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1,000	aad18ed0-6ddd-11ea-81db-ccda262736ce	https://socratic.org/questions/a-sample-of-nitrogen-gas-is-collected-over-water-at-20-c-the-vapor-pressure-of-w	747 mmHg	start physical_unit 29 30 partial_pressure mmhg qc_end physical_unit 1 4 10 11 temperature qc_end physical_unit 8 8 21 22 vapor_pressure qc_end physical_unit 8 8 10 11 temperature qc_end end	[{"type":"physical unit","value":"Partial pressure [OF] the nitrogen [IN] mmHg"}]	[{"type":"physical unit","value":"747 mmHg"}]	[{"type":"physical unit","value":"Temperature [OF] nitrogen gas sample [=] \\pu{20 ℃}"},{"type":"physical unit","value":"Vapor pressure [OF] water [=] \\pu{18 mmHg}"},{"type":"physical unit","value":"Temperature [OF] water [=] \\pu{20 ℃}"},{"type":"physical unit","value":"Total pressure [OF] the system [=] \\pu{765 mmHg}"}]	<h1 class="questionTitle" itemprop="name">A sample of nitrogen gas is collected over water at 20°C. The vapor pressure of water at 20°C is 18 mmHg. What is the partial pressure of the nitrogen if the total pressure is 765 mmHg?</h1>	null	747 mmHg	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#P_"SVP"#</mathjax> is the saturated vapour pressure, which is the vapour pressure of water, and is extensively tabulated across a range of temperatures. Of course, at <mathjax>#100#</mathjax> <mathjax>#""^@C#</mathjax> the saturated vapour pressure is <mathjax>#1#</mathjax> <mathjax>#atm#</mathjax>. Why?</p> <p>So if we want <mathjax>#P_"Gas"#</mathjax> (which we do), all we have to do is subtract <mathjax>#P_"SVP"#</mathjax> from <mathjax>#P_"measured"#</mathjax></p> <p><mathjax>#P_"measured"-P_"SVP"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#P_"Gas"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(765-18)mmHg#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#P_"measured"=P_"SVP"+P_"Gas"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#P_"SVP"#</mathjax> is the saturated vapour pressure, which is the vapour pressure of water, and is extensively tabulated across a range of temperatures. Of course, at <mathjax>#100#</mathjax> <mathjax>#""^@C#</mathjax> the saturated vapour pressure is <mathjax>#1#</mathjax> <mathjax>#atm#</mathjax>. Why?</p> <p>So if we want <mathjax>#P_"Gas"#</mathjax> (which we do), all we have to do is subtract <mathjax>#P_"SVP"#</mathjax> from <mathjax>#P_"measured"#</mathjax></p> <p><mathjax>#P_"measured"-P_"SVP"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#P_"Gas"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(765-18)mmHg#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A sample of nitrogen gas is collected over water at 20°C. The vapor pressure of water at 20°C is 18 mmHg. What is the partial pressure of the nitrogen if the total pressure is 765 mmHg?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/partial-pressure" itemprop="url"> <span class="breadcrumb" itemprop="title">Partial Pressure</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="276798" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-13T05:09:07" itemprop="dateCreated"> Jun 13, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#P_"measured"=P_"SVP"+P_"Gas"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#P_"SVP"#</mathjax> is the saturated vapour pressure, which is the vapour pressure of water, and is extensively tabulated across a range of temperatures. Of course, at <mathjax>#100#</mathjax> <mathjax>#""^@C#</mathjax> the saturated vapour pressure is <mathjax>#1#</mathjax> <mathjax>#atm#</mathjax>. Why?</p> <p>So if we want <mathjax>#P_"Gas"#</mathjax> (which we do), all we have to do is subtract <mathjax>#P_"SVP"#</mathjax> from <mathjax>#P_"measured"#</mathjax></p> <p><mathjax>#P_"measured"-P_"SVP"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#P_"Gas"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(765-18)mmHg#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/276798" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/534e256802bf342adfa30010"> How do you do a steam distillation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/53613f9f02bf3416cd9f8a34"> Question #f8a34 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-i-calculate-the-total-pressure-of-a-mixture-of-gases-by-adding-together-the-"> Can I calculate the total pressure of a mixture of gases by adding together the partial... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-formula-of-partial-pressure"> What is the formula of partial pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-dalton-s-law-of-partial-pressures"> What is the Dalton's law of partial pressures? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/nitrogen-gas-n2-reacts-with-hydrogen-gas-h2-to-form-ammonia-nh3-at-200-c-in-a-cl"> Nitrogen gas (N2) reacts with hydrogen gas (H2) to form ammonia (NH3). 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The vapor pressure of water at 20°C is 18 mmHg. What is the partial pressure of the nitrogen if the total pressure is 765 mmHg?	null
1,001	aa8df0d9-6ddd-11ea-a162-ccda262736ce	https://socratic.org/questions/how-many-moles-is-573-28-g-of-agcl	4.00 moles	start physical_unit 7 7 mole mol qc_end physical_unit 7 7 4 5 mass qc_end end	[{"type":"physical unit","value":"Mole [OF] AgCl [IN] moles"}]	[{"type":"physical unit","value":"4.00 moles"}]	[{"type":"physical unit","value":"Mass [OF] AgCl [=] \\pu{573.28 g}"}]	<h1 class="questionTitle" itemprop="name">How many moles is 573.28 g of #AgCl#? </h1>	null	4.00 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Find the relative mass of <mathjax>#AgCl#</mathjax> by adding together the relative <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">atomic mass</a> of each atom in the compound, </p> <p><mathjax>#107.868gmol^-1Ag + 35.45gmol^-1Cl = 143.318gmol^-1AgCl#</mathjax></p> <p>Divide the total mass of how much <mathjax>#AgCl#</mathjax> by the mass per mole to give you the number of moles,</p> <p><mathjax>#(573.28g)/(143.318gmol^-1)AgCl = 4.00molAgCl#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#4.00molAgCl#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Find the relative mass of <mathjax>#AgCl#</mathjax> by adding together the relative <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">atomic mass</a> of each atom in the compound, </p> <p><mathjax>#107.868gmol^-1Ag + 35.45gmol^-1Cl = 143.318gmol^-1AgCl#</mathjax></p> <p>Divide the total mass of how much <mathjax>#AgCl#</mathjax> by the mass per mole to give you the number of moles,</p> <p><mathjax>#(573.28g)/(143.318gmol^-1)AgCl = 4.00molAgCl#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles is 573.28 g of #AgCl#? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="251869" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/reudhreghs"><img alt="" class="" src="https://profilepictures.socratic.org/cbvHaqiiRa2eTNL3y20D_Just%20monkeying%20around%20%F0%9F%90%92%F0%9F%98%8D%F0%9F%8C%9E.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/reudhreghs"> reudhreghs </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-04-09T13:37:46" itemprop="dateCreated"> Apr 9, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#4.00molAgCl#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Find the relative mass of <mathjax>#AgCl#</mathjax> by adding together the relative <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">atomic mass</a> of each atom in the compound, </p> <p><mathjax>#107.868gmol^-1Ag + 35.45gmol^-1Cl = 143.318gmol^-1AgCl#</mathjax></p> <p>Divide the total mass of how much <mathjax>#AgCl#</mathjax> by the mass per mole to give you the number of moles,</p> <p><mathjax>#(573.28g)/(143.318gmol^-1)AgCl = 4.00molAgCl#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/251869" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? 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1,002	ab001b62-6ddd-11ea-8447-ccda262736ce	https://socratic.org/questions/58239abbb72cff56ee506a9b	140 grams	start physical_unit 9 9 mass g qc_end physical_unit 9 9 7 8 mole qc_end end	[{"type":"physical unit","value":"Mass [OF] Ca [IN] grams"}]	[{"type":"physical unit","value":"140 grams"}]	[{"type":"physical unit","value":"Mole [OF] Ca [=] \\pu{3.5 moles}"}]	<h1 class="questionTitle" itemprop="name">What is the mass in grams of #"3.5 moles Ca"#?</h1>	null	140 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First determine the molar mass of calcium. Molar mass is the mass in grams in one mole of a substance. For <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a>, we just need the atomic weight on <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a> written as g/mol.</p> <p>The molar mass of calcium is 40.078 g/mol.</p> <p>Now multiply the given number of moles of <mathjax>#"Ca"#</mathjax> by its molar mass.</p> <p><mathjax>#3.5 cancel"mol" "Ca"xx40.078"g"/cancel"mol"="140 g Ca"#</mathjax> to two significant figures</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The mass of 3.5 moles of Ca is 140 g to two <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First determine the molar mass of calcium. Molar mass is the mass in grams in one mole of a substance. For <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a>, we just need the atomic weight on <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a> written as g/mol.</p> <p>The molar mass of calcium is 40.078 g/mol.</p> <p>Now multiply the given number of moles of <mathjax>#"Ca"#</mathjax> by its molar mass.</p> <p><mathjax>#3.5 cancel"mol" "Ca"xx40.078"g"/cancel"mol"="140 g Ca"#</mathjax> to two significant figures</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the mass in grams of #"3.5 moles Ca"#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="333998" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-11-09T22:19:17" itemprop="dateCreated"> Nov 9, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The mass of 3.5 moles of Ca is 140 g to two <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First determine the molar mass of calcium. Molar mass is the mass in grams in one mole of a substance. For <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a>, we just need the atomic weight on <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a> written as g/mol.</p> <p>The molar mass of calcium is 40.078 g/mol.</p> <p>Now multiply the given number of moles of <mathjax>#"Ca"#</mathjax> by its molar mass.</p> <p><mathjax>#3.5 cancel"mol" "Ca"xx40.078"g"/cancel"mol"="140 g Ca"#</mathjax> to two significant figures</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/333998" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 11255 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the mass in grams of #"3.5 moles Ca"#?	null
1,003	aa78c8ac-6ddd-11ea-a2cc-ccda262736ce	https://socratic.org/questions/how-do-you-convert-3-01-x-23-atoms-of-silicon-to-moles-of-silicon	0.50 moles	start physical_unit 9 9 mole mol qc_end end	[{"type":"physical unit","value":"Mole [OF] silicon [IN] moles"}]	[{"type":"physical unit","value":"0.50 moles"}]	[{"type":"physical unit","value":"Number [OF] silicon atoms [=] \\pu{3.01 × 10^23}"}]	<h1 class="questionTitle" itemprop="name">How do you convert 3.01 x 23 atoms of silicon to moles of silicon?</h1>	null	0.50 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So <mathjax>#(3.01xx10^23)/(6.022xx10^23mol^-1)#</mathjax> is clearly 1/2 a mole of silicon atoms.</p> <p>You should be quickly able to tell me the mass of this quantity of silicon atoms. What is it?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Divide the given number by <mathjax>#"Avogadro's number, "6.022xx10^23mol^-1#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So <mathjax>#(3.01xx10^23)/(6.022xx10^23mol^-1)#</mathjax> is clearly 1/2 a mole of silicon atoms.</p> <p>You should be quickly able to tell me the mass of this quantity of silicon atoms. What is it?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you convert 3.01 x 23 atoms of silicon to moles of silicon?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="301847" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-08-23T07:33:17" itemprop="dateCreated"> Aug 23, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Divide the given number by <mathjax>#"Avogadro's number, "6.022xx10^23mol^-1#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So <mathjax>#(3.01xx10^23)/(6.022xx10^23mol^-1)#</mathjax> is clearly 1/2 a mole of silicon atoms.</p> <p>You should be quickly able to tell me the mass of this quantity of silicon atoms. What is it?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/301847" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 14390 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How do you convert 3.01 x 23 atoms of silicon to moles of silicon?	null
1,004	a9412b42-6ddd-11ea-8398-ccda262736ce	https://socratic.org/questions/ammonia-gas-decomposes-according-to-the-equation-2nh-3-g-n-2-g-3h-2-g-if-15-0-l-	45.0 liters	start physical_unit 27 27 volume l qc_end chemical_equation 7 13 qc_end physical_unit 18 18 15 16 volume qc_end c_other STP qc_end end	[{"type":"physical unit","value":"Volume [OF] hydrogen [IN] liters"}]	[{"type":"physical unit","value":"45.0 liters"}]	[{"type":"chemical equation","value":"2 NH3(g) -> N2(g) + 3 H2(g)"},{"type":"physical unit","value":"Volume [OF] nitrogen [=] \\pu{15.0 L}"},{"type":"other","value":"STP"}]	<h1 class="questionTitle" itemprop="name">Ammonia gas decomposes according to the equation: #2NH_3(g) -> N_2(g) + 3H_2(g)#. If 15.0 L of nitrogen is formed at STP, how many liters of hydrogen will be produced (also measured at STP)? </h1>	null	45.0 liters	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The thing to remember about reactions that involve gases held under the <strong>same conditions for pressure and temperature</strong> is that the <strong>mole ratio</strong> that exists between the gaseous <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a> in the balanced chemical equation is <strong>equivalent</strong> to a <em><strong>volume ratio</strong></em>. </p> <p>The balanced chemical equation that describes your reaction looks like this</p> <blockquote> <p><mathjax>#2"NH"_ (3(g)) -> "N"_ (2(g)) + color(red)(3)"H"_ (2(g))#</mathjax></p> </blockquote> <p>Notice that for <strong>every</strong> <mathjax>#2#</mathjax> <strong>moles</strong> of ammonia that take part in the reaction, you get <mathjax>#1#</mathjax> <strong>mole</strong> of nitrogen gas and <mathjax>#color(red)(3)#</mathjax> <strong>moles</strong> of hydrogen gas. </p> <p>When all three gases are kept under the <strong>same conditions for pressure and temperature</strong>, these <a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratios</a> become equivalent to volume ratios. More specifically, you know that nitrogen gas and hydrogen gas have a <mathjax>#1:color(red)(3)#</mathjax> <strong>mole ratio</strong>. </p> <p>When both gases are kept under <strong>STP conditions</strong>, you will have</p> <blockquote> <p><mathjax>#color(purple)(\|bar(ul(color(white)(a/a)color(black)(n_ ("N"_ 2)/n_ ("H"_ 2) = V_ ("N"_ 2)/V_ ("H"_ 2))color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>In this case, you have a <mathjax>#1:color(red)(3)#</mathjax> <strong>volume ratio</strong> between nitrogen gas and hydrogen gas. This means that you get</p> <blockquote> <p><mathjax>#1/color(red)(3) = V_ ("N"_ 2)/V_ ("H"_ 2) implies V_ ("H"_ 2) = color(red)(3) xx V_("N"_2)#</mathjax></p> </blockquote> <p>Plug in your values to find</p> <blockquote> <p><mathjax>#V_("H"_2) = color(red)(3) xx "15.0 L" = color(green)(\|bar(ul(color(white)(a/a)color(black)("45.0 L")color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"45.0 L"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The thing to remember about reactions that involve gases held under the <strong>same conditions for pressure and temperature</strong> is that the <strong>mole ratio</strong> that exists between the gaseous <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a> in the balanced chemical equation is <strong>equivalent</strong> to a <em><strong>volume ratio</strong></em>. </p> <p>The balanced chemical equation that describes your reaction looks like this</p> <blockquote> <p><mathjax>#2"NH"_ (3(g)) -> "N"_ (2(g)) + color(red)(3)"H"_ (2(g))#</mathjax></p> </blockquote> <p>Notice that for <strong>every</strong> <mathjax>#2#</mathjax> <strong>moles</strong> of ammonia that take part in the reaction, you get <mathjax>#1#</mathjax> <strong>mole</strong> of nitrogen gas and <mathjax>#color(red)(3)#</mathjax> <strong>moles</strong> of hydrogen gas. </p> <p>When all three gases are kept under the <strong>same conditions for pressure and temperature</strong>, these <a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratios</a> become equivalent to volume ratios. More specifically, you know that nitrogen gas and hydrogen gas have a <mathjax>#1:color(red)(3)#</mathjax> <strong>mole ratio</strong>. </p> <p>When both gases are kept under <strong>STP conditions</strong>, you will have</p> <blockquote> <p><mathjax>#color(purple)(\|bar(ul(color(white)(a/a)color(black)(n_ ("N"_ 2)/n_ ("H"_ 2) = V_ ("N"_ 2)/V_ ("H"_ 2))color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>In this case, you have a <mathjax>#1:color(red)(3)#</mathjax> <strong>volume ratio</strong> between nitrogen gas and hydrogen gas. This means that you get</p> <blockquote> <p><mathjax>#1/color(red)(3) = V_ ("N"_ 2)/V_ ("H"_ 2) implies V_ ("H"_ 2) = color(red)(3) xx V_("N"_2)#</mathjax></p> </blockquote> <p>Plug in your values to find</p> <blockquote> <p><mathjax>#V_("H"_2) = color(red)(3) xx "15.0 L" = color(green)(\|bar(ul(color(white)(a/a)color(black)("45.0 L")color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Ammonia gas decomposes according to the equation: #2NH_3(g) -> N_2(g) + 3H_2(g)#. If 15.0 L of nitrogen is formed at STP, how many liters of hydrogen will be produced (also measured at STP)? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/stoichiometry-involving-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="289949" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-20T00:53:10" itemprop="dateCreated"> Jul 20, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"45.0 L"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The thing to remember about reactions that involve gases held under the <strong>same conditions for pressure and temperature</strong> is that the <strong>mole ratio</strong> that exists between the gaseous <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a> in the balanced chemical equation is <strong>equivalent</strong> to a <em><strong>volume ratio</strong></em>. </p> <p>The balanced chemical equation that describes your reaction looks like this</p> <blockquote> <p><mathjax>#2"NH"_ (3(g)) -> "N"_ (2(g)) + color(red)(3)"H"_ (2(g))#</mathjax></p> </blockquote> <p>Notice that for <strong>every</strong> <mathjax>#2#</mathjax> <strong>moles</strong> of ammonia that take part in the reaction, you get <mathjax>#1#</mathjax> <strong>mole</strong> of nitrogen gas and <mathjax>#color(red)(3)#</mathjax> <strong>moles</strong> of hydrogen gas. </p> <p>When all three gases are kept under the <strong>same conditions for pressure and temperature</strong>, these <a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratios</a> become equivalent to volume ratios. More specifically, you know that nitrogen gas and hydrogen gas have a <mathjax>#1:color(red)(3)#</mathjax> <strong>mole ratio</strong>. </p> <p>When both gases are kept under <strong>STP conditions</strong>, you will have</p> <blockquote> <p><mathjax>#color(purple)(\|bar(ul(color(white)(a/a)color(black)(n_ ("N"_ 2)/n_ ("H"_ 2) = V_ ("N"_ 2)/V_ ("H"_ 2))color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>In this case, you have a <mathjax>#1:color(red)(3)#</mathjax> <strong>volume ratio</strong> between nitrogen gas and hydrogen gas. This means that you get</p> <blockquote> <p><mathjax>#1/color(red)(3) = V_ ("N"_ 2)/V_ ("H"_ 2) implies V_ ("H"_ 2) = color(red)(3) xx V_("N"_2)#</mathjax></p> </blockquote> <p>Plug in your values to find</p> <blockquote> <p><mathjax>#V_("H"_2) = color(red)(3) xx "15.0 L" = color(green)(\|bar(ul(color(white)(a/a)color(black)("45.0 L")color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/289949" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-apply-gas-stoichiometry"> How do you apply gas stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-solve-a-gas-law-stoichiometry-problem"> How do you solve a gas law stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-do-gas-stoichiometry-problems-at-stp"> How do you do gas stoichiometry problems at STP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-an-agno3-solution-is-treated-with-50-0-ml-of-hi-gas-to-give-0-235-g-of-agi-"> When an AgNO3 solution is treated with 50.0 mL of HI gas to give 0.235 g of AgI, what is the... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-10-0-ml-of-agno3-solution-is-treated-with-excess-amount-of-hi-gas-to-give-0"> When 10.0 mL of AgNO3 solution is treated with excess amount of HI gas to give 0.235 g of AgI,... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/hydrogen-sulfide-reacts-with-sulfur-dioxide-to-give-h2o-and-s-h2s-so2-h2o-s-soli"> Hydrogen sulfide reacts with sulfur dioxide to give H2O and S, H2S + SO2 = H2O + S(solid),... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-100-ml-of-hcl-gas-at-300-k-and-200-kpa-dissolved-in-pure-water-requires-12-50"> If 100 mL of HCl gas at 300 K and 200 kPa dissolved in pure water requires 12.50 mL of the NaOH... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-100-ml-of-hcl-gas-at-300-k-and-100-kpa-dissolved-in-pure-water-requires-12-50"> If 100 mL of HCl gas at 300 K and 100 kPa dissolved in pure water requires 12.50 mL of the NaOH... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-100-ml-of-hcl-gas-at-300-k-and-100-kpa-dissolve-in-20-ml-of-pure-water-what-i"> If 100 mL of HCl gas at 300 K and 100 kPa dissolve in 20 mL of pure water, what is the concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-2-00-g-mixture-of-na-and-ca-reat-with-water-1-164-l-hydrogen-was-produced-a"> When 2.00 g mixture of Na and Ca reat with water, 1.164 L hydrogen was produced at 300.0 K and... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/stoichiometry-involving-gases"> See all questions in Gas Stoichiometry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 25762 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Ammonia gas decomposes according to the equation: #2NH_3(g) -> N_2(g) + 3H_2(g)#. If 15.0 L of nitrogen is formed at STP, how many liters of hydrogen will be produced (also measured at STP)?	null
1,005	abc96309-6ddd-11ea-a1d0-ccda262736ce	https://socratic.org/questions/how-do-you-balance-the-equation-n2o5-no2-o2	2 N2O5 -> 4 NO2 + O2	start chemical_equation qc_end chemical_equation 6 10 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the equation"}]	[{"type":"chemical equation","value":"2 N2O5 -> 4 NO2 + O2"}]	[{"type":"chemical equation","value":"N2O5 -> NO2 + O2"}]	<h1 class="questionTitle" itemprop="name">How do you balance the equation _N2O5 -->_NO2+_O2? </h1>	null	2 N2O5 -> 4 NO2 + O2	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You have to count the number of nitrogens in the left side and be the same in the right side. 2*2=4 on the left, 4 on the right. Same for every element involved in the reaction</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2N_2O_5 -> 4NO_2 + O_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You have to count the number of nitrogens in the left side and be the same in the right side. 2*2=4 on the left, 4 on the right. Same for every element involved in the reaction</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you balance the equation _N2O5 -->_NO2+_O2? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="184564" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/apgt512"><img alt="" class="" src="https://profilepictures.socratic.org/1uF0g9QgSOuzxlhNBGXs_Laser.png" title=""/></a> <a class="secondContributorPic" href="/users/anahole"><img alt="" class="" src="https://profilepictures.socratic.org/du8Aj1C5RiRKl5jwGpNh_Enormous%20Za.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/apgt512"> Apgt512 </a>·<a class="topContributorLink" href="/users/anahole"> Anahole </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-06T04:26:58" itemprop="dateCreated"> Nov 6, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2N_2O_5 -> 4NO_2 + O_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You have to count the number of nitrogens in the left side and be the same in the right side. 2*2=4 on the left, 4 on the right. Same for every element involved in the reaction</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/184564" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------> H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -> Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? 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Sodium phosphate and calcium chloride react to form... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-equation-kclo3-kcl-o2"> How can I balance this equation? ____ #KClO_3 -># ____ #KCl +# ____ #O_2# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-balancing-chemical-equations-important"> Why is balancing chemical equations important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/balancing-chemical-equations"> See all questions in Balancing Chemical Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3037 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How do you balance the equation _N2O5 -->_NO2+_O2?	null
1,006	abfb77a8-6ddd-11ea-88e9-ccda262736ce	https://socratic.org/questions/a-helium-filled-balloon-escapes-a-child-s-hand-at-sea-level-and-23-0-c-when-it-r	1.5	start physical_unit 36 43 times none qc_end c_other OTHER qc_end physical_unit 1 2 11 12 temperature qc_end physical_unit 1 2 19 20 altitude qc_end physical_unit 1 2 25 26 temperature qc_end physical_unit 1 2 32 33 pressure qc_end end	[{"type":"physical unit","value":"Times [OF] its volume compare to that at sea level"}]	[{"type":"physical unit","value":"1.5"}]	[{"type":"other","value":"At sea level."},{"type":"physical unit","value":"Temperature1 [OF] helium-filled balloon [=] \\pu{23.0 ℃}"},{"type":"physical unit","value":"Altitude2 [OF] helium-filled balloon [=] \\pu{3000 m}"},{"type":"physical unit","value":"Temperature2 [OF] helium-filled balloon [=] \\pu{4.4 ℃}"},{"type":"physical unit","value":"Pressure2 [OF] helium-filled balloon [=] \\pu{0.71 atm}"}]	<h1 class="questionTitle" itemprop="name">A helium-filled balloon escapes a child's hand at sea level and 23.0 C. When it reaches an altitude of 3000 m, where the temperature is 4.4 C and the pressure is only 0.71 atm, how will its volume compare to that at sea level?</h1>	null	1.5	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The altitude itself is irrelevant. The <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> states <br/> <mathjax>#(P_1 * V_1)/T_1 = (P_2 * V_2)/T_2#</mathjax> The temperatures must be in ‘K for the ratio to be correct.</p> <p><mathjax>#(1atm * V_1)/296 = (0.71atm * V_2)/277.4#</mathjax></p> <p><mathjax>#V_1/V_2#</mathjax> = 277.4/296 * 0.71 ; <mathjax>#V_1/V_2#</mathjax> = 0.665</p> <p>Therefore, the volume at 3000m is 1/0.665 = 1.5 times larger than at sea level.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>It will be 1.5 times larger.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The altitude itself is irrelevant. The <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> states <br/> <mathjax>#(P_1 * V_1)/T_1 = (P_2 * V_2)/T_2#</mathjax> The temperatures must be in ‘K for the ratio to be correct.</p> <p><mathjax>#(1atm * V_1)/296 = (0.71atm * V_2)/277.4#</mathjax></p> <p><mathjax>#V_1/V_2#</mathjax> = 277.4/296 * 0.71 ; <mathjax>#V_1/V_2#</mathjax> = 0.665</p> <p>Therefore, the volume at 3000m is 1/0.665 = 1.5 times larger than at sea level.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A helium-filled balloon escapes a child's hand at sea level and 23.0 C. When it reaches an altitude of 3000 m, where the temperature is 4.4 C and the pressure is only 0.71 atm, how will its volume compare to that at sea level?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp" itemprop="url"> <span class="breadcrumb" itemprop="title">Molar Volume of a Gas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="311203" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/scooke"><img alt="" class="" src="https://profilepictures.socratic.org/ezAzqDkjRS6NXBmMH3lg_BioPic2010a.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/scooke"> SCooke </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-09-17T11:57:02" itemprop="dateCreated"> Sep 17, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>It will be 1.5 times larger.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The altitude itself is irrelevant. The <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> states <br/> <mathjax>#(P_1 * V_1)/T_1 = (P_2 * V_2)/T_2#</mathjax> The temperatures must be in ‘K for the ratio to be correct.</p> <p><mathjax>#(1atm * V_1)/296 = (0.71atm * V_2)/277.4#</mathjax></p> <p><mathjax>#V_1/V_2#</mathjax> = 277.4/296 * 0.71 ; <mathjax>#V_1/V_2#</mathjax> = 0.665</p> <p>Therefore, the volume at 3000m is 1/0.665 = 1.5 times larger than at sea level.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/311203" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-stoichiometric-ratios-relate-to-molar-volume-of-a-gas"> How do stoichiometric ratios relate to molar volume of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-a-gas-at-stp"> How do you calculate molar volume of a gas at STP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-molar-volume-of-hydrogen-gas"> How do you find the molar volume of hydrogen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-oxygen-gas"> How do you calculate molar volume of oxygen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molar-gas-volume"> What is molar gas volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/534c7bf202bf3420a007f014"> What is the volume at 0 °C and 1 atm of a mixture that contains 4.0 g of methane and 2.0 g of helium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5361f75702bf3429040e0599"> What is the difference between STP and NTP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-volume-of-25-moles-of-oxygen-o2-gas"> What is the volume of .25 moles of oxygen (O2) Gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-would-knowing-the-molar-volume-of-a-gas-be-important"> Why would knowing the molar volume of a gas be important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-22-4-liters-called-the-molar-volume-of-a-gas"> Why is 22.4 liters called the molar volume of a gas? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp"> See all questions in Molar Volume of a Gas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 7094 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A helium-filled balloon escapes a child's hand at sea level and 23.0 C. When it reaches an altitude of 3000 m, where the temperature is 4.4 C and the pressure is only 0.71 atm, how will its volume compare to that at sea level?	null
1,007	a8408080-6ddd-11ea-baa1-ccda262736ce	https://socratic.org/questions/what-is-the-formula-for-sodium-sulfate	Na2SO4	start chemical_formula qc_end substance 5 6 qc_end end	[{"type":"other","value":"Chemical Formula [OF] sodium sulfate [IN] default"}]	[{"type":"chemical equation","value":"Na2SO4"}]	[{"type":"substance name","value":"Sodium sulfate"}]	<h1 class="questionTitle" itemprop="name">What is the formula for sodium sulfate?</h1>	null	Na2SO4	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The sulfate ion, <mathjax>#SO_4^(2-)#</mathjax> is a very common ion counter ion, and has some aqueous solubility. In sulfate, the formal oxidation state of the sulfur is <mathjax>#VI^+#</mathjax>, and the negative charges are assumed to be distributed to the oxygen centres. Bisulfates, <mathjax>#HSO_4^-#</mathjax>, are also very common. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Na_2SO_4#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The sulfate ion, <mathjax>#SO_4^(2-)#</mathjax> is a very common ion counter ion, and has some aqueous solubility. In sulfate, the formal oxidation state of the sulfur is <mathjax>#VI^+#</mathjax>, and the negative charges are assumed to be distributed to the oxygen centres. Bisulfates, <mathjax>#HSO_4^-#</mathjax>, are also very common. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the formula for sodium sulfate?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/determining-formula-and-molar-masses" itemprop="url"> <span class="breadcrumb" itemprop="title">Determining Formula</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="229814" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-02-22T20:13:39" itemprop="dateCreated"> Feb 22, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Na_2SO_4#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The sulfate ion, <mathjax>#SO_4^(2-)#</mathjax> is a very common ion counter ion, and has some aqueous solubility. In sulfate, the formal oxidation state of the sulfur is <mathjax>#VI^+#</mathjax>, and the negative charges are assumed to be distributed to the oxygen centres. Bisulfates, <mathjax>#HSO_4^-#</mathjax>, are also very common. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/229814" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-it-possible-to-find-a-molecular-formula-from-molar-mass"> Is it possible to find a molecular formula from molar mass? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5368e0cc02bf34779e175781"> Question #75781 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-common-mistakes-students-make-when-determining-formulas"> What are some common mistakes students make when determining formulas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-formula-of-an-acid"> How can I determine the formula of an acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-chemical-formula-of-a-product"> How can I determine the chemical formula of a product? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-empirical-formula-of-a-compound"> How can I determine the empirical formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-formula-of-a-hydrate"> How can I determine the formula of a hydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-the-empirical-formula-indicate"> What does the empirical formula indicate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-molecule-with-molecular-weight-of-180-18-g-mol-is-analyzed-and-found-to-contai"> A molecule with molecular weight of 180.18 g/mol is analyzed and found to contain 40.00% carbon,... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/do-i-need-to-know-the-number-of-moles-of-each-element-to-determine-the-formula-o"> Do I need to know the number of moles of each element to determine the formula of the compound? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/determining-formula-and-molar-masses"> See all questions in Determining Formula </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 4173 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the formula for sodium sulfate?	null
1,008	ac6d7e62-6ddd-11ea-9783-ccda262736ce	https://socratic.org/questions/how-many-moles-are-there-in-1-5-g-of-ethanol-ch-3ch-2oh	3.24 moles	start physical_unit 10 10 mole mol qc_end physical_unit 10 10 6 7 mass qc_end end	[{"type":"physical unit","value":"Mole [OF] CH3CH2OH [IN] moles"}]	[{"type":"physical unit","value":"3.24 moles"}]	[{"type":"physical unit","value":"Mass [OF] CH3CH2OH [=] \\pu{1.5 g}"}]	<h1 class="questionTitle" itemprop="name">How many moles are there in 1.5 g of ethanol, #CH_3CH_2OH#? </h1>	null	3.24 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use the formula <br/> <mathjax>#n = m/M#</mathjax><br/> where <mathjax>#n#</mathjax> is the amount in moles (<mathjax>#mol#</mathjax>), <mathjax>#m#</mathjax> is the mass in grams (<mathjax>#g#</mathjax>), and <mathjax>#M#</mathjax> is the molar mass in grams per mole (<mathjax>#gmol^-1#</mathjax>).</p> <hr/> <p>To find the molar mass of ethanol:<br/> There are 2 <mathjax>#C#</mathjax> atoms (molar mass <mathjax>#12.011gmol^-1#</mathjax>), <br/> 6 <mathjax>#H#</mathjax> atoms (molar mass <mathjax>#1.008gmol^-1#</mathjax>),<br/> and 1 <mathjax>#O#</mathjax> atom (molar mass <mathjax>#15.999gmol^-1#</mathjax>)</p> <p><mathjax>#(2 xx 12.011) + (6 xx 1.008) + (1 xx 15.999) = 46.261176gmol^-1#</mathjax></p> <hr/> <p>To find the amount of ethanol:</p> <p><mathjax>#n(CH_3CH_2OH) = (1.5g)/(46.261176gmol^-1) #</mathjax></p> <p><mathjax>#= 3.242459724759267mol #</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#3.242459724759267mol #</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use the formula <br/> <mathjax>#n = m/M#</mathjax><br/> where <mathjax>#n#</mathjax> is the amount in moles (<mathjax>#mol#</mathjax>), <mathjax>#m#</mathjax> is the mass in grams (<mathjax>#g#</mathjax>), and <mathjax>#M#</mathjax> is the molar mass in grams per mole (<mathjax>#gmol^-1#</mathjax>).</p> <hr/> <p>To find the molar mass of ethanol:<br/> There are 2 <mathjax>#C#</mathjax> atoms (molar mass <mathjax>#12.011gmol^-1#</mathjax>), <br/> 6 <mathjax>#H#</mathjax> atoms (molar mass <mathjax>#1.008gmol^-1#</mathjax>),<br/> and 1 <mathjax>#O#</mathjax> atom (molar mass <mathjax>#15.999gmol^-1#</mathjax>)</p> <p><mathjax>#(2 xx 12.011) + (6 xx 1.008) + (1 xx 15.999) = 46.261176gmol^-1#</mathjax></p> <hr/> <p>To find the amount of ethanol:</p> <p><mathjax>#n(CH_3CH_2OH) = (1.5g)/(46.261176gmol^-1) #</mathjax></p> <p><mathjax>#= 3.242459724759267mol #</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles are there in 1.5 g of ethanol, #CH_3CH_2OH#? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="186295" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/glowing-grasshopper"><img alt="" class="" src="https://lh6.googleusercontent.com/-yAnywTuHSxk/AAAAAAAAAAI/AAAAAAAAAFI/pNn-rdsyXQk/photo.jpg?sz=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/glowing-grasshopper"> Cameron G. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-10T00:23:35" itemprop="dateCreated"> Nov 10, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#3.242459724759267mol #</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use the formula <br/> <mathjax>#n = m/M#</mathjax><br/> where <mathjax>#n#</mathjax> is the amount in moles (<mathjax>#mol#</mathjax>), <mathjax>#m#</mathjax> is the mass in grams (<mathjax>#g#</mathjax>), and <mathjax>#M#</mathjax> is the molar mass in grams per mole (<mathjax>#gmol^-1#</mathjax>).</p> <hr/> <p>To find the molar mass of ethanol:<br/> There are 2 <mathjax>#C#</mathjax> atoms (molar mass <mathjax>#12.011gmol^-1#</mathjax>), <br/> 6 <mathjax>#H#</mathjax> atoms (molar mass <mathjax>#1.008gmol^-1#</mathjax>),<br/> and 1 <mathjax>#O#</mathjax> atom (molar mass <mathjax>#15.999gmol^-1#</mathjax>)</p> <p><mathjax>#(2 xx 12.011) + (6 xx 1.008) + (1 xx 15.999) = 46.261176gmol^-1#</mathjax></p> <hr/> <p>To find the amount of ethanol:</p> <p><mathjax>#n(CH_3CH_2OH) = (1.5g)/(46.261176gmol^-1) #</mathjax></p> <p><mathjax>#= 3.242459724759267mol #</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/186295" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? 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1,009	aa7315c3-6ddd-11ea-914f-ccda262736ce	https://socratic.org/questions/how-many-moles-of-chlorine-gas-will-be-required-to-react-with-sufficient-iron-to	21.00 moles	start physical_unit 4 5 mole mol qc_end physical_unit 19 21 16 17 mole qc_end chemical_equation 22 29 qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Mole [OF] chlorine gas [IN] moles"}]	[{"type":"physical unit","value":"21.00 moles"}]	[{"type":"physical unit","value":"Mole [OF] iron (III) chloride [=] \\pu{14 moles}"},{"type":"chemical equation","value":"2 Fe(s) + 3 Cl2(g) -> 2 FeCl3(g)"},{"type":"other","value":"Sufficient iron."}]	<h1 class="questionTitle" itemprop="name">How many moles of chlorine gas will be required to react with sufficient iron to produce 14 moles of iron (III) chloride?</h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p><mathjax>#2Fe(s) + 3Cl_2(g) -> 2FeCl_3(g)#</mathjax></p></div> </h2> </div> </div>	21.00 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So the mol ratio <mathjax>#Cl_2divFeCl_3=3div2#</mathjax></p> <p>So for 14 mols of <mathjax>#FeCl_3#</mathjax> we need <mathjax>#3/2xx14=21#</mathjax> mols of <mathjax>#Cl_2#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The reaction is <mathjax>#2Fe+3Cl_2->2FeCl_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So the mol ratio <mathjax>#Cl_2divFeCl_3=3div2#</mathjax></p> <p>So for 14 mols of <mathjax>#FeCl_3#</mathjax> we need <mathjax>#3/2xx14=21#</mathjax> mols of <mathjax>#Cl_2#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles of chlorine gas will be required to react with sufficient iron to produce 14 moles of iron (III) chloride?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p><mathjax>#2Fe(s) + 3Cl_2(g) -> 2FeCl_3(g)#</mathjax></p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="369766" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meneernask"><img alt="" class="" src="https://profilepictures.socratic.org/gpA0lokRGK9vLVUnAMAy_meneernask.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meneernask"> MeneerNask </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-01-26T23:17:53" itemprop="dateCreated"> Jan 26, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The reaction is <mathjax>#2Fe+3Cl_2->2FeCl_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So the mol ratio <mathjax>#Cl_2divFeCl_3=3div2#</mathjax></p> <p>So for 14 mols of <mathjax>#FeCl_3#</mathjax> we need <mathjax>#3/2xx14=21#</mathjax> mols of <mathjax>#Cl_2#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/369766" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 26951 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many moles of chlorine gas will be required to react with sufficient iron to produce 14 moles of iron (III) chloride?	#2Fe(s) + 3Cl_2(g) -> 2FeCl_3(g)#
1,010	a9f63be4-6ddd-11ea-8851-ccda262736ce	https://socratic.org/questions/how-many-grams-are-there-in-4-5-10-22-molecules-of-ba-no-2-2	17.14 grams	start physical_unit 12 12 mass g qc_end end	[{"type":"physical unit","value":"Mass [OF] Ba(NO2)2 [IN] grams"}]	[{"type":"physical unit","value":"17.14 grams"}]	[{"type":"physical unit","value":"Number [OF] Ba(NO2)2 formula units [=] \\pu{4.5 × 10^22}"}]	<h1 class="questionTitle" itemprop="name">How many grams are there in #4.5 * 10^22# formula units of #Ba(NO_2)_2#?</h1>	null	17.14 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The molar mass of <mathjax>#Ba(NO_2)_2#</mathjax> is <mathjax>#229.34gmol^-1#</mathjax>.</p> <p>To get the mass of the given quantity, all we have do is divide this quantity by <mathjax>#"Avogadro's number"#</mathjax>, and then multiply by the molar mass.</p> <p><mathjax>#(4.5xx10^22)/(6.022xx10^23mol^-1)#</mathjax> <mathjax>#xx229.34g*mol^-1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??g#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, if there are <mathjax>#6.022xx10^23#</mathjax> <mathjax>#Ba(NO_2)_2#</mathjax> formula units there are <mathjax>#229.34g#</mathjax> by definition.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The molar mass of <mathjax>#Ba(NO_2)_2#</mathjax> is <mathjax>#229.34gmol^-1#</mathjax>.</p> <p>To get the mass of the given quantity, all we have do is divide this quantity by <mathjax>#"Avogadro's number"#</mathjax>, and then multiply by the molar mass.</p> <p><mathjax>#(4.5xx10^22)/(6.022xx10^23mol^-1)#</mathjax> <mathjax>#xx229.34gmol^-1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??g#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many grams are there in #4.5 * 10^22# formula units of #Ba(NO_2)_2#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="268505" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-22T17:48:31" itemprop="dateCreated"> May 22, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, if there are <mathjax>#6.022xx10^23#</mathjax> <mathjax>#Ba(NO_2)_2#</mathjax> formula units there are <mathjax>#229.34g#</mathjax> by definition.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The molar mass of <mathjax>#Ba(NO_2)_2#</mathjax> is <mathjax>#229.34gmol^-1#</mathjax>.</p> <p>To get the mass of the given quantity, all we have do is divide this quantity by <mathjax>#"Avogadro's number"#</mathjax>, and then multiply by the molar mass.</p> <p><mathjax>#(4.5xx10^22)/(6.022xx10^23mol^-1)#</mathjax> <mathjax>#xx229.34gmol^-1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??g#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/268505" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 10717 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many grams are there in #4.5 * 10^22# formula units of #Ba(NO_2)_2#?	null
1,011	ace4ba5a-6ddd-11ea-9466-ccda262736ce	https://socratic.org/questions/100-0-ml-of-a-ph-2-600-solution-of-hydrochloric-acid-is-diluted-with-pure-water--1	2.90	start physical_unit 28 29 ph none qc_end physical_unit 7 7 0 1 volume qc_end physical_unit 28 29 21 22 volume qc_end substance 14 15 qc_end end	[{"type":"physical unit","value":"pH2 [OF] the new solution"}]	[{"type":"physical unit","value":"2.90"}]	[{"type":"physical unit","value":"Volume1 [OF] hydrochloric acid solution [=] \\pu{100.0 mL}"},{"type":"physical unit","value":"pH1 [OF] hydrochloric acid solution [=] \\pu{2.600}"},{"type":"substance name","value":"Pure water"},{"type":"physical unit","value":"Volume2 [OF] hydrochloric acid solution [=] \\pu{200.0 mL}"}]	<h1 class="questionTitle" itemprop="name">100.0 mL of a pH=2.600 solution of hydrochloric acid is diluted with pure water to a new volume of 200.0 mL. Calculate the pH of the new solution?</h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>100.0 mL of a pH=2.600 solution of hydrochloric acid is diluted with<br/> pure water to a new volume of 200.0 mL. Calculate the pH of the new solution?</p></div> </h2> </div> </div>	2.90	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>pH is defined as 'minus the logarithm (in base 10) of the concentration of <mathjax>#H^+#</mathjax>'. To find the original concentration of <mathjax>#H^+#</mathjax>, we take the pH, change its sign from positive to negative and raise 10 to that power. </p> <p>That means the initial concentration of <mathjax>#H^+#</mathjax> (sometimes written as [<mathjax>#H^+#</mathjax>]) is <mathjax>#10^(-2.6)#</mathjax> = <mathjax>#2.51 xx 10^-3#</mathjax> <mathjax>#molL^-1#</mathjax>.</p> <p>If we double the amount of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a> (water) and leave the amount of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> (HCl) constant, the concentration of the solution will halve, because <mathjax>#C=n/V#</mathjax>, concentration equals number of moles of solute divided by volume of solution.</p> <p>The new concentration of <mathjax>#H^+#</mathjax> will be half of <mathjax>#2.51 xx 10^-3#</mathjax> = <mathjax>#1.26 xx 10^-3#</mathjax> <mathjax>#molL^-1#</mathjax>.</p> <p>To find the pH of this final solution, we reverse the process. We take the logarithm (to base 10):</p> <p><mathjax>#log_10(1.26 xx 10^-3)#</mathjax> = -2.90 </p> <p>Then we change the sign back to positive, and the new pH is 2.90.</p> <p>(Note: because HCl is a 'strong acid', I have assumed throughout that it is completely dissociated in solution)</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We use logarithms and powers of 10 to convert between <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> numbers and concentrations of <mathjax>#H^+#</mathjax> in acids.</p> <p>The pH changes from 2.6 to 2.9. It moves closer to a neutral pH of 7.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>pH is defined as 'minus the logarithm (in base 10) of the concentration of <mathjax>#H^+#</mathjax>'. To find the original concentration of <mathjax>#H^+#</mathjax>, we take the pH, change its sign from positive to negative and raise 10 to that power. </p> <p>That means the initial concentration of <mathjax>#H^+#</mathjax> (sometimes written as [<mathjax>#H^+#</mathjax>]) is <mathjax>#10^(-2.6)#</mathjax> = <mathjax>#2.51 xx 10^-3#</mathjax> <mathjax>#molL^-1#</mathjax>.</p> <p>If we double the amount of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a> (water) and leave the amount of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> (HCl) constant, the concentration of the solution will halve, because <mathjax>#C=n/V#</mathjax>, concentration equals number of moles of solute divided by volume of solution.</p> <p>The new concentration of <mathjax>#H^+#</mathjax> will be half of <mathjax>#2.51 xx 10^-3#</mathjax> = <mathjax>#1.26 xx 10^-3#</mathjax> <mathjax>#molL^-1#</mathjax>.</p> <p>To find the pH of this final solution, we reverse the process. We take the logarithm (to base 10):</p> <p><mathjax>#log_10(1.26 xx 10^-3)#</mathjax> = -2.90 </p> <p>Then we change the sign back to positive, and the new pH is 2.90.</p> <p>(Note: because HCl is a 'strong acid', I have assumed throughout that it is completely dissociated in solution)</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">100.0 mL of a pH=2.600 solution of hydrochloric acid is diluted with pure water to a new volume of 200.0 mL. Calculate the pH of the new solution?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>100.0 mL of a pH=2.600 solution of hydrochloric acid is diluted with<br/> pure water to a new volume of 200.0 mL. Calculate the pH of the new solution?</p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/the-ph-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">pH</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="311369" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/david-g-6"><img alt="" class="" src="https://graph.facebook.com/10153408096237887/picture?height=50&width=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/david-g-6"> David G. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-09-18T00:00:40" itemprop="dateCreated"> Sep 18, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We use logarithms and powers of 10 to convert between <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> numbers and concentrations of <mathjax>#H^+#</mathjax> in acids.</p> <p>The pH changes from 2.6 to 2.9. It moves closer to a neutral pH of 7.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>pH is defined as 'minus the logarithm (in base 10) of the concentration of <mathjax>#H^+#</mathjax>'. To find the original concentration of <mathjax>#H^+#</mathjax>, we take the pH, change its sign from positive to negative and raise 10 to that power. </p> <p>That means the initial concentration of <mathjax>#H^+#</mathjax> (sometimes written as [<mathjax>#H^+#</mathjax>]) is <mathjax>#10^(-2.6)#</mathjax> = <mathjax>#2.51 xx 10^-3#</mathjax> <mathjax>#molL^-1#</mathjax>.</p> <p>If we double the amount of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a> (water) and leave the amount of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> (HCl) constant, the concentration of the solution will halve, because <mathjax>#C=n/V#</mathjax>, concentration equals number of moles of solute divided by volume of solution.</p> <p>The new concentration of <mathjax>#H^+#</mathjax> will be half of <mathjax>#2.51 xx 10^-3#</mathjax> = <mathjax>#1.26 xx 10^-3#</mathjax> <mathjax>#molL^-1#</mathjax>.</p> <p>To find the pH of this final solution, we reverse the process. We take the logarithm (to base 10):</p> <p><mathjax>#log_10(1.26 xx 10^-3)#</mathjax> = -2.90 </p> <p>Then we change the sign back to positive, and the new pH is 2.90.</p> <p>(Note: because HCl is a 'strong acid', I have assumed throughout that it is completely dissociated in solution)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/311369" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="311371" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-09-18T00:03:30" itemprop="dateCreated"> Sep 18, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2.901#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Here's a quick way of solving this problem. You know that the <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> of the solution is given by the <em>concentration</em> of hydronium cations, <mathjax>#"H"_3"O"^(+)#</mathjax>.</p> <p>When you <strong>double</strong> the volume of the solution, you essentially <strong>halve</strong> the concentration of hydronium cations. This means that if you take <mathjax>#["H"_3"O"^(+)]_0#</mathjax> to be initial concentration of hydronium cations, you will have</p> <blockquote> <p><mathjax>#["H"_ 3"O"^(+)]_ "dil" = (["H"_ 3"O"^(+)]_0)/2 ->#</mathjax> <em>the concentration <strong>after the dilution</strong></em></p> </blockquote> <p>You know that</p> <blockquote> <p><mathjax>#color(purple)(bar(ul(\|color(white)(a/a)color(black)("pH" = - log(["H"_3"O"^(+)]))color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>You can thus say that <strong>after</strong> the solution is diluted, its pH will be</p> <blockquote> <p><mathjax>#"pH"_ "dil" = - log(["H"_ 3"O"^(+)]_"dil")#</mathjax></p> </blockquote> <p>This, in turn, is equivalent to </p> <blockquote> <p><mathjax>#"pH"_ "dil" = - log((["H"_ 3"O"^(+)]_0)/2)#</mathjax></p> <p><mathjax>#"pH"_ "dil" = -[log(["H"_ 3"O"^(+)]_ 0) - log2]#</mathjax></p> <p><mathjax>#"pH"_ "dil" = log2 - log(["H"_3"O"^(+)]_0)#</mathjax></p> </blockquote> <p>But since</p> <blockquote> <p><mathjax>#"pH"_ 0 = - log(["H"_ 3"O"^(+)]_0) = 2.600#</mathjax></p> </blockquote> <p>you will have</p> <blockquote> <p><mathjax>#"pH"_ "dil" = log2 + "pH"_ 0#</mathjax></p> <p><mathjax>#color(green)(bar(ul(\|color(white)(a/a)color(black)("pH" _ "dil" = 2.600 + log 2 = 2.901)color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <em>decimal places</em>.</p> <p>Finally, does this result make sense?</p> <p>Diluting the solution means <strong>decreasing</strong> its concentration of hydronium cations, which in turn implies <strong>increasing</strong> the pH of the solution, i.e. making it <em>less acidic</em>. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/311371" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-pka"> How do you determine pH from pKa? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-ph-values-of-acids-and-bases-differ"> How do pH values of acids and bases differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-something-on-a-ph-scale"> How do you calculate something on a pH scale? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-diprotic-acid"> How do you calculate pH diprotic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-from-acid-dissociation-constant"> How do you calculate pH from acid dissociation constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-of-acid-and-base-solution"> How do you calculate pH of acid and base solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ph-scale-0-14"> Why is the pH scale 0-14? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-ph-the-measure-of-the-hydrogen-ion-concentration"> Is pH a measure of the hydrogen ion concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-solubility-affect-ph"> How does solubility affect pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-ph-relate-to-pka-in-a-titration"> How does pH relate to pKa in a titration? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/the-ph-concept"> See all questions in pH </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 16840 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	100.0 mL of a pH=2.600 solution of hydrochloric acid is diluted with pure water to a new volume of 200.0 mL. Calculate the pH of the new solution?	100.0 mL of a pH=2.600 solution of hydrochloric acid is diluted with pure water to a new volume of 200.0 mL. Calculate the pH of the new solution?
