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700	aab623e2-6ddd-11ea-bff0-ccda262736ce	https://socratic.org/questions/1-mole-of-n-reacts-with-ca-to-form-ca3n2-how-many-moles-of-ca3n2-are-produced	1.00 moles	start physical_unit 9 9 mole mol qc_end physical_unit 3 3 0 1 mole qc_end chemical_equation 6 6 qc_end end	[{"type":"physical unit","value":"Mole [OF] Ca3N2 [IN] moles"}]	[{"type":"physical unit","value":"1.00 moles"}]	[{"type":"physical unit","value":"Mole [OF] N2 [=] \\pu{1 mole}"},{"type":"chemical equation","value":"Ca"}]	<h1 class="questionTitle" itemprop="name">#1# mole of #"N"_2# reacts with #"Ca"# to form #"Ca"_3"N"_2#. How many moles of #"Ca"_3"N"_2# are produced? </h1>	null	1.00 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that you need to write and examine the balanced chemical equation that describes the formation of calcium nitride from the reaction of calcium metal and nitrogen gas. </p> <blockquote> <p><mathjax>#3"Ca"_ ((s)) + "N"_ (2(g)) -> "Ca"_ 3"N"_ (2(s))#</mathjax></p> </blockquote> <p>Notice that it takes <mathjax>#3#</mathjax> <strong>moles</strong> of calcium to react with <mathjax>#1#</mathjax> <strong>mole</strong> of nitrogen gas and produce <mathjax>#1#</mathjax> <strong>mole</strong> of calcium nitride. </p> <p>In your case, you know that exactly <mathjax>#1#</mathjax> <strong>mole</strong> of nitrogen gas is taking part in this reaction, so you can that the reaction also consumed <mathjax>#3#</mathjax> <strong>moles</strong> of calcium metal. </p> <p> <iframe src="https://www.youtube.com/embed/S6UQX7ZdkTg?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"1 mole"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that you need to write and examine the balanced chemical equation that describes the formation of calcium nitride from the reaction of calcium metal and nitrogen gas. </p> <blockquote> <p><mathjax>#3"Ca"_ ((s)) + "N"_ (2(g)) -> "Ca"_ 3"N"_ (2(s))#</mathjax></p> </blockquote> <p>Notice that it takes <mathjax>#3#</mathjax> <strong>moles</strong> of calcium to react with <mathjax>#1#</mathjax> <strong>mole</strong> of nitrogen gas and produce <mathjax>#1#</mathjax> <strong>mole</strong> of calcium nitride. </p> <p>In your case, you know that exactly <mathjax>#1#</mathjax> <strong>mole</strong> of nitrogen gas is taking part in this reaction, so you can that the reaction also consumed <mathjax>#3#</mathjax> <strong>moles</strong> of calcium metal. </p> <p> <iframe src="https://www.youtube.com/embed/S6UQX7ZdkTg?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">#1# mole of #"N"_2# reacts with #"Ca"# to form #"Ca"_3"N"_2#. How many moles of #"Ca"_3"N"_2# are produced? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/mole-ratios" itemprop="url"> <span class="breadcrumb" itemprop="title">Mole Ratios</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="524850" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-12-20T12:08:40" itemprop="dateCreated"> Dec 20, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"1 mole"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that you need to write and examine the balanced chemical equation that describes the formation of calcium nitride from the reaction of calcium metal and nitrogen gas. </p> <blockquote> <p><mathjax>#3"Ca"_ ((s)) + "N"_ (2(g)) -> "Ca"_ 3"N"_ (2(s))#</mathjax></p> </blockquote> <p>Notice that it takes <mathjax>#3#</mathjax> <strong>moles</strong> of calcium to react with <mathjax>#1#</mathjax> <strong>mole</strong> of nitrogen gas and produce <mathjax>#1#</mathjax> <strong>mole</strong> of calcium nitride. </p> <p>In your case, you know that exactly <mathjax>#1#</mathjax> <strong>mole</strong> of nitrogen gas is taking part in this reaction, so you can that the reaction also consumed <mathjax>#3#</mathjax> <strong>moles</strong> of calcium metal. </p> <p> <iframe src="https://www.youtube.com/embed/S6UQX7ZdkTg?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/524850" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4178e02bf3469517a106e"> Question #a106e </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4178e02bf3469570e2e86"> Question #e2e86 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179102bf3469517a1072"> Question #a1072 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179402bf34694c8c5bf1"> Question #c5bf1 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a 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class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/mole-ratios"> See all questions in Mole Ratios </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 8955 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	#1# mole of #"N"_2# reacts with #"Ca"# to form #"Ca"_3"N"_2#. How many moles of #"Ca"_3"N"_2# are produced?	null
701	aad1dcf7-6ddd-11ea-8fca-ccda262736ce	https://socratic.org/questions/59a3b3ff11ef6b6c9de62d07	15.4 mol/L	start physical_unit 7 8 molarity mol/l qc_end physical_unit 7 8 6 6 percent qc_end physical_unit 8 8 13 14 density qc_end end	[{"type":"physical unit","value":"Molar concentration [OF] nitric acid [IN] mol/L"}]	[{"type":"physical unit","value":"15.4 mol/L"}]	[{"type":"physical unit","value":"Percent [OF] nitric acid in solution [=] \\pu{68%}"},{"type":"physical unit","value":"ρ [OF] acid [=] \\pu{1.41 g/mL}"}]	<h1 class="questionTitle" itemprop="name">What is the molar concentration of #68%# #"nitric acid"#, for which #rho_"acid"=1.41gmL^-1#?</h1>	null	15.4 mol/L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>By definition, <mathjax>#"Molarity"="Moles of solute (mol)"/"Volume of solution (L)"#</mathjax>, and thus it has the units <mathjax>#molL^-1#</mathjax>. So we need to address this quotient from the given data......</p> <p>We assume a <mathjax>#1mL#</mathjax> volume of solution, the which has a MASS of <mathjax>#1.41g#</mathjax>, of which 69% of that mass is nitric acid......And so....</p> <p><mathjax>#"Molarity"=((1.41gxx69%)/(63.01gmol^-1))/(1.00xx10^-3L)=15.4molL^-1#</mathjax></p> <p>Are you with me......please note the units of the calculation. We wanted an answer with units of <mathjax>#molL^-1#</mathjax>, and the quotient gave us such units - and this is an excellent check on our calculations.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Molarity"~=15molL^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>By definition, <mathjax>#"Molarity"="Moles of solute (mol)"/"Volume of solution (L)"#</mathjax>, and thus it has the units <mathjax>#molL^-1#</mathjax>. So we need to address this quotient from the given data......</p> <p>We assume a <mathjax>#1mL#</mathjax> volume of solution, the which has a MASS of <mathjax>#1.41g#</mathjax>, of which 69% of that mass is nitric acid......And so....</p> <p><mathjax>#"Molarity"=((1.41gxx69%)/(63.01gmol^-1))/(1.00xx10^-3L)=15.4molL^-1#</mathjax></p> <p>Are you with me......please note the units of the calculation. We wanted an answer with units of <mathjax>#molL^-1#</mathjax>, and the quotient gave us such units - and this is an excellent check on our calculations.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the molar concentration of #68%# #"nitric acid"#, for which #rho_"acid"=1.41gmL^-1#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/percent-concentration" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Concentration</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="468857" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-28T06:26:08" itemprop="dateCreated"> Aug 28, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Molarity"~=15molL^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>By definition, <mathjax>#"Molarity"="Moles of solute (mol)"/"Volume of solution (L)"#</mathjax>, and thus it has the units <mathjax>#molL^-1#</mathjax>. So we need to address this quotient from the given data......</p> <p>We assume a <mathjax>#1mL#</mathjax> volume of solution, the which has a MASS of <mathjax>#1.41g#</mathjax>, of which 69% of that mass is nitric acid......And so....</p> <p><mathjax>#"Molarity"=((1.41gxx69%)/(63.01gmol^-1))/(1.00xx10^-3L)=15.4molL^-1#</mathjax></p> <p>Are you with me......please note the units of the calculation. We wanted an answer with units of <mathjax>#molL^-1#</mathjax>, and the quotient gave us such units - and this is an excellent check on our calculations.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/468857" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-concentration-of-water-in-solution-be-decreased"> How can the concentration of water in solution be decreased? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-concentration-of-a-solution-be-increased"> How can the concentration of a solution be increased? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-concentration-of-a-solution-in-ppm"> How do you find the concentration of a solution in ppm? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-make-a-10-percent-solution"> How do you make a 10 percent solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-make-a-2-percent-solution"> How do you make a 2 percent solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-weight-per-volume-method-to-calculate-concentration"> What is the weight per volume method to calculate concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-percent-concentration-of-kcl-would-be-isotonic"> What percent concentration of KCl would be isotonic? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-of-sodium-chloride-in-normal-saline"> What is the percent concentration of sodium chloride in normal saline? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-of-a-6m-solution-of-nacl"> What is the percent concentration of a 6m solution of NaCl? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-formula"> What is the percent concentration formula? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/percent-concentration"> See all questions in Percent Concentration </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 9265 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the molar concentration of #68%# #"nitric acid"#, for which #rho_"acid"=1.41gmL^-1#?	null
702	ac0c45d8-6ddd-11ea-9ced-ccda262736ce	https://socratic.org/questions/what-volume-in-l-of-a-2-46-m-magnesium-nitrate-mg-no-3-2-solution-would-be-neede	0.09 L	start physical_unit 10 11 volume l qc_end physical_unit 10 11 6 7 molarity qc_end physical_unit 10 11 17 18 volume qc_end physical_unit 10 11 21 22 molarity qc_end end	[{"type":"physical unit","value":"Volume1 [OF] Mg(NO3)2 solution [IN] L"}]	[{"type":"physical unit","value":"0.09 L"}]	[{"type":"physical unit","value":"Molarity1 [OF] Mg(NO3)2 solution [=] \\pu{2.46 M}"},{"type":"physical unit","value":"Volume2 [OF] Mg(NO3)2 solution [=] \\pu{275 mL}"},{"type":"physical unit","value":"Molarity2 [OF] Mg(NO3)2 solution [=] \\pu{0.758 M}"}]	<h1 class="questionTitle" itemprop="name">What volume (in L) of a 2.46 M magnesium nitrate #Mg(NO_3)_2# solution would be needed to make 275 mL of a 0.758 M solution by dilution?</h1>	null	0.09 L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We need <mathjax>#275mL#</mathjax> of a solution that is <mathjax>#0.758molL^-1#</mathjax> with respect to magnesium nitrate.</p> <p><mathjax>#"Moles of solute"=0.275Lxx0.758molL^-1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.209mol#</mathjax>.</p> <p>So we divide this molar quantity, by the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of the mother solution to gives us the volume:</p> <p><mathjax>#(0.209mol)/(2.46molL^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#85*mL#</mathjax></p> <p>So we would take this volume and dilute it with fresh <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a> to give the required volume. Capisce? </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Under <mathjax>#0.1L#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We need <mathjax>#275mL#</mathjax> of a solution that is <mathjax>#0.758molL^-1#</mathjax> with respect to magnesium nitrate.</p> <p><mathjax>#"Moles of solute"=0.275Lxx0.758molL^-1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.209mol#</mathjax>.</p> <p>So we divide this molar quantity, by the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of the mother solution to gives us the volume:</p> <p><mathjax>#(0.209mol)/(2.46molL^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#85mL#</mathjax></p> <p>So we would take this volume and dilute it with fresh <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a> to give the required volume. Capisce? </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What volume (in L) of a 2.46 M magnesium nitrate #Mg(NO_3)_2# solution would be needed to make 275 mL of a 0.758 M solution by dilution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/dilution-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">Dilution Calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="261199" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-02T08:59:17" itemprop="dateCreated"> May 2, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Under <mathjax>#0.1L#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We need <mathjax>#275mL#</mathjax> of a solution that is <mathjax>#0.758molL^-1#</mathjax> with respect to magnesium nitrate.</p> <p><mathjax>#"Moles of solute"=0.275Lxx0.758molL^-1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.209mol#</mathjax>.</p> <p>So we divide this molar quantity, by the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of the mother solution to gives us the volume:</p> <p><mathjax>#(0.209mol)/(2.46molL^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#85mL#</mathjax></p> <p>So we would take this volume and dilute it with fresh <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a> to give the required volume. Capisce? </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/261199" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-concentration-from-absorbance"> How do you calculate concentration from absorbance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-concentration-from-titration"> How do you calculate concentration from titration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-dilution-factor"> How do you calculate dilution factor? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-do-serial-dilution-calculations"> How do you calculate serial dilutions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-calculate-concentration-of-solution-when-its-diluted"> How to calculate concentration of solution when it's diluted? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-examples-of-dilution-calculations"> What are some examples of dilution calculations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-would-be-the-concentration-of-a-solution-made-by-adding-250-ml-of-water-to-"> What would be the concentration of a solution made by adding 250 mL of water to 45.0 mL of 4.2 M KOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-would-be-the-concentration-of-a-solution-made-by-diluting-45-0-ml-of-4-2-m-"> What would be the concentration of a solution made by diluting 45.0 mL of 4.2 M KOH to 250 mL? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-a-solution-that-is-made-by-diluting-50-00-ml-of-a-4-74-m"> What is the molarity of a solution that is made by diluting 50.00 mL of a 4.74 M solution of HCl... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-volume-of-water-would-you-add-to-15-00-ml-of-a-6-77-m-solution-of-nitric-ac"> What volume of water would you add to 15.00 mL of a 6.77 M solution of nitric acid in order to... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/dilution-calculations"> See all questions in Dilution Calculations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 5277 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What volume (in L) of a 2.46 M magnesium nitrate #Mg(NO_3)_2# solution would be needed to make 275 mL of a 0.758 M solution by dilution?	null
703	ab0b7d74-6ddd-11ea-a639-ccda262736ce	https://socratic.org/questions/given-the-equation-lioh-hbr-libr-h2o-if-you-start-with-ten-grams-of-lithium-hydr	36.26 grams	start physical_unit 23 24 mass g qc_end chemical_equation 3 9 qc_end end	[{"type":"physical unit","value":"Mass [OF] lithium bromide [IN] grams"}]	[{"type":"physical unit","value":"36.26 grams"}]	[{"type":"chemical equation","value":"LiOH + HBr -> LiBr + H2O"},{"type":"physical unit","value":"Mass [OF] lithium hydroxide [=] \\pu{10 grams}"}]	<h1 class="questionTitle" itemprop="name">Given the equation: LiOH + HBr --> LiBr + H2O. If you start with ten grams of lithium hydroxide, how many grams of lithium bromide will be produced? </h1>	null	36.26 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"LiOH(aq)"+"HBr(aq)"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"LiBr(aq)"+"H"_2"O(l)"#</mathjax></p> <p><strong>Molar Masses of LiOH and LiBr</strong><br/> <mathjax>#"LiOH":#</mathjax><mathjax>#(1xx6.941 "g/mol Li")+(1xx15.999 "g/mol O")+(1xx1.00794 "g/mol H")="23.94794 g/mol LiOH"#</mathjax></p> <p><mathjax>#"LiBr":#</mathjax><mathjax>#(1xx6.941 "g/mol Li")+(1xx79.904"g/mol Br")="86.845 g/mol LiBr"#</mathjax></p> <p>To complete this problem, we are going to go from mass LiOH to moles LiOH to moles LiBr to mass LiBr.</p> <p><strong>Mass LiOH to Moles LiOH</strong><br/> Since you didn't give a numeric value for ten grams, it will be written as <mathjax>#10#</mathjax>, with only one significant figure. I will round the final answer to one significant figure.</p> <p><mathjax>#10cancel("g LiOH")xx(1"mol LiOH")/(23.94794cancel("g LiOH"))="0.41757 mol LiOH"#</mathjax></p> <p><strong>Mole LiOH to Mole LiBr</strong><br/> Multiply the mol LiOH times <a href="http://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio between LiBr and LiOH in the balanced equation, so that LiBr is in the numerator and LiOH is in the denominator so it will cancel.</p> <p><mathjax>#0.41757cancel("mol LiOH")xx(1"mol LiBr")/(1cancel("mol LiOH"))="0.41757 mol LiBr"#</mathjax></p> <p><strong>Mole LiBr to Mass LiBr</strong><br/> Multiply the mol LiBr times the molar mass of LiBr.</p> <p><mathjax>#0.41757"mol LiBr"xx(86.845"g LiBr")/(1"mol LiBr")="36.26 g LiBr"="40 g LiBr"#</mathjax> (rounded to one significant figure)</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Ten grams of LiOH will produce<mathjax>#~~"40 g LiBr"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"LiOH(aq)"+"HBr(aq)"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"LiBr(aq)"+"H"_2"O(l)"#</mathjax></p> <p><strong>Molar Masses of LiOH and LiBr</strong><br/> <mathjax>#"LiOH":#</mathjax><mathjax>#(1xx6.941 "g/mol Li")+(1xx15.999 "g/mol O")+(1xx1.00794 "g/mol H")="23.94794 g/mol LiOH"#</mathjax></p> <p><mathjax>#"LiBr":#</mathjax><mathjax>#(1xx6.941 "g/mol Li")+(1xx79.904"g/mol Br")="86.845 g/mol LiBr"#</mathjax></p> <p>To complete this problem, we are going to go from mass LiOH to moles LiOH to moles LiBr to mass LiBr.</p> <p><strong>Mass LiOH to Moles LiOH</strong><br/> Since you didn't give a numeric value for ten grams, it will be written as <mathjax>#10#</mathjax>, with only one significant figure. I will round the final answer to one significant figure.</p> <p><mathjax>#10cancel("g LiOH")xx(1"mol LiOH")/(23.94794cancel("g LiOH"))="0.41757 mol LiOH"#</mathjax></p> <p><strong>Mole LiOH to Mole LiBr</strong><br/> Multiply the mol LiOH times <a href="http://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio between LiBr and LiOH in the balanced equation, so that LiBr is in the numerator and LiOH is in the denominator so it will cancel.</p> <p><mathjax>#0.41757cancel("mol LiOH")xx(1"mol LiBr")/(1cancel("mol LiOH"))="0.41757 mol LiBr"#</mathjax></p> <p><strong>Mole LiBr to Mass LiBr</strong><br/> Multiply the mol LiBr times the molar mass of LiBr.</p> <p><mathjax>#0.41757"mol LiBr"xx(86.845"g LiBr")/(1"mol LiBr")="36.26 g LiBr"="40 g LiBr"#</mathjax> (rounded to one significant figure)</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Given the equation: LiOH + HBr --> LiBr + H2O. If you start with ten grams of lithium hydroxide, how many grams of lithium bromide will be produced? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="187640" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-12T23:33:49" itemprop="dateCreated"> Nov 12, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Ten grams of LiOH will produce<mathjax>#~~"40 g LiBr"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"LiOH(aq)"+"HBr(aq)"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"LiBr(aq)"+"H"_2"O(l)"#</mathjax></p> <p><strong>Molar Masses of LiOH and LiBr</strong><br/> <mathjax>#"LiOH":#</mathjax><mathjax>#(1xx6.941 "g/mol Li")+(1xx15.999 "g/mol O")+(1xx1.00794 "g/mol H")="23.94794 g/mol LiOH"#</mathjax></p> <p><mathjax>#"LiBr":#</mathjax><mathjax>#(1xx6.941 "g/mol Li")+(1xx79.904"g/mol Br")="86.845 g/mol LiBr"#</mathjax></p> <p>To complete this problem, we are going to go from mass LiOH to moles LiOH to moles LiBr to mass LiBr.</p> <p><strong>Mass LiOH to Moles LiOH</strong><br/> Since you didn't give a numeric value for ten grams, it will be written as <mathjax>#10#</mathjax>, with only one significant figure. I will round the final answer to one significant figure.</p> <p><mathjax>#10cancel("g LiOH")xx(1"mol LiOH")/(23.94794cancel("g LiOH"))="0.41757 mol LiOH"#</mathjax></p> <p><strong>Mole LiOH to Mole LiBr</strong><br/> Multiply the mol LiOH times <a href="http://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio between LiBr and LiOH in the balanced equation, so that LiBr is in the numerator and LiOH is in the denominator so it will cancel.</p> <p><mathjax>#0.41757cancel("mol LiOH")xx(1"mol LiBr")/(1cancel("mol LiOH"))="0.41757 mol LiBr"#</mathjax></p> <p><strong>Mole LiBr to Mass LiBr</strong><br/> Multiply the mol LiBr times the molar mass of LiBr.</p> <p><mathjax>#0.41757"mol LiBr"xx(86.845"g LiBr")/(1"mol LiBr")="36.26 g LiBr"="40 g LiBr"#</mathjax> (rounded to one significant figure)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/187640" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What is stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ab82402bf342f48d93ac6"> Question #93ac6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-we-study-stoichiometry"> Why do we study stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-naoh-is-produced-from-1-20-x-102-grams-of-na2o-na2o-h2o-2-naoh"> How many grams of NaOH is produced from #1.20 x 10^2# grams of #Na_2O#? #Na_2O + H_2O -> 2NaOH# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-na2o-are-required-to-produce-1-60-x-102-grams-of-naoh-na2o-h2o"> How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? 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If you start with ten grams of lithium hydroxide, how many grams of lithium bromide will be produced?	null
704	ab172818-6ddd-11ea-ba96-ccda262736ce	https://socratic.org/questions/how-many-liters-of-a-30-alcohol-solution-must-be-mixed-with-20-liters-of-a-80-so	5 liters	start physical_unit 6 7 volume l qc_end physical_unit 6 6 5 5 percent qc_end physical_unit 6 6 16 16 percent qc_end physical_unit 6 7 12 13 volume qc_end physical_unit 6 6 21 21 percent qc_end end	[{"type":"physical unit","value":"Volume1 [OF] alcohol solution [IN] liters"}]	[{"type":"physical unit","value":"5 liters"}]	[{"type":"physical unit","value":"Percent1 [OF] alcohol in solution [=] \\pu{30%}"},{"type":"physical unit","value":"Percent2 [OF] alcohol in solution [=] \\pu{80%}"},{"type":"physical unit","value":"Volume2 [OF] alcohol solution [=] \\pu{20 liters}"},{"type":"physical unit","value":"Percent3 [OF] alcohol in solution [=] \\pu{70%}"}]	<h1 class="questionTitle" itemprop="name"> How many liters of a 30% alcohol solution must be mixed with 20 liters of a 80% solution to get a 70% solution?</h1>	null	5 liters	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>I'll assume the given percentages are those <strong>by volume</strong> (i.e. <mathjax>#"v/v"#</mathjax>)..</p> <blockquote></blockquote> <p>We're asked to find the volume, in <mathjax>#"L"#</mathjax>, of a <mathjax>#30%#</mathjax> <mathjax>#"v/v"#</mathjax> alcohol solution must be added to <mathjax>#20#</mathjax> <mathjax>#"L"#</mathjax> of a <mathjax>#80%#</mathjax> <mathjax>#"v/v"#</mathjax> to obtain a solution that is <mathjax>#70%#</mathjax> <mathjax>#"v/v"#</mathjax>.</p> <blockquote></blockquote> <p>To do this, we can set up sort of an <em>algebraic equation</em> that represents this situation.</p> <p>Here, we have</p> <ul> <li> <p><mathjax>#x#</mathjax> liters of <mathjax>#0.3#</mathjax> fractional volume solution</p> </li> <li> <p><mathjax>#20#</mathjax> liters of <mathjax>#0.8#</mathjax> fractional volume solution</p> </li> </ul> <p>These two added together must be a solution with fractional volume <mathjax>#0.7#</mathjax> (the volume will be <mathjax>#20#</mathjax> <mathjax>#"L"#</mathjax> <mathjax>#+ x#</mathjax>), so we can write an equation</p> <blockquote> <p><mathjax>#ul(overbrace(x)^"volume of 30%"(0.3) + overbrace((20))^"volume of 80%"(0.8) = overbrace((x+20))^"total volume"(0.7)#</mathjax></p> </blockquote> <p>Now, we simply solve for <mathjax>#x#</mathjax>:</p> <blockquote> <p><mathjax>#0.3x + 16 = 0.7x + 14#</mathjax></p> <p><mathjax>#0.4x = 2#</mathjax></p> <p><mathjax>#color(red)(ul(x = 5#</mathjax></p> </blockquote> <p>So the required volume of the <mathjax>#30%#</mathjax> by volume solution is</p> <blockquote> <p><mathjax>#color(red)(ulbar(\|stackrel(" ")(" "5color(white)(l)"L"" ")\|)#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#5#</mathjax> <mathjax>#"L"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>I'll assume the given percentages are those <strong>by volume</strong> (i.e. <mathjax>#"v/v"#</mathjax>)..</p> <blockquote></blockquote> <p>We're asked to find the volume, in <mathjax>#"L"#</mathjax>, of a <mathjax>#30%#</mathjax> <mathjax>#"v/v"#</mathjax> alcohol solution must be added to <mathjax>#20#</mathjax> <mathjax>#"L"#</mathjax> of a <mathjax>#80%#</mathjax> <mathjax>#"v/v"#</mathjax> to obtain a solution that is <mathjax>#70%#</mathjax> <mathjax>#"v/v"#</mathjax>.</p> <blockquote></blockquote> <p>To do this, we can set up sort of an <em>algebraic equation</em> that represents this situation.</p> <p>Here, we have</p> <ul> <li> <p><mathjax>#x#</mathjax> liters of <mathjax>#0.3#</mathjax> fractional volume solution</p> </li> <li> <p><mathjax>#20#</mathjax> liters of <mathjax>#0.8#</mathjax> fractional volume solution</p> </li> </ul> <p>These two added together must be a solution with fractional volume <mathjax>#0.7#</mathjax> (the volume will be <mathjax>#20#</mathjax> <mathjax>#"L"#</mathjax> <mathjax>#+ x#</mathjax>), so we can write an equation</p> <blockquote> <p><mathjax>#ul(overbrace(x)^"volume of 30%"(0.3) + overbrace((20))^"volume of 80%"(0.8) = overbrace((x+20))^"total volume"(0.7)#</mathjax></p> </blockquote> <p>Now, we simply solve for <mathjax>#x#</mathjax>:</p> <blockquote> <p><mathjax>#0.3x + 16 = 0.7x + 14#</mathjax></p> <p><mathjax>#0.4x = 2#</mathjax></p> <p><mathjax>#color(red)(ul(x = 5#</mathjax></p> </blockquote> <p>So the required volume of the <mathjax>#30%#</mathjax> by volume solution is</p> <blockquote> <p><mathjax>#color(red)(ulbar(\|stackrel(" ")(" "5color(white)(l)"L"" ")\|)#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name"> How many liters of a 30% alcohol solution must be mixed with 20 liters of a 80% solution to get a 70% solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/solutions" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="459161" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/mrtas"><img alt="" class="" src="https://profilepictures.socratic.org/HY14X7r4S6AyDQgK2gwQ_IMG_0062.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/mrtas"> Nathan L. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-02T03:59:16" itemprop="dateCreated"> Aug 2, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#5#</mathjax> <mathjax>#"L"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>I'll assume the given percentages are those <strong>by volume</strong> (i.e. <mathjax>#"v/v"#</mathjax>)..</p> <blockquote></blockquote> <p>We're asked to find the volume, in <mathjax>#"L"#</mathjax>, of a <mathjax>#30%#</mathjax> <mathjax>#"v/v"#</mathjax> alcohol solution must be added to <mathjax>#20#</mathjax> <mathjax>#"L"#</mathjax> of a <mathjax>#80%#</mathjax> <mathjax>#"v/v"#</mathjax> to obtain a solution that is <mathjax>#70%#</mathjax> <mathjax>#"v/v"#</mathjax>.</p> <blockquote></blockquote> <p>To do this, we can set up sort of an <em>algebraic equation</em> that represents this situation.</p> <p>Here, we have</p> <ul> <li> <p><mathjax>#x#</mathjax> liters of <mathjax>#0.3#</mathjax> fractional volume solution</p> </li> <li> <p><mathjax>#20#</mathjax> liters of <mathjax>#0.8#</mathjax> fractional volume solution</p> </li> </ul> <p>These two added together must be a solution with fractional volume <mathjax>#0.7#</mathjax> (the volume will be <mathjax>#20#</mathjax> <mathjax>#"L"#</mathjax> <mathjax>#+ x#</mathjax>), so we can write an equation</p> <blockquote> <p><mathjax>#ul(overbrace(x)^"volume of 30%"(0.3) + overbrace((20))^"volume of 80%"(0.8) = overbrace((x+20))^"total volume"(0.7)#</mathjax></p> </blockquote> <p>Now, we simply solve for <mathjax>#x#</mathjax>:</p> <blockquote> <p><mathjax>#0.3x + 16 = 0.7x + 14#</mathjax></p> <p><mathjax>#0.4x = 2#</mathjax></p> <p><mathjax>#color(red)(ul(x = 5#</mathjax></p> </blockquote> <p>So the required volume of the <mathjax>#30%#</mathjax> by volume solution is</p> <blockquote> <p><mathjax>#color(red)(ulbar(\|stackrel(" ")(" "5color(white)(l)"L"" ")\|)#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/459161" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a 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The gram formula weight... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-solutions-differ-from-suspensions"> How do solutions differ from suspensions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-a-solution-differ-from-a-compound"> How does a solution differ from a compound? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/solutions"> See all questions in Solutions </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3558 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many liters of a 30% alcohol solution must be mixed with 20 liters of a 80% solution to get a 70% solution?	null
705	aa95e006-6ddd-11ea-a9cf-ccda262736ce	https://socratic.org/questions/the-volume-of-a-sample-of-gas-is-4-50-l-at-stp-what-volume-will-the-sample-occup	5.65 L	start physical_unit 4 6 volume l qc_end physical_unit 4 6 8 9 volume qc_end c_other STP qc_end physical_unit 4 6 19 20 temperature qc_end physical_unit 4 6 22 23 pressure qc_end end	[{"type":"physical unit","value":"Volume2 [OF] gas sample [IN] L"}]	[{"type":"physical unit","value":"5.65 L"}]	[{"type":"physical unit","value":"Volume1 [OF] gas sample [=] \\pu{4.50 L}"},{"type":"other","value":"STP"},{"type":"physical unit","value":"Temperature2 [OF] gas sample [=] \\pu{20.0 ℃}"},{"type":"physical unit","value":"Pressure2 [OF] gas sample [=] \\pu{650.0 torr}"}]	<h1 class="questionTitle" itemprop="name">The volume of a sample of gas is 4.50 L at STP What volume will the sample occupy at 20.0#"^o#C and 650.0 torr?</h1>	null	5.65 L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First, recall that “Standard” temperature and pressure are 0’C and 1 atm (760Torr), as opposed to “Normal” temperature and pressure of 20’C and 1 atm. </p> <p>In the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a> calculations all temperatures must be in “absolute” (‘Kelvin) degrees for the ratios to work correctly. Either Torr (mm Hg) or atm may be used for the pressure values.</p> <p>From the Ideal <a href="https://socratic.org/chemistry/the-behavior-of-gases/gas-laws">Gas Laws</a> we know that <mathjax>#((PV)/T)_1 = ((PV)/T)_2#</mathjax> </p> <p>Inserting our given values into this equation with the correct temperature values we get:</p> <p><mathjax>#(760 * 4.50L)/(273’K) = (650.0 * V_2)/(293’K)#</mathjax></p> <p><mathjax>#V_2 = (760/650) * (4.50)*(293/273)#</mathjax></p> <p><mathjax>#V_2 = 5.65 L#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>5.65 L</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First, recall that “Standard” temperature and pressure are 0’C and 1 atm (760Torr), as opposed to “Normal” temperature and pressure of 20’C and 1 atm. </p> <p>In the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a> calculations all temperatures must be in “absolute” (‘Kelvin) degrees for the ratios to work correctly. Either Torr (mm Hg) or atm may be used for the pressure values.</p> <p>From the Ideal <a href="https://socratic.org/chemistry/the-behavior-of-gases/gas-laws">Gas Laws</a> we know that <mathjax>#((PV)/T)_1 = ((PV)/T)_2#</mathjax> </p> <p>Inserting our given values into this equation with the correct temperature values we get:</p> <p><mathjax>#(760 * 4.50L)/(273’K) = (650.0 * V_2)/(293’K)#</mathjax></p> <p><mathjax>#V_2 = (760/650) * (4.50)*(293/273)#</mathjax></p> <p><mathjax>#V_2 = 5.65 L#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">The volume of a sample of gas is 4.50 L at STP What volume will the sample occupy at 20.0#"^o#C and 650.0 torr?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp" itemprop="url"> <span class="breadcrumb" itemprop="title">Molar Volume of a Gas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="337257" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/scooke"><img alt="" class="" src="https://profilepictures.socratic.org/ezAzqDkjRS6NXBmMH3lg_BioPic2010a.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/scooke"> SCooke </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-11-16T12:26:25" itemprop="dateCreated"> Nov 16, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>5.65 L</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First, recall that “Standard” temperature and pressure are 0’C and 1 atm (760Torr), as opposed to “Normal” temperature and pressure of 20’C and 1 atm. </p> <p>In the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a> calculations all temperatures must be in “absolute” (‘Kelvin) degrees for the ratios to work correctly. Either Torr (mm Hg) or atm may be used for the pressure values.</p> <p>From the Ideal <a href="https://socratic.org/chemistry/the-behavior-of-gases/gas-laws">Gas Laws</a> we know that <mathjax>#((PV)/T)_1 = ((PV)/T)_2#</mathjax> </p> <p>Inserting our given values into this equation with the correct temperature values we get:</p> <p><mathjax>#(760 * 4.50L)/(273’K) = (650.0 * V_2)/(293’K)#</mathjax></p> <p><mathjax>#V_2 = (760/650) * (4.50)*(293/273)#</mathjax></p> <p><mathjax>#V_2 = 5.65 L#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/337257" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-stoichiometric-ratios-relate-to-molar-volume-of-a-gas"> How do stoichiometric ratios relate to molar volume of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-a-gas-at-stp"> How do you calculate molar volume of a gas at STP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-molar-volume-of-hydrogen-gas"> How do you find the molar volume of hydrogen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-oxygen-gas"> How do you calculate molar volume of oxygen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molar-gas-volume"> What is molar gas volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/534c7bf202bf3420a007f014"> What is the volume at 0 °C and 1 atm of a mixture that contains 4.0 g of methane and 2.0 g of helium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5361f75702bf3429040e0599"> What is the difference between STP and NTP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-volume-of-25-moles-of-oxygen-o2-gas"> What is the volume of .25 moles of oxygen (O2) Gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-would-knowing-the-molar-volume-of-a-gas-be-important"> Why would knowing the molar volume of a gas be important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-22-4-liters-called-the-molar-volume-of-a-gas"> Why is 22.4 liters called the molar volume of a gas? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp"> See all questions in Molar Volume of a Gas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 15160 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	The volume of a sample of gas is 4.50 L at STP What volume will the sample occupy at 20.0#"^o#C and 650.0 torr?	null
706	acbbd3ae-6ddd-11ea-b5a6-ccda262736ce	https://socratic.org/questions/calculate-the-mass-of-oxygen-in-a-molecule-of-co2-by-using-percentage-compositio	5.3 × 10^(-23) g	start physical_unit 4 4 mass g qc_end end	[{"type":"physical unit","value":"Mass [OF] oxygen [IN] g"}]	[{"type":"physical unit","value":"5.3 × 10^(-23) g"}]	[{"type":"physical unit","value":"Number [OF] CO2 molecule [=] \\pu{1}"}]	<h1 class="questionTitle" itemprop="name">Calculate the mass of oxygen in a molecule of #"CO"_2# by using percentage composition? please help</h1>	null	5.3 × 10^(-23) g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The first thing you need to do here is to figure out the mass of oxygen in <mathjax>#1#</mathjax> <strong>mole</strong> of carbon dioxide. To do that, you must use the compound's <strong>molar mass</strong>. </p> <p>Now, carbon dioxide has a molar mass of <mathjax>#"44.01 g mol"^(-1)#</mathjax>. This means that <mathjax>#1#</mathjax> <strong>mole</strong> of carbon dioxide has a mass of <mathjax>#"44.01 g"#</mathjax>. </p> <p>You know that <mathjax>#1#</mathjax> <strong>mole</strong> of carbon dioxide contains </p> <blockquote> <ul> <li><em><strong>one mole</strong> of carbon</em>, <mathjax>#1 xx "C"#</mathjax></li> <li><em><strong>two moles</strong> of oxygen</em>, <mathjax>#2 xx "O"#</mathjax></li> </ul> </blockquote> <p>Oxygen has a molar mass of <mathjax>#"16.0 g mol"^(-1)#</mathjax>, so <mathjax>#1#</mathjax> <strong>mole</strong> of oxygen atoms has a mass of <mathjax>#"16.0 g"#</mathjax>. </p> <p>This means that if you take <mathjax>#"44.01 g"#</mathjax> of carbon dioxide, you know for a fact that it will contain </p> <blockquote> <p><mathjax>#2 color(red)(cancel(color(black)("moles O"))) * "16.0 g"/(1color(red)(cancel(color(black)("mole O")))) = "32.0 g O"#</mathjax></p> </blockquote> <p>This means that <mathjax>#"100 g"#</mathjax> of carbon dioxide will contain </p> <blockquote> <p><mathjax>#100color(red)(cancel(color(black)("g CO"_2))) * "32.0 g O"/(44.01color(red)(cancel(color(black)("g CO"_2)))) = "72.7 g O"#</mathjax></p> </blockquote> <p>Therefore, carbon dioxide has a <strong><a href="https://socratic.org/chemistry/the-mole-concept/percent-composition">percent composition</a></strong> of <mathjax>#"72.7%#</mathjax> oxygen, i.e. for every <mathjax>#"100 g"#</mathjax> of carbon dioxide you get <mathjax>#"72.7 g"#</mathjax> of oxygen. </p> <p>Now, you must determine the mass of oxygen present in <strong>a single molecule</strong> of carbon dioxide. Start by figuring out the mass of a single molecule of carbon dioxide.</p> <p>To do that, use <strong>Avogadro's constant</strong>, which tells you that</p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)("1 mole CO"_2 = 6.022 * 10^(23)"molecules CO"_2)))#</mathjax></p> </blockquote> <p>So, you know what</p> <blockquote> <p><mathjax>#"1 mole CO"_2 = "44.01 g" = 6.022 * 10^(23)"molecules CO"_2#</mathjax></p> </blockquote> <p>which means that <mathjax>#1#</mathjax> <strong>molecule</strong> of carbon dioxide has a mass of</p> <blockquote> <p><mathjax>#1 color(red)(cancel(color(black)("molecule CO"_2))) * "44.01 g"/(6.022 * 10^(23)color(red)(cancel(color(black)("molecules CO"_2))))#</mathjax></p> <blockquote> <blockquote> <p><mathjax># = 7.31 * 10^(-23)"g"#</mathjax></p> </blockquote> </blockquote> </blockquote> <p>Now you can use the percent composition of carbon dioxide to find the mass of oxygen present in <mathjax>#1#</mathjax> <strong>molecule</strong></p> <blockquote> <p><mathjax>#7.31 * 10^(-23) color(red)(cancel(color(black)("g CO"_2))) * "72.7 g O"/(100color(red)(cancel(color(black)("g CO"_2)))) = color(darkgreen)(ul(color(black)(5.3 * 10^(-23)"g O")))#</mathjax></p> </blockquote> <p>I'll leave the answer rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#5.3 * 10^(-23)"g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The first thing you need to do here is to figure out the mass of oxygen in <mathjax>#1#</mathjax> <strong>mole</strong> of carbon dioxide. To do that, you must use the compound's <strong>molar mass</strong>. </p> <p>Now, carbon dioxide has a molar mass of <mathjax>#"44.01 g mol"^(-1)#</mathjax>. This means that <mathjax>#1#</mathjax> <strong>mole</strong> of carbon dioxide has a mass of <mathjax>#"44.01 g"#</mathjax>. </p> <p>You know that <mathjax>#1#</mathjax> <strong>mole</strong> of carbon dioxide contains </p> <blockquote> <ul> <li><em><strong>one mole</strong> of carbon</em>, <mathjax>#1 xx "C"#</mathjax></li> <li><em><strong>two moles</strong> of oxygen</em>, <mathjax>#2 xx "O"#</mathjax></li> </ul> </blockquote> <p>Oxygen has a molar mass of <mathjax>#"16.0 g mol"^(-1)#</mathjax>, so <mathjax>#1#</mathjax> <strong>mole</strong> of oxygen atoms has a mass of <mathjax>#"16.0 g"#</mathjax>. </p> <p>This means that if you take <mathjax>#"44.01 g"#</mathjax> of carbon dioxide, you know for a fact that it will contain </p> <blockquote> <p><mathjax>#2 color(red)(cancel(color(black)("moles O"))) * "16.0 g"/(1color(red)(cancel(color(black)("mole O")))) = "32.0 g O"#</mathjax></p> </blockquote> <p>This means that <mathjax>#"100 g"#</mathjax> of carbon dioxide will contain </p> <blockquote> <p><mathjax>#100color(red)(cancel(color(black)("g CO"_2))) * "32.0 g O"/(44.01color(red)(cancel(color(black)("g CO"_2)))) = "72.7 g O"#</mathjax></p> </blockquote> <p>Therefore, carbon dioxide has a <strong><a href="https://socratic.org/chemistry/the-mole-concept/percent-composition">percent composition</a></strong> of <mathjax>#"72.7%#</mathjax> oxygen, i.e. for every <mathjax>#"100 g"#</mathjax> of carbon dioxide you get <mathjax>#"72.7 g"#</mathjax> of oxygen. </p> <p>Now, you must determine the mass of oxygen present in <strong>a single molecule</strong> of carbon dioxide. Start by figuring out the mass of a single molecule of carbon dioxide.</p> <p>To do that, use <strong>Avogadro's constant</strong>, which tells you that</p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)("1 mole CO"_2 = 6.022 * 10^(23)"molecules CO"_2)))#</mathjax></p> </blockquote> <p>So, you know what</p> <blockquote> <p><mathjax>#"1 mole CO"_2 = "44.01 g" = 6.022 * 10^(23)"molecules CO"_2#</mathjax></p> </blockquote> <p>which means that <mathjax>#1#</mathjax> <strong>molecule</strong> of carbon dioxide has a mass of</p> <blockquote> <p><mathjax>#1 color(red)(cancel(color(black)("molecule CO"_2))) * "44.01 g"/(6.022 * 10^(23)color(red)(cancel(color(black)("molecules CO"_2))))#</mathjax></p> <blockquote> <blockquote> <p><mathjax># = 7.31 * 10^(-23)"g"#</mathjax></p> </blockquote> </blockquote> </blockquote> <p>Now you can use the percent composition of carbon dioxide to find the mass of oxygen present in <mathjax>#1#</mathjax> <strong>molecule</strong></p> <blockquote> <p><mathjax>#7.31 * 10^(-23) color(red)(cancel(color(black)("g CO"_2))) * "72.7 g O"/(100color(red)(cancel(color(black)("g CO"_2)))) = color(darkgreen)(ul(color(black)(5.3 * 10^(-23)"g O")))#</mathjax></p> </blockquote> <p>I'll leave the answer rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Calculate the mass of oxygen in a molecule of #"CO"_2# by using percentage composition? please help</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/percent-composition" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Composition</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="371836" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-02-01T00:52:18" itemprop="dateCreated"> Feb 1, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#5.3 * 10^(-23)"g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The first thing you need to do here is to figure out the mass of oxygen in <mathjax>#1#</mathjax> <strong>mole</strong> of carbon dioxide. To do that, you must use the compound's <strong>molar mass</strong>. </p> <p>Now, carbon dioxide has a molar mass of <mathjax>#"44.01 g mol"^(-1)#</mathjax>. This means that <mathjax>#1#</mathjax> <strong>mole</strong> of carbon dioxide has a mass of <mathjax>#"44.01 g"#</mathjax>. </p> <p>You know that <mathjax>#1#</mathjax> <strong>mole</strong> of carbon dioxide contains </p> <blockquote> <ul> <li><em><strong>one mole</strong> of carbon</em>, <mathjax>#1 xx "C"#</mathjax></li> <li><em><strong>two moles</strong> of oxygen</em>, <mathjax>#2 xx "O"#</mathjax></li> </ul> </blockquote> <p>Oxygen has a molar mass of <mathjax>#"16.0 g mol"^(-1)#</mathjax>, so <mathjax>#1#</mathjax> <strong>mole</strong> of oxygen atoms has a mass of <mathjax>#"16.0 g"#</mathjax>. </p> <p>This means that if you take <mathjax>#"44.01 g"#</mathjax> of carbon dioxide, you know for a fact that it will contain </p> <blockquote> <p><mathjax>#2 color(red)(cancel(color(black)("moles O"))) * "16.0 g"/(1color(red)(cancel(color(black)("mole O")))) = "32.0 g O"#</mathjax></p> </blockquote> <p>This means that <mathjax>#"100 g"#</mathjax> of carbon dioxide will contain </p> <blockquote> <p><mathjax>#100color(red)(cancel(color(black)("g CO"_2))) * "32.0 g O"/(44.01color(red)(cancel(color(black)("g CO"_2)))) = "72.7 g O"#</mathjax></p> </blockquote> <p>Therefore, carbon dioxide has a <strong><a href="https://socratic.org/chemistry/the-mole-concept/percent-composition">percent composition</a></strong> of <mathjax>#"72.7%#</mathjax> oxygen, i.e. for every <mathjax>#"100 g"#</mathjax> of carbon dioxide you get <mathjax>#"72.7 g"#</mathjax> of oxygen. </p> <p>Now, you must determine the mass of oxygen present in <strong>a single molecule</strong> of carbon dioxide. Start by figuring out the mass of a single molecule of carbon dioxide.</p> <p>To do that, use <strong>Avogadro's constant</strong>, which tells you that</p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)("1 mole CO"_2 = 6.022 * 10^(23)"molecules CO"_2)))#</mathjax></p> </blockquote> <p>So, you know what</p> <blockquote> <p><mathjax>#"1 mole CO"_2 = "44.01 g" = 6.022 * 10^(23)"molecules CO"_2#</mathjax></p> </blockquote> <p>which means that <mathjax>#1#</mathjax> <strong>molecule</strong> of carbon dioxide has a mass of</p> <blockquote> <p><mathjax>#1 color(red)(cancel(color(black)("molecule CO"_2))) * "44.01 g"/(6.022 * 10^(23)color(red)(cancel(color(black)("molecules CO"_2))))#</mathjax></p> <blockquote> <blockquote> <p><mathjax># = 7.31 * 10^(-23)"g"#</mathjax></p> </blockquote> </blockquote> </blockquote> <p>Now you can use the percent composition of carbon dioxide to find the mass of oxygen present in <mathjax>#1#</mathjax> <strong>molecule</strong></p> <blockquote> <p><mathjax>#7.31 * 10^(-23) color(red)(cancel(color(black)("g CO"_2))) * "72.7 g O"/(100color(red)(cancel(color(black)("g CO"_2)))) = color(darkgreen)(ul(color(black)(5.3 * 10^(-23)"g O")))#</mathjax></p> </blockquote> <p>I'll leave the answer rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/371836" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-mole-percent"> What is mole percent? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4188602bf3469570e2e8b"> Question #e2e8b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4188702bf34695a6bc737"> Question #bc737 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418be02bf34695a6bc73b"> Question #bc73b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418c202bf3469570e2e8f"> Question #e2e8f </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418c802bf346963eb9857"> Question #b9857 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418ca02bf346963eb985b"> Question #b985b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418cc02bf34694a4fee41"> Question #fee41 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418d502bf34694c8c5c01"> Question #c5c01 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4196e02bf34695a6bc73f"> Question #bc73f </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/percent-composition"> See all questions in Percent Composition </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 62769 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Calculate the mass of oxygen in a molecule of #"CO"_2# by using percentage composition? please help	null
707	ac06ed0e-6ddd-11ea-8481-ccda262736ce	https://socratic.org/questions/how-many-moles-are-in-12-64-grams-of-carbon-dioxide	0.29 moles	start physical_unit 8 9 mole mol qc_end physical_unit 8 9 5 6 mass qc_end end	[{"type":"physical unit","value":"Mole [OF] carbon dioxide [IN] moles"}]	[{"type":"physical unit","value":"0.29 moles"}]	[{"type":"physical unit","value":"Mass [OF] carbon dioxide [=] \\pu{12.64 grams}"}]	<h1 class="questionTitle" itemprop="name">How many moles are in 12.64 grams of carbon dioxide?</h1>	null	0.29 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Divide the given mass of <mathjax>#"CO"_2#</mathjax> by its molar mass <mathjax>#(M)#</mathjax>. The molar mass of <mathjax>#"CO"_2#</mathjax> is determined by multiplying the subscript of each element by its molar mass and adding them. The molar mass of an element is its atomic weight on <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a> in g/mol.</p> <p><mathjax>#M_("CO"_2")#</mathjax><mathjax>#=#</mathjax><mathjax>#(1xx"12.011 g/mol C")+(2xx"15.999 g/mol O")="44.009 g/mol"#</mathjax></p> <p>Since molar mass is a fraction <mathjax>#("g"/"mol")#</mathjax>, we can divide by multiplying by the reciprocal of the molar mass <mathjax>#("mol"/"g")#</mathjax>.</p> <p><mathjax>#12.64color(red)cancel(color(black)("g CO"_2))xx(1"mol CO"_2)/(44.009color(red)cancel(color(black)("g CO"_2)))="0.2872 mol CO"_2#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>There are <mathjax>#"0.2872 mol CO"_2"#</mathjax> in <mathjax>#"12.64 g CO"_2#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Divide the given mass of <mathjax>#"CO"_2#</mathjax> by its molar mass <mathjax>#(M)#</mathjax>. The molar mass of <mathjax>#"CO"_2#</mathjax> is determined by multiplying the subscript of each element by its molar mass and adding them. The molar mass of an element is its atomic weight on <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a> in g/mol.</p> <p><mathjax>#M_("CO"_2")#</mathjax><mathjax>#=#</mathjax><mathjax>#(1xx"12.011 g/mol C")+(2xx"15.999 g/mol O")="44.009 g/mol"#</mathjax></p> <p>Since molar mass is a fraction <mathjax>#("g"/"mol")#</mathjax>, we can divide by multiplying by the reciprocal of the molar mass <mathjax>#("mol"/"g")#</mathjax>.</p> <p><mathjax>#12.64color(red)cancel(color(black)("g CO"_2))xx(1"mol CO"_2)/(44.009color(red)cancel(color(black)("g CO"_2)))="0.2872 mol CO"_2#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles are in 12.64 grams of carbon dioxide?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="540730" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-01-25T02:37:54" itemprop="dateCreated"> Jan 25, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>There are <mathjax>#"0.2872 mol CO"_2"#</mathjax> in <mathjax>#"12.64 g CO"_2#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Divide the given mass of <mathjax>#"CO"_2#</mathjax> by its molar mass <mathjax>#(M)#</mathjax>. The molar mass of <mathjax>#"CO"_2#</mathjax> is determined by multiplying the subscript of each element by its molar mass and adding them. The molar mass of an element is its atomic weight on <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a> in g/mol.</p> <p><mathjax>#M_("CO"_2")#</mathjax><mathjax>#=#</mathjax><mathjax>#(1xx"12.011 g/mol C")+(2xx"15.999 g/mol O")="44.009 g/mol"#</mathjax></p> <p>Since molar mass is a fraction <mathjax>#("g"/"mol")#</mathjax>, we can divide by multiplying by the reciprocal of the molar mass <mathjax>#("mol"/"g")#</mathjax>.</p> <p><mathjax>#12.64color(red)cancel(color(black)("g CO"_2))xx(1"mol CO"_2)/(44.009color(red)cancel(color(black)("g CO"_2)))="0.2872 mol CO"_2#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/540730" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 6402 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many moles are in 12.64 grams of carbon dioxide?	null
708	aa7c43b4-6ddd-11ea-a051-ccda262736ce	https://socratic.org/questions/the-pressure-on-one-cubic-foot-of-air-at-15-0-c-was-increased-from-14-7-lb-i-nch	132.51 ℃	start physical_unit 7 7 temperature °c qc_end physical_unit 7 7 3 5 volume qc_end physical_unit 7 7 9 10 temperature qc_end physical_unit 7 7 14 15 pressure qc_end physical_unit 7 7 18 19 pressure qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Temperature2 [OF] the air [IN] ℃"}]	[{"type":"physical unit","value":"132.51 ℃"}]	[{"type":"physical unit","value":"Volume [OF] the air [=] \\pu{1 cubic foot}"},{"type":"physical unit","value":"Temperature1 [OF] the air [=] \\pu{-15.0 ℃ }"},{"type":"physical unit","value":"Pressure1 [OF] the air [=] \\pu{14.7 lb/inch^2}"},{"type":"physical unit","value":"Pressure2 [OF] the air [=] \\pu{23.1 lb/inch^2}"},{"type":"other","value":"The volume remained constant."}]	<h1 class="questionTitle" itemprop="name">The pressure on one cubic foot of air at -15.0°C was increased from #14.7# #lb##/##i##nch^2# squared to 23.1 #lb##/##i##nch^2#. What is the final temperature, in °C, if the volume remained constant?</h1>	null	132.51 ℃	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>Since the volume is constant, this is an example of a problem involving Gay-Lussac's Law:</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(P_1/T_1=P_2/T_2)\|)#</mathjax></p> </blockquote> </blockquote> <p>Your data are:</p> <p><mathjax>#P_1 = "14.7 lb/in"^2#</mathjax>; <mathjax>#T_1 = "-15.0 °C" = "258.15 K"#</mathjax><br/> <mathjax>#P_2 = "23.1 lb/in"^2#</mathjax>; <mathjax># T_2 = "?"#</mathjax></p> <blockquote></blockquote> <p>We can rearrange the above formula to get</p> <p><mathjax>#T_2=T_1 × P_2/P_1#</mathjax></p> <p><mathjax>#T_2 = "258.15 K" × (23.1 color(red)(cancel(color(black)("lb/in"^2))))/(14.7 color(red)(cancel(color(black)("lb/in"^2)))) = "405.7 K" = "133 °C"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The final temperature is 133 °C.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>Since the volume is constant, this is an example of a problem involving Gay-Lussac's Law:</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(P_1/T_1=P_2/T_2)\|)#</mathjax></p> </blockquote> </blockquote> <p>Your data are:</p> <p><mathjax>#P_1 = "14.7 lb/in"^2#</mathjax>; <mathjax>#T_1 = "-15.0 °C" = "258.15 K"#</mathjax><br/> <mathjax>#P_2 = "23.1 lb/in"^2#</mathjax>; <mathjax># T_2 = "?"#</mathjax></p> <blockquote></blockquote> <p>We can rearrange the above formula to get</p> <p><mathjax>#T_2=T_1 × P_2/P_1#</mathjax></p> <p><mathjax>#T_2 = "258.15 K" × (23.1 color(red)(cancel(color(black)("lb/in"^2))))/(14.7 color(red)(cancel(color(black)("lb/in"^2)))) = "405.7 K" = "133 °C"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">The pressure on one cubic foot of air at -15.0°C was increased from #14.7# #lb##/##i##nch^2# squared to 23.1 #lb##/##i##nch^2#. What is the final temperature, in °C, if the volume remained constant?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/gay-lussac-s-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Gay Lussac's Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="266520" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-16T21:50:56" itemprop="dateCreated"> May 16, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The final temperature is 133 °C.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>Since the volume is constant, this is an example of a problem involving Gay-Lussac's Law:</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(P_1/T_1=P_2/T_2)\|)#</mathjax></p> </blockquote> </blockquote> <p>Your data are:</p> <p><mathjax>#P_1 = "14.7 lb/in"^2#</mathjax>; <mathjax>#T_1 = "-15.0 °C" = "258.15 K"#</mathjax><br/> <mathjax>#P_2 = "23.1 lb/in"^2#</mathjax>; <mathjax># T_2 = "?"#</mathjax></p> <blockquote></blockquote> <p>We can rearrange the above formula to get</p> <p><mathjax>#T_2=T_1 × P_2/P_1#</mathjax></p> <p><mathjax>#T_2 = "258.15 K" × (23.1 color(red)(cancel(color(black)("lb/in"^2))))/(14.7 color(red)(cancel(color(black)("lb/in"^2)))) = "405.7 K" = "133 °C"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/266520" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535d701102bf342f53d9bcb0"> Question #9bcb0 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-gay-lussac-s-law-formula"> What is the Gay Lussac's law formula? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-the-temperature-of-a-gas-in-a-container-is-doubled-on-the-kelvin-scale-the-pr"> If the temperature of a gas in a container is doubled on the Kelvin scale, what will happen to... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-the-original-pressure-of-a-gas-sample-at-20-c-was-5-00-atm-and-it-is-heated-u"> If the original pressure of a gas sample at 20 ˚C was 5.00 atm, and it is heated up to 40. ˚C ,... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-gay-lussac-s-law-state"> What does Gay Lussac's law state? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-gay-lussac-s-law-relate"> What does Gay Lussac's law relate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-sample-of-o2-under-2-00-atm-occupies-500-ml-at-25-0-c-what-pressure-will-the-s"> A sample of O2 under 2.00 atm occupies 500 ml at 25.0˚C. 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What is the final temperature, in °C, if the volume remained constant?	null
709	abb69700-6ddd-11ea-86a9-ccda262736ce	https://socratic.org/questions/how-many-milliliters-of-water-must-be-added-to-300-ml-of-70-alcoholic-solution-t	225 milliliters	start physical_unit 4 4 volume ml qc_end physical_unit 13 14 9 10 volume qc_end end	[{"type":"physical unit","value":"Volume [OF] water [IN] milliliters"}]	[{"type":"physical unit","value":"225 milliliters"}]	[{"type":"physical unit","value":"Volume1 [OF] alcoholic solution [=] \\pu{300 ml}"},{"type":"physical unit","value":"Percent1 [OF] alcohol in solution [=] \\pu{70%}"},{"type":"physical unit","value":"Percent2 [OF] alcohol in solution [=] \\pu{40%}"}]	<h1 class="questionTitle" itemprop="name">How many milliliters of water must be added to 300 ml of 70% alcoholic solution to make a 40% alcoholic solution?</h1>	null	225 milliliters	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>This is a dilution problem, so we can use the dilution formula:</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(\|color(white)(a/a)c_1V_1= c_2V_2color(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p><mathjax>#c_1 = 70 %; V_1 = "300 mL"#</mathjax><br/> <mathjax>#c_2 = 40 %; V_2 = "?"#</mathjax> </p> <p><mathjax>#V_2 = V_1 × c_1/c_2 ="300 mL" × (70 color(red)(cancel(color(black)(%))))/(40 color(red)(cancel(color(black)(%)))) = "525 mL"#</mathjax></p> <p>Thus, you would add 225 mL of water to 300 mL of 70 % alcohol, and you would get 525 mL of 40 % alcohol.</p> <blockquote></blockquote> <p><strong>Check:</strong></p> <p>300 mL of 70 % alcohol contains 210 mL of alcohol, and 525 mL of 40 % alcohol contains 210 mL of alcohol.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>You must add 225 mL of water.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>This is a dilution problem, so we can use the dilution formula:</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(\|color(white)(a/a)c_1V_1= c_2V_2color(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p><mathjax>#c_1 = 70 %; V_1 = "300 mL"#</mathjax><br/> <mathjax>#c_2 = 40 %; V_2 = "?"#</mathjax> </p> <p><mathjax>#V_2 = V_1 × c_1/c_2 ="300 mL" × (70 color(red)(cancel(color(black)(%))))/(40 color(red)(cancel(color(black)(%)))) = "525 mL"#</mathjax></p> <p>Thus, you would add 225 mL of water to 300 mL of 70 % alcohol, and you would get 525 mL of 40 % alcohol.</p> <blockquote></blockquote> <p><strong>Check:</strong></p> <p>300 mL of 70 % alcohol contains 210 mL of alcohol, and 525 mL of 40 % alcohol contains 210 mL of alcohol.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many milliliters of water must be added to 300 ml of 70% alcoholic solution to make a 40% alcoholic solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/dilution-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">Dilution Calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="360958" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-01-06T15:11:43" itemprop="dateCreated"> Jan 6, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>You must add 225 mL of water.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>This is a dilution problem, so we can use the dilution formula:</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(\|color(white)(a/a)c_1V_1= c_2V_2color(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p><mathjax>#c_1 = 70 %; V_1 = "300 mL"#</mathjax><br/> <mathjax>#c_2 = 40 %; V_2 = "?"#</mathjax> </p> <p><mathjax>#V_2 = V_1 × c_1/c_2 ="300 mL" × (70 color(red)(cancel(color(black)(%))))/(40 color(red)(cancel(color(black)(%)))) = "525 mL"#</mathjax></p> <p>Thus, you would add 225 mL of water to 300 mL of 70 % alcohol, and you would get 525 mL of 40 % alcohol.</p> <blockquote></blockquote> <p><strong>Check:</strong></p> <p>300 mL of 70 % alcohol contains 210 mL of alcohol, and 525 mL of 40 % alcohol contains 210 mL of alcohol.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/360958" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-concentration-from-absorbance"> How do you calculate concentration from absorbance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-concentration-from-titration"> How do you calculate concentration from titration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-dilution-factor"> How do you calculate dilution factor? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-do-serial-dilution-calculations"> How do you calculate serial dilutions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-calculate-concentration-of-solution-when-its-diluted"> How to calculate concentration of solution when it's diluted? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-examples-of-dilution-calculations"> What are some examples of dilution calculations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-would-be-the-concentration-of-a-solution-made-by-adding-250-ml-of-water-to-"> What would be the concentration of a solution made by adding 250 mL of water to 45.0 mL of 4.2 M KOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-would-be-the-concentration-of-a-solution-made-by-diluting-45-0-ml-of-4-2-m-"> What would be the concentration of a solution made by diluting 45.0 mL of 4.2 M KOH to 250 mL? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-a-solution-that-is-made-by-diluting-50-00-ml-of-a-4-74-m"> What is the molarity of a solution that is made by diluting 50.00 mL of a 4.74 M solution of HCl... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-volume-of-water-would-you-add-to-15-00-ml-of-a-6-77-m-solution-of-nitric-ac"> What volume of water would you add to 15.00 mL of a 6.77 M solution of nitric acid in order to... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/dilution-calculations"> See all questions in Dilution Calculations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 25692 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many milliliters of water must be added to 300 ml of 70% alcoholic solution to make a 40% alcoholic solution?	null
710	ab3ee9be-6ddd-11ea-9ca1-ccda262736ce	https://socratic.org/questions/what-is-the-oxidation-number-of-sn-in-the-compound-na-2sno-2	+2	start physical_unit 6 6 oxidation_number none qc_end chemical_equation 10 10 qc_end end	[{"type":"physical unit","value":"Oxidation number [OF] Sn"}]	[{"type":"physical unit","value":"+2"}]	[{"type":"chemical equation","value":"Na2SnO2"}]	<h1 class="questionTitle" itemprop="name">What is the oxidation number of #Sn# in the compound #Na_2SnO_2#?</h1>	null	+2	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To find the oxidation number of <mathjax>#Sn#</mathjax> in <mathjax>#Na_2SnO_2#</mathjax> we should know that:</p> <p>The oxidation number for <mathjax>#Na#</mathjax> is always <mathjax>#+1#</mathjax>.</p> <p>The oxidation number of <mathjax>#O#</mathjax> is always <mathjax>#-2#</mathjax> except in <mathjax>#H_2O_2#</mathjax> it is <mathjax>#-1#</mathjax> and in <mathjax>#OF_2#</mathjax> it is <mathjax>#+2#</mathjax>.</p> <p>Let the oxidation number of <mathjax>#Sn#</mathjax> be <mathjax>#x#</mathjax>, therefore,</p> <p><mathjax>#2xx(+1)+x+2xx(-2)=0#</mathjax></p> <p><mathjax>#=>2+x-4=0#</mathjax></p> <p><mathjax>#=>x-2=0#</mathjax> </p> <p><mathjax>#=>x=+2#</mathjax></p> <p>Thus, the oxidation number of <mathjax>#Sn#</mathjax> in <mathjax>#Na_2SnO_2#</mathjax> is <mathjax>#+2#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#+2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To find the oxidation number of <mathjax>#Sn#</mathjax> in <mathjax>#Na_2SnO_2#</mathjax> we should know that:</p> <p>The oxidation number for <mathjax>#Na#</mathjax> is always <mathjax>#+1#</mathjax>.</p> <p>The oxidation number of <mathjax>#O#</mathjax> is always <mathjax>#-2#</mathjax> except in <mathjax>#H_2O_2#</mathjax> it is <mathjax>#-1#</mathjax> and in <mathjax>#OF_2#</mathjax> it is <mathjax>#+2#</mathjax>.</p> <p>Let the oxidation number of <mathjax>#Sn#</mathjax> be <mathjax>#x#</mathjax>, therefore,</p> <p><mathjax>#2xx(+1)+x+2xx(-2)=0#</mathjax></p> <p><mathjax>#=>2+x-4=0#</mathjax></p> <p><mathjax>#=>x-2=0#</mathjax> </p> <p><mathjax>#=>x=+2#</mathjax></p> <p>Thus, the oxidation number of <mathjax>#Sn#</mathjax> in <mathjax>#Na_2SnO_2#</mathjax> is <mathjax>#+2#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the oxidation number of #Sn# in the compound #Na_2SnO_2#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#electrochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Electrochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/electrochemistry/oxidation-numbers" itemprop="url"> <span class="breadcrumb" itemprop="title">Oxidation Numbers</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="270945" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ali-h-1"><img alt="" class="" src="https://profilepictures.socratic.org/IITeL1YTQdODdLp0aJTL_StereoPicture%20copy.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ali-h-1"> Dr. Hayek </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-29T12:14:46" itemprop="dateCreated"> May 29, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#+2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To find the oxidation number of <mathjax>#Sn#</mathjax> in <mathjax>#Na_2SnO_2#</mathjax> we should know that:</p> <p>The oxidation number for <mathjax>#Na#</mathjax> is always <mathjax>#+1#</mathjax>.</p> <p>The oxidation number of <mathjax>#O#</mathjax> is always <mathjax>#-2#</mathjax> except in <mathjax>#H_2O_2#</mathjax> it is <mathjax>#-1#</mathjax> and in <mathjax>#OF_2#</mathjax> it is <mathjax>#+2#</mathjax>.</p> <p>Let the oxidation number of <mathjax>#Sn#</mathjax> be <mathjax>#x#</mathjax>, therefore,</p> <p><mathjax>#2xx(+1)+x+2xx(-2)=0#</mathjax></p> <p><mathjax>#=>2+x-4=0#</mathjax></p> <p><mathjax>#=>x-2=0#</mathjax> </p> <p><mathjax>#=>x=+2#</mathjax></p> <p>Thus, the oxidation number of <mathjax>#Sn#</mathjax> in <mathjax>#Na_2SnO_2#</mathjax> is <mathjax>#+2#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/270945" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-relate-to-electron-configuration"> How do oxidation numbers relate to electron configuration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-relate-to-valence-electrons"> How do oxidation numbers relate to valence electrons? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-vary-with-the-periodic-table"> How do oxidation numbers vary with the periodic table? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-oxidation-number-of-an-element-in-a-compound"> How do you calculate the oxidation number of an element in a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-sulfur"> What is the oxidation number for sulfur? </a> </div> </li> <li class="relatedQuestionItem"> <div 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zero? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/electrochemistry/oxidation-numbers"> See all questions in Oxidation Numbers </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 4318 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the oxidation number of #Sn# in the compound #Na_2SnO_2#?	null
