass. The molar mass of each element is its atomic weight on <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a> in g/mol. Since molar mass is a fraction, <mathjax>#"g"/"mol"#</mathjax>, multiply the given mass of each element by the inverse of its molar mass.</p> <p><mathjax>#"Ni:"#</mathjax> <mathjax>#1.05color(red)cancel(color(black)("g Ni"))xx(1"mol Ni")/(58.6934color(red)cancel(color(black)("g Ni")))="0.0179 mol Ni"#</mathjax></p> <p><mathjax>#"O:"#</mathjax> <mathjax>#0.58color(red)cancel(color(black)("g O"))xx(1"mol O")/(15.999color(red)cancel(color(black)("g O")))="0.036 mol O"#</mathjax></p> <p><a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">Mole Ratios</a></p> <p>Determine <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio between the two elements by dividing the mol of each element by the lowest number of moles.</p> <p><mathjax>#"Ni:"#</mathjax> <mathjax>#(0.0179color(red)cancel(color(black)("mol")))/(0.0179color(red)cancel(color(black)("mol")))=1.00#</mathjax></p> <p><mathjax>#"O:"#</mathjax> <mathjax>#(0.036color(red)cancel(color(black)("mol")))/(0.0179color(red)cancel(color(black)("mol")))=2.0#</mathjax></p> <p>The empirical formula is <mathjax>#"NiO"_2#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The empirical formula is <mathjax>#"NiO"_2#</mathjax>, which is nickel(IV) oxide.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The empirical formula of a compound is the lowest whole number ratio of the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> in the compound. These whole numbers are the subscripts. </p> <p>To determine an empirical formula, convert the given mass to moles. Then divide the number of moles of each element by the lowest number of moles. If you get whole numbers, those are the lowest whole number ratio. If you don't get whole numbers, you will need to multiply by a number that will give whole numbers.</p> <p>Moles</p> <p>Determine the moles of each element by dividing its given mass by its molar mass. The molar mass of each element is its atomic weight on <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a> in g/mol. Since molar mass is a fraction, <mathjax>#"g"/"mol"#</mathjax>, multiply the given mass of each element by the inverse of its molar mass.</p> <p><mathjax>#"Ni:"#</mathjax> <mathjax>#1.05color(red)cancel(color(black)("g Ni"))xx(1"mol Ni")/(58.6934color(red)cancel(color(black)("g Ni")))="0.0179 mol Ni"#</mathjax></p> <p><mathjax>#"O:"#</mathjax> <mathjax>#0.58color(red)cancel(color(black)("g O"))xx(1"mol O")/(15.999color(red)cancel(color(black)("g O")))="0.036 mol O"#</mathjax></p> <p><a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">Mole Ratios</a></p> <p>Determine <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio between the two elements by dividing the mol of each element by the lowest number of moles.</p> <p><mathjax>#"Ni:"#</mathjax> <mathjax>#(0.0179color(red)cancel(color(black)("mol")))/(0.0179color(red)cancel(color(black)("mol")))=1.00#</mathjax></p> <p><mathjax>#"O:"#</mathjax> <mathjax>#(0.036color(red)cancel(color(black)("mol")))/(0.0179color(red)cancel(color(black)("mol")))=2.0#</mathjax></p> <p>The empirical formula is <mathjax>#"NiO"_2#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">If something is made of 1.05 g #"Ni"# and 0.58 g #"O"#, what is the empirical formula? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="465997" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-20T03:45:58" itemprop="dateCreated"> Aug 20, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The empirical formula is <mathjax>#"NiO"_2#</mathjax>, which is nickel(IV) oxide.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The empirical formula of a compound is the lowest whole number ratio of the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> in the compound. These whole numbers are the subscripts. </p> <p>To determine an empirical formula, convert the given mass to moles. Then divide the number of moles of each element by the lowest number of moles. If you get whole numbers, those are the lowest whole number ratio. If you don't get whole numbers, you will need to multiply by a number that will give whole numbers.</p> <p>Moles</p> <p>Determine the moles of each element by dividing its given mass by its molar mass. The molar mass of each element is its atomic weight on <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a> in g/mol. Since molar mass is a fraction, <mathjax>#"g"/"mol"#</mathjax>, multiply the given mass of each element by the inverse of its molar mass.</p> <p><mathjax>#"Ni:"#</mathjax> <mathjax>#1.05color(red)cancel(color(black)("g Ni"))xx(1"mol Ni")/(58.6934color(red)cancel(color(black)("g Ni")))="0.0179 mol Ni"#</mathjax></p> <p><mathjax>#"O:"#</mathjax> <mathjax>#0.58color(red)cancel(color(black)("g O"))xx(1"mol O")/(15.999color(red)cancel(color(black)("g O")))="0.036 mol O"#</mathjax></p> <p><a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">Mole Ratios</a></p> <p>Determine <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio between the two elements by dividing the mol of each element by the lowest number of moles.</p> <p><mathjax>#"Ni:"#</mathjax> <mathjax>#(0.0179color(red)cancel(color(black)("mol")))/(0.0179color(red)cancel(color(black)("mol")))=1.00#</mathjax></p> <p><mathjax>#"O:"#</mathjax> <mathjax>#(0.036color(red)cancel(color(black)("mol")))/(0.0179color(red)cancel(color(black)("mol")))=2.0#</mathjax></p> <p>The empirical formula is <mathjax>#"NiO"_2#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/465997" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molecular-formula-of-a-compound"> How do you find molecular formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-diamond"> What is the chemical formula of a diamond? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-carbohydrate"> What is the chemical formula of a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-valproic-acid"> What is the empirical formula for valproic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-of-magnesium-oxide"> What is the empirical formula of magnesium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-empirical-formula-not-double-that-of-the-monosaccharides"> Why is the empirical formula not double that of the monosaccharides? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5331180502bf342f40b5c3b5"> Question #5c3b5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-molecular-formula-represents-a-carbohydrate"> What molecular formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-of-vinegar"> What is the molecular formula of vinegar? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/empirical-and-molecular-formulas"> See all questions in Empirical and Molecular Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 4421 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	If something is made of 1.05 g #"Ni"# and 0.58 g #"O"#, what is the empirical formula?	null
922	ab026563-6ddd-11ea-8701-ccda262736ce	https://socratic.org/questions/what-is-the-neutralization-reaction-between-sulfuric-acid-and-lithium-hydroxide	H2SO4(aq) + 2 LiOH(aq) -> LiSO4(aq) + 2 H2O(aq)	start chemical_equation qc_end substance 6 7 qc_end substance 9 10 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the neutralization reaction"}]	[{"type":"chemical equation","value":"H2SO4(aq) + 2 LiOH(aq) -> LiSO4(aq) + 2 H2O(aq)"}]	[{"type":"substance name","value":"Sulfuric acid"},{"type":"substance name","value":"Lithium hydroxide"}]	<h1 class="questionTitle" itemprop="name">What is the neutralization reaction between sulfuric acid and lithium hydroxide? </h1>	null	H2SO4(aq) + 2 LiOH(aq) -> LiSO4(aq) + 2 H2O(aq)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Is the given reaction stoichiometrically balanced? Two equiv lithium hydroxide reacts with one equiv sulfuric acid. If it had been barium hydroxide (and barium sulfate is sparingly soluble), how would you modify the equation?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#H_2SO_4(aq) + 2LiOH(aq) rarr Li_2SO_4(aq) + 2H_2O(aq)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Is the given reaction stoichiometrically balanced? Two equiv lithium hydroxide reacts with one equiv sulfuric acid. If it had been barium hydroxide (and barium sulfate is sparingly soluble), how would you modify the equation?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the neutralization reaction between sulfuric acid and lithium hydroxide? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#reactions-in-solution" itemprop="url"> <span class="breadcrumb" itemprop="title">Reactions in Solution</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/reactions-in-solution/neutralization" itemprop="url"> <span class="breadcrumb" itemprop="title">Neutralization</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="287561" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-12T20:04:37" itemprop="dateCreated"> Jul 12, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#H_2SO_4(aq) + 2LiOH(aq) rarr Li_2SO_4(aq) + 2H_2O(aq)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Is the given reaction stoichiometrically balanced? Two equiv lithium hydroxide reacts with one equiv sulfuric acid. If it had been barium hydroxide (and barium sulfate is sparingly soluble), how would you modify the equation?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/287561" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-neutralization-reactions-useful"> How are neutralization reactions useful? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-neutralization-reactions-be-identified-symbolically"> How can neutralization reactions be identified symbolically? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-neutralization-reaction-differ-from-buffer"> How does neutralization reaction differ from using a buffer? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-do-acid-base-neutralization-reactions"> How do you do acid base neutralization reactions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-neutralization-reactions-produce-heat"> Why do neutralization reactions produce heat? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-neutralization-a-double-replacement-reaction"> Why is neutralization a double replacement reaction? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-a-neutralization-reaction-exothermic"> Why is a neutralization reaction exothermic? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-predict-and-balance-acid-base-reactions"> How do you predict the products in acid-base reactions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-you-determine-the-strength-of-sulfuric-acid"> How can you determine the strength of sulfuric acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-a-neutralisation-reaction-exothermic"> Why is a neutralisation reaction exothermic? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/reactions-in-solution/neutralization"> See all questions in Neutralization </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 23375 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the neutralization reaction between sulfuric acid and lithium hydroxide?	null
923	a96d34ae-6ddd-11ea-917b-ccda262736ce	https://socratic.org/questions/a-sample-of-nitrogen-gas-is-collected-over-water-at-a-temperature-of-23-0-c-what	763.8 mmHg	start physical_unit 3 4 pressure mmhg qc_end physical_unit 1 4 13 14 temperature qc_end end	[{"type":"physical unit","value":"Pressure [OF] nitrogen gas [IN] mmHg"}]	[{"type":"physical unit","value":"763.8 mmHg"}]	[{"type":"physical unit","value":"Pressure [OF] atmosphere [=] \\pu{785 mmHg}"},{"type":"physical unit","value":"Temperature [OF] nitrogen gas sample [=] \\pu{23.0 ℃}"}]	<h1 class="questionTitle" itemprop="name">A sample of nitrogen gas is collected over water at a temperature of 23.0°C. What is the pressure of nitrogen gas if atmospheric pressure is 785 mm Hg?</h1>	null	763.8 mmHg	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Gas collected over water must always account for the saturated vapour pressure. I have included a link to a Table, but in an exam these data would be supplied.</p> <p>Thus <mathjax>#"atmospheric pressure"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#P_"SVP" + P_"dinitrogen"#</mathjax></p> <p><mathjax>#P_"dinitrogen"=(785-21.1)mmHg#</mathjax> <mathjax>#=#</mathjax> <mathjax>#763.8mmHg#</mathjax>.</p> <p>Note that when a gas is collecgted over water, we must always include <mathjax>#P_"SVP"#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The <a href="http://www.wiredchemist.com/chemistry/data/vapor-pressure" rel="nofollow">saturated vapour pressure of water at</a> <mathjax>#23#</mathjax> <mathjax>#""^@C#</mathjax> is 21.1 mm Hg.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Gas collected over water must always account for the saturated vapour pressure. I have included a link to a Table, but in an exam these data would be supplied.</p> <p>Thus <mathjax>#"atmospheric pressure"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#P_"SVP" + P_"dinitrogen"#</mathjax></p> <p><mathjax>#P_"dinitrogen"=(785-21.1)mmHg#</mathjax> <mathjax>#=#</mathjax> <mathjax>#763.8mmHg#</mathjax>.</p> <p>Note that when a gas is collecgted over water, we must always include <mathjax>#P_"SVP"#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A sample of nitrogen gas is collected over water at a temperature of 23.0°C. What is the pressure of nitrogen gas if atmospheric pressure is 785 mm Hg?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/ideal-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Ideal Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="294859" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-08-02T18:25:10" itemprop="dateCreated"> Aug 2, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The <a href="http://www.wiredchemist.com/chemistry/data/vapor-pressure" rel="nofollow">saturated vapour pressure of water at</a> <mathjax>#23#</mathjax> <mathjax>#""^@C#</mathjax> is 21.1 mm Hg.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Gas collected over water must always account for the saturated vapour pressure. I have included a link to a Table, but in an exam these data would be supplied.</p> <p>Thus <mathjax>#"atmospheric pressure"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#P_"SVP" + P_"dinitrogen"#</mathjax></p> <p><mathjax>#P_"dinitrogen"=(785-21.1)mmHg#</mathjax> <mathjax>#=#</mathjax> <mathjax>#763.8mmHg#</mathjax>.</p> <p>Note that when a gas is collecgted over water, we must always include <mathjax>#P_"SVP"#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/294859" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-ideal-gas-constant"> How do you find the ideal gas constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-solve-ideal-gas-law-problems"> How do you solve ideal gas law problems? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-know-which-ideal-gas-constant-to-use"> How do you know which ideal gas constant to use? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ideal-gas-constant-for-butane"> What is the ideal gas constant for butane? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-ideal-gas-law-in-kelvin"> Why is ideal gas law in kelvin? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ideal-gas-constant-important"> Why is the ideal gas constant important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-di-electric-constant"> What is the di-electric constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-volume-l-will-0-20-mol-hi-occupy-at-300-k-and-100-0-kpa-r-8-314-kpa-l-k-mol"> What volume (L) will 0.20 mol HI occupy at 300 K and 100.0 kPa? R = 8.314 kPa L / (K mol) =... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-molar-mass-of-a-gas"> How do you calculate the molar mass of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-should-i-use-the-ideal-gas-law-and-not-the-combined-gas-law"> When should I use the ideal gas law and not the combined gas law? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/ideal-gas-law"> See all questions in Ideal Gas Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 42795 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A sample of nitrogen gas is collected over water at a temperature of 23.0°C. What is the pressure of nitrogen gas if atmospheric pressure is 785 mm Hg?	null
924	acff3714-6ddd-11ea-9235-ccda262736ce	https://socratic.org/questions/two-hundred-liters-of-gas-at-zero-degrees-celsius-are-kept-under-a-pressure-of-1	200.00 L	start physical_unit 20 21 volume l qc_end physical_unit 20 21 15 16 pressure qc_end physical_unit 20 21 25 27 temperature qc_end physical_unit 20 21 34 35 pressure qc_end end	[{"type":"physical unit","value":"Volume2 [OF] the gas [IN] L"}]	[{"type":"physical unit","value":"200.00 L"}]	[{"type":"physical unit","value":"Volume1 [OF] the gas [=] \\pu{200 liters}"},{"type":"physical unit","value":"Temperature1 [OF] the gas [=] \\pu{0 degrees Celsius}"},{"type":"physical unit","value":"Pressure1 [OF] the gas [=] \\pu{150 kPa}"},{"type":"physical unit","value":"Temperature2 [OF] the gas [=] \\pu{273 degrees Celsius}"},{"type":"physical unit","value":"Pressure2 [OF] the gas [=] \\pu{600 kPa}"}]	<h1 class="questionTitle" itemprop="name">Two hundred liters of gas at zero degrees Celsius are kept under a pressure of 150 kPa. The temperature of the gas is raised to 273 degrees Celsius and the pressure is increased to 600 kPa. What is the new volume? </h1>	null	200.00 L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>...according to the combined gas equation...</p> <p>We solve for....<mathjax>#V_2=(P_1V_1)/T_1xxT_2/P_2#</mathjax></p> <p><mathjax>#=(150kPaxx200L)/(273K)xx(546K)/(600kPa)=??L#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, <mathjax>#(P_1V_1)/T_1=(P_2V_2)/T_2#</mathjax>...temperature is specified to be absolute...<mathjax>#0K=-273.15K#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>...according to the combined gas equation...</p> <p>We solve for....<mathjax>#V_2=(P_1V_1)/T_1xxT_2/P_2#</mathjax></p> <p><mathjax>#=(150kPaxx200L)/(273K)xx(546K)/(600kPa)=??L#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Two hundred liters of gas at zero degrees Celsius are kept under a pressure of 150 kPa. The temperature of the gas is raised to 273 degrees Celsius and the pressure is increased to 600 kPa. What is the new volume? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/gas-laws" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Laws</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="619035" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-05-23T20:58:01" itemprop="dateCreated"> May 23, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, <mathjax>#(P_1V_1)/T_1=(P_2V_2)/T_2#</mathjax>...temperature is specified to be absolute...<mathjax>#0K=-273.15K#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>...according to the combined gas equation...</p> <p>We solve for....<mathjax>#V_2=(P_1V_1)/T_1xxT_2/P_2#</mathjax></p> <p><mathjax>#=(150kPaxx200L)/(273K)xx(546K)/(600kPa)=??L#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/619035" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-boyles-law-relate-to-breathing"> How does Boyle's law relate to breathing? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/in-avogadro-s-law-what-would-happen-to-v-if-n-is-increased-decreased-and-what-wo"> In Avogadro's Law what would happen to V if N is increased/decreased? 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If the gas is compressed to 23.52 L and the... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-the-r-stand-for-in-the-ideal-gas-law-pv-nrt"> What does the R stand for in the ideal gas law (PV=nRT)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-mass-of-a-gas-that-occupies-48-9-liters-has-a-pressure-of-724-torr-a"> What is the mass of a gas that occupies 48.9 liters, has a pressure of 724 torr, a temperature... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-a-sample-of-neon-gas-occupies-a-volume-of-2-8l-at-1-8-atm-what-will-its-volum"> If a sample of neon gas occupies a volume of 2.8L at 1.8 atm. what will its volume be at 1.2 atm? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/gas-laws"> See all questions in Gas Laws </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3825 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Two hundred liters of gas at zero degrees Celsius are kept under a pressure of 150 kPa. The temperature of the gas is raised to 273 degrees Celsius and the pressure is increased to 600 kPa. What is the new volume?	null
925	a9739d50-6ddd-11ea-a001-ccda262736ce	https://socratic.org/questions/how-do-you-determine-the-ph-of-a-0-125-m-solution-of-nitric-acid	0.90	start physical_unit 10 10 ph none qc_end physical_unit 12 13 8 9 molarity qc_end end	[{"type":"physical unit","value":"pH [OF] nitric acid solution"}]	[{"type":"physical unit","value":"0.90"}]	[{"type":"physical unit","value":"Molarity [OF] nitric acid solution [=] \\pu{0.125 M}"}]	<h1 class="questionTitle" itemprop="name">How do you determine the pH of a 0.125 M solution of nitric acid?</h1>	null	0.90	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Nitric acid (<mathjax>#HNO_3#</mathjax>) is a strong acid (we refer to it as a mineral acid as opposed to carbon-containing organic acids which are mostly weak). This means that we assume it dissociates completely in solution. Therefore, since is it also monoprotic (it provides one mole of hydrogen ions per mole of acid), the concentration of hydrogen ions in solution equals the concentration of the acid i.e. 0.125M.</p> <p>Now we simply use the equation that defines pH, thus:</p> <p>pH = -lg<mathjax>#[H^+]#</mathjax> = -lg0.125 = 0.903 (to 3s.f.)</p> <p>NB 'lg' denotes logarithm to base 10.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>This is an easy one <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a>=-lg 0.125 = 0.903</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Nitric acid (<mathjax>#HNO_3#</mathjax>) is a strong acid (we refer to it as a mineral acid as opposed to carbon-containing organic acids which are mostly weak). This means that we assume it dissociates completely in solution. Therefore, since is it also monoprotic (it provides one mole of hydrogen ions per mole of acid), the concentration of hydrogen ions in solution equals the concentration of the acid i.e. 0.125M.</p> <p>Now we simply use the equation that defines pH, thus:</p> <p>pH = -lg<mathjax>#[H^+]#</mathjax> = -lg0.125 = 0.903 (to 3s.f.)</p> <p>NB 'lg' denotes logarithm to base 10.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you determine the pH of a 0.125 M solution of nitric acid?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/the-ph-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">pH</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="384309" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/b-m-1"><img alt="" class="" src="https://lh3.googleusercontent.com/-XdUIqdMkCWA/AAAAAAAAAAI/AAAAAAAAAAA/4252rscbv5M/photo.jpg?sz=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/b-m-1"> B M. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-02-28T14:18:21" itemprop="dateCreated"> Feb 28, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>This is an easy one <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a>=-lg 0.125 = 0.903</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Nitric acid (<mathjax>#HNO_3#</mathjax>) is a strong acid (we refer to it as a mineral acid as opposed to carbon-containing organic acids which are mostly weak). This means that we assume it dissociates completely in solution. Therefore, since is it also monoprotic (it provides one mole of hydrogen ions per mole of acid), the concentration of hydrogen ions in solution equals the concentration of the acid i.e. 0.125M.</p> <p>Now we simply use the equation that defines pH, thus:</p> <p>pH = -lg<mathjax>#[H^+]#</mathjax> = -lg0.125 = 0.903 (to 3s.f.)</p> <p>NB 'lg' denotes logarithm to base 10.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/384309" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-pka"> How do you determine pH from pKa? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-ph-values-of-acids-and-bases-differ"> How do pH values of acids and bases differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-something-on-a-ph-scale"> How do you calculate something on a pH scale? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-diprotic-acid"> How do you calculate pH diprotic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-from-acid-dissociation-constant"> How do you calculate pH from acid dissociation constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-of-acid-and-base-solution"> How do you calculate pH of acid and base solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ph-scale-0-14"> Why is the pH scale 0-14? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-ph-the-measure-of-the-hydrogen-ion-concentration"> Is pH a measure of the hydrogen ion concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-solubility-affect-ph"> How does solubility affect pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-ph-relate-to-pka-in-a-titration"> How does pH relate to pKa in a titration? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/the-ph-concept"> See all questions in pH </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 57399 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How do you determine the pH of a 0.125 M solution of nitric acid?	null
926	aaa2c1dc-6ddd-11ea-92b6-ccda262736ce	https://socratic.org/questions/a-93ml-sample-of-dry-air-cools-from-144-c-to-22-c-while-the-pressure-is-maintain	55.98 mL	start physical_unit 3 6 volume ml qc_end physical_unit 3 6 1 2 volume qc_end physical_unit 3 6 9 10 temperature qc_end physical_unit 3 6 12 13 temperature qc_end physical_unit 3 6 20 21 pressure qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Volume2 [OF] the dry air sample [IN] mL"}]	[{"type":"physical unit","value":"55.98 mL"}]	[{"type":"physical unit","value":"Volume1 [OF] the dry air sample [=] \\pu{93 mL}"},{"type":"physical unit","value":"Temperature1 [OF] the dry air sample [=] \\pu{144 ℃}"},{"type":"physical unit","value":"Temperature2 [OF] the dry air sample [=] \\pu{-22 ℃}"},{"type":"physical unit","value":"Pressure [OF] the dry air sample [=] \\pu{2.85 atm}"},{"type":"other","value":"Constant pressure."}]	<h1 class="questionTitle" itemprop="name">A 93mL sample of dry air cools from 144°C to -22°C while the pressure is maintained at 2.85 atm. What is the final volume? </h1>	null	55.98 mL	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is an example of <a href="https://socratic.org/chemistry/the-behavior-of-gases/charles-law">Charles' law</a>, which states that the volume of a given amount of gas held at constant pressure is directly proportional to the <strong>Kelvin temperature</strong> . This means that if the volume increases, so does the temperature, and vice versa. The formula for this law is:</p> <p><mathjax>#V_1/T_1=V_2/T_2#</mathjax>,</p> <p>where:</p> <p><mathjax>#V_1#</mathjax> is the initial volume, <mathjax>#V_2#</mathjax> is the final volume, <mathjax>#T_1#</mathjax> is the initial temperature, and <mathjax>#T_2#</mathjax> is the final temperature.</p> <p><strong>Organize the data:</strong></p> <p><strong>Known</strong></p> <p><mathjax>#V_1="93 mL"#</mathjax></p> <p><mathjax>#T_1="144"^@"C + 273.15"="417 K"#</mathjax> <mathjax>#larr#</mathjax> Temp must be in Kelvins.</p> <p><mathjax>#T_2=-22^@"C + 273.15"="251 K"#</mathjax> <mathjax>#larr#</mathjax> Temp must be in Kelvins.</p> <p><strong>Unknown</strong></p> <p><mathjax>#V_2#</mathjax></p> <p><strong>Solution</strong></p> <p>Rearrange the formula to isolate <mathjax>#V_2#</mathjax>. Plug in the known values and solve.</p> <p><mathjax>#V_2=(V_1T_2)/T_1#</mathjax></p> <p><mathjax>#((93"mL")xx(251color(red)cancel(color(black)("K"))))/(417color(red)cancel(color(black)("K")))="56 mL"#</mathjax> (rounded to two significant figures)</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The final volume will be <mathjax>#"56 mL"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is an example of <a href="https://socratic.org/chemistry/the-behavior-of-gases/charles-law">Charles' law</a>, which states that the volume of a given amount of gas held at constant pressure is directly proportional to the <strong>Kelvin temperature</strong> . This means that if the volume increases, so does the temperature, and vice versa. The formula for this law is:</p> <p><mathjax>#V_1/T_1=V_2/T_2#</mathjax>,</p> <p>where:</p> <p><mathjax>#V_1#</mathjax> is the initial volume, <mathjax>#V_2#</mathjax> is the final volume, <mathjax>#T_1#</mathjax> is the initial temperature, and <mathjax>#T_2#</mathjax> is the final temperature.</p> <p><strong>Organize the data:</strong></p> <p><strong>Known</strong></p> <p><mathjax>#V_1="93 mL"#</mathjax></p> <p><mathjax>#T_1="144"^@"C + 273.15"="417 K"#</mathjax> <mathjax>#larr#</mathjax> Temp must be in Kelvins.</p> <p><mathjax>#T_2=-22^@"C + 273.15"="251 K"#</mathjax> <mathjax>#larr#</mathjax> Temp must be in Kelvins.</p> <p><strong>Unknown</strong></p> <p><mathjax>#V_2#</mathjax></p> <p><strong>Solution</strong></p> <p>Rearrange the formula to isolate <mathjax>#V_2#</mathjax>. Plug in the known values and solve.</p> <p><mathjax>#V_2=(V_1T_2)/T_1#</mathjax></p> <p><mathjax>#((93"mL")xx(251color(red)cancel(color(black)("K"))))/(417color(red)cancel(color(black)("K")))="56 mL"#</mathjax> (rounded to two significant figures)</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A 93mL sample of dry air cools from 144°C to -22°C while the pressure is maintained at 2.85 atm. What is the final volume? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp" itemprop="url"> <span class="breadcrumb" itemprop="title">Molar Volume of a Gas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="586947" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-04-02T16:44:44" itemprop="dateCreated"> Apr 2, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The final volume will be <mathjax>#"56 mL"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is an example of <a href="https://socratic.org/chemistry/the-behavior-of-gases/charles-law">Charles' law</a>, which states that the volume of a given amount of gas held at constant pressure is directly proportional to the <strong>Kelvin temperature</strong> . This means that if the volume increases, so does the temperature, and vice versa. The formula for this law is:</p> <p><mathjax>#V_1/T_1=V_2/T_2#</mathjax>,</p> <p>where:</p> <p><mathjax>#V_1#</mathjax> is the initial volume, <mathjax>#V_2#</mathjax> is the final volume, <mathjax>#T_1#</mathjax> is the initial temperature, and <mathjax>#T_2#</mathjax> is the final temperature.</p> <p><strong>Organize the data:</strong></p> <p><strong>Known</strong></p> <p><mathjax>#V_1="93 mL"#</mathjax></p> <p><mathjax>#T_1="144"^@"C + 273.15"="417 K"#</mathjax> <mathjax>#larr#</mathjax> Temp must be in Kelvins.</p> <p><mathjax>#T_2=-22^@"C + 273.15"="251 K"#</mathjax> <mathjax>#larr#</mathjax> Temp must be in Kelvins.</p> <p><strong>Unknown</strong></p> <p><mathjax>#V_2#</mathjax></p> <p><strong>Solution</strong></p> <p>Rearrange the formula to isolate <mathjax>#V_2#</mathjax>. Plug in the known values and solve.</p> <p><mathjax>#V_2=(V_1T_2)/T_1#</mathjax></p> <p><mathjax>#((93"mL")xx(251color(red)cancel(color(black)("K"))))/(417color(red)cancel(color(black)("K")))="56 mL"#</mathjax> (rounded to two significant figures)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/586947" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-stoichiometric-ratios-relate-to-molar-volume-of-a-gas"> How do stoichiometric ratios relate to molar volume of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-a-gas-at-stp"> How do you calculate molar volume of a gas at STP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-molar-volume-of-hydrogen-gas"> How do you find the molar volume of hydrogen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-oxygen-gas"> How do you calculate molar volume of oxygen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molar-gas-volume"> What is molar gas volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/534c7bf202bf3420a007f014"> What is the volume at 0 °C and 1 atm of a mixture that contains 4.0 g of methane and 2.0 g of helium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5361f75702bf3429040e0599"> What is the difference between STP and NTP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-volume-of-25-moles-of-oxygen-o2-gas"> What is the volume of .25 moles of oxygen (O2) Gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-would-knowing-the-molar-volume-of-a-gas-be-important"> Why would knowing the molar volume of a gas be important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-22-4-liters-called-the-molar-volume-of-a-gas"> Why is 22.4 liters called the molar volume of a gas? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp"> See all questions in Molar Volume of a Gas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 14679 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A 93mL sample of dry air cools from 144°C to -22°C while the pressure is maintained at 2.85 atm. What is the final volume?	null
927	ac86abd8-6ddd-11ea-b49e-ccda262736ce	https://socratic.org/questions/if-a-sample-of-chloroform-is-initially-at-25-c-what-is-its-final-temperature-if-	31.94 ℃	start physical_unit 2 4 temperature °c qc_end physical_unit 2 4 8 9 temperature qc_end physical_unit 2 4 16 17 mass qc_end physical_unit 2 4 21 22 heat_energy qc_end physical_unit 2 4 32 35 specific_heat qc_end end	[{"type":"physical unit","value":"Temperature2 [OF] chloroform sample [IN] ℃"}]	[{"type":"physical unit","value":"31.94 ℃"}]	[{"type":"physical unit","value":"Temperature1 [OF] chloroform sample [=] \\pu{25 ℃}"},{"type":"physical unit","value":"Mass [OF] chloroform sample [=] \\pu{150.0 g}"},{"type":"physical unit","value":"Absorbed heat [OF] chloroform sample [=] \\pu{1.0 kilojoules}"},{"type":"physical unit","value":"Specific heat [OF] chloroform sample [=] \\pu{0.96 J/(g * ℃)}"}]	<h1 class="questionTitle" itemprop="name">If a sample of chloroform is initially at 25°C, what is its final temperature of 150.0 g of chloroform absorbs 1.0 kilojoules of heat, and the specific heat of chloroform is 0.96 J/g°C?</h1>	null	31.94 ℃	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>!! SHORT ANSWER !! </strong></p> <p>This problem is a pretty straightforward application of the equation</p> <blockquote> <p><mathjax>#color(blue)(q = m * c * DeltaT)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#q#</mathjax> - the amount of heat added / removed<br/> <mathjax>#m#</mathjax> - the mass of the sample<br/> <mathjax>#c#</mathjax> - the <a href="http://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> of the substance<br/> <mathjax>#DeltaT#</mathjax> - the change in temperature, calculated as the difference between the <em>final temperature</em> and the <em>initial temperature</em></p> <p>All you'd have to do here is rearrange this equation to solve for <mathjax>#DeltaT#</mathjax> and plug in your values - <strong>do not</strong> forget to convert the heat from <em>kilojoules</em> to <em>joules</em></p> <blockquote> <p><mathjax>#DeltaT = q/(m * c)#</mathjax></p> <p><mathjax>#DeltaT = (1.0 * 10^3 color(red)(cancel(color(black)("J"))))/(150.0 color(red)(cancel(color(black)("g"))) * 0.96color(red)(cancel(color(black)("J")))/(color(red)(cancel(color(black)("g"))) * ""^@"C")) = 6.94^@"C"#</mathjax></p> </blockquote> <p>The final temperature of the sample will thus be </p> <blockquote> <p><mathjax>#T_"final" = T_"initial" + DeltaT#</mathjax></p> <p><mathjax>#T_"final" = 25^@"C" + 6.94^@"C"#</mathjax> </p> <p><mathjax>#T_"final" = color(green)(32^@"C") ->#</mathjax> <em>rounded to two <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></em></p> </blockquote> <p><strong>!! AN ALTERNATIVE APPROACH !!</strong></p> <p>I want to show you how to solve such questions <strong>without</strong> using that equation. </p> <p>As you know, a substance's <strong>specific heat</strong> tells you how much heat is needed in order to increase the temperature of <mathjax>#"1 g"#</mathjax> of that substance by <mathjax>#1^@"C"#</mathjax>. </p> <p>In your case, chloroform is said to have a specific heat of</p> <blockquote> <p><mathjax>#c = 0.96"J"/("g" ""^@"C")#</mathjax></p> </blockquote> <p><em>So, what does that tell you?</em></p> <p>In order to increase the temperature of <mathjax>#"1 g"#</mathjax> of chloroform by <mathjax>#1^@"C"#</mathjax>, you need to provide it with <mathjax>#"0.96 J"#</mathjax> of heat. </p> <p>Now look at the data given to you. Focus on the <em>mass</em> of the sample first. </p> <p>Now, if you need to provide <mathjax>#"0.96 J"#</mathjax> of heat in order to increase the temperature of <mathjax>#"1 g"#</mathjax> of chloroform by <mathjax>#1^@"C"#</mathjax>, how much heat will be needed in order to increase the temperature of <mathjax>#"150.0 g"#</mathjax> of chloroform by <mathjax>#1^@"C"#</mathjax>?</p> <p>Since you need <mathjax>#"0.96 J"#</mathjax> <em>per gram</em>, you will need</p> <blockquote> <p><mathjax>#150.0 xx "0.96 J" = "144 J"#</mathjax></p> </blockquote> <p>Notice that the problem tells you that you add <mathjax>#"1 kJ"#</mathjax> of heat to the sample. This means that the <strong>ratio</strong> between the given heat and the amount of heat needed to increase the temperature of the sample by <mathjax>#1^@"C"#</mathjax> will represent the actual <strong>increase in temperature</strong>.</p> <p>You can thus say that</p> <blockquote> <p><mathjax>#1.0 color(red)(cancel(color(black)("kJ"))) * (10^3 color(red)(cancel(color(black)("J"))))/(1 color(red)(cancel(color(black)("kJ")))) * (1^@"C")/(144 color(red)(cancel(color(black)("J")))) = 6.94^@"C"#</mathjax></p> </blockquote> <p>The final temperature of the sample will thus be </p> <blockquote> <p><mathjax>#T_"final" = 25^@"C" + 6.94^@"C" = 31.94^@"C"#</mathjax></p> </blockquote> <p>Rounded to two <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the answer will once again be </p> <blockquote> <p><mathjax>#T_"final" = color(green)(32^@"C")#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#32^@"C"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>!! SHORT ANSWER !! </strong></p> <p>This problem is a pretty straightforward application of the equation</p> <blockquote> <p><mathjax>#color(blue)(q = m * c * DeltaT)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#q#</mathjax> - the amount of heat added / removed<br/> <mathjax>#m#</mathjax> - the mass of the sample<br/> <mathjax>#c#</mathjax> - the <a href="http://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> of the substance<br/> <mathjax>#DeltaT#</mathjax> - the change in temperature, calculated as the difference between the <em>final temperature</em> and the <em>initial temperature</em></p> <p>All you'd have to do here is rearrange this equation to solve for <mathjax>#DeltaT#</mathjax> and plug in your values - <strong>do not</strong> forget to convert the heat from <em>kilojoules</em> to <em>joules</em></p> <blockquote> <p><mathjax>#DeltaT = q/(m * c)#</mathjax></p> <p><mathjax>#DeltaT = (1.0 * 10^3 color(red)(cancel(color(black)("J"))))/(150.0 color(red)(cancel(color(black)("g"))) * 0.96color(red)(cancel(color(black)("J")))/(color(red)(cancel(color(black)("g"))) * ""^@"C")) = 6.94^@"C"#</mathjax></p> </blockquote> <p>The final temperature of the sample will thus be </p> <blockquote> <p><mathjax>#T_"final" = T_"initial" + DeltaT#</mathjax></p> <p><mathjax>#T_"final" = 25^@"C" + 6.94^@"C"#</mathjax> </p> <p><mathjax>#T_"final" = color(green)(32^@"C") ->#</mathjax> <em>rounded to two <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></em></p> </blockquote> <p><strong>!! AN ALTERNATIVE APPROACH !!</strong></p> <p>I want to show you how to solve such questions <strong>without</strong> using that equation. </p> <p>As you know, a substance's <strong>specific heat</strong> tells you how much heat is needed in order to increase the temperature of <mathjax>#"1 g"#</mathjax> of that substance by <mathjax>#1^@"C"#</mathjax>. </p> <p>In your case, chloroform is said to have a specific heat of</p> <blockquote> <p><mathjax>#c = 0.96"J"/("g" ""^@"C")#</mathjax></p> </blockquote> <p><em>So, what does that tell you?</em></p> <p>In order to increase the temperature of <mathjax>#"1 g"#</mathjax> of chloroform by <mathjax>#1^@"C"#</mathjax>, you need to provide it with <mathjax>#"0.96 J"#</mathjax> of heat. </p> <p>Now look at the data given to you. Focus on the <em>mass</em> of the sample first. </p> <p>Now, if you need to provide <mathjax>#"0.96 J"#</mathjax> of heat in order to increase the temperature of <mathjax>#"1 g"#</mathjax> of chloroform by <mathjax>#1^@"C"#</mathjax>, how much heat will be needed in order to increase the temperature of <mathjax>#"150.0 g"#</mathjax> of chloroform by <mathjax>#1^@"C"#</mathjax>?</p> <p>Since you need <mathjax>#"0.96 J"#</mathjax> <em>per gram</em>, you will need</p> <blockquote> <p><mathjax>#150.0 xx "0.96 J" = "144 J"#</mathjax></p> </blockquote> <p>Notice that the problem tells you that you add <mathjax>#"1 kJ"#</mathjax> of heat to the sample. This means that the <strong>ratio</strong> between the given heat and the amount of heat needed to increase the temperature of the sample by <mathjax>#1^@"C"#</mathjax> will represent the actual <strong>increase in temperature</strong>.</p> <p>You can thus say that</p> <blockquote> <p><mathjax>#1.0 color(red)(cancel(color(black)("kJ"))) * (10^3 color(red)(cancel(color(black)("J"))))/(1 color(red)(cancel(color(black)("kJ")))) * (1^@"C")/(144 color(red)(cancel(color(black)("J")))) = 6.94^@"C"#</mathjax></p> </blockquote> <p>The final temperature of the sample will thus be </p> <blockquote> <p><mathjax>#T_"final" = 25^@"C" + 6.94^@"C" = 31.94^@"C"#</mathjax></p> </blockquote> <p>Rounded to two <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the answer will once again be </p> <blockquote> <p><mathjax>#T_"final" = color(green)(32^@"C")#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">If a sample of chloroform is initially at 25°C, what is its final temperature of 150.0 g of chloroform absorbs 1.0 kilojoules of heat, and the specific heat of chloroform is 0.96 J/g°C?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/calorimetry" itemprop="url"> <span class="breadcrumb" itemprop="title">Calorimetry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="216137" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-23T20:13:20" itemprop="dateCreated"> Jan 23, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#32^@"C"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>!! SHORT ANSWER !! </strong></p> <p>This problem is a pretty straightforward application of the equation</p> <blockquote> <p><mathjax>#color(blue)(q = m * c * DeltaT)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#q#</mathjax> - the amount of heat added / removed<br/> <mathjax>#m#</mathjax> - the mass of the sample<br/> <mathjax>#c#</mathjax> - the <a href="http://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> of the substance<br/> <mathjax>#DeltaT#</mathjax> - the change in temperature, calculated as the difference between the <em>final temperature</em> and the <em>initial temperature</em></p> <p>All you'd have to do here is rearrange this equation to solve for <mathjax>#DeltaT#</mathjax> and plug in your values - <strong>do not</strong> forget to convert the heat from <em>kilojoules</em> to <em>joules</em></p> <blockquote> <p><mathjax>#DeltaT = q/(m * c)#</mathjax></p> <p><mathjax>#DeltaT = (1.0 * 10^3 color(red)(cancel(color(black)("J"))))/(150.0 color(red)(cancel(color(black)("g"))) * 0.96color(red)(cancel(color(black)("J")))/(color(red)(cancel(color(black)("g"))) * ""^@"C")) = 6.94^@"C"#</mathjax></p> </blockquote> <p>The final temperature of the sample will thus be </p> <blockquote> <p><mathjax>#T_"final" = T_"initial" + DeltaT#</mathjax></p> <p><mathjax>#T_"final" = 25^@"C" + 6.94^@"C"#</mathjax> </p> <p><mathjax>#T_"final" = color(green)(32^@"C") ->#</mathjax> <em>rounded to two <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></em></p> </blockquote> <p><strong>!! AN ALTERNATIVE APPROACH !!</strong></p> <p>I want to show you how to solve such questions <strong>without</strong> using that equation. </p> <p>As you know, a substance's <strong>specific heat</strong> tells you how much heat is needed in order to increase the temperature of <mathjax>#"1 g"#</mathjax> of that substance by <mathjax>#1^@"C"#</mathjax>. </p> <p>In your case, chloroform is said to have a specific heat of</p> <blockquote> <p><mathjax>#c = 0.96"J"/("g" ""^@"C")#</mathjax></p> </blockquote> <p><em>So, what does that tell you?</em></p> <p>In order to increase the temperature of <mathjax>#"1 g"#</mathjax> of chloroform by <mathjax>#1^@"C"#</mathjax>, you need to provide it with <mathjax>#"0.96 J"#</mathjax> of heat. </p> <p>Now look at the data given to you. Focus on the <em>mass</em> of the sample first. </p> <p>Now, if you need to provide <mathjax>#"0.96 J"#</mathjax> of heat in order to increase the temperature of <mathjax>#"1 g"#</mathjax> of chloroform by <mathjax>#1^@"C"#</mathjax>, how much heat will be needed in order to increase the temperature of <mathjax>#"150.0 g"#</mathjax> of chloroform by <mathjax>#1^@"C"#</mathjax>?</p> <p>Since you need <mathjax>#"0.96 J"#</mathjax> <em>per gram</em>, you will need</p> <blockquote> <p><mathjax>#150.0 xx "0.96 J" = "144 J"#</mathjax></p> </blockquote> <p>Notice that the problem tells you that you add <mathjax>#"1 kJ"#</mathjax> of heat to the sample. This means that the <strong>ratio</strong> between the given heat and the amount of heat needed to increase the temperature of the sample by <mathjax>#1^@"C"#</mathjax> will represent the actual <strong>increase in temperature</strong>.</p> <p>You can thus say that</p> <blockquote> <p><mathjax>#1.0 color(red)(cancel(color(black)("kJ"))) * (10^3 color(red)(cancel(color(black)("J"))))/(1 color(red)(cancel(color(black)("kJ")))) * (1^@"C")/(144 color(red)(cancel(color(black)("J")))) = 6.94^@"C"#</mathjax></p> </blockquote> <p>The final temperature of the sample will thus be </p> <blockquote> <p><mathjax>#T_"final" = 25^@"C" + 6.94^@"C" = 31.94^@"C"#</mathjax></p> </blockquote> <p>Rounded to two <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the answer will once again be </p> <blockquote> <p><mathjax>#T_"final" = color(green)(32^@"C")#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/216137" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-differential-scanning-in-calorimetry-work"> How does differential scanning in calorimetry work? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-read-differential-scanning-in-calorimetry"> What information do you get from a differential scanning calorimetry plot? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-measure-calorimetry"> How do you measure calorimetry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531d304102bf341e75b962a7"> Question #962a7 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5335021802bf344ae911dfc5"> Question #1dfc5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/533668f502bf34572c341af6"> Question #41af6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-definition-of-calorimetry"> What is calorimetry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-differential-scanning-calorimeter"> What is a differential scanning calorimeter? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-a-calorimeter-measure-energy"> How can a calorimeter measure energy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-calorimeters-made-of"> What are calorimeters made of? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/calorimetry"> See all questions in Calorimetry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 19536 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	If a sample of chloroform is initially at 25°C, what is its final temperature of 150.0 g of chloroform absorbs 1.0 kilojoules of heat, and the specific heat of chloroform is 0.96 J/g°C?	null
928	abcbd420-6ddd-11ea-ab9f-ccda262736ce	https://socratic.org/questions/what-is-the-h-of-a-solution-with-a-ph-of-6-6	3.98 × 10^(-7) M	start physical_unit 6 6 [h+] mol/l qc_end physical_unit 6 6 11 11 ph qc_end end	[{"type":"physical unit","value":"[H+] [OF] the solution [IN] M"}]	[{"type":"physical unit","value":"3.98 × 10^(-7) M"}]	[{"type":"physical unit","value":"pH [OF] the solution [=] \\pu{6.6}"}]	<h1 class="questionTitle" itemprop="name">What is the #[H^+]# of a solution with a pH of 6.6?</h1>	null	3.98 × 10^(-7) M	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#pH=-log_10[H^+]#</mathjax> by definition.</p> <p>If <mathjax>#pH=6.6#</mathjax>, then to get <mathjax>#[H^+]#</mathjax> we take the antilogarithm:</p> <p><mathjax>#[H^+]#</mathjax> <mathjax>#=#</mathjax> <mathjax>#10^(-6.6)#</mathjax> <mathjax>#mol*L^-1#</mathjax> with respect to <mathjax>#H^+#</mathjax> or <mathjax>#H_3O^+#</mathjax>, an equivalent representation.</p> <p>This solution is very slightly acidic. I don't think you could taste the difference. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#[H^+]=10^(-6.6)#</mathjax> <mathjax>#molL^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#pH=-log_10[H^+]#</mathjax> by definition.</p> <p>If <mathjax>#pH=6.6#</mathjax>, then to get <mathjax>#[H^+]#</mathjax> we take the antilogarithm:</p> <p><mathjax>#[H^+]#</mathjax> <mathjax>#=#</mathjax> <mathjax>#10^(-6.6)#</mathjax> <mathjax>#molL^-1#</mathjax> with respect to <mathjax>#H^+#</mathjax> or <mathjax>#H_3O^+#</mathjax>, an equivalent representation.</p> <p>This solution is very slightly acidic. I don't think you could taste the difference. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the #[H^+]# of a solution with a pH of 6.6?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/the-ph-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">pH</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="278491" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-17T18:18:48" itemprop="dateCreated"> Jun 17, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#[H^+]=10^(-6.6)#</mathjax> <mathjax>#molL^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#pH=-log_10[H^+]#</mathjax> by definition.</p> <p>If <mathjax>#pH=6.6#</mathjax>, then to get <mathjax>#[H^+]#</mathjax> we take the antilogarithm:</p> <p><mathjax>#[H^+]#</mathjax> <mathjax>#=#</mathjax> <mathjax>#10^(-6.6)#</mathjax> <mathjax>#molL^-1#</mathjax> with respect to <mathjax>#H^+#</mathjax> or <mathjax>#H_3O^+#</mathjax>, an equivalent representation.</p> <p>This solution is very slightly acidic. I don't think you could taste the difference. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/278491" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-pka"> How do you determine pH from pKa? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-ph-values-of-acids-and-bases-differ"> How do pH values of acids and bases differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-something-on-a-ph-scale"> How do you calculate something on a pH scale? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-diprotic-acid"> How do you calculate pH diprotic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-from-acid-dissociation-constant"> How do you calculate pH from acid dissociation constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-of-acid-and-base-solution"> How do you calculate pH of acid and base solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ph-scale-0-14"> Why is the pH scale 0-14? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-ph-the-measure-of-the-hydrogen-ion-concentration"> Is pH a measure of the hydrogen ion concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-solubility-affect-ph"> How does solubility affect pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-ph-relate-to-pka-in-a-titration"> How does pH relate to pKa in a titration? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/the-ph-concept"> See all questions in pH </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 7249 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the #[H^+]# of a solution with a pH of 6.6?	null
929	aa0e1693-6ddd-11ea-9259-ccda262736ce	https://socratic.org/questions/how-do-you-balance-bacl-2-al-2s-3-bas-alcl-3	3 BaCl2 + Al2S3 -> 3 BaS + 2 AlCl3	start chemical_equation qc_end chemical_equation 4 10 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the equation"}]	[{"type":"chemical equation","value":"3 BaCl2 + Al2S3 -> 3 BaS + 2 AlCl3"}]	[{"type":"chemical equation","value":"BaCl2 + Al2S3 -> BaS + AlCl3"}]	<h1 class="questionTitle" itemprop="name">How do you balance #BaCl_2 + Al_2S_3 -> BaS + AlCl_3#?</h1>	null	3 BaCl2 + Al2S3 -> 3 BaS + 2 AlCl3	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Let the four balancing factors be <mathjax>#a#</mathjax> <mathjax>#b#</mathjax> <mathjax>#c#</mathjax> <mathjax>#d#</mathjax> as follows:</p> <p><mathjax>#aBaCl_2+bAl_2S_3->cBaS+dAlCl_3#</mathjax></p> <p>For each element, we can have a balance equation:</p> <p><mathjax>#Ba: a=c#</mathjax></p> <p><mathjax>#Cl: 2a=3d#</mathjax></p> <p><mathjax>#Al: 2b=d#</mathjax></p> <p><mathjax>#S: 3b=c#</mathjax></p> <p>You can notice that if you set one of these factors it will chain you to the next factor. Let's set <mathjax>#a=1#</mathjax></p> <p><mathjax>#a=1#</mathjax></p> <p><mathjax>#c=a=1#</mathjax></p> <p><mathjax>#3d=2a<=>d=2/3#</mathjax></p> <p><mathjax>#2b=d<=>b=(2/3)/2=1/3#</mathjax></p> <p>Now the equation can be balanced:</p> <p><mathjax>#BaCl_2+1/3Al_2S_3->BaS+2/3AlCl_3#</mathjax></p> <p>However, many don't like the fractions because of the molecule concept. Since they have a common denuminator, multiply everything by 3 to get ride of the fractions:</p> <p><mathjax>#3BaCl_2+Al_2S_3->3BaS+2AlCl_3#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Create an equation for each of the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a>, then set one of them and solve for the others. Answer is:</p> <p><mathjax>#3BaCl_2+Al_2S_3->3BaS+2AlCl_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Let the four balancing factors be <mathjax>#a#</mathjax> <mathjax>#b#</mathjax> <mathjax>#c#</mathjax> <mathjax>#d#</mathjax> as follows:</p> <p><mathjax>#aBaCl_2+bAl_2S_3->cBaS+dAlCl_3#</mathjax></p> <p>For each element, we can have a balance equation:</p> <p><mathjax>#Ba: a=c#</mathjax></p> <p><mathjax>#Cl: 2a=3d#</mathjax></p> <p><mathjax>#Al: 2b=d#</mathjax></p> <p><mathjax>#S: 3b=c#</mathjax></p> <p>You can notice that if you set one of these factors it will chain you to the next factor. Let's set <mathjax>#a=1#</mathjax></p> <p><mathjax>#a=1#</mathjax></p> <p><mathjax>#c=a=1#</mathjax></p> <p><mathjax>#3d=2a<=>d=2/3#</mathjax></p> <p><mathjax>#2b=d<=>b=(2/3)/2=1/3#</mathjax></p> <p>Now the equation can be balanced:</p> <p><mathjax>#BaCl_2+1/3Al_2S_3->BaS+2/3AlCl_3#</mathjax></p> <p>However, many don't like the fractions because of the molecule concept. Since they have a common denuminator, multiply everything by 3 to get ride of the fractions:</p> <p><mathjax>#3BaCl_2+Al_2S_3->3BaS+2AlCl_3#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you balance #BaCl_2 + Al_2S_3 -> BaS + AlCl_3#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="254476" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/costas-c"><img alt="" class="" src="https://graph.facebook.com/1719068551659441/picture?height=50&width=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/costas-c"> Costas C. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-04-15T13:23:36" itemprop="dateCreated"> Apr 15, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Create an equation for each of the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a>, then set one of them and solve for the others. Answer is:</p> <p><mathjax>#3BaCl_2+Al_2S_3->3BaS+2AlCl_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Let the four balancing factors be <mathjax>#a#</mathjax> <mathjax>#b#</mathjax> <mathjax>#c#</mathjax> <mathjax>#d#</mathjax> as follows:</p> <p><mathjax>#aBaCl_2+bAl_2S_3->cBaS+dAlCl_3#</mathjax></p> <p>For each element, we can have a balance equation:</p> <p><mathjax>#Ba: a=c#</mathjax></p> <p><mathjax>#Cl: 2a=3d#</mathjax></p> <p><mathjax>#Al: 2b=d#</mathjax></p> <p><mathjax>#S: 3b=c#</mathjax></p> <p>You can notice that if you set one of these factors it will chain you to the next factor. Let's set <mathjax>#a=1#</mathjax></p> <p><mathjax>#a=1#</mathjax></p> <p><mathjax>#c=a=1#</mathjax></p> <p><mathjax>#3d=2a<=>d=2/3#</mathjax></p> <p><mathjax>#2b=d<=>b=(2/3)/2=1/3#</mathjax></p> <p>Now the equation can be balanced:</p> <p><mathjax>#BaCl_2+1/3Al_2S_3->BaS+2/3AlCl_3#</mathjax></p> <p>However, many don't like the fractions because of the molecule concept. Since they have a common denuminator, multiply everything by 3 to get ride of the fractions:</p> <p><mathjax>#3BaCl_2+Al_2S_3->3BaS+2AlCl_3#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/254476" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------> H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -> Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? 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Sodium phosphate and calcium chloride react to form... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-equation-kclo3-kcl-o2"> How can I balance this equation? ____ #KClO_3 -># ____ #KCl +# ____ #O_2# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-balancing-chemical-equations-important"> Why is balancing chemical equations important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/balancing-chemical-equations"> See all questions in Balancing Chemical Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1465 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How do you balance #BaCl_2 + Al_2S_3 -> BaS + AlCl_3#?	null