1,012	a94c4bdc-6ddd-11ea-afd5-ccda262736ce	https://socratic.org/questions/what-mass-of-magnesium-contains-the-same-number-of-atoms-as-8-0g-of-calcium	4.85 g	start physical_unit 3 3 mass g qc_end physical_unit 14 14 11 12 mass qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Mass [OF] magnesium [IN] g"}]	[{"type":"physical unit","value":"4.85 g"}]	[{"type":"physical unit","value":"Mass [OF] calcium [=] \\pu{8.0 g}"},{"type":"other","value":"Magnesium contains the same number of atoms as calcium."}]	<h1 class="questionTitle" itemprop="name">What mass of magnesium contains the same number of atoms as 8.0g of calcium?</h1>	null	4.85 g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Molar Mass of Magnesium <mathjax>#("Mg"): " 24.31 g/mol"#</mathjax><br/> Molar Mass of Calcium <mathjax>#("Ca"): " 40.08 g/mol"#</mathjax></p> <p>Avogadro's constant <mathjax>#= 6.02210^23#</mathjax> particles of a substance per mol of that substance</p> <p><mathjax>#8.0"g Ca" (1 "mol Ca")/(40.08"g Ca")(6.02210^23"atoms of Ca")/(1 "mol Ca") = 1.210^23"atoms of Ca"#</mathjax></p> <p>The number of atoms of Mg should be the same as the number of atoms of Ca, so:</p> <p><mathjax>#1.210^23"atoms of Mg"(1 "mol Mg")/(6.02210^23"atoms of Mg")(24.31"g Mg")/(1"mol Mg") = 4.9"g Mg"#</mathjax></p> <p>You can also eliminate the step of converting to atoms, as a mol of any substance contains <mathjax>#6.02210^23#</mathjax> particles of that substance</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"4.9 g Mg"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Molar Mass of Magnesium <mathjax>#("Mg"): " 24.31 g/mol"#</mathjax><br/> Molar Mass of Calcium <mathjax>#("Ca"): " 40.08 g/mol"#</mathjax></p> <p>Avogadro's constant <mathjax>#= 6.02210^23#</mathjax> particles of a substance per mol of that substance</p> <p><mathjax>#8.0"g Ca" (1 "mol Ca")/(40.08"g Ca")(6.02210^23"atoms of Ca")/(1 "mol Ca") = 1.210^23"atoms of Ca"#</mathjax></p> <p>The number of atoms of Mg should be the same as the number of atoms of Ca, so:</p> <p><mathjax>#1.210^23"atoms of Mg"(1 "mol Mg")/(6.02210^23"atoms of Mg")(24.31"g Mg")/(1"mol Mg") = 4.9"g Mg"#</mathjax></p> <p>You can also eliminate the step of converting to atoms, as a mol of any substance contains <mathjax>#6.02210^23#</mathjax> particles of that substance</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What mass of magnesium contains the same number of atoms as 8.0g of calcium?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="535987" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/samuel-w-3"><img alt="" class="" src="https://lh3.googleusercontent.com/-w_eRhncowMQ/AAAAAAAAAAI/AAAAAAAAADc/wEqZR4LumKg/photo.jpg?sz=50" title=""/></a> <a class="secondContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/samuel-w-3"> Vesco Santiago </a>·<a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-01-15T22:53:44" itemprop="dateCreated"> Jan 15, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"4.9 g Mg"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Molar Mass of Magnesium <mathjax>#("Mg"): " 24.31 g/mol"#</mathjax><br/> Molar Mass of Calcium <mathjax>#("Ca"): " 40.08 g/mol"#</mathjax></p> <p>Avogadro's constant <mathjax>#= 6.02210^23#</mathjax> particles of a substance per mol of that substance</p> <p><mathjax>#8.0"g Ca" (1 "mol Ca")/(40.08"g Ca")(6.02210^23"atoms of Ca")/(1 "mol Ca") = 1.210^23"atoms of Ca"#</mathjax></p> <p>The number of atoms of Mg should be the same as the number of atoms of Ca, so:</p> <p><mathjax>#1.210^23"atoms of Mg"(1 "mol Mg")/(6.02210^23"atoms of Mg")(24.31"g Mg")/(1"mol Mg") = 4.9"g Mg"#</mathjax></p> <p>You can also eliminate the step of converting to atoms, as a mol of any substance contains <mathjax>#6.02210^23#</mathjax> particles of that substance</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/535987" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" 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1,013	aa59e2c8-6ddd-11ea-8bbf-ccda262736ce	https://socratic.org/questions/587d36db11ef6b05d031b629	0.80 atm	start physical_unit 7 7 pressure atm qc_end physical_unit 7 7 10 11 volume qc_end physical_unit 7 7 4 5 pressure qc_end physical_unit 7 7 25 26 volume qc_end end	[{"type":"physical unit","value":"Pressure2 [OF] the gas [IN] atm"}]	[{"type":"physical unit","value":"0.80 atm"}]	[{"type":"physical unit","value":"Volume1 [OF] the gas [=] \\pu{8 mL}"},{"type":"physical unit","value":"Pressure1 [OF] the gas [=] \\pu{1.2 atm}"},{"type":"physical unit","value":"Volume2 [OF] the gas [=] \\pu{12 mL}"}]	<h1 class="questionTitle" itemprop="name">Under a pressure of #1.2atm# a gas occupies an #8mL# volume in a piston. What pressure develops if the volume is increased to #12*mL#?</h1>	null	0.80 atm	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's Law</a> holds that <mathjax>#P_1V_1=P_2V_2#</mathjax> at constant temperature.</p> <p>And thus <mathjax>#P_2=(P_1V_1)/V_2=(1.2atmxx8mL)/(12mL)=0.8atm#</mathjax>.</p> <p>This decrease in pressure is reasonable, given that we have INCREASED the volume. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#P_2=0.8atm#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's Law</a> holds that <mathjax>#P_1V_1=P_2V_2#</mathjax> at constant temperature.</p> <p>And thus <mathjax>#P_2=(P_1V_1)/V_2=(1.2atmxx8mL)/(12mL)=0.8*atm#</mathjax>.</p> <p>This decrease in pressure is reasonable, given that we have INCREASED the volume. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Under a pressure of #1.2atm# a gas occupies an #8mL# volume in a piston. What pressure develops if the volume is increased to #12mL#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/boyle-s-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Boyle's Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="365381" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-01-16T21:22:43" itemprop="dateCreated"> Jan 16, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#P_2=0.8atm#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's Law</a> holds that <mathjax>#P_1V_1=P_2V_2#</mathjax> at constant temperature.</p> <p>And thus <mathjax>#P_2=(P_1V_1)/V_2=(1.2atmxx8mL)/(12mL)=0.8atm#</mathjax>.</p> <p>This decrease in pressure is reasonable, given that we have INCREASED the volume. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/365381" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-graph-boyles-law"> How do you graph Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-functional-groups-are-found-in-lipids"> What functional groups are found in lipids? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-k-constant-in-boyle-s-law"> Why is k constant in Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-boyle-s-law-graph-curved-1"> Why is Boyle's law graph curved? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-boyle-s-law-an-inverse-relationship-2"> Why is Boyle's law an inverse relationship? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-40-0-l-tank-of-ammonia-has-a-pressure-of-8-00-atm-calculate-the-volume-of-the-"> A 40.0 L tank of ammonia has a pressure of 8.00 atm. Calculate the volume of the ammonia if its... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-charles-law-different-from-boyle-s-law"> How is Charles' law different from Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-boyle-s-law-written-mathematically"> How is Boyle's law written mathematically? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-temperature-affect-boyle-s-law"> How does temperature affect Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-boyle-s-law-relate-to-ventilation"> How does Boyle's law relate to ventilation? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/boyle-s-law"> See all questions in Boyle's Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1359 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Under a pressure of #1.2atm# a gas occupies an #8mL# volume in a piston. What pressure develops if the volume is increased to #12*mL#?	null
1,014	aab3b2d3-6ddd-11ea-ad8a-ccda262736ce	https://socratic.org/questions/what-is-the-molecular-formula-of-a-compound-that-has-a-molecular-mass-of-54-and-	C4H6	start chemical_formula qc_end physical_unit 7 7 14 15 molecular_weight qc_end c_other OTHER qc_end end	[{"type":"other","value":"Chemical Formula [OF] the compound [IN] molecular"}]	[{"type":"chemical equation","value":"C4H6"}]	[{"type":"physical unit","value":"molecular mass [OF] the compound [=] \\pu{54 g/mol}"},{"type":"other","value":"The compound has the empirical formula C2H3."}]	<h1 class="questionTitle" itemprop="name">What is the molecular formula of a compound that has a molecular mass of 54 and the empirical formula #C_2H_3#?</h1>	null	C4H6	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <mathjax>#"molecular formula"#</mathjax> is always a whole number multiple of the <mathjax>#"empirical formula"#</mathjax>.</p> <p>i.e. <mathjax>#"molecular formula"=nxx("empirical formula")#</mathjax> </p> <p><mathjax>#54gmol^-1=nxx(2xx12.011+3xx1.00794)gmol^-1#</mathjax></p> <p><mathjax>#=nxx(27.04)gmol^-1#</mathjax></p> <p>Clearly, <mathjax>#n=(54.0gmol^-1)/(27.04gmol^-1)=2#</mathjax></p> <p><mathjax>#"Molecular formula"=(C_2H_3)xx2=C_4H_6#</mathjax> as required. </p> <p>This compound has two degrees of unsaturation, so it is a butadiene, or a cylocbutene, or an allene derivative, or an alkyne......... </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_4H_6#</mathjax>.............</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <mathjax>#"molecular formula"#</mathjax> is always a whole number multiple of the <mathjax>#"empirical formula"#</mathjax>.</p> <p>i.e. <mathjax>#"molecular formula"=nxx("empirical formula")#</mathjax> </p> <p><mathjax>#54gmol^-1=nxx(2xx12.011+3xx1.00794)gmol^-1#</mathjax></p> <p><mathjax>#=nxx(27.04)gmol^-1#</mathjax></p> <p>Clearly, <mathjax>#n=(54.0gmol^-1)/(27.04gmol^-1)=2#</mathjax></p> <p><mathjax>#"Molecular formula"=(C_2H_3)xx2=C_4H_6#</mathjax> as required. </p> <p>This compound has two degrees of unsaturation, so it is a butadiene, or a cylocbutene, or an allene derivative, or an alkyne......... </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the molecular formula of a compound that has a molecular mass of 54 and the empirical formula #C_2H_3#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="423138" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-14T10:08:59" itemprop="dateCreated"> May 14, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_4H_6#</mathjax>.............</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <mathjax>#"molecular formula"#</mathjax> is always a whole number multiple of the <mathjax>#"empirical formula"#</mathjax>.</p> <p>i.e. <mathjax>#"molecular formula"=nxx("empirical formula")#</mathjax> </p> <p><mathjax>#54gmol^-1=nxx(2xx12.011+3xx1.00794)gmol^-1#</mathjax></p> <p><mathjax>#=nxx(27.04)gmol^-1#</mathjax></p> <p>Clearly, <mathjax>#n=(54.0gmol^-1)/(27.04gmol^-1)=2#</mathjax></p> <p><mathjax>#"Molecular formula"=(C_2H_3)xx2=C_4H_6#</mathjax> as required. </p> <p>This compound has two degrees of unsaturation, so it is a butadiene, or a cylocbutene, or an allene derivative, or an alkyne......... </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/423138" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molecular-formula-of-a-compound"> How do you find molecular 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and Molecular Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2064 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the molecular formula of a compound that has a molecular mass of 54 and the empirical formula #C_2H_3#?	null
1,015	ac647ee8-6ddd-11ea-8523-ccda262736ce	https://socratic.org/questions/copper-will-react-with-sulfur-to-form-a-copper-sulfide-if-1-500g-copper-reacts-w	Cu2S	start chemical_formula qc_end physical_unit 0 0 11 12 mass qc_end physical_unit 8 9 19 20 mass qc_end substance 4 4 qc_end end	[{"type":"other","value":"Chemical Formula [OF] the copper sulfide [IN] empirical"}]	[{"type":"chemical equation","value":"Cu2S"}]	[{"type":"physical unit","value":"Mass [OF] copper [=] \\pu{1.500 g}"},{"type":"physical unit","value":"Mass [OF] copper sulfide [=] \\pu{1.880 g}"},{"type":"substance name","value":"Sulfur"}]	<h1 class="questionTitle" itemprop="name">Copper will react with sulfur to form a copper sulfide, if 1.500g copper reacts with sulfur to form 1.880g of copper sulfide, what is the empirical formula of the copper sulfide?</h1>	null	Cu2S	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that you need to use the mass of copper and the mass of the copper sulfide to determine how much sulfur the produced compound contains, then convert these masses to a <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a>. </p> <p>So, assuming that sulfur is <em>in excess</em>, you know that <strong>all the number of moles</strong> of copper that reacted will now be a part of the copper sulfide. </p> <p>This mens that the difference between the recorded mass of the sulfide and the mass of the copper will be the mass of the sulfur.</p> <blockquote> <p><mathjax>#m_"copper sulfide" = m_"sulfur" + m_"copper"#</mathjax></p> <p><mathjax>#m_"sulfur" = "1.880 g" - "1.500 g" = "0.380 g S"#</mathjax></p> </blockquote> <p>So, the mass of copper sulfide contains</p> <blockquote> <ul> <li><mathjax>#"1.500 g"#</mathjax> of copper</li> <li><mathjax>#"0.380 g"#</mathjax> of sulfur</li> </ul> </blockquote> <p>Use the molar masses of these two <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> to find how many moles of each you'd get in this sample</p> <blockquote> <p><mathjax>#1.500color(red)(cancel(color(black)("g"))) * "1 mole Cu"/(63.546color(red)(cancel(color(black)("g")))) = "0.023605 moles Cu"#</mathjax></p> </blockquote> <p>and</p> <blockquote> <p><mathjax>#0.380color(red)(cancel(color(black)("g"))) * "1 mole S"/(32.065color(red)(cancel(color(black)("g")))) = "0.011851 moles S"#</mathjax></p> </blockquote> <p>To get <a href="http://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio that exists between these two elements in the copper sulfide, divide both values by the <em>smallest one</em> </p> <blockquote> <p><mathjax>#"For Cu: " (0.023605color(red)(cancel(color(black)("moles"))))/(0.011851color(red)(cancel(color(black)("moles")))) = 1.9918 ~~ 2#</mathjax></p> <p><mathjax>#"For S: " (0.011851color(red)(cancel(color(black)("moles"))))/(0.011851color(red)(cancel(color(black)("moles")))) = 1#</mathjax></p> </blockquote> <p>This means that the <em>empirical formula</em> of this copepr sulfide will be </p> <blockquote> <p><mathjax>#"Cu"_2"S " ->#</mathjax> <em>copper(I) sulfide</em></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Cu"_2"S"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that you need to use the mass of copper and the mass of the copper sulfide to determine how much sulfur the produced compound contains, then convert these masses to a <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a>. </p> <p>So, assuming that sulfur is <em>in excess</em>, you know that <strong>all the number of moles</strong> of copper that reacted will now be a part of the copper sulfide. </p> <p>This mens that the difference between the recorded mass of the sulfide and the mass of the copper will be the mass of the sulfur.</p> <blockquote> <p><mathjax>#m_"copper sulfide" = m_"sulfur" + m_"copper"#</mathjax></p> <p><mathjax>#m_"sulfur" = "1.880 g" - "1.500 g" = "0.380 g S"#</mathjax></p> </blockquote> <p>So, the mass of copper sulfide contains</p> <blockquote> <ul> <li><mathjax>#"1.500 g"#</mathjax> of copper</li> <li><mathjax>#"0.380 g"#</mathjax> of sulfur</li> </ul> </blockquote> <p>Use the molar masses of these two <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> to find how many moles of each you'd get in this sample</p> <blockquote> <p><mathjax>#1.500color(red)(cancel(color(black)("g"))) * "1 mole Cu"/(63.546color(red)(cancel(color(black)("g")))) = "0.023605 moles Cu"#</mathjax></p> </blockquote> <p>and</p> <blockquote> <p><mathjax>#0.380color(red)(cancel(color(black)("g"))) * "1 mole S"/(32.065color(red)(cancel(color(black)("g")))) = "0.011851 moles S"#</mathjax></p> </blockquote> <p>To get <a href="http://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio that exists between these two elements in the copper sulfide, divide both values by the <em>smallest one</em> </p> <blockquote> <p><mathjax>#"For Cu: " (0.023605color(red)(cancel(color(black)("moles"))))/(0.011851color(red)(cancel(color(black)("moles")))) = 1.9918 ~~ 2#</mathjax></p> <p><mathjax>#"For S: " (0.011851color(red)(cancel(color(black)("moles"))))/(0.011851color(red)(cancel(color(black)("moles")))) = 1#</mathjax></p> </blockquote> <p>This means that the <em>empirical formula</em> of this copepr sulfide will be </p> <blockquote> <p><mathjax>#"Cu"_2"S " ->#</mathjax> <em>copper(I) sulfide</em></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Copper will react with sulfur to form a copper sulfide, if 1.500g copper reacts with sulfur to form 1.880g of copper sulfide, what is the empirical formula of the copper sulfide?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="181061" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-10-29T19:33:26" itemprop="dateCreated"> Oct 29, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Cu"_2"S"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that you need to use the mass of copper and the mass of the copper sulfide to determine how much sulfur the produced compound contains, then convert these masses to a <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a>. </p> <p>So, assuming that sulfur is <em>in excess</em>, you know that <strong>all the number of moles</strong> of copper that reacted will now be a part of the copper sulfide. </p> <p>This mens that the difference between the recorded mass of the sulfide and the mass of the copper will be the mass of the sulfur.</p> <blockquote> <p><mathjax>#m_"copper sulfide" = m_"sulfur" + m_"copper"#</mathjax></p> <p><mathjax>#m_"sulfur" = "1.880 g" - "1.500 g" = "0.380 g S"#</mathjax></p> </blockquote> <p>So, the mass of copper sulfide contains</p> <blockquote> <ul> <li><mathjax>#"1.500 g"#</mathjax> of copper</li> <li><mathjax>#"0.380 g"#</mathjax> of sulfur</li> </ul> </blockquote> <p>Use the molar masses of these two <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> to find how many moles of each you'd get in this sample</p> <blockquote> <p><mathjax>#1.500color(red)(cancel(color(black)("g"))) * "1 mole Cu"/(63.546color(red)(cancel(color(black)("g")))) = "0.023605 moles Cu"#</mathjax></p> </blockquote> <p>and</p> <blockquote> <p><mathjax>#0.380color(red)(cancel(color(black)("g"))) * "1 mole S"/(32.065color(red)(cancel(color(black)("g")))) = "0.011851 moles S"#</mathjax></p> </blockquote> <p>To get <a href="http://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio that exists between these two elements in the copper sulfide, divide both values by the <em>smallest one</em> </p> <blockquote> <p><mathjax>#"For Cu: " (0.023605color(red)(cancel(color(black)("moles"))))/(0.011851color(red)(cancel(color(black)("moles")))) = 1.9918 ~~ 2#</mathjax></p> <p><mathjax>#"For S: " (0.011851color(red)(cancel(color(black)("moles"))))/(0.011851color(red)(cancel(color(black)("moles")))) = 1#</mathjax></p> </blockquote> <p>This means that the <em>empirical formula</em> of this copepr sulfide will be </p> <blockquote> <p><mathjax>#"Cu"_2"S " ->#</mathjax> <em>copper(I) sulfide</em></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/181061" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molecular-formula-of-a-compound"> How do you find molecular formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-diamond"> What is the chemical formula of a diamond? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-carbohydrate"> What is the chemical formula of a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-valproic-acid"> What is the empirical formula for valproic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-of-magnesium-oxide"> What is the empirical formula of magnesium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-empirical-formula-not-double-that-of-the-monosaccharides"> Why is the empirical formula not double that of the monosaccharides? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5331180502bf342f40b5c3b5"> Question #5c3b5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-molecular-formula-represents-a-carbohydrate"> What molecular formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-of-vinegar"> What is the molecular formula of vinegar? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/empirical-and-molecular-formulas"> See all questions in Empirical and Molecular Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 12183 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Copper will react with sulfur to form a copper sulfide, if 1.500g copper reacts with sulfur to form 1.880g of copper sulfide, what is the empirical formula of the copper sulfide?	null
1,016	a840807f-6ddd-11ea-a8e4-ccda262736ce	https://socratic.org/questions/silicon-tetrachloride-sicl-4-can-be-prepared-by-heating-si-in-chlorine-gas-si-s-	1.14 moles	start physical_unit 31 32 mole mol qc_end chemical_equation 12 17 qc_end physical_unit 2 2 21 22 mole qc_end end	[{"type":"physical unit","value":"Mole [OF] molecular chlorine [IN] moles"}]	[{"type":"physical unit","value":"1.14 moles"}]	[{"type":"chemical equation","value":"Si(s) + 2 Cl2(g) -> SiCl4(l)"},{"type":"physical unit","value":"Mole [OF] SiCl4 [=] \\pu{0.507 mole}"}]	<h1 class="questionTitle" itemprop="name">Silicon tetrachloride (#SiCl_4#) can be prepared by heating #Si# in chlorine gas: #Si (s) + 2Cl_2(g) -> SiCl_4(l)#. In one reaction, 0.507 mole of #SiCl_4# is produced. How many moles of molecular chlorine were used in the reaction?</h1>	null	1.14 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The stoichiometric equation, which you have correctly written, clearly and explicitly shows that <mathjax>#1#</mathjax> <mathjax>#mol#</mathjax> of silicon (approx. <mathjax>#28g#</mathjax>) reacts with <mathjax>#2"moles"#</mathjax> of chlorine gas (approx. <mathjax>#71*g#</mathjax>) to give <mathjax>#1#</mathjax> <mathjax>#mol#</mathjax> of <mathjax>#SiCl_4#</mathjax>.</p> <p>The equation establishes both the molar and mass balance. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">Stoichiometry</a> demands at least <mathjax>#1.14#</mathjax> <mathjax>#mol#</mathjax> of <mathjax>#Cl_2#</mathjax> gas. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The stoichiometric equation, which you have correctly written, clearly and explicitly shows that <mathjax>#1#</mathjax> <mathjax>#mol#</mathjax> of silicon (approx. <mathjax>#28g#</mathjax>) reacts with <mathjax>#2"moles"#</mathjax> of chlorine gas (approx. <mathjax>#71*g#</mathjax>) to give <mathjax>#1#</mathjax> <mathjax>#mol#</mathjax> of <mathjax>#SiCl_4#</mathjax>.</p> <p>The equation establishes both the molar and mass balance. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Silicon tetrachloride (#SiCl_4#) can be prepared by heating #Si# in chlorine gas: #Si (s) + 2Cl_2(g) -> SiCl_4(l)#. In one reaction, 0.507 mole of #SiCl_4# is produced. How many moles of molecular chlorine were used in the reaction?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/mole-ratios" itemprop="url"> <span class="breadcrumb" itemprop="title">Mole Ratios</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="303376" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-08-28T08:40:19" itemprop="dateCreated"> Aug 28, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">Stoichiometry</a> demands at least <mathjax>#1.14#</mathjax> <mathjax>#mol#</mathjax> of <mathjax>#Cl_2#</mathjax> gas. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The stoichiometric equation, which you have correctly written, clearly and explicitly shows that <mathjax>#1#</mathjax> <mathjax>#mol#</mathjax> of silicon (approx. <mathjax>#28g#</mathjax>) reacts with <mathjax>#2"moles"#</mathjax> of chlorine gas (approx. <mathjax>#71*g#</mathjax>) to give <mathjax>#1#</mathjax> <mathjax>#mol#</mathjax> of <mathjax>#SiCl_4#</mathjax>.</p> <p>The equation establishes both the molar and mass balance. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/303376" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a 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class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Silicon tetrachloride (#SiCl_4#) can be prepared by heating #Si# in chlorine gas: #Si (s) + 2Cl_2(g) -> SiCl_4(l)#. In one reaction, 0.507 mole of #SiCl_4# is produced. How many moles of molecular chlorine were used in the reaction?	null
1,017	a90693a8-6ddd-11ea-abee-ccda262736ce	https://socratic.org/questions/58e0ea8211ef6b3bf4e6ea1a	60 grams	start physical_unit 11 12 mass g qc_end physical_unit 11 14 9 9 w/w qc_end end	[{"type":"physical unit","value":"Mass [OF] caustic soda [IN] grams"}]	[{"type":"physical unit","value":"60 grams"}]	[{"type":"physical unit","value":"Volume [OF] caustic soda solution [=] \\pu{600 mL}"},{"type":"physical unit","value":"w/w [OF] caustic soda in water [=] \\pu{20%}"}]	<h1 class="questionTitle" itemprop="name">How do you make a #600mL# volume of #20%("w/w")# caustic soda in water?</h1>	null	60 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Measure a mass of <mathjax>#60g#</mathjax> caustic soda........and be quick because the stuff deliquesces in air (note that at a minimum you should be wearing safety spectacles to protect your mince pies, and avoid skin contact with the pellets). And pour in a measured volume of water, approx. <mathjax>#50-60mL#</mathjax>. The solution, <mathjax>#"the lye"#</mathjax>, will get hot as the sodium hydroxide dissolves; the heat of solution (and it will get very hot) should get all the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> into solution. Once the pellets have dissolved, make up the volume to <mathjax>#600mL#</mathjax>.</p> <p><mathjax>#"Concentration"="Mass of NaOH"/"Volume of solution"=(60g)/(300*g)xx100%=#</mathjax></p> <p><mathjax>#=1/5xx100%=20%#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Measure a mass of <mathjax>#60g#</mathjax> caustic soda........</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Measure a mass of <mathjax>#60g#</mathjax> caustic soda........and be quick because the stuff deliquesces in air (note that at a minimum you should be wearing safety spectacles to protect your mince pies, and avoid skin contact with the pellets). And pour in a measured volume of water, approx. <mathjax>#50-60mL#</mathjax>. The solution, <mathjax>#"the lye"#</mathjax>, will get hot as the sodium hydroxide dissolves; the heat of solution (and it will get very hot) should get all the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> into solution. Once the pellets have dissolved, make up the volume to <mathjax>#600mL#</mathjax>.</p> <p><mathjax>#"Concentration"="Mass of NaOH"/"Volume of solution"=(60g)/(300g)xx100%=#</mathjax></p> <p><mathjax>#=1/5xx100%=20%#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you make a #600mL# volume of #20%("w/w")# caustic soda in water?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/percent-concentration" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Concentration</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="403010" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-07T05:00:29" itemprop="dateCreated"> Apr 7, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Measure a mass of <mathjax>#60g#</mathjax> caustic soda........</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Measure a mass of <mathjax>#60g#</mathjax> caustic soda........and be quick because the stuff deliquesces in air (note that at a minimum you should be wearing safety spectacles to protect your mince pies, and avoid skin contact with the pellets). And pour in a measured volume of water, approx. <mathjax>#50-60mL#</mathjax>. The solution, <mathjax>#"the lye"#</mathjax>, will get hot as the sodium hydroxide dissolves; the heat of solution (and it will get very hot) should get all the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> into solution. Once the pellets have dissolved, make up the volume to <mathjax>#600mL#</mathjax>.</p> <p><mathjax>#"Concentration"="Mass of NaOH"/"Volume of solution"=(60g)/(300g)xx100%=#</mathjax></p> <p><mathjax>#=1/5xx100%=20%#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/403010" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-concentration-of-water-in-solution-be-decreased"> How can the concentration of water in solution be decreased? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-concentration-of-a-solution-be-increased"> How can the concentration of a solution be increased? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-concentration-of-a-solution-in-ppm"> How do you find the concentration of a solution in ppm? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-make-a-10-percent-solution"> How do you make a 10 percent solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-make-a-2-percent-solution"> How do you make a 2 percent solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-weight-per-volume-method-to-calculate-concentration"> What is the weight per volume method to calculate concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-percent-concentration-of-kcl-would-be-isotonic"> What percent concentration of KCl would be isotonic? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-of-sodium-chloride-in-normal-saline"> What is the percent concentration of sodium chloride in normal saline? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-of-a-6m-solution-of-nacl"> What is the percent concentration of a 6m solution of NaCl? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-formula"> What is the percent concentration formula? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/percent-concentration"> See all questions in Percent Concentration </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2843 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How do you make a #600mL# volume of #20%("w/w")# caustic soda in water?	null
1,018	ab43a622-6ddd-11ea-9891-ccda262736ce	https://socratic.org/questions/how-do-you-balance-nh-3-h-2so-4-nh-4-2so-4	2 NH3 + H2SO4 -> (NH4)2SO4	start chemical_equation qc_end chemical_equation 4 8 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the equation"}]	[{"type":"chemical equation","value":"2 NH3 + H2SO4 -> (NH4)2SO4"}]	[{"type":"chemical equation","value":"NH3 + H2SO4 -> (NH4)2SO4"}]	<h1 class="questionTitle" itemprop="name">How do you balance #NH_3 + H_2SO_4 -> (NH_4)_2SO_4#?</h1>	null	2 NH3 + H2SO4 -> (NH4)2SO4	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The balanced equation is the following:</p> <p><mathjax>#color(red)(2)NH_3+H_2SO_4->(NH_4)_2SO_4#</mathjax></p> <p>Explanation:<br/> First start by looking at the sulfate group <mathjax>#SO_4#</mathjax>, you will need to leave this group intact.</p> <p>Second, we have two nitrogen atoms in the product side, and only one in the reactants side, therefore, we can multiply <mathjax>#NH_3#</mathjax> by <mathjax>#color(red)(2)#</mathjax>.</p> <p>Third, look at the hydrogen atoms, you will find <mathjax>#color(blue)(8)#</mathjax> in each side of the reaction, and therefore, your reaction is balanced.</p> <p>In some cases, I prefer to balance equations using groups (or polyatomic ions) rather than atoms.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#color(red)(2)NH_3+H_2SO_4->(NH_4)_2SO_4#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The balanced equation is the following:</p> <p><mathjax>#color(red)(2)NH_3+H_2SO_4->(NH_4)_2SO_4#</mathjax></p> <p>Explanation:<br/> First start by looking at the sulfate group <mathjax>#SO_4#</mathjax>, you will need to leave this group intact.</p> <p>Second, we have two nitrogen atoms in the product side, and only one in the reactants side, therefore, we can multiply <mathjax>#NH_3#</mathjax> by <mathjax>#color(red)(2)#</mathjax>.</p> <p>Third, look at the hydrogen atoms, you will find <mathjax>#color(blue)(8)#</mathjax> in each side of the reaction, and therefore, your reaction is balanced.</p> <p>In some cases, I prefer to balance equations using groups (or polyatomic ions) rather than atoms.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you balance #NH_3 + H_2SO_4 -> (NH_4)_2SO_4#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="191410" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ali-h-1"><img alt="" class="" src="https://profilepictures.socratic.org/IITeL1YTQdODdLp0aJTL_StereoPicture%20copy.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ali-h-1"> Dr. Hayek </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-21T10:24:22" itemprop="dateCreated"> Nov 21, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#color(red)(2)NH_3+H_2SO_4->(NH_4)_2SO_4#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The balanced equation is the following:</p> <p><mathjax>#color(red)(2)NH_3+H_2SO_4->(NH_4)_2SO_4#</mathjax></p> <p>Explanation:<br/> First start by looking at the sulfate group <mathjax>#SO_4#</mathjax>, you will need to leave this group intact.</p> <p>Second, we have two nitrogen atoms in the product side, and only one in the reactants side, therefore, we can multiply <mathjax>#NH_3#</mathjax> by <mathjax>#color(red)(2)#</mathjax>.</p> <p>Third, look at the hydrogen atoms, you will find <mathjax>#color(blue)(8)#</mathjax> in each side of the reaction, and therefore, your reaction is balanced.</p> <p>In some cases, I prefer to balance equations using groups (or polyatomic ions) rather than atoms.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/191410" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="191411" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/chiara-g-1"><img alt="" class="" src="https://profilepictures.socratic.org/Y0YMEEsQZuqC7ijLEFP2_DSC_0026_2.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/chiara-g-1"> Chiara G. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-21T10:29:55" itemprop="dateCreated"> Nov 21, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2NH_3 + H_2SO_4 → (NH_4)_2SO_4#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You need to make sure that all the <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> are equal on both sides.</p> <p>The first step is write down what you have</p> <p><mathjax>#NH_3 + H_2SO_4 → (NH_4)_2SO_4#</mathjax> </p> <p>N: 1 the side in front of the arrow, 2 on the side after the arrow<br/> H: 5 on the side before the arrow, 8 on the side after the arrow<br/> <mathjax>#SO_4#</mathjax>: 1 on each side</p> <p>Now you can see that you need to change the amount of N and H on the side in front of the arrow, to match the amount of N and H after the arrow.</p> <p>Step two add a number in front of the elements to make both side match:</p> <p><mathjax>#2NH_3 + H_2SO_4 → (NH_4)_2SO_4#</mathjax></p> <p>Step three, check again, make changes if necessary:<br/> N: 2 on both sides<br/> H: 8 on both sides<br/> <mathjax>#SO_4#</mathjax>: 1 on each side</p> <p>As you can see, the reaction is now balanced :)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/191411" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> 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Sodium phosphate and calcium chloride react to form... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-equation-kclo3-kcl-o2"> How can I balance this equation? ____ #KClO_3 -># ____ #KCl +# ____ #O_2# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-balancing-chemical-equations-important"> Why is balancing chemical equations important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/balancing-chemical-equations"> See all questions in Balancing Chemical Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2147 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How do you balance #NH_3 + H_2SO_4 -> (NH_4)_2SO_4#?	null
1,019	aab45b28-6ddd-11ea-81db-ccda262736ce	https://socratic.org/questions/how-many-hydrogen-atoms-are-in-five-molecules-of-h-2o	10	start physical_unit 2 3 number none qc_end end	[{"type":"physical unit","value":"Number [OF] hydrogen atoms"}]	[{"type":"physical unit","value":"10"}]	[{"type":"physical unit","value":"Number [OF] H2O molecules [=] \\pu{5}"}]	<h1 class="questionTitle" itemprop="name">How many hydrogen atoms are in five molecules of #H_2O#? </h1>	null	10	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>One molecule of <mathjax>#H_2O#</mathjax> has 2 hydrogens then 5 molecules of water has 2 x 5 = 10 hydrogen atoms.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>10</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>One molecule of <mathjax>#H_2O#</mathjax> has 2 hydrogens then 5 molecules of water has 2 x 5 = 10 hydrogen atoms.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many hydrogen atoms are in five molecules of #H_2O#? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="443691" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/doc048"><img alt="" class="" src="https://profilepictures.socratic.org/e4gaeUMMQESTpfte6aRu_Friendly%20Chem%20Professor.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/doc048"> Doc048 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-23T23:48:05" itemprop="dateCreated"> Jun 23, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>10</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>One molecule of <mathjax>#H_2O#</mathjax> has 2 hydrogens then 5 molecules of water has 2 x 5 = 10 hydrogen atoms.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/443691" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? 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1,020	aa7e3fd8-6ddd-11ea-a641-ccda262736ce	https://socratic.org/questions/how-would-you-use-the-henderson-hasselbalch-equation-to-calculate-the-ph-of-a-bu	4.02	start physical_unit 13 14 ph none qc_end physical_unit 22 22 17 18 molarity qc_end physical_unit 29 29 24 25 molarity qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"pH [OF] the buffer solution"}]	[{"type":"physical unit","value":"4.02"}]	[{"type":"physical unit","value":"Molarity [OF] HCO2H solution [=] \\pu{0.27 M}"},{"type":"physical unit","value":"Molarity [OF] HCO2Na solution [=] \\pu{0.50 M}"},{"type":"other","value":"Henderson-Hasselbalch equation."}]	<h1 class="questionTitle" itemprop="name">How would you use the Henderson-Hasselbalch equation to calculate the pH of a buffer solution that is 0.27 M in formic acid (HCO2H) and 0.50 M in sodium formate (HCO2Na)?</h1>	null	4.02	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your <a href="http://socratic.org/chemistry/reactions-in-solution/buffer-theory">buffer solution</a> contains <em>formic acid</em>, <mathjax>#"HCOOH"#</mathjax>, a weak acid, and <em>sodium formate</em>, <mathjax>#"HCOONa"#</mathjax>, the salt of its conjugate base, the <em>formate anion</em>, <mathjax>#"HCOO"^(-)#</mathjax>. </p> <p>The <strong>Henderson - Hasselbalch equation</strong> allows you to calculate the <a href="http://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> of the buffer by using the <mathjax>#pK_a#</mathjax> of the weak acid and the ratio that exists between the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">concentrations</a> of the weak cid and conjugate base. </p> <blockquote> <p><mathjax>#color(blue)("pH" = pK_a + log( (["conjugate base"])/(["weak acid"])))#</mathjax></p> </blockquote> <p>The <mathjax>#pK_a#</mathjax> of formic acid is equal to <mathjax>#3.75#</mathjax></p> <p><a href="http://clas.sa.ucsb.edu/staff/Resource%20folder/Chem109ABC/Acid,%20Base%20Strength/Table%20of%20Acids%20w%20Kas%20and%20pKas.pdf" rel="nofollow" target="_blank">http://clas.sa.ucsb.edu/staff/Resource%20folder/Chem109ABC/Acid,%20Base%20Strength/Table%20of%20Acids%20w%20Kas%20and%20pKas.pdf</a></p> <p>Before plugging in the values given to you, try to predict what you expect the pH of the solution to be. Notice that <strong>at equal concentrations</strong> of weak acid and conjugate base, the log term is equal to zero. </p> <p>In this case, the pH of the solution will be equal to the acid's <mathjax>#pK_a#</mathjax>. Now, if you have <strong>more conjugate base</strong> than weak acid, like you have here, you would expect the log term to return a <em>positive</em> value. </p> <p>This means that the pH will actually <strong>increase</strong>, which is what you should expect to see in this case. </p> <blockquote> <p><mathjax>#"pH" = pK_a + log( (["HCOO"^(-)])/(["HCOOH"]))#</mathjax></p> <p><mathjax>#"pH" = 3,.75 + log( (0.50color(red)(cancel(color(black)("M"))))/(0.27color(red)(cancel(color(black)("M")))))#</mathjax></p> <p><mathjax>#"pH" = 3.75 + 0.268 = color(green)(4.02)#</mathjax></p> </blockquote> <p>Indeed, the pH of the buffer is higher than the <mathjax>#pK_a#</mathjax> of the acid.</p> <p> <iframe src="https://www.youtube.com/embed/Ub7eLn6ddvg?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"pH" = 4.02#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your <a href="http://socratic.org/chemistry/reactions-in-solution/buffer-theory">buffer solution</a> contains <em>formic acid</em>, <mathjax>#"HCOOH"#</mathjax>, a weak acid, and <em>sodium formate</em>, <mathjax>#"HCOONa"#</mathjax>, the salt of its conjugate base, the <em>formate anion</em>, <mathjax>#"HCOO"^(-)#</mathjax>. </p> <p>The <strong>Henderson - Hasselbalch equation</strong> allows you to calculate the <a href="http://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> of the buffer by using the <mathjax>#pK_a#</mathjax> of the weak acid and the ratio that exists between the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">concentrations</a> of the weak cid and conjugate base. </p> <blockquote> <p><mathjax>#color(blue)("pH" = pK_a + log( (["conjugate base"])/(["weak acid"])))#</mathjax></p> </blockquote> <p>The <mathjax>#pK_a#</mathjax> of formic acid is equal to <mathjax>#3.75#</mathjax></p> <p><a href="http://clas.sa.ucsb.edu/staff/Resource%20folder/Chem109ABC/Acid,%20Base%20Strength/Table%20of%20Acids%20w%20Kas%20and%20pKas.pdf" rel="nofollow" target="_blank">http://clas.sa.ucsb.edu/staff/Resource%20folder/Chem109ABC/Acid,%20Base%20Strength/Table%20of%20Acids%20w%20Kas%20and%20pKas.pdf</a></p> <p>Before plugging in the values given to you, try to predict what you expect the pH of the solution to be. Notice that <strong>at equal concentrations</strong> of weak acid and conjugate base, the log term is equal to zero. </p> <p>In this case, the pH of the solution will be equal to the acid's <mathjax>#pK_a#</mathjax>. Now, if you have <strong>more conjugate base</strong> than weak acid, like you have here, you would expect the log term to return a <em>positive</em> value. </p> <p>This means that the pH will actually <strong>increase</strong>, which is what you should expect to see in this case. </p> <blockquote> <p><mathjax>#"pH" = pK_a + log( (["HCOO"^(-)])/(["HCOOH"]))#</mathjax></p> <p><mathjax>#"pH" = 3,.75 + log( (0.50color(red)(cancel(color(black)("M"))))/(0.27color(red)(cancel(color(black)("M")))))#</mathjax></p> <p><mathjax>#"pH" = 3.75 + 0.268 = color(green)(4.02)#</mathjax></p> </blockquote> <p>Indeed, the pH of the buffer is higher than the <mathjax>#pK_a#</mathjax> of the acid.</p> <p> <iframe src="https://www.youtube.com/embed/Ub7eLn6ddvg?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How would you use the Henderson-Hasselbalch equation to calculate the pH of a buffer solution that is 0.27 M in formic acid (HCO2H) and 0.50 M in sodium formate (HCO2Na)?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#reactions-in-solution" itemprop="url"> <span class="breadcrumb" itemprop="title">Reactions in Solution</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/reactions-in-solution/buffer-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">Buffer Calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="189833" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-17T15:01:15" itemprop="dateCreated"> Nov 17, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"pH" = 4.02#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your <a href="http://socratic.org/chemistry/reactions-in-solution/buffer-theory">buffer solution</a> contains <em>formic acid</em>, <mathjax>#"HCOOH"#</mathjax>, a weak acid, and <em>sodium formate</em>, <mathjax>#"HCOONa"#</mathjax>, the salt of its conjugate base, the <em>formate anion</em>, <mathjax>#"HCOO"^(-)#</mathjax>. </p> <p>The <strong>Henderson - Hasselbalch equation</strong> allows you to calculate the <a href="http://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> of the buffer by using the <mathjax>#pK_a#</mathjax> of the weak acid and the ratio that exists between the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">concentrations</a> of the weak cid and conjugate base. </p> <blockquote> <p><mathjax>#color(blue)("pH" = pK_a + log( (["conjugate base"])/(["weak acid"])))#</mathjax></p> </blockquote> <p>The <mathjax>#pK_a#</mathjax> of formic acid is equal to <mathjax>#3.75#</mathjax></p> <p><a href="http://clas.sa.ucsb.edu/staff/Resource%20folder/Chem109ABC/Acid,%20Base%20Strength/Table%20of%20Acids%20w%20Kas%20and%20pKas.pdf" rel="nofollow" target="_blank">http://clas.sa.ucsb.edu/staff/Resource%20folder/Chem109ABC/Acid,%20Base%20Strength/Table%20of%20Acids%20w%20Kas%20and%20pKas.pdf</a></p> <p>Before plugging in the values given to you, try to predict what you expect the pH of the solution to be. Notice that <strong>at equal concentrations</strong> of weak acid and conjugate base, the log term is equal to zero. </p> <p>In this case, the pH of the solution will be equal to the acid's <mathjax>#pK_a#</mathjax>. Now, if you have <strong>more conjugate base</strong> than weak acid, like you have here, you would expect the log term to return a <em>positive</em> value. </p> <p>This means that the pH will actually <strong>increase</strong>, which is what you should expect to see in this case. </p> <blockquote> <p><mathjax>#"pH" = pK_a + log( (["HCOO"^(-)])/(["HCOOH"]))#</mathjax></p> <p><mathjax>#"pH" = 3,.75 + log( (0.50color(red)(cancel(color(black)("M"))))/(0.27color(red)(cancel(color(black)("M")))))#</mathjax></p> <p><mathjax>#"pH" = 3.75 + 0.268 = color(green)(4.02)#</mathjax></p> </blockquote> <p>Indeed, the pH of the buffer is higher than the <mathjax>#pK_a#</mathjax> of the acid.</p> <p> <iframe src="https://www.youtube.com/embed/Ub7eLn6ddvg?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/189833" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-buffer-solutions-used"> How are buffer solutions used? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-buffer-capacity"> How do you calculate buffer capacity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-buffer-solutions-maintain-the-ph-of-blood"> How do buffer solutions maintain the pH of blood? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-buffer-a-solution-with-a-ph-of-12"> How do you buffer a solution with a pH of 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-buffer-solutions-used-to-calibrate-ph"> Why are buffer solutions used to calibrate pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is--solution-used-in-complexometric-titration"> What is the role of buffer solution in complexometric titrations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-you-would-make-100-0-ml-of-a-bu-er-solution-with-a-ph-of-10-80-to-be-made-us"> How you would make 100.0 ml of a 1.00 mol/L buffer solution with a pH of 10.80 to be made using... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-henderson-hasselbalch-equation"> What is the Henderson-Hasselbalch equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-an-example-of-a-ph-buffer-calculation-problem"> What is an example of a pH buffer calculation problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-bicarbonate-buffering-system-important"> Why is the bicarbonate buffering system important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/reactions-in-solution/buffer-calculations"> See all questions in Buffer Calculations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 139888 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How would you use the Henderson-Hasselbalch equation to calculate the pH of a buffer solution that is 0.27 M in formic acid (HCO2H) and 0.50 M in sodium formate (HCO2Na)?	null
1,021	ab5601f6-6ddd-11ea-a801-ccda262736ce	https://socratic.org/questions/if-lithium-has-a-first-ionisation-energy-of-520kjmol-1-estimate-the-energy-requi	8.64 × 10^(-19) J	start physical_unit 17 18 energy j qc_end physical_unit 1 1 8 9 first_ionisation_energy qc_end physical_unit 21 22 16 16 number qc_end physical_unit 17 18 16 16 number qc_end end	[{"type":"physical unit","value":"Required energy [OF] Li+ ion [IN] J"}]	[{"type":"physical unit","value":"8.64 × 10^(-19) J"}]	[{"type":"physical unit","value":"First ionisation energy [OF] lithium [=] \\pu{520 kJ/mol}"},{"type":"physical unit","value":"Number [OF] Li atom [=] \\pu{1}"},{"type":"physical unit","value":"Number [OF] Li+ ion [=] \\pu{1}"}]	<h1 class="questionTitle" itemprop="name">If lithium has a first ionisation energy of #520# #kJ# #mol^(-1)#, estimate the energy required to form 1 #Li^+# ion from 1 Li atom?</h1>	null	8.64 × 10^(-19) J	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The ionization energy tells us that for 1 mole of gaseous lithium, <mathjax>#520kJ#</mathjax> of energy is needed to ionise each atom.</p> <p>We also know that 1 mole contains <mathjax>#6.0210^23#</mathjax> atoms (to <mathjax>#3#</mathjax> s.f.)</p> <p>So, 1 atom = <mathjax>#1/(6.0210^23)=6.0210^(-23) mol#</mathjax></p> <p><mathjax>#520kJ=520000J=5.210^5J#</mathjax></p> <p><mathjax>#(5.210^5)(6.0210^(-23))=8.6410^(-19)J#</mathjax></p> <p><mathjax>#(8.6410^(-19))/(1.60*10^(-19))=5.40eV#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Around <mathjax>#8.6410^(-19)J=5.40eV#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The ionization energy tells us that for 1 mole of gaseous lithium, <mathjax>#520kJ#</mathjax> of energy is needed to ionise each atom.</p> <p>We also know that 1 mole contains <mathjax>#6.0210^23#</mathjax> atoms (to <mathjax>#3#</mathjax> s.f.)</p> <p>So, 1 atom = <mathjax>#1/(6.0210^23)=6.0210^(-23) mol#</mathjax></p> <p><mathjax>#520kJ=520000J=5.210^5J#</mathjax></p> <p><mathjax>#(5.210^5)(6.0210^(-23))=8.6410^(-19)J#</mathjax></p> <p><mathjax>#(8.6410^(-19))/(1.6010^(-19))=5.40eV#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">If lithium has a first ionisation energy of #520# #kJ# #mol^(-1)#, estimate the energy required to form 1 #Li^+# ion from 1 Li atom?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-periodic-table" itemprop="url"> <span class="breadcrumb" itemprop="title">The Periodic Table</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-periodic-table/periodic-trends-in-ionization-energy" itemprop="url"> <span class="breadcrumb" itemprop="title">Periodic Trends in Ionization Energy</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="505853" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/1s2s2p"><img alt="" class="" src="https://profilepictures.socratic.org/cPx8AUZQiuNupyQTJzyw_Pinball.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/1s2s2p"> 1s2s2p </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-11-15T08:33:18" itemprop="dateCreated"> Nov 15, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Around <mathjax>#8.6410^(-19)J=5.40eV#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The ionization energy tells us that for 1 mole of gaseous lithium, <mathjax>#520kJ#</mathjax> of energy is needed to ionise each atom.</p> <p>We also know that 1 mole contains <mathjax>#6.0210^23#</mathjax> atoms (to <mathjax>#3#</mathjax> s.f.)</p> <p>So, 1 atom = <mathjax>#1/(6.0210^23)=6.0210^(-23) mol#</mathjax></p> <p><mathjax>#520kJ=520000J=5.210^5J#</mathjax></p> <p><mathjax>#(5.210^5)(6.0210^(-23))=8.6410^(-19)J#</mathjax></p> <p><mathjax>#(8.6410^(-19))/(1.6010^(-19))=5.40eV#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/505853" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="505856" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> <a class="secondContributorPic" href="/users/1s2s2p"><img alt="" class="" src="https://profilepictures.socratic.org/cPx8AUZQiuNupyQTJzyw_Pinball.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a>·<a class="topContributorLink" href="/users/1s2s2p"> 1s2s2p </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-11-15T08:39:10" itemprop="dateCreated"> Nov 15, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We are given the first ionization energy of the lithium atom....</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>That is we are given data for the reaction:</p> <p><mathjax>#Li(g) +Delta rarr Li^+(g)+e^(-)#</mathjax>...</p> <p>Where <mathjax>#Delta=520kJmol^-1#</mathjax>, and when we write <mathjax>#kJmol^-1#</mathjax> we mean PER MOLE of reaction as written.....</p> <p>And given the equation we need <mathjax>#520kJ#</mathjax> to produce a mole of gaseous lithium cations....</p> <p>To produce a SINGLE LITHIUM CATION, we divide the molar quantity by the Avocado number....the number of avocadoes in a mole, <mathjax>#N_A=6.022xx10^23mol^-1#</mathjax>.</p> <p><mathjax>#(520kJmol^-1)/(6.022xx10^23mol^-1)=8.64xx10^-22kJ=8.64xx10^-19J#</mathjax>. We could convert this value to <mathjax>#"ergs"#</mathjax> or <mathjax>#cm^-1#</mathjax> or <mathjax>#eV#</mathjax> if we are real masochists.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/505856" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-ionization-energy-relate-to-reactivity"> How does ionization energy relate to reactivity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-ionization-energy-measured-in"> What is ionization energy measured in? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-the-first-and-second-ionization-energies"> What are the first and second ionization energies? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-ionization-energy-increase"> How does ionization energy increase? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-ionization-energy-change-down-a-group"> How does ionization energy change down a group? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-trends-in-atomic-radius-relate-to-ionization-energy"> How do trends in atomic radius relate to ionization energy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/53f00f0102bf346733644238"> Question #44238 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/54a13803581e2a1c2d5fbdfe"> Question #fbdfe </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/54c642dc581e2a50cea1a23b"> Question #1a23b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/54e18faf581e2a2f288d7de9"> Question #d7de9 </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-periodic-table/periodic-trends-in-ionization-energy"> See all questions in Periodic Trends in Ionization Energy </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 21430 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	If lithium has a first ionisation energy of #520# #kJ# #mol^(-1)#, estimate the energy required to form 1 #Li^+# ion from 1 Li atom?	null
1,022	ac0d5a28-6ddd-11ea-8f5f-ccda262736ce	https://socratic.org/questions/how-many-grams-of-iron-ii-sulfide-per-liter-will-dissolve-in-a-0-20m-sodium-sulf	2.4 × 10^(-15) grams	start physical_unit 4 5 mass g qc_end physical_unit 14 16 12 13 molarity qc_end physical_unit 14 15 19 21 equilibrium_constant_k qc_end end	[{"type":"physical unit","value":"Mass [OF] Iron(II) sulfide [IN] grams"}]	[{"type":"physical unit","value":"2.4 × 10^(-15) grams"}]	[{"type":"physical unit","value":"Volume [OF] sodium sulfide solution [=] \\pu{1 liter}"},{"type":"physical unit","value":"Molarity [OF] sodium sulfide solution [=] \\pu{0.20 M}"},{"type":"physical unit","value":"Ksp [OF] sodium sulfide [=] \\pu{4.9 × 10^(-18)}"}]	<h1 class="questionTitle" itemprop="name">How many grams of Iron(II) sulfide will dissolve per liter in a #"0.20-M"# sodium sulfide solution? </h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>I don't get how to do this type of problem, I can do other Ksp stuff but don't understand the process for this.</p> <p><mathjax>#K_(sp) = 4.9 * 10^(-18)#</mathjax></p></div> </h2> </div> </div>	2.4 × 10^(-15) grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You know that iron(II) sulfide is considered <em>insoluble</em> in water, which implies that when you dissolve this salt in water, a dissociation equilibrium is established between the undissolved solid and the dissolved ions.</p> <blockquote> <p><mathjax>#"FeS"_ ((s)) rightleftharpoons "Fe"_ ((s))^(2+) + "S"_ ((aq))^(2-)#</mathjax></p> </blockquote> <p>Notice that <strong>every mole</strong> of iron(II) sulfide <strong>that dissociates</strong> produces <mathjax>#1#</mathjax> <strong>mole</strong> of iron(II) cations and <mathjax>#1#</mathjax> <strong>mole</strong> of sulfide anions. </p> <p>By definition, the <strong>solubility product constant</strong> for this equilibrium looks like this</p> <blockquote> <p><mathjax>#K_(sp) = ["Fe"^(2+)] * ["S"^(2-)]#</mathjax></p> </blockquote> <p>Now, let's say that <mathjax>#s#</mathjax> <mathjax>#"M"#</mathjax> represents the concentration of iron(II) sulfide <strong>that dissociates</strong> in water to produce a <strong>saturated solution</strong> of iron(II) sulfide, i.e. the number of moles per <mathjax>#"1 L"#</mathjax> of the solution. </p> <p>According to the equilibrium equation, if <mathjax>#s#</mathjax> <mathjax>#"M"#</mathjax> of the salt dissociates to produce ions, then the resulting solution will contain <mathjax>#s#</mathjax> <mathjax>#"M"#</mathjax> of iron(II) cations and <mathjax>#s#</mathjax> <mathjax>#"M"#</mathjax> of sulfide anions. </p> <p>You can thus say that <strong>in pure water</strong>, the expression of the solubility product constant will be--I'll write the equation <em>without added units</em>.</p> <blockquote> <p><mathjax>#K_(sp) = s * s = s^2#</mathjax></p> </blockquote> <p>This is the case because pure water doesn't contain any iron(II) cations or sulfide anions, so the two ions will have an equal concentration of <mathjax>#s#</mathjax> <mathjax>#"M"#</mathjax>.</p> <p>However, you're not dealing with pure water here. Your solution contains sodium sulfide, <mathjax>#"Na"_2"S"#</mathjax>, a <strong>soluble</strong> ionic compound that exists as ions in aqueous solution.</p> <blockquote> <p><mathjax>#"Na"_ 2"S"_ ((aq)) -> 2"Na"_ ((aq))^(+) + "S"_ ((aq))^(2-)#</mathjax></p> </blockquote> <p>Since sodium sulfide dissociates in a <mathjax>#1:1#</mathjax> <strong>mole ratio</strong> to produce sulfide anions, you can say that your solution has</p> <blockquote> <p><mathjax>#["S"^(2-)]_ 0 = ["Na"_ 2"S"] = "0.20 M"#</mathjax></p> </blockquote> <p>So now when you add the iron(II) sulfide, you say that <mathjax>#s#</mathjax> <mathjax>#"M"#</mathjax> will dissociate to produce <mathjax>#s#</mathjax> <mathjax>#"M"#</mathjax> of iron(II) cations and <mathjax>#s#</mathjax> <mathjax>#"M"#</mathjax> of sulfide anions, but since the solution already contains some sufide anions, their equilibrium concentration will be </p> <blockquote> <p><mathjax>#["S"^(2-)] = ["S"^(2-)]_ 0 + s#</mathjax></p> </blockquote> <p>which is </p> <blockquote> <p><mathjax>#["S"^(2-)] = overbrace("0.20 M")^(color(blue)("already in solution")) + overbrace(s quad "M")^(color(blue)("what dissociates"))#</mathjax></p> <p><mathjax>#["S"^(2-)] = (0.20 + s) quad "M"#</mathjax></p> </blockquote> <p>So in this case, the expression of the solubility equilibrium constant looks like this</p> <blockquote> <p><mathjax>#K_(sp) = s * (0.20 + s)#</mathjax></p> </blockquote> <p>which is equivalent to </p> <blockquote> <p><mathjax># s^2 + 0.20 * s - 4.9 * 10^(-18) = 0#</mathjax></p> </blockquote> <p>This quadratic equation will produce two <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a>, one positive and one negative. Since <mathjax>#s#</mathjax> is supposed to represent <em>concentration</em>, you can discard the negative solution and say that</p> <blockquote> <p><mathjax>#s = 2.776 * 10^(-17)#</mathjax></p> </blockquote> <p>Now, we've said that <mathjax>#s#</mathjax> <mathjax>#"M"#</mathjax> represents the number of moles of iron(II) sulfide <strong>that dissociate</strong> in <mathjax>#"1 L"#</mathjax> of solution to produce a saturated solution of iron(II) sulfide, i.e. the <strong>molar solubility</strong> of the salt at the given temperature. </p> <p>In other words, you can only hope to dissolve <mathjax>#2.776 * 10^(-17)#</mathjax> <strong>moles</strong> of iron(II) sulfide in <mathjax>#"1 L"#</mathjax> of solution to have a saturated solution of this salt. </p> <p>To find the solubility in <em>grams per liter</em>, use the <strong>molar mass</strong> of iron(II) sulfide</p> <blockquote> <p><mathjax>#(2.776 * 10^(-17) color(red)(cancel(color(black)("moles FeS"))))/("1 L solution") * "87.91 g"/(1color(red)(cancel(color(black)("mole FeS")))) = color(darkgreen)(ul(color(black)(2.4 * 10^(-15) quad "g L"^(-1))))#</mathjax></p> </blockquote> <p>The answer is rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2.4 * 10^(-15)#</mathjax> <mathjax>#"g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You know that iron(II) sulfide is considered <em>insoluble</em> in water, which implies that when you dissolve this salt in water, a dissociation equilibrium is established between the undissolved solid and the dissolved ions.</p> <blockquote> <p><mathjax>#"FeS"_ ((s)) rightleftharpoons "Fe"_ ((s))^(2+) + "S"_ ((aq))^(2-)#</mathjax></p> </blockquote> <p>Notice that <strong>every mole</strong> of iron(II) sulfide <strong>that dissociates</strong> produces <mathjax>#1#</mathjax> <strong>mole</strong> of iron(II) cations and <mathjax>#1#</mathjax> <strong>mole</strong> of sulfide anions. </p> <p>By definition, the <strong>solubility product constant</strong> for this equilibrium looks like this</p> <blockquote> <p><mathjax>#K_(sp) = ["Fe"^(2+)] * ["S"^(2-)]#</mathjax></p> </blockquote> <p>Now, let's say that <mathjax>#s#</mathjax> <mathjax>#"M"#</mathjax> represents the concentration of iron(II) sulfide <strong>that dissociates</strong> in water to produce a <strong>saturated solution</strong> of iron(II) sulfide, i.e. the number of moles per <mathjax>#"1 L"#</mathjax> of the solution. </p> <p>According to the equilibrium equation, if <mathjax>#s#</mathjax> <mathjax>#"M"#</mathjax> of the salt dissociates to produce ions, then the resulting solution will contain <mathjax>#s#</mathjax> <mathjax>#"M"#</mathjax> of iron(II) cations and <mathjax>#s#</mathjax> <mathjax>#"M"#</mathjax> of sulfide anions. </p> <p>You can thus say that <strong>in pure water</strong>, the expression of the solubility product constant will be--I'll write the equation <em>without added units</em>.</p> <blockquote> <p><mathjax>#K_(sp) = s * s = s^2#</mathjax></p> </blockquote> <p>This is the case because pure water doesn't contain any iron(II) cations or sulfide anions, so the two ions will have an equal concentration of <mathjax>#s#</mathjax> <mathjax>#"M"#</mathjax>.</p> <p>However, you're not dealing with pure water here. Your solution contains sodium sulfide, <mathjax>#"Na"_2"S"#</mathjax>, a <strong>soluble</strong> ionic compound that exists as ions in aqueous solution.</p> <blockquote> <p><mathjax>#"Na"_ 2"S"_ ((aq)) -> 2"Na"_ ((aq))^(+) + "S"_ ((aq))^(2-)#</mathjax></p> </blockquote> <p>Since sodium sulfide dissociates in a <mathjax>#1:1#</mathjax> <strong>mole ratio</strong> to produce sulfide anions, you can say that your solution has</p> <blockquote> <p><mathjax>#["S"^(2-)]_ 0 = ["Na"_ 2"S"] = "0.20 M"#</mathjax></p> </blockquote> <p>So now when you add the iron(II) sulfide, you say that <mathjax>#s#</mathjax> <mathjax>#"M"#</mathjax> will dissociate to produce <mathjax>#s#</mathjax> <mathjax>#"M"#</mathjax> of iron(II) cations and <mathjax>#s#</mathjax> <mathjax>#"M"#</mathjax> of sulfide anions, but since the solution already contains some sufide anions, their equilibrium concentration will be </p> <blockquote> <p><mathjax>#["S"^(2-)] = ["S"^(2-)]_ 0 + s#</mathjax></p> </blockquote> <p>which is </p> <blockquote> <p><mathjax>#["S"^(2-)] = overbrace("0.20 M")^(color(blue)("already in solution")) + overbrace(s quad "M")^(color(blue)("what dissociates"))#</mathjax></p> <p><mathjax>#["S"^(2-)] = (0.20 + s) quad "M"#</mathjax></p> </blockquote> <p>So in this case, the expression of the solubility equilibrium constant looks like this</p> <blockquote> <p><mathjax>#K_(sp) = s * (0.20 + s)#</mathjax></p> </blockquote> <p>which is equivalent to </p> <blockquote> <p><mathjax># s^2 + 0.20 * s - 4.9 * 10^(-18) = 0#</mathjax></p> </blockquote> <p>This quadratic equation will produce two <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a>, one positive and one negative. Since <mathjax>#s#</mathjax> is supposed to represent <em>concentration</em>, you can discard the negative solution and say that</p> <blockquote> <p><mathjax>#s = 2.776 * 10^(-17)#</mathjax></p> </blockquote> <p>Now, we've said that <mathjax>#s#</mathjax> <mathjax>#"M"#</mathjax> represents the number of moles of iron(II) sulfide <strong>that dissociate</strong> in <mathjax>#"1 L"#</mathjax> of solution to produce a saturated solution of iron(II) sulfide, i.e. the <strong>molar solubility</strong> of the salt at the given temperature. </p> <p>In other words, you can only hope to dissolve <mathjax>#2.776 * 10^(-17)#</mathjax> <strong>moles</strong> of iron(II) sulfide in <mathjax>#"1 L"#</mathjax> of solution to have a saturated solution of this salt. </p> <p>To find the solubility in <em>grams per liter</em>, use the <strong>molar mass</strong> of iron(II) sulfide</p> <blockquote> <p><mathjax>#(2.776 * 10^(-17) color(red)(cancel(color(black)("moles FeS"))))/("1 L solution") * "87.91 g"/(1color(red)(cancel(color(black)("mole FeS")))) = color(darkgreen)(ul(color(black)(2.4 * 10^(-15) quad "g L"^(-1))))#</mathjax></p> </blockquote> <p>The answer is rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many grams of Iron(II) sulfide will dissolve per liter in a #"0.20-M"# sodium sulfide solution? </h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>I don't get how to do this type of problem, I can do other Ksp stuff but don't understand the process for this.</p> <p><mathjax>#K_(sp) = 4.9 * 10^(-18)#</mathjax></p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-equilibrium" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Equilibrium</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-equilibrium/solubility-equilbria" itemprop="url"> <span class="breadcrumb" itemprop="title">Solubility Equilbria</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="556555" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-02-23T00:22:33" itemprop="dateCreated"> Feb 23, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2.4 * 10^(-15)#</mathjax> <mathjax>#"g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You know that iron(II) sulfide is considered <em>insoluble</em> in water, which implies that when you dissolve this salt in water, a dissociation equilibrium is established between the undissolved solid and the dissolved ions.</p> <blockquote> <p><mathjax>#"FeS"_ ((s)) rightleftharpoons "Fe"_ ((s))^(2+) + "S"_ ((aq))^(2-)#</mathjax></p> </blockquote> <p>Notice that <strong>every mole</strong> of iron(II) sulfide <strong>that dissociates</strong> produces <mathjax>#1#</mathjax> <strong>mole</strong> of iron(II) cations and <mathjax>#1#</mathjax> <strong>mole</strong> of sulfide anions. </p> <p>By definition, the <strong>solubility product constant</strong> for this equilibrium looks like this</p> <blockquote> <p><mathjax>#K_(sp) = ["Fe"^(2+)] * ["S"^(2-)]#</mathjax></p> </blockquote> <p>Now, let's say that <mathjax>#s#</mathjax> <mathjax>#"M"#</mathjax> represents the concentration of iron(II) sulfide <strong>that dissociates</strong> in water to produce a <strong>saturated solution</strong> of iron(II) sulfide, i.e. the number of moles per <mathjax>#"1 L"#</mathjax> of the solution. </p> <p>According to the equilibrium equation, if <mathjax>#s#</mathjax> <mathjax>#"M"#</mathjax> of the salt dissociates to produce ions, then the resulting solution will contain <mathjax>#s#</mathjax> <mathjax>#"M"#</mathjax> of iron(II) cations and <mathjax>#s#</mathjax> <mathjax>#"M"#</mathjax> of sulfide anions. </p> <p>You can thus say that <strong>in pure water</strong>, the expression of the solubility product constant will be--I'll write the equation <em>without added units</em>.</p> <blockquote> <p><mathjax>#K_(sp) = s * s = s^2#</mathjax></p> </blockquote> <p>This is the case because pure water doesn't contain any iron(II) cations or sulfide anions, so the two ions will have an equal concentration of <mathjax>#s#</mathjax> <mathjax>#"M"#</mathjax>.</p> <p>However, you're not dealing with pure water here. Your solution contains sodium sulfide, <mathjax>#"Na"_2"S"#</mathjax>, a <strong>soluble</strong> ionic compound that exists as ions in aqueous solution.</p> <blockquote> <p><mathjax>#"Na"_ 2"S"_ ((aq)) -> 2"Na"_ ((aq))^(+) + "S"_ ((aq))^(2-)#</mathjax></p> </blockquote> <p>Since sodium sulfide dissociates in a <mathjax>#1:1#</mathjax> <strong>mole ratio</strong> to produce sulfide anions, you can say that your solution has</p> <blockquote> <p><mathjax>#["S"^(2-)]_ 0 = ["Na"_ 2"S"] = "0.20 M"#</mathjax></p> </blockquote> <p>So now when you add the iron(II) sulfide, you say that <mathjax>#s#</mathjax> <mathjax>#"M"#</mathjax> will dissociate to produce <mathjax>#s#</mathjax> <mathjax>#"M"#</mathjax> of iron(II) cations and <mathjax>#s#</mathjax> <mathjax>#"M"#</mathjax> of sulfide anions, but since the solution already contains some sufide anions, their equilibrium concentration will be </p> <blockquote> <p><mathjax>#["S"^(2-)] = ["S"^(2-)]_ 0 + s#</mathjax></p> </blockquote> <p>which is </p> <blockquote> <p><mathjax>#["S"^(2-)] = overbrace("0.20 M")^(color(blue)("already in solution")) + overbrace(s quad "M")^(color(blue)("what dissociates"))#</mathjax></p> <p><mathjax>#["S"^(2-)] = (0.20 + s) quad "M"#</mathjax></p> </blockquote> <p>So in this case, the expression of the solubility equilibrium constant looks like this</p> <blockquote> <p><mathjax>#K_(sp) = s * (0.20 + s)#</mathjax></p> </blockquote> <p>which is equivalent to </p> <blockquote> <p><mathjax># s^2 + 0.20 * s - 4.9 * 10^(-18) = 0#</mathjax></p> </blockquote> <p>This quadratic equation will produce two <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a>, one positive and one negative. Since <mathjax>#s#</mathjax> is supposed to represent <em>concentration</em>, you can discard the negative solution and say that</p> <blockquote> <p><mathjax>#s = 2.776 * 10^(-17)#</mathjax></p> </blockquote> <p>Now, we've said that <mathjax>#s#</mathjax> <mathjax>#"M"#</mathjax> represents the number of moles of iron(II) sulfide <strong>that dissociate</strong> in <mathjax>#"1 L"#</mathjax> of solution to produce a saturated solution of iron(II) sulfide, i.e. the <strong>molar solubility</strong> of the salt at the given temperature. </p> <p>In other words, you can only hope to dissolve <mathjax>#2.776 * 10^(-17)#</mathjax> <strong>moles</strong> of iron(II) sulfide in <mathjax>#"1 L"#</mathjax> of solution to have a saturated solution of this salt. </p> <p>To find the solubility in <em>grams per liter</em>, use the <strong>molar mass</strong> of iron(II) sulfide</p> <blockquote> <p><mathjax>#(2.776 * 10^(-17) color(red)(cancel(color(black)("moles FeS"))))/("1 L solution") * "87.91 g"/(1color(red)(cancel(color(black)("mole FeS")))) = color(darkgreen)(ul(color(black)(2.4 * 10^(-15) quad "g L"^(-1))))#</mathjax></p> </blockquote> <p>The answer is rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/556555" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-solubility-affect-equilibrium"> How does solubility affect equilibrium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5351cdc002bf345ec38f076a"> Question #f076a </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-solubility-of-calcium-hydroxide"> How can I calculate solubility of calcium hydroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-an-example-of-a-solubility-equilibria-practice-problem"> What is an example of a solubility equilibria practice problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-common-mistakes-students-make-with-solubility-equilibria"> What are some common mistakes students make with solubility equilibria? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-examples-of-solubility-equilibria"> What are some examples of solubility equilibria? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-write-the-solubility-equilibrium-equation"> How can I write the solubility equilibrium equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-solubility-equilibrium-a-type-of-dynamic-equilibrium"> Is solubility equilibrium a type of dynamic equilibrium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-temperature-affect-solubility-equilibrium"> How does temperature affect solubility equilibrium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-solubility-equilibrium"> How can I calculate solubility equilibrium? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-equilibrium/solubility-equilbria"> See all questions in Solubility Equilbria </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 6963 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many grams of Iron(II) sulfide will dissolve per liter in a #"0.20-M"# sodium sulfide solution?	I don't get how to do this type of problem, I can do other Ksp stuff but don't understand the process for this. #K_(sp) = 4.9 * 10^(-18)#