711	ac0fd62a-6ddd-11ea-b3c7-ccda262736ce	https://socratic.org/questions/what-is-the-molality-of-a-solution-that-contains-63-0-g-hnc-3-in-0-500-kg-h-2o	4.06 mol/kg	start physical_unit 6 6 molality mol/kg qc_end physical_unit 11 11 9 10 mass qc_end physical_unit 15 15 13 14 mass qc_end end	[{"type":"physical unit","value":"Molality [OF] the solution [IN] mol/kg"}]	[{"type":"physical unit","value":"4.06 mol/kg"}]	[{"type":"physical unit","value":"Mass [OF] HNC3 [=] \\pu{63.0 g}"},{"type":"physical unit","value":"Mass [OF] H2O [=] \\pu{0.500 kg}"}]	<h1 class="questionTitle" itemprop="name">What is the molality of a solution that contains 63.0 g #HNC_3# in 0.500 kg #H_2O#?</h1>	null	4.06 mol/kg	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>If you mean <mathjax>#"methylamine"#</mathjax>, then the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molality">molality</a> of the solution is given by:</p> <p><mathjax>#"Moles of solute"/"Kilograms of solvent"=((63.0g)/(31.06gmol^-1))/(0.500kg)=4.06molkg^-1#</mathjax>.</p> <p>I would not want to be downwind of such a solution. It would smell VILE! If you mean a different <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a>, you must specify the unambiguous chemical formula. The <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of the solution would not be significantly different. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>What do you mean by <mathjax>#HNC_3#</mathjax>, do you mean <mathjax>#H_2NCH_3#</mathjax>, i.e. <mathjax>#"methylamine"#</mathjax>?</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>If you mean <mathjax>#"methylamine"#</mathjax>, then the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molality">molality</a> of the solution is given by:</p> <p><mathjax>#"Moles of solute"/"Kilograms of solvent"=((63.0g)/(31.06gmol^-1))/(0.500kg)=4.06molkg^-1#</mathjax>.</p> <p>I would not want to be downwind of such a solution. It would smell VILE! If you mean a different <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a>, you must specify the unambiguous chemical formula. The <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of the solution would not be significantly different. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the molality of a solution that contains 63.0 g #HNC_3# in 0.500 kg #H_2O#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="421350" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-11T06:59:33" itemprop="dateCreated"> May 11, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>What do you mean by <mathjax>#HNC_3#</mathjax>, do you mean <mathjax>#H_2NCH_3#</mathjax>, i.e. <mathjax>#"methylamine"#</mathjax>?</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>If you mean <mathjax>#"methylamine"#</mathjax>, then the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molality">molality</a> of the solution is given by:</p> <p><mathjax>#"Moles of solute"/"Kilograms of solvent"=((63.0g)/(31.06gmol^-1))/(0.500kg)=4.06molkg^-1#</mathjax>.</p> <p>I would not want to be downwind of such a solution. It would smell VILE! If you mean a different <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a>, you must specify the unambiguous chemical formula. The <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of the solution would not be significantly different. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/421350" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-morality-be-used-as-a-conversion-factor"> How can molarity be used as a conversion factor? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-high-can-molarity-be"> How high can molarity be? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-molarity-change-with-temperature"> How does molarity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molarity-of-a-solution"> How do you find molarity of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-10-naoh"> What is the molarity of 10 NaOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-3-hydrogen-peroxide"> What is the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 4630 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the molality of a solution that contains 63.0 g #HNC_3# in 0.500 kg #H_2O#?	null
712	a9e39bf6-6ddd-11ea-ab19-ccda262736ce	https://socratic.org/questions/how-many-times-more-basic-is-a-ph-of-12-compared-to-a-ph-of-8	10000	start physical_unit 3 4 times none qc_end end	[{"type":"physical unit","value":"Times [OF] more basic"}]	[{"type":"physical unit","value":"10000"}]	[{"type":"physical unit","value":"pH1 [OF] solution [=] \\pu{12}"},{"type":"physical unit","value":"pH2 [OF] solution [=] \\pu{8}"}]	<h1 class="questionTitle" itemprop="name">How many times more basic is a pH of 12 compared to a pH of 8?</h1>	null	10000	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Since <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> is a logarithmic scale, a change in pH of 1 results in a ten-fold change in the concentration of <mathjax>#H^+#</mathjax>, which would be a <strong>ten-fold change in acidity/basicity</strong> . This is because how acidic/basic a substance is can be determined by the <strong>concentration of hydrogen ions.</strong> The more <mathjax>#H^+#</mathjax> ions present, the more acidic the substance is, due to the fact that acids donate <mathjax>#H^+#</mathjax> ions. On the other hand, bases accept <mathjax>#H^+#</mathjax> ions, and thus the lower the concentration of <mathjax>#H^+#</mathjax>, the more basic the substance is. </p> <p>You can calculate the concentration of <mathjax>#H^+#</mathjax> from the pH and the equation <mathjax>#pH=-log[H^+]#</mathjax>. Rearranging, we get <mathjax>#[H^+]=10^(-pH)#</mathjax></p> <p>So for a pH of 8, we get <mathjax>#[H^+]=10^-8#</mathjax><br/> For a pH of 12, we get <mathjax>#[H^+]=10^-12#</mathjax></p> <p><mathjax>#10^-8/10^-12=10^4=10000#</mathjax> times less <mathjax>#H^+#</mathjax> ions and thus <mathjax>#10000#</mathjax> times more basic</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>10000 times more basic</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Since <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> is a logarithmic scale, a change in pH of 1 results in a ten-fold change in the concentration of <mathjax>#H^+#</mathjax>, which would be a <strong>ten-fold change in acidity/basicity</strong> . This is because how acidic/basic a substance is can be determined by the <strong>concentration of hydrogen ions.</strong> The more <mathjax>#H^+#</mathjax> ions present, the more acidic the substance is, due to the fact that acids donate <mathjax>#H^+#</mathjax> ions. On the other hand, bases accept <mathjax>#H^+#</mathjax> ions, and thus the lower the concentration of <mathjax>#H^+#</mathjax>, the more basic the substance is. </p> <p>You can calculate the concentration of <mathjax>#H^+#</mathjax> from the pH and the equation <mathjax>#pH=-log[H^+]#</mathjax>. Rearranging, we get <mathjax>#[H^+]=10^(-pH)#</mathjax></p> <p>So for a pH of 8, we get <mathjax>#[H^+]=10^-8#</mathjax><br/> For a pH of 12, we get <mathjax>#[H^+]=10^-12#</mathjax></p> <p><mathjax>#10^-8/10^-12=10^4=10000#</mathjax> times less <mathjax>#H^+#</mathjax> ions and thus <mathjax>#10000#</mathjax> times more basic</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many times more basic is a pH of 12 compared to a pH of 8?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/the-ph-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">pH</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="319485" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/henry-w-2"><img alt="" class="" src="https://profilepictures.socratic.org/7IFCgaDHTbGDlVtThZyG_elephant_seal1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/henry-w-2"> Henry W. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-10-08T21:57:41" itemprop="dateCreated"> Oct 8, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>10000 times more basic</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Since <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> is a logarithmic scale, a change in pH of 1 results in a ten-fold change in the concentration of <mathjax>#H^+#</mathjax>, which would be a <strong>ten-fold change in acidity/basicity</strong> . This is because how acidic/basic a substance is can be determined by the <strong>concentration of hydrogen ions.</strong> The more <mathjax>#H^+#</mathjax> ions present, the more acidic the substance is, due to the fact that acids donate <mathjax>#H^+#</mathjax> ions. On the other hand, bases accept <mathjax>#H^+#</mathjax> ions, and thus the lower the concentration of <mathjax>#H^+#</mathjax>, the more basic the substance is. </p> <p>You can calculate the concentration of <mathjax>#H^+#</mathjax> from the pH and the equation <mathjax>#pH=-log[H^+]#</mathjax>. Rearranging, we get <mathjax>#[H^+]=10^(-pH)#</mathjax></p> <p>So for a pH of 8, we get <mathjax>#[H^+]=10^-8#</mathjax><br/> For a pH of 12, we get <mathjax>#[H^+]=10^-12#</mathjax></p> <p><mathjax>#10^-8/10^-12=10^4=10000#</mathjax> times less <mathjax>#H^+#</mathjax> ions and thus <mathjax>#10000#</mathjax> times more basic</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/319485" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-pka"> How do you determine pH from pKa? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-ph-values-of-acids-and-bases-differ"> How do pH values of acids and bases differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-something-on-a-ph-scale"> How do you calculate something on a pH scale? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-diprotic-acid"> How do you calculate pH diprotic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-from-acid-dissociation-constant"> How do you calculate pH from acid dissociation constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-of-acid-and-base-solution"> How do you calculate pH of acid and base solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ph-scale-0-14"> Why is the pH scale 0-14? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-ph-the-measure-of-the-hydrogen-ion-concentration"> Is pH a measure of the hydrogen ion concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-solubility-affect-ph"> How does solubility affect pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-ph-relate-to-pka-in-a-titration"> How does pH relate to pKa in a titration? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/the-ph-concept"> See all questions in pH </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 60453 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many times more basic is a pH of 12 compared to a pH of 8?	null
713	ab520ee2-6ddd-11ea-863f-ccda262736ce	https://socratic.org/questions/what-is-the-2-methyl-cyclopentanone-condensed-formula	C6H10O	start chemical_formula qc_end substance 3 4 qc_end end	[{"type":"other","value":"Chemical Formula [OF] 2-methyl cyclopentanone [IN] default"}]	[{"type":"chemical equation","value":"C6H10O"}]	[{"type":"substance name","value":"2-methyl cyclopentanone"}]	<h1 class="questionTitle" itemprop="name">What is the 2-methyl cyclopentanone condensed formula?</h1>	null	C6H10O	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Looking at the molecular formula, there are clearly TWO degrees of unsaturation (i.e. as compared to a saturated hydrocarbon, which has a general formula of <mathjax>#C_nH_(2n+2)O#</mathjax>). This corresponds to (i) the carbonyl group, and (ii) the ring junction.......</p> <p>Of course, the given formula could correspond to other molecules.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_6H_10O#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Looking at the molecular formula, there are clearly TWO degrees of unsaturation (i.e. as compared to a saturated hydrocarbon, which has a general formula of <mathjax>#C_nH_(2n+2)O#</mathjax>). This corresponds to (i) the carbonyl group, and (ii) the ring junction.......</p> <p>Of course, the given formula could correspond to other molecules.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the 2-methyl cyclopentanone condensed formula?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/determining-formula-and-molar-masses" itemprop="url"> <span class="breadcrumb" itemprop="title">Determining Formula</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="383670" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-02-27T08:58:52" itemprop="dateCreated"> Feb 27, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_6H_10O#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Looking at the molecular formula, there are clearly TWO degrees of unsaturation (i.e. as compared to a saturated hydrocarbon, which has a general formula of <mathjax>#C_nH_(2n+2)O#</mathjax>). This corresponds to (i) the carbonyl group, and (ii) the ring junction.......</p> <p>Of course, the given formula could correspond to other molecules.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/383670" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-it-possible-to-find-a-molecular-formula-from-molar-mass"> Is it possible to find a molecular formula from molar mass? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5368e0cc02bf34779e175781"> Question #75781 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-common-mistakes-students-make-when-determining-formulas"> What are some common mistakes students make when determining formulas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-formula-of-an-acid"> How can I determine the formula of an acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-chemical-formula-of-a-product"> How can I determine the chemical formula of a product? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-empirical-formula-of-a-compound"> How can I determine the empirical formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-formula-of-a-hydrate"> How can I determine the formula of a hydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-the-empirical-formula-indicate"> What does the empirical formula indicate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-molecule-with-molecular-weight-of-180-18-g-mol-is-analyzed-and-found-to-contai"> A molecule with molecular weight of 180.18 g/mol is analyzed and found to contain 40.00% carbon,... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/do-i-need-to-know-the-number-of-moles-of-each-element-to-determine-the-formula-o"> Do I need to know the number of moles of each element to determine the formula of the compound? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/determining-formula-and-molar-masses"> See all questions in Determining Formula </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1429 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the 2-methyl cyclopentanone condensed formula?	null
714	ac5c6807-6ddd-11ea-94db-ccda262736ce	https://socratic.org/questions/what-is-the-pressure-of-4-moles-of-helium-in-a-50-l-tank-at-308-k	2.02 atm	start physical_unit 8 8 pressure atm qc_end physical_unit 8 8 5 6 mole qc_end physical_unit 8 8 11 12 volume qc_end physical_unit 8 8 15 16 temperature qc_end end	[{"type":"physical unit","value":"Pressure [OF] helium [IN] atm"}]	[{"type":"physical unit","value":"2.02 atm"}]	[{"type":"physical unit","value":"Mole [OF] helium [=] \\pu{4 moles}"},{"type":"physical unit","value":"Volume [OF] helium [=] \\pu{50 L}"},{"type":"physical unit","value":"Temperature [OF] helium [=] \\pu{308 K}"}]	<h1 class="questionTitle" itemprop="name">What is the pressure of 4 moles of helium in a 50 L tank at 308 K?</h1>	null	2.02 atm	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We assume ideality, and from the Ideal Gas Equation, </p> <p><mathjax>#P=(nRT)/V=(4molxx0.0821(Latm)/(Kmol)xx308K)/(50L)#</mathjax></p> <p><mathjax>#~=#</mathjax> <mathjax>#2*atm#</mathjax>.</p> <p>The difficult part of this equation is to select the appropriate gas constant, with the appropriate units. Fortunately, in any examination, several Gas constants, with a selection of appropriate units, will be supplied. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#P~=2atm#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We assume ideality, and from the Ideal Gas Equation, </p> <p><mathjax>#P=(nRT)/V=(4molxx0.0821(Latm)/(Kmol)xx308K)/(50L)#</mathjax></p> <p><mathjax>#~=#</mathjax> <mathjax>#2atm#</mathjax>.</p> <p>The difficult part of this equation is to select the appropriate gas constant, with the appropriate units. Fortunately, in any examination, several Gas constants, with a selection of appropriate units, will be supplied. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the pressure of 4 moles of helium in a 50 L tank at 308 K?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/ideal-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Ideal Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="374524" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-02-07T07:54:28" itemprop="dateCreated"> Feb 7, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#P~=2atm#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We assume ideality, and from the Ideal Gas Equation, </p> <p><mathjax>#P=(nRT)/V=(4molxx0.0821(Latm)/(Kmol)xx308K)/(50L)#</mathjax></p> <p><mathjax>#~=#</mathjax> <mathjax>#2atm#</mathjax>.</p> <p>The difficult part of this equation is to select the appropriate gas constant, with the appropriate units. Fortunately, in any examination, several Gas constants, with a selection of appropriate units, will be supplied. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/374524" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-ideal-gas-constant"> How do you find the ideal gas constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-solve-ideal-gas-law-problems"> How do you solve ideal gas law problems? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-know-which-ideal-gas-constant-to-use"> How do you know which ideal gas constant to use? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ideal-gas-constant-for-butane"> What is the ideal gas constant for butane? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-ideal-gas-law-in-kelvin"> Why is ideal gas law in kelvin? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ideal-gas-constant-important"> Why is the ideal gas constant important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-di-electric-constant"> What is the di-electric constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-volume-l-will-0-20-mol-hi-occupy-at-300-k-and-100-0-kpa-r-8-314-kpa-l-k-mol"> What volume (L) will 0.20 mol HI occupy at 300 K and 100.0 kPa? R = 8.314 kPa L / (K mol) =... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-molar-mass-of-a-gas"> How do you calculate the molar mass of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-should-i-use-the-ideal-gas-law-and-not-the-combined-gas-law"> When should I use the ideal gas law and not the combined gas law? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/ideal-gas-law"> See all questions in Ideal Gas Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3573 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the pressure of 4 moles of helium in a 50 L tank at 308 K?	null
715	ac108868-6ddd-11ea-8db5-ccda262736ce	https://socratic.org/questions/what-is-the-chemical-form-for-potassium-dichromate	K2Cr2O7	start chemical_formula qc_end substance 6 7 qc_end end	[{"type":"other","value":"Chemical Formula [OF] potassium dichromate [IN] default"}]	[{"type":"chemical equation","value":"K2Cr2O7"}]	[{"type":"substance name","value":"Potassium dichromate"}]	<h1 class="questionTitle" itemprop="name">What is the chemical form for potassium dichromate?</h1>	null	K2Cr2O7	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is an orange crystalline powder that is a potent oxidant; it does not tend to absorb atmospheric moisture. <mathjax>#Cr#</mathjax> is in the <mathjax>#VI+#</mathjax> oxidation state. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#K_2Cr_2O_7#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is an orange crystalline powder that is a potent oxidant; it does not tend to absorb atmospheric moisture. <mathjax>#Cr#</mathjax> is in the <mathjax>#VI+#</mathjax> oxidation state. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the chemical form for potassium dichromate?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#ionic-bonds-and-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Ionic Bonds</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/ionic-bonds-and-formulas/writing-ionic-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Writing Ionic Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="284752" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-04T21:03:36" itemprop="dateCreated"> Jul 4, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#K_2Cr_2O_7#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is an orange crystalline powder that is a potent oxidant; it does not tend to absorb atmospheric moisture. <mathjax>#Cr#</mathjax> is in the <mathjax>#VI+#</mathjax> oxidation state. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/284752" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-write-ionic-formulas-for-binary-compounds"> How do you write ionic formulas for binary compounds? 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716	acad191f-6ddd-11ea-b234-ccda262736ce	https://socratic.org/questions/how-would-you-balance-the-following-equation-zn-s-zns	Zn + S -> ZnS	start chemical_equation qc_end chemical_equation 7 11 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the following equation"}]	[{"type":"chemical equation","value":"Zn + S -> ZnS"}]	[{"type":"chemical equation","value":"Zn + S -> ZnS"}]	<h1 class="questionTitle" itemprop="name">How would you balance the following equation: Zn + S --> ZnS? </h1>	null	Zn + S -> ZnS	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is something that you should be able to get quite good at it. If you made a purchase, and presented the cashier with a large denomination banknote, the value of your purchase + the value of your change MUST equal the value of the banknote. This is something we do every day, and every time we make an electronic transaction; your account is <em>debited</em> with the <em>same</em> amount of money that the shopkeeper is <em>credited</em> . All of these are examples of <em><a href="http://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a></em>, which simply means in the right measure. For every reactant particle, there must be a corresponding product particle.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Zn + S rarr ZnS#</mathjax></p> <p>Do I win 5 lbs?</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is something that you should be able to get quite good at it. If you made a purchase, and presented the cashier with a large denomination banknote, the value of your purchase + the value of your change MUST equal the value of the banknote. This is something we do every day, and every time we make an electronic transaction; your account is <em>debited</em> with the <em>same</em> amount of money that the shopkeeper is <em>credited</em> . All of these are examples of <em><a href="http://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a></em>, which simply means in the right measure. For every reactant particle, there must be a corresponding product particle.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How would you balance the following equation: Zn + S --> ZnS? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="181053" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-10-29T19:15:41" itemprop="dateCreated"> Oct 29, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Zn + S rarr ZnS#</mathjax></p> <p>Do I win 5 lbs?</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is something that you should be able to get quite good at it. If you made a purchase, and presented the cashier with a large denomination banknote, the value of your purchase + the value of your change MUST equal the value of the banknote. This is something we do every day, and every time we make an electronic transaction; your account is <em>debited</em> with the <em>same</em> amount of money that the shopkeeper is <em>credited</em> . All of these are examples of <em><a href="http://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a></em>, which simply means in the right measure. For every reactant particle, there must be a corresponding product particle.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/181053" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------> H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -> Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? 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Sodium phosphate and calcium chloride react to form... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-equation-kclo3-kcl-o2"> How can I balance this equation? ____ #KClO_3 -># ____ #KCl +# ____ #O_2# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-balancing-chemical-equations-important"> Why is balancing chemical equations important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/balancing-chemical-equations"> See all questions in Balancing Chemical Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3803 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How would you balance the following equation: Zn + S --> ZnS?	null
717	a89328e2-6ddd-11ea-bc7e-ccda262736ce	https://socratic.org/questions/580a1a197c014951e661520f	CnH2n	start chemical_formula qc_end substance 6 6 qc_end end	[{"type":"other","value":"Chemical Formula [OF] cycloalkanes [IN] default"}]	[{"type":"chemical equation","value":"CnH2n"}]	[{"type":"substance name","value":"Cycloalkanes"}]	<h1 class="questionTitle" itemprop="name">What is the general formula for cycloalkanes?</h1>	null	CnH2n	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>On the other hand, the general formula of an alkane is <mathjax>#C_nH_(2n+2)#</mathjax>. In cycloalkanes, the ring junction, the extra <mathjax>#C-C#</mathjax> bond has reduced the hydrogen count by <mathjax>#2#</mathjax>. </p> <p>Chemists speak of degrees of unsaturation with respect to organic formulae. Alkanes are conceived to be saturated, and each 2 hydrogens less than the saturated formula corresponds to a so-called <mathjax>#"degree of unsaturation"#</mathjax>. See <a href="https://socratic.org/questions/how-do-you-classify-alkanes-alkenes-and-alkynes">here</a> for further explanation. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The general formula for a cycloalkane is <mathjax>#C_nH_(2n)#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>On the other hand, the general formula of an alkane is <mathjax>#C_nH_(2n+2)#</mathjax>. In cycloalkanes, the ring junction, the extra <mathjax>#C-C#</mathjax> bond has reduced the hydrogen count by <mathjax>#2#</mathjax>. </p> <p>Chemists speak of degrees of unsaturation with respect to organic formulae. Alkanes are conceived to be saturated, and each 2 hydrogens less than the saturated formula corresponds to a so-called <mathjax>#"degree of unsaturation"#</mathjax>. See <a href="https://socratic.org/questions/how-do-you-classify-alkanes-alkenes-and-alkynes">here</a> for further explanation. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the general formula for cycloalkanes?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#organic-chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Organic Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/organic-chemistry/naming-alkanes-alkenes-and-alkynes" itemprop="url"> <span class="breadcrumb" itemprop="title">Naming Alkanes, Alkenes, and Alkynes</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="325829" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-10-24T07:34:44" itemprop="dateCreated"> Oct 24, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The general formula for a cycloalkane is <mathjax>#C_nH_(2n)#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>On the other hand, the general formula of an alkane is <mathjax>#C_nH_(2n+2)#</mathjax>. In cycloalkanes, the ring junction, the extra <mathjax>#C-C#</mathjax> bond has reduced the hydrogen count by <mathjax>#2#</mathjax>. </p> <p>Chemists speak of degrees of unsaturation with respect to organic formulae. Alkanes are conceived to be saturated, and each 2 hydrogens less than the saturated formula corresponds to a so-called <mathjax>#"degree of unsaturation"#</mathjax>. See <a href="https://socratic.org/questions/how-do-you-classify-alkanes-alkenes-and-alkynes">here</a> for further explanation. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/325829" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-name-branched-chain-alkanes"> How do you name branched chain alkanes? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-name-branched-alkanes"> How do you name branched alkanes? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-name-alkanes-from-newman-projections"> How do you name alkanes from Newman projections? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-name-alkanes-with-double-bonds"> How do you name alkanes with double bonds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-name-alkanes-with-halogens"> How do you name alkanes with halogens? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-name-alkenes-with-two-double-bonds"> How do you name alkenes with two double bonds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-name-alkenes-using-systematic-names"> How do you name alkenes using systematic names? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-name-alkenes-with-alcohols"> How do you name alkenes with alcohols? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-name-alkenes-with-double-bonds"> How do you name alkenes with double bonds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-name-alkynes-with-two-triple-bonds"> How do you name alkynes with two triple bonds? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/organic-chemistry/naming-alkanes-alkenes-and-alkynes"> See all questions in Naming Alkanes, Alkenes, and Alkynes </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 8901 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the general formula for cycloalkanes?	null
718	aaaf6d79-6ddd-11ea-a2ca-ccda262736ce	https://socratic.org/questions/what-is-the-overall-equation-for-the-reaction-which-occurs-when-chlorine-is-bubb	SO2(g) + Cl(g) -> SO2Cl2(l)	start chemical_equation qc_end substance 11 11 qc_end substance 15 17 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the overall equation"}]	[{"type":"chemical equation","value":"SO2(g) + Cl(g) -> SO2Cl2(l)"}]	[{"type":"substance name","value":"Chlorine"},{"type":"substance name","value":"Aqueous sulphur dioxide"}]	<h1 class="questionTitle" itemprop="name">What is the overall equation for the reaction which occurs when chlorine is bubbled into aqueous sulphur dioxide?</h1>	null	SO2(g) + Cl(g) -> SO2Cl2(l)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And so we get a <mathjax>#S(VI+)#</mathjax> compound, whose formation typically requires catalysis, i.e.</p> <p><mathjax>#SO_2(g) + Cl_2(g) stackrel("activated carbon")rarrSO_2Cl_2(l)#</mathjax></p> <p>Is this a redox reaction? Why or why not?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Would we not get <mathjax>#"sulfuryl chloride"#</mathjax>, <mathjax>#SO_2Cl_2#</mathjax>?</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And so we get a <mathjax>#S(VI+)#</mathjax> compound, whose formation typically requires catalysis, i.e.</p> <p><mathjax>#SO_2(g) + Cl_2(g) stackrel("activated carbon")rarrSO_2Cl_2(l)#</mathjax></p> <p>Is this a redox reaction? Why or why not?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the overall equation for the reaction which occurs when chlorine is bubbled into aqueous sulphur dioxide?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="647077" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-08-13T12:18:30" itemprop="dateCreated"> Aug 13, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Would we not get <mathjax>#"sulfuryl chloride"#</mathjax>, <mathjax>#SO_2Cl_2#</mathjax>?</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And so we get a <mathjax>#S(VI+)#</mathjax> compound, whose formation typically requires catalysis, i.e.</p> <p><mathjax>#SO_2(g) + Cl_2(g) stackrel("activated carbon")rarrSO_2Cl_2(l)#</mathjax></p> <p>Is this a redox reaction? Why or why not?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/647077" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-equation-for-photosynthesis"> What is the chemical equation for photosynthesis? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-know-the-relative-number-of-grams-of-each-substance-used-or-produced-w"> How can I know the relative number of grams of each substance used or produced with chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-know-the-relative-number-of-moles-of-each-substance-with-chemical-equa"> How can I know the relative number of moles of each substance with chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-chemical-equations-illustrate-that-atoms-are-conserved-1"> How do chemical equations illustrate that atoms are conserved? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-know-the-formula-of-the-reactants-and-products-with-chemical-equations"> How can I know the formula of the reactants and products with chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-potassium-metal-and-chlorine-gas-combi"> How can I balance this chemical equations? 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719	ab5514dc-6ddd-11ea-ac42-ccda262736ce	https://socratic.org/questions/how-much-heat-is-required-to-warm-1-60-kg-of-sand-from-22-c-to-100-c	3.62 × 10^4 J	start physical_unit 10 10 heat_energy j qc_end physical_unit 10 10 7 8 mass qc_end physical_unit 10 10 12 13 temperature qc_end physical_unit 10 10 15 16 temperature qc_end end	[{"type":"physical unit","value":"Required heat [OF] sand [IN] J"}]	[{"type":"physical unit","value":"3.62 × 10^4 J"}]	[{"type":"physical unit","value":"Mass [OF] sand [=] \\pu{1.60 kg}"},{"type":"physical unit","value":"Temperature1 [OF] sand [=] \\pu{22 ℃}"},{"type":"physical unit","value":"Temperature2 [OF] sand [=] \\pu{100 ℃}"}]	<h1 class="questionTitle" itemprop="name">How much heat is required to warm 1.60 kg of sand from 22°C to 100°C?</h1>	null	3.62 × 10^4 J	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> capacity for sand, <mathjax>#c#</mathjax>, is <mathjax>#"0.290 J/g"^@"C"#</mathjax>.<br/> <a href="http://www2.ucdsb.on.ca/tiss/stretton/database/Specific_Heat_Capacity_Table.html" rel="nofollow" target="_blank">http://www2.ucdsb.on.ca/tiss/stretton/database/Specific_Heat_Capacity_Table.html</a></p> <p>The equation for determining the heat required to increase the temperature of the sand is <mathjax>#Q=cmDeltaT#</mathjax>, where <mathjax>#Q#</mathjax> is heat energy in Joules, <mathjax>#m#</mathjax> is mass in grams, <mathjax>#c#</mathjax> is specific heat capacity, and <mathjax>#Delta T#</mathjax> is the change in temperature, <mathjax>#(T_"final"-T_"initial")#</mathjax>.</p> <p><mathjax>#Delta T=(100^@"C")-(22^@"C")=78^@"C"#</mathjax></p> <p>Mass of sand in grams:</p> <p><mathjax>#1.60cancel"kg"xx(1000"g")/(1cancel"kg")="1600 g"#</mathjax></p> <p>Substitute the given values into the equation.</p> <p><mathjax>#Q=(0.290"J/g"^@"C")xx(1600"g")xx(78^@"C")="36000 J"#</mathjax> (rounded to two significant figures)</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The energy required to heat the sand by <mathjax>#78^@"C"#</mathjax> is <mathjax>#~~#</mathjax><mathjax>#"36000 J"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> capacity for sand, <mathjax>#c#</mathjax>, is <mathjax>#"0.290 J/g"^@"C"#</mathjax>.<br/> <a href="http://www2.ucdsb.on.ca/tiss/stretton/database/Specific_Heat_Capacity_Table.html" rel="nofollow" target="_blank">http://www2.ucdsb.on.ca/tiss/stretton/database/Specific_Heat_Capacity_Table.html</a></p> <p>The equation for determining the heat required to increase the temperature of the sand is <mathjax>#Q=cmDeltaT#</mathjax>, where <mathjax>#Q#</mathjax> is heat energy in Joules, <mathjax>#m#</mathjax> is mass in grams, <mathjax>#c#</mathjax> is specific heat capacity, and <mathjax>#Delta T#</mathjax> is the change in temperature, <mathjax>#(T_"final"-T_"initial")#</mathjax>.</p> <p><mathjax>#Delta T=(100^@"C")-(22^@"C")=78^@"C"#</mathjax></p> <p>Mass of sand in grams:</p> <p><mathjax>#1.60cancel"kg"xx(1000"g")/(1cancel"kg")="1600 g"#</mathjax></p> <p>Substitute the given values into the equation.</p> <p><mathjax>#Q=(0.290"J/g"^@"C")xx(1600"g")xx(78^@"C")="36000 J"#</mathjax> (rounded to two significant figures)</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How much heat is required to warm 1.60 kg of sand from 22°C to 100°C?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/calorimetry" itemprop="url"> <span class="breadcrumb" itemprop="title">Calorimetry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="261582" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-03T03:40:00" itemprop="dateCreated"> May 3, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The energy required to heat the sand by <mathjax>#78^@"C"#</mathjax> is <mathjax>#~~#</mathjax><mathjax>#"36000 J"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> capacity for sand, <mathjax>#c#</mathjax>, is <mathjax>#"0.290 J/g"^@"C"#</mathjax>.<br/> <a href="http://www2.ucdsb.on.ca/tiss/stretton/database/Specific_Heat_Capacity_Table.html" rel="nofollow" target="_blank">http://www2.ucdsb.on.ca/tiss/stretton/database/Specific_Heat_Capacity_Table.html</a></p> <p>The equation for determining the heat required to increase the temperature of the sand is <mathjax>#Q=cmDeltaT#</mathjax>, where <mathjax>#Q#</mathjax> is heat energy in Joules, <mathjax>#m#</mathjax> is mass in grams, <mathjax>#c#</mathjax> is specific heat capacity, and <mathjax>#Delta T#</mathjax> is the change in temperature, <mathjax>#(T_"final"-T_"initial")#</mathjax>.</p> <p><mathjax>#Delta T=(100^@"C")-(22^@"C")=78^@"C"#</mathjax></p> <p>Mass of sand in grams:</p> <p><mathjax>#1.60cancel"kg"xx(1000"g")/(1cancel"kg")="1600 g"#</mathjax></p> <p>Substitute the given values into the equation.</p> <p><mathjax>#Q=(0.290"J/g"^@"C")xx(1600"g")xx(78^@"C")="36000 J"#</mathjax> (rounded to two significant figures)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/261582" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-differential-scanning-in-calorimetry-work"> How does differential scanning in calorimetry work? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-read-differential-scanning-in-calorimetry"> What information do you get from a differential scanning calorimetry plot? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-measure-calorimetry"> How do you measure calorimetry? </a> </div> </li> <li 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from 22°C to 100°C?	null
720	aa0d7787-6ddd-11ea-ae2c-ccda262736ce	https://socratic.org/questions/what-is-the-molar-mass-of-benzene	78.11 g/mol	start physical_unit 6 6 molar_mass g/mol qc_end substance 6 6 qc_end end	[{"type":"physical unit","value":"Molar mass [OF] benzene [IN] g/mol"}]	[{"type":"physical unit","value":"78.11 g/mol"}]	[{"type":"substance name","value":"Benzene"}]	<h1 class="questionTitle" itemprop="name">What is the molar mass of benzene?</h1>	null	78.11 g/mol	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To find the <strong>molar mass</strong> of a compound, we first look at a <strong>periodic table</strong> to find the molar masses of each <strong>element</strong> in the compound:</p> <blockquote> <p><img alt="sciencenotes.org" src="https://useruploads.socratic.org/xPCmCXlISxq37QrHLvVU_NoNamePeriodicTable.png"/> </p> <blockquote></blockquote> </blockquote> <p>The chemical formula for benzene is</p> <blockquote> <p><mathjax>#ul("C"_6"H"_6#</mathjax></p> </blockquote> <p>So we need only look at the values for <strong>carbon</strong> and <strong>hydrogen</strong>.</p> <blockquote> <p><img alt="cafepress.com" src="http://i3.cpcache.com/product/709484950/elements_6_carbon_tile_coaster.jpg?width=750&height=750&Filters=%5B%7B%22name%22%3A%22background%22%2C%22value%22%3A%22F2F2F2%22%2C%22sequence%22%3A2%7D%5D"/> </p> <p><img alt="cafepress.com" src="http://i3.cpcache.com/product/1451373259/periodic_table_hydrogen_tile_coaster.jpg?width=750&height=750&Filters=%5B%7B%22name%22%3A%22background%22%2C%22value%22%3A%22F2F2F2%22%2C%22sequence%22%3A2%7D%5D"/></p> </blockquote> <p>We find that the molar masses are</p> <ul> <li> <p><mathjax>#"C":#</mathjax> <mathjax>#12.01#</mathjax> <mathjax>#"g/mol"#</mathjax></p> </li> <li> <p><mathjax>#"H":#</mathjax> <mathjax>#"1.01#</mathjax> <mathjax>#"g/mol"#</mathjax></p> </li> </ul> <p>We need to <strong>multiply</strong> these values by however many of each element there is in the compound, so we would then have</p> <ul> <li> <p><mathjax>#"C":#</mathjax> <mathjax>#12.011color(white)(l)"g/mol" xx 6 = color(red)(ul(72.066color(white)(l)"g/mol"#</mathjax></p> </li> <li> <p><mathjax>#"H":#</mathjax> <mathjax>#1.008color(white)(l)"g/mol" xx 6 = color(green)(ul(6.048color(white)(l)"g/mol"#</mathjax></p> <blockquote> <blockquote></blockquote> </blockquote> </li> </ul> <p>Finally, we <strong>add</strong> all the component <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> up:</p> <blockquote> <p><mathjax>#color(red)(72.066color(white)(l)"g/mol") + color(green)(6.048color(white)(l)"g/mol") = color(blue)(ulbar(\|stackrel(" ")(" "78.114color(white)(l)"g/mol"" ")\|)#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#78.114#</mathjax> <mathjax>#"g/mol"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To find the <strong>molar mass</strong> of a compound, we first look at a <strong>periodic table</strong> to find the molar masses of each <strong>element</strong> in the compound:</p> <blockquote> <p><img alt="sciencenotes.org" src="https://useruploads.socratic.org/xPCmCXlISxq37QrHLvVU_NoNamePeriodicTable.png"/> </p> <blockquote></blockquote> </blockquote> <p>The chemical formula for benzene is</p> <blockquote> <p><mathjax>#ul("C"_6"H"_6#</mathjax></p> </blockquote> <p>So we need only look at the values for <strong>carbon</strong> and <strong>hydrogen</strong>.</p> <blockquote> <p><img alt="cafepress.com" src="http://i3.cpcache.com/product/709484950/elements_6_carbon_tile_coaster.jpg?width=750&height=750&Filters=%5B%7B%22name%22%3A%22background%22%2C%22value%22%3A%22F2F2F2%22%2C%22sequence%22%3A2%7D%5D"/> </p> <p><img alt="cafepress.com" src="http://i3.cpcache.com/product/1451373259/periodic_table_hydrogen_tile_coaster.jpg?width=750&height=750&Filters=%5B%7B%22name%22%3A%22background%22%2C%22value%22%3A%22F2F2F2%22%2C%22sequence%22%3A2%7D%5D"/></p> </blockquote> <p>We find that the molar masses are</p> <ul> <li> <p><mathjax>#"C":#</mathjax> <mathjax>#12.01#</mathjax> <mathjax>#"g/mol"#</mathjax></p> </li> <li> <p><mathjax>#"H":#</mathjax> <mathjax>#"1.01#</mathjax> <mathjax>#"g/mol"#</mathjax></p> </li> </ul> <p>We need to <strong>multiply</strong> these values by however many of each element there is in the compound, so we would then have</p> <ul> <li> <p><mathjax>#"C":#</mathjax> <mathjax>#12.011color(white)(l)"g/mol" xx 6 = color(red)(ul(72.066color(white)(l)"g/mol"#</mathjax></p> </li> <li> <p><mathjax>#"H":#</mathjax> <mathjax>#1.008color(white)(l)"g/mol" xx 6 = color(green)(ul(6.048color(white)(l)"g/mol"#</mathjax></p> <blockquote> <blockquote></blockquote> </blockquote> </li> </ul> <p>Finally, we <strong>add</strong> all the component <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> up:</p> <blockquote> <p><mathjax>#color(red)(72.066color(white)(l)"g/mol") + color(green)(6.048color(white)(l)"g/mol") = color(blue)(ulbar(\|stackrel(" ")(" "78.114color(white)(l)"g/mol"" ")\|)#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the molar mass of benzene?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="462573" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/mrtas"><img alt="" class="" src="https://profilepictures.socratic.org/HY14X7r4S6AyDQgK2gwQ_IMG_0062.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/mrtas"> Nathan L. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-10T22:33:14" itemprop="dateCreated"> Aug 10, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#78.114#</mathjax> <mathjax>#"g/mol"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To find the <strong>molar mass</strong> of a compound, we first look at a <strong>periodic table</strong> to find the molar masses of each <strong>element</strong> in the compound:</p> <blockquote> <p><img alt="sciencenotes.org" src="https://useruploads.socratic.org/xPCmCXlISxq37QrHLvVU_NoNamePeriodicTable.png"/> </p> <blockquote></blockquote> </blockquote> <p>The chemical formula for benzene is</p> <blockquote> <p><mathjax>#ul("C"_6"H"_6#</mathjax></p> </blockquote> <p>So we need only look at the values for <strong>carbon</strong> and <strong>hydrogen</strong>.</p> <blockquote> <p><img alt="cafepress.com" src="http://i3.cpcache.com/product/709484950/elements_6_carbon_tile_coaster.jpg?width=750&height=750&Filters=%5B%7B%22name%22%3A%22background%22%2C%22value%22%3A%22F2F2F2%22%2C%22sequence%22%3A2%7D%5D"/> </p> <p><img alt="cafepress.com" src="http://i3.cpcache.com/product/1451373259/periodic_table_hydrogen_tile_coaster.jpg?width=750&height=750&Filters=%5B%7B%22name%22%3A%22background%22%2C%22value%22%3A%22F2F2F2%22%2C%22sequence%22%3A2%7D%5D"/></p> </blockquote> <p>We find that the molar masses are</p> <ul> <li> <p><mathjax>#"C":#</mathjax> <mathjax>#12.01#</mathjax> <mathjax>#"g/mol"#</mathjax></p> </li> <li> <p><mathjax>#"H":#</mathjax> <mathjax>#"1.01#</mathjax> <mathjax>#"g/mol"#</mathjax></p> </li> </ul> <p>We need to <strong>multiply</strong> these values by however many of each element there is in the compound, so we would then have</p> <ul> <li> <p><mathjax>#"C":#</mathjax> <mathjax>#12.011color(white)(l)"g/mol" xx 6 = color(red)(ul(72.066color(white)(l)"g/mol"#</mathjax></p> </li> <li> <p><mathjax>#"H":#</mathjax> <mathjax>#1.008color(white)(l)"g/mol" xx 6 = color(green)(ul(6.048color(white)(l)"g/mol"#</mathjax></p> <blockquote> <blockquote></blockquote> </blockquote> </li> </ul> <p>Finally, we <strong>add</strong> all the component <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> up:</p> <blockquote> <p><mathjax>#color(red)(72.066color(white)(l)"g/mol") + color(green)(6.048color(white)(l)"g/mol") = color(blue)(ulbar(\|stackrel(" ")(" "78.114color(white)(l)"g/mol"" ")\|)#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/462573" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li 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moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 114914 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the molar mass of benzene?	null
721	a972dae8-6ddd-11ea-b597-ccda262736ce	https://socratic.org/questions/what-is-the-h-concentration-for-an-aqueous-solution-with-poh-3-05-at-25-c	1.12 × 10^(-11) M	start physical_unit 3 3 concentration mol/l qc_end physical_unit 7 8 12 12 poh qc_end physical_unit 7 8 14 15 temperature qc_end end	[{"type":"physical unit","value":"concentration [OF] H+ [IN] M"}]	[{"type":"physical unit","value":"1.12 × 10^(-11) M"}]	[{"type":"physical unit","value":"pOH [OF] the aqueous solution [=] \\pu{3.05}"},{"type":"physical unit","value":"Temperature [OF] the aqueous solution [=] \\pu{25 ℃}"}]	<h1 class="questionTitle" itemprop="name">What is the #H^+# concentration for an aqueous solution with pOH = 3.05 at 25°C?</h1>	null	1.12 × 10^(-11) M	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#pH=-log(H^+)#</mathjax></p> <p>Now, what is <mathjax>#H^+#</mathjax> if your pH is 10.95 (since pH+pOH=14, your pH=10.95).</p> <p><mathjax>#(H^+)=10^(-10.95)#</mathjax></p> <p><mathjax>#(H^+)=1.122*10^-11#</mathjax></p> <p>This is your hydrogen ion concentration: <mathjax>#[H^+]=0.00000000001122#</mathjax> mol/L</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>If pOH is 3.05, <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> is 10.95 or <mathjax>#[H^+]=1.12210^-11#</mathjax> mol/L</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#pH=-log(H^+)#</mathjax></p> <p>Now, what is <mathjax>#H^+#</mathjax> if your pH is 10.95 (since pH+pOH=14, your pH=10.95).</p> <p><mathjax>#(H^+)=10^(-10.95)#</mathjax></p> <p><mathjax>#(H^+)=1.12210^-11#</mathjax></p> <p>This is your hydrogen ion concentration: <mathjax>#[H^+]=0.00000000001122#</mathjax> mol/L</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the #H^+# concentration for an aqueous solution with pOH = 3.05 at 25°C?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/ph-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">pH calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="412523" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/g-ozdilek"><img alt="" class="" src="https://profilepictures.socratic.org/KVknsUYQYSYlmT2ycLuw_kentkonseyi-%287%29HGO.jpg" title=""/></a> <a class="secondContributorPic" href="/users/martin-m-2"><img alt="" class="" src="https://profilepictures.socratic.org/f0sDBdFaTJCkuFNIfZjD_Profielfoto.PNG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/g-ozdilek"> G_Ozdilek </a>·<a class="topContributorLink" href="/users/martin-m-2"> Martin M. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-25T12:32:38" itemprop="dateCreated"> Apr 25, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>If pOH is 3.05, <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> is 10.95 or <mathjax>#[H^+]=1.12210^-11#</mathjax> mol/L</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#pH=-log(H^+)#</mathjax></p> <p>Now, what is <mathjax>#H^+#</mathjax> if your pH is 10.95 (since pH+pOH=14, your pH=10.95).</p> <p><mathjax>#(H^+)=10^(-10.95)#</mathjax></p> <p><mathjax>#(H^+)=1.12210^-11#</mathjax></p> <p>This is your hydrogen ion concentration: <mathjax>#[H^+]=0.00000000001122#</mathjax> mol/L</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/412523" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div 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href="/questions/how-can-i-calculate-the-ph-of-solution"> How can I calculate the pH of a solution? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/ph-calculations"> See all questions in pH calculations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 45051 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the #H^+# concentration for an aqueous solution with pOH = 3.05 at 25°C?	null
722	ac033dee-6ddd-11ea-b78a-ccda262736ce	https://socratic.org/questions/what-is-the-empirical-formula-of-b-3n-3h-6	BNH2	start chemical_formula qc_end chemical_equation 6 6 qc_end end	[{"type":"other","value":"Chemical Formula [OF] B3N3H6 [IN] empirical"}]	[{"type":"chemical equation","value":"BNH2"}]	[{"type":"chemical equation","value":"B3N3H6"}]	<h1 class="questionTitle" itemprop="name">What is the empirical formula of #B_3N_3H_6#?</h1>	null	BNH2	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The thing to remember about a compound's <strong>molecular formula</strong> is that it is always a <em>multiple</em> of its <strong>empirical formula</strong>. </p> <p>That is the case because the <em>empirical formula</em> tells you the <strong>smallest whole number ratio</strong> that exists between a compound's constituent <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a>. </p> <p>By comparison, the <em>molecular formula</em> tells you the <strong>exact number of atoms</strong> of each constituent element present in one molecule of said compound. </p> <p>In your case, the molecular formula is said to be </p> <blockquote> <p><mathjax>#"B"_3"N"_3"H"_6 ->#</mathjax> <em><strong>molecular formula</strong></em></p> </blockquote> <p>This tells you that one molecule of this compound contains </p> <blockquote> <ul> <li><em><strong>three atoms</strong> of boron</em>, <mathjax>#3 xx "B"#</mathjax></li> <li><em><strong>three atoms</strong> of nitrogen</em>, <mathjax>#3 xx "N"#</mathjax></li> <li><em><strong>six atoms</strong> of hydrogen</em>, <mathjax>#6 xx "H"#</mathjax></li> </ul> </blockquote> <p>Now, the <strong>smallest whole number ratio</strong> that exists between the elements is </p> <blockquote> <p><mathjax>#3 : 3 : 6 \|div 3 implies 1:1:2#</mathjax> </p> </blockquote> <p>This would make the compound's empirical formula</p> <blockquote> <p><mathjax>#"B"_1"N"_1"H"_2 implies color(green)(\|bar(ul(color(white)(a/a)color(black)("BNH"_2)color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>This means that you need <strong>three</strong> empirical formulas, <mathjax>#3 xx "BNH"_2#</mathjax>, to get the molecular formula for borazine, <mathjax>#"B"_3"N"_3"H"_6#</mathjax>.</p> <blockquote> <blockquote> <p><img alt="http://www.chemnet.com/cas/in/6569-51-3/Borazine.html" src="https://useruploads.socratic.org/66JFWrATqqgG4DcQiS7Z_cas6569-51-3.gif"/> </p> </blockquote> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"BNH"_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The thing to remember about a compound's <strong>molecular formula</strong> is that it is always a <em>multiple</em> of its <strong>empirical formula</strong>. </p> <p>That is the case because the <em>empirical formula</em> tells you the <strong>smallest whole number ratio</strong> that exists between a compound's constituent <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a>. </p> <p>By comparison, the <em>molecular formula</em> tells you the <strong>exact number of atoms</strong> of each constituent element present in one molecule of said compound. </p> <p>In your case, the molecular formula is said to be </p> <blockquote> <p><mathjax>#"B"_3"N"_3"H"_6 ->#</mathjax> <em><strong>molecular formula</strong></em></p> </blockquote> <p>This tells you that one molecule of this compound contains </p> <blockquote> <ul> <li><em><strong>three atoms</strong> of boron</em>, <mathjax>#3 xx "B"#</mathjax></li> <li><em><strong>three atoms</strong> of nitrogen</em>, <mathjax>#3 xx "N"#</mathjax></li> <li><em><strong>six atoms</strong> of hydrogen</em>, <mathjax>#6 xx "H"#</mathjax></li> </ul> </blockquote> <p>Now, the <strong>smallest whole number ratio</strong> that exists between the elements is </p> <blockquote> <p><mathjax>#3 : 3 : 6 \|div 3 implies 1:1:2#</mathjax> </p> </blockquote> <p>This would make the compound's empirical formula</p> <blockquote> <p><mathjax>#"B"_1"N"_1"H"_2 implies color(green)(\|bar(ul(color(white)(a/a)color(black)("BNH"_2)color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>This means that you need <strong>three</strong> empirical formulas, <mathjax>#3 xx "BNH"_2#</mathjax>, to get the molecular formula for borazine, <mathjax>#"B"_3"N"_3"H"_6#</mathjax>.</p> <blockquote> <blockquote> <p><img alt="http://www.chemnet.com/cas/in/6569-51-3/Borazine.html" src="https://useruploads.socratic.org/66JFWrATqqgG4DcQiS7Z_cas6569-51-3.gif"/> </p> </blockquote> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the empirical formula of #B_3N_3H_6#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="285834" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-07T20:31:49" itemprop="dateCreated"> Jul 7, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"BNH"_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The thing to remember about a compound's <strong>molecular formula</strong> is that it is always a <em>multiple</em> of its <strong>empirical formula</strong>. </p> <p>That is the case because the <em>empirical formula</em> tells you the <strong>smallest whole number ratio</strong> that exists between a compound's constituent <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a>. </p> <p>By comparison, the <em>molecular formula</em> tells you the <strong>exact number of atoms</strong> of each constituent element present in one molecule of said compound. </p> <p>In your case, the molecular formula is said to be </p> <blockquote> <p><mathjax>#"B"_3"N"_3"H"_6 ->#</mathjax> <em><strong>molecular formula</strong></em></p> </blockquote> <p>This tells you that one molecule of this compound contains </p> <blockquote> <ul> <li><em><strong>three atoms</strong> of boron</em>, <mathjax>#3 xx "B"#</mathjax></li> <li><em><strong>three atoms</strong> of nitrogen</em>, <mathjax>#3 xx "N"#</mathjax></li> <li><em><strong>six atoms</strong> of hydrogen</em>, <mathjax>#6 xx "H"#</mathjax></li> </ul> </blockquote> <p>Now, the <strong>smallest whole number ratio</strong> that exists between the elements is </p> <blockquote> <p><mathjax>#3 : 3 : 6 \|div 3 implies 1:1:2#</mathjax> </p> </blockquote> <p>This would make the compound's empirical formula</p> <blockquote> <p><mathjax>#"B"_1"N"_1"H"_2 implies color(green)(\|bar(ul(color(white)(a/a)color(black)("BNH"_2)color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>This means that you need <strong>three</strong> empirical formulas, <mathjax>#3 xx "BNH"_2#</mathjax>, to get the molecular formula for borazine, <mathjax>#"B"_3"N"_3"H"_6#</mathjax>.</p> <blockquote> <blockquote> <p><img alt="http://www.chemnet.com/cas/in/6569-51-3/Borazine.html" src="https://useruploads.socratic.org/66JFWrATqqgG4DcQiS7Z_cas6569-51-3.gif"/> </p> </blockquote> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/285834" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molecular-formula-of-a-compound"> How do you find molecular formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-diamond"> What is the chemical formula of a diamond? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" 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class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the empirical formula of #B_3N_3H_6#?	null
723	a993d112-6ddd-11ea-a5c3-ccda262736ce	https://socratic.org/questions/what-is-the-mass-in-grams-of-9-357-10-30-atoms-of-iron	8.68 × 10^8 grams	start physical_unit 12 12 mass g qc_end end	[{"type":"physical unit","value":"Mass [OF] iron [IN] grams"}]	[{"type":"physical unit","value":"8.68 × 10^8 grams"}]	[{"type":"physical unit","value":"Number [OF] iron atoms [=] \\pu{9.357 × 10^30}"}]	<h1 class="questionTitle" itemprop="name">What is the mass in grams of #9.357 * 10^30# atoms of iron?</h1>	null	8.68 × 10^8 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>An interesting approach to use here is to use iron's <strong>molar mass</strong> and <strong>Avogadro's number</strong> to find the mass of a <strong>single atom</strong> of iron, which you can then be used as a conversion factor to find the mass of <mathjax>#9.357 * 10^(30)#</mathjax> <strong>atoms</strong>. </p> <blockquote> <p><mathjax>#"mass of one mole " stackrel(color(red)(1)color(white)(aa))(->) " mass of one atom " stackrel(color(purple)(2)color(white)(aa))(->) " mass of"color(white)(a) 9.357 * 10^(30)"atoms"#</mathjax></p> </blockquote> <p><mathjax>#color(white)()#</mathjax><br/> <mathjax>#color(red)(1.)#</mathjax> </p> <p>The mass of <strong>one mole</strong> of any element is given by its <strong>molar mass</strong>. Iron has a molar mass of <mathjax>#"55.845 g mol"^(-1)#</mathjax>, which means that <strong>every mole</strong> of iron has mass of <mathjax>#"55.845 g"#</mathjax>. </p> <p>Now, <strong>one mole</strong> of any element is defined as <mathjax>#6.022 * 10^(23)#</mathjax> <strong>atoms</strong> of that element -- this is known as <strong>Avogadro's number</strong>. </p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a)"1 mole" = 6.022 * 10^(23)"atoms"color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>So, if <strong>one mole</strong> of iron contains <mathjax>#6.022 * 10^(23)#</mathjax> <strong>atoms</strong> of iron, and if the mass of one mole if <mathjax>#"55.845 g"#</mathjax>, it follows that the mass of <strong>one atom</strong> of iron will be </p> <blockquote> <p><mathjax>#1 color(red)(cancel(color(black)("atom Fe"))) * "55.845 g"/(6.022 * 10^(23)color(red)(cancel(color(black)("atoms Fe")))) = 9.2735 * 10^(-23)"g"#</mathjax></p> </blockquote> <p><mathjax>#color(white)()#</mathjax><br/> <mathjax>#color(purple)(2.)#</mathjax></p> <p>Now that you know the mass of <strong>one atom</strong>, you can use it to find the mass of <mathjax>#9.357 * 10^(30)#</mathjax> <strong>atoms</strong></p> <blockquote> <p><mathjax>#9.357 * 10^(30)color(purple)(cancel(color(black)("atoms Fe"))) * (9.2735 * 10^(-23)"g")/(1color(purple)(cancel(color(black)("atom Fe")))) = color(green)(\|bar(ul(color(white)(a/a)color(black)(8.677 * 10^8"g")color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer is rounded to four <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>. </p> <p><mathjax>#color(white)()#</mathjax><br/> <strong>ALTERNATIVE APPROACH</strong></p> <p>You can also find the answer by converting the number of atoms of iron to <em>moles</em> with the help of Avogadro's number, then by using iron's molar mass as a conversion factor. </p> <p>You will have </p> <blockquote> <p><mathjax>#9.357 * 10^(30) color(red)(cancel(color(black)("atoms Fe"))) * "1 mole Fe"/(6.022 * 10^(23)color(red)(cancel(color(black)("atoms Fe")))) = 1.5538 * 10^7"moles Fe"#</mathjax></p> </blockquote> <p>This will once again be equivalent to </p> <blockquote> <p><mathjax>#1.5538 * 10^(7)color(red)(cancel(color(black)("moles Fe"))) * "55.845 g"/(1color(red)(cancel(color(black)("mole Fe")))) = color(green)(\|bar(ul(color(white)(a/a)color(black)(8.677 * 10^8"g")color(white)(a/a)\|)))#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#8.677 * 10^(8)"g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>An interesting approach to use here is to use iron's <strong>molar mass</strong> and <strong>Avogadro's number</strong> to find the mass of a <strong>single atom</strong> of iron, which you can then be used as a conversion factor to find the mass of <mathjax>#9.357 * 10^(30)#</mathjax> <strong>atoms</strong>. </p> <blockquote> <p><mathjax>#"mass of one mole " stackrel(color(red)(1)color(white)(aa))(->) " mass of one atom " stackrel(color(purple)(2)color(white)(aa))(->) " mass of"color(white)(a) 9.357 * 10^(30)"atoms"#</mathjax></p> </blockquote> <p><mathjax>#color(white)()#</mathjax><br/> <mathjax>#color(red)(1.)#</mathjax> </p> <p>The mass of <strong>one mole</strong> of any element is given by its <strong>molar mass</strong>. Iron has a molar mass of <mathjax>#"55.845 g mol"^(-1)#</mathjax>, which means that <strong>every mole</strong> of iron has mass of <mathjax>#"55.845 g"#</mathjax>. </p> <p>Now, <strong>one mole</strong> of any element is defined as <mathjax>#6.022 * 10^(23)#</mathjax> <strong>atoms</strong> of that element -- this is known as <strong>Avogadro's number</strong>. </p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a)"1 mole" = 6.022 * 10^(23)"atoms"color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>So, if <strong>one mole</strong> of iron contains <mathjax>#6.022 * 10^(23)#</mathjax> <strong>atoms</strong> of iron, and if the mass of one mole if <mathjax>#"55.845 g"#</mathjax>, it follows that the mass of <strong>one atom</strong> of iron will be </p> <blockquote> <p><mathjax>#1 color(red)(cancel(color(black)("atom Fe"))) * "55.845 g"/(6.022 * 10^(23)color(red)(cancel(color(black)("atoms Fe")))) = 9.2735 * 10^(-23)"g"#</mathjax></p> </blockquote> <p><mathjax>#color(white)()#</mathjax><br/> <mathjax>#color(purple)(2.)#</mathjax></p> <p>Now that you know the mass of <strong>one atom</strong>, you can use it to find the mass of <mathjax>#9.357 * 10^(30)#</mathjax> <strong>atoms</strong></p> <blockquote> <p><mathjax>#9.357 * 10^(30)color(purple)(cancel(color(black)("atoms Fe"))) * (9.2735 * 10^(-23)"g")/(1color(purple)(cancel(color(black)("atom Fe")))) = color(green)(\|bar(ul(color(white)(a/a)color(black)(8.677 * 10^8"g")color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer is rounded to four <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>. </p> <p><mathjax>#color(white)()#</mathjax><br/> <strong>ALTERNATIVE APPROACH</strong></p> <p>You can also find the answer by converting the number of atoms of iron to <em>moles</em> with the help of Avogadro's number, then by using iron's molar mass as a conversion factor. </p> <p>You will have </p> <blockquote> <p><mathjax>#9.357 * 10^(30) color(red)(cancel(color(black)("atoms Fe"))) * "1 mole Fe"/(6.022 * 10^(23)color(red)(cancel(color(black)("atoms Fe")))) = 1.5538 * 10^7"moles Fe"#</mathjax></p> </blockquote> <p>This will once again be equivalent to </p> <blockquote> <p><mathjax>#1.5538 * 10^(7)color(red)(cancel(color(black)("moles Fe"))) * "55.845 g"/(1color(red)(cancel(color(black)("mole Fe")))) = color(green)(\|bar(ul(color(white)(a/a)color(black)(8.677 * 10^8"g")color(white)(a/a)\|)))#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the mass in grams of #9.357 * 10^30# atoms of iron?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="278593" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-17T23:51:40" itemprop="dateCreated"> Jun 17, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#8.677 * 10^(8)"g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>An interesting approach to use here is to use iron's <strong>molar mass</strong> and <strong>Avogadro's number</strong> to find the mass of a <strong>single atom</strong> of iron, which you can then be used as a conversion factor to find the mass of <mathjax>#9.357 * 10^(30)#</mathjax> <strong>atoms</strong>. </p> <blockquote> <p><mathjax>#"mass of one mole " stackrel(color(red)(1)color(white)(aa))(->) " mass of one atom " stackrel(color(purple)(2)color(white)(aa))(->) " mass of"color(white)(a) 9.357 * 10^(30)"atoms"#</mathjax></p> </blockquote> <p><mathjax>#color(white)()#</mathjax><br/> <mathjax>#color(red)(1.)#</mathjax> </p> <p>The mass of <strong>one mole</strong> of any element is given by its <strong>molar mass</strong>. Iron has a molar mass of <mathjax>#"55.845 g mol"^(-1)#</mathjax>, which means that <strong>every mole</strong> of iron has mass of <mathjax>#"55.845 g"#</mathjax>. </p> <p>Now, <strong>one mole</strong> of any element is defined as <mathjax>#6.022 * 10^(23)#</mathjax> <strong>atoms</strong> of that element -- this is known as <strong>Avogadro's number</strong>. </p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a)"1 mole" = 6.022 * 10^(23)"atoms"color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>So, if <strong>one mole</strong> of iron contains <mathjax>#6.022 * 10^(23)#</mathjax> <strong>atoms</strong> of iron, and if the mass of one mole if <mathjax>#"55.845 g"#</mathjax>, it follows that the mass of <strong>one atom</strong> of iron will be </p> <blockquote> <p><mathjax>#1 color(red)(cancel(color(black)("atom Fe"))) * "55.845 g"/(6.022 * 10^(23)color(red)(cancel(color(black)("atoms Fe")))) = 9.2735 * 10^(-23)"g"#</mathjax></p> </blockquote> <p><mathjax>#color(white)()#</mathjax><br/> <mathjax>#color(purple)(2.)#</mathjax></p> <p>Now that you know the mass of <strong>one atom</strong>, you can use it to find the mass of <mathjax>#9.357 * 10^(30)#</mathjax> <strong>atoms</strong></p> <blockquote> <p><mathjax>#9.357 * 10^(30)color(purple)(cancel(color(black)("atoms Fe"))) * (9.2735 * 10^(-23)"g")/(1color(purple)(cancel(color(black)("atom Fe")))) = color(green)(\|bar(ul(color(white)(a/a)color(black)(8.677 * 10^8"g")color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer is rounded to four <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>. </p> <p><mathjax>#color(white)()#</mathjax><br/> <strong>ALTERNATIVE APPROACH</strong></p> <p>You can also find the answer by converting the number of atoms of iron to <em>moles</em> with the help of Avogadro's number, then by using iron's molar mass as a conversion factor. </p> <p>You will have </p> <blockquote> <p><mathjax>#9.357 * 10^(30) color(red)(cancel(color(black)("atoms Fe"))) * "1 mole Fe"/(6.022 * 10^(23)color(red)(cancel(color(black)("atoms Fe")))) = 1.5538 * 10^7"moles Fe"#</mathjax></p> </blockquote> <p>This will once again be equivalent to </p> <blockquote> <p><mathjax>#1.5538 * 10^(7)color(red)(cancel(color(black)("moles Fe"))) * "55.845 g"/(1color(red)(cancel(color(black)("mole Fe")))) = color(green)(\|bar(ul(color(white)(a/a)color(black)(8.677 * 10^8"g")color(white)(a/a)\|)))#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/278593" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? 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724	aa3a7e11-6ddd-11ea-af17-ccda262736ce	https://socratic.org/questions/how-many-liters-of-ozone-can-be-destroyed-at-220-k-and-5-0-kpa-if-200-0-g-of-chl	2125.51 liters	start physical_unit 4 4 volume l qc_end physical_unit 4 4 9 10 temperature qc_end physical_unit 4 4 12 13 pressure qc_end physical_unit 18 19 15 16 mass qc_end chemical_equation 42 51 qc_end end	[{"type":"physical unit","value":"Volume [OF] ozone [IN] liters"}]	[{"type":"physical unit","value":"2125.51 liters"}]	[{"type":"physical unit","value":"Temperature [OF] ozone [=] \\pu{220 K}"},{"type":"physical unit","value":"Pressure [OF] ozone [=] \\pu{5.0 kPa}"},{"type":"physical unit","value":"Mass [OF] chlorine gas [=] \\pu{200.0 g}"},{"type":"chemical equation","value":"Cl2(g) + 2 O3(g) -> 2 ClO(g) + 2 O2(g)"}]	<h1 class="questionTitle" itemprop="name">How many liters of ozone can be destroyed at 220. K and 5.0 kPa if 200.0 g of chlorine gas react with it? </h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>Chlorine in the upper atmosphere can destroy ozone molecules, <mathjax>#O_3#</mathjax>. The reaction can be represented by the following equation: <mathjax>#Cl_2(g) + 2O_3(g) -> 2ClO(g) +2O_2(g)#</mathjax></p></div> </h2> </div> </div>	2125.51 liters	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>Balanced equation</strong></p> <p><mathjax>#"Cl"_2("g") + "2O"_3("g")"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"2ClO(g) + 2O"_2("g")"#</mathjax></p> <p>First we need to determine how many moles of ozone will react with <mathjax>#"200.0 g Cl"_2"#</mathjax>. Then we'll use the equation for the ideal gas law to determine the volume of ozone that will be destroyed.</p> <p>Determine mol <mathjax>#"Cl"_2"#</mathjax> by dividing its given mass by its molar mass <mathjax>#("68.9 g/mol")#</mathjax>. Do this by multiplying by the inverse of the molar mass (mol/g). Then determine mol <mathjax>#"O"_3"#</mathjax> by multiplying by the mol ratio between ozone and chlorine gas in the balanced equation, with ozone in the numerator.</p> <p><mathjax>#200.0color(red)cancel(color(black)("g Cl"_2))xx(1color(red)cancel(color(black)("mol Cl"_2)))/(68.9color(red)cancel(color(black)("g Cl"_2)))xx("mol O"_3)/(1color(red)cancel(color(black)("mol Cl"_2)))="5.81 mol O"_3"#</mathjax></p> <p><strong>Ideal gas law equation</strong></p> <p><mathjax>#PV=nRT#</mathjax></p> <p><strong>Known</strong></p> <p><mathjax>#P="5.0 kPa"#</mathjax></p> <p><mathjax>#n="5.81 mol O"_3"#</mathjax></p> <p><mathjax>#R="8.31447 L kPa K"^(-1) "mol"^(-1)"#</mathjax><br/> <a href="https://www.katmarsoftware.com/gconvals.htm" rel="nofollow" target="_blank">https://www.katmarsoftware.com/gconvals.htm</a></p> <p><mathjax>#T="220. K"#</mathjax></p> <p><strong>Unknown</strong></p> <p><mathjax>#V#</mathjax></p> <p><strong>Solution</strong></p> <p>Rearrange the equation to isolate volume, <mathjax>#V#</mathjax>. Plug in the known values and solve.</p> <p><mathjax>#V=(nRT)/P#</mathjax></p> <p><mathjax>#V=(5.81color(red)cancel(color(black)("mol"))xx8.31447" L" color(red)cancel(color(black)("kPa"))color(red)cancel(color(black)( "K"))^(-1) color(red)cancel(color(black)("mol"))^(-1)xx220color(red)cancel(color(black)("K")))/(5.0color(red)cancel(color(black)("kPa")))="2100 L"#</mathjax><br/> (rounded to two significant figures due to <mathjax>#"5.0 kPa"#</mathjax>)</p> <p><mathjax>#"200.0 g Cl"_2"#</mathjax> can destroy <mathjax>#"2100 L O"_3"#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"200.0 g Cl"_2"#</mathjax> can destroy <mathjax>#"2100 L O"_3"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>Balanced equation</strong></p> <p><mathjax>#"Cl"_2("g") + "2O"_3("g")"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"2ClO(g) + 2O"_2("g")"#</mathjax></p> <p>First we need to determine how many moles of ozone will react with <mathjax>#"200.0 g Cl"_2"#</mathjax>. Then we'll use the equation for the ideal gas law to determine the volume of ozone that will be destroyed.</p> <p>Determine mol <mathjax>#"Cl"_2"#</mathjax> by dividing its given mass by its molar mass <mathjax>#("68.9 g/mol")#</mathjax>. Do this by multiplying by the inverse of the molar mass (mol/g). Then determine mol <mathjax>#"O"_3"#</mathjax> by multiplying by the mol ratio between ozone and chlorine gas in the balanced equation, with ozone in the numerator.</p> <p><mathjax>#200.0color(red)cancel(color(black)("g Cl"_2))xx(1color(red)cancel(color(black)("mol Cl"_2)))/(68.9color(red)cancel(color(black)("g Cl"_2)))xx("mol O"_3)/(1color(red)cancel(color(black)("mol Cl"_2)))="5.81 mol O"_3"#</mathjax></p> <p><strong>Ideal gas law equation</strong></p> <p><mathjax>#PV=nRT#</mathjax></p> <p><strong>Known</strong></p> <p><mathjax>#P="5.0 kPa"#</mathjax></p> <p><mathjax>#n="5.81 mol O"_3"#</mathjax></p> <p><mathjax>#R="8.31447 L kPa K"^(-1) "mol"^(-1)"#</mathjax><br/> <a href="https://www.katmarsoftware.com/gconvals.htm" rel="nofollow" target="_blank">https://www.katmarsoftware.com/gconvals.htm</a></p> <p><mathjax>#T="220. K"#</mathjax></p> <p><strong>Unknown</strong></p> <p><mathjax>#V#</mathjax></p> <p><strong>Solution</strong></p> <p>Rearrange the equation to isolate volume, <mathjax>#V#</mathjax>. Plug in the known values and solve.</p> <p><mathjax>#V=(nRT)/P#</mathjax></p> <p><mathjax>#V=(5.81color(red)cancel(color(black)("mol"))xx8.31447" L" color(red)cancel(color(black)("kPa"))color(red)cancel(color(black)( "K"))^(-1) color(red)cancel(color(black)("mol"))^(-1)xx220color(red)cancel(color(black)("K")))/(5.0color(red)cancel(color(black)("kPa")))="2100 L"#</mathjax><br/> (rounded to two significant figures due to <mathjax>#"5.0 kPa"#</mathjax>)</p> <p><mathjax>#"200.0 g Cl"_2"#</mathjax> can destroy <mathjax>#"2100 L O"_3"#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many liters of ozone can be destroyed at 220. K and 5.0 kPa if 200.0 g of chlorine gas react with it? </h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>Chlorine in the upper atmosphere can destroy ozone molecules, <mathjax>#O_3#</mathjax>. The reaction can be represented by the following equation: <mathjax>#Cl_2(g) + 2O_3(g) -> 2ClO(g) +2O_2(g)#</mathjax></p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/gibbs-free-energy" itemprop="url"> <span class="breadcrumb" itemprop="title">Gibbs Free Energy</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="636112" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-06-27T02:46:08" itemprop="dateCreated"> Jun 27, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"200.0 g Cl"_2"#</mathjax> can destroy <mathjax>#"2100 L O"_3"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>Balanced equation</strong></p> <p><mathjax>#"Cl"_2("g") + "2O"_3("g")"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"2ClO(g) + 2O"_2("g")"#</mathjax></p> <p>First we need to determine how many moles of ozone will react with <mathjax>#"200.0 g Cl"_2"#</mathjax>. Then we'll use the equation for the ideal gas law to determine the volume of ozone that will be destroyed.</p> <p>Determine mol <mathjax>#"Cl"_2"#</mathjax> by dividing its given mass by its molar mass <mathjax>#("68.9 g/mol")#</mathjax>. Do this by multiplying by the inverse of the molar mass (mol/g). Then determine mol <mathjax>#"O"_3"#</mathjax> by multiplying by the mol ratio between ozone and chlorine gas in the balanced equation, with ozone in the numerator.</p> <p><mathjax>#200.0color(red)cancel(color(black)("g Cl"_2))xx(1color(red)cancel(color(black)("mol Cl"_2)))/(68.9color(red)cancel(color(black)("g Cl"_2)))xx("mol O"_3)/(1color(red)cancel(color(black)("mol Cl"_2)))="5.81 mol O"_3"#</mathjax></p> <p><strong>Ideal gas law equation</strong></p> <p><mathjax>#PV=nRT#</mathjax></p> <p><strong>Known</strong></p> <p><mathjax>#P="5.0 kPa"#</mathjax></p> <p><mathjax>#n="5.81 mol O"_3"#</mathjax></p> <p><mathjax>#R="8.31447 L kPa K"^(-1) "mol"^(-1)"#</mathjax><br/> <a href="https://www.katmarsoftware.com/gconvals.htm" rel="nofollow" target="_blank">https://www.katmarsoftware.com/gconvals.htm</a></p> <p><mathjax>#T="220. K"#</mathjax></p> <p><strong>Unknown</strong></p> <p><mathjax>#V#</mathjax></p> <p><strong>Solution</strong></p> <p>Rearrange the equation to isolate volume, <mathjax>#V#</mathjax>. Plug in the known values and solve.</p> <p><mathjax>#V=(nRT)/P#</mathjax></p> <p><mathjax>#V=(5.81color(red)cancel(color(black)("mol"))xx8.31447" L" color(red)cancel(color(black)("kPa"))color(red)cancel(color(black)( "K"))^(-1) color(red)cancel(color(black)("mol"))^(-1)xx220color(red)cancel(color(black)("K")))/(5.0color(red)cancel(color(black)("kPa")))="2100 L"#</mathjax><br/> (rounded to two significant figures due to <mathjax>#"5.0 kPa"#</mathjax>)</p> <p><mathjax>#"200.0 g Cl"_2"#</mathjax> can destroy <mathjax>#"2100 L O"_3"#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/636112" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-gibbs-free-energy-be-negative"> Can gibbs free energy be negative? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-enzymes-affect-gibbs-free-energy"> How do enzymes affect gibbs free energy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-gibbs-free-energy-calculated"> How is Gibbs Free Energy calculated? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-gibbs-free-energy-related-to-enthalpy-and-entropy"> How is gibbs free energy related to enthalpy and entropy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-does-gibbs-free-energy-decrease-with-temperature"> Why does gibbs free energy decrease with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-gibbs-free-energy-important"> Why is Gibbs free energy important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-does-gibbs-free-energy-have-to-be-negative"> Why does Gibbs free energy have to be negative? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-gibbs-free-energy-affected-by-a-catalyst"> Is Gibbs free energy affected by a catalyst? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-gibbs-free-energy-at-different-temperatures"> How can I calculate Gibbs free energy at different temperatures? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-gibbs-free-energy-measured"> How is Gibbs free energy measured? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/gibbs-free-energy"> See all questions in Gibbs Free Energy </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 4776 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many liters of ozone can be destroyed at 220. K and 5.0 kPa if 200.0 g of chlorine gas react with it?	Chlorine in the upper atmosphere can destroy ozone molecules, #O_3#. The reaction can be represented by the following equation: #Cl_2(g) + 2O_3(g) -> 2ClO(g) +2O_2(g)#