930	a89bd6b6-6ddd-11ea-acdf-ccda262736ce	https://socratic.org/questions/59ff0e5811ef6b3399a9b266	3	start physical_unit 38 38 value none qc_end physical_unit 3 5 14 15 mass qc_end c_other OTHER qc_end physical_unit 28 29 31 32 mass qc_end end	[{"type":"physical unit","value":"value [OF] x"}]	[{"type":"physical unit","value":"3"}]	[{"type":"physical unit","value":"mass [OF] CusO4.xH20 sample [=] \\pu{6.45 g}"},{"type":"other","value":"heat the sample"},{"type":"physical unit","value":"mass [OF] anhydrous salt [=] \\pu{4.82 g}"}]	<h1 class="questionTitle" itemprop="name">You weigh a sample of #"CusO"_4 * x"H"_2"O"# and find that it has a mass of #"6.45 g"#. After you heat the sample, you find that the mass of the anhydrous salt is #"4.82 g"#. What is the value of #x# ?</h1>	null	3	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that the difference between the mass of the hydrate and the mass of the anhydrous salt is equal to the mass of <em>water of hydration</em> present in the sample. </p> <p>In your case, you have</p> <blockquote> <p><mathjax>#m_"water" = "6.45 g " - " 4.82 g"#</mathjax></p> <p><mathjax>#m_"water" = "1.63 g"#</mathjax></p> </blockquote> <p>Use the <strong>molar mass</strong> of water to convert the mass to <em>moles</em>.</p> <blockquote> <p><mathjax>#1.63 color(red)(cancel(color(black)("g"))) * ("1 mole H"_2"O")/(18.015color(red)(cancel(color(black)("g")))) = "0.09048 moles H"_2"O"#</mathjax></p> </blockquote> <p>Do the same for anhydrous copper(II) sulfate, <mathjax>#"CuSO"_4#</mathjax>.</p> <blockquote> <p><mathjax>#4.82 color(red)(cancel(color(black)("g"))) * "1 mole CuSO"_4/(159.609color(red)(cancel(color(black)("g")))) = "0.03020 moles CuSO"_4#</mathjax></p> </blockquote> <p>Now, your goal here is to find the number of moles of water of hydration present <strong>for every mole</strong> of copper(II) sulfate hydrate, so divide both values by the <strong>smallest one</strong> to get <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio that exists between the anhydrous salt and the water of hydration in the hydrate.</p> <blockquote> <p><mathjax>#"For CuSO"_4:" " (0.03020 color(red)(cancel(color(black)("moles"))))/(0.03020color(red)(cancel(color(black)("moles")))) = 1#</mathjax></p> <p><mathjax>#"For H"_2"O": " " (0.09048color(red)(cancel(color(black)("moles"))))/(0.03020color(red)(cancel(color(black)("moles")))) = 2.996 ~~ 3#</mathjax></p> </blockquote> <p>Since <mathjax>#1:3#</mathjax> represents the <em>smallest whole number ratio</em> that can exist here, you can say that <strong>for every</strong> <mathjax>#1#</mathjax> <strong>mole</strong> of anhydrous copper(II) sulfate, the hydrate contains <mathjax>#3#</mathjax> <strong>moles</strong> of water of hydration. </p> <p>This means that you're dealing with <em>copper(II) sulfate trihydrate</em>, <mathjax>#"CuSO"_4 * 3"H"_2"O"#</mathjax>. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#x = 3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that the difference between the mass of the hydrate and the mass of the anhydrous salt is equal to the mass of <em>water of hydration</em> present in the sample. </p> <p>In your case, you have</p> <blockquote> <p><mathjax>#m_"water" = "6.45 g " - " 4.82 g"#</mathjax></p> <p><mathjax>#m_"water" = "1.63 g"#</mathjax></p> </blockquote> <p>Use the <strong>molar mass</strong> of water to convert the mass to <em>moles</em>.</p> <blockquote> <p><mathjax>#1.63 color(red)(cancel(color(black)("g"))) * ("1 mole H"_2"O")/(18.015color(red)(cancel(color(black)("g")))) = "0.09048 moles H"_2"O"#</mathjax></p> </blockquote> <p>Do the same for anhydrous copper(II) sulfate, <mathjax>#"CuSO"_4#</mathjax>.</p> <blockquote> <p><mathjax>#4.82 color(red)(cancel(color(black)("g"))) * "1 mole CuSO"_4/(159.609color(red)(cancel(color(black)("g")))) = "0.03020 moles CuSO"_4#</mathjax></p> </blockquote> <p>Now, your goal here is to find the number of moles of water of hydration present <strong>for every mole</strong> of copper(II) sulfate hydrate, so divide both values by the <strong>smallest one</strong> to get <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio that exists between the anhydrous salt and the water of hydration in the hydrate.</p> <blockquote> <p><mathjax>#"For CuSO"_4:" " (0.03020 color(red)(cancel(color(black)("moles"))))/(0.03020color(red)(cancel(color(black)("moles")))) = 1#</mathjax></p> <p><mathjax>#"For H"_2"O": " " (0.09048color(red)(cancel(color(black)("moles"))))/(0.03020color(red)(cancel(color(black)("moles")))) = 2.996 ~~ 3#</mathjax></p> </blockquote> <p>Since <mathjax>#1:3#</mathjax> represents the <em>smallest whole number ratio</em> that can exist here, you can say that <strong>for every</strong> <mathjax>#1#</mathjax> <strong>mole</strong> of anhydrous copper(II) sulfate, the hydrate contains <mathjax>#3#</mathjax> <strong>moles</strong> of water of hydration. </p> <p>This means that you're dealing with <em>copper(II) sulfate trihydrate</em>, <mathjax>#"CuSO"_4 * 3"H"_2"O"#</mathjax>. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">You weigh a sample of #"CusO"_4 * x"H"_2"O"# and find that it has a mass of #"6.45 g"#. After you heat the sample, you find that the mass of the anhydrous salt is #"4.82 g"#. What is the value of #x# ?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/determining-formula-and-molar-masses" itemprop="url"> <span class="breadcrumb" itemprop="title">Determining Formula</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="500814" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-11-06T00:24:58" itemprop="dateCreated"> Nov 6, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#x = 3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that the difference between the mass of the hydrate and the mass of the anhydrous salt is equal to the mass of <em>water of hydration</em> present in the sample. </p> <p>In your case, you have</p> <blockquote> <p><mathjax>#m_"water" = "6.45 g " - " 4.82 g"#</mathjax></p> <p><mathjax>#m_"water" = "1.63 g"#</mathjax></p> </blockquote> <p>Use the <strong>molar mass</strong> of water to convert the mass to <em>moles</em>.</p> <blockquote> <p><mathjax>#1.63 color(red)(cancel(color(black)("g"))) * ("1 mole H"_2"O")/(18.015color(red)(cancel(color(black)("g")))) = "0.09048 moles H"_2"O"#</mathjax></p> </blockquote> <p>Do the same for anhydrous copper(II) sulfate, <mathjax>#"CuSO"_4#</mathjax>.</p> <blockquote> <p><mathjax>#4.82 color(red)(cancel(color(black)("g"))) * "1 mole CuSO"_4/(159.609color(red)(cancel(color(black)("g")))) = "0.03020 moles CuSO"_4#</mathjax></p> </blockquote> <p>Now, your goal here is to find the number of moles of water of hydration present <strong>for every mole</strong> of copper(II) sulfate hydrate, so divide both values by the <strong>smallest one</strong> to get <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio that exists between the anhydrous salt and the water of hydration in the hydrate.</p> <blockquote> <p><mathjax>#"For CuSO"_4:" " (0.03020 color(red)(cancel(color(black)("moles"))))/(0.03020color(red)(cancel(color(black)("moles")))) = 1#</mathjax></p> <p><mathjax>#"For H"_2"O": " " (0.09048color(red)(cancel(color(black)("moles"))))/(0.03020color(red)(cancel(color(black)("moles")))) = 2.996 ~~ 3#</mathjax></p> </blockquote> <p>Since <mathjax>#1:3#</mathjax> represents the <em>smallest whole number ratio</em> that can exist here, you can say that <strong>for every</strong> <mathjax>#1#</mathjax> <strong>mole</strong> of anhydrous copper(II) sulfate, the hydrate contains <mathjax>#3#</mathjax> <strong>moles</strong> of water of hydration. </p> <p>This means that you're dealing with <em>copper(II) sulfate trihydrate</em>, <mathjax>#"CuSO"_4 * 3"H"_2"O"#</mathjax>. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/500814" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-it-possible-to-find-a-molecular-formula-from-molar-mass"> Is it possible to find a molecular formula from molar mass? 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</a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/determining-formula-and-molar-masses"> See all questions in Determining Formula </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 8994 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	You weigh a sample of #"CusO"_4 * x"H"_2"O"# and find that it has a mass of #"6.45 g"#. After you heat the sample, you find that the mass of the anhydrous salt is #"4.82 g"#. What is the value of #x# ?	null
931	ac05af34-6ddd-11ea-98b7-ccda262736ce	https://socratic.org/questions/a-sample-of-substance-x-that-has-a-mass-of-326-0-g-releases-4325-8-cal-when-it-f	775.6 cal/mol	start physical_unit 3 4 molar_heat cal/mol qc_end physical_unit 1 4 10 11 mass qc_end c_other OTHER qc_end physical_unit 1 4 13 14 heat_energy qc_end physical_unit 3 4 30 31 molar_mass qc_end end	[{"type":"physical unit","value":"Molar heat of fusion [OF] substance X [IN] cal/mol"}]	[{"type":"physical unit","value":"775.6 cal/mol"}]	[{"type":"physical unit","value":"Mass [OF] substance X sample [=] \\pu{326.0 g}"},{"type":"other","value":"It freezes at its freezing point."},{"type":"physical unit","value":"Released energy [OF] substance X sample [=] \\pu{4325.8 cal}"},{"type":"physical unit","value":"Molar mass [OF] substance X [=] \\pu{58.45 g/mol}"}]	<h1 class="questionTitle" itemprop="name">A sample of substance X that has a mass of 326.0 g releases 4325.8 cal when it freezes at its freezing point. If substance X has a molar mass of 58.45 g/mol, what is the molar heat of fusion for substance X?</h1>	null	775.6 cal/mol	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>For a given substance, the <strong>molar <a href="https://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> of fusion</strong>, <mathjax>#DeltaH_"fus"#</mathjax>, tells you the enthalpy change that accompanies a solid <mathjax>#->#</mathjax> liquid phase change of <mathjax>#1#</mathjax> <strong>mole</strong> of said substance.</p> <p>This implies that the molar enthalpy of fusion will almost always have a <strong>positive value</strong>, since heat is usually <strong>needed</strong> in order for a substance to go from solid at its melting point to liquid at its melting point. </p> <p>Now, your goal here is to figure out the enthalpy change that occurs when <mathjax>#1#</mathjax> <strong>mole</strong> of substance <mathjax>#"X"#</mathjax> goes from <em>liquid to solid</em> at its freezing point. </p> <p>You already know that the substance <strong>gives off</strong> energy when it freezes, so right from the start, you know that this enthalpy change will carry a <strong>negative sign</strong>.</p> <blockquote> <p><mathjax>#DeltaH_ ("liquid " -> " solid") = -"(a value) mol "^(-1)#</mathjax></p> <blockquote> <p><em>The minus sign symbolizes heat <strong>given off</strong> and</em> <mathjax>#"mol"^(-1)#</mathjax> <em>symbolizes that this enthalpy change occurs <strong>per mole</strong> of substance</em></p> </blockquote> </blockquote> <p>So start by making a note that you must have</p> <blockquote> <p><mathjax>#overbrace(DeltaH_"fus")^(color(blue)("must be positive")) = - overbrace(DeltaH_ ("liquid " -> " solid"))^(color(purple)("will be negative"))#</mathjax></p> </blockquote> <p>Next, use the <strong>molar mass</strong> of substance <mathjax>#"X"#</mathjax> to convert the mass to <em>moles</em>.</p> <blockquote> <p><mathjax>#326.0 color(red)(cancel(color(black)("g"))) * "1 mole X"/(58.45color(red)(cancel(color(black)("g")))) = "5.5774 moles X"#</mathjax></p> </blockquote> <p>So, you know that when <mathjax>#5.5774#</mathjax> <strong>moles</strong> of <mathjax>#"X"#</mathjax> freeze, <mathjax>#"4325.8 cal"#</mathjax> of heat are being <strong>given off</strong>. Use this information to find the heat given off when <mathjax>#1#</mathjax> <strong>mole</strong> of <mathjax>#"X"#</mathjax> freezes</p> <blockquote> <p><mathjax>#1 color(red)(cancel(color(black)("mole X"))) * "4325.8 cal"/(5.5774color(red)(cancel(color(black)("mole X")))) = "775.6 cal"#</mathjax></p> </blockquote> <p>You can thus say that the enthalpy change that occurs when <mathjax>#1#</mathjax> <strong>mole</strong> of <mathjax>#"X"#</mathjax> freezes is equal to</p> <blockquote> <p><mathjax>#DeltaH_ ("liquid " -> " solid") = - "775.6 cal mol"^(-1)#</mathjax></p> </blockquote> <p>Therefore, the molar enthalpy of fusion will be equal to</p> <blockquote> <p><mathjax>#DeltaH_"fus" = - (-"775.6 cal mol"^(-1))#</mathjax></p> <p><mathjax>#color(darkgreen)(ul(color(black)(DeltaH_"fus" = +"775.6 cal mol"^(-1))))#</mathjax></p> </blockquote> <p>The answer is rounded to four <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the mass of the sample. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#DeltaH_"fus" = "775.6 cal mol"^(-1)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>For a given substance, the <strong>molar <a href="https://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> of fusion</strong>, <mathjax>#DeltaH_"fus"#</mathjax>, tells you the enthalpy change that accompanies a solid <mathjax>#->#</mathjax> liquid phase change of <mathjax>#1#</mathjax> <strong>mole</strong> of said substance.</p> <p>This implies that the molar enthalpy of fusion will almost always have a <strong>positive value</strong>, since heat is usually <strong>needed</strong> in order for a substance to go from solid at its melting point to liquid at its melting point. </p> <p>Now, your goal here is to figure out the enthalpy change that occurs when <mathjax>#1#</mathjax> <strong>mole</strong> of substance <mathjax>#"X"#</mathjax> goes from <em>liquid to solid</em> at its freezing point. </p> <p>You already know that the substance <strong>gives off</strong> energy when it freezes, so right from the start, you know that this enthalpy change will carry a <strong>negative sign</strong>.</p> <blockquote> <p><mathjax>#DeltaH_ ("liquid " -> " solid") = -"(a value) mol "^(-1)#</mathjax></p> <blockquote> <p><em>The minus sign symbolizes heat <strong>given off</strong> and</em> <mathjax>#"mol"^(-1)#</mathjax> <em>symbolizes that this enthalpy change occurs <strong>per mole</strong> of substance</em></p> </blockquote> </blockquote> <p>So start by making a note that you must have</p> <blockquote> <p><mathjax>#overbrace(DeltaH_"fus")^(color(blue)("must be positive")) = - overbrace(DeltaH_ ("liquid " -> " solid"))^(color(purple)("will be negative"))#</mathjax></p> </blockquote> <p>Next, use the <strong>molar mass</strong> of substance <mathjax>#"X"#</mathjax> to convert the mass to <em>moles</em>.</p> <blockquote> <p><mathjax>#326.0 color(red)(cancel(color(black)("g"))) * "1 mole X"/(58.45color(red)(cancel(color(black)("g")))) = "5.5774 moles X"#</mathjax></p> </blockquote> <p>So, you know that when <mathjax>#5.5774#</mathjax> <strong>moles</strong> of <mathjax>#"X"#</mathjax> freeze, <mathjax>#"4325.8 cal"#</mathjax> of heat are being <strong>given off</strong>. Use this information to find the heat given off when <mathjax>#1#</mathjax> <strong>mole</strong> of <mathjax>#"X"#</mathjax> freezes</p> <blockquote> <p><mathjax>#1 color(red)(cancel(color(black)("mole X"))) * "4325.8 cal"/(5.5774color(red)(cancel(color(black)("mole X")))) = "775.6 cal"#</mathjax></p> </blockquote> <p>You can thus say that the enthalpy change that occurs when <mathjax>#1#</mathjax> <strong>mole</strong> of <mathjax>#"X"#</mathjax> freezes is equal to</p> <blockquote> <p><mathjax>#DeltaH_ ("liquid " -> " solid") = - "775.6 cal mol"^(-1)#</mathjax></p> </blockquote> <p>Therefore, the molar enthalpy of fusion will be equal to</p> <blockquote> <p><mathjax>#DeltaH_"fus" = - (-"775.6 cal mol"^(-1))#</mathjax></p> <p><mathjax>#color(darkgreen)(ul(color(black)(DeltaH_"fus" = +"775.6 cal mol"^(-1))))#</mathjax></p> </blockquote> <p>The answer is rounded to four <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the mass of the sample. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A sample of substance X that has a mass of 326.0 g releases 4325.8 cal when it freezes at its freezing point. If substance X has a molar mass of 58.45 g/mol, what is the molar heat of fusion for substance X?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/calorimetry" itemprop="url"> <span class="breadcrumb" itemprop="title">Calorimetry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="439429" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-14T01:23:45" itemprop="dateCreated"> Jun 14, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#DeltaH_"fus" = "775.6 cal mol"^(-1)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>For a given substance, the <strong>molar <a href="https://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> of fusion</strong>, <mathjax>#DeltaH_"fus"#</mathjax>, tells you the enthalpy change that accompanies a solid <mathjax>#->#</mathjax> liquid phase change of <mathjax>#1#</mathjax> <strong>mole</strong> of said substance.</p> <p>This implies that the molar enthalpy of fusion will almost always have a <strong>positive value</strong>, since heat is usually <strong>needed</strong> in order for a substance to go from solid at its melting point to liquid at its melting point. </p> <p>Now, your goal here is to figure out the enthalpy change that occurs when <mathjax>#1#</mathjax> <strong>mole</strong> of substance <mathjax>#"X"#</mathjax> goes from <em>liquid to solid</em> at its freezing point. </p> <p>You already know that the substance <strong>gives off</strong> energy when it freezes, so right from the start, you know that this enthalpy change will carry a <strong>negative sign</strong>.</p> <blockquote> <p><mathjax>#DeltaH_ ("liquid " -> " solid") = -"(a value) mol "^(-1)#</mathjax></p> <blockquote> <p><em>The minus sign symbolizes heat <strong>given off</strong> and</em> <mathjax>#"mol"^(-1)#</mathjax> <em>symbolizes that this enthalpy change occurs <strong>per mole</strong> of substance</em></p> </blockquote> </blockquote> <p>So start by making a note that you must have</p> <blockquote> <p><mathjax>#overbrace(DeltaH_"fus")^(color(blue)("must be positive")) = - overbrace(DeltaH_ ("liquid " -> " solid"))^(color(purple)("will be negative"))#</mathjax></p> </blockquote> <p>Next, use the <strong>molar mass</strong> of substance <mathjax>#"X"#</mathjax> to convert the mass to <em>moles</em>.</p> <blockquote> <p><mathjax>#326.0 color(red)(cancel(color(black)("g"))) * "1 mole X"/(58.45color(red)(cancel(color(black)("g")))) = "5.5774 moles X"#</mathjax></p> </blockquote> <p>So, you know that when <mathjax>#5.5774#</mathjax> <strong>moles</strong> of <mathjax>#"X"#</mathjax> freeze, <mathjax>#"4325.8 cal"#</mathjax> of heat are being <strong>given off</strong>. Use this information to find the heat given off when <mathjax>#1#</mathjax> <strong>mole</strong> of <mathjax>#"X"#</mathjax> freezes</p> <blockquote> <p><mathjax>#1 color(red)(cancel(color(black)("mole X"))) * "4325.8 cal"/(5.5774color(red)(cancel(color(black)("mole X")))) = "775.6 cal"#</mathjax></p> </blockquote> <p>You can thus say that the enthalpy change that occurs when <mathjax>#1#</mathjax> <strong>mole</strong> of <mathjax>#"X"#</mathjax> freezes is equal to</p> <blockquote> <p><mathjax>#DeltaH_ ("liquid " -> " solid") = - "775.6 cal mol"^(-1)#</mathjax></p> </blockquote> <p>Therefore, the molar enthalpy of fusion will be equal to</p> <blockquote> <p><mathjax>#DeltaH_"fus" = - (-"775.6 cal mol"^(-1))#</mathjax></p> <p><mathjax>#color(darkgreen)(ul(color(black)(DeltaH_"fus" = +"775.6 cal mol"^(-1))))#</mathjax></p> </blockquote> <p>The answer is rounded to four <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the mass of the sample. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/439429" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-differential-scanning-in-calorimetry-work"> How does differential scanning in calorimetry work? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-read-differential-scanning-in-calorimetry"> What information do you get from a differential scanning calorimetry plot? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-measure-calorimetry"> How do you measure calorimetry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531d304102bf341e75b962a7"> Question #962a7 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5335021802bf344ae911dfc5"> Question #1dfc5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/533668f502bf34572c341af6"> Question #41af6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-definition-of-calorimetry"> What is calorimetry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-differential-scanning-calorimeter"> What is a differential scanning calorimeter? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-a-calorimeter-measure-energy"> How can a calorimeter measure energy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-calorimeters-made-of"> What are calorimeters made of? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/calorimetry"> See all questions in Calorimetry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3014 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A sample of substance X that has a mass of 326.0 g releases 4325.8 cal when it freezes at its freezing point. If substance X has a molar mass of 58.45 g/mol, what is the molar heat of fusion for substance X?	null
932	abfdbf7d-6ddd-11ea-82a5-ccda262736ce	https://socratic.org/questions/in-the-reaction-n-2-3h-2-2nh-3-what-volume-of-ammonia-is-produced-when-5-0-l-of-	10.00 L	start physical_unit 13 13 volume l qc_end physical_unit 20 20 17 18 volume qc_end chemical_equation 3 9 qc_end end	[{"type":"physical unit","value":"Volume [OF] ammonia [IN] L"}]	[{"type":"physical unit","value":"10.00 L"}]	[{"type":"physical unit","value":"Volume [OF] Nitrogen [=] \\pu{5.0 L}"},{"type":"chemical equation","value":"N2 + 3 H2 -> 2 NH3"}]	<h1 class="questionTitle" itemprop="name">In the reaction #N_2 + 3H_2 -> 2NH_3#, what volume of ammonia is produced when 5.0 L of Nitrogen react?</h1>	null	10.00 L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The stoichiometrically balanced equation, which you have written is:</p> <p><mathjax>#N_2(g)+3H_2(g) rightleftharpoons 2NH_3(g)#</mathjax></p> <p>Given constant temperature and pressure, which we must assume, volume is proportional to the number of moles. And thus if <mathjax>#5.0L#</mathjax> of dinitrogen react (with <mathjax>#15.0L#</mathjax> of dihydrogen), <mathjax>#10.0*L#</mathjax> of ammonia gas will result.</p> <p>Of course, practically, we will get nothing like quantitative reaction, and the reaction is an equilibrium that must be manipulated. The one thing this reaction has got going for it is that the product, the ammonia, is condensable, and highly soluble in water, whereas the reactants are quite volatile gases. </p> <p>Dinitrogen reduction is regarded as the most important reaction performed on the planet. Why?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We follow the <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>.........<mathjax>#10L#</mathjax> of ammonia will result. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The stoichiometrically balanced equation, which you have written is:</p> <p><mathjax>#N_2(g)+3H_2(g) rightleftharpoons 2NH_3(g)#</mathjax></p> <p>Given constant temperature and pressure, which we must assume, volume is proportional to the number of moles. And thus if <mathjax>#5.0L#</mathjax> of dinitrogen react (with <mathjax>#15.0L#</mathjax> of dihydrogen), <mathjax>#10.0L#</mathjax> of ammonia gas will result.</p> <p>Of course, practically, we will get nothing like quantitative reaction, and the reaction is an equilibrium that must be manipulated. The one thing this reaction has got going for it is that the product, the ammonia, is condensable, and highly soluble in water, whereas the reactants are quite volatile gases. </p> <p>Dinitrogen reduction is regarded as the most important reaction performed on the planet. Why?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">In the reaction #N_2 + 3H_2 -> 2NH_3#, what volume of ammonia is produced when 5.0 L of Nitrogen react?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-reactions-and-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions and Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="370539" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-01-28T20:08:18" itemprop="dateCreated"> Jan 28, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We follow the <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>.........<mathjax>#10L#</mathjax> of ammonia will result. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The stoichiometrically balanced equation, which you have written is:</p> <p><mathjax>#N_2(g)+3H_2(g) rightleftharpoons 2NH_3(g)#</mathjax></p> <p>Given constant temperature and pressure, which we must assume, volume is proportional to the number of moles. And thus if <mathjax>#5.0L#</mathjax> of dinitrogen react (with <mathjax>#15.0L#</mathjax> of dihydrogen), <mathjax>#10.0L#</mathjax> of ammonia gas will result.</p> <p>Of course, practically, we will get nothing like quantitative reaction, and the reaction is an equilibrium that must be manipulated. The one thing this reaction has got going for it is that the product, the ammonia, is condensable, and highly soluble in water, whereas the reactants are quite volatile gases. </p> <p>Dinitrogen reduction is regarded as the most important reaction performed on the planet. Why?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/370539" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb002bf34694a4fee47"> Question #fee47 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb402bf34694c8c5c15"> Question #c5c15 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb802bf346950519eb9"> Question #19eb9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cbf02bf3469570e2ea2"> Question #e2ea2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc002bf34695a6bc751"> Question #bc751 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc202bf3469570e2ea6"> Question #e2ea6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531e867a02bf342492a08b07"> Question #08b07 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-thermochemical-equation-for-the-combustion-of-benzene"> What is the thermochemical equation for the combustion of benzene? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-reversible"> Why are chemical reactions reversible? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-important"> Why are chemical reactions important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/chemical-reactions-and-equations"> See all questions in Chemical Reactions and Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2900 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	In the reaction #N_2 + 3H_2 -> 2NH_3#, what volume of ammonia is produced when 5.0 L of Nitrogen react?	null
933	a99c5d39-6ddd-11ea-8d0a-ccda262736ce	https://socratic.org/questions/a-100-ml-test-portion-from-a-mining-site-requires-9-62-ml-of-0-000169m-ag-titran	423 mg/L	start physical_unit 29 29 concentration mg/l qc_end physical_unit 3 4 1 2 volume qc_end physical_unit 15 16 10 11 volume qc_end physical_unit 15 16 13 15 concentration qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Concentration [OF] CN- [IN] mg/L"}]	[{"type":"physical unit","value":"423 mg/L"}]	[{"type":"physical unit","value":"Volume [OF] test portion [=] \\pu{100 ml}"},{"type":"physical unit","value":"Volume [OF] Ag+ titrant [=] \\pu{9.62 mL}"},{"type":"physical unit","value":"Concentration [OF] Ag+ titrant [=] \\pu{0.000169 M Ag+}"},{"type":"other","value":"Reach the endpoint."}]	<h1 class="questionTitle" itemprop="name">A 100 ml test portion from a mining site requires 9.62 mL of 0.000169M Ag+ titrant to reach the endpoint using the reaction described above. What is the CN^-1 concentration in this water sample?</h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>Thank you. </p></div> </h2> </div> </div>	423 mg/L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>This appears to be a titration of cyanide ion with silver nitrate solution.</p> <p>You use a 5-(<em>p</em>-dimethylaminobenzylidine)rhodanine indicator and titrate to the first colour change from yellowish-brown to a pink ("salmon") colour.</p> <blockquote></blockquote> <p>The equation for the reaction is</p> <p><mathjax>#"Ag"^+"(aq) + CN"^"⁻" "(aq)" → "AgCN(s)"#</mathjax></p> <blockquote></blockquote> <p>The conversions involved are</p> <p><mathjax>#"Volume of Ag"^+ → "moles of Ag"^+ → "moles of CN"^"⁻" → "mass of CN"^"⁻" → "concentration of CN"^"⁻"#</mathjax></p> <blockquote></blockquote> <p><strong>1. Moles of <mathjax>#"Ag"^+#</mathjax></strong></p> <p><mathjax>#"Moles of Ag"^+ = 9.62 color(red)(cancel(color(black)("mL Ag"^+))) × ("0.169 mmol Ag"^+)/(1 color(red)(cancel(color(black)("mL Ag"^+)))) = "1.626 mmol Ag"^+#</mathjax></p> <blockquote></blockquote> <p><strong>2. Moles of <mathjax># "CN"^"⁻"#</mathjax></strong></p> <p><mathjax>#"Moles of CN"^"⁻" = 1.626 color(red)(cancel(color(black)("mmol Ag"^+))) × ("1 mmol CN"^"⁻")/(1 color(red)(cancel(color(black)("mmol Ag"^+)))) = "1.626 mmol CN"^"⁻"#</mathjax></p> <blockquote></blockquote> <p><strong>3. Mass of <mathjax>#"CN"^"⁻"#</mathjax></strong></p> <p><mathjax>#"Mass of CN"^"⁻" = 1.626 color(red)(cancel(color(black)("mmol CN"^"⁻"))) ×("26.02 mg CN"^"⁻")/(1color(red)(cancel(color(black)("mmol CN"^"⁻")))) ="42.30 mg CN"^"⁻"#</mathjax></p> <blockquote></blockquote> <p><strong>4. Concentration of <mathjax>#"CN"^"⁻"#</mathjax> in test portion</strong></p> <p><mathjax>#["CN"^"⁻"] = "42.30 mg"/"0.100 L" = "423 mg/L"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The concentration of <mathjax>#"CN"^"⁻"#</mathjax> is <strong>423 mg/L</strong>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>This appears to be a titration of cyanide ion with silver nitrate solution.</p> <p>You use a 5-(<em>p</em>-dimethylaminobenzylidine)rhodanine indicator and titrate to the first colour change from yellowish-brown to a pink ("salmon") colour.</p> <blockquote></blockquote> <p>The equation for the reaction is</p> <p><mathjax>#"Ag"^+"(aq) + CN"^"⁻" "(aq)" → "AgCN(s)"#</mathjax></p> <blockquote></blockquote> <p>The conversions involved are</p> <p><mathjax>#"Volume of Ag"^+ → "moles of Ag"^+ → "moles of CN"^"⁻" → "mass of CN"^"⁻" → "concentration of CN"^"⁻"#</mathjax></p> <blockquote></blockquote> <p><strong>1. Moles of <mathjax>#"Ag"^+#</mathjax></strong></p> <p><mathjax>#"Moles of Ag"^+ = 9.62 color(red)(cancel(color(black)("mL Ag"^+))) × ("0.169 mmol Ag"^+)/(1 color(red)(cancel(color(black)("mL Ag"^+)))) = "1.626 mmol Ag"^+#</mathjax></p> <blockquote></blockquote> <p><strong>2. Moles of <mathjax># "CN"^"⁻"#</mathjax></strong></p> <p><mathjax>#"Moles of CN"^"⁻" = 1.626 color(red)(cancel(color(black)("mmol Ag"^+))) × ("1 mmol CN"^"⁻")/(1 color(red)(cancel(color(black)("mmol Ag"^+)))) = "1.626 mmol CN"^"⁻"#</mathjax></p> <blockquote></blockquote> <p><strong>3. Mass of <mathjax>#"CN"^"⁻"#</mathjax></strong></p> <p><mathjax>#"Mass of CN"^"⁻" = 1.626 color(red)(cancel(color(black)("mmol CN"^"⁻"))) ×("26.02 mg CN"^"⁻")/(1color(red)(cancel(color(black)("mmol CN"^"⁻")))) ="42.30 mg CN"^"⁻"#</mathjax></p> <blockquote></blockquote> <p><strong>4. Concentration of <mathjax>#"CN"^"⁻"#</mathjax> in test portion</strong></p> <p><mathjax>#["CN"^"⁻"] = "42.30 mg"/"0.100 L" = "423 mg/L"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A 100 ml test portion from a mining site requires 9.62 mL of 0.000169M Ag+ titrant to reach the endpoint using the reaction described above. What is the CN^-1 concentration in this water sample?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>Thank you. </p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#reactions-in-solution" itemprop="url"> <span class="breadcrumb" itemprop="title">Reactions in Solution</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/reactions-in-solution/reactions-between-ions-in-solutions" itemprop="url"> <span class="breadcrumb" itemprop="title">Reactions Between Ions in Solutions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="255511" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-04-18T00:32:01" itemprop="dateCreated"> Apr 18, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The concentration of <mathjax>#"CN"^"⁻"#</mathjax> is <strong>423 mg/L</strong>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>This appears to be a titration of cyanide ion with silver nitrate solution.</p> <p>You use a 5-(<em>p</em>-dimethylaminobenzylidine)rhodanine indicator and titrate to the first colour change from yellowish-brown to a pink ("salmon") colour.</p> <blockquote></blockquote> <p>The equation for the reaction is</p> <p><mathjax>#"Ag"^+"(aq) + CN"^"⁻" "(aq)" → "AgCN(s)"#</mathjax></p> <blockquote></blockquote> <p>The conversions involved are</p> <p><mathjax>#"Volume of Ag"^+ → "moles of Ag"^+ → "moles of CN"^"⁻" → "mass of CN"^"⁻" → "concentration of CN"^"⁻"#</mathjax></p> <blockquote></blockquote> <p><strong>1. Moles of <mathjax>#"Ag"^+#</mathjax></strong></p> <p><mathjax>#"Moles of Ag"^+ = 9.62 color(red)(cancel(color(black)("mL Ag"^+))) × ("0.169 mmol Ag"^+)/(1 color(red)(cancel(color(black)("mL Ag"^+)))) = "1.626 mmol Ag"^+#</mathjax></p> <blockquote></blockquote> <p><strong>2. Moles of <mathjax># "CN"^"⁻"#</mathjax></strong></p> <p><mathjax>#"Moles of CN"^"⁻" = 1.626 color(red)(cancel(color(black)("mmol Ag"^+))) × ("1 mmol CN"^"⁻")/(1 color(red)(cancel(color(black)("mmol Ag"^+)))) = "1.626 mmol CN"^"⁻"#</mathjax></p> <blockquote></blockquote> <p><strong>3. Mass of <mathjax>#"CN"^"⁻"#</mathjax></strong></p> <p><mathjax>#"Mass of CN"^"⁻" = 1.626 color(red)(cancel(color(black)("mmol CN"^"⁻"))) ×("26.02 mg CN"^"⁻")/(1color(red)(cancel(color(black)("mmol CN"^"⁻")))) ="42.30 mg CN"^"⁻"#</mathjax></p> <blockquote></blockquote> <p><strong>4. Concentration of <mathjax>#"CN"^"⁻"#</mathjax> in test portion</strong></p> <p><mathjax>#["CN"^"⁻"] = "42.30 mg"/"0.100 L" = "423 mg/L"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/255511" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-ions-are-present-in-solutions-of-sodium-hydroxide"> What ions are present in solutions of sodium hydroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-orange-juice-considered-a-solution-doesn-t-it-have-pulp-in-it-so-its-a-su"> Why is orange juice considered a solution? 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What is the CN^-1 concentration in this water sample?	Thank you.
934	ab230f6e-6ddd-11ea-9047-ccda262736ce	https://socratic.org/questions/5904bbf47c01493dd44dcb3d	4.86 g	start physical_unit 20 21 mass g qc_end physical_unit 6 7 2 3 mass qc_end physical_unit 14 15 10 11 mass qc_end end	[{"type":"physical unit","value":"Mass [OF] potassium chlorate [IN] g"}]	[{"type":"physical unit","value":"4.86 g"}]	[{"type":"physical unit","value":"Mass [OF] potassium chloride [=] \\pu{2.96 g}"},{"type":"physical unit","value":"Mass [OF] dioxygen gas [=] \\pu{1.92 g}"}]	<h1 class="questionTitle" itemprop="name">If a #2.96g# mass of potassium chloride, and a #1.92g# mass of dioxygen gas react, what mass of #"potassium chlorate"# results?</h1>	null	4.86 g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>There are <mathjax>#xg#</mathjax> <mathjax>#KClO_3#</mathjax>...........</p> <p>And we recover <mathjax>#(2.96g)/(74.55gmol^-1)=0.0397mol#</mathjax> with respect to <mathjax>#KCl#</mathjax>. </p> <p>And <mathjax>#(1.92g)/(15.999gmol^-1)=0.120mol#</mathjax> with respect to <mathjax>#"oxygen"#</mathjax>. </p> <p>Clearly, there were <mathjax>#0.0397#</mathjax> <mathjax>#"mol"#</mathjax> with respect to <mathjax>#KClO_3#</mathjax>.</p> <p>And thus <mathjax>#x#</mathjax>, <mathjax>#"mass of potassium chlorate"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.0397molxx122.55gmol^-1=4.86*g#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#x<=............5g#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>There are <mathjax>#xg#</mathjax> <mathjax>#KClO_3#</mathjax>...........</p> <p>And we recover <mathjax>#(2.96g)/(74.55gmol^-1)=0.0397mol#</mathjax> with respect to <mathjax>#KCl#</mathjax>. </p> <p>And <mathjax>#(1.92g)/(15.999gmol^-1)=0.120mol#</mathjax> with respect to <mathjax>#"oxygen"#</mathjax>. </p> <p>Clearly, there were <mathjax>#0.0397#</mathjax> <mathjax>#"mol"#</mathjax> with respect to <mathjax>#KClO_3#</mathjax>.</p> <p>And thus <mathjax>#x#</mathjax>, <mathjax>#"mass of potassium chlorate"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.0397molxx122.55gmol^-1=4.86g#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">If a #2.96g# mass of potassium chloride, and a #1.92g# mass of dioxygen gas react, what mass of #"potassium chlorate"# results?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/determining-formula-and-molar-masses" itemprop="url"> <span class="breadcrumb" itemprop="title">Determining Formula</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="414909" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-29T16:51:46" itemprop="dateCreated"> Apr 29, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#x<=............5g#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>There are <mathjax>#xg#</mathjax> <mathjax>#KClO_3#</mathjax>...........</p> <p>And we recover <mathjax>#(2.96g)/(74.55gmol^-1)=0.0397mol#</mathjax> with respect to <mathjax>#KCl#</mathjax>. </p> <p>And <mathjax>#(1.92g)/(15.999gmol^-1)=0.120mol#</mathjax> with respect to <mathjax>#"oxygen"#</mathjax>. </p> <p>Clearly, there were <mathjax>#0.0397#</mathjax> <mathjax>#"mol"#</mathjax> with respect to <mathjax>#KClO_3#</mathjax>.</p> <p>And thus <mathjax>#x#</mathjax>, <mathjax>#"mass of potassium chlorate"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.0397molxx122.55gmol^-1=4.86g#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/414909" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-it-possible-to-find-a-molecular-formula-from-molar-mass"> Is it possible to find a molecular formula from molar mass? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5368e0cc02bf34779e175781"> Question #75781 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" 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class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/determining-formula-and-molar-masses"> See all questions in Determining Formula </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1276 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	If a #2.96g# mass of potassium chloride, and a #1.92g# mass of dioxygen gas react, what mass of #"potassium chlorate"# results?	null
935	a84a9a70-6ddd-11ea-8275-ccda262736ce	https://socratic.org/questions/what-is-the-final-temperature-after-840-j-is-absorbed-by-10-0-g-of-water-at-25-c	45 ℃	start physical_unit 14 14 temperature °c qc_end physical_unit 14 14 11 12 mass qc_end physical_unit 14 14 6 7 heat_energy qc_end physical_unit 14 14 16 17 temperature qc_end end	[{"type":"physical unit","value":"Temperature2 [OF] water [IN] ℃"}]	[{"type":"physical unit","value":"45 ℃"}]	[{"type":"physical unit","value":"Mass [OF] water [=] \\pu{10.0 g}"},{"type":"physical unit","value":"Absorberd heat [OF] water [=] \\pu{840 J}"},{"type":"physical unit","value":"Temperature1 [OF] water [=] \\pu{25 ℃}"}]	<h1 class="questionTitle" itemprop="name">What is the final temperature after 840 J is absorbed by 10.0 g of water at 25°C?</h1>	null	45 ℃	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We have the amount of energy gain<br/> <mathjax>#Q=mcDeltaT=mcDeltat#</mathjax></p> <p>where <mathjax>#c#</mathjax> = <mathjax>#4.184#</mathjax> <mathjax>#J#</mathjax>/<mathjax>#g.C#</mathjax> is the <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> of water, <mathjax>#m#</mathjax> is the mass of water</p> <p><mathjax>#=>#</mathjax><mathjax>#840=10#</mathjax> x <mathjax>#4.184*(t-25)#</mathjax><br/> <mathjax>#t=840/(10" x "4.184)+25=45#</mathjax> i.e. <mathjax>#45^@#</mathjax> <mathjax>#C#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The final temperature is equal to <mathjax>#45^@#</mathjax> <mathjax>#C#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We have the amount of energy gain<br/> <mathjax>#Q=mcDeltaT=mcDeltat#</mathjax></p> <p>where <mathjax>#c#</mathjax> = <mathjax>#4.184#</mathjax> <mathjax>#J#</mathjax>/<mathjax>#g.C#</mathjax> is the <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> of water, <mathjax>#m#</mathjax> is the mass of water</p> <p><mathjax>#=>#</mathjax><mathjax>#840=10#</mathjax> x <mathjax>#4.184*(t-25)#</mathjax><br/> <mathjax>#t=840/(10" x "4.184)+25=45#</mathjax> i.e. <mathjax>#45^@#</mathjax> <mathjax>#C#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the final temperature after 840 J is absorbed by 10.0 g of water at 25°C?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/calorimetry" itemprop="url"> <span class="breadcrumb" itemprop="title">Calorimetry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="265906" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/hoa-t"><img alt="" class="" src="https://graph.facebook.com/188157278233218/picture?height=50&width=50" title=""/></a> <a class="secondContributorPic" href="/users/grace-9"><img alt="" class="" src="https://profilepictures.socratic.org/gzi0U3RQNuMSxgKVeKgw_10960213_10153434463490909_9111641440892052754_o.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/hoa-t"> Dang Thi ThanhHoa </a>·<a class="topContributorLink" href="/users/grace-9"> Grace </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-15T03:40:29" itemprop="dateCreated"> May 15, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The final temperature is equal to <mathjax>#45^@#</mathjax> <mathjax>#C#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We have the amount of energy gain<br/> <mathjax>#Q=mcDeltaT=mcDeltat#</mathjax></p> <p>where <mathjax>#c#</mathjax> = <mathjax>#4.184#</mathjax> <mathjax>#J#</mathjax>/<mathjax>#g.C#</mathjax> is the <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> of water, <mathjax>#m#</mathjax> is the mass of water</p> <p><mathjax>#=>#</mathjax><mathjax>#840=10#</mathjax> x <mathjax>#4.184*(t-25)#</mathjax><br/> <mathjax>#t=840/(10" x "4.184)+25=45#</mathjax> i.e. <mathjax>#45^@#</mathjax> <mathjax>#C#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/265906" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-differential-scanning-in-calorimetry-work"> How does differential scanning in calorimetry work? </a> 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clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 25634 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the final temperature after 840 J is absorbed by 10.0 g of water at 25°C?	null
936	acf53a07-6ddd-11ea-a475-ccda262736ce	https://socratic.org/questions/how-many-moles-of-nacl-are-present-in-500-ml-of-a-1-55-nacl-solution	0.78 moles	start physical_unit 4 4 mole mol qc_end physical_unit 14 15 8 9 volume qc_end physical_unit 14 15 12 13 molarity qc_end end	[{"type":"physical unit","value":"Mole [OF] NaCl [IN] moles"}]	[{"type":"physical unit","value":"0.78 moles"}]	[{"type":"physical unit","value":"Volume [OF] NaCl solution [=] \\pu{500 mL}"},{"type":"physical unit","value":"Molarity [OF] NaCl solution [=] \\pu{1.55 M}"}]	<h1 class="questionTitle" itemprop="name">How many moles of #NaCl# are present in 500 mL of a 1.55 #NaCl# solution?</h1>	null	0.78 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Molarity" = "moles of solute"/"Liters of solution"#</mathjax></p> <p>First, we need to convert <mathjax>#"500 mL"#</mathjax> to Liters</p> <p><mathjax>#"500 ml" * "1 L"/"1000 ml" = ".5 L"#</mathjax></p> <p>Now we can plug into our formula</p> <p><mathjax>#"1.55M" = "moles"/".5"#</mathjax></p> <p><mathjax>#"moles = 0.775 moles of NaCl"#</mathjax></p> <p>Hope it was helpful!</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a>= moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a>/Liters of solution</p> <p><mathjax>#"1.55 M" = "moles"/".5"#</mathjax></p> <p><mathjax>#"moles = 0.775 moles of NaCl"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Molarity" = "moles of solute"/"Liters of solution"#</mathjax></p> <p>First, we need to convert <mathjax>#"500 mL"#</mathjax> to Liters</p> <p><mathjax>#"500 ml" * "1 L"/"1000 ml" = ".5 L"#</mathjax></p> <p>Now we can plug into our formula</p> <p><mathjax>#"1.55M" = "moles"/".5"#</mathjax></p> <p><mathjax>#"moles = 0.775 moles of NaCl"#</mathjax></p> <p>Hope it was helpful!</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles of #NaCl# are present in 500 mL of a 1.55 #NaCl# solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="406289" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/mayya-g"><img alt="" class="" src="https://lh3.googleusercontent.com/-Zy8KwpvB5Sg/AAAAAAAAAAI/AAAAAAAAAA4/f-dEHTNn9fs/photo.jpg?sz=50" title=""/></a> <a class="secondContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/mayya-g"> mayya g. </a>·<a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-13T14:10:05" itemprop="dateCreated"> Apr 13, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a>= moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a>/Liters of solution</p> <p><mathjax>#"1.55 M" = "moles"/".5"#</mathjax></p> <p><mathjax>#"moles = 0.775 moles of NaCl"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Molarity" = "moles of solute"/"Liters of solution"#</mathjax></p> <p>First, we need to convert <mathjax>#"500 mL"#</mathjax> to Liters</p> <p><mathjax>#"500 ml" * "1 L"/"1000 ml" = ".5 L"#</mathjax></p> <p>Now we can plug into our formula</p> <p><mathjax>#"1.55M" = "moles"/".5"#</mathjax></p> <p><mathjax>#"moles = 0.775 moles of NaCl"#</mathjax></p> <p>Hope it was helpful!</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/406289" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" 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</div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 47395 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many moles of #NaCl# are present in 500 mL of a 1.55 #NaCl# solution?	null
937	a8aec1b0-6ddd-11ea-8bfd-ccda262736ce	https://socratic.org/questions/a-compound-formed-of-0-059-mol-hydrogen-and-0-94-mol-oxygen-has-a-molecular-mass	H2O2	start chemical_formula qc_end physical_unit 6 6 4 5 mole qc_end physical_unit 10 10 8 9 mole qc_end physical_unit 0 1 16 17 molecular_weight qc_end end	[{"type":"other","value":"Chemical Formula [OF] this compound [IN] molecular"}]	[{"type":"chemical equation","value":"H2O2"}]	[{"type":"physical unit","value":"Mole [OF] hydrogen [=] \\pu{0.059 mol}"},{"type":"physical unit","value":"Mole [OF] oxygen [=] \\pu{0.94 mol}"},{"type":"physical unit","value":"Molecular mass [OF] A compound [=] \\pu{34.0 g/mole}"}]	<h1 class="questionTitle" itemprop="name">A compound formed of 0.059 mol hydrogen and 0.94 mol oxygen has a molecular mass of 34.0 g/mole. What is the molecular formula of this compound?</h1>	null	H2O2	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>As it turns out, the values given to you for the number of moles of hydrogen and oxygen present in a sample of this unknown compound are <em><strong>incorrect</strong></em>. More on that further down the page. </p> <p>However, you can actually find the <strong>molecular formula</strong> of this compound <em>without</em> finding its <em>empirical formula</em> first, all you really need here is a <strong><a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">periodic table</a></strong>. </p> <p>So, the problem tells you that this unknown compound contains two <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a>, hydrogen, <mathjax>#"H"#</mathjax>, and oxygen, <mathjax>#"O"#</mathjax>, and that it has a <strong>molar mass</strong> of <mathjax>#"34.0 g mol"^(-1)#</mathjax>. </p> <p>As you know, a compound's molar mass tells you the mass of exactly <strong>one mole</strong> of said compound. In this case, <strong>one mole</strong> of your unknown compound will have a mass of <mathjax>#"34.0 g"#</mathjax>. </p> <p>Now, take a look in <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a> and make a note of the <strong>molar masses</strong> of hydrogen and oxygen </p> <blockquote> <p><mathjax>#"For H: " M_M = "1.00794 g mol"^(-1)#</mathjax></p> <p><mathjax>#"For O: " M_M = "15.9994 g mol"^(-1)#</mathjax></p> </blockquote> <p>Notice that <strong>one mole</strong> of oxygen has a mass of <mathjax>#"15.9994 g"#</mathjax>, which means that you can only have <strong>two moles</strong> of oxygen <em>per mole</em> of your unknown compound. </p> <p>That is, <strong>one mole</strong> of your compound can contain a maximum number of <strong>two moles</strong> of oxygen, since you have </p> <blockquote> <p><mathjax>#2 color(red)(cancel(color(black)("moles"))) xx "15.9994 g" color(red)(cancel(color(black)("mol"^(-1)))) < "34.0 g" color(white)(a)color(green)(sqrt())#</mathjax></p> <p><mathjax>#3 color(red)(cancel(color(black)("moles"))) xx "15.9994 g" color(red)(cancel(color(black)("mol"^(-1)))) > "34.0 g"color(white)(a)color(red)(xx)#</mathjax></p> </blockquote> <p>The compound <strong>cannot</strong> have one mole of oxygen per mole because the difference between the mass of one mole of oxygen and the mass of one mole of the compound <strong>cannot</strong> be accounted for by the hydrogen. </p> <p>Why? Because you can't possibly form bonds between one mole of oxygen and approximately <mathjax>#18#</mathjax> moles of hydrogen, the number of moles of hydrogen you'd need to get a mass of </p> <blockquote> <p><mathjax>#"34.0 g " - " 15.9994 g" = "18.0006 g"#</mathjax></p> </blockquote> <p>So, <strong>one mole</strong> of your unknown compound contains <strong>two moles</strong> of oxygen. The mass of hydrogen <strong>per mole</strong> of compound will be </p> <blockquote> <p><mathjax>#"34.0 g " - 2 color(red)(cancel(color(black)("moles O"))) * "15.9994 g"/(1color(red)(cancel(color(black)("mole O")))) = "2.0012 g"#</mathjax></p> </blockquote> <p>This is equivalent to </p> <blockquote> <p><mathjax>#2.0012 color(red)(cancel(color(black)("g"))) * "1 mole H"/(1.00794color(red)(cancel(color(black)("g")))) = 1.985 ~~ "2 moles H"#</mathjax></p> </blockquote> <p>Therefore, the compound's <strong>molecular formula</strong>, which tells you exactly how many moles of each constituent element you get <em>per mole</em> of the compound, will be </p> <blockquote> <p><mathjax>#"molecular formula" = color(green)(\|bar(ul(color(white)(a/a)"H"_2"O"_2color(white)(a/a)\|))) ->#</mathjax> <em><strong>hydrogen peroxide</strong></em></p> <blockquote> <blockquote> <p><img alt="http://chemwiki.ucdavis.edu/" src="https://useruploads.socratic.org/4AsCZlkDTLiofMdMHSTu_hydrogen-peroxide-diagram.png"/> </p> </blockquote> </blockquote> </blockquote> <p><mathjax>#color(white)(a)#</mathjax><br/> <strong>ALTERNATIVE APPROACH</strong></p> <p>Now, here's why I said that the values given to you for the number of moles of hydrogen and of oxygen are incorrect. To get the compound's empirical formula, find <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio that exists between the two elements in the compound.</p> <blockquote> <p><mathjax>#"For H: " (0.059 color(red)(cancel(color(black)("moles"))))/(0.059 color(red)(cancel(color(black)("moles")))) = 1#</mathjax></p> <p><mathjax>#"For O: "(0.94color(red)(cancel(color(black)("moles"))))/(0.059color(red)(cancel(color(black)("moles")))) = 15.93 ~~ 16#</mathjax></p> </blockquote> <p>This suggest that the <strong>smallest whole number ratio</strong> that exists between the two elements is <mathjax>#1:16#</mathjax>. This cannot be true because you know that <strong>one mole</strong> of this unknown compound has a mass of <mathjax>#"34.0 g"#</mathjax>. </p> <p>You cannot possible have <strong>more than two moles</strong> of oxygen <em>per mole</em> of this unknown compound. </p> <p>Now, the problem would make sense like this </p> <blockquote> <blockquote> <p><em>A compound formed of 0.059 moles of hydrogen and 0.094 <strong>grams</strong> of oxygen has a molecular mass of 34.0 g/mol</em>.</p> </blockquote> </blockquote> <p>In this case, you'd have </p> <blockquote> <p><mathjax>#0.94 color(red)(cancel(color(black)("g"))) * "1 mole O"/(15.9994 color(red)(cancel(color(black)("g")))) = "0.05875 moles O"#</mathjax></p> </blockquote> <p>You would now have </p> <blockquote> <p><mathjax>#"For H: " (0.059 color(red)(cancel(color(black)("moles"))))/(0.05875 color(red)(cancel(color(black)("moles")))) = 1.004 ~~ 1#</mathjax></p> <p><mathjax>#"For O: " (0.05875color(red)(cancel(color(black)("moles"))))/(0.05875 color(red)(cancel(color(black)("moles")))) = 1#</mathjax></p> </blockquote> <p>The empirical formula would be </p> <blockquote> <p><mathjax>#color(green)(\|bar(ul(color(white)(a/a)"H"_1"O"_1 implies "HO"color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The molar mass of the <em>empirical formula</em> would be </p> <blockquote> <p><mathjax>#1 xx "1.00794 g mol"^(-1) + 1 xx "15.9994 g mol"^(-1) = "17.007 g mol"^(-1)#</mathjax></p> </blockquote> <p>This means that you will have </p> <blockquote> <p><mathjax>#17.007 color(red)(cancel(color(black)("g mol"^(-1)))) xx color(blue)(n) = 34.0 color(red)(cancel(color(black)("g mol"^(-1))))#</mathjax></p> <p><mathjax>#color(blue)(n) = 34.0/17.007 = 1.9992 ~~ 2#</mathjax></p> </blockquote> <p>Therefore, the compound's <strong>molecular formula</strong> will once again be </p> <blockquote> <p><mathjax>#("HO")_color(blue)(2) = color(green)(\|bar(ul(color(white)(a/a)"H"_2"O"_2color(white)(a/a)\|)))#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"H"_2"O"_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>As it turns out, the values given to you for the number of moles of hydrogen and oxygen present in a sample of this unknown compound are <em><strong>incorrect</strong></em>. More on that further down the page. </p> <p>However, you can actually find the <strong>molecular formula</strong> of this compound <em>without</em> finding its <em>empirical formula</em> first, all you really need here is a <strong><a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">periodic table</a></strong>. </p> <p>So, the problem tells you that this unknown compound contains two <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a>, hydrogen, <mathjax>#"H"#</mathjax>, and oxygen, <mathjax>#"O"#</mathjax>, and that it has a <strong>molar mass</strong> of <mathjax>#"34.0 g mol"^(-1)#</mathjax>. </p> <p>As you know, a compound's molar mass tells you the mass of exactly <strong>one mole</strong> of said compound. In this case, <strong>one mole</strong> of your unknown compound will have a mass of <mathjax>#"34.0 g"#</mathjax>. </p> <p>Now, take a look in <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a> and make a note of the <strong>molar masses</strong> of hydrogen and oxygen </p> <blockquote> <p><mathjax>#"For H: " M_M = "1.00794 g mol"^(-1)#</mathjax></p> <p><mathjax>#"For O: " M_M = "15.9994 g mol"^(-1)#</mathjax></p> </blockquote> <p>Notice that <strong>one mole</strong> of oxygen has a mass of <mathjax>#"15.9994 g"#</mathjax>, which means that you can only have <strong>two moles</strong> of oxygen <em>per mole</em> of your unknown compound. </p> <p>That is, <strong>one mole</strong> of your compound can contain a maximum number of <strong>two moles</strong> of oxygen, since you have </p> <blockquote> <p><mathjax>#2 color(red)(cancel(color(black)("moles"))) xx "15.9994 g" color(red)(cancel(color(black)("mol"^(-1)))) < "34.0 g" color(white)(a)color(green)(sqrt())#</mathjax></p> <p><mathjax>#3 color(red)(cancel(color(black)("moles"))) xx "15.9994 g" color(red)(cancel(color(black)("mol"^(-1)))) > "34.0 g"color(white)(a)color(red)(xx)#</mathjax></p> </blockquote> <p>The compound <strong>cannot</strong> have one mole of oxygen per mole because the difference between the mass of one mole of oxygen and the mass of one mole of the compound <strong>cannot</strong> be accounted for by the hydrogen. </p> <p>Why? Because you can't possibly form bonds between one mole of oxygen and approximately <mathjax>#18#</mathjax> moles of hydrogen, the number of moles of hydrogen you'd need to get a mass of </p> <blockquote> <p><mathjax>#"34.0 g " - " 15.9994 g" = "18.0006 g"#</mathjax></p> </blockquote> <p>So, <strong>one mole</strong> of your unknown compound contains <strong>two moles</strong> of oxygen. The mass of hydrogen <strong>per mole</strong> of compound will be </p> <blockquote> <p><mathjax>#"34.0 g " - 2 color(red)(cancel(color(black)("moles O"))) * "15.9994 g"/(1color(red)(cancel(color(black)("mole O")))) = "2.0012 g"#</mathjax></p> </blockquote> <p>This is equivalent to </p> <blockquote> <p><mathjax>#2.0012 color(red)(cancel(color(black)("g"))) * "1 mole H"/(1.00794color(red)(cancel(color(black)("g")))) = 1.985 ~~ "2 moles H"#</mathjax></p> </blockquote> <p>Therefore, the compound's <strong>molecular formula</strong>, which tells you exactly how many moles of each constituent element you get <em>per mole</em> of the compound, will be </p> <blockquote> <p><mathjax>#"molecular formula" = color(green)(\|bar(ul(color(white)(a/a)"H"_2"O"_2color(white)(a/a)\|))) ->#</mathjax> <em><strong>hydrogen peroxide</strong></em></p> <blockquote> <blockquote> <p><img alt="http://chemwiki.ucdavis.edu/" src="https://useruploads.socratic.org/4AsCZlkDTLiofMdMHSTu_hydrogen-peroxide-diagram.png"/> </p> </blockquote> </blockquote> </blockquote> <p><mathjax>#color(white)(a)#</mathjax><br/> <strong>ALTERNATIVE APPROACH</strong></p> <p>Now, here's why I said that the values given to you for the number of moles of hydrogen and of oxygen are incorrect. To get the compound's empirical formula, find <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio that exists between the two elements in the compound.</p> <blockquote> <p><mathjax>#"For H: " (0.059 color(red)(cancel(color(black)("moles"))))/(0.059 color(red)(cancel(color(black)("moles")))) = 1#</mathjax></p> <p><mathjax>#"For O: "(0.94color(red)(cancel(color(black)("moles"))))/(0.059color(red)(cancel(color(black)("moles")))) = 15.93 ~~ 16#</mathjax></p> </blockquote> <p>This suggest that the <strong>smallest whole number ratio</strong> that exists between the two elements is <mathjax>#1:16#</mathjax>. This cannot be true because you know that <strong>one mole</strong> of this unknown compound has a mass of <mathjax>#"34.0 g"#</mathjax>. </p> <p>You cannot possible have <strong>more than two moles</strong> of oxygen <em>per mole</em> of this unknown compound. </p> <p>Now, the problem would make sense like this </p> <blockquote> <blockquote> <p><em>A compound formed of 0.059 moles of hydrogen and 0.094 <strong>grams</strong> of oxygen has a molecular mass of 34.0 g/mol</em>.</p> </blockquote> </blockquote> <p>In this case, you'd have </p> <blockquote> <p><mathjax>#0.94 color(red)(cancel(color(black)("g"))) * "1 mole O"/(15.9994 color(red)(cancel(color(black)("g")))) = "0.05875 moles O"#</mathjax></p> </blockquote> <p>You would now have </p> <blockquote> <p><mathjax>#"For H: " (0.059 color(red)(cancel(color(black)("moles"))))/(0.05875 color(red)(cancel(color(black)("moles")))) = 1.004 ~~ 1#</mathjax></p> <p><mathjax>#"For O: " (0.05875color(red)(cancel(color(black)("moles"))))/(0.05875 color(red)(cancel(color(black)("moles")))) = 1#</mathjax></p> </blockquote> <p>The empirical formula would be </p> <blockquote> <p><mathjax>#color(green)(\|bar(ul(color(white)(a/a)"H"_1"O"_1 implies "HO"color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The molar mass of the <em>empirical formula</em> would be </p> <blockquote> <p><mathjax>#1 xx "1.00794 g mol"^(-1) + 1 xx "15.9994 g mol"^(-1) = "17.007 g mol"^(-1)#</mathjax></p> </blockquote> <p>This means that you will have </p> <blockquote> <p><mathjax>#17.007 color(red)(cancel(color(black)("g mol"^(-1)))) xx color(blue)(n) = 34.0 color(red)(cancel(color(black)("g mol"^(-1))))#</mathjax></p> <p><mathjax>#color(blue)(n) = 34.0/17.007 = 1.9992 ~~ 2#</mathjax></p> </blockquote> <p>Therefore, the compound's <strong>molecular formula</strong> will once again be </p> <blockquote> <p><mathjax>#("HO")_color(blue)(2) = color(green)(\|bar(ul(color(white)(a/a)"H"_2"O"_2color(white)(a/a)\|)))#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A compound formed of 0.059 mol hydrogen and 0.94 mol oxygen has a molecular mass of 34.0 g/mole. What is the molecular formula of this compound?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="258130" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-04-24T11:42:01" itemprop="dateCreated"> Apr 24, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"H"_2"O"_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>As it turns out, the values given to you for the number of moles of hydrogen and oxygen present in a sample of this unknown compound are <em><strong>incorrect</strong></em>. More on that further down the page. </p> <p>However, you can actually find the <strong>molecular formula</strong> of this compound <em>without</em> finding its <em>empirical formula</em> first, all you really need here is a <strong><a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">periodic table</a></strong>. </p> <p>So, the problem tells you that this unknown compound contains two <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a>, hydrogen, <mathjax>#"H"#</mathjax>, and oxygen, <mathjax>#"O"#</mathjax>, and that it has a <strong>molar mass</strong> of <mathjax>#"34.0 g mol"^(-1)#</mathjax>. </p> <p>As you know, a compound's molar mass tells you the mass of exactly <strong>one mole</strong> of said compound. In this case, <strong>one mole</strong> of your unknown compound will have a mass of <mathjax>#"34.0 g"#</mathjax>. </p> <p>Now, take a look in <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a> and make a note of the <strong>molar masses</strong> of hydrogen and oxygen </p> <blockquote> <p><mathjax>#"For H: " M_M = "1.00794 g mol"^(-1)#</mathjax></p> <p><mathjax>#"For O: " M_M = "15.9994 g mol"^(-1)#</mathjax></p> </blockquote> <p>Notice that <strong>one mole</strong> of oxygen has a mass of <mathjax>#"15.9994 g"#</mathjax>, which means that you can only have <strong>two moles</strong> of oxygen <em>per mole</em> of your unknown compound. </p> <p>That is, <strong>one mole</strong> of your compound can contain a maximum number of <strong>two moles</strong> of oxygen, since you have </p> <blockquote> <p><mathjax>#2 color(red)(cancel(color(black)("moles"))) xx "15.9994 g" color(red)(cancel(color(black)("mol"^(-1)))) < "34.0 g" color(white)(a)color(green)(sqrt())#</mathjax></p> <p><mathjax>#3 color(red)(cancel(color(black)("moles"))) xx "15.9994 g" color(red)(cancel(color(black)("mol"^(-1)))) > "34.0 g"color(white)(a)color(red)(xx)#</mathjax></p> </blockquote> <p>The compound <strong>cannot</strong> have one mole of oxygen per mole because the difference between the mass of one mole of oxygen and the mass of one mole of the compound <strong>cannot</strong> be accounted for by the hydrogen. </p> <p>Why? Because you can't possibly form bonds between one mole of oxygen and approximately <mathjax>#18#</mathjax> moles of hydrogen, the number of moles of hydrogen you'd need to get a mass of </p> <blockquote> <p><mathjax>#"34.0 g " - " 15.9994 g" = "18.0006 g"#</mathjax></p> </blockquote> <p>So, <strong>one mole</strong> of your unknown compound contains <strong>two moles</strong> of oxygen. The mass of hydrogen <strong>per mole</strong> of compound will be </p> <blockquote> <p><mathjax>#"34.0 g " - 2 color(red)(cancel(color(black)("moles O"))) * "15.9994 g"/(1color(red)(cancel(color(black)("mole O")))) = "2.0012 g"#</mathjax></p> </blockquote> <p>This is equivalent to </p> <blockquote> <p><mathjax>#2.0012 color(red)(cancel(color(black)("g"))) * "1 mole H"/(1.00794color(red)(cancel(color(black)("g")))) = 1.985 ~~ "2 moles H"#</mathjax></p> </blockquote> <p>Therefore, the compound's <strong>molecular formula</strong>, which tells you exactly how many moles of each constituent element you get <em>per mole</em> of the compound, will be </p> <blockquote> <p><mathjax>#"molecular formula" = color(green)(\|bar(ul(color(white)(a/a)"H"_2"O"_2color(white)(a/a)\|))) ->#</mathjax> <em><strong>hydrogen peroxide</strong></em></p> <blockquote> <blockquote> <p><img alt="http://chemwiki.ucdavis.edu/" src="https://useruploads.socratic.org/4AsCZlkDTLiofMdMHSTu_hydrogen-peroxide-diagram.png"/> </p> </blockquote> </blockquote> </blockquote> <p><mathjax>#color(white)(a)#</mathjax><br/> <strong>ALTERNATIVE APPROACH</strong></p> <p>Now, here's why I said that the values given to you for the number of moles of hydrogen and of oxygen are incorrect. To get the compound's empirical formula, find <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio that exists between the two elements in the compound.</p> <blockquote> <p><mathjax>#"For H: " (0.059 color(red)(cancel(color(black)("moles"))))/(0.059 color(red)(cancel(color(black)("moles")))) = 1#</mathjax></p> <p><mathjax>#"For O: "(0.94color(red)(cancel(color(black)("moles"))))/(0.059color(red)(cancel(color(black)("moles")))) = 15.93 ~~ 16#</mathjax></p> </blockquote> <p>This suggest that the <strong>smallest whole number ratio</strong> that exists between the two elements is <mathjax>#1:16#</mathjax>. This cannot be true because you know that <strong>one mole</strong> of this unknown compound has a mass of <mathjax>#"34.0 g"#</mathjax>. </p> <p>You cannot possible have <strong>more than two moles</strong> of oxygen <em>per mole</em> of this unknown compound. </p> <p>Now, the problem would make sense like this </p> <blockquote> <blockquote> <p><em>A compound formed of 0.059 moles of hydrogen and 0.094 <strong>grams</strong> of oxygen has a molecular mass of 34.0 g/mol</em>.</p> </blockquote> </blockquote> <p>In this case, you'd have </p> <blockquote> <p><mathjax>#0.94 color(red)(cancel(color(black)("g"))) * "1 mole O"/(15.9994 color(red)(cancel(color(black)("g")))) = "0.05875 moles O"#</mathjax></p> </blockquote> <p>You would now have </p> <blockquote> <p><mathjax>#"For H: " (0.059 color(red)(cancel(color(black)("moles"))))/(0.05875 color(red)(cancel(color(black)("moles")))) = 1.004 ~~ 1#</mathjax></p> <p><mathjax>#"For O: " (0.05875color(red)(cancel(color(black)("moles"))))/(0.05875 color(red)(cancel(color(black)("moles")))) = 1#</mathjax></p> </blockquote> <p>The empirical formula would be </p> <blockquote> <p><mathjax>#color(green)(\|bar(ul(color(white)(a/a)"H"_1"O"_1 implies "HO"color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The molar mass of the <em>empirical formula</em> would be </p> <blockquote> <p><mathjax>#1 xx "1.00794 g mol"^(-1) + 1 xx "15.9994 g mol"^(-1) = "17.007 g mol"^(-1)#</mathjax></p> </blockquote> <p>This means that you will have </p> <blockquote> <p><mathjax>#17.007 color(red)(cancel(color(black)("g mol"^(-1)))) xx color(blue)(n) = 34.0 color(red)(cancel(color(black)("g mol"^(-1))))#</mathjax></p> <p><mathjax>#color(blue)(n) = 34.0/17.007 = 1.9992 ~~ 2#</mathjax></p> </blockquote> <p>Therefore, the compound's <strong>molecular formula</strong> will once again be </p> <blockquote> <p><mathjax>#("HO")_color(blue)(2) = color(green)(\|bar(ul(color(white)(a/a)"H"_2"O"_2color(white)(a/a)\|)))#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/258130" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? 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What is the molecular formula of this compound?	null