1,023	aabd7fb6-6ddd-11ea-952d-ccda262736ce	https://socratic.org/questions/how-many-moles-are-equivalent-to-2-50-10-20-atoms-of-fe	4.15 × 10^(-4) moles	start physical_unit 11 11 mole mol qc_end end	[{"type":"physical unit","value":"Mole [OF] Fe [IN] moles"}]	[{"type":"physical unit","value":"4.15 × 10^(-4) moles"}]	[{"type":"physical unit","value":"Number [OF] Fe atoms [=] \\pu{2.50 × 10^20}"}]	<h1 class="questionTitle" itemprop="name">How many moles are equivalent to #2.50 * 10^20# atoms of #Fe#?</h1>	null	4.15 × 10^(-4) moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So we take the quotient:</p> <p><mathjax>#(2.50xx10^20" iron atoms")/(6.022140857(74)×10^23" iron atoms"*mol^-1)#</mathjax></p> <p><mathjax>#=#</mathjax> <mathjax>#??mol#</mathjax></p> <p>What is the mass of this molar quantity of iron. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>There are <mathjax>#6.022140857(74)×10^23#</mathjax> <mathjax>#Fe#</mathjax> atoms in <mathjax>#1#</mathjax> <mathjax>#mol#</mathjax> of iron.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So we take the quotient:</p> <p><mathjax>#(2.50xx10^20" iron atoms")/(6.022140857(74)×10^23" iron atoms"*mol^-1)#</mathjax></p> <p><mathjax>#=#</mathjax> <mathjax>#??mol#</mathjax></p> <p>What is the mass of this molar quantity of iron. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles are equivalent to #2.50 * 10^20# atoms of #Fe#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="276818" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-13T06:50:42" itemprop="dateCreated"> Jun 13, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>There are <mathjax>#6.022140857(74)×10^23#</mathjax> <mathjax>#Fe#</mathjax> atoms in <mathjax>#1#</mathjax> <mathjax>#mol#</mathjax> of iron.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So we take the quotient:</p> <p><mathjax>#(2.50xx10^20" iron atoms")/(6.022140857(74)×10^23" iron atoms"*mol^-1)#</mathjax></p> <p><mathjax>#=#</mathjax> <mathjax>#??mol#</mathjax></p> <p>What is the mass of this molar quantity of iron. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/276818" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 18490 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many moles are equivalent to #2.50 * 10^20# atoms of #Fe#?	null
1,024	ace33b4b-6ddd-11ea-84ec-ccda262736ce	https://socratic.org/questions/how-many-moles-of-gas-at-5-60-atm-and-300-k-will-occupy-a-volume-of-10-0-l	2.28 moles	start physical_unit 4 4 mole mol qc_end physical_unit 4 4 9 10 temperature qc_end physical_unit 4 4 6 7 pressure qc_end physical_unit 4 4 16 17 volume qc_end end	[{"type":"physical unit","value":"Mole [OF] the gas [IN] moles"}]	[{"type":"physical unit","value":"2.28 moles"}]	[{"type":"physical unit","value":"Temperature [OF] the gas [=] \\pu{300 K}"},{"type":"physical unit","value":"Pressure [OF] the gas [=] \\pu{5.60 atm}"},{"type":"physical unit","value":"Volume [OF] the gas [=] \\pu{10.0 L}"}]	<h1 class="questionTitle" itemprop="name">How many moles of gas at 5.60 atm and 300 K will occupy a volume of 10.0 L?</h1>	null	2.28 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> equation</p> <p><mathjax>#PV=nRT#</mathjax></p> <p>where</p> <p><mathjax>#P="pressure"=5.60#</mathjax> <mathjax>#"atm"#</mathjax><br/> <mathjax>#V="volume"=10.0#</mathjax> <mathjax>#"L"#</mathjax><br/> <mathjax>#n="moles"#</mathjax><br/> <mathjax>#R="ideal gas constant"=0.082#</mathjax> <mathjax>#("L atm")/("K mol")#</mathjax><br/> <mathjax>#T="temperature"=300#</mathjax> <mathjax>#"K"#</mathjax></p> <p>Since we want to find the amount of moles, we can rearrange the equation by dividing by <mathjax>#RT#</mathjax>.</p> <p><mathjax>#n=(PV)/(RT)#</mathjax></p> <p><mathjax>#n=(5.60xx10.0)/(.082xx300)=2.28#</mathjax> <mathjax>#"mol"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2.28#</mathjax> <mathjax>#"mol"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> equation</p> <p><mathjax>#PV=nRT#</mathjax></p> <p>where</p> <p><mathjax>#P="pressure"=5.60#</mathjax> <mathjax>#"atm"#</mathjax><br/> <mathjax>#V="volume"=10.0#</mathjax> <mathjax>#"L"#</mathjax><br/> <mathjax>#n="moles"#</mathjax><br/> <mathjax>#R="ideal gas constant"=0.082#</mathjax> <mathjax>#("L atm")/("K mol")#</mathjax><br/> <mathjax>#T="temperature"=300#</mathjax> <mathjax>#"K"#</mathjax></p> <p>Since we want to find the amount of moles, we can rearrange the equation by dividing by <mathjax>#RT#</mathjax>.</p> <p><mathjax>#n=(PV)/(RT)#</mathjax></p> <p><mathjax>#n=(5.60xx10.0)/(.082xx300)=2.28#</mathjax> <mathjax>#"mol"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles of gas at 5.60 atm and 300 K will occupy a volume of 10.0 L?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/stoichiometry-involving-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="201212" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/mason-m"><img alt="" class="" src="https://profilepictures.socratic.org/U70pu8hUTGGkEuy92fsO_IMG_2585.jpeg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/mason-m"> mason m </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-19T13:24:20" itemprop="dateCreated"> Dec 19, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2.28#</mathjax> <mathjax>#"mol"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> equation</p> <p><mathjax>#PV=nRT#</mathjax></p> <p>where</p> <p><mathjax>#P="pressure"=5.60#</mathjax> <mathjax>#"atm"#</mathjax><br/> <mathjax>#V="volume"=10.0#</mathjax> <mathjax>#"L"#</mathjax><br/> <mathjax>#n="moles"#</mathjax><br/> <mathjax>#R="ideal gas constant"=0.082#</mathjax> <mathjax>#("L atm")/("K mol")#</mathjax><br/> <mathjax>#T="temperature"=300#</mathjax> <mathjax>#"K"#</mathjax></p> <p>Since we want to find the amount of moles, we can rearrange the equation by dividing by <mathjax>#RT#</mathjax>.</p> <p><mathjax>#n=(PV)/(RT)#</mathjax></p> <p><mathjax>#n=(5.60xx10.0)/(.082xx300)=2.28#</mathjax> <mathjax>#"mol"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/201212" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> 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all questions in Gas Stoichiometry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1406 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many moles of gas at 5.60 atm and 300 K will occupy a volume of 10.0 L?	null
1,025	ad21794c-6ddd-11ea-bdd8-ccda262736ce	https://socratic.org/questions/what-amount-of-heat-is-required-to-completely-melt-a-29-95-gram-sample-of-h-2o-s	1.00 × 10^4 J	start physical_unit 12 14 heat_energy kj qc_end physical_unit 12 14 16 17 temperature qc_end physical_unit 12 14 10 11 mass qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Required heat [OF] H2O(s) sample [IN] J"}]	[{"type":"physical unit","value":"1.00 × 10^4 J"}]	[{"type":"other","value":"Completely melt."},{"type":"physical unit","value":"Mass [OF] H2O(s) sample [=] \\pu{29.95 grams}"},{"type":"physical unit","value":"Temperature [OF] 29.95 grams [=] \\pu{0 ℃}"}]	<h1 class="questionTitle" itemprop="name">What amount of heat is required to completely melt a 29.95-gram sample of #H_2O(s)# at 0° C?</h1>	null	1.00 × 10^4 J	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>When a sample of water melts from <em>ice</em> at <mathjax>#0^@"C"#</mathjax> to <em>liquid water</em> at <mathjax>#0^@"C"#</mathjax>, it undergoes a <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/introduction-to-phase-changes">phase change</a>.</p> <p>As you know, <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/introduction-to-phase-changes">phase changes</a> take place at <strong>constant temperature</strong>. All the heat added to the sample goes into disrupting the strong <a href="https://socratic.org/chemistry/intermolecular-bonding/hydrogen-bonds">hydrogen bonds</a> that keep the water molecules <strong>locked in place</strong> in the solid state. </p> <p>This means that you can't use water or ice's <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a>, since the heat added does <strong>not</strong> change the sample's temperature. </p> <p>Instead, you will use water's <em><a href="http://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> of fusion</em>, <mathjax>#DeltaH_f#</mathjax>, which tells you what the <em>change in enthalpy</em> is when heating a substance <strong>at its melting point</strong> to make it undergo a solid <mathjax>#->#</mathjax> liquid phase change. </p> <p>Water's enthalpy of fusion is approximately equal to </p> <blockquote> <p><mathjax>#DeltaH_f = "334 J/g"#</mathjax></p> </blockquote> <p><a href="http://www.engineeringtoolbox.com/latent-heat-melting-solids-d_96.html" rel="nofollow" target="_blank">http://www.engineeringtoolbox.com/latent-heat-melting-solids-d_96.html</a></p> <p>This tells you that in order to convert <mathjax>#"1 g"#</mathjax> of ice at <mathjax>#0^@"C"#</mathjax> to liquid water at <mathjax>#0^@"C"#</mathjax>, you need to provide it with <mathjax>#"334 J"#</mathjax> of heat. </p> <p>In your case, the sample is said to have a mass of <mathjax>#"29.95 g"#</mathjax>, which means that you'll need</p> <blockquote> <p><mathjax>#29.95 color(red)(cancel(color(black)("g"))) * "334 J"/(1color(red)(cancel(color(black)("g")))) = "10,003.3 J"#</mathjax></p> </blockquote> <p>Rounded to four <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the answer will be </p> <p><mathjax>#q = color(green)(1.000 * 10^4"J")#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1.000 * 10^4"J"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>When a sample of water melts from <em>ice</em> at <mathjax>#0^@"C"#</mathjax> to <em>liquid water</em> at <mathjax>#0^@"C"#</mathjax>, it undergoes a <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/introduction-to-phase-changes">phase change</a>.</p> <p>As you know, <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/introduction-to-phase-changes">phase changes</a> take place at <strong>constant temperature</strong>. All the heat added to the sample goes into disrupting the strong <a href="https://socratic.org/chemistry/intermolecular-bonding/hydrogen-bonds">hydrogen bonds</a> that keep the water molecules <strong>locked in place</strong> in the solid state. </p> <p>This means that you can't use water or ice's <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a>, since the heat added does <strong>not</strong> change the sample's temperature. </p> <p>Instead, you will use water's <em><a href="http://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> of fusion</em>, <mathjax>#DeltaH_f#</mathjax>, which tells you what the <em>change in enthalpy</em> is when heating a substance <strong>at its melting point</strong> to make it undergo a solid <mathjax>#->#</mathjax> liquid phase change. </p> <p>Water's enthalpy of fusion is approximately equal to </p> <blockquote> <p><mathjax>#DeltaH_f = "334 J/g"#</mathjax></p> </blockquote> <p><a href="http://www.engineeringtoolbox.com/latent-heat-melting-solids-d_96.html" rel="nofollow" target="_blank">http://www.engineeringtoolbox.com/latent-heat-melting-solids-d_96.html</a></p> <p>This tells you that in order to convert <mathjax>#"1 g"#</mathjax> of ice at <mathjax>#0^@"C"#</mathjax> to liquid water at <mathjax>#0^@"C"#</mathjax>, you need to provide it with <mathjax>#"334 J"#</mathjax> of heat. </p> <p>In your case, the sample is said to have a mass of <mathjax>#"29.95 g"#</mathjax>, which means that you'll need</p> <blockquote> <p><mathjax>#29.95 color(red)(cancel(color(black)("g"))) * "334 J"/(1color(red)(cancel(color(black)("g")))) = "10,003.3 J"#</mathjax></p> </blockquote> <p>Rounded to four <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the answer will be </p> <p><mathjax>#q = color(green)(1.000 * 10^4"J")#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What amount of heat is required to completely melt a 29.95-gram sample of #H_2O(s)# at 0° C?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/thermochemistry-of-phase-changes" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry of Phase Changes</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="201635" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-20T19:41:55" itemprop="dateCreated"> Dec 20, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1.000 * 10^4"J"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>When a sample of water melts from <em>ice</em> at <mathjax>#0^@"C"#</mathjax> to <em>liquid water</em> at <mathjax>#0^@"C"#</mathjax>, it undergoes a <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/introduction-to-phase-changes">phase change</a>.</p> <p>As you know, <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/introduction-to-phase-changes">phase changes</a> take place at <strong>constant temperature</strong>. All the heat added to the sample goes into disrupting the strong <a href="https://socratic.org/chemistry/intermolecular-bonding/hydrogen-bonds">hydrogen bonds</a> that keep the water molecules <strong>locked in place</strong> in the solid state. </p> <p>This means that you can't use water or ice's <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a>, since the heat added does <strong>not</strong> change the sample's temperature. </p> <p>Instead, you will use water's <em><a href="http://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> of fusion</em>, <mathjax>#DeltaH_f#</mathjax>, which tells you what the <em>change in enthalpy</em> is when heating a substance <strong>at its melting point</strong> to make it undergo a solid <mathjax>#->#</mathjax> liquid phase change. </p> <p>Water's enthalpy of fusion is approximately equal to </p> <blockquote> <p><mathjax>#DeltaH_f = "334 J/g"#</mathjax></p> </blockquote> <p><a href="http://www.engineeringtoolbox.com/latent-heat-melting-solids-d_96.html" rel="nofollow" target="_blank">http://www.engineeringtoolbox.com/latent-heat-melting-solids-d_96.html</a></p> <p>This tells you that in order to convert <mathjax>#"1 g"#</mathjax> of ice at <mathjax>#0^@"C"#</mathjax> to liquid water at <mathjax>#0^@"C"#</mathjax>, you need to provide it with <mathjax>#"334 J"#</mathjax> of heat. </p> <p>In your case, the sample is said to have a mass of <mathjax>#"29.95 g"#</mathjax>, which means that you'll need</p> <blockquote> <p><mathjax>#29.95 color(red)(cancel(color(black)("g"))) * "334 J"/(1color(red)(cancel(color(black)("g")))) = "10,003.3 J"#</mathjax></p> </blockquote> <p>Rounded to four <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the answer will be </p> <p><mathjax>#q = color(green)(1.000 * 10^4"J")#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/201635" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-much-energy-is-required-to-heat-100-g-of-ice-at-0-00-degrees-celsius-to-wate"> How much energy is required to convert 100.g of ice at 0.00 °C to water vapor at 100.00 °C? 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</a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/thermochemistry-of-phase-changes"> See all questions in Thermochemistry of Phase Changes </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 22578 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What amount of heat is required to completely melt a 29.95-gram sample of #H_2O(s)# at 0° C?	null
1,026	ab213a3b-6ddd-11ea-a126-ccda262736ce	https://socratic.org/questions/what-is-the-formula-for-this-reaction-sulfiric-acid-reacts-with-potassium-hydrox	H2SO4 + 2 KOH -> K2SO4 + 2 H2O	start chemical_equation qc_end substance 11 12 qc_end substance 7 8 qc_end substance 15 16 qc_end substance 18 18 qc_end end	[{"type":"other","value":"Chemical Equation [OF] this reaction"}]	[{"type":"chemical equation","value":"H2SO4 + 2 KOH -> K2SO4 + 2 H2O"}]	[{"type":"substance name","value":"Potassium hydroxide"},{"type":"substance name","value":"Sulfuric acid"},{"type":"substance name","value":"Potassium sulfate"},{"type":"substance name","value":"Water"}]	<h1 class="questionTitle" itemprop="name">What is the formula for this reaction: Sulfuric acid reacts with potassium hydroxide to produce potassium sulfate and water?</h1>	null	H2SO4 + 2 KOH -> K2SO4 + 2 H2O	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is an example of a double replacement (double displacement) reaction. This type of double replacement is called a <a href="https://socratic.org/chemistry/reactions-in-solution/neutralization">neutralization</a> reaction since an acid and a base react and one of the products is water.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Balanced chemical equation:</p> <p><mathjax>#"H"_2"SO"_4 + "2KOH"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"K"_2"SO"_4 + "2H"_2"O"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is an example of a double replacement (double displacement) reaction. This type of double replacement is called a <a href="https://socratic.org/chemistry/reactions-in-solution/neutralization">neutralization</a> reaction since an acid and a base react and one of the products is water.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the formula for this reaction: Sulfuric acid reacts with potassium hydroxide to produce potassium sulfate and water?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/determining-formula-and-molar-masses" itemprop="url"> <span class="breadcrumb" itemprop="title">Determining Formula</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="385714" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-03T04:19:06" itemprop="dateCreated"> Mar 3, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Balanced chemical equation:</p> <p><mathjax>#"H"_2"SO"_4 + "2KOH"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"K"_2"SO"_4 + "2H"_2"O"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is an example of a double replacement (double displacement) reaction. This type of double replacement is called a <a href="https://socratic.org/chemistry/reactions-in-solution/neutralization">neutralization</a> reaction since an acid and a base react and one of the products is water.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/385714" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-it-possible-to-find-a-molecular-formula-from-molar-mass"> Is it possible to find a molecular formula from molar mass? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5368e0cc02bf34779e175781"> Question #75781 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-common-mistakes-students-make-when-determining-formulas"> What are some common mistakes students make when determining formulas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-formula-of-an-acid"> How can I determine the formula of an acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-chemical-formula-of-a-product"> How can I determine the chemical formula of a product? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-empirical-formula-of-a-compound"> How can I determine the empirical formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-formula-of-a-hydrate"> How can I determine the formula of a hydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-the-empirical-formula-indicate"> What does the empirical formula indicate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-molecule-with-molecular-weight-of-180-18-g-mol-is-analyzed-and-found-to-contai"> A molecule with molecular weight of 180.18 g/mol is analyzed and found to contain 40.00% carbon,... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/do-i-need-to-know-the-number-of-moles-of-each-element-to-determine-the-formula-o"> Do I need to know the number of moles of each element to determine the formula of the compound? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/determining-formula-and-molar-masses"> See all questions in Determining Formula </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 31458 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the formula for this reaction: Sulfuric acid reacts with potassium hydroxide to produce potassium sulfate and water?	null
1,027	ab72c3e5-6ddd-11ea-99c8-ccda262736ce	https://socratic.org/questions/using-the-ideal-gas-formula-calculate-the-volume-of-1-5omoles-of-a-gas-at-115kpa	32.33 L	start physical_unit 1 3 volume l qc_end physical_unit 1 3 9 10 mole qc_end physical_unit 1 3 15 16 pressure qc_end physical_unit 1 3 21 22 temperature qc_end end	[{"type":"physical unit","value":"Volume [OF] the ideal gas [IN] L"}]	[{"type":"physical unit","value":"32.33 L"}]	[{"type":"physical unit","value":"Mole [OF] the ideal gas [=] \\pu{1.50 moles}"},{"type":"physical unit","value":"Pressure [OF] the ideal gas [=] \\pu{115 kPa}"},{"type":"physical unit","value":"Temperature [OF] the ideal gas [=] \\pu{298 K}"}]	<h1 class="questionTitle" itemprop="name">Using the ideal gas formula, calculate the volume of 1.50 moles of a gas at 115 kPA and a temperature of 298K?</h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>using the ideal gas formula, calculate the volume of 1.5omoles of a gas at 115kPA and a temperature of 298k?</p></div> </h2> </div> </div>	32.33 L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is a pretty straightforward <strong><a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a></strong> equation practice problem, so make sure that you're familiar with the aforementioned <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> equation</p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a)PV = nRTcolor(white)(a/a)\|)))" "#</mathjax>, where</p> </blockquote> <p><mathjax>#P#</mathjax> - the pressure of the gas<br/> <mathjax>#V#</mathjax> - the volume it occupies<br/> <mathjax>#n#</mathjax> - the number of moles of gas<br/> <mathjax>#R#</mathjax> - the <em>universal gas constant</em>, usually given as <mathjax>#0.0821("atm" * "L")/("mol" * "K")#</mathjax><br/> <mathjax>#T#</mathjax> - the <strong>absolute temperature</strong> of the gas</p> <p>Now, the most important thing to do at this point is make sure that the <strong>units</strong> given to you <strong>match</strong> those used in the expression of the ideal gas constant. </p> <p>As you can see, the <em>pressure</em> of the gas is given to you in <em>kPa</em>, but you actually need it to be expressed in <em>atm</em>. This means that you're going to have to convert it by using the conversion factor</p> <blockquote> <p><mathjax>#color(purple)(\|bar(ul(color(white)(a/a)color(black)("1 atm " = " 101.325 kPa")color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>Rearrange the ideal gas law equation to solve for <mathjax>#V#</mathjax>, the volume of the gas</p> <blockquote> <p><mathjax>#PV = nRT implies V = (nRT)/V#</mathjax></p> </blockquote> <p>Plug in your values to get</p> <blockquote> <p><mathjax>#V = (1.50color(red)(cancel(color(black)("moles"))) * 0.0821(color(red)(cancel(color(black)("atm"))) * "L")/(color(red)(cancel(color(black)("mol"))) * color(red)(cancel(color(black)("K")))) * 298color(red)(cancel(color(black)("K"))))/(115/101.325color(red)(cancel(color(black)("atm")))) = color(green)(\|bar(ul(color(white)(a/a)"32.3 L"color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p> <p> <iframe src="https://www.youtube.com/embed/TqLlfHBFY08?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"32.3 L"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is a pretty straightforward <strong><a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a></strong> equation practice problem, so make sure that you're familiar with the aforementioned <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> equation</p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a)PV = nRTcolor(white)(a/a)\|)))" "#</mathjax>, where</p> </blockquote> <p><mathjax>#P#</mathjax> - the pressure of the gas<br/> <mathjax>#V#</mathjax> - the volume it occupies<br/> <mathjax>#n#</mathjax> - the number of moles of gas<br/> <mathjax>#R#</mathjax> - the <em>universal gas constant</em>, usually given as <mathjax>#0.0821("atm" * "L")/("mol" * "K")#</mathjax><br/> <mathjax>#T#</mathjax> - the <strong>absolute temperature</strong> of the gas</p> <p>Now, the most important thing to do at this point is make sure that the <strong>units</strong> given to you <strong>match</strong> those used in the expression of the ideal gas constant. </p> <p>As you can see, the <em>pressure</em> of the gas is given to you in <em>kPa</em>, but you actually need it to be expressed in <em>atm</em>. This means that you're going to have to convert it by using the conversion factor</p> <blockquote> <p><mathjax>#color(purple)(\|bar(ul(color(white)(a/a)color(black)("1 atm " = " 101.325 kPa")color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>Rearrange the ideal gas law equation to solve for <mathjax>#V#</mathjax>, the volume of the gas</p> <blockquote> <p><mathjax>#PV = nRT implies V = (nRT)/V#</mathjax></p> </blockquote> <p>Plug in your values to get</p> <blockquote> <p><mathjax>#V = (1.50color(red)(cancel(color(black)("moles"))) * 0.0821(color(red)(cancel(color(black)("atm"))) * "L")/(color(red)(cancel(color(black)("mol"))) * color(red)(cancel(color(black)("K")))) * 298color(red)(cancel(color(black)("K"))))/(115/101.325color(red)(cancel(color(black)("atm")))) = color(green)(\|bar(ul(color(white)(a/a)"32.3 L"color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p> <p> <iframe src="https://www.youtube.com/embed/TqLlfHBFY08?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Using the ideal gas formula, calculate the volume of 1.50 moles of a gas at 115 kPA and a temperature of 298K?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>using the ideal gas formula, calculate the volume of 1.5omoles of a gas at 115kPA and a temperature of 298k?</p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/ideal-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Ideal Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="240671" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-17T01:03:34" itemprop="dateCreated"> Mar 17, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"32.3 L"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is a pretty straightforward <strong><a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a></strong> equation practice problem, so make sure that you're familiar with the aforementioned <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> equation</p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a)PV = nRTcolor(white)(a/a)\|)))" "#</mathjax>, where</p> </blockquote> <p><mathjax>#P#</mathjax> - the pressure of the gas<br/> <mathjax>#V#</mathjax> - the volume it occupies<br/> <mathjax>#n#</mathjax> - the number of moles of gas<br/> <mathjax>#R#</mathjax> - the <em>universal gas constant</em>, usually given as <mathjax>#0.0821("atm" * "L")/("mol" * "K")#</mathjax><br/> <mathjax>#T#</mathjax> - the <strong>absolute temperature</strong> of the gas</p> <p>Now, the most important thing to do at this point is make sure that the <strong>units</strong> given to you <strong>match</strong> those used in the expression of the ideal gas constant. </p> <p>As you can see, the <em>pressure</em> of the gas is given to you in <em>kPa</em>, but you actually need it to be expressed in <em>atm</em>. This means that you're going to have to convert it by using the conversion factor</p> <blockquote> <p><mathjax>#color(purple)(\|bar(ul(color(white)(a/a)color(black)("1 atm " = " 101.325 kPa")color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>Rearrange the ideal gas law equation to solve for <mathjax>#V#</mathjax>, the volume of the gas</p> <blockquote> <p><mathjax>#PV = nRT implies V = (nRT)/V#</mathjax></p> </blockquote> <p>Plug in your values to get</p> <blockquote> <p><mathjax>#V = (1.50color(red)(cancel(color(black)("moles"))) * 0.0821(color(red)(cancel(color(black)("atm"))) * "L")/(color(red)(cancel(color(black)("mol"))) * color(red)(cancel(color(black)("K")))) * 298color(red)(cancel(color(black)("K"))))/(115/101.325color(red)(cancel(color(black)("atm")))) = color(green)(\|bar(ul(color(white)(a/a)"32.3 L"color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p> <p> <iframe src="https://www.youtube.com/embed/TqLlfHBFY08?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/240671" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-ideal-gas-constant"> How do you find the ideal gas constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-solve-ideal-gas-law-problems"> How do you solve ideal gas law problems? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-know-which-ideal-gas-constant-to-use"> How do you know which ideal gas constant to use? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ideal-gas-constant-for-butane"> What is the ideal gas constant for butane? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-ideal-gas-law-in-kelvin"> Why is ideal gas law in kelvin? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ideal-gas-constant-important"> Why is the ideal gas constant important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-di-electric-constant"> What is the di-electric constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-volume-l-will-0-20-mol-hi-occupy-at-300-k-and-100-0-kpa-r-8-314-kpa-l-k-mol"> What volume (L) will 0.20 mol HI occupy at 300 K and 100.0 kPa? R = 8.314 kPa L / (K mol) =... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-molar-mass-of-a-gas"> How do you calculate the molar mass of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-should-i-use-the-ideal-gas-law-and-not-the-combined-gas-law"> When should I use the ideal gas law and not the combined gas law? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/ideal-gas-law"> See all questions in Ideal Gas Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 9737 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Using the ideal gas formula, calculate the volume of 1.50 moles of a gas at 115 kPA and a temperature of 298K?	using the ideal gas formula, calculate the volume of 1.5omoles of a gas at 115kPA and a temperature of 298k?
1,028	a94c234f-6ddd-11ea-b59c-ccda262736ce	https://socratic.org/questions/when-an-aqueous-solution-at-room-temperature-is-analyzed-the-h-is-found-to-be-2-	5.01 × 10^(-12) M	start physical_unit 2 3 [oh-] mol/l qc_end physical_unit 2 3 15 18 [h+] qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"[OH-] [OF] aqueous solution [IN] M"}]	[{"type":"physical unit","value":"5.01 × 10^(-12) M"}]	[{"type":"physical unit","value":"[H+] [OF] aqueous solution [=] \\pu{2.0 × 10^(-3) M}"},{"type":"other","value":"Room temperature."}]	<h1 class="questionTitle" itemprop="name">When an aqueous solution at room temperature is analyzed, the #[H^+]# is found to be #2.0*10^-3# #M#. What is the #[OH^-]#?</h1>	null	5.01 × 10^(-12) M	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>As you know water undergoes autoprotolysis:</p> <p><mathjax>#2H_2O rightleftharpoons H_3O^+ + HO^-#</mathjax></p> <p>At <mathjax>#298K#</mathjax> this equilibrium has been measured exhaustively and precisely:</p> <p><mathjax>#K_w=[H_3O^+][HO^-]#</mathjax> <mathjax>#=#</mathjax> <mathjax>#10^-14#</mathjax></p> <p>If we take <mathjax>#-log_10#</mathjax> of both sides:</p> <p><mathjax>#-pK_w#</mathjax> <mathjax>#=#</mathjax> <mathjax>#-log_10[HO^-] -log_10[H_3O^+]#</mathjax> <mathjax>#=#</mathjax> <mathjax>#-log_10(10^-14)#</mathjax></p> <p>i.e. <mathjax>#14=pH+pOH#</mathjax>, because <mathjax>#pH=-log_10[H_3O^+]#</mathjax> and <mathjax>#pOH= -log_10[HO^-]#</mathjax> by definition. </p> <p>So <mathjax>#[H_3O^+]#</mathjax> <mathjax>#=#</mathjax> <mathjax>#2.0xx10^-3#</mathjax>, and <mathjax>#pH=-log_10(2.0xx10^-3)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#-(-2.70)=2.70#</mathjax>.</p> <p>Thus <mathjax>#pOH=14-2.70=11.30#</mathjax>. <mathjax>#[HO^-]#</mathjax> <mathjax>#=#</mathjax> <mathjax>#10^(-11.30)molL^-1=5.01xx10^-12mol*L^-1#</mathjax>.</p> <p>You can check to see if I am right by multiplying <mathjax>#[H_3O^+]#</mathjax> and <mathjax>#[HO^-]#</mathjax>. What should the product equal?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#[HO^-]#</mathjax> <mathjax>#=#</mathjax> <mathjax>#5.01xx10^-12molL^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>As you know water undergoes autoprotolysis:</p> <p><mathjax>#2H_2O rightleftharpoons H_3O^+ + HO^-#</mathjax></p> <p>At <mathjax>#298K#</mathjax> this equilibrium has been measured exhaustively and precisely:</p> <p><mathjax>#K_w=[H_3O^+][HO^-]#</mathjax> <mathjax>#=#</mathjax> <mathjax>#10^-14#</mathjax></p> <p>If we take <mathjax>#-log_10#</mathjax> of both sides:</p> <p><mathjax>#-pK_w#</mathjax> <mathjax>#=#</mathjax> <mathjax>#-log_10[HO^-] -log_10[H_3O^+]#</mathjax> <mathjax>#=#</mathjax> <mathjax>#-log_10(10^-14)#</mathjax></p> <p>i.e. <mathjax>#14=pH+pOH#</mathjax>, because <mathjax>#pH=-log_10[H_3O^+]#</mathjax> and <mathjax>#pOH= -log_10[HO^-]#</mathjax> by definition. </p> <p>So <mathjax>#[H_3O^+]#</mathjax> <mathjax>#=#</mathjax> <mathjax>#2.0xx10^-3#</mathjax>, and <mathjax>#pH=-log_10(2.0xx10^-3)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#-(-2.70)=2.70#</mathjax>.</p> <p>Thus <mathjax>#pOH=14-2.70=11.30#</mathjax>. <mathjax>#[HO^-]#</mathjax> <mathjax>#=#</mathjax> <mathjax>#10^(-11.30)molL^-1=5.01xx10^-12mol*L^-1#</mathjax>.</p> <p>You can check to see if I am right by multiplying <mathjax>#[H_3O^+]#</mathjax> and <mathjax>#[HO^-]#</mathjax>. What should the product equal?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">When an aqueous solution at room temperature is analyzed, the #[H^+]# is found to be #2.010^-3# #M#. What is the #[OH^-]#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/ph-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">pH calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="298549" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-08-13T16:55:18" itemprop="dateCreated"> Aug 13, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#[HO^-]#</mathjax> <mathjax>#=#</mathjax> <mathjax>#5.01xx10^-12molL^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>As you know water undergoes autoprotolysis:</p> <p><mathjax>#2H_2O rightleftharpoons H_3O^+ + HO^-#</mathjax></p> <p>At <mathjax>#298K#</mathjax> this equilibrium has been measured exhaustively and precisely:</p> <p><mathjax>#K_w=[H_3O^+][HO^-]#</mathjax> <mathjax>#=#</mathjax> <mathjax>#10^-14#</mathjax></p> <p>If we take <mathjax>#-log_10#</mathjax> of both sides:</p> <p><mathjax>#-pK_w#</mathjax> <mathjax>#=#</mathjax> <mathjax>#-log_10[HO^-] -log_10[H_3O^+]#</mathjax> <mathjax>#=#</mathjax> <mathjax>#-log_10(10^-14)#</mathjax></p> <p>i.e. <mathjax>#14=pH+pOH#</mathjax>, because <mathjax>#pH=-log_10[H_3O^+]#</mathjax> and <mathjax>#pOH= -log_10[HO^-]#</mathjax> by definition. </p> <p>So <mathjax>#[H_3O^+]#</mathjax> <mathjax>#=#</mathjax> <mathjax>#2.0xx10^-3#</mathjax>, and <mathjax>#pH=-log_10(2.0xx10^-3)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#-(-2.70)=2.70#</mathjax>.</p> <p>Thus <mathjax>#pOH=14-2.70=11.30#</mathjax>. <mathjax>#[HO^-]#</mathjax> <mathjax>#=#</mathjax> <mathjax>#10^(-11.30)molL^-1=5.01xx10^-12molL^-1#</mathjax>.</p> <p>You can check to see if I am right by multiplying <mathjax>#[H_3O^+]#</mathjax> and <mathjax>#[HO^-]#</mathjax>. What should the product equal?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/298549" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-of-a-solution"> How do you determine ph of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-at-an-equivalence-point"> How do you determine pH at an equivalence point? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-molarity"> How do you determine pH from molarity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-alkalinity-mean"> What does alkalinity mean? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-base"> What is a base? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-acid-base-indicators-change-color"> How do acid base indicators change color? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-neutral-ph"> What is a neutral pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-alkalinity-affect-pool-water"> How does alkalinity affect pool water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ph-important-in-drinking-water"> Why is pH important in drinking water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-ph-of-solution"> How can I calculate the pH of a solution? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/ph-calculations"> See all questions in pH calculations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 4585 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	When an aqueous solution at room temperature is analyzed, the #[H^+]# is found to be #2.0*10^-3# #M#. What is the #[OH^-]#?	null
1,029	ab5b616c-6ddd-11ea-ba60-ccda262736ce	https://socratic.org/questions/what-volume-does-4-68-g-h-2o-occupy-at-stp	4.68 mL	start physical_unit 5 5 volume ml qc_end physical_unit 5 5 3 4 mass qc_end c_other STP qc_end end	[{"type":"physical unit","value":"Volume [OF] H2O [IN] mL"}]	[{"type":"physical unit","value":"4.68 mL"}]	[{"type":"physical unit","value":"Mass [OF] H2O [=] \\pu{4.68 g}"},{"type":"other","value":"STP"}]	<h1 class="questionTitle" itemprop="name">What volume does 4.68 g #H_2O# occupy at STP?</h1>	null	4.68 mL	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>At 0 °C, water can be a liquid or a solid.</p> <blockquote></blockquote> <p><strong>Liquid water at 0 °C</strong></p> <p>The <a href="http://socratic.org/chemistry/measurement-in-chemistry/density">density</a> of liquid water at 0 °C is <mathjax>#"0.9998 g/mL"#</mathjax>.</p> <p>The volume is given by</p> <p><mathjax>#4.68 color(red)(cancel(color(black)("g"))) × "1 mL"/(0.9998 color(red)(cancel(color(black)("g")))) = "4.68 mL"#</mathjax>.</p> <blockquote></blockquote> <p><strong>Ice at 0 °C</strong></p> <p>The density of ice at 0 °C is <mathjax>#"0.9170 g/cm"^3#</mathjax>.</p> <p>The volume is given by</p> <p><mathjax>#4.68 color(red)(cancel(color(black)("g"))) × ("1 cm"^3)/(0.9170 color(red)(cancel(color(black)("g")))) = "5.10 cm"^3#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The volume of liquid water at 0 °C is <mathjax>#"4.68 mL"#</mathjax>, and the volume of ice at 0 °C is <mathjax>#"5.10 cm"^3#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>At 0 °C, water can be a liquid or a solid.</p> <blockquote></blockquote> <p><strong>Liquid water at 0 °C</strong></p> <p>The <a href="http://socratic.org/chemistry/measurement-in-chemistry/density">density</a> of liquid water at 0 °C is <mathjax>#"0.9998 g/mL"#</mathjax>.</p> <p>The volume is given by</p> <p><mathjax>#4.68 color(red)(cancel(color(black)("g"))) × "1 mL"/(0.9998 color(red)(cancel(color(black)("g")))) = "4.68 mL"#</mathjax>.</p> <blockquote></blockquote> <p><strong>Ice at 0 °C</strong></p> <p>The density of ice at 0 °C is <mathjax>#"0.9170 g/cm"^3#</mathjax>.</p> <p>The volume is given by</p> <p><mathjax>#4.68 color(red)(cancel(color(black)("g"))) × ("1 cm"^3)/(0.9170 color(red)(cancel(color(black)("g")))) = "5.10 cm"^3#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What volume does 4.68 g #H_2O# occupy at STP?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/gas-laws" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Laws</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="223630" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-02-09T01:39:42" itemprop="dateCreated"> Feb 9, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The volume of liquid water at 0 °C is <mathjax>#"4.68 mL"#</mathjax>, and the volume of ice at 0 °C is <mathjax>#"5.10 cm"^3#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>At 0 °C, water can be a liquid or a solid.</p> <blockquote></blockquote> <p><strong>Liquid water at 0 °C</strong></p> <p>The <a href="http://socratic.org/chemistry/measurement-in-chemistry/density">density</a> of liquid water at 0 °C is <mathjax>#"0.9998 g/mL"#</mathjax>.</p> <p>The volume is given by</p> <p><mathjax>#4.68 color(red)(cancel(color(black)("g"))) × "1 mL"/(0.9998 color(red)(cancel(color(black)("g")))) = "4.68 mL"#</mathjax>.</p> <blockquote></blockquote> <p><strong>Ice at 0 °C</strong></p> <p>The density of ice at 0 °C is <mathjax>#"0.9170 g/cm"^3#</mathjax>.</p> <p>The volume is given by</p> <p><mathjax>#4.68 color(red)(cancel(color(black)("g"))) × ("1 cm"^3)/(0.9170 color(red)(cancel(color(black)("g")))) = "5.10 cm"^3#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/223630" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li 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If the gas is compressed to 23.52 L and the... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-the-r-stand-for-in-the-ideal-gas-law-pv-nrt"> What does the R stand for in the ideal gas law (PV=nRT)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-mass-of-a-gas-that-occupies-48-9-liters-has-a-pressure-of-724-torr-a"> What is the mass of a gas that occupies 48.9 liters, has a pressure of 724 torr, a temperature... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-a-sample-of-neon-gas-occupies-a-volume-of-2-8l-at-1-8-atm-what-will-its-volum"> If a sample of neon gas occupies a volume of 2.8L at 1.8 atm. what will its volume be at 1.2 atm? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/gas-laws"> See all questions in Gas Laws </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1337 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What volume does 4.68 g #H_2O# occupy at STP?	null
1,030	aa53531e-6ddd-11ea-912e-ccda262736ce	https://socratic.org/questions/at-340-k-one-atm-pressure-n-2o-4-is-66-dissociated-into-no-2-what-volume-of-10-g	5 L	start physical_unit 6 6 volume l qc_end physical_unit 6 6 1 2 temperature qc_end physical_unit 6 6 4 5 pressure qc_end physical_unit 6 6 15 16 mass qc_end end	[{"type":"physical unit","value":"Volume [OF] N2O4 [IN] L"}]	[{"type":"physical unit","value":"5 L"}]	[{"type":"physical unit","value":"Temperature [OF] N2O4 [=] \\pu{340 K}"},{"type":"physical unit","value":"Pressure [OF] N2O4 [=] \\pu{1 atm}"},{"type":"physical unit","value":"Percent [OF] N2O4 dissociated into NO2 [=] \\pu{66%}"},{"type":"physical unit","value":"Mass [OF] N2O4 [=] \\pu{10 g}"}]	<h1 class="questionTitle" itemprop="name">At #"340 K"# and #"1 atm"#, #"N"_2"O"_4# is #66%# dissociated into #"NO"_2#. What volume would #"10 g"# of #"N"_2"O"_4# occupy under these conditions?</h1>	null	5 L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Start by writing the balanced chemical equation that describes this dissociation equilibrium </p> <blockquote> <p><mathjax>#"N"_ 2"O"_ (4(g)) rightleftharpoons 2"NO"_ (2(g))#</mathjax></p> </blockquote> <p>Now, you know that at a temperature of <mathjax>#"340 K"#</mathjax> and a pressure of <mathjax>#"1 atm"#</mathjax>, <mathjax>#66%#</mathjax> of the dinitrogen tetroxide <em>dissociates</em> to produce nitrogen dioxide.</p> <p>This means that <strong>for every</strong> <mathjax>#100#</mathjax> <strong>moles</strong> of dinitrogen tetroxide present in the sample, <mathjax>#66#</mathjax> <strong>moles</strong> will dissociate to produce nitrogen dioxide. Notice that <em>for every</em> mole of dinitrogen tetroxide <strong>that dissociates</strong>, the reaction produces <mathjax>#2#</mathjax> <strong>moles</strong> of nitrogen dioxide. </p> <p>This means that <strong>for every</strong> <mathjax>#100#</mathjax> <strong>moles</strong> of dinitrogen tetroxide present in the sample, the reaction will produce</p> <blockquote> <p><mathjax>#overbrace(66 color(red)(cancel(color(black)("moles N"_2"O"_4))))^(color(blue)("what dissociates from 100 moles, i.e. 66%")) * "2 moles NO"_2/(1color(red)(cancel(color(black)("mole N"_2"O"_4)))) = "132 moles NO"_2#</mathjax></p> </blockquote> <p>Use the <strong>molar mass</strong> of dinitrogen tetroxide to calculate the number of moles present in your sample</p> <blockquote> <p><mathjax>#10 color(red)(cancel(color(black)("g"))) * ("1 mole N"_2"O"_4)/(92.011 color(red)(cancel(color(black)("g")))) = "0.1087 moles N"_2"O"_4#</mathjax></p> </blockquote> <p>This means that the reaction vessel will contain</p> <blockquote> <p><mathjax>#0.1087 color(red)(cancel(color(black)("moles N"_2"O"_4))) * "132 moles NO"_2/(100color(red)(cancel(color(black)("moles N"_2"O"_4)))) = "0.1435 moles NO"_2#</mathjax></p> </blockquote> <p>At equilibrium, the reaction vessel will contain <mathjax>#0.1435#</mathjax> <strong>moles</strong> of nitrogen dioxide and</p> <blockquote> <p><mathjax>#0.1087 color(red)(cancel(color(black)("moles N"_2"O"_4))) * overbrace(("34 moles N"_2"O"_4)/(100color(red)(cancel(color(black)("moles N"_2"O"_4)))))^(color(blue)("what does not dissociate, i.e. 34%")) = "0.03696 moles N"_2"O"_4#</mathjax></p> </blockquote> <p>The <strong>total number of moles</strong> of gas present in the reaction vessel will be</p> <blockquote> <p><mathjax>#"0.1435 moles " + " 0.03696 moles = 0.1805 moles"#</mathjax></p> </blockquote> <p>Now all you have to do is to use the <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> equation</strong> to find the <em>volume</em> of the gas mixture. </p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)(PV = nRT)))#</mathjax></p> </blockquote> <p>Here</p> <blockquote> <ul> <li><mathjax>#P#</mathjax> is the pressure of the gas</li> <li><mathjax>#V#</mathjax> is the volume it occupies</li> <li><mathjax>#n#</mathjax> is the number of moles of gas present in the sample</li> <li><mathjax>#R#</mathjax> is the <em>universal gas constant</em>, equal to <mathjax>#0.0821("atm L")/("mol K")#</mathjax></li> <li><mathjax>#T#</mathjax> is the <strong>absolute temperature</strong> of the gas</li> </ul> </blockquote> <p>Rearrange to solve for <mathjax>#V#</mathjax></p> <blockquote> <p><mathjax>#PV = nRT implies V = (nRT)/P#</mathjax></p> </blockquote> <p>Plug in your values to find</p> <blockquote> <p><mathjax>#V = (0.1805 color(red)(cancel(color(black)("moles"))) * 0.0821(color(red)(cancel(color(black)("atm"))) * "L")/(color(red)(cancel(color(black)("mol"))) * color(red)(cancel(color(black)("K")))) * 340color(red)(cancel(color(black)("K"))))/(1color(red)(cancel(color(black)("atm"))))#</mathjax></p> <p><mathjax>#V = color(darkgreen)(ul(color(black)("5 L")))#</mathjax></p> </blockquote> <p>The answer must be rounded to one <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figure</a></strong>, the number of sig figs you have for the mass of the dinitrogen tetroxide and the pressure of the mixture. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#V = "5 L"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Start by writing the balanced chemical equation that describes this dissociation equilibrium </p> <blockquote> <p><mathjax>#"N"_ 2"O"_ (4(g)) rightleftharpoons 2"NO"_ (2(g))#</mathjax></p> </blockquote> <p>Now, you know that at a temperature of <mathjax>#"340 K"#</mathjax> and a pressure of <mathjax>#"1 atm"#</mathjax>, <mathjax>#66%#</mathjax> of the dinitrogen tetroxide <em>dissociates</em> to produce nitrogen dioxide.</p> <p>This means that <strong>for every</strong> <mathjax>#100#</mathjax> <strong>moles</strong> of dinitrogen tetroxide present in the sample, <mathjax>#66#</mathjax> <strong>moles</strong> will dissociate to produce nitrogen dioxide. Notice that <em>for every</em> mole of dinitrogen tetroxide <strong>that dissociates</strong>, the reaction produces <mathjax>#2#</mathjax> <strong>moles</strong> of nitrogen dioxide. </p> <p>This means that <strong>for every</strong> <mathjax>#100#</mathjax> <strong>moles</strong> of dinitrogen tetroxide present in the sample, the reaction will produce</p> <blockquote> <p><mathjax>#overbrace(66 color(red)(cancel(color(black)("moles N"_2"O"_4))))^(color(blue)("what dissociates from 100 moles, i.e. 66%")) * "2 moles NO"_2/(1color(red)(cancel(color(black)("mole N"_2"O"_4)))) = "132 moles NO"_2#</mathjax></p> </blockquote> <p>Use the <strong>molar mass</strong> of dinitrogen tetroxide to calculate the number of moles present in your sample</p> <blockquote> <p><mathjax>#10 color(red)(cancel(color(black)("g"))) * ("1 mole N"_2"O"_4)/(92.011 color(red)(cancel(color(black)("g")))) = "0.1087 moles N"_2"O"_4#</mathjax></p> </blockquote> <p>This means that the reaction vessel will contain</p> <blockquote> <p><mathjax>#0.1087 color(red)(cancel(color(black)("moles N"_2"O"_4))) * "132 moles NO"_2/(100color(red)(cancel(color(black)("moles N"_2"O"_4)))) = "0.1435 moles NO"_2#</mathjax></p> </blockquote> <p>At equilibrium, the reaction vessel will contain <mathjax>#0.1435#</mathjax> <strong>moles</strong> of nitrogen dioxide and</p> <blockquote> <p><mathjax>#0.1087 color(red)(cancel(color(black)("moles N"_2"O"_4))) * overbrace(("34 moles N"_2"O"_4)/(100color(red)(cancel(color(black)("moles N"_2"O"_4)))))^(color(blue)("what does not dissociate, i.e. 34%")) = "0.03696 moles N"_2"O"_4#</mathjax></p> </blockquote> <p>The <strong>total number of moles</strong> of gas present in the reaction vessel will be</p> <blockquote> <p><mathjax>#"0.1435 moles " + " 0.03696 moles = 0.1805 moles"#</mathjax></p> </blockquote> <p>Now all you have to do is to use the <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> equation</strong> to find the <em>volume</em> of the gas mixture. </p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)(PV = nRT)))#</mathjax></p> </blockquote> <p>Here</p> <blockquote> <ul> <li><mathjax>#P#</mathjax> is the pressure of the gas</li> <li><mathjax>#V#</mathjax> is the volume it occupies</li> <li><mathjax>#n#</mathjax> is the number of moles of gas present in the sample</li> <li><mathjax>#R#</mathjax> is the <em>universal gas constant</em>, equal to <mathjax>#0.0821("atm L")/("mol K")#</mathjax></li> <li><mathjax>#T#</mathjax> is the <strong>absolute temperature</strong> of the gas</li> </ul> </blockquote> <p>Rearrange to solve for <mathjax>#V#</mathjax></p> <blockquote> <p><mathjax>#PV = nRT implies V = (nRT)/P#</mathjax></p> </blockquote> <p>Plug in your values to find</p> <blockquote> <p><mathjax>#V = (0.1805 color(red)(cancel(color(black)("moles"))) * 0.0821(color(red)(cancel(color(black)("atm"))) * "L")/(color(red)(cancel(color(black)("mol"))) * color(red)(cancel(color(black)("K")))) * 340color(red)(cancel(color(black)("K"))))/(1color(red)(cancel(color(black)("atm"))))#</mathjax></p> <p><mathjax>#V = color(darkgreen)(ul(color(black)("5 L")))#</mathjax></p> </blockquote> <p>The answer must be rounded to one <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figure</a></strong>, the number of sig figs you have for the mass of the dinitrogen tetroxide and the pressure of the mixture. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">At #"340 K"# and #"1 atm"#, #"N"_2"O"_4# is #66%# dissociated into #"NO"_2#. What volume would #"10 g"# of #"N"_2"O"_4# occupy under these conditions?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/ideal-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Ideal Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="485539" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-10-06T00:53:31" itemprop="dateCreated"> Oct 6, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#V = "5 L"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Start by writing the balanced chemical equation that describes this dissociation equilibrium </p> <blockquote> <p><mathjax>#"N"_ 2"O"_ (4(g)) rightleftharpoons 2"NO"_ (2(g))#</mathjax></p> </blockquote> <p>Now, you know that at a temperature of <mathjax>#"340 K"#</mathjax> and a pressure of <mathjax>#"1 atm"#</mathjax>, <mathjax>#66%#</mathjax> of the dinitrogen tetroxide <em>dissociates</em> to produce nitrogen dioxide.</p> <p>This means that <strong>for every</strong> <mathjax>#100#</mathjax> <strong>moles</strong> of dinitrogen tetroxide present in the sample, <mathjax>#66#</mathjax> <strong>moles</strong> will dissociate to produce nitrogen dioxide. Notice that <em>for every</em> mole of dinitrogen tetroxide <strong>that dissociates</strong>, the reaction produces <mathjax>#2#</mathjax> <strong>moles</strong> of nitrogen dioxide. </p> <p>This means that <strong>for every</strong> <mathjax>#100#</mathjax> <strong>moles</strong> of dinitrogen tetroxide present in the sample, the reaction will produce</p> <blockquote> <p><mathjax>#overbrace(66 color(red)(cancel(color(black)("moles N"_2"O"_4))))^(color(blue)("what dissociates from 100 moles, i.e. 66%")) * "2 moles NO"_2/(1color(red)(cancel(color(black)("mole N"_2"O"_4)))) = "132 moles NO"_2#</mathjax></p> </blockquote> <p>Use the <strong>molar mass</strong> of dinitrogen tetroxide to calculate the number of moles present in your sample</p> <blockquote> <p><mathjax>#10 color(red)(cancel(color(black)("g"))) * ("1 mole N"_2"O"_4)/(92.011 color(red)(cancel(color(black)("g")))) = "0.1087 moles N"_2"O"_4#</mathjax></p> </blockquote> <p>This means that the reaction vessel will contain</p> <blockquote> <p><mathjax>#0.1087 color(red)(cancel(color(black)("moles N"_2"O"_4))) * "132 moles NO"_2/(100color(red)(cancel(color(black)("moles N"_2"O"_4)))) = "0.1435 moles NO"_2#</mathjax></p> </blockquote> <p>At equilibrium, the reaction vessel will contain <mathjax>#0.1435#</mathjax> <strong>moles</strong> of nitrogen dioxide and</p> <blockquote> <p><mathjax>#0.1087 color(red)(cancel(color(black)("moles N"_2"O"_4))) * overbrace(("34 moles N"_2"O"_4)/(100color(red)(cancel(color(black)("moles N"_2"O"_4)))))^(color(blue)("what does not dissociate, i.e. 34%")) = "0.03696 moles N"_2"O"_4#</mathjax></p> </blockquote> <p>The <strong>total number of moles</strong> of gas present in the reaction vessel will be</p> <blockquote> <p><mathjax>#"0.1435 moles " + " 0.03696 moles = 0.1805 moles"#</mathjax></p> </blockquote> <p>Now all you have to do is to use the <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> equation</strong> to find the <em>volume</em> of the gas mixture. </p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)(PV = nRT)))#</mathjax></p> </blockquote> <p>Here</p> <blockquote> <ul> <li><mathjax>#P#</mathjax> is the pressure of the gas</li> <li><mathjax>#V#</mathjax> is the volume it occupies</li> <li><mathjax>#n#</mathjax> is the number of moles of gas present in the sample</li> <li><mathjax>#R#</mathjax> is the <em>universal gas constant</em>, equal to <mathjax>#0.0821("atm L")/("mol K")#</mathjax></li> <li><mathjax>#T#</mathjax> is the <strong>absolute temperature</strong> of the gas</li> </ul> </blockquote> <p>Rearrange to solve for <mathjax>#V#</mathjax></p> <blockquote> <p><mathjax>#PV = nRT implies V = (nRT)/P#</mathjax></p> </blockquote> <p>Plug in your values to find</p> <blockquote> <p><mathjax>#V = (0.1805 color(red)(cancel(color(black)("moles"))) * 0.0821(color(red)(cancel(color(black)("atm"))) * "L")/(color(red)(cancel(color(black)("mol"))) * color(red)(cancel(color(black)("K")))) * 340color(red)(cancel(color(black)("K"))))/(1color(red)(cancel(color(black)("atm"))))#</mathjax></p> <p><mathjax>#V = color(darkgreen)(ul(color(black)("5 L")))#</mathjax></p> </blockquote> <p>The answer must be rounded to one <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figure</a></strong>, the number of sig figs you have for the mass of the dinitrogen tetroxide and the pressure of the mixture. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/485539" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-ideal-gas-constant"> How do you find the ideal gas constant? 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R = 8.314 kPa L / (K mol) =... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-molar-mass-of-a-gas"> How do you calculate the molar mass of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-should-i-use-the-ideal-gas-law-and-not-the-combined-gas-law"> When should I use the ideal gas law and not the combined gas law? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/ideal-gas-law"> See all questions in Ideal Gas Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1521 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	At #"340 K"# and #"1 atm"#, #"N"_2"O"_4# is #66%# dissociated into #"NO"_2#. What volume would #"10 g"# of #"N"_2"O"_4# occupy under these conditions?	null