725	ab50dcc0-6ddd-11ea-91bb-ccda262736ce	https://socratic.org/questions/at-a-particular-temperature-a-2-00-l-flask-at-equilibrium-contains-2-80-10-4-mol	4.08 × 10^8	start physical_unit 38 38 equilibrium_constant_k none qc_end physical_unit 7 7 5 6 volume qc_end physical_unit 15 15 11 14 mole qc_end physical_unit 20 20 16 19 mole qc_end physical_unit 26 26 22 25 mole qc_end c_other OTHER qc_end chemical_equation 39 45 qc_end end	[{"type":"physical unit","value":"K [OF] the reaction"}]	[{"type":"physical unit","value":"4.08 × 10^8"}]	[{"type":"physical unit","value":"Volume [OF] flask [=] \\pu{2.00 L}"},{"type":"physical unit","value":"Mole [OF] N2 [=] \\pu{2.80 × 10^(-4) mol}"},{"type":"physical unit","value":"Mole [OF] O2 [=] \\pu{2.50 × 10^(-5) mol}"},{"type":"physical unit","value":"Mole [OF] N2O [=] \\pu{2.00 × 10^(-2) mol}"},{"type":"other","value":"Particular temperature."},{"type":"chemical equation","value":"2 N2(g) + O2(g) -> 2 N2O(g)"}]	<h1 class="questionTitle" itemprop="name">At a particular temperature a 2.00-L flask at equilibrium contains 2.80 10-4 mol N2, 2.50 10-5 mol O2, and 2.00 10-2 mol N2O. How would you calculate K at this temperature for the following reaction: 2 N2(g) + O2(g) --> 2 N2O(g)?</h1>	null	4.08 × 10^8	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"K"=(["N"_2"O"]^2)/(["N"_2]^2["O"_2])#</mathjax></p> <p>In an equilibrium reaction, the equilibrium constant <mathjax>#"K"#</mathjax> is found through taking the concentrations of the products over the concentrations of the reactants. (If you don't know why, ask.)</p> <p>The stoichiometric coefficients in the equation are used as exponents on the concentrations. (See how the equilibrium equation references <mathjax>#2"N"_2#</mathjax>, hence <mathjax>#["N"_2]^2#</mathjax> in the equilibrium constant expression.)</p> <p>To find the concentrations (molarity), divide <a href="http://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> amounts by the volume.</p> <p><mathjax>#["N"_2"O"]=(2.00xx10^-2"mol")/(2.00"L")=1.00xx10^-2"M"#</mathjax></p> <p><mathjax>#["N"_2]=(2.80xx10^-4"mol")/(2.00"L")=1.40xx10^-4"M"#</mathjax></p> <p><mathjax>#["O"_2]=(2.50xx10^-5"mol")/(2.00"L")=1.25xx10^-5"M"#</mathjax></p> <p><mathjax>#"K"=((1.00xx10^-2)^2)/((1.40xx10^-4)^2(1.25xx10^-5))=4.08xx10^8#</mathjax></p> <p>The equilibrium constant is unitless.</p> <p>An equilibrium constant <mathjax>#≫1#</mathjax> also tells us that the reaction is heavily product-favored.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#4.08xx10^8#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"K"=(["N"_2"O"]^2)/(["N"_2]^2["O"_2])#</mathjax></p> <p>In an equilibrium reaction, the equilibrium constant <mathjax>#"K"#</mathjax> is found through taking the concentrations of the products over the concentrations of the reactants. (If you don't know why, ask.)</p> <p>The stoichiometric coefficients in the equation are used as exponents on the concentrations. (See how the equilibrium equation references <mathjax>#2"N"_2#</mathjax>, hence <mathjax>#["N"_2]^2#</mathjax> in the equilibrium constant expression.)</p> <p>To find the concentrations (molarity), divide <a href="http://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> amounts by the volume.</p> <p><mathjax>#["N"_2"O"]=(2.00xx10^-2"mol")/(2.00"L")=1.00xx10^-2"M"#</mathjax></p> <p><mathjax>#["N"_2]=(2.80xx10^-4"mol")/(2.00"L")=1.40xx10^-4"M"#</mathjax></p> <p><mathjax>#["O"_2]=(2.50xx10^-5"mol")/(2.00"L")=1.25xx10^-5"M"#</mathjax></p> <p><mathjax>#"K"=((1.00xx10^-2)^2)/((1.40xx10^-4)^2(1.25xx10^-5))=4.08xx10^8#</mathjax></p> <p>The equilibrium constant is unitless.</p> <p>An equilibrium constant <mathjax>#≫1#</mathjax> also tells us that the reaction is heavily product-favored.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">At a particular temperature a 2.00-L flask at equilibrium contains 2.80 10-4 mol N2, 2.50 10-5 mol O2, and 2.00 10-2 mol N2O. How would you calculate K at this temperature for the following reaction: 2 N2(g) + O2(g) --> 2 N2O(g)?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-equilibrium" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Equilibrium</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-equilibrium/dynamic-equilibrium" itemprop="url"> <span class="breadcrumb" itemprop="title">Dynamic Equilibrium</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="200260" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/mason-m"><img alt="" class="" src="https://profilepictures.socratic.org/U70pu8hUTGGkEuy92fsO_IMG_2585.jpeg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/mason-m"> mason m </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-16T04:37:15" itemprop="dateCreated"> Dec 16, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#4.08xx10^8#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"K"=(["N"_2"O"]^2)/(["N"_2]^2["O"_2])#</mathjax></p> <p>In an equilibrium reaction, the equilibrium constant <mathjax>#"K"#</mathjax> is found through taking the concentrations of the products over the concentrations of the reactants. (If you don't know why, ask.)</p> <p>The stoichiometric coefficients in the equation are used as exponents on the concentrations. (See how the equilibrium equation references <mathjax>#2"N"_2#</mathjax>, hence <mathjax>#["N"_2]^2#</mathjax> in the equilibrium constant expression.)</p> <p>To find the concentrations (molarity), divide <a href="http://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> amounts by the volume.</p> <p><mathjax>#["N"_2"O"]=(2.00xx10^-2"mol")/(2.00"L")=1.00xx10^-2"M"#</mathjax></p> <p><mathjax>#["N"_2]=(2.80xx10^-4"mol")/(2.00"L")=1.40xx10^-4"M"#</mathjax></p> <p><mathjax>#["O"_2]=(2.50xx10^-5"mol")/(2.00"L")=1.25xx10^-5"M"#</mathjax></p> <p><mathjax>#"K"=((1.00xx10^-2)^2)/((1.40xx10^-4)^2(1.25xx10^-5))=4.08xx10^8#</mathjax></p> <p>The equilibrium constant is unitless.</p> <p>An equilibrium constant <mathjax>#≫1#</mathjax> also tells us that the reaction is heavily product-favored.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/200260" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-temperature-affect-dynamic-equilibrium"> How does temperature affect dynamic equilibrium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-dynamic-equilibrium-important-for-living-organisms"> Why is dynamic equilibrium important for living organisms? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-dynamic-equilibrium-1"> What is dynamic equilibrium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-common-mistakes-students-make-with-dynamic-equilibrium-1"> What are some common mistakes students make with dynamic equilibrium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-dynamic-equilibrium-be-disrupted"> Can dynamic equilibrium be disrupted? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-concentration-effect-dynamic-equilibrium"> How does concentration effect dynamic equilibrium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-dynamic-equilibrium-related-to-vapor-pressure-1"> How is dynamic equilibrium related to vapor pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-homeostasis-a-type-of-dynamic-equilibrium"> Is homeostasis a type of dynamic equilibrium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-the-concentration-of-reactants-equal-to-the-concentration-of-products-in-a-dy"> Is the concentration of reactants equal to the concentration of products in a dynamic equilibrium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/once-dynamic-equilibrium-is-established-will-it-shift-if-additional-reactants-ar"> Once dynamic equilibrium is established, will it shift if additional reactants are added? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-equilibrium/dynamic-equilibrium"> See all questions in Dynamic Equilibrium </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 21823 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	At a particular temperature a 2.00-L flask at equilibrium contains 2.80 10-4 mol N2, 2.50 10-5 mol O2, and 2.00 10-2 mol N2O. How would you calculate K at this temperature for the following reaction: 2 N2(g) + O2(g) --> 2 N2O(g)?	null
726	ac0c1779-6ddd-11ea-957a-ccda262736ce	https://socratic.org/questions/what-is-the-chemical-equation-for-ethane-reacting-with-oxygen-to-yield-carbon-di	2 C2H6 + 7 O2 -> 4 CO2 + 6 H2O	start chemical_equation qc_end substance 6 6 qc_end substance 9 9 qc_end substance 15 16 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the equation"}]	[{"type":"chemical equation","value":"2 C2H6 + 7 O2 -> 4 CO2 + 6 H2O"}]	[{"type":"substance name","value":"Ethane"},{"type":"substance name","value":"Oxygen"},{"type":"substance name","value":"Carbon dioxid"},{"type":"substance name","value":"Liquid water"}]	<h1 class="questionTitle" itemprop="name">What is the chemical equation for ethane reacting with oxygen to yield carbon dioxide and liquid water?</h1>	null	2 C2H6 + 7 O2 -> 4 CO2 + 6 H2O	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Is the reaction stoichiometrically balanced? How do I denote the physical states of reactants and products?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_2H_6 + 7/2O_2 rarr 2CO_2 + 3H_2O#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Is the reaction stoichiometrically balanced? How do I denote the physical states of reactants and products?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the chemical equation for ethane reacting with oxygen to yield carbon dioxide and liquid water?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-reactions-and-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions and Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="289531" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-18T18:07:27" itemprop="dateCreated"> Jul 18, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_2H_6 + 7/2O_2 rarr 2CO_2 + 3H_2O#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Is the reaction stoichiometrically balanced? How do I denote the physical states of reactants and products?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/289531" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb002bf34694a4fee47"> Question #fee47 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb402bf34694c8c5c15"> Question #c5c15 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb802bf346950519eb9"> Question #19eb9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cbf02bf3469570e2ea2"> Question #e2ea2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc002bf34695a6bc751"> Question #bc751 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc202bf3469570e2ea6"> Question #e2ea6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531e867a02bf342492a08b07"> Question #08b07 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-thermochemical-equation-for-the-combustion-of-benzene"> What is the thermochemical equation for the combustion of benzene? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-reversible"> Why are chemical reactions reversible? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-important"> Why are chemical reactions important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/chemical-reactions-and-equations"> See all questions in Chemical Reactions and Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2707 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the chemical equation for ethane reacting with oxygen to yield carbon dioxide and liquid water?	null
727	aa3a56c9-6ddd-11ea-8be2-ccda262736ce	https://socratic.org/questions/what-volume-will-2-3-moles-of-o-2-have-at-stp	51.52 mL	start physical_unit 6 6 volume ml qc_end physical_unit 6 6 3 4 mole qc_end c_other STP qc_end end	[{"type":"physical unit","value":"Volume [OF] O2 [IN] mL"}]	[{"type":"physical unit","value":"51.52 mL"}]	[{"type":"physical unit","value":"Mole [OF] O2 [=] \\pu{2.3 moles}"},{"type":"other","value":"STP"}]	<h1 class="questionTitle" itemprop="name">What volume will 2.3 moles of #O_2# have at STP?</h1>	null	51.52 mL	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So to your problem, <mathjax>#"Volume at STP"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#2.3cancel(mol)xx22.4L*cancel(mol^-1)=??L#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The molar volume of an Ideal gas at <mathjax>#"STP"#</mathjax> is <mathjax>#22.4Lmol^-1#</mathjax>. Dioxygen should have a volume approaching <mathjax>#50L#</mathjax> </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So to your problem, <mathjax>#"Volume at STP"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#2.3cancel(mol)xx22.4Lcancel(mol^-1)=??L#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What volume will 2.3 moles of #O_2# have at STP?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp" itemprop="url"> <span class="breadcrumb" itemprop="title">Molar Volume of a Gas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="258796" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-04-26T05:29:34" itemprop="dateCreated"> Apr 26, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The molar volume of an Ideal gas at <mathjax>#"STP"#</mathjax> is <mathjax>#22.4Lmol^-1#</mathjax>. Dioxygen should have a volume approaching <mathjax>#50L#</mathjax> </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So to your problem, <mathjax>#"Volume at STP"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#2.3cancel(mol)xx22.4Lcancel(mol^-1)=??L#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/258796" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-stoichiometric-ratios-relate-to-molar-volume-of-a-gas"> How do stoichiometric ratios relate to molar volume of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-a-gas-at-stp"> How do you calculate molar volume of a gas at STP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-molar-volume-of-hydrogen-gas"> How do you find the molar volume of hydrogen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-oxygen-gas"> How do you calculate molar volume of oxygen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molar-gas-volume"> What is molar gas volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/534c7bf202bf3420a007f014"> What is the volume at 0 °C and 1 atm of a mixture that contains 4.0 g of methane and 2.0 g of helium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5361f75702bf3429040e0599"> What is the difference between STP and NTP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-volume-of-25-moles-of-oxygen-o2-gas"> What is the volume of .25 moles of oxygen (O2) Gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-would-knowing-the-molar-volume-of-a-gas-be-important"> Why would knowing the molar volume of a gas be important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-22-4-liters-called-the-molar-volume-of-a-gas"> Why is 22.4 liters called the molar volume of a gas? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp"> See all questions in Molar Volume of a Gas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1923 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What volume will 2.3 moles of #O_2# have at STP?	null
728	a93feb88-6ddd-11ea-8212-ccda262736ce	https://socratic.org/questions/what-is-the-mass-of-4-50-mol-fe	251.33 g	start physical_unit 7 7 mass g qc_end physical_unit 7 7 5 6 mole qc_end end	[{"type":"physical unit","value":"Mass [OF] Fe [IN] g"}]	[{"type":"physical unit","value":"251.33 g"}]	[{"type":"physical unit","value":"Mole [OF] Fe [=] \\pu{4.50 mol}"}]	<h1 class="questionTitle" itemprop="name">What is the mass of 4.50 mol #Fe#?</h1>	null	251.33 g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So the mass of the given molar quantity?</p> <p><mathjax>#4.50molxx55.85gmol^-1#</mathjax> <mathjax>#~~#</mathjax> <mathjax>#250g#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Elemental iron has a molar mass of <mathjax>#55.85#</mathjax> <mathjax>#gmol^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So the mass of the given molar quantity?</p> <p><mathjax>#4.50molxx55.85gmol^-1#</mathjax> <mathjax>#~~#</mathjax> <mathjax>#250*g#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the mass of 4.50 mol #Fe#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="260881" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-01T08:36:58" itemprop="dateCreated"> May 1, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Elemental iron has a molar mass of <mathjax>#55.85#</mathjax> <mathjax>#gmol^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So the mass of the given molar quantity?</p> <p><mathjax>#4.50molxx55.85gmol^-1#</mathjax> <mathjax>#~~#</mathjax> <mathjax>#250*g#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/260881" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="260885" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/edmund-l"><img alt="" class="" src="https://profilepictures.socratic.org/DnAPD8TISDW0aROTp4qA_Day_3_Story_1._Photo_with_Sky_Tower_from_distance_Walked_around_most_of_west_Auckland_suburbs._Some_of_you_mightve_seen_.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/edmund-l"> Edmund Liew </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-01T08:46:25" itemprop="dateCreated"> May 1, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>4.50 moles <mathjax>#xx#</mathjax> molar mass of Fe<br/> 4.50 <mathjax>#xx#</mathjax> 55.9 = ?</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Assume that:<br/> n - number of moles<br/> m - mass of substance<br/> M - molar mass (same as atomic weight on periodic table)<br/> <mathjax>#n = m -: M#</mathjax></p> <p>4.50 moles (n) has been given to you.</p> <p>Now find the molar mass (M) of Fe. If you look into your periodic table, the molar mass of Fe is 55.9 g/mol.</p> <p>To find the mass of substance (m), you need to flip over the formula, therefore, <mathjax>#m = M xx n#</mathjax><br/> The mass (m) of Fe is:<br/> [55.9 g/mol <mathjax>#xx#</mathjax> 4.50 moles] = 251.6 grams.<br/> Note: It is rounded to the nearest one decimal place.</p> <p>4.50 moles of Fe should give you 251.6 grams of Fe.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/260885" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 7513 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the mass of 4.50 mol #Fe#?	null
729	aa71b8bd-6ddd-11ea-ade9-ccda262736ce	https://socratic.org/questions/with-a-0-5-m-solution-many-moles-of-naci-would-there-be-in-1-000-ml	0.50 moles	start physical_unit 8 8 mole mol qc_end physical_unit 8 8 2 3 molarity qc_end physical_unit 4 4 13 14 volume qc_end end	[{"type":"physical unit","value":"Mole [OF] NaCI [IN] moles"}]	[{"type":"physical unit","value":"0.50 moles"}]	[{"type":"physical unit","value":"Molarity [OF] NaCI solution [=] \\pu{0.5 M}"},{"type":"physical unit","value":"Volume [OF] NaCI solution [=] \\pu{1,000 mL}"}]	<h1 class="questionTitle" itemprop="name">With a 0.5 M solution, many moles of NaCI would there be in 1,000 mL?</h1>	null	0.50 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Let's begin with the equation for <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a>:<br/> <img alt="slideplayer.com" src="https://useruploads.socratic.org/4z0vwx7RRla5OizeNQHX_slide_3.jpg"/> <br/> We are given the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> and the volume of solution. The only issue is that the volume is given in mL instead of L. This issue can be fixed by using the following conversion factor:</p> <p><mathjax>#color(white)(aaaaaaaaaaaaaaaaaaaaa)1000mL = 1L#</mathjax></p> <p>Therefore, if we divide 1000mL by 1000mL we will obtain a value of <strong>1L.</strong></p> <p>Rearrange the equation to solve for moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a>:</p> <p><strong>Moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> = <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a> <mathjax>#xx#</mathjax> Liters of solution</strong></p> <p>Multiply 0.5 M by 1 L:</p> <p><mathjax>#(0.5mol)/(1 cancel"L") xx 1 cancel"L" = 0.5mol#</mathjax></p> <p>Boom, there would be 0.5 moles of NaCl!</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#0.5 "moles of NaCl"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Let's begin with the equation for <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a>:<br/> <img alt="slideplayer.com" src="https://useruploads.socratic.org/4z0vwx7RRla5OizeNQHX_slide_3.jpg"/> <br/> We are given the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> and the volume of solution. The only issue is that the volume is given in mL instead of L. This issue can be fixed by using the following conversion factor:</p> <p><mathjax>#color(white)(aaaaaaaaaaaaaaaaaaaaa)1000mL = 1L#</mathjax></p> <p>Therefore, if we divide 1000mL by 1000mL we will obtain a value of <strong>1L.</strong></p> <p>Rearrange the equation to solve for moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a>:</p> <p><strong>Moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> = <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a> <mathjax>#xx#</mathjax> Liters of solution</strong></p> <p>Multiply 0.5 M by 1 L:</p> <p><mathjax>#(0.5mol)/(1 cancel"L") xx 1 cancel"L" = 0.5mol#</mathjax></p> <p>Boom, there would be 0.5 moles of NaCl!</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">With a 0.5 M solution, many moles of NaCI would there be in 1,000 mL?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="300021" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/kayla-14"><img alt="" class="" src="https://profilepictures.socratic.org/OvMTWaamQPWcqLIkUNnG_793604964071127.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/kayla-14"> Kayla </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-08-18T01:46:28" itemprop="dateCreated"> Aug 18, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#0.5 "moles of NaCl"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Let's begin with the equation for <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a>:<br/> <img alt="slideplayer.com" src="https://useruploads.socratic.org/4z0vwx7RRla5OizeNQHX_slide_3.jpg"/> <br/> We are given the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> and the volume of solution. The only issue is that the volume is given in mL instead of L. This issue can be fixed by using the following conversion factor:</p> <p><mathjax>#color(white)(aaaaaaaaaaaaaaaaaaaaa)1000mL = 1L#</mathjax></p> <p>Therefore, if we divide 1000mL by 1000mL we will obtain a value of <strong>1L.</strong></p> <p>Rearrange the equation to solve for moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a>:</p> <p><strong>Moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> = <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a> <mathjax>#xx#</mathjax> Liters of solution</strong></p> <p>Multiply 0.5 M by 1 L:</p> <p><mathjax>#(0.5mol)/(1 cancel"L") xx 1 cancel"L" = 0.5mol#</mathjax></p> <p>Boom, there would be 0.5 moles of NaCl!</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/300021" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-morality-be-used-as-a-conversion-factor"> How can molarity be used as a conversion factor? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-high-can-molarity-be"> How high can molarity be? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-molarity-change-with-temperature"> How does molarity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molarity-of-a-solution"> How do you find molarity of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-10-naoh"> What is the molarity of 10 NaOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-3-hydrogen-peroxide"> What is the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 5190 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	With a 0.5 M solution, many moles of NaCI would there be in 1,000 mL?	null
730	acf1b2f8-6ddd-11ea-a0e2-ccda262736ce	https://socratic.org/questions/what-is-the-temperature-of-a-25-0-g-sample-of-neon-gas-that-exerts-a-pressure-of	29.48 K	start physical_unit 8 11 temperature k qc_end physical_unit 8 11 6 7 mass qc_end physical_unit 8 11 17 18 pressure qc_end physical_unit 8 11 24 25 volume qc_end end	[{"type":"physical unit","value":"Temperature [OF] neon gas sample [IN] K"}]	[{"type":"physical unit","value":"29.48 K"}]	[{"type":"physical unit","value":"Mass [OF] neon gas sample [=] \\pu{25.0 g}"},{"type":"physical unit","value":"Pressure [OF] neon gas sample [=] \\pu{0.922 atm}"},{"type":"physical unit","value":"Volume [OF] neon gas sample [=] \\pu{3.25 L}"}]	<h1 class="questionTitle" itemprop="name">What is the temperature of a 25.0 g sample of neon gas that exerts a pressure of .922 atm and has a volume of 3.25 L?</h1>	null	29.48 K	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First convert mass to moles by dividing the given mass of the substance by its molar mass. Then use the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> to determine its temperature in Kelvins.</p> <p><strong>Moles of Neon</strong></p> <p>The molar mass of neon is <mathjax>#"20.180 g/mol"#</mathjax>.</p> <p><mathjax>#25.0cancel"g Ne"xx(1"mol Ne")/(20.180cancel"g Ne")="1.23885 mol Ne"#</mathjax></p> <p><strong>Ideal Gas Law</strong></p> <p>The equation for the ideal gas law is <strong><mathjax>#PV=nRT#</mathjax></strong>, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvins.</p> <p><strong>Given/Known</strong><br/> <mathjax>#P="0.922 atm"#</mathjax><br/> <mathjax>#V="3.25 L"#</mathjax><br/> <mathjax>#n="1.23885 mol"#</mathjax><br/> <mathjax>#R="0.08206 L atm K"^(-1) "mol"^(-1)"#</mathjax><br/> <a href="https://en.m.wikipedia.org/wiki/Gas_constant" rel="nofollow" target="_blank">https://en.m.wikipedia.org/wiki/Gas_constant</a></p> <p><strong>Unknown</strong><br/> <mathjax>#T=???#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the ideal gas law equation to isolate temperature and substitute the known values into the equation, then solve.</p> <p><mathjax>#PV=nRT#</mathjax></p> <p><mathjax>#T=(PV)/(nR)#</mathjax></p> <p><mathjax>#T=((0.922cancel"atm"xx3.25cancel"L"))/((1.23885cancel"mol"xx0.08206cancel"L"·cancel"atm"·"K"^(-1)· cancel"mol"^(-1)))="29.5 K"#</mathjax> rounded to three <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The temperature of the neon sample will be 29.5 K.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First convert mass to moles by dividing the given mass of the substance by its molar mass. Then use the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> to determine its temperature in Kelvins.</p> <p><strong>Moles of Neon</strong></p> <p>The molar mass of neon is <mathjax>#"20.180 g/mol"#</mathjax>.</p> <p><mathjax>#25.0cancel"g Ne"xx(1"mol Ne")/(20.180cancel"g Ne")="1.23885 mol Ne"#</mathjax></p> <p><strong>Ideal Gas Law</strong></p> <p>The equation for the ideal gas law is <strong><mathjax>#PV=nRT#</mathjax></strong>, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvins.</p> <p><strong>Given/Known</strong><br/> <mathjax>#P="0.922 atm"#</mathjax><br/> <mathjax>#V="3.25 L"#</mathjax><br/> <mathjax>#n="1.23885 mol"#</mathjax><br/> <mathjax>#R="0.08206 L atm K"^(-1) "mol"^(-1)"#</mathjax><br/> <a href="https://en.m.wikipedia.org/wiki/Gas_constant" rel="nofollow" target="_blank">https://en.m.wikipedia.org/wiki/Gas_constant</a></p> <p><strong>Unknown</strong><br/> <mathjax>#T=???#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the ideal gas law equation to isolate temperature and substitute the known values into the equation, then solve.</p> <p><mathjax>#PV=nRT#</mathjax></p> <p><mathjax>#T=(PV)/(nR)#</mathjax></p> <p><mathjax>#T=((0.922cancel"atm"xx3.25cancel"L"))/((1.23885cancel"mol"xx0.08206cancel"L"·cancel"atm"·"K"^(-1)· cancel"mol"^(-1)))="29.5 K"#</mathjax> rounded to three <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the temperature of a 25.0 g sample of neon gas that exerts a pressure of .922 atm and has a volume of 3.25 L?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/ideal-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Ideal Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="256824" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-04-21T04:47:42" itemprop="dateCreated"> Apr 21, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The temperature of the neon sample will be 29.5 K.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First convert mass to moles by dividing the given mass of the substance by its molar mass. Then use the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> to determine its temperature in Kelvins.</p> <p><strong>Moles of Neon</strong></p> <p>The molar mass of neon is <mathjax>#"20.180 g/mol"#</mathjax>.</p> <p><mathjax>#25.0cancel"g Ne"xx(1"mol Ne")/(20.180cancel"g Ne")="1.23885 mol Ne"#</mathjax></p> <p><strong>Ideal Gas Law</strong></p> <p>The equation for the ideal gas law is <strong><mathjax>#PV=nRT#</mathjax></strong>, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvins.</p> <p><strong>Given/Known</strong><br/> <mathjax>#P="0.922 atm"#</mathjax><br/> <mathjax>#V="3.25 L"#</mathjax><br/> <mathjax>#n="1.23885 mol"#</mathjax><br/> <mathjax>#R="0.08206 L atm K"^(-1) "mol"^(-1)"#</mathjax><br/> <a href="https://en.m.wikipedia.org/wiki/Gas_constant" rel="nofollow" target="_blank">https://en.m.wikipedia.org/wiki/Gas_constant</a></p> <p><strong>Unknown</strong><br/> <mathjax>#T=???#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the ideal gas law equation to isolate temperature and substitute the known values into the equation, then solve.</p> <p><mathjax>#PV=nRT#</mathjax></p> <p><mathjax>#T=(PV)/(nR)#</mathjax></p> <p><mathjax>#T=((0.922cancel"atm"xx3.25cancel"L"))/((1.23885cancel"mol"xx0.08206cancel"L"·cancel"atm"·"K"^(-1)· cancel"mol"^(-1)))="29.5 K"#</mathjax> rounded to three <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/256824" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-ideal-gas-constant"> How do you find the ideal gas constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-solve-ideal-gas-law-problems"> How do you solve ideal gas law problems? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-know-which-ideal-gas-constant-to-use"> How do you know which ideal gas constant to use? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ideal-gas-constant-for-butane"> What is the ideal gas constant for butane? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-ideal-gas-law-in-kelvin"> Why is ideal gas law in kelvin? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ideal-gas-constant-important"> Why is the ideal gas constant important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-di-electric-constant"> What is the di-electric constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-volume-l-will-0-20-mol-hi-occupy-at-300-k-and-100-0-kpa-r-8-314-kpa-l-k-mol"> What volume (L) will 0.20 mol HI occupy at 300 K and 100.0 kPa? R = 8.314 kPa L / (K mol) =... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-molar-mass-of-a-gas"> How do you calculate the molar mass of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-should-i-use-the-ideal-gas-law-and-not-the-combined-gas-law"> When should I use the ideal gas law and not the combined gas law? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/ideal-gas-law"> See all questions in Ideal Gas Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 7686 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the temperature of a 25.0 g sample of neon gas that exerts a pressure of .922 atm and has a volume of 3.25 L?	null
731	a9be770a-6ddd-11ea-b510-ccda262736ce	https://socratic.org/questions/a-volume-of-50-0-milliliters-of-an-ideal-gas-at-stp-increases-to-100-milliliters	546.30 K	start physical_unit 7 8 temperature k qc_end physical_unit 7 8 3 4 volume qc_end physical_unit 7 8 13 14 volume qc_end c_other STP qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Temperature2 [OF] the ideal gas [IN] K"}]	[{"type":"physical unit","value":"546.30 K"}]	[{"type":"physical unit","value":"Volume1 [OF] the ideal gas [=] \\pu{50.0 milliliters}"},{"type":"physical unit","value":"Volume2 [OF] the ideal gas [=] \\pu{100 milliliters}"},{"type":"other","value":"STP"},{"type":"other","value":"Constant pressure."}]	<h1 class="questionTitle" itemprop="name">A volume of 50.0 milliliters of an ideal gas at STP increases to 100 milliliters. If the pressure remains constant, what must the new temperature be?</h1>	null	546.30 K	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This question involves <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/charles-law">Charles' law</a></strong> , which states that the volume of a given amount of gas varies directly with its temperature, as long as pressure and amount are kept constant. This means that if the volume increases, so does the temperature, and vice versa.</p> <p><strong>Equation</strong></p> <p><mathjax>#V_1/T_1=V_2/T_2#</mathjax>, where <mathjax>#V#</mathjax> represents volume, and <mathjax>#T#</mathjax> represents the Kelvin temperature.</p> <p><mathjax>#"STP"#</mathjax> can have more than one unit for pressure, but the temperature is <mathjax>#0^@"C"#</mathjax> or <mathjax>#"273.15 K"#</mathjax>. The temperature in gas law problems is always in Kelvins.</p> <p><strong>Known</strong><br/> <mathjax>#V_1="50.0 mL"#</mathjax><br/> <mathjax>#T_1="273.15 K"#</mathjax><br/> <mathjax>#V_2="100 mL"#</mathjax></p> <p><strong>Unknown</strong><br/> <mathjax>#T_2#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#T_2#</mathjax>. Plug in your known values and solve.</p> <p><mathjax>#T_2=(V_2T_1)/(V_1)#</mathjax></p> <p><mathjax>#T_2=(100cancel"mL"xx273.15"K")/(50.0cancel"mL")="546 K"="500 K"#</mathjax> rounded to one significant figure</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The final temperature will be 500 K rounded to one significant figure.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This question involves <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/charles-law">Charles' law</a></strong> , which states that the volume of a given amount of gas varies directly with its temperature, as long as pressure and amount are kept constant. This means that if the volume increases, so does the temperature, and vice versa.</p> <p><strong>Equation</strong></p> <p><mathjax>#V_1/T_1=V_2/T_2#</mathjax>, where <mathjax>#V#</mathjax> represents volume, and <mathjax>#T#</mathjax> represents the Kelvin temperature.</p> <p><mathjax>#"STP"#</mathjax> can have more than one unit for pressure, but the temperature is <mathjax>#0^@"C"#</mathjax> or <mathjax>#"273.15 K"#</mathjax>. The temperature in gas law problems is always in Kelvins.</p> <p><strong>Known</strong><br/> <mathjax>#V_1="50.0 mL"#</mathjax><br/> <mathjax>#T_1="273.15 K"#</mathjax><br/> <mathjax>#V_2="100 mL"#</mathjax></p> <p><strong>Unknown</strong><br/> <mathjax>#T_2#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#T_2#</mathjax>. Plug in your known values and solve.</p> <p><mathjax>#T_2=(V_2T_1)/(V_1)#</mathjax></p> <p><mathjax>#T_2=(100cancel"mL"xx273.15"K")/(50.0cancel"mL")="546 K"="500 K"#</mathjax> rounded to one significant figure</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A volume of 50.0 milliliters of an ideal gas at STP increases to 100 milliliters. If the pressure remains constant, what must the new temperature be?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/ideal-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Ideal Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="353510" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-12-18T03:22:05" itemprop="dateCreated"> Dec 18, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The final temperature will be 500 K rounded to one significant figure.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This question involves <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/charles-law">Charles' law</a></strong> , which states that the volume of a given amount of gas varies directly with its temperature, as long as pressure and amount are kept constant. This means that if the volume increases, so does the temperature, and vice versa.</p> <p><strong>Equation</strong></p> <p><mathjax>#V_1/T_1=V_2/T_2#</mathjax>, where <mathjax>#V#</mathjax> represents volume, and <mathjax>#T#</mathjax> represents the Kelvin temperature.</p> <p><mathjax>#"STP"#</mathjax> can have more than one unit for pressure, but the temperature is <mathjax>#0^@"C"#</mathjax> or <mathjax>#"273.15 K"#</mathjax>. The temperature in gas law problems is always in Kelvins.</p> <p><strong>Known</strong><br/> <mathjax>#V_1="50.0 mL"#</mathjax><br/> <mathjax>#T_1="273.15 K"#</mathjax><br/> <mathjax>#V_2="100 mL"#</mathjax></p> <p><strong>Unknown</strong><br/> <mathjax>#T_2#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#T_2#</mathjax>. Plug in your known values and solve.</p> <p><mathjax>#T_2=(V_2T_1)/(V_1)#</mathjax></p> <p><mathjax>#T_2=(100cancel"mL"xx273.15"K")/(50.0cancel"mL")="546 K"="500 K"#</mathjax> rounded to one significant figure</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/353510" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-ideal-gas-constant"> How do you find the ideal gas constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-solve-ideal-gas-law-problems"> How do you solve ideal gas law problems? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-know-which-ideal-gas-constant-to-use"> How do you know which ideal gas constant to use? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ideal-gas-constant-for-butane"> What is the ideal gas constant for butane? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-ideal-gas-law-in-kelvin"> Why is ideal gas law in kelvin? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ideal-gas-constant-important"> Why is the ideal gas constant important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-di-electric-constant"> What is the di-electric constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-volume-l-will-0-20-mol-hi-occupy-at-300-k-and-100-0-kpa-r-8-314-kpa-l-k-mol"> What volume (L) will 0.20 mol HI occupy at 300 K and 100.0 kPa? R = 8.314 kPa L / (K mol) =... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-molar-mass-of-a-gas"> How do you calculate the molar mass of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-should-i-use-the-ideal-gas-law-and-not-the-combined-gas-law"> When should I use the ideal gas law and not the combined gas law? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/ideal-gas-law"> See all questions in Ideal Gas Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 11117 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A volume of 50.0 milliliters of an ideal gas at STP increases to 100 milliliters. If the pressure remains constant, what must the new temperature be?	null
732	a8d25b9f-6ddd-11ea-896a-ccda262736ce	https://socratic.org/questions/5713343c11ef6b236c1dd4ac	3.61 × 10^24	start physical_unit 2 3 number none qc_end physical_unit 13 14 8 9 mass qc_end end	[{"type":"physical unit","value":"Number [OF] oxygen atoms"}]	[{"type":"physical unit","value":"3.61 × 10^24"}]	[{"type":"physical unit","value":"Mass [OF] carbon dioxide [=] \\pu{132 g}"}]	<h1 class="questionTitle" itemprop="name">How many oxygen atoms in a mass of #132*g# with respect to carbon dioxide?</h1>	null	3.61 × 10^24	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>What is <mathjax>#N_A#</mathjax>? It is simply <mathjax>#"Avogadro's number"#</mathjax>, <mathjax>#6.022xx10^23mol^-1#</mathjax>.</p> <p>If I have <mathjax>#6.022xx10^23#</mathjax> individual items of stuff, I have a mole of that stuff. <mathjax>#1#</mathjax> <mathjax>#mol#</mathjax> of <mathjax>#CO_2#</mathjax> is equivalent to a mass <mathjax>#44.0g#</mathjax>; <mathjax>#12.01#</mathjax> <mathjax>#g#</mathjax> of <mathjax>#C#</mathjax>, and <mathjax>#32.0#</mathjax> <mathjax>#g#</mathjax> of <mathjax>#O#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>There are <mathjax>#3#</mathjax> <mathjax>#mol#</mathjax> of <mathjax>#CO_2#</mathjax> in such a mass. Thus there are <mathjax>#6xxN_A#</mathjax> individual oxygen atoms. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>What is <mathjax>#N_A#</mathjax>? It is simply <mathjax>#"Avogadro's number"#</mathjax>, <mathjax>#6.022xx10^23mol^-1#</mathjax>.</p> <p>If I have <mathjax>#6.022xx10^23#</mathjax> individual items of stuff, I have a mole of that stuff. <mathjax>#1#</mathjax> <mathjax>#mol#</mathjax> of <mathjax>#CO_2#</mathjax> is equivalent to a mass <mathjax>#44.0g#</mathjax>; <mathjax>#12.01#</mathjax> <mathjax>#g#</mathjax> of <mathjax>#C#</mathjax>, and <mathjax>#32.0#</mathjax> <mathjax>#g#</mathjax> of <mathjax>#O#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many oxygen atoms in a mass of #132g# with respect to carbon dioxide?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="255275" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-04-17T08:33:55" itemprop="dateCreated"> Apr 17, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>There are <mathjax>#3#</mathjax> <mathjax>#mol#</mathjax> of <mathjax>#CO_2#</mathjax> in such a mass. Thus there are <mathjax>#6xxN_A#</mathjax> individual oxygen atoms. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>What is <mathjax>#N_A#</mathjax>? It is simply <mathjax>#"Avogadro's number"#</mathjax>, <mathjax>#6.022xx10^23mol^-1#</mathjax>.</p> <p>If I have <mathjax>#6.022xx10^23#</mathjax> individual items of stuff, I have a mole of that stuff. <mathjax>#1#</mathjax> <mathjax>#mol#</mathjax> of <mathjax>#CO_2#</mathjax> is equivalent to a mass <mathjax>#44.0g#</mathjax>; <mathjax>#12.01#</mathjax> <mathjax>#g#</mathjax> of <mathjax>#C#</mathjax>, and <mathjax>#32.0#</mathjax> <mathjax>#g#</mathjax> of <mathjax>#O#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/255275" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="255279" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/matt-20"><img alt="" class="" src="https://profilepictures.socratic.org/LqE7CmbkQeiPBoV4SQZ4_image.jpeg" title=""/></a> <a class="secondContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/matt-20"> Matt </a>·<a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-04-17T08:40:03" itemprop="dateCreated"> Apr 17, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#36.132 times 10^23 #</mathjax> oxygen atoms</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>If we work out the relative formula mass of <mathjax>#CO_2#</mathjax></p> <p>Relative <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">atomic mass</a>, <mathjax>#A_r#</mathjax> of <mathjax># C= 12#</mathjax><br/> Relative atomic mass, <mathjax>#A_r#</mathjax> of <mathjax># O=16#</mathjax>, so....</p> <p><mathjax>#M_r#</mathjax> of <mathjax># CO_2 =44#</mathjax></p> <p>The number of moles of a substance is given by :</p> <p><mathjax>#"mass in grams" /(M_r)#</mathjax></p> <p>So in this case:</p> <p><mathjax>#132/44=3"moles"#</mathjax></p> <p>One mole contains <mathjax>#6.022times 10^23#</mathjax> molecules (Avogadro's number).</p> <p>So 3 moles contains <mathjax>#18.066 times 10^23#</mathjax> molecules.</p> <p>Each molecule contains 2 oxygen atoms, so there will be <mathjax>#36.132 times 10^23 #</mathjax>oxygen atoms</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/255279" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? 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</a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 24824 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many oxygen atoms in a mass of #132*g# with respect to carbon dioxide?	null
733	a9af8c68-6ddd-11ea-841b-ccda262736ce	https://socratic.org/questions/to-what-pressure-would-you-have-to-compress-48-0-l-of-oxygen-gas-at-99-3-kpa-in-	298 kPa	start physical_unit 11 12 pressure kpa qc_end physical_unit 11 12 14 15 pressure qc_end physical_unit 11 12 8 9 volume qc_end physical_unit 11 12 23 24 volume qc_end end	[{"type":"physical unit","value":"Pressure2 [OF] oxygen gas [IN] kPa"}]	[{"type":"physical unit","value":"298 kPa"}]	[{"type":"physical unit","value":"Pressure1 [OF] oxygen gas [=] \\pu{99.3 kPa}"},{"type":"physical unit","value":"Volume1 [OF] oxygen gas [=] \\pu{48.0 L}"},{"type":"physical unit","value":"Volume2 [OF] oxygen gas [=] \\pu{16.0 L}"}]	<h1 class="questionTitle" itemprop="name">To what pressure would you have to compress 48.0 L of oxygen gas at 99.3 kPa in order to reduce its volume to 16.0 L? </h1>	null	298 kPa	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The answer can be determined by using <a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's Law</a>:<br/> <img alt="slideplayer.com" src="https://useruploads.socratic.org/UDDmD8A9TkaHlW0KT9Tm_slide_6.jpg"/> </p> <p>Let's identify our known and unknown variables. </p> <p><mathjax>#color(red)("Knowns:"#</mathjax><br/> <mathjax>#P_1#</mathjax>= 99.3 kpa<br/> <mathjax>#V_1#</mathjax>= 48.0 L<br/> <mathjax>#V_2#</mathjax>= 16.0 L</p> <p><mathjax>#color(maroon)("Unknowns:"#</mathjax><br/> <mathjax>#P_2#</mathjax> </p> <p>Rearrange the equation to solve for the final pressure by dividing both sides by <mathjax>#V_2#</mathjax> to get <mathjax>#P_2#</mathjax> by itself like this:</p> <p><mathjax>#P_2=(P_1xxV_1)/V_2#</mathjax></p> <p>Plug in your given values to obtain the final pressure:</p> <p><mathjax>#P_2=(99.3\kPa xx 48.0\ cancel"L")/(16.0\cancel"L")#</mathjax> = <mathjax>#298kPa#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#298 kPa#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The answer can be determined by using <a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's Law</a>:<br/> <img alt="slideplayer.com" src="https://useruploads.socratic.org/UDDmD8A9TkaHlW0KT9Tm_slide_6.jpg"/> </p> <p>Let's identify our known and unknown variables. </p> <p><mathjax>#color(red)("Knowns:"#</mathjax><br/> <mathjax>#P_1#</mathjax>= 99.3 kpa<br/> <mathjax>#V_1#</mathjax>= 48.0 L<br/> <mathjax>#V_2#</mathjax>= 16.0 L</p> <p><mathjax>#color(maroon)("Unknowns:"#</mathjax><br/> <mathjax>#P_2#</mathjax> </p> <p>Rearrange the equation to solve for the final pressure by dividing both sides by <mathjax>#V_2#</mathjax> to get <mathjax>#P_2#</mathjax> by itself like this:</p> <p><mathjax>#P_2=(P_1xxV_1)/V_2#</mathjax></p> <p>Plug in your given values to obtain the final pressure:</p> <p><mathjax>#P_2=(99.3\kPa xx 48.0\ cancel"L")/(16.0\cancel"L")#</mathjax> = <mathjax>#298kPa#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">To what pressure would you have to compress 48.0 L of oxygen gas at 99.3 kPa in order to reduce its volume to 16.0 L? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/boyle-s-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Boyle's Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="297626" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/kayla-14"><img alt="" class="" src="https://profilepictures.socratic.org/OvMTWaamQPWcqLIkUNnG_793604964071127.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/kayla-14"> Kayla </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-08-11T02:05:18" itemprop="dateCreated"> Aug 11, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#298 kPa#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The answer can be determined by using <a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's Law</a>:<br/> <img alt="slideplayer.com" src="https://useruploads.socratic.org/UDDmD8A9TkaHlW0KT9Tm_slide_6.jpg"/> </p> <p>Let's identify our known and unknown variables. </p> <p><mathjax>#color(red)("Knowns:"#</mathjax><br/> <mathjax>#P_1#</mathjax>= 99.3 kpa<br/> <mathjax>#V_1#</mathjax>= 48.0 L<br/> <mathjax>#V_2#</mathjax>= 16.0 L</p> <p><mathjax>#color(maroon)("Unknowns:"#</mathjax><br/> <mathjax>#P_2#</mathjax> </p> <p>Rearrange the equation to solve for the final pressure by dividing both sides by <mathjax>#V_2#</mathjax> to get <mathjax>#P_2#</mathjax> by itself like this:</p> <p><mathjax>#P_2=(P_1xxV_1)/V_2#</mathjax></p> <p>Plug in your given values to obtain the final pressure:</p> <p><mathjax>#P_2=(99.3\kPa xx 48.0\ cancel"L")/(16.0\cancel"L")#</mathjax> = <mathjax>#298kPa#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/297626" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-graph-boyles-law"> How do you graph Boyle's law? 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734	a914ba11-6ddd-11ea-92de-ccda262736ce	https://socratic.org/questions/what-is-the-empirical-formula-of-the-compound-c-6h-5-oh-2	C6H5(OH)2	start chemical_formula qc_end chemical_equation 8 8 qc_end end	[{"type":"other","value":"Chemical Formula [OF] C6H5(OH)2 [IN] empirical"}]	[{"type":"chemical equation","value":"C6H5(OH)2"}]	[{"type":"chemical equation","value":"C6H5(OH)2"}]	<h1 class="questionTitle" itemprop="name">What is the empirical formula of the compound #C_6H_5(OH)_2#?</h1>	null	C6H5(OH)2	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The empirical formula of a compound represents the lowest whole number ratio of <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> in the compound. The subscript <mathjax>#5#</mathjax> on <mathjax>#"H"#</mathjax> cannot be divided by a whole number into a smaller whole number, therefore, <mathjax>#"C"_6"H"_5("OH")_2"#</mathjax> is the empirical formula.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The empirical formula is <mathjax>#"C"_6"H"_5("OH")_2"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The empirical formula of a compound represents the lowest whole number ratio of <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> in the compound. The subscript <mathjax>#5#</mathjax> on <mathjax>#"H"#</mathjax> cannot be divided by a whole number into a smaller whole number, therefore, <mathjax>#"C"_6"H"_5("OH")_2"#</mathjax> is the empirical formula.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the empirical formula of the compound #C_6H_5(OH)_2#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="209713" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-08T06:17:47" itemprop="dateCreated"> Jan 8, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The empirical formula is <mathjax>#"C"_6"H"_5("OH")_2"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The empirical formula of a compound represents the lowest whole number ratio of <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> in the compound. The subscript <mathjax>#5#</mathjax> on <mathjax>#"H"#</mathjax> cannot be divided by a whole number into a smaller whole number, therefore, <mathjax>#"C"_6"H"_5("OH")_2"#</mathjax> is the empirical formula.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/209713" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molecular-formula-of-a-compound"> How do you find molecular formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-diamond"> What is the chemical formula of a diamond? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-carbohydrate"> What is the chemical formula of a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-valproic-acid"> What is the empirical formula for valproic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-of-magnesium-oxide"> What is the empirical formula of magnesium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-empirical-formula-not-double-that-of-the-monosaccharides"> Why is the empirical formula not double that of the monosaccharides? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5331180502bf342f40b5c3b5"> Question #5c3b5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-molecular-formula-represents-a-carbohydrate"> What molecular formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-of-vinegar"> What is the molecular formula of vinegar? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/empirical-and-molecular-formulas"> See all questions in Empirical and Molecular Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 4811 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the empirical formula of the compound #C_6H_5(OH)_2#?	null
735	ac25eb4a-6ddd-11ea-8941-ccda262736ce	https://socratic.org/questions/how-many-moles-of-carbon-dioxide-are-present-in-5-44-10-22-molecules-of-this-com	0.10 moles	start physical_unit 4 5 mole mol qc_end end	[{"type":"physical unit","value":"Mole [OF] carbon dioxide [IN] moles"}]	[{"type":"physical unit","value":"0.10 moles"}]	[{"type":"physical unit","value":"Number [OF] carbon dioxide molecules [=] \\pu{5.44 × 10^22}"}]	<h1 class="questionTitle" itemprop="name">How many moles of carbon dioxide are present in #5.44 × 10^22# molecules of this compound? </h1>	null	0.10 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So the answer is approx. <mathjax>#0.10*mol#</mathjax>.</p> <p>How many moles of oxygen atoms are in this molar quantity?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Moles of "CO_2#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(5.44xx10^22)/(6.022140857(74)xx10^23mol^-1)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So the answer is approx. <mathjax>#0.10mol#</mathjax>.</p> <p>How many moles of oxygen atoms are in this molar quantity?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles of carbon dioxide are present in #5.44 × 10^22# molecules of this compound? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/mole-ratios" itemprop="url"> <span class="breadcrumb" itemprop="title">Mole Ratios</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="306466" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-09-05T17:08:59" itemprop="dateCreated"> Sep 5, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Moles of "CO_2#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(5.44xx10^22)/(6.022140857(74)xx10^23mol^-1)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So the answer is approx. <mathjax>#0.10mol#</mathjax>.</p> <p>How many moles of oxygen atoms are in this molar quantity?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/306466" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4178e02bf3469517a106e"> Question #a106e </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4178e02bf3469570e2e86"> Question #e2e86 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179102bf3469517a1072"> Question #a1072 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179402bf34694c8c5bf1"> Question #c5bf1 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179702bf3469588dc373"> Question #dc373 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179c02bf34694c8c5bf9"> Question #c5bf9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417a302bf3469517a1076"> Question #a1076 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417c702bf3469588dc377"> Question #dc377 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417d002bf346963eb984f"> Question #b984f </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417d402bf346950519ea3"> Question #19ea3 </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/mole-ratios"> See all questions in Mole Ratios </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 12410 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many moles of carbon dioxide are present in #5.44 × 10^22# molecules of this compound?	null
736	a97e3ef6-6ddd-11ea-9304-ccda262736ce	https://socratic.org/questions/how-many-grams-of-h-3po-4-are-in-521-ml-of-a-9-30-m-solution-of-h-3po-4	474.79 grams	start physical_unit 4 4 mass g qc_end physical_unit 13 13 7 8 volume qc_end physical_unit 4 4 11 12 molarity qc_end end	[{"type":"physical unit","value":"Mass [OF] H3PO4 [IN] grams"}]	[{"type":"physical unit","value":"474.79 grams"}]	[{"type":"physical unit","value":"Volume [OF] H3PO4 solution [=] \\pu{521 mL}"},{"type":"physical unit","value":"Molarity [OF] H3PO4 solution [=] \\pu{9.30 M}"}]	<h1 class="questionTitle" itemprop="name">How many grams of #H_3PO_4# are in 521 mL of a 9.30 M solution of #H_3PO_4#? </h1>	null	474.79 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Mass of phosphoric acid"=521xx10^-3Lxx9.30molL^-1xx97.99gmol^-1=??g.#</mathjax></p> <p>Here <mathjax>#1mL=1xx10^-3L#</mathjax>, i.e. <mathjax>#1L=10^3*mL#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Under <mathjax>#500g#</mathjax> of <mathjax>#"phosphoric acid"#</mathjax>.</p> <p>Here, we consider only the mass of <mathjax>#H_3PO_4#</mathjax> used to prepare the solution, not its speciation. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Mass of phosphoric acid"=521xx10^-3Lxx9.30molL^-1xx97.99gmol^-1=??g.#</mathjax></p> <p>Here <mathjax>#1mL=1xx10^-3L#</mathjax>, i.e. <mathjax>#1L=10^3mL#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many grams of #H_3PO_4# are in 521 mL of a 9.30 M solution of #H_3PO_4#? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/solutions" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="329034" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-10-31T08:34:34" itemprop="dateCreated"> Oct 31, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Under <mathjax>#500g#</mathjax> of <mathjax>#"phosphoric acid"#</mathjax>.</p> <p>Here, we consider only the mass of <mathjax>#H_3PO_4#</mathjax> used to prepare the solution, not its speciation. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Mass of phosphoric acid"=521xx10^-3Lxx9.30molL^-1xx97.99gmol^-1=??g.#</mathjax></p> <p>Here <mathjax>#1mL=1xx10^-3L#</mathjax>, i.e. <mathjax>#1L=10^3mL#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/329034" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-solution-solute-and-solvent-related"> How are solution, solute, and solvent related? 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The gram formula weight... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-solutions-differ-from-suspensions"> How do solutions differ from suspensions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-a-solution-differ-from-a-compound"> How does a solution differ from a compound? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/solutions"> See all questions in Solutions </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1963 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many grams of #H_3PO_4# are in 521 mL of a 9.30 M solution of #H_3PO_4#?	null