938	ac2661ba-6ddd-11ea-bb8a-ccda262736ce	https://socratic.org/questions/what-is-the-chemical-formula-for-atp	C10H16N5O13P3	start chemical_formula qc_end chemical_equation 6 6 qc_end end	[{"type":"other","value":"Chemical Formula [OF] ATP [IN] default"}]	[{"type":"chemical equation","value":"C10H16N5O13P3"}]	[{"type":"chemical equation","value":"ATP"}]	<h1 class="questionTitle" itemprop="name">What is the chemical formula for ATP? </h1>	null	C10H16N5O13P3	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>ATP is adenosine triphosphate and is an energy molecule</p> <p>Its chemical formula is <mathjax>#C_10H_16N_5O_13P_3#</mathjax></p> <p><img alt="http://upload.wikimedia.org/" src="https://useruploads.socratic.org/8An472uxRa2G9qqcn0nM_ATP-Structure-300x148.jpg"/> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_10H_16N_5O_13P_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>ATP is adenosine triphosphate and is an energy molecule</p> <p>Its chemical formula is <mathjax>#C_10H_16N_5O_13P_3#</mathjax></p> <p><img alt="http://upload.wikimedia.org/" src="https://useruploads.socratic.org/8An472uxRa2G9qqcn0nM_ATP-Structure-300x148.jpg"/> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the chemical formula for ATP? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#organic-chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Organic Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/organic-chemistry/biochemical-molecules" itemprop="url"> <span class="breadcrumb" itemprop="title">Biochemical Molecules</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="620239" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/lucy-3"><img alt="" class="" src="https://profilepictures.socratic.org/KeyAay2ERSSf1kIznvBL_Swimmingfrog.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/lucy-3"> Lucy </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-05-25T23:51:27" itemprop="dateCreated"> May 25, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_10H_16N_5O_13P_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>ATP is adenosine triphosphate and is an energy molecule</p> <p>Its chemical formula is <mathjax>#C_10H_16N_5O_13P_3#</mathjax></p> <p><img alt="http://upload.wikimedia.org/" src="https://useruploads.socratic.org/8An472uxRa2G9qqcn0nM_ATP-Structure-300x148.jpg"/> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/620239" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-large-biochemical-molecules"> What are large biochemical molecules? 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939	ab4ca686-6ddd-11ea-b9b3-ccda262736ce	https://socratic.org/questions/599cc44a7c01495b8070d2c1	6.55 kJ	start physical_unit 9 9 heat_energy kj qc_end physical_unit 9 9 6 7 mass qc_end physical_unit 9 9 15 16 temperature qc_end physical_unit 9 9 20 23 specific_heat_capacity qc_end end	[{"type":"physical unit","value":"Absorbed heat [OF] water [IN] kJ"}]	[{"type":"physical unit","value":"6.55 kJ"}]	[{"type":"physical unit","value":"Mass [OF] water [=] \\pu{27 g}"},{"type":"physical unit","value":"Increased temperature [OF] water [=] \\pu{58 ℃}"},{"type":"physical unit","value":"c [OF] water [=] \\pu{4.184 J/(g * ℃)}"}]	<h1 class="questionTitle" itemprop="name">What is the heat absorbed by #"27 g"# of water that increases in temperature by #58^@ "C"#? Assume #c = "4.184 J/g"^@ "C"# for water in this temperature range.</h1>	null	6.55 kJ	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The heat <mathjax>#Q#</mathjax> for a given mass <mathjax>#m#</mathjax> of water with specific heat capacity <mathjax>#c = "4.184 J/g"^@ "C"#</mathjax> that increases in temperature by <mathjax>#58^@ "C"#</mathjax> is given by:</p> <blockquote> <p><mathjax>#Q = mcDeltaT#</mathjax></p> <p><mathjax>#= ("27 g") cdot ("4.184 J"//"g"^@"C")(58^@"C") = "6552 J"#</mathjax></p> <p><mathjax>#~~#</mathjax> <mathjax>#"6600 J"#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Q = "6600 Joules"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The heat <mathjax>#Q#</mathjax> for a given mass <mathjax>#m#</mathjax> of water with specific heat capacity <mathjax>#c = "4.184 J/g"^@ "C"#</mathjax> that increases in temperature by <mathjax>#58^@ "C"#</mathjax> is given by:</p> <blockquote> <p><mathjax>#Q = mcDeltaT#</mathjax></p> <p><mathjax>#= ("27 g") cdot ("4.184 J"//"g"^@"C")(58^@"C") = "6552 J"#</mathjax></p> <p><mathjax>#~~#</mathjax> <mathjax>#"6600 J"#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the heat absorbed by #"27 g"# of water that increases in temperature by #58^@ "C"#? Assume #c = "4.184 J/g"^@ "C"# for water in this temperature range.</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/calorimetry" itemprop="url"> <span class="breadcrumb" itemprop="title">Calorimetry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="467105" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/truong-son-n"><img alt="" class="" src="https://profilepictures.socratic.org/07k4plnQfmnmzMuesQzw_14844-1449381920.png" title=""/></a> <a class="secondContributorPic" href="/users/doc048"><img alt="" class="" src="https://profilepictures.socratic.org/e4gaeUMMQESTpfte6aRu_Friendly%20Chem%20Professor.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/truong-son-n"> Truong-Son N. </a>·<a class="topContributorLink" href="/users/doc048"> Doc048 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-23T01:39:23" itemprop="dateCreated"> Aug 23, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Q = "6600 Joules"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The heat <mathjax>#Q#</mathjax> for a given mass <mathjax>#m#</mathjax> of water with specific heat capacity <mathjax>#c = "4.184 J/g"^@ "C"#</mathjax> that increases in temperature by <mathjax>#58^@ "C"#</mathjax> is given by:</p> <blockquote> <p><mathjax>#Q = mcDeltaT#</mathjax></p> <p><mathjax>#= ("27 g") cdot ("4.184 J"//"g"^@"C")(58^@"C") = "6552 J"#</mathjax></p> <p><mathjax>#~~#</mathjax> <mathjax>#"6600 J"#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/467105" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-differential-scanning-in-calorimetry-work"> How does differential scanning in calorimetry work? 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Assume #c = "4.184 J/g"^@ "C"# for water in this temperature range.	null
940	aad3ffcd-6ddd-11ea-b521-ccda262736ce	https://socratic.org/questions/what-is-the-volume-of-45-grams-of-h-2-gas-at-stp	504.00 L	start physical_unit 8 9 volume l qc_end physical_unit 8 9 5 6 mass qc_end c_other STP qc_end end	[{"type":"physical unit","value":"Volume [OF] H2 gas [IN] L"}]	[{"type":"physical unit","value":"504.00 L"}]	[{"type":"physical unit","value":"Mass [OF] H2 gas [=] \\pu{45 grams}"},{"type":"other","value":"STP"}]	<h1 class="questionTitle" itemprop="name">What is the volume of 45 grams of #H_2# gas at STP?</h1>	null	504.00 L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>It is known that at STP, 1 mol of Ideal gas occupies a volume of <mathjax>#22.4#</mathjax> <mathjax>#L#</mathjax>.</p> <p>We assume, reasonably. that dihydrogen gas behaves ideally at STP.</p> <p>Thus <mathjax>#V#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(45cancelg)/(2cancelgcancel(mol^-1)) xx 22.4L*cancel(mol^-1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??L#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Volume" >500L#</mathjax>. We use the molar volume of an Ideal gas at STP.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>It is known that at STP, 1 mol of Ideal gas occupies a volume of <mathjax>#22.4#</mathjax> <mathjax>#L#</mathjax>.</p> <p>We assume, reasonably. that dihydrogen gas behaves ideally at STP.</p> <p>Thus <mathjax>#V#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(45cancelg)/(2cancelgcancel(mol^-1)) xx 22.4Lcancel(mol^-1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??L#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the volume of 45 grams of #H_2# gas at STP?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp" itemprop="url"> <span class="breadcrumb" itemprop="title">Molar Volume of a Gas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="248642" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-04-02T19:37:44" itemprop="dateCreated"> Apr 2, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Volume" >500L#</mathjax>. We use the molar volume of an Ideal gas at STP.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>It is known that at STP, 1 mol of Ideal gas occupies a volume of <mathjax>#22.4#</mathjax> <mathjax>#L#</mathjax>.</p> <p>We assume, reasonably. that dihydrogen gas behaves ideally at STP.</p> <p>Thus <mathjax>#V#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(45cancelg)/(2cancelgcancel(mol^-1)) xx 22.4Lcancel(mol^-1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??L#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/248642" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-stoichiometric-ratios-relate-to-molar-volume-of-a-gas"> How do stoichiometric ratios relate to molar volume of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-a-gas-at-stp"> How do you calculate molar volume of a gas at STP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-molar-volume-of-hydrogen-gas"> How do you find the molar volume of hydrogen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-oxygen-gas"> How do you calculate molar volume of oxygen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molar-gas-volume"> What is molar gas volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/534c7bf202bf3420a007f014"> What is the volume at 0 °C and 1 atm of a mixture that contains 4.0 g of methane and 2.0 g of helium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5361f75702bf3429040e0599"> What is the difference between STP and NTP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-volume-of-25-moles-of-oxygen-o2-gas"> What is the volume of .25 moles of oxygen (O2) Gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-would-knowing-the-molar-volume-of-a-gas-be-important"> Why would knowing the molar volume of a gas be important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-22-4-liters-called-the-molar-volume-of-a-gas"> Why is 22.4 liters called the molar volume of a gas? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp"> See all questions in Molar Volume of a Gas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1944 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the volume of 45 grams of #H_2# gas at STP?	null
941	aa48e8fa-6ddd-11ea-bc77-ccda262736ce	https://socratic.org/questions/how-do-you-calculate-the-ph-of-this-solution-h-8-3-x-10-10-m	9.08	start physical_unit 7 8 ph none qc_end physical_unit 7 8 11 14 [h+] qc_end end	[{"type":"physical unit","value":"pH [OF] this solution"}]	[{"type":"physical unit","value":"9.08"}]	[{"type":"physical unit","value":"[H+] [OF] this solution [=] \\pu{8.3 × 10^(-10) M}"}]	<h1 class="questionTitle" itemprop="name">How do you calculate the pH of this solution: #[H^+] = 8.3 xx 10^(-10)# M?</h1>	null	9.08	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The definition of <mathjax>#"pH"#</mathjax> is as follows:</p> <p><mathjax>#"pH" -= -log["H"^+]#</mathjax></p> <p>Assuming we have <mathjax>#["H"^+] = 8.3 xx 10^-10 "M"#</mathjax> as the only <mathjax>#"H"^(+)#</mathjax> in solution, </p> <blockquote> <p><mathjax>#"pH" = -log(8.3xx 10^-10) = 9.08#</mathjax>.</p> </blockquote> <p>As a rule of thumb, <mathjax>#"pH"#</mathjax> should be treated a dimensionless, meaning that it has no units.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"pH" = 9.08#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The definition of <mathjax>#"pH"#</mathjax> is as follows:</p> <p><mathjax>#"pH" -= -log["H"^+]#</mathjax></p> <p>Assuming we have <mathjax>#["H"^+] = 8.3 xx 10^-10 "M"#</mathjax> as the only <mathjax>#"H"^(+)#</mathjax> in solution, </p> <blockquote> <p><mathjax>#"pH" = -log(8.3xx 10^-10) = 9.08#</mathjax>.</p> </blockquote> <p>As a rule of thumb, <mathjax>#"pH"#</mathjax> should be treated a dimensionless, meaning that it has no units.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you calculate the pH of this solution: #[H^+] = 8.3 xx 10^(-10)# M?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/ph-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">pH calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="436837" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/abdur-r"><img alt="" class="" src="https://profilepictures.socratic.org/YXIUDMM0SoZAxTdY3kn6_niagara_falls_fog_water_height_6376_3840x2160.jpg" title=""/></a> <a class="secondContributorPic" href="/users/truong-son-n"><img alt="" class="" src="https://profilepictures.socratic.org/07k4plnQfmnmzMuesQzw_14844-1449381920.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/abdur-r"> Monzur R. </a>·<a class="topContributorLink" href="/users/truong-son-n"> Truong-Son N. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-09T01:05:19" itemprop="dateCreated"> Jun 9, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"pH" = 9.08#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The definition of <mathjax>#"pH"#</mathjax> is as follows:</p> <p><mathjax>#"pH" -= -log["H"^+]#</mathjax></p> <p>Assuming we have <mathjax>#["H"^+] = 8.3 xx 10^-10 "M"#</mathjax> as the only <mathjax>#"H"^(+)#</mathjax> in solution, </p> <blockquote> <p><mathjax>#"pH" = -log(8.3xx 10^-10) = 9.08#</mathjax>.</p> </blockquote> <p>As a rule of thumb, <mathjax>#"pH"#</mathjax> should be treated a dimensionless, meaning that it has no units.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/436837" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul 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</li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/ph-calculations"> See all questions in pH calculations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 7278 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How do you calculate the pH of this solution: #[H^+] = 8.3 xx 10^(-10)# M?	null
942	a9b8d074-6ddd-11ea-840c-ccda262736ce	https://socratic.org/questions/how-do-you-calculate-the-number-of-oxygen-atoms-in-9-20-moles-of-magnesium-iodat	3.25 × 10^25	start physical_unit 7 8 number none qc_end physical_unit 13 14 10 11 mole qc_end end	[{"type":"physical unit","value":"Number [OF] oxygen atoms"}]	[{"type":"physical unit","value":"3.25 × 10^25"}]	[{"type":"physical unit","value":"Mole [OF] magnesium iodate [=] \\pu{9.20 moles}"}]	<h1 class="questionTitle" itemprop="name">How do you calculate the number of oxygen atoms in 9.20 moles of magnesium iodate?</h1>	null	3.25 × 10^25	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is how I would do it</p> <p><mathjax>#9.20 * mol * Mg(IO_3)_2 #</mathjax> <mathjax>#(6molO)/(1molMg(IO_3)_2) #</mathjax><mathjax>#(6.0210^23 O)/(1 mol O)#</mathjax></p> <p><mathjax>#=3.25*10^25#</mathjax> atoms <mathjax>#O#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#3.2510^25#</mathjax> atoms <mathjax>#O#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is how I would do it</p> <p><mathjax>#9.20 mol * Mg(IO_3)_2 #</mathjax> <mathjax>#(6molO)/(1molMg(IO_3)_2) #</mathjax><mathjax>#(6.0210^23 O)/(1 mol O)#</mathjax></p> <p><mathjax>#=3.25*10^25#</mathjax> atoms <mathjax>#O#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you calculate the number of oxygen atoms in 9.20 moles of magnesium iodate?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="350469" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/dylan-k"><img alt="" class="" src="https://profilepictures.socratic.org/GwLaDkaTTHyco3132xvO_WIN_20180207_23_33_10_Pro.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/dylan-k"> Dylan K. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-12-12T05:03:07" itemprop="dateCreated"> Dec 12, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#3.2510^25#</mathjax> atoms <mathjax>#O#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is how I would do it</p> <p><mathjax>#9.20 mol * Mg(IO_3)_2 #</mathjax> <mathjax>#(6molO)/(1molMg(IO_3)_2) #</mathjax><mathjax>#(6.0210^23 O)/(1 mol O)#</mathjax></p> <p><mathjax>#=3.25*10^25#</mathjax> atoms <mathjax>#O#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/350469" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? 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943	aaea2262-6ddd-11ea-ac06-ccda262736ce	https://socratic.org/questions/how-do-you-determine-the-ph-of-a-solution-that-is-3-85-koh-by-mass-assume-that-t	13.84	start physical_unit 8 8 ph none qc_end physical_unit 12 12 11 11 mass_percent qc_end end	[{"type":"physical unit","value":"pH [OF] KOH solution"}]	[{"type":"physical unit","value":"13.84"}]	[{"type":"physical unit","value":"Percent by mass [OF] KOH in solution [=] \\pu{3.85%}"},{"type":"physical unit","value":"Density [OF] KOH solution [=] \\pu{1.01 g/mL}"}]	<h1 class="questionTitle" itemprop="name">How do you determine the pH of a solution that is 3.85% KOH by mass? Assume that the solution has density of 1.01 g/mL.</h1>	null	13.84	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In <mathjax>#1#</mathjax> <mathjax>#mL#</mathjax> of solution, <mathjax>#[NaOH]="moles of NaOH"/"volume of solution"#</mathjax></p> <p><mathjax>#=(1.01gxx3.85%)/(56.11gmol^-1)xx1/(1xx10^-3L)#</mathjax></p> <p><mathjax>#=0.693mol*L^-1#</mathjax></p> <p>Now <mathjax>#pOH=-log_10[HO^-]#</mathjax>, <mathjax>#pOH=-log_10(0.693)#</mathjax></p> <p><mathjax>#=0.159#</mathjax></p> <p>But in water, we know that <mathjax>#pH+pOH=14#</mathjax>,</p> <p>And thus <mathjax>#14-0.159=pH=13.84#</mathjax></p> <p>The high value of <mathjax>#pH#</mathjax> is reasonable for a solution of potash. </p> <p>See <a href="https://socratic.org/questions/how-does-pka-relate-to-acidity">here</a> for more on the relationship between <mathjax>#pH#</mathjax> and acidity. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#pH=-log_10[H_3O^+]=13.84#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In <mathjax>#1#</mathjax> <mathjax>#mL#</mathjax> of solution, <mathjax>#[NaOH]="moles of NaOH"/"volume of solution"#</mathjax></p> <p><mathjax>#=(1.01gxx3.85%)/(56.11gmol^-1)xx1/(1xx10^-3L)#</mathjax></p> <p><mathjax>#=0.693mol*L^-1#</mathjax></p> <p>Now <mathjax>#pOH=-log_10[HO^-]#</mathjax>, <mathjax>#pOH=-log_10(0.693)#</mathjax></p> <p><mathjax>#=0.159#</mathjax></p> <p>But in water, we know that <mathjax>#pH+pOH=14#</mathjax>,</p> <p>And thus <mathjax>#14-0.159=pH=13.84#</mathjax></p> <p>The high value of <mathjax>#pH#</mathjax> is reasonable for a solution of potash. </p> <p>See <a href="https://socratic.org/questions/how-does-pka-relate-to-acidity">here</a> for more on the relationship between <mathjax>#pH#</mathjax> and acidity. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you determine the pH of a solution that is 3.85% KOH by mass? Assume that the solution has density of 1.01 g/mL.</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/ph-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">pH calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="352916" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-12-16T19:07:38" itemprop="dateCreated"> Dec 16, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#pH=-log_10[H_3O^+]=13.84#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In <mathjax>#1#</mathjax> <mathjax>#mL#</mathjax> of solution, <mathjax>#[NaOH]="moles of NaOH"/"volume of solution"#</mathjax></p> <p><mathjax>#=(1.01gxx3.85%)/(56.11gmol^-1)xx1/(1xx10^-3L)#</mathjax></p> <p><mathjax>#=0.693mol*L^-1#</mathjax></p> <p>Now <mathjax>#pOH=-log_10[HO^-]#</mathjax>, <mathjax>#pOH=-log_10(0.693)#</mathjax></p> <p><mathjax>#=0.159#</mathjax></p> <p>But in water, we know that <mathjax>#pH+pOH=14#</mathjax>,</p> <p>And thus <mathjax>#14-0.159=pH=13.84#</mathjax></p> <p>The high value of <mathjax>#pH#</mathjax> is reasonable for a solution of potash. </p> <p>See <a href="https://socratic.org/questions/how-does-pka-relate-to-acidity">here</a> for more on the relationship between <mathjax>#pH#</mathjax> and acidity. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/352916" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-of-a-solution"> How do you determine ph of a solution? 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Assume that the solution has density of 1.01 g/mL.	null
944	a94f30a2-6ddd-11ea-b76d-ccda262736ce	https://socratic.org/questions/105-g-water-is-saturated-with-ammonia-gas-to-form-a-solution-of-density-1-0g-ml--1	135.00 mL	start physical_unit 11 11 volume ml qc_end physical_unit 2 2 0 1 mass qc_end physical_unit 6 6 18 19 mass qc_end end	[{"type":"physical unit","value":"Volume [OF] ammonia solution [IN] mL"}]	[{"type":"physical unit","value":"135.00 mL"}]	[{"type":"physical unit","value":"Mass [OF] water [=] \\pu{105 g}"},{"type":"physical unit","value":"Density [OF] ammonia solution [=] \\pu{1.0 g/mL}"},{"type":"physical unit","value":"Mass [OF] ammonia [=] \\pu{30 g}"}]	<h1 class="questionTitle" itemprop="name">105 g water is saturated with ammonia gas to form a solution of density 1.0g / mL and containing 30g ammonia, by mass. What is the volume of solution formed?</h1>	null	135.00 mL	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And you have specified the <a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a>, <mathjax>#rho_"solution"=1.0gmL^-1#</mathjax>.</p> <p>And since <mathjax>#rho="Mass of solution"/"Volume of solution"#</mathjax>, by definition.......</p> <p><mathjax>#"Volume of solution"="Mass of solution"/rho=(135cancelg)/(1.0cancelgmL^-1)#</mathjax></p> <p><mathjax>#=1351/(mL^-1)=1351/(1/(mL))=135mL#</mathjax>....</p> <p><mathjax>#[NH_3]="Moles of ammonia"/"Volume of solution"=((30g)/(17.03gmol^-1))/(0.135L)=13.0molL^-1.#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, clearly you have a solution mass of <mathjax>#135g#</mathjax>.....agreed?</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And you have specified the <a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a>, <mathjax>#rho_"solution"=1.0gmL^-1#</mathjax>.</p> <p>And since <mathjax>#rho="Mass of solution"/"Volume of solution"#</mathjax>, by definition.......</p> <p><mathjax>#"Volume of solution"="Mass of solution"/rho=(135cancelg)/(1.0cancelgmL^-1)#</mathjax></p> <p><mathjax>#=1351/(mL^-1)=1351/(1/(mL))=135mL#</mathjax>....</p> <p><mathjax>#[NH_3]="Moles of ammonia"/"Volume of solution"=((30g)/(17.03gmol^-1))/(0.135L)=13.0mol*L^-1.#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">105 g water is saturated with ammonia gas to form a solution of density 1.0g / mL and containing 30g ammonia, by mass. What is the volume of solution formed?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/solutions" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="458945" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-01T15:21:52" itemprop="dateCreated"> Aug 1, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, clearly you have a solution mass of <mathjax>#135g#</mathjax>.....agreed?</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And you have specified the <a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a>, <mathjax>#rho_"solution"=1.0gmL^-1#</mathjax>.</p> <p>And since <mathjax>#rho="Mass of solution"/"Volume of solution"#</mathjax>, by definition.......</p> <p><mathjax>#"Volume of solution"="Mass of solution"/rho=(135cancelg)/(1.0cancelgmL^-1)#</mathjax></p> <p><mathjax>#=1351/(mL^-1)=1351/(1/(mL))=135mL#</mathjax>....</p> <p><mathjax>#[NH_3]="Moles of ammonia"/"Volume of solution"=((30g)/(17.03gmol^-1))/(0.135L)=13.0mol*L^-1.#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/458945" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-solution-solute-and-solvent-related"> How are solution, solute, and solvent related? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-solutions-become-saturated"> Why do solutions become saturated? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-temperature-affect-solutions"> How does temperature affect solutions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-a-solution-differ-from-a-colloid"> How does a solution differ from a colloid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/calculate-the-amount-of-1-m-naoh-aqueous-solution-needed-to-make-100-ml-of-0-5-m"> Calculate the amount of 1 M NaOH aqueous solution needed to make 100 mL of 0.5 M NaOH aqueous solution. </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-buffering-a-solution-change-the-solutions-behavior"> How does buffering a solution change the solutions behavior? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-benedict-s-solution-change-colour"> How does Benedict's solution change colour? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/describe-how-would-you-prepare-1-l-of-a-1-m-solution-of-sodium-chloride-the-gram"> Describe how would you prepare 1 L of a 1 M solution of sodium chloride. The gram formula weight... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-solutions-differ-from-suspensions"> How do solutions differ from suspensions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-a-solution-differ-from-a-compound"> How does a solution differ from a compound? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/solutions"> See all questions in Solutions </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3511 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	105 g water is saturated with ammonia gas to form a solution of density 1.0g / mL and containing 30g ammonia, by mass. What is the volume of solution formed?	null
945	a8ddc6b4-6ddd-11ea-812a-ccda262736ce	https://socratic.org/questions/how-do-you-balance-hcl-ba-oh-2-bacl-2-h-2o	2 HCl + Ba(OH)2 -> BaCl2 + 2 H2O	start chemical_equation qc_end chemical_equation 4 10 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the equation"}]	[{"type":"chemical equation","value":"2 HCl + Ba(OH)2 -> BaCl2 + 2 H2O"}]	[{"type":"chemical equation","value":"HCl + Ba(OH)2 -> BaCl2 + H2O"}]	<h1 class="questionTitle" itemprop="name">How do you balance #HCl + Ba(OH)_2 -> BaCl_2 + H_2O#?</h1>	null	2 HCl + Ba(OH)2 -> BaCl2 + 2 H2O	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>When Balancing acid-base reactions, typically you balance the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> which are the salt's cation and anion's first, here the barium and the chlorine, the oxygen next, and the hydrogen should now be balanced. </p> <p>It is important to know all the valences of the species to make sure you have the salt right, look at the number of hydrogen and the acid and the number of hydroxides on the base for these numbers.</p> <p>We have,</p> <p><mathjax>#HCl + Ba(OH)_2 -> BaCl_2 + H_2O#</mathjax></p> <p>First we consider the barium, there is one on the LHS and one on the RHS, so we're good.</p> <p>Second we consider the chlorine, there is one on the LHS and two on the RHS, so we need to have two moles/atoms of <mathjax>#HCl#</mathjax> in the formula.</p> <p><mathjax>#color{red}2HCl + Ba(OH)_2 -> BaCl_color{red}2 + H_2O#</mathjax></p> <p>Third we consider the oxygen, since there are two <mathjax>#OH#</mathjax>'s in the barium hydroxide, there are two oxygen on the LHS, we need two on the RHS so there must be two moles/atoms of <mathjax>#H_2 O#</mathjax> in the formula.</p> <p><mathjax>#2HCl + Ba(OH)_color{red}2 -> BaCl_2 + color{red}2H_2O#</mathjax></p> <p>Now we count up the hydrogen's (it should be balanced already).<br/> There are two <mathjax>#HCl#</mathjax> atoms/moles for two hydrogen and another two in the pair of <mathjax>#OH#</mathjax>'s in the barium hydroxide, for a total of four on the LHS. On the right all the hydrogen is in the <mathjax>#H_2 O#</mathjax>, since two have two atoms/moles of <mathjax>#H_2 O#</mathjax>, each of which contains two hydrogens, we have four hydrogens on the RHS, so they are balances.</p> <p>This is the final form of the equation,<br/> <mathjax>#2HCl + Ba(OH)_2 -> BaCl_2 + 2H_2O#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Add a two in front of the <mathjax>#HCl#</mathjax> and add a two in front of the <mathjax>#H_2 O#</mathjax> to get</p> <p><mathjax>#2HCl + Ba(OH)_2 -> BaCl_2 + 2H_2O#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>When Balancing acid-base reactions, typically you balance the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> which are the salt's cation and anion's first, here the barium and the chlorine, the oxygen next, and the hydrogen should now be balanced. </p> <p>It is important to know all the valences of the species to make sure you have the salt right, look at the number of hydrogen and the acid and the number of hydroxides on the base for these numbers.</p> <p>We have,</p> <p><mathjax>#HCl + Ba(OH)_2 -> BaCl_2 + H_2O#</mathjax></p> <p>First we consider the barium, there is one on the LHS and one on the RHS, so we're good.</p> <p>Second we consider the chlorine, there is one on the LHS and two on the RHS, so we need to have two moles/atoms of <mathjax>#HCl#</mathjax> in the formula.</p> <p><mathjax>#color{red}2HCl + Ba(OH)_2 -> BaCl_color{red}2 + H_2O#</mathjax></p> <p>Third we consider the oxygen, since there are two <mathjax>#OH#</mathjax>'s in the barium hydroxide, there are two oxygen on the LHS, we need two on the RHS so there must be two moles/atoms of <mathjax>#H_2 O#</mathjax> in the formula.</p> <p><mathjax>#2HCl + Ba(OH)_color{red}2 -> BaCl_2 + color{red}2H_2O#</mathjax></p> <p>Now we count up the hydrogen's (it should be balanced already).<br/> There are two <mathjax>#HCl#</mathjax> atoms/moles for two hydrogen and another two in the pair of <mathjax>#OH#</mathjax>'s in the barium hydroxide, for a total of four on the LHS. On the right all the hydrogen is in the <mathjax>#H_2 O#</mathjax>, since two have two atoms/moles of <mathjax>#H_2 O#</mathjax>, each of which contains two hydrogens, we have four hydrogens on the RHS, so they are balances.</p> <p>This is the final form of the equation,<br/> <mathjax>#2HCl + Ba(OH)_2 -> BaCl_2 + 2H_2O#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you balance #HCl + Ba(OH)_2 -> BaCl_2 + H_2O#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="270841" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/maggie-5"><img alt="" class="" src="https://profilepictures.socratic.org/h6z9j5SR8yYM0Xf0blCA_Monarch-11.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/maggie-5"> Maggie </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-29T05:48:56" itemprop="dateCreated"> May 29, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Add a two in front of the <mathjax>#HCl#</mathjax> and add a two in front of the <mathjax>#H_2 O#</mathjax> to get</p> <p><mathjax>#2HCl + Ba(OH)_2 -> BaCl_2 + 2H_2O#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>When Balancing acid-base reactions, typically you balance the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> which are the salt's cation and anion's first, here the barium and the chlorine, the oxygen next, and the hydrogen should now be balanced. </p> <p>It is important to know all the valences of the species to make sure you have the salt right, look at the number of hydrogen and the acid and the number of hydroxides on the base for these numbers.</p> <p>We have,</p> <p><mathjax>#HCl + Ba(OH)_2 -> BaCl_2 + H_2O#</mathjax></p> <p>First we consider the barium, there is one on the LHS and one on the RHS, so we're good.</p> <p>Second we consider the chlorine, there is one on the LHS and two on the RHS, so we need to have two moles/atoms of <mathjax>#HCl#</mathjax> in the formula.</p> <p><mathjax>#color{red}2HCl + Ba(OH)_2 -> BaCl_color{red}2 + H_2O#</mathjax></p> <p>Third we consider the oxygen, since there are two <mathjax>#OH#</mathjax>'s in the barium hydroxide, there are two oxygen on the LHS, we need two on the RHS so there must be two moles/atoms of <mathjax>#H_2 O#</mathjax> in the formula.</p> <p><mathjax>#2HCl + Ba(OH)_color{red}2 -> BaCl_2 + color{red}2H_2O#</mathjax></p> <p>Now we count up the hydrogen's (it should be balanced already).<br/> There are two <mathjax>#HCl#</mathjax> atoms/moles for two hydrogen and another two in the pair of <mathjax>#OH#</mathjax>'s in the barium hydroxide, for a total of four on the LHS. On the right all the hydrogen is in the <mathjax>#H_2 O#</mathjax>, since two have two atoms/moles of <mathjax>#H_2 O#</mathjax>, each of which contains two hydrogens, we have four hydrogens on the RHS, so they are balances.</p> <p>This is the final form of the equation,<br/> <mathjax>#2HCl + Ba(OH)_2 -> BaCl_2 + 2H_2O#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/270841" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------> H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -> Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? 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Sodium phosphate and calcium chloride react to form... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-equation-kclo3-kcl-o2"> How can I balance this equation? ____ #KClO_3 -># ____ #KCl +# ____ #O_2# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-balancing-chemical-equations-important"> Why is balancing chemical equations important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/balancing-chemical-equations"> See all questions in Balancing Chemical Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 22582 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How do you balance #HCl + Ba(OH)_2 -> BaCl_2 + H_2O#?	null
946	a954fd4a-6ddd-11ea-a3a7-ccda262736ce	https://socratic.org/questions/how-many-moles-are-equivalent-to-3-75-10-24-molecules-of-carbon-dioxide	6.23 moles	start physical_unit 11 12 mole mol qc_end end	[{"type":"physical unit","value":"Mole [OF] carbon dioxide [IN] moles"}]	[{"type":"physical unit","value":"6.23 moles"}]	[{"type":"physical unit","value":"Number [OF] carbon dioxide molecules [=] \\pu{3.75 × 10^24}"}]	<h1 class="questionTitle" itemprop="name">How many moles are equivalent to #3.75 * 10^24# molecules of carbon dioxide? </h1>	null	6.23 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#Xxx6.0210^23=3.7510^24->#</mathjax></p> <p><mathjax>#X=(3.7510^24)/(6.0210^23)=0.623*10^1=6.23#</mathjax> moles</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>1 mole contains <mathjax>#6.021023#</mathjax> particles</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#Xxx6.0210^23=3.7510^24->#</mathjax></p> <p><mathjax>#X=(3.7510^24)/(6.0210^23)=0.62310^1=6.23#</mathjax> moles</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles are equivalent to #3.75 * 10^24# molecules of carbon dioxide? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="277193" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meneernask"><img alt="" class="" src="https://profilepictures.socratic.org/gpA0lokRGK9vLVUnAMAy_meneernask.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meneernask"> MeneerNask </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-14T09:43:17" itemprop="dateCreated"> Jun 14, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>1 mole contains <mathjax>#6.021023#</mathjax> particles</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#Xxx6.0210^23=3.7510^24->#</mathjax></p> <p><mathjax>#X=(3.7510^24)/(6.0210^23)=0.62310^1=6.23#</mathjax> moles</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/277193" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? 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947	aa40fd0a-6ddd-11ea-be1d-ccda262736ce	https://socratic.org/questions/560981c3581e2a2b1f33707f	C4H10	start chemical_formula qc_end c_other OTHER qc_end end	[{"type":"other","value":"Chemical Formula [OF] the compound [IN] molecular"}]	[{"type":"chemical equation","value":"C4H10"}]	[{"type":"physical unit","value":"Molecular mass [OF] the compound [=] \\pu{58 g/mol}"},{"type":"other","value":"The empirical formula of the compound is C2H5."}]	<h1 class="questionTitle" itemprop="name">If the empirical formula is #C_2H_5#, and the molecular mass is #58gmol^-1#, what is the molecular formula?</h1>	null	C4H10	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Butane is a <mathjax>#C_4#</mathjax> alkane. The isomer depicted is the straight chain, <em>n</em> -butane. It has 1 other isomer.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>If I am reading your question correctly, it is <mathjax>#H_3C-CH_2CH_2CH_3#</mathjax> or <mathjax>#C_4H_10#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Butane is a <mathjax>#C_4#</mathjax> alkane. The isomer depicted is the straight chain, <em>n</em> -butane. It has 1 other isomer.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">If the empirical formula is #C_2H_5#, and the molecular mass is #58gmol^-1#, what is the molecular formula?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="172673" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-09-28T18:16:21" itemprop="dateCreated"> Sep 28, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>If I am reading your question correctly, it is <mathjax>#H_3C-CH_2CH_2CH_3#</mathjax> or <mathjax>#C_4H_10#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Butane is a <mathjax>#C_4#</mathjax> alkane. The isomer depicted is the straight chain, <em>n</em> -butane. It has 1 other isomer.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/172673" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="172735" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-09-29T02:00:31" itemprop="dateCreated"> Sep 29, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"C"_4"H"_10#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>I assume that you have to determine the molecular formula of butane starting from its <em>empirical formula</em> and its molar mass, which is <mathjax>#~= "58 g"#</mathjax>.</p> <p>If you started from butane's <a href="http://socratic.org/chemistry/the-mole-concept/percent-composition">percent composition</a> of carbon and hydrogen, and provided that your calculations were correct, then the empirical formula should have come out as <mathjax>#"C"_2"H"_5#</mathjax>. </p> <p>Now, you know that the empirical formula tells you the <em>simplest ratio</em> of atoms between the <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> that make up a compound. </p> <p>In your case, you know that a butane molecule contains <strong>5 atoms</strong> of hydrogen <em>for every</em> <strong>2 atoms</strong> of carbon. </p> <p>Since you know what the compound's molar mass is, you can say that </p> <blockquote> <p><mathjax>#(2 xx M_"M carbon" + 5 xx M_"M hydrogen") * color(blue)(n) = "58 g"#</mathjax></p> </blockquote> <p>You know that the molecule contains <strong>at least</strong> two atoms of carbon and five atoms of hydrogen, but you don't <em>exactly</em> how many of each you have <mathjax>#->#</mathjax> this is what <mathjax>#color(blue)(n)#</mathjax> represents. </p> <p>So, use the molar masses of carbon and hydrogen to get the value of <mathjax>#color(blue)(n)#</mathjax></p> <blockquote> <p><mathjax>#(2 xx "12.01 g/mol" + 5 xx "1.01 g/mol") * color(blue)(n) = "58 g"#</mathjax></p> <p><mathjax>#color(blue)(n) = (58color(red)(cancel(color(black)("g"))))/(29.07color(red)(cancel(color(black)("g")))) = "1.995 ~= 2#</mathjax></p> </blockquote> <p>This means tha tthe molecular formula of butane is </p> <blockquote> <p><mathjax>#("C"_2"H"_5)_2 = color(green)("C"_4"H"_10)#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/172735" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? 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948	a86a8292-6ddd-11ea-8d09-ccda262736ce	https://socratic.org/questions/591a4a76b72cff69d6281d17	11.9 mg	start physical_unit 2 2 mass mg qc_end physical_unit 9 9 5 6 volume qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Mass [OF] octane [IN] mg"}]	[{"type":"physical unit","value":"11.9 mg"}]	[{"type":"physical unit","value":"Volume [OF] air [=] \\pu{0.500 L}"},{"type":"other","value":"Completely combust."}]	<h1 class="questionTitle" itemprop="name">How much octane could a #0.500*L# volume of air completely combust?</h1>	null	11.9 mg	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#(i)#</mathjax> <mathjax>#"Moles of dioxygen"=(PV)/(RT)=((749.1mmHg)/(760mmHgatm^-1)xx0.1048L)/(0.0821(Latm)/(Kmol)xx328.7K)#</mathjax></p> <p>(Note that I did adjust the volume of dioxygen to account for its percentage volume in air.)</p> <p><mathjax>#=3.383xx10^-3mol#</mathjax> WITH RESPECT TO DIOXYGEN. </p> <p><mathjax>#(ii)#</mathjax> And we follow the stoichiometric reaction to get stoichiometric equivalence,</p> <p><mathjax>#C_8H_18(l) + 25/2O_2(g) rarr 8CO_2(g) + 9H_2O(l)#</mathjax></p> <p>And so, <mathjax>#"Mass of propane"=(3.383xx10^-3mol)/(25/2)xx44.10gmol^-1#</mathjax></p> <p><mathjax>#=11.9*mg#</mathjax>..........</p> <p>Note that we assumed complete combustion, which is a not altogether reasonable assumption. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well we need to find TWO quantities..........and finally get a mass of <mathjax>#11.9mg#</mathjax> with respect to propane. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#(i)#</mathjax> <mathjax>#"Moles of dioxygen"=(PV)/(RT)=((749.1mmHg)/(760mmHgatm^-1)xx0.1048L)/(0.0821(Latm)/(Kmol)xx328.7K)#</mathjax></p> <p>(Note that I did adjust the volume of dioxygen to account for its percentage volume in air.)</p> <p><mathjax>#=3.383xx10^-3mol#</mathjax> WITH RESPECT TO DIOXYGEN. </p> <p><mathjax>#(ii)#</mathjax> And we follow the stoichiometric reaction to get stoichiometric equivalence,</p> <p><mathjax>#C_8H_18(l) + 25/2O_2(g) rarr 8CO_2(g) + 9H_2O(l)#</mathjax></p> <p>And so, <mathjax>#"Mass of propane"=(3.383xx10^-3mol)/(25/2)xx44.10gmol^-1#</mathjax></p> <p><mathjax>#=11.9mg#</mathjax>..........</p> <p>Note that we assumed complete combustion, which is a not altogether reasonable assumption. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How much octane could a #0.500L# volume of air completely combust?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/stoichiometry-involving-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="425038" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-17T17:06:46" itemprop="dateCreated"> May 17, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well we need to find TWO quantities..........and finally get a mass of <mathjax>#11.9mg#</mathjax> with respect to propane. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#(i)#</mathjax> <mathjax>#"Moles of dioxygen"=(PV)/(RT)=((749.1mmHg)/(760mmHgatm^-1)xx0.1048L)/(0.0821(Latm)/(Kmol)xx328.7K)#</mathjax></p> <p>(Note that I did adjust the volume of dioxygen to account for its percentage volume in air.)</p> <p><mathjax>#=3.383xx10^-3mol#</mathjax> WITH RESPECT TO DIOXYGEN. </p> <p><mathjax>#(ii)#</mathjax> And we follow the stoichiometric reaction to get stoichiometric equivalence,</p> <p><mathjax>#C_8H_18(l) + 25/2O_2(g) rarr 8CO_2(g) + 9H_2O(l)#</mathjax></p> <p>And so, <mathjax>#"Mass of propane"=(3.383xx10^-3mol)/(25/2)xx44.10gmol^-1#</mathjax></p> <p><mathjax>#=11.9*mg#</mathjax>..........</p> <p>Note that we assumed complete combustion, which is a not altogether reasonable assumption. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/425038" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" 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all questions in Gas Stoichiometry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1213 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How much octane could a #0.500*L# volume of air completely combust?	null
949	aa04721e-6ddd-11ea-8a02-ccda262736ce	https://socratic.org/questions/3-55-moles-h-2-g-1-25-moles-co-g-and-an-unknown-number-of-moles-n-2-g-were-place	2.05 moles	start physical_unit 12 12 mole mol qc_end physical_unit 2 2 0 1 mole qc_end physical_unit 5 5 3 4 mole qc_end physical_unit 41 42 21 22 temperature qc_end physical_unit 41 42 17 18 volume qc_end physical_unit 28 29 32 33 density qc_end end	[{"type":"physical unit","value":"Mole [OF] N2(g) [IN] moles"}]	[{"type":"physical unit","value":"2.05 moles"}]	[{"type":"physical unit","value":"Mole [OF] H2(g) [=] \\pu{3.55 moles}"},{"type":"physical unit","value":"Mole [OF] CO(g) [=] \\pu{1.25 moles}"},{"type":"physical unit","value":"Temperature [OF] the flask [=] \\pu{25.0 ℃}"},{"type":"physical unit","value":"Volume [OF] the flask [=] \\pu{5.00 L}"},{"type":"physical unit","value":"Density [OF] the gas mixture [=] \\pu{19.92 g/L}"}]	<h1 class="questionTitle" itemprop="name">3.55 moles #H_2# (g), 1.25 moles #CO# (g), and an unknown number of moles #N_2# (g) were placed into a 5.00 L flask at #25.0^oC#. Given the density of this gas mixture to be 19.92 g/L, how many moles of #N_2# were in the flask? </h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>What is the total pressure, in atm, inside the flask?</p></div> </h2> </div> </div>	2.05 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First start by finding the mass of the gas mixture.</p> <p><mathjax>#density = (mass )/ (volume)#</mathjax></p> <p><mathjax>#mass = density xx volume#</mathjax></p> <p><mathjax>#mass = 19.92 \ g/L xx 5.00 \ L#</mathjax></p> <p><mathjax>#mass = 19.92 \ g/cancel(L)xx 5.00 \ cancel(L)#</mathjax></p> <p><mathjax>#mass = 99.6 \ g#</mathjax></p> <p>The above mass is the mass of the gas mixture (<mathjax>#m_(mix)#</mathjax>). It includes the masses of <mathjax>#N_2 , H_2 #</mathjax> and <mathjax>#CO#</mathjax>.</p> <p><mathjax>#color (red) (m_(mix) = m_(N_2) + m_(H_2) + m_(CO))#</mathjax></p> <p><mathjax>#----------------#</mathjax></p> <p><mathjax>#underbrace(m_(N_2) = ???)#</mathjax></p> <p><mathjax>#m_(H_2) = n_(H_2) xx MM_(H_2)#</mathjax></p> <p><mathjax>#m_(H_2) = 3.55 \ mol. xx 2.016 \ g/(mol.)#</mathjax></p> <p><mathjax>#m_(H_2) = 3.55 \ cancel(mol.)xx 2.016 \ g/(cancel(mol.))#</mathjax></p> <p><mathjax>#underbrace(m_(H_2) = 7.16 \ g)#</mathjax></p> <p><mathjax>#m_(CO) = n_(CO) xx MM_(CO)#</mathjax></p> <p><mathjax>#m_(CO) = 1.25 \ mol. xx 28.01 g/(mol.)#</mathjax></p> <p><mathjax>#m_(CO) = 1.25 \ cancel(mol.) xx 28.011 g/(cancel(mol.))#</mathjax></p> <p><mathjax>#underbrace (m_(CO) = 35.0 \ g)#</mathjax></p> <p><mathjax>#m_(N_2) = m_(mix) -{ m_(H_2) + m_(CO)}#</mathjax></p> <p><mathjax>#m_(N_2) = 99.6 \ g - { 7.16 \ g +35.0 \ g}#</mathjax></p> <p><mathjax>#underbrace (m_(N_2) = 57.4 \ g)#</mathjax></p> <p>Once the mass of <mathjax>#N_2#</mathjax> is determined, find the number of moles.</p> <p><mathjax>#n_(N_2) = (m_(N_2))/ (MM_(N_2))#</mathjax></p> <p><mathjax>#n_(N_2) = (57.4 \ g)/ (28.02 \ g.mol.^-1)#</mathjax></p> <p><mathjax>#n_(N_2) = (57.4 \ cancel(g))/ (28.02 \ cancel(g).mol.^-1)#</mathjax></p> <p><mathjax>#n_(N_2) = 2.05 \ mol.#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>2.05 mol. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First start by finding the mass of the gas mixture.</p> <p><mathjax>#density = (mass )/ (volume)#</mathjax></p> <p><mathjax>#mass = density xx volume#</mathjax></p> <p><mathjax>#mass = 19.92 \ g/L xx 5.00 \ L#</mathjax></p> <p><mathjax>#mass = 19.92 \ g/cancel(L)xx 5.00 \ cancel(L)#</mathjax></p> <p><mathjax>#mass = 99.6 \ g#</mathjax></p> <p>The above mass is the mass of the gas mixture (<mathjax>#m_(mix)#</mathjax>). It includes the masses of <mathjax>#N_2 , H_2 #</mathjax> and <mathjax>#CO#</mathjax>.</p> <p><mathjax>#color (red) (m_(mix) = m_(N_2) + m_(H_2) + m_(CO))#</mathjax></p> <p><mathjax>#----------------#</mathjax></p> <p><mathjax>#underbrace(m_(N_2) = ???)#</mathjax></p> <p><mathjax>#m_(H_2) = n_(H_2) xx MM_(H_2)#</mathjax></p> <p><mathjax>#m_(H_2) = 3.55 \ mol. xx 2.016 \ g/(mol.)#</mathjax></p> <p><mathjax>#m_(H_2) = 3.55 \ cancel(mol.)xx 2.016 \ g/(cancel(mol.))#</mathjax></p> <p><mathjax>#underbrace(m_(H_2) = 7.16 \ g)#</mathjax></p> <p><mathjax>#m_(CO) = n_(CO) xx MM_(CO)#</mathjax></p> <p><mathjax>#m_(CO) = 1.25 \ mol. xx 28.01 g/(mol.)#</mathjax></p> <p><mathjax>#m_(CO) = 1.25 \ cancel(mol.) xx 28.011 g/(cancel(mol.))#</mathjax></p> <p><mathjax>#underbrace (m_(CO) = 35.0 \ g)#</mathjax></p> <p><mathjax>#m_(N_2) = m_(mix) -{ m_(H_2) + m_(CO)}#</mathjax></p> <p><mathjax>#m_(N_2) = 99.6 \ g - { 7.16 \ g +35.0 \ g}#</mathjax></p> <p><mathjax>#underbrace (m_(N_2) = 57.4 \ g)#</mathjax></p> <p>Once the mass of <mathjax>#N_2#</mathjax> is determined, find the number of moles.</p> <p><mathjax>#n_(N_2) = (m_(N_2))/ (MM_(N_2))#</mathjax></p> <p><mathjax>#n_(N_2) = (57.4 \ g)/ (28.02 \ g.mol.^-1)#</mathjax></p> <p><mathjax>#n_(N_2) = (57.4 \ cancel(g))/ (28.02 \ cancel(g).mol.^-1)#</mathjax></p> <p><mathjax>#n_(N_2) = 2.05 \ mol.#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">3.55 moles #H_2# (g), 1.25 moles #CO# (g), and an unknown number of moles #N_2# (g) were placed into a 5.00 L flask at #25.0^oC#. Given the density of this gas mixture to be 19.92 g/L, how many moles of #N_2# were in the flask? </h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>What is the total pressure, in atm, inside the flask?</p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/atmospheric-pressure" itemprop="url"> <span class="breadcrumb" itemprop="title">Atmospheric Pressure</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="288965" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/sam-54"><img alt="" class="" src="https://profilepictures.socratic.org/3bkyAGe2RVWw1lx2h1A5_Avatar%201.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/sam-54"> Sam </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-17T04:24:42" itemprop="dateCreated"> Jul 17, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>2.05 mol. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First start by finding the mass of the gas mixture.</p> <p><mathjax>#density = (mass )/ (volume)#</mathjax></p> <p><mathjax>#mass = density xx volume#</mathjax></p> <p><mathjax>#mass = 19.92 \ g/L xx 5.00 \ L#</mathjax></p> <p><mathjax>#mass = 19.92 \ g/cancel(L)xx 5.00 \ cancel(L)#</mathjax></p> <p><mathjax>#mass = 99.6 \ g#</mathjax></p> <p>The above mass is the mass of the gas mixture (<mathjax>#m_(mix)#</mathjax>). It includes the masses of <mathjax>#N_2 , H_2 #</mathjax> and <mathjax>#CO#</mathjax>.</p> <p><mathjax>#color (red) (m_(mix) = m_(N_2) + m_(H_2) + m_(CO))#</mathjax></p> <p><mathjax>#----------------#</mathjax></p> <p><mathjax>#underbrace(m_(N_2) = ???)#</mathjax></p> <p><mathjax>#m_(H_2) = n_(H_2) xx MM_(H_2)#</mathjax></p> <p><mathjax>#m_(H_2) = 3.55 \ mol. xx 2.016 \ g/(mol.)#</mathjax></p> <p><mathjax>#m_(H_2) = 3.55 \ cancel(mol.)xx 2.016 \ g/(cancel(mol.))#</mathjax></p> <p><mathjax>#underbrace(m_(H_2) = 7.16 \ g)#</mathjax></p> <p><mathjax>#m_(CO) = n_(CO) xx MM_(CO)#</mathjax></p> <p><mathjax>#m_(CO) = 1.25 \ mol. xx 28.01 g/(mol.)#</mathjax></p> <p><mathjax>#m_(CO) = 1.25 \ cancel(mol.) xx 28.011 g/(cancel(mol.))#</mathjax></p> <p><mathjax>#underbrace (m_(CO) = 35.0 \ g)#</mathjax></p> <p><mathjax>#m_(N_2) = m_(mix) -{ m_(H_2) + m_(CO)}#</mathjax></p> <p><mathjax>#m_(N_2) = 99.6 \ g - { 7.16 \ g +35.0 \ g}#</mathjax></p> <p><mathjax>#underbrace (m_(N_2) = 57.4 \ g)#</mathjax></p> <p>Once the mass of <mathjax>#N_2#</mathjax> is determined, find the number of moles.</p> <p><mathjax>#n_(N_2) = (m_(N_2))/ (MM_(N_2))#</mathjax></p> <p><mathjax>#n_(N_2) = (57.4 \ g)/ (28.02 \ g.mol.^-1)#</mathjax></p> <p><mathjax>#n_(N_2) = (57.4 \ cancel(g))/ (28.02 \ cancel(g).mol.^-1)#</mathjax></p> <p><mathjax>#n_(N_2) = 2.05 \ mol.#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/288965" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-atmospheric-pressure-affect-evaporation"> How does atmospheric pressure affect evaporation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-atmospheric-pressure-at-an-altitude"> How do you calculate atmospheric pressure at an altitude? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-air-pressure-greatest-at-the-earth-s-surface"> Why is air pressure greatest at the Earth's surface? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-causes-hydrostatic-pressure-in-blood-vessels"> What causes hydrostatic pressure in blood vessels? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-hydrostatic-pressure-created"> How is hydrostatic pressure created? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-atmospheric-pressure-change-in-the-troposphere"> How does atmospheric pressure change in the troposphere? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/does-air-pressure-change-with-humidity"> Does air pressure change with humidity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-atmospheric-pressure-affect-boiling-points"> How does atmospheric pressure affect boiling points? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-air-pressure-is-measured-for-weather-information"> How is air pressure measured for weather information? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-air-pressure-regulators-work"> How do air pressure regulators work? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/atmospheric-pressure"> See all questions in Atmospheric Pressure </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1673 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	3.55 moles #H_2# (g), 1.25 moles #CO# (g), and an unknown number of moles #N_2# (g) were placed into a 5.00 L flask at #25.0^oC#. Given the density of this gas mixture to be 19.92 g/L, how many moles of #N_2# were in the flask?	What is the total pressure, in atm, inside the flask?