1,031	ab7115fa-6ddd-11ea-a81e-ccda262736ce	https://socratic.org/questions/what-is-the-total-mass-of-kno-3-that-must-be-dissolved-in-50-grams-of-h-2o-at-60	57.50 grams	start physical_unit 6 6 mass g qc_end physical_unit 15 15 12 13 mass qc_end physical_unit 15 15 17 18 temperature qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Mass [OF] KNO3 [IN] grams"}]	[{"type":"physical unit","value":"57.50 grams"}]	[{"type":"physical unit","value":"Mass [OF] H2O [=] \\pu{50 grams}"},{"type":"physical unit","value":"Temperature [OF] H2O [=] \\pu{60 ℃}"},{"type":"other","value":"Saturated solution."}]	<h1 class="questionTitle" itemprop="name">What is the total mass of #KNO_3# that must be dissolved in 50 grams of #H_2O# at 60°C to make a saturated solution? </h1>	null	57.50 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to solve this problem, you must take a look at the <strong><a href="http://socratic.org/chemistry/solutions-and-their-behavior/solubility-graphs">solubility graph</a></strong> for <em>potassium nitrate</em>, <mathjax>#"KNO"_3#</mathjax>, which looks like this</p> <blockquote> <blockquote> <p><img alt="www.mts.net" src="https://useruploads.socratic.org/MfeqoD02TjWDptaZqgTq_lesson%25203k.jpg"/> </p> </blockquote> </blockquote> <p>Now, the solubility graph shows you how much <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> can be dissolved <strong>per</strong> <mathjax>#"100 g"#</mathjax> of water in order to make an <em>unsaturated</em>, a <em>saturated</em>, or a <em>supersaturated</em> solution. </p> <p>You're looking to make a <strong>saturated</strong> potassium nitrate solution using <mathjax>#"50 g"#</mathjax> of water at <mathjax>#60^@"C"#</mathjax>. Your starting point will be to determine how much potassium nitrate can be dissolved in <mathjax>#"100 g"#</mathjax> of water at that temperature in order to have a saturated solution. </p> <p>As you can see, the curve itself represents saturation. </p> <p>If you draw a <em>vertical line</em> that corresponds to <mathjax>#60^@"C"#</mathjax> and extend it until it intersects the curve, then draw a <em>horizontal line</em> that connects to the vertical axis, you will find that potassium has a solubility of about <mathjax>#"115 g"#</mathjax> <strong>per</strong> <mathjax>#"100 g"#</mathjax> of water. </p> <p>Use this as a <strong>conversion factor</strong> to help you find how much potassium nitrate can be dissolved in <mathjax>#"50 g"#</mathjax> of water at the same temperature</p> <blockquote> <p><mathjax>#50color(red)(cancel(color(black)("g water"))) * overbrace("115 g KNO"_3/(100color(red)(cancel(color(black)("g water")))))^(color(purple)("solubility at"color(white)(a) 60^@"C")) = "57.5 g KNO"_3#</mathjax></p> </blockquote> <p>You <em>should</em> round this off to one <strong><a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig fig</a></strong>, since that's how many sig figs you have for the mass of water, but I'll leave it rounded to two sig figs, just for good measure</p> <blockquote> <p><mathjax>#m_(KNO_3) = color(green)(\|bar(ul(color(white)(a/a)"58 g"color(white)(a/a)\|)))#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"58 g KNO"_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to solve this problem, you must take a look at the <strong><a href="http://socratic.org/chemistry/solutions-and-their-behavior/solubility-graphs">solubility graph</a></strong> for <em>potassium nitrate</em>, <mathjax>#"KNO"_3#</mathjax>, which looks like this</p> <blockquote> <blockquote> <p><img alt="www.mts.net" src="https://useruploads.socratic.org/MfeqoD02TjWDptaZqgTq_lesson%25203k.jpg"/> </p> </blockquote> </blockquote> <p>Now, the solubility graph shows you how much <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> can be dissolved <strong>per</strong> <mathjax>#"100 g"#</mathjax> of water in order to make an <em>unsaturated</em>, a <em>saturated</em>, or a <em>supersaturated</em> solution. </p> <p>You're looking to make a <strong>saturated</strong> potassium nitrate solution using <mathjax>#"50 g"#</mathjax> of water at <mathjax>#60^@"C"#</mathjax>. Your starting point will be to determine how much potassium nitrate can be dissolved in <mathjax>#"100 g"#</mathjax> of water at that temperature in order to have a saturated solution. </p> <p>As you can see, the curve itself represents saturation. </p> <p>If you draw a <em>vertical line</em> that corresponds to <mathjax>#60^@"C"#</mathjax> and extend it until it intersects the curve, then draw a <em>horizontal line</em> that connects to the vertical axis, you will find that potassium has a solubility of about <mathjax>#"115 g"#</mathjax> <strong>per</strong> <mathjax>#"100 g"#</mathjax> of water. </p> <p>Use this as a <strong>conversion factor</strong> to help you find how much potassium nitrate can be dissolved in <mathjax>#"50 g"#</mathjax> of water at the same temperature</p> <blockquote> <p><mathjax>#50color(red)(cancel(color(black)("g water"))) * overbrace("115 g KNO"_3/(100color(red)(cancel(color(black)("g water")))))^(color(purple)("solubility at"color(white)(a) 60^@"C")) = "57.5 g KNO"_3#</mathjax></p> </blockquote> <p>You <em>should</em> round this off to one <strong><a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig fig</a></strong>, since that's how many sig figs you have for the mass of water, but I'll leave it rounded to two sig figs, just for good measure</p> <blockquote> <p><mathjax>#m_(KNO_3) = color(green)(\|bar(ul(color(white)(a/a)"58 g"color(white)(a/a)\|)))#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the total mass of #KNO_3# that must be dissolved in 50 grams of #H_2O# at 60°C to make a saturated solution? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/saturated-and-supersaturated-solutions" itemprop="url"> <span class="breadcrumb" itemprop="title">Saturated and Supersaturated Solutions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="238187" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-11T11:44:37" itemprop="dateCreated"> Mar 11, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"58 g KNO"_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to solve this problem, you must take a look at the <strong><a href="http://socratic.org/chemistry/solutions-and-their-behavior/solubility-graphs">solubility graph</a></strong> for <em>potassium nitrate</em>, <mathjax>#"KNO"_3#</mathjax>, which looks like this</p> <blockquote> <blockquote> <p><img alt="www.mts.net" src="https://useruploads.socratic.org/MfeqoD02TjWDptaZqgTq_lesson%25203k.jpg"/> </p> </blockquote> </blockquote> <p>Now, the solubility graph shows you how much <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> can be dissolved <strong>per</strong> <mathjax>#"100 g"#</mathjax> of water in order to make an <em>unsaturated</em>, a <em>saturated</em>, or a <em>supersaturated</em> solution. </p> <p>You're looking to make a <strong>saturated</strong> potassium nitrate solution using <mathjax>#"50 g"#</mathjax> of water at <mathjax>#60^@"C"#</mathjax>. Your starting point will be to determine how much potassium nitrate can be dissolved in <mathjax>#"100 g"#</mathjax> of water at that temperature in order to have a saturated solution. </p> <p>As you can see, the curve itself represents saturation. </p> <p>If you draw a <em>vertical line</em> that corresponds to <mathjax>#60^@"C"#</mathjax> and extend it until it intersects the curve, then draw a <em>horizontal line</em> that connects to the vertical axis, you will find that potassium has a solubility of about <mathjax>#"115 g"#</mathjax> <strong>per</strong> <mathjax>#"100 g"#</mathjax> of water. </p> <p>Use this as a <strong>conversion factor</strong> to help you find how much potassium nitrate can be dissolved in <mathjax>#"50 g"#</mathjax> of water at the same temperature</p> <blockquote> <p><mathjax>#50color(red)(cancel(color(black)("g water"))) * overbrace("115 g KNO"_3/(100color(red)(cancel(color(black)("g water")))))^(color(purple)("solubility at"color(white)(a) 60^@"C")) = "57.5 g KNO"_3#</mathjax></p> </blockquote> <p>You <em>should</em> round this off to one <strong><a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig fig</a></strong>, since that's how many sig figs you have for the mass of water, but I'll leave it rounded to two sig figs, just for good measure</p> <blockquote> <p><mathjax>#m_(KNO_3) = color(green)(\|bar(ul(color(white)(a/a)"58 g"color(white)(a/a)\|)))#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/238187" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-saturated-solutions-at-equilibrium"> How are saturated solutions at equilibrium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-supersaturated-solutions-prepared"> How are supersaturated solutions prepared? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-you-identify-a-saturated-solution"> How can you identify a saturated solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-supersaturated-solutions-demonstrate-conservation-of-energy"> How do supersaturated solutions demonstrate conservation of energy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-make-saturated-solution-of-potassium-iodide"> How do you make saturated solution of potassium iodide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-make-saturated-solution-of-sodium-bicarbonate"> How do you make saturated solution of sodium bicarbonate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-an-example-of-a-saturation-practice-problem"> What is an example of a saturation practice problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-saturated-solution"> What is a saturated solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-an-example-of-a-saturated-solution-practice-problem"> What is an example of a saturated solution practice problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-common-mistakes-students-make-with-saturated-solutions"> What are some common mistakes students make with saturated solutions? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/saturated-and-supersaturated-solutions"> See all questions in Saturated and Supersaturated Solutions </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 32422 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the total mass of #KNO_3# that must be dissolved in 50 grams of #H_2O# at 60°C to make a saturated solution?	null
1,032	ac036523-6ddd-11ea-b82a-ccda262736ce	https://socratic.org/questions/what-is-the-volume-of-hydrogen-produced-at-room-temperature-and-pressure-when-0-	2.4 dm^3	start physical_unit 5 5 volume dm^3 qc_end c_other OTHER qc_end physical_unit 16 16 13 14 mole qc_end c_other OTHER qc_end physical_unit 27 27 24 25 mole qc_end physical_unit 27 27 29 30 volume qc_end chemical_equation 36 45 qc_end end	[{"type":"physical unit","value":"Volume [OF] hydrogen [IN] dm^3"}]	[{"type":"physical unit","value":"2.4 dm^3"}]	[{"type":"other","value":"At room temperature and pressure."},{"type":"physical unit","value":"Mole [OF] sodium [=] \\pu{0.2 mol}"},{"type":"other","value":"Excess of water."},{"type":"physical unit","value":"Mole [OF] gas [=] \\pu{1 mol}"},{"type":"physical unit","value":"Volume [OF] gas [=] \\pu{24 dm^3}"},{"type":"chemical equation","value":"2 Na(s) + 2 H2O(l) -> 2 NaOH(aq) + H2(g)"}]	<h1 class="questionTitle" itemprop="name">What is the volume of hydrogen produced at room temperature and pressure, when 0.2mol of sodium is reacted with an excess of water? [1 mol of gas occupies 24 dm^3 at room temperature and pressure.]</h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p><mathjax>#2Na(s) + 2H_2O(l) -> 2NaOH(aq) + H_2(g)#</mathjax></p></div> </h2> </div> </div>	2.4 dm^3	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#Na(s) + H_2O(l)rarr NaOH(aq) + 1/2H_2(g)uarr#</mathjax></p> <p>You equation clearly shows that each equiv sodium metal produces 1/2 an equiv of dihydrogen gas.</p> <p>You reacted <mathjax>#"0.2 mol"#</mathjax> sodium metal, and thus <mathjax>#"0.1 mol"#</mathjax> dihydrogen gas will evolve. Given your conditions, <mathjax>#0.1cancel(mol)xx24dm^-3cancel(mol^-1)#</mathjax> dihydrogen will be evolved, i.e. <mathjax>#2.4dm^3#</mathjax> <mathjax>#H_2#</mathjax> gas. </p> <p>Note that <mathjax>#1dm^3#</mathjax> <mathjax>#-=#</mathjax> <mathjax>#10^-3m^3#</mathjax> (because <mathjax>#1dm^3=(10^-1m)^3=10^-3m^3=1L);"there are 1000 litres in a cubic metre."#</mathjax> And thus <mathjax>#2.4*L#</mathjax> of dihydrogen.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2.4dm^3#</mathjax> dihydrogen gas will evolve. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#Na(s) + H_2O(l)rarr NaOH(aq) + 1/2H_2(g)uarr#</mathjax></p> <p>You equation clearly shows that each equiv sodium metal produces 1/2 an equiv of dihydrogen gas.</p> <p>You reacted <mathjax>#"0.2 mol"#</mathjax> sodium metal, and thus <mathjax>#"0.1 mol"#</mathjax> dihydrogen gas will evolve. Given your conditions, <mathjax>#0.1cancel(mol)xx24dm^-3cancel(mol^-1)#</mathjax> dihydrogen will be evolved, i.e. <mathjax>#2.4dm^3#</mathjax> <mathjax>#H_2#</mathjax> gas. </p> <p>Note that <mathjax>#1dm^3#</mathjax> <mathjax>#-=#</mathjax> <mathjax>#10^-3m^3#</mathjax> (because <mathjax>#1dm^3=(10^-1m)^3=10^-3m^3=1L);"there are 1000 litres in a cubic metre."#</mathjax> And thus <mathjax>#2.4L#</mathjax> of dihydrogen.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the volume of hydrogen produced at room temperature and pressure, when 0.2mol of sodium is reacted with an excess of water? [1 mol of gas occupies 24 dm^3 at room temperature and pressure.]</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p><mathjax>#2Na(s) + 2H_2O(l) -> 2NaOH(aq) + H_2(g)#</mathjax></p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp" itemprop="url"> <span class="breadcrumb" itemprop="title">Molar Volume of a Gas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="325478" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-10-23T14:24:08" itemprop="dateCreated"> Oct 23, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2.4dm^3#</mathjax> dihydrogen gas will evolve. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#Na(s) + H_2O(l)rarr NaOH(aq) + 1/2H_2(g)uarr#</mathjax></p> <p>You equation clearly shows that each equiv sodium metal produces 1/2 an equiv of dihydrogen gas.</p> <p>You reacted <mathjax>#"0.2 mol"#</mathjax> sodium metal, and thus <mathjax>#"0.1 mol"#</mathjax> dihydrogen gas will evolve. Given your conditions, <mathjax>#0.1cancel(mol)xx24dm^-3cancel(mol^-1)#</mathjax> dihydrogen will be evolved, i.e. <mathjax>#2.4dm^3#</mathjax> <mathjax>#H_2#</mathjax> gas. </p> <p>Note that <mathjax>#1dm^3#</mathjax> <mathjax>#-=#</mathjax> <mathjax>#10^-3m^3#</mathjax> (because <mathjax>#1dm^3=(10^-1m)^3=10^-3m^3=1L);"there are 1000 litres in a cubic metre."#</mathjax> And thus <mathjax>#2.4L#</mathjax> of dihydrogen.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/325478" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-stoichiometric-ratios-relate-to-molar-volume-of-a-gas"> How do stoichiometric ratios relate to molar volume of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-a-gas-at-stp"> How do you calculate molar volume of a gas at STP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-molar-volume-of-hydrogen-gas"> How do you find the molar volume of hydrogen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-oxygen-gas"> How do you calculate molar volume of oxygen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molar-gas-volume"> What is molar gas volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/534c7bf202bf3420a007f014"> What is the volume at 0 °C and 1 atm of a mixture that contains 4.0 g of methane and 2.0 g of helium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5361f75702bf3429040e0599"> What is the difference between STP and NTP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-volume-of-25-moles-of-oxygen-o2-gas"> What is the volume of .25 moles of oxygen (O2) Gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-would-knowing-the-molar-volume-of-a-gas-be-important"> Why would knowing the molar volume of a gas be important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-22-4-liters-called-the-molar-volume-of-a-gas"> Why is 22.4 liters called the molar volume of a gas? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp"> See all questions in Molar Volume of a Gas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 8780 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the volume of hydrogen produced at room temperature and pressure, when 0.2mol of sodium is reacted with an excess of water? [1 mol of gas occupies 24 dm^3 at room temperature and pressure.]	#2Na(s) + 2H_2O(l) -> 2NaOH(aq) + H_2(g)#
1,033	abb250cf-6ddd-11ea-a764-ccda262736ce	https://socratic.org/questions/given-the-reaction-2c3h7oh-9o2-co2-8h2o-how-many-moles-of-oxygen-are-needed-to-r	15.30 moles	start physical_unit 17 17 mole mol qc_end physical_unit 4 4 23 24 mole qc_end chemical_equation 3 12 qc_end end	[{"type":"physical unit","value":"Mole [OF] oxygen [IN] moles"}]	[{"type":"physical unit","value":"15.30 moles"}]	[{"type":"physical unit","value":"Mole [OF] C3H7OH [=] \\pu{3.40 mol}"},{"type":"chemical equation","value":"2 C3H7OH + 9 O2 -> CO2 + 8 H2O"}]	<h1 class="questionTitle" itemprop="name"> Given the reaction 2C3H7OH + 9O2 -->CO2 + 8H2O, how many moles of oxygen are needed to react with 3.40 mol C3H7OH? </h1>	null	15.30 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Equation:</p> <p><mathjax>#C_3H_7OH + 9/2O_2#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#3CO_2 + 4H_2O#</mathjax></p> <p>Is the equation above balanced? (If this was change from a large denomination bill I think you would immediately know whether you were being short-changed!). Let's see: LHS, <mathjax>#3C#</mathjax>, <mathjax>#8H#</mathjax>, and <mathjax>#10O#</mathjax>; RHS, <mathjax>#3C#</mathjax>, <mathjax>#8H#</mathjax>, and <mathjax>#10O#</mathjax>. So it is balanced.</p> <p>Your starting conditions requires the combustion of 3.4 mol propanol. You do the arithmetic, but make sure that you are right.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Given the balanced equation to follow, <mathjax>#9/2#</mathjax> moles of dioxygen gas are required to combust 1 mol propanol. So the answer? </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Equation:</p> <p><mathjax>#C_3H_7OH + 9/2O_2#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#3CO_2 + 4H_2O#</mathjax></p> <p>Is the equation above balanced? (If this was change from a large denomination bill I think you would immediately know whether you were being short-changed!). Let's see: LHS, <mathjax>#3C#</mathjax>, <mathjax>#8H#</mathjax>, and <mathjax>#10O#</mathjax>; RHS, <mathjax>#3C#</mathjax>, <mathjax>#8H#</mathjax>, and <mathjax>#10O#</mathjax>. So it is balanced.</p> <p>Your starting conditions requires the combustion of 3.4 mol propanol. You do the arithmetic, but make sure that you are right.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name"> Given the reaction 2C3H7OH + 9O2 -->CO2 + 8H2O, how many moles of oxygen are needed to react with 3.40 mol C3H7OH? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="179668" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-10-24T19:10:51" itemprop="dateCreated"> Oct 24, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Given the balanced equation to follow, <mathjax>#9/2#</mathjax> moles of dioxygen gas are required to combust 1 mol propanol. So the answer? </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Equation:</p> <p><mathjax>#C_3H_7OH + 9/2O_2#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#3CO_2 + 4H_2O#</mathjax></p> <p>Is the equation above balanced? (If this was change from a large denomination bill I think you would immediately know whether you were being short-changed!). Let's see: LHS, <mathjax>#3C#</mathjax>, <mathjax>#8H#</mathjax>, and <mathjax>#10O#</mathjax>; RHS, <mathjax>#3C#</mathjax>, <mathjax>#8H#</mathjax>, and <mathjax>#10O#</mathjax>. So it is balanced.</p> <p>Your starting conditions requires the combustion of 3.4 mol propanol. You do the arithmetic, but make sure that you are right.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/179668" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="180305" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/nikka-c"><img alt="" class="" src="https://profilepictures.socratic.org/AQ8VOCyTM1J7U0TvIWhw_nkahara.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/nikka-c"> Nikka C. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-10-27T10:26:29" itemprop="dateCreated"> Oct 27, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Are you sure about the equation? seems this isn't balanced seeing that there are 5 carbons on the left side of the equation and only 1 carbon on the right side... </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First, let's balance the above equation properly.</p> <p><mathjax>#C_3H_7OH#</mathjax> + <mathjax>#O_2#</mathjax> = <mathjax>#CO_2#</mathjax> + <mathjax>#H_2O#</mathjax></p> <p>left side:<br/> C = 3<br/> H = 8<br/> O = 1 + 2 (DO NOT ADD IT UP YET)</p> <p>right side:<br/> C = 1<br/> H = 2<br/> O = 2 + 1 (DO NOT ADD IT UP YET)</p> <p>balancing this equation we have</p> <p><mathjax>#C_3H_7OH#</mathjax> + <mathjax>#color (red) (9/2)O_2#</mathjax> = <mathjax>#color (red) 3CO_2#</mathjax> + <mathjax>#color (red) 4H_2O#</mathjax></p> <p>left side:<br/> C = 3<br/> H = 8<br/> O = 1 + (2 x <mathjax>#color (red) (9/2)#</mathjax>) = 10</p> <p>right side:<br/> C = 1 x <mathjax>#color (red) 3#</mathjax> = 3<br/> H = 2 x <mathjax>#color (red) 4#</mathjax> = 8<br/> O = (2 x <mathjax>#color (red) 3#</mathjax>) + (1 x <mathjax>#color (red) 4#</mathjax>) = 10</p> <p>Now that the equation is balanced, we can proceed in answering your initial question. Please note to <strong>ALWAYS</strong> check if the equation is balanced as your computation hangs on the correct coefficients in the chemical equation.</p> <p>You are being asked to compute the number of <mathjax>#O_2#</mathjax> moles needed to react with 3.40 moles of <mathjax>#C_3H_7OH#</mathjax>. </p> <p>From the balanced equation, we know that for every 1 mole of <mathjax>#C_3H_7OH#</mathjax>, it needs <mathjax>#9/2#</mathjax> (or 4.5) moles of <mathjax>#O_2#</mathjax> to react. Thus, </p> <p><mathjax>#3.40#</mathjax> <mathjax>#cancel "mol"#</mathjax> <mathjax>#C_3H_7OH#</mathjax> x <mathjax>#(4.5 "mol" O_2)/(1 cancel ("mol") C_3H_7OH)#</mathjax> = <mathjax>#15.3#</mathjax> <mathjax>#"mol"#</mathjax> <mathjax>#O_2#</mathjax></p> <p>Therefore, the correct answer should be <strong>15.3 moles of <mathjax>#O_2#</mathjax></strong></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/180305" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What is stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ab82402bf342f48d93ac6"> Question #93ac6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-we-study-stoichiometry"> Why do we study stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-naoh-is-produced-from-1-20-x-102-grams-of-na2o-na2o-h2o-2-naoh"> How many grams of NaOH is produced from #1.20 x 10^2# grams of #Na_2O#? #Na_2O + H_2O -> 2NaOH# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-na2o-are-required-to-produce-1-60-x-102-grams-of-naoh-na2o-h2o"> How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? Na2O + H2O ---> 2 NaOH </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-mass-of-iron-is-needed-to-react-with-16-0-grams-of-sulfur-8-fe-s8-8-fes"> What mass of iron is needed to react with 16.0 grams of sulfur? 8 Fe + S8 ---> 8 FeS </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/according-to-8-fe-s8-8-fes-how-many-grams-of-fes-are-produced"> According to 8 Fe + S8 ---> 8 FeS How many grams of FeS are produced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/12-00-moles-of-naclo3-will-produce-how-many-grams-of-o2-2-naclo3-2-nacl-3-o2"> 12.00 moles of NaClO3 will produce how many grams of O2? 2 NaClO3 ---> 2 NaCl + 3 O2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-nacl-are-produced-when-80-0-grams-of-o2-are-produced-2-naclo3-"> How many grams of NaCl are produced when 80.0 grams of O2 are produced? 2 NaClO3 ---> 2 NaCl + 3 O2 </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/stoichiometry"> See all questions in Stoichiometry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 19212 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Given the reaction 2C3H7OH + 9O2 -->CO2 + 8H2O, how many moles of oxygen are needed to react with 3.40 mol C3H7OH?	null
1,034	aaafbbba-6ddd-11ea-84b4-ccda262736ce	https://socratic.org/questions/for-this-reaction-ti-s-2f-2-g-tif-4-s-what-is-the-theoretical-yield-of-the-produ	5.21 grams	start physical_unit 15 16 theoretical_yield g qc_end physical_unit 3 3 23 24 mass qc_end physical_unit 6 6 27 28 mass qc_end chemical_equation 3 8 qc_end end	[{"type":"physical unit","value":"Theoretical yield [OF] the product [IN] grams"}]	[{"type":"physical unit","value":"5.21 grams"}]	[{"type":"physical unit","value":"Mass [OF] Ti [=] \\pu{4.8 g}"},{"type":"physical unit","value":"Mass [OF] F2 [=] \\pu{3.2 g}"},{"type":"chemical equation","value":"Ti(s) + 2 F2(g) -> TiF4(s)"}]	<h1 class="questionTitle" itemprop="name">For this reaction #Ti(s) +2F_2(g) -> TiF_4(s)#, what is the theoretical yield of the product, in grams, if you start with #4.8g Ti and 3.2g F_2# ?</h1>	null	5.21 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>We must first identify the limiting reactant, and then we can calculate the theoretical yield.</p> <p>We start with the balanced equation.</p> <p><mathjax>#color(white)(mmmmmmml)"Ti" +color(white)(l) "2F"_2 → color(white)(ll)"TiF"_4#</mathjax><br/> <mathjax>#"MM/g·mol"^"-1": 47.87color(white)(ll) 38.00color(white)(mll) 123.86#</mathjax></p> <blockquote></blockquote> <p><strong>(a) Identify the limiting reactant</strong></p> <p>We calculate the amount of <mathjax>#"TiF"_4#</mathjax> that can form from each reactant.</p> <blockquote></blockquote> <p><strong>Calculate the moles of <mathjax>#"Ti"#</mathjax></strong>.</p> <p><mathjax>#"Moles of Ti" = 4.8 color(red)(cancel(color(black)("g Ti"))) × "1 mol Ti"/(47.87 color(red)(cancel(color(black)("g Ti")))) = "0.100 mol Ti"#</mathjax></p> <blockquote></blockquote> <p>Calculate moles of <mathjax>#"TiF"_4#</mathjax> formed from <mathjax>#"Ti"#</mathjax></p> <p><mathjax>#0.100color(red)(cancel(color(black)("mol Ti"))) × "1 mol TiF"_4/(1 color(red)(cancel(color(black)("mol Ti")))) = "0.100 mol TiCl"_4#</mathjax></p> <blockquote></blockquote> <p><strong>Calculate the moles of <mathjax>#"F"2#</mathjax></strong></p> <p><mathjax>#"Moles of F"_2 = 3.2 color(red)(cancel(color(black)("g F"_2))) × "1 mol F"_2/(38.00 color(red)(cancel(color(black)("g F_2")))) = "0.0842 mol F"_2#</mathjax></p> <blockquote></blockquote> <p>Calculate moles of <mathjax>#"TiF"_4#</mathjax> formed from <mathjax>#"F"_2#</mathjax></p> <p><mathjax>#0.0842 color(red)(cancel(color(black)("mol F"_2))) × "1 mol TiF"_4/(2 color(red)(cancel(color(black)("mol F"_2)))) = "0.0421 mol TiF"_4#</mathjax></p> <p>The limiting reactant is <mathjax>#"F"_2#</mathjax>, because it produces fewer moles of <mathjax>#"TiF"_4#</mathjax>.</p> <blockquote></blockquote> <p><strong>(b) Calculate the theoretical yield of <mathjax>#"TiF"_4#</mathjax>.</strong></p> <p><mathjax>#"Theoretical yield" = 0.0421 color(red)(cancel(color(black)("mol TiF"_4))) × "123.86 g TiF"_4/(1 color(red)(cancel(color(black)("mol TiF"_4)))) = "5.2 g TiF"_4#</mathjax></p> <p>The theoretical yield of <mathjax>#"TiF"_4#</mathjax> is 5.2 g.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The theoretical yield of <mathjax>#"TiF"_4#</mathjax> is 5.2 g.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>We must first identify the limiting reactant, and then we can calculate the theoretical yield.</p> <p>We start with the balanced equation.</p> <p><mathjax>#color(white)(mmmmmmml)"Ti" +color(white)(l) "2F"_2 → color(white)(ll)"TiF"_4#</mathjax><br/> <mathjax>#"MM/g·mol"^"-1": 47.87color(white)(ll) 38.00color(white)(mll) 123.86#</mathjax></p> <blockquote></blockquote> <p><strong>(a) Identify the limiting reactant</strong></p> <p>We calculate the amount of <mathjax>#"TiF"_4#</mathjax> that can form from each reactant.</p> <blockquote></blockquote> <p><strong>Calculate the moles of <mathjax>#"Ti"#</mathjax></strong>.</p> <p><mathjax>#"Moles of Ti" = 4.8 color(red)(cancel(color(black)("g Ti"))) × "1 mol Ti"/(47.87 color(red)(cancel(color(black)("g Ti")))) = "0.100 mol Ti"#</mathjax></p> <blockquote></blockquote> <p>Calculate moles of <mathjax>#"TiF"_4#</mathjax> formed from <mathjax>#"Ti"#</mathjax></p> <p><mathjax>#0.100color(red)(cancel(color(black)("mol Ti"))) × "1 mol TiF"_4/(1 color(red)(cancel(color(black)("mol Ti")))) = "0.100 mol TiCl"_4#</mathjax></p> <blockquote></blockquote> <p><strong>Calculate the moles of <mathjax>#"F"2#</mathjax></strong></p> <p><mathjax>#"Moles of F"_2 = 3.2 color(red)(cancel(color(black)("g F"_2))) × "1 mol F"_2/(38.00 color(red)(cancel(color(black)("g F_2")))) = "0.0842 mol F"_2#</mathjax></p> <blockquote></blockquote> <p>Calculate moles of <mathjax>#"TiF"_4#</mathjax> formed from <mathjax>#"F"_2#</mathjax></p> <p><mathjax>#0.0842 color(red)(cancel(color(black)("mol F"_2))) × "1 mol TiF"_4/(2 color(red)(cancel(color(black)("mol F"_2)))) = "0.0421 mol TiF"_4#</mathjax></p> <p>The limiting reactant is <mathjax>#"F"_2#</mathjax>, because it produces fewer moles of <mathjax>#"TiF"_4#</mathjax>.</p> <blockquote></blockquote> <p><strong>(b) Calculate the theoretical yield of <mathjax>#"TiF"_4#</mathjax>.</strong></p> <p><mathjax>#"Theoretical yield" = 0.0421 color(red)(cancel(color(black)("mol TiF"_4))) × "123.86 g TiF"_4/(1 color(red)(cancel(color(black)("mol TiF"_4)))) = "5.2 g TiF"_4#</mathjax></p> <p>The theoretical yield of <mathjax>#"TiF"_4#</mathjax> is 5.2 g.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">For this reaction #Ti(s) +2F_2(g) -> TiF_4(s)#, what is the theoretical yield of the product, in grams, if you start with #4.8g Ti and 3.2g F_2# ?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/percent-yield" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Yield</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="298936" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-08-14T17:55:07" itemprop="dateCreated"> Aug 14, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The theoretical yield of <mathjax>#"TiF"_4#</mathjax> is 5.2 g.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>We must first identify the limiting reactant, and then we can calculate the theoretical yield.</p> <p>We start with the balanced equation.</p> <p><mathjax>#color(white)(mmmmmmml)"Ti" +color(white)(l) "2F"_2 → color(white)(ll)"TiF"_4#</mathjax><br/> <mathjax>#"MM/g·mol"^"-1": 47.87color(white)(ll) 38.00color(white)(mll) 123.86#</mathjax></p> <blockquote></blockquote> <p><strong>(a) Identify the limiting reactant</strong></p> <p>We calculate the amount of <mathjax>#"TiF"_4#</mathjax> that can form from each reactant.</p> <blockquote></blockquote> <p><strong>Calculate the moles of <mathjax>#"Ti"#</mathjax></strong>.</p> <p><mathjax>#"Moles of Ti" = 4.8 color(red)(cancel(color(black)("g Ti"))) × "1 mol Ti"/(47.87 color(red)(cancel(color(black)("g Ti")))) = "0.100 mol Ti"#</mathjax></p> <blockquote></blockquote> <p>Calculate moles of <mathjax>#"TiF"_4#</mathjax> formed from <mathjax>#"Ti"#</mathjax></p> <p><mathjax>#0.100color(red)(cancel(color(black)("mol Ti"))) × "1 mol TiF"_4/(1 color(red)(cancel(color(black)("mol Ti")))) = "0.100 mol TiCl"_4#</mathjax></p> <blockquote></blockquote> <p><strong>Calculate the moles of <mathjax>#"F"2#</mathjax></strong></p> <p><mathjax>#"Moles of F"_2 = 3.2 color(red)(cancel(color(black)("g F"_2))) × "1 mol F"_2/(38.00 color(red)(cancel(color(black)("g F_2")))) = "0.0842 mol F"_2#</mathjax></p> <blockquote></blockquote> <p>Calculate moles of <mathjax>#"TiF"_4#</mathjax> formed from <mathjax>#"F"_2#</mathjax></p> <p><mathjax>#0.0842 color(red)(cancel(color(black)("mol F"_2))) × "1 mol TiF"_4/(2 color(red)(cancel(color(black)("mol F"_2)))) = "0.0421 mol TiF"_4#</mathjax></p> <p>The limiting reactant is <mathjax>#"F"_2#</mathjax>, because it produces fewer moles of <mathjax>#"TiF"_4#</mathjax>.</p> <blockquote></blockquote> <p><strong>(b) Calculate the theoretical yield of <mathjax>#"TiF"_4#</mathjax>.</strong></p> <p><mathjax>#"Theoretical yield" = 0.0421 color(red)(cancel(color(black)("mol TiF"_4))) × "123.86 g TiF"_4/(1 color(red)(cancel(color(black)("mol TiF"_4)))) = "5.2 g TiF"_4#</mathjax></p> <p>The theoretical yield of <mathjax>#"TiF"_4#</mathjax> is 5.2 g.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/298936" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ebd02bf3469570e2e62"> Question #e2e62 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ec502bf34694a4fee2e"> Question #fee2e </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ec902bf34694a4fee32"> Question #fee32 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" 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<div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	For this reaction #Ti(s) +2F_2(g) -> TiF_4(s)#, what is the theoretical yield of the product, in grams, if you start with #4.8g Ti and 3.2g F_2# ?	null
1,035	a8d93098-6ddd-11ea-a244-ccda262736ce	https://socratic.org/questions/what-is-the-density-of-chlorine-gas-at-1-21-atm-and-34-9-c	3.40 g/L	start physical_unit 5 6 density g/l qc_end physical_unit 5 6 8 9 pressure qc_end physical_unit 5 6 11 12 temperature qc_end end	[{"type":"physical unit","value":"Density [OF] chlorine gas [IN] g/L"}]	[{"type":"physical unit","value":"3.40 g/L"}]	[{"type":"physical unit","value":"Pressure [OF] chlorine gas [=] \\pu{1.21 atm}"},{"type":"physical unit","value":"Temperature [OF] chlorine gas [=] \\pu{34.9 ℃}"}]	<h1 class="questionTitle" itemprop="name">What is the density of chlorine gas at 1.21 atm and 34.9°C?</h1>	null	3.40 g/L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We assume (reasonably) ideal gas behaviour.</p> <p>And thus <mathjax>#PV=nRT#</mathjax>, else <mathjax>#n/V=P/(RT)#</mathjax></p> <p><mathjax>#=#</mathjax> <mathjax>#(1.21atm)/(0.0821LatmK^-1mol^-1xx307.9K)#</mathjax></p> <p><mathjax>#=#</mathjax> <mathjax>#0.0479molL^-1#</mathjax>.</p> <p>So, we have worked out a <a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a> in <mathjax>#molL^-1#</mathjax>, and we multiply this by the molecular mass in <mathjax>#gmol^-1#</mathjax>.</p> <p>And <mathjax>#70.9gmol^-1xx0.0479molL^-1=3.40gL^-1.#</mathjax></p> <p>From where did I get the figure <mathjax>#70.9gmol^-1#</mathjax>?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#rho=3.40gL^-1.#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We assume (reasonably) ideal gas behaviour.</p> <p>And thus <mathjax>#PV=nRT#</mathjax>, else <mathjax>#n/V=P/(RT)#</mathjax></p> <p><mathjax>#=#</mathjax> <mathjax>#(1.21atm)/(0.0821LatmK^-1mol^-1xx307.9K)#</mathjax></p> <p><mathjax>#=#</mathjax> <mathjax>#0.0479molL^-1#</mathjax>.</p> <p>So, we have worked out a <a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a> in <mathjax>#molL^-1#</mathjax>, and we multiply this by the molecular mass in <mathjax>#gmol^-1#</mathjax>.</p> <p>And <mathjax>#70.9gmol^-1xx0.0479molL^-1=3.40gL^-1.#</mathjax></p> <p>From where did I get the figure <mathjax>#70.9gmol^-1#</mathjax>?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the density of chlorine gas at 1.21 atm and 34.9°C?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/ideal-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Ideal Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="349124" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-12-09T07:50:33" itemprop="dateCreated"> Dec 9, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#rho=3.40gL^-1.#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We assume (reasonably) ideal gas behaviour.</p> <p>And thus <mathjax>#PV=nRT#</mathjax>, else <mathjax>#n/V=P/(RT)#</mathjax></p> <p><mathjax>#=#</mathjax> <mathjax>#(1.21atm)/(0.0821LatmK^-1mol^-1xx307.9K)#</mathjax></p> <p><mathjax>#=#</mathjax> <mathjax>#0.0479molL^-1#</mathjax>.</p> <p>So, we have worked out a <a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a> in <mathjax>#molL^-1#</mathjax>, and we multiply this by the molecular mass in <mathjax>#gmol^-1#</mathjax>.</p> <p>And <mathjax>#70.9gmol^-1xx0.0479molL^-1=3.40gL^-1.#</mathjax></p> <p>From where did I get the figure <mathjax>#70.9gmol^-1#</mathjax>?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/349124" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-ideal-gas-constant"> How do you find the ideal gas constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-solve-ideal-gas-law-problems"> How do you solve ideal gas law problems? 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R = 8.314 kPa L / (K mol) =... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-molar-mass-of-a-gas"> How do you calculate the molar mass of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-should-i-use-the-ideal-gas-law-and-not-the-combined-gas-law"> When should I use the ideal gas law and not the combined gas law? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/ideal-gas-law"> See all questions in Ideal Gas Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 25530 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the density of chlorine gas at 1.21 atm and 34.9°C?	null
1,036	aab9fd5e-6ddd-11ea-acf5-ccda262736ce	https://socratic.org/questions/how-many-hydrogen-atoms-are-in-5-molecules-of-isopropyl-alcohol-c-3h-7o	40	start physical_unit 2 3 number none qc_end end	[{"type":"physical unit","value":"Number [OF] hydrogen atoms"}]	[{"type":"physical unit","value":"40"}]	[{"type":"physical unit","value":"Number [OF] C3H7O molecules [=] \\pu{5}"}]	<h1 class="questionTitle" itemprop="name">How many hydrogen atoms are in 5 molecules of isopropyl alcohol, #C_3H_7O#?</h1>	null	40	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First, the correct chemical formula of isopropyl alcohol is <mathjax>#C_3H_7OH#</mathjax> and not <mathjax>#C_3H_7O#</mathjax>.<br/> That being said, <mathjax>#C_3H_7OH#</mathjax> represents one molecule of isopropyl alcohol, which has <mathjax>#8#</mathjax> Hydrogen atoms.<br/> So, the number of Hydrogen atoms in 5 molecules of <mathjax>#C_3H_7OH#</mathjax> will be <mathjax>#8 xx 5 = 40#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#40#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First, the correct chemical formula of isopropyl alcohol is <mathjax>#C_3H_7OH#</mathjax> and not <mathjax>#C_3H_7O#</mathjax>.<br/> That being said, <mathjax>#C_3H_7OH#</mathjax> represents one molecule of isopropyl alcohol, which has <mathjax>#8#</mathjax> Hydrogen atoms.<br/> So, the number of Hydrogen atoms in 5 molecules of <mathjax>#C_3H_7OH#</mathjax> will be <mathjax>#8 xx 5 = 40#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many hydrogen atoms are in 5 molecules of isopropyl alcohol, #C_3H_7O#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="341982" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/arnav"><img alt="" class="" src="https://profilepictures.socratic.org/ADQ9Gpv9QMq8swEt508e_916af7c78e993e4c9623cf391a3029b8.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/arnav"> Arnav </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-11-26T05:38:24" itemprop="dateCreated"> Nov 26, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#40#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First, the correct chemical formula of isopropyl alcohol is <mathjax>#C_3H_7OH#</mathjax> and not <mathjax>#C_3H_7O#</mathjax>.<br/> That being said, <mathjax>#C_3H_7OH#</mathjax> represents one molecule of isopropyl alcohol, which has <mathjax>#8#</mathjax> Hydrogen atoms.<br/> So, the number of Hydrogen atoms in 5 molecules of <mathjax>#C_3H_7OH#</mathjax> will be <mathjax>#8 xx 5 = 40#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/341982" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? 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1,037	acb24937-6ddd-11ea-8ded-ccda262736ce	https://socratic.org/questions/57179ff711ef6b5a750792b8	Al2O3	start chemical_formula qc_end substance 5 5 qc_end end	[{"type":"other","value":"Chemical Formula [OF] alumina [IN] default"}]	[{"type":"chemical equation","value":"Al2O3"}]	[{"type":"substance name","value":"Alumina"}]	<h1 class="questionTitle" itemprop="name">What is the formula of alumina?</h1>	null	Al2O3	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#Al_2O_3#</mathjax> is the typical compound. This is widely used in industry as a material in the manufacture of glass, as an abrasive, and as an ingredient in sun blocks, and for other stuff. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>For aluminum oxide, alumina? <mathjax>#Al_2O_3#</mathjax> is the typical compound.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#Al_2O_3#</mathjax> is the typical compound. This is widely used in industry as a material in the manufacture of glass, as an abrasive, and as an ingredient in sun blocks, and for other stuff. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the formula of alumina?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="320551" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-10-11T15:35:32" itemprop="dateCreated"> Oct 11, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>For aluminum oxide, alumina? <mathjax>#Al_2O_3#</mathjax> is the typical compound.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#Al_2O_3#</mathjax> is the typical compound. This is widely used in industry as a material in the manufacture of glass, as an abrasive, and as an ingredient in sun blocks, and for other stuff. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/320551" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molecular-formula-of-a-compound"> How do you find molecular formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-diamond"> What is the chemical formula of a diamond? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-carbohydrate"> What is the chemical formula of a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-valproic-acid"> What is the empirical formula for valproic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-of-magnesium-oxide"> What is the empirical formula of magnesium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-empirical-formula-not-double-that-of-the-monosaccharides"> Why is the empirical formula not double that of the monosaccharides? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5331180502bf342f40b5c3b5"> Question #5c3b5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-molecular-formula-represents-a-carbohydrate"> What molecular formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-of-vinegar"> What is the molecular formula of vinegar? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/empirical-and-molecular-formulas"> See all questions in Empirical and Molecular Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2315 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the formula of alumina?	null
1,038	ac9615e5-6ddd-11ea-9027-ccda262736ce	https://socratic.org/questions/how-much-potassium-nitrate-do-you-think-could-dissolve-in-100-ml-of-water-at-60-	110 g	start physical_unit 2 3 mass g qc_end physical_unit 13 13 10 11 volume qc_end physical_unit 13 13 15 16 temperature qc_end end	[{"type":"physical unit","value":"Mass [OF] potassium nitrate [IN] g"}]	[{"type":"physical unit","value":"110 g"}]	[{"type":"physical unit","value":"Volume [OF] water [=] \\pu{100 mL}"},{"type":"physical unit","value":"Temperature [OF] water [=] \\pu{60 ℃}"}]	<h1 class="questionTitle" itemprop="name">How much potassium nitrate do you think could dissolve in 100 mL of water at 60°C? </h1>	null	110 g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your tool of choice here will be the <strong>solubility graph</strong> for potassium nitrate, <mathjax>#"KNO"_3#</mathjax>, in water. </p> <blockquote> <blockquote> <blockquote> <p><img alt="www.nakka-rocketry.net" src="https://useruploads.socratic.org/jP6PQ9TkOuSjfaXtw5Ug_kno3_solubility.gif"/> </p> </blockquote> </blockquote> </blockquote> <p>The solubility graph is a very useful tool because it tells you the amount of potassium nitrate that can be dissolved <strong>per</strong> <mathjax>#"100 mL"#</mathjax> <strong>of water</strong> in order to have a <strong>saturated solution</strong> of potassium nitrate at a given temperature. </p> <p>In order to find the solubility of the salt at <mathjax>#60^@"C"#</mathjax>, start from the <mathjax>#60^@"C"#</mathjax> mark on the graph and <strong>move up</strong> until you intersect the curve. At the point of intersection, <strong>move left</strong> until you intersect the <mathjax>#y#</mathjax> axis and read off the value that you land on. </p> <p>In this case, you can estimate that the solubility of potassium nitrate in water at <mathjax>#60^@"C"#</mathjax> is equal to about </p> <blockquote> <p><mathjax>#color(darkgreen)(ul(color(black)("solubility " ~~ " 110 g / 100 mL water")))#</mathjax></p> </blockquote> <p>This tells you that a <strong>saturated solution</strong> of potassium nitrate will hold about <mathjax>#"110 g"#</mathjax> of <strong>dissolved</strong> salt, i.e. of <em>dissociated salt</em>, per <mathjax>#"100 mL"#</mathjax> of water at <mathjax>#60^@"C"#</mathjax>. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>About <mathjax>#"110 g"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your tool of choice here will be the <strong>solubility graph</strong> for potassium nitrate, <mathjax>#"KNO"_3#</mathjax>, in water. </p> <blockquote> <blockquote> <blockquote> <p><img alt="www.nakka-rocketry.net" src="https://useruploads.socratic.org/jP6PQ9TkOuSjfaXtw5Ug_kno3_solubility.gif"/> </p> </blockquote> </blockquote> </blockquote> <p>The solubility graph is a very useful tool because it tells you the amount of potassium nitrate that can be dissolved <strong>per</strong> <mathjax>#"100 mL"#</mathjax> <strong>of water</strong> in order to have a <strong>saturated solution</strong> of potassium nitrate at a given temperature. </p> <p>In order to find the solubility of the salt at <mathjax>#60^@"C"#</mathjax>, start from the <mathjax>#60^@"C"#</mathjax> mark on the graph and <strong>move up</strong> until you intersect the curve. At the point of intersection, <strong>move left</strong> until you intersect the <mathjax>#y#</mathjax> axis and read off the value that you land on. </p> <p>In this case, you can estimate that the solubility of potassium nitrate in water at <mathjax>#60^@"C"#</mathjax> is equal to about </p> <blockquote> <p><mathjax>#color(darkgreen)(ul(color(black)("solubility " ~~ " 110 g / 100 mL water")))#</mathjax></p> </blockquote> <p>This tells you that a <strong>saturated solution</strong> of potassium nitrate will hold about <mathjax>#"110 g"#</mathjax> of <strong>dissolved</strong> salt, i.e. of <em>dissociated salt</em>, per <mathjax>#"100 mL"#</mathjax> of water at <mathjax>#60^@"C"#</mathjax>. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How much potassium nitrate do you think could dissolve in 100 mL of water at 60°C? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/solubility-graphs" itemprop="url"> <span class="breadcrumb" itemprop="title">Solubility Graphs</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="441658" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-19T00:54:49" itemprop="dateCreated"> Jun 19, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>About <mathjax>#"110 g"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your tool of choice here will be the <strong>solubility graph</strong> for potassium nitrate, <mathjax>#"KNO"_3#</mathjax>, in water. </p> <blockquote> <blockquote> <blockquote> <p><img alt="www.nakka-rocketry.net" src="https://useruploads.socratic.org/jP6PQ9TkOuSjfaXtw5Ug_kno3_solubility.gif"/> </p> </blockquote> </blockquote> </blockquote> <p>The solubility graph is a very useful tool because it tells you the amount of potassium nitrate that can be dissolved <strong>per</strong> <mathjax>#"100 mL"#</mathjax> <strong>of water</strong> in order to have a <strong>saturated solution</strong> of potassium nitrate at a given temperature. </p> <p>In order to find the solubility of the salt at <mathjax>#60^@"C"#</mathjax>, start from the <mathjax>#60^@"C"#</mathjax> mark on the graph and <strong>move up</strong> until you intersect the curve. At the point of intersection, <strong>move left</strong> until you intersect the <mathjax>#y#</mathjax> axis and read off the value that you land on. </p> <p>In this case, you can estimate that the solubility of potassium nitrate in water at <mathjax>#60^@"C"#</mathjax> is equal to about </p> <blockquote> <p><mathjax>#color(darkgreen)(ul(color(black)("solubility " ~~ " 110 g / 100 mL water")))#</mathjax></p> </blockquote> <p>This tells you that a <strong>saturated solution</strong> of potassium nitrate will hold about <mathjax>#"110 g"#</mathjax> of <strong>dissolved</strong> salt, i.e. of <em>dissociated salt</em>, per <mathjax>#"100 mL"#</mathjax> of water at <mathjax>#60^@"C"#</mathjax>. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/441658" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-solubility-affect-temperature"> How does solubility affect temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-solubility-change-with-temperature-for-gases"> How does solubility change with temperature for gases? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-solubility-at-different-temperatures"> How do you determine solubility at different temperatures? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-mutual-solubility-temperature"> What is mutual solubility temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-oxygen-saturation-important"> Why is oxygen saturation important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-does-saturation-occur"> Why does saturation occur? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-the-customary-units-of-solubility-on-solubility-curves"> What are the customary units of solubility on solubility curves? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-temperature-is-required-for-130-grams-of-glucose-to-dissolve-in-100-ml-of-w"> What temperature is required for 130 grams of glucose to dissolve in 100 mL of water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-a-dashed-line-on-a-solubility-curve-represent"> What does a dashed line on a solubility curve represent? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/which-substances-are-most-likely-gases-in-a-solubility-curve"> Which substances are most likely gases in a solubility curve? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/solubility-graphs"> See all questions in Solubility Graphs </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 43710 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How much potassium nitrate do you think could dissolve in 100 mL of water at 60°C?	null
1,039	ace2becd-6ddd-11ea-aa69-ccda262736ce	https://socratic.org/questions/how-many-hydrogen-atoms-are-represented-in-the-formula-ch-3-2ch-2	8	start physical_unit 2 3 number none qc_end chemical_equation 9 9 qc_end end	[{"type":"physical unit","value":"Number [OF] hydrogen atoms"}]	[{"type":"physical unit","value":"8"}]	[{"type":"chemical equation","value":"(CH3)2CH2"}]	<h1 class="questionTitle" itemprop="name">How many hydrogen atoms are represented in the formula #(CH_3)_2CH_2#?</h1>	null	8	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>How do you know there are 8 hydrogens? It is largely a matter of practice to look at a formula, and state it more simple terms.</p> <p>You have <mathjax>#(H_3C)_2CH_2#</mathjax>; I could equally as correctly represent this as <mathjax>#H_3C-CH_2-CH_3#</mathjax>. Is this clear from the formula? I could condense the formula to give <mathjax>#C_3H_8#</mathjax>, i.e. 8 hydrogens as required. </p> <p>So you have got propane, what about butane, <mathjax>#H_3C(CH_2)_2CH_3#</mathjax>, what about pentane, <mathjax>#H_3C(CH_2)_3CH_3#</mathjax>, what about hexane, <mathjax>#H_3C(CH_2)_4CH_3#</mathjax>? How many carbons in each molecule? And how many hydrogens? As the chain grows, of course, the opportunity for isomerism becomes greater. The general formula for alkanes is <mathjax>#C_nH_(2n+2)#</mathjax>. Do all the linear alkanes here obey this formula?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>You have represented propane. There are 8 hydrogen atoms in this molecule.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>How do you know there are 8 hydrogens? It is largely a matter of practice to look at a formula, and state it more simple terms.</p> <p>You have <mathjax>#(H_3C)_2CH_2#</mathjax>; I could equally as correctly represent this as <mathjax>#H_3C-CH_2-CH_3#</mathjax>. Is this clear from the formula? I could condense the formula to give <mathjax>#C_3H_8#</mathjax>, i.e. 8 hydrogens as required. </p> <p>So you have got propane, what about butane, <mathjax>#H_3C(CH_2)_2CH_3#</mathjax>, what about pentane, <mathjax>#H_3C(CH_2)_3CH_3#</mathjax>, what about hexane, <mathjax>#H_3C(CH_2)_4CH_3#</mathjax>? How many carbons in each molecule? And how many hydrogens? As the chain grows, of course, the opportunity for isomerism becomes greater. The general formula for alkanes is <mathjax>#C_nH_(2n+2)#</mathjax>. Do all the linear alkanes here obey this formula?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many hydrogen atoms are represented in the formula #(CH_3)_2CH_2#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/determining-formula-and-molar-masses" itemprop="url"> <span class="breadcrumb" itemprop="title">Determining Formula</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="209337" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-07T10:18:00" itemprop="dateCreated"> Jan 7, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>You have represented propane. There are 8 hydrogen atoms in this molecule.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>How do you know there are 8 hydrogens? It is largely a matter of practice to look at a formula, and state it more simple terms.</p> <p>You have <mathjax>#(H_3C)_2CH_2#</mathjax>; I could equally as correctly represent this as <mathjax>#H_3C-CH_2-CH_3#</mathjax>. Is this clear from the formula? I could condense the formula to give <mathjax>#C_3H_8#</mathjax>, i.e. 8 hydrogens as required. </p> <p>So you have got propane, what about butane, <mathjax>#H_3C(CH_2)_2CH_3#</mathjax>, what about pentane, <mathjax>#H_3C(CH_2)_3CH_3#</mathjax>, what about hexane, <mathjax>#H_3C(CH_2)_4CH_3#</mathjax>? How many carbons in each molecule? And how many hydrogens? As the chain grows, of course, the opportunity for isomerism becomes greater. The general formula for alkanes is <mathjax>#C_nH_(2n+2)#</mathjax>. Do all the linear alkanes here obey this formula?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/209337" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-it-possible-to-find-a-molecular-formula-from-molar-mass"> Is it possible to find a molecular formula from molar mass? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5368e0cc02bf34779e175781"> Question #75781 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-common-mistakes-students-make-when-determining-formulas"> What are some common mistakes students make when determining formulas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-formula-of-an-acid"> How can I determine the formula of an acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-chemical-formula-of-a-product"> How can I determine the chemical formula of a product? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-empirical-formula-of-a-compound"> How can I determine the empirical formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-formula-of-a-hydrate"> How can I determine the formula of a hydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-the-empirical-formula-indicate"> What does the empirical formula indicate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-molecule-with-molecular-weight-of-180-18-g-mol-is-analyzed-and-found-to-contai"> A molecule with molecular weight of 180.18 g/mol is analyzed and found to contain 40.00% carbon,... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/do-i-need-to-know-the-number-of-moles-of-each-element-to-determine-the-formula-o"> Do I need to know the number of moles of each element to determine the formula of the compound? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/determining-formula-and-molar-masses"> See all questions in Determining Formula </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 17127 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many hydrogen atoms are represented in the formula #(CH_3)_2CH_2#?	null
1,040	aa6972f9-6ddd-11ea-9e8d-ccda262736ce	https://socratic.org/questions/iron-is-extracted-from-iron-ore-part-of-the-process-involves-reduction-of-the-or	Fe2O3(s) + 3 CO(g) ->[\Delta] 2 Fe(l) + 3 CO2(g)	start chemical_equation qc_end chemical_equation 23 23 qc_end substance 16 17 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the reaction"}]	[{"type":"chemical equation","value":"Fe2O3(s) + 3 CO(g) ->[\\Delta] 2 Fe(l) + 3 CO2(g)"}]	[{"type":"chemical equation","value":"Fe2O3"},{"type":"substance name","value":"carbon monoxide"}]	<h1 class="questionTitle" itemprop="name">Iron is extracted from iron ore. Part of the process involves reduction of the ore with carbon monoxide. Iron ore contains iron oxide (#Fe_2O_3#). How would you write a balanced equation for the reaction of iron oxide with carbon monoxide?</h1>	null	Fe2O3(s) + 3 CO(g) ->[\Delta] 2 Fe(l) + 3 CO2(g)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And this is the effectual chemical reaction of our civilization. If you ever have a chance to tour a blast furnace (and most are in China and India now) do it.....you will feel very small. </p> <p>And <a href="https://socratic.org/questions/fe2o3-s-3co-g-2fe-s-3co2-g-using-the-following-balanced-equation-calculate-the-a-1?source=search">see this old answer.......</a> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Fe_2O_3(s) +3CO(g) stackrelDeltararr2Fe(l) + 3CO_2(g)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And this is the effectual chemical reaction of our civilization. If you ever have a chance to tour a blast furnace (and most are in China and India now) do it.....you will feel very small. </p> <p>And <a href="https://socratic.org/questions/fe2o3-s-3co-g-2fe-s-3co2-g-using-the-following-balanced-equation-calculate-the-a-1?source=search">see this old answer.......</a> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Iron is extracted from iron ore. Part of the process involves reduction of the ore with carbon monoxide. Iron ore contains iron oxide (#Fe_2O_3#). How would you write a balanced equation for the reaction of iron oxide with carbon monoxide?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/redox-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Redox Reactions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="509152" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-11-21T07:16:53" itemprop="dateCreated"> Nov 21, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Fe_2O_3(s) +3CO(g) stackrelDeltararr2Fe(l) + 3CO_2(g)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And this is the effectual chemical reaction of our civilization. If you ever have a chance to tour a blast furnace (and most are in China and India now) do it.....you will feel very small. </p> <p>And <a href="https://socratic.org/questions/fe2o3-s-3co-g-2fe-s-3co2-g-using-the-following-balanced-equation-calculate-the-a-1?source=search">see this old answer.......</a> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/509152" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/54423f26581e2a5bfd08340d"> Question #8340d </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-redox-reaction"> What is a redox reaction? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-oxidation"> What is oxidation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-reduction"> What is reduction? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/54d532c6581e2a49268014c4"> Question #014c4 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/556ea205581e2a438ccb58e9"> Question #b58e9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/55973977581e2a5f9d456add"> Question #56add </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/55ad1b09581e2a5dd320853f"> Question #0853f </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/55b8d545581e2a20b9abe12b"> Question #be12b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5618b78a11ef6b27240f7e3f"> Question #f7e3f </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/redox-reactions"> See all questions in Redox Reactions </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 8858 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Iron is extracted from iron ore. Part of the process involves reduction of the ore with carbon monoxide. Iron ore contains iron oxide (#Fe_2O_3#). How would you write a balanced equation for the reaction of iron oxide with carbon monoxide?	null
1,041	ac577500-6ddd-11ea-8014-ccda262736ce	https://socratic.org/questions/how-do-you-write-a-balanced-chemical-equation-for-the-reaction-of-magnesium-soli	Mg + H2SO4 -> MgSO4 + H2	start chemical_equation qc_end substance 12 13 qc_end substance 15 16 qc_end substance 19 20 qc_end substance 22 23 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the chemical equation"}]	[{"type":"chemical equation","value":"Mg + H2SO4 -> MgSO4 + H2"}]	[{"type":"substance name","value":"Magnesium solid"},{"type":"substance name","value":"Sulfuric acid"},{"type":"substance name","value":"Hydrogen gas"},{"type":"substance name","value":"Magnesium sulfate"}]	<h1 class="questionTitle" itemprop="name">How do you write a balanced chemical equation for the reaction of magnesium solid with sulfuric acid to form hydrogen gas and magnesium sulfate?</h1>	null	Mg + H2SO4 -> MgSO4 + H2	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Magnesium combined with sulfuric acid produces magnesium sulfate and hydrogen gas.</p> <p>Reactants:</p> <p>The symbol for magnesium is <mathjax>#Mg#</mathjax>.</p> <p>The formula for sulfuric acid is <mathjax>#H_2SO_4#</mathjax></p> <p>Products:</p> <p>Magnesium forms a <mathjax>#2+#</mathjax> ion: <mathjax>#Mg^(2+)#</mathjax></p> <p>The sulfate ion has a charge of <mathjax>#2-#</mathjax>: <mathjax>#SO_4^(2-)#</mathjax></p> <p>The charges balance and thus the formula for <br/> magnesum sulfate is <mathjax>#MgSO_4#</mathjax></p> <p>Hydrogen gas is diatomic: <mathjax>#H_2#</mathjax></p> <p><mathjax>#Mg + H_2SO_4->MgSO_4 +H_2#</mathjax></p> <p>The reaction is balanced as written. Each side has one magnesium atom, two hydrogen atoms and one sulfate ion.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Mg + H_2SO_4->MgSO_4 +H_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Magnesium combined with sulfuric acid produces magnesium sulfate and hydrogen gas.</p> <p>Reactants:</p> <p>The symbol for magnesium is <mathjax>#Mg#</mathjax>.</p> <p>The formula for sulfuric acid is <mathjax>#H_2SO_4#</mathjax></p> <p>Products:</p> <p>Magnesium forms a <mathjax>#2+#</mathjax> ion: <mathjax>#Mg^(2+)#</mathjax></p> <p>The sulfate ion has a charge of <mathjax>#2-#</mathjax>: <mathjax>#SO_4^(2-)#</mathjax></p> <p>The charges balance and thus the formula for <br/> magnesum sulfate is <mathjax>#MgSO_4#</mathjax></p> <p>Hydrogen gas is diatomic: <mathjax>#H_2#</mathjax></p> <p><mathjax>#Mg + H_2SO_4->MgSO_4 +H_2#</mathjax></p> <p>The reaction is balanced as written. Each side has one magnesium atom, two hydrogen atoms and one sulfate ion.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you write a balanced chemical equation for the reaction of magnesium solid with sulfuric acid to form hydrogen gas and magnesium sulfate?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="358046" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/shell"><img alt="" class="" src="https://profilepictures.socratic.org/q2t1BRS9Wt3Cxp4yEU4g_tumblrnflwc1gKKZ1qav3uso15002.gif" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/shell"> Shell </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-12-30T01:35:35" itemprop="dateCreated"> Dec 30, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Mg + H_2SO_4->MgSO_4 +H_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Magnesium combined with sulfuric acid produces magnesium sulfate and hydrogen gas.</p> <p>Reactants:</p> <p>The symbol for magnesium is <mathjax>#Mg#</mathjax>.</p> <p>The formula for sulfuric acid is <mathjax>#H_2SO_4#</mathjax></p> <p>Products:</p> <p>Magnesium forms a <mathjax>#2+#</mathjax> ion: <mathjax>#Mg^(2+)#</mathjax></p> <p>The sulfate ion has a charge of <mathjax>#2-#</mathjax>: <mathjax>#SO_4^(2-)#</mathjax></p> <p>The charges balance and thus the formula for <br/> magnesum sulfate is <mathjax>#MgSO_4#</mathjax></p> <p>Hydrogen gas is diatomic: <mathjax>#H_2#</mathjax></p> <p><mathjax>#Mg + H_2SO_4->MgSO_4 +H_2#</mathjax></p> <p>The reaction is balanced as written. Each side has one magnesium atom, two hydrogen atoms and one sulfate ion.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/358046" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------> H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -> Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? 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Sodium phosphate and calcium chloride react to form... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-equation-kclo3-kcl-o2"> How can I balance this equation? ____ #KClO_3 -># ____ #KCl +# ____ #O_2# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-balancing-chemical-equations-important"> Why is balancing chemical equations important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/balancing-chemical-equations"> See all questions in Balancing Chemical Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 91630 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How do you write a balanced chemical equation for the reaction of magnesium solid with sulfuric acid to form hydrogen gas and magnesium sulfate?	null