737	ac2500bf-6ddd-11ea-833a-ccda262736ce	https://socratic.org/questions/what-is-the-equation-for-the-reaction-of-tetraphosphorous-decaodixe-and-water-an	P4O10(s) + 6 H2O(l) -> 4 H3PO4(aq)	start chemical_equation qc_end substance 8 9 qc_end substance 11 11 qc_end substance 17 18 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the reaction"}]	[{"type":"chemical equation","value":"P4O10(s) + 6 H2O(l) -> 4 H3PO4(aq)"}]	[{"type":"substance name","value":"Tetraphosphorous decaoxide"},{"type":"substance name","value":"Water"},{"type":"substance name","value":"Phosphoric acid"}]	<h1 class="questionTitle" itemprop="name">What is the equation for the reaction of tetraphosphorous decaoxide and water and react together and form phosphoric acid?</h1>	null	P4O10(s) + 6 H2O(l) -> 4 H3PO4(aq)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#P_4O_10#</mathjax> is the acid anhydride of phosphoric acid; it is commonly used as a drying agent for halogenated organic solvents such as methylene chloride..........</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#P_4O_10(s) + 6H_2O(l) rarr 4H_3PO_4(aq)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#P_4O_10#</mathjax> is the acid anhydride of phosphoric acid; it is commonly used as a drying agent for halogenated organic solvents such as methylene chloride..........</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the equation for the reaction of tetraphosphorous decaoxide and water and react together and form phosphoric acid?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="438214" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-11T20:07:30" itemprop="dateCreated"> Jun 11, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#P_4O_10(s) + 6H_2O(l) rarr 4H_3PO_4(aq)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#P_4O_10#</mathjax> is the acid anhydride of phosphoric acid; it is commonly used as a drying agent for halogenated organic solvents such as methylene chloride..........</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/438214" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-equation-for-photosynthesis"> What is the chemical equation for photosynthesis? 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738	ac26d552-6ddd-11ea-ba2a-ccda262736ce	https://socratic.org/questions/57e6ad84b72cff6a46bd98f2	2.0 mL	start physical_unit 5 6 volume ml qc_end c_other Equivalence qc_end physical_unit 5 6 3 4 molarity qc_end physical_unit 19 19 3 4 molarity qc_end end	[{"type":"physical unit","value":"Volume [OF] sulfuric acid [IN] mL"}]	[{"type":"physical unit","value":"2.0 mL"}]	[{"type":"other","value":"Equivalence."},{"type":"physical unit","value":"Molarity [OF] sulfuric acid [=] \\pu{0.5 mol/L}"},{"type":"physical unit","value":"Molarity [OF] NaOH(aq) solution [=] \\pu{0.5 mol/L}"},{"type":"physical unit","value":"Volume [OF] NaOH(aq) solution [=] \\pu{20 mL}"}]	<h1 class="questionTitle" itemprop="name">What volume of #0.5molL^-1# #"sulfuric acid"# is required for equivalence with a #20mL# volume of #0.5mol*L^-1# #NaOH(aq)#?</h1>	null	2.0 mL	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We need (i) a stoichiometric equation.....</p> <p><mathjax>#2NaOH(aq) + H_2SO_4(aq) rarr Na_2SO_4(aq) + 2H_2O(l)#</mathjax></p> <p>And (ii) we need equivalent quantities of each reagent....</p> <p><mathjax>#"Moles of NaOH"=20mLxx10^-3LmL^-1xx0.1molL^-1=2xx10^-3mol.#</mathjax></p> <p>And we thus need a <mathjax>#1xx10^-3mol#</mathjax> quantity with respect to the DIACID <mathjax>#H_2SO_4#</mathjax>....</p> <p><mathjax>#V=n/C=(1xx10^-3mol)/(0.5molL^-1)xx10^3mLL^-1=2.0*mL#</mathjax></p> <p>Clearly, we should titrate the base with a LESS concentrated acid.....</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We need a <mathjax>#2.0mL#</mathjax> volume.......</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We need (i) a stoichiometric equation.....</p> <p><mathjax>#2NaOH(aq) + H_2SO_4(aq) rarr Na_2SO_4(aq) + 2H_2O(l)#</mathjax></p> <p>And (ii) we need equivalent quantities of each reagent....</p> <p><mathjax>#"Moles of NaOH"=20mLxx10^-3LmL^-1xx0.1molL^-1=2xx10^-3mol.#</mathjax></p> <p>And we thus need a <mathjax>#1xx10^-3mol#</mathjax> quantity with respect to the DIACID <mathjax>#H_2SO_4#</mathjax>....</p> <p><mathjax>#V=n/C=(1xx10^-3mol)/(0.5molL^-1)xx10^3mLL^-1=2.0mL#</mathjax></p> <p>Clearly, we should titrate the base with a LESS concentrated acid.....</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What volume of #0.5molL^-1# #"sulfuric acid"# is required for equivalence with a #20mL# volume of #0.5molL^-1# #NaOH(aq)#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#reactions-in-solution" itemprop="url"> <span class="breadcrumb" itemprop="title">Reactions in Solution</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/reactions-in-solution/titration-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">Titration Calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="477434" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-09-19T15:47:32" itemprop="dateCreated"> Sep 19, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We need a <mathjax>#2.0mL#</mathjax> volume.......</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We need (i) a stoichiometric equation.....</p> <p><mathjax>#2NaOH(aq) + H_2SO_4(aq) rarr Na_2SO_4(aq) + 2H_2O(l)#</mathjax></p> <p>And (ii) we need equivalent quantities of each reagent....</p> <p><mathjax>#"Moles of NaOH"=20mLxx10^-3LmL^-1xx0.1molL^-1=2xx10^-3mol.#</mathjax></p> <p>And we thus need a <mathjax>#1xx10^-3mol#</mathjax> quantity with respect to the DIACID <mathjax>#H_2SO_4#</mathjax>....</p> <p><mathjax>#V=n/C=(1xx10^-3mol)/(0.5molL^-1)xx10^3mLL^-1=2.0*mL#</mathjax></p> <p>Clearly, we should titrate the base with a LESS concentrated acid.....</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/477434" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-do-acid-base-titration-calculations"> How do you do acid base titration calculations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-use-titration-calculations-to-find-ph"> How do you use titration calculations to find pH? </a> </div> </li> <li class="relatedQuestionItem"> <div 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<div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1399 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What volume of #0.5molL^-1# #"sulfuric acid"# is required for equivalence with a #20mL# volume of #0.5mol*L^-1# #NaOH(aq)#?	null
739	a9e19b5c-6ddd-11ea-8bf1-ccda262736ce	https://socratic.org/questions/when-you-add-0-857-g-of-sodium-metal-to-an-excess-of-hydrochloric-acid-you-find-	-238.9 kJ/mol	start physical_unit 28 29 enthalpy kj/mol qc_end physical_unit 6 7 3 4 mass qc_end c_other OTHER qc_end physical_unit 28 29 17 18 heat_energy qc_end end	[{"type":"physical unit","value":"Enthalpy [OF] the reaction [IN] kJ/mol"}]	[{"type":"physical unit","value":"-238.9 kJ/mol"}]	[{"type":"physical unit","value":"Mass [OF] sodium metal [=] \\pu{0.857 g}"},{"type":"other","value":"Excess of hydrochloric acid."},{"type":"physical unit","value":"Produced heat [OF] the reaction [=] \\pu{8910 J}"}]	<h1 class="questionTitle" itemprop="name">When you add 0.857 g of sodium metal to an excess of hydrochloric acid, you find that 8910 J of heat are produced. What is the enthalpy of the reaction? </h1>	null	-238.9 kJ/mol	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We interrogate the reaction.....</p> <p><mathjax>#Na(s) + HCl(aq) rarr NaCl(aq) + 1/2H_2 + Delta#</mathjax></p> <p><mathjax>#"Moles of sodium"=(0.857g)/(22.99gmol^-1)=0.0373mol#</mathjax></p> <p>And thus <mathjax>#DeltaH_"rxn"^@=(8910J)/(0.0373mol)=-238.9kJmol^-1#</mathjax>, and we mean per mole of reaction as written. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#DeltaH_"rxn"^@=-238.9kJmol^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We interrogate the reaction.....</p> <p><mathjax>#Na(s) + HCl(aq) rarr NaCl(aq) + 1/2H_2 + Delta#</mathjax></p> <p><mathjax>#"Moles of sodium"=(0.857g)/(22.99gmol^-1)=0.0373mol#</mathjax></p> <p>And thus <mathjax>#DeltaH_"rxn"^@=(8910J)/(0.0373mol)=-238.9kJmol^-1#</mathjax>, and we mean per mole of reaction as written. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">When you add 0.857 g of sodium metal to an excess of hydrochloric acid, you find that 8910 J of heat are produced. What is the enthalpy of the reaction? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/enthalpy" itemprop="url"> <span class="breadcrumb" itemprop="title">Enthalpy</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="474127" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-09-11T17:18:29" itemprop="dateCreated"> Sep 11, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#DeltaH_"rxn"^@=-238.9kJmol^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We interrogate the reaction.....</p> <p><mathjax>#Na(s) + HCl(aq) rarr NaCl(aq) + 1/2H_2 + Delta#</mathjax></p> <p><mathjax>#"Moles of sodium"=(0.857g)/(22.99gmol^-1)=0.0373mol#</mathjax></p> <p>And thus <mathjax>#DeltaH_"rxn"^@=(8910J)/(0.0373mol)=-238.9kJmol^-1#</mathjax>, and we mean per mole of reaction as written. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/474127" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-enthalpy-changes-expressed-in-chemical-equations"> How are enthalpy changes expressed in chemical equations? 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</a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-enthalpy-a-state-function-2"> Why is enthalpy a state function? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-enthalpy-cannot-be-measured-directly"> Why can enthalpy not be measured directly? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-pressure-affect-enthalpy"> How does pressure affect enthalpy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-enthalpy-relate-to-internal-energy"> How does enthalpy relate to internal energy? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/enthalpy"> See all questions in Enthalpy </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 31908 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	When you add 0.857 g of sodium metal to an excess of hydrochloric acid, you find that 8910 J of heat are produced. What is the enthalpy of the reaction?	null
740	a8fd8976-6ddd-11ea-b75f-ccda262736ce	https://socratic.org/questions/if-a-gas-sample-occupies-4-2-l-at-a-pressure-of-101-kpa-what-volume-will-it-occu	1.8 L	start physical_unit 2 3 volume l qc_end physical_unit 2 3 5 6 volume qc_end physical_unit 2 3 11 12 pressure qc_end physical_unit 2 3 24 25 pressure qc_end end	[{"type":"physical unit","value":"Volume2 [OF] gas sample [IN] L"}]	[{"type":"physical unit","value":"1.8 L"}]	[{"type":"physical unit","value":"Volume1 [OF] gas sample [=] \\pu{4.2 L}"},{"type":"physical unit","value":"Pressure1 [OF] gas sample [=] \\pu{101 kPa}"},{"type":"physical unit","value":"Pressure2 [OF] gas sample [=] \\pu{235 kPa}"}]	<h1 class="questionTitle" itemprop="name">If a gas sample occupies 4.2 L at a pressure of 101 kPa. What volume will it occupy if the pressure is increased to 235 kPa?</h1>	null	1.8 L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>From Boyle’s Law</p> <blockquote> <p><mathjax>#"P"_1"V"_1 = "P"_2"V"_2#</mathjax></p> </blockquote> <p><mathjax>#"V"_2 = ("P"_1"V"_1)/"P"_2 = (101 cancel"kPa" × 4.2\ "L")/(235 cancel"kPa") = "1.8 L"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"1.8 L"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>From Boyle’s Law</p> <blockquote> <p><mathjax>#"P"_1"V"_1 = "P"_2"V"_2#</mathjax></p> </blockquote> <p><mathjax>#"V"_2 = ("P"_1"V"_1)/"P"_2 = (101 cancel"kPa" × 4.2\ "L")/(235 cancel"kPa") = "1.8 L"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">If a gas sample occupies 4.2 L at a pressure of 101 kPa. What volume will it occupy if the pressure is increased to 235 kPa?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/gas-pressure" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Pressure</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="615055" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/junaid-mirza"><img alt="" class="" src="https://profilepictures.socratic.org/BBeNx7NTQ7WmDQKll8wN_BDC9EDF4-5DCB-440D-8ADC-ADACE2966216.jpeg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/junaid-mirza"> Junaid Mirza </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-05-17T04:42:59" itemprop="dateCreated"> May 17, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"1.8 L"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>From Boyle’s Law</p> <blockquote> <p><mathjax>#"P"_1"V"_1 = "P"_2"V"_2#</mathjax></p> </blockquote> <p><mathjax>#"V"_2 = ("P"_1"V"_1)/"P"_2 = (101 cancel"kPa" × 4.2\ "L")/(235 cancel"kPa") = "1.8 L"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/615055" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-gas-pressure-be-changed"> How can gas pressure be changed? 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What volume will it occupy if the pressure is increased to 235 kPa?	null
741	abe9c489-6ddd-11ea-8440-ccda262736ce	https://socratic.org/questions/what-is-the-maximum-mass-of-s-8-that-can-be-produced-by-combining-83-0-g-of-each	117.14 g	start physical_unit 6 6 mass g qc_end physical_unit 22 22 13 14 mass qc_end physical_unit 25 25 13 14 mass qc_end chemical_equation 21 31 qc_end end	[{"type":"physical unit","value":"Mass [OF] S8 [IN] g"}]	[{"type":"physical unit","value":"117.14 g"}]	[{"type":"physical unit","value":"Mass [OF] SO2 [=] \\pu{83.0 g}"},{"type":"physical unit","value":"Mass [OF] H2S [=] \\pu{83.0 g}"},{"type":"chemical equation","value":"8 SO2 + 16 H2S -> 3 S8 + 16 H2O"}]	<h1 class="questionTitle" itemprop="name">What is the maximum mass of #S_8# that can be produced by combining 83.0 g of each reactant in the reaction #8SO_2 + 16H_2S -> 3S_8 + 16H_2O#??</h1>	null	117.14 g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that you need to use the <strong><a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a></strong> that exists between the two reactants to determine whether or not you're dealing with a <strong><a href="http://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a></strong>. </p> <p>Start by taking a look at the balanced chemical equation for this reaction</p> <blockquote> <p><mathjax>#color(red)(8)"SO"_2 + color(blue)(16)"H"_2"S" -> 3"S"_8 + 16"H"_2"O"#</mathjax></p> </blockquote> <p><em>Sulfur dioxide</em>, <mathjax>#"SO"_2#</mathjax>, and <em>hydrogen sulfide</em>, <mathjax>#"H"_2"S"#</mathjax>, will react in a <mathjax>#color(red)(1):color(blue)(2)#</mathjax> mole ratio, which means that the reaction will always consume <strong>twice as many</strong> moles of hydrogen sulfide as you have moles of sulfur dioxide <em>taking part in the reaction</em>. </p> <p>Your next step will be to determine how many <em>moles</em> of each reactant you get in those <mathjax>#"83.0-g"#</mathjax> samples. To do that, use their respective <strong>molar masses</strong></p> <p>For sulfur dioxide you will have</p> <blockquote> <p><mathjax>#83.0 color(red)(cancel(color(black)("g"))) * "1 mole SO"_2/(64.064color(red)(cancel(color(black)("g")))) = "1.2956 moles SO"_2#</mathjax></p> </blockquote> <p>For hydrogen sulfide you will have</p> <blockquote> <p><mathjax>#83.0color(red)(cancel(color(black)("g"))) * ("1 mole H"_2"S")/(34.081color(red)(cancel(color(black)("g")))) = "2.4354 moles H"_2"S"#</mathjax></p> </blockquote> <p>So, how do you test whether or not you're dealing with a <em><a href="http://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a></em>? </p> <p>Pick one reactant and use the <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratios</a> that exists between the two reactants. Let's go with sulfur dioxide here. </p> <blockquote> <p><mathjax>#1.2956color(red)(cancel(color(black)("moles SO"_2))) * (color(blue)(2)" moles H"_2"S")/(color(red)(1)color(red)(cancel(color(black)("mole SO"_2)))) = "2.5912 moles H"_2"S"#</mathjax></p> </blockquote> <p>So, in order for <strong>all the moles</strong> of sulfur dioxide to react, you need to have <mathjax>#2.5912#</mathjax> moles of hydrogen sulfide. SInce you have a little <em>less</em> than that, hydrogen sulfide will act as a <strong>limiting reagent</strong> here, i.e. it determine how many sulfur dioxide <em>actually</em> reacts. </p> <p>More specifically, the reaction will consume</p> <blockquote> <p><mathjax>#2.4354color(red)(cancel(color(black)("moles H"_2"S"))) * (color(red)(1)" mole SO"_2)/(color(blue)(2)color(red)(cancel(color(black)("moles H"_2"S")))) = "1.2177 moles SO"_2#</mathjax></p> </blockquote> <p>The remaining </p> <blockquote> <p><mathjax>#1.2956 - 1.2177 = "0.0779 moles SO"_2#</mathjax></p> </blockquote> <p>will be <strong>in excess</strong> and, implicitly, not take part in the reaction. </p> <p>Now that you know how many moles of each reactant take part in the reaction, pick one and use <a href="http://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio it has with sulfur, <mathjax>#"S"_8#</mathjax>, to determine how many grams would be <em>theoretically</em> result from the reaction. </p> <p>Let's pick sulfur dioxide, which has a <mathjax>#color(red)(8):3#</mathjax> mole ratio with sulfur. If <mathjax>#1.2177#</mathjax> moles of sulfur dioxide react, the reaction will produce</p> <blockquote> <p><mathjax>#1.2177color(red)(cancel(color(black)("moles SO"_2))) * "3 moles S"_2/(color(red)(8)color(red)(cancel(color(black)("moles SO"_2)))) = "0.45664 moles S"_8#</mathjax></p> </blockquote> <p>To determine how many <em>Grams</em> of sulfur would contain that many moles, use the element's <strong>molar mass</strong>. Do not forget that you're dealing with molecular sulfur, hence the <mathjax>#8#</mathjax> subscript in <mathjax>#"S"_8#</mathjax></p> <blockquote> <p><mathjax>#0.45664color(red)(cancel(color(black)("moles S"_8))) * (8 xx "32.065 g")/(1color(red)(cancel(color(black)("mole S"_8)))) = "117.14 g S"_8#</mathjax></p> </blockquote> <p>Rounded to three <strong><a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the samples of the two reactants, the answer will be </p> <blockquote> <p><mathjax>#m_(S_8) = color(green)(\|bar(ul(color(white)(a/a)"117 g S"_9color(white)(a/a)))\|)#</mathjax></p> </blockquote> <p>This represents the <strong>theoretical yield</strong> of the reaction, which is calculated assuming a <mathjax>#100%#</mathjax> reaction <strong><a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">yield</a></strong>. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"117 g S"_8#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that you need to use the <strong><a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a></strong> that exists between the two reactants to determine whether or not you're dealing with a <strong><a href="http://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a></strong>. </p> <p>Start by taking a look at the balanced chemical equation for this reaction</p> <blockquote> <p><mathjax>#color(red)(8)"SO"_2 + color(blue)(16)"H"_2"S" -> 3"S"_8 + 16"H"_2"O"#</mathjax></p> </blockquote> <p><em>Sulfur dioxide</em>, <mathjax>#"SO"_2#</mathjax>, and <em>hydrogen sulfide</em>, <mathjax>#"H"_2"S"#</mathjax>, will react in a <mathjax>#color(red)(1):color(blue)(2)#</mathjax> mole ratio, which means that the reaction will always consume <strong>twice as many</strong> moles of hydrogen sulfide as you have moles of sulfur dioxide <em>taking part in the reaction</em>. </p> <p>Your next step will be to determine how many <em>moles</em> of each reactant you get in those <mathjax>#"83.0-g"#</mathjax> samples. To do that, use their respective <strong>molar masses</strong></p> <p>For sulfur dioxide you will have</p> <blockquote> <p><mathjax>#83.0 color(red)(cancel(color(black)("g"))) * "1 mole SO"_2/(64.064color(red)(cancel(color(black)("g")))) = "1.2956 moles SO"_2#</mathjax></p> </blockquote> <p>For hydrogen sulfide you will have</p> <blockquote> <p><mathjax>#83.0color(red)(cancel(color(black)("g"))) * ("1 mole H"_2"S")/(34.081color(red)(cancel(color(black)("g")))) = "2.4354 moles H"_2"S"#</mathjax></p> </blockquote> <p>So, how do you test whether or not you're dealing with a <em><a href="http://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a></em>? </p> <p>Pick one reactant and use the <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratios</a> that exists between the two reactants. Let's go with sulfur dioxide here. </p> <blockquote> <p><mathjax>#1.2956color(red)(cancel(color(black)("moles SO"_2))) * (color(blue)(2)" moles H"_2"S")/(color(red)(1)color(red)(cancel(color(black)("mole SO"_2)))) = "2.5912 moles H"_2"S"#</mathjax></p> </blockquote> <p>So, in order for <strong>all the moles</strong> of sulfur dioxide to react, you need to have <mathjax>#2.5912#</mathjax> moles of hydrogen sulfide. SInce you have a little <em>less</em> than that, hydrogen sulfide will act as a <strong>limiting reagent</strong> here, i.e. it determine how many sulfur dioxide <em>actually</em> reacts. </p> <p>More specifically, the reaction will consume</p> <blockquote> <p><mathjax>#2.4354color(red)(cancel(color(black)("moles H"_2"S"))) * (color(red)(1)" mole SO"_2)/(color(blue)(2)color(red)(cancel(color(black)("moles H"_2"S")))) = "1.2177 moles SO"_2#</mathjax></p> </blockquote> <p>The remaining </p> <blockquote> <p><mathjax>#1.2956 - 1.2177 = "0.0779 moles SO"_2#</mathjax></p> </blockquote> <p>will be <strong>in excess</strong> and, implicitly, not take part in the reaction. </p> <p>Now that you know how many moles of each reactant take part in the reaction, pick one and use <a href="http://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio it has with sulfur, <mathjax>#"S"_8#</mathjax>, to determine how many grams would be <em>theoretically</em> result from the reaction. </p> <p>Let's pick sulfur dioxide, which has a <mathjax>#color(red)(8):3#</mathjax> mole ratio with sulfur. If <mathjax>#1.2177#</mathjax> moles of sulfur dioxide react, the reaction will produce</p> <blockquote> <p><mathjax>#1.2177color(red)(cancel(color(black)("moles SO"_2))) * "3 moles S"_2/(color(red)(8)color(red)(cancel(color(black)("moles SO"_2)))) = "0.45664 moles S"_8#</mathjax></p> </blockquote> <p>To determine how many <em>Grams</em> of sulfur would contain that many moles, use the element's <strong>molar mass</strong>. Do not forget that you're dealing with molecular sulfur, hence the <mathjax>#8#</mathjax> subscript in <mathjax>#"S"_8#</mathjax></p> <blockquote> <p><mathjax>#0.45664color(red)(cancel(color(black)("moles S"_8))) * (8 xx "32.065 g")/(1color(red)(cancel(color(black)("mole S"_8)))) = "117.14 g S"_8#</mathjax></p> </blockquote> <p>Rounded to three <strong><a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the samples of the two reactants, the answer will be </p> <blockquote> <p><mathjax>#m_(S_8) = color(green)(\|bar(ul(color(white)(a/a)"117 g S"_9color(white)(a/a)))\|)#</mathjax></p> </blockquote> <p>This represents the <strong>theoretical yield</strong> of the reaction, which is calculated assuming a <mathjax>#100%#</mathjax> reaction <strong><a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">yield</a></strong>. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the maximum mass of #S_8# that can be produced by combining 83.0 g of each reactant in the reaction #8SO_2 + 16H_2S -> 3S_8 + 16H_2O#??</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/limiting-reagent" itemprop="url"> <span class="breadcrumb" itemprop="title">Limiting Reagent</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="235642" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-06T01:08:26" itemprop="dateCreated"> Mar 6, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"117 g S"_8#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that you need to use the <strong><a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a></strong> that exists between the two reactants to determine whether or not you're dealing with a <strong><a href="http://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a></strong>. </p> <p>Start by taking a look at the balanced chemical equation for this reaction</p> <blockquote> <p><mathjax>#color(red)(8)"SO"_2 + color(blue)(16)"H"_2"S" -> 3"S"_8 + 16"H"_2"O"#</mathjax></p> </blockquote> <p><em>Sulfur dioxide</em>, <mathjax>#"SO"_2#</mathjax>, and <em>hydrogen sulfide</em>, <mathjax>#"H"_2"S"#</mathjax>, will react in a <mathjax>#color(red)(1):color(blue)(2)#</mathjax> mole ratio, which means that the reaction will always consume <strong>twice as many</strong> moles of hydrogen sulfide as you have moles of sulfur dioxide <em>taking part in the reaction</em>. </p> <p>Your next step will be to determine how many <em>moles</em> of each reactant you get in those <mathjax>#"83.0-g"#</mathjax> samples. To do that, use their respective <strong>molar masses</strong></p> <p>For sulfur dioxide you will have</p> <blockquote> <p><mathjax>#83.0 color(red)(cancel(color(black)("g"))) * "1 mole SO"_2/(64.064color(red)(cancel(color(black)("g")))) = "1.2956 moles SO"_2#</mathjax></p> </blockquote> <p>For hydrogen sulfide you will have</p> <blockquote> <p><mathjax>#83.0color(red)(cancel(color(black)("g"))) * ("1 mole H"_2"S")/(34.081color(red)(cancel(color(black)("g")))) = "2.4354 moles H"_2"S"#</mathjax></p> </blockquote> <p>So, how do you test whether or not you're dealing with a <em><a href="http://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a></em>? </p> <p>Pick one reactant and use the <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratios</a> that exists between the two reactants. Let's go with sulfur dioxide here. </p> <blockquote> <p><mathjax>#1.2956color(red)(cancel(color(black)("moles SO"_2))) * (color(blue)(2)" moles H"_2"S")/(color(red)(1)color(red)(cancel(color(black)("mole SO"_2)))) = "2.5912 moles H"_2"S"#</mathjax></p> </blockquote> <p>So, in order for <strong>all the moles</strong> of sulfur dioxide to react, you need to have <mathjax>#2.5912#</mathjax> moles of hydrogen sulfide. SInce you have a little <em>less</em> than that, hydrogen sulfide will act as a <strong>limiting reagent</strong> here, i.e. it determine how many sulfur dioxide <em>actually</em> reacts. </p> <p>More specifically, the reaction will consume</p> <blockquote> <p><mathjax>#2.4354color(red)(cancel(color(black)("moles H"_2"S"))) * (color(red)(1)" mole SO"_2)/(color(blue)(2)color(red)(cancel(color(black)("moles H"_2"S")))) = "1.2177 moles SO"_2#</mathjax></p> </blockquote> <p>The remaining </p> <blockquote> <p><mathjax>#1.2956 - 1.2177 = "0.0779 moles SO"_2#</mathjax></p> </blockquote> <p>will be <strong>in excess</strong> and, implicitly, not take part in the reaction. </p> <p>Now that you know how many moles of each reactant take part in the reaction, pick one and use <a href="http://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio it has with sulfur, <mathjax>#"S"_8#</mathjax>, to determine how many grams would be <em>theoretically</em> result from the reaction. </p> <p>Let's pick sulfur dioxide, which has a <mathjax>#color(red)(8):3#</mathjax> mole ratio with sulfur. If <mathjax>#1.2177#</mathjax> moles of sulfur dioxide react, the reaction will produce</p> <blockquote> <p><mathjax>#1.2177color(red)(cancel(color(black)("moles SO"_2))) * "3 moles S"_2/(color(red)(8)color(red)(cancel(color(black)("moles SO"_2)))) = "0.45664 moles S"_8#</mathjax></p> </blockquote> <p>To determine how many <em>Grams</em> of sulfur would contain that many moles, use the element's <strong>molar mass</strong>. Do not forget that you're dealing with molecular sulfur, hence the <mathjax>#8#</mathjax> subscript in <mathjax>#"S"_8#</mathjax></p> <blockquote> <p><mathjax>#0.45664color(red)(cancel(color(black)("moles S"_8))) * (8 xx "32.065 g")/(1color(red)(cancel(color(black)("mole S"_8)))) = "117.14 g S"_8#</mathjax></p> </blockquote> <p>Rounded to three <strong><a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the samples of the two reactants, the answer will be </p> <blockquote> <p><mathjax>#m_(S_8) = color(green)(\|bar(ul(color(white)(a/a)"117 g S"_9color(white)(a/a)))\|)#</mathjax></p> </blockquote> <p>This represents the <strong>theoretical yield</strong> of the reaction, which is calculated assuming a <mathjax>#100%#</mathjax> reaction <strong><a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">yield</a></strong>. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/235642" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-how-much-of-the-excess-reactant-is-left-over-also-how-do-yo"> How do you determine how much of the excess reactant is left over? 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742	ad1663ae-6ddd-11ea-86b3-ccda262736ce	https://socratic.org/questions/determine-the-total-pressure-of-a-gas-mixture-that-contains-oxygen-nitrogen-and-	93.40 kPa	start physical_unit 6 7 total_pressure kpa qc_end end	[{"type":"physical unit","value":"Total pressure [OF] the gas mixture [IN] kPa"}]	[{"type":"physical unit","value":"93.40 kPa"}]	[{"type":"physical unit","value":"Partial pressure [OF] O2 [=] \\pu{20.0 kPa}"},{"type":"physical unit","value":"Partial pressure [OF] N2 [=] \\pu{46.2 kPa}"},{"type":"physical unit","value":"Partial pressure [OF] He [=] \\pu{26.7 kPa}"}]	<h1 class="questionTitle" itemprop="name">Determine the total pressure of a gas mixture that contains oxygen, nitrogen, and helium if the partial pressures of the gases are as follows: #"P"_ ("O"_ 2) = "20.0 kPa"#, #P_ ("N"_ 2) = "46.7 kPa"#, and #P_ "He" = "26.7 kPa"# ?</h1>	null	93.40 kPa	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that the <strong>total pressure</strong> of the gaseous mixture will be equal to the sum of the <em>partial pressures</em> of the constituent gases <mathjax>#->#</mathjax> think <strong>Dalton's Law of Partial Pressures</strong> here. </p> <p>In other words, if you add the pressure that each gas would exert <strong>if alone</strong> in the container, you get the <strong>total pressure</strong> of the mixture. </p> <p><img alt="http://ch301.cm.utexas.edu/gases/#mixtures/mixtures-all.php" src="https://useruploads.socratic.org/iYb6W7kOTdX0Jt9SS8J4_partial-pressures.svg"/> </p> <p>So for a mixture that contains <mathjax>#i#</mathjax> gases, you have</p> <blockquote> <p><mathjax>#P_"total" = sum_i P_i#</mathjax></p> </blockquote> <p>In your case, the mixture contains three gases: oxygen gas, nitrogen gas, and helium. Moreover, you know that</p> <blockquote> <ul> <li><mathjax>#P_( "O"_ 2) = "20.0 kPa"#</mathjax></li> <li><mathjax>#P_ ("N"_ 2) = "46.7 kPa"#</mathjax></li> <li><mathjax>#P_ "he" = "26.7 kPa"#</mathjax></li> </ul> </blockquote> <p>This means that the <strong>total pressure</strong> of the gas is given by</p> <blockquote> <p><mathjax>#P_"total" = P_ ("O"_ 2) + P_ ("N"_ 2) + P_ "He"#</mathjax></p> </blockquote> <p>which is equal to</p> <blockquote> <p><mathjax>#P_"total" = "20.0 kPa" + "46.7 kPa" + "26.7 kPa"#</mathjax></p> <p><mathjax>#color(darkgreen)(ul(color(black)(P_"total" = "93.4 kPa")))#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"93.4 kPa"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that the <strong>total pressure</strong> of the gaseous mixture will be equal to the sum of the <em>partial pressures</em> of the constituent gases <mathjax>#->#</mathjax> think <strong>Dalton's Law of Partial Pressures</strong> here. </p> <p>In other words, if you add the pressure that each gas would exert <strong>if alone</strong> in the container, you get the <strong>total pressure</strong> of the mixture. </p> <p><img alt="http://ch301.cm.utexas.edu/gases/#mixtures/mixtures-all.php" src="https://useruploads.socratic.org/iYb6W7kOTdX0Jt9SS8J4_partial-pressures.svg"/> </p> <p>So for a mixture that contains <mathjax>#i#</mathjax> gases, you have</p> <blockquote> <p><mathjax>#P_"total" = sum_i P_i#</mathjax></p> </blockquote> <p>In your case, the mixture contains three gases: oxygen gas, nitrogen gas, and helium. Moreover, you know that</p> <blockquote> <ul> <li><mathjax>#P_( "O"_ 2) = "20.0 kPa"#</mathjax></li> <li><mathjax>#P_ ("N"_ 2) = "46.7 kPa"#</mathjax></li> <li><mathjax>#P_ "he" = "26.7 kPa"#</mathjax></li> </ul> </blockquote> <p>This means that the <strong>total pressure</strong> of the gas is given by</p> <blockquote> <p><mathjax>#P_"total" = P_ ("O"_ 2) + P_ ("N"_ 2) + P_ "He"#</mathjax></p> </blockquote> <p>which is equal to</p> <blockquote> <p><mathjax>#P_"total" = "20.0 kPa" + "46.7 kPa" + "26.7 kPa"#</mathjax></p> <p><mathjax>#color(darkgreen)(ul(color(black)(P_"total" = "93.4 kPa")))#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Determine the total pressure of a gas mixture that contains oxygen, nitrogen, and helium if the partial pressures of the gases are as follows: #"P"_ ("O"_ 2) = "20.0 kPa"#, #P_ ("N"_ 2) = "46.7 kPa"#, and #P_ "He" = "26.7 kPa"# ?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/partial-pressure" itemprop="url"> <span class="breadcrumb" itemprop="title">Partial Pressure</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="557135" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-02-24T00:45:58" itemprop="dateCreated"> Feb 24, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"93.4 kPa"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that the <strong>total pressure</strong> of the gaseous mixture will be equal to the sum of the <em>partial pressures</em> of the constituent gases <mathjax>#->#</mathjax> think <strong>Dalton's Law of Partial Pressures</strong> here. </p> <p>In other words, if you add the pressure that each gas would exert <strong>if alone</strong> in the container, you get the <strong>total pressure</strong> of the mixture. </p> <p><img alt="http://ch301.cm.utexas.edu/gases/#mixtures/mixtures-all.php" src="https://useruploads.socratic.org/iYb6W7kOTdX0Jt9SS8J4_partial-pressures.svg"/> </p> <p>So for a mixture that contains <mathjax>#i#</mathjax> gases, you have</p> <blockquote> <p><mathjax>#P_"total" = sum_i P_i#</mathjax></p> </blockquote> <p>In your case, the mixture contains three gases: oxygen gas, nitrogen gas, and helium. Moreover, you know that</p> <blockquote> <ul> <li><mathjax>#P_( "O"_ 2) = "20.0 kPa"#</mathjax></li> <li><mathjax>#P_ ("N"_ 2) = "46.7 kPa"#</mathjax></li> <li><mathjax>#P_ "he" = "26.7 kPa"#</mathjax></li> </ul> </blockquote> <p>This means that the <strong>total pressure</strong> of the gas is given by</p> <blockquote> <p><mathjax>#P_"total" = P_ ("O"_ 2) + P_ ("N"_ 2) + P_ "He"#</mathjax></p> </blockquote> <p>which is equal to</p> <blockquote> <p><mathjax>#P_"total" = "20.0 kPa" + "46.7 kPa" + "26.7 kPa"#</mathjax></p> <p><mathjax>#color(darkgreen)(ul(color(black)(P_"total" = "93.4 kPa")))#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/557135" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/534e256802bf342adfa30010"> How do you do a steam distillation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/53613f9f02bf3416cd9f8a34"> Question #f8a34 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-i-calculate-the-total-pressure-of-a-mixture-of-gases-by-adding-together-the-"> Can I calculate the total pressure of a mixture of gases by adding together the partial... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-formula-of-partial-pressure"> What is the formula of partial pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-dalton-s-law-of-partial-pressures"> What is the Dalton's law of partial pressures? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/nitrogen-gas-n2-reacts-with-hydrogen-gas-h2-to-form-ammonia-nh3-at-200-c-in-a-cl"> Nitrogen gas (N2) reacts with hydrogen gas (H2) to form ammonia (NH3). 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743	ac885b29-6ddd-11ea-8d2f-ccda262736ce	https://socratic.org/questions/how-do-you-balance-mg-no-3-2-k-3po-4-mg-3-po-4-2-kno-3	3 Mg(NO3)2 + 2 K3PO4 -> Mg3(PO4)2 + 6 KNO3	start chemical_equation qc_end chemical_equation 4 10 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the equation"}]	[{"type":"chemical equation","value":"3 Mg(NO3)2 + 2 K3PO4 -> Mg3(PO4)2 + 6 KNO3"}]	[{"type":"chemical equation","value":"Mg(NO3)2 + K3PO4 -> Mg3(PO4)2 + KNO3"}]	<h1 class="questionTitle" itemprop="name">How do you balance #Mg(NO_3)_2 + K_3PO_4 -> Mg_3(PO_4)_2 + KNO_3#?</h1>	null	3 Mg(NO3)2 + 2 K3PO4 -> Mg3(PO4)2 + 6 KNO3	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Is the given reaction stoichiometrically balanced? For every reactant particle, is there a corresponding product particle. If there is not, then the reaction cannot be accepted as a representation of chemical (i.e. physical) reality.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#3Mg(NO_3)_2 + 2K_3PO_4 rarr Mg_3(PO_4)_2 + 6KNO_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Is the given reaction stoichiometrically balanced? For every reactant particle, is there a corresponding product particle. If there is not, then the reaction cannot be accepted as a representation of chemical (i.e. physical) reality.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you balance #Mg(NO_3)_2 + K_3PO_4 -> Mg_3(PO_4)_2 + KNO_3#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="387770" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-07T07:24:48" itemprop="dateCreated"> Mar 7, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#3Mg(NO_3)_2 + 2K_3PO_4 rarr Mg_3(PO_4)_2 + 6KNO_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Is the given reaction stoichiometrically balanced? For every reactant particle, is there a corresponding product particle. If there is not, then the reaction cannot be accepted as a representation of chemical (i.e. physical) reality.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/387770" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="389272" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/nikka-c"><img alt="" class="" src="https://profilepictures.socratic.org/AQ8VOCyTM1J7U0TvIWhw_nkahara.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/nikka-c"> Nikka C. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-10T09:38:16" itemprop="dateCreated"> Mar 10, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#3Mg(NO_3)_2#</mathjax> + <mathjax>#2K_3PO_4#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#Mg_3(PO_4)_2#</mathjax> + <mathjax>#)6KNO_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Let's assume that the chemical reaction will progress as written.</p> <p>Balancing ionic equations can be quite easy AS LONG AS YOU MEMORIZE YOUR CATIONS AND ANIONS. There are a number of ways to do this, so you have to find a way that actually works for you. For now, let's do a tally sheet of all ions involved.</p> <p><mathjax>#Mg(NO_3)_2#</mathjax> + <mathjax>#K_3PO_4#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#Mg_3(PO_4)_2#</mathjax> + <mathjax>#KNO_3#</mathjax> </p> <p>Left side:<br/> <mathjax>#Mg^(2+)#</mathjax> = 1<br/> <mathjax>#NO_3^(-1)#</mathjax> = 2<br/> <mathjax>#K^(1+)#</mathjax> = 3<br/> <mathjax>#PO_4^(-3)#</mathjax> = 1</p> <p>Right side:</p> <p><mathjax>#Mg^(2+)#</mathjax> = 3<br/> <mathjax>#NO_3^(-1)#</mathjax> = 1<br/> <mathjax>#K^(1+)#</mathjax> = 1<br/> <mathjax>#PO_4^(-3)#</mathjax> = 2</p> <p>Let's balance the most complicated ion first: the <mathjax>#PO_4^(3-)#</mathjax>.</p> <p>Left side:<br/> <mathjax>#Mg^(2+)#</mathjax> = 1<br/> <mathjax>#NO_3^(-1)#</mathjax> = 2<br/> <mathjax>#K^(1+)#</mathjax> = 3<br/> <mathjax>#PO_4^(-3)#</mathjax> = 1 x <mathjax>#color(red)2#</mathjax> = <strong>2</strong></p> <p>Right side:</p> <p><mathjax>#Mg^(2+)#</mathjax> = 3<br/> <mathjax>#NO_3^(-1)#</mathjax> = 1<br/> <mathjax>#K^(1+)#</mathjax> = 1<br/> <mathjax>#PO_4^(-3)#</mathjax> = <strong>2</strong></p> <p>Since the <mathjax>#PO_4^(3-)#</mathjax> ion is bonded to the <mathjax>#K^(1+)#</mathjax> ion, you need to multiply it by 2 as well.</p> <p>Left side:<br/> <mathjax>#Mg^(2+)#</mathjax> = 1<br/> <mathjax>#NO_3^(-1)#</mathjax> = 2<br/> <mathjax>#K^(1+)#</mathjax> = 3 x <mathjax>#color(red)2#</mathjax> = <strong>6</strong><br/> <mathjax>#PO_4^(-3)#</mathjax> = 1 x <mathjax>#color(red)2#</mathjax> = <strong>2</strong></p> <p>Right side:</p> <p><mathjax>#Mg^(2+)#</mathjax> = 3<br/> <mathjax>#NO_3^(-1)#</mathjax> = 1<br/> <mathjax>#K^(1+)#</mathjax> = 1<br/> <mathjax>#PO_4^(-3)#</mathjax> = <strong>2</strong></p> <p><mathjax>#Mg(NO_3)_2#</mathjax> + <mathjax>#color(red)2K_3PO_4#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#Mg_3(PO_4)_2#</mathjax> + <mathjax>#KNO_3#</mathjax> </p> <p>Now notice that this move have created an imbalance in your <mathjax>#K^(1+)#</mathjax> ion with 6 ions on the left as opposed to only one ion on the right. To compensate, we have:</p> <p>Left side:<br/> <mathjax>#Mg^(2+)#</mathjax> = 1<br/> <mathjax>#NO_3^(-1)#</mathjax> = 2<br/> <mathjax>#K^(1+)#</mathjax> = 3 x 2 = <strong>6</strong><br/> <mathjax>#PO_4^(-3)#</mathjax> = 1 x 2 = <strong>2</strong></p> <p>Right side:</p> <p><mathjax>#Mg^(2+)#</mathjax> = 3<br/> <mathjax>#NO_3^(-1)#</mathjax> = 1<br/> <mathjax>#K^(1+)#</mathjax> = 1 x <mathjax>#color(blue)6#</mathjax> = <strong>6</strong><br/> <mathjax>#PO_4^(-3)#</mathjax> = <strong>2</strong></p> <p>Again, since the <mathjax>#K^(1+)#</mathjax> ion is bonded to the <mathjax>#NO_3^(-1)#</mathjax>, we need to also multiply it by 6.</p> <p>Left side:<br/> <mathjax>#Mg^(2+)#</mathjax> = 1<br/> <mathjax>#NO_3^(-1)#</mathjax> = 2 <br/> <mathjax>#K^(1+)#</mathjax> = 3 x 2 = <strong>6</strong><br/> <mathjax>#PO_4^(-3)#</mathjax> = 1 x 2 = <strong>2</strong></p> <p>Right side:</p> <p><mathjax>#Mg^(2+)#</mathjax> = 3<br/> <mathjax>#NO_3^(-1)#</mathjax> = 1 x <mathjax>#color(blue)6#</mathjax> = <strong>6</strong><br/> <mathjax>#K^(1+)#</mathjax> = 1 x <mathjax>#color(blue)6#</mathjax> = <strong>6</strong><br/> <mathjax>#PO_4^(-3)#</mathjax> = <strong>2</strong></p> <p><mathjax>#Mg(NO_3)_2#</mathjax> + <mathjax>#color(red)2K_3PO_4#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#Mg_3(PO_4)_2#</mathjax> + <mathjax>#color(blue)6KNO_3#</mathjax> </p> <p>Now your <mathjax>#NO_3^(-1)#</mathjax> ion is unbalanced with only 2 ions on the left as opposed to the 6 on the right. Thus,</p> <p>Left side:<br/> <mathjax>#Mg^(2+)#</mathjax> = 1 <br/> <mathjax>#NO_3^(-1)#</mathjax> = 2 x <mathjax>#color(green)3#</mathjax> = <strong>6</strong><br/> <mathjax>#K^(1+)#</mathjax> = 3 x 2 = <strong>6</strong><br/> <mathjax>#PO_4^(-3)#</mathjax> = 1 x 2 = <strong>2</strong></p> <p>Right side:</p> <p><mathjax>#Mg^(2+)#</mathjax> = 3<br/> <mathjax>#NO_3^(-1)#</mathjax> = 1 x 6 = <strong>6</strong><br/> <mathjax>#K^(1+)#</mathjax> = 1 x 6 = <strong>6</strong><br/> <mathjax>#PO_4^(-3)#</mathjax> = <strong>2</strong></p> <p>Same as above the <mathjax>#NO_3^(-1)#</mathjax> ion is bonded with your <mathjax>#Mg^(2+)#</mathjax>. Therefore,</p> <p>Left side:<br/> <mathjax>#Mg^(2+)#</mathjax> = 1 x <mathjax>#color(green)3#</mathjax> ==<strong>3</strong><br/> <mathjax>#NO_3^(-1)#</mathjax> = 2 x <mathjax>#color(green)3#</mathjax> = <strong>6</strong><br/> <mathjax>#K^(1+)#</mathjax> = 3 x 2 = <strong>6</strong><br/> <mathjax>#PO_4^(-3)#</mathjax> = 1 x 2 = <strong>2</strong></p> <p>Right side:</p> <p><mathjax>#Mg^(2+)#</mathjax> = <strong>3</strong><br/> <mathjax>#NO_3^(-1)#</mathjax> = 1 x 6 = <strong>6</strong><br/> <mathjax>#K^(1+)#</mathjax> = 1 x 6 = <strong>6</strong><br/> <mathjax>#PO_4^(-3)#</mathjax> = <strong>2</strong></p> <p>Final Answer:</p> <p><mathjax>#color(green)3Mg(NO_3)_2#</mathjax> + <mathjax>#color(red)2K_3PO_4#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#Mg_3(PO_4)_2#</mathjax> + <mathjax>#color(blue)6KNO_3#</mathjax> (balanced)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/389272" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------> H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -> Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? 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744	aa79a54a-6ddd-11ea-8b04-ccda262736ce	https://socratic.org/questions/a-sample-of-air-has-a-volume-of-140-0-ml-at-67-c-at-what-temperature-will-its-vo	-152.15 ℃	start physical_unit 1 3 temperature °c qc_end physical_unit 1 3 11 12 temperature qc_end physical_unit 1 3 8 9 volume qc_end physical_unit 1 3 21 22 volume qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Temperature2 [OF] air sample [IN] ℃"}]	[{"type":"physical unit","value":"-152.15 ℃"}]	[{"type":"physical unit","value":"Temperature1 [OF] air sample [=] \\pu{67 ℃}"},{"type":"physical unit","value":"Volume1 [OF] air sample [=] \\pu{140.0 mL}"},{"type":"physical unit","value":"Volume2 [OF] air sample [=] \\pu{50.0 mL}"},{"type":"other","value":"Constant pressure."}]	<h1 class="questionTitle" itemprop="name">A sample of air has a volume of 140.0 mL at 67°C . At what temperature will its volume be 50.0 mL at constant pressure?</h1>	null	-152.15 ℃	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><em>Volume</em> and <em>temperature</em> have a <strong>direct relationship</strong> when pressure and number of moles are <strong>kept constant</strong> - this is known as <a href="http://socratic.org/chemistry/the-behavior-of-gases/charles-law">Charles' Law</a>. </p> <p>What that means is that when pressure and number of moles are kept constant, <strong>increasing</strong> the temperature will result in an <strong>increase</strong> in volume. </p> <p>Likewise, a <strong>decrease</strong> in temperature will result in a <strong>decrease</strong> in volume. </p> <p><img alt="https://saylordotorg.github.io/text_introductory-chemistry/s10-03-gas-laws.html" src="https://useruploads.socratic.org/RnABcRmVQyDxBcZdraud_47356453c6e8c28b4aef25ea63139f7b.jpg"/> </p> <p>In your case, the volume of the gas <strong>decreased</strong> by a factor of about <mathjax>#3#</mathjax>, from <mathjax>#"140.0 mL"#</mathjax> to <mathjax>#"50.0 mL"#</mathjax>. That means that you should expect the temperature to <strong>lower</strong> by the <em>same factor</em> of about <mathjax>#3#</mathjax>. </p> <p>Mathematically, this can be written as </p> <blockquote> <p><mathjax>#color(blue)(V_1/T_1 = V_2/T_2)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#V_1#</mathjax>, <mathjax>#T_1#</mathjax> - the volume and temperature of the gas at an initial state<br/> <mathjax>#V_2#</mathjax>, <mathjax>#T_2#</mathjax> - the volume and temperature of the gas at a final state</p> <p>It is important to remember that the temperature of the gas <strong>must be</strong> expressed in <em>Kelvin</em>. The initial temperature of the gas will be </p> <blockquote> <p><mathjax>#T_1 = (273.15 + 67.0)"K" = "340.15 K"#</mathjax></p> </blockquote> <p>Rearrange the above equation to solve for <mathjax>#T_2#</mathjax></p> <blockquote> <p><mathjax>#V_1/T_1 = V_2/T_2 implies T_2 = V_2/V_1 * T_1#</mathjax></p> <p><mathjax>#T_2 = (50.0 color(red)(cancel(color(black)("mL"))))/(140.0color(red)(cancel(color(black)("mL")))) * "340.15 K"#</mathjax></p> <p><mathjax>#T_2 = "121.48 K"#</mathjax></p> </blockquote> <p>Rounded to three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the answer will be </p> <blockquote> <p><mathjax>#T_2 = color(green)("121 K")#</mathjax></p> </blockquote> <p>If you want, you can express this in <em>degrees Celsius</em></p> <blockquote> <p><mathjax>#T_2 = 121 - 273.15 = -152^@"C"#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"121 K"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><em>Volume</em> and <em>temperature</em> have a <strong>direct relationship</strong> when pressure and number of moles are <strong>kept constant</strong> - this is known as <a href="http://socratic.org/chemistry/the-behavior-of-gases/charles-law">Charles' Law</a>. </p> <p>What that means is that when pressure and number of moles are kept constant, <strong>increasing</strong> the temperature will result in an <strong>increase</strong> in volume. </p> <p>Likewise, a <strong>decrease</strong> in temperature will result in a <strong>decrease</strong> in volume. </p> <p><img alt="https://saylordotorg.github.io/text_introductory-chemistry/s10-03-gas-laws.html" src="https://useruploads.socratic.org/RnABcRmVQyDxBcZdraud_47356453c6e8c28b4aef25ea63139f7b.jpg"/> </p> <p>In your case, the volume of the gas <strong>decreased</strong> by a factor of about <mathjax>#3#</mathjax>, from <mathjax>#"140.0 mL"#</mathjax> to <mathjax>#"50.0 mL"#</mathjax>. That means that you should expect the temperature to <strong>lower</strong> by the <em>same factor</em> of about <mathjax>#3#</mathjax>. </p> <p>Mathematically, this can be written as </p> <blockquote> <p><mathjax>#color(blue)(V_1/T_1 = V_2/T_2)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#V_1#</mathjax>, <mathjax>#T_1#</mathjax> - the volume and temperature of the gas at an initial state<br/> <mathjax>#V_2#</mathjax>, <mathjax>#T_2#</mathjax> - the volume and temperature of the gas at a final state</p> <p>It is important to remember that the temperature of the gas <strong>must be</strong> expressed in <em>Kelvin</em>. The initial temperature of the gas will be </p> <blockquote> <p><mathjax>#T_1 = (273.15 + 67.0)"K" = "340.15 K"#</mathjax></p> </blockquote> <p>Rearrange the above equation to solve for <mathjax>#T_2#</mathjax></p> <blockquote> <p><mathjax>#V_1/T_1 = V_2/T_2 implies T_2 = V_2/V_1 * T_1#</mathjax></p> <p><mathjax>#T_2 = (50.0 color(red)(cancel(color(black)("mL"))))/(140.0color(red)(cancel(color(black)("mL")))) * "340.15 K"#</mathjax></p> <p><mathjax>#T_2 = "121.48 K"#</mathjax></p> </blockquote> <p>Rounded to three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the answer will be </p> <blockquote> <p><mathjax>#T_2 = color(green)("121 K")#</mathjax></p> </blockquote> <p>If you want, you can express this in <em>degrees Celsius</em></p> <blockquote> <p><mathjax>#T_2 = 121 - 273.15 = -152^@"C"#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A sample of air has a volume of 140.0 mL at 67°C . At what temperature will its volume be 50.0 mL at constant pressure?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/charles-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Charles' Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="207311" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-03T02:01:53" itemprop="dateCreated"> Jan 3, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"121 K"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><em>Volume</em> and <em>temperature</em> have a <strong>direct relationship</strong> when pressure and number of moles are <strong>kept constant</strong> - this is known as <a href="http://socratic.org/chemistry/the-behavior-of-gases/charles-law">Charles' Law</a>. </p> <p>What that means is that when pressure and number of moles are kept constant, <strong>increasing</strong> the temperature will result in an <strong>increase</strong> in volume. </p> <p>Likewise, a <strong>decrease</strong> in temperature will result in a <strong>decrease</strong> in volume. </p> <p><img alt="https://saylordotorg.github.io/text_introductory-chemistry/s10-03-gas-laws.html" src="https://useruploads.socratic.org/RnABcRmVQyDxBcZdraud_47356453c6e8c28b4aef25ea63139f7b.jpg"/> </p> <p>In your case, the volume of the gas <strong>decreased</strong> by a factor of about <mathjax>#3#</mathjax>, from <mathjax>#"140.0 mL"#</mathjax> to <mathjax>#"50.0 mL"#</mathjax>. That means that you should expect the temperature to <strong>lower</strong> by the <em>same factor</em> of about <mathjax>#3#</mathjax>. </p> <p>Mathematically, this can be written as </p> <blockquote> <p><mathjax>#color(blue)(V_1/T_1 = V_2/T_2)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#V_1#</mathjax>, <mathjax>#T_1#</mathjax> - the volume and temperature of the gas at an initial state<br/> <mathjax>#V_2#</mathjax>, <mathjax>#T_2#</mathjax> - the volume and temperature of the gas at a final state</p> <p>It is important to remember that the temperature of the gas <strong>must be</strong> expressed in <em>Kelvin</em>. The initial temperature of the gas will be </p> <blockquote> <p><mathjax>#T_1 = (273.15 + 67.0)"K" = "340.15 K"#</mathjax></p> </blockquote> <p>Rearrange the above equation to solve for <mathjax>#T_2#</mathjax></p> <blockquote> <p><mathjax>#V_1/T_1 = V_2/T_2 implies T_2 = V_2/V_1 * T_1#</mathjax></p> <p><mathjax>#T_2 = (50.0 color(red)(cancel(color(black)("mL"))))/(140.0color(red)(cancel(color(black)("mL")))) * "340.15 K"#</mathjax></p> <p><mathjax>#T_2 = "121.48 K"#</mathjax></p> </blockquote> <p>Rounded to three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the answer will be </p> <blockquote> <p><mathjax>#T_2 = color(green)("121 K")#</mathjax></p> </blockquote> <p>If you want, you can express this in <em>degrees Celsius</em></p> <blockquote> <p><mathjax>#T_2 = 121 - 273.15 = -152^@"C"#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/207311" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-must-charles-law-be-in-kelvins"> Why must Charles' law be in kelvin? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-charles-law-formula"> What is Charles' law formula? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/oxygen-gas-is-at-a-temperature-of-40-c-when-it-occupies-a-volume-of-2-3-liters-t"> Oxygen gas is at a temperature of 40°C when it occupies a volume of 2.3 liters. 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What will be volume of oxygen when the... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/charles-law"> See all questions in Charles' Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 38434 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A sample of air has a volume of 140.0 mL at 67°C . At what temperature will its volume be 50.0 mL at constant pressure?	null
745	a930a8f0-6ddd-11ea-95a0-ccda262736ce	https://socratic.org/questions/a-canister-contains-the-following-gases-at-the-following-pressures-oxygen-gas-at	1.86 atm	start physical_unit 32 33 total_pressure atm qc_end physical_unit 10 11 13 14 partial_pressure qc_end physical_unit 15 17 19 20 partial_pressure qc_end end	[{"type":"physical unit","value":"Total pressure [OF] this canister [IN] atm"}]	[{"type":"physical unit","value":"1.86 atm"}]	[{"type":"physical unit","value":"Partial pressure [OF] oxygen gas [=] \\pu{760 mmHg}"},{"type":"physical unit","value":"Partial pressure [OF] carbon dioxide gas [=] \\pu{0.24 atm}"},{"type":"physical unit","value":"Partial pressure [OF] nitrogen gas [=] \\pu{63 kPa}"}]	<h1 class="questionTitle" itemprop="name">A canister contains the following gases at the following pressures: oxygen gas at 760 mmHg, carbon dioxide gas at 0.24 atm, and nitrogen at 63 kPa. What is the total pressure inside this canister?</h1>	null	1.86 atm	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>According to <strong>Dalton's law of partial pressures</strong>, the total pressure of a system is the sum of the individual pressures of the gases if they were present alone.</p> <p>To keep things clear, we need to convert the pressure units to a <em>single</em> unit, and I'll choose <mathjax>#"mm Hg"#</mathjax>. </p> <p>Converting them:</p> <p><mathjax>#P_"O" = 760#</mathjax> <mathjax>#"mm Hg"#</mathjax> (given, no conversion necessary)</p> <p><mathjax>#P_ ("CO"_2) = 0.24cancel("atm")((760"mm Hg")/(1cancel("atm"))) = 180#</mathjax> <mathjax>#"mm Hg"#</mathjax> (<mathjax>#2#</mathjax> sig figs)</p> <p><mathjax>#P_ ("N"_2) = 63"kPa"((760"mm Hg")/(101.325"kPa")) = 470#</mathjax> <mathjax>#"mm Hg"#</mathjax> (<mathjax>#2#</mathjax> sig figs)</p> <p>Now that our units are consistent, let's add them up:</p> <p><mathjax>#760"mm Hg" + 180"mm Hg" + 470"mm Hg" = color(red)(1410#</mathjax> <mathjax>#color(red)("mm Hg"#</mathjax></p> <p>If you chose other units, you may have gotten answers something like</p> <p><mathjax>#color(red)(1.86#</mathjax> <mathjax>#color(red)("atm"#</mathjax></p> <p>or</p> <p><mathjax>#color(red)(188#</mathjax> <mathjax>#color(red)("kPa"#</mathjax></p> <p>(This may differ slightly from the other calculated pressures due to arbitrary rounding here and there, but these answers are correct, if you choose to follow all the rules for <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a>.)</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#P_"total" = 1410#</mathjax> <mathjax>#"mm Hg" = 1.86#</mathjax> <mathjax>#"atm" = 188#</mathjax> <mathjax>#"kPa"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>According to <strong>Dalton's law of partial pressures</strong>, the total pressure of a system is the sum of the individual pressures of the gases if they were present alone.</p> <p>To keep things clear, we need to convert the pressure units to a <em>single</em> unit, and I'll choose <mathjax>#"mm Hg"#</mathjax>. </p> <p>Converting them:</p> <p><mathjax>#P_"O" = 760#</mathjax> <mathjax>#"mm Hg"#</mathjax> (given, no conversion necessary)</p> <p><mathjax>#P_ ("CO"_2) = 0.24cancel("atm")((760"mm Hg")/(1cancel("atm"))) = 180#</mathjax> <mathjax>#"mm Hg"#</mathjax> (<mathjax>#2#</mathjax> sig figs)</p> <p><mathjax>#P_ ("N"_2) = 63"kPa"((760"mm Hg")/(101.325"kPa")) = 470#</mathjax> <mathjax>#"mm Hg"#</mathjax> (<mathjax>#2#</mathjax> sig figs)</p> <p>Now that our units are consistent, let's add them up:</p> <p><mathjax>#760"mm Hg" + 180"mm Hg" + 470"mm Hg" = color(red)(1410#</mathjax> <mathjax>#color(red)("mm Hg"#</mathjax></p> <p>If you chose other units, you may have gotten answers something like</p> <p><mathjax>#color(red)(1.86#</mathjax> <mathjax>#color(red)("atm"#</mathjax></p> <p>or</p> <p><mathjax>#color(red)(188#</mathjax> <mathjax>#color(red)("kPa"#</mathjax></p> <p>(This may differ slightly from the other calculated pressures due to arbitrary rounding here and there, but these answers are correct, if you choose to follow all the rules for <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a>.)</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A canister contains the following gases at the following pressures: oxygen gas at 760 mmHg, carbon dioxide gas at 0.24 atm, and nitrogen at 63 kPa. What is the total pressure inside this canister?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/gas-pressure" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Pressure</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="440482" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/mrtas"><img alt="" class="" src="https://profilepictures.socratic.org/HY14X7r4S6AyDQgK2gwQ_IMG_0062.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/mrtas"> Nathan L. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-16T03:27:50" itemprop="dateCreated"> Jun 16, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#P_"total" = 1410#</mathjax> <mathjax>#"mm Hg" = 1.86#</mathjax> <mathjax>#"atm" = 188#</mathjax> <mathjax>#"kPa"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>According to <strong>Dalton's law of partial pressures</strong>, the total pressure of a system is the sum of the individual pressures of the gases if they were present alone.</p> <p>To keep things clear, we need to convert the pressure units to a <em>single</em> unit, and I'll choose <mathjax>#"mm Hg"#</mathjax>. </p> <p>Converting them:</p> <p><mathjax>#P_"O" = 760#</mathjax> <mathjax>#"mm Hg"#</mathjax> (given, no conversion necessary)</p> <p><mathjax>#P_ ("CO"_2) = 0.24cancel("atm")((760"mm Hg")/(1cancel("atm"))) = 180#</mathjax> <mathjax>#"mm Hg"#</mathjax> (<mathjax>#2#</mathjax> sig figs)</p> <p><mathjax>#P_ ("N"_2) = 63"kPa"((760"mm Hg")/(101.325"kPa")) = 470#</mathjax> <mathjax>#"mm Hg"#</mathjax> (<mathjax>#2#</mathjax> sig figs)</p> <p>Now that our units are consistent, let's add them up:</p> <p><mathjax>#760"mm Hg" + 180"mm Hg" + 470"mm Hg" = color(red)(1410#</mathjax> <mathjax>#color(red)("mm Hg"#</mathjax></p> <p>If you chose other units, you may have gotten answers something like</p> <p><mathjax>#color(red)(1.86#</mathjax> <mathjax>#color(red)("atm"#</mathjax></p> <p>or</p> <p><mathjax>#color(red)(188#</mathjax> <mathjax>#color(red)("kPa"#</mathjax></p> <p>(This may differ slightly from the other calculated pressures due to arbitrary rounding here and there, but these answers are correct, if you choose to follow all the rules for <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a>.)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/440482" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-gas-pressure-be-changed"> How can gas pressure be changed? 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What volume will it occupy if the... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/gas-pressure"> See all questions in Gas Pressure </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3814 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A canister contains the following gases at the following pressures: oxygen gas at 760 mmHg, carbon dioxide gas at 0.24 atm, and nitrogen at 63 kPa. What is the total pressure inside this canister?	null
746	abde5e11-6ddd-11ea-ab31-ccda262736ce	https://socratic.org/questions/what-is-the-mass-of-1-mole-of-o-2-molecules	32.00 g	start physical_unit 8 9 mass g qc_end physical_unit 8 9 5 6 mole qc_end end	[{"type":"physical unit","value":"Mass [OF] O2 molecules [IN] g"}]	[{"type":"physical unit","value":"32.00 g"}]	[{"type":"physical unit","value":"Mole [OF] O2 molecules [=] \\pu{1 mole}"}]	<h1 class="questionTitle" itemprop="name">What is the mass of 1 mole of #O_2# molecules?</h1>	null	32.00 g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To obtain the mass of 1 mole <mathjax>#O_2#</mathjax> molecule, you simply have to multiply it to its molecular weight which is <mathjax>#31.9988 g/[mol]#</mathjax>.</p> <p>g <mathjax>#O_2 = 1 mol O_2 * (31.9988 g/[mol O_2])#</mathjax><br/> g <mathjax>#O_2 = 31.9988#</mathjax> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#31.9988 g#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To obtain the mass of 1 mole <mathjax>#O_2#</mathjax> molecule, you simply have to multiply it to its molecular weight which is <mathjax>#31.9988 g/[mol]#</mathjax>.</p> <p>g <mathjax>#O_2 = 1 mol O_2 * (31.9988 g/[mol O_2])#</mathjax><br/> g <mathjax>#O_2 = 31.9988#</mathjax> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the mass of 1 mole of #O_2# molecules?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="213721" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/kristhia-loren-maree-rafols-c"><img alt="" class="" src="https://profilepictures.socratic.org/LCQvyymMQmyD0Ro56Sh6_IMG_20161030_204540.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/kristhia-loren-maree-rafols-c"> Kris Caceres </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-18T08:12:15" itemprop="dateCreated"> Jan 18, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#31.9988 g#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To obtain the mass of 1 mole <mathjax>#O_2#</mathjax> molecule, you simply have to multiply it to its molecular weight which is <mathjax>#31.9988 g/[mol]#</mathjax>.</p> <p>g <mathjax>#O_2 = 1 mol O_2 * (31.9988 g/[mol O_2])#</mathjax><br/> g <mathjax>#O_2 = 31.9988#</mathjax> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/213721" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? 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747	ac429b4a-6ddd-11ea-b9ab-ccda262736ce	https://socratic.org/questions/57eba8a611ef6b0a94e88d73	130 grams	start physical_unit 4 4 mass g qc_end physical_unit 12 14 8 9 mass qc_end end	[{"type":"physical unit","value":"Mass [OF] solute [IN] grams"}]	[{"type":"physical unit","value":"130 grams"}]	[{"type":"physical unit","value":"Mass [OF] sodium hypochlorite solution [=] \\pu{2500 g}"},{"type":"physical unit","value":"m/m [OF] sodium hypochlorite in solution [=] \\pu{5.24%}"}]	<h1 class="questionTitle" itemprop="name">How many grams of solute are present in #"2500 g"# of a sodium hypochlorite solution that is #"5.24% m/m"# ?</h1>	null	130 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The solution's <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration</a> by mass</strong>, <mathjax>#"m/m%"#</mathjax>, tells you the number of grams of sodium hypochlorite, your <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a>, present in <mathjax>#"100 g"#</mathjax> of solution.</p> <p>In your case, you know that you have</p> <blockquote> <p><mathjax>#color(blue)(5.24color(red)(%))"m/m NaClO " -> " "color(blue)("5.24 g")color(white)(.)"NaClO for every"color(white)(.)color(red)("100 g of solution")#</mathjax></p> </blockquote> <p>This means that <mathjax>#"2500 g"#</mathjax> of solution will contain</p> <blockquote> <p><mathjax>#2500 color(red)(cancel(color(black)("g solution"))) * "5.24 g NaClO"/(100color(red)(cancel(color(black)("g solution")))) = color(darkgreen)(ul(color(black)("130 g NaClO")))#</mathjax></p> </blockquote> <p>The answer must be rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the mass of the solution. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"130 g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The solution's <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration</a> by mass</strong>, <mathjax>#"m/m%"#</mathjax>, tells you the number of grams of sodium hypochlorite, your <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a>, present in <mathjax>#"100 g"#</mathjax> of solution.</p> <p>In your case, you know that you have</p> <blockquote> <p><mathjax>#color(blue)(5.24color(red)(%))"m/m NaClO " -> " "color(blue)("5.24 g")color(white)(.)"NaClO for every"color(white)(.)color(red)("100 g of solution")#</mathjax></p> </blockquote> <p>This means that <mathjax>#"2500 g"#</mathjax> of solution will contain</p> <blockquote> <p><mathjax>#2500 color(red)(cancel(color(black)("g solution"))) * "5.24 g NaClO"/(100color(red)(cancel(color(black)("g solution")))) = color(darkgreen)(ul(color(black)("130 g NaClO")))#</mathjax></p> </blockquote> <p>The answer must be rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the mass of the solution. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many grams of solute are present in #"2500 g"# of a sodium hypochlorite solution that is #"5.24% m/m"# ?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/percent-concentration" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Concentration</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="441204" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-17T23:42:47" itemprop="dateCreated"> Jun 17, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"130 g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The solution's <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration</a> by mass</strong>, <mathjax>#"m/m%"#</mathjax>, tells you the number of grams of sodium hypochlorite, your <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a>, present in <mathjax>#"100 g"#</mathjax> of solution.</p> <p>In your case, you know that you have</p> <blockquote> <p><mathjax>#color(blue)(5.24color(red)(%))"m/m NaClO " -> " "color(blue)("5.24 g")color(white)(.)"NaClO for every"color(white)(.)color(red)("100 g of solution")#</mathjax></p> </blockquote> <p>This means that <mathjax>#"2500 g"#</mathjax> of solution will contain</p> <blockquote> <p><mathjax>#2500 color(red)(cancel(color(black)("g solution"))) * "5.24 g NaClO"/(100color(red)(cancel(color(black)("g solution")))) = color(darkgreen)(ul(color(black)("130 g NaClO")))#</mathjax></p> </blockquote> <p>The answer must be rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the mass of the solution. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/441204" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div 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href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many grams of solute are present in #"2500 g"# of a sodium hypochlorite solution that is #"5.24% m/m"# ?	null
748	aaec1e27-6ddd-11ea-8922-ccda262736ce	https://socratic.org/questions/what-is-the-approximate-percentage-of-co-2-combined-with-globin	23%	start physical_unit 6 9 percent none qc_end substance 9 9 qc_end chemical_equation 6 6 qc_end end	[{"type":"physical unit","value":"Percentage [OF] CO2 combined with globin"}]	[{"type":"physical unit","value":"23%"}]	[{"type":"substance name","value":"Globin"},{"type":"chemical equation","value":"CO2"}]	<h1 class="questionTitle" itemprop="name">What is the approximate percentage of #CO_2# combined with globin?</h1>	null	23%	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>Carbon dioxide is produced by all the cells in the body.</p> <p>It diffuses into the capillaries where about 7 % of it is transported as <mathjax>#"CO"_2"(aq)"#</mathjax> in the plasma.</p> <p><img alt="CO2 Transport" src="https://useruploads.socratic.org/DcXGZG0GT3CvbSIe2C2H_transport-of-carbon-dioxide-in-blood.jpg"/> <br/> (From SlideShare)</p> <p>The remaining 93 % diffuses into the red blood cells.</p> <p>In the red blood cells, about 23 % combines chemically with hemoglobin to form <strong>carbohemoglobin</strong>, <mathjax>#"Hb···CO"_2#</mathjax>.</p> <p>The other 70 % is converted to <mathjax>#"HCO"_3^"-"#</mathjax> ions, which are then transported in the plasma.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>About 23 % of carbon dioxide is combined with hemoglobin.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>Carbon dioxide is produced by all the cells in the body.</p> <p>It diffuses into the capillaries where about 7 % of it is transported as <mathjax>#"CO"_2"(aq)"#</mathjax> in the plasma.</p> <p><img alt="CO2 Transport" src="https://useruploads.socratic.org/DcXGZG0GT3CvbSIe2C2H_transport-of-carbon-dioxide-in-blood.jpg"/> <br/> (From SlideShare)</p> <p>The remaining 93 % diffuses into the red blood cells.</p> <p>In the red blood cells, about 23 % combines chemically with hemoglobin to form <strong>carbohemoglobin</strong>, <mathjax>#"Hb···CO"_2#</mathjax>.</p> <p>The other 70 % is converted to <mathjax>#"HCO"_3^"-"#</mathjax> ions, which are then transported in the plasma.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the approximate percentage of #CO_2# combined with globin?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/percent-composition" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Composition</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="346831" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-12-05T02:14:15" itemprop="dateCreated"> Dec 5, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>About 23 % of carbon dioxide is combined with hemoglobin.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>Carbon dioxide is produced by all the cells in the body.</p> <p>It diffuses into the capillaries where about 7 % of it is transported as <mathjax>#"CO"_2"(aq)"#</mathjax> in the plasma.</p> <p><img alt="CO2 Transport" src="https://useruploads.socratic.org/DcXGZG0GT3CvbSIe2C2H_transport-of-carbon-dioxide-in-blood.jpg"/> <br/> (From SlideShare)</p> <p>The remaining 93 % diffuses into the red blood cells.</p> <p>In the red blood cells, about 23 % combines chemically with hemoglobin to form <strong>carbohemoglobin</strong>, <mathjax>#"Hb···CO"_2#</mathjax>.</p> <p>The other 70 % is converted to <mathjax>#"HCO"_3^"-"#</mathjax> ions, which are then transported in the plasma.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/346831" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-mole-percent"> What is mole percent? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" 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href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the approximate percentage of #CO_2# combined with globin?	null