950	a92e88cb-6ddd-11ea-9b56-ccda262736ce	https://socratic.org/questions/how-do-you-write-the-equation-for-this-reaction-potassium-chloride-and-silver-ni	KCl + AgNO3 -> KNO3+ AgCl	start chemical_equation qc_end substance 9 10 qc_end substance 12 13 qc_end substance 17 18 qc_end substance 20 21 qc_end end	[{"type":"other","value":"Chemical Equation [OF] this reaction"}]	[{"type":"chemical equation","value":"KCl + AgNO3 -> KNO3+ AgCl"}]	[{"type":"substance name","value":"Potassium chloride"},{"type":"substance name","value":"Silver nitrate"},{"type":"substance name","value":"Potassium nitrate"},{"type":"substance name","value":"Silver chloride"}]	<h1 class="questionTitle" itemprop="name">How do you write the equation for this reaction: Potassium chloride and silver nitrate react to form potassium nitrate and silver chloride?</h1>	null	KCl + AgNO3 -> KNO3+ AgCl	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>Formulas for the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a>:</strong></p> <p><mathjax>#"KCl":#</mathjax> potassium chloride (reactant)<br/> <mathjax>#"AgNO"_3":#</mathjax> silver nitrate (reactant)<br/> <mathjax>#"KNO"_3":#</mathjax> potassium nitrate (product)<br/> <mathjax>#"AgCl":#</mathjax> silver chloride (product)</p> <p><mathjax>#"KCl + AgNO"_3#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"KNO"_3+"AgCl"#</mathjax></p> <p>If the compounds are in aqueous solution, then their physical states could be added.</p> <p><mathjax>#"KCl(aq) + AgNO"_3("aq")#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"KNO"_3("aq")+"AgCl(s)"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"KCl + AgNO"_3#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"KNO"_3+"AgCl"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>Formulas for the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a>:</strong></p> <p><mathjax>#"KCl":#</mathjax> potassium chloride (reactant)<br/> <mathjax>#"AgNO"_3":#</mathjax> silver nitrate (reactant)<br/> <mathjax>#"KNO"_3":#</mathjax> potassium nitrate (product)<br/> <mathjax>#"AgCl":#</mathjax> silver chloride (product)</p> <p><mathjax>#"KCl + AgNO"_3#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"KNO"_3+"AgCl"#</mathjax></p> <p>If the compounds are in aqueous solution, then their physical states could be added.</p> <p><mathjax>#"KCl(aq) + AgNO"_3("aq")#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"KNO"_3("aq")+"AgCl(s)"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you write the equation for this reaction: Potassium chloride and silver nitrate react to form potassium nitrate and silver chloride?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="335066" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-11-12T04:50:29" itemprop="dateCreated"> Nov 12, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"KCl + AgNO"_3#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"KNO"_3+"AgCl"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>Formulas for the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a>:</strong></p> <p><mathjax>#"KCl":#</mathjax> potassium chloride (reactant)<br/> <mathjax>#"AgNO"_3":#</mathjax> silver nitrate (reactant)<br/> <mathjax>#"KNO"_3":#</mathjax> potassium nitrate (product)<br/> <mathjax>#"AgCl":#</mathjax> silver chloride (product)</p> <p><mathjax>#"KCl + AgNO"_3#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"KNO"_3+"AgCl"#</mathjax></p> <p>If the compounds are in aqueous solution, then their physical states could be added.</p> <p><mathjax>#"KCl(aq) + AgNO"_3("aq")#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"KNO"_3("aq")+"AgCl(s)"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/335066" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div 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951	aa8d5478-6ddd-11ea-969b-ccda262736ce	https://socratic.org/questions/57f9dc597c01496082d70389	22.40 L	start physical_unit 8 8 volume l qc_end physical_unit 8 8 5 6 mole qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Volume [OF] the gas [IN] L"}]	[{"type":"physical unit","value":"22.40 L "}]	[{"type":"physical unit","value":"Mole [OF] the gas [=] \\pu{1 mol}"},{"type":"other","value":"Under standard conditions."}]	<h1 class="questionTitle" itemprop="name">What mole is occupied by #1*mol# of gas under standard conditions?</h1>	null	22.40 L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#V=(nRT)/P#</mathjax></p> <p><mathjax>#V=(1cancel(mol)xx0.0821Lcancel(atm)cancel(K^-1)cancel(mol^-1)xx273cancelK)/(1cancel(atm))#</mathjax></p> <p><mathjax>#=22.4L#</mathjax> or <mathjax>#22.4dm^3#</mathjax></p> <p>Note that <mathjax>#1dm^3=(1xx10^-1m)^3=1xx10^-3m^3=1L#</mathjax>, i.e. <mathjax>#1L=1dm^3=10^-3m^3#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#V=22.4dm^3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#V=(nRT)/P#</mathjax></p> <p><mathjax>#V=(1cancel(mol)xx0.0821Lcancel(atm)cancel(K^-1)cancel(mol^-1)xx273cancelK)/(1cancel(atm))#</mathjax></p> <p><mathjax>#=22.4L#</mathjax> or <mathjax>#22.4dm^3#</mathjax></p> <p>Note that <mathjax>#1dm^3=(1xx10^-1m)^3=1xx10^-3m^3=1L#</mathjax>, i.e. <mathjax>#1L=1*dm^3=10^-3m^3#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What mole is occupied by #1mol# of gas under standard conditions?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp" itemprop="url"> <span class="breadcrumb" itemprop="title">Molar Volume of a Gas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="357225" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-12-27T18:20:16" itemprop="dateCreated"> Dec 27, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#V=22.4dm^3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#V=(nRT)/P#</mathjax></p> <p><mathjax>#V=(1cancel(mol)xx0.0821Lcancel(atm)cancel(K^-1)cancel(mol^-1)xx273cancelK)/(1cancel(atm))#</mathjax></p> <p><mathjax>#=22.4L#</mathjax> or <mathjax>#22.4dm^3#</mathjax></p> <p>Note that <mathjax>#1dm^3=(1xx10^-1m)^3=1xx10^-3m^3=1L#</mathjax>, i.e. <mathjax>#1L=1dm^3=10^-3m^3#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/357225" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-stoichiometric-ratios-relate-to-molar-volume-of-a-gas"> How do stoichiometric ratios relate to molar volume of a gas? 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952	aae78aa7-6ddd-11ea-85c5-ccda262736ce	https://socratic.org/questions/what-is-the-mass-of-cl-in-21-g-of-nacl	12.78 grams	start physical_unit 5 5 mass g qc_end physical_unit 10 10 7 8 mass qc_end end	[{"type":"physical unit","value":"Mass [OF] Cl [IN] grams"}]	[{"type":"physical unit","value":"12.78 grams"}]	[{"type":"physical unit","value":"Mass [OF] NaCl [=] \\pu{21 g}"}]	<h1 class="questionTitle" itemprop="name">What is the mass of Cl in 21 g of NaCl? </h1>	null	12.78 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>21g of <mathjax>#NaCl#</mathjax> is equivalent to 0.36mol.</p> <p><mathjax>#Na#</mathjax> (atomic mass = 23 g/mol), <mathjax>#Cl#</mathjax> (atomic mass = 35.5g/mol)</p> <p>Mole = <mathjax>#("Atomic Mass") ("Molar Mass")#</mathjax></p> <p>Total molar mass of <mathjax>#NaCl#</mathjax> = 23 + 35.5 = <strong>58.5 g/mol</strong></p> <p>Mole = <mathjax>#21 cancel g NaCl#</mathjax> x <mathjax>#"1 mol"/ (58.5 cancel g) NaCl#</mathjax> = <strong>0.36 mol NaCl</strong></p> <p>1 mol of NaCl consists of 1 mol of Na ion and 1 mol of Cl ion </p> <p>or</p> <p><mathjax>#NaCl#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#Na^+#</mathjax> + <mathjax>#Cl^-#</mathjax></p> <p>Therefore, 0.36mol of NaCl is equal to 0.36mol of Cl.</p> <p>Mass of Cl = (Mole <mathjax>#Cl#</mathjax>) (Atomic Mass <mathjax>#Cl#</mathjax>) </p> <p>Mass of Cl = <mathjax>#0.36 "mol Cl"#</mathjax> x <mathjax>#"35 g"/ (1 cancel "mol") Cl#</mathjax></p> <p>Mass of Cl = <strong>12.78g <mathjax>#Cl#</mathjax></strong></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>12.78g</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>21g of <mathjax>#NaCl#</mathjax> is equivalent to 0.36mol.</p> <p><mathjax>#Na#</mathjax> (atomic mass = 23 g/mol), <mathjax>#Cl#</mathjax> (atomic mass = 35.5g/mol)</p> <p>Mole = <mathjax>#("Atomic Mass") ("Molar Mass")#</mathjax></p> <p>Total molar mass of <mathjax>#NaCl#</mathjax> = 23 + 35.5 = <strong>58.5 g/mol</strong></p> <p>Mole = <mathjax>#21 cancel g NaCl#</mathjax> x <mathjax>#"1 mol"/ (58.5 cancel g) NaCl#</mathjax> = <strong>0.36 mol NaCl</strong></p> <p>1 mol of NaCl consists of 1 mol of Na ion and 1 mol of Cl ion </p> <p>or</p> <p><mathjax>#NaCl#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#Na^+#</mathjax> + <mathjax>#Cl^-#</mathjax></p> <p>Therefore, 0.36mol of NaCl is equal to 0.36mol of Cl.</p> <p>Mass of Cl = (Mole <mathjax>#Cl#</mathjax>) (Atomic Mass <mathjax>#Cl#</mathjax>) </p> <p>Mass of Cl = <mathjax>#0.36 "mol Cl"#</mathjax> x <mathjax>#"35 g"/ (1 cancel "mol") Cl#</mathjax></p> <p>Mass of Cl = <strong>12.78g <mathjax>#Cl#</mathjax></strong></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the mass of Cl in 21 g of NaCl? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/percent-composition" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Composition</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="185239" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/patrick-t"><img alt="" class="" src="https://lh5.googleusercontent.com/-PzqK5nuqYqY/AAAAAAAAAAI/AAAAAAAAAeU/t9pnILka7tk/photo.jpg?sz=50" title=""/></a> <a class="secondContributorPic" href="/users/nikka-c"><img alt="" class="" src="https://profilepictures.socratic.org/AQ8VOCyTM1J7U0TvIWhw_nkahara.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/patrick-t"> Patrick T. </a>·<a class="topContributorLink" href="/users/nikka-c"> Nikka C. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-07T18:27:31" itemprop="dateCreated"> Nov 7, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>12.78g</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>21g of <mathjax>#NaCl#</mathjax> is equivalent to 0.36mol.</p> <p><mathjax>#Na#</mathjax> (atomic mass = 23 g/mol), <mathjax>#Cl#</mathjax> (atomic mass = 35.5g/mol)</p> <p>Mole = <mathjax>#("Atomic Mass") ("Molar Mass")#</mathjax></p> <p>Total molar mass of <mathjax>#NaCl#</mathjax> = 23 + 35.5 = <strong>58.5 g/mol</strong></p> <p>Mole = <mathjax>#21 cancel g NaCl#</mathjax> x <mathjax>#"1 mol"/ (58.5 cancel g) NaCl#</mathjax> = <strong>0.36 mol NaCl</strong></p> <p>1 mol of NaCl consists of 1 mol of Na ion and 1 mol of Cl ion </p> <p>or</p> <p><mathjax>#NaCl#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#Na^+#</mathjax> + <mathjax>#Cl^-#</mathjax></p> <p>Therefore, 0.36mol of NaCl is equal to 0.36mol of Cl.</p> <p>Mass of Cl = (Mole <mathjax>#Cl#</mathjax>) (Atomic Mass <mathjax>#Cl#</mathjax>) </p> <p>Mass of Cl = <mathjax>#0.36 "mol Cl"#</mathjax> x <mathjax>#"35 g"/ (1 cancel "mol") Cl#</mathjax></p> <p>Mass of Cl = <strong>12.78g <mathjax>#Cl#</mathjax></strong></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/185239" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-mole-percent"> What is mole percent? 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953	a8db5343-6ddd-11ea-9ea0-ccda262736ce	https://socratic.org/questions/how-many-moles-of-sodium-oxide-will-be-produced-when-10-moles-of-sodium-react-wi	5 moles	start physical_unit 4 5 mole mol qc_end physical_unit 4 4 10 11 mole qc_end substance 16 16 qc_end end	[{"type":"physical unit","value":"Mole [OF] sodium oxide [IN] moles"}]	[{"type":"physical unit","value":"5 moles"}]	[{"type":"physical unit","value":"Mole [OF] sodium [=] \\pu{10 moles}"},{"type":"substance name","value":"Oxygen"}]	<h1 class="questionTitle" itemprop="name">How many moles of sodium oxide will be produced when 10 moles of sodium react with oxygen? </h1>	null	5 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The reaction is:</p> <p><mathjax>#2Na(s)+O_2(g)->Na_2O(s)#</mathjax></p> <p>So, <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio between sodium and sodium oxide is <mathjax>#2:1=2#</mathjax>.</p> <p>Therefore, if ten moles of sodium are used, then we produce:</p> <p><mathjax>#10color(red)cancelcolor(black)("mol" \ Na)*(1 \ "mol" \ Na_2O)/(2color(red)cancelcolor(black)("mol" \ Na))=5 \ "mol" \ Na_2O#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#5#</mathjax> moles of sodium oxide</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The reaction is:</p> <p><mathjax>#2Na(s)+O_2(g)->Na_2O(s)#</mathjax></p> <p>So, <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio between sodium and sodium oxide is <mathjax>#2:1=2#</mathjax>.</p> <p>Therefore, if ten moles of sodium are used, then we produce:</p> <p><mathjax>#10color(red)cancelcolor(black)("mol" \ Na)*(1 \ "mol" \ Na_2O)/(2color(red)cancelcolor(black)("mol" \ Na))=5 \ "mol" \ Na_2O#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles of sodium oxide will be produced when 10 moles of sodium react with oxygen? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/mole-ratios" itemprop="url"> <span class="breadcrumb" itemprop="title">Mole Ratios</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="614242" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/nam-d"><img alt="" class="" src="https://profilepictures.socratic.org/QG4MnkoER6u99DIDVWKK_787554714770341.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/nam-d"> Nam D. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-05-16T00:29:21" itemprop="dateCreated"> May 16, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#5#</mathjax> moles of sodium oxide</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The reaction is:</p> <p><mathjax>#2Na(s)+O_2(g)->Na_2O(s)#</mathjax></p> <p>So, <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio between sodium and sodium oxide is <mathjax>#2:1=2#</mathjax>.</p> <p>Therefore, if ten moles of sodium are used, then we produce:</p> <p><mathjax>#10color(red)cancelcolor(black)("mol" \ Na)*(1 \ "mol" \ Na_2O)/(2color(red)cancelcolor(black)("mol" \ Na))=5 \ "mol" \ Na_2O#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/614242" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" 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clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many moles of sodium oxide will be produced when 10 moles of sodium react with oxygen?	null
954	aa4873df-6ddd-11ea-bda2-ccda262736ce	https://socratic.org/questions/what-is-the-oxidation-number-of-iron-in-fe-2o-3	+3	start physical_unit 6 6 oxidation_number none qc_end chemical_equation 8 8 qc_end end	[{"type":"physical unit","value":"Oxidation number [OF] iron"}]	[{"type":"physical unit","value":"+3"}]	[{"type":"chemical equation","value":"Fe2O3"}]	<h1 class="questionTitle" itemprop="name">What is the oxidation number of iron in #Fe_2O_3#?</h1>	null	+3	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So to find out the oxidation number of iron the iron oxide we start of by finding the oxidation number of oxygen and combine them.<br/> So we know that oxygen has a oxidation number of <mathjax>#-2#</mathjax>. Since we have 3 oxygens this would give a total of <mathjax>#-6#</mathjax>.<br/> We know that the charge should be stable <mathjax>#(=0)#</mathjax>, so therefore iron must have a oxidation number of <mathjax>#+3#</mathjax> since <mathjax>#2*3=6#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#+3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So to find out the oxidation number of iron the iron oxide we start of by finding the oxidation number of oxygen and combine them.<br/> So we know that oxygen has a oxidation number of <mathjax>#-2#</mathjax>. Since we have 3 oxygens this would give a total of <mathjax>#-6#</mathjax>.<br/> We know that the charge should be stable <mathjax>#(=0)#</mathjax>, so therefore iron must have a oxidation number of <mathjax>#+3#</mathjax> since <mathjax>#2*3=6#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the oxidation number of iron in #Fe_2O_3#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#electrochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Electrochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/electrochemistry/oxidation-numbers" itemprop="url"> <span class="breadcrumb" itemprop="title">Oxidation Numbers</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="596074" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/reza"><img alt="" class="" src="https://profilepictures.socratic.org/NoWrR4NeTkGIR65BT6As_PowerTowerdrawing.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/reza"> Shulgin </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-04-16T17:39:31" itemprop="dateCreated"> Apr 16, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#+3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So to find out the oxidation number of iron the iron oxide we start of by finding the oxidation number of oxygen and combine them.<br/> So we know that oxygen has a oxidation number of <mathjax>#-2#</mathjax>. Since we have 3 oxygens this would give a total of <mathjax>#-6#</mathjax>.<br/> We know that the charge should be stable <mathjax>#(=0)#</mathjax>, so therefore iron must have a oxidation number of <mathjax>#+3#</mathjax> since <mathjax>#2*3=6#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/596074" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-relate-to-electron-configuration"> How do oxidation numbers relate to electron configuration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-relate-to-valence-electrons"> How do oxidation numbers relate to valence electrons? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-vary-with-the-periodic-table"> How do oxidation numbers vary with the periodic table? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-oxidation-number-of-an-element-in-a-compound"> How do you calculate the oxidation number of an element in a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-sulfur"> What is the oxidation number for sulfur? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-carbon"> What is the oxidation number for carbon? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-copper"> What is the oxidation number for copper? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-nitrogen"> What is the oxidation number for nitrogen? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-oxygen"> What is the oxidation number for oxygen? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-oxidation-state-of-noble-gas-zero"> Why is the oxidation state of noble gas zero? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/electrochemistry/oxidation-numbers"> See all questions in Oxidation Numbers </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 8818 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the oxidation number of iron in #Fe_2O_3#?	null
955	aaad1280-6ddd-11ea-b08e-ccda262736ce	https://socratic.org/questions/58e94543b72cff09e0414899	169.60 g	start physical_unit 5 5 mass g qc_end physical_unit 12 13 8 9 mass qc_end end	[{"type":"physical unit","value":"Mass [OF] oxygen [IN] g"}]	[{"type":"physical unit","value":"169.60 g"}]	[{"type":"physical unit","value":"Mass [OF] carbon dioxide [=] \\pu{233.0 g }"}]	<h1 class="questionTitle" itemprop="name">What is the mass of oxygen in a #233.0*g# mass of carbon dioxide?</h1>	null	169.60 g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We calculate the molar quantity of carbon dioxide is........</p> <p><mathjax>#(233g)/(44.0gmol^-1)=5.30mol#</mathjax></p> <p>Now, clearly, if there are <mathjax>#5.30mol#</mathjax> <mathjax>#CO_2#</mathjax>, there are <mathjax>#10.6mol#</mathjax> <mathjax>#"oxygen atoms"#</mathjax>. Do you agree?</p> <p>And thus mass of oxygen <mathjax>#-=#</mathjax> <mathjax>#10.6molxx16.0g*mol^-1=??g#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Mass of oxygen"-=170g#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We calculate the molar quantity of carbon dioxide is........</p> <p><mathjax>#(233g)/(44.0gmol^-1)=5.30mol#</mathjax></p> <p>Now, clearly, if there are <mathjax>#5.30mol#</mathjax> <mathjax>#CO_2#</mathjax>, there are <mathjax>#10.6mol#</mathjax> <mathjax>#"oxygen atoms"#</mathjax>. Do you agree?</p> <p>And thus mass of oxygen <mathjax>#-=#</mathjax> <mathjax>#10.6molxx16.0gmol^-1=??g#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the mass of oxygen in a #233.0g# mass of carbon dioxide?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/equation-stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Equation Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="403809" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-08T20:22:47" itemprop="dateCreated"> Apr 8, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Mass of oxygen"-=170g#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We calculate the molar quantity of carbon dioxide is........</p> <p><mathjax>#(233g)/(44.0gmol^-1)=5.30mol#</mathjax></p> <p>Now, clearly, if there are <mathjax>#5.30mol#</mathjax> <mathjax>#CO_2#</mathjax>, there are <mathjax>#10.6mol#</mathjax> <mathjax>#"oxygen atoms"#</mathjax>. Do you agree?</p> <p>And thus mass of oxygen <mathjax>#-=#</mathjax> <mathjax>#10.6molxx16.0g*mol^-1=??g#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/403809" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4171602bf3469588dc36e"> What are the types of stoichiometry examples, with examples? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4171802bf3469570e2e82"> Question #e2e82 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/533668a402bf34573b4e66fb"> What mass of carbon dioxide can 1.00 kg of lithium oxide absorb? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-an-example-of-a-stoichiometry-practice-problem"> What is an example of a stoichiometry practice problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-an-example-of-a-balanced-equation-practice-problem"> What is an example of a balanced equation practice problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-a-chemical-equation"> How can I balance a chemical equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-stoichiometry-be-used"> How can stoichiometry be used? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-stoichiometric-ratios-relate-reactants-to-products"> How do stoichiometric ratios relate reactants to products? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-gas-stoichiometry-differ-from-stoichiometry-of-solids-and-liquids"> How does gas stoichiometry differ from stoichiometry of solids and liquids? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-stoichiometry-relate-to-the-law-of-conservation"> How does stoichiometry relate to the law of conservation? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/equation-stoichiometry"> See all questions in Equation Stoichiometry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1323 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the mass of oxygen in a #233.0*g# mass of carbon dioxide?	null
956	ab138118-6ddd-11ea-aab7-ccda262736ce	https://socratic.org/questions/5851b47fb72cff6a47c587d8	1.15 mL	start physical_unit 19 20 volume ml qc_end physical_unit 4 6 1 2 temperature qc_end physical_unit 19 20 24 25 temperature qc_end physical_unit 4 6 11 12 volume qc_end end	[{"type":"physical unit","value":"Volume2 [OF] the gas [IN] mL"}]	[{"type":"physical unit","value":"1.15 mL"}]	[{"type":"physical unit","value":"Temperature1 [OF] the gas sample [=] \\pu{95.0 ℃}"},{"type":"physical unit","value":"Temperature2 [OF] the gas [=] \\pu{0.2 ℃}"},{"type":"physical unit","value":"Volume1 [OF] the gas sample [=] \\pu{1.55 mL}"}]	<h1 class="questionTitle" itemprop="name">At #95.0^@"C"#, a sample of gas has a volume of #"1.55 mL"#. What will the volume be if the gas is cooled to #0.2^@"C"#? </h1>	null	1.15 mL	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your question involves <a href="https://socratic.org/chemistry/the-behavior-of-gases/charles-law">Charles' law</a>, which states that the volume of a gas is directly proportional to its Kelvin temperature, with pressure and mass remaining constant. This means that if the volume increases, the temperature will also increase, and vice versa.</p> <p><strong>Equation</strong></p> <p><mathjax>#V_1/T_1=V_2/T_2#</mathjax>, where <mathjax>#V#</mathjax> is volume, and <mathjax>#T#</mathjax> is temperature in Kelvins.</p> <p><strong>Known</strong><br/> <mathjax>#V_1="1.55 mL"#</mathjax><br/> <mathjax>#T_1="95.0"^@"C"+273.15=368.2 "K"#</mathjax><br/> <mathjax>#T_2="0.2"^@"C"+273.15=273.4 "K"#</mathjax></p> <p><strong>Unknown</strong><br/> <mathjax>#V_2#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#V_2#</mathjax>. Plug in the known values and solve.</p> <p><mathjax>#V_2=(V_1T_2)/T_1#</mathjax></p> <p><mathjax>#V_2=(1.55"mL"xx273.4"K")/(368.2"K")="1.15 mL"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The final volume will be <mathjax>#"1.15 mL"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your question involves <a href="https://socratic.org/chemistry/the-behavior-of-gases/charles-law">Charles' law</a>, which states that the volume of a gas is directly proportional to its Kelvin temperature, with pressure and mass remaining constant. This means that if the volume increases, the temperature will also increase, and vice versa.</p> <p><strong>Equation</strong></p> <p><mathjax>#V_1/T_1=V_2/T_2#</mathjax>, where <mathjax>#V#</mathjax> is volume, and <mathjax>#T#</mathjax> is temperature in Kelvins.</p> <p><strong>Known</strong><br/> <mathjax>#V_1="1.55 mL"#</mathjax><br/> <mathjax>#T_1="95.0"^@"C"+273.15=368.2 "K"#</mathjax><br/> <mathjax>#T_2="0.2"^@"C"+273.15=273.4 "K"#</mathjax></p> <p><strong>Unknown</strong><br/> <mathjax>#V_2#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#V_2#</mathjax>. Plug in the known values and solve.</p> <p><mathjax>#V_2=(V_1T_2)/T_1#</mathjax></p> <p><mathjax>#V_2=(1.55"mL"xx273.4"K")/(368.2"K")="1.15 mL"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">At #95.0^@"C"#, a sample of gas has a volume of #"1.55 mL"#. What will the volume be if the gas is cooled to #0.2^@"C"#? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/charles-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Charles' Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="353102" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-12-17T05:46:56" itemprop="dateCreated"> Dec 17, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The final volume will be <mathjax>#"1.15 mL"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your question involves <a href="https://socratic.org/chemistry/the-behavior-of-gases/charles-law">Charles' law</a>, which states that the volume of a gas is directly proportional to its Kelvin temperature, with pressure and mass remaining constant. This means that if the volume increases, the temperature will also increase, and vice versa.</p> <p><strong>Equation</strong></p> <p><mathjax>#V_1/T_1=V_2/T_2#</mathjax>, where <mathjax>#V#</mathjax> is volume, and <mathjax>#T#</mathjax> is temperature in Kelvins.</p> <p><strong>Known</strong><br/> <mathjax>#V_1="1.55 mL"#</mathjax><br/> <mathjax>#T_1="95.0"^@"C"+273.15=368.2 "K"#</mathjax><br/> <mathjax>#T_2="0.2"^@"C"+273.15=273.4 "K"#</mathjax></p> <p><strong>Unknown</strong><br/> <mathjax>#V_2#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#V_2#</mathjax>. Plug in the known values and solve.</p> <p><mathjax>#V_2=(V_1T_2)/T_1#</mathjax></p> <p><mathjax>#V_2=(1.55"mL"xx273.4"K")/(368.2"K")="1.15 mL"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/353102" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-must-charles-law-be-in-kelvins"> Why must Charles' law be in kelvin? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-charles-law-formula"> What is Charles' law formula? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/oxygen-gas-is-at-a-temperature-of-40-c-when-it-occupies-a-volume-of-2-3-liters-t"> Oxygen gas is at a temperature of 40°C when it occupies a volume of 2.3 liters. 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What will be volume of oxygen when the... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/charles-law"> See all questions in Charles' Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2705 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	At #95.0^@"C"#, a sample of gas has a volume of #"1.55 mL"#. What will the volume be if the gas is cooled to #0.2^@"C"#?	null
957	aae80b2c-6ddd-11ea-93af-ccda262736ce	https://socratic.org/questions/a-sample-of-carbon-dioxide-gas-at-125-c-and-248-torr-occupies-a-volume-of-275-l-	212.46 torr	start physical_unit 20 21 pressure torr qc_end physical_unit 20 21 16 17 volume qc_end physical_unit 20 21 10 11 pressure qc_end physical_unit 20 21 7 8 temperature qc_end physical_unit 20 21 30 31 volume qc_end physical_unit 20 21 7 8 temperature qc_end end	[{"type":"physical unit","value":"Pressure2 [OF] the gas [IN] torr"}]	[{"type":"physical unit","value":"212.46 torr"}]	[{"type":"physical unit","value":"Volume1 [OF] the gas [=] \\pu{275 L}"},{"type":"physical unit","value":"Pressure1 [OF] the gas [=] \\pu{248 torr}"},{"type":"physical unit","value":"Temperature1 [OF] the gas [=] \\pu{125 ℃}"},{"type":"physical unit","value":"Volume2 [OF] the gas [=] \\pu{321 L}"},{"type":"physical unit","value":"Temperature2 [OF] the gas [=] \\pu{125 ℃}"}]	<h1 class="questionTitle" itemprop="name">A sample of carbon dioxide gas at 125°C and 248 torr occupies a volume of 275 L. What will the gas pressure be if the volume is increased to 321 L at 125°C?</h1>	null	212.46 torr	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Let's use the <a href="https://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">combined gas law</a>:</p> <p><mathjax>#Rightarrow frac(P_(1) V_(1))(T_(1)) = frac(P_(2) V_(2))(T_(2))#</mathjax></p> <p>In our case, the temperature of <mathjax>#125^(@)#</mathjax> <mathjax>#"C"#</mathjax> is kept constant throughout the process, so <mathjax>#T_(1) = T_(2)#</mathjax>:</p> <p><mathjax>#Rightarrow frac(P_(1) V_(2))(T_(1)) = frac(P_(2) V_(2))(T_(1))#</mathjax></p> <p><mathjax>#Rightarrow P_(1) V_(1) = P_(2) V_(2)#</mathjax></p> <p>Then, let's substitute the relevant values:</p> <p><mathjax>#Rightarrow 248#</mathjax> <mathjax>#"torr" times 275#</mathjax> <mathjax>#"L" = P_(2) times 321#</mathjax> <mathjax>#"L"#</mathjax></p> <p><mathjax>#Rightarrow P_(2) = frac(248 " torr" times 275 " L")(321 " L")#</mathjax></p> <p><mathjax>#therefore P_(2) = 212.46105919#</mathjax> <mathjax>#"torr"#</mathjax></p> <p>Therefore, the final <a href="https://socratic.org/chemistry/the-behavior-of-gases/gas-pressure">gas pressure</a> will be around <mathjax>#212#</mathjax> <mathjax>#"torr"#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#212#</mathjax> <mathjax>#"torr"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Let's use the <a href="https://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">combined gas law</a>:</p> <p><mathjax>#Rightarrow frac(P_(1) V_(1))(T_(1)) = frac(P_(2) V_(2))(T_(2))#</mathjax></p> <p>In our case, the temperature of <mathjax>#125^(@)#</mathjax> <mathjax>#"C"#</mathjax> is kept constant throughout the process, so <mathjax>#T_(1) = T_(2)#</mathjax>:</p> <p><mathjax>#Rightarrow frac(P_(1) V_(2))(T_(1)) = frac(P_(2) V_(2))(T_(1))#</mathjax></p> <p><mathjax>#Rightarrow P_(1) V_(1) = P_(2) V_(2)#</mathjax></p> <p>Then, let's substitute the relevant values:</p> <p><mathjax>#Rightarrow 248#</mathjax> <mathjax>#"torr" times 275#</mathjax> <mathjax>#"L" = P_(2) times 321#</mathjax> <mathjax>#"L"#</mathjax></p> <p><mathjax>#Rightarrow P_(2) = frac(248 " torr" times 275 " L")(321 " L")#</mathjax></p> <p><mathjax>#therefore P_(2) = 212.46105919#</mathjax> <mathjax>#"torr"#</mathjax></p> <p>Therefore, the final <a href="https://socratic.org/chemistry/the-behavior-of-gases/gas-pressure">gas pressure</a> will be around <mathjax>#212#</mathjax> <mathjax>#"torr"#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A sample of carbon dioxide gas at 125°C and 248 torr occupies a volume of 275 L. What will the gas pressure be if the volume is increased to 321 L at 125°C?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/gas-laws" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Laws</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="438530" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/tazwar89"><img alt="" class="" src="https://lh3.googleusercontent.com/-XdUIqdMkCWA/AAAAAAAAAAI/AAAAAAAAAAA/4252rscbv5M/photo.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/tazwar89"> Tazwar Sikder </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-12T09:55:50" itemprop="dateCreated"> Jun 12, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#212#</mathjax> <mathjax>#"torr"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Let's use the <a href="https://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">combined gas law</a>:</p> <p><mathjax>#Rightarrow frac(P_(1) V_(1))(T_(1)) = frac(P_(2) V_(2))(T_(2))#</mathjax></p> <p>In our case, the temperature of <mathjax>#125^(@)#</mathjax> <mathjax>#"C"#</mathjax> is kept constant throughout the process, so <mathjax>#T_(1) = T_(2)#</mathjax>:</p> <p><mathjax>#Rightarrow frac(P_(1) V_(2))(T_(1)) = frac(P_(2) V_(2))(T_(1))#</mathjax></p> <p><mathjax>#Rightarrow P_(1) V_(1) = P_(2) V_(2)#</mathjax></p> <p>Then, let's substitute the relevant values:</p> <p><mathjax>#Rightarrow 248#</mathjax> <mathjax>#"torr" times 275#</mathjax> <mathjax>#"L" = P_(2) times 321#</mathjax> <mathjax>#"L"#</mathjax></p> <p><mathjax>#Rightarrow P_(2) = frac(248 " torr" times 275 " L")(321 " L")#</mathjax></p> <p><mathjax>#therefore P_(2) = 212.46105919#</mathjax> <mathjax>#"torr"#</mathjax></p> <p>Therefore, the final <a href="https://socratic.org/chemistry/the-behavior-of-gases/gas-pressure">gas pressure</a> will be around <mathjax>#212#</mathjax> <mathjax>#"torr"#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/438530" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-boyles-law-relate-to-breathing"> How does Boyle's law relate to breathing? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/in-avogadro-s-law-what-would-happen-to-v-if-n-is-increased-decreased-and-what-wo"> In Avogadro's Law what would happen to V if N is increased/decreased? 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What will the gas pressure be if the volume is increased to 321 L at 125°C?	null
958	ab5ac1e2-6ddd-11ea-89dd-ccda262736ce	https://socratic.org/questions/what-is-the-molarity-of-a-salt-solution-made-by-dissolving-240mg-of-nacl-in-4ml-	1.03 M	start physical_unit 6 7 molarity mol/l qc_end physical_unit 14 14 11 12 mass qc_end physical_unit 19 19 16 17 volume qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Molarity [OF] the salt solution [IN] M"}]	[{"type":"physical unit","value":"1.03 M"}]	[{"type":"physical unit","value":"Mass [OF] NaCl [=] \\pu{240 mg}"},{"type":"physical unit","value":"Volume [OF] water [=] \\pu{4 mL}"},{"type":"other","value":"Assume final volume is the same as the volume of water."}]	<h1 class="questionTitle" itemprop="name">What is the molarity of a salt solution made by dissolving 240mg of NaCl in 4ml of water? Assume final volume is the same as the volume of water.</h1>	null	1.03 M	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to find the <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></strong> of the solution, you must determine the number of moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> present in exactly</p> <blockquote> <p><mathjax>#"1 L" = 10^3#</mathjax> <mathjax>#"mL"#</mathjax> </p> </blockquote> <p>of solution. Notice that you already know the number of milligrams of sodium chloride, the solute, present in <mathjax>#"4 mL"#</mathjax> of solution, so start by calculating the mass of solute present in <mathjax>#10^3#</mathjax> <mathjax>#"mL"#</mathjax> of solution.</p> <blockquote> <p><mathjax>#10^3 color(red)(cancel(color(black)("mL solution"))) * "240 mg NaCl"/(4color(red)(cancel(color(black)("mL solution")))) = 60 * 10^3#</mathjax> <mathjax>#"mg"#</mathjax></p> </blockquote> <p>Since</p> <blockquote> <p><mathjax>#color(blue)("1 g" = 10^3color(white)(.)"mg"#</mathjax></p> </blockquote> <p>you can say that <mathjax>#10^3#</mathjax> <mathjax>#"mL"#</mathjax> of solution contain</p> <blockquote> <p><mathjax>#60 * color(blue)(10^3color(white)(.)"mg") = 60color(white)(.)color(blue)("g")#</mathjax></p> </blockquote> <p>of sodium chloride. Now, to convert this to <em>moles</em>, use the <strong>molar mass</strong> of the compound</p> <blockquote> <p><mathjax>#60 color(red)(cancel(color(black)("g"))) * "1 mole NaCl"/(58.44color(red)(cancel(color(black)("g")))) = "1.027 moles NaCl"#</mathjax></p> </blockquote> <p>Since this represents the number of moles of sodium chloride present in <mathjax>#10^3#</mathjax> <mathjax>#"mL"#</mathjax> of solution, you can say that the molarity of the solution is equal to</p> <blockquote> <p><mathjax>#color(darkgreen)(ul(color(black)("molarity = 1 mol L"^(-1)))#</mathjax></p> </blockquote> <p>The answer must be rounded to one <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figure</a></strong>, the number of sig figs you have for the volume of the solution. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"1 mol L"^(-1)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to find the <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></strong> of the solution, you must determine the number of moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> present in exactly</p> <blockquote> <p><mathjax>#"1 L" = 10^3#</mathjax> <mathjax>#"mL"#</mathjax> </p> </blockquote> <p>of solution. Notice that you already know the number of milligrams of sodium chloride, the solute, present in <mathjax>#"4 mL"#</mathjax> of solution, so start by calculating the mass of solute present in <mathjax>#10^3#</mathjax> <mathjax>#"mL"#</mathjax> of solution.</p> <blockquote> <p><mathjax>#10^3 color(red)(cancel(color(black)("mL solution"))) * "240 mg NaCl"/(4color(red)(cancel(color(black)("mL solution")))) = 60 * 10^3#</mathjax> <mathjax>#"mg"#</mathjax></p> </blockquote> <p>Since</p> <blockquote> <p><mathjax>#color(blue)("1 g" = 10^3color(white)(.)"mg"#</mathjax></p> </blockquote> <p>you can say that <mathjax>#10^3#</mathjax> <mathjax>#"mL"#</mathjax> of solution contain</p> <blockquote> <p><mathjax>#60 * color(blue)(10^3color(white)(.)"mg") = 60color(white)(.)color(blue)("g")#</mathjax></p> </blockquote> <p>of sodium chloride. Now, to convert this to <em>moles</em>, use the <strong>molar mass</strong> of the compound</p> <blockquote> <p><mathjax>#60 color(red)(cancel(color(black)("g"))) * "1 mole NaCl"/(58.44color(red)(cancel(color(black)("g")))) = "1.027 moles NaCl"#</mathjax></p> </blockquote> <p>Since this represents the number of moles of sodium chloride present in <mathjax>#10^3#</mathjax> <mathjax>#"mL"#</mathjax> of solution, you can say that the molarity of the solution is equal to</p> <blockquote> <p><mathjax>#color(darkgreen)(ul(color(black)("molarity = 1 mol L"^(-1)))#</mathjax></p> </blockquote> <p>The answer must be rounded to one <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figure</a></strong>, the number of sig figs you have for the volume of the solution. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the molarity of a salt solution made by dissolving 240mg of NaCl in 4ml of water? Assume final volume is the same as the volume of water.</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="440830" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-17T01:38:56" itemprop="dateCreated"> Jun 17, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"1 mol L"^(-1)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to find the <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></strong> of the solution, you must determine the number of moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> present in exactly</p> <blockquote> <p><mathjax>#"1 L" = 10^3#</mathjax> <mathjax>#"mL"#</mathjax> </p> </blockquote> <p>of solution. Notice that you already know the number of milligrams of sodium chloride, the solute, present in <mathjax>#"4 mL"#</mathjax> of solution, so start by calculating the mass of solute present in <mathjax>#10^3#</mathjax> <mathjax>#"mL"#</mathjax> of solution.</p> <blockquote> <p><mathjax>#10^3 color(red)(cancel(color(black)("mL solution"))) * "240 mg NaCl"/(4color(red)(cancel(color(black)("mL solution")))) = 60 * 10^3#</mathjax> <mathjax>#"mg"#</mathjax></p> </blockquote> <p>Since</p> <blockquote> <p><mathjax>#color(blue)("1 g" = 10^3color(white)(.)"mg"#</mathjax></p> </blockquote> <p>you can say that <mathjax>#10^3#</mathjax> <mathjax>#"mL"#</mathjax> of solution contain</p> <blockquote> <p><mathjax>#60 * color(blue)(10^3color(white)(.)"mg") = 60color(white)(.)color(blue)("g")#</mathjax></p> </blockquote> <p>of sodium chloride. Now, to convert this to <em>moles</em>, use the <strong>molar mass</strong> of the compound</p> <blockquote> <p><mathjax>#60 color(red)(cancel(color(black)("g"))) * "1 mole NaCl"/(58.44color(red)(cancel(color(black)("g")))) = "1.027 moles NaCl"#</mathjax></p> </blockquote> <p>Since this represents the number of moles of sodium chloride present in <mathjax>#10^3#</mathjax> <mathjax>#"mL"#</mathjax> of solution, you can say that the molarity of the solution is equal to</p> <blockquote> <p><mathjax>#color(darkgreen)(ul(color(black)("molarity = 1 mol L"^(-1)))#</mathjax></p> </blockquote> <p>The answer must be rounded to one <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figure</a></strong>, the number of sig figs you have for the volume of the solution. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/440830" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="440831" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-17T01:58:09" itemprop="dateCreated"> Jun 17, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>M=<mathjax>#"1 mol/L"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of a solution is the concentration of moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> per liter of solution, <mathjax>#"mol/L"#</mathjax>. The mass of <mathjax>#"NaCl"#</mathjax> must be converted to grams and then moles. The volume of the solution must be converted to liters.</p> <p><strong>Convert <mathjax>#"mg NaCl"#</mathjax> to <mathjax>#"g NaCl"#</mathjax>.</strong></p> <p><mathjax>#"1 g=1000 mg"#</mathjax></p> <p><mathjax>#240color(red)cancel(color(black)("mg NaCl"))xx(1"g")/(1000color(red)cancel(color(black)("mg")))="0.24 g NaCl"#</mathjax></p> <p><strong>Determine moles of <mathjax>#"NaCl"#</mathjax>.</strong></p> <p>Divide the mass of <mathjax>#"NaCl"#</mathjax> by its molar mass by multiplying by its inverse.</p> <p><strong>Molar mass <mathjax>#"NaCl=58.44 g/mol"#</mathjax></strong></p> <p><mathjax>#0.24color(red)cancel(color(black)("g NaCl"))xx(1"mol NaCl")/(58.44color(red)cancel(color(black)("g NaCl")))="0.0041 mol NaCl"#</mathjax></p> <p><strong>Molarity of <mathjax>#"NaCl"#</mathjax>.</strong></p> <p><strong>Convert <mathjax>#"4 mL"#</mathjax> to liters.</strong></p> <p><mathjax>#"1 L=1000 mL"#</mathjax></p> <p><mathjax>#4color(red)cancel(color(black)("mL"))xx(1"L")/(1000color(red)cancel(color(black)("mL")))="0.004 L"#</mathjax></p> <p><strong>Divide mol NaCl by volume of solution.</strong></p> <p><mathjax>#"M"=(0.0041"mol NaCl")/(0.004"L solution")="1 mol/L"#</mathjax> rounded to one sig fig due to <mathjax>#4#</mathjax> mL</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/440831" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-morality-be-used-as-a-conversion-factor"> How can molarity be used as a conversion factor? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-high-can-molarity-be"> How high can molarity be? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-molarity-change-with-temperature"> How does molarity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molarity-of-a-solution"> How do you find molarity of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-10-naoh"> What is the molarity of 10 NaOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-3-hydrogen-peroxide"> What is the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 66329 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the molarity of a salt solution made by dissolving 240mg of NaCl in 4ml of water? Assume final volume is the same as the volume of water.	null
959	abe2d02c-6ddd-11ea-8537-ccda262736ce	https://socratic.org/questions/we-prepare-a-buffer-by-adding-0-5289-mol-hno-3-to-0-5291-l-of-a-solution-contain	9.78	start physical_unit 3 3 ph none qc_end physical_unit 14 14 10 11 volume qc_end physical_unit 19 19 16 17 molarity qc_end physical_unit 19 19 22 24 kb qc_end end	[{"type":"physical unit","value":"pH [OF] the buffer"}]	[{"type":"physical unit","value":"9.78"}]	[{"type":"physical unit","value":"Mole [OF] HON3 [=] \\pu{0.5289 mol}"},{"type":"physical unit","value":"Volume [OF] (CH3)3N solution [=] \\pu{0.5291 L}"},{"type":"physical unit","value":"Molarity [OF] (CH3)3N solution [=] \\pu{1.924 M}"},{"type":"physical unit","value":"Kb [OF] (CH3)3N [=] \\pu{6.500 × 10^(-5)}"}]	<h1 class="questionTitle" itemprop="name">We prepare a buffer by adding 0.5289 mol #HNO_3# to 0.5291 L of a solution containing 1.924 M trimethylamine [#(CH_3)_3N#, #Kb = 6.500x10^-5#]. What is the pH of this buffer? How do you solve this? Please help!?</h1>	null	9.78	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Trimethylamine is a weak base and accepts a proton from water:</p> <p><mathjax>#sf((CH_3)_3N+H_2Orightleftharpoons(CH_3)_3NH^(+)+OH^-)#</mathjax></p> <p>For which:</p> <p><mathjax>#sf(K_b=([(CH_3)_3NH^+][OH^(-)])/([(CH_3)_3N])=6.500xx10^(-3)color(white)(x)"mol/l")#</mathjax></p> <p>These are equilibrium concentrations.</p> <p>We can use the data given to find <mathjax>#sf([OH^-])#</mathjax> and then use the ionic product of water to find <mathjax>#sf([H^+])#</mathjax> hence the <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a>.</p> <p>First we need to get the initial moles of TME:</p> <p><mathjax>#sf(n_(TME)=cxxv =1.924xx0.5291=1.018)#</mathjax></p> <p>When the nitric acid is added some of these are protonated to give the salt:</p> <p><mathjax>#sf((CH_3)_3N+H^(+)rarr(CH_3)_3NH^+)#</mathjax></p> <p>You can see that these react in a 1:1 molar ratio.</p> <p>So the number of moles of TME remaining = <mathjax>#sf(1.018-0.5289=0.4890)#</mathjax></p> <p>By the same reasoning the number of moles of the salt formed must be equal to the number of moles of nitric acid added.</p> <p><mathjax>#:.#</mathjax> no. moles of <mathjax>#sf((CH_3)_3NH^(+))#</mathjax> formed <mathjax>#sf(= 0.5289)#</mathjax></p> <p>Rearranging the expression for <mathjax>#sf(K_brArr)#</mathjax></p> <p><mathjax>#sf([OH^(-)]=K_bxx([(CH_3)_3N])/([(CH_3)_3NH^+]])#</mathjax></p> <p>Now we have worked out the <strong>initial moles</strong> of the base and the salt. The expression requires the no. of moles <strong>at equilibrium.</strong></p> <p>Because the value of <mathjax>#sf(K_b)#</mathjax> is small I am going to assume that the initial moles of base and salt are a good approximation for the equilibrium moles.</p> <p>There may be a volume change on mixing but this does not matter since the total volume is common to both base and salt so will cancel.</p> <p>This means we can put moles directly into the expression for <mathjax>#sf([OH^-]rArr)#</mathjax></p> <p><mathjax>#sf([OH^-]=6.500xx10^(-5)xx0.4890/0.5289=6.010xx10^(-5)color(white)(x)"mol/l")#</mathjax></p> <p><mathjax>#sf(pOH=-log[OH^-]=-log[6.010xx10^(-5)]=4.221)#</mathjax></p> <p>We know that:</p> <p><mathjax>#sf(pH+pOH=14)#</mathjax> at <mathjax>#sf(25 ^@"C")#</mathjax></p> <p><mathjax>#:.#</mathjax><mathjax>#sf(pH=14-pOH=14-4.221=9.78)#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#sf(pH=9.78)#</mathjax></p> <p>Here's how you can do this:</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Trimethylamine is a weak base and accepts a proton from water:</p> <p><mathjax>#sf((CH_3)_3N+H_2Orightleftharpoons(CH_3)_3NH^(+)+OH^-)#</mathjax></p> <p>For which:</p> <p><mathjax>#sf(K_b=([(CH_3)_3NH^+][OH^(-)])/([(CH_3)_3N])=6.500xx10^(-3)color(white)(x)"mol/l")#</mathjax></p> <p>These are equilibrium concentrations.</p> <p>We can use the data given to find <mathjax>#sf([OH^-])#</mathjax> and then use the ionic product of water to find <mathjax>#sf([H^+])#</mathjax> hence the <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a>.</p> <p>First we need to get the initial moles of TME:</p> <p><mathjax>#sf(n_(TME)=cxxv =1.924xx0.5291=1.018)#</mathjax></p> <p>When the nitric acid is added some of these are protonated to give the salt:</p> <p><mathjax>#sf((CH_3)_3N+H^(+)rarr(CH_3)_3NH^+)#</mathjax></p> <p>You can see that these react in a 1:1 molar ratio.</p> <p>So the number of moles of TME remaining = <mathjax>#sf(1.018-0.5289=0.4890)#</mathjax></p> <p>By the same reasoning the number of moles of the salt formed must be equal to the number of moles of nitric acid added.</p> <p><mathjax>#:.#</mathjax> no. moles of <mathjax>#sf((CH_3)_3NH^(+))#</mathjax> formed <mathjax>#sf(= 0.5289)#</mathjax></p> <p>Rearranging the expression for <mathjax>#sf(K_brArr)#</mathjax></p> <p><mathjax>#sf([OH^(-)]=K_bxx([(CH_3)_3N])/([(CH_3)_3NH^+]])#</mathjax></p> <p>Now we have worked out the <strong>initial moles</strong> of the base and the salt. The expression requires the no. of moles <strong>at equilibrium.</strong></p> <p>Because the value of <mathjax>#sf(K_b)#</mathjax> is small I am going to assume that the initial moles of base and salt are a good approximation for the equilibrium moles.</p> <p>There may be a volume change on mixing but this does not matter since the total volume is common to both base and salt so will cancel.</p> <p>This means we can put moles directly into the expression for <mathjax>#sf([OH^-]rArr)#</mathjax></p> <p><mathjax>#sf([OH^-]=6.500xx10^(-5)xx0.4890/0.5289=6.010xx10^(-5)color(white)(x)"mol/l")#</mathjax></p> <p><mathjax>#sf(pOH=-log[OH^-]=-log[6.010xx10^(-5)]=4.221)#</mathjax></p> <p>We know that:</p> <p><mathjax>#sf(pH+pOH=14)#</mathjax> at <mathjax>#sf(25 ^@"C")#</mathjax></p> <p><mathjax>#:.#</mathjax><mathjax>#sf(pH=14-pOH=14-4.221=9.78)#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">We prepare a buffer by adding 0.5289 mol #HNO_3# to 0.5291 L of a solution containing 1.924 M trimethylamine [#(CH_3)_3N#, #Kb = 6.500x10^-5#]. What is the pH of this buffer? How do you solve this? Please help!?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#reactions-in-solution" itemprop="url"> <span class="breadcrumb" itemprop="title">Reactions in Solution</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/reactions-in-solution/buffer-theory" itemprop="url"> <span class="breadcrumb" itemprop="title">Buffer Theory</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="295465" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/michael-2"><img alt="" class="" src="https://lh3.googleusercontent.com/-gCv6FQRhls0/AAAAAAAAAAI/AAAAAAAAAAA/AAnnY7oOJS05Ylqn3KuDSW0LfnbOk7FezQ/mo/photo.jpg?sz=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/michael-2"> Michael </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-08-04T16:55:21" itemprop="dateCreated"> Aug 4, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#sf(pH=9.78)#</mathjax></p> <p>Here's how you can do this:</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Trimethylamine is a weak base and accepts a proton from water:</p> <p><mathjax>#sf((CH_3)_3N+H_2Orightleftharpoons(CH_3)_3NH^(+)+OH^-)#</mathjax></p> <p>For which:</p> <p><mathjax>#sf(K_b=([(CH_3)_3NH^+][OH^(-)])/([(CH_3)_3N])=6.500xx10^(-3)color(white)(x)"mol/l")#</mathjax></p> <p>These are equilibrium concentrations.</p> <p>We can use the data given to find <mathjax>#sf([OH^-])#</mathjax> and then use the ionic product of water to find <mathjax>#sf([H^+])#</mathjax> hence the <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a>.</p> <p>First we need to get the initial moles of TME:</p> <p><mathjax>#sf(n_(TME)=cxxv =1.924xx0.5291=1.018)#</mathjax></p> <p>When the nitric acid is added some of these are protonated to give the salt:</p> <p><mathjax>#sf((CH_3)_3N+H^(+)rarr(CH_3)_3NH^+)#</mathjax></p> <p>You can see that these react in a 1:1 molar ratio.</p> <p>So the number of moles of TME remaining = <mathjax>#sf(1.018-0.5289=0.4890)#</mathjax></p> <p>By the same reasoning the number of moles of the salt formed must be equal to the number of moles of nitric acid added.</p> <p><mathjax>#:.#</mathjax> no. moles of <mathjax>#sf((CH_3)_3NH^(+))#</mathjax> formed <mathjax>#sf(= 0.5289)#</mathjax></p> <p>Rearranging the expression for <mathjax>#sf(K_brArr)#</mathjax></p> <p><mathjax>#sf([OH^(-)]=K_bxx([(CH_3)_3N])/([(CH_3)_3NH^+]])#</mathjax></p> <p>Now we have worked out the <strong>initial moles</strong> of the base and the salt. The expression requires the no. of moles <strong>at equilibrium.</strong></p> <p>Because the value of <mathjax>#sf(K_b)#</mathjax> is small I am going to assume that the initial moles of base and salt are a good approximation for the equilibrium moles.</p> <p>There may be a volume change on mixing but this does not matter since the total volume is common to both base and salt so will cancel.</p> <p>This means we can put moles directly into the expression for <mathjax>#sf([OH^-]rArr)#</mathjax></p> <p><mathjax>#sf([OH^-]=6.500xx10^(-5)xx0.4890/0.5289=6.010xx10^(-5)color(white)(x)"mol/l")#</mathjax></p> <p><mathjax>#sf(pOH=-log[OH^-]=-log[6.010xx10^(-5)]=4.221)#</mathjax></p> <p>We know that:</p> <p><mathjax>#sf(pH+pOH=14)#</mathjax> at <mathjax>#sf(25 ^@"C")#</mathjax></p> <p><mathjax>#:.#</mathjax><mathjax>#sf(pH=14-pOH=14-4.221=9.78)#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/295465" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="295577" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/truong-son-n"><img alt="" class="" src="https://profilepictures.socratic.org/07k4plnQfmnmzMuesQzw_14844-1449381920.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/truong-son-n"> Truong-Son N. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-08-04T22:01:57" itemprop="dateCreated"> Aug 4, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerDescription"> <div> <div class="markdown"><p>Although Michael's answer is just as valid, here's another approach.</p> <p>Using the <strong>Henderson-Hasselbalch</strong> equation, all we have to do is:</p> <ol> <li>Determine the <mathjax>#"pKa"#</mathjax>, if you are using the <mathjax>#"pKa"#</mathjax> version of the equation.</li> <li>Find <mathjax>#["BH"^(+)]#</mathjax> and <mathjax>#["B"]#</mathjax>.</li> <li>Calculate the <mathjax>#"pH"#</mathjax> from there.</li> </ol> <p>First:</p> <blockquote> <p><mathjax>#-log(K_b) = "pKb" = 4.187#</mathjax></p> </blockquote> <p>which means <mathjax>#color(green)("pKa") = "pKw" - "pKb" = 14 - 4.187 = color(green)(9.813)#</mathjax>.</p> <p>Next, we consider the equation itself:</p> <blockquote> <p><mathjax>#\mathbf("pH" = "pKa" + log \frac(["B"])(["BH"^(+)]))#</mathjax></p> <p>where <mathjax>#"B"#</mathjax> is trimethylamine and <mathjax>#"BH"^(+)#</mathjax> is protonated trimethylamine.</p> </blockquote> <p>A nice shortcut to finding <mathjax>#["B"]#</mathjax> and <mathjax>#["BH"^(+)]#</mathjax> is...</p> <blockquote> <p>When the added acid is strong, the <mathjax>#\mathbf("mol")#</mathjax><strong>s of acid added</strong> (here, it's <mathjax>#"HNO"_3#</mathjax>) is the <mathjax>#\mathbf("mol")#</mathjax><strong>s of <em>new</em> conjugate acid</strong> <mathjax>#\mathbf("BH"^(+))#</mathjax> <strong>formed</strong> and the <mathjax>#\mathbf("mol")#</mathjax><strong>s of <em>original</em> base</strong> <mathjax>#\mathbf("B")#</mathjax> <strong>lost</strong>.</p> <p>That is, <br/> <mathjax>#n_"strong acid" = n_("BH"^(+), "eq")#</mathjax><br/> <mathjax>#n_("B","eq") = n_("B",i) - n_"strong acid"#</mathjax></p> </blockquote> <p>Lastly, the volume of the solution is common to everything in the solution, so <strong>a molar ratio works</strong>, and you don't have to use concentrations.</p> <p>Therefore, we can write the (base-10) logarithm argument as <mathjax>#color(green)(\frac(["B"])(["BH"^(+)]) = (n_("B","eq"))/(n_("BH"^(+),"eq")) = (n_("B",i) - n_"strong acid")/(n_"strong acid"))#</mathjax>:</p> <blockquote> <p><mathjax>#"pH" = "pKa" + log ((n_("B",i) - n_"strong acid")/(n_"strong acid"))#</mathjax></p> </blockquote> <p>First we have <mathjax>#n_("B",i) = "0.5291 L" xx "1.924 mols/L" = color(green)("1.018 mols")#</mathjax>. Then we were given <mathjax>#n_"strong acid" = color(green)("0.5289 mols")#</mathjax> monoprotic strong acid, <mathjax>#"HNO"_3#</mathjax>, which adds <mathjax>#1:1#</mathjax>.</p> <p>So, our alternative method also gives us:</p> <blockquote> <p><mathjax>#color(blue)("pH") = 9.813 + log((1.018 - 0.5289)/(0.5289))#</mathjax></p> <p><mathjax>#~~ color(blue)(9.78)#</mathjax></p> </blockquote> <p>Use whichever method you prefer.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/295577" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-the-applications-of-a-buffer"> What are the applications of a buffer? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-buffer-ph-for-polyprotic-acids"> How do you calculate buffer pH for polyprotic acids? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-buffer-ph-for-monoprotic-acids"> How do you calculate buffer pH for monoprotic acids? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-buffer-capacity-of-a-buffer-solution"> What is the buffer capacity of a buffer solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-good-s-buffer-agents-exist"> How many Good's buffer agents exist? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/551c9f1f581e2a41f0fea6ed"> Question #ea6ed </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/552c0c9c581e2a24ad30d9d2"> Question #0d9d2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5539b797581e2a3629a26e0c"> Question #26e0c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/554bb2de581e2a6fa52c5de8"> Question #c5de8 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-do-you-mean-by-physiological-buffers-what-are-the-different-types-of-buffer"> What do you mean by physiological buffers? What are the different types of buffers found in the... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/reactions-in-solution/buffer-theory"> See all questions in Buffer Theory </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1552 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	We prepare a buffer by adding 0.5289 mol #HNO_3# to 0.5291 L of a solution containing 1.924 M trimethylamine [#(CH_3)_3N#, #Kb = 6.500x10^-5#]. What is the pH of this buffer? How do you solve this? Please help!?	null
960	ab050aa4-6ddd-11ea-8880-ccda262736ce	https://socratic.org/questions/what-is-the-concentration-in-parts-per-million-of-a-500-g-sample-of-drinking-wat	90.00 parts per million	start physical_unit 12 15 concentration ppm qc_end physical_unit 12 15 10 11 mass qc_end physical_unit 21 21 18 19 mass qc_end end	[{"type":"physical unit","value":"Concentration [OF] drinking water sample [IN] parts per million"}]	[{"type":"physical unit","value":"90.00 parts per million"}]	[{"type":"physical unit","value":"Mass [OF] drinking water sample [=] \\pu{500 g}"},{"type":"physical unit","value":"Mass [OF] lead [=] \\pu{45 mg}"}]	<h1 class="questionTitle" itemprop="name">What is the concentration in parts per million of a 500 g sample of drinking water that contains 45 mg of lead?</h1>	null	90.00 parts per million	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>PPM can be better understood in typical units of concentration! </p> <p>PPM can also be represented as mg/L! </p> <p>Assuming the <a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a> of water is 1.0g/ml, we can translate 500.0g of water to be 500.0mL of water! </p> <p>Therefore, </p> <p>Turning 500.0mL of water into L first; </p> <p><mathjax>#"500 mL" * "1 L"/"1000 mL" = "0.5 L"#</mathjax></p> <p>For PPM, we want to keep our mass in mg, which was already supplied! </p> <p>As such, </p> <p><mathjax>#"45 mg" /"0.5 L" = "90 mg/L" = "90 ppm"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"90 ppm"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>PPM can be better understood in typical units of concentration! </p> <p>PPM can also be represented as mg/L! </p> <p>Assuming the <a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a> of water is 1.0g/ml, we can translate 500.0g of water to be 500.0mL of water! </p> <p>Therefore, </p> <p>Turning 500.0mL of water into L first; </p> <p><mathjax>#"500 mL" * "1 L"/"1000 mL" = "0.5 L"#</mathjax></p> <p>For PPM, we want to keep our mass in mg, which was already supplied! </p> <p>As such, </p> <p><mathjax>#"45 mg" /"0.5 L" = "90 mg/L" = "90 ppm"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the concentration in parts per million of a 500 g sample of drinking water that contains 45 mg of lead?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/solving-using-ppm-parts-per-million" itemprop="url"> <span class="breadcrumb" itemprop="title">Solving Using PPM (Parts Per Million)</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="551411" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/mcwilliams"><img alt="" class="" src="https://profilepictures.socratic.org/7rbmw02SjG0Zao1h2E9A_Chromodorisverrieri.png" title=""/></a> <a class="secondContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/mcwilliams"> McWilliams </a>·<a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-02-14T02:51:42" itemprop="dateCreated"> Feb 14, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"90 ppm"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>PPM can be better understood in typical units of concentration! </p> <p>PPM can also be represented as mg/L! </p> <p>Assuming the <a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a> of water is 1.0g/ml, we can translate 500.0g of water to be 500.0mL of water! </p> <p>Therefore, </p> <p>Turning 500.0mL of water into L first; </p> <p><mathjax>#"500 mL" * "1 L"/"1000 mL" = "0.5 L"#</mathjax></p> <p>For PPM, we want to keep our mass in mg, which was already supplied! </p> <p>As such, </p> <p><mathjax>#"45 mg" /"0.5 L" = "90 mg/L" = "90 ppm"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/551411" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-ppm"> What is PPM? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-ppm-be-calculated-in-chemistry"> How can PPM be calculated in chemistry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-ppm-a-useful-measurement"> Why is PPM a useful measurement? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/54c39459581e2a50bb6742ad"> Question #742ad </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/54c4d4dc581e2a50d46797aa"> Question #797aa </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/h2s-g-concentrations-of-660ppm-is-dangerous-6-h2s-generators-continually-release"> H2S (g) concentrations of 660ppm is dangerous. (6) H2S generators continually release all of the... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-to-toothpaste-to-kill-a-rat-one-of-the-leading-toothpaste-brands-"> How many grams to toothpaste to kill a rat? One of the leading toothpaste brands advertises... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/550e033e581e2a2728e12b01"> Question #12b01 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5550c245581e2a6b70076a8d"> Question #76a8d </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-nacl-should-be-weighed-to-prepare-1-l-of-20-ppm-solution-of-na"> How many grams of #NaCl# should be weighed to prepare 1 L of 20 ppm solution of #Na^+#? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/solving-using-ppm-parts-per-million"> See all questions in Solving Using PPM (Parts Per Million) </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 39399 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the concentration in parts per million of a 500 g sample of drinking water that contains 45 mg of lead?	null