1,042	ac7ff400-6ddd-11ea-bf1f-ccda262736ce	https://socratic.org/questions/how-many-hydroxide-ions-are-needed-to-completely-neutralize-1-0-liter-of-0-50-m-	3.01 × 10^21	start physical_unit 2 3 number none qc_end physical_unit 14 14 12 13 molarity qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Number [OF] hydroxide ions"}]	[{"type":"physical unit","value":"3.01 × 10^21"}]	[{"type":"physical unit","value":"Volume [OF] HCl solution [=] \\pu{1.0 liter}"},{"type":"physical unit","value":"Molarity [OF] HCl solution [=] \\pu{0.50 M}"},{"type":"other","value":"Completely neutralize."}]	<h1 class="questionTitle" itemprop="name">How many hydroxide ions are needed to completely neutralize 1.0 liter of 0.50 M HCl?</h1>	null	3.01 × 10^21	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that the hydronium cations, <mathjax>#"H"_3"O"^(+)#</mathjax>, and the hydroxide anions, <mathjax>#"OH"^(-)#</mathjax>, react in a <mathjax>#1:1#</mathjax> <strong>mole ratio</strong> to reform water. </p> <p>In other words, it takes <mathjax>#1#</mathjax> <strong>mole</strong> of hydroxide anions to completely neutralize <mathjax>#1#</mathjax> <strong>mole</strong> of hydronium cations. Consequently, you can say that it takes <mathjax>#1#</mathjax> hydroxide anion to completely neutralize <mathjax>#1#</mathjax> hydronium cation. </p> <p><img alt="http://www.middleschoolchemistry.com/lessonplans/chapter6/lesson8" src="https://useruploads.socratic.org/O5MbtpX0RDaiK2OB3MPZ_water_molecules_reform.jpg"/> </p> <p>Now, you know that you're dealing with <mathjax>#"1.0 L"#</mathjax> of a <mathjax>#"0.50-M"#</mathjax> hydrochloric acid solution, so right from the start, you know that the solution contains <mathjax>#0.50#</mathjax> <strong>moles</strong> of hydrochloric acid <mathjax>#->#</mathjax> think about what <em><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></em> represents.</p> <p>Since hydrochloric acid is a <strong>strong acid</strong>, it will ionize completely in aqueous solution to produce hydronium cations</p> <blockquote> <p><mathjax>#"HCl"_ ((aq)) + "H"_ 2"O"_ ((l)) -> "H"_ 3"O"_ ((aq))^(+) + "Cl"_ ((aq))^(-)#</mathjax></p> </blockquote> <p>This means that your solution contains <mathjax>#0.50#</mathjax> <strong>moles</strong> of hydronium cations.</p> <p>As a result, you can say that you will need <mathjax>#0.50#</mathjax> <strong>moles</strong> of hydroxide anions to completely neutralize the number of moles of hydronium cations present in your sample. </p> <p>Now, to convert this to the <em>number of anions</em>, you need to use <strong>Avogadro's constant</strong>, which tells you that in order to have <mathjax>#1#</mathjax> <strong>mole</strong> of hydroxide anions you need to have <mathjax>#6.022 * 10^(23)#</mathjax> individual anions. </p> <p>Therefore, you will need</p> <blockquote> <p><mathjax>#0.50 color(red)(cancel(color(black)("moles OH"^(-)))) * (6.022 * 10^(23)color(white)(.)"OH"^(-)"anions")/(1color(red)(cancel(color(black)("mole OH"^(-))))) = color(darkgreen)(ul(color(black)(3.0 * 10^(23)color(white)(.)"OH"^(-)"anions"#</mathjax></p> </blockquote> <p>to completely neutralize <mathjax>#"1.0 L"#</mathjax> of <mathjax>#"0.50-M"#</mathjax> hydrochloric acid solution. </p> <p>The answer is rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#3.0 * 10^(23)#</mathjax> <mathjax>#"OH"^(-) "anions"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that the hydronium cations, <mathjax>#"H"_3"O"^(+)#</mathjax>, and the hydroxide anions, <mathjax>#"OH"^(-)#</mathjax>, react in a <mathjax>#1:1#</mathjax> <strong>mole ratio</strong> to reform water. </p> <p>In other words, it takes <mathjax>#1#</mathjax> <strong>mole</strong> of hydroxide anions to completely neutralize <mathjax>#1#</mathjax> <strong>mole</strong> of hydronium cations. Consequently, you can say that it takes <mathjax>#1#</mathjax> hydroxide anion to completely neutralize <mathjax>#1#</mathjax> hydronium cation. </p> <p><img alt="http://www.middleschoolchemistry.com/lessonplans/chapter6/lesson8" src="https://useruploads.socratic.org/O5MbtpX0RDaiK2OB3MPZ_water_molecules_reform.jpg"/> </p> <p>Now, you know that you're dealing with <mathjax>#"1.0 L"#</mathjax> of a <mathjax>#"0.50-M"#</mathjax> hydrochloric acid solution, so right from the start, you know that the solution contains <mathjax>#0.50#</mathjax> <strong>moles</strong> of hydrochloric acid <mathjax>#->#</mathjax> think about what <em><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></em> represents.</p> <p>Since hydrochloric acid is a <strong>strong acid</strong>, it will ionize completely in aqueous solution to produce hydronium cations</p> <blockquote> <p><mathjax>#"HCl"_ ((aq)) + "H"_ 2"O"_ ((l)) -> "H"_ 3"O"_ ((aq))^(+) + "Cl"_ ((aq))^(-)#</mathjax></p> </blockquote> <p>This means that your solution contains <mathjax>#0.50#</mathjax> <strong>moles</strong> of hydronium cations.</p> <p>As a result, you can say that you will need <mathjax>#0.50#</mathjax> <strong>moles</strong> of hydroxide anions to completely neutralize the number of moles of hydronium cations present in your sample. </p> <p>Now, to convert this to the <em>number of anions</em>, you need to use <strong>Avogadro's constant</strong>, which tells you that in order to have <mathjax>#1#</mathjax> <strong>mole</strong> of hydroxide anions you need to have <mathjax>#6.022 * 10^(23)#</mathjax> individual anions. </p> <p>Therefore, you will need</p> <blockquote> <p><mathjax>#0.50 color(red)(cancel(color(black)("moles OH"^(-)))) * (6.022 * 10^(23)color(white)(.)"OH"^(-)"anions")/(1color(red)(cancel(color(black)("mole OH"^(-))))) = color(darkgreen)(ul(color(black)(3.0 * 10^(23)color(white)(.)"OH"^(-)"anions"#</mathjax></p> </blockquote> <p>to completely neutralize <mathjax>#"1.0 L"#</mathjax> of <mathjax>#"0.50-M"#</mathjax> hydrochloric acid solution. </p> <p>The answer is rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many hydroxide ions are needed to completely neutralize 1.0 liter of 0.50 M HCl?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#reactions-in-solution" itemprop="url"> <span class="breadcrumb" itemprop="title">Reactions in Solution</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/reactions-in-solution/neutralization" itemprop="url"> <span class="breadcrumb" itemprop="title">Neutralization</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="446229" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-30T12:12:42" itemprop="dateCreated"> Jun 30, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#3.0 * 10^(23)#</mathjax> <mathjax>#"OH"^(-) "anions"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that the hydronium cations, <mathjax>#"H"_3"O"^(+)#</mathjax>, and the hydroxide anions, <mathjax>#"OH"^(-)#</mathjax>, react in a <mathjax>#1:1#</mathjax> <strong>mole ratio</strong> to reform water. </p> <p>In other words, it takes <mathjax>#1#</mathjax> <strong>mole</strong> of hydroxide anions to completely neutralize <mathjax>#1#</mathjax> <strong>mole</strong> of hydronium cations. Consequently, you can say that it takes <mathjax>#1#</mathjax> hydroxide anion to completely neutralize <mathjax>#1#</mathjax> hydronium cation. </p> <p><img alt="http://www.middleschoolchemistry.com/lessonplans/chapter6/lesson8" src="https://useruploads.socratic.org/O5MbtpX0RDaiK2OB3MPZ_water_molecules_reform.jpg"/> </p> <p>Now, you know that you're dealing with <mathjax>#"1.0 L"#</mathjax> of a <mathjax>#"0.50-M"#</mathjax> hydrochloric acid solution, so right from the start, you know that the solution contains <mathjax>#0.50#</mathjax> <strong>moles</strong> of hydrochloric acid <mathjax>#->#</mathjax> think about what <em><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></em> represents.</p> <p>Since hydrochloric acid is a <strong>strong acid</strong>, it will ionize completely in aqueous solution to produce hydronium cations</p> <blockquote> <p><mathjax>#"HCl"_ ((aq)) + "H"_ 2"O"_ ((l)) -> "H"_ 3"O"_ ((aq))^(+) + "Cl"_ ((aq))^(-)#</mathjax></p> </blockquote> <p>This means that your solution contains <mathjax>#0.50#</mathjax> <strong>moles</strong> of hydronium cations.</p> <p>As a result, you can say that you will need <mathjax>#0.50#</mathjax> <strong>moles</strong> of hydroxide anions to completely neutralize the number of moles of hydronium cations present in your sample. </p> <p>Now, to convert this to the <em>number of anions</em>, you need to use <strong>Avogadro's constant</strong>, which tells you that in order to have <mathjax>#1#</mathjax> <strong>mole</strong> of hydroxide anions you need to have <mathjax>#6.022 * 10^(23)#</mathjax> individual anions. </p> <p>Therefore, you will need</p> <blockquote> <p><mathjax>#0.50 color(red)(cancel(color(black)("moles OH"^(-)))) * (6.022 * 10^(23)color(white)(.)"OH"^(-)"anions")/(1color(red)(cancel(color(black)("mole OH"^(-))))) = color(darkgreen)(ul(color(black)(3.0 * 10^(23)color(white)(.)"OH"^(-)"anions"#</mathjax></p> </blockquote> <p>to completely neutralize <mathjax>#"1.0 L"#</mathjax> of <mathjax>#"0.50-M"#</mathjax> hydrochloric acid solution. </p> <p>The answer is rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/446229" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-neutralization-reactions-useful"> How are neutralization reactions useful? 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1,043	ac0eb494-6ddd-11ea-9bce-ccda262736ce	https://socratic.org/questions/58f9902111ef6b1009be55b5	9	start physical_unit 18 18 ph none qc_end physical_unit 1 1 10 10 kb qc_end physical_unit 1 1 16 17 molarity qc_end end	[{"type":"physical unit","value":"pH [OF] HONH2 solution"}]	[{"type":"physical unit","value":"9"}]	[{"type":"physical unit","value":"Kb [OF] HONH2 [=] \\pu{10^(-8)}"},{"type":"physical unit","value":"Molarity [OF] HONH2 solution [=] \\pu{0.024 mol/L}"}]	<h1 class="questionTitle" itemprop="name">#"Hydroxylamine"#, #HONH_2# is a weak Bronsted base with #K_b=10^-8#. What is #pH# for a #0.024molL^-1# solution?</h1>	null	9	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#HONH_2(aq) + H_2O(l) rightleftharpoonsHONH_3^+ + HO^-#</mathjax></p> <p>And then we write the equilibrium expression:</p> <p><mathjax>#K_b=10^-8=([HONH_3^+][HO^-])/([HONH_2])#</mathjax>,</p> <p>And we make the usual approximations, and invoke <mathjax>#x#</mathjax> as the moles of hydroxylamine that associate,</p> <p><mathjax>#K_b=x^2/(0.024-x)#</mathjax></p> <p>And if <mathjax>#"0.024>>>"x#</mathjax>, then <mathjax>#x~=sqrt(K_bxx0.024)#</mathjax></p> <p>i.e. <mathjax>#x~=sqrt(10^-8xx0.024)#</mathjax></p> <p><mathjax>#x_1=1.55xx10^-5molL^-1#</mathjax>, which is indeed small compared to <mathjax>#0.024#</mathjax>, but let us recycle that value back into the equation......</p> <p><mathjax>#x_2=1.55xx10^-5molL^-1#</mathjax>, </p> <p>So, from the equilibrium expression, we now know <mathjax>#x=[HO^-]=1.55xx10^-5molL^-1#</mathjax>.</p> <p>How does this help us, as we were asked to measure <mathjax>#pH#</mathjax>?</p> <p>Well in aqueous solution under standard condtions, <mathjax>#pH+pOH=14#</mathjax>, thus <mathjax>#pH=14-pOH=14+log_10{1.55xx10^-5}~=9#</mathjax>. This is slightly basic, as we would expect for a weak Bronsted base. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We need the stoichiometric equation............and get <mathjax>#pH~=9.#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#HONH_2(aq) + H_2O(l) rightleftharpoonsHONH_3^+ + HO^-#</mathjax></p> <p>And then we write the equilibrium expression:</p> <p><mathjax>#K_b=10^-8=([HONH_3^+][HO^-])/([HONH_2])#</mathjax>,</p> <p>And we make the usual approximations, and invoke <mathjax>#x#</mathjax> as the moles of hydroxylamine that associate,</p> <p><mathjax>#K_b=x^2/(0.024-x)#</mathjax></p> <p>And if <mathjax>#"0.024>>>"x#</mathjax>, then <mathjax>#x~=sqrt(K_bxx0.024)#</mathjax></p> <p>i.e. <mathjax>#x~=sqrt(10^-8xx0.024)#</mathjax></p> <p><mathjax>#x_1=1.55xx10^-5molL^-1#</mathjax>, which is indeed small compared to <mathjax>#0.024#</mathjax>, but let us recycle that value back into the equation......</p> <p><mathjax>#x_2=1.55xx10^-5molL^-1#</mathjax>, </p> <p>So, from the equilibrium expression, we now know <mathjax>#x=[HO^-]=1.55xx10^-5molL^-1#</mathjax>.</p> <p>How does this help us, as we were asked to measure <mathjax>#pH#</mathjax>?</p> <p>Well in aqueous solution under standard condtions, <mathjax>#pH+pOH=14#</mathjax>, thus <mathjax>#pH=14-pOH=14+log_10{1.55xx10^-5}~=9#</mathjax>. This is slightly basic, as we would expect for a weak Bronsted base. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">#"Hydroxylamine"#, #HONH_2# is a weak Bronsted base with #K_b=10^-8#. What is #pH# for a #0.024molL^-1# solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/ph-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">pH calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="410309" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-21T05:09:11" itemprop="dateCreated"> Apr 21, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We need the stoichiometric equation............and get <mathjax>#pH~=9.#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#HONH_2(aq) + H_2O(l) rightleftharpoonsHONH_3^+ + HO^-#</mathjax></p> <p>And then we write the equilibrium expression:</p> <p><mathjax>#K_b=10^-8=([HONH_3^+][HO^-])/([HONH_2])#</mathjax>,</p> <p>And we make the usual approximations, and invoke <mathjax>#x#</mathjax> as the moles of hydroxylamine that associate,</p> <p><mathjax>#K_b=x^2/(0.024-x)#</mathjax></p> <p>And if <mathjax>#"0.024>>>"x#</mathjax>, then <mathjax>#x~=sqrt(K_bxx0.024)#</mathjax></p> <p>i.e. <mathjax>#x~=sqrt(10^-8xx0.024)#</mathjax></p> <p><mathjax>#x_1=1.55xx10^-5molL^-1#</mathjax>, which is indeed small compared to <mathjax>#0.024#</mathjax>, but let us recycle that value back into the equation......</p> <p><mathjax>#x_2=1.55xx10^-5molL^-1#</mathjax>, </p> <p>So, from the equilibrium expression, we now know <mathjax>#x=[HO^-]=1.55xx10^-5molL^-1#</mathjax>.</p> <p>How does this help us, as we were asked to measure <mathjax>#pH#</mathjax>?</p> <p>Well in aqueous solution under standard condtions, <mathjax>#pH+pOH=14#</mathjax>, thus <mathjax>#pH=14-pOH=14+log_10{1.55xx10^-5}~=9#</mathjax>. This is slightly basic, as we would expect for a weak Bronsted base. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/410309" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-of-a-solution"> How do you determine ph of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-at-an-equivalence-point"> How do you determine pH at an equivalence point? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-molarity"> How do you determine pH from molarity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-alkalinity-mean"> What does alkalinity mean? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-base"> What is a base? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-acid-base-indicators-change-color"> How do acid base indicators change color? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-neutral-ph"> What is a neutral pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-alkalinity-affect-pool-water"> How does alkalinity affect pool water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ph-important-in-drinking-water"> Why is pH important in drinking water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-ph-of-solution"> How can I calculate the pH of a solution? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/ph-calculations"> See all questions in pH calculations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2209 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	#"Hydroxylamine"#, #HONH_2# is a weak Bronsted base with #K_b=10^-8#. What is #pH# for a #0.024molL^-1# solution?	null
1,044	acdf674c-6ddd-11ea-ba40-ccda262736ce	https://socratic.org/questions/how-many-moles-of-carbon-are-produced-when-1745-g-of-glucose-decomposes	58.14 moles	start physical_unit 4 4 mole mol qc_end physical_unit 11 11 8 9 mass qc_end end	[{"type":"physical unit","value":"Mole [OF] carbon [IN] moles"}]	[{"type":"physical unit","value":"58.14 moles"}]	[{"type":"physical unit","value":"Mass [OF] glucose [=] \\pu{1745 g}"}]	<h1 class="questionTitle" itemprop="name">How many moles of carbon are produced when 1745 g of glucose decomposes?</h1>	null	58.14 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Moles of carbon"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#6xx"moles of glucose"#</mathjax></p> <p><mathjax>#"Moles of glucose"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(1745g)/(180.16gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#9.69mol#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#9.69molxx6#</mathjax> <mathjax>#~=#</mathjax> <mathjax>#"60 moles of carbon"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Moles of carbon"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#6xx"moles of glucose"#</mathjax></p> <p><mathjax>#"Moles of glucose"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(1745g)/(180.16gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#9.69*mol#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles of carbon are produced when 1745 g of glucose decomposes?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="281604" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-26T18:08:12" itemprop="dateCreated"> Jun 26, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#9.69molxx6#</mathjax> <mathjax>#~=#</mathjax> <mathjax>#"60 moles of carbon"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Moles of carbon"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#6xx"moles of glucose"#</mathjax></p> <p><mathjax>#"Moles of glucose"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(1745g)/(180.16gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#9.69*mol#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/281604" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? 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1,045	ac03da24-6ddd-11ea-85d4-ccda262736ce	https://socratic.org/questions/what-is-the-equation-for-sodium-and-chlorine-react-to-form-sodium-chloride	2 Na + Cl2 -> 2 NaCl	start chemical_equation qc_end substance 5 5 qc_end substance 7 7 qc_end substance 11 12 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the equation"}]	[{"type":"chemical equation","value":"2 Na + Cl2 -> 2 NaCl"}]	[{"type":"substance name","value":"Sodium"},{"type":"substance name","value":"Chlorine"},{"type":"substance name","value":"Sodium chloride"}]	<h1 class="questionTitle" itemprop="name">What is the equation for sodium and chlorine react to form sodium chloride?</h1>	null	2 Na + Cl2 -> 2 NaCl	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The skeletal equation: <mathjax>#Na + Cl_2 -> NaCl #</mathjax></p> <p>Balanced: <mathjax>#2Na + Cl_2 -> 2NaCl #</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2Na + Cl_2 -> 2NaCl #</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The skeletal equation: <mathjax>#Na + Cl_2 -> NaCl #</mathjax></p> <p>Balanced: <mathjax>#2Na + Cl_2 -> 2NaCl #</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the equation for sodium and chlorine react to form sodium chloride?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="391216" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/marfre"><img alt="" class="" src="https://profilepictures.socratic.org/48J0XLK1To2NunsG33ct_11.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/marfre"> marfre </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-14T17:00:06" itemprop="dateCreated"> Mar 14, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2Na + Cl_2 -> 2NaCl #</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The skeletal equation: <mathjax>#Na + Cl_2 -> NaCl #</mathjax></p> <p>Balanced: <mathjax>#2Na + Cl_2 -> 2NaCl #</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/391216" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-equation-for-photosynthesis"> What is the chemical equation for photosynthesis? 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1,046	ab26a25d-6ddd-11ea-ae49-ccda262736ce	https://socratic.org/questions/592abb54b72cff02441670bf	+2	start physical_unit 6 7 oxidation_number none qc_end chemical_equation 9 9 qc_end end	[{"type":"physical unit","value":"Oxidation number [OF] the metal"}]	[{"type":"physical unit","value":"+2"}]	[{"type":"chemical equation","value":"GaCl2"}]	<h1 class="questionTitle" itemprop="name">What is the oxidation number of the metal in #GaCl_2#?</h1>	null	+2	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Net Oxidation State of a molecule should be zero.</p> <p>So, </p> <p><mathjax>#(Ga) + 2(Cl) = 0#</mathjax></p> <p>In Chloride Ion Form, Cl has a charge of -1.</p> <p>So Oxidation State of Chloride is -1.</p> <p>Let The Oxidation State of Gallium be x.</p> <p>So,</p> <p><mathjax>#[(x * 1) + {2 * (-1)}] = 0#</mathjax><br/> <mathjax>#rArr x - 2 = 0#</mathjax><br/> <mathjax>#rArr x = 2#</mathjax></p> <p>Hence explained the answer.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>+2</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Net Oxidation State of a molecule should be zero.</p> <p>So, </p> <p><mathjax>#(Ga) + 2(Cl) = 0#</mathjax></p> <p>In Chloride Ion Form, Cl has a charge of -1.</p> <p>So Oxidation State of Chloride is -1.</p> <p>Let The Oxidation State of Gallium be x.</p> <p>So,</p> <p><mathjax>#[(x * 1) + {2 * (-1)}] = 0#</mathjax><br/> <mathjax>#rArr x - 2 = 0#</mathjax><br/> <mathjax>#rArr x = 2#</mathjax></p> <p>Hence explained the answer.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the oxidation number of the metal in #GaCl_2#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#electrochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Electrochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/electrochemistry/oxidation-numbers" itemprop="url"> <span class="breadcrumb" itemprop="title">Oxidation Numbers</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="430935" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/soumalya-p"><img alt="" class="" src="https://profilepictures.socratic.org/y3rdUVmLSqqZYNQNXYxx_IMG_20180224_134054.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/soumalya-p"> Soumalya Pramanik </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-28T12:19:36" itemprop="dateCreated"> May 28, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>+2</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Net Oxidation State of a molecule should be zero.</p> <p>So, </p> <p><mathjax>#(Ga) + 2(Cl) = 0#</mathjax></p> <p>In Chloride Ion Form, Cl has a charge of -1.</p> <p>So Oxidation State of Chloride is -1.</p> <p>Let The Oxidation State of Gallium be x.</p> <p>So,</p> <p><mathjax>#[(x * 1) + {2 * (-1)}] = 0#</mathjax><br/> <mathjax>#rArr x - 2 = 0#</mathjax><br/> <mathjax>#rArr x = 2#</mathjax></p> <p>Hence explained the answer.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/430935" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="430938" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-28T12:23:59" itemprop="dateCreated"> May 28, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>This is clearly <mathjax>#stackrel(II+)"Ga"..........#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Oxidation state/number is the charge left on the central atom, when all the other bound atoms are removed, with the charge devolving to the most electronegative atom........</p> <p>Do this for <mathjax>#GaCl_2#</mathjax>, and we get <mathjax>#Ga^(2+) +2xxCl^-#</mathjax>. This is not a typical oxidation state for a Group 13 atom; it may be a mixed valence species of <mathjax>#GaCl#</mathjax>, and <mathjax>#GaCl_3#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/430938" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-relate-to-electron-configuration"> How do oxidation numbers relate to electron configuration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-relate-to-valence-electrons"> How do oxidation numbers relate to valence electrons? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-vary-with-the-periodic-table"> How do oxidation numbers vary with the periodic table? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-oxidation-number-of-an-element-in-a-compound"> How do you calculate the oxidation number of an element in a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-sulfur"> What is the oxidation number for sulfur? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-carbon"> What is the oxidation number for carbon? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-copper"> What is the oxidation number for copper? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-nitrogen"> What is the oxidation number for nitrogen? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-oxygen"> What is the oxidation number for oxygen? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-oxidation-state-of-noble-gas-zero"> Why is the oxidation state of noble gas zero? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/electrochemistry/oxidation-numbers"> See all questions in Oxidation Numbers </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2287 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the oxidation number of the metal in #GaCl_2#?	null
1,047	a8501837-6ddd-11ea-84e7-ccda262736ce	https://socratic.org/questions/the-ph-of-a-solution-is-8-7-what-is-the-poh	5.3	start physical_unit 4 4 poh none qc_end physical_unit 4 4 6 6 ph qc_end end	[{"type":"physical unit","value":"pOH [OF] the solution"}]	[{"type":"physical unit","value":"5.3"}]	[{"type":"physical unit","value":"pH [OF] solution [=] \\pu{8.7}"}]	<h1 class="questionTitle" itemprop="name">The pH of a solution is 8.7, what is the pOH? </h1>	null	5.3	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You can answer this question in one of two ways:</p> <ul> <li>Take the anti-log of the <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> to obtain the concentration of <mathjax>#H^+#</mathjax> ions in solution. After that, use the self-ionization of water formula:<br/> <img alt="study.com" src="https://useruploads.socratic.org/CZnAmLtpR46DAFc4TJb3_self-ionization-constant.jpg"/> </li> </ul> <p>Where <mathjax>#K_w#</mathjax> has a value of <mathjax>#1.0xx10^-14#</mathjax> Then you can rearrange the equation to solve for [<mathjax>#OH^-#</mathjax>]. Take the -log of that value to obtain the pOH. </p> <ul> <li>Subtract the pH from 14 to obtain the pOH.</li> </ul> <p>I'll show you both ways using these equations:</p> <p><img alt="www.slideshare.net" src="https://useruploads.socratic.org/rNa9WIGDROW29kZDA5cl_ph-scale-20-638.jpg"/> </p> <p><strong>THE PROCESS FOR METHOD 1:</strong></p> <p><mathjax>#[H^+]= 10^(-8.7) = 1.995xx10^-9 M#</mathjax><br/> <mathjax>#K_w = ["H"_3"O"^(+)]["OH"^(-)] = 1.0xx10^(-14)#</mathjax></p> <p><strong>Kw / [H+] = [OH-]</strong></p> <p><mathjax>#(1.0xx10^(-14))/(1.995xx10^(-9) "M") = 5.01xx10^(-6)"#</mathjax><br/> <mathjax>#[OH^(-)] = 5.01xx10^(-6)M#</mathjax><br/> <mathjax>#pOH = -log(5.01xx10^(-6))M#</mathjax><br/> <mathjax>#pOH = 5.3 #</mathjax></p> <p><strong>THE PROCESS FOR METHOD 2:</strong></p> <p><mathjax>#14-8.7 = 5.3#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><strong>pOH = 5.3</strong></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You can answer this question in one of two ways:</p> <ul> <li>Take the anti-log of the <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> to obtain the concentration of <mathjax>#H^+#</mathjax> ions in solution. After that, use the self-ionization of water formula:<br/> <img alt="study.com" src="https://useruploads.socratic.org/CZnAmLtpR46DAFc4TJb3_self-ionization-constant.jpg"/> </li> </ul> <p>Where <mathjax>#K_w#</mathjax> has a value of <mathjax>#1.0xx10^-14#</mathjax> Then you can rearrange the equation to solve for [<mathjax>#OH^-#</mathjax>]. Take the -log of that value to obtain the pOH. </p> <ul> <li>Subtract the pH from 14 to obtain the pOH.</li> </ul> <p>I'll show you both ways using these equations:</p> <p><img alt="www.slideshare.net" src="https://useruploads.socratic.org/rNa9WIGDROW29kZDA5cl_ph-scale-20-638.jpg"/> </p> <p><strong>THE PROCESS FOR METHOD 1:</strong></p> <p><mathjax>#[H^+]= 10^(-8.7) = 1.995xx10^-9 M#</mathjax><br/> <mathjax>#K_w = ["H"_3"O"^(+)]["OH"^(-)] = 1.0xx10^(-14)#</mathjax></p> <p><strong>Kw / [H+] = [OH-]</strong></p> <p><mathjax>#(1.0xx10^(-14))/(1.995xx10^(-9) "M") = 5.01xx10^(-6)"#</mathjax><br/> <mathjax>#[OH^(-)] = 5.01xx10^(-6)M#</mathjax><br/> <mathjax>#pOH = -log(5.01xx10^(-6))M#</mathjax><br/> <mathjax>#pOH = 5.3 #</mathjax></p> <p><strong>THE PROCESS FOR METHOD 2:</strong></p> <p><mathjax>#14-8.7 = 5.3#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">The pH of a solution is 8.7, what is the pOH? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/the-ph-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">pH</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="284811" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/kayla-14"><img alt="" class="" src="https://profilepictures.socratic.org/OvMTWaamQPWcqLIkUNnG_793604964071127.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/kayla-14"> Kayla </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-05T01:37:11" itemprop="dateCreated"> Jul 5, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><strong>pOH = 5.3</strong></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You can answer this question in one of two ways:</p> <ul> <li>Take the anti-log of the <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> to obtain the concentration of <mathjax>#H^+#</mathjax> ions in solution. After that, use the self-ionization of water formula:<br/> <img alt="study.com" src="https://useruploads.socratic.org/CZnAmLtpR46DAFc4TJb3_self-ionization-constant.jpg"/> </li> </ul> <p>Where <mathjax>#K_w#</mathjax> has a value of <mathjax>#1.0xx10^-14#</mathjax> Then you can rearrange the equation to solve for [<mathjax>#OH^-#</mathjax>]. Take the -log of that value to obtain the pOH. </p> <ul> <li>Subtract the pH from 14 to obtain the pOH.</li> </ul> <p>I'll show you both ways using these equations:</p> <p><img alt="www.slideshare.net" src="https://useruploads.socratic.org/rNa9WIGDROW29kZDA5cl_ph-scale-20-638.jpg"/> </p> <p><strong>THE PROCESS FOR METHOD 1:</strong></p> <p><mathjax>#[H^+]= 10^(-8.7) = 1.995xx10^-9 M#</mathjax><br/> <mathjax>#K_w = ["H"_3"O"^(+)]["OH"^(-)] = 1.0xx10^(-14)#</mathjax></p> <p><strong>Kw / [H+] = [OH-]</strong></p> <p><mathjax>#(1.0xx10^(-14))/(1.995xx10^(-9) "M") = 5.01xx10^(-6)"#</mathjax><br/> <mathjax>#[OH^(-)] = 5.01xx10^(-6)M#</mathjax><br/> <mathjax>#pOH = -log(5.01xx10^(-6))M#</mathjax><br/> <mathjax>#pOH = 5.3 #</mathjax></p> <p><strong>THE PROCESS FOR METHOD 2:</strong></p> <p><mathjax>#14-8.7 = 5.3#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/284811" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-pka"> How do you determine pH from pKa? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-ph-values-of-acids-and-bases-differ"> How do pH values of acids and bases differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-something-on-a-ph-scale"> How do you calculate something on a pH scale? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-diprotic-acid"> How do you calculate pH diprotic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-from-acid-dissociation-constant"> How do you calculate pH from acid dissociation constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-of-acid-and-base-solution"> How do you calculate pH of acid and base solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ph-scale-0-14"> Why is the pH scale 0-14? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-ph-the-measure-of-the-hydrogen-ion-concentration"> Is pH a measure of the hydrogen ion concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-solubility-affect-ph"> How does solubility affect pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-ph-relate-to-pka-in-a-titration"> How does pH relate to pKa in a titration? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/the-ph-concept"> See all questions in pH </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 24783 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	The pH of a solution is 8.7, what is the pOH?	null
1,048	ac863642-6ddd-11ea-bd14-ccda262736ce	https://socratic.org/questions/5968bcf6b72cff2ed90b85f6	190.42 g	start physical_unit 11 11 mass g qc_end end	[{"type":"physical unit","value":"Mass [OF] MgCl2 [IN] g"}]	[{"type":"physical unit","value":"190.42 g"}]	[{"type":"physical unit","value":"Number [OF] MgCl2 formula units [=] \\pu{12.04 × 10^23}"}]	<h1 class="questionTitle" itemprop="name">What is the mass of #12.04xx10^23# #"formula units"# of #MgCl_2#?</h1>	null	190.42 g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Do we know this? All I have is taken the molar mass of magnesium chloride, and translated this into a NUMBER of magnesium chloride formula units...</p> <p>And here we gots <mathjax>#12.04xx10^23#</mathjax> <mathjax>#MgCl_2#</mathjax> formula units.........</p> <p>And thus we gots the product...........</p> <p><mathjax>#(12.04xx10^23"formula units")/(6.022xx10^23"formula units"mol^-1)xx95.21gmol^-1#</mathjax>....</p> <p>And I make this a mass of <mathjax>#190.42g#</mathjax>........do you agree?</p> <p>Is the product dimensionally consistent?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, we know that <mathjax>#6.022xx10^23#</mathjax> <mathjax>#MgCl_2#</mathjax> formula units have a mass of <mathjax>#95.21g#</mathjax>.......</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Do we know this? All I have is taken the molar mass of magnesium chloride, and translated this into a NUMBER of magnesium chloride formula units...</p> <p>And here we gots <mathjax>#12.04xx10^23#</mathjax> <mathjax>#MgCl_2#</mathjax> formula units.........</p> <p>And thus we gots the product...........</p> <p><mathjax>#(12.04xx10^23"formula units")/(6.022xx10^23"formula units"mol^-1)xx95.21gmol^-1#</mathjax>....</p> <p>And I make this a mass of <mathjax>#190.42*g#</mathjax>........do you agree?</p> <p>Is the product dimensionally consistent?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the mass of #12.04xx10^23# #"formula units"# of #MgCl_2#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="451423" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-07-14T15:25:56" itemprop="dateCreated"> Jul 14, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, we know that <mathjax>#6.022xx10^23#</mathjax> <mathjax>#MgCl_2#</mathjax> formula units have a mass of <mathjax>#95.21g#</mathjax>.......</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Do we know this? All I have is taken the molar mass of magnesium chloride, and translated this into a NUMBER of magnesium chloride formula units...</p> <p>And here we gots <mathjax>#12.04xx10^23#</mathjax> <mathjax>#MgCl_2#</mathjax> formula units.........</p> <p>And thus we gots the product...........</p> <p><mathjax>#(12.04xx10^23"formula units")/(6.022xx10^23"formula units"mol^-1)xx95.21gmol^-1#</mathjax>....</p> <p>And I make this a mass of <mathjax>#190.42*g#</mathjax>........do you agree?</p> <p>Is the product dimensionally consistent?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/451423" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1396 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the mass of #12.04xx10^23# #"formula units"# of #MgCl_2#?	null
1,049	a9428323-6ddd-11ea-9cb6-ccda262736ce	https://socratic.org/questions/557e128c581e2a2c4ddb0a43	0.03 M	start physical_unit 5 7 concentration mol/l qc_end physical_unit 5 7 9 10 volume qc_end physical_unit 19 21 14 15 volume qc_end physical_unit 19 21 17 18 concentration qc_end end	[{"type":"physical unit","value":"Concentration [OF] hydrochloric acid solution [IN] M"}]	[{"type":"physical unit","value":"0.03 M"}]	[{"type":"physical unit","value":"Volume [OF] hydrochloric acid solution [=] \\pu{6.68 ml}"},{"type":"physical unit","value":"Volume [OF] potassium hydroxide solution [=] \\pu{13.90 ml}"},{"type":"physical unit","value":"Concentration [OF] potassium hydroxide solution [=] \\pu{0.0161 M}"}]	<h1 class="questionTitle" itemprop="name">What is the concentration of hydrochloric acid solution if 6.68 ml is neutralised by 13.90 ml of 0.0161 M potassium hydroxide solution ?</h1>	null	0.03 M	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You're dealing with a <a href="http://socratic.org/chemistry/reactions-in-solution/neutralization">neutralization reaction</a> in which hydrochloric acid, a strong acid, reacts with potassium hydroxide, a strong base, to produce potassium chloride, a salt, and water. </p> <p>The balanced chemical equation looks like this </p> <p><mathjax>#HCl_((aq)) + KOH_((aq)) -> KCl_((aq)) + H_2O_((l))#</mathjax></p> <p>The important thing to notice here is that you have a <mathjax>#1:1#</mathjax> <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> between hydrochloric acid and potassium hydroxide. This means that, in order to get a <em>complete <a href="http://socratic.org/chemistry/reactions-in-solution/neutralization">neutralization</a></em>, you need <strong>equal numbers of moles</strong> of acid and of base. </p> <p>Since <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> is defined as moles of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> per <strong>liters</strong> of solution, you can use the volume and molarity of the potassium hydroxide solution to determine how many moles of base were needed</p> <p><mathjax>#C = n/V => n = C * V#</mathjax></p> <p><mathjax>#n_(KOH) = "0.0161 M" * 13.90 * 10^(-3)"L" = "0.0002238 moles"#</mathjax> <mathjax>#KOH#</mathjax></p> <p>This means that your hydrochloric acid solution contained </p> <p><mathjax>#n_(HCl) = n_(KOH) = "0.0002238 moles"#</mathjax> <mathjax>#HCl#</mathjax></p> <p>Now use the volume of the hydrochloric solution and the number of moles of <mathjax>#HCl#</mathjax> it contains to determine its molarity</p> <p><mathjax>#C_(HCl) = n_(HCl)/V_(HCl) = "0.0002238 moles"/(6.68 * 10^(-3)"L")= color(green)("0.0335 M")#</mathjax></p> <p>The answer is rounded to three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the number of sig figs you gave for the molarity of the potassium hydroxide solution. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of the hydrochloric acid solution was <strong>0.0335 M</strong>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You're dealing with a <a href="http://socratic.org/chemistry/reactions-in-solution/neutralization">neutralization reaction</a> in which hydrochloric acid, a strong acid, reacts with potassium hydroxide, a strong base, to produce potassium chloride, a salt, and water. </p> <p>The balanced chemical equation looks like this </p> <p><mathjax>#HCl_((aq)) + KOH_((aq)) -> KCl_((aq)) + H_2O_((l))#</mathjax></p> <p>The important thing to notice here is that you have a <mathjax>#1:1#</mathjax> <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> between hydrochloric acid and potassium hydroxide. This means that, in order to get a <em>complete <a href="http://socratic.org/chemistry/reactions-in-solution/neutralization">neutralization</a></em>, you need <strong>equal numbers of moles</strong> of acid and of base. </p> <p>Since <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> is defined as moles of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> per <strong>liters</strong> of solution, you can use the volume and molarity of the potassium hydroxide solution to determine how many moles of base were needed</p> <p><mathjax>#C = n/V => n = C * V#</mathjax></p> <p><mathjax>#n_(KOH) = "0.0161 M" * 13.90 * 10^(-3)"L" = "0.0002238 moles"#</mathjax> <mathjax>#KOH#</mathjax></p> <p>This means that your hydrochloric acid solution contained </p> <p><mathjax>#n_(HCl) = n_(KOH) = "0.0002238 moles"#</mathjax> <mathjax>#HCl#</mathjax></p> <p>Now use the volume of the hydrochloric solution and the number of moles of <mathjax>#HCl#</mathjax> it contains to determine its molarity</p> <p><mathjax>#C_(HCl) = n_(HCl)/V_(HCl) = "0.0002238 moles"/(6.68 * 10^(-3)"L")= color(green)("0.0335 M")#</mathjax></p> <p>The answer is rounded to three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the number of sig figs you gave for the molarity of the potassium hydroxide solution. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the concentration of hydrochloric acid solution if 6.68 ml is neutralised by 13.90 ml of 0.0161 M potassium hydroxide solution ?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="152888" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-06-14T23:59:06" itemprop="dateCreated"> Jun 14, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of the hydrochloric acid solution was <strong>0.0335 M</strong>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You're dealing with a <a href="http://socratic.org/chemistry/reactions-in-solution/neutralization">neutralization reaction</a> in which hydrochloric acid, a strong acid, reacts with potassium hydroxide, a strong base, to produce potassium chloride, a salt, and water. </p> <p>The balanced chemical equation looks like this </p> <p><mathjax>#HCl_((aq)) + KOH_((aq)) -> KCl_((aq)) + H_2O_((l))#</mathjax></p> <p>The important thing to notice here is that you have a <mathjax>#1:1#</mathjax> <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> between hydrochloric acid and potassium hydroxide. This means that, in order to get a <em>complete <a href="http://socratic.org/chemistry/reactions-in-solution/neutralization">neutralization</a></em>, you need <strong>equal numbers of moles</strong> of acid and of base. </p> <p>Since <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> is defined as moles of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> per <strong>liters</strong> of solution, you can use the volume and molarity of the potassium hydroxide solution to determine how many moles of base were needed</p> <p><mathjax>#C = n/V => n = C * V#</mathjax></p> <p><mathjax>#n_(KOH) = "0.0161 M" * 13.90 * 10^(-3)"L" = "0.0002238 moles"#</mathjax> <mathjax>#KOH#</mathjax></p> <p>This means that your hydrochloric acid solution contained </p> <p><mathjax>#n_(HCl) = n_(KOH) = "0.0002238 moles"#</mathjax> <mathjax>#HCl#</mathjax></p> <p>Now use the volume of the hydrochloric solution and the number of moles of <mathjax>#HCl#</mathjax> it contains to determine its molarity</p> <p><mathjax>#C_(HCl) = n_(HCl)/V_(HCl) = "0.0002238 moles"/(6.68 * 10^(-3)"L")= color(green)("0.0335 M")#</mathjax></p> <p>The answer is rounded to three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the number of sig figs you gave for the molarity of the potassium hydroxide solution. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/152888" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="152890" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/michael-2"><img alt="" class="" src="https://lh3.googleusercontent.com/-gCv6FQRhls0/AAAAAAAAAAI/AAAAAAAAAAA/AAnnY7oOJS05Ylqn3KuDSW0LfnbOk7FezQ/mo/photo.jpg?sz=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/michael-2"> Michael </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-06-15T00:10:10" itemprop="dateCreated"> Jun 15, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The concentration of HCl = <mathjax>#0.033"mol/l"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#HCl_((aq))+KOH_((aq))rarrKCl_((aq))+H_2O_((l))#</mathjax></p> <p><mathjax>#c=n/v#</mathjax></p> <p><mathjax>#n=cv#</mathjax></p> <p>So no. moles KOH = <mathjax>#(13.90xx0.0161)/(1000)=2.23xx10^(-4)#</mathjax></p> <p>From the equation we can see that they react in a molar ratio of 1:1.</p> <p>This means that the no. moles HCl must be the same:</p> <p><mathjax>#nHCl=2.23xx10^(-4)#</mathjax></p> <p>Since <mathjax>#c=n/v#</mathjax>:</p> <p><mathjax>#[HCl]= (2.23xx10^(-4))/(6.68xx10^(-3))=0.033"mol/l"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/152890" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? 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1,050	ab265446-6ddd-11ea-9790-ccda262736ce	https://socratic.org/questions/1-09-g-h-2-is-allowed-to-react-with-10-2-g-n-2-producing-1-12-g-nh-3-what-is-the	3.06 grams	start physical_unit 23 24 theoretical_yield g qc_end physical_unit 2 2 0 1 mass qc_end physical_unit 10 10 8 9 mass qc_end physical_unit 14 14 12 13 mass qc_end end	[{"type":"physical unit","value":"Theoretical yield [OF] this reaction [IN] grams"}]	[{"type":"physical unit","value":"3.06 grams"}]	[{"type":"physical unit","value":"Mass [OF] H2 [=] \\pu{1.09 g}"},{"type":"physical unit","value":"Mass [OF] N2 [=] \\pu{10.2 g}"},{"type":"physical unit","value":"Mass [OF] NH3 [=] \\pu{1.12 g}"}]	<h1 class="questionTitle" itemprop="name">1.09 g #H_2# is allowed to react with 10.2 g #N_2#, producing 1.12 g #NH_3#. What is the theoretical yield in grams for this reaction under the given conditions?</h1>	null	3.06 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We need a stoichiometric equation:</p> <p><mathjax>#1/2N_2(g) + 3/2H_2(g)rightleftharpoonsNH_3(g)#</mathjax></p> <p><mathjax>#"Moles of dinitrogen"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(10.2g)/(28.02gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.364mol#</mathjax>.</p> <p><mathjax>#"Moles of dihydrogen"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(1.09g)/(2.02gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.540mol#</mathjax>.</p> <p><mathjax>#"Moles of ammonia"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(1.12g)/(17.03gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.0658mol#</mathjax>.</p> <p>Clearly dihydrogen is the <a href="https://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a>, and at most we can make <mathjax>#2/3#</mathjax> equiv ammonia, i.e. </p> <p><mathjax>#"% yield"#</mathjax> <mathjax>#-=#</mathjax> <mathjax>#(0.0658mol)/(2/3xx0.540mol)xx100%=??%#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Less than <mathjax>#20%#</mathjax>..............</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We need a stoichiometric equation:</p> <p><mathjax>#1/2N_2(g) + 3/2H_2(g)rightleftharpoonsNH_3(g)#</mathjax></p> <p><mathjax>#"Moles of dinitrogen"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(10.2g)/(28.02gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.364mol#</mathjax>.</p> <p><mathjax>#"Moles of dihydrogen"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(1.09g)/(2.02gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.540mol#</mathjax>.</p> <p><mathjax>#"Moles of ammonia"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(1.12g)/(17.03gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.0658mol#</mathjax>.</p> <p>Clearly dihydrogen is the <a href="https://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a>, and at most we can make <mathjax>#2/3#</mathjax> equiv ammonia, i.e. </p> <p><mathjax>#"% yield"#</mathjax> <mathjax>#-=#</mathjax> <mathjax>#(0.0658mol)/(2/3xx0.540mol)xx100%=??%#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">1.09 g #H_2# is allowed to react with 10.2 g #N_2#, producing 1.12 g #NH_3#. What is the theoretical yield in grams for this reaction under the given conditions?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/percent-yield" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Yield</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="387758" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-07T06:48:22" itemprop="dateCreated"> Mar 7, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Less than <mathjax>#20%#</mathjax>..............</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We need a stoichiometric equation:</p> <p><mathjax>#1/2N_2(g) + 3/2H_2(g)rightleftharpoonsNH_3(g)#</mathjax></p> <p><mathjax>#"Moles of dinitrogen"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(10.2g)/(28.02gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.364mol#</mathjax>.</p> <p><mathjax>#"Moles of dihydrogen"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(1.09g)/(2.02gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.540mol#</mathjax>.</p> <p><mathjax>#"Moles of ammonia"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(1.12g)/(17.03gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.0658mol#</mathjax>.</p> <p>Clearly dihydrogen is the <a href="https://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a>, and at most we can make <mathjax>#2/3#</mathjax> equiv ammonia, i.e. </p> <p><mathjax>#"% yield"#</mathjax> <mathjax>#-=#</mathjax> <mathjax>#(0.0658mol)/(2/3xx0.540mol)xx100%=??%#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/387758" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ebd02bf3469570e2e62"> Question #e2e62 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ec502bf34694a4fee2e"> Question #fee2e </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ec902bf34694a4fee32"> Question #fee32 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ece02bf346950519e89"> Question #19e89 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ed302bf34694c8c5bdc"> Question #c5bdc </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ee302bf3469517a1065"> Question #a1065 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-would-be-the-limiting-reagent-if-26-0-grams-of-c3h9n-were-reacted-with-46-3"> What would be the limiting reagent if 26.0 grams of C3H9N were reacted with 46.3 grams of... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-percent-yield-always-less-than-100"> Is percent yield always less than 100? 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What is the theoretical yield in grams for this reaction under the given conditions?	null
1,051	a8941d58-6ddd-11ea-b9b6-ccda262736ce	https://socratic.org/questions/56e2679b11ef6b57649affee	10 moles	start physical_unit 4 5 mole mol qc_end physical_unit 15 15 11 12 mole qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Mole [OF] oxygen gas [IN] moles"}]	[{"type":"physical unit","value":"10 moles"}]	[{"type":"physical unit","value":"Mole [OF] acetylene [=] \\pu{4 mol}"},{"type":"other","value":"Combust completely."}]	<h1 class="questionTitle" itemprop="name">How many moles of oxygen gas are required to combust a #4*mol# quantity of acetylene completely?</h1>	null	10 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The balanced chemical equation is given. Each mole of acetylene requires two and a half moles of oxygen gas. So if 4 mol acetylene are combusted, some 10 moles of dioxygen are necessary.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#H-C-=C-H(g) + 5/2O_2(g) rarr 2CO_2(g) + H_2O(g)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The balanced chemical equation is given. Each mole of acetylene requires two and a half moles of oxygen gas. So if 4 mol acetylene are combusted, some 10 moles of dioxygen are necessary.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles of oxygen gas are required to combust a #4*mol# quantity of acetylene completely?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/stoichiometry-involving-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="238102" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-11T07:32:59" itemprop="dateCreated"> Mar 11, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#H-C-=C-H(g) + 5/2O_2(g) rarr 2CO_2(g) + H_2O(g)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The balanced chemical equation is given. Each mole of acetylene requires two and a half moles of oxygen gas. So if 4 mol acetylene are combusted, some 10 moles of dioxygen are necessary.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/238102" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="238104" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/jarni-renz"><img alt="" class="" src="https://profilepictures.socratic.org/i6OiZQmVRHWljDVlwm8v_WIN_20160301_180231.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/jarni-renz"> Jarni Renz </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-11T08:00:08" itemprop="dateCreated"> Mar 11, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#10#</mathjax> <mathjax># mol#</mathjax> <mathjax># O_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><ol> <li> <p>First thing to do is to balance the chemical equation; The balanced equation is:<br/> <mathjax>#2C_2H_2 + 5O_2 rarr 4CO_2 + 2H_2O#</mathjax></p> </li> <li> <p>Then use the coefficients, which represents the number of mol of its compound/molecules in said reaction, to get the number of mol of <mathjax>#O_2#</mathjax> molecules;</p> </li> <li>Multiply the mol of acetylene as provided in the problem (<mathjax>#4 mol C_2H_2#</mathjax>) with the convertion ratio of the moles of acetylene and oxygen molecules (<mathjax>#(5 mol O_2)/(2mol C_2H_2#</mathjax>)) based on the balanced equation;</li> <li>Make sure to cancel <a href="http://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> of <mathjax>#C_2H_2#</mathjax> and get your desired mole of <mathjax>#O_2#</mathjax> molecules. </li> <li>The answer per computation is 10 mol of <mathjax>#O_2#</mathjax>moleules</li> </ol></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/238104" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-apply-gas-stoichiometry"> How do you apply gas stoichiometry? 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</a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-2-00-g-mixture-of-na-and-ca-reat-with-water-1-164-l-hydrogen-was-produced-a"> When 2.00 g mixture of Na and Ca reat with water, 1.164 L hydrogen was produced at 300.0 K and... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/stoichiometry-involving-gases"> See all questions in Gas Stoichiometry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 7022 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many moles of oxygen gas are required to combust a #4*mol# quantity of acetylene completely?	null
1,052	ac999935-6ddd-11ea-bace-ccda262736ce	https://socratic.org/questions/how-many-moles-of-chlorine-gas-are-needed-to-make-0-6-moles-of-sodium-chloride-g	0.30 moles	start physical_unit 4 5 mole mol qc_end physical_unit 13 14 10 11 mole qc_end chemical_equation 18 24 qc_end end	[{"type":"physical unit","value":"Mole [OF] chlorine gas [IN] moles"}]	[{"type":"physical unit","value":"0.30 moles"}]	[{"type":"physical unit","value":"Mole [OF] sodium chloride [=] \\pu{0.6 moles}"},{"type":"chemical equation","value":"2 Na + Cl2 -> 2 NaCl"}]	<h1 class="questionTitle" itemprop="name">How many moles of chlorine gas are needed to make 0.6 moles of sodium chloride given the reaction: #2Na + Cl_2 -> 2NaCl#?</h1>	null	0.30 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>as, 1 mole of Cl<mathjax>#rarr#</mathjax>2 moles of NaCl<br/> so, 1 mole of NaCl<mathjax>#rarr 1/2#</mathjax>moles of Cl<br/> now, 0.6 mole NaCl<mathjax>#rarr1/20.6#</mathjax> moles of Cl<br/> i.e. =<mathjax>#1/20.6=0.5*0.6#</mathjax><br/> =<mathjax>#0.3#</mathjax> moles of Cl</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.3 moles of chlorine gas gives 0.6 moles of sodium chloride</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>as, 1 mole of Cl<mathjax>#rarr#</mathjax>2 moles of NaCl<br/> so, 1 mole of NaCl<mathjax>#rarr 1/2#</mathjax>moles of Cl<br/> now, 0.6 mole NaCl<mathjax>#rarr1/20.6#</mathjax> moles of Cl<br/> i.e. =<mathjax>#1/20.6=0.5*0.6#</mathjax><br/> =<mathjax>#0.3#</mathjax> moles of Cl</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles of chlorine gas are needed to make 0.6 moles of sodium chloride given the reaction: #2Na + Cl_2 -> 2NaCl#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/mole-ratios" itemprop="url"> <span class="breadcrumb" itemprop="title">Mole Ratios</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="590769" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/shubh"><img alt="" class="" src="https://profilepictures.socratic.org/flchW4lbTKknvGCb8hDc_IMG-20180318-WA0057.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/shubh"> Shubh </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-04-08T17:27:54" itemprop="dateCreated"> Apr 8, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.3 moles of chlorine gas gives 0.6 moles of sodium chloride</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>as, 1 mole of Cl<mathjax>#rarr#</mathjax>2 moles of NaCl<br/> so, 1 mole of NaCl<mathjax>#rarr 1/2#</mathjax>moles of Cl<br/> now, 0.6 mole NaCl<mathjax>#rarr1/20.6#</mathjax> moles of Cl<br/> i.e. =<mathjax>#1/20.6=0.5*0.6#</mathjax><br/> =<mathjax>#0.3#</mathjax> moles of Cl</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/590769" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4178e02bf3469517a106e"> Question #a106e </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4178e02bf3469570e2e86"> Question #e2e86 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" 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given the reaction: #2Na + Cl_2 -> 2NaCl#?	null
1,053	a867ea55-6ddd-11ea-b2b2-ccda262736ce	https://socratic.org/questions/what-mass-of-oxygen-is-required-to-react-with-150-0-g-of-benzene	460.8 g	start physical_unit 3 3 mass g qc_end physical_unit 12 12 9 10 mass qc_end c_other reaction qc_end end	[{"type":"physical unit","value":"mass [OF] oxygen [IN] g"}]	[{"type":"physical unit","value":"460.8 g"}]	[{"type":"physical unit","value":"mass [OF] benzene [=] \\pu{150.0 g}"},{"type":"other","value":"reaction"}]	<h1 class="questionTitle" itemprop="name">What mass of oxygen is required to react with 150.0 g of benzene? </h1>	null	460.8 g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The chemical formula for benzene is <mathjax>#"C"_6"H"_6"#</mathjax>. When benzene undergoes combustion, carbon dioxide and water are formed.</p> <p><strong>Balanced Equation</strong></p> <p><mathjax>#"2C"_6"H"_6 + "15O"_2"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"12CO"_2 + "6H"_2"O"#</mathjax></p> <p>The process for answering this question will be:</p> <p><mathjax>#color(blue)"given mass benzene"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(blue)"mol benzene"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(blue)"mol oxygen"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(blue)"mass oxygen"#</mathjax></p> <p>In order to do this, we will need the appropriate mole ratio from the balanced equation, and the molar masses of benzene and oxygen. </p> <p>We need <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio between benzene and oxygen from the balanced equation.</p> <p><strong>Mole Ratio Benzene: Oxygen</strong></p> <p><mathjax>#("2 mol C"_6"H"_6)/("15 mol O"_2")#</mathjax> and <mathjax>#("15 mol O"_2)/("2 mol C"_6"H"_6")#</mathjax></p> <p><strong>Molar Masses of Benzene and Oxygen</strong><br/> Multiply the subscript of each element by its molar mass, the atomic weight on <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a> in g/mol.</p> <p><mathjax>#"C"_6"H"_6":#</mathjax><mathjax>#(6xx12.011"g/mol C")+(6xx1.008"g/mol H")="78.114 g/mol C"_6"H"_6"#</mathjax></p> <p><mathjax>#"O"_2":#</mathjax><mathjax>#(2xx15.999"g/mol O")="31.998 g/mol O"_2"#</mathjax></p> <p><strong>Determine Moles Benzene</strong><br/> Multiply the <mathjax>#color(blue)"given mass"#</mathjax> of benzene by the reciprocal of its molar mass.</p> <p><mathjax>#150.0color(red)cancel(color(black)("g C"_6"H"_6))xx(1"mol C"_6"H"_6)/(78.114color(red)cancel(color(black)("g C"_6"H"_6)))="1.9203 mol C"_6"H"_6"#</mathjax></p> <p><strong>Determine Moles Oxygen Using the Mole Ratio</strong></p> <p><mathjax>#1.9203 color(red)cancel(color(black)("mol C"_6"H"_6))xx("15 mol O"_2)/(2 color(red)cancel(color(black)("mol C"_6"H"_6)))="14.402 mol O"_2"#</mathjax></p> <p><strong>Determine Mass Oxygen Using Molar Mass of Oxygen</strong><br/> Multiply mol oxygen by its molar mass.</p> <p><mathjax>#14.402color(red)cancel(color(black)("mol O"_2))xx(31.998"g O"_2)/(1color(red)cancel(color(black)("mol O"_2)))="460.8 g O"_2"#</mathjax> rounded to four <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>It will require <mathjax>#"460.8 g O"_2"#</mathjax> to react with <mathjax>#"150.0 g C"_6"H"_6"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The chemical formula for benzene is <mathjax>#"C"_6"H"_6"#</mathjax>. When benzene undergoes combustion, carbon dioxide and water are formed.</p> <p><strong>Balanced Equation</strong></p> <p><mathjax>#"2C"_6"H"_6 + "15O"_2"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"12CO"_2 + "6H"_2"O"#</mathjax></p> <p>The process for answering this question will be:</p> <p><mathjax>#color(blue)"given mass benzene"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(blue)"mol benzene"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(blue)"mol oxygen"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(blue)"mass oxygen"#</mathjax></p> <p>In order to do this, we will need the appropriate mole ratio from the balanced equation, and the molar masses of benzene and oxygen. </p> <p>We need <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio between benzene and oxygen from the balanced equation.</p> <p><strong>Mole Ratio Benzene: Oxygen</strong></p> <p><mathjax>#("2 mol C"_6"H"_6)/("15 mol O"_2")#</mathjax> and <mathjax>#("15 mol O"_2)/("2 mol C"_6"H"_6")#</mathjax></p> <p><strong>Molar Masses of Benzene and Oxygen</strong><br/> Multiply the subscript of each element by its molar mass, the atomic weight on <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a> in g/mol.</p> <p><mathjax>#"C"_6"H"_6":#</mathjax><mathjax>#(6xx12.011"g/mol C")+(6xx1.008"g/mol H")="78.114 g/mol C"_6"H"_6"#</mathjax></p> <p><mathjax>#"O"_2":#</mathjax><mathjax>#(2xx15.999"g/mol O")="31.998 g/mol O"_2"#</mathjax></p> <p><strong>Determine Moles Benzene</strong><br/> Multiply the <mathjax>#color(blue)"given mass"#</mathjax> of benzene by the reciprocal of its molar mass.</p> <p><mathjax>#150.0color(red)cancel(color(black)("g C"_6"H"_6))xx(1"mol C"_6"H"_6)/(78.114color(red)cancel(color(black)("g C"_6"H"_6)))="1.9203 mol C"_6"H"_6"#</mathjax></p> <p><strong>Determine Moles Oxygen Using the Mole Ratio</strong></p> <p><mathjax>#1.9203 color(red)cancel(color(black)("mol C"_6"H"_6))xx("15 mol O"_2)/(2 color(red)cancel(color(black)("mol C"_6"H"_6)))="14.402 mol O"_2"#</mathjax></p> <p><strong>Determine Mass Oxygen Using Molar Mass of Oxygen</strong><br/> Multiply mol oxygen by its molar mass.</p> <p><mathjax>#14.402color(red)cancel(color(black)("mol O"_2))xx(31.998"g O"_2)/(1color(red)cancel(color(black)("mol O"_2)))="460.8 g O"_2"#</mathjax> rounded to four <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What mass of oxygen is required to react with 150.0 g of benzene? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-reactions-and-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions and Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="409733" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-20T03:42:25" itemprop="dateCreated"> Apr 20, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>It will require <mathjax>#"460.8 g O"_2"#</mathjax> to react with <mathjax>#"150.0 g C"_6"H"_6"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The chemical formula for benzene is <mathjax>#"C"_6"H"_6"#</mathjax>. When benzene undergoes combustion, carbon dioxide and water are formed.</p> <p><strong>Balanced Equation</strong></p> <p><mathjax>#"2C"_6"H"_6 + "15O"_2"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"12CO"_2 + "6H"_2"O"#</mathjax></p> <p>The process for answering this question will be:</p> <p><mathjax>#color(blue)"given mass benzene"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(blue)"mol benzene"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(blue)"mol oxygen"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(blue)"mass oxygen"#</mathjax></p> <p>In order to do this, we will need the appropriate mole ratio from the balanced equation, and the molar masses of benzene and oxygen. </p> <p>We need <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio between benzene and oxygen from the balanced equation.</p> <p><strong>Mole Ratio Benzene: Oxygen</strong></p> <p><mathjax>#("2 mol C"_6"H"_6)/("15 mol O"_2")#</mathjax> and <mathjax>#("15 mol O"_2)/("2 mol C"_6"H"_6")#</mathjax></p> <p><strong>Molar Masses of Benzene and Oxygen</strong><br/> Multiply the subscript of each element by its molar mass, the atomic weight on <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a> in g/mol.</p> <p><mathjax>#"C"_6"H"_6":#</mathjax><mathjax>#(6xx12.011"g/mol C")+(6xx1.008"g/mol H")="78.114 g/mol C"_6"H"_6"#</mathjax></p> <p><mathjax>#"O"_2":#</mathjax><mathjax>#(2xx15.999"g/mol O")="31.998 g/mol O"_2"#</mathjax></p> <p><strong>Determine Moles Benzene</strong><br/> Multiply the <mathjax>#color(blue)"given mass"#</mathjax> of benzene by the reciprocal of its molar mass.</p> <p><mathjax>#150.0color(red)cancel(color(black)("g C"_6"H"_6))xx(1"mol C"_6"H"_6)/(78.114color(red)cancel(color(black)("g C"_6"H"_6)))="1.9203 mol C"_6"H"_6"#</mathjax></p> <p><strong>Determine Moles Oxygen Using the Mole Ratio</strong></p> <p><mathjax>#1.9203 color(red)cancel(color(black)("mol C"_6"H"_6))xx("15 mol O"_2)/(2 color(red)cancel(color(black)("mol C"_6"H"_6)))="14.402 mol O"_2"#</mathjax></p> <p><strong>Determine Mass Oxygen Using Molar Mass of Oxygen</strong><br/> Multiply mol oxygen by its molar mass.</p> <p><mathjax>#14.402color(red)cancel(color(black)("mol O"_2))xx(31.998"g O"_2)/(1color(red)cancel(color(black)("mol O"_2)))="460.8 g O"_2"#</mathjax> rounded to four <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/409733" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb002bf34694a4fee47"> Question #fee47 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb402bf34694c8c5c15"> Question #c5c15 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb802bf346950519eb9"> Question #19eb9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cbf02bf3469570e2ea2"> Question #e2ea2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc002bf34695a6bc751"> Question #bc751 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc202bf3469570e2ea6"> Question #e2ea6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531e867a02bf342492a08b07"> Question #08b07 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-thermochemical-equation-for-the-combustion-of-benzene"> What is the thermochemical equation for the combustion of benzene? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-reversible"> Why are chemical reactions reversible? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-important"> Why are chemical reactions important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/chemical-reactions-and-equations"> See all questions in Chemical Reactions and Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 7503 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What mass of oxygen is required to react with 150.0 g of benzene?	null
1,054	ac101374-6ddd-11ea-b900-ccda262736ce	https://socratic.org/questions/what-is-the-empirical-formula-for-c3h6o3	CH2O	start chemical_formula qc_end chemical_equation 6 6 qc_end end	[{"type":"other","value":"Chemical Formula [OF] C3H6O3 [IN] empirical"}]	[{"type":"chemical equation","value":"CH2O"}]	[{"type":"chemical equation","value":"C3H6O3"}]	<h1 class="questionTitle" itemprop="name">What is the empirical formula for C3H6O3?</h1>	null	CH2O	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Empirical formula consist of the simplest or most reduced ratio of <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> in a compound while molecular formula contains the actual number of atoms for each element in the compound.</p> <p>Starting from the given molecular formula of <mathjax>#C_3H_6O_3#</mathjax>, the values 3 and 6 can be simplified to 1 and 2, respectively. That means, the empirical formula is <mathjax>#CH_2O#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#CH_2O#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Empirical formula consist of the simplest or most reduced ratio of <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> in a compound while molecular formula contains the actual number of atoms for each element in the compound.</p> <p>Starting from the given molecular formula of <mathjax>#C_3H_6O_3#</mathjax>, the values 3 and 6 can be simplified to 1 and 2, respectively. That means, the empirical formula is <mathjax>#CH_2O#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the empirical formula for C3H6O3?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="637341" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/dr-k"><img alt="" class="" src="https://yt3.ggpht.com/-9hqy4z72uJU/AAAAAAAAAAI/AAAAAAAAAAA/U4oALcr4dCU/s88-c-k-no-mo-rj-c0xffffff/photo.jpg?sz=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/dr-k"> Dr. K. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-06-30T16:08:30" itemprop="dateCreated"> Jun 30, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#CH_2O#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Empirical formula consist of the simplest or most reduced ratio of <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> in a compound while molecular formula contains the actual number of atoms for each element in the compound.</p> <p>Starting from the given molecular formula of <mathjax>#C_3H_6O_3#</mathjax>, the values 3 and 6 can be simplified to 1 and 2, respectively. That means, the empirical formula is <mathjax>#CH_2O#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/637341" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molecular-formula-of-a-compound"> How do you find molecular formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-diamond"> What is the chemical formula of a diamond? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-carbohydrate"> What is the chemical formula of a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-valproic-acid"> What is the empirical formula for valproic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-of-magnesium-oxide"> What is the empirical formula of magnesium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-empirical-formula-not-double-that-of-the-monosaccharides"> Why is the empirical formula not double that of the monosaccharides? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5331180502bf342f40b5c3b5"> Question #5c3b5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-molecular-formula-represents-a-carbohydrate"> What molecular formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-of-vinegar"> What is the molecular formula of vinegar? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/empirical-and-molecular-formulas"> See all questions in Empirical and Molecular Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 18342 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the empirical formula for C3H6O3?	null