749	ab0069bc-6ddd-11ea-9ecd-ccda262736ce	https://socratic.org/questions/59fb59d97c01493a301806e5	+3	start physical_unit 6 6 oxidation_number none qc_end chemical_equation 8 8 qc_end end	[{"type":"physical unit","value":"Oxidation number [OF] manganese"}]	[{"type":"physical unit","value":"+3"}]	[{"type":"chemical equation","value":"Mn2O3"}]	<h1 class="questionTitle" itemprop="name">What is the oxidation number of manganese in #"Mn"_2"O"_3# ?</h1>	null	+3	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In oxides of <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a>, oxygen atoms normally have <mathjax>#( -2)#</mathjax> as the value.of the oxidation state. </p> <p>That means <mathjax>#(-6)#</mathjax> charge comes from <mathjax>#3#</mathjax> oxygen atoms. Since <mathjax>#"Mn"_2"O"_3#</mathjax> is a neutral compound, each <mathjax>#"Mn"#</mathjax> atom should have <mathjax>#(+3)#</mathjax> oxidation value to balance the charge from the oxygen atoms.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#+3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In oxides of <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a>, oxygen atoms normally have <mathjax>#( -2)#</mathjax> as the value.of the oxidation state. </p> <p>That means <mathjax>#(-6)#</mathjax> charge comes from <mathjax>#3#</mathjax> oxygen atoms. Since <mathjax>#"Mn"_2"O"_3#</mathjax> is a neutral compound, each <mathjax>#"Mn"#</mathjax> atom should have <mathjax>#(+3)#</mathjax> oxidation value to balance the charge from the oxygen atoms.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the oxidation number of manganese in #"Mn"_2"O"_3# ?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#electrochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Electrochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/electrochemistry/oxidation-numbers" itemprop="url"> <span class="breadcrumb" itemprop="title">Oxidation Numbers</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="499356" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/kceylan"><img alt="" class="" src="https://profilepictures.socratic.org/JLNH4pU3SNuzruXSKZpg_kceylan-phto1.jpg" title=""/></a> <a class="secondContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/kceylan"> kceylan </a>·<a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-11-02T18:02:14" itemprop="dateCreated"> Nov 2, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#+3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In oxides of <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a>, oxygen atoms normally have <mathjax>#( -2)#</mathjax> as the value.of the oxidation state. </p> <p>That means <mathjax>#(-6)#</mathjax> charge comes from <mathjax>#3#</mathjax> oxygen atoms. Since <mathjax>#"Mn"_2"O"_3#</mathjax> is a neutral compound, each <mathjax>#"Mn"#</mathjax> atom should have <mathjax>#(+3)#</mathjax> oxidation value to balance the charge from the oxygen atoms.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/499356" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-relate-to-electron-configuration"> How do oxidation numbers relate to electron configuration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-relate-to-valence-electrons"> How do oxidation numbers relate to valence electrons? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-vary-with-the-periodic-table"> How do oxidation numbers vary with the periodic table? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-oxidation-number-of-an-element-in-a-compound"> How do you calculate the oxidation number of an element in a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-sulfur"> What is the oxidation number for sulfur? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-carbon"> What is the oxidation number for carbon? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-copper"> What is the oxidation number for copper? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-nitrogen"> What is the oxidation number for nitrogen? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-oxygen"> What is the oxidation number for oxygen? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-oxidation-state-of-noble-gas-zero"> Why is the oxidation state of noble gas zero? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/electrochemistry/oxidation-numbers"> See all questions in Oxidation Numbers </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3322 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the oxidation number of manganese in #"Mn"_2"O"_3# ?	null
750	ac89c229-6ddd-11ea-8f7e-ccda262736ce	https://socratic.org/questions/20g-of-nacl-were-added-to-an-8-180g-of-nacl-solution-what-is-the-mass-percent-of	17.20%	start physical_unit 20 23 mass_percent none qc_end physical_unit 3 3 0 1 mass qc_end physical_unit 12 13 9 10 mass qc_end physical_unit 20 23 8 8 mass_percent qc_end end	[{"type":"physical unit","value":"Mass percent2 [OF] NaCl in the solution"}]	[{"type":"physical unit","value":"17.20%"}]	[{"type":"physical unit","value":"Mass percent1 [OF] NaCl in the solution [=] \\pu{8%}"},{"type":"physical unit","value":"Mass1 [OF] NaCl solution [=] \\pu{180g}"},{"type":"physical unit","value":"Mass2 [OF] NaCl [=] \\pu{20 g}"}]	<h1 class="questionTitle" itemprop="name">20g of NaCl were added to an 8% 180g of NaCl solution. What is the mass percent of NaCl in the solution now?</h1>	null	17.20%	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>It seems we should have a three-part strategy:</p> <ol> <li>Calculate the mass of <mathjax>#"NaCl"#</mathjax> in the original solution.</li> <li>Calculate the new masses of <mathjax>#"NaCl"#</mathjax> and solution after adding <mathjax>#"NaCl"#</mathjax>.</li> <li>Calculate the percent of <mathjax>#"NaCl"#</mathjax> in the new solution.</li> </ol> <blockquote></blockquote> <p><strong>1. Mass of <mathjax>#bb"NaCl"#</mathjax> in original solution</strong></p> <p>The formula for <a href="https://socratic.org/chemistry/the-mole-concept/percent-composition">percent composition</a> is</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a) "Mass %" = "mass of component"/"mass of mixture" × "100 %"color(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>We can rearrange this to</p> <p><mathjax>#"Mass of component" = ("mass of mixture" × 100 %)/"mass %"#</mathjax></p> <p>∴ <mathjax>#"Mass of NaCl" = ("180 g" × 8 color(red)(cancel(color(black)(%))))/(100 color(red)(cancel(color(black)(%)))) = "14.4 g"#</mathjax></p> <blockquote></blockquote> <p><strong>2. New masses</strong></p> <p><mathjax>#"Mass of NaCl" = "14.4 g + 20 g" = "34.4 g"#</mathjax></p> <p><mathjax>#"Mass of solution" = "180 g + 20 g" = "200 g"#</mathjax></p> <blockquote></blockquote> <p><strong>3. New percent composition</strong></p> <p><mathjax>#"Mass %" = "mass of NaCl"/"mass of solution" × "100 %" = (34.4 color(red)(cancel(color(black)("g"))))/(200 color(red)(cancel(color(black)("g")))) × 100 % = 17 %#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The new solution is <mathjax>#17 % ("w/w")color(white)(l) "NaCl"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>It seems we should have a three-part strategy:</p> <ol> <li>Calculate the mass of <mathjax>#"NaCl"#</mathjax> in the original solution.</li> <li>Calculate the new masses of <mathjax>#"NaCl"#</mathjax> and solution after adding <mathjax>#"NaCl"#</mathjax>.</li> <li>Calculate the percent of <mathjax>#"NaCl"#</mathjax> in the new solution.</li> </ol> <blockquote></blockquote> <p><strong>1. Mass of <mathjax>#bb"NaCl"#</mathjax> in original solution</strong></p> <p>The formula for <a href="https://socratic.org/chemistry/the-mole-concept/percent-composition">percent composition</a> is</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a) "Mass %" = "mass of component"/"mass of mixture" × "100 %"color(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>We can rearrange this to</p> <p><mathjax>#"Mass of component" = ("mass of mixture" × 100 %)/"mass %"#</mathjax></p> <p>∴ <mathjax>#"Mass of NaCl" = ("180 g" × 8 color(red)(cancel(color(black)(%))))/(100 color(red)(cancel(color(black)(%)))) = "14.4 g"#</mathjax></p> <blockquote></blockquote> <p><strong>2. New masses</strong></p> <p><mathjax>#"Mass of NaCl" = "14.4 g + 20 g" = "34.4 g"#</mathjax></p> <p><mathjax>#"Mass of solution" = "180 g + 20 g" = "200 g"#</mathjax></p> <blockquote></blockquote> <p><strong>3. New percent composition</strong></p> <p><mathjax>#"Mass %" = "mass of NaCl"/"mass of solution" × "100 %" = (34.4 color(red)(cancel(color(black)("g"))))/(200 color(red)(cancel(color(black)("g")))) × 100 % = 17 %#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">20g of NaCl were added to an 8% 180g of NaCl solution. What is the mass percent of NaCl in the solution now?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/percent-concentration" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Concentration</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="279183" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-19T23:57:24" itemprop="dateCreated"> Jun 19, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The new solution is <mathjax>#17 % ("w/w")color(white)(l) "NaCl"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>It seems we should have a three-part strategy:</p> <ol> <li>Calculate the mass of <mathjax>#"NaCl"#</mathjax> in the original solution.</li> <li>Calculate the new masses of <mathjax>#"NaCl"#</mathjax> and solution after adding <mathjax>#"NaCl"#</mathjax>.</li> <li>Calculate the percent of <mathjax>#"NaCl"#</mathjax> in the new solution.</li> </ol> <blockquote></blockquote> <p><strong>1. Mass of <mathjax>#bb"NaCl"#</mathjax> in original solution</strong></p> <p>The formula for <a href="https://socratic.org/chemistry/the-mole-concept/percent-composition">percent composition</a> is</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a) "Mass %" = "mass of component"/"mass of mixture" × "100 %"color(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>We can rearrange this to</p> <p><mathjax>#"Mass of component" = ("mass of mixture" × 100 %)/"mass %"#</mathjax></p> <p>∴ <mathjax>#"Mass of NaCl" = ("180 g" × 8 color(red)(cancel(color(black)(%))))/(100 color(red)(cancel(color(black)(%)))) = "14.4 g"#</mathjax></p> <blockquote></blockquote> <p><strong>2. New masses</strong></p> <p><mathjax>#"Mass of NaCl" = "14.4 g + 20 g" = "34.4 g"#</mathjax></p> <p><mathjax>#"Mass of solution" = "180 g + 20 g" = "200 g"#</mathjax></p> <blockquote></blockquote> <p><strong>3. New percent composition</strong></p> <p><mathjax>#"Mass %" = "mass of NaCl"/"mass of solution" × "100 %" = (34.4 color(red)(cancel(color(black)("g"))))/(200 color(red)(cancel(color(black)("g")))) × 100 % = 17 %#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/279183" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="279184" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-20T00:04:03" itemprop="dateCreated"> Jun 20, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#17%#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that adding the <mathjax>#"20 g"#</mathjax> of sodium chloride, <mathjax>#"NaCl"#</mathjax>, will <strong>increase</strong> the <em><a href="https://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration</a> by mass</em> of the solution, so right from the start you should expect the concentration of the target solution to be <strong>higher</strong> than <mathjax>#8%#</mathjax>.</p> <p>A solution's <strong>percent concentration by mass</strong>, <mathjax>#"% m/m"#</mathjax>, essentially tells you how many grams of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a>, which in your case is sodium chloride, you get <strong>per</strong> <mathjax>#"100 g"#</mathjax> <strong>of solution</strong>. </p> <p>Initially, your solution has a mass of <mathjax>#"180 g"#</mathjax> and a percent concentration by mass equal to <mathjax>#8%#</mathjax>. This implies that the initial solution contains </p> <blockquote> <p><mathjax>#180 color(red)(cancel(color(black)("g solution"))) * overbrace("8 g NaCl"/(100color(red)(cancel(color(black)("g solution")))))^(color(blue)("= 8% m/m NaCl")) = "14.4 g NaCl"#</mathjax></p> </blockquote> <p>The <strong>target solution</strong> will contain a total of </p> <blockquote> <p><mathjax>#m_"NaCl" = "14.4 g" + "20 g" = "34.4 g NaCl"#</mathjax></p> </blockquote> <p>The <strong>total mass of the solution</strong> will now be </p> <blockquote> <p><mathjax>#m_"solution" = "180 g" + "20 g" = "200 g"#</mathjax></p> </blockquote> <p>Since <mathjax>#"200 g"#</mathjax> of solution contain <mathjax>#"34.4 g"#</mathjax> of sodium chloride, it follows that <mathjax>#"100 g"#</mathjax> will contain</p> <blockquote> <p><mathjax>#100color(red)(cancel(color(black)("g solution"))) * "34.4 g NaCl"/(200color(red)(cancel(color(black)("g solution")))) = "17.2 g NaCl"#</mathjax></p> </blockquote> <p>Therefore, the target solution's percent concentration by mass is</p> <blockquote> <p><mathjax>#"% m/m" = color(green)(\|bar(ul(color(white)(a/a)color(black)("17% NaCl")color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>I'll leave the answer rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p> <p>As predicted, the percent concentration of the solution <strong>increased</strong> upon the addition of more solute. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/279184" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-concentration-of-water-in-solution-be-decreased"> How can the concentration of water in solution be decreased? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-concentration-of-a-solution-be-increased"> How can the concentration of a solution be increased? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-concentration-of-a-solution-in-ppm"> How do you find the concentration of a solution in ppm? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-make-a-10-percent-solution"> How do you make a 10 percent solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-make-a-2-percent-solution"> How do you make a 2 percent solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-weight-per-volume-method-to-calculate-concentration"> What is the weight per volume method to calculate concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-percent-concentration-of-kcl-would-be-isotonic"> What percent concentration of KCl would be isotonic? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-of-sodium-chloride-in-normal-saline"> What is the percent concentration of sodium chloride in normal saline? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-of-a-6m-solution-of-nacl"> What is the percent concentration of a 6m solution of NaCl? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-formula"> What is the percent concentration formula? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/percent-concentration"> See all questions in Percent Concentration </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 5478 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	20g of NaCl were added to an 8% 180g of NaCl solution. What is the mass percent of NaCl in the solution now?	null
751	a8bc35e5-6ddd-11ea-bcc1-ccda262736ce	https://socratic.org/questions/how-many-moles-of-methane-gas-are-in-43-8-liters-of-methane-gas-at-stp	2 moles	start physical_unit 4 5 mole mol qc_end physical_unit 4 5 8 9 volume qc_end c_other STP qc_end end	[{"type":"physical unit","value":"Mole [OF] methane gas [IN] moles"}]	[{"type":"physical unit","value":"2 moles"}]	[{"type":"physical unit","value":"Volume [OF] methane gas [=] \\pu{43.8 liters}"},{"type":"other","value":"STP"}]	<h1 class="questionTitle" itemprop="name">How many moles of methane gas are in 43.8 liters of methane gas at STP? </h1>	null	2 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>At <a href="http://socratic.org/questions/how-do-you-calculate-molar-volume-of-a-gas-at-stp">STP</a> <mathjax>#1#</mathjax> <mathjax>#mol#</mathjax> of ideal gas has a volume of <mathjax>#22.4#</mathjax> <mathjax>#L#</mathjax>. </p> <p>We assume that methane approximates the behaviour of an ideal gas, and take the quotient:</p> <p><mathjax>#(43.8cancelL)/(22.4cancelL*mol^-1)#</mathjax> <mathjax>#~~#</mathjax> <mathjax>#2#</mathjax> <mathjax>#mol#</mathjax> <mathjax>#CH_4#</mathjax>. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>There are about 2 mol of methane present.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>At <a href="http://socratic.org/questions/how-do-you-calculate-molar-volume-of-a-gas-at-stp">STP</a> <mathjax>#1#</mathjax> <mathjax>#mol#</mathjax> of ideal gas has a volume of <mathjax>#22.4#</mathjax> <mathjax>#L#</mathjax>. </p> <p>We assume that methane approximates the behaviour of an ideal gas, and take the quotient:</p> <p><mathjax>#(43.8cancelL)/(22.4cancelL*mol^-1)#</mathjax> <mathjax>#~~#</mathjax> <mathjax>#2#</mathjax> <mathjax>#mol#</mathjax> <mathjax>#CH_4#</mathjax>. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles of methane gas are in 43.8 liters of methane gas at STP? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="223957" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> <a class="secondContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a>·<a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-02-09T18:29:13" itemprop="dateCreated"> Feb 9, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>There are about 2 mol of methane present.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>At <a href="http://socratic.org/questions/how-do-you-calculate-molar-volume-of-a-gas-at-stp">STP</a> <mathjax>#1#</mathjax> <mathjax>#mol#</mathjax> of ideal gas has a volume of <mathjax>#22.4#</mathjax> <mathjax>#L#</mathjax>. </p> <p>We assume that methane approximates the behaviour of an ideal gas, and take the quotient:</p> <p><mathjax>#(43.8cancelL)/(22.4cancelL*mol^-1)#</mathjax> <mathjax>#~~#</mathjax> <mathjax>#2#</mathjax> <mathjax>#mol#</mathjax> <mathjax>#CH_4#</mathjax>. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/223957" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 13924 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many moles of methane gas are in 43.8 liters of methane gas at STP?	null
752	a9972aae-6ddd-11ea-ab12-ccda262736ce	https://socratic.org/questions/hcl-is-called-hydrochloric-how-would-you-write-an-acid-ionization-reaction-equat	HCl(g) + H2O(l) -> H3O+ + Cl-	start chemical_equation qc_end chemical_equation 0 0 qc_end end	[{"type":"other","value":"Chemical Equation [OF] an acid ionization reaction equation"}]	[{"type":"chemical equation","value":"HCl(g) + H2O(l) -> H3O+ + Cl-"}]	[{"type":"chemical equation","value":"HCl"}]	<h1 class="questionTitle" itemprop="name">#HCl# is called hydrochloric. How would you write an acid ionization reaction equation for this acid?</h1>	null	HCl(g) + H2O(l) -> H3O+ + Cl-	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Any example of acid base behaviour is modified by the properties of the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a>. Generally, we encounter acid/base behaviour in aqueous solution, and the acidium ion is conceived to be <mathjax>#H_3O^+#</mathjax>, likely a cluster of water molecules with an extra <mathjax>#H^+#</mathjax> added. </p> <p>For strong acids such as hydrochloric acid and sulfuric, the extent of ionization is almost quantitative. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#HCl(g)darr + H_2O(l) rarr H_3O^+ + Cl^-#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Any example of acid base behaviour is modified by the properties of the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a>. Generally, we encounter acid/base behaviour in aqueous solution, and the acidium ion is conceived to be <mathjax>#H_3O^+#</mathjax>, likely a cluster of water molecules with an extra <mathjax>#H^+#</mathjax> added. </p> <p>For strong acids such as hydrochloric acid and sulfuric, the extent of ionization is almost quantitative. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">#HCl# is called hydrochloric. How would you write an acid ionization reaction equation for this acid?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-reactions-and-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions and Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="285730" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-07T15:19:25" itemprop="dateCreated"> Jul 7, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#HCl(g)darr + H_2O(l) rarr H_3O^+ + Cl^-#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Any example of acid base behaviour is modified by the properties of the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a>. Generally, we encounter acid/base behaviour in aqueous solution, and the acidium ion is conceived to be <mathjax>#H_3O^+#</mathjax>, likely a cluster of water molecules with an extra <mathjax>#H^+#</mathjax> added. </p> <p>For strong acids such as hydrochloric acid and sulfuric, the extent of ionization is almost quantitative. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/285730" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb002bf34694a4fee47"> Question #fee47 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb402bf34694c8c5c15"> Question #c5c15 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb802bf346950519eb9"> Question #19eb9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cbf02bf3469570e2ea2"> Question #e2ea2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc002bf34695a6bc751"> Question #bc751 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc202bf3469570e2ea6"> Question #e2ea6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531e867a02bf342492a08b07"> Question #08b07 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-thermochemical-equation-for-the-combustion-of-benzene"> What is the thermochemical equation for the combustion of benzene? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-reversible"> Why are chemical reactions reversible? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-important"> Why are chemical reactions important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/chemical-reactions-and-equations"> See all questions in Chemical Reactions and Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 4820 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	#HCl# is called hydrochloric. How would you write an acid ionization reaction equation for this acid?	null
753	aa94f5d3-6ddd-11ea-b974-ccda262736ce	https://socratic.org/questions/how-many-ml-of-0-350-m-solution-contains-0-200-mol-of-solute	571 mL	start physical_unit 6 6 volume ml qc_end physical_unit 6 6 4 5 molarity qc_end physical_unit 11 11 8 9 mole qc_end end	[{"type":"physical unit","value":"Volume [OF] solution [IN] mL"}]	[{"type":"physical unit","value":"571 mL"}]	[{"type":"physical unit","value":"Molarity [OF] solution [=] \\pu{0.350 M}"},{"type":"physical unit","value":"Mole [OF] solute [=] \\pu{0.200 mol}"}]	<h1 class="questionTitle" itemprop="name">How many mL of 0.350 M solution contains 0.200 mol of solute?</h1>	null	571 mL	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The thing to remember about <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></strong> is that its purpose is to tell you how many moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> you get in <strong>one liter of solution</strong>. </p> <p>This means that every time you're looking at the molarity of a solution, you're actually looking at the <em>number of moles of solute</em> present in <mathjax>#"1 L"#</mathjax> of solution. </p> <p>In this case, a molarity of <mathjax>#"0.350 M"#</mathjax> means that <mathjax>#"1 L"#</mathjax> of this solution contains <mathjax>#0.350#</mathjax> <strong>moles</strong> of solute. </p> <p>The immediate conclusion here is that you can use the molarity of a solution as a <em>conversion factor</em> to help you convert between the number of moles of solute and the volume of the solution and vice versa. </p> <p>You will thus have</p> <blockquote> <p><mathjax>#0.200 color(red)(cancel(color(black)("moles solute"))) * overbrace("1 L solution"/(0.350 color(red)(cancel(color(black)("moles solute")))))^(color(blue)("= 0.350 M")) = "0.571 L solution"#</mathjax></p> </blockquote> <p>Now all you have to do is convert this to <em>milliliters</em></p> <blockquote> <p><mathjax>#0.571 color(red)(cancel(color(black)("L"))) * (10^3"mL")/(1color(red)(cancel(color(black)("L")))) = color(green)(bar(ul(\|color(white)(a/a)color(black)("571 mL")color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"571 mL"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The thing to remember about <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></strong> is that its purpose is to tell you how many moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> you get in <strong>one liter of solution</strong>. </p> <p>This means that every time you're looking at the molarity of a solution, you're actually looking at the <em>number of moles of solute</em> present in <mathjax>#"1 L"#</mathjax> of solution. </p> <p>In this case, a molarity of <mathjax>#"0.350 M"#</mathjax> means that <mathjax>#"1 L"#</mathjax> of this solution contains <mathjax>#0.350#</mathjax> <strong>moles</strong> of solute. </p> <p>The immediate conclusion here is that you can use the molarity of a solution as a <em>conversion factor</em> to help you convert between the number of moles of solute and the volume of the solution and vice versa. </p> <p>You will thus have</p> <blockquote> <p><mathjax>#0.200 color(red)(cancel(color(black)("moles solute"))) * overbrace("1 L solution"/(0.350 color(red)(cancel(color(black)("moles solute")))))^(color(blue)("= 0.350 M")) = "0.571 L solution"#</mathjax></p> </blockquote> <p>Now all you have to do is convert this to <em>milliliters</em></p> <blockquote> <p><mathjax>#0.571 color(red)(cancel(color(black)("L"))) * (10^3"mL")/(1color(red)(cancel(color(black)("L")))) = color(green)(bar(ul(\|color(white)(a/a)color(black)("571 mL")color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many mL of 0.350 M solution contains 0.200 mol of solute?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="329972" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-11-01T23:46:36" itemprop="dateCreated"> Nov 1, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"571 mL"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The thing to remember about <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></strong> is that its purpose is to tell you how many moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> you get in <strong>one liter of solution</strong>. </p> <p>This means that every time you're looking at the molarity of a solution, you're actually looking at the <em>number of moles of solute</em> present in <mathjax>#"1 L"#</mathjax> of solution. </p> <p>In this case, a molarity of <mathjax>#"0.350 M"#</mathjax> means that <mathjax>#"1 L"#</mathjax> of this solution contains <mathjax>#0.350#</mathjax> <strong>moles</strong> of solute. </p> <p>The immediate conclusion here is that you can use the molarity of a solution as a <em>conversion factor</em> to help you convert between the number of moles of solute and the volume of the solution and vice versa. </p> <p>You will thus have</p> <blockquote> <p><mathjax>#0.200 color(red)(cancel(color(black)("moles solute"))) * overbrace("1 L solution"/(0.350 color(red)(cancel(color(black)("moles solute")))))^(color(blue)("= 0.350 M")) = "0.571 L solution"#</mathjax></p> </blockquote> <p>Now all you have to do is convert this to <em>milliliters</em></p> <blockquote> <p><mathjax>#0.571 color(red)(cancel(color(black)("L"))) * (10^3"mL")/(1color(red)(cancel(color(black)("L")))) = color(green)(bar(ul(\|color(white)(a/a)color(black)("571 mL")color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/329972" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li 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class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 13232 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many mL of 0.350 M solution contains 0.200 mol of solute?	null
754	a9922388-6ddd-11ea-bcb5-ccda262736ce	https://socratic.org/questions/what-is-the-volume-of-solution-with-0-82g-l-concentration-when-the-mass-of-the-s	9 L	start physical_unit 5 5 volume l qc_end physical_unit 5 5 7 8 concentration qc_end physical_unit 14 15 17 18 mass qc_end end	[{"type":"physical unit","value":"Volume [OF] solution [IN] L"}]	[{"type":"physical unit","value":"9 L"}]	[{"type":"physical unit","value":"Concentration [OF] solution [=] \\pu{0.82 g/L}"},{"type":"physical unit","value":"Mass [OF] the solute [=] \\pu{7 g}"}]	<h1 class="questionTitle" itemprop="name">What is the volume of solution with 0.82g/L concentration when the mass of the solute is 7g?</h1>	null	9 L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that the concentration of the solution tells you the number of grams of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> present <strong>for every</strong> <mathjax>#"1 L"#</mathjax> of the solution. </p> <p>This solution is said to have a concentration of <mathjax>#"0.82 g L"^(-1)#</mathjax>, which means that <mathjax>#"1 L"#</mathjax> of this solution will contain <mathjax>#"0.82 g"#</mathjax> of solute. </p> <p>Now, you know that you have a sample of this solution that contains <mathjax>#"7 g"#</mathjax> of solute. As you know, a solution is a <strong>homogeneous mixture</strong>, which implies that it has the <em>same composition throughout</em>. </p> <p>Consequently, you can use the concentration of the solution to determine how many liters would contain <mathjax>#"7 g"#</mathjax> of solute.</p> <blockquote> <p><mathjax>#7 color(red)(cancel(color(black)("g solute"))) * overbrace("1 L solution"/(0.82color(red)(cancel(color(black)("g solute")))))^(color(blue)("= 0.82 g L"^(-1))) = color(darkgreen)(ul(color(black)("9 L solution")))#</mathjax></p> </blockquote> <p>The answer is rounded to one <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figure</a></strong>, the number of sig figs you have for the mass of the solute. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"9 L"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that the concentration of the solution tells you the number of grams of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> present <strong>for every</strong> <mathjax>#"1 L"#</mathjax> of the solution. </p> <p>This solution is said to have a concentration of <mathjax>#"0.82 g L"^(-1)#</mathjax>, which means that <mathjax>#"1 L"#</mathjax> of this solution will contain <mathjax>#"0.82 g"#</mathjax> of solute. </p> <p>Now, you know that you have a sample of this solution that contains <mathjax>#"7 g"#</mathjax> of solute. As you know, a solution is a <strong>homogeneous mixture</strong>, which implies that it has the <em>same composition throughout</em>. </p> <p>Consequently, you can use the concentration of the solution to determine how many liters would contain <mathjax>#"7 g"#</mathjax> of solute.</p> <blockquote> <p><mathjax>#7 color(red)(cancel(color(black)("g solute"))) * overbrace("1 L solution"/(0.82color(red)(cancel(color(black)("g solute")))))^(color(blue)("= 0.82 g L"^(-1))) = color(darkgreen)(ul(color(black)("9 L solution")))#</mathjax></p> </blockquote> <p>The answer is rounded to one <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figure</a></strong>, the number of sig figs you have for the mass of the solute. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the volume of solution with 0.82g/L concentration when the mass of the solute is 7g?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/measuring-concentration" itemprop="url"> <span class="breadcrumb" itemprop="title">Measuring Concentration</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="545628" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-02-03T00:57:51" itemprop="dateCreated"> Feb 3, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"9 L"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that the concentration of the solution tells you the number of grams of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> present <strong>for every</strong> <mathjax>#"1 L"#</mathjax> of the solution. </p> <p>This solution is said to have a concentration of <mathjax>#"0.82 g L"^(-1)#</mathjax>, which means that <mathjax>#"1 L"#</mathjax> of this solution will contain <mathjax>#"0.82 g"#</mathjax> of solute. </p> <p>Now, you know that you have a sample of this solution that contains <mathjax>#"7 g"#</mathjax> of solute. As you know, a solution is a <strong>homogeneous mixture</strong>, which implies that it has the <em>same composition throughout</em>. </p> <p>Consequently, you can use the concentration of the solution to determine how many liters would contain <mathjax>#"7 g"#</mathjax> of solute.</p> <blockquote> <p><mathjax>#7 color(red)(cancel(color(black)("g solute"))) * overbrace("1 L solution"/(0.82color(red)(cancel(color(black)("g solute")))))^(color(blue)("= 0.82 g L"^(-1))) = color(darkgreen)(ul(color(black)("9 L solution")))#</mathjax></p> </blockquote> <p>The answer is rounded to one <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figure</a></strong>, the number of sig figs you have for the mass of the solute. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/545628" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-measure-concentration-from-absorbance"> How do you measure concentration from absorbance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-measure-concentration-of-a-solution"> How do you measure concentration of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-measure-concentration-of-co2"> How do you measure concentration of CO2? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-concentration-measure-changes-with-temperature"> What concentration measure changes with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-measure-the-concentration-of-salt-in-water"> How can I measure the concentration of salt in water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-the-concentration-of-a-solution-measured"> How is the concentration of a solution measured? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-concentration-of-electrolyte-affect-an-electrochemical-cell"> How does the concentration of electrolyte affect an electrochemical cell? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-normality-differ-from-molarity"> How does normality differ from molarity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molality-of-a-solution-of-10-g-naoh-in-500-g-water"> What is the molality of a solution of 10 g NaOH in 500 g water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-the-mole-fractions-of-the-components-of-the-solution-formed-when-92-g-g"> What are the mole fractions of the components of the solution formed when 92 g glycerol is mixed... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/measuring-concentration"> See all questions in Measuring Concentration </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1617 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the volume of solution with 0.82g/L concentration when the mass of the solute is 7g?	null
755	aa07f464-6ddd-11ea-bb63-ccda262736ce	https://socratic.org/questions/59121f6b11ef6b454bfa500e	18139.17 g	start physical_unit 14 15 mass g qc_end physical_unit 3 4 0 1 mass qc_end substance 9 10 qc_end end	[{"type":"physical unit","value":"Mass [OF] zinc oxide [IN] g"}]	[{"type":"physical unit","value":"18139.17 g"}]	[{"type":"physical unit","value":"Mass [OF] oxygen gas [=] \\pu{8934 g}"},{"type":"substance name","value":"Zinc sulfide"}]	<h1 class="questionTitle" itemprop="name">#8934*g# of oxygen gas is reacted with stoichiometric zinc sulfide. What mass of zinc oxide results? </h1>	null	18139.17 g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#2ZnS(s) + 3O_2(g) rarr 2ZnO(s) + 2SO_2(g)#</mathjax></p> <p><mathjax>#"Moles of dioxygen"=(8934g)/(32.00gmol^-1)=279.2mol#</mathjax>.</p> <p>And thus we represent an equivalent quantity of <mathjax>#"zinc sulfide"#</mathjax> as <mathjax>#279.2molxx2/3=186.1mol#</mathjax>; this quantity follows PRECISELY the <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> of the given equation. Agreed?</p> <p>i.e. <mathjax>#186.1molxx97.47gmol^-1="over 18"kg#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We interrogate the reaction............and get a mass of over <mathjax>#18kg#</mathjax> with respect to <mathjax>#"zinc oxide"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#2ZnS(s) + 3O_2(g) rarr 2ZnO(s) + 2SO_2(g)#</mathjax></p> <p><mathjax>#"Moles of dioxygen"=(8934g)/(32.00gmol^-1)=279.2mol#</mathjax>.</p> <p>And thus we represent an equivalent quantity of <mathjax>#"zinc sulfide"#</mathjax> as <mathjax>#279.2molxx2/3=186.1mol#</mathjax>; this quantity follows PRECISELY the <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> of the given equation. Agreed?</p> <p>i.e. <mathjax>#186.1molxx97.47gmol^-1="over 18"*kg#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">#8934g# of oxygen gas is reacted with stoichiometric zinc sulfide. What mass of zinc oxide results? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="421035" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-10T17:49:02" itemprop="dateCreated"> May 10, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We interrogate the reaction............and get a mass of over <mathjax>#18kg#</mathjax> with respect to <mathjax>#"zinc oxide"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#2ZnS(s) + 3O_2(g) rarr 2ZnO(s) + 2SO_2(g)#</mathjax></p> <p><mathjax>#"Moles of dioxygen"=(8934g)/(32.00gmol^-1)=279.2mol#</mathjax>.</p> <p>And thus we represent an equivalent quantity of <mathjax>#"zinc sulfide"#</mathjax> as <mathjax>#279.2molxx2/3=186.1mol#</mathjax>; this quantity follows PRECISELY the <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> of the given equation. Agreed?</p> <p>i.e. <mathjax>#186.1molxx97.47gmol^-1="over 18"kg#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/421035" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What is stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ab82402bf342f48d93ac6"> Question #93ac6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-we-study-stoichiometry"> Why do we study stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-naoh-is-produced-from-1-20-x-102-grams-of-na2o-na2o-h2o-2-naoh"> How many grams of NaOH is produced from #1.20 x 10^2# grams of #Na_2O#? #Na_2O + H_2O -> 2NaOH# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-na2o-are-required-to-produce-1-60-x-102-grams-of-naoh-na2o-h2o"> How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? 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What mass of zinc oxide results?	null
756	a849876e-6ddd-11ea-a86e-ccda262736ce	https://socratic.org/questions/ethanol-ch-3ch-2oh-has-a-vapor-pressure-of-59-mm-hg-at-25-c-what-quantity-of-ene	90.14 kJ	start physical_unit 25 26 energy kj qc_end physical_unit 1 1 7 8 vapor_pressure qc_end physical_unit 1 1 10 11 temperature qc_end physical_unit 25 26 22 23 volume qc_end physical_unit 25 26 41 42 enthalpy_of_vaporization qc_end physical_unit 25 26 49 50 density qc_end physical_unit 25 26 10 11 temperature qc_end end	[{"type":"physical unit","value":"Required energy [OF] the alcohol [IN] kJ"}]	[{"type":"physical unit","value":"90.14 kJ"}]	[{"type":"physical unit","value":"Vapor pressure [OF] CH3CH2OH [=] \\pu{59 mmHg}"},{"type":"physical unit","value":"Temperature [OF] CH3CH2OH [=] \\pu{25 ℃}"},{"type":"physical unit","value":"Volume [OF] the alcohol [=] \\pu{125 mL}"},{"type":"physical unit","value":"Enthalpy of vaporization [OF] the alcohol [=] \\pu{42.32 kJ/mol}"},{"type":"physical unit","value":"Density [OF] the alcohol [=] \\pu{0.7849 g/mL}"},{"type":"physical unit","value":"Temperature [OF] the alcohol [=] \\pu{25 ℃}"}]	<h1 class="questionTitle" itemprop="name">Ethanol, #CH_3CH_2OH#, has a vapor pressure of 59 mm Hg at 25 °C. What quantity of energy as heat is required to evaporate 125 mL of the alcohol at 25 °C?</h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>The enthalpy of vaporization of the alcohol at 25 °C is 42.32 kJ/mol. The density of the liquid is 0.7849 g/mL.</p></div> </h2> </div> </div>	90.14 kJ	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The <strong>mass</strong> of ethanol is</p> <p><mathjax>#"Mass" = 125 color(red)(cancel(color(black)("mL"))) × "0.7849 g"/(1 color(red)(cancel(color(black)("mL")))) = "98.11 g"#</mathjax></p> <blockquote></blockquote> <p>The <strong>moles</strong> of ethanol are</p> <p><mathjax>#"Moles" = 98.11 color(red)(cancel(color(black)("g"))) × "1 mol"/(46.07 color(red)(cancel(color(black)("g")))) = "2.130 mol"#</mathjax></p> <blockquote></blockquote> <p>The <strong>energy</strong> required to evaporate a given amount of a liquid is given by the formula</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a) q = nΔ_"vap"Hcolor(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>where</p> <p><mathjax>#q#</mathjax> is the energy required<br/> <mathjax>#n#</mathjax> is the number of moles<br/> <mathjax>#Δ_"vap"H#</mathjax> is the molar <a href="https://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> of vaporization</p> <blockquote></blockquote> <p>In your problem,</p> <p><mathjax>#n = "2.130 mol"#</mathjax><br/> <mathjax>#Δ_"vap"H = "42.32 kJ/mol"#</mathjax></p> <p>∴ <mathjax>#q = 2.130 color(red)(cancel(color(black)("mol"))) × "42.32 kJ"/(1 color(red)(cancel(color(black)("mol")))) = "90.1 kJ"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The energy required is 90.1 kJ.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The <strong>mass</strong> of ethanol is</p> <p><mathjax>#"Mass" = 125 color(red)(cancel(color(black)("mL"))) × "0.7849 g"/(1 color(red)(cancel(color(black)("mL")))) = "98.11 g"#</mathjax></p> <blockquote></blockquote> <p>The <strong>moles</strong> of ethanol are</p> <p><mathjax>#"Moles" = 98.11 color(red)(cancel(color(black)("g"))) × "1 mol"/(46.07 color(red)(cancel(color(black)("g")))) = "2.130 mol"#</mathjax></p> <blockquote></blockquote> <p>The <strong>energy</strong> required to evaporate a given amount of a liquid is given by the formula</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a) q = nΔ_"vap"Hcolor(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>where</p> <p><mathjax>#q#</mathjax> is the energy required<br/> <mathjax>#n#</mathjax> is the number of moles<br/> <mathjax>#Δ_"vap"H#</mathjax> is the molar <a href="https://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> of vaporization</p> <blockquote></blockquote> <p>In your problem,</p> <p><mathjax>#n = "2.130 mol"#</mathjax><br/> <mathjax>#Δ_"vap"H = "42.32 kJ/mol"#</mathjax></p> <p>∴ <mathjax>#q = 2.130 color(red)(cancel(color(black)("mol"))) × "42.32 kJ"/(1 color(red)(cancel(color(black)("mol")))) = "90.1 kJ"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Ethanol, #CH_3CH_2OH#, has a vapor pressure of 59 mm Hg at 25 °C. What quantity of energy as heat is required to evaporate 125 mL of the alcohol at 25 °C?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>The enthalpy of vaporization of the alcohol at 25 °C is 42.32 kJ/mol. The density of the liquid is 0.7849 g/mL.</p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/thermochemistry-of-phase-changes" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry of Phase Changes</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="302094" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-08-23T22:57:07" itemprop="dateCreated"> Aug 23, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The energy required is 90.1 kJ.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The <strong>mass</strong> of ethanol is</p> <p><mathjax>#"Mass" = 125 color(red)(cancel(color(black)("mL"))) × "0.7849 g"/(1 color(red)(cancel(color(black)("mL")))) = "98.11 g"#</mathjax></p> <blockquote></blockquote> <p>The <strong>moles</strong> of ethanol are</p> <p><mathjax>#"Moles" = 98.11 color(red)(cancel(color(black)("g"))) × "1 mol"/(46.07 color(red)(cancel(color(black)("g")))) = "2.130 mol"#</mathjax></p> <blockquote></blockquote> <p>The <strong>energy</strong> required to evaporate a given amount of a liquid is given by the formula</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a) q = nΔ_"vap"Hcolor(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>where</p> <p><mathjax>#q#</mathjax> is the energy required<br/> <mathjax>#n#</mathjax> is the number of moles<br/> <mathjax>#Δ_"vap"H#</mathjax> is the molar <a href="https://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> of vaporization</p> <blockquote></blockquote> <p>In your problem,</p> <p><mathjax>#n = "2.130 mol"#</mathjax><br/> <mathjax>#Δ_"vap"H = "42.32 kJ/mol"#</mathjax></p> <p>∴ <mathjax>#q = 2.130 color(red)(cancel(color(black)("mol"))) × "42.32 kJ"/(1 color(red)(cancel(color(black)("mol")))) = "90.1 kJ"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/302094" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-much-energy-is-required-to-heat-100-g-of-ice-at-0-00-degrees-celsius-to-wate"> How much energy is required to convert 100.g of ice at 0.00 °C to water vapor at 100.00 °C? 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</a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/thermochemistry-of-phase-changes"> See all questions in Thermochemistry of Phase Changes </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 11286 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Ethanol, #CH_3CH_2OH#, has a vapor pressure of 59 mm Hg at 25 °C. What quantity of energy as heat is required to evaporate 125 mL of the alcohol at 25 °C?	The enthalpy of vaporization of the alcohol at 25 °C is 42.32 kJ/mol. The density of the liquid is 0.7849 g/mL.
757	ab9ed15c-6ddd-11ea-b9f7-ccda262736ce	https://socratic.org/questions/how-many-grams-of-iron-would-be-produced-if-2-moles-of-fe2o3-reacted-with-3-mole	56 grams	start physical_unit 4 4 mass g qc_end physical_unit 12 12 9 10 mole qc_end physical_unit 18 18 15 16 mole qc_end end	[{"type":"physical unit","value":"Mass [OF] iron [IN] grams"}]	[{"type":"physical unit","value":"56 grams"}]	[{"type":"physical unit","value":"Mole [OF] Fe2O3 [=] \\pu{2 moles}"},{"type":"physical unit","value":"Mole [OF] CO [=] \\pu{3 moles}"}]	<h1 class="questionTitle" itemprop="name">How many grams of iron would be produced if 2 moles of Fe2O3 reacted with 3 moles of CO?</h1>	null	56 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The equation for reducing Iron Oxide using Carbon Monoxide is:<br/> iron(III) oxide + carbon monoxide → iron + carbon dioxide<br/> <mathjax>#Fe_2O_3 + 3CO→ 2Fe + 3CO_2#</mathjax></p> <p>We then use <em><a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a></em> - which is just a fancy word for looking at the ratios of different <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a> in the equation.<br/> For every mole of Iron Oxide in the equation, there are 2 moles of Iron - as shown by the <strong>coefficients</strong> (number before a compound showing the number of moles). This is a ratio of 1:2.</p> <p>So, if we have 2 moles of Iron Oxide we will have <mathjax>#2xx2 = 4#</mathjax> moles of Iron.</p> <p>Now we need to look at the relative <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">atomic mass</a> of Iron - which is 56. If you remember, a mole of any substance has a mass equal to the substance's relative mass in grams (e.g. a mole of carbon would weigh 12g). So for 4 moles of Iron, that's <mathjax>#4xx56 = 224g#</mathjax></p> <p>I hope this helps; let me know if I can do anything else:)</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>56g</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The equation for reducing Iron Oxide using Carbon Monoxide is:<br/> iron(III) oxide + carbon monoxide → iron + carbon dioxide<br/> <mathjax>#Fe_2O_3 + 3CO→ 2Fe + 3CO_2#</mathjax></p> <p>We then use <em><a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a></em> - which is just a fancy word for looking at the ratios of different <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a> in the equation.<br/> For every mole of Iron Oxide in the equation, there are 2 moles of Iron - as shown by the <strong>coefficients</strong> (number before a compound showing the number of moles). This is a ratio of 1:2.</p> <p>So, if we have 2 moles of Iron Oxide we will have <mathjax>#2xx2 = 4#</mathjax> moles of Iron.</p> <p>Now we need to look at the relative <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">atomic mass</a> of Iron - which is 56. If you remember, a mole of any substance has a mass equal to the substance's relative mass in grams (e.g. a mole of carbon would weigh 12g). So for 4 moles of Iron, that's <mathjax>#4xx56 = 224g#</mathjax></p> <p>I hope this helps; let me know if I can do anything else:)</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many grams of iron would be produced if 2 moles of Fe2O3 reacted with 3 moles of CO?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/equation-stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Equation Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="425648" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/sarah-c-7"><img alt="" class="" src="https://profilepictures.socratic.org/UWEvw7fxSwSTqsMemJwl_IMG_3617.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/sarah-c-7"> Sarah C </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-18T15:58:47" itemprop="dateCreated"> May 18, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>56g</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The equation for reducing Iron Oxide using Carbon Monoxide is:<br/> iron(III) oxide + carbon monoxide → iron + carbon dioxide<br/> <mathjax>#Fe_2O_3 + 3CO→ 2Fe + 3CO_2#</mathjax></p> <p>We then use <em><a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a></em> - which is just a fancy word for looking at the ratios of different <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a> in the equation.<br/> For every mole of Iron Oxide in the equation, there are 2 moles of Iron - as shown by the <strong>coefficients</strong> (number before a compound showing the number of moles). This is a ratio of 1:2.</p> <p>So, if we have 2 moles of Iron Oxide we will have <mathjax>#2xx2 = 4#</mathjax> moles of Iron.</p> <p>Now we need to look at the relative <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">atomic mass</a> of Iron - which is 56. If you remember, a mole of any substance has a mass equal to the substance's relative mass in grams (e.g. a mole of carbon would weigh 12g). So for 4 moles of Iron, that's <mathjax>#4xx56 = 224g#</mathjax></p> <p>I hope this helps; let me know if I can do anything else:)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/425648" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4171602bf3469588dc36e"> What are the types of stoichiometry examples, with examples? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4171802bf3469570e2e82"> Question #e2e82 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/533668a402bf34573b4e66fb"> What mass of carbon dioxide can 1.00 kg of lithium oxide absorb? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-an-example-of-a-stoichiometry-practice-problem"> What is an example of a stoichiometry practice problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-an-example-of-a-balanced-equation-practice-problem"> What is an example of a balanced equation practice problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-a-chemical-equation"> How can I balance a chemical equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-stoichiometry-be-used"> How can stoichiometry be used? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-stoichiometric-ratios-relate-reactants-to-products"> How do stoichiometric ratios relate reactants to products? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-gas-stoichiometry-differ-from-stoichiometry-of-solids-and-liquids"> How does gas stoichiometry differ from stoichiometry of solids and liquids? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-stoichiometry-relate-to-the-law-of-conservation"> How does stoichiometry relate to the law of conservation? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/equation-stoichiometry"> See all questions in Equation Stoichiometry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 21652 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many grams of iron would be produced if 2 moles of Fe2O3 reacted with 3 moles of CO?	null
758	a8d25ba0-6ddd-11ea-a303-ccda262736ce	https://socratic.org/questions/592a889a7c014979d03f5b1c	+6	start physical_unit 9 9 oxidation_state none qc_end chemical_equation 9 9 qc_end end	[{"type":"physical unit","value":"Oxidation state [OF] Cr2O7^2-"}]	[{"type":"physical unit","value":"+6"}]	[{"type":"chemical equation","value":"Cr2O7^2-"}]	<h1 class="questionTitle" itemprop="name">What is the metal oxidation state in #"dichromate ion"#, #Cr_2O_7^(2-)#?</h1>	null	+6	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The SUM of the individual oxidation states of chromium and the oxygen atoms in dichromate anion is equal to the charge on the ion.</p> <p>And thus <mathjax>#2xxCr_"oxidation number"+7xxO_"oxidation number"=-2#</mathjax>.</p> <p>Now oxygen generally has an oxidation of <mathjax>#-2#</mathjax> in its <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a>, and it does so here, so.............</p> <p><mathjax>#2xxCr_"oxidation number"+7xx(-2)=-2#</mathjax>.</p> <p>Add +14 to both sides..............</p> <p><mathjax>#2xxCr_"oxidation number"=+12#</mathjax>.</p> <p><mathjax>#Cr_"oxidation number"=+12/2=+VI#</mathjax>, as required................</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>In <mathjax>#"dichromate"#</mathjax>, <mathjax>#Cr_2O_7^(2-)#</mathjax>? We got <mathjax>#Cr(VI+)#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The SUM of the individual oxidation states of chromium and the oxygen atoms in dichromate anion is equal to the charge on the ion.</p> <p>And thus <mathjax>#2xxCr_"oxidation number"+7xxO_"oxidation number"=-2#</mathjax>.</p> <p>Now oxygen generally has an oxidation of <mathjax>#-2#</mathjax> in its <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a>, and it does so here, so.............</p> <p><mathjax>#2xxCr_"oxidation number"+7xx(-2)=-2#</mathjax>.</p> <p>Add +14 to both sides..............</p> <p><mathjax>#2xxCr_"oxidation number"=+12#</mathjax>.</p> <p><mathjax>#Cr_"oxidation number"=+12/2=+VI#</mathjax>, as required................</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the metal oxidation state in #"dichromate ion"#, #Cr_2O_7^(2-)#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#electrochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Electrochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/electrochemistry/oxidation-numbers" itemprop="url"> <span class="breadcrumb" itemprop="title">Oxidation Numbers</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="430880" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-28T08:33:59" itemprop="dateCreated"> May 28, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>In <mathjax>#"dichromate"#</mathjax>, <mathjax>#Cr_2O_7^(2-)#</mathjax>? We got <mathjax>#Cr(VI+)#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The SUM of the individual oxidation states of chromium and the oxygen atoms in dichromate anion is equal to the charge on the ion.</p> <p>And thus <mathjax>#2xxCr_"oxidation number"+7xxO_"oxidation number"=-2#</mathjax>.</p> <p>Now oxygen generally has an oxidation of <mathjax>#-2#</mathjax> in its <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a>, and it does so here, so.............</p> <p><mathjax>#2xxCr_"oxidation number"+7xx(-2)=-2#</mathjax>.</p> <p>Add +14 to both sides..............</p> <p><mathjax>#2xxCr_"oxidation number"=+12#</mathjax>.</p> <p><mathjax>#Cr_"oxidation number"=+12/2=+VI#</mathjax>, as required................</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/430880" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-relate-to-electron-configuration"> How do oxidation numbers relate to electron configuration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-relate-to-valence-electrons"> How do oxidation numbers relate to valence electrons? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-vary-with-the-periodic-table"> How do oxidation numbers vary with the periodic table? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-oxidation-number-of-an-element-in-a-compound"> How do you calculate the oxidation number of an element in a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-sulfur"> What is the oxidation number for sulfur? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-carbon"> What is the oxidation number for carbon? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-copper"> What is the oxidation number for copper? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-nitrogen"> What is the oxidation number for nitrogen? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-oxygen"> What is the oxidation number for oxygen? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-oxidation-state-of-noble-gas-zero"> Why is the oxidation state of noble gas zero? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/electrochemistry/oxidation-numbers"> See all questions in Oxidation Numbers </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1611 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the metal oxidation state in #"dichromate ion"#, #Cr_2O_7^(2-)#?	null
759	ac7fccee-6ddd-11ea-aa3a-ccda262736ce	https://socratic.org/questions/what-is-the-formula-for-magnesium-nitride	Mg3N2	start chemical_formula qc_end substance 5 6 qc_end end	[{"type":"other","value":"Chemical Formula [OF] magnesium nitride [IN] default"}]	[{"type":"chemical equation","value":"Mg3N2"}]	[{"type":"substance name","value":"Magnesium nitride"}]	<h1 class="questionTitle" itemprop="name">What is the formula for magnesium nitride? </h1>	null	Mg3N2	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Of course this is the ionic salt of <mathjax>#Mg^(2+)#</mathjax> and <mathjax>#N^(3-)#</mathjax>. Hydrolysis gives ammonia:</p> <p><mathjax>#Mg_3N_2(s) + 6H_2O(l) rarr 3Mg(OH)_2(aq) + 2NH_3(aq)#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Mg_3N_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Of course this is the ionic salt of <mathjax>#Mg^(2+)#</mathjax> and <mathjax>#N^(3-)#</mathjax>. Hydrolysis gives ammonia:</p> <p><mathjax>#Mg_3N_2(s) + 6H_2O(l) rarr 3Mg(OH)_2(aq) + 2NH_3(aq)#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the formula for magnesium nitride? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#ionic-bonds-and-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Ionic Bonds</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/ionic-bonds-and-formulas/writing-ionic-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Writing Ionic Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="259999" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-04-28T20:54:35" itemprop="dateCreated"> Apr 28, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Mg_3N_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Of course this is the ionic salt of <mathjax>#Mg^(2+)#</mathjax> and <mathjax>#N^(3-)#</mathjax>. Hydrolysis gives ammonia:</p> <p><mathjax>#Mg_3N_2(s) + 6H_2O(l) rarr 3Mg(OH)_2(aq) + 2NH_3(aq)#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/259999" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-write-ionic-formulas-for-binary-compounds"> How do you write ionic formulas for binary compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-formula-for-calcium-chloride"> What is the ionic formula for calcium chloride? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-formula-for-calcium-oxide"> What is the ionic formula for calcium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-formula-for-lithium-oxide"> What is the ionic formula for lithium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-formula-for-ionic-compounds"> How do you write the formula for ionic compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-correctly-write-the-ions-present-in-sn-no3-2"> How do I write #Sn(NO_3)_2# in Ionic formula? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-an-ionic-compound"> What is the empirical formula for an ionic compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-for-chorate"> What is the molecular formula for chorate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5363023c02bf343b2ee7086b"> Question #7086b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-polyatomic-ions-covalent-1"> Why are polyatomic ions covalent? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/ionic-bonds-and-formulas/writing-ionic-formulas"> See all questions in Writing Ionic Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 8680 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the formula for magnesium nitride?	null