961	a91fa2f4-6ddd-11ea-a583-ccda262736ce	https://socratic.org/questions/what-is-the-chemical-formula-for-silicon-dioxide	SiO2	start chemical_formula qc_end substance 6 7 qc_end end	[{"type":"other","value":"Chemical Formula [OF] silicon dioxide [IN] default"}]	[{"type":"chemical equation","value":"SiO2"}]	[{"type":"substance name","value":"Silicon dioxide"}]	<h1 class="questionTitle" itemprop="name">What is the chemical formula for silicon dioxide?</h1>	null	SiO2	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your biggest clue here is the "dioxide" part, which indicates you have two oxygens here. Silicon's position in <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a> indicates that it will have a +4 charge, and therefore you will just have the one silicon atom. </p> <p>Hope that helps :)</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#SiO_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your biggest clue here is the "dioxide" part, which indicates you have two oxygens here. Silicon's position in <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a> indicates that it will have a +4 charge, and therefore you will just have the one silicon atom. </p> <p>Hope that helps :)</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the chemical formula for silicon dioxide?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#ionic-bonds-and-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Ionic Bonds</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/ionic-bonds-and-formulas/naming-ionic-compounds" itemprop="url"> <span class="breadcrumb" itemprop="title">Naming Ionic Compounds</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="423019" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/darshan"><img alt="" class="" src="https://profilepictures.socratic.org/BlZFCtrsS8u8cwQJFgg6_ProfilePic.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/darshan"> Darshan Senthil </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-14T04:51:02" itemprop="dateCreated"> May 14, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#SiO_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your biggest clue here is the "dioxide" part, which indicates you have two oxygens here. Silicon's position in <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a> indicates that it will have a +4 charge, and therefore you will just have the one silicon atom. </p> <p>Hope that helps :)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/423019" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-name-ionic-compounds-with-transition-metals"> How do you name ionic compounds with transition metals? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-name-of-the-ionic-compound-ni3-po4-2"> What is the name of the ionic compound Ni3(PO4)2? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-rules-are-used-to-name-ionic-compounds"> What rules are used to name ionic compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-name-ionic-compounds-with-three-elements"> How can I name ionic compounds with three elements? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-name-ionic-compounds-with-transition-metals"> How can I name ionic compounds with transition metals? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-name-ionic-compounds-with-roman-numerals"> How do you name ionic compounds with roman numerals? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-name-polyatomic-ionic-compounds"> How can I name polyatomic ionic compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-name-ionic-compounds"> How can I name ionic compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-name-binary-ionic-compounds"> How can I name binary ionic compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-examples-of-ionic-compounds-names"> What are some examples of ionic compounds names? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/ionic-bonds-and-formulas/naming-ionic-compounds"> See all questions in Naming Ionic Compounds </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 6012 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the chemical formula for silicon dioxide?	null
962	ab3ac212-6ddd-11ea-bc15-ccda262736ce	https://socratic.org/questions/what-is-the-empirical-formula-of-a-compound-that-contains-40-carbon-6-7-hydrogen	CH2O	start chemical_formula qc_end end	[{"type":"other","value":"Chemical Formula [OF] the compound [IN] empirical"}]	[{"type":"chemical equation","value":"CH2O"}]	[{"type":"physical unit","value":"Percent [OF] carbon in the compound [=] \\pu{40%}"},{"type":"physical unit","value":"Percent [OF] hydrogen in the compound [=] \\pu{6.7%}"},{"type":"physical unit","value":"Percent [OF] oxygen in the compound [=] \\pu{53.3%}"}]	<h1 class="questionTitle" itemprop="name">What is the empirical formula of a compound that contains 40% carbon, 6.7% hydrogen, and 53.3% oxygen? </h1>	null	CH2O	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To find the ratio in moles you divide by the <mathjax>#A_r#</mathjax> of each element. </p> <p>Using approximate values:</p> <p>Ratio in grams <mathjax>#C:H:OrArr#</mathjax></p> <p><mathjax>#40:6.7:53.3#</mathjax></p> <p>Ratio in moles <mathjax>#rArr#</mathjax></p> <p><mathjax>#40/12:6.7/1:53.3/16rArr#</mathjax></p> <p><mathjax>#3.33:6.7:3.33#</mathjax></p> <p>Dividing through by <mathjax>#3.33rArr#</mathjax></p> <p><mathjax>#1:2:1#</mathjax></p> <p>So the empirical formula is:</p> <p><mathjax>#CH_2O#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#CH_2O#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To find the ratio in moles you divide by the <mathjax>#A_r#</mathjax> of each element. </p> <p>Using approximate values:</p> <p>Ratio in grams <mathjax>#C:H:OrArr#</mathjax></p> <p><mathjax>#40:6.7:53.3#</mathjax></p> <p>Ratio in moles <mathjax>#rArr#</mathjax></p> <p><mathjax>#40/12:6.7/1:53.3/16rArr#</mathjax></p> <p><mathjax>#3.33:6.7:3.33#</mathjax></p> <p>Dividing through by <mathjax>#3.33rArr#</mathjax></p> <p><mathjax>#1:2:1#</mathjax></p> <p>So the empirical formula is:</p> <p><mathjax>#CH_2O#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the empirical formula of a compound that contains 40% carbon, 6.7% hydrogen, and 53.3% oxygen? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="178795" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/michael-2"><img alt="" class="" src="https://lh3.googleusercontent.com/-gCv6FQRhls0/AAAAAAAAAAI/AAAAAAAAAAA/AAnnY7oOJS05Ylqn3KuDSW0LfnbOk7FezQ/mo/photo.jpg?sz=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/michael-2"> Michael </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-10-21T13:38:31" itemprop="dateCreated"> Oct 21, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#CH_2O#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To find the ratio in moles you divide by the <mathjax>#A_r#</mathjax> of each element. </p> <p>Using approximate values:</p> <p>Ratio in grams <mathjax>#C:H:OrArr#</mathjax></p> <p><mathjax>#40:6.7:53.3#</mathjax></p> <p>Ratio in moles <mathjax>#rArr#</mathjax></p> <p><mathjax>#40/12:6.7/1:53.3/16rArr#</mathjax></p> <p><mathjax>#3.33:6.7:3.33#</mathjax></p> <p>Dividing through by <mathjax>#3.33rArr#</mathjax></p> <p><mathjax>#1:2:1#</mathjax></p> <p>So the empirical formula is:</p> <p><mathjax>#CH_2O#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/178795" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? 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963	a8ef640a-6ddd-11ea-bdd8-ccda262736ce	https://socratic.org/questions/what-is-the-concentration-in-molarity-of-a-250-ml-solution-made-with-43-4-grams-	2.0 M	start physical_unit 10 10 molarity mol/l qc_end physical_unit 10 10 8 9 volume qc_end physical_unit 16 16 13 14 mass qc_end end	[{"type":"physical unit","value":"Concentration in molarity [OF] the solution [IN] M"}]	[{"type":"physical unit","value":"2.0 M"}]	[{"type":"physical unit","value":"Volume [OF] the solution [=] \\pu{250 mL}"},{"type":"physical unit","value":"Mass [OF] LiBr [=] \\pu{43.4 grams}"}]	<h1 class="questionTitle" itemprop="name">What is the concentration in molarity of a 250 mL solution made with 43.4 grams of LiBr?</h1>	null	2.0 M	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a> = molar concentration = how many moles in <mathjax>#"1 L"#</mathjax> of solution.</p> <p><mathjax>#M_("LiBr") = M_"Li" + M_"Br" = "6.9 g/mol" + "79.9 g/mol" = "86.8 g/mol"#</mathjax></p> <p>(I've used the rounded molar masses)</p> <p><mathjax>#n_"LiBr" = "43.4 g"/"86.8 g/mol" = "0.5moles"#</mathjax></p> <p><mathjax>#V_"solution" = "250 mL" = "0.25L"#</mathjax></p> <p>So</p> <p><mathjax>#c = n_"LiBr"/ V_"solution" = "0.5 moles"/"0.25 L" = "2.0 M"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"2.0 M"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a> = molar concentration = how many moles in <mathjax>#"1 L"#</mathjax> of solution.</p> <p><mathjax>#M_("LiBr") = M_"Li" + M_"Br" = "6.9 g/mol" + "79.9 g/mol" = "86.8 g/mol"#</mathjax></p> <p>(I've used the rounded molar masses)</p> <p><mathjax>#n_"LiBr" = "43.4 g"/"86.8 g/mol" = "0.5moles"#</mathjax></p> <p><mathjax>#V_"solution" = "250 mL" = "0.25L"#</mathjax></p> <p>So</p> <p><mathjax>#c = n_"LiBr"/ V_"solution" = "0.5 moles"/"0.25 L" = "2.0 M"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the concentration in molarity of a 250 mL solution made with 43.4 grams of LiBr?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="559353" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/justme314"><img alt="" class="" src="https://graph.facebook.com/1022769511193043/picture?height=50&width=50" title=""/></a> <a class="secondContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/justme314"> JustMe314 </a>·<a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-02-27T12:19:30" itemprop="dateCreated"> Feb 27, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"2.0 M"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a> = molar concentration = how many moles in <mathjax>#"1 L"#</mathjax> of solution.</p> <p><mathjax>#M_("LiBr") = M_"Li" + M_"Br" = "6.9 g/mol" + "79.9 g/mol" = "86.8 g/mol"#</mathjax></p> <p>(I've used the rounded molar masses)</p> <p><mathjax>#n_"LiBr" = "43.4 g"/"86.8 g/mol" = "0.5moles"#</mathjax></p> <p><mathjax>#V_"solution" = "250 mL" = "0.25L"#</mathjax></p> <p>So</p> <p><mathjax>#c = n_"LiBr"/ V_"solution" = "0.5 moles"/"0.25 L" = "2.0 M"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/559353" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="559355" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/nam-d"><img alt="" class="" src="https://profilepictures.socratic.org/QG4MnkoER6u99DIDVWKK_787554714770341.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/nam-d"> Nam D. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-02-27T12:22:31" itemprop="dateCreated"> Feb 27, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2 \ "M"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a> is defined by the following equation</p> <p><mathjax>#"molarity"="moles of solute"/"liters of solution"#</mathjax></p> <p>So, we first need to convert <mathjax>#43.4 \ "g"#</mathjax> of <mathjax>#LiBr#</mathjax> into moles.</p> <p><mathjax>#LiBr#</mathjax> has a molar mass of <mathjax>#86.845 \ "g/mol"#</mathjax>.</p> <p>So, <mathjax>#43.4 \ "g"#</mathjax> of <mathjax>#LiBr#</mathjax> is equivalent to</p> <p><mathjax>#(43.4color(red)cancelcolor(black)"g")/(86.845color(red)cancelcolor(black)"g""/mol")~~0.5 \ "mol"#</mathjax></p> <p>We can also convert the amount of milliliters to liters.</p> <p><mathjax>#1 \ "L"=1000 \ "mL"#</mathjax></p> <p>So, <mathjax>#250 \ "mL"=0.25 \ "L"#</mathjax></p> <p>Now, we have the desired units, we can plug it into the molarity equation.</p> <p><mathjax>#:."molarity"=(0.5 \ "mol")/(0.25 \ "L")=2 \ "mol/L"#</mathjax></p> <p>We can also write it as <mathjax>#2 \ "M"#</mathjax>, since <mathjax>#1 \ "M"=1 \ "mol/L"#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/559355" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> 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class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 7264 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the concentration in molarity of a 250 mL solution made with 43.4 grams of LiBr?	null
964	abe6529d-6ddd-11ea-aded-ccda262736ce	https://socratic.org/questions/when-sulfuric-acid-and-copper-ii-are-allowed-to-react-copper-ii-sulfate-and-wate	CuO(s) + H2SO4(aq) -> CuSO4(aq) + H2O(l)	start chemical_equation qc_end substance 1 2 qc_end substance 4 5 qc_end substance 10 12 qc_end substance 14 14 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the balanced equation"}]	[{"type":"chemical equation","value":"CuO(s) + H2SO4(aq) -> CuSO4(aq) + H2O(l)"}]	[{"type":"substance name","value":"Sulfuric acid"},{"type":"substance name","value":"Copper (II)"},{"type":"substance name","value":"Copper (II) sulfate"},{"type":"substance name","value":"Water"}]	<h1 class="questionTitle" itemprop="name">When sulfuric acid and copper (II) are allowed to react, copper (II) sulfate and water are formed. How do you write a balanced equation for this reaction?</h1>	null	CuO(s) + H2SO4(aq) -> CuSO4(aq) + H2O(l)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>I always enjoyed doing this reaction as it is a beautiful reaction to do. You add the acid, and you get the lovely blue colour of the hexa-aqua ion, <mathjax>#[Cu(OH_2)_6]^(2+)#</mathjax> as it sulfate salt. The reaction above is simply an acid base reaction. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#CuO(s) + H_2SO_4(aq) rarr CuSO_4(aq) + H_2O(l)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>I always enjoyed doing this reaction as it is a beautiful reaction to do. You add the acid, and you get the lovely blue colour of the hexa-aqua ion, <mathjax>#[Cu(OH_2)_6]^(2+)#</mathjax> as it sulfate salt. The reaction above is simply an acid base reaction. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">When sulfuric acid and copper (II) are allowed to react, copper (II) sulfate and water are formed. How do you write a balanced equation for this reaction?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="323320" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-10-18T15:55:17" itemprop="dateCreated"> Oct 18, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#CuO(s) + H_2SO_4(aq) rarr CuSO_4(aq) + H_2O(l)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>I always enjoyed doing this reaction as it is a beautiful reaction to do. You add the acid, and you get the lovely blue colour of the hexa-aqua ion, <mathjax>#[Cu(OH_2)_6]^(2+)#</mathjax> as it sulfate salt. The reaction above is simply an acid base reaction. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/323320" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------> H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -> Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? 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Sodium phosphate and calcium chloride react to form... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-equation-kclo3-kcl-o2"> How can I balance this equation? ____ #KClO_3 -># ____ #KCl +# ____ #O_2# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-balancing-chemical-equations-important"> Why is balancing chemical equations important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/balancing-chemical-equations"> See all questions in Balancing Chemical Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 20692 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	When sulfuric acid and copper (II) are allowed to react, copper (II) sulfate and water are formed. How do you write a balanced equation for this reaction?	null
965	a95747ba-6ddd-11ea-b0ab-ccda262736ce	https://socratic.org/questions/for-the-reaction-represented-by-the-equation-n-2-3h-2-2nh-3-how-many-moles-of-ni	9.00 moles	start physical_unit 18 18 mole mol qc_end physical_unit 26 26 23 24 mole qc_end chemical_equation 7 13 qc_end end	[{"type":"physical unit","value":"Mole [OF] nitrogen [IN] moles"}]	[{"type":"physical unit","value":"9.00 moles"}]	[{"type":"physical unit","value":"Mole [OF] ammonia [=] \\pu{18 mol}"},{"type":"chemical equation","value":"N2 + 3 H2 -> 2 NH3"}]	<h1 class="questionTitle" itemprop="name">For the reaction represented by the equation #N_2 + 3H_2 -> 2NH_3#, how many moles of nitrogen are required to produce 18 mol of ammonia?</h1>	null	9.00 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The reaction is:</p> <p><mathjax>#N_2(g) + 3H_2(g)->2HN_3(g)#</mathjax></p> <p>The molar ratio between Nitrogen and ammonia is <mathjax>#1:3#</mathjax>, therefore, to produce 18 moles of ammonia, we will need:</p> <p><mathjax>#?molN_2=18cancel(molNH_3)xx(1molN_2)/(2cancel(molNH_3))=9molN_2#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#9molN_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The reaction is:</p> <p><mathjax>#N_2(g) + 3H_2(g)->2HN_3(g)#</mathjax></p> <p>The molar ratio between Nitrogen and ammonia is <mathjax>#1:3#</mathjax>, therefore, to produce 18 moles of ammonia, we will need:</p> <p><mathjax>#?molN_2=18cancel(molNH_3)xx(1molN_2)/(2cancel(molNH_3))=9molN_2#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">For the reaction represented by the equation #N_2 + 3H_2 -> 2NH_3#, how many moles of nitrogen are required to produce 18 mol of ammonia?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/equation-stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Equation Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="217295" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ali-h-1"><img alt="" class="" src="https://profilepictures.socratic.org/IITeL1YTQdODdLp0aJTL_StereoPicture%20copy.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ali-h-1"> Dr. Hayek </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-26T15:25:24" itemprop="dateCreated"> Jan 26, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#9molN_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The reaction is:</p> <p><mathjax>#N_2(g) + 3H_2(g)->2HN_3(g)#</mathjax></p> <p>The molar ratio between Nitrogen and ammonia is <mathjax>#1:3#</mathjax>, therefore, to produce 18 moles of ammonia, we will need:</p> <p><mathjax>#?molN_2=18cancel(molNH_3)xx(1molN_2)/(2cancel(molNH_3))=9molN_2#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/217295" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="260877" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/edmund-l"><img alt="" class="" src="https://profilepictures.socratic.org/DnAPD8TISDW0aROTp4qA_Day_3_Story_1._Photo_with_Sky_Tower_from_distance_Walked_around_most_of_west_Auckland_suburbs._Some_of_you_mightve_seen_.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/edmund-l"> Edmund Liew </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-01T08:00:27" itemprop="dateCreated"> May 1, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerDescription"> <div> <div class="markdown"><p>Compare <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio between <mathjax>#NH_3#</mathjax> and <mathjax>#N_2#</mathjax>. <br/> The mole ratio between <mathjax>#NH_3 : N_2#</mathjax> is <mathjax>#2:1#</mathjax>.</p> <p>If 2 moles of <mathjax>#NH_3#</mathjax> gives you 1 mole of <mathjax>#N_2#</mathjax>,</p> <p>then 18 moles of <mathjax>#NH_3#</mathjax> should give you:<br/> [18 moles<mathjax>#-:#</mathjax> 2 <mathjax>#xx#</mathjax> 1] = 9 moles of <mathjax>#N_2#</mathjax></p> <p>Therefore 9 moles of nitrogen are required to produce 18 moles of ammonia.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/260877" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4171602bf3469588dc36e"> What are the types of stoichiometry examples, with examples? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4171802bf3469570e2e82"> Question #e2e82 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/533668a402bf34573b4e66fb"> What mass of carbon dioxide can 1.00 kg of lithium oxide absorb? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" 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reactants to products? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-gas-stoichiometry-differ-from-stoichiometry-of-solids-and-liquids"> How does gas stoichiometry differ from stoichiometry of solids and liquids? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-stoichiometry-relate-to-the-law-of-conservation"> How does stoichiometry relate to the law of conservation? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/equation-stoichiometry"> See all questions in Equation Stoichiometry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 57381 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	For the reaction represented by the equation #N_2 + 3H_2 -> 2NH_3#, how many moles of nitrogen are required to produce 18 mol of ammonia?	null
966	a8ca14d3-6ddd-11ea-b6c9-ccda262736ce	https://socratic.org/questions/the-compound-copper-ii-bromide-is-a-strong-electrolyte-what-is-the-reaction-when	CuBr2(s) -> Cu^2+(aq) + 2 Br-(aq)	start chemical_equation qc_end c_other OTHER qc_end substance 13 15 qc_end substance 19 19 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the reaction"}]	[{"type":"chemical equation","value":"CuBr2(s) -> Cu^2+(aq) + 2 Br-(aq)"}]	[{"type":"other","value":"The compound copper(II) bromide is a strong electrolyte."},{"type":"substance name","value":"Solid copper(II) bromide"},{"type":"substance name","value":"Water"}]	<h1 class="questionTitle" itemprop="name">The compound copper(II) bromide is a strong electrolyte. What is the reaction when solid copper(II) bromide is put into water?</h1>	null	CuBr2(s) -> Cu^2+(aq) + 2 Br-(aq)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Upon dissolution of anhydrous cupric bromide, the beautiful blue colour of <mathjax>#Cu^(2+)(aq)#</mathjax>, i.e. <mathjax>#[Cu(OH_2)_6]^(2+)#</mathjax>, would develop.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#CuBr_2(s) rarr Cu^(2+)(aq) + 2Br^(-)(aq)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Upon dissolution of anhydrous cupric bromide, the beautiful blue colour of <mathjax>#Cu^(2+)(aq)#</mathjax>, i.e. <mathjax>#[Cu(OH_2)_6]^(2+)#</mathjax>, would develop.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">The compound copper(II) bromide is a strong electrolyte. What is the reaction when solid copper(II) bromide is put into water?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-reactions-and-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions and Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="239583" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-14T15:06:23" itemprop="dateCreated"> Mar 14, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#CuBr_2(s) rarr Cu^(2+)(aq) + 2Br^(-)(aq)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Upon dissolution of anhydrous cupric bromide, the beautiful blue colour of <mathjax>#Cu^(2+)(aq)#</mathjax>, i.e. <mathjax>#[Cu(OH_2)_6]^(2+)#</mathjax>, would develop.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/239583" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb002bf34694a4fee47"> Question #fee47 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb402bf34694c8c5c15"> Question #c5c15 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb802bf346950519eb9"> Question #19eb9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cbf02bf3469570e2ea2"> Question #e2ea2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc002bf34695a6bc751"> Question #bc751 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc202bf3469570e2ea6"> Question #e2ea6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531e867a02bf342492a08b07"> Question #08b07 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-thermochemical-equation-for-the-combustion-of-benzene"> What is the thermochemical equation for the combustion of benzene? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-reversible"> Why are chemical reactions reversible? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-important"> Why are chemical reactions important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/chemical-reactions-and-equations"> See all questions in Chemical Reactions and Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 14799 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	The compound copper(II) bromide is a strong electrolyte. What is the reaction when solid copper(II) bromide is put into water?	null
967	a92c91b4-6ddd-11ea-9847-ccda262736ce	https://socratic.org/questions/what-is-the-ionic-equation-for-na2co3-ba-no3-2-baco3-2nano3	Ba^2+(aq) + CO3^2-(aq) -> BaCO3(s)	start chemical_equation qc_end chemical_equation 6 13 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the ionic equation"}]	[{"type":"chemical equation","value":"Ba^2+(aq) + CO3^2-(aq) -> BaCO3(s)"}]	[{"type":"chemical equation","value":"Na2CO3 + Ba(NO3)2 -> BaCO3 + 2 NaNO3"}]	<h1 class="questionTitle" itemprop="name">What is the ionic equation for Na2CO3 + Ba(NO3)2 -> BaCO3 + 2NaNO3?</h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>It is the reaction between sodium carbonate and barium nitrate. It would be super helpful if you could also show the net ionic equation.</p></div> </h2> </div> </div>	Ba^2+(aq) + CO3^2-(aq) -> BaCO3(s)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Both reaction <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a> are ionic and are aqueous in solution. </p> <p>The products are a relatively insoluble compound and a compound that remains in solution as ions. </p> <p>The complete ionic equation is </p> <p><mathjax># 2 Na^(+1)(aq) + 1 CO_3(-2)(aq) + 1 Ba^(+2)(aq) + 2 NO_3^(-1)(aq) ->#</mathjax></p> <p><mathjax># 2 Na^(+1)(aq) + 2 NO_3^(-1)(aq) + 1 BaCO_3(s) #</mathjax></p> <p>Since the Sodium ions <mathjax>#Na^(+1)(aq) #</mathjax> and Nitrate <mathjax>#NO_3^(-1)(aq)#</mathjax><br/> Do not Change they are not part of the net ionic equation. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The net ionic equation is <mathjax># Ba^(+2)(aq) + CO_3^(-2)(aq) -> BaCO_3(s)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Both reaction <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a> are ionic and are aqueous in solution. </p> <p>The products are a relatively insoluble compound and a compound that remains in solution as ions. </p> <p>The complete ionic equation is </p> <p><mathjax># 2 Na^(+1)(aq) + 1 CO_3(-2)(aq) + 1 Ba^(+2)(aq) + 2 NO_3^(-1)(aq) ->#</mathjax></p> <p><mathjax># 2 Na^(+1)(aq) + 2 NO_3^(-1)(aq) + 1 BaCO_3(s) #</mathjax></p> <p>Since the Sodium ions <mathjax>#Na^(+1)(aq) #</mathjax> and Nitrate <mathjax>#NO_3^(-1)(aq)#</mathjax><br/> Do not Change they are not part of the net ionic equation. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the ionic equation for Na2CO3 + Ba(NO3)2 -> BaCO3 + 2NaNO3?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>It is the reaction between sodium carbonate and barium nitrate. It would be super helpful if you could also show the net ionic equation.</p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/double-replacement-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Double Replacement Reactions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="323565" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/david-drayer"><img alt="" class="" src="https://graph.facebook.com/10206723679871989/picture?height=50&width=50" title=""/></a> <a class="secondContributorPic" href="/users/grace-9"><img alt="" class="" src="https://profilepictures.socratic.org/gzi0U3RQNuMSxgKVeKgw_10960213_10153434463490909_9111641440892052754_o.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/david-drayer"> David Drayer </a>·<a class="topContributorLink" href="/users/grace-9"> Grace </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-10-19T03:21:55" itemprop="dateCreated"> Oct 19, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The net ionic equation is <mathjax># Ba^(+2)(aq) + CO_3^(-2)(aq) -> BaCO_3(s)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Both reaction <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a> are ionic and are aqueous in solution. </p> <p>The products are a relatively insoluble compound and a compound that remains in solution as ions. </p> <p>The complete ionic equation is </p> <p><mathjax># 2 Na^(+1)(aq) + 1 CO_3(-2)(aq) + 1 Ba^(+2)(aq) + 2 NO_3^(-1)(aq) ->#</mathjax></p> <p><mathjax># 2 Na^(+1)(aq) + 2 NO_3^(-1)(aq) + 1 BaCO_3(s) #</mathjax></p> <p>Since the Sodium ions <mathjax>#Na^(+1)(aq) #</mathjax> and Nitrate <mathjax>#NO_3^(-1)(aq)#</mathjax><br/> Do not Change they are not part of the net ionic equation. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/323565" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41c3a02bf346963eb9867"> How do you balance the chemical equations for double replacement reactions? 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</a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/double-replacement-reactions"> See all questions in Double Replacement Reactions </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 53924 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the ionic equation for Na2CO3 + Ba(NO3)2 -> BaCO3 + 2NaNO3?	It is the reaction between sodium carbonate and barium nitrate. It would be super helpful if you could also show the net ionic equation.
968	aadef954-6ddd-11ea-9da7-ccda262736ce	https://socratic.org/questions/a-sample-of-nitrogen-gas-occupies-130-ml-at-20-c-what-volume-will-the-gas-occupy	141.09 mL	start physical_unit 1 4 volume ml qc_end physical_unit 1 4 6 7 volume qc_end physical_unit 1 4 9 10 temperature qc_end physical_unit 1 4 18 19 temperature qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Volume2 [OF] nitrogen gas sample [IN] mL"}]	[{"type":"physical unit","value":"141.09 mL"}]	[{"type":"physical unit","value":"Volume1 [OF] nitrogen gas sample [=] \\pu{130 mL}"},{"type":"physical unit","value":"Temperature1 [OF] nitrogen gas sample [=] \\pu{20 ℃}"},{"type":"physical unit","value":"Temperature2 [OF] nitrogen gas sample [=] \\pu{45 ℃}"},{"type":"other","value":"Constant pressure."}]	<h1 class="questionTitle" itemprop="name">A sample of nitrogen gas occupies 130 mL at 20°C. What volume will the gas occupy at 45°C if the pressure remains constant?</h1>	null	141.09 mL	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This problem requires the use of <a href="https://socratic.org/chemistry/the-behavior-of-gases/charles-law">Charles' Law</a> comparing the direct relationship between Volume and Temperature.</p> <p><mathjax>#V_1/T_1 = V_2/T_2#</mathjax></p> <p><mathjax>#V_1= 130 mL#</mathjax><br/> <mathjax>#T_1=20^oC = 293K#</mathjax> <br/> <mathjax>#V_2=?#</mathjax><br/> <mathjax>#T_2=45^oC = 318K#</mathjax></p> <p>Always convert <mathjax>#^oC#</mathjax> to <mathjax>#K#</mathjax></p> <p><mathjax>#K=^oC +273#</mathjax></p> <p>I prefer to isolate the variable before I plug in the values</p> <p><mathjax>#(V_1T_2)/T_1 = V_2#</mathjax></p> <p><mathjax>#(130mL(318cancelK))/(293cancelK)= V_2#</mathjax></p> <p><mathjax>#V_2 = 141.09 mL#</mathjax></p> <p> <iframe src="https://www.youtube.com/embed/DiURoQ4bhvA?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#V_2 = 141.09 mL#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This problem requires the use of <a href="https://socratic.org/chemistry/the-behavior-of-gases/charles-law">Charles' Law</a> comparing the direct relationship between Volume and Temperature.</p> <p><mathjax>#V_1/T_1 = V_2/T_2#</mathjax></p> <p><mathjax>#V_1= 130 mL#</mathjax><br/> <mathjax>#T_1=20^oC = 293K#</mathjax> <br/> <mathjax>#V_2=?#</mathjax><br/> <mathjax>#T_2=45^oC = 318K#</mathjax></p> <p>Always convert <mathjax>#^oC#</mathjax> to <mathjax>#K#</mathjax></p> <p><mathjax>#K=^oC +273#</mathjax></p> <p>I prefer to isolate the variable before I plug in the values</p> <p><mathjax>#(V_1T_2)/T_1 = V_2#</mathjax></p> <p><mathjax>#(130mL(318cancelK))/(293cancelK)= V_2#</mathjax></p> <p><mathjax>#V_2 = 141.09 mL#</mathjax></p> <p> <iframe src="https://www.youtube.com/embed/DiURoQ4bhvA?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A sample of nitrogen gas occupies 130 mL at 20°C. What volume will the gas occupy at 45°C if the pressure remains constant?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/charles-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Charles' Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="259218" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/brian-m"><img alt="" class="" src="https://profilepictures.socratic.org/ZCpnJDgSFKORtvaSPDeG_Lego%20Me.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/brian-m"> BRIAN M. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-04-27T02:57:49" itemprop="dateCreated"> Apr 27, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#V_2 = 141.09 mL#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This problem requires the use of <a href="https://socratic.org/chemistry/the-behavior-of-gases/charles-law">Charles' Law</a> comparing the direct relationship between Volume and Temperature.</p> <p><mathjax>#V_1/T_1 = V_2/T_2#</mathjax></p> <p><mathjax>#V_1= 130 mL#</mathjax><br/> <mathjax>#T_1=20^oC = 293K#</mathjax> <br/> <mathjax>#V_2=?#</mathjax><br/> <mathjax>#T_2=45^oC = 318K#</mathjax></p> <p>Always convert <mathjax>#^oC#</mathjax> to <mathjax>#K#</mathjax></p> <p><mathjax>#K=^oC +273#</mathjax></p> <p>I prefer to isolate the variable before I plug in the values</p> <p><mathjax>#(V_1T_2)/T_1 = V_2#</mathjax></p> <p><mathjax>#(130mL(318cancelK))/(293cancelK)= V_2#</mathjax></p> <p><mathjax>#V_2 = 141.09 mL#</mathjax></p> <p> <iframe src="https://www.youtube.com/embed/DiURoQ4bhvA?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/259218" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-must-charles-law-be-in-kelvins"> Why must Charles' law be in kelvin? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-charles-law-formula"> What is Charles' law formula? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/oxygen-gas-is-at-a-temperature-of-40-c-when-it-occupies-a-volume-of-2-3-liters-t"> Oxygen gas is at a temperature of 40°C when it occupies a volume of 2.3 liters. 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969	aa718ef1-6ddd-11ea-924b-ccda262736ce	https://socratic.org/questions/599054c5b72cff3fecd96af8	Mg(s) + H2SO4(aq) -> MgSO4(aq) + H2(g)^	start chemical_equation qc_end substance 2 3 qc_end substance 6 7 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the equation"}]	[{"type":"chemical equation","value":"Mg(s) + H2SO4(aq) -> MgSO4(aq) + H2(g)^"}]	[{"type":"substance name","value":"Magnesium metal"},{"type":"substance name","value":"Sulfuric acid"}]	<h1 class="questionTitle" itemprop="name">How is magnesium metal oxidized by sulfuric acid?</h1>	null	Mg(s) + H2SO4(aq) -> MgSO4(aq) + H2(g)^	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Magnesium is quite an active metal, and hydrogen ion is strong enuff to cause its oxidation......</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Mg(s) + H_2SO_4(aq) rarr MgSO_4(aq) + H_2(g)uarr#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Magnesium is quite an active metal, and hydrogen ion is strong enuff to cause its oxidation......</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How is magnesium metal oxidized by sulfuric acid?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="463507" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-13T13:39:14" itemprop="dateCreated"> Aug 13, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Mg(s) + H_2SO_4(aq) rarr MgSO_4(aq) + H_2(g)uarr#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Magnesium is quite an active metal, and hydrogen ion is strong enuff to cause its oxidation......</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/463507" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? 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970	aaac1eb4-6ddd-11ea-b52c-ccda262736ce	https://socratic.org/questions/what-volume-is-needed-to-store-0-80-moles-of-helium-gas-at-204-6-kpa-and-300-k	9.76 L	start physical_unit 9 10 volume l qc_end physical_unit 9 10 6 7 mole qc_end physical_unit 9 10 15 16 temperature qc_end physical_unit 9 10 12 13 pressure qc_end end	[{"type":"physical unit","value":"Volume [OF] helium gas [IN] L"}]	[{"type":"physical unit","value":"9.76 L"}]	[{"type":"physical unit","value":"Mole [OF] helium gas [=] \\pu{0.80 moles}"},{"type":"physical unit","value":"Temperature [OF] helium gas [=] \\pu{300 K}"},{"type":"physical unit","value":"Pressure [OF] helium gas [=] \\pu{204.6 kPa}"}]	<h1 class="questionTitle" itemprop="name">What volume is needed to store 0.80 moles of helium gas at 204.6 kPa and 300 K?</h1>	null	9.76 L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>For this type of question we would use the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law equation</a><br/> <mathjax>#PxxV = nxxRxxT#</mathjax>. </p> <ul> <li>P represents pressure (must have units of atm)</li> <li>V represents volume (must have units of liters)</li> <li>n represents the number of moles</li> <li>R is the proportionality constant (has a value of 0.0821 with units of <mathjax>#(Lxxatm)/ (molxxK)#</mathjax>)</li> <li>T represents the temperature, which must be in Kelvins.</li> </ul> <p>Now what you want to do is list your known and unknown variables. Our only unknown is the volume of helium gas. Our known variables are P,n,R, and T. </p> <p>The pressure has the incorrect units because the pressure should be in atmospheres instead of kPa. In order to go from kPa to atm we use the following relationship:</p> <p><mathjax>#101.325 kPa = 1 atm#</mathjax></p> <p><mathjax>#(204.6cancel"kPa")/(101.325cancel"kPa")xx1atm#</mathjax> = <mathjax>#2.019atm#</mathjax></p> <p>Now all we have to do is rearrange the equation and solve for P like so: <br/> <mathjax>#V = (nxxRxxT)/P#</mathjax><br/> <mathjax>#V = (0.80cancel"mol"xx0.0821(Lxxcancel"atm")/(cancel"mo"lxxcancel"K")xx(300cancel"K"))/(2.019cancel"atm")#</mathjax><br/> <mathjax>#V = 9.76 L#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The volume of helium gas is <mathjax>#9.76 L#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>For this type of question we would use the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law equation</a><br/> <mathjax>#PxxV = nxxRxxT#</mathjax>. </p> <ul> <li>P represents pressure (must have units of atm)</li> <li>V represents volume (must have units of liters)</li> <li>n represents the number of moles</li> <li>R is the proportionality constant (has a value of 0.0821 with units of <mathjax>#(Lxxatm)/ (molxxK)#</mathjax>)</li> <li>T represents the temperature, which must be in Kelvins.</li> </ul> <p>Now what you want to do is list your known and unknown variables. Our only unknown is the volume of helium gas. Our known variables are P,n,R, and T. </p> <p>The pressure has the incorrect units because the pressure should be in atmospheres instead of kPa. In order to go from kPa to atm we use the following relationship:</p> <p><mathjax>#101.325 kPa = 1 atm#</mathjax></p> <p><mathjax>#(204.6cancel"kPa")/(101.325cancel"kPa")xx1atm#</mathjax> = <mathjax>#2.019atm#</mathjax></p> <p>Now all we have to do is rearrange the equation and solve for P like so: <br/> <mathjax>#V = (nxxRxxT)/P#</mathjax><br/> <mathjax>#V = (0.80cancel"mol"xx0.0821(Lxxcancel"atm")/(cancel"mo"lxxcancel"K")xx(300cancel"K"))/(2.019cancel"atm")#</mathjax><br/> <mathjax>#V = 9.76 L#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What volume is needed to store 0.80 moles of helium gas at 204.6 kPa and 300 K?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/ideal-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Ideal Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="275802" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/kayla-14"><img alt="" class="" src="https://profilepictures.socratic.org/OvMTWaamQPWcqLIkUNnG_793604964071127.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/kayla-14"> Kayla </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-10T02:18:29" itemprop="dateCreated"> Jun 10, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The volume of helium gas is <mathjax>#9.76 L#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>For this type of question we would use the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law equation</a><br/> <mathjax>#PxxV = nxxRxxT#</mathjax>. </p> <ul> <li>P represents pressure (must have units of atm)</li> <li>V represents volume (must have units of liters)</li> <li>n represents the number of moles</li> <li>R is the proportionality constant (has a value of 0.0821 with units of <mathjax>#(Lxxatm)/ (molxxK)#</mathjax>)</li> <li>T represents the temperature, which must be in Kelvins.</li> </ul> <p>Now what you want to do is list your known and unknown variables. Our only unknown is the volume of helium gas. Our known variables are P,n,R, and T. </p> <p>The pressure has the incorrect units because the pressure should be in atmospheres instead of kPa. In order to go from kPa to atm we use the following relationship:</p> <p><mathjax>#101.325 kPa = 1 atm#</mathjax></p> <p><mathjax>#(204.6cancel"kPa")/(101.325cancel"kPa")xx1atm#</mathjax> = <mathjax>#2.019atm#</mathjax></p> <p>Now all we have to do is rearrange the equation and solve for P like so: <br/> <mathjax>#V = (nxxRxxT)/P#</mathjax><br/> <mathjax>#V = (0.80cancel"mol"xx0.0821(Lxxcancel"atm")/(cancel"mo"lxxcancel"K")xx(300cancel"K"))/(2.019cancel"atm")#</mathjax><br/> <mathjax>#V = 9.76 L#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/275802" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-ideal-gas-constant"> How do you find the ideal gas constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-solve-ideal-gas-law-problems"> How do you solve ideal gas law problems? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-know-which-ideal-gas-constant-to-use"> How do you know which ideal gas constant to use? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ideal-gas-constant-for-butane"> What is the ideal gas constant for butane? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-ideal-gas-law-in-kelvin"> Why is ideal gas law in kelvin? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ideal-gas-constant-important"> Why is the ideal gas constant important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-di-electric-constant"> What is the di-electric constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-volume-l-will-0-20-mol-hi-occupy-at-300-k-and-100-0-kpa-r-8-314-kpa-l-k-mol"> What volume (L) will 0.20 mol HI occupy at 300 K and 100.0 kPa? R = 8.314 kPa L / (K mol) =... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-molar-mass-of-a-gas"> How do you calculate the molar mass of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-should-i-use-the-ideal-gas-law-and-not-the-combined-gas-law"> When should I use the ideal gas law and not the combined gas law? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/ideal-gas-law"> See all questions in Ideal Gas Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 4829 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What volume is needed to store 0.80 moles of helium gas at 204.6 kPa and 300 K?	null
971	a978244a-6ddd-11ea-81f3-ccda262736ce	https://socratic.org/questions/5a40599a7c014940a71858d2	11.70	start physical_unit 6 7 ph none qc_end physical_unit 6 7 18 19 temperature qc_end end	[{"type":"physical unit","value":"pH [OF] the aqueous solution"}]	[{"type":"physical unit","value":"11.70"}]	[{"type":"physical unit","value":"Concentration [OF] hydroxid [=] \\pu{5 × 10^(-3) M}"},{"type":"physical unit","value":"Temperature [OF] the aqueous solution [=] \\pu{25 ℃}"}]	<h1 class="questionTitle" itemprop="name">What is the #"pH"# for an aqueous solution with a hydroxide concentration of #5 xx 10^(-3) "M"# at #25^@ "C"#?</h1>	null	11.70	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote> <p><mathjax>#"pOH" = - log["OH"^-]#</mathjax></p> </blockquote> <p><mathjax>#"pOH" = - log(5 × 10^-3) = 3 - log5 = 2.30#</mathjax></p> <p>Now,</p> <blockquote> <p><mathjax>#"pH" + "pOH" = 14#</mathjax></p> </blockquote> <p><mathjax>#"pH" = 14 - "pOH" = 14 - 2.30 = 11.7#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#11.7#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote> <p><mathjax>#"pOH" = - log["OH"^-]#</mathjax></p> </blockquote> <p><mathjax>#"pOH" = - log(5 × 10^-3) = 3 - log5 = 2.30#</mathjax></p> <p>Now,</p> <blockquote> <p><mathjax>#"pH" + "pOH" = 14#</mathjax></p> </blockquote> <p><mathjax>#"pH" = 14 - "pOH" = 14 - 2.30 = 11.7#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the #"pH"# for an aqueous solution with a hydroxide concentration of #5 xx 10^(-3) "M"# at #25^@ "C"#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/the-ph-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">pH</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="526531" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/junaid-mirza"><img alt="" class="" src="https://profilepictures.socratic.org/BBeNx7NTQ7WmDQKll8wN_BDC9EDF4-5DCB-440D-8ADC-ADACE2966216.jpeg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/junaid-mirza"> Junaid Mirza </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-12-25T02:26:13" itemprop="dateCreated"> Dec 25, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#11.7#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote> <p><mathjax>#"pOH" = - log["OH"^-]#</mathjax></p> </blockquote> <p><mathjax>#"pOH" = - log(5 × 10^-3) = 3 - log5 = 2.30#</mathjax></p> <p>Now,</p> <blockquote> <p><mathjax>#"pH" + "pOH" = 14#</mathjax></p> </blockquote> <p><mathjax>#"pH" = 14 - "pOH" = 14 - 2.30 = 11.7#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/526531" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="526875" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/chirag-1"><img alt="" class="" src="https://profilepictures.socratic.org/bBbJzRtrQ8KzJdgnn3mc_1556627021124401.jpg" title=""/></a> <a class="secondContributorPic" href="/users/truong-son-n"><img alt="" class="" src="https://profilepictures.socratic.org/07k4plnQfmnmzMuesQzw_14844-1449381920.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/chirag-1"> Chirag Mehta </a>·<a class="topContributorLink" href="/users/truong-son-n"> Truong-Son N. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-12-26T08:13:02" itemprop="dateCreated"> Dec 26, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"pH" ~~ color(blue)(11.7)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#color (indigo)(pH=-log [H_3O^+])#</mathjax><br/> <mathjax>#color (indigo)(pOH=-log [OH^-])#</mathjax><br/> <mathjax>#color(cyan)([OH^-]=0.005)#</mathjax><br/> Here, <br/> <mathjax>#pOH=-log [0.005]#</mathjax><br/> <mathjax>#pOH=-log [5×10^-3]#</mathjax><br/> <mathjax>#pOH=2.3010299957#</mathjax></p> <p><mathjax>#color (green)(pH=14-pOH)#</mathjax></p> <p><mathjax>#ph=14-2.301 =11.699#</mathjax> <mathjax>#~~#</mathjax> <mathjax>#bb11.7#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/526875" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-pka"> How do you determine pH from pKa? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-ph-values-of-acids-and-bases-differ"> How do pH values of acids and bases differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-something-on-a-ph-scale"> How do you calculate something on a pH scale? </a> </div> </li> <li class="relatedQuestionItem"> <div 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href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the #"pH"# for an aqueous solution with a hydroxide concentration of #5 xx 10^(-3) "M"# at #25^@ "C"#?	null
972	a9eb3f69-6ddd-11ea-98ce-ccda262736ce	https://socratic.org/questions/at-stp-560-l-of-argon-gas-masses-how-much	998.7 g	start physical_unit 5 6 mass g qc_end physical_unit 5 6 2 3 volume qc_end c_other STP qc_end end	[{"type":"physical unit","value":"Mass [OF] argon gas [IN] g"}]	[{"type":"physical unit","value":"998.7 g"}]	[{"type":"physical unit","value":"Volume [OF] argon gas [=] \\pu{560 L}"},{"type":"other","value":"STP"}]	<h1 class="questionTitle" itemprop="name">At STP, 560 L of argon gas masses how much?</h1>	null	998.7 g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>One mole of Argon weighs 39.948g</p> <p>One litre of any gas at STP has a volume of 22.4 L</p> <p>So #(540L)/(22.4L) = 25 moles of argon</p> <p>25 moles Ar x 39.948 g/mol = 998.7 g</p> <p>Since you started with a measurement containing only two significant digits, your answer can only contain two significant digits, so it rounds to 1.0x10^3 g (or 1.0 kg)</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>1.0 kg</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>One mole of Argon weighs 39.948g</p> <p>One litre of any gas at STP has a volume of 22.4 L</p> <p>So #(540L)/(22.4L) = 25 moles of argon</p> <p>25 moles Ar x 39.948 g/mol = 998.7 g</p> <p>Since you started with a measurement containing only two significant digits, your answer can only contain two significant digits, so it rounds to 1.0x10^3 g (or 1.0 kg)</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">At STP, 560 L of argon gas masses how much?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp" itemprop="url"> <span class="breadcrumb" itemprop="title">Molar Volume of a Gas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="235826" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/richard-g-3"><img alt="" class="" src="https://graph.facebook.com/10204652475061709/picture?height=50&width=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/richard-g-3"> Richard G. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-06T13:45:43" itemprop="dateCreated"> Mar 6, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>1.0 kg</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>One mole of Argon weighs 39.948g</p> <p>One litre of any gas at STP has a volume of 22.4 L</p> <p>So #(540L)/(22.4L) = 25 moles of argon</p> <p>25 moles Ar x 39.948 g/mol = 998.7 g</p> <p>Since you started with a measurement containing only two significant digits, your answer can only contain two significant digits, so it rounds to 1.0x10^3 g (or 1.0 kg)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/235826" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-stoichiometric-ratios-relate-to-molar-volume-of-a-gas"> How do stoichiometric ratios relate to molar volume of a gas? 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973	ab926cf6-6ddd-11ea-a822-ccda262736ce	https://socratic.org/questions/a-sample-of-an-gas-has-a-volume-of-2-25-l-at-286-k-and-1-13-atm-what-is-the-pres	1.42 atm	start physical_unit 4 4 pressure atm qc_end physical_unit 4 4 9 10 volume qc_end physical_unit 4 4 12 13 temperature qc_end physical_unit 4 4 15 16 pressure qc_end physical_unit 4 4 25 26 volume qc_end physical_unit 4 4 30 31 pressure qc_end end	[{"type":"physical unit","value":"Pressure2 [OF] the gas sample [IN] atm"}]	[{"type":"physical unit","value":"1.42 atm"}]	[{"type":"physical unit","value":"Volume1 [OF] the gas sample [=] \\pu{2.25 L}"},{"type":"physical unit","value":"Temperature1 [OF] the gas sample [=] \\pu{286 K}"},{"type":"physical unit","value":"Pressure1 [OF] the gas sample [=] \\pu{1.13 atm}"},{"type":"physical unit","value":"Volume2 [OF] the gas sample [=] \\pu{1.89 L}"},{"type":"physical unit","value":"Pressure2 [OF] the gas sample [=] \\pu{302 K}"}]	<h1 class="questionTitle" itemprop="name">A sample of an gas has a volume of 2.25 L at 286 K and 1.13 atm. What is the pressure when the volume is 1.89 L and temperature is 302 K?</h1>	null	1.42 atm	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And so <mathjax>#P_2=(P_1V_1T_2)/(T_1V_2).#</mathjax> </p> <p>The RHS expression clearly has the units of pressure as required, why?</p> <p><mathjax>#P_2=(1.13atmxx2.25cancelLxx302cancelK)/(286cancelKxx1.89*cancelL)=??atm#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The <a href="https://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">combined gas law</a> holds that <mathjax>#(P_1V_1)/T_1=(P_2V_2)/T_2#</mathjax>. The amount of gas is assumed to be constant. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And so <mathjax>#P_2=(P_1V_1T_2)/(T_1V_2).#</mathjax> </p> <p>The RHS expression clearly has the units of pressure as required, why?</p> <p><mathjax>#P_2=(1.13atmxx2.25cancelLxx302cancelK)/(286cancelKxx1.89*cancelL)=??atm#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A sample of an gas has a volume of 2.25 L at 286 K and 1.13 atm. What is the pressure when the volume is 1.89 L and temperature is 302 K?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/atmospheric-pressure" itemprop="url"> <span class="breadcrumb" itemprop="title">Atmospheric Pressure</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="388228" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-08T06:46:47" itemprop="dateCreated"> Mar 8, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The <a href="https://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">combined gas law</a> holds that <mathjax>#(P_1V_1)/T_1=(P_2V_2)/T_2#</mathjax>. The amount of gas is assumed to be constant. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And so <mathjax>#P_2=(P_1V_1T_2)/(T_1V_2).#</mathjax> </p> <p>The RHS expression clearly has the units of pressure as required, why?</p> <p><mathjax>#P_2=(1.13atmxx2.25cancelLxx302cancelK)/(286cancelKxx1.89*cancelL)=??atm#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/388228" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-atmospheric-pressure-affect-evaporation"> How does atmospheric pressure affect evaporation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-atmospheric-pressure-at-an-altitude"> How do you calculate atmospheric pressure at an altitude? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-air-pressure-greatest-at-the-earth-s-surface"> Why is air pressure greatest at the Earth's surface? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-causes-hydrostatic-pressure-in-blood-vessels"> What causes hydrostatic pressure in blood vessels? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-hydrostatic-pressure-created"> How is hydrostatic pressure created? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-atmospheric-pressure-change-in-the-troposphere"> How does atmospheric pressure change in the troposphere? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/does-air-pressure-change-with-humidity"> Does air pressure change with humidity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-atmospheric-pressure-affect-boiling-points"> How does atmospheric pressure affect boiling points? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-air-pressure-is-measured-for-weather-information"> How is air pressure measured for weather information? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-air-pressure-regulators-work"> How do air pressure regulators work? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/atmospheric-pressure"> See all questions in Atmospheric Pressure </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1488 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A sample of an gas has a volume of 2.25 L at 286 K and 1.13 atm. What is the pressure when the volume is 1.89 L and temperature is 302 K?	null
974	a8882964-6ddd-11ea-ab0c-ccda262736ce	https://socratic.org/questions/to-resolve-an-object-in-an-electron-microscope-the-wavelength-of-the-electrons-m	4.18 × 10^(-20) J	start physical_unit 11 12 kinetic_energy j qc_end physical_unit 5 6 50 53 mass qc_end physical_unit 33 35 38 39 diameter qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"kinetic energy [OF] the electrons [IN] J"}]	[{"type":"physical unit","value":"4.18 × 10^(-20) J"}]	[{"type":"physical unit","value":"Mass [OF] an electron [=] \\pu{9.11 x 10^(-31) kg}"},{"type":"physical unit","value":"Diameter [OF] a protein molecule [=] \\pu{2.40 nm}"},{"type":"other","value":"To resolve an object in an electron microscope, the wavelength of the electrons must be close to the diameter of the object. "}]	<h1 class="questionTitle" itemprop="name">To resolve an object in an electron microscope, the wavelength of the electrons must be close to the diameter of the object. What kinetic energy must the electrons have in order to resolve a protein molecule that is 2.40 nm in diameter? </h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>Take the mass of an electron to be <mathjax>#9.11x 10^-31#</mathjax> kg. </p></div> </h2> </div> </div>	4.18 × 10^(-20) J	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>I will set the wavelength of the electron to be equal to the diameter of the protein molecule:</p> <p><mathjax>#sf(lambda=2.4xx10^(-9)color(white)(x)m)#</mathjax></p> <p>The de Broglie expression gives us:</p> <p><mathjax>#sf(lambda=h/(mv))#</mathjax></p> <p><mathjax>#:.#</mathjax><mathjax>#sf(v=h/(mlambda))#</mathjax></p> <p><mathjax>#sf(v=(6.63xx10^(-34))/(9.11xx10^(-31)xx2.4xx10^(-9))color(white)(x)"m/s")#</mathjax></p> <p><mathjax>#sf(v=3.03xx10^(5)color(white)(x)"m/s")#</mathjax></p> <p>Kinetic energy <mathjax>#sf(=1/2mv^2)#</mathjax></p> <p><mathjax>#:.#</mathjax><mathjax>#sf(KE=1/2xx9.11xx10^(-31)xx(3.03xx10^5)^2color(white)(x)J)#</mathjax></p> <p><mathjax>#sf(KE=4.18xx10^(-20)color(white)(x)J)#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#sf(4.18xx10^(-20)color(white)(x)J)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>I will set the wavelength of the electron to be equal to the diameter of the protein molecule:</p> <p><mathjax>#sf(lambda=2.4xx10^(-9)color(white)(x)m)#</mathjax></p> <p>The de Broglie expression gives us:</p> <p><mathjax>#sf(lambda=h/(mv))#</mathjax></p> <p><mathjax>#:.#</mathjax><mathjax>#sf(v=h/(mlambda))#</mathjax></p> <p><mathjax>#sf(v=(6.63xx10^(-34))/(9.11xx10^(-31)xx2.4xx10^(-9))color(white)(x)"m/s")#</mathjax></p> <p><mathjax>#sf(v=3.03xx10^(5)color(white)(x)"m/s")#</mathjax></p> <p>Kinetic energy <mathjax>#sf(=1/2mv^2)#</mathjax></p> <p><mathjax>#:.#</mathjax><mathjax>#sf(KE=1/2xx9.11xx10^(-31)xx(3.03xx10^5)^2color(white)(x)J)#</mathjax></p> <p><mathjax>#sf(KE=4.18xx10^(-20)color(white)(x)J)#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">To resolve an object in an electron microscope, the wavelength of the electrons must be close to the diameter of the object. What kinetic energy must the electrons have in order to resolve a protein molecule that is 2.40 nm in diameter? </h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>Take the mass of an electron to be <mathjax>#9.11x 10^-31#</mathjax> kg. </p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/kinetic-theory-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Kinetic Theory of Gases</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="418127" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/michael-2"><img alt="" class="" src="https://lh3.googleusercontent.com/-gCv6FQRhls0/AAAAAAAAAAI/AAAAAAAAAAA/AAnnY7oOJS05Ylqn3KuDSW0LfnbOk7FezQ/mo/photo.jpg?sz=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/michael-2"> Michael </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-05T13:01:49" itemprop="dateCreated"> May 5, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#sf(4.18xx10^(-20)color(white)(x)J)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>I will set the wavelength of the electron to be equal to the diameter of the protein molecule:</p> <p><mathjax>#sf(lambda=2.4xx10^(-9)color(white)(x)m)#</mathjax></p> <p>The de Broglie expression gives us:</p> <p><mathjax>#sf(lambda=h/(mv))#</mathjax></p> <p><mathjax>#:.#</mathjax><mathjax>#sf(v=h/(mlambda))#</mathjax></p> <p><mathjax>#sf(v=(6.63xx10^(-34))/(9.11xx10^(-31)xx2.4xx10^(-9))color(white)(x)"m/s")#</mathjax></p> <p><mathjax>#sf(v=3.03xx10^(5)color(white)(x)"m/s")#</mathjax></p> <p>Kinetic energy <mathjax>#sf(=1/2mv^2)#</mathjax></p> <p><mathjax>#:.#</mathjax><mathjax>#sf(KE=1/2xx9.11xx10^(-31)xx(3.03xx10^5)^2color(white)(x)J)#</mathjax></p> <p><mathjax>#sf(KE=4.18xx10^(-20)color(white)(x)J)#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/418127" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-kinetic-molecular-theory-explain-gas-laws"> How does kinetic molecular theory explain gas laws? 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What kinetic energy must the electrons have in order to resolve a protein molecule that is 2.40 nm in diameter?	Take the mass of an electron to be #9.11x 10^-31# kg.