1,055	a8641a1c-6ddd-11ea-a90d-ccda262736ce	https://socratic.org/questions/what-is-the-molar-mass-of-silver-nitrate	169.87 grams/mole	start physical_unit 6 7 molar_mass g/mol qc_end substance 6 7 qc_end end	[{"type":"physical unit","value":"Molar mass [OF] silver nitrate [IN] grams/mole"}]	[{"type":"physical unit","value":"169.87 grams/mole"}]	[{"type":"substance name","value":"Silver nitrate"}]	<h1 class="questionTitle" itemprop="name">What is the molar mass of silver nitrate?</h1>	null	169.87 grams/mole	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The molar mass of a chemical is the molecular weight of the chemical in grams.</p> <p>i.e. 1 mole = (molecular mass) grams of the chemical.</p> <p>Molecular weight of silver nitrate = the sum of the atomic masses of the atoms in 1 "molecule" of silver nitrate, in grams.</p> <p>Formula for silver nitrate = <mathjax>#AgNO_3#</mathjax></p> <p>This gives the molar mass as </p> <p><mathjax>#(107.87+14.007+(3*15.999)) = 169.874#</mathjax> grams/mole</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>169.874# grams/mole</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The molar mass of a chemical is the molecular weight of the chemical in grams.</p> <p>i.e. 1 mole = (molecular mass) grams of the chemical.</p> <p>Molecular weight of silver nitrate = the sum of the atomic masses of the atoms in 1 "molecule" of silver nitrate, in grams.</p> <p>Formula for silver nitrate = <mathjax>#AgNO_3#</mathjax></p> <p>This gives the molar mass as </p> <p><mathjax>#(107.87+14.007+(3*15.999)) = 169.874#</mathjax> grams/mole</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the molar mass of silver nitrate?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="643243" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/pj"><img alt="" class="" src="https://profilepictures.socratic.org/9zsnYVyT4qXnpsc97ZNg_Room.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/pj"> PJ </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-07-25T04:58:18" itemprop="dateCreated"> Jul 25, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>169.874# grams/mole</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The molar mass of a chemical is the molecular weight of the chemical in grams.</p> <p>i.e. 1 mole = (molecular mass) grams of the chemical.</p> <p>Molecular weight of silver nitrate = the sum of the atomic masses of the atoms in 1 "molecule" of silver nitrate, in grams.</p> <p>Formula for silver nitrate = <mathjax>#AgNO_3#</mathjax></p> <p>This gives the molar mass as </p> <p><mathjax>#(107.87+14.007+(3*15.999)) = 169.874#</mathjax> grams/mole</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/643243" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? 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1,056	abda6a28-6ddd-11ea-b4f0-ccda262736ce	https://socratic.org/questions/58f550787c01496a7ac60033	58 ℃	start physical_unit 19 19 temperature °c qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Temperature [OF] water [IN] ℃"}]	[{"type":"physical unit","value":"58 ℃"}]	[{"type":"other","value":"Dissolve equal amounts of ammonium chloride and hydrogen chloride in the same amount of water."}]	<h1 class="questionTitle" itemprop="name">At what temperature can we dissolve equal amounts of ammonium chloride and hydrogen chloride in the same amount of water?</h1>	null	58 ℃	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>I presume that you are asked to interpret a solubility curve like the one below.</p> <p><img alt="Solubility" src="https://useruploads.socratic.org/D8J7iKbMRDgkGsokmKEi_Solubi1.jpg"/> <br/> (Adapted from KentChemistry HOME)</p> <p>Find the curves for <mathjax>#"NH"_4"Cl"#</mathjax> and <mathjax>#"HCl"#</mathjax> and locate the point where they cross.</p> <p>Then, drop a line down to the temperature axis and note the temperature.</p> <p>In this diagram, it looks like both <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a> have the same solubility (about 56 g/100 g of water) at 58 °C.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Equal amounts can be dissolved at 58 °C.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>I presume that you are asked to interpret a solubility curve like the one below.</p> <p><img alt="Solubility" src="https://useruploads.socratic.org/D8J7iKbMRDgkGsokmKEi_Solubi1.jpg"/> <br/> (Adapted from KentChemistry HOME)</p> <p>Find the curves for <mathjax>#"NH"_4"Cl"#</mathjax> and <mathjax>#"HCl"#</mathjax> and locate the point where they cross.</p> <p>Then, drop a line down to the temperature axis and note the temperature.</p> <p>In this diagram, it looks like both <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a> have the same solubility (about 56 g/100 g of water) at 58 °C.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">At what temperature can we dissolve equal amounts of ammonium chloride and hydrogen chloride in the same amount of water?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/factors-affecting-solubility" itemprop="url"> <span class="breadcrumb" itemprop="title">Factors Affecting Solubility</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="408420" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-18T01:58:31" itemprop="dateCreated"> Apr 18, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Equal amounts can be dissolved at 58 °C.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>I presume that you are asked to interpret a solubility curve like the one below.</p> <p><img alt="Solubility" src="https://useruploads.socratic.org/D8J7iKbMRDgkGsokmKEi_Solubi1.jpg"/> <br/> (Adapted from KentChemistry HOME)</p> <p>Find the curves for <mathjax>#"NH"_4"Cl"#</mathjax> and <mathjax>#"HCl"#</mathjax> and locate the point where they cross.</p> <p>Then, drop a line down to the temperature axis and note the temperature.</p> <p>In this diagram, it looks like both <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a> have the same solubility (about 56 g/100 g of water) at 58 °C.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/408420" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-factors-affect-solubility-in-a-solid-liquid-combination"> What factors affect solubility in a solid-liquid combination? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-factors-affect-solubility-in-water"> What factors affect solubility 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href="/chemistry/solutions-and-their-behavior/factors-affecting-solubility"> See all questions in Factors Affecting Solubility </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3062 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	At what temperature can we dissolve equal amounts of ammonium chloride and hydrogen chloride in the same amount of water?	null
1,057	a918d8ae-6ddd-11ea-a151-ccda262736ce	https://socratic.org/questions/how-many-water-molecules-are-in-39-formula-units-of-calcium-chloride-dihydrate	78	start physical_unit 2 3 number none qc_end end	[{"type":"physical unit","value":"Number [OF] water molecules"}]	[{"type":"physical unit","value":"78"}]	[{"type":"physical unit","value":"Number [OF] calcium chloride dihydrate formula units [=] \\pu{39}"}]	<h1 class="questionTitle" itemprop="name">How many water molecules are in 39 formula units of calcium chloride dihydrate?</h1>	null	78	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>di = 2 </p> <p>So, in each formula unit of calcium chloride dihydrate,<br/> <mathjax># CaCl_2. 2H_2O#</mathjax>, there are two water molecules. </p> <p>Multiply 39 formula units x 2 water molecules per formula unit. </p> <p><mathjax># "39 formula units" xx ("2 water molecules")/("1 formula unit") = "78 water molecules"#</mathjax># </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>78 </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>di = 2 </p> <p>So, in each formula unit of calcium chloride dihydrate,<br/> <mathjax># CaCl_2. 2H_2O#</mathjax>, there are two water molecules. </p> <p>Multiply 39 formula units x 2 water molecules per formula unit. </p> <p><mathjax># "39 formula units" xx ("2 water molecules")/("1 formula unit") = "78 water molecules"#</mathjax># </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many water molecules are in 39 formula units of calcium chloride dihydrate?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="404235" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/david-drayer"><img alt="" class="" src="https://graph.facebook.com/10206723679871989/picture?height=50&width=50" title=""/></a> <a class="secondContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/david-drayer"> David Drayer </a>·<a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-09T22:00:05" itemprop="dateCreated"> Apr 9, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>78 </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>di = 2 </p> <p>So, in each formula unit of calcium chloride dihydrate,<br/> <mathjax># CaCl_2. 2H_2O#</mathjax>, there are two water molecules. </p> <p>Multiply 39 formula units x 2 water molecules per formula unit. </p> <p><mathjax># "39 formula units" xx ("2 water molecules")/("1 formula unit") = "78 water molecules"#</mathjax># </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/404235" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? 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1,058	ac2fa406-6ddd-11ea-8cd7-ccda262736ce	https://socratic.org/questions/how-many-moles-are-there-in-400-0-grams-of-carbon	33.31 moles	start physical_unit 9 9 mole mol qc_end physical_unit 9 9 6 7 mass qc_end end	[{"type":"physical unit","value":"Mole [OF] carbon [IN] moles"}]	[{"type":"physical unit","value":"33.31 moles"}]	[{"type":"physical unit","value":"Mass [OF] carbon [=] \\pu{400.0 grams}"}]	<h1 class="questionTitle" itemprop="name">How many moles are there in 400.0 grams of carbon? </h1>	null	33.31 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#12.01 g #</mathjax> of carbon consists of <mathjax>#1 mol#</mathjax><br/> <mathjax>#:. 400.0 g#</mathjax> of carbon consists of <mathjax>#(400.0 g)/(12.01 g//mol#</mathjax></p> <p><mathjax>#" "= 33.31 mol#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#ans~~33.31 mol#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#12.01 g #</mathjax> of carbon consists of <mathjax>#1 mol#</mathjax><br/> <mathjax>#:. 400.0 g#</mathjax> of carbon consists of <mathjax>#(400.0 g)/(12.01 g//mol#</mathjax></p> <p><mathjax>#" "= 33.31 mol#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles are there in 400.0 grams of carbon? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="469738" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/sarthak-3"><img alt="" class="" src="https://profilepictures.socratic.org/r1uCBFoR32iP5CryFHLD_1174593909317479.jpg" title=""/></a> <a class="secondContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/sarthak-3"> Sarthak </a>·<a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-30T11:07:18" itemprop="dateCreated"> Aug 30, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#ans~~33.31 mol#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#12.01 g #</mathjax> of carbon consists of <mathjax>#1 mol#</mathjax><br/> <mathjax>#:. 400.0 g#</mathjax> of carbon consists of <mathjax>#(400.0 g)/(12.01 g//mol#</mathjax></p> <p><mathjax>#" "= 33.31 mol#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/469738" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? 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1,059	ab6d7512-6ddd-11ea-a5ee-ccda262736ce	https://socratic.org/questions/how-many-grams-of-co-are-needed-to-to-produce-442-grams-of-fe-1fe-2o-3-3co-3co-2	331.5 grams	start physical_unit 4 4 mass g qc_end chemical_equation 14 24 qc_end physical_unit 13 13 10 11 mass qc_end end	[{"type":"physical unit","value":"Mass [OF] CO [IN] grams"}]	[{"type":"physical unit","value":"331.5 grams"}]	[{"type":"chemical equation","value":"1 Fe2O3 + 3 CO -> 3 CO2 + 2 Fe"},{"type":"physical unit","value":"Mass [OF] Fe [=] \\pu{442 grams}"}]	<h1 class="questionTitle" itemprop="name">How many grams of CO are needed to to produce 442 grams of Fe? #1Fe_2O_3 + 3CO -> 3CO_2 + 2Fe#</h1>	null	331.5 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#n mol Fe = m/( MW) = (442 g)/(56 g/(mol)) = 7.89 mol#</mathjax></p> <p><mathjax>#n mol CO = 7.89 mol Fe * ((3 mol CO)/(2 mol Fe)) = 11.84 mol CO#</mathjax></p> <p><mathjax># mass CO = n * MW = 11.84 mol * (28 g)/(mol) = 331.5 g CO#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>331.5 g of CO are needed.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#n mol Fe = m/( MW) = (442 g)/(56 g/(mol)) = 7.89 mol#</mathjax></p> <p><mathjax>#n mol CO = 7.89 mol Fe * ((3 mol CO)/(2 mol Fe)) = 11.84 mol CO#</mathjax></p> <p><mathjax># mass CO = n * MW = 11.84 mol * (28 g)/(mol) = 331.5 g CO#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many grams of CO are needed to to produce 442 grams of Fe? #1Fe_2O_3 + 3CO -> 3CO_2 + 2Fe#</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="401832" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/mm-4"><img alt="" class="" src="https://profilepictures.socratic.org/HvEacoQwTRuTItKdTnmp_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/mm-4"> MM </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-05T05:09:00" itemprop="dateCreated"> Apr 5, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>331.5 g of CO are needed.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#n mol Fe = m/( MW) = (442 g)/(56 g/(mol)) = 7.89 mol#</mathjax></p> <p><mathjax>#n mol CO = 7.89 mol Fe * ((3 mol CO)/(2 mol Fe)) = 11.84 mol CO#</mathjax></p> <p><mathjax># mass CO = n * MW = 11.84 mol * (28 g)/(mol) = 331.5 g CO#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/401832" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? 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1,060	a92b7b06-6ddd-11ea-b751-ccda262736ce	https://socratic.org/questions/what-is-the-total-mass-of-iron-in-1-0-mole-of-fe-2o-3	111.69 g	start physical_unit 6 6 mass g qc_end physical_unit 11 11 8 9 mole qc_end end	[{"type":"physical unit","value":"Mass [OF] iron [IN] g"}]	[{"type":"physical unit","value":"111.69 g"}]	[{"type":"physical unit","value":"Mole [OF] Fe2O3 [=] \\pu{1.0 mole}"}]	<h1 class="questionTitle" itemprop="name">What is the total mass of iron in 1.0 mole of #Fe_2O_3#?</h1>	null	111.69 g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"1.0 mol Fe"_2"O"_3"#</mathjax> contains <mathjax>#"2 mol Fe"#</mathjax> ions.</p> <p>The molar mass of Fe is 55.845 g/mol.</p> <p><mathjax>#2"mol Fe"xx55.845"g/mol"="111.69 g Fe"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"1.0 mol Fe"_2"O"_3"#</mathjax> contains <mathjax>#"111.69 g Fe"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"1.0 mol Fe"_2"O"_3"#</mathjax> contains <mathjax>#"2 mol Fe"#</mathjax> ions.</p> <p>The molar mass of Fe is 55.845 g/mol.</p> <p><mathjax>#2"mol Fe"xx55.845"g/mol"="111.69 g Fe"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the total mass of iron in 1.0 mole of #Fe_2O_3#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="232857" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-02-29T07:23:46" itemprop="dateCreated"> Feb 29, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"1.0 mol Fe"_2"O"_3"#</mathjax> contains <mathjax>#"111.69 g Fe"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"1.0 mol Fe"_2"O"_3"#</mathjax> contains <mathjax>#"2 mol Fe"#</mathjax> ions.</p> <p>The molar mass of Fe is 55.845 g/mol.</p> <p><mathjax>#2"mol Fe"xx55.845"g/mol"="111.69 g Fe"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/232857" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? 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1,061	a98d4437-6ddd-11ea-bfb4-ccda262736ce	https://socratic.org/questions/what-is-the-density-of-methyl-chloride-gas-ch-3cl-at-stp	2.25 × 10^(-3) g/mL	start physical_unit 8 8 density g/ml qc_end c_other STP qc_end end	[{"type":"physical unit","value":"Density [OF] CH3Cl [IN] g/mL"}]	[{"type":"physical unit","value":"2.25 × 10^(-3) g/mL"}]	[{"type":"other","value":"STP"}]	<h1 class="questionTitle" itemprop="name">What is the density of methyl chloride gas, #CH_3Cl#, at STP?</h1>	null	2.25 × 10^(-3) g/mL	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>If you assume that it behaves as an ideal gas then it's simple enough, and will give you a fair estimate:</p> <p>One mole of an ideal gas at STP occupies <mathjax>#22.4#</mathjax> <mathjax>#L#</mathjax>. Molar mass of methyl chloride is <mathjax>#50.49#</mathjax> <mathjax>#g#</mathjax>/<mathjax>#mol#</mathjax>. </p> <p>Then simply divide the molar mass by the molar volume which gives you a <a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a> in <mathjax>#g#</mathjax>/<mathjax>#l#</mathjax>.</p> <p>i.e. <mathjax>#"Density" = "Molar mass"/"Molar volume"#</mathjax> </p> <p>= <mathjax>#50.49 / 22.4#</mathjax> = <mathjax>#2.25#</mathjax> <mathjax>#g#</mathjax>/<mathjax>#L#</mathjax> = <mathjax>#0.00225#</mathjax> <mathjax>#g#</mathjax>/<mathjax>#ml#</mathjax>.</p> <p>If you want a more accurate figure you will need to use the full form of the gas equation incorporating a virial expansion, but that's a lot more complicated!</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>If you assume it behaves as an ideal gas, then <mathjax>#0.00225#</mathjax> <mathjax>#g#</mathjax>/<mathjax>#ml#</mathjax> at <mathjax>#STP#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>If you assume that it behaves as an ideal gas then it's simple enough, and will give you a fair estimate:</p> <p>One mole of an ideal gas at STP occupies <mathjax>#22.4#</mathjax> <mathjax>#L#</mathjax>. Molar mass of methyl chloride is <mathjax>#50.49#</mathjax> <mathjax>#g#</mathjax>/<mathjax>#mol#</mathjax>. </p> <p>Then simply divide the molar mass by the molar volume which gives you a <a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a> in <mathjax>#g#</mathjax>/<mathjax>#l#</mathjax>.</p> <p>i.e. <mathjax>#"Density" = "Molar mass"/"Molar volume"#</mathjax> </p> <p>= <mathjax>#50.49 / 22.4#</mathjax> = <mathjax>#2.25#</mathjax> <mathjax>#g#</mathjax>/<mathjax>#L#</mathjax> = <mathjax>#0.00225#</mathjax> <mathjax>#g#</mathjax>/<mathjax>#ml#</mathjax>.</p> <p>If you want a more accurate figure you will need to use the full form of the gas equation incorporating a virial expansion, but that's a lot more complicated!</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the density of methyl chloride gas, #CH_3Cl#, at STP?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp" itemprop="url"> <span class="breadcrumb" itemprop="title">Molar Volume of a Gas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="266652" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/simon-moore"><img alt="" class="" src="https://profilepictures.socratic.org/0ztdJJ7RCWUlBSPeGa9N_6EB6CADA-35F5-4BAA-9B66-9D6F64A622BA.jpeg" title=""/></a> <a class="secondContributorPic" href="/users/grace-9"><img alt="" class="" src="https://profilepictures.socratic.org/gzi0U3RQNuMSxgKVeKgw_10960213_10153434463490909_9111641440892052754_o.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/simon-moore"> Simon Moore </a>·<a class="topContributorLink" href="/users/grace-9"> Grace </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-17T09:14:09" itemprop="dateCreated"> May 17, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>If you assume it behaves as an ideal gas, then <mathjax>#0.00225#</mathjax> <mathjax>#g#</mathjax>/<mathjax>#ml#</mathjax> at <mathjax>#STP#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>If you assume that it behaves as an ideal gas then it's simple enough, and will give you a fair estimate:</p> <p>One mole of an ideal gas at STP occupies <mathjax>#22.4#</mathjax> <mathjax>#L#</mathjax>. Molar mass of methyl chloride is <mathjax>#50.49#</mathjax> <mathjax>#g#</mathjax>/<mathjax>#mol#</mathjax>. </p> <p>Then simply divide the molar mass by the molar volume which gives you a <a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a> in <mathjax>#g#</mathjax>/<mathjax>#l#</mathjax>.</p> <p>i.e. <mathjax>#"Density" = "Molar mass"/"Molar volume"#</mathjax> </p> <p>= <mathjax>#50.49 / 22.4#</mathjax> = <mathjax>#2.25#</mathjax> <mathjax>#g#</mathjax>/<mathjax>#L#</mathjax> = <mathjax>#0.00225#</mathjax> <mathjax>#g#</mathjax>/<mathjax>#ml#</mathjax>.</p> <p>If you want a more accurate figure you will need to use the full form of the gas equation incorporating a virial expansion, but that's a lot more complicated!</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/266652" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-stoichiometric-ratios-relate-to-molar-volume-of-a-gas"> How do stoichiometric ratios relate to molar volume of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-a-gas-at-stp"> How do you calculate molar volume of a gas at STP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-molar-volume-of-hydrogen-gas"> How do you find the molar volume of hydrogen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-oxygen-gas"> How do you calculate molar volume of oxygen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molar-gas-volume"> What is molar gas volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/534c7bf202bf3420a007f014"> What is the volume at 0 °C and 1 atm of a mixture that contains 4.0 g of methane and 2.0 g of helium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5361f75702bf3429040e0599"> What is the difference between STP and NTP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-volume-of-25-moles-of-oxygen-o2-gas"> What is the volume of .25 moles of oxygen (O2) Gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-would-knowing-the-molar-volume-of-a-gas-be-important"> Why would knowing the molar volume of a gas be important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-22-4-liters-called-the-molar-volume-of-a-gas"> Why is 22.4 liters called the molar volume of a gas? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp"> See all questions in Molar Volume of a Gas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 4553 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the density of methyl chloride gas, #CH_3Cl#, at STP?	null
1,062	ab802626-6ddd-11ea-9190-ccda262736ce	https://socratic.org/questions/what-does-a-solution-with-a-hydronium-ion-concentration-of-10-11-m-have-a-ph-of	11.00	start physical_unit 3 3 ph none qc_end physical_unit 6 7 10 11 concentration qc_end end	[{"type":"physical unit","value":"pH [OF] the solution"}]	[{"type":"physical unit","value":"11.00"}]	[{"type":"physical unit","value":"Concentration [OF] hydronium ion [=] \\pu{10^(-11) M}"}]	<h1 class="questionTitle" itemprop="name">What does a solution with a hydronium ion concentration of# 10^-11# M have a pH of?</h1>	null	11.00	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#pH=-log_10[H_3O^+]#</mathjax></p> <p><mathjax>#[H_3O^+]=10^-11molL^-1#</mathjax></p> <p><mathjax>#-log_10[H_3O^+]=-log_10(10^-11)=-(-11)=11#</mathjax>.</p> <p>Clearly, this is an aqueous solution. Is this an acidic or basic solution?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#pH=11#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#pH=-log_10[H_3O^+]#</mathjax></p> <p><mathjax>#[H_3O^+]=10^-11molL^-1#</mathjax></p> <p><mathjax>#-log_10[H_3O^+]=-log_10(10^-11)=-(-11)=11#</mathjax>.</p> <p>Clearly, this is an aqueous solution. Is this an acidic or basic solution?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What does a solution with a hydronium ion concentration of# 10^-11# M have a pH of?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/ph-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">pH calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="351270" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-12-13T20:29:52" itemprop="dateCreated"> Dec 13, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#pH=11#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#pH=-log_10[H_3O^+]#</mathjax></p> <p><mathjax>#[H_3O^+]=10^-11molL^-1#</mathjax></p> <p><mathjax>#-log_10[H_3O^+]=-log_10(10^-11)=-(-11)=11#</mathjax>.</p> <p>Clearly, this is an aqueous solution. Is this an acidic or basic solution?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/351270" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-of-a-solution"> How do you determine ph of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-at-an-equivalence-point"> How do you determine pH at an equivalence point? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-molarity"> How do you determine pH from molarity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-alkalinity-mean"> What does alkalinity mean? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-base"> What is a base? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-acid-base-indicators-change-color"> How do acid base indicators change color? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-neutral-ph"> What is a neutral pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-alkalinity-affect-pool-water"> How does alkalinity affect pool water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ph-important-in-drinking-water"> Why is pH important in drinking water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-ph-of-solution"> How can I calculate the pH of a solution? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/ph-calculations"> See all questions in pH calculations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 5073 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What does a solution with a hydronium ion concentration of# 10^-11# M have a pH of?	null
1,063	ab37dbc2-6ddd-11ea-89f0-ccda262736ce	https://socratic.org/questions/57d0b53c7c01491f3363e108	+4	start physical_unit 3 3 oxidation_state none qc_end end	[{"type":"physical unit","value":"Oxidation state [OF] metal"}]	[{"type":"physical unit","value":"+4"}]	[{"type":"chemical equation","value":"Fe(SO4)"}]	<h1 class="questionTitle" itemprop="name">What is the metal oxidation state in #Fe(SO_4)_2#?</h1>	null	+4	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The sulfate ion is <mathjax>#SO_4^(2-)#</mathjax>. There is a <mathjax>#"ferrous sulfate, "FeSO_4", and a ferric sulfate, " Fe_2(SO_4)_3#</mathjax>. <mathjax>#Fe(IV+)#</mathjax> salts would be rare. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>That's <mathjax>#Fe^(4+)#</mathjax>! It is probably a typo.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The sulfate ion is <mathjax>#SO_4^(2-)#</mathjax>. There is a <mathjax>#"ferrous sulfate, "FeSO_4", and a ferric sulfate, " Fe_2(SO_4)_3#</mathjax>. <mathjax>#Fe(IV+)#</mathjax> salts would be rare. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the metal oxidation state in #Fe(SO_4)_2#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#ionic-bonds-and-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Ionic Bonds</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/ionic-bonds-and-formulas/ionic-compounds" itemprop="url"> <span class="breadcrumb" itemprop="title">Ionic Compounds</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="309716" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-09-13T15:54:10" itemprop="dateCreated"> Sep 13, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>That's <mathjax>#Fe^(4+)#</mathjax>! It is probably a typo.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The sulfate ion is <mathjax>#SO_4^(2-)#</mathjax>. There is a <mathjax>#"ferrous sulfate, "FeSO_4", and a ferric sulfate, " Fe_2(SO_4)_3#</mathjax>. <mathjax>#Fe(IV+)#</mathjax> salts would be rare. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/309716" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52f1151302bf34732c779c2f"> Question #79c2f </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52f1151302bf3473360cd842"> Question #cd842 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52f1151702bf34733dc14e7e"> Why do ionic compounds dissolve in water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52f1151b02bf3473394975aa"> Question #975aa </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52f1151b02bf3473394975ae"> Question #975ae </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52f1151e02bf34733e367e72"> Question #67e72 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/532eff8902bf341e776bd809"> What do the terms anhydrous, hydrous, and undissociated mean? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-ionic-compounds"> What are ionic compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-identify-ionic-compounds"> How can I identify ionic compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-ionic-compounds-solid-at-a-room-temperature"> Why are ionic compounds solid at room temperature? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/ionic-bonds-and-formulas/ionic-compounds"> See all questions in Ionic Compounds </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1500 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the metal oxidation state in #Fe(SO_4)_2#?	null
1,064	a8c02a1d-6ddd-11ea-8322-ccda262736ce	https://socratic.org/questions/what-is-the-chemical-formula-for-silver-sulfate	Ag2SO4	start chemical_formula qc_end substance 6 7 qc_end end	[{"type":"other","value":"Chemical Formula [OF] silver sulfate [IN] default"}]	[{"type":"chemical equation","value":"Ag2SO4"}]	[{"type":"substance name","value":"Silver sulfate"}]	<h1 class="questionTitle" itemprop="name">What is the chemical formula for silver sulfate?</h1>	null	Ag2SO4	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Silver commonly forms the <mathjax>#Ag^+#</mathjax> ion. Hence 2 equiv silver ion will give a neutral salt with 1 equiv sulfate ion.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Ag_2SO_4#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Silver commonly forms the <mathjax>#Ag^+#</mathjax> ion. Hence 2 equiv silver ion will give a neutral salt with 1 equiv sulfate ion.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the chemical formula for silver sulfate?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#covalent-bonds-and-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Covalent Bonds</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/covalent-bonds-and-formulas/covalent-formulas-and-nomenclature" itemprop="url"> <span class="breadcrumb" itemprop="title">Covalent Formulas and Nomenclature</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="312523" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-09-20T20:33:37" itemprop="dateCreated"> Sep 20, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Ag_2SO_4#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Silver commonly forms the <mathjax>#Ag^+#</mathjax> ion. Hence 2 equiv silver ion will give a neutral salt with 1 equiv sulfate ion.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/312523" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-for-sugar"> What is the chemical formula for sugar? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-chemical-formula-represents-a-carbohydrate"> What chemical formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-for-gold"> What is the chemical formula for gold? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-for-a-diamond"> What is the chemical formula for a diamond? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-formulas-for-covalent-compounds"> How do you find formulas for covalent compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-common-mistakes-students-make-with-empirical-forumlas"> What are common mistakes students make with empirical forumlas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-empirical-formulas"> What are empirical formulas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-examples-of-empirical-formulas"> What are some examples of empirical formulas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-naming-a-covalent-bond-between-atoms-how-would-you-write-the-prefix-for-if-"> When naming a covalently-bonded molecule, how would you write the prefix if you had four atoms... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-nomenclature-for-ch3cl"> What is the chemical nomenclature for CH3Cl? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/covalent-bonds-and-formulas/covalent-formulas-and-nomenclature"> See all questions in Covalent Formulas and Nomenclature </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 5145 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the chemical formula for silver sulfate?	null
1,065	aa335e8c-6ddd-11ea-934e-ccda262736ce	https://socratic.org/questions/if-the-solubility-of-a-compound-is-36-grams-per-liter-how-many-grams-of-the-comp	180.00 grams	start physical_unit 15 16 mass g qc_end physical_unit 15 16 7 10 solubility qc_end end	[{"type":"physical unit","value":"Mass [OF] the compound [IN] grams"}]	[{"type":"physical unit","value":"180.00 grams"}]	[{"type":"physical unit","value":"Solubility [OF] the compound [=] \\pu{36 grams per liter}"},{"type":"physical unit","value":"Volume [OF] solution [=] \\pu{5 liters}"}]	<h1 class="questionTitle" itemprop="name">If the solubility of a compound is 36 grams per liter, how many grams of the compound will dissolve in 5 liters? </h1>	null	180.00 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Multiply the soluble mass per liter by the number of liters.</p> <p><mathjax>#36("g")/(cancel"L")xx5cancel"L"="180 g"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Five liters would contain 180 g of the dissolved <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Multiply the soluble mass per liter by the number of liters.</p> <p><mathjax>#36("g")/(cancel"L")xx5cancel"L"="180 g"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">If the solubility of a compound is 36 grams per liter, how many grams of the compound will dissolve in 5 liters? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/factors-affecting-solubility" itemprop="url"> <span class="breadcrumb" itemprop="title">Factors Affecting Solubility</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="358060" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-12-30T03:25:35" itemprop="dateCreated"> Dec 30, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Five liters would contain 180 g of the dissolved <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Multiply the soluble mass per liter by the number of liters.</p> <p><mathjax>#36("g")/(cancel"L")xx5cancel"L"="180 g"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/358060" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-factors-affect-solubility-in-a-solid-liquid-combination"> What factors affect solubility in a solid-liquid combination? 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1,066	a9be293e-6ddd-11ea-b1a3-ccda262736ce	https://socratic.org/questions/calcium-carbonate-caco-3-has-a-ksp-value-of-1-4-x-10-8-what-is-the-solubility-of	1.18 × 10^(-2) g/L	start physical_unit 2 2 solubility g/l qc_end physical_unit 2 2 8 10 equilibrium_constant_k qc_end end	[{"type":"physical unit","value":"Solubility [OF] CaCO3 [IN] g/L"}]	[{"type":"physical unit","value":"1.18 × 10^(-2) g/L"}]	[{"type":"physical unit","value":"Ksp value [OF] CaCO3 [=] \\pu{1.4 × 10^(−8)}"}]	<h1 class="questionTitle" itemprop="name">Calcium carbonate, #CaCO_3# has a Ksp value of #1.4 x 10^-8#, what is the solubility of #CaCO_3#?</h1>	null	1.18 × 10^(-2) g/L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#K_(sp)=[Ca^(2+)][CO_3^(2-)]#</mathjax> <mathjax>#=#</mathjax> <mathjax>#1.4xx10^-8#</mathjax>.</p> <p>If we call the solubility <mathjax>#S#</mathjax>, then <mathjax>#S=[Ca^(2+)]=[CO_3^(2-)]#</mathjax>, and,</p> <p><mathjax>#K_(sp)=[Ca^(2+)][CO_3^(2-)]#</mathjax> <mathjax>#=#</mathjax> <mathjax>#1.4xx10^-8#</mathjax> <mathjax>#=#</mathjax> <mathjax>#S^2#</mathjax></p> <p>So <mathjax>#Ca^(2+)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#sqrt{K_"sp"}#</mathjax> <mathjax>#=#</mathjax> <mathjax>#sqrt(1.4xx10^-8)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#1.18xx10^(-4)#</mathjax> <mathjax>#molL^-1#</mathjax>.</p> <p><mathjax>#"Solubility"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#1.18xx10^-4xx100.09gmol^-1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??gL^-1#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#CaCO_3(s) rightleftharpoons Ca^(2+) + CO_3^(2-)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#K_(sp)=[Ca^(2+)][CO_3^(2-)]#</mathjax> <mathjax>#=#</mathjax> <mathjax>#1.4xx10^-8#</mathjax>.</p> <p>If we call the solubility <mathjax>#S#</mathjax>, then <mathjax>#S=[Ca^(2+)]=[CO_3^(2-)]#</mathjax>, and,</p> <p><mathjax>#K_(sp)=[Ca^(2+)][CO_3^(2-)]#</mathjax> <mathjax>#=#</mathjax> <mathjax>#1.4xx10^-8#</mathjax> <mathjax>#=#</mathjax> <mathjax>#S^2#</mathjax></p> <p>So <mathjax>#Ca^(2+)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#sqrt{K_"sp"}#</mathjax> <mathjax>#=#</mathjax> <mathjax>#sqrt(1.4xx10^-8)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#1.18xx10^(-4)#</mathjax> <mathjax>#molL^-1#</mathjax>.</p> <p><mathjax>#"Solubility"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#1.18xx10^-4xx100.09gmol^-1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??gL^-1#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Calcium carbonate, #CaCO_3# has a Ksp value of #1.4 x 10^-8#, what is the solubility of #CaCO_3#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-equilibrium" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Equilibrium</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-equilibrium/ksp" itemprop="url"> <span class="breadcrumb" itemprop="title">Ksp</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="302181" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-08-24T08:05:18" itemprop="dateCreated"> Aug 24, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#CaCO_3(s) rightleftharpoons Ca^(2+) + CO_3^(2-)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#K_(sp)=[Ca^(2+)][CO_3^(2-)]#</mathjax> <mathjax>#=#</mathjax> <mathjax>#1.4xx10^-8#</mathjax>.</p> <p>If we call the solubility <mathjax>#S#</mathjax>, then <mathjax>#S=[Ca^(2+)]=[CO_3^(2-)]#</mathjax>, and,</p> <p><mathjax>#K_(sp)=[Ca^(2+)][CO_3^(2-)]#</mathjax> <mathjax>#=#</mathjax> <mathjax>#1.4xx10^-8#</mathjax> <mathjax>#=#</mathjax> <mathjax>#S^2#</mathjax></p> <p>So <mathjax>#Ca^(2+)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#sqrt{K_"sp"}#</mathjax> <mathjax>#=#</mathjax> <mathjax>#sqrt(1.4xx10^-8)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#1.18xx10^(-4)#</mathjax> <mathjax>#molL^-1#</mathjax>.</p> <p><mathjax>#"Solubility"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#1.18xx10^-4xx100.09gmol^-1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??gL^-1#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/302181" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li 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</ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-equilibrium/ksp"> See all questions in Ksp </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 47122 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Calcium carbonate, #CaCO_3# has a Ksp value of #1.4 x 10^-8#, what is the solubility of #CaCO_3#?	null
1,067	a91dd41d-6ddd-11ea-a979-ccda262736ce	https://socratic.org/questions/how-many-grams-are-in-5-66-mol-of-caco-3	566.57 grams	start physical_unit 8 8 mass g qc_end physical_unit 8 8 5 6 mole qc_end end	[{"type":"physical unit","value":"Mass [OF] CaCO3 [IN] grams"}]	[{"type":"physical unit","value":"566.57 grams"}]	[{"type":"physical unit","value":"Mole [OF] CaCO3 [=] \\pu{5.66 mol}"}]	<h1 class="questionTitle" itemprop="name">How many grams are in 5.66 mol of #CaCO_3#?</h1>	null	566.57 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#5.66#</mathjax> <mathjax>#cancel(mol)#</mathjax> <mathjax>#xx#</mathjax> <mathjax>#100.1#</mathjax> <mathjax>#g*cancel(mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??g#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Molar mass of calcium carbonate is <mathjax>#100.1#</mathjax> <mathjax>#gmol^(-1)#</mathjax>. There are 5.66 mol. So.............. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#5.66#</mathjax> <mathjax>#cancel(mol)#</mathjax> <mathjax>#xx#</mathjax> <mathjax>#100.1#</mathjax> <mathjax>#gcancel(mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??g#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many grams are in 5.66 mol of #CaCO_3#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="195813" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-03T10:57:34" itemprop="dateCreated"> Dec 3, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Molar mass of calcium carbonate is <mathjax>#100.1#</mathjax> <mathjax>#gmol^(-1)#</mathjax>. There are 5.66 mol. So.............. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#5.66#</mathjax> <mathjax>#cancel(mol)#</mathjax> <mathjax>#xx#</mathjax> <mathjax>#100.1#</mathjax> <mathjax>#gcancel(mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??g#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/195813" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 20782 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many grams are in 5.66 mol of #CaCO_3#?	null
1,068	abef1bf0-6ddd-11ea-89f0-ccda262736ce	https://socratic.org/questions/how-do-you-write-a-chemical-formula-for-the-following-scenario-nitric-acid-is-a-	4 NO2(g) + O2(g) + 2 H2O(l) -> 4 HNO3(aq)	start chemical_equation qc_end substance 35 37 qc_end substance 22 24 qc_end substance 28 29 qc_end substance 31 32 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the chemical formula"}]	[{"type":"chemical equation","value":"4 NO2(g) + O2(g) + 2 H2O(l) -> 4 HNO3(aq)"}]	[{"type":"substance name","value":"Aqueous nitric acid"},{"type":"substance name","value":"Gaseous nitrogen dioxide"},{"type":"substance name","value":"Gaseous oxygen"},{"type":"substance name","value":"Liquid water"}]	<h1 class="questionTitle" itemprop="name">How do you write a chemical formula for the following scenario: Nitric acid is a component of acid rain that forms when gaseous nitrogen dioxide pollutant reacts with gaseous oxygen and liquid water to form aqueous nitric acid?</h1>	null	4 NO2(g) + O2(g) + 2 H2O(l) -> 4 HNO3(aq)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is a synthesis reaction, also called a combination reaction, because two or more reactants produce a single product. You essentially have been given a word equation, which does not give the chemical formulas of each substance. In order to write a chemical equation, you need to determine the chemical formulas of each substance. Then write the equation and balance it.</p> <p><strong>Reactants</strong><br/> Gaseous nitrogen dioxide: <mathjax>#"NO"_2("g")#</mathjax><br/> Gaseous oxygen: <mathjax>#"O"_2("g")#</mathjax><br/> Liquid water: <mathjax>#"H"_2"O"(l)"#</mathjax></p> <p><strong>Product</strong><br/> Aqueous nitric acid: <mathjax>#"HNO"_3("aq")#</mathjax></p> <p><strong>Balanced Equation</strong></p> <p><mathjax>#"4NO"_2("g")+"O"_2("g")+"2H"_2"O("l")#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"4HNO"_3("aq")#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"4NO"_2("g")+"O"_2("g")+"2H"_2"O("l")#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"4HNO"_3("aq")#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is a synthesis reaction, also called a combination reaction, because two or more reactants produce a single product. You essentially have been given a word equation, which does not give the chemical formulas of each substance. In order to write a chemical equation, you need to determine the chemical formulas of each substance. Then write the equation and balance it.</p> <p><strong>Reactants</strong><br/> Gaseous nitrogen dioxide: <mathjax>#"NO"_2("g")#</mathjax><br/> Gaseous oxygen: <mathjax>#"O"_2("g")#</mathjax><br/> Liquid water: <mathjax>#"H"_2"O"(l)"#</mathjax></p> <p><strong>Product</strong><br/> Aqueous nitric acid: <mathjax>#"HNO"_3("aq")#</mathjax></p> <p><strong>Balanced Equation</strong></p> <p><mathjax>#"4NO"_2("g")+"O"_2("g")+"2H"_2"O("l")#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"4HNO"_3("aq")#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you write a chemical formula for the following scenario: Nitric acid is a component of acid rain that forms when gaseous nitrogen dioxide pollutant reacts with gaseous oxygen and liquid water to form aqueous nitric acid?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="277892" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-16T05:21:25" itemprop="dateCreated"> Jun 16, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"4NO"_2("g")+"O"_2("g")+"2H"_2"O("l")#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"4HNO"_3("aq")#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is a synthesis reaction, also called a combination reaction, because two or more reactants produce a single product. You essentially have been given a word equation, which does not give the chemical formulas of each substance. In order to write a chemical equation, you need to determine the chemical formulas of each substance. Then write the equation and balance it.</p> <p><strong>Reactants</strong><br/> Gaseous nitrogen dioxide: <mathjax>#"NO"_2("g")#</mathjax><br/> Gaseous oxygen: <mathjax>#"O"_2("g")#</mathjax><br/> Liquid water: <mathjax>#"H"_2"O"(l)"#</mathjax></p> <p><strong>Product</strong><br/> Aqueous nitric acid: <mathjax>#"HNO"_3("aq")#</mathjax></p> <p><strong>Balanced Equation</strong></p> <p><mathjax>#"4NO"_2("g")+"O"_2("g")+"2H"_2"O("l")#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"4HNO"_3("aq")#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/277892" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-equation-for-photosynthesis"> What is the chemical equation for photosynthesis? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-know-the-relative-number-of-grams-of-each-substance-used-or-produced-w"> How can I know the relative number of grams of each substance used or produced with chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-know-the-relative-number-of-moles-of-each-substance-with-chemical-equa"> How can I know the relative number of moles of each substance with chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-chemical-equations-illustrate-that-atoms-are-conserved-1"> How do chemical equations illustrate that atoms are conserved? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-know-the-formula-of-the-reactants-and-products-with-chemical-equations"> How can I know the formula of the reactants and products with chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-potassium-metal-and-chlorine-gas-combi"> How can I balance this chemical equations? 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1,069	ab3c96ec-6ddd-11ea-b48e-ccda262736ce	https://socratic.org/questions/what-is-the-mass-in-grams-of-3-40-10-22-atoms-he	0.23 grams	start physical_unit 11 11 mass g qc_end end	[{"type":"physical unit","value":"Mass [OF] He [IN] grams"}]	[{"type":"physical unit","value":"0.23 grams"}]	[{"type":"physical unit","value":"Number [OF] He atoms [=] \\pu{3.40 × 10^22}"}]	<h1 class="questionTitle" itemprop="name">What is the mass, in grams, of #3.40*10^22# atoms #He#?</h1>	null	0.23 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You can get to the answer in two steps:</p> <ol> <li>calculate: <mathjax>#3.4010^22#</mathjax> atoms = <mathjax>#color(red)x#</mathjax> mol ? <br/> using Avogadro's constant.</li> <li>calculate: <mathjax>#color(red)x#</mathjax> mol = <mathjax>#color(red)?#</mathjax> grams, <br/> using the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">atomic mass</a> of Helium.</li> </ol> <p><strong>Step 1</strong><br/> Avogadro's constant says that <mathjax>#1#</mathjax> mole of any atom contains <mathjax>#6.02210^23#</mathjax> atoms. In this case you have <mathjax>#3.4010^22#</mathjax> atoms:</p> <p><mathjax>#(3.4010^22 color(red)cancel(color(black)("atoms")))/ (6.02210^23 color(red)cancel(color(black)("atoms"))/"mol"#</mathjax> = <mathjax>#5.6510^-2 mol#</mathjax></p> <p><strong>Step 2</strong><br/> The atomic mass of helium (He) will give you the weight of one mole of this molecule: <mathjax>#1#</mathjax> mol = <mathjax>#4.00#</mathjax> gram:</p> <p><mathjax>#4.00 g/(color(red)cancel color(black)"mol") * 5.6510^-2 color(red)cancel color(black)"mol"#</mathjax> = <mathjax>#0.226 g#</mathjax></p> <p>So the <mathjax>#3.4010^22#</mathjax> helium atoms weigh <mathjax>#color(red)(0.226) color(red) " gram"#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.226 gram.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You can get to the answer in two steps:</p> <ol> <li>calculate: <mathjax>#3.4010^22#</mathjax> atoms = <mathjax>#color(red)x#</mathjax> mol ? <br/> using Avogadro's constant.</li> <li>calculate: <mathjax>#color(red)x#</mathjax> mol = <mathjax>#color(red)?#</mathjax> grams, <br/> using the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">atomic mass</a> of Helium.</li> </ol> <p><strong>Step 1</strong><br/> Avogadro's constant says that <mathjax>#1#</mathjax> mole of any atom contains <mathjax>#6.02210^23#</mathjax> atoms. In this case you have <mathjax>#3.4010^22#</mathjax> atoms:</p> <p><mathjax>#(3.4010^22 color(red)cancel(color(black)("atoms")))/ (6.02210^23 color(red)cancel(color(black)("atoms"))/"mol"#</mathjax> = <mathjax>#5.6510^-2 mol#</mathjax></p> <p><strong>Step 2</strong><br/> The atomic mass of helium (He) will give you the weight of one mole of this molecule: <mathjax>#1#</mathjax> mol = <mathjax>#4.00#</mathjax> gram:</p> <p><mathjax>#4.00 g/(color(red)cancel color(black)"mol") * 5.6510^-2 color(red)cancel color(black)"mol"#</mathjax> = <mathjax>#0.226 g#</mathjax></p> <p>So the <mathjax>#3.4010^22#</mathjax> helium atoms weigh <mathjax>#color(red)(0.226) color(red) " gram"#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the mass, in grams, of #3.4010^22# atoms #He#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="280591" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/jo-lle"><img alt="" class="" src="https://profilepictures.socratic.org/QLjj3UhKRDegWjG5OG8v_1712995393.jpeg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/jo-lle"> Joëlle </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-23T16:51:34" itemprop="dateCreated"> Jun 23, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.226 gram.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You can get to the answer in two steps:</p> <ol> <li>calculate: <mathjax>#3.4010^22#</mathjax> atoms = <mathjax>#color(red)x#</mathjax> mol ? <br/> using Avogadro's constant.</li> <li>calculate: <mathjax>#color(red)x#</mathjax> mol = <mathjax>#color(red)?#</mathjax> grams, <br/> using the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">atomic mass</a> of Helium.</li> </ol> <p><strong>Step 1</strong><br/> Avogadro's constant says that <mathjax>#1#</mathjax> mole of any atom contains <mathjax>#6.02210^23#</mathjax> atoms. In this case you have <mathjax>#3.4010^22#</mathjax> atoms:</p> <p><mathjax>#(3.4010^22 color(red)cancel(color(black)("atoms")))/ (6.02210^23 color(red)cancel(color(black)("atoms"))/"mol"#</mathjax> = <mathjax>#5.6510^-2 mol#</mathjax></p> <p><strong>Step 2</strong><br/> The atomic mass of helium (He) will give you the weight of one mole of this molecule: <mathjax>#1#</mathjax> mol = <mathjax>#4.00#</mathjax> gram:</p> <p><mathjax>#4.00 g/(color(red)cancel color(black)"mol") 5.6510^-2 color(red)cancel color(black)"mol"#</mathjax> = <mathjax>#0.226 g#</mathjax></p> <p>So the <mathjax>#3.4010^22#</mathjax> helium atoms weigh <mathjax>#color(red)(0.226) color(red) " gram"#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/280591" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 120838 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the mass, in grams, of #3.40*10^22# atoms #He#?	null
1,070	a8af0f6e-6ddd-11ea-b3e2-ccda262736ce	https://socratic.org/questions/how-many-grams-of-h-3po-4-are-produced-when-10-0-moles-of-water-react-with-an-ex	653.66 grams	start physical_unit 4 4 mass g qc_end physical_unit 11 11 8 9 mole qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Mass [OF] H3PO4 [IN] grams"}]	[{"type":"physical unit","value":"653.66 grams"}]	[{"type":"physical unit","value":"Mole [OF] water [=] \\pu{10.0 moles}"},{"type":"other","value":"an excess of P4O10."}]	<h1 class="questionTitle" itemprop="name">How many grams of #H_3PO_4# are produced when 10.0 moles of water react with an excess of #P_4O_10#?</h1>	null	653.66 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We'll first write the chemical equation for this reaction:</p> <p><mathjax>#"P"_4"O"_10(s) + 6"H"_2"O"(l) rarr 4"H"_3"PO"_4(aq)#</mathjax></p> <p>Let's now find the relative number of moles of phosphoric acid (<mathjax>#"H"_3"PO"_4#</mathjax>) using the coefficients of the equation, and the fact that <mathjax>#10.0#</mathjax> <mathjax>#"mol H"_2"O"#</mathjax> react:</p> <p><mathjax>#10.0cancel("mol H"_2"O")((4color(white)(l)"mol H"_3"PO"_4)/(6cancel("mol H"_2"O"))) = color(red)(6.67#</mathjax> <mathjax>#color(red)("mol H"_3"PO"_4#</mathjax></p> <p>Now, using the molar mass of <mathjax>#"H"_3"PO"_4#</mathjax> (calculated to be <mathjax>#98.00#</mathjax> <mathjax>#"g/mol"#</mathjax>), let's find the theoretical mass of phosphoric acid produced:</p> <p><mathjax>#color(red)(6.67)color(white)(l)cancel(color(red)("mol H"_3"PO"_4))((98.00color(white)(l)"g H"_3"PO"_4)/(1cancel("mol H"_3"PO"_4))) = color(blue)(653#</mathjax> <mathjax>#color(blue)("mol H"_3"PO"_4#</mathjax></p> <p>Thus, if the reaction goes to completion, there will be a yield of <mathjax>#color(blue)(653#</mathjax> <mathjax>#sfcolor(blue)("grams of phosphoric acid"#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#653#</mathjax> <mathjax>#"g H"_3"PO"_4#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We'll first write the chemical equation for this reaction:</p> <p><mathjax>#"P"_4"O"_10(s) + 6"H"_2"O"(l) rarr 4"H"_3"PO"_4(aq)#</mathjax></p> <p>Let's now find the relative number of moles of phosphoric acid (<mathjax>#"H"_3"PO"_4#</mathjax>) using the coefficients of the equation, and the fact that <mathjax>#10.0#</mathjax> <mathjax>#"mol H"_2"O"#</mathjax> react:</p> <p><mathjax>#10.0cancel("mol H"_2"O")((4color(white)(l)"mol H"_3"PO"_4)/(6cancel("mol H"_2"O"))) = color(red)(6.67#</mathjax> <mathjax>#color(red)("mol H"_3"PO"_4#</mathjax></p> <p>Now, using the molar mass of <mathjax>#"H"_3"PO"_4#</mathjax> (calculated to be <mathjax>#98.00#</mathjax> <mathjax>#"g/mol"#</mathjax>), let's find the theoretical mass of phosphoric acid produced:</p> <p><mathjax>#color(red)(6.67)color(white)(l)cancel(color(red)("mol H"_3"PO"_4))((98.00color(white)(l)"g H"_3"PO"_4)/(1cancel("mol H"_3"PO"_4))) = color(blue)(653#</mathjax> <mathjax>#color(blue)("mol H"_3"PO"_4#</mathjax></p> <p>Thus, if the reaction goes to completion, there will be a yield of <mathjax>#color(blue)(653#</mathjax> <mathjax>#sfcolor(blue)("grams of phosphoric acid"#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many grams of #H_3PO_4# are produced when 10.0 moles of water react with an excess of #P_4O_10#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="443652" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/mrtas"><img alt="" class="" src="https://profilepictures.socratic.org/HY14X7r4S6AyDQgK2gwQ_IMG_0062.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/mrtas"> Nathan L. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-23T21:27:27" itemprop="dateCreated"> Jun 23, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#653#</mathjax> <mathjax>#"g H"_3"PO"_4#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We'll first write the chemical equation for this reaction:</p> <p><mathjax>#"P"_4"O"_10(s) + 6"H"_2"O"(l) rarr 4"H"_3"PO"_4(aq)#</mathjax></p> <p>Let's now find the relative number of moles of phosphoric acid (<mathjax>#"H"_3"PO"_4#</mathjax>) using the coefficients of the equation, and the fact that <mathjax>#10.0#</mathjax> <mathjax>#"mol H"_2"O"#</mathjax> react:</p> <p><mathjax>#10.0cancel("mol H"_2"O")((4color(white)(l)"mol H"_3"PO"_4)/(6cancel("mol H"_2"O"))) = color(red)(6.67#</mathjax> <mathjax>#color(red)("mol H"_3"PO"_4#</mathjax></p> <p>Now, using the molar mass of <mathjax>#"H"_3"PO"_4#</mathjax> (calculated to be <mathjax>#98.00#</mathjax> <mathjax>#"g/mol"#</mathjax>), let's find the theoretical mass of phosphoric acid produced:</p> <p><mathjax>#color(red)(6.67)color(white)(l)cancel(color(red)("mol H"_3"PO"_4))((98.00color(white)(l)"g H"_3"PO"_4)/(1cancel("mol H"_3"PO"_4))) = color(blue)(653#</mathjax> <mathjax>#color(blue)("mol H"_3"PO"_4#</mathjax></p> <p>Thus, if the reaction goes to completion, there will be a yield of <mathjax>#color(blue)(653#</mathjax> <mathjax>#sfcolor(blue)("grams of phosphoric acid"#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/443652" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" 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1,071	ad1fc9be-6ddd-11ea-9e60-ccda262736ce	https://socratic.org/questions/the-volume-of-a-gas-is-27-5-ml-at-22-c-and-740-mmhg-what-will-be-its-volume-at-1	26.31 mL	start physical_unit 4 4 volume ml qc_end physical_unit 4 4 6 7 volume qc_end physical_unit 4 4 9 10 temperature qc_end physical_unit 4 4 12 13 pressure qc_end physical_unit 4 4 20 21 temperature qc_end physical_unit 4 4 23 24 pressure qc_end end	[{"type":"physical unit","value":"Volume2 [OF] the gas [IN] mL"}]	[{"type":"physical unit","value":"26.31 mL"}]	[{"type":"physical unit","value":"Volume1 [OF] the gas [=] \\pu{27.5 mL}"},{"type":"physical unit","value":"Temperature1 [OF] the gas [=] \\pu{22 ℃}"},{"type":"physical unit","value":"Pressure1 [OF] the gas [=] \\pu{740 mmHg}"},{"type":"physical unit","value":"Temperature2 [OF] the gas [=] \\pu{15.0 ℃}"},{"type":"physical unit","value":"Pressure2 [OF] the gas [=] \\pu{755 mmHg}"}]	<h1 class="questionTitle" itemprop="name">The volume of a gas is 27.5 mL at 22°C and 740 mmHg. What will be its volume at 15.0°C and 755 mmHg?</h1>	null	26.31 mL	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This question involves the <a href="https://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">combined gas law</a>. The equation to use is:</p> <p><img alt="http://www.virtualhomeschoolgroup.com" src="https://d2jmvrsizmvf4x.cloudfront.net/p8ERNcXfTsWqombPbkwC_images"/> </p> <p>When working with <a href="https://socratic.org/chemistry/the-behavior-of-gases/gas-laws">gas laws</a>, the temperature is always in Kelvins. To get Kelvins from a Celsius temperature, add 273.15 to the Celsius temperature.</p> <p>Determine what is known and what is unknown.</p> <p><strong>Known</strong><br/> <mathjax>#P_1="740 mmHg"#</mathjax><br/> <mathjax>#V_1="27.5 mL"#</mathjax><br/> <mathjax>#T_1="22"^@"C"+"273.15"="295 K"#</mathjax><br/> <mathjax>#P_2="755 mmHg"#</mathjax><br/> <mathjax>#T_2="15.0"^@"C"+"273.15"="288 K"#</mathjax></p> <p><strong>Unknown</strong><br/> <mathjax>#V_2#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#V_2#</mathjax>. Substitute the known values into the equation and solve.</p> <p><mathjax>#(P_1V_1)/T_1=(P_2V_2)/T_2#</mathjax></p> <p><mathjax>#V_2=(P_1V_1T_2)/(T_1P_2)#</mathjax></p> <p><mathjax>#V_2=(740"mmHg"xx27.5"mL"xx288"K")/(295"K"xx755"mmHg")#</mathjax><mathjax>#=#</mathjax><mathjax>#~~26 "mL"#</mathjax> rounded to two significant figures</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The new volume will be <mathjax>#~~26 "mL"#</mathjax> rounded to two <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This question involves the <a href="https://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">combined gas law</a>. The equation to use is:</p> <p><img alt="http://www.virtualhomeschoolgroup.com" src="https://d2jmvrsizmvf4x.cloudfront.net/p8ERNcXfTsWqombPbkwC_images"/> </p> <p>When working with <a href="https://socratic.org/chemistry/the-behavior-of-gases/gas-laws">gas laws</a>, the temperature is always in Kelvins. To get Kelvins from a Celsius temperature, add 273.15 to the Celsius temperature.</p> <p>Determine what is known and what is unknown.</p> <p><strong>Known</strong><br/> <mathjax>#P_1="740 mmHg"#</mathjax><br/> <mathjax>#V_1="27.5 mL"#</mathjax><br/> <mathjax>#T_1="22"^@"C"+"273.15"="295 K"#</mathjax><br/> <mathjax>#P_2="755 mmHg"#</mathjax><br/> <mathjax>#T_2="15.0"^@"C"+"273.15"="288 K"#</mathjax></p> <p><strong>Unknown</strong><br/> <mathjax>#V_2#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#V_2#</mathjax>. Substitute the known values into the equation and solve.</p> <p><mathjax>#(P_1V_1)/T_1=(P_2V_2)/T_2#</mathjax></p> <p><mathjax>#V_2=(P_1V_1T_2)/(T_1P_2)#</mathjax></p> <p><mathjax>#V_2=(740"mmHg"xx27.5"mL"xx288"K")/(295"K"xx755"mmHg")#</mathjax><mathjax>#=#</mathjax><mathjax>#~~26 "mL"#</mathjax> rounded to two significant figures</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">The volume of a gas is 27.5 mL at 22°C and 740 mmHg. What will be its volume at 15.0°C and 755 mmHg?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/gas-laws" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Laws</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="321159" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-10-13T04:22:00" itemprop="dateCreated"> Oct 13, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The new volume will be <mathjax>#~~26 "mL"#</mathjax> rounded to two <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This question involves the <a href="https://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">combined gas law</a>. The equation to use is:</p> <p><img alt="http://www.virtualhomeschoolgroup.com" src="https://d2jmvrsizmvf4x.cloudfront.net/p8ERNcXfTsWqombPbkwC_images"/> </p> <p>When working with <a href="https://socratic.org/chemistry/the-behavior-of-gases/gas-laws">gas laws</a>, the temperature is always in Kelvins. To get Kelvins from a Celsius temperature, add 273.15 to the Celsius temperature.</p> <p>Determine what is known and what is unknown.</p> <p><strong>Known</strong><br/> <mathjax>#P_1="740 mmHg"#</mathjax><br/> <mathjax>#V_1="27.5 mL"#</mathjax><br/> <mathjax>#T_1="22"^@"C"+"273.15"="295 K"#</mathjax><br/> <mathjax>#P_2="755 mmHg"#</mathjax><br/> <mathjax>#T_2="15.0"^@"C"+"273.15"="288 K"#</mathjax></p> <p><strong>Unknown</strong><br/> <mathjax>#V_2#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#V_2#</mathjax>. Substitute the known values into the equation and solve.</p> <p><mathjax>#(P_1V_1)/T_1=(P_2V_2)/T_2#</mathjax></p> <p><mathjax>#V_2=(P_1V_1T_2)/(T_1P_2)#</mathjax></p> <p><mathjax>#V_2=(740"mmHg"xx27.5"mL"xx288"K")/(295"K"xx755"mmHg")#</mathjax><mathjax>#=#</mathjax><mathjax>#~~26 "mL"#</mathjax> rounded to two significant figures</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/321159" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-boyles-law-relate-to-breathing"> How does Boyle's law relate to breathing? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/in-avogadro-s-law-what-would-happen-to-v-if-n-is-increased-decreased-and-what-wo"> In Avogadro's Law what would happen to V if N is increased/decreased? 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What will be its volume at 15.0°C and 755 mmHg?	null