760	aaa9f938-6ddd-11ea-875f-ccda262736ce	https://socratic.org/questions/575bdcd111ef6b2e73f01782	5000.00 mol	start physical_unit 2 3 mole mol qc_end physical_unit 13 13 9 10 mass qc_end end	[{"type":"physical unit","value":"Mole [OF] oxygen gas [IN] mol"}]	[{"type":"physical unit","value":"5000.00 mol"}]	[{"type":"physical unit","value":"Mass [OF] water [=] \\pu{9 kg}"}]	<h1 class="questionTitle" itemprop="name">How much oxygen gas can I make from a #9*kg# mass of water? </h1>	null	5000.00 mol	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You have <mathjax>#90xx10^3g#</mathjax> of water. This represents a MOLAR quantity of <mathjax>#(90xx10^3g)/(18gmol^-1)=??mol#</mathjax>.</p> <p>The number of moles of oxygen gas, <mathjax>#O_2#</mathjax>, is half this molar quantity by the stoichiometric equation.</p> <p>And of course each mole of oxygen gas has a mass of <mathjax>#32*g#</mathjax>. From where am I getting these masses? Do you have to learn them?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#H_2O(g) rarr 1/2O_2(g) + H_2(g)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You have <mathjax>#90xx10^3g#</mathjax> of water. This represents a MOLAR quantity of <mathjax>#(90xx10^3g)/(18gmol^-1)=??mol#</mathjax>.</p> <p>The number of moles of oxygen gas, <mathjax>#O_2#</mathjax>, is half this molar quantity by the stoichiometric equation.</p> <p>And of course each mole of oxygen gas has a mass of <mathjax>#32*g#</mathjax>. From where am I getting these masses? Do you have to learn them?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How much oxygen gas can I make from a #9kg# mass of water? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="278284" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-17T05:21:53" itemprop="dateCreated"> Jun 17, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#H_2O(g) rarr 1/2O_2(g) + H_2(g)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You have <mathjax>#90xx10^3g#</mathjax> of water. This represents a MOLAR quantity of <mathjax>#(90xx10^3g)/(18gmol^-1)=??mol#</mathjax>.</p> <p>The number of moles of oxygen gas, <mathjax>#O_2#</mathjax>, is half this molar quantity by the stoichiometric equation.</p> <p>And of course each mole of oxygen gas has a mass of <mathjax>#32g#</mathjax>. From where am I getting these masses? Do you have to learn them?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/278284" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What is stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ab82402bf342f48d93ac6"> Question #93ac6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-we-study-stoichiometry"> Why do we study stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-naoh-is-produced-from-1-20-x-102-grams-of-na2o-na2o-h2o-2-naoh"> How many grams of NaOH is produced from #1.20 x 10^2# grams of #Na_2O#? #Na_2O + H_2O -> 2NaOH# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-na2o-are-required-to-produce-1-60-x-102-grams-of-naoh-na2o-h2o"> How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? 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761	ab5a4cca-6ddd-11ea-a826-ccda262736ce	https://socratic.org/questions/what-is-the-volume-occupied-by-30-7-g-cl-2-g-at-35-c-and-745-torr	11 L	start physical_unit 8 8 volume l qc_end physical_unit 8 8 6 7 mass qc_end physical_unit 8 8 10 11 temperature qc_end physical_unit 8 8 13 14 pressure qc_end end	[{"type":"physical unit","value":"Volume [OF] Cl2(g) [IN] L"}]	[{"type":"physical unit","value":"11 L"}]	[{"type":"physical unit","value":"Mass [OF] Cl2(g) [=] \\pu{30.7 g}"},{"type":"physical unit","value":"Temperature [OF] Cl2(g) [=] \\pu{35 ℃}"},{"type":"physical unit","value":"Pressure [OF] Cl2(g) [=] \\pu{745 torr}"}]	<h1 class="questionTitle" itemprop="name">What is the volume occupied by 30.7 g #Cl_2#(g) at 35°C and 745 torr?</h1>	null	11 L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We must first express the pressure exerted by the gas. We know that <mathjax>#1atm#</mathjax> of pressure will support a column of mercury that is <mathjax>#760mm#</mathjax> high. And thus a mercury column, even if you face an awful problem if the column breaks and the mercury spills, is a good visual representation of pressure. </p> <p>And thus <mathjax>#1atm-=760mmHg#</mathjax>.......</p> <p>And then we fill in the variables for <mathjax>#V=(nRT)/P#</mathjax>, i.e.</p> <p><mathjax>#V=((30.7g)/(70.9gmol^-1)xx0.0821(Latm)/(Kmol)xx308.2K)/((745mmHg)/(760mmHgatm^-1))=??L#</mathjax></p> <p>Is this expression dimensionally consistent? That is when I cancel out the units in the numerator and the denominator, I SHOULD get an answer in <mathjax>#L#</mathjax>...........All care taken but no responsibility admitted.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We use the old <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a>, and get <mathjax>#V~=11L#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We must first express the pressure exerted by the gas. We know that <mathjax>#1atm#</mathjax> of pressure will support a column of mercury that is <mathjax>#760mm#</mathjax> high. And thus a mercury column, even if you face an awful problem if the column breaks and the mercury spills, is a good visual representation of pressure. </p> <p>And thus <mathjax>#1atm-=760mmHg#</mathjax>.......</p> <p>And then we fill in the variables for <mathjax>#V=(nRT)/P#</mathjax>, i.e.</p> <p><mathjax>#V=((30.7g)/(70.9gmol^-1)xx0.0821(Latm)/(Kmol)xx308.2K)/((745mmHg)/(760mmHgatm^-1))=??*L#</mathjax></p> <p>Is this expression dimensionally consistent? That is when I cancel out the units in the numerator and the denominator, I SHOULD get an answer in <mathjax>#L#</mathjax>...........All care taken but no responsibility admitted.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the volume occupied by 30.7 g #Cl_2#(g) at 35°C and 745 torr?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/gas-laws" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Laws</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="437549" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-10T15:10:45" itemprop="dateCreated"> Jun 10, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We use the old <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a>, and get <mathjax>#V~=11L#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We must first express the pressure exerted by the gas. We know that <mathjax>#1atm#</mathjax> of pressure will support a column of mercury that is <mathjax>#760mm#</mathjax> high. And thus a mercury column, even if you face an awful problem if the column breaks and the mercury spills, is a good visual representation of pressure. </p> <p>And thus <mathjax>#1atm-=760mmHg#</mathjax>.......</p> <p>And then we fill in the variables for <mathjax>#V=(nRT)/P#</mathjax>, i.e.</p> <p><mathjax>#V=((30.7g)/(70.9gmol^-1)xx0.0821(Latm)/(Kmol)xx308.2K)/((745mmHg)/(760mmHgatm^-1))=??*L#</mathjax></p> <p>Is this expression dimensionally consistent? That is when I cancel out the units in the numerator and the denominator, I SHOULD get an answer in <mathjax>#L#</mathjax>...........All care taken but no responsibility admitted.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/437549" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-boyles-law-relate-to-breathing"> How does Boyle's law relate to breathing? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/in-avogadro-s-law-what-would-happen-to-v-if-n-is-increased-decreased-and-what-wo"> In Avogadro's Law what would happen to V if N is increased/decreased? 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762	a98ab558-6ddd-11ea-bfe2-ccda262736ce	https://socratic.org/questions/59363ad111ef6b0d28bf5fcc	2.12 M	start physical_unit 6 6 molarity mol/l qc_end physical_unit 6 6 16 17 temperature qc_end end	[{"type":"physical unit","value":"Molar concentration [OF] methanol [IN] M"}]	[{"type":"physical unit","value":"2.12 M"}]	[{"type":"physical unit","value":"Mol fraction [OF] methanol in solution [=] \\pu{0.040}"},{"type":"physical unit","value":"Temperature [OF] methanol [=] \\pu{4 ℃}"}]	<h1 class="questionTitle" itemprop="name">What is the molar concentration of methanol if the mol fraction of methanol is #0.040# at #4^@ "C"#?</h1>	null	2.12 M	<div class="answerDescription"> <div> <div class="markdown"><p>About <mathjax>#"2.12 M"#</mathjax> if you can look up the <a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a> of methanol. About <mathjax>#"2.31 M"#</mathjax> if you cannot, which would be around <mathjax>#9%#</mathjax> error.</p> <hr/> <p>Recall that:</p> <blockquote> <p><mathjax>#"molarity" -= ("mol solute")/("L soln")#</mathjax></p> </blockquote> <p>Since we are given that the mol fraction of methanol is</p> <blockquote> <p><mathjax>#chi_(MeOH) = (n_(MeOH))/(n_(MeOH) + n_(H_2O)) = 0.040#</mathjax>,</p> </blockquote> <p>we probably have to make an assumption here, as we are only given a relative quantity with the mol fraction. </p> <p>Assume that you have <mathjax>#"1 L"#</mathjax> of <strong>water</strong> so that we can use the density of water (at <mathjax>#4^@ "C"#</mathjax>):</p> <blockquote> <p><mathjax>#cancel("1 L H"_2"O") xx (1000 cancel("g H"_2"O"))/cancel"L" xx ("1 mol H"_2"O")/(18.015 cancel("g H"_2"O"))#</mathjax></p> <p><mathjax>#=#</mathjax> <mathjax>#"55.51 mols"#</mathjax></p> <p>(note that this also means that the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of pure water [at <mathjax>#4^@ "C"#</mathjax>] is <mathjax>#"55.51 M"#</mathjax>.)</p> </blockquote> <p>Given we know the mols of water now, we can use the mol fraction to <strong>solve for the mols of methanol</strong>:</p> <blockquote> <p><mathjax>#0.040 = n_(MeOH)/(n_(MeOH) + 55.51)#</mathjax></p> <p><mathjax>#=> 0.040n_(MeOH) + 0.040(55.51) = n_(MeOH)#</mathjax> </p> <p><mathjax>#=> 0.960n_(MeOH) = 2.220#</mathjax></p> <p><mathjax>#=> n_(MeOH) = "2.313 mols"#</mathjax> </p> </blockquote> <p>This then gives us a molarity of:</p> <blockquote> <p><mathjax>#"2.313 mols MeOH"/V_(sol n)#</mathjax></p> <p><mathjax>#"2.313 mols MeOH"/(V_(MeOH) + V_(H_2O))#</mathjax></p> <p><mathjax>#= "2.313 mols MeOH"/(n_(MeOH)barV_(MeOH) + V_(H_2O))#</mathjax></p> <p>where <mathjax>#barV#</mathjax> is the molar volume in <mathjax>#"L/mol"#</mathjax>. </p> </blockquote> <p>In a situation where you cannot look up the density of methanol, we would have had to assume that <mathjax>#V_(sol n) ~~ V_(H_2O)#</mathjax> for a sufficiently dilute solution, and we would have gotten <mathjax>#color(red)("2.313 M")#</mathjax>. That is, however, not entirely accurate.</p> <p>We'll simply <a href="http://www.ddbst.com/en/EED/PCP/DEN_C110.php" rel="nofollow">look up the density of methanol</a>, which is <mathjax>#~~#</mathjax> <mathjax>#"806 g/L"#</mathjax> (by interpolation at <mathjax>#"277.15 K"#</mathjax>). So, we have:</p> <blockquote> <p><mathjax>#barV_(MeOH) = "1 L"/(806 cancel"g MeOH") xx (32.04 cancel"g MeOH")/("mol") = "0.0398 L/mol"#</mathjax></p> </blockquote> <p>This means the volume of methanol in the solution is:</p> <blockquote> <p><mathjax>#V_(MeOH) = n_(MeOH)barV_(MeOH )#</mathjax></p> <p><mathjax>#= "2.313 mols" xx "0.0398 L/mol" = "0.0919 L"#</mathjax></p> </blockquote> <p>Assuming additivity of volumes of water and methanol:</p> <blockquote> <p><mathjax>#V_(sol n) ~~ V_(MeOH) + V_(H_2O) ~~ "1.0919 L soln"#</mathjax></p> </blockquote> <p>So, the molarity is:</p> <blockquote> <p><mathjax>#color(blue)(["MeOH"(aq)]) ~~ "2.313 mols"/"1.0919 L" = color(blue)("2.12 M")#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerDescription"> <div> <div class="markdown"><p>About <mathjax>#"2.12 M"#</mathjax> if you can look up the <a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a> of methanol. About <mathjax>#"2.31 M"#</mathjax> if you cannot, which would be around <mathjax>#9%#</mathjax> error.</p> <hr/> <p>Recall that:</p> <blockquote> <p><mathjax>#"molarity" -= ("mol solute")/("L soln")#</mathjax></p> </blockquote> <p>Since we are given that the mol fraction of methanol is</p> <blockquote> <p><mathjax>#chi_(MeOH) = (n_(MeOH))/(n_(MeOH) + n_(H_2O)) = 0.040#</mathjax>,</p> </blockquote> <p>we probably have to make an assumption here, as we are only given a relative quantity with the mol fraction. </p> <p>Assume that you have <mathjax>#"1 L"#</mathjax> of <strong>water</strong> so that we can use the density of water (at <mathjax>#4^@ "C"#</mathjax>):</p> <blockquote> <p><mathjax>#cancel("1 L H"_2"O") xx (1000 cancel("g H"_2"O"))/cancel"L" xx ("1 mol H"_2"O")/(18.015 cancel("g H"_2"O"))#</mathjax></p> <p><mathjax>#=#</mathjax> <mathjax>#"55.51 mols"#</mathjax></p> <p>(note that this also means that the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of pure water [at <mathjax>#4^@ "C"#</mathjax>] is <mathjax>#"55.51 M"#</mathjax>.)</p> </blockquote> <p>Given we know the mols of water now, we can use the mol fraction to <strong>solve for the mols of methanol</strong>:</p> <blockquote> <p><mathjax>#0.040 = n_(MeOH)/(n_(MeOH) + 55.51)#</mathjax></p> <p><mathjax>#=> 0.040n_(MeOH) + 0.040(55.51) = n_(MeOH)#</mathjax> </p> <p><mathjax>#=> 0.960n_(MeOH) = 2.220#</mathjax></p> <p><mathjax>#=> n_(MeOH) = "2.313 mols"#</mathjax> </p> </blockquote> <p>This then gives us a molarity of:</p> <blockquote> <p><mathjax>#"2.313 mols MeOH"/V_(sol n)#</mathjax></p> <p><mathjax>#"2.313 mols MeOH"/(V_(MeOH) + V_(H_2O))#</mathjax></p> <p><mathjax>#= "2.313 mols MeOH"/(n_(MeOH)barV_(MeOH) + V_(H_2O))#</mathjax></p> <p>where <mathjax>#barV#</mathjax> is the molar volume in <mathjax>#"L/mol"#</mathjax>. </p> </blockquote> <p>In a situation where you cannot look up the density of methanol, we would have had to assume that <mathjax>#V_(sol n) ~~ V_(H_2O)#</mathjax> for a sufficiently dilute solution, and we would have gotten <mathjax>#color(red)("2.313 M")#</mathjax>. That is, however, not entirely accurate.</p> <p>We'll simply <a href="http://www.ddbst.com/en/EED/PCP/DEN_C110.php" rel="nofollow">look up the density of methanol</a>, which is <mathjax>#~~#</mathjax> <mathjax>#"806 g/L"#</mathjax> (by interpolation at <mathjax>#"277.15 K"#</mathjax>). So, we have:</p> <blockquote> <p><mathjax>#barV_(MeOH) = "1 L"/(806 cancel"g MeOH") xx (32.04 cancel"g MeOH")/("mol") = "0.0398 L/mol"#</mathjax></p> </blockquote> <p>This means the volume of methanol in the solution is:</p> <blockquote> <p><mathjax>#V_(MeOH) = n_(MeOH)barV_(MeOH )#</mathjax></p> <p><mathjax>#= "2.313 mols" xx "0.0398 L/mol" = "0.0919 L"#</mathjax></p> </blockquote> <p>Assuming additivity of volumes of water and methanol:</p> <blockquote> <p><mathjax>#V_(sol n) ~~ V_(MeOH) + V_(H_2O) ~~ "1.0919 L soln"#</mathjax></p> </blockquote> <p>So, the molarity is:</p> <blockquote> <p><mathjax>#color(blue)(["MeOH"(aq)]) ~~ "2.313 mols"/"1.0919 L" = color(blue)("2.12 M")#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the molar concentration of methanol if the mol fraction of methanol is #0.040# at #4^@ "C"#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="436856" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/truong-son-n"><img alt="" class="" src="https://profilepictures.socratic.org/07k4plnQfmnmzMuesQzw_14844-1449381920.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/truong-son-n"> Truong-Son N. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-09T02:02:44" itemprop="dateCreated"> Jun 9, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerDescription"> <div> <div class="markdown"><p>About <mathjax>#"2.12 M"#</mathjax> if you can look up the <a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a> of methanol. About <mathjax>#"2.31 M"#</mathjax> if you cannot, which would be around <mathjax>#9%#</mathjax> error.</p> <hr/> <p>Recall that:</p> <blockquote> <p><mathjax>#"molarity" -= ("mol solute")/("L soln")#</mathjax></p> </blockquote> <p>Since we are given that the mol fraction of methanol is</p> <blockquote> <p><mathjax>#chi_(MeOH) = (n_(MeOH))/(n_(MeOH) + n_(H_2O)) = 0.040#</mathjax>,</p> </blockquote> <p>we probably have to make an assumption here, as we are only given a relative quantity with the mol fraction. </p> <p>Assume that you have <mathjax>#"1 L"#</mathjax> of <strong>water</strong> so that we can use the density of water (at <mathjax>#4^@ "C"#</mathjax>):</p> <blockquote> <p><mathjax>#cancel("1 L H"_2"O") xx (1000 cancel("g H"_2"O"))/cancel"L" xx ("1 mol H"_2"O")/(18.015 cancel("g H"_2"O"))#</mathjax></p> <p><mathjax>#=#</mathjax> <mathjax>#"55.51 mols"#</mathjax></p> <p>(note that this also means that the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of pure water [at <mathjax>#4^@ "C"#</mathjax>] is <mathjax>#"55.51 M"#</mathjax>.)</p> </blockquote> <p>Given we know the mols of water now, we can use the mol fraction to <strong>solve for the mols of methanol</strong>:</p> <blockquote> <p><mathjax>#0.040 = n_(MeOH)/(n_(MeOH) + 55.51)#</mathjax></p> <p><mathjax>#=> 0.040n_(MeOH) + 0.040(55.51) = n_(MeOH)#</mathjax> </p> <p><mathjax>#=> 0.960n_(MeOH) = 2.220#</mathjax></p> <p><mathjax>#=> n_(MeOH) = "2.313 mols"#</mathjax> </p> </blockquote> <p>This then gives us a molarity of:</p> <blockquote> <p><mathjax>#"2.313 mols MeOH"/V_(sol n)#</mathjax></p> <p><mathjax>#"2.313 mols MeOH"/(V_(MeOH) + V_(H_2O))#</mathjax></p> <p><mathjax>#= "2.313 mols MeOH"/(n_(MeOH)barV_(MeOH) + V_(H_2O))#</mathjax></p> <p>where <mathjax>#barV#</mathjax> is the molar volume in <mathjax>#"L/mol"#</mathjax>. </p> </blockquote> <p>In a situation where you cannot look up the density of methanol, we would have had to assume that <mathjax>#V_(sol n) ~~ V_(H_2O)#</mathjax> for a sufficiently dilute solution, and we would have gotten <mathjax>#color(red)("2.313 M")#</mathjax>. That is, however, not entirely accurate.</p> <p>We'll simply <a href="http://www.ddbst.com/en/EED/PCP/DEN_C110.php" rel="nofollow">look up the density of methanol</a>, which is <mathjax>#~~#</mathjax> <mathjax>#"806 g/L"#</mathjax> (by interpolation at <mathjax>#"277.15 K"#</mathjax>). So, we have:</p> <blockquote> <p><mathjax>#barV_(MeOH) = "1 L"/(806 cancel"g MeOH") xx (32.04 cancel"g MeOH")/("mol") = "0.0398 L/mol"#</mathjax></p> </blockquote> <p>This means the volume of methanol in the solution is:</p> <blockquote> <p><mathjax>#V_(MeOH) = n_(MeOH)barV_(MeOH )#</mathjax></p> <p><mathjax>#= "2.313 mols" xx "0.0398 L/mol" = "0.0919 L"#</mathjax></p> </blockquote> <p>Assuming additivity of volumes of water and methanol:</p> <blockquote> <p><mathjax>#V_(sol n) ~~ V_(MeOH) + V_(H_2O) ~~ "1.0919 L soln"#</mathjax></p> </blockquote> <p>So, the molarity is:</p> <blockquote> <p><mathjax>#color(blue)(["MeOH"(aq)]) ~~ "2.313 mols"/"1.0919 L" = color(blue)("2.12 M")#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/436856" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="483797" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-10-02T20:03:09" itemprop="dateCreated"> Oct 2, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><blockquote></blockquote> <p>The <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> is 2.1 mol/L.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>Assume that we have a solution containing 0.040 mol methanol and 0.960 mol water (<mathjax>#chi_text(MeOH) = 0.040#</mathjax>).</p> <p><mathjax>#"Volume of MeOH" = 0.040 color(red)(cancel(color(black)("mol MeOH"))) × (32.04 color(red)(cancel(color(black)("g MeOH"))))/(1 color(red)(cancel(color(black)("mol MeOH")))) × "1 mL MeOH"/(0.792 color(red)(cancel(color(black)("g MeOH")))) = 1.62 "mL MeOH"#</mathjax></p> <p><mathjax>#"Volume of H"_2"O" = 0.960 color(red)(cancel(color(black)("mol H"_2"O"))) × (18.02 color(red)(cancel(color(black)("g H"_2"O"))))/(1 color(red)(cancel(color(black)("mol H"_2"O")))) × ("1 mL H"_2"O")/(1.0 color(red)(cancel(color(black)("g H"_2"O")))) = "17.3 mL H"_2"O"#</mathjax></p> <blockquote></blockquote> <p>If there is no volume change on mixing,</p> <p><mathjax>#"Total volume" = "(1.62 + 17.3) mL" = "18.9 mL"#</mathjax></p> <p>Then,</p> <p><mathjax>#"Molarity" = "moles of methanol"/"litres of solution" = "0.040 mol"/"0.0189 L" = "2.1 mol/L"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/483797" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? 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763	ab5562e4-6ddd-11ea-b500-ccda262736ce	https://socratic.org/questions/when-propane-c-3h-8-is-burned-carbon-dioxide-and-water-vapor-are-produced-accord	44 g	start physical_unit 1 1 mass g qc_end chemical_equation 17 26 qc_end physical_unit 20 20 33 34 mass qc_end physical_unit 23 23 40 41 mass qc_end physical_unit 26 26 45 46 mass qc_end end	[{"type":"physical unit","value":"Mass [OF] propane [IN] g"}]	[{"type":"physical unit","value":"44 g"}]	[{"type":"chemical equation","value":"C3H8 + 5 O2 -> 3 CO2 + 4 H2O"},{"type":"physical unit","value":"Mass [OF] O2 [=] \\pu{160.0 g}"},{"type":"physical unit","value":"Mass [OF] CO2 [=] \\pu{132 g}"},{"type":"physical unit","value":"Mass [OF] H2O [=] \\pu{72.0 g}"}]	<h1 class="questionTitle" itemprop="name">When propane, #C_3H_8#, is burned, carbon dioxide and water vapor are produced according to the following reaction: #C_3H_8 + 5O_2 -> 3CO_2 + 4H_2O#. How much propane is burned if 160.0 g of O2 are used and 132 g of CO2 and 72.0 g of H2O are produced?</h1>	null	44 g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Moles of carbon dioxide:"#</mathjax> <mathjax>#(132g)/(44.0gmol^-1)=3mol#</mathjax></p> <p><mathjax>#"Moles of water:"#</mathjax> <mathjax>#(72g)/(18.01gmol^-1)=4mol#</mathjax></p> <p><mathjax>#"Moles of oxygen:"#</mathjax> <mathjax>#(160g)/(32.0gmol^-1)=5mol#</mathjax></p> <p>Because there were <mathjax>#3#</mathjax> <mathjax>#mol#</mathjax> carbon dioxide produced, and stoichiometric water, one mole precisely of propane was combusted.</p> <p>If pentane were burned in excess dioxygen, and <mathjax>#220*g#</mathjax> carbon dioxide were produced, what was the starting mass of pentane?</p> <p><mathjax>#C_5H_12 + 8O_2 rarr 5CO_2 + 6H_2O#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_3H_8+5O_2 rarr 3CO_2 + 4H_2O#</mathjax></p> <p>Precisely one mole, <mathjax>#44g#</mathjax> of pentane, were combusted.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Moles of carbon dioxide:"#</mathjax> <mathjax>#(132g)/(44.0gmol^-1)=3mol#</mathjax></p> <p><mathjax>#"Moles of water:"#</mathjax> <mathjax>#(72g)/(18.01gmol^-1)=4mol#</mathjax></p> <p><mathjax>#"Moles of oxygen:"#</mathjax> <mathjax>#(160g)/(32.0gmol^-1)=5mol#</mathjax></p> <p>Because there were <mathjax>#3#</mathjax> <mathjax>#mol#</mathjax> carbon dioxide produced, and stoichiometric water, one mole precisely of propane was combusted.</p> <p>If pentane were burned in excess dioxygen, and <mathjax>#220g#</mathjax> carbon dioxide were produced, what was the starting mass of pentane?</p> <p><mathjax>#C_5H_12 + 8O_2 rarr 5CO_2 + 6H_2O#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">When propane, #C_3H_8#, is burned, carbon dioxide and water vapor are produced according to the following reaction: #C_3H_8 + 5O_2 -> 3CO_2 + 4H_2O#. How much propane is burned if 160.0 g of O2 are used and 132 g of CO2 and 72.0 g of H2O are produced?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-reactions-and-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions and Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="354034" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-12-19T08:29:53" itemprop="dateCreated"> Dec 19, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_3H_8+5O_2 rarr 3CO_2 + 4H_2O#</mathjax></p> <p>Precisely one mole, <mathjax>#44g#</mathjax> of pentane, were combusted.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Moles of carbon dioxide:"#</mathjax> <mathjax>#(132g)/(44.0gmol^-1)=3mol#</mathjax></p> <p><mathjax>#"Moles of water:"#</mathjax> <mathjax>#(72g)/(18.01gmol^-1)=4mol#</mathjax></p> <p><mathjax>#"Moles of oxygen:"#</mathjax> <mathjax>#(160g)/(32.0gmol^-1)=5mol#</mathjax></p> <p>Because there were <mathjax>#3#</mathjax> <mathjax>#mol#</mathjax> carbon dioxide produced, and stoichiometric water, one mole precisely of propane was combusted.</p> <p>If pentane were burned in excess dioxygen, and <mathjax>#220g#</mathjax> carbon dioxide were produced, what was the starting mass of pentane?</p> <p><mathjax>#C_5H_12 + 8O_2 rarr 5CO_2 + 6H_2O#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/354034" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb002bf34694a4fee47"> Question #fee47 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb402bf34694c8c5c15"> Question #c5c15 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb802bf346950519eb9"> Question #19eb9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cbf02bf3469570e2ea2"> Question #e2ea2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc002bf34695a6bc751"> Question #bc751 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc202bf3469570e2ea6"> Question #e2ea6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531e867a02bf342492a08b07"> Question #08b07 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-thermochemical-equation-for-the-combustion-of-benzene"> What is the thermochemical equation for the combustion of benzene? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-reversible"> Why are chemical reactions reversible? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-important"> Why are chemical reactions important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/chemical-reactions-and-equations"> See all questions in Chemical Reactions and Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 8029 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	When propane, #C_3H_8#, is burned, carbon dioxide and water vapor are produced according to the following reaction: #C_3H_8 + 5O_2 -> 3CO_2 + 4H_2O#. How much propane is burned if 160.0 g of O2 are used and 132 g of CO2 and 72.0 g of H2O are produced?	null
764	a8d7d09c-6ddd-11ea-a24f-ccda262736ce	https://socratic.org/questions/how-many-moles-of-sodium-chloride-solute-are-in-155-grams-of-an-85-5-percent-by-	2.27 moles	start physical_unit 4 6 mole mol qc_end physical_unit 4 6 13 13 mass_percent qc_end physical_unit 4 6 9 10 mass qc_end end	[{"type":"physical unit","value":"Mole [OF] sodium chloride solute [IN] moles"}]	[{"type":"physical unit","value":"2.27 moles"}]	[{"type":"physical unit","value":"Percent by mass [OF] sodium chloride solute in solution [=] \\pu{85.5 percent}"},{"type":"physical unit","value":"Mass [OF] sodium chloride solute [=] \\pu{155 grams}"}]	<h1 class="questionTitle" itemprop="name">How many moles of sodium chloride solute are in 155 grams of an 85.5 percent by mass solution? </h1>	null	2.27 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Thus if <mathjax>#"% by mass"=85%#</mathjax>, there are <mathjax>#85.5%xx155g" solute"#</mathjax> in a solution whose mass is <mathjax>#155g#</mathjax>.</p> <p><mathjax>#"Moles of NaCl"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(85.5%xx155g)/(58.44gmol^-1)#</mathjax> </p> <p><mathjax>#=#</mathjax> <mathjax>#2.27mol" with respect to NaCl"#</mathjax>.</p> <p>This result makes no chemical sense at all inasmuch as I do not think you can prepare a solution of sodium chloride with that concentration. C'est la vie. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"% by mass"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"mass of solute"/"mass of solution"xx100%#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Thus if <mathjax>#"% by mass"=85%#</mathjax>, there are <mathjax>#85.5%xx155g" solute"#</mathjax> in a solution whose mass is <mathjax>#155g#</mathjax>.</p> <p><mathjax>#"Moles of NaCl"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(85.5%xx155g)/(58.44gmol^-1)#</mathjax> </p> <p><mathjax>#=#</mathjax> <mathjax>#2.27mol" with respect to NaCl"#</mathjax>.</p> <p>This result makes no chemical sense at all inasmuch as I do not think you can prepare a solution of sodium chloride with that concentration. C'est la vie. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles of sodium chloride solute are in 155 grams of an 85.5 percent by mass solution? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/percent-concentration" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Concentration</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="301517" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-08-22T06:53:29" itemprop="dateCreated"> Aug 22, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"% by mass"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"mass of solute"/"mass of solution"xx100%#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Thus if <mathjax>#"% by mass"=85%#</mathjax>, there are <mathjax>#85.5%xx155g" solute"#</mathjax> in a solution whose mass is <mathjax>#155g#</mathjax>.</p> <p><mathjax>#"Moles of NaCl"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(85.5%xx155g)/(58.44gmol^-1)#</mathjax> </p> <p><mathjax>#=#</mathjax> <mathjax>#2.27mol" with respect to NaCl"#</mathjax>.</p> <p>This result makes no chemical sense at all inasmuch as I do not think you can prepare a solution of sodium chloride with that concentration. C'est la vie. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/301517" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-concentration-of-water-in-solution-be-decreased"> How can the concentration of water in solution be decreased? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-concentration-of-a-solution-be-increased"> How can the concentration of a solution be increased? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-concentration-of-a-solution-in-ppm"> How do you find the concentration of a solution in ppm? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-make-a-10-percent-solution"> How do you make a 10 percent solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-make-a-2-percent-solution"> How do you make a 2 percent solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-weight-per-volume-method-to-calculate-concentration"> What is the weight per volume method to calculate concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-percent-concentration-of-kcl-would-be-isotonic"> What percent concentration of KCl would be isotonic? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-of-sodium-chloride-in-normal-saline"> What is the percent concentration of sodium chloride in normal saline? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-of-a-6m-solution-of-nacl"> What is the percent concentration of a 6m solution of NaCl? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-formula"> What is the percent concentration formula? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/percent-concentration"> See all questions in Percent Concentration </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3720 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many moles of sodium chloride solute are in 155 grams of an 85.5 percent by mass solution?	null
765	ad01ae70-6ddd-11ea-8f8c-ccda262736ce	https://socratic.org/questions/how-much-heat-is-added-if-617g-of-water-is-increased-in-temperature-by-241-degre	0.62 J	start physical_unit 9 9 heat_energy j qc_end physical_unit 9 9 6 7 mass qc_end physical_unit 9 9 15 17 temperature qc_end end	[{"type":"physical unit","value":"Added heat [OF] water [IN] J"}]	[{"type":"physical unit","value":"0.62 J"}]	[{"type":"physical unit","value":"Mass [OF] water [=] \\pu{0.617 g}"},{"type":"physical unit","value":"Increased temperature [OF] water [=] \\pu{0.241 degrees C}"}]	<h1 class="questionTitle" itemprop="name">How much heat is added if .617g of water is increased in temperature by .241 degrees C? </h1>	null	0.62 J	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to solve this problem, you need the formula:<br/> <mathjax>#q=mC_sDeltaT#</mathjax></p> <p>Assuming water is in its liquid state, the <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> capacity or <mathjax>#C_s#</mathjax> would be 4.18 <mathjax>#J/(g* degrees Celsius)#</mathjax></p> <p><mathjax>#DeltaT#</mathjax> in this case would be 0.241 degrees Celsius since this represents the change in temperature.</p> <p><mathjax>#m#</mathjax> would be 0.617 grams.</p> <p>Plug in all the values and you would get 0.622 joules!<br/> Hope this helps! </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.622 J</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to solve this problem, you need the formula:<br/> <mathjax>#q=mC_sDeltaT#</mathjax></p> <p>Assuming water is in its liquid state, the <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> capacity or <mathjax>#C_s#</mathjax> would be 4.18 <mathjax>#J/(g* degrees Celsius)#</mathjax></p> <p><mathjax>#DeltaT#</mathjax> in this case would be 0.241 degrees Celsius since this represents the change in temperature.</p> <p><mathjax>#m#</mathjax> would be 0.617 grams.</p> <p>Plug in all the values and you would get 0.622 joules!<br/> Hope this helps! </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How much heat is added if .617g of water is increased in temperature by .241 degrees C? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/specific-heat" itemprop="url"> <span class="breadcrumb" itemprop="title">Specific Heat</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="529508" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/kai-12"><img alt="" class="" src="https://profilepictures.socratic.org/sPfa5LVCTsaJw9GVGTcy_tumblr_n6phblVObs1smkr46o1_1280.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/kai-12"> kai </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-01-02T20:52:47" itemprop="dateCreated"> Jan 2, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.622 J</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to solve this problem, you need the formula:<br/> <mathjax>#q=mC_sDeltaT#</mathjax></p> <p>Assuming water is in its liquid state, the <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> capacity or <mathjax>#C_s#</mathjax> would be 4.18 <mathjax>#J/(g* degrees Celsius)#</mathjax></p> <p><mathjax>#DeltaT#</mathjax> in this case would be 0.241 degrees Celsius since this represents the change in temperature.</p> <p><mathjax>#m#</mathjax> would be 0.617 grams.</p> <p>Plug in all the values and you would get 0.622 joules!<br/> Hope this helps! </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/529508" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-specific-heat-be-used-to-identify-substances"> How can specific heat be used to identify substances? 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766	a85b78a4-6ddd-11ea-b41a-ccda262736ce	https://socratic.org/questions/a-cylinder-of-argon-gas-contains-50-0-l-of-ar-at-18-4-atm-and-127-c-how-many-mol	28.0 moles	start physical_unit 3 4 mole mol qc_end physical_unit 3 4 6 7 volume qc_end physical_unit 3 4 11 12 pressure qc_end physical_unit 3 4 14 15 temperature qc_end end	[{"type":"physical unit","value":"Mole [OF] Ar gas [IN] moles"}]	[{"type":"physical unit","value":"28.0 moles"}]	[{"type":"physical unit","value":"Volume [OF] Ar gas [=] \\pu{50.0 L}"},{"type":"physical unit","value":"Pressure [OF] Ar gas [=] \\pu{18.4 atm}"},{"type":"physical unit","value":"Temperature [OF] Ar gas [=] \\pu{127 ℃}"}]	<h1 class="questionTitle" itemprop="name"> A cylinder of argon gas contains 50.0 L of #Ar# at 18.4 atm and 127 °C. How many moles of argon are in the cylinder? </h1>	null	28.0 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a>.</p> <p><mathjax>#PV=nRT#</mathjax>, where <mathjax>#n#</mathjax> is moles and <mathjax>#R#</mathjax> is the gas constant.</p> <p><strong>Known</strong><br/> <mathjax>#P="18.4 atm"#</mathjax><br/> <mathjax>#V="50.0 L"#</mathjax><br/> <mathjax>#T=127^@"C+273.15=400 K"#</mathjax><br/> <mathjax>#R="L atm K"^(-1) "mol"^(-1)#</mathjax><br/> <a href="https://en.m.wikipedia.org/wiki/Gas_constant" rel="nofollow" target="_blank">https://en.m.wikipedia.org/wiki/Gas_constant</a></p> <p><strong>Unknown</strong><br/> <mathjax>#n#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#n#</mathjax>. Substitute the known values into the equation and solve for <mathjax>#n#</mathjax>.</p> <p><mathjax>#PV=nRT#</mathjax></p> <p><mathjax>#n=(PV)/(RT)#</mathjax></p> <p><mathjax>#n=(18.4cancel"atm" * 50.0cancel"L")/(0.082057338 cancel"L" * cancel"atm" * cancel"K"^(-1) * "mol"^(-1) * 400"K")="28.0 mol Ar"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The cylinder contains <mathjax>#"28.0 mol Ar"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a>.</p> <p><mathjax>#PV=nRT#</mathjax>, where <mathjax>#n#</mathjax> is moles and <mathjax>#R#</mathjax> is the gas constant.</p> <p><strong>Known</strong><br/> <mathjax>#P="18.4 atm"#</mathjax><br/> <mathjax>#V="50.0 L"#</mathjax><br/> <mathjax>#T=127^@"C+273.15=400 K"#</mathjax><br/> <mathjax>#R="L atm K"^(-1) "mol"^(-1)#</mathjax><br/> <a href="https://en.m.wikipedia.org/wiki/Gas_constant" rel="nofollow" target="_blank">https://en.m.wikipedia.org/wiki/Gas_constant</a></p> <p><strong>Unknown</strong><br/> <mathjax>#n#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#n#</mathjax>. Substitute the known values into the equation and solve for <mathjax>#n#</mathjax>.</p> <p><mathjax>#PV=nRT#</mathjax></p> <p><mathjax>#n=(PV)/(RT)#</mathjax></p> <p><mathjax>#n=(18.4cancel"atm" * 50.0cancel"L")/(0.082057338 cancel"L" * cancel"atm" * cancel"K"^(-1) * "mol"^(-1) * 400"K")="28.0 mol Ar"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name"> A cylinder of argon gas contains 50.0 L of #Ar# at 18.4 atm and 127 °C. How many moles of argon are in the cylinder? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="228632" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-02-19T20:21:15" itemprop="dateCreated"> Feb 19, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The cylinder contains <mathjax>#"28.0 mol Ar"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a>.</p> <p><mathjax>#PV=nRT#</mathjax>, where <mathjax>#n#</mathjax> is moles and <mathjax>#R#</mathjax> is the gas constant.</p> <p><strong>Known</strong><br/> <mathjax>#P="18.4 atm"#</mathjax><br/> <mathjax>#V="50.0 L"#</mathjax><br/> <mathjax>#T=127^@"C+273.15=400 K"#</mathjax><br/> <mathjax>#R="L atm K"^(-1) "mol"^(-1)#</mathjax><br/> <a href="https://en.m.wikipedia.org/wiki/Gas_constant" rel="nofollow" target="_blank">https://en.m.wikipedia.org/wiki/Gas_constant</a></p> <p><strong>Unknown</strong><br/> <mathjax>#n#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#n#</mathjax>. Substitute the known values into the equation and solve for <mathjax>#n#</mathjax>.</p> <p><mathjax>#PV=nRT#</mathjax></p> <p><mathjax>#n=(PV)/(RT)#</mathjax></p> <p><mathjax>#n=(18.4cancel"atm" * 50.0cancel"L")/(0.082057338 cancel"L" * cancel"atm" * cancel"K"^(-1) * "mol"^(-1) * 400"K")="28.0 mol Ar"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/228632" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 13138 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A cylinder of argon gas contains 50.0 L of #Ar# at 18.4 atm and 127 °C. How many moles of argon are in the cylinder?	null
767	a95e37dd-6ddd-11ea-b2cc-ccda262736ce	https://socratic.org/questions/how-many-moles-of-co-2-are-present-in-0-200-l-of-a-0-400-m-solution-of-coi-2	0.08 moles	start physical_unit 4 4 mole mol qc_end physical_unit 14 14 8 9 volume qc_end physical_unit 16 16 12 13 molarity qc_end end	[{"type":"physical unit","value":"Mole [OF] Co^2+ [IN] moles"}]	[{"type":"physical unit","value":"0.08 moles"}]	[{"type":"physical unit","value":"Volume [OF] CoI2 solution [=] \\pu{0.200 L}"},{"type":"physical unit","value":"Molarity [OF] CoI2 solution [=] \\pu{0.400 M}"}]	<h1 class="questionTitle" itemprop="name">How many moles of #Co^(2+)# are present in 0.200 L of a 0.400 M solution of #CoI_2#?</h1>	null	0.08 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Concentration = number of moles of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> / volume of solution.</p> <p>Or: </p> <p><mathjax>#c=n/v#</mathjax></p> <p><mathjax>#:.n= cxxv#</mathjax></p> <p><mathjax>#n= 0.4 xx0.2= 0.08#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.08 moles.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Concentration = number of moles of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> / volume of solution.</p> <p>Or: </p> <p><mathjax>#c=n/v#</mathjax></p> <p><mathjax>#:.n= cxxv#</mathjax></p> <p><mathjax>#n= 0.4 xx0.2= 0.08#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles of #Co^(2+)# are present in 0.200 L of a 0.400 M solution of #CoI_2#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="182398" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/michael-2"><img alt="" class="" src="https://lh3.googleusercontent.com/-gCv6FQRhls0/AAAAAAAAAAI/AAAAAAAAAAA/AAnnY7oOJS05Ylqn3KuDSW0LfnbOk7FezQ/mo/photo.jpg?sz=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/michael-2"> Michael </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-03T01:48:05" itemprop="dateCreated"> Nov 3, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.08 moles.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Concentration = number of moles of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> / volume of solution.</p> <p>Or: </p> <p><mathjax>#c=n/v#</mathjax></p> <p><mathjax>#:.n= cxxv#</mathjax></p> <p><mathjax>#n= 0.4 xx0.2= 0.08#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/182398" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? 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</a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-3-hydrogen-peroxide"> What is the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 14021 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many moles of #Co^(2+)# are present in 0.200 L of a 0.400 M solution of #CoI_2#?	null
768	a9adca5a-6ddd-11ea-9573-ccda262736ce	https://socratic.org/questions/the-volume-of-a-sample-of-a-gas-at-273-kelvin-and-is-100-0-l-if-the-volume-is-de	136.50 K	start physical_unit 7 7 temperature k qc_end physical_unit 7 7 9 10 temperature qc_end physical_unit 7 7 13 14 volume qc_end physical_unit 7 7 21 22 volume qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Temperature2 [OF] gas sample [IN] K"}]	[{"type":"physical unit","value":"136.50 K"}]	[{"type":"physical unit","value":"Temperature1 [OF] gas sample [=] \\pu{273 Kelvin}"},{"type":"physical unit","value":"Volume1 [OF] gas sample [=] \\pu{100.0 L}"},{"type":"physical unit","value":"Volume2 [OF] gas sample [=] \\pu{50.0 L}"},{"type":"other","value":"Constant pressure."}]	<h1 class="questionTitle" itemprop="name">The volume of a sample of a gas at 273 Kelvin and is 100.0 L. If the volume is decreased to 50.0 L at constant pressure, what will be the new temperature of the gas? </h1>	null	136.50 K	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is an example of <a href="http://socratic.org/chemistry/the-behavior-of-gases/charles-law">Charles' law</a>, which states that the volume of a given amount of a gas is directly proportional to its Kelvin temperature. The formula to use for this law is <mathjax>#V_1/T_1=V_2/T_2#</mathjax>.</p> <p><strong>Given</strong><br/> <mathjax>#V_1="100.0 L"#</mathjax><br/> <mathjax>#T_1="273 K"#</mathjax><br/> <mathjax>#V_2="50.0 L"#</mathjax></p> <p><strong>Unknown</strong><br/> <mathjax>#T_2#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the formula to isolate <mathjax>#T_2#</mathjax>. Substitute the given values into the formula and solve.</p> <p><mathjax>#V_1/T_1=V_2/T_2#</mathjax></p> <p><mathjax>#T_2=(T_1V_2)/V_1#</mathjax></p> <p><mathjax>#T_2=(273"K" xx 50.0cancel"L")/(100.0cancel"L")#</mathjax></p> <p><mathjax>#T_2="136.5 K"="137 K"#</mathjax> rounded to three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a></p> <p>The proportionality between volume and temperature can be easily seen in this problem. As the volume decreased by half, the Kelvin temperature decreased by half.</p> <p>A very good tutorial on the <a href="http://socratic.org/chemistry/the-behavior-of-gases/gas-laws">gas laws</a> can be found at <a href="http://chemistry.bd.psu.edu/jircitano/gases.html" rel="nofollow" target="_blank">http://chemistry.bd.psu.edu/jircitano/gases.html</a>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The new temperature will be <mathjax>#color(blue)("137 K")#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is an example of <a href="http://socratic.org/chemistry/the-behavior-of-gases/charles-law">Charles' law</a>, which states that the volume of a given amount of a gas is directly proportional to its Kelvin temperature. The formula to use for this law is <mathjax>#V_1/T_1=V_2/T_2#</mathjax>.</p> <p><strong>Given</strong><br/> <mathjax>#V_1="100.0 L"#</mathjax><br/> <mathjax>#T_1="273 K"#</mathjax><br/> <mathjax>#V_2="50.0 L"#</mathjax></p> <p><strong>Unknown</strong><br/> <mathjax>#T_2#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the formula to isolate <mathjax>#T_2#</mathjax>. Substitute the given values into the formula and solve.</p> <p><mathjax>#V_1/T_1=V_2/T_2#</mathjax></p> <p><mathjax>#T_2=(T_1V_2)/V_1#</mathjax></p> <p><mathjax>#T_2=(273"K" xx 50.0cancel"L")/(100.0cancel"L")#</mathjax></p> <p><mathjax>#T_2="136.5 K"="137 K"#</mathjax> rounded to three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a></p> <p>The proportionality between volume and temperature can be easily seen in this problem. As the volume decreased by half, the Kelvin temperature decreased by half.</p> <p>A very good tutorial on the <a href="http://socratic.org/chemistry/the-behavior-of-gases/gas-laws">gas laws</a> can be found at <a href="http://chemistry.bd.psu.edu/jircitano/gases.html" rel="nofollow" target="_blank">http://chemistry.bd.psu.edu/jircitano/gases.html</a>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">The volume of a sample of a gas at 273 Kelvin and is 100.0 L. If the volume is decreased to 50.0 L at constant pressure, what will be the new temperature of the gas? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/charles-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Charles' Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="234804" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-04T06:54:57" itemprop="dateCreated"> Mar 4, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The new temperature will be <mathjax>#color(blue)("137 K")#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is an example of <a href="http://socratic.org/chemistry/the-behavior-of-gases/charles-law">Charles' law</a>, which states that the volume of a given amount of a gas is directly proportional to its Kelvin temperature. The formula to use for this law is <mathjax>#V_1/T_1=V_2/T_2#</mathjax>.</p> <p><strong>Given</strong><br/> <mathjax>#V_1="100.0 L"#</mathjax><br/> <mathjax>#T_1="273 K"#</mathjax><br/> <mathjax>#V_2="50.0 L"#</mathjax></p> <p><strong>Unknown</strong><br/> <mathjax>#T_2#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the formula to isolate <mathjax>#T_2#</mathjax>. Substitute the given values into the formula and solve.</p> <p><mathjax>#V_1/T_1=V_2/T_2#</mathjax></p> <p><mathjax>#T_2=(T_1V_2)/V_1#</mathjax></p> <p><mathjax>#T_2=(273"K" xx 50.0cancel"L")/(100.0cancel"L")#</mathjax></p> <p><mathjax>#T_2="136.5 K"="137 K"#</mathjax> rounded to three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a></p> <p>The proportionality between volume and temperature can be easily seen in this problem. As the volume decreased by half, the Kelvin temperature decreased by half.</p> <p>A very good tutorial on the <a href="http://socratic.org/chemistry/the-behavior-of-gases/gas-laws">gas laws</a> can be found at <a href="http://chemistry.bd.psu.edu/jircitano/gases.html" rel="nofollow" target="_blank">http://chemistry.bd.psu.edu/jircitano/gases.html</a>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/234804" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-must-charles-law-be-in-kelvins"> Why must Charles' law be in kelvin? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-charles-law-formula"> What is Charles' law formula? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/oxygen-gas-is-at-a-temperature-of-40-c-when-it-occupies-a-volume-of-2-3-liters-t"> Oxygen gas is at a temperature of 40°C when it occupies a volume of 2.3 liters. 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What will be volume of oxygen when the... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/charles-law"> See all questions in Charles' Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3726 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	The volume of a sample of a gas at 273 Kelvin and is 100.0 L. If the volume is decreased to 50.0 L at constant pressure, what will be the new temperature of the gas?	null
769	a930f78c-6ddd-11ea-ae71-ccda262736ce	https://socratic.org/questions/what-is-the-mass-in-grams-of-4-6-10-21-molecules-of-carbon-tetrabromide	2.53 grams	start physical_unit 12 13 mass g qc_end end	[{"type":"physical unit","value":"Mass [OF] carbon tetrabromide [IN] grams"}]	[{"type":"physical unit","value":"2.53 grams"}]	[{"type":"physical unit","value":"Number [OF] carbon tetrabromide molecules [=] \\pu{4.6 × 10^21}"}]	<h1 class="questionTitle" itemprop="name">What is the mass in grams of #4.6*10^21# molecules of carbon tetrabromide?</h1>	null	2.53 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#6.022xx10^23#</mathjax> molecules, i.e. a mole, of <mathjax>#CBr_4#</mathjax>, have a mass of <mathjax>#331.61g#</mathjax>.</p> <p>So the mass of your given number of molecules is:</p> <p><mathjax>#(4.6xx10^21"molecules")/(6.022xx10^23"molecules""mol"^-1)xx331.61gmol^-1=?*g#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#(4.6xx10^21" molecules")/(6.022xx10^23" molecules mol"^-1)xx331.61gmol^-1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax> <mathjax>#g#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#6.022xx10^23#</mathjax> molecules, i.e. a mole, of <mathjax>#CBr_4#</mathjax>, have a mass of <mathjax>#331.61g#</mathjax>.</p> <p>So the mass of your given number of molecules is:</p> <p><mathjax>#(4.6xx10^21"molecules")/(6.022xx10^23"molecules""mol"^-1)xx331.61gmol^-1=?*g#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the mass in grams of #4.610^21# molecules of carbon tetrabromide?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="254624" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-04-15T19:16:57" itemprop="dateCreated"> Apr 15, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#(4.6xx10^21" molecules")/(6.022xx10^23" molecules mol"^-1)xx331.61gmol^-1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax> <mathjax>#g#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#6.022xx10^23#</mathjax> molecules, i.e. a mole, of <mathjax>#CBr_4#</mathjax>, have a mass of <mathjax>#331.61g#</mathjax>.</p> <p>So the mass of your given number of molecules is:</p> <p><mathjax>#(4.6xx10^21"molecules")/(6.022xx10^23"molecules""mol"^-1)xx331.61gmol^-1=?g#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/254624" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? 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</a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 10910 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the mass in grams of #4.6*10^21# molecules of carbon tetrabromide?	null
770	a842ca99-6ddd-11ea-8536-ccda262736ce	https://socratic.org/questions/how-many-grams-of-salt-must-be-added-to-300g-of-water-to-increase-its-boiling-po	86 grams	start physical_unit 4 4 mass g qc_end physical_unit 12 12 9 10 mass qc_end physical_unit 12 12 19 20 boiling_point_temperature qc_end end	[{"type":"physical unit","value":"Mass [OF] salt [IN] grams"}]	[{"type":"physical unit","value":"86 grams"}]	[{"type":"physical unit","value":"Mass [OF] water [=] \\pu{300 g}"},{"type":"physical unit","value":"Increased boiling point [OF] water [=] \\pu{5 ℃}"}]	<h1 class="questionTitle" itemprop="name">How many grams of salt must be added to 300g of water to increase its boiling point by 5°C?</h1>	null	86 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The formula for boiling point elevation is</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(ΔT_"b" = iK_"b"m)\|)#</mathjax></p> </blockquote> </blockquote> <p>where</p> <ul> <li><mathjax>#i#</mathjax> is the van't Hoff factor</li> <li><mathjax>#ΔT_"b"#</mathjax> is the boiling point elevation</li> <li><mathjax>#K_"b"#</mathjax> is the boiling point elevation constant</li> <li><mathjax>#m#</mathjax> is the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molality">molality</a> of the solution</li> </ul> <p>We can solve the equation for the molality of the solution.</p> <p><mathjax>#m = (ΔT_"b")/(iK_"b")#</mathjax></p> <blockquote></blockquote> <p>In this problem,</p> <p><mathjax>#ΔT_"b" = "5 °C"#</mathjax><br/> <mathjax>#i = 2#</mathjax>, because 1 mol of <mathjax>#"NaCl"#</mathjax> gives 2 mol of particles in solution.<br/> <mathjax>#K_"b" = "0.512 °C·kg·mol"^"-1"#</mathjax></p> <p>∴ <mathjax>#m = (5 color(red)(cancel(color(black)("°C"))))/(2 × 0.512 color(red)(cancel(color(black)("°C")))·"kg·mol"^"-1") = "4.88 mol·kg"^"-1"#</mathjax></p> <blockquote></blockquote> <p>Next, we calculate the moles of <mathjax>#"NaCl"#</mathjax>.</p> <p>The formula for molality is</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(\|color(white)(a/a) "Molality" = "moles of solute"/"kilograms of solvent"color(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>∴ <mathjax>#"Moles of NaCl" = 0.300 color(red)(cancel(color(black)("kg"))) × "4.88 mol"·color(red)(cancel(color(black)("kg"^"-1"))) = "1.46 mol"#</mathjax></p> <blockquote></blockquote> <p>Finally, convert moles of <mathjax>#"NaCl"#</mathjax> to grams of <mathjax>#"NaCl"#</mathjax>.</p> <p><mathjax>#"Mass of NaCl" = 1.46 color(red)(cancel(color(black)("mol NaCl"))) × "58.44 g NaCl"/(1 color(red)(cancel(color(black)("mol NaCl")))) = "86 g NaCl"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>You must add 86 g of salt.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The formula for boiling point elevation is</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(ΔT_"b" = iK_"b"m)\|)#</mathjax></p> </blockquote> </blockquote> <p>where</p> <ul> <li><mathjax>#i#</mathjax> is the van't Hoff factor</li> <li><mathjax>#ΔT_"b"#</mathjax> is the boiling point elevation</li> <li><mathjax>#K_"b"#</mathjax> is the boiling point elevation constant</li> <li><mathjax>#m#</mathjax> is the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molality">molality</a> of the solution</li> </ul> <p>We can solve the equation for the molality of the solution.</p> <p><mathjax>#m = (ΔT_"b")/(iK_"b")#</mathjax></p> <blockquote></blockquote> <p>In this problem,</p> <p><mathjax>#ΔT_"b" = "5 °C"#</mathjax><br/> <mathjax>#i = 2#</mathjax>, because 1 mol of <mathjax>#"NaCl"#</mathjax> gives 2 mol of particles in solution.<br/> <mathjax>#K_"b" = "0.512 °C·kg·mol"^"-1"#</mathjax></p> <p>∴ <mathjax>#m = (5 color(red)(cancel(color(black)("°C"))))/(2 × 0.512 color(red)(cancel(color(black)("°C")))·"kg·mol"^"-1") = "4.88 mol·kg"^"-1"#</mathjax></p> <blockquote></blockquote> <p>Next, we calculate the moles of <mathjax>#"NaCl"#</mathjax>.</p> <p>The formula for molality is</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(\|color(white)(a/a) "Molality" = "moles of solute"/"kilograms of solvent"color(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>∴ <mathjax>#"Moles of NaCl" = 0.300 color(red)(cancel(color(black)("kg"))) × "4.88 mol"·color(red)(cancel(color(black)("kg"^"-1"))) = "1.46 mol"#</mathjax></p> <blockquote></blockquote> <p>Finally, convert moles of <mathjax>#"NaCl"#</mathjax> to grams of <mathjax>#"NaCl"#</mathjax>.</p> <p><mathjax>#"Mass of NaCl" = 1.46 color(red)(cancel(color(black)("mol NaCl"))) × "58.44 g NaCl"/(1 color(red)(cancel(color(black)("mol NaCl")))) = "86 g NaCl"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many grams of salt must be added to 300g of water to increase its boiling point by 5°C?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/colligative-properties" itemprop="url"> <span class="breadcrumb" itemprop="title">Colligative Properties</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="355658" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-12-22T23:04:51" itemprop="dateCreated"> Dec 22, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>You must add 86 g of salt.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The formula for boiling point elevation is</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(ΔT_"b" = iK_"b"m)\|)#</mathjax></p> </blockquote> </blockquote> <p>where</p> <ul> <li><mathjax>#i#</mathjax> is the van't Hoff factor</li> <li><mathjax>#ΔT_"b"#</mathjax> is the boiling point elevation</li> <li><mathjax>#K_"b"#</mathjax> is the boiling point elevation constant</li> <li><mathjax>#m#</mathjax> is the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molality">molality</a> of the solution</li> </ul> <p>We can solve the equation for the molality of the solution.</p> <p><mathjax>#m = (ΔT_"b")/(iK_"b")#</mathjax></p> <blockquote></blockquote> <p>In this problem,</p> <p><mathjax>#ΔT_"b" = "5 °C"#</mathjax><br/> <mathjax>#i = 2#</mathjax>, because 1 mol of <mathjax>#"NaCl"#</mathjax> gives 2 mol of particles in solution.<br/> <mathjax>#K_"b" = "0.512 °C·kg·mol"^"-1"#</mathjax></p> <p>∴ <mathjax>#m = (5 color(red)(cancel(color(black)("°C"))))/(2 × 0.512 color(red)(cancel(color(black)("°C")))·"kg·mol"^"-1") = "4.88 mol·kg"^"-1"#</mathjax></p> <blockquote></blockquote> <p>Next, we calculate the moles of <mathjax>#"NaCl"#</mathjax>.</p> <p>The formula for molality is</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(\|color(white)(a/a) "Molality" = "moles of solute"/"kilograms of solvent"color(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>∴ <mathjax>#"Moles of NaCl" = 0.300 color(red)(cancel(color(black)("kg"))) × "4.88 mol"·color(red)(cancel(color(black)("kg"^"-1"))) = "1.46 mol"#</mathjax></p> <blockquote></blockquote> <p>Finally, convert moles of <mathjax>#"NaCl"#</mathjax> to grams of <mathjax>#"NaCl"#</mathjax>.</p> <p><mathjax>#"Mass of NaCl" = 1.46 color(red)(cancel(color(black)("mol NaCl"))) × "58.44 g NaCl"/(1 color(red)(cancel(color(black)("mol NaCl")))) = "86 g NaCl"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/355658" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-colligative-properties-determined"> How are colligative properties determined? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-freezing-point-depression"> How do you calculate freezing point depression? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-freezing-point-depression-determine-purity"> How can freezing point depression 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the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many grams of salt must be added to 300g of water to increase its boiling point by 5°C?	null
771	a86ba3b4-6ddd-11ea-b360-ccda262736ce	https://socratic.org/questions/how-do-you-find-the-mass-in-grams-of-5-00-x-10-23-molecules-of-n-2	23.3 grams	start physical_unit 14 14 mass g qc_end end	[{"type":"physical unit","value":"Mass [OF] N2 [IN] grams"}]	[{"type":"physical unit","value":"23.3 grams"}]	[{"type":"physical unit","value":"Number [OF] N2 molecules [=] \\pu{5.00 × 10^23}"}]	<h1 class="questionTitle" itemprop="name">How do you find the mass, in grams, of #5.00 xx 10^23# molecules of #N_2#?</h1>	null	23.3 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>One mole of <mathjax>#"N"_2#</mathjax> contains <mathjax>#6.022xx10^23#</mathjax> molecules. The mass of one mole of <mathjax>#"N"_2#</mathjax> is <mathjax>#"28.014 g/mol"#</mathjax>.</p> <p>To determine the mol <mathjax>#"N"_2#</mathjax> molecules, divide the given number of molecules by <mathjax>#6.022xx10^23#</mathjax> molecules/mol by multiplying by the inverse. Then multiply by the molar mass of <mathjax>#"N"_2#</mathjax>.</p> <p><mathjax>#5.00xx10^23color(red)cancel(color(black)("molecules N"_2))xx(1"mol N"_2)/(6.022xx10^23color(red)cancel(color(black)("molecules N"_2)))xx(28.014"g N"_2)/(1color(red)cancel(color(black)("mol N"_2)))="23.3 g N"_2"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The mass of <mathjax>#5.00xx10^23#</mathjax> molecules of <mathjax>#"N"_2#</mathjax> is <mathjax>#"23.3 g N"_2"#</mathjax>.</p> <p>Refer to the explanation for the process.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>One mole of <mathjax>#"N"_2#</mathjax> contains <mathjax>#6.022xx10^23#</mathjax> molecules. The mass of one mole of <mathjax>#"N"_2#</mathjax> is <mathjax>#"28.014 g/mol"#</mathjax>.</p> <p>To determine the mol <mathjax>#"N"_2#</mathjax> molecules, divide the given number of molecules by <mathjax>#6.022xx10^23#</mathjax> molecules/mol by multiplying by the inverse. Then multiply by the molar mass of <mathjax>#"N"_2#</mathjax>.</p> <p><mathjax>#5.00xx10^23color(red)cancel(color(black)("molecules N"_2))xx(1"mol N"_2)/(6.022xx10^23color(red)cancel(color(black)("molecules N"_2)))xx(28.014"g N"_2)/(1color(red)cancel(color(black)("mol N"_2)))="23.3 g N"_2"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you find the mass, in grams, of #5.00 xx 10^23# molecules of #N_2#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="464933" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-17T02:50:44" itemprop="dateCreated"> Aug 17, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The mass of <mathjax>#5.00xx10^23#</mathjax> molecules of <mathjax>#"N"_2#</mathjax> is <mathjax>#"23.3 g N"_2"#</mathjax>.</p> <p>Refer to the explanation for the process.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>One mole of <mathjax>#"N"_2#</mathjax> contains <mathjax>#6.022xx10^23#</mathjax> molecules. The mass of one mole of <mathjax>#"N"_2#</mathjax> is <mathjax>#"28.014 g/mol"#</mathjax>.</p> <p>To determine the mol <mathjax>#"N"_2#</mathjax> molecules, divide the given number of molecules by <mathjax>#6.022xx10^23#</mathjax> molecules/mol by multiplying by the inverse. Then multiply by the molar mass of <mathjax>#"N"_2#</mathjax>.</p> <p><mathjax>#5.00xx10^23color(red)cancel(color(black)("molecules N"_2))xx(1"mol N"_2)/(6.022xx10^23color(red)cancel(color(black)("molecules N"_2)))xx(28.014"g N"_2)/(1color(red)cancel(color(black)("mol N"_2)))="23.3 g N"_2"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/464933" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 24111 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How do you find the mass, in grams, of #5.00 xx 10^23# molecules of #N_2#?	null
772	aa5c2cf1-6ddd-11ea-b346-ccda262736ce	https://socratic.org/questions/what-is-the-total-mass-in-grams-of-0-013-mole-of-i-2	3.3 grams	start physical_unit 11 11 mass g qc_end physical_unit 11 11 8 9 mole qc_end end	[{"type":"physical unit","value":"Mass [OF] I2 [IN] grams"}]	[{"type":"physical unit","value":"3.3 grams"}]	[{"type":"physical unit","value":"Mole [OF] I2 [=] \\pu{0.013 mole}"}]	<h1 class="questionTitle" itemprop="name"> What is the total mass in grams of 0.013 mole of #I_2#?</h1>	null	3.3 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The key here is the <strong>molar mass</strong> of iodine, which is listed as</p> <blockquote> <p><mathjax>#M_ ("M I"_2) = "253.81 g mol"^(-1)#</mathjax></p> </blockquote> <p>The thing to remember about the molar mass of a chemical substance is that you can use it as a <em>conversion factor</em> to go from moles to grams or vice versa. </p> <p>In other words, the molar mass allows you to figure out how many <em>grams</em> are needed in order to have <strong>exactly</strong> <mathjax>#1#</mathjax> <strong>mole</strong> of a given substance. </p> <p>In this case, you need <mathjax>#"253.81 g"#</mathjax> of iodine to have exactly <mathjax>#1#</mathjax> <strong>mole</strong> of iodine. </p> <p>This means that <mathjax>#0.013#</mathjax> <strong>moles</strong> of iodine would be equivalent to</p> <blockquote> <p><mathjax>#0.013 color(red)(cancel(color(black)("moles I"_2))) * overbrace("253.81 g"/(1color(red)(cancel(color(black)("mole I"_2)))))^(color(blue)("the molar mass of I"_2)) = color(darkgreen)(ul(color(black)("3.3 g")))#</mathjax></p> </blockquote> <p>The answer is rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the number of moles of iodine. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"3.3 g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The key here is the <strong>molar mass</strong> of iodine, which is listed as</p> <blockquote> <p><mathjax>#M_ ("M I"_2) = "253.81 g mol"^(-1)#</mathjax></p> </blockquote> <p>The thing to remember about the molar mass of a chemical substance is that you can use it as a <em>conversion factor</em> to go from moles to grams or vice versa. </p> <p>In other words, the molar mass allows you to figure out how many <em>grams</em> are needed in order to have <strong>exactly</strong> <mathjax>#1#</mathjax> <strong>mole</strong> of a given substance. </p> <p>In this case, you need <mathjax>#"253.81 g"#</mathjax> of iodine to have exactly <mathjax>#1#</mathjax> <strong>mole</strong> of iodine. </p> <p>This means that <mathjax>#0.013#</mathjax> <strong>moles</strong> of iodine would be equivalent to</p> <blockquote> <p><mathjax>#0.013 color(red)(cancel(color(black)("moles I"_2))) * overbrace("253.81 g"/(1color(red)(cancel(color(black)("mole I"_2)))))^(color(blue)("the molar mass of I"_2)) = color(darkgreen)(ul(color(black)("3.3 g")))#</mathjax></p> </blockquote> <p>The answer is rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the number of moles of iodine. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name"> What is the total mass in grams of 0.013 mole of #I_2#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="391424" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-15T00:16:42" itemprop="dateCreated"> Mar 15, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"3.3 g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The key here is the <strong>molar mass</strong> of iodine, which is listed as</p> <blockquote> <p><mathjax>#M_ ("M I"_2) = "253.81 g mol"^(-1)#</mathjax></p> </blockquote> <p>The thing to remember about the molar mass of a chemical substance is that you can use it as a <em>conversion factor</em> to go from moles to grams or vice versa. </p> <p>In other words, the molar mass allows you to figure out how many <em>grams</em> are needed in order to have <strong>exactly</strong> <mathjax>#1#</mathjax> <strong>mole</strong> of a given substance. </p> <p>In this case, you need <mathjax>#"253.81 g"#</mathjax> of iodine to have exactly <mathjax>#1#</mathjax> <strong>mole</strong> of iodine. </p> <p>This means that <mathjax>#0.013#</mathjax> <strong>moles</strong> of iodine would be equivalent to</p> <blockquote> <p><mathjax>#0.013 color(red)(cancel(color(black)("moles I"_2))) * overbrace("253.81 g"/(1color(red)(cancel(color(black)("mole I"_2)))))^(color(blue)("the molar mass of I"_2)) = color(darkgreen)(ul(color(black)("3.3 g")))#</mathjax></p> </blockquote> <p>The answer is rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the number of moles of iodine. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/391424" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li 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773	ac0ba22a-6ddd-11ea-b44a-ccda262736ce	https://socratic.org/questions/58feb8117c014918a98ec65a	1:3:2	start physical_unit 6 8 molar_ratio none qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Molar ratios [OF] reactants and products"}]	[{"type":"physical unit","value":"1:3:2"}]	[{"type":"other","value":"Dinitrogen reduction by dihydrogen."}]	<h1 class="questionTitle" itemprop="name">What are the molar ratios of reactants and products in dinitrogen reduction by dihydrogen?</h1>	null	1:3:2	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And thus the molar ratio follows the given <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> of the reaction:</p> <p><mathjax>#N_2 + 3H_2(g) rarr 2NH_3(g)#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, <mathjax>#"dinitrogen : dihydrogen : ammonia = 1 : 3 : 2".#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And thus the molar ratio follows the given <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> of the reaction:</p> <p><mathjax>#N_2 + 3H_2(g) rarr 2NH_3(g)#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What are the molar ratios of reactants and products in dinitrogen reduction by dihydrogen?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/mole-ratios" itemprop="url"> <span class="breadcrumb" itemprop="title">Mole Ratios</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="415688" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-01T09:18:18" itemprop="dateCreated"> May 1, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, <mathjax>#"dinitrogen : dihydrogen : ammonia = 1 : 3 : 2".#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And thus the molar ratio follows the given <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> of the reaction:</p> <p><mathjax>#N_2 + 3H_2(g) rarr 2NH_3(g)#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/415688" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related 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<h5>Impact of this question</h5> <div class="impactStatements"> 1428 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What are the molar ratios of reactants and products in dinitrogen reduction by dihydrogen?	null