975	ac488ab0-6ddd-11ea-a86d-ccda262736ce	https://socratic.org/questions/what-is-the-molarity-of-2-mol-of-ki-dissolved-in-1-l-water	2.00 M	start physical_unit 8 8 molarity mol/l qc_end physical_unit 8 8 5 6 mole qc_end physical_unit 13 13 11 12 volume qc_end end	[{"type":"physical unit","value":"Molarity [OF] KI solution [IN] M"}]	[{"type":"physical unit","value":"2.00 M"}]	[{"type":"physical unit","value":"Mole [OF] KI [=] \\pu{2 mol}"},{"type":"physical unit","value":"Volume [OF] water [=] \\pu{1 L}"}]	<h1 class="questionTitle" itemprop="name">What is the molarity of 2 mol of #KI# dissolved in 1 L water? </h1>	null	2.00 M	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong><a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a></strong> is simply a measure of concentration. </p> <p>For a given solution, <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> is calculated by taking into account how many <strong>moles of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a></strong> you get <strong>per liter of solution</strong>. </p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a)"molarity" = "moles of solute"/"liters of solution"color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>This means that in order to find a solution's molarity, you essentially need to know two things </p> <blockquote> <ul> <li><em>the <strong>number of moles of solute</strong></em></li> <li><em>the <strong>total volume of the solution</strong> expressed in <strong>liters</strong></em></li> </ul> </blockquote> <p>In your case, you know that the solution has a volume of <mathjax>#"1 L"#</mathjax>. Since molarity tells you how many moles of solute you get in <strong>one liter</strong> of solution, the number of moles of solute present in this solution will essentially be equivalent to its molarity. </p> <p>So, if you have <mathjax>#2#</mathjax> <strong>moles</strong> of potassium iodide, <mathjax>#"KI"#</mathjax>, which is your solute, in <mathjax>#"1 L"#</mathjax> of solution, you have a solution of <mathjax>#"2 mol L"^(-1)#</mathjax>, or <mathjax>#"2 molar"#</mathjax>. </p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a)c = n_"solute"/V_"solution"color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>This is equivalent to </p> <blockquote> <p><mathjax>#c_(KI) = "2 moles"/"1 L" = color(green)(\|bar(ul(color(white)(a/a)"2 mol L"^(-1)color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>So keep in mind that every time you're looking for a solution's molarity, you are essentially looking for how many moles of solute you get in <strong>one liter</strong> of solution. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"2 mol L"^(-1)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong><a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a></strong> is simply a measure of concentration. </p> <p>For a given solution, <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> is calculated by taking into account how many <strong>moles of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a></strong> you get <strong>per liter of solution</strong>. </p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a)"molarity" = "moles of solute"/"liters of solution"color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>This means that in order to find a solution's molarity, you essentially need to know two things </p> <blockquote> <ul> <li><em>the <strong>number of moles of solute</strong></em></li> <li><em>the <strong>total volume of the solution</strong> expressed in <strong>liters</strong></em></li> </ul> </blockquote> <p>In your case, you know that the solution has a volume of <mathjax>#"1 L"#</mathjax>. Since molarity tells you how many moles of solute you get in <strong>one liter</strong> of solution, the number of moles of solute present in this solution will essentially be equivalent to its molarity. </p> <p>So, if you have <mathjax>#2#</mathjax> <strong>moles</strong> of potassium iodide, <mathjax>#"KI"#</mathjax>, which is your solute, in <mathjax>#"1 L"#</mathjax> of solution, you have a solution of <mathjax>#"2 mol L"^(-1)#</mathjax>, or <mathjax>#"2 molar"#</mathjax>. </p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a)c = n_"solute"/V_"solution"color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>This is equivalent to </p> <blockquote> <p><mathjax>#c_(KI) = "2 moles"/"1 L" = color(green)(\|bar(ul(color(white)(a/a)"2 mol L"^(-1)color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>So keep in mind that every time you're looking for a solution's molarity, you are essentially looking for how many moles of solute you get in <strong>one liter</strong> of solution. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the molarity of 2 mol of #KI# dissolved in 1 L water? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="249091" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-04-03T18:38:39" itemprop="dateCreated"> Apr 3, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"2 mol L"^(-1)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong><a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a></strong> is simply a measure of concentration. </p> <p>For a given solution, <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> is calculated by taking into account how many <strong>moles of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a></strong> you get <strong>per liter of solution</strong>. </p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a)"molarity" = "moles of solute"/"liters of solution"color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>This means that in order to find a solution's molarity, you essentially need to know two things </p> <blockquote> <ul> <li><em>the <strong>number of moles of solute</strong></em></li> <li><em>the <strong>total volume of the solution</strong> expressed in <strong>liters</strong></em></li> </ul> </blockquote> <p>In your case, you know that the solution has a volume of <mathjax>#"1 L"#</mathjax>. Since molarity tells you how many moles of solute you get in <strong>one liter</strong> of solution, the number of moles of solute present in this solution will essentially be equivalent to its molarity. </p> <p>So, if you have <mathjax>#2#</mathjax> <strong>moles</strong> of potassium iodide, <mathjax>#"KI"#</mathjax>, which is your solute, in <mathjax>#"1 L"#</mathjax> of solution, you have a solution of <mathjax>#"2 mol L"^(-1)#</mathjax>, or <mathjax>#"2 molar"#</mathjax>. </p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a)c = n_"solute"/V_"solution"color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>This is equivalent to </p> <blockquote> <p><mathjax>#c_(KI) = "2 moles"/"1 L" = color(green)(\|bar(ul(color(white)(a/a)"2 mol L"^(-1)color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>So keep in mind that every time you're looking for a solution's molarity, you are essentially looking for how many moles of solute you get in <strong>one liter</strong> of solution. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/249091" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-morality-be-used-as-a-conversion-factor"> How can molarity be used as a conversion factor? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-high-can-molarity-be"> How high can molarity be? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-molarity-change-with-temperature"> How does molarity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molarity-of-a-solution"> How do you find molarity of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-10-naoh"> What is the molarity of 10 NaOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-3-hydrogen-peroxide"> What is the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 10288 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the molarity of 2 mol of #KI# dissolved in 1 L water?	null
976	aa8d2da4-6ddd-11ea-8792-ccda262736ce	https://socratic.org/questions/what-is-the-ph-of-a-solution-with-oh-2-0-times-10-10-m	4.30	start physical_unit 6 6 ph none qc_end physical_unit 6 6 10 13 [oh-] qc_end end	[{"type":"physical unit","value":"pH [OF] the solution"}]	[{"type":"physical unit","value":"4.30"}]	[{"type":"physical unit","value":"[OH-] [OF] the solution [=] \\pu{2.0 × 10^(-10) M}"}]	<h1 class="questionTitle" itemprop="name">What is the pH of a solution with #[OH^-] = 2.0 times 10^-10# #M#?</h1>	null	4.30	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We interrogate the equilibrium:</p> <p><mathjax>#2H_2Orightleftharpoons H_3O^+ + HO^-#</mathjax></p> <p>We know that in aqueous solution under standard conditions that:</p> <p><mathjax>#[H_3O^+][HO^-]=K_w=10^-14#</mathjax></p> <p>We take <mathjax>#log_10#</mathjax> OF BOTH SIDES:</p> <p><mathjax>#log_10[H_3O^+] +log_10[HO^-]=log_10(10^-14)#</mathjax></p> <p>But by definition, the logarithmic function is that power to which you raise the base to get the specific answer.........i.e. if <mathjax>#log_aB=c#</mathjax>, then <mathjax>#a^c=B#</mathjax>. </p> <p>And thus <mathjax>#log_10(10^-14)=-14#</mathjax></p> <p>And so <mathjax>#log_10[H_3O^+] +log_10[HO^-]=-14#</mathjax></p> <p>OR <mathjax>#-log_10[H_3O^+] -log_10[HO^-]=14#</mathjax></p> <p>But we define <mathjax>#pH=-log_10[H_3O^+]#</mathjax>, and <mathjax>#pOH=-log_10[HO^-]#</mathjax>, and so...........</p> <p><mathjax>#14=pH+pOH#</mathjax>. </p> <p>And now finally, <mathjax>#pH=14-pOH#</mathjax> </p> <p><mathjax>#14-(-log_10(2.0xx10^-10)=4.30#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We find <mathjax>#pH~=4#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We interrogate the equilibrium:</p> <p><mathjax>#2H_2Orightleftharpoons H_3O^+ + HO^-#</mathjax></p> <p>We know that in aqueous solution under standard conditions that:</p> <p><mathjax>#[H_3O^+][HO^-]=K_w=10^-14#</mathjax></p> <p>We take <mathjax>#log_10#</mathjax> OF BOTH SIDES:</p> <p><mathjax>#log_10[H_3O^+] +log_10[HO^-]=log_10(10^-14)#</mathjax></p> <p>But by definition, the logarithmic function is that power to which you raise the base to get the specific answer.........i.e. if <mathjax>#log_aB=c#</mathjax>, then <mathjax>#a^c=B#</mathjax>. </p> <p>And thus <mathjax>#log_10(10^-14)=-14#</mathjax></p> <p>And so <mathjax>#log_10[H_3O^+] +log_10[HO^-]=-14#</mathjax></p> <p>OR <mathjax>#-log_10[H_3O^+] -log_10[HO^-]=14#</mathjax></p> <p>But we define <mathjax>#pH=-log_10[H_3O^+]#</mathjax>, and <mathjax>#pOH=-log_10[HO^-]#</mathjax>, and so...........</p> <p><mathjax>#14=pH+pOH#</mathjax>. </p> <p>And now finally, <mathjax>#pH=14-pOH#</mathjax> </p> <p><mathjax>#14-(-log_10(2.0xx10^-10)=4.30#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the pH of a solution with #[OH^-] = 2.0 times 10^-10# #M#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/the-ph-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">pH</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="408177" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-17T17:30:00" itemprop="dateCreated"> Apr 17, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We find <mathjax>#pH~=4#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We interrogate the equilibrium:</p> <p><mathjax>#2H_2Orightleftharpoons H_3O^+ + HO^-#</mathjax></p> <p>We know that in aqueous solution under standard conditions that:</p> <p><mathjax>#[H_3O^+][HO^-]=K_w=10^-14#</mathjax></p> <p>We take <mathjax>#log_10#</mathjax> OF BOTH SIDES:</p> <p><mathjax>#log_10[H_3O^+] +log_10[HO^-]=log_10(10^-14)#</mathjax></p> <p>But by definition, the logarithmic function is that power to which you raise the base to get the specific answer.........i.e. if <mathjax>#log_aB=c#</mathjax>, then <mathjax>#a^c=B#</mathjax>. </p> <p>And thus <mathjax>#log_10(10^-14)=-14#</mathjax></p> <p>And so <mathjax>#log_10[H_3O^+] +log_10[HO^-]=-14#</mathjax></p> <p>OR <mathjax>#-log_10[H_3O^+] -log_10[HO^-]=14#</mathjax></p> <p>But we define <mathjax>#pH=-log_10[H_3O^+]#</mathjax>, and <mathjax>#pOH=-log_10[HO^-]#</mathjax>, and so...........</p> <p><mathjax>#14=pH+pOH#</mathjax>. </p> <p>And now finally, <mathjax>#pH=14-pOH#</mathjax> </p> <p><mathjax>#14-(-log_10(2.0xx10^-10)=4.30#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/408177" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="408181" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/darshan"><img alt="" class="" src="https://profilepictures.socratic.org/BlZFCtrsS8u8cwQJFgg6_ProfilePic.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/darshan"> Darshan Senthil </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-17T17:33:50" itemprop="dateCreated"> Apr 17, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>4.30</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Right off the bat, if you don't understand the general concepts of <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> and pOH, I suggest you watch this 5-minute <a href="https://www.youtube.com/watch?v=3dFRD_bI3Rg&t=1s" rel="nofollow">video</a> before proceeding to read this answer.</p> <p>Recall that pH is an index for describing the concentration of hydronium ion. Mathematically, pH is described as:</p> <p><mathjax>#pH = -log[H_3O^+]#</mathjax></p> <p>A common mistake to make in this sort of problem is to move too quickly, and take <mathjax>#-log(2.0 * 10^-10)#</mathjax>, and get your pH as 9.70. This is wrong, because you're not given a hydronium ion concentration, but a <em>hydroxide</em> ion concentration. Therefore, what you've calculated is really something called the <strong>pOH</strong>, not the pH. </p> <p>So how do you work this out? Basically, you'll need to know that the product of the concentration of hydroxide and hydronium ions in a solution will always equal <mathjax>#10^-14#</mathjax> at <mathjax>#24^oC#</mathjax> Mathematically speaking:</p> <p><mathjax>#[H_3O^+][OH^-] = 10^-14#</mathjax></p> <p>Taking the negative log of both sides of the equation yields:</p> <p><mathjax>#pH + pOH = 14#</mathjax></p> <p>Given this, there's 2 ways to do this problem. Method one is to use the 1st equation, and solve for <mathjax>#[H_3O^+]#</mathjax>. Then, you just take the negative log of that. </p> <p>Method 2 (easier, in my opinion) is to solve for the pOH, and then subtract it from 14. </p> <p>Either way, you should get an answer of <strong>4.30.</strong></p> <p>Do a reality check: your concentration of hydroxide is very small. Therefore, your pOH value would be fairly large, meaning that your pH would be small. This aligns with what we got. </p> <p>Hope that helps :) </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/408181" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-pka"> How do you determine pH from pKa? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-ph-values-of-acids-and-bases-differ"> How do pH values of acids and bases differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-something-on-a-ph-scale"> How do you calculate something on a pH scale? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-diprotic-acid"> How do you calculate pH diprotic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-from-acid-dissociation-constant"> How do you calculate pH from acid dissociation constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-of-acid-and-base-solution"> How do you calculate pH of acid and base solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ph-scale-0-14"> Why is the pH scale 0-14? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-ph-the-measure-of-the-hydrogen-ion-concentration"> Is pH a measure of the hydrogen ion concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-solubility-affect-ph"> How does solubility affect pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-ph-relate-to-pka-in-a-titration"> How does pH relate to pKa in a titration? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/the-ph-concept"> See all questions in pH </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 25260 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the pH of a solution with #[OH^-] = 2.0 times 10^-10# #M#?	null
977	a98f5eda-6ddd-11ea-8f61-ccda262736ce	https://socratic.org/questions/how-many-millilieters-of-a-12-v-v-propyl-alcohol-solution-would-you-need-to-obta	47.50 millilieters	start physical_unit 7 9 volume ml qc_end physical_unit 7 8 15 16 volume qc_end end	[{"type":"physical unit","value":"Volume [OF] propyl alcohol solution [IN] millilieters"}]	[{"type":"physical unit","value":"47.50 millilieters"}]	[{"type":"physical unit","value":"v/v [OF] propyl alcohol in the solution [=] \\pu{12%}"},{"type":"physical unit","value":"Volume [OF] propyl alcohol [=] \\pu{5.7 mL}"}]	<h1 class="questionTitle" itemprop="name"> How many millilieters of a 12% (v/v) propyl alcohol solution would you need to obtain 5.7 mL of propyl alcohol?</h1>	null	47.50 millilieters	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>A solution's <strong>volume by volume <a href="https://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration</a></strong>, <mathjax>#"% v/v"#</mathjax>, is a measure of how many milliliters of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> it contains in <mathjax>#"100 mL"#</mathjax> of solution. </p> <p>In your case, a <mathjax>#"12% v/v"#</mathjax> solution will contain <mathjax>#"12 mL"#</mathjax> of solute <strong>for every</strong> <mathjax>#"100 mL"#</mathjax> of solution. </p> <p>This means that in order to have <mathjax>#"5.7 mL"#</mathjax> of solute, you need to have</p> <blockquote> <p><mathjax>#5.7 color(red)(cancel(color(black)("mL solute"))) * "100 mL solution"/(12color(red)(cancel(color(black)("mL solute")))) = color(darkgreen)(ul(color(black)("48 mL solution")))#</mathjax></p> </blockquote> <p>The answer is rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"48 mL"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>A solution's <strong>volume by volume <a href="https://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration</a></strong>, <mathjax>#"% v/v"#</mathjax>, is a measure of how many milliliters of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> it contains in <mathjax>#"100 mL"#</mathjax> of solution. </p> <p>In your case, a <mathjax>#"12% v/v"#</mathjax> solution will contain <mathjax>#"12 mL"#</mathjax> of solute <strong>for every</strong> <mathjax>#"100 mL"#</mathjax> of solution. </p> <p>This means that in order to have <mathjax>#"5.7 mL"#</mathjax> of solute, you need to have</p> <blockquote> <p><mathjax>#5.7 color(red)(cancel(color(black)("mL solute"))) * "100 mL solution"/(12color(red)(cancel(color(black)("mL solute")))) = color(darkgreen)(ul(color(black)("48 mL solution")))#</mathjax></p> </blockquote> <p>The answer is rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name"> How many millilieters of a 12% (v/v) propyl alcohol solution would you need to obtain 5.7 mL of propyl alcohol?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/percent-concentration" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Concentration</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="353015" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-12-17T00:12:24" itemprop="dateCreated"> Dec 17, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"48 mL"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>A solution's <strong>volume by volume <a href="https://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration</a></strong>, <mathjax>#"% v/v"#</mathjax>, is a measure of how many milliliters of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> it contains in <mathjax>#"100 mL"#</mathjax> of solution. </p> <p>In your case, a <mathjax>#"12% v/v"#</mathjax> solution will contain <mathjax>#"12 mL"#</mathjax> of solute <strong>for every</strong> <mathjax>#"100 mL"#</mathjax> of solution. </p> <p>This means that in order to have <mathjax>#"5.7 mL"#</mathjax> of solute, you need to have</p> <blockquote> <p><mathjax>#5.7 color(red)(cancel(color(black)("mL solute"))) * "100 mL solution"/(12color(red)(cancel(color(black)("mL solute")))) = color(darkgreen)(ul(color(black)("48 mL solution")))#</mathjax></p> </blockquote> <p>The answer is rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/353015" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" 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alcohol solution would you need to obtain 5.7 mL of propyl alcohol?	null
978	ac274ec8-6ddd-11ea-9866-ccda262736ce	https://socratic.org/questions/roman-mixes-12-litres-of-8-acid-solution-with-a-20-acid-solution-which-results-i	24 litres	start physical_unit 6 7 volume l qc_end physical_unit 6 7 2 3 volume qc_end physical_unit 6 6 5 5 percent qc_end physical_unit 6 6 10 10 percent qc_end physical_unit 6 6 17 17 percent qc_end end	[{"type":"physical unit","value":"Volume2 [OF] acid solution [IN] litres"}]	[{"type":"physical unit","value":"24 litres"}]	[{"type":"physical unit","value":"Volume1 [OF] acid solution [=] \\pu{12 litres}"},{"type":"physical unit","value":"Percent1 [OF] acid in solution [=] \\pu{8%}"},{"type":"physical unit","value":"Percent2 [OF] acid in solution [=] \\pu{20%}"},{"type":"physical unit","value":"Percent3 [OF] acid in solution [=] \\pu{16%}"}]	<h1 class="questionTitle" itemprop="name">Roman mixes 12 litres of 8% acid solution with a 20% acid solution, which results in a 16% acid solution. How do you find the number of litres of 20% acid solution in the new mixture?</h1>	null	24 litres	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>We can use the "volume × concentration" formula to work out the answer.</p> <p><mathjax>#"Volume of 8 % acid + volume of 20 % acid = volume of 16 % acid"#</mathjax></p> <p>Let <mathjax>#x#</mathjax> be the volume of 20 % acid.</p> <p>Then <mathjax>#(12 + x)color(white)(l) "L"#</mathjax> is the new volume of the 16 % acid.</p> <p>We can write</p> <p><mathjax>#V_1c_1 + V_2c_2 = V_3c_3#</mathjax></p> <p><mathjax>#12 color(red)(cancel(color(black)("L"))) × 8 color(red)(cancel(color(black)(%))) + x color(red)(cancel(color(black)("L"))) × 20 color(red)(cancel(color(black)(%))) = (12 +x) color(red)(cancel(color(black)("L"))) × 16 color(red)(cancel(color(black)(%)))#</mathjax></p> <p><mathjax>#96 + 20x = 192 + 16x#</mathjax></p> <p><mathjax>#4x = "192 - 96" = 96#</mathjax></p> <p><mathjax>#x = 96/4 = 24#</mathjax></p> <p>∴ The volume of 20 % acid is 24 L. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The volume of 20 % acid is 24 L.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>We can use the "volume × concentration" formula to work out the answer.</p> <p><mathjax>#"Volume of 8 % acid + volume of 20 % acid = volume of 16 % acid"#</mathjax></p> <p>Let <mathjax>#x#</mathjax> be the volume of 20 % acid.</p> <p>Then <mathjax>#(12 + x)color(white)(l) "L"#</mathjax> is the new volume of the 16 % acid.</p> <p>We can write</p> <p><mathjax>#V_1c_1 + V_2c_2 = V_3c_3#</mathjax></p> <p><mathjax>#12 color(red)(cancel(color(black)("L"))) × 8 color(red)(cancel(color(black)(%))) + x color(red)(cancel(color(black)("L"))) × 20 color(red)(cancel(color(black)(%))) = (12 +x) color(red)(cancel(color(black)("L"))) × 16 color(red)(cancel(color(black)(%)))#</mathjax></p> <p><mathjax>#96 + 20x = 192 + 16x#</mathjax></p> <p><mathjax>#4x = "192 - 96" = 96#</mathjax></p> <p><mathjax>#x = 96/4 = 24#</mathjax></p> <p>∴ The volume of 20 % acid is 24 L. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Roman mixes 12 litres of 8% acid solution with a 20% acid solution, which results in a 16% acid solution. How do you find the number of litres of 20% acid solution in the new mixture?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/dilution-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">Dilution Calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="358716" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-12-31T15:15:02" itemprop="dateCreated"> Dec 31, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The volume of 20 % acid is 24 L.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>We can use the "volume × concentration" formula to work out the answer.</p> <p><mathjax>#"Volume of 8 % acid + volume of 20 % acid = volume of 16 % acid"#</mathjax></p> <p>Let <mathjax>#x#</mathjax> be the volume of 20 % acid.</p> <p>Then <mathjax>#(12 + x)color(white)(l) "L"#</mathjax> is the new volume of the 16 % acid.</p> <p>We can write</p> <p><mathjax>#V_1c_1 + V_2c_2 = V_3c_3#</mathjax></p> <p><mathjax>#12 color(red)(cancel(color(black)("L"))) × 8 color(red)(cancel(color(black)(%))) + x color(red)(cancel(color(black)("L"))) × 20 color(red)(cancel(color(black)(%))) = (12 +x) color(red)(cancel(color(black)("L"))) × 16 color(red)(cancel(color(black)(%)))#</mathjax></p> <p><mathjax>#96 + 20x = 192 + 16x#</mathjax></p> <p><mathjax>#4x = "192 - 96" = 96#</mathjax></p> <p><mathjax>#x = 96/4 = 24#</mathjax></p> <p>∴ The volume of 20 % acid is 24 L. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/358716" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-concentration-from-absorbance"> How do you calculate concentration from absorbance? 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</a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-would-be-the-concentration-of-a-solution-made-by-adding-250-ml-of-water-to-"> What would be the concentration of a solution made by adding 250 mL of water to 45.0 mL of 4.2 M KOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-would-be-the-concentration-of-a-solution-made-by-diluting-45-0-ml-of-4-2-m-"> What would be the concentration of a solution made by diluting 45.0 mL of 4.2 M KOH to 250 mL? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-a-solution-that-is-made-by-diluting-50-00-ml-of-a-4-74-m"> What is the molarity of a solution that is made by diluting 50.00 mL of a 4.74 M solution of HCl... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-volume-of-water-would-you-add-to-15-00-ml-of-a-6-77-m-solution-of-nitric-ac"> What volume of water would you add to 15.00 mL of a 6.77 M solution of nitric acid in order to... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/dilution-calculations"> See all questions in Dilution Calculations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1556 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Roman mixes 12 litres of 8% acid solution with a 20% acid solution, which results in a 16% acid solution. How do you find the number of litres of 20% acid solution in the new mixture?	null
979	ab728846-6ddd-11ea-8d1f-ccda262736ce	https://socratic.org/questions/what-volume-of-hydrogen-at-stp-is-produced-when-2-5-g-of-zinc-react-with-an-exce	0.86 L	start physical_unit 3 3 volume l qc_end c_other STP qc_end physical_unit 12 12 9 10 mass qc_end c_other OTHER qc_end chemical_equation 23 30 qc_end end	[{"type":"physical unit","value":"Volume [OF] hydrogen [IN] L"}]	[{"type":"physical unit","value":"0.86 L"}]	[{"type":"other","value":"STP"},{"type":"physical unit","value":"Mass [OF] zinc [=] \\pu{2.5 g}"},{"type":"other","value":"Excess hydrochloric acid."},{"type":"chemical equation","value":"Zn + 2 HCl -> ZnCl2 + H2"}]	<h1 class="questionTitle" itemprop="name">What volume of hydrogen at STP is produced when 2.5 g of zinc react with an excess of hydrochloric acid in the reaction #Zn + 2HCl -> ZnCl_2 + H_2#?</h1>	null	0.86 L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#1 "mol"#</mathjax> of <mathjax>#"Zn"#</mathjax> has mass of <mathjax>#65.39 "g"#</mathjax>.</p> <p>The amount of <mathjax>#"Zn"#</mathjax> is <mathjax>#frac{2.5 "g"}{65.39 "g/mol"} = 0.038 "mol"#</mathjax>.</p> <p>The amount of <mathjax>#"H"_2#</mathjax> produced is the same as the amount of <mathjax>#"Zn"#</mathjax> consumed <mathjax>#(0.038 "mol")#</mathjax>.</p> <p><mathjax>#1 "mol"#</mathjax> of <a href="http://hyperphysics.phy-astr.gsu.edu/hbase/kinetic/idegas.html" rel="nofollow">ideal gas</a> will occupy <mathjax>#22.4 "L"#</mathjax> at STP.</p> <p>The <mathjax>#"H"_2#</mathjax> will occupy <mathjax>#0.038 "mol" xx 22.4 "L/mol" = 0.86 "L"#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#0.86 "L"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#1 "mol"#</mathjax> of <mathjax>#"Zn"#</mathjax> has mass of <mathjax>#65.39 "g"#</mathjax>.</p> <p>The amount of <mathjax>#"Zn"#</mathjax> is <mathjax>#frac{2.5 "g"}{65.39 "g/mol"} = 0.038 "mol"#</mathjax>.</p> <p>The amount of <mathjax>#"H"_2#</mathjax> produced is the same as the amount of <mathjax>#"Zn"#</mathjax> consumed <mathjax>#(0.038 "mol")#</mathjax>.</p> <p><mathjax>#1 "mol"#</mathjax> of <a href="http://hyperphysics.phy-astr.gsu.edu/hbase/kinetic/idegas.html" rel="nofollow">ideal gas</a> will occupy <mathjax>#22.4 "L"#</mathjax> at STP.</p> <p>The <mathjax>#"H"_2#</mathjax> will occupy <mathjax>#0.038 "mol" xx 22.4 "L/mol" = 0.86 "L"#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What volume of hydrogen at STP is produced when 2.5 g of zinc react with an excess of hydrochloric acid in the reaction #Zn + 2HCl -> ZnCl_2 + H_2#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp" itemprop="url"> <span class="breadcrumb" itemprop="title">Molar Volume of a Gas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="232397" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/bio"><img alt="" class="" src="https://profilepictures.socratic.org/Qm2uaSgSTeLzBx8JHnK7_bq.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/bio"> Bio </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-02-28T09:59:34" itemprop="dateCreated"> Feb 28, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#0.86 "L"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#1 "mol"#</mathjax> of <mathjax>#"Zn"#</mathjax> has mass of <mathjax>#65.39 "g"#</mathjax>.</p> <p>The amount of <mathjax>#"Zn"#</mathjax> is <mathjax>#frac{2.5 "g"}{65.39 "g/mol"} = 0.038 "mol"#</mathjax>.</p> <p>The amount of <mathjax>#"H"_2#</mathjax> produced is the same as the amount of <mathjax>#"Zn"#</mathjax> consumed <mathjax>#(0.038 "mol")#</mathjax>.</p> <p><mathjax>#1 "mol"#</mathjax> of <a href="http://hyperphysics.phy-astr.gsu.edu/hbase/kinetic/idegas.html" rel="nofollow">ideal gas</a> will occupy <mathjax>#22.4 "L"#</mathjax> at STP.</p> <p>The <mathjax>#"H"_2#</mathjax> will occupy <mathjax>#0.038 "mol" xx 22.4 "L/mol" = 0.86 "L"#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/232397" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-stoichiometric-ratios-relate-to-molar-volume-of-a-gas"> 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href="/questions/why-is-22-4-liters-called-the-molar-volume-of-a-gas"> Why is 22.4 liters called the molar volume of a gas? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp"> See all questions in Molar Volume of a Gas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 103354 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What volume of hydrogen at STP is produced when 2.5 g of zinc react with an excess of hydrochloric acid in the reaction #Zn + 2HCl -> ZnCl_2 + H_2#?	null
980	a9db59a7-6ddd-11ea-9a1a-ccda262736ce	https://socratic.org/questions/what-is-the-specific-heat-of-copper-metal	0.39 kJ/(kg * ℃)	start physical_unit 6 7 specific_heat kj/(kg_·_°c) qc_end substance 6 7 qc_end end	[{"type":"physical unit","value":"Specific heat [OF] copper metal [IN] kJ/(kg * ℃)"}]	[{"type":"physical unit","value":"0.39 kJ/(kg * ℃)"}]	[{"type":"substance name","value":"Copper metal"}]	<h1 class="questionTitle" itemprop="name">What is the specific heat of copper metal? </h1>	null	0.39 kJ/(kg * ℃)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You can find the value in the public domain at a number of locations.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.39 kJ/kg.K</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You can find the value in the public domain at a number of locations.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the specific heat of copper metal? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/specific-heat" itemprop="url"> <span class="breadcrumb" itemprop="title">Specific Heat</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="282262" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/simon-moore"><img alt="" class="" src="https://profilepictures.socratic.org/0ztdJJ7RCWUlBSPeGa9N_6EB6CADA-35F5-4BAA-9B66-9D6F64A622BA.jpeg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/simon-moore"> Simon Moore </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-28T15:52:50" itemprop="dateCreated"> Jun 28, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.39 kJ/kg.K</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You can find the value in the public domain at a number of locations.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/282262" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-specific-heat-be-used-to-identify-substances"> How can specific heat be used to identify substances? 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981	a87da1f6-6ddd-11ea-8aa3-ccda262736ce	https://socratic.org/questions/what-is-the-empirical-formula-of-a-substance-with-74-0-c-8-65-h-and-17-4-n	C5H7N	start chemical_formula qc_end end	[{"type":"other","value":"Chemical Formula [OF] a substance [IN] empirical"}]	[{"type":"chemical equation","value":"C5H7N"}]	[{"type":"physical unit","value":"percent [OF] C in a substance [=] \\pu{74.0%}"},{"type":"physical unit","value":"percent [OF] H in a substance [=] \\pu{8.65%}"},{"type":"physical unit","value":"percent [OF] N in a substance [=] \\pu{17.4%}"}]	<h1 class="questionTitle" itemprop="name">What is the empirical formula of a substance with 74.0% C , 8.65% H, and 17.4% N? </h1>	null	C5H7N	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First, assume that there is 100 g of substance.</p> <p>Next is to calculate the number of moles or each element:</p> <p><mathjax>#74.0 g C * (1mol C )/ (12.01 g) ~~ 6.16 mol C#</mathjax><br/> <mathjax>#8.65 g H * (1mol H )/ (1.008 g) ~~ 8.58 mol H#</mathjax><br/> <mathjax>#17.4 g N * (1mol N )/ (14.01 g) ~~ 1.24 mol N#</mathjax></p> <p>After getting the mol of each element, you can calculate now <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio. Do this by dividing each number of moles by the lowest number of moles obtained.</p> <p><mathjax># C= (6.16/1.24)~~ 5#</mathjax><br/> <mathjax># H= (8.58/1.24)~~ 7#</mathjax><br/> <mathjax># N= (1.24/1.24)~~ 1#</mathjax></p> <p>Therefore, the empirical formula of a substance with 74.0% C , 8.65% H, and 17.4% N is <strong><mathjax>#C_5H_7N#</mathjax></strong></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_5H_7N#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First, assume that there is 100 g of substance.</p> <p>Next is to calculate the number of moles or each element:</p> <p><mathjax>#74.0 g C * (1mol C )/ (12.01 g) ~~ 6.16 mol C#</mathjax><br/> <mathjax>#8.65 g H * (1mol H )/ (1.008 g) ~~ 8.58 mol H#</mathjax><br/> <mathjax>#17.4 g N * (1mol N )/ (14.01 g) ~~ 1.24 mol N#</mathjax></p> <p>After getting the mol of each element, you can calculate now <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio. Do this by dividing each number of moles by the lowest number of moles obtained.</p> <p><mathjax># C= (6.16/1.24)~~ 5#</mathjax><br/> <mathjax># H= (8.58/1.24)~~ 7#</mathjax><br/> <mathjax># N= (1.24/1.24)~~ 1#</mathjax></p> <p>Therefore, the empirical formula of a substance with 74.0% C , 8.65% H, and 17.4% N is <strong><mathjax>#C_5H_7N#</mathjax></strong></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the empirical formula of a substance with 74.0% C , 8.65% H, and 17.4% N? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="281275" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/kristhia-loren-maree-rafols-c"><img alt="" class="" src="https://profilepictures.socratic.org/LCQvyymMQmyD0Ro56Sh6_IMG_20161030_204540.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/kristhia-loren-maree-rafols-c"> Kris Caceres </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-25T17:17:52" itemprop="dateCreated"> Jun 25, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_5H_7N#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First, assume that there is 100 g of substance.</p> <p>Next is to calculate the number of moles or each element:</p> <p><mathjax>#74.0 g C * (1mol C )/ (12.01 g) ~~ 6.16 mol C#</mathjax><br/> <mathjax>#8.65 g H * (1mol H )/ (1.008 g) ~~ 8.58 mol H#</mathjax><br/> <mathjax>#17.4 g N * (1mol N )/ (14.01 g) ~~ 1.24 mol N#</mathjax></p> <p>After getting the mol of each element, you can calculate now <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio. Do this by dividing each number of moles by the lowest number of moles obtained.</p> <p><mathjax># C= (6.16/1.24)~~ 5#</mathjax><br/> <mathjax># H= (8.58/1.24)~~ 7#</mathjax><br/> <mathjax># N= (1.24/1.24)~~ 1#</mathjax></p> <p>Therefore, the empirical formula of a substance with 74.0% C , 8.65% H, and 17.4% N is <strong><mathjax>#C_5H_7N#</mathjax></strong></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/281275" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molecular-formula-of-a-compound"> How do you find molecular formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-diamond"> What is the chemical formula of a diamond? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-carbohydrate"> What is the chemical formula of a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-valproic-acid"> What is the empirical formula for valproic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-of-magnesium-oxide"> What is the empirical formula of magnesium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-empirical-formula-not-double-that-of-the-monosaccharides"> Why is the empirical formula not double that of the monosaccharides? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5331180502bf342f40b5c3b5"> Question #5c3b5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-molecular-formula-represents-a-carbohydrate"> What molecular formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-of-vinegar"> What is the molecular formula of vinegar? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/empirical-and-molecular-formulas"> See all questions in Empirical and Molecular Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 4023 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the empirical formula of a substance with 74.0% C , 8.65% H, and 17.4% N?	null
982	a9a18acc-6ddd-11ea-80f7-ccda262736ce	https://socratic.org/questions/how-many-grams-of-naoh-are-needed-to-prepare-250-ml-of-0-205-m-naoh	2.05 grams	start physical_unit 4 4 mass g qc_end physical_unit 4 4 12 13 molarity qc_end end	[{"type":"physical unit","value":"Mass [OF] NaOH [IN] grams"}]	[{"type":"physical unit","value":"2.05 grams"}]	[{"type":"physical unit","value":"Volume [OF] NaOH solution [=] \\pu{250 mL}"},{"type":"physical unit","value":"Molarity [OF] NaOH solution [=] \\pu{0.205 M}"}]	<h1 class="questionTitle" itemprop="name">How many grams of NaOH are needed to prepare 250 mL of 0.205 M NaOH?</h1>	null	2.05 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Concentration"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Moles of solute (moles)"/"Volume of solution (L)"#</mathjax></p> <p>Thus <mathjax>#"Concentration"xx"volume"="moles of solute"#</mathjax></p> <p><mathjax>#0.205molcancel(L^-1)xx0.250cancelL="Moles of solute"#</mathjax></p> <p><mathjax>#=0.0513mol#</mathjax>, an answer in moles as required. </p> <p>And thus <mathjax>#"mass of NaOH"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"moles "xx" molar mass"#</mathjax></p> <p><mathjax>#=0.0513cancel(mol)xx40.0gcancel(mol^-1)#</mathjax></p> <p><mathjax>#=2.05g#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>A bit over <mathjax>#2g#</mathjax>...............</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Concentration"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Moles of solute (moles)"/"Volume of solution (L)"#</mathjax></p> <p>Thus <mathjax>#"Concentration"xx"volume"="moles of solute"#</mathjax></p> <p><mathjax>#0.205molcancel(L^-1)xx0.250cancelL="Moles of solute"#</mathjax></p> <p><mathjax>#=0.0513mol#</mathjax>, an answer in moles as required. </p> <p>And thus <mathjax>#"mass of NaOH"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"moles "xx" molar mass"#</mathjax></p> <p><mathjax>#=0.0513cancel(mol)xx40.0gcancel(mol^-1)#</mathjax></p> <p><mathjax>#=2.05*g#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many grams of NaOH are needed to prepare 250 mL of 0.205 M NaOH?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/solutions" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="384211" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-02-28T07:44:06" itemprop="dateCreated"> Feb 28, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>A bit over <mathjax>#2g#</mathjax>...............</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Concentration"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Moles of solute (moles)"/"Volume of solution (L)"#</mathjax></p> <p>Thus <mathjax>#"Concentration"xx"volume"="moles of solute"#</mathjax></p> <p><mathjax>#0.205molcancel(L^-1)xx0.250cancelL="Moles of solute"#</mathjax></p> <p><mathjax>#=0.0513mol#</mathjax>, an answer in moles as required. </p> <p>And thus <mathjax>#"mass of NaOH"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"moles "xx" molar mass"#</mathjax></p> <p><mathjax>#=0.0513cancel(mol)xx40.0gcancel(mol^-1)#</mathjax></p> <p><mathjax>#=2.05*g#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/384211" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-solution-solute-and-solvent-related"> How are solution, solute, and solvent related? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-solutions-become-saturated"> Why do solutions become saturated? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-temperature-affect-solutions"> How does temperature affect solutions? </a> </div> 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The gram formula weight... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-solutions-differ-from-suspensions"> How do solutions differ from suspensions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-a-solution-differ-from-a-compound"> How does a solution differ from a compound? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/solutions"> See all questions in Solutions </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 91415 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many grams of NaOH are needed to prepare 250 mL of 0.205 M NaOH?	null
983	a94b8724-6ddd-11ea-b9d2-ccda262736ce	https://socratic.org/questions/if-chlorine-gas-has-a-volume-of-465ml-at-50-c-what-is-the-volume-if-the-temperat	436 mL	start physical_unit 1 2 volume ml qc_end physical_unit 1 2 7 8 volume qc_end physical_unit 1 2 10 11 temperature qc_end physical_unit 1 2 21 22 temperature qc_end end	[{"type":"physical unit","value":"Volume2 [OF] chlorine gas [IN] mL"}]	[{"type":"physical unit","value":"436 mL"}]	[{"type":"physical unit","value":"Volume1 [OF] chlorine gas [=] \\pu{465 mL}"},{"type":"physical unit","value":"Temperature1 [OF] chlorine gas [=] \\pu{50 ℃}"},{"type":"physical unit","value":"Temperature2 [OF] chlorine gas [=] \\pu{30 ℃}"}]	<h1 class="questionTitle" itemprop="name">If chlorine gas has a volume of 465mL at 50°C ,what is the volume if the temperature decreases to 30°C?</h1>	null	436 mL	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To answer this question, we will need to assume the following:</p> <ol> <li>Chlorine gas is behaving ideally, so we can use the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a>: <mathjax>#PV=nRT#</mathjax></li> <li>During the process, the pressure is remaining constant.</li> </ol> <p>Since we are heating the ballon, the number of mole is not changing and therefore, <mathjax>#n#</mathjax> is constant too.</p> <p>Thus <mathjax>#V=underbrace((nR)/P)_(color(blue)("constant k"))T=>V/T=k=>(V_1)/(T_1)=(V_2)/(T_2)#</mathjax></p> <p><mathjax>#=>V_2=(V_1)/(T_1)xxT_2=(465mL)/(323cancel(K))xx303cancel(K)=436mL#</mathjax></p> <p>Therefore, chlorine will occupy a volume of <mathjax>#436mL#</mathjax> at <mathjax>#30^@C#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#V_2=436mL#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To answer this question, we will need to assume the following:</p> <ol> <li>Chlorine gas is behaving ideally, so we can use the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a>: <mathjax>#PV=nRT#</mathjax></li> <li>During the process, the pressure is remaining constant.</li> </ol> <p>Since we are heating the ballon, the number of mole is not changing and therefore, <mathjax>#n#</mathjax> is constant too.</p> <p>Thus <mathjax>#V=underbrace((nR)/P)_(color(blue)("constant k"))T=>V/T=k=>(V_1)/(T_1)=(V_2)/(T_2)#</mathjax></p> <p><mathjax>#=>V_2=(V_1)/(T_1)xxT_2=(465mL)/(323cancel(K))xx303cancel(K)=436mL#</mathjax></p> <p>Therefore, chlorine will occupy a volume of <mathjax>#436mL#</mathjax> at <mathjax>#30^@C#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">If chlorine gas has a volume of 465mL at 50°C ,what is the volume if the temperature decreases to 30°C?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/charles-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Charles' Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="196882" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ali-h-1"><img alt="" class="" src="https://profilepictures.socratic.org/IITeL1YTQdODdLp0aJTL_StereoPicture%20copy.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ali-h-1"> Dr. Hayek </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-06T08:18:02" itemprop="dateCreated"> Dec 6, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#V_2=436mL#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To answer this question, we will need to assume the following:</p> <ol> <li>Chlorine gas is behaving ideally, so we can use the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a>: <mathjax>#PV=nRT#</mathjax></li> <li>During the process, the pressure is remaining constant.</li> </ol> <p>Since we are heating the ballon, the number of mole is not changing and therefore, <mathjax>#n#</mathjax> is constant too.</p> <p>Thus <mathjax>#V=underbrace((nR)/P)_(color(blue)("constant k"))T=>V/T=k=>(V_1)/(T_1)=(V_2)/(T_2)#</mathjax></p> <p><mathjax>#=>V_2=(V_1)/(T_1)xxT_2=(465mL)/(323cancel(K))xx303cancel(K)=436mL#</mathjax></p> <p>Therefore, chlorine will occupy a volume of <mathjax>#436mL#</mathjax> at <mathjax>#30^@C#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/196882" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div 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984	a914e11c-6ddd-11ea-864c-ccda262736ce	https://socratic.org/questions/what-is-the-balanced-equation-for-the-complete-combustion-of-c-3h-7coc-2h-5	2 C3H7COC2H5 + 17 O2 -> 12 CO2 + 12 H2O	start chemical_equation qc_end chemical_equation 10 10 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the complete combustion"}]	[{"type":"chemical equation","value":"2 C3H7COC2H5 + 17 O2 -> 12 CO2 + 12 H2O"}]	[{"type":"chemical equation","value":"C3H7COC2H5"}]	<h1 class="questionTitle" itemprop="name">What is the balanced equation for the complete combustion of #C_3H_7COC_2H_5#?</h1>	null	2 C3H7COC2H5 + 17 O2 -> 12 CO2 + 12 H2O	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Complete combustion of <mathjax>#C_3H_7COC_2H_5#</mathjax> in oxygen will produce Carbon dioxide and water. If <mathjax>#a,b,c,d#</mathjax> are the respective molecules in the balanced equation, we have </p> <p><mathjax>#aC_3H_7COC_2H_5+bO_2->cCO_2+dH_2O#</mathjax></p> <p>Lets start with <mathjax>#a=1#</mathjax>. Balancing the number of carbon on both sides we obtain <mathjax>#c=6#</mathjax>. And the equation becomes<br/> <mathjax>#aC_3H_7COC_2H_5+bO_2->6CO_2+6H_2O#</mathjax></p> <p><mathjax>#C_3H_7COC_2H_5+bO_2->6CO_2+dH_2O#</mathjax><br/> Now balancing hydrogen atoms we obtain <mathjax>#d=6#</mathjax>. And the equation becomes</p> <p><mathjax>#C_3H_7COC_2H_5+bO_2->6CO_2+6H_2O#</mathjax><br/> Now balancing <mathjax>#O#</mathjax> atoms we see that it <mathjax>#b=17/2#</mathjax><br/> Multiplying all with 2 we obtain balanced equation as</p> <p><mathjax>#2C_3H_7COC_2H_5+17O_2->12CO_2+12H_2O#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2C_3H_7COC_2H_5+17O_2->12CO_2+12H_2O#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Complete combustion of <mathjax>#C_3H_7COC_2H_5#</mathjax> in oxygen will produce Carbon dioxide and water. If <mathjax>#a,b,c,d#</mathjax> are the respective molecules in the balanced equation, we have </p> <p><mathjax>#aC_3H_7COC_2H_5+bO_2->cCO_2+dH_2O#</mathjax></p> <p>Lets start with <mathjax>#a=1#</mathjax>. Balancing the number of carbon on both sides we obtain <mathjax>#c=6#</mathjax>. And the equation becomes<br/> <mathjax>#aC_3H_7COC_2H_5+bO_2->6CO_2+6H_2O#</mathjax></p> <p><mathjax>#C_3H_7COC_2H_5+bO_2->6CO_2+dH_2O#</mathjax><br/> Now balancing hydrogen atoms we obtain <mathjax>#d=6#</mathjax>. And the equation becomes</p> <p><mathjax>#C_3H_7COC_2H_5+bO_2->6CO_2+6H_2O#</mathjax><br/> Now balancing <mathjax>#O#</mathjax> atoms we see that it <mathjax>#b=17/2#</mathjax><br/> Multiplying all with 2 we obtain balanced equation as</p> <p><mathjax>#2C_3H_7COC_2H_5+17O_2->12CO_2+12H_2O#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the balanced equation for the complete combustion of #C_3H_7COC_2H_5#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="215151" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/a08"><img alt="" class="" src="https://profilepictures.socratic.org/fZvgXOhDR1W7ogoxiea9_Ridge%2C_Shimla.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/a08"> A08 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-21T17:24:20" itemprop="dateCreated"> Jan 21, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2C_3H_7COC_2H_5+17O_2->12CO_2+12H_2O#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Complete combustion of <mathjax>#C_3H_7COC_2H_5#</mathjax> in oxygen will produce Carbon dioxide and water. If <mathjax>#a,b,c,d#</mathjax> are the respective molecules in the balanced equation, we have </p> <p><mathjax>#aC_3H_7COC_2H_5+bO_2->cCO_2+dH_2O#</mathjax></p> <p>Lets start with <mathjax>#a=1#</mathjax>. Balancing the number of carbon on both sides we obtain <mathjax>#c=6#</mathjax>. And the equation becomes<br/> <mathjax>#aC_3H_7COC_2H_5+bO_2->6CO_2+6H_2O#</mathjax></p> <p><mathjax>#C_3H_7COC_2H_5+bO_2->6CO_2+dH_2O#</mathjax><br/> Now balancing hydrogen atoms we obtain <mathjax>#d=6#</mathjax>. And the equation becomes</p> <p><mathjax>#C_3H_7COC_2H_5+bO_2->6CO_2+6H_2O#</mathjax><br/> Now balancing <mathjax>#O#</mathjax> atoms we see that it <mathjax>#b=17/2#</mathjax><br/> Multiplying all with 2 we obtain balanced equation as</p> <p><mathjax>#2C_3H_7COC_2H_5+17O_2->12CO_2+12H_2O#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/215151" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------> H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -> Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? 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985	aa5d64dc-6ddd-11ea-881a-ccda262736ce	https://socratic.org/questions/a-sample-of-25-l-of-nh-3-gas-at-10-c-is-heated-at-constant-pressure-until-it-fil	293.00 ℃	start physical_unit 6 7 temperature °c qc_end physical_unit 6 7 9 10 temperature qc_end physical_unit 6 7 3 4 volume qc_end physical_unit 6 7 22 23 volume qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Temperature2 [OF] NH3 gas sample [IN] ℃"}]	[{"type":"physical unit","value":"293.00 ℃"}]	[{"type":"physical unit","value":"Temperature1 [OF] NH3 gas sample [=] \\pu{10 ℃}"},{"type":"physical unit","value":"Volume1 [OF] NH3 gas sample [=] \\pu{25 L}"},{"type":"physical unit","value":"Volume2 [OF] NH3 gas sample [=] \\pu{50 L}"},{"type":"other","value":"Constant pressure."}]	<h1 class="questionTitle" itemprop="name">A sample of 25 L of #NH_3# gas at 10°C is heated at constant pressure until it fills a volume of 50 L. What is the new temperature in °C?</h1>	null	293.00 ℃	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We're asked to find the <strong>new temperature</strong> of the <mathjax>#"NH"_3#</mathjax> after it is subdued to a change in volume (with constant pressure).</p> <blockquote></blockquote> <p>To do this, we can use the temperature-volume relationship of gases, illustrated by <strong>Charles's law</strong>:</p> <blockquote> <p><mathjax>#ulbar(\|stackrel(" ")(" "(V_1)/(T_1) = (V_2)/(T_2)" ")\|)#</mathjax> <mathjax>#" "#</mathjax>(constant pressure and quantity of gas)</p> </blockquote> <p>where</p> <ul> <li> <p><mathjax>#V_1#</mathjax> and <mathjax>#V_2#</mathjax> are the <strong>initial</strong> and <strong>final volumes</strong> of the gas</p> </li> <li> <p><mathjax>#T_1#</mathjax> and <mathjax>#T_2#</mathjax> are the <strong>initial</strong> and <strong>final <em>absolute</em> temperatures</strong> of the gas (which <strong>must be in Kelvin</strong>)</p> <blockquote></blockquote> </li> </ul> <p>We have:</p> <ul> <li> <p><mathjax>#V_1 = 25#</mathjax> <mathjax>#"L"#</mathjax></p> </li> <li> <p><mathjax>#V_2 = 50#</mathjax> <mathjax>#"L"#</mathjax></p> </li> <li> <p><mathjax>#T_1 = 10#</mathjax> <mathjax>#""^"o""C" +273 = ul(283color(white)(l)"K"#</mathjax></p> </li> <li> <p><mathjax>#T_2 = ?#</mathjax></p> <blockquote> <blockquote></blockquote> </blockquote> </li> </ul> <p>Let's rearrange the above equation to solve for the <strong>final temperature</strong>, <mathjax>#T_2#</mathjax>:</p> <blockquote> <p><mathjax>#T_2 = (V_2T_1)/(V_1)#</mathjax></p> </blockquote> <p>Plugging in known values:</p> <blockquote> <p><mathjax>#T_2 = ((50cancel("L"))(283color(white)(l)"K"))/(25cancel("L")) = color(red)(ul(566color(white)(l)"K"#</mathjax></p> <blockquote></blockquote> </blockquote> <p>You asked for the temperature in <strong>degrees Celsius</strong>, so we convert back:</p> <blockquote> <p><mathjax>#color(red)(566color(white)(l)"K") - 273 = color(blue)(ulbar(\|stackrel(" ")(" "293color(white)(l)""^"o""C"" ")\|)#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#293#</mathjax> <mathjax>#""^"o""C"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We're asked to find the <strong>new temperature</strong> of the <mathjax>#"NH"_3#</mathjax> after it is subdued to a change in volume (with constant pressure).</p> <blockquote></blockquote> <p>To do this, we can use the temperature-volume relationship of gases, illustrated by <strong>Charles's law</strong>:</p> <blockquote> <p><mathjax>#ulbar(\|stackrel(" ")(" "(V_1)/(T_1) = (V_2)/(T_2)" ")\|)#</mathjax> <mathjax>#" "#</mathjax>(constant pressure and quantity of gas)</p> </blockquote> <p>where</p> <ul> <li> <p><mathjax>#V_1#</mathjax> and <mathjax>#V_2#</mathjax> are the <strong>initial</strong> and <strong>final volumes</strong> of the gas</p> </li> <li> <p><mathjax>#T_1#</mathjax> and <mathjax>#T_2#</mathjax> are the <strong>initial</strong> and <strong>final <em>absolute</em> temperatures</strong> of the gas (which <strong>must be in Kelvin</strong>)</p> <blockquote></blockquote> </li> </ul> <p>We have:</p> <ul> <li> <p><mathjax>#V_1 = 25#</mathjax> <mathjax>#"L"#</mathjax></p> </li> <li> <p><mathjax>#V_2 = 50#</mathjax> <mathjax>#"L"#</mathjax></p> </li> <li> <p><mathjax>#T_1 = 10#</mathjax> <mathjax>#""^"o""C" +273 = ul(283color(white)(l)"K"#</mathjax></p> </li> <li> <p><mathjax>#T_2 = ?#</mathjax></p> <blockquote> <blockquote></blockquote> </blockquote> </li> </ul> <p>Let's rearrange the above equation to solve for the <strong>final temperature</strong>, <mathjax>#T_2#</mathjax>:</p> <blockquote> <p><mathjax>#T_2 = (V_2T_1)/(V_1)#</mathjax></p> </blockquote> <p>Plugging in known values:</p> <blockquote> <p><mathjax>#T_2 = ((50cancel("L"))(283color(white)(l)"K"))/(25cancel("L")) = color(red)(ul(566color(white)(l)"K"#</mathjax></p> <blockquote></blockquote> </blockquote> <p>You asked for the temperature in <strong>degrees Celsius</strong>, so we convert back:</p> <blockquote> <p><mathjax>#color(red)(566color(white)(l)"K") - 273 = color(blue)(ulbar(\|stackrel(" ")(" "293color(white)(l)""^"o""C"" ")\|)#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A sample of 25 L of #NH_3# gas at 10°C is heated at constant pressure until it fills a volume of 50 L. What is the new temperature in °C?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/charles-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Charles' Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="461899" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/mrtas"><img alt="" class="" src="https://profilepictures.socratic.org/HY14X7r4S6AyDQgK2gwQ_IMG_0062.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/mrtas"> Nathan L. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-09T03:11:16" itemprop="dateCreated"> Aug 9, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#293#</mathjax> <mathjax>#""^"o""C"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We're asked to find the <strong>new temperature</strong> of the <mathjax>#"NH"_3#</mathjax> after it is subdued to a change in volume (with constant pressure).</p> <blockquote></blockquote> <p>To do this, we can use the temperature-volume relationship of gases, illustrated by <strong>Charles's law</strong>:</p> <blockquote> <p><mathjax>#ulbar(\|stackrel(" ")(" "(V_1)/(T_1) = (V_2)/(T_2)" ")\|)#</mathjax> <mathjax>#" "#</mathjax>(constant pressure and quantity of gas)</p> </blockquote> <p>where</p> <ul> <li> <p><mathjax>#V_1#</mathjax> and <mathjax>#V_2#</mathjax> are the <strong>initial</strong> and <strong>final volumes</strong> of the gas</p> </li> <li> <p><mathjax>#T_1#</mathjax> and <mathjax>#T_2#</mathjax> are the <strong>initial</strong> and <strong>final <em>absolute</em> temperatures</strong> of the gas (which <strong>must be in Kelvin</strong>)</p> <blockquote></blockquote> </li> </ul> <p>We have:</p> <ul> <li> <p><mathjax>#V_1 = 25#</mathjax> <mathjax>#"L"#</mathjax></p> </li> <li> <p><mathjax>#V_2 = 50#</mathjax> <mathjax>#"L"#</mathjax></p> </li> <li> <p><mathjax>#T_1 = 10#</mathjax> <mathjax>#""^"o""C" +273 = ul(283color(white)(l)"K"#</mathjax></p> </li> <li> <p><mathjax>#T_2 = ?#</mathjax></p> <blockquote> <blockquote></blockquote> </blockquote> </li> </ul> <p>Let's rearrange the above equation to solve for the <strong>final temperature</strong>, <mathjax>#T_2#</mathjax>:</p> <blockquote> <p><mathjax>#T_2 = (V_2T_1)/(V_1)#</mathjax></p> </blockquote> <p>Plugging in known values:</p> <blockquote> <p><mathjax>#T_2 = ((50cancel("L"))(283color(white)(l)"K"))/(25cancel("L")) = color(red)(ul(566color(white)(l)"K"#</mathjax></p> <blockquote></blockquote> </blockquote> <p>You asked for the temperature in <strong>degrees Celsius</strong>, so we convert back:</p> <blockquote> <p><mathjax>#color(red)(566color(white)(l)"K") - 273 = color(blue)(ulbar(\|stackrel(" ")(" "293color(white)(l)""^"o""C"" ")\|)#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/461899" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-must-charles-law-be-in-kelvins"> Why must Charles' law be in kelvin? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-charles-law-formula"> What is Charles' law formula? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/oxygen-gas-is-at-a-temperature-of-40-c-when-it-occupies-a-volume-of-2-3-liters-t"> Oxygen gas is at a temperature of 40°C when it occupies a volume of 2.3 liters. 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986	acad191e-6ddd-11ea-9b8a-ccda262736ce	https://socratic.org/questions/a-sample-of-c25h52-weighs-29-29-g-its-molar-mass-is-352-77g-mol-how-many-grams-o	24.93 grams	start physical_unit 17 17 mass g qc_end physical_unit 1 3 5 6 mass qc_end physical_unit 1 3 11 12 molar_mass qc_end end	[{"type":"physical unit","value":"Weight [OF] carbon [IN] grams"}]	[{"type":"physical unit","value":"24.93 grams"}]	[{"type":"physical unit","value":"Weight [OF] C25H52 sample [=] \\pu{29.29 g}"},{"type":"physical unit","value":"Molar mass [OF] C25H52 sample [=] \\pu{352.77 g/mol}"}]	<h1 class="questionTitle" itemprop="name">A sample of C25H52 weighs 29.29 g. Its molar mass is 352.77g/mol. How many grams of carbon are in this sample? </h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>Any help is much appreciated!</p></div> </h2> </div> </div>	24.93 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Given is sample of <mathjax>#"C"_25"H"_52#</mathjax></p> <p>We see that <mathjax>#1" g mol"#</mathjax> of sample has <mathjax>#25#</mathjax> carbon atoms</p> <p>Taking Average <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">atomic mass</a> of carbon <mathjax>#"C"=12.011" amu"#</mathjax>, we obtain gram molecular weight of carbon in 1 mol of sample<mathjax>#=25xx12.011#</mathjax> <br/> <mathjax>#=300.275#</mathjax><br/> Setting up the equation </p> <p><mathjax>#352.77g#</mathjax> of sample has carbon<mathjax>#=300.275g#</mathjax><br/> <mathjax>#1g#</mathjax> of sample has carbon<mathjax>#=300.275/352.77g#</mathjax><br/> <mathjax>#29.29 g#</mathjax> of sample has carbon<mathjax>#=300.275/352.77xx29.29#</mathjax><br/> <mathjax>#=24.93g#</mathjax>, rounded to two decimal places.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#24.93g#</mathjax>, rounded to two decimal places.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Given is sample of <mathjax>#"C"_25"H"_52#</mathjax></p> <p>We see that <mathjax>#1" g mol"#</mathjax> of sample has <mathjax>#25#</mathjax> carbon atoms</p> <p>Taking Average <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">atomic mass</a> of carbon <mathjax>#"C"=12.011" amu"#</mathjax>, we obtain gram molecular weight of carbon in 1 mol of sample<mathjax>#=25xx12.011#</mathjax> <br/> <mathjax>#=300.275#</mathjax><br/> Setting up the equation </p> <p><mathjax>#352.77g#</mathjax> of sample has carbon<mathjax>#=300.275g#</mathjax><br/> <mathjax>#1g#</mathjax> of sample has carbon<mathjax>#=300.275/352.77g#</mathjax><br/> <mathjax>#29.29 g#</mathjax> of sample has carbon<mathjax>#=300.275/352.77xx29.29#</mathjax><br/> <mathjax>#=24.93g#</mathjax>, rounded to two decimal places.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A sample of C25H52 weighs 29.29 g. Its molar mass is 352.77g/mol. How many grams of carbon are in this sample? </h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>Any help is much appreciated!</p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="368742" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/a08"><img alt="" class="" src="https://profilepictures.socratic.org/fZvgXOhDR1W7ogoxiea9_Ridge%2C_Shimla.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/a08"> A08 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-01-24T17:30:13" itemprop="dateCreated"> Jan 24, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#24.93g#</mathjax>, rounded to two decimal places.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Given is sample of <mathjax>#"C"_25"H"_52#</mathjax></p> <p>We see that <mathjax>#1" g mol"#</mathjax> of sample has <mathjax>#25#</mathjax> carbon atoms</p> <p>Taking Average <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">atomic mass</a> of carbon <mathjax>#"C"=12.011" amu"#</mathjax>, we obtain gram molecular weight of carbon in 1 mol of sample<mathjax>#=25xx12.011#</mathjax> <br/> <mathjax>#=300.275#</mathjax><br/> Setting up the equation </p> <p><mathjax>#352.77g#</mathjax> of sample has carbon<mathjax>#=300.275g#</mathjax><br/> <mathjax>#1g#</mathjax> of sample has carbon<mathjax>#=300.275/352.77g#</mathjax><br/> <mathjax>#29.29 g#</mathjax> of sample has carbon<mathjax>#=300.275/352.77xx29.29#</mathjax><br/> <mathjax>#=24.93g#</mathjax>, rounded to two decimal places.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/368742" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="368744" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-01-24T17:33:56" itemprop="dateCreated"> Jan 24, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Approx. <mathjax>#25g#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#%"by mass of carbon with respect to 1 mole of "C_25H_52#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(25xx12.011gmol^-1)/(352.77gmol^-1)xx100%=85.12%#</mathjax></p> <p>And thus, in a <mathjax>#29.29g#</mathjax> mass, <mathjax>#%C=29.29*gxx85.12%=??#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/368744" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the 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questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 5683 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A sample of C25H52 weighs 29.29 g. Its molar mass is 352.77g/mol. How many grams of carbon are in this sample?	Any help is much appreciated!