1,072	a9199c34-6ddd-11ea-8a32-ccda262736ce	https://socratic.org/questions/how-do-i-calculate-the-ph-of-the-buffer-solution-when-1-00-g-of-potassium-ethano	4.77	start physical_unit 7 9 ph none qc_end physical_unit 14 15 11 12 mass qc_end physical_unit 24 25 19 20 volume qc_end physical_unit 24 25 22 23 molarity qc_end physical_unit 24 25 28 30 ka qc_end end	[{"type":"physical unit","value":"pH [OF] the buffer solution"}]	[{"type":"physical unit","value":"4.77"}]	[{"type":"physical unit","value":"Mass [OF] potassium ethanoate [=] \\pu{1.00 g}"},{"type":"physical unit","value":"Volume [OF] ethanoic acid [=] \\pu{50.0 cm^3 }"},{"type":"physical unit","value":"Molarity [OF] ethanoic acid [=] \\pu{0.20 mol/dm^3}"},{"type":"physical unit","value":"Ka [OF] ethanoic acid [=] \\pu{1.74 × 10^(−5)}"}]	<h1 class="questionTitle" itemprop="name">How do I calculate the #"pH"# of the buffer solution when #1.00# #"g"# of potassium ethanoate is dissolved in #50.0# #"cm"^3# of #0.20# #"mol"# #"dm"^-3# ethanoic acid (#"K"_"a"=1.74xx10^-5# #"mol"# #"dm"^-3#)?</h1>	null	4.77	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#rho#</mathjax>(potassium ethanoate) <mathjax>#=1/(50divide1000) =20#</mathjax> <mathjax>#"g"#</mathjax> <mathjax>#"dm"^-3#</mathjax></p> <p><mathjax>#rho="c"xx"Mr"therefore#</mathjax></p> <p>[potassium ethanoate]<mathjax>#=20/(39.1+24+32+3)=0.20387#</mathjax></p> <p><mathjax>#["H"^+]="K"_"a"xx[["HA"]]/[["A"^-]]=1.74xx10^-5xx0.2/0.20387=1.7xx10^-5#</mathjax></p> <p><mathjax>#"pH"=-log(1.7xx10^-5)=4.77#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"pH"=4.77#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#rho#</mathjax>(potassium ethanoate) <mathjax>#=1/(50divide1000) =20#</mathjax> <mathjax>#"g"#</mathjax> <mathjax>#"dm"^-3#</mathjax></p> <p><mathjax>#rho="c"xx"Mr"therefore#</mathjax></p> <p>[potassium ethanoate]<mathjax>#=20/(39.1+24+32+3)=0.20387#</mathjax></p> <p><mathjax>#["H"^+]="K"_"a"xx[["HA"]]/[["A"^-]]=1.74xx10^-5xx0.2/0.20387=1.7xx10^-5#</mathjax></p> <p><mathjax>#"pH"=-log(1.7xx10^-5)=4.77#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do I calculate the #"pH"# of the buffer solution when #1.00# #"g"# of potassium ethanoate is dissolved in #50.0# #"cm"^3# of #0.20# #"mol"# #"dm"^-3# ethanoic acid (#"K"_"a"=1.74xx10^-5# #"mol"# #"dm"^-3#)?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#reactions-in-solution" itemprop="url"> <span class="breadcrumb" itemprop="title">Reactions in Solution</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/reactions-in-solution/buffer-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">Buffer Calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="409368" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/abdur-r"><img alt="" class="" src="https://profilepictures.socratic.org/YXIUDMM0SoZAxTdY3kn6_niagara_falls_fog_water_height_6376_3840x2160.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/abdur-r"> Monzur R. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-19T15:38:25" itemprop="dateCreated"> Apr 19, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"pH"=4.77#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#rho#</mathjax>(potassium ethanoate) <mathjax>#=1/(50divide1000) =20#</mathjax> <mathjax>#"g"#</mathjax> <mathjax>#"dm"^-3#</mathjax></p> <p><mathjax>#rho="c"xx"Mr"therefore#</mathjax></p> <p>[potassium ethanoate]<mathjax>#=20/(39.1+24+32+3)=0.20387#</mathjax></p> <p><mathjax>#["H"^+]="K"_"a"xx[["HA"]]/[["A"^-]]=1.74xx10^-5xx0.2/0.20387=1.7xx10^-5#</mathjax></p> <p><mathjax>#"pH"=-log(1.7xx10^-5)=4.77#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/409368" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-buffer-solutions-used"> How are buffer solutions used? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-buffer-capacity"> How do you calculate buffer capacity? </a> </div> </li> <li class="relatedQuestionItem"> <div 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href="/chemistry/reactions-in-solution/buffer-calculations"> See all questions in Buffer Calculations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3414 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How do I calculate the #"pH"# of the buffer solution when #1.00# #"g"# of potassium ethanoate is dissolved in #50.0# #"cm"^3# of #0.20# #"mol"# #"dm"^-3# ethanoic acid (#"K"_"a"=1.74xx10^-5# #"mol"# #"dm"^-3#)?	null
1,073	a94bd56f-6ddd-11ea-b630-ccda262736ce	https://socratic.org/questions/59656af511ef6b0e67eaa21e	1.24 moles	start physical_unit 4 4 mole mol qc_end chemical_equation 4 15 qc_end physical_unit 7 7 26 27 mass qc_end end	[{"type":"physical unit","value":"Mole [OF] C6H6OS [IN] moles"}]	[{"type":"physical unit","value":"1.24 moles"}]	[{"type":"chemical equation","value":"C6H6OS + 8 O2 -> 6 CO2 + 3 H2O + SO2"},{"type":"physical unit","value":"Mass [OF] O2 [=] \\pu{317 g}"}]	<h1 class="questionTitle" itemprop="name">In the chemical reaction #"C"_6"H"_6"OS" + "8O"_2"##rarr##"6CO"_2 + "3H"_2"O" + "SO"_2#, how many moles of #"C"_6"H"_6"OS"# are needed to react with #"317 g O"_2"#? </h1>	null	1.24 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>Balanced equation:</strong></p> <p><mathjax>#"C"_6"H"_6"OS" + "8O"_2"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"6CO"_2 + "3H"_2"O" + "SO"_2#</mathjax></p> <p><strong>First convert the given mass of <mathjax>#"O"_2#</mathjax> to moles. The molar mass of <mathjax>#"O"_2#</mathjax> is <mathjax>#"31.998 g/mol"#</mathjax>.</strong></p> <p><mathjax>#317color(red)cancel(color(black)("g O"_2))xx(1"mol O"_2)/(31.998color(red)cancel(color(black)("g O"_2)))="9.91 mol O"_2#</mathjax></p> <p><strong>Determine the moles <mathjax>#"C"_6"H"_6"OS"#</mathjax> that will react with <mathjax>#"317 g O"_2"#</mathjax> by multiplying moles of <mathjax>#"O"_2#</mathjax> by <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio between <mathjax>#"C"_6"H"_6"OS"#</mathjax> and <mathjax>#"O"_2#</mathjax> from the balanced equation so that moles <mathjax>#"O"_2#</mathjax> are canceled.</strong> </p> <p><mathjax>#9.91color(red)cancel(color(black)("mol O"_2))xx(1"mol C"_6"H"_6"OS")/(8color(red)cancel(color(black)("mol O"_2)))="1.24 mol C"_6"H"_6"OS"#</mathjax> (rounded to three sig figs)</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"1.24 mol C"_6"H"_6"OS"#</mathjax> are needed to react with <mathjax>#"317 g O"_2#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>Balanced equation:</strong></p> <p><mathjax>#"C"_6"H"_6"OS" + "8O"_2"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"6CO"_2 + "3H"_2"O" + "SO"_2#</mathjax></p> <p><strong>First convert the given mass of <mathjax>#"O"_2#</mathjax> to moles. The molar mass of <mathjax>#"O"_2#</mathjax> is <mathjax>#"31.998 g/mol"#</mathjax>.</strong></p> <p><mathjax>#317color(red)cancel(color(black)("g O"_2))xx(1"mol O"_2)/(31.998color(red)cancel(color(black)("g O"_2)))="9.91 mol O"_2#</mathjax></p> <p><strong>Determine the moles <mathjax>#"C"_6"H"_6"OS"#</mathjax> that will react with <mathjax>#"317 g O"_2"#</mathjax> by multiplying moles of <mathjax>#"O"_2#</mathjax> by <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio between <mathjax>#"C"_6"H"_6"OS"#</mathjax> and <mathjax>#"O"_2#</mathjax> from the balanced equation so that moles <mathjax>#"O"_2#</mathjax> are canceled.</strong> </p> <p><mathjax>#9.91color(red)cancel(color(black)("mol O"_2))xx(1"mol C"_6"H"_6"OS")/(8color(red)cancel(color(black)("mol O"_2)))="1.24 mol C"_6"H"_6"OS"#</mathjax> (rounded to three sig figs)</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">In the chemical reaction #"C"_6"H"_6"OS" + "8O"_2"##rarr##"6CO"_2 + "3H"_2"O" + "SO"_2#, how many moles of #"C"_6"H"_6"OS"# are needed to react with #"317 g O"_2"#? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="450604" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-07-12T01:18:31" itemprop="dateCreated"> Jul 12, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"1.24 mol C"_6"H"_6"OS"#</mathjax> are needed to react with <mathjax>#"317 g O"_2#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>Balanced equation:</strong></p> <p><mathjax>#"C"_6"H"_6"OS" + "8O"_2"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"6CO"_2 + "3H"_2"O" + "SO"_2#</mathjax></p> <p><strong>First convert the given mass of <mathjax>#"O"_2#</mathjax> to moles. The molar mass of <mathjax>#"O"_2#</mathjax> is <mathjax>#"31.998 g/mol"#</mathjax>.</strong></p> <p><mathjax>#317color(red)cancel(color(black)("g O"_2))xx(1"mol O"_2)/(31.998color(red)cancel(color(black)("g O"_2)))="9.91 mol O"_2#</mathjax></p> <p><strong>Determine the moles <mathjax>#"C"_6"H"_6"OS"#</mathjax> that will react with <mathjax>#"317 g O"_2"#</mathjax> by multiplying moles of <mathjax>#"O"_2#</mathjax> by <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio between <mathjax>#"C"_6"H"_6"OS"#</mathjax> and <mathjax>#"O"_2#</mathjax> from the balanced equation so that moles <mathjax>#"O"_2#</mathjax> are canceled.</strong> </p> <p><mathjax>#9.91color(red)cancel(color(black)("mol O"_2))xx(1"mol C"_6"H"_6"OS")/(8color(red)cancel(color(black)("mol O"_2)))="1.24 mol C"_6"H"_6"OS"#</mathjax> (rounded to three sig figs)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/450604" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What is stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ab82402bf342f48d93ac6"> Question #93ac6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-we-study-stoichiometry"> Why do we study stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-naoh-is-produced-from-1-20-x-102-grams-of-na2o-na2o-h2o-2-naoh"> How many grams of NaOH is produced from #1.20 x 10^2# grams of #Na_2O#? #Na_2O + H_2O -> 2NaOH# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-na2o-are-required-to-produce-1-60-x-102-grams-of-naoh-na2o-h2o"> How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? 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1,074	a8f000a6-6ddd-11ea-a867-ccda262736ce	https://socratic.org/questions/a-sample-of-gas-x-occupies-10-m-3-at-the-pressure-of-120-kpa-if-the-volume-of-th	400 kPa	start physical_unit 29 30 pressure kpa qc_end physical_unit 1 4 6 7 volume qc_end physical_unit 1 4 12 13 pressure qc_end physical_unit 18 19 21 22 volume qc_end end	[{"type":"physical unit","value":"Pressure2 [OF] the gas [IN] kPa"}]	[{"type":"physical unit","value":"400 kPa"}]	[{"type":"physical unit","value":"Volume1 [OF] gas X sample [=] \\pu{10 m^3}"},{"type":"physical unit","value":"Pressure1 [OF] gas X sample [=] \\pu{120 kPa}"},{"type":"physical unit","value":"Volume2 [OF] the sample [=] \\pu{3 m^3}"}]	<h1 class="questionTitle" itemprop="name">A sample of gas X occupies 10#m^3# at the pressure of 120 kPa. If the volume of the sample is 3#m^3#, what is the new pressure of the gas? </h1>	null	400 kPa	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To solve this problem use <a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's law</a>.</p> <p>As the volume decreases the pressure increases. This means that the new pressure will be greater than the original pressure. </p> <p><mathjax>#V_1 xx P_1 = V_2 xx P_2#</mathjax> </p> <p><mathjax># V_1 = 10m^3#</mathjax><br/> <mathjax># P_1 = 120 kPa#</mathjax><br/> <mathjax>#V_2 = 3m^3#</mathjax> <br/> <mathjax># P_2 = ?#</mathjax></p> <p>Putting these values into the equation gives.</p> <p><mathjax># 10m^3 xx 120 kPa = 3m^3 xx ?#</mathjax> </p> <p>Dividing both sides by <mathjax># 3m^3#</mathjax> gives </p> <p><mathjax># (10m^3 xx 120kPa)/(3m^3) = (3m^3 xx ?)/(3m^3)#</mathjax> This gives </p> <p>400 kPa = ?</p> <p>The unknown is 400 kPa.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The new pressure is 400 kPa </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To solve this problem use <a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's law</a>.</p> <p>As the volume decreases the pressure increases. This means that the new pressure will be greater than the original pressure. </p> <p><mathjax>#V_1 xx P_1 = V_2 xx P_2#</mathjax> </p> <p><mathjax># V_1 = 10m^3#</mathjax><br/> <mathjax># P_1 = 120 kPa#</mathjax><br/> <mathjax>#V_2 = 3m^3#</mathjax> <br/> <mathjax># P_2 = ?#</mathjax></p> <p>Putting these values into the equation gives.</p> <p><mathjax># 10m^3 xx 120 kPa = 3m^3 xx ?#</mathjax> </p> <p>Dividing both sides by <mathjax># 3m^3#</mathjax> gives </p> <p><mathjax># (10m^3 xx 120kPa)/(3m^3) = (3m^3 xx ?)/(3m^3)#</mathjax> This gives </p> <p>400 kPa = ?</p> <p>The unknown is 400 kPa.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A sample of gas X occupies 10#m^3# at the pressure of 120 kPa. If the volume of the sample is 3#m^3#, what is the new pressure of the gas? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/gas-pressure" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Pressure</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="367243" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/david-drayer"><img alt="" class="" src="https://graph.facebook.com/10206723679871989/picture?height=50&width=50" title=""/></a> <a class="secondContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/david-drayer"> David Drayer </a>·<a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-01-21T03:16:43" itemprop="dateCreated"> Jan 21, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The new pressure is 400 kPa </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To solve this problem use <a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's law</a>.</p> <p>As the volume decreases the pressure increases. This means that the new pressure will be greater than the original pressure. </p> <p><mathjax>#V_1 xx P_1 = V_2 xx P_2#</mathjax> </p> <p><mathjax># V_1 = 10m^3#</mathjax><br/> <mathjax># P_1 = 120 kPa#</mathjax><br/> <mathjax>#V_2 = 3m^3#</mathjax> <br/> <mathjax># P_2 = ?#</mathjax></p> <p>Putting these values into the equation gives.</p> <p><mathjax># 10m^3 xx 120 kPa = 3m^3 xx ?#</mathjax> </p> <p>Dividing both sides by <mathjax># 3m^3#</mathjax> gives </p> <p><mathjax># (10m^3 xx 120kPa)/(3m^3) = (3m^3 xx ?)/(3m^3)#</mathjax> This gives </p> <p>400 kPa = ?</p> <p>The unknown is 400 kPa.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/367243" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-gas-pressure-be-changed"> How can gas pressure be changed? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-you-increase-gas-pressure-in-a-container"> How can you increase gas pressure in a container? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-gas-pressure-created"> How is gas pressure created? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-does-gas-pressure-increase-when-temperature-increases"> Why does gas pressure increase when temperature increases? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-gas-pressure-zero-at-absolute-zero"> Why is gas pressure zero at absolute zero? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-does-gas-pressure-increase-with-temperature"> Why does gas pressure increase with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-there-no-gas-pressure-in-a-vacuum"> Why is there no gas pressure in a vacuum? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-total-gas-pressure-in-a-sealed-flask-that-contains-oxygen-at-a-parti-1"> What is the total gas pressure in a sealed flask that contains oxygen at a partial pressure of... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-the-absolute-pressure-of-a-gas-is-550-280-kpa-what-is-its-gage-pressure"> If the absolute pressure of a gas is 550.280 kPa, what is its gage pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-a-gas-sample-occupies-4-2-l-at-a-pressure-of-101-kpa-what-volume-will-it-occu"> If a gas sample occupies 4.2 L at a pressure of 101 kPa. What volume will it occupy if the... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/gas-pressure"> See all questions in Gas Pressure </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 6898 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A sample of gas X occupies 10#m^3# at the pressure of 120 kPa. If the volume of the sample is 3#m^3#, what is the new pressure of the gas?	null
1,075	ab19e728-6ddd-11ea-9f60-ccda262736ce	https://socratic.org/questions/what-mass-of-kc-2h-3o-2-is-produced-when-10-0-l-co-2-is-produced	86.37 g	start physical_unit 3 3 mass g qc_end physical_unit 9 9 7 8 volume qc_end substance 13 14 qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Mass [OF] KC2H3O2 [IN] g"}]	[{"type":"physical unit","value":"86.37 g"}]	[{"type":"physical unit","value":"Volume [OF] CO2 [=] \\pu{10.0 L}"},{"type":"substance name","value":"Potassium carbonate"},{"type":"other","value":"Excess acetic acid."}]	<h1 class="questionTitle" itemprop="name">What mass of #KC_2H_3O_2# is produced when 10.0 L #CO_2# is produced from potassium carbonate and excess acetic acid?</h1>	null	86.37 g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The reaction equation is:</p> <p><mathjax>#2CH_3COOH + K_2CO_3 -> 2KC_2H_3O_2 + CO_2 + H_2O#</mathjax></p> <p>from which you can see that <strong>two</strong> units of <em>potassium acetate</em> <mathjax>#(KC_2H_3O_2#</mathjax>) are generated together with <strong>one</strong> mole of <mathjax>#CO_2#</mathjax>.<br/> Hence, provided one mol of <mathjax>#CO_2#</mathjax> at S.T.P. (standard temperature and pressure: T = 0 °C, P = 1 bar) have an approximate volume of 22.7 liters, the volume of 10 L would correspond to: <mathjax>#"10 L"/"22.7 L/mol" = "0.44 moles"#</mathjax>.</p> <p>Then the chemical amount of potassium acetate are 0.88 mol. <br/> The molar mass of potassium acetate is 98.15 g/mol.</p> <p>So, the mass of potassium acetate is <mathjax>#98.15 "g/mol" * 0.88 "moles" = 86 g#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0,88 moles of <mathjax>#KC_2H_3O_2#</mathjax>, that is 84 grams, are produced from 0.44 moles (10 L @ S.T.P.) of <mathjax>#CO_2#</mathjax>. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The reaction equation is:</p> <p><mathjax>#2CH_3COOH + K_2CO_3 -> 2KC_2H_3O_2 + CO_2 + H_2O#</mathjax></p> <p>from which you can see that <strong>two</strong> units of <em>potassium acetate</em> <mathjax>#(KC_2H_3O_2#</mathjax>) are generated together with <strong>one</strong> mole of <mathjax>#CO_2#</mathjax>.<br/> Hence, provided one mol of <mathjax>#CO_2#</mathjax> at S.T.P. (standard temperature and pressure: T = 0 °C, P = 1 bar) have an approximate volume of 22.7 liters, the volume of 10 L would correspond to: <mathjax>#"10 L"/"22.7 L/mol" = "0.44 moles"#</mathjax>.</p> <p>Then the chemical amount of potassium acetate are 0.88 mol. <br/> The molar mass of potassium acetate is 98.15 g/mol.</p> <p>So, the mass of potassium acetate is <mathjax>#98.15 "g/mol" * 0.88 "moles" = 86 g#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What mass of #KC_2H_3O_2# is produced when 10.0 L #CO_2# is produced from potassium carbonate and excess acetic acid?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="225249" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/alfredo-t"><img alt="" class="" src="https://profilepictures.socratic.org/x1lv0EJXTqJyzJeKKIjz_tW08y6eJQe6cqhoJ3PGb_io_peony_22-06-14_rid2.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/alfredo-t"> Alfredo T. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-02-12T17:26:22" itemprop="dateCreated"> Feb 12, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0,88 moles of <mathjax>#KC_2H_3O_2#</mathjax>, that is 84 grams, are produced from 0.44 moles (10 L @ S.T.P.) of <mathjax>#CO_2#</mathjax>. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The reaction equation is:</p> <p><mathjax>#2CH_3COOH + K_2CO_3 -> 2KC_2H_3O_2 + CO_2 + H_2O#</mathjax></p> <p>from which you can see that <strong>two</strong> units of <em>potassium acetate</em> <mathjax>#(KC_2H_3O_2#</mathjax>) are generated together with <strong>one</strong> mole of <mathjax>#CO_2#</mathjax>.<br/> Hence, provided one mol of <mathjax>#CO_2#</mathjax> at S.T.P. (standard temperature and pressure: T = 0 °C, P = 1 bar) have an approximate volume of 22.7 liters, the volume of 10 L would correspond to: <mathjax>#"10 L"/"22.7 L/mol" = "0.44 moles"#</mathjax>.</p> <p>Then the chemical amount of potassium acetate are 0.88 mol. <br/> The molar mass of potassium acetate is 98.15 g/mol.</p> <p>So, the mass of potassium acetate is <mathjax>#98.15 "g/mol" * 0.88 "moles" = 86 g#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/225249" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What is stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ab82402bf342f48d93ac6"> Question #93ac6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-we-study-stoichiometry"> Why do we study stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-naoh-is-produced-from-1-20-x-102-grams-of-na2o-na2o-h2o-2-naoh"> How many grams of NaOH is produced from #1.20 x 10^2# grams of #Na_2O#? #Na_2O + H_2O -> 2NaOH# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-na2o-are-required-to-produce-1-60-x-102-grams-of-naoh-na2o-h2o"> How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? 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1,076	ac0476ac-6ddd-11ea-a2f5-ccda262736ce	https://socratic.org/questions/how-much-heat-is-released-when-88-2-g-of-water-cools-from-33-8-c-to-12-9-c	7716.39 J	start physical_unit 9 9 heat_energy j qc_end physical_unit 9 9 6 7 mass qc_end physical_unit 9 9 12 13 temperature qc_end physical_unit 9 9 15 16 temperature qc_end end	[{"type":"physical unit","value":"Released heat [OF] water [IN] J"}]	[{"type":"physical unit","value":"7716.39 J"}]	[{"type":"physical unit","value":"Mass [OF] water [=] \\pu{88.2 g}"},{"type":"physical unit","value":"Temperature1 [OF] water [=] \\pu{33.8 ℃}"},{"type":"physical unit","value":"Temperature2 [OF] water [=] \\pu{12.9 ℃}"}]	<h1 class="questionTitle" itemprop="name">How much heat is released when 88.2 g of water cools from 33.8°C to 12.9°C?</h1>	null	7716.39 J	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The specific heat of water is high as specific heats go. Part of the reason is that water is a very dense substance. </p> <p>Heat transferred <mathjax>#=#</mathjax> <mathjax>#DeltaTxxC_Pxx"mass#</mathjax></p> <p><mathjax>#=#</mathjax> <mathjax>#-20.9Kxx88.2gxx4.186Jg^-1*K^-1#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> of water is <mathjax>#4.186Jg^-1K^-1#</mathjax>. This should have been quoted with the question. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The specific heat of water is high as specific heats go. Part of the reason is that water is a very dense substance. </p> <p>Heat transferred <mathjax>#=#</mathjax> <mathjax>#DeltaTxxC_Pxx"mass#</mathjax></p> <p><mathjax>#=#</mathjax> <mathjax>#-20.9Kxx88.2gxx4.186Jg^-1K^-1#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How much heat is released when 88.2 g of water cools from 33.8°C to 12.9°C?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/calorimetry" itemprop="url"> <span class="breadcrumb" itemprop="title">Calorimetry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="280002" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-22T05:26:43" itemprop="dateCreated"> Jun 22, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> of water is <mathjax>#4.186Jg^-1K^-1#</mathjax>. This should have been quoted with the question. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The specific heat of water is high as specific heats go. Part of the reason is that water is a very dense substance. </p> <p>Heat transferred <mathjax>#=#</mathjax> <mathjax>#DeltaTxxC_Pxx"mass#</mathjax></p> <p><mathjax>#=#</mathjax> <mathjax>#-20.9Kxx88.2gxx4.186Jg^-1K^-1#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/280002" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-differential-scanning-in-calorimetry-work"> How does differential scanning in calorimetry work? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-read-differential-scanning-in-calorimetry"> What information do you get from a differential scanning calorimetry plot? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-measure-calorimetry"> How do you measure calorimetry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531d304102bf341e75b962a7"> Question #962a7 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5335021802bf344ae911dfc5"> Question #1dfc5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/533668f502bf34572c341af6"> Question #41af6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-definition-of-calorimetry"> What is calorimetry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-differential-scanning-calorimeter"> What is a differential scanning calorimeter? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-a-calorimeter-measure-energy"> How can a calorimeter measure energy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-calorimeters-made-of"> What are calorimeters made of? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/calorimetry"> See all questions in Calorimetry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1234 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How much heat is released when 88.2 g of water cools from 33.8°C to 12.9°C?	null
1,077	a9d566ba-6ddd-11ea-bb38-ccda262736ce	https://socratic.org/questions/a-piece-of-gold-initially-at-a-temperature-of-25-1-c-absorbs-675-j-of-heat-raisi	165.86 g	start physical_unit 38 39 mass g qc_end physical_unit 3 3 29 32 specific_heat qc_end end	[{"type":"physical unit","value":"Mass [OF] the sample [IN] g"}]	[{"type":"physical unit","value":"165.86 g"}]	[{"type":"physical unit","value":"Temperature1 [OF] the gold piece [=] \\pu{25.1 ℃}"},{"type":"physical unit","value":"Temperature2 [OF] the gold piece [=] \\pu{57.4 ℃}"},{"type":"physical unit","value":"Absorbed heat [OF] the gold piece [=] \\pu{675 J}"},{"type":"physical unit","value":"Specific heat [OF] gold [=] \\pu{0.126 J/(g * ℃)}"}]	<h1 class="questionTitle" itemprop="name">A piece of gold initially at a temperature of 25.1 °C absorbs 675 J of heat, raising its temperature to 57.4 °C. Assuming the specific heat of gold is 0.126 J/(g°C), what is the mass of the sample?</h1>	null	165.86 g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The key here is the <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> of gold, which is said to be equal to </p> <blockquote> <p><mathjax>#c_"gold" = "0.126 J g"^(-1)""^@"C"^(-1)#</mathjax></p> </blockquote> <p>This tells you that in order to increase the temperature of <mathjax>#"1 g"#</mathjax> of gold by <mathjax>#1^@"C"#</mathjax>, you need to provide it with <mathjax>#"0.126 J"#</mathjax> of heat.</p> <p>In your case, the temperature increases from <mathjax>#25.1^@"C"#</mathjax> to <mathjax>#57.4^@"C"#</mathjax>, which implies that it changes by</p> <blockquote> <p><mathjax>#57.4^@"C" - 25.1^@"C" = 32.3^@"C"#</mathjax></p> </blockquote> <p>Now, you can use the specific heat of gold to calculate how much energy would be needed to increase the temperature of gold by <mathjax>#32.3^@"C"#</mathjax>.</p> <blockquote> <p><mathjax>#32.3 color(red)(cancel(color(black)(""^@"C"))) * "0.126 J"/("1 g" * 1color(red)(cancel(color(black)(""^@"C")))) = "4.0698 J g"^(-1)#</mathjax></p> </blockquote> <p>This tells you that in order to increase the temperature of <mathjax>#"1 g"#</mathjax> of gold by <mathjax>#32.3^@"C"#</mathjax>, you need to provide it with <mathjax>#"4.0698 J"#</mathjax> of heat. </p> <p>You can thus say that <mathjax>#"675 J"#</mathjax> of heat will increase the temperature of </p> <blockquote> <p><mathjax>#675 color(red)(cancel(color(black)("J"))) * "1 g"/(4.0698color(red)(cancel(color(black)("J")))) = "165.86 g"#</mathjax></p> </blockquote> <p>of gold by <mathjax>#32.3^@"C"#</mathjax>. Rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the answer will be</p> <blockquote> <p><mathjax>#color(darkgreen)(ul(color(black)("mass of gold = 166 g")))#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"166 g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The key here is the <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> of gold, which is said to be equal to </p> <blockquote> <p><mathjax>#c_"gold" = "0.126 J g"^(-1)""^@"C"^(-1)#</mathjax></p> </blockquote> <p>This tells you that in order to increase the temperature of <mathjax>#"1 g"#</mathjax> of gold by <mathjax>#1^@"C"#</mathjax>, you need to provide it with <mathjax>#"0.126 J"#</mathjax> of heat.</p> <p>In your case, the temperature increases from <mathjax>#25.1^@"C"#</mathjax> to <mathjax>#57.4^@"C"#</mathjax>, which implies that it changes by</p> <blockquote> <p><mathjax>#57.4^@"C" - 25.1^@"C" = 32.3^@"C"#</mathjax></p> </blockquote> <p>Now, you can use the specific heat of gold to calculate how much energy would be needed to increase the temperature of gold by <mathjax>#32.3^@"C"#</mathjax>.</p> <blockquote> <p><mathjax>#32.3 color(red)(cancel(color(black)(""^@"C"))) * "0.126 J"/("1 g" * 1color(red)(cancel(color(black)(""^@"C")))) = "4.0698 J g"^(-1)#</mathjax></p> </blockquote> <p>This tells you that in order to increase the temperature of <mathjax>#"1 g"#</mathjax> of gold by <mathjax>#32.3^@"C"#</mathjax>, you need to provide it with <mathjax>#"4.0698 J"#</mathjax> of heat. </p> <p>You can thus say that <mathjax>#"675 J"#</mathjax> of heat will increase the temperature of </p> <blockquote> <p><mathjax>#675 color(red)(cancel(color(black)("J"))) * "1 g"/(4.0698color(red)(cancel(color(black)("J")))) = "165.86 g"#</mathjax></p> </blockquote> <p>of gold by <mathjax>#32.3^@"C"#</mathjax>. Rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the answer will be</p> <blockquote> <p><mathjax>#color(darkgreen)(ul(color(black)("mass of gold = 166 g")))#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A piece of gold initially at a temperature of 25.1 °C absorbs 675 J of heat, raising its temperature to 57.4 °C. Assuming the specific heat of gold is 0.126 J/(g°C), what is the mass of the sample?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/calorimetry" itemprop="url"> <span class="breadcrumb" itemprop="title">Calorimetry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="437115" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-09T14:39:22" itemprop="dateCreated"> Jun 9, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"166 g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The key here is the <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> of gold, which is said to be equal to </p> <blockquote> <p><mathjax>#c_"gold" = "0.126 J g"^(-1)""^@"C"^(-1)#</mathjax></p> </blockquote> <p>This tells you that in order to increase the temperature of <mathjax>#"1 g"#</mathjax> of gold by <mathjax>#1^@"C"#</mathjax>, you need to provide it with <mathjax>#"0.126 J"#</mathjax> of heat.</p> <p>In your case, the temperature increases from <mathjax>#25.1^@"C"#</mathjax> to <mathjax>#57.4^@"C"#</mathjax>, which implies that it changes by</p> <blockquote> <p><mathjax>#57.4^@"C" - 25.1^@"C" = 32.3^@"C"#</mathjax></p> </blockquote> <p>Now, you can use the specific heat of gold to calculate how much energy would be needed to increase the temperature of gold by <mathjax>#32.3^@"C"#</mathjax>.</p> <blockquote> <p><mathjax>#32.3 color(red)(cancel(color(black)(""^@"C"))) * "0.126 J"/("1 g" * 1color(red)(cancel(color(black)(""^@"C")))) = "4.0698 J g"^(-1)#</mathjax></p> </blockquote> <p>This tells you that in order to increase the temperature of <mathjax>#"1 g"#</mathjax> of gold by <mathjax>#32.3^@"C"#</mathjax>, you need to provide it with <mathjax>#"4.0698 J"#</mathjax> of heat. </p> <p>You can thus say that <mathjax>#"675 J"#</mathjax> of heat will increase the temperature of </p> <blockquote> <p><mathjax>#675 color(red)(cancel(color(black)("J"))) * "1 g"/(4.0698color(red)(cancel(color(black)("J")))) = "165.86 g"#</mathjax></p> </blockquote> <p>of gold by <mathjax>#32.3^@"C"#</mathjax>. Rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the answer will be</p> <blockquote> <p><mathjax>#color(darkgreen)(ul(color(black)("mass of gold = 166 g")))#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/437115" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-differential-scanning-in-calorimetry-work"> How does differential scanning in calorimetry work? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-read-differential-scanning-in-calorimetry"> What information do you get from a differential scanning calorimetry plot? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-measure-calorimetry"> How do you measure calorimetry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531d304102bf341e75b962a7"> Question #962a7 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5335021802bf344ae911dfc5"> Question #1dfc5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/533668f502bf34572c341af6"> Question #41af6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-definition-of-calorimetry"> What is calorimetry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-differential-scanning-calorimeter"> What is a differential scanning calorimeter? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-a-calorimeter-measure-energy"> How can a calorimeter measure energy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-calorimeters-made-of"> What are calorimeters made of? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/calorimetry"> See all questions in Calorimetry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1542 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A piece of gold initially at a temperature of 25.1 °C absorbs 675 J of heat, raising its temperature to 57.4 °C. Assuming the specific heat of gold is 0.126 J/(g°C), what is the mass of the sample?	null
1,078	acde559e-6ddd-11ea-9af3-ccda262736ce	https://socratic.org/questions/what-is-the-number-of-moles-of-hydrogen-in-three-moles-of-c-6h-12o-6	48 moles	start physical_unit 7 7 mole mol qc_end physical_unit 12 12 9 10 mole qc_end end	[{"type":"physical unit","value":"Mole [OF] hydrogen [IN] moles"}]	[{"type":"physical unit","value":"48 moles"}]	[{"type":"physical unit","value":"Mole [OF] C6H12O6 [=] \\pu{3 moles}"}]	<h1 class="questionTitle" itemprop="name">What is the number of moles of hydrogen in three moles of #C_6H_12O_6#?</h1>	null	48 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Clearly, there are 12 moles of hydrogen atoms in ONE mole of sugar.</p> <p>How many moles of hydrogen atoms in THREE moles of sugar. What is the mass of this molar quantity of hydrogen atoms?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>What is <mathjax>#3xx12?#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Clearly, there are 12 moles of hydrogen atoms in ONE mole of sugar.</p> <p>How many moles of hydrogen atoms in THREE moles of sugar. What is the mass of this molar quantity of hydrogen atoms?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the number of moles of hydrogen in three moles of #C_6H_12O_6#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="368531" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-01-24T07:06:09" itemprop="dateCreated"> Jan 24, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>What is <mathjax>#3xx12?#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Clearly, there are 12 moles of hydrogen atoms in ONE mole of sugar.</p> <p>How many moles of hydrogen atoms in THREE moles of sugar. What is the mass of this molar quantity of hydrogen atoms?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/368531" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2994 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the number of moles of hydrogen in three moles of #C_6H_12O_6#?	null
1,079	ace3a967-6ddd-11ea-9acb-ccda262736ce	https://socratic.org/questions/58a90523b72cff266efe5031	9.00 moles	start physical_unit 4 4 mole mol qc_end physical_unit 14 15 8 9 volume qc_end physical_unit 14 15 12 13 molarity qc_end end	[{"type":"physical unit","value":"Mole [OF] KOH [IN] moles"}]	[{"type":"physical unit","value":"9.00 moles"}]	[{"type":"physical unit","value":"Volume [OF] KOH solution [=] \\pu{1 L}"},{"type":"physical unit","value":"Molarity [OF] KOH solution [=] \\pu{9 M}"}]	<h1 class="questionTitle" itemprop="name">How many moles of #"KOH"# are in a #"1 L"# of a #"9 M KOH"# solution?</h1>	null	9.00 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The symbol <mathjax>#"M"#</mathjax>, which is pronounced molar, represents the concentration of a solution in <mathjax>#"mol/L"#</mathjax>.</p> <p>So a <mathjax>#"9.00 M"#</mathjax> solution of KOH, would contain <mathjax>#"9 mol KOH/L"#</mathjax>.<br/> .</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"9 moles KOH"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The symbol <mathjax>#"M"#</mathjax>, which is pronounced molar, represents the concentration of a solution in <mathjax>#"mol/L"#</mathjax>.</p> <p>So a <mathjax>#"9.00 M"#</mathjax> solution of KOH, would contain <mathjax>#"9 mol KOH/L"#</mathjax>.<br/> .</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles of #"KOH"# are in a #"1 L"# of a #"9 M KOH"# solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="379880" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-02-19T02:48:48" itemprop="dateCreated"> Feb 19, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"9 moles KOH"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The symbol <mathjax>#"M"#</mathjax>, which is pronounced molar, represents the concentration of a solution in <mathjax>#"mol/L"#</mathjax>.</p> <p>So a <mathjax>#"9.00 M"#</mathjax> solution of KOH, would contain <mathjax>#"9 mol KOH/L"#</mathjax>.<br/> .</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/379880" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? 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</a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-3-hydrogen-peroxide"> What is the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 5906 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many moles of #"KOH"# are in a #"1 L"# of a #"9 M KOH"# solution?	null
1,080	ac0fec0b-6ddd-11ea-b9d3-ccda262736ce	https://socratic.org/questions/at-22-5-c-and-1-25-atm-pressure-a-sample-of-carbon-dioxide-gas-occupies-a-volume	0.14 moles	start physical_unit 23 24 mole mol qc_end physical_unit 8 12 1 2 temperature qc_end physical_unit 8 12 4 5 pressure qc_end physical_unit 8 12 17 18 volume qc_end end	[{"type":"physical unit","value":"Mole [OF] the gas [IN] moles"}]	[{"type":"physical unit","value":"0.14 moles"}]	[{"type":"physical unit","value":"Temperature [OF] carbon dioxide gas sample [=] \\pu{22.5 ℃}"},{"type":"physical unit","value":"Pressure [OF] carbon dioxide gas sample [=] \\pu{1.25 atm}"},{"type":"physical unit","value":"Volume [OF] carbon dioxide gas sample [=] \\pu{2.65 L}"}]	<h1 class="questionTitle" itemprop="name">At 22.5 ºC and 1.25 atm pressure, a sample of carbon dioxide gas occupies a volume of 2.65 L. How many moles of the gas are present? </h1>	null	0.14 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#PV=nRT#</mathjax></p> <p>We want to find the no. of moles, which is <mathjax>#n#</mathjax>, so</p> <p><mathjax>#n= (PV)/(RT)#</mathjax></p> <p>Here</p> <blockquote> <ul> <li><mathjax>#"P = 1.25 atm"#</mathjax></li> <li><mathjax>#V = "2.65 L"#</mathjax></li> <li><mathjax>#R= "0.0821 atm(L)/mol(K)"#</mathjax></li> <li><mathjax>#T = 22.5^@"C" +273.15 = "295.7 K"#</mathjax></li> </ul> </blockquote> <p>Now plug it into the formula</p> <p><mathjax>#n = (("1.25 atm")("2.65 L"))/(("0.0821 atm(L)/mol(K)")("295.7 K"))#</mathjax></p> <p><mathjax>#n = 3.3125/24.273#</mathjax> <mathjax>#"mol"#</mathjax></p> <p><mathjax>#n = 1.36 xx 10^(-1)#</mathjax> <mathjax>#"mol CO"_2#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1.36 xx 10^(-1)#</mathjax> <mathjax>#"mol CO"_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#PV=nRT#</mathjax></p> <p>We want to find the no. of moles, which is <mathjax>#n#</mathjax>, so</p> <p><mathjax>#n= (PV)/(RT)#</mathjax></p> <p>Here</p> <blockquote> <ul> <li><mathjax>#"P = 1.25 atm"#</mathjax></li> <li><mathjax>#V = "2.65 L"#</mathjax></li> <li><mathjax>#R= "0.0821 atm(L)/mol(K)"#</mathjax></li> <li><mathjax>#T = 22.5^@"C" +273.15 = "295.7 K"#</mathjax></li> </ul> </blockquote> <p>Now plug it into the formula</p> <p><mathjax>#n = (("1.25 atm")("2.65 L"))/(("0.0821 atm(L)/mol(K)")("295.7 K"))#</mathjax></p> <p><mathjax>#n = 3.3125/24.273#</mathjax> <mathjax>#"mol"#</mathjax></p> <p><mathjax>#n = 1.36 xx 10^(-1)#</mathjax> <mathjax>#"mol CO"_2#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">At 22.5 ºC and 1.25 atm pressure, a sample of carbon dioxide gas occupies a volume of 2.65 L. How many moles of the gas are present? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/ideal-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Ideal Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="504462" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/giuliana-1"><img alt="" class="" src="https://profilepictures.socratic.org/ssuvOnaRhO5vlzbsJ1ZA_JAZZZ.jpg" title=""/></a> <a class="secondContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/giuliana-1"> giuliana </a>·<a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-11-13T03:07:54" itemprop="dateCreated"> Nov 13, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1.36 xx 10^(-1)#</mathjax> <mathjax>#"mol CO"_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#PV=nRT#</mathjax></p> <p>We want to find the no. of moles, which is <mathjax>#n#</mathjax>, so</p> <p><mathjax>#n= (PV)/(RT)#</mathjax></p> <p>Here</p> <blockquote> <ul> <li><mathjax>#"P = 1.25 atm"#</mathjax></li> <li><mathjax>#V = "2.65 L"#</mathjax></li> <li><mathjax>#R= "0.0821 atm(L)/mol(K)"#</mathjax></li> <li><mathjax>#T = 22.5^@"C" +273.15 = "295.7 K"#</mathjax></li> </ul> </blockquote> <p>Now plug it into the formula</p> <p><mathjax>#n = (("1.25 atm")("2.65 L"))/(("0.0821 atm(L)/mol(K)")("295.7 K"))#</mathjax></p> <p><mathjax>#n = 3.3125/24.273#</mathjax> <mathjax>#"mol"#</mathjax></p> <p><mathjax>#n = 1.36 xx 10^(-1)#</mathjax> <mathjax>#"mol CO"_2#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/504462" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-ideal-gas-constant"> How do you find the ideal gas constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-solve-ideal-gas-law-problems"> How do you solve ideal gas law problems? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-know-which-ideal-gas-constant-to-use"> How do you know which ideal gas constant to use? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ideal-gas-constant-for-butane"> What is the ideal gas constant for butane? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-ideal-gas-law-in-kelvin"> Why is ideal gas law in kelvin? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ideal-gas-constant-important"> Why is the ideal gas constant important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-di-electric-constant"> What is the di-electric constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-volume-l-will-0-20-mol-hi-occupy-at-300-k-and-100-0-kpa-r-8-314-kpa-l-k-mol"> What volume (L) will 0.20 mol HI occupy at 300 K and 100.0 kPa? R = 8.314 kPa L / (K mol) =... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-molar-mass-of-a-gas"> How do you calculate the molar mass of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-should-i-use-the-ideal-gas-law-and-not-the-combined-gas-law"> When should I use the ideal gas law and not the combined gas law? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/ideal-gas-law"> See all questions in Ideal Gas Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 9804 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	At 22.5 ºC and 1.25 atm pressure, a sample of carbon dioxide gas occupies a volume of 2.65 L. How many moles of the gas are present?	null
1,081	aaa91494-6ddd-11ea-af44-ccda262736ce	https://socratic.org/questions/how-do-you-complete-the-equation-c-8h-18-c-6h-14	C8H18 -> C6H14 + C2H4	start chemical_equation qc_end chemical_equation 6 10 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the equation"}]	[{"type":"chemical equation","value":"C8H18 -> C6H14 + C2H4"}]	[{"type":"chemical equation","value":"C8H18 -> C6H14 + _"}]	<h1 class="questionTitle" itemprop="name">How do you complete the equation #C_8H_18 -> C_6H_14 + __#?</h1>	null	C8H18 -> C6H14 + C2H4	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote> <p><mathjax>#"C"_8"H"_18 -> "C"_6"H"_14 + "__" #</mathjax></p> </blockquote> <p>There are <mathjax>#8#</mathjax> carbons & <mathjax>#18#</mathjax> Hydrogens in reactant side and <mathjax>#6#</mathjax> carbons & <mathjax>#14#</mathjax> Hydrogens in product side. So, another molecule should contain <mathjax>#2#</mathjax> carbons and <mathjax>#4#</mathjax> Hydrogens.</p> <blockquote> <p><mathjax>#"C"_8"H"_18 -> "C"_6"H"_14 + underbrace("C"_2"H"_4)#</mathjax><br/> <mathjax>#color(white)(............................)"ethene"#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"C"_2"H"_4#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote> <p><mathjax>#"C"_8"H"_18 -> "C"_6"H"_14 + "__" #</mathjax></p> </blockquote> <p>There are <mathjax>#8#</mathjax> carbons & <mathjax>#18#</mathjax> Hydrogens in reactant side and <mathjax>#6#</mathjax> carbons & <mathjax>#14#</mathjax> Hydrogens in product side. So, another molecule should contain <mathjax>#2#</mathjax> carbons and <mathjax>#4#</mathjax> Hydrogens.</p> <blockquote> <p><mathjax>#"C"_8"H"_18 -> "C"_6"H"_14 + underbrace("C"_2"H"_4)#</mathjax><br/> <mathjax>#color(white)(............................)"ethene"#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you complete the equation #C_8H_18 -> C_6H_14 + __#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-reactions-and-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions and Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="593560" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/junaid-mirza"><img alt="" class="" src="https://profilepictures.socratic.org/BBeNx7NTQ7WmDQKll8wN_BDC9EDF4-5DCB-440D-8ADC-ADACE2966216.jpeg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/junaid-mirza"> Junaid Mirza </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-04-12T17:29:22" itemprop="dateCreated"> Apr 12, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"C"_2"H"_4#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote> <p><mathjax>#"C"_8"H"_18 -> "C"_6"H"_14 + "__" #</mathjax></p> </blockquote> <p>There are <mathjax>#8#</mathjax> carbons & <mathjax>#18#</mathjax> Hydrogens in reactant side and <mathjax>#6#</mathjax> carbons & <mathjax>#14#</mathjax> Hydrogens in product side. So, another molecule should contain <mathjax>#2#</mathjax> carbons and <mathjax>#4#</mathjax> Hydrogens.</p> <blockquote> <p><mathjax>#"C"_8"H"_18 -> "C"_6"H"_14 + underbrace("C"_2"H"_4)#</mathjax><br/> <mathjax>#color(white)(............................)"ethene"#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/593560" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="593561" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/shubh"><img alt="" class="" src="https://profilepictures.socratic.org/flchW4lbTKknvGCb8hDc_IMG-20180318-WA0057.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/shubh"> Shubh </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-04-12T17:31:44" itemprop="dateCreated"> Apr 12, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerDescription"> <div> <div class="markdown"><p>it is the example of Aromatization in which higher alkanes is divided into smaller akanes & alkenes.<br/> so, eqn is,<br/> <mathjax>#C_8H_18 rarr C_6H_14 + C_2H_4#</mathjax><br/> octane <mathjax>#rarr#</mathjax> hexane + ethene</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/593561" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb002bf34694a4fee47"> Question #fee47 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb402bf34694c8c5c15"> Question #c5c15 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb802bf346950519eb9"> Question #19eb9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cbf02bf3469570e2ea2"> Question #e2ea2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc002bf34695a6bc751"> Question #bc751 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc202bf3469570e2ea6"> Question #e2ea6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531e867a02bf342492a08b07"> Question #08b07 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-thermochemical-equation-for-the-combustion-of-benzene"> What is the thermochemical equation for the combustion of benzene? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-reversible"> Why are chemical reactions reversible? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-important"> Why are chemical reactions important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/chemical-reactions-and-equations"> See all questions in Chemical Reactions and Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1477 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How do you complete the equation #C_8H_18 -> C_6H_14 + __#?	null
1,082	ab126134-6ddd-11ea-a610-ccda262736ce	https://socratic.org/questions/what-is-the-theoretical-yield-of-aluminum-oxide-if-1-60-mol-of-aluminum-metal-is	1.0 mol	start physical_unit 6 7 theoretical_yield mol qc_end physical_unit 12 13 9 10 mole qc_end physical_unit 20 20 17 18 mole qc_end end	[{"type":"physical unit","value":"Theoretical yield [OF] aluminum oxide [IN] mol"}]	[{"type":"physical unit","value":"1.0 mol"}]	[{"type":"physical unit","value":"Mole [OF] aluminum metal [=] \\pu{1.60 mol}"},{"type":"physical unit","value":"Mole [OF] oxygen [=] \\pu{1.50 mol}"}]	<h1 class="questionTitle" itemprop="name">What is the theoretical yield of aluminum oxide if 1.60 mol of aluminum metal is exposed to 1.50 mol of oxygen? </h1>	null	1.0 mol	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First, write the balanced chemical reaction. Then, see how many of the available moles of each reactant will be used. The theoretical yield is the value at which one of the reactants has been completely reacted.</p> <p><mathjax>#2Al + 3O_2 → 2Al_2O_3 #</mathjax> </p> <p>We need THREE moles of oxygen for every TWO moles of aluminum to produce TWO moles of aluminum oxide.</p> <p>We have 1.60 mol of Al and 1.50 mol <mathjax>#O_2#</mathjax>, so <mathjax>#O_2#</mathjax> is the <a href="https://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a>, and the maximum amount of aluminum oxide that could be produced is 1.50mol <mathjax>#O_2 * (2/3)((Al_2O_3)/(O_2))#</mathjax> = 1.0mol <mathjax>#Al_2O_3 #</mathjax> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>1.0 mole</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First, write the balanced chemical reaction. Then, see how many of the available moles of each reactant will be used. The theoretical yield is the value at which one of the reactants has been completely reacted.</p> <p><mathjax>#2Al + 3O_2 → 2Al_2O_3 #</mathjax> </p> <p>We need THREE moles of oxygen for every TWO moles of aluminum to produce TWO moles of aluminum oxide.</p> <p>We have 1.60 mol of Al and 1.50 mol <mathjax>#O_2#</mathjax>, so <mathjax>#O_2#</mathjax> is the <a href="https://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a>, and the maximum amount of aluminum oxide that could be produced is 1.50mol <mathjax>#O_2 * (2/3)((Al_2O_3)/(O_2))#</mathjax> = 1.0mol <mathjax>#Al_2O_3 #</mathjax> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the theoretical yield of aluminum oxide if 1.60 mol of aluminum metal is exposed to 1.50 mol of oxygen? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/percent-yield" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Yield</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="390531" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/scooke"><img alt="" class="" src="https://profilepictures.socratic.org/ezAzqDkjRS6NXBmMH3lg_BioPic2010a.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/scooke"> SCooke </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-13T09:31:08" itemprop="dateCreated"> Mar 13, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>1.0 mole</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First, write the balanced chemical reaction. Then, see how many of the available moles of each reactant will be used. The theoretical yield is the value at which one of the reactants has been completely reacted.</p> <p><mathjax>#2Al + 3O_2 → 2Al_2O_3 #</mathjax> </p> <p>We need THREE moles of oxygen for every TWO moles of aluminum to produce TWO moles of aluminum oxide.</p> <p>We have 1.60 mol of Al and 1.50 mol <mathjax>#O_2#</mathjax>, so <mathjax>#O_2#</mathjax> is the <a href="https://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a>, and the maximum amount of aluminum oxide that could be produced is 1.50mol <mathjax>#O_2 * (2/3)((Al_2O_3)/(O_2))#</mathjax> = 1.0mol <mathjax>#Al_2O_3 #</mathjax> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/390531" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ebd02bf3469570e2e62"> Question #e2e62 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ec502bf34694a4fee2e"> Question #fee2e </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ec902bf34694a4fee32"> Question #fee32 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ece02bf346950519e89"> Question #19e89 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ed302bf34694c8c5bdc"> Question #c5bdc </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ee302bf3469517a1065"> Question #a1065 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-would-be-the-limiting-reagent-if-26-0-grams-of-c3h9n-were-reacted-with-46-3"> What would be the limiting reagent if 26.0 grams of C3H9N were reacted with 46.3 grams of... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-percent-yield-always-less-than-100"> Is percent yield always less than 100? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-would-be-the-limiting-reagent-if-41-9-grams-of-c2h3of-were-reacted-with-61-"> What would be the limiting reagent if 41.9 grams of C2H3OF were reacted with 61.0 grams of... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-yield-of-the-following-reaction-if-60-grams-of-caco3-is-heat"> What is the percent yield of the following reaction if 60 grams of CaCO3 is heated to give 15... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/percent-yield"> See all questions in Percent Yield </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 16506 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the theoretical yield of aluminum oxide if 1.60 mol of aluminum metal is exposed to 1.50 mol of oxygen?	null
1,083	aad44eb8-6ddd-11ea-8330-ccda262736ce	https://socratic.org/questions/how-many-grams-of-calcium-are-in-4-55-moles	180.36 grams	start physical_unit 4 4 mass g qc_end physical_unit 4 4 7 8 mole qc_end end	[{"type":"physical unit","value":"Mass [OF] Calcium [IN] grams"}]	[{"type":"physical unit","value":"180.36 grams"}]	[{"type":"physical unit","value":"Mole [OF] Calcium [=] \\pu{4.55 moles}"}]	<h1 class="questionTitle" itemprop="name">How many grams of Calcium are in 4.55 moles? </h1>	null	180.36 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And in <mathjax>#4.55#</mathjax> <mathjax>#"moles"#</mathjax> of metal, there are <mathjax>#4.5cancel(mol)xx40.08gcancel(mol^-1)#</mathjax> <mathjax>#~=#</mathjax> <mathjax>#180g#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, in one mole of calcium there are <mathjax>#40.08g#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And in <mathjax>#4.55#</mathjax> <mathjax>#"moles"#</mathjax> of metal, there are <mathjax>#4.5cancel(mol)xx40.08gcancel(mol^-1)#</mathjax> <mathjax>#~=#</mathjax> <mathjax>#180*g#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many grams of Calcium are in 4.55 moles? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="308941" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-09-12T06:00:46" itemprop="dateCreated"> Sep 12, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, in one mole of calcium there are <mathjax>#40.08g#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And in <mathjax>#4.55#</mathjax> <mathjax>#"moles"#</mathjax> of metal, there are <mathjax>#4.5cancel(mol)xx40.08gcancel(mol^-1)#</mathjax> <mathjax>#~=#</mathjax> <mathjax>#180*g#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/308941" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? 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1,084	a920dc6c-6ddd-11ea-8daa-ccda262736ce	https://socratic.org/questions/what-is-the-poh-of-a-solution-with-an-oh-concentration-of-9-2-x-10-11-m	10.0	start physical_unit 6 6 poh none qc_end physical_unit 6 6 12 15 [oh-] qc_end end	[{"type":"physical unit","value":"pOH [OF] the solution"}]	[{"type":"physical unit","value":"10.0"}]	[{"type":"physical unit","value":"[OH-] concentration [OF] the solution [=] \\pu{9.2 × 10^(-11) M}"}]	<h1 class="questionTitle" itemprop="name">What is the pOH of a solution with an [OH-] concentration of #9.2 x 10^-11# M?</h1>	null	10.0	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#pOH=-log_10[HO^-]#</mathjax>.</p> <p>If <mathjax>#[HO^-]=9.2xx10^-11molL^-1#</mathjax>, then <mathjax>#pOH=-log_(10)[9.2xx10^-11]=10.0#</mathjax></p> <p>What is <mathjax>#pH#</mathjax> of this solution?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#pOH=10.0#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#pOH=-log_10[HO^-]#</mathjax>.</p> <p>If <mathjax>#[HO^-]=9.2xx10^-11molL^-1#</mathjax>, then <mathjax>#pOH=-log_(10)[9.2xx10^-11]=10.0#</mathjax></p> <p>What is <mathjax>#pH#</mathjax> of this solution?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the pOH of a solution with an [OH-] concentration of #9.2 x 10^-11# M?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/ph-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">pH calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="415845" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-01T15:12:30" itemprop="dateCreated"> May 1, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#pOH=10.0#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#pOH=-log_10[HO^-]#</mathjax>.</p> <p>If <mathjax>#[HO^-]=9.2xx10^-11molL^-1#</mathjax>, then <mathjax>#pOH=-log_(10)[9.2xx10^-11]=10.0#</mathjax></p> <p>What is <mathjax>#pH#</mathjax> of this solution?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/415845" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-of-a-solution"> How do you determine ph of a solution? 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1,085	a96626c0-6ddd-11ea-b25a-ccda262736ce	https://socratic.org/questions/how-many-moles-are-present-in-34-grams-of-cu-oh-2	0.35 moles	start physical_unit 9 9 mole mol qc_end physical_unit 9 9 6 7 mass qc_end end	[{"type":"physical unit","value":"Mole [OF] Cu(OH)2 [IN] moles"}]	[{"type":"physical unit","value":"0.35 moles"}]	[{"type":"physical unit","value":"Mass [OF] Cu(OH)2 [=] \\pu{34 grams}"}]	<h1 class="questionTitle" itemprop="name">How many moles are present in 34 grams of #Cu(OH)_2#?</h1>	null	0.35 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Moles of"#</mathjax> <mathjax># Cu(OH)_2#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(34cancelg)/(97.6cancelg*mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??" moles"#</mathjax>.</p> <p>How many formula units of <mathjax>#Cu(OH)_2#</mathjax> are in this quantity?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Approx. <mathjax>#1/3#</mathjax> of a mole. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Moles of"#</mathjax> <mathjax># Cu(OH)_2#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(34cancelg)/(97.6cancelg*mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??" moles"#</mathjax>.</p> <p>How many formula units of <mathjax>#Cu(OH)_2#</mathjax> are in this quantity?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles are present in 34 grams of #Cu(OH)_2#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="228236" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-02-18T23:13:49" itemprop="dateCreated"> Feb 18, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Approx. <mathjax>#1/3#</mathjax> of a mole. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Moles of"#</mathjax> <mathjax># Cu(OH)_2#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(34cancelg)/(97.6cancelg*mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??" moles"#</mathjax>.</p> <p>How many formula units of <mathjax>#Cu(OH)_2#</mathjax> are in this quantity?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/228236" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="228237" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ayako-sho"><img alt="" class="" src="https://lh3.googleusercontent.com/-XdUIqdMkCWA/AAAAAAAAAAI/AAAAAAAAAAA/4252rscbv5M/photo.jpg?sz=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ayako-sho"> Ayako_Sho </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-02-18T23:14:03" itemprop="dateCreated"> Feb 18, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>There are 0.348 moles in 34 grams of <mathjax>#Cu(OH)_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Number of moles = <mathjax>#Mass//Molar Mass#</mathjax><br/> Molar mass of <mathjax>#Cu(OH)_2#</mathjax><br/> Cu - 63.55<br/> O - 2(16)<br/> H - 2(1.01)<br/> = 97.57g/mol<br/> Thus <br/> <mathjax>#34//97.57#</mathjax><br/> <mathjax>#= 0.348#</mathjax><br/> Thus, there are 0.348 moles in 34 grams of <mathjax>#Cu(OH)_2#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/228237" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a 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class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 27540 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many moles are present in 34 grams of #Cu(OH)_2#?	null
1,086	a8d22b46-6ddd-11ea-9914-ccda262736ce	https://socratic.org/questions/the-specific-heat-capacity-of-liquid-water-is-4-18-kj-g-c-how-would-you-calculat	239 J	start physical_unit 6 6 energy j qc_end physical_unit 5 6 8 11 specific_heat qc_end physical_unit 6 6 28 29 temperature qc_end physical_unit 6 6 31 32 temperature qc_end end	[{"type":"physical unit","value":"Required energy [OF] water [IN] J"}]	[{"type":"physical unit","value":"239 J"}]	[{"type":"physical unit","value":"Specific heat [OF] liquid water [=] \\pu{4.18 kJ/(g * ℃)}"},{"type":"physical unit","value":"Mass [OF] water [=] \\pu{1.0 g}"},{"type":"physical unit","value":"Temperature1 [OF] water [=] \\pu{26.5 ℃}"},{"type":"physical unit","value":"Temperature2 [OF] water [=] \\pu{83.7 ℃}"}]	<h1 class="questionTitle" itemprop="name">The specific heat capacity of liquid water is 4.18 kJ/g C, how would you calculate the quantity of energy required to heat 1.00 g of water from 26.5 C to 83.7 C? </h1>	null	239 J	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First thing first, you mistyped the <a href="http://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> of water, which should be </p> <blockquote> <p><mathjax>#c_"water" = 4.18"J"/("g" ""^@"C")#</mathjax></p> </blockquote> <p>Now, a substance's <em><a href="http://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a></em> tells you how much heat is required to increase the temperature of <mathjax>#"1 g"#</mathjax> of that substance by <mathjax>#1^@"C"#</mathjax>. </p> <p>In the case of water, you would need <mathjax>#"4.18 J"#</mathjax> to increase the temperature of <mathjax>#"1 g"#</mathjax> of water by <mathjax>#1^@"C"#</mathjax>. </p> <p>Notice that your sample of water has a mass of <mathjax>#"1 g"#</mathjax> as well, which means that the only factor that will determine the amount of heat needed will be the difference in temperature.</p> <p>The equation that establishes a relationshop between heat and change in temperature looks like this</p> <blockquote> <p><mathjax>#color(blue)(q = m * c * DeltaT)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#q#</mathjax> - heat absorbed<br/> <mathjax>#c#</mathjax> - the specific heat of the substance, in your case of water<br/> <mathjax>#DeltaT#</mathjax> - the change in temperature, defined as the difference between the <em>final temperature</em> and the <em>initial temperature</em></p> <p>Plug in your values and solve for <mathjax>#q#</mathjax> to get</p> <blockquote> <p><mathjax>#q = 1.00color(red)(cancel(color(black)("g"))) * 4.18"J"/(color(red)(cancel(color(black)("g"))) * color(red)(cancel(color(black)(""^@"C")))) * (83.7 - 26.5)color(red)(cancel(color(black)(""^@"C")))#</mathjax> </p> <p><mathjax>#q = "239.096 J"#</mathjax></p> </blockquote> <p>Rounded to three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the answer will be </p> <blockquote> <p><mathjax>#q = color(green)("239 J")#</mathjax></p> </blockquote> <p> <iframe src="https://www.youtube.com/embed/c2NaAHEusm4?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p> <p><strong>SIDE NOTE</strong> <em>Notice how much heat would be needed to increase the temperature of 57.2 g of water by</em> <mathjax>#1^@"C"#</mathjax>. <mathjax>#DeltaT#</mathjax> <em>will now be equal to</em> <mathjax>#1^@"C"#</mathjax> <em>and you'd have</em></p> <blockquote> <p><mathjax>#q = 57.2color(red)(cancel(color(black)("g"))) * 4.18"J"/(color(red)(cancel(color(black)("g"))) * color(red)(cancel(color(black)(""^@"C")))) * 1color(red)(cancel(color(black)(""^@"C")))#</mathjax> </p> <p><mathjax>#q = "239 J"#</mathjax></p> </blockquote> <p>This tells you that you need the same amount of heat to increase the temperature of <mathjax>#"1 g"#</mathjax> of water by <mathjax>#57.2^@"C"#</mathjax>, as you do to increase the temperature of <mathjax>#"57.2 g"#</mathjax> of water by <mathjax>#1^@"C"#</mathjax>. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"239 J"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First thing first, you mistyped the <a href="http://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> of water, which should be </p> <blockquote> <p><mathjax>#c_"water" = 4.18"J"/("g" ""^@"C")#</mathjax></p> </blockquote> <p>Now, a substance's <em><a href="http://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a></em> tells you how much heat is required to increase the temperature of <mathjax>#"1 g"#</mathjax> of that substance by <mathjax>#1^@"C"#</mathjax>. </p> <p>In the case of water, you would need <mathjax>#"4.18 J"#</mathjax> to increase the temperature of <mathjax>#"1 g"#</mathjax> of water by <mathjax>#1^@"C"#</mathjax>. </p> <p>Notice that your sample of water has a mass of <mathjax>#"1 g"#</mathjax> as well, which means that the only factor that will determine the amount of heat needed will be the difference in temperature.</p> <p>The equation that establishes a relationshop between heat and change in temperature looks like this</p> <blockquote> <p><mathjax>#color(blue)(q = m * c * DeltaT)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#q#</mathjax> - heat absorbed<br/> <mathjax>#c#</mathjax> - the specific heat of the substance, in your case of water<br/> <mathjax>#DeltaT#</mathjax> - the change in temperature, defined as the difference between the <em>final temperature</em> and the <em>initial temperature</em></p> <p>Plug in your values and solve for <mathjax>#q#</mathjax> to get</p> <blockquote> <p><mathjax>#q = 1.00color(red)(cancel(color(black)("g"))) * 4.18"J"/(color(red)(cancel(color(black)("g"))) * color(red)(cancel(color(black)(""^@"C")))) * (83.7 - 26.5)color(red)(cancel(color(black)(""^@"C")))#</mathjax> </p> <p><mathjax>#q = "239.096 J"#</mathjax></p> </blockquote> <p>Rounded to three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the answer will be </p> <blockquote> <p><mathjax>#q = color(green)("239 J")#</mathjax></p> </blockquote> <p> <iframe src="https://www.youtube.com/embed/c2NaAHEusm4?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p> <p><strong>SIDE NOTE</strong> <em>Notice how much heat would be needed to increase the temperature of 57.2 g of water by</em> <mathjax>#1^@"C"#</mathjax>. <mathjax>#DeltaT#</mathjax> <em>will now be equal to</em> <mathjax>#1^@"C"#</mathjax> <em>and you'd have</em></p> <blockquote> <p><mathjax>#q = 57.2color(red)(cancel(color(black)("g"))) * 4.18"J"/(color(red)(cancel(color(black)("g"))) * color(red)(cancel(color(black)(""^@"C")))) * 1color(red)(cancel(color(black)(""^@"C")))#</mathjax> </p> <p><mathjax>#q = "239 J"#</mathjax></p> </blockquote> <p>This tells you that you need the same amount of heat to increase the temperature of <mathjax>#"1 g"#</mathjax> of water by <mathjax>#57.2^@"C"#</mathjax>, as you do to increase the temperature of <mathjax>#"57.2 g"#</mathjax> of water by <mathjax>#1^@"C"#</mathjax>. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">The specific heat capacity of liquid water is 4.18 kJ/g C, how would you calculate the quantity of energy required to heat 1.00 g of water from 26.5 C to 83.7 C? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/calorimetry" itemprop="url"> <span class="breadcrumb" itemprop="title">Calorimetry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="180201" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-10-26T21:58:48" itemprop="dateCreated"> Oct 26, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"239 J"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First thing first, you mistyped the <a href="http://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> of water, which should be </p> <blockquote> <p><mathjax>#c_"water" = 4.18"J"/("g" ""^@"C")#</mathjax></p> </blockquote> <p>Now, a substance's <em><a href="http://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a></em> tells you how much heat is required to increase the temperature of <mathjax>#"1 g"#</mathjax> of that substance by <mathjax>#1^@"C"#</mathjax>. </p> <p>In the case of water, you would need <mathjax>#"4.18 J"#</mathjax> to increase the temperature of <mathjax>#"1 g"#</mathjax> of water by <mathjax>#1^@"C"#</mathjax>. </p> <p>Notice that your sample of water has a mass of <mathjax>#"1 g"#</mathjax> as well, which means that the only factor that will determine the amount of heat needed will be the difference in temperature.</p> <p>The equation that establishes a relationshop between heat and change in temperature looks like this</p> <blockquote> <p><mathjax>#color(blue)(q = m * c * DeltaT)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#q#</mathjax> - heat absorbed<br/> <mathjax>#c#</mathjax> - the specific heat of the substance, in your case of water<br/> <mathjax>#DeltaT#</mathjax> - the change in temperature, defined as the difference between the <em>final temperature</em> and the <em>initial temperature</em></p> <p>Plug in your values and solve for <mathjax>#q#</mathjax> to get</p> <blockquote> <p><mathjax>#q = 1.00color(red)(cancel(color(black)("g"))) * 4.18"J"/(color(red)(cancel(color(black)("g"))) * color(red)(cancel(color(black)(""^@"C")))) * (83.7 - 26.5)color(red)(cancel(color(black)(""^@"C")))#</mathjax> </p> <p><mathjax>#q = "239.096 J"#</mathjax></p> </blockquote> <p>Rounded to three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the answer will be </p> <blockquote> <p><mathjax>#q = color(green)("239 J")#</mathjax></p> </blockquote> <p> <iframe src="https://www.youtube.com/embed/c2NaAHEusm4?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p> <p><strong>SIDE NOTE</strong> <em>Notice how much heat would be needed to increase the temperature of 57.2 g of water by</em> <mathjax>#1^@"C"#</mathjax>. <mathjax>#DeltaT#</mathjax> <em>will now be equal to</em> <mathjax>#1^@"C"#</mathjax> <em>and you'd have</em></p> <blockquote> <p><mathjax>#q = 57.2color(red)(cancel(color(black)("g"))) * 4.18"J"/(color(red)(cancel(color(black)("g"))) * color(red)(cancel(color(black)(""^@"C")))) * 1color(red)(cancel(color(black)(""^@"C")))#</mathjax> </p> <p><mathjax>#q = "239 J"#</mathjax></p> </blockquote> <p>This tells you that you need the same amount of heat to increase the temperature of <mathjax>#"1 g"#</mathjax> of water by <mathjax>#57.2^@"C"#</mathjax>, as you do to increase the temperature of <mathjax>#"57.2 g"#</mathjax> of water by <mathjax>#1^@"C"#</mathjax>. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/180201" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-differential-scanning-in-calorimetry-work"> How 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</div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 216262 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	The specific heat capacity of liquid water is 4.18 kJ/g C, how would you calculate the quantity of energy required to heat 1.00 g of water from 26.5 C to 83.7 C?	null