774	ab27da83-6ddd-11ea-95df-ccda262736ce	https://socratic.org/questions/how-do-you-balance-ch3oh-o2-co2-h2o	2 CH3OH + 3 O2 -> 2 CO2 + 4 H2O	start chemical_equation qc_end chemical_equation 4 10 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the equation"}]	[{"type":"chemical equation","value":"2 CH3OH + 3 O2 -> 2 CO2 + 4 H2O"}]	[{"type":"chemical equation","value":"CH3OH + O2 -> CO2 + H2O"}]	<h1 class="questionTitle" itemprop="name">How do you balance CH3OH + O2 -- CO2 + H2O? </h1>	null	2 CH3OH + 3 O2 -> 2 CO2 + 4 H2O	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>You follow a systematic procedure to balance the equation.</p> <p>Start with the unbalanced equation:</p> <p><mathjax>#"CH"_3"OH" + "O"_2 → "CO"_2 + "H"_2"O"#</mathjax></p> <p>A method that often works is first to balance everything other than <mathjax>#"O"#</mathjax> and <mathjax>#"H"#</mathjax>, then balance <mathjax>#"O"#</mathjax>, and finally balance <mathjax>#"H"#</mathjax>.</p> <p>Another useful procedure is to start with what looks like the most complicated formula.</p> <p>The most complicated formula looks like <mathjax>#"CH"_3"OH"#</mathjax>. We put a 1 in front of it to remind ourselves that the number is now fixed.</p> <blockquote></blockquote> <p>We start with</p> <p><mathjax>#color(red)(1)"CH"_3"OH" + "O"_2 → "CO"_2 + "H"_2"O"#</mathjax></p> <blockquote></blockquote> <p><strong>Balance <mathjax>#"C"#</mathjax>:</strong></p> <p>We have <mathjax>#"1 C"#</mathjax> on the left, so we need <mathjax>#"1 C"#</mathjax> on the right. We put a 1 in front of the <mathjax>#"CO"_2#</mathjax>.</p> <p><mathjax>#color(red)(1)"CH"_3"OH" + "O"_2 → color(blue)(1)"CO"_2 + "H"_2"O"#</mathjax></p> <blockquote></blockquote> <p><strong>Balance <mathjax>#"H"#</mathjax>:</strong></p> <p>We can't balance <mathjax>#"O"#</mathjax> because we have two oxygen-containing molecules without coefficients. ∴ Let's balance <mathjax>#"H"#</mathjax> instead.</p> <p>We have <mathjax>#"4 H"#</mathjax> on the left, so we need <mathjax>#"4 H"#</mathjax> on the right. There are already <mathjax>#"2 H"#</mathjax> atoms on the right. We must put a 2 in front of the <mathjax>#"H"_2"O"#</mathjax>.</p> <p><mathjax>#color(red)(1)"CH"_3"OH" + "O"_2 → color(blue)(1)"CO"_2 + color(orange)(2)"H"_2"O"#</mathjax></p> <blockquote></blockquote> <p><strong>Balance <mathjax>#"O"#</mathjax></strong>:</p> <p>We have fixed <mathjax>#"4 O"#</mathjax> on the right and <mathjax>#"1 O"#</mathjax> on the left. We need <mathjax>#"3 O"#</mathjax> on the left.</p> <p><strong>Uh, oh! Fractions!</strong></p> <p>We start over, this time doubling all the coefficients.</p> <p><mathjax>#color(red)(2)"CH"_3"OH" + "O"_2 → color(blue)(2)"CO"_2 + color(orange)(4)"H"_2"O"#</mathjax></p> <p>Now we can balance <mathjax>#"O"#</mathjax> by putting a 3 in front of <mathjax>#"O"_2#</mathjax></p> <p><mathjax>#color(red)(2)"CH"_3"OH" + color(purple)(3)"O"_2 → color(blue)(2)"CO"_2 + color(orange)(4)"H"_2"O"#</mathjax></p> <p>Every formula now has a coefficient. We should have a balanced equation.</p> <blockquote></blockquote> <p>Let's check.</p> <p><mathjax>#"Atom" color(white)(m)"lhs"color(white)(m)"rhs"#</mathjax><br/> <mathjax>#color(white)(m)"C"color(white)(mml)2color(white)(mm)2#</mathjax><br/> <mathjax>#color(white)(m)"H"color(white)(mml)8color(white)(mm)8#</mathjax><br/> <mathjax>#color(white)(m)"O"color(white)(mml)8color(white)(mm)8#</mathjax></p> <blockquote></blockquote> <p>All atoms balance. The balanced equation is</p> <p><mathjax>#2"CH"_3"OH" + 3"O"_2 → 2"CO"_2 + 4"H"_2"O"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The balanced equation is <mathjax>#2"CH"_3"OH" + 3"O"_2 → 2"CO"_2 + 4"H"_2"O"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>You follow a systematic procedure to balance the equation.</p> <p>Start with the unbalanced equation:</p> <p><mathjax>#"CH"_3"OH" + "O"_2 → "CO"_2 + "H"_2"O"#</mathjax></p> <p>A method that often works is first to balance everything other than <mathjax>#"O"#</mathjax> and <mathjax>#"H"#</mathjax>, then balance <mathjax>#"O"#</mathjax>, and finally balance <mathjax>#"H"#</mathjax>.</p> <p>Another useful procedure is to start with what looks like the most complicated formula.</p> <p>The most complicated formula looks like <mathjax>#"CH"_3"OH"#</mathjax>. We put a 1 in front of it to remind ourselves that the number is now fixed.</p> <blockquote></blockquote> <p>We start with</p> <p><mathjax>#color(red)(1)"CH"_3"OH" + "O"_2 → "CO"_2 + "H"_2"O"#</mathjax></p> <blockquote></blockquote> <p><strong>Balance <mathjax>#"C"#</mathjax>:</strong></p> <p>We have <mathjax>#"1 C"#</mathjax> on the left, so we need <mathjax>#"1 C"#</mathjax> on the right. We put a 1 in front of the <mathjax>#"CO"_2#</mathjax>.</p> <p><mathjax>#color(red)(1)"CH"_3"OH" + "O"_2 → color(blue)(1)"CO"_2 + "H"_2"O"#</mathjax></p> <blockquote></blockquote> <p><strong>Balance <mathjax>#"H"#</mathjax>:</strong></p> <p>We can't balance <mathjax>#"O"#</mathjax> because we have two oxygen-containing molecules without coefficients. ∴ Let's balance <mathjax>#"H"#</mathjax> instead.</p> <p>We have <mathjax>#"4 H"#</mathjax> on the left, so we need <mathjax>#"4 H"#</mathjax> on the right. There are already <mathjax>#"2 H"#</mathjax> atoms on the right. We must put a 2 in front of the <mathjax>#"H"_2"O"#</mathjax>.</p> <p><mathjax>#color(red)(1)"CH"_3"OH" + "O"_2 → color(blue)(1)"CO"_2 + color(orange)(2)"H"_2"O"#</mathjax></p> <blockquote></blockquote> <p><strong>Balance <mathjax>#"O"#</mathjax></strong>:</p> <p>We have fixed <mathjax>#"4 O"#</mathjax> on the right and <mathjax>#"1 O"#</mathjax> on the left. We need <mathjax>#"3 O"#</mathjax> on the left.</p> <p><strong>Uh, oh! Fractions!</strong></p> <p>We start over, this time doubling all the coefficients.</p> <p><mathjax>#color(red)(2)"CH"_3"OH" + "O"_2 → color(blue)(2)"CO"_2 + color(orange)(4)"H"_2"O"#</mathjax></p> <p>Now we can balance <mathjax>#"O"#</mathjax> by putting a 3 in front of <mathjax>#"O"_2#</mathjax></p> <p><mathjax>#color(red)(2)"CH"_3"OH" + color(purple)(3)"O"_2 → color(blue)(2)"CO"_2 + color(orange)(4)"H"_2"O"#</mathjax></p> <p>Every formula now has a coefficient. We should have a balanced equation.</p> <blockquote></blockquote> <p>Let's check.</p> <p><mathjax>#"Atom" color(white)(m)"lhs"color(white)(m)"rhs"#</mathjax><br/> <mathjax>#color(white)(m)"C"color(white)(mml)2color(white)(mm)2#</mathjax><br/> <mathjax>#color(white)(m)"H"color(white)(mml)8color(white)(mm)8#</mathjax><br/> <mathjax>#color(white)(m)"O"color(white)(mml)8color(white)(mm)8#</mathjax></p> <blockquote></blockquote> <p>All atoms balance. The balanced equation is</p> <p><mathjax>#2"CH"_3"OH" + 3"O"_2 → 2"CO"_2 + 4"H"_2"O"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you balance CH3OH + O2 -- CO2 + H2O? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="328902" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> <a class="secondContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a>·<a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-10-30T23:17:43" itemprop="dateCreated"> Oct 30, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The balanced equation is <mathjax>#2"CH"_3"OH" + 3"O"_2 → 2"CO"_2 + 4"H"_2"O"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>You follow a systematic procedure to balance the equation.</p> <p>Start with the unbalanced equation:</p> <p><mathjax>#"CH"_3"OH" + "O"_2 → "CO"_2 + "H"_2"O"#</mathjax></p> <p>A method that often works is first to balance everything other than <mathjax>#"O"#</mathjax> and <mathjax>#"H"#</mathjax>, then balance <mathjax>#"O"#</mathjax>, and finally balance <mathjax>#"H"#</mathjax>.</p> <p>Another useful procedure is to start with what looks like the most complicated formula.</p> <p>The most complicated formula looks like <mathjax>#"CH"_3"OH"#</mathjax>. We put a 1 in front of it to remind ourselves that the number is now fixed.</p> <blockquote></blockquote> <p>We start with</p> <p><mathjax>#color(red)(1)"CH"_3"OH" + "O"_2 → "CO"_2 + "H"_2"O"#</mathjax></p> <blockquote></blockquote> <p><strong>Balance <mathjax>#"C"#</mathjax>:</strong></p> <p>We have <mathjax>#"1 C"#</mathjax> on the left, so we need <mathjax>#"1 C"#</mathjax> on the right. We put a 1 in front of the <mathjax>#"CO"_2#</mathjax>.</p> <p><mathjax>#color(red)(1)"CH"_3"OH" + "O"_2 → color(blue)(1)"CO"_2 + "H"_2"O"#</mathjax></p> <blockquote></blockquote> <p><strong>Balance <mathjax>#"H"#</mathjax>:</strong></p> <p>We can't balance <mathjax>#"O"#</mathjax> because we have two oxygen-containing molecules without coefficients. ∴ Let's balance <mathjax>#"H"#</mathjax> instead.</p> <p>We have <mathjax>#"4 H"#</mathjax> on the left, so we need <mathjax>#"4 H"#</mathjax> on the right. There are already <mathjax>#"2 H"#</mathjax> atoms on the right. We must put a 2 in front of the <mathjax>#"H"_2"O"#</mathjax>.</p> <p><mathjax>#color(red)(1)"CH"_3"OH" + "O"_2 → color(blue)(1)"CO"_2 + color(orange)(2)"H"_2"O"#</mathjax></p> <blockquote></blockquote> <p><strong>Balance <mathjax>#"O"#</mathjax></strong>:</p> <p>We have fixed <mathjax>#"4 O"#</mathjax> on the right and <mathjax>#"1 O"#</mathjax> on the left. We need <mathjax>#"3 O"#</mathjax> on the left.</p> <p><strong>Uh, oh! Fractions!</strong></p> <p>We start over, this time doubling all the coefficients.</p> <p><mathjax>#color(red)(2)"CH"_3"OH" + "O"_2 → color(blue)(2)"CO"_2 + color(orange)(4)"H"_2"O"#</mathjax></p> <p>Now we can balance <mathjax>#"O"#</mathjax> by putting a 3 in front of <mathjax>#"O"_2#</mathjax></p> <p><mathjax>#color(red)(2)"CH"_3"OH" + color(purple)(3)"O"_2 → color(blue)(2)"CO"_2 + color(orange)(4)"H"_2"O"#</mathjax></p> <p>Every formula now has a coefficient. We should have a balanced equation.</p> <blockquote></blockquote> <p>Let's check.</p> <p><mathjax>#"Atom" color(white)(m)"lhs"color(white)(m)"rhs"#</mathjax><br/> <mathjax>#color(white)(m)"C"color(white)(mml)2color(white)(mm)2#</mathjax><br/> <mathjax>#color(white)(m)"H"color(white)(mml)8color(white)(mm)8#</mathjax><br/> <mathjax>#color(white)(m)"O"color(white)(mml)8color(white)(mm)8#</mathjax></p> <blockquote></blockquote> <p>All atoms balance. The balanced equation is</p> <p><mathjax>#2"CH"_3"OH" + 3"O"_2 → 2"CO"_2 + 4"H"_2"O"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/328902" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="329106" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/aditya-9"><img alt="" class="" src="https://profilepictures.socratic.org/JI8xltWvSDeHqZTzxqDb_25.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/aditya-9"> Aditya Banerjee. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-10-31T12:06:25" itemprop="dateCreated"> Oct 31, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2CH_3OH#</mathjax> <mathjax>#+ 3O_2#</mathjax> <mathjax>#rarr 2CO_2 +4H_2O#</mathjax> . </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><ul> <li>First try to balance atoms other than O and H. So first balance the C atoms.<br/> <mathjax>#2CH_3OH#</mathjax> <mathjax>#+ O_2#</mathjax> <mathjax>#rarr 2CO_2 +H_2O#</mathjax> . </li> <li>Then balance the H atoms, as no. of H atoms is less than no. of O atoms.<br/> <mathjax>#2CH_3OH#</mathjax> <mathjax>#+ O_2#</mathjax> <mathjax>#rarr 2CO_2 +4H_2O#</mathjax> .</li> <li>Now, balance the remaining O atoms.<br/> <mathjax>#2CH_3OH#</mathjax> <mathjax>#+3 O_2#</mathjax> <mathjax>#rarr 2CO_2 +4H_2O#</mathjax> .</li> </ul> <p>Now, check that the no. of all individual atoms in L.H.S and R.H.S are equal.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/329106" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------> H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -> Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? 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775	aa85b364-6ddd-11ea-964b-ccda262736ce	https://socratic.org/questions/how-many-milliliters-of-a-25-m-v-naoh-solution-would-contain-75-g-of-naoh	3.00 × 10^2 milliliters	start physical_unit 7 8 volume ml qc_end physical_unit 7 7 11 12 mass qc_end end	[{"type":"physical unit","value":"Volume [OF] NaOH solution [IN] milliliters"}]	[{"type":"physical unit","value":"3.00 × 10^2 milliliters"}]	[{"type":"physical unit","value":"m/v [OF] NaOH in solution [=] \\pu{25%}"},{"type":"physical unit","value":"Mass [OF] NaOH [=] \\pu{75 g}"}]	<h1 class="questionTitle" itemprop="name">How many milliliters of a 25% (m/v) #NaOH# solution would contain 75 g of #NaOH#?</h1>	null	3.00 × 10^2 milliliters	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>yuor)s ;penapht haw eesd an,keel life you ch asum as asjustuld o cuyoOr <br/> A solution's <em>mass by volume <a href="https://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration</a></em>, <mathjax>#"% m/v"#</mathjax>, essentially tells you how many <strong>grams of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a></strong> you get <strong>per</strong> <mathjax>#"100 mL"#</mathjax> <strong>of solution</strong>. </p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a)"% m/v" = "mass of solute"/"100 mL solution" xx 100color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>In your case, a sodium hydroxide solution is said to have a <mathjax>#"25% m/v"#</mathjax> concentration, which means that every <mathjax>#"100 mL"#</mathjax> of this solution will contain <mathjax>#"25 g"#</mathjax> of sodium hydroxide, <mathjax>#"NaOH"#</mathjax>.</p> <p>Therefore, the volume of solution that will contain <mathjax>#"75 g"#</mathjax> of sodium hydroxide will be </p> <blockquote> <p><mathjax>#75 color(red)(cancel(color(black)("g NaOH"))) * overbrace("100 mL solution"/(25color(red)(cancel(color(black)("g NaOH")))))^(color(purple)("= 25% m/v")) = color(green)(\|bar(ul(color(white)(a/a)3.0 * 10^2"mL"color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer is rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>. </p> <p> <iframe src="https://www.youtube.com/embed/dl6G_p6gsJc?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p> <p>Or</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#3.0 * 10^2"mL"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>yuor)s ;penapht haw eesd an,keel life you ch asum as asjustuld o cuyoOr <br/> A solution's <em>mass by volume <a href="https://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration</a></em>, <mathjax>#"% m/v"#</mathjax>, essentially tells you how many <strong>grams of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a></strong> you get <strong>per</strong> <mathjax>#"100 mL"#</mathjax> <strong>of solution</strong>. </p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a)"% m/v" = "mass of solute"/"100 mL solution" xx 100color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>In your case, a sodium hydroxide solution is said to have a <mathjax>#"25% m/v"#</mathjax> concentration, which means that every <mathjax>#"100 mL"#</mathjax> of this solution will contain <mathjax>#"25 g"#</mathjax> of sodium hydroxide, <mathjax>#"NaOH"#</mathjax>.</p> <p>Therefore, the volume of solution that will contain <mathjax>#"75 g"#</mathjax> of sodium hydroxide will be </p> <blockquote> <p><mathjax>#75 color(red)(cancel(color(black)("g NaOH"))) * overbrace("100 mL solution"/(25color(red)(cancel(color(black)("g NaOH")))))^(color(purple)("= 25% m/v")) = color(green)(\|bar(ul(color(white)(a/a)3.0 * 10^2"mL"color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer is rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>. </p> <p> <iframe src="https://www.youtube.com/embed/dl6G_p6gsJc?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p> <p>Or</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many milliliters of a 25% (m/v) #NaOH# solution would contain 75 g of #NaOH#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/percent-concentration" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Concentration</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="258871" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-04-26T10:11:22" itemprop="dateCreated"> Apr 26, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#3.0 * 10^2"mL"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>yuor)s ;penapht haw eesd an,keel life you ch asum as asjustuld o cuyoOr <br/> A solution's <em>mass by volume <a href="https://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration</a></em>, <mathjax>#"% m/v"#</mathjax>, essentially tells you how many <strong>grams of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a></strong> you get <strong>per</strong> <mathjax>#"100 mL"#</mathjax> <strong>of solution</strong>. </p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a)"% m/v" = "mass of solute"/"100 mL solution" xx 100color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>In your case, a sodium hydroxide solution is said to have a <mathjax>#"25% m/v"#</mathjax> concentration, which means that every <mathjax>#"100 mL"#</mathjax> of this solution will contain <mathjax>#"25 g"#</mathjax> of sodium hydroxide, <mathjax>#"NaOH"#</mathjax>.</p> <p>Therefore, the volume of solution that will contain <mathjax>#"75 g"#</mathjax> of sodium hydroxide will be </p> <blockquote> <p><mathjax>#75 color(red)(cancel(color(black)("g NaOH"))) * overbrace("100 mL solution"/(25color(red)(cancel(color(black)("g NaOH")))))^(color(purple)("= 25% m/v")) = color(green)(\|bar(ul(color(white)(a/a)3.0 * 10^2"mL"color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer is rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>. </p> <p> <iframe src="https://www.youtube.com/embed/dl6G_p6gsJc?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p> <p>Or</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/258871" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="278528" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-17T20:14:59" itemprop="dateCreated"> Jun 17, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#3.0 * 10^2"mL"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>A solution's <em>mass by volume <a href="https://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration</a></em>, <mathjax>#"% m/v"#</mathjax>, tells you how many grams of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> you get <strong>per</strong> <mathjax>#"100 mL"#</mathjax> <strong>of solution</strong>. </p> <p>In your case, a <mathjax>#"25% m/v"#</mathjax> solution of sodium hydroxide, <mathjax>#"NaOH"#</mathjax>, will contain <mathjax>#"25 g"#</mathjax> of sodium hydroxide <strong>for every</strong> <mathjax>#"100 mL"#</mathjax> <strong>of solution</strong>. </p> <p>This means that you can use the solution's percent concentration as a <em>conversion factor</em> to help you determine how many milliliters would contain that many grams of sodium hydroxide. </p> <blockquote> <p><mathjax>#75 color(red)(cancel(color(black)("g NaOH"))) * overbrace("100 mL solution"/(25color(red)(cancel(color(black)("g NaOH")))))^(color(blue)("= 25% m/v")) = color(green)(\|bar(ul(color(white)(a/a)color(black)(3.0 * 10^2"mL")color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer is rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p> <p> <iframe src="https://www.youtube.com/embed/BcVRF4j1p4c?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/278528" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-concentration-of-water-in-solution-be-decreased"> How can the concentration of water in solution be decreased? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-concentration-of-a-solution-be-increased"> How can the concentration of a solution be increased? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-concentration-of-a-solution-in-ppm"> How do you find the 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question</h5> <div class="impactStatements"> 36567 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many milliliters of a 25% (m/v) #NaOH# solution would contain 75 g of #NaOH#?	null
776	acb2be5a-6ddd-11ea-a5c2-ccda262736ce	https://socratic.org/questions/what-is-the-ph-of-a-0-0453-m-hcl-solution	1.34	start physical_unit 8 9 ph none qc_end physical_unit 8 9 6 7 molarity qc_end end	[{"type":"physical unit","value":"pH [OF] HCl solution"}]	[{"type":"physical unit","value":"1.34"}]	[{"type":"physical unit","value":"Molarity [OF] HCl solution [=] \\pu{0.0453 M}"}]	<h1 class="questionTitle" itemprop="name">What is the pH of a 0.0453 M #HCl# solution?</h1>	null	1.34	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Hydrochloric acid is a stong acid, it fully ionizes to produce the hydronium ion and the chloride ion.</p> <p><mathjax>#HCl -> H^+ + Cl^-#</mathjax> </p> <p>So, <mathjax>#[H^+] = [HCl] #</mathjax> as a result of the complete ionization.</p> <p><mathjax># [H^+] = 0.0453 \ M#</mathjax></p> <p><mathjax>#pH = - log (0.0453)#</mathjax></p> <p><mathjax>#pH = 1.344#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#pH = 1.344#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Hydrochloric acid is a stong acid, it fully ionizes to produce the hydronium ion and the chloride ion.</p> <p><mathjax>#HCl -> H^+ + Cl^-#</mathjax> </p> <p>So, <mathjax>#[H^+] = [HCl] #</mathjax> as a result of the complete ionization.</p> <p><mathjax># [H^+] = 0.0453 \ M#</mathjax></p> <p><mathjax>#pH = - log (0.0453)#</mathjax></p> <p><mathjax>#pH = 1.344#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the pH of a 0.0453 M #HCl# solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="288162" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/sam-54"><img alt="" class="" src="https://profilepictures.socratic.org/3bkyAGe2RVWw1lx2h1A5_Avatar%201.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/sam-54"> Sam </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-14T18:29:44" itemprop="dateCreated"> Jul 14, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#pH = 1.344#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Hydrochloric acid is a stong acid, it fully ionizes to produce the hydronium ion and the chloride ion.</p> <p><mathjax>#HCl -> H^+ + Cl^-#</mathjax> </p> <p>So, <mathjax>#[H^+] = [HCl] #</mathjax> as a result of the complete ionization.</p> <p><mathjax># [H^+] = 0.0453 \ M#</mathjax></p> <p><mathjax>#pH = - log (0.0453)#</mathjax></p> <p><mathjax>#pH = 1.344#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/288162" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-resonance-structures-affect-acidity"> How do resonance structures affect acidity? 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777	a9e1faac-6ddd-11ea-a79f-ccda262736ce	https://socratic.org/questions/a-solution-is-made-by-dissolving-29-g-of-sodium-chloride-to-a-final-volume-of-20	14.36%	start physical_unit 1 1 mass/volume_percent none qc_end physical_unit 9 10 6 7 mass qc_end physical_unit 1 1 16 17 volume qc_end end	[{"type":"physical unit","value":"mass/volume % [OF] solute in solution"}]	[{"type":"physical unit","value":"14.36%"}]	[{"type":"physical unit","value":"Mass [OF] sodium chloride [=] \\pu{29 g}"},{"type":"physical unit","value":"Volume [OF] solution [=] \\pu{202 mL}"}]	<h1 class="questionTitle" itemprop="name">A solution is made by dissolving 29 g of sodium chloride to a final volume of 202 mL solution. What is the mass/volume % of the solute?</h1>	null	14.36%	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>A solution's <strong>mass by volume <a href="https://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration</a></strong>, <mathjax>#"% m/v"#</mathjax>, is simply the number of grams of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> present in <mathjax>#"100 mL"#</mathjax> of solution. </p> <p>This means that in order to find your solution's mass by volume percent concentration, you need to figure out how many grams of solute, which in your case is sodium chloride, <mathjax>#"NaCl"#</mathjax>, you get in <mathjax>#"100 mL"#</mathjax> of solution. </p> <p>At that point, you can tag along a <mathjax>#%#</mathjax> sign to the value to get the answer. </p> <p>Notice that the problem tells you that your solution contains <mathjax>#"29 g"#</mathjax> of solute in <mathjax>#"202 mL"#</mathjax> of solution. This <strong>know composition</strong> of the solution can be used to figure out how many grams of sodium chloride you'd get in a little under half that volume</p> <blockquote> <p><mathjax>#100 color(red)(cancel(color(black)("mL solution"))) * "29 g NaCl"/(202color(red)(cancel(color(black)("mL solution")))) = "14.356 g NaCl"#</mathjax></p> </blockquote> <p>Since this is how many grams of solute you get in <mathjax>#"100 mL"#</mathjax> of solution, you can add a <mathjax>#%#</mathjax> sign to that value and say that the mass by volume percent concentration is equal to</p> <blockquote> <p><mathjax>#"% m/v NaCl" = color(green)(\|bar(ul(color(white)(a/a)color(black)(14.3%)color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>I'll leave the answer rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, but keep in mind that you have two sig figs for the mass of sodium chloride. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"14.3% NaCl"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>A solution's <strong>mass by volume <a href="https://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration</a></strong>, <mathjax>#"% m/v"#</mathjax>, is simply the number of grams of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> present in <mathjax>#"100 mL"#</mathjax> of solution. </p> <p>This means that in order to find your solution's mass by volume percent concentration, you need to figure out how many grams of solute, which in your case is sodium chloride, <mathjax>#"NaCl"#</mathjax>, you get in <mathjax>#"100 mL"#</mathjax> of solution. </p> <p>At that point, you can tag along a <mathjax>#%#</mathjax> sign to the value to get the answer. </p> <p>Notice that the problem tells you that your solution contains <mathjax>#"29 g"#</mathjax> of solute in <mathjax>#"202 mL"#</mathjax> of solution. This <strong>know composition</strong> of the solution can be used to figure out how many grams of sodium chloride you'd get in a little under half that volume</p> <blockquote> <p><mathjax>#100 color(red)(cancel(color(black)("mL solution"))) * "29 g NaCl"/(202color(red)(cancel(color(black)("mL solution")))) = "14.356 g NaCl"#</mathjax></p> </blockquote> <p>Since this is how many grams of solute you get in <mathjax>#"100 mL"#</mathjax> of solution, you can add a <mathjax>#%#</mathjax> sign to that value and say that the mass by volume percent concentration is equal to</p> <blockquote> <p><mathjax>#"% m/v NaCl" = color(green)(\|bar(ul(color(white)(a/a)color(black)(14.3%)color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>I'll leave the answer rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, but keep in mind that you have two sig figs for the mass of sodium chloride. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A solution is made by dissolving 29 g of sodium chloride to a final volume of 202 mL solution. What is the mass/volume % of the solute?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/percent-concentration" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Concentration</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="293101" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-29T00:04:28" itemprop="dateCreated"> Jul 29, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"14.3% NaCl"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>A solution's <strong>mass by volume <a href="https://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration</a></strong>, <mathjax>#"% m/v"#</mathjax>, is simply the number of grams of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> present in <mathjax>#"100 mL"#</mathjax> of solution. </p> <p>This means that in order to find your solution's mass by volume percent concentration, you need to figure out how many grams of solute, which in your case is sodium chloride, <mathjax>#"NaCl"#</mathjax>, you get in <mathjax>#"100 mL"#</mathjax> of solution. </p> <p>At that point, you can tag along a <mathjax>#%#</mathjax> sign to the value to get the answer. </p> <p>Notice that the problem tells you that your solution contains <mathjax>#"29 g"#</mathjax> of solute in <mathjax>#"202 mL"#</mathjax> of solution. This <strong>know composition</strong> of the solution can be used to figure out how many grams of sodium chloride you'd get in a little under half that volume</p> <blockquote> <p><mathjax>#100 color(red)(cancel(color(black)("mL solution"))) * "29 g NaCl"/(202color(red)(cancel(color(black)("mL solution")))) = "14.356 g NaCl"#</mathjax></p> </blockquote> <p>Since this is how many grams of solute you get in <mathjax>#"100 mL"#</mathjax> of solution, you can add a <mathjax>#%#</mathjax> sign to that value and say that the mass by volume percent concentration is equal to</p> <blockquote> <p><mathjax>#"% m/v NaCl" = color(green)(\|bar(ul(color(white)(a/a)color(black)(14.3%)color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>I'll leave the answer rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, but keep in mind that you have two sig figs for the mass of sodium chloride. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/293101" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-concentration-of-water-in-solution-be-decreased"> How can the concentration of water in solution be decreased? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-concentration-of-a-solution-be-increased"> How can the concentration of a solution be increased? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-concentration-of-a-solution-in-ppm"> How do you find the concentration of a solution in ppm? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-make-a-10-percent-solution"> How do you make a 10 percent solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-make-a-2-percent-solution"> How do you make a 2 percent solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-weight-per-volume-method-to-calculate-concentration"> What is the weight per volume method to calculate concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-percent-concentration-of-kcl-would-be-isotonic"> What percent concentration of KCl would be isotonic? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-of-sodium-chloride-in-normal-saline"> What is the percent concentration of sodium chloride in normal saline? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-of-a-6m-solution-of-nacl"> What is the percent concentration of a 6m solution of NaCl? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-formula"> What is the percent concentration formula? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/percent-concentration"> See all questions in Percent Concentration </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 5287 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A solution is made by dissolving 29 g of sodium chloride to a final volume of 202 mL solution. What is the mass/volume % of the solute?	null
778	abf314d3-6ddd-11ea-84b0-ccda262736ce	https://socratic.org/questions/599cdc6a11ef6b6c9ddceef4	27.46 g	start physical_unit 3 3 mass g qc_end physical_unit 10 10 8 9 mass qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Mass [OF] CO2 [IN] g"}]	[{"type":"physical unit","value":"27.46 g"}]	[{"type":"physical unit","value":"Mass [OF] CO [=] \\pu{17.48 g}"},{"type":"other","value":"Excess O2."}]	<h1 class="questionTitle" itemprop="name">What mass of #"CO"_2"# will be produced when #"17.48 g CO"# reacts with excess #"O"_2"#?</h1>	null	27.46 g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Balanced Equation</p> <p><mathjax>#"2CO(g) + O"_2("g")#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"2CO"_2("g")"#</mathjax></p> <p>First, determine mol <mathjax>#"CO"#</mathjax> in <mathjax>#"17.48 g"#</mathjax> by dividing its given mass by its molar mass <mathjax>#("28.010 g/mol")#</mathjax>. Since molar mass is a fraction, <strong>g/mol</strong> , you can multiply the given mass by the inverse of the molar mass, <strong>mol/g</strong> .</p> <p>Next multiply the moles <mathjax>#"CO"#</mathjax> by <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio between <mathjax>#"CO"#</mathjax> and <mathjax>#"CO"_2"#</mathjax> from the balanced equation with <mathjax>#"CO"_2#</mathjax> in the numerator. </p> <p>Finally, multiply mol <mathjax>#"CO"_2"#</mathjax> by its molar mass <mathjax>#("44.009 g/mol")#</mathjax>.</p> <p><mathjax>#17.48color(red)cancel(color(black)("g CO"))xx(1color(red)cancel(color(black)("mol CO")))/(28.010color(red)cancel(color(black)("g CO")))xx(2color(red)cancel(color(black)("mol CO"_2)))/(2color(red)cancel(color(black)("mol CO")))xx(44.009"g CO"_2)/(1color(red)cancel(color(black)("mol CO"_2)))="27.46 g CO"_2"#</mathjax> (rounded to four significant figures)</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Under the conditions given, <mathjax>#"27.46 g CO"_2#</mathjax> will be produced.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Balanced Equation</p> <p><mathjax>#"2CO(g) + O"_2("g")#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"2CO"_2("g")"#</mathjax></p> <p>First, determine mol <mathjax>#"CO"#</mathjax> in <mathjax>#"17.48 g"#</mathjax> by dividing its given mass by its molar mass <mathjax>#("28.010 g/mol")#</mathjax>. Since molar mass is a fraction, <strong>g/mol</strong> , you can multiply the given mass by the inverse of the molar mass, <strong>mol/g</strong> .</p> <p>Next multiply the moles <mathjax>#"CO"#</mathjax> by <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio between <mathjax>#"CO"#</mathjax> and <mathjax>#"CO"_2"#</mathjax> from the balanced equation with <mathjax>#"CO"_2#</mathjax> in the numerator. </p> <p>Finally, multiply mol <mathjax>#"CO"_2"#</mathjax> by its molar mass <mathjax>#("44.009 g/mol")#</mathjax>.</p> <p><mathjax>#17.48color(red)cancel(color(black)("g CO"))xx(1color(red)cancel(color(black)("mol CO")))/(28.010color(red)cancel(color(black)("g CO")))xx(2color(red)cancel(color(black)("mol CO"_2)))/(2color(red)cancel(color(black)("mol CO")))xx(44.009"g CO"_2)/(1color(red)cancel(color(black)("mol CO"_2)))="27.46 g CO"_2"#</mathjax> (rounded to four significant figures)</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What mass of #"CO"_2"# will be produced when #"17.48 g CO"# reacts with excess #"O"_2"#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="467126" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-23T03:51:34" itemprop="dateCreated"> Aug 23, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Under the conditions given, <mathjax>#"27.46 g CO"_2#</mathjax> will be produced.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Balanced Equation</p> <p><mathjax>#"2CO(g) + O"_2("g")#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"2CO"_2("g")"#</mathjax></p> <p>First, determine mol <mathjax>#"CO"#</mathjax> in <mathjax>#"17.48 g"#</mathjax> by dividing its given mass by its molar mass <mathjax>#("28.010 g/mol")#</mathjax>. Since molar mass is a fraction, <strong>g/mol</strong> , you can multiply the given mass by the inverse of the molar mass, <strong>mol/g</strong> .</p> <p>Next multiply the moles <mathjax>#"CO"#</mathjax> by <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio between <mathjax>#"CO"#</mathjax> and <mathjax>#"CO"_2"#</mathjax> from the balanced equation with <mathjax>#"CO"_2#</mathjax> in the numerator. </p> <p>Finally, multiply mol <mathjax>#"CO"_2"#</mathjax> by its molar mass <mathjax>#("44.009 g/mol")#</mathjax>.</p> <p><mathjax>#17.48color(red)cancel(color(black)("g CO"))xx(1color(red)cancel(color(black)("mol CO")))/(28.010color(red)cancel(color(black)("g CO")))xx(2color(red)cancel(color(black)("mol CO"_2)))/(2color(red)cancel(color(black)("mol CO")))xx(44.009"g CO"_2)/(1color(red)cancel(color(black)("mol CO"_2)))="27.46 g CO"_2"#</mathjax> (rounded to four significant figures)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/467126" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What is stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ab82402bf342f48d93ac6"> Question #93ac6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-we-study-stoichiometry"> Why do we study stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-naoh-is-produced-from-1-20-x-102-grams-of-na2o-na2o-h2o-2-naoh"> How many grams of NaOH is produced from #1.20 x 10^2# grams of #Na_2O#? #Na_2O + H_2O -> 2NaOH# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-na2o-are-required-to-produce-1-60-x-102-grams-of-naoh-na2o-h2o"> How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? 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779	aae62f38-6ddd-11ea-a053-ccda262736ce	https://socratic.org/questions/na3po4-dissolves-in-water-to-produce-an-electrolyte-solution-what-is-the-osmolar	8.00 × 10^(-3) osmol/L	start physical_unit 19 20 osmolarity osmol/l qc_end physical_unit 19 20 15 18 molarity qc_end substance 3 3 qc_end end	[{"type":"physical unit","value":"Osmolarity [OF] Na3PO4 solution [IN] osmol/L"}]	[{"type":"physical unit","value":"8.00 × 10^(-3) osmol/L"}]	[{"type":"physical unit","value":"Molarity [OF] Na3PO4 solution [=] \\pu{2.0 × 10^(-3) M}"},{"type":"substance name","value":"Water"}]	<h1 class="questionTitle" itemprop="name">#"Na"_3"PO"_4# dissolves in water to produce an electrolyte solution. What is the Osmolarity of a #2.0 * 10^(-3)"M Na"_3"PO"_4# solution? Thank you! </h1>	null	8.00 × 10^(-3) osmol/L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The thing to keep in mind about <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/osmolarity">osmolarity</a></strong> is that it takes into account the <em>number of moles of particles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a></em> that are <strong>produced</strong> in a solution when a given number of moles of solute are <strong>dissolved</strong> to make said solution. </p> <p>In other words, you can think about osmolarity as being a <em>multiple</em> of <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></strong></p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)("osmolarity" = i xx "molarity")))#</mathjax></p> </blockquote> <p>Here <mathjax>#i#</mathjax> represents the <strong>van't Hoff factor</strong>, which tells you the ratio that exists between the number of moles of particles of solute produced in solution and the number of moles of solute dissolved in solution. </p> <p>In your case, trisodium phosphate is a <strong>strong electrolyte</strong>, which implies that it dissociates completely in aqueous solution to produce sodium cations and phosphate anions</p> <blockquote> <p><mathjax>#"Na"_ 3"PO"_ (4(aq)) -> 3"Na"_ ((aq))^(+) + "PO"_( 4(aq))^(-)#</mathjax></p> </blockquote> <p>Now, notice that <strong>every mole</strong> of trisodium phosphate that dissociates in solution produces a total of</p> <blockquote> <p><mathjax>#"3 moles Na"^(+) + "1 mole PO"_4^(-) = "4 moles ions"#</mathjax></p> </blockquote> <p>The number of moles of particles of solute produced in solution are actually called <strong>osmoles</strong>. </p> <p>As a result, the van't Hoff factor will be equal to </p> <blockquote> <p><mathjax>#i = "4 moles ions produced (osmoles)"/("1 mole Na"_3"PO"_4color(white)(.)"dissolved") = 4#</mathjax></p> </blockquote> <p>Since you know that</p> <blockquote> <p><mathjax>#["Na"_3"PO"_4] = 2.0 * 10^(-3)"M"#</mathjax></p> </blockquote> <p>you can say that the solution will have an osmolarity equal to </p> <blockquote> <p><mathjax>#color(darkgreen)(ul(color(black)("osmolarity" = 4 xx 2.0 * 10^(-3)"M" = 8.0 * 10^(-3)color(white)(.)"osmol L"^(-1))))#</mathjax></p> </blockquote> <p>It's important to keep in mind that osmolarity is expressed in <em>osmoles per liter</em> because you have</p> <blockquote> <p><mathjax>#(2.0 * 10^(-3)color(red)(cancel(color(black)("moles Na"_3"PO"_4))))/"1 L solution" * "4 osmoles"/(1color(red)(cancel(color(black)("mole Na"_3"PO"_4)))) = 8.0 * 10^(-3)color(white)(.)"osmol L"^(-1)#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#8.0 * 10^(-3)"osmol L"^(-1)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The thing to keep in mind about <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/osmolarity">osmolarity</a></strong> is that it takes into account the <em>number of moles of particles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a></em> that are <strong>produced</strong> in a solution when a given number of moles of solute are <strong>dissolved</strong> to make said solution. </p> <p>In other words, you can think about osmolarity as being a <em>multiple</em> of <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></strong></p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)("osmolarity" = i xx "molarity")))#</mathjax></p> </blockquote> <p>Here <mathjax>#i#</mathjax> represents the <strong>van't Hoff factor</strong>, which tells you the ratio that exists between the number of moles of particles of solute produced in solution and the number of moles of solute dissolved in solution. </p> <p>In your case, trisodium phosphate is a <strong>strong electrolyte</strong>, which implies that it dissociates completely in aqueous solution to produce sodium cations and phosphate anions</p> <blockquote> <p><mathjax>#"Na"_ 3"PO"_ (4(aq)) -> 3"Na"_ ((aq))^(+) + "PO"_( 4(aq))^(-)#</mathjax></p> </blockquote> <p>Now, notice that <strong>every mole</strong> of trisodium phosphate that dissociates in solution produces a total of</p> <blockquote> <p><mathjax>#"3 moles Na"^(+) + "1 mole PO"_4^(-) = "4 moles ions"#</mathjax></p> </blockquote> <p>The number of moles of particles of solute produced in solution are actually called <strong>osmoles</strong>. </p> <p>As a result, the van't Hoff factor will be equal to </p> <blockquote> <p><mathjax>#i = "4 moles ions produced (osmoles)"/("1 mole Na"_3"PO"_4color(white)(.)"dissolved") = 4#</mathjax></p> </blockquote> <p>Since you know that</p> <blockquote> <p><mathjax>#["Na"_3"PO"_4] = 2.0 * 10^(-3)"M"#</mathjax></p> </blockquote> <p>you can say that the solution will have an osmolarity equal to </p> <blockquote> <p><mathjax>#color(darkgreen)(ul(color(black)("osmolarity" = 4 xx 2.0 * 10^(-3)"M" = 8.0 * 10^(-3)color(white)(.)"osmol L"^(-1))))#</mathjax></p> </blockquote> <p>It's important to keep in mind that osmolarity is expressed in <em>osmoles per liter</em> because you have</p> <blockquote> <p><mathjax>#(2.0 * 10^(-3)color(red)(cancel(color(black)("moles Na"_3"PO"_4))))/"1 L solution" * "4 osmoles"/(1color(red)(cancel(color(black)("mole Na"_3"PO"_4)))) = 8.0 * 10^(-3)color(white)(.)"osmol L"^(-1)#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">#"Na"_3"PO"_4# dissolves in water to produce an electrolyte solution. What is the Osmolarity of a #2.0 * 10^(-3)"M Na"_3"PO"_4# solution? Thank you! </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/osmolarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Osmolarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="392444" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-16T23:55:46" itemprop="dateCreated"> Mar 16, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#8.0 * 10^(-3)"osmol L"^(-1)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The thing to keep in mind about <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/osmolarity">osmolarity</a></strong> is that it takes into account the <em>number of moles of particles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a></em> that are <strong>produced</strong> in a solution when a given number of moles of solute are <strong>dissolved</strong> to make said solution. </p> <p>In other words, you can think about osmolarity as being a <em>multiple</em> of <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></strong></p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)("osmolarity" = i xx "molarity")))#</mathjax></p> </blockquote> <p>Here <mathjax>#i#</mathjax> represents the <strong>van't Hoff factor</strong>, which tells you the ratio that exists between the number of moles of particles of solute produced in solution and the number of moles of solute dissolved in solution. </p> <p>In your case, trisodium phosphate is a <strong>strong electrolyte</strong>, which implies that it dissociates completely in aqueous solution to produce sodium cations and phosphate anions</p> <blockquote> <p><mathjax>#"Na"_ 3"PO"_ (4(aq)) -> 3"Na"_ ((aq))^(+) + "PO"_( 4(aq))^(-)#</mathjax></p> </blockquote> <p>Now, notice that <strong>every mole</strong> of trisodium phosphate that dissociates in solution produces a total of</p> <blockquote> <p><mathjax>#"3 moles Na"^(+) + "1 mole PO"_4^(-) = "4 moles ions"#</mathjax></p> </blockquote> <p>The number of moles of particles of solute produced in solution are actually called <strong>osmoles</strong>. </p> <p>As a result, the van't Hoff factor will be equal to </p> <blockquote> <p><mathjax>#i = "4 moles ions produced (osmoles)"/("1 mole Na"_3"PO"_4color(white)(.)"dissolved") = 4#</mathjax></p> </blockquote> <p>Since you know that</p> <blockquote> <p><mathjax>#["Na"_3"PO"_4] = 2.0 * 10^(-3)"M"#</mathjax></p> </blockquote> <p>you can say that the solution will have an osmolarity equal to </p> <blockquote> <p><mathjax>#color(darkgreen)(ul(color(black)("osmolarity" = 4 xx 2.0 * 10^(-3)"M" = 8.0 * 10^(-3)color(white)(.)"osmol L"^(-1))))#</mathjax></p> </blockquote> <p>It's important to keep in mind that osmolarity is expressed in <em>osmoles per liter</em> because you have</p> <blockquote> <p><mathjax>#(2.0 * 10^(-3)color(red)(cancel(color(black)("moles Na"_3"PO"_4))))/"1 L solution" * "4 osmoles"/(1color(red)(cancel(color(black)("mole Na"_3"PO"_4)))) = 8.0 * 10^(-3)color(white)(.)"osmol L"^(-1)#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/392444" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-osmolarity-of-a-solution"> How do you calculate osmolarity of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-osmolarity-of-the-blood-maintain-homeostasis"> How does osmolarity of the blood maintain homeostasis? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-calculate-osmolarity-from-molarity"> How do you calculate osmolarity from molarity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-osmolarity"> What is osmolarity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-dehydration-affect-osmolarity"> How does dehydration affect osmolarity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-osmolarity-affect-blood-pressure"> How does osmolarity affect blood pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-osmolarity-affect-cells"> How does osmolarity affect cells? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/do-relative-osmolarities-relate-to-water-movement"> Do relative osmolarities relate to water movement? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-osmolarity-affect-osmosis"> How does osmolarity affect osmosis? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-water-affect-osmolarity"> How does water affect osmolarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/osmolarity"> See all questions in Osmolarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 19247 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	#"Na"_3"PO"_4# dissolves in water to produce an electrolyte solution. What is the Osmolarity of a #2.0 * 10^(-3)"M Na"_3"PO"_4# solution? Thank you!	null
780	a9f9e546-6ddd-11ea-9ea5-ccda262736ce	https://socratic.org/questions/how-many-moles-are-in-4-81-10-14-molecules-of-nh-3	7.99 × 10^(-10) moles	start physical_unit 10 10 mole mol qc_end end	[{"type":"physical unit","value":"Mole [OF] NH3 [IN] moles"}]	[{"type":"physical unit","value":"7.99 × 10^(-10) moles"}]	[{"type":"physical unit","value":"Number [OF] NH3 molecules [=] \\pu{4.81 × 10^14}"}]	<h1 class="questionTitle" itemprop="name">How many moles are in #4.81 * 10^14# molecules of #NH_3#?</h1>	null	7.99 × 10^(-10) moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="http://socratic.org/chemistry/the-mole-concept/the-mole">The mole</a> is simply a number (like a dozen, or 10, or 100); admittedly it's a very large number. If I have Avogadro's number (<mathjax>#N_A#</mathjax>) or ammonia molecules then I have Avogadro's number of nitrogen atoms, and <mathjax>#3xxN_A#</mathjax> of hydrogen atoms. Are you with me? So all you have to do is divide the given quantity by Avogadro's number as set out in the intro. Can you tell me the mass of this quantity of ammonia? </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>There are <mathjax>#(4.81xx10^14)/(6.022xx10^23*mol^-1)#</mathjax> ammonia molecules.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="http://socratic.org/chemistry/the-mole-concept/the-mole">The mole</a> is simply a number (like a dozen, or 10, or 100); admittedly it's a very large number. If I have Avogadro's number (<mathjax>#N_A#</mathjax>) or ammonia molecules then I have Avogadro's number of nitrogen atoms, and <mathjax>#3xxN_A#</mathjax> of hydrogen atoms. Are you with me? So all you have to do is divide the given quantity by Avogadro's number as set out in the intro. Can you tell me the mass of this quantity of ammonia? </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles are in #4.81 * 10^14# molecules of #NH_3#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="193964" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-28T14:05:13" itemprop="dateCreated"> Nov 28, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>There are <mathjax>#(4.81xx10^14)/(6.022xx10^23*mol^-1)#</mathjax> ammonia molecules.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="http://socratic.org/chemistry/the-mole-concept/the-mole">The mole</a> is simply a number (like a dozen, or 10, or 100); admittedly it's a very large number. If I have Avogadro's number (<mathjax>#N_A#</mathjax>) or ammonia molecules then I have Avogadro's number of nitrogen atoms, and <mathjax>#3xxN_A#</mathjax> of hydrogen atoms. Are you with me? So all you have to do is divide the given quantity by Avogadro's number as set out in the intro. Can you tell me the mass of this quantity of ammonia? </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/193964" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 5944 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many moles are in #4.81 * 10^14# molecules of #NH_3#?	null
781	a8c69250-6ddd-11ea-af83-ccda262736ce	https://socratic.org/questions/how-many-liters-would-14-0-grams-of-chlorine-gas-occupy-at-300-0-k-and-1-51-atm	3.22 liters	start physical_unit 7 8 volume l qc_end physical_unit 7 8 11 12 temperature qc_end physical_unit 7 8 14 15 pressure qc_end physical_unit 7 8 4 5 mass qc_end end	[{"type":"physical unit","value":"Volume [OF] chlorine gas [IN] liters"}]	[{"type":"physical unit","value":"3.22 liters"}]	[{"type":"physical unit","value":"Temperture [OF] chlorine gas [=] \\pu{300.0 K}"},{"type":"physical unit","value":"Pressure [OF] chlorine gas [=] \\pu{1.51 atm}"},{"type":"physical unit","value":"Mass [OF] chlorine gas [=] \\pu{14.0 grams}"}]	<h1 class="questionTitle" itemprop="name">How many liters would 14.0 grams of chlorine gas occupy at 300.0 K and 1.51 atm? </h1>	null	3.22 liters	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The first thing to do here is use the molar mass of chlorine gas to determine how many <em>moles</em> of chlorine gas you have in that sample. </p> <blockquote> <p><mathjax>#14.0color(red)(cancel(color(black)("g"))) * "1 mole Cl"_2/(70.906color(red)(cancel(color(black)("g")))) = "0.1974 moles Cl"_2#</mathjax></p> </blockquote> <p>Now that you know how many moles of gas you're dealing with, and the conditions for pressure andtemperature at which the gas is kept, you can use the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> equation to solve for the volume of the sample.</p> <blockquote> <p><mathjax>#color(blue)(PV = nRT)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#P#</mathjax> - the pressure of the sample<br/> <mathjax>#V#</mathjax> - the volume it occupies<br/> <mathjax>#n#</mathjax> - the number of moles of gas<br/> <mathjax>#R#</mathjax> - the <em>universal gas constant</em>, usually given as <mathjax>#0.082("atm" * "L")/("mol" * "K")#</mathjax><br/> <mathjax>#T#</mathjax> - the temperature of the gas, expressed in Kelvin</p> <p>Rearrange this equation to solve for <mathjax>#V#</mathjax>, then plug in your values to get</p> <blockquote> <p><mathjax>#PV = nRT implies V = (nRT)/P#</mathjax></p> <p><mathjax>#V = (0.1974color(red)(cancel(color(black)("moles"))) * 0.082(color(red)(cancel(color(black)("atm"))) * "L")/(color(red)(cancel(color(black)("mol"))) * color(red)(cancel(color(black)("K")))) * 300.0color(red)(cancel(color(black)("K"))))/(1.51color(red)(cancel(color(black)("atm")))) = "3.2159 L"#</mathjax></p> </blockquote> <p>Rounded to three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the answer will be </p> <blockquote> <p><mathjax>#V = color(green)("3.22 L")#</mathjax></p> </blockquote> <p> <iframe src="https://www.youtube.com/embed/TqLlfHBFY08?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"3.22 L"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The first thing to do here is use the molar mass of chlorine gas to determine how many <em>moles</em> of chlorine gas you have in that sample. </p> <blockquote> <p><mathjax>#14.0color(red)(cancel(color(black)("g"))) * "1 mole Cl"_2/(70.906color(red)(cancel(color(black)("g")))) = "0.1974 moles Cl"_2#</mathjax></p> </blockquote> <p>Now that you know how many moles of gas you're dealing with, and the conditions for pressure andtemperature at which the gas is kept, you can use the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> equation to solve for the volume of the sample.</p> <blockquote> <p><mathjax>#color(blue)(PV = nRT)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#P#</mathjax> - the pressure of the sample<br/> <mathjax>#V#</mathjax> - the volume it occupies<br/> <mathjax>#n#</mathjax> - the number of moles of gas<br/> <mathjax>#R#</mathjax> - the <em>universal gas constant</em>, usually given as <mathjax>#0.082("atm" * "L")/("mol" * "K")#</mathjax><br/> <mathjax>#T#</mathjax> - the temperature of the gas, expressed in Kelvin</p> <p>Rearrange this equation to solve for <mathjax>#V#</mathjax>, then plug in your values to get</p> <blockquote> <p><mathjax>#PV = nRT implies V = (nRT)/P#</mathjax></p> <p><mathjax>#V = (0.1974color(red)(cancel(color(black)("moles"))) * 0.082(color(red)(cancel(color(black)("atm"))) * "L")/(color(red)(cancel(color(black)("mol"))) * color(red)(cancel(color(black)("K")))) * 300.0color(red)(cancel(color(black)("K"))))/(1.51color(red)(cancel(color(black)("atm")))) = "3.2159 L"#</mathjax></p> </blockquote> <p>Rounded to three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the answer will be </p> <blockquote> <p><mathjax>#V = color(green)("3.22 L")#</mathjax></p> </blockquote> <p> <iframe src="https://www.youtube.com/embed/TqLlfHBFY08?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many liters would 14.0 grams of chlorine gas occupy at 300.0 K and 1.51 atm? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/ideal-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Ideal Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="185103" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-07T12:33:53" itemprop="dateCreated"> Nov 7, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"3.22 L"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The first thing to do here is use the molar mass of chlorine gas to determine how many <em>moles</em> of chlorine gas you have in that sample. </p> <blockquote> <p><mathjax>#14.0color(red)(cancel(color(black)("g"))) * "1 mole Cl"_2/(70.906color(red)(cancel(color(black)("g")))) = "0.1974 moles Cl"_2#</mathjax></p> </blockquote> <p>Now that you know how many moles of gas you're dealing with, and the conditions for pressure andtemperature at which the gas is kept, you can use the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> equation to solve for the volume of the sample.</p> <blockquote> <p><mathjax>#color(blue)(PV = nRT)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#P#</mathjax> - the pressure of the sample<br/> <mathjax>#V#</mathjax> - the volume it occupies<br/> <mathjax>#n#</mathjax> - the number of moles of gas<br/> <mathjax>#R#</mathjax> - the <em>universal gas constant</em>, usually given as <mathjax>#0.082("atm" * "L")/("mol" * "K")#</mathjax><br/> <mathjax>#T#</mathjax> - the temperature of the gas, expressed in Kelvin</p> <p>Rearrange this equation to solve for <mathjax>#V#</mathjax>, then plug in your values to get</p> <blockquote> <p><mathjax>#PV = nRT implies V = (nRT)/P#</mathjax></p> <p><mathjax>#V = (0.1974color(red)(cancel(color(black)("moles"))) * 0.082(color(red)(cancel(color(black)("atm"))) * "L")/(color(red)(cancel(color(black)("mol"))) * color(red)(cancel(color(black)("K")))) * 300.0color(red)(cancel(color(black)("K"))))/(1.51color(red)(cancel(color(black)("atm")))) = "3.2159 L"#</mathjax></p> </blockquote> <p>Rounded to three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the answer will be </p> <blockquote> <p><mathjax>#V = color(green)("3.22 L")#</mathjax></p> </blockquote> <p> <iframe src="https://www.youtube.com/embed/TqLlfHBFY08?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/185103" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-ideal-gas-constant"> How do you find the ideal gas constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-solve-ideal-gas-law-problems"> How do you solve ideal gas law problems? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-know-which-ideal-gas-constant-to-use"> How do you know which ideal gas constant to use? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ideal-gas-constant-for-butane"> What is the ideal gas constant for butane? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-ideal-gas-law-in-kelvin"> Why is ideal gas law in kelvin? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ideal-gas-constant-important"> Why is the ideal gas constant important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-di-electric-constant"> What is the di-electric constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-volume-l-will-0-20-mol-hi-occupy-at-300-k-and-100-0-kpa-r-8-314-kpa-l-k-mol"> What volume (L) will 0.20 mol HI occupy at 300 K and 100.0 kPa? R = 8.314 kPa L / (K mol) =... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-molar-mass-of-a-gas"> How do you calculate the molar mass of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-should-i-use-the-ideal-gas-law-and-not-the-combined-gas-law"> When should I use the ideal gas law and not the combined gas law? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/ideal-gas-law"> See all questions in Ideal Gas Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 4089 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many liters would 14.0 grams of chlorine gas occupy at 300.0 K and 1.51 atm?	null
782	aa74eade-6ddd-11ea-86e3-ccda262736ce	https://socratic.org/questions/how-many-moles-of-hydrogen-are-needed-to-completely-react-with-two-moles-of-nitr	6.00 moles	start physical_unit 4 4 mole mol qc_end physical_unit 14 14 11 12 mole qc_end chemical_equation 19 25 qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Mole [OF] hydrogen [IN] moles"}]	[{"type":"physical unit","value":"6.00 moles"}]	[{"type":"physical unit","value":"Mole [OF] nitrogen [=] \\pu{2 moles}"},{"type":"chemical equation","value":"N2 + 3 H2 -> 2 NH3"},{"type":"other","value":"Completely react."}]	<h1 class="questionTitle" itemprop="name">How many moles of hydrogen are needed to completely react with two moles of nitrogen? According to the reaction: N2 + 3H2 -->2NH3 </h1>	null	6.00 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Take a look at the balanced chemical equation for this <a href="http://socratic.org/chemistry/chemical-reactions/synthesis-reactions">synthesis reaction</a></p> <blockquote> <p><mathjax>#"N"_text(2(g]) + color(red)(3)"H"_text(2(g]) -> 2"NH"_text(3(g])#</mathjax></p> </blockquote> <p>Notice that you have a <mathjax>#1:color(red)(3)#</mathjax> <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> between nitrogen gas and hydrogen gas. This means that, <em>regardless</em> of how many moles of nitrogen gas you have, the reaction will <strong>always</strong> consume <strong>twice as many</strong> moles of hydrogen gas. </p> <p>So, if you have <mathjax>#2#</mathjax> moles of nitrogen taking part in the reaction, you will need</p> <blockquote> <p><mathjax>#2color(red)(cancel(color(black)("moles N"_2))) * (color(red)(3)" moles H"_2)/(1color(red)(cancel(color(black)("mole N"_2)))) = "6 moles H"_2#</mathjax></p> </blockquote> <p> <iframe src="https://www.youtube.com/embed/uCoXO48QSFU?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"6 moles"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Take a look at the balanced chemical equation for this <a href="http://socratic.org/chemistry/chemical-reactions/synthesis-reactions">synthesis reaction</a></p> <blockquote> <p><mathjax>#"N"_text(2(g]) + color(red)(3)"H"_text(2(g]) -> 2"NH"_text(3(g])#</mathjax></p> </blockquote> <p>Notice that you have a <mathjax>#1:color(red)(3)#</mathjax> <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> between nitrogen gas and hydrogen gas. This means that, <em>regardless</em> of how many moles of nitrogen gas you have, the reaction will <strong>always</strong> consume <strong>twice as many</strong> moles of hydrogen gas. </p> <p>So, if you have <mathjax>#2#</mathjax> moles of nitrogen taking part in the reaction, you will need</p> <blockquote> <p><mathjax>#2color(red)(cancel(color(black)("moles N"_2))) * (color(red)(3)" moles H"_2)/(1color(red)(cancel(color(black)("mole N"_2)))) = "6 moles H"_2#</mathjax></p> </blockquote> <p> <iframe src="https://www.youtube.com/embed/uCoXO48QSFU?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles of hydrogen are needed to completely react with two moles of nitrogen? According to the reaction: N2 + 3H2 -->2NH3 </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/mole-ratios" itemprop="url"> <span class="breadcrumb" itemprop="title">Mole Ratios</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="188129" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-14T00:44:12" itemprop="dateCreated"> Nov 14, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"6 moles"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Take a look at the balanced chemical equation for this <a href="http://socratic.org/chemistry/chemical-reactions/synthesis-reactions">synthesis reaction</a></p> <blockquote> <p><mathjax>#"N"_text(2(g]) + color(red)(3)"H"_text(2(g]) -> 2"NH"_text(3(g])#</mathjax></p> </blockquote> <p>Notice that you have a <mathjax>#1:color(red)(3)#</mathjax> <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> between nitrogen gas and hydrogen gas. This means that, <em>regardless</em> of how many moles of nitrogen gas you have, the reaction will <strong>always</strong> consume <strong>twice as many</strong> moles of hydrogen gas. </p> <p>So, if you have <mathjax>#2#</mathjax> moles of nitrogen taking part in the reaction, you will need</p> <blockquote> <p><mathjax>#2color(red)(cancel(color(black)("moles N"_2))) * (color(red)(3)" moles H"_2)/(1color(red)(cancel(color(black)("mole N"_2)))) = "6 moles H"_2#</mathjax></p> </blockquote> <p> <iframe src="https://www.youtube.com/embed/uCoXO48QSFU?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/188129" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4178e02bf3469517a106e"> Question #a106e </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4178e02bf3469570e2e86"> Question #e2e86 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179102bf3469517a1072"> Question #a1072 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179402bf34694c8c5bf1"> Question #c5bf1 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179702bf3469588dc373"> Question #dc373 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179c02bf34694c8c5bf9"> Question #c5bf9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417a302bf3469517a1076"> Question #a1076 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417c702bf3469588dc377"> Question #dc377 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417d002bf346963eb984f"> Question #b984f </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417d402bf346950519ea3"> Question #19ea3 </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/mole-ratios"> See all questions in Mole Ratios </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 164264 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many moles of hydrogen are needed to completely react with two moles of nitrogen? According to the reaction: N2 + 3H2 -->2NH3	null
783	ad05a577-6ddd-11ea-88b6-ccda262736ce	https://socratic.org/questions/the-pressure-of-oxygen-gas-inside-a-container-is-5-00-atm-at-25-c-if-the-tempera	4.41 atm	start physical_unit 3 4 pressure atm qc_end physical_unit 3 4 9 10 pressure qc_end physical_unit 3 4 12 13 temperature qc_end physical_unit 3 4 19 20 temperature qc_end end	[{"type":"physical unit","value":"Pressure2 [OF] oxygen gas [IN] atm"}]	[{"type":"physical unit","value":"4.41 atm"}]	[{"type":"physical unit","value":"Pressure1 [OF] oxygen gas [=] \\pu{5.00 atm}"},{"type":"physical unit","value":"Temperature1 [OF] oxygen gas [=] \\pu{25 ℃}"},{"type":"physical unit","value":"Temperature2 [OF] oxygen gas [=] \\pu{-10 ℃}"}]	<h1 class="questionTitle" itemprop="name">The pressure of oxygen gas inside a container is 5.00 atm at 25°C. If the temperature falls to -10°C, what is the new pressure inside the container?</h1>	null	4.41 atm	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>Given</strong></p> <p>The pressure (<mathjax>#P_1#</mathjax>) of a gas at a temperature <mathjax>#T_1#</mathjax><br/> A second temperature <mathjax>#T_2#</mathjax></p> <blockquote></blockquote> <p><strong>Find</strong></p> <p>The second pressure <mathjax>#P_2#</mathjax></p> <blockquote></blockquote> <p><strong>Strategy</strong></p> <p>A problem involving two gas pressures and two temperatures must be a <a href="https://socratic.org/questions/what-is-gay-lussac-s-law">Gay-Lussac's Law</a> problem.</p> <p>Gay-Lussac's Law is</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a) P_1/T_1 = P_2/T_2color(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>In your problem, </p> <p><mathjax>#P_1 = "5.00 atm"; T_1 = "(25 + 273.15K)" color(white)(ll)= "298.15 K"#</mathjax><br/> <mathjax>#P_2 = "?"; color(white)(mmmll)T_2 = "(-10 + 273.15 K)" = "263.15 K"#</mathjax></p> <p>Insert the numbers into the Gay-Lussac's Law expression.</p> <blockquote></blockquote> <p><strong>Solution</strong></p> <p><mathjax>#P_1/T_1 = P_2/T_2#</mathjax></p> <p><mathjax>#P_2 = P_1 × T_2/T_1 = "5.00 atm" × (263.15 cancel("K"))/(298.15 cancel("K")) = "4.41 atm"#</mathjax></p> <p>The new pressure is 4.41 atm.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The new pressure is 4.41 atm.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>Given</strong></p> <p>The pressure (<mathjax>#P_1#</mathjax>) of a gas at a temperature <mathjax>#T_1#</mathjax><br/> A second temperature <mathjax>#T_2#</mathjax></p> <blockquote></blockquote> <p><strong>Find</strong></p> <p>The second pressure <mathjax>#P_2#</mathjax></p> <blockquote></blockquote> <p><strong>Strategy</strong></p> <p>A problem involving two gas pressures and two temperatures must be a <a href="https://socratic.org/questions/what-is-gay-lussac-s-law">Gay-Lussac's Law</a> problem.</p> <p>Gay-Lussac's Law is</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a) P_1/T_1 = P_2/T_2color(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>In your problem, </p> <p><mathjax>#P_1 = "5.00 atm"; T_1 = "(25 + 273.15K)" color(white)(ll)= "298.15 K"#</mathjax><br/> <mathjax>#P_2 = "?"; color(white)(mmmll)T_2 = "(-10 + 273.15 K)" = "263.15 K"#</mathjax></p> <p>Insert the numbers into the Gay-Lussac's Law expression.</p> <blockquote></blockquote> <p><strong>Solution</strong></p> <p><mathjax>#P_1/T_1 = P_2/T_2#</mathjax></p> <p><mathjax>#P_2 = P_1 × T_2/T_1 = "5.00 atm" × (263.15 cancel("K"))/(298.15 cancel("K")) = "4.41 atm"#</mathjax></p> <p>The new pressure is 4.41 atm.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">The pressure of oxygen gas inside a container is 5.00 atm at 25°C. If the temperature falls to -10°C, what is the new pressure inside the container?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/gay-lussac-s-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Gay Lussac's Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="258198" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-04-24T15:28:35" itemprop="dateCreated"> Apr 24, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The new pressure is 4.41 atm.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>Given</strong></p> <p>The pressure (<mathjax>#P_1#</mathjax>) of a gas at a temperature <mathjax>#T_1#</mathjax><br/> A second temperature <mathjax>#T_2#</mathjax></p> <blockquote></blockquote> <p><strong>Find</strong></p> <p>The second pressure <mathjax>#P_2#</mathjax></p> <blockquote></blockquote> <p><strong>Strategy</strong></p> <p>A problem involving two gas pressures and two temperatures must be a <a href="https://socratic.org/questions/what-is-gay-lussac-s-law">Gay-Lussac's Law</a> problem.</p> <p>Gay-Lussac's Law is</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a) P_1/T_1 = P_2/T_2color(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>In your problem, </p> <p><mathjax>#P_1 = "5.00 atm"; T_1 = "(25 + 273.15K)" color(white)(ll)= "298.15 K"#</mathjax><br/> <mathjax>#P_2 = "?"; color(white)(mmmll)T_2 = "(-10 + 273.15 K)" = "263.15 K"#</mathjax></p> <p>Insert the numbers into the Gay-Lussac's Law expression.</p> <blockquote></blockquote> <p><strong>Solution</strong></p> <p><mathjax>#P_1/T_1 = P_2/T_2#</mathjax></p> <p><mathjax>#P_2 = P_1 × T_2/T_1 = "5.00 atm" × (263.15 cancel("K"))/(298.15 cancel("K")) = "4.41 atm"#</mathjax></p> <p>The new pressure is 4.41 atm.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/258198" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535d701102bf342f53d9bcb0"> Question #9bcb0 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-gay-lussac-s-law-formula"> What is the Gay Lussac's law formula? 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If the temperature falls to -10°C, what is the new pressure inside the container?	null
784	ace8b200-6ddd-11ea-8f2c-ccda262736ce	https://socratic.org/questions/58fe319d11ef6b68dba6d379	3.25 × 10^25	start physical_unit 2 2 number none qc_end physical_unit 7 7 4 5 mole qc_end end	[{"type":"physical unit","value":"Number [OF] atoms"}]	[{"type":"physical unit","value":"3.25 × 10^25"}]	[{"type":"physical unit","value":"Mole [OF] water [=] \\pu{18 mol}"}]	<h1 class="questionTitle" itemprop="name">How many atoms in #18*mol# of water?</h1>	null	3.25 × 10^25	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>By definition a mole of stuff SPECIFIES <mathjax>#6.022xx10^23#</mathjax> individual items of that stuff. Why should we use such an absurdly large number? Well, it turns out that <mathjax>#6.022xx10^23#</mathjax> individual <mathjax>#""^1H#</mathjax> atoms have a mass of <mathjax>#1.00g#</mathjax> precisely. <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">The mole</a> is thus the link between the submicro world of atoms and molecules, to the macro world of grams, kilograms, and litres.</p> <p>We also conveniently use the symbol <mathjax>#N_A#</mathjax>, where <mathjax>#N_A-=6.022xx10^23#</mathjax>. And we can use the <mathjax>#"mole"#</mathjax> as we would any other collective number, i.e. <mathjax>#"dozen"#</mathjax>, <mathjax>#"Bakers' dozen"#</mathjax>, <mathjax>#"score"#</mathjax>, <mathjax>#"gross......"#</mathjax></p> <p>And so we have <mathjax>#18mol#</mathjax> of <mathjax>#H_2O#</mathjax>, which is equivalent to <mathjax>#3xx18xx6.022xx10^23#</mathjax> individual atoms. What is the mass of this quantity of given atoms?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#54xxN_A#</mathjax>, where <mathjax>#N_A-="Avogadro's Number................."#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>By definition a mole of stuff SPECIFIES <mathjax>#6.022xx10^23#</mathjax> individual items of that stuff. Why should we use such an absurdly large number? Well, it turns out that <mathjax>#6.022xx10^23#</mathjax> individual <mathjax>#""^1H#</mathjax> atoms have a mass of <mathjax>#1.00g#</mathjax> precisely. <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">The mole</a> is thus the link between the submicro world of atoms and molecules, to the macro world of grams, kilograms, and litres.</p> <p>We also conveniently use the symbol <mathjax>#N_A#</mathjax>, where <mathjax>#N_A-=6.022xx10^23#</mathjax>. And we can use the <mathjax>#"mole"#</mathjax> as we would any other collective number, i.e. <mathjax>#"dozen"#</mathjax>, <mathjax>#"Bakers' dozen"#</mathjax>, <mathjax>#"score"#</mathjax>, <mathjax>#"gross......"#</mathjax></p> <p>And so we have <mathjax>#18mol#</mathjax> of <mathjax>#H_2O#</mathjax>, which is equivalent to <mathjax>#3xx18xx6.022xx10^23#</mathjax> individual atoms. What is the mass of this quantity of given atoms?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many atoms in #18mol# of water?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="412041" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-24T18:19:18" itemprop="dateCreated"> Apr 24, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#54xxN_A#</mathjax>, where <mathjax>#N_A-="Avogadro's Number................."#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>By definition a mole of stuff SPECIFIES <mathjax>#6.022xx10^23#</mathjax> individual items of that stuff. Why should we use such an absurdly large number? Well, it turns out that <mathjax>#6.022xx10^23#</mathjax> individual <mathjax>#""^1H#</mathjax> atoms have a mass of <mathjax>#1.00g#</mathjax> precisely. <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">The mole</a> is thus the link between the submicro world of atoms and molecules, to the macro world of grams, kilograms, and litres.</p> <p>We also conveniently use the symbol <mathjax>#N_A#</mathjax>, where <mathjax>#N_A-=6.022xx10^23#</mathjax>. And we can use the <mathjax>#"mole"#</mathjax> as we would any other collective number, i.e. <mathjax>#"dozen"#</mathjax>, <mathjax>#"Bakers' dozen"#</mathjax>, <mathjax>#"score"#</mathjax>, <mathjax>#"gross......"#</mathjax></p> <p>And so we have <mathjax>#18*mol#</mathjax> of <mathjax>#H_2O#</mathjax>, which is equivalent to <mathjax>#3xx18xx6.022xx10^23#</mathjax> individual atoms. What is the mass of this quantity of given atoms?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/412041" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1173 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many atoms in #18*mol# of water?	null