987	aab4c49e-6ddd-11ea-b08d-ccda262736ce	https://socratic.org/questions/58b8393fb72cff4ffbc5fe6e	HIO3 + 5 HI -> 3 I2 + 3 H2O	start chemical_equation qc_end chemical_equation 4 4 qc_end chemical_equation 9 9 qc_end substance 13 13 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the equation"}]	[{"type":"chemical equation","value":"HIO3 + 5 HI -> 3 I2 + 3 H2O"}]	[{"type":"chemical equation","value":"HIO3"},{"type":"chemical equation","value":"I-"},{"type":"substance name","value":"Iodine"}]	<h1 class="questionTitle" itemprop="name">How does #"iodic acid"#, #HIO_3#, react with iodide anion, #I^-#, to give elemental iodine?</h1>	null	HIO3 + 5 HI -> 3 I2 + 3 H2O	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Iodic acid"#</mathjax> is reduced to elemental iodine:</p> <p><mathjax>#HI^(+V)O_3 + 5H^(+)+5e^(-) rarr 1/2I_2 +3H_2O#</mathjax> <mathjax>#(i)#</mathjax></p> <p><mathjax>#"Iodide"#</mathjax> is oxidized to elemental iodine:</p> <p><mathjax>#I^(-) rarr 1/2I_2+e^(-)#</mathjax> <mathjax>#(ii)#</mathjax></p> <p>So <mathjax>#(i)+5xx(ii)=#</mathjax></p> <p><mathjax>#HI^(+V)O_3 + 5H^(+)+5I^(-) rarr 3I_2 +3H_2O#</mathjax></p> <p>This is AFAIK balanced with respect to mass and charge, and therefore a reasonable representation of chemical reality. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>This is a so-called <mathjax>#"comproportionation reaction"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Iodic acid"#</mathjax> is reduced to elemental iodine:</p> <p><mathjax>#HI^(+V)O_3 + 5H^(+)+5e^(-) rarr 1/2I_2 +3H_2O#</mathjax> <mathjax>#(i)#</mathjax></p> <p><mathjax>#"Iodide"#</mathjax> is oxidized to elemental iodine:</p> <p><mathjax>#I^(-) rarr 1/2I_2+e^(-)#</mathjax> <mathjax>#(ii)#</mathjax></p> <p>So <mathjax>#(i)+5xx(ii)=#</mathjax></p> <p><mathjax>#HI^(+V)O_3 + 5H^(+)+5I^(-) rarr 3I_2 +3H_2O#</mathjax></p> <p>This is AFAIK balanced with respect to mass and charge, and therefore a reasonable representation of chemical reality. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How does #"iodic acid"#, #HIO_3#, react with iodide anion, #I^-#, to give elemental iodine?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#electrochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Electrochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/electrochemistry/balancing-redox-equations-using-the-oxidation-number-method" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Redox Equations Using the Oxidation Number Method</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="386051" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-03T20:34:54" itemprop="dateCreated"> Mar 3, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>This is a so-called <mathjax>#"comproportionation reaction"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Iodic acid"#</mathjax> is reduced to elemental iodine:</p> <p><mathjax>#HI^(+V)O_3 + 5H^(+)+5e^(-) rarr 1/2I_2 +3H_2O#</mathjax> <mathjax>#(i)#</mathjax></p> <p><mathjax>#"Iodide"#</mathjax> is oxidized to elemental iodine:</p> <p><mathjax>#I^(-) rarr 1/2I_2+e^(-)#</mathjax> <mathjax>#(ii)#</mathjax></p> <p>So <mathjax>#(i)+5xx(ii)=#</mathjax></p> <p><mathjax>#HI^(+V)O_3 + 5H^(+)+5I^(-) rarr 3I_2 +3H_2O#</mathjax></p> <p>This is AFAIK balanced with respect to mass and charge, and therefore a reasonable representation of chemical reality. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/386051" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="386120" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-04T00:23:08" itemprop="dateCreated"> Mar 4, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><strong>WARNING! Long answer!</strong> The balanced equation is</p> <p><mathjax>#"HIO"_3 + "5HI" → "3I"_2 + "3H"_2"O"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>We start with the unbalanced equation:</p> <p><mathjax>#"HIO"_3 + "HI" → "I"_2 + "H"_2"O"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 1. Identify the atoms that change oxidation number</strong></p> <p>We start by determining the <a href="https://socratic.org/chemistry/electrochemistry/oxidation-numbers">oxidation numbers</a> of every atom in the equation.</p> <p><mathjax>#stackrelcolor(blue)("+1")("H")stackrelcolor(blue)("+5")("I")stackrelcolor(blue)("-2")("O")_3 + stackrelcolor(blue)("+1")("H")stackrelcolor(blue)("-1")("I") → stackrelcolor(blue)(0)("I")_2 + stackrelcolor(blue)("+1")("H")_2stackrelcolor(blue)("-2")("O")#</mathjax><br/> <mathjax>#color(white)(stackrelcolor(blue)("+1")("H")stackrelcolor(blue)("+5")("I")stackrelcolor(blue)("-6")("O")_3 + stackrelcolor(blue)("+1")("H")stackrelcolor(blue)("-1")("I") → stackrelcolor(blue)(0)("I")_2 + stackrelcolor(blue)("+2")("H")_2stackrelcolor(blue)("-2")("O"))#</mathjax></p> <p>We see that the oxidation number of <mathjax>#"I"#</mathjax> in <mathjax>#"HIO"_3#</mathjax> is reduced to 0 in <mathjax>#"I"_2#</mathjax> and the oxidation number if <mathjax>#"I"#</mathjax> in <mathjax>#"HI"#</mathjax> is increased to 0 in <mathjax>#"I"_2#</mathjax>.</p> <p>This is a <strong>comproportionation</strong> reaction, a reaction in which an element in a higher oxidation state reacts with the same element in a lower oxidation state to give the element in an intermediate oxidation state.</p> <blockquote></blockquote> <p>The changes in oxidation number are:</p> <p><mathjax>#"I: +5 → 0";color(white)(l) "Change" =color(white)(l) "-5 (reduction)"#</mathjax><br/> <mathjax>#"I: -1 → 0"; color(white)(ll)"Change ="color(white)(l) "+1 (oxidation)"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 2. Equalize the changes in oxidation number</strong></p> <p>We need 1 atom of <mathjax>#"I"#</mathjax> in <mathjax>#"HIO"_3#</mathjax> for every 5 atoms of <mathjax>#"I"#</mathjax> in <mathjax>#"HI"#</mathjax>.</p> <p>That also means that we need a total of 6 <mathjax>#"I"#</mathjax> atoms.</p> <blockquote></blockquote> <p><strong>Step 3. Insert coefficients to get these numbers</strong></p> <p><mathjax>#color(red)(1)"HIO"_3 + color(red)(5)"HI" → color(red)(3)"I"_2 + "H"_2"O"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 4. Balance <mathjax>#"O"#</mathjax></strong></p> <p>We have fixed 3 <mathjax>#"O"#</mathjax> atoms on the left, so we need 3 <mathjax>#"O"#</mathjax> atoms on the right. Put a 3 before <mathjax>#"H"_2"O"#</mathjax>.</p> <p><mathjax>#color(red)(1)"HIO"_3 + color(red)(5)"HI" → color(red)(3)"I"_2 + color(blue)(3)"H"_2"O"#</mathjax></p> <p>Every formula now has a coefficient. The equation should be balanced.</p> <blockquote></blockquote> <p><strong>Step 7. Check that all atoms are balanced.</strong></p> <p><mathjax>#bb("On the left"color(white)(l) "On the right")#</mathjax><br/> <mathjax>#color(white)(mm)"6 H"color(white)(mmmml) "6 H"#</mathjax><br/> <mathjax>#color(white)(mm)"6 I"color(white)(mmmmll) 6 color(white)(l)"I"#</mathjax><br/> <mathjax>#color(white)(mm)"3 O"color(white)(mmmml) "3 O"#</mathjax></p> <blockquote></blockquote> <p>The balanced equation is</p> <p><mathjax>#color(red)("HIO"_3 + "5HI" → "3I"_2 + "3H"_2"O")#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/386120" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-balance-redox-reactions-in-basic-solution"> How do you balance redox reactions in basic solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-balance-redox-equations-by-oxidation-number-method"> How do you balance redox equations by oxidation number method? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-balance-redox-equations-in-acidic-solutions"> How do you balance redox equations in acidic solutions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-method"> What is the oxidation number method? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-examples-of-balancing-redox-equations-using-the-oxidation-number-m"> What are some examples of balancing redox equations using the oxidation number method? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-oxidation-number-method-useful"> Why is the oxidation number method useful? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-it-necessary-to-break-the-equation-into-half-reactions-in-the-oxidation-numbe"> Is it necessary to break the equation into half reactions in the oxidation number method? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-difference-between-the-oxidation-number-method-and-the-ion-electron-"> What is the difference between the oxidation number method and the ion-electron method? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-balance-the-equation-using-the-oxidation-states-method-mno2-al-mn-al2o3"> Can you balance the equation using the oxidation states method MnO2+Al--->Mn+Al2O3? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-balance-this-redox-reaction-using-the-oxidation-number-method-fe2-aq-"> How do you balance this redox reaction using the oxidation number method? Fe2+(aq) + MnO4–(aq)... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/electrochemistry/balancing-redox-equations-using-the-oxidation-number-method"> See all questions in Balancing Redox Equations Using the Oxidation Number Method </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 4211 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How does #"iodic acid"#, #HIO_3#, react with iodide anion, #I^-#, to give elemental iodine?	null
988	ab2605b7-6ddd-11ea-bbec-ccda262736ce	https://socratic.org/questions/what-is-the-mass-of-2-6-moles-of-ag	280.46 g	start physical_unit 8 8 mass g qc_end physical_unit 8 8 5 6 mole qc_end end	[{"type":"physical unit","value":"Mass [OF] Ag [IN] g"}]	[{"type":"physical unit","value":"280.46 g"}]	[{"type":"physical unit","value":"Mole [OF] Ag [=] \\pu{2.6 moles}"}]	<h1 class="questionTitle" itemprop="name">What is the mass of 2.6 moles of Ag? </h1>	null	280.46 g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Multiply the moles of <mathjax>#"Ag"#</mathjax> by its molar mass (atomic weight in g/mol).</p> <p><mathjax>#2.6color(red)cancel(color(black)("mol Ag "))xx(107.8682"g Ag")/(1color(red)cancel(color(black)("mol Ag")))= "280 g Ag"#</mathjax> (rounded to two significant figures)</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"2.6 mol Ag"#</mathjax> has a mass of <mathjax>#"280 g"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Multiply the moles of <mathjax>#"Ag"#</mathjax> by its molar mass (atomic weight in g/mol).</p> <p><mathjax>#2.6color(red)cancel(color(black)("mol Ag "))xx(107.8682"g Ag")/(1color(red)cancel(color(black)("mol Ag")))= "280 g Ag"#</mathjax> (rounded to two significant figures)</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the mass of 2.6 moles of Ag? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="639302" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-07-08T14:48:05" itemprop="dateCreated"> Jul 8, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"2.6 mol Ag"#</mathjax> has a mass of <mathjax>#"280 g"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Multiply the moles of <mathjax>#"Ag"#</mathjax> by its molar mass (atomic weight in g/mol).</p> <p><mathjax>#2.6color(red)cancel(color(black)("mol Ag "))xx(107.8682"g Ag")/(1color(red)cancel(color(black)("mol Ag")))= "280 g Ag"#</mathjax> (rounded to two significant figures)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/639302" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? 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989	aa543d62-6ddd-11ea-8e27-ccda262736ce	https://socratic.org/questions/a-sample-of-c-3h-8-has-6-72-times-10-24-h-atoms-how-many-carbon-atoms-does-the-s	2.52 × 10^24	start physical_unit 12 13 number none qc_end physical_unit 8 9 5 7 number qc_end chemical_equation 3 3 qc_end end	[{"type":"physical unit","value":"Number [OF] carbon atoms"}]	[{"type":"physical unit","value":"2.52 × 10^24"}]	[{"type":"physical unit","value":"Number [OF] H atoms [=] \\pu{6.72 × 10^24}"},{"type":"chemical equation","value":"C3H8"}]	<h1 class="questionTitle" itemprop="name">A sample of #C_3H_8# has #6.72 times 10^24# #H# atoms. How many carbon atoms does the sample contain?</h1>	null	2.52 × 10^24	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>If we have <mathjax>#6.72xx10^24#</mathjax> hydrogen atoms in the propane sample, surely given the formula of propane, i.e. <mathjax>#C_3H_8#</mathjax>, there would be <mathjax>#3/8xx6.72xx10^24#</mathjax> individual carbon atoms...... </p> <p>The numbers here are pretty irrelevant (meaning that I could choose any number), save that we also know that <mathjax>#"Avogadro's Number"#</mathjax> of <mathjax>#"propane molecules"#</mathjax>, <mathjax>#6.022xx10^23#</mathjax> individual molecules of propane, has a mass of <mathjax>#44.1*g#</mathjax>. Can you tell us the mass of the given quantity of propane in the question?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Would this not simply be <mathjax>#3/8xx6.72xx10^24#</mathjax> <mathjax>#"carbon atoms"#</mathjax>?</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>If we have <mathjax>#6.72xx10^24#</mathjax> hydrogen atoms in the propane sample, surely given the formula of propane, i.e. <mathjax>#C_3H_8#</mathjax>, there would be <mathjax>#3/8xx6.72xx10^24#</mathjax> individual carbon atoms...... </p> <p>The numbers here are pretty irrelevant (meaning that I could choose any number), save that we also know that <mathjax>#"Avogadro's Number"#</mathjax> of <mathjax>#"propane molecules"#</mathjax>, <mathjax>#6.022xx10^23#</mathjax> individual molecules of propane, has a mass of <mathjax>#44.1*g#</mathjax>. Can you tell us the mass of the given quantity of propane in the question?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A sample of #C_3H_8# has #6.72 times 10^24# #H# atoms. How many carbon atoms does the sample contain?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="448092" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-07-05T04:52:08" itemprop="dateCreated"> Jul 5, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Would this not simply be <mathjax>#3/8xx6.72xx10^24#</mathjax> <mathjax>#"carbon atoms"#</mathjax>?</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>If we have <mathjax>#6.72xx10^24#</mathjax> hydrogen atoms in the propane sample, surely given the formula of propane, i.e. <mathjax>#C_3H_8#</mathjax>, there would be <mathjax>#3/8xx6.72xx10^24#</mathjax> individual carbon atoms...... </p> <p>The numbers here are pretty irrelevant (meaning that I could choose any number), save that we also know that <mathjax>#"Avogadro's Number"#</mathjax> of <mathjax>#"propane molecules"#</mathjax>, <mathjax>#6.022xx10^23#</mathjax> individual molecules of propane, has a mass of <mathjax>#44.1*g#</mathjax>. Can you tell us the mass of the given quantity of propane in the question?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/448092" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1784 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A sample of #C_3H_8# has #6.72 times 10^24# #H# atoms. How many carbon atoms does the sample contain?	null
990	ad1ffa70-6ddd-11ea-bc11-ccda262736ce	https://socratic.org/questions/57a734ca11ef6b2a1b6eaa62	7.31 × 10^(-22) g	start physical_unit 6 8 mass g qc_end physical_unit 6 8 5 5 number qc_end end	[{"type":"physical unit","value":"Mass [OF] carbon dioxide molecules [IN] g"}]	[{"type":"physical unit","value":"7.31 × 10^(-22) g"}]	[{"type":"physical unit","value":"Number [OF] carbon dioxide molecules [=] \\pu{10}"}]	<h1 class="questionTitle" itemprop="name">What is the mass of 10 carbon dioxide molecules?</h1>	null	7.31 × 10^(-22) g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And <mathjax>#N_A="Avogadro's number"=6.022xx10^23mol^-1#</mathjax></p> <p><mathjax>#"Mass of 10 carbon dioxide molecules"#</mathjax></p> <p><mathjax>#=#</mathjax> <mathjax>#(44.01gmol^-1xx10)/(6.022xx10^23mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??g#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well the mass of <mathjax>#N_A" carbon dioxide molecules"#</mathjax> is <mathjax>#44.01g#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And <mathjax>#N_A="Avogadro's number"=6.022xx10^23mol^-1#</mathjax></p> <p><mathjax>#"Mass of 10 carbon dioxide molecules"#</mathjax></p> <p><mathjax>#=#</mathjax> <mathjax>#(44.01gmol^-1xx10)/(6.022xx10^23*mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??g#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the mass of 10 carbon dioxide molecules?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="296476" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-08-07T13:58:49" itemprop="dateCreated"> Aug 7, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well the mass of <mathjax>#N_A" carbon dioxide molecules"#</mathjax> is <mathjax>#44.01g#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And <mathjax>#N_A="Avogadro's number"=6.022xx10^23mol^-1#</mathjax></p> <p><mathjax>#"Mass of 10 carbon dioxide molecules"#</mathjax></p> <p><mathjax>#=#</mathjax> <mathjax>#(44.01gmol^-1xx10)/(6.022xx10^23*mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??g#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/296476" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? 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991	acabe092-6ddd-11ea-a3bb-ccda262736ce	https://socratic.org/questions/how-do-you-calculate-the-equilibrium-concentration-of-h-3o-in-a-0-20-m-solution-	0.08 M	start physical_unit 8 8 equilibrium_concentration mol/l qc_end physical_unit 15 16 11 12 concentration qc_end end	[{"type":"physical unit","value":"Equilibrium concentration [OF] H3O+ [IN] M"}]	[{"type":"physical unit","value":"0.08 M"}]	[{"type":"physical unit","value":"Concentration [OF] oxalic acid solution [=] \\pu{0.20 M}"}]	<h1 class="questionTitle" itemprop="name">How do you calculate the equilibrium concentration of #H_3O+# in a 0.20 M solution of oxalic acid?</h1>	null	0.08 M	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The oxalic acid is a dicarboxylic acid. Each molecule of the acid partially disassociates to produce up to two hydronium ions when dissolved in water. Calculation of <mathjax>#"H"_3"O"^+#</mathjax> for the <mathjax>#0.20 color(white)(l) "M"#</mathjax> solution requires knowledge of both first and the second acid disassociation constants of the oxalic acid.</p> <p>From <a href="https://en.wikipedia.org/wiki/Oxalic_acid" rel="nofollow">the Wikipedia page</a> for oxalic acid,</p> <ul> <li><mathjax>#pK_a = 1.27#</mathjax> for the partial disassociation of <mathjax>#"C"_2"H"_2"O"_4#</mathjax></li> <li><mathjax>#pK_b = 4.27#</mathjax> for the partial disassociation of <mathjax>#"C"_2"H" "O"_4^(-)#</mathjax></li> </ul> <p>Construct a rice table (also in <mathjax>#"M"#</mathjax>) for each of the process. Let the final increase in hydronium concentration due to the disassociation of <mathjax>#"C"_2"H"_2"O"_4#</mathjax> be <mathjax>#x#</mathjax>.</p> <p><strong>R</strong> <mathjax>#"C"_2"H"_2"O"_4 (aq) + "H"_2"O"(l) rightleftharpoons "C"_2"H""O"_4^(-)(aq) + "H"_3"O"^(+)(aq)#</mathjax><br/> <strong>I</strong> <mathjax>#color(white)(I)0.20 color(white)(."O"_4 (aq) + "H"_2"O"(l) rightleftharpoons) 0 color(white)("."_2"H""O"_4^(-)(aq) + ) 0 #</mathjax><br/> <strong>C</strong> <mathjax>#-x color(white)("l"_2"O"_4 (aq) + "H"_2"O"(l)rightleftharpoons) +x color(white)("O"_4^(-)(aq) + ) +x#</mathjax><br/> <strong>E</strong> <mathjax>#0.20 - x color(white)((aq) + "H"_2"O"(l) rightleftharpoons) color(grey)(cancel(x)) color(white)("."_2"H""O"_4^(-)(aq) + ) color(grey)(cancel(x))#</mathjax></p> <p>The disassociation of <mathjax>#"C"_2"H"_2"O"_4#</mathjax> accounts for all <mathjax>#"H"_3"O"^(+)#</mathjax> and <mathjax>#"C"_2"H" "O"_4^(-)#</mathjax> in the system before the onset of the second process. Concentrations for these two species in the initial conditions of the second <strong>RICE</strong> table for the disassociation of <mathjax>#"C"_2"H" "O"_4^(-)#</mathjax> are therefore identical to those in the final condition of the first process. Let the increase in hydronium concentration due to the disassociation of <mathjax>#"C"_2"H" "O"_4^(-)#</mathjax> be <mathjax>#y#</mathjax>.</p> <p><strong>R</strong> <mathjax>#"C"_2"H""O"_4^(-) (aq) + "H"_2"O"(l) rightleftharpoons "C"_2"O"_4^(2-)(aq) + "H"_3"O"^(+)(aq)#</mathjax><br/> <strong>I</strong> <mathjax>#color(white)(I)x color(white)("c"_2"H""O"_4 (aq) + "H"_2"O"(l) rightleftharpoons) 0 color(white)("."_2"O"_4^(2-)(aq) + ) x #</mathjax><br/> <strong>C</strong> <mathjax>#-y color(white)("l"_2"O"_4 (aq) + "H"_2"O"(l)rightleftharpoons) +y color(white)("."_4^(2-)(aq) + ) +y#</mathjax><br/> <strong>E</strong> <mathjax># color(purple)(x - y) color(white)("C"_4 (aq) + "H"_2"O"(l) rightleftharpoons) y color(white)("."_2"l""O"_4^(-)(aq) + ) color(purple)(x + y)#</mathjax></p> <p>The solution to the two <strong>RICE</strong> table shall satisfy the equilibrium condition for both processes simultaneously. However, both equations are supposed to take the equilibrium concentration found in the second and the last table in case the concentration of a species (e.g., <mathjax>#"H"_3"O"^(+)#</mathjax> is changed in both processes. That is:</p> <ul> <li><mathjax>#(( color(purple)(x - y) ) * ( color(purple)(x + y)) ) / ( 0.20 - x) = 10 ^ (-1.27)#</mathjax> for the first process and </li> <li><mathjax>#(( color(purple)(x + y) ) * ( y )) / ( color(purple)(x - y) ) = 10 ^ (-4.27)#</mathjax> for the second process.</li> </ul> <p>Solving the quadratic system (preferably with a Computer Algebra System) yields a collection of sets of values for <mathjax>#x#</mathjax> and <mathjax>#y#</mathjax>. Both <mathjax>#x#</mathjax> and <mathjax>#y#</mathjax> are supposed to be greater than zero given that concentrations of species such as <mathjax>#"H"_3"O"^(+)#</mathjax> and <mathjax>#"C"_2"O"_4^(-)#</mathjax> always take non-negative values. <a href="https://www.wolframalpha.com/input/?i=Solve%5B%7B%28%20x%20%5E%202%20%29%20/%20%28%200.20%20-%20x%29%20==%2010%20%5E%20%28-1.27%29,%20%28%28%20x%20%2b%20y%20%29%20%20%28%20y%20%29%29%20/%20%28%20x%20-%20y%20%29%20==%2010%20%5E%20%28-4.27%29,%20x%20%3E=%200,%20y%20%3E=%200%7D,%20%7Bx,%20y%7D%5D" rel="nofollow">Screening</a> the result with the condition <mathjax>#x >= 0#</mathjax>, <mathjax>#y >= 0#</mathjax> help narrows down to <a href="https://www.wolframalpha.com/input/?i=Solve%5B%7B%28%20x%20%5E%202%20%29%20/%20%28%200.20%20-%20x%29%20==%2010%20%5E%20%28-1.27%29,%20%28%28%20x%20%2b%20y%20%29%20%20%28%20y%20%29%29%20/%20%28%20x%20-%20y%20%29%20==%2010%20%5E%20%28-4.27%29,%20x%20%3E=%200,%20y%20%3E=%200%7D,%20%7Bx,%20y%7D%5D" rel="nofollow">a single possible outcome</a>:</p> <ul> <li><mathjax>#x = 8.02 xx 10^(-2)#</mathjax></li> <li><mathjax>#y = 5.36 xx 10^(-4)#</mathjax></li> </ul> <p>The second <strong>RICE</strong> table gives the equilibrium concentration for <mathjax>#"H"_3"O"^(+)#</mathjax>:</p> <p><mathjax>#["H"_3"O"^(+)] = color(purple)(x + y) ~~ 0.0803 color(white)(l) "mol" * "dm"^(-3)#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#["H"_3"O"^(+)] = 0.0803 color(white)(l) "mol" * "dm"^(-3)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The oxalic acid is a dicarboxylic acid. Each molecule of the acid partially disassociates to produce up to two hydronium ions when dissolved in water. Calculation of <mathjax>#"H"_3"O"^+#</mathjax> for the <mathjax>#0.20 color(white)(l) "M"#</mathjax> solution requires knowledge of both first and the second acid disassociation constants of the oxalic acid.</p> <p>From <a href="https://en.wikipedia.org/wiki/Oxalic_acid" rel="nofollow">the Wikipedia page</a> for oxalic acid,</p> <ul> <li><mathjax>#pK_a = 1.27#</mathjax> for the partial disassociation of <mathjax>#"C"_2"H"_2"O"_4#</mathjax></li> <li><mathjax>#pK_b = 4.27#</mathjax> for the partial disassociation of <mathjax>#"C"_2"H" "O"_4^(-)#</mathjax></li> </ul> <p>Construct a rice table (also in <mathjax>#"M"#</mathjax>) for each of the process. Let the final increase in hydronium concentration due to the disassociation of <mathjax>#"C"_2"H"_2"O"_4#</mathjax> be <mathjax>#x#</mathjax>.</p> <p><strong>R</strong> <mathjax>#"C"_2"H"_2"O"_4 (aq) + "H"_2"O"(l) rightleftharpoons "C"_2"H""O"_4^(-)(aq) + "H"_3"O"^(+)(aq)#</mathjax><br/> <strong>I</strong> <mathjax>#color(white)(I)0.20 color(white)(."O"_4 (aq) + "H"_2"O"(l) rightleftharpoons) 0 color(white)("."_2"H""O"_4^(-)(aq) + ) 0 #</mathjax><br/> <strong>C</strong> <mathjax>#-x color(white)("l"_2"O"_4 (aq) + "H"_2"O"(l)rightleftharpoons) +x color(white)("O"_4^(-)(aq) + ) +x#</mathjax><br/> <strong>E</strong> <mathjax>#0.20 - x color(white)((aq) + "H"_2"O"(l) rightleftharpoons) color(grey)(cancel(x)) color(white)("."_2"H""O"_4^(-)(aq) + ) color(grey)(cancel(x))#</mathjax></p> <p>The disassociation of <mathjax>#"C"_2"H"_2"O"_4#</mathjax> accounts for all <mathjax>#"H"_3"O"^(+)#</mathjax> and <mathjax>#"C"_2"H" "O"_4^(-)#</mathjax> in the system before the onset of the second process. Concentrations for these two species in the initial conditions of the second <strong>RICE</strong> table for the disassociation of <mathjax>#"C"_2"H" "O"_4^(-)#</mathjax> are therefore identical to those in the final condition of the first process. Let the increase in hydronium concentration due to the disassociation of <mathjax>#"C"_2"H" "O"_4^(-)#</mathjax> be <mathjax>#y#</mathjax>.</p> <p><strong>R</strong> <mathjax>#"C"_2"H""O"_4^(-) (aq) + "H"_2"O"(l) rightleftharpoons "C"_2"O"_4^(2-)(aq) + "H"_3"O"^(+)(aq)#</mathjax><br/> <strong>I</strong> <mathjax>#color(white)(I)x color(white)("c"_2"H""O"_4 (aq) + "H"_2"O"(l) rightleftharpoons) 0 color(white)("."_2"O"_4^(2-)(aq) + ) x #</mathjax><br/> <strong>C</strong> <mathjax>#-y color(white)("l"_2"O"_4 (aq) + "H"_2"O"(l)rightleftharpoons) +y color(white)("."_4^(2-)(aq) + ) +y#</mathjax><br/> <strong>E</strong> <mathjax># color(purple)(x - y) color(white)("C"_4 (aq) + "H"_2"O"(l) rightleftharpoons) y color(white)("."_2"l""O"_4^(-)(aq) + ) color(purple)(x + y)#</mathjax></p> <p>The solution to the two <strong>RICE</strong> table shall satisfy the equilibrium condition for both processes simultaneously. However, both equations are supposed to take the equilibrium concentration found in the second and the last table in case the concentration of a species (e.g., <mathjax>#"H"_3"O"^(+)#</mathjax> is changed in both processes. That is:</p> <ul> <li><mathjax>#(( color(purple)(x - y) ) * ( color(purple)(x + y)) ) / ( 0.20 - x) = 10 ^ (-1.27)#</mathjax> for the first process and </li> <li><mathjax>#(( color(purple)(x + y) ) * ( y )) / ( color(purple)(x - y) ) = 10 ^ (-4.27)#</mathjax> for the second process.</li> </ul> <p>Solving the quadratic system (preferably with a Computer Algebra System) yields a collection of sets of values for <mathjax>#x#</mathjax> and <mathjax>#y#</mathjax>. Both <mathjax>#x#</mathjax> and <mathjax>#y#</mathjax> are supposed to be greater than zero given that concentrations of species such as <mathjax>#"H"_3"O"^(+)#</mathjax> and <mathjax>#"C"_2"O"_4^(-)#</mathjax> always take non-negative values. <a href="https://www.wolframalpha.com/input/?i=Solve%5B%7B%28%20x%20%5E%202%20%29%20/%20%28%200.20%20-%20x%29%20==%2010%20%5E%20%28-1.27%29,%20%28%28%20x%20%2b%20y%20%29%20%20%28%20y%20%29%29%20/%20%28%20x%20-%20y%20%29%20==%2010%20%5E%20%28-4.27%29,%20x%20%3E=%200,%20y%20%3E=%200%7D,%20%7Bx,%20y%7D%5D" rel="nofollow">Screening</a> the result with the condition <mathjax>#x >= 0#</mathjax>, <mathjax>#y >= 0#</mathjax> help narrows down to <a href="https://www.wolframalpha.com/input/?i=Solve%5B%7B%28%20x%20%5E%202%20%29%20/%20%28%200.20%20-%20x%29%20==%2010%20%5E%20%28-1.27%29,%20%28%28%20x%20%2b%20y%20%29%20%20%28%20y%20%29%29%20/%20%28%20x%20-%20y%20%29%20==%2010%20%5E%20%28-4.27%29,%20x%20%3E=%200,%20y%20%3E=%200%7D,%20%7Bx,%20y%7D%5D" rel="nofollow">a single possible outcome</a>:</p> <ul> <li><mathjax>#x = 8.02 xx 10^(-2)#</mathjax></li> <li><mathjax>#y = 5.36 xx 10^(-4)#</mathjax></li> </ul> <p>The second <strong>RICE</strong> table gives the equilibrium concentration for <mathjax>#"H"_3"O"^(+)#</mathjax>:</p> <p><mathjax>#["H"_3"O"^(+)] = color(purple)(x + y) ~~ 0.0803 color(white)(l) "mol" * "dm"^(-3)#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you calculate the equilibrium concentration of #H_3O+# in a 0.20 M solution of oxalic acid?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-equilibrium" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Equilibrium</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-equilibrium/dynamic-equilibrium" itemprop="url"> <span class="breadcrumb" itemprop="title">Dynamic Equilibrium</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="641305" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/jacob-t-3"><img alt="" class="" src="https://profilepictures.socratic.org/cDl6OiFtT16bIyMtJPfM_Protractor.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/jacob-t-3"> Jacob T. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-07-17T07:52:55" itemprop="dateCreated"> Jul 17, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#["H"_3"O"^(+)] = 0.0803 color(white)(l) "mol" * "dm"^(-3)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The oxalic acid is a dicarboxylic acid. Each molecule of the acid partially disassociates to produce up to two hydronium ions when dissolved in water. Calculation of <mathjax>#"H"_3"O"^+#</mathjax> for the <mathjax>#0.20 color(white)(l) "M"#</mathjax> solution requires knowledge of both first and the second acid disassociation constants of the oxalic acid.</p> <p>From <a href="https://en.wikipedia.org/wiki/Oxalic_acid" rel="nofollow">the Wikipedia page</a> for oxalic acid,</p> <ul> <li><mathjax>#pK_a = 1.27#</mathjax> for the partial disassociation of <mathjax>#"C"_2"H"_2"O"_4#</mathjax></li> <li><mathjax>#pK_b = 4.27#</mathjax> for the partial disassociation of <mathjax>#"C"_2"H" "O"_4^(-)#</mathjax></li> </ul> <p>Construct a rice table (also in <mathjax>#"M"#</mathjax>) for each of the process. Let the final increase in hydronium concentration due to the disassociation of <mathjax>#"C"_2"H"_2"O"_4#</mathjax> be <mathjax>#x#</mathjax>.</p> <p><strong>R</strong> <mathjax>#"C"_2"H"_2"O"_4 (aq) + "H"_2"O"(l) rightleftharpoons "C"_2"H""O"_4^(-)(aq) + "H"_3"O"^(+)(aq)#</mathjax><br/> <strong>I</strong> <mathjax>#color(white)(I)0.20 color(white)(."O"_4 (aq) + "H"_2"O"(l) rightleftharpoons) 0 color(white)("."_2"H""O"_4^(-)(aq) + ) 0 #</mathjax><br/> <strong>C</strong> <mathjax>#-x color(white)("l"_2"O"_4 (aq) + "H"_2"O"(l)rightleftharpoons) +x color(white)("O"_4^(-)(aq) + ) +x#</mathjax><br/> <strong>E</strong> <mathjax>#0.20 - x color(white)((aq) + "H"_2"O"(l) rightleftharpoons) color(grey)(cancel(x)) color(white)("."_2"H""O"_4^(-)(aq) + ) color(grey)(cancel(x))#</mathjax></p> <p>The disassociation of <mathjax>#"C"_2"H"_2"O"_4#</mathjax> accounts for all <mathjax>#"H"_3"O"^(+)#</mathjax> and <mathjax>#"C"_2"H" "O"_4^(-)#</mathjax> in the system before the onset of the second process. Concentrations for these two species in the initial conditions of the second <strong>RICE</strong> table for the disassociation of <mathjax>#"C"_2"H" "O"_4^(-)#</mathjax> are therefore identical to those in the final condition of the first process. Let the increase in hydronium concentration due to the disassociation of <mathjax>#"C"_2"H" "O"_4^(-)#</mathjax> be <mathjax>#y#</mathjax>.</p> <p><strong>R</strong> <mathjax>#"C"_2"H""O"_4^(-) (aq) + "H"_2"O"(l) rightleftharpoons "C"_2"O"_4^(2-)(aq) + "H"_3"O"^(+)(aq)#</mathjax><br/> <strong>I</strong> <mathjax>#color(white)(I)x color(white)("c"_2"H""O"_4 (aq) + "H"_2"O"(l) rightleftharpoons) 0 color(white)("."_2"O"_4^(2-)(aq) + ) x #</mathjax><br/> <strong>C</strong> <mathjax>#-y color(white)("l"_2"O"_4 (aq) + "H"_2"O"(l)rightleftharpoons) +y color(white)("."_4^(2-)(aq) + ) +y#</mathjax><br/> <strong>E</strong> <mathjax># color(purple)(x - y) color(white)("C"_4 (aq) + "H"_2"O"(l) rightleftharpoons) y color(white)("."_2"l""O"_4^(-)(aq) + ) color(purple)(x + y)#</mathjax></p> <p>The solution to the two <strong>RICE</strong> table shall satisfy the equilibrium condition for both processes simultaneously. However, both equations are supposed to take the equilibrium concentration found in the second and the last table in case the concentration of a species (e.g., <mathjax>#"H"_3"O"^(+)#</mathjax> is changed in both processes. That is:</p> <ul> <li><mathjax>#(( color(purple)(x - y) ) * ( color(purple)(x + y)) ) / ( 0.20 - x) = 10 ^ (-1.27)#</mathjax> for the first process and </li> <li><mathjax>#(( color(purple)(x + y) ) * ( y )) / ( color(purple)(x - y) ) = 10 ^ (-4.27)#</mathjax> for the second process.</li> </ul> <p>Solving the quadratic system (preferably with a Computer Algebra System) yields a collection of sets of values for <mathjax>#x#</mathjax> and <mathjax>#y#</mathjax>. Both <mathjax>#x#</mathjax> and <mathjax>#y#</mathjax> are supposed to be greater than zero given that concentrations of species such as <mathjax>#"H"_3"O"^(+)#</mathjax> and <mathjax>#"C"_2"O"_4^(-)#</mathjax> always take non-negative values. <a href="https://www.wolframalpha.com/input/?i=Solve%5B%7B%28%20x%20%5E%202%20%29%20/%20%28%200.20%20-%20x%29%20==%2010%20%5E%20%28-1.27%29,%20%28%28%20x%20%2b%20y%20%29%20%20%28%20y%20%29%29%20/%20%28%20x%20-%20y%20%29%20==%2010%20%5E%20%28-4.27%29,%20x%20%3E=%200,%20y%20%3E=%200%7D,%20%7Bx,%20y%7D%5D" rel="nofollow">Screening</a> the result with the condition <mathjax>#x >= 0#</mathjax>, <mathjax>#y >= 0#</mathjax> help narrows down to <a href="https://www.wolframalpha.com/input/?i=Solve%5B%7B%28%20x%20%5E%202%20%29%20/%20%28%200.20%20-%20x%29%20==%2010%20%5E%20%28-1.27%29,%20%28%28%20x%20%2b%20y%20%29%20%20%28%20y%20%29%29%20/%20%28%20x%20-%20y%20%29%20==%2010%20%5E%20%28-4.27%29,%20x%20%3E=%200,%20y%20%3E=%200%7D,%20%7Bx,%20y%7D%5D" rel="nofollow">a single possible outcome</a>:</p> <ul> <li><mathjax>#x = 8.02 xx 10^(-2)#</mathjax></li> <li><mathjax>#y = 5.36 xx 10^(-4)#</mathjax></li> </ul> <p>The second <strong>RICE</strong> table gives the equilibrium concentration for <mathjax>#"H"_3"O"^(+)#</mathjax>:</p> <p><mathjax>#["H"_3"O"^(+)] = color(purple)(x + y) ~~ 0.0803 color(white)(l) "mol" * "dm"^(-3)#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/641305" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-temperature-affect-dynamic-equilibrium"> How does temperature affect dynamic equilibrium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-dynamic-equilibrium-important-for-living-organisms"> Why is dynamic equilibrium important for living organisms? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-dynamic-equilibrium-1"> What is dynamic equilibrium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-common-mistakes-students-make-with-dynamic-equilibrium-1"> What are some common mistakes students make with dynamic equilibrium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-dynamic-equilibrium-be-disrupted"> Can dynamic equilibrium be disrupted? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-concentration-effect-dynamic-equilibrium"> How does concentration effect dynamic equilibrium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-dynamic-equilibrium-related-to-vapor-pressure-1"> How is dynamic equilibrium related to vapor pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-homeostasis-a-type-of-dynamic-equilibrium"> Is homeostasis a type of dynamic equilibrium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-the-concentration-of-reactants-equal-to-the-concentration-of-products-in-a-dy"> Is the concentration of reactants equal to the concentration of products in a dynamic equilibrium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/once-dynamic-equilibrium-is-established-will-it-shift-if-additional-reactants-ar"> Once dynamic equilibrium is established, will it shift if additional reactants are added? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-equilibrium/dynamic-equilibrium"> See all questions in Dynamic Equilibrium </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 4458 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How do you calculate the equilibrium concentration of #H_3O+# in a 0.20 M solution of oxalic acid?	null
992	aadcaa54-6ddd-11ea-93ac-ccda262736ce	https://socratic.org/questions/what-is-the-percent-yield-for-the-following-chemical-reaction	75%	start physical_unit 58 59 percent_yield none qc_end chemical_equation 28 34 qc_end physical_unit 28 28 36 37 mole qc_end physical_unit 31 31 36 37 mole qc_end physical_unit 19 19 46 47 mole qc_end end	[{"type":"physical unit","value":"Percent yield [OF] the reaction"}]	[{"type":"physical unit","value":"75%"}]	[{"type":"chemical equation","value":"N2(g) + 3 H2(g) -> 2 NH3(g) "},{"type":"physical unit","value":"Mole [OF] N2 [=] \\pu{1 mole}"},{"type":"physical unit","value":"Mole [OF] H2 [=] \\pu{1 mole}"},{"type":"physical unit","value":"Mole [OF] NH3 [=] \\pu{0.50 moles}"}]	<h1 class="questionTitle" itemprop="name">What is the percent yield for the following chemical reaction?</h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>The Haber process can be used to produce ammonia, <mathjax>#NH_3#</mathjax>, and it is based on the following reaction.</p> <p><mathjax>#N_2(g)+3H_2(g)->2NH_3(g)#</mathjax></p> <p>If one mole each of <mathjax>#N_2#</mathjax> and <mathjax>#H_2#</mathjax> are mixed and 0.50 moles of <mathjax>#NH_3#</mathjax> are produced, what is the percent yield for the reaction?</p></div> </h2> </div> </div>	75%	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The first thing that you need to do here is to calculate the <strong>theoretical yield</strong> of the reaction, i.e. what you get if the reaction has a <mathjax>#100%#</mathjax> <strong>yield</strong>. </p> <p>The balanced chemical equation</p> <blockquote> <p><mathjax>#"N"_ (2(g)) + 3"H"_ (2(g)) -> 2"NH"_ (3(g))#</mathjax></p> </blockquote> <p>tells you that <strong>every</strong> <mathjax>#1#</mathjax> <strong>mole</strong> of nitrogen gas that takes part in the reaction will consume <mathjax>#3#</mathjax> <strong>moles</strong> of hydrogen gas and produce <mathjax>#1#</mathjax> <strong>mole</strong> of ammonia. </p> <p>In your case, you know that <mathjax>#1#</mathjax> <strong>mole</strong> of nitrogen gas reacts with <mathjax>#1#</mathjax> <strong>mole</strong> of hydrogen gas. Since you don't have enough hydrogen gas to ensure that <strong>all the moles</strong> of nitrogen gas can react</p> <blockquote> <p><mathjax>#overbrace("3 moles H"_2)^(color(blue)("what you need")) " " > " " overbrace("1 mole H"_2)^(color(blue)("what you have"))#</mathjax></p> </blockquote> <p>you can say that hydrogen gas will act as a <strong><a href="https://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a></strong>, i.e. it will be completely consumed <em>before</em> all the moles of nitrogen gas will get the chance to take part in the reaction. </p> <p>So, the reaction will consume <mathjax>#1#</mathjax> <strong>mole</strong> of hydrogen gas and produce </p> <blockquote> <p><mathjax>#1 color(red)(cancel(color(black)("mole H"_2))) * "2 moles NH"_3/(3color(red)(cancel(color(black)("moles H"_2)))) = "0.667 moles NH"_3#</mathjax></p> </blockquote> <p>at <mathjax>#100%#</mathjax> <strong>yield</strong>. This represents the reaction's <strong>theoretical yield</strong>. </p> <p>Now, you know that the reaction produced <mathjax>#0.50#</mathjax> <strong>moles</strong> of ammonia. This represents the reaction's <strong>actual yield</strong>. </p> <p>In order to find the <strong><a href="https://socratic.org/chemistry/stoichiometry/percent-yield">percent yield</a></strong>, you need to figure out how many moles of ammonia are <em>actually</em> produced for every <mathjax>#100#</mathjax> <strong>moles</strong> of ammonia that <em>could theoretically</em> be produced. </p> <p>You know that <mathjax>#0.667#</mathjax> <strong>moles</strong> will produce <mathjax>#0.50#</mathjax> <strong>moles</strong>, so you can say that</p> <blockquote> <p><mathjax>#100 color(red)(cancel(color(black)("moles NH"_3color(white)(.)"in theory"))) * ("0.50 moles NH"_3color(white)(.)"actual")/(0.667color(red)(cancel(color(black)("moles NH"_3color(white)(.)"in theory")))) = "75 moles NH"_3color(white)(.)"actual"#</mathjax></p> </blockquote> <p>Therefore, you can say that the reaction has a <strong>percent yield</strong> equal to</p> <blockquote> <p><mathjax>#color(darkgreen)(ul(color(black)("% yield = 75%")))#</mathjax></p> </blockquote> <p>I'll leave the answer rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#75%#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The first thing that you need to do here is to calculate the <strong>theoretical yield</strong> of the reaction, i.e. what you get if the reaction has a <mathjax>#100%#</mathjax> <strong>yield</strong>. </p> <p>The balanced chemical equation</p> <blockquote> <p><mathjax>#"N"_ (2(g)) + 3"H"_ (2(g)) -> 2"NH"_ (3(g))#</mathjax></p> </blockquote> <p>tells you that <strong>every</strong> <mathjax>#1#</mathjax> <strong>mole</strong> of nitrogen gas that takes part in the reaction will consume <mathjax>#3#</mathjax> <strong>moles</strong> of hydrogen gas and produce <mathjax>#1#</mathjax> <strong>mole</strong> of ammonia. </p> <p>In your case, you know that <mathjax>#1#</mathjax> <strong>mole</strong> of nitrogen gas reacts with <mathjax>#1#</mathjax> <strong>mole</strong> of hydrogen gas. Since you don't have enough hydrogen gas to ensure that <strong>all the moles</strong> of nitrogen gas can react</p> <blockquote> <p><mathjax>#overbrace("3 moles H"_2)^(color(blue)("what you need")) " " > " " overbrace("1 mole H"_2)^(color(blue)("what you have"))#</mathjax></p> </blockquote> <p>you can say that hydrogen gas will act as a <strong><a href="https://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a></strong>, i.e. it will be completely consumed <em>before</em> all the moles of nitrogen gas will get the chance to take part in the reaction. </p> <p>So, the reaction will consume <mathjax>#1#</mathjax> <strong>mole</strong> of hydrogen gas and produce </p> <blockquote> <p><mathjax>#1 color(red)(cancel(color(black)("mole H"_2))) * "2 moles NH"_3/(3color(red)(cancel(color(black)("moles H"_2)))) = "0.667 moles NH"_3#</mathjax></p> </blockquote> <p>at <mathjax>#100%#</mathjax> <strong>yield</strong>. This represents the reaction's <strong>theoretical yield</strong>. </p> <p>Now, you know that the reaction produced <mathjax>#0.50#</mathjax> <strong>moles</strong> of ammonia. This represents the reaction's <strong>actual yield</strong>. </p> <p>In order to find the <strong><a href="https://socratic.org/chemistry/stoichiometry/percent-yield">percent yield</a></strong>, you need to figure out how many moles of ammonia are <em>actually</em> produced for every <mathjax>#100#</mathjax> <strong>moles</strong> of ammonia that <em>could theoretically</em> be produced. </p> <p>You know that <mathjax>#0.667#</mathjax> <strong>moles</strong> will produce <mathjax>#0.50#</mathjax> <strong>moles</strong>, so you can say that</p> <blockquote> <p><mathjax>#100 color(red)(cancel(color(black)("moles NH"_3color(white)(.)"in theory"))) * ("0.50 moles NH"_3color(white)(.)"actual")/(0.667color(red)(cancel(color(black)("moles NH"_3color(white)(.)"in theory")))) = "75 moles NH"_3color(white)(.)"actual"#</mathjax></p> </blockquote> <p>Therefore, you can say that the reaction has a <strong>percent yield</strong> equal to</p> <blockquote> <p><mathjax>#color(darkgreen)(ul(color(black)("% yield = 75%")))#</mathjax></p> </blockquote> <p>I'll leave the answer rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the percent yield for the following chemical reaction?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>The Haber process can be used to produce ammonia, <mathjax>#NH_3#</mathjax>, and it is based on the following reaction.</p> <p><mathjax>#N_2(g)+3H_2(g)->2NH_3(g)#</mathjax></p> <p>If one mole each of <mathjax>#N_2#</mathjax> and <mathjax>#H_2#</mathjax> are mixed and 0.50 moles of <mathjax>#NH_3#</mathjax> are produced, what is the percent yield for the reaction?</p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/percent-yield" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Yield</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="477145" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-09-19T00:02:30" itemprop="dateCreated"> Sep 19, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#75%#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The first thing that you need to do here is to calculate the <strong>theoretical yield</strong> of the reaction, i.e. what you get if the reaction has a <mathjax>#100%#</mathjax> <strong>yield</strong>. </p> <p>The balanced chemical equation</p> <blockquote> <p><mathjax>#"N"_ (2(g)) + 3"H"_ (2(g)) -> 2"NH"_ (3(g))#</mathjax></p> </blockquote> <p>tells you that <strong>every</strong> <mathjax>#1#</mathjax> <strong>mole</strong> of nitrogen gas that takes part in the reaction will consume <mathjax>#3#</mathjax> <strong>moles</strong> of hydrogen gas and produce <mathjax>#1#</mathjax> <strong>mole</strong> of ammonia. </p> <p>In your case, you know that <mathjax>#1#</mathjax> <strong>mole</strong> of nitrogen gas reacts with <mathjax>#1#</mathjax> <strong>mole</strong> of hydrogen gas. Since you don't have enough hydrogen gas to ensure that <strong>all the moles</strong> of nitrogen gas can react</p> <blockquote> <p><mathjax>#overbrace("3 moles H"_2)^(color(blue)("what you need")) " " > " " overbrace("1 mole H"_2)^(color(blue)("what you have"))#</mathjax></p> </blockquote> <p>you can say that hydrogen gas will act as a <strong><a href="https://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a></strong>, i.e. it will be completely consumed <em>before</em> all the moles of nitrogen gas will get the chance to take part in the reaction. </p> <p>So, the reaction will consume <mathjax>#1#</mathjax> <strong>mole</strong> of hydrogen gas and produce </p> <blockquote> <p><mathjax>#1 color(red)(cancel(color(black)("mole H"_2))) * "2 moles NH"_3/(3color(red)(cancel(color(black)("moles H"_2)))) = "0.667 moles NH"_3#</mathjax></p> </blockquote> <p>at <mathjax>#100%#</mathjax> <strong>yield</strong>. This represents the reaction's <strong>theoretical yield</strong>. </p> <p>Now, you know that the reaction produced <mathjax>#0.50#</mathjax> <strong>moles</strong> of ammonia. This represents the reaction's <strong>actual yield</strong>. </p> <p>In order to find the <strong><a href="https://socratic.org/chemistry/stoichiometry/percent-yield">percent yield</a></strong>, you need to figure out how many moles of ammonia are <em>actually</em> produced for every <mathjax>#100#</mathjax> <strong>moles</strong> of ammonia that <em>could theoretically</em> be produced. </p> <p>You know that <mathjax>#0.667#</mathjax> <strong>moles</strong> will produce <mathjax>#0.50#</mathjax> <strong>moles</strong>, so you can say that</p> <blockquote> <p><mathjax>#100 color(red)(cancel(color(black)("moles NH"_3color(white)(.)"in theory"))) * ("0.50 moles NH"_3color(white)(.)"actual")/(0.667color(red)(cancel(color(black)("moles NH"_3color(white)(.)"in theory")))) = "75 moles NH"_3color(white)(.)"actual"#</mathjax></p> </blockquote> <p>Therefore, you can say that the reaction has a <strong>percent yield</strong> equal to</p> <blockquote> <p><mathjax>#color(darkgreen)(ul(color(black)("% yield = 75%")))#</mathjax></p> </blockquote> <p>I'll leave the answer rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/477145" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ebd02bf3469570e2e62"> Question #e2e62 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ec502bf34694a4fee2e"> Question #fee2e </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ec902bf34694a4fee32"> Question #fee32 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ece02bf346950519e89"> Question #19e89 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ed302bf34694c8c5bdc"> Question #c5bdc </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ee302bf3469517a1065"> Question #a1065 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-would-be-the-limiting-reagent-if-26-0-grams-of-c3h9n-were-reacted-with-46-3"> What would be the limiting reagent if 26.0 grams of C3H9N were reacted with 46.3 grams of... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-percent-yield-always-less-than-100"> Is percent yield always less than 100? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-would-be-the-limiting-reagent-if-41-9-grams-of-c2h3of-were-reacted-with-61-"> What would be the limiting reagent if 41.9 grams of C2H3OF were reacted with 61.0 grams of... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-yield-of-the-following-reaction-if-60-grams-of-caco3-is-heat"> What is the percent yield of the following reaction if 60 grams of CaCO3 is heated to give 15... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/percent-yield"> See all questions in Percent Yield </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 172686 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the percent yield for the following chemical reaction?	The Haber process can be used to produce ammonia, #NH_3#, and it is based on the following reaction. #N_2(g)+3H_2(g)->2NH_3(g)# If one mole each of #N_2# and #H_2# are mixed and 0.50 moles of #NH_3# are produced, what is the percent yield for the reaction?