1,087	aaa35be4-6ddd-11ea-9777-ccda262736ce	https://socratic.org/questions/what-is-the-concentration-in-molarity-of-a-250-ml-solution-made-with-43-4-grams-	2.0 M	start physical_unit 16 16 concentration mol/l qc_end physical_unit 10 10 8 9 volume qc_end physical_unit 16 16 13 14 mass qc_end end	[{"type":"physical unit","value":"Concentration in molarity [OF] the solution [IN] M"}]	[{"type":"physical unit","value":"2.0 M"}]	[{"type":"physical unit","value":"Volume [OF] the solution [=] \\pu{250 mL}"},{"type":"physical unit","value":"Mass [OF] LiBr [=] \\pu{43.4 grams}"}]	<h1 class="questionTitle" itemprop="name">What is the concentration in molarity of a 250 mL solution made with 43.4 grams of LiBr?</h1>	null	2.0 M	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a> = molar concentration = how many moles in <mathjax>#"1 L"#</mathjax> of solution.</p> <p><mathjax>#M_("LiBr") = M_"Li" + M_"Br" = "6.9 g/mol" + "79.9 g/mol" = "86.8 g/mol"#</mathjax></p> <p>(I've used the rounded molar masses)</p> <p><mathjax>#n_"LiBr" = "43.4 g"/"86.8 g/mol" = "0.5moles"#</mathjax></p> <p><mathjax>#V_"solution" = "250 mL" = "0.25L"#</mathjax></p> <p>So</p> <p><mathjax>#c = n_"LiBr"/ V_"solution" = "0.5 moles"/"0.25 L" = "2.0 M"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"2.0 M"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a> = molar concentration = how many moles in <mathjax>#"1 L"#</mathjax> of solution.</p> <p><mathjax>#M_("LiBr") = M_"Li" + M_"Br" = "6.9 g/mol" + "79.9 g/mol" = "86.8 g/mol"#</mathjax></p> <p>(I've used the rounded molar masses)</p> <p><mathjax>#n_"LiBr" = "43.4 g"/"86.8 g/mol" = "0.5moles"#</mathjax></p> <p><mathjax>#V_"solution" = "250 mL" = "0.25L"#</mathjax></p> <p>So</p> <p><mathjax>#c = n_"LiBr"/ V_"solution" = "0.5 moles"/"0.25 L" = "2.0 M"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the concentration in molarity of a 250 mL solution made with 43.4 grams of LiBr?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="559353" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/justme314"><img alt="" class="" src="https://graph.facebook.com/1022769511193043/picture?height=50&width=50" title=""/></a> <a class="secondContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/justme314"> JustMe314 </a>·<a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-02-27T12:19:30" itemprop="dateCreated"> Feb 27, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"2.0 M"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a> = molar concentration = how many moles in <mathjax>#"1 L"#</mathjax> of solution.</p> <p><mathjax>#M_("LiBr") = M_"Li" + M_"Br" = "6.9 g/mol" + "79.9 g/mol" = "86.8 g/mol"#</mathjax></p> <p>(I've used the rounded molar masses)</p> <p><mathjax>#n_"LiBr" = "43.4 g"/"86.8 g/mol" = "0.5moles"#</mathjax></p> <p><mathjax>#V_"solution" = "250 mL" = "0.25L"#</mathjax></p> <p>So</p> <p><mathjax>#c = n_"LiBr"/ V_"solution" = "0.5 moles"/"0.25 L" = "2.0 M"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/559353" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="559355" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/nam-d"><img alt="" class="" src="https://profilepictures.socratic.org/QG4MnkoER6u99DIDVWKK_787554714770341.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/nam-d"> Nam D. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-02-27T12:22:31" itemprop="dateCreated"> Feb 27, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2 \ "M"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a> is defined by the following equation</p> <p><mathjax>#"molarity"="moles of solute"/"liters of solution"#</mathjax></p> <p>So, we first need to convert <mathjax>#43.4 \ "g"#</mathjax> of <mathjax>#LiBr#</mathjax> into moles.</p> <p><mathjax>#LiBr#</mathjax> has a molar mass of <mathjax>#86.845 \ "g/mol"#</mathjax>.</p> <p>So, <mathjax>#43.4 \ "g"#</mathjax> of <mathjax>#LiBr#</mathjax> is equivalent to</p> <p><mathjax>#(43.4color(red)cancelcolor(black)"g")/(86.845color(red)cancelcolor(black)"g""/mol")~~0.5 \ "mol"#</mathjax></p> <p>We can also convert the amount of milliliters to liters.</p> <p><mathjax>#1 \ "L"=1000 \ "mL"#</mathjax></p> <p>So, <mathjax>#250 \ "mL"=0.25 \ "L"#</mathjax></p> <p>Now, we have the desired units, we can plug it into the molarity equation.</p> <p><mathjax>#:."molarity"=(0.5 \ "mol")/(0.25 \ "L")=2 \ "mol/L"#</mathjax></p> <p>We can also write it as <mathjax>#2 \ "M"#</mathjax>, since <mathjax>#1 \ "M"=1 \ "mol/L"#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/559355" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> 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class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 7265 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the concentration in molarity of a 250 mL solution made with 43.4 grams of LiBr?	null
1,088	aa0de81e-6ddd-11ea-a4e7-ccda262736ce	https://socratic.org/questions/if-4-00-moles-of-gasoline-are-burned-what-volume-of-oxygen-is-needed-if-the-pres	1326.69 L	start physical_unit 10 10 volume l qc_end physical_unit 4 4 1 2 mole qc_end physical_unit 10 10 17 18 pressure qc_end physical_unit 10 10 23 24 temperature qc_end end	[{"type":"physical unit","value":"Volume [OF] oxygen [IN] L"}]	[{"type":"physical unit","value":"1326.69 L"}]	[{"type":"physical unit","value":"Mole [OF] gasoline [=] \\pu{4.00 moles}"},{"type":"physical unit","value":"Pressure [OF] oxygen [=] \\pu{0.953 atm}"},{"type":"physical unit","value":"Temperature [OF] oxygen [=] \\pu{35.0 ℃}"}]	<h1 class="questionTitle" itemprop="name">If 4.00 moles of gasoline are burned, what volume of oxygen is needed if the pressure is 0.953 atm, and the temperature is 35.0°C? </h1>	null	1326.69 L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We need (i) a stoichiometric equation........</p> <p><mathjax>#C_8H_18(l) +25/2O_2(g) rarr 8CO_2(g) + 9H_2O(l)#</mathjax></p> <p>And so we need <mathjax>#25/2#</mathjax> equiv dioxygen gas.......</p> <p>And thus if <mathjax>#4mol#</mathjax> of octane are combusted we need <mathjax>#25/2xx4=50mol#</mathjax> <mathjax>#"dioxygen gas."#</mathjax></p> <p>And (ii) given <mathjax>#V=(nRT)/P=(50molxx0.0821(Latm)/(Kmol)xx308K)/(0.953atm)#</mathjax></p> <p>Approx....<mathjax>#1300L#</mathjax> or <mathjax>#1.3m^3#</mathjax> <mathjax>#"dioxygen gas"#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well we will treat gasoline as octanes......<mathjax>#C_8H_18#</mathjax>, and we get a volume of </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We need (i) a stoichiometric equation........</p> <p><mathjax>#C_8H_18(l) +25/2O_2(g) rarr 8CO_2(g) + 9H_2O(l)#</mathjax></p> <p>And so we need <mathjax>#25/2#</mathjax> equiv dioxygen gas.......</p> <p>And thus if <mathjax>#4mol#</mathjax> of octane are combusted we need <mathjax>#25/2xx4=50mol#</mathjax> <mathjax>#"dioxygen gas."#</mathjax></p> <p>And (ii) given <mathjax>#V=(nRT)/P=(50molxx0.0821(Latm)/(Kmol)xx308K)/(0.953atm)#</mathjax></p> <p>Approx....<mathjax>#1300L#</mathjax> or <mathjax>#1.3m^3#</mathjax> <mathjax>#"dioxygen gas"#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">If 4.00 moles of gasoline are burned, what volume of oxygen is needed if the pressure is 0.953 atm, and the temperature is 35.0°C? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp" itemprop="url"> <span class="breadcrumb" itemprop="title">Molar Volume of a Gas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="447698" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-07-04T08:03:45" itemprop="dateCreated"> Jul 4, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well we will treat gasoline as octanes......<mathjax>#C_8H_18#</mathjax>, and we get a volume of </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We need (i) a stoichiometric equation........</p> <p><mathjax>#C_8H_18(l) +25/2O_2(g) rarr 8CO_2(g) + 9H_2O(l)#</mathjax></p> <p>And so we need <mathjax>#25/2#</mathjax> equiv dioxygen gas.......</p> <p>And thus if <mathjax>#4mol#</mathjax> of octane are combusted we need <mathjax>#25/2xx4=50mol#</mathjax> <mathjax>#"dioxygen gas."#</mathjax></p> <p>And (ii) given <mathjax>#V=(nRT)/P=(50molxx0.0821(Latm)/(Kmol)xx308K)/(0.953atm)#</mathjax></p> <p>Approx....<mathjax>#1300L#</mathjax> or <mathjax>#1.3m^3#</mathjax> <mathjax>#"dioxygen gas"#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/447698" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-stoichiometric-ratios-relate-to-molar-volume-of-a-gas"> How do stoichiometric ratios relate to molar volume of a gas? 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1,089	ac5c91b5-6ddd-11ea-b44b-ccda262736ce	https://socratic.org/questions/how-many-co-2-molecules-are-in-1-70-10-2-mole-of-co-2	1.02 × 10^22	start physical_unit 2 3 number none qc_end physical_unit 2 2 6 9 mole qc_end end	[{"type":"physical unit","value":"Number [OF] CO2 molecules"}]	[{"type":"physical unit","value":"1.02 × 10^22"}]	[{"type":"physical unit","value":"Mole [OF] CO2 [=] \\pu{1.70 × 10^(-2) mole}"}]	<h1 class="questionTitle" itemprop="name">How many #CO_2# molecules are in #1.70 * 10^-2# mole of #CO_2#?</h1>	null	1.02 × 10^22	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>.......where <mathjax>#N_A="Avogadro's Number"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#6.022xx10^23mol^-1#</mathjax>.</p> <p>And so, <mathjax>#1.70xx10^-2molxxN_A=1.70xx10^-2cancel(mol)xx6.022xx10^23cancel(mol^-1)#</mathjax>, approx. <mathjax>#1.0xx10^22#</mathjax> <mathjax>#"carbon dioxide molecules"#</mathjax>. We get the answer as a number as required. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>There are <mathjax>#1.70xx10^-2molxxN_A#</mathjax> <mathjax>#CO_2#</mathjax> molecules, where.......</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>.......where <mathjax>#N_A="Avogadro's Number"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#6.022xx10^23mol^-1#</mathjax>.</p> <p>And so, <mathjax>#1.70xx10^-2molxxN_A=1.70xx10^-2cancel(mol)xx6.022xx10^23*cancel(mol^-1)#</mathjax>, approx. <mathjax>#1.0xx10^22#</mathjax> <mathjax>#"carbon dioxide molecules"#</mathjax>. We get the answer as a number as required. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many #CO_2# molecules are in #1.70 * 10^-2# mole of #CO_2#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="350706" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-12-12T17:56:10" itemprop="dateCreated"> Dec 12, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>There are <mathjax>#1.70xx10^-2molxxN_A#</mathjax> <mathjax>#CO_2#</mathjax> molecules, where.......</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>.......where <mathjax>#N_A="Avogadro's Number"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#6.022xx10^23mol^-1#</mathjax>.</p> <p>And so, <mathjax>#1.70xx10^-2molxxN_A=1.70xx10^-2cancel(mol)xx6.022xx10^23*cancel(mol^-1)#</mathjax>, approx. <mathjax>#1.0xx10^22#</mathjax> <mathjax>#"carbon dioxide molecules"#</mathjax>. We get the answer as a number as required. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/350706" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1179 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many #CO_2# molecules are in #1.70 * 10^-2# mole of #CO_2#?	null
1,090	ab1198ba-6ddd-11ea-96bf-ccda262736ce	https://socratic.org/questions/what-is-the-mass-in-grams-of-9-45-x-10-24-molecules-of-methanol-ch-3oh	50.3 grams	start physical_unit 13 13 mass g qc_end end	[{"type":"physical unit","value":"Mass [OF] CH3OH [IN] grams"}]	[{"type":"physical unit","value":"50.3 grams"}]	[{"type":"physical unit","value":"Number [OF] CH3OH molecules [=] \\pu{9.45 × 10^24}"}]	<h1 class="questionTitle" itemprop="name">What is the mass (in grams) of #9.45 xx 10^24# molecules of methanol, #"CH"_3"OH"# ?</h1>	null	50.3 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Start by converting the number of molecules of methanol to <em>moles</em> by using <strong>Avogadro's constant</strong>.</p> <blockquote> <p><mathjax>#9.45 * 10^(24) color(red)(cancel(color(black)("molecules CH"_3"OH"))) * overbrace(("1 mole CH"_3"OH")/(6.022 * 10^(23)color(red)(cancel(color(black)("molecules CH"_3"OH")))))^(color(blue)("Avogadro's constant"))#</mathjax></p> <blockquote> <blockquote> <blockquote> <p><mathjax># = "15.69 moles CH"_3"OH"#</mathjax></p> </blockquote> </blockquote> </blockquote> </blockquote> <p>Now, in order to go from <em>moles</em> to <em>grams</em>, you need to use the <strong>molar mass</strong> of the compound, i.e. the mass of exactly <mathjax>#1#</mathjax> <strong>mole</strong> of methanol. </p> <p>Use the molar mass as a conversion factor to get</p> <blockquote> <p><mathjax>#15.69 color(red)(cancel(color(black)("moles CH"_3"OH"))) * "32.04 g"/(1color(red)(cancel(color(black)("mole CH"_3"OH")))) = color(darkgreen)(ul(color(black)("50.3 g")))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the number of molecules present in the sample. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"50.3 g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Start by converting the number of molecules of methanol to <em>moles</em> by using <strong>Avogadro's constant</strong>.</p> <blockquote> <p><mathjax>#9.45 * 10^(24) color(red)(cancel(color(black)("molecules CH"_3"OH"))) * overbrace(("1 mole CH"_3"OH")/(6.022 * 10^(23)color(red)(cancel(color(black)("molecules CH"_3"OH")))))^(color(blue)("Avogadro's constant"))#</mathjax></p> <blockquote> <blockquote> <blockquote> <p><mathjax># = "15.69 moles CH"_3"OH"#</mathjax></p> </blockquote> </blockquote> </blockquote> </blockquote> <p>Now, in order to go from <em>moles</em> to <em>grams</em>, you need to use the <strong>molar mass</strong> of the compound, i.e. the mass of exactly <mathjax>#1#</mathjax> <strong>mole</strong> of methanol. </p> <p>Use the molar mass as a conversion factor to get</p> <blockquote> <p><mathjax>#15.69 color(red)(cancel(color(black)("moles CH"_3"OH"))) * "32.04 g"/(1color(red)(cancel(color(black)("mole CH"_3"OH")))) = color(darkgreen)(ul(color(black)("50.3 g")))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the number of molecules present in the sample. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the mass (in grams) of #9.45 xx 10^24# molecules of methanol, #"CH"_3"OH"# ?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="435733" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-06T23:43:17" itemprop="dateCreated"> Jun 6, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"50.3 g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Start by converting the number of molecules of methanol to <em>moles</em> by using <strong>Avogadro's constant</strong>.</p> <blockquote> <p><mathjax>#9.45 * 10^(24) color(red)(cancel(color(black)("molecules CH"_3"OH"))) * overbrace(("1 mole CH"_3"OH")/(6.022 * 10^(23)color(red)(cancel(color(black)("molecules CH"_3"OH")))))^(color(blue)("Avogadro's constant"))#</mathjax></p> <blockquote> <blockquote> <blockquote> <p><mathjax># = "15.69 moles CH"_3"OH"#</mathjax></p> </blockquote> </blockquote> </blockquote> </blockquote> <p>Now, in order to go from <em>moles</em> to <em>grams</em>, you need to use the <strong>molar mass</strong> of the compound, i.e. the mass of exactly <mathjax>#1#</mathjax> <strong>mole</strong> of methanol. </p> <p>Use the molar mass as a conversion factor to get</p> <blockquote> <p><mathjax>#15.69 color(red)(cancel(color(black)("moles CH"_3"OH"))) * "32.04 g"/(1color(red)(cancel(color(black)("mole CH"_3"OH")))) = color(darkgreen)(ul(color(black)("50.3 g")))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the number of molecules present in the sample. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/435733" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" 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href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 139555 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the mass (in grams) of #9.45 xx 10^24# molecules of methanol, #"CH"_3"OH"# ?	null
1,091	abe679ac-6ddd-11ea-ad5c-ccda262736ce	https://socratic.org/questions/what-is-the-formula-for-the-ionic-compound-copper-bromide-containing-the-cu-ion	CuBr2	start chemical_formula qc_end substance 8 9 qc_end chemical_equation 12 12 qc_end end	[{"type":"other","value":"Chemical Formula [OF] ionic compound [IN] default"}]	[{"type":"chemical equation","value":"CuBr2"}]	[{"type":"substance name","value":"Copper bromide"},{"type":"chemical equation","value":"Cu+"}]	<h1 class="questionTitle" itemprop="name">What is the formula for the ionic compound copper bromide containing the #Cu^+# ion?</h1>	null	CuBr2	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And thus <mathjax>#"cuprous bromide"#</mathjax> is formulated as <mathjax>#CuBr#</mathjax>, A NEUTRAL SALT... </p> <p>On the other hand <mathjax>#"cupric bromide"-=CuBr_2#</mathjax>...here we gots <mathjax>#Cu^(2+)#</mathjax>...</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, bromine forms the bromide ion....</p> <p><mathjax>#1/2Br_2 + e^(-) rarr Br^-#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And thus <mathjax>#"cuprous bromide"#</mathjax> is formulated as <mathjax>#CuBr#</mathjax>, A NEUTRAL SALT... </p> <p>On the other hand <mathjax>#"cupric bromide"-=CuBr_2#</mathjax>...here we gots <mathjax>#Cu^(2+)#</mathjax>...</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the formula for the ionic compound copper bromide containing the #Cu^+# ion?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#ionic-bonds-and-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Ionic Bonds</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/ionic-bonds-and-formulas/writing-ionic-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Writing Ionic Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="626324" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-06-06T13:47:12" itemprop="dateCreated"> Jun 6, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, bromine forms the bromide ion....</p> <p><mathjax>#1/2Br_2 + e^(-) rarr Br^-#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And thus <mathjax>#"cuprous bromide"#</mathjax> is formulated as <mathjax>#CuBr#</mathjax>, A NEUTRAL SALT... </p> <p>On the other hand <mathjax>#"cupric bromide"-=CuBr_2#</mathjax>...here we gots <mathjax>#Cu^(2+)#</mathjax>...</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/626324" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-write-ionic-formulas-for-binary-compounds"> How do you write ionic formulas for binary compounds? 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</a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-an-ionic-compound"> What is the empirical formula for an ionic compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-for-chorate"> What is the molecular formula for chorate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5363023c02bf343b2ee7086b"> Question #7086b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-polyatomic-ions-covalent-1"> Why are polyatomic ions covalent? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/ionic-bonds-and-formulas/writing-ionic-formulas"> See all questions in Writing Ionic Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 5300 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the formula for the ionic compound copper bromide containing the #Cu^+# ion?	null
1,092	aad8b1ca-6ddd-11ea-892d-ccda262736ce	https://socratic.org/questions/an-aqueous-solution-of-4-62-m-potassium-bromide-kbr-has-a-density-of-1-37-g-ml-w	40.13%	start physical_unit 22 25 mass_percent none qc_end end	[{"type":"physical unit","value":"Percent by mass [OF] KBr in the solution"}]	[{"type":"physical unit","value":"40.13%"}]	[{"type":"physical unit","value":"Molarity [OF] KBr aqueous solution [=] \\pu{4.62 M}"},{"type":"physical unit","value":"Density [OF] KBr aqueous solution [=] \\pu{1.37 g/mL}"}]	<h1 class="questionTitle" itemprop="name">An aqueous solution of 4.62 M potassium bromide, KBr, has a density of 1.37 g/mL. What is the percent by mass of KBr in the solution?</h1>	null	40.13%	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your strategy here will be to </p> <ul> <li> <p><em>pick a sample volume of this solution and use its <a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a> to determine its mass</em></p> </li> <li> <p><em>use the solution's <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> to find how many moles of potassium bromide it contains</em></p> </li> <li> <p><em>use potassium bromide's <strong>molar mass</strong> to determine how many grams of the compound will contain that many moles</em></p> </li> </ul> <p>Since you're dealing with <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a>, which as you know is defined as moles of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a>, in this case <em>potassium bromide</em>, <mathjax>#"KBr"#</mathjax>, per <strong>liters</strong> of solution, you can make the calculations easier by picking a <mathjax>#"1.00-L"#</mathjax> sample of this solution. </p> <p>This sample will have a <strong>mass</strong> of </p> <blockquote> <p><mathjax>#1.00 color(red)(cancel(color(black)("L"))) * (1000 color(red)(cancel(color(black)("mL"))))/(1color(red)(cancel(color(black)("L")))) * "1.37 g"/(1color(red)(cancel(color(black)("mL")))) = "1370 g"#</mathjax></p> </blockquote> <p>Since you know the molarity of this solution, you can say that this <mathjax>#"1.00-L"#</mathjax> sample will contain</p> <blockquote> <p><mathjax>#color(blue)(c = n/V implies n = c * V)#</mathjax></p> <p><mathjax>#n_(KBr) = "4.62 M" * "1.00 L" = "4.62 moles KBr"#</mathjax></p> </blockquote> <p>Potassium bromide has a <strong>molar mass</strong> of <mathjax>#"119.0 g/mol"#</mathjax>, which means that <strong>one mole</strong> of potassium bromide has a mass of <mathjax>#"119 g"#</mathjax>. In your case, <mathjax>#4.62#</mathjax> moles of potassium bromide will have a mass of </p> <blockquote> <p><mathjax>#4.62 color(red)(cancel(color(black)("moles KBr"))) * "119.0 g"/(1color(red)(cancel(color(black)("mole KBr")))) = "549.78 g"#</mathjax></p> </blockquote> <p>Finally, a solution's <a href="https://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration by mass</a> is definedas the mass of solute divided by the <strong>total mass</strong> of the solution, and multiplied by <mathjax>#100#</mathjax></p> <blockquote> <p><mathjax>#color(blue)("% w/w" = "mass of solute"/"mass of solution" xx 100)#</mathjax></p> </blockquote> <p>Since this <mathjax>#"1.00-L"#</mathjax> sample has a mass of <mathjax>#"1370 g"#</mathjax>, the solution's <a href="http://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration</a> by mass will be</p> <blockquote> <p><mathjax>#"% w/w" = (549.78 color(red)(cancel(color(black)("g"))))/(1370color(red)(cancel(color(black)("g")))) xx 100 = color(green)("40.1%")#</mathjax></p> </blockquote> <p>The answer is rounded to three <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"40.1% w/w"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your strategy here will be to </p> <ul> <li> <p><em>pick a sample volume of this solution and use its <a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a> to determine its mass</em></p> </li> <li> <p><em>use the solution's <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> to find how many moles of potassium bromide it contains</em></p> </li> <li> <p><em>use potassium bromide's <strong>molar mass</strong> to determine how many grams of the compound will contain that many moles</em></p> </li> </ul> <p>Since you're dealing with <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a>, which as you know is defined as moles of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a>, in this case <em>potassium bromide</em>, <mathjax>#"KBr"#</mathjax>, per <strong>liters</strong> of solution, you can make the calculations easier by picking a <mathjax>#"1.00-L"#</mathjax> sample of this solution. </p> <p>This sample will have a <strong>mass</strong> of </p> <blockquote> <p><mathjax>#1.00 color(red)(cancel(color(black)("L"))) * (1000 color(red)(cancel(color(black)("mL"))))/(1color(red)(cancel(color(black)("L")))) * "1.37 g"/(1color(red)(cancel(color(black)("mL")))) = "1370 g"#</mathjax></p> </blockquote> <p>Since you know the molarity of this solution, you can say that this <mathjax>#"1.00-L"#</mathjax> sample will contain</p> <blockquote> <p><mathjax>#color(blue)(c = n/V implies n = c * V)#</mathjax></p> <p><mathjax>#n_(KBr) = "4.62 M" * "1.00 L" = "4.62 moles KBr"#</mathjax></p> </blockquote> <p>Potassium bromide has a <strong>molar mass</strong> of <mathjax>#"119.0 g/mol"#</mathjax>, which means that <strong>one mole</strong> of potassium bromide has a mass of <mathjax>#"119 g"#</mathjax>. In your case, <mathjax>#4.62#</mathjax> moles of potassium bromide will have a mass of </p> <blockquote> <p><mathjax>#4.62 color(red)(cancel(color(black)("moles KBr"))) * "119.0 g"/(1color(red)(cancel(color(black)("mole KBr")))) = "549.78 g"#</mathjax></p> </blockquote> <p>Finally, a solution's <a href="https://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration by mass</a> is definedas the mass of solute divided by the <strong>total mass</strong> of the solution, and multiplied by <mathjax>#100#</mathjax></p> <blockquote> <p><mathjax>#color(blue)("% w/w" = "mass of solute"/"mass of solution" xx 100)#</mathjax></p> </blockquote> <p>Since this <mathjax>#"1.00-L"#</mathjax> sample has a mass of <mathjax>#"1370 g"#</mathjax>, the solution's <a href="http://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration</a> by mass will be</p> <blockquote> <p><mathjax>#"% w/w" = (549.78 color(red)(cancel(color(black)("g"))))/(1370color(red)(cancel(color(black)("g")))) xx 100 = color(green)("40.1%")#</mathjax></p> </blockquote> <p>The answer is rounded to three <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">An aqueous solution of 4.62 M potassium bromide, KBr, has a density of 1.37 g/mL. What is the percent by mass of KBr in the solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/percent-concentration" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Concentration</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="198541" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-10T23:45:44" itemprop="dateCreated"> Dec 10, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"40.1% w/w"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your strategy here will be to </p> <ul> <li> <p><em>pick a sample volume of this solution and use its <a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a> to determine its mass</em></p> </li> <li> <p><em>use the solution's <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> to find how many moles of potassium bromide it contains</em></p> </li> <li> <p><em>use potassium bromide's <strong>molar mass</strong> to determine how many grams of the compound will contain that many moles</em></p> </li> </ul> <p>Since you're dealing with <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a>, which as you know is defined as moles of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a>, in this case <em>potassium bromide</em>, <mathjax>#"KBr"#</mathjax>, per <strong>liters</strong> of solution, you can make the calculations easier by picking a <mathjax>#"1.00-L"#</mathjax> sample of this solution. </p> <p>This sample will have a <strong>mass</strong> of </p> <blockquote> <p><mathjax>#1.00 color(red)(cancel(color(black)("L"))) * (1000 color(red)(cancel(color(black)("mL"))))/(1color(red)(cancel(color(black)("L")))) * "1.37 g"/(1color(red)(cancel(color(black)("mL")))) = "1370 g"#</mathjax></p> </blockquote> <p>Since you know the molarity of this solution, you can say that this <mathjax>#"1.00-L"#</mathjax> sample will contain</p> <blockquote> <p><mathjax>#color(blue)(c = n/V implies n = c * V)#</mathjax></p> <p><mathjax>#n_(KBr) = "4.62 M" * "1.00 L" = "4.62 moles KBr"#</mathjax></p> </blockquote> <p>Potassium bromide has a <strong>molar mass</strong> of <mathjax>#"119.0 g/mol"#</mathjax>, which means that <strong>one mole</strong> of potassium bromide has a mass of <mathjax>#"119 g"#</mathjax>. In your case, <mathjax>#4.62#</mathjax> moles of potassium bromide will have a mass of </p> <blockquote> <p><mathjax>#4.62 color(red)(cancel(color(black)("moles KBr"))) * "119.0 g"/(1color(red)(cancel(color(black)("mole KBr")))) = "549.78 g"#</mathjax></p> </blockquote> <p>Finally, a solution's <a href="https://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration by mass</a> is definedas the mass of solute divided by the <strong>total mass</strong> of the solution, and multiplied by <mathjax>#100#</mathjax></p> <blockquote> <p><mathjax>#color(blue)("% w/w" = "mass of solute"/"mass of solution" xx 100)#</mathjax></p> </blockquote> <p>Since this <mathjax>#"1.00-L"#</mathjax> sample has a mass of <mathjax>#"1370 g"#</mathjax>, the solution's <a href="http://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration</a> by mass will be</p> <blockquote> <p><mathjax>#"% w/w" = (549.78 color(red)(cancel(color(black)("g"))))/(1370color(red)(cancel(color(black)("g")))) xx 100 = color(green)("40.1%")#</mathjax></p> </blockquote> <p>The answer is rounded to three <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/198541" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-concentration-of-water-in-solution-be-decreased"> How can the concentration of water in solution be decreased? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-concentration-of-a-solution-be-increased"> How can the concentration of a solution be increased? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-concentration-of-a-solution-in-ppm"> How do you find the concentration of a solution in ppm? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-make-a-10-percent-solution"> How do you make a 10 percent solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-make-a-2-percent-solution"> How do you make a 2 percent solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-weight-per-volume-method-to-calculate-concentration"> What is the weight per volume method to calculate concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-percent-concentration-of-kcl-would-be-isotonic"> What percent concentration of KCl would be isotonic? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-of-sodium-chloride-in-normal-saline"> What is the percent concentration of sodium chloride in normal saline? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-of-a-6m-solution-of-nacl"> What is the percent concentration of a 6m solution of NaCl? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-formula"> What is the percent concentration formula? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/percent-concentration"> See all questions in Percent Concentration </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 14826 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	An aqueous solution of 4.62 M potassium bromide, KBr, has a density of 1.37 g/mL. What is the percent by mass of KBr in the solution?	null
1,093	a9709001-6ddd-11ea-8f8c-ccda262736ce	https://socratic.org/questions/if-42-9ml-rubbing-alcohol-is-dissolved-of-in-water-to-make-215ml-of-solution-wha	19.95%	start physical_unit 15 15 volume_percent none qc_end physical_unit 3 4 1 2 volume qc_end substance 9 9 qc_end physical_unit 15 15 12 13 volume qc_end end	[{"type":"physical unit","value":"Volume/volume % [OF] the solute in solution"}]	[{"type":"physical unit","value":"19.95%"}]	[{"type":"physical unit","value":"Volume [OF] rubbing alcohol [=] \\pu{42.9 mL}"},{"type":"substance name","value":"Water"},{"type":"physical unit","value":"Volume [OF] solution [=] \\pu{215 mL}"}]	<h1 class="questionTitle" itemprop="name">If 42.9mL rubbing alcohol is dissolved of in water to make 215mL of solution, what is the concentration expressed in volume/volume % of the solute? </h1>	null	19.95%	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>A solution's <em>volume by volume <a href="https://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration</a></em>, <mathjax>#"% v/v"#</mathjax>, is a measure of the concentration of the solution in terms of the <strong>volume of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a></strong> present in <mathjax>#"100 mL"#</mathjax> <strong>of solution</strong>. </p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a)"% v/v" = "volume of solute"/"100 mL of solution" xx 100color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>This means that all you have to do in order to find a solution's <mathjax>#"% v/v"#</mathjax> concentration is to figure out what volume of solute you get in <mathjax>#"100 mL"#</mathjax> of solution. </p> <p>In your case, you know that you're adding <mathjax>#"42.9 mL"#</mathjax> of rubbing alcohol, which is your solute, to enough water to make the total volume of the solution equal to <mathjax>#"215 mL"#</mathjax>.</p> <p>Since you know how many milliliters of solute you have in <mathjax>#"215 mL"#</mathjax> of solution, you can use this as a <strong>conversion factor</strong> to see how many milliliters of solute would correspond to <mathjax>#"100 mL"#</mathjax> of solution</p> <blockquote> <p><mathjax>#100 color(red)(cancel(color(black)("mL solution"))) * "42.9 mL solute"/(215color(red)(cancel(color(black)("mL solution")))) = "20.0 mL solute"#</mathjax></p> </blockquote> <p>So, if <mathjax>#"100 mL"#</mathjax> of solution contains <mathjax>#"20.0 mL"#</mathjax> of solute, it follows that the <mathjax>#"% v/v"#</mathjax> concentration is </p> <blockquote> <p><mathjax>#"% v/v" = "20.0 mL solute"/(color(red)(cancel(color(black)(100)))"mL solution") * color(red)(cancel(color(black)(100))) = color(green)(\|bar(ul(color(white)(a/a)color(black)("20.0 %")color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#20.0%#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>A solution's <em>volume by volume <a href="https://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration</a></em>, <mathjax>#"% v/v"#</mathjax>, is a measure of the concentration of the solution in terms of the <strong>volume of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a></strong> present in <mathjax>#"100 mL"#</mathjax> <strong>of solution</strong>. </p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a)"% v/v" = "volume of solute"/"100 mL of solution" xx 100color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>This means that all you have to do in order to find a solution's <mathjax>#"% v/v"#</mathjax> concentration is to figure out what volume of solute you get in <mathjax>#"100 mL"#</mathjax> of solution. </p> <p>In your case, you know that you're adding <mathjax>#"42.9 mL"#</mathjax> of rubbing alcohol, which is your solute, to enough water to make the total volume of the solution equal to <mathjax>#"215 mL"#</mathjax>.</p> <p>Since you know how many milliliters of solute you have in <mathjax>#"215 mL"#</mathjax> of solution, you can use this as a <strong>conversion factor</strong> to see how many milliliters of solute would correspond to <mathjax>#"100 mL"#</mathjax> of solution</p> <blockquote> <p><mathjax>#100 color(red)(cancel(color(black)("mL solution"))) * "42.9 mL solute"/(215color(red)(cancel(color(black)("mL solution")))) = "20.0 mL solute"#</mathjax></p> </blockquote> <p>So, if <mathjax>#"100 mL"#</mathjax> of solution contains <mathjax>#"20.0 mL"#</mathjax> of solute, it follows that the <mathjax>#"% v/v"#</mathjax> concentration is </p> <blockquote> <p><mathjax>#"% v/v" = "20.0 mL solute"/(color(red)(cancel(color(black)(100)))"mL solution") * color(red)(cancel(color(black)(100))) = color(green)(\|bar(ul(color(white)(a/a)color(black)("20.0 %")color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">If 42.9mL rubbing alcohol is dissolved of in water to make 215mL of solution, what is the concentration expressed in volume/volume % of the solute? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/percent-concentration" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Concentration</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="283479" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-01T11:15:50" itemprop="dateCreated"> Jul 1, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#20.0%#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>A solution's <em>volume by volume <a href="https://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration</a></em>, <mathjax>#"% v/v"#</mathjax>, is a measure of the concentration of the solution in terms of the <strong>volume of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a></strong> present in <mathjax>#"100 mL"#</mathjax> <strong>of solution</strong>. </p> <blockquote> <p><mathjax>#color(blue)(\|bar(ul(color(white)(a/a)"% v/v" = "volume of solute"/"100 mL of solution" xx 100color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>This means that all you have to do in order to find a solution's <mathjax>#"% v/v"#</mathjax> concentration is to figure out what volume of solute you get in <mathjax>#"100 mL"#</mathjax> of solution. </p> <p>In your case, you know that you're adding <mathjax>#"42.9 mL"#</mathjax> of rubbing alcohol, which is your solute, to enough water to make the total volume of the solution equal to <mathjax>#"215 mL"#</mathjax>.</p> <p>Since you know how many milliliters of solute you have in <mathjax>#"215 mL"#</mathjax> of solution, you can use this as a <strong>conversion factor</strong> to see how many milliliters of solute would correspond to <mathjax>#"100 mL"#</mathjax> of solution</p> <blockquote> <p><mathjax>#100 color(red)(cancel(color(black)("mL solution"))) * "42.9 mL solute"/(215color(red)(cancel(color(black)("mL solution")))) = "20.0 mL solute"#</mathjax></p> </blockquote> <p>So, if <mathjax>#"100 mL"#</mathjax> of solution contains <mathjax>#"20.0 mL"#</mathjax> of solute, it follows that the <mathjax>#"% v/v"#</mathjax> concentration is </p> <blockquote> <p><mathjax>#"% v/v" = "20.0 mL solute"/(color(red)(cancel(color(black)(100)))"mL solution") * color(red)(cancel(color(black)(100))) = color(green)(\|bar(ul(color(white)(a/a)color(black)("20.0 %")color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/283479" itemprop="url">Answer link</a> </div> </div> </div> </div> <div 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around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	If 42.9mL rubbing alcohol is dissolved of in water to make 215mL of solution, what is the concentration expressed in volume/volume % of the solute?	null
1,094	a9c51f50-6ddd-11ea-ab9b-ccda262736ce	https://socratic.org/questions/55f63848581e2a726692083f	0.03 mol/L	start physical_unit 7 10 solubility mol/l qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Solubility [OF] magnesium hydroxide in water [IN] mol/L"}]	[{"type":"physical unit","value":"0.03 mol/L"}]	[{"type":"other","value":"In terms of Ksp."}]	<h1 class="questionTitle" itemprop="name">How do we find the solubility of magnesium hydroxide in water in terms of #K_(sp)#? </h1>	null	0.03 mol/L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>From the above reaction, clearly, <mathjax>#K_(sp) = [Mg^(2+)][OH^-]^2#</mathjax>. We call the solubility of the magnesium salt, <mathjax>#S#</mathjax>, and plugging this back into the equation, <mathjax>#K_(sp) = S xx (2S)^2 = 4S^3#</mathjax> (because for magnesium ion in solution there are 2 hydroxide ions!). So now you have a cubic equation and unknown <mathjax>#S#</mathjax>, which you can solve here without approximation. </p> <p><mathjax>#S=""^3sqrt(1/4xx1.4xx10^-4)=??molL^-1#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We write the solubility expression as before:</p> <p><mathjax>#Mg(OH)_2(s) rightleftharpoons Mg^(2+) + 2OH^-#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>From the above reaction, clearly, <mathjax>#K_(sp) = [Mg^(2+)][OH^-]^2#</mathjax>. We call the solubility of the magnesium salt, <mathjax>#S#</mathjax>, and plugging this back into the equation, <mathjax>#K_(sp) = S xx (2S)^2 = 4S^3#</mathjax> (because for magnesium ion in solution there are 2 hydroxide ions!). So now you have a cubic equation and unknown <mathjax>#S#</mathjax>, which you can solve here without approximation. </p> <p><mathjax>#S=""^3sqrt(1/4xx1.4xx10^-4)=??molL^-1#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do we find the solubility of magnesium hydroxide in water in terms of #K_(sp)#? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-equilibrium" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Equilibrium</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-equilibrium/solubility-equilbria" itemprop="url"> <span class="breadcrumb" itemprop="title">Solubility Equilbria</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="168342" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-09-14T06:21:01" itemprop="dateCreated"> Sep 14, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We write the solubility expression as before:</p> <p><mathjax>#Mg(OH)_2(s) rightleftharpoons Mg^(2+) + 2OH^-#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>From the above reaction, clearly, <mathjax>#K_(sp) = [Mg^(2+)][OH^-]^2#</mathjax>. We call the solubility of the magnesium salt, <mathjax>#S#</mathjax>, and plugging this back into the equation, <mathjax>#K_(sp) = S xx (2S)^2 = 4S^3#</mathjax> (because for magnesium ion in solution there are 2 hydroxide ions!). So now you have a cubic equation and unknown <mathjax>#S#</mathjax>, which you can solve here without approximation. </p> <p><mathjax>#S=""^3sqrt(1/4xx1.4xx10^-4)=??molL^-1#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/168342" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-solubility-affect-equilibrium"> How does solubility affect equilibrium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5351cdc002bf345ec38f076a"> Question #f076a </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-solubility-of-calcium-hydroxide"> How can I calculate solubility of calcium hydroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-an-example-of-a-solubility-equilibria-practice-problem"> What is an example of a solubility equilibria practice problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-common-mistakes-students-make-with-solubility-equilibria"> What are some common mistakes students make with solubility equilibria? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-examples-of-solubility-equilibria"> What are some examples of solubility equilibria? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-write-the-solubility-equilibrium-equation"> How can I write the solubility equilibrium equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-solubility-equilibrium-a-type-of-dynamic-equilibrium"> Is solubility equilibrium a type of dynamic equilibrium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-temperature-affect-solubility-equilibrium"> How does temperature affect solubility equilibrium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-solubility-equilibrium"> How can I calculate solubility equilibrium? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-equilibrium/solubility-equilbria"> See all questions in Solubility Equilbria </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 5751 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How do we find the solubility of magnesium hydroxide in water in terms of #K_(sp)#?	null
1,095	abc98a12-6ddd-11ea-a050-ccda262736ce	https://socratic.org/questions/what-is-the-ph-of-a-solution-with-a-concentration-of-2-4-10-5-molar-h-2o	4.62	start physical_unit 6 6 ph none qc_end physical_unit 15 15 11 14 concentration qc_end end	[{"type":"physical unit","value":"pH [OF] the solution"}]	[{"type":"physical unit","value":"4.62"}]	[{"type":"physical unit","value":"Concentration [OF] H3O+ [=] \\pu{2.4 × 10^(-5) M}"}]	<h1 class="questionTitle" itemprop="name">What is the pH of a solution with a concentration of #2.4*10^-5# molar #H_3O^+#?</h1>	null	4.62	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#pH#</mathjax> <mathjax>#=#</mathjax> <mathjax>#-log_(10)[H_3O^+]#</mathjax>.</p> <p>The solution will be slightly acidic.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#pH#</mathjax> <mathjax>#=#</mathjax> <mathjax>#-log_(10)2.4xx10^(-5)#</mathjax>. </p> <p>You will have to look this up.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#pH#</mathjax> <mathjax>#=#</mathjax> <mathjax>#-log_(10)[H_3O^+]#</mathjax>.</p> <p>The solution will be slightly acidic.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the pH of a solution with a concentration of #2.4*10^-5# molar #H_3O^+#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/the-ph-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">pH</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="291403" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-24T09:38:04" itemprop="dateCreated"> Jul 24, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#pH#</mathjax> <mathjax>#=#</mathjax> <mathjax>#-log_(10)2.4xx10^(-5)#</mathjax>. </p> <p>You will have to look this up.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#pH#</mathjax> <mathjax>#=#</mathjax> <mathjax>#-log_(10)[H_3O^+]#</mathjax>.</p> <p>The solution will be slightly acidic.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/291403" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-pka"> How do you determine pH from pKa? 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1,096	a99be5d9-6ddd-11ea-9038-ccda262736ce	https://socratic.org/questions/chlorine-gas-occupies-a-volume-of-1-20-liters-at-720-torr-pressure-what-volume-w	1.14 liters	start physical_unit 0 1 volume l qc_end physical_unit 0 1 6 7 volume qc_end physical_unit 0 1 9 10 pressure qc_end physical_unit 0 1 18 19 pressure qc_end c_other constant_temperature qc_end end	[{"type":"physical unit","value":"Volume2 [OF] chlorine gas [IN] liters"}]	[{"type":"physical unit","value":"1.14 liters"}]	[{"type":"physical unit","value":"Volume1 [OF] chlorine gas [=] \\pu{1.20 liters}"},{"type":"physical unit","value":"Pressure1 [OF] chlorine gas [=] \\pu{720 torr}"},{"type":"physical unit","value":"Pressure2 [OF] chlorine gas [=] \\pu{1 atm}"},{"type":"other","value":"ConstantTemperature"}]	<h1 class="questionTitle" itemprop="name">Chlorine gas occupies a volume of 1.20 liters at 720 torr pressure. What volume will it occupy at 1 atm pressure? Assume that temperature remains the same.</h1>	null	1.14 liters	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And <mathjax>#1atm-=760mmHg#</mathjax> or rather <mathjax>#1atm#</mathjax> will support a column of mercury that is <mathjax>#760* mm#</mathjax> high...and I truly hope you have seen such a column because the health and safety commissars at my establishment have declared the mercury column counter-revolutionary. </p> <p>And we simply apply old <mathjax>#"Boyles' Law.."#</mathjax> <mathjax>#P_1V_1=P_2V_2#</mathjax></p> <p>We solve for <mathjax>#V_2=(P_1V_1)/P_2=(1.20Lxx(720mmHg)/(760mmHgatm^-1))/((760mmHg)/(760mmHgatm^-1))#</mathjax></p> <p><mathjax>#-=1.14L#</mathjax>...the VOLUME has reduced because we INCREASED the PRESSURE.... </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, <mathjax>#"1 Torr = 1 mm Hg"#</mathjax>...</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And <mathjax>#1atm-=760mmHg#</mathjax> or rather <mathjax>#1atm#</mathjax> will support a column of mercury that is <mathjax>#760* mm#</mathjax> high...and I truly hope you have seen such a column because the health and safety commissars at my establishment have declared the mercury column counter-revolutionary. </p> <p>And we simply apply old <mathjax>#"Boyles' Law.."#</mathjax> <mathjax>#P_1V_1=P_2V_2#</mathjax></p> <p>We solve for <mathjax>#V_2=(P_1V_1)/P_2=(1.20Lxx(720mmHg)/(760mmHgatm^-1))/((760mmHg)/(760mmHgatm^-1))#</mathjax></p> <p><mathjax>#-=1.14L#</mathjax>...the VOLUME has reduced because we INCREASED the PRESSURE.... </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Chlorine gas occupies a volume of 1.20 liters at 720 torr pressure. What volume will it occupy at 1 atm pressure? Assume that temperature remains the same.</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/atmospheric-pressure" itemprop="url"> <span class="breadcrumb" itemprop="title">Atmospheric Pressure</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="628773" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-06-11T16:08:54" itemprop="dateCreated"> Jun 11, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, <mathjax>#"1 Torr = 1 mm Hg"#</mathjax>...</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And <mathjax>#1atm-=760mmHg#</mathjax> or rather <mathjax>#1atm#</mathjax> will support a column of mercury that is <mathjax>#760* mm#</mathjax> high...and I truly hope you have seen such a column because the health and safety commissars at my establishment have declared the mercury column counter-revolutionary. </p> <p>And we simply apply old <mathjax>#"Boyles' Law.."#</mathjax> <mathjax>#P_1V_1=P_2V_2#</mathjax></p> <p>We solve for <mathjax>#V_2=(P_1V_1)/P_2=(1.20Lxx(720mmHg)/(760mmHgatm^-1))/((760mmHg)/(760mmHgatm^-1))#</mathjax></p> <p><mathjax>#-=1.14L#</mathjax>...the VOLUME has reduced because we INCREASED the PRESSURE.... </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/628773" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-atmospheric-pressure-affect-evaporation"> How does atmospheric pressure affect evaporation? 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What volume will it occupy at 1 atm pressure? Assume that temperature remains the same.	null
1,097	abe4a4e9-6ddd-11ea-b137-ccda262736ce	https://socratic.org/questions/59bc1564b72cff58f8477564	5.42 × 10^24	start physical_unit 2 2 number none qc_end physical_unit 10 11 7 8 mole qc_end end	[{"type":"physical unit","value":"Number [OF] atoms"}]	[{"type":"physical unit","value":"5.42 × 10^24"}]	[{"type":"physical unit","value":"Mole [OF] magnesium nitrate [=] \\pu{1 mole}"}]	<h1 class="questionTitle" itemprop="name">How many atoms in a mass of ONE MOLE of #"magnesium nitrate"#?</h1>	null	5.42 × 10^24	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And so there are <mathjax>#1xxMg+2xxN+6xxO"atoms"#</mathjax>.......</p> <p>And we could calculate the molar mass of the nitrate....</p> <p>...which is <mathjax>#148.30gmol^-1#</mathjax>. And thus in <mathjax>#"Avogadro's number of magnesium nitrate formula units,"#</mathjax> <mathjax>#"i.e. a mass of 148.3 g"#</mathjax>, <mathjax>#N_A-=6.022xx10^23mol^-1#</mathjax>, there are <mathjax>#1xxN_A(Mg) + 2xxN_A(N) + 6xxN_A(O)-=9N_A#</mathjax> atoms in toto....</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>You have the formula <mathjax>#Mg(NO_3)_2#</mathjax>....</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And so there are <mathjax>#1xxMg+2xxN+6xxO"atoms"#</mathjax>.......</p> <p>And we could calculate the molar mass of the nitrate....</p> <p>...which is <mathjax>#148.30gmol^-1#</mathjax>. And thus in <mathjax>#"Avogadro's number of magnesium nitrate formula units,"#</mathjax> <mathjax>#"i.e. a mass of 148.3 g"#</mathjax>, <mathjax>#N_A-=6.022xx10^23mol^-1#</mathjax>, there are <mathjax>#1xxN_A(Mg) + 2xxN_A(N) + 6xxN_A(O)-=9N_A#</mathjax> atoms in toto....</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many atoms in a mass of ONE MOLE of #"magnesium nitrate"#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#ionic-bonds-and-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Ionic Bonds</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/ionic-bonds-and-formulas/writing-ionic-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Writing Ionic Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="475900" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-09-15T18:46:14" itemprop="dateCreated"> Sep 15, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>You have the formula <mathjax>#Mg(NO_3)_2#</mathjax>....</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And so there are <mathjax>#1xxMg+2xxN+6xxO"atoms"#</mathjax>.......</p> <p>And we could calculate the molar mass of the nitrate....</p> <p>...which is <mathjax>#148.30gmol^-1#</mathjax>. And thus in <mathjax>#"Avogadro's number of magnesium nitrate formula units,"#</mathjax> <mathjax>#"i.e. a mass of 148.3 g"#</mathjax>, <mathjax>#N_A-=6.022xx10^23mol^-1#</mathjax>, there are <mathjax>#1xxN_A(Mg) + 2xxN_A(N) + 6xxN_A(O)-=9N_A#</mathjax> atoms in toto....</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/475900" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-write-ionic-formulas-for-binary-compounds"> How do you write ionic formulas for binary compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-formula-for-calcium-chloride"> What is the ionic formula for calcium chloride? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-formula-for-calcium-oxide"> What is the ionic formula for calcium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-formula-for-lithium-oxide"> What is the ionic formula for lithium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-formula-for-ionic-compounds"> How do you write the formula for ionic compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-correctly-write-the-ions-present-in-sn-no3-2"> How do I write #Sn(NO_3)_2# in Ionic formula? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-an-ionic-compound"> What is the empirical formula for an ionic compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-for-chorate"> What is the molecular formula for chorate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5363023c02bf343b2ee7086b"> Question #7086b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-polyatomic-ions-covalent-1"> Why are polyatomic ions covalent? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/ionic-bonds-and-formulas/writing-ionic-formulas"> See all questions in Writing Ionic Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2691 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many atoms in a mass of ONE MOLE of #"magnesium nitrate"#?	null
1,098	a9be293f-6ddd-11ea-84b6-ccda262736ce	https://socratic.org/questions/what-is-the-chemical-equation-for-the-neutralization-of-nitric-acid-hno-3-with-m	Mg(OH)2(s) + HNO3(aq) -> Mg(NO3)2(aq) + 2 H2O(l)	start chemical_equation qc_end chemical_equation 11 11 qc_end chemical_equation 15 15 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the neutralization"}]	[{"type":"chemical equation","value":"Mg(OH)2(s) + HNO3(aq) -> Mg(NO3)2(aq) + 2 H2O(l)"}]	[{"type":"chemical equation","value":"HNO3"},{"type":"chemical equation","value":"Mg(OH)2"}]	<h1 class="questionTitle" itemprop="name">What is the chemical equation for the neutralization of nitric acid, #HNO_3#, with magnesium hydroxide, #Mg(OH)_2#, first with spectator ions and then without spectator ions?</h1>	null	Mg(OH)2(s) + HNO3(aq) -> Mg(NO3)2(aq) + 2 H2O(l)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#Mg(OH)_2(s) + 2HNO_3(aq) rarr Mg(NO_3)_2(aq) + 2H_2O(l)#</mathjax></p> <p>...the net ionic equation is simply...</p> <p><mathjax>#HO^(-) + H^+ rarrH_2O(l)#</mathjax>...i.e. simply the garden variety acid-base reaction...</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, magnesium hydroxide is dibasic, and requires 2 equiv nitric acid for equivalence....</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#Mg(OH)_2(s) + 2HNO_3(aq) rarr Mg(NO_3)_2(aq) + 2H_2O(l)#</mathjax></p> <p>...the net ionic equation is simply...</p> <p><mathjax>#HO^(-) + H^+ rarrH_2O(l)#</mathjax>...i.e. simply the garden variety acid-base reaction...</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the chemical equation for the neutralization of nitric acid, #HNO_3#, with magnesium hydroxide, #Mg(OH)_2#, first with spectator ions and then without spectator ions?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="539242" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-01-22T09:27:19" itemprop="dateCreated"> Jan 22, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, magnesium hydroxide is dibasic, and requires 2 equiv nitric acid for equivalence....</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#Mg(OH)_2(s) + 2HNO_3(aq) rarr Mg(NO_3)_2(aq) + 2H_2O(l)#</mathjax></p> <p>...the net ionic equation is simply...</p> <p><mathjax>#HO^(-) + H^+ rarrH_2O(l)#</mathjax>...i.e. simply the garden variety acid-base reaction...</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/539242" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-equation-for-photosynthesis"> What is the chemical equation for photosynthesis? 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1,099	aca3f936-6ddd-11ea-9564-ccda262736ce	https://socratic.org/questions/the-amount-of-heat-needed-to-raise-the-temperature-of-25-g-or-a-substance-by-15-	2.44 J/(g * ℃)	start physical_unit 27 28 specific_heat j/(°c_·_g) qc_end physical_unit 27 28 19 20 heat_energy qc_end physical_unit 27 28 10 11 mass qc_end physical_unit 27 28 16 17 temperature qc_end end	[{"type":"physical unit","value":"Specific heat [OF] the substance [IN] J/(g * ℃)"}]	[{"type":"physical unit","value":"2.44 J/(g * ℃)"}]	[{"type":"physical unit","value":"Needed heat [OF] the substance [=] \\pu{915 J}"},{"type":"physical unit","value":"Mass [OF] the substance [=] \\pu{25 g}"},{"type":"physical unit","value":"Raised temperature [OF] the substance [=] \\pu{15 ℃}"}]	<h1 class="questionTitle" itemprop="name">The amount of heat needed to raise the temperature of 25 g or a substance by 15°C is 915 J. What is the specific heat of the substance?</h1>	null	2.44 J/(g * ℃)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <strong>amount of heat</strong> (<mathjax>#q#</mathjax>) absorbed by the system in this case could be expressed as follows:</p> <p><mathjax>#q=mxxsxxDeltaT#</mathjax></p> <p>Where, <mathjax>#m#</mathjax> is the mass of the substance, </p> <p><mathjax>#s#</mathjax> is <strong>the <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> capacity</strong> of the substance,</p> <p>and <mathjax>#DeltaT#</mathjax> is the change on temperature during the heating process.</p> <p>Thus, the specific heat capacity could be found by:</p> <p><mathjax>#s=q/(mxxDeltaT)=(915J)/(25gxx15^@C)=2.44J/(g*""^@C)#</mathjax> </p> <p>Here is a video that explains this topic in more details:<br/> <strong>Thermochemistry \| <a href="https://socratic.org/chemistry/thermochemistry/enthalpy">Enthalpy</a> and <a href="https://socratic.org/chemistry/thermochemistry/calorimetry">Calorimetry</a>.</strong><br/> <iframe src="https://www.youtube.com/embed/RuBReH04pyE?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#s=2.44J/(g""^@C)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <strong>amount of heat</strong> (<mathjax>#q#</mathjax>) absorbed by the system in this case could be expressed as follows:</p> <p><mathjax>#q=mxxsxxDeltaT#</mathjax></p> <p>Where, <mathjax>#m#</mathjax> is the mass of the substance, </p> <p><mathjax>#s#</mathjax> is <strong>the <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> capacity</strong> of the substance,</p> <p>and <mathjax>#DeltaT#</mathjax> is the change on temperature during the heating process.</p> <p>Thus, the specific heat capacity could be found by:</p> <p><mathjax>#s=q/(mxxDeltaT)=(915J)/(25gxx15^@C)=2.44J/(g""^@C)#</mathjax> </p> <p>Here is a video that explains this topic in more details:<br/> <strong>Thermochemistry \| <a href="https://socratic.org/chemistry/thermochemistry/enthalpy">Enthalpy</a> and <a href="https://socratic.org/chemistry/thermochemistry/calorimetry">Calorimetry</a>.</strong><br/> <iframe src="https://www.youtube.com/embed/RuBReH04pyE?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">The amount of heat needed to raise the temperature of 25 g or a substance by 15°C is 915 J. What is the specific heat of the substance?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/specific-heat" itemprop="url"> <span class="breadcrumb" itemprop="title">Specific Heat</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="263364" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ali-h-1"><img alt="" class="" src="https://profilepictures.socratic.org/IITeL1YTQdODdLp0aJTL_StereoPicture%20copy.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ali-h-1"> Dr. Hayek </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-07T21:00:20" itemprop="dateCreated"> May 7, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#s=2.44J/(g""^@C)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <strong>amount of heat</strong> (<mathjax>#q#</mathjax>) absorbed by the system in this case could be expressed as follows:</p> <p><mathjax>#q=mxxsxxDeltaT#</mathjax></p> <p>Where, <mathjax>#m#</mathjax> is the mass of the substance, </p> <p><mathjax>#s#</mathjax> is <strong>the <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> capacity</strong> of the substance,</p> <p>and <mathjax>#DeltaT#</mathjax> is the change on temperature during the heating process.</p> <p>Thus, the specific heat capacity could be found by:</p> <p><mathjax>#s=q/(mxxDeltaT)=(915J)/(25gxx15^@C)=2.44J/(g""^@C)#</mathjax> </p> <p>Here is a video that explains this topic in more details:<br/> <strong>Thermochemistry \| <a href="https://socratic.org/chemistry/thermochemistry/enthalpy">Enthalpy</a> and <a href="https://socratic.org/chemistry/thermochemistry/calorimetry">Calorimetry</a>.</strong><br/> <iframe src="https://www.youtube.com/embed/RuBReH04pyE?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/263364" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-specific-heat-be-used-to-identify-substances"> How can specific heat be used to identify substances? 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What is the specific heat of the substance?	null

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