785	a8dd27e6-6ddd-11ea-960f-ccda262736ce	https://socratic.org/questions/stoichiometry-predicts-that-the-yield-of-beryllium-chloride-is-10-7-grams-if-my-	71.03%	start physical_unit 6 7 percent_yield none qc_end physical_unit 6 7 9 10 percent_yield qc_end physical_unit 6 7 16 17 actual_yield qc_end end	[{"type":"physical unit","value":"Percent yield [OF] beryllium chloride"}]	[{"type":"physical unit","value":"71.03%"}]	[{"type":"physical unit","value":"Yield [OF] beryllium chloride [=] \\pu{10.7 grams}"},{"type":"physical unit","value":"Actual yield [OF] beryllium chloride [=] \\pu{7.6 grams}"}]	<h1 class="questionTitle" itemprop="name">Stoichiometry predicts that the yield of beryllium chloride is 10.7 grams. If my actual yield was 7.6 grams, what was my percent yield? </h1>	null	71.03%	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Of course you need a stoichiometric equation to represent the <mathjax>#BeCl_2#</mathjax> synthesis. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Percentage yield"="Recovered product(g)"/"Potential product(g)"xx100%=??#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Of course you need a stoichiometric equation to represent the <mathjax>#BeCl_2#</mathjax> synthesis. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Stoichiometry predicts that the yield of beryllium chloride is 10.7 grams. If my actual yield was 7.6 grams, what was my percent yield? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/percent-yield" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Yield</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="276975" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-13T18:33:48" itemprop="dateCreated"> Jun 13, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Percentage yield"="Recovered product(g)"/"Potential product(g)"xx100%=??#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Of course you need a stoichiometric equation to represent the <mathjax>#BeCl_2#</mathjax> synthesis. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/276975" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ebd02bf3469570e2e62"> Question #e2e62 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ec502bf34694a4fee2e"> Question #fee2e </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ec902bf34694a4fee32"> Question #fee32 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ece02bf346950519e89"> Question #19e89 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ed302bf34694c8c5bdc"> Question #c5bdc </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ee302bf3469517a1065"> Question #a1065 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-would-be-the-limiting-reagent-if-26-0-grams-of-c3h9n-were-reacted-with-46-3"> What would be the limiting reagent if 26.0 grams of C3H9N were reacted with 46.3 grams of... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-percent-yield-always-less-than-100"> Is percent yield always less than 100? 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If my actual yield was 7.6 grams, what was my percent yield?	null
786	a860f790-6ddd-11ea-b5bb-ccda262736ce	https://socratic.org/questions/what-is-the-chemical-equation-for-pure-uranium-being-obtained-by-reacting-uraniu	UCl4(s) + 2 Mg(s) ->[\Delta] U(s) + 2 MgCl2(s)	start chemical_equation qc_end substance 6 7 qc_end substance 12 14 qc_end substance 16 16 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the equation"}]	[{"type":"chemical equation","value":"UCl4(s) + 2 Mg(s) ->[\\Delta] U(s) + 2 MgCl2(s)"}]	[{"type":"substance name","value":"Pure uranium"},{"type":"substance name","value":"Uranium (IV) chloride"},{"type":"substance name","value":"Magnesium"}]	<h1 class="questionTitle" itemprop="name">What is the chemical equation for pure uranium being obtained by reacting uranium (IV) chloride with magnesium?</h1>	null	UCl4(s) + 2 Mg(s) ->[\Delta] U(s) + 2 MgCl2(s)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Will it work? I don't know. I guess you need some pretty fierce conditions....</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#UCl_4(s) + 2Mg(s) stackrel(Delta)rarrU(s) + 2MgCl_2(s)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Will it work? I don't know. I guess you need some pretty fierce conditions....</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the chemical equation for pure uranium being obtained by reacting uranium (IV) chloride with magnesium?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="636807" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-06-28T17:16:27" itemprop="dateCreated"> Jun 28, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#UCl_4(s) + 2Mg(s) stackrel(Delta)rarrU(s) + 2MgCl_2(s)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Will it work? I don't know. I guess you need some pretty fierce conditions....</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/636807" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-equation-for-photosynthesis"> What is the chemical equation for photosynthesis? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-know-the-relative-number-of-grams-of-each-substance-used-or-produced-w"> How can I know the relative number of grams of each substance used or produced with chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-know-the-relative-number-of-moles-of-each-substance-with-chemical-equa"> How can I know the relative number of moles of each substance with chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-chemical-equations-illustrate-that-atoms-are-conserved-1"> How do chemical equations illustrate that atoms are conserved? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-know-the-formula-of-the-reactants-and-products-with-chemical-equations"> How can I know the formula of the reactants and products with chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-potassium-metal-and-chlorine-gas-combi"> How can I balance this chemical equations? 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787	a99f4110-6ddd-11ea-9550-ccda262736ce	https://socratic.org/questions/if-335-g-of-water-at-65-5-c-loses-9750-j-heat-what-is-the-final-temperature-of-t	58.6 ℃	start physical_unit 4 4 temperature °c qc_end physical_unit 4 4 1 2 mass qc_end physical_unit 4 4 6 7 temperature qc_end physical_unit 4 4 9 10 heat_energy qc_end end	[{"type":"physical unit","value":"Temperature2 [OF] water [IN] ℃"}]	[{"type":"physical unit","value":"58.6 ℃"}]	[{"type":"physical unit","value":"Mass [OF] water [=] \\pu{335 g}"},{"type":"physical unit","value":"Temperature1 [OF] water [=] \\pu{65.5 ℃}"},{"type":"physical unit","value":"Lost heat [OF] water [=] \\pu{9750 J}"}]	<h1 class="questionTitle" itemprop="name">If 335 g of water at 65.5°C loses 9750 J heat, what is the final temperature of the water? </h1>	null	58.6 ℃	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Let the final temperature be <mathjax>#=TºC#</mathjax></p> <p>Then,</p> <p><mathjax>#DeltaT=(65.5-T)ºC#</mathjax></p> <p>Mass of water, <mathjax>#m=0.335kg#</mathjax></p> <p>Heat lost, <mathjax>#H=9.750kJ#</mathjax></p> <p><a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> of water, <mathjax>#s=4.186kJkg^-1ºC^-1#</mathjax></p> <p>Therefore,</p> <p><mathjax>#H=msDeltaT#</mathjax></p> <p><mathjax>#9.750=0.3354.186(65.5-T)#</mathjax></p> <p><mathjax>#65.5-T=9.750/(0.335*4.186)=6.95#</mathjax></p> <p><mathjax>#T=65.5-6.95=58.6ºC#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The final temperature is <mathjax>#=58.6ºC#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Let the final temperature be <mathjax>#=TºC#</mathjax></p> <p>Then,</p> <p><mathjax>#DeltaT=(65.5-T)ºC#</mathjax></p> <p>Mass of water, <mathjax>#m=0.335kg#</mathjax></p> <p>Heat lost, <mathjax>#H=9.750kJ#</mathjax></p> <p><a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> of water, <mathjax>#s=4.186kJkg^-1ºC^-1#</mathjax></p> <p>Therefore,</p> <p><mathjax>#H=msDeltaT#</mathjax></p> <p><mathjax>#9.750=0.3354.186(65.5-T)#</mathjax></p> <p><mathjax>#65.5-T=9.750/(0.335*4.186)=6.95#</mathjax></p> <p><mathjax>#T=65.5-6.95=58.6ºC#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">If 335 g of water at 65.5°C loses 9750 J heat, what is the final temperature of the water? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/calorimetry" itemprop="url"> <span class="breadcrumb" itemprop="title">Calorimetry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="396599" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/narad-t"><img alt="" class="" src="https://profilepictures.socratic.org/zsDo4Wx9QIqYad4PXKE9_150317-1041.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/narad-t"> Narad T. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-26T07:38:02" itemprop="dateCreated"> Mar 26, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The final temperature is <mathjax>#=58.6ºC#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Let the final temperature be <mathjax>#=TºC#</mathjax></p> <p>Then,</p> <p><mathjax>#DeltaT=(65.5-T)ºC#</mathjax></p> <p>Mass of water, <mathjax>#m=0.335kg#</mathjax></p> <p>Heat lost, <mathjax>#H=9.750kJ#</mathjax></p> <p><a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> of water, <mathjax>#s=4.186kJkg^-1ºC^-1#</mathjax></p> <p>Therefore,</p> <p><mathjax>#H=msDeltaT#</mathjax></p> <p><mathjax>#9.750=0.3354.186(65.5-T)#</mathjax></p> <p><mathjax>#65.5-T=9.750/(0.335*4.186)=6.95#</mathjax></p> <p><mathjax>#T=65.5-6.95=58.6ºC#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/396599" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-differential-scanning-in-calorimetry-work"> How does differential scanning in calorimetry work? 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788	ac35490d-6ddd-11ea-8733-ccda262736ce	https://socratic.org/questions/597697f211ef6b7fd5372eb6	0.03 moles	start physical_unit 7 7 mole mol qc_end physical_unit 7 7 5 6 mass qc_end end	[{"type":"physical unit","value":"Mole [OF] Fe [IN] moles"}]	[{"type":"physical unit","value":"0.03 moles"}]	[{"type":"physical unit","value":"Mass [OF] Fe [=] \\pu{1.68 g}"}]	<h1 class="questionTitle" itemprop="name">How many moles are in #"1.68 g Fe"#?</h1>	null	0.03 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Divide the mass of iron by its molar mass in g/mol to get the moles of iron. </p> <p><mathjax>#(1.68color(red)cancel(color(black)("g Fe")))/(55.845color(red)cancel(color(black)("g Fe"))/"mol Fe")="0.0301 mol Fe"#</mathjax></p> <p>One mole of anything is <mathjax>#6.022xx10^23#</mathjax> of anything, including atoms. Multiply mol Fe by <mathjax>#(6.022xx10^23)/("mol")#</mathjax>.</p> <p><mathjax>#0.0301color(red)cancel(color(black)("mol Fe"))xx(6.022xx10^23"atoms Fe")/(1color(red)cancel(color(black)("mol Fe")))=1.81xx10^22 "atoms Fe"#</mathjax> (rounded to three sig figs)</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>There is <mathjax>#"0.0301 mol Fe"#</mathjax> in <mathjax>#"1.68 g Fe"#</mathjax>.</p> <p>There are <mathjax>#1.81xx10^22#</mathjax> atoms in <mathjax>#"1.68 g Fe"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Divide the mass of iron by its molar mass in g/mol to get the moles of iron. </p> <p><mathjax>#(1.68color(red)cancel(color(black)("g Fe")))/(55.845color(red)cancel(color(black)("g Fe"))/"mol Fe")="0.0301 mol Fe"#</mathjax></p> <p>One mole of anything is <mathjax>#6.022xx10^23#</mathjax> of anything, including atoms. Multiply mol Fe by <mathjax>#(6.022xx10^23)/("mol")#</mathjax>.</p> <p><mathjax>#0.0301color(red)cancel(color(black)("mol Fe"))xx(6.022xx10^23"atoms Fe")/(1color(red)cancel(color(black)("mol Fe")))=1.81xx10^22 "atoms Fe"#</mathjax> (rounded to three sig figs)</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles are in #"1.68 g Fe"#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="455933" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-07-25T02:12:08" itemprop="dateCreated"> Jul 25, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>There is <mathjax>#"0.0301 mol Fe"#</mathjax> in <mathjax>#"1.68 g Fe"#</mathjax>.</p> <p>There are <mathjax>#1.81xx10^22#</mathjax> atoms in <mathjax>#"1.68 g Fe"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Divide the mass of iron by its molar mass in g/mol to get the moles of iron. </p> <p><mathjax>#(1.68color(red)cancel(color(black)("g Fe")))/(55.845color(red)cancel(color(black)("g Fe"))/"mol Fe")="0.0301 mol Fe"#</mathjax></p> <p>One mole of anything is <mathjax>#6.022xx10^23#</mathjax> of anything, including atoms. Multiply mol Fe by <mathjax>#(6.022xx10^23)/("mol")#</mathjax>.</p> <p><mathjax>#0.0301color(red)cancel(color(black)("mol Fe"))xx(6.022xx10^23"atoms Fe")/(1color(red)cancel(color(black)("mol Fe")))=1.81xx10^22 "atoms Fe"#</mathjax> (rounded to three sig figs)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/455933" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 10928 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many moles are in #"1.68 g Fe"#?	null
789	a96fcd50-6ddd-11ea-9015-ccda262736ce	https://socratic.org/questions/58dab212b72cff01e67ee7f1	5.85 g	start physical_unit 10 11 mass g qc_end physical_unit 6 7 1 2 volume qc_end physical_unit 6 7 4 5 molarity qc_end physical_unit 6 7 20 20 ph qc_end end	[{"type":"physical unit","value":"Mass [OF] ammonium chloride [IN] g"}]	[{"type":"physical unit","value":"5.85 g"}]	[{"type":"physical unit","value":"Volume [OF] aqueous ammonia [=] \\pu{250 mL}"},{"type":"physical unit","value":"Molarity [OF] aqueous ammonia [=] \\pu{0.200 mol/L}"},{"type":"physical unit","value":"pH [OF] aqueous ammonia [=] \\pu{8.90}"}]	<h1 class="questionTitle" itemprop="name">Given #250mL# of #0.200mol*L^-1# aqueous ammonia, how much ammonium chloride would be added to achieve a #pH-=8.90#?</h1>	null	5.85 g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We use the buffer equation.......which is derived here, <a href="/questions/how-do-buffers-maintain-ph#270129">https://socratic.org/questions/how-do-buffers-maintain-ph#270129</a>. </p> <p>But here <mathjax>#[A^-]=[NH_3]#</mathjax>, and <mathjax>#[HA]=[NH_4Cl]#</mathjax>. </p> <p>For such a buffer <mathjax>#pH=pK_a+log_10{[[NH_3(aq)]]/[[NH_4Cl(aq)]]}#</mathjax></p> <p>And I also ASSUME, that the required <mathjax>#pH=8.90#</mathjax></p> <p>Now <mathjax>#pK_a=9.24#</mathjax> for ammonium ion.</p> <p>And thus, substituting these values into the equation..........</p> <p><mathjax>#log_10{[[NH_3(aq)]]/[[NH_4Cl(aq)]]}=-0.34#</mathjax></p> <p>i.e. <mathjax>#([NH_3(aq)])/([NH_4Cl(aq)])=10^(-0.34)#</mathjax>,</p> <p>i.e. <mathjax>#"moles of ammonium chloride"xx0.457="moles of ammonia"#</mathjax>, BECAUSE the volume was the same in each case. </p> <p><mathjax>#"moles of ammonia"=0.250Lxx0.200molL^-1=5.00xx10^-2mol#</mathjax></p> <p><mathjax>#"ammonium chloride"=(5.00xx10^-2mol)/(0.457)=0.109mol#</mathjax></p> <p>And thus we have to add............</p> <p><mathjax>#0.109molxx53.49gmol^-1=5.85g#</mathjax></p> <p>To the initial <mathjax>#250.0mL#</mathjax> volume of ammonia. </p> <p>Just as a recheck, let us substitute these values back into the buffer equation:</p> <p><mathjax>#pH=9.24+log_10{{5.00xx10^-2molxx1/0.2500L)/((5.85g)/(53.49gmol^-1)xx1/0.2500*L)}#</mathjax></p> <p><mathjax>#=8.90#</mathjax> as required..........</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Doubtless you mean <mathjax>#"ammonium chloride"#</mathjax>, <mathjax>#NH_4Cl#</mathjax>. I calculate a mass of <mathjax>#5.85g#</mathjax>..................</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We use the buffer equation.......which is derived here, <a href="/questions/how-do-buffers-maintain-ph#270129">https://socratic.org/questions/how-do-buffers-maintain-ph#270129</a>. </p> <p>But here <mathjax>#[A^-]=[NH_3]#</mathjax>, and <mathjax>#[HA]=[NH_4Cl]#</mathjax>. </p> <p>For such a buffer <mathjax>#pH=pK_a+log_10{[[NH_3(aq)]]/[[NH_4Cl(aq)]]}#</mathjax></p> <p>And I also ASSUME, that the required <mathjax>#pH=8.90#</mathjax></p> <p>Now <mathjax>#pK_a=9.24#</mathjax> for ammonium ion.</p> <p>And thus, substituting these values into the equation..........</p> <p><mathjax>#log_10{[[NH_3(aq)]]/[[NH_4Cl(aq)]]}=-0.34#</mathjax></p> <p>i.e. <mathjax>#([NH_3(aq)])/([NH_4Cl(aq)])=10^(-0.34)#</mathjax>,</p> <p>i.e. <mathjax>#"moles of ammonium chloride"xx0.457="moles of ammonia"#</mathjax>, BECAUSE the volume was the same in each case. </p> <p><mathjax>#"moles of ammonia"=0.250Lxx0.200molL^-1=5.00xx10^-2mol#</mathjax></p> <p><mathjax>#"ammonium chloride"=(5.00xx10^-2mol)/(0.457)=0.109mol#</mathjax></p> <p>And thus we have to add............</p> <p><mathjax>#0.109molxx53.49gmol^-1=5.85g#</mathjax></p> <p>To the initial <mathjax>#250.0mL#</mathjax> volume of ammonia. </p> <p>Just as a recheck, let us substitute these values back into the buffer equation:</p> <p><mathjax>#pH=9.24+log_10{{5.00xx10^-2molxx1/0.2500L)/((5.85g)/(53.49gmol^-1)xx1/0.2500L)}#</mathjax></p> <p><mathjax>#=8.90#</mathjax> as required..........</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Given #250mL# of #0.200molL^-1# aqueous ammonia, how much ammonium chloride would be added to achieve a #pH-=8.90#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#reactions-in-solution" itemprop="url"> <span class="breadcrumb" itemprop="title">Reactions in Solution</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/reactions-in-solution/buffer-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">Buffer Calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="412750" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-25T19:30:16" itemprop="dateCreated"> Apr 25, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Doubtless you mean <mathjax>#"ammonium chloride"#</mathjax>, <mathjax>#NH_4Cl#</mathjax>. I calculate a mass of <mathjax>#5.85g#</mathjax>..................</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We use the buffer equation.......which is derived here, <a href="/questions/how-do-buffers-maintain-ph#270129">https://socratic.org/questions/how-do-buffers-maintain-ph#270129</a>. </p> <p>But here <mathjax>#[A^-]=[NH_3]#</mathjax>, and <mathjax>#[HA]=[NH_4Cl]#</mathjax>. </p> <p>For such a buffer <mathjax>#pH=pK_a+log_10{[[NH_3(aq)]]/[[NH_4Cl(aq)]]}#</mathjax></p> <p>And I also ASSUME, that the required <mathjax>#pH=8.90#</mathjax></p> <p>Now <mathjax>#pK_a=9.24#</mathjax> for ammonium ion.</p> <p>And thus, substituting these values into the equation..........</p> <p><mathjax>#log_10{[[NH_3(aq)]]/[[NH_4Cl(aq)]]}=-0.34#</mathjax></p> <p>i.e. <mathjax>#([NH_3(aq)])/([NH_4Cl(aq)])=10^(-0.34)#</mathjax>,</p> <p>i.e. <mathjax>#"moles of ammonium chloride"xx0.457="moles of ammonia"#</mathjax>, BECAUSE the volume was the same in each case. </p> <p><mathjax>#"moles of ammonia"=0.250Lxx0.200molL^-1=5.00xx10^-2mol#</mathjax></p> <p><mathjax>#"ammonium chloride"=(5.00xx10^-2mol)/(0.457)=0.109mol#</mathjax></p> <p>And thus we have to add............</p> <p><mathjax>#0.109molxx53.49gmol^-1=5.85g#</mathjax></p> <p>To the initial <mathjax>#250.0mL#</mathjax> volume of ammonia. </p> <p>Just as a recheck, let us substitute these values back into the buffer equation:</p> <p><mathjax>#pH=9.24+log_10{{5.00xx10^-2molxx1/0.2500L)/((5.85g)/(53.49gmol^-1)xx1/0.2500*L)}#</mathjax></p> <p><mathjax>#=8.90#</mathjax> as required..........</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/412750" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-buffer-solutions-used"> How are buffer solutions used? 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790	a9f26e9c-6ddd-11ea-af14-ccda262736ce	https://socratic.org/questions/what-is-the-molar-mass-of-c-6h-6	78.11 g/mol	start physical_unit 6 6 molar_mass g/mol qc_end chemical_equation 6 6 qc_end end	[{"type":"physical unit","value":"Molar mass [OF] C6H6 [IN] g/mol"}]	[{"type":"physical unit","value":"78.11 g/mol"}]	[{"type":"chemical equation","value":"C6H6"}]	<h1 class="questionTitle" itemprop="name">What is the molar mass of #C_6H_6#?</h1>	null	78.11 g/mol	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The molar mass of a compound is the mass of one mole in g/mol. It is determined by multiplying the subscript of each element by its molar mass, which is its relative <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">atomic mass</a> on <a href="http://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a> in g/mol.</p> <p><strong>Determine the Molar Mass of <mathjax>#"C"_6"H"_6"#</mathjax></strong></p> <p><strong>First</strong> determine the molar mass of each element by using the periodic table.</p> <p>Molar mass of <mathjax>#"C:"#</mathjax> <mathjax>#"12.0107 g/mol"#</mathjax></p> <p>Molar mass of <mathjax>#"H:"#</mathjax> <mathjax>#"1.00794 g/mol"#</mathjax></p> <p><strong>Next</strong> determine the molar mass of <mathjax>#"C"_6"H"_6"#</mathjax>.</p> <p><mathjax>#(6xx12.0107"g/mol")+(6xx1.00794"g/mol")="78.1118 g/mol"#</mathjax></p> <p>The molar mass of the compound <mathjax>#"C"_6"H"_6"#</mathjax> is <mathjax>#"78.1118 g/mol"#</mathjax>.</p> <p><strong>Note:</strong> Some periodic tables give the relative atomic mass of carbon as 12.011 and 1.008 for hydrogen.</p> <p><strong>Also Note:</strong> If you aren't required to show how to calculate the molar mass, there are reliable websites where you can look it up. One site, believe it or not, is Wikipedia. Another site is The Pubchem Project at <a href="http://pubchem.ncbi.nlm.nih.gov/" rel="nofollow" target="_blank">http://pubchem.ncbi.nlm.nih.gov/</a>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The molar mass of the compound <mathjax>#"C"_6"H"_6"#</mathjax> is <mathjax>#"78.1118 g/mol"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The molar mass of a compound is the mass of one mole in g/mol. It is determined by multiplying the subscript of each element by its molar mass, which is its relative <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">atomic mass</a> on <a href="http://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a> in g/mol.</p> <p><strong>Determine the Molar Mass of <mathjax>#"C"_6"H"_6"#</mathjax></strong></p> <p><strong>First</strong> determine the molar mass of each element by using the periodic table.</p> <p>Molar mass of <mathjax>#"C:"#</mathjax> <mathjax>#"12.0107 g/mol"#</mathjax></p> <p>Molar mass of <mathjax>#"H:"#</mathjax> <mathjax>#"1.00794 g/mol"#</mathjax></p> <p><strong>Next</strong> determine the molar mass of <mathjax>#"C"_6"H"_6"#</mathjax>.</p> <p><mathjax>#(6xx12.0107"g/mol")+(6xx1.00794"g/mol")="78.1118 g/mol"#</mathjax></p> <p>The molar mass of the compound <mathjax>#"C"_6"H"_6"#</mathjax> is <mathjax>#"78.1118 g/mol"#</mathjax>.</p> <p><strong>Note:</strong> Some periodic tables give the relative atomic mass of carbon as 12.011 and 1.008 for hydrogen.</p> <p><strong>Also Note:</strong> If you aren't required to show how to calculate the molar mass, there are reliable websites where you can look it up. One site, believe it or not, is Wikipedia. Another site is The Pubchem Project at <a href="http://pubchem.ncbi.nlm.nih.gov/" rel="nofollow" target="_blank">http://pubchem.ncbi.nlm.nih.gov/</a>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the molar mass of #C_6H_6#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="226061" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-02-14T08:26:36" itemprop="dateCreated"> Feb 14, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The molar mass of the compound <mathjax>#"C"_6"H"_6"#</mathjax> is <mathjax>#"78.1118 g/mol"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The molar mass of a compound is the mass of one mole in g/mol. It is determined by multiplying the subscript of each element by its molar mass, which is its relative <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">atomic mass</a> on <a href="http://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a> in g/mol.</p> <p><strong>Determine the Molar Mass of <mathjax>#"C"_6"H"_6"#</mathjax></strong></p> <p><strong>First</strong> determine the molar mass of each element by using the periodic table.</p> <p>Molar mass of <mathjax>#"C:"#</mathjax> <mathjax>#"12.0107 g/mol"#</mathjax></p> <p>Molar mass of <mathjax>#"H:"#</mathjax> <mathjax>#"1.00794 g/mol"#</mathjax></p> <p><strong>Next</strong> determine the molar mass of <mathjax>#"C"_6"H"_6"#</mathjax>.</p> <p><mathjax>#(6xx12.0107"g/mol")+(6xx1.00794"g/mol")="78.1118 g/mol"#</mathjax></p> <p>The molar mass of the compound <mathjax>#"C"_6"H"_6"#</mathjax> is <mathjax>#"78.1118 g/mol"#</mathjax>.</p> <p><strong>Note:</strong> Some periodic tables give the relative atomic mass of carbon as 12.011 and 1.008 for hydrogen.</p> <p><strong>Also Note:</strong> If you aren't required to show how to calculate the molar mass, there are reliable websites where you can look it up. One site, believe it or not, is Wikipedia. Another site is The Pubchem Project at <a href="http://pubchem.ncbi.nlm.nih.gov/" rel="nofollow" target="_blank">http://pubchem.ncbi.nlm.nih.gov/</a>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/226061" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molecular-formula-of-a-compound"> How do you find molecular formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-diamond"> What is the chemical formula of a diamond? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-carbohydrate"> What is the chemical formula of a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-valproic-acid"> What is the empirical formula for valproic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-of-magnesium-oxide"> What is the empirical formula of magnesium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-empirical-formula-not-double-that-of-the-monosaccharides"> Why is the empirical formula not double that of the monosaccharides? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5331180502bf342f40b5c3b5"> Question #5c3b5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-molecular-formula-represents-a-carbohydrate"> What molecular formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-of-vinegar"> What is the molecular formula of vinegar? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/empirical-and-molecular-formulas"> See all questions in Empirical and Molecular Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3069 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the molar mass of #C_6H_6#?	null
791	aa94f5d2-6ddd-11ea-bf8c-ccda262736ce	https://socratic.org/questions/how-many-moles-of-mgs-2o-3-are-in-235-g-of-the-compound	1.72 moles	start physical_unit 4 4 mole mol qc_end physical_unit 10 11 7 8 mass qc_end end	[{"type":"physical unit","value":"Mole [OF] MgS2O3 [IN] moles"}]	[{"type":"physical unit","value":"1.72 moles"}]	[{"type":"physical unit","value":"Mass [OF] the compound [=] \\pu{235 g}"}]	<h1 class="questionTitle" itemprop="name">How many moles of #MgS_2O_3# are in 235 g of the compound?</h1>	null	1.72 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Molar quantity"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Mass"/"Molar mass"#</mathjax></p> <p><mathjax>#=#</mathjax> <mathjax>#(235cancelg)/(136.4cancelg*mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??mol#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>A little bit under <mathjax>#2#</mathjax> <mathjax>#"moles"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Molar quantity"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Mass"/"Molar mass"#</mathjax></p> <p><mathjax>#=#</mathjax> <mathjax>#(235cancelg)/(136.4cancelg*mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??mol#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles of #MgS_2O_3# are in 235 g of the compound?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="306156" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-09-04T20:55:21" itemprop="dateCreated"> Sep 4, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>A little bit under <mathjax>#2#</mathjax> <mathjax>#"moles"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Molar quantity"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Mass"/"Molar mass"#</mathjax></p> <p><mathjax>#=#</mathjax> <mathjax>#(235cancelg)/(136.4cancelg*mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??mol#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/306156" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? 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792	ac402630-6ddd-11ea-a99a-ccda262736ce	https://socratic.org/questions/sterling-silver-is-an-alloy-made-by-combining-silver-with-copper-in-a-ratio-of-2	6.09 kg	start physical_unit 10 10 mass kg qc_end physical_unit 1 1 25 26 mass qc_end end	[{"type":"physical unit","value":"Mass [OF] copper [IN] kg"}]	[{"type":"physical unit","value":"6.09 kg"}]	[{"type":"physical unit","value":"Ratio [OF] silver to copper [=] \\pu{23:2}"},{"type":"physical unit","value":"Mass [OF] silver [=] \\pu{70 kg}"}]	<h1 class="questionTitle" itemprop="name">Sterling silver is an alloy made by combining silver with copper in a ratio of 23 to 2. How much copper should be combined with 70 kg of silver to make sterling silver?</h1>	null	6.09 kg	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#2div23=Xdiv70#</mathjax> or <mathjax>#2/23=X/70#</mathjax></p> <p>Cross-multiply:<br/> <mathjax>#23X=270->X=(270)/23~~6.09#</mathjax> kg of copper.</p> <p><strong>Another way:</strong></p> <p><mathjax>#70#</mathjax>kg amounts to <mathjax>#70/23=3,0347...#</mathjax> times as much as <mathjax>#27#</mathjax></p> <p>So we need <mathjax>#3,0347...#</mathjax> times as much copper (same answer)</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2Cuharr23Ag#</mathjax>. Question is <mathjax>#?Cuharr70Ag#</mathjax><br/> A ratio question.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#2div23=Xdiv70#</mathjax> or <mathjax>#2/23=X/70#</mathjax></p> <p>Cross-multiply:<br/> <mathjax>#23X=270->X=(270)/23~~6.09#</mathjax> kg of copper.</p> <p><strong>Another way:</strong></p> <p><mathjax>#70#</mathjax>kg amounts to <mathjax>#70/23=3,0347...#</mathjax> times as much as <mathjax>#27#</mathjax></p> <p>So we need <mathjax>#3,0347...#</mathjax> times as much copper (same answer)</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Sterling silver is an alloy made by combining silver with copper in a ratio of 23 to 2. How much copper should be combined with 70 kg of silver to make sterling silver?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-periodic-table" itemprop="url"> <span class="breadcrumb" itemprop="title">The Periodic Table</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-periodic-table/metals-and-nonmetals" itemprop="url"> <span class="breadcrumb" itemprop="title">Metals and Nonmetals</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="358639" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meneernask"><img alt="" class="" src="https://profilepictures.socratic.org/gpA0lokRGK9vLVUnAMAy_meneernask.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meneernask"> MeneerNask </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-12-31T12:10:39" itemprop="dateCreated"> Dec 31, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2Cuharr23Ag#</mathjax>. Question is <mathjax>#?Cuharr70Ag#</mathjax><br/> A ratio question.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#2div23=Xdiv70#</mathjax> or <mathjax>#2/23=X/70#</mathjax></p> <p>Cross-multiply:<br/> <mathjax>#23X=270->X=(270)/23~~6.09#</mathjax> kg of copper.</p> <p><strong>Another way:</strong></p> <p><mathjax>#70#</mathjax>kg amounts to <mathjax>#70/23=3,0347...#</mathjax> times as much as <mathjax>#27#</mathjax></p> <p>So we need <mathjax>#3,0347...#</mathjax> times as much copper (same answer)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/358639" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-metalloids-different-from-metals"> How are metalloids different from metals? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-nonmetals-are-there-in-the-periodic-table"> How many nonmetals are there in the periodic table? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-metalloids-described-as-semiconductors"> Why are metalloids described as semiconductors? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-metals-are-good-conductors-of-electricity"> Why metals are good conductors of electricity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-metals-malleable"> Why are metals malleable? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-elements-are-metals-1"> What elements are metals? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-metals-ductile-instead-of-brittle"> Why are metals ductile instead of brittle? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-nonmetals-form-anions"> Why do nonmetals form anions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-nonmetals-are-most-chemically-reactive"> What nonmetals are most chemically reactive? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-nonmetals-are-liquid-at-room-temperature"> What elements are liquid at room temperature? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-periodic-table/metals-and-nonmetals"> See all questions in Metals and Nonmetals </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3589 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Sterling silver is an alloy made by combining silver with copper in a ratio of 23 to 2. How much copper should be combined with 70 kg of silver to make sterling silver?	null
793	a8ce5ad1-6ddd-11ea-86ae-ccda262736ce	https://socratic.org/questions/find-out-the-volume-of-6-023-10-of-ammonia-at-stp	2.27 L	start physical_unit 9 9 volume l qc_end physical_unit 9 9 5 7 number qc_end c_other STP qc_end end	[{"type":"physical unit","value":"Volume [OF] ammonia [IN] L"}]	[{"type":"physical unit","value":"2.27 L"}]	[{"type":"physical unit","value":"Number [OF] ammonia [=] \\pu{6.023 × 10^22}"},{"type":"other","value":"STP"}]	<h1 class="questionTitle" itemprop="name">Find out the volume of 6.023*10²² of ammonia at stp?</h1>	null	2.27 L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>Method 1. Using the Ideal Gas Law</strong></p> <p>We can use the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law"><strong>Ideal Gas Law</strong></a> to solve this problem.</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(\|color(white)(a/a)pV = nRTcolor(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>where </p> <ul> <li><mathjax>#p#</mathjax> is the pressure</li> <li><mathjax>#V#</mathjax> is the volume</li> <li><mathjax>#n#</mathjax> is the number of moles</li> <li><mathjax>#R#</mathjax> is the gas constant</li> <li><mathjax>#T#</mathjax> is the temperature</li> </ul> <blockquote></blockquote> <p>We can rearrange the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a> to get</p> <blockquote> <blockquote> <p><mathjax>#V = (nRT)/p#</mathjax></p> </blockquote> </blockquote> <p><strong>Step 1. Calculate the moles of ammonia</strong></p> <p><mathjax>#n = 6.023 × 10^22 color(red)(cancel(color(black)("molecules NH"_3))) × "1 mol NH"_3/(6.022 × 10^23 color(red)(cancel(color(black)("molecules NH"_3)))) = "0.100 02 mol NH"_3#</mathjax></p> <blockquote></blockquote> <p><strong>Step 2. Calculate the volume at STP</strong></p> <p>Remember that STP is defined as 0 °C and 1 bar.</p> <p><mathjax>#n = "0.100 02 mol"#</mathjax><br/> <mathjax>#R = "0.083 14 bar·L·K"^"-1""mol"^"-1"#</mathjax><br/> <mathjax>#T = "(0 + 273.15) K" = "273.15 K"#</mathjax><br/> <mathjax>#p = "1 bar"#</mathjax></p> <blockquote></blockquote> <p><mathjax>#V = (nRT)/p = ("0.100 02" color(red)(cancel(color(black)("g"))) × "0.083 14" color(red)(cancel(color(black)("bar"))) ·"L"· color(red)(cancel(color(black)("K"^"-1""mol"^"-1"))) × 273.15 color(red)(cancel(color(black)("K"))))/(1 color(red)(cancel(color(black)("bar")))) = "2.271 L"#</mathjax></p> <blockquote></blockquote> <p><strong>Method 2. Using the molar volume</strong></p> <p>We know that there are 0.100 02 mol of <mathjax>#"NH"_3#</mathjax>.</p> <p>We also know that the molar volume of a gas is 22.71 L at STP.</p> <p>∴ <mathjax>#V = "0.100 02" color(red)(cancel(color(black)("mol NH"_3))) × "22.71 L NH"_3/(1 color(red)(cancel(color(black)("mol NH"_3)))) = "2.271 L NH"_3#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><blockquote></blockquote> <p>The volume is 2.271 L.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>Method 1. Using the Ideal Gas Law</strong></p> <p>We can use the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law"><strong>Ideal Gas Law</strong></a> to solve this problem.</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(\|color(white)(a/a)pV = nRTcolor(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>where </p> <ul> <li><mathjax>#p#</mathjax> is the pressure</li> <li><mathjax>#V#</mathjax> is the volume</li> <li><mathjax>#n#</mathjax> is the number of moles</li> <li><mathjax>#R#</mathjax> is the gas constant</li> <li><mathjax>#T#</mathjax> is the temperature</li> </ul> <blockquote></blockquote> <p>We can rearrange the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a> to get</p> <blockquote> <blockquote> <p><mathjax>#V = (nRT)/p#</mathjax></p> </blockquote> </blockquote> <p><strong>Step 1. Calculate the moles of ammonia</strong></p> <p><mathjax>#n = 6.023 × 10^22 color(red)(cancel(color(black)("molecules NH"_3))) × "1 mol NH"_3/(6.022 × 10^23 color(red)(cancel(color(black)("molecules NH"_3)))) = "0.100 02 mol NH"_3#</mathjax></p> <blockquote></blockquote> <p><strong>Step 2. Calculate the volume at STP</strong></p> <p>Remember that STP is defined as 0 °C and 1 bar.</p> <p><mathjax>#n = "0.100 02 mol"#</mathjax><br/> <mathjax>#R = "0.083 14 bar·L·K"^"-1""mol"^"-1"#</mathjax><br/> <mathjax>#T = "(0 + 273.15) K" = "273.15 K"#</mathjax><br/> <mathjax>#p = "1 bar"#</mathjax></p> <blockquote></blockquote> <p><mathjax>#V = (nRT)/p = ("0.100 02" color(red)(cancel(color(black)("g"))) × "0.083 14" color(red)(cancel(color(black)("bar"))) ·"L"· color(red)(cancel(color(black)("K"^"-1""mol"^"-1"))) × 273.15 color(red)(cancel(color(black)("K"))))/(1 color(red)(cancel(color(black)("bar")))) = "2.271 L"#</mathjax></p> <blockquote></blockquote> <p><strong>Method 2. Using the molar volume</strong></p> <p>We know that there are 0.100 02 mol of <mathjax>#"NH"_3#</mathjax>.</p> <p>We also know that the molar volume of a gas is 22.71 L at STP.</p> <p>∴ <mathjax>#V = "0.100 02" color(red)(cancel(color(black)("mol NH"_3))) × "22.71 L NH"_3/(1 color(red)(cancel(color(black)("mol NH"_3)))) = "2.271 L NH"_3#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Find out the volume of 6.023*10²² of ammonia at stp?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp" itemprop="url"> <span class="breadcrumb" itemprop="title">Molar Volume of a Gas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="465101" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-17T14:22:08" itemprop="dateCreated"> Aug 17, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><blockquote></blockquote> <p>The volume is 2.271 L.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>Method 1. Using the Ideal Gas Law</strong></p> <p>We can use the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law"><strong>Ideal Gas Law</strong></a> to solve this problem.</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(\|color(white)(a/a)pV = nRTcolor(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>where </p> <ul> <li><mathjax>#p#</mathjax> is the pressure</li> <li><mathjax>#V#</mathjax> is the volume</li> <li><mathjax>#n#</mathjax> is the number of moles</li> <li><mathjax>#R#</mathjax> is the gas constant</li> <li><mathjax>#T#</mathjax> is the temperature</li> </ul> <blockquote></blockquote> <p>We can rearrange the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a> to get</p> <blockquote> <blockquote> <p><mathjax>#V = (nRT)/p#</mathjax></p> </blockquote> </blockquote> <p><strong>Step 1. Calculate the moles of ammonia</strong></p> <p><mathjax>#n = 6.023 × 10^22 color(red)(cancel(color(black)("molecules NH"_3))) × "1 mol NH"_3/(6.022 × 10^23 color(red)(cancel(color(black)("molecules NH"_3)))) = "0.100 02 mol NH"_3#</mathjax></p> <blockquote></blockquote> <p><strong>Step 2. Calculate the volume at STP</strong></p> <p>Remember that STP is defined as 0 °C and 1 bar.</p> <p><mathjax>#n = "0.100 02 mol"#</mathjax><br/> <mathjax>#R = "0.083 14 bar·L·K"^"-1""mol"^"-1"#</mathjax><br/> <mathjax>#T = "(0 + 273.15) K" = "273.15 K"#</mathjax><br/> <mathjax>#p = "1 bar"#</mathjax></p> <blockquote></blockquote> <p><mathjax>#V = (nRT)/p = ("0.100 02" color(red)(cancel(color(black)("g"))) × "0.083 14" color(red)(cancel(color(black)("bar"))) ·"L"· color(red)(cancel(color(black)("K"^"-1""mol"^"-1"))) × 273.15 color(red)(cancel(color(black)("K"))))/(1 color(red)(cancel(color(black)("bar")))) = "2.271 L"#</mathjax></p> <blockquote></blockquote> <p><strong>Method 2. Using the molar volume</strong></p> <p>We know that there are 0.100 02 mol of <mathjax>#"NH"_3#</mathjax>.</p> <p>We also know that the molar volume of a gas is 22.71 L at STP.</p> <p>∴ <mathjax>#V = "0.100 02" color(red)(cancel(color(black)("mol NH"_3))) × "22.71 L NH"_3/(1 color(red)(cancel(color(black)("mol NH"_3)))) = "2.271 L NH"_3#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/465101" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-stoichiometric-ratios-relate-to-molar-volume-of-a-gas"> How do stoichiometric ratios relate to molar volume of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-a-gas-at-stp"> How do you calculate molar volume of a gas at STP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-molar-volume-of-hydrogen-gas"> How do you find the molar volume of hydrogen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-oxygen-gas"> How do you calculate molar volume of oxygen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molar-gas-volume"> What is molar gas volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/534c7bf202bf3420a007f014"> What is the volume at 0 °C and 1 atm of a mixture that contains 4.0 g of methane and 2.0 g of helium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5361f75702bf3429040e0599"> What is the difference between STP and NTP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-volume-of-25-moles-of-oxygen-o2-gas"> What is the volume of .25 moles of oxygen (O2) Gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-would-knowing-the-molar-volume-of-a-gas-be-important"> Why would knowing the molar volume of a gas be important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-22-4-liters-called-the-molar-volume-of-a-gas"> Why is 22.4 liters called the molar volume of a gas? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp"> See all questions in Molar Volume of a Gas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 15597 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Find out the volume of 6.023*10²² of ammonia at stp?	null
794	ab267b24-6ddd-11ea-b263-ccda262736ce	https://socratic.org/questions/596f8adc7c01496a1e472a2a	2.83 g	start physical_unit 5 5 mass g qc_end physical_unit 13 14 9 10 volume qc_end substance 18 18 qc_end end	[{"type":"physical unit","value":"Mass [OF] Ca^2+C#C^2- [IN] g"}]	[{"type":"physical unit","value":"2.83 g"}]	[{"type":"physical unit","value":"Volume [OF] acetylene gas [=] \\pu{1.12 L}"},{"type":"substance name","value":"Water"}]	<h1 class="questionTitle" itemprop="name">What mass of calcium carbide, #Ca^(2+)C-=C^(2-)# will give a #1.12*L# volume of acetylene gas upon treatment with water?</h1>	null	2.83 g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>It is a fact that <mathjax>#"1 mole"#</mathjax> of <mathjax>#"Ideal Gas"#</mathjax> occupies <mathjax>#25.4L#</mathjax> under standard conditions. You will have to check your syllabus, because standards vary across curricula........especially these days.</p> <p>We assume ideality, and thus, since moles of acetylene are equivalent to moles of calcium carbide, we need a mass..........</p> <p><mathjax>#(1.12L)/(25.4Lmol^-1)xx64.1gmol^-1-=2.83*g#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, you need to specify your conditions...we follow the stoichiometric equation....</p> <p><mathjax>#Ca^(2+){C-=C}^(2-) + 2H_2O rarr HC-=CH(g)uarr+ Ca(OH)_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>It is a fact that <mathjax>#"1 mole"#</mathjax> of <mathjax>#"Ideal Gas"#</mathjax> occupies <mathjax>#25.4L#</mathjax> under standard conditions. You will have to check your syllabus, because standards vary across curricula........especially these days.</p> <p>We assume ideality, and thus, since moles of acetylene are equivalent to moles of calcium carbide, we need a mass..........</p> <p><mathjax>#(1.12L)/(25.4Lmol^-1)xx64.1gmol^-1-=2.83*g#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What mass of calcium carbide, #Ca^(2+)C-=C^(2-)# will give a #1.12L# volume of acetylene gas upon treatment with water?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/stoichiometry-involving-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="453698" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-07-19T16:46:49" itemprop="dateCreated"> Jul 19, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, you need to specify your conditions...we follow the stoichiometric equation....</p> <p><mathjax>#Ca^(2+){C-=C}^(2-) + 2H_2O rarr HC-=CH(g)uarr+ Ca(OH)_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>It is a fact that <mathjax>#"1 mole"#</mathjax> of <mathjax>#"Ideal Gas"#</mathjax> occupies <mathjax>#25.4L#</mathjax> under standard conditions. You will have to check your syllabus, because standards vary across curricula........especially these days.</p> <p>We assume ideality, and thus, since moles of acetylene are equivalent to moles of calcium carbide, we need a mass..........</p> <p><mathjax>#(1.12L)/(25.4Lmol^-1)xx64.1gmol^-1-=2.83g#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/453698" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-apply-gas-stoichiometry"> How do you apply gas stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-solve-a-gas-law-stoichiometry-problem"> How do you solve a gas law stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-do-gas-stoichiometry-problems-at-stp"> How do you do gas stoichiometry problems at STP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-an-agno3-solution-is-treated-with-50-0-ml-of-hi-gas-to-give-0-235-g-of-agi-"> When an AgNO3 solution is treated with 50.0 mL of HI gas to give 0.235 g of AgI, what is the... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-10-0-ml-of-agno3-solution-is-treated-with-excess-amount-of-hi-gas-to-give-0"> When 10.0 mL of AgNO3 solution is treated with excess amount of HI gas to give 0.235 g of AgI,... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/hydrogen-sulfide-reacts-with-sulfur-dioxide-to-give-h2o-and-s-h2s-so2-h2o-s-soli"> Hydrogen sulfide reacts with sulfur dioxide to give H2O and S, H2S + SO2 = H2O + S(solid),... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-100-ml-of-hcl-gas-at-300-k-and-200-kpa-dissolved-in-pure-water-requires-12-50"> If 100 mL of HCl gas at 300 K and 200 kPa dissolved in pure water requires 12.50 mL of the NaOH... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-100-ml-of-hcl-gas-at-300-k-and-100-kpa-dissolved-in-pure-water-requires-12-50"> If 100 mL of HCl gas at 300 K and 100 kPa dissolved in pure water requires 12.50 mL of the NaOH... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-100-ml-of-hcl-gas-at-300-k-and-100-kpa-dissolve-in-20-ml-of-pure-water-what-i"> If 100 mL of HCl gas at 300 K and 100 kPa dissolve in 20 mL of pure water, what is the concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-2-00-g-mixture-of-na-and-ca-reat-with-water-1-164-l-hydrogen-was-produced-a"> When 2.00 g mixture of Na and Ca reat with water, 1.164 L hydrogen was produced at 300.0 K and... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/stoichiometry-involving-gases"> See all questions in Gas Stoichiometry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2282 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What mass of calcium carbide, #Ca^(2+)C-=C^(2-)# will give a #1.12*L# volume of acetylene gas upon treatment with water?	null
795	aca3d7ad-6ddd-11ea-95ca-ccda262736ce	https://socratic.org/questions/what-is-a-balanced-chemical-equation-including-physical-state-symbols-for-the-co	H3C-CH3(g) + 7/2 O2(g) -> 2 CO2(g) + 3 H2O(g)	start chemical_equation qc_end substance 14 15 qc_end substance 17 19 qc_end substance 21 22 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the combustion"}]	[{"type":"chemical equation","value":"H3C-CH3(g) + 7/2 O2(g) -> 2 CO2(g) + 3 H2O(g)"}]	[{"type":"substance name","value":"Gaseous ethane"},{"type":"substance name","value":"Gaseous carbon dioxide"},{"type":"substance name","value":"Gaseous water"}]	<h1 class="questionTitle" itemprop="name">What is a balanced chemical equation, including physical state symbols, for the combustion of gaseous ethane into gaseous carbon dioxide and gaseous water?</h1>	null	H3C-CH3(g) + 7/2 O2(g) -> 2 CO2(g) + 3 H2O(g)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So two questions: is mass balanced?; is charge balanced? If you like you can double the equation to eliminate the half-integral coefficient; the mass transfer, the <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> is still the same. And what does the symbol <mathjax>#Delta#</mathjax> mean in relation to the reaction?</p> <p>What about <mathjax>#"methane"#</mathjax>, what about <mathjax>#"propane"#</mathjax>?</p> <p>Normally, we would present the reactants and products in their standard states under standard conditions......</p> <p><mathjax>#H_3C-CH_3(g) + 7/2O_2(g) rarr 2CO_2(g) + 3H_2O(l) +Delta_2#</mathjax></p> <p><mathjax>#Delta_2>Delta_1#</mathjax>...........why?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#H_3C-CH_3(g) + 7/2O_2(g) rarr 2CO_2(g) + 3H_2O(g) +Delta_1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So two questions: is mass balanced?; is charge balanced? If you like you can double the equation to eliminate the half-integral coefficient; the mass transfer, the <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> is still the same. And what does the symbol <mathjax>#Delta#</mathjax> mean in relation to the reaction?</p> <p>What about <mathjax>#"methane"#</mathjax>, what about <mathjax>#"propane"#</mathjax>?</p> <p>Normally, we would present the reactants and products in their standard states under standard conditions......</p> <p><mathjax>#H_3C-CH_3(g) + 7/2O_2(g) rarr 2CO_2(g) + 3H_2O(l) +Delta_2#</mathjax></p> <p><mathjax>#Delta_2>Delta_1#</mathjax>...........why?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is a balanced chemical equation, including physical state symbols, for the combustion of gaseous ethane into gaseous carbon dioxide and gaseous water?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="437412" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-10T08:58:48" itemprop="dateCreated"> Jun 10, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#H_3C-CH_3(g) + 7/2O_2(g) rarr 2CO_2(g) + 3H_2O(g) +Delta_1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So two questions: is mass balanced?; is charge balanced? If you like you can double the equation to eliminate the half-integral coefficient; the mass transfer, the <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> is still the same. And what does the symbol <mathjax>#Delta#</mathjax> mean in relation to the reaction?</p> <p>What about <mathjax>#"methane"#</mathjax>, what about <mathjax>#"propane"#</mathjax>?</p> <p>Normally, we would present the reactants and products in their standard states under standard conditions......</p> <p><mathjax>#H_3C-CH_3(g) + 7/2O_2(g) rarr 2CO_2(g) + 3H_2O(l) +Delta_2#</mathjax></p> <p><mathjax>#Delta_2>Delta_1#</mathjax>...........why?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/437412" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------> H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -> Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? 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Sodium phosphate and calcium chloride react to form... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-equation-kclo3-kcl-o2"> How can I balance this equation? ____ #KClO_3 -># ____ #KCl +# ____ #O_2# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-balancing-chemical-equations-important"> Why is balancing chemical equations important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/balancing-chemical-equations"> See all questions in Balancing Chemical Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 4147 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is a balanced chemical equation, including physical state symbols, for the combustion of gaseous ethane into gaseous carbon dioxide and gaseous water?	null
796	ac81f0ad-6ddd-11ea-bf96-ccda262736ce	https://socratic.org/questions/what-is-the-ph-of-a-6-7x10-5-m-h-solution	4.17	start physical_unit 10 11 ph none qc_end physical_unit 10 11 6 9 molarity qc_end end	[{"type":"physical unit","value":"pH [OF] H+ solution"}]	[{"type":"physical unit","value":"4.17"}]	[{"type":"physical unit","value":"Molarity [OF] H+ solution [=] \\pu{6.7 × 10^(-5) M}"}]	<h1 class="questionTitle" itemprop="name">What is the pH of a #6.7x10^-5#M #H^+# solution?</h1>	null	4.17	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#pH=-log_(10)(6.7xx10^-5)#</mathjax> <mathjax>#~=#</mathjax> <mathjax>#4#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#pH=-log_(10)[H^+]#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#pH=-log_(10)(6.7xx10^-5)#</mathjax> <mathjax>#~=#</mathjax> <mathjax>#4#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the pH of a #6.7x10^-5#M #H^+# solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/ph-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">pH calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="283603" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-01T17:07:52" itemprop="dateCreated"> Jul 1, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#pH=-log_(10)[H^+]#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#pH=-log_(10)(6.7xx10^-5)#</mathjax> <mathjax>#~=#</mathjax> <mathjax>#4#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/283603" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-of-a-solution"> How do you determine ph of a solution? 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797	a8d44f7c-6ddd-11ea-8cb9-ccda262736ce	https://socratic.org/questions/if-213-j-raises-a-sample-of-water-8-2-c-what-is-the-mass-of-the-water	6.2 grams	start physical_unit 15 16 mass g qc_end physical_unit 5 7 1 2 energy qc_end physical_unit 5 7 8 9 temperature qc_end end	[{"type":"physical unit","value":"Mass [OF] the water [IN] grams"}]	[{"type":"physical unit","value":"6.2 grams"}]	[{"type":"physical unit","value":"Needed energy [OF] water sample [=] \\pu{213 J}"},{"type":"physical unit","value":"Raised temperature [OF] water sample [=] \\pu{8.2 ℃}"}]	<h1 class="questionTitle" itemprop="name">If 213 J raises a sample of water 8.2°C, what is the mass of the water? </h1>	null	6.2 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use the formula <mathjax>#q=mCΔT#</mathjax></p> <p>q = heat absorbed or released, in joules (J)<br/> m = mass<br/> C = <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> capacity (for water, it is <mathjax>#4.18 J / (g * K)#</mathjax>)<br/> ΔT = change in temperature</p> <p><strong>Plug known values into the formula.</strong></p> <p><mathjax>#213 = m(4.18)(8.2)#</mathjax><br/> <mathjax>#213 = 34.276m#</mathjax><br/> <mathjax>#6.214260707 = m#</mathjax></p> <p>The answer, expressed in 2 <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a>, is <strong>6.2 g.</strong> </p> <p>Hope this helps!</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>6.2 g</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use the formula <mathjax>#q=mCΔT#</mathjax></p> <p>q = heat absorbed or released, in joules (J)<br/> m = mass<br/> C = <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> capacity (for water, it is <mathjax>#4.18 J / (g * K)#</mathjax>)<br/> ΔT = change in temperature</p> <p><strong>Plug known values into the formula.</strong></p> <p><mathjax>#213 = m(4.18)(8.2)#</mathjax><br/> <mathjax>#213 = 34.276m#</mathjax><br/> <mathjax>#6.214260707 = m#</mathjax></p> <p>The answer, expressed in 2 <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a>, is <strong>6.2 g.</strong> </p> <p>Hope this helps!</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">If 213 J raises a sample of water 8.2°C, what is the mass of the water? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/calorimetry" itemprop="url"> <span class="breadcrumb" itemprop="title">Calorimetry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="447036" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/michelle-33"><img alt="" class="" src="https://profilepictures.socratic.org/QwvZBefRmOXvj0OScuwA_bfb655b5a099a18b5c1023c5f8de9367--violet-aesthetic-pastel-tumblr-purple-aesthetic.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/michelle-33"> Michelle </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-07-02T14:37:02" itemprop="dateCreated"> Jul 2, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>6.2 g</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use the formula <mathjax>#q=mCΔT#</mathjax></p> <p>q = heat absorbed or released, in joules (J)<br/> m = mass<br/> C = <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> capacity (for water, it is <mathjax>#4.18 J / (g * K)#</mathjax>)<br/> ΔT = change in temperature</p> <p><strong>Plug known values into the formula.</strong></p> <p><mathjax>#213 = m(4.18)(8.2)#</mathjax><br/> <mathjax>#213 = 34.276m#</mathjax><br/> <mathjax>#6.214260707 = m#</mathjax></p> <p>The answer, expressed in 2 <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a>, is <strong>6.2 g.</strong> </p> <p>Hope this helps!</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/447036" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-differential-scanning-in-calorimetry-work"> How does differential scanning in calorimetry work? 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798	abe679a8-6ddd-11ea-874c-ccda262736ce	https://socratic.org/questions/what-is-the-balanced-equation-for-the-combustion-of-ethanol	C2H5OH(l) + 7/2 O2(g) -> 2 CO2(g) + 3 H2O(l)	start chemical_equation qc_end substance 9 9 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the combustion"}]	[{"type":"chemical equation","value":"C2H5OH(l) + 7/2 O2(g) -> 2 CO2(g) + 3 H2O(l)"}]	[{"type":"substance name","value":"Ethanol"}]	<h1 class="questionTitle" itemprop="name">What is the balanced equation for the combustion of ethanol?</h1>	null	C2H5OH(l) + 7/2 O2(g) -> 2 CO2(g) + 3 H2O(l)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Is the equation above balanced? How do you know? Can I have half a molecule of oxygen? Note that the equation is not only balanced stoichiometrically, it is balanced energetically, in that the combustion of a given quantity of ethanol will give rise to a given quantity of energy. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#H_3C-CH_2OH(l) + 7/2O_2(g) rarr 2CO_2(g) + 3H_2O(l)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Is the equation above balanced? How do you know? Can I have half a molecule of oxygen? Note that the equation is not only balanced stoichiometrically, it is balanced energetically, in that the combustion of a given quantity of ethanol will give rise to a given quantity of energy. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the balanced equation for the combustion of ethanol?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-reactions-and-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions and Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="200572" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-17T03:54:44" itemprop="dateCreated"> Dec 17, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#H_3C-CH_2OH(l) + 7/2O_2(g) rarr 2CO_2(g) + 3H_2O(l)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Is the equation above balanced? How do you know? Can I have half a molecule of oxygen? Note that the equation is not only balanced stoichiometrically, it is balanced energetically, in that the combustion of a given quantity of ethanol will give rise to a given quantity of energy. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/200572" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb002bf34694a4fee47"> Question #fee47 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb402bf34694c8c5c15"> Question #c5c15 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb802bf346950519eb9"> Question #19eb9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cbf02bf3469570e2ea2"> Question #e2ea2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc002bf34695a6bc751"> Question #bc751 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc202bf3469570e2ea6"> Question #e2ea6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531e867a02bf342492a08b07"> Question #08b07 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-thermochemical-equation-for-the-combustion-of-benzene"> What is the thermochemical equation for the combustion of benzene? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-reversible"> Why are chemical reactions reversible? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-important"> Why are chemical reactions important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/chemical-reactions-and-equations"> See all questions in Chemical Reactions and Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 4351 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the balanced equation for the combustion of ethanol?	null
799	a9e174c6-6ddd-11ea-bada-ccda262736ce	https://socratic.org/questions/if-a-solution-is-0-5-w-v-how-many-mg-ml-is-that	5 mg/ml	start physical_unit 2 2 concentration mg/ml qc_end end	[{"type":"physical unit","value":"Concentration [OF] solution [IN] mg/ml"}]	[{"type":"physical unit","value":"5 mg/ml"}]	[{"type":"physical unit","value":"w/v [OF] solute in solution [=] \\pu{0.5%}"}]	<h1 class="questionTitle" itemprop="name">If a solution is 0.5% (w/v), how many mg/ml is that? </h1>	null	5 mg/ml	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The solution's <strong>mass by volume <a href="https://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration</a></strong>, <mathjax>#"m/v %"#</mathjax>, tells you the number of grams of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> present for every <mathjax>#"100 mL"#</mathjax> of the solution. </p> <p>In your case, the solution is said to have a mass by volume percent concentration of <mathjax>#0.5%#</mathjax>, which means that you get <mathjax>#"0.5 g"#</mathjax> of solute for every <mathjax>#"100 mL"#</mathjax> of the solution. </p> <blockquote> <p><mathjax>#color(blue)(0.5)color(darkorange)(%) quad "m/v" = color(blue)("0.5 g") quad "solute per" quad color(darkorange)("100 mL") quad "of the solution"#</mathjax></p> </blockquote> <p>You can thus say that <mathjax>#"1 mL"#</mathjax> of this solution will contain </p> <blockquote> <p><mathjax>#1 color(red)(cancel(color(black)("mL solution"))) * "0.5 g solute"/(100color(red)(cancel(color(black)("mL solution")))) = "0.005 g solute"#</mathjax></p> </blockquote> <p>To convert this to <em>milligrams</em>, use the fact that</p> <blockquote> <p><mathjax>#"1 g" = 10^3 quad "mg"#</mathjax></p> </blockquote> <p>You will end up with</p> <blockquote> <p><mathjax>#0.005 color(red)(cancel(color(black)("g"))) * (10^3 quad "mg")/(1color(red)(cancel(color(black)("g")))) = "5 mg"#</mathjax></p> </blockquote> <p>Since this represents the number of milligrams of solute present for every <mathjax>#"1 mL"#</mathjax> of the solution, you can say that the solution has a concentration of </p> <blockquote> <p><mathjax>#"concentration" = color(darkgreen)(ul(color(black)("5 mg mL"^(-1))))#</mathjax></p> </blockquote> <p>The answer is rounded to one <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figure</a></strong>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"5 mg mL"^(-1)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The solution's <strong>mass by volume <a href="https://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration</a></strong>, <mathjax>#"m/v %"#</mathjax>, tells you the number of grams of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> present for every <mathjax>#"100 mL"#</mathjax> of the solution. </p> <p>In your case, the solution is said to have a mass by volume percent concentration of <mathjax>#0.5%#</mathjax>, which means that you get <mathjax>#"0.5 g"#</mathjax> of solute for every <mathjax>#"100 mL"#</mathjax> of the solution. </p> <blockquote> <p><mathjax>#color(blue)(0.5)color(darkorange)(%) quad "m/v" = color(blue)("0.5 g") quad "solute per" quad color(darkorange)("100 mL") quad "of the solution"#</mathjax></p> </blockquote> <p>You can thus say that <mathjax>#"1 mL"#</mathjax> of this solution will contain </p> <blockquote> <p><mathjax>#1 color(red)(cancel(color(black)("mL solution"))) * "0.5 g solute"/(100color(red)(cancel(color(black)("mL solution")))) = "0.005 g solute"#</mathjax></p> </blockquote> <p>To convert this to <em>milligrams</em>, use the fact that</p> <blockquote> <p><mathjax>#"1 g" = 10^3 quad "mg"#</mathjax></p> </blockquote> <p>You will end up with</p> <blockquote> <p><mathjax>#0.005 color(red)(cancel(color(black)("g"))) * (10^3 quad "mg")/(1color(red)(cancel(color(black)("g")))) = "5 mg"#</mathjax></p> </blockquote> <p>Since this represents the number of milligrams of solute present for every <mathjax>#"1 mL"#</mathjax> of the solution, you can say that the solution has a concentration of </p> <blockquote> <p><mathjax>#"concentration" = color(darkgreen)(ul(color(black)("5 mg mL"^(-1))))#</mathjax></p> </blockquote> <p>The answer is rounded to one <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figure</a></strong>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">If a solution is 0.5% (w/v), how many mg/ml is that? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/percent-concentration" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Concentration</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="590953" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-04-09T00:02:53" itemprop="dateCreated"> Apr 9, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"5 mg mL"^(-1)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The solution's <strong>mass by volume <a href="https://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration</a></strong>, <mathjax>#"m/v %"#</mathjax>, tells you the number of grams of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> present for every <mathjax>#"100 mL"#</mathjax> of the solution. </p> <p>In your case, the solution is said to have a mass by volume percent concentration of <mathjax>#0.5%#</mathjax>, which means that you get <mathjax>#"0.5 g"#</mathjax> of solute for every <mathjax>#"100 mL"#</mathjax> of the solution. </p> <blockquote> <p><mathjax>#color(blue)(0.5)color(darkorange)(%) quad "m/v" = color(blue)("0.5 g") quad "solute per" quad color(darkorange)("100 mL") quad "of the solution"#</mathjax></p> </blockquote> <p>You can thus say that <mathjax>#"1 mL"#</mathjax> of this solution will contain </p> <blockquote> <p><mathjax>#1 color(red)(cancel(color(black)("mL solution"))) * "0.5 g solute"/(100color(red)(cancel(color(black)("mL solution")))) = "0.005 g solute"#</mathjax></p> </blockquote> <p>To convert this to <em>milligrams</em>, use the fact that</p> <blockquote> <p><mathjax>#"1 g" = 10^3 quad "mg"#</mathjax></p> </blockquote> <p>You will end up with</p> <blockquote> <p><mathjax>#0.005 color(red)(cancel(color(black)("g"))) * (10^3 quad "mg")/(1color(red)(cancel(color(black)("g")))) = "5 mg"#</mathjax></p> </blockquote> <p>Since this represents the number of milligrams of solute present for every <mathjax>#"1 mL"#</mathjax> of the solution, you can say that the solution has a concentration of </p> <blockquote> <p><mathjax>#"concentration" = color(darkgreen)(ul(color(black)("5 mg mL"^(-1))))#</mathjax></p> </blockquote> <p>The answer is rounded to one <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figure</a></strong>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/590953" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-concentration-of-water-in-solution-be-decreased"> How can the concentration of water in solution be decreased? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-concentration-of-a-solution-be-increased"> How can the concentration of a solution be increased? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-concentration-of-a-solution-in-ppm"> How do you find the concentration of a solution in ppm? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-make-a-10-percent-solution"> How do you make a 10 percent solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-make-a-2-percent-solution"> How do you make a 2 percent solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-weight-per-volume-method-to-calculate-concentration"> What is the weight per volume method to calculate concentration? 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