993	abc6cb3e-6ddd-11ea-ba97-ccda262736ce	https://socratic.org/questions/c3h7oh-is-propanol-suppose-you-have-85-9-g-sample-of-propanol-how-many-carbon-at	2.58 × 10^24	start physical_unit 13 14 number none qc_end physical_unit 0 0 6 7 mass qc_end end	[{"type":"physical unit","value":"Number [OF] carbon atoms"}]	[{"type":"physical unit","value":"2.58 × 10^24"}]	[{"type":"physical unit","value":"Mass [OF] C3H7OH sample [=] \\pu{85.9 g}"}]	<h1 class="questionTitle" itemprop="name">C3H7OH is propanol. Suppose you have 85.9 g sample of propanol. How many carbon atoms are in the sample?</h1>	null	2.58 × 10^24	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The molecular formula of propanol is <mathjax>#C_3 H_8 O#</mathjax>.<br/> First, we should calculate its molecular mass. I prefer to work with rounded numbers because that's how I was taught and frankly it makes life much easier. You should have memorised that the molar masses of carbon, hydrogen and oxygen are, respectively, <mathjax>#12g/(mol)#</mathjax>, <mathjax>#1g/(mol)#</mathjax> and <mathjax>#16g/(mol)#</mathjax>.<br/> So let's add all that up:</p> <blockquote> <p><mathjax>#M = (312)+(81)+(116)#</mathjax><br/> <mathjax>#M = 60g/(mol)#</mathjax></p> </blockquote> <p>Okay, but that doesn't tell us much by itself. <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">Elements</a> make up substances in different proportions, because they have different masses, so how much of propanol is actually carbon, in terms of percentage? Remember, <mathjax>#36g#</mathjax> of that is carbon:</p> <blockquote> <p><mathjax>#{:(60g -> 100%), (36g -> x%) :}} implies x = 60%#</mathjax></p> </blockquote> <p>So now we know that any given sample of propanol is sixty percent carbon. Now we can use the information that we were given: <mathjax>#85.9g#</mathjax>. If that's the total mass of propanol, sixty percent of that must be carbon:</p> <blockquote> <p><mathjax>#{: (85.9g -> 100%), (ycolor(white)(x)g -> 60%) :}} implies y = 51.54g#</mathjax></p> </blockquote> <p>Now, let us return to the concept of a mole. A mole is a quantity of <mathjax>#610^23#</mathjax> of something. You might be used to using a more accurate value, but for now let us use that simplified number. Molar mass is the mass of a mole of something; so <mathjax>#610^23#</mathjax> atoms of carbon have a total mass of <mathjax>#12g#</mathjax>. With that in mind, we can now work out how many atoms of carbon have a total mass of <mathjax>#51.54g#</mathjax>:</p> <p><mathjax>#{:(610^23 "atoms" -> 12g), (zcolor(white)(x) "atoms" -> 51.54g) :}} implies z = 2.58*10^24 "atoms"#</mathjax></p> <p>My answer might be different from somebody else's because, as I said, I prefer to work with simpler values. I hope, however, that the logic is clear! Cheers.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>I got: <mathjax>#2.58 * 10^24#</mathjax> carbon atoms.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The molecular formula of propanol is <mathjax>#C_3 H_8 O#</mathjax>.<br/> First, we should calculate its molecular mass. I prefer to work with rounded numbers because that's how I was taught and frankly it makes life much easier. You should have memorised that the molar masses of carbon, hydrogen and oxygen are, respectively, <mathjax>#12g/(mol)#</mathjax>, <mathjax>#1g/(mol)#</mathjax> and <mathjax>#16g/(mol)#</mathjax>.<br/> So let's add all that up:</p> <blockquote> <p><mathjax>#M = (312)+(81)+(116)#</mathjax><br/> <mathjax>#M = 60g/(mol)#</mathjax></p> </blockquote> <p>Okay, but that doesn't tell us much by itself. <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">Elements</a> make up substances in different proportions, because they have different masses, so how much of propanol is actually carbon, in terms of percentage? Remember, <mathjax>#36g#</mathjax> of that is carbon:</p> <blockquote> <p><mathjax>#{:(60g -> 100%), (36g -> x%) :}} implies x = 60%#</mathjax></p> </blockquote> <p>So now we know that any given sample of propanol is sixty percent carbon. Now we can use the information that we were given: <mathjax>#85.9g#</mathjax>. If that's the total mass of propanol, sixty percent of that must be carbon:</p> <blockquote> <p><mathjax>#{: (85.9g -> 100%), (ycolor(white)(x)g -> 60%) :}} implies y = 51.54g#</mathjax></p> </blockquote> <p>Now, let us return to the concept of a mole. A mole is a quantity of <mathjax>#610^23#</mathjax> of something. You might be used to using a more accurate value, but for now let us use that simplified number. Molar mass is the mass of a mole of something; so <mathjax>#610^23#</mathjax> atoms of carbon have a total mass of <mathjax>#12g#</mathjax>. With that in mind, we can now work out how many atoms of carbon have a total mass of <mathjax>#51.54g#</mathjax>:</p> <p><mathjax>#{:(610^23 "atoms" -> 12g), (zcolor(white)(x) "atoms" -> 51.54g) :}} implies z = 2.58*10^24 "atoms"#</mathjax></p> <p>My answer might be different from somebody else's because, as I said, I prefer to work with simpler values. I hope, however, that the logic is clear! Cheers.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">C3H7OH is propanol. Suppose you have 85.9 g sample of propanol. How many carbon atoms are in the sample?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="176597" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/marilia-e"><img alt="" class="" src="https://profilepictures.socratic.org/he1v8fg3TWOXSgMYYiGS_CdgDRhtWwAA2YvD.jpg" title=""/></a> <a class="secondContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/marilia-e"> Marilia E.K. </a>·<a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-10-14T09:17:09" itemprop="dateCreated"> Oct 14, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>I got: <mathjax>#2.58 * 10^24#</mathjax> carbon atoms.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The molecular formula of propanol is <mathjax>#C_3 H_8 O#</mathjax>.<br/> First, we should calculate its molecular mass. I prefer to work with rounded numbers because that's how I was taught and frankly it makes life much easier. You should have memorised that the molar masses of carbon, hydrogen and oxygen are, respectively, <mathjax>#12g/(mol)#</mathjax>, <mathjax>#1g/(mol)#</mathjax> and <mathjax>#16g/(mol)#</mathjax>.<br/> So let's add all that up:</p> <blockquote> <p><mathjax>#M = (312)+(81)+(116)#</mathjax><br/> <mathjax>#M = 60g/(mol)#</mathjax></p> </blockquote> <p>Okay, but that doesn't tell us much by itself. <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">Elements</a> make up substances in different proportions, because they have different masses, so how much of propanol is actually carbon, in terms of percentage? Remember, <mathjax>#36g#</mathjax> of that is carbon:</p> <blockquote> <p><mathjax>#{:(60g -> 100%), (36g -> x%) :}} implies x = 60%#</mathjax></p> </blockquote> <p>So now we know that any given sample of propanol is sixty percent carbon. Now we can use the information that we were given: <mathjax>#85.9g#</mathjax>. If that's the total mass of propanol, sixty percent of that must be carbon:</p> <blockquote> <p><mathjax>#{: (85.9g -> 100%), (ycolor(white)(x)g -> 60%) :}} implies y = 51.54g#</mathjax></p> </blockquote> <p>Now, let us return to the concept of a mole. A mole is a quantity of <mathjax>#610^23#</mathjax> of something. You might be used to using a more accurate value, but for now let us use that simplified number. Molar mass is the mass of a mole of something; so <mathjax>#610^23#</mathjax> atoms of carbon have a total mass of <mathjax>#12g#</mathjax>. With that in mind, we can now work out how many atoms of carbon have a total mass of <mathjax>#51.54g#</mathjax>:</p> <p><mathjax>#{:(610^23 "atoms" -> 12g), (zcolor(white)(x) "atoms" -> 51.54g) :}} implies z = 2.58*10^24 "atoms"#</mathjax></p> <p>My answer might be different from somebody else's because, as I said, I prefer to work with simpler values. I hope, however, that the logic is clear! Cheers.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/176597" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="176611" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-10-14T10:26:30" itemprop="dateCreated"> Oct 14, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The number of carbon atoms in an 85.9 g sample of propanol is <mathjax>#2.58xx10^24"atoms C"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Propanol: <mathjax>#"C"_3"H"_7"OH"#</mathjax><mathjax>#=#</mathjax><mathjax>#"C"_3"H"_8"O"#</mathjax> </p> <p>The molar masses of carbon, hydrogen, and oxygen are:<br/> <mathjax>#"C"="12.0107 g/mol"#</mathjax><br/> <mathjax>#"H"="1.00794 g/mol"#</mathjax><br/> <mathjax>#"O"="15.999 g/mol"#</mathjax></p> <p><mathjax>#"Molar mass of propanol"=(3xx12.0107)+(8xx1.00794)+(1xx15.999)="60.095 g/mol"#</mathjax>. </p> <p><strong>Identify the Molar Masses of Propanol and Carbon</strong></p> <p>Molar mass of propanol: <mathjax>#"60.095 g/mol"#</mathjax><br/> Molar mass of carbon: <mathjax>#(3xx12.0107)="36.032 g/mol"#</mathjax></p> <p><strong>Determine the Percentage of Carbon</strong></p> <p><mathjax>#"Percentage of C in propanol"=("molar mass of C")/("molar mass of propanol")xx100=(36.032"g/mol C")/(60.095"g/mol propanol")xx100="59.958% C"#</mathjax></p> <p><strong>Determine the Mass of Carbon in 85.9 g of Propanol</strong></p> <p>In order to determine the mass of carbon present in 85.9 g propanol, we need to multiply the mass of propanol times the percentage of carbon as a decimal (e.g. <mathjax>#(25%)/(100)=0.25#</mathjax>).</p> <p><mathjax>#"85.9 g propanol"xx(0.59958 "C")="51.504 g C"#</mathjax></p> <p>There are <mathjax>#"51.504 g C"#</mathjax> in <mathjax>#"85.9 g propanol"#</mathjax></p> <p><strong>Determining the Number of Carbon Atoms</strong> </p> <p>Use the mass of carbon in the compound and carbon's molar mass to convert to moles of carbon. Then multiply the moles of carbon times <mathjax>#6.022xx10^23 "atoms/mol"#</mathjax>.</p> <p><mathjax>#51.504cancel"g C"xx(1cancel"mol C")/(12.0107cancel"g C")xx(6.022xx10^23"atoms C")/(1cancel"mol C")=2.58xx10^24"atoms C"#</mathjax> rounded to three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/176611" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 26268 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	C3H7OH is propanol. Suppose you have 85.9 g sample of propanol. How many carbon atoms are in the sample?	null
994	ab1bec4a-6ddd-11ea-b05f-ccda262736ce	https://socratic.org/questions/how-do-you-use-the-henderson-hasselbalch-to-calculate-the-ph-of-a-buffer-solutio	9.65	start physical_unit 12 13 ph none qc_end c_other Henderson-Hasselbalch qc_end physical_unit 19 19 16 17 molarity qc_end physical_unit 24 24 21 22 molarity qc_end physical_unit 26 26 29 29 pkb qc_end end	[{"type":"physical unit","value":"pH [OF] the buffer solution"}]	[{"type":"physical unit","value":"9.65"}]	[{"type":"other","value":"Henderson-Hasselbalch"},{"type":"physical unit","value":"Molarity [OF] NH3 solution [=] \\pu{0.50 M}"},{"type":"physical unit","value":"Molarity [OF] NH4Cl solution [=] \\pu{0.20 M}"},{"type":"physical unit","value":"pKb [OF] ammonia [=] \\pu{4.75}"}]	<h1 class="questionTitle" itemprop="name">How do you use the Henderson-Hasselbalch to calculate the pH of a buffer solution that is .50 M in #NH_3# and . 20 M in #NH_4Cl#?</h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>For ammonia, <mathjax>#pK_b=4.75#</mathjax>.</p></div> </h2> </div> </div>	9.65	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Before I introduce Henderson-Hasselbalch's equation, we should identify the acid and base. <strong>Ammonia <mathjax>#(NH_3)#</mathjax> is always a base</strong> and the <strong>ammonium ion <mathjax>#(NH_4^(+))#</mathjax> is the conjugate acid of ammonia.</strong> A conjugate acid has one more proton <mathjax>#(H^+)#</mathjax>than the base you started with.</p> <p>Now, we can use this equation:<br/> <img alt="www.chemteam.info" src="https://useruploads.socratic.org/voZKqTbLQTSan1ihzJEn_HH-equation3.gif"/> </p> <p>As you can see, we are given a pKb instead of a pKa. But, no worries we can use the following equation that relates both constants to each other:</p> <p><mathjax>#color(white)(aaaaaaaaaaaaaaaaaaa)#</mathjax><strong>pKa + pKb = 14</strong></p> <p>We can solve for the pKa by subtracting the given pKb from 14: </p> <p><mathjax>#14 - 4.75 = 9.25#</mathjax></p> <p>Thus, <strong>your pKa is 9.25</strong></p> <p>Next, we can obtain the [base] and [acid] from the question.</p> <p><strong>[<mathjax>#NH_3#</mathjax>]= .50 M [<mathjax>#NH_4#</mathjax>] =.20 M</strong></p> <p>We're not really concerned with the chloride anion that attached to the ammonium ion because it's a spectator ion and it has no effect on the buffer system. </p> <p>Now, we have all of the information to determine the pH. Let's plug our values into the equation:</p> <p><mathjax>#pH = 9.25 + log( [0.50]/[0.20])#</mathjax></p> <p><mathjax>#pH = 9.65#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>That buffer solution has a <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> of <mathjax>#9.65#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Before I introduce Henderson-Hasselbalch's equation, we should identify the acid and base. <strong>Ammonia <mathjax>#(NH_3)#</mathjax> is always a base</strong> and the <strong>ammonium ion <mathjax>#(NH_4^(+))#</mathjax> is the conjugate acid of ammonia.</strong> A conjugate acid has one more proton <mathjax>#(H^+)#</mathjax>than the base you started with.</p> <p>Now, we can use this equation:<br/> <img alt="www.chemteam.info" src="https://useruploads.socratic.org/voZKqTbLQTSan1ihzJEn_HH-equation3.gif"/> </p> <p>As you can see, we are given a pKb instead of a pKa. But, no worries we can use the following equation that relates both constants to each other:</p> <p><mathjax>#color(white)(aaaaaaaaaaaaaaaaaaa)#</mathjax><strong>pKa + pKb = 14</strong></p> <p>We can solve for the pKa by subtracting the given pKb from 14: </p> <p><mathjax>#14 - 4.75 = 9.25#</mathjax></p> <p>Thus, <strong>your pKa is 9.25</strong></p> <p>Next, we can obtain the [base] and [acid] from the question.</p> <p><strong>[<mathjax>#NH_3#</mathjax>]= .50 M [<mathjax>#NH_4#</mathjax>] =.20 M</strong></p> <p>We're not really concerned with the chloride anion that attached to the ammonium ion because it's a spectator ion and it has no effect on the buffer system. </p> <p>Now, we have all of the information to determine the pH. Let's plug our values into the equation:</p> <p><mathjax>#pH = 9.25 + log( [0.50]/[0.20])#</mathjax></p> <p><mathjax>#pH = 9.65#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you use the Henderson-Hasselbalch to calculate the pH of a buffer solution that is .50 M in #NH_3# and . 20 M in #NH_4Cl#?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>For ammonia, <mathjax>#pK_b=4.75#</mathjax>.</p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/ph-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">pH calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="295258" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/kayla-14"><img alt="" class="" src="https://profilepictures.socratic.org/OvMTWaamQPWcqLIkUNnG_793604964071127.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/kayla-14"> Kayla </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-08-04T02:52:41" itemprop="dateCreated"> Aug 4, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>That buffer solution has a <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> of <mathjax>#9.65#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Before I introduce Henderson-Hasselbalch's equation, we should identify the acid and base. <strong>Ammonia <mathjax>#(NH_3)#</mathjax> is always a base</strong> and the <strong>ammonium ion <mathjax>#(NH_4^(+))#</mathjax> is the conjugate acid of ammonia.</strong> A conjugate acid has one more proton <mathjax>#(H^+)#</mathjax>than the base you started with.</p> <p>Now, we can use this equation:<br/> <img alt="www.chemteam.info" src="https://useruploads.socratic.org/voZKqTbLQTSan1ihzJEn_HH-equation3.gif"/> </p> <p>As you can see, we are given a pKb instead of a pKa. But, no worries we can use the following equation that relates both constants to each other:</p> <p><mathjax>#color(white)(aaaaaaaaaaaaaaaaaaa)#</mathjax><strong>pKa + pKb = 14</strong></p> <p>We can solve for the pKa by subtracting the given pKb from 14: </p> <p><mathjax>#14 - 4.75 = 9.25#</mathjax></p> <p>Thus, <strong>your pKa is 9.25</strong></p> <p>Next, we can obtain the [base] and [acid] from the question.</p> <p><strong>[<mathjax>#NH_3#</mathjax>]= .50 M [<mathjax>#NH_4#</mathjax>] =.20 M</strong></p> <p>We're not really concerned with the chloride anion that attached to the ammonium ion because it's a spectator ion and it has no effect on the buffer system. </p> <p>Now, we have all of the information to determine the pH. Let's plug our values into the equation:</p> <p><mathjax>#pH = 9.25 + log( [0.50]/[0.20])#</mathjax></p> <p><mathjax>#pH = 9.65#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/295258" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-of-a-solution"> How do you determine ph of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-at-an-equivalence-point"> How do you determine pH at an equivalence point? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-molarity"> How do you determine pH from molarity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-alkalinity-mean"> What does alkalinity mean? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-base"> What is a base? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-acid-base-indicators-change-color"> How do acid base indicators change color? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-neutral-ph"> What is a neutral pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-alkalinity-affect-pool-water"> How does alkalinity affect pool water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ph-important-in-drinking-water"> Why is pH important in drinking water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-ph-of-solution"> How can I calculate the pH of a solution? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/ph-calculations"> See all questions in pH calculations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 29768 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How do you use the Henderson-Hasselbalch to calculate the pH of a buffer solution that is .50 M in #NH_3# and . 20 M in #NH_4Cl#?	For ammonia, #pK_b=4.75#.
995	aa31ff10-6ddd-11ea-99c7-ccda262736ce	https://socratic.org/questions/how-many-particles-are-in-6-84-grams-of-li-2co-3	5.57 × 10^22	start physical_unit 2 2 number none qc_end physical_unit 8 8 5 6 mass qc_end physical_unit 8 8 11 12 molar_mass qc_end end	[{"type":"physical unit","value":"Number [OF] particles"}]	[{"type":"physical unit","value":"5.57 × 10^22"}]	[{"type":"physical unit","value":"Mass [OF] Li2CO3 [=] \\pu{6.84 grams}"},{"type":"physical unit","value":"Molecular [OF] Li2CO3 [=] \\pu{73.890 g/mol}"}]	<h1 class="questionTitle" itemprop="name">How many particles are in 6.84 grams of #Li_2Co_3#?</h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>It is 73.890 g/mol.</p></div> </h2> </div> </div>	5.57 × 10^22	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And thus this molar quantity represents <mathjax>#2xx9.26xx10^-2mol#</mathjax> of <mathjax>#"lithium atoms"#</mathjax>, <mathjax>#9.26xx10^-2mol#</mathjax> of <mathjax>#"carbon atoms"#</mathjax>, and <mathjax>#3xx9.26xx10^-2mol#</mathjax> of <mathjax>#"oxygen atoms"#</mathjax>.</p> <p>To get the molar quantity of <mathjax>#"lithium carbonate"#</mathjax> I simply took the quotient, <mathjax>#"mass"/"molar mass"#</mathjax>, i.e. <mathjax>#(6.84g)/(73.89gmol^-1)=??*mol#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#6.84g#</mathjax> represents <mathjax>#9.26xx10^-2mol#</mathjax> of <mathjax>#"lithium carbonate"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And thus this molar quantity represents <mathjax>#2xx9.26xx10^-2mol#</mathjax> of <mathjax>#"lithium atoms"#</mathjax>, <mathjax>#9.26xx10^-2mol#</mathjax> of <mathjax>#"carbon atoms"#</mathjax>, and <mathjax>#3xx9.26xx10^-2mol#</mathjax> of <mathjax>#"oxygen atoms"#</mathjax>.</p> <p>To get the molar quantity of <mathjax>#"lithium carbonate"#</mathjax> I simply took the quotient, <mathjax>#"mass"/"molar mass"#</mathjax>, i.e. <mathjax>#(6.84g)/(73.89gmol^-1)=??*mol#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many particles are in 6.84 grams of #Li_2Co_3#?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>It is 73.890 g/mol.</p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="343878" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-11-29T16:43:46" itemprop="dateCreated"> Nov 29, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#6.84g#</mathjax> represents <mathjax>#9.26xx10^-2mol#</mathjax> of <mathjax>#"lithium carbonate"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And thus this molar quantity represents <mathjax>#2xx9.26xx10^-2mol#</mathjax> of <mathjax>#"lithium atoms"#</mathjax>, <mathjax>#9.26xx10^-2mol#</mathjax> of <mathjax>#"carbon atoms"#</mathjax>, and <mathjax>#3xx9.26xx10^-2mol#</mathjax> of <mathjax>#"oxygen atoms"#</mathjax>.</p> <p>To get the molar quantity of <mathjax>#"lithium carbonate"#</mathjax> I simply took the quotient, <mathjax>#"mass"/"molar mass"#</mathjax>, i.e. <mathjax>#(6.84g)/(73.89gmol^-1)=??*mol#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/343878" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1630 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many particles are in 6.84 grams of #Li_2Co_3#?	It is 73.890 g/mol.
996	ad07ef0a-6ddd-11ea-93fe-ccda262736ce	https://socratic.org/questions/56afb21b11ef6b589ee3b3bf	44.8 mL	start physical_unit 9 9 volume ml qc_end physical_unit 9 9 5 6 mole qc_end c_other STP qc_end end	[{"type":"physical unit","value":"Volume [OF] O2 [IN] mL"}]	[{"type":"physical unit","value":"44.8 mL"}]	[{"type":"physical unit","value":"Mole [OF] O2 [=] \\pu{2 mol}"},{"type":"other","value":"STP"}]	<h1 class="questionTitle" itemprop="name">What is the volume of #2# #mol# of oxygen, #O_2#, at STP?</h1>	null	44.8 mL	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>If we assume standard laboratory conditions, <mathjax>#25#</mathjax> <mathjax>#""^@C#</mathjax> and <mathjax>#1#</mathjax> <mathjax>#atm#</mathjax> (or thereabouts; the standard is slightly different now!), <mathjax>#2L#</mathjax> dioxygen gas represents, <mathjax>#(2L)/(25.4Lmol^-1)#</mathjax> <mathjax>#""approx 1/12*mol #</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>You need to specify (i) a pressure, and (ii) a temperature, before the molar quantity can be calculated.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>If we assume standard laboratory conditions, <mathjax>#25#</mathjax> <mathjax>#""^@C#</mathjax> and <mathjax>#1#</mathjax> <mathjax>#atm#</mathjax> (or thereabouts; the standard is slightly different now!), <mathjax>#2L#</mathjax> dioxygen gas represents, <mathjax>#(2L)/(25.4Lmol^-1)#</mathjax> <mathjax>#""approx 1/12*mol #</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the volume of #2# #mol# of oxygen, #O_2#, at STP?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp" itemprop="url"> <span class="breadcrumb" itemprop="title">Molar Volume of a Gas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="233164" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-02-29T21:43:55" itemprop="dateCreated"> Feb 29, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>You need to specify (i) a pressure, and (ii) a temperature, before the molar quantity can be calculated.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>If we assume standard laboratory conditions, <mathjax>#25#</mathjax> <mathjax>#""^@C#</mathjax> and <mathjax>#1#</mathjax> <mathjax>#atm#</mathjax> (or thereabouts; the standard is slightly different now!), <mathjax>#2L#</mathjax> dioxygen gas represents, <mathjax>#(2L)/(25.4Lmol^-1)#</mathjax> <mathjax>#""approx 1/12*mol #</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/233164" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="233171" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/david-g-6"><img alt="" class="" src="https://graph.facebook.com/10153408096237887/picture?height=50&width=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/david-g-6"> David G. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-02-29T21:59:20" itemprop="dateCreated"> Feb 29, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Assuming that the gas is at standard temperature and pressure (STP), one mole of any gas occupies <mathjax>#22.4#</mathjax> <mathjax>#L#</mathjax>. This means the number of moles of <mathjax>#O_2#</mathjax> is <mathjax>#2/22.4=0.089#</mathjax> <mathjax>#mol#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a> makes certain assumptions about the gases: that the particles are very tiny and featureless and that there is no force acting between them. If these assumptions are correct, then one mole of any gas will occupy <mathjax>#22.4#</mathjax> <mathjax>#L#</mathjax> at STP.</p> <p>The assumptions are not quite the case for <mathjax>#O_2#</mathjax>, but the deviations from it are small enough that we can still use this approach and receive an accurate answer.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/233171" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-stoichiometric-ratios-relate-to-molar-volume-of-a-gas"> How do stoichiometric ratios relate to molar volume of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-a-gas-at-stp"> How do you calculate molar volume of a gas at STP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-molar-volume-of-hydrogen-gas"> How do you find the molar volume of hydrogen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-oxygen-gas"> How do you calculate molar volume of oxygen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molar-gas-volume"> What is molar gas volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/534c7bf202bf3420a007f014"> What is the volume at 0 °C and 1 atm of a mixture that contains 4.0 g of methane and 2.0 g of helium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5361f75702bf3429040e0599"> What is the difference between STP and NTP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-volume-of-25-moles-of-oxygen-o2-gas"> What is the volume of .25 moles of oxygen (O2) Gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-would-knowing-the-molar-volume-of-a-gas-be-important"> Why would knowing the molar volume of a gas be important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-22-4-liters-called-the-molar-volume-of-a-gas"> Why is 22.4 liters called the molar volume of a gas? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp"> See all questions in Molar Volume of a Gas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 31557 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the volume of #2# #mol# of oxygen, #O_2#, at STP?	null
997	ab12a662-6ddd-11ea-b0ce-ccda262736ce	https://socratic.org/questions/a-10-0-ml-sample-of-h-2so-4-solution-from-an-automobile-battery-requires-32-75-m	1.64 M	start physical_unit 3 6 molarity mol/l qc_end physical_unit 3 6 1 2 volume qc_end physical_unit 17 17 12 13 molarity qc_end physical_unit 6 6 15 16 volume qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Molarity [OF] H2SO4 solution sample [IN] M"}]	[{"type":"physical unit","value":"1.64 M"}]	[{"type":"physical unit","value":"Volume [OF] H2SO4 solution sample [=] \\pu{10.0 mL}"},{"type":"physical unit","value":"Molarity [OF] NaOH solution [=] \\pu{32.75 mL}"},{"type":"physical unit","value":"Volume [OF] NaOH solution [=] \\pu{1 M}"},{"type":"other","value":"Complete reaction."}]	<h1 class="questionTitle" itemprop="name">A 10.0 mL sample of #H_2SO_4# solution from an automobile battery requires 32.75 mL of M NaOH for a complete reaction. What is the molarity of the #H_2SO_4# solution?</h1>	null	1.64 M	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Since both <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> are a strong acid/base, no <mathjax>#K_a//K_b#</mathjax> calculations are required. In a reaction between sulfuric acid and sodium hydroxide, two mols of base are required to fully neutralize one mol of acid.</p> <p>Also, for the purposes of this question, I will assume that the molarity of <mathjax>#NaOH_{(aq)}=1.0\ mols#</mathjax>, since this information was accidentaly skipped in the question. (Or defaults to 1.0 mols/L anyways, as Michael suggested)</p> <p>Step 1) Write the equation.</p> <p><mathjax>#mols\ H_2SO_{4(aq)} * 2= mols\ NaOH_{(aq)}#</mathjax></p> <p><mathjax>#10.0\ mL * {1\ L}/{1000\ mL} * {2\ mols\ NaOH_{(aq)}}/{1\ mol\ H_2SO_{4(aq)}} * x = 32.75\ mL * {1\ L}/{1000\ mL}1.0\ {mols}/{L}#</mathjax></p> <p><mathjax>#0.010\ L {2\ mols\ NaOH_{(aq)}}/{1\ mol\ H_2SO_{4(aq)}} * x = 0.03275\ L * 1.0\ {mols}/{L}#</mathjax></p> <p>Step 2) Isolate the variable being solved for. (<mathjax>#x#</mathjax>)</p> <p><mathjax>#x={0.03275\ L}/{0.010\ L} * {1\ mol\ H_2SO_{4(aq)}}/{2\ mols\ NaOH_{(aq)}} * 1.0\ {mols}/{L}#</mathjax></p> <p>After that, solve, and you have your answer of <mathjax>#1.6375\ {mols}/{L}#</mathjax>, or properly rounded, <mathjax>#1.64\ {mols}/{L}#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1.64\ {mols}/{L}#</mathjax>, assuming that the molarity of <mathjax>#NaOH_{(aq)}#</mathjax> is <mathjax>#1.0\ {mols}/{L}#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Since both <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> are a strong acid/base, no <mathjax>#K_a//K_b#</mathjax> calculations are required. In a reaction between sulfuric acid and sodium hydroxide, two mols of base are required to fully neutralize one mol of acid.</p> <p>Also, for the purposes of this question, I will assume that the molarity of <mathjax>#NaOH_{(aq)}=1.0\ mols#</mathjax>, since this information was accidentaly skipped in the question. (Or defaults to 1.0 mols/L anyways, as Michael suggested)</p> <p>Step 1) Write the equation.</p> <p><mathjax>#mols\ H_2SO_{4(aq)} * 2= mols\ NaOH_{(aq)}#</mathjax></p> <p><mathjax>#10.0\ mL * {1\ L}/{1000\ mL} * {2\ mols\ NaOH_{(aq)}}/{1\ mol\ H_2SO_{4(aq)}} * x = 32.75\ mL * {1\ L}/{1000\ mL}1.0\ {mols}/{L}#</mathjax></p> <p><mathjax>#0.010\ L {2\ mols\ NaOH_{(aq)}}/{1\ mol\ H_2SO_{4(aq)}} * x = 0.03275\ L * 1.0\ {mols}/{L}#</mathjax></p> <p>Step 2) Isolate the variable being solved for. (<mathjax>#x#</mathjax>)</p> <p><mathjax>#x={0.03275\ L}/{0.010\ L} * {1\ mol\ H_2SO_{4(aq)}}/{2\ mols\ NaOH_{(aq)}} * 1.0\ {mols}/{L}#</mathjax></p> <p>After that, solve, and you have your answer of <mathjax>#1.6375\ {mols}/{L}#</mathjax>, or properly rounded, <mathjax>#1.64\ {mols}/{L}#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A 10.0 mL sample of #H_2SO_4# solution from an automobile battery requires 32.75 mL of M NaOH for a complete reaction. What is the molarity of the #H_2SO_4# solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#reactions-in-solution" itemprop="url"> <span class="breadcrumb" itemprop="title">Reactions in Solution</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/reactions-in-solution/titration-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">Titration Calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="277829" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/mathmints"><img alt="" class="" src="https://profilepictures.socratic.org/TZ99d4wfTiWzCaTWeYky_Splash.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/mathmints"> MathMints </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-15T23:34:42" itemprop="dateCreated"> Jun 15, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1.64\ {mols}/{L}#</mathjax>, assuming that the molarity of <mathjax>#NaOH_{(aq)}#</mathjax> is <mathjax>#1.0\ {mols}/{L}#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Since both <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> are a strong acid/base, no <mathjax>#K_a//K_b#</mathjax> calculations are required. In a reaction between sulfuric acid and sodium hydroxide, two mols of base are required to fully neutralize one mol of acid.</p> <p>Also, for the purposes of this question, I will assume that the molarity of <mathjax>#NaOH_{(aq)}=1.0\ mols#</mathjax>, since this information was accidentaly skipped in the question. (Or defaults to 1.0 mols/L anyways, as Michael suggested)</p> <p>Step 1) Write the equation.</p> <p><mathjax>#mols\ H_2SO_{4(aq)} * 2= mols\ NaOH_{(aq)}#</mathjax></p> <p><mathjax>#10.0\ mL * {1\ L}/{1000\ mL} * {2\ mols\ NaOH_{(aq)}}/{1\ mol\ H_2SO_{4(aq)}} * x = 32.75\ mL * {1\ L}/{1000\ mL}1.0\ {mols}/{L}#</mathjax></p> <p><mathjax>#0.010\ L {2\ mols\ NaOH_{(aq)}}/{1\ mol\ H_2SO_{4(aq)}} * x = 0.03275\ L * 1.0\ {mols}/{L}#</mathjax></p> <p>Step 2) Isolate the variable being solved for. (<mathjax>#x#</mathjax>)</p> <p><mathjax>#x={0.03275\ L}/{0.010\ L} * {1\ mol\ H_2SO_{4(aq)}}/{2\ mols\ NaOH_{(aq)}} * 1.0\ {mols}/{L}#</mathjax></p> <p>After that, solve, and you have your answer of <mathjax>#1.6375\ {mols}/{L}#</mathjax>, or properly rounded, <mathjax>#1.64\ {mols}/{L}#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/277829" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="296316" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-08-07T02:41:20" itemprop="dateCreated"> Aug 7, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of the <mathjax>#"H"_2"SO"_4#</mathjax> is 1.64 mol/L.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>Step 1.</strong> Write the balanced chemical equation for the reaction</p> <p><mathjax>#"H"_2"SO"_4 + "2NaOH" → "Na"_2"SO"_4 + "2H"_2"O"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 2.</strong> Calculate the moles of <mathjax>#"NaOH"#</mathjax></p> <p>I assume that the molarity of the <mathjax>#"NaOH"#</mathjax> is 1.00 mol/L.</p> <p><mathjax>#"Moles of NaOH" = "0.032 75" color(red)(cancel(color(black)("L NaOH"))) × "1.00 mol NaOH"/(1 color(red)(cancel(color(black)("L NaOH")))) = "0.032 75 mol NaOH"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 3.</strong> Calculate the moles of <mathjax>#"H"_2"SO"_4#</mathjax>.</p> <p><mathjax>#"Moles of H"_2"SO"_4 = "0.032 75" color(red)(cancel(color(black)("mol NaOH"))) × ("1 mol H"_2"SO"_4)/(2 color(red)(cancel(color(black)("mol NaOH")))) = "0.016 375 mol H"_2"SO"_4#</mathjax></p> <blockquote></blockquote> <p><strong>Step 4.</strong> Calculate the molarity of the <mathjax>#"H"_2"SO"_4#</mathjax></p> <p><mathjax>#"Molarity" = "moles"/"litres" = "0.016 375 mol"/"0.0100 L" = "1.64 mol/L"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/296316" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-do-acid-base-titration-calculations"> How do you do acid base titration calculations? 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What is the molarity of the #H_2SO_4# solution?	null
998	aa6ad25c-6ddd-11ea-bbb8-ccda262736ce	https://socratic.org/questions/3a-chemical-reaction-produces-653-550-kj-of-energy-as-heat-in-142-3-min-what-is-	4592.76 kilojoules per minute	start physical_unit 2 2 energy_transfer_rate kj/min qc_end physical_unit 2 2 4 6 heat_energy qc_end physical_unit 2 2 12 13 time qc_end end	[{"type":"physical unit","value":"Rate of energy transfer [OF] the reaction [IN] kilojoules per minute"}]	[{"type":"physical unit","value":"4592.76 kilojoules per minute"}]	[{"type":"physical unit","value":"Produced energy [OF] the reaction [=] \\pu{653 550 kJ}"},{"type":"physical unit","value":"Time [OF] the reaction [=] \\pu{142.3 min}"}]	<h1 class="questionTitle" itemprop="name">3A chemical reaction produces 653 550 kJ of energy as heat in 142.3 min. What is the rate of energy transfer in kilojoules per minute.?</h1>	null	4592.76 kilojoules per minute	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Notice that the problem provides you with </p> <blockquote> <ul> <li><em>the <strong>total amount of energy</strong> released by the reaction</em></li> <li><em>the <strong>total time</strong> needed for this energy to be released</em></li> </ul> </blockquote> <p>Your goal here will be to use this information to find the <em>rate of energy transfer</em>, which is simply the amount of energy produced <strong>per minute</strong> by the reaction, assuming of course that the heat is released at a constant rate. </p> <p>Essentially, you must figure out how much heat is given off <strong>in one minute</strong> by using the fact that you know how much heat is being given off in <mathjax>#"142.3#</mathjax> <strong>minutes</strong>. </p> <p>Use the information given to you by the problem as a <em>conversion factor</em> to find</p> <blockquote> <p><mathjax>#1 color(red)(cancel(color(black)("minute"))) * "653,550 kJ"/(142.3 color(red)(cancel(color(black)("min")))) = "4592.76 kJ"#</mathjax></p> </blockquote> <p>Now, because this is how much heat is given off in <mathjax>#1#</mathjax> <strong>minute</strong>, you can say that the rate of energy transfer is </p> <blockquote> <p><mathjax>#"rate of energy transfer" = color(green)(\|bar(ul(color(white)(a/a)color(black)("4593 kJ min"^(-1))color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer is rounded to four <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the total time of the reaction. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"4593 kJ min"^(-1)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Notice that the problem provides you with </p> <blockquote> <ul> <li><em>the <strong>total amount of energy</strong> released by the reaction</em></li> <li><em>the <strong>total time</strong> needed for this energy to be released</em></li> </ul> </blockquote> <p>Your goal here will be to use this information to find the <em>rate of energy transfer</em>, which is simply the amount of energy produced <strong>per minute</strong> by the reaction, assuming of course that the heat is released at a constant rate. </p> <p>Essentially, you must figure out how much heat is given off <strong>in one minute</strong> by using the fact that you know how much heat is being given off in <mathjax>#"142.3#</mathjax> <strong>minutes</strong>. </p> <p>Use the information given to you by the problem as a <em>conversion factor</em> to find</p> <blockquote> <p><mathjax>#1 color(red)(cancel(color(black)("minute"))) * "653,550 kJ"/(142.3 color(red)(cancel(color(black)("min")))) = "4592.76 kJ"#</mathjax></p> </blockquote> <p>Now, because this is how much heat is given off in <mathjax>#1#</mathjax> <strong>minute</strong>, you can say that the rate of energy transfer is </p> <blockquote> <p><mathjax>#"rate of energy transfer" = color(green)(\|bar(ul(color(white)(a/a)color(black)("4593 kJ min"^(-1))color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer is rounded to four <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the total time of the reaction. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">3A chemical reaction produces 653 550 kJ of energy as heat in 142.3 min. What is the rate of energy transfer in kilojoules per minute.?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/energy-change-in-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Energy Change in Reactions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="290640" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-22T00:59:55" itemprop="dateCreated"> Jul 22, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"4593 kJ min"^(-1)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Notice that the problem provides you with </p> <blockquote> <ul> <li><em>the <strong>total amount of energy</strong> released by the reaction</em></li> <li><em>the <strong>total time</strong> needed for this energy to be released</em></li> </ul> </blockquote> <p>Your goal here will be to use this information to find the <em>rate of energy transfer</em>, which is simply the amount of energy produced <strong>per minute</strong> by the reaction, assuming of course that the heat is released at a constant rate. </p> <p>Essentially, you must figure out how much heat is given off <strong>in one minute</strong> by using the fact that you know how much heat is being given off in <mathjax>#"142.3#</mathjax> <strong>minutes</strong>. </p> <p>Use the information given to you by the problem as a <em>conversion factor</em> to find</p> <blockquote> <p><mathjax>#1 color(red)(cancel(color(black)("minute"))) * "653,550 kJ"/(142.3 color(red)(cancel(color(black)("min")))) = "4592.76 kJ"#</mathjax></p> </blockquote> <p>Now, because this is how much heat is given off in <mathjax>#1#</mathjax> <strong>minute</strong>, you can say that the rate of energy transfer is </p> <blockquote> <p><mathjax>#"rate of energy transfer" = color(green)(\|bar(ul(color(white)(a/a)color(black)("4593 kJ min"^(-1))color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer is rounded to four <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the total time of the reaction. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/290640" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-endothermic-reactions-happen"> Why do endothermic reactions happen? 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What is the change in... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/energy-change-in-reactions"> See all questions in Energy Change in Reactions </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 4376 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	3A chemical reaction produces 653 550 kJ of energy as heat in 142.3 min. What is the rate of energy transfer in kilojoules per minute.?	null
999	a9cd71f6-6ddd-11ea-ac93-ccda262736ce	https://socratic.org/questions/a-gas-is-found-to-have-a-density-of-1-80-g-l-at-76-cm-of-hg-and-27-degree-c-the-	CO2	start chemical_formula qc_end physical_unit 17 18 9 10 density qc_end physical_unit 17 18 12 13 pressure qc_end physical_unit 17 18 15 16 temperature qc_end end	[{"type":"other","value":"Chemical Formula [OF] the gas [IN] default"}]	[{"type":"chemical equation","value":"CO2"}]	[{"type":"physical unit","value":"Density [OF] the gas [=] \\pu{1.80 g/L}"},{"type":"physical unit","value":"Pressure [OF] the gas [=] \\pu{76 mmHg}"},{"type":"physical unit","value":"Temperature [OF] the gas [=] \\pu{27 ℃}"}]	<h1 class="questionTitle" itemprop="name">A gas is found to have a density of #"1.80 g/L"# at #"76 cm Hg"# and #27^@ "C"#. The gas is?</h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>a)Oxygen b)Carbon Dioxide c)Ammonia d)Sulphur dioxide</p></div> </h2> </div> </div>	CO2	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that you need to figure out the <strong>molar mass</strong> of the gas by using its <a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a> under the given conditions for pressure and temperature. </p> <p>Your tool of choice will be the <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> equation</strong></p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)(PV = nRT)))#</mathjax></p> </blockquote> <p>Here</p> <blockquote> <ul> <li><mathjax>#P#</mathjax> is the pressure of the gas</li> <li><mathjax>#V#</mathjax> is the volume it occupies</li> <li><mathjax>#n#</mathjax> is the number of moles of gas present in the sample</li> <li><mathjax>#R#</mathjax> is the <em>universal gas constant</em>, equal to <mathjax>#0.0821("atm L")/("mol K")#</mathjax></li> <li><mathjax>#T#</mathjax> is the <strong>absolute temperature</strong> of the gas</li> </ul> </blockquote> <p>Start by converting the pressure of the gas to <em>atmospheres</em> and the temperature to <em>Kelvin</em>. You will have</p> <blockquote> <p><mathjax>#76 color(red)(cancel(color(black)("cmHg"))) * "1.0 atm"/(76 color(red)(cancel(color(black)("cmHg")))) = "1.0 atm"#</mathjax></p> </blockquote> <p>and</p> <blockquote> <p><mathjax>#T["K"] = 27^@"C" + 273.15 = "300.15 K"#</mathjax></p> </blockquote> <p>Now, you know that the density of the gas, <mathjax>#rho#</mathjax>, can be expressed by using the <strong>mass</strong> of the sample, let's say <mathjax>#m#</mathjax>, and the <strong>volume</strong> it occupies, <mathjax>#V#</mathjax></p> <blockquote> <p><mathjax>#color(blue)(rho = m / V)#</mathjax></p> </blockquote> <p>The number of moles of gas can be expressed by using the mass of the sample and the <strong>molar mass</strong> of the gas, let's say <mathjax>#M_M#</mathjax></p> <blockquote> <p><mathjax>#n = m/M_M#</mathjax></p> </blockquote> <p>Plug this into the ideal gas law equation to get</p> <blockquote> <p><mathjax>#PV = m/M_M * RT#</mathjax></p> </blockquote> <p>Rearrange to isolate the molar mass of the gas</p> <blockquote> <p><mathjax>#M_M = color(blue)(m/V) * (RT)/P#</mathjax></p> </blockquote> <p>This is equivalent to </p> <blockquote> <p><mathjax>#M_M = color(blue)(rho) * (RT)/P#</mathjax></p> </blockquote> <p>Plug in your values to find</p> <blockquote> <p><mathjax>#M_M = "1.80 g" color(red)(cancel(color(black)("L"^(-1)))) * (0.0821(color(red)(cancel(color(black)("atm"))) * color(red)(cancel(color(black)("L"))))/("mol" * color(red)(cancel(color(black)("K")))) * 300.15color(red)(cancel(color(black)("K"))) )/(1.0color(red)(cancel(color(black)("atm"))))#</mathjax></p> <p><mathjax>#M_M = "44 g mol"^(-1) ->#</mathjax> <em>rounded to <strong>two <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong></em></p> </blockquote> <p>The closest match is carbon dioxide, which has a molar mass of </p> <blockquote> <p><mathjax>#M_ ("M CO"_ 2) = "44.01 g mol"^(-1)#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>I'd go for <strong>(b)</strong> <mathjax>#"CO"_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that you need to figure out the <strong>molar mass</strong> of the gas by using its <a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a> under the given conditions for pressure and temperature. </p> <p>Your tool of choice will be the <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> equation</strong></p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)(PV = nRT)))#</mathjax></p> </blockquote> <p>Here</p> <blockquote> <ul> <li><mathjax>#P#</mathjax> is the pressure of the gas</li> <li><mathjax>#V#</mathjax> is the volume it occupies</li> <li><mathjax>#n#</mathjax> is the number of moles of gas present in the sample</li> <li><mathjax>#R#</mathjax> is the <em>universal gas constant</em>, equal to <mathjax>#0.0821("atm L")/("mol K")#</mathjax></li> <li><mathjax>#T#</mathjax> is the <strong>absolute temperature</strong> of the gas</li> </ul> </blockquote> <p>Start by converting the pressure of the gas to <em>atmospheres</em> and the temperature to <em>Kelvin</em>. You will have</p> <blockquote> <p><mathjax>#76 color(red)(cancel(color(black)("cmHg"))) * "1.0 atm"/(76 color(red)(cancel(color(black)("cmHg")))) = "1.0 atm"#</mathjax></p> </blockquote> <p>and</p> <blockquote> <p><mathjax>#T["K"] = 27^@"C" + 273.15 = "300.15 K"#</mathjax></p> </blockquote> <p>Now, you know that the density of the gas, <mathjax>#rho#</mathjax>, can be expressed by using the <strong>mass</strong> of the sample, let's say <mathjax>#m#</mathjax>, and the <strong>volume</strong> it occupies, <mathjax>#V#</mathjax></p> <blockquote> <p><mathjax>#color(blue)(rho = m / V)#</mathjax></p> </blockquote> <p>The number of moles of gas can be expressed by using the mass of the sample and the <strong>molar mass</strong> of the gas, let's say <mathjax>#M_M#</mathjax></p> <blockquote> <p><mathjax>#n = m/M_M#</mathjax></p> </blockquote> <p>Plug this into the ideal gas law equation to get</p> <blockquote> <p><mathjax>#PV = m/M_M * RT#</mathjax></p> </blockquote> <p>Rearrange to isolate the molar mass of the gas</p> <blockquote> <p><mathjax>#M_M = color(blue)(m/V) * (RT)/P#</mathjax></p> </blockquote> <p>This is equivalent to </p> <blockquote> <p><mathjax>#M_M = color(blue)(rho) * (RT)/P#</mathjax></p> </blockquote> <p>Plug in your values to find</p> <blockquote> <p><mathjax>#M_M = "1.80 g" color(red)(cancel(color(black)("L"^(-1)))) * (0.0821(color(red)(cancel(color(black)("atm"))) * color(red)(cancel(color(black)("L"))))/("mol" * color(red)(cancel(color(black)("K")))) * 300.15color(red)(cancel(color(black)("K"))) )/(1.0color(red)(cancel(color(black)("atm"))))#</mathjax></p> <p><mathjax>#M_M = "44 g mol"^(-1) ->#</mathjax> <em>rounded to <strong>two <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong></em></p> </blockquote> <p>The closest match is carbon dioxide, which has a molar mass of </p> <blockquote> <p><mathjax>#M_ ("M CO"_ 2) = "44.01 g mol"^(-1)#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A gas is found to have a density of #"1.80 g/L"# at #"76 cm Hg"# and #27^@ "C"#. The gas is?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>a)Oxygen b)Carbon Dioxide c)Ammonia d)Sulphur dioxide</p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/ideal-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Ideal Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="419963" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-09T00:03:30" itemprop="dateCreated"> May 9, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>I'd go for <strong>(b)</strong> <mathjax>#"CO"_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that you need to figure out the <strong>molar mass</strong> of the gas by using its <a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a> under the given conditions for pressure and temperature. </p> <p>Your tool of choice will be the <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> equation</strong></p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)(PV = nRT)))#</mathjax></p> </blockquote> <p>Here</p> <blockquote> <ul> <li><mathjax>#P#</mathjax> is the pressure of the gas</li> <li><mathjax>#V#</mathjax> is the volume it occupies</li> <li><mathjax>#n#</mathjax> is the number of moles of gas present in the sample</li> <li><mathjax>#R#</mathjax> is the <em>universal gas constant</em>, equal to <mathjax>#0.0821("atm L")/("mol K")#</mathjax></li> <li><mathjax>#T#</mathjax> is the <strong>absolute temperature</strong> of the gas</li> </ul> </blockquote> <p>Start by converting the pressure of the gas to <em>atmospheres</em> and the temperature to <em>Kelvin</em>. You will have</p> <blockquote> <p><mathjax>#76 color(red)(cancel(color(black)("cmHg"))) * "1.0 atm"/(76 color(red)(cancel(color(black)("cmHg")))) = "1.0 atm"#</mathjax></p> </blockquote> <p>and</p> <blockquote> <p><mathjax>#T["K"] = 27^@"C" + 273.15 = "300.15 K"#</mathjax></p> </blockquote> <p>Now, you know that the density of the gas, <mathjax>#rho#</mathjax>, can be expressed by using the <strong>mass</strong> of the sample, let's say <mathjax>#m#</mathjax>, and the <strong>volume</strong> it occupies, <mathjax>#V#</mathjax></p> <blockquote> <p><mathjax>#color(blue)(rho = m / V)#</mathjax></p> </blockquote> <p>The number of moles of gas can be expressed by using the mass of the sample and the <strong>molar mass</strong> of the gas, let's say <mathjax>#M_M#</mathjax></p> <blockquote> <p><mathjax>#n = m/M_M#</mathjax></p> </blockquote> <p>Plug this into the ideal gas law equation to get</p> <blockquote> <p><mathjax>#PV = m/M_M * RT#</mathjax></p> </blockquote> <p>Rearrange to isolate the molar mass of the gas</p> <blockquote> <p><mathjax>#M_M = color(blue)(m/V) * (RT)/P#</mathjax></p> </blockquote> <p>This is equivalent to </p> <blockquote> <p><mathjax>#M_M = color(blue)(rho) * (RT)/P#</mathjax></p> </blockquote> <p>Plug in your values to find</p> <blockquote> <p><mathjax>#M_M = "1.80 g" color(red)(cancel(color(black)("L"^(-1)))) * (0.0821(color(red)(cancel(color(black)("atm"))) * color(red)(cancel(color(black)("L"))))/("mol" * color(red)(cancel(color(black)("K")))) * 300.15color(red)(cancel(color(black)("K"))) )/(1.0color(red)(cancel(color(black)("atm"))))#</mathjax></p> <p><mathjax>#M_M = "44 g mol"^(-1) ->#</mathjax> <em>rounded to <strong>two <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong></em></p> </blockquote> <p>The closest match is carbon dioxide, which has a molar mass of </p> <blockquote> <p><mathjax>#M_ ("M CO"_ 2) = "44.01 g mol"^(-1)#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/419963" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-ideal-gas-constant"> How do you find the ideal gas constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-solve-ideal-gas-law-problems"> How do you solve ideal gas law problems? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-know-which-ideal-gas-constant-to-use"> How do you know which ideal gas constant to use? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ideal-gas-constant-for-butane"> What is the ideal gas constant for butane? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-ideal-gas-law-in-kelvin"> Why is ideal gas law in kelvin? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ideal-gas-constant-important"> Why is the ideal gas constant important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-di-electric-constant"> What is the di-electric constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-volume-l-will-0-20-mol-hi-occupy-at-300-k-and-100-0-kpa-r-8-314-kpa-l-k-mol"> What volume (L) will 0.20 mol HI occupy at 300 K and 100.0 kPa? 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The gas is?	a)Oxygen b)Carbon Dioxide c)Ammonia d)Sulphur dioxide

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